Springer Monographs in Mathematics
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Dietlinde Lau
Function Algebras on Finite Sets A Basic Course on Many-Valued Logic and Clone Theory
With 42 Figures and 46 Tables
123
Dietlinde Lau Institute for Mathematics University of Rostock Universitätsplatz 1 18055 Rostock, Germany e-mail:
[email protected]
Library of Congress Control Number: 2006929534
Mathematics Subject Classification (2000): 03B50, 08Axx, 08A40, 08A30, 08A05, 06A15 ISSN 1439-7382 ISBN-10 3-540-36022-0 Springer-Verlag Berlin Heidelberg New York ISBN-13 978-3-540-36022-3 Springer-Verlag Berlin Heidelberg New York This work is subject to copyright. All rights are reserved, whether the whole or part of the material is concerned, specifically the rights of translation, reprinting, reuse of illustrations, recitation, broadcasting, reproduction on microfilm or in any other way, and storage in data banks. Duplication of this publication or parts thereof is permitted only under the provisions of the German Copyright Law of September 9, 1965, in its current version, and permission for use must always be obtained from Springer. Violations are liable for prosecution under the German Copyright Law. Springer is a part of Springer Science+Business Media springer.com © Springer-Verlag Berlin Heidelberg 2006 Printed in Germany The use of general descriptive names, registered names, trademarks, etc. in this publication does not imply, even in the absence of a specific statement, that such names are exempt from the relevant protective laws and regulations and therefore free for general use. Typesetting by the author using a Springer TEX macro package Production: LE-TEX Jelonek, Schmidt & Vöckler GbR, Leipzig Cover design: Erich Kirchner, Heidelberg Printed on acid-free paper
44/3100YL - 5 4 3 2 1 0
To my mother, Brigitte Lau
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Preface
Functions (or operations), which are defined on finite sets, occur in almost all fields of mathematics. For more than 80 years, algebras (so-called function algebras), whose universes are such functions, have been studied. Particularly in Mathematical Logic, in Universal Algebra (more precise in the Clone Theory), and in parts of Computer Science, certain knowledge about these algebras are subject of the fundamental knowledge. Currently only one book has been published about function algebras, apart from certain monographs or dissertations of specific themes, survey articles and books that contain sections about function algebras or clones. This book has been written by R. P¨ oschel und L. A. Kaluˇznin in the German language and gives a very good overview about the results achieved up to 1979. During the last 26 years, many new results have been obtained; however, a new book about function algebras is overdue. The aim of the present book is to introduce the reader to the theory of function algebras and to give the latest state of research for some selected fields. The author would like to acquaint the reader with proof of the fundamental theorems and the different proof methods, to enable research in the field of the function algebras. This book is self-contained. All necessary fundamental concepts and facts are introduced, but some background knowledge about linear and abstract algebra would be helpful for readers. In the following Introduction, the reader finds short summaries of the 26 chapters of this book. The adjoined section Preliminaries explains abbreviations and some general symbols, which are more or less standard, and gives some facts from basic mathematics. Part I of this book introduces the reader to Universal Algebra to provide almost every knowledge concerning other fields of mathematics. Moreover, this part of Universal Algebra informs the reader that many of the following results
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of function algebras reply to questions that arise upon studying an algebra. The structure of this book enables the reader to skip the first part and immediately start reading Part II Function Algebras. The author provides the reader with new proofs concerning classic results of the theory of function algebras. The remaining proofs are adapted to the style of the book. The theorems from Sections 14.10, 15.4, 18.2, 18.3, and from Chapter 17 have not yet been published. Small mistakes from the original papers (including the papers of the author) have been corrected in this book without referring to the original mistakes. During the writing process I have tried to solve open mathematics questions and problems, which I recognized during my study of the corresponding literature. In some cases colleagues helped me. In such a case their names are mentioned in the relevant places in the book. I would like to thank my colleagues as well as the authors of the articles I referred to in my book. Especially, I would like to thank my doctoral thesis supervisors, Prof. G. Burosch (R¨overshagen), and Prof. V. B. Kudrjavcev (Moscow). I received first information on the complexity of themes in this book from their lectures. I owe Prof. I. G. Rosenberg (Montreal) much gratitude, as I learned many proof methods while studying his papers. I thank my colleagues Prof. Dr. K. Denecke (Potsdam), Prof. Dr. L. Haddad (Kingston), and Prof. Dr. R. P¨ oschel (Dresden) for their fruitful cooperation during many years. In particular, Prof. Haddad was a very great aid during the finishing of the book. I also owe him the organization and the financing (by the Natural Sciences and Engineering Council of Canada) of a linguistic correction of my text by Ms Eryn Kirkwood (from RedInk Editors, Ottawa ON, Canada). Ms Kirkwood deserves my special thanks.
Rostock, June 2006
Dietlinde Lau
Contents
Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
1
Preliminaries . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 Part I Universal Algebra 1
Basic Concepts of Universal Algebra . . . . . . . . . . . . . . . . . . . . . . . 1.1 Universal Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2 Examples of Universal Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.1 Gruppoids . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.2 Semigroups . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.3 Monoids . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.4 Groups . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.5 Semirings . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.6 Rings . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.7 Fields . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.8 Modules . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.9 Vector Spaces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.10 Semilattices . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.11 Lattices . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.12 Boolean Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2.13 Function Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.3 Subalgebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
25 25 27 27 28 28 28 28 28 29 29 29 29 30 30 30 31
2
Lattices . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.1 Two Definitions of a Lattice . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.2 Examples for Lattices . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.3 Isomorphic Lattices and Sublattices . . . . . . . . . . . . . . . . . . . . . . . . 2.4 Complete Lattices and Equivalence Relations . . . . . . . . . . . . . . .
35 35 39 39 41
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3
Hull Systems and Closure Operators . . . . . . . . . . . . . . . . . . . . . . . 45 3.1 Basic Concepts . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 45 3.2 Some Properties of Hull Systems and Closure Operators . . . . . . 46
4
Homomorphisms, Congruences, and Galois Connections . . . 4.1 Homomorphisms and Isomorphisms . . . . . . . . . . . . . . . . . . . . . . . . 4.2 Congruence Relations and Factor Algebras of Algebras . . . . . . . 4.3 Examples for Congruence Relations and Some Homomorphism Theorems . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4.3.1 Congruences on Groups . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4.3.2 Congruences on Rings . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4.4 Galois Connections . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
51 51 52 56 56 58 59
5
Direct and Subdirect Products . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61 5.1 Direct Products . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61 5.2 Subdirect Products . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 66
6
Varieties, Equational Classes, and Free Algebras . . . . . . . . . . . 6.1 Varieties . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6.2 Terms, Term Algebras, and Term Functions . . . . . . . . . . . . . . . . . 6.3 Equations and Equational Classes . . . . . . . . . . . . . . . . . . . . . . . . . 6.4 Free Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6.5 Connections Between Varieties and Equational Defined Classes 6.6 Deductive Closure of Equation Sets and Equational Theory . . . 6.7 Finite Axiomatizability of Algebras . . . . . . . . . . . . . . . . . . . . . . . .
71 71 73 76 78 81 82 84
Part II Function Algebras 1
Basic Concepts, Notations, and First Properties . . . . . . . . . . . 91 1.1 Functions on Finite Sets . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 91 1.2 Operations on PA , Function Algebras . . . . . . . . . . . . . . . . . . . . . . 94 1.3 Superpositions, Subclasses, and Clones . . . . . . . . . . . . . . . . . . . . . 96 1.4 Generating Systems for PA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 98 1.5 Some Applications of the Function Algebras . . . . . . . . . . . . . . . . 104 1.5.1 Classification of Universal Algebras . . . . . . . . . . . . . . . . . . 104 1.5.2 Propositional Logic and First Order Logic . . . . . . . . . . . . 105 1.5.3 Many-Valued Logics . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 115 1.5.4 Information Transformer . . . . . . . . . . . . . . . . . . . . . . . . . . . 116 1.5.5 Classification of Combinatorial Problems . . . . . . . . . . . . . 118
2
The Galois-Connection Between Function- and Relation-Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 125 2.1 Relations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 125 2.2 Diagonal Relations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126
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2.3 Elementary Operations on Rk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 2.4 Relation Algebras, Co-Clones, and Derivation of Relations . . . . 127 2.5 Some Operations on Rk Derivable from the Elementary Operations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 128 2.6 The Preserving of Relations; Pol, Inv . . . . . . . . . . . . . . . . . . . . . . 130 2.7 The Relations χn and Gn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 132 2.8 The Operator ΓA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 134 2.9 The Galois Theory for Function- and Relation-Algebras . . . . . . 135 2.10 Some Modifications of the P ol-Inv-Connection . . . . . . . . . . . . . . 137 2.10.1 Galois Theory for Finite Monoids and Finite Groups . . . 137 2.10.2 Galois Theory for Iterative Function Algebras . . . . . . . . . 139 2.11 Some Connections Between the Relation Operations . . . . . . . . . 142 3
The Subclasses of P2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 145 3.1 Definitions of the Subclasses of P2 and Post’s Theorem . . . . . . . 145 3.2 A Proof for Post’s Theorem . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 149 3.2.1 The Subclasses A of P2 with A ⊆ L and A ⊆ S . . . . . . . . 149 3.2.2 The Subclasses of L . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 154 3.2.3 The Subclasses of S, Which Are Not Subsets of L . . . . . 155 3.2.4 A Completeness Criterion for P2 . . . . . . . . . . . . . . . . . . . . 156
4
The Subclasses of Pk Which Contain Pk1 . . . . . . . . . . . . . . . . . . . 159
5
The Maximal Classes of Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 163 5.1 Introduction, a Rough Description of the Maximal Classes . . . . 163 5.2 Definitions of the Maximal Classes of Pk . . . . . . . . . . . . . . . . . . . 165 5.2.1 Maximal Classes of Type M (Maximal Classes of Monotone Functions) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 165 5.2.2 Maximal Classes of Type S (Maximal Classes of Autodual Functions) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 167 5.2.3 Maximal Classes of Type U (Maximal Classes of Functions, Which Preserve Non-Trivial Equivalence Relations) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 170 5.2.4 Maximal Classes of Type L (Maximal Classes of Quasi-Linear Functions) . . . . . . . . . . . . . . . . . . . . . . . . . . . . 171 5.2.5 Maximal Classes of Type C (Maximal Classes of Functions, Which Preserve Central Relations) . . . . . . . . . 173 5.2.6 Maximal Classes of Type B (Maximal Classes of Functions, Which Preserve h-Universal Relations) . . . . . 174 5.3 Proof of the Maximality of the Classes Defined in Section 5.2 . 179 5.4 The Number of the Maximal Classes of Pk . . . . . . . . . . . . . . . . . . 183 5.5 Remarks to the Maximal Classes of Pk (l) . . . . . . . . . . . . . . . . . . . 188
6
Rosenberg’s Completeness Criterion for Pk . . . . . . . . . . . . . . . . 191 6.1 Proof of Completeness Criterion . . . . . . . . . . . . . . . . . . . . . . . . . . . 191
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7
Further Completeness Criteria . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 211 7.1 A Criterion for Sheffer-Functions . . . . . . . . . . . . . . . . . . . . . . . . . . 211 7.2 A Completeness Criterion for Surjective Functions . . . . . . . . . . . 216 7.3 Fundamental Sets . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 217
8
Some Properties of the Lattice Lk . . . . . . . . . . . . . . . . . . . . . . . . . 219 8.1 Cardinality Statements . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 219 8.2 On the Cardinalities of Maximal Sublattices of Lk . . . . . . . . . . . 224 8.3 Some Strategies for the Determination of Sublattices of Lk . . . . 229
9
Congruences and Automorphisms on Function Algebras . . . 233 9.1 Some Basic Concepts and First Properties . . . . . . . . . . . . . . . . . . 234 9.2 Congruences on the Subclasses of P2 . . . . . . . . . . . . . . . . . . . . . . . 235 9.3 Characterization of the Non-Arity Congruences . . . . . . . . . . . . . 238 9.4 About the Number of the Congruences on a Subclass of Pk . . . 243 9.5 A Criterion for the Proof of the Countability of Con A for Certain A ⊆ Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 248 9.6 Congruences on Some Classes of Linear Functions . . . . . . . . . . . 250 9.7 Congruences on the Maximal Classes of Pk . . . . . . . . . . . . . . . . . 256 9.8 Congruences on Subclasses of [Pk1 ] . . . . . . . . . . . . . . . . . . . . . . . . . 265 9.9 Congruences on Some Subclasses of Pk,l . . . . . . . . . . . . . . . . . . . . 273 9.10 Some Further General Properties of the Congruences and the l-Classes . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 278 9.11 The Connection Between Clone Congruences and Fully Invariant Congruences . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 282 9.12 Automorphisms of Function Algebras . . . . . . . . . . . . . . . . . . . . . . 285
10 The Relation Degree and the Dimension of Subclasses of Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 291 10.1 The Definition of the Relation Degree and of the Dimension of a Subclass of Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 291 10.2 The Dimensions and Relation Degrees of Post’s Classes . . . . . . 293 10.3 Further Examples of the Dimension and Relation Degree of Classes . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 301 11 On Generating Systems and Orders of the Subclasses of Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 307 11.1 Some General Properties of Generating Systems and Bases . . . 308 11.2 The Orders and Sheffer-Functions of the Classes of Type C1 , S or U . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 310 11.3 Orders of the Classes of Type L, C, B . . . . . . . . . . . . . . . . . . . . . . 314 11.4 The Order of P olk for ∈ Mk and k ≤ 7 . . . . . . . . . . . . . . . . . . 319 11.5 A Maximal Clone of Monotone Functions That Is Not Finitely Generated . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 324 11.6 Classifications and Basis Enumerations in Pk . . . . . . . . . . . . . . . 332
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12 Subclasses of Pk,2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 335 12.1 Notations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 336 12.2 Some Properties of the Inverse Images . . . . . . . . . . . . . . . . . . . . . 337 12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 342 12.4 The Pl -projectable and the P oll {α}-projectable Subclasses of Pk,l . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 350 12.5 The Maximal and the Submaximal Classes of Pk,2 . . . . . . . . . . . 354 12.6 The Classes A with M ∩ T0 ∩ T1 ⊆ prA or L ∩ T0 ∩ S ⊆ prA or prA = M ∩ S . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 361 13 Classes of Linear Functions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 383 13.1 Some Properties of the Subclasses of Ud That Contain rd . . . . . 384 13.2 The Subclasses of Linear Functions of Pk with k ∈ P . . . . . . . . . 387 13.3 A Survey of Further Results on Linear Functions . . . . . . . . . . . . 390 14 Submaximal Classes of P3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 399 14.1 A Survey of the Submaximal Classes of P3 . . . . . . . . . . . . . . . . . . 400 14.2 Some Declarations and Lemmas for Sections 14.3–14.9 . . . . . . . 408 14.3 Proof of Theorem 14.1.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 410 14.4 Proof of Theorem 14.1.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 412 14.5 Proof of Theorem 14.1.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 415 14.6 Proof of Theorem 14.1.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 418 14.7 Proof of Theorem 14.1.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 418 14.8 Proof of Theorem 14.1.8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 421 14.9 Proof of Theorem 14.1.9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 424 14.10On the Cardinality of L↓3 (A) for Submaximal Clones A . . . . . . . 425 15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 433 15.1 The Lattice of Subclasses of P3 of Linear Functions . . . . . . . . . . 433 15.2 The Subsemigroups of (P31 ; ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 15.3 Classes of Quasilinear Functions of P3 . . . . . . . . . . . . . . . . . . . . . . 456 15.3.1 Some Notations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 456 15.3.2 Subclasses of L0,1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 457 15.3.3 The Subclasses of L0,1 ∪ L0,2 That Are Not Subclasses of L0,1 or L0,2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 461 15.3.4 The Remaining Subclasses of L . . . . . . . . . . . . . . . . . . . . . 463 15.4 The Subclasses of [O1 ∪ {max}] . . . . . . . . . . . . . . . . . . . . . . . . . . . 464 15.4.1 Some Descriptions of the Class M . . . . . . . . . . . . . . . . . . . 464 15.4.2 Some Lemmas and a Rough Partition of the Subclasses of M . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 465 15.4.3 The Subclasses of [M 1 ] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 470 15.4.4 The Subclasses of R . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 471 15.4.5 The Subclasses of M ∩ P ol3 {(0, 2)} . . . . . . . . . . . . . . . . . . 482
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15.4.6 The Remaining Subclasses of M . . . . . . . . . . . . . . . . . . . . . 488 16 The Maximal Classes of a∈Q P olk {a} for Q ⊆ Ek . . . . . . . . . 499 16.1 Notations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 499 16.2 Results of Chapter 16 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 16.3 Some Lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 502 16.4 Proof of Theorem 16.2.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 513 17 Maximal Classes of P olk El for 2 ≤ l < k . . . . . . . . . . . . . . . . . . . 515 17.1 Notations, Definitions, and Some Lemmas . . . . . . . . . . . . . . . . . . 515 17.2 Results of Chapter 17 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 519 17.3 Maximality Proofs . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 520 17.4 Some Lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 528 17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 529 17.6 Classes Describable by Relations of Rmax (Pl ) ∪ Rmax (Pk ) . . . . 549 18 Further Submaximal Classes of Pk . . . . . . . . . . . . . . . . . . . . . . . . . 555 18.1 The Maximal Classes of P olk s for s ∈ Sk . . . . . . . . . . . . . . . . . 555 18.2 Some Maximal Classes of a Maximal Class of Type U . . . . . . . . 561 18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)}) . . . . . . . . . . . . 573 18.3.1 Definitions of the U -Maximal Classes . . . . . . . . . . . . . . . . 573 18.3.2 Proof of the U -Maximality of the Classes Defined in 18.3.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 576 18.3.3 Proof of the Completeness Criterion for U . . . . . . . . . . . . 584 19 Minimal Classes and Minimal Clones of Pk . . . . . . . . . . . . . . . . 589 19.1 Minimal Classes . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 589 19.2 The Five Types of Minimal Clones . . . . . . . . . . . . . . . . . . . . . . . . . 590 20 Partial Function Algebras . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 597 20.1 Basic Concepts . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 598 20.2 One-Point Extension . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 600 20.3 Description of Partial Clones by Relations . . . . . . . . . . . . . . . . . . 604 3 . . . . . . . . . . . . . . . . . . 606 2 and P 20.4 The Maximal Partial Classes of P k . . . . . . . . . . . . . . . . . . . . . . . . 614 20.5 The Completeness Criterion for P k . . . . . . . . 616 20.6 Some Properties of the Maximal Partial Clones of P 20.7 Intervals of Partial Clones That Contain a Maximal Clone . . . . 619 20.8 Intervals of Boolean Partial Classes . . . . . . . . . . . . . . . . . . . . . . . . 627 20.9 On Congruences of Partial Clones . . . . . . . . . . . . . . . . . . . . . . . . . 628 References . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 639 Glossary . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 655 Index . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 663
Introduction
The present book deals with a subarea of the Discrete Mathematics. We study functions, which are defined on finite sets, and we study the composition of these functions. Such functions are used, for example, in Computer Science (in particular, in the Switching Theory and in the Theory of Automata), in Mathematical Logic, and in Universal Algebra (in particular, the Clone Theory).1 In other words, we choose an arbitrary finite set A and study an algebra, whose universe is the set PA
(or Pk := P{0,1,2,..,k−1} )
of all n-ary mappings (n ∈ N), which maps the Cartesian power An (of all ordered n-tuples of elements from A) into A, and whose operations are the so-called superposition operations that are described as follows:2 – permutation of variables – identification of variables – adding of fictitious variables and – substitution of variables of a function by functions Denote F (n) the set of all n-ary functions of F ⊆ PA . Moreover, let Ω be the set of all superposition operations described above. Then, PA := (PA ; Ω) is called (full) function algebra (on A). The universe of a subalgebra of PA is called closed set or a subclass (or briefly a class) of PA . If F is a subclass of Pk then F is also called a subclass of the k-valued logic. The set of all closed sets of Pk together with the set inclusion forms a lattice Lk . 1 2
See, for this purpose, also Section 1.5 of Part II. One finds an exact definition of these operations in Section 1.2 of Part II.
2
Introduction
The closed sets of P2 were already determined in the papers [Pos 20] and [Pos 41] by E. L. Post. For over 50 years, many papers have dealt with function algebras or closed sets of Pk for arbitrary k. One finds a survey of the essential articles, which were published up to the year 1978, on the topic in [P¨ os-K 79] with 730 references and in [Ros 77] with 464 references. To give the reader a first impression of the problems handled in the theory of the function algebras, some explanations are subsequently given to the completeness problem3 , which stood in the center of a line of investigations in many articles: One finds a criterion, to decide if a set of functions that belong to Pk is sufficient for the construction of any arbitrary other function of Pk (by means of the superposition operations). A general answer to that is given by the following criterion, which was formulated by E. L. Post in 1921, first, for Boolean functions, i.e., for functions of P2 : A set F ⊆ Pk is complete in Pk if and only if F is a subset of no maximal class of Pk . A closed set M ⊂ Pk is said to be maximal in Pk , if M can not be properly extended to a closed proper subset of Pk . With regard to such and similar question formulations, one naturally deals with the structure of the subclasses of Pk or with the lattice of the subclasses of Pk . The first and most important result in this direction is Post’s pioneering description of L2 ([Pos 41], see Figure 1), now known as Post lattice. One can describe the many Post’s classes with the aid of the classes P2 , M , S, L, Ta (1) Ta,µ , D ∪ C, K ∪ C, [P2 ], C, (a ∈ {0, 1}, µ ∈ N \ {1}) and through formation of certain intersections of these classes, where T0 , T1 , M , S, and L are exactly the maximal classes of P2 .4 For some time, it was thought that L3 is equally simple. Then, Ju. I. Janov and A. A. Muˇcnik showed in the year 1959 the existence of subclasses of Pk for k ≥ 3 with infinite and without basis, respectively, and this implies the existence of a non-countable infinite set of subclasses in Lk (see also [Ehr 55]). Thus, there are as many closed sets in Pk as there are subsets of Pk for k ≥ 3. In contrast to k = 2, therefore, it seems hard to give an effective description of Lk for k ≥ 3. Nevertheless, one could determine the maximal classes of Pk for arbitrary k. S. V. Jablonskij determined all 18 maximal classes of P3 in [Jab 54] and [Jab 58]. Moreover, he extended his results by describing several types of maximal classes of Pk . This work was continued by V. V. Martynyuk [Mar 60], E. Ju. Zacharova [Zac 67], R. A. Bairamov [Bai 67] ˇ ˇ 67]. In [Zac-K-J (some results incorrect) and V. L. Rvaˇcev/ L. I. Sljarov [Rva-S 71] it has been reported that late A. I. Mal’tsev had all 82 maximal sets of P4 . I. G. Rosenberg published the missing maximal classes for Pk in [Ros 65] and 3 4
In Section 1.5 of Part II, it is shown that this problem is a mathematical way to describe problems that occur during the construction of electronic circuits. See Chapter 3 of Part II for details.
Introduction
3
he proved in the book [Ros 70a] that there can not be any further maximal classes for arbitrary k, whereby the general completeness problem for Pk was solved. Rosenberg’s description of the maximal classes is based on the idea of a function preserving a relation; i.e., he could prove that every maximal class has the form P olk , where is a certain h-ary relation on Ek , 1 ≤ h ≤ k, k ≥ 3 and P olk is the set of all functions of Pk , which preserve the relation . To find the maximal ones among classes of the form P olk , he designed a sieve method, which eliminates at each step every relation for which a relation σ is found in the list such that P olk ⊆ P olk σ. The process terminates when the candidate list contains only relations such that P olk can be proved to be maximal. This approach was twofold in scope. To discover the maximal classes and, at the same time, to prove that one has a full list of them. The idea to describe classes through relations kept on being developed to a Galois-theory for function algebras and relation algebra by V. G. Bodnarˇcuk, L. A. Kaluˇznin, V.N. Kotov, B. A. Romov (in [Bod-K-K-R 69]). The interesting subclasses of Pk are not only the maximal ones, and so the Galois theory was and is an important aid for the study of subclasses of Pk . Namely, one can classify finite universal algebras and also combinatorial problems with the aid of the elements of Lk (see Section 1.5 of Part II). These and many other applications presuppose, however, precise knowledge about the subclasses of Pk . Therefore, the object of this book is to explain some methods to the finding of subclasses of Pk and to give a survey of subclasses and their properties, which were determined in the last years. To familiarize the reader from the beginning also with the algebraic side of the function algebras and to show that the concepts introduced for function algebras are only special cases of more general concepts mostly from the Universal Algebra, we begin with an introduction to the Universal Algebra in the first part of this book. One finds supplements to this short introduction to the Universal Algebra in the books [Bur-S 81], [Coh 65], [Gr¨ a 68], [Ihr 93] (or [Ihr 2003]), [McK-M-T 87], [Wer 78] and [Lau 2004], volume 2. In Part II, we deal only with the function algebras. The construction of the book is chosen in a way that one can immediately begin reading Part II and, if one needs concepts and facts from Part I, one can reference these. Unlike Part I, which is strongly linearly structured in that each chapter is based on the preceding chapter, after studying the first two chapters of Part II, all successive studies can also be studied. We concentrate in Part II on the following topics: • • • • •
Basic concepts and notations Galois-connection between function algebras and relation algebras Post’s results on the subclasses of P2 the maximal classes of Pk completeness criterions for Pk (in particular, the Rosenberg’s completeness criterion)
4
Introduction
• congruences on subclasses of Pk • complexity measures for generating systems (for example as order or relation degree and dimension) of certain subclasses of Pk • subclasses of linear functions of Pp (p prime number) • a survey on subclasses of Pk , whose functions have at most two different values • submaximal classes of P3 • the description of all finite and countably infinite sublattices of the depth 1 or 2 of the lattice of all subclasses of P3 • submaximal classes of Pk , which are subsets of maximal classes described by unary relations • a survey of results to maximal classes of Pk for arbitrary k • minimal clones • partial function algebras. One finds completions to this book and a survey on further topics of the function-algebras-theory in [P¨ os-K 79] and [Ros 84]. Subsequently the content of this text is described in brief without the necessary concepts and notations.
Part I Chapter 1 begins with the definition of a universal algebra (briefly: algebra) as a pair (A;F) consists of a nonempty set A and a set F of certain operations on A and gives numerous examples of algebras (among that also the function algebras). In addition, one finds the very important concept of the subalgebra in this chapter. Chapter 2 compiles needed order concepts within the framework of an introduction to the lattice theory. The usual definitions of a lattice are indicated, and the calculation in the lattice theory illustrates by means of the proof of a few classical theorems of the lattice theory. Chapter 3 generalizes observations, which one can make when one examines more closely such concepts as subalgebra or linear hull of subsets of a vector space (or another closure operators of the classical algebra), to the concepts hull system and closure operator. Then, it is shown that these concepts deliver, roughly, the same. In addition, certain combinations to the lattice theory are given, and the lattices, formed from the subalgebras of an algebra, are uniquely characterized through certain properties. Chapter 4 combines properties of such important concepts as the homomorphic and isomorphic mappings between universal algebras, which the readers surely know from the classical algebra here, and which are defined obviously for universal algebras. It is shown, how homomorphic mappings are
Introduction
5
ultimately determined by congruence relations (i.e., by equivalence relations, which are compatible with the operations of algebra). The (general) homomorphism theorem keeps on being proved and is shown by examples, as this theorem can be improved for concrete algebras. A section of Chapter 4 deals with Galois connections between set systems that are continued later for function algebras in Chapter 2 of the second part. Chapter 5 shows how one can form new algebras from given algebras through direct or subdirect products and how one can recognize whether a given algebra is isomorphic to an algebra formed in this way. More precisely: we deal with the following two questions: Which algebras are smallest constituents of given algebras? How can one reduce a given algebra to its smallest constituents? Answers to these questions are given by theorems found by G. Birkhoff. We prove these theorems in Chapter 5. In particular, we prove the representation theorems for algebras: Each finite algebra is isomorphic to a direct product of directly irreducible algebras. Each algebra is isomorphic to a subdirect product of subdirectly irreducible algebras. Chapter 6 deals with classes of algebras of the same type and some theorems on such classes, which were found also by G. Birkhoff. At first we introduce so-called varieties as classes of algebras, which are closed in respect to the formation of subalgebras, homomorphic images and direct products. We then come to a method for the construction of algebra classes that strongly differs from the first method at first sight: Based upon certain equations from variables and operation symbols of a certain type τ , we form the class of all algebras of type τ that these equations fulfill. The result is so-called equational classes. We will see, however, that there is a close connection between the two methods of the algebra class construction: class of algebras is equational defined if and only if it is a variety. In the section on equational classes, we will also treat such concepts as the conclusion of an equational set. In addition, we treat ways to receive such conclusions. In Chapter 9 of Part II, we show that the results on congruences of a subclass F ⊆ PA imply results on subvarieties of the variety, which is generated by the algebra (A; F ) and vice versa.
6
Introduction
Part II Chapter 1 begins with the precise definition of function algebras (PA ; Ω), where Ω is an infinite set of operations, which describe the above superposition operations exactly, on PA first. It is shown then how one can receive the operations of the set Ω through five elementary operations (so-called “Mal’tsevOperationen”) ζ, τ, ∆, ∇ and by means of composition. The basis of further investigations is, then, the (full iterative) function algebra PA := (PA ; ζ, τ, ∆, ∇, ) bzw. Pk := PEk mit Ek := {0, 1, ..., k − 1}. A universe of a subalgebra of Pk is called subclass (or more briefly, class) in the following. If [T ] denotes the set of all functions of PA , which one can form from the functions of T ⊆ PA by means of superposition operations, then we have [F ] = F for arbitrary subclass F of PA . (n) n A mapping defined by ei : EA −→ A, (x1 , x2 , ..., xn ) → xi , where i ∈ {1, 2, ..., n}, is called a projection. A clone is a subclass of PA , which contains all projections of PA . In Chapter 1 there are notations, concepts . . . that are used in the following chapters repeatedly. In addition, it is shown that the set PA and some subsets of PA can be formed from binary functions of PA by means of superposition operations. At the end of Chapter 1, we briefly show how one can use the results of this book and how certain investigations are motivated in the theory of function algebras. Chapter 2 provides tools (like the the concepts of “a function preserves a relation” and “a relation is an invariant for a function”) by which classes, dealt in later chapters, can be effectively described. The set Rk of all n-ary relations on Ek (n = 1, 2, 3, ...) is defined and operations over the set Rk so that Rk with these operations forms a relation algebra Rk . Each universe of a subalgebra of Rk is called a co-clone of Rk . The main result of Chapter 2 is the proof that the lattice of the clones of Pk is antiisomorphic to the lattice of all co-clones of Rk . The basis of this result is the Galois-connection (P ol, Inv), where P ol : P(Rk ) −→ P(Pk ) and Inv : P(Pk ) −→ P(Rk ) are mappings defined by P olk Q := {f ∈ Pk | f preserves each relation of Q}, Invk F := { ∈ Rk | is an invariant for each function f of F } for arbitrary Q ⊆ Rk and arbitrary F ⊆ Pk . The Galois-connection (P ol, Inv) makes it possible to consider the function algebras instead of relation algebras and vice versa. Moreover, one can handle function algebras and relation algebras with equal significance, as it happens in [P¨ os-K 79], for example. We deal, however, with the clones in this book and proceed only with the co-clones if the proof methods developed for function algebras are not sufficient.
Introduction T0 T0,2
T0,3
T0,∞
P2
M T 1
K
S∩M
K ∪C
S
C0
I
L [P21 ]
I C
D∪C
7
T1,2 T1,3
T1,∞
D
C1
∅
Fig. 1. The Post’s lattice
The connection between algebras and relations was introduced by M. Krasner ([Kra 46] and [Kra 68/69]). He has completely developed the special Galois-connection between subsets of the permutation groups Sn := {f ∈ (1) Pk | f is bijective} and subsets of Rk . Later, Krasner also developed a sim(1) ilar theory for subsemigroups of Pk . Krasner’s theory was generalized by V. G. Bodnarˇcuk, L. A. Kaluˇznin, V. N. Kotov, and B. A. Romov in [Bod-K-K-R 69]. Chapter 3 gives all subclasses from P2 (the so-called Post’s classes) and proves the completeness of the list. In addition, smallest generating systems (“bases”) and the orders of the Post’s classes are determined. The results of Chapter 3 were found by E. L. Post (see [Pos 20] and [Pos 41]). Figure 1 gives the Hasse-diagram of the lattice of the subclasses of P2 . A knot of the graph without denotation represents a class that can be described as an intersection of classes that lie above it. Chapter 4 describes all classes that contain all unary functions of Pk . There exist k + 1 of such classes, which form a chain in the lattice of all subclasses of Pk . The results of Chapter 4 were found by G. A. Burle (see [Bur 67]). Chapter 5 begins with a coarse description of the maximal classes of Pk . The idea to describe classes this way was indicated already in [Kuz 59] by
8
Introduction
A. V. Kuznecov. Then classes, from which we show later (in Section 5.3) that they are maximal classes of Pk , are defined. (In Chapter 6, the proof is all maximal classes are determined.) As in [Ros 70] the classes are divided in Section 5.2 into six types and characterized by their invariants (relations). We denote the relation sets needed in this case with with Mk , Sk , Uk , Lk , Ck and Bk . Subsequently a maximal class is called a maximal class of the type X, when it can be described with the aid of a relation from set Xk , where X ∈ {M, S, U, L, C, B}. Next to the definitions of the maximal classes of Pk one finds the proofs of some properties of the maximal classes needed in later chapters, and the derivation of a recursion formula for the number determination of the maximal classes of Pk . Chapter 6 gives the proof found by I. G. Rosenberg and published in [Ros 70a] that the classes defined in Section 5.2 are the only maximal classes of Pk for arbitrary k. In some parts, the original proof can be abbreviated by using proof ideas from some papers (for example from [Qua 82] and [P¨ os-K 79]). As already explained, there is also a solution of the completeness problem for Pk through the description of maximal classes of Pk . Chapter 7 shows how one can derive some further completeness criteria for specific question formulations from the Rosenberg’s completeness criterion 6.1. First of all we will handle a criterion for Sheffer functions which was found by G. Rousseau. 5 Then we will show how one can reduce the conditions from Theorem 6.1 if one considers only surjective functions. Finally, we deal with criteria indicate under which conditions a set (⊆ Pk ) consisting of certain unary functions and a Slupecki-function 6 is complete in Pk . Chapter 8 explains the qualitative differences between the lattice L2 of the subclasses of P2 and the lattice Lk of the subclasses of Pk for k ≥ 3. While L2 is countable-infinite, Lk has the cardinality of the continuum (denoted by c) for k ≥ 3. This results from the fact that, for every k ≥ 3, the set Pk has a subclass with an infinite basis. One finds examples of such classes not only in Chapter 8, but also in Sections 12.3 and 14.10. Moreover, we deal with cardinality statements about chains and antichains (in Lk ) and with the embedding of Lk into Lk in Chapter 8. Then the question is clarified, which cardinalities the lattices L↓k (A) 7 for maximal classes A of Pk have. In the last section of Chapter 8, the reader finds “strategies” for the determination of “manageable” sublattices of Lk . In addition, two examples of theorems prove how one can determine certain sections of Lk . Chapter 9 deals with homomorphic mappings from a subclass of Pk onto a 5 6 7
A Sheffer function is a function that every function of Pk can be formed from by means of the superposition operations. This is a function f ∈ Pk \ [Pk1 ] with Im(f ) = Ek . L↓k (A) denotes the set of all subclasses of A.
Introduction
9
subclass of Pk , As generally accepted,8 one can characterize every homomorphism from a class A through a certain congruence relation9 on A. After some basic concepts are defined, all congruences on the subclasses of P2 are determined in Chapter 9. It is the aim of the sections following then, to specify the general homomorphism theorem for function algebras and to find statements on the number of congruences on a subclass of Pk through determination of some general properties of the congruences on subclasses of Pk . Then, all congruences are determined for selected classes (among other things, these are the maximal classes of Pk and certain classes from linear functions). Criteria with which one can find out whether on a partial class of Pk only trivial congruences exist are in addition derived. A further section deals with the connection between clone congruences and the fully invariant congruences on free algebras. The theorem found in this case has interesting inferences and is a bridge between certain investigations in the Universal Algebra and certain investigations in the theory of the function algebras. At the end of this chapter, one can find some results on automorphisms. It is proven that Pk , the subclasses of P2 , and the maximal classes of Pk have only inner automorphisms. The starting point and the basis of subsequent results are derived from an article by A. I. Mal’tsev (see [Mal 66]). Important contributions to the topic of Chapter 9 are also performed by V. V. Gorlov and I. A. Mal’tsev. Chapter 10 deals with the relation degree and the dimension of subclasses A of Pk . The relation degree of A is the smallest number h so that the class A is unambiguously described by a relation set whose elements have the arity h at most. The dimension of A is the smallest arity of a relation that characterizes the class A unambiguously. Chapter 10 begins by investigating the connections between these two complexity measures of the relational description of classes. After that, the relation degrees and dimensions of the Post’s classes, which were found by G. N. Blochina in [Blo 70], are proven. In Section 10.3, one can find further classes for which one knows the relation degree or the dimension. Chapter 11 deals with a further measure (the so-called order of a class), with whose aid the complexity of a description of a subclass of Pk can be characterized. If the class A ⊆ Pk is finitely generated, we call the smallest number r with [A(n) ] = A the order of A. In the case that the subclass A ⊆ Pk is not finitely generated we write ord A = ∞. Section 11.1 shows that one can determine the order easily for a class, if one knows the subclasses of the treated class. Therefore, order statements are often the “by-products” of considerations, which were actually used for determining certain classes or 8 9
See also Chapter 4 of Part I. Those ones are the equivalence relations, which are compatible with the superposition operations on the considered class.
10
Introduction
sublattices of Pk . So, for example, the orders of the Post’s classes result from the considerations of Chapter 3 for verification of the Post’s lattice. Further order statements are found in Chapters 13 and 14. Therefore, in Chapter 11, only the statements on the maximal classes that are described in Chapter 5 are determined. It is proven that, for k ≥ 3, each maximal class of the type S, U, L, B or C1 has the order 2 and that, for the order of a class of the type Ch , where h ≥ 2, the arity h of the descriptive relation of this class is an upper bound. If M ⊂ Pk is a maximal class of the type M, we can only prove that M has the order 2 for the cases 2 ≤ k ≤ 7 and for case that the descriptive binary relation of M has certain properties. For k ≥ 8 there are maximal classes of the type M that do not have a finite order. To prove this fact, we give an example, published by G. Tardos in [Tar 86]. If one has a finite generating class A, it is an interesting problem to clarify which cardinalities are possible for the bases of this class A. In Section 11.2 we show that the proof for ord P olk ≤ 3, where ∈ C1k ∪ Uk ∪ Sk , implies the existence of functions f with [f ] = P olk . Following corresponding notation for functions from Pk , such function f is called a Sheffer function for P olk . The last section explains shortly, as one can determine the cardinalities of the possible bases of the class A, if ord A < ∞. Furthermore, some basic ideas of [Miy 71], [Miy-S-L-R 86], [Miy 88], and [Sto 87] are explained on basis classifications. For more information on the topic, we direct the reader to [Miy 88] and [Sto 87] of M. Miyakawa and I. Stojmenovic. Chapter 12 summarizes the subclasses of the class Pk,2 := {f ∈ Pk | f has only values of the set {0, 1} }, which were found by G. Burosch, J. Dassow, N. Gr¨ unwald, W. Harnau, and the author. When one restricts the domain of a function f (n) ∈ Pk,2 to the set E2n , a homomorphic mapping pr (“projection”) from Pk,2 onto P2 can be defined. Since the image prA of a subclass A of Pk,2 is a subclass of P2 and the subclasses of P2 are known, one can hope to find of certain properties of the inverse images (⊆ Pk,2 ) through the known properties of the images (⊆ P2 ). This hope confirmed itself in a certain sense (see, e.g., Theorem 12.2.5 and Theorem 9.7.6). Conversely, Pk,2 , k ≥ 3, also reflects the negative properties of Pk because the examples of classes from Section 8.1.1 with infinite and without bases are subclasses of Pk,2 . Further, the functions of Pk,2 are important since they can be interpreted as predicates. Chapter 12 is organized as follows: Section 12.1 contains the basic concepts and notations. Section 12.2 contains results on inverse images of subclasses of P2 (with respect to the above projection). The remaining sections deal with the determination of cardinality and with the determination of the elements
Introduction
11
Fig. 2. A survey on |Nk (B)| for B ∈ L2
of the set Nk (B) := {A | A is a subclass of Pk,2 with pr A = B} for arbitrary subclass B of P2 . In Section 12.3, one can find some structure statements about the lattice of all subclass of Pk,2 . It is also clarified in this section whether the set Nk (B) is finite or infinite or has the cardinality of continuum. Section 12.4 generalizes some statements from Section 12.3 for Pk,l with 2 ≤ l < k. In Section 12.5, the maximal and the submaximal classes of Pk,2 are determined. Then, the investigations are continued from Section 12.3 for k = 3, i.e., for many classes B ⊆ P2 with |N3 (B)| ≤ ℵ0 the elements of the set N3 (B) are determined. Figure 2 shows a survey of the obtained results. This figure shows the Post’s graph, where the knots of this graph are differently labeled. If a class B of P2 is marked in this graph through , this means that the set Nk (B) has the cardinality of the continuum. The second marker means that |Nk (B)| ≥ ℵ0 and |N3 (B)| = ℵ0 are valid. For the remaining classes B whose knots do not have any marker the set Nk (B) is finite for arbitrary k ∈ N. Chapter 13 deals with classes of linear functions of Pk , i.e., with closed subsets of the set
12
Introduction
Lk :=
n≥1
{f (n) ∈ Pk | ∃a0 , ..., an ∈ Ek : f (x) = a0 +
n
ai · xi (mod k)}.
i=1
The lattice of the subclasses of Lk belongs to the earliest and best investigated sublattices of Lk . For the case that k is a prime number, all subclasses, which are no subsets of [L1k ], were determined by A. A. Salomaa in [Sal 64]. The results of [Sal 64] were proven by J. Bagyinszki and J. Demetrovics in [Bag-D 82] and complemented with the remaining subclasses of [L1k ], p ∈ P. ´ Szendrei. For examMany results about linear functions were obtained by A. ple, she proved in [Sze 78] that Lk has only finitely many subclasses, if k is square-free. In addition, she showed that an arbitrary class has, at most, the order 2 (or 3), if k is quare-free and k is an odd number (or an even number), respectively. For the case that k is not square-free, one easily finds a class that does not have any finite basis, whereby the set Lk has infinitely-many subclasses in this case. Section 13.1 starts with properties of certain subclasses of the set (n) := ∈ Lk | ∃a0 , ..., an ∈ Ek ∃j ∈ {1, ..., n} : Ud n≥1 {f f (x) = a0 + aj · xj + d · i=1,i=j ai · xi }. This set is closed, if d is a divisor of k (notation: d | k). Then, with the aid of the results from the first section new proofs are indicated for the theorems of [Sal 64] and [Bag-D 82] in Section 13.2. Chapter 13 ends with a survey on further results about linear and quasi-linear functions. Chapter 14 is the first chapter in this book of this book that deals only with submaximal classes. A subclass (or a subclone) of Pk is called submaximal if it is covered by a maximal class (clone). The concept submaximal class was introduced by I. G. Rosenberg in [Ros 74]. In [Ros 74] one finds also the first results about submaximal classes of Pk (see Chapter 17 for details). The submaximal classes are interesting not only because of their position in the second layer below Pk , but also because further completeness criteria for Pk result from a list of all submaximal classes. For arbitrary k, the full list of the maximal classes of a maximal class A of Pk is only known if A has the type S ([Ros-S 84], see Section 18.1), C1 (see Chapters 16 and 17) or A = P olk , 2 ∪ {(k − 1, k − 1)} (see Section 18.3). There are, however, where := Ek−1 some papers, in which one finds submaximal classes for specific k or only such submaximal classes that contain certain functions. In Section 14.1, one finds a complete description of all submaximal classes of P3 and some remarks about generalizations of the indicated theorems. The following papers provide a basis for this description: [Mac 79], [Mar-D-H 80], [Sal 64], [Bag-D 82] and [Lau 82a]. The theorems from Section 14.1 are proven then in Sections 14.2 – 14.9. In Section 14.10, we will prove that there are 5 submaximal classes with finitely many subclasses; 7 have countably many
Introduction
13
subclasses, and the remaining 146 submaximal classes have uncountably many subclasses. All elements of the lattices L↓3 (A), where A is a submaximal class with|L↓3 (A)| ≤ ℵ0 are determined in Chapter 15. Chapter 15 gives all finite or countably infinite sublattices of depth 1 or 2 of the lattice of the subclasses of P3 , where the finite cases are easy conclusions from Chapter 13. We say that the lattice L↓k (A) of subclasses of A = [A] ⊆ Pk has the depth t, if t is the least integer for which there are some classes A1 , ..., At−1 ∈ Lk with A ⊂ A1 ⊂ A2 ⊂ ... ⊂ At−1 ⊂ Pk . For k = 3 by the Theorems 13.2.3 and 8.1.6 there exist finite and countably infinite sublattices of the depth 1 or 2. In Chapter 15 these sublattices shall be determined exactly. The finite lattices L↓3 (L3 ) of depth 1 are found in Section 15.1. This lattice is a conclusion from Chapter 13. In addition, by Section 14.10, this lattice is the only finite lattice of depth 1 and, further, this lattice contains all finite sublattices of L3 of depth 2. Because of Theorem 14.10.1, there are exactly 7 submaximal classes with |L↓3 (A)| = ℵ0 . One obtains these classes through formation of isomorphic pictures of the following two classes: (1) L3 = [P3 ] ∪ n≥1 {f (n) ∈ P3 | ∃f0 , f1 , ..., fn ∈ P31 : f (x1 , ..., xn ) = f0 (f1 (x1 ) + f2 (x2 ) + ... + fn (xn ) (mod 2))} and M :=
{f (n) ∈ P3 | ∃f1 , ..., fn ∈ O1 : f (x1 , ..., xn ) = f1 (x1 ) ∨ ... ∨ fn (x)},
n≥1
where O1 is the set of all unary monotonous functions (in respect to the total order 0 < 1 < 2) of P3 and x ∨ y := max{x, y}. Since L3 contains also all subclasses, which are generated from unary functions of P3 . First of all, the 1299 subsemigroups of the semigroup (P31 ; ) are determined in Section 15.2. The list of these semigroups is then an important aid in Section 15.3 during the determination of the remaining subclasses of L3 . In Section 15.4 one finds all subclasses of M. Chapter 16 supplies the description (coming from [Sze 91] or [Lau 82b, 95a]) of all maximal classes of the subclass P olk {a} TQ := a∈Q
of Pk for arbitrary Q with ∅ = Q ⊆ Ek , k ≥ 2. With the aid of these classes, a completeness criterion for TQ can be formulated easily. This criterion implies
14
Introduction
necessary and sufficient conditions for whether a finite algebra is semi-primal and has only trivial subalgebras. If |Q| = 1, then TQ is a maximal class of Pk and the maximal classes of TQ , given in Chapter 15, are submaximal classes of Pk . Moreover, if |Q| ≥ 2, we prove that every maximal class of TQ is an intersection of TQ with certain maximal classes of Pk or P olk {a} (a ∈ Q). Chapter 17 continues the investigations of Chapter 16 and generalizes Theorem 14.1.3. For arbitrary k, l ∈ N with 2 ≤ l ≤ k − 1 all maximal classes of P olk El are determined, where 9 relation sets are needed. It is important to note that, for the description of the maximal classes of P olk {a}, a ∈ Ek , one needs only 6 relation sets. With the help of the maximal classes of P olk El , one can easily give a completeness criterion for P olk El . The proofs given in Chapter 17 resemble those ones from Chapter 6, i.e., the results of this chapter were achieved with the means developed by I. G. Rosenberg in [Ros 70a]. Chapter 18 gives a survey (partial without proof) over further submaximal classes found until now. In supplement to Chapters 16 and 17, all submaximal classes of a maximal class of the type S are described in this chapter. It is shown, then, how one can prove the special case k ∈ P of this general description easily. The rest of this chapter deals with submaximal classes of Pk that lie below a maximal class of the type U. In Section 18.2, one can find some maximal classes of P olk , where ∈ Uk is arbitrary. Then, in Section 18.3, the list is completed from Section 18.2 to the list of all maximal classes 2 ∪ {(k − 1, k − 1)} . of P olk for = Ek−1 Chapter 19 Chapter 19 deals with classes of Lk , which are either direct predecessors of the empty set (so-called minimal classes) or which are direct predecessors of the set of all projections (so-called minimal clones). Consequently, it is not difficult to determine the minimal classes. However, for the minimal clones, only partial results can be given. In Chapter 19, one finds a description of all minimal classes. Moreover, Rosenberg’s classification of minimal clones is proven. At the end of Chapter 19, one finds a survey of further results about minimal clones and the description of all partial minimal clones. Chapter 20 deals with partial function algebras. A partial n-ary function k the set on Ek is a mapping from a subset of Ekn into Ek , n ∈ N. Let P of all such functions with n ∈ N. Then one can introduce certain modified k of all partial functions on Ek . Then, the Mal’tsev-operations over the set P set Pk , together with these operations, forms a so-called (full) partial function k ; τ, ζ, ∆, ∇, ), which can similarly be examined like the function algebra (P algebra (Pk ; τ, ζ, ∆, ∇, ). The choice of results on partial function algebras in this chapter focuses on questions already treated for Pk in previous chapters.
Introduction
15
After a composition of some basic concepts in Section 20.1, Section 20.2 shows k is isomorphic to a certain sublattice that the lattice of all partial clones of P of the lattice of all clones of Pk+1 . Thus, one gets many properties of the partial clones from the properties of the clones, which were already found. However many results on clones that may be helpful to find certain partial clones with the aid of the above-mentioned isomorphism are missing. One k with the help could, for example, not solve the completeness problem for P of an isomorphism. In Section 20.3, we show how to describe partial clones by relations. Sections 20.4 and 20.5 deal with the maximal partial clones, with whose help, as for Pk , the completeness problem of the partial logic is soluble. We will 3 has exactly 58 maximal partial clones. In 2 has exactly 8 and P prove that P k for arbitrary Section 20.5, there is a complete list of all maximal clones of P k ∈ N, found by L. Haddad and I. G. Rosenberg. The list is given without proof. In Section 20.6, we determine those descriptive relations of the maximal clones of Pk , which are also descriptive relations of the maximal partial clones k . In addition, we survey those papers that deal with the determination of of P the orders of maximal partial clones. Section 20.7 deals with the determinak | C = [C] ∧ C ∩ Pk = A}, tion of the cardinality of the set I(A) := {C ⊆ P where A is an arbitrary maximal clone of Pk . We will prove that, if A has the type U, S or C, I(A) is a finite set. On the other hand, the set I(A) has the cardinality of continuum if A has the type L or B. For the type M we can give only partial results. Section 20.8 surveys of the cardinalities of the sets I(A), where A is an arbitrary subclass of P2 . In the last section we determine the congruences on the maximal partial k has exactly 4 congruences, whereas clones. It is proven, particularly, that P a maximal partial clone has exactly 4, 8, or 10 pairwise distinct congruences. Finally, one can find some technical references: As already noted, the chapters of this book are not continuously numbered, except for the chapters of the first and second part. References to parts, chapters, sections, lemmas, theorems, ... are given through their numbers. If a reference of the first or second part is missing, then the part discussed is referred to. About the basics of Universal Algebra there are many publications and books. Therefore, only some references for the theorems are given in Part I of this text. In Part II of the book, references for a theorem are left out only if one can prove the theorem easily and if there are several references for this theorem. Normally, one finds references at the beginning of the chapters and with the theorems, whereby it is also clear that the lemmas appertaining to these theorems are based on considerations from the quoted references. For some few theorems, the proofs are taken over from the quoted references directly.
16
Introduction
However new and shorter proofs are presented particularly for theorems that come from older books. The end of a proof (or of a statement with easy proof) is marked by . Some book parts that can be ignored during the first reading differ from the remaining text through a smaller writing.
Preliminaries
We assume that the reader has some knowledge about the basic concepts from the set theory1 , linear algebra, classical algebraic structures and mathematical logic. The following is a list of terms to which we assume the reader is familiar. 1) Logical Symbols So that we can write down mathematical statements quickly and correctly, we use the following symbols from mathematical logic:
symbol
denotation for
∧
and
∨
or
¬
not
=⇒
implies; if - then
⇐⇒
if and only if; iff
:= :⇐⇒
equal by definition equivalent by definition
∃
there exists; it exists at least
∃!
it exists exactly
∀
for all
In order to save parentheses, we write instead of ∃x ( E ) (read: “There exists an x with the property E”) shortly ∃x : E. We arrange analogous one for 1
A naive theory of sets is sufficient for our purposes.
18
Preliminaries
formulas that contain the sign ∀. In addition, ∀x ∃y ... stands for ∀x (∃y (...)), and so forth. 2) Symbols and Concepts of the Set Theory In dealing with sets, we use the following standard notations: membership (∈), nonmembership (∈), set-builder notations ({.... | ...........} 2 ), the empty set (∅), (⊆), proper inclusion (⊂), intersection (∩ inclusion (⊆), noninclusion and ), union (∪ and ) and difference (\). The power set of a set A is the set {B | B ⊆ A} of all subsets of A. It is denoted by P(A). N, N0 , Z, Q, R, C denote respectively the set {1, 2, 3, ....} of all natural numbers, the set N ∪ {0}, the set of all integers, the set of all rational numbers, the set of all real numbers, and the set of all complex numbers. For n ∈ N, we write the order n-tuples (briefly n-tuples) in the form (x1 , x2 , ..., xn ). For two n-tuples x := (x1 , x2 , ..., xn ) and y := (y1 , y2 , ..., yn ) is x = y iff xi = yi for all i ∈ {1, 2, ..., n}. A × B is the set of all 2-tuples (a, b) with a ∈ A and b ∈ B and is called the (Cartesian or direct) product of the sets A and B. For n ∈ N, Π1n Ai (or Πi∈I Ai , where I := {1, 2, ..., n}) denotes the set of all (a1 , a2 , ..., an ) with ai ∈ Ai for all i ∈ I. 3 Further, let An := {(a1 , ..., an ) | ∀i ∈ {1, 2, ..., n} : ai ∈ A} be the direct n-powers of the set A, n ∈ N. A correspondence F of A into B is a subset of A × B, where D(f ) := {a ∈ A | ∃b ∈ B : (a, b) ∈ F } is the domain of F and Im(f ) := {b ∈ b | ∃a ∈ A : (a, b) ∈ F } is the image (or range) of F . If D(F ) = A, then F is a correspondence from F . If Im(F ) = B, then we say that F is a correspondence onto B. The inverse (or converse) F −1 of a correspondence F ⊆ A × B is given by F −1 := {(b, a) ∈ B × A | (a, b) ∈ F }. If F ⊆ A × B and G ⊆ B × C, then the correspondence product F G is defined by F G := {(a, c) ∈ A × C | ∃b ∈ B : (a, b) ∈ F ∧ (b, c) ∈ G}. We remark that (F G)−1 = G−1 F −1 and is associative. A mapping (or map) f from A into B is a subset of A × B such that for each a ∈ A there is exactly one b ∈ B with (a, b) ∈ f . If f is a mapping from A into B, then we write f : A −→ B and, if (a, b) ∈ f , f (a) = b, or a → b. A mapping f : A −→ B is called injective (or is an injection) iff f (a) = f (a ) implies a = a for all a, a ∈ A. The mapping f : A −→ B is surjective (or is a surjection) iff Im(f ) = B. The mapping f : A −→ B is bijective (or is a bijection) iff is both injective and surjective. Let A be a set and n ∈ N. Then, an n-ary relation on A (or an n-ary 2 3
For example, we write S := {x | x ∈ A ∧ P (x)} or briefly S := {x ∈ A | P (x)} instead of “S is the set of all x ∈ A with the property P (x)”. For arbitrary I, we will define Πi∈I Ai in Part I, Section 5.
Preliminaries
19
relation over A) is a subset of An . A 2-ary , 3-ary or 4-ary relation on A is called respectively a binary, ternary or quaternary relation on A. Two sets A and B have the same cardinality (in symbol |A| = |B|) iff there exists a bijection from A onto B. A set A is infinite, iff there is a subset B ⊂ A with |A| = |B|. A set A is called finite iff A is not infinite. If A is a finite set, then |A| denotes the number of elements of A, i.e., |∅| = 0 and |x ∪ {x}| = |x| + 1 (or n = |{0, 1, 2, ..., n − 1}| for all n ∈ N0 , where n is called a (finite) ordinal). We put ℵ0 := |N| and c := |R|. The set A is called countable if |A| = ℵ0 . If |A| = c, we say that A has the cardinality of the continuum. It is well-known that ℵ0 is the least infinite ordinal and that N and R do not have ∞ the same cardinality. Further, it holds |Q| = ℵ0 , |C| = c, |P(N)| = c and | n=1 An | = ℵ0 if |An | = ℵ0 for all n ∈ N.
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Part I
Universal Algebra
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Part I Universal Algebra
23
The Universal Algebra is a mathematical discipline, which examines so-called universal algebras, where the classic algebraic structures – such as groups, rings, and lattices – are special cases of such algebras. Roughly said, a universal algebra is nothing other than a nonempty set together with a family of finite-ary operations over this set. Although the concept universal algebra was used already at the end of the 19th century, the development of the theory Universal Algebra started only in the 1930’s. This development has two historical roots. The first root is the classical algebra and the studies of properties that have all algebraic structures (such as semigroups, groups, rings, etc.). The second root is the Mathematical Logic. In the last decades, the Universal Algebra has continued the classic examinations and has also developed new areas. An introduction to the bases of the Universal Algebra follows. The topic of the following six chapters is based on what is needed later, during the investigation of the function algebras. The first five chapters show that the Universal Algebra is a general theory of the algebraic partial disciplines. Chapter 6 treats problems with an impression of the mode of operation of the algebra and that have partial also contact points to the mathematical logic. 1 Additions to the topics can be found in [Lau 2004] 2 . In detail one can study the Universal Algebra with the aid of the following books [Bur-S 81], [Coh 65], [Den-T 96], [Den 2003], [Gr¨ a 68], [Ihr 2003], [McKM-T 87], [Wer 78]. The book [McK-M-T 87] can particularly be recommended. In the preface, we have already noted that to understand the second part of the text need not be read absolutely. Thus, readers can select for themselves the required terms and theorems from Part I, during the reading of Part II. One night notice, after reading Part II, that some examinations are special cases of general problems.
1 2
To realize this, reads [Bur-S 81] and [Ric 78]. There, one finds a continuation to the chapters of Universal Algebra of this book and additional chapters.
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1 Basic Concepts of Universal Algebra
1.1 Universal Algebras First, we define the concept of an n-ary partial operation: Let A be a nonempty set, n ∈ N and ∅ ⊂ ⊆ An . An n-ary partial operation is a mapping f from into A. The number n is called arity of f and the arity of f is also denoted by af . To denote the arity of f we also write f (n) or briefly f n , since for content-related reasons, the interpretation is impossible of f n as Cartesian product in the following. If (a1 , ..., an ) ∈ then let f (a1 , ..., an ) be the image of (a1 , ..., an ) under an n-ary operation f . The set we call domain of f , and we denote the domain of f by D(f, A) or briefly by D(f ). Let Im(f ) be the set {f (a1 , ..., an ) | (a1 , ..., an ) ∈ D(f )}, which is called image or range of f . (n) (n) For n ∈ N let c∞ be the n-ary partial operation with D(c∞ ) = ∅.1 n If = A and n ≥ 1, then f is called an n-ary operation on A. If D(f (n) ) ⊂ An we call f (n) a proper partial operation. A nullary operation f on A is an element f of A with af := 0, D(f ) := ∅ and Im(f ) := {f }. Example The operation ◦ of a group (see also Section 1.2) is a binary operation. One can understand the formation of inverse elements in a group as a unary operation −1 and the identity e (unit element) of a group as a nullary operation. As is generally accepted, one can form compositions of mappings in the following manner: If f : M1 −→ M2 and g : M2 −→ M3 are mappings, then we denote the mapping 1
The necessity of such a definition is seen, if one forms superpositions of partial (1) functions (see Part II, Chapter 1). For example, it holds gf = c∞ for the unary operations f , g with D(f ) := {a} and a ∈ Im(g).
26
1 Basic Concepts of Universal Algebra
f g : M1 −→ M3 , x → g(f (x)) by f g. It is well-known (or it is easy to see) that is associative. Thus we can renounce the putting of brackets in the case of more than two compositions. Furthermore, we write g1 g2 ...gr instead of
g1 g2 ...gr (gi : Mi −→ Mi+1 , i = 1, ..., r),
if the operation follows from the context. We notice that the above definition of is a special case of the following definition, if one writes the mappings in the form of subsets of Cartesian products: Let R ⊆ A × B and Q ⊆ B × C. Then let RQ := {(a, c) | ∃b ∈ B : (a, b) ∈ R ∧ (b, c) ∈ Q}. With the help of the partial operations, we can define the following concepts: A partial algebra is an ordered pair A := (A; F ), where A is an arbitrary nonempty set and F is a set of partial operations on A. The set A is called universe (or underlying set) of A. The elements of F are called (partial) fundamental operations of A. A universal algebra or briefly an algebra is a partial algebra (A; F ), where every element of F is an operation, i.e., F does not have any proper partial operations. Here we usually only deal with algebras. Therefore, we often introduce the following concepts only for algebras. If F = {f1 , ..., fr } holds we write (A; F ) in the form (A; f1 , ..., fr ), where we often choose af1 ≥ af2 ≥ ... ≥ afr . We also use the notation (A; (fi )i∈I ), if F = {fi | i ∈ I} and I is a certain index set. A (partial) algebra (A; F ) is called finite, if A is a finite set, otherwise infinite. In order to receive a first classification of the algebras, it offers itself to carry out a classification according to the arities of the (partial) operations of the algebras. For this purpose, we define the concept type of an algebra (A; (fi )i∈I ) as a sequence
1.2 Examples of Universal Algebras
27
τ := (afi | i ∈ I) of the arities of their fundamental operations, if I is a finite or countable set. In the case that I is uncountable, we define as type of A the mapping τ : I −→ N, i → afi . If I is a finite set, then (A; (fi )i∈I ) is called of finite type. If A = (A; f1 , ..., fr ), af1 ≥ af2 ≥ ... ≥ afr , then let τ = (af1 , af2 , ..., afr ). Two (partial) algebras (A; F ), (B; G) are of same type, iff there is a bijection ϕ : F −→ G, f → g with af = ag. Examples2 1) A semigroup (H, ◦) is an algebra of type (2) (F := {◦}). 2) By the above remark, a group is an algebra of the type (2, 1, 0). 3) A lattice (see 1.2.11) is an algebra of type (2, 2). Because of existence of a bijection between the operations of two algebras A := (A; F ) and B := (B; G) of same type, we often denote the operation sets of A and of B with the same symbol (F or G). In analog mode we deal with the denotation of the elements. If it is necessary to denote the operations of two different algebras A and B of the same type differently, then we write f A or f B (or also fA or fB ), respectively. Before we deal with further basic terms from the theory of the algebras, let’s define some specific algebras. We will study some of these specific algebras in detail later.
1.2 Examples of Universal Algebras We start with some “classical algebras”. In defining these algebras, we try to use no existence quantor. 3 We call the equations, which are given for the definition of an algebra, axioms. As usual, we will try to use only a few (independent) axioms. We differ from this principle in the following only in few places (see e.q. the definition of a lattice). 1.2.1 Gruppoids An algebra (A; ◦) of type (2) is called gruppoid. Thus, a gruppoid is not a different one as a nonempty set together with a binary operation. 2 3
Section 1.2 contains the explanations to the concepts used. In Chapter 6, we see that this manner of description has interesting conclusions. In the following, we use the descriptions of the algebraic structures given in this section.
28
1 Basic Concepts of Universal Algebra
1.2.2 Semigroups A gruppoid (H; ◦) is called semigroup if the algebra (H; ◦) fulfills the following axiom: (A)
∀x, y, z ∈ H : (x ◦ y) ◦ z = x ◦ (y ◦ z)
(associativity).
A semigroup is called commutative, if it satisfies the following condition in addition: (C) ∀x, y ∈ H : x ◦ y = y ◦ x. 1.2.3 Monoids An algebra (M ; ◦, e) of type (2, 0) is called monoid, if (M ; ◦) is a semigroup and (E) ∀x ∈ M : e ◦ x = x ◦ e = x holds. The (nullary) operation e is the the neutral element of M . 1.2.4 Groups A group is an algebra (G; ◦,−1 , e) of type (2, 1, 0), which fulfills the above axioms (A), (E) for x, y, z, e ∈ G and (I)
∀x ∈ G : x ◦ x−1 = x−1 ◦ x = e .
x−1 is called the inverse element of x. A group, which (C) fulfills in addition, is called Abelian (or commutative). It is usual in Abelean groups to use +, −x, 0 instead of ◦, x−1 , e (the additive notation). 1.2.5 Semirings An algebra (R; +, ·) of type (2, 2) is called a semiring if (R; +) is a commutative semigroup, (R; ·) is a semigroup, and if the following distributive laws hold: ∀x, y, z ∈ R : x · (y + z) = (x · y) + (x · z), (D1 ) ∀x, y, z ∈ R : (x + y) · z = (x · z) + (y · z). (D2 ) 1.2.6 Rings An algebra (R; +, ·, −, 0) of type (2, 2, 1, 0) is called ring if (R; +, −, 0) is an Abelean group and (R; +, ·) is a semiring. In order to save parentheses, we use the known rule subsequently “The dot bill is carried out before the stroke bill”. A unitary ring (or a ring with a unit element) is an algebra (R; +, ·, −, 0, 1) of type (2, 2, 1, 0, 0), where (R; +, ·, −, 0) is a ring and (E) holds with e = 1 and ◦ = ·.
1.2 Examples of Universal Algebras
29
1.2.7 Fields A partial algebra (K; +, ·, −,−1 , 0, 1) is called field if the algebra (K; +, ·, −, 0, 1) is an unitary ring and (K\{0}; ·,−1 , 1) is an Abelean group. We remark that the operation −1 on K is only a partial operation, since 0−1 is not defined. 1.2.8 Modules Let R := (R; +, ·, −, 0) be a ring. An algebra (M ; F ) where F := {+, −, 0}∪R, + is binary, 0 is a nullary and − and all r ∈ R are unary operations is called a R-module (or module over the ring R), if (M ; +, −, 0) is an Abelean group and if for all r, s ∈ R the following equations hold: (M1 ) (M2 ) (M3 )
∀x, y ∈ M : r(x + y) = r(x) + r(y), ∀x, y ∈ M : (r + s)(x) = r(x) + s(x), ∀x ∈ M : (r · s)(x) = r(s(x)).
Let M := (M ; +, −, (r)r∈R , 0) be the short notation for the R-module defined above. Further, we say that M has the type (2, 1, (1)r∈R , 0). A module over a unitary ring (R; +, ·, −, 0, 1) is an above module that also satisfies the following condition: (M4 )
∀x ∈ M : 1(x) = x.
Three remarks to the above definitions: – Instead of the unary operations r ∈ R one can also define a mapping : R × M −→ M, (r, x) → r x, which fulfills the axioms. However, a module would then not be a universal algebra. – A module has infinite many operations if the ring R is infinite. – The operation symbols +, −, 0 have two different meanings: on the one hand, they describe the operations of the Abelean group (R; +, −, 0); on the other hand, they describe the operations of the Abelean group (M ; +, −, 0). 1.2.9 Vector Spaces Let K := (K; +, ·, −, 0, 1) be a field. Then every K-module (V ; +, −, (k)k∈K , 0) is called K-vector space (or vector space over the field K). 1.2.10 Semilattices A commutative semigroup (S; ◦), in which ∀x ∈ S : x ◦ x = x holds, is called semilattice.
