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LP(1I'2) is a two-sided Fredholm inverse of BA -1. Thus B in (2.36) is Fredholm. To compute the index, consider the I-parameter family of operators
BT
S; 00, sp ;::: 2.
is Fredholm, of index zero, and Ker B consists of constants.
+ 1)1/2, consider q(x, D) = BA -1 : p(1I'2) ---t p(1I'2).
PROOF. Setting A = (-~ (2.37)
0, and n :::: 2,
=
Iloglxll-s
0, and n :::: 1,
(3.13)
Y
(3.9)
157
II'\7xe-yvQ>fIILco ::::; Ci(Y) ,
with
where Zj
ESTIMATES FOR THE DIRICHLET PROBLEM
3.
f E C{ws+d(JR.n ).
This can be verified directly from the definition (1.64) in Chapter I; alternatively, see the computations (A.1O)-(A.15) of Chapter I (in which s is replaced by -s). Now (3.12) implie..'l f E CU,) , with A(j) = r(1+s) (d. (1.65) of Chapter I), and then Proposition 3.1 gives the implication in (3.11).
J/').
I
Ytl,)\I~-Lnl')f(x')dx'.
IR n
We use the relatively elementary fact that
0). Let k E COO(lR m \ 0) be homogeneous of degree -n, and odd, i.e., k( -z) = -k(z). We look at the singular integral operator with kernel k(