An Introduction to Nonlinear Boundary Value Problems
This is Volume 109 in MATHEMATICS IN SCIENCE AND ENGINEERING A series of monographs and textbooks Edited by RICHARD BELLMAN, University of Southern California The complete listing of books in this series is available from the Publisher upon request.
An Introduction to Nonlinear BoundaryValue Problems Stephen R. Bernfeld Department of Mathematics Memphis State University Memphis, Tennessee
V Lakshmtkantham Department of Mathematics University of Texas Arlington, Texas
Academic Press, Inc.
New York and London
I974
A Subsidiary of Harcourt Brace Jovanovich. Publishers
COPYRIGHT 0 1974, BY ACADEMIC PRESS, INC. ALL RIGHTS RESERVED. NO PART OF THIS PUBLICATION MAY BE REPRODUCED OR TRANSMITTED IN ANY FORM OR BY ANY MEANS, ELECTRONIC OR MECHANICAL, INCLUDING PHOTOCOPY, RECORDING, OR ANY INFORMATION STORAGE AND RETRIEVAL SYSTEM, WITHOUT PERMISSION IN WRITING FROM THE PUBLISHER.
ACADEMIC PRESS, INC.
111 Fifth Avenw, New York. New York loo03
United Kingdom Edition published by ACADEMIC PRESS, INC. (LONDON)LTD. 24/28 Oval Road, London NWl
Library of Congress Cataloging in Publication Data Bernfeld, Stephen R An introduction to nonlinear boundary value problems. (Mathematics in science and engineering, v. ) Bibliography: p. 1. Boundary value problems. 2. Nonlinear theories. I. Lakshmikantham,V., joint author. 11. Title. 111. Series. QA319.B41 515l.35 73-21996
ISBN 0-12-093150-8
Contents Preface . . . Acknowledgments
ChuprerI 1 .0. 1.1. 1.2. 1.3. 1.4. 1.5. 1.6. 1.7. 1.8. 1.9. 1.10. 1.11. 1.12. 1.13. 1.14. 1.15. Chapter 2
2.0. 2.1. 2.2. 2.3.
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
MethodsInvolvingDifferentialInequalities . Introduction . . . . . . . . Existencein thesmall . . . . . Upper and Lower Solutions . . . TheModifiedFunction . . . . . Nagumo’s Condition . . . . . Existence in the Large . . . . . Lyapunov-Like Functions . . . Existence on Infinite Intervals . . Super-and Subfunctions . . . . Properties of Subfunctions . . . Perron’s Method . . . . . . . ModifiedVectorFunction . . . Nagumo’s Condition (Continued) . Existence in the Large for Systems. Further Results for Systems . . . Notesandcomments . . . . .
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ix
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. . . . . . . . . . . . . Introduction . . . . . . . . . . . . . . . . . Shooting Type Methods
Uniqueness Implies Existence . . . General Linear Boundary Conditions . Weaker Uniqueness Conditions . . . V
1 1 2 12 18 25 31 39 44 46 52 62 69 74 81 84 93 94 94
. . . . . . . . 94 . . . . . . . . 101 . . . . . . . . 109
CONTENTS
2.4. 2.5. 2.6. 2.7. 2.8. 2.9. 2.10. 2.1 1. 2.12.
Chapter 3 3.0. 3.1. 3.2. 3.3. 3.4. 3.5. 3.6.
Chapter 4 4.0. 4.1. 4.2. 4.3. 4.4. 4.5. 4.6. 4.7. 4.8. 4.9. 4.10. 4.1 1. 4.12. 4.13. 4.14. 4.15. 4.16. 4.17.
Nonlinear Boundary Conditions . . . Angular Function Technique. . . . . Fundamental Lemmas . . . . . . . Existence . . . . . . . . . . . Uniqueness . . . . . . . . . . Estimation of Number of Solutions . . Existence of Infinite Number of Solutions Nonlinear Boundary Conditions . . . Notes and Comments . . . . . . . Topological Methods
. . . . . . . 113 . . . . . . . 116
. . . . . . . 117 . . . . . . . 121 . . . . . . . 127
. . . . . . . 136
. . . . . . . 142 . . . . . . . 145 . . . . . . . 152
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Introduction . . . . . . . . . . . Solution Funnels . . . . . . . . . Application to Second-Order Equations . . Wazewski Retract Method . . . . . . Generalized Differential Equations . . . Dependence ofSolutions on Boundary Data Notes and Comments . . . . . . . . Functional Analytic Methods
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Introduction . . . . . . . . . . . . Linear Problems for Linear Systems . . . . Linear Problems for Nonlinear Systems . . . Interpolation Problems . . . . . . . . Further Nonlinear Problems . . . . . . . Generalized Spaces . . . . . . . . . . Integral Equations . . . . . . . . . . Application to Existence and Uniqueness . . Method of A Priori Estimates . . . . . . Bounds for Solutions in Admissible Subspaces . b r a y Schauder’s Alternative . . . . . . Application of LeraySchauder’s Alternative . Periodic Boundary Conditions . . . . . . Set-Valued Mappings and Functional Equations General Linear Problems . . . . . . . . General Results for Set-Valued Mappings . . Set-Valued Differential Equations . . . . . Notes and Comments . . . . . . . . . vi
153
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. 232 . 248 . 256 . 263 . 265 . 269 . 278 . 282 . 289 . 295 . 302
CONTENTS
. . . . . 304 Introduction . . . . . . . . . . . . . . . . . 304 Existence in the Small . . . . . . . . . . . . . . 304
Chapter5
Extensions to Functional Differential Equations
5.0. 5.1. 5.2. 5.3. 5.4. 5.5. 5.6. 5.7. 5.8.
Existence in the Large . . . . . . . . . Shooting Method . . . . . . . . . . Nonhomogeneous Linear Boundary Conditions Linear Problems . . . . . . . . . . . Nonlinear Problems. . . . . . . . . . Degenerate Cases . . . . . . . . . . Notes and Comments . . . . . . . . .
Chapter 6 6.0. 6.1. 6.2. 6.3. 6.4. 6.5. 6.6.
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. 312 . 315 . 320 . 324 . 330 . 335
. . . . . . . . . . . . . . . . 337 Introduction . . . . . . . . . . . . . . . . . 337 Newton's Method . . . . . . . . . . . . . . . 337
Selected Topics
The Goodman-Lance Method . . . . . . . The Method of Quasilinearization . . . . . . Nonlinear Eigenvalue Problems . . . . . . . n-Parameter Families and Interpolation Problems . Notes and Comments . . . . . . . . . .
Bibliography . . . . Additional Bibliography Index
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vii
385
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'Ihe theory of nonlinear boundary value problems is an extremely important and interesting area of research in differential equations. Due to the entirely different nature of the underlying physical processes, its study is substantially more difficult than that of initial value problems and consequently belongs to a third course in differential equations. Although this sophisticated branch of research has, in recent years, developed significantly, the available books are either more elementary in nature, for example the book by Baily, Shampine, and Waltman, or directed to a particular method of importance, such as that by Bellman and Kalaba. Hence it is felt that a book on an advanced level that exposes the reader to this fascinating field of differential equations and provides a ready access to an up-to-date state of this art is of immense value. With this as motivation, we present in our book a variety of techniques that are employed in the theory of nonlinear boundary value problems. For example, we discuss the following: (i) methods that involve differentid inequalities; (ii) shooting and angular function techniques; (iii) functional analytic approaches; (iv) topological methods. We have also included a chapter on nonlinear boundary value problems for functional differential equations and a chapter covering special topics of interest. The main features of the book are (i) a coverage of a portion of the material from the contribution of Russian mathematics of which the English speaking world is not well aware; (ii) the use of several Lyapunov-like functions and differential inequalities in a fruitful way; (iii) the inclusion of many examples and problems to help the reader develop an expertise in the field. This book is an outgrowth of a seminar course given by the authors. We ix
PREFACE
have assumed the reader is familiar with the fundamental theory of ordinary differential equations, including the theory of differential inequalities, as well as the basic theory of real and functional analysis. It is designed to serve as a textbook for an advanced course and as a research monograph. It is therefore useful to the specialist and the nonspecialist alike. The reader who is familiar with the contents of the book, it is hoped, is fully equipped to contribute to the area.
X
Acknowledgments We wish to express our warmest thanks to Professor Richard Bellman whose interest and enthusiastic support made this work possible. We are immensely pleased that our book appears in his series. m e staff of Academic Press has been most helpfil. We thank our colleagues who participated in the seminar on boundary value problems at the University of Rhode Island in 1971-1972. In particular, we appreciate the comments and criticism of Professors E. Roxin, R. Driver, and M. Berman. Moreover, we gratefilly acknowledge several helpfil suggestions offered by Professor L. Jackson. We are very much indebted to Professors G.S. Lad& and S. Leela for their enthusiastic support in many stages of the development of this monograph and to Mr. T. K. Teng for his careful proofreading. Moreover, we wish to thank Mrs. Rosalind Shumate and Mr. Sreekantham for their excellent typing of the manuscript, and we wish to express our appreciation to Ms.Elaine Barth for her superb vping of the final copy. m e first-mentioned author wouM like to acknowledge some interesting helpfirl discussions on boundary value problems with the differential equation 3 group at the University of Missouri at Columbia. Finally, the final preparation of this book was facilitated by a National Science Foundation Gmnt GP-3 7838.
xi
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Chapter 1 METHODS INVOLVING DIFFERENTIAL INEQUALITIES
1.0
INTRODUCTION A variety of techniques a r e employed i n the theory of
nonlinear boundary value problems.
!Chis chapter i s primarily
concerned with the methods involving d i f f e r e n t i a l inequalities. The basic idea i s t o modify the given boundary value problem suitably, and then t o use the theory of d i f f e r e n t i a l inequalities and the existence theorems i n the small t o establish the desired existence r e s u l t s i n the large. After presenting needed existence theorems i n the small, we f i r s t concentrate on scalar second-order d i f f e r e n t i a l equations and associated boundary value problems.
We then
introduce upper and lower solutions, discuss the modification technique, and u t i l i z e Nagumo's condition t o obtain a p r i o r i bounds on solutions and t h e i r derivatives.
Once we have these
bounds a t our disposal, t o prove existence theorems on f i n i t e o r i n f i n i t e intervals i s r e l a t i v e l y simple and straightforward. Boundary value problems subjected t o nonlinear boundary conditions as well are treated i n t h i s framework.
We then
develop Q,rapunov-like theory f o r boundary value problems employing several w a p o v - l i k e functions and the theory of d i f f e r e n t i a l inequalities i n a f r u i t f u l way.
We also t r e a t
i n d e t a i l Perron's method of proving existence i n the large 1
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
by u t i l i z i n g the properties of sub-
and superf'unctions and
the existence r e s u l t s i n the small.
!Ibis technique works well
f o r scalar equations. We next extend the r e s u l t s considered f o r scalar equations t o 8 f i n i t e system of second-order d i f f e r e n t i a l equations. Here there are two directions t o follow, t h a t is, e i t h e r t r y t o obtain the required bounds componentwise o r i n terms of a convenient norm. We o f f e r r e s u l t s from both points of view indicating t h e i r r e l a t i v e merits and using I&-apunov-like theory, whenever possible, t o derive general r e s u l t s . 1.1 EXISTENCE IN l E 3 SMALL
denote t h e r e a l n-dimensional, Euclidean space
Rn
Let
and f o r x
E
Rn,
16(11
let
denote any convenient norm of
x.
be the i n t e r v a l
[a,b]. We s h a l l mean by C(n)[A,B] the class of n-times continuously differentiable functions Let
J
from a s e t A
into
8.
set
B.
We w i l l be concerned, i n t h i s section, w i t h the existence of solutions of the second-order d i f f e r e n t i a l equations of the form (1.1.1)
x" = P(t,x,x'),
satisfying the boundary conditions (1.1.2) where
n n
f E C[JXRnXR ,R
3.
For the purposes of t h i s chapter,
we also need an existence r e s u l t under more general boundary conditions.
This we do consider f o r the s c a l a r case, l e a v i a
a thorough discussion of the general theory t o a l a t e r chapter. F i r s t of a l l , we observe t h a t the only solution of (1.1.3)
XI1 =
0,
subject t o the boundary conditions 2
1.1. EXISTENCE IN THE SMALL
i s the t r i v i a l solution.
This implies, from the theory of
linear d i f f e r e n t i a l equations, that there e x i s t s a unique solution of
(1.1.5)
h(t),
X" =
satisfying (1.1.4) f o r each h
E
C[J,Rn].
Moreover, since the
problem (1.1.3), (1.1.4) possesses the two l i n e a r l y independent solutions u ( t ) = (t - t l ) J v ( t ) = ( t 2 -t ) , the method of variation o f parameters readily gives the i n t e g r a l equation (1.1.6)
x(t) =
+
-
(t2- t ) (S tl)h(S)
jr2(t -
tl)(t2
- s ) h ( s ) ds
dS
I
for the solution x ( t ) of (1.1.5) subject t o (1.1.4). Relation (1.1.6) can be written i n the familiar form
"1 where
i s usually referred t o as the Green's f'unction f o r the boundary value problem i n question. Hence
%is function G(t,s)
the solution of (1.1.5) verifying conditions (1.1.2) takes the form
3
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(1.1.8)
x(t) =
rt2
G(t,s)h(s) ds
+ w(t),
w(t2) = x where w”(t) = 0 and w(t,) = x 1’ 2‘ follows that if x ( t ) is a solution of (1.1.1), (1-1-9)x ( t )
=lt2
G(t,s)f(S,x(s),
~ ‘ ( 8 ) )ds
It therefore
(1.1.2),
then
+ w(t).
Conversely, i f x ( t ) i s a solution of (1.1.9), we can verify by differentiation of (1.1.6) that x ( t ) s a t i s f i e s ( l . l . l ) , (1.1.2). L e t us next r e c a l l some properties of the function G(t,s) f o r later use. For a fixed t, the maximum of IG(t,s)l i s attained a t s = t and IG(t,t)l has i t s maximum value at t = (t1+t2)/2, that i s ,
(1.1. lo)
Iw,~)I
5 ( t 2 - tl)/J+
Furthermore,
and consequently
Wreover,
-
ds = ( ( t tl)
2
+ (t2 - t ) 2 ) / 2 ( t 2
- tl) ,
the maximum of which is attained a t t = t l and t = t 2 . Hence, we obtain 4
1.1. EXISTENCE IN THE SMALL
We are now ready t o prove an existence and uniqueness r e s u l t by using t h e contraction mapping theorem,
where
K, L
>0
are constants such t h a t
Then the boundary value problem ( l . l . l ) ,
(1.1.2) has a unique
solution. Proof: u E CT[[tl,t2],
Let
B
Rn]
Define the operator Tu(t)
be the Banach space of functions with t h e norm
T: B + B
=Lt2
by
G ( t , s ) f ( s , u ( s ) , u t ( s ) ) ds
1
We then have, by (1.l.l.l)and (1.1.13),
Also, because of (l.l.l2), 5
+ w(t).
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
It then follows t h a t
ThisJ i n view of assumption (1.1.14)' shows t h a t
T
is a
contraction mapping and thus has a unique fixed point which i s t h e solution of t h e problem (l.l.l)J (1.1.2).
m e proof i s
complete.
An i n t e r e s t i n g problem i s t o f i n d the l a r g e s t possible i n t e r v a l i n which t h e preceding theorem i s v a l i d . f E C[JXRXR,R],
when
result.
I n t h e case
one can o f f e r such a best possible
We have i n t e n t i o n a l l y given such a r e s u l t i n t h e
following exercise with generous h i n t s . EXERCISE 1.1.1. Assume t h a t
s a t i s f i e s (1.1.13).
Let
(1.1.15)
U"
which vanishes a t number such t h a t
t
u(t)
and
be any solution of
+Lu' + K u = 0
t
and l e t a(L,K) be t h e f i r s t unique 1 u l ( t ) = O f o r t = t l + a ( L J K ) . Show t h a t t h e =
boundary value problem (1.1.1)' if
f E C[JxRXR,R]
(1.1.2) has a unique solution
t 2 - t l < 2a(LJK) and t h a t t h i s r e s u l t i s best possible. Hints:
Step 1. F i r s t show t h a t t h e r e i s a unique solution
t o t h e boundary value problem x 1 ( t 3 )=
3
if
XI'
-
(t3 tl) < a(L,K).
= f(t,x,x'), x(t ) = x 1 1'
This can be shown by apply-
ing the contraction mapping theorem r e l a t i v e t o the M a c h space
E = C(1)[[tl,t3],R]
with t h e norm 6
1 . 1 . EXISTENCE IN THE SMALL I-
where u o ( t )
>0
i s a solution of
for
Lu' +Ku =
+
UI'
cy
s u f f i c i e n t l y close t o 1.
cy
Step 2.
Show t h a t the existence of unique solutions of
(l.l,l),(1.1.2) and of (1.1.1)with e i t h e r
x ( t l ) = x 1' ) = x 3 ' x ( t 2 ) = x 2 on any i n t e r v a l of
x'(t ) = x or x ( 3 3 ' length l e s s than
implies the existence of a unique solution
d
of (1.1.1)' (1.1.2) on any i n t e r v a l of length l e s s than Step 3. show t h a t ing
2d.
To prove t h a t the r e s u l t i s the best possible
u" + Llu'
I + Ku = 0
u(t,) = u ( t 2 )= 0,
where
has a n o n t r i v i a l solution verif'y-
t2- t l =2CY(L,K).
Since u ( t ) = O
also s a t i s f i e s the problem, argue t h a t the r e s u l t i s best possible.
Observe t h a t
EXERCISE 1.1.2.
i n Theorem 1.1.1f o r where N
m
a(L,K)
can be e x p l i c i t l y computed.
Show t h a t it i s s u f f i c i e n t t o define
t
E
/(XI( -< N,
[tl,t21y
IIx' 11 < 4N/(t2
f
- tl),
satisfies either
2 ( t 2 tl>
-a
-< N [ l - ( K
Hint: Apply hll05 N where
2 ( t 2 tl>
-a
t h e contraction mapping theorem on the b a l l
7
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
To obtain merely an existence result we employ Schauder's
fixed point theorem as is usual.
THEOREM 1.1.2. l e t , f o r t E J, IlxII where
f E
I& M > 0, N
ItYII ,< PJ,
5 m,
C[JFRnXRn ,Rn 1.
>0
be given numbers and
Ilf(t,x,Y)II
5
q,
Suppose that
6 = 1nin[(8M/q)~, 2N/ql. Then any problem (1.1,1), (1.1.2) such that [t1,t21 J, t2 tl I 6, Ilx1II 5 M, I ~ x, I 5 M, and Ilx, x211/(t2 t l ) I N, has a solution. Furthermore, given any E > 0, there i s a solution x ( t ) such that
-
-
-
llx(t) -W(t)ll < E, Ilx*(t) -wl(t)ll t2 tl i s sufficiently small.
-
is a closed, convex subset o f
bY
ICx(t)
=
< E on [tl,t21, provided
B. Define the mapping T: B+B
1"'
G(t,s) f (s,x(s),xl (s)) ds + w(t).
Using now estimates (l.l.ll), (l.l.E!),
8
we obtain
1.l.EXISTENCE IN
THE SMALL
and
t2- t l 5 6, T maps
Hence, f o r
II(W"(t)Il
5
into i t s e l f .
Bo
Ilf(t,x(t), x ' ( t ) ) l l
by Ascoli's theorem it follows t h a t
T
5
Also, since
q,
i s completely continuous.
Schauder's fixed point theorem therefore assures t h a t fixed point i n If
x(t)
which i s a solution of ( l . l . l ) ,
Bo,
x
IIx(t) - w ( t )
t
E
(1.1.2).
i s a solution of t h e boundary value problem
(l.l.l), (1.1.2), with
for
T has a
[tl,t2].
E
Bo,
then we have
-
II 5
( ( t 2 tl12/8) 9,
Consequently t h e last assertion follows and
the proof of Theorem 1.1.2 i s complete. COROLLARY 1.1.1. Assume t h a t
and i s bounded on
[tl,t2] XRn xRn.
f E C[[t,,t2]
x R n xRn,Rn]
Then every boundary value
problem (l.l.l), (1.1.2) has a solution. Proof:
where
q
Pick M
>0
s u f f i c i e n t l y large so t h a t
i s an upper bound of
f.
The conclusion then follows
from Theorem 1.1.2.
As was indicated e a r l i e r , we s h a l l next discuss the 9
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
s i t u a t i o n where f E C [J XR x R , R ] . Then a natural question is under what general boundary conditions can one construct a Green's m c t i o n f o r the scalar equation (1.1.3). L e t us look a t t h e boundary conditions
- a2x1 (t,)
(1.1.16)
alx(tl)
(1.1.17)
b x ( t 2 ) +b2X1( t 2 ) = 0 .
= 0,
1
A s long as there e x i s t two l i n e a r l y independent solutions of
(1.1.3) satisfying (1.1.16), ( l . l . l 7 ) , it is possible t o cons t r u c t the desired Green's f'unction. One sufficient condition i s t o f i n d two nonparallel l i n e s satisfying (1.1.16) and (1.1.17), t h a t i s , demanding t h a t alb2 + a2bl
(1.1.18)
#
0.
Another s u f f i c i e n t condition, for example, i s t o require t h a t a2b2 = 0 . I n view of these remarks, it is s u f f i c i e n t t o assume that a1+ b1 > 0,
2 0,
(1.1.19) al,a2,bl,b2
and
a2+b2
> 0.
L e t us now consider the nonhomogeneous boundary conditions (1.1.20)
alx(tl)
-
(1.1.21)
blx(t2)
+ bF'(t2)
a2x1(tl) = A, = B.
It i s not difficult; t o conclude the existence of a solution cp(t) satisfying (1.1.3) and (1.1.20), (1.1.21). Thus any
solution x ( t ) of (1.1.1)obeying the boundary conditions (1.1.20) and (1.1.21), takes the form (1.1.22)
x(t)
Go(t,s)f(s,x(s>,x(s>)
= Jt2
1 where 10
+ T'(t),
1.1. EXISTENCE IN THE SMALL
and
- v(t)u'(t).
c = u(t)v'(t)
Here we assume u ( t ) , v ( t )
are two l i n e a r l y independent solutions o f (1.1.3)which s a t i s f y
(1.1.16), (1.1.17). This discussion leads t o t h e following result. TEEOREM
1.1.3.
[tl,t2] X R X R . (1.1.20),
f E C [[t,,t2]
Let
X R xR,R],
bounded on
Then t h e boundary value problem (l.l.l),
(1.1.21) has a solution, whenever (1.1.18) o r (1.1.19)
holds. Proof:
Let
Define a mapping
M be the bound of T: E + E
where the Banach space
f
on
[tl,t2] x R X R .
by
E = C ( l ) [[tl,t2],R]
Letting
it follows t h a t 11
with t h e norm
1. METHODS INVOLVING DIFFERENTIAL INEQUALITiEs
Hence,
T maps the closed, bounded, and convex s e t
Bo = [X E E: ( x ( t )I 5 NM+L,
Ix'
(t) I
5 NIM+L1]
into i t s e l f . mreover, since I ( ~ ) " l < M, T i s completely continuous by Ascoli's theorem. The Schauder's fixed point theorem then yields the fixed point of T w h i c h i s a solution of (l.l.l), (1.1.20), (1.1.21), thus completing the proof of' the theorem. EXEXCISE 1.1.3.
-
Find the solution of the boundary value
problem x" = t, x(0) x' (0) = 1 and x(1) = 0. 1.2 UPPER AND lxlwER SOLUTIONS Let us consider the second-order equation
(1.2.1)
x" = f(t,X,X'),
where f E C[JxRxR,R], J being the i n t e r v a l [a,b] as before. The i n t e r i o r of J w i l l be denoted by J 0 L e t us define certain types of solutions of d i f f e r e n t i a l inequalities t h a t w i l l play a prominent part i n the subsequent work.
.
DEFINIITION 1.2.1. i s said t o be
A f'unction
cy E
C[J,Rl
(i) a lower solution of (1.2.1) on
-
D "'(t) =lim inf
h+ 0
(ii)
TI
a' ( t + h ) -a'( t - h ) 2h
J
h-t 0
-
C(l)[Jo,R]
if
,> f ( t , a ( t ) , a ' ( t ) ) ,
upper solution of (1.2.1) on J
D-a'(t) slim sup
n
if
a t ( t + h ) - a t ( t h) < f(tp(t),a'(t)), 2h
-
A f'undamental r e s u l t concerning the upper and lower 12
t cJo;
0
t EJ
1.2. UPPER AND LOWER SOLUTIONS
solutions i s t h e following.
THEOmM 1.2.1. (i) f
in x
C[JxRxR,R]
E
f o r each (ii)
Assume t h a t and
(t,y) E J x R ;
i s a lower solution and
cy
i s nondecreasing
f(t,x,y)
i s an upper solution
@
of (1.2.1) on J ; (iii)
@ ( a )5 @ ( a ) and cy(b)
5 B(b).
If one of t h e d i f f e r e n t i a l i n e q u a l i t i e s involved i s s t r i c t ,
then we have Proof: some t E J that
m(t)
sequently,
a(t)
0
< B(t) on J 0
.
Suppose, on t h e contrary, t h a t
.
@ ( t )2 B(t)
Then, s e t t i n g m(t) = a ( * ) - B ( t ) ,
m(to)
> 0,
m ' ( t o ) = 0,
we notice
to E J
has a nonnegative maximum q t some
0
D-mt(tO) 5 0.
and
for
.
ConHence
Thus
i n view of t h e monotonic character of
f.
!this i s a contra-
diction since one o f t h e d i f f e r e n t i a l i n e q u a l i t i e s i s assumed t o be s t r i c t .
The proof i s therefore complete.
We observe t h a t the proof of Theorem 1 . 2 . 1 breaks down i f one of t h e d i f f e r e n t i a l i n e q u a l i t i e s i s not assumed s t r i c t . Nonetheless, t h e following assertion i s t r u e , DIEOREM 1.2.2. 1 . 2 . 1 hold.
Assume -theses
Suppose f'urther t h a t 13
( i ) - ( i i i ) o f Theorem f(t,x,y)
obeys a one-sided
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Lipschitz condition i n y
on each compact subset of
J X R xR,
that i s ,
Then the inequality a ( t ) _< p ( t ) on J, Proof:
Suppose t h a t
2& = m a x [ a ( t ) - p ( t ) ]
a(.)
- P ( c ) = E,
a ( % )> p ( t )
on J .
U(d)
- B(d)=
f o r some t
[c,d]
Let
a(t)
E,
i s true.
C
E
J
0
.
Let
be such t h a t
J
- p(t) 2
t
E,
E
[C,dI
-
to E (c,d) such t h a t a ( t o ) p ( t o ) = 2 E . Consider the compact subset given by
and there e x i s t s a
s
=
[(t,x,y): t
For any
6
E
[c,dl,
IPW-xl
5
1, I B ' W - Y I
_< 11.
> 0 s u f f i c i e n t l y small, l e t p ( t ) s a t i s f y the
conditions p" = ( L + l ) p ' ,
-min(6,E)
< p ' ( t ) _< 1,
0
Set m(t) = p ( t ) p'(t)
- p(t).
2 m'(t), t
-< p ( t ) _< 0 ,
E
Note t h a t
(c,d).
t
E
monotonicity of
E
[c,dl,
-> P ( t ) ,
t
E
(c,d).
m(t)
Moreover, f o r
using successively the assumptions on If we now l e t
t
v ( t ) = m ( t ) + E,
t
E
[c,d],
and
(c,d),
f.
we see, because of the
f,
D'v'(t) =D'm'(t) < f ( t , m ( t ) , m ' ( t ) ) _ < f ( t , v ( t ) , v ' ( t ) ) , Also, 14
t
E
(c,d).
1.2. UPPER AND LOWER SOLUTIONS
+
E
-< m(c) +
E =
v(c),
a ( d ) = @ ( d )+
E
< m(d) +
& =
v(d).
a(.)
= B(c)
An a p p l i c a t i o n of Theorem 1 . 2 . 1 y i e l d s t h a t a(t)
< v(t),
t
E
(c,d).
we o b t a i n
From t h e d e f i n i t i o n of m(t),
B(t) _ < m ( t ) and, as a r e s u l t , we o b t a i n a t
B(t) +
E
t=t
0'
This contradiction proves t h e theorem.
We can deduce a uniqueness r e s u l t f o r a c e r t a i n boundary value problem from Theorem 1.2.2. COROLLARY 1.2.1.
L e t t h e assumptions of Theorem 1.2.2
hold except ( i i ) and ( i i i ) . are s o l u t i o n s on x(t2) = y(t,).
[tl,t2]
with respect t o
y
i s no longer v a l i d .
x"=($)
C
Then x ( t )
REMARK 1.2.1.
This we s t a t e as a c o r o l l a r y .
Suppose t h a t
x,y
such t h a t
x(t,)
J
E
y(t)
on
E
C(2)[[t,,t2],R]
= y(tl),
[tl,t21.
If t h e Lipschitz condition on f ( t , x , y ) on compact sets i s omitted, Corollary 1 . 2 . 1 For example, t h e boundary value problem
(: 5
has s o l u t i o n s x ( t )
1 and
x ( t ) = lt15/2 on
[-1,11.
Instead o f the one-sided Lipschitz condition on f, one could assume t h a t s o l u t i o n s of i n i t i a l value problems XI'
= f(t,x,x')
Theorem 1.2.2.
a r e unique, t o conclude t h e v a l i d i t y of This i s p r e c i s e l y what t h e next theorem does.
THEOREM 1.2.3.
Suppose t h a t 15
I . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(i) in
x
f
C[JXRXR,R]
E
f o r each (ii)
(tJy)
E
and
f(tJx,y)
i s a lower solution and
CY
i s nondecreasing
JxR; i s an upper solution
@
of (1.2.1) on (iii) are unique;
[c,d] C J; solutions of i n i t i a l value problems f o r (1.2.1)
(iv) a ( c >< B(c)
a(t)
Then we have
and CY(d-1 5 @ ( a ) .
5 p(t)
on
[CJd].
The proof of t h i s theorem r e s t s on a r e s u l t t h a t we are going t o consider i n t h e following section and therefore w i l l be given t h e r e . COROLLARY 1.2.2.
If
f(t,x,x')
s a t i s f i e s hypotheses ( i )
and ( i i i ) of Theorem 1.2.3, and i f solutions on
[tl,t2]
x ( t 2 ) = y ( t 2 ) J then
C
J
x,y
such t h a t
E
C(2)[[tl,t2]JR]
are
x(tl)=y(tl),
x ( t ) = y ( t ) on
[tl,t21.
Another i n t e r e s t i n g r e s u l t concerning lower and upper solutions which would y i e l d uniqueness of solutions with general l i n e a r boundary conditions i s t h e following. THEOREM 1.2.4.
(i)
f E C[JxRxR,R]
creasing i n (ii)
Assume t h a t
x f o r each CY
and
(t,y)
E
i s s t r i c t l y in-
f(t,x,y) JxR;
i s a lower solution and
@
i s an upper solution
of (1.2.1) on J; (iii)
f o r each
(t,x,yl),
If(tJx,yl)-f(tJxJy2)I (iv)
a,a(a>
(t,x,y2) E J X R X R j
5
LIY1-Y21J
- a2a' ( a ) 5 al@(a) - a2@'(81,
bl,(b)+b2ct'(b) 5 bl@(b)+b2@'(b), where b +b2 1
> 0,
>O;
a1,a2,blJb2
20,
and
16
a +bl 1
a 1+a2 > 0 ,
>o.
1.2. UPPER AND LOWER SOLUTIONS
Then a ( t ) Proof: -
5
p(t)
on J .
We s h a l l f i r s t show t h a t at the end points of
J
the desired inequality holds. and hence
that
> B(a) which implies from ( i v ) t h a t a2 # 0 a' (a) > p ' ( a ) . Then t h e r e e x i s t s a 6 > 0 such > p ( t ) on [a,6). Consequently, using t h e s t r i c t
.(a)
Let
a(t)
monotony of
and condition ( i i i ) , we obtain
f
D
-
0'
- D-p'
(t)
(t)
-
_> L [ a ' ( t ) B ' ( t ) ] ,
which, by t h e theory of d i f f e r e n t i a l inequalities, y i e l d s a' ( t )
- B ' ( t ) 2 [a'( a ) - B ' ( a ) le L(t-a)
This, together with a ' ( t ) U'(t)
p'(t)
on
[a,6].
- p ' ( t ) -< 0,
assures us t h a t
I n view of (1.2.2), we then a r r i v e
a t the contradiction
-
D-a' ( t ) D-B' ( t ) > 0 which establishes t h e claim
to E [a,s).
(to)
-
- Bf(t) > 0
argument may be extended t o show t h a t a(b)
>0
f o r some
Again, we appeal t o t h e d i f f e r e n t i a l inequality
(1.2.2) t o conclude a ' ( t ) that
(to)
> p(b).
on 6= b
[t0,6].
This
which implies
The l a s t conclusion, i n i t s turn, leads
t o the contradiction a l ( b )
-< p ' ( b ) 17
because of t h e second
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
inequality i n ( i v ) . lation
a(a)
>
p(a)
i s impossible.
a ( t ) 5 B(t)
a ( & ) > p(a)
Thus
a(b)
If we assume t h a t
>
i s impossible.
p(b), we a r e lead t o t h e re-
arguing as before, which we have shown
It therefore remains t o be shown t h a t
on
which i s exactly s i m i l a r t o t h e proof
(a,b),
of Theorem 1.2.1.
The proof of t h e theorem i s therefore
complete.
1.3 THE MODIFIED FUNCTION Employing the notion of upper and lower solutions and t h e existence theorem i n t h e small, it i s possible t o e s t a b l i s h t h e existence of solutions i n t h e large of some boundary value problems f o r a modified form of the d i f f e r e n t i a l equation XI' = f(t,X,X'),
(1.3.1) where
f E C[J xRxR,R].
Let us f i r s t define the modified
function. DEFINITION 1.3.1. on
J
and l e t
c
J.
Then define
>0
Let
a,p
C(l)[JJR]
E
be such t h a t
with
Icy'(t) I, I p l ( t )
I
a(t) < p(t)
< c on
2 c,
f(t,x,c)
for
XI
f(t,X,X')
for
IX'I
f(tJx,-c)
for
x'
5 CJ 5 -c,
and
F(t,x,x') =
F{ The function
F*( t ,B (t),XI) + [x-B(t) ] / 1 + x2
for
F*(tJx,x')
for a ( t ) < x < B ( t ) , for x < a ( t ) .
* (t , a ( t ) , x ' ) + [ x - a ( t ) ] / 1 + x 2
F(t,x,x')
J
w i l l be called the modification of
f ( t J x J x ' ) associated with t h e t r i p l e follows from the d e f i n i t i o n t h a t on J x R x R
x >p(t)
and t h a t 18
a ( t ) , p(t), c.
F(t,x,x')
It
i s continuous
1.3. THE MODIFIED FUNCTION
Let us consider now the modified boundary value problem
(1.3.2)
X"
= F(t,X,X'),
.(a)
=
y, x(b)
= 6,
r e l a t i v e t o which we have t h e following.
THEOREM 1.3.1.
a,f3 E C(l)[J,R]
Let
be, respectively,
lower and upper solutions of (1.3.1) on J a(t)
5
B(t)
on J .
such t h a t
Then t h e boundary value problem (1.3.2),
i s the modification of f associated with t h e t r i p l e cr(t)J B(t)J c, has a solution x E C(2)[J,R] s a t i s f y i n g where
F
a ( t >5 x ( t )
(1.3.3) provided t h a t
Proof:
5
.(a)
y
B(t)
on J,
-
p(a), a ( b ) < 6
5
B(b).
By Corollary 1.1.1, t h e boundary value problem
(1.3.2) has a solution show (1.3.3).
5
5
x c c ( 2 ) [ ~ , ~ ~~ h. u swe only need t o
We s h a l l only prove t h a t
x(t)
5
@ ( t ) on J .
The arguments are e s s e n t i a l l y t h e same f o r t h e case a(t)
x(t).
Assume, i f possible, t h a t
-
x(t)
> B(t)
f o r some
t E J . Then x ( t ) p ( t ) has a positive maximum a t a point 0 to E J Hence it follows t h a t x ' ( t , ) = @ ' ( t o ) , I x ' ( t O ) ( c c
.
and
x"(to) = F ( t O , x ( t O ) , x '( t o ) )
19
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and therefore, we arrive at
-
which i s impossible a t a maximum of x ( t ) B(t). We conclude that x ( t ) 5 B(t) on J . The proof i s complete. Let us next consider the general linear boundary conditions
(1.3.4)
a,x(a)
-
(a) = A,
blx(b)
+ b2x1(b)
= B,
where a1 + a2 > 0, b 1 + b2 > O j a1ja2jbljb2 2 0, and a + b l > 0 . We w i s h t o prove a result analogous t o Theorem 1 1.3.1 w i t h respect t o conditions (1.3.4). F i r s t of a l l , we need the following lemma.
LFMMA 1 . 3 . 1 . Assume that ( i ) a,@ E C(l)[J,R] are, respectively, lower and upper solutions of (1.3.1) on J such that a ( t ) 5 B(t) on J; ( i i ) f E C[J XRXR,R] and for t E Jj a ( t ) 5 x 5 B ( t ) , f ( t , x , x ' ) s a t i s f i e s a Lipschitz condition i n X I f o r a constant L > 0. Then, there exists a f'unction f* E C [ J xRxR,R] which is bounded on J X R X R and i s Lipschitzian for the same constant L > 0 whenever t E J and a ( t ) 5 x ,< B(t).
Proof:
A s before, l e t
I a ' ( t ) l , lB'(t)l t E J and a ( t )
c > 0 be such that
< c on J. Then define f*(t,xJx') f o r 5 x 5 p ( t ) by setting
20
1.3. THE MODIFIED FUNCTION
f*(t,x,x*) =
{
x ' 2 c, ( x ' ) 5 c,
f(t,x,c) f(t,x,xl)
for for
f(t,x,-c)
for
We then extend the domain of definition of J X R X R by l e t t i n g f*(t,x,x')
XI
5 -c.
f*(t,x,x')
f*(t,B(t),x')
for x > B(t),
f*(t,a(t),x')
for x < a ( t ) .
to
=
It i s easy t o see that the function f* so defined possesses a l l the stated properties. Hence the proof i s complete. E-EOREM 1.3.2.
Let hypotheses ( i ) and ( i i ) of Lemma 1 . 3 . 1
Then there exists a solution x
hold.
(1.3.5)
E
C(2)[J,R]
of
XI' = f*(t,X,X')
which s a t i s f i e s the boundary conditions (1.3,4), provided that
(1.3.6)
.,.(a)
Proof: F(t,x,x') =
- a2a' (a) 5 A 5 alp(") - a 2 P (a),
Define the ftmction F(t,x,xl)
{
on J x R x R as
f*C(t,B(t),xl) + ~ ( [ x - ~ ( t ) ~ / l +for x ~ )x > ~(t), f*(t,x,x') for 4 t ) _ < X S B ( t ) , f*(t,a(t),x') + ( [ x - a ( t ) ] / 1 + x 2 ) f o r x < a ( t > ,
where f*(t,x,x') i s the f'unction obtained i n &ma 1.3.1. Since f* is bounded, F is also bounded. Hence, by Corollary 1.1.1, there exists a solution x E C ( 2 ) [ J , R ] of (1.3.8)
X"
= F(t,x,x')
satisfying the boundary conditions (1.3.4).