30
1 Basic Concepts of Universal Algebra
1.2.11 Lattices A lattice is an algebra (L; ∨, ∧) of type (2, 2), in which for arbitrary x, y, z ∈ L it holds: (L1 ) x ∨ y = y ∨ x, x ∧ y = y ∧ x (L2 ) x ∨ (y ∨ z) = (x ∨ y) ∨ z, x ∧ (y ∧ z) = (x ∧ y) ∧ z (L3 ) x ∨ x = x, x ∧ x = x (L4 ) x ∨ (x ∧ y) = x, x ∧ (x ∨ y) = x
(commutativity), (associativity), (idempotency), (absorption).
A bounded lattice (or a lattice with 0 and 1) is an algebra (L; ∨, ∧, 0, 1) of type (2, 2, 0, 0) such that (L; ∨, ∧) is a lattice and furthermore the following equations hold for all x ∈ L: (L5 )
x ∧ 0 = 0, x ∨ 1 = 1.
A lattice is called distributive, if the following distributive laws hold: (DL1 ) (DL2 )
∀x, y, z ∈ L : x ∧ (y ∨ z) = (x ∧ y) ∨ (x ∧ z), ∀x, y, z ∈ L : x ∨ (y ∧ z) = (x ∨ y) ∧ (x ∨ z).
Remark: One can show (with the help of (L1 )–(L4 )) that (DL1 ) and (DL2 ) are equivalent; that is, it suffices to require either (D1 ) or (D2 ) in the definition of a distributive lattice. 1.2.12 Boolean Algebras An algebra (B; ∨, ∧,− , 0, 1) of type (2, 2, 1, 0, 0) is called Boolean algebra if (B; ∨, ∧, 0, 1) is a bounded distributive lattice and the following equalities hold for all x ∈ B: (B1 ) (B2 ) where x :=
−
x ∧ x = 0, x ∨ x = 1 x ∧ 0 = 0, x ∨ 1 = 1,
(x).
1.2.13 Function Algebras One can choose the set of all operations defined on A as a universe of an algebra and can then define operations on the operations on A. For the purpose of distinction we will subsequently replace the concept “operation (on the set A)” by the concept “function (on the set A)”. In Part II, the set A is always a finite set. Therefore, the following concepts become explained only for a specific k-element set Ek . Put Ek := {0, 1, ..., k − 1},
1.3 Subalgebras
31
k ∈ N\{1}. Let Pkn be the set of all n-ary functions f n , which map the n-fold n n Cartesian product Ek into Ek . Put Pk := n≥1 Pk . Elementary operations (called Mal’tsev-operations) over Pk are ζ, τ, ∆, ∇ (unary operations) and (a binary operation) defined by (ζf )(x1 , ..., xn ) := f (x2 , x3 , ..., xn , x1 ), (τ f )(x1 , ..., xn ) := f (x2 , x1 , x3 , ..., xn ), (∆f )(x1 , ..., xn−1 ) := f (x1 , x1 , x2 , ..., xn−1 ) if n ≥ 2, ζf = τ f = ∆f := f if n = 1, (∇f )(x1 , ..., xn+1 ) := f (x2 , x3 , ..., xn+1 ), (f g)(x1 , ..., xm+n−1 ) := f (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ) (f n , g m ∈ Pk ). It holds the following (see Part II, Chapter 1): With the help of the Mal’tsev-operations, one can form the following operations (for arbitrary functions and arbitrary variables of the functions): – permutation of variables – identification of variables – adding of fictitious variables and – substitution of variables of a function by functions The set of all functions that can be obtained by a finite number of applications of the above operations from the functions of F ⊆ Pk is called the closure of F , and is denoted by [F ]. If F = [F ], then we say that F is closed or F is a (sub)class of Pk . The algebra (Pk ; ζ, τ, ∆, ∇, ) of type (1, 1, 1, 1, 2) is called (full) iterative function algebra. If A is a subclass of Pk then (A; ζ, τ, ∆, ∇, ) is called function algebra.
1.3 Subalgebras Let A = (A; F ) be a (partial) algebra and let B be a nonempty subset of A. The (partial) algebra B = (B; F ) of the same type as A is called (partial) subalgebra of A (or A is an extension of B) iff it holds D(fB , B) ⊆ D(fA , A) for arbitrary f ∈ F and fA (x1 , ..., xaf ) = fB (x1 , ..., xaf ) for all (x1 , ..., xaf ) ∈ B af ∩ D(f, A). Then we write
32
1 Basic Concepts of Universal Algebra
B ≤ A. If A has a nullary operation f ∈ A and B is a subalgebra of A, then f also belongs to B. The following lemma summarizes easy consequences from the above definition of a subalgebra. Lemma 1.3.1 (a) A subset B of the universe A of an algebra (A; F ) together with the restrictions f|B of the operations f of A to B forms an algebra if and only if f (b1 , ..., baf ) ∈ B for all b1 , ..., baf , if af ≥ 1, and f ∈ B if af = 0 holds for arbitrary f ∈ F . (b) Let I bean arbitrary index set, Bi ≤ A for every i ∈ I and i∈I Bi = ∅. Then ( i∈I Bi ; F ) is a subalgebra of A. (c) For every nonempty subset T of the universe A of an algebra A = (A; F ) there exists exactly one smallest subalgebra T of A, which contains T and which one can describe as follows: T = (T ; F ) with T := {B | B ≤ A and T ⊆ B}.
The set T from Lemma 1.3.1, (c) is called generating system of the algebra T and the universe T of T is denoted by [T ]A or [T ]F or by [T ]f1 ,...,fr , if F = {f1 , ..., fr }, or simply by [T ]. Example For the algebra A = ({0, 1, 2, ..., k − 1}; f ) of the type (3) with f (x, y, z) = x + y − z (mod k) for arbitrary x, y, z ∈ A, it holds e.g. [{a}] = {a} for every a ∈ A and [{0, 1}] = A. If [T ] = T for a subset T ⊆ A of an algebra A = (A; F ), then we say that T is closed. The following lemma gives another possibility of the description of the set [T ], defined above. Lemma 1.3.2 Let A = (A; F ) be an algebra, T be a subset of A and F 0 be the set of all nullary operations of F . Then, for T we can define recursively the following subsets Tn of A as follows: T0 := T ∪ F 0 Tn+1 := Tn ∪ {f (g1 , ..., gaf ) | f ∈ F \F 0 and {g1 , ..., gaf } ⊆ Tn } (n ∈ N0 ).
1.3 Subalgebras
Then
[T ]A =
Tn .
n≥0
Proof. To prove “⊆” in (1.1), we have to show that
33
(1.1)
is the universe of n≥0 Tn a subalgebra of A. This would be shown if we have shown that n≥0 Tn is closed regarding the application of all operations of F \ F 0 . Now let f ∈ F \ F 0 and {g1 , ..., gaf } ⊆ n≥0 Tn be arbitrary. Since af ∈ N, there is an m ∈ N with {g1 , ..., gaf } ⊆ Tm . Consequently, f (g1 , ..., gaf ) belongs to Tm+1 , i.e., the set n≥0 Tn is closed. “⊇” follows from Tn ⊆ [T ]A for all n ≥ 0. This inclusion is easy to prove by induction on n, since [T ]A is the universe of a subalgebra of A.
The set
S(A) := {B | B is subalgebra of A} ∪ {∅}
we call briefly set of all subalgebras of A. Per definitionem (essentially for technical reasons) is also the empty set a subalgebra of each algebra. Then (as the reader can easily verify) S(A) together with the operations ∧ : S(A) × S(A) −→ S(A), B1 ∧ B2 = (B1 ∩ B2 ; F ) ∨ : S(A) × S(A) −→ S(A), B1 ∨ B2 = ([B1 ∪ B2 ]F ; F ) forms a lattice.4
4
This property would not hold for all algebras, if the empty set was not an algebra.
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2 Lattices
Lattices arise often in algebraic investigations. In the following we see that the concept “lattice” is always needed, if the elements of sets are ordered in a certain meaning. In addition, the lattice theory is an interesting branch of the Universal Algebra. For space reasons, only the most important basis concepts and some proof ideas of the lattice theory can be indicated here. For a secondary study of the lattice theory, refer to the books on the Universal Algebra and to [Bir 48], [Ern 82], [Sko 73] and [Dav-P 90].
2.1 Two Definitions of a Lattice There are two standard ways of defining lattices. One of these ways was already given in Section 1.2.11: Definition (First Definition of a Lattice) Let L be a nonempty set on which the binary operations ∨ (called “join”) and ∧ (called “meet”) are defined. (L; ∨, ∧) is called lattice if for arbitrary x, y, z ∈ L the following identities hold: (L1 a) x ∨ y = y ∨ x, (L1 b) x ∧ y = y ∧ x
(commutativity),
(L2 a) x ∨ (y ∨ z) = (x ∨ y) ∨ z, (L2 b) x ∧ (y ∧ z) = (x ∧ y) ∧ z
(associativity),
(L3 a) x ∨ x = x, (L3 b) x ∧ x = x
(idempotency),
(L4 a) x ∨ (x ∧ y) = x, (L4 b) x ∧ (x ∨ y) = x
(absorption).
36
2 Lattices
Since one receives an axiom again by exchanging of ∨ and ∧ in above axioms, results from every equation, which the axioms imply, by exchanging of ∨ and ∧ a further valid equation. One names this procedure of deriving equations in lattices, using the duality principle of the lattice theory. In the following proofs we often use the equivalence x ∨ y = y ⇐⇒ x ∧ y = x,
(2.1)
which is a conclusion from the absorption laws and from the commutative laws. For the second definition of a lattice we need some concepts and notations: Definitions • A binary relation ≤ (⊆ A × A) is called a partial order on the set A, if it fulfills the following conditions: (O1 ) ∀a ∈ A : a ≤ a (reflexivity), (O2 ) ∀a, b ∈ A : (a ≤ b and b ≤ a) =⇒ a = b (antisymmetry), (O3 ) ∀a, b, c ∈ A : (a ≤ b and b ≤ c) =⇒ a ≤ c (transitivity). • The pair (A; ≤), where ≤ satisfies the above conditions, we call partially ordered set or, briefly, poset. In examples, we often declare the posets through order diagrams1 (or Hasse diagrams). • A poset P := (P ; ≤) with P ⊆ A × A, which besides fulfills the condition (O4 ) ∀a, b ∈ A : a ≤ b or b ≤ a , is called totally ordered set or linearly ordered set or, briefly, chain. We also use the notation a < b if a ≤ b and a = b is valid, where (L; ≤) is a poset and a, b ∈ L. We also write b ≥ a instead of a ≤ b. Definition Let Q be a subset of P , where P = (P ; ≤) is a poset. The element s ∈ P is said to be a supremum of Q (denoted by sup Q) iff s has the following properties: (S1 ) ∀q ∈ Q : q ≤ s; (S2 ) ∀p ∈ P ((∀q ∈ Q : q ≤ p) =⇒ s ≤ p). Remark The supremum of Q does not exist in general for every subset Q of a poset P . Let e.g. P = {0, 1, 2, 3, 4} and let ≤ defined by the following order diagram: 1
Here, the elements of the poset are represented as points in the plane and, if x < y and no z exists with x < z < y, we draw y higher up than x and connect x and y with a line segment.
2.1 Two Definitions of a Lattice
37
4 2 3 0 1 Fig. 2.1
Then, sup{0, 1} does not exist, since for p ∈ {2, 3} 0 ≤ p and 1 ≤ p are valid, the elements 2 and 3 are not comparable in respect to ≤. Definition Let Q be a subset of P , where P = (P ; ≤) is a poset. The element i ∈ P is said to be an infimum of Q (denoted by inf Q) iff i has the following properties: (I1 ) ∀q ∈ Q : i ≤ q; (I2 ) ∀p ∈ P ((∀q ∈ Q : p ≤ q) =⇒ p ≤ i). Definition (Second Definition of a Lattice) A poset L := (L; ≤) is called lattice iff for arbitrary a, b ∈ L both sup{a, b} and inf{a, b} in L exist. Some elementary properties of sup and inf in a lattice are summarized in the following lemma: Lemma 2.1.1 Let (P ; ≤) be a lattice by the second definition. Then, for arbitrary x, y, z, u, v ∈ P it holds: (a) x ≤ y =⇒ sup{x, z} ≤ sup{y, z}, (b) x ≤ y =⇒ inf{x, z} ≤ inf{y, z}, (c) (x ≤ y and u ≤ v) =⇒ sup{x, u} ≤ sup{y, v}, (d) (x ≤ y and u ≤ v) =⇒ inf{x, u} ≤ inf{y, v}. Proof. (a) and (b) are easy to check. (c): Let x ≤ y and u ≤ v. Then by (a) it holds sup{x, u} ≤ sup{y, u} and sup{y, u} ≤ sup{y, v}. Since ≤ is transitive, by this (c) follows. One can prove (d) analogously to (c). The next theorem shows how the two lattice definitions are associated. Theorem 2.1.2 It holds: (a) If (L; ∨, ∧) is a lattice by the first definition, then one can define by a ≤ b :⇐⇒ a = a ∧ b
(2.2)
a partial order ≤, which together with L forms a lattice by the second definition.2
38
2 Lattices
(b) Conversely, if (L; ≤) is a lattice by the second definition, then one can define two binary operations ∨, ∧ by a ∨ b := sup{a, b} a ∧ b := inf{a, b}
and
and (L; ∨, ∧) is a lattice by the first definition. Proof. (a): Let (L; ∨, ∧) be a lattice and ≤ is defined by (2.2). Then a ∧ a = a
holds and thus a ≤ a for every a ∈ A. Hence ≤ is reflexive. If a ≤ b and b ≤ a, we have a = a ∧ b and b = b ∧ a. This and (L1 b) imply a = b. Thus ≤ is antisymmetric. Let now a ≤ b and b ≤ c. Then it holds a = a ∧ b and b = b ∧ c by definition of ≤. By this and by (L2 b) we have a = a ∧ (b ∧ c) = (a ∧ b) ∧ c = a ∧ c. Hence a ≤ c and thus ≤ is transitive. It remains to show that there exist sup{a, b} and inf{a, b} for all a, b ∈ L. For these let a, b ∈ L be arbitrary. By (L4 a) and (L4 b) then we have a = a ∧ (a ∨ b) and b = b ∧ (a ∨ b). Thus a ≤ a ∨ b and b ≤ a ∨ b. Let now a ≤ u and b ≤ u for a certain u ∈ L. Then the following equations hold: a = a ∧ u, b = b ∧ u, a ∨ u = (a ∧ u) ∨ u = u, b ∨ u = (b ∧ u) ∨ u = u, and (a ∨ b) ∨ u = (a ∨ u) ∨ (b ∨ u) = u ∨ u = u. If one uses the equation (a ∨ b) ∨ u = u, which just was proven, then one gets: (a ∨ b) ∧ u = (a ∨ b) ∧ ((a ∨ b) ∨ u) = a ∨ b. Therefore, we have a ∨ b ≤ u and sup{a, b} = a ∨ b holds by definition of sup. Analogously, one can show a ∧ b = inf{a, b}. For this, one mixed up ∧ in above considerations by ∨ and one replaced ≤ by ≥. Thus (L; ≤) is a lattice. (b): Let (L; ≤) be a lattice, a ∨ b := sup{a, b} and a ∧ b := inf{a, b}. Obviously, the so defined operations ∨ and ∧ are commutatively and idempotent. To show the validity of the associative law sup{x, sup{y, z}} = sup{sup{x, y}, z} one can prove (under use of Lemma 2.1.1) sup{x, sup{y, z}} ≤ sup{sup{x, y}, z} and sup{x, sup{y, z}} ≥ sup{sup{x, y}, z}. Analogously, one can show the associativity of inf. Because of sup{x, inf{x, y}} ≥ x and sup{x, inf{x, y}} ≤ x it holds obvious sup{x, inf{x, y}} = x. Analogously, one can show another absorption law. Consequently, (L; ∨, ∧) is a lattice by the first definition. 2
Because of (2.1) one also could have defined the following: a ≤ b :⇐⇒ a ∨ b = b.
2.3 Isomorphic Lattices and Sublattices
39
Because of Theorem 2.1.2 we can use the first or the second definition of an lattice subsequently according to requirement, where the statements of the Theorem 2.1.2 are used where appropriate. If one wants the above-mentioned duality principle on inequalities of the form ... ≤ ... enlarge, one has to define the exchanging of ≤ through ≥ as an additional replacement rule. In addition the implication (x ≤ y and u ≤ v) =⇒ (x ∨ u ≤ y ∨ v and x ∧ u ≤ y ∧ v),
(2.3)
resulting from Lemma 2.1.1 and from Theorem 2.1.2, will be an important aid in the below-given proofs.
2.2 Examples for Lattices 2.2.1 Let L := {0, 1}. Further, let ∨ be the conjunction on L and let ∧ be the disjunction on L. Obviously, (L; ∨, ∧) is a lattice. 2.2.2 Let L := N0 , let a ∨ b be the least common multiple and let a ∧ b be greatest common divisor of the integers a, b ∈ N0 . In this case, it is also easy to check that (L; ∨, ∧) is a lattice. 2.2.3 Examples for lattices by the second definition are: (P(A); ⊆), where A is an arbitrary nonempty set; (R; ≤), where ≤ is the usual order on R. One finds further examples in Section 2.4 and in the following chapters.
2.3 Isomorphic Lattices and Sublattices Definition Two lattices L1 , L2 are called isomorphic, iff there exists a bijective mapping α from L1 onto L2 such that for arbitrary a, b ∈ L1 the following two equations hold: α(a ∨ b) = α(a) ∨ α(b)
and
α(a ∧ b) = α(a) ∧ α(b). The mapping α is also called an isomorphism. Definition Let (P1 , ≤) and (P2 ; ≤) be posets. A mapping α from P1 onto P2 is called order-preserving, if the following holds: ∀a, b ∈ P1 : a ≤ b =⇒ α(a) ≤ α(b). Figure 2.2 gives an example of an order-preserving mapping between the lattices L1 and L2 :
40
2 Lattices
L2
L1 Fig. 2.2
Theorem 2.3.1 Two lattices L1 and L2 are isomorphic iff there is a bijective mapping α from L1 onto L2 such that both α and α−1 are order-preserving. Proof. “=⇒”: Let α be an isomorphism from L1 onto L2 . Then for all a, b ∈ L1
it holds:
a ≤ b =⇒ a = a ∧ b =⇒ α(a) = α(a ∧ b) = α(a) ∧ α(b).
Consequently, we have α(a) ≤ α(b), i.e., α is order-preserving. Let now c, d ∈ L2 arbitrary with c ≤ d. Then there exist a, b ∈ L1 with α(a) = c and α(b) = d. That α−1 is also order-preserving follows then from c ≤ d =⇒ α(a) ≤ α(b) =⇒ α(a) ∧ α(b) = α(a) =⇒ α(a ∧ b) = α(a) =⇒ a ∧ b = a =⇒ a ≤ b. “⇐=”: Let now α be a bijective mapping from L1 onto L2 with the property that both α and α−1 are order-preserving. Then for arbitrary a, b ∈ L1 we have a ≤ a ∨ b and b ≤ a ∨ b. Thus, α(a) ≤ α(a ∨ b) and α(b) ≤ α(a ∨ b). From this, it follows α(a) ∨ α(b) ≤ α(a ∨ b). Further, for arbitrary u ∈ L2 it holds α(a) ∨ α(b) ≤ u =⇒ α(a) ≤ u and α(b) ≤ u =⇒ a ≤ α−1 (u) and b ≤ α−1 (u) =⇒ a ∨ b ≤ α−1 (u) =⇒ α(a ∨ b) ≤ u. Consequently, α(a ∨ b) = sup{α(a), α(b)} and therefore α(a) ∨ α(b) = α(a ∨ b). Analogously, one can prove α(a) ∧ α(b) = α(a ∧ b).
Remark Figure 2.2 shows that one cannot leave the condition “α−1 orderpreserving” from Theorem 2.3.1.
2.4 Complete Lattices and Equivalence Relations
41
Theorem 2.3.2 For every poset (P ; ≤) there is a set system MP such that (P ; ≤) and (MP ; ⊆) are isomorphic; i.e., there exists a bijective mapping α from P onto MP with the property that α and α−1 are order-preserving. Proof. For every p ∈ P let M (p) := {x ∈ P | x ≤ p}. Then the set MP := {M (p) | p ∈ P } is a set system with the properties claimed in the theorem. To show this, we study the mapping α : P −→ MP . α is surjective by definition. From M (a) = M (b) it follows a ∈ M (b) and b ∈ M (a). Hence a ≤ b and b ≤ a, i.e., a = b. Thus α is injective. α is order-preserving, since a ≤ b and x ∈ M (a) imply x ≤ a ≤ b. Therefore, a ≤ b implies M (a) ⊆ M (b). Furthermore, M (a) ⊆ M (b) implies a ≤ b, i.e., α−1 is also order-preserving and thus α is an isomorphism. The following definition is a special case of a definition from Section 1.3: Definition
If L is a lattice and L is a subset of L with the property ∀x, y ∈ L : x ∨ y ∈ L and x ∧ y ∈ L ,
then (L ; ∨, ∧) is called a sublattice of (L; ∨, ∧). Remark Let (P ; ≤) and (Q; ≤) be posets with Q ⊆ P . Then, it is not valid in general that (Q; ∨, ∧) is a sublattice of the lattice (P ; ∨, ∧), where ∨, ∧ are defined in Theorem 2.1.2. An example is the poset ({0, 1, 2, 3, 4}; ≤) defined by the following order diagram: 4 3 2 1 0 Fig. 2.3
Obviously, ({0, 1, 2, 4}; ≤) is a poset, but ({0, 1, 2, 4}; ∨, ∧) is not a sublattice of ({0, 1, 2, 3, 4}; ∨, ∧), since 1 ∨ 2 = 3 ∈ {0, 1, 2, 4}. Definition A lattice L1 can be embedded into a lattice L2 , if there is a sublattice of L2 isomorphic to L1 .
2.4 Complete Lattices and Equivalence Relations Definition A poset is called complete iff for every subset A of P both sup A (denoted by A) and inf A (denoted by A) exist.
42
2 Lattices
A lattice which is complete as poset is a complete lattice. Examples 1) Obviously, each complete poset is also a lattice. 2) Every finite lattice is complete. 3) (R; ≤) is not complete. One can find further examples in Theorems 2.4.3 and 2.4.5. Theorem 2.4.1 For an arbitrary poset (L; ≤) with a greatest and a least element it holds:
∀A ⊆ L ∃ A ⇐⇒ ∀A ⊆ L ∃ A. Proof. “=⇒”: Let Ao := {x ∈ L | ∀a ∈ A : a ≤ x}. Since L has a greatest element,
we have Ao = ∅. It is easy to check that then can prove “⇐=”.
A=
Ao holds. Analogously, one
Theorem 2.4.2 Let A be an algebra. Then the lattice (S(A); ⊆) of all subalgebras of A is a complete lattice. Proof. The proof follows from Theorem 2.4.1 and the fact that every intersection of subalgebras of A is also a subalgebra of A (see Lemma 1.3.1, (b)). The following is a short summary of the equivalence relations: Definitions A binary relation is called an equivalence relation on a (nonempty) set A, if fulfills the following conditions: (E1 ) {(a, a) | a ∈ A} ⊆ (reflexivity); (E2 ) ∀a, b ∈ A : (a, b) ∈ =⇒ (b, a) ∈ (symmetry); (E3 ) ∀a, b, c ∈ A : ((a, b) ∈ and (b, c) ∈ ) =⇒ (a, c) ∈ (transitivity). Let Eq(A) be the set of all equivalence relations on A. By defining of the operation
−1
: P(A × A) −→ P(A × A), → −1 by
−1 := {(b, a) | (a, b) ∈ } and of the binary operation : P(A × A) × P(A × A) −→ P(A × A), (, ) → ◦ by
:= {(a, c) | ∃b ∈ A : (a, b) ∈ and (b, c) ∈ },
one can also write down the above conditions (E2 ) and (E3 ) as follows: (E2 ) −1 = , (E3 ) ⊆ .
2.4 Complete Lattices and Equivalence Relations
43
Instead of (a, b) ∈ we often write ab or (a, b) or a = b (mod ) or a ∼ b (mod ) (one say: a is equals (or equivalent) to b modulo ). For every set A there are two trivial equivalence relations: ∇A (:= κ1 ) := A2 (all relation)
and
∆A (:= κ0 ) := {(a, a) | a ∈ A} (identity or diagonale). Theorem 2.4.3 (Eq(A); ⊆) is a complete lattice for every nonempty set A. One can determine the infimum and the supremum of an arbitrary subset T := {i | i ∈ I} of Eq(A) as follows: T = i∈I i , T = i0 ,...,it ∈I;t<ℵ0 i0 i1 ...it . In particular, it holds for the equivalence relations κ and µ: κ ∨ µ = κ ∪ (κµ) ∪ (κµκ) ∪ (κµκµ) ∪ ... (i.e., (a, b) ∈ κ∨µ ⇐⇒ ∃c1 , ..., cn ∈ A : (∀i ∈ {1, 2, ..., n − 1} : (ci , ci+1 ) ∈ κ or (ci , ci+1 ) ∈ µ) and (a, b) = (c1 , cn )). Proof. The statement “(Eq(A); ⊆) is a complete lattice” follows from Theorem
2.4.1 and from the easily verifiable fact that the intersection of arbitrarily many equivalence relations on A is an equivalence relation on A again. The remaining statements one can easily check.
Definitions Let ∈ Eq(A) and a ∈ A. The set [a] (:= a/) := {x ∈ A | (a, x) ∈ } is called equivalence class of . The set A/ := {a/ | a ∈ A} of all equivalence classes of is called factor set of A by . The proof of the following theorem can be found in many books with sections on basic mathematics concepts. Theorem 2.4.4 Let A be a nonempty set. Then, for arbitrary ∈ Eq(A) and arbitrary a, b ∈ A: (a) A = a∈A a/; (b) a/ = b/ ⇐⇒ a/ ∩ b/ = ∅.
44
2 Lattices
Definitions A partition π of the set A is a set of nonempty subsets Ai (i ∈ I) of A (called blocks of π) with the properties: (Z1 ) i∈I Ai = A and (Z2 ) ∀i, j ∈ I : Ai ∩ Aj = ∅ or Ai = Aj . Let Π(A) be the set of all partitions of A. Regarding the contents, the following theorem, written with the help of concepts of the lattice theory, is identical to the well-known Main Theorem over equivalence relations. Theorem 2.4.5 If the partial order ≤ on Π(A) is defined by π ≤ π :⇐⇒ ∀b ∈ π ∃b ∈ π : b ⊆ b , then the lattices (Eq(A); ⊆) and (Π(A); ≤) are isomorphic. An order-preserving mapping α of Eq(A) auf Π(A) can be defined as follows: Let κ ∈ Eq(A) and π := {bi | i ∈ I} ∈ Π(A). Then α(κ) := {x/κ | x ∈ A} and
α−1 (π) := {(x, y) | ∃i ∈ I : {x, y} ⊆ bi }.
3 Hull Systems and Closure Operators
This chapter generalized observations that can be made when examining such similar concepts as subalgebra or linear hull of subsets of a vector space (or another closure operators of the classical algebra), to the concepts hull system and closure operator. Then, it is shown that these concepts deliver roughly the same.
3.1 Basic Concepts Definitions Let A be a nonempty set and let P(A) be the power set of A. A subset H of P(A) is a hull system (or a closed set system) on the set A if and only if (i) A ∈ H, and (ii) B := {b | b ∈ B} ∈ H for every nonempty subset B of H.1 The elements of H are called hulls. Examples 1) The set of all closed subsets of an algebra A is a hull system on A. 2) The set systems P(A), {A} and {A} ∪ {E ∈ P(A) | E finite} are hull systems on A for every nonempty set A. 3) The set of all equivalence relations Eq(A) is a hull system on A2 , A = ∅. Definitions A mapping C : P(A) −→ P(A) is called closure operator on A if and only if the following three conditions hold for all X, Y ⊆ A: (i) X ⊆ C(X) (extensivity), (ii) X ⊆ Y =⇒ C(X) ⊆ C(Y ) (monotony), (iii) C(C(X)) = C(X) (idempotency). 1
Let
{b | b ∈ B} :=
b∈B
b := {x | ∀b ∈ B : x ∈ b}.
46
3 Hull Systems and Closure Operators
Sets of the form C(X) are called closed, and we say that C(X) is generated of X. Example By Section 1.3, for every algebra, the operator [...]A is a closure operator. Definition If a closure operator C fulfills the following condition in addition (iv) ∀X ⊆ A : C(X) = {C(Y ) | Y ⊆ X and Y is finite}, then it is called algebraic closure operator.
3.2 Some Properties of Hull Systems and Closure Operators Hull systems and closure operators are generally the same: Theorem 3.2.1 (Main Theorem on Hull Systems and Closure Operators) (a) Let H be a hull system on A. For all X ⊆ A let CH (X) := {h ∈ H | X ⊆ h}. Then
(3.1)
CH : P(A) −→ P(A), X → CH (X)
is a closure operator on A, and the closed sets of CH are exactly the hulls of H. (b) Conversely, let C be a closure operator on A. Then HC := {C(X) | X ⊆ A}
(3.2)
is a hull system on A, and the hulls of HC are exactly the closed sets of A. (c) For every hull system H on A it holds H(CH ) = H,
(3.3)
and for every closure operator C on A it holds C(HC ) = C.
(3.4)
Proof. (a): The extensivity of the operator defined by (3.1) follows directly from the definition of CH (X). If X ⊆ Y , we have U := {h ∈ H | X ⊆ h} ⊇ V := {h ∈
3.2 Some Properties of Hull Systems and Closure Operators
47
H | Y ⊆ h}. Thus, CH (X) = {h ∈ H | X ⊆ h} ⊆ CH (Y ) = {h ∈ H | Y ⊆ h}. Therefore CH is monotone. To prove the idempotency of CH , first we show Y ⊆ CH (Z) =⇒ CH (Y ) ⊆ CH (Z).
(3.5)
Y ⊆ CH (Z) implies {h ∈ H | Z ⊆ h} ⊆ {h ∈ H | Y ⊆ h} and from this CH (Y ) ⊆ CH (Z), i.e., (3.5) holds. Choosing in (3.5) Y = CH (Z), then CH (CH (Z)) ⊆ CH (Z) follows from (3.5). By the extensivity of CH we have CH (Z) ⊆ CH (CH (Z)). Thus, CH is also idempotent and therefore CH is a closure operator. Next we prove (3.6) X ∈ H ⇐⇒ CH (X) = X. The statement “=⇒” in (3.6) follows directly from the definition of CH . “⇐=” follows from the definition of CH and the assumption (ii) (see Section 3.1). Thus (a) is proven. (b): Let C : P(A) −→ P(A) be a closure operator and HC is defined as in (3.2). The following equivalences are easy to check: ∀X ⊆ A (X ∈ HC ⇐⇒ C(X) = X).
(3.7)
The definition of C implies ⊆ A, i.e., A = C(A) ∈ HC . For arbitrary A ⊆ C(A) B∈B B ⊆ HC we have further B (= X∈B X) ∈ HC to show. Since for every we have B = C(B) and X∈B X ⊆ B, the extensivity ofC implies C( X∈B X) ⊆ C(B) = B for every B ∈ B. Then, by this we have C( X∈BX) ⊆ B∈B B. On the other hand X∈B X ⊆ C( X∈B X) also holds. Thus, C( B) = B ∈ HC is valid. (c): By using (3.7) and (3.6) it follows H(CH ) = H from X ∈ H(CH ) ⇐⇒ CH (X) = X ⇐⇒ X ∈ H. To prove C(HC ) = C, let Y ⊆ A be arbitrary. We have C(HC ) (Y ) = C(Y ) to show. By definition it holds that C(HC ) (Y ) = {Z | Z ∈ HC , Y ⊆ Z}. Consequently, by (3.7), C(HC ) (Y ) = {Z | C(Z) = Z, Y ⊆ Z}. Because of C(Y ) = C(C(Y )), we have {Z | C(Y ) = Z, Y ⊆ Z} ⊆ C(Y ). On the other hand it follows from Y ⊆ Z = C(Z) that C(Y ) ⊆ C(Z) = Z. This implies {Z | C(Z) = Z, Y ⊆ Z} ⊇ C(Y ). By summarizing, we obtain {Z | C(Y ) = Z, Y ⊆ Z} = C(Y ).
Theorem 3.2.2 (a) For every algebra A = (A; F ), [...]A is an algebraic closure operator on A. (b) Conversely, for every algebraic closure operator C on the set A there is a set F of operations on A such that {C(X) | X ⊆ A} is the set of all subalgebras of A = (A; F ). Proof. (a) follows from the description of the closure [T ]A of an arbitrary set T ⊆ A (see Lemma 1.3.1).
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3 Hull Systems and Closure Operators
(b): Let C be an algebraic closure operator. We have to define a certain set of operations F on A such that C(X) = [X]F holds for arbitrary X ⊆ A. For every finite n-element subset E := {e1 , ..., en } of A and for every e ∈ C(E) we define fE;e as follows: e, if {x1 , ..., xn } = E, n (x1 , ..., xn ) := fE;e x1 otherwise. We summarize the functions of type fE;e to the set F : n {fE;e | |E| = n, E ⊆ A, e ∈ C(E)}. F := n∈N
Then, by construction, we have C(E) = [E]F . Since C is an algebraic closure operator, from this C(X) = [X]F follows for every subset X ⊆ A.
Theorem 3.2.3 (a) Let C be a closure operator on A and let LC := {X ⊆ A | C(X) = X}. Then LC is a complete lattice with
C(Ai ) = C(Ai ) i∈I
and
i∈I
C(Ai ) = C(
i∈I
Ai ).
i∈I
(b) Every complete lattice is isomorphic to the lattice LC of all closed subsets of a certain set A with a closure operator C. Proof. (a) is easy to check. (b) Let L be a complete lattice. For X ⊆ L we define C(X) := {a ∈ L | a ≤ sup X}. Then C is a closure operator on L and the mapping α : L −→ LC , a → {b ∈ L | b ≤ a} is an isomorphic mapping from L into LC .
Definitions Let X, Y ⊆ A, let H be a hull system on A and let h ∈ H. • X is called a generating system (or a generating set) of h, if h = CH (X) holds. • h is finitely generated, if there is a finite set E ⊆ h with h = CH (E).
3.2 Some Properties of Hull Systems and Closure Operators
49
• X is CH -independent (or briefly: independent), if for all x ∈ X it holds x ∈ CH (X\{x}). • X is called a CH -basis (or briefly: basis) of h, if X is a CH -independent generating set of h. From general theorems about hull systems and closure operators, one gets the following statements (about algebras), which we will prove, only for the concrete hull system S(A) and the corresponding closure operator [...]A . Theorem 3.2.4 (a) Let A be a finitely generated algebra. Then, for every generating set T of A, there is a finitely generating set T ⊆ T of A. (b) Every finitely generated algebra has a finite basis. (c) Every algebra, which has not a basis, is not finitely generated. (d) Let A be an algebra that has a subalgebra A1 with countable infinite basis. Then S(A) has a cardinality that is greater than or equal to the cardinality of the continuum. Proof. (a): Let A = (A; F ) be finitely generated. Then, there is a finite generating set B0 = {b1 , b2 , ..., br } ⊆ A of the universe A with [B0 ]A = A. Now let T ⊆ A be an arbitrary generating set of the algebra A. Because of [T ] = A and because of Lemma 1.3.2, one can get an arbitrary element a ∈ A from elements of T by successively applying the operations of F . In particular, this also holds for the elements b1 , ..., br of B0 . Obviously, the set of all elements of T needed for this is a finitely generating set T ⊆ T of A. (b): Let A = (A; F ) be a finitely generated algebra. Then by (a) there exists with every generating set T of A a finite subset T ⊆ T that is already a generating set for the given algebra. If t ∈ [T \{t}] for all t ∈ T , then T is a finite basis. Otherwise, if t1 ∈ [T \{t1 }], T := T \ {t1 } is a generating set for A. If now for all t ∈ T it holds t ∈ [T \{t}], then T is basis for A. In opposite case, we deal with T like with T by going over to T , etc. By the finiteness of T , this process breaks off with the construction of a basis for A, whereby (b) is proven. (c) follows from (b). (d): Let T := {t1 , t2 , ...} be a countable infinite basis of the subalgebra A1 of A. By definition, for all subsets T ⊂ T , we have, then, that a ∈ T \T implies a ∈ [T ]. Therefore, different subsets T and T of T define different subalgebras [T ] and [T ]. Consequently, the cardinality of the set S(A) is not less than the cardinality of the set P(T ). Now, it is well-known that P(T ) has the cardinality of continuum. Thus (c) holds.
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4 Homomorphisms, Congruences and Galois Connections
It is clear that abstract algebraic properties of an algebra do not change if the elements and the operations of the algebra get other names. One can describe this fact mathematically using the concept isomorphism or isomorphic mapping. A generalization of this concept is homomorphism (or homomorphic mapping), with which one can describe similarities of algebras. Congruences and factor algebras are aids to determine homomorphisms. A Galois connection is a pair of mappings (σ, τ ) between two power sets P(A) and P(B), where the mappings τ and σ are antitone and extensive (see Section 4.4). With the aid of these mappings, one can define hull operators on A and on B. Then, these operators define closed set systems (⊆ P(A) or ⊆ P(B), respectively). Part of the usefulness of such Galois connections resides in the possibility of drawing conclusions about a closed set system on the basis of information about the other system. The Galois connection between function algebras and relation algebras, which we study in Chapter 2 of Part II, is an important aid in the solution of the completeness problem of the many-valued logic (see Part II, Chapter 5 and 6).
4.1 Homomorphisms and Isomorphisms Definitions Let (A; F ) and (B; G) be two universal algebras of the same type and F = {fi | i ∈ I} and G = {gi | i ∈ I} with afi = agi for every i ∈ I. We call the mapping ϕ : A −→ B a homomorphism or a homomorphic mapping from A into B, if ϕ is compatible with all f ∈ F , g ∈ G; i.e., it holds for all i ∈ I and all a1 , ..., aafi ∈ A: ϕ(fi (a1 , ..., aafi )) = gi (ϕ(a1 ), ϕ(a2 ), ..., ϕ(aafi )), if afi > 0, and ϕ(fi ) = gi for all fi ∈ F with afi = 0.
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4 Homomorphisms, Congruences, and Galois Connections
If ϕ in addition is bijective from A onto B, then ϕ is called an isomorphism or an isomorphic mapping from A onto B. A homomorphism from an algebra A into A is called an endomorphism of A. An isomorphism from A onto A is an automorphism of A. Obviously, ϕ−1 is an isomorphism from B onto A, if ϕ is an isomorphism from A onto B. Therefore, we can say: “A and B are isomorphic”, we write in this case A∼ =B (read: “A isomorphic B”) for the identification of this fact. It is easy to see that the composition of homomorphic mappings ϕ1 ϕ2 (ϕ1 : A1 −→ A2 , ϕ2 : A2 −→ A3 ) is a homomorphism from A1 = (A1 ; F1 ) into A3 = (A3 ; F3 ). With the help of this property, one can show that the relation “∼ =” is an equivalence relation on sets of algebras. The following lemma summarizes further elementary properties of homomorphic mappings. Lemma 4.1.1 Let ϕ be a homomorphic mapping from A = (A; F ) into B = (B; G). Then it holds: (a) ϕ(A) is closed in respect to B; i.e., (ϕ(A); G) is a subalgebra of B, which is called homomorphic image of A by ϕ. (b) If A is a subalgebra of A, then (ϕ(A ); G) is a subalgebra of (ϕ(A); G). (c) If T ⊆ A is a generating system of A, then ϕ(T ) is a generating system of ϕ(A). (d) If (B ; G) is a subalgebra of (ϕ(A); G), then the so-called inverse image (ϕ−1 (B ); F ) with ϕ−1 (B ) := {a ∈ A | ϕ(a) ∈ B } is a subalgebra of A. (e) Let ψ be a homomorphism from A into B, which is identical with ϕ on a generating system of A. Then, ϕ(a) = ψ(a) for each a ∈ A.
4.2 Congruence Relations and Factor Algebras of Algebras Definitions A congruence relation (briefly: congruence) or a kernel of a homomorphic mapping ϕ of an algebra A = (A; F ) is an equivalence relation κϕ on A that is induced by the homomorphism ϕ from A into B, that is, for all a, a ∈ A it holds: (a, a ) ∈ κϕ :⇐⇒ ϕ(a) = ϕ(a ). In the following, we also denote the relation κϕ with Ker ϕ. Let Con(A) be the set of all congruences of A. Examples The identity mapping idA with idA : A −→ A, a → a
4.2 Congruence Relations and Factor Algebras of Algebras
53
and the mapping ϕC with ϕC : A −→ {c}, a → c from A onto the 1-element algebra of the same type ({c}; G), where g(c, c, ..., c) = c for all g ∈ G, if ag > 0, and g = c, if ag = 0 holds, induce two so-called trivial congruences, the zero-congruence κ0 and the all-congruence (or one-congruence) κ1 : κ0 := {(a, a) | a ∈ A}, κ1 := A × A. Definition An algebra, which has only both congruences κ0 and κ1 , is called simple. Examples for simple algebras are groups of prime order and the fields. As the following lemma demonstrates, it is possible to describe the concept “congruence” without use of the concept “homomorphism”. Lemma 4.2.1 An equivalence relation κ on A is a congruence on the algebra A = (A; F ) if and only if it is compatible with all not nullary operations of F ; i.e., if for all f n ∈ F with n = af > 0 and arbitrary a1 , ..., an , a1 , ..., an ∈ A it holds: {(a1 , a1 ), ..., (an , an )} ⊆ κ =⇒ (f (a1 , ..., an ), f (a1 , ..., an )) ∈ κ. Proof. Let
F := {fini | i ∈ I},
where I denotes a certain index set. “=⇒”: Let κ be a congruence on A. Then, by the definition of a congruence, there exists an algebra B := (B; G), where G := {gini | i ∈ I}, and a homomorphic mapping with the property
ϕ : A −→ B
κ = {(a, a ) | ϕ(a) = ϕ(a )}.
We have to show that κ is compatible with all f ∈ F \ F 0 . To show this let f := fini ∈ F \F 0 be arbitrary. For the purpose of simplification, we put n := ni and g := gini . Furthermore, let (a1 , a1 ), ..., (an , an ) ∈ κ be arbitrary. Since ϕ is a homomorphism, then we have
54
4 Homomorphisms, Congruences, and Galois Connections ϕ(f (a1 , ..., an )) = g(ϕ(a1 ), ..., ϕ(an )) = g(ϕ(a1 ), ..., ϕ(an )) = ϕ(f (a1 , ..., an )).
Consequently, (f (a1 , ..., an ), f (a1 , ..., an )) ∈ κ. “⇐=”: Conversely, let the equivalence relation κ on A be compatible with all operations of the algebra A = (A; F ). We have to show: There is an algebra B = (B; G) of the same type as A and a homomorphic mapping ϕ : A −→ B with the property {(x, y) | ϕ(x) = ϕ(y)} = κ. To construct the algebra B, we define: a/κ := {x ∈ A | (x, a) ∈ κ}
(a ∈ A)
(i.e., a/κ is the notation of the equivalence class in which lies a) and B := A/κ := {a/κ | a ∈ A} (i.e., B is the set of all equivalence classes of κ). Now, we are able to define the operations gini on the set B as follows: gini (a1 /κ, ..., ani /κ) := fini (a1 , ..., ani )/κ
(4.1)
(i.e., gini (a1 /κ, ..., ani /κ) is exactly the equivalence class in which fini (a1 , ..., ani ) lies). The above definition is possible, since fi is compatible with κ. Detailed: Choosing (a1 , a1 ), ..., (ani , ani ) ∈ κ, then it holds (a1 /κ, ..., ani /κ) = (a1 /κ, ..., ani /κ) and fini (a1 , ..., ani )/κ = fini (a1 , ..., ani )/κ. We put G := {gini | i ∈ I}. Then the mapping
ϕ : A −→ B, a → a/κ
is a homomorphic mapping from A onto B := (B; G), since by definition of κ ϕ(fini (a1 , ..., ani )) = fini (a1 , ..., ani )/κ holds and (by the compatibility of κ with fini and by the definition (4.1) of gi ∈ G further fini (a1 , ..., ani )/κ = gini (a1 /κ, ..., ani /κ) = gini (ϕ(a1 ), ..., ϕ(ani )) holds, which implies ϕ(fini (a1 , ..., ani )) = gini (ϕ(a1 ), ..., ϕ(ani )). Furthermore, by definition of ϕ and by the properties of an equivalence relation, it holds: {(x, y) ∈ A × A | ϕ(x) = ϕ(y)} = {(x, y) ∈ A × A | x/κ = y/κ} = κ.
4.2 Congruence Relations and Factor Algebras of Algebras
Definitions Lemma 4.2.1,
55
The above algebra, which was designed in the proof of the (A/κ; G)
of the so-called congruence classes of A modulo κ is called factor algebra of (A; F ) (or quotient algebra). The homomorphic mapping ϕ : A −→ A/κ, a → a/κ, defined in the proof of Lemma 4.2.1, is called natural homomorphism (or quotient homomorphism) from A onto A/κ. We make following use of our agreement from the first chapter according to which the operations of algebras of the same type are described equal. Only then, if distinctions are necessary at the denotation, do we indicate the operations. After these preparations, we can prove the following theorem (in generalization of analogous theorems over groups, rings, ...): Theorem 4.2.2 (General Homomorphism Theorem) For each homomorphism ϕ from an algebra A := (A; F ) into an algebra of the same type B := (B; F ) the algebra ϕ(A) := (ϕ(A); F ) is isomorphic to the factor algebra A/κϕ := (A/κϕ ; F ), where κϕ = {(a, a ) ∈ A × A | ϕ(a) = ϕ(a )}. Proof. It suffices to check that α : ϕ(A) −→ A/κϕ , ϕ(a) → a/κϕ is an isomorphism. Since a/κϕ = a /κϕ =⇒ (a, a ) ∈ κϕ =⇒ ϕ(a) = ϕ(a ), α is a mapping. Obviously, by definition, α is a surjection. The injectivity of α follows from the following: α(ϕ(a)) = α(ϕ(a )) =⇒ a/κϕ = a /κϕ =⇒ (a, a ) ∈ κϕ =⇒ ϕ(a) = ϕ(a ) (a, a ∈ A). Thus, α is bijective. To prove that α is a homomorphism, let f n ∈ F and let ϕ(a1 ), ..., ϕ(an ) ∈ ϕ(A) be arbitrary. Then it holds:
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4 Homomorphisms, Congruences, and Galois Connections α(fϕ(A) (ϕ(a1 ), ..., ϕ(an ))) = α(ϕ(fA (a1 , ..., an )))
(since ϕ is a homomorphism)
= f (a1 , ..., an )/κϕ
(by definition of α)
= fA/κϕ (a1 /κϕ , ..., an /κϕ )
(since κϕ is compatible with f )
= fA/κϕ (α(ϕ(a1 )), ..., α(ϕ(an ))) (by definition of α), Thus our bijective mapping α is an isomorphism. The next lemma summarizes some elementary properties of congruences. The proof for this lemma is left to the reader. Lemma 4.2.3 It holds: (a) The intersection of arbitrary many congruences of an algebra A is also a congruence on A. (b) If κ is a congruence on (A; F ) and ϕ is a homomorphism defined over A with κϕ ⊆ κ, then ϕ(κ) := {(ϕ(a), ϕ(a )) | (a, a ) ∈ κ} is a congruence on (ϕ(A); F ). (c) If π is a congruence on (ϕ(A); F ) and ϕ is a homomorphism defined on (A; F ), then ϕ−1 (π) := {(a, a ) ∈ A × A | (ϕ(a), ϕ(a )) ∈ π} is a congruence on (A; F ), which κϕ includes. (d) If κ is a congruence on A = (A; F ) and B = (B; F ) is a subalgebra of A, then κ|B := {(b, b ) ∈ κ | b, b ∈ B} is a congruence on B. (e) The set ConA of all congruence relations of an algebra A is a complete lattice in respect to the inclusion ⊆ with inf{κj | j ∈ J} = j∈J κj , sup{κj | j ∈ J} =< j∈J κj >ConA , where {κj | j ∈ J} ⊆ ConA and < j∈J κj >ConA is the intersection of all congruences which contain j∈J κj .
4.3 Examples for Congruence Relations and Some Homomorphism Theorems In the following, we characterize the congruence relations by groups and rings more closely. In addition, we give the special homomorphism theorems that follow from these characterizations. 4.3.1 Congruences on Groups Let G = (G; ◦,−1 , e) be a group. A subgroup N of G is called a normal subgroup iff
4.3 Examples for Congruence Relations and Some Homomorphism Theorems
57
∀x ∈ G : x ◦ N = N ◦ x holds. Let NG be the set of all normal subgroups of G. If N is a normal subgroup of G, one also writes N G. The following connections between normal subgroups and congruences on G can easily be checked: (a) For every κ ∈ ConG, e/κ is a normal subgroup of G, and for arbitrary a, b ∈ G it holds: (a, b) ∈ κ ⇐⇒ a ◦ b−1 ∈ e/κ. (b) If N is a normal subgroup then one can obtain by κN := {(a, b) | a ◦ b−1 ∈ N } a congruence on G with e/κ = N . Consequently, the mapping α : ConG −→ NG, κ → e/κ is an order-preserving bijection. Since for every homomorphism ϕ from G into a group G the neutral element e is mapped to the neutral element of G , the properties (a), (b), and Theorem 4.2.2 imply the following Theorem 4.3.1.1 (Homomorphism Theorem for Groups) For every homomorphism ϕ from a group G into a group G there exists as so-called kernel (notation: ker ϕ) a normal subgroup K of G, which consists of all the elements of G which are mapped to the neutral element of G . The group G is isomorphic to the factor group G/K = ({x ◦ K | x ∈ G}; ◦,−1 , K)), where
(x ◦ K) ◦ (y ◦ K) := (x ◦ y) ◦ K
for arbitrary x, y ∈ G. Conversely, if K is a normal subgroup of G, then K is the kernel of the natural homomorphism from G onto the factor group G/K (∀x ∈ G : x → x ◦ K). We notice that the concept kernel of a group homomorphism differs from the general term kernel of a homomorphism. The corresponding is valid for the concept kernel from Theorem 4.3.2.1.
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4 Homomorphisms, Congruences, and Galois Connections
4.3.2 Congruences on Rings Let R = (R; +, −, 0, ·) be a ring. A subgroup I of (R; +, −, 0) is called an ideal of R iff ∀x ∈ R : x · I ⊆ I ∧ I · x ⊆ I holds. Let IR be the set of all ideals of R. Connections between congruences on R and ideals of R are the following: For every κ ∈ ConR, 0/κ is an ideal of R and we have for arbitrary a, b ∈ R: (a, b) ∈ κ ⇐⇒ a − b ∈ 0/κ. If I is an ideal of R then one can obtain by κI := {(a, b) | a − b ∈ I} a congruence on R with 0/κI = I. Consequently, the mapping ConR −→ IR, κ → 0/κ is an order-preserving bijection. Further it holds: Theorem 4.3.2.1 (Homomorphism Theorem for Rings) For every homomorphism ϕ from a ring R into a ring R belongs as a kernel (notation: ker ϕ) an ideal I of R, which consists of all the elements of R which are mapped to the zero element of R . The ring R is isomorphic to the residue class ring R/I = ({x + I | x ∈ R}; +, −, I, ·), where (x + I) + (y + I) := (x + y) + I and (x + I) · (y + I) := (x · y) + I for arbitrary x, y ∈ R. Conversely, if I is an ideal of R then I is the kernel of the natural homomorphism from R onto R/I (∀x ∈ R : x → x + I). It is obvious idea, according to a homomorphism theorem for rings, to find also a homomorphism theorem for fields. The next theorem shows, however, that such a theorem is only a trivial and special case of the general homomorphism theorem. Theorem 4.3.2.2 A ring R, which is also a field, has only the two trivial ideals {0} and R. In other words: A field has only the trivial congruences κ0 and κ1 . Proof. Let R be a field and let κ be a congruence of R, which is different from
κ0 . Denote I the ideal belonging to κ. Since κ = κ0 , there is certain a, b ∈ R with a = b and (a, b) ∈ κ. Consequently, we have (c, 0) := (a − b, b − b) ∈ κ. Hence, I contains the invertable element c. Since I also contains all elements r · c for every r ∈ R (specially, r = r · c−1 with arbitrary r ∈ R) we have I = R. Thus, κ = κ1 .
4.4 Galois Connections
59
4.4 Galois Connections Definitions A Galois connection (or a Galois correspondence) between the sets A and B is a pair (σ, τ ) of mappings σ : P(A) −→ P(B) and
τ : P(B) −→ P(A),
such that for all X, X ⊆ A and all Y, Y ⊆ B the following conditions are fulfilled:
X ⊆ X =⇒ σ(X) ⊇ σ(X ) (antitony) (GC1) Y ⊆ Y =⇒ τ (Y ) ⊇ τ (Y ) X ⊆ τ (σ((X))) (GC2) (extensivity). Y ⊆ σ(τ ((Y ))) Let (P ; ≤) be a poset. The dual order ≤δ to the order ≤ is defined by x ≤δ y :⇐⇒ y ≤ x. (P ; ≤) is called dual isomorphic (or antiisomorphic) to (Q; ≤), iff (P ; ≤) is isomorphic to (Q; ≤δ ). The bijective mapping appertaining to this fact is called dual isomorphism (or antiisomorphism) . Theorem 4.4.1 Let the pair (σ, τ ) of mappings σ: P(A) −→ P(B) and τ : P(B) −→ P(A) be a Galois connection between A and B. Then it holds: (a) The mappings and
στ := στ : P(A) −→ P(A) τ σ := τ σ : P(B) −→ P(B)
are hull operators on A or B, respectively. (b) The στ -closed sets are exactly the sets of the form τ (Y ), Y ⊆ B. The τ σ-closed sets are exactly the sets of the form σ(X), X ⊆ A. (c) Let Hστ and Hτ σ be the hull systems that are assigned to στ and τ σ, respectively. Then the lattices (Hστ ; ⊆) and (Hτ σ ; ⊆) are dual isomorphic, and σ and τ are inversely dual isomorphisms to each other of these lattices. Proof. (a): The extensivity and the monotony of στ and τ σ immediately follow from (GC1) and (GC2), respectively. Thus, for all X ⊆ A we have X ⊆ τ (σ(X)) and therefore σ(X) ⊇ σ(τ (σ(X))). On the other hand, σ(X) ⊆ (τ σ)(σ(X)) = σ(τ (σ(X))) follows from (GC2). Consequently, we have
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4 Homomorphisms, Congruences, and Galois Connections
and analogously Then the equations and
σ(X) = σ(τ (σ(X)))
(4.2)
τ (Y ) = τ (σ(τ (Y ))).
(4.3)
τ (σ(X)) = τ (σ(τ (σ(X)))) σ(τ (Y )) = σ(τ (σ(τ (Y ))))
follow from these. Thus, στ and τ σ are idempotent. (b): For a στ -closed set X we have X = τ (σ(X)); that is, X has the form X = τ (Y ) with Y := σ(X) ⊆ B. Conversely, a set of the form X := τ (Y ), Y ⊆ B, is στ -closed by (4.3). Analogously, one can prove the assertion for τ σ-closed sets. (c): Because of (b) and Theorem 3.2.1 it holds Hστ = {τ (Y ) | Y ⊆ B} and Hτ σ = {σ(X) | X ⊆ A}. Thus, we have σ(Hστ ) := {σ(τ (Y )) | Y ⊆ B} = Hτ σ and τ (Hτ σ ) := {τ (σ(X)) | X ⊆ A} = Hστ . By (GC1) σ and τ are antitone, and therefore the restrictions of these mappings to Hστ and Hτ σ have also this property. It follows from the idempotence of στ that στ on Hστ is the identical mapping. Analogously, one can see that τ σ is also the identical mapping on Hτ σ . Therefore, the mappings σ : Hστ −→ Hτ σ and τ : Hτ σ −→ Hστ are bijective mappings and it holds σ −1 = τ . Consequently, σ, τ are isomorphisms of the lattices (Hστ ; ⊆) and (Hτ σ ; ⊆δ )
An example of a Galois connection concludes this section. Further examples can be found in [Den-E-W 2004]. Theorem 4.4.2 Let A, B be nonempty sets and let R ⊆ A × B with R = ∅. The mappings σ : P(A) −→ P(B), τ : P(B) −→ P(A) are defined by σ(X) := {y ∈ B | ∀x ∈ X : (x, y) ∈ R}, τ (Y ) := {x ∈ A | ∀y ∈ Y : (x, y) ∈ R}. Then the pair (σ, τ ) is a Galois connection between A and B. Proof. Because of symmetry of the assumptions, it suffices to show that σ is an antitone and τ σ is an extensive mapping. Let X ⊆ X ⊆ A. Then for every y ∈ σ(X ) we have: (x, y) ∈ R for all x ∈ X . Thus (by X ⊆ X ) we have also (x, y) ∈ R for all x ∈ X. Therefore σ(X ) ⊆ σ(X) holds. The inclusion X ⊆ τ (σ(X)) follows directly from τ (σ(X)) = {x ∈ A | ∀y ∈ σ(X) : (x, y) ∈ R} and from the definition of σ(X).
5 Direct and Subdirect Products
With the help of direct and subdirect products, it is possible to form new algebras with larger universes from given algebras. Of these constructions one immediately asks the following questions: Which algebras are smallest “constituents” of given algebras? How can one reduce a given algebra to its smallest “constituents”? First, we will show that every finite algebra is isomorphic to a direct product of directly irreducible algebras. Then, we prove that every algebra is isomorphic to a subdirect product of subdirectly irreducible algebras.
5.1 Direct Products First, we consider direct products of two algebras. Definitions Let B = (B; F ) and C = (C; F ) be algebras of the same type τ. The algebra A := B × C of type τ is called direct product of the algebras B and C, iff B × C is the universe of the algebra A and the operations of A are defined as follows: If f ∈ F is nullary, then let fA := (fB , fC ). If af ≥ 1, let fA defined as follows: fB×C ((b1 , c1 ), (b2 , c2 ), ..., (baf , caf )) := (fB (b1 , ..., baf ), fC (c1 , ..., caf )). Obviously, B and C are homomorphic images of the algebra B × C, since the (so-called projection-)mappings pr1 : B × C −→ B, (b, c) → pr1 (b, c) := b and pr2 : B × C −→ C, (b, c) → pr2 (b, c) := c are homomorphisms from B × C onto B or C, respectively. The kernels of these projection mappings (congruences on B × C)
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Ker pri := {((b, c), (b , c )) ∈ (B × C)2 | pri (b, c) = pri (b , c )} (i = 1, 2) are distinguished from other congruences by certain properties (see Theorem 5.1.2). We can describe these properties with the help of the following Definition Two equivalence relations κ, µ ∈ Eq(A) are called permutable, if κµ = µκ holds; i.e., ∀x, z ∈ A : (∃y ∈ A : (x, y) ∈ κ ∧ (y, z) ∈ µ) ⇐⇒ (∃y ∈ A : (x, y ) ∈ µ ∧ (y , z) ∈ κ). The following lemma gives some other definition possibilities for the above concept. In this lemma and in the following theorems, (Eq; ⊆), by Theorem 2.4.3, is a complete lattice and operations ∧ = ∩ (“infimum”) and ∨ (“supremum”) are defined on Eq (see Chapter 2). Lemma 5.1.1 For κ, µ ∈ Eq(A) the following statements are equivalent: (a) (b) (c) (d) (e)
κ and µ are permutable κµ ⊆ µκ µκ ⊆ κµ κ ∨ µ = κµ µ ∨ κ = κµ
Proof. Because of the commutativity of ∨, we have (d)⇐⇒(e). The equivalence (b)⇐⇒(c) is a conclusion from (a)⇐⇒(b). Thus, we have to show that (a)⇐⇒(b) and (a)⇐⇒(e) holds. (a)=⇒(b) is trivial. (b)=⇒(a): Let κµ ⊆ µκ. Then (by (κµ)−1 = µ−1 κ−1 and by the symmetry of κ and µ): (κµ)−1 ⊆ (µκ)−1 =⇒ µ−1 κ−1 ⊆ κ−1 µ−1 . =µκ
=κµ
Hence, κµ = µκ. (a)=⇒(e): Let κµ = µκ. (e) is shown, if it is proven that κµ is the smallest equivalence relation on A, which contains κ ∪ µ. Because of ∀(x, y) ∈ κ (( (x, y) ∈ κ ∧ (y, y) ∈ µ) =⇒ (x, y) ∈ κµ), ∀(x, y) ∈ µ (( (x, x) ∈ κ ∧ (x, y) ∈ µ) =⇒ (x, y) ∈ κµ) we have κ ∪ µ ⊆ κµ. κµ is reflexive, since κ (or µ) is reflexive. The symmetry of κµ follows from (κµ)−1 = µ−1 κ−1 = µκ = κµ. Because of (κµ)(κµ) = κ (µκ) µ = (κκ) (µµ) ⊆ κµ =κµ
⊆κ
⊆µ
κµ is also transitive. Thus, κµ is an equivalence relation on A. κµ is the smallest equivalence relation of Eq(A), which contains κ ∪ µ, since every
5.1 Direct Products
63
other equivalence relation, which contains κ ∪ µ, also contains the transitive closure of κ ∪ µ and therefore contains κµ. (e)=⇒(a): Let κ ∨ µ = κµ. Since κ ∨ µ is an equivalence relation, the compatibility of κ and µ follows from κµ = κ ∨ µ = (κµ)−1 = µ−1 κ−1 = µκ.
Theorem 5.1.2 For algebras B and C of the same type and the projection mappings pr1 : B × C −→ B and pr2 : B × C −→ C it holds: (a) Ker pr1 ∧ Ker pr2 = κ0 (b) Ker pr1 ∨ Ker pr2 = κ1 (c) Ker pr1 and Ker pr2 are permutable Proof. Let ((b, c), (b , c )) ∈ Ker pr1 ∩ Ker pr2 be arbitrary. Then, pri (b, c) =
pri (b , c ) for i = 1, 2. This means, however, that b = b and c = c . Therefore, (a) is shown. For arbitrary b, b ∈ B, c, c ∈ C we have ( (b, c), (b, c ) ) ∈ Ker pr1 ∧ ( (b, c ), (b , c ) ) ∈ Ker pr1 . Hence, ( (b, c), (b , c ) ) ∈ κµ for all b, b ∈ B and c, c ∈ C and thus (Ker pr1 )(Ker pr2 ) = κ1 . With the help of Lemma 5.1.1, the assertions (b) and (c) follow from this.
Now we will examine the conditions under which an algebra is a direct product of two other smaller algebras. Theorem 5.1.2 provides instructions on how to proceed. Theorem 5.1.3 Let A = (A; F ) be an algebra and let κ, µ ∈ ConA be two congruence relations with the following three properties: (a) κ ∧ µ = κ0 (b) κ ∨ µ = κ1 (c) κ and µ are permutable Then A is isomorphic to the direct product of A/κ and A/µ. An isomorphism ϕ: A −→ A/κ × A/µ is defined by ∀a ∈ A : ϕ(a) := (a/κ, a/µ). Proof. ϕ is injective: Let ϕ(a) = ϕ(b). Then, a/κ = b/κ and a/µ = b/µ. From these (a, b) ∈ κ ∧ µ follows. Thus a = b by (a). ϕ is surjective: By (b) and (c) for every pair a, b there is a c ∈ A with (a, c) ∈ κ and (c, b) ∈ µ. Consequently, (a/κ, b/µ) = (c/κ, c/µ) = ϕ(c). ϕ is an isomorphism: For all fA ∈ F (afA =: n) and arbitrary a1 , ..., an ∈ A it holds ϕ(fA (a1 , ..., an )) = (fA (a1 , ..., an )/κ, fA (a1 , .., an )/µ) = (fA/κ (a1 /κ, ..., an /κ), fA/µ (a1 /µ, ..., an /µ)) = fA/κ×A/µ (ϕ(a1 ), ..., ϕ(an )).
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Definition An algebra A is called directly irreducible, iff A ∼ = B×C implies |B| = 1 or |C| = 1 for all algebras B and C. Example Obviously, every finite algebra A with |A| ∈ P is directly irreducible. One finds further examples after Theorem 5.1.4. Theorem 5.1.4 An algebra A is directly irreducible iff κ0 and κ1 are the only one pair of congruences of ConA, which satisfy the conditions (a)–(c) of Theorem 5.1.3. Proof. Let A be directly irreducible. Further, κ, µ ∈ ConA fulfill the conditions (a)–(c) of Theorem 5.1.3. Then, by Theorem 5.1.3, we have A ∼ = A/κ × A/µ. Thus, w.l.o.g., |A/κ| = 1. From this, κ = κ1 follows, and then µ = κ0 by (a). Conversely, Let κ0 and κ1 be the only one pair of congruences of A with the properties (a)–(c) of Theorem 5.1.3, and let A ∼ = B × C. Obviously, then κ0 and κ1 are the only one pair of congruence relations on B × C with (a)–(c). By Theorem 5.1.2 the kernels of the projection mappings pr1 and pr2 fulfill (a)–(c). Thus Ker pr1 = κ0 or Ker pr2 = κ0 holds and we have |C| = 1 or |B| = 1, respectively.
With the help of Theorem 5.1.4, one can prove the following statements:1 (a) Every simple algebra A; i.e., every algebra A with Con A = {κ0 , κ1 }, is directly irreducible. (b) If A is a Boolean algebra then A is directly irreducible ⇐⇒ |A| ≤ 2. (c) The residue class group (Zn ; +, −, 0) is directly irreducible iff n is a prime number power. (d) A vector space V := (V ; +, −, K, 0) over the field K is directly irreducible iff |V | = 1 or V is 1-dimensional. One can generalize our definition of the direct product of two algebras in an obvious way for finite many algebras of the same type. As the next definitions demonstrate, it is also possible to form direct products of arbitrarily many algebras of the same type. Definitions The Cartesian product Πj∈J Aj of the sets Aj (j ∈ J) is the set of all mappings α from J into j∈J Aj with α(j) ∈ Aj for all j ∈ J. We write down the elements of Πj∈J Aj in the form (xj | j ∈ J). In analog mode too, one can define then the algebra (Πj∈J Aj ; (fi )i∈I ) as a direct product Πj∈J Aj of the algebras Aj (j ∈ J), where 1
The proof for the statements can be found in [Lau 2004], volume 2.
5.1 Direct Products
65
fi ((aj1 |j ∈ J), (aj2 |j ∈ J), ..., (aj,afi |j ∈ J)) := (fji (aj1 , aj2 , ..., aj,afi )|j ∈ J) for arbitrary ((aj1 |j ∈ J), ..., (aj,afi |j ∈ J) ∈ Πj∈J Aj , if afi > 0, and fi = (fji |j ∈ J), if afi = 0. If J = ∅, then let Πj∈J Aj be the 1-element algebra of the corresponding type. If Aj = A for all j ∈ J, we write AJ instead of Πj∈J Aj . If J = {1, 2, .., n}, one also uses the denotation A1 × ... × An for the direct product of the algebras Aj . Theorem 5.1.5 Every finite algebra is isomorphic to a direct product of direct irreducible algebras. Proof. Induction over the cardinality of the universes of the algebras:
Obviously, every algebra A with |A| = 1 is directly irreducible. Now, let A be a finite algebra with |A| ≥ 2, and assume that the assertion is proven for all algebras A with |A | < |A|. If A is directly irreducible, we have to show nothing more. If, however, A ∼ = B × C with |B| > 1, |C| > 1 is valid, then we have |B| < |A| and |C| < |A|; i.e., one can find direct irreducible algebras B1 , ..., Bm , C1 , ..., Cn with B∼ = B1 × ... × Bm , C∼ = C1 × ... × Cn .
