An Introduction to Nonlinear Boundary Value Problems
This is Volume 109 in MATHEMATICS IN SCIENCE AND ENGINEERING A series of monographs and textbooks Edited by RICHARD BELLMAN, University of Southern California The complete listing of books in this series is available from the Publisher upon request.
An Introduction to Nonlinear BoundaryValue Problems Stephen R. Bernfeld Department of Mathematics Memphis State University Memphis, Tennessee
V Lakshmtkantham Department of Mathematics University of Texas Arlington, Texas
Academic Press, Inc.
New York and London
I974
A Subsidiary of Harcourt Brace Jovanovich. Publishers
COPYRIGHT 0 1974, BY ACADEMIC PRESS, INC. ALL RIGHTS RESERVED. NO PART OF THIS PUBLICATION MAY BE REPRODUCED OR TRANSMITTED IN ANY FORM OR BY ANY MEANS, ELECTRONIC OR MECHANICAL, INCLUDING PHOTOCOPY, RECORDING, OR ANY INFORMATION STORAGE AND RETRIEVAL SYSTEM, WITHOUT PERMISSION IN WRITING FROM THE PUBLISHER.
ACADEMIC PRESS, INC.
111 Fifth Avenw, New York. New York loo03
United Kingdom Edition published by ACADEMIC PRESS, INC. (LONDON)LTD. 24/28 Oval Road, London NWl
Library of Congress Cataloging in Publication Data Bernfeld, Stephen R An introduction to nonlinear boundary value problems. (Mathematics in science and engineering, v. ) Bibliography: p. 1. Boundary value problems. 2. Nonlinear theories. I. Lakshmikantham,V., joint author. 11. Title. 111. Series. QA319.B41 515l.35 73-21996
ISBN 0-12-093150-8
Contents Preface . . . Acknowledgments
ChuprerI 1 .0. 1.1. 1.2. 1.3. 1.4. 1.5. 1.6. 1.7. 1.8. 1.9. 1.10. 1.11. 1.12. 1.13. 1.14. 1.15. Chapter 2
2.0. 2.1. 2.2. 2.3.
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
MethodsInvolvingDifferentialInequalities . Introduction . . . . . . . . Existencein thesmall . . . . . Upper and Lower Solutions . . . TheModifiedFunction . . . . . Nagumo’s Condition . . . . . Existence in the Large . . . . . Lyapunov-Like Functions . . . Existence on Infinite Intervals . . Super-and Subfunctions . . . . Properties of Subfunctions . . . Perron’s Method . . . . . . . ModifiedVectorFunction . . . Nagumo’s Condition (Continued) . Existence in the Large for Systems. Further Results for Systems . . . Notesandcomments . . . . .
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ix
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. . . . . . . . . . . . . Introduction . . . . . . . . . . . . . . . . . Shooting Type Methods
Uniqueness Implies Existence . . . General Linear Boundary Conditions . Weaker Uniqueness Conditions . . . V
1 1 2 12 18 25 31 39 44 46 52 62 69 74 81 84 93 94 94
. . . . . . . . 94 . . . . . . . . 101 . . . . . . . . 109
CONTENTS
2.4. 2.5. 2.6. 2.7. 2.8. 2.9. 2.10. 2.1 1. 2.12.
Chapter 3 3.0. 3.1. 3.2. 3.3. 3.4. 3.5. 3.6.
Chapter 4 4.0. 4.1. 4.2. 4.3. 4.4. 4.5. 4.6. 4.7. 4.8. 4.9. 4.10. 4.1 1. 4.12. 4.13. 4.14. 4.15. 4.16. 4.17.
Nonlinear Boundary Conditions . . . Angular Function Technique. . . . . Fundamental Lemmas . . . . . . . Existence . . . . . . . . . . . Uniqueness . . . . . . . . . . Estimation of Number of Solutions . . Existence of Infinite Number of Solutions Nonlinear Boundary Conditions . . . Notes and Comments . . . . . . . Topological Methods
. . . . . . . 113 . . . . . . . 116
. . . . . . . 117 . . . . . . . 121 . . . . . . . 127
. . . . . . . 136
. . . . . . . 142 . . . . . . . 145 . . . . . . . 152
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Introduction . . . . . . . . . . . Solution Funnels . . . . . . . . . Application to Second-Order Equations . . Wazewski Retract Method . . . . . . Generalized Differential Equations . . . Dependence ofSolutions on Boundary Data Notes and Comments . . . . . . . . Functional Analytic Methods
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Introduction . . . . . . . . . . . . Linear Problems for Linear Systems . . . . Linear Problems for Nonlinear Systems . . . Interpolation Problems . . . . . . . . Further Nonlinear Problems . . . . . . . Generalized Spaces . . . . . . . . . . Integral Equations . . . . . . . . . . Application to Existence and Uniqueness . . Method of A Priori Estimates . . . . . . Bounds for Solutions in Admissible Subspaces . b r a y Schauder’s Alternative . . . . . . Application of LeraySchauder’s Alternative . Periodic Boundary Conditions . . . . . . Set-Valued Mappings and Functional Equations General Linear Problems . . . . . . . . General Results for Set-Valued Mappings . . Set-Valued Differential Equations . . . . . Notes and Comments . . . . . . . . . vi
153
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. 232 . 248 . 256 . 263 . 265 . 269 . 278 . 282 . 289 . 295 . 302
CONTENTS
. . . . . 304 Introduction . . . . . . . . . . . . . . . . . 304 Existence in the Small . . . . . . . . . . . . . . 304
Chapter5
Extensions to Functional Differential Equations
5.0. 5.1. 5.2. 5.3. 5.4. 5.5. 5.6. 5.7. 5.8.
Existence in the Large . . . . . . . . . Shooting Method . . . . . . . . . . Nonhomogeneous Linear Boundary Conditions Linear Problems . . . . . . . . . . . Nonlinear Problems. . . . . . . . . . Degenerate Cases . . . . . . . . . . Notes and Comments . . . . . . . . .
Chapter 6 6.0. 6.1. 6.2. 6.3. 6.4. 6.5. 6.6.
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. 312 . 315 . 320 . 324 . 330 . 335
. . . . . . . . . . . . . . . . 337 Introduction . . . . . . . . . . . . . . . . . 337 Newton's Method . . . . . . . . . . . . . . . 337
Selected Topics
The Goodman-Lance Method . . . . . . . The Method of Quasilinearization . . . . . . Nonlinear Eigenvalue Problems . . . . . . . n-Parameter Families and Interpolation Problems . Notes and Comments . . . . . . . . . .
Bibliography . . . . Additional Bibliography Index
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vii
385
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'Ihe theory of nonlinear boundary value problems is an extremely important and interesting area of research in differential equations. Due to the entirely different nature of the underlying physical processes, its study is substantially more difficult than that of initial value problems and consequently belongs to a third course in differential equations. Although this sophisticated branch of research has, in recent years, developed significantly, the available books are either more elementary in nature, for example the book by Baily, Shampine, and Waltman, or directed to a particular method of importance, such as that by Bellman and Kalaba. Hence it is felt that a book on an advanced level that exposes the reader to this fascinating field of differential equations and provides a ready access to an up-to-date state of this art is of immense value. With this as motivation, we present in our book a variety of techniques that are employed in the theory of nonlinear boundary value problems. For example, we discuss the following: (i) methods that involve differentid inequalities; (ii) shooting and angular function techniques; (iii) functional analytic approaches; (iv) topological methods. We have also included a chapter on nonlinear boundary value problems for functional differential equations and a chapter covering special topics of interest. The main features of the book are (i) a coverage of a portion of the material from the contribution of Russian mathematics of which the English speaking world is not well aware; (ii) the use of several Lyapunov-like functions and differential inequalities in a fruitful way; (iii) the inclusion of many examples and problems to help the reader develop an expertise in the field. This book is an outgrowth of a seminar course given by the authors. We ix
PREFACE
have assumed the reader is familiar with the fundamental theory of ordinary differential equations, including the theory of differential inequalities, as well as the basic theory of real and functional analysis. It is designed to serve as a textbook for an advanced course and as a research monograph. It is therefore useful to the specialist and the nonspecialist alike. The reader who is familiar with the contents of the book, it is hoped, is fully equipped to contribute to the area.
X
Acknowledgments We wish to express our warmest thanks to Professor Richard Bellman whose interest and enthusiastic support made this work possible. We are immensely pleased that our book appears in his series. m e staff of Academic Press has been most helpfil. We thank our colleagues who participated in the seminar on boundary value problems at the University of Rhode Island in 1971-1972. In particular, we appreciate the comments and criticism of Professors E. Roxin, R. Driver, and M. Berman. Moreover, we gratefilly acknowledge several helpfil suggestions offered by Professor L. Jackson. We are very much indebted to Professors G.S. Lad& and S. Leela for their enthusiastic support in many stages of the development of this monograph and to Mr. T. K. Teng for his careful proofreading. Moreover, we wish to thank Mrs. Rosalind Shumate and Mr. Sreekantham for their excellent typing of the manuscript, and we wish to express our appreciation to Ms.Elaine Barth for her superb vping of the final copy. m e first-mentioned author wouM like to acknowledge some interesting helpfirl discussions on boundary value problems with the differential equation 3 group at the University of Missouri at Columbia. Finally, the final preparation of this book was facilitated by a National Science Foundation Gmnt GP-3 7838.
xi
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Chapter 1 METHODS INVOLVING DIFFERENTIAL INEQUALITIES
1.0
INTRODUCTION A variety of techniques a r e employed i n the theory of
nonlinear boundary value problems.
!Chis chapter i s primarily
concerned with the methods involving d i f f e r e n t i a l inequalities. The basic idea i s t o modify the given boundary value problem suitably, and then t o use the theory of d i f f e r e n t i a l inequalities and the existence theorems i n the small t o establish the desired existence r e s u l t s i n the large. After presenting needed existence theorems i n the small, we f i r s t concentrate on scalar second-order d i f f e r e n t i a l equations and associated boundary value problems.
We then
introduce upper and lower solutions, discuss the modification technique, and u t i l i z e Nagumo's condition t o obtain a p r i o r i bounds on solutions and t h e i r derivatives.
Once we have these
bounds a t our disposal, t o prove existence theorems on f i n i t e o r i n f i n i t e intervals i s r e l a t i v e l y simple and straightforward. Boundary value problems subjected t o nonlinear boundary conditions as well are treated i n t h i s framework.
We then
develop Q,rapunov-like theory f o r boundary value problems employing several w a p o v - l i k e functions and the theory of d i f f e r e n t i a l inequalities i n a f r u i t f u l way.
We also t r e a t
i n d e t a i l Perron's method of proving existence i n the large 1
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
by u t i l i z i n g the properties of sub-
and superf'unctions and
the existence r e s u l t s i n the small.
!Ibis technique works well
f o r scalar equations. We next extend the r e s u l t s considered f o r scalar equations t o 8 f i n i t e system of second-order d i f f e r e n t i a l equations. Here there are two directions t o follow, t h a t is, e i t h e r t r y t o obtain the required bounds componentwise o r i n terms of a convenient norm. We o f f e r r e s u l t s from both points of view indicating t h e i r r e l a t i v e merits and using I&-apunov-like theory, whenever possible, t o derive general r e s u l t s . 1.1 EXISTENCE IN l E 3 SMALL
denote t h e r e a l n-dimensional, Euclidean space
Rn
Let
and f o r x
E
Rn,
16(11
let
denote any convenient norm of
x.
be the i n t e r v a l
[a,b]. We s h a l l mean by C(n)[A,B] the class of n-times continuously differentiable functions Let
J
from a s e t A
into
8.
set
B.
We w i l l be concerned, i n t h i s section, w i t h the existence of solutions of the second-order d i f f e r e n t i a l equations of the form (1.1.1)
x" = P(t,x,x'),
satisfying the boundary conditions (1.1.2) where
n n
f E C[JXRnXR ,R
3.
For the purposes of t h i s chapter,
we also need an existence r e s u l t under more general boundary conditions.
This we do consider f o r the s c a l a r case, l e a v i a
a thorough discussion of the general theory t o a l a t e r chapter. F i r s t of a l l , we observe t h a t the only solution of (1.1.3)
XI1 =
0,
subject t o the boundary conditions 2
1.1. EXISTENCE IN THE SMALL
i s the t r i v i a l solution.
This implies, from the theory of
linear d i f f e r e n t i a l equations, that there e x i s t s a unique solution of
(1.1.5)
h(t),
X" =
satisfying (1.1.4) f o r each h
E
C[J,Rn].
Moreover, since the
problem (1.1.3), (1.1.4) possesses the two l i n e a r l y independent solutions u ( t ) = (t - t l ) J v ( t ) = ( t 2 -t ) , the method of variation o f parameters readily gives the i n t e g r a l equation (1.1.6)
x(t) =
+
-
(t2- t ) (S tl)h(S)
jr2(t -
tl)(t2
- s ) h ( s ) ds
dS
I
for the solution x ( t ) of (1.1.5) subject t o (1.1.4). Relation (1.1.6) can be written i n the familiar form
"1 where
i s usually referred t o as the Green's f'unction f o r the boundary value problem i n question. Hence
%is function G(t,s)
the solution of (1.1.5) verifying conditions (1.1.2) takes the form
3
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(1.1.8)
x(t) =
rt2
G(t,s)h(s) ds
+ w(t),
w(t2) = x where w”(t) = 0 and w(t,) = x 1’ 2‘ follows that if x ( t ) is a solution of (1.1.1), (1-1-9)x ( t )
=lt2
G(t,s)f(S,x(s),
~ ‘ ( 8 ) )ds
It therefore
(1.1.2),
then
+ w(t).
Conversely, i f x ( t ) i s a solution of (1.1.9), we can verify by differentiation of (1.1.6) that x ( t ) s a t i s f i e s ( l . l . l ) , (1.1.2). L e t us next r e c a l l some properties of the function G(t,s) f o r later use. For a fixed t, the maximum of IG(t,s)l i s attained a t s = t and IG(t,t)l has i t s maximum value at t = (t1+t2)/2, that i s ,
(1.1. lo)
Iw,~)I
5 ( t 2 - tl)/J+
Furthermore,
and consequently
Wreover,
-
ds = ( ( t tl)
2
+ (t2 - t ) 2 ) / 2 ( t 2
- tl) ,
the maximum of which is attained a t t = t l and t = t 2 . Hence, we obtain 4
1.1. EXISTENCE IN THE SMALL
We are now ready t o prove an existence and uniqueness r e s u l t by using t h e contraction mapping theorem,
where
K, L
>0
are constants such t h a t
Then the boundary value problem ( l . l . l ) ,
(1.1.2) has a unique
solution. Proof: u E CT[[tl,t2],
Let
B
Rn]
Define the operator Tu(t)
be the Banach space of functions with t h e norm
T: B + B
=Lt2
by
G ( t , s ) f ( s , u ( s ) , u t ( s ) ) ds
1
We then have, by (1.l.l.l)and (1.1.13),
Also, because of (l.l.l2), 5
+ w(t).
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
It then follows t h a t
ThisJ i n view of assumption (1.1.14)' shows t h a t
T
is a
contraction mapping and thus has a unique fixed point which i s t h e solution of t h e problem (l.l.l)J (1.1.2).
m e proof i s
complete.
An i n t e r e s t i n g problem i s t o f i n d the l a r g e s t possible i n t e r v a l i n which t h e preceding theorem i s v a l i d . f E C[JXRXR,R],
when
result.
I n t h e case
one can o f f e r such a best possible
We have i n t e n t i o n a l l y given such a r e s u l t i n t h e
following exercise with generous h i n t s . EXERCISE 1.1.1. Assume t h a t
s a t i s f i e s (1.1.13).
Let
(1.1.15)
U"
which vanishes a t number such t h a t
t
u(t)
and
be any solution of
+Lu' + K u = 0
t
and l e t a(L,K) be t h e f i r s t unique 1 u l ( t ) = O f o r t = t l + a ( L J K ) . Show t h a t t h e =
boundary value problem (1.1.1)' if
f E C[JxRXR,R]
(1.1.2) has a unique solution
t 2 - t l < 2a(LJK) and t h a t t h i s r e s u l t i s best possible. Hints:
Step 1. F i r s t show t h a t t h e r e i s a unique solution
t o t h e boundary value problem x 1 ( t 3 )=
3
if
XI'
-
(t3 tl) < a(L,K).
= f(t,x,x'), x(t ) = x 1 1'
This can be shown by apply-
ing the contraction mapping theorem r e l a t i v e t o the M a c h space
E = C(1)[[tl,t3],R]
with t h e norm 6
1 . 1 . EXISTENCE IN THE SMALL I-
where u o ( t )
>0
i s a solution of
for
Lu' +Ku =
+
UI'
cy
s u f f i c i e n t l y close t o 1.
cy
Step 2.
Show t h a t the existence of unique solutions of
(l.l,l),(1.1.2) and of (1.1.1)with e i t h e r
x ( t l ) = x 1' ) = x 3 ' x ( t 2 ) = x 2 on any i n t e r v a l of
x'(t ) = x or x ( 3 3 ' length l e s s than
implies the existence of a unique solution
d
of (1.1.1)' (1.1.2) on any i n t e r v a l of length l e s s than Step 3. show t h a t ing
2d.
To prove t h a t the r e s u l t i s the best possible
u" + Llu'
I + Ku = 0
u(t,) = u ( t 2 )= 0,
where
has a n o n t r i v i a l solution verif'y-
t2- t l =2CY(L,K).
Since u ( t ) = O
also s a t i s f i e s the problem, argue t h a t the r e s u l t i s best possible.
Observe t h a t
EXERCISE 1.1.2.
i n Theorem 1.1.1f o r where N
m
a(L,K)
can be e x p l i c i t l y computed.
Show t h a t it i s s u f f i c i e n t t o define
t
E
/(XI( -< N,
[tl,t21y
IIx' 11 < 4N/(t2
f
- tl),
satisfies either
2 ( t 2 tl>
-a
-< N [ l - ( K
Hint: Apply hll05 N where
2 ( t 2 tl>
-a
t h e contraction mapping theorem on the b a l l
7
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
To obtain merely an existence result we employ Schauder's
fixed point theorem as is usual.
THEOREM 1.1.2. l e t , f o r t E J, IlxII where
f E
I& M > 0, N
ItYII ,< PJ,
5 m,
C[JFRnXRn ,Rn 1.
>0
be given numbers and
Ilf(t,x,Y)II
5
q,
Suppose that
6 = 1nin[(8M/q)~, 2N/ql. Then any problem (1.1,1), (1.1.2) such that [t1,t21 J, t2 tl I 6, Ilx1II 5 M, I ~ x, I 5 M, and Ilx, x211/(t2 t l ) I N, has a solution. Furthermore, given any E > 0, there i s a solution x ( t ) such that
-
-
-
llx(t) -W(t)ll < E, Ilx*(t) -wl(t)ll t2 tl i s sufficiently small.
-
is a closed, convex subset o f
bY
ICx(t)
=
< E on [tl,t21, provided
B. Define the mapping T: B+B
1"'
G(t,s) f (s,x(s),xl (s)) ds + w(t).
Using now estimates (l.l.ll), (l.l.E!),
8
we obtain
1.l.EXISTENCE IN
THE SMALL
and
t2- t l 5 6, T maps
Hence, f o r
II(W"(t)Il
5
into i t s e l f .
Bo
Ilf(t,x(t), x ' ( t ) ) l l
by Ascoli's theorem it follows t h a t
T
5
Also, since
q,
i s completely continuous.
Schauder's fixed point theorem therefore assures t h a t fixed point i n If
x(t)
which i s a solution of ( l . l . l ) ,
Bo,
x
IIx(t) - w ( t )
t
E
(1.1.2).
i s a solution of t h e boundary value problem
(l.l.l), (1.1.2), with
for
T has a
[tl,t2].
E
Bo,
then we have
-
II 5
( ( t 2 tl12/8) 9,
Consequently t h e last assertion follows and
the proof of Theorem 1.1.2 i s complete. COROLLARY 1.1.1. Assume t h a t
and i s bounded on
[tl,t2] XRn xRn.
f E C[[t,,t2]
x R n xRn,Rn]
Then every boundary value
problem (l.l.l), (1.1.2) has a solution. Proof:
where
q
Pick M
>0
s u f f i c i e n t l y large so t h a t
i s an upper bound of
f.
The conclusion then follows
from Theorem 1.1.2.
As was indicated e a r l i e r , we s h a l l next discuss the 9
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
s i t u a t i o n where f E C [J XR x R , R ] . Then a natural question is under what general boundary conditions can one construct a Green's m c t i o n f o r the scalar equation (1.1.3). L e t us look a t t h e boundary conditions
- a2x1 (t,)
(1.1.16)
alx(tl)
(1.1.17)
b x ( t 2 ) +b2X1( t 2 ) = 0 .
= 0,
1
A s long as there e x i s t two l i n e a r l y independent solutions of
(1.1.3) satisfying (1.1.16), ( l . l . l 7 ) , it is possible t o cons t r u c t the desired Green's f'unction. One sufficient condition i s t o f i n d two nonparallel l i n e s satisfying (1.1.16) and (1.1.17), t h a t i s , demanding t h a t alb2 + a2bl
(1.1.18)
#
0.
Another s u f f i c i e n t condition, for example, i s t o require t h a t a2b2 = 0 . I n view of these remarks, it is s u f f i c i e n t t o assume that a1+ b1 > 0,
2 0,
(1.1.19) al,a2,bl,b2
and
a2+b2
> 0.
L e t us now consider the nonhomogeneous boundary conditions (1.1.20)
alx(tl)
-
(1.1.21)
blx(t2)
+ bF'(t2)
a2x1(tl) = A, = B.
It i s not difficult; t o conclude the existence of a solution cp(t) satisfying (1.1.3) and (1.1.20), (1.1.21). Thus any
solution x ( t ) of (1.1.1)obeying the boundary conditions (1.1.20) and (1.1.21), takes the form (1.1.22)
x(t)
Go(t,s)f(s,x(s>,x(s>)
= Jt2
1 where 10
+ T'(t),
1.1. EXISTENCE IN THE SMALL
and
- v(t)u'(t).
c = u(t)v'(t)
Here we assume u ( t ) , v ( t )
are two l i n e a r l y independent solutions o f (1.1.3)which s a t i s f y
(1.1.16), (1.1.17). This discussion leads t o t h e following result. TEEOREM
1.1.3.
[tl,t2] X R X R . (1.1.20),
f E C [[t,,t2]
Let
X R xR,R],
bounded on
Then t h e boundary value problem (l.l.l),
(1.1.21) has a solution, whenever (1.1.18) o r (1.1.19)
holds. Proof:
Let
Define a mapping
M be the bound of T: E + E
where the Banach space
f
on
[tl,t2] x R X R .
by
E = C ( l ) [[tl,t2],R]
Letting
it follows t h a t 11
with t h e norm
1. METHODS INVOLVING DIFFERENTIAL INEQUALITiEs
Hence,
T maps the closed, bounded, and convex s e t
Bo = [X E E: ( x ( t )I 5 NM+L,
Ix'
(t) I
5 NIM+L1]
into i t s e l f . mreover, since I ( ~ ) " l < M, T i s completely continuous by Ascoli's theorem. The Schauder's fixed point theorem then yields the fixed point of T w h i c h i s a solution of (l.l.l), (1.1.20), (1.1.21), thus completing the proof of' the theorem. EXEXCISE 1.1.3.
-
Find the solution of the boundary value
problem x" = t, x(0) x' (0) = 1 and x(1) = 0. 1.2 UPPER AND lxlwER SOLUTIONS Let us consider the second-order equation
(1.2.1)
x" = f(t,X,X'),
where f E C[JxRxR,R], J being the i n t e r v a l [a,b] as before. The i n t e r i o r of J w i l l be denoted by J 0 L e t us define certain types of solutions of d i f f e r e n t i a l inequalities t h a t w i l l play a prominent part i n the subsequent work.
.
DEFINIITION 1.2.1. i s said t o be
A f'unction
cy E
C[J,Rl
(i) a lower solution of (1.2.1) on
-
D "'(t) =lim inf
h+ 0
(ii)
TI
a' ( t + h ) -a'( t - h ) 2h
J
h-t 0
-
C(l)[Jo,R]
if
,> f ( t , a ( t ) , a ' ( t ) ) ,
upper solution of (1.2.1) on J
D-a'(t) slim sup
n
if
a t ( t + h ) - a t ( t h) < f(tp(t),a'(t)), 2h
-
A f'undamental r e s u l t concerning the upper and lower 12
t cJo;
0
t EJ
1.2. UPPER AND LOWER SOLUTIONS
solutions i s t h e following.
THEOmM 1.2.1. (i) f
in x
C[JxRxR,R]
E
f o r each (ii)
Assume t h a t and
(t,y) E J x R ;
i s a lower solution and
cy
i s nondecreasing
f(t,x,y)
i s an upper solution
@
of (1.2.1) on J ; (iii)
@ ( a )5 @ ( a ) and cy(b)
5 B(b).
If one of t h e d i f f e r e n t i a l i n e q u a l i t i e s involved i s s t r i c t ,
then we have Proof: some t E J that
m(t)
sequently,
a(t)
0
< B(t) on J 0
.
Suppose, on t h e contrary, t h a t
.
@ ( t )2 B(t)
Then, s e t t i n g m(t) = a ( * ) - B ( t ) ,
m(to)
> 0,
m ' ( t o ) = 0,
we notice
to E J
has a nonnegative maximum q t some
0
D-mt(tO) 5 0.
and
for
.
ConHence
Thus
i n view of t h e monotonic character of
f.
!this i s a contra-
diction since one o f t h e d i f f e r e n t i a l i n e q u a l i t i e s i s assumed t o be s t r i c t .
The proof i s therefore complete.
We observe t h a t the proof of Theorem 1 . 2 . 1 breaks down i f one of t h e d i f f e r e n t i a l i n e q u a l i t i e s i s not assumed s t r i c t . Nonetheless, t h e following assertion i s t r u e , DIEOREM 1.2.2. 1 . 2 . 1 hold.
Assume -theses
Suppose f'urther t h a t 13
( i ) - ( i i i ) o f Theorem f(t,x,y)
obeys a one-sided
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Lipschitz condition i n y
on each compact subset of
J X R xR,
that i s ,
Then the inequality a ( t ) _< p ( t ) on J, Proof:
Suppose t h a t
2& = m a x [ a ( t ) - p ( t ) ]
a(.)
- P ( c ) = E,
a ( % )> p ( t )
on J .
U(d)
- B(d)=
f o r some t
[c,d]
Let
a(t)
E,
i s true.
C
E
J
0
.
Let
be such t h a t
J
- p(t) 2
t
E,
E
[C,dI
-
to E (c,d) such t h a t a ( t o ) p ( t o ) = 2 E . Consider the compact subset given by
and there e x i s t s a
s
=
[(t,x,y): t
For any
6
E
[c,dl,
IPW-xl
5
1, I B ' W - Y I
_< 11.
> 0 s u f f i c i e n t l y small, l e t p ( t ) s a t i s f y the
conditions p" = ( L + l ) p ' ,
-min(6,E)
< p ' ( t ) _< 1,
0
Set m(t) = p ( t ) p'(t)
- p(t).
2 m'(t), t
-< p ( t ) _< 0 ,
E
Note t h a t
(c,d).
t
E
monotonicity of
E
[c,dl,
-> P ( t ) ,
t
E
(c,d).
m(t)
Moreover, f o r
using successively the assumptions on If we now l e t
t
v ( t ) = m ( t ) + E,
t
E
[c,d],
and
(c,d),
f.
we see, because of the
f,
D'v'(t) =D'm'(t) < f ( t , m ( t ) , m ' ( t ) ) _ < f ( t , v ( t ) , v ' ( t ) ) , Also, 14
t
E
(c,d).
1.2. UPPER AND LOWER SOLUTIONS
+
E
-< m(c) +
E =
v(c),
a ( d ) = @ ( d )+
E
< m(d) +
& =
v(d).
a(.)
= B(c)
An a p p l i c a t i o n of Theorem 1 . 2 . 1 y i e l d s t h a t a(t)
< v(t),
t
E
(c,d).
we o b t a i n
From t h e d e f i n i t i o n of m(t),
B(t) _ < m ( t ) and, as a r e s u l t , we o b t a i n a t
B(t) +
E
t=t
0'
This contradiction proves t h e theorem.
We can deduce a uniqueness r e s u l t f o r a c e r t a i n boundary value problem from Theorem 1.2.2. COROLLARY 1.2.1.
L e t t h e assumptions of Theorem 1.2.2
hold except ( i i ) and ( i i i ) . are s o l u t i o n s on x(t2) = y(t,).
[tl,t2]
with respect t o
y
i s no longer v a l i d .
x"=($)
C
Then x ( t )
REMARK 1.2.1.
This we s t a t e as a c o r o l l a r y .
Suppose t h a t
x,y
such t h a t
x(t,)
J
E
y(t)
on
E
C(2)[[t,,t2],R]
= y(tl),
[tl,t21.
If t h e Lipschitz condition on f ( t , x , y ) on compact sets i s omitted, Corollary 1 . 2 . 1 For example, t h e boundary value problem
(: 5
has s o l u t i o n s x ( t )
1 and
x ( t ) = lt15/2 on
[-1,11.
Instead o f the one-sided Lipschitz condition on f, one could assume t h a t s o l u t i o n s of i n i t i a l value problems XI'
= f(t,x,x')
Theorem 1.2.2.
a r e unique, t o conclude t h e v a l i d i t y of This i s p r e c i s e l y what t h e next theorem does.
THEOREM 1.2.3.
Suppose t h a t 15
I . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(i) in
x
f
C[JXRXR,R]
E
f o r each (ii)
(tJy)
E
and
f(tJx,y)
i s a lower solution and
CY
i s nondecreasing
JxR; i s an upper solution
@
of (1.2.1) on (iii) are unique;
[c,d] C J; solutions of i n i t i a l value problems f o r (1.2.1)
(iv) a ( c >< B(c)
a(t)
Then we have
and CY(d-1 5 @ ( a ) .
5 p(t)
on
[CJd].
The proof of t h i s theorem r e s t s on a r e s u l t t h a t we are going t o consider i n t h e following section and therefore w i l l be given t h e r e . COROLLARY 1.2.2.
If
f(t,x,x')
s a t i s f i e s hypotheses ( i )
and ( i i i ) of Theorem 1.2.3, and i f solutions on
[tl,t2]
x ( t 2 ) = y ( t 2 ) J then
C
J
x,y
such t h a t
E
C(2)[[tl,t2]JR]
are
x(tl)=y(tl),
x ( t ) = y ( t ) on
[tl,t21.
Another i n t e r e s t i n g r e s u l t concerning lower and upper solutions which would y i e l d uniqueness of solutions with general l i n e a r boundary conditions i s t h e following. THEOREM 1.2.4.
(i)
f E C[JxRxR,R]
creasing i n (ii)
Assume t h a t
x f o r each CY
and
(t,y)
E
i s s t r i c t l y in-
f(t,x,y) JxR;
i s a lower solution and
@
i s an upper solution
of (1.2.1) on J; (iii)
f o r each
(t,x,yl),
If(tJx,yl)-f(tJxJy2)I (iv)
a,a(a>
(t,x,y2) E J X R X R j
5
LIY1-Y21J
- a2a' ( a ) 5 al@(a) - a2@'(81,
bl,(b)+b2ct'(b) 5 bl@(b)+b2@'(b), where b +b2 1
> 0,
>O;
a1,a2,blJb2
20,
and
16
a +bl 1
a 1+a2 > 0 ,
>o.
1.2. UPPER AND LOWER SOLUTIONS
Then a ( t ) Proof: -
5
p(t)
on J .
We s h a l l f i r s t show t h a t at the end points of
J
the desired inequality holds. and hence
that
> B(a) which implies from ( i v ) t h a t a2 # 0 a' (a) > p ' ( a ) . Then t h e r e e x i s t s a 6 > 0 such > p ( t ) on [a,6). Consequently, using t h e s t r i c t
.(a)
Let
a(t)
monotony of
and condition ( i i i ) , we obtain
f
D
-
0'
- D-p'
(t)
(t)
-
_> L [ a ' ( t ) B ' ( t ) ] ,
which, by t h e theory of d i f f e r e n t i a l inequalities, y i e l d s a' ( t )
- B ' ( t ) 2 [a'( a ) - B ' ( a ) le L(t-a)
This, together with a ' ( t ) U'(t)
p'(t)
on
[a,6].
- p ' ( t ) -< 0,
assures us t h a t
I n view of (1.2.2), we then a r r i v e
a t the contradiction
-
D-a' ( t ) D-B' ( t ) > 0 which establishes t h e claim
to E [a,s).
(to)
-
- Bf(t) > 0
argument may be extended t o show t h a t a(b)
>0
f o r some
Again, we appeal t o t h e d i f f e r e n t i a l inequality
(1.2.2) t o conclude a ' ( t ) that
(to)
> p(b).
on 6= b
[t0,6].
This
which implies
The l a s t conclusion, i n i t s turn, leads
t o the contradiction a l ( b )
-< p ' ( b ) 17
because of t h e second
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
inequality i n ( i v ) . lation
a(a)
>
p(a)
i s impossible.
a ( t ) 5 B(t)
a ( & ) > p(a)
Thus
a(b)
If we assume t h a t
>
i s impossible.
p(b), we a r e lead t o t h e re-
arguing as before, which we have shown
It therefore remains t o be shown t h a t
on
which i s exactly s i m i l a r t o t h e proof
(a,b),
of Theorem 1.2.1.
The proof of t h e theorem i s therefore
complete.
1.3 THE MODIFIED FUNCTION Employing the notion of upper and lower solutions and t h e existence theorem i n t h e small, it i s possible t o e s t a b l i s h t h e existence of solutions i n t h e large of some boundary value problems f o r a modified form of the d i f f e r e n t i a l equation XI' = f(t,X,X'),
(1.3.1) where
f E C[J xRxR,R].
Let us f i r s t define the modified
function. DEFINITION 1.3.1. on
J
and l e t
c
J.
Then define
>0
Let
a,p
C(l)[JJR]
E
be such t h a t
with
Icy'(t) I, I p l ( t )
I
a(t) < p(t)
< c on
2 c,
f(t,x,c)
for
XI
f(t,X,X')
for
IX'I
f(tJx,-c)
for
x'
5 CJ 5 -c,
and
F(t,x,x') =
F{ The function
F*( t ,B (t),XI) + [x-B(t) ] / 1 + x2
for
F*(tJx,x')
for a ( t ) < x < B ( t ) , for x < a ( t ) .
* (t , a ( t ) , x ' ) + [ x - a ( t ) ] / 1 + x 2
F(t,x,x')
J
w i l l be called the modification of
f ( t J x J x ' ) associated with t h e t r i p l e follows from the d e f i n i t i o n t h a t on J x R x R
x >p(t)
and t h a t 18
a ( t ) , p(t), c.
F(t,x,x')
It
i s continuous
1.3. THE MODIFIED FUNCTION
Let us consider now the modified boundary value problem
(1.3.2)
X"
= F(t,X,X'),
.(a)
=
y, x(b)
= 6,
r e l a t i v e t o which we have t h e following.
THEOREM 1.3.1.
a,f3 E C(l)[J,R]
Let
be, respectively,
lower and upper solutions of (1.3.1) on J a(t)
5
B(t)
on J .
such t h a t
Then t h e boundary value problem (1.3.2),
i s the modification of f associated with t h e t r i p l e cr(t)J B(t)J c, has a solution x E C(2)[J,R] s a t i s f y i n g where
F
a ( t >5 x ( t )
(1.3.3) provided t h a t
Proof:
5
.(a)
y
B(t)
on J,
-
p(a), a ( b ) < 6
5
B(b).
By Corollary 1.1.1, t h e boundary value problem
(1.3.2) has a solution show (1.3.3).
5
5
x c c ( 2 ) [ ~ , ~ ~~ h. u swe only need t o
We s h a l l only prove t h a t
x(t)
5
@ ( t ) on J .
The arguments are e s s e n t i a l l y t h e same f o r t h e case a(t)
x(t).
Assume, i f possible, t h a t
-
x(t)
> B(t)
f o r some
t E J . Then x ( t ) p ( t ) has a positive maximum a t a point 0 to E J Hence it follows t h a t x ' ( t , ) = @ ' ( t o ) , I x ' ( t O ) ( c c
.
and
x"(to) = F ( t O , x ( t O ) , x '( t o ) )
19
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and therefore, we arrive at
-
which i s impossible a t a maximum of x ( t ) B(t). We conclude that x ( t ) 5 B(t) on J . The proof i s complete. Let us next consider the general linear boundary conditions
(1.3.4)
a,x(a)
-
(a) = A,
blx(b)
+ b2x1(b)
= B,
where a1 + a2 > 0, b 1 + b2 > O j a1ja2jbljb2 2 0, and a + b l > 0 . We w i s h t o prove a result analogous t o Theorem 1 1.3.1 w i t h respect t o conditions (1.3.4). F i r s t of a l l , we need the following lemma.
LFMMA 1 . 3 . 1 . Assume that ( i ) a,@ E C(l)[J,R] are, respectively, lower and upper solutions of (1.3.1) on J such that a ( t ) 5 B(t) on J; ( i i ) f E C[J XRXR,R] and for t E Jj a ( t ) 5 x 5 B ( t ) , f ( t , x , x ' ) s a t i s f i e s a Lipschitz condition i n X I f o r a constant L > 0. Then, there exists a f'unction f* E C [ J xRxR,R] which is bounded on J X R X R and i s Lipschitzian for the same constant L > 0 whenever t E J and a ( t ) 5 x ,< B(t).
Proof:
A s before, l e t
I a ' ( t ) l , lB'(t)l t E J and a ( t )
c > 0 be such that
< c on J. Then define f*(t,xJx') f o r 5 x 5 p ( t ) by setting
20
1.3. THE MODIFIED FUNCTION
f*(t,x,x*) =
{
x ' 2 c, ( x ' ) 5 c,
f(t,x,c) f(t,x,xl)
for for
f(t,x,-c)
for
We then extend the domain of definition of J X R X R by l e t t i n g f*(t,x,x')
XI
5 -c.
f*(t,x,x')
f*(t,B(t),x')
for x > B(t),
f*(t,a(t),x')
for x < a ( t ) .
to
=
It i s easy t o see that the function f* so defined possesses a l l the stated properties. Hence the proof i s complete. E-EOREM 1.3.2.
Let hypotheses ( i ) and ( i i ) of Lemma 1 . 3 . 1
Then there exists a solution x
hold.
(1.3.5)
E
C(2)[J,R]
of
XI' = f*(t,X,X')
which s a t i s f i e s the boundary conditions (1.3,4), provided that
(1.3.6)
.,.(a)
Proof: F(t,x,x') =
- a2a' (a) 5 A 5 alp(") - a 2 P (a),
Define the ftmction F(t,x,xl)
{
on J x R x R as
f*C(t,B(t),xl) + ~ ( [ x - ~ ( t ) ~ / l +for x ~ )x > ~(t), f*(t,x,x') for 4 t ) _ < X S B ( t ) , f*(t,a(t),x') + ( [ x - a ( t ) ] / 1 + x 2 ) f o r x < a ( t > ,
where f*(t,x,x') i s the f'unction obtained i n &ma 1.3.1. Since f* is bounded, F is also bounded. Hence, by Corollary 1.1.1, there exists a solution x E C ( 2 ) [ J , R ] of (1.3.8)
X"
= F(t,x,x')
satisfying the boundary conditions (1.3.4).
21
We now show that
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
t
for
E
J, a ( t )
-< x ( t ) -< @ ( t ) ,
which implies t h a t
a solution of the problem (1.3.4), (1.3.5). Assume t h a t x(a) > @(a) i n which case zero.
Then there exists a
[a,6).
By definition of
(1.3.9)
x"(t) - D - B ' ( t )
f*,
+
f*(t,B(t),x'(t))
-
cannot be
h(t) - B(t)l 2 l + x (t)
f*(tJ@(t)?B'( t ) )
-> -Llx' ( t ) - B ' ( t ) I since
Y
i s a l s o an upper solution of (1.3.8).
p(t)
is
> a such t h a t x ( t ) > p ( t ) on F, we have f o r a
6
2
a2
x(t)
Also,
r e l a t i o n (1.3.6) implies, because of the assumption x ( a ) _> p(a), t h a t x ' ( a ) 2 @ ' ( a ) . We claim that there i s a to E [a,6) such that
x'(t,)
on a
5
t
5
- @ ' ( t o )> 0 .
6.
If not, suppose t h a t
Then, by (1.3.9), x"(t)
- D-B'
x'(t)
- p'(t)IO
we would obtain
( t ) _> L[X' ( t )
- B' (t)1
which, by the theory of d i f f e r e n t i a l inequalities, yields x'(t)
- B'(t) 2
This, together with on
a
x'(t)
[x'(a)
- B'(a)le L(t-a)
- B ' ( t ) -4,
implies t h a t
x ' ( t ) Epl(t)
On the basis of (l.3.9), we then arrive a t the
contradict ion
-
x ' ( t o ) @ ' ( t o )> 0 f o r some to E [a,&). Again appealing t o the d i f f e r e n t i a l inequality (1.3.9), we conclude t h a t x ' ( t ) - B ' ( t ) > 0 on [t0,8]. I n
which establishes the claim,
fact, t h i s argument leads t o follows t h a t tradiction
x(b) > p(b).
6 = b and, consequently, it This, i n turn, leads t o the con-
< @'(b), i n view of the relations (1.3.4) x'(b) -
and (1.3.7). 22
1.3. THE MODIFIED FUNCTION
I f , on the other hand, we assume t h a t are lead t o the r e l a t i o n
x(b) > B(b), we arguing as before, which
x(a) > B(a)
has j u s t been shown t o be impossible. show that
x(t)
5
t
@(t) for
Assume then there e x i s t
E J
t
x(t)
- p(t),
It therefore remains t o
.
f o r which
E Jo
tl,t2
"his implies the existence of
The difference
0
E
J
> B(t).
x(t)
such t h a t
therefore, assmes a positive
maximum a t some to E (tl,t2). Clearly, x ' ( t o ) = @ ' ( t o ) and x"(to) D-B' ( t o ) _< 0 . A computation, however, leads t o the contradiction
-
noting ( x t ( t o l = l p T ( t o ) l< c and the definition of f". We < B(t) on J . One can similarly have thus established x ( t ) verify that
a(t) < x(t)
on J
completing the proof.
Let us now proceed t o supply the proof of Theorm 1.2.3.
For t h i s purpose we need the following r e s u l t . THEOREM
1.3.3. Assume t h a t
f E C[JxRxR,R]
and t h a t
,
solutions of i n i t i a l value problems f o r (1.3 .l)are unique. Let a,@ E C(l)[J,R] be lower and upper solutions o f (1.3.1) on J, respectively, such t h a t a ( t ) < p ( t ) on J . Then, i f a ( t o ) = @ ( t o ) and CY ( ) = p ( ) f o r some to E J, it follows ' ' that a ( t ) p ( t ) on J .
Proof:
Suppose t h a t
a ( t ) f p(t)
the case where there i s an i n t e r v a l
on J .
(to,tl]
C
We w i l l consider J
such t h a t
a ( t o ) = @ ( t o ) ,Q ' ( t o ) = B ' ( t o ) , and a ( t ) < B(t) on 23
[to,tlI-
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Fl(t,x,x')
Let
be the modification jknction of
according t o Definition 1.3.1 f o r the i n t e r v a l the t r i p l e a,p,cl.
f(t,x,x') [to,t,]
and
a ( t l ) < S1 < @(tl), we have by
Then, i f
Theorem 1.3.1 t h a t the boundary value problem (BVP) =
X"
Fl(t,x,x'),
has a solution x1 a(t)
5 x,(t) _<
E
B(t)
x(to) = a ( t o ) C(2)[[to,t,],R] on
[tO,tll.
x ' ( t o ) = a l ( t o ) and since of
such that Therefore,
I x i ( t ) I < c1
to, it follows by the definition of
interval
[t0,t2]
(1.3.1).
If
C
t2 = t
[tO,tl]
x ( t 1) = 61
xl(tO)
=
u(to),
on some neighborhood
F1, there i s a maximal
on which x ( t ) 1
i s a solution of
1'
a ( t 2 ) = a@,) < S1 = Xl(t2) = x 1(t1) < @ ( t l ) .
to < t 2 < t
it i s s t i l l t r u e t h a t m(t2) < xl(t2) < p(t2) 1' for, if e i t h e r inequality were an equality, we would have
If
Ixi(t)l
< c1 and the i n t e r v a l [t0 , t 2 3 would not be maximal.
We can therefore construct another modification f'unction
[t ,t ] r e l a t i v e t o the t r i p l e 0 2 a , p, c2. A n application of meorem 1.3.1 again w i t h a ( t 2 ) < 62 < p ( t 2 ) , shows t h a t there i s a solution x2 E C(2) [[t0,t2],R] of the BVP F2(t,x,x')
of
f(t,x,x')
satisfying
a ( t ) < x2(t)
-
on
5 p(t)
on
[t
0'
t 2 1.
it follows t h a t there i s a maximal i n t e r v a l on which x 2 ( t )
A s before,
[to,t3] i s a solution of (1.3.1) and t h a t
C
[t0,t21
a ( t 3 ) < x2(t3) < p(t3). lnnis contradicts the assumption that solutions of i n i t i a l value problems f o r (1.3.1) are unique, since xl(tO) = x 2 ( t 0 ) and x l ( t ) = x;(to). conclude t h a t
a(t)
p(t)
1
on
24
0 J.
We therefore
1.4. NAGUMO'S CONDITION
We a r e now ready t o give t h e proof o f Theorem 1.2.3. Proof of meorem 1.2.3: some points o f
[c,d]
Assume t h a t
and l e t
Clearly t h e r e e x i s t s a
a(t)
-
> p ( t ) at
N = m a x [ a ( t ) @ ( t ) l on
-
[c~d].
to E [ c , d ] where a ( t O ) @ ( t o )= N
and a ' ( t o ) = B ' ( t o ) . The functions (Y and B , = p + N s a t i s f y t h e conditions o f Theorem 1.3.3 i n view of t h e nondecreasing nature f(t,x,xl)
of
@ ( t )+ N
a(t)
in
Consequently it follows t h a t
x.
on
[c,d],
a c o n t r a d i c t i o n which proves t h e
theorem.
1.4 NAGW'S CONDITION A s we have seen, t h e proofs f o r t h e existence theorems
for solutions o f boundary value problems depend on f i n d i n g a Here we
p r i o r i bounds f o r t h e s o l u t i o n and i t s d e r i v a t i v e .
present some s u f f i c i e n t conditions f o r obtaining such bounds. DEFINITION 1.4.1. C[J,R]
with
Let
E
t
J, w ( t ) _< x _< @ ( t ) and
(1.4.1) where h
If(tJXYX') E
C[JXRxR;R]
E
a(t) < @ ( t ) on
a,p E
f
x'
E
J.
and
Suppose t h a t f o r
R,
I 5 h ( Ix' 1 )
C [R+j ( o J m ) ] . If
THEOREM 1.4.1. condition on J
Assume t h a t
f
satisfies Nagumo's
with respect t o t h e p a i r 25
a , @ . m e n f o r any
1.
METHODS INVOLVING DIFFERENTIAL INEQUALITIES
solution x E C(')[J,R] of (1.3.1) with a ( t ) _< x ( t ) ,< @ ( t ) on J, there e x i s t s an N > 0 depending only on a,@,h such that Ix'(t) I
(1.4.4)
5N
on J .
Because o f (1.4.2), we can choose an N > h such
Proof: that
(b - a ) x l ( t o ) = x(b)
to E Jo is such t h a t
If
- x(a),
then by
I x l ( t O )I 5 h. Assume t h a t (1.4.4) i s not Then there e x i s t s an i n t e r v a l [tl,t21 C J such t h a t
(1.4.3), we have true.
the following cases hold: = N,
and
A < x'(t)
=
N, x l ( t , ) = A,
and
h
x ' ( t 1)
=
-A,
x'(t,)
= -N,
(i) x l ( t ) = A, x ' ( t , ) 1
< N,
t c (tl,t2),
( i i ) x'(t,)
t
E
(tl,t2), (iii)
t
E
(tl,t2), (iv)
t
E
< x ' ( t ) < N,
x'(t2)
= -N,
and
-N < x ' ( t )
< -A,
x
=
-h,
and
-N < x l ( t )
<
)
-A,
(tl,t2).
L e t us consider case ( i ) .
On
[tl,t21,
and as a r e s u l t
26
we obtain, by (l,b.l),
1.4. NAGUMO'S CONDITION
This leads t o t h e c o n t r a d i c t i o n
We can d e a l with t h e remaining p o s s i b i l i t i e s i n a s i m i l a r way
and therefore we conclude t h a t (1.4.4) i s v a l i d .
Then, f o r any s o l u t i o n exists an N lx'(t)l
5
>0 on
N
x
E
C(2)[J,R1 with
depending only on J.
Also,
N -10
M,h, (b
as
( x ( t ) ( 5 M,
- a)
there
such t h a t
M -0.
The conclusion of Corollary 1 . 4 . 1 i s n n C[JxRnxR , R ] and absolute values a r e re-
REMARK 1.4.1.
false, i f
f
E
placed by norms, as t h e following example shows. (cos n t , s i n n t ) llX"
( t ) 11 = n2 =
hold with
(Ix'
so t h a t ( t ) I/*.
Let
x(t)
=
Ilx(t)(I = 1, Ilxl(t)ll = n, Thus t h e assumptions of Corollary 1 . 4 . 1
M = 1, h ( s ) = s2
+
1. However, t h e r e does not e x i s t
an N > 0 such t h a t / / x t ( t ) )_<) N f o r a l l choices of n. Thus it is c l e a r t h a t Nagumo's condition i s not s u f f i c i e n t t o obtain the desired conclusion i n t h e case of systems. We s h a l l discuss t h i s f u r t h e r when we t r e a t systems of equations l a t e r i n t h i s chapter. 21
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
EXERCISE 1.4.1.
on
Suppose t h a t
J.
a(t)
Let
5
5
where
L
>
f E C[JxRxR,R]
p(t), Y 1 J Y 2
I 0
(
J xJ
C(l)[JJR] with
E
Y,)
and f o r
a(t)
t
E
-< p ( t )
JJ
RJ
-
(t J xJY2)
i s a constant.
Show
condition. THEOREM 1.4.2.
Assume t h a t such t h a t
( i ) a,p E C(l)[J,R] a(b) = p(b)J W
and a ( t )
5
p(t)
On
.(a)
= p(a),
J;
( i i ) (pJJI E C(')[uJR] with q ( t J x ) 5 Jl(t,x) on = [(t,X): a ( t ) <X < (u(t)J t E J ] and O n W,
(1.4.5)
q t ( t J x ) + qx(tJx)q(tJx)
< f(tJxJq(tJx)),
(1.4.6)
$ t ( t J x ) + qx(tJx)q(tJx)
> f(tJXJq(tJX)),
Proof:
a(t)
Let
x(t)
(u,
where
be any solution of (1.3.1) such t h a t
_< x ( t ) 5 p ( t ) on J . Then, by
(i)and ( i i i ) it follows
that ' ~ ( a , x ( a )5 )
X I(a)
Assume now t h a t there exists a
5
Jr(a,x(a)).
to E (a,b)
such t h a t
< ' p ( t o J x ( t o ) ) . Then there must e x i s t an i n t e r v a l [tl,t2]C J with tl < to < t2 such t h a t x ' ( t i ) = ' P ( t i > x ( t i ) ) Ji = 1,2 and x ' ( t ) < ' P ( t , x ( t ) ) , t i < t < t 2 J
x'(to)
28
1.4. NACUMO'S CONDITION
and f u r t h e r t h a t
This i s a c o n t r a d i c t i o n because of assumption ( i i ) .
f o r e conclude t h a t merit shows t h a t
x'(t)
x'(t)
-> ' p ( t , x ( t ) )
-< J r ( t , x ( t ) )
on
on J
We there-
A s i m i l a r argu-
J.
and t h e proof i s
complete. We remark t h a t t h e i n e q u a l i t y s i g n i n (1.4.5) could be reversed i n which case t h e c o n t r a d i c t i o n i s a r r i v e d a t because of
(1.4.6).
A s i m i l a r coment holds r e l a t i v e t o i n e q u a l i t y
Of
course, i n t h i s case, we have t o replace ( i i i ) by V(b,a@))
5 a'@>,
_< Jr(b,B(b))*
COROLLARY 1.4.2. Assume ( i ) of Theorem 1.4.2.
e x i s t constants B'(a),B'(b)
N
5N2,
N such t h a t 1 ' 2 and f(t,x,Ni)
a"(a), a' (b)
#
0, i = 1,2.
clusion of Theorem 1.4.2 i s t r u e w i t h $ { t A=
9.
EXERCISE 1.4.2. Assume t h a t
Ix'I
--fw
f
E
Let there
2 N1, Then t h e con-
cp(t,x) = N1
and
L e t hypothesis ( i ) of Theorem 1.4.2 hold.
C[JXRXR,R]
and
uniformly on compact
lf(t,x,x')I
(t,x)
sets.
-tm
as
Show t h a t t h e
conclusion of Corollary 1.4.2 i s t r u e . EXERCISE 1.4.3. 1 . 4 . 1 h o l d and flmctions
h(s)
Show t h a t i f t h e assumptions o f Corollary i s nondecreasing, t h e r e always e x i s t
'p(t,x), @ ( t , x ) (independent of
t ) satisfying the
hypotheses of Theorem 1.4.2. Consider t h e ' following example on J = [-1,11,' 29
1 , METHODS
= e-2(x+1)
XI'
where
n
INVOLVING DIFFERENTIAL INEQUALITIES
- (x')2nJ
x(-1) = 0 = x ( l ) ,
i s a p o s i t i v e integer.
B ( t ) = 0.
Choose N1 = - 2
Take
and
a ( t ) = t 2 - 1 and
N2 = 2.
Then we see a l l t h e
hypotheses of Corollary 1.4.2 a r e s a t i s f i e d . t h a t any solution x ( t ) Ixr(t)(5 2
on J.
such t h a t
Hence we conclude
t 2 -15 x ( t ) _< 0
However, we notice t h a t f o r n
satisfies
>
* J
Corollary 1 . 4 . 1 is not applicable. A variant of Theorem 1.4.2 which i s more useful i s t h e following r e s u l t .
Proof:
Let
f (t>XJX') such t h a t
o(t)
_< x ( t ) 5 B(t), t
to E (a,bl
be any solution o f
x E C(2)[J,R1
such t h a t
cp(a,x(a)) E
J.
5 x *( a ) 5
q(a,x(a))
x" = and
Suppose t h a t t h e r e e x i s t s a
x'(to)
> q ( t o , x ( t o ) ) . Define
30
15. EXISTENCE IN THE LARGE
Then,
i n some i n t e r v a l t o t h e l e f t of
to. This implies t h a t
V(t)
t increases and p o s i t i v e near to and hence on [a, toI. Thus we have V(a) > 0 o r equivalently x ' ( a ) > $ ( a , x ( a ) ) which i s a contradiction. Hence x ' ( t ) _< $ ( t J x ( t ) ) on J . S i m i l a r l y we can v e r i f y i s nonincreasing as
'p(tJx(t))
5 x'(t>
on J.
1.5 EXISTENCE I N THE LARGE We a r e now ready t o prove theorems on existence i n t h e large.
We begin with one of t h e b a s i c r e s u l t s i n t h i s d i r e c t i o n .
THEOREM 1.5.1.
Let
a,p
E
C(l)[J,R]
be, respectively,
lower and upper s o l u t i o n s of (1.3.1) on J
@(t) _< @ ( t ) on J.
Suppose f u r t h e r that
such t h a t f(t,x,x')
satisfies
Nagumo's condition on J any .(a)
(1.5.1)
5
c
5
r e l a t i v e t o t h e p a i r a,@. Then, f o r @ ( a ) , ~ ( b 5) d 5 B ( ~ ) J t h e BVP
x" = f ( t , x , x ' ) ,
has a s o l u t i o n x
E
x ( a ) = c,
c ( 2 ) [ J ~ R ] with
31
x ( b ) = d,
a ( t >_< x ( t > _< @ ( t )and
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
lx'(t)l
5N
on J,
where
depends only on a,@ and t h e
N
Nagumo's function h. By Theorem 1.4.1, t h e r e i s an N
Proof:
only on a,p,h with
a(t)
5
such t h a t
Ix'(t)l
x ( t ) _< @ ( t ) on J .
( c u ' ( t ) ( < cl,
(P'(t)(
<
5
on J
N
depending
f o r any solution
c > N so t h a t 1 Then, by Theorem 1.3.1, t h e
Choose a
on J.
c1
>0
BVP x" = F ( t , x , x ' ) , has a solution on J,
where
f(t,x,x')
x ( a ) = c,
x E C(2)[J,R]
a ( t ) 5 x ( t ) _< p ( t ) i s t h e modification f'unction of
F(t,x,x')
with respect t o
to
theorem t h e r e i s a
x ( b ) = d,
E Jo
such t h a t
a,p,
and
cl.
By t h e mean value
such t h a t
(b - a ) x ' ( t o ) = x ( b )
- x(a),
and as a r e s u l t using (1.4.3) it follows t h a t
Ix'(t,)l 5 h < N < cl. This implies t h a t t h e r e i s an i n t e r v a l containing toy where x ( t ) i s a solution of x" = f ( t , x , x ' ) . By Theorem
1.4.1, we have
Ix'(t)l
5
N
< c1 on t h i s i n t e r v a l .
However, I x ' ( t ) J < cl-
x ( t > i s a s o l u t i o n of
XI' = f ( t , x , x ' )
We conclude t h a t
i s a solution of (1.5.1) on J.
x(t)
as long as
The
proof i s complete.
COROLLARY 1.5.1.
Under t h e assumptions of Theorem 1.5.1,
any i n f i n i t e sequence of solutions of the relation
a(t)
,< x ( t ) _<
p(t)
XI'
on J,
= f(t,x,x')
obeying
has a uniformly con-
vergent subsequence converging t o a solution of
x'l = f ( t , x , x ' )
on J . A conclusion similar t o Theorem 1 . 5 . 1 may be drawn r e l a t i v e
t o t h e boundary value problem (1.3.1), Theorem 1.3.2,
EXercise 1.4.1,
(1.3.4), on the b a s i s of
and the proof of Theorem 1.5.1.
32
1.5. EXISTENCE IN THE LARGE
We state it in the following exercise. Let hypotheses (i) and (ii) of Lemma Show that for any A,B for which relations (1.3.6)
EXERCISE 1.5.1.
1.3.1 hold.
and (1.3.7) are valid, the BVP (1.3.1), (1.3.4) has a solution such that a(%) _< x(t) _< p(t) on J and x E C(*)[J,R] Ix'(t)l < N on J, where N > 0 depends o n l y on a,@,L. EXERCISE 1.5.2.
Let f E C [ J x R x R , R ] , f(t,x,x') be nondecreasing in x for each (t,x') and satisfy If(t,x,yl)f(t,x,y2)l5~ Iy1-y21 for (t,x> E J X R and yljy2 E R. Show that the BVP (1.3.1), (1.3.4) has a solution. If f is strictly increasing in x, then show that the solution is unique. Hint: -
Set M
max f(t,O,O), m = min f(t,O,O) and J J let p(t) > - 0, a(t) _< 0 be solutions of x" + L l x ' I - m = 0 , XI'- Llx'l - M = 0 , respectively, subject to (1.3.6), (1.3.7) which may be computed explicitly. Then, using monotony of f, show a,@ are lower, upper solutions. For uniqueness, use =
Theorem 1.2.4. 2
1.5.3. Verify that p(t) = t, a(t) = t 1 - 3t +2 are upper, lower solutions for the problem x'' = - 1x1' + t, x(1) = 0, x'(2) = 1, on J = [1,2]. Draw conclusions on the applicability of Exercises 1.5.1, 1.5.2 to this problem. Discuss the merits. EXERCISE
The foregoing discussion concerning the problem (1.3.1),
(1.3.4) imposes more restrictions on the function f compared This is apparently due to the techniques to the B W (1.5.1). involved in the process rather than the need, because the result that we present next involves nonlinear boundary conditions more general than (1.3.4) and yet the assumptions on f are just 33
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
those required f o r t h e BW (1.5.1). We s h a l l f i r s t prove t h e following.
THEOREM 1.5.2. (a) a,@
E
Assume t h a t
C(l)[J,R],
s o l u t i o n s of (1.3.1) on
respectively, a r e lower and upper such t h a t
J
a(t) 5 B(t)
on J
and
a(a) < B(a); (b)
s a t i s f i e s Nagumo's condition on
f(t,x,x')
respect t o t h e p a i r (c) y
g
E
f o r each
(1.5.2)
a(b) J
_<
d
g(x,y)
i s nondecreasing i n
and
g(a(a),a'(a))
2
g(B(a),B'(a))
0,
It i s enough t o show t h a t given
Proof:
with
a,B;
C[[a(a),B(a)] xR,R],
x,
J
_< f3(b),
there i s a solution
x(t,E)
5
0.
E
>
0
and
of (1.3.1)
on
that fulfills x(b,E> = d,
and
a ( t ) 5 x(t,E)
that that such
on
<E
J.
_< d _< B(b), l e t T(c) denote t h e s e t (1.5.1) such t h a t a ( a ) _ < c < B ( a ) a ( t ) _< x ( t ) _< p ( t ) on J. By Theorem 1.5.1, it i s c l e a r ~ ( c ) i s nonempty f o r a l l a(&)5 c _< @(a). Suppose now t h e theorem i s not t r u e . Then t h e r e exists an EO > 0 , t h a t f o r every a ( a ) _< c 5 p ( a ) and x ( t ) E ~ ( c ) , we have For a f i x e d
of s o l u t i o n s and
5 B(t)
Ig(X(a,E), x'(a,E))I
x(t)
a(b)
t o t h e BW
Ig(x(a),x'
(4)I 2 E O . 34
1.5. EXISTENCE IN THE LARGE
Define the set S by
and let co = sup[x(a) = c: x(t) E S]. We notice that x(t) E T(cy(a)) implies a'(a) _< x ' ( a ) which by (1.5.2) yields g(x(a>,xl(a>) E ~ . Similarly, x(t> E .rr(@(a)) implies
>
5 -EO. This observation x'(a) _< @'(a) so that g(x(a),x'(a)) proves that co < p(a). Let yo(t) be a solution of (1.3.1) which is obtained as a uniform limit of members of S so that (1-5.3) yO(a> =c0,
Yo@) = d ,
and g(Yo(a>, Y;)(a))
2
€0.
For n 2 N, Now let N 2 1 be such that co + (1/N) 5 @(a). satisfying, in addition, the inlet yn(t) E T(C~ f (l/n))
>
equality yn(t) yo(t) on J. This is clearly possible since yo(t) may be treated as a lower solution of (1.3.1). Then a subsequence of yn(t) converges to a solution xo(t) obeying xo(t) yo(t) on J. By definition of co,
>
E T ( C ~ )
we have
5 -cO and consequent- g(xo(a>, x;(a)) _< g(yn(a), y;(a)) Since x;(a) 2 y;)(a) and xo(a) = yo(a), this leads to g(y,(a), y;)(a)) 5 - E O which is a contradiction in view of (1.5.3).
-E~.
The proof is complete.
Employing similar arguments as in the proof of Theorem 1.5.2, which were based on a consequence of Theorem 1.5.1, namely Corollary 1.5.1, we may prove the following theorem. THEOREM 1.5.3.
Assume that
respectively, are lower and upper C(l)[J,R], solutions of (1.3.1) on J such that (a) a,@
E
a(t)
5
@(t)
on J and a(b) < @(b);
(b) f(t,x,x') satisfies Nagumo's condition on J relative to the pair a,@; 35
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(c) h
C[[a(b),B(b)]
E
xR,R],
y for each x and h(a(b),
=
f(t,x,x'),
5
a'(b))
Then, for any .(a) 5 c 5 @(a) x C E C(2)[J,R] of the BVP x"
h(x,y)
2
h(B(b),B'(b))
0.
there is a solution
x(a) = c,
which satisfies a(t)
0,
is nondecreasing in
5 xc(t) 5
h(x(b),x'(b))
B(t)
= 0
on J.
Combining the proofs of Theorems 1.5.2 and 1.5.3, we may obtain our main result relative to nonlinear boundary conditions. THEOREM
1.5.4. Assume that
(a) a,@
E
C(l)[J,R],
respectively, are lower and upper
solutions of (1.3.1) on J .(a>
such that Q(t)
5 B(t)
on J and
4 b ) < Bb); (b) f(t,x,x') satisfies Nagumo's condition on J with
< B(a),
respect to the pair a,B; E C[[a(a),B(a)l xR,R], h E C[[o(b),B(b)] xR,R], (c) g(x,y), h(x,y) are nondecreasing in y for each x and
g(a(a),al(a)) h(a(b),a'(b))
2
0,
5
0,
Then there is a solution x XI' = f(t,x,x'),
g(B(a),B'(a)) h(B(b),B'(b)) E
which satisfies a(t)
= 0,
5 x(t) _<
@(t)
Proof: For each a(b) 5 d set of solutions of the BVP
x"
=
f(t,x,x'),
5
2
0-
h(x(b),
x'(b))
= 0,
on J.
@(b),
g(x(a>,x'(a))
0,
of the BVP
C(*)[J,R]
g(x(a),x'(a))
5
let T ( d ) denote the = 0,
x(b) = d,
which satisfy a(t) 5 x(t) 5 B(t) on J. By Theorem 1.5.2, is nonempty for all it is clear that the set T(d) 36
15. EXISTENCE IN THE LARGE
which contradicts the supposition that the theorem is not Now use y(t) in place of a(t) true. Hence y(a) < @(a). in Theorem 1.5.2 to conclude that the set D = [x(t): x(t)
E
T(d),
do
< d 5 B(b),
y(t)
5 x(t)
.< @(t>
on
JI
in nonempty. Moreover, x(t) E n(d) implies that h(x(b), x'(b)) > 0 . However, inf[x(b) = d: x(t) E D] = do, which leads to a contradiction by a convergence argument and the fact that h(x,y) is nondecreasing in y. Hence the proof is complete. On the basis of Theorem 1.4.3, it is possible to relax the condition of the basic Theorem 1.5.1 which is the content of the next result. THEOREM 1.5.5. Suppose that assumptions (i) and (ii) of Theorem 1.4.3 hold. Let a,@ be lower and upper solutions of (1.3.1), respectively, on J, such that a(&) = @(a) and
cp(t,y(t))
5 ~'(t)I +(t,r(t>),
for y(t) 37
=
a(t),B(t),
t
E
J.
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Then, f o r any
5
a(b)
d
_< B(b) and u(a)
BVP (1.5.1) has a solution
x E C(2)[J,R]
(t,x(t),x'(t>) where
E
n,
t
= c = B(a),
the
such t h a t E J,
il i s t h e s e t given by
R = [(t,x,x'):
Proof:
(t,x>
E
(0
and
cp(t,x)
Define a modified function
5 x' 5
Jr(t,x)l.
F(t,x,x')
on
cuxR
by f(t,x,dt,x)) f(t,x,+(t,x)) and extend
F(t,x,x')
to
if x '
< cp(t,x>,
if
(t,x,x')
if
XI
>
E
n,
q(t,x),
J x R x R by s e t t i n g
F(t,a(t),x')
if
x < a(t),
F(t,B(t),x')
if
x > @(t).
F(t,x,x') = Observe t h a t
i s bounded on J x R x R
F(t,x,x')
s a t i s f i e s Nagumo's condition.
a',@'), w,B,
assumptions on
and therefore
Furthermore (because of t h e a r e a l s o lower and upper solutions
relative t o
Consequently, by Theorem 1.5.1 t h e r e exists a solution x E C(2)[J,R]
t o t h e modified BVP
x" = F(t,x,x'), such t h a t and
a(b)
a(t)
5
d
x ( a ) = c,
x(b) = d,
5 x(t) 5
_< B(b).
B(t), t E J f o r .(a) = c = B(a) We now apply Theorem 1.4.3 t o conclude
i s a c t u a l l y a s o l u t i o n of t h e BVP (1.5.1) s a t i s f y i n g ( t , x ( t ) , x ' ( t ) ) E R, t E J. Hence t h e proof i s
that this
x(t)
complete.
38
1.6. LYAPUNOV-LIKE FUNCTIONS
1.6.
LYAPUNOV-LIKE FUNCTIONS We wish t o employ, i n t h i s section, Wapunov-like functions
and the theory of d i f f e r e n t i a l i n e q u a l i t i e s t o e s t a b l i s h existence i n t h e large f o r t h e BVP (1.5.1).
+
We define t h e generalized derivative
x" = f ( t , x , x t )
the d i f f e r e n t i a l equation Dt,( t
J
X, X
V
Let
C[JxRxR,R].
E
D Vf(tJxJx') relative t o
by
')
- V(t,x,x')].
lim sup 1 [V(t + h , x + h x ' , x ' + h f ( t , x , x ' ) ) h+O+ h We s h a l l often use s e v e r a l f'unctions ViJ
i = 1,2,.
..,n,
which
we c a l l I(fapunov-like f'unctions and f o r n o t a t i o n a l consistency we write Vi
of
+
D V. ( t , x , x t )
t o denote t h e generalized derivative
If
with respect t o t h e d i f f e r e n t i a l equation
(1.6.1)
XI1 =
THEOREM 1.6.1.
(i) F(t,x,x') the t r i p l e (ii)
Assume t h a t
a , p c C(l)[J,R]
such t h a t
i s t h e modified f'unction of
a,p,c,
a(t)
-< p ( t )
f(t,x,x')
on
J
and
relative t o
as given i n t h e Definition 1.3.1;
t h e r e e x i s t two Wapunov functions
wi
x [x: x ,< a ( t ) ] xR, D2
= J
i = 1 J 2 J . where
B(t)]xR,
f(t,X,X').
D1
= J
E
C[D~,R],
x [x: x >
W ( t , x , x ' ) = 0 i f x = a ( t ) , Wl(t,x,xl)>O 1 x < a ( t ) , W2(t,x,xt) = 0 i f x = B(t), W2(t,x,x1) > O i f
if
such t h a t
x > B(t); (iii)
for
i = 1,2, g
locally Lipschitzian i n
+
D WP(t,x,xt)
+
D W2F(t,x,xt)
i
E
+
C[JxR , R ] , Wi(t,x,xl)
is
( x , x t ) and
_> gl(t,Wl(t,x,xl)) g2(t,W2(t,x,x1))
39
i n t h e i n t e r i o r of
D1j
i n t h e i n t e r i o r of
D2;
1.
to
E
METHODS INVOLVING DIFFERENTIAL INEQUALITIES
( i v ) the only solution of J , i s r ( t ) p 0 on J .
5
Then, if .(a) (1.6.2)
c
5
has a solution x
d
5
r ( t o ) = 0,
the BVP
B(b),
x ( a ) = c,
C(2)[J,R]
E
5
B(a), a ( b )
x" = F ( t , x , x ' ) ,
r ' = gi(t,r),
x(b) = d,
satisfying
a(t)
-< x ( t ) 5 p ( t )
on J . Proof: x
E
By Corollary 1.1.1, the BVP (1.6.2) has a solution
C(2)[J,R].
on J .
It s u f f i c e s t o show t h a t
We w i l l only prove t h a t
proof f o r
x(t)
5
[tl,t21C (a,b)
E
such t h a t
< a ( t ) for t
E
a(t)
5 x(t)
-
< x(t) < @(t) on J since the
i s e s s e n t i a l l y the same.
< a ( t ) f o r some t
x(t) x(t)
p(t)
a(t)
(a,b).
Then t h e r e e x i s t s an i n t e r v a l
x ( t l ) = a(t,),
(tl,t2).
Assume t h a t
x(t2) = a ( t 2 ) ,
and
We thus have by (ii)
From ( i i i ) and the theory of d i f f e r e n t i a l i n e q u a l i t i e s , we obtain (1.6.4) where
Wl(t,x(t),x'(t)) r(t,t2,ro)
r ( t2 ) = r 0 clear that
5
r(t,t2,ro),
a
5
t
i s the l e f t maximal solution of
5 t2, r ' = gl(t,r),
~y ( i v ) and (1.6.3), it i s 1( t2, x ( t 2 ) , x t ( t 2 ) ) . we r ( t , t 2 , 0 ) 1 0 . However, f o r any t E (tl,t2),
= W
obtain, because of ( i i ) and (1.6.4), the contradiction 0
< W1(t,x(t),x'(t)) 5
0.
The proof i s therefore complete. We notice t h a t t h i s theorem generalizes Theorem 1 . 3 . 1 . In case
a(t), p(t)
respectively, on J,
a r e lower and upper solutions of (1.6.2),
it is enough t o choose W l ( t , x , x r ) = a ( t ) - x 40
1.6. LYAPUNOV-LIKE FUNCTIONS
It i s easy t o check that
and W2(t,x,x') = x - p(t).
Wl
s a t i s f i e s a l l the assumptions of Theorem 1.6.1 w i t h g1 = 0 . The only condition t h a t requires a l i t t l e explanation i s ( i i i ) , + For this, namely D WD(t,x,x') 2 0 i n the interior o f D
1' does not a t t a i n a it is sufficient t o prove that Wl(t,x,x') localmaxhum i n the interior of Arguing as i n the proof D1. of Theorem 1.3.1, we see that it i s necessary t h a t a ( t l ) = x ( t ) 1 a t some tl E (a,b) i n order for W1 t o a t t a i n a local maxjmum.
However, for t = t we obtain DWb(tl,x(tl), x ' ( t l ) ) > 0 as 1' i n the proof o f Theorem 1.3.1 which i s impossible a t a local maximum of W1. A similar reasoning holds for W2 and thus the conditions of Theorem 1.6.1 are verified. The next theorem offers a general s e t of conditions t o ensure that / x ' ( t ) I is bounded.
-
Assume that a,p E C(l)[J,R] and a ( t ) < p(t) on J . Define the s e t s El = J x [x: a ( t ) 5 x 5 p ( t ) ] x [x': X ' ,> 01 and E2 = J X [x: a ( t ) ,< x @ ( t ) ]X [x'; X I 5 01.
THEOREM 1.6.2.
Suppose that there exist Iyapunov f b c t i o n s Vi, i = 1,2,3,4, that are locally Lipschitzian i n (x,xl) such that ( i ) Vi E CIE1,R] and Vi(t,x,x') + m as uniformly on J x [x: a ( t ) < x 5 B(t)], i = 1,2; and ( i i ) D+Vlf(t,x,xl) 5 gl(t,Vl(t,x,x'))
-
XI
+m
-+
D V2f(t,x,x') 2 g2(t,V2(t,x,x')) on El; ( i i i ) Vi c C[E2,R] and Vi(t,x,x') + m as x' +-uniformly on J X [x: a ( t ) x 5 B(t)], i = 3,4; + (iv) on E2, D V3f(t,x,xt) -c g3 (t,V3(t,x,x')) and -i.
D V4f(t,X,X-) ,> gq(t,Vq(t,x,x')); (v) Vi(t,x,x') 5 Jri(lxII), i = 1,2,3,4, for r > 0 are continuous f b c t i o n s . Suppose f i r t h e r that
41
where
Jli(r)>O
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(Vi)
gi
C[JXR,R], i = 1’2’3’4
f
and f o r
to f J, ro
E
R,
a l l solutions of
e x i s t on rt = g i ( t J r ) , r ( t o ) = roJ i = 1 , 3 [ t O , b l J and a l l solutions of rt = g i ( t J r ) ’ r ( t ) = r
i = 2,4
e x i s t on
Then there e x i s t s an N with
a(t)
Define f o r
>0
-< x ( t ) -< @ ( t )
t
0
[aJto].
0’
such t h a t every solution of
on
J
satisfies
Ixt(t)l
-<
N
(1.6.1) on
J.
E J
and L.1 =
max
to E J
lri(tJtoJqi(A))
IJ
i =
2’4,
where ri(tJtOJjri(h)), i = 1’3 (i = 2’4) i s the r i g h t ( l e f t ) maximal solution of rt = g i ( t J r ) ’ r ( t o ) = qi(A). Then cond i t i o n ( v i ) guarantees t h a t t h e L.’s a r e f i n i t e . By ( i ) and ( i i i ) , there e x i s t
(1.6.5)
Ni
>0
1
i = 1,2
3 4 such t h a t
> Lij
i = 1’2’
v.1(tjxj-Ni) > Lij
i = 3’4.
Vi(tjXjNi)
and
kt N >maX[Nijh]y i = 1J2j3y4. We Claim t h a t IX’(t)l 5 N on J where x ( t ) i s any solution of (1.6.1) with a ( t ) 5 x(t)
5
@ ( t ) on J .