21
We now show that
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
t
for
E
J, a ( t )
-< x ( t ) -< @ ( t ) ,
which implies t h a t
a solution of the problem (1.3.4), (1.3.5). Assume t h a t x(a) > @(a) i n which case zero.
Then there exists a
[a,6).
By definition of
(1.3.9)
x"(t) - D - B ' ( t )
f*,
+
f*(t,B(t),x'(t))
-
cannot be
h(t) - B(t)l 2 l + x (t)
f*(tJ@(t)?B'( t ) )
-> -Llx' ( t ) - B ' ( t ) I since
Y
i s a l s o an upper solution of (1.3.8).
p(t)
is
> a such t h a t x ( t ) > p ( t ) on F, we have f o r a
6
2
a2
x(t)
Also,
r e l a t i o n (1.3.6) implies, because of the assumption x ( a ) _> p(a), t h a t x ' ( a ) 2 @ ' ( a ) . We claim that there i s a to E [a,6) such that
x'(t,)
on a
5
t
5
- @ ' ( t o )> 0 .
6.
If not, suppose t h a t
Then, by (1.3.9), x"(t)
- D-B'
x'(t)
- p'(t)IO
we would obtain
( t ) _> L[X' ( t )
- B' (t)1
which, by the theory of d i f f e r e n t i a l inequalities, yields x'(t)
- B'(t) 2
This, together with on
a
x'(t)
[x'(a)
- B'(a)le L(t-a)
- B ' ( t ) -4,
implies t h a t
x ' ( t ) Epl(t)
On the basis of (l.3.9), we then arrive a t the
contradict ion
-
x ' ( t o ) @ ' ( t o )> 0 f o r some to E [a,&). Again appealing t o the d i f f e r e n t i a l inequality (1.3.9), we conclude t h a t x ' ( t ) - B ' ( t ) > 0 on [t0,8]. I n
which establishes the claim,
fact, t h i s argument leads t o follows t h a t tradiction
x(b) > p(b).
6 = b and, consequently, it This, i n turn, leads t o the con-
< @'(b), i n view of the relations (1.3.4) x'(b) -
and (1.3.7). 22
1.3. THE MODIFIED FUNCTION
I f , on the other hand, we assume t h a t are lead t o the r e l a t i o n
x(b) > B(b), we arguing as before, which
x(a) > B(a)
has j u s t been shown t o be impossible. show that
x(t)
5
t
@(t) for
Assume then there e x i s t
E J
t
x(t)
- p(t),
It therefore remains t o
.
f o r which
E Jo
tl,t2
"his implies the existence of
The difference
0
E
J
> B(t).
x(t)
such t h a t
therefore, assmes a positive
maximum a t some to E (tl,t2). Clearly, x ' ( t o ) = @ ' ( t o ) and x"(to) D-B' ( t o ) _< 0 . A computation, however, leads t o the contradiction
-
noting ( x t ( t o l = l p T ( t o ) l< c and the definition of f". We < B(t) on J . One can similarly have thus established x ( t ) verify that
a(t) < x(t)
on J
completing the proof.
Let us now proceed t o supply the proof of Theorm 1.2.3.
For t h i s purpose we need the following r e s u l t . THEOREM
1.3.3. Assume t h a t
f E C[JxRxR,R]
and t h a t
,
solutions of i n i t i a l value problems f o r (1.3 .l)are unique. Let a,@ E C(l)[J,R] be lower and upper solutions o f (1.3.1) on J, respectively, such t h a t a ( t ) < p ( t ) on J . Then, i f a ( t o ) = @ ( t o ) and CY ( ) = p ( ) f o r some to E J, it follows ' ' that a ( t ) p ( t ) on J .
Proof:
Suppose t h a t
a ( t ) f p(t)
the case where there i s an i n t e r v a l
on J .
(to,tl]
C
We w i l l consider J
such t h a t
a ( t o ) = @ ( t o ) ,Q ' ( t o ) = B ' ( t o ) , and a ( t ) < B(t) on 23
[to,tlI-
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Fl(t,x,x')
Let
be the modification jknction of
according t o Definition 1.3.1 f o r the i n t e r v a l the t r i p l e a,p,cl.
f(t,x,x') [to,t,]
and
a ( t l ) < S1 < @(tl), we have by
Then, i f
Theorem 1.3.1 t h a t the boundary value problem (BVP) =
X"
Fl(t,x,x'),
has a solution x1 a(t)
5 x,(t) _<
E
B(t)
x(to) = a ( t o ) C(2)[[to,t,],R] on
[tO,tll.
x ' ( t o ) = a l ( t o ) and since of
such that Therefore,
I x i ( t ) I < c1
to, it follows by the definition of
interval
[t0,t2]
(1.3.1).
If
C
t2 = t
[tO,tl]
x ( t 1) = 61
xl(tO)
=
u(to),
on some neighborhood
F1, there i s a maximal
on which x ( t ) 1
i s a solution of
1'
a ( t 2 ) = a@,) < S1 = Xl(t2) = x 1(t1) < @ ( t l ) .
to < t 2 < t
it i s s t i l l t r u e t h a t m(t2) < xl(t2) < p(t2) 1' for, if e i t h e r inequality were an equality, we would have
If
Ixi(t)l
< c1 and the i n t e r v a l [t0 , t 2 3 would not be maximal.
We can therefore construct another modification f'unction
[t ,t ] r e l a t i v e t o the t r i p l e 0 2 a , p, c2. A n application of meorem 1.3.1 again w i t h a ( t 2 ) < 62 < p ( t 2 ) , shows t h a t there i s a solution x2 E C(2) [[t0,t2],R] of the BVP F2(t,x,x')
of
f(t,x,x')
satisfying
a ( t ) < x2(t)
-
on
5 p(t)
on
[t
0'
t 2 1.
it follows t h a t there i s a maximal i n t e r v a l on which x 2 ( t )
A s before,
[to,t3] i s a solution of (1.3.1) and t h a t
C
[t0,t21
a ( t 3 ) < x2(t3) < p(t3). lnnis contradicts the assumption that solutions of i n i t i a l value problems f o r (1.3.1) are unique, since xl(tO) = x 2 ( t 0 ) and x l ( t ) = x;(to). conclude t h a t
a(t)
p(t)
1
on
24
0 J.
We therefore
1.4. NAGUMO'S CONDITION
We a r e now ready t o give t h e proof o f Theorem 1.2.3. Proof of meorem 1.2.3: some points o f
[c,d]
Assume t h a t
and l e t
Clearly t h e r e e x i s t s a
a(t)
-
> p ( t ) at
N = m a x [ a ( t ) @ ( t ) l on
-
[c~d].
to E [ c , d ] where a ( t O ) @ ( t o )= N
and a ' ( t o ) = B ' ( t o ) . The functions (Y and B , = p + N s a t i s f y t h e conditions o f Theorem 1.3.3 i n view of t h e nondecreasing nature f(t,x,xl)
of
@ ( t )+ N
a(t)
in
Consequently it follows t h a t
x.
on
[c,d],
a c o n t r a d i c t i o n which proves t h e
theorem.
1.4 NAGW'S CONDITION A s we have seen, t h e proofs f o r t h e existence theorems
for solutions o f boundary value problems depend on f i n d i n g a Here we
p r i o r i bounds f o r t h e s o l u t i o n and i t s d e r i v a t i v e .
present some s u f f i c i e n t conditions f o r obtaining such bounds. DEFINITION 1.4.1. C[J,R]
with
Let
E
t
J, w ( t ) _< x _< @ ( t ) and
(1.4.1) where h
If(tJXYX') E
C[JXRxR;R]
E
a(t) < @ ( t ) on
a,p E
f
x'
E
J.
and
Suppose t h a t f o r
R,
I 5 h ( Ix' 1 )
C [R+j ( o J m ) ] . If
THEOREM 1.4.1. condition on J
Assume t h a t
f
satisfies Nagumo's
with respect t o t h e p a i r 25
a , @ . m e n f o r any
1.
METHODS INVOLVING DIFFERENTIAL INEQUALITIES
solution x E C(')[J,R] of (1.3.1) with a ( t ) _< x ( t ) ,< @ ( t ) on J, there e x i s t s an N > 0 depending only on a,@,h such that Ix'(t) I
(1.4.4)
5N
on J .
Because o f (1.4.2), we can choose an N > h such
Proof: that
(b - a ) x l ( t o ) = x(b)
to E Jo is such t h a t
If
- x(a),
then by
I x l ( t O )I 5 h. Assume t h a t (1.4.4) i s not Then there e x i s t s an i n t e r v a l [tl,t21 C J such t h a t
(1.4.3), we have true.
the following cases hold: = N,
and
A < x'(t)
=
N, x l ( t , ) = A,
and
h
x ' ( t 1)
=
-A,
x'(t,)
= -N,
(i) x l ( t ) = A, x ' ( t , ) 1
< N,
t c (tl,t2),
( i i ) x'(t,)
t
E
(tl,t2), (iii)
t
E
(tl,t2), (iv)
t
E
< x ' ( t ) < N,
x'(t2)
= -N,
and
-N < x ' ( t )
< -A,
x
=
-h,
and
-N < x l ( t )
<
)
-A,
(tl,t2).
L e t us consider case ( i ) .
On
[tl,t21,
and as a r e s u l t
26
we obtain, by (l,b.l),
1.4. NAGUMO'S CONDITION
This leads t o t h e c o n t r a d i c t i o n
We can d e a l with t h e remaining p o s s i b i l i t i e s i n a s i m i l a r way
and therefore we conclude t h a t (1.4.4) i s v a l i d .
Then, f o r any s o l u t i o n exists an N lx'(t)l
5
>0 on
N
x
E
C(2)[J,R1 with
depending only on J.
Also,
N -10
M,h, (b
as
( x ( t ) ( 5 M,
- a)
there
such t h a t
M -0.
The conclusion of Corollary 1 . 4 . 1 i s n n C[JxRnxR , R ] and absolute values a r e re-
REMARK 1.4.1.
false, i f
f
E
placed by norms, as t h e following example shows. (cos n t , s i n n t ) llX"
( t ) 11 = n2 =
hold with
(Ix'
so t h a t ( t ) I/*.
Let
x(t)
=
Ilx(t)(I = 1, Ilxl(t)ll = n, Thus t h e assumptions of Corollary 1 . 4 . 1
M = 1, h ( s ) = s2
+
1. However, t h e r e does not e x i s t
an N > 0 such t h a t / / x t ( t ) )_<) N f o r a l l choices of n. Thus it is c l e a r t h a t Nagumo's condition i s not s u f f i c i e n t t o obtain the desired conclusion i n t h e case of systems. We s h a l l discuss t h i s f u r t h e r when we t r e a t systems of equations l a t e r i n t h i s chapter. 21
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
EXERCISE 1.4.1.
on
Suppose t h a t
J.
a(t)
Let
5
5
where
L
>
f E C[JxRxR,R]
p(t), Y 1 J Y 2
I 0
(
J xJ
C(l)[JJR] with
E
Y,)
and f o r
a(t)
t
E
-< p ( t )
JJ
RJ
-
(t J xJY2)
i s a constant.
Show
condition. THEOREM 1.4.2.
Assume t h a t such t h a t
( i ) a,p E C(l)[J,R] a(b) = p(b)J W
and a ( t )
5
p(t)
On
.(a)
= p(a),
J;
( i i ) (pJJI E C(')[uJR] with q ( t J x ) 5 Jl(t,x) on = [(t,X): a ( t ) <X < (u(t)J t E J ] and O n W,
(1.4.5)
q t ( t J x ) + qx(tJx)q(tJx)
< f(tJxJq(tJx)),
(1.4.6)
$ t ( t J x ) + qx(tJx)q(tJx)
> f(tJXJq(tJX)),
Proof:
a(t)
Let
x(t)
(u,
where
be any solution of (1.3.1) such t h a t
_< x ( t ) 5 p ( t ) on J . Then, by
(i)and ( i i i ) it follows
that ' ~ ( a , x ( a )5 )
X I(a)
Assume now t h a t there exists a
5
Jr(a,x(a)).
to E (a,b)
such t h a t
< ' p ( t o J x ( t o ) ) . Then there must e x i s t an i n t e r v a l [tl,t2]C J with tl < to < t2 such t h a t x ' ( t i ) = ' P ( t i > x ( t i ) ) Ji = 1,2 and x ' ( t ) < ' P ( t , x ( t ) ) , t i < t < t 2 J
x'(to)
28
1.4. NACUMO'S CONDITION
and f u r t h e r t h a t
This i s a c o n t r a d i c t i o n because of assumption ( i i ) .
f o r e conclude t h a t merit shows t h a t
x'(t)
x'(t)
-> ' p ( t , x ( t ) )
-< J r ( t , x ( t ) )
on
on J
We there-
A s i m i l a r argu-
J.
and t h e proof i s
complete. We remark t h a t t h e i n e q u a l i t y s i g n i n (1.4.5) could be reversed i n which case t h e c o n t r a d i c t i o n i s a r r i v e d a t because of
(1.4.6).
A s i m i l a r coment holds r e l a t i v e t o i n e q u a l i t y
Of
course, i n t h i s case, we have t o replace ( i i i ) by V(b,a@))
5 a'@>,
_< Jr(b,B(b))*
COROLLARY 1.4.2. Assume ( i ) of Theorem 1.4.2.
e x i s t constants B'(a),B'(b)
N
5N2,
N such t h a t 1 ' 2 and f(t,x,Ni)
a"(a), a' (b)
#
0, i = 1,2.
clusion of Theorem 1.4.2 i s t r u e w i t h $ { t A=
9.
EXERCISE 1.4.2. Assume t h a t
Ix'I
--fw
f
E
Let there
2 N1, Then t h e con-
cp(t,x) = N1
and
L e t hypothesis ( i ) of Theorem 1.4.2 hold.
C[JXRXR,R]
and
uniformly on compact
lf(t,x,x')I
(t,x)
sets.
-tm
as
Show t h a t t h e
conclusion of Corollary 1.4.2 i s t r u e . EXERCISE 1.4.3. 1 . 4 . 1 h o l d and flmctions
h(s)
Show t h a t i f t h e assumptions o f Corollary i s nondecreasing, t h e r e always e x i s t
'p(t,x), @ ( t , x ) (independent of
t ) satisfying the
hypotheses of Theorem 1.4.2. Consider t h e ' following example on J = [-1,11,' 29
1 , METHODS
= e-2(x+1)
XI'
where
n
INVOLVING DIFFERENTIAL INEQUALITIES
- (x')2nJ
x(-1) = 0 = x ( l ) ,
i s a p o s i t i v e integer.
B ( t ) = 0.
Choose N1 = - 2
Take
and
a ( t ) = t 2 - 1 and
N2 = 2.
Then we see a l l t h e
hypotheses of Corollary 1.4.2 a r e s a t i s f i e d . t h a t any solution x ( t ) Ixr(t)(5 2
on J.
such t h a t
Hence we conclude
t 2 -15 x ( t ) _< 0
However, we notice t h a t f o r n
satisfies
>
* J
Corollary 1 . 4 . 1 is not applicable. A variant of Theorem 1.4.2 which i s more useful i s t h e following r e s u l t .
Proof:
Let
f (t>XJX') such t h a t
o(t)
_< x ( t ) 5 B(t), t
to E (a,bl
be any solution o f
x E C(2)[J,R1
such t h a t
cp(a,x(a)) E
J.
5 x *( a ) 5
q(a,x(a))
x" = and
Suppose t h a t t h e r e e x i s t s a
x'(to)
> q ( t o , x ( t o ) ) . Define
30
15. EXISTENCE IN THE LARGE
Then,
i n some i n t e r v a l t o t h e l e f t of
to. This implies t h a t
V(t)
t increases and p o s i t i v e near to and hence on [a, toI. Thus we have V(a) > 0 o r equivalently x ' ( a ) > $ ( a , x ( a ) ) which i s a contradiction. Hence x ' ( t ) _< $ ( t J x ( t ) ) on J . S i m i l a r l y we can v e r i f y i s nonincreasing as
'p(tJx(t))
5 x'(t>
on J.
1.5 EXISTENCE I N THE LARGE We a r e now ready t o prove theorems on existence i n t h e large.
We begin with one of t h e b a s i c r e s u l t s i n t h i s d i r e c t i o n .
THEOREM 1.5.1.
Let
a,p
E
C(l)[J,R]
be, respectively,
lower and upper s o l u t i o n s of (1.3.1) on J
@(t) _< @ ( t ) on J.
Suppose f u r t h e r that
such t h a t f(t,x,x')
satisfies
Nagumo's condition on J any .(a)
(1.5.1)
5
c
5
r e l a t i v e t o t h e p a i r a,@. Then, f o r @ ( a ) , ~ ( b 5) d 5 B ( ~ ) J t h e BVP
x" = f ( t , x , x ' ) ,
has a s o l u t i o n x
E
x ( a ) = c,
c ( 2 ) [ J ~ R ] with
31
x ( b ) = d,
a ( t >_< x ( t > _< @ ( t )and
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
lx'(t)l
5N
on J,
where
depends only on a,@ and t h e
N
Nagumo's function h. By Theorem 1.4.1, t h e r e i s an N
Proof:
only on a,p,h with
a(t)
5
such t h a t
Ix'(t)l
x ( t ) _< @ ( t ) on J .
( c u ' ( t ) ( < cl,
(P'(t)(
<
5
on J
N
depending
f o r any solution
c > N so t h a t 1 Then, by Theorem 1.3.1, t h e
Choose a
on J.
c1
>0
BVP x" = F ( t , x , x ' ) , has a solution on J,
where
f(t,x,x')
x ( a ) = c,
x E C(2)[J,R]
a ( t ) 5 x ( t ) _< p ( t ) i s t h e modification f'unction of
F(t,x,x')
with respect t o
to
theorem t h e r e i s a
x ( b ) = d,
E Jo
such t h a t
a,p,
and
cl.
By t h e mean value
such t h a t
(b - a ) x ' ( t o ) = x ( b )
- x(a),
and as a r e s u l t using (1.4.3) it follows t h a t
Ix'(t,)l 5 h < N < cl. This implies t h a t t h e r e i s an i n t e r v a l containing toy where x ( t ) i s a solution of x" = f ( t , x , x ' ) . By Theorem
1.4.1, we have
Ix'(t)l
5
N
< c1 on t h i s i n t e r v a l .
However, I x ' ( t ) J < cl-
x ( t > i s a s o l u t i o n of
XI' = f ( t , x , x ' )
We conclude t h a t
i s a solution of (1.5.1) on J.
x(t)
as long as
The
proof i s complete.
COROLLARY 1.5.1.
Under t h e assumptions of Theorem 1.5.1,
any i n f i n i t e sequence of solutions of the relation
a(t)
,< x ( t ) _<
p(t)
XI'
on J,
= f(t,x,x')
obeying
has a uniformly con-
vergent subsequence converging t o a solution of
x'l = f ( t , x , x ' )
on J . A conclusion similar t o Theorem 1 . 5 . 1 may be drawn r e l a t i v e
t o t h e boundary value problem (1.3.1), Theorem 1.3.2,
EXercise 1.4.1,
(1.3.4), on the b a s i s of
and the proof of Theorem 1.5.1.
32
1.5. EXISTENCE IN THE LARGE
We state it in the following exercise. Let hypotheses (i) and (ii) of Lemma Show that for any A,B for which relations (1.3.6)
EXERCISE 1.5.1.
1.3.1 hold.
and (1.3.7) are valid, the BVP (1.3.1), (1.3.4) has a solution such that a(%) _< x(t) _< p(t) on J and x E C(*)[J,R] Ix'(t)l < N on J, where N > 0 depends o n l y on a,@,L. EXERCISE 1.5.2.
Let f E C [ J x R x R , R ] , f(t,x,x') be nondecreasing in x for each (t,x') and satisfy If(t,x,yl)f(t,x,y2)l5~ Iy1-y21 for (t,x> E J X R and yljy2 E R. Show that the BVP (1.3.1), (1.3.4) has a solution. If f is strictly increasing in x, then show that the solution is unique. Hint: -
Set M
max f(t,O,O), m = min f(t,O,O) and J J let p(t) > - 0, a(t) _< 0 be solutions of x" + L l x ' I - m = 0 , XI'- Llx'l - M = 0 , respectively, subject to (1.3.6), (1.3.7) which may be computed explicitly. Then, using monotony of f, show a,@ are lower, upper solutions. For uniqueness, use =
Theorem 1.2.4. 2
1.5.3. Verify that p(t) = t, a(t) = t 1 - 3t +2 are upper, lower solutions for the problem x'' = - 1x1' + t, x(1) = 0, x'(2) = 1, on J = [1,2]. Draw conclusions on the applicability of Exercises 1.5.1, 1.5.2 to this problem. Discuss the merits. EXERCISE
The foregoing discussion concerning the problem (1.3.1),
(1.3.4) imposes more restrictions on the function f compared This is apparently due to the techniques to the B W (1.5.1). involved in the process rather than the need, because the result that we present next involves nonlinear boundary conditions more general than (1.3.4) and yet the assumptions on f are just 33
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
those required f o r t h e BW (1.5.1). We s h a l l f i r s t prove t h e following.
THEOREM 1.5.2. (a) a,@
E
Assume t h a t
C(l)[J,R],
s o l u t i o n s of (1.3.1) on
respectively, a r e lower and upper such t h a t
J
a(t) 5 B(t)
on J
and
a(a) < B(a); (b)
s a t i s f i e s Nagumo's condition on
f(t,x,x')
respect t o t h e p a i r (c) y
g
E
f o r each
(1.5.2)
a(b) J
_<
d
g(x,y)
i s nondecreasing i n
and
g(a(a),a'(a))
2
g(B(a),B'(a))
0,
It i s enough t o show t h a t given
Proof:
with
a,B;
C[[a(a),B(a)] xR,R],
x,
J
_< f3(b),
there i s a solution
x(t,E)
5
0.
E
>
0
and
of (1.3.1)
on
that fulfills x(b,E> = d,
and
a ( t ) 5 x(t,E)
that that such
on
<E
J.
_< d _< B(b), l e t T(c) denote t h e s e t (1.5.1) such t h a t a ( a ) _ < c < B ( a ) a ( t ) _< x ( t ) _< p ( t ) on J. By Theorem 1.5.1, it i s c l e a r ~ ( c ) i s nonempty f o r a l l a(&)5 c _< @(a). Suppose now t h e theorem i s not t r u e . Then t h e r e exists an EO > 0 , t h a t f o r every a ( a ) _< c 5 p ( a ) and x ( t ) E ~ ( c ) , we have For a f i x e d
of s o l u t i o n s and
5 B(t)
Ig(X(a,E), x'(a,E))I
x(t)
a(b)
t o t h e BW
Ig(x(a),x'
(4)I 2 E O . 34
1.5. EXISTENCE IN THE LARGE
Define the set S by
and let co = sup[x(a) = c: x(t) E S]. We notice that x(t) E T(cy(a)) implies a'(a) _< x ' ( a ) which by (1.5.2) yields g(x(a>,xl(a>) E ~ . Similarly, x(t> E .rr(@(a)) implies
>
5 -EO. This observation x'(a) _< @'(a) so that g(x(a),x'(a)) proves that co < p(a). Let yo(t) be a solution of (1.3.1) which is obtained as a uniform limit of members of S so that (1-5.3) yO(a> =c0,
Yo@) = d ,
and g(Yo(a>, Y;)(a))
2
€0.
For n 2 N, Now let N 2 1 be such that co + (1/N) 5 @(a). satisfying, in addition, the inlet yn(t) E T(C~ f (l/n))
>
equality yn(t) yo(t) on J. This is clearly possible since yo(t) may be treated as a lower solution of (1.3.1). Then a subsequence of yn(t) converges to a solution xo(t) obeying xo(t) yo(t) on J. By definition of co,
>
E T ( C ~ )
we have
5 -cO and consequent- g(xo(a>, x;(a)) _< g(yn(a), y;(a)) Since x;(a) 2 y;)(a) and xo(a) = yo(a), this leads to g(y,(a), y;)(a)) 5 - E O which is a contradiction in view of (1.5.3).
-E~.
The proof is complete.
Employing similar arguments as in the proof of Theorem 1.5.2, which were based on a consequence of Theorem 1.5.1, namely Corollary 1.5.1, we may prove the following theorem. THEOREM 1.5.3.
Assume that
respectively, are lower and upper C(l)[J,R], solutions of (1.3.1) on J such that (a) a,@
E
a(t)
5
@(t)
on J and a(b) < @(b);
(b) f(t,x,x') satisfies Nagumo's condition on J relative to the pair a,@; 35
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(c) h
C[[a(b),B(b)]
E
xR,R],
y for each x and h(a(b),
=
f(t,x,x'),
5
a'(b))
Then, for any .(a) 5 c 5 @(a) x C E C(2)[J,R] of the BVP x"
h(x,y)
2
h(B(b),B'(b))
0.
there is a solution
x(a) = c,
which satisfies a(t)
0,
is nondecreasing in
5 xc(t) 5
h(x(b),x'(b))
B(t)
= 0
on J.
Combining the proofs of Theorems 1.5.2 and 1.5.3, we may obtain our main result relative to nonlinear boundary conditions. THEOREM
1.5.4. Assume that
(a) a,@
E
C(l)[J,R],
respectively, are lower and upper
solutions of (1.3.1) on J .(a>
such that Q(t)
5 B(t)
on J and
4 b ) < Bb); (b) f(t,x,x') satisfies Nagumo's condition on J with
< B(a),
respect to the pair a,B; E C[[a(a),B(a)l xR,R], h E C[[o(b),B(b)] xR,R], (c) g(x,y), h(x,y) are nondecreasing in y for each x and
g(a(a),al(a)) h(a(b),a'(b))
2
0,
5
0,
Then there is a solution x XI' = f(t,x,x'),
g(B(a),B'(a)) h(B(b),B'(b)) E
which satisfies a(t)
= 0,
5 x(t) _<
@(t)
Proof: For each a(b) 5 d set of solutions of the BVP
x"
=
f(t,x,x'),
5
2
0-
h(x(b),
x'(b))
= 0,
on J.
@(b),
g(x(a>,x'(a))
0,
of the BVP
C(*)[J,R]
g(x(a),x'(a))
5
let T ( d ) denote the = 0,
x(b) = d,
which satisfy a(t) 5 x(t) 5 B(t) on J. By Theorem 1.5.2, is nonempty for all it is clear that the set T(d) 36
15. EXISTENCE IN THE LARGE
which contradicts the supposition that the theorem is not Now use y(t) in place of a(t) true. Hence y(a) < @(a). in Theorem 1.5.2 to conclude that the set D = [x(t): x(t)
E
T(d),
do
< d 5 B(b),
y(t)
5 x(t)
.< @(t>
on
JI
in nonempty. Moreover, x(t) E n(d) implies that h(x(b), x'(b)) > 0 . However, inf[x(b) = d: x(t) E D] = do, which leads to a contradiction by a convergence argument and the fact that h(x,y) is nondecreasing in y. Hence the proof is complete. On the basis of Theorem 1.4.3, it is possible to relax the condition of the basic Theorem 1.5.1 which is the content of the next result. THEOREM 1.5.5. Suppose that assumptions (i) and (ii) of Theorem 1.4.3 hold. Let a,@ be lower and upper solutions of (1.3.1), respectively, on J, such that a(&) = @(a) and
cp(t,y(t))
5 ~'(t)I +(t,r(t>),
for y(t) 37
=
a(t),B(t),
t
E
J.
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Then, f o r any
5
a(b)
d
_< B(b) and u(a)
BVP (1.5.1) has a solution
x E C(2)[J,R]
(t,x(t),x'(t>) where
E
n,
t
= c = B(a),
the
such t h a t E J,
il i s t h e s e t given by
R = [(t,x,x'):
Proof:
(t,x>
E
(0
and
cp(t,x)
Define a modified function
5 x' 5
Jr(t,x)l.
F(t,x,x')
on
cuxR
by f(t,x,dt,x)) f(t,x,+(t,x)) and extend
F(t,x,x')
to
if x '
< cp(t,x>,
if
(t,x,x')
if
XI
>
E
n,
q(t,x),
J x R x R by s e t t i n g
F(t,a(t),x')
if
x < a(t),
F(t,B(t),x')
if
x > @(t).
F(t,x,x') = Observe t h a t
i s bounded on J x R x R
F(t,x,x')
s a t i s f i e s Nagumo's condition.
a',@'), w,B,
assumptions on
and therefore
Furthermore (because of t h e a r e a l s o lower and upper solutions
relative t o
Consequently, by Theorem 1.5.1 t h e r e exists a solution x E C(2)[J,R]
t o t h e modified BVP
x" = F(t,x,x'), such t h a t and
a(b)
a(t)
5
d
x ( a ) = c,
x(b) = d,
5 x(t) 5
_< B(b).
B(t), t E J f o r .(a) = c = B(a) We now apply Theorem 1.4.3 t o conclude
i s a c t u a l l y a s o l u t i o n of t h e BVP (1.5.1) s a t i s f y i n g ( t , x ( t ) , x ' ( t ) ) E R, t E J. Hence t h e proof i s
that this
x(t)
complete.
38
1.6. LYAPUNOV-LIKE FUNCTIONS
1.6.
LYAPUNOV-LIKE FUNCTIONS We wish t o employ, i n t h i s section, Wapunov-like functions
and the theory of d i f f e r e n t i a l i n e q u a l i t i e s t o e s t a b l i s h existence i n t h e large f o r t h e BVP (1.5.1).
+
We define t h e generalized derivative
x" = f ( t , x , x t )
the d i f f e r e n t i a l equation Dt,( t
J
X, X
V
Let
C[JxRxR,R].
E
D Vf(tJxJx') relative t o
by
')
- V(t,x,x')].
lim sup 1 [V(t + h , x + h x ' , x ' + h f ( t , x , x ' ) ) h+O+ h We s h a l l often use s e v e r a l f'unctions ViJ
i = 1,2,.
..,n,
which
we c a l l I(fapunov-like f'unctions and f o r n o t a t i o n a l consistency we write Vi
of
+
D V. ( t , x , x t )
t o denote t h e generalized derivative
If
with respect t o t h e d i f f e r e n t i a l equation
(1.6.1)
XI1 =
THEOREM 1.6.1.
(i) F(t,x,x') the t r i p l e (ii)
Assume t h a t
a , p c C(l)[J,R]
such t h a t
i s t h e modified f'unction of
a,p,c,
a(t)
-< p ( t )
f(t,x,x')
on
J
and
relative t o
as given i n t h e Definition 1.3.1;
t h e r e e x i s t two Wapunov functions
wi
x [x: x ,< a ( t ) ] xR, D2
= J
i = 1 J 2 J . where
B(t)]xR,
f(t,X,X').
D1
= J
E
C[D~,R],
x [x: x >
W ( t , x , x ' ) = 0 i f x = a ( t ) , Wl(t,x,xl)>O 1 x < a ( t ) , W2(t,x,xt) = 0 i f x = B(t), W2(t,x,x1) > O i f
if
such t h a t
x > B(t); (iii)
for
i = 1,2, g
locally Lipschitzian i n
+
D WP(t,x,xt)
+
D W2F(t,x,xt)
i
E
+
C[JxR , R ] , Wi(t,x,xl)
is
( x , x t ) and
_> gl(t,Wl(t,x,xl)) g2(t,W2(t,x,x1))
39
i n t h e i n t e r i o r of
D1j
i n t h e i n t e r i o r of
D2;
1.
to
E
METHODS INVOLVING DIFFERENTIAL INEQUALITIES
( i v ) the only solution of J , i s r ( t ) p 0 on J .
5
Then, if .(a) (1.6.2)
c
5
has a solution x
d
5
r ( t o ) = 0,
the BVP
B(b),
x ( a ) = c,
C(2)[J,R]
E
5
B(a), a ( b )
x" = F ( t , x , x ' ) ,
r ' = gi(t,r),
x(b) = d,
satisfying
a(t)
-< x ( t ) 5 p ( t )
on J . Proof: x
E
By Corollary 1.1.1, the BVP (1.6.2) has a solution
C(2)[J,R].
on J .
It s u f f i c e s t o show t h a t
We w i l l only prove t h a t
proof f o r
x(t)
5
[tl,t21C (a,b)
E
such t h a t
< a ( t ) for t
E
a(t)
5 x(t)
-
< x(t) < @(t) on J since the
i s e s s e n t i a l l y the same.
< a ( t ) f o r some t
x(t) x(t)
p(t)
a(t)
(a,b).
Then t h e r e e x i s t s an i n t e r v a l
x ( t l ) = a(t,),
(tl,t2).
Assume t h a t
x(t2) = a ( t 2 ) ,
and
We thus have by (ii)
From ( i i i ) and the theory of d i f f e r e n t i a l i n e q u a l i t i e s , we obtain (1.6.4) where
Wl(t,x(t),x'(t)) r(t,t2,ro)
r ( t2 ) = r 0 clear that
5
r(t,t2,ro),
a
5
t
i s the l e f t maximal solution of
5 t2, r ' = gl(t,r),
~y ( i v ) and (1.6.3), it i s 1( t2, x ( t 2 ) , x t ( t 2 ) ) . we r ( t , t 2 , 0 ) 1 0 . However, f o r any t E (tl,t2),
= W
obtain, because of ( i i ) and (1.6.4), the contradiction 0
< W1(t,x(t),x'(t)) 5
0.
The proof i s therefore complete. We notice t h a t t h i s theorem generalizes Theorem 1 . 3 . 1 . In case
a(t), p(t)
respectively, on J,
a r e lower and upper solutions of (1.6.2),
it is enough t o choose W l ( t , x , x r ) = a ( t ) - x 40
1.6. LYAPUNOV-LIKE FUNCTIONS
It i s easy t o check that
and W2(t,x,x') = x - p(t).
Wl
s a t i s f i e s a l l the assumptions of Theorem 1.6.1 w i t h g1 = 0 . The only condition t h a t requires a l i t t l e explanation i s ( i i i ) , + For this, namely D WD(t,x,x') 2 0 i n the interior o f D
1' does not a t t a i n a it is sufficient t o prove that Wl(t,x,x') localmaxhum i n the interior of Arguing as i n the proof D1. of Theorem 1.3.1, we see that it i s necessary t h a t a ( t l ) = x ( t ) 1 a t some tl E (a,b) i n order for W1 t o a t t a i n a local maxjmum.
However, for t = t we obtain DWb(tl,x(tl), x ' ( t l ) ) > 0 as 1' i n the proof o f Theorem 1.3.1 which i s impossible a t a local maximum of W1. A similar reasoning holds for W2 and thus the conditions of Theorem 1.6.1 are verified. The next theorem offers a general s e t of conditions t o ensure that / x ' ( t ) I is bounded.
-
Assume that a,p E C(l)[J,R] and a ( t ) < p(t) on J . Define the s e t s El = J x [x: a ( t ) 5 x 5 p ( t ) ] x [x': X ' ,> 01 and E2 = J X [x: a ( t ) ,< x @ ( t ) ]X [x'; X I 5 01.
THEOREM 1.6.2.
Suppose that there exist Iyapunov f b c t i o n s Vi, i = 1,2,3,4, that are locally Lipschitzian i n (x,xl) such that ( i ) Vi E CIE1,R] and Vi(t,x,x') + m as uniformly on J x [x: a ( t ) < x 5 B(t)], i = 1,2; and ( i i ) D+Vlf(t,x,xl) 5 gl(t,Vl(t,x,x'))
-
XI
+m
-+
D V2f(t,x,x') 2 g2(t,V2(t,x,x')) on El; ( i i i ) Vi c C[E2,R] and Vi(t,x,x') + m as x' +-uniformly on J X [x: a ( t ) x 5 B(t)], i = 3,4; + (iv) on E2, D V3f(t,x,xt) -c g3 (t,V3(t,x,x')) and -i.
D V4f(t,X,X-) ,> gq(t,Vq(t,x,x')); (v) Vi(t,x,x') 5 Jri(lxII), i = 1,2,3,4, for r > 0 are continuous f b c t i o n s . Suppose f i r t h e r that
41
where
Jli(r)>O
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(Vi)
gi
C[JXR,R], i = 1’2’3’4
f
and f o r
to f J, ro
E
R,
a l l solutions of
e x i s t on rt = g i ( t J r ) , r ( t o ) = roJ i = 1 , 3 [ t O , b l J and a l l solutions of rt = g i ( t J r ) ’ r ( t ) = r
i = 2,4
e x i s t on
Then there e x i s t s an N with
a(t)
Define f o r
>0
-< x ( t ) -< @ ( t )
t
0
[aJto].
0’
such t h a t every solution of
on
J
satisfies
Ixt(t)l
-<
N
(1.6.1) on
J.
E J
and L.1 =
max
to E J
lri(tJtoJqi(A))
IJ
i =
2’4,
where ri(tJtOJjri(h)), i = 1’3 (i = 2’4) i s the r i g h t ( l e f t ) maximal solution of rt = g i ( t J r ) ’ r ( t o ) = qi(A). Then cond i t i o n ( v i ) guarantees t h a t t h e L.’s a r e f i n i t e . By ( i ) and ( i i i ) , there e x i s t
(1.6.5)
Ni
>0
1
i = 1,2
3 4 such t h a t
> Lij
i = 1’2’
v.1(tjxj-Ni) > Lij
i = 3’4.
Vi(tjXjNi)
and
kt N >maX[Nijh]y i = 1J2j3y4. We Claim t h a t IX’(t)l 5 N on J where x ( t ) i s any solution of (1.6.1) with a ( t ) 5 x(t)
5
@ ( t ) on J .
There e x i s t s a
to E (a,b)
42
such t h a t
x(b)
- x ( a ) = x ’ (tO)(b-a)
1.6. LYAPUNOV-LIKE FUNCTIONS
and therefore it follows t h a t Ix' ( t o ) I 5 h < N. There are four cases t o be considered depending upon whether there e x i s t s
t2 such t h a t x ' ( t 2 ) = N or x ' ( t 2 ) = -N and whether t2 > to o r t2 < to. Assume, f o r example, x ' ( t 2 ) = N and a
t 2 > to. Then there e x i s t s a tl with that
xl(t,) = A
h < xl(t)
and
t
< N for t
(v) we obtain Vl(tl>x(tl)Jxl(tl)) arrive a t the estimate
5
< t 1 < t2 such
0 -
E
(t,,t,).
From
$1(~) and from ( i i ) we
using the theory of d i f f e r e n t i a l inequalities. Relations (1.6.5) and (1.6.6) lead us t o the contradiction L1 < v1(t2JX(t2)JX' ( t 2 ) )
because of the definitions of
5
L1
L1 and N.
On the basis of the preceding argument, we can arrive a t a similar contradiction i n the remaining three cases. the d e t a i l s .
We omit
The proof i s therefore complete.
The r e s u l t we have j u s t proved offers a general s e t of sufficient conditions which imply that
Ixl ( t ) I
i s bounded
and thus relaxes the more stringent Nagumols condition assumed i n Theorem 1.4.1.
In f a c t , the intent of the following
exercise i s t o c l a r i f y t h i s advantage f u r t h e r . EXERCISE 1.6.1.
Let
hi
E
C[R+,(O,m)], f
E
C[JxRxR,R],
and
Suppose t h a t
t
E
J
and
aJf3E C[J,R]
a(t)
5x5
with w ( t ) < B(t)
@ ( t ) J assume that
43
on J.