Thus A ∼ = B1 × ... × Bm × C1 × ... × Cn .
The direct products of more than two algebras have similar properties, like the direct products of only two algebras. For example, the j0 -th projection prj0 from Πj∈J Aj onto Aj with (aj | j ∈ J) → aj0 is a homomorphism for every j0 ∈ J. One can easily check the following property of direct products. Theorem 5.1.6 For every family2 ϕi : B −→ Ai , i ∈ I, of homomorphisms one can form a homomorphism ϕ: B −→ Πi∈I Ai by (ϕ(b))i := ϕi (b).
2
A family (ai | i ∈ I) of elements of a set A is a mapping ϕ : I → A, i → ai . This denotation is used around a certain selection of (not necessarily different) elements from A to characterize. Then, I is called index set of the family (ai | i ∈ I).
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5.2 Subdirect Products Unlike finite algebras, infinite algebras cannot always be represented by direct products of directly irreducible algebras. Example As we already noticed above, a Boolean algebra A is directly irreducible iff |A| ≤ 2. Furthermore, one can easily prove that every 2-element Boolean algebra is isomorphic to the algebra B = ({0, 1}; ∨, ∧,− , 0, 1). An infinite direct product of B is not countable. Consequently, the countable Boolean algebra C = (C; ∨ , ∧ , ¬) with C := {(a1 , a2 , ...) ∈ {0, 1}N | |{i ∈ N | ai = 0}| < ℵ0 or |{i ∈ N | ai = 1}| < ℵ0 }, (a1 , a2 , ...) ◦ (b1 , b2 , ...) := (a1 ◦ b1 , a2 ◦ b2 , ...) for ◦ ∈ {∨, ∧} and ¬(a1 , a2 , ...) := (a1 , a2 , ...) is not isomorphic to a direct product of directly irreducible algebras, however, it is a subalgebra of the direct product BN . In generalizing this example, we get the following new product concept: Definition Let the algebras Ai , i ∈ I, be of the same type. A subalgebra B of Πi∈I Ai is called a subdirect product of the Ai iff prj (B) = Aj holds for all j ∈ I. Example
Obviously, every direct product is also a subdirect product.
Theorem 5.2.1 For a subdirect product B of the algebras Ai , i ∈ I, and the projection mappings prj : Πi∈I Ai −→ Aj it holds Ker(prj )|B = κ0 . j∈I
Proof. a = b.
If (a, b) ∈
j∈I
Ker(prj )|B , then aj = bj follows for all j ∈ I and therefore
By the above theorem and by the fact that all prj|B are surjective, the subdirect products are already characterized: Theorem 5.2.2 Let A be an algebra. For certain congruences κi ∈ ConA, i ∈ I, let κi = κ0 . i∈I
Then A is isomorphic to a subdirect product of the algebras A/κi , i ∈ I. By ϕ(a) := (a/κi | i ∈ I) an injective homomorphism ϕ: A −→ Πi∈I (A/κi ) is defined, and ϕ(A) is a subdirect product of the algebras A/κi .
5.2 Subdirect Products
67
Proof. By Theorem 5.1.6 ϕ is a homomorphism. ϕ is also injective: Let ϕ(a) = ϕ(b). This implies a/κi = b/κi and thus (a, b) ∈ κi for all i ∈ I. Therefore, (a, b) ∈ κ i∈I i = κ0 ; i.e., a = b. Consequently, A and ϕ(A) are isomorphic. Further, by definition of ϕ we have prj (ϕ(A)) = A/κj for all j ∈ I. Hence, ϕ(A) is a subdirect product of the algebras A/κi . Definition An injective homomorphism (a so-called embedding) ϕ: A −→ Πi∈I Ai is called a subdirect representation of A, if ϕ(A) is a subdirect product of the algebras Ai . Example The mapping ϕ of Theorem 5.2.2 is a subdirect representation. Definition An algebra A is called subdirectly irreducible, if for every subdirect representation ϕ : A −→ Πi∈I Ai there exists a j ∈ I such that the mapping ϕprj : A −→ Aj is an isomorphism. Thus, an algebra is subdirectly irreducible if and only if one gets by with a single component in every subdirect representation. Theorem 5.2.3 An algebra A is subdirectly irreducible, if and only if the universe of A contains at most an element, or if (ConA\{κ0 }) = κ0 holds. The latter holds obviously iff κ0 exactly has an upper neighbor in ConA: ConA :
κ1
(ConA\{κ0 })
κ0 Proof. W.l.o.g. let |A| ∈ {0, 1} in the following. Suppose, (ConA\{κ0 }) = κ0 . Put I := ConA\{κ0 }. Then, with the help of Theorem 5.2.2, one obtains a subdirect representation ϕ: A −→ Πκ∈I (A/κ). For every mapping prκ (κ ∈ I) and all a ∈ A it holds (ϕprκ )(a) = a/κ. By κ0 ∈ I, therefore ϕprκ : A −→ A/κ is not injective (i.e., is not an isomorphism). Thus, A is not subdirectly irreducible. Let now µ := (ConA\{κ0 }) = κ0 ; i.e., there exists (a, b) ∈ µ \ κ0 , and denote ϕ: A −→ Πi∈I Ai a subdirect representation of A. We have to show that there exists an
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i ∈ I so that ϕpri is an isomorphism from A onto Ai . Since ϕ is injective and a = b, there exists a j ∈ I with prj (ϕ(a)) = prj (ϕ(b)), whereby (a, b) ∈ Ker(ϕprj ). Thus, by (a, b) ∈ µ, we have µ ⊆ Ker(ϕprj ). Then, by definition of µ, Ker(ϕprj ) = κ0 holds; i.e., ϕprj is injective. Since ϕ(A) is a subdirect product, ϕprj is surjective. Therefore, ϕprj is an isomorphism. Consequently, A is subdirectly irreducible. With the help of Theorems 5.2.3 and 5.1.4, one can easily prove the following connection between the direct and the subdirectly irreducible algebras: A is subdirectly irreducible =⇒ A is directly irreducible.
(5.1)
The reversal of the statement (5.1) is not valid, because one can prove with the help of a 3-element lattice which is directly irreducible but which is not subdirectly irreducible. An essential aid for proving the following Theorem is Zorn’s Lemma which is indicated without proof here. This lemma is equivalent to the axiom of choice (see e.g. [Her 55]). Lemma 5.2.4 (Zorn’s Lemma) In every set system M with the property ∀T ⊆ M ((∀X, Y ∈ T ∃Z ∈ T : X ∪ Y ⊆ Z) =⇒
X ∈ M)
X∈T
(i.e., M is an inductively set system) there is a maximal element3 ; i.e., an element M ∈ M that is not contained in any proper subset of M. After these preparations we can prove the following theorem, published by G. Birkhoff in 1944. Theorem 5.2.5 Every algebra is isomorphic to a subdirect product of subdirectly irreducible algebras. Proof. Let A be an algebra. One can easily see that, for every pair a, b ∈ A with a = b, the set Ma,b := {κ ∈ ConA | (a, b) ∈ κ} is an inductive set system. By Lemma 5.2.4 Ma,b has a maximal element Φ(a, b). In the lattice ConA the element Φ(a, b) has exactly an upper neighbor, namely Φ(a, b) ∨ Ω(a, b), where Ω(a, b) is the congruence relation generated by (a, b). It is easy to check that the factor algebra A/Φ(a, b) is isomorphic to an interval [Φ(a, b), κ1 ] := {κ ∈ ConA | Φ(a, b) ⊆ κ ⊆ κ1 } 3
Let (B; ≤) be a poset. A maximal element of the set A ⊆ B is then an element a ∈ A with a < x =⇒ x ∈ A for all x ∈ B.
5.2 Subdirect Products
69
of ConA. By Theorem 5.2.3 the algebra A/Φ(a, b) is subdirectly irreducible. From {Φ(a, b) | a, b ∈ A ∧ a = b} = κ0 and from Theorem 5.2.2, it follows that A is isomorphic to a subdirect product of subdirectly irreducible algebras (namely of the algebras A/Φ(a, b)).
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6 Varieties, Equational Classes, and Free Algebras
In this Chapter, only certain classes1 of algebras of the same type shall be regarded. First we introduce so-called varieties as classes of algebras, which are closed in respect to formation of subalgebras, homomorphic images, and direct products. We then come to a method for constructing algebra classes that strongly differs from the first method at first sight: Starting from certain equations from variables and operation symbols of a certain type τ , we form the class of all algebras of type τ that fulfill these equations. The result is an equational class. We will see, however, that there is a close connection between the two methods of algebra class construction: A class of algebras is equationally definable if and only if it is a variety. Free algebras are “the most general” algebras within a variety or an equational class (or an equationally definable class). In the section on equational classes, we will also address such concepts such as conclusion of an equational set. In addition, we investigate methods to receive such conclusions.
6.1 Varieties The following operators S, H, P , I map a class K of algebras of type τ to a class of algebras of the same type. Let S(K) be the class of all subalgebras of algebras aus K, H(K) be the class of all homomorphic images of algebras of K, P (K) be the class of all direct products of families of algebras of K, I(K) be the class of all algebras which are isomorphic to algebras of K. 1
The concept “class” is a generalization of the concept “set”. Informally speaking, a class is a collection so large that subjecting it to the operations admissible for sets would lead to logical contradictions.
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6 Varieties, Equational Classes, and Free Algebras
We denote the composition of the operators Y, X ∈ {H, S, P, I} by XY ; i.e., it holds XY (K) := X(Y (K)). It is easy to check that S, H and IP are hull operators; i.e., for all classes K and L of algebras of the same type we have: ∀X ∈ {S, H, IP } : K ⊆ X(K) ∧ (K ⊆ L =⇒ X(K) ⊆ X(L)) ∧ X(K) = X(X(K)). The operator P is not idempotent: For all A, B, C ∈ K it holds (A×B)×C ∈ P (P (K)), but (A×B)×C ∈ P (K) generally does not hold. However, (A × B) × C ∼ = A × B × C ∈ P (K) is right; i.e., (A × B) × C ∈ IP (K). Definitions • A class K of algebras of the same type is called under X ∈ {S, H, P } closed, if X(K) ⊆ K holds. • If the class K of algebras of the same type is closed under the three operators S, H and P , then the class K is called a variety. Examples (1) It is easy to see that the class of all groups is a variety. (2) Since the direct product of the field Z2 with the field Z2 because of ∀x, y ∈ Z2 : (0, 1) · (x, y) = (0 · x, 1 · y) = (0, y) = (1, 1) is not a field, the class of all fields is not a variety. Lemma 6.1.1 For every class K of algebras of the same type it holds: (a) SH(K) ⊆ HS(K), (b) P S(K) ⊆ SP (K), (c) P H(K) ⊆ HP (K). Proof. (a): Let A ∈ SH(K); i.e., there is an algebra B ∈ H(K) with A ≤ B and B is homomorphic image of an algebra C ∈ K. Let ϕ: C −→ B be a surjective homomorphism. Then, for the subalgebra ϕ−1 (A) of C it holds ϕ(ϕ−1 (A)) = A. Consequently, we have A ∈ HS(K). (b): Let A ∈ P S(K). Then it holds A = Πi∈I Bi with Bi ≤ Ci ∈ K for all i ∈ I. Since obviously Πi∈I Bi is a subalgebra of Πi∈I Ci , we have A ∈ SP (K). (c): Let A ∈ P H(K). Then, A = Πi∈I Bi , where for every i ∈ I there are an algebra Ci and a surjective homomorphism ϕi : Ci −→ Bi . If prj : Πi∈I Ci −→ Cj is the projection mapping, then prj ϕj : Πi∈I Ci −→ Bj is a surjective homomorphism. By Theorem 5.1.6 we get by ϕ(c)j := (prj ϕj )(c) a homomorphism ϕ: Πi∈I Ci −→ Πi∈I Bi , which is also surjective. Consequently, we have A ∈ HP (K).
Theorem 6.1.2 A class K of algebras of the same type is a variety if and only if HSP (K) = K holds.
6.2 Terms, Term Algebras, and Term Functions
73
Proof. If K is a variety, then obviously HSP (K) = K.
Let now HSP (K) = K. We have to show H(K) ⊆ K, S(K) ⊆ K and P (K) ⊆ K. It holds: H(K) = H(HSP (K)) = HSP (K), since H is idempotent. Thus,
H(K) = K
by assumption. Further we have: S(K) = S(HSP (K)) = SH(SP (K)) ⊆ HS(SP (K)) ⊆ HSP (K) by Lemma 6.1.1, (a) and since S is idempotent. Therefore, S(K) ⊆ K holds. Furthermore, P (K) = P HSP (K) ⊆ HP SP (K) ⊆ HSP P (K) ⊆ HSIP IP (K) = HSIP (K) ⊆ HSHP (K) ⊆ HHSP (K) = HSP (K) by Lemma 6.1.1 and since the operators IP and H are idempotent. Thus, P (K) ⊆ K holds. Consequently, K is a variety.
Every variety is exactly determined by its elements, which are subdirect irreducible algebras: Theorem 6.1.3 Every algebra of a variety K is isomorphic to a subdirect product of subdirect irreducible algebras of K. Proof. By Theorem 5.2.5, every algebra A is isomorphic to a subdirect product of
subdirect irreducible algebras Ai , where every Ai is isomorphic to a factor algebra of A; i.e., it holds Ai ∈ H(A). If A belongs to a variety K, then Ai ∈ H(K) ⊆ K.
6.2 Terms, Term Algebras, and Term Functions In Section 1.1, we had agreed to describe the operations of algebras of the same type by the same notations, if it is clearly from the context to which algebra a given operation belongs. Since we will often make use of this convention, we generalize the concept “type of an algebra” as follows: Definitions A type of algebras is an ordered pair (F, τ ), where F is a set, whose elements are called operation symbols, and τ : F −→ N0 is a mapping, which assigns the arity af to every operation f ∈ F. Then, the algebra A = (A; F ) with F := {fA | f ∈ F} is called algebra of type (F, τ ). Let Fn be the set of the n-ary operation symbols of F . Now let (F, τ ) be a type of algebras and let X
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be a finite or countable infinite set, whose elements are called variables, where X ∩ F0 = ∅. T (X) denotes the smallest set with the following two properties: (1) X ∪ F0 ⊆ T (X), (2) (f ∈ Fn ∧ {t1 , ..., tn } ⊆ T (X)) =⇒ f (t1 , ..., tn ) ∈ T (X). One observes that f (t1 , ..., tn ) is a syntactic expression (a symbol sequence) and not a function value. The elements of T (X) are called terms of type (F, τ ) over the alphabet X. Example Let F := {e, f }, τ (e) := 0, τ (f ) := 2 and X := {x, y, z}. Then T (X) = {e, x, y, z, f (e, e), f (e, x), ..., f (z, y), f (f (e, e), e), f (f (x, e), e), ..., f (f (x, z), f (z, y)), ........}. We agree that (u ◦ v) := f (u, v) for arbitrary u, v ∈ T (X) and, furthermore, we do without outer brackets. Then the set T (X) can be also written down as follows: {e, x, y, z, e ◦ e, e ◦ x, ..., z ◦ y, (e ◦ e) ◦ e, (x ◦ e) ◦ e, ..., (x ◦ z) ◦ (z ◦ y), ...}. T (X) is the universe of the so-called term algebra T(X) := (T (X); F ) of type (F, τ ), where for every f ∈ Fn (n ∈ N ∪ {0}) the operations of this algebra are defined as follows: fT(X) := f, if n = 0, and ∀t1 , ..., tn ∈ T (X) : fT(X) (t1 , ..., tn ) := f (t1 , ..., tn ) for n ≥ 1. A part of the operation table of the operation fT(X) from the above example then looks as follows: u e e x ◦ (y ◦ e)
v e e◦x (x ◦ x) ◦ z
fT(X) (u, v) e◦e e ◦ (e ◦ x) (x ◦ (y ◦ e)) ◦ ((x ◦ x) ◦ z)
The following lemma follows directly from the definition of T(X):
6.2 Terms, Term Algebras, and Term Functions
75
Lemma 6.2.1 The term algebra T(X) is generated by X; i.e., it holds [X] = T (X). The following theorem gives an important property of the algebra T(X): Theorem 6.2.2 Let T(X) be the term algebra of type (F, τ ) over X. Then, for every algebra A of type (F, τ ) and for every mapping ϕ: X −→ A there is exactly one homomorphism ϕ : T(X) −→ A, which ϕ continues, i.e., for which ϕ| X = ϕ holds. Proof. For a given algebra A of type (F, τ ) and for a given mapping ϕ: X −→ A let ϕ: T (X) −→ A be a mapping with the properties: ∀x ∈ X : ϕ(x) := ϕ(x) and
∀f (t1 , ..., tn ) ∈ T (X)\X : ϕ(f (t1 , ...tn )) := fA (ϕ(t 1 ), ..., ϕ(t n )).
Obviously, ϕ is defined over T (X) by the above conditions, and it is the only possible continuation of ϕ over T (X).
Using the concepts from Part II, Chapter 1, we can briefly define the following Definition The term functions of an algebra A = (A; F ) of type (F, τ ) are operations over A that can be formed by superposition from the fundamental operations of F and from the projections. Without using concepts from Part II, Chapter 1, we can define the term functions an algebra A of type (F, τ ) as follows: Let t be a term of type (F, τ ) over X = {x1 , ..., xn }, and for a1 , ..., an ∈ A let ϕa1 ,...,an : T(X) −→ A be the unique homomorphism with xi → ai , i = 1, 2, ..., n. Then we can define an n-ary operation tA : An −→ A by
∀a1 , ..., an ∈ A : tA (a1 , ..., an ) := ϕa1 ,...,an (t).
These operations are identical with the term functions already defined above. If t and TA are defined as above, we say that the term t induces the term function tA . Let T F (A) be the set of all term functions of A. One can prove the next two lemmas with properties of T F (A) easily. Lemma 6.2.3 Let [..] be the subalgebra-hull-operator (see Chapter 3). Then for every algebra A and every subset B of A it holds: [B] = {tA (b1 , ..., bn ) | n ∈ N ∧ t ∈ T ({x1 , ..., xn }) ∧ {b1 , ..., bn } ⊆ B}.
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Lemma 6.2.4 The algebras A, B and the n-ary term t have the same type. Then, for every homomorphism ϕ: A −→ B and all a1 , ..., an ∈ A it holds: ϕ(tA (a1 , ..., an )) = tB (ϕ(a1 ), ..., ϕ(an )); i.e., the term functions react just like the fundamental operations in respect to homomorphisms.
6.3 Equations and Equational Classes In this section, let T (X) be the set of all terms of type (F, τ ). To show that the variables of the term t ∈ T (X) are of the set {x1 , ..., xn } ⊆ X, we write t < x1 , ..., xn > and set
t = t < x1 , ..., xn > .
The notation
s := t < t1 , ..., tn >
meant that the term s was formed from the term t by substituting every variable xi (1 ≤ i ≤ n) by ti in every place the variable xi in t appeared. We agree on an analogous notation for term functions. Definitions • The elements of T (X) × T (X) are called equations (or identities) over X and we write s ≈ t :⇐⇒ (s, t) ∈ T (X) × T (X). • An algebra A of type (F, τ ) fulfills the equation s < x1 , ..., xn >≈ t < x1 , ..., xn > (or the equation s ≈ t holds in A), if for all a1 , ..., an ∈ A sA < a1 , ..., an >= tA < a1 , ..., an > is right. In this case, we also write A |= s ≈ t. Further, we set IdX (A) := {(s, t) ∈ T (X) × T (X) | A |= s ≈ t}.
6.3 Equations and Equational Classes
77
• Let be for Σ ⊆ T (X) × T (X) and classes K of algebras of the same type (F, τ ): A |= Σ :⇐⇒ (∀s ≈ t ∈ Σ : A |= s ≈ t). • The class
M od(Σ) := {A | A |= Σ}
is called the set of all models of Σ. • Conversely, for every class K of algebras of type (F, τ ) let IdX (K) := {(s, t) ∈ T (X) × T (X) | ∀A ∈ K : A |= s ≈ t} be the class of all equations over X that hold in all algebras of K. • A class K of algebras is equationally definable, if there exists a Σ ⊆ T (X) × T (X) with M od(Σ) = K. • A set Σ ⊆ T (X) × T (X) is called equational theory over X, if there is a class K of algebras with Σ = IdX (K). • An equation s ≈ t is called a conclusion of Σ ⊆ T (X) × T (X), if A |= s ≈ t holds for all A ∈ M od(Σ). Let ConsX (Σ) be the set of all conclusions of Σ; i.e., it holds ConsX (Σ) := IdX (M od(Σ)). Instead of Y (Z(..)), where Y, Z ∈ {M od, IdX , ConsX }, we write briefly Y Z(..). The following theorem summarizes elementary properties of the sets defined above and connections between the concepts just defined. Theorem 6.3.1 For arbitrary Σ, Σ ⊆ T (X) × T (X) and arbitrary classes K, K of algebras of type F it holds: (1) Σ ⊆ Σ =⇒ M od(Σ ) ⊆ M od(Σ), K ⊆ K =⇒ IdX (K ) ⊆ IdX (K); (2) Σ ⊆ IdX M od(Σ), K ⊆ M odIdX (K); (3) M odIdX M od(Σ) = M od(Σ), IdX M odIdX (K) = IdX (K); (4) Σ ⊆ ConsX (Σ), Σ ⊆ Σ =⇒ ConsX (Σ) ⊆ ConsX (Σ ), ConsX ConsX (Σ) = ConsX (Σ); (5) K ⊆ M odIdX (K), K ⊆ K =⇒ M odIdX (K) ⊆ M odIdX (K ), M odIdX M odIdX (K) = M odIdX (K); (6) Σ is equational theory ⇐⇒ Σ = ConsX (Σ), K is equationally definable ⇐⇒ K = M odIdX (K).
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Proof. (1) and (2) immediately follow from the definitions of M od and IdX . (3): By (2) Σ ⊆ IdX M od(Σ) =: Σ holds. Thus, by means of (1), we have M odIdX M od(Σ) ⊆ M od(Σ). Conversely, we have also by (2): K := M od(Σ) ⊆ M odIdX M od(Σ). Therefore, M od(Σ) = M odIdX M od(Σ). Analogously, one can show IdX M odIdX (K) = IdX (K). (4) and (5) one can easily prove by means of (1)–(3). (6): Let Σ be an equational theory; i.e., there is a class K of algebras of type (F, τ ) with Σ = IdX (K). Then ConsX (Σ) = IdX M od(Σ)
assumption
=
(3)
IdX M odIdX (K) = IdX (K)
assumption
=
Σ.
Conversely, let Σ = ConsX (Σ). Then we have Σ = IdX M od(Σ); i.e., Σ is an equational theory. The statement over equational definable classes can be proven analogously.
If we neglect that the objects formed by classes need an exact definition, 2 then the following theorem is an immediate conclusion of the above theorem and of Theorem 4.4.1. Theorem 6.3.2 Let X be a countable infinite set, Alg(F, τ ) the class of all algebras of type (F, τ ) over X and let T (X) be the set of all terms of type (F, τ ). Then the pair (IdX , M od) forms a Galois connection between P(T (X) × T (X)) and P(Alg(F, τ )). Furthermore, the lattice of all equational classes of Alg(F, τ ) is antiisomorphic to the lattice of all equational theories of type (F, τ ).
6.4 Free Algebras To define a free algebra, we need the following properties of T(X): Theorem 6.4.1 Let K be a class of algebras of type (F, τ ), and let T(X) be the term algebra of the same type over the alphabet X. Then (a) IdX (K) = {Ker ϕ | ∃A ∈ K : ϕ : T(X) −→ A is a homomorphic mapping}, (b) IdX (K) ∈ ConT(X). Proof. (a): Let s, t ∈ T (X ) with X := {x1 , ..., xn } ⊆ X. For every algebra A ∈ K and all a1 , ..., an ∈ A there is by Theorem 6.2.2 a homomorphism ϕ: T(X) −→ A with ϕ(xi ) = ai , i = 1, ..., n. For every ϕ it holds ϕ(s) = sA (a1 , ..., an ) and ϕ(t) = tA (a1 , ..., an ). Therefore we have (s, t) ∈ Ker ϕ for all ϕ : T(X) −→ A with A ∈ K if and only if for all A ∈ K and all a1 , .., an ∈ A the equation sA (a1 , ..., an ) = tA (a1 , ..., an ) holds. But this is equivalently with A |= s ≈ t for all A ∈ K. (b) follows directly from (a), since the intersection of congruences of an algebra is a congruence of the algebra, as is well-known. 2
See, for example, [Sch 74], Chapter II.
6.4 Free Algebras
79
By the above theorem, we can form the factor algebra: T(X)/IdX (K)
(6.1)
for an arbitrary class K of algebras of the same type and of a set X of variables. Definitions If the factor algebra (6.1)belongs to K, then T(X)/IdX (K) is called the free algebra of K with free generating set X. If (6.1) belongs to K, we describe (6.1) with FK (X). In case X = {x1 , ..., xn } we also write FK (x1 , ..., xn ) or briefly FK (n), and, if X = {xi | i ∈ N}, we write FK (x1 , x2 , ...) or FK (ℵ0 ) (or FK (ω)). We notice, that, strictly speaking, the free algebra FK (X) is not generated by the set X but by the congruence classes x/IdX (K), x ∈ X. Nevertheless, one often writes x instead of x/IdX (K), since in a nontrivial class K of algebras (i.e., K contains not only 0- or 1-element algebras), the equation x/IdX (K) = y/IdX (K) implies x = y. The importance of the free algebras results from the following theorems with whose aid the main theorems to the equational theory are proven in Section 6.5. The factor algebra T(X)/IdX (K), in respect to the class K, has the same property as T(X) in respect to the class of all algebras of type (F, τ ) (see Theorem 6.2.2): Theorem 6.4.2 Let K be a class of algebras of type (F, τ ) and T(X) be the term algebra of the same type. Furthermore, let x := x/IdX (K) and X := {x | x ∈ X}. Then there is for every algebra A ∈ K and every mapping ϕ : X −→ A exactly one homomorphism ϕ : T(X)/IdX (K) −→ A, which continues ϕ; i.e., for which ϕ|X = ϕ holds. Proof. Let α : X −→ A be a mapping defined by α(x) := ϕ(x). Then, by Theorem 6.2.2 there is a homomorphism α : T(X) −→ A, which continues α. For the homomorphism π : T(X) −→ T(X)/IdX (K) with Ker π = IdX (K) we have by Theorem 6.4.1, (a) that Ker π ⊆ Ker α holds; i.e., it holds: π(s) = π(t) =⇒ α(s) = α(t). By ϕ(π(t)) := α(t) one receives a well-defined mapping ϕ : T (X)/IdX (K) −→ A. It is easy to see that ϕ is a homomorphism and that ϕ(x) = ϕ(x) for all x ∈ X holds. Because of [X] = [π(X)] = π[X] = π(T (X)) = T (X)/IdX (K) the mapping ϕ is uniquely defined through the definition over X. Theorem 6.4.3 For every class K of algebras of the same type and every variable set X it holds T(X)/IdX (K) ∈ ISP (K). Proof. Let T := T (X) and κ := IdX (K). By Theorem 6.4.1 (a) and with the help of Lemma 17.4.1 from [Lau 2004], volume 2 one can prove {(Ker ϕ)/κ | ∃A ∈ K : ϕ : T −→ A is a homomorphic mapping} = ∆T /κ (= κ0 on T /κ). Because of Theorem 5.2.2, the algebra T/κ is isomorphic to a subdirect product of the algebras (T/κ)/((Ker ϕ)/κ)
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with ϕ : T −→ A, A ∈ K. For every such ϕ it holds (by the First Isomorphism Theorem 3 ) (T/κ)/((Ker ϕ)/κ) ∼ = T/(Ker ϕ) ∼ = ϕ(T) ∈ S(K). Therefore one gets altogether T/κ ∈ ISP (IS(K)) ⊆ ISP (S(K)) ⊆ ISP (K), where, obviously, the first inclusion is valid and the second inclusion follows from Lemma 6.1.1, (b). An immediate conclusion from Theorem 6.4.3 is as follows: Theorem 6.4.4 For every class K of algebras of the same type (in particular for a variety K) which is closed in respect to the operators I, S and P , it holds T(X)/IdX (K) ∈ K; i.e., K contains a free algebra FK (X). Lemma 6.4.5 Every free algebra FK (X) of a variety is isomorphic to a subdirect product of certain algebras FK (E), where E ⊆ X is finite and E = ∅. Proof. For x ∈ X let x := x/IdX (K). Further, for every E ⊆ X let E := {e ∈ FK (X) | e ∈ E}. Denote U(E) the subalgebra of FK (X) which is generated by E. It is easy to check that U(E) and FK (E) are isomorphic. Therefore, it is sufficient to show that FK (X) is isomorphic to a subdirect product of the algebras U(E), where E ⊆ X is nonempty and finite. For every such E, one chooses a surjective mapping ϕE : X −→ E with (ϕE )|E = idE . Then, the homomorphic continuation ϕE is surjective, and it holds (ϕE )|U (E) = idU (E) . Every term has only finite many variables. Thus for every pair s, t ∈ FK (X), there is a finite subset E ⊆ X with = t we have even (s, t) ∈ Ker (ϕE ) because of ϕE (s) = s s, t ∈ U (E). In the case s and ϕE (t) = t. Therefore {Kern(ϕE ) | ∅ ⊂ E ⊆ X ∧ E is finite} = κ0 . By Theorem 5.2.2 FK (X) is also isomorphic to an subdirect product of FK (x)/Kern(ϕE ). Because of FK (X)/Kern(ϕE ) ∼ = U(E), the assertion follows. Theorem 6.4.6 For every variety K it holds K = HSP ({FK (n) | n ∈ N}) = HSP ({FK (ω)}). Proof. Every algebra A ∈ K is a homomorphic image of FK (X), if |X| ≥ |A| (one chooses a mapping ϕ : X −→ A and then one uses Theorem 6.4.2). Thus, the first equality sign in our theorem follows from Lemma 6.4.5, and the second equality sign follows from the fact that FK (n) is isomorphic to a subalgebra of FK (ω) for all n ∈ N.
3
See for example [Wec 92], p. 140 or [Den-W 2002], Theorem 3.2.2 or Theorem 17.4.2 from [Lau 2004], volume 2.
6.5 Connections Between Varieties and Equational Defined Classes
81
6.5 Connections Between Varieties and Equational Defined Classes We need the following statement. Lemma 6.5.1 Let K be a class of algebras of the same type. Then it holds for an arbitrary alphabet X that: (a) ∀Op ∈ {H, S, P } : Op(K) ⊆ M odIdX (K); (b) M odIdX (K) is a variety. Proof. (a): Let Op = H. First, we will show that IdX (K) ⊆ IdX (H(K)) is right. Let s < x1 , ..., xn >≈ t < x1 , ..., xn > be an equation of IdX (K) with {x1 , ..., xn } ⊆ X. Then, this equation also holds in an arbitrary algebra B ∈ H(K): If namely ϕ(A) = B for a certain algebra A ∈ K and a surjective homomorphism ϕ, then for arbitrary b1 , ..., bn ∈ B there are a1 , ..., an ∈ A with the property sB < b1 , ..., bn > = sB < ϕ(a1 ), ..., ϕ(an ) > = ϕ(sA < a1 , ..., an >) = ϕ(tA < a1 , ..., an >) = tB < ϕ(a1 ), ..., ϕ(an ) > = tB < b1 , ..., bn >, i.e., s ≈ t ∈ IdX ({B}) holds, and thus we have IdX (K) ⊆ IdX (H(K)). Now, if one uses Theorem 6.3.1, (1), then one gets M odIdX (H(K)) ⊆ M odIdX (K). Furthermore, by Theorem 6.3.1, (2), we have H(K) ⊆ M odIdX (H(K)). Thus H(K) ⊆ M odIdX (K). Analogously one can prove (a) for Op ∈ {S, P }. (b): Let K ∗ = M odIdX (K). Then, by (a) and with the help of Theorem 6.3.1, (3) it holds for every Op ∈ {H, S, P }: Op(K ∗ ) ⊆ M odIdX (K ∗ ) = M od(IdX M odIdX (K)) = M odIdX (K) = K ∗ . Therefore, K ∗ is a variety.
Theorem 6.5.2 (First Main Theorem of the Equational Theory; [Bir 35]) A class K of algebras of the same type is a variety iff it is equationally definable; i.e., it holds (by Theorem 6.3.1, (6) and Theorem 6.1.2): K = HSP (K) ⇐⇒ ∃X : K = M odIdX (K). Proof. “⇐=”: By Lemma 6.5.1, (a) it holds Op(K) ⊆ M odIdX (K) for every Op ∈ {H, S, P }. If now K = M odIdX (K), then this implies Op(K) ⊆ K. Thus K is a variety. “=⇒”: Let K be a variety. By Lemma 6.5.1, (b) the class K ∗ := M odIdX (K) is also a variety and we have for an arbitrary alphabet X:
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6 Varieties, Equational Classes, and Free Algebras FK∗ (X) = T(X)/IdX (K∗ ) (by definition) = T(X)/IdX (K)
(since by Theorem 6.3.1, (3) : IdX (K ∗ ) = IdX M odIdX (K) = IdX (K))
= FK (X)
(by definition).
From that (with the aid of Theorem 6.4.6 and X := {x1 , x2 , ...}) we get the equations K = HSP ({FK (ω)}) = HSP ({FK∗ (ω)}) = K ∗ Therefore, K is equationally definable.
6.6 Deductive Closure of Equation Sets and Equational Theory With the following definition of the deductive closure, we generalize the usual procedure of deriving equations from already proven equations. At the end of this section, we will be able to prove that the deductive closure of an equation sets Σ is identical with the set of all conclusions of Σ. Definitions Let (F, τ ) be a type of algebras, T (X) is defined as in Section 6.2 and Σ ⊆ T (X) × T (X). Then, the deductive closure D(Σ) of Σ is the smallest subset of T (X) × T (X) containing Σ such that the following five conditions hold: (R1) ∀p ∈ T (X) : p ≈ p ∈ D(Σ); (R2) ∀p, q ∈ T (X) : p ≈ q ∈ D(Σ) =⇒ q ≈ p ∈ D(Σ); (R3) ∀p, q, r ∈ T (X) : (p ≈ q ∈ D(Σ) ∧ q ≈ r ∈ D(Σ) =⇒ p ≈ r ∈ D(Σ)); (Rep) ∀f n ∈ F ∀{s1 ≈ t1 , ...., sn ≈ tn } ⊆ D(Σ) : f (s1 , ..., sn ) ≈ f (t1 , ..., tn ) ∈ D(Σ); (“replacement rule”); (Sub) ∀s < x1 , ..., xn >≈ t < x1 , ..., xn >∈ D(Σ) ∀t1 , ..., tn ∈ T (X) : s < t1 , ..., tn >≈ t < t1 , ..., tn >∈ D(Σ) (“substitution rule”). Σ ⊆ T (X) × T (X) is called deductively closed if D(Σ) = Σ holds. Obviously, every set Σ of equations with Σ = IdX (K), where K denotes a class of algebras of type (F, τ ), is deductively closed. In other words, if Σ is an equational theory of a class of algebras, then Σ is deductively closed. Furthermore, it holds that D(Σ) ⊆ ConsX (Σ). The aim of the following considerations is the proof that the reversals of the above two statements are also right. Exacter: It shall be shown that every deductively closed set of equations is
6.6 Deductive Closure of Equation Sets and Equational Theory
83
the equational theory of a certain class of algebras and that for every set Σ of equations, it holds ConsX (Σ) ⊆ D(Σ). Obviously, a deductively closed set Σ ⊆ T (X) × T (X) can also be characterized as follows: Because of (R1)–(R3) Σ is an equivalence relation, because of (Rep) Σ is a congruence on T (X), and because of (Sub) Σ is compatible with every endomorphism of T(X) (this is a homomorphism from T(X) into T(X)) (Proof: Let t1 , ..., tn ∈ T (X) be arbitrary. Then there exists an endomorphism ϕ of T(X) with ϕ(x1 ) = t1 , ϕ(x2 ) = t2 , ..., ϕ(xn ) = tn , and for every such endomorphism, it holds that ϕ(s) = s < t1 , ..., tn > and ϕ(t) = t < t1 , ..., tn >.). Definition A congruence relation κ of an algebra A is called fully invariant, if it is compatible with all endomorphisms of A; i.e., if for every endomorphism ϕ of A, (a, b) ∈ κ implies (ϕ(a), ϕ(b)) ∈ κ. The following two lemmas follow immediately from this definition and the above considerations. Lemma 6.6.1 A set Σ ⊆ T (X) × T (X) is deductively closed iff Σ is a fully invariant congruence on T(X). Lemma 6.6.2 For every class K of algebras of the same type and every variable set X, IdX (K) is a fully invariant congruence on T(X). The reversal of Lemma 6.6.2 is also valid: Lemma 6.6.3 For every fully invariant congruence κ over T(X) it holds that IdX ({T(X)/κ}) = κ, i.e., for arbitrary s, t ∈ T (X) we have: (s, t) ∈ κ ⇐⇒ T(X)/κ |= s ≈ t. In other words, an arbitrary fully invariant congruence κ on T(X) is an equational theory of the algebra T(X)/κ. Proof. “=⇒”: Let s = s < x1 , ..., xn >, t = t < x1 , ..., xn > and (s, t) ∈ κ. For arbitrary t1 , ..., tn ∈ T (X) it holds because of full invariance of κ: (s < t1 , ..., tn >, t < t1 , ..., tn >) ∈ κ. Consequently, we have: sT(X)/κ < t1 /κ, ..., tn /κ >= tT(X)/κ < t1 /κ, ..., tn /κ >, i.e., the equation s ≈ t holds in T(X)/κ. “⇐=”: Let s ≈ t ∈ IdX (T(X)/κ). Then it holds sT(X)/κ < x1 /κ, ..., xn /κ >= tT(X)/κ < x1 /κ, ..., xn /κ > . Thus (sT(X) , tT(X) ) ∈ κ and (s, t) ∈ κ.
The following theorem is a conclusion from the Lemmas 6.6.2 and 6.6.3:
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6 Varieties, Equational Classes, and Free Algebras
Theorem 6.6.4 (Second Main Theorem of the Equational Theory; [Bir 35]) A set Σ ⊆ T (X) × T (X) is an equational theory iff Σ is a fully invariant congruence on T (X). Because of Theorem 6.3.1, (6) and Lemma 6.6.1, one can also write Theorem 6.6.4 as follows: Theorem 6.6.5 (Completeness Theorem for the Equational Logic; [Bir 35]) For an arbitrary alphabet X and an arbitrary Σ ⊆ T (X) × T (X) it holds: (a) Σ = ConsX (Σ) ⇐⇒ D(Σ) = Σ; (b) D(Σ) = ConsX (Σ). Proof. (a): “=⇒”: Let Σ = ConsX (Σ). Then, we have D(Σ) ⊆ ConsX (Σ) = Σ and Σ ⊆ D(Σ). Thus D(Σ) = Σ. “⇐=”: Let D(Σ) = Σ. Then, by Theorem 6.6.1, Σ is a fully invariant congruence on T (X). With the help of Theorem 6.6.4 it follows from this that Σ is an equational theory. Therefore, by Theorem 6.3.1, (6) Σ = ConsX (Σ). (b): Let Σ1 := D(Σ). Then we have D(Σ1 ) = Σ1 , Σ ⊆ Σ1 and D(Σ) ⊆ ConsX (Σ) ⊆ ConsX (Σ1 ).
(6.2)
By D(Σ1 ) = Σ1 it follows from (a): ConsX (Σ1 ) = Σ1 . Then, because of the idempotency of D, we have: D(Σ) = D(D(Σ)) = D(Σ1 ) = ConsX (Σ1 ). This and (6.2) imply D(Σ) = ConsX (Σ).
6.7 Finite Axiomatizability of Algebras The reader needs knowledge of the other sections of this chapter, as well as some knowledge of Part II for this section. An old question in universal algebra is whether, for given algebra A of finite type, there is a finite set Σ ⊆ IdX (A) with D(Σ) = IdX (A), where X := {x1 , x2 , x3 , ...}. For the case that D(Σ) = IdX (A) holds for a finite set Σ, we say that A is finitely axiomatizable or finitely based. The following theorem is easy to prove.
6.7 Finite Axiomatizability of Algebras
85
Theorem 6.7.1 ([Lyn 51]) Let A := (A; F ), B := (B; G) be finite and equivalent algebras of finite types; i.e., |A| < ℵ0 , A = B, |F | < ℵ0 , |G| < ℵ0 and T F (A) = T F (B) 4 . Then A is finitely axiomatizable if and only if B is.
The next theorem was founded by G. Birkhoff. Theorem 6.7.2 Let A be a finite algebra of finite type (F, τ ) and let Xn := {x1 , x2 , ..., xn } be a finite set of variables. Then IdXn (A) is finitely axiomatizable. Proof. Let κ := {(s, t) ∈ T (Xn )×T (Xn ) | A |= s ≈ t}. Then κ ∈ ConT(Xn ) by Theorem 6.4.2, (b). The congruence κ has only a finitely many equivalence classes ε1 , ..., εq , since A, F and Xn are finite, and since (s, t) ∈ κ iff the induced term functions sA , tA satisfy sA = tA . For t ∈ T (X) we denote by #t the number of operation symbols (∈ F) occurring in t. In particular, if t ∈ X then #t = 0. Now, from each equivalence class εi (i ∈ {1, ..., q}) of κ, we choose one representative ri with #ri ≤ #t for all terms t ∈ εi . Set M := {r1 , ..., rq }∪{f (ri1 , ri2 , ..., riaf ) | f ∈ F\F0 , {ri1 , ..., riaf } ⊆ {r1 , ..., rq }}, m := max{#ϕ | ϕ ∈ M } and Σ := {s ≈ t ∈ IdXn (A) | #s ≤ m ∧ # t ≤ m}. By induction on α we prove that ∀α ∈ N0 : (s ≈ t ∈ IdXn (A) ∧ #s ≤ α ∧ #t ≤ α) =⇒ s ≈ t ∈ D(Σ) . =:S(α)
(6.3) (I) If α ≤ m, then the statement S(α) is obviously valid. (II) Assume, S(β) holds for certain β ≥ m. Let s ≈ t ∈ IdXn (A) be arbitrary with #s ≤ β + 1 and #t ≤ β + 1. First, we consider the case s := f (s1 , s2 , ..., saf ), t := g(t1 , t2 , ..., tag ),
(6.4)
where f, g ∈ F and s1 , ..., saf , t1 , ...tag ∈ T (Xn ). Then #s1 +...+#saf ≤ β and #t1 + ... + #tag ≤ β. By definition of r1 , ..., rq there exist u1 , u2 , ...., uaf , v1 , v2 , ..., vag , w ∈ {1, ..., q} with [s1 ]κ = [ru1 ]κ , ..., [saf ]κ = [ruaf ]κ , [t1 ]κ = 4
In other words, the operations of algebra A can be represented as superpositions over the operations of algebra B and vice versa (see Part II, Section 1.5.1).
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6 Varieties, Equational Classes, and Free Algebras
[rv1 ]κ , ...., [tag ]κ = [rvag ]κ , [f (s1 , ..., saf )]κ = [rw ]κ = [g(t1 , ..., tag )]κ . Then, by assumption, we have si ≈ rui , tj ≈ rvj ∈ D(Σ) and (by definition of Σ) f (ru1 , ..., ruaf ) ≈ rw , g(rv1 , ..., rvag ) ≈ rw ∈ Σ. With the aid of these equations and the rules (R1)–(R3), (Rep) and (Sub) we get Σ f (s1 , ..., saf ) ≈ f (s1 , ..., sn ) =⇒ Σ f (s1 , ..., saf ) ≈ f (ru1 , ..., ruaf ) =⇒ Σ f (s1 , ..., saf ) ≈ rw =⇒ Σ f (s1 , ..., saf ) ≈ g(rv1 , ..., rvag ) =⇒ Σ f (s1 , ..., saf ) ≈ g(t1 , ..., tag ), i.e., (s, t) ∈ D(Σ) in case (6.4). In the remaining cases (i.e., {s, t}∩Xn = ∅), one can prove the above in analog mode as well. Thus, (6.3) is right, whereby IdXn (A) is finitely axiomatizable. Remark: The above proof shows that one can choose, instead of Σ, the following finite set Σ : Σ := {x ≈ y | x, y ∈ Xm ∧ (x, y) ∈ κ}∪ {x ≈ r | x ∈ Xn ∧ r ∈ {r1 , ..., rq } ∧ (x, r) ∈ κ}∪ {f (g1 , ..., gaf ) ≈ g | f ∈ F ∧ {g1 , ..., gaf , g} ⊆ {r1 , ..., rq } ∧ (f (g1 , ..., gaf ), g) ∈ κ} As a conclusion of Theorems 6.7.1 and 6.7.2 we get: Theorem 6.7.3 Let A := (A; F ) be a finite algebra of finite type with [A] ⊆ (1) [PA ], i.e, the operations of F have at most an essential variable (see Part II, Chapter 1). Then A is finitely axiomatizable. The equational theory and parts of the mathematical logic deal with similar problems. Therefore, one can use sometimes results of the one theory for the other and vice versa. For this purpose, the next theorem provides an example. Because of the better survey, we agree with the following notation: If A = ({0, 1}; F ), f ∈ F defined by f (x) := ¬x or f (x, y) := x ◦ y
(6.5)
(◦ ∈ {∨, ∧, ⇒}) and t is a term, whose operation symbols belong to F , then tˆ denotes a formula of P rop (see Part II, Section 1.5.2), which one obtains by (6.5).
6.7 Finite Axiomatizability of Algebras
87
Theorem 6.7.4 ([Lyn 51]) Let A = ({0, 1}; 0, 1, f1 , f2 , f3 , g) be an algebra of the type (0, 0, 1, 2, 2, 2) with f1 (x) := ¬x, f2 (x, y) := x ∧ y, f3 (x, y) := x ∨ y and g(x, y) := x ⇒ y (see Table 1.2 of Part II). Further, let T be a set of tautologies (⊆ P rop) with the property that every tautology has a derivation from T with the help of sub and modus ponens. 5 Then, the equations (1) x ⇒ x ≈ 1 ( g(x, x) ≈ 1 ), (2) 1 ⇒ x ≈ x ( g(1, x) ≈ x ), (3) (x ⇒ y) ⇒ y ≈ (y ⇒ x) ⇒ x ( g(g(x, y), y) ≈ g(g(y, x), x) ) and the equations of the type (4) t ≈ 1 f¨ ur every t ∈ T form a system Σ of equations with D(Σ) = IdX (A) (more precise: D(Σ) = {ˆ α | α ∈ IdX (A)}). Proof. First, we show that (ϕ ∈ P rop is a tautology) implies ( ϕ ≈ 1 ∈ D(Σ) ).
(6.6)
By assumption, we can derive a tautology ϕ from T with the aid of sub and modus ponens. Consequently, we have to prove that it is possible to copy the modus ponens through the rules (R1)–(R3), (Rep) and (Sub). Let σ ≈ 1, σ ⇒ τ ≈ 1 ∈ D(Σ). Then τ ≈ 1 ∈ D(Σ) follows from (2)
Sub
σ ≈ 1, σ ⇒ τ ≈ 1 1 ⇒ τ ≈ 1 τ ≈ 1. Thus (6.6) holds. Now, let α ≈ β ∈ IdX (A) be arbitrary; i.e., α ⇒ β and β ⇒ α are tautologies. We show α ≈ β ∈ D(Σ). By (6.6) we have that α ⇒ β ≈ 1 and β⇒α≈1
(6.7)
belong to D(Σ). Furthermore, by (3) and (Rep): (β ⇒ α) ⇒ α ≈ (α ⇒ β) ⇒ β ∈ D(Σ). Thus (β ⇒ α) ⇒ α ≈ (α ⇒ β) ⇒ β
(Sub),(6.7)
1⇒α≈1⇒β
(2),(Sub)
α ≈ β,
whereby α ≈ β ∈ D(Σ) is shown. R. L. Lyndon proven the following basic result with the aid of Theorem 6.7.1 and Post’s theorem (see Part II, Theorem 3.1.1): 5
see Part II, Section 1.5.2.
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6 Varieties, Equational Classes, and Free Algebras
Theorem 6.7.5 ([Lyn 51], without proof ) Every two-element algebra of finite type is finitely axiomatizable. Notice that J. Berman gave a short proof for the above theorem in [Ber 80] with the aid of theorems by Baker ([Bak 77]) and McKenzie ([McK 78]). R. C. Lyndon constructed a 7-element algebra of type (0, 2) whose equations are not finitely based (see [Lyn 54]). The smallest such example was found by V. L. Murskij: Theorem 6.7.6 ([Mur 65]; without proof ) The algebra ({0, 1, 2}; ◦), where ◦ is defined by ◦ 0 1 2 0 0 0 0 , 1 0 0 1 2 0 2 2 is not finitely axiomatizable. Notice that all finite groups, rings and lattices are finitely axiomatizable (see [Oat-P 65], [Kru 73], and [McK 70], respectively). The result for lattices was considerably generalized by K. Baker ([Bak 77]), who proven that every finite algebra whose generated variety is congruence distributive is finitely axiomatizable. In [Per 69] was proven that the multiplicative semigroup of all 2 × 2matrices over a 2-element field has a 6-element subsemigroup with no finite basis. One can find further important results on the topic in [McK 78] and [Wil 2001].
Part II
Function Algebras
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1 Basic Concepts, Notations, and First Properties
In this chapter, we begin by investigating multi-digit operations, which are defined on a finite set A. We define some operations on the set of these operations. For the purpose of distinction, we subsequently replace the concept “operation (on the set A)” by the concept “function (on the set A)”.
1.1 Functions on Finite Sets Let A be a finite set with at least two elements. Often we choose the set Ek := {0, 1, 2, ..., k − 1}, k ≥ 2 instead of A in the following. We say that f is an n-ary (n-digit) function on A (or an n-ary function of the |A|-valued logic1 ), if f a mapping from the n-fold Cartesian product An into A, n ≥ 1. For technical reasons (see Section 1.3), we renounce that, in this section, we consider also nullary functions. Otherwise, we use the concepts introduced in Chapter 1 of Part I for operations: af , f n , D(f ), ... . Let PAn be the set of all n-ary functions on A 2 , n ≥ 1. Instead of PEnk we write also Pkn . Further let
1 2
One finds an explanation for this notation in Section 1.5. A confusion with the direct product is not possible for content-related reasons.
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1 Basic Concepts, Notations, and First Properties
PA :=
n≥1
PAn ,
F n := F ∩ PAn for every subset F of PA , Pk := n≥1 Pkn , PA,B := {f ∈ PA | Im(f ) ⊆ B}, Pk,l := PEk ,El , PA (l) := {f ∈ PA | |Im(f )| ≤ l}, Pk (l) := PEk (l), PA [l] := {f ∈ PA | |Im(f )| = l} and Pk [l] := PEk [l] (2 ≤ l ≤ k). With (x1 , ..., xn ) (briefly x(n) ) or x we denote an arbitrary n-tuple of An or Ekn and usually we say that the xi (i = 1, 2, ..., n) are variables. If n = 2 or n = 3 we also write (x, y) or (x, y, z) instead of (x1 ..., xn ), respectively. We will define, subsequently, specific functions f n from Pk either through a table of the form Table 1.1 x1 x2 0 0 0 0 . . a1 a2 . . k−1 k−1
... xn ... 0 ... 1 ... . ... an ... . ... k − 1
f (x1 , x2 , ..., xn ) f (0, 0, ..., 0) f (0, 0, ..., 1) . f (a1 , a2 , ..., an ) . f (k − 1, k − 1, ..., k − 1)
or through formulas, for example, of the form ∀x ∈ Ekn : f (x1 , ..., xn ) := x1 + ... + xn (mod k),
(1.1)
on the (variable-) alphabet {x, y, z, x1 , x2 , ...}. We write often instead of (1.1) briefly (1.2) f (x1 , ..., xn ) := x1 + ... + xn (mod k) or (if the arity of f is clear from the context or is without importance) we write still more briefly “f is defined by x1 + ... + xn (mod k) ”;
(1.3)
i.e., we do not distinguish between a function and the formula (or term) defining it.3 3
One finds the concept “term” explained in Part I, Section 6.2.
1.1 Functions on Finite Sets
93
Two functions f n , g m ∈ PA are identical (we write f n = g m ) iff n = m and f (x) = g(x) for all x ∈ An hold. Let f n ∈ PA and i ∈ {1, 2, ..., n}. Then we say that the i-th variable (or the i-th place) of the function f ∈ PA is essential, iff there are n-tuples a = (a1 , ..., ai−1 , b, ai+1 , ..., an ) and a = (a1 , ..., ai−1 , c, ai+1 , ..., an ) such that b = c and f (a) = f (a ) hold. In the opposite case, one calls the i-th variable (or i-th place) of f fictitious (or non-essential). If the i-th variable of f is not fictitious, we say that f depends on the i-th variable. The function eni defined by eni (x1 , ..., xn ) := xi (i ∈ {1, ..., n}) is called projection or also selector. Let JA (or Jk ) be the set of all projections of PA (or Pk ), respectively. A constant function (briefly, constant) is a function cna defined by cna (x1 , ..., xn ) := a, where a ∈ A. Notations for certain functions of P2 , the Boolean functions, are given in the following table, where it is defined, as usual ◦(x, y) := x ◦ y if ◦ ∈ {∧, ∨, +, ⇒, ⇐⇒} and
−
(x) := x.
Table 1.2
x x x y x ∧ y x ∨ y x + y x ⇒ y x ⇐⇒ y 0 1 0 0 0 0 0 1 1 1 0 0 1 0 1 1 1 0 1 0 0 1 1 0 0 1 1 1 1 0 1 1 Instead of x ∧ y we also write x · y or we write xy briefly. It can easily be shown that the above functions have the following properties: Theorem 1.1.1 It holds: (a) ∀◦ ∈ {∨, ∧, ⇐⇒, +} : x ◦ (y ◦ z) = (x ◦ y) ◦ z; (b) x ∨ x = x, x ∧ x = x, x ⇐⇒ x = 1, x ⇒ x = 1, x + x = 0, x ∨ 0 = x, x ∧ 1 = x, x ∨ 1 = 1, x ∧ 0 = 0;
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1 Basic Concepts, Notations, and First Properties
(c) ∀◦ ∈ {∨, ∧, +, ⇐⇒} : x ◦ y = y ◦ x; (d) x ∧ x = 0, x ∨ x = 1, x = x, x ∨ y = x ∧ y, x ∧ y = x ∨ y (“de Morgan’s laws”); (e) x ⇒ y = x ∨ y, x ⇒ y = x ∧ y; (f ) x ∧ (y ∨ z) = (x ∧ y) ∨ (x ∧ z), x ∨ (y ∧ z) = (x ∨ y) ∧ (x ∨ z); (g) x ∧ (x ∨ y) = x, x ∨ (x ∧ y) = x.
1.2 Operations on PA, Function Algebras The “formula notation” of our functions from the first section motivates the determination of the following operations on PA : – permutation of variables, – identification of variables, – adding of fictitious variables and – substitution of variables of a function by functions; which are called superposition operations on PA and which one can describe in different way exactly. We give only two possibilities here. First we want describe the above operations through the following (infinite many) partial operations: πs : PAn −→ PAn ∆t : PAn −→ PAr (r < n) ∇q : PAn −→ PAu (u > n) i : PAn × PAm −→ PAn+m−1 Let f n , g m be functions of PA , let s be a permutation on the set {1, 2, ..., n}, let t be a mapping from {1, 2, ..., n} onto {1, 2, ..., r} (r < n), let q be an injective mapping from {1, 2, ..., n} into {1, 2, ..., u} (u > n) and let i ∈ {1, 2, ..., n}. Then, πs f ∈ PAn , ∆t f ∈ PAr , ∇q f ∈ PAu , f i g ∈ PAm+n−1 are defined by (πs f )(x1 , ..., xn ) := f (xs(1) , xs(2) , ..., xs(n) ) (“permutation of variables of f ”), (∆t f )(x1 , ..., xr ) := f (xt(1) , xt(2) , ..., xt(n) ) (“identification of certain variables of f ”), (∇q f )(x1 , x2 , ..., xu ) := f (xq(1) , xq(2) , ..., xq(n) ) (“adding of certain fictitious variables”)
1.2 Operations on PA , Function Algebras
and
95
(f i g)(x1 , ..., xm+n−1 ) := f (x1 , ..., xi−1 , g(xi , ..., xi+m−1 ), xi+m , ..., xm+n−1 ) (“the replacement of the i-th variable of f through the function g and the changing of the denotation of variables of f ”).
For partial operations α ∈ {πs , ∆t , ∇q , i } defined above, one can continue to certain operations α on PA . For later investigations, however, it is better that we choose the minimal number of the operations on PA . Therefore, next we consider that there are five elementary operations (or Mal’tsevoperations) ζ, τ, ∆, ∇, on PA , with which we can form certain continuations of the partial operations πs , ∆t , ∇q , i for arbitrary s, t, q, i, n, m through composition. These operations were published by A. I. Mal’tsev in [Mal 66], and one can define these operations as follows for arbitrary f n , g m ∈ PA : max{1,n−1}
ζf n ∈ PAn , τ f n ∈ PAn , ∆f n ∈ PA
, ∇f n ∈ PAn+1 , f n g m ∈ PAm+n−1
and (ζf )(x1 , ..., xn ) := f (x2 , x3 , ..., xn , x1 ), (τ f )(x1 , ..., xn ) := f (x2 , x1 , x3 , ..., xn ), (∆f )(x1 , ..., xn−1 ) := f (x1 , x1 , x2 , ..., xn−1 ) if n ≥ 2, ζf = τ f = ∆f = f if n = 1, (∇f )(x1 , ..., xn+1 ) := f (x2 , x3 , ..., xn+1 ), (f g)(x1 , ..., xm+n−1 ) := f (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ). To prove that one can describe the operation πs (over PAn ) by means of operations ζ, τ (over PA ), it suffices to show that the set Sn of all permutations on the set {1, 2, ..., n} is generating by the permutations (12...n) and (12) (given in cyclic description); that is, that [{(12...n), (12)}] = Sn holds, where (ss )(x) := s (s(x)) for all s, s ∈ Sn . But, this follows from the fact that every permutation s ∈ Sn is a product of pairwise disjunct cycles: s = (i1 ...ip )(j1 ...jq )..., that every cycle is a product of transpositions (i1 ...ip ) = (i1 i2 )(i1 i3 )...(i1 ip ), and that
(ij) = (1i)(1j)(i1) for arbitrary i > j, i > 1, (1i) = (12)(23)...(i − 1i)(i − 1, i − 2)...(21) and (i, i + 1) = (12...n)n−i+1 (12)(12...n)i−1
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1 Basic Concepts, Notations, and First Properties
are valid. Evidently, then, the operations ∆t or ∇q or i can be created (in respect to ) through the operations πs (s ∈ Sn ), ∆ or πs (s ∈ Sn ), ∇ or πs (s ∈ Sn ), respectively. Thus we proven the following lemma. Lemma 1.2.1 It holds: (a) For every permutation s ∈ Sn there exists an operation π ∈ [{ζ, τ }] with πs f = π s f for all f ∈ PAn . (b) For every mapping t from {1, 2, ..., n} onto {1, 2, ..., r} (r < n) there ex ∈ [{ζ, τ, ∆}] with ∆t f = ∆ t f for arbitrary f ∈ P n . ists an operation ∆ A (c) For every injective mapping q from {1, 2, ..., n} into {1, 2, ..., u} there ex q f for arbitrary f ∈ P n . q ∈ [{ζ, τ, ∇}] with ∇q f = ∇ ists an operation ∇ A (d) For every i ∈ {1, 2, ..., n}, there exists an operation i ∈ [{ζ, τ, }] with i g for arbitrary f ∈ PAn and arbitrary g ∈ PAm . f i g = f By means of the operations ζ, τ, ∆, ∇, we can describe the subject of investigation of this chapter. PA together with the operations e21 , ζ, τ, ∆, forms an algebra (PA ; e21 , ζ, τ, ∆, ) of the type (0, 1, 1, 1, 2), which is called (full) function algebra on A. A little changed form of the full function algebra is the so-called iterative (full) function algebra (PA ; ζ, τ, ∆, ∇, ) of the type (1, 1, 1, 1, 2). Since ∇f = f (τ e21 ) is valid, however, both algebras can be regarded as equivalent in a certain sense: If (S; e21 , ζ, τ, ∆, ) is a subalgebra of (PA ; e21 , ζ, τ, ∆, ), then (S; ζ, τ, ∆, ∇, ) is also a subalgebra of (PA ; ζ, τ, ∆, ∇, ). Conversely, if (T ; ζ, τ, ∆, ∇, ) is a subalgebra of (PA ; ζ, τ, ∆, ∇, ), then (T ∪JA ; e21 , ζ, τ, ∆, ) is a subalgebra of (PA ; e21 , ζ, τ, ∆, ). Therefore, we often deal only with the algebra PA = (PA ; ζ, τ, ∆, ∇, ).
1.3 Superpositions, Subclasses, and Clones A function f ∈ PA is called a superposition over F (⊆ PA ), if f can be obtained by a finite number of applications of the operations ζ, τ, ∆, ∇, from the functions of F . We describe a superposition f over F in the rarest cases f through a term over certain function symbols, ζ, τ, ∆, ∇, and parentheses. We use the variable alphabet {x, y, z, x1 , x2 , ...},
1.3 Superpositions, Subclasses, and Clones
97
certain function symbols, commas, and parenthesis instead of this. In some cases, where an equation for the precise definition of the function would be necessary formally, we are satisfied with the the right side of the defining equation if the remaining information on the function results from the context. Further, if f ∈ Pkn , g1 , ...gn ∈ Pkm and the m-ary function h ∈ Pk is defined by h(x1 , ..., xm ) := f (g1 (x1 , ..., xm ), g2 (x1 , ..., xm ), ..., gn (x1 , ..., xm )), then, we write briefly
h := f (g1 , ..., gn ).
The set of all superpositions over F (⊆ PA ) is called hull or closure of F and it is denoted by [F ]. Obviously, [..] is a hull operator on the set PA . A set F ⊆ PA satisfying [F ] = F is called a closed set or a subclass or briefly class of PA . We define that the empty set is also a closed set, i.e., ∅ = [∅]. One can form many examples of closed sets with the aid of the following concept: Let T ⊆ Pkm and f ∈ Pkn . Then we say that f preserves the set T iff ∀g1 , ..., gn ∈ T : f (g1 , ..., gn ) ∈ T. It is easy to see that a projection preserves every set T ⊆ Pkm and that the set of all functions, which preserve the set T , is closed. The set F ⊆ PA is called a clone of PA , if F is closed and JA ⊆ F holds.4 Obviously, the subclasses of PA are exactly the universes of subalgebras of (PA ; ζ, τ, ∆, ∇, ) and clones are exactly the universes of subalgebras of (PA ; e21 , ζ, τ, ∆, ). Let LA be the set of all closed subsets of PA . Put Lk := LEk . (LA ; ⊆) is a lattice (see Part I, Chapter 2). Further, let L↓A (F ) := {F ∈ LA | F ⊆ F } and
L↑A (F ) := {F ∈ LA | F ⊆ F }.
Analogously, one can define L↑k (F ) and L↓k (F ) for A = Ek . Further, let LA (F ; G) := L↑A (F ) ∩ L↓A (G), where F, G ∈ LA and F ⊂ G. 4
If F is a class of PA , then JA ⊆ F iff e11 ∈ F .
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1 Basic Concepts, Notations, and First Properties
If [G] = F (⊆ PA ), then G is called complete in F . In particular, if F = PA , we say, G is complete or G is a complete set. A closed set F is called a maximal subclass of the closed set F , if F ⊂ F and [F ∪ {f }] = F for every f ∈ F \F . If F = PA then, we say briefly, F is a maximal class. The maximal classes of the maximal classes of PA are called submaximal classes. As usual, we call a subset F of F a generating system of F , if [F ] = F . A generating system F of F is called basis of the closed set F , if every proper subset of F is not a generating system of F . If a subclass F of PA has a finite generating system, then the order of F we denote with ord F . We understand from that, the smallest number with [F r ] = F . If F does not have any finite generating system, we write ord F = ∞.
1.4 Generating Systems for PA For the purpose of determining of generating systems for the set PA , we consider some descriptions (so-called “normal forms”) for an arbitrary function f n ∈ PA . These descriptions are superpositions over certain functions of PA , which are to be described easily and which have small arities. We use the following notations: 1 if x = a, ja (x) := 0 otherwise (a ∈ A) and
ja (x1 , ..., xn ) :=
1 if (x1 , ..., xn ) = a, 0 otherwise
(a ∈ An , n ∈ N). Theorem 1.4.1 (Representation Theorem for Functions of PA ) Let 0, 1 ∈ A and let ∧, ∨ be two binary associative5 operations on A with a ∧ 1 = a, 0 ∨ a = a ∨ 0 = a and a ∧ 0 = 0
(1.4)
for each a ∈ A. Then, for every function f n ∈ PA it holds: f (x) = (
m
fai (x) := )fa1 (x) ∨ fa2 (x) ∨ ... ∨ fam (x),
i=1
where An := {a1 , ..., am }, m := |A|n and
(1.5)
1.4 Generating Systems for PA
99
fai (x) := cf (ai ) (x1 ) ∧ jai (x) (i = 1, ..., m). Furthermore: jai (x) = jai1 (x1 ) ∧ jai2 (x2 ) ∧ ... ∧ jain (xn ), where ai := (ai1 , ..., ain ). Proof. The correctness of the equation (1.5) can be assured by checking that on both the left side and the right side of the formula, the same value stands for every x. If A = {0, 1}, the functions ∨, ∧ (= ·) are defined as in Table 1.2, j0 (x) = x and j1 (x) = x, then one receives the disjunctive normal form (or DNF) of an arbitrary Boolean function f n ∈ P2 as an conclusion from (1.5): f (x1 , ..., xn ) = f (a1 , ..., an ) · xa1 1 · xa2 2 · ... · xann , (1.6) a∈E2n
where
α
x :=
x if α = 0, x if α = 1
(α ∈ E2 ). If f = cn0 , then we can write f (x1 , ..., xn ) =
xa1 1 · xa2 2 · ... · xann
(1.7)
a∈E2n ,f (x)=1
instead of (1.6). For example, f (x, y, z) = x · y · z ∨ x · y · z ∨ x · y · z is the DNF for the ternary function f defined by Table 1.3. Table 1.3
x 0 0 0 0 1 1 1 1 5
y 0 0 1 1 0 0 1 1
z f (x, y, z) 0 0 1 0 0 1 1 0 0 1 1 0 0 0 1 1
The associativity can be renounced if the necessary parentheses are put in the following formulas.
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If A is an arbitrary finite set, then one can choose ∧ and ∨ as lattice operations with 0 = A and 1 = A. Then, by Theorem 2.1.2 of Part I, we have ∨(x, y) = sup {x, y} and ∧(x, y) = inf {x, y}, where is the partial order (appertaining to the lattice) over A with the greatest element 1 and the least element 0. If A = Ek , then the functions ∨ := + (mod k) and ∧ := · (mod k) also fulfill (1.4) and we get the following normal form for an arbitrary function f n ∈ Pk : f (a1 , ..., an ) · ja1 (x1 ) · ... · jan (xn ) (mod k) (1.8) f (x) = a∈Ekn
The following theorem results from the above considerations immediately: Theorem 1.4.2 It holds: (a) Let ∨ and ∧ be binary operations on A, which (1.4) fulfill. Then, {∨, ∧}∪ {c1a , ja1 | a ∈ A} is a generating system for PA . In particular, if A = E2 , then [{∨, ∧,− }] = P2 and (because of Theorem 1.1.1, (d)) [{∨,− }] = [{∧,− }] = P2 . (b) ord PA = 2.