There e x i s t s a
to E (a,b)
42
such t h a t
x(b)
- x ( a ) = x ’ (tO)(b-a)
1.6. LYAPUNOV-LIKE FUNCTIONS
and therefore it follows t h a t Ix' ( t o ) I 5 h < N. There are four cases t o be considered depending upon whether there e x i s t s
t2 such t h a t x ' ( t 2 ) = N or x ' ( t 2 ) = -N and whether t2 > to o r t2 < to. Assume, f o r example, x ' ( t 2 ) = N and a
t 2 > to. Then there e x i s t s a tl with that
xl(t,) = A
h < xl(t)
and
t
< N for t
(v) we obtain Vl(tl>x(tl)Jxl(tl)) arrive a t the estimate
5
< t 1 < t2 such
0 -
E
(t,,t,).
From
$1(~) and from ( i i ) we
using the theory of d i f f e r e n t i a l inequalities. Relations (1.6.5) and (1.6.6) lead us t o the contradiction L1 < v1(t2JX(t2)JX' ( t 2 ) )
because of the definitions of
5
L1
L1 and N.
On the basis of the preceding argument, we can arrive a t a similar contradiction i n the remaining three cases. the d e t a i l s .
We omit
The proof i s therefore complete.
The r e s u l t we have j u s t proved offers a general s e t of sufficient conditions which imply that
Ixl ( t ) I
i s bounded
and thus relaxes the more stringent Nagumols condition assumed i n Theorem 1.4.1.
In f a c t , the intent of the following
exercise i s t o c l a r i f y t h i s advantage f u r t h e r . EXERCISE 1.6.1.
Let
hi
E
C[R+,(O,m)], f
E
C[JxRxR,R],
and
Suppose t h a t
t
E
J
and
aJf3E C[J,R]
a(t)
5x5
with w ( t ) < B(t)
@ ( t ) J assume that
43
on J.
For
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
-
-h2(xf) c f ( t , x , x ' ) -h (-XI)
3
5 f ( t , x , x ' ) 5 hq(-xl)
Show t h a t for any solution x a ( t ) 5 x ( t ) 5 B(t) on J, only on cu,p,hi such t h a t Hint: -
hl(xl)
E
C(2)[J,R]
if
x'
if
x'
-> 0, -< 0 .
of (1.6.1) w i t h
there e x i s t s an N > 0 I x l ( t ) l L N on J .
depending
Under the assumptions show one can construct four
Qfapunov functions satisfying the conditions of Theorem 1.6.2. For example s e t V1 = exp[t - x + ./:' s ds/hl(s)] on El show the assumptions are verified w i t h g l ( t , r ) = r and and V4. similarly construct V2, V
and
3'
we may ccanbine Theorems 1.6.1 and 1.6.2 t o obtain the existence of solutions (1.5.1). "he proof i s similar t o Theorem1.5.1. Wemerely statethefollawingtheoremwhichisagener~izationofTheorem1.5.1.
THEOREM 1.6.3.
-
a,@ E C(l)[J,R] w i t h a ( t ) c B(t) Assume t h a t there e x i s t two l$fapunov f'unctions W1, W2 Let
on J . s a t i s Q i n g the hypotheses of Theorem 1.6.1. Suppose further t h a t there exist four Qrapunov functions Vi, i = 1,2,3,4 such t h a t they obey the hypotheses of Theorem 1.6.2. Then f o r any .(a) c c c p(a), u(b) 5 d 5 p(b) t h e BVP (1.5.1) has a solution x E C(*)[J,R] with a ( t ) c x ( t ) C p ( t ) and Ix'(t)l S N on J .
- -
-
-
1.7 EXISTENCE ON INFINITE INTERVALS On the basis of Theorems 1.4.1 and 1.5.1 it i s possible t o obtain the existence of solutions on i n f i n i t e intervals.
THEOREM 1.7.1. Assume t h a t f o r each b > a , f ( t , x , x ' ) s a t i s f i e s Nagumofs condition on [a,b] r e l a t i v e t o the p a i r a,B E C(l)[[a,m),R] with u ( t ) 5 B(t) on [a,-). Suppose 44
1.7. EXISTENCE ON INFINITE INTERVALS
also that a , @ are lower and upper solutions of (1.6.1) on [a,m), respectively. Then f o r any a ( a ) 5 c 5 @(a) the B W (1-7.1)
xtt = f(t,x,x'),
he8 a solution
x
on
E
x(a) = c,
C(2)[[a,m),R]
-
such t h a t a ( t ) c x ( t ) < p(t)
[a,m). Proof: -
By Theorem 1.5.1, it follows that f o r each n 1 1 there i s a solution xn E C(2)[[a,a+n],R] such t h a t xn(a) = c,
xn(a+n) = p ( a + n ) ,
and a ( t ) 5 x n ( t )
5 p ( t ) on [ a , a + n l .
-
Furthermore, there i s an Nn > 0 such t h a t I x t ( t ) l < Nn on [ a , a + n l f o r any solution satisfying a ( t ) 5 x ( t ) 5 p ( t ) on > 1, x,(t) is a solution on [a,a+n]. Thus f o r any fixed n [a,a+nI verifying a ( t ) 5 x,(t) 5 p ( t ) and Ix;(t)l 5 N~ on [ a , a + n ] f o r a l l m > n. Consequently, f o r m i n the sequences {xm(t)], {x;(t)] are both uniformly bounded and equicontinuous on [a, a + n ] Then, employing the standard diagonalization arguments, we obtain a subsequence which converges uniformly on a l l compact subintervals of [ a , ~ ) t o a solution x ( t ) . The desired solution of (1.7.1) is precisely this x ( t ) . Hence the proof is complete.
.
Essentially a similar proof may be given t o the following, s a t i s f i e s Nagumo's condition on [-a,a] f o r each a > 0 w i t h respect t o the pair @,p E C(l)[R,RI w i t h a ( t ) 5 p ( t ) on R. Suppose also t h a t (Y,B are lower and upper solutions of (1.6.1) on R . Then there i s a solution of (1.6.1) on R such t h a t a ( % ) 5 x ( t ) 5 B(t) on R. !MEOREM 1.7.2.
Assume t h a t
f(t,x,xt)
We shall merely s t a t e below a r e s u l t analogous t o Theorem 1.7.1 i n terms of Qfapunov-like functions.
45
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
THEOREM
on
[a,m)
1.7.3. L e t a,@
and l e t
f
f
c C(')[[a,-),R]
C[[a,-)xRxR,R].
with a ( t ) 5 p ( t ) Assume there e x i s t
two Wapunov functions Wl(t,x,xl), W2(t,x,x1) obeying the hypotheses of Theorem 1.6.1 where we now replace
[a, b 1 with
[a,m).
Assume also t h a t there e x i s t two Iiyapunov functions V2, V4 s a t i s w i n g the corresponding properties of !Theorem 1.6.2 w i t h [a,bl replaced by [a,-). Wre precisely suppose that ( i ) V2(t,x,x') subsets of
-
[a,m) x [x: a ( t )
+
(ii) D V2f(t,x,xl)
a ( t ) < x 5 B ( t ) and x' ( i i i ) V4(t,x,xt) 4 subsets of
as
-t-
uniformly on compact
+Q)
5 x 5 @(t)];
3 g2(t,v2(t,x,x1)) for t
2
E
[a,-),
0;
m
[arm) x [x: a ( t )
+
XI
as
x'
5x5
uniformly on compact
--f-c=~
p(t)l;
( i v ) D V4f(t>x,x1)2 g4(t,v4(t9x,xt)) f o r t E [a,m), a(t) 5 x B(t) and x ' 5 0; (v) there e x i s t qi, i = 2,4 where qi e C([a,m) xR,R] and Qi(t,u) i s increasing i n t for each u such t h a t f o r each
2 a, Vi(t,x,x') e qi(T, Ix' I ) 5x5 T
for
t
E
[a,T]
and
(vi) gi E C[[a,-) XR,R], i = 2,4 such t h a t f o r each t 0 e [a,-) and ro 2 0 a l l solutions of r' = gi(t,r), r ( t o ) = ro e x i s t on [a,tol. !Then for any
c
satisf'ying
a(.)
6 c 5 B(a) there e x i s t s
-
a solution of (1.7.1) such that a ( t ) c x ( t )
5 B(t)
on
[a,-).
Clearly a theorem analogous t o Theorem 1.7.2 may be formulated, which we leave as an exercise.
1.8 SUPER- AND SUBFUNCTIONS Here we define subf'unctions and superfunctions r e l a t i v e t o the solutions of XI' = f ( t , x , x ' ) and discuss necessary and 46
1.8. SUPER- AND SUBFUNCTIONS
sufficient conditions I o r such functions t o be, respectively, lower and upper solutions.
To avoid repetition, most of the
results w i l l be stated only i n terms of lower solutions and When it becomes necessary l a t e r t o r e f e r t o a
subfunctions.
result concerning superfunctions and upper solutions, we s h a l l simply r e f e r t o the subfunction statement of the r e s u l t .
DEFINITION 1.8.1.
A function
function r e l a t i v e t o solutions of val J
[tl,t2]
i f f o r any
C
Cp(t)
is said t o be a
x" = f ( t , x , x ' )
2-
on an inter-
and f o r any solution
J
.)> cp(t.), i = 1,2 implies x ( t ) 2 cp(t) C(2) [[tl,t21,R] , x (t 1 1 on [t t 1. A superfunction may be defined similarly by re1 ' 2 versing the respective inequalities.
x
E
We have immediately the following r e s u l t . THEOREN
1.8.1.
Assume t h a t
cp c C[J,R] I I C(l)[J0,R]
is a
subfunction on J w i t h respect t o the solution of
(1.8.1)
XI1
where f E C[J X R xR,R]. (1.8.1) on J . Proof:
Let
Then
to 6 Jo
sufficiently small.
= f(t,X,X') Cp
and h > 0, k > 0, h
-
E
C(2)[[t0-k,t0+h],R].
subfunction, we readily obtain Cp'
-
be
x ( t O+ h ) = q ( t o + h ) ,
x ( t O k) = g ( t 0 k),
has a solution x
+k >0
Then by Theorem 1.1.2 t h e BVP
-
X" = f(t,X,X'),
i s a lower solution of
-
(to+ h ) Cp' ( t o k) h+k
->
X' (to + h )
X'
cp
is a
-
(to k)
h+k =
for some t o- k < s < to + h.
-
Since
x'l(s) = f ( s , x ( s ) , x ' ( s ) )
!the continuity of 47
f
together
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
with "heorem 1.1.2, implies that f ( s , x ( s ) , x t ( s ) ) --3 f ( t O , x ( t O ) , x t ( t O ) )
as h + k
+ 0.
Thus
and, i n particular,
from which it follows t h a t (1.8.1) on J.
i s a lower solution r e l a t i v e t o
cp
Assuming only the continuity of f , it w i l l not be possible i n general t o show t h a t a lower function is a subf'unction. Since a solution i s a lower solution, if lower solutions are subf'unctions, then solutions are subf'unctions From the definition of subfunctions it would then follow t h a t , if a BVP on an i n t e r v a l has a solution, thet solution is unique. Hence stronger assmptions other than continuity of f are required t o conclude that a lower solution i s a subfunction. A s e t of sufficient conditions i s given i n the next theorem.
.
THEOREM 1.8.2.
Assume t h a t
( i ) f E C[JxRxR,R] and i n x f o r each (t,g); ( i i ) either f satisfies a i n y on each compact subset of i n i t i a l value problems f o r (1.8.1) Then a lower solution on J t o solutions of (1.8.1).
f(t,x,y)
i s nondecreasing
one-sided Lipschitz condition J x R x R o r solutions of are unique.
is a subfunction on J r e l a t i v e
The proof i s a direct consequence of Theorems 1.2.2 and 48
1.8. SUPER- AND SUBFUNCTIONS
1.2.3.
I n t h e preceding r e s u l t conditions a r e imposed on f ( t , x , y ) which a r e s u f f i c i e n t t o imply t h a t lower solutions a r e subf'unctions and, therefore, t h a t solutions of BVP's, when they
I n t h e next r e s u l t we take t h e uniqueness
exist, a r e unique.
of BVP's as one of t h e hypotheses. THEOREM 1.8.3. Assume t h a t each i n i t i a l value problem f o r (1.8.1) has a s o l u t i o n which extends throughout [a,b]. Suppose
further t h a t solutions of boundary value problems X"
= f(t,X,X'),
x ( t l ) = xl,
~ ( 6 =~x2, )
[tl,t2] C J,
when they e x i s t , a r e unique.
Then, i f
i s a lower solution on
i s a subfunction on I.
Proof:
Assume t h a t
there i s an i n t e r v a l such t h a t (c,d).
CY E
is a
x,(c)
C(l)[[c,d],R],
>0
cy
[c,d]
and
i s not a subfunction on C
I
and solution
F(t,x,x')
on
C(l)[I,R]
cy E
I.
Then
xo E C(2)[[c,d],R]
and x,(t) [c,d] X R x R
< a(t)
on
by
i s continuous on [c,d] X R X R and it follows from Theorem 1.1.2 t h a t there
F(t,x,x') 6
cy
= cy(c), xo(d) = cy(d),
We now define
Since
I,
IC J
such t h a t
[tl,t2]
C
[c,d]
and
t2-tl 5
6
implies the BVP X"
= F(t,x,x'),
has a solution
x
x(t,)
= Q(tl>,
E C(2)[[tl,t2],R].
x ( t 2 > = a(t2),
Using t h e f a c t t h a t
a ( t ) 5 x ( t ) on with t h e same type of argument as used i n t h e proof
i s a lower solution, we can show t h a t [tl,t2]
Ly
of Theorem
1.3.1.
As a r e s u l t , f o r 49
[t1,t2] C [c,d]
and
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
t2- tl
5 XI1
t h e BVP
6, =
f(t,X,X'),
has a s o l u t i o n x
x(tl) = a(tl), C(2)[[t,,t,],R]
E
x ( t 2 ) = a(t,),
with
a(t) < x(t)
on
[tl,t2]. Thus a i s a subfunction " i n t h e small." Clearly d c > 6; f o r otherwise t h e r e would be a s o l u t i o n
-
x(t)
with
[c,d].
x(c) = a ( c ) , x(d) = a(d),
an% x ( t )
-> a ( t )
This s o l u t i o n would be d i s t i n c t from x ( t ) 0
on
contra-
d i e t i n g t h e assumption concerning t h e uniqueness of s o l u t i o n s of BVP's.
Now f o r each p o s i t i v e i n t e g e r
n,
let
P(n)
t h e proposition t h a t t h e r e e x i s t s an i n t e r v a l [cn,dn] with 0 < dn - c < d - c - (n 1)s and a s o l u t i o n n-
-
x n on
E
C(2)[[cn,dn],R]
such t h a t
d i s t i n c t s o l u t i o n with boundary values
X"
C
[c,d]
x (c ) = a ( c n ) , xn(d ) = a ( t ) n n n i s t r u e with [cl,dl] = [ c , d ]
( c , d ). Evidently P(1) n n and x 1( t ) = x o ( t ) . Assume P(k) i s t r u e . Then otherwise we would o b t a i n a c o n t r a d i c t i o n o f x , ( t )
z,(t)
be
a(ck)
4,- Ck >
6,
being t h e
and a ( % ) .
Let
be t h e s o l u t i o n of t h e BVP =
f(t,X,X'),
x(c,)
=
X ( Ck + 6) = a ( c k + 6 ) .
CU(C,),
Since each i n i t i a l value problem has a s o l u t i o n extending throughout t h a t z,(t)
J,
i s not t r u e .
t h e r e i s a s o l u t i o n z 2 ( t ) on [ck,%I such z,(t) on [ c k , c k + 6 ] . Suppose t h a t P ( k + l ) Then we must have
Also we must have
z2(%)
z2(t)
> "(4,). If
2 a ( t ) on [ c k + 6 , 4 , ] . 4, - ck - 6 5 6, t h e
BVP
E C ( 2 ) [ [ ~ k + 6 , 4 , ] , R ] with a ( t ) < z ( t ) . z3 - 3 Then, s i n c e z ( ) < z2(4,) and s o l u t i o n s of BVPls a r e unique 3 % t E cCk+6,%1. a(t) 5 z 3 w 5 z , ~ ,
has a s o l u t i o n
50
1.8 SUPER- AND SUBFUNCTIONS
This implies z (Ck+6)
3
= z2(Ck+6)
Consequently,
u(t),
and
Z'(C
3
k
+ S ) = Z'(C +6).
2
k
defined by
i s of c l a s s C(2)[[ck,%],R]
and i s a s o l u t i o n on
[ck,%]
However, u ( t ) # \ ( t ) with u ( ck ) = %(ck), u($) = \(\). on rek,%] and t h i s c o n t r a d i c t s t h e uniqueness of s o l u t i o n s of BVP's.
We conclude t h a t
% - ck >
This being t h e case,
6.
the BVP X"
= f(t,X,x'),
has a s o l u t i o n
x(ck+ S ) = a(ck+ S),
z4
E
X(C +26) k
C(2)[[c + 6,ck+26],R]
k
+ 6) 4 k
= z;(ck+ 6).
v(t) =
!Phis s o l u t i o n P(k+1)
on
v(t)
z4(ck + 6 ) = z2(ck + 6) Hence
z,(t)
on
[ck,ck+61,
z4(t)
on
(ck+ 6,ck+281,
has an extension
z (t)
5
a(ck+28),
with
This again assures us t h a t z'(c
=
and
on J .
Since
i s assumed t o be f a l s e , we must have
[ck+2S,%]
and
z,(%)
> a(\).
z5(t) 2 a ( t ) I n t h i s way t h e fore-
going arguments can be repeated and t h e assumption t h a t 51
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
P(k+l)
i s f a l s e permits us t o work our way across the
interval
[ckJ%] by subintervals of length
6 u n t i l we
> a ( t > on a(%) = \(%).
obtain a solution w c c(*) [ [ c k J % l , ~ 1 with w ( t >
[C,J%]J w(ck) = a ( ck = s ( c k ) and w(%) = xJt) on [c,J%] which again i s a contradiction Then w(t)
+
t o uniqueness of solutions of BVP’s. We therefore conclude t h a t , i f i s true.
P(k+l)
leads t o the contradiction 0 Hence a
P(k)
i s true, then
i s true f o r a l l n
Thus P(n)
i s a subfunction on
2
1, which
< d - c - (n - 1)s f o r a l l n > I
1.
and the proof i s complete.
Show t h a t i n Theorem 1.8.3 the hypothesis
EXERCISE 1.8.1.
t h a t each i n i t i a l value problem f o r (1.8.1) has a solution which extends throughout
can be replaced by Na@;umo’s condition.
J
1.9 PROPERTIES OF SUBFUNCTIONS Before proceeding t o outline the Perron’s method, it w i l l be necessary t o make a more detailed examination of the propert i e s of subt h i s section.
and superf’unctions.
This w i l l be undertaken i n
Again most r e s u l t s w i l l be stated i n terms of
subf’unctions and the obvious analogs f o r superf’unctions w i l l be omitted. IMEOREM I C J,
then
1.9.1. cp
If
cp
has r i g h t and l e f t limits i n the extended
r e a l s a t each point i n
Io and has appropriate one-sided
limits a t the end points of
Let
i s a subfunction on an i n t e r v a l
I.
Proof: Clearly it i s sufficient t o consider one case. to E Io and suppose t h a t cp(t-) 0 = limt+t_, cp(t) does
not e x i s t i n the extended r e a l s . numbers a,@ such t h a t
52
Then there e x i s t r e a l
1.9. PROPERTIES OF SUBFUNCTIONS
cp(t) < a < p < l i m sup cp(t)
lim inf t4t; It,},
Let
{s,]
t4;
be s t r i c t l y increasing sequences i n
I
t n < sn < tn+l f o r n 2 1, l i m t n = lim sn = to,
that
iim cp(tn) Taking
iim sup cp(t) t-tt;
=
t ( B -a),
E =
6> 0
is a
x" = f(t,X,X'),
has a solution x $(a+B)I
it follows from Theorem 1.1.2 t h a t there
<
[t,,t2]
C
[tl,tO]
with
the BVP
t2 tl
(1.9.1)
lim cp(sn) = lim inf cp(t). t+t;
and
such t h a t f o r any
- -< 6
such
E
E
on
x ( t 1) = x ( t 2 ) = $ ( a + p ) ,
C ( ~ ) [ [ ~ , , ~ ~ I satisfying ,R]
[tl,t2].
Let
Ix(t)
-
n be a fixed positive integer
-
sufficiently large so t h a t
sn+l sn -< 6, rp(sn) < a, q ~ ( s ~ <+a~,) and cp(tn+l) > p. This implies t h a t there i s a solution of (1.9.1) with [ t , t 1 = [S , S 1 and 1 2 n n +l Since ]. cp i s a subfunction lx(t) -$(a + B) I < E on [ S ~ , S ~ + ~ on 1 and cp(sn) < X(Sn)' cp(sn+l) < X(sn+l), it must be the case t h a t
cp(tn+l)
5 x(tn+l).
X(tn+l> <
3. + B )
However, + E
< B < cp(t,+,>,
a contradiction from which we conclude extended r e a l s .
cp(t',)
e x i s t s i n the
The proof i s complete.
COROLIARY 1.9.1. If cp i s a bounded subfunction on IcJ, Cp has a t most a countable number of discontinuities on A t each to E I0 cP(tO) 5 max[T(ti),Cp(t,)l.
then I.
Proof:
The f i r s t assertion i s a c l a s s i c a l r e s u l t t h a t
follows from the f a c t t h a t
+
cp(to) 53
and
cp(ti)
e x i s t a t each
to
E
0
I
.
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
By Theorem 1.1.2 and t h e f a c t t h a t
i s a sub-
cp
function, t h e second a s s e r t i o n r e a d i l y follows. We consider next t h e d i f f e r e n t i a b i l i t y of subfunctions For a f'unction
with a f i n i t e r i g h t l i m i t
h(t)
h(t:)
.
at
to, we define
-
+
Dh(tO) = lim
+
h ( t ) h(t;) t-t 0
t+tO provided t h e l i m i t e x i s t s .
THEOREM 1 . 9 . 2 . then
to
E
Dcp(t:), 0
I
.
cp
Proof:
i s a bounded subfunction on
I c J,
e x i s t i n t h e extended r e a l s f o r each
I. A s i n Theorem l . g . l w e s h a l l consider only one
Suppose t h a t
lim i n f
+
t-tt
to
t
E
- to
Io and t h a t
< l i m sup t-tt
0
Let
Dh(ti).
The appropriate one-sided derivatives e x i s t a t f i n i t e
end points of
case.
If
Dcp(ti)
Analogously we define
+
-
cp(t> cp(to>
t
- to
0
m be a r e a l number s t r i c t l y between these two limits.
Then t h e i n i t i a l value problem x" = f ( t , x , x ' ) , has a solution
+
x(t,) = cp(tO), x ' ( t o ) = m
x E C ( ~ ) [ [ ~ ~ , ~ ~ f+o r~ some I , R I6
54
>
0.
AS
1.9. PROPERTIES OF SUBFUNCTIONS
there e x i s t
t 1, t2, t3 such t h a t
It follows t h a t
x(t2).
Since
cp
to < t < t2 < t < t 3
1
0
cp(t,) < x(t,), cp(t,) < x ( t 3 ) , and cp(t2) i s a subf’unction t h i s i s a contradiction
+
6,
>
and therefore we are done.
The c l a s s i c a l r e s u l t s i n the theory of r e a l variables give as a consequence the following corollary.
COROLLARY 1 . 9 . 2 . If cp i s a bounded subfunction on I c J, then cp has a f i n i t e derivative almost everywhere on I. LEMMA 1.9.1. If
cp
i s a subf’unction on
I
bounded above on each compact subinterval of
I,
i s a subfunction on
I.
y(t) = l i m
cp(s)
Proof:
Let
[tlyt21
C
J
and i s
then
I a n d l e t x ( t ) b e a s o l u t i o n o f (1.8.1)
with y(t,) 5 x(t,) and y ( t 2 ) 5 x ( t 2 ) . Then cp(ti) 5 y ( t i ) 5 x(ti), i = 1,2, and, because cp(t) i s a subf’unction,
5 x ( t ) on [t,,t,]. We therefore have f o r each tl < t < t2, y ( t ) = l i m sups+t cp(s) 5 x ( t ) . Hence y ( t ) 5
p(t) x(t)
on
[tl,t2]
and y ( t )
i s a s u b f b c t i o n on
I.
We now proceed t o discuss some l a t t i c e properties of subf’unctions.
THEOREM 1.9.3. Assume t h a t the s e t of subfunctions 55
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
on the i n t e r v a l I C J i s bounded above a t each I. Then cp,(t) = supCYEA cpCY ( t ) i s a subf’unction on
{cpCY: CY E A]
point of
I. I and x E C(2)[[tl,t2],R] Suppose t h a t [tl,t2] i s a solution w i t h cp,(t) < x ( t ) a t t = tl,t2. By the definition of q0, we then have cpCY(t)5 x ( t ) a t t = t t 1’ 2 f o r each CY E A . Since each cpCY i s a subfunction on I, it follows t h a t cpCY(t)5 x ( t ) on [tl,t2] f o r each CY E A . This implies cpo(t) < x ( t ) on [tl,t,] and cpo(t) i s a subfunction on I.
Proof:
IIHEOREM 1.9.4.
I&
cp be a subfunction on an i n t e r v a l
I1 w i t h I1= i1n I. Suppose further that cp,(t) 5 cp(t) a t f i n i t e end points of I1 which are contained i n I. Then cp2 defined by IC J
and cpl
a subfunction on
cp,(t> =
{
~“P1(t)>cp(t)l>
I1J
t
cp(t>,
E
I - 11,
i s a subf’unction on I. Proof: By h y p t h e s i s cp,(t) = cp(t) i s a s u b m c t i o n on I I1 and, by Theorem 1.9.3, cp2(t) i s a subfunction on I1. Consequently, we need only t o show t h a t we have the correct behavior on intervals [tl,t,] C I which are not contained i n e i t h e r I1 o r I-I1. Again l e t us consider j u s t one case since the arguments are similar. Assume tl E 11, t2 E I 11,
-
-
56
1.9. PROPERTIES OF SUBFUNCTIONS
i s a subf'unction on
In particular,
-
cp(t) < x ( t )
we obtain
I,
5
cp2(t) = cp(t)
x(t)
on
on
(t3,t2].
[t,,t,].
Also
'~l(t35 ) c ~ ( t 3 )_< x(t3) and cpl(t1) 5 ~ 2 ( t l 5 > x ( t l > , hence cp,(t) 5 x ( t ) on [ t t I because cpl(t) i s a subfunction 1'
3
cp2(t) = max[cp(t), cpl(t)] < x(t)
We thus i n f e r t h a t
on
I1.
on
[tl,t3].
Putting these things together we see t h a t
cp2(t) 5 x ( t ) on [tl,t2]. The other p o s s i b i l i t i e s a r e dealt with i n a similar way and we conclude t h a t cp2(t) i s a subfunction on
I.
MEOREM
(i) x
f
for each
1.9.5. E
Suppose t h a t
C[J xR x R , R ] , f ( t , x , x I )
i s nondecreasing i n
(t,xl)
and ( i i ) t h a t solutions of i n i t i a l value problems are unique.
Then, i f
$(t)
i s an upper solution on
cp(t> i s a bounded subfunction on and cp(t;> 5 $(t,>, we have
Proof:
Suppose t h a t
[tlJt2]
[tlJt2]
cp(t1.5 $ ( t )
cp(t) > $ ( t )
C
J
and
with cp(t1) on
5 $(tl>
(tl't2).
a t some points of
(tlJt2). Observe t h a t it i s enough t o consider the case where cp i s upper semicontinuous on (tl,t2). To see t h i s , l e t
cp(t) = l i m sup cp(s) on (t,,t,). Then by Lermna 1.9.1, s+t -cp(t) i s a subfunction on (t t ). By Corollary 1.9.1, 1' 2 - + + cp(tl>= cp(t,> 5 $(tl> and F(t; cp(t;> 5 J'(t2). mreover, rp(t) > @ ( t ) a t some points i n
(t t ).
at some points i n
rp(t;)
5
(tl,t2).
a t some points i n
$(t,)
implies
cp(t)
[to
- 6, to+ 61
6
>0
(tlJt2),
and 0
57
This being the case,
(tl,t2)
- $(t)
which i s assumed on a compact s e t Then there e x i s t s a
implies T ( t ) > q ( t )
As a r e s u l t we may assume cp(t)
1' 2 i s upper semicontinuous on
cp(t>> + ( t )
(tlJt2)
<
and
cp(tf)
5
$(tl>,
has a positive maximum M E C (tl,t2).
E
>0
&
< $(to+ E ) +
Let
to= lub E.
such t h a t M - 9(t0 + 6 ) ~
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and such t h a t the BVP
has a solution x
C(2) [[to
E
Since
by Theorem 1.1.2.
- 6,
$(t)
+
to+ 6],R]. This i s assured M i s an upper solution, we
+
x(t) < - $(t)
obtain by Theorem 1.2.3,
However ,
V(t0
- 6) 5 $(to - 6)
cp(t
+ 6) < +(to + 6) +
+
on
M
( t o - 6, to+ 6).
-
M = X(tO 6)
and
which yields
0
5 x(to),
cp(to)
subfunction on cp(to) = + ( t o )
+
M-
E =
X(tO + S ) ,
because of the f a c t
t0 We therefore conclude t h a t
(tlJt2). M.
This contradicts
E
cp(t) i s a E
-
q ( t ) < $(t)
(tlJt2).
On
and
EXERCISE 1.9.1. Prove t h a t the assertion of Theorem
1.9.5 remains valid
i f i n place of the assumption "that
solutions of i n i t i a l value problems are unique" we suppose that to
f (t,x,x')
XI
s a t i s f i e s a Lipschitz condition with respect
on each compact subset o f
J X R xR.
We s h a l l now discuss properties of bounded functions t h a t are subfunctions and superfunctions simultaneously.
We w i l l
need a well-known r e s u l t concerning solutions of i n i t i a l value problems which we merely s t a t e . LEMMA 1.9.2.
6
> 0, % >
0,
If
and
%>0
i n i t i a l value problem i s defined on
I
6
=
(tOJXOJxi)E J X R X R ,
such t h a t every solution of the
x" = f ( t , x , x ' ) ,
[to
- 6,
there exist
to+ 61 58
n
J.
x ( t o ) = xo, x f ( t o ) = xd Moreover,
1.9. PROPERTIES OF SUBFUNCTIONS
THEOREM 1.9.6.
Assume t h a t
f(t,x,xt)
i s such t h a t
C(2)
solutions of boundary value problems, when they exist, are unique. I
and t h a t
J
C
Suppose t h a t z(t)
i s bounded on each compact subset
z(t)
i s simultaneously a subfunction and a
superfunction on
I. Then z ( t ) i s a solution of x " = f ( t , x , x t ) on an open subset of I the complement of which has measure zero.
Furthermore, i f
z(t)
a t which
z(t)
to E Io i s a p i n t of continuity of does not have a f i n i t e derivative, then
either
+
Dz(tO) = Dz(t-) = + m 0
+
+
If z ( t o ) > z(t,)J D z ( t 0 )
+
DZ(tO) = Dz(t')
=
0
Proof:
-
+
or =
D z ( t ) = Dz(t-) = 0
Dz(t-) 0
=+m
0
and
z(ti)
-
W.
< z(t,),
W.
By Corollary 1.9.2,
z(t)
has a f i n i t e derivative
to E Io i s a point a t which z ( t ) has a f i n i t e derivative, there i s a 6 > 0 such t h a t almost everywhere on
[ t o -6, t 0 + 6 1 and
I.
I J Iz(t)l
If
5
Iz(to)l
1 On
[ t o - 6, t 0 + 6 1 ,
It then follows from Theorem 1.1.2 t h a t there i s a 0
<
45
6, X"
61
= f(t,x,x'),
has a solution x(t)
a solution of
0,
x
E
C(2)[[to
~ ( t , + 6 ~= ) ~ ( t ~ + 6 ~ ) ,
- 61,t0+61]JR].
Since
z(t)
a t the same time a subf'unction and a superfunction on z(t)
>
such t h a t the BVP
on
[to
- 61Jt0 + S1].
xtt = f ( t , x , x t ) 59
We conclude t h a t
on an open subset of
is
I, z(t) I
the
is
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
complement of which has measure zero.
to f 'I be a point of continuity of z ( t ) at which ~ ( t )does not have a f i n i t e derivative. By Theorem + 1.9.2 Dz(tO) and Dz(ti) both exist i n extended r e a l s . If Next l e t
both are f i n i t e , then by the same argument as used above there
i s an i n t e r v a l around to i n which This contradicts the assumption t h a t
Dz(t0)
Dz(t:)
=
+m
z(t)
i s infinite.
and Dz(ti)
# + m.
Then there e x i s t numbers
> w(t)
>0
f(t,X,X'),
x(tO
has a solution x1 there i s a
b2
solution on
>0
-
E
- 4)=
C(2)[[to
= f(t,X,X'),
41
W(tO
such that the x(to) =
Z(to),
1.9.2, can be extended t o be a
x,(t)
By Lemma
and such t h a t a l l solutions of
x ( t o ) = Xl(tO)'
[ t O , t O+ 6*1
- 61)y
- 61,tO],R].
such t h a t
[to 61 ,t 0 + the i n i t i a l value problem
e x i s t on
-
4, 0 < 61 5 6,
BVP
XI1
6
on to 6 5 t < to.
= z(to) + N ( t -to)
By Theorem 1.1.2, there i s a
=
does not have a
such t h a t
and N
XI1
z(t)
to. Consequently, a t l e a s t one of To be specific, suppose
f i n i t e derivative a t Dz(t:),
i s a solution.
z(t)
and s a t i s f y
x'(to) =
lx(t)
X 1' ( t
0 ),
- x(to) I 5 M ( t - t o )
[ t 0 , t 0 + 6 2 ] y where M = I x ' ( t ) I + 1. Again applying 1 0 Theorem 1.1.2 we i n f e r t h a t there i s an q, 0 < 7 5 min[fj ,6 1, 1 2 such t h a t f o r 0 < 6 < q the BVP
on
3-
X" = f(t,X,X'),
X(tO
- 63 ) = Xl(tO - 63),
x ( t O+ 6 ) = Xl(tO)
3
60
+
(M+ &)6
3
1.9. PROPERTIES OF SUBFUNCTIONS
has a solution E
> 0.
that
As 0
<
x2
- 63 , t0 + 63 ],R]
f o r some fixed
E C ( 2 ) [[to
4
Dz(ti) = + m, we can assume t h a t i s chosen s o 5 q and xl(tO) + ( M + & ) 6 < z ( t 0 + 6 ). Then
4
3
3
xl(tO + 6 ) < x 2 ( t 0 + 6 )
3
3
< z ( t O +6 ) 3
and
- 9'
Xl(tO
=
X2(t0 - 6+
5
- 4,.
z(tO
The l a s t inequality follows from the f a c t t h a t
- 9)
~ ( t )i s a
- 4).
superfunction and xl(tO) = z ( t o ) , xl(tO < z(tO Since ~ ( t )i s a superfunction, we deduce from the above inequalities t h a t
-< z ( t )
x2(t)
on
[to
- 63 ,t0 + 63 ].
From the
same inequalities and the f a c t t h a t the solutions of BVPIs, when they exist, are unique, we also i n f e r t h a t on
[to - 6 ,t + 6 3
3I.
0
x i ( t o ) = x;(to),
Thus
hence,
xl(t) 5 x 2 ( t ) x (t ) = z ( t o ) = x2(t0) and 1 0 x 2 ( t ) i s a solution of t h e i n i t i a l
value problem with the i n i t i a l conditions x l ( t o ) = x ' ( t ). 1 0
However,
Ix2(to +
4,- X2(t0) I
=
x(t,) = xl(tO),
(M+ €183
which contradicts the f a c t t h a t a l l solutions of t h i s i n i t i a l Ix(t) - xl(tO) I 5 M ( t - t o ) on We are forced t o conclude t h a t 'Dz(t;) = + m.
value problem s a t i s f y
[ t O , t O+ 4 1 . By similar arguments using t h e f a c t t h a t
z(t)
i s also a
subfunction, the other statements regarding the behavior of a t a point of continuity can be established.
z(t)
We consider now the behavior of If
z ( t ) i s bounded on each compact inter+ Furthermore, z ( t o ) # z ( t 0 ) since, by Corollary
and are f i n i t e since Val of
a t p i n t s of
to E Io i s a p i n t of discontinuity of and z ( t i ) both e x i s t then by Theorem 1.9.1, z(t:)
discontinuity. z(t),
z(t)
I.
1.9.1, 61
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
+ > .(ti)
Assume t h a t
is a z(t)
6
z(to)
>0
< w(t)
and an N =
= f(t,x,xf),
has a solution Xl(t0) = z(t:) and
z(t)
x
2
Dz(ti)
6
Then t h e r e
[tO,tO + 61 C I and on to < t 5 to + 6. By
-to)
4,
0
<
45
such t h a t t h e BVP
6,
x(tO+fjl) = w ( t O + 61),.
x(to) = z(ti), 1
# + m.
such t h a t
+ z(to) + N ( t
Theorem 1.1.2 t h e r e i s a XI'
and t h a t
C ( 2 ) [ [ t o , t o + 611,R].
x1 (t0 '61)
z(to),
i s a subfunction,
x,(t)
= w(to+61)
1 z(t)
on
>
z(to+61),
[to,to+61].
Now proceeding as i n t h e previous paragraph and using the f a c t that
z(t)
i s a subfunction, we can obtain a solution of t h e
i n i t i a l value problem XIt = f ( t , X , X ' ) ,
x ( t o ) = Xl(tO),
X'(t0) = x;(to),
t h e graph of which i s not contained i n t h e sector t o t h e l e f t of
to in which such solutions must be.
diction, we conclude t h a t
+ Dz(tO) = +=J.
From t h i s contraThe other assertions
concerning derivatives a t points of discontinuity of are d e a l t with i n a similar w a y .
z(t) The proof of t h e theorem i s
now complete. 1.10
PERRON'S METHOD mploying t h e properties of sub-
and superfunctions and
the existence " i n the small" theorem, we consider the existence
i n the large f o r t h e boundary value problems by Perron's method. DEFIXITION 1.10.1.
A bounded real-valued function
62
1 .lo. PERRON'S METHOD
defined on J
i s said t o be an underfunction with respect t o
the BVP (1.10.1)
x" = f ( t , x , x ' ) ,
where
C[J X R xR,R],
f E
i s a subfunction on J
.(a)
= A,
i n case
v(a)
x(b) = B,
5 A,
cp(b)
5
and cp
B,
r e l a t i v e t o (1.8.1). An overfunction
i s defined similarly i n an obvious way. THEOREM 1.10.1.
x"
=
f(t,x,x')
unique.
Assume t h a t solutions of BVP's f o r
on subintervals of
when they e x i s t , are
J,
Suppose t h a t there e x i s t both an underfunction cpo
and an overfunction $ r e l a t i v e t o BVP (1.10.1) such t h a t 0 cpo(t) 1. q0(t) on J . Let Q be the s e t of a l l underfunctions cp
such t h a t
cp(t) < $o(t)
i s simultaneously a sub-
function on J.
a solution x
5
E
z(t,),
W e define
Then
z ( t ) = sup
and superfunction on J.
It follows from Theorem 1.9.3 t h a t
Proof:
subfhnction on J .
x(t2)
on J .
zl(t)
Suppose now t h a t
z(t)
but
x(t)
>
such t h a t
z(t)
[tl,t2]
is a C J
x(tl) < z(tl),
a t some points of
LtlJt21
on J Then by Theorem 1.9.4, zl(a) = z(a)
zl(t)
-< A,
- Ctl,t21.
i s a subfunction on z (b) = z(b) 1
-< B.
and
(tl,t2).
on J by
Zl(t) = { ~ ~ ~ ( t ) J z ( t ) l on
kreover
z(t)
i s hot a super-
Then there i s a subinterval C(2)[[tlyt2],R]
cp(t) v=Q
J
and
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and
jro
[tl,t2].
a superfunction implies t h a t Consequently, we have
we i n f e r t h a t x(t)
> z(t)
which proves
x(t)
5
z,(t)
5
jro(t)
jro(t)
on
on Hence,
J.
E 0 and z,(t) < z ( t ) . However, z1( t ) = 1 a t some points i n (t,,t2), a contradiction
z
i s a superfunction on
z(t)
J.
This proves
t h e theorem. The function
DEFINITION 1.10.2.
obtained i n t h e
z(t)
preceding theorem depends on t h e BVP (1.10.1) function
We s h a l l say t h a t
jr0.
z(t)
and on t h e over-
i s a generalized
solution of the BVP (1.10.1) and we s h a l l designate it by z(t;JIO). Notice t h a t since
z(t;jr ) 0
i s a subfunction and a super-
function a t t h e same time, the assertions made i n Theorem
1.9.6 apply t o z(t;Jro). We therefore have t o consider the behavior of
a t t h e end points of
z(t;jro)
J = [a,b].
We
discuss t h i s i n t h e following theorem. THEOREM 1.10.2.
Assume t h a t the hypotheses of Theorem
1.10.1 are s a t i s f i e d and l e t
z ( t ) = z(t;Jro) be the corresponding generalized solution of (1.10.1). Then .(a) = A. If
Dz(a+)
Hence, i f
z(a+)
#+m,
Dz(a+)
-< .(a).
i s finite,
t
assertions are t r u e a t Proof: cp*(a) = cp(a)
cp*(t)
+
c, c
cp(t)
Assume now t h a t z(t)
6,0
Dz(a+)
< 6 < b - a,
< w(t)
= z(a+)
-m.
Similar
i s a subfunction on J,
cp*(t) = cp(t)
on
i s also a subfunction.
gether with the d e f i n i t i o n of there i s a
=
= b.
defined by
> 0,
< A, Dz(a+)
z(a+) = z ( a ) = A.
Observe t h a t i f
the function
z(a+)
If
z(t),
# +m
and
and an
+ N(t 64
yields
-a),
N
z(a+)
(a,bl
This, t o -
z ( a ) = A.
>
~ ( a ) . Then
such t h a t a
and
< t 5 a + 6.
1.10. PERRON'S METHOD
By Theorem 1.1.2 it follows t h a t f o r
0
<
E
< z(a+) -.(a)
and 0 < 6 < 6 s u f f i c i e n t l y small, t h e BVP 1-
has a solution x
E
C(2)[[a,a+61],R]. z ( t ) _< x ( t )
f'unction, we have z(a+)
5
on
x(a+) = .(a)
This contradiction proves t h a t Finally, suppose t h a t
[&,a+ = z(a+)
Dz (a+)
Z(a>* z(a+)
Since
41
z(t)
i s a sub-
which yields
- E.
# +m
implies
< A and Dz(a+)
# - m.
using an analogous argument as above and the f a c t t h a t
i s also a superfunction on J, implies
-
Dz(a+) =
If Dz(a+)
z (a+) 5
we can conclude t h a t
Then
~ ( t ) z(a+) < A
m.
i s f i n i t e , then combining the assertions of
t h i s theorem we arrive a t
A = .(a)
i s complete.
> A. -> z(a+) -
The proof
From the preceding r e s u l t s it i s clear t h a t Perron's method of studying t h e BVP (1.10.1) canbe separated i n t o twoparts. The f i r s t p a r t dealswiththeproblemofestablishingtheexistenceof an overfunction qo and an underfunction cP,(t) 5 q o ( t )
on J.
rp 0
such t h a t
The second part consists of finding
conditions under which the generalized solution of class
C(2)[J,R]
and i s a solution on J .
z (t;qo)
is
I n view of
Theorems 1.9.6, 1.10.1, and 1.10.2, accomplishing t h i s i s equivalent t o showing t h a t Dz(t-)
i s f i n i t e on
Dz(t+)
i s f i n i t e on
[a,b)
and
(a,b].
Let us f i r s t give s u f f i c i e n t conditions f o r the existence
of under-
and overf'unctions
LEMMA 1.10.1.
nondecreasing i n x
Let
.
f E C[JxRxR,R]
f o r fixed 65
(t,x').
and f ( t , x , x ' ) be Assume t h a t f ( t , x , x ' )
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
i s such t h a t lower and upper solutions of the d i f f e r e n t i a l equation x'' = f ( t , x , x 7 ) are subrespectively.
and superfunctions,
Then,
i s a solution of XI' = f ( t , x , x I ) (a) i f u E C ( 2 ) [ J , R ] on J, there e x i s t overf'unctions and underf'unctions r e l a t i v e t o any BVP on J; (b)
i f there i s a
(1.10.2)
k
>0
such t h a t
5
If(t,O,x') -f(t,O,O)l
t
klx'),
E J,
XI
E
R,
there e x i s t overfunctions and underfunctions r e l a t i v e t o any BVP on
J.
For any s u f f i c i e n t l y large M > 0, q o ( t ) = u ( t ) + M i s an overfunction, rpo ( t ) = u ( t ) M i s an underfunction, and
Proof:
cpo(t)
5
q 0 ( t ) on J.
-
This proves ( a ) .
To prove (b), we l e t
sider the solution w(t)
M = maxlf(t,O,O)l
5
M
>0
q 0 ( t ) = w(t)
v" = - k v ' v(t)
5
0
As a
on J
+
and we a s s e r t t h a t ,
M w i n be an overfunction
v ( t ) be the solution of BVP
+ My
and v ' ( t )
that dt = klv'
-< f(t,w,w')
i s s u f f i c i e n t l y large.
Similarly, l e t
on J .
wf(b) = 0.
and w t ( t )
f(t,O,wt)
f o r a given BVP, provided
Then
w(a) = 0,
-> 0 on J. Hence, by (1.10.2), = - kw' - M = - klw' I - M < f (t,O,w') - f (t,O,O) - M. 410
Then w(t)
Thus w"
and con-
of BY!?
w" = - k w * - M y
W"
on J
v(a) = 0,
-< 0
on J,
v'(b) = 0. from which it follows
I +M> f(t,O,v') -f(t,O,O) + M > f(t,O,v') r e s u l t , vl' > - f ( t , v , v * ) on J and, f o r M > 0
s u f f i c i e n t l y large,
cp,(t) = v ( t ) 66
-M
i s an underfunction
1.10. PERRON'S METHOD
relative t o a given BVP. Obviously, we have q 0 ( t ) on J. !Chis completes the proof of the lemma.
5
qo(t)
We are now ready t o s t a t e our main r e s u l t . THEOREM 1.10.3.
Assume t h a t
i s nondecreasing i n x
f o r each
f
Q
(t,x'),
of i n i t i a l value problems are unique. that there i s a
k
C[JxRxR,R], f ( t , x , x ' )
> 0 Such t h a t
and t h a t solutions
In addition, suppose
I f ( t J 0 J x ' ) -f(tJOjO)l < klx'
t E J and x t e R . Then f o r any BVP on J with an associated overflrnction q0 ( t ) , the generalized solution 0 Z(t) = Z(t;qo) E C(2)[Jo,R] and Z" = f ( t J ? d J Z ' ) On J for
.
Proof:
By Lemma l . l O J I J we readily obtain the existence
rpo
Jr0 with respect - JIo(t) on J . Consequently, t o BVP (1.10.1) such t h a t cpo(t) < the generalized solution z ( t ) = z(t;q0) i s defined. b r e over, the hypotheses imply t h a t solutions of BVP's when they exist, a r e unique and, therefore, the conclusions of Theorem 1.9.6 apply t o z ( t ) . Thus it suffices t o show t h a t Dz(t+), of an underfunction
and an overfunction
0
0
.
Let to E Jo and Dz(t0) a r e f i n i t e f o r every to E J + suppose t h a t z ( t O ) 2 z ( t i ) . The alternative case can be dealt with i n a similar way and w i l l not be t r e a t e d . We break the discussion i n t o two p a r t s .
F i r s t assume
that z ( t i ) 2 0. Let + ( t ) be a solution of Jr" = - kJr' -M, where M = max If(t,O,O)l, with Jr(to) = 0 , + ' ( t ) _> 0 on [tOJb], and
J
Jr(b) _>z(b-), which can be computed.
in Lemma 1.10.1, +,(t)
=
q(t)
+ + z(to)
on [t0'b1 w i t h z(tA) _< ql(tO) and follows from Theorem 1.9.5 t h a t z ( t )
$ ( t ) be a solution of
i s an upper solution
z(b-) Jr,(t)
_< Jrl(b). on
It (tOJb),
q ' ( t ) < m. Applying Theorem 1 0 z ( t ) i s continuous a t to. Now l e t
which implies t h a t Dz(tt)
1.9.6, we a s s e r t t h a t
Then as
Jr"
5
= kJr'
67
-M
on
[a,to]
such t h a t
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
$ ( t o ) = 0 , $(a)
2
z(a+),
$'(t) <0
and
again by Theorem 1.9.5, we have Dz(t0) 2 $ ' ( t o ) > - m. z ( t ) has a f i n i t e derivative a t implies
Finally, suppose t h a t solution of
cpl'
z(a+), cp(to) = 0, Theorem 1.9.5,
kcp'
=
+
and
on
2
<
0
0
on
cp,(t) be a
and l e t such t h a t [a,tol.
cp(a)
Theorem 1.9.6 t h a t we can show t h a t
z(t)
i s continuous a t
+ > - m.
5
Then, by
,> cp,(t) - z ( t 0 ) on (a,to), Dz(t0) 5 cp;(to) < m. It follows
z(t)
assures us t h a t
Then
to.
[a,to]
cp'(t)
[a,tol.
z ( t ) 5 $ ( t ) + z ( t o ) , which We i n f e r t h a t i n t h i s case
.(ti)
M
on
which from
to. Similarly
Thus we again conclude t h a t
Dz ( t o )
to. z ( t ) has a f i n i t e derivative a t each point of
z ( t ) has a f i n i t e derivative a t J
0
,
Since
it follows from !Theorem 1.9.6 t h a t z E C(2)[Jo,R] and 0 z" = f ( t , z , z ' ) on J This completes the
.
i s a solution of proof.
The following exercise i s instructive. EXERCISE 1.10.1.
Under the hypotheses of Theorem 1.10.3,
show t h a t the BVP x" = f ( t , x , x ' ) , x(a) = x(b) = 0 has a unique solution x ( t )
where M,k
on J,
Hints:
- k$, - M)
If
such t h a t
as i n Theorem 1.10.3.
$,(t),$2(t)
are the solutions of BIT'S
9; = k$, -M, q2(b) = 0, = 0, show t h a t Jrg(t) = min[$,(t),$,(t)] i s an overfunction. Similarly obtain an underfunction cpo(t) 5 $ o ( t ) $'I
=
1 $;(a)
on J . cpo(t)
5
Jrl(a) = 0, $;(b)
= 0,
Using Theorems 1.10.2 and 1.10.3, proceed t o show that z(t;q0)
5
q 0 ( t ) on J 68
and
z(t;q0)
i s a solution of
1.1 1 . MODIFIED VECTOR FUNCTION
t h e desired BVP which i s unique.
Compute
qoJq0 and est a b l i s h t h e bound on I x ( t ) l ; show t h a t m e x Jr ( t ) = J O -minJ cpo(t>. If to E JO and x ( t o > > 0 , l e t q1(t;t0)J q 2 ( t' - 0t ) be the respective solutions of BVP's
- kJr' -M,
$1
=
+"
= kJr'
- M,
q(t,) = 0,
$'(b) = 0;
+ ( t o ) = 0, $ ' ( a ) = 0 .
prove t h a t
q$(to;tO) ,< x ' ( t O ) 5 Jri(t,;t,),
x ( t o ) < 0,
obtain analogous relations.
Similarly, i f
Since the functions
involved and t h e i r derivatives can be computed, deduce the desired bound on
Ix' ( t ) I.
1.11 KlDIFIED VECTOR FUNCTION
Some of the r e s u l t s considered so f a r f o r scalar secondorder d i f f e r e n t i a l equations w i l l now be extended, i n the sections t h a t follow, t o f i n i t e systems of second-order difTo avoid repetition, l e t us agree on
f e r e n t i a l equations. the following:
..,n;
1,2,.
the subscripts
range over the integers
i,j
vectorial inequalities w i l l be used freely with
the understanding t h a t the same inequalities hold between t h e i r respective components. L e t us consider a system of second-order d i f f e r e n t i a l
equations written i n the vector form (1.11.1)
where
XI1 =
n
f E C [J xRn X R
,Rn 1.
f(t,X,X'), We s h a l l next define modified
vector functions i n different ways. DEFINITION 1.11.1. Let a(t) that
5
p(t)
on J
IcY'(t)l,
cr,B
E
C(l)[J,Rn] with
and l e t a constant vector
\pl(t)( < c F*(t,X,X')
on J . =
69
Then define
f(tJx,z')
c
>0
be such
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
("s
where
-x!J
=
if
J if -c < x! j - J if x!
-C
J
Fr((t,f;,x')
,x,
,x,x') =
XI
+ (xi
-
>c 3' 5 cj , < -c 3'
2 B i ( t ) ) / l + x i if xi
>
Bi(t),
Fy ( t x ) if a i ( t ) 5 ~ i ( ~ i ( t ) , 2 F y ( ( t , x , x ' ) + (xi - a i ( t ) ) / l + x i if xi < a i ( t ) ,
where
The f'unction f(t,x,x')
will be c a l l e d t h e modification of
F(t,x,x')
relative t o the t r i p l e
the definition t h a t J xRnxRn.
a,@,c.
It i s c l e a r from
i s continuous and bounded on
F(t,x,x')
IF'I ,< c and a ( t ) ,< 5 5 @ ( t )
Also note t h a t
on J . DEFINITION 1.11.2. on
J
A,
where, as before,
and l e t
cp,$
E
Let
a,@
E
C[J,Rn]
with
F ( t , x , x ' ) = f(t,x,f;'),
-(.
Bj(t)
x3
j
aj(t)
< B(t)
such t h a t cp(t,x) 5 q ( t , x ) on A = [(t,x): a ( t ) <x< @ ( t ) , t E J].
C[A,Rn]
men define
where
a(*)
if x.J
>
Bj(t), if a . ( t ) < x . < B . ( t ) ,
if
and
70
J - J - J x. < a . ( t ) , J J
1.11. MODIFIED VECTOR FUNCTION
x! J
-
=
> J;i(t,x),
Jrg(t,X)
if xj'
x'
if cp.(t,x)
{ scpj(t,x)
5 x!J 5 Jlj(t,X), J if x! < cpj(t,x). J
We shall c a l l the f'unction F(t,x,x'), the modified f'unction o f f ( t , x , x ' ) associated w i t h a,@,cp, and $. fgain, it i s easily seen t h a t F(t,x,x') i s continuous and bounded on JxRnxRn.
Furthermore,
a(t) <
x -< @ ( t ) and
cp(t,x)
5
5
$(t,x>* DEFINITION 1 . 1 1 . 3 .
Let
E = [(t,x,x'): t
+ +
E
J,
C[R ,R 1 be such that 6(s) = 0 accordingly as 0 5 s respectively. Then define Let
6
E
N > 0 be given and l e t
p,
(Ix((
C P, X'
E
Rnl.
c
6(s)
< 1, and 5 N, N < s < 2N, and s > 2N 6(s) = 1, 0
We s h a l l sey that F ( t , x , x ' ) i s a modified function of f ( t , x , x ' ) r e l a t i v e t o p,6. Clearly the f'unction F ( t , x , x ' ) n n i s continuous and bounded on J xR xR
.
A r e s u l t analogous t o Theorem 1.3.1 w i l l be proved next.
where
71
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
and I a ' ( t ) l J I p ' ( t ) l < c. Suppose f u r t h e r t h a t n n f E [ J X R ~ X ,R R I and f ( t J x , y ) i s quasimonotone nonincreasing i n
t h a t is, f o r fixed
x,y,
increasing i n y
for j is nonincreasing i n x t h e modification of
j
f
and f o r fixed
i
for
(t,x), f i ( t , x , y )
j
#
f(t,x,x')
t h e BW
(1.11.2)
x" = F ( t , x , x ' ) , x
has a solution
E
5y5
.(a)
x ( a ) = y,
C(*)[J,Rn]
is
F(t,x,x')
associated with
cording t o Definition 1.11.1, and 6 5 p(b),
(t,y), fi(t,x,y)
Then, i f
i.
i s non-
a,p,c
ac-
p(a), a ( b ) 5
x ( b ) = 6,
satisfying
a(t)
-< x ( t )
_< p ( t )
on J . Proof:
By Corollary 1.1.1, t h e BVP (1.11.2) has a solution.
Hence we need only t o show t h a t
w i l l show t h a t x(t)
5
p(t)
a(t)
on
5
x(t)
5
a(t)
on J,
x(t)
5
p(t)
on J .
since t h e proof of
follows s i m i l a r l y .
J
Suppose it i s not t r u e t h a t t h e r e e x i s t s an index k
a(t)
_< x ( t ) on J.
and an i n t e r v a l
Then
[ t l J t 2 ] C (a,b)
such t h a t 5 ( t 2 > = ak(t2)J
%(tl> = ak(tl), and 5(t) Thus
ak(t) -\(t)
%(to) = a i ( t o ) .
< ak(t>J
(tlJt2)'
has a maximum at some Hence
I
/%(to)< ck
have
72
to
E
(tl,t2)
and
and consequently, we
We
1.1 1 . MODIFIED VECTOR FUNCTION
i n view of t h e d e f i n i t i o n of nonincreasing character of possible at a maximum of
F(t,x,x') f(t,x,x')
cik(t)
and t h e quasimonotone
x,x'.
in
- %(t)
and hence t h e proof.
The quasimonotone nonincreasing nature of x,x'
This i s im-
in
f (t,x,x')
assumed i n Theorem 1 . l l . l b e c o m e s superfluous i f t h e
assumptions concerning
a,p
are made stronger.
"his we s t a t e
i n the following exericse. EXERCISE 1.U.1. Suppose t h a t with
a(t)
5
p(t)
on
J
and f o r
fi( t,A(t,i),At ( t , i ) ) , D-p;(t) A(t,i)
,
=
A ( t i) =
5
n 2
a,p E CIJ,Rnl
t
E
J
0
, D-a;(t)
C(l)[Jo,Rn]
fi( t , B ( t , i ) , B ' ( t , i ) ) ,
( X1' .. ., x i - l > q t ) , x i + l , ( xi, .. .,x i - 1,ai ( t ) ,xi+1,
*
where
.,xn),
...,xn ),
...7xi-19Pi(t),xi+l,. . .,xn), B 1( t , i ) = ( x i , .. . p i (t),xi+l, .. n ) ,
B(t,i)
= (xl,
.,XI
provided a . ( t ) < x . < p . ( t ) and - c . < x! 5 c f o r j # i, J - J - J J J j c being any vector s a t i s f y i n g I a ' ( t ) l , l p t ( t ) l < c . Show .(a)
-< y < p(a),
p(b) has a solution x E C(2)[J,Rnl
satisfying
that t h e BVP (1.11.2) such t h a t
73
a(b)
-<
6 _<
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
a(t)
-< x ( t ) 5
B(t)
on J.
REMARK 1.ll.1.
From t h e foregoing discussion, a n a t u r a l
question t h a t a r i s e s i s whether a r e s u l t analogous t o Theorem 1.11.1remains t r u e i f
a,B
ww,
solutions, i n a n a t u r a l
equation x" = f ( t , x , x ' ) .
a r e defined as lower and upper r e l a t i v e t o the vector d i f f e r e n t i a l
This can be done by defining a
modified function which has a jump discontinuity along t h e upper and lower solutions.
EXERCISE 1.U.2.
Let
x E C(2)[J,Rn]
be a solution of
xff = F ( t , x , x ' ) ,
where F i s the modified function of n n f E C[JxRnxR ,R ] r e l a t i v e t o p,6 as i n Definition 1.11.3,
Ilx(a) 1 , Ilx(b) 11 5 p. Suppose t h a t there e x i s t s a V E C[D,R+] such t h a t V(t,x,y) i s l o c a l l y Lipschitzian i n such t h a t
( x , ~ ) ,V(t,x,y) = 0 if llxll = P, V(t,x,y) > 0 if IIxll > P + and D VF(t,x,x') 2 0 in t h e i n t e r i o r of D, D being t h e set on
D = [[a,bl
x [x: llxll > P I xRn].
Show t h a t
Ilx(t)II
-< P
[a,b].
1.12 NAGUMO1s CONDITION
(CONTINUED)
I n remark 1.4.1, we noted t h a t Nagumo's condition i s not suff i c i e n t t o conclude
IIx' ( t ) 11 i s bounded, i f
n
f E C[J xRn xR ,R
n
Nonetheless, we can make conclusions on t h e a r c length of t h e curve
Ilx(t)II,
that i s
/ / / x ' ( s ) l / ds,
LEMMA 1.12.1. Assume t h a t
h E C[R+, (0,m) (1.12.1) where
.few
Ilf
1.
as the next lemma shows.
n n f E C[JxRnXR ,R ]
and
Suppose t h a t
(t,x,x')
11 5 h ( IIx' [I),
s ds/h(s) =
m.
(t,x,x')
E
J xRn xRn,
Then, t h e r e e x i s t s a 74
y: R' - t R +
1.
1.12. NAGUMO'S CONDITION (CONTINUED)
Proof: Since lorn s ds/h(s) y: R + Z satisfying
=
there e x i s t s a f'unction
rn,
From assumption (l.I2.1), we obtain
Hence i f
-
a < v, w < b,
by the change o f variables are equal (and zero) f o r respect t o w
((XI
v=w,
(s)II
--f
s;
the two integrals
and the derivatives with
e x i s t almost everywhere and are equal.
follows t h a t the integrals are equal since
Ilx'(w)II
It
is
absolutely continuous. Choose v and w such t h a t 11x' (v) 1) = el/ (b-a) (which i s possible by the mean value theorem) llxt(w)(I = max Ilx'(s)II on a 5 s 5 b . The desired r e s u l t then follows from (1.l2.2) and ( 1 . 2 . 3 ) and t h e proof i s and
complete.
It i s , however, possible t o extend Theorem 1.4.1 t o deal with the vector s i t u a t i o n . DLEORFM 1.12.1.
Suppose t h a t the following assumptions
hold: 75
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
n n ( i ) f E C[JxRnxR ,R 1, a , p E C[J,Rn] such t h a t a ( t > 5 p ( t ) on J and f o r t c J, u ( t > 5 x 5 p ( t ) , x f E R",
(1.l2.4)
5 hi(lX11),
Ifi(t,X,X')l
+
h, E C[R ,(O,m)]
(ii)
...,n,
i = 1,
and s a t i s f i e s
) - min a, ( t ) , where
Then, f o r any solution a(t) N
2
5
5
x(t)
@ ( t ) on
(1.u .6)
J
Ixf(t)l
N
E
C(2)[J,Rn]
of (1.11.1) with
t h e r e e x i s t s a constant vector u,p,h,
-< N
such t h a t on J .
I n view of ( l e a . ? ) , t h e r e e x i s t s a constant
Proof: vector
x
depending only on
0,
I.
- a ) = max[Ia(a) - @ ( a )
h(b
>
0
such t h a t
If (1.12.6) i s not t r u e , we m q r assume, without loss of
generality, t h a t t h e r e i s an index
t
J, I s ( t ) have E
I > Nk.
to = t O ( k )
\
E
such t h q t f o r some
However, by t h e mean value theorem, we
- s ( a >= where
k
(a,b)
x$t0)(b
- a),
and consequently, it follows t h a t
I%(tO) I 5 < Nk. The remainder of t h e proof i s almost identical t o the proof of Theorem 1 . 4 . 1 and we therefore leave it t o the reader.
76
1.12. NAGUMO'S CONDITION (CONTINUED)
The next r e s u l t i s an extension of Theorem 1.4.3 t o the present situation. TE30REM 1.12.2. (i) (ii) (t,x)
E
C(l)[J,Rn]
with
a(t)
'p,+
E
C(')[A,Rn]
with
cp(t,x)
+ 'px(t,x)
'pt
+t (iii)
-< p ( t )
a,@
where A = [ ( t , x ) : a ( t )
A,
E
Suppose t h a t
+
5x5
5
on J;
+(t,x)
p(t), t
E
and for J],
cp(t,x> 5 f(t,x,'p(t,x)),
*
Jrx(t,x> * + ( t , x )
f E C[JxRnxRn ,Rn 3
2
and
f(t,x,+(t,x)); cp(a,x(a))
< x ' ( a ) _<
-
+(a,x(a)) * Then, f o r any solution x a(t)
5 x(t) 5
(1.12.7)
p(t)
on J,
cp(t,x(t))
Proof:
Let
C(2)[J,Rn]
E
we have
5 x'(t>5
x(t)
of (l.ll.1) such t h a t
Jr(t,x(t)),
t
E J.
be any solution of (l.U.1) satisfying
'p(a,x(a)) _< x ' (a) 5 +(a,x(a)). We s h a l l only prove t h a t p ( t , x ( t ) )
-< x ' ( t )
on J,
since the proof of the other case i n ( l . X . 7 ) i s similar. Assume t h a t t h i s i s not t r u e . and a
on
to
E
(a,b]
such t h a t
Then there e x i s t s an index k X;c(to) < cpk(to,x(to)). Set
(tl,to]. Such an i n t e r v a l
'pk(t,x(t)) -X;c(t)
>
0.
(tl,to] e x i s t s where
It then follows t h a t
77
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
on
(tl,to].
5
zi(t)
t
0
This together with assumption ( i i ) yields on
(tl,to]
increases.
Thus
and hence zk(tl)
tended t o conclude t h a t
>
0.
z,(t)
This argument can be ex-
>0
z,(a)
i s nonincreasing as
which implies t h a t
cp,(a,x(a)) > %(a), a contradiction t o assumption ( i i i ) . This proves cp(t,x(t)) 5 x l ( t ) on J and the proof i s complete. Another r e s u l t t h a t may be u s e h l i n some s i t u a t i o n s i s t h e following. THEOREM 1.12.3.
(i) .(a)
a,p E C(l)[J,Rn]
(ii)
#
with
a(t) < p(t)
h E C[JxRy,R~], h ( t , u )
i
where
t h a t is,
u,
t
f o r each
( 1.12.8)
E J,
and
u ( a ) = A,
A = max[la'(a)), l p l ( a ) l ] ,
for
t
E
J, a ( t )
5x5
I
e x i s t s on
> 0,
x(t)
5
B(t)
on J,
[a,b];
p(t),
5 h(t,
Then f o r any solution x E C(*)[J,Rn]
5
i s nondecreasing i n u
and t h e maximal solution of
If(t,X,X')
N
J
i s quasimonotone non-
hi(t,u)
u 1 = h(t,u),
(iii)
a(t)
on
= B(a);
decreasing i n j
Suppose t h a t
Ix'
I). of ( l . l l . 1 ) with
t h e r e e x i s t s a constant vector
depending only on a,@,h such t h a t I x l ( t ) l IN,
t
E J.
j'
1.12. NAGUMOS CONDlTlON (CONTINUED)
Proof:
a(t)
5
that
Let
5
x(t)
.(a)
x(t)
be any solution of (1.11.1)with
@ ( t ) on
= p(a),
This, i n view of t h e assumption
J.
implies t h a t
fine m(t) = l x ' ( t ) l .
5
al(a)
Then m(a)
-< A
D+m(t) < Ix"(t)I = I f ( t , x ( t ) , x ' ( t ) ) l
xl(a)
5
p'(a).
De-
and, by ( i i i ) ,
5
t
h(t,m(t)),
E
J.
Consequently, by t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s , we have m(t) where
[a,b].
5 N,
r(t,a,h)
t
r(t,a,A),
J,
E
i s t h e maximal solution of (1.12.8) which
r(t,a,A)
exists on
5
t
Let
E J.
N
>0
be a vector such t h a t
Then t h e s t a t e d conclusion follows
immediately. One can a l s o deduce a bound on Wapunov-like method.
IIx'(t))I by employing a This i s t h e content of t h e next two
theorems. THEOREM 1.12.4. (i)
in x,y, bl(u)
V
CID1,R+],
E
as
V(t,x,y)
D1 = J X[x:
where
+ w
Assume t h a t
u
+ w
( ( ~ 1 1-<
i s l o c a l l y Lipschitzian
5 b2( IIYII 1,
+
( i i ) D V(t,x,x') = lim sup h+O
(t,X,Y) +
+
D1;
(t,x,x')
and t h e m a x i m a l solution
of exists on
E
- V(t,x,x')]
-< g ( t , V ( t , x , x ' ) ) f o r
C [ J x R ,R]
u'
+ + 1,
C[R ,R
( l / h ) [V(t + h , x + h x ' ,
x' + h f ( t , x , x ' ) )
E
E
and
b l ( I h l l ) ~V(t,X,Y)
(iii) g
bl,b2
p] XRn,
u ( a ) = A ? 0,
= g(t,u),
[a,b].
79
E Int D ~ ;
r(t,a,h)
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Then, f o r any solution
x E C(2)[J,Rn] of (1.11.1)such t h a t
llx'(a)II
5
pending only on
p, po,g
such t h a t
Proof:
x(t)
Ilx(t)((_< p
Ilx(t)II
5
and
Let and
P
t h e r e e x i s t s an
po,
N
> 0 de-
be any solution of (1.11.1)such t h a t
5
llx'(a)II
Define
p0.
m(t) = V ( t , x ( t ) , x ' ( t ) ) .
Then by ( i ) , we obtain m(a) 5 b2( IIx'(a)lI) 5 b2(po). h = b2(po). Also, because o f t h e assumptions on V,
Choose
it
follows t h a t ~+m(t5 > @;(t,m(t>),
t
E
(a,bl
and consequently, by t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s , we obtain m(t)
-< r ( t , a , h ) ,
t
E J.
By ( i ) , t h i s i n t u r n yields
< r(t,a,h), bl( I I x l ( t > I I ) 5 V ( t J x ( t ) , x ' ( t ) ) = m(t> Since that
r(t,a,h) r(t,a,A)
e x i s t s on
5
M on
[a,b],
[a,b].
there is a
t
M
Furthermore, as
E
J.
> 0 such
bl(u)
--3m
> 0 such t h a t M < b(N). These considerations imply t h a t IIx' ( t ) 11 5 N on J . Clearly
as N
u
--3 m,
t h e r e e x i s t s an
depends only on
pJp0,
THEOREM 1.12.5.
where
and
E = [ [ a ~ b X] [x: llxll
5
V(t,XJX') _> ( t - a ) b ( [ l x ' I I ) ,
r
+m,
+
and
that ing
5
p] XRn],
on
[a,b],
Ilxl(t)ll _< N
on
[a,bl.
such t h a t
V
6
C[E,R+],
V(t,x,y)
< L i n the i n t e r i o r of
x E C(2'[[a,b],Rn]
p
Ilx(t)ll
This completes t h e proof.
(x,y), V ( a , x ( a ) , x ' ( a ) ) = 0, + + where b E C[R ,R ] with b ( r ) + m
D Vf(t,x,x')
Then f o r any solution
g.
Suppose t h a t t h e r e e x i s t s a
i s l o c a l l y Lipschitzian i n as
N
of (1.11.1)such
there e x i s t s an
80
E.
N >0
satisfy-
1 . 1 3 . EXISTENCE IN THE LARGE FOR SYSTEMS
Proof: such t h a t
By assumption on
b(r)
>L
if
r
b(r),
> N. -
t h e r e e x i s t s an
N
>0
A l s o , we have by t h e theory
of d i f f e r e n t i a l i n e q u a l i t i e s
v ( t , x ( t > J x ' ( t > )5 V ( a , x ( a ) , x ' ( a ) ) + L(t I f we now suppose t h a t f o r some
t2
E
- a),
t
(a,bl, Ilx(t2
then we a r e lead t o t h e contradiction
< (t2-a)[b(llx'(t2)11)-L] 5 V ( a , x ( a ) , x ' ( a ) )
0
= 0.
Hence t h e conclusion of the theorem i s t r u e . EXISTENCE IN THE LARGE FOR S
1.13
Y
S
~
We s h a l l f i r s t prove an existence r e s u l t analogous t o Theorem 1 . 5 . 1 f o r t h e BVP (1.13.1) where
f
XI'
E
= f(tJXJX')J
X(a) = A,
x(b) = B,
C[JxRnxRn,Rn], A,B E Rn.
THEOREM 1.13.1. Suppose t h a t t h e following conditions
hold: on J D-ai(t)
( i ) a , p E C[J,Rn] II C(l)[JoJRn] 0 and f o r t E J ,
such t h a t
a(t)
5
@(t)
_> f i ( t ~ a ( t ) ~ a ( t ~ i ) D-B'(t) )~ 5 fi(tJp(t)Jb(t>i))>
where
81
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
(iii)
hi
E
-I.
C[R ,(O,-)]
s a t i s f i e s (1.12.5).
and hi
Then f o r any .(a) 5 A 5 B(a), a(b) 5 B (1.13.1) has a solution x E C(2)[J,Rn] a(t)
5
vector
x(t)
No
p(b),
t h e BVP
such t h a t
5 p ( t ) on J . k r e o v e r t h e r e e x i s t s a constant
>0
Proof: -
5
such t h a t
Ix'(t)
I 5 No
on
J.
Ey hypothesis ( i i ) , we can choose a vector
depending only on c?,p,h,
as i n Theorem 1.12.1. L e t
N
> 0,
No be
such t h a t
Choose
c
> No.
Let
F(t,x,x')
be t h e modification function
as defined i n Definition 1.11.1r e l a t i v e t o the t r i p l e
a,p,c.
Then by Theorem 1.11.1it follows t h a t t h e BVP XI'
= F(t,x,x'),
has a solution
J.
x
x(a) = A,
x(b) = B,
with a ( t )
E C(2)[J,Rn]
-< x ( t ) -< B(t)
on
Hence we have X"
= F(t,x,x') = f ( t , x , x ' )
i n view of t h e d e f i n i t i o n of by ( i i )
,
5x 5
B(t), t
F.
Consequently, we obtain,
Recalling t h a t 1Z;l < ci and proceeding as i n the proof of meorern 1.12.1, it i s e a s i l y
whenever
shown t h a t
a(t)
( x '( t ) I
F(t,x,x') = f ( t , x , x ' )
E
J.
No on Jo.
This then implies t h a t
a d therefore
solution of t h e desired BVP
x(t)
is actually a
(1.13.1) completing t h e proof.
Based on Theorem 1.12.2, it i s possible t o exhibit.
82
1.13. EXISTENCE IN THE LARGE FOR SYSTEMS
another existence theorem which i s an extension of Theorem
1.5.5.
on JoJ where
83
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
SZ being the s e t
n = [(t,x,x): (t,x)
E
n
and cp(t,x)
,< x' ,< Jr(t,x)l.
-
Proof: Let F(t,x,xt) be a modified f'unction of as in Definition 1.11.2 f ( t , x , x l ) associated w i t h cu,@,cp,@ which i s continuous and bounded on J xRn xRn and therefore s a t i s f i e s -theses ( i ) and ( i i i ) of Theorem 1.13.1. Furthermore, in view of the assumptions relative t o a l , p l i n ( i i i ) , it i s easily verified that hypothesis (i) is true w i t h respect t o F ( t , x , x l ) i n place of f ( t , x , x ' ) . This implies that
condition (i) of Theorem 1.13.1 holds w i t h cp,@ instead of -c,c respectively. As a result, it follows, by Theorem 1.13.1 that there exists a solution x E: C(2)[J,Rn] t o the modified
BW x" = F(t,x,x'),
x(a) = A,
x(b) = B,
such that a ( t ) 5 x ( t ) 5 @ ( t ) on J, where @(a)= A = @(a), a ( b ) 5 B 5 @(b). We now apply Theorem 1.12.2 t o assert that x ( t ) is actually a solution of the BVP (1.13.1) satisfying ( t , x ( t ) , x ' ( t ) ) E 12, t E J. For t h i s , it is necessary t o check that a l l the hypotheses of Theorem 1.12.2 are s a t i s f i e d which we leave t o the reader since it i s similar t o the proof of Theorem 1.5.5. This completes the proof. EI(ERC1SE 1.13.1.
Under the assumptions of Exercises show that the BVP XI' = f ( t , x , x t ) , x(a) = A, x(b) '= B has a solution. 1.11.2 and Theorem 1.12.5,
1.14 FUR'MER RESULTS FOR SYSTEM Let us consider the d i f f e r e n t i a l system
(1.14.1) where f
X'l
E
= f(t,X,X'),
n n C [ [ O , ~ ] X R ~ X,R R
3,
84
subject t o the boundary
1.14. FURTHER RESULTS FOR SYSTEMS
conditions (1.14.2)
= 0, ~ ( 0 -AOx'(0) )
(1.14.3)
x(l)+A1x'(l) = 0 ,
AOjA1
being
matrices.
dxd
Here we s h a l l study t h e existence of solutions of t h e BVP (1.14.1)
- (1.14.3)
earlier results.
i n a more general s e t up than t h e
We employ mapunov-like fbnctions and t h e
theory of d i f f e r e n t i a l i n e q u a l i t i e s i n a s l i g h t l y d i f f e r e n t way which throws much l i g h t on t h e underlying ideas.