For
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
-
-h2(xf) c f ( t , x , x ' ) -h (-XI)
3
5 f ( t , x , x ' ) 5 hq(-xl)
Show t h a t for any solution x a ( t ) 5 x ( t ) 5 B(t) on J, only on cu,p,hi such t h a t Hint: -
hl(xl)
E
C(2)[J,R]
if
x'
if
x'
-> 0, -< 0 .
of (1.6.1) w i t h
there e x i s t s an N > 0 I x l ( t ) l L N on J .
depending
Under the assumptions show one can construct four
Qfapunov functions satisfying the conditions of Theorem 1.6.2. For example s e t V1 = exp[t - x + ./:' s ds/hl(s)] on El show the assumptions are verified w i t h g l ( t , r ) = r and and V4. similarly construct V2, V
and
3'
we may ccanbine Theorems 1.6.1 and 1.6.2 t o obtain the existence of solutions (1.5.1). "he proof i s similar t o Theorem1.5.1. Wemerely statethefollawingtheoremwhichisagener~izationofTheorem1.5.1.
THEOREM 1.6.3.
-
a,@ E C(l)[J,R] w i t h a ( t ) c B(t) Assume t h a t there e x i s t two l$fapunov f'unctions W1, W2 Let
on J . s a t i s Q i n g the hypotheses of Theorem 1.6.1. Suppose further t h a t there exist four Qrapunov functions Vi, i = 1,2,3,4 such t h a t they obey the hypotheses of Theorem 1.6.2. Then f o r any .(a) c c c p(a), u(b) 5 d 5 p(b) t h e BVP (1.5.1) has a solution x E C(*)[J,R] with a ( t ) c x ( t ) C p ( t ) and Ix'(t)l S N on J .
- -
-
-
1.7 EXISTENCE ON INFINITE INTERVALS On the basis of Theorems 1.4.1 and 1.5.1 it i s possible t o obtain the existence of solutions on i n f i n i t e intervals.
THEOREM 1.7.1. Assume t h a t f o r each b > a , f ( t , x , x ' ) s a t i s f i e s Nagumofs condition on [a,b] r e l a t i v e t o the p a i r a,B E C(l)[[a,m),R] with u ( t ) 5 B(t) on [a,-). Suppose 44
1.7. EXISTENCE ON INFINITE INTERVALS
also that a , @ are lower and upper solutions of (1.6.1) on [a,m), respectively. Then f o r any a ( a ) 5 c 5 @(a) the B W (1-7.1)
xtt = f(t,x,x'),
he8 a solution
x
on
E
x(a) = c,
C(2)[[a,m),R]
-
such t h a t a ( t ) c x ( t ) < p(t)
[a,m). Proof: -
By Theorem 1.5.1, it follows that f o r each n 1 1 there i s a solution xn E C(2)[[a,a+n],R] such t h a t xn(a) = c,
xn(a+n) = p ( a + n ) ,
and a ( t ) 5 x n ( t )
5 p ( t ) on [ a , a + n l .
-
Furthermore, there i s an Nn > 0 such t h a t I x t ( t ) l < Nn on [ a , a + n l f o r any solution satisfying a ( t ) 5 x ( t ) 5 p ( t ) on > 1, x,(t) is a solution on [a,a+n]. Thus f o r any fixed n [a,a+nI verifying a ( t ) 5 x,(t) 5 p ( t ) and Ix;(t)l 5 N~ on [ a , a + n ] f o r a l l m > n. Consequently, f o r m i n the sequences {xm(t)], {x;(t)] are both uniformly bounded and equicontinuous on [a, a + n ] Then, employing the standard diagonalization arguments, we obtain a subsequence which converges uniformly on a l l compact subintervals of [ a , ~ ) t o a solution x ( t ) . The desired solution of (1.7.1) is precisely this x ( t ) . Hence the proof is complete.
.
Essentially a similar proof may be given t o the following, s a t i s f i e s Nagumo's condition on [-a,a] f o r each a > 0 w i t h respect t o the pair @,p E C(l)[R,RI w i t h a ( t ) 5 p ( t ) on R. Suppose also t h a t (Y,B are lower and upper solutions of (1.6.1) on R . Then there i s a solution of (1.6.1) on R such t h a t a ( % ) 5 x ( t ) 5 B(t) on R. !MEOREM 1.7.2.
Assume t h a t
f(t,x,xt)
We shall merely s t a t e below a r e s u l t analogous t o Theorem 1.7.1 i n terms of Qfapunov-like functions.
45
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
THEOREM
on
[a,m)
1.7.3. L e t a,@
and l e t
f
f
c C(')[[a,-),R]
C[[a,-)xRxR,R].
with a ( t ) 5 p ( t ) Assume there e x i s t
two Wapunov functions Wl(t,x,xl), W2(t,x,x1) obeying the hypotheses of Theorem 1.6.1 where we now replace
[a, b 1 with
[a,m).
Assume also t h a t there e x i s t two Iiyapunov functions V2, V4 s a t i s w i n g the corresponding properties of !Theorem 1.6.2 w i t h [a,bl replaced by [a,-). Wre precisely suppose that ( i ) V2(t,x,x') subsets of
-
[a,m) x [x: a ( t )
+
(ii) D V2f(t,x,xl)
a ( t ) < x 5 B ( t ) and x' ( i i i ) V4(t,x,xt) 4 subsets of
as
-t-
uniformly on compact
+Q)
5 x 5 @(t)];
3 g2(t,v2(t,x,x1)) for t
2
E
[a,-),
0;
m
[arm) x [x: a ( t )
+
XI
as
x'
5x5
uniformly on compact
--f-c=~
p(t)l;
( i v ) D V4f(t>x,x1)2 g4(t,v4(t9x,xt)) f o r t E [a,m), a(t) 5 x B(t) and x ' 5 0; (v) there e x i s t qi, i = 2,4 where qi e C([a,m) xR,R] and Qi(t,u) i s increasing i n t for each u such t h a t f o r each
2 a, Vi(t,x,x') e qi(T, Ix' I ) 5x5 T
for
t
E
[a,T]
and
(vi) gi E C[[a,-) XR,R], i = 2,4 such t h a t f o r each t 0 e [a,-) and ro 2 0 a l l solutions of r' = gi(t,r), r ( t o ) = ro e x i s t on [a,tol. !Then for any
c
satisf'ying
a(.)
6 c 5 B(a) there e x i s t s
-
a solution of (1.7.1) such that a ( t ) c x ( t )
5 B(t)
on
[a,-).
Clearly a theorem analogous t o Theorem 1.7.2 may be formulated, which we leave as an exercise.
1.8 SUPER- AND SUBFUNCTIONS Here we define subf'unctions and superfunctions r e l a t i v e t o the solutions of XI' = f ( t , x , x ' ) and discuss necessary and 46
1.8. SUPER- AND SUBFUNCTIONS
sufficient conditions I o r such functions t o be, respectively, lower and upper solutions.
To avoid repetition, most of the
results w i l l be stated only i n terms of lower solutions and When it becomes necessary l a t e r t o r e f e r t o a
subfunctions.
result concerning superfunctions and upper solutions, we s h a l l simply r e f e r t o the subfunction statement of the r e s u l t .
DEFINITION 1.8.1.
A function
function r e l a t i v e t o solutions of val J
[tl,t2]
i f f o r any
C
Cp(t)
is said t o be a
x" = f ( t , x , x ' )
2-
on an inter-
and f o r any solution
J
.)> cp(t.), i = 1,2 implies x ( t ) 2 cp(t) C(2) [[tl,t21,R] , x (t 1 1 on [t t 1. A superfunction may be defined similarly by re1 ' 2 versing the respective inequalities.
x
E
We have immediately the following r e s u l t . THEOREN
1.8.1.
Assume t h a t
cp c C[J,R] I I C(l)[J0,R]
is a
subfunction on J w i t h respect t o the solution of
(1.8.1)
XI1
where f E C[J X R xR,R]. (1.8.1) on J . Proof:
Let
Then
to 6 Jo
sufficiently small.
= f(t,X,X') Cp
and h > 0, k > 0, h
-
E
C(2)[[t0-k,t0+h],R].
subfunction, we readily obtain Cp'
-
be
x ( t O+ h ) = q ( t o + h ) ,
x ( t O k) = g ( t 0 k),
has a solution x
+k >0
Then by Theorem 1.1.2 t h e BVP
-
X" = f(t,X,X'),
i s a lower solution of
-
(to+ h ) Cp' ( t o k) h+k
->
X' (to + h )
X'
cp
is a
-
(to k)
h+k =
for some t o- k < s < to + h.
-
Since
x'l(s) = f ( s , x ( s ) , x ' ( s ) )
!the continuity of 47
f
together
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
with "heorem 1.1.2, implies that f ( s , x ( s ) , x t ( s ) ) --3 f ( t O , x ( t O ) , x t ( t O ) )
as h + k
+ 0.
Thus
and, i n particular,
from which it follows t h a t (1.8.1) on J.
i s a lower solution r e l a t i v e t o
cp
Assuming only the continuity of f , it w i l l not be possible i n general t o show t h a t a lower function is a subf'unction. Since a solution i s a lower solution, if lower solutions are subf'unctions, then solutions are subf'unctions From the definition of subfunctions it would then follow t h a t , if a BVP on an i n t e r v a l has a solution, thet solution is unique. Hence stronger assmptions other than continuity of f are required t o conclude that a lower solution i s a subfunction. A s e t of sufficient conditions i s given i n the next theorem.
.
THEOREM 1.8.2.
Assume t h a t
( i ) f E C[JxRxR,R] and i n x f o r each (t,g); ( i i ) either f satisfies a i n y on each compact subset of i n i t i a l value problems f o r (1.8.1) Then a lower solution on J t o solutions of (1.8.1).
f(t,x,y)
i s nondecreasing
one-sided Lipschitz condition J x R x R o r solutions of are unique.
is a subfunction on J r e l a t i v e
The proof i s a direct consequence of Theorems 1.2.2 and 48
1.8. SUPER- AND SUBFUNCTIONS
1.2.3.
I n t h e preceding r e s u l t conditions a r e imposed on f ( t , x , y ) which a r e s u f f i c i e n t t o imply t h a t lower solutions a r e subf'unctions and, therefore, t h a t solutions of BVP's, when they
I n t h e next r e s u l t we take t h e uniqueness
exist, a r e unique.
of BVP's as one of t h e hypotheses. THEOREM 1.8.3. Assume t h a t each i n i t i a l value problem f o r (1.8.1) has a s o l u t i o n which extends throughout [a,b]. Suppose
further t h a t solutions of boundary value problems X"
= f(t,X,X'),
x ( t l ) = xl,
~ ( 6 =~x2, )
[tl,t2] C J,
when they e x i s t , a r e unique.
Then, i f
i s a lower solution on
i s a subfunction on I.
Proof:
Assume t h a t
there i s an i n t e r v a l such t h a t (c,d).
CY E
is a
x,(c)
C(l)[[c,d],R],
>0
cy
[c,d]
and
i s not a subfunction on C
I
and solution
F(t,x,x')
on
C(l)[I,R]
cy E
I.
Then
xo E C(2)[[c,d],R]
and x,(t) [c,d] X R x R
< a(t)
on
by
i s continuous on [c,d] X R X R and it follows from Theorem 1.1.2 t h a t there
F(t,x,x') 6
cy
= cy(c), xo(d) = cy(d),
We now define
Since
I,
IC J
such t h a t
[tl,t2]
C
[c,d]
and
t2-tl 5
6
implies the BVP X"
= F(t,x,x'),
has a solution
x
x(t,)
= Q(tl>,
E C(2)[[tl,t2],R].
x ( t 2 > = a(t2),
Using t h e f a c t t h a t
a ( t ) 5 x ( t ) on with t h e same type of argument as used i n t h e proof
i s a lower solution, we can show t h a t [tl,t2]
Ly
of Theorem
1.3.1.
As a r e s u l t , f o r 49
[t1,t2] C [c,d]
and
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
t2- tl
5 XI1
t h e BVP
6, =
f(t,X,X'),
has a s o l u t i o n x
x(tl) = a(tl), C(2)[[t,,t,],R]
E
x ( t 2 ) = a(t,),
with
a(t) < x(t)
on
[tl,t2]. Thus a i s a subfunction " i n t h e small." Clearly d c > 6; f o r otherwise t h e r e would be a s o l u t i o n
-
x(t)
with
[c,d].
x(c) = a ( c ) , x(d) = a(d),
an% x ( t )
-> a ( t )
This s o l u t i o n would be d i s t i n c t from x ( t ) 0
on
contra-
d i e t i n g t h e assumption concerning t h e uniqueness of s o l u t i o n s of BVP's.
Now f o r each p o s i t i v e i n t e g e r
n,
let
P(n)
t h e proposition t h a t t h e r e e x i s t s an i n t e r v a l [cn,dn] with 0 < dn - c < d - c - (n 1)s and a s o l u t i o n n-
-
x n on
E
C(2)[[cn,dn],R]
such t h a t
d i s t i n c t s o l u t i o n with boundary values
X"
C
[c,d]
x (c ) = a ( c n ) , xn(d ) = a ( t ) n n n i s t r u e with [cl,dl] = [ c , d ]
( c , d ). Evidently P(1) n n and x 1( t ) = x o ( t ) . Assume P(k) i s t r u e . Then otherwise we would o b t a i n a c o n t r a d i c t i o n o f x , ( t )
z,(t)
be
a(ck)
4,- Ck >
6,
being t h e
and a ( % ) .
Let
be t h e s o l u t i o n of t h e BVP =
f(t,X,X'),
x(c,)
=
X ( Ck + 6) = a ( c k + 6 ) .
CU(C,),
Since each i n i t i a l value problem has a s o l u t i o n extending throughout t h a t z,(t)
J,
i s not t r u e .
t h e r e i s a s o l u t i o n z 2 ( t ) on [ck,%I such z,(t) on [ c k , c k + 6 ] . Suppose t h a t P ( k + l ) Then we must have
Also we must have
z2(%)
z2(t)
> "(4,). If
2 a ( t ) on [ c k + 6 , 4 , ] . 4, - ck - 6 5 6, t h e
BVP
E C ( 2 ) [ [ ~ k + 6 , 4 , ] , R ] with a ( t ) < z ( t ) . z3 - 3 Then, s i n c e z ( ) < z2(4,) and s o l u t i o n s of BVPls a r e unique 3 % t E cCk+6,%1. a(t) 5 z 3 w 5 z , ~ ,
has a s o l u t i o n
50
1.8 SUPER- AND SUBFUNCTIONS
This implies z (Ck+6)
3
= z2(Ck+6)
Consequently,
u(t),
and
Z'(C
3
k
+ S ) = Z'(C +6).
2
k
defined by
i s of c l a s s C(2)[[ck,%],R]
and i s a s o l u t i o n on
[ck,%]
However, u ( t ) # \ ( t ) with u ( ck ) = %(ck), u($) = \(\). on rek,%] and t h i s c o n t r a d i c t s t h e uniqueness of s o l u t i o n s of BVP's.
We conclude t h a t
% - ck >
This being t h e case,
6.
the BVP X"
= f(t,X,x'),
has a s o l u t i o n
x(ck+ S ) = a(ck+ S),
z4
E
X(C +26) k
C(2)[[c + 6,ck+26],R]
k
+ 6) 4 k
= z;(ck+ 6).
v(t) =
!Phis s o l u t i o n P(k+1)
on
v(t)
z4(ck + 6 ) = z2(ck + 6) Hence
z,(t)
on
[ck,ck+61,
z4(t)
on
(ck+ 6,ck+281,
has an extension
z (t)
5
a(ck+28),
with
This again assures us t h a t z'(c
=
and
on J .
Since
i s assumed t o be f a l s e , we must have
[ck+2S,%]
and
z,(%)
> a(\).
z5(t) 2 a ( t ) I n t h i s way t h e fore-
going arguments can be repeated and t h e assumption t h a t 51
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
P(k+l)
i s f a l s e permits us t o work our way across the
interval
[ckJ%] by subintervals of length
6 u n t i l we
> a ( t > on a(%) = \(%).
obtain a solution w c c(*) [ [ c k J % l , ~ 1 with w ( t >
[C,J%]J w(ck) = a ( ck = s ( c k ) and w(%) = xJt) on [c,J%] which again i s a contradiction Then w(t)
+
t o uniqueness of solutions of BVP’s. We therefore conclude t h a t , i f i s true.
P(k+l)
leads t o the contradiction 0 Hence a
P(k)
i s true, then
i s true f o r a l l n
Thus P(n)
i s a subfunction on
2
1, which
< d - c - (n - 1)s f o r a l l n > I
1.
and the proof i s complete.
Show t h a t i n Theorem 1.8.3 the hypothesis
EXERCISE 1.8.1.
t h a t each i n i t i a l value problem f o r (1.8.1) has a solution which extends throughout
can be replaced by Na@;umo’s condition.
J
1.9 PROPERTIES OF SUBFUNCTIONS Before proceeding t o outline the Perron’s method, it w i l l be necessary t o make a more detailed examination of the propert i e s of subt h i s section.
and superf’unctions.
This w i l l be undertaken i n
Again most r e s u l t s w i l l be stated i n terms of
subf’unctions and the obvious analogs f o r superf’unctions w i l l be omitted. IMEOREM I C J,
then
1.9.1. cp
If
cp
has r i g h t and l e f t limits i n the extended
r e a l s a t each point i n
Io and has appropriate one-sided
limits a t the end points of
Let
i s a subfunction on an i n t e r v a l
I.
Proof: Clearly it i s sufficient t o consider one case. to E Io and suppose t h a t cp(t-) 0 = limt+t_, cp(t) does
not e x i s t i n the extended r e a l s . numbers a,@ such t h a t
52
Then there e x i s t r e a l
1.9. PROPERTIES OF SUBFUNCTIONS
cp(t) < a < p < l i m sup cp(t)
lim inf t4t; It,},
Let
{s,]
t4;
be s t r i c t l y increasing sequences i n
I
t n < sn < tn+l f o r n 2 1, l i m t n = lim sn = to,
that
iim cp(tn) Taking
iim sup cp(t) t-tt;
=
t ( B -a),
E =
6> 0
is a
x" = f(t,X,X'),
has a solution x $(a+B)I
it follows from Theorem 1.1.2 t h a t there
<
[t,,t2]
C
[tl,tO]
with
the BVP
t2 tl
(1.9.1)
lim cp(sn) = lim inf cp(t). t+t;
and
such t h a t f o r any
- -< 6
such
E
E
on
x ( t 1) = x ( t 2 ) = $ ( a + p ) ,
C ( ~ ) [ [ ~ , , ~ ~ I satisfying ,R]
[tl,t2].
Let
Ix(t)
-
n be a fixed positive integer
-
sufficiently large so t h a t
sn+l sn -< 6, rp(sn) < a, q ~ ( s ~ <+a~,) and cp(tn+l) > p. This implies t h a t there i s a solution of (1.9.1) with [ t , t 1 = [S , S 1 and 1 2 n n +l Since ]. cp i s a subfunction lx(t) -$(a + B) I < E on [ S ~ , S ~ + ~ on 1 and cp(sn) < X(Sn)' cp(sn+l) < X(sn+l), it must be the case t h a t
cp(tn+l)
5 x(tn+l).
X(tn+l> <
3. + B )
However, + E
< B < cp(t,+,>,
a contradiction from which we conclude extended r e a l s .
cp(t',)
e x i s t s i n the
The proof i s complete.
COROLIARY 1.9.1. If cp i s a bounded subfunction on IcJ, Cp has a t most a countable number of discontinuities on A t each to E I0 cP(tO) 5 max[T(ti),Cp(t,)l.
then I.
Proof:
The f i r s t assertion i s a c l a s s i c a l r e s u l t t h a t
follows from the f a c t t h a t
+
cp(to) 53
and
cp(ti)
e x i s t a t each
to
E
0
I
.
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
By Theorem 1.1.2 and t h e f a c t t h a t
i s a sub-
cp
function, t h e second a s s e r t i o n r e a d i l y follows. We consider next t h e d i f f e r e n t i a b i l i t y of subfunctions For a f'unction
with a f i n i t e r i g h t l i m i t
h(t)
h(t:)
.
at
to, we define
-
+
Dh(tO) = lim
+
h ( t ) h(t;) t-t 0
t+tO provided t h e l i m i t e x i s t s .
THEOREM 1 . 9 . 2 . then
to
E
Dcp(t:), 0
I
.
cp
Proof:
i s a bounded subfunction on
I c J,
e x i s t i n t h e extended r e a l s f o r each
I. A s i n Theorem l . g . l w e s h a l l consider only one
Suppose t h a t
lim i n f
+
t-tt
to
t
E
- to
Io and t h a t
< l i m sup t-tt
0
Let
Dh(ti).
The appropriate one-sided derivatives e x i s t a t f i n i t e
end points of
case.
If
Dcp(ti)
Analogously we define
+
-
cp(t> cp(to>
t
- to
0
m be a r e a l number s t r i c t l y between these two limits.
Then t h e i n i t i a l value problem x" = f ( t , x , x ' ) , has a solution
+
x(t,) = cp(tO), x ' ( t o ) = m
x E C ( ~ ) [ [ ~ ~ , ~ ~ f+o r~ some I , R I6
54
>
0.
AS
1.9. PROPERTIES OF SUBFUNCTIONS
there e x i s t
t 1, t2, t3 such t h a t
It follows t h a t
x(t2).
Since
cp
to < t < t2 < t < t 3
1
0
cp(t,) < x(t,), cp(t,) < x ( t 3 ) , and cp(t2) i s a subf’unction t h i s i s a contradiction
+
6,
>
and therefore we are done.
The c l a s s i c a l r e s u l t s i n the theory of r e a l variables give as a consequence the following corollary.
COROLLARY 1 . 9 . 2 . If cp i s a bounded subfunction on I c J, then cp has a f i n i t e derivative almost everywhere on I. LEMMA 1.9.1. If
cp
i s a subf’unction on
I
bounded above on each compact subinterval of
I,
i s a subfunction on
I.
y(t) = l i m
cp(s)
Proof:
Let
[tlyt21
C
J
and i s
then
I a n d l e t x ( t ) b e a s o l u t i o n o f (1.8.1)
with y(t,) 5 x(t,) and y ( t 2 ) 5 x ( t 2 ) . Then cp(ti) 5 y ( t i ) 5 x(ti), i = 1,2, and, because cp(t) i s a subf’unction,
5 x ( t ) on [t,,t,]. We therefore have f o r each tl < t < t2, y ( t ) = l i m sups+t cp(s) 5 x ( t ) . Hence y ( t ) 5
p(t) x(t)
on
[tl,t2]
and y ( t )
i s a s u b f b c t i o n on
I.
We now proceed t o discuss some l a t t i c e properties of subf’unctions.
THEOREM 1.9.3. Assume t h a t the s e t of subfunctions 55
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
on the i n t e r v a l I C J i s bounded above a t each I. Then cp,(t) = supCYEA cpCY ( t ) i s a subf’unction on
{cpCY: CY E A]
point of
I. I and x E C(2)[[tl,t2],R] Suppose t h a t [tl,t2] i s a solution w i t h cp,(t) < x ( t ) a t t = tl,t2. By the definition of q0, we then have cpCY(t)5 x ( t ) a t t = t t 1’ 2 f o r each CY E A . Since each cpCY i s a subfunction on I, it follows t h a t cpCY(t)5 x ( t ) on [tl,t2] f o r each CY E A . This implies cpo(t) < x ( t ) on [tl,t,] and cpo(t) i s a subfunction on I.
Proof:
IIHEOREM 1.9.4.
I&
cp be a subfunction on an i n t e r v a l
I1 w i t h I1= i1n I. Suppose further that cp,(t) 5 cp(t) a t f i n i t e end points of I1 which are contained i n I. Then cp2 defined by IC J
and cpl
a subfunction on
cp,(t> =
{
~“P1(t)>cp(t)l>
I1J
t
cp(t>,
E
I - 11,
i s a subf’unction on I. Proof: By h y p t h e s i s cp,(t) = cp(t) i s a s u b m c t i o n on I I1 and, by Theorem 1.9.3, cp2(t) i s a subfunction on I1. Consequently, we need only t o show t h a t we have the correct behavior on intervals [tl,t,] C I which are not contained i n e i t h e r I1 o r I-I1. Again l e t us consider j u s t one case since the arguments are similar. Assume tl E 11, t2 E I 11,
-
-
56
1.9. PROPERTIES OF SUBFUNCTIONS
i s a subf'unction on
In particular,
-
cp(t) < x ( t )
we obtain
I,
5
cp2(t) = cp(t)
x(t)
on
on
(t3,t2].
[t,,t,].
Also
'~l(t35 ) c ~ ( t 3 )_< x(t3) and cpl(t1) 5 ~ 2 ( t l 5 > x ( t l > , hence cp,(t) 5 x ( t ) on [ t t I because cpl(t) i s a subfunction 1'
3
cp2(t) = max[cp(t), cpl(t)] < x(t)
We thus i n f e r t h a t
on
I1.
on
[tl,t3].
Putting these things together we see t h a t
cp2(t) 5 x ( t ) on [tl,t2]. The other p o s s i b i l i t i e s a r e dealt with i n a similar way and we conclude t h a t cp2(t) i s a subfunction on
I.
MEOREM
(i) x
f
for each
1.9.5. E
Suppose t h a t
C[J xR x R , R ] , f ( t , x , x I )
i s nondecreasing i n
(t,xl)
and ( i i ) t h a t solutions of i n i t i a l value problems are unique.
Then, i f
$(t)
i s an upper solution on
cp(t> i s a bounded subfunction on and cp(t;> 5 $(t,>, we have
Proof:
Suppose t h a t
[tlJt2]
[tlJt2]
cp(t1.5 $ ( t )
cp(t) > $ ( t )
C
J
and
with cp(t1) on
5 $(tl>
(tl't2).
a t some points of
(tlJt2). Observe t h a t it i s enough t o consider the case where cp i s upper semicontinuous on (tl,t2). To see t h i s , l e t
cp(t) = l i m sup cp(s) on (t,,t,). Then by Lermna 1.9.1, s+t -cp(t) i s a subfunction on (t t ). By Corollary 1.9.1, 1' 2 - + + cp(tl>= cp(t,> 5 $(tl> and F(t; cp(t;> 5 J'(t2). mreover, rp(t) > @ ( t ) a t some points i n
(t t ).
at some points i n
rp(t;)
5
(tl,t2).
a t some points i n
$(t,)
implies
cp(t)
[to
- 6, to+ 61
6
>0
(tlJt2),
and 0
57
This being the case,
(tl,t2)
- $(t)
which i s assumed on a compact s e t Then there e x i s t s a
implies T ( t ) > q ( t )
As a r e s u l t we may assume cp(t)
1' 2 i s upper semicontinuous on
cp(t>> + ( t )
(tlJt2)
<
and
cp(tf)
5
$(tl>,
has a positive maximum M E C (tl,t2).
E
>0
&
< $(to+ E ) +
Let
to= lub E.
such t h a t M - 9(t0 + 6 ) ~
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and such t h a t the BVP
has a solution x
C(2) [[to
E
Since
by Theorem 1.1.2.
- 6,
$(t)
+
to+ 6],R]. This i s assured M i s an upper solution, we
+
x(t) < - $(t)
obtain by Theorem 1.2.3,
However ,
V(t0
- 6) 5 $(to - 6)
cp(t
+ 6) < +(to + 6) +
+
on
M
( t o - 6, to+ 6).
-
M = X(tO 6)
and
which yields
0
5 x(to),
cp(to)
subfunction on cp(to) = + ( t o )
+
M-
E =
X(tO + S ) ,
because of the f a c t
t0 We therefore conclude t h a t
(tlJt2). M.
This contradicts
E
cp(t) i s a E
-
q ( t ) < $(t)
(tlJt2).
On
and
EXERCISE 1.9.1. Prove t h a t the assertion of Theorem
1.9.5 remains valid
i f i n place of the assumption "that
solutions of i n i t i a l value problems are unique" we suppose that to
f (t,x,x')
XI
s a t i s f i e s a Lipschitz condition with respect
on each compact subset o f
J X R xR.
We s h a l l now discuss properties of bounded functions t h a t are subfunctions and superfunctions simultaneously.
We w i l l
need a well-known r e s u l t concerning solutions of i n i t i a l value problems which we merely s t a t e . LEMMA 1.9.2.
6
> 0, % >
0,
If
and
%>0
i n i t i a l value problem i s defined on
I
6
=
(tOJXOJxi)E J X R X R ,
such t h a t every solution of the
x" = f ( t , x , x ' ) ,
[to
- 6,
there exist
to+ 61 58
n
J.
x ( t o ) = xo, x f ( t o ) = xd Moreover,
1.9. PROPERTIES OF SUBFUNCTIONS
THEOREM 1.9.6.
Assume t h a t
f(t,x,xt)
i s such t h a t
C(2)
solutions of boundary value problems, when they exist, are unique. I
and t h a t
J
C
Suppose t h a t z(t)
i s bounded on each compact subset
z(t)
i s simultaneously a subfunction and a
superfunction on
I. Then z ( t ) i s a solution of x " = f ( t , x , x t ) on an open subset of I the complement of which has measure zero.
Furthermore, i f
z(t)
a t which
z(t)
to E Io i s a p i n t of continuity of does not have a f i n i t e derivative, then
either
+
Dz(tO) = Dz(t-) = + m 0
+
+
If z ( t o ) > z(t,)J D z ( t 0 )
+
DZ(tO) = Dz(t')
=
0
Proof:
-
+
or =
D z ( t ) = Dz(t-) = 0
Dz(t-) 0
=+m
0
and
z(ti)
-
W.
< z(t,),
W.
By Corollary 1.9.2,
z(t)
has a f i n i t e derivative
to E Io i s a point a t which z ( t ) has a f i n i t e derivative, there i s a 6 > 0 such t h a t almost everywhere on
[ t o -6, t 0 + 6 1 and
I.
I J Iz(t)l
If
5
Iz(to)l
1 On
[ t o - 6, t 0 + 6 1 ,
It then follows from Theorem 1.1.2 t h a t there i s a 0
<
45
6, X"
61
= f(t,x,x'),
has a solution x(t)
a solution of
0,
x
E
C(2)[[to
~ ( t , + 6 ~= ) ~ ( t ~ + 6 ~ ) ,
- 61,t0+61]JR].
Since
z(t)
a t the same time a subf'unction and a superfunction on z(t)
>
such t h a t the BVP
on
[to
- 61Jt0 + S1].
xtt = f ( t , x , x t ) 59
We conclude t h a t
on an open subset of
is
I, z(t) I
the
is
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
complement of which has measure zero.
to f 'I be a point of continuity of z ( t ) at which ~ ( t )does not have a f i n i t e derivative. By Theorem + 1.9.2 Dz(tO) and Dz(ti) both exist i n extended r e a l s . If Next l e t
both are f i n i t e , then by the same argument as used above there
i s an i n t e r v a l around to i n which This contradicts the assumption t h a t
Dz(t0)
Dz(t:)
=
+m
z(t)
i s infinite.
and Dz(ti)
# + m.
Then there e x i s t numbers
> w(t)
>0
f(t,X,X'),
x(tO
has a solution x1 there i s a
b2
solution on
>0
-
E
- 4)=
C(2)[[to
= f(t,X,X'),
41
W(tO
such that the x(to) =
Z(to),
1.9.2, can be extended t o be a
x,(t)
By Lemma
and such t h a t a l l solutions of
x ( t o ) = Xl(tO)'
[ t O , t O+ 6*1
- 61)y
- 61,tO],R].
such t h a t
[to 61 ,t 0 + the i n i t i a l value problem
e x i s t on
-
4, 0 < 61 5 6,
BVP
XI1
6
on to 6 5 t < to.
= z(to) + N ( t -to)
By Theorem 1.1.2, there i s a
=
does not have a
such t h a t
and N
XI1
z(t)
to. Consequently, a t l e a s t one of To be specific, suppose
f i n i t e derivative a t Dz(t:),
i s a solution.
z(t)
and s a t i s f y
x'(to) =
lx(t)
X 1' ( t
0 ),
- x(to) I 5 M ( t - t o )
[ t 0 , t 0 + 6 2 ] y where M = I x ' ( t ) I + 1. Again applying 1 0 Theorem 1.1.2 we i n f e r t h a t there i s an q, 0 < 7 5 min[fj ,6 1, 1 2 such t h a t f o r 0 < 6 < q the BVP
on
3-
X" = f(t,X,X'),
X(tO
- 63 ) = Xl(tO - 63),
x ( t O+ 6 ) = Xl(tO)
3
60
+
(M+ &)6
3
1.9. PROPERTIES OF SUBFUNCTIONS
has a solution E
> 0.
that
As 0
<
x2
- 63 , t0 + 63 ],R]
f o r some fixed
E C ( 2 ) [[to
4
Dz(ti) = + m, we can assume t h a t i s chosen s o 5 q and xl(tO) + ( M + & ) 6 < z ( t 0 + 6 ). Then
4
3
3
xl(tO + 6 ) < x 2 ( t 0 + 6 )
3
3
< z ( t O +6 ) 3
and
- 9'
Xl(tO
=
X2(t0 - 6+
5
- 4,.
z(tO
The l a s t inequality follows from the f a c t t h a t
- 9)
~ ( t )i s a
- 4).
superfunction and xl(tO) = z ( t o ) , xl(tO < z(tO Since ~ ( t )i s a superfunction, we deduce from the above inequalities t h a t
-< z ( t )
x2(t)
on
[to
- 63 ,t0 + 63 ].
From the
same inequalities and the f a c t t h a t the solutions of BVPIs, when they exist, are unique, we also i n f e r t h a t on
[to - 6 ,t + 6 3
3I.
0
x i ( t o ) = x;(to),
Thus
hence,
xl(t) 5 x 2 ( t ) x (t ) = z ( t o ) = x2(t0) and 1 0 x 2 ( t ) i s a solution of t h e i n i t i a l
value problem with the i n i t i a l conditions x l ( t o ) = x ' ( t ). 1 0
However,
Ix2(to +
4,- X2(t0) I
=
x(t,) = xl(tO),
(M+ €183
which contradicts the f a c t t h a t a l l solutions of t h i s i n i t i a l Ix(t) - xl(tO) I 5 M ( t - t o ) on We are forced t o conclude t h a t 'Dz(t;) = + m.
value problem s a t i s f y
[ t O , t O+ 4 1 . By similar arguments using t h e f a c t t h a t
z(t)
i s also a
subfunction, the other statements regarding the behavior of a t a point of continuity can be established.
z(t)
We consider now the behavior of If
z ( t ) i s bounded on each compact inter+ Furthermore, z ( t o ) # z ( t 0 ) since, by Corollary
and are f i n i t e since Val of
a t p i n t s of
to E Io i s a p i n t of discontinuity of and z ( t i ) both e x i s t then by Theorem 1.9.1, z(t:)
discontinuity. z(t),
z(t)
I.
1.9.1, 61
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
+ > .(ti)
Assume t h a t
is a z(t)
6
z(to)
>0
< w(t)
and an N =
= f(t,x,xf),
has a solution Xl(t0) = z(t:) and
z(t)
x
2
Dz(ti)
6
Then t h e r e
[tO,tO + 61 C I and on to < t 5 to + 6. By
-to)
4,
0
<
45
such t h a t t h e BVP
6,
x(tO+fjl) = w ( t O + 61),.
x(to) = z(ti), 1
# + m.
such t h a t
+ z(to) + N ( t
Theorem 1.1.2 t h e r e i s a XI'
and t h a t
C ( 2 ) [ [ t o , t o + 611,R].
x1 (t0 '61)
z(to),
i s a subfunction,
x,(t)
= w(to+61)
1 z(t)
on
>
z(to+61),
[to,to+61].
Now proceeding as i n t h e previous paragraph and using the f a c t that
z(t)
i s a subfunction, we can obtain a solution of t h e
i n i t i a l value problem XIt = f ( t , X , X ' ) ,
x ( t o ) = Xl(tO),
X'(t0) = x;(to),
t h e graph of which i s not contained i n t h e sector t o t h e l e f t of
to in which such solutions must be.
diction, we conclude t h a t
+ Dz(tO) = +=J.
From t h i s contraThe other assertions
concerning derivatives a t points of discontinuity of are d e a l t with i n a similar w a y .
z(t) The proof of t h e theorem i s
now complete. 1.10
PERRON'S METHOD mploying t h e properties of sub-
and superfunctions and
the existence " i n the small" theorem, we consider the existence
i n the large f o r t h e boundary value problems by Perron's method. DEFIXITION 1.10.1.
A bounded real-valued function
62
1 .lo. PERRON'S METHOD
defined on J
i s said t o be an underfunction with respect t o
the BVP (1.10.1)
x" = f ( t , x , x ' ) ,
where
C[J X R xR,R],
f E
i s a subfunction on J
.(a)
= A,
i n case
v(a)
x(b) = B,
5 A,
cp(b)
5
and cp
B,
r e l a t i v e t o (1.8.1). An overfunction
i s defined similarly i n an obvious way. THEOREM 1.10.1.
x"
=
f(t,x,x')
unique.
Assume t h a t solutions of BVP's f o r
on subintervals of
when they e x i s t , are
J,
Suppose t h a t there e x i s t both an underfunction cpo
and an overfunction $ r e l a t i v e t o BVP (1.10.1) such t h a t 0 cpo(t) 1. q0(t) on J . Let Q be the s e t of a l l underfunctions cp
such t h a t
cp(t) < $o(t)
i s simultaneously a sub-
function on J.
a solution x
5
E
z(t,),
W e define
Then
z ( t ) = sup
and superfunction on J.
It follows from Theorem 1.9.3 t h a t
Proof:
subfhnction on J .
x(t2)
on J .
zl(t)
Suppose now t h a t
z(t)
but
x(t)
>
such t h a t
z(t)
[tl,t2]
is a C J
x(tl) < z(tl),
a t some points of
LtlJt21
on J Then by Theorem 1.9.4, zl(a) = z(a)
zl(t)
-< A,
- Ctl,t21.
i s a subfunction on z (b) = z(b) 1
-< B.
and
(tl,t2).
on J by
Zl(t) = { ~ ~ ~ ( t ) J z ( t ) l on
kreover
z(t)
i s hot a super-
Then there i s a subinterval C(2)[[tlyt2],R]
cp(t) v=Q
J
and
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and
jro
[tl,t2].
a superfunction implies t h a t Consequently, we have
we i n f e r t h a t x(t)
> z(t)
which proves
x(t)
5
z,(t)
5
jro(t)
jro(t)
on
on Hence,
J.
E 0 and z,(t) < z ( t ) . However, z1( t ) = 1 a t some points i n (t,,t2), a contradiction
z
i s a superfunction on
z(t)
J.
This proves
t h e theorem. The function
DEFINITION 1.10.2.
obtained i n t h e
z(t)
preceding theorem depends on t h e BVP (1.10.1) function
We s h a l l say t h a t
jr0.
z(t)
and on t h e over-
i s a generalized
solution of the BVP (1.10.1) and we s h a l l designate it by z(t;JIO). Notice t h a t since
z(t;jr ) 0
i s a subfunction and a super-
function a t t h e same time, the assertions made i n Theorem
1.9.6 apply t o z(t;Jro). We therefore have t o consider the behavior of
a t t h e end points of
z(t;jro)
J = [a,b].
We
discuss t h i s i n t h e following theorem. THEOREM 1.10.2.