Theorem 1.4.3 Let A = Ek and let k = pm be a prime number power. Then one can define operations + and · on Ek so that (Ek ; +, ·) is a field with the neutral element o in respect to + and the neutral element e of the group (Ek \{o}; ·). Then, one can represent an arbitrary function f n ∈ Pk with the aid of these field operations as follows: ai1 i2 ...in · xi11 · xi22 · ... · xinn (1.9) f (x) = (i1 ,...,in )∈Ekn
(x0 := e; ai1 i2 ...in ∈ Ek ). This representation is unique except the order of addends, i.e., the equality of the corresponding coefficients results from the equality of two functions ∈ Pkn . Proof. The existence of a field (Ek ; +, ·) for k = pm , p ∈ P and m ∈ N is well-known. (see for example [Lid-N 87] or [Lau 2004], volume 2).
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Every polynomial of the form (1.9) is uniquely represented through the sen quence of coefficients. Thus there are k (k ) different formulas of the form (1.9). n (kn ) , our theorem is proven if Since |Pk | = k f (x) = (i1 ,...,in )∈E n ai1 i2 ...in xi11 xi22 ...xinn and k f (x) = (i1 ,...,in )∈E n bi1 i2 ...in xi11 xi22 ...xinn k
implies ai1 ...in = bi1 ...in for all (i1 , ..., in ) ∈ Ekn . This is clear for (i1 , ..., in ) = (o, o, ..., o) (one forms f (o, ..., o)!). Let I := {xij | ij = o ∧ j ∈ {1, ..., n}} for the proof of ai1 ...in = bi1 ...in in the case (i1 , ..., in ) ∈ Ekn \{o}. If one identifies now the variables in f from I with x and one replaces the remaining variables through c0 (x), then one receives a unary function f that can be represented as follows: (1.10) f (x) = a0 + a1 · x + a2 · x2 + ... + ar−1 · xr−1 or
f (x) = b0 + b1 · x + b2 · x2 + ... + br−1 · xr−1
(1.11)
with r−1 := |I|, ar−1 = ai1 ...in and br−1 = bi1 ...in for certain a0 , ..., ar−2 , b0 , ..., br−2 . If one forms now in (1.10) and (1.11) f (α1 ), f (α2 ), ..., f (αr ) for pairwise distinct α1 , α2 , ..., αr ∈ Ek , then one sees that both (a0 , ..., ar−1 )T as also (b0 , ..., br−1 )T is a solution of the matrix equation A · x = (f (α1 ), ..., f (αr ))T with ⎛ ⎞ 1 α1 α12 ... α1r−1 ⎜ 1 α2 α2 ... αr−1 ⎟ 2 2 ⎟ A := ⎜ ⎝ ................. ⎠. 1 αr αr2 ... αrr−1 But, because of det A = o,6 this is only possible for a0 = b0 , ..., ar−1 = br−1 . The next property of functions of Pk for k ≥ 3 is not only useful while determining from generating systems for Pk ; it also has interesting consequences, which we will deal with later. We need the following denotation:7 ιhk := {(a1 , ..., ah ) ∈ Ekh | |{a1 , ..., ah } | ≤ h − 1} (h ≥ 2), 3 δ{α,β} := {(a1 , a2 , a3 ) ∈ Ek3 | aα = aβ } (α, β ∈ {1, 2, 3}) and 3 δ{1,2,3} := {(x, x, x) | x ∈ Ek }. 6 7
This follows from the fact that A is a Vandermonde matrix (see for example [Lau 2004], volume 1). See also Chapter 2.
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Furthermore, for arbitrary ri := (r1i , r2i , ..., rhi ) ∈ Ekh , i = 1, 2, .., n, and f ∈ Pkn we put: f (r1 , ..., rn ) := (f (r11 , r12 , ..., r1n ), f (r21 , r22 , ..., r2n ), .., f (rh1 , rh2 , ..., rhn )). Theorem 1.4.4 Let f be an n-ary function of Pk , which is essentially dependent of at least two variables (w.l.o.g. of x1 and x2 ) and which has q pairwise distinct values. Then: 3 3 (a) q ≥ 3 =⇒ ∃r1 , ..., rn ∈ δ{1,2} ∪ δ{2,3} : f (r1 , ..., rn ) ∈ Ek3 \ι3k
(“Fundamental Lemma of Jablonskij”); (Jab 58]) (b) q ≥ 3 =⇒ ∃r1 , ..., rn ∈ ιqk : f (r1 , ..., rn ) ∈ Ekq \ιqk ; 3 3 3 3 ∪ δ{2,3} : f (r1 , ..., rn ) ∈ δ{1,3} \δ{1,2,3} . (c) q = 2 =⇒ ∃r1 , ..., rn ∈ δ{1,2}
Proof. (a), (c): Since f depends on the variable x1 essentially, there is an a := (a2 , ..., an ) ∈ Ekn−1 , so that Ta := {f (x, a2 , ..., an ) | x ∈ Ek } has at least two different elements. We distinguish two cases: Case 1: |Ta | < q. In this case, one can find a tuple c = (c1 , ..., cn ) with γ := f (c) ∈ Ta . Consequently, we have ⎞ ⎛ ⎞ ⎞ ⎛ ⎛ α f (a1 , a2 , ..., an ) a1 a2 ... an f ⎝ c1 a2 ... an ⎠ := ⎝ f (c1 , a2 , ..., an ) ⎠ = ⎝ β ⎠ c1 c2 ... cn γ f (c1 , c2 , ..., cn ) and |{α, β, γ}| = 3 for certain a1 ∈ Ek . Case 2: |Ta | = q. Since f also depends on x2 essentially, the function f1 (x1 , ..., xn−1 ) := f (d, x1 , ..., xn−1 ) is not a constant function for certain d ∈ Ek . Let now β := f (d, a2 , ..., an ). Because of f1 = cβ there are certain c2 , ..., cn and a γ with γ := f (d, c2 , ..., cn ) = β . Since |Ta | = q, then one can find an a1 ∈ Ek with γ if q = 2, α := f (a1 , a2 , ..., an ) = α ∈ {β , γ } if q ≥ 3. Consequently, we have ⎞ ⎛ ⎞ α a1 a2 ... an f ⎝ d a2 ... an ⎠ = ⎝ β ⎠ . d c2 ... cn γ ⎛
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(b) follows easy from (a). From the many conclusions from this theorem, we provide only the following, first. Lemma 1.4.5 Let f n be a function of Pk , which is essentially dependent on two variables and which has q ≥ 3 distinguish values. Then: Pk,Im(f ) ⊆ [{f } ∪ Pk (q − 1)]. Proof. W.l.o.g. let Im(f ) = Eq . By Theorem 1.4.4, (b) there exist r1 , ..., rn ∈ ιqk with f (r1 , ..., rn ) = (0, 1, ..., q − 1)T and ⎞ ⎛ a02 ... a0n a01 ⎜ a11 a12 ... a1n ⎟ ⎟ (r1T , ..., rnT ) = ⎜ ⎝ ....................... ⎠. aq−1,1 aq−1,2 ... aq−1,n For an arbitrary function g m ∈ Pk,Im(f ) let gj (x1 , ..., xm ) = aij :⇐⇒ ∃i : g(x1 , ..., xm ) = i, (j = 1, 2, ..., n). Obviously, the functions g1 , ..., gn belong to Pk (q − 1) and it holds: g(x1 , ..., xm ) = f (g1 (x1 , ..., xm ), ..., gn (x1 , ..., xm )). Thus g ∈ [{f } ∪ Pk (q − 1)]. Subsequently, we declare another possibility of the characterization of functions of Pk that we need later during the description of a certain type of maximal classes of Pk . Lemma 1.4.6 Let Ai (i ∈ Ek ) be a partition of the set Ek and ai ∈ Ai (i ∈ Ek ). Furthermore, let y if ∃i ∈ Ek : x = ai and y ∈ Ai , x y := x otherwise. Then, an arbitrary function f n of Pk is a superposition over the functions z, gf , fi (i ∈ Ek ) defined by z(x, y) := x y, ai ⇐⇒ f (x1 , ..., xn ) ∈ Ai , gf (x1 , ..., xn ) := f (x1 , ..., xn ) if f (x1 , ..., xn ) ∈ Ai , fi (x1 , ..., xn ) := otherwise ai (i ∈ Ek ), and
f (x) = ((...((gf (x) f0 (x)) f1 (x)) ...) fk −1 (x)) n
is a representation of f .
(1.12)
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1.5 Some Applications of the Function Algebras It is the aim of this section to show by examples how results in function algebras can be used in other mathematical disciplines. In addition, some problems that motivate certain investigations with function algebras are explained. 1.5.1 Classification of Universal Algebras In Part I, Chapter 1, we introduced the concept of the type of an algebra, and in Chapter 6 combinations (classes) of algebras of the same type, which fulfill certain equations. Such a decomposition of the algebras is, however, very coarse. The set MA of all finite algebras on the same universal A can be more finely decomposed with the aid of the following equivalence relation RA : The algebras (A; F ) and (A; G) with F, G ⊆ PA are called equivalent in respect to RA , iff [F ] = [G] holds, i.e., iff the operations of the one algebra can be represented as superpositions over the operations of the other algebra and vice versa. The equivalence classes (blocks) of the relation RA form a partition of the set MA , where the set of all algebras (A; F ) with F ∈ LA is a representative system of these equivalence classes. Reducts of (A; F ) are defined to be algebras of the form (A; G) with G ⊆ [F ]. An algebra (A; F ) with [F ] = PA is called primal ([Fos 59]). For example, by Theorem 1.4.2, the two-element Boolean algebra is primal. The Rosenberg’s completeness criterion from Chapter 6 can be used to obtain further examples of primal algebras (see also Chapter 7). An algebra (A; F ) is called preprimal iff [F ] is a maximal clone of PA ([Den 82], [Kno 85]). For a description of further generalizations of “primal algebras”, we need some concepts and results of Chapter 2 and the notations S(A) (the set of all subalgebras of the algebra A), Aut(A) (the set of all automorphisms on A), SubIso(A) (the set of all isomorphisms between subalgebras of A) and Con(A) (the set of all congruences of A). Let A := (A; F ) be an algebra, for which there is a relation set Q on A with [F ] = P olA Q. Then A is called • semiprimal iff Q ⊆ Rk1 , i.e., iff Q = S(A) (or with other words: iff every operation on A which preserves all subalgebras of A belongs to [F ]) [Fos-P 64]; • demiprimal iff Q = Aut(A) ([Qua 71]); • infraprimal (or demisemiprimal) iff Q = S(A) ∪ Aut(A) [Qua 71]; • quasiprimal iff Q = SubIso(A) ([Pix 71]); • hemiprimal iff Q = Con(A) ([Fos 70]);
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For further concepts and properties of the above-defined algebras, refer to [Den 82], [Den-W 2002] and [Sze 86]. Since the present book describes many clones, one finds properties of the above-defined algebras, in many places in this book. 1.5.2 Propositional Logic and First Order Logic A proposition is a “sentence” (of a natural or artificial language) for which it makes sense to ask whether it false (notation: 0) or true (notation: 1). At the basis of the concept “proposition” we have the two-value principle (also called principle of the excluded middle). This means that each proposition must be either false or true, there is no other possibility “in between”. The following are propositions: – Rostock is a city in Germany. – There are infinite many prime numbers. – 2 · 3 = 5. – There exists extra-terrestrial life. The following are not propositions: – Two chickens on the way after the day before yesterday. – Everything that I say is false. – It is a beautiful day. – Be quiet! Propositions will be denoted by capital letters A, B, .... Instead of “A is an arbitrary proposition” we say “A is a proportional variable”. Therefore, a propositional variable takes the values 0 and 1. One can associate propositions (“sentences”) in the informal language in multiple ways with each other (for example through such conjunctions as “and”, “or”, “if – then”, ...). The result of this connection is normally, again, a proposition, whose value (0 or 1) is dependent from the values of associated single propositions. In the propositional logic, a part of the colloquial connections is modelled and defined exactly (unlike the informal language). Since we abstract from the content of a proposition during the consideration of a proposition (i.e., we have interest only in the so-called truth value 0 or 1 of the proposition), proposition combinations are multi-digit functions on {0, 1}, i.e., Boolean functions (or function of the 2-valued logic). Interpretations of the Boolean functions that are defined in Table 1.2 are, for example, • The negation of the proposition A: A (“not A”). A is true if and only if A is false. • The conjunction of the propositions A, B: A ∧ B (“A and B”). A ∧ B is true if and only if A as well as B are true. • The disjunction of the propositions A, B: A ∨ B (“A or B”). A ∨ B is true if and only if either A or B or both are true.
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• contravalence: A + B (“either A or B”). A + B is true if and only if either A or B is true. • equivalence: A ⇐⇒ B (“A if and only if B”). A ⇐⇒ B is true if and only if A and B have the same truth value. • implication: A ⇒ B (“A implies B”; “If A, then B”). A ⇒ B is false if and only if A has the value 1 and B has the value 0. To provide mathematics with a precise language, the mathematical logic creates an artificial, formal language. Next, we give a short introduction on proportional logic; that is, the logic that deals only with propositions. Later, we extend our treatment to the first order logic, which also takes properties of individuals into account. The process of formalization of proportional logic consists of two stages: (i) present a formal language (ii) specify a procedure for obtaining valid or true propositions. The language of propositional logic has an alphabet consisting of • the set of proposition symbols At := {A, B, C, ..., A1 , B1 , C1 , ..., An , Bn , Cn , ...} (the elements of At are called atoms or atomic propositions) • the set of connectives J0 := {∧, ∨, ¬, ⇒, ⇔} • the set of auxilliary symbols {(, )} The set P rop is the smallest set X with the following three properties: • At ∪ {0, 1} ⊆ X • if α, β ∈ X, then (α ◦ β) ∈ X for all ◦ ∈ J0 • if α ∈ X, then (¬α) ∈ X Notice that P rop = T (At) (see Part I, Section 6.2). A mapping v : P rop −→ {0, 1} is called a valuation if v(0) = 0, v(1) = 1, v(¬α) = ¬v(α) and v(α ◦ β) = v(α) ◦ v(β) for all α, β ∈ P rop and all ◦ ∈ J0 . 8 If v(α) = 1 (or v(α) = 0) then α is true (or false) under v, respectively. If α = (β) ∈ P rop, then we only write β instead of α in the following. Obviously, we have: If v0 : At −→ {0, 1}, then there exists a unique valuation v such that v(α) = v0 (α) for all α ∈ At. α ∈ P rop is a tautology if v(α) = 1 for all valuations v. We write |= α (or ∅ |= α) for “α is a tautology”. If Σ ⊆ P rop and α ∈ P rop, then 8
Notice that the right sides of the equations are determined by Table 1.2.
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Σ |= α iff for all valuations v: v(σ) = 1 for all σ ∈ Σ implies v(α) = 1. If Σ |= α then α is called a consequence of Σ. Further, set Cons(Σ) := {α ∈ P rop | Σ |= α}. It is a classical problem of the propositional logic to find a system of axioms and rules with which one can determine all tautologies and all consequences from a set of propositions. In books about mathematical logic, one finds many solutions for this purpose. We declare a solution with proof here. The proof is chosen so that it can be used as proof for a corresponding theorem of the predicate logic as a basic idea. It is normal to write down the rule “R: if α1 , ..., αr ∈ P rop are derivable, then αr+1 is derivable” in the following form: α1 , ..., αr R αr+1 As an example, we give the substitution rule sub: Let α ∈ P rop, which contains x ∈ At (in symbol: α(..., x, ...) ). If α is a tautology, then one can form a tautology by replacing every occurrence of x by β ∈ P rop in α: α(..., x, ...); β ∈ F orm sub . α(..., β, ...) The Hilbert-type-calculus for the classical proportional logic is defined by the following 13 axioms and a rule, where α, β, γ, σ, τ are arbitrary elements of P rop: (I) Axioms are all formulas of the form (A1) α ⇒ α (A2) α ⇒ (β ⇒ α) (A3) (α ⇒ β) ⇒ ((β ⇒ γ) ⇒ (α ⇒ γ)) (A4) (α ⇒ (β ⇒ γ)) ⇒ ((α ⇒ β) ⇒ (α ⇒ γ)) (A5) α ⇒ (α ∨ β), β ⇒ (α ∨ β) (A6) (α ⇒ γ) ⇒ ((β ⇒ γ) ⇒ ((α ∨ β) ⇒ γ)) (A7) (α ∧ β) ⇒ α, (α ∧ β) ⇒ β (A8) (γ ⇒ α) ⇒ ((γ ⇒ β) ⇒ (γ ⇒ (α ∧ β))) (A9) ((α ∧ β) ∨ γ) ⇒ ((α ∨ γ) ∧ (β ∨ γ)), ((α ∨ γ) ∧ (β ∨ γ)) ⇒ ((α ∧ β) ∨ γ) (A10) ((α ∨ β) ∧ γ) ⇒ ((α ∧ γ) ∨ (β ∧ γ)), ((α ∧ γ) ∨ (β ∧ γ)) ⇒ ((α ∨ β) ∧ γ) (A11) (α ⇒ β) ⇒ (¬β ⇒ ¬α) (A12) (α ∧ ¬α) ⇒ β (A13) β ⇒ (α ∨ ¬α). 9 (II) Rules: There is only one rule: “from σ and σ ⇒ τ conclude τ ”, written as 9
One can also choose α, β, γ as three different variables and the substitution rule sub as an additional rule.
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σ, σ ⇒ τ (“modus ponens”) τ A derivation of ϕ from Σ (⊆ P rop) is a finite sequence (ϕ1 , ϕ2 , ..., ϕn ) of formulas with ϕn = ϕ, where each ϕi (1 ≤ i ≤ n) is an axiom or is an element of Σ or is the result of the application of modus ponens on ϕu , ϕv (u, v < i). Let be the derivation operator defined in this way, i.e., we write Σϕ iff there is a derivation of ϕ from Σ. Put cons(Σ) := {ϕ | Σ ϕ} (the set of all derivation consequences from Σ). It is easy to check that cons(Σ) ⊆ Cons(Σ), since the axioms are tautologies and since, for each valuation v, v(σ) = 1 and v(σ ⇒ τ ) = 1 imply v(τ ) = 1. For proof that cons(Σ) ⊂ Cons(Σ) is false, we need the following notations and facts: Since P rop is a set of terms, one can form the term algebra Prop := (P rop; ∨, ∧, ⇒, ¬, 0, 1) of the type (2, 2, 2, 1, 0, 0). For arbitrary α, β ∈ P rop let α ≈Σ β iff (Σ α ⇒ β and Σ β ⇒ α). Theorem 1.5.2.1 The relation ≈Σ has the following properties for arbitrary Σ: (a) (b) (c) (d)
≈Σ is a congruence of the algebra Prop. The factor algebra (P rop/≈Σ ; ∨, ∧, ¬, 0, 1) is a Boolean algebra. The set cons(Σ) is the 1 of the Boolean algebra (P rop/≈Σ ; ∨, ∧, ¬, 0, 1). There exists a homomorphic mapping ν from Prop onto Prop/≈Σ with ν(ϕ) = 1 iff Σ ϕ.
Proof. (a): First we show that ≈Σ is an equivalence relation. By Σ α ⇒ α (see (A1)) is ≈Σ reflexive. The symmetry of ≈Σ follows from the definition of ≈Σ . One can prove the transitivity of ≈Σ with the aid of (A3) and the modus ponens as follows: Let α ≈Σ β and β ≈Σ γ be arbitrary, i.e., it holds: Σ α ⇒ β, Σ β ⇒ α, Σ β ⇒ γ, Σ γ ⇒ β. By means of the modus pones ( σ := α ⇒ β, σ ⇒ τ := (A3) ) and (A3) one obtains Σ (β ⇒ γ) ⇒ (α ⇒ γ). When one uses the modus pones (σ := β ⇒ γ) again, one receives Σ α ⇒ γ. Analogously, one can show Σ γ ⇒ α. Thus, ≈Σ is an equivalence relation. To prove the compatibility of ≈Σ with ⇒ we consider
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ϕ ≈Σ ϕ , ψ ≈Σ ψ , ( ϕ, ϕ , ψ, ψ ∈ P rop), i.e., it holds Σ ϕ ⇒ ϕ , Σ ϕ ⇒ ϕ, Σ ψ ⇒ ψ , Σ ψ ⇒ ψ. (ψ ⇒ ψ ) ⇒ (ϕ ⇒ (ψ ⇒ ψ )) (α = ψ ⇒ ψ and τ = β in (A2)) and the modus ponens imply Σ ϕ ⇒ (ψ ⇒ ψ ). Furthermore, by (A4), we have ((ϕ ⇒ (ψ ⇒ ψ )) ⇒ ((ϕ ⇒ ψ) ⇒ (ϕ ⇒ ψ )). Hence we get Σ ((ϕ ⇒ ψ) ⇒ (ϕ ⇒ ψ )) with the aid of modus ponens. Analogously, one can show Σ ((ϕ ⇒ ψ ) ⇒ (ϕ ⇒ ψ)). Consequently,
ϕ ⇒ ψ ≈Σ ϕ ⇒ ψ .
(1.13)
By (A3) we have Σ (ϕ ⇒ ϕ) ⇒ ((ϕ ⇒ ψ ) ⇒ (ϕ ⇒ ψ )), whereby Analogously, and therefore, Then
Σ (ϕ ⇒ ψ ) ⇒ (ϕ ⇒ ψ ). Σ (ϕ ⇒ ψ ) ⇒ (ϕ ⇒ ψ ), ϕ ⇒ ψ ≈Σ ϕ ⇒ ψ .
(1.14)
ϕ ⇒ ψ ≈Σ ϕ ⇒ ψ ,
since ≈Σ is transitive and (1.13) and (1.14) are valid. Hence, ≈Σ is compatible with ⇒. To prove that ≈Σ is compatible with ¬ we assume α ≈Σ β; i.e., we have Σ α ⇒ β and Σ β ⇒ α. Then, by (A11) and the modus ponens, we get Σ ¬β ⇒ ¬α and Σ ¬α ⇒ ¬β, whereby ¬α ≈Σ ¬β. Because of this property of ≈Σ , we can define a partial order on Prop/≈Σ as follows: [ϕ]≈Σ ≤ [ψ]≈Σ iff Σ ϕ ⇒ ψ, where [ϕ]≈Σ = [ψ]≈Σ means that ϕ ≈Σ ψ (i.e., Σ ϕ ⇒ ψ and Σ ψ ⇒ ϕ) holds. (By (A1) is ≤ reflexive; (A3) implies the transitivity of ≤. The antisymmetry follows from the definition of ≈Σ : I If Σ ϕ ⇒ ψ and Σ ψ ⇒ ϕ, then we have ϕ ≈Σ ψ.) Now (A5) shows that [α]≈Σ ≤ [α ∨ β]≈Σ and [β]≈Σ ≤ [α ∨ β]≈Σ .
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Assume there is a γ with [α]≈Σ ≤ [γ]≈Σ and [β]≈Σ ≤ [γ]≈Σ . By (A6) and the modus ponens, this implies [α ∨ β]≈Σ ≤ [γ]≈Σ , whereby
sup([α]≈Σ , [β]≈Σ ) = [α]≈Σ ∨ [β]≈Σ = [α ∨ β]≈Σ
holds. Analogously, inf ([α]≈Σ , [β]≈Σ ) = [α]≈Σ ∧ [β]≈Σ = [α ∧ β]≈Σ follows from (A7), (A8) and the modus ponens. Thus ≈Σ is also compatible with the operations ∨ and ∧. (b): (a) implies that Prop/≈Σ is a lattice. Because of the axioms (A9) and (A10) this lattice is distributive. Assume Σ ϕ and Σ ψ. Then [ϕ]≈Σ = [ψ]≈Σ , since Σ ψ ⇒ ϕ and Σ ϕ ⇒ ψ follows from this with the aid of (A2) and the modus ponens. Because of (A2), we have Σ (β ⇒ α) for all β ∈ P rop and all α ∈ P rop with Σ α, i.e., β ≤ α. Therefore, {α | Σ α} is the greatest element of the lattice Prop/≈Σ . By (A12) the smallest element is the equivalence class [α ∧ ¬α]≈Σ . Consequently, the algebra Prop/≈Σ also fulfills the axioms (B1 ) (see Section 1.2.12). (B2 ) follows from the fact that ≈Σ is compatible with ∧, ∨ and ¬ with the aid of (A13) as follows: [α]≈Σ ∧ (¬[α]≈Σ ) = [α ∧ (¬α)]≈Σ = 0 (see above), [α]≈Σ ∨ (¬[α]≈Σ ) = [α ∨ (¬α)]≈Σ = 1 (because of [β]≈Σ ≤ [α ∨ ¬α]≈Σ for each β ∈ P rop by (A13)). Hence, Prop/≈Σ is a Boolean algebra. (c): We have shown above that the 1 of P rop/≈Σ contains all formulas derivable from Σ. Further, if α ∈ P rop belongs to the equivalence class 1 of P rop/≈Σ , then we get Σ ϕ ⇒ α for each ϕ with Σ ϕ by the above shown. Thus (by modus ponens) we have Σ α. Hence, (c) is proven. (d) By Part I, Section 4.1, the natural homomorphism ϕ : P rop −→ P rop/≈Σ , α → [α]/≈Σ fulfills (d). Theorem 1.5.2.2 (Completeness Theorem of Proportional Logic) Let Σ ⊆ P rop. Then cons(Σ) = Cons(Σ).
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Proof. Obviously, cons(Σ) ⊆ Cons(Σ). Assume there exists an α ∈ Cons(Σ) \ cons(Σ). Then [α]/≈Σ = [1]/≈Σ by Theorem 1.5.2.1, whereby α is an element of a certain prime ideal (maximal ideal) of the Boolean algebra Prop/≈Σ .10 Consequently, there exists a homomorphism µ from Prop/≈Σ onto the two-element Boolean algebra {0, 1} with µ([α]/≈Σ ) = 0. Then, with the aid of Theorem 1.5.2.1, (d), it is easy to see that v := νµ is a valuation with v(α) = 0 and v(σ) = 1 for all σ ∈ Σ. But, this is a contradiction to α ∈ Cons(Σ). Next is a short introduction to predicate logic (or first order logic). Predicate logic is a language to describe statements about algebraic structures (to given signature). A signature is a pair δ := ((ni )i∈I , (mj )j∈J ) with ni ∈ N0 , mj ∈ N for all i ∈ I and j ∈ J. A := (A; (fiA )i∈I , (RjA )j∈J ) is called a structure of signature δ, if (A; (fiA )i∈I ) an algebra of the type (ni )i∈I and RjA ⊆ Amj holds for all j ∈ J. We say “fiA is the interpretation of fi ” and “RjA is the interpretation of Rj ”. With the aid of a mapping P from Ah into {0, 1}, one can describe an h-ary relation R on a set A (i.e., R ⊆ Ah ) as follows: P (a1 , .., ah ) = 1 iff (a1 , ..., ah ) ∈ R. Such a mapping P is called an h-ary predicate. Let P, Q be predicates on A. Then one can understand the predicates as propositions and form (¬P ) and (P ◦ Q) for each ◦ ∈ J0 . m Therefore, let Pj j be the mj -ary predicate with mj
Pj (a1 , .., amj ) = 1 iff (a1 , ..., amj ) ∈ Rj
in the following. The alphabet of the first order logic consists of the following symbols: • • • •
the set V ar := {x0 , x1 , x2 , ...} of variables m the set {Pj j | j ∈ J} of predicate symbols the set {fini | i ∈ I} of operation symbols the set of connectives J := {∧, ∨, ¬, ⇒, ⇔, ∃, ∀} (∃ and ∀ are called the existential and universal quantifier) • the set of auxilliary symbols {(, )} As described in Part I, Section 6.2, we form the set of all terms T erm := T (V ar) and the term algebra Term = (T erm; (fi )i∈I ). Then, F ORM is the smallest set X with the following four properties:
10
See books on Boolean algebras or universal algebras.
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• Pj (t1 , ..., tmj ) ∈ X for all j ∈ J and all t1 , ..., tmj ∈ T erm (Pj (t1 , ..., tmj ) is called an atom); • if α, β ∈ X , then (α ◦ β) ∈ X for all ◦ ∈ J0 • if α ∈ X then (¬α) ∈ X • if α ∈ X then (∃xk α) ∈ X and (∀xk α) ∈ X for all k ∈ N0 If t ∈ T erm, then V ar(t) denotes the set of all elements of X, which occur in T . For ϕ ∈ F ORM the set V ar(ϕ) of all variables of ϕ is defined by • V ar(Pj (t1 , ..., tmj )) := V ar(t1 ) ∪ ... ∪ V ar(tmj ) • V ar(¬α) := V ar(α) and V ar(α ◦ β) := V ar(α) ◦ V ar(β) for all ◦ ∈ J0 • V ar(∃xk α) = V ar(∀xk α) := V ar(α) ∪ {xk } (α, β ∈ F ORM ). The set f r(ϕ) of free variables of ϕ is defined by • f r(ϕ) := V ar(ϕ) if ϕ is an atom • f r(¬α) := f r(α) and f r(α ◦ β) := f r(α) ◦ f r(β) for all ◦ ∈ J0 • f r(∀xk α) = f r(∃xk α) := f r(α)\{xk } (α, β ∈ F ORM ). The set bd(ϕ) of bound variables of ϕ is defined by • bd(ϕ) := ∅ if ϕ is an atom • bd(¬α) := bd(α) and bd(α ◦ β) := bd(α) ◦ bd(β) for all ◦ ∈ J0 • bd(∀xk α) = bd(∃xk α) := bd(α) ∪ {xk } (α, β ∈ F ORM ). – ϕ is called open formula if bd(ϕ) = ∅. ϕ is a sentence or is closed, if f r(ϕ) = ∅. Obviously, V ar(ϕ) = f r(ϕ) ∪ bd(ϕ), but f r(α) ∩ bd(ϕ) need not be empty. Let u, u be mappings from V ar into A. Then we write u =xk u iff u(xj ) = u (xj ) for all j = k. Let A := (A; (fi )i∈I , (Rj )j∈J ) be a structure of signature δ and let u : V ar −→ A be a mapping. For u, there is exactly one homomorphism u : T(Var) −→ (A; (fi )i∈I ), which u continues (see Part I, Theorem 6.2.2). In the following manner, one can interpret the elements of F ORM with the aid of A, u and u : An interpretation function (or valuation) is a mapping vA,u from F ORM into {0, 1} defined by • vA,u (Pj (t1 , ..., tmj )) = 1 iff ( u(t1 ), ..., u (tmj )) ∈ RjA • vA,u (¬α) := ¬(vA,u (α)) and vA,u (α ◦ β) := vA,u (α) ◦ vA,u (β) for all ◦ ∈ J0 • vA,u (∀xk ϕ) = 1 iff v A,u (ϕ) = 1 for all u with u =xk u (i.e., vA,u (∀xk ϕ) = u , u=x u vA,u (ϕ)) k • vA,u (∃xk ϕ) = 1 iff there is a u with u =xk u and vA,u (ϕ) = 1 (i.e., vA,u (∃xk ϕ) = u , u=x u vA,u (ϕ) ) k
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ϕ ∈ F ORM is satisfied by u : V ar −→ A iff vA,u (ϕ) = 1. ϕ is true (or valid) in A, iff vA,u (ϕ) = 1 for all u : V ar −→ A. A |= ϕ stands for “ϕ is true in A”. A |= ϕ stands for “ϕ is not true (or false) in A”. If A |= ϕ, we call A a model of ϕ. In general, if A |= σ for all σ ∈ Σ ⊆ F ORM , we call A a model of Σ. Notice that a closed formula of F ORM is either true or false in A. Formulas α, β ∈ F ORM are equivalent (in symbol α ≡ β) iff vA,u (α) = vA,u (β) for every structure A and for every u : V ar −→ A. The following theorem is easy to prove: Theorem 1.5.2.3 Let ϕ, ψ ∈ F ORM . Then: (1) ¬∀xk ϕ ≡ ∃xk ¬ϕ, ¬∃xk ϕ ≡ ∀xk ¬ϕ; (2) if xk ∈ f r(ψ) then (Qxk ϕ ◦ ψ) ≡ Qxk (ϕ ◦ ψ) for all Q ∈ {∃, ∀} and ◦ ∈ {∧, ∨}; (3) (∀xk ϕ ∧ ∀xk ψ) ≡ ∀xk (ϕ ∧ ψ), (∃xk ϕ ∨ ∃xk ψ) ≡ ∃xk (ϕ ∨ ψ); (4) ∀xk ∀xl ϕ ≡ ∀xl ∀xk ϕ, ∃xk ∃xl ϕ ≡ ∃xl ∃xk ϕ. Next, we define the mappings repτ , tutτ and subτ from F ORM into F ORM , where τ is a mapping from V ar into T erm. With repτ , one can describe the replacement of variables by some terms in a formula from F ORM . The mapping tutτ renames the bound variables of a formula so that there are no variables of the formula anymore, which is free and bound. subτ is a combination of repτ and tutτ . Let τ : V ar −→ T erm be an arbitrary mapping and τ : T erm −→ T erm the unique homomorphic continuation of τ . Then the mapping repτ : F ORM −→ F ORM is defined by • repτ (Pj (t1 , ..., tmj )) := Pj ( τ (t1 ), ..., τ(tmj )) • repτ (¬α) := ¬repτ (α) and repτ (α ◦ β) := repτ (α) ◦ repτ (β) for all ◦ ∈ J0 • if ϕ = Qxk α with Q ∈ {∀, ∃}, then repτ (ϕ) := Qxk repτ (α), where xk if xi = xk , τ (xi ) := τ (xi ) if xi = xk . For the mapping τ : V ar −→ T erm and ϕ ∈ F ORM let n(τ, ϕ) be the smallest number j0 ∈ N0 with xj ∈ f r(ϕ) ∪ V ar(τ (x)) for all x ∈ f r(ϕ). Let tutτ : F ORM −→ F ORM be defined by • tutτ (ϕ) = ϕ if ϕ is an atom • tutτ (¬ϕ) = ¬(tutτ (ϕ)) and tutτ (ϕ ◦ ψ) = tutτ (ϕ) ◦ tutτ (ψ) for all ◦ ∈ J0 ; • for Q ∈ {∀, ∃} let tutτ (Qxk ϕ) = Qxj tutτ (repτk,j (ϕ)) with j := n(τ, ϕ) and xj if k = l, τk,j (xl ) := xl otherwise.
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For τ : V ar −→ T erm and arbitrary ϕ ∈ F ORM set subτ (ϕ) := repτ (tutτ (ϕ)). The following lemma gives some properties of the above mappings: Lemma 1.5.2.4 (without proof ) Let A be a structure of signature δ, u : V ar −→ A a mapping with the homomorphic continuation u : T erm −→ A. Then: (a) vA,u (ϕ) = vA,u (tutτ (ϕ)); (b) f r(ϕ) = f r(tutτ (ϕ)); (c) vA,τ u (ϕ) = vA,u (subτ (ϕ)). With the aid of the above mapping, we can describe the Hilbert-typecalculus for the classical predicative logic, which consists of following axioms and rules: (I) axioms are: (a) the axioms (A1) - (A13) of the classical propositional logic; (b) all formulas of the form (A14) (∀xk ϕ) ⇒ subτ (ϕ), where τ =xk id (i.e, τ replaces something at most for the variable xk ); (A15) ∃xk ϕ ⇒ ¬∀xk ¬ϕ, ¬∀xk ¬ϕ ⇒ ∃xk ϕ; (A16) subid (ϕ) ⇒ ϕ. (II) rules are: (a) the modus ponens; (b)
ϕ ⇒ subτk,l (ψ) ϕ ⇒ ∀xk ψ,
where
τk,l (xj ) :=
xl if j = k, xj otherwise
and xl ∈ V ar(ψ) ∪ f r(ϕ) (“∀-introductory-rule”); (c) ϕ subτ (ϕ) for all τ . Analogously to the proportional logic, one can define and cons(Σ) for Σ ∈ F ORM in respect to the above calculus. The completeness theorem of the first order logic says that = |= holds, i.e., cons(Σ) = Cons(Σ) is valid for all Σ ⊆ F ORM and that there are axioms and rules, so that = |= was proven for the first time by K. G¨ odel in his dissertation 1929. For the above calculus one can prove the completeness theorem for first order
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logic similar to Theorem 1.5.2.2, where the Rasiowa-Sikorski-Tarski-Lemma is needed (see [Ric 78] for details). The famous incompleteness theorems of G¨odel say that second order logic 11 does not have a completeness theorem in general.
1.5.3 Many-Valued Logics The above considerations can be generalized when one assigns the “sentences” certain values from the set Ek (k ≥ 3). We receive then a so-called k-valued logic or many-valued logic. One finds a full introduction to the logic for example in [Got 89] or [Kre-G-S 88]. From a mathematical perspective it doesn’t matter which interpretations have the elements of Ek . Nevertheless, it is shown which interpretations of the elements of Ek , for example, are possible. According to these interpretations, one can select certain functions of Pk , with which one can form many-valued logics. For reasons of space limitations, we have excluded information. These functions can be found in [Men 85], where literature on the topic is also provided. 1.5.2.1 The three values of a three-valued logic can be interpreted as follows: “false”, “indefinite”, “true”; “false”, “possible”, “true”; “false”, “undecidable”, “true” or “invalid”, “in part valid”, “full-valid”. Legally relevant actions can be divided in “punishable”, “prohibited but not punishable”, “allowed”. 1.5.2.2 The 4-valued logic seems particularly suitable for analyzing problem areas logically, in which there are two different kinds of truth (or validity) and two different kinds of falsehood (or nullity). Examples: “fact falsehood”, “legal nullity”, “legal validity”, “fact truth” ; “knowledge falsehood”, “belief falsehood”, “belief truth”, “knowledge truth”. 1.5.2.3 A legal interpretation of the 6-valued logic is, for example, 0: “logically false”, 1: “legally invalid”, 2: “false according to facts”, 3: “true according to facts”, 4: “legally valid”, 5: “logically true”. 11
In this logic, quantifications over elements of a structure as well at quantifications over partial sets and relations of the structure are allowed.
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1.5.2.4 Instead of Ek , one can also choose a finite subset of the real numbers x with 0 ≤ x ≤ 1. Then, with the aid of such a set, a probability logic can be formed: The value 1 corresponds to the certainty of the truth; the value 0.5 corresponds to the uncertainty, whether true or false; the value 0 corresponds to the certainty of the falsehood (or the impossibility); values between 1 and 0.5 correspond to degrees of higher probability; values between 0.5 and 0 correspond to degrees of low probability. We notice that one could also have chosen the interpretation of the Fuzzy Logic instead of the above-mentioned probability logic (see for example [BanG 90] or [Til 92]). The problems of all the above-mentioned logics correspond basically to those of the propositional logic. 1.5.4 Information Transformer The functions f n ∈ PA can be understood simply as mathematical models of objects that process information (see Figure 1.1). The “object” from Figure 1.1 receives the information x1 , ..., xn ∈ A at the entries, processed to the information f (x1 ..., xn ) ∈ A. In this case, we neglect the time which is needed for the workmanship. x1 x2 ... xn
f
x ) f (x1 , ..., n Fig. 1.1
Superpositions over functions of PA correspond with this model to the “assembling” of such objects. For example, one can describe the diagram x1
x2
x3
f
g
g(f (x1 , x2 ), x3 , x3 ) Fig. 1.2
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through the formula g(f (x1 , x2 ), x3 , x3 ). In particular, Boolean functions are used for the mathematical description of electrical circuits or components in computers. This mathematical description is independent of the concrete technical realization (as, for example, relay contact circuits or transistors). Naturally, one receives the so-called completeness problem from these interpretations of the functions from PA : A necessary and sufficient criterion is searched in order to be able to decide whether a system of certain selected functions (which correspond to certain elementary elements) produces all functions from PA by means of superposition. One way of finding this criterion indicates the following theorem: Theorem 1.5.4.1 Let A be a subclass of Pk with the property that to every proper subclass A of A there exists a certain maximal class M of A with A ⊆ M . Furthermore, denote M the set of all maximal classes of A. Then for an arbitrary subset T of A it holds: [T ] = A ⇐⇒ ∀M ∈ M : T ⊆ M.
(1.15)
Proof. “=⇒”: Let [T ] = A. Suppose there is an M ∈ M with T ⊆ M . Then, a contradiction results; however, from that, immediately, A = [T ] ⊆ [M ] = M ⊂ A. “⇐=”: Let T ⊆ Pk be no subset of a maximal class of A. Suppose, [T ] ⊂ A. Then, by assumption, one can find a certain maximal class M ∈ M with [T ] ⊆ M , a contradiction to the supposition. By Theorem 11.1.1, every finitely generated class fulfills the conditions of Lemma 1.5.3.1 and has only finitely many maximal classes, whereby (1.15) supplies a criterion of the wanted kind if one knows the maximal classes of A. Further problems that result from interpreting the functions of PA as information transformers are the following: • Find minimal generating systems, where “minimal” is related to the number of the generating system’s functions or to the arities of the generating system’s functions. • Find algorithms to construct a minimal realization of a given function by certain elementary functions. One can find further problems and their solutions in [Rin 84] and [P¨ os-K 79].
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1.5.5 Classification of Combinatorial Problems In this section, we need some notations (Rk , P olk , Invk , ...) of Chapter 2. Further, we need some concepts of the algorithm theory:12 Algorithms are techniques for solving problems, wherein the word “problem” is used in a very general sense: A problem class consists of infinitely many instances having a common structure. A problem, whose solution is either “yes” or “no”, is called a decision problem. Often, finding a solution algorithm for the solution of a mathematical problem does not suffice. Statements about the complexity of the algorithms are important for the applicability of algorithms in particular. The complexity of an algorithm is a function f (n), which gives the number of the arithmetic steps (e.g. value assignments, elementary arithmetic operations, comparison operations, ...) which are necessary to the estimating of a solution of a given problem with n master data. For g : N −→ R+ let O(g(n)) := {f (n) | (f : N −→ R+ ) ∧ (∃c > 0 ∀n ∈ N : f (n) ≤ c · g(n))} We say that the algorithm has the complexity O(g(n)), if the complexity f (n) of the algorithm belongs to O(g(n)). Generally one holds algorithms with a complexity O(nt ) for “good” and these algorithms are called polynomial algorithms. A decision problem with the complexity O(nt ), where n, t ∈ N, is called tractable. Let P be the class of all tractable problems. L denotes the class of all problems with the complexity O(log n). The class of decision problems for which a positive answer can be verified in polynomial time is denoted by NP (for “non-deterministic polynomial”). That is, we do not only require the answer “yes” or “no”, but the explicit specification of a certificate which allows to verify the correctness of a positive answer. LP denotes the class of decision problems for which a positive answer can be verified in logarithmic time. Obviously, P ⊆ NP. Further, we know that L ⊆ NL ⊆ P. It is the greatest problem of the algorithm theory to decipher whether P = NP is valid. Most people believe, however, that P = NP. A problem is called NP-complete if is in NP and if the polynomial solvability of this problem would imply that all problems in NP are solvable in polynomial time as well. In other words: Each problem in NP can be “transformed” (in polynomial time) to the given NP-complete problem, such that 12
See e.g. [Pap 94] and [Jun 2005].
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a solution of the NP-complete problem also gives a solution to that other problem in NP. Therefore, if one finds a polynomial algorithm for an NPcomplete problem, this would imply that P = NP. Next, is a short introduction to some papers that deal with classifications of combinatorial problems. Definition A CSP (or a “constraint satisfication problem”) is a triple (V, D, C), where • V is a set of variables • D is a set of values which can take the variables • C := {C1 , C2 , ..., Cq } with Ci := (si , τi ) for i = 1, ..., q, where si is an mi -ary tuple of variables and τi is an mi -ary relation on D (Ci is called constraint). A solution of the CSP is a mapping f : V −→ D with the property ∀ Ci := ((xi1 , xi2 , ..., ximi ), τi ) ∈ C : (f (xi1 ), f (xi2 ), ..., f (ximi )) ∈ τi . Many combinatorial problems can be described as CSP (see [Jea 97] 13 ) Example The problem SAT as CSP An instance of the standard propositional satisfiability problem is specified by giving a formula on propositional logic, and asking whether there are values for the variables that make the formula true. For example, consider the formula t(x1 , x2 , x3 , x4 ) := (x1 ∨ x2 ∨ x3 ∨ x4 ) ∧ (x1 ∨ x2 ∨ x3 )∧ (x3 ∨ x4 ∨ x1 ) ∧ (x3 ∨ x2 ∨ x4 ) ∧ (x1 ∨ x3 ). The question is whether there are a1 , a2 , a3 , a4 ∈ {0, 1} with t(a1 , a2 , a3 , a4 ) = 1. This problem can be expressed as the CSP as follows: Put V := {x1 , x2 , x3 , x4 }, D := {0, 1}, C1 C2 C3 C4 C5 C
:= := := := := :=
((x1 , x2 , x3 , x4 ), D4 \ {(0, 0, 0, 0)}), ((x1 , x2 , x3 ), D3 \ {(1, 1, 0)}), ((x3 , x4 , x1 ), D3 \ {(1, 1, 0)}), ((x3 , x2 , x4 ), D3 \ {(1, 1, 0)}), ((x1 , x3 ), D2 \ {(1, 1)}), {C1 , c2 , C3 , C4 }.
The solutions of the above problem are 13
In this paper are 20 combinatorial problems expressed as CSP.
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x1 x2 x3 x4 f1 f2 f3 f4 f5 f6
: : : : : :
0 0 0 0 1 1
0 0 1 1 0 0
0 1 0 0 0 0
1 0 0 1 0 1
It is also possible to describe a CSP with the aid of the following notations: Definitions Let V be a nonempty set and let τ1 , τ2 , ..., τt be relations on V . Then, (V ; τ1 , τ2 , ..., τt ) is called relational structure. The mapping : {1, 2, ..., t} −→ N is the rank functions of the relational structure (V ; τ1 , τ2 , ..., τt ) if (i) is the arity of the relation τi (i = 1, 2, ..., t). A relational structure Σ is similar to a relational structure Σ if they have the same rank function. Let Σ := (V ; τ1 , ..., τt ) and Σ := (V ; τ1 , ..., τt ) be two similar relational structure, and let be their common rank function. A homomorphism from Σ into Σ is a mapping h : V −→ V such that ∀i ∈ {1, ..., t} : (a1 , .., ahi ) ∈ τi =⇒ (h(a1 ), ..., h(ahi )) ∈ τi . Let Hom(Σ, Σ ) be the set of all homomorphisms from Σ into Σ . Obviously, it holds that Theorem 1.5.5.1 ([Jea-C-P 98]) (a) Let P := (V, D, C) be a CSP with C := {(s1 , τ1 ), (s2 , τ2 ), ..., (sq , τq )}. Then, the set of all solutions of P is the set Hom(Σ, Σ ), where Σ := (V ; {s1 }, {s2 }..., {sq }) and Σ := (D; τ1 , τ2 , ..., τq ). Conversely: Let Σ := (V ; τ1 , ..., τt ) and Σ := (D; τ1 , ..., τt ) be two similar relational structures. Then, Hom(Σ, Σ ) is the set of all solutions of the CSP (V, D, S) with C :=
t
{(s, τi ) | s ∈ τi }.
i=1
The following theorem is our first example of an application of P ol and Inv (see Chapter 2) in algorithm theory.
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Theorem 1.5.5.2 Let D := Ek , Γ := {1 , ..., q } ⊆ Rk , V := {x1 , ..., xn } and let M be a set of mappings from V into Ek . Then it holds: There exists a CSP (V , D, C), where V ⊆ V and C = {(c1 , 1 ), ..., (cq , q )}, with the solution set S and S|V = M if and only if := {(f (x1 ), ..., f (xn )) | f ∈ M } ∈ Invk (P olk Γ ). The proof of the above theorem is explained by subsequent examples: We choose: D := E2 , 1 := {(0, 1, 1), (1, 0, 0), (1, 1, 1)}, 2 := {(0, 0), (1, 0)}, 3 := {(1, 1)}, Γ := {1 , 2 , 3 }, V := {x1 , x2 , x3 , x4 } and M := {f1 , f2 }, where x f1 (x) f2 (x) x1 0 1 x2 1 0 x3 1 1 x4 1 1 “⇐=”: Assume, := {(f (x1 ), ..., f (xn )) | f ∈ M } ∈ Invk (P olk Γ ). Then can be obtained by a finite number of applications of the elementary operations 3 (see Section 2.3). For example: ζ, τ, pr, ∧ and × from and δk;{1,2} = {(x1 , x2 , x3 , x4 ) ∈ E24 | ∃x5 ∈ E2 : (x1 , x5 , x3 ) ∈ 1 ∧ (x5 , x2 ) ∈ 2 ∧ (x5 , x4 ) ∈ 3 }. Therefore, V = {x1 , x2 , x3 , x4 , x5 } and (V , D, C), where C := {((x1 , x5 , x3 ), 1 ), ((x5 , x2 ), 2 ), ((x5 , x4 ), 3 )}, is a CSP with the solution set S = {f1 , f2 }, where x f1 (x) f2 (x) x1 0 1 x2 1 0 x3 1 1 x4 1 1 x5 1 1 and S|V = M = {f1 , f2 }. “=⇒”: Choose V := {x1 , x2 } and M := {g1 , g2 }, where x g1 (x) g2 (x) x1 0 1 x2 0 0 ({x1 , x2 , x3 , x4 , x5 }, E2 , C) with C := {((x1 , x5 , x3 ), 1 ), ((x5 , x2 ), 2 ), ((x5 , x4 ), 3 )} is a CSP and it holds S|V = M = {g1 , g2 }. Then
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1 Basic Concepts, Notations, and First Properties
= {(0, 0), (1, 0)} = {(x1 , x2 ) ∈ E22 | ∃x3 ∈ E2 ∃x4 ∈ E2 ∃x5 ∈ E2 : (x1 , x5 , x3 ) ∈ 1 ∧ (x5 , x2 ) ∈ 2 ∧ (x5 , x4 ) ∈ 3 } Thus ∈ Invk P olk Γ (see Chapter 2). Next we show how one can use the above theorem for solving the following task: Put D := E2 , Γ
:= { ⊆ E22 | = ∅} =: {1 , ..., 15 },
x f1 (x) f2 (x) f3 (x) x1 0 0 0 M := {f1 , f2 , f3 }, where x2 0 0 1 x3 0 1 0 x4 1 0 0 Is there a CSP (V , E2 , C) with V ⊆ V , C = {((c1 , 1 )), ..., (c1515 )} and the solution set S which ones S|V = M is valid for? Because of the above theorem, this question is equivalent for the following question: := {(f (x1 , ..., f (x4 ))) | f ∈ M } = {(0, 0, 0, 1), (0, 0, 1, 0), (0, 1, 0, 0)} ∈ Inv2 P ol2 Γ ? With the help of the results of Chapter 3, it is easy to prove that P ol2 Γ =
15
P ol2 i = [h2 ],
i=1
where h2 (x, y, z) := (x ∧ y) ∨ (x ∧ z) ∧ (y ∨ z). Then, because of ⎛ ⎞ ⎛ ⎞ 0 0 0 0 ⎜0 0 1⎟ ⎜0⎟ ⎟ ⎜ ⎟ h2 ⎜ ⎝0 1 0⎠=⎝0⎠ 1 0 0 0 we have ∈ Inv2 P ol2 ; i.e., there is no CSP with the above properties. Definitions The general combinatorial problem (GCP) is the decision problem with: Instance: A pair (Σ1 , Σ2 ) of similar finite relational structures Σ1 and Σ2 . Question: Is there a homomorphism from Σ1 to Σ2 ? For any GCP instance P := (Σ1 , Σ2 ) a homomorphism from Σ1 to Σ2 will be called a solution of P .
1.5 Some Applications of the Function Algebras
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The GCP (or CSP) is known to be NP-complete. However, certain restrictions may affect the complexity of GCP (or CSP). One of the natural possibilities for restricting CSP is by limiting the relations that can appear in constraints (or relational structures). Definition Let Γ be a set of relations on the set D. Denote by CSP(Γ ) the subclass of CSP defined by the following property: any constraint relation in any instance must belong to Γ . The next theorem is the basis for the following theorems. Theorem 1.5.5.3 ([Jea 98]; without proof ) Let Γ and Ψ be finite sets of relation on D (w.l.o.g. we put D := Ek ). If Ψ ⊆ Invk (P olk Γ ) then GCP(Ψ ) can be reduced in polynomial time to GCP(Γ ). In other words: For any finite set Γ ⊆ Rk , the complexity of GCP(Γ ) is determined, up to polynomial-time reductions, by P olk Γ . Theorem 1.5.5.4 ([Jea 98]; without proof ) Let D := Ek , k ≥ 2 and Γ ⊆ Rk . Then (1) GCP(Γ ) ⊆ P, if one of the following conditions is valid: (a) P olk Γ contains a constant function. (b) P olk Γ contains a binary function which is associative, commutative and idempotent. (c) r ∈ P olk Γ , where r(x, y, z) := x + y + z and (Ek ; +) is Abelian 2group. (2) If P olk Γ contains a ternary function ϕ defined by y if y = z, ϕ(x, y, z) := x otherwise, then GCP(Γ ) ⊆ NL. (3) If each function of P olk Γ is either a projection or a semiprojection, then GCP(Γ ) is NP-complete. With the aid of the above theorem and Post’s description of all closed sets of Boolean functions, one can prove the following: Theorem 1.5.5.5 ([Sch 78]) For arbitrary Γ ⊆ R2 it holds: GCP(Γ ) is NP-complete, if P ol2 Γ ⊆ [P21 ]; in all other cases we have GCP(Γ ) ⊆ P. More can be found on the topic in [Jea 98], [Jea-C-P 98], [Bul-K-J 2000] and [Coh-J-G 2003].
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2 The Galois-Connection Between Function- and Relation-Algebras
This section aims to develop a “suitable” means to describe function algebras or clones. I mean, suitable in the sense that “big” function algebras (or clones) can be described with an “expenditure” as small as possible. Analogously to other fields of algebra we introduce invariants for our function algebras. The two papers [Bod-K-K-R 68/69] of V. G. Bodnarˇcuk, L. A. Kaluˇznin, V. N. Kotov and B. A. Romov are basis of this so-called Pol-Inv theory (or Galois theory for function- and relation-algebras). These articles generalize results by M. Krasner on a Galois theory for groups (see [Kra 45], [Kra 68/69]). A full representation of the Pol-Inv theory with many applications can be found in the monograph [P¨ os-K 79] by R. P¨ oschel and L. A. Kaluˇznin.
2.1 Relations An h-ary relation on Ek is a subset of the h-fold Cartesian product Ekh of the set Ek , h ∈ N. The elements (a1 , a2 , ..., ah ) of (we say “h-tuple”) are written as columns ⎞ ⎛ a1 ⎜ a2 ⎟ ⎟ ⎜ ⎝ ... ⎠ , ah and then we also write
⎛
⎞ a1 ⎜ a2 ⎟ ⎜ ⎟ ⎝ ... ⎠ ∈ . ah
The relation is written often as a matrix whose columns are the elements of the relation. For example,
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2 The Galois-Connection Between Function- and Relation-Algebras
⎞ a1 a1 a1 := ⎝ ... ... ... ⎠ ah ah ah ⎛
instead of := {(a1 , ..., ah ), (a1 , ..., ah ), (a1 , ..., ah )}. We think of this matrix representation of if we subsequently talk about the length h and the width || of the relation as well as about rows from . Denote Rkh the set of all h-ary relations on Ek and let Rk := Rkh . h≥1
We remark that the empty set is an element of Rk . If Q ⊆ Rk then let Qh := Q ∩ Rkh .
2.2 Diagonal Relations The simplest relations, in a certain sense1 , are the diagonal relations (or diagonals) defined as follows: For an arbitrary equivalence relation ε on {1, 2, ..., h} let h δk,ε := {(a1 , ..., ah ) ∈ Ekh | (i, j) ∈ ε =⇒ ai = aj }.
If h or k follows from the context, then we write only δε or δεh or δk,ε . Every element of the set h Dkh := { δk,ε | ε is an equivalence relation on {1, 2, ..., h} }.
is called a diagonal h-ary relation. Let Dk := {∅} ∪
Dkh
h≥1
be the set of all diagonal relations. h , we often declare this For the purpose of a more simple description of δk,ε relation in the form h δk;ε 1 ,...,εr or, briefly, by δε1 ,...,εr , where ε1 , ..., εr are exactly the equivalence classes of ε, which have at least two elements. In particular, we have h δk; = Ekh
and 1
See Theorem 2.5.1.
h = {(x, x, ..., x) ∈ Ekh | x ∈ Ek }. δk;E k
2.4 Relation Algebras, Co-Clones, and Derivation of Relations
127
2.3 Elementary Operations on Rk We define in this section some operation ζ, τ, pr, ∧ and × on Rk with whose aid we can form later more “complex” operations on Rk . We call, therefore, the operations ζ, τ, pr, ∧ and × the elementary operations on Rk .
Let ∈ Rkh and ∈ Rkh , where h, h ∈ N. Then, if = ∅ and = ∅, let ζ ∈ Rkh , τ ∈ Rkh , pr ∈ Rkh−1 for h ≥ 2 and pr = ∅ for h = 1, × ∈ Rkh+h and ∧ ∈ Rkh (only for h = h ) defined by: ζ := {(a2 , a3 , ..., ah , a1 ) | (a1 , a2 , ..., ah ) ∈ } (cyclical exchanging of the rows), τ := {(a2 , a1 , a3 , ..., ah ) | (a1 , a2 , ..., ah ) ∈ } (exchange of the first two rows) for h ≥ 2 and ζ = τ = for h = 1 or = ∅; pr := {(a2 , ..., ah ) | ∃a1 ∈ Ek : (a1 , a2 , ..., ah ) ∈ } (projection onto the 2th,..., h-th coordinate or the strike of the first row) for h ≥ 2, × := {(a1 , ..., ah , b1 , ..., bh ) | (a1 , a2 , ..., ah ) ∈ ∧ (b1 , b2 , ..., bh ) ∈ } (Cartesian product of and ) and ∧ := {(a1 , ..., ah ) | (a1 , ..., ah ) ∈ ∩ } (intersection of the relations and ).
2.4 Relation Algebras, Co-Clones, and Derivation of Relations The algebra
3 , ζ, τ, pr, ∧, ×) Rk := (Rk ; δk;{1,2}
of type (0, 1, 1, 1, 2, 2) is called full relation algebra on Ek . Every subalgebra Q of Rk (in symbol Q ≤ Rk ) is a relation algebra on Ek . Let Q ⊆ Rk . Then, [Q] denotes the set of all relations of Rk that can be obtained by a finite number of applications of the elementary operations 3 ,i.e., [Q] is the universe of ζ, τ, pr, ∧ and × from the relations of Q and δk;{1,2} the smallest relation algebra, which contains Q. If [Q] = Q (⊆ Rk ) we say that Q is closed or Q is a co-clone of Rk . Further, we say a relation can be derived from the relation (or is -derivable), if ∈ [{}]. In this case we also write: .
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2 The Galois-Connection Between Function- and Relation-Algebras
2.5 Some Operations on Rk Derivable from the Elementary Operations We say that an operation on Rk is derivable from the elementary operations ζ, τ, pr, ∧ and × (or {ζ, τ, pr, ∧, ×}-derivable), if their effect on an arbitrary relation ∈ Rk can also be described by the effect of a finite com3 on . position of the elementary operations and δk;{1,2} The following is a small list of such derivable operations. In this case, always describes an h-ary and an h -ary relation of Rk . (O1 ): Permutation of coordinates (or permutations of rows). As is known, the permutations 1 2 ... h − 1 h 1 2 3 ... h and 2 3 ... h 1 2 1 3 ... h form a generating system for the symmetric group Sh (i.e., for the set of all permutations on {1, 2, ..., h} with the operation ). Consequently one can realize all rearrangements of the rows of with the aid of ζ and τ . Thus, for every s ∈ Sh , σs () := {(as(1) , ..., as(h) ) | (a1 , ..., ah ) ∈ } is a {ζ, τ, pr, ∧, ×}-derivable operation. (O2 ): Projection onto the α1 -th, ..., αt -th coordinates (or deleting of rows). For {α1 , ..., αt } ⊆ {1, 2, .., h} it holds: prα1 ,...,αt () := {(aα1 , ..., aαt ) | (a1 , .., ah ) ∈ } = pr(pr(...(pr (σs ()))...)), h−t times where s ∈ Sh and s(α1 ) = h − t + 1, s(α2 ) = h − t + 2, ..., s(αt ) = h. In particular, we have prs(1),...,s(n) () = σs (). We remark that, in the case where is given in the form {(a0 , a1 , ..., ah−1 ) | ....}, we choose {α1 , ..., αt } ⊆ {0, 1, 2, .., h − 1} and define prα1 ,...,αt () in analog manner, as above.
2.5 Some Operations on Rk Derivable from the Elementary Operations
129
(O3 ): Identification of coordinates. For i, j ∈ {1, 2, ..., h} and i = j let ∆i,j () := {(a1 , ..., aj−1 , aj+1 , ..., ah ) | (a1 , ..., aj−1 , ai , aj+1 , ..., ah ) ∈ } and ∆ := ∆1,2 . ∆i,j can be formed as follows: 3 ) = Ek and It is easy to prove that pr1 (δk;{1,2} h δk;{i,j} = pr1,...,i−1,h+1,i+1,...,j−1,h+2,j+1,...,k (1 ), 3 and i < j. Consequently, ∆i,j is where 1 := Ek × ... × Ek ×pr1,2 δk;{1,2} h−2 times derivable because of h ∆i,j = pr1,...,j−1,j+1,...,h ( ∧ δk,{i,j} ).
(O4 ): Doubling of coordinates (rows). One receives a doubling of the i-th row of as follows: νi () := {(a1 , ..., ai−1 , ai , ai , ai+1 , ..., ah ) | (a1 , ..., ah ) ∈ } 3 = pr1,...,i−1,h,h+1,,i,...,h−1 (∆i,h+1 ( × pr(δk;{2,3} )).
(O5 ): Adding of fictitious coordinates. Let ∇ := {(a1 , ..., ah+1 )|a1 ∈ Ek ∧ (a2 , ..., ah+1 ) ∈ }. The first coordinate of ∇ is a so-called fictitious coordinate. Then, with the aid of (O1 ) one can derive the relation ∇i := {(a1 , ..., ai−1 , ai , ai+1 , ..., ah+1 ) ∈ Ekh+1 | (a1 , ..., ai−1 , ai+1 , ..., ah+1 ) ∈ } for i ∈ {1, ..., h + 1}. (O6 ): General composition (relation product). Let ◦t := {(a1 , ..., ah−t , bt+1 , ..., bh ) | ∃u1 , ..., ut ∈ Ek : (a1 , ..., ah−t , u1 , ..., ut ) ∈ ∧ (u1 , ..., ut , bt+1 , ..., bh ) ∈ } for t ∈ N with t ≤ h and t ≤ h . In particular, o := o1 . For h = h = 2, ◦ is the well-known relation product . The following theorem results from the above considerations.
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2 The Galois-Connection Between Function- and Relation-Algebras
Theorem 2.5.1 Every co-clone Q of Rk contains all diagonal relations and is closed in respect to – permutation of coordinates (rows), – projection onto coordinates (or deleting of rows), – identification of coordinates (rows), – doubling of coordinates (rows), – adding of fictitious coordinates, – (finite) intersection formation, – Cartesian products and – general composition.
2.6 The Preserving of Relations; Pol, Inv We say that a function f n ∈ Pk preserves the relation ∈ Rkh (or is invariant for f or is a invariant for f ), if ⎛ ⎛ ⎞ ⎞ f (a11 , a12 , ..., a1n ) a11 a12 ... a1n ⎜ f (a21 , a22 , ..., a2n ) ⎟ ⎜ a21 a22 ... a2n ⎟ ⎜ ⎟ ⎟ f⎜ ⎝ . . . . . . . . . . . . . . . ⎠ := ⎝ . . . . . . . . . . . . . . . . . . ⎠ ∈ ah1 ah2 ... ahn f (ah1 , ah2 , ..., ahn ) for all
⎛
⎞ ⎛ a11 a12 ⎜ a21 ⎟ ⎜ a22 ⎜ ⎟ ⎜ ⎝ ... ⎠ , ⎝ ... ah1 ah2
⎞
⎛
⎞ a1n ⎟ ⎜ ⎟ ⎟ , ..., ⎜ a2n ⎟ ∈ . ⎠ ⎝ ... ⎠ ahn
The empty set ∅ is preserved by every function f ∈ PA . Note that f preserves iff is the universe of a subalgebra (A; f )h . By P olk or, briefly, P ol we denote the set of all functions f ∈ Pk that preserve the relation . For Q ⊆ Rk , we put P olk . P olk Q := ∈Q
P olk or P olk Q is a short-cut of polymorphisms of or Q, respectively. The set of all relations ∈ Rk that are preserved from the function f ∈ Pk is Invk f. For A ⊆ Pk let
2.6 The Preserving of Relations; Pol, Inv
Invk A :=
131
Invk f
f ∈A
be the set of all invariants of A and let (Invk A)n := (Invk A) ∩ Rkh be the set of all n-ary invariants of A. If k can be seen from the context, we write Inv instead of Invk . Further notations used by us are P oln Q := (P ol Q)n (Q ⊆ Rk or Q ∈ Rk ) and
Inv n A := (Inv A)n (A ⊆ Pk or A ∈ Pk )
for n ∈ N. Elementary connections between P ol and Inv are summarized in the following theorem. Theorem 2.6.1 For arbitrary A, B ⊆ Pk and arbitrary S, T ⊆ Rk , it holds: (a) A ⊆ B =⇒ Inv B ⊆ Inv A, S ⊆ T =⇒ P ol T ⊆ P ol S; (b) A ⊆ P ol Inv A, S ⊆ Inv P ol S; ((a) and (b) mean that the pair (P ol, Inv) of mappings P ol : P(Pk ) −→ P(Rk ), A → P olk A and P ol : P(Rk ) −→ P(Pk ), Q → Invk Q is a Galois connection (see Part I, 4.4) between the sets Pk and Rk .) (c) Inv P ol Inv A = Inv A, P ol Inv P ol S = P ol S; (d) A ⊆ P ol S ⇐⇒ S ⊆ Inv A; (e) P ol (S ∪ T ) = P ol S ∩ P ol T , Inv A ∪ B = Inv A ∩ Inv B. Proof. (a), (b), (d), and (e) are direct conclusions from the definitions of P ol and Inv. (c): Let S := Inv A. By (b) we have S ⊆ Inv P ol S. Conversely, it holds A ⊆ P ol Inv A and thus by (a): Inv P ol Inv A ⊆ Inv A. Therefore, Inv P ol Inv A = Inv A. Analogously, one can show that P ol Inv P ol S = P ol S holds.
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Theorem 2.6.2 For every A ⊆ Pk and every Q ⊆ Rk the sets Inv A and P ol Q are closed (in respect to the operations defined above, respectively); i.e., P ol Q is a clone of Pk and Inv A is a co-clone of Rk . Furthermore, it holds: Inv [A] = Inv A and P ol [Q] = P ol Q. In particular we have: Inv [{e21 }] = Rh and P ol Dk = Pk . Proof. Let , ∈ Inv A and f ∈ A be arbitrary. Then, f preserves the -derivable relations ζ, τ , pr, ∧ and × obviously. Thus {ζ, τ , pr, ∧ , × } ⊆ Inv A, whereby Inv A is closed. Now let f n , g m ∈ P ol Q and ∈ Q be arbitrary. Clear that, then the functions ζf, τ f and ∆f also preserve . Further, the relation is also an invariant of f g, because f (g(r1 , ..., rm ), rm+1 , ..., rm+n−1 ) ∈ holds for all r1 , ..., rm+n−1 ∈ , since g(r1 , .., rm ) ∈ . Inv [A] = Inv A follows from Inv [A] ⊆ Inv A (because of A ⊆ [A] and Theorem 2.6.1, (a)) and Inv A ⊆ Inv [A]. (By Theorem 2.6.1, (a) we have A ⊆ P ol Inv A indeed. Since P ol Inv A is closed, this implies [A] ⊆ P ol Inv A. If one uses Theorem 2.6.1, (a) again and then 2.6.1, (c), one receives Inv P ol Inv A = Inv A ⊆ Inv [A].) Analogously, one can prove P ol [Q] = P ol Q. One can easily checks the remaining statements of the theorem. A conclusion of Theorem 2.6.1, (a) and of the definition of (see Section 2.4) is the following Theorem 2.6.3 For arbitrary relations , ∈ Rk it holds: =⇒ P ol ⊆ P ol .