The
technique i s , of course, the modified function approach.
The
following lemma i s very u s e f u l i n our discussion. LEMMA 1.14.1.
(i)
U E
Assume t h a t
C ( * ) [ [ O J ~ ] J R + ] Jg
i s nonincreasing i n u
g(t,u,v)
c [ [ o J 1 X] R + X R J R - ] J
f o r each
-> g ( t J u J u ' ) ; ~ ' ( 1< ) 0, and
(1.14.4)
(t,v)
and
U''
(ii) some ct
E
u'(0)
2
0,
u(0)
-< m ' ( 0 )
for
-> 0 ;
(iii)
G E C [ [ O J ~ ] X R + ~ R ]and t h e r e exists an
such t h a t f o r u
2 L,
t
s a t i s f i e s t h e estimate
E
L>
[0,1],
r(t,TJO)
< aoJ t
E [oJT]J
where
a0 = min(+, 1/a); (iv)
t h e l e f t maximal solution
right minimal solution
(1.14.7)
p(t,O,O)
of
v ' = g(t,2L,v) 85
r(tJ1,O)
and t h e
o
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
e x i s t s on
[0,13.
Then there e x i s t s a
(1.14.8)
u(t)
5
Bo
>0
such that
and
Bo
5
lu'(t)l
Bo,
Proof: Assume t h a t the maximum of
0
u(t)
-< t -< 1.
occurs a t a
-
tl. From conditions u ' ( 0 ) > 0 and ~ ' ( 1 <) 0, it follows t h a t u'(t,) = 0 . Clearly tl > 0 , f o r otherwise
point
we would have
u(tl)
5 mt(tl)
>
Define
2L.
-
u ( t ) 10.
u ( t ) < 2L, 0
L for t E [O,tll.
W e s h a l l show t h a t
u(tl)
and consequently
= 0
If not, define
to = sup[t Since u(tl)
>
E
[O,t11:
U'(t)
to is well
by the mean value theorem,
2L,
defined.
It i s then e a s i l y seen t h a t
(1.14-9)
u'(to)
Setting
-> +u(t)].
2
L ,< u ( t ) ,
cuou(tO),
z(t) = u'(t)/u(t)
for t
t
[tO,tll
E
E
[tO,tll.
and using
assumption (1.14.5) we readily obtain ' ~ ' ( t 2) G ( t , z ( t ) ) , Notice t h a t
z(to) = 0
and
t
z(to)
E
[to,t,l.
1 cyo > 0 .
By the theory
of d i f f e r e n t i a l inequalities, we then i n f e r t h a t z(t) where with on
5
r(t,tl,z(tl)),
r(t,tl,z(tl)) T =
t
[tO,tl],
1'
t
E
[tO,tlI,
is t h e lef't maximal solution of (1.14.6)
Since z(tl) = 0, we see t h a t r(t,tl,O) < CY 0 and as a r e s u l t , we are lead t o t h e contradiction
This proves t h a t
u(t)
5
2L on
86
[0,11.
1.14. FURTHER RESULTS FOR SYSTEMS
U s i n g t h i s i n e q u a l i t y and t h e nonincreasing nature of g(tJuJv) i n
u,
we obtain
u"
-> g ( t , 2 L , u ' ) .
-> 0, ~'(1)5 0, d i f f e r e n t i a l i n e q u a l i t i e s , we have 0 p(tJ0JO)J
Again, using t h e f a c t t h a t theory of
where
for
and t h e
r ( t J 1 , 0 ) , p ( t J O J 0 ) are, respectively, l e f t maximal and
r i g h t minimal s o l u t i o n s of
on
u'(0)
[O,L]. 0
(1.14.7)which
Thus, we can f i n d a
-< t -< 1, B = max
[I
B
>0
a r e assumed t o e x i s t
such t h a t
Iu'(t)I
where max O< t <-l
r(tJIJo)lJ
I
min
- -
O < t < l
p(t,O,O)l].
The conclusion of t h e lemma now follows by choosing B = max[2LJB]. 0
The proof i s complete. 1
The functions g ( t , u , v ) = - k [ l + (2u)'+ 2 0, G(tjZ) = - ( a + k \ z I + Z ) J V(tjX) *11X112 are
COROLLARY 1.14.1. k
IVl]j
>
admissible i n Lemma 1.14.1, where h = $ a0e -(k+l),
provided
a
La
=
k(1
< aOke- (k+l)
+
(1/2h)
+ hk),
Our aim i s t o prove t h e following r e s u l t . IREOREM 1.14.1.
(a)
Assume t h a t
f E c[[OJ1]xRnxRnJRn]
and
A ~ , A a~r e p o s i t i v e
d e f i n i t e o r i d e n t i c a l l y zero; (b)
v
E
c ( 2 ) [ [ 0 , 1 ] XRnrR+],
g E C [ [ O J ~ ] X R + X R ~ R -g](~t , u , v )
each
( t J v ) ; and f o r
(t,X,X')
E
V(t,x)
i s positive definite,
i s nonincreasing i n [0,1] X R n X R n ,
(1.14.10) Vg(tJx) > g ( t J V ( t J x ) J V ' ( t J x ) )+ v / l f ( t J X J X ' )( 1 )
87
u for
u>oJ
1 . METHODS INVOLVING DIFFERENTIAL INEQUALITIES
where V'(t,x) = Vt(t,x) VF(t,x) = Vtt(t,x)
+ vx(t,x) x ' , + 2Vtx(t,x)
+ vx(t,x)
x ' + Vxx(t,X)X'
x'
f(t,x,x');
( c ) The boundary conditions (1.14.2), (1.14.3) imply, for
some a 2 0,
that
(1.14.12)
2 0, V'(l,x(l)) 5 V(O,X(O>) 5 (Yv'(O,x(O)); V'(O,x(O))
(d) G that f o r
u
E
and there e x i s t s an L
C[[O,l]R',R]
2 L,
t
E
7 E
and
>
0
such
[O,11
(l/u)g(t,u,v) and f o r any
0
-
(V/UI2
2 G(t,v/u)
(0,1], the l e f t maximal solution
r(t,7,0)
of Z'
= G(t,z),
Z(2)
= 0
s a t i s f i e s the inequality r(t,T,O) < ao, t E [O,T], where = min(+,l/a), (e) the l e f t m a x i m a l solution r ( t , l , O ) and the r i g h t minimal solution p(t,O,O) of a.
v ' = g(t,2L,v) exist on
[0,11.
Then there exists a solution x boundary value problem (1.14.1) Proof:
E
C(2)[[0,1],R
- (1.14.3).
Define the function
88
6(u,v)
dl
of the
on R+xR+
as
1.14. FURTHER RESULTS FOR SYSTEMS
osu, (1.14.1'3)
vLB,
( 1 i B - v),
O l u l B l v l B + 1,
(l+B-u)(l+B-v),
Blu,
0 5 v_
~ ( u , v )=
vlB+1,
otherwise. Next define t h e modified function
F
of
f
on
d d [0,1]X R X R
by
(1.14.14)
F(t,x,x'
Clearly t h e function [0,1] xRdxRd.
F
= S(llxll, IIX' Il)f(t,XjX'
1.
i s continuous and bounded on
Hence t h e r e e x i s t s a solution
x
E
C(*)[[O,l],R
d
]
of the boundary value problem
(1.14.15)
X"
= F(t,x,x'),
Set m(t) = V ( t , x ( t ) )
x(O)-Ax'(O) = 0 ,
X(1) + A I X ' ( l ) = O *
so t h a t , because of assumption ( c ) , we have
the r e l a t i o n s
which leads t o t h e f u r t h e r inequality
(1.14.18)
m"(t)
_> .g(t,m(t),m'(t)) + allx"(t)ll.
Hence, by Lemma 1.14.1,
it follows t h a t t h e r e exists a Bo > 0
such t h a t
89
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
As a result, s e t t i n g
-N = [min g(t,u,v): 0 ,< t 5 1, u ,< Bo, Ivl ,< Bol, we obtain from (1.14.18) m"(t) Thus, for 0
5
s
5
t
2 -N+ullx"(t)ll.
5 1,
2 IIx'(t)ll- IIx(l>ll- IIx(O)ll. Since V(t,x) i s assumed t o be positive definite, it follows, from the estimate V ( t , x ( t ) ) = m(t) 5 Bo, 0 5 t 5 1, t h a t (lx(t)II 5 B*, 0 5 t ,< 1. Consequently, we deduce that Ilx(t)ll
5 a*+
(2Bo +N)
O < t l l .
"B,
Eivdently, t h i s implies t h a t (1.14-19)
IIX(t)ll
€3
IIX'(t)ll
and
This, i n view of the definition of
5
B,
0
5 t 5 1,
assures us t h a t x ( t ) is actually a solution of t h e boundary value problem (1.14.)(1.14.3). The proof i s cmplete.
90
F,
1.14. FURTHER RESULTS FOR SYSTEMS
If f satisfies Nagumo's condition, assumption (1.14.10) may be weakened as the next theorem shows.
THEOREM 1.14.2. Let the hypotheses of Theorem 1.14.1 hold except that inequalities (1.14.10) and (1.14.U) are replaced by
2 g(t,V(t,x),V'(t,x))
(1.14.20) V;(t,x)
(1.14.21)
U(t,X,X')
+ u ~ ~ x ' ~ ~u,> 0,
+ 1 ,> IIX'II.
Suppose that Ilf(t,x,x')ll 5 h JJx'/Ifor (t,x,x') E [0,1] xRnxRn, and s ds/h(s) = 00. Then there where h E C[R+,(O,.o)] exists a solution x E C(2)[[0,1],Rn] of the boundary value problem (1.14.1) (1.14.3).
-
Proof:
We proceed exactly as in the proof of Theorem 1.14.1 until we arrive at inequalities (1.14.16). Consider first the case when u 11. Then, in view of (1.14.17), relations (1.14.20) and (1.14.21) yield the inequality (1.14.22)
Vi(t,x)
2 g(t,V(t,x),V'(t,x)) + (1-S,[IIx'II
-> g(t,V(t,x),V'(t,x))
z g(t,V(t,x),V'
+ u6I]x'II
- 13 -1+
IIx'~~[~(u1)+ 1 I
-
I(x'11,
(t,x>) 1
+
using the facts g 5 0, 0 5 S 5 1. Here we have used 6 for 6(u,v). If, on the other hand, 0 < u < 1, noting that (1.14.21) implies uIIx'(I 5 1 + U(t,x,x'), we obtain
(1.14.23)
Vi(t,x)
g(t,V(t,x),V' +
(t,x))
-t
u6IIx'11
(1-E)[ullx'II -13
,> g(t,V(t,x),V'(t,x))
-> g(t,V(t,x),V'(t,x)) 91
- 1 + IIx'II[uS + (1-s)al
- 1 + u(Jx')(.
1. METHODS INVOLVING DIFFERENTIAL INEQUALITIES
Since by L a m a 1.14.1 we have
inequalities (1.14.22), (1.14.23) lead to m"(t)
2- ( N + 1 ) +
m"(t)
2- ( N + 1 ) + ollx'(t)ll,
IIx'(t)ll
and respectively, where, as before,
It then follows that 0 ( l ) From Lemma 1.12.1, we have IIX'(t>jl
5 (2B0 + N +l)/o
L r ( e W ) 5 ?(MI,
Letting B = m[B*,y(M)], the proof as before.
0
M
L
t
5
in any case. 1.
we obtain (1.14.19)which concludes
Finally, for later use, we shall state a uniqueness result leaving the proof as an exercise. THEOREM
1.14.3. Assume that f
V 6 C(2)[[0,1]xRnXRn,Rf], X = Y and
V(t,x,y)
E
C[[O,1] xRnxRn,Rn], 0 if and Only if
1.15, NOTES AND COMMENTS
Then the BVP (1.14.1), one solution.
x(0) = xo and x(1)
=
x has at most 1
1.15 NOTES AND COMMENTS For the existence results in the small contained in Section 1.1, see Hartman [31, Jackson [2], and Bailey, et al.
[31. The results of Sections 1.2 and 1.3 are taken from Jackson [2] except Theorems 1.2.4 and 1.3.2 which are based on the work of Schmitt [5]. Theorem 1.4.1, the Nagumo's condition, is taken from Jackson [2], while Theorems 1.4.2 and 1.4.3 are adapted from Schmitt [2] and Ako [I.], respectively (see also Hartman 133). Theorem 1.5.1 is taken from Jackson [21. Theorems 1.5.2, 1.5.4 are due to Erbe [l] and Theorem 1.5.5 is due to Schmitt [2]. The results of Section 1.6 are due to Bernfeld et al. [l]. Fxercise 1.6.1 contains the work of Schrader [2]. See George and Sutton [l] for the use of Wapunov-like functions. The contents of Sections 1.7-1.10 are taken from Jackson [2] where other related references may be found. The work contained in Sections 1.11-1.13 is due to Bernfeld et al. [41 except Lemma 1.12.1which is due to Lasota and Yorke [13]. The definition of the modified function as given in Definition 1.11.3 may be found in Hartman [31 where a number of results for second-order systems are given. The contents of Section 1.14 are due to Bernfeld et al. [j]. For further results in this direction, see Hartman [?I. For related results, see Knobloch [1,21, Schrader [5,61, Jackson and Schrader 111, Schmitt [31, Moyer [l], Gaines [3,41, Halikov [l], Gudkov and Lepin [l], Gudkov [21, and Mamedov [l].
93
Chapter 2 SHOOTING TYPE METHODS
2.0
INTRODUCTION
This chapter is essentially divided into two parts in which the shooting method serves as the underlying technique. The first part is concerned with the question as to whether uniqueness of solutions of boundary value problems implies the existence of solutions. Although the interdependence between uniqueness and existence is complicated for nonlinear equations, it can be formulated in simple terms for second-order differential equations. We examine this problem under linear and nonlinear boundary conditions and show that the results obtained are the best possible. The second part is devoted to an hportant method known as the "angular function technique." A number of results concerning existence, uniqueness, and criteria for existence of a finite OF infinite number of solutions are studied using this method as a tool. Einploying Lyapunov-like functions and the theory of differential inequalities, this technique is extended to cover nonlinear boundary conditions and systems of differential equations. 2.1
UNIQUENESS IMPLIES EXISTENCE
For linear differential equations, it is well known that the uniqueness of solutions implies the existence of solutions. For nonlinear equations the interdependence between uniqueness and existence is much more complicated. However, in the case of second-order differential equations this relationship can surprisingly be formulated in simple terms.
94
2.1. UNIQUENESS IMPLIES EXISTENCE
An extremely useful technique in handling these questions for second-order boundary value problems is the so-called shooting method. The idea of this method is to fix one initial value and to allow the slope at the initial point to vary through the real numbers. From the connectedness of the solution funnel and the uniqueness of BVP‘s, it is then possible to show that the values of the solutions at the final point cover the real line. In what follows we plan to illustrate this important technique in a detailed manner. Our discussion depends on the following variation of Kneser’s theorem. LEMMA 2.1.1. Consider the initial value problem X’ =
F(t,x),
x(to>
= X0’
where F E CCRXRn,Rn 1. Let S be any compact, connected set. Assume all solutions x(t,tO,xO) exist on [tO,tl]. Then
is a compact, connected set. Our first result will be concerned with a system of two first-order equations subject to simple boundary conditions. Consider the differential system x ’ = f(t,x)
(2.1.1)
with the boundary conditions Xl(tl)
(2.1.2)
where f result.
E
C [R x R ,R
Xl(t2)
=
2 2
= C2’
1. For this problem we have the following
95
2 , SHOOTING TYPE METHODS
0
J
THEOREM 2.1.1. =
(a,b).
Let J
=
(a,b],
-m
5 a < b < m, and
Assume
(i) fl(t,xl,x2) is an increasing function of x2 for fixed (t,x,) satisfying fl(t,xl,x2) + & m as x2 + k m uniformly on compact sets in (a,b)xR; (ii) all solutions of (2.1.1) exist on J; (iii) there exists at most one solution of (2.1.1), 0 (2.1.2) for all tl,t2 E J and all cl, c2. Then every BVP (2.1.1), (2.1.2) has exactly one solution 0 if tl E J , t2 E J. Proof: We may assume without loss of generality t2 = b. Let tl, c1 be given where a < tl < b. Let x(t) = be a solution of (2.1.1) satisfying the initial (x,(t),x,(t>) condition
Then define
S = [x(b): x(t) is a solution of (2.1.1) k satisfying (2.1.3) for each Irl 5 k]. By Lemma 2.1.1,
N
is connected. Let Sk be the projection of Sk on the x axis. Hence S is an interval which is 1 $ 0 nondecreasing in k. Define S = - Sk; then is an interval. To prove the stated result, it is sufficient to show S = (-m,m). If this is not true, suppose that S is bounded above. A similar proof holds if is bounded below. Then c (-m,M) for some M > 0 . Let xn(t) be a sequence of solutions of (2.1.1) satisfying Sk
-
N
z
&
N
N
s
(2.1.4) If s1,s2,
xn(tl)
...,sn
=
(cl,n),
n
=
,... .
1,2
is a sequence of t-values on a compact 96
2.1. UNIQUENESS IMPLIES EXISTENCE
f o r otherwise, from the well-known convergence theorems a subsequence of
[x ( t ) ]
n
converges uniformly t o a solution of
(2.1.1)J on a l l compact subsets of
J
0
,
a contradiction t o
(2.1.4). Let
x ( t ) be the f i r s t component of x n ( t ) . Observe n, 1 t h a t ~ ~ + ~ ,> x~n J( l (t t )) and x (s) < x (s) f o r n+l, 1 n, 1 t E (t,,6] and s E [ t l - 6 , t 1) f o r s u f f i c i e n t l y small 6. However, from ( i i i ) we immediately obtain
for
a < s < t l < t < b .
W e claim t h a t the sequence x
bounded on any subinterval of there e x i s t s a
C
J
0
.
n,l
(t) is not uniformly
If we assume not, then
> 0 and an i n t e r v a l [al,bll
such t h a t
From the mean value theorem
Ix ( t ) l 5 C f o r t E [a,,b,I. n, 1 there e x i s t s rn E [a J b ] such t h a t /xh,l(rn)( 52C/(bl- al). 1 1 Then condition ( i ) implies llxn(rn)ll i s bounded f o r all n. However, t h i s contradicts (2.1.5). of
[ t l - 6m,tl],[tl,tl+6m]
uniformly bounded. vn, wn
Letting
Hence, on any subintervals [x ( t ) l i s not n, 1 we see there e x i s t points
the sequence 6m + 0
where vn < tl,
v +t n 1’
wn>
w +t
n
1
such that, i n view of (2.1.6),
(2.1.7) as
n
x
n,l
(v ) n
+-m
and
xn,l(wn>
++a0
+m.
Let x*(t)
be any solution of (2.1.1) satisfying
91
2. SHOOTING TYPE METHODS
x*(b) = M; hence, since S E (-m,M),xT(b) 1 n. From (2.l.7), f o r l a r g e n
x ( t ) and xT(t) n, 1
This implies
d i c t i r q assumption ( i i i ) .
> xn,l(b)
for a l l
i n t e r s e c t twice, contra-
This completes the proof of Theorem
2.1.1. COROLLARY 2.1.1.
where
Consider the BVP
h E C[JxRxR,R], J = (a,b]. (i)
Assume t h a t
a l l solutions of (2.1.8) e x i s t on
(a,b];
( i i ) t h e r e e x i s t s a t most one solution of (2.1.8), (2.1.9) f o r tl,t2 E (a,b], c1,c2 E R. Then there e x i s t s exactly one solution of (2.1.8) and (2.1.9). Proof:
The BVP (2.1.8),
xi
= x2,
(2.1.9) can be w r i t t e n as = h ( t , x ,X
X'
1 21,
2
x (t ) = C2' 1 2
x ( t ) = c 1 1 1'
We see immediately t h a t t h e conditions i n Theorem 2.1.1 a r e satisfied.
Hence Corollary 2.1.1 follows.
EXERCISE 2.1.1.
suppose t h a t
Consider t h e BVP (2.1.8),
h(t,x,x')
is s t r i c t l y increasing i n x.
Assume that a l l solutions of (2.1.8) exist on there e x i s t s exactly one solution of (2.1.8),
tl,t2
E
(a,b]
Hint:
and a l l
(2.1.9) and
c1,c2
E
(a,b].
Then
(2.1.9) f o r a l l
R.
Show t h a t there exists a t most one solution by 98
2.1. UNIQUENESS IMPLIES EXISTENCE
showing t h a t t h e difference of any two solutions cannot a t t a i n a positive maximum o r negative minimum.
Then use Corollary
2.1.1. EXERCISE 2.1.2.
Assume
h(t,x,x')
satisfies
where
Then (2.1.8),
Hint:
(2.1.9) has a unique solution. Show t h a t t h e inequality
q(t)ixl + p(t)lx'I
lx"I
with boundary conditions x ( t l ) = 0, x(t,) = 0 has only the zero solution, where I t2- t I C b a. Then use Corollary 1 2.1.1.
-
Observe t h a t i n Theorem 2.1.1we obtained t h e existence of a solution on
(a,b].
t h a t we cannot s u b s t i t u t e EXAMPLE 2.1.1.
I n t h e following example we show [a,bI
for
(a,b].
The implicit equation
P > -2,
cp + (P/2) t a n - l cp = 9,
The family of a l l solutions of
has a unique solution cp(p,q). (2.1.10)
x'1 = - x +
1
3
tan-'
cp(sin t , x sin t
+
x ' cos t )
can be represented by x ( t ) = A cos t where A
and
B
+
B sin t
+ 3 tan-1 B,
a r e a r b i t r a r y constants.
Consider the
boundary conditions ( 2 . 1 . ~ ) x ( t l ) =xl
and
x ( t2 ) = x2, 99
tl,t2
E
[o,~].
2 . SHOOTING TYPE METHODS
Then x i
=
A cos ti + B sin ti +
Eliminating A, (2.1.12)
1
2
tan-1 B,
i
=
1,2.
we obtain
-
B sin(t2 t ) + ~ ( C O Stl - cos t2) tan-1 B 1 = x2 cos tl- x cos t2' 1
We now claim that there exists at most one solution of (2.1.10), (2.1.11). If 0 5 t l < t2 < T or 0 < t < t2 5 T , then 1
sin(t2- tl) > 0
cos t2- cos t < 0 . 1
and
Thus from (2.1.12), we see that, for any xl, x2, tl, t2, B and A are uniquely determined. Thus solutions of (2.1.10), (2.1.11) are uniquely determined. For the case t = 0, t2 = 7, (2.1.12) reduces to 1 (2.1.13)
tan-'
B
=
x1 + x2'
Once again uniqueness of solutions foUows. Thus on [ O , T ] the conditions of Corollary 2.1.1 hold. However, observe (2.1.13) implies there exists no solution, if )x1+x21 = T/2EXERCISE 2.1.3.
(2.1.14)
Show that solutions of y"
=
-y + arctan y,
(2.1.15)
when they exist, are unique for t ,t E [ 0 , 7 ] . Then show 1 2 there exists no solution of (2.1.14) satisfying (2.1.16)
Hint:
Y(0)
= 0,
Y(T)
=
3T.
Assume there exist two solutions y,(t),
100
y,(t)
of
2.2, GENERAL LINEAR BOUNDARY CONDITIONS
(2.1.14), y,(t)
tlyt2 E
(2.1.15) f o r
- y2(t)
satisfies
i s a subfunction of subinterval of W(T) > u(T),
w"(t)
y" = -y. ul' = -u
u ' ( ~ / 2 ) . Prove that
u(t)
leads t o a contradiction. of (2.1.15), (2.1.16), vl' = -v
and
Argue .that y(T) y(O) = 0 , ~ ' ( 0 )= m.
m.
and
x'.
> u(O),
has two zeros on
[O,T]
which
To show t h e r e exists no solution
~ ' ( 0 )= m
+ 1,
of
[O,T]
with respect t o (2.1.14) f o r any
< v(T)
= 2T,
where
y
s a t i s f i e s (2.1.14),
I n t e r e s t i n g l y enough we can, under c e r t a i n derive t h e r e s u l t s of Corollary
2.1.1 f o r t h e case when J = [a,b]. h
i s not a proper
w(0)
v(t)
conditions on h ( t , x , x ' ) , example, t h a t
w(t)
w ( ~ / 2 )= u ( T / ~ ) , w ' ( T / ~ )=
v(0) = 0 ,
i s a subfunction on
and prove that
[tlyt2]
If
=
w(t)
prove t h a t t h e solution
+ T,
REMARK 2.1.1.
2 -w(t)
then show that
[O,T], where
Show t h a t
(0,T).
It i s s u f f i c i e n t , f o r
s a t i s f y a Lipschitz condition i n both x
This follows by considering t h e l i n e a r equation
derived from t h e Lipschitz condition, and using t h e f a c t t h a t t h e uniqueness of t h e BVP f o r t h e l i n e a r equation on a l l subi n t e r v a l s of
implies t h e existence of unique solutions
[a,bl
on a l l subintervals of
of BVP's f o r x" = h ( t , x , x ' ) Moreover, an estimate of
[a,b]
[a,b].
can be derived i n terms of
hyperbolic f'unctions. 2.2
GENERAL LINEAR BOUNDARY CONDITIONS "he question as t o whether uniqueness of solutions of
(2.1.8) with t h e general l i n e a r boundary conditions (2.2.1)
alx(tl)
+
ap'(tl)
= cl,
blx(t2)
+ b p ' ( t 2 ) = c2
implies existence i s n a t u r a l l y more d i f f i c u l t since it depends upon t h e c o e f f i c i e n t s
al,
a2, bly b2.
101
2. SHOOTING TYPE METHODS
We shall show, as a consequence of our next result, that Corollary 2.1.1 holds for (2.1.8) and (2.2.1) whenever a2b2 = 0 . THEOREM 2.2.1. Let J, x, f be as in Theorem 2.1.1 except that condition (iii) is replaced by the following:
(iv) there is at most one solution of (2.1.1) satisfying (2.2.2)
x1(t1)
for any tl,t2
E
=
J
0
c1
and
x2(t2)
and c1,c2
E
=
c2'
tl
#
t2'
R.
Then (a) every boundary value problem (2.1.1), (2.1.2) has a unique solution; (b) every boundary value problem (2.1.1), (2.2.2) has a unique solution. Proof: In order to show (a), we must show condition (iii) of Theorem 2.1.1 holds. Let x(t), y(t) be distinct solutions 0 of (2.1.1) satisfying xl(tl) = y (t ) for some tl E J It 1 1 0 suffices to show that xl(t) # yl(t) for tl f t E J We show this for tl < t < b as a similar argument holds for Without loss of generality, we may assume from t E (a,t,). (iv) that y,(t) > x2(t) for t E (tl,b). Then either
.
.
Y2(t1> = X2(tl) or Y2(t1> > X2(tl)' If Y (t 1 = X2(tl)' 01 then, by (iv), yl(t) f x,(t) for tl # t E J If then yi(t,) > xi(tl) by (i), so that there y2(tl) > x2(tl), exists a 6 > 0 such that yl(t) > x,(t) for t E (tl,tl+6). Assume that there exists a least T,tl< 7 < b such that xl(T) = yl(T). However, then ~'(7) 2 y'1(T), which implies 1 x2(T) 2 y2(T). This contradiction shows that xl(t) # yl(t) on (tl,b) and thus completes the proof of part (a).
.
102
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
The proof of part (b) i s similar t o t h a t of Theorem 2.1.1.
t2 =
Assume without l o s s of generality t h a t Define
Sk a s i n Theorem 2.1.1 and l e t
projection of
3
on t h e
Sk
i s an i n t e r v a l . A
bounded below).
3
axis.
Let
It suffices t o show
s^
3 =U,
m
be t h e r
z
but
$
(--,MI
2.
then
S,;
i s the r e a l l i n e .
We may assume t h a t t h e r e e x i s t s
(-m,M)
C
x2
8,
i s bounded above ( a similar proof holds i f
Suppose S that
b.
M
A s before, l e t
^s
>0
is such
xn(t)
be
a sequence of solutions of (2.1.1) s a t i s f y i n g
n
xn(tl) = (c,,n),
(2.2.3)
= 1,2
,... .
Then there e x i s t sequences
such t h a t (2.1.7) holds vn, "n [ t h i s follows since ( a ) i s the same as ( i i i ) i n Theorem 2.1.11.
From (2.2.3) there e x i s t s a sequence {zn] such t h a t t
+ t l and xn2(zn) 1 n solution of (2.1.1) s a t i s f y i n g
as
n
403.
x*,(b) = M.
Let
x*(t)
be any
From t h e f a c t t h a t
^s c (-m,M), xz(b) > xn2(b) f o r a l l n, but f o r l a r g e x:(zn) < xn2(zn). Thus there exists zk such t h a t
n
(2.2.4)
From (2.1.7)
< x,(wn),
x;(wn)
so t h a t t h e r e e x i s t s
zk
1
#
d',
> xnl(vn)
n
v n
n
and
n
< znt t < wn.
then (2.2.4) and (2.2.5) contradict ( i v ) .
Suppose z ' = z t t - then define x ( t ) = x n ( t )
n
for large
such t h a t
z"
X*(Zt') = Xd(ZB),
(2-2-5) If
xT(vn)
n'
x ( t ) = x*(t)
for
of (2.1.1)
such t h a t
x*,(b) = M,
so t h a t
z'
n
Gl(tl)
(--,MI
< t 5 b. = xnl(tl) E
3,
for
Then x ( t ) = c1
a
zk,
i s a solution
and x2(b) =
a contradiction.
This
completes t h e proof of Theorem 2.2.2. COROLLARY 2.2.1.
Consider t h e BVP (2.1.8),
103
(2.2.1) and
2 . SHOOTING TYPE METHODS
assume
a2b2 = 0.
Suppose a l l s o l u t i o n s of (2.1.8)
e x i s t on
( a , b ] and t h e r e e x i s t s a t most one s o l u t i o n o f (2.1.8), (2.2.1) f o r every tl,t2 E ( a , b ) . Then t h e r e e x i s t s
b
(a)
a unique s o l u t i o n o f (2.1.8),
(2.l.g),
(b)
a unique s o l u t i o n o f (2.1.8),
(2.2.1).
Proof: -
2
= 1 and
Without loss of g e n e r a l i t y , assume a1 = 1. Then (2.1.8),
a s t h e f i r s t - o r d e r BVP f o r X'
1
L-
x2-b x 1 1'
X$ =
x
=
(2.2.1)
(xl,x;
h(t,Xl,x2
+
a2 = 0,
can be w r i t t e n
blxl)
- b 1x 1)
and
i n which
+ bl(X2
- blxl),
We t h e r e f o r e see t h a t t h e hypotheses o f Theorem 2 . 2 . 1 h o l d and t h e r e s u l t follows. Assume i n (2.1.8) t h a t t h e f u n c t i o n
EXERCISE 2.2.1. h(t,x,y) lhxI 5 M, for
E
2
C(l) [ (a,b) xR , R ] s a t i s f i e s t h e i n e q u a l i t i e s IhyI 5 K. If I b - a l < l y / b ((u 2 +Klul +M)-')du
al = 1, a2 = 0, bl = 1, b2
#
0,
2
then t h e BVP (2.1,8),
(2.2.1) has a unique s o l u t i o n .
Hint: -
Prove (2.1.8), (2.2.1) has a t most one s o l u t i o n .
!Phis can be done by assuming t h a t t h e r e e x i s t s o l u t i o n s x2
a n d b y s e t t i n g x = x1-x2
obtain
xl,
lx"I < Mix1 + Klx'I,
x ( t ) = 0, x ( t 2 ) + b 2 x T ( t 2 )= 0. Then l e t t i n g w = x ' / x , 1 < w2 + KIWI + M, w ( t l - 0 ) = + m and w(t 2 ) = -l/b2. deduce ( w ' 1 By t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s conclude t h a t
w(t) < u ( t ) ,
where
-u' = u2
u(t)
+
i s the solution of
Klul + M,
F i n a l l y o b t a i n a contradiction. 104
u(t2) =
- l/b2.
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
I n t h e next two examples, we show t h a t Corollary 2.2.1 does not necessarily hold without t h e assumption t h a t a2b2 = 0 . EXAMPLFi 2.2.1.
(2.2.6)
The equation
2t l + t2
=
2 - x, 1+t2
X'
has the general s o l u t i o n x ( t ) = A(t2
-m
- 1) + B t .
+m
Hence there
e x i s t s one solution s a t i s f y i n g t h e boundary conditions x l ( t , ) = c1,x1(t2) = c2.
Observe
x 1( t )
are two d i f f e r e n t solutions s a t i s f y i n g
and
0
x2 ( t )
p
x(-1) = 0, x(1) = 0.
Moreover, t h e r e e x i s t s no solution s a t i s f y i n g
x(-1) = 0,
x(1) = 1. Thus (a) i n Corollary 2.2.1 i s violated.
EXAMPLE 2.2.2.
Let
be defined as i n Example 2.1.1.
Cp
Consider t h e d i f f e r e n t i a l equation
with t h e boundary conditions xt(t,)
- x(tl)
x ' ( t 2 ) - x ( t 2 ) = r 2'
= r 1'
The family of solutions of (*) i s given by x(t) = A where
A
and
B
+
Bet + t tan-'
B,
a r e a r b i t r a r y constants.
conditions lead t o ( l - t i ) tan Eliminating A
-1
B-A=
we obtain (tl
- t2)
tan
-1
105
B = r
2-rl
The boundary
-
t2 1
2 . SHOOTING TYPE METHODS
and thus t h e r e e x i s t s a t most one s o l u t i o n of t h e BVP.
How-
ever, i f
-
Ir2 rll _> (7J/2) It2-t1I, t h e r e e x i s t s no s o l u t i o n .
Hence (b) i n Corollary 2.2.1 does
not hold. When (2.2.7)
a2b2
#
rx(tl)
we can r e w r i t e (2.2.1) i n t h e form
0
+
x l ( t ) = c 1’ 1
s x ( t 2 ) + x l ( t2 ) = c
2‘
We now present a r e s u l t i n which uniqueness of (2.1.8) and (2.2.7)
implies existence under c e r t a i n added conditions.
-
Consider t h e ordering on
(al,bl)
Write
I: (a0,b0) (al,bl)
defined a s
R2
a. < bo
and
a1
5
a.
and
bl
3 bo,
> bo
and
a
2
a.
and
b
5
a.
1
1
bo.
< (aO,bo) when (al,bl) 5 (aO,bo) and
(al,bl) # (aO,bo). noted by ( h ; r , s ) . THEOREM 2.2.2.
Problem (2.1.8) and (2.2.7) w i l l be de-
Assume a l l s o l u t i o n s of (2.1.8) e x i s t on
(a,b) and a r e uniquely determined by t h e i r i n i t i a l values. Assume problem ( h ; r o , s O ) i s unique f o r any tl,t2 E (a,b), then t h e r e e x i s t s a unique s o l u t i o n o f
(h;rl,sl)
whenever
(rl,sl) < (r0,so)* Proof:
Assume t h a t
The o t h e r cases have s i m i l a r arguments and t h e r e f o r e we s h a l l consider t h i s case only. x(t,v)
Fix
tl, t2, and
c1
be t h e s o l u t i o n of (2.1.8) s a t i s f y i n g
106
and l e t
2.2. GENERAL LINEAR BOUNDARY CONDITIONS
x ( t 1, v ) = v,
x'(t,,v)
= cl-r
+
soX(t,v).
0
v.
Define T(t,v) = x ' ( t , v )
(h;ro,sO), v + T (t , v )
From t h e uniqueness o f mapping f o r
t
1 tl.
Define
( T(t,v2)
AT/Av Then
AT/&
t'tl f o r a l l t 2 tl.
=
i s a one-to-one
-ro + so
>
- T(t,vl))/(v2 - vl). 0.
Thus
+
so h / A v
AT/Av
i s positive
'ken, s i n c e
AT/Av = h ' / A v
>
0,
we see t h a t
Setting S(t,V) = x ' ( t , V ) + SIX(t,V) = T(t,V)
Hence
v +S(t2,v)
+
(sl
- S,)X(t,V),
i s a one-to-one mapping of
This i s equivalent t o
(h;rl,sl)
R
onto i t s e l f .
having exactly one s o l u t i o n
and thus t h e proof i s complete.
i s s t r i c t l y increasing and t h a t s o l u t i o n s of (2.1.8) e x i s t on (a,b) and a r e
COROLLARY 2.2.2. in
x
Assume
h(t,x,y)
uniquely determined by i n i t i a l conditions.
s
> 0,
problem (2.1.8),
Then, f o r
(2.2.7) has a unique solution. 107
r < 0,
2 . SHOOTING TYPE METHODS
Proof:
ro, so
To prove t h i s , choose
r < ro < 0 , 0 < so < s .
Hence
(r0,so) > (r,s) and by it s u f f i c e s t o show (h;ro,sO) i s unique.
Theorem 2.2.2,
Assume t h e r e e x i s t two s o l u t i o n s x = x1-x2.
and x2 and l e t 1 attains either its
x ( t ) f 0, x ( t )
Since
x
p o s i t i v e maximum o r negative minhum on x
such t h a t
Assume t h a t
[tl,t2].
a t t a i n s i t s p o s i t i v e maximum (the case i n which
i t s negative minimum uses a similar argument).
tl,
occurs a t
then
maximum occurs at
t h e second condition
s x(t ) 0
to
t h e maximum occurs at
>
x'(tl)
5
If t h e maximum
and t h e f i r s t
0,
r o x ( t ) + x ( ) = 0 cannot hold. If t h e 1 ' t2, then x ( t 2 ) > 0, x ' ( t 2 ) 2 0, and
boundary condition
x(t,)
> 0,
x(tl)
x attains
2
E
+
xt(t,) = 0
(tl,t2),
x ' ( t o ) = 0,
0,
however, by t h e monotonicity o f
cannot hold.
If
then x"(to)
h(t,x,x'),
5
0;
we have
a contradiction.
I n t h e next e x e r c i s e , we show t h a t t h e s t r i c t i n e q u a l i t y (rl,sl)
< (ro,so) cannot be weakened t o t h e i n e q u a l i t y
(rlYs1) 5 (ro,so). This w i l l provide another example i n which a2b2 # 0 and uniqueness o f t h e boundary value problem does not imply existence. EXERCISE 2.2.2.
Construct an example i n which t h e
hypotheses of Theorem 2.2.2 hold with replaced by t h e weaker condition
( y l ) < (ro'so) (rl,sl) 5 (ro,so) such
t h a t t h e r e e x i s t s no s o l u t i o n of t h e problem (2.1.8), (2.2.7).
Hint:
Let
Cp(p,q)
CP + p a r c t a n CP = q.
be t h e s o l u t i o n of t h e equation
Consider t h e d i f f e r e n t i a l equation 108
2.3. WEAKER UNIQUENESS CONDITIONS XI'
= F"cp(l/F',
x t / F t ) on t h e i n t e r v a l
w i l l be determined.
Let
w = x';
(-1,2),
w
then
where
F
s a t i s f i e s the
general solution
+
w ' ( t ) = BF'(t)
Solve f o r
x(t)
i n terms of
w(t)
conditions, where we may assume conditions on
F(tl),
This leads t o
1 where
F2
+
-r ( t + l )
1. Then obtain
t
F'(t)
>0
E
[-LO],
6
[0,11,
E
[1,21,
on
satisfies
tl
=
I (rc2 - c1)/(2r
-
F2(0) = 1 e'r, g(0) = l / r t g(1) = 1, g ' ( 0 ) = g'(1) = 0. Show
such t h a t
-4,t2 = 3/2 - 1)I 2 T / 2 ,
-< 1,
and
and f o r cl, c2 chosen so t h a t t h e r e e x i s t s no solution o f
(Use ideas i n B m p l e 2.1.1,)
(2.1.8) and (2.2.7). 2.3
>
t t
( ~ ~ (- 1l)el-t, )
i n which g 6 C ( l ) [ [ O , l ] , R ] l/r < g ( t ) < 1 for 0
tha t for
s = 1, r
and such t h a t
F2 + g(t)F; = 1,
-
and s u b s t i t u t e t h e boundary
F f ( t l ) , F ( t 2 ) , F 1 ( t 2 ) such t h a t unique-
ness holds (see Example 2.1.1) (-1,2).
a r c t a n B.
WEAKER UNIQUENESS CONDITIONS
It i s n a t u r a l t o ask whether it i s possible t o weaken t h e uniqueness condition of t h e BVP (2.1.8), (2.1.2) by not demanding t h a t t h i s condition hold f o r a l l tl,t2 [a,b+&) (or
tl,t2
E
(a-&,b]).
6
I n t h i s section, we plan
t o discuss how some of t h e previous r e s u l t s remain t r u e even when t h e uniqueness assumptions a r e weakened f o r and f o r
t2
E (b
- &,b + E )
THMlREM 2.3.1.
Let
f o r some h
6
E
>
0.
C[[a,b+E) xR2,R]
109
t1 = a f o r some
2 . SHOOTING TYPE METHODS
>
E
and suppose t h a t a l l s o l u t i o n s of i n i t i a l value problems
0
[a,b + E).
f o r (2.1.1) e x i s t on
Assume t h a t f o r a f i x e d
t h e r e e x i s t s a t most one s o l u t i o n on
[a,t2]
c
o f t h e BVP
1
(2.1.1) and (2.3.1)
.(a)
for a l l
= c1 '
and t2
c2 E R
x ( t 2 ) = C2'
(b
E
- E,
b + E).
Then t h e r e e x i s t s
e x a c t l y one s o l u t i o n of (2.1.1) and (2.3 - 2 )
.(a)
f o r each
= cl,
x ( b ) = c2
c2 E R. For each m E R
Proof:
define
Am = [x(t,m) E C ( 2 ) [[a,b
+E)
x R , R ] : x(t,m)
i s a s o l u t i o n of (2.1.1) with
x(a) = c
x ' ( a ) = m].
and Define t h e mapping
r(m) = [x(b,m)]; I?
maps p o i n t s i n t o s e t s
and an a p p l i c a t i o n of Lemma 2.1.1 y i e l d s t h a t connected s e t s i n t o compact, connected s e t s . then
i
5
r(m)
m <m2 < m 1
r(mi).
m2 < m
t h e BVP.
3
Since
there exists
m*
ml
#
m2,
5 max r(m2).
We now show E
maps compact,
fl r(m2) = $, because of t h e uniqueness of s o l u t i o n s We can thus define r(m,) 5 r(m2) i f and only i f
max r(m,)
x
r
If
r(ml)
of BVP.
that
1
m*
3'
E
i s monotone.
Assume, f o r example,
r(m,) < r(m3) < r(m2). Let < x < x2 and F ( [m ,m 1 ) i s connected, 1 3 1 2 [m,,m2] such t h a t x(b,m+) = x Since 3' and
x
we have a c o n t r a d i c t i o n t o t h e uniqueness of
The o t h e r cases may be t r e a t e d by a similar argument.
I n order t o complete t h e proof of Theorem 2.3.1, enough t o show
r ( R ) = R.
If not, t h e r e exists a
9
We f i r s t prove t h a t E
r(R) 110
r(R)
it i s i s open.
t h a t i s not i n t h e i n t e r i o r .
2.3. WEAKER UNIQUENESS CONDITIONS
Hence there i s an
r
t o n i c i t y of
r ((;,-GI)
m
such t h a t
x(b,m) = JI.
we can find m > m N
contains
-
< m such t h a t
or
as an i n t e r i o r point.
JI
contradict ion.
r(R)
It thus suffices t o prove t h a t
above nor below,
By the mono-
r(R)
Assume
This i s a
i s neither bounded
i s bounded above (a similar
argument i s t r u e f o r the other case) and l e t '1 = sup r(R). L e t xn(t,m ) denote a sequence of solutions of (2.1.1), n (xn(a,mn)) = cl,(x;(a,mn)) = mn such t h a t xn(b,mn) + q . For c E ( b , b + & ) and from the uniqueness of BW,
-
xn(c,mn> xn(b,mn) C-b
where
K = min {0, (x1(c,m,)
> -
- xn(b,mn)
xl(c,ml)
-> K
C-b
- q)/(c - b)].
We m a y assume t h a t , f o r i n f i n i t e l y many nls, we have x;(b,mn) 5 0, because a similar argument can be made f o r c E (b &,b) i n case x;(b,mn) _> 0 f o r i n f i n i t e l y m a n y n ' s .
-
We r e s t r i c t our arguments t o those Let
sn
=
[t:
o> x;(t,mn) 2
n
such t h a t
K, t E [ b , c ~ ] .
This s e t i s nonempty by the mean value theorem.
-
s = min S then b < s n < c and n n' without loss o f generality, sn + s
x;(b,mn)
If
x;(b,mn) x;(t*,mn)
t*
E
<
= 0,
0,
= 0
then
b = s
n then xn(t,mn) < q
x;(b,mn)
0 and.
kt
- n n n 5
K < x t ( s ,m )
0.
Thus,
(s m ) +?,. n n' n xn(sn,mn) < q. If
and
XI
t E [b,t*l, where and t* i s the f i r s t such point. men
Sn and therefore
for
sn E [b,t*].
Thus again xn(sn,mn) < q . [b,c]] (from the
Since xn(sn,mn) _> min [xl(t,mn): t E uniqueness of BVP), there e x i s t s a subsequence of
{xn(sn,mn)] which we choose t o c a l l by the same labeling, such t h a t
-
x (s ,m ) +xo. Thus, sn + s o , x (s ,m ) + x o , x;(sn,mn) + x o . n n n n n n Let S(6) be a 6 - b a l l i n R3 about ( S ~ , X ~ , ~ ~ ) , 111
2. SHOOTING TYPE METHODS
where
6
- so.
E
For
n
s u f f i c i e n t l y large
(snJxn(~nJmn),x~(sn,~n)) E ~(6). Since a l l solutions of (2.1.8) e x i s t on Ix$(t,m,)I
[a,b
there exists
+&),
< Q for t
E
[ a , s O + 6 ] . Let
be solutions o f (2.1.8) with montonicity of X(b9-Q)
2
q
or
x(b,*), x(b,Q)
Q
x(b,-Q)
> Xn(bjmn)
such t h a t
x(t,Q)
x(a,+Q) = cl;
either
>0
and
x(t,-Q)
then by the
> xn(b,mn)
which means
so that
x(b,Q)
2
q.
This i s a contradiction and t h e proof of Theorem 2 . 3 . 1 i s
complete. COROLLARY 2.3.1.
the BVP (2.1.8),
Under the conditions of Theorem 2.3.1,
(2.2.1) has a unique solution, i f
We leave the proof as an exercise.
m a y be helpful.
For a fixed
a2b2 = 0.
The following h i n t s
Consider the boundary conditions
clJ
define
r(m) = [x(b,m): where
x(t,m)
of (2.1.8) such t h a t
x' (.a,m)
= c1
- rlml.
i s a solution
x(a,m) = m
Then using the same techniques as i n Theorem 2.3.1,
and
show
r(R) = R.
By combining the techniques employed i n Theorems 2.1.1 and 2.3.1,
one can deduce t h e following generalization, the
proof of which we leave t o the reader. THEOREM 2.3.2.
Consider t h e BVP (2,1.1),
(2.1.2)
assuming conditions ( i ) and ( i i ) of Theorem 2.1.1.
Suppose
t h a t t h e condition r e l a t i v e t o t h e uniqueness of BVP, i n the sense of Theorem 2.3.1 i s t r u e . solution of (2.1.1),
(2.1.2).
112
Then t h e r e e x i s t s a unique
2.4. NONLINEAR BOUNDARY CONDITIONS
2.4
NONLINEAR BOUNDARY CONDITIONS We now present a r e s u l t i n which t h e boundary conditions
are. nonlinear.
Under some additional hypotheses on h ( t , x , x ‘ ) ,
it i s possible t o deduce existence r e s u l t s f o r general l i n e a r boundary conditions f o r which corollary t o our main r e s u l t . THEOREM 2.4.1.
S1, let
as
x2
-L
g2 (c)
+ y2
--tm
i n e i t h e r direction.
R2
be nonempty.
Assume f o r
t
uniformly f o r
E
(b
- E,b + E)
and a l l
one solution of (2.4.1)
Proof:
f = (fl,f2)
E [a,b+&),
and t h a t a l l
(2.4.2) c E R,
- (2.4.3).
and
g,(x(s),y(s))
= c
there e x i s t s exactly
The idea of the proof i s similar t o t h a t of the
proof of Theorem 2.3.1. gl(x,y) = c1
For every
[ a , b + & ) . men i f there e x i s t s
a t most one solution of (2.4.1),
s
This we s t a t e as a
Y ’ = f2(t,X,Y),
solutions of (2.4.1) e x i s t on for
0.
when parameterized i n terms of a r c length, leaves
every bounded region i n C,
#
Consider t h e boundary value problem
x’ = fl(t,X,Y),
(2.4.1)
then
a2b2
Let
Po
and parameterize 113
be an a r b i t r a r y point of
S1 by a r c length with
Po
2 . SHOOTING TYPE METHODS
a s t h e i n i t i a l point.
The points on
s
For any f i x e d
t h e parameter.
E
S1 w i l l be denoted by
[a,b + E ) ,
define f o r
s1
P E
Ts(P) =
[ (x(S,P),Y(s,P)),
where
(x(t,P),y(t~P))
denotes a s o l u t i o n of (2.4.1) s a t i s f y i n g ( x ( a , p > , y ( a , p > ) = PI, and l e t
rs(p) =
[g2(x(s,p),y(s,p)):
( X ( S , P > ~ Y ( S , P >E ) T ~ ( P > ] .
It i s s u f f i c i e n t t o show rb(R) = R, t o prove t h e theorem. From Lemma 2.1.1, Ts(A) i s compact and connected, i f A
i s compact and connected.
g (x,y) i s continuous, 2 It follows from a simple
Since
i s compact and connected.
rs(A)
argument t h a t
rs(R)
i s connected. rs(P1) n rs(P2) = @ f o r i s an i n t e r v a l o r p o i n t . We
By uniqueness o f t h e BVP, s E (b
- E,b + E ) .
rs
now show t h a t
Thus
r S (P)
i s monotone f o r
s
(b - E,b
E
+ E).
Let
< P2 < P (ordered by a r c l e n g t h ) and assume rs(P2) < 3 rs(P 1) < r s ( P 3 ) ( t h e o t h e r cases follow s i m i l a r l y ) . Let
P1 x
E rs(Pi), i = 1,2,3. Since i t h e r e e x i s t s P*, P2 5 P* < P
Since
P
1
< P2 5 P*,
i s connected,
rs([P2,P3])
E rs(P*). 1 t h i s c o n t r a d i c t s uniqueness o f s o l u t i o n s
- 3
such t h a t
x
of boundary value problems. Assume now
rb(R)
i s not a l l of
R
and t h a t
bounded above [ a s i m i l a r argument holds i f below], that
q
Let E
q = sup rb(R).
rb(R).
(x(t),y(t))
We claim
rb(R)
q d, rb(R).
is
rb(R)
i s bounded Suppose
Then t h e r e e x i s t s a s o l u t i o n of (2.4.1),
s a t i s f y i n g (2.4.2) and g2(x(b),y(b)) = q.
Let
and choose P2, P3 such t h a t P2 < P1 < P 3' Then from t h e monotonicity of rb, e i t h e r rb(P2) > rb(P1)
P1 = ( x ( a ) , y ( a ) )
or
rb(P3)
>
rb(Pl),
Since
q E rb(Pl)
114
t h i s contradicts the
2.4. NONLINEAR BOUNDARY CONDITIONS
maximality of
q k, rb(R).
and thus
q
There e x i s t s
zn
rb(R)
E
such t h a t
zn t q.
To each
t h e r e e x i s t s a unique point P E S1 and a unique s o l u t i o n n n of (2.4.1), ( x n ( t ) , y n ( t ) ) through Pn a t t = a such t h a t z
g2(xn(b),yn(b)) = zn.
Also
qn(t) = g2(xn(t),~,(t)), t
Pn E
i s monotonic i n
n.
Let
[a,b +&I. Then
A s i n t h e proof of Theorem 2.3.1, we want t o o b t a i n a
convergent subsequgnce of i n i t i a l p o i n t s
t
E (b
- &,b+ & ) ,
monotone i n
or
$A(b)
$A(b)
5
-< 0
t
E
(b
i s monotone i n n since {Pn] i s n and BVP's a r e unique. Also, e i t h e r $;(b) $ (t)
n
f o r i n f i n i t e l y many n ' s .
[a similar argument i s v a l i d i f
monotone decreasing i n
b
-< sn 5 b +A(b)
+ s
<
Let
E
n
+so,
monotonicity of Jln(sn), +A(",)
t*
E
$
n
[b,b
E
Let
+ E).
> -
0
Assume
qn(t)
is
Then
From t h e mean value
sn = min S
n'
Then
K < $;(sn) < 0. Thus, without l o s s o f $A(",) +qo. If $;(b) = 0, t h e n b = s
and
0, q n ( t )
However, then
t*
_> $A(t) 2 K].
i s not empty.
Sn
generality If
n].
>b, 0 Sn = [ t : t -
theorem,
We may assume
$'(b) > 0. n i s monotone increasing i n n f o r
qn(t)
- &,b + & )
Define
For f i x e d
A similar argument holds when
0.
also that
(xn,yn).
<
Sn
q
until and thus
we have
$'(t*)= 0 n qn(sn)
JIl(sn)
< q.
< JI,(sn).
a r e bounded condition (2.4.4)
t* > b.
f o r some From t h e Since implies
l i e i n a bounded region.
{xn(sn),yn(sn)] Choose a convergent subsequence
115
sn + so, x (s ) n n
--f
x0'
n
.
2 . SHOOTING TYPE METHODS
yn(sn) + y o . where
6
Let
be a b a l l of radius
Ss
- so.
6 about
For large n, (sn,xn,yn)
E
S6.
(so,xo,yo) Since a l l
[a,so + 61, we have ( x n ( a ) , y n ( a ) ) E Sk s u f f i c i e n t l y large. Let Pn = ( x n ( a ) , y n ( a ) ) , Pick
solutions e x i s t on for
k
Ql,%
E
S1
llqll > k, Ilgll > k,
such t h a t
rb
From the montonicity of rb(Q2)
> rb(Pn)
f o r a l l n.
either
rb(%)
Thus e i t h e r
Q1 > Pn > %. > rb(Pn) o r rb(%) 2 q o r and
rb(&2) 2 q. This i s a contradiction t o t h e maximality of and the proof follows. COROLLARY 2.4.1.
q
Consider t h e BVP
(2.4.5)
X"
,
= h ( t X, x ' ),
(2.4.6)
r x(a) 1
+
r2x1(a) = c 1'
(2.4.7)
s x(b) 1
+
s 2 x ' ( b ) = c2,
2
where h E C[[a,b+E)xR ,R]
and assume t h e BVP (2.4.5),
(2.4.6) and s 1x ( t ) + s 2 x ' ( t ) = c has a t most one solution on [ a , t ] f o r each t E ( b - E , b + & ) and a l l c E R. I f
[s x + s 2 x 1 I 2 + [s x ' + s 2 h ( t , x , x ' ) ] 2 1 1 uniformly f o r
t
E
solution of (2.4.5) 2.5
[b
- E , b + E],
- (2.4.7).
+m
as
x2
+ xf2 +m
then there e x i s t s exactly one
ANGULAR FUNCTION TECHNIQUE
I n the preceding sections of t h i s chapter, we used a shooting type method t o prove t h e existence of solutions from uniqueness assumptions.
I n what follows, we wish t o employ
the angular f'unction technique t o study a number of r e s u l t s concerning existence and uniqueness i n a unified way.
In
p a r t i c u l a r , we are i n t e r e s t e d i n discussing the solutions of the d i f f e r e n t i a l equations
116
2.6. FUNDAMENTAL LEMMAS
(2.5.1)
Y' = g ( t , x , y )
x ' = f(t,X,Y),
s a t i s e i n g the boundary conditions (2.5.2)
.(a)
(2.5.3)
x(b) s i n p - y ( b ) cos f3 = 0.
Here we assume
s i n a - y ( a ) cos CY = 0 ,
2
f,g E C[[a,b] xR ,R],
0
-< CY < T
and
0
< f3 5
T.
We may geometrically i n t e r p r e t t h e problem as finding a solution z ( t ) = ( x ( t ) , y ( t ) ) of (2.5.1) which l i e s on the s t r a i g h t l i n e x s i n . a , y cos CY = 0 a t t = a, and on the l i n e
-
x s i n B - y cos B = O
at
t=b.
With respect t o t h e solution polar angle cp(t)
z ( t ) = ( x ( t ) , y ( t ) ) the
i s defined i n the
q(t)
xy plane.
i s called the angular function of
defined as long as formulas r e l a t e
cp(t)
and
z(t)
x ( t ) = Ilz(t)ll cos d t ) ,
=
and i s well
z(t)
~ ( t )does not vanish.
The function
Thus the following
(x(t),y(t)):
Y(t) = llz(t)II sin cp(t),
and
cp'(t>= Observe a l s o t h a t (2.5.3)
x(t)y' ( t )
- y(t)x' ( t )
x 2 ( t ) +Y2(t) z(t)
i s a solution of the BVP (2.5.1)-
i f and only i f i t s angular function
cp(a) = a, f o r some integer
q(t)
satisfies
cp(b) = B + k-rr
k.
The following lemma i s a version of Lemma 2.1.1.
117
2. SHOOTING TYPE METHODS
LEbW 2.6.1.
[a,b].
s
Let
Assume a l l s o l u t i o n s of (2.5.1) e x i s t on 2 be m y compact connected s e t i n [a,b] X R
.
Then t h e s e t o f a l l s o l u t i o n s passing through 2 connected s e t i n R
.
form a compact,
S
Consider now t h e i n i t i a l conditions (2.6.1)
x(to) =
y ( t o ) = YoJ
xoJ
and denote t h e s o l u t i o n s of (2.5.1) and (2.6.1) a s
z(t,z0) =
( x ( t J x 0 J ~ o ) JY ( ~ J X ~ J Y ~where ))J 0 = (xoJy0)* ~ e t~ ( t , z o ) denote t h e angular function of any s o l u t i o n of (2.5.1) s a t i s % ing (2.6.1).
Observe t h a t
cp(t,zo),
f o r each
t
E
[aJbIJ is
multivalued s i n c e s o l u t i o n s a r e not i n g e n e r a l wniquely defined We now present a lemma s i m i l a r t o
by t h e i n i t i a l conditions.
2.6.1 f o r angular functions.
-ma
LEMMA 2.6.2.
Let
be any compact connected s e t o f
S
R2
such t h a t t h e r e e x i s t s a l i n e through t h e o r i g i n which does not intersect all
t
E
S.
Assume t h a t f o r a l l
[a,b].
#
0
for
Then 2
u
0
forms a segment f o r each EXERCISE 2.6.1.
Hint: -
zo E S, z ( t , z o )
dtJzo)
ES
t
E
[a,b].
Prove Lemma 2.6.2.
Assume t h a t t h e r e s u l t i s not t r u e and use Lemma
2.6.1 t o o b t a i n a contradiction. LEMMA 2.6.3.
There e x i s t functions
m(u)
and
that m(IIzoII) _< IIZ(tJZO)ll _< ~ ( l l z ~ l l ) ~
118
M(u)
such
2.6. FUNDAMENTAL LEMMAS
where
lim m(u) =
u+ Proof:
+m,
+m
Define
and m(u) =
inf IIz(t,zO)Il. llzo II 2 u
t c [a,b I By Leinma 2.6.1,
M(u)
lhu++w m(U) =
show
and +m.
a r e w e l l defined.
m(u) Let
ro
>0
be given.
t h e s o l u t i o n s of (2.5.1) passing through t h e s e t
We now Consider
S =[(t,z):
E [ a , b l , I/zII 5 ro]. By Lemma 2.6.1 t h e r e e x i s t s a u > 0 0 such t h a t llz(t)l/ 5 uo where ~ ( t )passes through S. Hence
t
if
I/zoII > uo,
then
> r0
for
thus
m(u)
-
llz(t,ZO)ll > ro f o r a l l t E [a,b] u
> u 0'
and
This proves t h e lemma.
We now s t a t e t h e following known r e s u l t on t h e semicontinuity behavior of s o l u t i o n funnels. IEMMA 2.6.4.
Assume t h a t s o l u t i o n s of
r' where
F
E
n n C[[a,b] X R ,R
there e x i st s
6
>
0
6(t)
e x i s t on
= F(t,r)
i s continuous and
solution r 2 ( t )
of
[a,b].
For each
such t h a t f o r each s o l u t i o n rl
where
1,
= F(t,r),
r ' = F(t,r),
satisfying 119
+
rl(t)
6(t),
116(t)II < 6, where
there i s a
r ( a ) = r,(a), 1
E
of
>0
2. SHOOTING TYPE METHODS
- r 2 ( t ) II < E
Ilr,(t) f o r a l l t E [a,b]. We s h a l l now compare (2.6.2)
x' =
(2.5.1) with
N
Y ' = &,X,Y),
f(t,X,Y),
2 f , g E C[[a,b]xR ,R].
N
where
N
side of (2.6.2)
Assume also t h a t t h e right-hand
are p o s i t i v e l y homogeneous, t h a t is, N
N
(2.6.3)
f ( t , c x , c y ) = c?(t,x,y),
for a l l
c
2 0.
We write
xg(t,X,Y)
[f,g]
@;(t,cx,cy)= cg(t,x,Y)
2 {F,;i?
- Yf(t,X,Y) 2 &(t,X,Y)
if N
-Yf(t,x,Y).
We now present a comparison r e s u l t . LEMMI1 2.6.5.
L e t solutions
(2.5.1) and (2.6.2), never vanish.
Let
z(t)
and 2 ( t )
of systems
respectively, be defined on cp(t)
and
2 t )
[a,b]
and
be the respective angular
f'unctions of t h e solutions and assume
v(a> 2 5(4,
(2.6.4)
Cf,d ,> C G I .
Then
V ( t > 2 6m(t) where (2.6.5)
for
a l l t E [a,b],
N
(pm(t) i s the minimal solution of $ ' ( t ) = z ( t , c o s $,sin
$)
120
N
N
N
cos cp-f(t,cos cp,sin
5) s i n $.
2.7. EXISTENCE
The theory of d i f f e r e n t i a l i n e q u a l i t i e s then gives
The proof i s complete. If solutions of (2.5.1)
and (2.6.2)
a r e uniquely determined
by i n i t i a l conditions, then we may conclude t h a t Observe a l s o t h a t
?(t,O,O)
i s a solution of (2.6.2).
g(t,O,O)
E
E
0
cp(t) 1 ;(t); so t h a t z ( t ) E 0
Moreover, we notice, from the
homogeneity t h a t Il?(t,x,y)II 5 A (x2 + y2)*, llz(t,x,y)/l 5 I 2 A (x + y2)2 f o r some A > 0. This implies t h a t a l l solutions of (2.6.2) e x i s t on
[a,b].
From the calculations used i n t h e
previous l m a , we see t h a t the angular function s a t i s f i e s a d i f f e r e n t i a l equation independent of t h e solution, so it i s consistent t o discuss the angular function of a system with a given i n i t i a l angle. 2.7
EXISTENCE Before proving existence r e s u l t s f o r (2.5.1)
- (2.5.3),
it
i s necessary t h a t c e r t a i n r e s t r i c t i o n s be placed on the solutions of t h e comparison equation (2.6.2) which s a t i s f y t h e boundary conditions (2.5.2)
and (2.5.3).
When solutions of (2.5.1)
and
(2.6.2) are uniquely determined by i n i t i a l conditions, these r e s t r i c t i o n s reduce t o t h e following:
l e t ?+(t)
denote the angular functions of (2.6.2) conditions
-4-
cp (a) = a, ?-(a) = CY
121
+
T
and ? ( t )
s a t i s f y i n g the i n i t i a l
and suppose t h a t
2 . SHOOTING TYPE METHODS
f3
+ kT<
y ( b ) < f3
+ (k+l)T
and
f3
+
( k + l ) T < $-(b) < p
f o r a certain integer
k.
+ (k+2)~
This condition, i n f a c t , implies
t h a t t h e only s o l u t i o n o f t h e BVP (2.6.2), Z(t)
=
(2.5.2),
(2.5.3) i s
0.
Since we do not assume t h e uniqueness of s o l u t i o n s , t h e previous conditions w i l l be i n terms of minimal and maximal solutions. Consider t h e a u x i l i a r y systems
(2.7 1)
x'
= :(t,x,Y),
Y ' = b(t,X,Y)
x'
= C(t,X,Y),
Y ' = d(t,X,Y),
and
(2.7.2) where in
a,b,c,d
x and y.
2 C[[a,b] X R ,R]
E
Let
8(t)
of (2.7.1) and (2.7.2).
and
and a r e p o s i t i v e l y homogeneous $(t)
be t h e angular flmctions
Then a computation similar t o one i n
Lemma 2.6.5 y i e l d s
(2.7.3)
€ I t ( t ) = b ( t , c o s @ , s i n 8 ) cos e - a ( t , c o s B,sin 8) s i n 0,
and
(2.7.4)
$ ' ( t ) = d ( t , c o s $ , s i n 9) cos $ - c ( t , c o s $ , s i n $) s i n $.
I n order t o avoid r e p e t i t i o n , l e t us l i s t below c e r t a i n hypotheses t h a t w i l l be needed subsequently, (H ) The m a x i m a l s o l u t i o n s $ i ( t ) and $ i ( t ) 1 . satisfying and +-(a) = CY + T obey M (a) = M
$i(b) < p
+ (k+l)T
f o r some i n t e g e r
and
k;
122
o f (2.7.4)
$ i ( b ) < f3 + ( k + 2 ) 1 ~
2.7. EXISTENCE
(H2) The minimal solutions satisfying
0+(a) = m
$(b)
CY
and e-(a) m
+ krr
>p
f o r t h e same i n t e g e r
k
@:(t)
+
=
IT obey
0 i ( b ) > f3
and
+
(k+l)r
a s i n (Hl);
(3)The following i n e q u a l i t y holds between
(2.5.1),
(2.7.1),
b(tJxJy)x
- a(tJx,y)y +i(tJxJy)
t
1. g(tJxJy)x-
-
E
(t,x>y)y
- c ( ~ J x J Y ) +Y% ( ~ J X J Y ) ,
[a,bl.
Observe t h a t when solutions a r e unique (H1) t h a t t h e only s o l u t i o n of (2.7.l),
(2.5.2),
systems
and (2.7.2):
< d(t,x,Y)x
uniformly f o r
of (2.7.3)
and e i ( t )
(2.5.2),
and
(2.5.3)
( 5 )imply
and (2.7.2),
(2.5.3) i s t h e t r i v i a l s o l u t i o n .
We now s t a t e and prove our main existence r e s u l t . THEOREM 2.7.1.
(2.5.1)
- (2.5.3)
Proof:
Under t h e hypotheses (H1)
-
(3), t h e BVP
admits a solution.
Let
z(t,c) = (x(t,c),y(t,c))
be any solution of
(2.5.1) sat i s fying t h e i n i t i a l condition (2.7.5) Let
cp(t,c)
x ( a ) = c cos a,
y ( a ) = c s i n a.
be the angular function of cp(a,c) =
("
IT
123
z(t,c)
if
c 7 0,
if
c
such t h a t
2. SHOOTING TYPE METHODS
From (€$), we o b t a i n 'pf(t,c)
(2.7.6)
5 b(t,cos
(&sin
cos v - a ( t , c o s
'p)
'p,sin
s i n cp
'p)
+ B0(t),
2 2 _s(t,x(t,c),Y(t,c))/(x ( t f c ) + Y ( t j c ) ) . be t h e minimal s o l u t i o n s of
where 60(t) -+ e m ( t ) , g-(t) m
rv
;l(t)
(2.7.7)
Let
g)
= b ( t , c o s 0 , s i n 0 ) cos z - a ( t , c o s 5 , s i n
s i n ;i'
+ 60(t),
-+ 0 (a)
where
=
m
a, g-(a) m
= cf
+ T, it follows t h a t
From (2.7.6) and t h e proof o f Lemma 2.6.5,
(%),
In view of
>
0:(b)
(2.7.9)
f3
we may p i c k
+ krr +
@-(a) =
cf
(2.7.10) whenever
Oi(b) > B + ( k + l ) T +
E,
6>0
so t h a t t h e r e
e+(t), 0-(t)
o f (2.7.3),
where
0 (a) = a,
p
>0
E
satisfying
- e-(t>I
le;(t)
and
< 6 for a l l t
I6,(t)I
+
that
- e+(t>l < E
Iz:(t)
[a,b]. Bo(t)
<
IcI
llz(a,c)I(
> ro,
We thus obtain, using (2.7.8) (2.7.11)
'p(b,c)
> 0:(b)
then
6 if
124
b(t,c)
- (2.7.10),
-> e+(b) - E > 0:(b)
<
E,
7I
Because o f (
MOreover, Lemma 2.6.3 implies t h a t t h e r e exists an such t h a t , i f
E.
we may p i c k
+ TT,such
there exists a
> 0 so small t h a t
(%),
By Lemma 2.6.4 and exist solutions
E
llz(t,c)
> P.
ro > 0
11 > P.
t h a t for
-E
),
>B+
c
krr,
2 ro
2.7. EXISTENCE
By applying a s i m i l a r analysis t o t h e maximal solutions of
(2.7.4) and using (H1)’ we i n f e r the existence of that, for
c
2 rl
(2 7.13
q(b,C)
r1
>0
)
l i e on
such
< B + (k+l)Tf~
and f o r c
(2.7.14)
5 -r 1 (k 4-2)T.
q(bJC) < @
Hence, f o r
c
2 r3
max(r J r ), 0
1
B + ki-r < cp(b,c) <: B + (k + l ) ~ , and f o r
5 -r3
c
B + ( k + l ) n < q(b,c) < This a s s e r t s t h a t the points
@
+ (k+2)7r.
z(b,r )
3
d i f f e r e n t sides of the s t r a i g h t l i n e Consider the s e t of solutions
2.6.1, is
x sin
3 3
such t h a t
@ - ycos @ = 0.
Thus
z(b,-r
x sin @
-y
uIlz I1 <: r3 [ z ( t , c ) 1.
t h i s s e t i s connected i n
c* E (-r , r )
and
R2-for each
z(b,c*) z(t,c*)
3
cos f3 = 0.
t.
BY
Lemma
Hence there
l i e s on the s t r a i g h t l i n e i s a solution of the BW.
This concludes the proof of Theorem 2.7.1.
We leave the proof of t h e following theorem as an exercise since i t s proof i s very similar t o t h e proof of Theorem 2.7.1. 13IEOREM 2.7.2.
(H2) holds. and
ei(t)
Consider the system (2.7.1) and assume
Moreover suppose t h e maximal solutions of (2.7.3)
satisfying
125
+ OM(&)=
cy
and
ei(t) @;(a) = a +7r
2 . SHOOTING TYPE METHODS
e+(b) < f3 + ( k + l ) n and M e x i s t s a s o l u t i o n of
obey
EXERCISE 2.7.1. COROLLARY 2.7.1. (Theorem 2.7.2)
ei(b)
< f3
f
(k+2)T.
Then t h e r e
Prove Theorem 2.7.2. Under t h e hypotheses of Theorem 2.7.1
t h e r e e x i s t s s o l u t i o n s of (2.5.1)
[(2.7.15)]
s a t i s f y i n g t h e boundary conditions x(a) s i n a
(2.7.16)
- y(a)
cos CY = c
x ( b ) s i n p - y ( b ) cos
f o r any
c1,c2
E
Hint: -
1' c2
R.
EXERCISE 2.7.2.
bounded by
f3 =
Prove Corollary 2.7.1.
U s e t h e f a c t t h a t a homogeneous expression i s 2 A(x + y2)' and make a change of v a r i a b l e s by
t r a n s l a t i n g t h e p o i n t of i n t e r s e c t i o n of t h e two l i n e s i n (2.7.16) t o t h e o r i g i n .
Then apply Theorem 2.7.1 (Theorem
2.7.2). EXAMPLE 2.7.1.
The equation x"(t)
+a
sin x + h ( t )
= 0
has a s o l u t i o n which s a t i s f i e s t h e condition
x(a)
= x(b) = 0 .
To show t h i s consider t h e s o l u t i o n s of XI'
= 0,
x ( a ) = x ( b ) = 0.
It i s clear t h a t t h e only s o l u t i o n of t h i s BVP i s t h e t r i v i a l
126
2.8. UNIQUENESS
solution x ( t )
as
1x1 + I x ’ (
=
0.
bbreover
(a s i n x + h ( t ) ( / ( ( x l+
(XI
I)
+O
An immediate application of Theorem 2.7.2
+m.
y i e l d s the desired r e s u l t . EXERCISE 2.7.3.
Show t h a t t h e boundary value problem
x” + g ( t , x , x ’ ) = 0,
x ( a ) = x(b) = 0,
has a solution, i f Ig(t,x,x’)1 2.8
1. Alxl +
B,
where
E
C[[a,b] xR+,R]
A(b-a)
2
<
2
IT
.
UNIQUUENESS
Assume t h a t
Li,
Mi,
Ki,
Ni
homogeneous i n t h e i r second variable. conclude t h a t
127
and a r e positively
From (2.8.1), we may
2. SHOOTING TYPE METHODS
Define now the Functions
128
2.8. UNIQUENESS
uv
-> 0,
uv
<
uv
> 0, -
uv
<
UV?
uv
<
UV?
0,
0, 0, 0, 0,
uv < 0. Consider t h e comparison systems (2.8.2)
u'
= P1(t,u,v),
v' = P2(t,u,v),
(2.8.3)
U'
= Ql(t,U,v),
V'
Observe t h a t u
and
v.
= &(t,u,v).
Pi, Qi, i = 1 , 2 a r e p o s i t i v e l y homogeneous i n + Letting $ ( t ) , $ - ( t ) be t h e angular f'unctions
associated with (2.8.2) and
+
8 (t), e-(t)
be t h e angular
functions associated with (2.8.3), we have (2.8.4)
$ ' ( t ) = Pl(t,cos Fl(t,
(2.8.5)
$1,
e i ( t ) = Ql(t,cos @ , s i n e ) cos e - & ( t , c o s @ , s i n e ) s i n 3
Since
$,sin +) cos + - P 2 ( t , c o s $ , s i n JI) s i n JI
Pi,
Q.
1
F2(t,8).
a r e continuous everywhere except along t h e co-
o r d i n a t e axes, we agree t h a t s o l u t i o n s of (2.8.2), d i f f e r e n t i a b l e almost everywhere.
(2.8.3) are
A s i m i l a r statement holds f o r
t h e angular functions which a r e not d i f f e r e n t i a b l e along t h e angular rays
n~r/2, n = 0 , +I, 2 2 ,
... .
We a r e now a b l e t o s t a t e and prove a uniqueness r e s u l t .
129
e
2 . SHOOTING TYPE METHODS
!EBOREN 2.8.1.
Assume
t h a t conditions (H1) and
(2.8.9, respectively.
f
and g
(5)hold
s a t i s f y (2.8.1) and
r e l a t i v e t o (2.8.4) and
Then i f solutions of (2.5.1) a r e
uniquely defined by the i n i t i a l conditions, there e x i s t s one solution of t h e BVP (2.5.1)- (2.5.3).
then z ( t ) = (;(t),y(t)) (2.5.2),
(2.5.3).
satisf'y the boundary conditions
Also l e t
angular function of -~ ( t ) . For convenience, we s h$atl)l l ebet the G(t), = y(t), -z = T ( t ) , and = $ t ) . We claim t h a t -x%(t,z,F) -T€$(t,x,y) 5 FIG-GIT (2.8.6) -< 5;P2(t,<,7) - y P p , Z , T ) . 3
From our previous estimates
-x(%(t,;) -
-
x ( % ( t , x ) +N2(t,y)) if i;
= xP2(t,Z,T). Similarly,
130
+N2(t,y)) if 2
y 2 0, ? < 0,
2.8. UNIQUENESS
The lower estimates i n (2.8.6) a r e obtained i n t h e same manner. Hence we obtain from (2.8.6), (2.8.7) where
F2(t,p)
5 7' =
6 y1-: z')/(s;2+y2)5 Fl(t,$),
F1, F2 correspond t o (2.8.4) and (2.8.5), respectively.