Assume t h a t the hypotheses of Theorem
1.10.1 are s a t i s f i e d and l e t
z ( t ) = z(t;Jro) be the corresponding generalized solution of (1.10.1). Then .(a) = A. If
Dz(a+)
Hence, i f
z(a+)
#+m,
Dz(a+)
-< .(a).
i s finite,
t
assertions are t r u e a t Proof: cp*(a) = cp(a)
cp*(t)
+
c, c
cp(t)
Assume now t h a t z(t)
6,0
Dz(a+)
< 6 < b - a,
< w(t)
= z(a+)
-m.
Similar
i s a subfunction on J,
cp*(t) = cp(t)
on
i s also a subfunction.
gether with the d e f i n i t i o n of there i s a
=
= b.
defined by
> 0,
< A, Dz(a+)
z(a+) = z ( a ) = A.
Observe t h a t i f
the function
z(a+)
If
z(t),
# +m
and
and an
+ N(t 64
yields
-a),
N
z(a+)
(a,bl
This, t o -
z ( a ) = A.
>
~ ( a ) . Then
such t h a t a
and
< t 5 a + 6.
1.10. PERRON'S METHOD
By Theorem 1.1.2 it follows t h a t f o r
0
<
E
< z(a+) -.(a)
and 0 < 6 < 6 s u f f i c i e n t l y small, t h e BVP 1-
has a solution x
E
C(2)[[a,a+61],R]. z ( t ) _< x ( t )
f'unction, we have z(a+)
5
on
x(a+) = .(a)
This contradiction proves t h a t Finally, suppose t h a t
[&,a+ = z(a+)
Dz (a+)
Z(a>* z(a+)
Since
41
z(t)
i s a sub-
which yields
- E.
# +m
implies
< A and Dz(a+)
# - m.
using an analogous argument as above and the f a c t t h a t
i s also a superfunction on J, implies
-
Dz(a+) =
If Dz(a+)
z (a+) 5
we can conclude t h a t
Then
~ ( t ) z(a+) < A
m.
i s f i n i t e , then combining the assertions of
t h i s theorem we arrive a t
A = .(a)
i s complete.
> A. -> z(a+) -
The proof
From the preceding r e s u l t s it i s clear t h a t Perron's method of studying t h e BVP (1.10.1) canbe separated i n t o twoparts. The f i r s t p a r t dealswiththeproblemofestablishingtheexistenceof an overfunction qo and an underfunction cP,(t) 5 q o ( t )
on J.
rp 0
such t h a t
The second part consists of finding
conditions under which the generalized solution of class
C(2)[J,R]
and i s a solution on J .
z (t;qo)
is
I n view of
Theorems 1.9.6, 1.10.1, and 1.10.2, accomplishing t h i s i s equivalent t o showing t h a t Dz(t-)
i s f i n i t e on
Dz(t+)
i s f i n i t e on
[a,b)
and
(a,b].
Let us f i r s t give s u f f i c i e n t conditions f o r the existence
of under-
and overf'unctions
LEMMA 1.10.1.
nondecreasing i n x
Let
.
f E C[JxRxR,R]
f o r fixed 65
(t,x').
and f ( t , x , x ' ) be Assume t h a t f ( t , x , x ' )
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
i s such t h a t lower and upper solutions of the d i f f e r e n t i a l equation x'' = f ( t , x , x 7 ) are subrespectively.
and superfunctions,
Then,
i s a solution of XI' = f ( t , x , x I ) (a) i f u E C ( 2 ) [ J , R ] on J, there e x i s t overf'unctions and underf'unctions r e l a t i v e t o any BVP on J; (b)
i f there i s a
(1.10.2)
k
>0
such t h a t
5
If(t,O,x') -f(t,O,O)l
t
klx'),
E J,
XI
E
R,
there e x i s t overfunctions and underfunctions r e l a t i v e t o any BVP on
J.
For any s u f f i c i e n t l y large M > 0, q o ( t ) = u ( t ) + M i s an overfunction, rpo ( t ) = u ( t ) M i s an underfunction, and
Proof:
cpo(t)
5
q 0 ( t ) on J.
-
This proves ( a ) .
To prove (b), we l e t
sider the solution w(t)
M = maxlf(t,O,O)l
5
M
>0
q 0 ( t ) = w(t)
v" = - k v ' v(t)
5
0
As a
on J
+
and we a s s e r t t h a t ,
M w i n be an overfunction
v ( t ) be the solution of BVP
+ My
and v ' ( t )
that dt = klv'
-< f(t,w,w')
i s s u f f i c i e n t l y large.
Similarly, l e t
on J .
wf(b) = 0.
and w t ( t )
f(t,O,wt)
f o r a given BVP, provided
Then
w(a) = 0,
-> 0 on J. Hence, by (1.10.2), = - kw' - M = - klw' I - M < f (t,O,w') - f (t,O,O) - M. 410
Then w(t)
Thus w"
and con-
of BY!?
w" = - k w * - M y
W"
on J
v(a) = 0,
-< 0
on J,
v'(b) = 0. from which it follows
I +M> f(t,O,v') -f(t,O,O) + M > f(t,O,v') r e s u l t , vl' > - f ( t , v , v * ) on J and, f o r M > 0
s u f f i c i e n t l y large,
cp,(t) = v ( t ) 66
-M
i s an underfunction
1.10. PERRON'S METHOD
relative t o a given BVP. Obviously, we have q 0 ( t ) on J. !Chis completes the proof of the lemma.
5
qo(t)
We are now ready t o s t a t e our main r e s u l t . THEOREM 1.10.3.
Assume t h a t
i s nondecreasing i n x
f o r each
f
Q
(t,x'),
of i n i t i a l value problems are unique. that there i s a
k
C[JxRxR,R], f ( t , x , x ' )
> 0 Such t h a t
and t h a t solutions
In addition, suppose
I f ( t J 0 J x ' ) -f(tJOjO)l < klx'
t E J and x t e R . Then f o r any BVP on J with an associated overflrnction q0 ( t ) , the generalized solution 0 Z(t) = Z(t;qo) E C(2)[Jo,R] and Z" = f ( t J ? d J Z ' ) On J for
.
Proof:
By Lemma l . l O J I J we readily obtain the existence
rpo
Jr0 with respect - JIo(t) on J . Consequently, t o BVP (1.10.1) such t h a t cpo(t) < the generalized solution z ( t ) = z(t;q0) i s defined. b r e over, the hypotheses imply t h a t solutions of BVP's when they exist, a r e unique and, therefore, the conclusions of Theorem 1.9.6 apply t o z ( t ) . Thus it suffices t o show t h a t Dz(t+), of an underfunction
and an overfunction
0
0
.
Let to E Jo and Dz(t0) a r e f i n i t e f o r every to E J + suppose t h a t z ( t O ) 2 z ( t i ) . The alternative case can be dealt with i n a similar way and w i l l not be t r e a t e d . We break the discussion i n t o two p a r t s .
F i r s t assume
that z ( t i ) 2 0. Let + ( t ) be a solution of Jr" = - kJr' -M, where M = max If(t,O,O)l, with Jr(to) = 0 , + ' ( t ) _> 0 on [tOJb], and
J
Jr(b) _>z(b-), which can be computed.
in Lemma 1.10.1, +,(t)
=
q(t)
+ + z(to)
on [t0'b1 w i t h z(tA) _< ql(tO) and follows from Theorem 1.9.5 t h a t z ( t )
$ ( t ) be a solution of
i s an upper solution
z(b-) Jr,(t)
_< Jrl(b). on
It (tOJb),
q ' ( t ) < m. Applying Theorem 1 0 z ( t ) i s continuous a t to. Now l e t
which implies t h a t Dz(tt)
1.9.6, we a s s e r t t h a t
Then as
Jr"
5
= kJr'
67
-M
on
[a,to]
such t h a t
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
$ ( t o ) = 0 , $(a)
2
z(a+),
$'(t) <0
and
again by Theorem 1.9.5, we have Dz(t0) 2 $ ' ( t o ) > - m. z ( t ) has a f i n i t e derivative a t implies
Finally, suppose t h a t solution of
cpl'
z(a+), cp(to) = 0, Theorem 1.9.5,
kcp'
=
+
and
on
2
<
0
0
on
cp,(t) be a
and l e t such t h a t [a,tol.
cp(a)
Theorem 1.9.6 t h a t we can show t h a t
z(t)
i s continuous a t
+ > - m.
5
Then, by
,> cp,(t) - z ( t 0 ) on (a,to), Dz(t0) 5 cp;(to) < m. It follows
z(t)
assures us t h a t
Then
to.
[a,to]
cp'(t)
[a,tol.
z ( t ) 5 $ ( t ) + z ( t o ) , which We i n f e r t h a t i n t h i s case
.(ti)
M
on
which from
to. Similarly
Thus we again conclude t h a t
Dz ( t o )
to. z ( t ) has a f i n i t e derivative a t each point of
z ( t ) has a f i n i t e derivative a t J
0
,
Since
it follows from !Theorem 1.9.6 t h a t z E C(2)[Jo,R] and 0 z" = f ( t , z , z ' ) on J This completes the
.
i s a solution of proof.
The following exercise i s instructive. EXERCISE 1.10.1.
Under the hypotheses of Theorem 1.10.3,
show t h a t the BVP x" = f ( t , x , x ' ) , x(a) = x(b) = 0 has a unique solution x ( t )
where M,k
on J,
Hints:
- k$, - M)
If
such t h a t
as i n Theorem 1.10.3.
$,(t),$2(t)
are the solutions of BIT'S
9; = k$, -M, q2(b) = 0, = 0, show t h a t Jrg(t) = min[$,(t),$,(t)] i s an overfunction. Similarly obtain an underfunction cpo(t) 5 $ o ( t ) $'I
=
1 $;(a)
on J . cpo(t)
5
Jrl(a) = 0, $;(b)
= 0,
Using Theorems 1.10.2 and 1.10.3, proceed t o show that z(t;q0)
5
q 0 ( t ) on J 68
and
z(t;q0)
i s a solution of
1.1 1 . MODIFIED VECTOR FUNCTION
t h e desired BVP which i s unique.
Compute
qoJq0 and est a b l i s h t h e bound on I x ( t ) l ; show t h a t m e x Jr ( t ) = J O -minJ cpo(t>. If to E JO and x ( t o > > 0 , l e t q1(t;t0)J q 2 ( t' - 0t ) be the respective solutions of BVP's
- kJr' -M,
$1
=
+"
= kJr'
- M,
q(t,) = 0,
$'(b) = 0;
+ ( t o ) = 0, $ ' ( a ) = 0 .
prove t h a t
q$(to;tO) ,< x ' ( t O ) 5 Jri(t,;t,),
x ( t o ) < 0,
obtain analogous relations.
Similarly, i f
Since the functions
involved and t h e i r derivatives can be computed, deduce the desired bound on
Ix' ( t ) I.
1.11 KlDIFIED VECTOR FUNCTION
Some of the r e s u l t s considered so f a r f o r scalar secondorder d i f f e r e n t i a l equations w i l l now be extended, i n the sections t h a t follow, t o f i n i t e systems of second-order difTo avoid repetition, l e t us agree on
f e r e n t i a l equations. the following:
..,n;
1,2,.
the subscripts
range over the integers
i,j
vectorial inequalities w i l l be used freely with
the understanding t h a t the same inequalities hold between t h e i r respective components. L e t us consider a system of second-order d i f f e r e n t i a l
equations written i n the vector form (1.11.1)
where
XI1 =
n
f E C [J xRn X R
,Rn 1.
f(t,X,X'), We s h a l l next define modified
vector functions i n different ways. DEFINITION 1.11.1. Let a(t) that
5
p(t)
on J
IcY'(t)l,
cr,B
E
C(l)[J,Rn] with
and l e t a constant vector
\pl(t)( < c F*(t,X,X')
on J . =
69
Then define
f(tJx,z')
c
>0
be such
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
("s
where
-x!J
=
if
J if -c < x! j - J if x!
-C
J
Fr((t,f;,x')
,x,
,x,x') =
XI
+ (xi
-
>c 3' 5 cj , < -c 3'
2 B i ( t ) ) / l + x i if xi
>
Bi(t),
Fy ( t x ) if a i ( t ) 5 ~ i ( ~ i ( t ) , 2 F y ( ( t , x , x ' ) + (xi - a i ( t ) ) / l + x i if xi < a i ( t ) ,
where
The f'unction f(t,x,x')
will be c a l l e d t h e modification of
F(t,x,x')
relative t o the t r i p l e
the definition t h a t J xRnxRn.
a,@,c.
It i s c l e a r from
i s continuous and bounded on
F(t,x,x')
IF'I ,< c and a ( t ) ,< 5 5 @ ( t )
Also note t h a t
on J . DEFINITION 1.11.2. on
J
A,
where, as before,
and l e t
cp,$
E
Let
a,@
E
C[J,Rn]
with
F ( t , x , x ' ) = f(t,x,f;'),
-(.
Bj(t)
x3
j
aj(t)
< B(t)
such t h a t cp(t,x) 5 q ( t , x ) on A = [(t,x): a ( t ) <x< @ ( t ) , t E J].
C[A,Rn]
men define
where
a(*)
if x.J
>
Bj(t), if a . ( t ) < x . < B . ( t ) ,
if
and
70
J - J - J x. < a . ( t ) , J J
1.11. MODIFIED VECTOR FUNCTION
x! J
-
=
> J;i(t,x),
Jrg(t,X)
if xj'
x'
if cp.(t,x)
{ scpj(t,x)
5 x!J 5 Jlj(t,X), J if x! < cpj(t,x). J
We shall c a l l the f'unction F(t,x,x'), the modified f'unction o f f ( t , x , x ' ) associated w i t h a,@,cp, and $. fgain, it i s easily seen t h a t F(t,x,x') i s continuous and bounded on JxRnxRn.
Furthermore,
a(t) <
x -< @ ( t ) and
cp(t,x)
5
5
$(t,x>* DEFINITION 1 . 1 1 . 3 .
Let
E = [(t,x,x'): t
+ +
E
J,
C[R ,R 1 be such that 6(s) = 0 accordingly as 0 5 s respectively. Then define Let
6
E
N > 0 be given and l e t
p,
(Ix((
C P, X'
E
Rnl.
c
6(s)
< 1, and 5 N, N < s < 2N, and s > 2N 6(s) = 1, 0
We s h a l l sey that F ( t , x , x ' ) i s a modified function of f ( t , x , x ' ) r e l a t i v e t o p,6. Clearly the f'unction F ( t , x , x ' ) n n i s continuous and bounded on J xR xR
.
A r e s u l t analogous t o Theorem 1.3.1 w i l l be proved next.
where
71
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and I a ' ( t ) l J I p ' ( t ) l < c. Suppose f u r t h e r t h a t n n f E [ J X R ~ X ,R R I and f ( t J x , y ) i s quasimonotone nonincreasing i n
t h a t is, f o r fixed
x,y,
increasing i n y
for j is nonincreasing i n x t h e modification of
j
f
and f o r fixed
i
for
(t,x), f i ( t , x , y )
j
#
f(t,x,x')
t h e BW
(1.11.2)
x" = F ( t , x , x ' ) , x
has a solution
E
5y5
.(a)
x ( a ) = y,
C(*)[J,Rn]
is
F(t,x,x')
associated with
cording t o Definition 1.11.1, and 6 5 p(b),
(t,y), fi(t,x,y)
Then, i f
i.
i s non-
a,p,c
ac-
p(a), a ( b ) 5
x ( b ) = 6,
satisfying
a(t)
-< x ( t )
_< p ( t )
on J . Proof:
By Corollary 1.1.1, t h e BVP (1.11.2) has a solution.
Hence we need only t o show t h a t
w i l l show t h a t x(t)
5
p(t)
a(t)
on
5
x(t)
5
a(t)
on J,
x(t)
5
p(t)
on J .
since t h e proof of
follows s i m i l a r l y .
J
Suppose it i s not t r u e t h a t t h e r e e x i s t s an index k
a(t)
_< x ( t ) on J.
and an i n t e r v a l
Then
[ t l J t 2 ] C (a,b)
such t h a t 5 ( t 2 > = ak(t2)J
%(tl> = ak(tl), and 5(t) Thus
ak(t) -\(t)
%(to) = a i ( t o ) .
< ak(t>J
(tlJt2)'
has a maximum at some Hence
I
/%(to)< ck
have
72
to
E
(tl,t2)
and
and consequently, we
We
1.1 1 . MODIFIED VECTOR FUNCTION
i n view of t h e d e f i n i t i o n of nonincreasing character of possible at a maximum of
F(t,x,x') f(t,x,x')
cik(t)
and t h e quasimonotone
x,x'.
in
- %(t)
and hence t h e proof.
The quasimonotone nonincreasing nature of x,x'
This i s im-
in
f (t,x,x')
assumed i n Theorem 1 . l l . l b e c o m e s superfluous i f t h e
assumptions concerning
a,p
are made stronger.
"his we s t a t e
i n the following exericse. EXERCISE 1.U.1. Suppose t h a t with
a(t)
5
p(t)
on
J
and f o r
fi( t,A(t,i),At ( t , i ) ) , D-p;(t) A(t,i)
,
=
A ( t i) =
5
n 2
a,p E CIJ,Rnl
t
E
J
0
, D-a;(t)
C(l)[Jo,Rn]
fi( t , B ( t , i ) , B ' ( t , i ) ) ,
( X1' .. ., x i - l > q t ) , x i + l , ( xi, .. .,x i - 1,ai ( t ) ,xi+1,
*
where
.,xn),
...,xn ),
...7xi-19Pi(t),xi+l,. . .,xn), B 1( t , i ) = ( x i , .. . p i (t),xi+l, .. n ) ,
B(t,i)
= (xl,
.,XI
provided a . ( t ) < x . < p . ( t ) and - c . < x! 5 c f o r j # i, J - J - J J J j c being any vector s a t i s f y i n g I a ' ( t ) l , l p t ( t ) l < c . Show .(a)
-< y < p(a),
p(b) has a solution x E C(2)[J,Rnl
satisfying
that t h e BVP (1.11.2) such t h a t
73
a(b)
-<
6 _<
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
a(t)
-< x ( t ) 5
B(t)
on J.
REMARK 1.ll.1.
From t h e foregoing discussion, a n a t u r a l
question t h a t a r i s e s i s whether a r e s u l t analogous t o Theorem 1.11.1remains t r u e i f
a,B
ww,
solutions, i n a n a t u r a l
equation x" = f ( t , x , x ' ) .
a r e defined as lower and upper r e l a t i v e t o the vector d i f f e r e n t i a l
This can be done by defining a
modified function which has a jump discontinuity along t h e upper and lower solutions.
EXERCISE 1.U.2.
Let
x E C(2)[J,Rn]
be a solution of
xff = F ( t , x , x ' ) ,
where F i s the modified function of n n f E C[JxRnxR ,R ] r e l a t i v e t o p,6 as i n Definition 1.11.3,
Ilx(a) 1 , Ilx(b) 11 5 p. Suppose t h a t there e x i s t s a V E C[D,R+] such t h a t V(t,x,y) i s l o c a l l y Lipschitzian i n such t h a t
( x , ~ ) ,V(t,x,y) = 0 if llxll = P, V(t,x,y) > 0 if IIxll > P + and D VF(t,x,x') 2 0 in t h e i n t e r i o r of D, D being t h e set on
D = [[a,bl
x [x: llxll > P I xRn].
Show t h a t
Ilx(t)II
-< P
[a,b].
1.12 NAGUMO1s CONDITION
(CONTINUED)
I n remark 1.4.1, we noted t h a t Nagumo's condition i s not suff i c i e n t t o conclude
IIx' ( t ) 11 i s bounded, i f
n
f E C[J xRn xR ,R
n
Nonetheless, we can make conclusions on t h e a r c length of t h e curve
Ilx(t)II,
that i s
/ / / x ' ( s ) l / ds,
LEMMA 1.12.1. Assume t h a t
h E C[R+, (0,m) (1.12.1) where
.few
Ilf
1.
as the next lemma shows.
n n f E C[JxRnXR ,R ]
and
Suppose t h a t
(t,x,x')
11 5 h ( IIx' [I),
s ds/h(s) =
m.
(t,x,x')
E
J xRn xRn,
Then, t h e r e e x i s t s a 74
y: R' - t R +
1.
1.12. NAGUMO'S CONDITION (CONTINUED)
Proof: Since lorn s ds/h(s) y: R + Z satisfying
=
there e x i s t s a f'unction
rn,
From assumption (l.I2.1), we obtain
Hence i f
-
a < v, w < b,
by the change o f variables are equal (and zero) f o r respect t o w
((XI
v=w,
(s)II
--f
s;
the two integrals
and the derivatives with
e x i s t almost everywhere and are equal.
follows t h a t the integrals are equal since
Ilx'(w)II
It
is
absolutely continuous. Choose v and w such t h a t 11x' (v) 1) = el/ (b-a) (which i s possible by the mean value theorem) llxt(w)(I = max Ilx'(s)II on a 5 s 5 b . The desired r e s u l t then follows from (1.l2.2) and ( 1 . 2 . 3 ) and t h e proof i s and
complete.
It i s , however, possible t o extend Theorem 1.4.1 t o deal with the vector s i t u a t i o n . DLEORFM 1.12.1.
Suppose t h a t the following assumptions
hold: 75
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
n n ( i ) f E C[JxRnxR ,R 1, a , p E C[J,Rn] such t h a t a ( t > 5 p ( t ) on J and f o r t c J, u ( t > 5 x 5 p ( t ) , x f E R",
(1.l2.4)
5 hi(lX11),
Ifi(t,X,X')l
+
h, E C[R ,(O,m)]
(ii)
...,n,
i = 1,
and s a t i s f i e s
) - min a, ( t ) , where
Then, f o r any solution a(t) N
2
5
5
x(t)
@ ( t ) on
(1.u .6)
J
Ixf(t)l
N
E
C(2)[J,Rn]
of (1.11.1) with
t h e r e e x i s t s a constant vector u,p,h,
-< N
such t h a t on J .
I n view of ( l e a . ? ) , t h e r e e x i s t s a constant
Proof: vector
x
depending only on
0,
I.
- a ) = max[Ia(a) - @ ( a )
h(b
>
0
such t h a t
If (1.12.6) i s not t r u e , we m q r assume, without loss of
generality, t h a t t h e r e i s an index
t
J, I s ( t ) have E
I > Nk.
to = t O ( k )
\
E
such t h q t f o r some
However, by t h e mean value theorem, we
- s ( a >= where
k
(a,b)
x$t0)(b
- a),
and consequently, it follows t h a t
I%(tO) I 5 < Nk. The remainder of t h e proof i s almost identical t o the proof of Theorem 1 . 4 . 1 and we therefore leave it t o the reader.
76
1.12. NAGUMO'S CONDITION (CONTINUED)
The next r e s u l t i s an extension of Theorem 1.4.3 t o the present situation. TE30REM 1.12.2. (i) (ii) (t,x)
E
C(l)[J,Rn]
with
a(t)
'p,+
E
C(')[A,Rn]
with
cp(t,x)
+ 'px(t,x)
'pt
+t (iii)
-< p ( t )
a,@
where A = [ ( t , x ) : a ( t )
A,
E
Suppose t h a t
+
5x5
5
on J;
+(t,x)
p(t), t
E
and for J],
cp(t,x> 5 f(t,x,'p(t,x)),
*
Jrx(t,x> * + ( t , x )
f E C[JxRnxRn ,Rn 3
2
and
f(t,x,+(t,x)); cp(a,x(a))
< x ' ( a ) _<
-
+(a,x(a)) * Then, f o r any solution x a(t)
5 x(t) 5
(1.12.7)
p(t)
on J,
cp(t,x(t))
Proof:
Let
C(2)[J,Rn]
E
we have
5 x'(t>5
x(t)
of (l.ll.1) such t h a t
Jr(t,x(t)),
t
E J.
be any solution of (l.U.1) satisfying
'p(a,x(a)) _< x ' (a) 5 +(a,x(a)). We s h a l l only prove t h a t p ( t , x ( t ) )
-< x ' ( t )
on J,
since the proof of the other case i n ( l . X . 7 ) i s similar. Assume t h a t t h i s i s not t r u e . and a
on
to
E
(a,b]
such t h a t
Then there e x i s t s an index k X;c(to) < cpk(to,x(to)). Set
(tl,to]. Such an i n t e r v a l
'pk(t,x(t)) -X;c(t)
>
0.
(tl,to] e x i s t s where
It then follows t h a t
77
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
on
(tl,to].
5
zi(t)
t
0
This together with assumption ( i i ) yields on
(tl,to]
increases.
Thus
and hence zk(tl)
tended t o conclude t h a t
>
0.
z,(t)
This argument can be ex-
>0
z,(a)
i s nonincreasing as
which implies t h a t
cp,(a,x(a)) > %(a), a contradiction t o assumption ( i i i ) . This proves cp(t,x(t)) 5 x l ( t ) on J and the proof i s complete. Another r e s u l t t h a t may be u s e h l i n some s i t u a t i o n s i s t h e following. THEOREM 1.12.3.
(i) .(a)
a,p E C(l)[J,Rn]
(ii)
#
with
a(t) < p(t)
h E C[JxRy,R~], h ( t , u )
i
where
t h a t is,
u,
t
f o r each
( 1.12.8)
E J,
and
u ( a ) = A,
A = max[la'(a)), l p l ( a ) l ] ,
for
t
E
J, a ( t )
5x5
I
e x i s t s on
> 0,
x(t)
5
B(t)
on J,
[a,b];
p(t),
5 h(t,
Then f o r any solution x E C(*)[J,Rn]
5
i s nondecreasing i n u
and t h e maximal solution of
If(t,X,X')
N
J
i s quasimonotone non-
hi(t,u)
u 1 = h(t,u),
(iii)
a(t)
on
= B(a);
decreasing i n j
Suppose t h a t
Ix'
I). of ( l . l l . 1 ) with
t h e r e e x i s t s a constant vector
depending only on a,@,h such t h a t I x l ( t ) l IN,
t
E J.
j'
1.12. NAGUMOS CONDlTlON (CONTINUED)
Proof:
a(t)
5
that
Let
5
x(t)
.(a)
x(t)
be any solution of (1.11.1)with
@ ( t ) on
= p(a),
This, i n view of t h e assumption
J.
implies t h a t
fine m(t) = l x ' ( t ) l .
5
al(a)
Then m(a)
-< A
D+m(t) < Ix"(t)I = I f ( t , x ( t ) , x ' ( t ) ) l
xl(a)
5
p'(a).
De-
and, by ( i i i ) ,
5
t
h(t,m(t)),
E
J.
Consequently, by t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s , we have m(t) where
[a,b].
5 N,
r(t,a,h)
t
r(t,a,A),
J,
E
i s t h e maximal solution of (1.12.8) which
r(t,a,A)
exists on
5
t
Let
E J.
N
>0
be a vector such t h a t
Then t h e s t a t e d conclusion follows
immediately. One can a l s o deduce a bound on Wapunov-like method.
IIx'(t))I by employing a This i s t h e content of t h e next two
theorems. THEOREM 1.12.4. (i)
in x,y, bl(u)
V
CID1,R+],
E
as
V(t,x,y)
D1 = J X[x:
where
+ w
Assume t h a t
u
+ w
( ( ~ 1 1-<
i s l o c a l l y Lipschitzian
5 b2( IIYII 1,
+
( i i ) D V(t,x,x') = lim sup h+O
(t,X,Y) +
+
D1;
(t,x,x')
and t h e m a x i m a l solution
of exists on
E
- V(t,x,x')]
-< g ( t , V ( t , x , x ' ) ) f o r
C [ J x R ,R]
u'
+ + 1,
C[R ,R
( l / h ) [V(t + h , x + h x ' ,
x' + h f ( t , x , x ' ) )
E
E
and
b l ( I h l l ) ~V(t,X,Y)
(iii) g
bl,b2
p] XRn,
u ( a ) = A ? 0,
= g(t,u),
[a,b].
79
E Int D ~ ;
r(t,a,h)
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Then, f o r any solution
x E C(2)[J,Rn] of (1.11.1)such t h a t
llx'(a)II
5
pending only on
p, po,g
such t h a t
Proof:
x(t)
Ilx(t)((_< p
Ilx(t)II
5
and
Let and
P
t h e r e e x i s t s an
po,
N
> 0 de-
be any solution of (1.11.1)such t h a t
5
llx'(a)II
Define
p0.
m(t) = V ( t , x ( t ) , x ' ( t ) ) .
Then by ( i ) , we obtain m(a) 5 b2( IIx'(a)lI) 5 b2(po). h = b2(po). Also, because o f t h e assumptions on V,
Choose
it
follows t h a t ~+m(t5 > @;(t,m(t>),
t
E
(a,bl
and consequently, by t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s , we obtain m(t)
-< r ( t , a , h ) ,
t
E J.
By ( i ) , t h i s i n t u r n yields
< r(t,a,h), bl( I I x l ( t > I I ) 5 V ( t J x ( t ) , x ' ( t ) ) = m(t> Since that
r(t,a,h) r(t,a,A)
e x i s t s on
5
M on
[a,b],
[a,b].
there is a
t
M
Furthermore, as
E
J.
> 0 such
bl(u)
--3m
> 0 such t h a t M < b(N). These considerations imply t h a t IIx' ( t ) 11 5 N on J . Clearly
as N
u
--3 m,
t h e r e e x i s t s an
depends only on
pJp0,
THEOREM 1.12.5.
where
and
E = [ [ a ~ b X] [x: llxll
5
V(t,XJX') _> ( t - a ) b ( [ l x ' I I ) ,
r
+m,
+
and
that ing
5
p] XRn],
on
[a,b],
Ilxl(t)ll _< N
on
[a,bl.
such t h a t
V
6
C[E,R+],
V(t,x,y)
< L i n the i n t e r i o r of
x E C(2'[[a,b],Rn]
p
Ilx(t)ll
This completes t h e proof.
(x,y), V ( a , x ( a ) , x ' ( a ) ) = 0, + + where b E C[R ,R ] with b ( r ) + m
D Vf(t,x,x')
Then f o r any solution
g.
Suppose t h a t t h e r e e x i s t s a
i s l o c a l l y Lipschitzian i n as
N
of (1.11.1)such
there e x i s t s an
80
E.
N >0
satisfy-
1 . 1 3 . EXISTENCE IN THE LARGE FOR SYSTEMS
Proof: such t h a t
By assumption on
b(r)
>L
if
r
b(r),
> N. -
t h e r e e x i s t s an
N
>0
A l s o , we have by t h e theory
of d i f f e r e n t i a l i n e q u a l i t i e s
v ( t , x ( t > J x ' ( t > )5 V ( a , x ( a ) , x ' ( a ) ) + L(t I f we now suppose t h a t f o r some
t2
E
- a),
t
(a,bl, Ilx(t2
then we a r e lead t o t h e contradiction
< (t2-a)[b(llx'(t2)11)-L] 5 V ( a , x ( a ) , x ' ( a ) )
0
= 0.
Hence t h e conclusion of the theorem i s t r u e . EXISTENCE IN THE LARGE FOR S
1.13
Y
S
~
We s h a l l f i r s t prove an existence r e s u l t analogous t o Theorem 1 . 5 . 1 f o r t h e BVP (1.13.1) where
f
XI'
E
= f(tJXJX')J
X(a) = A,
x(b) = B,
C[JxRnxRn,Rn], A,B E Rn.
THEOREM 1.13.1. Suppose t h a t t h e following conditions
hold: on J D-ai(t)
( i ) a , p E C[J,Rn] II C(l)[JoJRn] 0 and f o r t E J ,
such t h a t
a(t)
5
@(t)
_> f i ( t ~ a ( t ) ~ a ( t ~ i ) D-B'(t) )~ 5 fi(tJp(t)Jb(t>i))>
where
81
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(iii)
hi
E
-I.
C[R ,(O,-)]
s a t i s f i e s (1.12.5).
and hi
Then f o r any .(a) 5 A 5 B(a), a(b) 5 B (1.13.1) has a solution x E C(2)[J,Rn] a(t)
5
vector
x(t)
No
p(b),
t h e BVP
such t h a t
5 p ( t ) on J . k r e o v e r t h e r e e x i s t s a constant
>0
Proof: -
5
such t h a t
Ix'(t)
I 5 No
on
J.
Ey hypothesis ( i i ) , we can choose a vector
depending only on c?,p,h,
as i n Theorem 1.12.1. L e t
N
> 0,
No be
such t h a t
Choose
c
> No.
Let
F(t,x,x')
be t h e modification function
as defined i n Definition 1.11.1r e l a t i v e t o the t r i p l e
a,p,c.
Then by Theorem 1.11.1it follows t h a t t h e BVP XI'
= F(t,x,x'),
has a solution
J.
x
x(a) = A,
x(b) = B,
with a ( t )
E C(2)[J,Rn]
-< x ( t ) -< B(t)
on
Hence we have X"
= F(t,x,x') = f ( t , x , x ' )
i n view of t h e d e f i n i t i o n of by ( i i )
,
5x 5
B(t), t
F.
Consequently, we obtain,
Recalling t h a t 1Z;l < ci and proceeding as i n the proof of meorern 1.12.1, it i s e a s i l y
whenever
shown t h a t
a(t)
( x '( t ) I
F(t,x,x') = f ( t , x , x ' )
E
J.
No on Jo.
This then implies t h a t
a d therefore
solution of t h e desired BVP
x(t)
is actually a
(1.13.1) completing t h e proof.
Based on Theorem 1.12.2, it i s possible t o exhibit.
82
1.13. EXISTENCE IN THE LARGE FOR SYSTEMS
another existence theorem which i s an extension of Theorem
1.5.5.
on JoJ where
83
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
SZ being the s e t
n = [(t,x,x): (t,x)
E
n
and cp(t,x)
,< x' ,< Jr(t,x)l.
-
Proof: Let F(t,x,xt) be a modified f'unction of as in Definition 1.11.2 f ( t , x , x l ) associated w i t h cu,@,cp,@ which i s continuous and bounded on J xRn xRn and therefore s a t i s f i e s -theses ( i ) and ( i i i ) of Theorem 1.13.1. Furthermore, in view of the assumptions relative t o a l , p l i n ( i i i ) , it i s easily verified that hypothesis (i) is true w i t h respect t o F ( t , x , x l ) i n place of f ( t , x , x ' ) . This implies that
condition (i) of Theorem 1.13.1 holds w i t h cp,@ instead of -c,c respectively. As a result, it follows, by Theorem 1.13.1 that there exists a solution x E: C(2)[J,Rn] t o the modified
BW x" = F(t,x,x'),
x(a) = A,
x(b) = B,
such that a ( t ) 5 x ( t ) 5 @ ( t ) on J, where @(a)= A = @(a), a ( b ) 5 B 5 @(b). We now apply Theorem 1.12.2 t o assert that x ( t ) is actually a solution of the BVP (1.13.1) satisfying ( t , x ( t ) , x ' ( t ) ) E 12, t E J. For t h i s , it is necessary t o check that a l l the hypotheses of Theorem 1.12.2 are s a t i s f i e d which we leave t o the reader since it i s similar t o the proof of Theorem 1.5.5. This completes the proof. EI(ERC1SE 1.13.1.
Under the assumptions of Exercises show that the BVP XI' = f ( t , x , x t ) , x(a) = A, x(b) '= B has a solution. 1.11.2 and Theorem 1.12.5,
1.14 FUR'MER RESULTS FOR SYSTEM Let us consider the d i f f e r e n t i a l system
(1.14.1) where f
X'l
E
= f(t,X,X'),
n n C [ [ O , ~ ] X R ~ X,R R
3,
84
subject t o the boundary
1.14. FURTHER RESULTS FOR SYSTEMS
conditions (1.14.2)
= 0, ~ ( 0 -AOx'(0) )
(1.14.3)
x(l)+A1x'(l) = 0 ,
AOjA1
being
matrices.
dxd
Here we s h a l l study t h e existence of solutions of t h e BVP (1.14.1)
- (1.14.3)
earlier results.
i n a more general s e t up than t h e
We employ mapunov-like fbnctions and t h e
theory of d i f f e r e n t i a l i n e q u a l i t i e s i n a s l i g h t l y d i f f e r e n t way which throws much l i g h t on t h e underlying ideas.
The
technique i s , of course, the modified function approach.
The
following lemma i s very u s e f u l i n our discussion. LEMMA 1.14.1.
(i)
U E
Assume t h a t
C ( * ) [ [ O J ~ ] J R + ] Jg
i s nonincreasing i n u
g(t,u,v)
c [ [ o J 1 X] R + X R J R - ] J
f o r each
-> g ( t J u J u ' ) ; ~ ' ( 1< ) 0, and
(1.14.4)
(t,v)
and
U''
(ii) some ct
E
u'(0)
2
0,
u(0)
-< m ' ( 0 )
for
-> 0 ;
(iii)
G E C [ [ O J ~ ] X R + ~ R ]and t h e r e exists an
such t h a t f o r u
2 L,
t
s a t i s f i e s t h e estimate
E
L>
[0,1],
r(t,TJO)
< aoJ t
E [oJT]J
where
a0 = min(+, 1/a); (iv)
t h e l e f t maximal solution
right minimal solution
(1.14.7)
p(t,O,O)
of
v ' = g(t,2L,v) 85
r(tJ1,O)
and t h e
o
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
e x i s t s on
[0,13.
Then there e x i s t s a
(1.14.8)
u(t)
5
Bo
>0
such that
and
Bo
5
lu'(t)l
Bo,
Proof: Assume t h a t the maximum of
0
u(t)
-< t -< 1.
occurs a t a
-
tl. From conditions u ' ( 0 ) > 0 and ~ ' ( 1 <) 0, it follows t h a t u'(t,) = 0 . Clearly tl > 0 , f o r otherwise
point
we would have
u(tl)
5 mt(tl)
>
Define
2L.
-
u ( t ) 10.
u ( t ) < 2L, 0
L for t E [O,tll.
W e s h a l l show t h a t
u(tl)
and consequently
= 0
If not, define
to = sup[t Since u(tl)
>
E
[O,t11:
U'(t)
to is well
by the mean value theorem,
2L,
defined.
It i s then e a s i l y seen t h a t
(1.14-9)
u'(to)
Setting
-> +u(t)].
2
L ,< u ( t ) ,
cuou(tO),
z(t) = u'(t)/u(t)
for t
t
[tO,tll
E
E
[tO,tll.
and using
assumption (1.14.5) we readily obtain ' ~ ' ( t 2) G ( t , z ( t ) ) , Notice t h a t
z(to) = 0
and
t
z(to)
E
[to,t,l.
1 cyo > 0 .
By the theory
of d i f f e r e n t i a l inequalities, we then i n f e r t h a t z(t) where with on
5
r(t,tl,z(tl)),
r(t,tl,z(tl)) T =
t
[tO,tl],
1'
t
E
[tO,tlI,
is t h e lef't maximal solution of (1.14.6)
Since z(tl) = 0, we see t h a t r(t,tl,O) < CY 0 and as a r e s u l t , we are lead t o t h e contradiction
This proves t h a t
u(t)
5
2L on
86
[0,11.
1.14. FURTHER RESULTS FOR SYSTEMS
U s i n g t h i s i n e q u a l i t y and t h e nonincreasing nature of g(tJuJv) i n
u,
we obtain
u"
-> g ( t , 2 L , u ' ) .
-> 0, ~'(1)5 0, d i f f e r e n t i a l i n e q u a l i t i e s , we have 0 p(tJ0JO)J
Again, using t h e f a c t t h a t theory of
where
for
and t h e
r ( t J 1 , 0 ) , p ( t J O J 0 ) are, respectively, l e f t maximal and
r i g h t minimal s o l u t i o n s of
on
u'(0)
[O,L]. 0
(1.14.7)which
Thus, we can f i n d a
-< t -< 1, B = max
[I
B
>0
a r e assumed t o e x i s t
such t h a t
Iu'(t)I
where max O< t <-l
r(tJIJo)lJ
I
min
- -
O < t < l
p(t,O,O)l].
