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Gjv(Mci), such that for every t > 0:
Proof. Since g./v(Kd) is free, (p can be extended in a unique way in a Lie algebra isomorphism fljv(]R 0. Now, since Gjv(Rd) is simply connected and nilpotent, we can define a group automorphism -> GN(Rd) by the property T^expz) = exp(^(x)), x £ It is then easily checked that for every t > 0:
and moreover that Tv commutes with the dilations Ac, c > 0.
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The maps Tv give the formulas for a change of basis in the theory of free Carnot groups. Notice that without the freeness assumption, Tv may fail to exist. Remark 2.9 Notice that the map Aut (Rd) -> Aut (Gjv(Md)),