#
Notice t h a t ( z ( a ) , y ( a ) )
(0,O)
by t h e uniqueness of
i n i t i a l value problems and t h a t t h e r e e x i s t s no y ( t o ) = ( x ( t o ) , y ( t o ) ) = (0,O).
such t h a t
to
E
[a,b]
This implies
-
cp(t)
i s w e l l defined. From (H1),
(H2), and (2.8.6) and the theory of d i f f e r e n t i a l
inequalities, which i s applicable since continuous everywhere except a t
Fl(t,%),F2(t,5)
0 = nn/2, n = 0, 51,2 2 ,
are
...,
we obtain, using exactly t h e same methods as i n the proof of that either
"heorem 2.7.1, f3
+
krr < F(b) < p
+
(k+ l)a
if
cp(a) =
CY
+
( k + 2)n
if
q(a) =
CY
or
p
+
( k + 1)n < p ( b )
I n e i t h e r case
<
f3
x(b),y(b)
+ n.
cannot s a t i s f y
-
x(b) s i n p - y ( b ) cos p = 0 ,
unless ( z ( b ) , y ( b ) ) E 0,
a contradiction.
The existence of a
solution follows from t h e next corollary.
COROLLARY 2.8.1.
Assume t h a t t h e hypotheses of Theorem
2.8.1hold with t h e exception of the uniqueness of solutions Then there e x i s t s a solution of
of i n i t i a l value problems. the BVP (2.5.1) Proof:
(3) holds.
- (2.5.3).
I n view of Theorem 2.7.1, Let
x2 = y2
E
0
and
131
it s u f f i c e s t o show
x 1 = x, y1 = y.
Then we
2 . SHOOTING TYPE METHODS
o b t a i n from (2.8.6)
Letting
we see t h a t
G(t,x,y) = xg(t,O,O) -yf(t,O,O), G(t,x,y)/(x
lim
2 2 x +y + m
t
uniformly f o r
E
[a,b].
2
+y
2
1=
0
Thus (H ) holds and t h e proof of
3
Corollary 2 . 8 . 1 i s done.
A s before, our r e s u l t s immediately apply t o t h e more
g e n e r a l boundary conditions (2.7.16).
THEOREM 2.8.2. (Corollary 2.8.1)
Under t h e conditions of Theorem 2.8.1 t h e BVP (2.5.1),
(2.7.16)
has e x a c t l y one
s o l u t i o n ( a t l e a s t one s o l u t i o n ) . EXERCISE 2.8.1.
Prove Theorem 2.8.2.
We now apply our r e s u l t s t o t h e case i n which 2
C(l)[[a,b] xR ,R].
f,g E
I n o r d e r t o do so we must consider f i r s t
t h e case of l i n e a r systems; namely, t h e system x ' = all(t)x
(2.8.8) where
a
ij
E
+ a12(t)y,
C[[a,b],R].
(2.8.9)
e l ( t ) = a21 cos
8 = e(t)
Let
a s s o c i a t e d with (2.8.8).
Y ' = agl(t)x
a22(t)~,
be t h e p o l a r angle
Then 2
F3(t,e).
8
+ (a22 - a 11)
cos 0 s i n 8
Assume now t h e r e e x i s t two l i n e a r systems (2.8.10 )
+
z' = A(t)z,
z ' = A(t)z,
132
- a 12 s i n 2 8
2.8. UNIQUENESS
where
ma
Letting
Cp,
z t = x(t)z
JI be the angular functions associated with and
z7 = A(t)z,
V(t)
F3(t,cp)
respectively, we obtain, as i n
(2.8.91, (2.8.11) Since and
f
and g
and
J17(t) = F3(t,q).
a r e d i f f e r e n t i a b l e we have, f o r
(x2,Y2),
where
133
(xl,yl)
2 . SHOOTING TYPE METHODS
f o r a l l t E [a,bl and -m < x,y,u,v uniqueness statement i s true.
<
Then t h e following
+m.
COROLLARY 2.8.2. Assume i n (2.5.1) t h a t f , g E 2 C(l)[[a,b]xR ,R] and t h a t there e x i s t systems (2.8.10)
satisfying (2.8.14).
Assume a l s o t h a t t h e solutions
cp(t),
of (2.8.11) s a t i s f y (H1) and (H2), respectively.
Jr(t)
the B W (2.5.1), Proof:
(2.7.16) has exactly one solution.
Replacing
x
by
x2
+
s(yl-y2),
and integrating (2.8.14)
respect t o
s,
Hyptheses (H1),
Then
s(x1-x2)' from
0
y to
by
y2
1 with
we obtain
(%),
and (2.8.15)
imply t h a t t h e r e e x i s t s no In
n o n t r i v i a l solution of the BVP (2.8.8) and (2.7.16). (2.8.12) and (2.8.13) then (2.5.1)
where
+
let
x2 = y2 = 0
and
x1 = x, y1 = y;
reduces t o
6 ( t ) = f(t,O,O)
3
s3(t)/(x2+y2)
-10,
and
s 4 ( t ) = g(t,O,O).
s4(t)/(x2+y2)
134
-10
as
Hence x2
+
y2
-+ma
2.8. UNIQUENESS
Because of Theorem 2.7.1, (2.7.16)
t h i s assures us t h a t (2.8.16),
o r t h e equivalent problem (2.5.1),
(2.7.16)
has a
solution. Assume now t h a t t h e r e a r e two s o l u t i o n s (X1W,Yl(t)),
Z,(t)
z (t) =
1
= ( X 2 ( t 1 , Y 2 ( t ) ) of (2*5*1), ( 2 * 7 * 1 6 ) *
m e n x ( t ) = x,(t) - x 2 ( t ) , y ( t ) = y,(t) - y 2 ( t ) i s a s o l u t i o n As j u s t mentioned, t h e r e e x i s t s of (2.8.8), (2.5.2), (2.5.3). no n o n t r i v i a l s o l u t i o n of (2.8.8),
-
x(t) = y(t) complete.
(2.5.2),
(2.5.3).
Hence
"hus s o l u t i o n s a r e unique and t h e proof i s
0.
EXAMPLE 2.8.1.
We show t h a t t h e equation
x"(t)
+
6 sin x
+ h(t)
= 0
has a unique s o l u t i o n s a t i s f y i n g t h e boundary conditions .(a)
= x(b) = 0
if
I n Example 2.7.1 we have shown t h e r e e x i s t s a t least one solution.
We now apply Corollary 2.8.2 t o prove t h e r e exists
a t most one s o l u t i o n .
Observe t h a t t h e system x " ( t ) k 161x = 0
s a t i s f i e s (2.8.14)
with
.(a)
= x ( b ) = 0.
of t h i s problem a r e unique, if
according t o Corollary 2.8.2,
x(a)
= x(b) = 0
.
-
t h e equation with conditions
has a unique s o l u t i o n .
EXERCISE 2.8.2. XI'
(61<
We know t h a t s o l u t i o n s 2 Hence, T2/(b a)
+
Show t h a t t h e boundary value problem x ( a ) = x ( b ) = 0,
g ( t , x ) = 0,
has a unique s o l u t i o n i f E
5
gx(t,x)
5
2 /(b - a ) 2 )
(T
135
-
E,
E
> 0.
2 . SHOOTING TYPE METHODS
2.9
ESTIMATION O F
NUMBER OF SOLUTIONS
I n some cases, it i s of i n t e r e s t t o determine i f a BW has s e v e r a l s o l u t i o n s and t o estimate t h e number of t h e s e s o l u t i o n s . Before s t a t i n g our main r e s u l t we need some preliminary developments.
Assume t h a t t h e r e e x i s t two systems
(2.9.11
x ' = r(t,x,y),
Y ' = S(t,X,Y),
(2.9.2)
x'
Y ' = W(t,X,Y),
where
Let
8
r,s,v,w and JI
= V(t,X,Y),
E
C [(a,b] xR2,R]
and p o s i t i v e l y homogeneous.
be t h e p o l a r angles a s s o c i a t e d with (2.9.1) and
(2.9.2),
respectively.
Then
(2.9.3)
0 ' = s ( t , c o s @ , s i n 8 ) cos 8 - r ( t , c o s 0 , s i n 8 ) s i n 8
and (2.9.4)
$I
= w(t,cos + , s i n
$) cos $ - v ( t , c o s $ , s i n J I ) s i n 9.
We now assume conditions similar t o (H1) t h a t i s , assume t h a t :
( 5 )of
Theorem 2.7.1;
(HI) t h e maximal s o l u t i o n s & ( t ) and $;(-ti) of (2.9.4) 1 . s a t i s f y i n g $ ( a ) = a and *-(a) = a + 7r have t h e property M
JIL(b)
(H;) satisfying
M
< p + (a+l)n
and
t h e minimal s o l u t i o n s
+ 8 (a) = m
a
and
$&b) 0:(t)
@'(a) = a m
136
< B + (a+2)n;
and
+
T
0i(t)
of (2.9.3)
have t h e property
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
where
a r e continuous an d
Ej2
,ljt
B1 (t,x, Y 1
lim
x2+ y2 4 0
x
= o
and
lim 2 x +y24 0
+ Y
,X,Y 1
62 (t
2
x + Y
2
= 0.
We a r e now able t o estimate t h e number of solutions of the BVP (2.5.1)-
(2.5.3).
Assume t h a t conditions (H1) - (?), ( H i ) THEOREM 2.9.1. (5)a r e s a t i s f i e d . Then t h e BVP (2.5.1) - (2.5.3) has a t l e a s t 2 ( k- P, I nonzero solutions, whenever k # a .
Proof:
z(t,c) = (x(t,c),y(t,c))
Let
be any solution of
(2.5.1) s a t i s f y i n g t h e i n i t i a l conditions = c cos
.(a) and l e t
y(a) = c s i n
a,
(Y
be t h e angular function o f t h i s solution such
cp(t,c)
that
Assume now Theorem 2.7.1, an
rl
>0
c
>
Using the same pmof as t h a t of
0.
we conclude from (H1)
such t h a t f o r
p
+ kn<
c
2
cp(b,c)
0
such t h a t f o r
0
there e x i s t s
rl
Similarly, we obtain from (Hi)
r
- (3) that
< c -< r0
(k+l)n.
- (3) the
existence of an
ro < rl, we can apply Lemma 2.1.1, q(b,[ro,rl]) i s connected, The previous
Since we may assume and conclude t h a t
two i n e q u a l i t i e s on
cp(b,c)
then imply the existence of 137
2. SHOOTING TYPE METHODS
p o s i t i v e numbers
+
cp(b,c.) = p J
m
where
+
c
E
3
+
[ro,rl]
such t h a t
( j = m+l,m+2
jT
,...,m + ( k - J l ) ,
= min(k,J).
S i m i l a r l y t h e existence of negative numbers
c-
3
found f o r which cp(b,cT) = @ +
J
T +
jn
(j = m + l , m + 2
Hence t h e r e e x i s t s o l u t i o n s
+
z(t,cj)
,...,m +
and
2 ( k-
implying t h a t t h e r e a r e a t l e a s t
can be
Ik-Jl).
z(t,cT)
J
of t h e BVP
s o l u t i o n s , completing
t h e proof o f Theorem 2.9.1.
We now present conditions on system (Hj) a r e s a t i s f i e d . and s a t i s f y
Assume t h a t
f(t,O,O)
2.5.1)
so t h a t ( H i ) 2 ,R]
f , g E C'')[[a,blxR
g(t,O,O)
0.
Let
and consider t h e l i n e a r system (2.9- 5) The angular f'unction (2.9.6)
p(t)
then s a t i s f i e s
P ' ( t ) = gx(t,O,O) cos
x cos
p
2
IJ. + [gy(t,O,O) -fx(t,O,O)l
sin p - f
2
Y
(t,O,O) s i n
+
p.
+
% ( t ) = pm(t) = + pi(t) p - ( t ) where & ( t ) , p i ( t ) a r e , p ( t ) and G ( t ) Let r e s p e c t i v e l y , maximal and minimal s o l u t i o n s of (2.9.6). The s o l u t i o n s of (2.9.6) a r e unique and thus
us assume t h a t
138
-
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
a.
f o r some i n t e g e r Now l e t
cp(t,c)
be t h e angular function of any s o l u t i o n
z ( t , c ) = ( x ( t , c ) J y ( t J c ) ) of (2.5.1). x(t) c x(t,c),y(t)
E
we o b t a i n
y(t,c),
T ' ( t ) = gx(tJoJo) cos
2
Consequently, l e t t i n g
cp + ~ ~ y ~ t J o J o ) ~ f x ( t J o , O ) ~
2 x cos cp s i n cp-fy(t,OJ0) s i n cp
+
6(t),
where
Since
- gy(t,oJo)y(t)
[@;(tJxJy)-gx(tJo,o)x(t)
6(t)
g
fx(tJOJO)x(t)
- fy(tJO>O)y(t)1/(x2(t) + Y 2 ( t ) ) *
is differentiable,
6(t) + O
as
x
Hence (HI) i s s a t i s f i e d , i f we choose 6(t)(x2
+
y 2 )3 and
systems (2.9.1)
-f(t,xJy)
+
y2 - 0 .
Gl(t,x,y) Our comparison f
Gl(t,xJy).
b2(t,x,y)
2
and (2.9.2) a r e p r e c i s e l y system (2.9.5) and
the conditions (HI) and (H;) follows immediately from (2.9.7). 1 We thus deduce t h e following r e s u l t . COROLLARY 2.9.1.
f J g E C ( l ) [ [ a J b ] XSP,R] and s a t i s f y
f(t,O,O)
Assume t h a t (H1) J
where
sp
= g(t,O,O) = 0 .
- (H
) hold.
c (X,Y)3 IX2
y2
Let
5
P23 ,
If t h e s o l u t i o n s of
(2.9.6) s a t i s f y (2.9.7), then t h e r e exist a t least s o l u t i o n s of t h e BVP (2.5.1) (2.5.3).
-
21k- 41
It i s i n t e r e s t i n g t o f i n d conditions such t h a t t h e 2 I k - R 1 nonzero s o l u t i o n s .
boundary value problem has e x a c t l y
Clearly, t h i s w i l l always occur when monotonic i n
c,
both f o r
a s u f f i c i e n t condition f o r
c
>0
cp(t,c)
139
cp(t,c)
and
c
<
is strictly 0.
We now present
t o be s t r i c t l y monotonic.
2 . SHOOTING TYPE METHODS
Assume system (2.5.1) has the following
LENMA 2.9.1.
properties : 2 xg(t,X,Y) -Yf(t,x,Y) 2 0 , ( t , X , Y > E [a,bI xR 2 the paths of two d i f f e r e n t solutions z,(t) and
(a) (b)
z 2 ( t ) which s a t i s f y the conditions cp (a) = cp (a) = t a n 1 2
tan where and
-1
a
cp ( t )
1 z2(t), (c)
5
cp,(t),
and
-1 a,
cp,(t> 5
cp (b) = rp2(b) = t a n 1
B
tan-'
t
for
E
-1 p,
[a,bl,
cp2(t) a r e the angular functions of
zl(t)
respectively, do not i n t e r s e c t ; ( l / r ) [ g ( t , r cos cp,r s i n cp) cos cp
F(t,cp,r)
i s s t r i c t l y increasing i n
f ( t , r cos cp,r s i n cp) s i n cp] Then f o r each solution
z(t,c)
the angular function
i s s t r i c t l y increasing function i n
r.
cp(t,c)
c.
If the inequality i n (a) i s reversed and i f
s t r i c t l y decreasing, then EXERCISE 2.9.1.
Hint:
Let
cp(t,c)
Prove Lemma 2.9.1.
cpl(t,cl)
and
f o r two solutions
zl(t,cl)
and show
> cp;(a,c2).
t
E
cpi(a,c,)
(a,a+6)
if
F(t,cp,r) i s i s s t r i c t l y decreasing i n c.
6
cp2(t,c2)
and
be angular functions
z2(t,c2).
Assume
c1
>
c2
This inequality holds f o r
i s s u f f i c i e n t l y small.
Show t h a t the
(a,b] by using (b) and (c) and the theory of d i f f e r e n t i a l i n e q u a l i t i e s . inequality holds on
We have thus proved the following r e s u l t . COROLLARY 2.9.2.
Assume t h a t the conditions of Theorem
2.9.1 and Lemma 2.9.1 a r e s a t i s f i e d . 21k-
Then there e x i s t exactly
a ( nonzero solutions of the BVP (2.5.1)
140
- (2.5.3).
2.9. ESTIMATION OF NUMBER OF SOLUTIONS
Observe t h a t Corollary 2.9.2 remains v a l i d when i s s t r i c t l y decreasing i n
EXAMPLE 2.9.1.
cp(t,c)
c.
We o b t a i n an estimate, depending on
6,
of the number of s o l u t i o n s of t h e equation
+
X"
6 sin x
=
0,
s a t i s fying x ( 0 ) = 0,
x(1) = 0 .
W e apply Corollary 2.9.2 t o o b t a i n t h e r e s u l t . 2 Then system (2.9.5) becomes 161 < 7r
.
(2.9.8)
x ' = y,
Assume
y' = -&
with t h e boundary conditions x(1) = 0 .
x ( 0 ) = 0,
Since t h e r e e x i s t no nonzero s o l u t i o n s , it follows e a s i l y t h a t
a
= -1.
I n order t o find
k,
we observe t h a t t h e r e e x i s t s no
s o l u t i o n of x" = 0,
x ( 0 ) = 0,
x ( 1 ) = 0.
It follows e a s i l y t h a t k =-1. Thus f o r 161 <
2
7r
, we s e e (even
though k = a ) from Corollary 2.9.2 t h a t t h e r e e x i s t no n o n t r i v i a l 2 2 solution; hence t h e r e e x i s t s o n l y t h e t r i v i a l s o l u t i o n . If n T < I 61 < (n + 1)2T2, n = +1,+2, , t h e n an easy c a l c u l a t i o n y i e l d s
...
= n - 1. Hence t h e r e e x i s t s We l e a v e t h e case EXERCISE 2.9.2.
x"
+
2 [ ( n - 1)+1] 2n
1 61 = n2T2
solutions.
f o r t h e following exercise.
Determine t h e number of s o l u t i o n s of x(0) = 0 = x ( l ) ,
6 sin x = 0 ,
s a t i s fying
141
2 . SHOOTING TYPE METHODS
x ( 0 ) = x(1) = 0
when 2.10
161 =
n
2 2
T ,
,... .
n = 1,2
EXISTENCE OF IJYFINITE NUMBER OF SOLUTIONS I n Section 2.7,
we discussed t h e existence of s o l u t i o n s
of t h e BVP by showing
l i e s i n two s e c t o r s located on
z(b,c)
x s i n @ - y cos @ = 0
d i f f e r e n t s i d e s of t h e s t r a i g h t l i n e when
Ic I
i s sufficiently large.
It i s geometrically c l e a r t h a t t h e boundary value problem a l s o has a s o l u t i o n i f
z(b,c)
has a s p i r a l character when
c
tends t o i n f i n i t y . THEOREM 2.10.1.
Consider t h e BVP (2.5.1)
- (2.5.3).
Let
the inequality F(t,cp,r)
=
(l/r) [ g ( t , r cos cp,r s i n cp] cos cp f ( t , r cos cp,r s i n cp) s i n cp]
-
> E hold f o r
r
2
p0.
o > O
Suppose t h a t t h e
i n t o a f i n i t e number of s e c t o r s
such t h a t
-
t
E
[a,bl,
(t,cp), qj +
where
E
.
S1,. ,,Sm;
F(t,(P,r) =
lim r+ uniformly i n
xy plane can be divided
EL
cps ~
+a
P ~ + ~( j- = E
,...,n),
1
i s an a r b i t r a r i l y small constant.
Then
t h e BVP has an i n f i n i t e number o f s o l u t i o n s . Proof:
By Lemma 2.6.3,
there exists
142
co
>
0
such t h a t
2.10. EXISTENCE OF INFINITE NUMBER OF SOLUTIONS
z(t, c) function and a
p1
lo
1)
2
E
and t h e r e f o r e t h e angular
of t h i s s o l u t i o n i s w e l l defined.
cp(t,c)
Pick any
(2.
1 c 1 > co
does not vanish f o r
>
M > 0.
and choose
0
There e x i s t s
{'pj];=l
so t h a t
p0
2
F(t,cp,r)
r 2
holds f o r a l l
I5
,pl
I C P - CP.
M
where
-< t -< b,
a
M,
E.
J Define t h e discontinuous function H(CP) =
{
for
(61 5
c p = cp. -t 6 ,
J
E,
all o t h e r values of
cp.
\
We s e e immediately F(t,cP,r)
(2.10.2)
for
t
E
[a,b]
2
r
and
> H(V)
pl.
Consider t h e s o l u t i o n
$(t)
of +(a) = a-
+ ' ( t ) = H(+), Observe t h a t t h e time assume t h e value
ty
z =
Hence
$(b)
By Lemma
lcl
2
cp(t,c)
then
p2
is
2T
- $(a) 2 2nk,
z -10;
++a,
+
( ~ E / E ~n ) +
i n t e r v a l s of length M
z which i s required f o r $ ( t ) t o
where
k
i s t h e l a r g e s t number of
z contained i n
and thus $(b)
2.6.3,
(27r-2~n).
(l/M)
4 + m
there exists
Ilz(t,c)ll
[cp(a,c) = a, c
2
2
p,
E -0
As and
E
and
--3
0
M
-++a.
> 0 such t h a t when
Hence, t h e angular f'unction
pl.
of
p,]
[a,b]. as
satisfies t h e
z(t,c)
d i f f e r e n t i a l inequality lb(t,c)ll
CP'(t,c) = F ( t , T ( t , c ) ) ,
2
By t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s
t
E
[a,b].
Hence
cp(b,c)
4 + m
143
as
c
++m.
H(cP(t,c)). cp(t,c) _> $ ( t )
for
Also, i n a s i m i l a r
2 . SHOOTING TYPE METHODS
manner, we conclude
cp(b,c)
By Lema 2.6.2,
of
c,
as
++m
c
+-a.
t h e r e e x i s t s an i n f i n i t e number of values
both p o s i t i v e and negative f o r which cp(b,c) =
B
(mod
TI-).
Hence our BVP has an i n f i n i t e number of s o l u t i o n s .
The proof
i s complete.
EXAMPI8 2.10.1. x' where
gJ h
=
-h(y),
Consider t h e BVP y ' = g(x),
a r e continuous and odd.
= x(b) = 0
.(a) Assume
xg(x)
2,
2
Yh(Y) _> EoY2 and 1bx+,g(X)/X = +ooj limy+m h(y)/y = +a. To show t h a t t h i s problem has an i n f i n i t e number of s o l u t i o n s , we merely check t h e hypotheses o f Theorem 2.10.1.
We n o t i c e
inmediately
Consider t h e four segments
SiJ i = l J 2 , 3 , k J i n t h e
xy plane
defined by
where
E
i s any small constant less than a,b]xSi,
where
M(r)
T/4.
For
we have
has t h e property t h a t
144
g(x)/x
> M(r)
for
1x1
>r
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
and h(y)/y SO
that
> M(r)
M(r)
for
lyl
r
as
-++a
> r.
Since
M(r)
can be chosen
we see t h e hypotheses of
-++a,
Theorem 2.10.1 hold. EXERCISE 2.10.1. x"
Show t h e BW
+ x ( ~ + x ' ~ ) ~+ /h' ( t )
x(a) = x(b) = 0
= 0,
has an i n f i n i t e number of s o l u t i o n s . 2.11
NONLINEAR BOUNDARY CONDITIONS
Using techniques s i m i l a r t o those used i n Section 2.7, we i n v e s t i g a t e t h e existence of s o l u t i o n s of a two-dimensional d i f f e r e n t i a l system s a t i s f y i n g nonlinear boundary conditions. Results on t h e uniqueness and number of s o l u t i o n s may a l s o be deduced under conditions s i m i l a r t o those i n t h e previous s e c t i o n s , but we s h a l l omit them here. Before s t a t i n g our existence theorem c e r t a i n preliminaries need some mentioning.
I n p a r t i c u l a r , consider system (2.5.1).
Assume t h e r e e x i s t two functions, C(')[[a,b] W
such t h a t f o r each
xR2,R]
i s a l l of
W(t,x,y),V(t,x,y)
t
E
t h e range o f
V
and
and t h e s e t
R
(2.11.1) f o r a l l r e a l numbers (2.ll.2)
as
c1
and
c2;
IV(t,X,Y)l + IW(t,X,Y)l
llxll + llyll
--)a
uniformly f o r
The d e r i v a t i v e of V'(t,x,y)
=
av/at +
V
E
[a,bl.
along s o l u t i o n s of (2.5.1)
(t,x,y) +
av/+
t
-tm
av/:X
is
(t,x,y).f(t,x,y)
(t,x,y)*g(t,x,y)-
A s i m i l a r expression holds f o r Let
x(t)
and
y(t)
W'(t,x,y). be any s o l u t i o n of (2.5.1). 145
Now
2 , SHOOTING TYPE METHODS
T(t)
consider t h e angular function defined i n t h e
where V
VW
Fi,Gi
E
W;
and
and
(2.11.4)
plane.
Gi(t,V,W)/(IV(
uniformly f o r
t
E
p(t)
!%us
C [[a,bl XR2,R] Gi(t,V,W)
and polar radius
E
are p o s i t i v e l y homogeneous i n 2 such t h a t C[[a,b] xR ,R]
+ IW() - + 0
( V ( + (WI
as
[a,b].
Define
146
-> 0,
if
V
if
V < 0,
if
W
-> 0,
if
W
< 0,
if
V
-> 0,
if
V
<
0,
-+m
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
Ql(t,V,W) =
Fl(t,V,W)
if W
-> 0,
F2(t,V,W)
if
W
< 0.
where
v_>o, w_>oJ v10,
w
v
w10,
v
t h e comparison systems a r e
(2.11.6)
A' = &l(t,A,B),
B' = &2(t,A,B),
(2.11.7)
s'
T'
= Pl(t,S,T),
= P2(tJS,T).
As before we see t h a t systems (2.11.6)
have d i s c o n t i n u i t i e s along t h e l i n e s well as
S = 0, T = 0.
A = 0
and (2.11.7)
and
B = 0
may
as
Assume t h a t a l l s o l u t i o n s of (2.ll.6)
and (2.11.7) e x i s t on [a,b] and are continuously d i f f e r e n t i a b l e everywhere except a t t h e previously mentioned l i n e s . Observe that
P1,
P2,
%, %
a r e p o s i t i v e l y homogeneous i n t h e i r last 147
2. SHOOTING TYPE METHODS
two v a r i a b l e s . 0(t)
Let
and
ing t o (2.11.6) B(t)/A(t),
+(t)
be t h e angular functions correspond-
and (2.11.7),
where
B(t)
respectively.
Since
tan e ( t ) =
are s o l u t i o n s of (2.U.6),
and A ( t )
we have @ ' ( t ) = Q2(t,cos 8 , s i n 0 ) cos 8
(2.11.8)
-
%(t,cos @,sin e ) s i n
e.
S i m i l a r l y,
+
+ ' ( t ) = P2(t,cos + , s i n +) cos
(2.11.9)
-
Pl(t,cos
+ , s i n +) s i n
+.
Consider t h e BVP (2.11.10)
x' = f(t,x,y),
y ' = g(t,x,y),
with t h e boundary conditions V(a,x(a),y(a)) s i n a - w ( a , x ( a ) , y ( a ) ) cos
(2.11.11) where
0
CY
= 0,
V(b,x(b),y(b)) s i n B - W ( b , x ( b ) , ~ ( b ) ) cos B = 0 ,
-< CY < T
and
0
We now assume e s s e n t i a l l y t h e same hypotheses (H1)-
as i n Section 2.7.1.
Since t h e n o t a t i o n i s t h e same we w i l l
not repeat t h e d e f i n i t i o n s .
Therefore, assume t h e following:
( G ~ ) The maximal s o l u t i o n s
++ ( a )
(2.11.9) such t h a t +;(b)
<
f3
f o r some i n t e g e r (G2) such t h a t
M
+
=
(k+l)n
m
+L(t)
CY, +'(a) M and
= a
+i(b)
of
and
+
Tr
satisfy
< p + (k+2)i'f
k;
The minimal s o l u t i o n s
+ 8 (a)
(3)
=
a, @'(a) m
=
a +
148
ei(t) T
and
satisfy
@:(t)
of (2.11.8)
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
0i(b)
>p +
(k+l)T
f o r the same integer
and
>@ +
e:(b)
kT
k as i n (G1).
We a r e now able t o s t a t e our main existence r e s u l t .
Since
the proof i s similar t o t h a t of Theorem 2.7.1 we leave it as an exercise. For any
'MEOFEM 2.11.1.
- (2.11.3)
ing (2.11.1) (2.11.10),
(2.11.11)
R~
and W(t,x,y)
satisf'y-
t h e r e e x i s t s a solution of t h e BVP provided (G1) and ( G g ) hold. Prove Theorem 2.11.1.
EXERCISE 2.11.1.
Hint:
V(t,x,y)
For any
c
let
(x(a,c),y(a,c))
be a point i n
satisfying V(a,x(a,c),y(a,c)) = c cos a, W(a,x(a,c),y(a,c)) = c s i n CY. Letting
through cp(t,c)
(x(t,c),y(t,c))
(x(a,c),y(a,c)),
be any solution of (2.11.10)
we obtain the angular flmction
where t a n q ( t , c ) = ~(t,x(t,c),~(t,c))/~(t,x(t,c),~(t,c))
Proceed now as i n the proof of !theorem 2.7.1 and obtain f o r s u f f i c i e n t l y large
N
the two points
and
l i e on d i f f e r e n t s i d e s of t h e s t r a i g h t l i n e V s i n p - W cos B = 0
149
2 . SHOOTING TYPE METHODS
VW
i n the
plane.
Show then t h a t t h e r e e x i s t s a s e t V(a,S) = [-N,N].
S
C
R2
such t h a t
Thus t h e s e t
i s connected i n
R
2
.
The r e s u l t then follows.
L e t t h e hypotheses of Theorem 2.11.1
COROLLARY 2.11.1.
Then t h e r e e x i s t s a s o l u t i o n of (2.11.10) s a t i s f y i n g the
hold.
boundary conditions RIV(a,x($),y(a))
+ R2W(a,x(a),y(a)) = clY
R3V(b,x(b),y(b)) + R&W(b,x(b),y(b)) = c2, f o r any r e a l numbers
Ri,
i = 1,2,3,4
and
c., i 1
= 1,2.
Under t h e conditions of Theorem 2.11.1 and Corollary 2.11.1,
we n o t i c e t h a t when s o l u t i o n s of systems (2.11.8)
(2.11.9)
and
a r e uniquely determined by i n i t i a l conditions, then
and (G2) t o g e t h e r a r e equivalent t o t h e fact t h a t t h e r e
(G1)
e x i s t no s o l u t i o n s of (2.11.6)
and (2.11.7)
satisfying the
boundary conditions (2.11.11).
EXAMPLF 2.11.1. x’
(2.11.12)
=
2
x where
f,g
lf(Y)l
E
Consider t h e boundary value problem
x
(8)
+
f(y),
-Y(a) =
y ’ = 2y C1’
+o
Define
x,
w= 150
g(x);
x ( b ) = C2’
C[
v=
+
2
x -y.
2.1 1 . NONLINEAR BOUNDARY CONDITIONS
We a r e thus i n t e r e s t e d i n finding s o l u t i o n s of (2.11.12) s a t i s f y ing
V(b)
w(a) = c 1'
V
Observe t h a t curves
and k2.
V = kl
and W
and W
c
=
2'
s a t i s f y (2.11.1) intersect i n
= k2
since t h e l e v e l
R2 f o r every kl
It i s not d i f f i c u l t t o v e r i f y (2.11.2). V'
=
x'
=
x
+
W' = 2 x x ' - y '
f(y) = 2 2x
=
= 2y
v+ +
Now
f(y),
2xf(y)-*-g(x)
- 2w + 2xf(y) - 2y - g ( x ) +
= -2w
- g(x).
2xf(y)
F = F = V , 6 = 6 = f ( y ) , G = G = -2w, and 1 2 1 3 1 2 S~ = 62 = 2 x f ( y ) - g ( x ) . Since 1 2 x f ( y ) - g ( x ) I / ( 1 x 2 - y ~ + I ~ I ) - ~ o as 1x2-yl + 1x1 -+a, we see t h a t (2.11.4) holds. Systems Let
(2.11.6)
and p2 (2.11.9)
and. (2.ll.7) are then t h e same, with
=%
I
-2w.
P1
=
Ql
Because t h e s o l u t i o n s of (2.11.8)
=V and
a r e uniquely determined by i n i t i a l conditions due t o
the l i n e a r i t y of
Pi
%,
and
it i s s u f f i c i e n t t o
i = 1,2,
show t h e r e e x i s t no s o l u t i o n s of
v,
V' =
W ' = -2w,
satisfying W(a) = 0,
V(b) = 0 ;
t h a t t h i s i s t r u e i s c l e a r f o r any
a
and b.
Show t h e r e e x i s t s a s o l u t i o n of t h e BVP
EXERCISE 2.11.2. XI
=
x
+
2y s i n
y ' = (y/2) y ( a ) = cl,
+
2
x,
2 s i n x;
2 x ( b ) - Y (b) = c2.
151
2. SHOOTING TYPE METHODS
EXERCISE 2.11.3. 2.8 and 2.11,
Keeping i n mind t h e r e s u l t s o f Sections
s t a t e and prove a uniqueness theorem f o r a BVP
with nonlinear boundary conditions. 2.12
NOTES AND COMMENTS Example 2.1.1 i s
Theorem 2.1.1 i s due t o Hartman [41. taken from Lasota and Opial [81. Lasota and Opial [7] and Jackson
For Corollary 2.1.1,
[el.
r e s u l t o f Lees [l] while Exercise 2.1.2 2.1.3 may be found i n Jackson [2].
see
Exercise 2.1.1 i s a
i s of Levin [l]. Exercise
Theorem 2.2.1 i s due t o
Hartman [41.
Exercise 2.2.1 i s a c l a s s i c a l r e s u l t of De La Vallge
Poussin [ I ] .
meorem 2.2.2
i s due t o Tutaj [ l l .
i s taken from Keller [l] and Exercise 2.2.4
Corollary 2.2.2
i s based on Heidel
[l]. Section 2.3 i s adapted from Schrader and Waltman [4], while Section 2.4 is t h e work of Waltman [3]. For r e l a t e d discussion on uniqueness questions, see Bailey e t a l . [3], Shampine [ l ] and Sherman [ l ] . The contents o f Sections 2.5
- 2.10
a r e based on t h e work
of Perov [ l ] and Krasnoselskii e t a l . [2]. on existence and uniqueness
, s e e Waltman
due t o Bernfeld and Lakshmikanthan [2].
152
For r e l a t e d r e s u l t s
[3 1.
Section 2. ll i s
Chapter 3 TOPOLOGICAL METHODS
3.0
INTRODUCTION
I n t h i s chapter, various t o p o l o g i c a l p r i n c i p l e s a r e u t i l i z e d i n solving boundary value problems.
For example, t h e
Wazewski's t o p o l o g i c a l method t o g e t h e r with t h e connectedness properties of s o l u t i o n funnels i s used t o prove t h e existence of s o l u t i o n s .
I n t h i s s e t up, t h e boundary conditions consist
of s e t s which, i n p a r t i c u l a r cases, can be constructed from the knowledge o f upper and lower s o l u t i o n s and Nagumo's condition. We a l s o develop t h e Wazewski-like method f o r boundary value problems associated with contingent equations and s e t valued d i f f e r e n t i a l equations.
F i n a l l y , t h e continuous dependence of
solutions on boundary d a t a i s discussed.
3.1 SOLUTION FUNNELS We s h a l l consider t h e existence of s o l u t i o n s of boundary value problems a s s o c i a t e d with t h e two-dimensional system
153
3. TOPOLOGICAL METHODS
Let
f(t,x,y)
and g ( t , x , y )
be continuous i n a s e t
E
which
i s open r e l a t i v e t o
Q(to) where Q(to) I 7 R C E. tl,t2 2 0 and l e t S be a subset of C(tl). Denote by IE(S,tlJt2), the s e t of a l l points (x,Y) such t h a t there Let
is a solution
(x(t),y(t))
of (3.1.1) on
[tl,t2]
i n which
( x ( t l ) , Y ( t l ) ) E S, (x(t,),Y(t,)) = (%Y> and ( t , x ( t ) , Y ( t ) ) E E This s e t , as we have seen i s called the f o r a l l t E [t,,t2].
t = t 2' Before s t a t i n g our main r e s u l t s , we s h a l l need the following hypotheses w h i c h r e s t r i c t the behavior of solutions as they
solution funnel cross section a t
cross the
cp
and
surfaces.
$
We s h a l l always assume:
'
(Hi) f o r a n t i E [OJtoIJ (Xl'Y1) I ~ ( S l J 0 , t l ) sq(t1) implies t h a t there e x i s t s a solution of (3.1.1) emanating from w i t h a trajectory which i s on or above the $-surface (tlJxl,yl)
on some right neighborhood of
t
1'
(H2) f o r a l l tl E [O,tOl, (xl,Y1) E IE(Sl~O,tl) n)lt(,,.s , implies t h a t there e x i s t s a solution of ( 3 . 1 . 1 ) which emanates w i t h a trajectory which is on or below the from (tl,xlJy1) cp-surface on some right neighborhood of tl.
Our f i r s t r e s u l t describes qualitatively the behavior of solutions
of (3.1.1) assuming (H1) and (H2) hold. THEOREM 3.1.1. C(0)
Let
which intersects (i)
S1 be a compact connected s e t i n S+(O)
and
Sp(0).
Then e i t h e r
IE(SIJO>t) contains a compact connected component
C(t) which intersects both S ( t ) and S ( t ) f o r a l l Jr cp t E [OJto], or ( i i ) there i s a solution of (3.1.1) w i t h (x(O),y(O)) E S1 having a maximal right i n t e r v a l of [O,t+] C [O,tO] such t h a t in
154
3.1. SOLUTION FUNNELS
E: (p(t,y) - 1 < x < Jr(t,y) + 11. Assume t h e r e i s no number K such t h a t f o r a l l t E [O,tO], Proof:
Let
E'
(x,y) E IEl(Sl,O,t)
i s some i n t e r v a l
[(t,x,y)
implies [O,t+]
> K for t
C
(xn,yn) E IEl(Sl,O,tn).
lynl
+a.
IyI
5
K.
Then t h e r e
Ixn I + m,
1x1
>K
or
tn + t Ixnl + m o r
Then, e i t h e r +(t,y)
and
-k
and
it
(P(t,y),
Iyn I -+ m.
then
>0
K
Pick any sequence
By t h e continuity o f
case we have
and
such t h a t e i t h e r
let
follows t h a t i f
-< K
1x1
+ + [ t - &,t).
E
E
[O,tO] such t h a t f o r any
&(K) > 0
there e x i s t s an IyI
E
Hence i n e i t h e r
lynl + m.
By a standard diagonalization process, using t h e s o l u t i o n s
{ (xn,yn)},
associated with
of (3.1.1) with
(x(t),y(t)) on
[O,t]
[O,t+)
C
Moreover,
we may construct a s o l u t i o n which e x i s t s
(x(O),y(O)) E S1
and such t h a t
ly(t)l
+.
t +t
as
+m
This i s case ( i i ) .
( t , x ( t ) , y ( t ) ) E E' c E.
Hence, t o complete t h e proof we may assume t h e r e e x i s t s a
K
number implies
>
1x1
Let
such t h a t f o r a l l
0
-< K
t
T be the s e t of a l l p o i n t s the set 0 E T
[O,tO] such t h a t ,
E
IEl(Sl,O,t)
C ( t ) which i n t e r s e c t s both
i s nonempty s i n c e
contains a component
S J l ( t ) and
Sq(t).
Then
T
to. We
and i s bounded above by
i s closed and thus i f we l e t
s h a l l show T
(x,y) E I E l ( S l , O , t )
E (O,tO],
J y J5 K.
and
f o r a l l t E [O,T], in
t
s = sup T,
then
s = to implies t h e conclusion of Theorem 3.1.1. Let
be a sequence of p i n t s i n
{s.}
s with Ci
1
C
C(si)
S (si)
intersects both
l i m i t set of
a component of
{Ci}
Jr
and
and l e t
Then there e x i s t s a sequence where
(x;,yf)
E
C;
and
I E (S l
Let
S (s.).
' p 1 (a,b) E
L
E(x;,y;)I
converging t o
T
1'
0 si)
L
since
'
which
denote t h e L
i s nonempty.
converging t o
i s a subsequence of
{C;]
155
(a,b)
{Ci}.
3. TOPOLOGICAL METHODS
Let
be the s e t o f l i m i t points of
L'
compact and since for a l l If
intersects both
C;
then
i
{C;};
hence
S (s!) c p 1
and
is
L'
S (s;) Jr
L' intersects both S (s) and S (s).
cp Jr contains no component which intersects both
L'
S (s) and ST("), then since L1 is compact and intersects Jr both S (s) and S (s), L' i s the union of two nonempty cp compact s e t s
that
A
n L'
Assume {C!].
There e x i s t s a point
s; +s,
C
in
C(s)
closed.
a subsequence of
c (x;,~;)]
t o be the subsequence of
Thus
(p,q)
(p,q)
(p,q) E L 1 and
and we conclude
and
For i s u f f i c i e n t l y large the connected i n t e r s e c t s A and l e t (pi,qi) be the
C;.
IE,(Ci,si,s)
then
be any point i n N
(z',?') E C i ,
where
points of intersection. and since
(c,d)
Let
E M.
+ (c,d),
contained i n
such
= cp.
Choose { (x;,yy)]
1
set
J,
and N which are separated by an arc A
(a,b)
(?',Ti)
let
M
(pi,qi)
E
n S.
IEl(C;,s;,s)
which i s a l i m i t point of
i s a limit point of
(p,q) E A fl LI.
{C;].
{(pi,qi)] However,
This i s a contradiction
IEl(Sl,O,s) contains a component intersecting both S (s) and S (s). Thus T i s cp JI L'
and thus
By assumptions (H1)
and (H2) there e x i s t s a
6>0
such
that
and
IEl(C,s,t)
contains a component which ir,tersects both
S (t)
and S ( t ) f o r a l l t E ( s , s + 6 ) . However, t h i s JI cp contradicts the f a c t t h a t s = sup T. Thus s = to and ( i )
i s proven.
This concludes the proof of Theorem 3 . 1 . 1 .
Theorem 3.1.1 w i t h conditions t h a t r e s t r i c t the possibility of ( i i ) occurring can be used t o deduce existence theorems. have seen i n Chapter 1t h a t one such condition is Nagumo's condition.
The following condition w i l l thus be imposed:
156
We
3.1. SOLUTION FUNNELS
(H3) Given any number N(tO,n)
n
>0
and
to > 0 t h e r e e x i s t s a
such t h a t f o r any s o l u t i o n ( x ( t ) , y ( t ) )
(3.1.1) with
ly(O)[ < n and ( t , x ( t ) , y ( t ) ) E F, f o r l y ( t ) l < N(tOJn) f o r a l l t E [O,tO).
we have
of
t
[O,tO)
E
We now p r e s e n t an existence theorem. Assume conditions (H1)- (H ) hold.
THEOREM 3.1.2.
S1 be a compact connected s e t i n Sq(0)
and
C(to)
such t h a t
S (0). cp
Let
(x(t),y(t))
t h a t ( x(O),Y(O) )’ E S1’ for a l l t E [O,tOl. Proof: (x,y)
and l e t
S1,
E
s1
Since
l y ( t ) l < N(tO,n) (x(O),y(O)) E S1 IE(SIJO,tO)
which i n t e r s e c t s both
be a closed connected subset of
S2
S2 f l [(x,y): y
e x i s t s a s o l u t i o n of
C(0)
# $,
arbitrary]
of (3.1.1) on
( x(to)tY(t0))
E
then t h e r e [O,to]
n = sup (yI f o r
5 ).
N = N(tO,n) be a s i n (
f o r ally ( x ( t ) J y ( t ) )
Of
C ( t o ) which i n t e r s e c t s both S2
Then
(3.1.1) with
t E [OJtO]. By Theorem 3.1.1,
contains a compact connected component
conditions imposed on
such
S2 with ( t , x ( t ) , ~ ( t ) )E E
i s a compact s e t , l e t
and a l l
Let
3
S (t ) $ 0
and
insure t h a t
S2
S (t ).
cpo
n
C
The
IE(SIJO,tO)
in
# 9.
This concludes t h e proof of t h e theorem. Another approach t o t h i s problem i s t h e a p p l i c a t i o n of t h e Wazewski’s method.
We s h a l l introduce t h i s method here.
Consider t h e d i f f e r e n t i a l system (3.1.2) where
f
X’
E
= f(tJx),
n C[nJR 3, R
be an open set of closure of
x ( t 0 ) = xo
2
J
being any open set i n
OJ
Rn+l.
Let
n, anoJ t h e boundary, and E0 t h e
Ro
no.
DEFINITION 3.1.1.
A point
157
( t O J x O )E
fi
n ano
is said
3 . TOPOLOGICAL METHODS
t o be an egress point of
with respect t o t h e system
Ro
(3.1.2) i f , f o r every solution E
>0
such t h a t
x(t)
of (3.1.2),
to- E 5 t < to. An egress
for
( t , x ( t ) ) E Ro
there i s an
no i s called a s t r i c t egress point of no, Tio f o r to < t 5 to + E f o r a small E > 0.
point
( t O , x O ) of
if ( t , x ( t ) ) Denote t h e s e t of a l l points of egress ( s t r i c t egress) as
S
(S") DEFIXITION 3.1.2. topological space and B
into A
such t h a t
A
If T:
C
~ ( p =) p
i s s a i d t o be a r e t r a c t i o n of a r e t r a c t i o n of
B
onto
B
are any two s e t s of a
is a continuous mapping from
B +A
f o r every
B onto
A, A
p E A,
then
T
When t h e r e exists
A.
i s called a r e t r a c t of
B.
The following theorem of Wazewski i s quite useful. THEOREM 3.1.3.
Let
f E C[R,Rn), R
Assume t h a t through every point of solution of (3.1.2).
Let
Ro
be a nonempty subset of
r e t r a c t of
S,
there passes a unique
be an open subset of
Qo U S
but not a r e t r a c t of
at least one point
$+l R.
Suppose
no are s t r i c t egress points.
t h a t a l l egress points of Z
R
open i n
such t h a t 2.
Z fl S
Let
is a
Then there e x i s t s
no such t h a t the solution ( t , x ( t ) ) of (3.1.2) remains i n no on i t s maximal i n t e r v a l (tO,xO) E Z fl
of existence t o the right of
to.
W e now apply Theorem 3.1.3 t o the BVP prescribed i n Theorem 3.1.2.
Although we assume uniqueness of solutions of (3.1.1)
t h i s i s not e s s e n t i a l a s a Wazewski-like theorem f o r nonuniqueness has been developed.
Let
R = [(t,x,y): t
2 03 -S2;
a r e l a t i v e l y open subset of the h a l f space
no = [(t,x,y): 0 5 t < tl,
then
[(t,x,y): t
2
is 01. Let R
q ( t ) < x < q ( t ) , IyI < m1 where now a r e independent of y. Let Z f S From 1' hypotheses (H1) and (%), it i s not d i f f i c u l t t o see t h a t S = S", $(t,y), q ( t , y )
158
3.1. SOLUTION FUNNELS
and
consists of t h e union of t h e s e t s
S
We see from t h e properties of
i s a r e t r a c t of
S.
i s not a r e t r a c t of
and t h e s e t
that
S1n S
S
of (3.1.1) such t h a t
solution ( x ( t ) , y ( t ) )
S2
n S i s not connected S1 n S 1 Hence from Theorem 3.1.2 there i s a
Since
S1.
S
( tl,x(tl),y(tl))
E
and such t h a t ( t , x ( t ) , y ( t ) ) remains i n no on i t s S1 n C(t,) r i g h t m a x i m a l i n t e r v a l of existence. This implies ( t 2 , x ( t 2 ) J
due t o (H ).
Hence t h e r e e x i s t s a solution s a t i s f y -
y ( t 2 ) ) E S2 3 ing t h e BVP prescribed i n Theorem 3.1.2.
We now can obtain under t h e same hypotheses the existence of a solution remaining i n THEOREM
3.1.2, that
n
&(to).
3.1.4. Under the same hypotheses as i n Theorem
t h e r e e x i s t s a solution ( x ( t ) , y ( t ) ) of (3.1.1) such (x(O),Y(O)) E S1' ( x ( t , ) , y ( t O ) )
n
~ ( t ) E) R
Hint: -
=E
6
S ~ Jand
(t,x(t>,
Q(t,).
EXERCISE 3.1.1.
E~
R
Prove Theorem 3.1.4.
Choose a sequence of open s e t s
n
~ R+ ~~ ( t ,I ),
E~ = E,
and
n,,
W
Show t h e r e e x i s t solutions which l i e i n
where E
En boundary conditions by applying Theorem 3.1.2.
n Q(t,). and s a t i s f y t h e
= R
Then apply
Ascoli's theorem t o obtain t h e desired solution. We can now prove a r e s u l t f o r a semiinfinite BVP.
THEOREM 3.1.5.
Let
f , g E C [ [ O , ~ ) ~ R * , Rand ] assume 159
3. TOPOLOGICAL METHODS
-
kt
(H1) (H3) hold. intersecting both solution
S1 be a compact connected s e t i n C(0)
(x(t),y(t))
and ( t , x ( t ) , y ( t ) )
E
Sq(0).
e x i s t i n g on
R
n
Then (3.1.1) has a with
[O,m)
2
Q(to)for a l l t
(x(O),y(O)) cS1
0.
Prove Theorem 3.1.5.
EXERCISE 3.1.2.
Hint: -
and
S (0) $
Use Theorem 3.1.4 and a standard diagonalization
argument. 3.2
APPLICATION TO SECOND-ORDER E a T I O N S
In t h i s section we apply the r e s u l t s of Section 3.1 t o t h e case i n which
f(t,x,y) = y
i n (3.1.1).
That is, we consider
the equivalent second-order s c a l a r equation
(3s2O1)
XI1
= @;(t,X,X').
Recall t h a t a ftmction a ( t ) E C(2)[0,t
of (3.2.1)
if
(3.2.2)
a"(t) 2 g(t,(Y('(t),(Y'(t)),
bbreover,
(Y
- is >
1
t
i s a lower solution
E
[O,tOl.
becomes a s t r i c t lower solution if, i n (3.2.2),
replaced by
>.
Similarly a f'unction
i s an upper solution of (3.2.1) (3.2.3)
0
V(t)
5
B(t) E C(2)[0,to]
if
g(t,B(t),B'(t)),
t
E
[O,tOl-
If i n (3.2.3) 5 i s replaced by <, then B is a s t r i c t upper solution. We now present a general existence r e s u l t , Notice t h a t i n Chapter l o t h e r techniques have been used t o prove similar types of theorems. TI-IEOm 3.2.1. (i)
Assume t h a t :
there e x i s t s an upper solution
160
@ ( t )and a lower
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
solution a ( t ) E
of (3.2.1) with
-< B(t)
a(t)
be any open s e t containing the s e t
5x5
a(t)
S,
I
# gj
and such t h a t
with
I<
such t h a t
(x(to)Jx'(to)) E
n
with
2
y'
0
Let
5 t 5 to,
such t h a t ( x , x l ) E S1 fl S a ( 0 ) f o r some
B'(0)
be a closed connected subset of
S2
[ ( x , ~ ' ) : x'
x(t)
C(0)
' ( 0 ) f o r some
#9
Let
S2
e x i s t s a solution
Proof:
x' <~
S1 fl S (0) B
(y,y') E S1 fl Sg(0). C(to)
[(t,x,x'):
be a compact connected s e t i n
S1 fl S a ( 0 )
[O,tO].
(3) holds.
(ii) Let
Ix'
B(t)J
on
of (3.2.1)
arbitrary]
# 8.
such t h a t
(x(O),x'(O)) E S ~ ,
s2 with a ( t ) < x(t) < @ ( t ) On
We f i r s t prove t h e r e s u l t with
a(t)
Then there [Ojt0I. and
p(t)
assumed t o be s t r i c t lower and upper solutions, respectively.
(3) i s s a t i s f i e d the p o s s i b i l i t y of
Since
Theorem 3.1.1 i s eliminated. of
IE(Sl,O,t)
Let
Ct
C
which i n t e r s e c t s both
C(t)
Sa(t)
be a component and
P by
Define
P
I
B
< x1 -
(x,x') E S a ( t ) fl Ct such a l ( t ) and there e x i s t s ( y , y l ) E
ct n sB ( t ) t E [oJ51]* P
S (t).
[t;: there e x i s t s that
Notice
case ( i i ) i n
such t h a t
i s nonempty since
y'
0 E P.
-> B ' ( t )
Let
f o r a11
n = sup P.
It i s
s u f f i c i e n t t o show n = to. Exactly a s i n t h e proof of Theorem 3.1.1 it follows t h a t There e i t h e r e x i s t s
n
E
P.
We omit the d e t a i l s .
( x , x l ) E Cn fl Sa(n)
such t h a t
x = a ( n ) , x ' = a l ( n ) o r there e x i s t s
(y,y') E Cn fl S (n) B f o r i f not, then there e x i s t s y = p(n), y ' = @ ' ( n ) such t h a t nl E P. This i s impossible.
such t h a t
nl
>n
( y , y l ) E Cn fl SB (n) such The other case i s similar. I f
Consider then the case where that
y = p(n), y ' = p ' ( n ) .
161
3. TOPOLOGICAL METHODS
y ( t ) i s any solution of (3.2.1) w i t h y(n) = B(n), y ' ( n ) p'(n), then there e x i s t s an &l > 0 such that y ( t ) >
=
p ( t ) , y ' ( t ) > p f ( t ) on (n,n+E1). This follows since p ( t ) i s a strict upper solution on [O,tO]. Moreover, f o r any t > n, any solution y ( t ) of (3.2.1) w i t h y(T) = p(T), y ' ( z ) < PI(:) satisfies y(t) < p(t) for < t < % + S and y ( t ) > p ( t ) on 6 < t C t forsome 6>0. Eythecontinuityof g, it follows t h a t there e x i s t s an E~ > 0 and p l > 0 such t h a t p"(t) < g(t,y,y') for a l l t E [ n , n + ~ ~and l a l l ( y , y f ) such t h a t d((y,y'), ( p ( t ) , B ' ( t ) ) ) < pl, where d denotes t h e Euclidean metric. By standard arguments there e x i s t an &3 > 0 and p2 > 0 such t h a t any solution y ( t ) of (3.2.1) w i t h
z-
y(n) = YoJ y ' ( n ) = YA with d((YoJY~),(p(n),B'(n)))< p2 s a t i s f i e s d(y(t>,y'(t)),(p(t),p'(t))) < p1 f o r a l l t E [ n , n + ~ ~ ] . Moreover, B"(t) < y " ( t ) f o r a l l t E [ n , n + m i n [ ~ ~ , ~ ~ l . Finally, there e x i s t s an &4 > 0 such that f o r any solution
~i
where (Y1,Yi) €Cn ~ l ( t )of (3*2*1)w i t h y l ( n ) = ~ 1 y9i ( n ) = and a((Y,,Yi>,(B(n),B'(n))) < P1 both y,(t) _> B(t) and y i ( t ) 5 p ' ( t ) are not possible f o r any t E [ n , n + &4 1. If we l e t E = min[& , E ,& 1, then it follows from the 1 2 3'&4 preceding observations t h a t Ct n S p ( t ) # # and y' 2 p ' ( t ) f o r some (y,yl) E Ct fl S ( t ) f o r a l l t E [O,n+&]. A similar B argument leads t o the conclusion t h a t Ct n S 2 ( t ) # $ and x ' < a ' ( t ) f o r some (x,xt> E ct n SCY(t) f o r t E [o,n+El. Then nl = min[n+&, n + F ] E P and nl > n, a contradiction.
-
Thus n = to and we conclude that IE(Sl,O,tO) contains a compact connected component intersecting both SCy( t o ) and Sp(to). Hence S2 fl IE(SIJO,tO) # $ and hence there e x i s t s a solution x ( t )
of (3.2.1) w i t h (x(O),x'(O)) E S1, ( x ( t o ) , and ( t , x ( t ) , x ' ( t ) ) E E. Using the same type of x f ( t o ) E) S2, proof' as i n Theorem 3.1.4, we may conclude that a ( t ) 5 x ( t ) 5 p ( t ) f o r a l l t E [O,tal.
162
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
We now prove Theorem 3.2.1, B(t) 0
assuming t h a t
a(t)
a r e lower and upper solutions, respectively.
1, l e t
A (t) = a(t) - y
and
Y
and
For
+ y.
B ( t ) = B(t)
Y
Define
x >
g ( t , B ( t ) , x ' ) + x - B(t),
Q(t5 > x 5 B(t), x
g(t,a(t),x') + x-a(t),
< a(t).
Ix' I + 1 and l e t N be t h e number ( X J ' )fS1 associated with M i n ( ). Choose K = max(N, m a x Let
M = max
5
t Ero, t 0~ i
( l Q ' ( t ) l , I B ' ( t ) l > ) and define
I2K Ix' I 5 K
Ix' H(t,x,x') =
-
+
+ 2,
+ 1,
1< x '
(K+2 x ' ) G ( t , x , K + l ) ,
K
( K + 2 + x ' ) G ( t , x , - K - l),
-K- 2
<
X'
< K + 2, < - K - 1.
Eloreover A"(t) = ~ " ( t _>) g ( t , a ( t ) , ~ ' ( t ) > ) g ( t , a ( t ) , A;/(t)) - Y
Y
B"(t) = B"(t)
Y
Hence A
5
and
Y
g ( t , B(t), B ' ( t ) )
B
Y
X" =
(p,q)
(u,v)
E
union of
E
s n 1
S1,
S1
n
AY(t), A+(t)),
< g(t,
B(t), B+(t)) + y
= H(t,
By&), B;i(t))-
a r e s t r i c t lower and upper solutions of
(3.2.4) Let
= H(t,
H(t,x,x').
[ ( x , x ' ) : x = Q(o),
XI
2
B(0)l.
t h e l i n e segment from
(p,q)
[(y,yl): y = B(O),
t h e l i n e segment from
(u,v)
yi
to
and l e t
5 a'(0)1, Let
X
Y
be the
(p - ~ , q ) and
to
(u + y,v).
Consider now t h e BVP (3.2.4) with t h e boundary conditions (3.2.5)
(X(O),X'(O))
E
xY' 163
( x(t,>,x'
( t o >)
E
S2'
3 . TOPOLOGICAL METHODS
Let
E = [ ( t > X > X ' ) :O
Ix'I
<
Since
m1.
5 t 5 t O JQ ( t ) - 1 < X <
H(t,x,x') = 0
[ x ' I _> K
for
+
B(t)
+
1,
2,
we may
apply t h e proof of the f i r s t h a l f of t h i s theorem, r e c a l l i n g that
A (t), B ( t )
a r e s t r i c t lower and upper solutions Y Y respectively, t o conclude t h e existence of a solution Xy(t)
of t h e BVP (3.2.4),
< B ( t ) for - Y
X (t)
Y
for
2
Ix'I
K
+
2
(3.2.5) with t h e property t h a t A ( t ) < Y t E [O,tO]. Also, since H(t,x,x') = O i X r ( t ) [5 K
it follows t h a t
Y
+
2
on
By Kamke's convergence theorem a subsequence of converges t o a solution
Xo(t)
of (3.2.4) on
[O,tO].
n]i=l
{X
[O,tO]
11 such
that
( xo(l)Jxi)(l))
(xo(o)~xi)(o)) ' 1 ' Also A
a(t)
l/n
For
5
Xo(t)
(t) = a(t)
a(t)
g(t,x,x').
5
B(t),
- (l/n)
-< x -< B(t),
'2'
since
5 X l / n (t) 5
B(t) + ( l / n ) = Blln(t).
Ix'I < K + 1 we have
It follows, from
(?),
that
H(t,x,x') =
IXi)(t)[ < N
-< K.
Hence
s a t i s f i e s t h e BVP and t h i s concludes t h e proof of meorem Xo 3.2.1. It i s not necessary t o assume
t
and lower surface at which eventually hook
= 0
S1
i n t e r s e c t s t h e upper
provided t h e r e e x i s t solutions
S1 onto t h e lower and upper surfaces.
More precisely, we have t h e following r e s u l t .
THEOREM 3.2.2. a, B
Assume (H ) holds r e l a t i v e t o
3
E.
Let
B(t)
be lower and upper solutions f o r (3.2.1) with a ( t ) on [O,tO]. L e t S1 be a compact connected s e t i n
C(0)
and l e t
that
S2 fl [ ( x , x ' ) : x '
S2 be a closed connected subset of arbitrary]
#
@.
If
s1 such that
[(xl(u)Jxi(u))] 164
C(tO) such
(x,(t),xi(t))
and ( x 2 ( t ) , x h ( t ) ) a r e solutions of (3.2.1) with (x2(0)Jx6(0))
-<
( xl(0),xi(O)), s ~ ( u )# @
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
[(x,(V)Jx;(v))] n s 2 ( v ) # $ f o r some v E (OJt0IJ then t h e r e exists a s o l u t i o n x ( t ) of
f o r some
u
( o , ~ , I and
E
(3.2.1) with
< x(t) a(t) -
( x ( 0 ) J X ' ( 0 ) ) E S1j (X(t,),X' ( t o ) )
-< p ( t )
and
S2j
f o r a l l t E [OJtoI.
The proof i s similar t o t h a t o f Theorem 3.2.1
Proof: since
E
I (S , O , t )
E l Sp(t) for t
has a component i n t e r s e c t i n g
2 max[uJvl.
Sa(t)
and
I n Chapter 1, we have provided s u f f i c i e n t conditions f o r
(3) t o hold,
One such condition was Nagumo's condition.
We now o b t a i n a r e s u l t t o show how Nagumo's condition can be u t i l i z e d t o determine
S1 and S2.
lower and upper s o l u t i o n s of (3.2.1)
t
E
Let with
a(t)
and
a(t)
[ O J t O l . Define
A = max
I
Ia(0)
J
max
g(t,x,y)
J
Ia'(t)lJ
max lp'(t)l [OJt01
s a t i s f i e s Nagumo's condition lg(t>xJy)l
f o r a l l t E [,,to]'
-< B ( t )
IMO)- B(0) I
- B(to) I [OJt01
and assume
B ( t ) be
a(t)
5
(P(lYl)
-< x < B(t),
Letting
165
IyI
<
w
such t h a t
for
3. TOPOLOGICAL METHODS
we observe t h a t
THEOREM 3.2.3.
Assume
g(t,x,y)
s a t i s f i e s Nagumo's
a(t),B(t) E C(2)[0,to] with a ( t ) 5 B ( t ) . If S1 is any closed connected subset of C ( 0 ) such t h a t S1 fl S # 0, S1 n S4 # 0 and i f S2 is any closed 3 connected subset of C(to) such t h a t S2 n S # jd and 5 S2 n S6 # I ,then there e x i s t s a solution x ( t ) of (3.2.1) such t h a t (x(O),x' ( 0 ) ) E S1, ( x ( t o ) , x l ( t o ) ) f: S2 with condition with respect t o
a ( t >,< x ( t > 5 B ( t ) * Proof:
Choose
n
(o,xl,xi)
G
s1 n s3
and
(o,x2,x;)
E
Sq such t h a t both p i n t s belong t o t h e same component S1 of S1 n [(O,X,Y): 5 N l . Choose (O,B(O),x) ) E Sp(0) as follows. If x1 = p(O), l e t = xi; i f x1 < B(O), S1
c
choose
IY)
5 > N.
Let
%
be t h e l i n e segment joining 166
(0,xl,xi)
3.2. APPLICATION TO SECOND-ORDER EQUATIONS
to
(O,p(O),x'), 3-
where, i n t h e case when
p(O), L1 = I n a similar manner, choose ( O , ~ ( O ) , X & c )
[ ( O , X ~ , X ; )c I sl. by l e t t i n g
xk = xh
Scy(0)
x2
>a(O)
and take
( O , X ~ , X ~t )o observe
x1
x2
if
= a(0)
or
=
xc
<
-N
if
t o be t h e l i n e segment joining
L2
(O,a(O),xi).
Let
ST
= L1 U
zl
and
U L2
ST i s compact, connected, and i n t e r s e c t s both
[(O,a(O),x'): x' 5 a ' ( O ) ] and {(O,p(O),x'): x' 2 p'(0)). Pick (t , x , x ' ) E S2 n s5 and (tO>X6'Xi) E s2 n s6
-
0 5 5
such t h a t both points belong t o t h e same component S2 S2
n
[(tO,X,X'):
l i n e s given by and l e t
s;
= L
5
5 N(tO)]. Let [(t0,x5,y): y 2 x;l IX'I
u 8, u L6.
Consider the BVP (3.2.1) (3.2.6)
(O,X(O),X'(O)) E
L5
and
of and L6 be t h e half [(to,x6,Y): y
and
( t0,x(to),x'(t0))
,s;
E
5 xi1
*
S2'
By the construction of
ST and t h e assumptions on g(t,x,y), there e x i s t s a compact, connected subset C C C(to) of the funnel cross section F(tO,O,ST) = i n t e r s e c t s both
uses++ F(tO,O,s)
which
1
S p ( t o ) : y 2 p t ( t o ) ] and Hence, by Theorem 3.2.1 the al(t,)].
[(tO,x,y)
E
[(tO,x,y) E S2(t0): y 5 BVP (3.2.l), (3.2.6) has a solution
x ( t ) with
a(t)
-< x ( t ) -<
B b ) , I x ' ( t O ) l 5 N(tO) and ( t O , x ( t O ) , x ' ( t O ) E) S2* From Nagumo's condition Ix'(0)I 5 N and by t h e construction of Sr, (O,x(O),x'(O)) E S1. This concludes the proof of Theorem 3.2.3. EXA.MFTE 3.2.1.
A s an application of t h i s r e s u l t consider
the following BVP a r i s i n g i n the dynamics of c e r t a i n chemical reactions. (3.2.7) (3.2.8)
X" = -LIX'
x(0) = 0,
- L2k(x),
x ' ( 1 ) = -L1X(l).
167
3 . TOPOLOGICAL METHODS
The positive constants
and
L1
of t h e physical problem with on
[O,c]
such t h a t
k(x)
L2
k(x)
>0
for
depend on various parameters continuous and nonincreasing 0
<x
and
k ( c ) = 0.
Theorem 3.2.3 gives t h e existence of a solution x ( t ) of t h e BVP (3.2.7), (3.2.8) with 0 < x(t) < c since m(t) = 0 and @ ( t )= c are lower and upper solutions, respectively, and Nagumo's condition i s c l e a r l y s a t i s f i e d .
3.3 WAZEWSKI RETRACT METHOD "his section i s devoted t o an application of t h e Wazewski r e t r a c t method t o (3.2.1) with boundary conditions
- blxl(0),
(3.3.1)
L1(x) = rl,
L1(x)
= alx(0)
(3.3.2)
L2(x) = r2,
L2(x)
= a2x(to) +
b2x1(t0).
Without loss of generality, we may assume b ,b > 0. Let 1 2 m(t) and B(t) be lower and upper solutions of (3.2.1) such that (3.3.3)
~ ~ ( 50 ri, )
(3.3.4)
Li(B)
We s h a l l assume t h a t
g
2
ri,
i = 1,2, i = 1,2.
s a t i s f i e s Negumo's condition, t h a t is,
As an application of Theorem
1.4.1, we obtain t h e following
lemmas.
168
3.3. WAZEWSKI RETRACT METHOD
U M M A 3.3.1.
Assume t h a t
Then, f o r every
> 0,
c
t h e r e e x i s t s a constant
t h a t each s o l u t i o n x ( t )
t
E
I
satisfies Nagmots condition.
g
satisfying
a(t)
M(c)
-< x ( t ) 5
such
p(t)
for
[O,tO] and which s a t i s f i e s
C
Jx'(sol
5
c
for
some
s0 E I
a l s o has t h e property
Assume t h a t t h e r e e x i s t s a s t r i c t lower
LEMMA 3.3.2.
solution a ( t )
and s t r i c t upper s o l u t i o n
t o ( 3 . 2 . 1 ) J s a t i s e i n g (3.3.3), all t
E
(3.2.1)
(3.3.4)
p(t)
with
with respect
< p(t) for
a(t)
Then, t h e r e e x i s t s a s o l u t i o n x o ( t )
[O,tO].
defined on
[O,h+&] C [O,tO] f o r some h _> 0 ,
of &
> 0,
a(t) < xo(t) 5 p(t) for a l l x o ( t ) > p ( t ) f o r t E (h,h+E].
s a t i s f y i n g (3.3.1) and such t h a t
t E [O,h], xo(h) = @(h) and S i m i l a r l y t h e r e e x i s t s a s o l u t i o n z o ( t ) s a t i s f y i n g (3.3.1), e x i s t i n g on an i n t e r v a l [O,k+ 61 C [O,tO] f o r some k _> 0, 6
> 0,
such t h a t
zo(h) = a ( h ) Proof:
and
a(t)
xo(0) = @(O),
zo(t)].
t
for
for a l l t
We show t h e existence of
y i e l d s t h e existence of letting
-< Zo(t) -< @ ( t )
zo(t) < a ( t )
E
xo(t)
E [ O J ~ ] ,
[k,k+61.
[ a similar proof
#
F i r s t assume bl
we o b t a i n from (3.3.4)
that
0;
then,
xA(0)
>
Hence t h e r e s u l t holds f o r h = 0.
p'(0).
Let
bl
#
0
and consider a s o l u t i o n s ( t )
s a t i s f y i n g , f o r each i n t e g e r
n,
xn(o) = r a 11'
169
x;(o> = n.
of (3.2.1)
3. TOPOLOGICAL METHODS
> M(B),
For N
there e x i s t s
s
0
E
[O,tO) satisfying %(so) =
and a ( t ) c % ( t ) < B(t), t E (O,so). Assume not; then e i t h e r cy(t) < % ( t ) < @ ( t ) f o r a l l t E (O,tO) o r there B(so)
T < to such t h a t x,(Tn) = a(Tn), a ( t ) < x n ( t ) < n for t E (O,%). I n e i t h e r case, there e x i s t s a
exists a
B(t), tNE [O,tO] such t h a t lXrj(tN)I 5 B. [In the second case, we make use of the f a c t < a r ( t N ) , since cy(t) i s a s t r i c t lower solution. ]
s(5)
Lemma 3.3.1,
since xP;(O)
= N,
ls(t)l-<
f o r t E [O,tNl and we have a contradiction f o r N > M(B). M(B)
Thus f o r some h E [O,t,I,a(t) 5 B(t) for a l l t E [O,hl and %(h) = p(h). Since p ( t ) i s a s t r i c t upper solution, we have
> B'(h). Thus, there e x i s t s an E > 0 such t h a t % ( t ) > p(t), t E (h,h+&]. The proof i s complete. Xp;(h)
U M M A
3.3.3.
by a parameter
simultaneously.
x(t,p)
Let
Let
p.
x(t,p)
open exterior of
U Int
where
t
M
=
C
be continuous i n
t
and
Let C be a simple closed curve i n the
plane and denote by I n t C C
be a family of functions indexed
and x ( t , p )
(t,x)
and E k t C the open i n t e r i o r and
Suppose t h a t f o r each
C.
p
p, (O,x(O,p))
is defined on an i n t e r v a l
E
[O,TM]
( T ,x(Tp,p)) E Ext C. Define y(p) = t where CI CI sup[t > 0 : ( t , x ( t , p ) ) E I n t CI. Then y is bwer semi-
continuous.
If, i n addition, each M c t i o n
x(t,p)
has the
t
t + h ), P' CI l.l then y i s continuous. (Lemma 3.3.3 is another version of the Wazewski method.) additional property t h a t
THEOREM 3.3.1.
B(t)
(t,x(t,p))
E
Ext C
for
E
(t
Assume t h a t there e x i s t s an upper solution
-
and a lower solution a ( % ) of (3.2.1) with cy(t) < B(t)
Let f f o r a l l t E [O,tOl, s a t i s w i n g (3.3.3) and (3.3.4). satisfy Nagumo's condition with respect t o cy and B. Then there is a solution x ( t ) of t h e B" (3.2.l), (3.3.1), (3.3.2) 170
3.3. WAZEWSKI RETRACT METHOD
Proof:
We may assume t h a t (3.3.5)
since we may redefine
g
o u t s i d e of
holds f o r a l l x D
E
R
so t h a t t h e Nagwno’s
condition w i l l hold. that g
We f i r s t prove Theorem 3.3.1 under t h e stronger hypotheses w ( t ) and B(t) a r e s t r i c t lower and upper s o l u t i o n s and
i s l o c a l l y Lipschitzian.
We w i l l then show how these
hypotheses may be weakened. Consider the s e t of s o l u t i o n s of (3.2.1) and (3.3.1) such that a ( 0 ) < x(0) < p(0). These s o l u t i o n s form a one-parameter family of functions a r e connected.
{x(t,p)],
where t h e s e t of values of
Define a map cp:
P
--f
( t p , x ( t p , PI),
t i s defined i n Lemma 3.3.3 i n which C P Jordan curve forming t h e boundary of t h e region x ( t , p) i s continuous i n both t and p since Lipschitz and thus applying Lemma 3.3.3 we have continuous. Thus cp i s continuous and {rp(p)} Combining Lemma 3.3.2 w i t h t h e connectedness of have the existence of v1 and p2, such t h a t
is the
where
Since
CY
and
p
0
are strict solutions
171
D.
g
Now i s locally
y: p -+ t is CL i s connected. {cp(p)}, we
3. TOPOLOGICAL METHODS
The solution x ( t , p o )
i s a solution of BVP (3.2.l),
(3.3.2). We no longer assume From (3.3.6),
g
(3.3.1),
s a t i s f i e s a Lipschitz condition.
there e x i s t s an
>0
E~
such t h a t i f
<
0
E
<
then
There e x i s t s a sequence of l o c a l l y Lipschitzian functions
E gn ( t , x, Y 1Inzl M
2 [O,tO]X R
.
Ign(t,x,y) Pick N
which converge t o
g(t,x,y)
Assume t h a t
- g(t,x,y) I 5
1/n
so large such t h a t
for 1/N
5
n
> N, a
(t,x,y)
[0,t0I X R
2
and
E~
1/< ~ inf[Iatt - g ( t , a , a l ~ ,
Thus, f o r
uniformly on
IB"
-g(t,~,~f)Il,
p w i l l be s t r i c t lower and s t r i c t
and
upper solutions for (3.3.7)
XI'
= gn(t,x,x'),
where Ign(t,x,y)
I 5 h ( IY I )
+
(l/n)*
By o u r previous analysis, t h e r e e x i s t s a function s ( t ) s a t i s f y i n g (3.3.7), (3.3.1), and (3.3.2). From t h e mean value theorem, there e x i s t s a such t h a t
Ix'(T)I
5
K/to
Choose M = M(K)
= K1.
so large t h a t
SMiqq K1
Then, t h e r e e x i s t s
N1,
sds
'K*
such t h a t f o r 172
n
> N1
T
E
[O,tO]
E ~ ,
3.3. WAZEWSKI RETRACT METHOD
s
s ds + (l/nl
h(s) K1
As i n the proof of Theorem 1.4.1,
> K.
we have f o r
t
Ix;(t)l
IM(K)
for
all
Ixn(t)I
IK
for
all t
n
> N1j
E [OJtO].
Since E
[OJtO]J
it follows t h a t Ixi(t)
I I max[lg(tJxJy)I 1x1
Therefore t h e sequence
5 K,
[O,to],
+ 1:
I MI. for n > max(N,N1)
IYI
{xn(t)?,
subsequence which converges i n t h e
C(l)
function i s then a solution of (3.2.1)
norm.
has a
The l i m i t
and s a t i s f i e s (3.3.1)
and (3.3.2). We now remove t h e r e s t r i c t i o n t h a t a ( t ) and B(t) are s t r i c t lower and upper solutions. Let p: [O,tO] -+ (O,tO] satisfy
p"(t)
i = 1,2,
and
-< 0
for a l l t
E
[O,tOl Li(p) 2 0
a,(t) = a ( t )
Define 173
for
i = 1,2,
for
i = 1,2.
for
- EP(t).
3. TOPOLOGICAL METHODS
and l e t
where
6 ( & ) i s t h e modulus o f c o n t i n u i t y of
g(t,x,y)
domain D' = [ ( t , x J y ) : t E [ 0 , t 0 I ,
1x1 5 K, IyI i s defined as before and S > max (M(K), "Pt
5
K
E [0
[O,tOl I p ' ( t ) l ) .
Since
and
Ig(t,c?Jc?')- g(t,ct&Jc?;)l <
y& ( t , a E Ja E' ) E
to1 l a w I >
<
we have
= -2
g ( t , a , a ' ) = B(t,CY&,CYL) E
where
laE(t)-a(t)l + la;(t)-al(t)l
SU%€
Moreover, since
SIJ
on t h e
E
- 6(E).
Hence
a; > a"
aE i s a s t r i c t l o w e r s o l u t i o n o f
Thus
Similarly
BE i s a s t r i c t upper s o l u t i o n of (3.3.8).