The conclusion of t h e lemma now follows by choosing B = max[2LJB]. 0
The proof i s complete. 1
The functions g ( t , u , v ) = - k [ l + (2u)'+ 2 0, G(tjZ) = - ( a + k \ z I + Z ) J V(tjX) *11X112 are
COROLLARY 1.14.1. k
IVl]j
>
admissible i n Lemma 1.14.1, where h = $ a0e -(k+l),
provided
a
La
=
k(1
< aOke- (k+l)
+
(1/2h)
+ hk),
Our aim i s t o prove t h e following r e s u l t . IREOREM 1.14.1.
(a)
Assume t h a t
f E c[[OJ1]xRnxRnJRn]
and
A ~ , A a~r e p o s i t i v e
d e f i n i t e o r i d e n t i c a l l y zero; (b)
v
E
c ( 2 ) [ [ 0 , 1 ] XRnrR+],
g E C [ [ O J ~ ] X R + X R ~ R -g](~t , u , v )
each
( t J v ) ; and f o r
(t,X,X')
E
V(t,x)
i s positive definite,
i s nonincreasing i n [0,1] X R n X R n ,
(1.14.10) Vg(tJx) > g ( t J V ( t J x ) J V ' ( t J x ) )+ v / l f ( t J X J X ' )( 1 )
87
u for
u>oJ
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
where V'(t,x) = Vt(t,x) VF(t,x) = Vtt(t,x)
+ vx(t,x) x ' , + 2Vtx(t,x)
+ vx(t,x)
x ' + Vxx(t,X)X'
x'
f(t,x,x');
( c ) The boundary conditions (1.14.2), (1.14.3) imply, for
some a 2 0,
that
(1.14.12)
2 0, V'(l,x(l)) 5 V(O,X(O>) 5 (Yv'(O,x(O)); V'(O,x(O))
(d) G that f o r
u
E
and there e x i s t s an L
C[[O,l]R',R]
2 L,
t
E
7 E
and
>
0
such
[O,11
(l/u)g(t,u,v) and f o r any
0
-
(V/UI2
2 G(t,v/u)
(0,1], the l e f t maximal solution
r(t,7,0)
of Z'
= G(t,z),
Z(2)
= 0
s a t i s f i e s the inequality r(t,T,O) < ao, t E [O,T], where = min(+,l/a), (e) the l e f t m a x i m a l solution r ( t , l , O ) and the r i g h t minimal solution p(t,O,O) of a.
v ' = g(t,2L,v) exist on
[0,11.
Then there exists a solution x boundary value problem (1.14.1) Proof:
E
C(2)[[0,1],R
- (1.14.3).
Define the function
88
6(u,v)
dl
of the
on R+xR+
as
1.14. FURTHER RESULTS FOR SYSTEMS
osu, (1.14.1'3)
vLB,
( 1 i B - v),
O l u l B l v l B + 1,
(l+B-u)(l+B-v),
Blu,
0 5 v_
~ ( u , v )=
vlB+1,
otherwise. Next define t h e modified function
F
of
f
on
d d [0,1]X R X R
by
(1.14.14)
F(t,x,x'
Clearly t h e function [0,1] xRdxRd.
F
= S(llxll, IIX' Il)f(t,XjX'
1.
i s continuous and bounded on
Hence t h e r e e x i s t s a solution
x
E
C(*)[[O,l],R
d
]
of the boundary value problem
(1.14.15)
X"
= F(t,x,x'),
Set m(t) = V ( t , x ( t ) )
x(O)-Ax'(O) = 0 ,
X(1) + A I X ' ( l ) = O *
so t h a t , because of assumption ( c ) , we have
the r e l a t i o n s
which leads t o t h e f u r t h e r inequality
(1.14.18)
m"(t)
_> .g(t,m(t),m'(t)) + allx"(t)ll.
Hence, by Lemma 1.14.1,
it follows t h a t t h e r e exists a Bo > 0
such t h a t
89
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
As a result, s e t t i n g
-N = [min g(t,u,v): 0 ,< t 5 1, u ,< Bo, Ivl ,< Bol, we obtain from (1.14.18) m"(t) Thus, for 0
5
s
5
t
2 -N+ullx"(t)ll.
5 1,
2 IIx'(t)ll- IIx(l>ll- IIx(O)ll. Since V(t,x) i s assumed t o be positive definite, it follows, from the estimate V ( t , x ( t ) ) = m(t) 5 Bo, 0 5 t 5 1, t h a t (lx(t)II 5 B*, 0 5 t ,< 1. Consequently, we deduce that Ilx(t)ll
5 a*+
(2Bo +N)
O < t l l .
"B,
Eivdently, t h i s implies t h a t (1.14-19)
IIX(t)ll
€3
IIX'(t)ll
and
This, i n view of the definition of
5
B,
0
5 t 5 1,
assures us t h a t x ( t ) is actually a solution of t h e boundary value problem (1.14.)(1.14.3). The proof i s cmplete.
90
F,
1.14. FURTHER RESULTS FOR SYSTEMS
If f satisfies Nagumo's condition, assumption (1.14.10) may be weakened as the next theorem shows.
THEOREM 1.14.2. Let the hypotheses of Theorem 1.14.1 hold except that inequalities (1.14.10) and (1.14.U) are replaced by
2 g(t,V(t,x),V'(t,x))
(1.14.20) V;(t,x)
(1.14.21)
U(t,X,X')
+ u ~ ~ x ' ~ ~u,> 0,
+ 1 ,> IIX'II.
Suppose that Ilf(t,x,x')ll 5 h JJx'/Ifor (t,x,x') E [0,1] xRnxRn, and s ds/h(s) = 00. Then there where h E C[R+,(O,.o)] exists a solution x E C(2)[[0,1],Rn] of the boundary value problem (1.14.1) (1.14.3).
-
Proof:
We proceed exactly as in the proof of Theorem 1.14.1 until we arrive at inequalities (1.14.16). Consider first the case when u 11. Then, in view of (1.14.17), relations (1.14.20) and (1.14.21) yield the inequality (1.14.22)
Vi(t,x)
2 g(t,V(t,x),V'(t,x)) + (1-S,[IIx'II
-> g(t,V(t,x),V'(t,x))
z g(t,V(t,x),V'
+ u6I]x'II
- 13 -1+
IIx'~~[~(u1)+ 1 I
-
I(x'11,
(t,x>) 1
+
using the facts g 5 0, 0 5 S 5 1. Here we have used 6 for 6(u,v). If, on the other hand, 0 < u < 1, noting that (1.14.21) implies uIIx'(I 5 1 + U(t,x,x'), we obtain
(1.14.23)
Vi(t,x)
g(t,V(t,x),V' +
(t,x))
-t
u6IIx'11
(1-E)[ullx'II -13
,> g(t,V(t,x),V'(t,x))
-> g(t,V(t,x),V'(t,x)) 91
- 1 + IIx'II[uS + (1-s)al
- 1 + u(Jx')(.
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Since by L a m a 1.14.1 we have
inequalities (1.14.22), (1.14.23) lead to m"(t)
2- ( N + 1 ) +
m"(t)
2- ( N + 1 ) + ollx'(t)ll,
IIx'(t)ll
and respectively, where, as before,
It then follows that 0 ( l ) From Lemma 1.12.1, we have IIX'(t>jl
5 (2B0 + N +l)/o
L r ( e W ) 5 ?(MI,
Letting B = m[B*,y(M)], the proof as before.
0
M
L
t
5
in any case. 1.
we obtain (1.14.19)which concludes
Finally, for later use, we shall state a uniqueness result leaving the proof as an exercise. THEOREM
1.14.3. Assume that f
V 6 C(2)[[0,1]xRnXRn,Rf], X = Y and
V(t,x,y)
E
C[[O,1] xRnxRn,Rn], 0 if and Only if
1.15, NOTES AND COMMENTS
Then the BVP (1.14.1), one solution.
x(0) = xo and x(1)
=
x has at most 1
1.15 NOTES AND COMMENTS For the existence results in the small contained in Section 1.1, see Hartman [31, Jackson [2], and Bailey, et al.
[31. The results of Sections 1.2 and 1.3 are taken from Jackson [2] except Theorems 1.2.4 and 1.3.2 which are based on the work of Schmitt [5]. Theorem 1.4.1, the Nagumo's condition, is taken from Jackson [2], while Theorems 1.4.2 and 1.4.3 are adapted from Schmitt [2] and Ako [I.], respectively (see also Hartman 133). Theorem 1.5.1 is taken from Jackson [21. Theorems 1.5.2, 1.5.4 are due to Erbe [l] and Theorem 1.5.5 is due to Schmitt [2]. The results of Section 1.6 are due to Bernfeld et al. [l]. Fxercise 1.6.1 contains the work of Schrader [2]. See George and Sutton [l] for the use of Wapunov-like functions. The contents of Sections 1.7-1.10 are taken from Jackson [2] where other related references may be found. The work contained in Sections 1.11-1.13 is due to Bernfeld et al. [41 except Lemma 1.12.1which is due to Lasota and Yorke [13]. The definition of the modified function as given in Definition 1.11.3 may be found in Hartman [31 where a number of results for second-order systems are given. The contents of Section 1.14 are due to Bernfeld et al. [j]. For further results in this direction, see Hartman [?I. For related results, see Knobloch [1,21, Schrader [5,61, Jackson and Schrader 111, Schmitt [31, Moyer [l], Gaines [3,41, Halikov [l], Gudkov and Lepin [l], Gudkov [21, and Mamedov [l].
93
Chapter 2 SHOOTING TYPE METHODS
2.0
INTRODUCTION
This chapter is essentially divided into two parts in which the shooting method serves as the underlying technique. The first part is concerned with the question as to whether uniqueness of solutions of boundary value problems implies the existence of solutions. Although the interdependence between uniqueness and existence is complicated for nonlinear equations, it can be formulated in simple terms for second-order differential equations. We examine this problem under linear and nonlinear boundary conditions and show that the results obtained are the best possible. The second part is devoted to an hportant method known as the "angular function technique." A number of results concerning existence, uniqueness, and criteria for existence of a finite OF infinite number of solutions are studied using this method as a tool. Einploying Lyapunov-like functions and the theory of differential inequalities, this technique is extended to cover nonlinear boundary conditions and systems of differential equations. 2.1
UNIQUENESS IMPLIES EXISTENCE
For linear differential equations, it is well known that the uniqueness of solutions implies the existence of solutions. For nonlinear equations the interdependence between uniqueness and existence is much more complicated. However, in the case of second-order differential equations this relationship can surprisingly be formulated in simple terms.
94
2.1. UNIQUENESS IMPLIES EXISTENCE
An extremely useful technique in handling these questions for second-order boundary value problems is the so-called shooting method. The idea of this method is to fix one initial value and to allow the slope at the initial point to vary through the real numbers. From the connectedness of the solution funnel and the uniqueness of BVP‘s, it is then possible to show that the values of the solutions at the final point cover the real line. In what follows we plan to illustrate this important technique in a detailed manner. Our discussion depends on the following variation of Kneser’s theorem. LEMMA 2.1.1. Consider the initial value problem X’ =
F(t,x),
x(to>
= X0’
where F E CCRXRn,Rn 1. Let S be any compact, connected set. Assume all solutions x(t,tO,xO) exist on [tO,tl]. Then
is a compact, connected set. Our first result will be concerned with a system of two first-order equations subject to simple boundary conditions. Consider the differential system x ’ = f(t,x)
(2.1.1)
with the boundary conditions Xl(tl)
(2.1.2)
where f result.
E
C [R x R ,R
Xl(t2)
=
2 2
= C2’
1. For this problem we have the following
95
2 , SHOOTING TYPE METHODS
0
J
THEOREM 2.1.1. =
(a,b).
Let J
=
(a,b],
-m
5 a < b < m, and
Assume
(i) fl(t,xl,x2) is an increasing function of x2 for fixed (t,x,) satisfying fl(t,xl,x2) + & m as x2 + k m uniformly on compact sets in (a,b)xR; (ii) all solutions of (2.1.1) exist on J; (iii) there exists at most one solution of (2.1.1), 0 (2.1.2) for all tl,t2 E J and all cl, c2. Then every BVP (2.1.1), (2.1.2) has exactly one solution 0 if tl E J , t2 E J. Proof: We may assume without loss of generality t2 = b. Let tl, c1 be given where a < tl < b. Let x(t) = be a solution of (2.1.1) satisfying the initial (x,(t),x,(t>) condition
Then define
S = [x(b): x(t) is a solution of (2.1.1) k satisfying (2.1.3) for each Irl 5 k]. By Lemma 2.1.1,
N
is connected. Let Sk be the projection of Sk on the x axis. Hence S is an interval which is 1 $ 0 nondecreasing in k. Define S = - Sk; then is an interval. To prove the stated result, it is sufficient to show S = (-m,m). If this is not true, suppose that S is bounded above. A similar proof holds if is bounded below. Then c (-m,M) for some M > 0 . Let xn(t) be a sequence of solutions of (2.1.1) satisfying Sk
-
N
z
&
N
N
s
(2.1.4) If s1,s2,
xn(tl)
...,sn
=
(cl,n),
n
=
,... .
1,2
is a sequence of t-values on a compact 96
2.1. UNIQUENESS IMPLIES EXISTENCE
f o r otherwise, from the well-known convergence theorems a subsequence of
[x ( t ) ]
n
converges uniformly t o a solution of
(2.1.1)J on a l l compact subsets of
J
0
,
a contradiction t o
(2.1.4). Let
x ( t ) be the f i r s t component of x n ( t ) . Observe n, 1 t h a t ~ ~ + ~ ,> x~n J( l (t t )) and x (s) < x (s) f o r n+l, 1 n, 1 t E (t,,6] and s E [ t l - 6 , t 1) f o r s u f f i c i e n t l y small 6. However, from ( i i i ) we immediately obtain
for
a < s < t l < t < b .
W e claim t h a t the sequence x
bounded on any subinterval of there e x i s t s a
C
J
0
.
n,l
(t) is not uniformly
If we assume not, then
> 0 and an i n t e r v a l [al,bll
such t h a t
From the mean value theorem
Ix ( t ) l 5 C f o r t E [a,,b,I. n, 1 there e x i s t s rn E [a J b ] such t h a t /xh,l(rn)( 52C/(bl- al). 1 1 Then condition ( i ) implies llxn(rn)ll i s bounded f o r all n. However, t h i s contradicts (2.1.5). of
[ t l - 6m,tl],[tl,tl+6m]
uniformly bounded. vn, wn
Letting
Hence, on any subintervals [x ( t ) l i s not n, 1 we see there e x i s t points
the sequence 6m + 0
where vn < tl,
v +t n 1’
wn>
w +t
n
1
such that, i n view of (2.1.6),
(2.1.7) as
n
x
n,l
(v ) n
+-m
and
xn,l(wn>
++a0
+m.
Let x*(t)
be any solution of (2.1.1) satisfying
91
2. SHOOTING TYPE METHODS
x*(b) = M; hence, since S E (-m,M),xT(b) 1 n. From (2.l.7), f o r l a r g e n
x ( t ) and xT(t) n, 1
This implies
d i c t i r q assumption ( i i i ) .
> xn,l(b)
for a l l
i n t e r s e c t twice, contra-
This completes the proof of Theorem
2.1.1. COROLLARY 2.1.1.
where
Consider the BVP
h E C[JxRxR,R], J = (a,b]. (i)
Assume t h a t
a l l solutions of (2.1.8) e x i s t on
(a,b];
( i i ) t h e r e e x i s t s a t most one solution of (2.1.8), (2.1.9) f o r tl,t2 E (a,b], c1,c2 E R. Then there e x i s t s exactly one solution of (2.1.8) and (2.1.9). Proof:
The BVP (2.1.8),
xi
= x2,
(2.1.9) can be w r i t t e n as = h ( t , x ,X
X'
1 21,
2
x (t ) = C2' 1 2
x ( t ) = c 1 1 1'
We see immediately t h a t t h e conditions i n Theorem 2.1.1 a r e satisfied.
Hence Corollary 2.1.1 follows.
EXERCISE 2.1.1.
suppose t h a t
Consider t h e BVP (2.1.8),
h(t,x,x')
is s t r i c t l y increasing i n x.
Assume that a l l solutions of (2.1.8) exist on there e x i s t s exactly one solution of (2.1.8),
tl,t2
E
(a,b]
Hint:
and a l l
(2.1.9) and
c1,c2
E
(a,b].
Then
(2.1.9) f o r a l l
R.
Show t h a t there exists a t most one solution by 98
2.1. UNIQUENESS IMPLIES EXISTENCE
showing t h a t t h e difference of any two solutions cannot a t t a i n a positive maximum o r negative minimum.
Then use Corollary
2.1.1. EXERCISE 2.1.2.
Assume
h(t,x,x')
satisfies
where
Then (2.1.8),
Hint:
(2.1.9) has a unique solution. Show t h a t t h e inequality
q(t)ixl + p(t)lx'I
lx"I
with boundary conditions x ( t l ) = 0, x(t,) = 0 has only the zero solution, where I t2- t I C b a. Then use Corollary 1 2.1.1.
-
Observe t h a t i n Theorem 2.1.1we obtained t h e existence of a solution on
(a,b].
t h a t we cannot s u b s t i t u t e EXAMPLE 2.1.1.
I n t h e following example we show [a,bI
for
(a,b].
The implicit equation
P > -2,
cp + (P/2) t a n - l cp = 9,
The family of a l l solutions of
has a unique solution cp(p,q). (2.1.10)
x'1 = - x +
1
3
tan-'
cp(sin t , x sin t
+
x ' cos t )
can be represented by x ( t ) = A cos t where A
and
B
+
B sin t
+ 3 tan-1 B,
a r e a r b i t r a r y constants.
Consider the
boundary conditions ( 2 . 1 . ~ ) x ( t l ) =xl
and
x ( t2 ) = x2, 99
tl,t2
E
[o,~].
2 . SHOOTING TYPE METHODS
Then x i
=
A cos ti + B sin ti +
Eliminating A, (2.1.12)
1
2
tan-1 B,
i
=
1,2.
we obtain
-
B sin(t2 t ) + ~ ( C O Stl - cos t2) tan-1 B 1 = x2 cos tl- x cos t2' 1
We now claim that there exists at most one solution of (2.1.10), (2.1.11). If 0 5 t l < t2 < T or 0 < t < t2 5 T , then 1
sin(t2- tl) > 0
cos t2- cos t < 0 . 1
and
Thus from (2.1.12), we see that, for any xl, x2, tl, t2, B and A are uniquely determined. Thus solutions of (2.1.10), (2.1.11) are uniquely determined. For the case t = 0, t2 = 7, (2.1.12) reduces to 1 (2.1.13)
tan-'
B
=
x1 + x2'
Once again uniqueness of solutions foUows. Thus on [ O , T ] the conditions of Corollary 2.1.1 hold. However, observe (2.1.13) implies there exists no solution, if )x1+x21 = T/2EXERCISE 2.1.3.
(2.1.14)
Show that solutions of y"
=
-y + arctan y,
(2.1.15)
when they exist, are unique for t ,t E [ 0 , 7 ] . Then show 1 2 there exists no solution of (2.1.14) satisfying (2.1.16)
Hint:
Y(0)
= 0,
Y(T)
=
3T.
Assume there exist two solutions y,(t),
100
y,(t)
of
2.2, GENERAL LINEAR BOUNDARY CONDITIONS
(2.1.14), y,(t)
tlyt2 E
(2.1.15) f o r
- y2(t)
satisfies
i s a subfunction of subinterval of W(T) > u(T),
w"(t)
y" = -y. ul' = -u
u ' ( ~ / 2 ) . Prove that
u(t)
leads t o a contradiction. of (2.1.15), (2.1.16), vl' = -v
and
Argue .that y(T) y(O) = 0 , ~ ' ( 0 )= m.
m.
and
x'.
> u(O),
has two zeros on
[O,T]
which
To show t h e r e exists no solution
~ ' ( 0 )= m
+ 1,
of
[O,T]
with respect t o (2.1.14) f o r any
< v(T)
= 2T,
where
y
s a t i s f i e s (2.1.14),
I n t e r e s t i n g l y enough we can, under c e r t a i n derive t h e r e s u l t s of Corollary
2.1.1 f o r t h e case when J = [a,b]. h
i s not a proper
w(0)
v(t)
conditions on h ( t , x , x ' ) , example, t h a t
w(t)
w ( ~ / 2 )= u ( T / ~ ) , w ' ( T / ~ )=
v(0) = 0 ,
i s a subfunction on
and prove that
[tlyt2]
If
=
w(t)
prove t h a t t h e solution
+ T,
REMARK 2.1.1.
2 -w(t)
then show that
[O,T], where
Show t h a t
(0,T).
It i s s u f f i c i e n t , f o r
s a t i s f y a Lipschitz condition i n both x
This follows by considering t h e l i n e a r equation
derived from t h e Lipschitz condition, and using t h e f a c t t h a t t h e uniqueness of t h e BVP f o r t h e l i n e a r equation on a l l subi n t e r v a l s of
implies t h e existence of unique solutions
[a,bl
on a l l subintervals of
of BVP's f o r x" = h ( t , x , x ' ) Moreover, an estimate of
[a,b]
[a,b].
can be derived i n terms of
hyperbolic f'unctions. 2.2
GENERAL LINEAR BOUNDARY CONDITIONS "he question as t o whether uniqueness of solutions of
(2.1.8) with t h e general l i n e a r boundary conditions (2.2.1)
alx(tl)
+
ap'(tl)
= cl,
blx(t2)
+ b p ' ( t 2 ) = c2
implies existence i s n a t u r a l l y more d i f f i c u l t since it depends upon t h e c o e f f i c i e n t s
al,
a2, bly b2.
101
2. SHOOTING TYPE METHODS
We shall show, as a consequence of our next result, that Corollary 2.1.1 holds for (2.1.8) and (2.2.1) whenever a2b2 = 0 . THEOREM 2.2.1. Let J, x, f be as in Theorem 2.1.1 except that condition (iii) is replaced by the following:
(iv) there is at most one solution of (2.1.1) satisfying (2.2.2)
x1(t1)
for any tl,t2
E
=
J
0
c1
and
x2(t2)
and c1,c2
E
=
c2'
tl
#
t2'
R.
Then (a) every boundary value problem (2.1.1), (2.1.2) has a unique solution; (b) every boundary value problem (2.1.1), (2.2.2) has a unique solution. Proof: In order to show (a), we must show condition (iii) of Theorem 2.1.1 holds. Let x(t), y(t) be distinct solutions 0 of (2.1.1) satisfying xl(tl) = y (t ) for some tl E J It 1 1 0 suffices to show that xl(t) # yl(t) for tl f t E J We show this for tl < t < b as a similar argument holds for Without loss of generality, we may assume from t E (a,t,). (iv) that y,(t) > x2(t) for t E (tl,b). Then either
.
.
Y2(t1> = X2(tl) or Y2(t1> > X2(tl)' If Y (t 1 = X2(tl)' 01 then, by (iv), yl(t) f x,(t) for tl # t E J If then yi(t,) > xi(tl) by (i), so that there y2(tl) > x2(tl), exists a 6 > 0 such that yl(t) > x,(t) for t E (tl,tl+6). Assume that there exists a least T,tl< 7 < b such that xl(T) = yl(T). However, then ~'(7) 2 y'1(T), which implies 1 x2(T) 2 y2(T). This contradiction shows that xl(t) # yl(t) on (tl,b) and thus completes the proof of part (a).
.
102
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
The proof of part (b) i s similar t o t h a t of Theorem 2.1.1.
t2 =
Assume without l o s s of generality t h a t Define
Sk a s i n Theorem 2.1.1 and l e t
projection of
3
on t h e
Sk
i s an i n t e r v a l . A
bounded below).
3
axis.
Let
It suffices t o show
s^
3 =U,
m
be t h e r
z
but
$
(--,MI
2.
then
S,;
i s the r e a l l i n e .
We may assume t h a t t h e r e e x i s t s
(-m,M)
C
x2
8,
i s bounded above ( a similar proof holds i f
Suppose S that
b.
M
A s before, l e t
^s
>0
is such
xn(t)
be
a sequence of solutions of (2.1.1) s a t i s f y i n g
n
xn(tl) = (c,,n),
(2.2.3)
= 1,2
,... .
Then there e x i s t sequences
such t h a t (2.1.7) holds vn, "n [ t h i s follows since ( a ) i s the same as ( i i i ) i n Theorem 2.1.11.
From (2.2.3) there e x i s t s a sequence {zn] such t h a t t
+ t l and xn2(zn) 1 n solution of (2.1.1) s a t i s f y i n g
as
n
403.
x*,(b) = M.
Let
x*(t)
be any
From t h e f a c t t h a t
^s c (-m,M), xz(b) > xn2(b) f o r a l l n, but f o r l a r g e x:(zn) < xn2(zn). Thus there exists zk such t h a t
n
(2.2.4)
From (2.1.7)
< x,(wn),
x;(wn)
so t h a t t h e r e e x i s t s
zk
1
#
d',
> xnl(vn)
n
v n
n
and
n
< znt t < wn.
then (2.2.4) and (2.2.5) contradict ( i v ) .
Suppose z ' = z t t - then define x ( t ) = x n ( t )
n
for large
such t h a t
z"
X*(Zt') = Xd(ZB),
(2-2-5) If
xT(vn)
n'
x ( t ) = x*(t)
for
of (2.1.1)
such t h a t
x*,(b) = M,
so t h a t
z'
n
Gl(tl)
(--,MI
< t 5 b. = xnl(tl) E
3,
for
Then x ( t ) = c1
a
zk,
i s a solution
and x2(b) =
a contradiction.
This
completes t h e proof of Theorem 2.2.2. COROLLARY 2.2.1.
Consider t h e BVP (2.1.8),
103
(2.2.1) and
2 . SHOOTING TYPE METHODS
assume
a2b2 = 0.
Suppose a l l s o l u t i o n s of (2.1.8)
e x i s t on
( a , b ] and t h e r e e x i s t s a t most one s o l u t i o n o f (2.1.8), (2.2.1) f o r every tl,t2 E ( a , b ) . Then t h e r e e x i s t s
b
(a)
a unique s o l u t i o n o f (2.1.8),
(2.l.g),
(b)
a unique s o l u t i o n o f (2.1.8),
(2.2.1).
Proof: -
2
= 1 and
Without loss of g e n e r a l i t y , assume a1 = 1. Then (2.1.8),
a s t h e f i r s t - o r d e r BVP f o r X'
1
L-
x2-b x 1 1'
X$ =
x
=
(2.2.1)
(xl,x;
h(t,Xl,x2
+
a2 = 0,
can be w r i t t e n
blxl)
- b 1x 1)
and
i n which
+ bl(X2
- blxl),
We t h e r e f o r e see t h a t t h e hypotheses o f Theorem 2 . 2 . 1 h o l d and t h e r e s u l t follows. Assume i n (2.1.8) t h a t t h e f u n c t i o n
EXERCISE 2.2.1. h(t,x,y) lhxI 5 M, for
E
2
C(l) [ (a,b) xR , R ] s a t i s f i e s t h e i n e q u a l i t i e s IhyI 5 K. If I b - a l < l y / b ((u 2 +Klul +M)-')du
al = 1, a2 = 0, bl = 1, b2
#
0,
2
then t h e BVP (2.1,8),
(2.2.1) has a unique s o l u t i o n .
Hint: -
Prove (2.1.8), (2.2.1) has a t most one s o l u t i o n .
!Phis can be done by assuming t h a t t h e r e e x i s t s o l u t i o n s x2
a n d b y s e t t i n g x = x1-x2
obtain
xl,
lx"I < Mix1 + Klx'I,
x ( t ) = 0, x ( t 2 ) + b 2 x T ( t 2 )= 0. Then l e t t i n g w = x ' / x , 1 < w2 + KIWI + M, w ( t l - 0 ) = + m and w(t 2 ) = -l/b2. deduce ( w ' 1 By t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s conclude t h a t
w(t) < u ( t ) ,
where
-u' = u2
u(t)
+
i s the solution of
Klul + M,
F i n a l l y o b t a i n a contradiction. 104
u(t2) =
- l/b2.
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
I n t h e next two examples, we show t h a t Corollary 2.2.1 does not necessarily hold without t h e assumption t h a t a2b2 = 0 . EXAMPLFi 2.2.1.
(2.2.6)
The equation
2t l + t2
=
2 - x, 1+t2
X'
has the general s o l u t i o n x ( t ) = A(t2
-m
- 1) + B t .
+m
Hence there
e x i s t s one solution s a t i s f y i n g t h e boundary conditions x l ( t , ) = c1,x1(t2) = c2.
Observe
x 1( t )
are two d i f f e r e n t solutions s a t i s f y i n g
and
0
x2 ( t )
p
x(-1) = 0, x(1) = 0.
Moreover, t h e r e e x i s t s no solution s a t i s f y i n g
x(-1) = 0,
x(1) = 1. Thus (a) i n Corollary 2.2.1 i s violated.
EXAMPLE 2.2.2.
Let
be defined as i n Example 2.1.1.
Cp
Consider t h e d i f f e r e n t i a l equation
with t h e boundary conditions xt(t,)
- x(tl)
x ' ( t 2 ) - x ( t 2 ) = r 2'
= r 1'
The family of solutions of (*) i s given by x(t) = A where
A
and
B
+
Bet + t tan-'
B,
a r e a r b i t r a r y constants.
conditions lead t o ( l - t i ) tan Eliminating A
-1
B-A=
we obtain (tl
- t2)
tan
-1
105
B = r
2-rl
The boundary
-
t2 1
2 . SHOOTING TYPE METHODS
and thus t h e r e e x i s t s a t most one s o l u t i o n of t h e BVP.
How-
ever, i f
-
Ir2 rll _> (7J/2) It2-t1I, t h e r e e x i s t s no s o l u t i o n .
Hence (b) i n Corollary 2.2.1 does
not hold. When (2.2.7)
a2b2
#
rx(tl)
we can r e w r i t e (2.2.1) i n t h e form
0
+
x l ( t ) = c 1’ 1
s x ( t 2 ) + x l ( t2 ) = c
2‘
We now present a r e s u l t i n which uniqueness of (2.1.8) and (2.2.7)
implies existence under c e r t a i n added conditions.
-
Consider t h e ordering on
(al,bl)
Write
I: (a0,b0) (al,bl)
defined a s
R2
a. < bo
and
a1
5
a.
and
bl
3 bo,
> bo
and
a
2
a.
and
b
5
a.
1
1
bo.
< (aO,bo) when (al,bl) 5 (aO,bo) and
(al,bl) # (aO,bo). noted by ( h ; r , s ) . THEOREM 2.2.2.
Problem (2.1.8) and (2.2.7) w i l l be de-
Assume a l l s o l u t i o n s of (2.1.8) e x i s t on
(a,b) and a r e uniquely determined by t h e i r i n i t i a l values. Assume problem ( h ; r o , s O ) i s unique f o r any tl,t2 E (a,b), then t h e r e e x i s t s a unique s o l u t i o n o f
(h;rl,sl)
whenever
(rl,sl) < (r0,so)* Proof:
Assume t h a t
The o t h e r cases have s i m i l a r arguments and t h e r e f o r e we s h a l l consider t h i s case only. x(t,v)
Fix
tl, t2, and
c1
be t h e s o l u t i o n of (2.1.8) s a t i s f y i n g
106
and l e t
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
x ( t 1, v ) = v,
x'(t,,v)
= cl-r
+
soX(t,v).
0
v.
Define T(t,v) = x ' ( t , v )
(h;ro,sO), v + T (t , v )
From t h e uniqueness o f mapping f o r
t
1 tl.
Define
( T(t,v2)
AT/Av Then
AT/&
t'tl f o r a l l t 2 tl.
=
i s a one-to-one
-ro + so
>
- T(t,vl))/(v2 - vl). 0.
Thus
+
so h / A v
AT/Av
i s positive
'ken, s i n c e
AT/Av = h ' / A v
>
0,
we see t h a t
Setting S(t,V) = x ' ( t , V ) + SIX(t,V) = T(t,V)
Hence
v +S(t2,v)
+
(sl
- S,)X(t,V),
i s a one-to-one mapping of
This i s equivalent t o
(h;rl,sl)
R
onto i t s e l f .
having exactly one s o l u t i o n
and thus t h e proof i s complete.
i s s t r i c t l y increasing and t h a t s o l u t i o n s of (2.1.8) e x i s t on (a,b) and a r e
COROLLARY 2.2.2. in
x
Assume
h(t,x,y)
uniquely determined by i n i t i a l conditions.
s
> 0,
problem (2.1.8),
Then, f o r
(2.2.7) has a unique solution. 107
r < 0,
2 . SHOOTING TYPE METHODS
Proof:
ro, so
To prove t h i s , choose
r < ro < 0 , 0 < so < s .
Hence
(r0,so) > (r,s) and by it s u f f i c e s t o show (h;ro,sO) i s unique.
Theorem 2.2.2,
Assume t h e r e e x i s t two s o l u t i o n s x = x1-x2.
and x2 and l e t 1 attains either its
x ( t ) f 0, x ( t )
Since
x
p o s i t i v e maximum o r negative minhum on x
such t h a t
Assume t h a t
[tl,t2].
a t t a i n s i t s p o s i t i v e maximum (the case i n which
i t s negative minimum uses a similar argument).
tl,
occurs a t
then
maximum occurs at
t h e second condition
s x(t ) 0
to
t h e maximum occurs at
>
x'(tl)
5
If t h e maximum
and t h e f i r s t
0,
r o x ( t ) + x ( ) = 0 cannot hold. If t h e 1 ' t2, then x ( t 2 ) > 0, x ' ( t 2 ) 2 0, and
boundary condition
x(t,)
> 0,
x(tl)
x attains
2
E
+
xt(t,) = 0
(tl,t2),
x ' ( t o ) = 0,
0,
however, by t h e monotonicity o f
cannot hold.
If
then x"(to)
h(t,x,x'),
5
0;
we have
a contradiction.
I n t h e next e x e r c i s e , we show t h a t t h e s t r i c t i n e q u a l i t y (rl,sl)
< (ro,so) cannot be weakened t o t h e i n e q u a l i t y
(rlYs1) 5 (ro,so). This w i l l provide another example i n which a2b2 # 0 and uniqueness o f t h e boundary value problem does not imply existence. EXERCISE 2.2.2.
Construct an example i n which t h e
hypotheses of Theorem 2.2.2 hold with replaced by t h e weaker condition
( y l ) < (ro'so) (rl,sl) 5 (ro,so) such
t h a t t h e r e e x i s t s no s o l u t i o n of t h e problem (2.1.8), (2.2.7).
Hint:
Let
Cp(p,q)
CP + p a r c t a n CP = q.
be t h e s o l u t i o n of t h e equation
Consider t h e d i f f e r e n t i a l equation 108
2.3. WEAKER UNIQUENESS CONDITIONS XI'
= F"cp(l/F',
x t / F t ) on t h e i n t e r v a l
w i l l be determined.
Let
w = x';
(-1,2),
w
then
where
F
s a t i s f i e s the
general solution
+
w ' ( t ) = BF'(t)
Solve f o r
x(t)
i n terms of
w(t)
conditions, where we may assume conditions on
F(tl),
This leads t o
1 where
F2
+
-r ( t + l )
1. Then obtain
t
F'(t)
>0
E
[-LO],
6
[0,11,
E
[1,21,
on
satisfies
tl
=
I (rc2 - c1)/(2r
-
F2(0) = 1 e'r, g(0) = l / r t g(1) = 1, g ' ( 0 ) = g'(1) = 0. Show
such t h a t
-4,t2 = 3/2 - 1)I 2 T / 2 ,
-< 1,
and
and f o r cl, c2 chosen so t h a t t h e r e e x i s t s no solution o f
(Use ideas i n B m p l e 2.1.1,)
(2.1.8) and (2.2.7). 2.3
>
t t
( ~ ~ (- 1l)el-t, )
i n which g 6 C ( l ) [ [ O , l ] , R ] l/r < g ( t ) < 1 for 0
tha t for
s = 1, r
and such t h a t
F2 + g(t)F; = 1,
-
and s u b s t i t u t e t h e boundary
F f ( t l ) , F ( t 2 ) , F 1 ( t 2 ) such t h a t unique-
ness holds (see Example 2.1.1) (-1,2).
a r c t a n B.
WEAKER UNIQUENESS CONDITIONS
It i s n a t u r a l t o ask whether it i s possible t o weaken t h e uniqueness condition of t h e BVP (2.1.8), (2.1.2) by not demanding t h a t t h i s condition hold f o r a l l tl,t2 [a,b+&) (or
tl,t2
E
(a-&,b]).
6
I n t h i s section, we plan
t o discuss how some of t h e previous r e s u l t s remain t r u e even when t h e uniqueness assumptions a r e weakened f o r and f o r
t2
E (b
- &,b + E )
THMlREM 2.3.1.
Let
f o r some h
6
E
>
0.
C[[a,b+E) xR2,R]
109
t1 = a f o r some
2 . SHOOTING TYPE METHODS
>
E
and suppose t h a t a l l s o l u t i o n s of i n i t i a l value problems
0
[a,b + E).
f o r (2.1.1) e x i s t on
Assume t h a t f o r a f i x e d
t h e r e e x i s t s a t most one s o l u t i o n on
[a,t2]
c
o f t h e BVP
1
(2.1.1) and (2.3.1)
.(a)
for a l l
= c1 '
and t2
c2 E R
x ( t 2 ) = C2'
(b
E
- E,
b + E).
Then t h e r e e x i s t s
e x a c t l y one s o l u t i o n of (2.1.1) and (2.3 - 2 )
.(a)
f o r each
= cl,
x ( b ) = c2
c2 E R. For each m E R
Proof:
define
Am = [x(t,m) E C ( 2 ) [[a,b
+E)
x R , R ] : x(t,m)
i s a s o l u t i o n of (2.1.1) with
x(a) = c
x ' ( a ) = m].
and Define t h e mapping
r(m) = [x(b,m)]; I?
maps p o i n t s i n t o s e t s
and an a p p l i c a t i o n of Lemma 2.1.1 y i e l d s t h a t connected s e t s i n t o compact, connected s e t s . then
i
5
r(m)
m <m2 < m 1
r(mi).
m2 < m
t h e BVP.
3
Since
there exists
m*
ml
#
m2,
5 max r(m2).
We now show E
maps compact,
fl r(m2) = $, because of t h e uniqueness of s o l u t i o n s We can thus define r(m,) 5 r(m2) i f and only i f
max r(m,)
x
r
If
r(ml)
of BVP.
that
1
m*
3'
E
i s monotone.
Assume, f o r example,
r(m,) < r(m3) < r(m2). Let < x < x2 and F ( [m ,m 1 ) i s connected, 1 3 1 2 [m,,m2] such t h a t x(b,m+) = x Since 3' and
x
we have a c o n t r a d i c t i o n t o t h e uniqueness of
The o t h e r cases may be t r e a t e d by a similar argument.
I n order t o complete t h e proof of Theorem 2.3.1, enough t o show
r ( R ) = R.
If not, t h e r e exists a
9
We f i r s t prove t h a t E
r(R) 110
r(R)
it i s i s open.
t h a t i s not i n t h e i n t e r i o r .