2.7 The Relations χn and Gn For arbitrary n ∈ N and k ∈ N\{1} denote χk;n or – if k can be seen from the context – χn the k n -ary relation, whose rows are just all (x1 , ..., xn ) ∈ Ekn that are arranged (we say “lexicographical”) unambiguously according to the following regulation:
2.7 The Relations χn and Gn
133
The tuple (x1 , ..., xn ) is before the tuple (y1 , ..., yn ), if the integer x1 · k n−1 + x2 · k n−2 + ... + xn−1 · k + xn is smaller than y1 · k n−1 + y2 · k n−2 + ... + yn−1 · k + yn . For example, the following is valid:
χ2;3
⎛
0 ⎜0 ⎜ ⎜0 ⎜ ⎜0 := ⎜ ⎜1 ⎜ ⎜1 ⎜ ⎝1 1
0 0 1 1 0 0 1 1
⎞ 0 1⎟ ⎟ 0⎟ ⎟ 1⎟ ⎟. 0⎟ ⎟ 1⎟ ⎟ 0⎠ 1
We denote the columns of χn with χ(1), ..., χ(n). Obviously, there is exactly a function fr ∈ Pkn with f (χn ) = r to every column n r ∈ Ekk . The relation n Gn (A) := {r ∈ Ekk |fr ∈ An }, which one can form with the aid of the functions fr , is called n-th graphic of A ⊆ Pk . The following theorem summarizes elementary properties of the relation Gn (A). Theorem 2.7.1 For an arbitrary clone A ⊆ Pk it holds: (a) ∀n ∈ N : Gn (A) ∈ Inv A; (b) f n ∈ An ⇐⇒ f n ∈ P ol Gn (A); (c) A ⊆ ... ⊆ P ol Gn (A) ⊆ P ol Gn−1 (A) ⊆ ... ⊆ P ol G2 (A) ⊆ P ol G1 (A); (d) A = n≥1 P ol Gn (A); (e) ∀ ∈ Inv A : ∈ [ n≥1 {Gn (A)}]; (f ) Inv A = [ n≥1 {Gn (A)}]. Proof. (a): Let g m ∈ A and r1 , ..., rm ∈ Gn (A) be arbitrary. Then g(r1 , ..., rm ) = g(fr1 , ..., frm ) = h(χn ), where
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2 The Galois-Connection Between Function- and Relation-Algebras
h(x1 , ..., xn ) := g(fr1 (x1 , ..., xn ), ..., frm (x1 , ..., xn )). Since h belongs to An , we obtain h(χn ) ∈ Gn (A). (b): If f n ∈ A, we have f n ∈ P ol for every ∈ Inv A. Consequently, f n ∈ P ol Gn (A) because of (a). On the other hand, f n ∈ Gn (A) implies the existence of a certain r ∈ Gn (A) with f n (χn ) = r; thus f = fr ∈ An is valid. (c) and (d) follow from (b) and from the clone properties. (e): Let ∈ Inv h A be arbitrary and t := ||. We show that can be derived from Gt (A) using the operation prα1 ,...,αh . Since Jk ⊆ A, we have χt ⊆ Gt (A). For every j ∈ {1, ..., h}, one can find an αj so that the j-th row of is identical with the αj -th row of χt . Because of ∈ Inv h A, it follows prα1 ,...,αh Gt (A) = ∈ [{Gt (A)}]. (f): By (e) we have Inv A ⊆ [ n≥1 {Gn (A)}]. Further, because of (a) and Theorem 2.6.2, we have [ n≥1 {Gn (A)}] ⊆ Inv A. Hence, (f) is valid.
2.8 The Operator ΓA For arbitrary A ⊆ Pk denote ΓA a mapping from Rk into Rk , which is defined for σ ∈ Rkh as follows: (2.1) ΓA (σ) := { ∈ Rk | ∈ Inv A ∧ σ ⊆ }. In the language of the Universal Algebra, ΓA (σ) is a subalgebra of (Ek ; A)h , which is generated by σ, or ΓA (σ) is the universe of the smallest subalgebra of the algebra (Ek ; A)h , which contains the set σ. Obviously, ΓA is a hull operator. Theorem 2.8.1 For an arbitrary clone A ⊆ Pk and every n ∈ N it holds: (a) ΓA (χn ) ∈ Inv A; (b) ΓA (χn ) = Gn (A); (c) An = {fr |r ∈ ΓA (χn )}. Proof. (a) follows from [Inv A] = Inv A (see Theorem 2.6.2) and the definition of ΓA (χn ). (b): Since every projection eni belongs to An , we have χn ⊆ Gn (A). Denote now an arbitrary k n -ary relation of Rk with χn ⊆ . If ∈ Inv A, then f (χn ) ∈ for every f ∈ An , i.e., Gn (A) ⊆ . Consequently, we have shown that Gn (A) ⊆ ΓA (χn ) holds. ΓA (χn ) ⊆ Gn (A) follows from Gn (A) ∈ Inv A (see Theorem 2.7.1, (a)). (c) is an easy conclusion from (b) and the definition of Gn (A).
2.9 The Galois Theory for Function- and Relation-Algebras
135
2.9 The Galois Theory for Function- and Relation-Algebras Theorem 2.9.1 Let A be a clone of Pk . Then A = P ol Inv A. Proof. By Theorem 2.6.1, (b) we have A ⊆ P ol Inv A. To prove that P ol Inv A ⊆ A let f n ∈ P ol Inv A be arbitrary. Because of Theorem 2.7.1, (a) we have that f ∈ P ol Gn (A) holds and (by Theorem 2.7.1, (b)) f ∈ An . Thus A = P ol Inv A. Theorem 2.9.2 Let Q be a co-clone of Rk . Then Q = Inv P ol Q. Proof. Let A := P ol Q. Because of Theorem 2.6.1, (b) we have Q ⊆ Inv A. To prove that Inv A ⊆ Q it is sufficient to show that Γ (χt ) ∈ Q for arbitrary t ∈ N, since [ t≥1 {ΓA (χt )}] = Inv A (see Theorem 2.7.1, (f) and Theorem 2.8.1, (b)). Let now γ := { ∈ Q|χt ⊆ }. t
Because of Ekk ∈ Q and the fact that Q is closed in respect to ∩, we have t χt ⊆ γ and γ is the smallest relation (∈ Qk ), which contains χt , in respect to cardinality. Further, we have ΓA (χt ) ⊆ γ, since γ ∈ Q ⊆ Inv A (see (2.1)). Consequently, our theorem is proven, if we can show ΓA (χt ) = γ. Suppose, ΓA (χt ) ⊂ γ. Then, there is a column r ∈ γ\ΓA (χt ). Because of At = {fs |s ∈ ΓA (χt )} (see Theorem 2.8.1, (c)) we have fr ∈ At . Consequently, there exists an m-ary relation β ∈ Inv A and certain columns r1 , ..., rm ∈ β with f (r1 , ..., rm ) ∈ β. Every row of the matrix (r1 , ..., rm ) is also a row of the matrix χt . Denote ij the number of a row of χt , which agrees with the j-th row of (r1 , ..., rm ) (j = 1, 2, ..., m). Let now t
k +m γ := pr1,2,...,kt (γ × β) ∩ δ{i . t t t 1 ,k +1},{i2 ,k +2},...,{im ,k +m}
Since Q is closed, γ belongs to Q, and by construction of γ we have χt ⊆ γ ⊆ γ. Furthermore, we have r ∈ γ\γ , since r1 , ...., rt ∈ β, fr (r1 , ..., rt ) ∈ β and fr (χt ) = r ∈ γ. With γ we received a contradiction to the choice of γ. Thus, γ = ΓA (χt ). With the aid of Theorems 2.9.1 and 2.9.2, we can prove the important properties of the P ol-Inv-connection:
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Theorem 2.9.3 (Theorem of V. G. Bodnarˇ cuk, L. A. Kaluˇ znin, V. N. Kotov and B. A. Romov; [Bod-K-K-R 68/69]) indextheorem of Bodnarˇcuk, Kaluˇznin,. Kotov and Romov Let L(Pk ) (or L(Rk )) be the set of all clones (or co-clones) of Pk (or Rk ) respectively. Then the mappings Inv : L(Pk ) −→ L(Rk ), A → Inv A and
P ol : L(Rk ) −→ L(Pk ), Q → P ol Q
are bijective mappings, which reverse the partial order ⊆, i.e., it holds ∀A, B ∈ L(Pk ) : A ⊆ B =⇒ Inv B ⊆ Inv A and
∀S, T ∈ L(Rk ) : S ⊆ T =⇒ P ol T ⊆ P ol S.
In other words: The lattices (L(Pk ), ⊆) and (L(Rk ), ⊆) are antiisomorphic. Pk
Rk
= P ol Inv A B A Inv
P ol T
B
S = Inv P ol S
Inv A
P ol S
T
Jk
Dk
Fig. 2.1
Proof. By Theorem 2.6.2, the mappings Inv and P ol are mappings from L(Pk ) (or L(Rk )) into L(Rk ) (or L(Pk )), respectively. The surjectivity and the injectivity (and then the bijectivity) of these mappings are easy conclusions from Theorem 2.9.1 and Theorem 2.9.2 (with the help of Theorem 2.6.2). The “reversal property” of P ol and Inv (in respect to ⊆) was already given in Theorem 2.6.1, (a).
2.10 Some Modifications of the P ol-Inv-Connection
137
2.10 Some Modifications of the P ol-Inv-Connection 2.10.1 Galois Theory for Finite Monoids and Finite Groups It is well-known that every finite semigroup H = (H; ◦) is isomorphic to a 1 certain subsemigroup of (P|H| ; ) and every finite group G = (G; ◦) is isomorphic to a certain subgroup of the group (S|G| ; ), where Sk := Pk1 [k] for k ∈ N. 2
Furthermore we have Lemma 2.10.1.1 For an arbitrary subset A of [Pk1 ], the set A is a clone of [Pk1 ] if and only if A = [A]∇ holds and (A1 ; ) is a subsemigroup of (Pk1 ; ) with the unit element e. In other words, a clone A ⊆ [Pk1 ] is completely determined by the monoid (A1 ; ). Because of the above properties, it is possible to derive a Galois theory for semigroups and groups from the Galois theory for function algebras (see Section 2.9). For this purpose, we define two new operations ∨ and ¬ on Rk : For arbitrary , ∈ Rkh and h ∈ N we set ∨ := ∪ (union) and
¬ := Ekh \ (negation, complement).
The following lemma supplies a reason for these new relation operations. Lemma 2.10.1.2 It holds: (a) ∀H ⊆ Pk1 : , ∈ Inv h H =⇒ ∨ ∈ Inv h H; (b) ∀G ⊆ Sk : ∈ Inv h G =⇒ ¬ ∈ Inv h G. Proof. (a): If f ∈ H ⊆ Pk1 , {, } ⊆ Inv H and r ∈ ∨ , then we have obvious r ∈ or r ∈ , whereby f (r) ∈ ∨ , since f preserves the relations and . Consequently, ∨ is also an invariant of f . (b): Let f ∈ G ⊆ Sk , ∈ Inv G and r ∈ ¬ be arbitrary. Set r := f (r). Then r belongs to ¬, since f −1 (r ) = r, f −1 ∈ [G] and Inv G = Inv [G] (see Theorem 2.6.2). Consequently, f preserves the relation ¬. An algebra of the form 3 (Q; δk;{1,2} , ζ, τ, pr, ×, ∧, ∨) 2
For proof, one can assume w.l.o.g. H = G = {0, 1, ..., k − 1}. Let now fa (x) := a ◦ x ∈ Pk1 for arbitrary a ∈ Ek . Then, the mapping α : Ek −→ Pk1 , a → fa is an isomorphic mapping from H (or G) onto the semigroup (or group) (A)
({f0 , f1 , ..., fk−1 }; ), since α(a ◦ b)(x) = fa◦b (x) = (a ◦ b) ◦ x = a ◦ (b ◦ x) = fa (fb (x)) = (fa fb )(x).
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2 The Galois-Connection Between Function- and Relation-Algebras
with Q ⊆ Rk is called Krasner-algebra of first kind and an algebra of the form 3 , ζ, τ, pr, ×, ∧, ∨, ¬) (Q; δk;{1,2} with Q ⊆ Rk Krasner-algebra of second kind. In Theorem 2.10.1.4, we will see that the algebras just defined are the right partners for semigroups (or groups) for a Galois-correspondence. Following our terminology from Section 2.4, we call this a clone, which is also closed, concerning the operation ∨, a co-monoid. Moreover, a co-monoid, which is closed concerning the operation ¬, is a co-group. The following lemma summarizes all auxiliary statements that are necessary to prove Theorem 2.10.1.4. Lemma 2.10.1.3 Let H, G ⊆ Pk1 and Q, T ⊆ Rk . Further, let H := (H; ) be a monoid, G := (G; ) be a group, Q be a co-monoid, and T be a co-group. Then (a)
H = P ol1 Inv H
(a’)
G = P ol1 Inv G
(b)
P ol Q ⊆ [Pk1 ]
(b’)
P ol T ⊆ [Sk ]
(c)
Q = Inv P ol1 Q
(c’)
T = Inv P ol1 T .
Proof. (a), (a’): Let A be a monoid of Pk1 (or a group of Sk ). Then, by Lemma 2.10.1.1, [A]∇ is a clone of Pk and, because of Theorem 2.6.2, we have [A]∇ = P ol Inv [A]∇ = P ol Inv A. Consequently, A = [A]1 = P ol1 Inv A. (b): Since the diagonal relations belong to Q and since Q is closed in respect to ∨, the relation 3 3 ∪ δk;{2,3} γ := δk;{1,2} belongs to Q. With the help of Theorem 1.4.4, it can easily be shown that the relation is preserved of no function of Pk , which depends on at least two variables essentially. Thus, P ol Q ⊆ [Pk1 ]. (b’): Through (b) we already proven P ol T ⊆ [Pk1 ]. Further, the diagonal relation ι2k := {(x, x)|x ∈ Ek } belongs to Q, whereby also ¬ι2k ∈ Q. Obviously the relation ¬ι2k = {(x, y)|x = y} is preserved, however, only from the permutations of Pk1 . Consequently, we have P ol T ⊆ [Sk ]. (c), (c’): If Q is a co-monoid (or is a co-group) of Rk , then Q is also a co-clone of Rk and it is valid (because of P ol1 Q ⊆ P ol Q, Theorem 2.6.1, (a) and Theorem 2.9.2): Q = Inv P ol Q ⊆ Inv P ol1 Q. By (b) (or (b’)) we have in addition P ol Q ⊆ [P ol1 Q], whereby Inv [P ol1 Q] ⊆ Inv P ol Q and (because of Inv P ol1 Q = Inv [P ol1 Q] by Theorem 2.6.2 and Inv P ol Q = Q by Theorem 2.9.2) Inv P ol1 Q ⊆ Q follow. One obtains the following theorem as an easy conclusion in analogy to the above theorem from Lemmas 2.10.1.2 and 2.10.1.3.
2.10 Some Modifications of the P ol-Inv-Connection
139
Theorem 2.10.1.4 ([Kra 45], [Kra 68/69]) Let M be the set of all monoids of the form (M ; ) with M ⊆ Pk1 and G be the set of all groups of the form (G; ) with G ⊆ Sk . Further, let K1 be the set of all co-monoids of Rk and K2 be the set of all co-groups of Rk . Then, the lattices (M; ⊆) and (K1 ; ⊆) and the lattices (G; ⊆) and (K2 ; ⊆) are antiisomorphic. In particular, for i ∈ {1, 2}, L1 := M and L2 := G are valid: The mappings P ol1 : Ki −→ Li , Q → P ol1 Q and
Inv : Li −→ Ki , H → Inv H
are bijective mappings, which reverse the partial order ⊆, i.e., it holds ∀H, G ⊆ Li : H ⊆ G =⇒ Inv G ⊆ Inv H and
∀S, T ⊆ Ki : S ⊆ T =⇒ P ol1 T ⊆ P ol1 S.
2.10.2 Galois Theory for Iterative Function Algebras Iterative function algebras are algebras of the form (Pk ; ζ, τ, ∆, ∇; ). The universes of subalgebras of these algebras Pk (k ∈ N\{1}) are called subclasses or, briefly, classes of Pk . Unlike clones of Pk , there are classes of Pk that do not contain the projections. Nevertheless, for the classes of Pk , one can also find certain relation algebras as partners for a Galois-correspondence. Subsequently, two possibilities for this purpose will be presented. For the first possibility, we choose a certain class A of Pk that does not contain the function e11 and which, therefore, is not a clone. Let L↓k (A) be the lattice of all subclasses of A and let Lk (Jk , Jk ∪ A) be the lattice of all subclasses of Jk ∪ A, which have Jk as a subset. Moreover, let Lk (Inv(Jk ∪ A), Rk ) be the set of all co-clones C of Rk with Inv(Jk ∪ A) ⊆ C. Obviously, the mapping α : L↓k (A) −→ Lk (Jk , Jk ∪ A), T → Jk ∪ T is an isomorphism from L↓k onto Lk (Jk , Jk ∪ A). Since the elements of Lk (Jk , Jk ∪ A) are clones of Pk , the lattice Lk (Jk , Jk ∪ A) is antiisomorphic to the lattice Lk (Inv(Jk ∪ A), Rk ) by Theorem 2.9.3. Consequently, we have
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2 The Galois-Connection Between Function- and Relation-Algebras
Theorem 2.10.2.1 Let A be a subclass of Pk . Further, put P olA Q := A ∩ P olk Q for arbitrary Q ⊆ Rk . Then the mappings Inv : L↓k (A) −→ Lk (Inv(Jk ∪ A)), T → Inv T, and
P olA : Lk (Inv(Jk ∪ A), Rk ) −→ L↓k (A), Q → P olA Q
are bijective mappings, and the lattices L↓k (A) and Lk (Inv(Jk ∪ A), Rk ) are antiisomorphic. As W. Harnau in [Har 83] was pointing, another possibility to characterize subclasses of Pk consists that one establishes relation pairs and relation-pairalgebras. Let Rphk := {(, ) ∈ Rkh × Rkh | ⊆ } and
Rpk :=
Rphk .
h≥1
The elements of Rpk are called relation pairs. We say that f n ∈ Pk preserves the relation pair (, ) ∈ Rpk , if f (r1 , ..., rn ) ∈ for arbitrary r1 , ..., rn ∈ . By definition, each function of Pk preserves the pair (∅, ∅). If = , then the fact “f preserves the relation pair (, )” is identical with the fact “f preserves ”. Let F ⊆ Pk and Q ⊆ Rpk . Then, denote Invpk F the set of all relation pairs of Rpk , which are preserved from every function of F . Further, let P olpk Q be the set of all functions of Pk , which preserve each relation pair of Q. It can easily be shown that the following lemma holds: Lemma 2.10.2.2 ([Har 83]) (a) ∀Q ⊆ Rpk : P olpk Q = [P olpk Q]ζ,τ,∆,∇, ; (b) ∀(, ) ∈ Rpk : ([P ol(, )]e21 ,ζ,τ,∆, = P ol(, ) ⇐⇒ = ). Analogous to Section 2.3, one can define certain operations on the set Rpk : h+1 (“the doubling For α ∈ {ζ, τ, ∆, pr, ∼} (see Section 2.3, ∼ h := ∇ ∧ δ{1,2} of the first row of ”)) and (, ), (µ, µ ) ∈ Rpk we set: α(, ) := (α, α ), (∇, ∇ ), if = ∅, ∇(, ) := (∇, ∅), if = ∅, and
2.10 Some Modifications of the P ol-Inv-Connection
141
(, ) × (µ, µ ) := ( × µ, × µ ).
Further, put E := h≥1 Ekh in the following. For each a ∈ E one can define two operations on Rpk as follows: (\{a}, ), if ⊆ \{a}, ν1,a (, ) := otherwise, (, ) and ν2,a (, ) :=
(, ∪ {a}), if a ∈ , otherwise (, )
((, ) ∈ Rpk ). 3 The importance of the above-defined operations results from the following lemma, which one can easily check. Lemma 2.10.2.3 Let (, ) be a relation pair which is derivable from Q (⊆ Rpk ) by means of the operations ζ, τ, ∆, ∇, ∼, pr, ×, ν1,a , ν2,a (a ∈ E). Then P olpk Q ⊆ P olpk (, ). The algebra Rpk := (Rpk ; (∅, ∅), ζ, τ, ∆, pr, ∼, ×, (ν1,a )a∈E , (ν2,a )a∈E ) of the type (0,1,1,1,1,1,2,1,1,1,...) is called full relation-pair algebra on Ek . A relation-pair algebras is a subalgebra of this algebra. Further, a universe of a relation-pair algebra is called co-class. Then, the following theorem can be proven with some expenditure (ultimately similar to the proof of Theorem 2.9.3): Theorem 2.10.2.4 ([Har 83]) Let L(Pk ) (or L(Rpk )) be the set of all classes (or co-classes) of Pk (or Rpk ), respectively. Then the mappings Invk : L(Pk ) −→ L(Rpk ), A → Invk A and P olpk : L(Rpk ) −→ L(Pk ), Q → P olpk Q 3
In [Har 83] so-called multi-operators dh and dv are first defined instead of the operations ν1,a , ν2,a (a ∈ E): dh (, ) := {(, µ) ∈ Rpk | ⊆ µ ⊆ }, dv (, ) := {(µ, ) ∈ Rpk | ⊆ µ ⊆ }. Then, relation-matrix-algebras, in which these multi-operators are describable through two operations, are introduced. It is shown how one can repair the “lack” with the multi-operators by going over to the relation-matrix-algebras with finite many operations.
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2 The Galois-Connection Between Function- and Relation-Algebras
are bijective mappings with the properties ∀A, B ∈ L(Pk ) : A ⊆ B =⇒ Invk B ⊆ Invk A, ∀S, T ∈ L(Rpk ) : S ⊆ T =⇒ P olpk T ⊆ P olpk S; i.e., the lattices (L(Pk ); ⊆) and (L(Rpk ); ⊆) are antiisomorphic.
2.11 Some Connections Between the Relation Operations In this last section of Chapter 2, we want to clarify the order in which one can use the relation operations given in Section 2.3, to obtain all relations from the set [Q] (⊆ Rk ) as effectively as possible. Let ∆ := {(x1 , x2 , ..., xh ) ∈ | x1 = x2 } ( ∈ Rkh ). This relation is obvious derivable from our elementary operations. For arbitrary α, α1 , ..., αt ∈ {ζ, τ, ∆, ∆ , ∇, pr} we use the following notations: α1 := α(), αi := α(αi−1 ) for i ∈ N, α1 α2 ...αt := α1 (...(αt−1 (αt ())...) ( ∈ Rk ). It can easily be shown that the Lemma 2.11.1 holds.
Lemma 2.11.1 For arbitrary relations ∈ Rkh , ∈ Rkh and ∈ Rkh it is valid:
(a) × = (ζ h ∆h ) ∩ (∇h ); 3 (b) ∅ = prh , δk;{1,2} = ∆ ∇3 ∅;
(c) ζ(pr) = pr(ζ(τ ())), τ (pr) = pr(ζ h−1 (τ (ζ()))), ∆ (pr) = pr(ζ h−1 (∆ (ζ()))), ∇(pr) = pr(τ ((∇()))); (d) ζ( ∧ ) = (ζ) ∧ (ζ ), τ ( ∧ ) = (τ ) ∧ (τ ), ∆ ( ∧ ) = (∇) ∧ (∇ ), if h = h ; (e) ( ∨ ) ∧ = ( ∧ ) ∨ ( ∧ ), if h = h = h .
2.11 Some Connections Between the Relation Operations
143
3 Theorem 2.11.2 Let Ω := {δk;{1,2} , ζ, τ, pr, ×, ∧}. Then for all Q ⊆ Rk it is valid:
(a) [Q]Ω = [Q]ζ,τ,∆ ,∇,pr,∧ ; (b) [Q]ζ,τ,∆ ,∇,pr,∧ = [ [[Q]ζ,τ,∆ ,∇ ]∧ ]pr ; (c) [Q]Ω∪{∨} = [Q]ζ,τ,∆ ,∇,pr,∧,∨ ; (d) [Q]ζ,τ,∆ ,∇,pr,∧,∨ = [ [ [ [Q]ζ,τ,∆ ,∇ ]∧ ]∨ ]pr . Proof. (a): Since ∆ and ∇ are Ω-derivable operations, we have [Q]ζ,τ,∆ ,∇,pr,∧ ⊆ [Q]Ω . The reversed inclusion [Q]Ω ⊆ [Q]ζ,τ,∆ ,∇,pr,∧ follows from Lemma 2.11.1, (a), (b). (b) follows from Lemma 2.11.1, (c), (d). One proves the statements (c) and (d) analogously to (a) and (b) using Lemma 2.11.1, (e). A translation of these observations into the language of mathematical logic can be found in [P¨ os-K 79], p. 63–68.
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3 The Subclasses of P2
A basic result of many-valued logic is the description of all closed sets of Boolean functions given by E. L. Post in [Pos 20] and [Pos 41]. Since Post’s proof is long and rather complicated, revisions (for instance [Jab-G-K 70] and [Ugo 88]) and new proofs (for instance [Ber 80], [McK-M-T 87] and [Res-D 89] or [Den-W 2002]) have been published. The new proof methods of the last years mainly result from the fact that parts of Post’ results are special cases or conclusions of certain theorems of many-valued logic or universal algebra. In this chapter, we tried to verify Post’s results in an elementary way by working out some essential basic ideas.
3.1 Definitions of the Subclasses of P2 and Post’s Theorem We need some notations introduced in Chapter 1 to define the subclasses of P2 and to describe certain generated sets of this subclasses. We shall define functions of P2 by formulae over the alphabet {x, y, z, x1 , x2 , ...} and we use the usual symbols ∧ (“conjunction” or “multiplication modulo 2”), ∨ (“disjunction”), + (“addition modulo 2”) and − (“negation”). By ◦ ∈ {∧, ∨, +},
−
, cna (a ∈ E2 ), eni (1 ≤ i ≤ n), m3 , t2 , q 3 , r3 , hµ+1 (µ ∈ N) µ
we denote functions of P2 given by
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3 The Subclasses of P2
◦(x, y) := x ◦ y, −
(x) := x,
cna (x1 , ..., xn ) := a, eni (x1 , ..., xn ) := xi , m(x, y, z) := x ∧ (y ∨ z), t(x, y) := x ∧ y, q(x, y, z) := x ∧ (y ∨ z), r(x, y, z) := x + y + z, µ+1 hµ (x1 , ..., xµ+1 ) := i=1 (x1 ∧ x2 ∧ ... ∧ xi−1 ∧ xi+1 ∧ ... ∧ xµ+1 ) = 1 if ∃i ∈ {1, ..., µ + 1} : x1 = ... = xi−1 = xi+1 = ... = xµ+1 = 1, 0 otherwise (h1 = ∨), respectively. We write x for (x1 , ..., xn ), α for (α, α, ..., α) (α ∈ E2 ) and often xy instead of x ∧ y. Finally, let x, if σ = 0, xσ := x, if σ = 1. The mapping
δ : P2 −→ P2 , f n −→ (f δ )n
with
f δ (x1 , ..., xn ) := f (x1 , x2 , ..., xn )
is known to be an automorphism from P2 , which we shall use to describe isomorphic closed subsets of P2 (see Section 9.11), where Aδ := {f δ | f ∈ A}. We remark that δ is the unique non-trivial isomorphism from a subalgebra of P2 to a subalgebra of P2 (see Theorem 9.12.5). In the following, we define some closed subsets of P2 with the help of which we can describe all subclasses of P2 with the applications of ∩ and ∪: 0 0 1 • M := P ol 0 1 1 = n≥1 {f n ∈ P2 | ∀a, b ∈ E2n : a ≤ b =⇒ f (a) ≤ f (b)} (set of all non-decreasing monotone functions), • S := P ol =
0 1 1 0
n≥1 {f
n
∈ P2 | f (x1 , ..., xn ) = f (x1 , x2 , ..., xn )}
(set of all self-dual functions),
3.1 Definitions of the Subclasses of P2 and Post’s Theorem
• L :=
n≥1 {f
n
147
n ∈ P2 | ∃a0 , ..., an ∈ E2 : f (x) = a0 + Σn=1 ai · xi }
(set of all linear functions), • T0,µ := P olE2µ \{1} if µ ∈ N ( f n ∈ T0,µ ⇐⇒ (∀a1 , ..., aµ ∈ E2µ : (∀i ∈ {1, ..., µ} : f (ai ) = 1 and ai = (ai1 , ..., ain )) =⇒ ∃ j ∈ {1, ..., n} : a1j = a2j = ... = aµj = 1) ⇐⇒ (∀a1 , ..., aµ ∈ E2n ∃ j ∈ {1, ..., n} : ∀x ∈ {a1 , ..., aµ } : f (x) = xj ∧ f (x))), δ T1,µ := T0,µ = P olE2µ \{0},
Ta := Ta,1 , where a ∈ E2 , T0,∞ := µ≥1 T0,µ =
n≥1 {f
n
∈ P2 | ∃j ∈ {1, ..., n}∃f ∈ P2 : f (x) = xj ∧ f (x)},
δ , T1,∞ := T0,∞
• K := [∧] (set of all conjunctions), • D := K δ = [∨] (set of all disjunctions), • C := [c0 , c1 ] (set of all constant functions), • Ca := [ca ], a ∈ E2 , • I := [e11 ] (set of all projections), • I := [− ].
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3 The Subclasses of P2
Theorem 3.1.1 (Post’s Theorem; [Pos 41]) (1) The set of all subclasses of P2 is countably infinite. (2) The non-empty subclasses of P2 are P2 , S, M, L, Ta,µ , Ta,µ ∩ Ta , Ta,µ ∩ M, Ta,µ ∩ M ∩ Ta , K ∪ C, K ∪ Ca , K, D ∪ C, D ∪ Ca , D, S ∩ T0 , S ∩ M, S ∩ L, S ∩ L ∩ T0 , L ∩ Ta , I ∪ C, I ∪ C, I, I ∪ Ca , I, C, Ca , where a ∈ E2 and µ ∈ {1, 2, ..., ∞}. (The Hasse-diagram of these classes is given in Figure 3.1.) (3) In the set P2 , there exists exactly (a) 9 closed subsets of order 1: [P21 ], I ∪ C, I, I ∪ C0 , I ∪ C1 , I, C, C0 , C1 ; (b) 20 closed subsets of order 2: P2 , T0 , T1 , M, L, M ∩ T0 , M ∩ T1 , L ∩ T0 , L ∩ T1 , M ∩ T0 ∩ T1 , K ∪ C, K ∪ C0 , K ∪ C1 , K, D ∪ C, D ∪ C0 , D ∪ C1 , D, T0,∞ , T1,∞ ; (c) 20 closed subsets of order 3: S, S ∩ T0 , S ∩ M, S ∩ L, S ∩ L ∩ T0 , T0,2 , T1,2 , T0,2 ∩ T1 , T1,2 ∩ T0 , T0,2 ∩ M, T1,2 ∩ M, T0,2 ∩ M ∩ T1 , T1,2 ∩ T0 ∩ M, T0,∞ ∩ T1 , T1,∞ ∩ T0 , T0,∞ ∩ M, T1,∞ ∩ M, T0,∞ ∩ M ∩ T1 , T1,∞ ∩ M ∩ T0 , T0 ∩ T1 ; (d) 8 closed subsets of order µ + 1 (µ ≥ 3): Ta,µ , Ta,µ ∩ Ta , Ta,µ ∩ M, Ta,µ ∩ M ∩ Ta (a ∈ E2 ).
3.2 A Proof for Post’s Theorem T0 T0,2
T0,3
T0,∞
P2
M T 1
K
S∩M
K ∪C
S
C0
L
[P21 ]
I
I C
D∪C
149
T1,2 T1,3
T1,∞
D
C1
∅
Fig. 3.1. The Post Lattice
3.2 A Proof for Post’s Theorem For any subclass A of P2 , the following three cases are possible: Case 1: A ⊆ L and A ⊆ S, Case 2: A ⊆ L, Case 3: A ⊆ L and A ⊆ S. By following this case distinction, all subclasses of P2 and minimal generating subsets of these classes are determined as follows. The orders of the subclasses given are easy conclusions from the proven statements about generating sets of the subclasses. We start with: 3.2.1 The Subclasses A of P2 with A ⊆ L and A ⊆ S Theorem 3.2.1.1 The following holds: P2 = [◦,− ] for ◦ ∈ {∧, ∨}, M = [∨, ∧, c0 , c1 ], T0,µ = [hµ , t], T0,µ ∩T1 = [hµ , q], T0,µ ∩ M = [hµ , m, c0 ] ( T0 ∩ M = [∨, ∧, c0 ] ), T0,µ ∩ M ∩ T1 = [hµ , m], T0,∞ = [t], T0,∞ ∩ T1 = [q], T0,∞ ∩ M = [m, c0 ] and T0,∞ ∩ M ∩ T1 = [m], where µ ∈ N.
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3 The Subclasses of P2
Proof. Let be f n ∈ P2 , for which µ + 1 distinct tuples a1 , ..., aµ+1 exist with f (a1 ) = ... = f (aµ+1 ) = 1. Then, we have f (x) = hµ (fa1 (x), fa2 (x), ..., faµ+1 (x)), where
fai (x) :=
(3.1)
0 if x = ai , f (x) otherwise
(i = 1, 2, ..., µ + 1). We call every function f n of a subclass A of P2 with {hµ , fa1 , ..., faµ+1 } ⊆ A and
f (a1 ) = ... = f (aµ+1 ) = 1
for certain a1 , ..., aµ+1 ∈ E2n a reducible function. We denote by NA the set of all not reducible functions f of a class A. Obviously, the set NA ∪ {hµ } is a generating set for the class A, if hµ ∈ A and A ∩ {h1 , ..., hµ−1 } = ∅ for certain µ ≥ 1. The Table 3.1 gives an easily verifiable description of the set (NA )n for A ∈ {P2 , T0,m , M, T0,m ∩ M, T0,m ∩ T1 , T0,m ∩ M ∩ T1 }, m ∈ N, and the minimal µ with hµ ∈ A. 1 The functions gJ and mJ for J ⊆ E2n from Table 3.1 are defined by 1 if x ∈ J, gJ (x) := 0 otherwise and
mJ (x) :=
1 if ∃a ∈ J : x ≥ a, 0 otherwise. Table 3.1
A
NAn
P2
{gJ | |J| ≤ 1}
1
M
{mJ | |J| ≤ 1}
1
T0,µ
{gJ | |J| ≤ µ and ∃t : gJ (x) = xt ∧ gJ (x)}
µ
T0,µ ∩ T1
{gJ ∈ NTn0,µ | 1 ∈ J}
µ
T0,µ ∩ M
{mJ | |J| ≤ µ and ∃t : mJ (x) = xt ∧ mJ (x)}
µ
T0,µ ∩ M ∩ T1 {mJ ∈ NTn0,µ ∩M | 1 ∈ J} 1
a minimal µ with hµ ∈ A
µ
One possible proof of Table 3.1 is as follows: We start with a ”partition” of an arbitrary f ∈ A in functions fai by (3.1), then we repeat this construction for the functions fai instead of f , if fai ∈ NA , etc. In case A ⊆ M be let all tuples ai minimal with respect to ≤ by this fai ∈ M .
3.2 A Proof for Post’s Theorem
151
Since g∅n = mn∅ = cn0 , n g{(a (x) = xσ1 1 ∧ xσ2 2 ∧ ... ∧ xσnn , 1 ,...,an )}
mn{0} = cn1 , mn{(a1 ,...,an )} (x) = xi1 ∧ xi2 ∧ ... ∧ xiν if {i1 , ..., iν } = {i | ai = 1} = ∅, we have
NP2 ⊆ [∧,− ],
NT0 ⊆ [c0 , ∧, t], = [t],
NM ⊆ [∧, c0 , c1 ], NM ∩T0 ⊆ [∧, c0 ] and NM ∩T0 ∩T1 ⊆ [∧]. Consequently, P2 = [∨, ∧,− ] (and P2 = [◦,− ] for ◦ ∈ {∨, ∧} by Morgan’s laws), T0 = [∨, t], M = [∨, ∧, c0 , c1 ], M ∩ T0 = [∨, ∧, c0 ] and M ∩ T0 ∩ T1 = [∨, ∧]. Furthermore, Table 3.1 implies the following: if A = T0,µ ∩ B with B ∈ T0,∞ ∩ B = {P 2 , T1 , nM, T1 ∩ M } and µ ≥ 2, then A = [{hnµ } ∪ (T0,∞ ∩ B)] and {f ∈ P | ∃i ∈ {1, 2, ..., n} ∃ f ∈ B : f (x) = x ∧ f (x)}. By this 2 i n≥1 fact, from a generating subset {f n , g m , ...} of B, we get a generating subset of the form {∧ f, ∧ g, ...} for the class T0,∞ ∩ B. Thus, T0,∞ = [t], since t(x, t(x, y)) = x ∧ y and P2 = [∧,− ]. T0,∞ ∩ T1 = [q] follows from T1 = T0δ = [∧, tδ ], tδ (x, y) = x ∨ y and ∧ ∧, ∧ tδ ∈ [q]. By T1 ∩ M = [∧, ∨, c1 ] and {∧ ∧, ∧ ∨, ∧ c11 = e22 } ⊆ [m] is T0,∞ ∩ T1 ∩ M = [m]. Finally, T0,∞ ∩ M = [m, c0 ], since T0,∞ ∩ M = (T0,∞ ∩ M ∩ T1 ) ∪ [c0 ]. Lemma 3.2.1.2 If A = [A] ⊆ P2 , ca ∈ A for certain a ∈ E2 and A ⊆ L, then A contains a binary non-linear function. Proof. By x◦y+x+y = x◦ y for {◦, ◦ } = {∧, ∨}, ∆(+c1 ) =− and Theorem 1.4.2 we have [◦, +, c1 ] = P2 for ◦ ∈ {∧, ∨}, i.e., every function g n ∈ P2 has a description of the form ai1 i2 ...iν ◦ xi1 ◦ xi2 ◦ ... ◦ xiν g(x) = a0 + {i1 ,i2 ,...,iν }⊆{1,2,...,n}
for some a0 , ai1 i2 ...iν ∈ E2 (see Theorem 1.4.3). Therefore, because A ⊆ L, there exists a function f n ∈ A with f (x) = a0 + x1 ◦ x2 ◦ ... ◦ xr +
n i=1
where r ≥ 2 and
ai ◦ xi +
ai1 ...iν ◦ xi1 ◦ ... ◦ xiν ,
i1 , ..., iν ∈ {1, 2, ..., n}, ν ≥ r, {i1 , ..., iν } ⊆ {1, 2, ..., r}
152
3 The Subclasses of P2
◦ :=
∨ if a = 1, ∧ if a = 0.
Our statement follows from f (x, y, y, ..., y , ca , ...., ca ) = b + x ◦ y + c ◦ x + d ◦ y ∈ A\L (r−1) times for some b, c, d ∈ E2 . Lemma 3.2.1.3 Let A be a subclass of P2 , which is not a subset of L and not a subset of S. Then, the function ∧ or the function ∨ belongs to A. Proof. It is easy to verify that ∨ or ∧ is a superposition over a binary nonlinear function of P2 . Thus, we have to show A2 ⊆ L. Since A ⊆ S, there exists an f ∈ A with 0 1 a f = , 1 0 a a ∈ E2 , i.e., f ∈ {f1 , f2 , ..., f8 } (see Table 3.2). x 0 0 1 1
y f1 0 0 1 0 0 0 1 0
f2 1 1 1 1
Table 3.2
f3 1 0 0 1
f4 0 1 1 0
f5 0 0 0 1
f6 1 0 0 0
f7 0 1 1 1
f8 1 1 1 0
The functions f5 , ..., f8 are non-linear. If f ∈ {f1 , ..., f4 } then ∆f is a constant function and A2 ⊆ L follows from Lemma 3.2.1.2. Lemma 3.2.1.4 Let A be a subclass of P2 with ∧ ∈ A. Then the following implications hold: (a) (∃a ∈ E2 : A ⊆ Ta ) =⇒ ca ∈ A, (b) (A ⊆ M and A ⊆ K ∪ C) =⇒ m ∈ A, (c) A ⊆ M =⇒ q ∈ A, (d) (A ⊆ K ∪ C and A ⊆ T0 ) =⇒ ∨ ∈ A, (e) (∃µ ∈ N : A ⊆ T0,µ and A ⊆ T0,µ+1 ) =⇒ hµ ∈ A. Proof. (a): If A ⊆ Ta there exists a g 1 ∈ A with g(a) = a, i.e., g ∈ {ca ,− }. ca ∈ A follows from ∧ ∈ A, x ∧ x = 0 and 0 = 1. (b): f denotes an n-ary function of A\(K ∪ C). Then there exist two tuple a = (a1 , ..., an ) and b = (b1 , ..., bn ) with the following properties: f (a) = f (b) = 1, a ≤ b, b ≤ a and f (c) = 0 for every c with c < a or c < b . Defining functions gi3 ∈ A by
3.2 A Proof for Post’s Theorem
gi (x, y, z) :=
⎧ ⎪ ⎪ x ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ y ⎪ ⎨
if if
ai bi ai bi
=
=
1 1 0 1
153
, ,
ai 1 ⎪ ⎪ z if = , ⎪ ⎪ b 0 ⎪ i ⎪ ⎪ ⎪ ⎪ ⎪ ai 0 ⎪ ⎪ = ⎪ ⎩ yz if bi 0
(i = 1, 2, ..., n) we obtain x ∧ f (g1 (x, y, z), ..., gn (x, y, z)) = m(x, y, z) ∈ A, since f ∈ M . (c): By A ⊆ M we have a function h3 in A with 1 0 0 1 h = . 1 0 1 0 Consequently, h (x, y, z) := x ∧ h(x, y, z) ∈ A and h (x, y, z) ∈ {x ∧ y ∧ z, x(y+z+1), x∧z, x(y∨z)}. Since x∧(y∧z) = x(y∨z) and x(yz+z+1) = x(y∨z), it holds q ∈ A. (d): By (a), (b), (c) and m(x, y, z) = q(x, y, q(x, y, z)) it holds {c1 , m} ⊆ A and hence ∆(m c11 ) = ∨ ∈ A. (e): If A ⊆ T0,µ+1 , there is an f ∈ A with f (E2µ+1 \{1}) = 1, i.e., w.l.o.g.: ⎛ ⎞ ⎛ ⎞ 1 0 1 1 ... 1 0 0 0 ... 0 ...... 0 ⎜1⎟ ⎜ 1 0 1 ... 1 0 1 1 ... 0 ...... 0 ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎟ f⎜ ⎜ 1 1 0 ... 1 1 0 1 ... 0 ...... 0 ⎟ = ⎜ 1 ⎟ . ⎝.⎠ ⎝ ................................ ⎠ 1 1 1 1 ... 0 1 1 1 ... 1 ...... 0 (µ+1) times Since ∧ ∈ A, we have f (x1 , ..., xµ+1 ) := f (x1 , ..., xµ+1 , x1 x2 , x1 x3 , ..., x1 x2 x3 , ..., x1 x2 ...xµ+1 ) ∈ A. By f ∈ T0,µ we have
f (x) =
hµ (x) if x = 1, a if x = 1
for a certain a ∈ E2 . If a = 1 then f = hµ ∈ A. If a = 0 and µ ≥ 2 then f (x1 , ..., xµ−1 , xµ xµ+1 , f (x1 , ..., xµ+1 )) = hµ (x) ∈ A. Finally, if a = 0 and µ = 1, we have f = + and h1 (x, y) = xy + x + z ∈ A.
154
3 The Subclasses of P2
Theorem 3.2.1.5 The subclasses A of P2 with A ⊆ S and A ⊆ L are P2 , M, Ta,µ , Ta,µ ∩ B, K, K ∪ Ca , K ∪ C, D, D ∪ Ca , D ∪ C, where a ∈ E2 , µ ∈ {∞, 1, 2, ...} and B ∈ {Ta , M, M ∩ Ta }. Proof. Denote A a subclass of P2 with A ⊆ S and A ⊆ L. By Lemma 3.2.1.3, we have that A obtains K or D. W.l.o.g. [∧] = K ⊆ A. If A ∈ {K, K ∪ C0 , K ∪ C1 , K ∪ C} then we can distinguish 8 cases, which are given in Table 3.3. Using Lemma 3.2.1.4 and Theorem 3.2.1.1, we see that A is a certain class, which is given in the last column of Table 3.3. Table 3.3
∃µ ∈ A ⊆ T1 A ⊆ M {∞, 1, 2, ...} : A ⊆ T0,µ ∧ A ⊆ T0,µ+1 − − − − − + − + − − + + + − − + − + + + − + + +
conclusions from the assumptions
A
{c1 , c0 , q} ⊆ A {c1 , c0 , m} ⊆ A {c1 , q} ⊆ A ⊆ T1 {c1 , m} ⊆ A ⊆ T1 ∩ M {hµ , c0 , q} ⊆ A ⊆ T0,µ {hµ , c0 , m} ⊆ A ⊆ T0,µ ∩ M {hµ , q} ⊆ A ⊆ T0,µ ∩ T1 {hµ , m} ⊆ A ⊆ T0,µ ∩ T1 ∩ M
P2 M T1 T1 ∩ M T0,µ T0,µ ∩ M T0,µ ∩ T1 T0,µ ∩ T1 ∩ M
(+ stands for the truth of the assertion in the first row, − for the truth of the negated assertion. Furthermore, let T0,∞+1 := ∅ and h∞ := e11 ) 3.2.2 The Subclasses of L Obviously, all subclasses of [P21 ] [P21 ], I ∪ C, I, I ∪ C0 , I ∪ C1 , C, C0 , C1 , I, ∅ are also subclasses of L. With the help of these sets, we can determine all subclasses of L with the following. Lemma 3.2.2.1 Let L be subclass of L with L ⊆ [P21 ]. Then L = [L1 ∪ {r}] (r(x, y, z) = x + y + z). Proof. Let L = [L] ⊆ L and L ⊆ [P21 ]. Then, there is a function g ∈ L with g(x, y, z) = a + x + y + bz for some a, b ∈ E2 . Thus g(g(x, y, z), z, z) = r(x, y, z) ∈ L. By forming of the functions of the type r r ... r and by n identifying of variables in these functions, we get that every function i=1 bi xi
3.2 A Proof for Post’s Theorem
155
with b1 + ... + bn = 1 belongs to [r] ⊆ A. Now, denote f an n-ary function of n L and let f (x) = a0 + i=1 ai xi . Then, we have f (x, x1 , ..., xn ) := x + (a2 + ... + an )x1 +
n
ai xi ∈ [r]
i=2
and
f (x) = f (f (x1 , ..., x1 ), x1 , ..., xn ).
Therefore f ∈ [{r} ∪ L1 ] and [{r} ∪ L1 ] = L is proven. Looking for subsemigroups of (P21 ; ), which have the property to be preserved by r, we get the following Theorem 3.2.2.2 All subclasses of L are L, L ∩ T0 = [c0 , +], L ∩ T1 , L ∩ S = [− , r], L ∩ T0 ∩ S = [r], [P21 ], I ∪ C, I, I ∪ C0 , I ∪ C1 , I, C, C0 , C1 , ∅. 3.2.3 The Subclasses of S, Which Are Not Subsets of L Obviously, a function f n ∈ P2 (n ≥ 2) belongs to S iff there exists a function F n−1 ∈ P2 with the property f (x1 , ..., xn ) = x1 F (x2 , ..., xn ) ∨ x1 F (x2 , ..., xn ), where
(3.2)
F (x2 , ..., xn ) := f (0, x2 , ..., xn ).
Consequently, we can define a bijective mapping α of S := S\S 1 onto P2 as follows: α : f −→ F. Lemma 3.2.3.1 The mapping α has the following properties: τ, ∆, ∇ and (a) For the operations ζ, , defined by )(x1 , ..., xn ) := f (x1 , x3 , x4 , ..., xn , x2 ), (ζf ( τ f )(x1 , ..., xn ) := f (x1 , x3 , x2 , x4 , ..., xn ), )(x1 , ..., xn−1 ) := f (x1 , x2 , x2 , x3 , ..., xn−1 ), (∆f (∇f )(x1 , ..., xn+1 ) := f (x1 , x3 , x4 , ..., xn+1 ) and (f g)(x1 , ..., xm+n−2 ) := f (x1 , g(x1 , ..., xm ), xm+1 , ..., xm+n−2 ) (n, m ≥ 2), it holds α( γ f ) = γ(α(f )) for every γ ∈ {ζ, τ, ∆, ∇} and α(f g) = α(f ) α(g), i.e., the algebra (S ; ζ, τ, ∆, ∇, ) is isomorphic to the algebra (P2 ; ζ, τ, ∆, ∇, ). (b) For every subclass A (= ∅) of S, α(A) is a subclass of P2 , and it holds α(A) ⊆ S, A ⊆ α(A) and α(A) ∩ S = A.
156
3 The Subclasses of P2
Proof. (a) is easy to check. (b): Let A be a subclass of S. By (a) we have that α(A) is also a closed set. Assume α(A) ⊆ S. Then F (x2 , ..., xn ) = F (x2 , ..., xn ) for every f n ∈ A. Thus by (3.2) we get that the variable x1 is fictitious for every function f n ∈ A. However, this is not possible. Hence α(A) ⊆ S holds. Let f n ∈ A. Then ∇f ∈ A and therefore α(∇f ) = f ∈ α(A), i.e., A ⊆ α(A). If f n ∈ S ∩ α(A), we have ∆(α−1 f ) = f ∈ A and thus S ∩ α(A) ⊆ A. From this, it follows that A = S ∩ α(A), since A ⊆ α(A) and A ⊆ S. With the help of Lemma 3.2.3.1 and Theorem 3.2.1.5, it is not difficult to determine the missing subclasses of S. It holds Theorem 3.2.3.2 (a) The sets S ∩ M and S ∩ T0 are the only proper subclasses of S, which are not subsets of L. (b) It holds that S = [h2 ,− ], S ∩ T0 = [h2 , r], S ∩ M = [h2 ]. Proof. (a): Let A be a subclass of S with A ⊆ L. Then it holds α(A) ⊆ L. By Lemma 3.2.1.2 and Lemma 3.2.1.3, we have {∨, ∧} ∩ α(A) = ∅. Consequently, the function h2 (= xyz ∨ x(y ∨ z)) or the function g(x, y, z) := x(y ∨ z) ∨ xyz belong to A. Since it holds g(g(x, y, z), y, z) = h2 (x, y, z), h2 ∈ A. Further, the functions α(h2 ) = ∧, x ∧ h2 (x, y, z) = x(y ∨ z) and c10 = α(e21 ) are elements of α(A). Thus, T0,2 ∩M ⊆ α(A) and by Lemma 3.2.3.1, (b) we have T0,2 ∩M ∩S ⊆ A. By Theorem 3.2.1.5, there exists only the following possibilities for A: S ∩ T0,2 , S ∩ M = S ∩ M ∩ T0 , S ∩ T0 and (a) follows from S ∩ T0,2 = S ∩ M . (This fact is easy to prove, for example, with the help of the relation product and theproperty P ol ∩ P ol ⊆P ol : 1 0 0 0 1 0 0 1 Let 1 := , 2 := and 3 := , Then 2 1 = 3 0 1 0 1 0 0 1 1 and thus S ∩ T0,2 ⊆ S ∩ M . Conversely, S ∩ M ⊆ S ∩ T0,2 holds, since 3 1 = 2 .) (b) follows from Theorem 3.2.1.1 and Lemma 3.2.3.1. 3.2.4 A Completeness Criterion for P2 The following is a conclusion from Theorem 3.1.1: Theorem 3.2.4.1 (Completeness Criterion for P2 ) Let A ⊆ P2 . Then [A] = P2 ⇐⇒ ∀X ∈ {T0 , T1 , M, S, L} : A ⊆ X.
3.2 A Proof for Post’s Theorem
157
Without using of Theorem 3.1.1, one can prove Theorem 3.2.4.1 with the help of Theorem 1.5.4.1 and the following: Theorem 3.2.4.2 P2 has exactly five maximal classes: T0 , T1 , M, S, and L. Proof. It is easy to see that the sets T0 , T1 , M, S, L are pairwise distinct proper subclasses of P2 . Therefore, proof of the following suffices for the proof of our theorem: ∀A ⊆ P2 : ((∀K ∈ {T0 , T1 , M, S, L} : A ⊆ K) =⇒ [A] = P2 ) Let now A ⊆ P2 with {f0 , f1 , fM , fS , fL } ⊆ A, where f0 ∈ T0 , f1 ∈ T1 , fM ∈ M, fS ∈ S and fL ∈ L. If one identifies all variables of f0 with each other, then one gets an unary function f0 ∈ [A] with f0 (0) = 1, i.e., f0 ∈ {c1 , e11 }. Case 1: f0 = c1 . In this case, it holds that f1 (c1 (x), ..., c1 (x)) = c0 (x) ∈ [A]. Since fM ∈ A\M , there are some (ai , bi ) ∈ {(0, 0), (0, 1), (1, 1)} (i = 1, 2, ..., n) with f (a1 , ..., an ) > f (b1 , ..., bn ). Consequently, the function e11 is a superposition over {fM , c0 , c1 } ⊆ [A]. Thus P21 belongs to [A]. By the proof of Lemma 3.2.1.2 (see also Theorem 1.4.3), we can describe the function fLn with the help of a so-called Shegalkin polynom. Since fL does not belong to L, we can assume w.l.o.g. that fL (x) = a0 + x1 · x2 · ... · xr +
n i=1
ai · xi +
ai1 ...iν · xi1 · ... · xiν ,
i1 , ..., iν ∈ {1, ..., n}, ν ≥ r, {i1 , ..., iν } ⊆ {1, ..., r}
holds for r ≥ 2. Now, we consider the function fL (x, y) := fL (x,
y, ..., y , c0 (x), ..., c0 (x)) (r−1) times
which has the form fL (x, y) = a + b · x + c · y + x · y for some a, b, c ∈ {0, 1}. It is easy to check that x · y is a superposition over {fL } ∪ P21 (⊆ A). Consequently, by Theorem 1.4.2, we have [A] = P2 . Case 2: f0 = e11 . Since fSn ∈ S, there exist some a1 , ..., an ∈ {0, 1} with fS (a1 , ..., an ) = fS (a1 , ..., an ). Thus, c1 is a superposition over {fS , e11 } and the Case 2 is put down to the Case 1.
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4 The Subclasses of Pk Which Contain Pk1
We start with the definitions of some subclasses of Pk . We show later that these classes are all classes A of Pk with Pk1 ⊆ A. Let Ut := Pk (t) ∪ [Pk1 ] for t = 2, 3, ..., k. In particular, Uk = Pk . Further, let Lk be the set 1 {f n ∈ Pk | ∃a ∈ E2 ∃f0 ∈ Pk1 ∃f1 , ..., fn ∈ Pk,2 : [Pk1 ]∪ n≥1
f (x) = f0 (a + f1 (x1 ) + f2 (x2 ) + ... + fn (xn ) (mod 2))}.
For k = 2 Lk is the set L, already defined in Chapter 3. The sets Ut and Lk can be described with the help of relations: Lemma 4.1 Let ιhk := {(a0 , ..., ah−1 ) ∈ Ekh | ∃i, j ∈ Ek : i = j ∧ ai = aj } and
λk := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ Ek }.
Then (a) Ut = P ol ιt+1 for each t ∈ {2, 3, ..., k − 1} k and (b) Lk = P ol λk . t+1 Proof. (a): Obviously, Ut is a subset of P ol ιt+1 k . The inclusion Ut ⊂ P ol ιk t+1 (i.e., there is a function (∈ P ol ιk ) that essentially depends on at least two variables and which has at least t + 1 different values) is false because of
160
4 The Subclasses of Pk Which Contain Pk1
Theorem 1.4.4, (b). Thus, Ut = P ol ιt+1 k . (b): It is easy to check that Lk ⊆ P ol λk . For the proof of P ol λk ⊆ Lk , denote f n an arbitrary function from Pk,2 ∩ (P ol λk ). First, we will show that then f (x1 , 0, ..., 0) + f (0, x2 , ..., xn ) + f (0, 0, ..., 0) = f (x1 , ..., xn ) (mod 2)
(4.1)
holds. Suppose, for some x1 = a1 , ..., xn = an is this false. Then, we have ⎞ ⎛ ⎛ ⎞ a a a a1 0 ... 0 ⎜ 0 a2 ... an ⎟ ⎜ a b b ⎟ ⎟ ⎜ ⎟ f⎜ ⎝ 0 0 ... 0 ⎠ ∈ ⎝ b a b ⎠ a1 a2 ... an b b a for arbitrary a, b ∈ E2 . However, this is a contradiction to f ∈ P ol λk . Therefore, (4.1) holds and this implies: f (x1 , ..., xn ) = a + f1 (x1 ) + ... + fn (xn ) (mod 2), where a := (n − 1) · f (0, 0, ..., 0) (mod 2) and fi (x) := f (0, ..., 0,
x , 0, ..., 0). i-th place
Because of pr1,2,3 λk = ι3k , an arbitrary function g from (P ol λk )\[Pk1 ] has exactly only two different values. Consequently, there exists a certain permutation s ∈ Sk with s(Im(g)) = {0, 1} such that g has the description s−1 (s g) and s g belongs to Pk,2 ∩ P ol λk . It is obvious then that g ∈ Lk . Definition Let E ⊆ Ek with |E| ≥ 2. Then we can define a mapping prE from Pk,E into PE as follows: prE f n = g m :⇐⇒ (n = m ∧ ∀a ∈ E n : f (a) = g(a)) (f n ∈ Pk,E , g m ∈ PE ). Lemma 4.2 Let f 2 be a function from Lk with f (x, y) = x + y (mod 2) for all x, y ∈ E2 , let g m be a function from Pk,2 with prE2 g ∈ L2 and let h ∈ Ut \Ut−1 . Then, (a) Lk = [Pk1 ∪ {f }], (b) U2 = [Pk1 ∪ {g}] and (c) ∀t ∈ {3, 4, ..., k} : Ut = [Ut−1 ∪ {h}]. Proof. (a) follows directly from the definition of Lk . 1 ] = P2 . Therefore, some binary (b): By Theorem 3.2.4.1, [{prE2 g} ∪ prE2 Pk,2
4 The Subclasses of Pk Which Contain Pk1
161
functions ∧ , + with prE2 ∧ = ∧ and prE2 + = + belong to [Pk1 ∪ {g}] and an arbitrary function ut of Pk,2 is a superposition over Pk1 ∪ {∧ , + }: u(a1 , ..., at ) · ja1 (x1 ) · ... · jat (xt ) (mod 2) u(x1 , ..., xt ) = (a1 , ..., at ) ∈ Ekt
(see (1.8) from Section 1.4). This implies (b). (c) is a consequence from Lemma 1.4.5.
Theorem 4.3 (Burle’s Theorem, [Bur 67]) The classes with
[Pk1 ], Lk , U2 , U3 , ..., Uk−1 , Pk [Pk1 ] ⊂ Lk ⊂ U2 ⊂ U3 ⊂ ... ⊂ Uk−1 ⊂ Pk
are the only subclasses of Pk which contain Pk1 . Proof. Suppose there exists a class A of Pk with Pk1 ⊂ A, which is different from the classes of the above theorem. Then A contains a certain function f n , which has at least two essentially variables and at least l ≥ 2 different values. Consequently, by Theorem 1.4.4, (a), (c), there exists some a1 , ..., an , b1 , ..., bn , α, β, γ ∈ Ek with ⎛ ⎞ ⎛ ⎞ a1 a2 a3 ...an α f ⎝ a1 b2 b3 ...bn ⎠ = ⎝ β ⎠ , b1 b2 b3 ...bn γ where |{α, β, γ}| = 3 for l ≥ 3 and α = γ and α = β for l = 2. Then, a binary function f with f (x, y) := g0 (f (g1 (x), g2 (y), ..., gn (y))) and ⎛ ⎞ ⎛ ⎞ 0 0 0 f ⎝ 0 1 ⎠ = ⎝ 1 ⎠ 1 1 0 is a superposition over f and some g0 , ..., gn ∈ Pk1 . We distinguish two cases: Case 1: f (1, 0) = 0. In this case, the function prE2 f is nonlinear. Thus, by Lemma 4.2, (b) it holds U2 ⊆ A. Since we have assumed, however, A = Ut for each t ∈ {2, ..., k}, we obtain a contradiction with the aid of Lemma 4.2, (c). Case 2: f (1, 0) = 1. In this case, by Lemma 4.2, (a) Lk is a subset of A and, because of A = Lk , there is a function g ∈ A, which does not preserve λk . Then, one can form a function g ∈ A ∩ Pk,2 with prE2 g ∈ L2 as a superposition over g and some functions of Lk . Thus, by Case 1, we get a contradiction.
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4 The Subclasses of Pk Which Contain Pk1
Consequently, the classes given in our theorem are the only subclasses of Pk that contain Pk1 . The claimed chain property is an immediate conclusion from the definitions of these classes. The claimed chain property is a direct conclusion from the definitions of these classes.
5 The Maximal Classes of Pk
5.1 Introduction, a Rough Description of the Maximal Classes A subclass A of Pk is maximal in Pk (or A is called maximal class)1 if and only if no further classes of Pk exist between A and Pk . In other words: A = [A] ⊆ Pk is maximal in Pk if and only if A = Pk and [A ∪ {f }] = Pk for each f ∈ Pk \A. One is interested in these classes not only for structural reasons, but particularly because one can solve a central problem of the Many-Valued Logic (the so-called Completeness Problem) with the aid of these classes (see Theorem 1.5.4.1). Inter alia, the following papers dealt with the determination and description of maximal classes: [Pos 41], [Jab 54], [Jab 58], [Ros 70;a], [Mart 60], [Lo 63;a– ˇ 70;b]. c], [Lo 64], [Zac 67], [Zac-K-J 69], [Bai 67] and [Sai One knows the maximal classes T0 , T1 , M, S, and L of P2 (see Theorem 3.2.4.2) through the papers [Pos 20], [Pos 41] by E. L. Post. Efforts to determine all maximal classes of Pk for k ≥ 3 began more than 50 years ago. S. V. Jablonskij determined all 18 maximal classes of P3 in [Jab 54]. A. I. Mal’tsev proved how in the paper [Zac-K-J 69] was mentioned that P4 has exactly 82 maximal classes. I. G. Rosenberg was the first that succeeded in the description of all maximal classes of Pk for each k ∈ N \ {1} (see [Ros 65]), and he proved in [Ros 70a] that the list of the given classes is complete. Rosenberg defined six relation sets, which are subsequently denoted by us with Uk , Mk , Sk , Lk , Ck and Bk , and he proved that the set {P olk | ∈ Uk ∪ Mk ∪ Sk ∪ Lk ∪ Ck ∪ Bk } 1
One uses instead of “maximal class” the concept “precomplete class” in older papers.
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5 The Maximal Classes of Pk
is exactly the set of all maximal classes of Pk . He could use that some other authors had shown already the maximality of some classes P ol . For example, for classes of the form P ol 1 with 1 ∈ Uk ∪ Sk ∪ C1k and ∈ Lk , where k is a prime number, it was proven in [Jab 58] that these classes are maximal classes. In [Mart 60], one finds maximal classes of the form P ol 2 with 2 ∈ Mk . For further details, we refer the reader to [Ros 70;a]. In Section 5.2, we will describe the maximal classes of Pk in the manner found from Rosenberg.2 Further, we give first properties of the maximal classes, where these properties are consequences from the definitions more or less. Then, in Section 5.3, the maximality of the classes described in the theorem is proven. It turns out, in this case, that one manages with three basic ideas in the proof. Chapter 6 is dedicated to the proof of the completeness of the given set of maximal classes then. This most difficult part of the determination of maximal classes orientates itself strongly onto the proof given in [Ros 70;a]. One could abbreviate, however, the proof through transfer and modification of some ideas from the papers [Qua 82], [P¨ os- K 79] (p. 126-129) and [Lau 92a]. A first coarse description of the maximal classes supplies the following theorem basically already proven by A. V. Kuznezov in 1959. Theorem 5.1.1 ([Kuz 59], [Ros 70;a] (3.2.5), [But 60]) The class Lk for k = 2 or Uk−1 (= P olk ιkk ) for k ≥ 3 is the only maximal class of Pk , which contains Pk1 . For every maximal class A of Pk , which is different from L2 and Uk−1 , is valid: A = P olk G1 (A). Proof. Let A be an arbitrary maximal class of Pk . Then, the following two cases are possible: Case 1: A1 = Pk1 . Then, by Theorem 4.3, A is the set L2 for k = 2 or the set Uk−1 for k ≥ 3. Case 2: A1 ⊂ Pk1 . In this case, (A1 ; ) is a proper subsemigroup of (Pk1 ; ) which e := e11 contains, what one can prove as follows: Suppose, e ∈ A1 . Then A1 ∩ [Pk1 [k]] = ∅, since sk = e for all s ∈ Pk1 [k]. Consequently, we have A ⊂ Jk ∪ A = [Jk ∪ A] ⊂ Pk , which contradicts the presupposed maximality of A. Thus A is a clone, for which, by Theorem 2.7.1, (c) A ⊆ P olk G1 (A) ⊆ Pk 2
This is not the only means to describe maximal classes. In [Den-P 88] one can find descriptions of maximal classes of Pk through hyperidentities. One finds more about hyperidentities in the book [Den-W 2000] of K. Denecke and S. L. Wismath.
5.2 Definitions of the Maximal Classes of Pk
165
holds. Because of A1 = Pk1 and the maximality of A, this is possible only for A = P olk G1 (A).
5.2 Definitions of the Maximal Classes of Pk The maximal classes are defined with the aid of the relation sets Mk , Sk , Uk , Lk , Ck and Bk . Indeed, by Theorem 5.1.1, one can describe every maximal class of Pk for k ≥ 3 with the aid of a certain k-ary relation in the form P ol . If P ol is a maximal class, then, P ol = P ol isvalid for all -derivable non-diagonal k relation . Therefore, the elements of h=1 Rkh \Dkh are possible descriptive relations for a maximal class P olk . The subsequently defined relations of Mk , Sk , Uk , Lk , Ck and Bk are (with few exceptions), with respect to the arity, minimally chosen relations, which one can use to describe the maximal classes (see Chapter 10). We say that a maximal class A is a class of type X, if there exist an X ∈ {M, S, U, L, C, B} and a ∈ Xk with A = P olk . 5.2.1 Maximal Classes of Type M (Maximal Classes of Monotone Functions) Let Mk be the set of all partial orders on Ek with a greatest and a least element. More exactly, a binary relation ∈ Rk belongs to Mk if and only if has the following four properties: 1) is reflexive (i.e., ι2k ⊆ ); 2) is antisymmetric (i.e., ∩ −1 = ι2k ); 3) is transitive (i.e., ◦ = ) and 4) there exist elements o (”least element”) and e (”greatest element”) in Ek with {(o , x), (x, e ) | x ∈ Ek } ⊆ . It can easily be shown (see proof of Lemma 6.1.6) that the elements o and e are uniquely determined. We write a ≤ b instead of (a, b) ∈ and a < b, if (a, b) ∈ \ι2k . Furthermore, for a, b ∈ Ekn we put a ≤ b :⇐⇒ ∀i ∈ {1, ..., n} : ai ≤ bi . Obviously, a function f n ∈ Pk preserves the relation ∈ Mk if and only if the following holds: ∀a, b ∈ Ekn : a ≤ b =⇒ f (a) ≤ f (b). Thus the functions of P ol are (non-decreasing) monotone functions. Obviously, we have:
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Lemma 5.2.1.1 ∀, ∈ Mk : (P ol = P ol ⇐⇒ = τ ∨ = ).