Furthermore,
as
-> g ( t , a , a ' ) > gE(t,aE,a;).
E
+O.
g (t,xJy) E
Therefore
converges t o
g (t,x,y) E
g(t,x,y)
uniformu
satisfies Nagumo's condition
and as before t h e r e e x i s t s a s o l u t i o n x E ( t J x , y ) of (3.3.8), (3.3.1),
and (3.3.2).
Moreover, 174
Ex,}
converges i n t h e
C(l)
E
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
The l i m i t i n g f'unction i s then a s o l u t i o n of the BVP (3.2.1), (3.3.1), and (3.3.2). This concludes the proof of Theorem 3.3.1.
norm as
E
+ 0.
REMARK 3.3.1.
The significance of t h i s r e s u l t i s that we can show existence of solutions of t h e Neumann problem, that i s , when a1 = a2 0 i n (3.3.1) and (3.3.2). Observe t h a t except f o r t h i s very important case Theorem 3.3.1 i s a consequence of Lemma 3.3.2 and Theorem 3.2.2. The following example i l l u s t r a t e s Theorem 3.3.1. EXAMPLE 3.3.1.
Assume r1
=
and. satisfies Nagumo's condition.
r2 = 0 Let
and
(3.3 . l o ) then, from (3.3.9)
c > 1/E
t € [O,
11
e x i s t and satisfy
gx
Then the boundary value problem (3.2.1), a solution. To see t h i s l e t Ig(t,O,O)
g: [0,1]xR2 - t R
(3.3.1),
(3.3.2) has
I;
we have
g(t,O,O) -g(t,-C,O) _> CE. Using (3.3.10 ) , we then obtain
g(t,-C,O) < 0. Thus a ( t ) = -C i s a b w e r solution and similarly ~ ( t =) c i s an upper s o l u t i o n f o r (3.2.1), (3.3.1), and (3.3.2). By Theorem 3.3.1, there exists a solution of t h e BVP (3.2.l), (3 03 el), (3 e3.2). 3.4
GENERALIZED DIFFERENTIAL EQUATIONS
I n t h i s section we develop a Wazewski theorem f o r con-
tingent d i f f e r e n t i a l equations and. u t i l i z e it t o prove 175
3. TOPOLOGICAL METHODS
existence theorems f o r BVP's. The following preliminaries w i l l prove usef'ul i n t h e discussion.
Let
(cc(Rn)) be t h e c o l l e c t i o n of a l l
c(Rn)
nonempty compact (compact and convex) subsets of
x
and A,B E c(Rn),
E Rn
and
let
For
Rn.
q(x,B) = i n f [ l l x - b ( ( : b c B]
q(A,B) = sup[q(x,B): x E A].
Then
d(A,B)
I
max[q(B,A),q(A,B)] i s t h e Hausdorff metric on c(Rn) and n c(R ) i s a complete metric space. Let V be a subset of R x R n and denote t h e points of V by
p = (t,x).
continuous (USC) at a
6
>0
such t h a t
If we replace
continuous
> 0,
p E V
i f , f o r each
E
IlQ-pII
<
q(F(Q),F(p))
implies
6
q(F(Q),F(p)) by
d(F(Q),F(p)),
X be an open subset of
Let
be USC.
.
i s upper semi-
F: V + c(Rn)
A mapping
RxRn
there e x i s t s then
and l e t
<
E.
is
F
F: X +cc(Rn)
A s o l u t i o n of t h e generalized d i f f e r e n t i a l equation
(3 4.1)
x ' E F(t,x)
9
i s a function
cp: I + R
n
which is absolutely continuous on
each compact s u b i n t e r v a l of everywhere on For
I
and
cp' ( t ) E F(t,cp(t))
almost
I.
E C X
and
po = (to,xo),
an accumulation point of
at p0 i s D+(E,pO) = [y E Rn: t h e r e e x i s t s {(tn,xn)3 C E, (tn,xn) + (to,xo), tn > to, ( x n - x O ) / ( t n - t O ) + y as n + m I . The negative E,
E
t h e p o s i t i v e contingent of
contingent and contingent of
similar manner. then w r i t e
If
+ D cp(to)
E
E
at
p
0
a r e defined i n a
i s t h e graph of a function
instead of
+ D (E,pO).
cp: I +Rn,
A solution of t h e
contingent equation
(3.4.2)
Dx C F ( t , x )
i s a continuous function
F(t,cp(t))
f o r a l l t E I.
cp: I + R n
such t h a t
A function
176
cp(t)
Dcp(t) C i s a solution
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
of (3.4.1) if and only i f it i s a s o l u t i o n of (3.4.2). The b a s i c theory f o r generalized equations hold; namely, t h e Peano's e x i s t e n c e theorem, e x t e n d a b i l i t y of s o l u t i o n s , and t h e Kamke convergence theorem are true f o r generalized equations, and we shall not expound on t h i s f'urther. Denote t h e maximal i n t e r v a l of existence of a s o l u t i o n D Before s t a t i n g a Wazewski theorem f o r cp' generalized equations, we w i l l need t h e following d e f i n i t i o n .
cp(t)
of (3.4.1) by
DEFDIITION 3.4.1.
A s e t A c X i s ( p o s i t i v e l y ) weakly i n v a r i a n t
with r e s p e c t t o (3.4.1) if f o r each po = ( t O , x o ) E A , t h e r e i s a solution V(t) of ( 3 . 4 . l ) w i t h cp(to) REMARK 3.4.1.
(t,cp(t)) E A
A closed set
v a r i a n t if and only if
LEMMA 3.4.1.
=Xo,
on
D cp
I [tO,m).
i s p o s i t i v e l y weakly in-
E
+ D (E,pO) fl F(pO) f 6
f o r all po
E
E.
are r e l a t i v e l y closed, X with X = E U E2. 1 i s p o s i t i v e l y weakly i n v a r i a n t .
Assume
and E2 1 p o s i t i v e l y weakly i n v a r i a n t subsets of Then H = E fl E2 1 Proof:
Let
two s o l u t i o n s and an Let
a> 0
L(t)
E
po = ( t O , x O ) E H.
qi(t)
By hypotheses, t h e r e e x i s t
of (3.4.1) with (t,cpi(t))
such t h a t
be t h e segment j o i n i n g
E
(pi(to) = xo, Ei
to 5 t < to + a.
for
(t,cpl(t))
i = 1,2,
to
(t,cp,(t)
)
( E n~ E~). Then x ( t ) = a(t)cpl(t) + (1-ct(t))cp2(t), 0 5 a ( t ) ,< 1. Choose a sequence {t,); + t n + t o , and a ( t n ) +ao. Then and l e t
(t,x(t)) E L(t)
n
We now can choose a subsequence
{t,]
t h e l i m i t t h e l e f t s i d e belongs t o s i d e equals
aovl + ( 1 - a o ) v 2
where
177
of
{t,}
Df(H,pO) vi
E
such t h a t i n
and t h e r i g h t
D+cpi(to).
3 . TOPOLOGICAL METHODS
By convexity, D+(H,pO) H
cy
n F(pO) # fl
v + (1-wo)v2 i s i n F(pO) and thus 0 1 and as a r e s u l t , by our previous remark,
i s p o s i t i v e l y weakly i n v a r i a n t .
This concludes t h e proof of
Lemma 3.4.1. The following i d e a s w i l l be needed f o r t h e Wazewski theorem. For
vc
po = ( t O J x O ) E
t h e zone of emission r e l a t i v e t o
X,
is
Ev(po) = [(T,y): y = cp(T), cp(t) with cp(to) = xo and ( t , c p ( t ) ) E V and
21,
v
i s a s o l u t i o n of (3.4.1)
t between to
for a l l
and t h e r i g h t zone of emission r e l a t i v e t o
'
is
V
E;(Po) = [(.JY>: ( T ~ Y )E Ev(Po), >_ t o ] . If A X J Ev(A> = i s s i m i l a r l y defined. U[EV(p): p E A ] and E+(A) V L e t W be a r e l a t i v e l y closed subset of X. For po E W, t h e t r a c e of emission r e l a t i v e t o W i s defined t o be T&~)
(aw
n
n
= $(Po)
(aw
n w)
+
A c w, T ~ ( A )= $(a)
and, f o r
n
w). DEF~ITION
3.4.2.
A point
Q E
aw n w
i s a s t r i c t egress
p o i n t r e l a t i v e t o (3.4.1) i f f o r every s o l u t i o n s u p [ t : (s,cp(s,Q)) E a W ll W, t
<
Q-
6
_< t l < m,
cp(t,Q), c = cp and t h e r e e x i s t s
with ( tn,cp(tn,Q)) E X - W. {t,], tn + c cp We w i l l denote t h e s e t of s t r i c t egress p o i n t s by
a sequence
Finally, a solution
cp(t,p), p E W,
i f t h e r e exists some
( tlY(p(tlJP))
x- w.
tl
E D
cp
n
[t P'
of (3.4.1) m)
S.
"leaves
W,"
such t h a t
Before s t a t i n g t h e Wazewski theorem we w i l l need t h e following lemmas. LEMMA 3.4.2.
p o i n t s of
Let
z C i n t W U S and assume t h a t a l l a r e s t r i c t egress p o i n t s . If a l l
+ + T (2) = T (z) W
s o l u t i o n s through
p C W U S l e a v e W,
then
T+(p)
is
compact. Proof:
We s h a l l show any sequence 178
{$I
C
T+(p)
contains
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
a subsequence which converges t o a p o i n t of frpn(t)] be s o l u t i o n s of (3.4.1) through p
+
Let such t h a t
T (p).
an extension of m e ' s convergence (tn,cpn(tn)) = $. theorem t o contingent equations, t h e r e i s a subsequence {cpk(t)]
of
{cpn(t)} converging t o a s o l u t i o n
of (3.4.1)
cp(t)
with
cp(t ) = x By assumption cp(t) leaves W. Thus P P' ta > t such t h a t ( ta,cp(ta) ) E X - w. there exists P For a l l k s u f f i c i e n t l y l a r g e , ( t a , ( P k ( ta ) ) E X - w , hence
-
t < tk < ta. Choose a subsequence {t,] such t h a t tm+ P tb < ta' Then % = (tm,'pkctm)) + (\,(P(tb))* NOW (tb,cp(tb)) j ~ + ( p >implies f o r m s u f f i c i e n t l y l a r g e , t h a t &m i s not a s t r i c t egress point. This l e a d s t o a c o n t r a d i c t i o n and thus W 3.4.3.
L
Let
a l l points USC map on Z. Proof:
p
as
[pn]
n + m.
that
E
Z
sequence
pn
and
{cpk(t)}
of (3.4.1) with
for each
then t h e r e i s a n
such t h a t
Hence f o r each
q(g,T+(p,))
through
W,
p
Z,
E
~ + ( p >i s compact.
3.4.2,
not USC a t some po E Z, sequence
leave
W U S.
+ T
a r e s t r i c t egress p o i n t s , then
emm ma
BY
i s compact.
be a nonempty subset of
Z
a l l s o l u t i o n s through
+ T (Z)
T+(p)
>
E.
$. of
pn + p o and n, t h e r e i s a
Let
cpn(t)
E
>
If
If
and if i s an
is
T+
and a sub-
0
q(T+(p ),T+(p,)) 2
$
E T
+n
(p,)
such
be a s o l u t i o n of (3.4.1)
By t h e convergencetheoremthere i s asub-
converging t o a s o l u t i o n cp(t)
{cp,(t)]
cp(to) = xo.
By assumption,
A s i n t h e proof of Lemma 3.4.2,
cp(t)
leaves
we can f i n d a subsequence
+
W.
{t,}
of Etk3 such t h a t (tm,~mCt,)) = &m + ($,cp(tb)) E T (Po) which i s a contradiction. This completes t h e proof of Lemma 3.4.2. We now s t a t e and prove t h e Wazewski theorem which w i l l
then be used t o o b t a i n t h e existence of s o l u t i o n s of BW's 179
E
3. TOPOLOGICAL METHODS
associated with THEOR334
points of
(3.4.1). Z
Let
3.4.1.
i n t W U S be connected.
C
T+(Z) a r e s t r i c t egress points and i f po
not connected, then t h e r e e x i s t s
Proof:
Assume not; then f o r any
depends on
and t h e r e exists
W
leaves
such t h a t
cp)
( t ,cp(t
[ t , t 1. P Q compact f o r each p E Z. (t,cp(t,p))
E
on
W
Q
Q”
we w i l l show
w
E
on
D cp
p
E
E
T+(p) c aW
Q
))
By Lemma
T+(Z) i s
and a solution
Z
(3.4.1) such t h a t (t,cp(t,p,))
cp(t,pO) of
cp(t,p)
E
If all
E
n
[tO,m).
every solution
Z,
aw n w
nW
(Q
and
3.4.2, T+(p) i s
is connected. If i s a s t r i c t egress point. Clearly, T+(p) i s then connected. Let V = i n t W, p1 E V fl Z, -Iand assume t h a t T (p,) = C , U C2 is a separation where CY For each
n
p E Z
C2
S,
p E Z,
then
p
+
T (p)
E
T+(p)
p
and
a r e nonempty d i s j o i n t compact s e t s . For a solution
cp(t,p)
of
(3.4.1) with p
E
let
V,
I = D fl [tp,m) = [ t w) be t h e r i g h t maximal i n t e r v a l of c p c p P’ existence of cp(t,p) r e l a t i v e t o X and l e t J = [ t p , y ) be cp t h e r i g h t maximal i n t e r v a l of existence of cp(t,p) r e l a t i v e t o
V.
Let
to
V,
o(p) and l e t
denote t h e r i g h t t r a j e c t o r y o f u(A,B)
-
= inf[((a bll: a
E
cp(t,p)
A, b E B]
,
relative where
a r e a r b i t r a r y sets.
A,B
El = [p E V: t h e r e e x i s t s a solution cp(t,p) I =J or t h e r e exists a solution cp(t,p) such t h a t
Define with
c p c p
with a(O(p),C1) 5 o(o(p),C2)]. Define E2 s i m i l a r l y Icp # Jcp with t h e inequality reversed. It follows t h a t El, Eg a r e closed r e l a t i v e t o V, a r e p o s i t i v e l y w e a k l y invariant, such t h a t p 1
E
E1
n E ~ . ~y emm ma 3.4.1, q(t,pl)
u E2
t h e r e i s a solution
of (3.4.1) such -“hat (t,cp(t,p,)) However.,
V = El
E, must leave W. 180
E
n E*
on J
and rp(t,p,)
cp’
Hence (y,cp(y,pl))
E
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
+
Let T (p,) = C1 U C2. Assume t h a t ( y,cp(y,pl)) E C1. be a sequence of points on O(pl) such t h a t % + ( y , p ( y , p l ) ) ~
g E E2,
Since
C1.
(3.4.1) Since
such t h a t
t h e r e e x i s t s a solution
{
cp(t,P,>,
tPl 5 t
cp(t,g),
tB, c t <
i s a solution of (3.4.1) through through
5
wn,
of
$(y,pl) = (p(y,pl)
s u f f i c i e n t l y large,
+ $(t,pl)
$k(t,pl)
+
(y,cp(y,pl)) E C1 C T (p1) i s a contradiction. Thus Lemma 3.4.3,
$,(t,p,)
uniformly on
Jr(t,pl)
and a subsequence
{ q n ( t ) } such t h a t f o r any compact i n t e r v a l
all k
must leave
eh,
This implies t h a t there e x i s t s a solution (3.4.1) with
I
I
k
+ m.
of
{qk(t)l C
D
i s defined on as
n.
tan>
p1 E Z, $n (t,pl) ( yn,cp(yn, ) E C2.
and hence
C2
of
> 0(@(%),C2) f o r each CJ(O(%),C,) -
$*(t,P1) =
W
cp(t,$)
JI
I
and and
However, then
i s not a s t r i c t egress point, which T+(p,) i s connected. Finally, from
i s an USC map on 2 from which it follows
T'
This i s a contradiction t o t h e assumption
T+(Z)
i s connected.
T+(Z)
i s not connected.
po E Z
and a solution
(t,cp(t,po)) E W on of Theorem 3.4.1.
I
Cp
Hence we conclude t h a t there e x i s t s Cp(t,po)
of (3.4.1)
= DCp fl [tO,w).
such t h a t
This concludes t h e proof
An a l t e r n a t e way of s t a t i n g Theorem 3.4.1 i s i n t e r n s of retracts.
Let
A, B be subsets of
Rn+'
with
t h e r e e x i s t s an USC mapping
G: A -+ c(Rn+l)
i s connected f o r a l l x E A
and x E G(x)
then
B
i s a r e t r a c t of
THE!ORE!M 3.4.2.
t h a t a l l points of
Let
B C A.
such t h a t
If
G(x) C B
f o r a l l x E B,
A.
Z
be a subset of
int W U S
T+(Z) a r e s t r i c t egress points.
181
If
such
3 . TOPOLOGICAL METHODS
Z
n
exists
+
i s a r e t r a c t of
T+(Z)
po E Z,
T (Z), but not of
such t h a t
(t,Cp(t,p,))
E
Z, t h e n t h e r e W for a l l t E D n Cp
[to,..). If t h e conclusion does not hold, then f o r a l l
Proof:
Z, every s o l u t i o n cp(t,p) of (3.4.1) leaves W, and + i s USC on Z. Let H: T+(Z) + T+(Z) fl Z be a rehence T + + t r a c t i o n o f T (Z) onto T (Z) n Z which i s assumed t o e x i s t . "hen H: T+ i s a r e t r a c t i o n of z onto T+(z> n Z. "his i s a p
E
c o n t r a d i c t i o n and concludes t h e proof o f Theorem 3.4.2. "he preceding r e s u l t s remain v a l i d i f
open subset of
X,
[a,m) xRn, W
X
i s a relatively
i s a r e l a t i v e l y closed subset of
and Z i s a connected subset of
i n t W U S.
We now apply
Theorems 3.4.1 and 3.4.2 t o BVP's a s s o c i a t e d with second-order contingent equations. Consider t h e generalized second-order d i f f e r e n t i a l equation x" E G ( t , x , x t ) ,
(3.4.3) where
G:
2 [a,b] X R
--3
cc(R)
extension, we may assume
i s upper semicontinuous (USC). By on X = [a,m)xR 2 Letting
.
i s USC
G
= Y2' H(tJy) = (Y2JG(tJY1JY2))J = Y1J 2 we see H: X --3cc(R ) i s USC and
(3.4.4)
A mction
s o l u t i o n of (3.4.3) on (3.4.5) for a l l t
I
Dxt(t) E
DEFINITION
I
and
C
C
[a,..)
x ( t > E c ( ~ ) ( I ) is a
i f and only i f
G(t,x(t),x'(t))
Dxt(t)
3.4.3.
y = (Y1'Yp)J
H(tJy)
Y'
i s equivalent t o (3.4.3).
where
#$
f o r a11 t E I.
The functions
+ ( t ) J cp(t)
are called
s t r i c t upper, lower s o l u t i o n s f o r (3.4.3)J r e s p e c t i v e l y , if, +(t), q ( t ) E C(l)(I)J I
C
[a,..) 182
and if
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
We w i l l assume t h a t
Note t h a t surface of
W
O(t) < $ ( t )
t
for a l l
i s a r e l a t i v e l y closed subset of i s the s e t
W
= [(t,x,x'):
S
1 and the lower surface of
$ ( t ) , x ' E R]
W
[ ( t J x J x ' ) : t E [aJb], x = cp(t), x ' E R]. connected subset of
W fl [ t = a ] such t h a t
S1 a t a single p i n t of single point of
A2.
and
A1
t
E
!he upper
X.
[a,b], x =
E
i s the s e t Let Z1
S2 =
be a
Z1
intersects
intersects
Z1
Define
I.
S2
at a
We now present a theorem which i s i n the
same s p i r i t as Theorem 3.2.1. THEOREM 3.4.3.
If
$(t)
lower solutions of (3.4.3), (i) (ii)
and
cp(t)
are s t r i c t upper and
then e i t h e r
T+(Z,) fl [ t = b ] # there i s a solution
or
$J
x(t)
of (3.4.3)
(&,X(a)Jx'(&)) z l J cp(t) 5 x(t) 1. $(t) On + where [aJw+) (w+ < b) I x ' ( t ) l - + m as t -+w maximal i n t e r v a l o f existence of Proof:
Assume
+
such t h a t
(t,x(t),x'(t>) E
for
w
t
E
) J and i s the r i g h t
x(t).
T (Z,) il [ t = b ] =
solution of (3.4.3)
such t h a t
+
8.
Let
x(t)
be a
( a , x ( a ) , x ' ( a ) ) E ZIJ [a,t,]
183
and
( t O J x ( t O ) ' x ' ( t O )E) S 1.
3 . TOPOLOGICAL METHODS
Then x ( t o ) = +(to)
and
5
x(t)
$(t)
t
for
E
[a,tol,
Similarly s o x ' ( t o ) 2 + ' ( t o ) . Hence ( t O , x ( t O ) , x l( t o ) ) E A1. a solution from Z can intersect the lower surface S2 only 1 + a t points of A2. Thus T (Z,) C A 1 U A2. Observe also T+(Z1) since A1 fl Z1 Let
n A1 # 9
##
and
and A2 flZ
T+(Z,)
n
A2
##
# #.
1+ i s a s t r i c t egress point. We now show any point of T (Z,) + Q = (tO,xO,x;)) E A1 n T (Z,). Assume Q i s not a s t r i c t
egress point; then there e x i s t s an i n t e r v a l and, a solution x ( t ) + ( t ) on
[ t , , ~ ] , to < T, Q such t h a t x ( t ) <
emanating from
[ t , , ~ ] . Clearly,
x'(to) = +'(to).
Let
-
and consider the sequence
-
-
tn + t o
{ [XI(t,) x ' (t,)/(t, t o ) ] . Since Dx' ( t o ) C G ( t O y x ( t O ) , x T ( t O )and ) since G(tO,x(tO),xt( t o ) ) i s compact, the sequence i s bounded. Thus there e x i s t s a subsequence {t,] such t h a t
=
G(t0>+(t0)'+l(t0)).
-
cause
+(t)
-
{ [ + I (t,) +' ( t o ) ]/(t, to)}. Bei s a s t r i c t upper solution, t h i s sequence contains
Consider now the sequence
a subsequence converging t o a point i n there e x i s t s a subsequence +'(tj)
for
8 E (t,,~]
implies
j
of
s u f f i c i e n t l y large.
such t h a t
x(e) >
{t,]
$(e),
shown t h a t any point of
x'(t) > $!(t)
{t,] such t h a t x ' ( t . ) > J Hence there e x i s t s
n
T+(Z,)
t
for
a contradiction.
A2
E
( t o , @ ) . This
Similarly, it can be
i s a s t r i c t egress point.
We can now apply Theorem 3.4.1because
184
Therefore,
(-m,y).
a l l points of
3.4. GENERALIZED DIFFERENTIAL EQUATIONS
T + ( z ~ ) a r e s t r i c t egress p o i n t s and Hence t h e r e i s a s o l u t i o n x ( t )
T+(z,)
of (3.4.3)
i s not connected. such t h a t
( a , x ( a ) , x l ( a ) ) E Z1 and cp(t) < x(t) < $ ( t ) on [a,w+) with + + w < - b. Furthermore I x l ( t ) l - + m as t + w , f o r i f not,
+
fl [ t = b ] # $.
T (Z,)
holds.
Hence i f ( i ) does not hold, then ( i i )
This concludes t h e proof o f Theorem 3.4.3. The proof o f Theorem 3.4.3
REMARK 3.4.2.
than t h a t of Theorem 3.2.1. Theorem 3.4.3
i s different
We could have, however, proved
i n a manner similar t o t h a t of Theorem 3.2.1.
This follows from t h e fact t h a t it can be shown t h a t t h e r e + exists a connected subset of T (Z ) i n W fl [ t = b ] which 1 A
and A2. 1 We now extend t h e concept of Nagumo's condition t o second-
intersects
order contingent equations. DEFINITION 3.4.4.
The function
G:
[a,b] X R
satisfies Nagumo's condition r e l a t i v e t o W p o s i t i v e function
G(t,x,x')] < h ( Ix'
h ( s ) E C([O,m))
such t h a t
I)
E
for
(t,x,x')
W
and
2
+cc(R)
if there exists a
max[lzl : z E /" s d s / h ( s ) = +m.
The following lemma can be proved s i m i l a r l y t o t h a t of Lemma 1.4.1.
s a t i s f i e s Nagumo's condition on [a,c], then, given an i n t e r v a l [ a , c ] , a < c < b, t h e r e exists an and i f
N > 0
cp(t)
G(t,x,x')
such t h a t f o r any s o l u t i o n x ( t )
5
x(t)
5
q(t)
EXERCISE 3.4.1. Let
Z2
on
[a,c],
then
of (3.4.3)
Ix'(t)l
with on
[a,c].
Prove Lemma 3.4.4.
be a subset of
W fl [ t = b ]
185
so that t h e r e exists
3. TOPOLOGICAL METHODS
a separation W fl [ t = b ]
n
and A2 El f o r a BVP.
[t =b 1
THEOREM 3.4.4.
C
- Z2
= El U E2
with
A1 fl [ t = b ] C
We now state an existence theorem
E2.
If t h e r e exist s t r i c t upper and lower
solutions f o r (3.4.3)
on
and if G(t,x,x')
[a,b],
Nagumo's condition with respect t o
satisfies
then there i s a solution
W,
o f (3.4.3) such t h a t q ( t ) < x(t) < Jr(t) on satisfies t h e boundary conditions (a,x(a),x' ( a ) )
x(t)
(b,x(b),x'(b) Proof: immediate.
)
If T+(Zl) fl Z2 Assume then t h a t
+
C
S1 U S2
A l l points of
s t r i c t egress points. Q E
A1,
and
Z,
# #, then t h e conclusion T+ (Z,) n Z2 = 8. Then
is
-
u
(W fl [ t = b ] Z2),
and as i n t h e proof of Theorem 3.4.3,
+ T (Z,) n
E
and
Z2'
T (2,)
i = 1,2.
[a,b]
El U E2
C
W
T+(Z,)
n
[t =b]
fl Si C A i
for
are obviously
This together with t h e f a c t , t h a t
i = 1,2,
with
point implies t h a t a l l points of
t < b,
Q
"+(Zl)
is a s t r i c t egress are s t r i c t egress
points (see t h e proof of Theorem 3.4.3). Since
+
(A, U El) U (A2 U E2) and since El U E2 it follows t h a t @(Z,) fl Z1 W fl [ t = b ] Z2, T+(Zl). However, T+(Zl) n Z1 i s not a r e t r a c t
T (Z,) i s a separation o f
i s a r e t r a c t of
C
-
x ( t ) of (3.4.3) with (a,x(a),xl(a)) E Z1 such t h a t ( t , x ( t ) , x l ( t ) ) E W on i t s maximal i n t e r v a l o f existence [t,,w) r e l a t i v e t o X. This means w < - b and I x l ( t ) I 4 m as t +w-. By Lemma + 3.4.4 t h i s i s impossible. Therefore T (Z,) fl Z2 # @ and t h i s concludes t h e proof o f Theorem 3.4.4.
of
3.5
Z1.
By Theorem 3.4.2,
t h e r e e x i s t s a solution
DEPENDENCE OF SOLUTIONS ON BOUNDARY DATA This section u t i l i z e s t h e topological properties of
186
35. DEPENDENCE OF SOLUTIONS ON BOUNDARY DATA
s o l u t i o n funnels t o deduce r e s u l t s on t h e continuous dependence on boundary values of s o l u t i o n s of BVP's f o r systems o f d i f f e r e n t i a l equations with generalized boundary conditions. Let
I be an open i n t e r v a l i n
and
We w i l l consider t h e two point BVP
f = (fl,f2).
(3 5.1)
x' = f ( t , x ) , g ( x ( a ) ) = r,
(3.5.2) where
R, x = (x1,x2),
2
f E C [ I x R ,R
2
1,
h(x(b)) = q
(a,b
I),
E
2 2 g E C [ R , R ] , h E C[R , R ] .
We s h a l l use some of t h e notions dealing with compact sets t h a t were developed i n t h e preceding s e c t i o n . we introduce s i m i l a r n o t a t i o n h e r e . int A
(a)denote t h e
If
A
For completeness
is a s e t , l e t the
i n t e r i o r (boundary) o f
A
and l e t
[a]
be the one-point s e t containing a . 2 Let c ( R ) denote t h e f a m i l y of a l l compact, nonempty 2 subsets of R Let q(x,B) = inf[llx-y(l: y E B], q(A,B) =
.
A], d(A,B) = max ( q(A,B),q(B,A)). When A C R2 and E > 0 l e t N(A,&) = [x: q(x,A)
sup[q(x,B): x A,B E R2 f o r
E
w i l l be denoted by N(x, E). For
X
C
R
2
,
t h e mapping
2 F: X + c ( R )
upper semicontinuous (continuous) a t
x
E
x
5
i s s a i d t o be i f y + x implies
q(F(y), F ( 4 ) -0. As we have observed, (3.5.1) generates a mapping 2
R XIXI i n t o t h e f a m i l y of a l l closed subsets of
R2
F
of
defined
bY F(x,tO,tl) = [y: y = x(t,), x = x ( t ) i s a s o l u t i o n of (3.5.1), x(to) = This i s p r e c i s e l y t h e cross s e c t i o n a t funnel through The mapping
tl
XI.
of t h e i n t e g r a l
(to,x). F has t h e following well-known p r o p e r t i e s :
187
E)
3. TOPOLOGICAL METHODS
(I) F(A,t 0 J t1)
= UIF(xJtO,tl): x E A ]
and connected) provided (3.5.1), (11)
i s a continuum (compact
i s a continuum and a l l solutions of
A
x(tO) = yJ y E A
e x i s t on
[tOJtl].
I f every solution of (3.5.1) through
( t O J x O )E
Q C
IxR2
e x i s t on
A x{to} C Q
and
q(B,A)
[ t o - h , to+ h ] , then given a compact s e t E > 0 t h e r e a r e 6 > 0 and q > 0 such t h a t
<
6,
Is - t o [< 6 implies q(F(BJsJtl)J F(AJtOJtl)) < EJ and
Itl- t21 < q
implies
~ ( F ( A J ~ ~~ J( ~ J~t )o JJ t z<) )E J provided
It2- t oI
BX{S}
C
Q,
t
SJ
5 h.
Let
and l e t
t
1’ 2
E
IJ
IS-tll
5 h,
Ito-t,I
x o ( t ) be a solution of (3.5.1) defined on [ a J b ] C I 2 0 be a subset of [ a J b ] x R The BVP (3.5.1)J (3.5.2)
.
i s s a i d t o be unique r e l a t i v e t o x o ( t ) , [ a ~ b ] and ~ any solution for
t
5 hJ
y(t)
of (3.5.1),
t h e conditions
0,
if for
(t,y(t)) E Q
[CJ~]
g(Y(c)) = g(xo(c))J h(Y(d)) = h(xo(d)) imply y ( t ) = x o ( t > on [CJd]. We a r e now able t o s t a t e a continuous dependence r e s u l t . 6
The proof of t h i s w i l l follow a f t e r a s e r i e s of lemmas.
THEOREM
(i)
3.5.1.
For a l l
f J g, h
Let
r
E
s a t i s f y the conditions:
t h e curves
Rj
K(r) = [x: g(x) = r ] ,
H(r) = [x: h(x) = r ] a r e simple arcs separating R2; ( i i ) For a l l r, q E R, K(r) n H(q) i s a one-point s e t . Let
x = x o ( t ) be a solution of t h e BVP (3.5.1)J and
(3.5.3)
g(x(o)) =
r
~
J
188
h ( x ( l ) ) = 91’
35. DEPENDENCE OF SOLUTIONS ON BOUNDARY DATA
Let t h e BVP (3.5.1),
(3.5.2) be unique r e l a t i v e t o
[0,1], and some open s e t
[(t,x): x = xo( t) , t
Q E [0,1] xR2
xo(t), containing t h e a r c
[0,111.
E
such Then there i s a neighborhood U of (O,l,r o’91) t h a t f o r a l l (a,b,r,q) E U, t h e BVP (3.5.1), (3.5.2) has a solution
= x(t,a,b,r,q)
x
t
uniformly i n
satisfying
If uniqueness of t h e
--f
xo(t)
( a , b , r , q ) + (O,l,rO,ql).
[0,1] as
E
x(t,a,b,r,q)
BVP i n t h e “usual sense” i s assumed,
we obtain immediately t h e following corollary. COROLLARY 3.5.1.
Assume ( i ) and ( i i ) hold and t h a t t h e
solutions of the BVP (3.5.1), a r e unique.
If the solution of t h e BVP (3.5.1),
then t h e BVP (3.5.1), for a l l and
(3.5.2), whenever they e x i s t ,
(a,b,r,q)
(3.5.2) has a s o l u t i o n x = x ( t , a , b , r , q ) i n a c e r t a i n neighborhood U of (O,l,ro,ql)
i s continuous on
x(t,a,b,r,q)
I n order t o prove Theorem 3.5.1, liminary r e s u l t s .
(3.5.3) e x i s t s ,
Choose
>0
&
[0,1] X U . we w i l l need some pre-
such t h a t t h e s e t
[(t,x):
Ilx-xo(t)II 5 2&, t E [0,1]] i s i n Q. L e t h > 0 be t h e number with t h e property t h a t if s E [0,11, l l y - x o ( s ) / / 5 E, then every solution
x = x(t)
[s - h , s + h l
e x i s t s on
of (3.5.1) s a t i s f y i n g
and s a t i s f i e s
t h i s interval. Choose a sequence of numbers
ti+l - t . < h
such t h a t
1
5
2& on
< .-.< tm ..,m - 1, 1and l e t
0 = to < t
i = 0,.
if
Ilx(t) - x o ( t ) l l
x(s) = y
= 1
xi - x0 ( t 1 . ) , Ni = N(xi,&), ri = g(xi), q r = h(xi), Ui = [x: h ( x ) < q r ] , Vi = [x: h(x) > qy]. By the choice of
then
F
h,
if
A C N ( x ~ ( s ) , E ) ,0
s a t i s f i e s (I) and (11) and
For
A
C
Ni - 1, write
sets
Si, i = 0 , .
K(ro)
n No
..,m - 1,
containing x
0’
Fi(A) by
So
‘i+l
189
F(A,s,t) c N ( x o ( t ) , 2 & ) . F(A,t i-1’t i ).
Define the
as the component of as t h e component of
3. TOPOLOGICAL METHODS
n
(S ) Ni+l containing xi+l. Fi+li compact, it follows from (I) t h a t
Since
Si
a r e compact.
uniqueness condition on the BVP (3.5.1), (305.4)
Fi+l (Si)
LEMMA 3.5.1.
n H(qT+l) Let
Ao, Bo
=
=
(3.5.2)
Exi+,l,
=
and Ni
So
i =
satisfy
A.
are
The
implies t h a t
o , i , . ..,m
U Bo = K ( r o )
- 1. n
n ai,
&To,
F ~ ( A ~ ul, ) F ~ ( B ~ Ivl. Let Ai = ~ ~ ( s ~ ui , ~ > Bi = Fi(Siml) fl Vi n bi. Then given T E ( t l , l ] there e x i s t s a S
of
>0
>0
q
and
n
such t h a t f o r every solution
(3.5.1) defined on
Ix(t) - x o ( t ) l
5
x(p) E N(Ai,q)
[O,T] U [p,Tl,
t
x = x(t)
t h e conditions
[o,Tl U [p,Tl; l p - t i l < q, [or x(p) E N(Bi,q)l f o r some ti E LO,")
2~
for
E
bPl-Y
(3.5.5)
h(x(t)) c h(xo(t))
on
n
[t,Tl
or
h(x(t)
> h(xo(t)) + 8
[p,Tl.
Proof: n = 1,2
-8
,...,
Assume t h e r e s u l t i s not true.
Let
yJt),
be a sequence of solutions of (3.5.1)
-
such t h a t
Yn(Pn) E N(Ai,l/n), h(Yn(Sn>)2 h(xo(s,)) ( l / n l , where Ipn-til c l/n, sn E [pn,T] [t,TI. We may assume sn + s 0 and y n ( t ) + y o ( t ) uniformly on [ O , T I .
n
Uij h(Yo(So)) 2 h(XO(SO)), so t h i s implies t h a t t h e r e i s a solution z ( t ) s a t i s f y i n g Hence
yo(ti)
z(0) E K ( r o ) ,
ro,tii,
w(t) =
E
Ai
z ( t i ) = yo(ti).
Y,W
on
Let
w(t) = z ( t )
> ti;
on
[ti,sOi'
we have g ( w ( 0 ) ) = g(xo(o)), h(w(ti)) h ( xo(ti)), h(w(so)) 2 h(xo(so)), contradicting t h e uniqueness. This completes the proof of Lemma IZMMk 3.5.2. 8i(Ei+l)
3.5.1.
For a given
such t h a t if
Is
E
~
- t i / < Ei, 190
>+ 0 ~ t h e r e
is a
1s -ti+ll 5 h,
tji =
3.5. DEPENDENCE OF SOLUTIONS ON BOUNDARY DATA
D c N(siJsi) n N ( X ~ ( S ) , E ) , then a l l components of F(DysJti+l) which i n t e r s e c t H(qi+l) are i n N(Si+l, Ei+l). Ni+l
*
Proof: E ~ + ~ 0, >
Since S = F (S ) n Ni+l i+l i t h e r e is a decomposition of
2
Let
D1(6), N(Fi+l(Si)
-
be t h e union of a l l components o f
>0
6
i n t o compact s e t s
such t h a t
X , X ,S = X1 U X2 1
is compact f o r any S
S , 6 ) fl Ni+l
which i n t e r s e c t
and l e t
N(XlJ6),
Then by (3.5.6) D 2 ( 6 ) = ( N(Fi+l(Si) -S,6) n Ni+l) -D,(S). and (3.5.7), t h e sets Ck(6) = N($,6) u D k ( 6 ) (k = 1 J 2 ) satisfy
provided
6
is s u f f i c i e n t l y small.
Applying t h e semicontinuity of such t h a t if D CN(Si,6) IS-ti+l
I -< h,
F,
n N(xO(S),E),
choose
6. = b . ( E 1
I t i - s l < 6i,
1
)
i+l
then F(ti+lJSJD)
N ( F i + l ( s i ) ~6 ) -
The a s s e r t i o n follows immediately with t h e use of (3.5.8) and t h e formula N ( F ~ + ~ ( S ~ )n, & N ) ~ =+ ~ ~ ~ ( u 6~ )~ ( 6 ) . We a r e now i n a p o s i t i o n t o prove Theorem 3.5.1. Pmof o f Theorem 3.5.1: of t h e s e t
K(r)
n
N(xo(a),
Let E)
191
S O ( r , a ) be t h e component
which i n t e r s e c t s t h e sets
n
3 . TOPOLOGICAL METHODS
> h(xo(a))3.
cx: h ( x ) < h(Xo(a))3, cx: h ( x ) Let
Si(r,a),
i = l,...,m-l,
denote t h e component of
sim1,ti) fl Nij where
F(Si(r,a), satisfying Set
so = a, s j =
# 8,
s i ( r , a ) n ui C(r,a,b) = F(S,
S i ( r J a ) n vi # l ( r , a ) , tm,lJb ) .
t j for
j
fl.
2
1,
prove t h e
TO
theorem, it i s enough t o show t h a t
# fl
(3-5-9)
C ( r ~ a ~ b )H(q)
where
i s a c e r t a i n neighborhood of
U
I n f a c t , (3.5.9) x(tjajb,rjq) Since of
Of
for
E
UJ
(O,l,rO,ql).
implies t h e existence of a s o l u t i o n
t h e BvP (3.5.1)j
x(tiJaJbJr,q)
(aJbJr,q)
E
Ni
for
(3.5.2)
for
(ajbjrjq) E
...,m - 1,
i = 1,
by t h e choice
ti’ I x ( t , a , b , r , q ) - x ( t ) 1 < 2~ on some i n t e r v a l 0
[0,1]. Thus, t h e family
containing
i s equicontinuous on ness of
xo(t),
[c,d].
u.
[c,d]
{x(t,a,b,r,q)},
(a,b,r,q) E U
By Ascoli‘s theorem and t h e unique-
we deduce t h e uniform convergence on
[0,1] of
x(t,aJbJrJq) as ( a J b > r l q ) -3 (OYlYr0Jq1)* I n o r d e r t o show t h a t (3.5.9) i s t r u e , we f i r s t prove t h a t a l l sets enough.
Si(r,a)
exist if
Ir
For t h i s , define constants
- ro I
ai > 0,
N ( K ( ~ ~ ) a, o ) n 3 ~ c 0 N(AO
(3.5.10 )
N ( F ~ ( sl )~J ~ i ) n
a~~ C N ( A u~ B ~ , Q )
(3*5=11)
am-l>
Em-l =
E~ =
and
u
for
Ai, F(.,s
duct ion. Let (3.5.12)
>0
a r e small by
BOJ~),
for
i = lJ...,m-lJ
min(aiJ6i(~i+l)) if
where
E~
la I
i = m-2,...,0,
are as i n Lemma 3.5.1 and 6 i ( * ) i s defined ti+l) a s i n Lemma 3.5.2. We now proceed by ini’
BiJ q
.4
>0
be so chosen t h a t SO(r,a)
So(r,a)
N(SO,EO),
192
e x i s t s and where
3.5. DEPENDENCE OF SOLUTIONS ON BOUNDARY DATA
(3*5*l3)
so(rJa>
N(A~Jfl)
#
So(r,a)
#J
N(B~J?)
##
-
la I 5 a, Ir ro I 5 a. The p o s s i b i l i t y of such an R follows from (i), (ii),and the c o n t i n u i t y of g, h, and xo.
for a l l
kt
k =
min(a,eo,q). If la1 5 k, Ir-rol 5 k, then e x i s t . To see t h i s , observe that i f Si(r,a)
a l l Si(r,a) e x i s t s and i f it s a t i s f i e s the condition
(3.5.14),
Si(r,a)
N(SiJ~i),
and the condition t h a t
there are solutions ui(t), vi(t) (3.5.1) such t h a t u i ( s . ) , vi(s.) J J f o r j = O,...,i; ui(sh) E N ( % , ? ) ,
(3.5.151,
vi(sk) s
then,
Si+l(r,a)
j
=
t
E
j
1
J
f o r some h, k (so = a,
N(BkJq)
for
of f S.(r,a)
-< j -<
i),
e x i s t s and s a t i s f i e s (3.5.14)i+1
and
(3 5*15)i+1I n f a c t (3.5.15)i and Lemma 3.5.1 imply t h a t F ~ + ~ ( u ~ ( ~ ~ ) ) J ); hence a t least one ( v . ( t . ) ) a r e separated by H(q*i+l Fi+l1 1 Fi+l(Si(r,a)) n N ~ +i n t~e r s e c t s u i+l and Vi+l. By Lemma 3.5.2, Si+l(rJa) C N(Si+lJ~i+l), t h a t is, ( 3 . 5 ~ 4 ) , + holds. ~ To show (3.5.15)i+1 holds, choose any point ui+l i n S i + l ( r J a ) ui+l &i+lJi f t h i s s e t is nonempty; otherwise (u ( t ) ) ( v ~ +is~ chosen s i m i l a r l y ) . If l e t ui+l Fi+li i Fi+l(Si(r,a)) n Ui+l n aNi+l # # J then by (3.5.10), Ai+l # compnent of
"
$ 0
Hence by (3.5.14)i+l, (3.5.11), and (3.5.10), ui+l E N(Ai+l,q). Thus i n every case, t h e r e is a s o l u t i o n ui+l(t) through ( t i + l ' u i + l ) satisfying (3.5.15)i+1. By (3.5012) and (3.5.13)J So(',&) e x i s t s and s a t i s f i e s (3.5.14),, (3.5.15), for a l l \a1 5 k, and Ir-rol 5 k. Hence, by induction, Si(r,a) e x i s t s f o r a l l i > 0. 193
3. TOPOLOGICAL METHODS
To prove (3.5.9), observe t h a t the existence of (r,a) implies the existence of C(r,a,t) f o r a l l
'm- I
14 5 k,
+hl. By property Ir-rol 5 k, and t E [trn,& trn-l c ( r , a , t ) is continuous i n t on 1' tm- 1 + hl. Thus (3.5.15)m-1 and Lemma 3.5.1 imply t h a t (II),
(3 5 16) I
E
C(r,a,b)] < h(xo(b))
max{h(x): x
E
C(r,a,b)] > h(xo(b)) + 8
-
1. 5 k,
hold f o r
-
minCh(x): x
8,
-
Ir r o \ ,< k, Ib 11 5 kl, where kl > 0 is sufficiently small. Since C(r,a,b) is connected, then ( i ) and (3.5.16) i m p l y t h a t (3.5.9) holds, thus completing the proof o f Theorem 3.5.1.
Equation (3.5.1) with the boundary condition (3 -5-17) m a ~ rbe
g(x(b))
&(a>) = r,
=
9
considered as a special case of the BVP (3,5,1), (3.5.2).
EXERCISE 3.5.1.
State and prove a theorem similar t o Beorem 3.5.1 f o r the BVP (3.5.1), (3.5.17). We now consider a special case of Theorem 3.5.1,
fl(t,xl,x2)
= x2
and g and h are linear.
THEOREM 3.5.2. (i)
(t,y)
E
Assume t h a t
x1 < x2 implies f(t,xl,y)
[a,blxR;
(ii)
If(t,x,y)
- f(t,x,z) I
5 f(t,x2,y)
5 Mly - zI on
( i i i ) aO,al,bo,bl 2 0, a. + bo >
bo
when
+ bl > 0.
0,
f o r a=
[a,bl xR2;
a. + a1 > 0,
Then the BVP x" = f ( t , x , x ' ) ,
aox(a) - a 1x l ( a ) = r,
194
box@) + blxl(b) = q,
3.6. NOTES AND COMMENTS
has a unique solution x'(t,r,q)
x(t,r,q)
a r e continuous on
EXERCISE 3.5.2.
Hint:
f o r any 2 [a,b]xR
.
r, q
and
x(t,r,q),
Prove Theorem 3.5.2.
Show t h a t
e x i s t s and i s unique by
x(t,r,q)
a b + albo 0 1 implies condition ( i i ) of Theorem 3.5.1 holds.
u t i l i z i n g ( i ) and ( i i ) .
By ( i i i )
> 0.
This
Apply f i n a l l y
Corollary 3.5.1. In t h e s p i r i t of Exercise 3.5.1, we s t a t e the following result.
THEOREM 3.5.3.
Let
f: I X R
2
+R
be continuous,
Let
x o ( t ) be a solution of t h e BVP (3.5.18)
X"
= f(t,XJX'),
corresponding t o
is a
6
>0
f(t,XJx')
x(b) = 9,
(a,b,r,q) = (O,l,roJql).
such t h a t i f
with
X(a) = r, x(t)
a,b E 1
Assume t h a t there
i s a solution of
x" =
x ( a ) = xo(a), x(b) = xo(b), a,b E [0,1
I x ( t ) - x o ( t ) l < 6, I x l ( t ) - x l ) ( t ) l x ( t ) E x o ( t ) on [a,b].
< 6 on
Then the BVP (3.5.18) has a solution
[a,b],
t 9
then
x(t,a,b,r,q
EXERCISE 3.5.3. Prove Theorem 3.5.3 by applying Theorem 3.5.1 t o the s p e c i a l case i n which g(x,y) E h(x,y) = x and
fl(t,X,Y)
3.6
= Y.
NOTES AND C O ~ ~ T S Theorems 3.1.1 and 3.1.2 of Section 3.1 are taken from
Bebernes and Wilhelmsen [6] , while the subsequent discussion 195
3. TOPOLOGICAL METHODS
dealing w i t h Wazewski's method is based on Jackson and Klaasen
[3] who t r e a t a more general problem not demanding uniqueness. Theorems 3.1.4 and 3.1.5 are also taken from Berbernes and Wilhelmsen [61. The results contained i n Theorems 3.2.1 and 3.2.2 are due to Bebernes and Wilhelmsen [6] (see also Sedziwy [31). Theorem 3.2.3 m a y be found,in Bebernes and Fraker [g]. Exercise 3.2.1 is due t o Markus and Amundsen [ l ] . Section 3.3 contains the results of Kaplan e t al. [l]. Lemmas 3.4.1-3.4.3 are from Bebernes and Schuur [71 w h i l e Remark 3.4.1 is based on Bebernes and Schuur "71 and Yorke [l]. The other results of Section 3.4 are due t o Bebernes and Kelley [lo]. Section 3.5 Consists o f the results of Sedziwy [l]. For related work on continuous dependence, see Bebernes and Gaines [41, Gaines [1,21, Klaasen [l],and Ingram [ l l ,
196
Chapter 4 FUNCTIONAL ANALYTIC METHODS
4.0
INTRODUCTION
Many diverse problems in the qualitative theory of d i f f e r e n t i a l equations are concerned with the existence of a solution which belongs t o a specified subset of a given Banach space.
These problems can be treated i n a unified s e t t i n g by
techniques commonly used i n functional analysis.
These tech-
niques suggest themselves i n a n a t u r a l way, when the considerations involving the i n t e g r a l equation obtained by the method o f variation of parameters are translated into a suitable
abstract setting.
This i s the underlying theme of t h i s im-
portant chapter. A variety of nonlinear functional analytic techniques
l i k e the Fredholm alternative, the Schauder's fixed p i n t theorem, the method of a p r i o r i estimates, the notion of admissibility of spaces, Leray-Schauder's alternative, and the degree theory are employed t o investigate existence r e s u l t s f o r boundary value problems i n various ways.
Some of t h e r e s u l t s
are concerned with periodic boundary conditions. We s t a t e Schauder's fixed point theorem and the contraction mapping principle i n a generalized normed space and then u t i l i z i n g these r e s u l t s , prove existence and uniqueness of solutions of a system of i n t e g r a l equations.
As an application
of the l a t t e r results, we derive existence and uniqueness theorems f o r various boundary value problems including a generalized Nicoletti problem. We present an existence and uniqueness r e s u l t f o r nonl i n e a r functional equations i n terms of the theory of set-
197
4. FUNCTIONAL ANALYTIC METHODS
valued mappings. As an application o f t h i s r e s u l t , we consider the question of existence of solutions of general l i n e a r problems. We then proceed t o develop a general theory of l i n e a r problems f o r set-valuea differential equations utilizing the fixed point theorems for set-valued mappings.
Finally, we
prove an existence r e s u l t f o r boundary value problems associated with set-valued d i f f e r e n t i a l equations.
4.1
LINEAR mOBLEM FOR LINEAR SYSTEMS
For an n-dimensional vector x nxn
(xl,.
=
r e a l matrix A = { a . . I J l e t
..,xn )
and an
1J
n
IIXII =
c
i=1
n
IXil,
lbll =
c
IbiJI*
i,j=1
Consider any compact i n t e r v a l A = [OJh] and define C(M) = C(M)[A,Rl t o be the space of continuous matrix functions A(t) = {a. . ( t ) } 1J defined on A with norm
IbII,
=
max[lb(t)II: t
E
A].
As before, C = C[A,R] w i l l be the s e t of a l l continuous vector functions x ( t ) with norm IlxII. = m [ l k ( t ) I I :
t
E
A].
L1 be the l i n e a r space of a l l r e a l n-dimensional vector functions defined and integrable i n A w i t h norm Let
Define
L,l. (M)
t o be the l i n e a r space of a l l r e a l n x n matrix
Functions A(t) = {a. . ( t ) } defined and integrable i n A with 1J the norm 198
4.1. LINEAR PROBLEMS FOR LINEAR SYSTEMS
A ( t ) E L1(M),
For any
lbllo = 1F11,.
thus L1(M)
define
Then t h e mapping J: A(t)
isometrically onto t h e subspace
continuous
3
?i(t)
Co(M) of a l l absolutely
matrix functions t h a t vanish a t
n xn
maps
t
= 0.
We w i l l a l s o be using t h e norm on A ( t )
Let
L(C,Rn)
mappings
denote the l i n e a r space of a l l continuous l i n e a r
T of
C
into
Rn
with t h e u s u a l norm
IITII = sup[llm(t)II: x ( t ) E C,
llxll0
5
11
For a given T i n L(C,Rn), !I? w i l l be t h e induced mapping of C(M) i n t o t h e space of r e a l matrices which t o every matrix A(t) of
in
C(M)
assigns t h e matrix obtained by t h e application
T t o every column of
A(t).
Hence
!I?
i s a linear
continuous mapping and T[A(t)c] = [T"A(t)]c f o r any
c
E
R".
The following preliminary lemma w i l l be important i n subsequent discussions. LFMMA 4.1.1.
function w(t)
K = [A(t)
E
For any nonnegative Lebesgue integrable
on A,
L1(M):
the s e t
I!.A(t)ll5 w ( t )
199
almost everywhere i n A1
4. FUNCTIONAL ANALYTIC METHODS
i s compact. Proof:
be any sequence i n For any i n t e r v a l
Letting
k
i s a closed s e t .
We f i r s t show K
such t h a t
K
+s]
[t,t
C
lh-Ao
A,
Now l e t t i n g s
4 0,
Lebesgue p i n t
t
lb, ( t ) 11 5 a ( t )
J(K)
i s r e l a t i v e l y compact i n
i s compact i n
it follows t h a t
continuous. compact i n
J(K)
K.
L1(M).
i s continuous, we need C,(M).
From the definition
i s uniformly bounded and equi-
By Ascoli's theorem, the s e t C(M).
a t every
and t h i s implies A o ( t ) belongs t o
Since the mapping J-l: Co(M) 4 L1(M) K,
+ m.
k
we have
it i s clear t h a t
It suffices t o show K
of
+ 0 as
we obtain
4 m,
only show t h a t
1'
{%(%)I
Let
J(K)
is relatively
Since a uniform l i m i t of equicontinuous
f'tmctions, which are absolutely continuous, i s also absolutely continuous, it follows t h a t C, (M),
i s r e l a t i v e l y compact i n
J(K)
This completes the proof.
We s h a l l consider the l i n e a r nonhomogeneous system of d i f f e r e n t i a l equations (4.1.1)
X' =
where A(t)
E
L1(M)
and b ( t )
continuous and linear. (4.1.1) (4.1.2)
A(t)x
+ b(t), E
L1.
Let
T: C + R n
be
We s h a l l be interested i n solutions of
satisfying =(t) = r
200
4.1. LINEAR PROBLEMS FOR LINEAR SYSTEMS
f o r a given
r
E
R ~ .
We now s t a t e a well-known r e s u l t exhibiting a r e l a t i o n ship between homogeneous and nonhomogeneous systems. THEOREM 4.1.1. The BVP (4.1.1), (4.1.2) has a unique solution f o r every r E Rn and every b ( t ) E L1 i f and only if the corresponding homogeneous l i n e a r BVP (4.1.3)
X’
(4.1.4)
= A(t)x,
Tx(t) = 0,
has only the t r i v i a l s o l u t i o n
x ( t ) = 0.
Proof: Let U(t) be the fundamental matrix s o l u t i o n of (4.1.3) w i t h U(0) = I. The general s o l u t i o n of (J+.Ll), then satisfies x(t)
=
where (4.1.5)
xo ( t )
=
U(t)
i s a s o l u t i o n of (4.1.1) arbitrary element of
takes the form
R
n
U(t)c + x o ( t ) ,
lt 0
U-’(s)b(s)
ds
such that x o ( 0 ) = 0 and c i s an Thus the boundary condition (4.1.2)
.
T[U(t)c + xo ( t ) ]
=
r
or
Then (4.1.6) has a unique s o l u t i o n f o r any if
201
r
E
Rn
i f and only
4. FUNCTIONAL ANALYTIC METHODS
t h a t is, i f and only i f (4.1.3) and (4.1.4) has only the t r i v i a l solution. Furthermore, when (4.1.6) (4.1.1),
(4.1.2)
(4.1.8)
i s s a t i s f i e d , the solution of
i s uniquely represented by t h e formula
x(t) = u(t)[fi(t)I-l r
- Tko( t )
+ xo ( t ) .
This completes t h e proof of Theorem 4.1.1. We now l e t
S be a s e t i n
L1(M)
s a t i s f y i n g t h e follow-
ing two properties : (i)
IklI, 5 CY
t h e r e e x i s t s a positive constant
such t h a t
CY
f o r each A ( t ) E S,
(ii)
f o r each
A(t)
in
S,
t h e BVP (4.1.3),
(4.1.4) has
only the t r i v i a l solution. From ( i i ) , it follows t h a t (4.1.1),
(4.1.2) has a unique
solution f o r each A ( t ) E S, b ( t ) E L1,
and
r
E
Rn.
I n t h e following discussion, we l e t the mapping T E L(C,Rn) and t h e vector r be fixed and only A ( t ) and respectively. b ( t ) w i l l change i n S and L1, Let Q: S xL1 C be the mapping which assigns t o each pair
(A(t), b ( t ) )
(4.1.2).
in
t h e unique solution of (4.1.1),
SxL1
!t%e continuity properties of
Q w i l l be inferred
from the Cartesian product topology induced i n t h e space L1(M) xL1 in
by t h e norm
11- 1 '
in
L1(M)
and t h e norm
11- Ill
L1,
LEMMA 4.1.2.
If the s e t
( i ) and ( i i ) , then t h e map Proof:
Q
S C L1(M)
s a t i s f i e s conditions
i s continuous.
We can consider the mapping
202
Q
C+,Q
where
4.1. LINEAR PROBLEMS FOR LINEAR SYSTEMS
Here
U(t)
denotes t h e fundamental solution of (4.1.3),
i s given by (4.1.5),
x,(t)
and x ( t )
by (4.1.8).
Let
F: L1(M) -,C(M)
denote t h e mapping which t o each A ( t ) E L1(M) assigns the fundamental matrix of (4.1.3). I n t h e commutative diagram
the mapping
%
i s continuous since from ( i ) it follows t h a t
t h e r e s t r i c t i o n of of
i s continuous.
S
follows immediately from (4.1.5)
Q1
of t h e mapping of
F(S)
F to F(S)
into
The continuity
and from t h e continuity
which t o every
C(M)
assigns i t s inverse matrix U-l(t).
U(t)
in
Finally, t h e mapping
% i s a l s o continuous since from ( i i ) it follows t h a t (4.1.7) holds f o r any U(t) i n F(S) so t h a t t h e matrix [ f i ( t ) ] ’ l i s a continuous fbnction of
U(t).
Hence, we see t h a t
Q
is
continuous thus completing t h e proof of Lemma 4.1.2. IEMMA 4.1.3.
If a compact s e t
sc
L ~ ( M ) satisfies ( i )
and ( i i ) , then there e x i s t s positive constants only on
S
such t h a t
f o r each A ( t ) Proof: -
B, y depending
in
S
and b ( t )
in
L1.
From t h e continuity of t h e r e s t r i c t i o n of the
mapping F t o the s e t follows t h a t t h e s e t
S F(S)
and from the compactness of
i s compact i n C(M).
203
S,
Defining
it
4. FUNCTIONAL ANALYTIC METHODS
(4.1.10)
Ibll,
mex
a =
UEF(S)
b* = c
we deduce easily from (4.1.5)
llxll
5
=
max
II(T%>-~II,
UEF(S)
and (4.1.8)
that
y = ac and
@ = (l+acIITll)ab*.
Thus
i s proven.
Although S xL1
IkJ'lll,
a c l r l + (l+acllTll)ab*lbI1l,
so t h a t , i n (k.l.g), Lemma 4.1.3
m a
UEF(S)
Q
does not i n g e n e r a l map bounded subsets of
i n t o compact subsets o f
f o r c e r t a i n subsets o f
t h i s property does hold
C,
I n p a r t i c u l a r , we have t h e
S xL1.
following lemma.
4.1.4. and ( i i ) and i f
If a compact s e t
D
i s a set i n
(4.1.11)
Ib(t)ll
for
b(t) E D
then
Q(SxD) Proof:
and
t
E
A,
S
C
L1(M)
satisfies (i)
L 1 such t h a t
1. m ( t >
where
m(t)
i s i n t e g r a b l e i n A,
i s a r e l a t i v e l y compact s e t i n
C.
From t h e diagram i n t h e proof o f Lemma 4.1.2 we
have
(4.1.Q) since
Q(S X D ) = %[Q1(F(S) X D ) ] , Q(S
that, for
xD) U(t)
= F(S)
in
xD.
F(S)
From (4.1.5), and b ( t )
in
(4.L.U) D,
x o ( t ) satisfy
llxo llo 5 ab*
m(t) d t
Since
204
= d.
it follows
t h e functions
4.2. LINEAR PROBLEMS FOR NONLINEAR SYSTEMS
for
<s
0
continuous. in
C(M) xC.
that
Q(S xD)
so t h a t t h e functions
Then, t h e set
%
Since
(sF(S) x D )
x, ( t )
a r e equi-
i s r e l a t i v e l y compact
i s continuous, we see, from (4.1.12),
i s a l s o compact, thus completing t h e proof of
Lema 4.1.4. 4.2
LINEAR PROBLEN FOR NONLINEAR SYSTEM3
Using t h e r e s u l t s i n Section 4.1, we prove e x i s t e n c e theorems f o r t h e BVP (4.2.1)
X'
and (4.1.2). A(t,x),
We assume t h a t t h e
and t h e vector f'unction
x f o r almost a l l t in
Rn.
= A(t,x)x
in
+
b(t,x)
nxn
matrix functions
b(t,x)
are continuous i n
A and measurable i n t
for a l l x
Assume, moreover, t h a t t h e functions
are integrable i n
A.
This implies, by t h e well-known
Caratheodory theorem, t h a t s o l u t i o n s of i n i t i a l value problems of (4.2.1) e x i s t l o c a l l y .
For a given l i n e a r mapping
T: C - t R n
and an a r b i t r a r y
r i n Rn, we consider t h e BVP (4.2.1) and (4.1.2). By an a p p l i c a t i o n of t h e Schauder f i x e d p i n t theorem and t h e
vector
r e s u l t s of t h e previous section, we prove t h e following existence theorem.
We use t h e same n o t a t i o n and symbols as i n
t h e previous section.
205
4. FUNCTIONAL ANALYTIC METHODS
TKEOREM 4.2.1. t h a t f o r any
S be a closed set i n L1(M)
Let
A(t)
E
t r i v i a l solution.
t h e BVP (4.1.3),
S,
Assume t h a t
(4.1.4)
A(t,y(t))
S
E
such
has only t h e
f o r each y ( t )
and t h a t
in C (4.2.2)
Then t h e r e exists a t least one s o l u t i o n of t h e BVP (4,2.1), (4.1.2). Proof: y(t)
E
C]
5
The closure
of t h e s e t
i s a closed subset of
g e n e r a l i t y , we may assume
S
5.
S =
N = [A(t,y(t)):
so, without loss of
From Lemma 4.1.1,
S
is
a closed subset o f a compact set and t h e r e f o r e i s i t s e l f W e have f o r
compact.
a
S
= JA a ( t ) at. Let
W: C + R n
t h a t ( i ) is s a t i s f i e d with
be the mapping which t o each y ( t )
in
C
assigns t h e unique s o l u t i o n s of
x'
(4.2.3)
s a t i s f y i n g (4.1.2). show t h a t
= A(t,Y(t))X
To prove Theorem 4.2.1.,
as signs t h e p a i r
P: C + S xL1
which t o each y ( t )
(A(t,y(t)), b ( t , y ( t ) ) )
Indeed, f o r a sequence
{yk(t)} C C
we have by t h e c o n t i n u i t y of
x,
it s u f f i c e s t o
W has a f i x e d p o i n t i n C.
The mapping
to
+ b(t,Y(t))
A(t,x)
that
206
in
C
i s continuous.
such t h a t
and
b(t,x)
with respect
4.2. LINEAR PROBLEMS FOR NONLINEAR SYSTEMS
almost everywhere i n
A
s o by t h e Lebesgue dominated convergence
theorem, we see t h a t
it follows from Lemma 4.1.2 t h a t t h e mapping
Since W = Bp,
i s continuous.
W
Furthermore, since
[y(t) E
Bk=
c:
P
l/yII 5 k ( j
maps
k =
~
J
~
J
O
.
.
SXD,, where Dk [ b ( t ) E L1: Ib(t)II 5 Bk(t), A], we i n f e r from Lemma 4.1.4 t h a t W i s a compact mapping.
into the set
t
E
F i n a l l y , from (4.1.9) we have
f o r any
y(t)
in
Bk.
From (4.2.2),
s u f f i c i e n t l y l a r g e , W maps
Bk
we see t h a t f o r
into itself.
k
Therefore W
s a t i s f i e s Schauder's theorem and has a t least one f i x e d point. This completes t h e proof of Theorem 4.2.1. From Theorem 4.2.1we MEOREM 4.2.2.
derive t h e following theorem.
If t h e r e i s a p o s i t i v e constant
6
such
that
-
J d e t f i ( t ) )> 6
(4.2.4)
i n N e [ A ( t , y ( t ) ) : y ( t ) E C] and i f (4.2.2) holds, t h e BVP (4,2.1), (4.1.2) has a s o l u t i o n . f o r every A ( t )
Proof: -
closed s e t
From Lemma 4.1.1, S =
it follows inmediately t h a t t h e
3 s a t i s f i e s condition ( i ) . 201
From continuous
4. FUNCTIONAL ANALYTIC METHODS
dependence, we obtain t h a t t h e mapping F: A ( t ) + U ( t ) continuous i n in
thus implying (4.2.4) holds f o r any A ( t )
S,
and hence the s e t
S =
is
satisfies (ii).
S
An appli-
cation of t h e proof of Theorem 4.2.1 completes the proof.
4.3
INTERPOLATION PROBLEMS We now apply Theorem 4.2.1 t o t h e well-known N i c o l e t t i
problem f o r nth-order nonlinear d i f f e r e n t i a l equations. For t h e nth-order s c a l a r d i f f e r e n t i a l equation
)...,x ( n - l > ) ,
x(n) = f ( t , x , x (1)
(4.3.1)
we consider the following problem:
tl < t2 < rl,r2,
-**
...,rn'
< tn
in
A and n
given
n
d i s t i n c t points
a r b i t r a r y r e a l numbers
does there e x i s t a solution
x(t)
of (4.3.1)
such t h a t
X(ti) = ri,
(4.3.2) Assume t h a t the s e t
AxRn,
f (t,x)
=
i = l,...,n?
f (t,x1,x2,.
continuous i n
and measurable i n t h a t there e x i s t
t n
f o r each
..,
i s defined i n
xn)
f o r almost a l l t i n A n x E R , Furthermore, assume
x
nonnegative integrable functions
p,(t), ,,. , p n ( t ) and a nonnegative function po ( t , x ) s a t i s f y ing t h e same r e g u l a r i t y conditions as f ( t , x ) such t h a t (4.3.3)
If(t,x)
I 5 p,(t>
lXll
+ P2(t)
14
+ ***
+ Pn(t)lXnI + PO(t,X),
for
k = 1,2,
...,
t h e functions
(4.3.4) are integrable i n
A,
and
(4.3.5) 208
4.3. INTERPOLATION PROBLEMS
we have
r n
1
we arrive at
We can now w r i t e (4.3.1)
i n the form
which i s equivalent t o the following system of d i f f e r e n t i a l
equations (4.3.7)
and
x!I
=
(i
xit1
=
l,...,n-
1),
n
condition (4.3.2) becomes
(4.3.8)
xl(ti)
=
( i = ly...Jn).
ri
The l i n e a r problem (4.3.7),
(4.2.1)J
(4.1.2) w i t h
209
(4.3.8) i s a special case of
4. FUNCTIONAL ANALYTIC METHODS
0
1
o . . .
0
0
1 0 . .
0
0
0 1 0 .
0
0
0
a (tJx) 1
ae(t>x)
A(tJx) =
.
. . . . . . . . . . . .
We e a s i l y see t h a t t h e family S in
L1(M)
0
.
1
.
'
an(tJx)
of a l l matrix functions
of the form
1
o . . . . .
0
0
l o . . . .
0
0
O l O . . .
. . . . . . . . . . . .
0
o o o . . .
1
. . . . . .
0
a2(t)
i s closed i n
4.1.
'
an(t>
L~(M) and s a t i s f i e s condition ( i ) of Section
Condition ( i i ) i s equivalent t o the requirement t h a t the
f'unction
x(t)
0
i s the unique solution o f t h e problem
210
4.3. INTERPOLATION PROBLEMS
n x
( 4.3 .lo)
an(t)x("-l)
=
x(ti)
= 0,
+
**.
+ a,(t>x,
i = l,...,n
w i t h the coefficients
a i ( t ) s a t i s f y i n g (4.3.9). This requirement i s equivalent t o the condition t h a t
x ( t ) = 0 i s the unique function w i t h an absolutely continuous (n 1)st derivative s a t i s f y i n g conditions (4.3.10) almost everywhere i n A, s a t i s f i e s the inequality
- -
(4.3.11)
Ix (n) ( t ) I
5 p n ( t ) Ixn-l(t> I
+ *** +
p,(t) I x ( t ) 1
Finally, from the d e f i n i t i o n of A(t,x) and (4.3.6) it follows that A ( t , x ( t ) ) E S f o r any x ( t ) i n C and that (4.3.5) implies (4.2.2). Thus, by appealing t o Theorem 4.2.1, we have proved t h e following r e s u l t : THEOREM 4.3.1.
For (4.3.1) assume conditions (4.3.3)
-
(4.3.5) hold. If x ( t ) E 0 i s t h e unique solution of inequality (4.3.11) w i t h absolutely continuous (n 1 ) t h derivative s a t i s f y i n g t h e boundary condition i n (4.3.10), then there exists a t least one solution of t h e problem (4.3.1),
- -
(4.3.2). The following uniqueness theorem follows readily.
-< 2
i=1
Assume
x(t)
=0
pi(t)Ix;-Xil.
i s t h e unique solution of
xn(t> = an(t)xn-l(t) 21 1
+
0 . .
+ a,(t>x(t>
4 . FUNCTIONAL ANALYTIC METHODS
t h derivative satisfying (n - 1 )l a i ( t ) I 5 p i ( t ) . Then there e x i s t s a unique s o l u t i o n of the BVP (4.3.1) and (4.3.2).
w i t h absolutely continuous
(4.3.10), whenever
EXERCISE 4.3.1.
Hint:
Prove Theorem 4.3.2.
Show t h a t ( 4 . 3 . E ) implies t h a t conditions (4.3.3)
-
(4.3.5) hold. Then apply Theorem 4 . 3 . 1 t o show the existence of a s o l u t i o n . The uniqueness then f o l l o w s readily. We now employ these last two theorems by giving s u f f i c i e n t
conditions on t h e f'unctions p i ( t ) and the length of t h e i n t e r v a l [a,b] t o ensure t h a t t h e only s o l u t i o n o f (4.3.10) and (4.3.1) i s the t r i v i a l solution. THEOREM 4.3.3.
n
{pi'li=l
where
Assume
with
s a t i s f i e s (4.3.3)
- (4.3.5),
satisfy
n (4 03 13)
f
c k=O
h = b -a.
one s o l u t i o n i n
hk
2%((k- 1)/2)!(k/2)! Then t h e BVP (4.3.1), [a,b
EXERCISE 4.3.2.
I.
pn-k
'
(4.3.2) has a t least
Prove Theorem 4.3.3.
Hint:
Show (4.3.13) implies t h e only s o l u t i o n of (4.3.10) and (4.3.1) i s the t r i v i a l s o l u t i o n . Then use Theorem 4.3.1. We now apply our r e s u l t t o the BVP
(4.3.14)
x"
= f(t,X,X'),
(4.3.15) Consider the system
212
4.4. FURTHER NONLINEAR PROBLEMS
( 4.3 .16)
x" = p 2 ( t ) x '
+
pl(t)x
and assume 2m
=
max lp2(t)/, t~[a,bl
k =
max
t~[a,bl
Ip,(t)l.
Consider t h e following property o f (4.3.16). LFMMA 4.3.1.
If
4m(b - a ) + k(b
(4.3.17)
- a )2 < 2 , TT
then t h e only s o l u t i o n of (4.3.16) s a t i s f y i n g x(t2) = 0
x(t,)
= 0,
is the t r i v i a l solution.
EXERCISE 4.3.3.
Prove Lemma 4.3.1.
F i n a l l y we s t a t e t h e following r e s u l t .
and t h a t (4.3.17) holds.
Then (4.3.14),
(4.3.15) has a t l e a s t
one s o l u t i o n . Proof:
The proof follows immediately from Lemma 4.3.1
and Theorem 4.3.1.
4.4
FURTHER NONLINEAR PROBLEMS We now apply t h e r e s u l t s of Section 4.3 i n a s l i g h t l y
d i f f e r e n t manner.
N a m e l y , we provide conditions o t h e r than
those used i n Section 4 . 1 t o v e r i f y t h e hypotheses of Theorem 4.2.1.
a r e l a t i o n s h i p on a term involving t h e operator p e r t u r b a t i o n term (4.4.1)
we assume
For example, i n s t e a d of condition (4.2.2),
b(t,x). X'
T
and t h e
L e t us f i r s t consider t h e BVP
= A(t)x
213
+ b(t,x),
4. FUNCTIONAL ANALYTIC METHODS
(4.4.2)
Tx
As before, l e t
U(t)
r.
be t h e fundamental matrix o f
(4.4.3)
X' =
and assume t h a t (a)
=
det[h(t)l
+
A(t)x,
0;
t h i s says t h a t t h e r e s t r i c t i o n of t h e operator TA,
T,
c a l l it
t o t h e space of s o l u t i o n s of (4.4.3) i s i n v e r t i b l e .
This
i s equivalent, a s we have seen, t o t h e fact t h a t t h e only
s o l u t i o n of (4.4.3) s a t i s f y i n g
Tx = 0
is the t r i v i a l solution.
We s h a l l a l s o suppose t h a t (b) where
Ik(t)ll
p(t)
5
P(t),
t
E
A,
i s i n t e g r a b l e on A.
Observe t h a t conditions ( a ) and (b) a r e of t h e same nature as conditions ( i i ) and ( i ) i n Sect'ion 4.2, r e s p e c t i v e b .
we
now present an existence theorem i n w h i c h w e u s e t h e v a r i a t i o n o f parameters formula as w e l l as t h e Brouwer f i x e d p o i n t theorem. MEOREM 4.4.1. satisfied. (c)
Assume t h a t conditions ( a ) and (b) are
I n addition, suppose t h a t b ( t ,x)
verifies t h e Carathgodary conditions i n
and t h a t t h e r e e x i s t s , f o r some s u f f i c i e n t l y l a r g e
RXRn
an i n t e g r a b l e fbnction (4.4.4)
b(tJx)ll
i n A,
vk(t),
5
V,(~>J
t
f
such t h a t
AJ
lkll 5 k,
and
Then t h e BVP (4.4.1), each
r
E
(4.4.2)
has a t l e a s t one s o l u t i o n f o r
R ~ . 214
k,
4.4. FURTHER NONLINEAR PROBLEMS
Proof:
We f i r s t prove t h e r e s u l t i n t h e case t h a t
i s independent of
As before, l e t U(t,)
which
t h a t is, (4.4.4)
k,
+
E
R.
0 1, define f o r each
t 5 to t
for
F ( t ) = U(t)c h
>
i
x(t) = c
where
t
for some
For each i n t e g e r
(4.4.6)
holds with
be t h e fundamental matrix of (4.4.3) f o r
U(t)
= I
vk(t) v(t) vk(t).
E
Rn
U-l(s)b(s,x(s - h / i ) ) ds,
U(t)
i s t h e length of
c
A.
The mapping
i s a continuous transformation of For each C +r
r
E Rn,
Rn
C[A,Rn].
t h e mapping
- W(k) J
.t
c
- h / i ) ) ds
U-l(s)b(s,x(s
i s then a continuous transformation of
f i r e o v e r , from ( a ) ,
into
Rn
into i t s e l f .
e x i s t s , i s continuous, and thus t h e
Ti1
mapping
(4.4.7)
- U-l(t)TihJ(t)
c +dl(t)Tilr
x
Lt
U-’(s)b(s,x(s
- (h/i)))
ds
0
i s a continuous transformation o f since
U(t), U - l ( t )
n R
a r e bounded on A,
215
into itself. we have
Moreover,
4. FUNCTIONAL ANALYTIC METHODS
llU-l(t)Tilr
t
- U-l(t)T;h(t)
U-l(s)b ( s , x ( s
Rn
hence t h e transformation (4.4.7) maps M
in
- (h/i)))
ds
i n t o a bounded set
R”.
By t h e Brouwer f i x e d p o i n t theorem t h e r e exists a
c E Rn
such t h a t (4.4.8)
-dl(t)T;h(t)
c = U-l(t)Tilr
U-l(s)b(s,x(s
xj:
- (h/i)))
ds.