2.3. WEAKER UNIQUENESS CONDITIONS
Hence there i s an
r
t o n i c i t y of
r ((;,-GI)
m
such t h a t
x(b,m) = JI.
we can find m > m N
contains
-
< m such t h a t
or
as an i n t e r i o r point.
JI
contradict ion.
r(R)
It thus suffices t o prove t h a t
above nor below,
By the mono-
r(R)
Assume
This i s a
i s neither bounded
i s bounded above (a similar
argument i s t r u e f o r the other case) and l e t '1 = sup r(R). L e t xn(t,m ) denote a sequence of solutions of (2.1.1), n (xn(a,mn)) = cl,(x;(a,mn)) = mn such t h a t xn(b,mn) + q . For c E ( b , b + & ) and from the uniqueness of BW,
-
xn(c,mn> xn(b,mn) C-b
where
K = min {0, (x1(c,m,)
> -
- xn(b,mn)
xl(c,ml)
-> K
C-b
- q)/(c - b)].
We m a y assume t h a t , f o r i n f i n i t e l y many nls, we have x;(b,mn) 5 0, because a similar argument can be made f o r c E (b &,b) i n case x;(b,mn) _> 0 f o r i n f i n i t e l y m a n y n ' s .
-
We r e s t r i c t our arguments t o those Let
sn
=
[t:
o> x;(t,mn) 2
n
such t h a t
K, t E [ b , c ~ ] .
This s e t i s nonempty by the mean value theorem.
-
s = min S then b < s n < c and n n' without loss o f generality, sn + s
x;(b,mn)
If
x;(b,mn) x;(t*,mn)
t*
E
<
= 0,
0,
= 0
then
b = s
n then xn(t,mn) < q
x;(b,mn)
0 and.
kt
- n n n 5
K < x t ( s ,m )
0.
Thus,
(s m ) +?,. n n' n xn(sn,mn) < q. If
and
XI
t E [b,t*l, where and t* i s the f i r s t such point. men
Sn and therefore
for
sn E [b,t*].
Thus again xn(sn,mn) < q . [b,c]] (from the
Since xn(sn,mn) _> min [xl(t,mn): t E uniqueness of BVP), there e x i s t s a subsequence of
{xn(sn,mn)] which we choose t o c a l l by the same labeling, such t h a t
-
x (s ,m ) +xo. Thus, sn + s o , x (s ,m ) + x o , x;(sn,mn) + x o . n n n n n n Let S(6) be a 6 - b a l l i n R3 about ( S ~ , X ~ , ~ ~ ) , 111
2. SHOOTING TYPE METHODS
where
6
- so.
E
For
n
s u f f i c i e n t l y large
(snJxn(~nJmn),x~(sn,~n)) E ~(6). Since a l l solutions of (2.1.8) e x i s t on Ix$(t,m,)I
[a,b
there exists
+&),
< Q for t
E
[ a , s O + 6 ] . Let
be solutions o f (2.1.8) with montonicity of X(b9-Q)
2
q
or
x(b,*), x(b,Q)
Q
x(b,-Q)
> Xn(bjmn)
such t h a t
x(t,Q)
x(a,+Q) = cl;
either
>0
and
x(t,-Q)
then by the
> xn(b,mn)
which means
so that
x(b,Q)
2
q.
This i s a contradiction and t h e proof of Theorem 2 . 3 . 1 i s
complete. COROLLARY 2.3.1.
the BVP (2.1.8),
Under the conditions of Theorem 2.3.1,
(2.2.1) has a unique solution, i f
We leave the proof as an exercise.
m a y be helpful.
For a fixed
a2b2 = 0.
The following h i n t s
Consider the boundary conditions
clJ
define
r(m) = [x(b,m): where
x(t,m)
of (2.1.8) such t h a t
x' (.a,m)
= c1
- rlml.
i s a solution
x(a,m) = m
Then using the same techniques as i n Theorem 2.3.1,
and
show
r(R) = R.
By combining the techniques employed i n Theorems 2.1.1 and 2.3.1,
one can deduce t h e following generalization, the
proof of which we leave t o the reader. THEOREM 2.3.2.
Consider t h e BVP (2,1.1),
(2.1.2)
assuming conditions ( i ) and ( i i ) of Theorem 2.1.1.
Suppose
t h a t t h e condition r e l a t i v e t o t h e uniqueness of BVP, i n the sense of Theorem 2.3.1 i s t r u e . solution of (2.1.1),
(2.1.2).
112
Then t h e r e e x i s t s a unique
2.4. NONLINEAR BOUNDARY CONDITIONS
2.4
NONLINEAR BOUNDARY CONDITIONS We now present a r e s u l t i n which t h e boundary conditions
are. nonlinear.
Under some additional hypotheses on h ( t , x , x ‘ ) ,
it i s possible t o deduce existence r e s u l t s f o r general l i n e a r boundary conditions f o r which corollary t o our main r e s u l t . THEOREM 2.4.1.
S1, let
as
x2
-L
g2 (c)
+ y2
--tm
i n e i t h e r direction.
R2
be nonempty.
Assume f o r
t
uniformly f o r
E
(b
- E,b + E)
and a l l
one solution of (2.4.1)
Proof:
f = (fl,f2)
E [a,b+&),
and t h a t a l l
(2.4.2) c E R,
- (2.4.3).
and
g,(x(s),y(s))
= c
there e x i s t s exactly
The idea of the proof i s similar t o t h a t of the
proof of Theorem 2.3.1. gl(x,y) = c1
For every
[ a , b + & ) . men i f there e x i s t s
a t most one solution of (2.4.1),
s
This we s t a t e as a
Y ’ = f2(t,X,Y),
solutions of (2.4.1) e x i s t on for
0.
when parameterized i n terms of a r c length, leaves
every bounded region i n C,
#
Consider t h e boundary value problem
x’ = fl(t,X,Y),
(2.4.1)
then
a2b2
Let
Po
and parameterize 113
be an a r b i t r a r y point of
S1 by a r c length with
Po
2 . SHOOTING TYPE METHODS
a s t h e i n i t i a l point.
The points on
s
For any f i x e d
t h e parameter.
E
S1 w i l l be denoted by
[a,b + E ) ,
define f o r
s1
P E
Ts(P) =
[ (x(S,P),Y(s,P)),
where
(x(t,P),y(t~P))
denotes a s o l u t i o n of (2.4.1) s a t i s f y i n g ( x ( a , p > , y ( a , p > ) = PI, and l e t
rs(p) =
[g2(x(s,p),y(s,p)):
( X ( S , P > ~ Y ( S , P >E ) T ~ ( P > ] .
It i s s u f f i c i e n t t o show rb(R) = R, t o prove t h e theorem. From Lemma 2.1.1, Ts(A) i s compact and connected, i f A
i s compact and connected.
g (x,y) i s continuous, 2 It follows from a simple
Since
i s compact and connected.
rs(A)
argument t h a t
rs(R)
i s connected. rs(P1) n rs(P2) = @ f o r i s an i n t e r v a l o r p o i n t . We
By uniqueness o f t h e BVP, s E (b
- E,b + E ) .
rs
now show t h a t
Thus
r S (P)
i s monotone f o r
s
(b - E,b
E
+ E).
Let
< P2 < P (ordered by a r c l e n g t h ) and assume rs(P2) < 3 rs(P 1) < r s ( P 3 ) ( t h e o t h e r cases follow s i m i l a r l y ) . Let
P1 x
E rs(Pi), i = 1,2,3. Since i t h e r e e x i s t s P*, P2 5 P* < P
Since
P
1
< P2 5 P*,
i s connected,
rs([P2,P3])
E rs(P*). 1 t h i s c o n t r a d i c t s uniqueness o f s o l u t i o n s
- 3
such t h a t
x
of boundary value problems. Assume now
rb(R)
i s not a l l of
R
and t h a t
bounded above [ a s i m i l a r argument holds i f below], that
q
Let E
q = sup rb(R).
rb(R).
(x(t),y(t))
We claim
rb(R)
q d, rb(R).
is
rb(R)
i s bounded Suppose
Then t h e r e e x i s t s a s o l u t i o n of (2.4.1),
s a t i s f y i n g (2.4.2) and g2(x(b),y(b)) = q.
Let
and choose P2, P3 such t h a t P2 < P1 < P 3' Then from t h e monotonicity of rb, e i t h e r rb(P2) > rb(P1)
P1 = ( x ( a ) , y ( a ) )
or
rb(P3)
>
rb(Pl),
Since
q E rb(Pl)
114
t h i s contradicts the
2.4. NONLINEAR BOUNDARY CONDITIONS
maximality of
q k, rb(R).
and thus
q
There e x i s t s
zn
rb(R)
E
such t h a t
zn t q.
To each
t h e r e e x i s t s a unique point P E S1 and a unique s o l u t i o n n n of (2.4.1), ( x n ( t ) , y n ( t ) ) through Pn a t t = a such t h a t z
g2(xn(b),yn(b)) = zn.
Also
qn(t) = g2(xn(t),~,(t)), t
Pn E
i s monotonic i n
n.
Let
[a,b +&I. Then
A s i n t h e proof of Theorem 2.3.1, we want t o o b t a i n a
convergent subsequgnce of i n i t i a l p o i n t s
t
E (b
- &,b+ & ) ,
monotone i n
or
$A(b)
$A(b)
5
-< 0
t
E
(b
i s monotone i n n since {Pn] i s n and BVP's a r e unique. Also, e i t h e r $;(b) $ (t)
n
f o r i n f i n i t e l y many n ' s .
[a similar argument i s v a l i d i f
monotone decreasing i n
b
-< sn 5 b +A(b)
+ s
<
Let
E
n
+so,
monotonicity of Jln(sn), +A(",)
t*
E
$
n
[b,b
E
Let
+ E).
> -
0
Assume
qn(t)
is
Then
From t h e mean value
sn = min S
n'
Then
K < $;(sn) < 0. Thus, without l o s s o f $A(",) +qo. If $;(b) = 0, t h e n b = s
and
0, q n ( t )
However, then
t*
_> $A(t) 2 K].
i s not empty.
Sn
generality If
n].
>b, 0 Sn = [ t : t -
theorem,
We may assume
$'(b) > 0. n i s monotone increasing i n n f o r
qn(t)
- &,b + & )
Define
For f i x e d
A similar argument holds when
0.
also that
(xn,yn).
<
Sn
q
until and thus
we have
$'(t*)= 0 n qn(sn)
JIl(sn)
< q.
< JI,(sn).
a r e bounded condition (2.4.4)
t* > b.
f o r some From t h e Since implies
l i e i n a bounded region.
{xn(sn),yn(sn)] Choose a convergent subsequence
115
sn + so, x (s ) n n
--f
x0'
n
.
2 . SHOOTING TYPE METHODS
yn(sn) + y o . where
6
Let
be a b a l l of radius
Ss
- so.
6 about
For large n, (sn,xn,yn)
E
S6.
(so,xo,yo) Since a l l
[a,so + 61, we have ( x n ( a ) , y n ( a ) ) E Sk s u f f i c i e n t l y large. Let Pn = ( x n ( a ) , y n ( a ) ) , Pick
solutions e x i s t on for
k
Ql,%
E
S1
llqll > k, Ilgll > k,
such t h a t
rb
From the montonicity of rb(Q2)
> rb(Pn)
f o r a l l n.
either
rb(%)
Thus e i t h e r
Q1 > Pn > %. > rb(Pn) o r rb(%) 2 q o r and
rb(&2) 2 q. This i s a contradiction t o t h e maximality of and the proof follows. COROLLARY 2.4.1.
q
Consider t h e BVP
(2.4.5)
X"
,
= h ( t X, x ' ),
(2.4.6)
r x(a) 1
+
r2x1(a) = c 1'
(2.4.7)
s x(b) 1
+
s 2 x ' ( b ) = c2,
2
where h E C[[a,b+E)xR ,R]
and assume t h e BVP (2.4.5),
(2.4.6) and s 1x ( t ) + s 2 x ' ( t ) = c has a t most one solution on [ a , t ] f o r each t E ( b - E , b + & ) and a l l c E R. I f
[s x + s 2 x 1 I 2 + [s x ' + s 2 h ( t , x , x ' ) ] 2 1 1 uniformly f o r
t
E
solution of (2.4.5) 2.5
[b
- E , b + E],
- (2.4.7).
+m
as
x2
+ xf2 +m
then there e x i s t s exactly one
ANGULAR FUNCTION TECHNIQUE
I n the preceding sections of t h i s chapter, we used a shooting type method t o prove t h e existence of solutions from uniqueness assumptions.
I n what follows, we wish t o employ
the angular f'unction technique t o study a number of r e s u l t s concerning existence and uniqueness i n a unified way.
In
p a r t i c u l a r , we are i n t e r e s t e d i n discussing the solutions of the d i f f e r e n t i a l equations
116
2.6. FUNDAMENTAL LEMMAS
(2.5.1)
Y' = g ( t , x , y )
x ' = f(t,X,Y),
s a t i s e i n g the boundary conditions (2.5.2)
.(a)
(2.5.3)
x(b) s i n p - y ( b ) cos f3 = 0.
Here we assume
s i n a - y ( a ) cos CY = 0 ,
2
f,g E C[[a,b] xR ,R],
0
-< CY < T
and
0
< f3 5
T.
We may geometrically i n t e r p r e t t h e problem as finding a solution z ( t ) = ( x ( t ) , y ( t ) ) of (2.5.1) which l i e s on the s t r a i g h t l i n e x s i n . a , y cos CY = 0 a t t = a, and on the l i n e
-
x s i n B - y cos B = O
at
t=b.
With respect t o t h e solution polar angle cp(t)
z ( t ) = ( x ( t ) , y ( t ) ) the
i s defined i n the
q(t)
xy plane.
i s called the angular function of
defined as long as formulas r e l a t e
cp(t)
and
z(t)
x ( t ) = Ilz(t)ll cos d t ) ,
=
and i s well
z(t)
~ ( t )does not vanish.
The function
Thus the following
(x(t),y(t)):
Y(t) = llz(t)II sin cp(t),
and
cp'(t>= Observe a l s o t h a t (2.5.3)
x(t)y' ( t )
- y(t)x' ( t )
x 2 ( t ) +Y2(t) z(t)
i s a solution of the BVP (2.5.1)-
i f and only i f i t s angular function
cp(a) = a, f o r some integer
q(t)
satisfies
cp(b) = B + k-rr
k.
The following lemma i s a version of Lemma 2.1.1.
117
2. SHOOTING TYPE METHODS
LEbW 2.6.1.
[a,b].
s
Let
Assume a l l s o l u t i o n s of (2.5.1) e x i s t on 2 be m y compact connected s e t i n [a,b] X R
.
Then t h e s e t o f a l l s o l u t i o n s passing through 2 connected s e t i n R
.
form a compact,
S
Consider now t h e i n i t i a l conditions (2.6.1)
x(to) =
y ( t o ) = YoJ
xoJ
and denote t h e s o l u t i o n s of (2.5.1) and (2.6.1) a s
z(t,z0) =
( x ( t J x 0 J ~ o ) JY ( ~ J X ~ J Y ~where ))J 0 = (xoJy0)* ~ e t~ ( t , z o ) denote t h e angular function of any s o l u t i o n of (2.5.1) s a t i s % ing (2.6.1).
Observe t h a t
cp(t,zo),
f o r each
t
E
[aJbIJ is
multivalued s i n c e s o l u t i o n s a r e not i n g e n e r a l wniquely defined We now present a lemma s i m i l a r t o
by t h e i n i t i a l conditions.
2.6.1 f o r angular functions.
-ma
LEMMA 2.6.2.
Let
be any compact connected s e t o f
S
R2
such t h a t t h e r e e x i s t s a l i n e through t h e o r i g i n which does not intersect all
t
E
S.
Assume t h a t f o r a l l
[a,b].
#
0
for
Then 2
u
0
forms a segment f o r each EXERCISE 2.6.1.
Hint: -
zo E S, z ( t , z o )
dtJzo)
ES
t
E
[a,b].
Prove Lemma 2.6.2.
Assume t h a t t h e r e s u l t i s not t r u e and use Lemma
2.6.1 t o o b t a i n a contradiction. LEMMA 2.6.3.
There e x i s t functions
m(u)
and
that m(IIzoII) _< IIZ(tJZO)ll _< ~ ( l l z ~ l l ) ~
118
M(u)
such
2.6. FUNDAMENTAL LEMMAS
where
lim m(u) =
u+ Proof:
+m,
+m
Define
and m(u) =
inf IIz(t,zO)Il. llzo II 2 u
t c [a,b I By Leinma 2.6.1,
M(u)
lhu++w m(U) =
show
and +m.
a r e w e l l defined.
m(u) Let
ro
>0
be given.
t h e s o l u t i o n s of (2.5.1) passing through t h e s e t
We now Consider
S =[(t,z):
E [ a , b l , I/zII 5 ro]. By Lemma 2.6.1 t h e r e e x i s t s a u > 0 0 such t h a t llz(t)l/ 5 uo where ~ ( t )passes through S. Hence
t
if
I/zoII > uo,
then
> r0
for
thus
m(u)
-
llz(t,ZO)ll > ro f o r a l l t E [a,b] u
> u 0'
and
This proves t h e lemma.
We now s t a t e t h e following known r e s u l t on t h e semicontinuity behavior of s o l u t i o n funnels. IEMMA 2.6.4.
Assume t h a t s o l u t i o n s of
r' where
F
E
n n C[[a,b] X R ,R
there e x i st s
6
>
0
6(t)
e x i s t on
= F(t,r)
i s continuous and
solution r 2 ( t )
of
[a,b].
For each
such t h a t f o r each s o l u t i o n rl
where
1,
= F(t,r),
r ' = F(t,r),
satisfying 119
+
rl(t)
6(t),
116(t)II < 6, where
there i s a
r ( a ) = r,(a), 1
E
of
>0
2. SHOOTING TYPE METHODS
- r 2 ( t ) II < E
Ilr,(t) f o r a l l t E [a,b]. We s h a l l now compare (2.6.2)
x' =
(2.5.1) with
N
Y ' = &,X,Y),
f(t,X,Y),
2 f , g E C[[a,b]xR ,R].
N
where
N
side of (2.6.2)
Assume also t h a t t h e right-hand
are p o s i t i v e l y homogeneous, t h a t is, N
N
(2.6.3)
f ( t , c x , c y ) = c?(t,x,y),
for a l l
c
2 0.
We write
xg(t,X,Y)
[f,g]
@;(t,cx,cy)= cg(t,x,Y)
2 {F,;i?
- Yf(t,X,Y) 2 &(t,X,Y)
if N
-Yf(t,x,Y).
We now present a comparison r e s u l t . LEMMI1 2.6.5.
L e t solutions
(2.5.1) and (2.6.2), never vanish.
Let
z(t)
and 2 ( t )
of systems
respectively, be defined on cp(t)
and
2 t )
[a,b]
and
be the respective angular
f'unctions of t h e solutions and assume
v(a> 2 5(4,
(2.6.4)
Cf,d ,> C G I .
Then
V ( t > 2 6m(t) where (2.6.5)
for
a l l t E [a,b],
N
(pm(t) i s the minimal solution of $ ' ( t ) = z ( t , c o s $,sin
$)
120
N
N
N
cos cp-f(t,cos cp,sin
5) s i n $.
2.7. EXISTENCE
The theory of d i f f e r e n t i a l i n e q u a l i t i e s then gives
The proof i s complete. If solutions of (2.5.1)
and (2.6.2)
a r e uniquely determined
by i n i t i a l conditions, then we may conclude t h a t Observe a l s o t h a t
?(t,O,O)
i s a solution of (2.6.2).
g(t,O,O)
E
E
0
cp(t) 1 ;(t); so t h a t z ( t ) E 0
Moreover, we notice, from the
homogeneity t h a t Il?(t,x,y)II 5 A (x2 + y2)*, llz(t,x,y)/l 5 I 2 A (x + y2)2 f o r some A > 0. This implies t h a t a l l solutions of (2.6.2) e x i s t on
[a,b].
From the calculations used i n t h e
previous l m a , we see t h a t the angular function s a t i s f i e s a d i f f e r e n t i a l equation independent of t h e solution, so it i s consistent t o discuss the angular function of a system with a given i n i t i a l angle. 2.7
EXISTENCE Before proving existence r e s u l t s f o r (2.5.1)
- (2.5.3),
it
i s necessary t h a t c e r t a i n r e s t r i c t i o n s be placed on the solutions of t h e comparison equation (2.6.2) which s a t i s f y t h e boundary conditions (2.5.2)
and (2.5.3).
When solutions of (2.5.1)
and
(2.6.2) are uniquely determined by i n i t i a l conditions, these r e s t r i c t i o n s reduce t o t h e following:
l e t ?+(t)
denote the angular functions of (2.6.2) conditions
-4-
cp (a) = a, ?-(a) = CY
121
+
T
and ? ( t )
s a t i s f y i n g the i n i t i a l
and suppose t h a t
2 . SHOOTING TYPE METHODS
f3
+ kT<
y ( b ) < f3
+ (k+l)T
and
f3
+
( k + l ) T < $-(b) < p
f o r a certain integer
k.
+ (k+2)~
This condition, i n f a c t , implies
t h a t t h e only s o l u t i o n o f t h e BVP (2.6.2), Z(t)
=
(2.5.2),
(2.5.3) i s
0.
Since we do not assume t h e uniqueness of s o l u t i o n s , t h e previous conditions w i l l be i n terms of minimal and maximal solutions. Consider t h e a u x i l i a r y systems
(2.7 1)
x'
= :(t,x,Y),
Y ' = b(t,X,Y)
x'
= C(t,X,Y),
Y ' = d(t,X,Y),
and
(2.7.2) where in
a,b,c,d
x and y.
2 C[[a,b] X R ,R]
E
Let
8(t)
of (2.7.1) and (2.7.2).
and
and a r e p o s i t i v e l y homogeneous $(t)
be t h e angular flmctions
Then a computation similar t o one i n
Lemma 2.6.5 y i e l d s
(2.7.3)
€ I t ( t ) = b ( t , c o s @ , s i n 8 ) cos e - a ( t , c o s B,sin 8) s i n 0,
and
(2.7.4)
$ ' ( t ) = d ( t , c o s $ , s i n 9) cos $ - c ( t , c o s $ , s i n $) s i n $.
I n order t o avoid r e p e t i t i o n , l e t us l i s t below c e r t a i n hypotheses t h a t w i l l be needed subsequently, (H ) The m a x i m a l s o l u t i o n s $ i ( t ) and $ i ( t ) 1 . satisfying and +-(a) = CY + T obey M (a) = M
$i(b) < p
+ (k+l)T
f o r some i n t e g e r
and
k;
122
o f (2.7.4)
$ i ( b ) < f3 + ( k + 2 ) 1 ~
2.7. EXISTENCE
(H2) The minimal solutions satisfying
0+(a) = m
$(b)
CY
and e-(a) m
+ krr
>p
f o r t h e same i n t e g e r
k
@:(t)
+
=
IT obey
0 i ( b ) > f3
and
+
(k+l)r
a s i n (Hl);
(3)The following i n e q u a l i t y holds between
(2.5.1),
(2.7.1),
b(tJxJy)x
- a(tJx,y)y +i(tJxJy)
t
1. g(tJxJy)x-
-
E
(t,x>y)y
- c ( ~ J x J Y ) +Y% ( ~ J X J Y ) ,
[a,bl.
Observe t h a t when solutions a r e unique (H1) t h a t t h e only s o l u t i o n of (2.7.l),
(2.5.2),
systems
and (2.7.2):
< d(t,x,Y)x
uniformly f o r
of (2.7.3)
and e i ( t )
(2.5.2),
and
(2.5.3)
( 5 )imply
and (2.7.2),
(2.5.3) i s t h e t r i v i a l s o l u t i o n .
We now s t a t e and prove our main existence r e s u l t . THEOREM 2.7.1.
(2.5.1)
- (2.5.3)
Proof:
Under t h e hypotheses (H1)
-
(3), t h e BVP
admits a solution.
Let
z(t,c) = (x(t,c),y(t,c))
be any solution of
(2.5.1) sat i s fying t h e i n i t i a l condition (2.7.5) Let
cp(t,c)
x ( a ) = c cos a,
y ( a ) = c s i n a.
be the angular function of cp(a,c) =
("
IT
123
z(t,c)
if
c 7 0,
if
c
such t h a t
2. SHOOTING TYPE METHODS
From (€$), we o b t a i n 'pf(t,c)
(2.7.6)
5 b(t,cos
(&sin
cos v - a ( t , c o s
'p)
'p,sin
s i n cp
'p)
+ B0(t),
2 2 _s(t,x(t,c),Y(t,c))/(x ( t f c ) + Y ( t j c ) ) . be t h e minimal s o l u t i o n s of
where 60(t) -+ e m ( t ) , g-(t) m
rv
;l(t)
(2.7.7)
Let
g)
= b ( t , c o s 0 , s i n 0 ) cos z - a ( t , c o s 5 , s i n
s i n ;i'
+ 60(t),
-+ 0 (a)
where
=
m
a, g-(a) m
= cf
+ T, it follows t h a t
From (2.7.6) and t h e proof o f Lemma 2.6.5,
(%),
In view of
>
0:(b)
(2.7.9)
f3
we may p i c k
+ krr +
@-(a) =
cf
(2.7.10) whenever
Oi(b) > B + ( k + l ) T +
E,
6>0
so t h a t t h e r e
e+(t), 0-(t)
o f (2.7.3),
where
0 (a) = a,
p
>0
E
satisfying
- e-(t>I
le;(t)
and
< 6 for a l l t
I6,(t)I
+
that
- e+(t>l < E
Iz:(t)
[a,b]. Bo(t)
<
IcI
llz(a,c)I(
> ro,
We thus obtain, using (2.7.8) (2.7.11)
'p(b,c)
> 0:(b)
then
6 if
124
b(t,c)
- (2.7.10),
-> e+(b) - E > 0:(b)
<
E,
7I
Because o f (
MOreover, Lemma 2.6.3 implies t h a t t h e r e exists an such t h a t , i f
E.
we may p i c k
+ TT,such
there exists a
> 0 so small t h a t
(%),
By Lemma 2.6.4 and exist solutions
E
llz(t,c)
> P.
ro > 0
11 > P.
t h a t for
-E
),
>B+
c
krr,
2 ro
2.7. EXISTENCE
By applying a s i m i l a r analysis t o t h e maximal solutions of
(2.7.4) and using (H1)’ we i n f e r the existence of that, for
c
2 rl
(2 7.13
q(b,C)
r1
>0
)
l i e on
such
< B + (k+l)Tf~
and f o r c
(2.7.14)
5 -r 1 (k 4-2)T.
q(bJC) < @
Hence, f o r
c
2 r3
max(r J r ), 0
1
B + ki-r < cp(b,c) <: B + (k + l ) ~ , and f o r
5 -r3
c
B + ( k + l ) n < q(b,c) < This a s s e r t s t h a t the points
@
+ (k+2)7r.
z(b,r )
3
d i f f e r e n t sides of the s t r a i g h t l i n e Consider the s e t of solutions
2.6.1, is
x sin
3 3
such t h a t
@ - ycos @ = 0.
Thus
z(b,-r
x sin @
-y
uIlz I1 <: r3 [ z ( t , c ) 1.
t h i s s e t i s connected i n
c* E (-r , r )
and
R2-for each
z(b,c*) z(t,c*)
3
cos f3 = 0.
t.
BY
Lemma
Hence there
l i e s on the s t r a i g h t l i n e i s a solution of the BW.
This concludes the proof of Theorem 2.7.1.
We leave the proof of t h e following theorem as an exercise since i t s proof i s very similar t o t h e proof of Theorem 2.7.1. 13IEOREM 2.7.2.
(H2) holds. and
ei(t)
Consider the system (2.7.1) and assume
Moreover suppose t h e maximal solutions of (2.7.3)
satisfying
125
+ OM(&)=
cy
and
ei(t) @;(a) = a +7r
2 . SHOOTING TYPE METHODS
e+(b) < f3 + ( k + l ) n and M e x i s t s a s o l u t i o n of
obey
EXERCISE 2.7.1. COROLLARY 2.7.1. (Theorem 2.7.2)
ei(b)
< f3
f
(k+2)T.
Then t h e r e
Prove Theorem 2.7.2. Under t h e hypotheses of Theorem 2.7.1
t h e r e e x i s t s s o l u t i o n s of (2.5.1)
[(2.7.15)]
s a t i s f y i n g t h e boundary conditions x(a) s i n a
(2.7.16)
- y(a)
cos CY = c
x ( b ) s i n p - y ( b ) cos
f o r any
c1,c2
E
Hint: -
1' c2
R.
EXERCISE 2.7.2.
bounded by
f3 =
Prove Corollary 2.7.1.
U s e t h e f a c t t h a t a homogeneous expression i s 2 A(x + y2)' and make a change of v a r i a b l e s by
t r a n s l a t i n g t h e p o i n t of i n t e r s e c t i o n of t h e two l i n e s i n (2.7.16) t o t h e o r i g i n .
Then apply Theorem 2.7.1 (Theorem
2.7.2). EXAMPLE 2.7.1.
The equation x"(t)
+a
sin x + h ( t )
= 0
has a s o l u t i o n which s a t i s f i e s t h e condition
x(a)
= x(b) = 0 .
To show t h i s consider t h e s o l u t i o n s of XI'
= 0,
x ( a ) = x ( b ) = 0.
It i s clear t h a t t h e only s o l u t i o n of t h i s BVP i s t h e t r i v i a l
126
2.8. UNIQUENESS
solution x ( t )
as
1x1 + I x ’ (
=
0.
bbreover
(a s i n x + h ( t ) ( / ( ( x l+
(XI
I)
+O
An immediate application of Theorem 2.7.2
+m.
y i e l d s the desired r e s u l t . EXERCISE 2.7.3.
Show t h a t t h e boundary value problem
x” + g ( t , x , x ’ ) = 0,
x ( a ) = x(b) = 0,
has a solution, i f Ig(t,x,x’)1 2.8
1. Alxl +
B,
where
E
C[[a,b] xR+,R]
A(b-a)
2
<
2
IT
.
UNIQUUENESS
Assume t h a t
Li,
Mi,
Ki,
Ni
homogeneous i n t h e i r second variable. conclude t h a t
127
and a r e positively
From (2.8.1), we may
2. SHOOTING TYPE METHODS
Define now the Functions
128
2.8. UNIQUENESS
uv
-> 0,
uv
<
uv
> 0, -
uv
<
UV?
uv
<
UV?
0,
0, 0, 0, 0,
uv < 0. Consider t h e comparison systems (2.8.2)
u'
= P1(t,u,v),
v' = P2(t,u,v),
(2.8.3)
U'
= Ql(t,U,v),
V'
Observe t h a t u
and
v.
= &(t,u,v).
Pi, Qi, i = 1 , 2 a r e p o s i t i v e l y homogeneous i n + Letting $ ( t ) , $ - ( t ) be t h e angular f'unctions
associated with (2.8.2) and
+
8 (t), e-(t)
be t h e angular
functions associated with (2.8.3), we have (2.8.4)
$ ' ( t ) = Pl(t,cos Fl(t,
(2.8.5)
$1,
e i ( t ) = Ql(t,cos @ , s i n e ) cos e - & ( t , c o s @ , s i n e ) s i n 3
Since
$,sin +) cos + - P 2 ( t , c o s $ , s i n JI) s i n JI
Pi,
Q.
1
F2(t,8).
a r e continuous everywhere except along t h e co-
o r d i n a t e axes, we agree t h a t s o l u t i o n s of (2.8.2), d i f f e r e n t i a b l e almost everywhere.
(2.8.3) are
A s i m i l a r statement holds f o r
t h e angular functions which a r e not d i f f e r e n t i a b l e along t h e angular rays
n~r/2, n = 0 , +I, 2 2 ,
... .
We a r e now a b l e t o s t a t e and prove a uniqueness r e s u l t .
129
e
2 . SHOOTING TYPE METHODS
!EBOREN 2.8.1.
Assume
t h a t conditions (H1) and
(2.8.9, respectively.
f
and g
(5)hold
s a t i s f y (2.8.1) and
r e l a t i v e t o (2.8.4) and
Then i f solutions of (2.5.1) a r e
uniquely defined by the i n i t i a l conditions, there e x i s t s one solution of t h e BVP (2.5.1)- (2.5.3).
then z ( t ) = (;(t),y(t)) (2.5.2),
(2.5.3).
satisf'y the boundary conditions
Also l e t
angular function of -~ ( t ) . For convenience, we s h$atl)l l ebet the G(t), = y(t), -z = T ( t ) , and = $ t ) . We claim t h a t -x%(t,z,F) -T€$(t,x,y) 5 FIG-GIT (2.8.6) -< 5;P2(t,<,7) - y P p , Z , T ) . 3
From our previous estimates
-x(%(t,;) -
-
x ( % ( t , x ) +N2(t,y)) if i;
= xP2(t,Z,T). Similarly,
130
+N2(t,y)) if 2
y 2 0, ? < 0,
2.8. UNIQUENESS
The lower estimates i n (2.8.6) a r e obtained i n t h e same manner. Hence we obtain from (2.8.6), (2.8.7) where
F2(t,p)
5 7' =
6 y1-: z')/(s;2+y2)5 Fl(t,$),
F1, F2 correspond t o (2.8.4) and (2.8.5), respectively.
#
Notice t h a t ( z ( a ) , y ( a ) )
(0,O)
by t h e uniqueness of
i n i t i a l value problems and t h a t t h e r e e x i s t s no y ( t o ) = ( x ( t o ) , y ( t o ) ) = (0,O).
such t h a t
to
E
[a,b]
This implies
-
cp(t)
i s w e l l defined. From (H1),
(H2), and (2.8.6) and the theory of d i f f e r e n t i a l
inequalities, which i s applicable since continuous everywhere except a t
Fl(t,%),F2(t,5)
0 = nn/2, n = 0, 51,2 2 ,
are
...,
we obtain, using exactly t h e same methods as i n the proof of that either
"heorem 2.7.1, f3
+
krr < F(b) < p
+
(k+ l)a
if
cp(a) =
CY
+
( k + 2)n
if
q(a) =
CY
or
p
+
( k + 1)n < p ( b )
I n e i t h e r case
<
f3
x(b),y(b)
+ n.
cannot s a t i s f y
-
x(b) s i n p - y ( b ) cos p = 0 ,
unless ( z ( b ) , y ( b ) ) E 0,
a contradiction.
The existence of a
solution follows from t h e next corollary.
COROLLARY 2.8.1.
Assume t h a t t h e hypotheses of Theorem
2.8.1hold with t h e exception of the uniqueness of solutions Then there e x i s t s a solution of
of i n i t i a l value problems. the BVP (2.5.1) Proof:
(3) holds.
- (2.5.3).
I n view of Theorem 2.7.1, Let
x2 = y2
E
0
and
131
it s u f f i c e s t o show
x 1 = x, y1 = y.
Then we
2 . SHOOTING TYPE METHODS
o b t a i n from (2.8.6)
Letting
we see t h a t
G(t,x,y) = xg(t,O,O) -yf(t,O,O), G(t,x,y)/(x
lim
2 2 x +y + m
t
uniformly f o r
E
[a,b].
2
+y
2
1=
0
Thus (H ) holds and t h e proof of
3
Corollary 2 . 8 . 1 i s done.
A s before, our r e s u l t s immediately apply t o t h e more
g e n e r a l boundary conditions (2.7.16).
THEOREM 2.8.2. (Corollary 2.8.1)
Under t h e conditions of Theorem 2.8.1 t h e BVP (2.5.1),
(2.7.16)
has e x a c t l y one
s o l u t i o n ( a t l e a s t one s o l u t i o n ) . EXERCISE 2.8.1.
Prove Theorem 2.8.2.
We now apply our r e s u l t s t o t h e case i n which 2
C(l)[[a,b] xR ,R].
f,g E
I n o r d e r t o do so we must consider f i r s t
t h e case of l i n e a r systems; namely, t h e system x ' = all(t)x
(2.8.8) where
a
ij
E
+ a12(t)y,
C[[a,b],R].
(2.8.9)
e l ( t ) = a21 cos
8 = e(t)
Let
a s s o c i a t e d with (2.8.8).
Y ' = agl(t)x
a22(t)~,
be t h e p o l a r angle
Then 2
F3(t,e).
8
+ (a22 - a 11)
cos 0 s i n 8
Assume now t h e r e e x i s t two l i n e a r systems (2.8.10 )
+
z' = A(t)z,
z ' = A(t)z,
132
- a 12 s i n 2 8
2.8. UNIQUENESS
where
ma
Letting
Cp,
z t = x(t)z
JI be the angular functions associated with and
z7 = A(t)z,
V(t)
F3(t,cp)
respectively, we obtain, as i n
(2.8.91, (2.8.11) Since and
f
and g
and
J17(t) = F3(t,q).
a r e d i f f e r e n t i a b l e we have, f o r
(x2,Y2),
where
133
(xl,yl)
2 . SHOOTING TYPE METHODS
f o r a l l t E [a,bl and -m < x,y,u,v uniqueness statement i s true.
<
Then t h e following
+m.
COROLLARY 2.8.2. Assume i n (2.5.1) t h a t f , g E 2 C(l)[[a,b]xR ,R] and t h a t there e x i s t systems (2.8.10)
satisfying (2.8.14).
Assume a l s o t h a t t h e solutions
cp(t),
of (2.8.11) s a t i s f y (H1) and (H2), respectively.
Jr(t)
the B W (2.5.1), Proof:
(2.7.16) has exactly one solution.
Replacing
x
by
x2
+
s(yl-y2),
and integrating (2.8.14)
respect t o
s,
Hyptheses (H1),
Then
s(x1-x2)' from
0
y to
by
y2
1 with
we obtain
(%),
and (2.8.15)
imply t h a t t h e r e e x i s t s no In
n o n t r i v i a l solution of the BVP (2.8.8) and (2.7.16). (2.8.12) and (2.8.13) then (2.5.1)
where
+
let
x2 = y2 = 0
and
x1 = x, y1 = y;
reduces t o
6 ( t ) = f(t,O,O)
3
s3(t)/(x2+y2)
-10,
and
s 4 ( t ) = g(t,O,O).
s4(t)/(x2+y2)
134
-10
as
Hence x2
+
y2
-+ma
2.8. UNIQUENESS
Because of Theorem 2.7.1, (2.7.16)
t h i s assures us t h a t (2.8.16),
o r t h e equivalent problem (2.5.1),
(2.7.16)
has a
solution. Assume now t h a t t h e r e a r e two s o l u t i o n s (X1W,Yl(t)),
Z,(t)
z (t) =
1
= ( X 2 ( t 1 , Y 2 ( t ) ) of (2*5*1), ( 2 * 7 * 1 6 ) *
m e n x ( t ) = x,(t) - x 2 ( t ) , y ( t ) = y,(t) - y 2 ( t ) i s a s o l u t i o n As j u s t mentioned, t h e r e e x i s t s of (2.8.8), (2.5.2), (2.5.3). no n o n t r i v i a l s o l u t i o n of (2.8.8),
-
x(t) = y(t) complete.
(2.5.2),
(2.5.3).
Hence
"hus s o l u t i o n s a r e unique and t h e proof i s
0.
EXAMPLE 2.8.1.
We show t h a t t h e equation
x"(t)
+
6 sin x
+ h(t)
= 0
has a unique s o l u t i o n s a t i s f y i n g t h e boundary conditions .(a)
= x(b) = 0
if
I n Example 2.7.1 we have shown t h e r e e x i s t s a t least one solution.