For k ∈ {2, 3} all classes of type M are 0 0 1 M = P ol2 , 0 1 1 0 1 2 0 0 1 P ol3 0 1 2 1 2 2 0 1 2 0 0 2 P ol3 0 1 2 2 1 1 0 1 2 2 2 0 P ol3 0 1 2 0 1 1
(0 < 1 < 2), (0 < 2 < 1) and (2 < 0 < 1).
For larger k it is better to give the Hasse diagram, which characterizes the relation in unambiguous way, instead of the elements of . Figures 5.1 and 5.2 give the possible “basic diagrams” (i.e., diagrams without node names) for k = 4 and k = 5; hence (Ek ; ≤ ) is a lattice for k ≤ 5. k=4:
Fig. 5.1 k=5:
Fig. 5.2
For k ≥ 6 there are, however, ∈ Mk , so that (Ek , ) is not a lattice. Figure 5.3 is an example.
5.2 Definitions of the Maximal Classes of Pk
167
Fig. 5.3
5.2.2 Maximal Classes of Type S (Maximal Classes of Autodual Functions) For an arbitrary permutation s ∈ Sk , let s := {(x, s(x)) | x ∈ Ek }. Functions, which preserve a relation of the form s , are called autodual (in respect to s). Let Sk be the set of all relations of the form s , where s is an arbitrary permutation on Ek with k/p cycles of the same prime length p. Some examples for maximal classes of type S are the following: 0 1 P ol2 , 1 0 0 1 2 , P ol3 1 2 0 0 1 2 3 4 5 , P ol6 1 0 3 2 5 4 0 1 2 3 4 5 . P ol6 1 2 0 4 5 3 Subsequently, we assume that an arbitrary permutation s with s ∈ Sk is defined as follows: If k = l · p (p a prime number, l ≥ 1) and {a1,0 , ..., a1,p−1 , a2,0 , ..., a2,p−1 , ..., al,0 , ..., al,p−1 } = Ek , we put s(ar,i ) := ar,i+1 (mod p) (r = 1, 2, ..., l; i = 0, 1, ..., p − 1). Then, it holds
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5 The Maximal Classes of Pk
sa (ar,i ) = ar,i+a (mod p) if a = 0, 1, .... By definition of s , we have for arbitrary function f n ∈ P ol s : s(f (x1 , x2 , ..., xn )) = f (s(x1 ), s(x2 ), ..., s(xn ))
(5.1)
or f (x1 , x2 , ..., xn ) = si (f (sp−i (x1 ), sp−i (x2 ), ..., sp−i (xn ))) (i = 0, 1, ..., p − 1). (5.2) This implies that f (ar,i , x2 , ..., xn ) = si (f (ar,0 , sp−i (x2 ), ..., sp−i (xn ))) (i = 0, 1, ..., p − 1; r = 1, 2, ..., l).
(5.3)
Let Skn be the set of all n-ary functions f ∈ Pk , for which there exists some (n − 1)-ary functions F1 , F2 , ..., Fl ∈ Pk ∪ Ek such that f (x) =
p−1 l
jar,i (x1 ) · si (Fr (sp−i (x2 ), ..., sp−i (xn ))),
(5.4)
r=1 i=0
where + is the addition modulo k, · is the multiplication modulo k and ja is defined by 1 if x = a, ja (x) := 0 otherwise, for a ∈ E2 . We call the function Fr r-th component of f . Theorem 5.2.2.1 It holds: P ol s =
n≥1
Skn .
Proof. For every function f ∈ Pkn there exists a description of the form f (x) =
k−1
ji (x1 ) · f (i, x2 , ..., xn ) (mod k).
(5.5)
i=0
If f ∈ P ol s then it follows from (5.5) with the aid of (5.3): f (x) =
p−1 l
jar,i (x1 ) · si (f (ar,0 , sp−i (x2 ), ..., sp−i (xn ))).
r=1 i=0
Consequently, P ol s ⊆ Let now g ∈ Pkn with g(x) =
p−1 l r=1 i=0
n≥1
Skn .
jar,i (x1 ) · si (Gr (sp−i (x2 ), ..., sp−i (xn ))) ∈ Skn ,
(5.6)
5.2 Definitions of the Maximal Classes of Pk
169
where G1 , G2 , ..., Gl are some (n − 1)-ary functions of Pk . We have to show that g ∈ P olk s . For i ∈ Ep and 1 ≤ r ≤ l it holds: g(s(ar,i ), s(x2 ), ..., s(xn )) = g(ar,i+1 mod p , s(x2 ), ..., s(xn )) = si+1 (Gr (sp−(i+1) (s(x2 )), ..., sp−(i+1) (s(xn )))) = s(si (Gr (sp−i (x2 ), ..., sp−i (xn )))) = s(g(ar,i , x2 , ..., xn )), i.e., g ∈ P olk s . Thus, n≥1 Skn = P olk s . We will need the following lemma to determine the number of maximal classes of Pk later. Lemma 5.2.2.2 ∀s , s ∈ Sk : P olk s = P olk s ⇐⇒ ∃i ∈ {1, ..., k} : si = s . Proof. “=⇒”: Let s, s ∈ Sk and P olk s = P olk s . Then we have Im(s) = Im(s ) = Ek and s, s ∈ P olk s . Therefore, by Lemma 5.2.2.1, we can de are nullary functions, i.e., elscribe s in the form (5.4), where S0 , ..., Sp−1 ements of Ek . Thus, s is unique determined by s (ar,0 ) (r = 1, 2, ..., l). For every r ∈ {1, 2, ..., l}, s (ar,0 ) belongs to {ar,0 , ar,1 , ..., ar,p−1 }, since one receives a contradiction in choosing s in the opposite case, as follows:Suppose we have s (ar,0 ) = as,i with r = s for certain r, s, i. Set V := {as,i , s(ar,i ), ..., sp−1 (ar,i )}. Then, the permutation t with t(x) := s(x) for all x ∈ V and t(x) := x for x ∈ Ek \V belongs to P ol s and, therefore, also to P ol s . Because of s (ar,0 ) = as,i we have (ar,0 , as,i ) ∈ s and, by definition of t, this implies ar,0 ar,0 . = t as,i s(as,i ) Thus, (because of t ∈ P ol s ) as,i = s(as,i ), in contradiction to s ∈ Sk . Let now s (a1,0 ) = a1,i for certain i ∈ Ep . We have to show that s (ar,0 ) = ar,i for all r ∈ {2, 3, ..., l} holds. Suppose s (ar,0 ) = ar,j for certain j ∈ Ep \{i} and r ∈ {2, 3, ..., l}. Then, a function g 2 with g(a1,0 , ar,0 ) = g(a1,0 , ar,j−i (mod p) ) = ar,0 belongs to P olk s , for which we have, by (5.3), a1,0 ar,0 ar,0 g = ∈ s . a1,i ar,j ar,i Hence, the function g does not preserve the relation s , contrary to the assumption P olk s = P olk s . Thus we have s (ar,0 ) = ar,i for all r ∈ {1, 2, ..., l} and si = s holds. “⇐=”: If s, s ∈ Sk and si = s then s s and s s. Hence P olk s ⊆ P olk s and P olk s ⊆ P olk s by Theorem 2.6.3. Thus, P olk s = P olk s .
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5 The Maximal Classes of Pk
5.2.3 Maximal Classes of Type U (Maximal Classes of Functions, Which Preserve Non-Trivial Equivalence Relations) Let Uk be the set of all non-trivial equivalence relations on Ek , i.e., for an arbitrary binary relation ∈ Rk we have: ∈ Uk ⇐⇒ (ι2k ⊆ ∧ −1 = ∧ ◦ = ∧ ∈ {ι2k , Ek2 }). For k = 2, classes of the type U do not occur. For k = 3 there are exactly three classes of the form P ol with ∈ U3 : 0 1 2 0 1 , P ol3 0 1 2 1 0 0 1 2 0 2 and P ol3 0 1 2 2 0 0 1 2 1 2 . P ol3 0 1 2 2 1 In the following, let be an arbitrary relation of Uk . Further, let Ai (i ∈ Ek ) be the equivalence classes (blocks) of this relation. By Lemma 1.4.6, an arbitrary function f n ∈ Pk is representable in the form (1.12). Since, in this case, the used functions fi (i ∈ Ek ) and the function z belong to P ol , the function f preserves the relation if and only if gf ∈ P ol is valid. One can easily show that the functions of the form gf (∈ P ol ) are completely determined through their values on the set {ai | i ∈ Ek }n . Hence, ({gf | f ∈ P ol }; ζ, τ, ∆, ∇, ) is isomorphic to
(Pk ; ζ, τ, ∆, ∇, ).
Let now q a unary function of Pk defined by ∀i ∈ Ek : q(x) = ai :⇐⇒ x ∈ Ai . Then, the following lemma results from our above considerations. Lemma 5.2.3.1 ∀f n ∈ Pk : f ∈ P ol ⇐⇒ ∃hn ∈ P{a0 ...,ak −1 } : gf (x) = h(q(x1 ), ..., q(xn )).
In addition, the following is obviously valid: Lemma 5.2.3.2 ∀, ∈ Uk : P ol = P ol ⇐⇒ = .
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171
5.2.4 Maximal Classes of Type L (Maximal Classes of Quasi-Linear Functions) The maximal classes, which are treated in this section, only occur if k is a prime number power pm . Therefore, we assume k = pm with p ∈ P in this section. Let G be the set of all p-elementary Abelean groups of the form (Ek , ⊕). All elements of such groups, which are different from the neutral element, have the order p, i.e., if o denotes the neutral element of the group (Ek , ⊕) ∈ G, then p is the smallest number with x ⊕ x ⊕ ... ⊕ x = o p times for all x ∈ Ek \ {o}. Let Lk be the set of all relations λG with G := (Ek ; ⊕) ∈ G and λG := {(a, b, c, d) ∈ Ek4 | a ⊕ b = c ⊕ d}. If k is not a prime number power, we set Lk = ∅. One can also describe the maximal classes of the form P ol λG as follows: Since k is a prime number power, it is well-known that one can define certain operations + and · on Ek , so that the algebra GF (pm ) := (Ek ; +, ·) is a field, where the additive group of this field belongs to G. If one now chooses a suitable field with the operations + := ⊕ and · to a group G := (Ek , ⊕) ∈ G, then (by Theorem 1.4.3) every function f n ∈ Pk is uniquely definable through a formula of the form f (x) = ai1 ...in · xi11 · ... · xinn (i1 ...,in )∈Ekn
with the aid of the chosen field operations. A function g n , which is defined through a formula of the specific form g(x) = a0 +
n m−1 i=1 j=0
j
aij · xpi ,
(5.7)
is called quasi-linear. In particular, if m = 1 (i.e., k is a prime number), then g is called a linear function as usual. The set of all quasi-linear functions g n (n = 1, 2, ...) of the form (5.7) is a closed set, as one can easily check with aid of the well-known fact i
i
i
∀i ∈ {0, 1..., m} : (x + y)p = xp + y p , where x, y ∈ GF (pm ). Further, it holds that
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5 The Maximal Classes of Pk
Lemma 5.2.4.1 The following statements are equivalent: (a) f n ∈ P ol λG ; (b) f n is quasi-linear; (c) f (x1 + y1 , x2 + y2 , ..., xn + yn ) = f (x1 , ..., xn ) + f (y1 , ..., yn ) + f (o, ..., o). Proof. (a) ⇐⇒ (c): Because of (x, y, x + y, o) ∈ λG every f n ∈ P ol λG satisfies the condition (c). Conversely, if (c) holds and (xi , yi , ui , vi ) ∈ λG (i = 1, 2, ..., n), then f (x1 , ..., xn ) + f (y1 , ..., yn ) = f (x1 + y1 , ..., xn + yn ) + f (o, ..., o) = f (u1 + v1 , ..., un + vn ) + f (o, ..., o) = f (u1 , ..., un ) + f (v1 , ..., vn ). Thus f ∈ P ol λG . (a) ⇐⇒ (b): Since every quasi-linear function is obviously a superposition i over B := {x + y, xp , a · x, ca | i ∈ {1, .., m − 1} ∧ a ∈ Ek }, and by (5.8) all functions of B preserve the relation λG , the implication (b) =⇒ (a) is valid. In Theorem 5.3.6, we show that the set of all quasi-linear functions is maximal in Pk . Therefore, (a) =⇒ (b) is right. Lemma 5.2.4.2 Let G := (Ek ; +) and G := (Ek , + ) be elements of G. Then, the following statements are equivalent: (a) P ol λG = P ol λG . (b) There exists an element c ∈ Ek such that die mapping α : Ek −→ Ek , x → x + c is an isomorphism from G onto G. (c) λG = λG . Proof. Denote o and o the neutral elements of G and G , respectively. (a) =⇒ (b): Let P ol λG = P ol λG . Then, the function g 2 with g(x, y) = x + y belongs to P ol λG . Because of (x, o , o , x), (o , y, o , y) ∈ λG this implies g(x, y) = g(x, o ) + g(o , y) − g(o , o ) or
x + y = x + y − o .
(5.8)
With the aid of (5.8), one can verify that α(x) := x − o is an isomorphic mapping from G onto G. (b) =⇒ (a): Let α be an isomorphism from G onto G with α(x) := x + c for certain c ∈ Ek . Then, for arbitrary f n ∈ P ol λG by Lemma 5.2.4.1, we have f (o) = f (o + c) = f (o ) + f (c) − f (o) and
f (x + y) = f (x) + f (y) + f (c) − f (c) − f (o) − f (o).
It results from (5.9) and (5.10):
(5.9) (5.10)
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173
f (x + y) = f (x) + f (y) − f (o ). Thus
α(f (x + y)) = (f (x) + c) + (f (y) + c) − (f (o ) + c) = α(f (x)) + α(f (y)) − α(f (o )) = α(f (x) + f (y) − f (o ))
holds because α is an isomorphism. Consequently, by Lemma 5.2.4.1, f preserves the relation λ; hence P ol λG ⊆ P ol λG . Since α−1 is also an isomorphism (from G onto G ), we have also P ol λG ⊆ P ol λG . Thus (a) holds. (a) ⇐⇒ (c) follows easily by means of (a) ⇐⇒ (b). The following representation of quasi-linear functions is better suited for some purposes (for example, determining subclasses of P ol λG ) than the above definition. It is well-known that every group G = (Ek ; +) of G is isomorphic to (W ; ⊕), where W := Epm and (x1 , ..., xm ) ⊕ (y1 , ..., ym ) := (x1 + y1 (mod p), ..., xm + ym (mod p)) for arbitrary (x1 , ..., xm ), (y1 , ..., ym ) ∈ Epm . One can assign a function F n ∈ PW to every function f n ∈ Pk (k = pm ) by means of the isomorphism α, as follows: F n (α(x1 ), ..., α(xn )) := α(f (x1 , ..., xn )). Let LnW be the set of all n-ary functions of PW , for which there are an a ∈ W and some matrices A1 , ..., An ∈ Epm×m such that F (X1 , ..., Xn ) = a + X1 · A1 + ... + Xn · An ,
(5.11)
where + and · are the usual matrix operations and Xi := (xi1 , ..., xin ) ∈ Epm (i = 1, ..., n). Then, we have: Lemma 5.2.4.3 ([Ros 70;a], 7.3.3) LW := n≥1 LnW is isomorphic to P ol λG for all G ∈ G. Proof. It is easy to check that each function of the form (5.11) fulfills the condition (c) of Lemma 5.2.4.1, whereby LW is isomorphic to a subset of P ol λG . 2 LW ∼ = P ol λG follows from the fact that |LnW | = pm+n·m = (pm )1+n·m = k 1+n·m = |(P ol λG )n |. 5.2.5 Maximal Classes of Type C (Maximal Classes of Functions, Which Preserve Central Relations) An h-ary relation γ (1 ≤ h ≤ k − 1) auf Ek is called central, iff γ has the three following properties:
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5 The Maximal Classes of Pk
1) γ is totally reflexive and non-diagonal, i.e., it holds ιhk ⊆ γ = Ekh (ι1k := ∅); 2) γ is totally symmetric, i.e., for every permutation s on {1, 2, ..., h} it holds: (a1 , ..., ah ) ∈ γ =⇒ (as(1) , ..., as(h) ) ∈ γ; 3) there exists at least a central element c ∈ Ek , i.e., (a1 , ..., ah−1 , c) ∈ γ for all a1 , ..., ah−1 ∈ Ek . Let Chk be the set of all central h-ary relations on Ek and Ck := Chk . h≥1
Notice that
C1k = { | ∅ ⊂ ⊂ Ek }.
For k ∈ {2, 3}, only the following classes are defined by central relations: P ol2 (0), P ol2 (1), P ol3 (a) (a ∈ E3 ), P ol3 (a b) if {a, b} ⊆ E3 and a = b, 0 1 2 a b a c if {a, b, c} = E3 . P ol3 0 1 2 b a c a Because of total reflexivity and total symmetry of the relations of Ck , Pk,{a1 ,...,ah } is a subset of P ol γ for every γ ∈ Ck and (a1 , ..., ah ) ∈ γ. With the aid of this property, one can easily prove that the following lemma holds: Lemma 5.2.5.1 ∀γ, γ ∈ Ck : P ol γ = P ol γ ⇐⇒ γ = γ . 5.2.6 Maximal Classes of Type B (Maximal Classes of Functions, Which Preserve h-Universal Relations) In the literature, one finds two possibilities for describing the defining relations of the maximal classes of the type B. Both possibilities go back to papers from I. G. Rosenberg. We begin with the definition from [Ros 65]. At the end of this section, the reader finds the second description for classes of the type B, which uses so-called h-regular relation sets defined in [Ros 70c]. One can represent every a ∈ Ehm (h ≥ 3, m ≥ 1) unique in the form a = a(m−1) · hm−1 + a(m−2) · hm−2 + ... + a(1) · h + a(0) ,
(5.12)
where a(m−1) , a(m−2) , ..., a(0) ∈ Eh are suitably chosen. h ⊆ Ehhm is called h-ary elementary, if it holds: The h-ary relation ξm (i)
(i)
(i)
h (a0 , ..., ah−1 ) ∈ ξm :⇐⇒ ∀i ∈ Em : (a0 , a1 , ..., ah−1 ) ∈ ιhk .
In particular, ξ1h = ιhk for m = 1. An h-ary relation on Ek is a homomorphic inverse image of an h-ary
5.2 Definitions of the Maximal Classes of Pk
175
relation on Ek , if there exists a mapping q from Ek onto Ek , such that, for all a1 , ..., ah ∈ Ek , it holds: (a1 , a2 , ..., ah ) ∈ ⇐⇒ (q(a1 ), q(a2 ), ..., q(ah )) ∈ . Let Bhk be the set of all homomorphic inverse images of the h-ary elementary h and put relation ξm k Bhk . Bk := h=3
Bhk
The elements of are also called h-universal relations. For k = 3 we have B = {ι33 }. To derive a description of the functions from the clone P ol with ∈ Bk without using relations, we assume that is an h-ary relation on Ek which h ⊆ Ehm in is a homomorphic inverse image of the h-ary elementary relation ξm m the following. In addition, let q be the mapping from Ek onto Eh which belongs to this relation because of definition. This mapping defines a partition on Ek in the blocks Ai := {x ∈ Ek | q(x) = i}, i ∈ Ehm . We select a representative ai from every one of these blocks Ai . Further, let r be a unary function with r(i) = ai for all i ∈ Ehm . As already given in Lemma 1.4.6, an arbitrary function f n from Pk is as a superposition over the functions z, gf , fi (i ∈ Ehm ), defined by z(x, y) := xy ( xy = y if ∃i ∈ Ek : x = ai and y ∈ Ai ; xy = x otherwise), gf (x1 , ..., xn ) := ai ⇐⇒ f (x1 , ..., xn ) ∈ Ai , f (x1 , ..., xn ) if f (x1 , ..., xn ) ∈ Ai , fi (x1 , ..., xn ) := otherwise ai (i ∈ Ek ), represents as follows: f (x) = ((...((gf (x)f0 (x))f1 (x))...)fhm −1 (x)).
(5.13)
Since an arbitrary function tn ∈ Phm is describable in the form t(x) = (t(x))(m−1) · hm−1 + (t(x))(m−2) · hm−2 + ... + ((t(x))(0)
(5.14)
(see also (5.12)), we can describe the function from (5.13) with the aid of (5.14) as follows: gf (x) = r(fm−1 (x) · hm−1 + fm−2 (x) · hm−2 + ... + f1 (x) · h + f0 (x)), (5.15)
where fi (x1 , ..., xn ) := (q(f (x1 , ..., xn )))(i) for i ∈ Ehm . Now, one can describe the functions of P ol without using relations, as follows:
176
5 The Maximal Classes of Pk
Theorem 5.2.6.1 ([Lau 78;a]) An n-ary function f ∈ Pk belongs to the class P ol if and only if for the function gf (see (5.15)) is valid: ∀ i ∈ {0, 1, . . . , m − 1} : either (|Im(fi )| ≤ h − 1) or there are j ∈ {1, . . . , n}, v ∈ Em , a permutation s on Eh
(5.16)
such that fi (x1 , . . . , xn ) = s((q(xj ))(v) ) . Proof. Obviously, every function with the properties of the above theorem belongs to the class P ol . We must prove that an arbitrary n-ary function f , which does not fulfill the conditions of the theorem, does not belong to P ol . Case 1: In the description (5.15), for gf , there is an i so that fi is dependent at least of two variables essentially and it holds Im(fi ) = Eh . Then, by Theorem 1.4.4, (b) there exists some h−tuples r1 , ..., rn ∈ ιhk with fi (r1 , ..., rn ) ∈ Ekh \ιhk . Consequently, f (r1 , ..., rn ) ∈ . Case 2: In the description (5.15), for gf , there is an i, so that fi is dependent essentially only of the variable xj (1 ≤ j ≤ n), |Im(fi )| = Eh and fi can not be described in the form fi (x1 , . . . , xn ) = s((q(xj ))(v) ). h 1 ) with fi (x1 , ..., xn ) = F (q(xj )) exists. Case 2.1: No function F ∈ (P ol ξm In this case, there are tuples a = (a1 , ..., an ), b = (b1 , ..., bn ) ∈ Ekn with fi (a) = fi (b) and (q(a1 ), q(a2 ), ..., q(an )) = (q(b1 ), ..., q(bn )). By Im(fi ) = Eh there exist tuples c2 , c3 , ..., ch−1 ∈ Ekn with {fi (a), fi (b), fi (c2 ), ..., fi (ch−1 )} = Eh . Consequently, (f (a), f (b), f (c2 ), ..., f (ch−1 )) ∈ . This and the fact that the columns of the matrix ⎞ ⎛ a ⎟ ⎜b ⎟ ⎜ ⎜ c2 ⎟ ⎟ ⎜ ⎠ ⎝ ... ch−1 belong to imply f ∈ P ol . h 1 Case 2.2: There exists a function F ∈ (P ol ξm ) with fi (x1 , ..., xn ) = F (q(xj )). With the aid of function F , one can define an m-ary function F ∗ ∈ Ph as follows: F ∗ (a(m−1) , a(m−2) , ..., a(0) ) := F (a(m−1) · hm−1 + a(m−2) · hm−2 + ... + a(0) ). If one can not describe the function fi as it is given in the theorem, then the function F ∗ must depend on at least two variables, essentially. With the aid
5.2 Definitions of the Maximal Classes of Pk
177
of Theorem 1.4.4, (b) this implies that f does not preserve . We illustrate the above theorem with the following Examples Let h = 3, m = 2, k = 11, q : E11 −→ E9 be defined by q(x) := x + 1 (mod 9) for x ∈ E9 , q(9) = 4 and q(10) = 1. Further, let the two permutations s1 and s2 be defined by x s1 (x) s2 (x) 0 1 2 1 0 0 2 2 1 For x = x(1) · 3 + x(0) ∈ E9 , let g(x) := s1 (x(0) ) and g (x) := s2 (x(1) ), i.e., x x(1) x(0) g(x) g (x) 0 0 0 1 2 1 0 1 0 2 2 0 2 2 2 3 1 0 1 0 4 1 1 0 0 5 1 2 2 0 6 2 0 1 1 7 2 1 0 1 8 2 2 2 1 Then, the ternary functions f, h ∈ P9 defined by f (x1 , x2 , x3 ) := g(x1 ) · 3 + g (x3 ) (1)
(0)
(here f0 (x1 , x2 , x3 ) = g (x3 ) = s2 (x3 ) and f1 (x1 , x2 , x3 ) = g(x1 ) = s1 (x1 )) and h(x1 , x2 , x3 ) := g(x2 ) · 3 + f (x1 , x2 , x3 ), where Im(f ) ⊂ {0, 1, 2} and |Im(f )| ≤ 2, both belong to Pol ζ2 . The following is an example of a unary function f ∈ P11 (see last column below) that preserves the relation : x q(x) (q(x))(1) (q(x))(0) s1 ((q(x))(1) ) r(x) q(f (x)) f (x) 0 1 0 1 1 1 4 3 1 2 0 2 1 1 4 9 2 3 1 0 0 1 1 10 3 4 1 1 0 1 1 0 4 5 1 2 0 0 0 8 5 6 2 0 2 0 6 5 6 7 2 1 2 0 6 5 7 8 2 2 2 1 7 6 8 0 0 0 1 1 4 3 9 4 1 1 0 1 1 0 10 1 0 1 1 1 4 9
178
since
5 The Maximal Classes of Pk
q(f (x)) = s1 ((q(x))[1] ) · 3 + r(x).
Lemma 5.2.6.2 follows from the definition of the classes of the form P ol with ∈ Bk : Lemma 5.2.6.2 ∀, ∈ Bk : P ol = P ol ⇐⇒ = . Finally, we declare another possibility for describing of h-universal relations. We need the following concepts and notations: Let 3 ≤ h ≤ k, m ≥ 1, hm ≤ k, let ϑi for i ∈ Em be an equivalence relation on Ek and T := {ϑ0 , ..., ϑm−1 }. Then, T is called h-regular if T fulfills the following two conditions: 1) For every i ∈ Em , the equivalence relation ϑi has exactly h equivalence classes. 2) Choosing for every i ∈ Em an equivalence class εi of the relation ϑi m−1 arbitrary, then i=0 εi = ∅. An h-ary relation ⊆ Ekh is called h-regular if there exists an h-regular set T := {ϑ0 , ..., ϑm−1 } such that for arbitrary a0 , ..., ah−1 ∈ Ek it holds: (a0 , ..., ah−1 ) ∈ ⇐⇒ (∀i ∈ Em ∃ {r, s} ⊂ Eh : r = s ∧ (ar , as ) ∈ ϑi ). Lemma 5.2.6.3 ([Ros 70c]) Let 3 ≤ h ≤ k, m ≥ 1, hm ≤ k and ∈ Ekh . Then, is h-universal iff is h-regular. Proof. “=⇒”: Let be h-universal; i.e., there exists a surjective mapping q : Ek −→ Ehm with h (a0 , ..., ah−1 ) ∈ ⇐⇒ (q(a0 ), ..., q(ah−1 )) ∈ ξm .
With the aid of , one can define equivalence relations ϑi ⊆ Ek2 with i ∈ Em as follows: (a, b) ∈ ϑi :⇐⇒ (q(a))(i) = (q(b))(i) . It is easy to check that T := {ϑ0 , ..., ϑm−1 } is h-regular and the h-regular relation T defined with the aid of T is identical with . “⇐=”: Let be h-regular and T := {ϑ0 , ..., ϑm−1 } denotes the corresponding h-regular set. Let εi,0 , εi,1 , ..., εi,h−1 be the equivalence classes of the equivalence relation ϑi for i ∈ Em . Every x ∈ Ek belongs to exactly one equivalence class of ϑi , which we describe with εi,ai (x) . With the help of the numbers ai (x) ∈ Eh one can define a mapping q as follows:
5.3 Proof of the Maximality of the Classes Defined in Section 5.2
q : Ek −→ Ehm , x →
m−1
179
ai (x) · hi .
i=0
Obviously, q is surjective. Furthermore, we have (x0 , ..., xh−1 ) ∈ if and only if ({ai (x0 ), ..., ai (xh−1 )) ∈ ιhh for all i ∈ Em . Consequently, q is a mapping from Ek onto Ehm with h , (x0 , ..., xh−1 ) ∈ ⇐⇒ (q(x0 )), ..., q(xh−1 ) ∈ ξm
i.e., is h-universal.
5.3 Proof of the Maximality of the Classes Defined in Section 5.2 An h-ary relation is called a strong relation iff it fulfills the following two conditions: 1 ∈ P ol : fr,s (r) = s \ιhk = ∅ and ∀r ∈ \ιhk ∀s ∈ ∃fr,s
(5.17)
(ιhk := ∅ for h = 1). A set T ⊆ Ekq is called -independent if for arbitrary pairwise different tuples a1 , a2 , ..., ah of T (ai := (ai1 , ai2 , ..., aiq ) for i = 1, ..., h) there is an j ∈ {1, 2, ..., q} with (a1j , a2j , ..., ahj ) ∈ . Lemma 5.3.1 Let be an h-ary relation with the properties: (a) is a strong relation. (b) For every q ∈ N and for every -independent set T := {a1 , ..., a|T| } ⊆ Ekq it holds
|T |
{(f (a1 ), ..., f (a|T| )) | f ∈ (P ol)q } = Ek .
(5.18)
(c) (h = 1) ∨ (h = 2 ∧ ∩ ιhk ∈ {∅, ιhk }) ∨ (h ≥ 3 ∧ (∃A ⊆ Ek : |A| = h ∧ PEk ,A ⊆ P olk ). Then P ol is maximal in Pk . Proof. Let g m ∈ Pk \P ol be arbitrary; i.e., there are some s1 , ..., sm ∈ with g(s1 , ..., sm ) ∈ . Because of (a) for every r ∈ \ιhk there exists a function fr,si with fr,si (r) = si (i = 1, 2, ..., m). Consequently, the function hr defined by hr (x) := g(fr,s1 (x), ..., fr,sm (x)) has the following properties: hr (r) ∈ and hr ∈ [P ol ∪ {g}]. Let {h1 , h2 , ..., ht } := {hr | r ∈ \ιhk }. It is easy to check that for h ∈ {1, 2} and for every n ∈ N the set Tn := {(x1 , ..., xn , h1 (x1 ), h1 (x2 ), ..., h1 (xn ), h2 (x1 ), h2 (x2 ), ..., n·(t+1)
h2 (xn ), ..., ht (x1 ), ht (x2 ), ..., ht (xn )) | x1 , ..., xn ∈ Ek } ⊆ Ek
180
5 The Maximal Classes of Pk
is -independent. Then, by (b), for every n-ary function f ∈ Pk one can find an n · (t + 1)-ary function f with f (x1 , ..., xn ) = f (x1 , ..., xn , h1 (x1 ), ..., h1 (xn ), ..., ht (x1 ), ..., ht (xn )). Consequently, we have [P ol ∪ {g}] = Pk in the case h ∈ {1, 2}. One can handle the case h ≥ 3 in analog mode when one uses the -independent set Tn := {(x1 , ..., xn , h1 (g1 ), ..., h1 (gu )) | x1 , ..., xn ∈ Ek } with {g1 , ..., gu } := PEnk ,A and suitably chosen h1 instead of Tn . Theorem 5.3.2 ([Jab 58], [Mart 60], [Ros 70;a]) For every ∈ Mk ∪ Uk ∪ Sk ∪ Ck the clone P ol is maximal in Pk . Proof. Obviously, every ∈ Mk ∪ Uk ∪ Sk ∪ Ck satisfies the condition (c) of Lemma 5.3.1. In the following, we show that such relation also fulfills the conditions (a) and (b). For this purpose, hn 1 (n1 ∈ {1, n}) denotes a function of Pk , which either fulfills h (r) = s for arbitrary r (∈ \ιhk ) and s ∈ (see (5.17)), or which can take arbitrary values on an arbitrary -independent set T ⊆ Ekn (see (5.18)). If ∈ Uk ∪Sk ∪Ck , one can consider easily determination for h , so that h ∈ P ol is valid. (For example, if ∈ Ck and h (x) is not yet defined, one sets h (x) = c, where c is a central element of . For ∈ Uk ∪ Sk one can use Lemma 5.2.3.1 and Theorem 5.2.2.1.) If h is a function of the form fr,s with r = Let ∈ Mk in thefollowing. α a ∈ and s = ∈ , then β b a if x < α, h := b otherwise, is a function of P ol. If h is supposed to be determined in the above manner through a -independent set T and (5.18), we put for all x ∈ Ekn \T : o if ∃a ∈ T : x < a, h := e otherwise, where o is the least element and e is the greatest element of Ek in respect to . The function h defined in this way belongs to P ol, as one can prove as follows: Suppose h ∈ P ol. Then, there exists some a, b ∈ Ekn with {a, b} ⊆ T , a < b and t := (h (a), h (b)) ∈ {(α, o), (e, α), (e, o)} ⊆ Ek2 \ for a certain α ∈ Ek \{o, e}. If t = (α, o), we have a ∈ T and thus b ∈ T . Because of h (b) = o, this implies (by the definition of h ) the existence of a c ∈ T with b < c, whereby a < c for a, c ∈ T , in contradiction to the construction of
5.3 Proof of the Maximality of the Classes Defined in Section 5.2
181
T . In similar way one can show that t ∈ {(e, α), (e, o)} is also not possible: If t = (e, α), then b ∈ T and a ∈ T ; hence h (a) = o by the definition of h , in contradiction to h (a) = e. If t = (e, o) then the following three cases are possible: Case 1: a ∈ T and b ∈ T . Because of b ∈ T and h (b) = o there exists a c ∈ T with b < c. By a < b; however, this implies a < c, what was impossible for tuples a, c ∈ T . Case 2: a ∈ T and b ∈ T . This case contradicts the definition of the function h : h (a) = o, since a ∈ T and a < b ∈ T . Case 3: a ∈ T and b ∈ T . Because of h (b) = o and b ∈ T there exists a c ∈ T with b < c. Then a < c is also valid, however; hence h (a) = o, in contradiction to the assumption h (a) = e. Thus our assertion results from Lemma 5.3.1. Theorem 5.3.3 ([Ros 70;a]) For every ∈ Bk the clone P ol is a maximal class of Pk . Proof. Let be defined as in Section 5.2.6. Then, one can represent an arbitrary function f n ∈ Pk \P ol in the form (4.14), (5.15) (see also Lemma 1.4.6), where, by Theorem 5.2.6.1, there exists a function fi that takes all values of {0, 1, ..., h − 1} on some tuples r1 , ..., rn ∈ (see also the proof of Theorem 5.2.6.1). Since g(x) := (q(x))(i) ∈ P ol and Pk,B ⊆ P ol for all B := {b1 , .., bh } with (b1 , ..., bh ) ∈ , the function g f = fi and a function of Pk,h are superpositions over f and some functions of Pk,B ⊂ [P ol ∪ {f }]. Therefore, by Lemma 1.4.5, Pk,h ⊆ [P ol ∪ {f }]; hence all functions of Pk are superpositions over P ol ∪ {f } (see Lemma 1.4.6 and Theorem 5.2.6.1). Now, we come to the proof of the maximality of the classes of type L. For this purpose, let k = pm (p prime, m ≥ 1) and let G := (Ek ; +, ·) be a field with (w.l.o.g.) the zero element 0 and the unit element 1. Let QG be the set of all quasi-linear functions (in respect to G) of Pk . We need two lemmas for proof of the Pk -maximality of QG . Lemma 5.3.4 ([Ros 70;a], 7.2.19) Let f n ∈ Pk \QG (k = pm ). Then [QG ∪ {f }] contains a function of the form h(x, y) =
m p −1
aij · xi · y j ,
i,j=0
which has at least a coefficient ast = 0 with 0 < s, t ≤ pm−1 . Proof. By Theorem 1.4.3, one can represent f in the form (1.9). Because of f ∈ Pk \QG , the following two cases are possible:
182
5 The Maximal Classes of Pk
Case 1: There exists at least a coefficient ai1 ...in with |{i1 , i2 , ..., in }\{0}| ≥ 2. Obviously, in this case, one receives the function h from the function f by identifying some variables and by substituting variables through c1 . Case 2: Each addend different of zero in the formula (1.9) has the form i a0...0ij 0...0 · xjj and there exists a q with g(x) := f (c0 , ..., c0 ,
x , c0 , ..., c0 ) ∈ Pk \QG . q -th place
pm −1 Since c0 ∈ QG , we have g ∈ [QG ∪ {f }]. Now let g(x) := i=0 bi · xi and let d be the greatest index in such kind that d is not a power of p and bd = 0 holds. Then one can also write d in the form d = d1 · pt , where t ≥ 0 and d1 > 0 is relatively prime to p. pm −1 When one forms the function w(x, y) := g(x + y) = i,j=0 aij xi y j , so surrent
t
ders with the aid of the binomial of xd−p y p is theorem that the coefficient d d identical with ad−pt ,pt = · bd . Next, we show that is relatively pt pt prime to p. Obviously, we have: d1 pt (d1 pt − 1)..(d1 pt − p)..(d1 pt − p2 )..(d1 pt − pt + 1) d d 1 pt . = = t t p p pt (pt − 1)......(pt − p)....(pt − p2 )...(pt − pt + 1)
In the numerator and denominator of the above number, some factors, which one can divide by a power of p, stand. When one divides the above fraction by corresponding powers of p, one receives! a"fraction whose factors have the form a + b with p|a and p |b. Therefore, pdt is relatively prime to p. Hence (by bd = 0) ad−pt ,pt = 0. Lemma 5.3.5 ([Ros 70;a], 7.2.11) pm −1 Let h(x, y) = i,j=0 aij xi y j with ast = 0 for some 0 < s, t ≤ pm − 1. Then the function r(x, y) = xs · y t belongs to [QG ∪ {f }]. Proof. Let (u, v) ∈ Ep2m with (u, v) = (s, t). W.l.o.g. we can assume u = s. For a primitive element α of Ek (i.e. for an α ∈ Ek with {αi | 1 ≤ i ≤ pm − 1} = Ek \{0}, see e.g. [Lid-N 87]) we form the superposition g(x, y) := αu · h(x, y) − h(α · x, y) over {h(x, y), αu · x − y, α · x} ⊆ QG ∪ {f }. Then it holds g(x, y) :=
m p −1
(αu − αi ) · aij · xi · y j ,
i,j=0
and we put aij := (αu − αi ) · aij . Obviously, auj = 0. By the properties of a primitive element and because of u = s we have αu = αs and thus ast = 0.
5.4 The Number of the Maximal Classes of Pk
183
Furthermore, aij = 0, if aij = 0. Through repeated use of this construction for every (u, v) = (s, t), one obtains a function d with d(x, y) = dst xs y t and dst = 0. Let b ∈ Ek \{0} be the inverse element of dst . Since b · x ∈ QG , we have b · dst · xs · y t = xs · y t ∈ [QG ∪ {h}]. Theorem 5.3.6 ([Ros 70;a], 7.2.12) Let k = pm (p prime, m ≥ 1). Then, for every λG ∈ Lk (G := (Ek ; +, ·) is a field) the clone P olk λG is maximal in Pk . Proof. W.l.o.g. let 0 be the zero element and let 1 be the unit element of G. In the proof of Lemma 5.2.4.1 we saw that QG ⊆ P olλG . Since P olλG = Pk and QG = [QG ] are also valid, we have only to show the Pk -maximality of QG . Let f ∈ Pk \QG be arbitrary. Then, by Lemmas 5.3.4 and 5.3.5, a function r(x, y) = xs · y t belongs to [QG ∪ {f }], where 0 < s, t ≤ pm − 1. One can also give s and t in the form s = h · pu and t = l · pv , where u, v ≥ 0 and i m h, l are relatively prime to p. Since xp ∈ QG (i ∈ Em ) and xp = x holds, m−u m−v we have w(x, y) := r(xp , yp ) = xh · y l ∈ [QG ∪ {f }]. If one forms now the superposition q(x, y) := w(x + 1, y + 1) over QG ∪ {f }, then one gets the following with the aid of the binomial theorem: h
l
(x + 1) · (y + 1) =
m p −1
aij · xi · y j .
i,j=0
It is easy to check that a11
h l = · = h · l. 1 1
Since h and l are relatively prime to p, this implies a11 = 0 and, therefore, x · y belongs to [P olG ∪ {f }] because of Lemma 5.3.5, Thus, {x · y, x + y, a · x, ca (x) | a ∈ Ek } ⊆ [QG ∪ {f }] holds. Obviously, [QG ∪ {f }] = Pk results from that then because of Theorem 1.4.3.
5.4 The Number of the Maximal Classes of Pk Let
Rmax (Pk ) := Mk ∪ Sk ∪ Uk ∪ Lk ∪ Ck ∪ Bk .
Because of Lemmas 5.2.1.1 and 5.2.2.2 the following relation ∼ is an equivalence relations on Mk ∪ Sk : ∼ :⇐⇒ ∃X ∈ {M, S} : {, } ⊆ Xk ∧ P olk = P olk . When one selects exactly a representative from every equivalence class of ∼, ∼ one receives the relation sets M∼ k ⊆ Mk and Sk ⊆ Sk .
184
5 The Maximal Classes of Pk
Theorem 5.4.1 ([Ros 69]) Let ∼ ∼ (Pk ) := M∼ Rmax k ∪ Sk ∪ Uk ∪ Lk ∪ Ck ∪ Bk . ∼ Then for all , ∈ Rmax it holds:
P olk = P olk ⇐⇒ = .
∼
(5.19) ∼
Proof. Let ∈ Xk and ∈ Yk with X, Y ∈ {M , S , U, L, C, B}. If X = Y, then one can easily prove the assertion (by constructing functions f , g with f ∈ P olk \P olk and f ∈ P olk \P olk ). In the case X = Y the assertion (5.20) follows from Lemmas 5.2.1.1, 5.2.2.2, 5.2.3.2, 5.2.4.3, 5.2.5.1 and 5.2.6.2.
Theorem 5.4.2 ([Ros 73]) For k ≥ 2 there is exactly ∼ ∼ |Rmax | = |M∼ k | + |Sk | + |Uk | + |Lk | + |Ck | + |Bk |
(5.20)
maximal classes of Pk and it is valid: • |M∼ k|=
k·(k−1) 2
· o(k − 2),
where o(i) denotes the number of all different partial order relations on an i-element set (o(0) := 1); 1 k! • |S∼ k|= k=m·p, p prime p−1 · m!·pm ; • |Uk | = z(k) − 2, where z(i) denotes the number of all partitions on a k-element set, which one can calculate as follows: k i=0
• |Lk | = • |Ck | =
(−1)i ·
(k−1)!
i t=0
p( 2 ) ·(p−1)·(p2 −1)·...·(pm −1) m
0
1≤h
− 1,
(−1)t ·
tk ; t! · (i − t)! k = pm , p prime,
, if otherwise;
! " ! " ! " k−1 k−2 0 where ch (k) := k1 · 2( h ) − k2 · 2( h ) + ... + (−1)k−1 · kk · 2(h) and !x" h := 0, if x < h); • |Bk | = 3≤h≤k b(k, h), where b(k, h) :=
m≥0,hm ≤k
for h ≥ 3.
m h h 1 t · ( (−1) · · (hm − t)k ) m! · (h!)m t=0 t m
5.4 The Number of the Maximal Classes of Pk
185
(Specific numbers are given in the following tables.3 )
k 2 3 4 5 6 7 8 ∼ |Rmax | 5 18 82 643 15 182 7 848 984 549 761 933 169 k |M∼ k| |S∼ k| |Uk | |Lk | |Ck | |Bk |
2 1 1 0 1 2 0
3 3 1 3 1 9 1
4 18 3 13 1 40 7
5 6 7 8 9 10 190 3285 88 851 3 640 644 6 35 120 105 1120 19 089 50 201 875 4398 6 0 120 30 840 0 355 11490 7 758 205 549 758 283 980 36 171 813 4012
∼ Proof. In Chapter 6, we prove that {P olk | ∈ Rmax } is the set of all maximal classes of Pk . Because of Theorem 5.4.1, we have to determine the numbers |Xk | with X ∈ {M∼ , S∼ , U, L, C, B}. Case 1: X = M∼ . Obviously, there are k · (k − 1) possibilities to choose a greatest element and a smallest element of a relation ∈ Mk . Consequently, we have |Mk | = k·(k−1) · o(k − 2). k · (k − 1) · o(k − 2); with the aid of Lemma 5.2.1.1: |M∼ k|= 2 Case 2: X = S∼ . Let k = p · m, p prime, m ≥ 1. Then k k−p k − 2p p k! · · · ... · = p p p p m! · pm
is the number of the possible permutations s on Ek , which have exactly m cycles of the length p. Because of Lemma 5.2.2.2 the p − 1 permutations exactly the same maximal class P olk s . Therefore, s, s2 , ..., sp−1 determine k! 1 | = we have |S∼ k k=m·p, p prime p−1 · m!·pm . Case 3: X = U. Obviously, |Uk | = z(k) − 2, where z(k) denotes the number of the possible partitions of a k-element set. Case 4: X = L. Let k = pm , p prime, m ≥ 1. First, we determine |G|, where (as in Section 5.2.4) G is the set of all elementar Abelean p-groups of the form (Ek ; ⊕). As is generally known, every group G ∈ G is isomorphic to an m-fold direct product V := (Zpm ; +) of the group (Zp ; + (mod p)). If s : Zpm −→ Ek is a bijective mapping, then one can define Gs := (Ek ; +s ) as follows: 3
To |M∼ 8 | see also [Com 66], [Rad 83] and [Roz 85].
186
5 The Maximal Classes of Pk
∀x, y ∈ Ek : x +s y := s(s−1 (x) + s−1 (y)). It is easy to check that Gs = Gt ⇐⇒ s−1 t is an automorphism holds for arbitrary bijective mappings s, t from Zpm onto Ek . Consequently, we have k! , |G| = |A| where A denotes the set of all automorphisms on V . Since |A| is identical with the number of the bases of V , we obtain |A| = (pm − 1) · (pm − p) · (pm − p2 ) · ... · (pm − pm−1 ) = p · p2 · ... · pm−1 · (pm − 1) · (pm−1 − 1) · ...(p2 − 1) · (p − 1) m = p( 2 ) · (pm − 1) · (pm−1 − 1) · ... · (p − 1). Furthermore, by Lemma 5.2.4.2, we have |Lk | = |G| k . This implies our assertion about |Lk |. Case 5: X = C. Let Ah be the set of all h-element subsets of Ek , 1 ≤ h ≤ k. Then one can assign an element a of P(Ah ) as follows to every totally reflexive, totally symmetric, h-ary relation in unique manner: {a0 , a1 , ..., ah−1 } ∈ a ⇐⇒ (a0 , a1 , ..., ah−1 ) ∈ \ιhk .
(5.21)
Consequently, if belongs to Chk and the set of all central elements of contains the set C, then by means of (5.21), the relation is unambiguously definite through a subset a of Th,C := {A ∈ Ah | A ∩ C = ∅}. Because of |Th,C | = !k−|C|" k−|C| and |P(T )| = 2( h ) one obtains the number of elements of Ch ∪ h,C
h
{Ekh } through use of the principle of the inclusion and exclusion: k−1 k−2 0 k k k · 2( h ) + ... + (−1)k−1 · · 2( h ) − · 2(h) , ch (k) := 2 1 k
where
!x" h
:= 0 for x < h. Consequently, we have |Ck | =
k−1
h=1 ch (k)
k
− 1.
Case 6: X = B. Let h ≥ 3 and m ≥ 1. A bijective mapping s from Ehm onto Ehm is called an automorphism of ξm , if ∀(a0 , a1 , ..., ah−1 ) ∈ ξm : (s(a0 ), s(a1 ), ..., s(a0 )) ∈ ξm . Let and be relations of Bhk ; i.e., there exists certain mappings q or q from Ek onto Ehm or Ehm with = q −1 (ξm ) and = q −1 (ξm ), respectively (see Section 5.2.6). Next, we show that the equivalence
5.4 The Number of the Maximal Classes of Pk
187
= ⇐⇒ m = m ∧ (5.22) (∃ automorphism s on ξm : ∀x ∈ Ek : q (x) = s(q(x)) ) holds. “=⇒”: If = , then it follows from the definition of the relations = q −1 (ξm ) or = q −1 (ξm ) that the mapping equivalences κα := {(x, y) ∈ Ek2 | α(x) = α(y)} for α ∈ {q, q } are identical. Then, κq = κq implies the right side of the equivalence (5.22). “⇐=” follows from (a0 , a1 , ..., ah−1 ) ∈ ⇐⇒ ⇐⇒ ⇐⇒ ⇐⇒
(q(a0 ), q(a1 ), ..., q(ah−1 )) ∈ ξm (s(q(a0 )), s(q(a1 )), ..., s(q(ah−1 ))) ∈ ξm (q (a0 ), q(a1 ), ..., q (ah−1 )) ∈ ξm (a0 , a1 , ..., ah−1 ) ∈ .
Denote b1 (k, h) the number of the mappings from Ek onto Ehm and denote b2 (h, m) the number of the automorphisms on ξm . Because of (5.22), we have |Bhk | =
b1 (k, h) . b2 (h, m)
(5.23)
With the aid of the principle of the inclusion and exclusion, one can calculate the number b1 (k, h) as follows: m
h
hm b1 (k, h) = (−1) · t t=0 t
· (hm − t)k .
(5.24)
For the purpose of determining b2 (h, m) the following considerations follows directly from the definition of the automorphisms of ξm that these are some functions of P olk ξm . Then, we have (because of the bijectivity of the automorphisms and by Theorem 5.2.6.1) that each automorphism s of ξm has a representation of the form s(x) =
m−1
si (x( tx ) ) · hi ,
(5.25)
i=0
where s0 , s1 , ..., sm−1 are some permutations on Eh and {t0 , t1 , ..., tm−1 } = Em holds. Therefore, (5.26) b2 (h, m) = m! · (h!)m . Then, (5.23)–(5.26) imply our assertion. We notice that there are also asymptotic estimates for the number of all maximal classes of Pk . One can take further information on that from the book [P¨ os- K 79] (p. 111) or the original papers [Kuz 59] and [Zac K J 64].
188
5 The Maximal Classes of Pk
5.5 Remarks to the Maximal Classes of Pk(l) For A ⊆ Pk , l ∈ N, l ≤ k, ∈ Rk put A(l) := {f ∈ A | |Im(f )| ≤ l}, P ol := (P olk )(l), λk := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ Ek }. Let Mk (l) be the set of all partial orders on Ek with the property that every l-element subset of Ek has a least and a greatest element with respect to . Notice that Mk (k) = Mk . We say that the h-ary relation on Ek is an l-central relation if = Ekh is totally reflexive, totally symmetric, and for every l-element subset E of Ek there exists an element cE ∈ E with (a1 , ..., ah−1 , cE ) ∈ for all a1 , ..., ah−1 ∈ E. The element cE is called a central element of ∩ E h . Let Chk (l) be the set of all h-ary l-central relations on Ek and let Ck (l) := l−1 h h=1 Ck (l). Notice that Ck (k) = Ck . Since any unary relation is totally reflexive and totally symmetric, we have C1k (l) = { ⊂ Ek | k − l + 1 ≤ || < k}. For the next definition, we need some notations of Section 5.2.6 and χ() := {α1 , ..., ah } ⊆ Ek | (a1 , ..., ah ) ∈ }. Notice that a totally reflexive and totally symmetric h-ary relation is completely determined by the set χ(). Bhk (l) denotes the set of all h-ary non-diagonal relations with the following three properties: (1) ∀E ⊆ Ek : |E| = l =⇒ ∩ E h ∈ Bhk ∪ {E h }, (2) ∀E ⊆ Ek : |E| = l =⇒ (∃idE ∈ (P ol)1 : ∀x ∈ E : idE (x) = x); (3) ∀A, B ∈ χ() : (A = B =⇒ ∃gA,B ∈ (P ol)1 : gA,B (A) = B). Example: Let be k = 5, l = 4 and h = 3. Then, the totally reflexive and totally symmetric h-ary relation with χ() := {A1 , A2 , A3 }, A1 := {0, 1, 2}, A2 := {1, 2, 3}, A3 := {1, 2, 4} is an element of Bhk (l), since ∩ {0, 2, 3, 4}4 = {0, 2, 3, 4}4 , ∩ {0, 1, 3, 4}4 = {0, 1, 3, 4}4 and ∩ {1, 2, 3, 4}4 , ∩ {0, 1, 2, 4}4 and ∩ {0, 1, 2, 3}4 are homomorphic inverse images of the relation ι33 and the functions idt := idE5 \{t} (t ∈ E5 ) and gpq := gAp ,Aq (p = q, p, q ∈ {1, 2, 3}) satisfy the conditions (2) and (3) (see the below indicated tables).
5.5 Remarks to the Maximal Classes of Pk (l)
x 0 1 2 3 4 x 0 1 2 3 4 Put
id0 id1 id2 id3 id4 3 0 0 0 0 1 0 1 1 1 2 2 0 2 2 3 3 3 4 3 4 4 4 4 3
g12 g13 g21 g23 g31 g32 1 1 2 4 2 3 2 2 0 1 0 1 3 4 1 2 1 2 1 1 2 4 2 3 1 1 2 4 2 3 l−1
Bk (l) :=
189
h=3
∅
Bhk (l) if
l > 3,
otherwise.
Let Hk (l) be the set of all l-ary totally reflexive and totally symmetric relations = Ekh that satisfy the above condition (3). Examples for such relations are, as follows: 1) ιlk ; 2) E := Ekl \ {(as(0) , as(1) , ..., as(l−1) ) | s permutation on El }, where E := {a0 , ..., ah−1 } and |E| = l; 3) every relation of Blk (see [Lau 88d]). For l = 2 we define Hk (2) := {Ek2 \ {(a, b), (b, a)} | (a, b) ∈ Ek2 \ ι2k }. Theorem 5.5.1 ([Lau 92a]; without proof ) Let A ⊆ Pk (l), 2 ≤ l < k and Rk (l) := Mk (l) ∪ Uk ∪ Ck (l) ∪ Bk (l) ∪ Hk (l). Then (a) [A] = Pk (l) ⇐⇒ ((∀ ∈ Rk (l) : A ⊆ P ol) ∧ (l = 2 =⇒ A ⊆ P olλk )). (b) P ol is Pk (l)-maximal for every ∈ Rk (l) and (P olλk )(2) is Pk (2)maximal. (c) The maximal classes of Pk (2) are sets of the form (P ol )(2) with ∈ C1k (2) ∪ Mk (2) ∪ Uk ∪ Hk (2) ∪ {λk }; i.e., every maximal class of P olk (l), which is not equal (P olk λ)(2), is a intersection of Pk (2) with a certain maximal class of Pk .
190
5 The Maximal Classes of Pk
We remark that for l ≥ 3 not every Pk (l)-maximal class is an intersection of Pk (l) with a certain maximal class of Pk . An example for this fact is the relation {(a, b, c) ∈ E53 | {a, b, c} ∈ {{0, 3, 4}, {1, 2, 3}}} ∈ C35 (4). Notice that the Pk (l)-maximality of the class P ol for ∈ Mk (l) was proven by V. Kolpakov in [Kol 74].
6 Rosenberg’s Completeness Criterion for Pk
Since Pk is finitely generated, every proper subclass of Pk belongs to a certain maximal class of Pk ; therefore, by Theorem 1.5.3.1, it follows that a subset T of Pk is complete (i.e., it holds [T ] = Pk ) if and only if T is not a subset of a maximal subclass of Pk . The aim of this chapter is to prove that the classes of Chapter 5 are all maximal classes of Pk :
Theorem 6.1 (Rosenberg’s Completeness Criterion for Pk ; [Ros 65], [Ros 70;a]) For an arbitrary subset T of Pk it holds: [T ] = Pk ⇐⇒ ∀ ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk : T ⊆ P ol.
(6.1)
6.1 Proof of Completeness Criterion By Section 4.9, the equivalence (6.1) follows from (6.2), which we still must prove: A is maximal in Pk =⇒ (6.2) ∃γ ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk : A ⊆ P olγ. Denote A an arbitrary maximal class of Pk in the following. To simplify the proof of (6.2), some assumptions over A are given. These assumptions result from the following considerations: • We show in Chapter 4 that there is exactly a Pk -maximal class that contains Pk1 . In addition, were shown that every other Pk -maximal class has k the form P ol, where ∈ h=1 Rkh .
192
6 Rosenberg’s Completeness Criterion for Pk
• For every -derivable relation ’, which is not diagonal, we have by Theorem 2.6.3 that P ol ⊆ P ol ⊂ Pk . Obviously, if P ol is Pk -maximal then for an arbitrary -derivable non-diagonal relation ’ it holds: P ol = P ol . • Every unary non-diagonal relation ∈ Rk (i.e., ∅ ⊂ ⊂ Ek ) describes a maximal class of Pk (see Theorem 5.3.2). Thus, w.l.o.g. we can assume that our maximal class A of Pk can be described by a certain h-ary relation : A = P ol (1 ≤ h ≤ k). Further, we assume w.l.o.g. that fulfills the three conditions (I) P ol is Pk -maximal and (P ol)1 = Pk1 ;
k (II) For every -derivable h -ary relation ∈ h=1 Rkh it holds: (a) ∈ InvPk =⇒ h ≥ h (i.e., is a relation with minimal arity which describes the maximal class P ol); (b) (h = h = 2 ∧ = ∩ (τ )) =⇒ ∈ Dk2 ∪ {} (i.e., by ∩ (τ ) no other relation which describes P ol either is derivable. With other words: If possible, we choose a symmetrical relation for the description of P ol; (c) (h = h ≥ 2 ∧ ιhk ⊆ ⊆ ∧ ( is totally symmetric ∨ (h = 2 ∧ is antisymmetric) )) =⇒ ∈ {, Ekh } (i.e., if is totally reflexive and totally symmetric or reflexive and antisymmetric, then for the description of the class P ol we choose a binary relation which has the greatest cardinality.); (III) is not a unary relation, i.e., h ≥ 2. Now, we want to prove: If fulfills the obove conditions (I)–(III), then or a -derivable relation belongs to Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk . (6.3) (6.3) implies (6.2) and our Theorem 6.1 follows from (6.2), which was already mentioned. For k = 2 it is easy to check that only the relations 0 1 0 0 1 and 1 0 0 1 1 satisfy (I)–(III); hence (6.1) is clearly for k = 2. Therefore, let k≥3 be in the following. In the proof of (6.1) for k ≥ 3 we use the notations for relations and relation
6.1 Proof of Completeness Criterion
193
operations from Sections 2.1–2.5. In particular, ◦ denotes the relation product and let i := ◦ ◦ ...o .1 i times An h-tuple a from Ekh with h ≤ k we often give in the form (a0 , a1 , ..., ah−1 ), i.e., we also choose the indices from Ek . Remember that a relation ’ is called -derivable iff can be obtained by a finite number of applications of the relation operations (see 2.3) from and the diagonal relations. The following lemma is easy to check (see also Theorem 2.11.2): Lemma 6.1.1 ([Ros 70;a], 4.1.2) Each relation of the form C := {(a0 , ..., at−1 ) | ∃at , ..., am·h−1 ∈ Ek : (∀i : (aci1 , ..., acih ) ∈ )}, where C := (cij )m,h is a matrix of type (m, h) with elements from Em·h , is a -derivable relation. We remark that every one of the following claims on -derivability of a certain relation almost follows from the above lemma. For the proof of (6.1), we distinguish two cases:
Case 1: h = 2. Figure 6.1 gives a survey on the possible subcases and on the following lemmas. For 2 ≤ i ≤ k, the relation σi () := {(a1 , ..., ai ) | ∃u ∈ Ek : {(a1 , u), ..., (ai , u)} ⊆ } is a -derivable relation and it holds: Lemma 6.1.2 σ2 () = Ek2 =⇒ (∀i ∈ {2, 3, ..., k} : σi () = Eki ). Proof. We prove the statement by induction on i ≥ 2. For i = 2 the statement holds by assumption. Assume, σt−1 = Ekt−1 is valid for certain t−1 ∈ {2, ..., k− 1}. Then, by definition of σt (), we have ιtk ⊆ σt (). If ιtk ⊆ σt () ⊂ Ekt , then σt () is no invariant of Pk and hence (by (I)) P ol = P olσt () holds. This is, however, a contradiction of the fact that Pk (2) ⊆ P olσt (), whereby P olσt () does not have any description by a binary relation. Therefore, σt () = Ekt . Lemma 6.1.3 Either is reflexive (i.e., ι2k ⊆ ) or there exists a -derivable relation ’ which belongs to Sk . 1
For content-related reasons, it is not possible to confuse the index i with the arity of .
194
6 Rosenberg’s Completeness Criterion for Pk
is reflexive
is not reflexive
6.1.4 is symmetric 6.1.5
6.1.3
is antisymmetric 6.1.6 6.1.7
∈ Uk ∪ C2k
∈ Mk
∈ Sk
Fig. 6.1. A survey about the proof in Case 1
Proof. The relation 1 := ∩ ι2k is -derivable. If we have ∅ ⊂ 1 ⊂ ι2k , then pr1 is a non-diagonal -derivable unary relation, in contradiction to (IIa). Thus, is reflexive or areflexive. Now, let be areflexive. Since pr0 = pr1 = Ek holds by (II), we have ι2k ⊆ ◦ ζ =: . Because of this, (I) and the fact that P ol does not contain any constants, it follows that ∈ {ι2k , Ek2 }. If = Ek2 , then by ◦ ζ = σ2 () and by Lemma 6.1.2, we get a contradiction to the areflexivity of . Therefore, = ι2k holds, i.e., is a fixed-point free permutation on Ek . If has not k/t cycles of the same length, then there is an i with ∅ ⊂ i ∩ ι2k ⊂ Ek2 and we have pr(i ∩ ι2k ) ∈ C1k , in contradiction to (IIa). Thus, the permutation has cycles of the same length t. The length t is a prime number, since for t = p · q (p prime, q ≥ 2), the -derivable relation := q has only cycles of prime length p. Therefore ’ belongs to Sk . Lemma 6.1.4 Let be reflexive. Then is either symmetric (i.e., ∩ζ = ) or antisymmetric (i.e., ∩ ζ = ι2k ). Proof. Since ι2k ⊆ , ι2k ⊆ ∩ ζ ⊆ holds, and by (IIb) we have ∩ ζ = ι2k or ∩ ζ = . Lemma 6.1.5 Let be reflexive and symmetric. Then ∈ Uk ∪ C2k . Proof. It is easy to check that ι2k ⊂ ⊆ ◦ . Then by (IIc) the following three cases are possible: Case 1: ◦ = . Obviously, in this case, is transitive and ∈ Uk .
6.1 Proof of Completeness Criterion
195
Case 2: ◦ = Ek2 . Since ◦ = σ2 (), σk () = Ekk follows from Lemma 6.1.2. Hence, for Ek there is a u ∈ Ek with {(e, u) | e ∈ Ek } ⊆ . Thus the relation belongs to C2k . Lemma 6.1.6 Let be reflexive and antisymmetric. Then, for Ek , there exists (with respect to ) a greatest element e ∈ Ek and (with respect to ) a least element o ∈ Ek , i.e., it holds: {(x, e ), (o , x) | x ∈ Ek } ⊆ , and these elements are uniquely determined. Proof. Since is reflexive, we have ι2k ⊆ ⊆ σ2 (). It is obvious that the relation σ2 () is symmetric and thus ⊂ σ2 (). This and (IIc) imply σ2 () = Ek2 . Then, because of k ≥ 3 and with the aid of Lemma 6.1.2, we have σk () = Ekk . Hence we find an e ∈ Ek with {(x, e ) | x ∈ Ek } ⊆ . Then e is a greatest element of Ek . The uniqueness of e is to see as follows: Assume there are two greatest elements a, a ∈ Ek . Then we have (a, a ) ∈ and (a , a) ∈ and thus a = a by the antisymmetry of . The existence of a unique least element can be shown analogously starting with the -derivable relation σi (ζ) instead of σi (). Lemma 6.1.7 Let be a reflexive and antisymmetric relation with the property that Ek has a (unique) least and a (unique) greatest element with respect to . Then is transitive, i.e., ∈ Mk . Proof. We consider the -derivable relation 2 . Since ⊆ 2 , by (IIc) only the cases 2 = (i.e., is transitive) or 2 = Ek2 are possible. Let’s assume ◦ = Ek2 and let o be least element of Ek with respect to . Then we have (a, o ) ∈ for a ∈ Ek \{o }, (a, o ) ∈ ◦ and there is a b ∈ Ek with (a, b) ∈ and (b, o ) ∈ . However, this cannot hold by the antisymmetry of and by the choose of o . Thus the case 2 = Ek2 cannot occur and 2 = holds. Summing up, we have in Case 1: ∈ Uk ∪ Mk ∪ C2k ∪ Sk .
Case 2: h ≥ 3. Figure 6.2 gives a survey about the proof in this case.
196
6 Rosenberg’s Completeness Criterion for Pk
h=3
h≥4
6.1.8
is not totally reflexive
satisfies (*)
is totally reflexive
6.1.9
6.1.10
6.1.11 ... 6.1.15
a relation λ ∈ Lk is -derivable and k = pm , p prime
is totally symmetric
6.1.16
∈ Ck
is strongly homogeneous 6.1.17 ... 6.1.22 ∈ Bk
Fig. 6.2. A survey about the proof in Case 2
First, we give some conclusions of the assumptions (I)–(III) over .
(IV )
∀r ≤ h − 1 ∀i1 , ..., ir ∈ Eh : pri1 ,...,ir = Ekr .
Since, if ∩ ιhk = ∅, pr1,2 is not an invariant of Pk , we have by (IIa) (V )
∩ ιhk = ∅.
Obviously, it follows from (IIa):
6.1 Proof of Completeness Criterion
(V I)
197
∀δ ∈ Dkh \{Ekh } : ∩ δ ∈ Dkh .
If \ιhk = ∅, then, by (V I), the relation is an primitive relation (i.e., a union of certain diagonal relations), which is preserved by all unary functions of Pk . Hence it follows from (I): (V II) \ιhk = ∅. Lemma 6.1.8 If 4 ≤ h ≤ k, then either is totally reflexive or satisfies the following condition: (*): h = 4 ∧ | | = k 3 ∧ 4 4 4 ∪ δ{0,2},{1,3} ∪ δ{0,3},{1,2} ⊆ . δ{0,1},{2,3} Proof. First, note that for every (a, b), (b, c), (c, d) ∈ Eh2 \ι2h with |{a, b, c, d}| = 4, the implications
and
(h ≥ 4 ∧ (x0 , ..., xh−1 ) ∈ ∧ xa = xb ) =⇒ xb = xc
(6.4)
(h ≥ 5 ∧ (x0 , ..., xh−1 ) ∈ ∧ xa = xb ) =⇒ xc = xd
(6.5)
do not hold by (IV ). Next we will prove (∃(a, b) ∈ Eh2 \ι2h : δ{a,b} ⊆ ) =⇒ (∀(c, d) ∈ Eh2 \ι2h : δ{c,d} ⊆ ).