0
we can f i n d ccii E M s a t i s f y i n g i such t h a t a subsequence of { c ], which we again c a l l
Therefore, f o r each (4.4.8)
{ c’],
i,
converges. Now with t h e
ci
xi defined by (4.4.6), (4.4.9)
chosen, we consider t h e corresponding that is,
Xi@) = U(t)ci + U ( t )
t
for
E
d1(s)b(s,xi(s
- (h/i))
A,
and Tx.1 = r.
(4.4.10) Furthermore, s i n c e U(t)ci = T i l r
- T’ib(t)
t
U-’(s)b
216
s,xi(s
- (h/i))
ds,
ds,
4.4. FURTHER NONLINEAR PROBLEMS
we have
Ilkt
U(t)U-l(s)b(s,xi(s
-
( h / i ) ) ) dslJ
0
-< Hence,
{xi(t)]
t o see t h a t
//%’r//+ (1f / / C I T / /
{xi(t)]
which we again c a l l
From (4.4.9) and (4.4.10),
i s a s o l u t i o n of t h e BVP (4.4.1),
{x.(t)} 1
Since
llIll = n,
sup
t, s
it follows t h a t
and from (b) we see
217
F i r s t we
Immediately we have
kJ(t)U’l(s)ll.
it follows by l e t t i n g
converges
(4.4.2).
From t h e Gronwall i n e q u a l i t y , we observe t h a t
Using (4.4.11),
v(s) ds-
it i s c l e a r t h a t
We now prove t h e r e s u l t f o r t h e o r i g i n a l case.
o b t a i n a bound on
A
a r e equicontinuous and by Ascoli’s theorem
{xi(t)]
t o a f b c t i o n y(t).
/b-J(t)U-’(s)//$
%reover, it i s easy
a r e uniformly bounded.
a subsequence of y(t)
SUP
t, s
i
+m
4. FUNCTIONAL ANALYTIC METHODS
Now assume the existence o f a k and vk s a t i s f y i n g Consider the vector defined by (4.4.4) and (4.4.5).
s a t i s f i e s Carathgodary conditions as w e l l
Obviously F ( t , x ) as
lb(tJx)ll 5 vk(t) for a l l x
E
Rn
-
and t
xf
=
E
A.
However, we have shown the problem
A(t)z + T(t,F),
-=
Tx
r
has a s o l u t i o n s a t i s f y i n g (4.4.12) w i t h v replaced by vk. Because o f (4.4.l-l) and (4.4.5), we have 1511 5 k, and thus b ( t , x ) = b ( t , x ) . Consequently, x ( t ) i s a s o l u t i o n o f the BVP (4.4.1), (4.4.2). This completes the proof of Theorem 4.4.1. C O R O L M Y 4.4.1.
Assume conditions (a) and (b).
Suppose
that
( c ' ) b ( t J x ) s a t i s f i e s Carath6odary conditions and f o r each p > 0 , t h e r e e x i s t s an integrable function v ( t ) such P
that
(4.4.13 )
llb(t,x>II 1. v p ( t >
and
218
4.4. FURTHER NONLINEAR PROBLEMS
Then t h e BVP (4.4.1), Proof:
(4.4.2) has a s o l u t i o n .
From (4.4.14),
it follows t h a t f o r
E
>
0
such
that
Now l e t
k
be chosen s o t h a t it a l s o
satisfies
Hence,
I n e q u a l i t i e s (4.4.16) and (4.4.17) imply t h a t inequalities (4.4.4) and (4.4.5) hold w i t h v k ( t ) replaced by vI(t) + Ek. Thus we may apply Theorem 4.4.1 t o assert the s t a t e d result.
219
4. FUNCTIONAL ANALYTIC METHODS
Reduce t h e conditions so t h a t t h e second h a l f of
Hint:
t h e proof of Theorem 4.4.1 i s applicable. strutting a new function
-b ( t , x )
Do t h i s by con-
which i s bounded by an
i n t e g r a b l e function by using conditions (i)and ( i i ) . t h e s o l u t i o n i s bounded by an appropriate number where
and b
Show
-b
agree.
def
TA
E
fi=
0
U&2)
0
0
0
0
0
0
-
. . . . . .
We now look a t a more g e n e r a l r e p r e s e n t a t i o n f o r t h e operator
T.
I n p a r t i c u l a r , l e t us consider t h e S t i e l t z e s
integral
220
4.4. FURTHER NONLINEAR PROBLEMS
(4.4.18)
F = F(t)
where
t
E
A.
dF
fi
i s an
X
= 1"J
nxn
Then f o r any s o l u t i o n
X E
C[A,Rn],
matrix of bounded v a r i a t i o n f o r u
of (4.4.3)
r
T = T u = T U c = A JA dF uc u A
and thus hypothesis ( a ) i s equivalent t o (4.4.19)
det L d F U # O ;
D = /A dF U has an inverse . 'iD A Hence we immediately have t h e following extension of
t h a t i s , t h e matrix Theorem 4.4.1. THEOREM 4.4.2.
Assume (4.4.19) holds as w e l l a s conditions
(b) and ( c ) of Theorem 4.4.1.
Then t h e BVP (4.4.1),
(4.4.18)
has a s o l u t i o n . REMARK 4.4.1.
I n t h e preceding r e s u l t s , namely Theorems
4.4.1 and 4.4.2,
observe t h a t we have assumed t h a t t h e range
of t h e o p e r a t o r
T
i n (4.4.2) l i e s i n
necessary as t h e range of
m.
Rn.
This i s not
T may be a subset o f
f o r any
Rm
The proofs a r e e x a c t l y t h e same where, i n s t e a d of t h e
condition Rn + R m
det
fi #
0,
i s one-to-one.
we assume t h e operator I n fact, f o r t h e case
s o l u t i o n o f t h e BVP (4.4.1),
G(t,s)
fl =
3
fi:
Rn,
the
(4.4.18) i s equivalent t o finding
a s o l u t i o n o f t h e i n t e g r a l equation
where
TA
i s t h e Green's matrix defined as
221
4. FUNCTIONAL ANALYTIC METHODS
tO+h
(-U(t)Dil
dF U(t)U-'(s)
+ U(t)U-l(s),
t < s,
Of course, a fixed point theorem could be applied d i r e c t l y t o
However, t h e proof of "heorem 4.4.1
t h i s i n t e g r a l equation.
i s quite f l e x i b l e i n t h a t it was not necessary t o assume m=n. We again consider the questions posed i n Sections 4 . 1 - 4.3, t h a t i s , finding solutions of the BVP (4.4.20)
X'
= A(t,x)x
+ b(t,x)
s a t i s f y i n g (4.4.18). L e t us now assume t h a t instead of (a),
(a')
Ib(t,x)ll
5
p ( t ) , t E A, x E Rn,
A(t,x) where
satisfies p(t)
is
integrable on A. Let
in
ti < ti+y be any i n f i n i t e sequence o f points
Eti3;=l,
A.
Consider the s e r i e s
(4.4.21)
R(t,s,x) = I
+ o t rt-
+ [If A(t,x)
U(t)U-'(s)].
j sJ
A(tl,x)A(t2,s)
dtl dt2 + * * *
S
i s independent of
x,
then
R(t,s,x) =
It i s easy t o v e r i w t h a t t h i s s e r i e s converges
absolutely and uniformly with respect t o
(t,s,x),
t,s E A
i s a continuous
and
f'unction of
x
E
Rn
and thus
R(t,s,x)
for
(t,s,x).
We have the following r e s u l t . WORE!M
A(t,x)
4.4.3.
Consider the BVP (4.4.20),
s a t i s f i e s ( a ' ) and b ( t , x ) 222
satisfies
(4.4.18) where
.
4.4. FURTHER NONLINEAR PROBLEMS
(c") v(t)
[/b(t,x)(I 5 v ( t )
i s i n t e g r a b l e on
for a l l
idet
id XEC [A,Rn]
Then t h e BVP (4.4.20),
E
AxRn,
where
A.
Moreover, assume t h a t (4.4.22)
(t,x)
Ja
dF R ( t , t O , x ) I
=
> 0.
(4.4.18) has a s o l u t i o n .
Since t h e proof i s similar t o t h a t of Theorem
Proof:
4.4.1 we s h a l l only sketch it. For a f i x e d i n t e g e r x e C[A,R*]
i,
c define
and f o r each
as
x ( t ) = c,
t ,< to, P t
we have
Using (4.4.18),
which can be w r i t t e n i n t h e form B(c)c = b ( c ) . The matrix
B(c)
t h e f'unctions
x,
vector -xandare.
b(c)
a r e continuous i n
Now condition (4.4.22) implies t h a t
B(c)
c
since
i s bounded and
By an a p p l i c a t i o n of t h e Brouwer f i x e d point
has an inverse.
theorem we can o b t a i n f o r each i n t e g e r ci which l i e i n a bounded set f o r a l l
a set of s o l u t i o n s
i, i.
Using t h e same technique as i n Theorem 4.4.1 we have t h e existence of a
y
E
C[A,Rn]
and
223
c E Rn
such t h a t
4. FUNCTIONAL ANALYTIC METHODS
n t
n
It i s not d i f f i c u l t t o show that
y
(4.4.20),
i s a s o l u t i o n of the BVP
(4.4.18). We have mentioned t h a t one application o f Theorem 4.4.1 i s the N i c o l e t t i BVP. We now show an application of Theorem 4.4.3. EXAMPLE 4.4.1.
Consider the equation
x(k) where
A
=
i s a parameter.
we derive (4.4.20)
where
,...,xk-1),
Acp(t,X,X 1 Letting
n = k
224
+
1. I n t h i s case we obtain
4 5 . GENERALIZED SPACES
We want the matrix F then t o obey the condition
s,
f
R(t,to,x)
that is, the only polynomial P ( t )
0,
of degree less than o r
equal t o k satisfying the condition
=o
i s p(t) e 0.
4.5
GENERALIZED SPACES
x,y
If
E
Rn,
we s a y
x
5y
if and only if xi L y i )
i = l,...,n.
DEFINITION 4.5.1. generalized
norm
Let E be a r e a l vector space. A for E is a mapping I)* : ,1 E - t R n denoted
bY I/xIIo = (al(x),
.
0
,an ( 4 )
such that
(a)
llxIIG 3 0,
(b)
IIXI/~=
(c)
llMllG = Ihl IIxllG, that is,
(a)
I~X+Y
ai(x) = O
+
0
that i s ,
2
cri(x)
i f and only i f
x = 0,
f o r a l l i i f and only i f
bll,
+
Ibll,,
0
for a l l i; that is,
x = 0; cri(W) = Ihlcui(x);
that is,
ai(x+y)
(.yi(Y>.
For each x E E,
and
E E
225
Fin,
E
> 0,
let
5
4. FUNCTIONAL ANALYTIC METHODS
BE(x) = [y E E: Ib-xll, < &I. Then [BE(x): x E > 0 1 i s a b a s i s f o r a topology on E.
REMARK 4.5.1.
f
E,
E E
Rn,
It i s not d i f f i c u l t t o see t h a t every
generalized normed space
(E,
I*I,)
2
has an equivalent
I~xI/~
and For example i n R , = ( lxll, 1x2 1 ) IlxII = m a x ( ( x l ( , (x2I) are equivalent. For purely algebraic (ordinary) norm.
and topological considerations, it i s immaterial whether we view
a s a generalized norm space o r an ordinary norm space.
E
Such concepts as convexity, closure, completeness and compactness remain the same.
We do, however, have more f l e x i b i l i t y working
with generalized spaces.
We s h a l l need the following terminology. An A-matrix i s a nonnegative matrix
DEIFIXITION 4.5.2. S
such t h a t
i s positive d e f i n i t e .
I-S
A p o s i t i v e d e f i n i t e matrix
such t h a t
x*Sx > 0
S w i l l be any
f o r a l l x E Rn.
n x n matrix
We w i l l use the following
properties of a positive d e f i n i t e matrix S: (i) (ii)
det S
>
0,
a l l the principalminors of
S
a r e positive
definite, (iii)
i f a l l the off-diagonal elements of
positive then (iv)
(I
a r e non-
S-l i s nonnegative,
if
i f f o r some
S
S
> ~~
m, I - S
- s)-l = C”n=0
sn.
EXERCISE 4.5.1.
then
0,
m
ciz0Sn
converges i f and only
i s positive d e f i n i t e i n which case
Prove ( i )
- (iv).
We now s t a t e the Schauder fixed point theorem and cont r a c t i o n mapping theorem i n a generalized normed space. mOREM
4.5.1.
Let
E be a generalized M a c h space and 226
4 5 . GENERALIZED SPACES
let
F
C
E be closed and convex.
continuous, then
i s completely
has a f i x e d point.
T
I n view o f Remark 4.5.1,
Proof:
T: F + F
If
we ma;y view
E
as an
ordinary Banach space with an equivalent ordinary norm. Theorem 4.5.1.
Then
becomes t h e c l a s s i c a l Schauder-Schonoff theorem,
DEFINITION 4.5.3.
Let
generalized metric f o r
E
be a r e a l vector space. A n d: E X E --f R such
i s a mapping
E
that (b)
d(xJy) = d ( y ? x ) ; d ( x J y ) 2 0 and d(x,y) = 0
(c)
d(x,z)
elements of
5
d(x,y)
+
i f and on*
d ( y J z ) J where
x = y;
if
x, y, z
a r e any
E.
THEOREM 4.5.2. space and l e t
Let
T: E + E
E
be a complete generalized metric
such t h a t
d(=?S) 5 Sd(xJy), where
S
i s a nonnegative matrix such t h a t f o r some m, Sm
i s an A-matrix.
Then
F’urther f o r any
x E E
T
has a unique f i x e d p o i n t
x*.
and
We leave t h e proof a s an exercise. EXERCISE 4.5.2.
Hint:
Prove Theorem 4.5.2.
Use ( i v ) t o show T?x 227
i s a Cauchy sequence.
4. FUNCTIONAL ANALYTIC METHODS
Then use the same arguments as i n the c l a s s i c a l case. COROLLARY 4.5.1.
space and l e t
T: E
Let 4
E
E such t h a t
d(%Ty)
where S such t h a t point
x*
be a complete generalized metric
_< Sd(X,Y),
i s a nonnegative matrix.
If there i s an xo E E Snd(Txo,xo) converges, then T has a fixed such t h a t
xiZo
x*
= lim F X o . n,tm
4.6
INTEGRAL EQUATIONS Let
J = [a,b]
be a fixed i n t e r v a l and l e t
be a vector such t h a t
M.
..,pn)
We w i l l consider the space
[ J ] i s the space of Lebesgue pi-integrable functions. pi i s a generalized Banach space with the generalized norm
where
L P
1 5 pi 5
p = (pl,.
L
b
To avoid confusion, i f f ( t ) = Ja g ( t , s ) ds and f E L b P' Ilfllp. We wish t o consider a then we write 111, g ( t , s ) dsllp vector i n t e g r a l equation (4.6.1) where
F [ x ] ( ~ )= K: J X J x R n + R n
b
J'a
K(t,s,x(s)) ds
and b: J -+R
operator defined by
228
n
.
+ b(t), Let
K be the
4.6. INTEGRAL EQUATIONS
nb - K(t,s,x(s))
K[x](t) =
a
We w i l l denote t h e i t h coordinate of
K(t,s,x)
...,Kn(t,s,x)).
K(t,s,x) = (%(t,s,x),
hence
ds. by
Ki(t,s,x);
A similar
notation w i l l be employed f o r other vector-valued functions. We s h a l l need t h e following assumptions: (HI) that is
K. ( t , s , x ) 1
K.(t,s,x)
s a t i s f i e s t h e Carathe'odory conditions; i s continuous i n
1
and measurable i n
(t,s)
x
f o r each fixed
f o r each fixed
x.
(5) //K(t,s,x)llG5 M ( t , s ) / / x / l G + r ( t , s ) ,
M: J
XJ
(t,s)
where
i s a nonnegative measurable matrix-valued r: J X J 3 Rn i s a nonnegative measurable vector-
Rn2
function and
valued function.
.
( 5 ) f o r some
p = (pl,. . , p ) t h e operator M defined n by M[x](t) = ./,[M(t,s)x(s) + r ( t , s ) ] ds maps L into L b P P' where S M(t,s)x(s) ds$ 5 S//x$,, x E L (H4) P' i s a nonnegative matrix such t h a t f o r some m, Sm i s m Ab
I/. ,
matrix
.
(Hg) ( i )
IIK(t,s,x)
(ii) LEMMA 4.6.1.
t h e operator
If
K maps
EXERCISE 4.6.1.
Hint: -
- K(t,s,Y)IIG 5 M(t,s)IIx
IIK(t,s,O)IIG
5
-
s a t i s f i e s (H1) (%), then
K(t,s,x) L P
into
L P'
Prove Lemma 4.6.1.
i s a simple function and show
F i r s t assume x(s)
t h a t t h e a s s e r t i o n holds.
Then assume
measurable function and show t h a t Let
x E L
P
-YIIG,
r(t,s).
and using (H2), (H )
3
x(s)
i s an a r b i t r a r y
K(t,s,x(s)) conclude t h a t
i s measurable. Ki(t,s,x(s)) E
L (J2). An immediate application of f i b i n i ' s theorem yields pi the r e s u l t . 229
4. FUNCTIONAL ANALYTIC METHODS
THEOREM 4.6.1.
(i)
b(t)
E
-
L
Assume t h a t (H1) - (H4) are s a t i s f i e d and
P’ t h e operator
-+ L i s completely continuous. P P Further any fixed point x Then F has a fixed point i n L P of F i n L satisfies P
(ii)
K: L
.
We w i l l apply Theorem 4.5.1 t o obtain o u r r e s u l t .
Proof:
+ b(t),
F: L 3 L i s completely P P continuous from ( i i ) ; it i s s u f f i c i e n t t o show t h a t there
Since F [ x ] ( t ) = K[x](t)
e x i s t s a closed convex s e t which i s invariant under
-
F.
Now we have from (H2) (H4)
where
11 =
Section 4.5, ‘J
111,b r ( t , s )
-1 = (I-S) q.
ds$
+
(/b(/p. By property (iv) i n
i s invertible and
I-S
Then
S‘J
+
11
=
B = [X E L
u,
.
P’
B
Thus
4B
F: B
and, by Theorem
Let
Define
llxll,
i s closed and convex.
Obviously
(I-S)-’ > 0.
5 ‘J1. For
x
E
B,
we have
4.5.1, F has a t l e a s t one
fixed point i n B. hreover, if
x
i s any fixed point of
that 230
F,
we obtain
which implies
and since
-
(I S)"
2 0, we conclude t h a t
( 5 )-
Assume t h a t (H1), ( € I 5 ) are s a t i s f i e d and t h a t b ( t ) E L Then F has a unique fixed point x* E L P' P' Further for any x E L we have P' THEOREM
4.6.2.
x*(t) = lim Fn[xl(t) n-)m
and
23 1
4. FUNCTIONAL ANALYTIC METHODS
where
S
>0 -
and f o r some m, Sm i s an A-matrix.
Theorem 4.5.2,
Hence by
F has a unique f i x e d p o i n t which m a y be
obtained by successive approximations. Theorem 4.5.2 implies (4.6.2)
The estimate i n
holds thus concluding t h e proof
of Theorem 4.6.2.
4.7
APPLICATION TO EXISTENCE AND UNIQUENESS
In t h i s s e c t i o n we wish t o consider t h e BW x'
(4.7 1)
= f(t,x)
n
, By a s o l u t i o n of (4.7.1) and (4.7.2), we mean an a b s o l u t e l y continuous m c t i o n which s a t i s f i e s f : JxRn + R
where
(4.7.1) 0
almost everywhere and passes through t h e p o i n t s
(ti+
If we l e t
y = x-x
0
0
0
x = (x1,x2, 0
transforms (4.7.1)
...
0
), then t h e s u b s t i t u t i o n n and (4.7.2) i n t o ,X
Solving (4.7.3) and (4.7.4)
i s equivalent t o f i n d i n g a
f i x e d point of t h e i n t e g r a l operator
(4.7.5)
Gi[YI(t) =
gi(S,Y(S))
232
G[yl(t)
given by
i = l ~ * * * ~ n *
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
LEMMA 4.7.1.
The following i d e n t i t y holds.
i n which 1, -1, 0,
ti 5 s 5 t, t < s < ti, otherwise.
Hence (4.7.6) holds. We now s t a t e our main existence r e s u l t , a s p e c i a l case o f which i s t h e N i c o l e t t i BVP considered i n Section 4.3.
THEOREM 4.7.1.
Assume t h a t
233
f(t,x)
satisfies the
4. FUNCTIONAL ANALYTIC METHODS
Carath6odory conditions and t h a t
(ii)
t h e r e i s a matrix
Sm i s an A-matrix and
Then t h e BVP (4.7.1), Moreover any s o l u t i o n x*
n q E R,
where
(4.7.2) has a s o l u t i o n x* E L P satisfies t h e estimate
lIx*-x O IIP
(4.7.8)
Proof:
such t h a t f o r some m,
S = (u. .) =J
5
.
(I-s)-lq,
and
We first observe t h a t
continuous function of
t
;1
i
a
ij
(s)"
ds
is a
so t h a t t h e left-hand s i d e of (4.7.7)
i s defined. We w i l l apply Theorem 4.6.1 t o show t h a t t h e operator
G
given by
where in
L
P' (4.7.1),
K(t,s,y)
i s defined i n Lemma 4.7.1,
has a f i x e d point
By our previous remarks t h i s w i l l imply t h a t t h e
(4.7.2)
has a s o l u t i o n . 234
BVP
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
We now show hypotheses (H1) and ( i i ) of Theorem 4.6.1. V e r i f i c a t i o n of (H1).
- (H4) hold
as w e l l as (i)
We have
K i ( t J s > y ( s ) ) = q i ( t J s ) g i ( s J Y ( s ) ) = $ i ( t J s ) f i ( sJY(s) + Since
fi
xo)*
s a t i s f i e s t h e CarathGodory conditions so does
gi(t,y) = fi(t, y+xo). be measurable,
Hence
Moreover
qi(tJs)
Ki(t,s,y)
i s e a s i l y seen t o
s a t i s f i e s t h e Carathgodory
conditions, verifying (H1). V e r i f i c a t i o n of (H2).
We observe t h a t
n
n
Thus
where
and
ri(tjS) =
n
C
M. . ( t , S )
j=1
Hence
(%)
IX.0
J
‘J
I
+ Iqi(tJs) Ici(s).
i s verified.
V e r i f i c a t i o n of (%).
Let
235
y E L
P
,p =
(plJ ...,pn);
4. FUNCTIONAL ANALYTIC METHODS
then
n
Applying Tonelli's theorem t o t h e positive and negative p a r t s
/,b
En M. . ( t , s ) y . ( s ) j = 1 ij
of (4.7.9), we see t h a t is a measurable function of
J
t.
we have
where
a
ij
Ni =
(s)
E
Since
Ll[a,b].
a
ij
1
ds
(s) E Lqj[a,b], q > 1,
3-
Therefore our estimates y i e l d
cYz1 llaijllqj 1bj"p. +
constant depending only on conclude
1b71
a i j ( s ) ds Since
F'
n
c
ds
Furthermore,
+ ci(s)
from Holder's inequality.
+ri(t,s)
Mij(t,s)y.(s) J
+ ri(t,s)
236
ci E L , we Pi
is a
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
Thus
(3) holds. Verification of (Hk).
in (ii).
Let
We wish t o show
that is,
For a fixed
i,
let
Then
237
S = (a ) ij
be the matrix given
4. FUNCTIONAL ANALYTIC METHODS
n
(by Holder s i n e q u a l i t y )
n
Hence (H4) i s s a t i s f i e d . A l l t h a t remains i s t o v e r i f y conditions ( i ) and ( i i ) of Theorem 4.6.1. We observe immediately t h a t b ( t ) F: L since P 0. Hence ( i ) holds. i n t h e case under consideration b ( t )
V e r i f i c a t i o n of ( i i ) .
L +L P
P
We show t h a t t h e operator
G:
defined by
i s completely continuous.
To prove t h i s we w i l l use Helley's
f i r s t theorem which we s t a t e here.
HELLFX'S FIRST THEOREM.
Let
bounded family of fhnctions on 238
3 be a n i n f i n i t e uniformly
[a,b]
whose members a r e
4.7, APPLICATION TO EXISTENCE AND UNIQUENESS
uniformly bounded in variation; that is, there is an M > 0 b [ f1 is the such that for each f E 5, v [f1 1. M, where a a total variation of f on [a,b]. Then there is an infinite
'?
sequence in 5 which converges pointwise on
[a,b].
Now let
B where (cy1,a
=
[Y E LP'* IIY/IpI a],
is an arbitrary element in RY, that is, cy cy ), cyi 2 0, i = 1, n. Then for each y n
cy
*,...,
...,
= E
B
and hence
2
Mi,
where Mi only depends on a.
239
Thus for each y
E
B, Ki[y]
4. FUNCTIONAL ANALYTIC METHODS
are uniformly bounded in variation on [a,bl. Since K.[y](ti) = 0 for each i, we conclude that IKi[y](t)l 1
5 Mi;
that is, K.[y] are uniformly bounded for y E B. 1 Let y (t) be any sequence in B and apply Helly's first
n
theorem to select a subsequence, again denoted by y,(t), such that K[yn](t) converges pointwise on [a,bl to some function z(t). Since IKi[yn](t)( 5 Mi, we have by the Lebesgue dominated convergence theorem that IIK[yn] Thus K: L + L
P
P
- zllp + 0
as n + m.
is completely continuous and hence (ii) is
satisfied. Hence we apply Theorem 4.6.1 to obtain a solution y(t) of (4.7.3), (4.7.4). n u s x(t) = xo + y(t) is a solution of
(4.7.1), (4.7.2). We also have from Theorem 4.6.1 that
where
This completes the proof of Theorem 4.7.1.
REMARK 4.7.1.
Our proof of verifying (ii) essentially
handles the case when p i < m for all i. If all pi> 1, then all p i < m and we may apply Ascoli's theorem to verify
(ii). Then the general case in which 1 5 pi 5 m follows by combining the cases 1 5 pi C m and 1 C p i s m. We now apply Theorem 4.6.2 to obtain a unique solution of
(4.7.1), (4.7.2).
240
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
THEOREM 4.7.2.
Assume t h a t
satisfies t h e
f(t,x)
Carathhodory conditions and t h a t
(l/Pi)
+
(ii)
t h e r e exists a matrix
where f o r some m,
s"
= 1;
S = (u. .) 1J
i s an A-matrix.
(4.7.2) has a unique s o l u t i o n x*
2
0
such t h a t
Then t h e BVP (4.7.1),
L Moreover, x* P' be r e a l i z e d by successive approximations and satisfies E
can
where
Proof:
We wish t o apply Theorem 4.6.2 t o t h e operator
G
given by
Since much of t h e argument i s t h e same as in Theorem 4.7.1 we w i l l only sketch t h e proof.
As i n Theorem 4.7.1, K ( t , s , y ) s a t i s f i e s (H1). Moreover (H3) and (H ) follow a l s o as i n Theorem 4.7.1. 4 V e r i f i c a t i o n of (H ). We f i r s t show ( i ) of (H?) holds.
5
24 1
4. FUNCTIONAL ANALYTIC METHODS
Observe t h a t
we immediately have t h a t (ii) of ( H ) i s s a t i s f i e d with
5
r i ( t , s > = Iti(t,s)fi(s,xo)I Observe t h a t (H2) follows from (H ), (H1),
5
Theorem 4.6.2 may be applied t o t h e operator
a unique s o l u t i o n p
of (4.7.3) and (4.7.4).
and ( i ) . G
Thus
t o guarantee Hence x * ( t ) =
x o ( t ) + y*(t) i s t h e unique s o l u t i o n of (4.7.1), (4.7.2) and x* E L Moreover x* can be obtained by successive apP proximations. Finally, by l e t t i n g yo = 0 we have from
.
Theorem 4.6.2 t h a t
which implies
This completes t h e proof of Theorem 4.7.2. I n both Theorems 4.7.1 and 4.7.2 we observe t h a t i f 242
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
i s continuous i n both
f(t,x) C(l)
t
and
then we o b t a i n a
x,
s o l u t i o n of t h e BVP. We now study t h e BVP
(4.7.10) (4.7.11) where
+ f(t,X,X')
XI1
.(a)
f : [a,b]
=
0,
= x(b) = 0,
xRz + R .
Using t h e Green's function we o b t a i n some i n t e r e s t i n g estimates on t h e s o l u t i o n s of (4.7.10),
(4.7.11) by applying
the previous techniques of t h i s s e c t i o n . R e c a l l t h a t t h e Green's function xtt = 0, x ( a ) = x(b) = 0
G(t,s)
associated with
is
(s
- a)(b - t)/h,
s
5 t,
(t
- a ) (b - s)/h,
s
2
G(t,x) = where
h
=
b-a.
t,
Then a s o l u t i o n x ( t ) of
(4.7.12)
XI1
+
f(t) = 0
s a t i s e i n g (4.7.11) has t h e form (4.7.13)
G ( t , s ) f ( s ) ds.
We now o b t a i n an existence r e s u l t f o r t h e BVP (4.7.10), (4.7.11) a s w e l l a s estimates on t h e
L1 norm and
of t h e s o l u t i o n s ( i n Chapter 1 we discussed t h e THEOREM 4.7.3. cy
and
@
Let
L,
f ( t , x , y ) E C[[a,b] x R 2 , R ]
be nonnegative numbers such t h a t (cyh2/4)
+ Bh < 1.
243
L2 norm norm). and l e t
4. FUNCTIONAL ANALYTIC METHODS
If(tJxJy)
I
_< ~ 1 x 1+
BIYI
r(t>J
+
r ( t ) E L1[aJb], then (4.7.10), (4.7.11) has a s o l u t i o n . Further every s o l u t i o n s a t i s f i e s
where
(4.7.14) and
(4.7.15) (b)
If
(t JxlJY1) - (t J x2JY2) I 5 a I x1- x2 1
I
+
@ lY1- Y2 IJ
(4.7.11) has a unique s o l u t i o n satisfying (4.7.14) and (4.7.15) w i t h r ( t ) = f(t,O,O).
then (4.7.10),
Prove Theorem 4.7.3 by using Theorem
EXERCISE 4.7.1.
4.6.1 i n (a) and Theorem 4.6.2 i n (b). Here our generalized space E i s the space of % flxnctions x ( t ) = (x,(t),x,(t)) w i t h norm IIxII1 = ( IlxllI1~ Ih2111). A similar theorem i s now presented f o r the (.12 norm. THEOREM 4.7.4.
f ( t J x J y ) be continuous and l e t a and p be nonnegative constants such t h a t Let
(ah
2 2 /TI- ) + (@h/.rr) < 1.
(a> If I f ( t J x J ~ ) l5 ~ 1 x 1+ where
r(t)
E
BIYI
L2[aJb], then (4.7.10),
+
r(t>J
(4.7.11) has a solution.
Every solution s a t i s f i e s moreover,
(4.7.16)
IIX
12
5
h2 2
T ~ - C -p-rrh Y ~
244
Ilr
12
4.7. APPLICATION TO EXISTENCE AND UNIQUENESS
and (4 7.17 1
then (4.7.10),
(4.7.11) has a unique s o l u t i o n which s a t i s f i e s (4.7.16) and (4.7.17) w i t h r ( t ) = f(t,O,O). EXERCISE 4.7.2.
Prove Theorem 4.7.4.
We now wish t o consider t h e BVP
( 4.7.18)
X"
+ A2x .(a)
(4.7.19)
=
f(t,X,X'),
=
x(b)
= 0,
where f : [a,b] xR2n - t R n and A i s a constant matrix of order n. Using the techniques of Chapter 1, we consider the associated nonhomogeneous l i n e a r problem (4.7.20)
X"
2
+A x
= f(t)
and express t h e solution of (4.7.18),
(4.7.19) i n terms of the
Green's function f o r the problem 2
( 4.7.21)
X" + A X = 0
and (4.7.19).
I n order t o guarantee t h e uniqueness o f solutions of
(4.7.18) and (4.7.19), and hence the existence of a Green's fwnction, we assume the eigenvalues o f A, j = lJ**-Jn have the property t h a t
SJ
(PI
hj
#
kTr/(b-a),
k = O,It:1,+2,
This allows us t o deduce t h a t s i n A(b 245
- a)
... . i s i n v e r t i b l e and
4. FUNCTIONAL ANALYTIC METHODS
we may obtain, a f t e r some computation, t h a t the Green's function is
G(t,s) =
{
A-'(sin
Ah)"
s i n A(b
-t)
s i n A(s
- a),
s
A-'(sin
Ah)-1 s i n A(b
- s)
s i n A(t
- a),
s >t.
(4.7.20), (4.7.19) i s
Hence, the unique solution of x(t) = further, x'(t)
s,"
=J
b
a
5 t,
G ( t , s ) f ( s ) ds;
G t ( t , s ) f ( s ) ds.
To obtain an existence theorem f o r t h e BVP (4;7.18), (4.7.19) we need t h e following preliminary computations. If B = (bij) i s a matrix of order IBI
5
ICI,
n,
then l e t
IB
I
=
(
then
Ic W
sin BI =
2k+l
2k+l
k=0
1.
a,
- k=0
Similarly, lcos
BI
5
(e
1'1 + e-ICI)/z.
We now present an existence theorem. 246
lbij
I ).
If
4.1. APPLICATION TO EXISTENCE AND UNIQUENESS
THEOREM 4.7.5.
Let
f ( t J x J y ) be continuous and assume
that + r ( t ) , where P and (a) IIf(t,X,Y)IIm _< PllxII, + Qb//, n a r e nonnegative constant matrices and r E C[[a,b],R+].
Assume t h a t t h e eigenvalues of
be a nonnegative
A
have property (P).
2 n x 2 n matrix i n which
Moreover, assume f o r some m, Sm i s an A-matrix. BVP (4.7.18),
solution
(4.7.19) has a s o l u t i o n .
x(t)
R e c a l l here
r(t)
=
f(t,O,O). Prove "heorem 4.7.5.
A solution x ( t )
satisfies
rb
247
Then t h e
Furthermore any
o f (4.7.18) and (4.7.19)
EXERCISE 4.7.3. Hint: -
Let
satisfies
Q
4. FUNCTIONAL ANALYTIC METHODS
Apply Theorem 4.6.1 where now the operator i s defined as
F = (F1,F2)
and
Show t h e hypotheses of Theorem 4.6.1 a r e s a t i s f i e d i n a manner similar t o t h a t used t o prove Theorem
4.6.1. The only new
point i s t h e v e r i f i c a t i o n of (H ). I n t h i s case show
4
and
This then implies
IM(t,s)l
-<
(l/h) S
and thus
The conclusion of the theorem follows readily.
4.8
METHOD OF A PRIOR1 ESTIMATES Here we s h a l l present theorems on the existence of
solutions of boundary value problems, with both l i n e a r and nonlinear boundary conditions, using t h e method of "a p r i o r i estimates. "
This technique can be described as follows. 248
4.8. METHOD OF A PRIOR1 ESTIMATES
Suppose t h a t it i s required t o prove t h e existence of a solution, where t h e solution i s chosen from some topological space
i n other words, it i s required t o show t h a t a
H;
c e r t a i n subset
H
G
of t h e problem).
i s nonempty (the subset of solutions
To do t h i s , we construct a sequence of
problems of a s i m i l a r type, t h a t i s , a sequence of s e t s
..,
G _C H (p = 1,2,. ) approximating the o r i g i n a l problem P i n t h e sense t h a t g E G (pk --f CQ), g + g implies t h a t k' k ' k ' > 0, h g E G. We f'urther construct a s c a l a r function w(h) -
E
which w i l l give an estimate such t h a t t h e condition EG w(gp) P P subsequence g
""*g
<
w i l l imply t h e existence of a convergent
CQ
+g. Finally, it i s shown t h a t each of t h e *k satisfyapproximating problems has a t l e a s t one solution g P ing sup w(gp) < CQ. This implies t h a t G i s nonempty. P Suppose i n some l i n e a r topological space H we have a
set
G
5H
and a mapping
L of t h e space
H
into
Rn.
We
a r e i n t e r e s t e d i n showing t h e existence of a solution of t h e problem (4.8.1) where
a
E
i s given.
Rn
value problems,
I n applying t h e method t o boundary
i s t h e s e t of solutions of t h e given
G
Assume t h a t there e x i s t s a s c a l a r
d i f f e r e n t i a l equation.
lower semicontinuous function w
in
H
s a t i s f y i n g the in-
equalities 0
(4.8.2)
-< w(h) -<
w(ah)
w(h1 + h2)
CQ,
5 w(h)
whenever
,< w(hl) 0
+ w(hZ),
< a < 1.
Suppose t h a t t h e following conditions a r e s a t i s f i e d : (i)
The operator
continuous operators
L
can be w r i t t e n as t h e sum of two
LO + L ~ ;
249
H,
4. FUNCTIONAL ANALYTIC METHODS
(ii)
there e x i s t s a s e t
0 G
0
(4.8.3)
v
depends continuously on
0
0
f o r any
a E Rn
and t h e solution
a;
there e x i s t s a "comparison problem"
(iii)
*
0 Y E G ,
where
f o r which the problem
L v = a
V E G ,
has a unique solution
-C H
Ly=b,
i s a continuous operator mapping
L*
H
into
R"
e x i s t s and i s unique f o r any b E yb X C Rn, we have supybEGow(yb) < m.
whose solution f o r any sphere
8
and
The preceding conditions guarantee the existence of an operator
A
defined as
= L*V a
Aa
which i s a continuous, one-to-one mapping of and i s hence a homeomorphism.
where
B
(iv) that
E
Rn
into i t s e l f
Thus
.
-1 A
The s e t
g E G k' k' and f o r any b
G
and E
Rn
can be approximated by s e t s
g + g as pk + m implies t h a t k ' each of t h e problems
st
P
g E G;
L*s = b
s E G P' has a unique solution
such
G
depending continuously on b
n = sup w(s,p -Yp) < PER b cRn
250
m.
and
4.8. METHOD OF A PRIOR1 ESTIMATES
(v) The condition sup w(gp) < m implies the existence P of a convergent subsequence g + g. P ( v i ) For any M > 0 and b y a E Rn, there e x i s t s a sphere
such t h a t f o r any b E X, s E G, w(s
X C Rn
- yb) < M,
we have 0
A ( L yb THEOREM
- LS + a )
X.
E
I f conditions ( i )
4.8.1.
- (vi)
are s a t i s f i e d ,
then the problem (4.8.1) has a t l e a s t one solution.
sphere X
M = 1+
Let
Proof:
and f o r the given
according t o ( v i ) .
of the space
Define mappings
i n t o i t s e l f by the formula
Rn
a,
choose the
T P
(p = 1,2)
0 b T b = A ( L y -Ls + a ) P b p Xp = T X.
and s e t
same center as f o r any for
p
an
E
k
+ w
E
and
X,,
> 0,
E
with a radius
X
> 1,
> p,. >1
Let
P
be a sphere having the times greater.
E
that there exists a
p
E
such t h a t
Suppose the claim i s f a l s e . and a sequence
%=T
*k
k
#
b
XE.
b
k
E X
Set
-< sup w(s;-yb) p,b
by condition ( i v ) . a subsequence
sk = s , bk +
Xp
- XE
C
Then t h e r e e x i s t s
such t h a t
W(Sk)5 s'p(w(Sk-Y k bk
We claim,
w(Y
+bo k then
bk
b
as
1)
+ sup W(Yb) < b EX
w
Then ( i v ) and (v) imply the existence of
s of ki
s k' 'ki
25 1
+s
E G.
Hence
4. FUNCTIONAL ANALYTIC METHODS
since t h e lower semicontinuity of w(s - y
implies t h a t
'ki ) < inf w(sb - y b ) < M. bo - i ki ki
However, then, f o r i
w
s u f f i c i e n t l y large,
I
%.
for a l l
E XE
1
-> I.
This i s a contradiction and t h e claim i s proved.
Hence Xp C -X
for
E
p
s u f f i c i e n t l y large.
we have by t h e Brouwer fixed point theorem
T X + X p E XE, P: t h a t f o r each p
there exist
b E X P
Tb = b PP P hbreover,
E
P
--f
Since
0
p + M.
as
A ( L 0yb
P
+ &
and
E
P
such t h a t
P'
Hence, t h e equality
Lsb P + a) = b + E P P P
implies t h a t 0
LSp
bP
= a + L y -B(b bP P =E+Bb
Since
P
sup w(sEp) < P
+ E )
P
we obtain from (v) the existence of a
of
sp
Isbpi }
and thus
Pi P i s a solution of (4.8.1).
REMARK 4.8.1. Go
b
Pi sb + g , Lsbpi + a
such t h a t
If the operator
Pi Lo
1
basis f o r
G
,
Pi
i s linear, the s e t 2 , , vn i s some
i s l i n e a r and n-dimensional, and v , v 0
p+m.
M,
subsequence g
as
=B(b + & ) + a P P
...
then the statement t h a t the problem (4.8.3)
i s uniquely solvable and t h a t t h e solution depends continuously
252
4.8. METHOD OF A PRIOR1 ESTIMATES
on
a
i s equivalent t o the statement t h a t the determinant
A
=
0 1 0 2 On det(L v , L v ,...,I, v )
is nonzero.
We apply now the r e s u l t s t o t h e boundary value problem
$(x
l J . . . Jm )~=
a k
(k = l J . . . , n J
where
fi
a l l ni
>
where
n = n
1
+
.- -
(nm-U a r e defined f o r t E [ t1' t 2 1, -m < x 1, ,xm < 0, and the f'unctionals are defined on the s e t
...
4
of functions
derivatives
x ( t ) = { x i ( t ) ] J tl 5 t 5 t2, f o r which a l l the (ni- 1) xi are absolutely continuous. We assume
s a t i s f i the Carath6odoqy conditions; t h a t is, f i s (nm4 measurable i n t f o r fixed xlJ...,x , continuous with m (nm4 respect t o (xlJ...,x ) f o r each fixed t, and f o r any m M > 0 there e x i s t s an integrable fhnction M ' On (tl't2) such t h a t Ifi/ 5 f M ( t ) f o r a l l i and t E (tlJt2), and that
IIx II
fi
< MJ We m a y write problem (4.8.4) i n the form
(4.8.5) Here
Dx = 0, H
Lx
=
a.
i s the space of functions
x ( t ) = {xi(t)], (ni-1) f o r which a l l the derivatives x are
tl 5 t 5 t 2 J absolutely continuous and the norm on H i s
253
i
coJ
4. FUNCTIONAL ANALYTIC METHODS
n -1
m IIX
Let
max
=
1
be the s e t of solutions of
G
The operator then
It
i
Dx = 0,
where
i s obtained from D by s e t t i n g a l l f
Do
i s the s e t of a l l solutions o f t h e equation
Go
0
i
= 0,
Dx=O. Let t h e comparison problem be the Cauchy problem 0
Dy=O
We thus have t h e following r e s u l t . Suppose t h a t t h e following conditions are
THEOREM 4.8.2.
s a t i s f ied: (i) xi,
Let
...,xm( n m 4,
0 L = L
(ii)
+
L
5
where
fo(t)
where
Lo
t
for
E
L
and
L1
a; (iv) a sphere X
For any M C
Rn
>0
[tl,t2];
a r e continuous operators i n
The boundary value problem
a unique solution f o r any
and all
can be w r i t t e n i n t h e form
H; (iii)
[tl,t2]
i s integrable on
fo
The operator
,
1
Ifi\
0
0
D v = 0, L v = a
has
a E R ~ , depending continuously on and f o r any
such t h a t for any
254
a E Rn,
b E X, s E G,
there e x i s t s and
4.8. METHOD OF A PRIOR1 ESTIMATES
w(s
- yb)
< Mj we have 0
A ( L yb
-b
+ a)
E
x
(see t h e n o t a t i o n i n Theorem 4.8.1). Then t h e BVP (4.8.5) has a t l e a s t one s o l u t i o n . Proof:
We use Theorem 4.8.1 t o prove t h e r e s u l t ; it
thus s u f f i c e s t o v e r i f y conditions ( i v ) and (v) of Theorem
4.8.1, s i n c e conditions ( i ) - ( i i i ) , ( v i ) follow immediately, Observe t h a t each
f
i
can be approximated by
is Lipschitz and s a t i s f i e s an estimate of t h e form Ifi
P
I
_< f o ( t ) , where
fo(t)
i s i n t e g r a b l e on
f
i P
[tlJt2].
which Then
conditions ( i v ) and (v) follow from t h e Lipschitzian p r o p e r t i e s
, t h e d e f i n i t i o n of w(x), and t h e continuous dependence P of d i f f e r e n t i a l equations on i n i t i a l d a t a . This concludes t h e of
fi
S i m i l a r l y t h e following r e s u l t s may be
proof o f Theorem 4.8.2. obtained. THEOREM 4.8.3. 4.8.2 hold. If Lo Q
> 0,
p = constant
-
Suppose conditions ( i ) ( i i i ) of Theorem i s p o s i t i v e l y homogeneous (Loax = Q PLx,
> 0)
and f o r any
lim lla-PL1axll = 0, a400 sP ' w (x) < M a t l e a s t one s o l u t i o n . EXERCISE 4.8.1.
THEOREM 4.8.4.
M
> 0,
we have
then t h e BVP (4.8.5) has
Prove Theorem 4.8.3. Suppose t h a t conditions (i) and ( i i ) of
i s l i n e a r , A # 0, -1 1 and f o r any M > 0 we have limwm S U ~ ~ ( )la~ )L ax11 < ~= 0 , then t h e BVP (4.8.5) has a t l e a s t one s o l u t i o n . Theorem 4.8.2 hold.
EXERCISE 4.8.2.
If t h e operator
Lo
Prove Theorem 4.8.4. 255
4. FUNCTIONAL ANALYTIC METHODS
REMARK 4.8.2.
Observe t h a t i f the boundary operator L 0 1 i s linear, then we may assume L = L and L = 0. Then Theorem 4.8.4 essentially says t h a t the BVP (4.8.5) has a 0 0 solution i f the problem D x I 0, L x = 0 has only the t r i v i a l solution. This r e s u l t has been proved using other techniques i n Section 4.3. 4.9
BOUNDS FOR SOLUTIONS W ADMISSIBU SUBSPACES
I n t h i s section our treatment of the previously considered BVP
(4.9- 1)
X' =
(4.902)
A(t)x + f ( t , x ) , LX = r,
is quite different from that of e a r l i e r sections.
I n particular,
t h e treatment r e s t s on a characterization of the class of linear
d i f f e r e n t i a l equations (4.9.3)
X'
= A(t)x
+ b(t)
f o r which there e x i s t s a solution satisfying (4.9.2). Let J be any compact i n t e r v a l and we mqf think of L as a continuous linear mapping from C[J] onto Rn. Denote by V the inverse image of any r E Rn. W e see t h a t V is a closed l i n e a r variety o f codimension m i n C. W e first examine under what conditions (4.9.3) has a t least one solution belonging t o V whenever b E C = C[J,Rn], Corresponding t o some fixed t o E J, define cp: C - + C t o be the mapping which associates w i t h each b E C the particular solution of (4.9.3) that equals 0 a t to; that is,
256
4.9. BOUNDS FOR SOLUTIONS IN ADMlSSIBLE SUBSPACES
where U(t)
i s a f'undamental matrix of
x' = A(t)x.
be the mapping whose value a t each
Y: Rn + C
solution of
x ' = A(t)x which equals
s at
s
E
Let i s the
Rn
to; t h a t i s
Jr(s) = u(t)v-~(t,)s.
Thus every solution x
of (4.9.3) has the unique representation
x = +(s)
s = x(t,).
+
cp(b)
where
(4.9.3) has a solution i n V
i f and only i f the equation
L o $(s) = r
(4.994)
- L o q(b)
has a solution i n Rn. n L e t Y = L o Jr(R ), CJ = - L O cp B
Then
Hence, it follows t h a t
and define
= CJ -1( - r + Y ) .
is e i t h e r empty o r a closed l i n e a r variety i n
B
the l a t t e r case, every equation (4.9.3) with b l e a s t one solution i n V,
E
B
C.
In
has a t
that is, satisfying (4.9.2).
Xo of L O Jr i s a closed X1 be the complement of Xo and l e t P be the projection of Rn onto Xo. b r e o v e r , the r e s t r i c t i o n of L o $ t o X1 i s an isomorphism of X onto 1 Observe that the n u l l space
linear subspace of
Let
I n addition, there i s a constant
Y. z
Rn.
E
Y,
there i s a unique
and llx,ll 5 hllzII. lemma. IJ?,MMA 4.9.1.
x1 E X1
> 0,
such t h a t
i n which f o r each L o
Jr(xl) = z
We essentially have proved the following
If
B
i s nonempty, there exist positive
constants a, p, y such t h a t given any xo E xo, (4.9.3) has f o r every b E B a unique solution x E V with PX(tO)=xO for which (4.9.5)
IIxlI
5
allx,
11
+ Bllrll + y b 11.
257
4. FUNCTIONAL ANALYTIC METHODS
From Lemma 4.9.1,
c: (xoJb) + x
induces a mapping continuous.
we see t h a t i f
For, consider
x X B into
V which i s
0
x0 XB,
(XoJbl)J (GOJb2) i n
such t h a t
with b = b 1 -b2
of
- c(z0’ b 2)
the mapping w = c(xo,bl)
i s nonempty, (4.9.3)
B
i s a solution of (4.9.3)
p w ( t ) = xo - x o h
0
This implies from (4.9.5) t h a t
then
and
L(w) = 0.
(4.9.6) As we pointed out before, i f linear variety.
r
then
Y,
E
This occurs i f and only i f
l e a s t one solution belonging t o
For
V.
B
i s a closed
x’ = A(t)x has a t t h i s i s always
r = 0
true.
LEMMA 4.9.2.
Jr i s a continuous mapping of Rn onto Rn, then B i s a topological direct summand of C; t h a t i s C = A @ B, where A and B are closed l i n e a r v a r i e t i e s . Proof: Rn
onto Rn
of
Rn,
If
Since
r
E
and
Y
Lo
P O
i s a continuous linear mapping of
L O cp o Jr
whose n u l l space i s a topological d i r e c t summand
there e x i s t s a continuous l i n e a r injection
which i s the right inverse of Y =
- 9 0 M of
Rn
onto the supplement of
Rn
into
Lo
Define the injection
Jr.
cpo
and l e t
C
Q be the projection of
We claim that
Y.
M: Rn + R n
is
T = Y OQO@
a continuous projection of C f o r which T(B) = 0, t h a t i s -1 ? (0) = B. Clearly T i s continuous and i s a projection because some
0
c
o
Y
E C,
i s the identity mapping.
fireover,
and t h i s i s equivalent t o
i s equivalent t o
it follows t h a t
c
E
o-’(Y).
Since
r
~ ( c =) 0
Q o O(c) = 0, E
Y
implies
which B = o-’(Y),
= B.
This completes the proof. We now consider the d i f f e r e n t i a l equation (4.9.1). .C-’(O)
convenience introduce, f o r every b
t + (t,b(t))
of
J
for
into
JxRn, 258
E
V,
For
the injection
so we may write
f o
g,,
g,,: for
4.9. BOUNDS FOR SOLUTIONS IN ADMISSIBLE SUBSPACES
t - + f ( t , b ( t ) ) of J i n t o Rn. The a, B, y w i l l always be those referred t o i n Lemma
t h e continuous mapping constants
4.9.1. A necessary condition f o r (4.9.1) t o have a s o l u t i o n be-
longing t o
is that
V
be nonempty and we assume t h i s
B
throughout. We now attempt t o o b t a i n s u f f i c i e n t conditions f o r t h e existence of s o l u t i o n s of (4.9.1) belonging t o
V,
that is,
s a t i s f y i n g (4.9.2). Suppose t h e r e i s a closed b a l l X f
0
gb
E
f o r every
B
b
E
in
Then (4.9.1)
X.
V
such t h a t
gives r i s e t o t h e
mapping
of x
into
XoXB
O f course
V.
C(xo,b)
i s t h e unique s o l u t i o n
of t h e l i n e a r d i f f e r e n t i a l equation
(4.9.7)
X'
which belongs t o t i n u i t y of b +f
0
gb
2
of
+ f(t,b(t))
= A(t)x
and s a t i s f i e s
V
P x ( t O ) = xo.
The con-
follows from t h e continuity o f the mapping into
X
and t h e c o n t i n u i t y of
B
u: Xo x B 4 V .
Clearly every u E X f o r which C(x0 , u ) = u f o r some xo i s a s o l u t i o n of (4.9.1) i n V with Fu(tO)= x Thus we 0'
need conditions f o r which t h e mapping V
has a f i x e d point f o r some THEOREM 4.9.1.
such t h a t ball in IlbII
5
r
(4.9.1),
llxll
5
s
cya Xo
+
Let
llrll
a
+ yp 5
with c e n t e r a t
implies
f
0
gb
E
B
xo
-> 0, s
0
s
of
X
into
Xo.
>
0, p
>0
be constants
and denote by X 0 t h e closed and r a d i u s a. If b E V and
and
(4.9.2) has a s o l u t i o n x and
E
b 4C(x0,b)
xo
Px(tO) = xo.
259
[If
gbll
5
p,
f o r each x
then t h e BVP E
Xo
with
4. FUNCTIONAL ANALYTIC METHODS
Proof: subset of
The b a l l X = [b E V: because
C
i s closed.
V
assumptions, we have
C(xo,X)
[ v ( t > : v E ~ ( ,xX I ]
set
over, any
0
v
C
)I -< s ]
By Lemma 4.9.1and our
f o r any
X
i s a convex closed xo E X.
Hence the
i s r e l a t i v e l y compact i n R ~ . m r e -
i s a solution of (4.9.7) f o r some
C(xo,x)
E
Ilb
b E X. and thus s a t i s f i e s
Hence
C(Xo,X)
i s equicontinuous and by Ascoli’s theorem,
r e l a t i v e l y compact i n f o r each
x
E
C(xo,x) = x. (4.9.2).
Hence
such t h a t
This concludes t h e proof.
and denote by and radius
f
(ii)
f
(iii)
H
s.
(i)
0
x EX
i s a solution of t h e BVP (4.9.1),
x
Let
be so chosen t h a t
Ilf.9,
By Schauder’s fixed point theorem,
t h e r e e x i s t a f’unction
Xo,
THEOREM 4.9.2. p
C.
a
-> 0
and positive constant
cya + Bllrll + yp
s
the closed b a l l i n Rn
(9< l), 2ks < p, with center a t 0
Suppose i s Lipschitzian i n
0
5
k, s ,
gb E B
there i s a
f o r every
I xH
for t h e constant
b E V with
bo E V with
IboII5
k;
IlLll 5 S; s such t h a t
I I I P -2b.
Then f o r each xo E Xo there e x i s t a unique solution u of the BVP (4.9.1), (4.9.2) with l/u 11 5 s and X 0 xO i s continuous Pux ( t o ) = xo. b r e o v e r t h e mapping xo -x0 0
i n Xo. Proof: subspace of every
b E X,
The b a l l X = [b E V: 1/b11 5 s ] C.
i s a complete
Ilf 0 gbII 5 p for by Lemma 4.9.1 we can define a sequence {vn]
Since by our assumption
260
4.9. BOUNDS FOR SOLUTIONS IN ADMISSIBLE SUBSPACES
of points i n X
such t h a t
v
0
and v = Z(x v ) for n 0’ n-1 = un(xo), where each
= bo
n > 1. By induction, we may w r i t e
un’* X 0 + X
i s continuous.
f o r any xo
E
foxo
x0.
in E
X
Mediately Clearly ux (4.9.1),
F r o m (4.9.6) we observe t h a t
and t h i s implies that
0’
u
Thus
and xo + u
Xo
vn
X
0
X
0
un
converges uni-
= l i m un(xO) e x i s t s f o r every
i s continuous i n X 0 ’
It follows
and ~ ( x o ~ U)x =0 u 0 f o r every x0 E x0 ’ i s unique. For i f w i s another s o l u t i o n of
uX 0
X
E
0
lbll 5
(4.9.2) s a t i s f y i n g
s
and
Fw(t ) 0
=
x
0’
then
w-u is a s o l u t i o n of t h e l i n e a r equation (4.9.3) with X 0 b = fo%-fogU such t h a t Fv(tO) = 0 and T(v) = 0 . v
=
X
0
Since by Lemma 4.9.1 t h e r e i s only one s o l u t i o n we conclude v
=
c(O,b)
However,
and t h i s implies from (4.9.6)
w = u
X
0
because
ky < 1, thus completing the proof.
When B i s a t o p o l o g i c a l d i r e c t summand o f C we can s a y more. For i n t h i s case, t h e r e e x i s t s a continuous p r o j e c t i o n T of
C
with
Thus, even i f
a-l(O) = B and, f o r every b
f
0
gb
does not belong t o
E
X’ =
A(t)x
-b
f(t,b(t)) -%(t)
261
a unique
B f o r any b
t h e l i n e a r equation (4.9.10)
C,
E
V,
4. FUNCTIONAL ANALYTIC METHODS
has a unique s o l u t i o n x ( t ) x
0
E
xo with
Fx(t ) = x 0
following r e s u l t .
of
s a t i s f y i n g (4.9.2) f o r each This y i e l d s immediately t h e
0’
COROLLARY 4.9.1. Let B be a t o p o l o g i c a l d i r e c t summand C. Let T be a continuous p r o j e c t i o n of C with z-’(O>=B a > 0, s
and l e t
2ypl(BI/ 5 s .
If
> 0,
p
(If gbll 0
>0 5P
be constants such t h a t f o r every
then t h e r e e x i s t s f o r each xo E Xo (Iu((5 s , F%(tO)= xo
(4.9.2) with (4.9.U)
U’
b E V with
a function
0
( ( b (5( s,
satisfying
and
( t ) = A(t)u(t) + f ( t , u ( t ) )
[Here h ( u ) = z ( f
u
(Ya + Bllrll+
- hu(t).
g,)].
EXERCISE 4.9.1.
S t a t e and prove a c o r o l l a r y f o r Theorem
4.9.2 i n a formulation similar t o Corollary 4.9.1. We now apply our previous r e s u l t s t o t h e case i n which J = [O,T]
(4.9.
and (4.9.2) becomes
w
W = ~ ( 0 -)x ( T ) = 0.
Thus we a r e looking f o r a s o l u t i o n of (4.9.1) s a t i s f y i n g t h e p e r i o d i c boundary conditions space o f p e r i o d i c mappings Choose
to = 0
and l e t
x’ = A ( t ) x with and
cp: C + C
U
x ( 0 ) = x(T).
u
C
f o r which
V
is the
u ( 0 ) = u(T).
be t h e fundamental matrix o f
U(0) = I.
Jr: Rn + C
Then t h e mappings
can be w r i t t e n as cp(b): t + U ( t )
+(x): t - + U ( t ) x ,
(4.9.13)
E
Here
JtU - l ( s ) b ( s ) ds,
xo i s t h e n u l l space, and Y t h e range of t h e mapping I U(T) The mapping L cp Jr i s the b i j e c t i o n x -TU(T)x !Thus
-
.
0
0
so t h e assumptions of Lemma 4.9.2 a r e s a t i s f i e d . set
B o f mappings b
E
Hence t h e
C f o r which t h e l i n e a r d i f f e r e n t i a l
262
4.10. LERAYSCHAUDER’S ALTERNATIVE
equation (4.9.3) has at l e a s t one periodic solution i s a topological sununand of
C.
A topological supplement t o
Q
choosing
( i n the proof of m
the projection of of
I - U(T),
of
I-U(T).
projection
and
Y : Rn
Rn
Then -r = Y
onto t h e n u l l space
f o r example, as Yo
of the adjoint
0
B
i s the n u l l space of t h e continuous n CJ: C --f R i s the mapping
Q O CJ where
+ C such t h a t
It follows t h a t Qyb = 0
B
t
--f
(1/T) U(t)U-l(T)x.
i s precisely the s e t of those b
E
C
for
where
1
T
yb = (l/T) U(T)
4.10
a 4.9.2),
which i s an orthogonal supplement t o the range
Y(x):
which
B may be constructed by
U-’(s)b(s)
0
ds.
LFRAY-SCHAUDER’S ALTERNATIVE Let us now investigate t h e general existence problems
based on d i f f e r e n t geometric ideas.
We s h a l l employ, as the
t i t l e of t h e section indicates, the Leray-Schauder‘s theory of topological degree. DEFTNITION 4.10.1. operators defined f o r
ht
To, T1
u E S
P’
with values i n a M a c h space
be completely continuous
where E.
S
P
= [u E E:
llull
5
p],
Then we s h a l l s a y t h a t
are homotopic i f there e x i s t s an operator T(u,h), To, T1 t h a t i s completely continuous on M[0,1] such t h a t T(u,O)
E
TOu, T(u,l) = T1u
for
263
u E S
P
and
T(u,h)
#
u
for
4. FUNCTIONAL ANALYTIC METHODS
IluII = P. We need the following r e s u l t of Leray-Schauder. LFJDfA 4.10.1.
defined on
S
P
Let
be a completely continuous operator
T
E.
with values i n
Suppose t h a t
t o the operator i d e n t i c a l l y equal t o zero. a t least one solution u Ilull
<
x
C(2)
i s homotopic
Then t h e r e e x i s t s
Tu = u such t h a t
P.
Let E
of t h e equation
T
X
E [0,1] and l e t
[ [0, 11,Rn]
(4.10.1) f
where
S(h)
XI1
= hf(t,X,X'),
n n C [ [0,1]X R n X R ,R ] J
E
denote the s e t of functions
satisfying
and t h e general boundary
conditions (4.10.2)
~ ( 0 -A0x'(O) ) = 0,
(4.10.3)
x(l)+A1x'(l) = 0 ,
A.
, A1
being
n Xn
matrices.
Then we can prove t h e following
r e s u l t which we give as an exercise with generous h i n t s .
EXERCISE 4.10.1. i d e n t i c a l l y zero. B
>
0
Ilx(t)ll
5B
Then show t h a t the s e t Hints:
Ao, A1
be positive d e f i n i t e or be
Suppose f u r t h e r t h e r e e x i s t s a constant
such t h a t , i f
(4.10.4)
Let
X
E
[0,1] and
S(X),
we have
t
E
[0,11.
i s nonempty.
Recall t h a t t h e t r i v i a l solution i s the only
solution of t h e homogeneous equation (4.10.2),
E
llx'(t)l( 5 B,
and S(1)
x
(4.10.3)
XI' = 0 which s a t i s f i e s
and t h a t there e x i s t s a Green's matrix
G(t,s) such t h a t (4.10.1) with (4.10.2) (4.10.3) i s equivalent 1 t o x ( t ) = A .fo G ( t , s ) f ( s , x ( s ) , x * ( s ) ) ds. Now use t h e f a c t 264
4.1 1 . APPLICATION OF LERAY-SCHAUDER'S ALTERNATIVE
t h a t t h e map
1 x ( t ) + J 0 G ( t , s ) f ( s , x ( s > , x ' ( s ) ) ds
continuous i n t h e Banach space
c ( ~ [)[O 11 ,Rn] J
i s completely
with the
supremum norm and apply k m a 4.10.1. APPLICATION OF LERAY-SCHAUDER'S ALTERNATIVE
4.11
A s an application of Leray-Schauder
1s
a l t e r n a t i v e , we
s h a l l , i n t h i s section, prove existence of solutions of the d i f f e r e n t i a l system
(4. ll.1) where
XI1
= f(t,X,X')
n n f E C[[O,l]xRnxR ,R
1,
subjected t o the boundary
conditions (4.10.2) and (4.10.3).
Let us begin with the follow-
ing r e s u l t .
THEOREM 4.11.1. (i) definite; (ii)
n
f E c [ [ o , ~X I R ~ X R,R
(t,v)
(4.11.2)
n
V E C(2)[[0,1] xRn,R+],
g E C[[O,l] x R + x R , R - ] , each
Assume t h a t
and f o r V:(tJx)
g(t,u,v)
3
and A ~ A~ , V(t,x)
i s positive d e f i n i t e ,
i s nonincreasing i n
( t , x ) E [O,l]XRnJ
2
g((tJV(tJx)J V'(tJX))J
265
are positive
u for
4. FUNCTIONAL ANALYTIC METHODS
V'(O,x(O)) f o r some
2 cy
(iv)
0, V'(Lx(1))
5
xR+,R]
G E C "0,l.l
such that f o r
u
2
V(O,x(O))
5
aV'(O,x(O))
T E
and t h e r e e x i s t s an
L
>
0
L, t E [O,l],
- (V/Ul2
(l/u) g(t,u,v) and f o r any
and
0
> 0.
(0,1],
1 G(t,v/u)
t h e l e f t maximal solution
r(t,T,O)
of G(t,z),
Z' =
z(T) = 0
r ( t J T J O ) < a0, t E [O,T],
s a t i s f i e s t h e inequality
where
a. = min(+-,l/a);
(v)
the l e f t maximal solution
minimal solution
p(t,O,O)
r(t,l,O)
and t h e r i g h t
of
v' = g(t,2L,v) e x i s t s on
[0,1].
Assume a l s o t h a t f o r each solution x o ( t ) xo(t)
i s defined f o r a l l t E
bounded.
[0,11
or
of ( 4 . l l . l )
either
Ilxo(t)II i s un-
Then there e x i s t s a solution of (4.ll.l) satisfying
(4.10.2) and (4.10.3). Proof: V,
By Lemma
1.14.1 and t h e positive definiteness of
we have f o r each
(4.11.3 )
(h,x)
Ilx(t)ll
We s h a l l show t h a t
< t< 1 Il(p(t)[I and
5 B*,
i.
Since
llv' !lo],
A.
A.
[0,1] xC(')[[0,l],Rn]
= max[/b//OJ
(p E
where
C(')[[O,l],Rn].
we may assume t h a t
vergent t o some all
i s compact i n
and xo
as
hi
i
and
+ m.
lllpll0 =
If not, there
{hi,x.1 ( * ) I with no l i m i t i n
e x i s 5 asequence /Ixi(0)II
-< t -< 1.
0
B*,
S
IlrpI1l
with respect t o norm
s'po
5
E S,
xi(0)
Let
S.
Since are con-
yi = x;(O)
i s assumed t o be positive d e f i n i t e , 266
for
4.1 1 . APPLICATION OF LERAY-SCHAUDER'S ALTERNATlVE
yi = A.-1xi(0),
by (4.10.2),
which converges t o some y
-1
0
= A x 0 0'
From the standard convergence theorem, there i s a solution x o ( t ) of (4.10.1) with I = [O,T)
(a)
C
[0,1]
h = ho
defined on an i n t e r v a l
such t h a t
xo(0) = xo, x ' ( 0 ) = yo
and e i t h e r
I = [O,T]
or
x0 ( t ) cannot be defined continuously on any larger i n t e r v a l as well as a t T; (b) i
+m,
x i ( t ) -+xo(t) on
By (4.11.3),
and x;(t)
-+x;(t)
uniformly, as
I.
we must have
Ilxo(t)II _< B", t E I. Since x o ( t ) i s bounded, the hypothesis of the theorem implies I = [0,1].
t = 1, applying (b) above, it follows t h a t x o ( t ) s a t i s f i e s (4.10.3). Hence (Xo,xo) E S, contradicting our assumption t h a t (A x . ) has no limit point i n S. The s e t S i s therei' 1 fore compact as claimed. We now consider the derivative evaluation f'unction n F: [0,1] XS + R given by F ( t , x ( t ) ) + x ' ( t ) . This function i s continuous and i t s domain i s compact. Hence )$II is bounded by some B1 > 0, which, i n turn, implies t h a t
At
IIx'(t)II I :B1> Let
0
-< t -< 1
and
(h,x)
E
s.
B = m a x [ ~ * , ~ ~ ~n ] . application of Exercise 4.10.1 proves
the s t a t e d r e s u l t . Notice t h a t the assumption A.
i s positive d e f i n i t e i s
crucial i n the proof of Theorem 4.11.1.
i s true, i f
Ao, A1
Whether the r e s u l t
are identically zero, remains an open
question. COROLLARY 4.ll.1.
and f o r some k
2
Assume t h a t
n n
f E C[[O,l] xRnxR ,R
0,
l l ~ 1 1+~ x*f(t,x,y) 2 -k[1 267
+
lkll
+ 1x-y
11
]
4. FUNCTIONAL ANALYTIC METHODS
for
(t,x,y)
E
[0,1] xRnxRn.
positive d e f i n i t e .
Let t h e matrices
Ao, A1
be
is
Suppose t h a t f o r each solution x o ( t )
defined f o r a l l t E [O,l]
or
t h e BIT (4,11.1), (4.10.2),
and (4.10.3) has a solution.
Ilxo(t)I) i s unbounded.
"hen
Next we s h a l l give another proof of Theorem 1.14.1 which depends on bray-Schauder I s a l t e r n a t i v e . Alternate proof of Theorem 1.14.1.
s where
S(h),
= [(h,x): A E [0,13 and
x E S(A)],
as i n Section 4.10, denotes t h e set of functions
x satisfying (4.10.1), is nonempty, since i f and define
Let
(4.10.2), x
E
and (4.10.3).
then
0,
(0,x) E S.
The set
S
(A,x)
Let
E S
m(t) = V ( t , x ( t ) ) ,
so t h a t because of assumption (c), we have (1.14.16) as before. Also since (A,x) E S, 0
2 g(t,V(t,x),V' (t,x))
+ dlhf(t,x,xl)
11
which again leads t o t h e d i f f e r e n t i a l inequality (1.14.18). The r e s t of t h e proof is exactly t h e same as t h a t of t h e proof of meorem 1.14.1 as given i n Section 14 of Chapter 1, u n t i l The s t a t e d conclusion
we a r r i v e a t t h e inequality (1.14.19).
follows, i n t h e present case, by Exercise 4.10.1 and t h i s completes t h e proof.
COROLLARY 4.11.2. hold.
Let hypothesis (a) of Theorem 1.14.1
Assume t h a t f o r some k > 0
Ih.1I2 + x * f ( t , x , y ) -> -k[1 for
d d ( t , x , y ) E [0,1] XR X R
+
.
hII
and
+
m
Ix*Y~]
> 0, + Ullf(t,x,y)II
men t h e r e e x i s t s a solution
f o r the boundary value problem (4.11,1),
268
(4.10.2),
and (4.10.3).
4.12. PERIODIC BOUNDARY CONDITIONS
COROLLARY 4.11.3.
1.14.1 i s s a t i s f i e d .
for
(t,x,y>
E
[0,11
Assume t h a t hypothesis ( a ) of Theorem
For some
k > 0, u > 0, l e t
X R ~ ~ R Then, ~ . if
s a t i s f i e s ~agumo's
f
condition, t h e r e e x i s t s a s o l u t i o n f o r t h e problem (4.11.1), (4.10.2),
and (4.10.3).
We can a l s o give another proof o f Theorem 1.14.2.
Alternate proof of Theorem 1.14.2.
m(t)
Let
S,(h,x)
and
be as i n t h e a l t e r n a t e proof of Theorem 1.14.1.
u
Distinguishing t h e two cases
-> 1
and
0
arguing as i n t h e proof of Theorem 1.14.2,
V h ( t , x ) _> g ( t , V ( t , x ) , V ' ( t , x ) )
< u < 1, and
we obt,ain
-1+
llx' II
These i n e q u a l i t i e s imply t h e f u r t h e r i n e q u a l i t i e s
m"(t) > -(N + 1) + llx~(t)ll,
m"(t)
- ( N + 1)
+
~llx~(t)ll
and consequently, as before, we a r r i v e a t 0
-< t -< 1,
(1.14.19)
4.12
using Lemma 1.12.1.
Ilx'(t)((5 y(M), This then implies t h e estimates
and Exercise 4.10.1 then concludes t h e proof.
PERIODIC BOUNDARY CONDITIONS This s e c t i o n provides s u f f i c i e n t conditions f o r t h e
s o l u t i o n s of t h e second-order d i f f e r e n t i a l system
(4.l2.1)
XI'
=
f(t,X,X')
s a t i s f y i n g t h e p e r i o d i c boundary conditions (4.12.2)
~ ( 0 =) x(T),
~ ' ( 0= ) x'(T). 269
4. FUNCTIONAL ANALYTIC METHODS
A solution of the BVP (4.12.1), (4.12.2) will be called a periodic solution. The approach is to establish existence results for the boundary condition
(4.12.3)
x(0) = y = x(T)
and then study the vector field
-
(4.12.4)
U(Y) = X' ( 0 , ~ ) X'(T,Y),
where x(t,y) is the unique solution of (4.12.1), (4.12.3). To solve the BVP (4.12.1), (4.12.2), it is sufficient to prove the existence of a y such that U(y) = 0. We shall assume n n that f E C[[O,Tl XRnXR ,R
1.
LEMMA 4.12.1.
Let Dn be the closed n-ball with radius one, that is, Dn = [x: ((x((5 13. Assume for each y E Dn, (&.12.1), (4.12.3) has a unique solution x(t;y). Further, 0 let there exist a constant N [depending on Dn (interior
-< N Then x(t,y) t E I.
and x'(t,y)
MERCISE 4.12.1.
for 0 5 t 5 T, y
E
Dn.
are continuous in y for each
Prove Lemma 4.12.1 by applying Ascoli's
theorem. Before introducing our main result, we need the following infornation on degree theory. Because the ideas of degree theory are strongly connected with algebraic topology we shall only mention, without proof, the essential theory needed. The idea is to obtain for each f: Sn +Sn an integer (positive, negative, or zero) called its degree. Here S" is the boundary of Dn+l. We shall always assume f is continuous. 270
4.12. PERIODIC BOUNDARY CONDITIONS
For
1
n = 1 t h e degree of
f: S
number of times t h e image point
r o t a t e s around S1 when 1 S In particular, f o r
f(z)
.
z p e r f o m one oriented r o t a t i o n of each
22,.
k = O,+l,
..,
t h e map
+ zk has degree
z
The d e f i n i t i o n of t h e degree of i s a generalization of t h e case details. Let
O:
LEMMA 4.12.2.
then
D(f) = D(g).
property t h a t
x
E
such t h a t and
X
Let
n l 0.
If
Let
n> 0
and
f(-x) = -f(x).
there e x i s t s an x
E
Recall t h a t two O(x,O) = f ( x ) ,
cp(x,*) never vanishes. f,g: Sn + S n f : Sn + S n
Then D(f)
a r e hamotopic, have t h e
i s odd; i n p a r t i c u l a r ,
f ( x ) = 0.
such t h a t
Dn+l
n>1
D(f).
I = [0,1].
X X I +Y
f o r each
for
a r e called homotopic i f t h e r e
f,g: X + Y
e x i s t s a continuous O(x,l) = g(x)
by
f
be two spaces and
continuous maps
f : Sn + Sn
k.
n = 1. We shall omit t h e
Denote t h e degree of X, Y
i s simply t h e
+S1
We now s t a t e our main r e s u l t .
THEOREM 4.12.1.
Let t h e hypotheses of Lemma 4.12.1 hold.
n is a convex homeomorphic image of Do and l e t nbe symmetric about a point z E n. For each y E D define
Assume t h a t
-
U(y) = x ' ( 0 , y ) - x ' ( T , y ) .
an (the boundary of
Let
be t h e continuous mapping of
A
n) onto i t s e l f which maps each y
onto the point which i s symmetric t o Further assume t h a t f o r all y U(y)
and
c
>
0
such t h a t
U(y) = cU(Ay)].
e x i s t s a solution of t h e BVP (4.12.1), Proof:
If t h e r e e x i s t s a
then t h e proof i s complete. field U
does not vanish on
synnnetric about
0,
do not have t h e same d i r e c t i o n [ t h a t is,
U(Ay)
there e x i s t s no
z.
with respect t o
y
an f o r which U(y) f
E
E ail
z,
y
E
Then there
(4.12.2).
an such t h a t U(y)
= 0,
Assume therefore t h a t t h e vector
an.
Since
5
i s convex and of Dn
there exists a homeomorphism g 27 1
4. FUNCTIONAL ANALYTIC METHODS
onto
1
such that
t h a t is, f o r all r E aDn, sn- 1 onto i t s e l f .
i s t h e antipodal map of
g-lAg
Define t h e vector f i e l d
on
cp
Dn
by
cp(r) = U ( g ( r ) ) . By Lemma 4.12.1, continuous.
U
i s continuous, thus implying
vanish on aDn.
an,
does not vanish on
Since U
cp
cp
is
w i l l not
Observe t h a t
cp(r>= U ( g ( r ) ) and
d-r)
= u ( g ( - r ) ) = U(Ag(r)).
From t h e hypothesis on U, we see t h a t w i l l have d i f f e r e n t d i r e c t i o n s on aDn;
#
cp(-r)/M-r)I
cp(r) and that is
cp(-r)
cp(r)/lcp(r>l
Hence t h e vector f i e l d
I - A cp(-r)/lcp(-r)I
$(r, A) = cp(r>/l cp(r>
h 5 1. Since J r ( r , O ) and never vanishes on aDn f o r 0 Jr(r,l) a r e homotopic, t h e i r topological degrees a r e i d e n t i c a l
by Lemma 4.12.2.