We now apply Corollary 2.8.2 t o prove t h e r e exists
a t most one s o l u t i o n .
Observe t h a t t h e system x " ( t ) k 161x = 0
s a t i s f i e s (2.8.14)
with
.(a)
= x ( b ) = 0.
of t h i s problem a r e unique, if
according t o Corollary 2.8.2,
x(a)
= x(b) = 0
.
-
t h e equation with conditions
has a unique s o l u t i o n .
EXERCISE 2.8.2. XI'
(61<
We know t h a t s o l u t i o n s 2 Hence, T2/(b a)
+
Show t h a t t h e boundary value problem x ( a ) = x ( b ) = 0,
g ( t , x ) = 0,
has a unique s o l u t i o n i f E
5
gx(t,x)
5
2 /(b - a ) 2 )
(T
135
-
E,
E
> 0.
2 . SHOOTING TYPE METHODS
2.9
ESTIMATION O F
NUMBER OF SOLUTIONS
I n some cases, it i s of i n t e r e s t t o determine i f a BW has s e v e r a l s o l u t i o n s and t o estimate t h e number of t h e s e s o l u t i o n s . Before s t a t i n g our main r e s u l t we need some preliminary developments.
Assume t h a t t h e r e e x i s t two systems
(2.9.11
x ' = r(t,x,y),
Y ' = S(t,X,Y),
(2.9.2)
x'
Y ' = W(t,X,Y),
where
Let
8
r,s,v,w and JI
= V(t,X,Y),
E
C [(a,b] xR2,R]
and p o s i t i v e l y homogeneous.
be t h e p o l a r angles a s s o c i a t e d with (2.9.1) and
(2.9.2),
respectively.
Then
(2.9.3)
0 ' = s ( t , c o s @ , s i n 8 ) cos 8 - r ( t , c o s 0 , s i n 8 ) s i n 8
and (2.9.4)
$I
= w(t,cos + , s i n
$) cos $ - v ( t , c o s $ , s i n J I ) s i n 9.
We now assume conditions similar t o (H1) t h a t i s , assume t h a t :
( 5 )of
Theorem 2.7.1;
(HI) t h e maximal s o l u t i o n s & ( t ) and $;(-ti) of (2.9.4) 1 . s a t i s f y i n g $ ( a ) = a and *-(a) = a + 7r have t h e property M
JIL(b)
(H;) satisfying
M
< p + (a+l)n
and
t h e minimal s o l u t i o n s
+ 8 (a) = m
a
and
$&b) 0:(t)
@'(a) = a m
136
< B + (a+2)n;
and
+
T
0i(t)
of (2.9.3)
have t h e property
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
where
a r e continuous an d
Ej2
,ljt
B1 (t,x, Y 1
lim
x2+ y2 4 0
x
= o
and
lim 2 x +y24 0
+ Y
,X,Y 1
62 (t
2
x + Y
2
= 0.
We a r e now able t o estimate t h e number of solutions of the BVP (2.5.1)-
(2.5.3).
Assume t h a t conditions (H1) - (?), ( H i ) THEOREM 2.9.1. (5)a r e s a t i s f i e d . Then t h e BVP (2.5.1) - (2.5.3) has a t l e a s t 2 ( k- P, I nonzero solutions, whenever k # a .
Proof:
z(t,c) = (x(t,c),y(t,c))
Let
be any solution of
(2.5.1) s a t i s f y i n g t h e i n i t i a l conditions = c cos
.(a) and l e t
y(a) = c s i n
a,
(Y
be t h e angular function o f t h i s solution such
cp(t,c)
that
Assume now Theorem 2.7.1, an
rl
>0
c
>
Using the same pmof as t h a t of
0.
we conclude from (H1)
such t h a t f o r
p
+ kn<
c
2
cp(b,c)
0
such t h a t f o r
0
there e x i s t s
rl
Similarly, we obtain from (Hi)
r
- (3) that
< c -< r0
(k+l)n.
- (3) the
existence of an
ro < rl, we can apply Lemma 2.1.1, q(b,[ro,rl]) i s connected, The previous
Since we may assume and conclude t h a t
two i n e q u a l i t i e s on
cp(b,c)
then imply the existence of 137
2. SHOOTING TYPE METHODS
p o s i t i v e numbers
+
cp(b,c.) = p J
m
where
+
c
E
3
+
[ro,rl]
such t h a t
( j = m+l,m+2
jT
,...,m + ( k - J l ) ,
= min(k,J).
S i m i l a r l y t h e existence of negative numbers
c-
3
found f o r which cp(b,cT) = @ +
J
T +
jn
(j = m + l , m + 2
Hence t h e r e e x i s t s o l u t i o n s
+
z(t,cj)
,...,m +
and
2 ( k-
implying t h a t t h e r e a r e a t l e a s t
can be
Ik-Jl).
z(t,cT)
J
of t h e BVP
s o l u t i o n s , completing
t h e proof o f Theorem 2.9.1.
We now present conditions on system (Hj) a r e s a t i s f i e d . and s a t i s f y
Assume t h a t
f(t,O,O)
2.5.1)
so t h a t ( H i ) 2 ,R]
f , g E C'')[[a,blxR
g(t,O,O)
0.
Let
and consider t h e l i n e a r system (2.9- 5) The angular f'unction (2.9.6)
p(t)
then s a t i s f i e s
P ' ( t ) = gx(t,O,O) cos
x cos
p
2
IJ. + [gy(t,O,O) -fx(t,O,O)l
sin p - f
2
Y
(t,O,O) s i n
+
p.
+
% ( t ) = pm(t) = + pi(t) p - ( t ) where & ( t ) , p i ( t ) a r e , p ( t ) and G ( t ) Let r e s p e c t i v e l y , maximal and minimal s o l u t i o n s of (2.9.6). The s o l u t i o n s of (2.9.6) a r e unique and thus
us assume t h a t
138
-
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
a.
f o r some i n t e g e r Now l e t
cp(t,c)
be t h e angular function of any s o l u t i o n
z ( t , c ) = ( x ( t , c ) J y ( t J c ) ) of (2.5.1). x(t) c x(t,c),y(t)
E
we o b t a i n
y(t,c),
T ' ( t ) = gx(tJoJo) cos
2
Consequently, l e t t i n g
cp + ~ ~ y ~ t J o J o ) ~ f x ( t J o , O ) ~
2 x cos cp s i n cp-fy(t,OJ0) s i n cp
+
6(t),
where
Since
- gy(t,oJo)y(t)
[@;(tJxJy)-gx(tJo,o)x(t)
6(t)
g
fx(tJOJO)x(t)
- fy(tJO>O)y(t)1/(x2(t) + Y 2 ( t ) ) *
is differentiable,
6(t) + O
as
x
Hence (HI) i s s a t i s f i e d , i f we choose 6(t)(x2
+
y 2 )3 and
systems (2.9.1)
-f(t,xJy)
+
y2 - 0 .
Gl(t,x,y) Our comparison f
Gl(t,xJy).
b2(t,x,y)
2
and (2.9.2) a r e p r e c i s e l y system (2.9.5) and
the conditions (HI) and (H;) follows immediately from (2.9.7). 1 We thus deduce t h e following r e s u l t . COROLLARY 2.9.1.
f J g E C ( l ) [ [ a J b ] XSP,R] and s a t i s f y
f(t,O,O)
Assume t h a t (H1) J
where
sp
= g(t,O,O) = 0 .
- (H
) hold.
c (X,Y)3 IX2
y2
Let
5
P23 ,
If t h e s o l u t i o n s of
(2.9.6) s a t i s f y (2.9.7), then t h e r e exist a t least s o l u t i o n s of t h e BVP (2.5.1) (2.5.3).
-
21k- 41
It i s i n t e r e s t i n g t o f i n d conditions such t h a t t h e 2 I k - R 1 nonzero s o l u t i o n s .
boundary value problem has e x a c t l y
Clearly, t h i s w i l l always occur when monotonic i n
c,
both f o r
a s u f f i c i e n t condition f o r
c
>0
cp(t,c)
139
cp(t,c)
and
c
<
is strictly 0.
We now present
t o be s t r i c t l y monotonic.
2 . SHOOTING TYPE METHODS
Assume system (2.5.1) has the following
LENMA 2.9.1.
properties : 2 xg(t,X,Y) -Yf(t,x,Y) 2 0 , ( t , X , Y > E [a,bI xR 2 the paths of two d i f f e r e n t solutions z,(t) and
(a) (b)
z 2 ( t ) which s a t i s f y the conditions cp (a) = cp (a) = t a n 1 2
tan where and
-1
a
cp ( t )
1 z2(t), (c)
5
cp,(t),
and
-1 a,
cp,(t> 5
cp (b) = rp2(b) = t a n 1
B
tan-'
t
for
E
-1 p,
[a,bl,
cp2(t) a r e the angular functions of
zl(t)
respectively, do not i n t e r s e c t ; ( l / r ) [ g ( t , r cos cp,r s i n cp) cos cp
F(t,cp,r)
i s s t r i c t l y increasing i n
f ( t , r cos cp,r s i n cp) s i n cp] Then f o r each solution
z(t,c)
the angular function
i s s t r i c t l y increasing function i n
r.
cp(t,c)
c.
If the inequality i n (a) i s reversed and i f
s t r i c t l y decreasing, then EXERCISE 2.9.1.
Hint:
Let
cp(t,c)
Prove Lemma 2.9.1.
cpl(t,cl)
and
f o r two solutions
zl(t,cl)
and show
> cp;(a,c2).
t
E
cpi(a,c,)
(a,a+6)
if
F(t,cp,r) i s i s s t r i c t l y decreasing i n c.
6
cp2(t,c2)
and
be angular functions
z2(t,c2).
Assume
c1
>
c2
This inequality holds f o r
i s s u f f i c i e n t l y small.
Show t h a t the
(a,b] by using (b) and (c) and the theory of d i f f e r e n t i a l i n e q u a l i t i e s . inequality holds on
We have thus proved the following r e s u l t . COROLLARY 2.9.2.
Assume t h a t the conditions of Theorem
2.9.1 and Lemma 2.9.1 a r e s a t i s f i e d . 21k-
Then there e x i s t exactly
a ( nonzero solutions of the BVP (2.5.1)
140
- (2.5.3).
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
Observe t h a t Corollary 2.9.2 remains v a l i d when i s s t r i c t l y decreasing i n
EXAMPLE 2.9.1.
cp(t,c)
c.
We o b t a i n an estimate, depending on
6,
of the number of s o l u t i o n s of t h e equation
+
X"
6 sin x
=
0,
s a t i s fying x ( 0 ) = 0,
x(1) = 0 .
W e apply Corollary 2.9.2 t o o b t a i n t h e r e s u l t . 2 Then system (2.9.5) becomes 161 < 7r
.
(2.9.8)
x ' = y,
Assume
y' = -&
with t h e boundary conditions x(1) = 0 .
x ( 0 ) = 0,
Since t h e r e e x i s t no nonzero s o l u t i o n s , it follows e a s i l y t h a t
a
= -1.
I n order t o find
k,
we observe t h a t t h e r e e x i s t s no
s o l u t i o n of x" = 0,
x ( 0 ) = 0,
x ( 1 ) = 0.
It follows e a s i l y t h a t k =-1. Thus f o r 161 <
2
7r
, we s e e (even
though k = a ) from Corollary 2.9.2 t h a t t h e r e e x i s t no n o n t r i v i a l 2 2 solution; hence t h e r e e x i s t s o n l y t h e t r i v i a l s o l u t i o n . If n T < I 61 < (n + 1)2T2, n = +1,+2, , t h e n an easy c a l c u l a t i o n y i e l d s
...
= n - 1. Hence t h e r e e x i s t s We l e a v e t h e case EXERCISE 2.9.2.
x"
+
2 [ ( n - 1)+1] 2n
1 61 = n2T2
solutions.
f o r t h e following exercise.
Determine t h e number of s o l u t i o n s of x(0) = 0 = x ( l ) ,
6 sin x = 0 ,
s a t i s fying
141
2 . SHOOTING TYPE METHODS
x ( 0 ) = x(1) = 0
when 2.10
161 =
n
2 2
T ,
,... .
n = 1,2
EXISTENCE OF IJYFINITE NUMBER OF SOLUTIONS I n Section 2.7,
we discussed t h e existence of s o l u t i o n s
of t h e BVP by showing
l i e s i n two s e c t o r s located on
z(b,c)
x s i n @ - y cos @ = 0
d i f f e r e n t s i d e s of t h e s t r a i g h t l i n e when
Ic I
i s sufficiently large.
It i s geometrically c l e a r t h a t t h e boundary value problem a l s o has a s o l u t i o n i f
z(b,c)
has a s p i r a l character when
c
tends t o i n f i n i t y . THEOREM 2.10.1.
Consider t h e BVP (2.5.1)
- (2.5.3).
Let
the inequality F(t,cp,r)
=
(l/r) [ g ( t , r cos cp,r s i n cp] cos cp f ( t , r cos cp,r s i n cp) s i n cp]
-
> E hold f o r
r
2
p0.
o > O
Suppose t h a t t h e
i n t o a f i n i t e number of s e c t o r s
such t h a t
-
t
E
[a,bl,
(t,cp), qj +
where
E
.
S1,. ,,Sm;
F(t,(P,r) =
lim r+ uniformly i n
xy plane can be divided
EL
cps ~
+a
P ~ + ~( j- = E
,...,n),
1
i s an a r b i t r a r i l y small constant.
Then
t h e BVP has an i n f i n i t e number o f s o l u t i o n s . Proof:
By Lemma 2.6.3,
there exists
142
co
>
0
such t h a t
2.10. EXISTENCE OF INFINITE NUMBER OF SOLUTIONS
z(t, c) function and a
p1
lo
1)
2
E
and t h e r e f o r e t h e angular
of t h i s s o l u t i o n i s w e l l defined.
cp(t,c)
Pick any
(2.
1 c 1 > co
does not vanish f o r
>
M > 0.
and choose
0
There e x i s t s
{'pj];=l
so t h a t
p0
2
F(t,cp,r)
r 2
holds f o r a l l
I5
,pl
I C P - CP.
M
where
-< t -< b,
a
M,
E.
J Define t h e discontinuous function H(CP) =
{
for
(61 5
c p = cp. -t 6 ,
J
E,
all o t h e r values of
cp.
\
We s e e immediately F(t,cP,r)
(2.10.2)
for
t
E
[a,b]
2
r
and
> H(V)
pl.
Consider t h e s o l u t i o n
$(t)
of +(a) = a-
+ ' ( t ) = H(+), Observe t h a t t h e time assume t h e value
ty
z =
Hence
$(b)
By Lemma
lcl
2
cp(t,c)
then
p2
is
2T
- $(a) 2 2nk,
z -10;
++a,
+
( ~ E / E ~n ) +
i n t e r v a l s of length M
z which i s required f o r $ ( t ) t o
where
k
i s t h e l a r g e s t number of
z contained i n
and thus $(b)
2.6.3,
(27r-2~n).
(l/M)
4 + m
there exists
Ilz(t,c)ll
[cp(a,c) = a, c
2
2
p,
E -0
As and
E
and
--3
0
M
-++a.
> 0 such t h a t when
Hence, t h e angular f'unction
pl.
of
p,]
[a,b]. as
satisfies t h e
z(t,c)
d i f f e r e n t i a l inequality lb(t,c)ll
CP'(t,c) = F ( t , T ( t , c ) ) ,
2
By t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s
t
E
[a,b].
Hence
cp(b,c)
4 + m
143
as
c
++m.
H(cP(t,c)). cp(t,c) _> $ ( t )
for
Also, i n a s i m i l a r
2 . SHOOTING TYPE METHODS
manner, we conclude
cp(b,c)
By Lema 2.6.2,
of
c,
as
++m
c
+-a.
t h e r e e x i s t s an i n f i n i t e number of values
both p o s i t i v e and negative f o r which cp(b,c) =
B
(mod
TI-).
Hence our BVP has an i n f i n i t e number of s o l u t i o n s .
The proof
i s complete.
EXAMPI8 2.10.1. x' where
gJ h
=
-h(y),
Consider t h e BVP y ' = g(x),
a r e continuous and odd.
= x(b) = 0
.(a) Assume
xg(x)
2,
2
Yh(Y) _> EoY2 and 1bx+,g(X)/X = +ooj limy+m h(y)/y = +a. To show t h a t t h i s problem has an i n f i n i t e number of s o l u t i o n s , we merely check t h e hypotheses o f Theorem 2.10.1.
We n o t i c e
inmediately
Consider t h e four segments
SiJ i = l J 2 , 3 , k J i n t h e
xy plane
defined by
where
E
i s any small constant less than a,b]xSi,
where
M(r)
T/4.
For
we have
has t h e property t h a t
144
g(x)/x
> M(r)
for
1x1
>r
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
and h(y)/y SO
that
> M(r)
M(r)
for
lyl
r
as
-++a
> r.
Since
M(r)
can be chosen
we see t h e hypotheses of
-++a,
Theorem 2.10.1 hold. EXERCISE 2.10.1. x"
Show t h e BW
+ x ( ~ + x ' ~ ) ~+ /h' ( t )
x(a) = x(b) = 0
= 0,
has an i n f i n i t e number of s o l u t i o n s . 2.11
NONLINEAR BOUNDARY CONDITIONS
Using techniques s i m i l a r t o those used i n Section 2.7, we i n v e s t i g a t e t h e existence of s o l u t i o n s of a two-dimensional d i f f e r e n t i a l system s a t i s f y i n g nonlinear boundary conditions. Results on t h e uniqueness and number of s o l u t i o n s may a l s o be deduced under conditions s i m i l a r t o those i n t h e previous s e c t i o n s , but we s h a l l omit them here. Before s t a t i n g our existence theorem c e r t a i n preliminaries need some mentioning.
I n p a r t i c u l a r , consider system (2.5.1).
Assume t h e r e e x i s t two functions, C(')[[a,b] W
such t h a t f o r each
xR2,R]
i s a l l of
W(t,x,y),V(t,x,y)
t
E
t h e range o f
V
and
and t h e s e t
R
(2.11.1) f o r a l l r e a l numbers (2.ll.2)
as
c1
and
c2;
IV(t,X,Y)l + IW(t,X,Y)l
llxll + llyll
--)a
uniformly f o r
The d e r i v a t i v e of V'(t,x,y)
=
av/at +
V
E
[a,bl.
along s o l u t i o n s of (2.5.1)
(t,x,y) +
av/+
t
-tm
av/:X
is
(t,x,y).f(t,x,y)
(t,x,y)*g(t,x,y)-
A s i m i l a r expression holds f o r Let
x(t)
and
y(t)
W'(t,x,y). be any s o l u t i o n of (2.5.1). 145
Now
2 , SHOOTING TYPE METHODS
T(t)
consider t h e angular function defined i n t h e
where V
VW
Fi,Gi
E
W;
and
and
(2.11.4)
plane.
Gi(t,V,W)/(IV(
uniformly f o r
t
E
p(t)
!%us
C [[a,bl XR2,R] Gi(t,V,W)
and polar radius
E
are p o s i t i v e l y homogeneous i n 2 such t h a t C[[a,b] xR ,R]
+ IW() - + 0
( V ( + (WI
as
[a,b].
Define
146
-> 0,
if
V
if
V < 0,
if
W
-> 0,
if
W
< 0,
if
V
-> 0,
if
V
<
0,
-+m
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
Ql(t,V,W) =
Fl(t,V,W)
if W
-> 0,
F2(t,V,W)
if
W
< 0.
where
v_>o, w_>oJ v10,
w
v
w10,
v
t h e comparison systems a r e
(2.11.6)
A' = &l(t,A,B),
B' = &2(t,A,B),
(2.11.7)
s'
T'
= Pl(t,S,T),
= P2(tJS,T).
As before we see t h a t systems (2.11.6)
have d i s c o n t i n u i t i e s along t h e l i n e s well as
S = 0, T = 0.
A = 0
and (2.11.7)
and
B = 0
may
as
Assume t h a t a l l s o l u t i o n s of (2.ll.6)
and (2.11.7) e x i s t on [a,b] and are continuously d i f f e r e n t i a b l e everywhere except a t t h e previously mentioned l i n e s . Observe that
P1,
P2,
%, %
a r e p o s i t i v e l y homogeneous i n t h e i r last 147
2. SHOOTING TYPE METHODS
two v a r i a b l e s . 0(t)
Let
and
ing t o (2.11.6) B(t)/A(t),
+(t)
be t h e angular functions correspond-
and (2.11.7),
where
B(t)
respectively.
Since
tan e ( t ) =
are s o l u t i o n s of (2.U.6),
and A ( t )
we have @ ' ( t ) = Q2(t,cos 8 , s i n 0 ) cos 8
(2.11.8)
-
%(t,cos @,sin e ) s i n
e.
S i m i l a r l y,
+
+ ' ( t ) = P2(t,cos + , s i n +) cos
(2.11.9)
-
Pl(t,cos
+ , s i n +) s i n
+.
Consider t h e BVP (2.11.10)
x' = f(t,x,y),
y ' = g(t,x,y),
with t h e boundary conditions V(a,x(a),y(a)) s i n a - w ( a , x ( a ) , y ( a ) ) cos
(2.11.11) where
0
CY
= 0,
V(b,x(b),y(b)) s i n B - W ( b , x ( b ) , ~ ( b ) ) cos B = 0 ,
-< CY < T
and
0
We now assume e s s e n t i a l l y t h e same hypotheses (H1)-
as i n Section 2.7.1.
Since t h e n o t a t i o n i s t h e same we w i l l
not repeat t h e d e f i n i t i o n s .
Therefore, assume t h e following:
( G ~ ) The maximal s o l u t i o n s
++ ( a )
(2.11.9) such t h a t +;(b)
<
f3
f o r some i n t e g e r (G2) such t h a t
M
+
=
(k+l)n
m
+L(t)
CY, +'(a) M and
= a
+i(b)
of
and
+
Tr
satisfy
< p + (k+2)i'f
k;
The minimal s o l u t i o n s
+ 8 (a)
(3)
=
a, @'(a) m
=
a +
148
ei(t) T
and
satisfy
@:(t)
of (2.11.8)
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
0i(b)
>p +
(k+l)T
f o r the same integer
and
>@ +
e:(b)
kT
k as i n (G1).
We a r e now able t o s t a t e our main existence r e s u l t .
Since
the proof i s similar t o t h a t of Theorem 2.7.1 we leave it as an exercise. For any
'MEOFEM 2.11.1.
- (2.11.3)
ing (2.11.1) (2.11.10),
(2.11.11)
R~
and W(t,x,y)
satisf'y-
t h e r e e x i s t s a solution of t h e BVP provided (G1) and ( G g ) hold. Prove Theorem 2.11.1.
EXERCISE 2.11.1.
Hint:
V(t,x,y)
For any
c
let
(x(a,c),y(a,c))
be a point i n
satisfying V(a,x(a,c),y(a,c)) = c cos a, W(a,x(a,c),y(a,c)) = c s i n CY. Letting
through cp(t,c)
(x(t,c),y(t,c))
(x(a,c),y(a,c)),
be any solution of (2.11.10)
we obtain the angular flmction
where t a n q ( t , c ) = ~(t,x(t,c),~(t,c))/~(t,x(t,c),~(t,c))
Proceed now as i n the proof of !theorem 2.7.1 and obtain f o r s u f f i c i e n t l y large
N
the two points
and
l i e on d i f f e r e n t s i d e s of t h e s t r a i g h t l i n e V s i n p - W cos B = 0
149
2 . SHOOTING TYPE METHODS
VW
i n the
plane.
Show then t h a t t h e r e e x i s t s a s e t V(a,S) = [-N,N].
S
C
R2
such t h a t
Thus t h e s e t
i s connected i n
R
2
.
The r e s u l t then follows.
L e t t h e hypotheses of Theorem 2.11.1
COROLLARY 2.11.1.
Then t h e r e e x i s t s a s o l u t i o n of (2.11.10) s a t i s f y i n g the
hold.
boundary conditions RIV(a,x($),y(a))
+ R2W(a,x(a),y(a)) = clY
R3V(b,x(b),y(b)) + R&W(b,x(b),y(b)) = c2, f o r any r e a l numbers
Ri,
i = 1,2,3,4
and
c., i 1
= 1,2.
Under t h e conditions of Theorem 2.11.1 and Corollary 2.11.1,
we n o t i c e t h a t when s o l u t i o n s of systems (2.11.8)
(2.11.9)
and
a r e uniquely determined by i n i t i a l conditions, then
and (G2) t o g e t h e r a r e equivalent t o t h e fact t h a t t h e r e
(G1)
e x i s t no s o l u t i o n s of (2.11.6)
and (2.11.7)
satisfying the
boundary conditions (2.11.11).
EXAMPLF 2.11.1. x’
(2.11.12)
=
2
x where
f,g
lf(Y)l
E
Consider t h e boundary value problem
x
(8)
+
f(y),
-Y(a) =
y ’ = 2y C1’
+o
Define
x,
w= 150
g(x);
x ( b ) = C2’
C[
v=
+
2
x -y.
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
We a r e thus i n t e r e s t e d i n finding s o l u t i o n s of (2.11.12) s a t i s f y ing
V(b)
w(a) = c 1'
V
Observe t h a t curves
and k2.
V = kl
and W
and W
c
=
2'
s a t i s f y (2.11.1) intersect i n
= k2
since t h e l e v e l
R2 f o r every kl
It i s not d i f f i c u l t t o v e r i f y (2.11.2). V'
=
x'
=
x
+
W' = 2 x x ' - y '
f(y) = 2 2x
=
= 2y
v+ +
Now
f(y),
2xf(y)-*-g(x)
- 2w + 2xf(y) - 2y - g ( x ) +
= -2w
- g(x).
2xf(y)
F = F = V , 6 = 6 = f ( y ) , G = G = -2w, and 1 2 1 3 1 2 S~ = 62 = 2 x f ( y ) - g ( x ) . Since 1 2 x f ( y ) - g ( x ) I / ( 1 x 2 - y ~ + I ~ I ) - ~ o as 1x2-yl + 1x1 -+a, we see t h a t (2.11.4) holds. Systems Let
(2.11.6)
and p2 (2.11.9)
and. (2.ll.7) are then t h e same, with
=%
I
-2w.
P1
=
Ql
Because t h e s o l u t i o n s of (2.11.8)
=V and
a r e uniquely determined by i n i t i a l conditions due t o
the l i n e a r i t y of
Pi
%,
and
it i s s u f f i c i e n t t o
i = 1,2,
show t h e r e e x i s t no s o l u t i o n s of
v,
V' =
W ' = -2w,
satisfying W(a) = 0,
V(b) = 0 ;
t h a t t h i s i s t r u e i s c l e a r f o r any
a
and b.
Show t h e r e e x i s t s a s o l u t i o n of t h e BVP
EXERCISE 2.11.2. XI
=
x
+
2y s i n
y ' = (y/2) y ( a ) = cl,
+
2
x,
2 s i n x;
2 x ( b ) - Y (b) = c2.
151
2. SHOOTING TYPE METHODS
EXERCISE 2.11.3. 2.8 and 2.11,
Keeping i n mind t h e r e s u l t s o f Sections
s t a t e and prove a uniqueness theorem f o r a BVP
with nonlinear boundary conditions. 2.12
NOTES AND COMMENTS Example 2.1.1 i s
Theorem 2.1.1 i s due t o Hartman [41. taken from Lasota and Opial [81. Lasota and Opial [7] and Jackson
For Corollary 2.1.1,
[el.
r e s u l t o f Lees [l] while Exercise 2.1.2 2.1.3 may be found i n Jackson [2].
see
Exercise 2.1.1 i s a
i s of Levin [l]. Exercise
Theorem 2.2.1 i s due t o
Hartman [41.
Exercise 2.2.1 i s a c l a s s i c a l r e s u l t of De La Vallge
Poussin [ I ] .
meorem 2.2.2
i s due t o Tutaj [ l l .
i s taken from Keller [l] and Exercise 2.2.4
Corollary 2.2.2
i s based on Heidel
[l]. Section 2.3 i s adapted from Schrader and Waltman [4], while Section 2.4 is t h e work of Waltman [3]. For r e l a t e d discussion on uniqueness questions, see Bailey e t a l . [3], Shampine [ l ] and Sherman [ l ] . The contents o f Sections 2.5
- 2.10
a r e based on t h e work
of Perov [ l ] and Krasnoselskii e t a l . [2]. on existence and uniqueness
, s e e Waltman
due t o Bernfeld and Lakshmikanthan [2].
152
For r e l a t e d r e s u l t s
[3 1.
Section 2. ll i s
Chapter 3 TOPOLOGICAL METHODS
3.0
INTRODUCTION
I n t h i s chapter, various t o p o l o g i c a l p r i n c i p l e s a r e u t i l i z e d i n solving boundary value problems.
For example, t h e
Wazewski's t o p o l o g i c a l method t o g e t h e r with t h e connectedness properties of s o l u t i o n funnels i s used t o prove t h e existence of s o l u t i o n s .
I n t h i s s e t up, t h e boundary conditions consist
of s e t s which, i n p a r t i c u l a r cases, can be constructed from the knowledge o f upper and lower s o l u t i o n s and Nagumo's condition. We a l s o develop t h e Wazewski-like method f o r boundary value problems associated with contingent equations and s e t valued d i f f e r e n t i a l equations.
F i n a l l y , t h e continuous dependence of
solutions on boundary d a t a i s discussed.
3.1 SOLUTION FUNNELS We s h a l l consider t h e existence of s o l u t i o n s of boundary value problems a s s o c i a t e d with t h e two-dimensional system
153
3. TOPOLOGICAL METHODS
Let
f(t,x,y)
and g ( t , x , y )
be continuous i n a s e t
E
which
i s open r e l a t i v e t o
Q(to) where Q(to) I 7 R C E. tl,t2 2 0 and l e t S be a subset of C(tl). Denote by IE(S,tlJt2), the s e t of a l l points (x,Y) such t h a t there Let
is a solution
(x(t),y(t))
of (3.1.1) on
[tl,t2]
i n which
( x ( t l ) , Y ( t l ) ) E S, (x(t,),Y(t,)) = (%Y> and ( t , x ( t ) , Y ( t ) ) E E This s e t , as we have seen i s called the f o r a l l t E [t,,t2].
t = t 2' Before s t a t i n g our main r e s u l t s , we s h a l l need the following hypotheses w h i c h r e s t r i c t the behavior of solutions as they
solution funnel cross section a t
cross the
cp
and
surfaces.
$
We s h a l l always assume:
'
(Hi) f o r a n t i E [OJtoIJ (Xl'Y1) I ~ ( S l J 0 , t l ) sq(t1) implies t h a t there e x i s t s a solution of (3.1.1) emanating from w i t h a trajectory which i s on or above the $-surface (tlJxl,yl)
on some right neighborhood of
t
1'
(H2) f o r a l l tl E [O,tOl, (xl,Y1) E IE(Sl~O,tl) n)lt(,,.s , implies t h a t there e x i s t s a solution of ( 3 . 1 . 1 ) which emanates w i t h a trajectory which is on or below the from (tl,xlJy1) cp-surface on some right neighborhood of tl.
Our f i r s t r e s u l t describes qualitatively the behavior of solutions
of (3.1.1) assuming (H1) and (H2) hold. THEOREM 3.1.1. C(0)
Let
which intersects (i)
S1 be a compact connected s e t i n S+(O)
and
Sp(0).
Then e i t h e r
IE(SIJO>t) contains a compact connected component
C(t) which intersects both S ( t ) and S ( t ) f o r a l l Jr cp t E [OJto], or ( i i ) there i s a solution of (3.1.1) w i t h (x(O),y(O)) E S1 having a maximal right i n t e r v a l of [O,t+] C [O,tO] such t h a t in
154
3.1. SOLUTION FUNNELS
E: (p(t,y) - 1 < x < Jr(t,y) + 11. Assume t h e r e i s no number K such t h a t f o r a l l t E [O,tO], Proof:
Let
E'
(x,y) E IEl(Sl,O,t)
i s some i n t e r v a l
[(t,x,y)
implies [O,t+]
> K for t
C
(xn,yn) E IEl(Sl,O,tn).
lynl
+a.
IyI
5
K.
Then t h e r e
Ixn I + m,
1x1
>K
or
tn + t Ixnl + m o r
Then, e i t h e r +(t,y)
and
-k
and
it
(P(t,y),
Iyn I -+ m.
then
>0
K
Pick any sequence
By t h e continuity o f
case we have
and
such t h a t e i t h e r
let
follows t h a t i f
-< K
1x1
+ + [ t - &,t).
E
E
[O,tO] such t h a t f o r any
&(K) > 0
there e x i s t s an IyI
E
Hence i n e i t h e r
lynl + m.
By a standard diagonalization process, using t h e s o l u t i o n s
{ (xn,yn)},
associated with
of (3.1.1) with
(x(t),y(t)) on
[O,t]
[O,t+)
C
Moreover,
we may construct a s o l u t i o n which e x i s t s
(x(O),y(O)) E S1
and such t h a t
ly(t)l
+.
t +t
as
+m
This i s case ( i i ) .
( t , x ( t ) , y ( t ) ) E E' c E.
Hence, t o complete t h e proof we may assume t h e r e e x i s t s a
K
number implies
>
1x1
Let
such t h a t f o r a l l
0
-< K
t
T be the s e t of a l l p o i n t s the set 0 E T
[O,tO] such t h a t ,
E
IEl(Sl,O,t)
C ( t ) which i n t e r s e c t s both
i s nonempty s i n c e
contains a component
S J l ( t ) and
Sq(t).
Then
T
to. We
and i s bounded above by
i s closed and thus i f we l e t
s h a l l show T
(x,y) E I E l ( S l , O , t )
E (O,tO],
J y J5 K.
and
f o r a l l t E [O,T], in
t
s = sup T,
then
s = to implies t h e conclusion of Theorem 3.1.1. Let
be a sequence of p i n t s i n
{s.}
s with Ci
1
C
C(si)
S (si)
intersects both
l i m i t set of
a component of
{Ci}
Jr
and
and l e t
Then there e x i s t s a sequence where
(x;,yf)
E
C;
and
I E (S l
Let
S (s.).
' p 1 (a,b) E
L
E(x;,y;)I
converging t o
T
1'
0 si)
L
since
'
which
denote t h e L
i s nonempty.
converging t o
i s a subsequence of
{C;]
155
(a,b)
{Ci}.
3. TOPOLOGICAL METHODS
Let
be the s e t o f l i m i t points of
L'
compact and since for a l l If
intersects both
C;
then
i
{C;};
hence
S (s!) c p 1
and
is
L'
S (s;) Jr
L' intersects both S (s) and S (s).
cp Jr contains no component which intersects both
L'
S (s) and ST("), then since L1 is compact and intersects Jr both S (s) and S (s), L' i s the union of two nonempty cp compact s e t s
that
A
n L'
Assume {C!].
There e x i s t s a point
s; +s,
C
in
C(s)
closed.
a subsequence of
c (x;,~;)]
t o be the subsequence of
Thus
(p,q)
(p,q)
(p,q) E L 1 and
and we conclude
and
For i s u f f i c i e n t l y large the connected i n t e r s e c t s A and l e t (pi,qi) be the
C;.
IE,(Ci,si,s)
then
be any point i n N
(z',?') E C i ,
where
points of intersection. and since
(c,d)
Let
E M.
+ (c,d),
contained i n
such
= cp.
Choose { (x;,yy)]
1
set
J,
and N which are separated by an arc A
(a,b)
(?',Ti)
let
M
(pi,qi)
E
n S.
IEl(C;,s;,s)
which i s a l i m i t point of
i s a limit point of
(p,q) E A fl LI.
{C;].
{(pi,qi)] However,
This i s a contradiction
IEl(Sl,O,s) contains a component intersecting both S (s) and S (s). Thus T i s cp JI L'
and thus
By assumptions (H1)
and (H2) there e x i s t s a
6>0
such
that
and
IEl(C,s,t)
contains a component which ir,tersects both
S (t)
and S ( t ) f o r a l l t E ( s , s + 6 ) . However, t h i s JI cp contradicts the f a c t t h a t s = sup T. Thus s = to and ( i )
i s proven.
This concludes the proof of Theorem 3 . 1 . 1 .
Theorem 3.1.1 w i t h conditions t h a t r e s t r i c t the possibility of ( i i ) occurring can be used t o deduce existence theorems. have seen i n Chapter 1t h a t one such condition is Nagumo's condition.
The following condition w i l l thus be imposed:
156
We
3.1. SOLUTION FUNNELS
(H3) Given any number N(tO,n)
n
>0
and
to > 0 t h e r e e x i s t s a
such t h a t f o r any s o l u t i o n ( x ( t ) , y ( t ) )
(3.1.1) with
ly(O)[ < n and ( t , x ( t ) , y ( t ) ) E F, f o r l y ( t ) l < N(tOJn) f o r a l l t E [O,tO).
we have
of
t
[O,tO)
E
We now p r e s e n t an existence theorem. Assume conditions (H1)- (H ) hold.
THEOREM 3.1.2.
S1 be a compact connected s e t i n Sq(0)
and
C(to)
such t h a t
S (0). cp
Let
(x(t),y(t))
t h a t ( x(O),Y(O) )’ E S1’ for a l l t E [O,tOl. Proof: (x,y)
and l e t
S1,
E
s1
Since
l y ( t ) l < N(tO,n) (x(O),y(O)) E S1 IE(SIJO,tO)
which i n t e r s e c t s both
be a closed connected subset of
S2
S2 f l [(x,y): y
e x i s t s a s o l u t i o n of
C(0)
# $,
arbitrary]
of (3.1.1) on
( x(to)tY(t0))
E
then t h e r e [O,to]
n = sup (yI f o r
5 ).
N = N(tO,n) be a s i n (
f o r ally ( x ( t ) J y ( t ) )
Of
C ( t o ) which i n t e r s e c t s both S2
Then
(3.1.1) with
t E [OJtO]. By Theorem 3.1.1,
contains a compact connected component
conditions imposed on
such
S2 with ( t , x ( t ) , ~ ( t ) )E E
i s a compact s e t , l e t
and a l l
Let
3
S (t ) $ 0
and
insure t h a t
S2
S (t ).
cpo
n
C
The
IE(SIJO,tO)
in
# 9.
This concludes t h e proof of t h e theorem. Another approach t o t h i s problem i s t h e a p p l i c a t i o n of t h e Wazewski’s method.
We s h a l l introduce t h i s method here.
Consider t h e d i f f e r e n t i a l system (3.1.2) where
f
X’
E
= f(tJx),
n C[nJR 3, R
be an open set of closure of
x ( t 0 ) = xo
2
J
being any open set i n
OJ
Rn+l.
Let
n, anoJ t h e boundary, and E0 t h e
Ro
no.
DEFINITION 3.1.1.
A point
157
( t O J x O )E
fi
n ano
is said
3 . TOPOLOGICAL METHODS
t o be an egress point of
with respect t o t h e system
Ro
(3.1.2) i f , f o r every solution E
>0
such t h a t
x(t)
of (3.1.2),
to- E 5 t < to. An egress
for
( t , x ( t ) ) E Ro
there i s an
no i s called a s t r i c t egress point of no, Tio f o r to < t 5 to + E f o r a small E > 0.
point
( t O , x O ) of
if ( t , x ( t ) ) Denote t h e s e t of a l l points of egress ( s t r i c t egress) as
S
(S") DEFIXITION 3.1.2. topological space and B
into A
such t h a t
A
If T:
C
~ ( p =) p
i s s a i d t o be a r e t r a c t i o n of a r e t r a c t i o n of
B
onto
B
are any two s e t s of a
is a continuous mapping from
B +A
f o r every
B onto
A, A
p E A,
then
T
When t h e r e exists
A.
i s called a r e t r a c t of
B.