(6.6)
For this, it is sufficient to show that δ{0,1} ⊆ =⇒ δ{1,2} ⊆
(6.7)
holds. Let δ{0,1} ⊆ . Then we have δ{0,1,2} ⊆ ∩ δ{1,2} . Furthermore, by (V I) ∩ δ{1,2} is diagonal. Thus ∩ δ{1,2} ∈ {δ{0,1,2} , δ{1,2} }. Since an implication of form (6.4) follows from ∩ δ{1,2} = δ{0,1,2} , δ{1,2} ⊆ holds and therefore (6.7) and (6.6). For the proof of the total reflexivity of , we consider the relation 1 := ∩ δ{0,1} , which by (V ) and (V I) is a nonempty diagonal relation. Since the implications (6.4) and (6.5) are not true for , we have if h ≥ 5, = δ{0,1} 1 ∈ {δ{0,1},{2,3} , δ{0,1} } if h = 4.
198
6 Rosenberg’s Completeness Criterion for Pk
By (6.6) we have only to examine the case h = 4 and δ{0,1},{2,3} ∪ δ{0,2},{1,3} ∪ {0,3},{1,2} ⊆ . Obviously, either satisfies the condition (*) and our proof is closed or it holds || > k 3 . Let || > k 3 . Therefore w.l.o.g. there exists certain ai ∈ Ek (i = 0, 1, 2, 3) with (a0 , a1 , a2 , a3 ) ∈ , (a0 , a1 , a2 , a3 ) ∈ , a3 = a3 .
(6.8)
Then the -derivable relation 2 := {(a1 , a2 , a3 , a3 ) | ∃a0 : (a0 , a1 , a2 , a3 ) ∈ ∧ (a0 , a1 , a2 , a3 ) ∈ } has the properties (since pr1,2,3 =
2 ∩ δ{2,3} = δ{2,3}
(6.9)
Ek3 ), δ{2,3} ⊂ 2 (by (6.8)) and 2 ⊂ Ek4 .
Thus 2 is not an invariant of Pk . Further, is totally reflexive by (6.9) and (6.6). Then, by definition of 2 , we have now ∩ δ{0,1} = δ{0,1},{2,3} , a contradiction to our assumptions on . Lemma 6.1.9 If is totally reflexive, then is totally symmetric. Proof. The total symmetry of follows from (IIb) via ιhk ⊆ s∈Sh s ⊆ , where Sh denotes the set of all permutations on Eh and s denotes the relation {(as(0) , ..., as(h−1) ) | (a0 , ..., ah−1 ) ∈ }. Consequently, for the proof of (6.1), it is sufficient to examine the following cases: 2.1. satisfies (*) or it holds: h = 3 and is not totally reflexive and 2.2. h ≥ 3 and is totally symmetric and totally reflexive.
Case 2.1: satisfies (*) or h = 3 and ∩ ιhk = ιhk . W.l.o.g. we can assume that there does not exist a -derivable relation which is non-diagonal and totally reflexive.
6.1 Proof of Completeness Criterion
199
Lemma 6.1.10 The ternary relation is either of the form (a) = σ ∪ δ{0,1,2} with the properties ∅ ⊂ σ ⊆ Ek3 \ι3k and for any a, b ∈ Ek there are exactly a c1 , exactly a c2 and exactly a c3 with (c1 , a, b), (a, c2 , b), (a, b, c3 ) ∈ ; or of the form (b) = σ ∪ δ{a,b} ∪ δ{a,c} with ∩ s = δ{a,b} , where ∅ ⊂ σ ⊆ Ek3 \ι3k , {a, b, c} = {0, 1, 2}, s(a) := b, s(b) := a, s(c) := c and s := {(as(0) , as(1) , as(2) ) | (a0 , a1 , a2 ) ∈ }. Proof. By (V I) and (V II) it is sufficient to examine w.l.o.g. the following cases: = σ ∪ δ{0,1,2} (6.10) = σ ∪ δ{0,1}
(6.11)
= σ ∪ δ{0,1} ∪ {0,2}
(6.12)
Ek3 \ι3k .
where ∅ ⊂ σ ⊆ First let be of the form (6.11). A -derivable relation in this case is the totally symmetric relation i := {(a1 , ..., ai ) | ∃a, b : (∀i : (ai , a, b) ∈ )} (i = 2, 3, ..., k). Obviously, this relation has the property ∀i ∈ {2, ..., k − 1} : i = Eki =⇒ i+1 totally reflexive.
(6.13)
By our assumption in Case 2.1 and by (I) it follows from the total symmetry and total reflexivity of i+1 that i+1 = Eki+1 . However, this cannot occur, since for i = k − 1 it holds (0, 1, ..., k − 1) ∈ k =⇒ ∃a, b ∈ Ek : {(0, a, b), ..., (b, a, b), ..., (k − 1, a, b)} ⊆ } and ∩ ι3k = δ{0,1} is not possible. Thus our relation is not of the form (6.11), since we can show that 2 = Ek2 : δ{0,1} ⊆ implies ι2k ⊆ 2 . By pr0,1 = Ek2 there are certain a, b (a = b) and c with (a, b, c) ∈ . Furthermore we have (b, b, c) ∈ . Thus (a, b) ∈ 2 and 2 = Ek2 by (IIa). If = σ ∪ δ{0,1,2} and assumed does not fulfill the condition of (a) (w.l.o.g. for c3 ), then the -derivable relation := {(b, c, c ) | ∃a : (a, b, c) ∈ ∧ (a, b, c ) ∈ } is a non-diagonal relation of the form (6.11), of which we have shown that it cannot describe a maximal class of Pk . If has the form (6.12), it must hold ∩ (τ ) = δ{0,1} , since, in the opposite case, the -derivable relation ∩ (τ ) has the form (6.11). Thus by Lemma 6.1.10, we can assume w.l.o.g. that is either of the form (6.10) or (6.12) and fulfills the conditions of Lemma 6.1.10.
200
6 Rosenberg’s Completeness Criterion for Pk
Lemma 6.1.11 It is possible to derive from a quaternary non-diagonal relation λ with the following 8 properties: 1) λ ∩ δ{0,2} = δ{0,2},{1,3} = λ ∩ δ{1,3} 2) λ ∩ δ{0,3} = δ{0,3},{1,2} = λ ∩ δ{1,2} 3) ∩ ι3k = δ{0,1} ∪ δ{0,2} ⇒ δ{0,1},{2,3} ⊆ λ 4) λ ∩ (τ λ) = λ, where τ λ := {(b, a, c, d) | (a, b, c, d) ∈ λ} 5) λ ∩ (λ)s = λ, where (λ)s := {(d, c, b, a) | (a, b, c, d) ∈ λ} 6) ∀x, y, z, z , o ∈ Ek : (x, y, z, o) ∈ ∧ (x, y, z , o) ∈ =⇒ z = z 7) pr0,1,3 λ = Ek3 8) pr0,2,3 λ = Ek3 . Proof. If the condition (*) fulfills, it is easy to check that the -derivable relation λ := ∩ τ () ∩ {(d, c, b, a) | (a, b, c, d) ∈ } has the properties 1)–8), since it is possible in the opposite case to derive a non-diagonal totally reflexive, ternary relation from λ, in contradiction to the assumptions in Case 2.1. Let now h = 3 and let be a relation of the form (6.10) or (6.12) in the following. A -derivable relation is λ11 if has the form (6.10), λ1 := λ12 if has the form (6.12), where λ11 := {(a, b, c, d) | ∃u, v : {(u, d, a), (d, v, b), (u, v, c)} ⊆ } and λ12 := {(a, b, c, d) | ∃u1 , ..., u4 , v1 , ..., v4 : {(u1 , a, c), (u2 , b, d), (u3 , a, d), (u4 , b, c), (v1 , a, c), (v2 , b, d), (v3 , a, d), (v4 , b, c), (b, d, u1 ), (a, c, u2 ), (b, c, u3 ), (a, d, u4 ), (d, b, v1 ), (c, a, v2 ), (c, b, v3 ), (d, a, v4 )} ⊆ }. With the help of the properties of , which are given in Lemma 6.10, it is easy to see that λ1 fulfills the conditions 1)–3). Since δ{0,2},{1,3} ∪ δ{0,3},{1,2} ⊆ λ11 ∩ (τ λ11 ) ∩ (λ11 )s and
δ{0,2},{1,3} ∪ δ{0,3},{1,2} ∪ δ{0,1},{2,3} ⊆ λ12 ∩ (τ λ12 ), ∩(λ12 )s
6.1 Proof of Completeness Criterion
201
the non-diagonal relation λ := λ1 ∩ (τ λ1 ) ∩ (λ1 )s has the properties 1)–5). Furthermore, for any i, j ∈ E4 , i = j, it holds pri λ = Ek and pri,j λ = Ek2 .
(6.14)
If λ does not fulfill 6), we can derive the non-diagonal relation λ := {(c, c , a) | ∃b, d : (a, b, c, d) ∈ λ ∧ (a, b, c , d) ∈ λ} from λ. However λ is of the form σ ∪ δ{0,1} with ∅ ⊂ σ ⊆ Ek3 \ι3k (by 1) and 2)), what is not possible by the proof of Lemma 6.1.10. Thus λ fulfills 1)–6). If = σ∪δ{0,1,2} , the properties 7) and 8) follow from (6.14), from the property (a) of Lemma 6.1.10 and from the definition of λ1 . If has the form σ ∪ δ{0,1} ∪ δ{0,2} , then we have ι3k ⊆ pr0,α,3 λ (α ∈ {1, 2}) by 1)–3) and hence pr0,α,3 λ = Ek3 , since the case pr0,α,3 λ ⊂ Ek3 is a contradiction to our assumptions over . By Lemma 6.1.11( 6), 7)) with the aid of λ, we can define for a fixed o ∈ Ek an operation +o on Ek as follows: x +o y = z :⇐⇒ (x, y, z, o) ∈ λ.
(6.15)
Lemma 6.1.12 The operation +o has the following properties: 1) (Ek ; +o ) is an Abelean group with the identity element o. 2) There exists a prime number p so that every element of Ek \ {o} has the order p and it holds k = pm for certain m ≥ 1. Proof. 1): All properties of +o (except the associativity), which we have to show, follow directly from Lemma 6.1.11. By 1) of Lemma 6.1.11 o is the identity element of (Ek , +o ). Because of 4)–8) for every a ∈ Ek there exists an inverse element a ∈ Ek with a +o a = o. The operation +o is kommutative by 4). For proof of the associativity of +o , we consider the λ-derivable relation λ := {(a, b, c) | (a +o b) +o c = a +o (b +o c)} = {(a, b, c) | ∃u, v, w : {(a, b, u, o), (u, c, v, o), (b, c, w, o), (a, w, v, o)} ⊆ λ}, which is totally reflexive by {(o, a, a), (a, o, a), (a, a, o) | a ∈ Ek } ⊆ λ and (II). However, this is only possible if λ = Ek3 by our assumptions over . Thus +o is associative. 2): A λ-derivable relation is µn := {(x, o) | x +o x +o ... +o x = o} n times = {(x, o)|∃ui : {(x, x, u1 , o), (u1 , x, u2 , o), ..., (un−2 , x, o, o)} ⊆ λ}.
202
6 Rosenberg’s Completeness Criterion for Pk
By o +o o = o for all o ∈ Ek this relation is reflexive. Assume there exists two elements of Ek \{o} with the orders n and m (= n) respectively. Then we have ι2k ⊂ µn ⊂ Ek2 , in contradiction to our assumptions over . Thus all elements (= o) of (Ek , +o ) have the same order. Now it is easy to show that this order is a certain prime number p: If n > 1 is not a prime number, there exist r, s ∈ N with n = r · s, 1 < r < n and 1 < s < n. For a b ∈ Ek \ {0} we set c := s · b := b +o b +o ... +o b = o. Then we have c = o and r · c = n · b = o, s times a contradiction to the above-proven fact that the order of b is n. k = pm for a certain m is a conclusion from well-known theorems about Abelian groups. Lemma 6.1.13 For every x, y, o, o1 ∈ Ek it holds: 1) x +o1 x = x +o x −o o1 2) x +o1 o = x −o o1 3) k ≥ 4 =⇒ x +o1 y = x +o y −o o1 . Proof. To prove i) (i ∈ {1, 2, 3}) we consider certain λ-derivable relations λi : λ1 := {(x, o1 , o) | x +o1 x = x +o x −o o1 } = {(x, o1 , o) | ∃u, v, w : {(x, x, u, o1 ), (x, x, v, o), (o1 , w, o, o), (v, w, u, o)} ⊆ λ}, λ2 := {(x, o, o1 ) | x +o1 o = x −o o1 } and
= {(x, o, o1 ) | ∃u, v : {(x, o, u, o1 ), (o1 , v, o, o), (x, v, u, o)} ⊆ λ}
λ3 := {(x, y, o, o1 ) | x +o1 y = x +o y −o o1 } = {(x, y, o, o1 ) | ∃u, v, w : {(x, y, u, o1 ), (o1 , v, o, o), (x, y, w, o), (w, v, u, o)} ⊆ λ}. If we can show that λ1 , λ2 and λ3 are totally reflexive relations, then we have λ1 = λ2 = Ek3 and λ3 = Ek4 for k ≥ 4 by our assumptions in Case 2.1 and the statements of Lemma 6.1.13 are proven. For all x, o ∈ Ek we have: – (x, x, o) ∈ λ1 , since x +x x = x = x +o x −o x. – (x, o1 , x) ∈ λ1 , because for v = x, w = u and Lemma 6.1.11, 5) the conditions of definition of λ1 hold. – (x, o, o) ∈ λ1 , since x +o x = x +o x −o o. Thus 1) is proven. For all x, o, o1 ∈ Ek it holds: – (o, o, o1 ) ∈ λ2 , because o +o1 o = o +o o −o o1 = o −o o1 by 1). – (o1 , o, o1 ) ∈ λ2 , since o1 +o1 o = o = o1 −o o1 . – (x, o, o) ∈ λ2 by x +o o = x = x −o o.
6.1 Proof of Completeness Criterion
203
Thus b) is proven). 3) follows from – (x, x, o, o1 ) ∈ λ3 by 1); – (o, y, o, o1 ) ∈ λ3 , since o +o1 y = y +o1 o = y −o o1 = o +o y −o o1 by 2); – (o1 , y, o, o1 ) ∈ λ3 by o1 +o1 y = y = o1 +o y −o o1 ; – (x, o, o, o1 ) ∈ λ3 , since (by 2)) x +o1 o = x −o o1 = x +o o −o o1 ; – (x, o1 , o, o1 ) ∈ λ3 since x +o1 o1 = x = x +o o1 −o o1 ; – (x, y, o, o) ∈ λ3 , since x +o y = x +o y −o o. Lemma 6.1.14 For every o ∈ Ek and all a, b, c, d ∈ Ek the following equivalence holds: (a, b, c, d) ∈ λ ⇐⇒ a +o b = c +o d. Proof. If k ≥ 4 then we have by definition of +o and by Lemmas 6.1.12 and 6.1.13: (a, b, c, d) ∈ λ ⇐⇒ a +d b = c ⇐⇒ a +d b = a +o b −o d = c ⇐⇒ a +o b = c +o d. For k = 3 our statement follows from Lemma 6.1.11, 1), 2), 5) and Lemma 6.1.13, 1). Then the following lemma is a conclusion from the Lemmas 6.1.11, 6.1.12, and 6.1.14: Lemma 6.1.15 The -derivable relation λ belongs to Lk . Proof. If k ≥ 4, then λ ∈ Lk (k = pm , p prime, m ≥ 1) follows from the Lemmas 6.1.9, 6.1.10 and 6.1.12. For k = p = 3 the relation λ := {(a, b, c, d) | ∃α : a +o b = α +o α ∧ c +o d = α +o α} is -derivable and belongs to Lk . Summing up: Our Case 2.1 is only possible if k is a prime power. Furthermore, we have for k = pm : P ol = P olλ for certain λ ∈ Lk .
Case 2.2: is totally reflexive and totally symmetric. Since Pk (h − 1) ⊆ P ol for every totally reflexive h -ary relation (h ≥ 2), it is not possible to find a totally reflexive h -ary relation with P ol = P ol and h > h. Thus we can assume the following property for : (V III)
∀ ∈ [{} ∪ InvPk ]h : h < h ≤ k ∧ ιhk ⊆ =⇒ = Ekh .
204
6 Rosenberg’s Completeness Criterion for Pk
An h-ary, totally reflexive, and totally symmetric relation γ we will call strongly homogeneous, if the following holds: (∃v0 , ..., vh−1 ∈ Ek : (v0 , ..., vh−1 ) ∈ γ ∧ ∀i ∈ Eh ∀j ∈ Eh \{i} : (a0 , ..., aj−1 , vi , aj+1 , ..., ah−1 ) ∈ γ) =⇒ (a0 , a1 , ..., ah−1 ) ∈ γ.
(6.16)
Lemma 6.1.16 Either is central or strongly homogeneous. Proof. First we consider the -derivable relation t := {(a0 , ..., at−1 ) | ∃c : (∀i0 , ..., ih−2 ∈ Et : (ai0 , ..., aih−2 , c) ∈ ))}, for t ∈ {h, h + 1, ..., k}. The total symmetry of implies that t is totally symmetric. By choosing c = a0 for t = h, we see that ⊆ h . Thus by our assumption (IIc), only the following two cases are possible: Case 1: h = Ekh . Then we have h < k since, in the opposite case, = Ekk holds by definition of . Obviously, for h < k, the -derivable relation h+1 is totally reflexive and thus, by (V III), h+1 = Ekh+1 . By induction, it is easy to see that i = Eki for all i ∈ {h + 1, ..., k}. Then, ∈ Ck follows from k = Ekk . Case 2: = h . In this case, is homogeneous, i.e., has the property (∃v : ∀i ∈ Eh : (a0 , ..., ai−1 , v, ai+1 , ..., ah−1 ) ∈ ) =⇒ (a0 , a1 , ..., ah−1 ) ∈ . for arbitrary a0 , a1 , ..., ah−1 ∈ Ek . We consider the -derivable relation γt := {(a0 , ..., at−1 ) | ∃v0 , v1 , ..., vt−1 : (∀i1 , ..., ih ∈ Et : (vi1 , ..., vih ) ∈ ) ∧ (∀n ∈ Et ∀j1 , ..., jh−2 ∈ Et \{n} : (aj1 , ..., ajh−2 , an , vn ) ∈ )} (t ∈ {h, h + 1, ..., k}). Obviously, γt is totally symmetric and, if γt−1 = Ekt−1 , is totally reflexive. Furthermore, ⊆ γh for h = t. (This follows from the definition of γh by setting vα = aα for all α ∈ Eh .) = γh implies that is strongly homogeneous. Now by (IIc) we have γh ∈ {, Ekh }. Thus our lemma is proven if we can show that γh = Ekh cannot occur. Assume γh = Ekh and h < k. Then γh+1 is totally reflexive. Thus, γh+1 = Ekh+1 by (V III) and γk = Ekk via induction. Hence, for every a0 , ..., ah−1 ∈ Ek there exists certain v0 , ..., vh−1 ∈ Ek with (v0 , v1 , ..., vh−1 ) ∈
(6.17)
6.1 Proof of Completeness Criterion
205
and ∀n ∈ Eh ∀α1 , ..., αh−2 ∈ Ek \{an } : (α1 , ..., αh−2 , an , vn ) ∈ .
(6.18)
With the help of this and by induction, we can show that ∀t ≥ 0 ∀a0 , ..., at−1 ∈ Ek : (a0 , ..., at−1 , vt , vt+1 , ..., vh−1 ) ∈
(6.19)
holds: For t = 0, (6.19) follows from (6.17). Assume (6.19) holds for t = n. Then (6.19) for t = n + 1 is a conclusion from the induction hypothesis, the homogeneity of , the totally symmetry of and from (6.18) putting v = vn in (6.16) for the tuple (a0 , ..., an , vn+1 , ..., vh−1 ). By (6.19) and t = h, we get a contradiction to ⊂ Ekh : ∀a0 , ..., ah−1 ∈ Ek : (a0 , ..., ah−1 ) ∈ . Hence γh = Ekh cannot occur and thus γh = , i.e., is strongly homogeneous. By Lemma 6.1.16, we have to show for the proof of our theorem that, if is strongly homogeneous, the relation or a -derivable relation belongs to Bk . Thus we can assume that is subsequently a strongly homogeneous relation. For this relation, we will prove first that is a homomorphic inverse image of a certain relation ξ and then that the relation ξ is isomorphic to a certain elementary h-ary relation ξm .2 Lemma 6.1.17 The relation ε := {(a, b) ∈ Ek2 | ∀a0 , ..., ah−3 ∈ Ek : (a0 , a1 , ..., ah−3 , a, b) ∈ } is an equivalence relation on Ek . Proof. By the total reflexivity and total symmetry of , it follows directly the reflexivity and symmetry of ε. To prove the transitivity of ε, let {(a, b), (b, c)} ⊆ ε. Choosing v0 = α0 , v1 = α1 , ..., vh−3 = αh−3 , vh−2 = b and vh−1 = b in (6.16) for the tuple (α0 , α1 , ..., αh−3 , a, c), we get (α0 , ...., αh−3 , a, c) ∈ for arbitrary α0 , ..., αh−3 ∈ Ek . Hence, (a, c) ∈ ε. By the equivalence relation ε, the set Ek is partitioned into certain (nonempty) equivalence classes Ai (i = 1, 2, ...., r), from which we choose a representative αi . With the help of the representative set V := {α1 , ..., αr } we can define a mapping F : Ek −→ V by F (a) = αi :⇐⇒ {a, αi } ⊆ Ai . 2
See Lemma 6.1.22 to the concept “isomorphic”.
206
6 Rosenberg’s Completeness Criterion for Pk
Lemma 6.1.18 Let be strongly homogeneous. Then (a) (a0 , ...., ah−1 ) ∈ ⇐⇒ (F (a0 ), ..., F (ah−1 )) ∈ (b) ((∀a0 , ..., ah−3 ∈ V : (a0 , ..., ah−3 , a, b) ∈ ) ∧ {a, b} ⊆ V ) =⇒ a = b. Proof. (a): First, we show that the equivalence (a, a1 , ..., ah−1 ) ∈ ⇐⇒ (b, a1 , ..., ah−1 ) ∈
(6.20)
holds for (a, b) ∈ ε and for all a0 , ..., ah−1 ∈ Ek . If (a, a1 , ..., ah−1 ) ∈ then (b, a1 , ...., ah−1 ) ∈ follows from the strong homogeneity of , choosing v0 = v1 = .... = vh−1 = a. Since ε is symmetric, we have also proven “⇐=” of (6.20). Now (a) follows from (6.20) because of (ai , F (ai )) ∈ ε (i ∈ Eh ), Lemma 6.1.17 and of the total symmetry of : (a0 , ...., ah−1 ) ∈ ⇐⇒ ⇐⇒ ⇐⇒ ⇐⇒
(F (a0 ), a1 , ..., ah−1 ) ∈ (F (a0 ), F (a1 ), a2 , ..., ah−1 ) ∈ ... (F (a0 ), ..., F (ah−1 )) ∈ .
(b) is a conclusion from the definitions of ε and V and from (a). Now put ξ := F () := {(F (a0 ), ..., F (ah−1 )) | (a0 , ..., ah−1 ) ∈ }. By Lemma 6.1.18, (a) is a homomorphic inverse image of this relation, i.e., = {(a0 , ..., ah−1 ) ∈ Ekh | (F (a0 ), ..., F (ah−1 )) ∈ ξ} holds. Since = Ekh , ζ = V h . Thus w.l.o.g. we can assume V = Er and (0, 1, ..., h − 1) ∈ V h \ξ. To show that ξ is isomorphic to a certain h-ary elementary relation ξm (⊆ Ehhm ), i.e., that there is a bijective mapping ϕ of Ehm onto V with the property ξ = {(ϕ(a0 ), ..., ϕ(ah−1 )) | (a0 , ..., ah−1 ) ∈ ξm } we consider the -derivable hi -ary graphic i
Ghi (P ol) := χhi ∪ {f (κ1 , ..., κhi ) | f ∈ (P ol)h }, where χhi := (κ1 , ..., κhi ) is the hi -ary abscissa over Ek (in matrix form; see Section 2.7), i ∈ {h, h + 1, ..., k}. Let j1 , ..., ji be the numbers of those rows of χhi for which Ai := prj1 ,...,ji χhi is a matrix form of the relation Ehi . Further, let µi := prj1 ,...,ji Ghi (P ol).
6.1 Proof of Completeness Criterion
207
Lemma 6.1.19 If is strongly homogeneous and (0, 1, 2, ..., h − 1) ∈ , then µi = Eki for every i ∈ {h, h + 1, ..., k}, i.e., the functions of P ol can take every value of Ek on every row of the matrix Ai . Proof. First, we remark that = Ekh \{(a0 , ..., ah−1 ) | {a0 , ..., ah−1 } = Eh } because of ∈ Ck . Further, if (b0 , ..., bh−1 ) ∈ , all functions g with Im(g) = {b0 , ..., bh−1 } belong to P olk . Suppose the lemma is false for i = h. Then, we can form an h-ary relation with ⊂ ⊂ Ekh with the help of the hi -th graphic of P ol by projection, contradicting (IIc). Since all functions of P ol, which have at most hi essential variables, belong i+1 it is easy to show by induction that it holds: to (P ol)h ∀i ∈ {h, ..., k − 1} : µi = Eki =⇒ ιi+1 ⊆ µi+1 . k Consequently, our lemma follows from (V III). By Lemma 6.1.19, we can find an hk -ary function f ∈ P ol with the properties Im(f ) = V and
⎛
⎞ F (0) ⎜ F (1) ⎟ ⎟. f (Ak ) = ⎜ ⎝ ⎠ ... F (k − 1)
Next we will give some properties of this function f , from which will follows ∈ Bk . k Recall, f ∈ P ol means on tuples of Ehh that f preserves the relation ιhh . k The elements z of Ehh we also give in the form (z[1], z[2], ..., z[hk ]) k
and, for every z ∈ Ehh , denote z t,a (t ∈ {1, 2, ..., hk }, a ∈ Eh ) k
an element of Ehh , which is defined by a, if i = t, z t,a [i] := z[i] otherwise (i ∈ {1, 2, ..., hk }). k
Lemma 6.1.20 Let t ∈ {1, 2, ..., hk }, z ∈ Ehh and (f (z t,0 ), ..., f (z t,h−1 )) ∈ ξ. Then (a) f (z t,0 ) = ... = f (z t,h−1 ), k
(b) ∀w ∈ Ehh : f (wt,0 ) = ... = f (wt,h−1 ).
208
6 Rosenberg’s Completeness Criterion for Pk
Proof. (a): For proof, it is sufficient to show that (w.l.o.g.) f (z t,h−2 ) = f (z t,h−1 ). First, we prove k
∀b0 , ..., bh−3 ∈ Ehh : (f (b0 ), ..., f (bh−3 ), f (z t,h−2 ), f (z t,h−1 )) ∈ ξ.
(6.21)
If {b0 [t], b1 [t], ..., bh−3 [t]} = {0, 1, ..., h − 3}, then (6.21) holds, since in this case, all columns of the matrix ⎛ ⎞ b0 ⎜ b1 ⎟ ⎜ ⎟ ⎜ ... ⎟ ⎜ ⎟ B := ⎜ ⎟ h−3 ⎟ ⎜ bt,h−2 ⎝z ⎠ z t,h−1 belong to ιhh and f preserves . Let w.l.o.g. bi [t] = i for i ∈ Eh−2 . Substituting the i-th row of B by z t,j , where i = j, we obtain a matrix Bi,j whose columns belong to ιhh . Hence f (Bi,j ) ∈ ξ holds. Consequently, by the strong homogeneity of , choosing vj = f (z t,j ) (j ∈ Eh ) for the tuple (f (b0 ), ..., f (bh−3 ), f (z t,h−2 ), f (z t,h−1 )), we get (6.21). k Since {f (α) | α ∈ Ehh } = V , for all a0 , ..., ah−3 ∈ V there are certain k b0 , ..., bh−3 ∈ Ehh with f (bi ) = ai (i ∈ Eh−2 ). Thus by (6.21) we have ∀a0 , ..., ah−2 ∈ V : (a0 , ..., ah−3 , f (z t,h−2 ), f (z t,h−1 )) ∈ ξ. Then, with the help of Lemma 6.1.18, (b) it follows f (z t,h−2 ) = f (z t,h−1 ). (b): Because of (a) it is sufficient to show that (f (wt,0 ), ...., f (wt,h−1 )) ∈ ξ
(6.22)
holds. By (6.21), it follows (f (wt,0 ), ..., f (wt,h−3 ), f (z t,h−2 ), f (z t,h−1 )) ∈ ξ. It is easy to check that every exchange of an i-th row in ⎞ ⎛ wt,0 ⎜ wt,1 ⎟ ⎟ ⎜ ⎝ ... ⎠ wt,h−1 by wt,j for i ∈ Eh−3 or by z t,j for i ∈ {h − 2, h − 1} and i = j, gives a matrix M, whose columns belong to ιhh , and it holds f (M) ∈ ξ. Hence by the strong homogeneity of , choosing v0 = f (wt,0 ), ..., vh−3 = f (wt,h−3 )), vh−2 = f (z t,h−2 ) and vh−1 = f (z t,h−1 ), we get (6.22). Lemma 6.1.21 For the function f , there exists certain digits t1 , ..., tm , which k are exactly the essential digits of f|E hk (restriction of f to Ehh ), and f has h
k
different values on any two different tuples of Ehh , i.e., it holds
6.1 Proof of Completeness Criterion k
∀z, w ∈ Ehh : f (z) = f (w) ⇐⇒ ∀i ∈ {t1 , ..., tm } : z[i] = w[i].
209
(6.23)
Further, f has the properties |Im(f )| = hm and ∀r1 , ..., rhk ∈ Ehh : ({rt1 , ..., rtm } ⊆ ιhh =⇒ f (r1 , ..., rhk ) ∈ )
(6.24)
Proof. For every t ∈ {1, 2, ..., hk }, we have either f (z t,0 ) = f (z t,1 ) = ... = k f (z t,h−1 ) for every z ∈ Ehh or (f (z t,0 ), f (z t,1 ), ..., f (z t,h−1 )) ∈ for all z ∈ k Ehh by Lemma 6.1.20. Let T := {t1 , ..., tm } be the set of all t ∈ {1, 2, ..., hk }, for which (f (z t,0 ), ..., f (z t,h−1 )) ∈ holds. Now, we will show that the digits ti ∈ T have the properties of Lemma 6.1.21. First, let f (z) = f (w) for certain k z, w ∈ Ehh and assume there exists an i ∈ T with α := z[i] = w[i]. Then, the columns of the matrix ⎛ i,0 ⎞ z ⎜ ... ⎟ ⎜ i,α−1 ⎟ ⎜z ⎟ ⎜ ⎟ ⎜ A := ⎜ w ⎟ ⎟ ⎜ z i,α+1 ⎟ ⎜ ⎟ ⎝ ... ⎠ z i,h−1 belong to ιhh . Thus f (A) ∈ ξ and by f (w) = f (z) = f (z i,α ) it follows (f (z i,0 ), ..., f (z i,h−1 )) ∈ ξ, a contradiction to i ∈ T and to the definition of T . Therefore “=⇒” in (6.23) holds. Let now z[i] = w[i] for every i ∈ T and w.l.o.g. T = {1, 2, ..., m}. f (w) = f (z) is proven, if we can show that f (un−1 ) = f (un )
(6.25) k
holds for every tuple un := (z[1], ..., z[n], w[n + 1], w[n + 2], ..., w[h ]) and all n ∈ {m + 1, m + 2, ..., hk }, since f (um ) = f (w) and f (uhk ) = f (z). By n > m n,j and the definition of T , we have f (un,i n−1 ) = f (un−1 ) for every i, j ∈ Eh . As n,w[n] n,z[n] un−1 = un−1 and un−1 = un we have (6.25) and (6.23) is proven. k (6.23) and {f (x) | x ∈ Ehh } = V imply |V | = hm . Finally, we prove (6.24). Assume (6.24) is false. Then there exists certain k z0 , z1 , ..., zh−1 ∈ Ehh with (f (z0 ), f (z1 ), ..., f (zh−1 )) ∈ ξ and (w.l.o.g.) zi [1] = k i for all i ∈ Eh and 1 ∈ T . Let w ∈ Ehh . Then, all columns of the matrix ⎛ ⎞ w1,0 ⎜ ... ⎟ ⎜ 1,j−1 ⎟ ⎜w ⎟ ⎜ ⎟ 1,i ⎜ ⎟ Ci,j := ⎜ zj ⎟ ⎜ w1,j+1 ⎟ ⎜ ⎟ ⎝ ... ⎠ w1,h−1
210
6 Rosenberg’s Completeness Criterion for Pk
belong to ιhh for i = j. Thus f (Ci,j ) ∈ ξ. By choosing vi = f (zi ), for the tuple (f (w1,0 ), ..., f (w1,h−1 )) and i ∈ Eh from this and the strong homogeneity of it follows (f (w1,0 ), ..., f (w1,h−1 )) ∈ ξ. But this contradicts the definition of T and 1 ∈ T . Lemma 6.1.22 If is strongly homogeneous, then there exists for certain m, a bijective mapping ϕ from Ehm onto V with ξ = ϕ(ξm ) := {(ϕ(a0 ), ..., ϕ(ah−1 )) | (a0 , ..., ah−1 ) ∈ ξm } and it holds that = {(a0 , ..., ah−1 ) ∈ Ekh | (ϕ−1 (F (a0 )), ..., ϕ−1 (F (ah−1 ))) ∈ ξm }, i.e., ∈ Bhk . Proof. With the function f in Lemma 6.1.21, we can define a bijective mapping from Ehm onto V as follows: ϕ(a(m−1) hm−1 + a(m−2) hm−2 + ... + a(1) h + a(0) ) = f (z) :⇐⇒ (z[t1 ], z[t2 ], ..., z[tm ]) = (a(m−1) , a(m−2) , ..., a(0) )), where a ∈ Ehm . Let (a0 , ..., ah−1 ) ∈ ξm . Then there are certain z0 , ..., zh−1 ∈ k Ehh , where (z0 [i], ..., zh−1 [i]) ∈ ιhh for all i ∈ {1, 2, ..., hk }, with the property (ϕ(a0 ), ϕ(a1 ), ..., ϕ(ah−1 )) = (f (z0 ), f (z1 ), ..., f (zh−1 )). Since f ∈ P ol, this implies (ϕ(a0 ), ..., ϕ(ah−1 )) ∈ ξ. Hence ϕ(ξm ) ⊆ ξ. Assume, there exists a tuple (a0 , ..., ah−1 ) ∈ ξ\ϕ(ξm ). By definition of ϕ, we k find certain z0 , ..., zh−1 ∈ Ehh with (f (z0 ), ..., f (zh−1 )) = (a0 , ..., ah−1 ), where (z0 [i], ..., zh−1 [i]) ∈ ιhh for certain i ∈ {t1 , ..., tm }. But this is contrary to (6.24). Thus ξ = ϕ(ξm ). The other statements follow from Lemma 6.1.18, (a) and the definition of ξ. To sum up, we have in Case 2.2: ∈ Ck ∪ Bk , and Theorem 6.1 is proven.
7 Further Completeness Criteria
In the literature, one finds many articles which deal with complete sets. With the aid of complete sets, it is easy to obtain completeness criteria. In this chapter, we discuss only three types of such criteria. First we handle a criterion for Sheffer functions, which was found by G. Rousseau. Then, we show how one can reduce the conditions from Theorem 6.1 if one considers only surjective functions. Finally, we deal with criteria that indicate under which conditions a set (⊆ Pk ) which consists of certain unary functions and a Slupecki-function is complete in Pk .
7.1 A Criterion for Sheffer-Functions Definitions A function f ∈ Pk is called a Slupecki-function, if f ∈ P olk ιkk , i.e., if f depends on at least two variables essentially and takes k different values. A function f is called a Sheffer-function of Pk , if every g ∈ Pk is a superposition over f , i.e., if (7.1) [f ] = Pk holds. Obviously, every Sheffer-function is a Slupecki-function. The function x | y := x ∨ y which fulfills (7.1) for k = 2 was published by H. M. Sheffer (in [She 13]). This function and the function x ∧ y, which is dual to this function, are the only binary functions of P2 , which generate P2 (cf. [Zyl 25]). One can easily prove this with the aid of the following theorem.
212
7 Further Completeness Criteria
Theorem 7.1.1 Let f n ∈ P2 . Then [f ] = P2 ⇐⇒ (f ∈ T0 ∧ f ∈ T1 ∧ f ∈ S).
(7.2)
Proof. “=⇒” is trivial. “⇐=”: Because off (0, ..., 0) = 1 and f (1, ..., 1) = 0, we have f ∈ M . Since f 0 1 does not preserve , there are some a1 , ..., an ∈ E2 with f (a1 , ..., an ) = 1 0 f (a1 , ..., an ). Consequently, (f (0, ..., 0), f (a1 , ..., an ), f (a1 , ..., an ), f (1, ..., 1)) does not belong to α := {(a, b, c, d) ∈ E24 | a + b = c + d (mod 2)}, although (0, ai , ai , 1) ∈ α for every i ∈ {1, ..., n} is valid. Thus, we have also f ∈ P ol2 α. With the aid of Theorem 3.3.1, this implies [f ] = P2 . Lemma 7.1.2 Let f n ∈ Pk be a Slupecki-function which preserves a certain h-ary relation ∈ Rk . Then (a) (∃s ∈ Sk \{e11 } : = {(a, s(a)) | a ∈ Ek }) =⇒ (∃γ ∈ Sk ∪ C1k : f ∈ P olγ); (or: (∃s ∈ Sk \{e11 } : f (x1 , ..., xn ) = s−1 (f (s(x1 ), ..., s(xn ))) ) =⇒ ∃γ ∈ Sk ∪ C1k : f ∈ P olγ; (b) ∈ Mk =⇒ ∃γ ∈ C1k : f ∈ P olγ; (c) (2 ≤ h ≤ k − 1 ∧ ∈ Chk ) =⇒ ∃γ ∈ C1k : f ∈ P olγ; (d) (k = pm (p prime, m ≥ 1) ∧ ∈ Lk ) =⇒ ∃γ ∈ Uk ∪ Sk : f ∈ P olγ; (e) ∈ Bk =⇒ ∃γ ∈ Uk ∪ Sk : f ∈ P olγ. Proof. (a): In the proof of Lemma 6.1.3, we had shown that, from the relation s := {(a, s(a)) | a ∈ Ek } (s ∈ Sk \{e11 }), either a relation of C1k (in the case s ∩ ι2k = ∅) or a relation of Sk (in the case s ∩ι2k = ∅) are derivable, whereby we have f ∈ P olγ for a certain γ ∈ C1k ∪Sk . (b): Let o ∈ Ek be the least element in respect to ∈ Mk . Because of Im(f ) = Ek and f ∈ P ol, f (o, ..., o) = o holds. Thus we have f ∈ P ol{o}. (c): Let C be the set of all central elements of the relation ∈ Chk , 2 ≤ h ≤ k − 1. Then, because of (a0 , ..., ah−2 , c) ∈ for every c ∈ C and arbitrary a0 , ..., ah−2 ∈ Ek , it results from f ∈ P ol and Im(f ) = Ek that f (c1 , ..., cn ) ∈
7.1 A Criterion for Sheffer-Functions
213
C is valid for all c1 , ..., cn ∈ C. Consequently, f preserves a relation of C1k . (d): Let k = pm (p prime, m ≥ 1) and let f n be a quasi-linear function. By Lemma 5.2.4.3, f is isomorphic to a certain function fˆn ∈ PA , where A := Epm . One can describe this function fˆn as follows: fˆ(x1 , ..., xn ) = a + x1 · A1 + ... + xn · An , where a, x1 , ..., xm ∈ Epm , A1 , ..., An are some matrices of the type (m, m) over Ep and + and · are the usual matrix operations over the field (Ep ; + (mod p), · (mod p)). We form fˆ1 (x) := fˆ(x, x, ..., x) = a + x · A, where A := A1 + ... + An , and distinguish two cases for A: Case 1: det(A − I) = 0. 1 Then there exists b ∈ Epm with b · (A − I) = −a or a + b · A = b. Consequently, we have fˆ(b, ..., b) = b and f preserves a relation of C1k . Case 2: det(A − I) = 0. In this case, there is a d ∈ Epm \{o}, o := (0, ..., 0), with d · (A − I) = o and it holds: fˆ(x1 + d, x2 + d, ..., xn + d) − d = a + (x1 + d) · A1 + ... + (xn + d) · An − d = a + d · (A1 + ... + An ) −d +x1 · A1 + ...xn · An =A = fˆ(x1 , ..., xn ).
o
Thus, fˆ preserves the relation {(x, s(x)) | x ∈ Epm } with s(x) := x + d. With the help of (a), this implies f ∈ P olγ for certain γ ∈ Sk . (e): Let ∈ Bk . Then, by definition, there exists a mapping q from Ek onto Ehm (m ≥ 1) with (a0 , ..., ah−1 ) ∈ =⇒ (q(a0 ), ..., q(ah−1 )) ∈ ξm , where ξm is the h-ary elementary relation on Ehm . Because of Theorem 5.2.6.1, one can describe f ∈ P ol with Im(f ) = Ek in the form (5.14), where gf has the form m−1 si ((q(xji ))α(i)) · hi (7.3) gf (x1 , ..., xn ) = i=0
with {j0 , ..., jm−1 } ⊆ {1, 2, ..., n}, s0 , s1 , ..., sm−1 are some permutations on Ek and α is a certain mapping from Em into Em . By means of (7.3), one can prove that the function f preserves the equivalence relation 1
I denotes the identity matrix of the type (m, m).
214
7 Further Completeness Criteria
{(a, b) ∈ Ek2 | q(a) = q(b)}.
(7.4)
Consequently, f belongs to P olγ for a certain γ ∈ Uk , if q is not bijective. We still have to examine the case that q is bijective. W.l.o.g. let q be the identical mapping in the following. Thus our function f has the form f (x1 , ..., xn ) =
m−1
si ((xji )(α(i)) ) · hi
(7.5)
i=0
and we have k = hm and m ≥ 2 (because of f ∈ P olk ιkk ). For the mapping α, two cases are possible: Case 1: α is not a permutation. In this case, there is a proper subset A of Ek , which is preserved from α. Then, by means of (7.5), it is easy to check that f preserves the non-trivial equivalence relation {(a, b) ∈ Ek2 | ∀i ∈ A : a(i) = b(i) }; hence f ∈ P olγ holds for a certain γ ∈ Uk . Case 2: α is a permutation. We form f1 (x) := f (x, x, ..., x) and set α1 x := α(x), αi x := α(αi−1 x), i ≥ 2. Then we have by assumption and (7.5): g(x) := (f1 f1 ... f1 ) = m times m
where x(α
i)
m
si (sαi (...(sαm−1 i (x(α
i)
))...)) · hi ,
i=0
= x(i) . The function g has the properties g −1 (x) =
m−1 i=1
and
m−1
−1 −1 (i) i s−1 αm−1 i (sαm−2 i (...(si (x ))...)) · h
g −1 (f (g(x1 ), g(x2 ), ..., g(xn ))) = f (x1 , x2 , ..., xn ).
Thus, if g = e11 then by (a) f preserves a certain relation of Sk and (e) was proven. If g = e11 then for every a ∈ Ek the function f preserves the element m−1
sαi (sα2 i (...(sαm−1 i (a(i) ))...)) · hi
i=0
of Ek , whereby f preserves a relation of C1k . The following generalization of Theorem 7.1.1 was found by G. Rousseau.
7.1 A Criterion for Sheffer-Functions
215
Theorem 7.1.3 (Characterization Theorem for Sheffer-Functions; [Rou 67]) Let f n ∈ Pk . Then [f ] = Pk ⇐⇒ ∀ ∈ C1k ∪ Uk ∪ S∼ k : f ∈ P ol.
(7.6)
Proof. Obviously, “=⇒” is valid. “⇐=”: Let f ∈ Pk be a function that does not preserve any relation of the set C1k ∪ S∼ k ∪ Uk . Then f is a Slupecki-function and, because of Theorem 6.1, it is sufficient to show for the proof of “⇐=” of (7.6) that ∀ ∈ Mk ∪ Lk ∪ Bk ∪
k−1
Chk : f ∈ P olk
(7.7)
h=2
holds. From the assumption that (7.7) is false, contradictions to the assumption result with the aid of the statements (b) - (e) from Lemma 7.1.2 in all cases to be scrutinized for . Theorem 7.1.4 ([Sch 69]) One can not reduce the conditions from Theorem 7.1.3; that is, these conditions are independent of each other. Proof. It was shown in [Sch 69] by P. Schofield that every class of the form P olk with ∈ C1k ∪ Sk ∪ Uk can be generated by one function (see Section 11.2). With the help of this property, one can easily prove that our assertion is valid: Assume there is a relation α ∈ C1k ∪ S∼ k ∪ Uk with [f ] = Pk ⇐⇒ ∀ ∈ (C1k ∪ Uk ∪ S∼ k ) \ {α} : f ∈ P ol. Furthermore, let f be a function of A with [f ] = A. Since A is not complete in Pk , there exists a maximal class B = A of Pk with f ∈ B. Then, f belongs to A ∩ B and we get A = [f ] ⊆ A ∩ B ⊆ B. Because of A = B, however, this is contradictory to the Pk -maximality of A.
The literary about concrete Sheffer-functions is very extensive. One finds a bibliography for this purpose for example in [P¨ os-K 79], p. 135, and in [Ros 77] (or [Ros 84]). The following theorem gives only one of the classical examples for Sheffer-functions, which was published in 1936. Theorem 7.1.5 (Theorem of Webb; [Web 36]) The function f (x, y) := min(x, y) + 1 (mod k) is a Sheffer-function for Pk .
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7 Further Completeness Criteria
Proof. A possible proof is the construction of a known generating system os-K 79]. We prove the for Pk over the function f , which one can look up [P¨ assertion here with the aid of (7.6). Superpositions over f are the functions f1 := ∆f with f1 (x) = x + 1 (mod k) and min := f1 f1 ... f1 f . k−1 times Obviously, the function f1 does not preserve any relation ∈ C1k . Thus we have f ∈ P olk for all ∈ C1k . 0 b Let ∈ Sk . Then there are a, b ∈ Ek with {(0, a), (b, 0)} ⊆ and f = a 0 1 . Consequently, f does not preserve any relation ∈ Sk . 1 Since f1 ∈ P olk is false for every ∈ Uk , we assume that f1 ∈ P olk for certain ∈ Uk is valid. Then, the equivalence classes of are equipotent, and there exist two equivalence classes [a] and [a + 1] of with the following properties: [a] = [a + 1] , b ∈ [a] , a < b, k − 1 ∈ [a] . a b+1 a Then (a, b), (a + 1, b + 1) ∈ and min = ∈ . Conseb a+1 a+1 quently, the function f does not preserve any relation of Uk . By means of Theorems 7.1.3, it is already recognizable that the number of Sheffer-functions is quite great. The next theorem summarizes some statements about concrete numbers and certain convergence. Theorem 7.1.6 Let ϕn (k) be the number of all n-ary Sheffer-functions of Pk . Then (a) ϕn (2) = 22 (b) limn→∞
n
−2
ϕn (2) 2 2n
− 22
n−1
−1
;
= 14 ;
(c) ϕ2 (3) = 3774 ([Mar 54]); (d) limk→∞
ϕn (k) k kn
= limn→∞
ϕn (k) k kn
=
1 e
for k ≥ 3, [Bai 67a].
(e) For a large k, given a randomly selected f one can decide whether f ∈ Pkn , n ≥ 2, is a Sheffer-function with probability almost 1 by testing the condition f (x, x, ..., x) = x for every x ∈ Ek only; [Dav 68]. Proof. (a) and (b) are easy to check. One can find proofs for (c) –(e) in [Mar 54] and [Dav 68].
7.2 A Completeness Criterion for Surjective Functions For the case that one only considers subsets A ⊆ Pk of functions with the range of values Ek (i.e., surjective functions), our general completeness criterion (7.1) can be simplified. It holds:
7.3 Fundamental Sets
217
Theorem 7.2.1 ([Ros 70c], [Ros 75]) For k = hm with h ≥ 3 and m ≥ 1 let B∗k := { ∈ Bk | ∃n : is isomorphic to ξn }. Then, for arbitrary A ⊆ Pk [k] we have: [A] = Pk ⇐⇒ ∀ ∈ C1k ∪ Sk ∪ Uk ∪ Lk ∪ B∗k : A ⊆ P olk .
(7.8)
Proof. “=⇒” is trivial. “⇐=”: Our theorem follows from Theorem 6.1 if we can show that A is not a k−1 subset of clones P olk for every ∈ Mk ∪ ( h=2 Chk ) ∪ (Bk \B∗k ). Suppose it holds: k−1 ∃ ∈ Mk ∪ ( Chk ) ∪ (Bk \B∗k ) : A ⊆ P olk . (7.9) h=2
We distinguish three cases: Case 1: ∈ Mk . Let o be the least element of Ek in respect to . Since each function of A has the range Ek , we have then that A is a subset of P olk {o}, in contradiction to our assumption. Thus Case 1 is not possible. Case 2: ∈ Chk , 2 ≤ h ≤ k − 1. In analog mode to the proof of Lemma 7.1.2 (c), one can show that every function of A preserves the set of the central elements of the relation in this case. However, this also contradicts our assumption. Case 3: ∈ Bk \B∗k . One can describe the functions of A, then, by means of formulas of the form (5.14), where gf has the form (7.3); hence every function of A preserves the nontrivial equivalence relation (7.4). Consequently, Case 3 is not possible and, with that, the assumption (7.9) is wrong.
7.3 Fundamental Sets By Chapter 4, the set Pk1 ∪ {f }, where f is a Slupecki-function, is complete in Pk . Consequently, a subset A of Pk is complete in Pk iff Pk1 ∪ {f } ⊆ [A] holds. One can now attempt to improve this completeness criterion in such a way that the set Pk1 is replaced by certain subsets of Pk1 . Definitions A subset A of Pk1 with ∀f ∈ Pk \([Pk1 ] ∪ Pk (k − 1)) : 2 [A ∪ {f }] = Pk 2
E.i., f is a Slupecki-function.
218
7 Further Completeness Criteria
is called fundamental set in Pk . If in particular, A is a group (or a semigroup) in respect to the operation , then A is also called fundamental group (or fundamental semigroup), respectively. We need the following definition to describe some fundamental sets: Definition A semigroup H ⊆ Pk1 is called t-fold transitive, t ∈ {1, 2, ..., k}, if for arbitrary pairwise distinct elements a1 , ..., at ∈ Ek and for arbitrary pairwise distinct elements b1 , ..., bt ∈ Ek there exists an h ∈ H with h(ai ) = bi for all i ∈ {1, 2, ..., t}. One finds some examples of fundamental sets in the following theorem. Theorem 7.3.1 (1) The following sets are fundamental semigroups: (a) Pk1 \Pk1 [k]; (b) a set H ⊆ Pk1 with k ≥ 5, which is (k − 1)-fold transitive ([Mal 67]); (c) a set H ⊆ Pk1 with k ∈ {3, 4} and the property that H and also H ∩ Pk1 (k − 1) are (k − 1)-fold transitive ([Mal 67]). (2) There are fundamental groups in Pk only for k ≥ 5 and examples for fundamental groups are (a) Pk1 [k]; (b) the set of all functions of Pk1 , which are even permutations on Ek .3 Proof. The statements of the theorem are easy consequences of Rosenberg’s completeness criterion 6.1 (see [P¨os-K 79], p. 132 and p. 135). One can find proof that does not use Theorem 6.1, for the above statements in [Jab-L 80], 1.2.4–1.2.6.
3
A permutation s ∈ Sn is called even, if the inversion number I(s), i.e., the number of all pairs (i, j) with i < j and s(i) > s(j), is even.
8 Some Properties of the Lattice Lk
It is the aim of this first section above Lk to basically elaborate on the differences between L2 , which we already completely determined in Chapter 3, and Lk for k ≥ 3. In particular, we deal with cardinality statements (both about Lk , than also about chains and antichains in Lk ) and with the embedding of Lk into Lk . Furthermore, the question, which cardinalities have the lattices L↓k (A) for maximal classes A of Pk , is clarified. In the last section of chapter, there are remarks about “strategies” during the determination of “manageable” sublattices of Lk . In addition, two examples of theorems are proven as one can determine certain subsets of Lk . Notice that one can find further properties of Lk , for instance, in [Bul-K-S-S 95], [Bul-K-S-S-S 2001], [Bul 99a,b], and [Bul 2001].
8.1 Cardinality Statements We begin with proving the existence of a subclass C ⊆ Pk for k ≥ 3, which has an infinite basis. This example was published by J. I. Janov and A. A. Mucnik in 1959. Let ⎧ ∃i ∈ I : (xi ∈ {1, 2} ∧ ⎨ 1 if n (∀j ∈ J ∪ (I\{i}) : xj = 2)), (x1 , ..., xn ) := gI,J (8.1) ⎩ 0 otherwise, where I and J are certain disjoint subsets of {1, 2, ..., n}. n with fn . Except the subsequently We also denote the functions g{1,2,...,n},∅ indicated tuples, the function takes only the value 0:
220
8 Some Properties of the Lattice Lk
⎞ ⎛ ⎞ 1 1 2 2 ... 2 2 ⎜ 2 1 2 ... 2 2 ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ ⎜ ⎜ . . . . . . . . . . . . . . ⎟ ⎜ ... ⎟ ⎟ ⎜ ⎟ fn ⎜ ⎜ 2 2 2 ... 1 2 ⎟ = ⎜ 1 ⎟ . ⎟ ⎜ ⎟ ⎜ ⎝ 2 2 2 ... 2 1 ⎠ ⎝ 1 ⎠ 1 2 2 2 ... 2 2
(8.2)
B := {fi | i ∈ N}
(8.3)
⎛
Let and let C be the set
n {gI,J | I, J ⊆ {1, 2, ..., n} ∧ I ∩ J = ∅}.
(8.4)
n≥1
Lemma 8.1.1 For the above-defined sets C and B is valid: (a) C is a subclass of Pk . (b) ∀i ∈ N : fi ∈ [B\{fi }]. (c) B is an infinite basis of C. Proof. Obviously, set C is closed in respect to the operations ζ, τ, δ, ∇. The completeness of C in respect to follows from ⎧ n+n −1 ⎪ ⎪ ⎪ g{a+n −1 | a∈I},{a+n −1 | a∈J} if 1 ∈ I ∪ J ∧ n ≥ 2, ⎨ n+n −1 n if 1 ∈ J ∨ (n = 1 ∧ I = ∅), gI,J gIn ,J = c0n+n −1 = g∅,∅ ⎪ ⎪ ⎪ ⎩ g n+n −1 if 1 ∈ I ∧ n ≥ 1. I ,J ∪{a+n −1 | a∈J∪(I\{1})} In addition, it results from the above formulas that set B is a generating system for C that does not continue being reducible, because of
n ∈ [{gIn ,J ∈ C | |I | = |I|}]. fn = gI,∅
Theorem 8.1.2 Let N be a countable set and let L(N) := (P(N ); ⊆). Then, for k ≥ 3, one can embed the lattice L(N) into the lattice Lk ; i.e., there exists a bijective mapping α from P(N ) in Pk , for which it holds: ∀A, B ∈ P(N ) : A ⊆ B =⇒ α(A) ⊆ α(B). In particular, for all k ≥ k ≥ 2, the lattice Lk one can embed into the lattice in Lk . Proof. W.l.o.g. let N := N. Then, for every subset T of N, one can form a subclass CT := [{fi | i ∈ T }] of the class C defined in (8.4). Because of Lemma 8.1.1, we have: T = T ⇐⇒ CT = CT . Since T ⊆ T =⇒ CT ⊆ CT , we have that α : P(N) −→ Pk , T −→ CT is an embedding of L(N) into Lk .
8.1 Cardinality Statements
221
With the aid of the above theorem we can prove the statements of the following two theorems easily. In particular, the theorem shows that the crucial importance, which has the 2 in many fields of the algebra, is also provable for the function algebras. So, P2 has countable-many subclasses, however, the set Pk for k ≥ 3 already continuum-many subclasses: Theorem 8.1.3 (Theorem About the Cardinality of Lk (Pk )) It holds: (a) |Lk (P2 )| = ℵ0 . ([Pos 41]) (b) |Lk (Pk )| = c for k ≥ 3. ([Jan-M 59]) Proof. (a) was proven in Chapter 3. (b): Obviously, the set Pk is countable infinite. As is generally known, the set of all subsets of Pk has the cardinality of the continuum. Consequently, there are at least continuum-many subclasses of Pk . Thus, (b) follows from Theorem 8.1.2, since |P(N)| = c (see e.g. [Lau 2004], volume 1). Theorem 8.1.4 ([P¨ os-K 79]) For k ≥ 3 there are in Lk both chains and antichains of the cardinality of the continuum. Proof. Because of Theorem 8.1.2, it suffices to prove that there are a chain and an antichain with the cardinality of the continuum in L(N), |N | = ℵ0 . Let Q be the set of all rational numbers and R be the set of all real numbers. For arbitrary s ∈ R we put Ms := {q ∈ Q | q ≤ s}. Then, the set {Ms | s ∈ R} forms a chain of the cardinality c in the lattice L(Q). For the purpose of constructing an uncountable antichain, let H := {(m, i) | m ∈ N ∧ i ∈ {0, 1}} and HI := {(m, 0) | m ∈ I} ∪ {(m, 1) | m ∈ I}. Obviously, {HI | I ⊆ N} is an antichain of the cardinality c in the lattice L(H) (|H| = ℵ0 ). Because of the above theorems, the concrete determination of the elements of the lattice Lk seems for k ≥ 3 to be a hopeless task. Nevertheless, one can attempt to determine certain “manageable parts” of Lk or one can try to get a general idea of the position of the “not manageable parts” of the lattice Lk . The following theorem is useful for proving that certain sublattices of Lk are countable, which is a generalization of a theorem that was proven by I. A. Mal’tsev (see [Mal 73]).
Theorem 8.1.5 (Countability Criterion; [Lau 86]) Let A be a subclass of Pk (or an algebra with countable many elements). Furthermore, there exists an order relation ≤ on A with the following three properties:
222
8 Some Properties of the Lattice Lk
(a) f ≤ g =⇒ [f ] ⊆ [g], (b) every chain is well-ordered (in respect to ≤), i.e., every chain has a minimal element (in respect to ≤), (c) every antichain (in respect to ≤) has only finitely many elements. Then, A has at most only countable many different subclasses (or the algebra A has at most only countable many different subalgebras). Proof. Let B be a closed subset of A and let G be the set of all minimal elements of A\B (in respect to ≤). First, we prove that G determines the set B unambiguously. Let f be an arbitrary function of A. The following cases are possible: Case 1: There exists a function g ∈ G with f ≤ g and f = g. Then f ∈ B, since for f ∈ B the function g is not a minimal element of A\B. Case 2: There exists a function g ∈ G with g ≤ f . Because of g ≤ f and by assumption (a), we have that g is a superposition over f . Thus f ∈ A\B, since g ∈ A\B. Case 3: Every function of G is not comparable with the f (in respect to ≤), or G = ∅. Because of the assumption (b) and by Zorn’s Lemma, this case is only possible for f ∈ B. Consequently, G determines the class B unambiguously. The set G is an antichain (in respect to ≤) and a finite set because of assumption (c). Every subclass B of A is also definable by a finite subset G of A. Obviously, A contains countable many elements. Consequently, there are only countable many possibilities for G and, therefore, there are only countable many closed subsets of A. Let ◦ be an operation on Ek with the properties a) ∀ a, b, c ∈ Ek : a ◦ (b ◦ c) = (a ◦ b) ◦ c, b) ∀ a, b ∈ Ek : a ◦ b = b ◦ a, c) ∃ r ≥ 1 : (∀ a ∈ Ek : a ◦ a ◦. . . ◦ a = a). (1+r)times
The properties a) - c) are e.g. fulfills, if (Ek ; ◦) is an Abelean group or x ◦ y := maxω (x, y) or x◦y := minω (x, y) (ω is a partial order relation, for which exists max or min). With the help of ◦ one can define a subset K(m, ◦) of Pk for an m ∈ N as follows: K n (m, ◦), (8.5) K(m, ◦) := n≥1
where
8.1 Cardinality Statements
223
f n ∈ K n (m, ◦) :⇐⇒ m ∃ f01 , f1n1 , . . . , ftnt ∈ i=1 Pki : f (x1 , . . . , xn ) = f0 (f1 (x1 , ..., xn1 ) ◦ f2 (xn1 +1 , ..., xn1 +n2 ) ◦ . . . ◦ fn (xn1 +...+nt−1 +1 , ..., xn )) (8.6) In general, the set K0 is not closed. K0 contains, however, through suitable choice of m and ◦ a line of interesting subclasses of Pk (as for example the set of linear or quasi-linear functions) and it is valid: Theorem 8.1.6 A subclass A of Pk , for which exist an m ∈ N and an operation ◦ which the above properties a) - c) fulfills, with A ⊆ K(m, ◦), has only countable many subclasses. Proof. We will define a partial order relation ≤ on K(m, ◦), which fulfills the conditions (a)–(c) from the Theorem 8.1.5, whereby our theorem follows from Theorem 8.1.5. Every function of f n ∈ K(m, ◦) with the form (8.6) is well-defined by tuples ϕ(f ) := (f0 , f1 , ..., ft ). Two functions f1 , f2 with ϕi (fi ) := (fi,0 , fi,1 , ..., fi,ti ), i = 1, 2, are called -equivalent, iff these functions fulfill the following three conditions: 1) f1,0 = f2,0 ; 2) {f1,1 , ..., f1,t1 } = {f2,1 , ..., f2,t2 }; 3) If f occurs in (f1,1 , ..., f1,t1 ) exactly q times, then there exists a certain integer s, so that f occurs in (f2,1 , ..., f2,t2 ) exactly (s + r · q) times, where r denotes the smallest integer for which ◦ fulfills die condition c). Obviously, the factor set K(m, ◦)/ is finite. Set {K1 , K2 , ..., Ku } := K(m, ◦)/ . On the sets K1 , K2 , ..., Ku one can define a partial order relation ≤ as follows: For functions f1 , f2 ∈ Ki , i ∈ {1, 2, ..., u}, with ϕ(fi ) = (fi,0 , ..., fi,ti ) we write f1 ≤ f2 if and only if for every f , which occurs in (f1,1 , ..., f1,t1 ) j − 1 times and occurs in (f2,1 , ..., f2,t2 ) j2 times, it holds j1 ≤ j2 . This partial order relation satisfies the condition (a) of Theorem 8.1.5, since one can receive the function f from g with the aid of the operations ζ, τ, ∆ by the changing of the denotation of certain r variables and by the identifying of groups of variables with r · q + 1 (q ≥ 1) elements because of the property (c) of ◦ . Obviously, the property (b) of Theorem 8.1.5 is also valid. Thus it remains to be seen that every antichain in the set K(m, ◦) in respect to ≤ has only finite-many elements. m On i=1 Pk1 one can define a total order. For ϕ(f ) = (f0 , ..., ft ), we arrange (concerning this order) that fi0 is the smallest element of the set {f1 , ..., ft }; fi1 is the smallest element of the set {f1 , ..., ft }\{fi0 }; ... and fis is the greatest element of {f1 , ..., ft }. If fij occurs in (f1 , ..., ft ) exactly bj times, j = 0, 1, ..., s, then let α(f ) := (b0 , b1 , ..., bs ). Further, let Di := {α(f ) | f ∈ Ki }, i = 1, 2, ..., u. One can define a partial order relation on Di . We set α(fi ) ≤ α(f2 ) iff f1 ≤ f2 . The partial ordered sets Ki and Di are isomorphic, i = 1, 2, ..., u. Conse-
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8 Some Properties of the Lattice Lk
quently, for the end of our proof, it suffices to show that an arbitrary antichain C of Di is a finite set: Obviously, if C consists only of tuples of the length 1, then C is a finite set. Suppose our assertion is proven for tuples of the length s and all tuples of C have the length s + 1. We select a certain tuple (b0 ..., bs ) in C and decompose the set C to this tuple in finite many classes as follows: Let the first class be the set of all tuples whose first coordinate is 1. All functions with the first coordinate 2 belong into the second class, ..., all functions with the first coordinate b0 − 1 belong into the (b0 − 1)-th class. All the tuples whose second coordinate 1 is and which are not tuples of the already defined classes, belong in the b0 -th class, and so forth. Since the tuples of C are not comparable (i.e., if (b11 , ..., b1s ) = (b21 , ..., b2s ) are elements of C then there exist some i = j with b1i < b2i and b1j > b2j ), all elements of C\{(b0 ..., bs )} are in the above-described classes contained. By assumption, every class has only finite many elements. Hence C is a finite set.
8.2 On the Cardinalities of Maximal Sublattices of Lk In this section, we determine the cardinality of the lattice L↓k (A), where A is an arbitrary maximal class of Pk . We start with a lemma that is a consequence of [Dem-H 83], Lemma 1. Lemma 8.2.1 Let k = 2 · l with l ≥ 2, let s := (0 1)(2 3)(4 5)....(2l − 2 2l − 1) be the cycle representation of a permutation s on E2l , s := {(x, s(x)) | x ∈ (n) E2l } and yi := (0, 0, ..., 0, 1 , 0, ..., 0) for 1 ≤ i ≤ n. Furthermore, let tn i
(n ≥ 4) be an n-ary function of P olk s with the following properties: (n)
(α) (∀i ≥ 1 : tn ( yi ) = 1) ∧ tn (0, 1, 1, ..., 1) = 0; (n)
(n)
(β) ∀x ∈ E4n \{ y1 , ..., yn } : x1 ∈ {0, 2} =⇒ tn (x) = 2; (γ) ∀x ∈ Ekn \E4n : x1 ∈ {0, 2, 4, ..., 2l − 2} =⇒ tn (x1 , ..., xn ) = x1 . Let n be the n-ary relation (n)
{ yi
| 1 ≤ i ≤ n} ∪ (E4n \{0, 1}n ).
Then (a) The functions tn with n ≥ 4 are unique determined by the conditions (α)–(γ) and belong to P olk s . (b) ∀n ≥ 4 : tn ∈ P olk n . (c) ∀m = n : tm ∈ P olk n .