$(-r,l)
Since
4.12.3 that t h e degree of t h e degree of exists
-
r
and hence
0
E Dn
Jr(r,O)
= -$(r,l)
we have by Lemma
i s an odd integer.
Jr(r,l)
Hence
i s an odd i n t e g e r which implies t h e r e
such that
U(g(y) ) = 0
Jr(T,o)
where
This implies
= 0.
g(y)
E
a.
)cp;(
= 0
This proves t h e
existence of a s o l u t i o n of t h e BVP (4.12.1),
(4.12.2).
I n our f i r s t application, we s h a l l assume f o r each M > 0,
t h e r e e x i s t s an
N > 0 such t h a t whenever x ( t ) 272
is
4.12. PERIODIC BOUNDARY CONDITIONS
a solution of (4.12.1) defined on
I = [O,T]
Ilx(t)ll
with
5 M,
then Ilx'(t)II ,< N. Further there e x i s t s a constant p 7 N such that i f x ( t ) i s a solution defined on I of the perturbed equation
(4.12.5) with
x"
+
f(t,X,X')
=
Ex,
0
<
,< EO,
&
Ilx(t>ll I M, then IlxT(t>ll_< P. We f u r t h e r adopt the following convention.
are vectors i n R ~ , then l e t AX f(t,X,Y)
- f(t,G3.
THEOREM 4.12.2.
-
x,
-
If x, y, y = x - x, AY = y y, ~f =
-
Let there exist a positive constant R
such t h a t 2
x * f ( t , x , y ) + IIy(( _> 0
(4.12.6) (IxI( = R,
if x-y = 0 ,
and
- n f o r any x, x E R , Ilxll, _< R, x # and y, y E Rn w i t h Ax-Ay = 0. Then there exists a solution x ( t ) of (4.12.1),
lxl
(4.12.2) with Proof:
IIx((5 R. Let
E
>
0
be given with
E
_<
EO.
perturbed equation (4.12.5) and l e t F(t,x,x',E) Then, from (4.12.5), it follows t h a t
(4.12-8)
x * F + llyll
i f . x*y = 0
and
llxll
2
= x-f
2
Consider the f(t,x,x') 2
+ Ellxll + lly112 >_ Ellxll > 0
= R.
Furthermore, from (4.12.7), we observe that
(4.12.9)
AX-AF
+ l l A ~ 1 1=~ AxeAf +
2 &llAXll2 '0 , 273
+
llA~11~
+
Ex.
4. FUNCTIONAL ANALYTIC METHODS
if Axdy
=
0 and
Ax f 0.
We have seen in Section 1.14 that conditions (4.12.8) and (4.12.9) imply that the BVP (4.12.10)
X" =
(4.12.11)
F(tyX,X',E)
~ ( 0 )= z = x(T)
has a unique solution x(t,z,E)
with
IIX(t,z,E>II 5 R,
(4.12.12)
for any z, IIzII 5 R. Let fi = [x: llxll < R]. Then, by assumption there exists a p > 0 such that //x'(t,z,E)// _< p for any z E 5. Thus by Lemma 4.12.1, the vector field U(z,E) = x'(O,Z,E)
-
-x'(T,z,E)
is continuous on n. Again assume that U(z,E) does not vanish for z E ail. Letting r(t) = 3llx(t,z,E)II 2, we find
rl (t)
(4.12.13)
=
x(t,z,E)*x' (t,z,E),
and (4.12.14) From (4.12.8) and (4.12.12)- (4.12.14), it follows that r'(0) < 0 < r'(T) for any z Therefore,
E
an which implies Z.U(Z,E) < o for z
U(ZYE)/llU(Z,E>II
#
u(-z,~>/llu(-z,E)II,
z
E
E ail.
3%
that is, U(z,E) and U(-z,E) cannot have the same direction. By Theorem 4.12.1, we conclude U(z,E) will have a zero in fi for every E, 0 < E < Eo, tfiat is, there exists a solution x(t,E) of the BVP (4.12.10), (4.12.U). By a standard application of Ascoli's theorem, there exists a sequence Ei + O
2 74
4.12. PERIODIC BOUNDARY CONDITIONS
such that x(tyEi) + x ( t ) as i + a and x ( t ) i s a solution of the BVP (4.12.1), (4.12.2). This completes t h e proof of Theorem 4.12.1. We now use t h e theory of d i f f e r e n t i a l i n e q u a l i t i e s d i s cussed i n Chapter 1 together w i t h Theorem 4.12.1 t o derive some r e s u l t s . We s h a l l assume t h a t i n (4.12.1) f i s independent of x ' . I n RL1, consider t h e usual p a r t i a l ordering x 5 y if and only i f xi ,< yi, i = 1, n and x < y if and only i f x . < yi, i = 1,. ,n. Recall t h a t a function ty E C(2)[I,Rn] 1 i s c a l l e d a lower solution of (4.12.1) i f
...,
..
cy"(t) 2 f(t,CY(t)),
(4.12.15)
f3
Similarly,
E
C(2)[I,Rn]
t
i s c a l l e d an upper solution i f
f3"(t) ,< f ( t , B ( t ) ) ,
(4.12.16)
I.
E
Further, we w i l l assume t h a t
t
1.
E
f(t,x)
i s quasimonotone
increasing i n x. THEOREM 4.12.3.
L e t there e x i s t lower and upper solutions
and @ of (4.12.1) with a ( t ) 5 p ( t ) , t quasimonotone increasing i n x on t h e s e t w = { ( t , x ) : u ( t ) ,< x
Moreover, l e t (4-12-17)
cy
Q(0)
5
p(t), t
I
E
cy
E
and l e t
f
be
I}.
and f3 be such that = ~(T)Y
~ ' ( 0 2)
u'(T),
Further, assume t h a t f o r every
B(0)
= B(T),
B'(0)
5
y,
B'(T)*
with
cy(0)
5 y ,< 8(0)
the
BVP
(4.12.18)
X"
=
f(t,x),
and (4.12.3), has a t most one s o l u t i o n x ( t ) such that ( t , x ( t ) ) E w. Then t h e r e e x i s t s a s o l u t i o n of the BVP (4.12.18), (4.12.2). 275
4. FUNCTIONAL ANALYTIC METHODS
[cu,BI = [y: a ( 0 ) 5 y
Let
Proof:
5
Then by
B(0)l.
Theorem 1.ll.1and t h e hypotheses of Theorem 4.12.3 of (4.12.18)
e x i s t s a unique Solution x ( t , y )
there
such that
X(0,Y) = X(T,Y) and
a(t)
5 x(t,y) 5
B(t)
>0 Ilx(t,Y>II, I l x ~ ( t , ~ ) ,< lI N
t h e r e exists an N
for every y
[a,@]. Further [cu,B1 such t h a t
depending on for
Y
E
The vector
[cu,~].
E
field U(Y> = X'(O,Y)-X'(T,Y) i s continuous on (4.12.17),
[cy,@I.
that
fact, if t h e r e exists an Bi(0),
If
U(cu(0)) = 0 i,
cy(0) =
it follows from In
p(O),
and t h e proof i s complete.
15 i 5 n
such t h a t
~ ~ ( =0 )
then it follows again from (4.12.17) t h a t (U(y))i
is
Therefore we need only t o consider zero f o r all y E [a,p]. t h e components (U(y)). f o r those j i n which cu.(O) < f3.(0). J J J W e assume now cu.(O) < B.(O) f o r j = 1 n, the contrary J J s i t u a t i o n w i l l follow by using a similar argument i n a l a v e r
,...,
dimensional s e t t i n g . Thus l e t y
E
an such t h a t
assume U ail
52 =
U(y) = 0,
t h e proof i s done.
does not vanish on 8%
mapping y
If t h e r e exists
[y: a ( 0 ) C y < p(O)]. Let
Otherwise
be the mapping on
A
i n t o t h e point symmetric t o
y
about
b ( O ) + B(O)I/2.
Let that
hi
be a continuous function on
hi(pi(0))
<
0 C hi(ai(0))
and l e t
Consider t h e vector f i e i d defined f o r
276
[cyi(0),Bi(O)] &
y E
>
sd
0
be given.
given by
such
4.12. PERIODIC BOUNDARY CONDITIONS
Thus O(y,E) and O ( A y , E ) do not have the same direction, which implies O(y,E) must have a zero in R. Pick a converging monotonically to zero sequence E1 > E2 > E 3**and let yn be a sequence of O(y,En) in n. This sequence has a convergent subsequence converging to a zero of U(y) in R. This concludes the proof of Theorem 4.12.3. COROLLAHY 4.12.1. Assume that there exists constant vectors Q and p, Q < p such that f(t,Q)
5
0
L f(t,B)
and f is quasimonotone increasing on {x: each t E I. Let f(t,x) satisfy Ilf(t,x)
(Y
x
5
p]
for
- f(t,Y>ll 5 Lllx - YII
for some L > 0 where o ,< x, y 5 p. Then the BVP (4.12.1), (4.12.2) has a solution provided L < 8/T2. MERCISE 4.12.2. Prove Corollary 4.12.1.
Hint:
Apply Theorem 4.12.3 by showing there exist at most one solution of (4.12.18) and (4.12.3). This may be done by setting up an integral equation and showing the operator is a contraction mapping with constant T2L/8.
EXAMPLE 4.12.1. Consider the two-dimensional secondorder system 277
4. FUNCTIONAL ANALYTIC METHODS
(4.12.19)
XI'
=
x3- y + p(t),
y" = -x + y3
+ q(t),
a, lq(t)l 5 a. Choose b > 0 so that Then letting f3 = (b,b), o = (-b,-b), we find that f3 is an upper solution and o is a lower solution of (4.12.19). The right-hand side of' (4.l2.19) is quasimonotone increasing in x and y for -h ,< x, y b and is Lipschitzcontinuous in the region. Thus, we may conclude for T sufficiently s m a l l the hy-potheses of Corollary 4.12.1 are satisfied. Thus there exists a solution of (4.12.19), (4.12.2) for T sufficiently s m a l l .
where
Ip(t)l
b3- b - a 2 0.
5
4.13 SET-VALUED MAPPINGS AND FUNCTIONAL EQUATIONS We wish to present here an existence and uniqueness result for nonlinear functional equations, which will be stated in terms of the theory of set-valued mappings. The approach is topological in nature and it permits us to establish the existence of solutions provided a criterion of uniqueness is f'ulfilled. Let E be a Banach space and let n(E) denote the family of all nonempty subsets of E. For a set A in n(E), a mapping H: A --f n(E) is called upper semicontinuous if its graph [ (x,y): y E H(x)I is closed in A X E . The map H is said to be cmpact if, for any bounded subset B of A, the closure of the set UxaBH(x) is compact in E. The map H is called completely continuous if it is upper semicontinuous and cmpact. For a single-valued mapping h: A +E, the upper semicontinuity of the mapping H: x + h(x) is equivalent to the continuity of h, the compactness of H is equivalent to that of h and the complete continuity of H means the complete continuity of h. We now state our fixed point theorem.
278
4.13. SET-VALUED MAPPINGS AND FUNCTIONAL EQUATIONS
space
THEOREM 4.13.1. Let U be a neighborhood of 0 i n t h e E and l e t H: U + n ( E ) be a completely continuous map-
ping such t h a t
x
(4.13.1)
E
H(x), x
E
U
Then, f o r any continuous mapping
h: E + E ,
h(x) - h ( y ) E H ( x - y )
(4.13.2)
x = 0.
implies
for
t h e condition
x-y E U
implies t h a t t h e equation
x
( 4 13 3)
= h(x)
has e x a c t l y one s o l u t i o n . Proof: by u ( x ) = center a t
u
Denote by u ( x )
+x
x
= [y
+ x: y
and of radius
t h e neighborhood of E
u ] and by
K(x)
x
t h e b a l l with
chosen i n such a way t h a t u ( x )
&
contains t h e b a l l with center a t
x
of radius
2 ~ .
Assumption (4.13 .l) implies t h a t t h e mapping where
I
defined
-
T = I h,
denotes t h e i d e n t i t y mapping, i s one-to-one when
r e s t r i c t e d t o t h e neighborhood
U(X),
f o r every x E E,
which,
i n i t s t u r n , shows t h a t (4.13.4) Let
T ( X ~=) T ( x ~ ) , xl S(x)
#
x ~ + K ( x ~n ) K ( x ~ =)
denote t h e boundary of t h e b a l l
claim t h a t t h e r e e x i s t s a
6
> 0,
independent of
$.
K(x).
We
x,
such
that (4.13.5)
Y E s(x)
Suppose t h a t it i s f a l s e .
* h'(y) - T(x) 11 > 6Then t h e r e e x i s t sequences
{x,],
{yn] such t h a t limn+w ( T(Y,) - ~ ( x , ) ) = 0 and Ibn-xnll = for n = l J 2 , . . . S e t t i n g rn = T(yn) -T(xn), we have
.
279
E
4 . FUNCTIONAL ANALYTIC METHODS
and consequently, by (4.13.2), (4.13.6)
Y,
- xn - rn
-
n
H(yn x,),
E
= 1,2,.
Since by assumption t h e closure of t h e set compact, we may suppose t h a t t h e sequence an element
such t h a t
z,
llzI( =
H
is
II 5 E
H(x) { y n - x n - rn} o r , IIX
{yn - xn] i s convergent t o Relation (4.13.6) and t h e
which means t h e same, t h e sequence upper semicontinuity of
u
.. .
E.
imply t h a t
which i s a
z E H(z),
c o n t r a d i c t i o n t o (4.13.1).
it follows t h a t t h e continuous
From t h e condition (4.13.2), mapping every
i s completely continuous.
h x
E
Thus, by (4.13.5),
for
we have
E,
(4.13 7 ) This shows, i n t u r n , t h a t t h e s e t
It i s e a s i l y seen that
T(E) of
#
E,
and l e t Since
T(E).
y
T(E) = E.
y
of radius
i s open,
T(E) 6,
(E,T)
simply connected,
T
Indeed, suppose t h a t
y
does not belong t o
T(x)
T(E).
lying i n t h e neighborhood
we see, by (4.13.7),
that
y
(4.13.7) and t h e f a c t
Relations (4.13.4), t h a t the p a i r
E.
be an a r b i t r a r y element on t h e boundary
On t h e o t h e r hand, f o r a point of
i s open i n
T(E)
i s a covering space f o r
f
T(E) E.
T(E). =
E
Since
imply E
is
i s a homeonorphism, and t h i s completes
t h e proof of t h e theorem.
RFMARK 4.13.1.
It i s easy t o see t h a t i f a mapping
s a t i s f i e s condition (4.13.2), t h e mapping
ha: x
--f
h(x)
- a.
then f o r every
If
b E E
h and
E
E,
so does
t h e mapping
I-h
onto i t s e l f .
i s a mapping of t h e form
A: E + E
E
Therefore, Theorem 4.13.1 may
be s t a t e d i n an equivalent form as follows:
i s a homeomorphism of
a
h
h(x) = A x
+ b,
where
i s a completely continuous l i n e a r operator,
Theorem 4.13.1 y i e l d s t h e e s s e n t i a l p a r t of the f i r s t theorem of 280
4.13. SET-VALUED MAPPINGS AND FUNCTIONAL EQUATIONS
It s u f f i c e s t o s e t
Fredholm.
H(x) = {Ax} and t o observe
t h a t condition (4.13.1) means t h e uniqueness o f s o l u t i o n of t h e
We a l s o note t h a t i n t h e
l i n e a r homogeneous equation
x = Ax.
Fredholm theorem t h e map A
may be noncontractive i n general.
The assumption t h a t t h e map
h
i s continuous, i n Theorem
4.13.1 may be dropped by strengthening t h e conditions imposed on t h e mapping
This i s t h e content of t h e next theorem,
H.
Let
THEOREM 4.13.2.
space
E
and l e t
H:
u
u +n(E)
be a neighborhood of
i n the
0
be a completely continuous
mapping such t h a t t h e implication (4.13.1) holds t r u e and (4.13.8)
H(0) = 0 .
Then f o r any mapping
h: E + E
s a t i s f y i n g (4.13.2),
Eq. (4.13.3)
has e x a c t l y one s o l u t i o n . Proof continuous
It i s enough t o show t h a t
h
i s necessarily
To t h i s end, assume t h a t a sequence
convergent t o
xo.
Then, f o r
n
Exn]
is a
s u f f i c i e n t l y large, we have
( 4-13 9 Suppose now t h a t compactness of converges t o
{h(xn)] H,
yo
#
does not converge t o
t h e r e e x i s t s a subsequence h(xo).
h(xo).
By the
{h(% ) ] n
On passing t o t h e l i m i t i n
which
(4.13.9),
we see t h a t
and t h i s implies, by (4.13,8),
that
yo
- h(xo) =
0.
This
c o n t r a d i c t i o n proves t h e theorem.
We wish t o point out t h a t without t h e assumption (4.13.8), Theorem 4.13.2
i s not t r u e .
For example, i n
281
R2
let
4. FUNCTIONAL ANALYTIC METHODS
H(x) =
[-1,11
for
x = 0,
[-1,$x]
for
x
<
0,
and
3
1
h(x) = q ( x - 7 - [x-$]). It i s easy t o v e r i f y t h a t a l l t h e assumptions of Theorem 4.13.2
a r e s a t i s f i e d except (4.13.8).
The function
not continuous and t h e equation
x = h(x)
h,
however, i s
does not have any
so l u t ion.
4.14
GENERAL LINEAR PROBLEMS A s an a p p l i c a t i o n of t h e t o p o l o g i c a l method developed i n
t h e preceding s e c t i o n , we s h a l l consider t h e question of existence of s o l u t i o n s of g e n e r a l l i n e a r problems.
I n general,
one compares t h e l i n e a r problem under consideration with another homogeneous problem s u i t a b l y chosen and from t h e uniqueness of s o l u t i o n s of t h e second, concludes t h e existence of s o l u t i o n s of t h e f i r s t .
I n t h e present case t h i s comparison
problem involves e i t h e r an equation with set-valued right-hand s i d e or some d i f f e r e n t i a l i n e q u a l i t y . denote t h e family of a l l nonempty, closed, n and convex subsets o f R For A E cf(Rn), we s e t lbll = Let
cf(Rn)
.
sup [Ilpll: p E A]. Let J be a compact i n t e r v a l of n C = C[J,R 1 with t h e norm of uniform convergence,
m a xt c J Ilx(t)II. (1) F
t
E
J xRn
i s a mapping of
IIxII =
into
cf (R").
For each
i s upper semicontinuous with respect t o
and f o r each compact s e t
(4.14.1)
and l e t
Let us assume t h a t
J, F ( t , x )
summable on
R
J,
K C Rn
x, t h e r e e x i s t s a function m(t),
such t h a t
I l ~ ( t , x ) l I1. m(t), 282
t
E J,
x
E
K;
4.14. GENERAL I.INEAR PROBLEMS
(2)
f
i s a mapping o f
JxRn
is continuous r e l a t i v e t o
f(t,x)
is suwnable with respect t o
(3)
L
into
x,
f(t,x)
Rn.
t;
i s a l i n e a r continuous mapping o f
Given t h e mappings
F, f ,
(4.14.2)
and E
t
For each
and f o r f i x e d x
c
into
E:
J,
E
R ~ ,
R ~ .
we consider t h e equation
L,
F(t,x(t))
with t h e homogeneous l i n e a r condition (4.14.3)
Ix= 0
and t h e ordinary d i f f e r e n t i a l equation X'(t) = f ( t , x ( t ) )
(4.14.4)
with t h e l i n e a r condition ~x= r,
(4.14.5)
r c R ~ .
A n absolutely continuous f'unction
a s o l u t i o n of (4.14.2) s a t i s f i e s (4.14.2)
x
E
C w i l l be called i f it
[respectively, of (4.14.4)l
[respectively, (4.14.4) ] almost everywhere
on J.
THEOREM 4.14.1.
Assume t h a t t h e h c t i o n s
-
s a t i s f y conditions (1) (3) and f o r
(4.14.6)
f(t,q)
- f(t,P)
E
Suppose f u r t h e r t h a t t h e h c t i o n of (4.14.2) s a t i s f y i n g (4.14.3).
t
E
F, f ,
L
and
J, p,q E R ~ ,
F ( t , q - PI.
x
I
0
i s t h e unique s o l u t i o n
Then f o r every
e x i s t s one and only s o l u t i o n of (4.14.4)
r
E R",
there
s a t i s f y i n g (4.14.5).
Proof: We wish t o apply Theorem 4.13.1. Consider t h e mapping H of E = C x R " i n t o cf(Rn) such t h a t f o r every point (x,p) its image H(x,p) is a s e t of a l l p a i r s (y,q) given by t h e formula
283
4. FUNCTIONAL ANALYTIC METHODS
y(t) for
u(s)
E
t
= aJ
F(s,x(s))
t h a t f o r every p o i n t
U(S)
ds + p,
q = p
- Lx
and t h e mapping h of E i n t o i t s e l f such (x,p)
i t s image h ( x , p )
is a pair
(y,q)
given by
where
a
i s a f i x e d point i n J.
From (4.14.1),
follows t h a t f o r every compact s e t sup)I\f(t,p)l\:p
E
KI
K
(4.13.2)
problem (4.14.4),
Rn,
i s bounded by a summable fbnction
Ilf(t,O) (I. It i s easy t o see t h a t t h e maps
(4.13.1),
C
H, h
H
it
m(t)
s a t i s f y conditions
and t h a t t h e existence of s o l u t i o n s of (4.14.5)
i s equivalent t o t h e existence of
s o l u t i o n s of t h e f u n c t i o n a l equation (4.13.3). map
(4.14.6),
t h e function
i s compact and t h e map h
Evidently t h e
i s continuous.
Thus t o
complete t h e proof, it i s s u f f i c i e n t t o show t h a t
H
i s upper
semicontinuous. Suppose t h a t
Then we have
and consequently
This, t o g e t h e r with t h e upper semicontinuity of
284
F,
implies
+
4.14. GENERAL LINEAR PROBLEMS
i s t h e distance f'unction. By Lema 4.14.1 (which follows below) it then follows t h a t
where
p(p,A)
~ ' ( t E) F ( t , x ( t ) ) .
(4.14.8)
On passing t o t h e l i m i t i n (4.14.7), (4.14.9)
Y(a> = P,
we obtain, f o r
9 = P
-
t = a,
Ix
and, as a r e s u l t , (4.14.10)
Y(t>
t
=J a
From r e l a t i o n s (4.14.8), that
4.13.1.
Y'(S.1 ds + p. and (4.14.10) it follows
(4.14.9),
and t h e proof i s complete by Theorem
(y,q) E H(x,p)
We now prove Lemma 4.14.1which we used i n t h e preceding proof. LEMMA 4.14.1.
Let
G
be a mapping on
J
into
cf(Rn)
and l e t a sequence {vk} of absolutely continuous f'unctions, n vk: J + R (k = 1,2, ...) s a t i s f y t h e conditions
l h v,(t)
= v(t)
k+m (4.14.11) (4.14.12)
Ivl;(t)I
Proof:
h(t),
t
a.e.
lim p ( v i ( t ) , G ( t ) ) = 0 k+ 00
Then t h e f'unction
( 4.14.13 )
5
for
v
E J
a.e.,
h ( s ) ds <
m,
a.e.
i s absolutely continuous, and
v'(t)
E
G(t)
Define 285
a.e.
i n J.
4. FUNCTIONAL ANALYTIC METHODS
m
( 4.14.14)
m
H(t) = f l conv fl v i ( t ) , i=l
k=i
where conv A denotes t h e smallest convex and closed set containing A. In view of (4.14.12), (4.14.15)
H(t)
C
G ( t ) a.e.
t
E J.
H(t) i s compact, convex, nonempty a.e. measurable i n t and Clearly
( 4.14.16)
IIH(t)ll
5 h(t)
t
a.e.
E
t
E
J,
J.
I n the proof we s h a l l use t h e following property (4.14.17)
( t - s)"
rt
r(H(u), H(s)) du + 0
as
t + s, t f s,
J S
f o r almost every s, where r(A,B) = m&x(p(A,B),p(B,A)), p(A,B) = supxd p(x,B),A,BC Rn. If H(t) reduces t o a (integrable) vector function, t h i s property i s a classical result. For t h e general case, it can be proved by using t h e standard r e a l variable methods. The function v ( t ) i s absolutely continuous because of (4.14.U). Hence the derivative v ' ( t ) e x i s t s a.e. i n J. We s h a l l now show t h a t (4.14.18)
v'(s)
E
if
H(s)
v'(s)
exists
and i f (4.14.17), (4.14.12) f o r t = s are s a t i s f i e d . The inclusion (4.14.18) i s equivalent t o ( 4.14.19)
p
( vO-v(s), t-s
because v t ( s ) exists.
H(s))+O
as
By v i r t u e of (4.14.ll),
p(vi(t),H(t)) and by (4.14.14)
286
I 2h(t)
t + s,
t >
(4.14.16),
8,
4.14. GENERAL LINEAR PROBLEMS
p(vi(t),H(t)) + O
a.e.
i n J.
Hence
Since H ( s ) i s compact and convex, there e x i s t s a unique point %(u) E H ( s ) such t h a t
-
p(vi(u),H(s)) = IIvi(u) Pk(‘>ll>
(4.14*21) the vector
pk(u)
(4.14.22)
gk(t) = ( t - s)-l
We have
(4.14.23)
p(
is integrable and
pk(u) du
w,
H ( s ) ) = k+m lim
It follows from (4.14.22) that
Therefore, we f i n d that
because of (4.14.21),
and consequently 287
p(
E
H(s).
-
vk(t> t-s
4. FUNCTIONAL ANALYTIC METHODS
+ ( t- s ) - l By
v i r t u e of (4.14.20),
Lt
r(H(u),H(s)) ds.
(4.14.23),
(4.14.24),
we obtain
The conand by (4.14.17) we obtain (4.14.19) and (4.14.18). clusion (4.14.13) easily follows because of (4.14.15). The proof i s complete.
Theorem 4.14.1 assumes a particularly simple form, i f Eq.
(4.14.2) reduces t o a d i f f e r e n t i a l i n e q u a l i t y (4.14.25)
+
where w: J xR + R
+
IIX’
II 5 w ( t ,
llxll ),
i s a f’unction satisfying t h e condition
(4) f o r each t E J, w(t,u) i s continuous w i t h respect + t o u and f o r each u E R , w(t,u) i s measurable w i t h respect t o t; the functions sup[w(t,u): u 5 k], k = 1 , 2 are
,...,
suuimable. COROLLARY 4.14.1.
t h e conditions (2) -
and L satisfy (4) and, i n addition, the inequality
Ilf(t,P)
If t h e functions
f, w
- f(tY d I I 5 w ( t , IIP - 911 )
holds and i f the problem (4.14.3),
(4.14.4) has only t h e t r i v i a l s o l u t i o n x = 0, then there exists one and only s o l u t i o n of t h e problem (4.14.4), (4.14.5). For the proof it is enough t o set
F(t,p) = [q: ((qll,< and then apply Theorem 4.14.1. w(t,llpll)] L e t us demonstrate Corollary 4.14.1by an example. 288
4.15. GENERAL RESULTS FOR SET-VALUED MAPPINGS
Consider Eq. (4.14.4) with the boundary condition (4.14.26)
x(a) + k ( b ) = r,
h
> 0,
J
=
[a,bl.
It is easily verified that every solution of the d i f f e r e n t i a l
inequality IIx' 11 < tp(t)llxll where cp(t) i s a positive sumable b function such that I, cp(s) ds < T, satisfying the homogeneous boundary condition x(a) + k ( b ) = 0 i s necessarily t r i v i a l . Indeed, it is w e l l known that f o r an absolutely continuous function x ( t ) satisfying the d i f f e r e n t i a l inequality IIx'I) < cp(t)Ilxll, either x ( t ) p 0 o r x ( t ) i s never 0 on J. Suppose t h a t x ( t ) i s never 0. Then s e t t i n g z ( t ) = x(t)/llx(t)ll, we a r r i v e a t the following contadiction
Thus from Corollary 4.14.1the next corollary follows
immediately. COROUARY 4.14.2.
If the function
f
s a t i s f i e s hypothesis
(2) and the inequality
IIfhP)
- f(t,q>ll 5 cp(t)llp-
911,
where y ( t )
i s positive sumable function verifying I, rp(s) ds < T, then f o r each r E Rn, the problem (4.14.4), (4.14.26) has exactly one solution. b
4.15
GENERAL RESULTS FOR SET-VALUED MAPPINGS
In what follows, we wish t o construct a general theory of l i n e a r problems f o r set-valued d i f f e r e n t i a l equations o r some times called contingent equations, by u t i l i z i n g fixed point theorems f o r set-valued mappings. With t h i s motive, we introduce necessary tools and prove some general r e s u l t s concerning set valued mappings. We s h a l l first s t a t e the Kakutani-Ky Fan fixed point theorem. 289
4. FUNCTIONAL ANALYTIC METHODS
THEOREM
4.15.1. Let L be a locally convex topological
linear space and K a compact convex set in L. Let cf(K) be the family of all closed convex nonempty subsets of K. Then for any upper semicontinuous point to set transformation f from K into cf(K), there exists a point xo E K such that xo E f(xo). We shall now consider some preliminary results. We shall continue to use the same notation of Section 4.14. Let Lp (15 p ,< m) denote the Banach space of all real-valued P will denote its n 3 functions p-summable on J = [a,b]; Ln Cartesian power. In both Lp, LE, the norm w i l l be denoted by
II. Itp*
For a linear normed space E, let, as before, cf(E) denote the set of all closed, convex, nonempty subsets of E. A mapping G: J + cf(Rn) is called measurable if for every p E Rn the distance from p to G(t) is measurable on J. The following lemmas are needed in our main results. LEMMA
4.15.1. If sequences {wi] c Lg, {v,]
C Lp and functions v E Lp and w satisfy the a.e. conditions: Iwi(t)l 5 vi(t) a.e. on J, wi(t) +w(t) on J and llvi- vllp + 0 , then w E LE and llwi-wllp 4 0 .
(1,< p <
m),
The proof is left to the reader as an easy exercise. LEMMA 4.15.2. For a sequence {w,] C L’ and a m c t i o n n L1 satisfying Iwi(t)l 5 cp(t) a.e. on J, there exists k = i,i+l, ...) of a double sequence {A.ik] (i = 1,2 m real nonnegative numbers such that %=1 hik = 1, hik = 0 for sufficiently large k (depending on i), and the sequence
cp E
,...;
m
290
4.15. GENERAL RESULTS FOR SET-VALUED MAPPINGS
converges a.e. on J to a function w Proof: Setting yi(t) = wi(t)/[l
E
1 Ln.
+ cp(t)]",
1
we have
and consequently, we can find a sequence {y 3 and a function 2 Pi yo E Ln such that limi+.. yBi = yo in the sense of weak con2 vergence in Ln. By virtue of the Banach-Saks theorem, one can find a conveniently chosen partial sequence such that
in place of the sequence {y 1. Bi
As the sequences
tend to zero because of (4.1.!j01),we obtain ,,
2
n +n-1
By Riesz's theorem, there exists a sequence of an? n such that CY
lim
n-w
u
n
f o r a l l t E J.
c" i=un
YBi(t) = y,(t>,
an
=
It is now easy to see that
29 1
2
an + an- 1
4. FUNCTIONAL ANALYTIC METHODS
converges f”r a l l values on J
t o t h e function
w =
TI“.
Thus i n order t-o show t h e conclusion it i s 2 s u f f i c i e n t t o s e t Aik = 1/ci if t h e r e e x i s t s an index i
yo/[l +
k = pi,
f o r which
an
LEMMA 4.15.3.
a function y
E
a.e. on J, such t h a t
Lt
of i n t e r s e c t i o n
G(t)
center a t t h e o r i g i n of
to
0
where y(t)
E
It i s enough t o take f o r
Proof:
hi k = 0
Let a map G: J +cf(Rn)
5 rp(t)
IlG(t)II
and s e t
The proof i s complete.
contrary case.
let
5 pi 5 an,
G(t),
n
K(t),
0
of
where
i n the
be measurable and 1 Then t h e r e i s
cp E L
.
G(t)
a.e. on J.
y(t)
t h e unique point
K(t)
i s t h e b a l l with
and radius equal t o t h e distance
Rn
and appiy t h e known theorem t h a t t h e i n t e r -
section of two measurable functions i s a l s o measurable. Let
F: J xRn + cf(Rn) be such t h a t
(i)
f o r every fixed
n R , t h e function
x
E
t
E J,
F(t,x)
is
measurable on J; (ii)
f o r every fixed
upper semicontinuous on (iii)
and
qP2)
case
1_< p2
p1 = such t h a t
R”.
t h e r e exist functions
s = P1P2/(P1-
*,
THEOREM 4.15.2.
0
0
Let
F E
CY
p2 L , @ E Ls,
E
I P29 < PI’
< *,
For a given function x
t h e function
Iq <
03,
s
F(t,x)
is
where
1 I P1’P2 < co ( i n = p2 i s not excluded),
s a t i s f y assumptions ( i ) - ( i i i ) .
P1 Ln , l e t 292
Q(x)
denote t h e s e t of
4.15. GENERAL RESULTS FOR SET-VALUED MAPPINGS
y: J + Rn
a l l measurable f’unctions
y(t) E F(t,x(t))
llxll
Q(x)
(b)
Q(x) i s convex;
(C)
(a)
p2. Q(X) C Ln 9 Q(x) i s closed;
(e)
f o r every
5
k
on J.
x
We have t o show that f o r every
(a)
P1
a.e.
x + Q(x) defines a bounded mapping
Then t h e correspondence
Proof:
such that
E
P1 Ln
i s nonempty;
implies
t h e r e e x i s t s an M > 0
k > 0, lly[[
p2
C M
-
f o r every
y
E
such t h a t
Q(x).
We would prove only ( a ) , because (b) i s t r i v i a l l y true, ( e ) follows immediately from assumption ( i i i ) and obviously implies (c), and
kt
{xi] c
(a) w i l l
2
follow from Theorm 4.15.2 below.
be a sequence of measurable functions
admitting only a f i n i t e number of d i f f e r e n t values, convergent p1 La.e. on J. By assumption ( i ) t h e 11 (i = 1,2, ...) a r e measurable on J functions F ( t , x i ( t ) ) 1 and therefore, by Lemma 4.15.3, there a r e functions yi E Ln such t h a t yi($) E F ( t , x i ( t ) ) a.e. on J. For
t o a f’unction x
E
we have, by assumption ( i i i ) ,
Ilwi(t)l/
51
a.e.
on J.
Now
a straightforward application of Lemma 4.15.2 gives a sequence Gii(t) = C hikwk(t), k=i
293
i = 1,2
,...,
4. FUNCTIONAL ANALYTIC METHODS
which converges t o a function w E LL
n
a.e. on J.
It i s
e a s i l y seen t h a t t h e corresponding sequence
converges a.e.
t o a function
on J
Y(t> = w(t>[a(t> +
B(t>l!dt>llql
On the other hand, by assumption ( i i ) , f o r almost every fixed
t
and any
E J
>
E
F(t,xi(t))
there i s an integer
0
C
F(t,x(t) = [u
for
i
3 N(&,t).
+ kE
+ v: u
E
E
F(t,x(t)),llvll
F ( t , x ( t ) ) + kE,
and, by the convexity of yi(t>
2
E
F ( t , x ( t ) ) + kE,
THEOREM 4.15.3.
a.e. on J.
r
If
i n t o a Banach space
i
2 N(E,t)
i
2 N(E,t),
i s a l i n e a r transformation of then
E,
I'Q
It i s c l e a r t h a t f o r every
i s convex.
p1 {xi] C Ln , {z,]
imply
z
E
rQ(x).
E]
This proves t h e theorem.
maps
and i s upper semicontinuous.
TQ(x)
5
F(t,x(t)),
y(t) E F(t,x(t))
Proof:
such t h a t
Thus
yi(t>
so t h a t
N(E,t)
x
E
2
$
into
cf(E)
the set
Thus it remains t o prove t h a t f o r sequences
c E,
and x
E
p1 Ln , z
E
E,
For t h i s purpose, define 294
t h e conditions
zi =
mi,
yi E
a(.,)#
4.1 6 . SET-VALUED DIFFERENTIAL EQUATIONS
As i n t h e proof of Theorem 4.15.2
l o s s of generality, t h a t
[one can assume, without a.e. on 51 an
xi(t) + x ( t )
application of Lemma 4.15.2 y i e l d s a convergent sequence W
such t h a t
y(t)
E
F(t,x(t))
that is,
a.e. on J,
y
E
Q(x).
By assumption ( i i i ) , we have W
W
= a(t)
Denoting by
vi(t)
+
@(t)llx(t)llq, we f i n d e a s i l y t h a t applying Lemma 4.15.2,
k=i
4.16
-
-
+0 p2
+ 0.
and then, On t h e other
W
$ 1. = Z h i kIyi c m p l e te
llvi
(Iyi yII
we obtain
W
so that
v(t) = a(t) +
t h e l a s t sum and s e t t i n g
=
z = Iy and therefore
.
z
E
rQ(x).
The proof i s
SET-VALUED DIFFERENTIAL EQUATIONS Having developed necessary r e s u l t s concerning set-valued
mappings i n t h e preceding section, we a r e now ready t o employ t h e Kakutani-w Fan theorem t o prove an existence theorem f o r boundary value problems of set-valued d i f f e r e n t i a l equations. The r e s u l t s we present may be considered as extensions of c l a s s i c a l theorems on boundary value problems. Consider a system 295
4. FUNCTIONAL ANALYTIC METHODS
(4.16.1)
x'(t)
E
A(t)x(t) + F ( t , x ( t ) )
and a condition Lx = r.
(4.16.2) We shall assume t h a t
(a) A: J +A*, where A* i s the algebra of n x n matrices, which a r e measurable and integrable i n J ; +cf(Rn) such t h a t n (bl) f o r each x E R , the function F(t,x) i s measurable, n t h a t is, f o r each p E R , the distance from p t o the s e t (b)
F: J x R "
F ( t , x ) i s a measurable function (b2) f o r each t E J, the semicontinuous on R ~ , that i s , implies yo E F(t,xo); (b ) t h e r e exist function 3 integrable i n J such that
(a) (4.16.3)
E
in
i s upper
xi +xo, yi +yo, yi
E
F(t,xi)
a, f3 which a r e measurable and
R".
A, L,
and
x'(t)
r
are such that the problem
- A(t)x(t)
admits solutions for a l l Q~
F(t,x)
is a l i n e a r continuous operator from C = C[J,Rn]
(c) L i n t o R ~ ,r
i n J; function
f
=
f(t),
Lx = r,
belonging t o a l i n e a r manifold
L ;:
( e ) f o r every x E C, Q(x) i s the s e t of functions n y: J + R , measurable, such t h a t y ( t ) E F ( t , x ( t ) ) a.e. on J, and suppose t h a t Q(v) E cf(Qr), for each v E C w i t h Lv = r. Observe that condition ( a ) implies the existence of a which i s continuous and s a t i s f i e s unique function U: J X J +A*, the i n t e g r a l equation 296
4.16. SET-VALUED DIFFERENTIAL EQUATIONS
where
In i s t h e i d e n t i t y of
Also
i s a l i n e a r operator, continuous (and
U(.,s)
n R
compact), from
A*.
into
while t h e composition product
C,
% = L.Uf.,S) i s a l i n e a r operator from Rn
Furthermore, it i s known
m x n matrix has a generalized inverse and con-
t h a t every
%
sequently, t h e r e e x i s t matrices
For a fixed
:'I
f
+I'f
$ and hence can be
into
represented by an m x n matrix.
s
E
J,
of type
L1 n
= -U(t,s)q
into
such t h a t
l e t us define t h e l i n e a r operator
1
t
U(t,T)f(T)
dT
+
S
from
nxm
Lt
U(t,T)f(T) d7,
It i s easy t o prove by Ascoli's theorem
C.
t h a t t h i s i s a compact operator. Let us f i x a solution
c E Rn
+
Hr = u(t,s)(c
We claim t h a t i f
f E Or,
of
L$
= 0
and write
9).
t h e function
x=m+Hr i s a solution of problem (4.16.3).
t h e l i n e a r operator D(X
+
d/dt
Indeed, denoting by
- A(t)
from
t
Hr) = D [ - U ( t , s ) Q l S
297
c
into
D
Li we have
U(t,T)f(T) dT]
+
4. FUNCTIONAL ANALYTIC METHODS
+D
L t U(t,T)f(T)
+ D[U(t,s)(c + 9 1
dT
f t U(t,T)f(T) dT = f ( t ) .
= D
J S
Concerning t h e second equation i n (4.16.3), f E Or
means t h a t t h e r e e x i s t s an
7
E
we n o t i c e t h a t such that
Rn
n t
and hence
Js
+ L
U(t,T)f(T) d T +
= G [ r - L J
n t
U(t,T)f(T) dT1 + L
S
t
= r-L
r
U(t,T)f(T)
S
t
U(t,T)f(T) dT + L
J S
=
+
dT
r
t
U(t,T)f(T) dT
J S
r,
which proves our claim. By Theorem 4.15.2,
t h e correspondence x +Q(x) defines 1 a bounded transformation from C i n t o cf(Ln) and consequently, by Theorem 4.15.3,
r Q
and i s upper semicontinuous.
Hence
T: x + T ( x )
transforms
= I'Q(x)
+
C
cf(C)
[Hr}
i s a n upper semicontinuous transformation from C 29 8
into
into
cf(C).
4.16. SET-VALUED DIFFERENTIAL EQUATIONS
Let us denote by Vr, the linear manifold in C
vr
= [v E C: Lv = rl.
To prove the existence of solutions of the boundary value problem (4.16.1), (4.16.2), under hypotheses (a)- (e), it is enough to show the existence of a f’unction v E Vr such that v E T(v). By (e), T transforms Vr into cf(Vr). Indeed, the by (e); hence, transformation Q maps Vr into cf(Or), for each f E or, H + Hr is a solution of (4.16.3). Conl Y + Hr E Vr or transforms Or into vr- EH,~. sequent-, As r is linear, rQ(x) is convex for each v E Vr and since rQ is upper semicontinuous, it follows that rQ is closed for each v E Vr. This shows that T transforms Vr into cf(Vr). For x E C, z E T(x), we have by assumption (b ),
(4.16.4)
llzll
L llrll(ao + ~ ~ ) 1 1 ~ +1 1I I ~ r l l ,
where a. = JJ a ( s ) ds, Po,=’! JJ B ( s ) ds, and llrll of r. Let us suppose that Bollrll < 1 and set
K
P
= [X E
p =
C:
IIxII
_<
3
is the norm
P,
(~oIIrIt + IIH~II)(1-p0IIrII-’)
+ a,
where a > 0 is sufficiently large so that K fl Vr # #. P It follows easily from (4.16.4) that T(x) C K for P that is, T(KP) c KP, where T(KP) = T(x). each x E K P’ P Hence, we have T(KP n V,) c K I-7 Vr. AS K n vr is bounded, by Theorem 4.15.2, Q(K~ n v ,) P is bounded and as P is compact, it follows that T(K P fl V , ) is relatively compact in C. which Let us consider the convex closure of T(KD n V,),
uxEK
299
-
4. FUNCTIONAL ANALYTIC METHODS
we denote by co T(Kp
-
n V,);
then we readily obtain
n v,) C C O ( K ~n
c0 T(K,,
vr) =
K~ n
vr
as Vr, being the inverse image of the point r by the continuous operator L, is closed and K II Vr is closed and P convex. Hence T(=
T ( K ~n
vr))
c T ( K ~n
vr) = CO T ( K ~n v,).
Therefore the upper semicontinuous map T transforms the compact and convex set co T(K n Vr) into itself and conseP quently an application of Ky Fan fixed point Theorem 4.15.1 shows the existence of v E T ( K n Vr) such that v E Vr P We have thus proved the following theorem. and v E T(v).
4.16.1. Under hypotheses (a) - (e), problem (4.16.1), (4.16.2) has a solution if f3, = lJf3(s) ds is THEOREM
sufficiently small. If $ = m 5 n, problem (4.16.3) has a solution for each 1 f E Ln and each r and conversely. Let us call this hypothesis (f). If (f) holds, Qr = L1 n for each r E ? and in this case (a) is automatically satisfied. Hence from Theorem 4.16.1, we obtain the next corollary.
4.16.1. Under hy-potheses (a)- (c), (f), problem (4.16.1), (4.16.2) has a solution for ar!y r E ? if COROUARY
lJf3(s) d s
is sufficiently s m a l l . which .If $ = m = n, there exists only one matrix is the inverse of $ , for which the only solution of $C = 0 is c = 0 . Thus denoting by (h) the hypothesis that problem (4.16.3) has a unique solution for each f E Li and each n r E R , we have the following corollary. Po
=
COROUARY
Ltf
4.16.2. Uhder hypotheses (a)- (c), (h), problem 300
4.16. SET-VALUED DIFFERENTIAL EQUATIONS
(4.16.1),
so
(4.16.2) has a solution f o r each r = JJB(s) ds is sufficiently s m a l l .
Rn,
E
if
I n order t o i l l u s t r a t e the results, consider t h e following problem analogous t o the classical problem of Nicoletti,
(4.16.5)
x'
F(t,x),
E
xi(ti) = ri,
ti
E J,
Since the corresponding homogeneous problem x'
= 0,
xi(ti) = 0,
ri
E
R, i = l , 2
,...,n.
,...,n,
i = 1,2
has a unique solution x ( t ) a 0, an application of Corolhry
,...,
4.16.2 w i t h A(t) 5 0 and Lx = (x(tl),x(t2) x ( t n ) ) yields the existence of a t l e a s t one solution of (4.16.5) f o r arbitrary (rl,r2,. ,rn), provided F satisfies hypothesis (b) and
s,
..
= /,s(s>
-= 1.
ds
I n the case of the Cauchy problem
(4.16.6)
x'
E
F(t,x),
x ( t o ) = r,
to E J,
r
E
n
R
,
condition Po < 1 i s superfluous. It i s easy t o verify that replacing the usual norm i n .C by
we obtain, instead of (4.16.4) 11zo
f o r every
5 311x" + a() +
llrll
T(x). KLSO T ( K ~ )c K~ f o r P = 2(a0 + Ilrll). This implies t h a t i f F satisfies m o t h e s i s (b), then the Cauchy problem (4.16.6) has a t least one solution defined on J. Let us conclude with one more application. Consider the z
E
problem
(4.16.7)
X'
-A(t)x
E
F(t,x), 301
-
x(T) x(0) = 0,
4. FUNCTIONAL ANALYTIC METHODS
where
i s a periodic
A(t)
F: R x R n + cf(Rn)
n x n matrix of period
such that
F ( t +T,x) = F ( t , x ) .
T
and
Let hypotheses
( a ) , ( b ) hold and l e t
(4.16.8) with
f(t
X'
+
(4.16.3).
- A(t)x = f ( t ) ,
T) = f ( t ) ,
x(T)
- ~ ( 0 =) 0
be t h e problem s i m i l a r t o problem
Recall t h a t i f t h e homogeneous system has p e r i o d i c
s o l u t i o n s , then t h e a d j o i n t system has a l s o such s o l u t i o n s . Denoting by
Z
Assume t h a t
F ( t , v ( t ) ) E cf(OO) f o r each
t h e space of such s o l u t i o n s , we have
v E Vo,
where
Vo
i s t h e space of f'unctions from R i n t o Rn, continuous and p e r i o d i c with period T. Then by Theorem 4.16.1, Eq. (4.16.7) admits a t l e a s t one s o l u t i o n x ( t )
and t h e r e f o r e t h e set-valued
d i f f e r e n t i a l equation (4.16.7) has a l e a s t one p e r i o d i c s o l u t i o n of period 4.17
T.
NOTES AND COMMENTS Sections 4.1
- 4.3
a r e concerned with t h e r e s u l t s of Opial [2].
For r e l a t e d work, see Lasota and Opial [ 2 ] and Whyburn [l]. The contents of Section 4.4 are based on Conti [1,2]. further references,
see Conti's survey paper [21.
For
The results
contained i n Sections 4.5- 4.7 a r e adapted from Perov and Ribenko [2].
See Lepin and Nyshkis [l] f o r t h e r e s u l t s i n
Section 4.8.
The work i n Section 4.9 i s due t o Antosiewicz
[l].
Sections 4.10 and
and Yorke [ U I . [ 31.
4.11 c o n s i s t
of t h e results of Lasota
See, f o r more g e n e r a l results, Bernfeld e t al.
Section 4.12 contains t h e work of Schmitt [7 1.
Related
r e s u l t s on p e r i o d i c s o l u t i o n s may be found i n Schmitt [1,6,8] and Mawhin [1-31.
Sections 4.13 and 4.14 d e a l with t h e results
of Lasota and Opial [71 and Lasota [91. 302
For Lennna 4.14.1,
4.11. NOTES AND COMMENTS
see Plis [l]. For the results of Section 4.15, see Lasota and Opial [ j ] . The contents of Section 4.16 are taken from Grandolfi [ 11. For further results, see Lasota [51, Lasota and Olech [61, Ky Fan [11 and Chow and Lasota [l].
303
Chapter 5 EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
5.0
INTRODUCTION
We extend, in this chapter, some of the results of the preceding chapters, to boundary value problems associated with f'unctional differential equations. We begin by proving existence theorems in the s m a l l . We then extend the theory of differential inequalities and the modified function approach, to establish existence results in the large. A shooting type method is presented to derive existence and uniqueness results. We also consider the question of existence of solutions of quasilinear functional differential equations with nonhomogeneous linear boundary conditions. Finally, a more general problem is treated where the boundary conditions are prescribed in terms of bounded linear operators.
5.1 EXISTENCE
I N THE SMALL
are given functions that are bounded together with their derivatives on their respective domains. We shall Consider the BVP
( 5 1.1) (5.1.2)
x"(t) x(t)
=
=
cp(t)
f(t,x(t>,x(h(t,x(t)),x' on Ja,
x(t)
=
(t)), $(t)
We seek functions x where f E C[JxRxR,R]. satisfying the BVP (5.1.1), (5.1.2). Consider the Banach space B given by
3 04
on Jb> E
C(2)[J,R1
5 . l . EXISTENCE IN THE SMALL
with t h e norm I-
Here
I - \
BC"'[I,R]
C(l)[I,R] bounded on
means, as x u a l t h e class of f'unctions
such t h a t
implies that
y E BC(l)[I,R]
y,y'
are
I.
Recall from Section 1.1.1, t h a t if G(t,s)
is the Green's
function associated with the BVP
x"
x ( a ) = x(b) = 0,
= 0,
of t h e BVP
then the solution x ( t )
x ( a ) = x ( b ) = 0,
x" = p ( t ) ,
is of t h e form x ( t ) =
Iab
-
G(t,x) =
G(t,s)p(s) ds.
{
t
:i"yx)'
Also, l e t w ( t ) be defined on R
t
Define G(t,x) E
J,
J.
such t h a t
t t
-
b) ~ b-a Then c l e a r l y
w
(t-a )
p (
E
B,
Tx(t)
+
cp(a>, t
E
Ja,
E Jb, 6
J.
E B.
We next define t h e operator
x
as
=s,"
T
on B such t h a t f o r each
F ( t , s ) f ( s , x ( s ) , x ( h ( s , x ( s ) ) ) , x ' ( s ) ) ds
The following properties of
+ w(t).
T may be e a s i l y established as
i n Section 1.1.1:
305
5. EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
Tx(t)
(2)
i s twice continuously d i f f e r e n t i a b l e on 3 ;
(3) (W'W = f ( t J x ( t > i x ( h ( t , x ( t > ) J(~t )' ) on J; ( 4 ) T: B + B and the fixed points of T a r e solutions of t h e BVP (5.1.1) and (5.1.2); ( 5 ) T i s a continuous operator. Let R.
>0
M,N
be given such that
(w(t)l
(w'(t)( IN
5 Mj
We consider the closed, convex, bounded subset
Bo
on
of B
defined by Ix(t)l
Bo = [X E B:
_<
Ix'(t)l
_< 2N]
and we l e t q = [ s ~ P I ~ ( ~ , x , Y , t~ )EI J:J
If x
Irac(t>l
E BoJ
5
IYI 5
IzI
we can compute, a s i n Theorem 1.1.2,
((b-a)2/8)
t o conclude
1x1,
4
+ M J
5
I(m)'(t)l
5 m]*
t h e estimates
( ( b - a ) / 2 ) q +N,
-
(b a)*/8 5 M, We can then use Ascoli's theorem and
TBo c Bo;
provided t h a t
((b - a)/2) q 5 N. Schauder's fixed point theorem t o complete t h e proof of the following r e s u l t concerning t h e existence i n t h e small.
COROLLARY 5.1.1.
bounded on J x R 3
.
Assume t h a t
f E c[JXR3,R]
Then every BVP (5.1.1),
(5.1.2)
and i s has a
solution. The foregoing r e s u l t s remain v a l i d if we assume that
306
f
5.1, EXISTENCE IN THE SMALL
and x are vector-valued functions and I I denotes an appropriate vector norm. In fact, one can suitably state and prove a more general existence result when the derivative x' also contains a deviated argument like x'(g(t)). This we give as an exercise. EXERCISE 5.1.1.
State and prove an existence theorem for
the BVP x"(t> = f ( t , x ( t > y x ( h ( t , x ( t > > > , x (t>yx'(g(t>>), ' x(t) = cp(t),x'(t> = cp'(t> on Jay x(t> = Jr(t),x'(t) = Jr'(t) on Jb. Regarding the question of uniqueness of solutions, the following example illustrates the difference between the BVP
(5.1.1), (5.1.2) and its associated BVP without derivatives in the arguments Consider the BVP
.
x"(t)
-
=
x(t> 1 + IX(X(t>)l
for t < o
X = O
y
oet..
and
tLT.
It is easy to check that x(t) = c sin t is a solution of this problem for any c 5 0 whereas, the corresponding problem, nameXY, x"(t)
=
-
x/(l
+
[XI),
x(0)
=
x(7r)
0
5
t
< ny
= 0,
has only the trivial solution. Nonetheless, the uniqueness is guaranteed, if f satisfies an appropriate Lipschitz condition, as is common in these type of problems. A verification of this statement is left to the reader.
307
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
and f o r
t
E
Ix(t)l
(b
- a)/2]
,< kl,
<1
kl, ( h ( t , x )
- h(t,xl))
5 M I X - xl/.
(5.1.2) has a t most one solution x ( t )
Then t h e BVP (5.1.1), with
5
J, 1x1, Ixl(
5
Ix'(t)l
where
q = L1
k2
provided t h a t
2 q max[(b-a) /2,
+ L 2 ( l + k p ) + L3-
Let us now s i n g l e out f o r l a t e r use, a s p e c i a l case of t h e
BVP (5.l.l),
(5.1.2)
specifically, l e t and
Jb,
i n which f t
h(t,x)
- 7,
i s of retarded type. 7
> 0,
so t h a t
More
Ja = [ a - 7,aI
The corresponding BVP may be s t a t e d
a s i n g l e point.
as (5.1.3) (5.1.4) 5.2
x"(t) = f(t,x(t),x(t x ( t ) = cp(t),
t
E
- T),x'(t)),
[&-?,a],
x ( b ) = B.
EXISTENCE I N THE LARGE
Let us consider t h e second-order functional d i f f e r e n t i a l equation (5.1.1) together with t h e boundary conditions (5.1.2), with respect t o which, we shall define upper and lower solutions. DEFINITION 5.2.1.
A f'unction
second derivative on J (5.1.1),
(5.1.2),
CY E
B
having a continuous
w i l l be called a lower solution of
if
( i ) a " ( t >2 f(t,CY(t>,CY(h(t,CY(t>)),a'(t)), t E J, ( i i ) a ( t ) 5 cp(t) on Ja, a ( t ) 5 q ( t ) on Jb.
An upper solution @(t)
of (5.1.1),
(5.1.2) i s defined
s i m i l a r l y by reversing i n e q u a l i t i e s ( i ) and ( i i ) . We s h a l l e s t a b l i s h t h e following r e s u l t . THEOREN 5.2.1.
f
Consider t h e BVP (5.1.1),
s a t i s f i e s t h e conditions: 308
(5.1.2),
where
THE LARGE
5 . 2 . EXISTENCE IN
(i)
f(t,x,y,z)
(t,x, z 1;
is nonincreasing i n y
f o r each
3
( i t > If(t,x,y,z)I ,< 9 on J x R , ( i i i ) there exist constant functions
Q,
which a r e
f3
(5.1.2)
lower and upper solutions, respectively, of (5.1.1), such t h a t
Q
_< B.
Then there e x i s t s a solution x ( t )
(5.1.2) with a,< x ( t )
(5.1.1),
,< f3, t
of
R.
E
Let us define a modified f'unction F by
Proof:
If(t,ff,?,x')
x-a -
+
if
x
< a,
l + x
where
B Y
a Since
> B, if ~ ~ Y I B , i f y < a.
if Y
i s bounded, because of ( i i ) , by Corollary 5.1.1,
F
modified BVP x " ( t ) = F(t,x(t),x(h(t,x(t))),x'(t)), has a solution x ( t ) .
Also, by the definition of
the
(5.1.2) F and
assumption ( i i i ) , we have (5.201)
F(t,Q,a,O) _< 0
We now claim t h a t a f a l s e . Then, since
tl,t2
E
(a,b)
and x(t,)
=
5
,< x ( t ) _< B, t E Q 5 x ( t ) _< B, t
=
Suppose that t h i s i s
R. J,
x(t)
>
there e x i s t
tl < t < t2 x ( t 2 ) o r x ( t ) < a f o r tl < t < t2 and
such t h a t e i t h e r
B
F(t,B,P,O)*
f3
for
a = x ( t 2 ). We s h a l l deal with t h e f i r s t case, the arguments of the second case being similar. There e x i s t s a
x(t,)
=
tO,tl < to < t2, such t h a t
x(t) 309
-B
assumes a positive
5 . EXTENSlQNS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
maximum a t
to, with x ' ( t o )
Then because of (5.2.1),
= 0.
we o b t a i n
By condition (i)and t h e d e f i n i t i o n of
-
F,
we f i n d t h a t
2
x " ( t o ) 2 ( x ( t o ) @)/(1 + x ( t o ) )> 0. This c o n t r a d i c t s t h e f a c t t h a t x ( t ) @ assumes a p o s i t i v e maximum a t to. Therefore x ( t ) _< f3, t E R. Similarly, we conclude Q _< x ( t ) on R. This, however, implies t h a t
Hence
-
which assures t h a t (5.1.2).
x(t)
i s a c t u a l l y a s o l u t i o n of (5.1.1),
The proof i s thus complete.
The next r e s u l t i s concerned with t h e existence of s o l u t i o n s of t h e BVP (5.1.1),
(5.1.2) where a s s m p t i o n (ii)of Theorem
5.2.1 i s omitted.
THEOREM 5.2.2.
Assume f u r t h e r t h a t
( i )and (iii) of Theorem 5.2.1 hold.
satisfies Nagumo's condition on whenever
CY
5 x ( t ) _< @ , a5
[a,b]
x(h(t,x))
(5.1.2) has a s o l u t i o n such t h a t Proof:
and l e t
Consider t h e BVP (5.1.1), (5.1.2)
Q
5
relative to f3.
_< x ( t ) 5 B on R.
W e f i r s t d e f i n e t h e f u n c t i o n Fo by
where, as before,
310
a,
Then t h e BVP
f
f3
(5.1.1),
5 . 2 . EXISTENCE IN THE LARGE
'=I
-
Then
x
if
a-<xL@,
Q
if
x
y=t
-
< a,
Y a
t h e r e i s an
x(t)
such t h a t i f
N> 0
x " ( t ) = F,(t,x(t),x(h(t,x(t))),x'(t)) Q _< x ( h ( t , x ( t ) ) ) 5 B, then I x ' ( t ) l t h e function
Then F
F
Hence, by Theorem 1.4.1,
satisfies Nagumo's condition.
Fo
if Q I Y I B , i f y < a.
i s a s o l u t i o n of
and
Q
on
N
_< x ( t ) 5 B, J.
Now define
F by
a l s o s a t i s f i e s t h e Nagumo's condition and furthermore,
Also
i s bounded on JxR'.
F(t,a,cY,O)
5
0
5
F(t,@,B,O).
We thus conclude by Theorem 5.2.1 t h a t t h e f u n c t i o n a l d i f f e r e n t i a l equation
x " ( t > = F(t,x(t>,x(h(t,x(t>>>,x'( t ) ) together with t h e boundary conditions (5.1.2) has a s o l u t i o n
x(t)
satisfying
CY
Ix(t)
By t h e d e f i n i t i o n of
F,
_< B on R.
Hence a l s o
t h i s implies t h a t
a solution of (5.1.1), (5.1.2),
Ix'(t)l
5
N.
x ( t ) i s actually
completing t h e proof.
If t h e deviating argument i s independent of t h e s o l u t i o n
i t s e l f , that is,
h(t,x)
E
h(t)
may be assumed t o be functions of
only, upper and lower s o l u t i o n s
t
i n s t e a d of constants.
We
s h a l l merely s t a t e as exercises r e s u l t s corresponding t o t h a t situation.
In f a c t , we s h a l l r e s t r i c t ourselves t o t h e BVP
(5*1-3), (5*1*4). EXERCISE 5.2.1.
With respect t o t h e BVP (5.1.3),
l e t hypotheses (i)and (ii)of Theorem 5.2.1 hold.
311
(5.1.4),
Furthermore
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
suppose t h a t t h e r e e x i s t lower and upper s o l u t i o n s r e l a t i v e t o (5.1.3),
of (5.1.3),
Then t h e r e i s a s o l u t i o n x ( t ) a(t)
5
5
x(t)
p(t)
on
(5.1.4) s a t i s f y i n g
R.
(5.1.4),
Relative t o t h e BVP (5.1.3),
EXERCISE 5.2.2.
cu(t),@(t) on R.
a ( t ) _< p ( t )
(5.1.4) such t h a t
l e t a l l t h e hypotheses of Theorem 5.2.2 hold except t h a t
a,p
are not assumed t o be constant lower and upper s o l u t i o n s . there exists a solution x ( t ) a(t)
_< x ( t ) 5 p ( t ) on R.
5.3
SHOOTING METHOD
of (5.1.3),
Then
(5.1.4) such t h a t
Let us consider t h e second-order delay d i f f e r e n t i a l equation x"(t) = f(t,x(t),x(t- h(t))),
(5.3.1) where
where
x ( t ) = cp(t), cp
C[[-c,o],R]
E
5t5
T,
s u b j e c t t o t h e boundary conditions
h E C[[O,T],R+],
(5.3.2)
0
t
and
E
x(T) = A,
[-c,O],
- c = min[t
- h(t):
0
5t5
TI.
We
assume t h a t (1) f E C[[O,T] xR2,R],
f o r each
(t,x);
(2)
P,Po,q
-P(t)(xif
x
-
XI
C[[O,Tl,R],
E
- q(t)(Y-?)
sz, y < y
and
q(t)
5 f(t,X,Y) t
E
i s nonincreasing i n y
f(t,x,y)
2
0
such t h a t
- f(t,%?)5 - P , ( t ) ( x - 3 ,
[O,Tl;
(3) t h e s o l u t i o n u ( t )
of t h e i n i t i a l value problem
(m) (5.3.3)
u"(t) + P(t)u(t)
(5.3.4)
u(t)
i s p o s i t i v e on
5
0,
-c
+ q(t)u(t- h(t))
5t5
(0,TI.
312
0,
= 0,
U'(O+) = 1,
5.3. SHOOTING METHOD
LEMMA 5.3.1. Under assumptions (1)- (3), the rvP (5.3.1) with the initial conditions x(t) = cp(t), t E [-c,O], x'(O+)=s has a unique solution. The conclusion of Lemma 5.3.1 is immediate because hypothesis (2) implies that f satisfies a uniform Lipschitz condition with respect to x,y, which in thrn yields the existence and uniqueness of solutions of IvP's.
LEMMA 5.3.2. Under assumptions (1)-(3), the BVP (5.3.1), (5.3.2) has at most one solution.
Proof:
Let x(t), y(t) be two different solutions of (5.3.1), (5.3.2) and set m(t) = x(t)-y(t). By Lemma 5.3.1, Without loss of generality, we may therefore x ' (O+) f y' (O+). suppose that there exists a tl,O < tl _< T such that m(t) > 0, 0 on [-c,O]. 0 5 t 5 tl and m(0) = m(t ) = 0 . Also m(t) 1 Because of (2), we then arrive at the differential inequality
In view of assumption (3), it is possible to choose an r > sufficiently large so that ru(t) > m(t), 0 < t ,< tl, and since (5.3.3) is linear and homogeneous, ru(t) is again a solution of (5.3.3). Consider now the BVP
(5.3-5)
u"(t)
(5.3-6)
u(t)
+ p(t)u(t) p
0
+ q(t)u(t
on [-c,Ol,
- h(t)) u(t,)
0
= 0,
= 0.
Clearly m(t) is a laver solution and ru(t) is an upper solution of (5.3.5), (5.3.6). Recalling the fact that q(t) 2 0 , we conclude, on the basis of Exercise 5.2.2, that there is a solution y(t) of the BVP (5.3.5), (5.3.6) such that 313
5 . EXTENSION TO FUNCTIONAL DIFFERENTIAL EQUATIONS
However, y(t) =
y(t)
k(t)
> 0.
u(t,)
i s a solution of (5.3.3) and consequently
r" < 0 .
f o r some
This contradicts t h e f a c t t h a t
Hence the proof i s complete.
LEMMA 5.3.3.
Let
u(t), x(t,s),
solutions of t h e IVP's (5.3.3), on
[-c,o], x ~ ( o + )= s;
vl(O+)
= 1,
and
respectively.
v"
and
(5.3.4),
+
v(t)
(5.3.1);
be t h e x ( t ) = cp(t)
Po(t)v = 0 , v ( 0 ) = 0 ,
Then for
s" _>
s,
we have
The proof of t h i s lemma i s similar t o t h e proof of Lemma and hence we leave it t o t h e reader.
5.3.2,
LEMMA 5.3.4.
Lemma 5.3.3. Then
g(s)
Let
u(t), x(t,s),
M[u(T)
Let
-k
v(T)] = 2
and
v(t)
be a s i n
and
g(s) = s-M[x(T,s)-A].
has a unique fixed point. Let
s" >
g(g)
- g(s)
Proof:
Using (5.3.7),
s.
Then . . u
= s
- s - M[x(T,g) - x(T,s)].
we then see t h a t lg(s)
- !&-)I
_<
YlS
-4
y = (v(T) -u(T))/(u(T) + v(T)). Since 0 5 y < 1, g i s a contraction mapping and therefore has a unique fixed point
where S*.
In view of t h e preceding lemmas, i f we note t h a t
x(T,s*) =A,
we have proved t h e following r e s u l t . THEOREM 5.3.1.
Then t h e BVP (5.3.1),
Suppose t h a t hypotheses (1)-(3) hold. (5.3.2) has a unique solution which may
314
5.4. NONHOMOGENEOUS LINEAR BOUNDARY CONDITIONS
be computed by the shooting method. Assumption (2) above, may be weakened. by the following:
THEOREM 5.3.2. of Theorem 5.3.1.
Let us replace it
Assumptions (l), (3) - (5) imply the conclusion
Proof: We observe that in proving Lemma 5.3.2 and the first half of inequality (5.3.7), assumption (4) rather than (2) was employed. Thus the BVF (5.3.1), (5.3.2) has at most one solution and for 0
g>
s,
< (g- s)u(t) 5 x(t,g)
- x(t,s),
0
< t 5 T,
holds. Let s be fixed and let g -+w. Then, since u(T) > 0 , we obtain x(T,Z) -+ m. Keeping s fixed and letting s + -m, N
we conclude similarly that x(T,s) +-w. Assumption (5) implies that x(T, s ) A is a continuous function of s, which must cover the whole real line by the above argument. Hence there
-
exists an s*
such that x(T,s*)
5.4 NONHOMOGENEOUS LINEAR
=
A and the proof is complete.
BOUNDARY CONDITIONS
In this section, we shall be concerned with the question of existence of solutions of a quasilinear f'unctional differential equation subjected to nonhomogeneous linear boundary conditions. The equations considered include both functional differential equations of retarded type and of advanced type. 315
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
h,k _> 0
Let
and l e t
> 0.
T
As before, l e t
C[[O,T],Rn]
denote the Banach space w i t h the norm
llxllo = supO < t < T I l X ( t > l l ’ We need the following function spaces simultaneously and consequently, we s h a l l adopt the notation given below f o r convenience.
I n each of the above cases the norm i s the sup norm. x
E
C4
and
t
E
[O,T],
we define the element
xt
E
the relationship -h
xt(8) = x ( t +8), Let
and l e t
f E C[ [ 0, T I
.
x C3,Rn]
C
3
by
k.
n x n matrix with domain
be a continuous
A(t)
,< 8 5
For any
[O,T]
We consider the functional
d i f f e r e n t i a l equation x ’ ( t ) = A(t)x(t) + f(t,xt),
(5.4.1) Let
O(t),$(t)
domains
be continuous
[-h,O],
[T,T+k]
0
5t5
T.
n x n matrices with respective
such that
Q ( 0 ) = I = $(T),
where
I
i s the identity matrix.
l i n e a r operator on
C
into
Let
L be a continuous
We a r e interested i n the
Rn.
existence of a t l e a s t one solution x ( t ) of (5.4.1) which, n satisfies the following additional f o r a given r E R
,
conditions (5.4.2)
k ( t ) = r,
(5.4.3)
x ( t ) = cp(t)x(O),
0
316
5t5 -h
T,
5t5
0,
5 A. NONHOMOGENEOUS LINEAR BOUNDARY CONDITIONS
(5.4.4)
T
x ( t ) = $(t)x(T),
If
5t5
T
is a continuous matrix on
B(t)
IIB(t>rll,
Rn> and
we denote by
l i n e a r operator
+ k.
[a,b],
we l e t
llBl10 = S‘PtE[a,b]
t h e usual norm f o r a
((-((
L.
Recall t h e fact t h a t t h e solution of
x’
(5.4.5)
for every b
(5.4.6)
+ b(t),
= A(t)x
Lx(t) = r,
r
E
Rn,
i s given by
E C
Lt
x ( t ) = U(t)[L%(t)l-’[r-
+
u(t)
t
L(U(t)
u-l( s ) b ( s )
U-l(s)b(s) as]
ds,
and t h a t BVP (5.4.5) has a unique solution for every and every f E C if and only i f t h e BW
= A(t)x,
X’
XI
R”
Here U(t) is the fundamental
= A(t)x
such t h a t
Let us define a mapping way.
E
Lx(t) = 0
has only the t r i v i a l solution. matrix solution of
r
S: C4 + C 4
U(0) = I.
in the following
let
For each y E C4,
where (i) for each
t
E
x ( t ) is t h e unique solution
[O,T],
of t h e d i f f e r e n t i a l equation X’
= A(t)x + f ( t , y t ) ,
0
5 t 5 T,
s a t i s f y i n g t h e boundary condition
t ( i i i ) for t (ii) f o r
E [-h,O],
Lx(t) = r; x ( t ) = Q(t)x(O);
E [T,T+kl,
x ( t ) = Jr(t)x(T).
317
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
Noticing t h a t f o r each y
E C4, f ( t , y t ) i s a continuous function t for t E [,,TI, it i s clear, from the f a c t mentioned above, t h a t the mapping S i s well defined. We s h a l l next show t h a t the mapping S i s continuous on C4. Let y,z E C4. Then
of
Also, from (5.4.6) we obtain
Since U(t)
i s a fundamental matrix solution and
L
is a
continuous l i n e a r operator, there exist positive constants cy,
p,y, 6 such t h a t
-1
IlLll 5 6 -
Moreover, we have, llSY
- SZIll
5
Ilmll,llsY(o)
-< IlmIllIIsY and
318
-
- sz(0)Il
SZ/IO’
5.4. NONHOMOGENEOUS LINEAR BOUNDARY CONDITIONS
The foregoing three inequalities, then yield IISY
- SZII 5 maX[llQII1,
IIJrll,,ll@BT(wj
+
l)llf(t,Yt)
- f(t,zt)llO,
which, in view of the assumed continuity of f on [O,T] X C 3 shows that S is a continuous operator on C4. We shall impose conditions on f to ensure that for some
>
5 Bp, where B = [Y E C,+: P then it follows from (5.4.6) that p
0 , S(Bp)
I/Y(/~
_< PI. Let
y E Bp;
These inequalities imply that
where llO1lo
v1, and
q2
l/$l l.
are constants depending on a,p,y,6,T, Thus if p is such that
.
then S(Bp) 5 B y1 particular, p may whenever y E B P’ P be chosen this way provided f satisfies the condition that for sufficiently large p
(5.4.8)
Ilf(t,u)ll
5
(P-
IIuI~~
111)/11*,
whenever 5 p. We next verify that S ( B ) is sequentially compact. P Indeed, since S(Bp) 5 Bp, S(B ) is uniformly bounded. FurtherP more, if y E B then for t E [O,T] P’
319
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
and hence t h e assumption (5.4.8) on equicontinuous on
imply that
f
{Sy]
is
Moreover, as
[ 0, T I .
S y ( t ) = @(t)Sy(O),
for
-h
5t5
0,
and
it i s evident that and
[T,T
+ k].
{Sy} i s also equicontinuous on
[-h,O]
The sequential compactness i s therefore a
consequence of Ascoli's theorem. We summarize the foregoing considerations i n t h e following existence theorem. THEOREM 5.4.1.
Let
and s a t i s f y (5.4.8). solution f o r every
BVP x '
be continuous on
[O,T] xC3
Assume t h a t t h e BVP (5.4.5) has a unique n r E R and every bc C if and only i f the
= A(t)x, & ( t ) = 0 has only the t r i v i a l s o l u t i o n .
t h e BVp (5.4.1)
5.5
f(t,u)
- (5.4.4)
Then
has a t l e a s t one solution.
LINEAR PROBLEMS
I n t h e following section we shall continue our study of boundary value problems f o r f'unctional d i f f e r e n t i a l equations. Some preliminary notation w i l l be needed.
Let
Ch
denote t h e Banach space of continuous functions from into
Let
Rn,
L(t,cp)
where f o r
and
[a,b] xCh + R n
cp E Ch
f(t,cp)
be continuous mappings from
and f o r each
t
E
bounded l i n e a r operator from Ch function f ( t )
[ a - h,a]
defined on
[a,b],
320
[a,b], into let
let Rn. ft
L(t,cp)
be a
For any continuous denote t h e element
5 5 . LINEAR PROBLEMS
of
f t ( 8 ) = f ( t + 8 ) , 8 E [ a - h , a ] , t E [a,b].
defined by
Ch
We w i l l consider t h e two point BVP (5-5.1)
where
t
Y ' ( t > = L(t,Yt) + f(t,Yt),
and N
M
E
[a,bI
a r e bounded l i n e a r operators on
We s h a l l assume:
(%)
There e x i s t s a bounded integrable function
such t h a t
IIL(t,(p)ll
(H2) f(t,cp)
5
J(t)Il(p11,
Rn
E
[a,b]
and
J(t)
(p E
Ch.
[a,b] xCh
and s a t i s f i e s
u n SUPIJ(plJO-)m llf~t,P~ll/ll~l10 = 0, t
Ya =
t
for
maps closed bounded subsets of
i n t o bounded s e t s i n (5-5.3)
'h'
E
uniformly f o r
[a,b].
(H3 ) Solutions of t h e i n i t i a l value problem (5.5.1) with ch
e x i s t and a r e unique.
We w i l l make use of t h e properties of t h e l i n e a r equations
x'(t>
(5.5.4)
g
E
C[[a,b],Rn].
= L(t,xt),
For any i n i t i a l
q E Ch,
we write
x(q,g)(t)
as the solution of (5.5.5) s a t i s f y i n g xa(q,g) = q. For each and q E Ch a solution of t h e i n i t i a l value g E C[[a,b],Rn] problem (5.5.5) exists and i s unique.
The solution can be
represented as (5.5.6)
x ( q , g ) ( t ) = x(q,O)(t) + x(O,g)(t),
t
2
a - h*
From Gronwall's inequality, it follows, using (5.5.5) and (I-$), that
321
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
The following elementary result f o r t h e l i n e a r equation (5.5.4) gives a necessary and s u f f i c i e n t condition f o r t h e (5.5.2) t o have a s o l u t i o n .
BVP (5.5.5), LEMMA
5.5.1.
The two p o i n t BVP (5.5.5),
s o l u t i o n if and only i f denotes t h e range and
which maps
q
E
Ch
N%(O,g) X
E
(5.5.2) has a
JI + R(M+NX),
i s an operator on
i n t o t h e segment a t
t h e i n i t i a l value problem (5.5.4) with
Ch
R
where
defined by
of t h e s o l u t i o n of
b
xa
= q.