The following theorem of Wazewski i s quite useful. THEOREM 3.1.3.
Let
f E C[R,Rn), R
Assume t h a t through every point of solution of (3.1.2).
Let
Ro
be a nonempty subset of
r e t r a c t of
S,
there passes a unique
be an open subset of
Qo U S
but not a r e t r a c t of
at least one point
$+l R.
Suppose
no are s t r i c t egress points.
t h a t a l l egress points of Z
R
open i n
such t h a t 2.
Z fl S
Let
is a
Then there e x i s t s
no such t h a t the solution ( t , x ( t ) ) of (3.1.2) remains i n no on i t s maximal i n t e r v a l (tO,xO) E Z fl
of existence t o the right of
to.
W e now apply Theorem 3.1.3 t o the BVP prescribed i n Theorem 3.1.2.
Although we assume uniqueness of solutions of (3.1.1)
t h i s i s not e s s e n t i a l a s a Wazewski-like theorem f o r nonuniqueness has been developed.
Let
R = [(t,x,y): t
2 03 -S2;
a r e l a t i v e l y open subset of the h a l f space
no = [(t,x,y): 0 5 t < tl,
then
[(t,x,y): t
2
is 01. Let R
q ( t ) < x < q ( t ) , IyI < m1 where now a r e independent of y. Let Z f S From 1' hypotheses (H1) and (%), it i s not d i f f i c u l t t o see t h a t S = S", $(t,y), q ( t , y )
158
3.1. SOLUTION FUNNELS
and
consists of t h e union of t h e s e t s
S
We see from t h e properties of
i s a r e t r a c t of
S.
i s not a r e t r a c t of
and t h e s e t
that
S1n S
S
of (3.1.1) such t h a t
solution ( x ( t ) , y ( t ) )
S2
n S i s not connected S1 n S 1 Hence from Theorem 3.1.2 there i s a
Since
S1.
S
( tl,x(tl),y(tl))
E
and such t h a t ( t , x ( t ) , y ( t ) ) remains i n no on i t s S1 n C(t,) r i g h t m a x i m a l i n t e r v a l of existence. This implies ( t 2 , x ( t 2 ) J
due t o (H ).
Hence t h e r e e x i s t s a solution s a t i s f y -
y ( t 2 ) ) E S2 3 ing t h e BVP prescribed i n Theorem 3.1.2.
We now can obtain under t h e same hypotheses the existence of a solution remaining i n THEOREM
3.1.2, that
n
&(to).
3.1.4. Under the same hypotheses as i n Theorem
t h e r e e x i s t s a solution ( x ( t ) , y ( t ) ) of (3.1.1) such (x(O),Y(O)) E S1' ( x ( t , ) , y ( t O ) )
n
~ ( t ) E) R
Hint: -
=E
6
S ~ Jand
(t,x(t>,
Q(t,).
EXERCISE 3.1.1.
E~
R
Prove Theorem 3.1.4.
Choose a sequence of open s e t s
n
~ R+ ~~ ( t ,I ),
E~ = E,
and
n,,
W
Show t h e r e e x i s t solutions which l i e i n
where E
En boundary conditions by applying Theorem 3.1.2.
n Q(t,). and s a t i s f y t h e
= R
Then apply
Ascoli's theorem t o obtain t h e desired solution. We can now prove a r e s u l t f o r a semiinfinite BVP.
THEOREM 3.1.5.
Let
f , g E C [ [ O , ~ ) ~ R * , Rand ] assume 159
3. TOPOLOGICAL METHODS
-
kt
(H1) (H3) hold. intersecting both solution
S1 be a compact connected s e t i n C(0)
(x(t),y(t))
and ( t , x ( t ) , y ( t ) )
E
Sq(0).
e x i s t i n g on
R
n
Then (3.1.1) has a with
[O,m)
2
Q(to)for a l l t
(x(O),y(O)) cS1
0.
Prove Theorem 3.1.5.
EXERCISE 3.1.2.
Hint: -
and
S (0) $
Use Theorem 3.1.4 and a standard diagonalization
argument. 3.2
APPLICATION TO SECOND-ORDER E a T I O N S
In t h i s section we apply the r e s u l t s of Section 3.1 t o t h e case i n which
f(t,x,y) = y
i n (3.1.1).
That is, we consider
the equivalent second-order s c a l a r equation
(3s2O1)
XI1
= @;(t,X,X').
Recall t h a t a ftmction a ( t ) E C(2)[0,t
of (3.2.1)
if
(3.2.2)
a"(t) 2 g(t,(Y('(t),(Y'(t)),
bbreover,
(Y
- is >
1
t
i s a lower solution
E
[O,tOl.
becomes a s t r i c t lower solution if, i n (3.2.2),
replaced by
>.
Similarly a f'unction
i s an upper solution of (3.2.1) (3.2.3)
0
V(t)
5
B(t) E C(2)[0,to]
if
g(t,B(t),B'(t)),
t
E
[O,tOl-
If i n (3.2.3) 5 i s replaced by <, then B is a s t r i c t upper solution. We now present a general existence r e s u l t , Notice t h a t i n Chapter l o t h e r techniques have been used t o prove similar types of theorems. TI-IEOm 3.2.1. (i)
Assume t h a t :
there e x i s t s an upper solution
160
@ ( t )and a lower
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
solution a ( t ) E
of (3.2.1) with
-< B(t)
a(t)
be any open s e t containing the s e t
5x5
a(t)
S,
I
# gj
and such t h a t
with
I<
such t h a t
(x(to)Jx'(to)) E
n
with
2
y'
0
Let
5 t 5 to,
such t h a t ( x , x l ) E S1 fl S a ( 0 ) f o r some
B'(0)
be a closed connected subset of
S2
[ ( x , ~ ' ) : x'
x(t)
C(0)
' ( 0 ) f o r some
#9
Let
S2
e x i s t s a solution
Proof:
x' <~
S1 fl S (0) B
(y,y') E S1 fl Sg(0). C(to)
[(t,x,x'):
be a compact connected s e t i n
S1 fl S a ( 0 )
[O,tO].
(3) holds.
(ii) Let
Ix'
B(t)J
on
of (3.2.1)
arbitrary]
# 8.
such t h a t
(x(O),x'(O)) E S ~ ,
s2 with a ( t ) < x(t) < @ ( t ) On
We f i r s t prove t h e r e s u l t with
a(t)
Then there [Ojt0I. and
p(t)
assumed t o be s t r i c t lower and upper solutions, respectively.
(3) i s s a t i s f i e d the p o s s i b i l i t y of
Since
Theorem 3.1.1 i s eliminated. of
IE(Sl,O,t)
Let
Ct
C
which i n t e r s e c t s both
C(t)
Sa(t)
be a component and
P by
Define
P
I
B
< x1 -
(x,x') E S a ( t ) fl Ct such a l ( t ) and there e x i s t s ( y , y l ) E
ct n sB ( t ) t E [oJ51]* P
S (t).
[t;: there e x i s t s that
Notice
case ( i i ) i n
such t h a t
i s nonempty since
y'
0 E P.
-> B ' ( t )
Let
f o r a11
n = sup P.
It i s
s u f f i c i e n t t o show n = to. Exactly a s i n t h e proof of Theorem 3.1.1 it follows t h a t There e i t h e r e x i s t s
n
E
P.
We omit the d e t a i l s .
( x , x l ) E Cn fl Sa(n)
such t h a t
x = a ( n ) , x ' = a l ( n ) o r there e x i s t s
(y,y') E Cn fl S (n) B f o r i f not, then there e x i s t s y = p(n), y ' = @ ' ( n ) such t h a t nl E P. This i s impossible.
such t h a t
nl
>n
( y , y l ) E Cn fl SB (n) such The other case i s similar. I f
Consider then the case where that
y = p(n), y ' = p ' ( n ) .
161
3. TOPOLOGICAL METHODS
y ( t ) i s any solution of (3.2.1) w i t h y(n) = B(n), y ' ( n ) p'(n), then there e x i s t s an &l > 0 such that y ( t ) >
=
p ( t ) , y ' ( t ) > p f ( t ) on (n,n+E1). This follows since p ( t ) i s a strict upper solution on [O,tO]. Moreover, f o r any t > n, any solution y ( t ) of (3.2.1) w i t h y(T) = p(T), y ' ( z ) < PI(:) satisfies y(t) < p(t) for < t < % + S and y ( t ) > p ( t ) on 6 < t C t forsome 6>0. Eythecontinuityof g, it follows t h a t there e x i s t s an E~ > 0 and p l > 0 such t h a t p"(t) < g(t,y,y') for a l l t E [ n , n + ~ ~and l a l l ( y , y f ) such t h a t d((y,y'), ( p ( t ) , B ' ( t ) ) ) < pl, where d denotes t h e Euclidean metric. By standard arguments there e x i s t an &3 > 0 and p2 > 0 such t h a t any solution y ( t ) of (3.2.1) w i t h
z-
y(n) = YoJ y ' ( n ) = YA with d((YoJY~),(p(n),B'(n)))< p2 s a t i s f i e s d(y(t>,y'(t)),(p(t),p'(t))) < p1 f o r a l l t E [ n , n + ~ ~ ] . Moreover, B"(t) < y " ( t ) f o r a l l t E [ n , n + m i n [ ~ ~ , ~ ~ l . Finally, there e x i s t s an &4 > 0 such that f o r any solution
~i
where (Y1,Yi) €Cn ~ l ( t )of (3*2*1)w i t h y l ( n ) = ~ 1 y9i ( n ) = and a((Y,,Yi>,(B(n),B'(n))) < P1 both y,(t) _> B(t) and y i ( t ) 5 p ' ( t ) are not possible f o r any t E [ n , n + &4 1. If we l e t E = min[& , E ,& 1, then it follows from the 1 2 3'&4 preceding observations t h a t Ct n S p ( t ) # # and y' 2 p ' ( t ) f o r some (y,yl) E Ct fl S ( t ) f o r a l l t E [O,n+&]. A similar B argument leads t o the conclusion t h a t Ct n S 2 ( t ) # $ and x ' < a ' ( t ) f o r some (x,xt> E ct n SCY(t) f o r t E [o,n+El. Then nl = min[n+&, n + F ] E P and nl > n, a contradiction.
-
Thus n = to and we conclude that IE(Sl,O,tO) contains a compact connected component intersecting both SCy( t o ) and Sp(to). Hence S2 fl IE(SIJO,tO) # $ and hence there e x i s t s a solution x ( t )
of (3.2.1) w i t h (x(O),x'(O)) E S1, ( x ( t o ) , and ( t , x ( t ) , x ' ( t ) ) E E. Using the same type of x f ( t o ) E) S2, proof' as i n Theorem 3.1.4, we may conclude that a ( t ) 5 x ( t ) 5 p ( t ) f o r a l l t E [O,tal.
162
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
We now prove Theorem 3.2.1, B(t) 0
assuming t h a t
a(t)
a r e lower and upper solutions, respectively.
1, l e t
A (t) = a(t) - y
and
Y
and
For
+ y.
B ( t ) = B(t)
Y
Define
x >
g ( t , B ( t ) , x ' ) + x - B(t),
Q(t5 > x 5 B(t), x
g(t,a(t),x') + x-a(t),
< a(t).
Ix' I + 1 and l e t N be t h e number ( X J ' )fS1 associated with M i n ( ). Choose K = max(N, m a x Let
M = max
5
t Ero, t 0~ i
( l Q ' ( t ) l , I B ' ( t ) l > ) and define
I2K Ix' I 5 K
Ix' H(t,x,x') =
-
+
+ 2,
+ 1,
1< x '
(K+2 x ' ) G ( t , x , K + l ) ,
K
( K + 2 + x ' ) G ( t , x , - K - l),
-K- 2
<
X'
< K + 2, < - K - 1.
Eloreover A"(t) = ~ " ( t _>) g ( t , a ( t ) , ~ ' ( t ) > ) g ( t , a ( t ) , A;/(t)) - Y
Y
B"(t) = B"(t)
Y
Hence A
5
and
Y
g ( t , B(t), B ' ( t ) )
B
Y
X" =
(p,q)
(u,v)
E
union of
E
s n 1
S1,
S1
n
AY(t), A+(t)),
< g(t,
B(t), B+(t)) + y
= H(t,
By&), B;i(t))-
a r e s t r i c t lower and upper solutions of
(3.2.4) Let
= H(t,
H(t,x,x').
[ ( x , x ' ) : x = Q(o),
XI
2
B(0)l.
t h e l i n e segment from
(p,q)
[(y,yl): y = B(O),
t h e l i n e segment from
(u,v)
yi
to
and l e t
5 a'(0)1, Let
X
Y
be the
(p - ~ , q ) and
to
(u + y,v).
Consider now t h e BVP (3.2.4) with t h e boundary conditions (3.2.5)
(X(O),X'(O))
E
xY' 163
( x(t,>,x'
( t o >)
E
S2'
3 . TOPOLOGICAL METHODS
Let
E = [ ( t > X > X ' ) :O
Ix'I
<
Since
m1.
5 t 5 t O JQ ( t ) - 1 < X <
H(t,x,x') = 0
[ x ' I _> K
for
+
B(t)
+
1,
2,
we may
apply t h e proof of the f i r s t h a l f of t h i s theorem, r e c a l l i n g that
A (t), B ( t )
a r e s t r i c t lower and upper solutions Y Y respectively, t o conclude t h e existence of a solution Xy(t)
of t h e BVP (3.2.4),
< B ( t ) for - Y
X (t)
Y
for
2
Ix'I
K
+
2
(3.2.5) with t h e property t h a t A ( t ) < Y t E [O,tO]. Also, since H(t,x,x') = O i X r ( t ) [5 K
it follows t h a t
Y
+
2
on
By Kamke's convergence theorem a subsequence of converges t o a solution
Xo(t)
of (3.2.4) on
[O,tO].
n]i=l
{X
[O,tO]
11 such
that
( xo(l)Jxi)(l))
(xo(o)~xi)(o)) ' 1 ' Also A
a(t)
l/n
For
5
Xo(t)
(t) = a(t)
a(t)
g(t,x,x').
5
B(t),
- (l/n)
-< x -< B(t),
'2'
since
5 X l / n (t) 5
B(t) + ( l / n ) = Blln(t).
Ix'I < K + 1 we have
It follows, from
(?),
that
H(t,x,x') =
IXi)(t)[ < N
-< K.
Hence
s a t i s f i e s t h e BVP and t h i s concludes t h e proof of meorem Xo 3.2.1. It i s not necessary t o assume
t
and lower surface at which eventually hook
= 0
S1
i n t e r s e c t s t h e upper
provided t h e r e e x i s t solutions
S1 onto t h e lower and upper surfaces.
More precisely, we have t h e following r e s u l t .
THEOREM 3.2.2. a, B
Assume (H ) holds r e l a t i v e t o
3
E.
Let
B(t)
be lower and upper solutions f o r (3.2.1) with a ( t ) on [O,tO]. L e t S1 be a compact connected s e t i n
C(0)
and l e t
that
S2 fl [ ( x , x ' ) : x '
S2 be a closed connected subset of arbitrary]
#
@.
If
s1 such that
[(xl(u)Jxi(u))] 164
C(tO) such
(x,(t),xi(t))
and ( x 2 ( t ) , x h ( t ) ) a r e solutions of (3.2.1) with (x2(0)Jx6(0))
-<
( xl(0),xi(O)), s ~ ( u )# @
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
[(x,(V)Jx;(v))] n s 2 ( v ) # $ f o r some v E (OJt0IJ then t h e r e exists a s o l u t i o n x ( t ) of
f o r some
u
( o , ~ , I and
E
(3.2.1) with
< x(t) a(t) -
( x ( 0 ) J X ' ( 0 ) ) E S1j (X(t,),X' ( t o ) )
-< p ( t )
and
S2j
f o r a l l t E [OJtoI.
The proof i s similar t o t h a t o f Theorem 3.2.1
Proof: since
E
I (S , O , t )
E l Sp(t) for t
has a component i n t e r s e c t i n g
2 max[uJvl.
Sa(t)
and
I n Chapter 1, we have provided s u f f i c i e n t conditions f o r
(3) t o hold,
One such condition was Nagumo's condition.
We now o b t a i n a r e s u l t t o show how Nagumo's condition can be u t i l i z e d t o determine
S1 and S2.
lower and upper s o l u t i o n s of (3.2.1)
t
E
Let with
a(t)
and
a(t)
[ O J t O l . Define
A = max
I
Ia(0)
J
max
g(t,x,y)
J
Ia'(t)lJ
max lp'(t)l [OJt01
s a t i s f i e s Nagumo's condition lg(t>xJy)l
f o r a l l t E [,,to]'
-< B ( t )
IMO)- B(0) I
- B(to) I [OJt01
and assume
B ( t ) be
a(t)
5
(P(lYl)
-< x < B(t),
Letting
165
IyI
<
w
such t h a t
for
3. TOPOLOGICAL METHODS
we observe t h a t
THEOREM 3.2.3.
Assume
g(t,x,y)
s a t i s f i e s Nagumo's
a(t),B(t) E C(2)[0,to] with a ( t ) 5 B ( t ) . If S1 is any closed connected subset of C ( 0 ) such t h a t S1 fl S # 0, S1 n S4 # 0 and i f S2 is any closed 3 connected subset of C(to) such t h a t S2 n S # jd and 5 S2 n S6 # I ,then there e x i s t s a solution x ( t ) of (3.2.1) such t h a t (x(O),x' ( 0 ) ) E S1, ( x ( t o ) , x l ( t o ) ) f: S2 with condition with respect t o
a ( t >,< x ( t > 5 B ( t ) * Proof:
Choose
n
(o,xl,xi)
G
s1 n s3
and
(o,x2,x;)
E
Sq such t h a t both p i n t s belong t o t h e same component S1 of S1 n [(O,X,Y): 5 N l . Choose (O,B(O),x) ) E Sp(0) as follows. If x1 = p(O), l e t = xi; i f x1 < B(O), S1
c
choose
IY)
5 > N.
Let
%
be t h e l i n e segment joining 166
(0,xl,xi)
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
to
(O,p(O),x'), 3-
where, i n t h e case when
p(O), L1 = I n a similar manner, choose ( O , ~ ( O ) , X & c )
[ ( O , X ~ , X ; )c I sl. by l e t t i n g
xk = xh
Scy(0)
x2
>a(O)
and take
( O , X ~ , X ~t )o observe
x1
x2
if
= a(0)
or
=
xc
<
-N
if
t o be t h e l i n e segment joining
L2
(O,a(O),xi).
Let
ST
= L1 U
zl
and
U L2
ST i s compact, connected, and i n t e r s e c t s both
[(O,a(O),x'): x' 5 a ' ( O ) ] and {(O,p(O),x'): x' 2 p'(0)). Pick (t , x , x ' ) E S2 n s5 and (tO>X6'Xi) E s2 n s6
-
0 5 5
such t h a t both points belong t o t h e same component S2 S2
n
[(tO,X,X'):
l i n e s given by and l e t
s;
= L
5
5 N(tO)]. Let [(t0,x5,y): y 2 x;l IX'I
u 8, u L6.
Consider the BVP (3.2.1) (3.2.6)
(O,X(O),X'(O)) E
L5
and
of and L6 be t h e half [(to,x6,Y): y
and
( t0,x(to),x'(t0))
,s;
E
5 xi1
*
S2'
By the construction of
ST and t h e assumptions on g(t,x,y), there e x i s t s a compact, connected subset C C C(to) of the funnel cross section F(tO,O,ST) = i n t e r s e c t s both
uses++ F(tO,O,s)
which
1
S p ( t o ) : y 2 p t ( t o ) ] and Hence, by Theorem 3.2.1 the al(t,)].
[(tO,x,y)
E
[(tO,x,y) E S2(t0): y 5 BVP (3.2.l), (3.2.6) has a solution
x ( t ) with
a(t)
-< x ( t ) -<
B b ) , I x ' ( t O ) l 5 N(tO) and ( t O , x ( t O ) , x ' ( t O ) E) S2* From Nagumo's condition Ix'(0)I 5 N and by t h e construction of Sr, (O,x(O),x'(O)) E S1. This concludes the proof of Theorem 3.2.3. EXA.MFTE 3.2.1.
A s an application of t h i s r e s u l t consider
the following BVP a r i s i n g i n the dynamics of c e r t a i n chemical reactions. (3.2.7) (3.2.8)
X" = -LIX'
x(0) = 0,
- L2k(x),
x ' ( 1 ) = -L1X(l).
167
3 . TOPOLOGICAL METHODS
The positive constants
and
L1
of t h e physical problem with on
[O,c]
such t h a t
k(x)
L2
k(x)
>0
for
depend on various parameters continuous and nonincreasing 0
<x
and
k ( c ) = 0.
Theorem 3.2.3 gives t h e existence of a solution x ( t ) of t h e BVP (3.2.7), (3.2.8) with 0 < x(t) < c since m(t) = 0 and @ ( t )= c are lower and upper solutions, respectively, and Nagumo's condition i s c l e a r l y s a t i s f i e d .
3.3 WAZEWSKI RETRACT METHOD "his section i s devoted t o an application of t h e Wazewski r e t r a c t method t o (3.2.1) with boundary conditions
- blxl(0),
(3.3.1)
L1(x) = rl,
L1(x)
= alx(0)
(3.3.2)
L2(x) = r2,
L2(x)
= a2x(to) +
b2x1(t0).
Without loss of generality, we may assume b ,b > 0. Let 1 2 m(t) and B(t) be lower and upper solutions of (3.2.1) such that (3.3.3)
~ ~ ( 50 ri, )
(3.3.4)
Li(B)
We s h a l l assume t h a t
g
2
ri,
i = 1,2, i = 1,2.
s a t i s f i e s Negumo's condition, t h a t is,
As an application of Theorem
1.4.1, we obtain t h e following
lemmas.
168
3.3. WAZEWSKI RETRACT METHOD
U M M A 3.3.1.
Assume t h a t
Then, f o r every
> 0,
c
t h e r e e x i s t s a constant
t h a t each s o l u t i o n x ( t )
t
E
I
satisfies Nagmots condition.
g
satisfying
a(t)
M(c)
-< x ( t ) 5
such
p(t)
for
[O,tO] and which s a t i s f i e s
C
Jx'(sol
5
c
for
some
s0 E I
a l s o has t h e property
Assume t h a t t h e r e e x i s t s a s t r i c t lower
LEMMA 3.3.2.
solution a ( t )
and s t r i c t upper s o l u t i o n
t o ( 3 . 2 . 1 ) J s a t i s e i n g (3.3.3), all t
E
(3.2.1)
(3.3.4)
p(t)
with
with respect
< p(t) for
a(t)
Then, t h e r e e x i s t s a s o l u t i o n x o ( t )
[O,tO].
defined on
[O,h+&] C [O,tO] f o r some h _> 0 ,
of &
> 0,
a(t) < xo(t) 5 p(t) for a l l x o ( t ) > p ( t ) f o r t E (h,h+E].
s a t i s f y i n g (3.3.1) and such t h a t
t E [O,h], xo(h) = @(h) and S i m i l a r l y t h e r e e x i s t s a s o l u t i o n z o ( t ) s a t i s f y i n g (3.3.1), e x i s t i n g on an i n t e r v a l [O,k+ 61 C [O,tO] f o r some k _> 0, 6
> 0,
such t h a t
zo(h) = a ( h ) Proof:
and
a(t)
xo(0) = @(O),
zo(t)].
t
for
for a l l t
We show t h e existence of
y i e l d s t h e existence of letting
-< Zo(t) -< @ ( t )
zo(t) < a ( t )
E
xo(t)
E [ O J ~ ] ,
[k,k+61.
[ a similar proof
#
F i r s t assume bl
we o b t a i n from (3.3.4)
that
0;
then,
xA(0)
>
Hence t h e r e s u l t holds f o r h = 0.
p'(0).
Let
bl
#
0
and consider a s o l u t i o n s ( t )
s a t i s f y i n g , f o r each i n t e g e r
n,
xn(o) = r a 11'
169
x;(o> = n.
of (3.2.1)
3. TOPOLOGICAL METHODS
> M(B),
For N
there e x i s t s
s
0
E
[O,tO) satisfying %(so) =
and a ( t ) c % ( t ) < B(t), t E (O,so). Assume not; then e i t h e r cy(t) < % ( t ) < @ ( t ) f o r a l l t E (O,tO) o r there B(so)
T < to such t h a t x,(Tn) = a(Tn), a ( t ) < x n ( t ) < n for t E (O,%). I n e i t h e r case, there e x i s t s a
exists a
B(t), tNE [O,tO] such t h a t lXrj(tN)I 5 B. [In the second case, we make use of the f a c t < a r ( t N ) , since cy(t) i s a s t r i c t lower solution. ]
s(5)
Lemma 3.3.1,
since xP;(O)
= N,
ls(t)l-<
f o r t E [O,tNl and we have a contradiction f o r N > M(B). M(B)
Thus f o r some h E [O,t,I,a(t) 5 B(t) for a l l t E [O,hl and %(h) = p(h). Since p ( t ) i s a s t r i c t upper solution, we have
> B'(h). Thus, there e x i s t s an E > 0 such t h a t % ( t ) > p(t), t E (h,h+&]. The proof i s complete. Xp;(h)
U M M A
3.3.3.
by a parameter
simultaneously.
x(t,p)
Let
Let
p.
x(t,p)
open exterior of
U Int
where
t
M
=
C
be continuous i n
t
and
Let C be a simple closed curve i n the
plane and denote by I n t C C
be a family of functions indexed
and x ( t , p )
(t,x)
and E k t C the open i n t e r i o r and
Suppose t h a t f o r each
C.
p
p, (O,x(O,p))
is defined on an i n t e r v a l
E
[O,TM]
( T ,x(Tp,p)) E Ext C. Define y(p) = t where CI CI sup[t > 0 : ( t , x ( t , p ) ) E I n t CI. Then y is bwer semi-
continuous.
If, i n addition, each M c t i o n
x(t,p)
has the
t
t + h ), P' CI l.l then y i s continuous. (Lemma 3.3.3 is another version of the Wazewski method.) additional property t h a t
THEOREM 3.3.1.
B(t)
(t,x(t,p))
E
Ext C
for
E
(t
Assume t h a t there e x i s t s an upper solution
-
and a lower solution a ( % ) of (3.2.1) with cy(t) < B(t)
Let f f o r a l l t E [O,tOl, s a t i s w i n g (3.3.3) and (3.3.4). satisfy Nagumo's condition with respect t o cy and B. Then there is a solution x ( t ) of t h e B" (3.2.l), (3.3.1), (3.3.2) 170
3.3. WAZEWSKI RETRACT METHOD
Proof:
We may assume t h a t (3.3.5)
since we may redefine
g
o u t s i d e of
holds f o r a l l x D
E
R
so t h a t t h e Nagwno’s
condition w i l l hold. that g
We f i r s t prove Theorem 3.3.1 under t h e stronger hypotheses w ( t ) and B(t) a r e s t r i c t lower and upper s o l u t i o n s and
i s l o c a l l y Lipschitzian.
We w i l l then show how these
hypotheses may be weakened. Consider the s e t of s o l u t i o n s of (3.2.1) and (3.3.1) such that a ( 0 ) < x(0) < p(0). These s o l u t i o n s form a one-parameter family of functions a r e connected.
{x(t,p)],
where t h e s e t of values of
Define a map cp:
P
--f
( t p , x ( t p , PI),
t i s defined i n Lemma 3.3.3 i n which C P Jordan curve forming t h e boundary of t h e region x ( t , p) i s continuous i n both t and p since Lipschitz and thus applying Lemma 3.3.3 we have continuous. Thus cp i s continuous and {rp(p)} Combining Lemma 3.3.2 w i t h t h e connectedness of have the existence of v1 and p2, such t h a t
is the
where
Since
CY
and
p
0
are strict solutions
171
D.
g
Now i s locally
y: p -+ t is CL i s connected. {cp(p)}, we
3. TOPOLOGICAL METHODS
The solution x ( t , p o )
i s a solution of BVP (3.2.l),
(3.3.2). We no longer assume From (3.3.6),
g
(3.3.1),
s a t i s f i e s a Lipschitz condition.
there e x i s t s an
>0
E~
such t h a t i f
<
0
E
<
then
There e x i s t s a sequence of l o c a l l y Lipschitzian functions
E gn ( t , x, Y 1Inzl M
2 [O,tO]X R
.
Ign(t,x,y) Pick N
which converge t o
g(t,x,y)
Assume t h a t
- g(t,x,y) I 5
1/n
so large such t h a t
for 1/N
5
n
> N, a
(t,x,y)
[0,t0I X R
2
and
E~
1/< ~ inf[Iatt - g ( t , a , a l ~ ,
Thus, f o r
uniformly on
IB"
-g(t,~,~f)Il,
p w i l l be s t r i c t lower and s t r i c t
and
upper solutions for (3.3.7)
XI'
= gn(t,x,x'),
where Ign(t,x,y)
I 5 h ( IY I )
+
(l/n)*
By o u r previous analysis, t h e r e e x i s t s a function s ( t ) s a t i s f y i n g (3.3.7), (3.3.1), and (3.3.2). From t h e mean value theorem, there e x i s t s a such t h a t
Ix'(T)I
5
K/to
Choose M = M(K)
= K1.
so large t h a t
SMiqq K1
Then, t h e r e e x i s t s
N1,
sds
'K*
such t h a t f o r 172
n
> N1
T
E
[O,tO]
E ~ ,
3.3. WAZEWSKI RETRACT METHOD
s
s ds + (l/nl
h(s) K1
As i n the proof of Theorem 1.4.1,
> K.
we have f o r
t
Ix;(t)l
IM(K)
for
all
Ixn(t)I
IK
for
all t
n
> N1j
E [OJtO].
Since E
[OJtO]J
it follows t h a t Ixi(t)
I I max[lg(tJxJy)I 1x1
Therefore t h e sequence
5 K,
[O,to],
+ 1:
I MI. for n > max(N,N1)
IYI
{xn(t)?,
subsequence which converges i n t h e
C(l)
function i s then a solution of (3.2.1)
norm.
has a
The l i m i t
and s a t i s f i e s (3.3.1)
and (3.3.2). We now remove t h e r e s t r i c t i o n t h a t a ( t ) and B(t) are s t r i c t lower and upper solutions. Let p: [O,tO] -+ (O,tO] satisfy
p"(t)
i = 1,2,
and
-< 0
for a l l t
E
[O,tOl Li(p) 2 0
a,(t) = a ( t )
Define 173
for
i = 1,2,
for
i = 1,2.
for
- EP(t).
3. TOPOLOGICAL METHODS
and l e t
where
6 ( & ) i s t h e modulus o f c o n t i n u i t y of
g(t,x,y)
domain D' = [ ( t , x J y ) : t E [ 0 , t 0 I ,
1x1 5 K, IyI i s defined as before and S > max (M(K), "Pt
5
K
E [0
[O,tOl I p ' ( t ) l ) .
Since
and
Ig(t,c?Jc?')- g(t,ct&Jc?;)l <
y& ( t , a E Ja E' ) E
to1 l a w I >
<
we have
= -2
g ( t , a , a ' ) = B(t,CY&,CYL) E
where
laE(t)-a(t)l + la;(t)-al(t)l
SU%€
Moreover, since
SIJ
on t h e
E
- 6(E).
Hence
a; > a"
aE i s a s t r i c t l o w e r s o l u t i o n o f
Thus
Similarly
BE i s a s t r i c t upper s o l u t i o n of (3.3.8).
Furthermore,
as
-> g ( t , a , a ' ) > gE(t,aE,a;).
E
+O.
g (t,xJy) E
Therefore
converges t o
g (t,x,y) E
g(t,x,y)
uniformu
satisfies Nagumo's condition
and as before t h e r e e x i s t s a s o l u t i o n x E ( t J x , y ) of (3.3.8), (3.3.1),
and (3.3.2).
Moreover, 174
Ex,}
converges i n t h e
C(l)
E
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
The l i m i t i n g f'unction i s then a s o l u t i o n of the BVP (3.2.1), (3.3.1), and (3.3.2). This concludes the proof of Theorem 3.3.1.
norm as
E
+ 0.
REMARK 3.3.1.
The significance of t h i s r e s u l t i s that we can show existence of solutions of t h e Neumann problem, that i s , when a1 = a2 0 i n (3.3.1) and (3.3.2). Observe t h a t except f o r t h i s very important case Theorem 3.3.1 i s a consequence of Lemma 3.3.2 and Theorem 3.2.2. The following example i l l u s t r a t e s Theorem 3.3.1. EXAMPLE 3.3.1.
Assume r1
=
and. satisfies Nagumo's condition.
r2 = 0 Let
and
(3.3 . l o ) then, from (3.3.9)
c > 1/E
t € [O,
11
e x i s t and satisfy
gx
Then the boundary value problem (3.2.1), a solution. To see t h i s l e t Ig(t,O,O)
g: [0,1]xR2 - t R
(3.3.1),
(3.3.2) has
I;
we have
g(t,O,O) -g(t,-C,O) _> CE. Using (3.3.10 ) , we then obtain
g(t,-C,O) < 0. Thus a ( t ) = -C i s a b w e r solution and similarly ~ ( t =) c i s an upper s o l u t i o n f o r (3.2.1), (3.3.1), and (3.3.2). By Theorem 3.3.1, there exists a solution of t h e BVP (3.2.l), (3 03 el), (3 e3.2). 3.4
GENERALIZED DIFFERENTIAL EQUATIONS
I n t h i s section we develop a Wazewski theorem f o r con-
tingent d i f f e r e n t i a l equations and. u t i l i z e it t o prove 175
3. TOPOLOGICAL METHODS
existence theorems f o r BVP's. The following preliminaries w i l l prove usef'ul i n t h e discussion.
Let
(cc(Rn)) be t h e c o l l e c t i o n of a l l
c(Rn)
nonempty compact (compact and convex) subsets of
x
and A,B E c(Rn),
E Rn
and
let
For
Rn.
q(x,B) = i n f [ l l x - b ( ( : b c B]
q(A,B) = sup[q(x,B): x E A].
Then
d(A,B)
I
max[q(B,A),q(A,B)] i s t h e Hausdorff metric on c(Rn) and n c(R ) i s a complete metric space. Let V be a subset of R x R n and denote t h e points of V by
p = (t,x).
continuous (USC) at a
6
>0
such t h a t
If we replace
continuous
> 0,
p E V
i f , f o r each
E
IlQ-pII
<
q(F(Q),F(p))
implies
6
q(F(Q),F(p)) by
d(F(Q),F(p)),
X be an open subset of
Let
be USC.
.
i s upper semi-
F: V + c(Rn)
A mapping
RxRn
there e x i s t s then
and l e t
<
E.
is
F
F: X +cc(Rn)
A s o l u t i o n of t h e generalized d i f f e r e n t i a l equation
(3 4.1)
x ' E F(t,x)
9
i s a function
cp: I + R
n
which is absolutely continuous on
each compact s u b i n t e r v a l of everywhere on For
I
and
cp' ( t ) E F(t,cp(t))
almost
I.
E C X
and
po = (to,xo),
an accumulation point of
at p0 i s D+(E,pO) = [y E Rn: t h e r e e x i s t s {(tn,xn)3 C E, (tn,xn) + (to,xo), tn > to, ( x n - x O ) / ( t n - t O ) + y as n + m I . The negative E,
E
t h e p o s i t i v e contingent of
contingent and contingent of
similar manner. then w r i t e
If
+ D cp(to)
E
E
at
p
0
a r e defined i n a
i s t h e graph of a function
instead of
+ D (E,pO).
cp: I +Rn,
A solution of t h e
contingent equation
(3.4.2)
Dx C F ( t , x )
i s a continuous function
F(t,cp(t))
f o r a l l t E I.
cp: I + R n
such t h a t
A function
176
cp(t)
Dcp(t) C i s a solution
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
of (3.4.1) if and only i f it i s a s o l u t i o n of (3.4.2). The b a s i c theory f o r generalized equations hold; namely, t h e Peano's e x i s t e n c e theorem, e x t e n d a b i l i t y of s o l u t i o n s , and t h e Kamke convergence theorem are true f o r generalized equations, and we shall not expound on t h i s f'urther. Denote t h e maximal i n t e r v a l of existence of a s o l u t i o n D Before s t a t i n g a Wazewski theorem f o r cp' generalized equations, we w i l l need t h e following d e f i n i t i o n .
cp(t)
of (3.4.1) by
DEFDIITION 3.4.1.
A s e t A c X i s ( p o s i t i v e l y ) weakly i n v a r i a n t
with r e s p e c t t o (3.4.1) if f o r each po = ( t O , x o ) E A , t h e r e i s a solution V(t) of ( 3 . 4 . l ) w i t h cp(to) REMARK 3.4.1.
(t,cp(t)) E A
A closed set
v a r i a n t if and only if
LEMMA 3.4.1.
=Xo,
on
D cp
I [tO,m).
i s p o s i t i v e l y weakly in-
E
+ D (E,pO) fl F(pO) f 6
f o r all po
E
E.
are r e l a t i v e l y closed, X with X = E U E2. 1 i s p o s i t i v e l y weakly i n v a r i a n t .
Assume
and E2 1 p o s i t i v e l y weakly i n v a r i a n t subsets of Then H = E fl E2 1 Proof:
Let
two s o l u t i o n s and an Let
a> 0
L(t)
E
po = ( t O , x O ) E H.
qi(t)
By hypotheses, t h e r e e x i s t
of (3.4.1) with (t,cpi(t))
such t h a t
be t h e segment j o i n i n g
E
(pi(to) = xo, Ei
to 5 t < to + a.
for
(t,cpl(t))
i = 1,2,
to
(t,cp,(t)
)
( E n~ E~). Then x ( t ) = a(t)cpl(t) + (1-ct(t))cp2(t), 0 5 a ( t ) ,< 1. Choose a sequence {t,); + t n + t o , and a ( t n ) +ao. Then and l e t
(t,x(t)) E L(t)
n
We now can choose a subsequence
{t,]
t h e l i m i t t h e l e f t s i d e belongs t o s i d e equals
aovl + ( 1 - a o ) v 2
where
177
of
{t,}
Df(H,pO) vi
E
such t h a t i n
and t h e r i g h t
D+cpi(to).
3 . TOPOLOGICAL METHODS
By convexity, D+(H,pO) H
cy
n F(pO) # fl
v + (1-wo)v2 i s i n F(pO) and thus 0 1 and as a r e s u l t , by our previous remark,
i s p o s i t i v e l y weakly i n v a r i a n t .
This concludes t h e proof of
Lemma 3.4.1. The following i d e a s w i l l be needed f o r t h e Wazewski theorem. For
vc
po = ( t O J x O ) E
t h e zone of emission r e l a t i v e t o
X,
is
Ev(po) = [(T,y): y = cp(T), cp(t) with cp(to) = xo and ( t , c p ( t ) ) E V and
21,
v
i s a s o l u t i o n of (3.4.1)
t between to
for a l l
and t h e r i g h t zone of emission r e l a t i v e t o
'
is
V
E;(Po) = [(.JY>: ( T ~ Y )E Ev(Po), >_