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0 for t > O. Then differentiation of the double integral for
0 for t > O. Thus (14) with 6 = -1 implies that A > I, and the theorem follows.] Let us now consider the case where the function p can only take positive or zero values, assuming that it is not identically zero. The functions fn(t),
I they will satisfy the inequality
(/"-1 +
0
for every real value of t different from zero. This may be demonstrated in the following way: Putting S"
= (/,,-1 +