JI + R(M+NX). To show t h e BVP (5.5.5), (5.5.2) has a s o l u t i o n , it suffices t o e s t a b l i s h t h e e x i s t e n c e of a s o l u t i o n of t h e f u n c t i o n a l equation Proof:
(5.5.9) Using (5.5.6),
Suppose
%(O,g)
E
Mq + N%(q,g) =
E
'$9
'h'
we can w r i t e (5.5.9) as
(5*5-10)
Mq
+ NXq + N%(O,g)
=
'$a
N%(O,g) E Jr + R(M+NX). Conversely, i f t h e boundary value problem (5.5.5) and (5.5.2) This has a s o l u t i o n s i n c e
a s o l u t i o n x ( t ) on [ a - h,b], t h e n xa = q Consequently, N%(O,g) (5.5.8) and (5.5.9). completing t h e proof.
satisfies E
JI + R(M+NX)
We a l s o need t h e following r e s u l t on t h e operator LEMMA 5.5.2.
l i n e a r operator on
The operator Ch.
322
X
has
X.
i s a completely continuous
5.5. LINEAR PROBLEMS
Proof: For q1,q2
E
Ch and scalars
cy
and 0,
define
Immediately, we see, due to the linearity of L(t,(P), that z(t) satisfies (5.5.4) with za = 0. By uniqueness z(t) = 0, proving X is linear. Moreover, X is continuous due to the fact that solutions depend continuously on initial conditions. It remains to show X is compact. Let {R} be a bounded sequence in ch> 1l%llo 5 M. From (5.5.7)
Hence EX%]
is uniformly bounded.
Moreover
are equicontinuous and an application of the Hence EX%] Ascoli's theorem proves that X is completely continuous. Before stating our main results we need two lemma's which provide conditions on an operator so that the range of the operator is the whole space. We omit the proofs. LEMMA 5.5.3.
Let Y be a completely continuous mapping of a Banach space B into itself. If
(5*5*u)
ljJn SUP
llwll/lld < 1,
Il(Pll'm
then R(1- Y )
=
LEMMA 5.5.4.
B. Recall R(1-
Y)
means the range of I- I.
Let To be a contraction operator of a 323
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
Banach space
Let
into itself.
B
be a completely con-
T1
tinuous operator of a Banach space i n t o i t s e l f such t h a t
-
( 5 5 12)
~ ~ T l ( P ~ ~ / / k=P /0/.
Lim
l cp Il+
Then R(I
+
+ T1)
To
LEMMA 5.5.5.
= B.
Let
from a Banach space
B
T be a completely continuous operator into
Assume t h a t t h e only s o l u t i o n
B.
of t h e equation
(I + T)x = is x
z
E
Then f o r each
0.
y
E
t h e r e exists a unique
B,
such t h a t
B
(I + T)z Lemma 5.5.5
5.6
0
=
i s o f t e n r e f e r r e d t o as t h e F r e d h o h a l t e r n a t i v e .
NONLINEAR PROBLEMS We now consider a r e s u l t f o r t h e BVP (5.5.1),
THEOREM 5.6.1. Eq.
(5.5.1).
Assume hypotheses (H1)- ( H ) hold f o r
Let t h e operator
a r e given i n (5.5.2) and inverse.
(5.5.2).
(M
X i n (5.5.8),
Then t h e BVP (5.5.1),
3
+ NX),
where
M
and
N
have a continuous
(5.5.2) has a t l e a s t one
solution. Proof:
For each
q E Ch,
denote by
of t h e i n i t i a l value problem (5.5.1) with g(q)(t) = f(t,yt(q)).
Then y ( t , q )
y(t,q) y
a = q. Define i s a s o l u t i o n of t h e
nonhomogeneous l i n e a r equation (5.6.1)
x ' ( t > = L(t,xt) + g ( q ) ( t ) *
Thus 324
the solution
5.6. NONLINEAR PROBLEMS
A solution of the BVP i s determined by an i n i t i a l condition which is a solution of the functional equation
(506.3)
(M
+ NT)q
This may be rewritten as ( M
= JI,
JI
E Ch.
+ NX + N(T-
X ) ) q = Jr.
I? = (I4 + NX)'l which exists by hypothesis. can be rewritten as
Let
(5-6.4)
( I + l"(T-X))q = I'$,
Then (5.6.3)
$ E Ch.
We w i l l use Lemma 5.5.3 t o show the existence of solutions by
letting
Y = m(T- X)
and
B = C[O,h].
Since I T i s con-
tinuous, it i s sufficient t o show that T - X i s completely continuous i n order f o r Y t o be completely continuous. We now show T - X i s completely continuous. Let q E Ch and consider the solution y(t,q) of (5.5.1) w i t h ya = q. Then, by (5.5.3), (5-5.71, we have
where L = exp(/: R(s) as) and Mo is any constant such t h a t Ilf(t,cP)II 5 II9II0 + Mo f o r a l l t E [a,b]. An application of Gronwall's inequality then leads t o
Let
be
that from (5.5.7),
any bounded sequence i n Ch. Ubserve (5.6.2), and (5.6.5), we obtain
325
5 . EXTENSIONS TO FUNCTlONAL DIFFERENTIAL EQUATlONS
-
which shows
i s uniformly bounded.
{ (T X)R}
I n addition,
by (5.5.3)
Furthermore, f o r
t
E
[a,b],
we derive from (5.5.6),
(5.5.7)J and (5.6.5)
From t h i s estimate, (H1),
1%
( 0 J g (%)
and (5.6.5), we see, using (5.6.6),
) (lo
i s uniformly bounded. ~n a p p l i c a t i o n of A s c o l i ' s theorem y i e l d s the complete continuity of T - X . I n order t o apply Lemma 5.5.3, it i s s u f f i c i e n t t o show (5.5.11) holds. Suppose t h e r e e x i s t s a sequence of functions
that
s
E
Ch,
Ibt(g)II
l l ~ l +l
--1m
as
t h e r e e x i s t s an
~llcpll~for IIys
as n
n + m such t h a t
r >o
or
E
such t h a t i f
a l l t E [a,b].
(s) lo >r
o <
Let
+m.
<
pn
sup, < < b
1 / ~ ~y ~ .(7.5.3)J
IIqII, > F J
llf(tJv)II
Since f o r each s E [ a , b l , 1l0 5 r J we a r r i v e a t
l/y, (s)
326
5
5.6. NONLINEAR PROBLEMS
Since E is arbitrary, (5.5.11) holds w i t h Y = T - X f o r any sequence cq, such t h a t the corresponding sequence B n as n + m . However, i f {@,I are bounded, then (5.6.7)
+m
implies
11%
lim
(O,@;(Qn)
= 0,
11% (lo
ll¶JO-)m
so again (5.5.U) holds.
)lo
This completes the proof of the
theorem.
5.6.1.
Assume that the two point BVP (5.5.4), (5.5.2) has only the t r i v i a l solution f o r Jr 2 0. If M has COROLLARY
a closed inverse, then the BVP (5.5.1),
Proof: -
(5.5.2) has a solution.
By t h e closed graph theorem, The relation (5.5.2) may be rewritten as
M-l
i s continuous.
Hence it is s u f f i c i e n t t o prove (I + M-hX)-’ e x i s t s i n order t o use meorem 5.6.1. To do t h i s we w i l l invoke k m a 5.5.5. Since X i s completely continuous, so i s M - h . Hence by hy-pothesis the only solution of ( I + M-lNX)ya = 0 i s ya s 0. follows.
Thus
(I + M - h )
321
has an inverse and the result
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
COROLIARY 5.6.2.
Suppose t h a t t h e mappings
- a;
that is
f ( t + ~ , c p ) = f(t,cp)
for a l l
(5.5.1) are p e r i o d i c with period L ( t +P,cp) = L(t,cp)
and a l l cp
and
L and f
P = b
in
t 2 a
If t h e only P-periodic s o l u t i o n of (5.5.4)
E Ch.
i s t h e i d e n t i c a l l y zero s o l u t i o n , then Eq. (5.5.1) has a P[a,m).
p e r i o d i c s o l u t i o n on Proof:
Let
M= apply Corollary 5.6.1.
I, N = -1,
Jr
and
=0
i n (5.5.2) and
The following e x e r c i s e provides t h e uniqueness o f s o l u t i o n s of t h e BVP by assuming a Lipschitz condition on
f(t,cp)
and
u t i l i z i n g t h e contraction mapping theorem. EXERCISE 5.6.1.
Ch.
E
f i n e d i n (5.5.8)
(5.5.2)
and
kt
assume (€$) holds.
f o r a l l cp
Consider t h e BVP (5.5.1),
If t h e operator
, has
M
-t
NX,
where
a bounded inverse and i f
s u f f i c i e n t l y small, t h e n the BVP (5.5.1),
(b
X
- a)
i s de-
is
(5.5.2) has a unique
solution. Hint: -
Consider t h e operator
Fq = W - r N ( T - X ) q j
r
where
(M+NX)-'
and
defines a contraction on condition on
f
defined by @ E
ch,
i s defined by (5.6.2). Show F by u t i l i z i n g t h e Lipschitz
T
5
and choosing
show a f i x e d p o i n t of
F
b
-a
s u f f i c i e n t l y small.
Then
F y i e l d s a s o l u t i o n t o t h e BVP (5.5.1),
(5.5.2). EXAMPLE 5.6.1.
We now e x h i b i t an example which i l l u s t r a t e s
328
5.6. NONLINEAR PROBLEMS
Theorem 5.6.1. (506.8)
Consider the functional d i f f e r e n t i a l equation
- 1 ) + f(t,y,),
y'(t) = Y ( t
t
[0,2]
E
subject t o the boundary conditions (5.6.9)
Yo =
1
ii Ye,
Y0'Y2
E cr-1,01.
Here L(t,yt) = y ( t - 1 ) , M = I , N = - I, a = 0, b = 2, h = 1, satisfying (H1) and JI = 0, and f E C[[O,2] xC[-l,O],Rn] (€$). For example, l e t f(t,cp) = A(t)kpl/i, 0 < < 1, Observe t h a t the i n i t i a l value problem for the A E C[O,21. homogeneous li ne a r equation X ' (t ) = x ( t
( 5.6.10)
- 1)
can be solved by the method of steps; that is, f o r any i n i t i a l function q E C[-1,0], we have (5.6.U)
x ( t ) = q(O) +
Jt
0
5t
- 1) as
du,
q(s -1) as,
Lt L ~ -- ~
q(s
+
1
1,< t
,< 2.
Thus Xq(@) is given by
xq(e) = L
~ + ~
and we h n ed i at e l y see t h a t
-
(I $X)
q(s
1)
s'plIqll
as au,
e
E [-1,01
IbqII < 4. Hence
-1 has a continuous inverse !&~d an application of
Theorem 5.6.1 yields the existence of a solution of the BVP (5.6.8), (5.6.9). EXERCISE 5.6.2.
Prove the existence of a periodic solution
of 329
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
where
0
<
(r
< 1.
Hint:
Apply Corollary 5.6.2 t o show t h e existence of a s o l u t i o n of period 2 ~ .
5.7
DEGENERATE CASES
I n t h i s s e c t i o n we consider (5.5.1) when t h e l i n e a r p a r t i s not a f u n c t i o n a l on
Ivbre s p e c i f i c a l l y , we consider
Ch.
t h e f u n c t i o n a l d i f f e r e n t i a l equations of t h e form (5 07.1) where
Y ' ( t > = A ( t ) Y ( t ) + f(tJYt)Y f
and A ( t )
i s a continuous mapping from is a n x n
[a,b] xCh i n t o Rn matrix function continuous i n t . We
s h a l l assume t h a t (H2) and
( 5 )hold.
We f i r s t consider t h e case when A ( t ) t h e operator
X
= 0.
I n t h i s case
reduces t o
(5.7.2)
xq = :(a),
i s the function i n
where
:(a)
q(a).
with t h e constant value
The following equivalent norm on q E Chy define
Ch
w i l l be u s e f u l .
For each (5.7.3)
IlqII, = Ilq(a)II + 11qll0.
For a l i n e a r operator
THEOREM 5.7.1.
T
If
on
r0
Ch
define
= (M+N)-'
IIPoNlla < 1, then t h e BVP (5.7.1), has a s o l u t i o n . and
330
e x i s t s , i s continuous, (5.5.2) with
A(t)
=0
5 .I. DEGENERATE CASES
Proof:
I n view of Theorem 5.6.1,
it i s enough t o show e x i s t s and is continuous where X i s given
(M+NX)’l
that
by (5.7.2).
Consider the m c t i o n a l equation
(5.7.4)
(M+W)q = CP, CP E Ch,
which may be rewritten a s
+
(M
N
+ N(X - 1))s = 9,
cp E Ch,
w h i c h is equivalent t o
(5.7.5)
I
+
rON(X-I) q =
r’p. 0
-
Hence, by Lemma 5.5.4, it suffices t o show t h a t roN(X I ) is a contraction, f o r then, the inverse of M + NX would e x i s t ,
For any
919%
Il(X
E
- I)ql-
ch (X
- I)Q211a =
-
-c
Ihl(a)
= Ils,(a)
lql
=
Since on
Ch.
~ ~ I ’ o N<~1 ~,a the operator Hence (5.7.5)
This implies
- I)q21/ - c12(a) II + Ils, - q21Io - q2 (a) I1 + llql - q2 1l0
11(X I)s,-
(X
- %JIa*
-
roN(X I) is a contraction
has a unique solution f o r every rp E Ch.
( I + roN(@- I))-1
exists.
The continuity
follows and thus (M+IlX)-l
is continuous. proof.
= (I
+
- I))-‘r0
TON(X
An application of Theorem 5.6.1 concludes the
EXAMPLE 5.7.1.
We show the existence of a solution of
the BVP
331
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
ma
y ' ( t ) = f(t,Yt), where
-
Mq(0) = q(0)
0 E [a-h,a]
:/
<(a), Nq(0) =
< b - a. We see
and h
+
+
M
NYb = O,
<(a) +
+
t
Jea
q(z) d'r,
+ *A, > 1=
N = I
-
where
Let us assume t h a t b a h. Then killa < 1. Thus (M + N ) - l e x i s t s and s a t i s f i e s /1(M+N)-llla5 74 . k r e o v e r , llNlla < 4. 3 Hence II(M+N)-hlla _< II(M+N)-lllalIN/la < 1
Aq(8) =
q ( z ) dz.
and we m a y apply Theorem 5 . 7 . 1 t o conclude t h e existence of a solution of t h e BVP f o r any
(3).
s a t i s f y i n g (H2) and
f(t,yt)
We now consider (4.7.1) when A ( t ) # 0. which A ( t ) = 0, t h e assumption on ro r u l e s out t h e p o s s i b i l i t y For t h e case i n
This i s reasonable since the
of having periodic solutions.
equation
x'
0
has any constant as a solution with periodic Now we w i l l be i n t e r e s t e d i n establishing
boundary conditions.
Since we a r e now
t h e existence r e s u l t s of periodic solutions. looking a t t h e reduced equation
(5.7.6) t h e mapping X functions
t
x ' ( t ) = A(t)x(t), ql,%
[a,bl,
E
w i l l assign t h e same value t o t h e d i f f e r e n t E
as long as
Ch
Hence it i s
q,(a) = q2(a).
unreasonable t o expect t h e operator
M + NX t o be i n v e r t i b l e .
I n our previous r e s u l t we imposed t h e condition order t o insure the i n v e r t i b i l i t y of
M
+
Ilr0NI1
< 1 in
Here we present
NX.
a r e s u l t which w i l l allow f o r periodic boundary conditions. We now assume t h a t U(t)
and N
M
are
nxn
matrices and l e t
be t h e fundamental matrix of (5.7.6) with
i d e n t i t y matrix.
Define t h e operator
Xuq(0) = U ( b - a
THEOREM 5.7.2. Suppose t h a t f o r a l l
Let
+
0)q(e),
M
and N
0 E [a
i s nonsingular and t h a t
- h,a]
r(0)
I
332
5:Ch
U(a) = I,
+Ch
the
by
8 E [a-h,a].
be
nxn
t h e matrix
(M+NU(b - a
matrices.
( 'M +
+ 0))-'
NU(b
- a + 0))-'
satisfies
5 .I. DEGENERATE CASES
llrmuIlo =
(5.7.7)
Then the BVP (5.7.1)J
sup
a-hs91a
b(e)NU(b-a+9)11 < 1.
(5.5.2) has a t l e a s t one solution.
The s o l u t i o n y t ( s )
Proof:
of (5.7.1) can be represented
as
for
9 E
(5.7.9)
[a-hJa].
Let
To
TOq(@)= s ( a ) +
be a
mapping defined on Ch
rb-a+e
u-l(s)f
Ja
(s ,ys
by
(9)) as.
From (5.7.8),
(5.7.9), we have yb(q) 'XuT0q. Thus a solution of the BVP (5.7.1)J (5.5.2) can be found by solving the functiona l equation (5.7.10 ) Let
(M + JWuTo)q = JIJ
JI
E
C*
F be an operator defined by
(m)(') ClearlyJ
=
r(e)q(e)J
F i s invertible.
[a-hJal.
Therefore (5.7.10) i s equivalent
to
(5.7.11) Let
TO-IGT
(I + 1
rmu(To- 1 ) ) s
+T2
defined by
333
=
WJ
JI
E
Ch-
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
we w i l l use Lemma 5.5.4 i s a contraction and I'NX T u 2 is completely continuous and s a t i s f i e s (5.5.12). We again work
To o b t a i n a s o l u t i o n of (5.7.11), and show t h a t
FNXuTl
with t h e norm
ll*lla
introduced i n (5.7.3).
Then from (5.7.12), Il(T1q1
- TI921
one obtains, f o r any
(8)
II 5 -< =
Ilql(a) IlsJa)
- q2WII + - q2(a>I/ +
Let
q1,q2
E
Ch.
8 E [a-h,al
Ilsp) lPl
-
II
- q21Io
Ils,- q211a,
and thus it follows t h a t
IIT1ql
- T1% IIa 5 Ihl - q2 IIa-
This together with (5.7.7) implies Observe, from (5.7.13)
i s completely continuous.
I'NXUTl
and (H2),
Since
immediately have t h a t r%T2
i s a contraction.
t h a t t h e operator
%
i s continuous, we
T2
i s completely continuous.
From (5.7.9), we obtain
Using (5.5.4) and t h e Gronwall a - h s t s b I/U(t)II. i n e q u a l i t y we deduce t h e existence of p o s i t i v e constants
where and
K = sup
%
such t h a t
//yt(q)llo 5 Klllq/lo
3.
K2
f o r all t
It then follows t h a t
and hence with (5.7.7), we conclude t h a t
An a p p l i c a t i o n of Lemma 5.5.5 completes t h e proof.
334
K1
E
[a,b].
5 B. NOTES AND COMMENTS
EXERCISE 5.7.1. M
+ NU(b
- a+0)
Show t h a t t h e i n v e r t i b i l i t y of the matrix
f o r each
0 E [a
t h e following requirement: condition MX(a) each
z
+ NX(2)
( 5 -7.15) (H2),
can be accomplished by
Eq. (5.7.6)
= 0
subject t o t h e boundary
has only t h e t r i v i a l solution f o r
E [b-h,bl.
EXAMPLE 5.7.2.
where
- h,a]
Consider t h e one-dimens ional equation
Y’(t) = -Y@)
f ( t +.rr,yt) = f ( t , y t )
(?),
t
+ f(t,Yt), for a l l t
2
0
-’0,
and satisfies
together with t h e periodic boundary conditions Yo = Y$
(5.7.16)
Yo’Y,
Here M = 1, N = -1, U(t) = e (1-e -(n+e))-l
=
r(e>.
-t
E
c [-LO].
and thus
(M
+ NU(b - a+€)))-’
mreover,
Hence (5.7.7) holds and an inmediate application o f Theorem 5.7.2 y i e l d s the existence of a solution of the BVP (5.7.15))
(5.7 ~ 6 ) .
5.8
NOTES AND COIMEXCS
The material contained i n Sections 5.1 and 5.2 i s taken
from G r h and Schmitt [ l ] , while the work of Section 5.3 i s due t o De Nevers and Schmitt [l]. Section 5.4 consists o f t h e r e s u l t s of Schmitt [g].
The contents of Sections 5.5
are based on t h e work of Waltman and Wong [4].
- 5.7
For the tech-
niques of operator theory employed i n these sections, see Granas [l]. For r e l a t e d r e s u l t s concerning f’unctional d i f f e r e n t i a l equations, r e f e r t o Gustafson and Schmitt [ l ] , Fennel [2],
335
=
5 . EXTENSIONS TO FUNCTIONAL DIFFERENTIAL EQUATIONS
Fennel and W a l t m a n [ l ] ,Schmitt [ 4 ] , Norkin [ l ] J Mawhin [31J and H a l e [l].
336
Chapter 6 SELECTED TOPICS
6.0
INTRODUCTION
This chapter i s concerned with some s e l e c t e d t o p i c s of current i n t e r e s t .
F i r s t of a l l , we present i n a u n i f i e d
s e t t i n g Newton's method which i s of p a r t i c u l a r value i n applications.
We discuss as i l l u s t r a t i o n s two numerical techniques
of solving boundary value problems.
These a r e t h e Goodman-
Lance method and t h e method of q u a s i l i n e a r i z a t i o n , which have a t t r a c t e d considerable a t t e n t i o n i n recent years.
We then
consider nonlinear eigenvalue problems as an a p p l i c a t i o n of t h e angular function technique.
The n-point boundary value
problem i s investigated i n d e t a i l by studying n-parameter f a m i l i e s of solutions.
Under t h e assumption of uniqueness,
some r e s u l t s on existence of s o l u t i o n s a r e derived.
6.1 "TON'S METHOD Here we wish t o present an a b s t r a c t formulation of Newton's method in a u n i f i e d s e t t i n g and then i n subsequent sections, deduce, from t h e g e n e r a l r e s u l t s f o r Newton's method, as i l l u s t r a t i o n s , two numerical techniques of solving boundary value problems.
These a r e t h e Goodman-Lance method and t h e
method of q u a s i l i n e a r i z a t i o n , which have a t t r a c t e d considerable a t t e n t i o n i n recent years. Let
X
and Y
denote r e a l Banach spaces and suppose
t h a t t h e b a s i c equation t o be solved,
(6.1.1)
f ( x ) = 0,
i s given by a mapping of an open subset which i s continuously d i f f e r e n t i a b l e . 337
U
of
X
i n t o Y,
This means t h a t
f
has
6 . SELECTED TOPICS
a derivative
f'(x)
f o r every x E U
continuous mapping of
into
X
i s defined as t h e unique element i n ( l / h l l ) Ilf (x + h )
lim
L(X,Y)
- f (x) - f ' (x)h 11 =
(x)h I/: //h11
of f'(x)
f o r which
so t h a t , i n p a r t i c u l a r , Ilf'(x) I1 = sup ((If
L(X,Y)
A s usual,
Y.
is a
f'(.)
i n t o t h e Banach space
U
continuous l i n e a r mappings of
llhII-tO
such t h a t
5
11
0
.
It follows then from the mean value theorem t h a t t h e r e e x i s t s , f o r every
xo
with center
x
(If
(6.1.2)
E
u
and every
and radius
0
(x2) - f(xl)
E
>
r
0,
an open b a l l
B(xoJr) C U
such t h a t
- f ' (xo)(x2 - xl) 11 5
Elk2
- xlll
f o r any two points f
If
f"(x)
xlJx2 E B(xoJr). i s twice d i f f e r e n t i a b l e i n U,
of
f
a t any
U may be defined i n a n a t u r a l way with a continuous b i l i n e a r mapping of X x X i n t o Y, and consequently
IIf"
(X)
II =
SUP
[(If"
x
t h e second derivative
E
(X) (hlJh2)
II: I$,I
Furthermore, i f i n a d d i t i o n . llfl' (XI
5
(1 5 k,
1, IIh2 II
5
x
we deduce, as
E
U,
13
a consequence of t h e mean value theorem, t h a t
IIf'
(6.1.3)
f o r every open b a l l
(x2)
- f ' (x,) II 5 kIIx2 - xlII
B(xo,r) c U
and
XlJX2
E
B(X0").
Also,
as a consequence of Taylor's theorem, t h e r e r e s u l t s t h e inequality
(6.1.4) When
l/f(x2)-f(xl)-f'(x1)(x2-x1)II
5 3 kllx2-x111 2.
n m X = R , Y = R , our assumption implies that, each
p a r t i a l derivative continuous i n
U,
1s
Djfi, 1_< i 5 m, j5 n and f l ( x ) a t x = (x1,x 2 338
e x i s t s and i s
,...,xn )
is the
6.1. NEWTON'S METHOD
n
l i n e a r mapping of
R
J(x1,x2,
into R"
...,xn ) =
given by the Jacobian matrix D f (X j i 1 '
...,xn ).
m I n particular, when X = Y = R observe t h a t f ' ( x ) i s a l i n e a r homeomorphism of F? onto i t s e l f i f and only i f the Jacobian, det J(x1,x2,. .,x n ) i s different from zero. Let us now state a r e s u l t concerning the modified Newton's method.
.
THEOREM 6.1.1. Suppose t h a t f i s continuously d i f f e r entiable i n U and t h a t there is an xo E U f o r which f l ( x o ) i s a l i n e a r homeomorphism of X onto Y. men, f o r any a E (O,l), there i s an open b a l l B(xo,r) C U such that, i f
II 5 r ( l - a > ,
IIfl-l(xo)f(xo)
(6.1.5)
w .
there e x i s t s a unique x E B(xo,r) f o r which f ( 2 ) = 0. Moreover, f o r any sequence {Tn] of l i n e a r homeomorphisms of X onto Y satisfying
Ilf'
(6.1.6) f o r every n
(6.1.7)
,> 0,
-1 (x,)
f
' (xo) II 5 71
.. Tn-I (xn>J
n =
O j l j Z j a . . ,
{xn] of points i n B(xo,r) ll~-xn+lll ,< ( & / ( 3 - a ) ) III-xnll
(6.1.8)
f o r every n
-
t h e successive i t e r a t i o n s
xn+l = xn
define a sequence such t h a t to
1I IlT,
2 0. 339
which converges
6 . SELECTED TOPICS
Since f i s continuously differentiable i n U, there i s an open b a l l B(xo,r) C U f o r which x E B(xo,r) Proof:
implies
(6.1.10) We prove by induction that the i t e r a t i o n s (6.1.7) generate a sequence Ex,} i n B(xoJr). Indeed, from (6.1.6) we deduce that
(6.1.11) f o r every with
n > 0.
n = 0,
(6.1.12)
5 (3/(3 - Q')) Ilf'-l(x0) 11
(ITilll
Hence, i f
then
x 1 i s determined from (6.1.7)
Ilxl-xoll _< 111- Til(To - f f ( x o ) ) l l ~k'-l(xo)f(xo)ll
< 3 r ( l - a ) / ( 3- 0 ) by (6.1.5)~
(6.1.6) and (6.1.11), s o t h a t x1 E B(xo,r). Thus, suppose xlJ...,x are points i n B(xo,r) satisfying P Then (6.1.2) and (6.1.6) show ,p-1. (6.1.7) f o r n = 0,l
,...
that
(6.1.13)
IIf(xn+l)
II =
IIf(xn+l)
- f(xn) - Tn(~n+l- xn) II
-< ( 2 q 3 Ilf ' -l(Xo 1I1) holds f o r
llxn+l
- Xn I1
n = O,l,...,p-1.
Therefore, if x n=p,
i s determined from (6.1.7) w i t h P+l then (6.1.11) and (6.1.13) im-ply t h a t
(6.L14) for
llxn+2-xn+lll _< ( 2 4 3 - a ) ) l$+l-xnll
n = O,l,...,p-l.
Hence, i n particular,
340
6.1. NEWTON'S METHOD
and so, by (6.1.12),
xp+l
E B(xo,r).
This proves our assertion,
It follows t h a t the i n e q u a l i t i e s ( 6 . ~ 1 3 )(~6.1.14) hold f o r every
t o a point
and therefore
5
(6*1*16) f o r all n
2 0,
n
I I X ~ ~ - X ~ I (I( 3
-
-> 0
and
p
- ~ ' ) / 3 ( 1 - ~ ' ) ) ( & / ( -3a ) ) "
-> 1.
This implies t h a t
Ik1-x0II
{x }
converges n as a consequence
x E B(xo,r) f o r which f ( 2 ) = 0, of (6.1.13) and t h e continuity of f . If there were another
point
;i E B(xo,r)
f o r which
f(T) = 0,
we could deduce from
(6.1.2) and (6.1.10) t h a t
which i s absurd unless
x = x . Clearly, ( 6 . 1 . ~ ) and (6.1.16) N
-
imply t h a t (6.1.9) i s s a t i s f i e d f o r every
n
,> 0.
Since, by
construction,
( 6 . ~ 2 ) (6.1.6), ~ every
n
,> 0.
REMARK
and (6.1.n) show t h a t (6.1.8) holds f o r
The proof i s complete.
6.1.1.
If t h e open b a l l B(xo,r) C U
i s chosen as
i n t h e proof of Theorem 6.1.1, then (6.1.10) implies t h a t f ' ( x ) i s , f o r every x E B(xo,r), a l i n e a r homeomorphism of X onto Y. Thus, we rnw s e l e c t i n Theorem 6.1.1 t h e sequence {Tn] of l i n e a r homeomorphisms of
-> 0, Tn
X
and
Y
such t h a t , f o r every
Since (6.1.6) i s n then automatically s a t i s f i e d , the assertions of Theorem 6.1.1
n
= fl(z )
f o r some
remain v a l i d without change.
zn E B(xO,r).
I n p a r t i c u l a r , t h e proof of
Theorem 6.1.1 shows t h a t we m q always take every
n
0,
zn
=
i n which case the i t e r a t i o n s (6.1.7)
form
341
for assume t h e
6. SELECTED TOPICS
xn+l -- xn
(6.1.19)
-f
-1(xn)f(xn),
n = 0,1,.
.. .
These a r e t h e i t e r a t i o n s of Newton's method. I n Theorem 6.1.1,
REMARK 6.1.2.
choice f o r t h e sequence and
Y is t o let
the condition
of l i n e a r homeomorphisms of
{Tn]
Tn = To
a p a r t i c u l a r l y simple n 2 0.
f o r every
X
I n t h a t case
(6.1.6), which implies ~ / T ~ l * f l ( x o )5-uI /~( ~3 - u ) <$,
may be replaced by a weaker requirement t h a t homeomorphism of
onto
X
Y
-1
ITo
be a l i n e a r
To
f o r which
-1II < 1,
f'(xo)
and t h e conclusions of Theorem 6.1.1 may be strengthened as -1 follows: f o r any CY satisfying fl(xo) < c0 < 1, 0
there i s an open b a l l
/IT,
B (x , r ) 0
0
C
U
111
such t h a t , i f
lb0-1f(xo)lI < r ( l - a o ) , there e x i s t s a unique point and t h e i t e r a t i o n s
in
(6.1.7)
Bo(xo,r) f o r which generate a sequence Exn] E
N
-
f o r every
n
2
0.
of points
x such t h a t N
BO(xO,r) which converge t o
Ilx xn+lll
f ( g ) = 0,
N
CYo IIX
- xnll,
Observe t h a t , i n p a r t i c u l a r , we may take
= f ' ( x ) i n which case these assertions remain valid f o r 0 any CY E ( 0 , l ) . This i s t h e so-called modified Newton's 0
T
0
method.
342
6.1. NEWTON'S METHOD
COROLLARY 6.1.1. U
If
f
i s continuously differentiable i n
and, i n addition, there i s a constant
> 0 satisfying
k
( 6 . ~ 3 )then ~ the assertions of Theorem 6.1.1 hold r e l a t i v e t o
any open b a l l B(xOJr) contained i n U
f o r which
Mareover, under t h i s additional assumption, t h e convergence estimates ( 6 . ~ 8 )(6.1.9) ~ can be considerably improved f o r the i t e r a t i o n s (6.1.19) of Newton s method. EXERCISE 6.1.1.
in U
Suppose t h a t
and t h a t there i s a point
i s a linear homeomorphism of CY E
(o,+]
f o r every one point
X
f
x
0
i s twice differentiable
onto
E
I f there i s an
Y.
and a closed b a l l s ( x o J r ) c
x
f o r which f ' ( x o )
E U
u
such t h a t
E ( x O J r ) , then show t h a t there e x i s t s a t l e a s t
;; E E(xoJr)
f o r which
f(2) = 0.
Also show t h a t
the i t e r a t i o n s (6.1.19) are defined f o r every generate a sequence verges t o
x
Exn]
of points i n
such that, f o r every
n _> 0 and B(X J r ) which con-
-
n _> 0,
0
and
where the sequences
{an}, {rn }
343
are obtained by s e t t i n g
6 . SELECTED TOPICS
a, ro = r and for every n 2 0.
a. =
Hint: -
2 2 S ~ / ( ~ - ~ C Y ~ + ~rC U , =) ,a r n+l n n’
F i r s t show that i f the p i n t
x P’
f o r some p
2 0,
i s such t h a t the assertions a(xn,rn) C U, f (x,) is a l i n e a r homeomorphism of X onto Y, \If ‘-l(xn)f (x,) 11 5 r n ( l -an), (2/rn) an for every x E B(xn,rn) are IIf1-’(xn)II IP(xn)II true with n = p , then they remain t r u e with n = p + l f o r t h e point x determined from (6.1.19) with n = p . Then, since P+1 these assertions are t r u e f o r the point xo, use the induction argument t o complete the proof. 6.2
THE GOODM-LANCE METHOD
Newton’s method provides a convenient framework f o r deriving convergence c r i t e r i a f o r a variety of techniques f o r the numerical solution of two point boundary value problems of ordinary d i f f e r e n t i a l equations. As i l l u s t r a t i o n , we discuss briefly, i n t h i s section, the Goodman-Lance method and i n the next section, the method of quasilinearization. These two methods are t y p i c a l examples f o r t h e two groups into which a l l such numerical techniques w be divided. Though they are basically i t e z + i v e in the sense t h a t the solutions of the given problem appears as the limit of a sequence of solutions of auxiliary problems, they d i f f e r i n the way these auxiliary problems are chosen.
I n t h e Goodman-
Lance method, these latter problems are i t e r a t i v e l y generated i n i t i a l value problems f o r t h e same given d i f f e r e n t i a l equation, whereas in the method of quasilinearization, they are boundary value problems involving t h e same boundary conditions, f o r iteratively generated l i n e a r d i f f e r e n t i a l equations. I n order t o avoid umjmportant d e t a i l s , l e t us r e s t r i c t ourselves t o the problem of determining, i n a given compact 344
6.2. THE GOODMAN-LANCE METHOD
i n t e r v a l J = [O,T],
a solution
(6.2.1)
G
of t h e d i f f e r e n t i a l equation
f(t,x)
XI1 =
which s a t i s f i e s t h e given boundary conditions N
(6.2.2)
u ( 0 ) = a,
G(T) = b.
m m
We w i l l assume throughout t h a t and i s continuous on (6.2.3)
and f o r
JX?
(tJx,)J
1,
fx(t,x)
(tJx,)
E
exists
JXR~,
- J ( t , x 2 ) I/ 5 y b 1 - x211,
IIJ(t,xl)
where t h e Jacobian matrix a t
i s i d e n t i f i e d with
f E C[JxR ,R
(t,x)
J(t,x).
of
with respect t o
f
The norm
IIJ(t,x)II
t h e matrix norm induced by t h e given norm i n
x
is, as usual,
Rf".
The Goodman-Lance method i s based on t h e following construction.
Suppose t h a t
s o l u t i o n of (6.2.1) i n and
u,(T)
value
#
b.
unJ
f o r some i n t e g e r
> 0,
is a
f o r which
u ( 0 ) = a, uA(0) = xn n Then f i n d , f o r every i n t e g e r i E [l,m], t h e J
of t h e s o l u t i o n wi
wi(0)
n
in
J
of t h e a d j o i n t v a r i -
a t i o n a l equation (6.2.4) f o r which
= J*(tJun(t))x
XI'
and form t h e matrix W(un ) m i s an orthogonal basis of R If
w.(T) = 0, wj(T) = ei,
(wi(0)*ej),
1
where
ei
there i s a point
xn+l
(6.2.5)
w(un>(xn+l
such t h a t t h e s o l u t i o n ~'(0= ) xn+l
E
=
satisfying
R"
u
.
- xn> = un(T) - b
of (6.2.1) with
i s defined i n
J,
u ( 0 ) = a,
l e t t h a t s o l u t i o n be
u ~ + ~ .
Obviously, our aim i s t o generate i n t h i s way, from a given s o l u t i o n u 0 of (6.2.1) i n J with u 0 (0) = a , u0l ( 0 ) = "0, sequence {un} of s o l u t i o n s un o f (6.2.1) i n J with
345
a
6 . SELECTED TOPICS
u (0) = a, uA(0)
= x such that {un] converges uniformly in n n' J to a solution u" of (6.2.1) for which (6.2.2) is satisfied. We will show that this is indeed possible, under suitable assumptions. Let us first observe that, if (6.2.1) is a linear differential equation, say
(6.2.6)
X" =
A(t)x,
then any solution v of (6.2.6) in J integer i
E
[l,m],
to the solution w
equation
(6.2.7)
X" =
for which wi(T)
(6.2.8)
is related, for every
= 0,
wj(T)
wi(0)'v'(O)
=
i
of the adjoint linear
A*(t) x
=
ei by the equation
- ei-v(T),
wj(O).v(O)
-
as a consequence of the Green's formula. Hence, if (6.2.6)
has a solution u" in J such that u(0) = a, u'(0) = x" and ;(T) = b, and if u is any other solution of (6.2.6) for which u(0) = a, u'(0) = x, then in particular N
(6.2.9)
w. 1(O).(G-
for every integer i
[l,m];
E
x)
=
ei-(u(T)
- b) N
that is, x - x satisfies the
equation (6.2.10)
where Wo
W ( g - x ) = u(T)- b, 0
is the matrix (wi(0)*ej).
Thus, in this case,
the Goodman-Lance method does yield, in one step, the missing initial value x" = c ' ( 0 ) for the solution u" of (6.2.6) that satisfies the boundary conditions (6.2.2). In the general case, our assumptions imply, among others, the following facts. If (6.2.1) admits a solution uo with u0 (0) = a, u;)(O) = xo which is defined in J, then there 346
6.2. THE GOODMAN-LANCE METHOD
e x i s t s an open neighborhood
U
x E U,
u of (6.2.1) with
t h e unique s o l u t i o n
u'(0) = x
C
Rm
i s a l s o defined i n J.
xo such t h a t f o r every
of
Moreover, t h e r e l a t i o n which
a s s o c i a t e s with every
x
of (6.2.1) s a t i s f y i n g
u(0) = a, u ' ( 0 ) = x
d i f f e r e n t i a b l e mapping
E U
h
u(T)
t h e value
of
U
u ( 0 ) = a,
into
of t h e s o l u t i o n
i s a continuously
Rm.
We assert t h a t t h e Goodman-Lance i t e r a t i o n i s p r e c i s e l y t h e i t e r a t i o n of Newton's method f o r determining a point
x"
E
U
f o r which
(6.2.11)
h(x")-b = 0 .
Clearly, any such p o i n t
x
gives rise t o a s o l u t i o n
u ( 0 ) = a, c ' ( 0 ) = N
(6.2.1) with satisfies
N
x"
N
u
which i s defined i n
of J
and
Z ( T ) = b.
n 2 0 and i f un i s t h e corresponding s o l u t i o n of (6.2.1) i n J with u ( 0 ) = a, n u'(0) = x then t h e p a r t i a l d e r i v a t i v e D.h(xn) of h a t n n' J x f o r each j E [l,m], i s given by n' Indeed, i f
xn
E
_.
U
f o r some i n t e g e r
D.h(xn) = v.(T) J J
(6.2.12)
i s the solution i n J
x"
(6.2.13) f o r which each
= J(t,un(t))x
v,(O) = 0 , v l ( 0 ) = e,.
v.(T) J solution w
J
i
of t h e v a r i a t i o n a l equation
J
J
Since by t h e Green's formula,
i s r e l a t e d , f o r every i n t e g e r
i E [l,m],
t o the
of (6.2.4) by t h e equation
( 6.2.14)
e * v . ( T ) = -wi(0).e i
J
it follows t h a t t h e d e r i v a t i v e h ' ( x n )
j' of
h
a t xn
is
given by
( 6.2.15) where, as before,
h ' ( x n ) = -W(un) W(un)
i s t h e matrix (wi(0).e.). J
347
Thus,
6 . SELECTED TOPICS
h ' ( x ) i s nonsingular, the i t e r a t i o n of Newton's method n (6.1.19) i s
if
and t h i s i s equivalent t o t h e i t e r a t i o n (6.2.5) because h(xn) = un(T),
by definition.
Therefore, any of the r e s u l t s f o r Newton's method, such as Corollary 6.1.1 or Ekercise 6.1.1 w i l l yield automatically sufficient conditions f o r the convergence of the i t e r a t i o n s of the Goodman-Lance method.
We s h a l l formulate below only
a direction consequence of Corollary 6.1.1. THEOREM 6.2.1.
Suppose t h a t (6.2.1) has a solution uo
with uo(0) = a, u;)(O) = xo which i s defined i n J, U
C
x
Rm be an open neighborhood of
E U
the unique solution u
~ ' ( 0 =) x
of
U
e x i s t s i n J.
into
Rm
and l e t
holds f o r any x1,x2
E U.
0
h
-1
as the mapping x +u(T)
be any constant f o r which
If t h e Jacobian matrix
nonsingular and there a r e constants such t h a t
and l e t
such t h a t f o r every
of (6.2.1) with u ( 0 ) = a,
Define
B>
xo
CY
E
(0,l)
h'(xo)
and
is
r> 0
B(xo,r) c U, ~ ~ h ' - l ( x o ) h ( x o<) ~r(1~ CY), and
@I(h' (xo)((5 u/r, then there e x i s t s a unique point x" E B(xo,r) f o r which the solution u" of (6.2.1) i n J with u"(C) = a, G'(0) =
x"
s a t i s f i e s (6.2.2).
Moreover, the i t e r a t i o n s of
Goodman-Lance method a r e defined for every a sequence
{xn} of points i n
B(xo,r)
n 2 0 and generate which converges t o
x such t h a t t h e corresponding sequence {un 1 of solutions u of (6.2.1) i n J w i t h u ( 0 ) = a, uA(0) = x n n n converge t o w
u"
uniformly i n J,
and that
348
6.3. THE METHOD OF QUASILINEARIZATION
and N
Ilx- Xnll
_<
;
2n
1-CY
2"
for every n 2 0 .
Ilhl-'(xo)h(x0)ll
6.3 THE METHOD OF QUASILINEARIZATION Let us now discuss the method of quasilinearization as it applies to the problem of constructing a solution u" of (6.2.1) which is defined in J = [O,T] and satisfies (6.2.2). As before, we shall assume that f E C[JxRm,F?], fx(t,x) exists and is continuous on J xRm and (6.2.3) holds. Our aim, again, is to generate, from a given continuous mapping uo of J into R ~ ,a sequence {un] of continuous mappings of J into R" such that {u ] converges uniformly n in J to a mapping u" which is a solution of (6.2.1) in J satisfying (6.2.2). However, in contrast to the Goodmanfor every n 2 0, is not Lance method, the mapping u n+l' chosen as a solution in J of the nonlinear equation (6.2.1) but, instead, is to be a solution in J of the linear equation
(6.3.1)
X" =
J(t,u,(t))x
+ f(ttun(t))
- J(t,un(t))un(t)
for which
(6.3.2)
= a,
un+l(T)
=
b.
This requires, of course, that a continuous mapping uo of J into R" can be found such that not only the equation (6.3.1) with n = 0 but, moreover, each iteratively generated equation (6.3.1) with n 1. 1 admits a solution un+l which satisfies the boundary conditions (6.3.2). We will now show that this demand can indeed be met, under appropriate assumptions. We note first that a continuous mapping u" of J into F? is a solution of (6.2.1), (6.2.2) if and only if
349
6. SELECTED TOPICS
where G
i s the Green's function i n J X J
such that
(l/T)(T- t ) s ,
0
_< s _< t 5 T,
(l/T) t ( T - s ) ,
0
5t5s5
G(t,s) =
This may be forxmilated i n the following manner.
T.
Consider the
Banach space C = C[J,Rm] with the usual norm llull = suptd IIu(t)ll. Define cp as the mapping of C into it,self such that
(6.3.4)
cp(u): t + a
f o r every u
E
C,
+ -tT
(b-a)
-k
T
G(t,s)f(s,u(s)) ds
and s e t
o(u)
(6.3.5)
=
u - cp(u).
then any point u" E C i s a solution of (6.2.1) which s a t i s f i e s (6.2.2) i f and only i f
o(i-i)
(6.3.6) Our assumptions on
= 0.
imply that the mapping cp is continuously differentiable i n C. Indeed, from (6.1.2) we infer inrmediately that the derivative cp'(u) of cp a t u E C is the continuous linear mapping of C into i t s e l f such that, f o r every v E C,
t
+
-
f
LT
G(t,s)J(s,u(s))v(s) ds.
Hence the mapping 0 of C into i t s e l f , as defined by (6.3.5), is also continuously differentiable i n C. In fact, since evidently
350
6.3. THE METHOD OF QUASILINEARIZATION
for every u E C, where e is the identity mapping in C, we deduce f r m (6.2.3) and (6.3.7) that
(6.3.9) for any ul,u2 E C. Observe that, as a consequence of (6.3.7) and (6.3.8), @'(u) is, for some u E C, a linear homeomorphism of C onto itself if and only if @'(u)v = 0 implies v = 0 or, equivalently, if and only if the relation ( 6.3.10)
v(t)
T =-
G(t,s)J(s,u(s))v(s)
ds
for every t E J implies v(t) = 0 in J. Thus, Q'(u) is a linear homeomorphism of C onto itself precisely for those u E C for which the homogeneous linear differential equation
(6-3-u)
X" =
J(t,u(t))x
has no nontrivial solution v in J such that v(0) = 0 , v(T) = 0 or equivalently, for which the nonhomogeneous linear differential equation ( 6.3.12)
x"
=
J(t,u(t))x
+ w(t)
has, for every w E C, a unique solution v such that v(0) = a, v(T) = b. In particular, O'(u) is a linear homeomorphism of C onto itself for any point u E C for which IIcp'(u)ll < 1, and in that case IIO ' - l ( u )
II 5 ( 1 - (IT' (u>II I-?
We claim that, if the iterations of Newton's method for determining a point u" E C for which (6.3.6) holds, namely the iterations
(6.3013)
Un+l
6 . SELECTED TOPICS
are defined for every n > _0, then they are exactly the iterations of the method of quasilinearization. More precisely, the point u n+l E C obtained from (6.3.13) is then, for every n > 0, the unique continuous mapping of J into R" which is a solution of (6.3.1) satisfying (6-3*2)Clearly, if the iterations (6.3.13) are defined for every n l 0, then (0' -1(u,) exists for every n 2 0. Hence (6.3.13) implies by (6.3.5) that
(6.3.14) which, in turn, implies by (6.3.4) and (6.3.7) that
(6.3.15) un+l(t>
=
a
+
(t/T)(b
- a)
for every t E J. This shows that un+l is a solution of the linear differential equation (6.3.1) for which (6.3.2) holds. In fact, un+l is the only such solution, because the existence of (O'-l(un) assures, by the preceding remarks, that the homogeneous linear differential equation (6.3.11) corresponding to (6.3.1) has no nontrivial solution v in J such that v(0) = 0, v(T) = 0 . This proves our claim. Thus, sufficient conditions for the convergence of the iterations of the method of quasilinearization can be deduced directly from any of the general results for Newton's method, such as Corollary 6.1.1 or EXercise 6.1.1, by simply applying the latter to the mapping (0 as defined by (6.3.5). We state here the following result which is a direct consequence of Corollary 6.1.1. THEOREM
6.3.1. Let uo be the mapping of J into 352
F?
6.4. NONLINEAR EIGENVALUE PROBLEMS
for which u o ( t ) = a + (t/T)(b- a )
t
for every
E
J,
let
lk(t,uo(t))ll
be positive constants such t h a t
a,B
5
l l J ( t , u o ( t ) ) / / 5 B,
a,
t
E
J,
2 and suppose t h a t ( 1 / 8 ) ~ < ~ 1. If there exist positive constants
where
a
0
y> 0
<1
and
r
such t h a t
i s a constant for which (6.2.3) holds, then there
e x i s t s a unique continuous mapping
u"
of J
into
Rf"
with
Ilu"-uoll < r which i s a solution of (6.2.1) and (6.2.2) i n J. Moreover, t h e i t e r a t i o n s of t h e method of quasilinearization generate an i n f i n i t e sequence J
into
R"
{un]
which converges t o
u"
of continuous mappings of uniformly i n J
and Ilu- unll N
for every
6.4
a2n 0
1 5 aO
1-a:
such t h a t
8 aT2
1 - g1B T 2
n > 0.
N0NLINEA.R EIGENVALUE PROBLEMS
mploying t h e angular function technique, discussed i n Chapter 2, we s h a l l consider t h e boundary value problem PA
353
6. SELECTED TOPICS
3
2
2
where f,g E C[J XR ,R], J = [a,bl, A1 + A2 > 0 , and 2 2 B1 + B2 > 0 . We seek values of the parameter h for which PA possesses a nontrivial solution. Let us list the following assumptions. (H1) f,g E C[JxR 3,R], the solutions of (6.4.1),
(6.4.2) can be continued over J, and x(t) 0, y(t) the only solution of (6.4.1), (6.4.2) with x(to) = 0 ,
0
y(t 0 )
is
= 0 for any to E J. (H2) There exists a continuous f'unction H(t,u,v,h) 2 2 defined on JxDxR, where D = [(u,v): u + v = 11, such that
3 2 on J x R , where r
=
2
x
.
+ y2
We shall first prove an elementary result. !I'HEOm
6.4.1. Let (H1) and ($) hold. Suppose that l i m inf
(6.4.6)
A+
+m
Lb
G(t,h) dt
=
-m,
where G(t,h)
=
[SUP H(t,u,v,h):
Then there exists a sequence such that
Am <
{\I
<
(u,v)
DI.
of eigenvalues of PA
with l h k+m
354
f
\
=+O0,
6.4. NONLINEAR EIGENVALUE PROBLEMS
is nonnegative integer. If x(t,\), y(t,\) is an eigenflrnction pair f o r \, k 2 m, then x ( t , \ ) has a t least k zeros, while y ( t , \ ) has a t least k - 1 zeros on J. where m
Proof:
( x ( t ) , y ( t ) ) be a solution of (6.4.1) - (6.4.3). We set x = r cos 8, y = r s i n 8, w i t h 8 normalized so t h a t it s a t i s f i e s - ~ / 2< 8(a,h) 5 ~ / 2 . A simple calculation shows, i n view of (H2) and the definition of G(t,h), that Let
e’(t,h)
5
cos
H(t,
8,
s i n e,h) 5 G(t,h),
which, when integrated, yields
Ja
the condition
e(a,h) = arc tan(-A1/A2), (6.4.6) gives lim inf e(b,h) = -00.
Recalling t h a t
A+m
For each k = 0,1,2
4, =
[A>
,...,
define
0: e(a,h) = arc t a n
(:)--,
8(b,h) = a r c t a n
where B(t,h) is arc t a n y ( t ) / x ( t ) f o r the corresponding solution of (6.4.1)- (6.4.3). Since e@,h) is continuous i n h and limb, 0(b,h) = -m, t h e range o f 8(b,A) contains the interval
( -m,8(bto)).
Let m z
such t h a t Am i s nonempty.
The sets defining 8(b,\
\,
k
o
integer we may define
be the s e e s t
Then f o r k
2
m,
> m, are also nonempty, since
-1) > arc tan(-Bl/B2) - kT
h with 1 i m infh+m O(b,h)
=-m.
355
and 8(b,h) is continuous i n Finally, notice that e ( t , \ )
6 . SELECTED TOPICS
crosses each of the l i n e s a t l e a s t once t o give
0 = -(2j
x(t,\)
+ 1) ~ / 2 ,j
a t least
0(t,\)
crosses each of t h e l i n e s
so t h a t
y(t,A,)
has a t l e a s t
k
0 =
-1
k
- jT,
zeros.
= 0,1,.
zeros.
..,k-1,
Also,
j = 1,2
,...,k - 1 ,
The proof i s
therefore complete. EXERCISE 6.4.1.
Prove other p o s s i b i l i t i e s of Theorem
6.4.1, namely ( i ) replace (6.4.6) by lim infh-m =
Sab G(t,A)dt
( i i ) reverse t h e inequality i n (H2) and assume t h a t b G(t, A) d t = + m. lim SUP&+ -m,
I,
A drawback of Theorem 6.4.1 l i e s i n t h e function
For very simple systems,
G(t,A). f o r large
G(t,A)
may become constant
and consequently t h e condition (6.4.6) cannot
A
-
For example i n t h e case x ' = y, y ' = ( A + l ) x , 2 H(t,x,y,h) = - ( A + l ) x - y 2 so t h a t G ( t , A ) = - 1 f o r
be s a t i s f i e d . we have
large positive
A.
hood of
from t h e consideration t o get b e t t e r r e s u l t s .
x = 0
Clearly one needs t o eliminate a neighbor-
This i s exactly t h e point of t h e exceptional s e t i n the follow-
ing hypotheses. On t h e u n i t c i r c l e
D,
f i n i t e s e t of points, where angle
-T
< CY 5
For each
7T.
3
that
(i)
D
6
P u (aii= 1
E6 =
(H )
let
E = [a1, ...,a ] denote a P i s parametrized by t h e c e n t r a l
> 0,
6,Ui + 6).
There e x i s t s a f i n i t e s e t there i s a
K
t
E J,
(ii)
h if
2 0,
CY
E
E
E
of p i n t s on D
such
> 0 f o r which
H(t, cos a, s i n a , h ) for
let
6'
< -K
for a l l s u f f i c i e n t l y small 6,> 0,
G (A) = sup[H(t, cos a, s i n C Y , ~ )t: E J, a E D - E ~ ] , 6
356
6.4. NONLINEAR EIGENVALUE PROBLEMS
then
lim inf
h+m
G (A) = 6
f o r each s u f f i c i e n t l y small
-m,
6>0.
i s s a t i s f i e d , i f we take 5 )and K = 1. [T/2, -T/2], 6 <4 If (H1) - (H ) hold, then the THEOFSM 6.4.2. 3 In the example, (
E =
assertions
of Theorem 6.4.1 remain valid.
l i m infbm
We need only t o show t h a t
Proof:
B(b, h ) =
-00,
since the remainder of the proof of Theorem 6.4.1 applies. M, 8(b,A) > -2M, f o r be the exceptional s e t and define
Suppose the contrary, t h a t i s , f o r some h> 0.
E = [a1,.
Let
F = [ql
,...,cpP 3 =
..,aP ]
1< i
[ai-2rj:
< p,
j = 0,1,..., M I .
< K(b - a)/kp(M+ 1 ) . For each h 2
l e t ti, i = 1 p, denote the unique time such t h a t B(t*i' h ) = cp.1 6. Notice t h a t ti,tr depend on h and are well defined because
Choose
6
,...,
8'
< -K when -
8 = 'pi 2
B(t,h)
-
In f a c t ,
6.
el(t,h) < -K,
so t h a t
0,
t
E
[ti,t21,
t
on
1. - K ( t y -
ti)
i s s t r i c t l y decreasing i n
[ti,"].
We have also
-
-26 = B(t?c,h) 1 B(ti,h) and, as a r e s u l t , we conclude t h a t (b
- a)/2(M+ 1)p.
i n t e r v a l s i n J,
i
Since there are a t most
5
26/K <
p(M+ 1) such
the measure of t h e s e t
T (h) = [t: t 1
satisfies
t*- ti
E
J,B(t,h)
m(Tl(h)) < ( b - a ) / 2 ,
E6]
so the measure of
T2(A) = [ t : t E J, B(t,h) 351
E
Esl
6 . SELECTED TOPICS
- a)/2.
i s g r e a t e r than
(b
so t h a t by ($),
it follows t h a t
5
e(bJh)
Since m(T2(h))
G&h)
=
- mJ
However,
- m ( T l (+h Gg(h)m(T2(h))n ))
>
(b-a)/2
f o r every
h and lim infh+,
h > 0 f o r which 8(b,h) < -2MT.
there e x i s t s a
This contradiction proves the theorem.
6.5
n-PARAMETER FAMILIES AND INTERPOLATION PROBLEM3 In Section 2.1, it was shown f o r second-order s c a l a r
equations t h a t the uniqueness of t h e two-point BVP implies i t s
An analogous theorem e x i s t s f o r the third-order
existence.
equation; however, the question of uniqueness implying existence n
remains open f o r the n-point BVP,
2 4.
I n t h i s section, we
prove under t h e additional assumption of " l o c a l s o l v a b i l i t y , t h a t the uniqueness does i n f a c t imply t h e existence f o r the n - p i n t BVP.
Our main technique i s the theory of a n-parameter
f a m i l y of functions.
We s t a t e our r e s u l t f o r t h e f i r s t order n-dimensional system; a s p e c i a l case of t h i s , of course, i s t h e nth order s c a l a r equation.
THEOREM 6.5.1. (6.5.1)
x' = f(t,x), x (t.) = c 3' O J
(6.5.2)
t 1 < t2 < (A)
Consider the boundary value problem
-.-< tnJ where f(t,x)
E
.
j = 1,. . J n J
x = (xo,xl,...,x
n n C[(a,b)xR J R 1;
358
n-1
).
Assume
6.5. n-PARAMETER FAMILIES AND INTERPOLATION PROBLEMS
a l l s o l u t i o n s of (6.5.1) e x i s t on
(B)
(a,b);
t h e r e e x i s t s a t most one s o l u t i o n of (6.5.1) and
(C) (6.5.2) f o r a l l
< tn;
c
E
3
and t . J
R
t h e BW (6.5.1),
(D)
every point
(6.5.2)
to E (a,b);
(a,b)
E
a r e l o c a l l y solvable a t
t h i s i s , f o r every
e x i s t s an open i n t e r v a l
tl < t2 <
where
to E (a,b)
I ( t O ) , t O E I ( t O ) E (a,b)
there
such t h a t
(6.5.1) and (6.5.2) has a s o l u t i o n f o r a l l d i s t i n c t and a l l
(6.5.2) has a unique solution.
Then every BVP (6.5.1),
We s h a l l need some d e f i n i t i o n s and lemmas f i r s t . DEFTNITION 6.5.1.
A set
F
of functions
f E C[(a,b),R]
i s s a i d t o be an n-parameter family on (a,b) i f f o r every s e t of n d i s t i n c t points tl < t2 < * . * < tn of (a,b) and every s e t of element
n
fo E F
numbers
cl,.
satisfying
.., cn
f ( t ) = c
(6.5.3)
0
DEFINITION 6.5.2.
j = l,...,n.
3’
3
t h e r e i s one and only one
A family
F of functions
f E C[(a,b),R]
i s s a i d t o be a l o c a l n-parameter f a m i l y i f f o r every
to E (a,b)
t h e r e i s an open i n t e r v a l ,
such t h a t
t h e s e t of r e s t r i c t i o n s
f E F
an n-parameter f a m i l y on
I ( t O ) , t O E I ( t O ) C (a,b) f l I ( t o ) of t h e elements of
is
I(tO).
Observe t h a t t h e conditions s o l u t i o n s of t h e BVP (6.5.1),
(B) and (D) imply t h a t t h e
(6.5.2) form a l o c a l n-parameter
I n order t o obtain t h e r e s u l t of Theorem 6.5.1 it i s s u f f i c i e n t t o show t h a t F i s indeed an n-parameter f a m i l y
family on
F.
(a,b).
Our next r e s u l t shows t h i s i s indeed so.
Thus
Theorem 6.5.1 i s incorporated i n t h e following more general setting.
359
6 . SELECTED TOPICS
THEOREM 6.5.2.
functions on
(a,b)
F = { f } be a f a m i l y of continuous
satisfying
i s a l o c a l n - p a r a m e t e r f a m i l y on
(i)
F
(ii)
if
has a t most Then
Let
f,g
a r e d i s t i n c t elements o f
c - 1 zeros on
and
F, then f - g
(a,b).
i s an n-parameter f a m i l y on
F
(a,b)
(a,b).
To prove Theorem 6.5.2 we s h a l l need some lemmas. LEMMA 6.5.1. f -g
(i)
If
has
n-1
F be an n-parameter family on
Let
f,g
are d i s t i n c t elements of
zeros on
(a,b),
each o f i t s zeros. (ii)
fo(t) = fo(t,tl
if
element of
(Cl,
then
2 n + 1 variables f o r n Cn) f R
.
...,
t
such t h a t
changes signs at
f -g
,...,t n ,cl ,...,cn )
determined by (6.5.3),
F
function of i t s
< tn < b,
then
F
fo
i s t h e unique i s a continuous
(a,b), a
E
(a,b).
< tl <
9 . 9
We s h a l l p r o v i d e p a r t o f t h e proof i n t h e following exercise. EXERCISE 6.5.1. Hints:
Prove Lemma 6.5.1.
For p a r t ( i ) assume
f
-g
does not change s i g n
a t some x 1' L e t ( a ' , b t ) be an i n t e r v a l having x1 i n i t s i n t e r i o r and containing none o f t h e abcissas of t h e o t h e r n-2 f(xt)
p o i n t s of i n t e r s e c t i o n .
#
g(xf).
Let
restricted t o n
-2
Show t h a t i f
f
the other
Ft
( a t , b t ) of t h e members of
(at,bt)
such t h a t
F
passing through
p o i n t s o f i n t e r s e c t i o n and through
(xt,g(xf)).
i n t e r s e c t s any element
(at,b')
e x a c t l y one time, then
f-g x2,x3
Then choose
f 2 E F'
and
g E Ft
changes sign.
by t a k i n g two p o i n t s fl
9
Choose x t
be t h e one parameter f a m i l y o f functions
such t h a t such t h a t
360
a'
in
This can be done
< x2 < x1 < x < b t fl(x2) = g ( x , )
3
and
.
6.5. n-PARAMETER FAMILIES AND INTERPOLATION PROBLEMS
-g
Show t h a t i f f f (x ) = g(x3). 2 3 then f l = f 2 at some point on
does not change signs, (%,?). But t h i s i s impossible
since f l and f2 belong t o F’. For ( i i ) show that f o r any sequence
) converging t o
“lk’ ‘ ’s9 ) (t’T4tJ* * J z nk’ slk’’ - ’snk
,...,
{T%,T~
,...,Tn ,
,...J ~ n )thenk converges t o f(t,zl, ...,zn’
( T ~
T~~
k
s1
sn) uniformly f o r t E (a,b)}. This can be shown by using t h e r e s u l t s of the first p a r t of t h e 1-a. S1>*..Y
TXMMA 6.5.2.
Aasume the conditions of Theorem 6.5.2 and
let
Then
Sl
is an open subset of R2n ,
-.-
Proof: Let toE (a,b) and sl < s2 < < sn be points of the open i n t e r v a l I ( t O ) . Recall f / I ( t O ) forms an nparameter family and l e t 7
f(t) = f(t,
be t h e unique element of For fixed to and sl, defined by
S1’
6
,...>C
n)
F satisfying
...,sn
We f i r s t show t h a t
..., n , c 1
rp
f ( s ) = cj, j = l,...,n, d consider the maming rp: A x R n + a
i s a continuous fbnction.
...
..,
sufficient to show t h a t f (t, sl, ,sn, cl,. continuous function of ( t , cl,. ,c ). kt J n i n t e r v a l contained i n (aJb) such that ti is
..
361
It i s
cn ) i s a be any closed contained in
6 . SELECTED TOPICS
the i n t e r i o r of
and to E J.
J
an open i n t e r v a l I ( x ) an n-parameter f a m i l y . ~
Ui=,
such t h a t
,...,k
E
restricted t o
F
f(t, s
I(xi) U I ( t O ) . Observe t h a t
...,
i s a continuous function of
J,
define
I(x)
form
some k.
On
rl,
E
I(%)
I(tO)n
,...,xn , c 1,...,"n)
on I ( t O )XR" (t, cl, cn I ( t O ) intersects I(%) f o r apply @ m a 6.5.1 by considering any points I(%) having the values that i s ,
because of Lemma 6.5.1.
...,rn
x
There e x i s t s a f i n i t e number of x2, I k such t h a t Ui=, I(xi) covers J. Let S =
i = 1
k
For each point
Now
3' ... ,sn, c1 ,...,cn), j 1,...,n. A p p l y now Lemma J 6.5.1 t o f ( t , r1 ,...,rn, al ,...,an) f ( t , s1 ,...,sn, c 1,...,cn ) on I(%). Hence f ( t , s1 ,...,sn, c1 ,...,cn) i s continuous f o r ( t , cl, ...,cn) on I ( t O ) U I(%). We may continue t h i s process a.
= f ( rj,
sl,
=
=
a f i n i t e number of times and obtain the continuity of
,...,
f ( t , s1 sn, cl,..",cn) on S x R n . Hence we see t h a t cp i s continuous on A X R ~ . We immediately have t h a t cp i s one-to-one on AxR" because of condition ( i i ) i n Theorem 6.5.2. Since A x R n i s open i n R2n then cp(A xRn) = i s open i n R2n by the Brouwer invariance of domain theorem. We now generalize 6.5.1 as follows. LEMMA
6.5.3.
Let
F be a family of continuous functions
on an open i n t e r v a l
f(t)
(i) (ii)
the s e t
has a t most
n
such t h a t
i s open and
Cl C R2n
f,g
if
(a,b)
are d i s t i n c t elements of
-1
zeros on
F,
then
f -g
(a,b).
%en
(a) If f , g (a,b),
then
f
(b) If
element of
F
-g
E
F
and. f - g
has exactly n - 1
zeros on
changes signs at each of i t s zeros.
f ( t ) = f ( t , tl satisfying
,...,tn, c1 ,...,cn)
f ( t i ) = ci, 362
then
f
i s the unique i s a continuous
6.5. n-PARAMETER FAMILIES AND INTERPOLATION PROBLEMS
2 n + l variables for t
function of i t s
(tl,
f
-g
...
..
,tn, C1'.
Proof: -
'Cn)
Let
vanishing at
there e x i s t s
neighborhood about o r contained i n of
51 we
an h
E
rnw
(a,b)
and
52.
E
f,g
E
F be d i s t i n c t elements of
t
=
tl,
...,tn-l
> 0 such t h a t
k
E
tk. Choose any s
(a,tk)
pick an
E
i+l. Suppose
i n some deleted (tk-l,tk)
if
k
>1
k = 1. Because of t h e openness
if 6
ti c t
where
-g >0
f
F with
> 0 so
s m a l l such t h a t there exists
F having t h e property t h a t
for
h ( t j ) = f ( t j )= g ( t j ) h(s) = f ( s )
h(t
and
-
-
k
+&)
j =
#
k
g(tk+E).
Observe that f h and g h each vanish a t n - 1 points. However, t h e continuity of f,g, and h imply t h a t either
o r g - h vanishes on (s, tk + & ) since f - g > 0 i n some deleted neighborhood of tk (which we may assume contains mis contradicts ( i i ) tk+ E ) The proof of the second part i s the same as i n Exercise f -h
.
.
6.5.1. U M M A 6.5.4.
Let
F be a s e t of continuous f'unctions
Then F is an n-parameter f ( t ) on an open i n t e r v a l (a,b). family on (a,b) i f it has properties ( i ) and ( i i ) of Lemma 6.5.3, t h e property (iii)
(6.5.4)
...
i s any sequence of
fi(t)
5 fi+l(t)
for i = 1,2,...
fi(t)
2 fi+l(t)
for
if
on a compact s e t
fl,f2,
[Q',p] c (a,b),
363
i = 1,2,...,
then e i t h e r
F satisfying
or
6 . SELECTED TOPICS
exists on
f ( t ) = lim f i ( t )
(6.5.5)
(a,b)
and
f
or
lim I f i ( t ) l =
(6.5.6)
on a dense set of
m
i-tm
(a,b)
and the property
to E (a,b) i s not bounded above o r below. (iv) for a l l
Proof:
To show
F
f i c i e n t t o show t h a t
Q .
..,t n )
the s e t
S ( t O ) = { f ( t o ) : f E F}
i s an n-parameter f a m i l y it i s sufn = A XR Let k, where 15 k _< n,
.
..,
..,
(cl,. c ~ - ~ c ~, + ~ , .cn ) be fixed and l e t S = ( Ck: (tl,. .,tn, cl,. .,c n ) E Q ) . We m e d i a t e l y have t h a t S i s open from (i)of Lemma 6 5 - 3 *
(tl,.
E
and
A,
.
S
i s a l s o closed.
{c, }
satisfying
We now show t h a t consider a sequence
c
k
E
j
{c
sequence and without loss of generality
ck
3
k
j -tm.
BY ~enrma6.5.3,
j.
m
ck
as
j
If
We may assume
and
4c
.
#
k, f j ( t k ) = c k
if 9
f
E
j
F
k j
S for j
5
= 1,2,.
..
i s a monotone
}
for a l l
c
kj+l and s a t i s f i e s f ( t ) = cm for j
j
then
m
j
r=O,
where
i s not empty
S
...,k - 2,
a = to and b = tn+l. Thus by condition ( i i i ) e i t h e r
(6.5.5) holds, and ck E S o r (6.5.6) holds. Assume (6.5.6) holds. By ( i v ) we can f i n d some f satisfying
f (t,)
>
ck
>
.
f (t,)
J
3 64
for a l l j
.
E
F
For s u f f i c i e n t l y
6 5 . n-PARAMETER FAMILIES AND INTERPOLATION PROBLEMS
hrge
we have i n view of (6.5.6) and (6.5.7)
j,
that
f-f
3
vanishes on either s i d e of tk a r b i t r a r i l y near tk and also arbitrarily near tm f o r rn f k. Thus, f o r large j, f - f j has n zeros on (a,b), a contradiction t o ( i i ) of Lemma 6.5.3. Thus S i s closed. Hence S = (-m,-) inplying n(a,b) = A(a,b) xRn. The proof of Theorem 6.5.2 thus follows from &mmas 6.5.1- 6.5.4. For our further discussion we shall consider the Bvp
x(n) = (6.509)
...
JX(
f(t,X,X',
x ( t i ) = ci,
The results of Theorem 6.5.1,
d ) ,
,...,n.
i = 1
applied t o the BVP (6.5.8) and
(6.5.9), remain true without the local solvability condition ( i i i ) f o r n = 3 (as w e l l as n = 2). Thus, we have the following theorem.
THEOREM 6.5.3.
Consider the BVP
Assume t h a t ( i ) f(t,x1,x2,x3)
E
C[(a,b) x R 3. , R l
( i i ) solutions of i n i t i a l values of xm = f(t,x,x',x") extend on (a,b) (iii) there exists a t most one solution of the BVP (6.5.10) f o r each ti' i =1 J 2 J 3 J where tl < t2 < t 3 and
each
c
i
E
R.
Then there exists exactly one solution of t h e BVP (6.5.10).
365
6 . SELECTED TOPICS
As we have pointed out, we have from Theorem 6.5.1 that (A)- (D) imply the existence of solutions of BVP (6.5.8) and (6.5.9). Under assumptions (A)- (C) we have seen that the following condition is equivalent to (D): is a sequence of solutions of (6.5.8) (D1) If {x,(t)}L=l which is uniformly bounded and montone on a compact interval [c,d] C (a,b), then limit x (t) = x(t) is a solution of k (6.5.8) on [c,d]. Another condition under assumptions (A) - (C) to (D) and (D1) is
equivalent
If {%(t)};=, is a sequence of solutions of (6.5.9) which is uniformly bounded on a compact interval [c,d] C (sib), (i1(t)} then there is a subsequence {xk (t)} such that {x, (D2)
j
converges uniformly for each 0 _< i 5 n-1. For
j
it can be proved that if the BVP (6.5.8), (6.5.9) satisfies (A)- (C), then it also satisfies (D2) (from which the existence of solutions follows). For completeness of discussion we now state a result for the k-point BVP, (6.5.8) and
(6.5.ll)
n
= 2,3
i x (t.) J
=
-1, l < j < k ,
cij, k
6.5.4. If solutions of initial value problems for (6.5.8) are unique and if the n-point BVP (6.5.8), (6.5.9) THEOREM
have unique solutions which extend throughout (a,b), then the k-point BVP (6.5.8), (6.5.11) have unique solutions. Thus in view of our previous results, conditions (A)- (C), uniqueness of initial value problems f o r (6.5.9) and either 366
6.6. NOTES AND COMMENTS
(D), (D,), or (D,) imply the existence and uniqueness of npoint BVP's and k-point BVP's.
6.6
NOTES AND COMMENTS
The contents of Sections 6.1- 6.3 are taken from htosiewicz [41. For a detailed treatment of quasilinearization techniques, see Bellman and Kalaba [l]. Section 6.4 consists of the work of Macki and Waltman [l]. For further results using similar methods, see Macki and Waltman [ 21 and Hartman [ 51. The results of Section 6.5 concerning n-parameter families are adapted from Hartman [41. In particular, Lemma 6.5.1 is due to Tornheim [l]. See also Klaasen [ 3 ] and Jackson [TI for related results. The results relating the k-point and n-point problems may be found in Hartman [l], Jackson and Klaasen [31 and Jackson The special results on the third-order equation can be found in Jackson and Schrader [4,5]. See also Klaasen [2].
[a].
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383
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INDEX A A-matrix, 226 Adjoint equation, 346 A priori estimates, 248 Angular function technique, 116
B Boundary value problems (see also Existence of solutions), boundary conditions of, linear--2point,2,10,81,95,101 linear-n point, 208, 358 general linear, 200 nonlinear, 34,36,113 sets for, 159 integral conditions for, 221 Bounds on derivatives, 26,73, 76 Brouwer invariance of domain theorem, 362
C Carathdodory theorem, 205 Contingent equations (see also Set-valued differential equations), 176 upper and lower solutions of, 182 Nagumo condition for, 185 existence theorems for, 186
in the large, 31 over infinite interval, 44 with general linear boundary conditions, 10 with nonlinear boundary conditions, 36 Existence of solutions of second order vector equations, in the small, 71 in the large, 81,83,85 Existence of solutions for first order twodimensional systems, estimation of number of solutions for, 121 finite, 136 infinite, 142 Eigenvalue problems, 353
F Functional differential equations, existence results for, 304, 308, 320, 324,332 uniqueness results for, 328 Funnel of solutions, 94, 153 b
Generalized spaces, 225 Schauder fixed point theorem, 226 contraction mapping theorem, 227 Goodman-Lance method, 344 Green’s function, 3, 246
D
H
Degree theory, 270 Dependence of solutions on boundary data, 186
Hausdorff metric, 176 Helly’s theorem, 238 Homogeneous function, 120 Homotopic, 263,271
E Egress points, 157,178 Existence of solutions of second order scalar equations, of two point boundary value problems, in the small. 2
I Interpolation problem, 208,358 Invariant sets, 177
385
INDEX
P
K Kakutani-Ky Fan fixed point theorem, 289 Kneser’s theorem, 95,188
Periodic solutions of functional differential equations, 328 of ordinary differential equations, 269 of set-valued differential equations, 301 Perron’s method, 62 Perturbed linear problems, 213
L LeraySchauder theory, 263 L p solutions, 234,243 Lyapunov functions, for existence theorems, 39, 87,265 for bounds on derivatives, 41,79 for boundary conditions, 145
Q Quasilinearization method, 349 Quasimonotone property, 72,209
M
S
Minimal and maximal solutions, 122 Modified functions, scalar-valued, 18 vector-valued, 69,89
Schauder fixed point theorem, 207 Set-valued mappings, 278,289 Set-valued differential equations, 176, 283,295 Shooting method, 95,312 Subspaces of solutions, 256 Super- and subfunction, 47 properties of, 52 relation with lower and upper solutions, 47
N N-parameter families of functions, 359 Nagumo’s condition, for scalar equations, 25 for systems, 74,76 for contingent equantions, 185 to determine boundary conditions, 166 Nicoletti problem (see also Interpolation problem), existence for, 209,211 uniqueness for, 2 11 Nonhomogeneous systems, of ordinary differential equations, 200,25 6 of set-valued differential equations, 283 of functional differential equations, 316,321 Nonlinear boundary conditions (see Boundary conditions)
T Topological methods, 154, 160 Tonelli’s theorem, 2 36
U Underfunction, 6 3 Uniqueness, 15,127 Uniqueness implies existence, 94, 102, 106,109,358 Upper and lower solutions, 12 Upper semicontinuous mappings, 278,292
W
0
Wazewski topological method, 157, 168, 180
Over function, 6 3
38 6