Corrigenda to “Mellin Transforms and Asymptotics: Harmonic Sums”, by P. Flajolet,. X. Gourdon, and P. Dumas, Theoretical...
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Corrigenda to “Mellin Transforms and Asymptotics: Harmonic Sums”, by P. Flajolet,. X. Gourdon, and P. Dumas, Theoretical Computer Science 144 (1995), pp. 3–58. P. 11, Figure 1; P. 12, first diplay. [ca 2000, due to Julien Cl´ement.] The Mellin transform of f (1/x) is f ? (−s) [this corrects the third entry of Fig. 1, P. 11], f ? (s)
f (x)
f (1/x) f ? (−s) Also [this corrects the first display on P. 12], 1 M f ; s = f ? (−s). x (The sign in the original is wrong.) P. 20, statement of Theorem 4 and Proof. [2004-12-16, due to Manavendra Nath Mahato] Replace the three occurrences of (log x)k by (log x)k−1 . (Figure 4 stands as it is.) Globally, the right residue calculation, in accordance with the rest of the paper, is (−1)k−1 −ξ x−s x (log x)k−1 . = Res k (s − ξ) (k − 1)! P. 48, Example 19. [2004-10-17, due to Brigitte Vall´ee] Define ∞ X X r(k) 1 ρ(s) = = . s k (m2 + n2 )s m,n≥1 k=1 P∞ −m2 x2 Let Θ(x) = . The Mellin transform of Θ(x1/2 ) is ζ(2s)Γ(s), and m=1 e accordingly [this corrects Eq. (61) of the original; the last display on P. 29 on which this is based is correct] √ π 1 1 1/2 √ − + R(x), Θ(x ) = 2 x 2 where R(x) is exponentially small. By squaring, √ π π 1 1 1/2 √ + + R2 (x), Θ(x ) = − 4x 2 x 4 with again R2 (x) exponentially small. On the other hand, the Mellin transform of Θ(x1/2 )2 is [this corrects the display before Eq. (61)] M(Θ(x1/2 )2 , s) = ρ(s)Γ(s). (Equivalently, the transform of Θ(x)2 is 21 ρ(s/2)Γ(s/2).) Comparing the singular expansion of M(Θ(x1/2 )2 , s) induced by the asymptotic form of Θ(x1/2 )2 as x → 0 to the exact form ρ(s)Γ(s) of the Mellin transform shows that ρ(s) is meromorphic 1
2
in the whole of C, with simple poles at s = 1, 12 only and singular expansion [this corrects the last display of page 48] 1 1 1 π + − + + [0]s=−1 + [0]s=−2 + · · · . ρ(s) 4(s − 1) s=1 2 s − 12 s=1/2 4 s=0 (Due to a confusion in notations, the expansion computed in the paper was relative to ρ(2s) rather than to ρ(s); furthermore, a pole has been erroneously introduced at s = 0 in the last display of P. 48 In fact ρ(0) = 14 , as stated above.)