8.2 On the Cardinalities of Maximal Sublattices of Lk
225
Proof. (a): Because of Theorem 5.2.2.1, an arbitrary n-ary function f n ∈ P olk s is uniquely determined by the function f (a, x2 , ..., xn ) with a ∈ {0, 2, 4, ..., 2l − 2}. It is easy to check that the conditions (α)–(γ) determine the functions tn (a, x2 , ..., xn ) for arbitrary a ∈ {2, 4, ..., 2l − 2}. (b) follows from ⎛ ⎞ ⎛ ⎞ 1 0 ... 0 1 ⎜ 0 1 ... 0 ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ tn ⎜ ⎝ . . . . . . . . . ⎠ = ⎝ ... ⎠ . 0 0 ... 1 1 (c): Let n = m and let r1 , ..., rn ∈ n be arbitrary. If an ri belong to E4n \{0, 1}n (n) (n) then tm (r1 , ..., rm ) ∈ E4n \{0, 1}n . If {r1 , ..., rm } ⊆ { y1 , ..., yn }, then one can show (when one distinguishes the cases m < n and m > n) that tm (r1 , ..., rn ) ∈ n . For the following lemma, we need the description of a subset T of the set 0 1 2 , S3 := P ol3 1 2 0 which is the only maximal class of type S for k = 3. A function f n belongs to T if and only if f n fulfills the following four conditions: 1) f ∈ S3 ∩ P ol3 {0, 1}. 2) The restriction of f onto E2n (we write pr f ) is a function of T1,∞ ∩ M ∩ T0 . In order to be able to formulate the third and fourth condition, we need one property of the functions g m ∈ T1,∞ ∩ M ∩ T0 , which is a conclusion of Chapter 3: Every such function g m can be described through a formula above a variable alphabet and through the signs ∨ (disjunction) and ∧ (conjunction), as follows: g(x1 , ..., xm ) = xi ∨ A1 ∨ ... ∨ At , where i ∈ {1, 2, ..., m} and Aj (1 ≤ j ≤ t) are formulas of the form xj1 ∧ xj2 ∧ ... ∧ xjlj (”conjunctions”, lj ≥ 1). Since x ∨ (x ∧ y) = x as is generally known, we can assume that the sets of the indexes of the variables of the conjunctions Aj in the formula for g are not contained pairwise in each other (we speak in this case from an abbreviated DNF for g). 3) If variables, which take values of E2 in the tuple a, exist in every conjunction of the abbreviated DNF of pr f , then f (a) ∈ E2 . 4) The abbreviated DNF of pr f has the form (pr f )(x1 , ..., xn ) = xi1 ∨ xi2 ∨ ...xij ∨ A1 ∨ ... ∨ Ap , where A1 , ..., Ap are conjunctions, which consist of at least two variables in each case, over the variable set {x1 , ..., xn }\{xi1 , ..., xij }. If there are tuples
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8 Some Properties of the Lattice Lk
a1 := (a11 , ..., a1n ), ..., ar := (ar1 , ..., arn ) of E3n with f (x1 ) = ... = f (xr ) = 0 and every of the conjunctions A1 , ..., Ap contains variables xi1 , xi2 , ..., xij , which only take values of {0, 1} in every tuple a1 , ..., ar , then there exists an s ∈ {1, ..., j} with a1is = ... = aris = 0. The following theorem was proven by S. S. Marcenkov: Theorem 8.2.2 ([Mar 83]) The set T is a closed set and contains a subclass, which has an infinite basis. Proof. One can find the proof for [T ] = T in [Mar 83]. In the following, we construct a subclass of the form [Φ] with Φ := {ϕ2 , ϕ3 , ...} ⊆ T, where the functions ϕn have the property ϕn ∈ [Φ\{ϕn }] for every n ≥ 2; i.e., [Φ] is a subclass of T with infinite basis. For every n ≥ 2 let ϕn be a function of T 2n , which has the following three properties: (pr ϕn )(x1 , ..., xn , y1 , ..., yn ) := x1 ∨ ... ∨ xn ∨ y1 · y2 · ... · yn
(8.7)
(· := ∧), ϕn (1, 0, ..., 0, 2, 0, ..., 0) = ϕn (0, 1, 0, ..., 0, 0, 2, 0, ..., 0) = ... = n
n
ϕn (0, 0, ..., 1, 0, 0, 0, ..., 2, 0) = ϕn (0, 0, ..., 0, 1, 0, 0, 0, ..., 2) = 0, n
(8.8)
n
and ϕn (a) = 1 holds for every tuple a := (a1 , ..., an , an+1 , ..., a2n ), which fulfills the condition 1 ∈ {a1 , ..., an } =⇒ (a1 , ..., an ) ∈ {0, 1}n and which is different from the tuples that occur in (8.8). Because of condition ϕn ∈ T ⊆ S, many more values of the function are given through the above determination. It is easy to check that one can define the function, so on remaining tuples, that ϕn ∈ T is valid. How this happens is not important for the below-indicated considerations. Some remarks on the definition of the functions ϕn : If the elements ai of the tuple a := (a1 , ..., an , an+1 , ..., a2n ) take only, at most, two different values, then ϕn (a) is already determines by (8.7). Let An be the set of all tuples of E32n which occur in the condition (8.8). Let now a ∈ E32n \ An with |{a1 , ..., a2n }| = 3. Suppose a1 = ... = an . By ϕn ∈ S we can assume w.l.o.g. a1 = ... = an = 1. Then by 3) we have ϕn (a) ∈ E2 . Because of 4) the case ϕn (a) = 0 is not possible, so that ϕn (a) = 1 holds. Let |{a1 , ..., an }| = 2. W.l.o.g. {a1 , ..., an } = E2 . Then the conditions a ∈ An , 3) and 4) imply ϕn (a) = 1.
8.2 On the Cardinalities of Maximal Sublattices of Lk
227
If |{a1 , ..., an }| = 3, then the definition of the set T does not supply any determination for ϕn (a). Further, we remark that (a1 , ..., an ) ∈ E2n and ϕn (a) = 0 are only possible if either a ∈ An or a1 = ... = an = 0 holds. From that, the correctness of the fourth property results for the functions ϕn . One easily checks that the functions ϕn also fulfill the remaining three properties from the definition of set T . Suppose ϕn is a superposition over {ϕm | m = n}. We consider a formula V (x1 , ..., xn , y1 , ..., yn ) with function symbols of Φ\{ϕn } and with minimal complexity (related to the arity of their functional symbols), which describes the function v(x1 , ..., xn , y1 , ..., yn ), where v(x) = 0 for all x ∈ An and v fulfills the equation (pr v)(x1 , ..., xn , y1 , ..., yn ) = x1 ∨ ... ∨ xn ∨ y1 · ... · yn . One can find a such formula, since by assumption ϕn (x) = 0 for all x ∈ An and ϕn fulfills (8.7). We remark that v ∈ T . Let V (x1 , ..., xn , y1 , ..., yn ) = ϕm (f1 (x1 , ..., xn , y1 , ..., yn ), ..., f2m (x1 , ..., xn , y1 , ..., yn )), where {f1 , ..., f2m } ⊂ [Φ\{ϕn }]. Suppose there exists a function fα ∈ {f1 , ..., f2m } with fα (x) = 0 for every x ∈ An . Obviously, pr v = pr f1 ∨ pr f2 ∨ ... pr fm ∨ ... ∨ pr f2m .
(8.9)
Consequently, the abbreviated DNF of the function pr ft has the form xi1 ∨ ... ∨ xis ∨ xj1 · ...xjt · yl1 · ... · ylu ,
(8.10)
where {i1 , ..., is } ∩ {j1 , ..., jt } = ∅ and u = n for t = 0. Let s < n. Let B be the set of all tuple x := (x1 , ..., xn , y1 , ..., yn ) ∈ An with xi1 = xi2 = ... = xis = 1. If t > 0 then xjt = 0 for each x ∈ B. If t = 0 then we have u = n, {l1 , ..., lu } = {1, ..., n} and for every yi of an arbitrary tuple (x1 , ..., xn , y1 , ..., yn ) ∈ B with i ∈ {i1 , ..., is } we have yi = 0. Consequently, in this case, every conjunction of the abbreviated DNF, which defines the function pr fα , contains a variable that has the value 0 in every tuple of B. Since fα (x) = 0 for every x ∈ B and fα ∈ T , this is a contradiction to the property 3), because each tuple of the set B has to stand no 0 at the id -th place for 1 ≤ d ≤ s. Consequently, we have: s = n, {i1 , ..., is } = {1, ..., n}, t = 0, u = n, {l1 , ..., lu } = {1, ..., n} and pr fα = x1 ∨ ... ∨ xn ∨ y1 · ... · yn , whereby the function fα has the properties of v, which contradict the presupposed minimality of the formula V . Consequently, there is no i ∈ {1, ..., n}
228
8 Some Properties of the Lattice Lk
with fi (x) = 0 for every x ∈ An . Moreover, the abbreviated DNF of the functions pr f1 , ..., pr fm do not have the form (8.10). Therefore, and by property 3), {fi (x) | x ∈ An } = E2 for every i ∈ {1, ..., n}. For each i ∈ {1, ..., m} we choose a tuple ci ∈ An with f (ci ) = 1. Set C := {c1 , ..., cm }. Then, for arbitrary c ∈ C is valid: (f1 (c), ..., fm (c)) ∈ E2m , 1 ∈ {f1 (c), ..., fm (c)}.
(8.11)
Assume there exists an i ∈ {m + 1, ..., 2n} with {fi (c) | c ∈ C} ⊆ E2 . Then one obtains a contradiction to the property 4) of the functions ϕm , if one considers tuples of the form (f1 (a), ..., f2n (a)) with a ∈ C. Consequently, 2 ∈ {fi (c) | c ∈ C} for every i ∈ {m + 1, ..., 2n}. Now let m < n. Because of the property 3) we have for each f ∈ T : f (a) = 2 if and only if every variable of f which occurs in a conjunction of the abbreviated DNF of pr f has the value 2 in the tuple a. Every tuple of C has, however, the value 2 only at exactly a place. Therefore the abbreviated DNF of every function of {pr fm+1 , ..., pr f2m } contains a certain element of {y1 , ..., yn } as a unary conjunction. By (8.9) the product of these variables induces a conjunction of the form yj1 · ...yjt , where t < n (because of m < n), in the abbreviated DNF of the function pr v. Consequently, the case m < n is not possible. Let m > n. Since C ⊆ An , there exists a tuple a with fi (a) = 2 for at least two i ∈ {m + 1, ..., 2m}. By (8.11) and by the definition of the function ϕm this implies ϕm (f1 (a), ..., f2m (a)) = 1, which is a contradiction to v(a) = 0, however. After these preparations, the main result of this section can be formulated and proven: Theorem 8.2.3 ([Dem-H 83], [Mar 83]) Let k ≥ 3 and let A be an arbitrary maximal class of Pk . Then |L↓k (A)| = c if and only if A is not a maximal class of the type L. If A of type L, then we have k = pm , where p ∈ P and m ∈ N, and it holds < ℵ0 if m = 1, |L↓k (A)| = ℵ0 otherwise. Proof. Because of Theorem 6.1, we can assume that A = P olk with ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk . For proof of |L↓k (A)| = c for ∈ Mk ∪ Uk ∪ Sk ∪ Ck ∪ Bk , showing that the class A has a subclass with infinite basis suffices. If ∈ Mk ∪ Sk ∪ Lk there exists a 2-element subset E ⊂ Ek with Pk,E ⊂ A. Then, with the aid of the Lemma 8.1.1 one can find a subclass of A with an
8.3 Some Strategies for the Determination of Sublattices of Lk
229
infinite basis easily. If A has the type M, then one can change the example from the Lemma 8.1.1 in the following manner: Instead of 0, 1, 2 one chooses a, b, c of Ek with a < b < c and with the property ∀x ∈ Ek : b < x ≤ c =⇒ x = c. Consequently, A has also for ∈ Mk a subclass with an infinite basis. If ∈ Sk , the construction of a corresponding example is more complicated. Let := s ∈ Sk , where s is defined as in Section 5.2.2. If s has only cycles of the length 2, then P olk s has a subclass with a infinite basis because of Lemma 8.2.1. In the following we assume that the cycles of s have a length ≥ 3. If k = 3 then |L↓3 (P ol3 s )| = c results from Theorem 8.2.2. If k > 3 then we can assume w.l.o.g. that the cycle representation of s contains a cycle of the form (0 1 2 ...). In generalization of our example from the proof of the Theorem 8.2.2 one can define then 2n-ary functions ψn , which agree with the above functions ϕn on the set E32n and which are otherwise so defined that ψn ∈ P olk s holds and that [{ψ2 , ψ3 , ...}] has an infinite basis. We notice that one can find another proof for |L↓k (P olk s )| = c in the case of k ≥ 4 in [Dem-H 83]. The remaining statements of our theorem result from Chapter 5, Theorem 8.1.6 and Chapter 13. In Chapter 13 one can find all subclasses from A for the case that ∈ Lk and k is a prime number. Further, one finds in Chapter 13 an example of a class from linear functions, which has no basis if k is not square-free. One can generalize this example easily then for an example of a class from quasi-linear functions without basis, if k = pm and m ≥ 2. For k = 3 we will show in Chapter 15 that there are exactly 7 submaximal classes B with B = L3 and |L↓3 (B)| = ℵ0 .
8.3 Some Strategies for the Determination of Sublattices of Lk Because of Theorem 8.1.3, there is little hope that one can ever describe all elements of Lk for k ≥ 3. Nevertheless, one can attempt to get a certain idea of the construction of lattice Lk through the restriction to certain “manageable” sublattices. For example, one can restrict oneself to finitely generated subclasses of Pk . Subsequently, an enumeration is declared by sets for which there is a line of article in the literature and which characterize certain “sections” of Lk quite well: (a) The lattice of the subclasses from linear or quasi-linear functions (see Chapter 13, 15.3 and e.g. [Sze 79], [Sze 80], [Sza-S 80], [Bag-D 82], [Sze 86], [Bul 98a,b]. (b) The set of all commutator sets or subclasses of autodual functions (e.g. [Har 74-76], [Mar 79], [Mar-D-H 80], [Csa-G 80], [Csa 80], [Mac-R 2004]) (c) subclasses of
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8 Some Properties of the Lattice Lk
Uω :=
{f n ∈ Pk | (∃i : xi = ω) =⇒ f (x1 , ..., xi , ..., xn ) = ω}
n≥1
(this set is isomorphic to the set of all partial functions of Pk−1 ) (see e.g. [Mal 66], [Ros 88], [Ros-H 87,89,91] and Chapter 20) (d) subclasses of Pk , which contain certain subsemigroups of (Pk1 ; ) (see e.g. Chapter 4, [Had-R 94], [Kro 99]) (e) subclasses of Pk , which contain a “near unanimity function” or the discriminator z, if x = y, t(x, y, z) := x, otherwise (see e.g. [Bak-P 75], [Wer 78], [Csa-G 81]). (f) The set of the inverse images of subclasses of Pl in respect to certain mappings (see Chapter 12). (g) The set of all intersections from already determined classes (e.g. the maximal classes). (In this connection one can use for example the results on basis classifications from [Miy 71], [Miy-S-L-R 87], [Miy 88], and [Sto 87].) (h) clones with certain properties (e.g. minimal clones, solidifyable clones etc.), see e.g. Chapter 19 and [Den-W 2000]. For some further chapters we still need two theorems, which are the basis for the determination of certain sublattices of Pk . The following theorem is an insignificant generalization of the Theorem of Baker-Pixley which is proven in analog mode to [Wer 78] here. Theorem 8.3.1 Let A be a subclass of Pk , which contains a “near unanimity function” dm for certain m ≥ 2, i.e., an m + 1-ary function with the property dm (x1 , ..., xm+1 ) = x, if there is an i ∈ {1, ..., m + 1} with x1 = ... = xi−1 = xi+1 = ... = xm+1 = x. Then, A = P olk Inv m A holds, i.e., for fixed numbers m and k there are only finite-many subclasses A ∈ Lk with dm ∈ A. Proof. Obviously,
A ⊆ P olk(Invkm A).
Let f n ∈ P olk (Inv m A). Further, for T ⊆ Ekn denote fT a function of Pk , which agrees with the function f on tuples from T . We prove by induction on |T | =: t ≥ m that there exists a certain function fT ∈ A to every T ⊆ Ekn ; through that f ∈ A for t = k m would be shown and A = P olk (Invkm A) would be proven. I) t = m: Let T = {(ai1 , ai2 , ..., ain ) | i = 1, 2, ..., m},
8.3 Some Strategies for the Determination of Sublattices of Lk
⎛
⎞
231
a11 a12 ... a1n ⎜ a21 a22 ... a2n ⎟ ⎟ := ⎜ ⎝ ................. ⎠ am1 am2 ... amn and let be the least relation of Inv m A with ⊆ , i.e., ⎛ ⎛ ⎞ a11 a12 ... a1n a1 ⎜ ⎜ a2 ⎟ ⎜ ⎟ ∈ \ ⇐⇒ ∃q ∈ An : q ⎜ a21 a22 ... a2n ⎝ ................. ⎝ ... ⎠ am am1 am2 ... amn
it holds ⎞ ⎛
⎞ a1 ⎟ ⎜ a2 ⎟ ⎟=⎜ ⎟ ⎠ ⎝ ... ⎠ . am (8.12) Since f n preserves the m-ary invariants of A, we have f () ∈ . If f () belongs to , there is a certain function in A which agrees with the function f on tuples from T . If also on the other hand, f () ∈ \ is valid, then there is because of (8.12) also a certain function fT in A. Thus the above assertion was proven for t = m. II) t −→ t + 1: Suppose for every T ⊆ Ekn with |T | = t, t ≥ m, there is a function fT ∈ A with fT (a) = f (a) for all a ∈ T . Let now T = {a1 , a2 , ..., at+1 } and |T | = t + 1. Because of our assumption, there exist functions fi ∈ An with fi (a) = f (a) for all a ∈ T \{ai }, i = 1, 2, ..., m + 1. Since dm ∈ A, we have through dm (f1 (x), f2 (x), ..., fm+1 (x)) a function in A, which agrees with f on tuples aus T . In Chapter 12, we generalize this theorem for Pk,l . The last theorem of this chapter, which is a slight generalization of Lemma 3.2.3.1, shows that there are sublattices of the form L↓k (A) of Pk whose elements one can receive by means of intersection formations of A with classes that are not subsets of A. We will use this theorem in Chapters 14 and 18. In preparation for the announced theorem, some notations and properties are given: Let s be a permutation of Pk defined by s(x) := x + 1 (mod k), let s := {(x, s(x)) | x ∈ Ek } and put Sk := P olk s . Analogously to the proof of Theorem 5.2.2.1, one can prove that a function f n ∈ Pk belongs to Sk if and only if there exists an (n − 1)-ary function F of Pk := Pk ∪ Ek 1 with the following property: f (x1 , ..., xn ) =
k−1
ji (x1 ) · si (F (sk−1 (x2 ), ..., sk−i (xn ))) (mod k)
(8.13)
i=0
(si (x) := x+i (mod k); F (x1 , ..., xn−1 ) := f (0, x1 , ..., xn−1 )). Because of (8.13) it is possible to define a bijective mapping α of Sk (⊆ Pk ) onto Pk as follows: α : f −→ F. 1
In this case, the elements of Ek are the nullary functions of Pk .
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8 Some Properties of the Lattice Lk
Theorem 8.3.2 The mapping α has the following properties: τ, ∆, ∇ and (a) For the operations ζ, defined by )(x1 , ..., xn ) = f (x1 , x3 , x4 , ..., xn , x2 ), (ζf ( τ f )(x1 , ..., xn ) = f (x1 , x3 , x2 x4 , ..., xn ), )(x1 , ..., xn−1 ) = f (x1 , x2 , x2 , x3 , ..., xn−1 ), (∆f )(x1 , ..., xn+1 ) = f (x1 , x3 , x4 , ..., xn+1 ) und (∇f (f g)(x1 , ..., xm+n−2 ) = f (x1 , g(x1 , ..., xm ), xm+1 , ..., xm+n−2 ) (n, m ≥ 2), it holds α( γ f ) = γ(α(f )) for every γ ∈ {ζ, τ, ∆, ∇} and α(f g) = τ, ∆, ∇, ) is isomorphic to the algebra α(f ) α(g); i.e., the algebra (Sk ; ζ, (Pk ; ζ, τ, ∆, ∇, ). (b) For every subclass A (= ∅) of Sk , α(A) is a subclass of Pk , and it holds α(A) ⊆ Sk , A ⊆ α(A) and α(A) ∩ Sk = A. Proof. (a) is easy to check. (b): Let A be a subclass of Sk . By (a) we have that α(A) is also a closed set. Assume α(A) ⊆ Sk . Then we have F (x2 , ..., xn ) = si (F (sk−i (x2 ), ..., sk−i (xn ))) for every i ∈ {0, 1, ..., k − 1} and for every f n ∈ A. Thus by (8.13) we get that the variable x1 is fictitious for every function f n ∈ A. However, this is not possible. Hence α(A) ⊆ Sk holds. Let f n ∈ A. Then ∇f ∈ A and therefore α(∇f ) = f ∈ α(A), i.e., A ⊆ α(A). If f n ∈ Sk ∩ α(A), we have ∆(α−1 f ) = f ∈ A and thus Sk ∩ α(A) ⊆ A. From this it follows that A = Sk ∩ α(A), since A ⊆ α(A) and A ⊆ Sk .
9 Congruences and Automorphisms on Function Algebras
As generally known, one can characterize the homomorphic mappings from the algebra A := (A; F ) into the algebra B through the congruences of A (see Chapter 4 of Part I). Therefore, we will not deal here with the homomorphisms of function algebras but only with the congruences on the subclasses on Pk . After some basic concepts are defined, all congruences on the subclasses of P2 are determined in this chapter. It is the aim of the following sections, then, to specify the general homomorphism theorem for function algebras and to find statements on the number of the congruences on a subclass of Pk by determining some general properties of the congruences on subclasses of Pk . Then, all congruences are determined for selected classes (among other things these are the maximal classes of Pk and certain classes from linear functions). Criteria with which one can discuss whether, on a subclass of Pk , only trivial congruences exist are also derived. A later section deals with the connection between clone congruences and the fully invariant congruences on free algebras. The theorem found in this case has interesting inferences and is a bridge between certain investigations in the Universal Algebra and certain investigations in the theory of the function algebras. At the end of this chapter, are some results on automorphisms. It is proven that Pk , the subclasses of P2 , and the maximal classes of Pk have only inner automorphisms. The starting point and the basis of the subsequently compiled results was an article of A. I. Mal’tsev from the year 1966 (see [Mal 66]). Important contributions to the topic of Chapter 9 are also performed by V. V. Gorlov and I. A. Mal’tsev.
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9.1 Some Basic Concepts and First Properties Definition A congruence on a subclass A of Pk is an equivalence relation κ on A, which fulfills the following condition: ∀(f, g), (s, t) ∈ κ ∀α ∈ {ζ, τ, ∆, ∇} : (αf, αg) ∈ κ) ∧ (f ∗ s, g ∗ t) ∈ κ. Let
Con A
be the set of all congruences on the class A ∈ Lk . In the following, we write f ∼ g (κ) instead of
(f, g) ∈ κ
and we call such functions f and g κ-congruent. Furthermore, let κ(n) := κ ∩ (An × An ). If one wants to realize whether an equivalence relation on a subclass of Pk is compatible with the operation , it is helpful to use the equivalence given in the following lemma. Lemma 9.1.1 Let A be a subclass of Pk and let κ be an equivalence relation on A. Then, the following two conditions are equivalent: (1) ∀(f, g), (u, v) ∈ κ : (f u, g v) ∈ κ (2) ∀(f, g) ∈ κ ∀t ∈ A : ((f t, g t) ∈ κ ∧ (t f, t g) ∈ κ). Proof. “(1) =⇒ (2)” follows from the reflexivity of κ. “(2) =⇒ (1)”: Let (f, g), (u, v) ∈ κ. Choosing t = u in (2) and then t = g, one receives: (f u, g u) ∈ κ and (g u, g v) ∈ κ. Since κ is transitive, this implies (1). Next to the trivial congruences κ0 := {(f, f ) | f ∈ A} and κ1 := A × A, the following congruence, which we want also to call trivial congruence, exists on every subclass of Pk : κa := {(f, g) ∈ A2 | af = ag}. Later we obtain the following theorem as a consequence of Lemmas 9.7.1 and 9.2.1: Theorem 9.1.2 ([Mal 66]) The (trivial) congruences κ0 , κa and κ1 are the only congruences on Pk .
9.2 Congruences on the Subclasses of P2
235
It is easy to check that ∀A ∈ Lk ∀κ ∈ Con A : (κa ⊂ κ ⊆ κ1 =⇒ κ = κ1 ). Consequently, the following partition of Con A, where A is a subclass of Pk , is reasonable: Con1 A := {κ ∈ ConA | κ ⊆ κa } (congruences of the first kind, non-arity congruences) and
Cona A := {κ ∈ ConA | κ ⊆ κa } (congruences of the second kind, arity congruences).
9.2 Congruences on the Subclasses of P2 We take over the notations from Chapter 3. Further, for an arbitrary subclass A of P2 set: κc := {(f, g) ∈ κa ∩ (A × A) | ∃a ∈ E2 : f (x) = g(x) + a}, µ := {(f, g) ∈ κa ∩ (A × A) | f = g =⇒ {f, g} ⊆ C}, κa := (C0 × C0 ) ∪ (C1 × C1 ) (More generally, the relation κa is defined in (9.1)). It can easily be shown that κc is a congruence on the class A, if A ⊆ L; µ is a congruence on A, if A = [A] ⊆ [P21 ]; and κa is a congruence on the set C. Lemma 9.2.1 Let A ⊆ Pk be a clone. Then κ1 is the only non-arity congruence on A. Proof. Let κ be a congruence on A with κ ⊆ κa . Then, there are certain f n , g m ∈ A with (f, g) ∈ κ and n > m. Consequently, we have (∆(e22 ∗ ∆n−2 f ), ∆(e22 ∗ ∆n−2 g)) = (e22 , e11 ) ∈ κ and therefore
t−1 1 t t−1 (e22 ∗ et−1 t−1 , e1 ∗ et−1 ) = (et , et−1 ) ∈ κ
for t = 2, 3, ... . Then, since κ is an equivalence relation, it follows that ∀s, t ∈ N : (ess , ett ) ∈ κ. This implies κ = κ1 , since for every function hq ∈ A (e22 ∗ h, e11 ∗ h) = (eq+1 q+1 , h) ∈ κ holds.
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Lemma 9.2.2 Let A ⊆ Pk be a clone and κ ∈ Con A with κ ∩ {(e11 , c10 ), (e11 , c11 ), (e21 , e22 )} = ∅. Then κa is the only arity congruence on A. Proof. Assume κ is an arity congruence on the clone A and f n is an arbitrary function of A. Put e := e11 and ca := c1a for a ∈ {0, 1}. Then, (e, ca ) ∈ κ implies (e∗f, ca ∗f ) = (f n , cna ) ∈ κ and (e21 , e22 ) ∈ κ implies (e21 (f (x), x1 ), e22 (f (x), x1 )) = (f (x), en1 (x)) ∈ κ. Since κ is an equivalence relation, κ = κa follows from that. With the aid of Lemmas 9.2.1 and 9.2.2, one can easily prove the following lemma. Lemma 9.2.3 The congruences κa , µ and κc are the only nontrivial congruences on a subclass of [P21 ]. Lemma 9.2.4 Let A be a subclass of P2 that contains ∧ or ∨. Then A has only trivial congruences. Proof. W.l.o.g. let ∧ ∈ A. Suppose there is a nontrivial congruence κ on A. Then, because of Lemma 9.2.1, we have κ0 ⊂ κ ⊂ κa and there exists κ-congruent functions f n , g n ∈ A with f = g. For f and g we distinguish two cases: Case 1: {∆n−1 f, ∆n−1 g} ∩ {c0 , c1 , e} = ∅. Because of (f, g) ∈ κ \ κ0 one can form different unary κ-congruent functions f , g when one identifies variables and replaces certain variables of f, g by the function h ∈ {c0 , c1 , e} ∩ A. W.l.o.g. (f , g ) ∈ {(e, c0 ), (e, c1 ), (e, e), (c0 , c1 )}. If (f , g ) = (e, e) ∈ κ, then, by ∧ ∈ A, the tuple (e, c0 ) = (e ∧ e, e ∧ e) belongs to κ. If (c0 , c1 ) ∈ κ then (e ∧ c0 , e ∧ c1 ) = (c0 , e) ∈ κ. Consequently, we have {(e, c0 ), (e, c1 )} ∩ κ = ∅ and by Lemma 9.2.2 κ = κa , in contradiction to the assumption. Case 2: ∆n−1 f = ∆n−1 g = e. Since f = g, there is an a ∈ E2n \{0, 1} with (w.l.o.g.) f (a) = 0 and g(a) = 1. When one identifies certain variables of the functions f and g, one receives from (f, g) ∈ κ the existence of two binary κ-congruent functions f , g with f (0, 0) = f (0, 1) = 0, f (1, 1) = 1 and
g (0, 0) = 0, g (0, 1) = g (1, 1) = 1,
i.e., (f , g ) ∈ {(∧, e22 ), (∧, ∨), (e21 , e22 ), (e21 , ∨)}. If (∧, e22 ) ∈ κ then (τ ∧, τ e22 ) = (∧, e21 ) and thus (by the transitivity and symmetry of κ) we have (e22 , e21 ) ∈ κ. Analogously, (e21 , ∨) ∈ κ implies (e22 , e21 ) ∈ κ. If (∧, ∨) ∈ κ then x = (x ∧ y) ∨ x ∼ (x ∧ y) ∧ x = x ∧ y (κ). Therefore, (e21 , e22 ) ∈ κ in Case 2. A contradiction from this results with the aid of Lemma 9.2.2.
9.2 Congruences on the Subclasses of P2
237
Lemma 9.2.5 Let A be a subclass of S, which contains the function h2 defined by h2 (x, y, z) := xy ∨ xz ∨ yz. Then A has only trivial congruences. Proof. Assume κ is a nontrivial congruence on A. Then, by Lemma 9.2.1, there exists two κ-congruent functions f n , g n ∈ A with f (a) = 0 and g(a) = 1 for a certain a ∈ E2n . If a ∈ {0, 1} then e belongs to A and {∆n−1 f, ∆n−1 g} = {e, e} holds, i.e., (e, e) ∈ κ. This implies x = h2 (x, y, y) ∼ h2 (x, y, y) = y (κ) and then (e21 , e22 ) ∈ κ. Therefore, by Lemma 9.2.2, κ = κa holds, if a ∈ {0, 1}. If a does not belong to {0, 1}, one can form two binary κ-congruent functions f and g when one identifies certain variables of f and of g. Since S 2 = {e21 , e22 , e21 , e22 }, this implies (e21 , e22 ) ∈ κ and thus κ = κa by Lemma 9.2.2. This is, however, a contradiction to the assumption. Theorem 9.2.6 Let A ⊆ L be a subclass, which contains the function r defined by r(x, y, z) = x + y + z. Then, κc is the only nontrivial congruence on A. Proof. Let κ be an arity congruence on A. The following two cases are possible: Case 1: κ0 ⊂ κ ⊆ κc . In this case, there exists κ-congruent functions f and g with f (x) = g(x) + 1. Consequently, because of r ∈ A, we have : x1 = f (x) + f (x) + x1 ∼ g(x) + f (x) + x1 = x1 + 1 (κ), i.e., (e, e) ∈ κ. Therefore, κ = κc . Case 2: κ ⊆ κc . Then, there are two κ-congruent functions f n , g n with f (x) = a0 + a1 x1 + ... + an xn , g(x) = b0 + b1 x1 + ... + bn xn and (w.l.o.g.) a1 = 0 and b1 = 1. Thus r(y, f (x, y, ..., y), f (y, y, ..., y)) = y ∼ r(y, g(x, y, ..., y), g(y, y, ..., y)) = x (κ). Consequently, κ = κa by Lemma 9.2.2. The following theorem is a consequence of the Post’s graph and of the six above lemmas: Theorem 9.2.7 (Congruence Theorem for P2 , [Gor 73]) The only nontrivial congruences on a subclass of P2 are µ (on classes A with A ⊆ [P21 ]), κc (on classes B with B ⊆ L) and κa (on C). An arbitrary subclass (= ∅) of P2 has at least two and at most five different congruences. The congruence lattices are given in Figure 9.1.
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κ1
κ1
κ1
κa
κa
κa
κc
κc
µ
κ0
µ
κ0
κ1 κ a κa κ0
κ0 [P21 ]
L, L ∩ S
I ∪C
C
κ1
κ1
κ0
κa κ0
C0 , C1
in all remaining cases
Fig. 9.1. Congruence lattices of the subclasses of P2
9.3 Characterization of the Non-Arity Congruences In this section let A be a subclass of Pk . Definition We say that two functions f m and g n of A ⊆ Pk are associated (in A), or we say that f is associated with g (in A), written f g, iff there exist functions u1 , u2 , ..., um+n ∈ A1 with f (u1 (x), u2 (x), ..., um (x)) = g(un+1 (x), un+2 (x), ..., um+n (x)). Obviously, each function f ∈ A is associated with each function αf for α ∈ {ζ, τ, ∆, ∇}) and with f g, where g ∈ A. Let p0 , pt+1 ∈ A. We define an equivalence relation κa on A as follows: p0 ∼ pt+1 (κa ) :⇐⇒ ∃p1 , p2 , ..., pt ∈ A : p0 p1 p2 ... pt pt+1 .
(9.1)
9.3 Characterization of the Non-Arity Congruences
239
Lemma 9.3.1 The relation κa defined by (9.1) is a congruence on A = [A] ⊆ Pk . Proof. Obviously, κa is an equivalence relation on A. To prove the compatibility of κa with the superposition operations, let p0 ∼ pt+1 (κa ) and q0 ∼ qs+1 (κa ) be arbitrary, i.e., there exist functions pi (i = 1, 2, ..., t), qj (j = 1, 2, ..., s) of A with p0 p1 p2 ... pt pt+1 and
q0 q1 q2 ... qs qs+1 .
Because of αp0 p0 p1 p2 ... pt pt+1 αpt+1 (α ∈ {ζ, τ, ∆, ∇}) we have αp0 ∼ αpt+1 (κa ). Furthermore, p0 q0 ∼ pt+1 qs+1 (κa ), since p0 q0 p0 p1 p2 ... pt+1 pt+1 qs+1 . Thus κa is a congruence on A. Lemma 9.3.2 Every equivalence relation κ with κa ⊆ κ is a congruence on A. Proof. Let f ∼ g (κ) and u ∼ v (κ) be arbitrary. Then f ∼ αf (κa ) g ∼ αg (κa ) (κ) (α ∈ {ζ, τ, ∆, ∇}) and
f u ∼ f (κa ) g v ∼ g (κa ) (κ)
.
Because of κa ⊆ κ we have thus αf ∼ αg (κ) and f u ∼ g v (κ). Lemma 9.3.3 Let κ be a non-arity congruence on a subclass A of Pk . Then κa ⊆ κ. Proof. Let h1 ∈ A1 be arbitrary and let hi be the function ∇i−1 h1 with n ∈ N\{1}. We prove (9.2) ∀i, j ∈ N : hi ∼ hj (κ).
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9 Congruences and Automorphisms on Function Algebras
Since κ is a non-arity congruence, there exist κ-congruent functions f n and g m of A with n > m. Consequently, we have h2 (∆n−2 f ) = h3 ∼ h2 (∆n−2 g) = h2 (κ), h2 = ∆h3 ∼ ∆h2 = h1 (κ), ∇h3 = h4 ∼ ∇h2 = h3 (κ), etc. Thus, (9.2) holds. Next we prove ∀f n ∈ A ∀g1 , ..., gn ∈ A1 : f (x1 , ..., xn ) ∼ f (g1 (x1 ), ..., gn (x1 )) (κ).
(9.3)
Let f n ∈ A be arbitrary and set f1 := ∇f . Then: f2 := f1 h1 ∼ f1 hn+1 =: f3 (κ) and where and
f4 := ∆f2 ∼ ∆f3 =: f5 (κ), f4 (x1 , ..., xn ) = f (x1 , ..., xn ) f5 (x1 , ..., x2·n ) = f (xn+1 , ..., x2·n ).
Consequently, we have for all g1 , ..., gn ∈ A1 : (ζ(...((ζ((ζ((ζ n+1 f5 ) gn )) gn−1 )) gn−2 )...) g1 ∼ (ζ(...((ζ((ζ((ζ n+1 f4 ) gn )) gn−1 )) gn−2 )...) g1 (κ) which can be written more briefly in the form f4 (g1 (x1 ), ..., gn (x1 )) = f (g1 (x1 ), ..., gn (x1 )) ∼ f5 (g1 (x1 ), ..., gn (x1 ), x1 , ..., xn ) = f (x1 , ..., xn ) (κ). Thus (9.3) is right. Finally, we prove the following fact: ∀f, g ∈ A : (f ∼ g (κa ) =⇒ f ∼ g (κ)). If f ∼ g (κa ), there are functions p1 , ..., pt+1 ∈ A with p0 := f p1 p2 ... pt pt+1 := g. Then, by definition (9.1) and by property (9.3), we obtain p0 := f ∼ p1 ∼ p2 ∼ ... ∼ pt ∼ pt+1 := g (κ), i.e., f ∼ g (κ). Thus κa ⊆ κ.
(9.4)
9.3 Characterization of the Non-Arity Congruences
241
Theorem 9.3.4 (I. A. Mal’tsev’s Theorem, [Mal 76]) Let A be a subclass of Pk . Then A has only finite many non-arity congruences. These congruences are equivalence relations on A with κa ⊆ κ. In particular, for arbitrary subclasses A of Pk it holds: Con1 A = {κ1 } ⇐⇒ κa = κ1 and
1 ≤ |Con1 A| ≤ µ(|A1 |),
where µ(n) denotes the number of possible equivalence relations on an nelement set. Proof. The statements of our theorem result directly from Lemmas 9.3.1– 9.3.3 and the fact that every function f ∈ A is κa –congruent to a certain unary function of A. We still notice that the above theorem is not valid if the operation ∇ is renounced. One finds an example for this purpose in [Gor 73]. The relation κ1 is the only non-arity relation on many classes. In Lemma 9.2.1, it was shown that this is valid for all clones. In generalizing Lemma 9.2.1 we get: Lemma 9.3.5 ([Mal 76]) Let A be a subclass of Pk . If there is a unary function u ∈ A with (a) ∀f ∈ A : u f = f (i.e., “u is a left unit”) or (b) ∀g ∈ A1 : g u = u (i.e., “u is a right zero”), then κ1 is the only non-arity congruence on A. Proof. By Theorem 9.3.4 it is sufficient to show that κa = κ1 . (a) : If u is a left unit then for arbitrary f n ∈ A we have f (u, u, ..., u) := u1 u u1 = u1 . Consequently, f u and therefore κa = κ1 . (b) : If u is a right zero of A then ∀ f n ∈ A : f (u, u, ..., u) = u and u u = u. This implies f u. Therefore κa = κ1 . When one proves κa = κ1 , one receives the next lemma as a conclusion of Theorem 9.3.4. Lemma 9.3.6 If the subclass A ⊆ Pk contains all constant functions on Ek and
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9 Congruences and Automorphisms on Function Algebras
∀ f1 , ft+1 ∈ A ∃f2 , ..., ft ∈ A : ∀i ∈ {1, 2, ..., t} : Im(fi ) ∩ Im(fi+1 ) = ∅, holds, then κ1 is the only non-arity congruence on A. Finally, we solve the problem how the structure of classes is which ones have the maximum number of possible non-arity congruences (see Theorem 9.3.4). Lemma 9.3.7 Let A be a subclass of Pk and let σ be a relation on A defined by (9.5) (f n , g m ) ∈ σ :⇐⇒ {f, g} ⊆ A ∧ ∆n−1 f = ∆m−1 g. Then: (a) The relation σ is a congruence on A if and only if A has the property ∀ r, s ∈ A1 : r s = r. (1) κa
(1) κ0 . 1 1
(b) κa = σ ⇐⇒ = (c) There are exactly µ(|A |) fulfills the condition (9.6). Proof. Obviously,
(9.6)
non-arity congruences on A if and only if A
σ ⊆ κa
(9.7)
holds for the relation defined by (9.5). (a): “=⇒”: Let σ be a congruence on A. Then, by Theorem 9.3.4 and (9.7), we have σ = κa . In particular, it holds (f 1 , g 1 ) ∈ σ ⇐⇒ f = g ∈ A1 .
(9.8)
Suppose (9.6) is false, i.e., there are certain r, s ∈ A1 with r s =: t = r. Because of r (s h) = t h for arbitrary h ∈ A1 , we have that r and t are associated in A. Because of r = t and σ = κa , this is, however, a contradiction to the equivalence (9.8). Therefore (9.6) holds. “⇐=”: Fulfill A the condition (9.6). Obviously, σ is an equivalence relation on A, which is compatible with all unary superposition operations. We have to show therefore only still the compatibility from σ with . Let (f n , g m ), (sp , tq ) ∈ σ be arbitrary. Then ∆n−1 f = ∆m−1 g =: f1 and ∆p−1 s = ∆q−1 t =: s1 . This implies (∆n+p−1 (f s))(x) = f (s1 (x), x, ..., x) (9.6)
= f (s1 ((s1 (x)), s1 (x), ..., s1 (x))
(9.6)
= f (s1 (x), s1 (x), ..., s1 (x)) = g(s1 (x), s1 (x), ..., s1 (x))
(9.6)
= g(s1 (s1 (x)), s1 (x), ..., s1 (x))
(9.6)
= g(s1 (x), x, ..., x) = (∆m+q−1 (g t))(x).
1
See Theorem 9.3.4.
9.4 About the Number of the Congruences on a Subclass of Pk
243
Thus (f s, g t) ∈ σ. (b): Obviously, “=⇒” holds. (1) (1) “⇐=”: Let κa = κ0 . The following two cases are possible: Case 1: A fulfills (9.6). Because of (a) the relation σ in this case is a congruence, which is identical with κa because of (9.7) and Theorem 9.3.4. Case 2: A does not fulfill (9.6). (1) (1) In the proof of (a), we have shown that a contradiction results from κa = κ0 . (c) follows from Theorem 9.3.4 and (b). Lemma 9.3.8 Let κ be a non-arity congruence on A = [A] ⊆ Pk . Further, let µ := κ ∩ (A1 × A1 ). (µ is a congruence of the semigroup (A1 ; ).) Then, for every equivalence class F of µ it holds: ∀g ∈ A1 : F g ⊆ F. Proof. Suppose µ has a certain equivalence class F , for which there are f1 , g1 ∈ F with f1 g1 ∈ F . Let now f2m+1 := (∇f1 )hm and f3p+1 := (∇f1 )tp , where (hm , tp ) ∈ κ and m < p. (Such h and t exist, since κ ⊆ κa .) Then, (f2 , f3 ) ∈ κ, (∆p−1 f2 , ∆p−1 f3 ) = (f1 , ∇f1 ) ∈ κ and (f1 g1 , (∇f1 ) g1 ) ∈ κ. This implies (∆(f1 g1 ), ∆((∇f1 ) g1 )) = (f1 g1 , f1 ) ∈ κ, contrary to the assumption. We will see in Theorem 9.8.8 that, to every congruence on (A1 ; ), which fulfills the condition of Lemma 9.3.8, there is exactly a non-arity congruence on [A1 ].
9.4 About the Number of the Congruences on a Subclass of Pk Denote ki (A) (i = 1, 2) the cardinality of the set of all congruences i-th kind on the subclass A of Pk . Further let k(A) := k1 (A) + k2 (A). The next theorem is a direct conclusion from the results of Section 9.2: Theorem 9.4.1 For every closed subset A of P2 it holds: k1 (A) ∈ {1, 2}, k2 (A) ∈ {1, 2, 3, 4} and k(A) ∈ {2, 3, 4, 5}. For k ≥ 3 the determination of all congruences is more complicated on an arbitrary class A ⊆ Pk . The following theorem mediates a first idea of that. Theorem 9.4.2 Let k ≥ 3. For every integer n ≥ 2 there is a subclass An of Pk with k(An ) = n. Furthermore there exist certain closed sets B and C of Pk with k(B) = ℵ0 and k(C) = c.
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9 Congruences and Automorphisms on Function Algebras
Proof. Obviously, a closed set of Pk has at least two different congruences and at most continuum-many. Next, we give a class C with continuum-many different congruences. Let the set C be defined as in Section 8.1. In Lemma 8.1.1 it was proven that C is closed and that C has an infinite basis. With the aid of properties of functions of C (given in the proof of Lemma 8.1.1) one can easily prove that the equivalence relation defined by sn ∼ tm (κN ) :⇐⇒ {s, t} ⊆ C ∧ n = m ∧ (s = t ∨ {s, t} ⊆ {gI,J ∈ C | |I| ∈ N ∨ J = ∅ ∨ I = J = ∅})
is a congruence on C for every N ⊆ N. Furthermore, it holds that κN = κN for N = N . Therefore, by |P(N)| = c, there are continuum-many congruences on C. Next we determine the congruences on the closed set At , t ≥ 0, which is the set of all functions n , |J| ≤ t, n ≥ 1. gJn := g∅,J For all r with 0 ≤ r ≤ t, the equivalence relation πr defined by
gJn ∼ gJn :⇐⇒ n = n ∧ (J = J ∨ (|J| ≤ r ∧ |J | ≤ r) ) is obvious a congruence on the class At . In particular, we have π0 = κ0 and πt = κa on At . Obviously, κ0 = κa and κ1 are the only congruences on A0 . If t ≥ 1 and κ is a congruence on At with πs ⊂ κ ⊆ κa , 0 ≤ s ≤ t − 1, then there exist functions gJn1 , gJn2 ∈ At with gJn1 ∼ gJn2 (κ), J1 = J2 and |J1 ≥ s+1. If |J2 | ≤ s, we have gJn1 ∼ cn0 (κ) and thus gJm ∼ cm 0 (κ) with |J| ≤ |J1 | and m ≥ 1, since one can form all functions gjm as superpositions on gJ1 . Therefore, in this case πs+1 ⊆ κ. If |J2 | ≥ s + 1 then w.l.o.g. one can assume 1 ∈ J1 and 1 ∈ J2 . Hence, we obtain gJn1 c10 = gJn1 ∼ cn0 = gJn2 c10 (κ), i.e., we have also in this case πs+1 ⊆ κ. In summarizing we see that κ0 , π1 , π2 ,..., πt−1 and κa are the only arity congruences on At . Because of Lemma 9.2.1, κ1 is the only non-arity congruence on At . Consequently, for t ≥ 0, At is a class with exactly t + 2 different congruences. It is easy to see that the set of all congruences on the closed set B := t≥0 At has the cardinality ℵ0 . Each class A with |Con(A)| ∈ {ℵ0 , c} defined in the above proof has no basis or an infinite basis, respectively. A connection between ord A = ∞ and |Con(A)| ∈ {ℵ0 , c} does not exist, however, as the examples show from the following two lemmas. Lemma 9.4.3 For each k ≥ 3 there is a subclass A of Pk with ord A = ∞ and Con A = 3.
9.4 About the Number of the Congruences on a Subclass of Pk
245
Proof. Proving the lemma for k = 3 suffices. We consider the class {f ∈ P3,2 | ∀a ∈ E2n : f (a) = 0}, A := n≥1
for which we prove in Chapter 12 that it does not have any finite generating system. Subsequently, we will show that A has only trivial congruences. Let κ be a congruence on A with κ = κa . Then, the following two cases are possible: Case 1: κ0 ⊂ κ ⊆ κa . In this case, there are n-ary κ-congruent functions f, g ∈ A with f = g. W.l.o.g. we can assume that n = 3, f (0, 1, 2) = 0 and g(0, 1, 2) = 1. Consequently, we have f (c0 (x), j2 (x), x) = c10 (x) ∼ j2 (x) = g(c0 (x), j2 (x), x) (κ). Let tm be an arbitrary m-ary function of A. Then the (2 · m)-ary function ht defined by t(x1 , ..., xm ) if xm+1 = ... = x2·m = 0, ht (x1 , x2 , ..., x2·m ) := 0 otherwise belongs to A. From that we receive ht (x1 , ..., xm , c0 (x1 ), ..., c0 (xm )) = t(x1 , ..., xm ) ∼ cm 0 (x1 , ..., xm ) = ht (x1 , ..., xm , j2 (x1 ), ..., j2 (xm )) (κ). This implies κ = κa immediately. Case 2: κ ⊆ κa . Since A has a right zero, κ = κ1 results in this case from Lemma 9.3.5. Without use of Lemma 9.3.5, this can be shown as follows: If κ ⊆ κa then there are κ-congruent functions f n , g m ∈ A with n > m. Therefore, c10 (∆n−1 f ) = c20 ∼ c10 = c10 (∆n−1 g) (κ). This implies that all constant functions of A are κ-congruent to each other. Furthermore, for a binary function h ∈ A with h(0, 2) = 1 we have: ∆((τ (h c10 )) c10 ) = c10 (x) ∼ r(x, y) := ∆((τ (h c20 )) c10 ) (κ), where r(0, 2) = 1. Because of (c10 , c20 ) ∈ κ, this implies (c20 , r) ∈ κ and thus κ ∩ κa = κ0 . Then κ = κ1 follows from our considerations for Case 1 and from the κ-congruence of the functions cn0 for arbitrary n. Hence A has only trivial congruences. The class defined in the following lemma was published by V. L. Murskij in [Mur 65] as an example for a class without a finite basis of identities.
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Lemma 9.4.4 Let m be defined by x, if (x, y) ∈ {(1, 2), (2, 1), (2, 2)}, m(x, y) := 0 otherwise a binary function of P3 . congruences.
2
Then, the subclass M := [m] has infinite-many
Proof. For f n ∈ M we denote with χ(f ) the set of all tuples a of E3n with f (a) ∈ {1, 2}. Further, let Krn := {f ∈ P3n | ∀N ⊆ χ(f ) : (|N | ≤ r =⇒ (∃i : ∀(a1 , ..., an ) ∈ N : ai = 2} and
Kr :=
Krn .
n≥1
One can easily prove the following statement: ∀f n ∈ M ∃i : a ∈ χ(f ) =⇒ f (a) = ai .
(9.9)
For r ≥ 1, we consider the equivalence relation µr on M defined by f n ∼ g m (µr ) :⇐⇒ n = m ∧ (f = g ∨ {f, g} ⊆ Krn ) and show that it is a congruence on M . For this purpose, we choose arbitrary functions f n , g n , pm , q m of M with (f, g), (p, q) ∈ µr . Then we have (αf, αg) ∈ µr for every α ∈ {ζ, τ, ∆, ∇}. For the proof of (f p, g q) ∈ µr , it suffices to show that (f ∈ Kr ∨ p ∈ Kr ) ∧ (f depends essentially of x1 ) =⇒ f p ∈ Kr (9.10) holds for arbitrary f, p ∈ M . Let the first place of the function f be essential. We distinguish two cases: Case 1: f ∈ Kr . Let a1 , ..., as ∈ χ(f p), 1 ≤ s ≤ r, aj := (aj,1 , ..., aj,n+m−1 ), j = 1, 2, ..., s, p(aj,1 , ..., aj,m ) =: bj . Because of f ∈ Kr we have either b1 = ... = bs = 2 or there exists a u ≥ m + 1 with a1,u = ... = as,u = 2. If b1 = ... = bs = 2, there is by (9.9) a v with 1 ≤ v ≤ m and av,1 = ... = av,s = 2. Consequently, f p belongs to Kr . Case 2: p ∈ Kr . In this case, since by assumption the first place of f is essential, (f n pm )(a) ∈ {1, 2} for a ∈ E3m+n−1 is only possible, if p(a1 , ..., am ) ∈ {1, 2}. Consequently, we have χ(f p) ⊆ {a ∈ E3m+n−1 | (a1 , ..., am ) ∈ χ(p)} and this implies f p ∈ Kr . Thus (9.10) was proven and µr is a congruence on M . One can 2
We notice that the function m can be interpreted as a binary partial projection. In this case m(a, b) = 0 stands instead of “m(a, b) is not defined”.
9.4 About the Number of the Congruences on a Subclass of Pk
247
prove that the congruences of the form µr are different pairwise as follows: Let xy := m(x, y). The functions tn and sn defined by t(x1 , ..., xn ) := ((((((x1 ((x2 x1 ))(x3 x1 ))(x3 x2 ))(x4 x1 ))...(x4 x3 ))...)(xn xn−1 )(xn x1 ))(x3 x2 )) ...(xn xn−1 )) x1 if x ∈ {(1, 2, ..., 2), (2, 1, 2, ..., 2), ..., (2, ..., 2, 1), (2, ..., 2)}, = 0 otherwise and
s(x1 , ..., xn ) := t(m(x1 , x1 ), ..., m(xn , xn )) 2 if x1 = ... = xn = 2, = 0 otherwise
belong to M , and it holds (tn , sn ) ∈ µn−1 and (tn , sn ) ∈ µn for arbitrary n ≥ 1. Consequently, there are infinite-many congruences on M . With the aid of Lemma 9.10.1 and [Oat-W 80], we will later prove that the above-defined class M has continuum-many congruences. The following theorem gives examples of classes A whose congruences are completely determined by the congruences on certain sets B with A ⊆ B. We use this theorem in Section 9.6. Theorem 9.4.5 Let S be the set of all functions f n ∈ Pk for which f (x1 , x2 , ..., xn ) = s−1 (f (s(x1 ), s(x2 ), ..., s(xn )) holds, i.e., S = P olk {(x, s(x)) | x ∈ Ek }. Further, let α be the isomorphism defined in Theorem 8.3.2. Then, |Con A| ≤ |Con α(A)|. More precisely: Let A (= ∅) be a subclass of S, let κ be a congruence on A and let α(κ) be a relation on α(A) defined by (F, G) ∈ α(κ) :⇐⇒ (α−1 F, α−1 G) ∈ κ. Then (a) α(κ) is a congruence on A; (b) α(κ)/A = κ, i.e., by means of restriction on A one can get the congruences on A from the congruences on α(A). Proof. Since κ is a congruence on A, κ is compatible with the operations ˆ τ ,∆, ˆ∇ ˆ and ˆ ζ,ˆ ∗ . This and Theorem 8.3.2, (a) imply our statement (a). By Theorem 8.3.2, (b) we have A ⊂ α(A). Therefore, α(κ)/A is a congruence on A. Now let f and g be arbitrary functions of A. If (f, g) ∈ κ then
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9 Congruences and Automorphisms on Function Algebras
(∇f, ∇g) ∈ κ and by definition of α(κ); further, we have (α(∇f ), α(∇g)) = (f, g) ∈ α(κ)/A , i.e., κ ⊆ α(κ)/A . If (f, g) ∈ α(κ)/A then (α−1 f, α−1 g) ∈ κ. Since f, g ∈ S, it holds α−1 f = ∇f and α−1 g = g. Consequently, (∇f, ∇g) ∈ κ and (∆(∇f ), ∆(∇g)) = (f, g) ∈ κ, i.e., α(κ)/A ⊆ κ. This implies (b).
9.5 A Criterion for the Proof of the Countability of Con A for Certain A ⊆ Pk It is possible to choose a congruence relation on an algebra (in particular, a function algebra) as a universe of another algebra, as follows: Let A be the universe of a subalgebra of Pk = (Pk ; ζ, τ, ∆, ∇, ∗). Then, one can define for arbitrary (f, g), (p, q) ∈ A × A: ∀ α ∈ {ζ, τ, ∆, ∇} : α(f, g) := (αf, αg), (f, g) ∗ (p, q) := (f ∗ p, g ∗ q), σ(f, g) := (g, f ) and (f, q) if g = p, ((f, g), (p, q)) := (f, g) otherwise. Then each congruence on A is a universe of a subalgebra of the algebra (A × A; ζ, τ, ∆, ∇, ∗, σ, , (f, f )f ∈A ); i.e., it holds Con A = Sub(A × A; ζ, τ, ∆, ∇, ∗, σ, , (f, f )f ∈A ). (The tupel (f, f ), where f ∈ A is arbitrary, are certain nullary operations of the above defined algebra.) In particular, we have for the arity congruences: An × An ; ζ, τ, ∆, ∇, ∗, σ, , (f, f )f ∈A ). Cona A = Sub( n≥1
In order to be able to prove the countability of Con A for some A ⊆ Pk later with the aid of Theorem 8.1.5, we show first that class A fulfills the conditions of Theorem 8.1.5. Denote ◦ an operation on Ek with the properties a) ∀ a, b, c ∈ Ek : a ◦ (b ◦ c) = (a ◦ b) ◦ c, b) ∀ a, b ∈ Ek : a ◦ b = b ◦ a, c) ∃ r ≥ 1 : (∀ a ∈ Ek : a ◦ a ◦. . . ◦ a = a). (1+r)−times
The properties a)–c) e.g. are fulfilled, if (Ek , ◦) is an Abelean group or x ◦ y := maxω (x, y) or x◦y := minω (x, y) (ω is a partial order relation, for which exists max or min, respectively).
9.5 A Criterion for the Proof of the Countability of Con A for Certain A ⊆ Pk
249
With the help of ◦ one can define the following subset of Pk : K0 := {f n ∈ Pk | ∃ f0 , f1 , . . . , fn ∈ PE1 : f (x1 , . . . , xn ) = n≥1
f0 (f1 (x1 ) ◦ f2 (x2 ) ◦ . . . ◦ fn (xn ))}. In general, the set K0 is not closed; it contains, however, some closed sets in the case of suitable choice of ◦ (see Theorem 9.5.2). In analog manner to the proof of |Sub A| ≤ ℵ0 for all A = [A] ⊆ K0 in Theorem 8.1.6 one can show: Theorem 9.5.1 ([Lau 90]) Each subclass A of Pk , for which exists an operation ◦ with the properties a)–c) and A ⊆ K0 , has at most countable-many congruences. Proof. Since, by Theorem 9.3.4, every subclass of Pk has only finite-many non-arity congruences, it is sufficient to show that the set Con ( n≥1 An × An ; ζ, τ, ∆, ∇, ∗, σ, ) is finite or countable. For this purpose we define an or≤, which fulfills the conditions 1)–3) from Theorem 8.1.5, on der relation K0∗ := n≥1 K0n × K0n . Then, our theorem follows from Theorem 8.1.5. Each pair (f, g) ∈ K0n × K0n with f (˜ x) = f0 (f1 (x1 ) ◦ . . . ◦ fn (xn )) and g(˜ x) = g0 (g1 (x1 ) ◦ . . . ◦ gn (xn )) is well-defined by the tuples ϕ(f, g) := ((f0 , g0 ), (f1 , g1 ), . . . , (fn , gn )). Two pairs (f, g) and (p, q) with ϕ(f, g) = ((f0 , g0 ), . . . , (fn , gn )) and ϕ(p, q) = ((p0 , q0 ), . . . , (pm , qm )) are called ∼–equivalent, if they fulfill the three following conditions: (1) (f0 , g0 ) = (p0 , q0 ), (2) {(f1 , g1 ), . . . , (fn , gn )} = {(p1 , q1 ), . . . , (pm , qm )}, (3) If (fi , gi ) occurs in ((f1 , g1 ), . . . , (fn , gn )) exactly u times, then there exists a certain integer v so that (fi , gi ) occurs in ((p1 , q1 ), . . . , (pm , qm )) exactly (u + v · r) times, where r denotes the smallest integer for which ◦ fulfills the condition c). Obviously, the factor set K0∗/∼ is finite. Set {K1 , ..., Kt } := K0∗/∼ . On the sets K1 , . . . , Kt one can define an order relation ≤ as follows: For (f n , g n ), (pm , q m ) ∈ Ki (i = 1, . . . , t) with ϕ(f, g) = ((f0 , g0 ), . . . , (fn , gn )) and ϕ(p, q) = ((p0 , q0 ), . . . , (pm , qm )) we write (f, g) ≤ (p, q) if and only if for every (fi , gi ), which occurs in ((f1 , g1 ), . . . , (fn , gn )) j1 times and occurs in ((p1 , q1 ), . . . , (pm , qm )) j2 times, it holds j1 ≤ j2 . This order relation ≤ fulfills the condition 1) of Theorem 8.1.5, since one can receive (f, g) from (p, q) with the aid of the operations ζ, τ, ∆, if (f, g)≤(p, q) is valid (because of property c) of ◦). Obviously the property 2) of Theorem 8.1.5 is also valid. Thus, it remains to show that every antichain in the set K0∗ in respect to 1 1 ≤ has only finite-many elements. On PE × PE one can define a total order. For ϕ(f, g) = ((f0 , g0 ), . . . , (fn , gn )), we arrange (concerning this order) that
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(fi0 , gi0 ) is the smallest element of the set {(f1 , g1 ), . . . , (fn , gn )}; (fi1 , gi1 ) is the smallest element of the set {(f1 , g1 ), . . . , (fn , gn )}\ {(fi0 , gi0 )}, . . . and (fis , gis ) is the the greatest element of {(f1 , g1 ), . . . , (fn , gn )}. If (fij , gij ) occurs in {(f1 , g1 ), . . . , (fn , gn )} exactly bj times, j = 0, 1, . . . , s, then let α(f, g) := (b0 , b1 , . . . , bs ). Further, let Di := {α(f, g)| (f, g) ∈ Ki }, i = 1, 2, . . . , t. We set α(f, g) ≤ α(p, q) iff (f, g)≤(p, q). The ordered sets Ki and Di are isomorphic. In the proof of Theorem 8.1.6, it was shown that every antichain C ⊆ Di is a finite set. Therefore, ≤ also fulfills the condition 3) of Theorem 8.1.5. Some consequences from Theorem 9.5.1 are summarized in the following: Theorem 9.5.2 If A is a subclass of one of the sets (a) Lk (see Chapter 4), (b) P olk λ, λ ∈ Lk (see Section 5.2.4), (c) Ln (see Chapter 14) or (d) [O1 ∪ {max}] (see Chapter 15), then |Con A| ≤ ℵ0 . More precise statements about Con A for the above cases (a)–(c) are treated in the next section.
9.6 Congruences on Some Classes of Linear Functions Let R = (R; +, ·) be a unitary ring and let M = (M ; +, ·) be a left module on R. Then one can define a closed subset LM of PM as follows: LM :=
{f n ∈ PM | ∃ a0 ∈ M ∃ a1 , . . . , an ∈ R : f (x) = a0 +
n
ai · xi }.
i=1
n≥1
By [Sze 80], for every subclass A of LM that contains the function r defined by r(x, y, z) := x + y − z, there exists a uniquely defined subring TA of R and an uniquely defined submodule NA of R × M on TA with A=
{f n ∈ LM | ∃ a0 ∈ M ∃ a1 , . . . , an ∈ TA : f (x) = a0 +
n i=1
n≥1
(1 − a1 − a2 − · · · − an , a0 ) ∈ NA } . The sets TA and NA are defined by TA := {a ∈ R | ax + (1 − a)y ∈ A}, NA := {(1 − a, b) ∈ R × M | ax + b ∈ A1 }.
ai xi ∧
9.6 Congruences on Some Classes of Linear Functions
251
For the purpose of determining of the congruences on A, let I be an arbitrary ideal of TA , and let U be a suitably elected submodule of NA with ∀α, β ∈ TA ∀u, v ∈ NA : (α − β ∈ I ∧ u − v ∈ U =⇒ α · u − β · v ∈ U ). (9.11) With the help of I and U , one can define a relation κ(I, U ) (⊆ κa ) as follows: n n (a0 + i=1 ai xi , b0 + i=1 bi xi ) ∈ κ(I, U ) :⇐⇒ ∀i ∈ {1, . . . , n} : ai − bi ∈ I ∧ (1 − a1 − · · · − an , a0 ) − (1 − b1 − · · · − bn , b0 ) ∈ U. Lemma 9.6.1 κ(I, U ) is a congruence on A. Proof. It can easily be shown that κ(I, U ) is an equivalence relation and that κ(I, U ) is compatible with the operations ζ, τ, ∆ and ∇. Let now (f n , g n ), (sm , tm ) ∈ κ(I, U ) be arbitrary with f (x) = a0 + a1 x1 + · · · + an xn , g(x) = b0 +b1 x1 +· · ·+bn xn , s(x) = co +c1 x1 +· · ·+cm xm and t(x) = d0 + d1 x1 + · · · + dm xm . Then, bi = ai + αi , dj = cj + βj for certain αi , βj ∈ I (i = 1, . . . , n, j = 1, . . . , m), (f ∗ s)(x) = a0 + a1 c0 + a1 c1 x1 + . . . + a1 cm xm + a2 xm+1 + . . . + an xm+n−1 , (g ∗ t)(x) = b0 + b1 d0 + b1 d1 x1 + . . . + b1 dm xm + b2 xm+1 + . . . + bn xm+n−1 , a1 ci − b1 di = −α1 βi − α1 ci − a1 βi ∈ I (i = 1, . . . , m) and (1 − a1 c1 − . . . − a1 cm − a2 − . . . − am , a0 + a1 c0 ) −(1 − b1 d1 − . . . − b1 dm − b2 − . . . − bm , b0 + b1 d0 ) = a1 (1 − c1 − . . . − cm , c0 ) − b1 (1 − d1 − . . . − dm , d0 ) +(1 − a1 − . . . − an , a0 ) − (1 − b1 − . . . − bn , b0 ) ∈ U by (9.11) and (f, g), (s, t) ∈ κ. Thus κ(I, U ) is a congruence on A. We need some denotation and the following three lemmas to prove that on A next to the trivial congruences only congruences of the type κ(I, U ) still exist. The function qa (for a ∈ R) is defined by qa (x, y) := a · x + (1 − a) · y. Lemma 9.6.2 Let κ ⊆ κa be a congruence on A, let f (x) = a0 + a1 x1 + . . . + an xn ∈ A and let g(x) = b0 + b1 x1 + . . . + bn xn ∈ A. Then (f, g) ∈ κ ⇐⇒ ∀i ∈ {1, . . . , n} : (qai , qbi ) ∈ κ ∧ (∆n−1 f, ∆n−1 g) ∈ κ with ∆i+1 f := ∆(∆i f ), ∆1 f := ∆f . Proof. Let h ∈ {f, g}, h(x1 , . . . , xn ) = α0 + α1 x1 + . . . + αn xn , and denote rn the (n + 2)–ary function of [{r}] which is defined by rn (x1 , . . . , xn+2 ) :=
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x1 +x2 +. . .+xn+1 −n·xn+2 . Then, the statement of our lemma easily follows from the following identities: qαi (x, y) = r(h(y, . . . , y, x , y, . . . , y), y, h(y, . . . , y)) and i
h(x) = rn (qα1 (x1 , x1 ), qα2 (x2 , x1 ), . . . , qαn (xn , x1 ), (∆n−1 h)(x1 ), x1 ).
Let QA := {qa ∈ A2 | a ∈ TA }. One can define two operations ⊕, on QA as follows: (qa ⊕ qb )(x, y) := r(qa (x, y), qb (x, y), y) and (qa qb )(x, y) := qa (qb (x, y), y). Because of qa ⊕ qb = qa+b and qa qb = qa·b , one can easily prove that the following holds: Lemma 9.6.3 The algebra (QA ; ⊕, ) is isomorphic to (TA ; +, ·). For arbitrary g, h ∈ A1 and arbitrary α ∈ TA we set now (g ⊕ h)(x) := r(g(x), h(x), x) and (α g)(x) := qa (g(x), x). With the help of the mapping ϕ : A1 −→ NA , ax + b −→ (1 − a, b) one can easily prove the following lemma: Lemma 9.6.4 The left module (A1 ; ⊕, ) and (NA ; +, ·) over TA are isomorph. Theorem 9.6.5 Let A be a subclass of LM with r ∈ A. Then A has only the congruences κ0 , κa , κ1 and such of the type κ(I, U ). Proof. Let κ be a congruence on A with κ = κ1 . By r ∈ A, A is a clone. Therefore, κ ⊆ κa (see Lemma 9.2.1 or Lemma 9.3.5). With the aid of Lemmas 9.6.2 and 9.6.3 (or 9.6.4) one can see that κ determines a congruence µκ (or νκ ) on TA (or NA ), respectively: (qa , qb ) ∈ κ ⇐⇒ (a, b) ∈ µκ (or (ax + b, cx + d) ∈ κ ⇐⇒ ((1 − a, b), (1 − c, d)) ∈ νκ ).
(9.12) (9.13)
Then there is an ideal I of TA and a submodule U of NA with the properties
9.6 Congruences on Some Classes of Linear Functions
(a, b) ∈ µκ ⇐⇒ a − b ∈ I, (u, v) ∈ νκ ⇐⇒ u − v ∈ U.
253
(9.14) (9.15)
To prove (9.11) let a, b ∈ TA , let u = (1 − α, β), v = (1 − γ, δ) ∈ NA with a − b ∈ I and let u − v ∈ U . Then, it holds {(qa , qb ), (αx + β, γx + δ)} ⊆ κ. Consequently, we have (qa (αx + β, x), qb (γx + δ, x)) = ((aα + 1 − a)x + aβ, (bγ + 1 − b)x + bδ) ∈ κ. Therefore, ((1 − (aα + 1 − a), aβ), (1 − (bγ + 1 − b), bδ)) = ((a − aα, aβ), (b − bγ, bδ)) ∈ νκ and thus a · (1 − α, β) − b · (1 − γ, δ)) ∈ U , i.e., (9.11) holds. By Lemma 9.6.2 and (9.12)–(9.15), we have κ = κ(I, U ). Next, we determine a property of the congruences on the closed subset LM ;id := n≥1 {f n ∈ LM | ∃a0 , . . . , an : n f (x) = a0 + i=1 ai xi ∧ a1 + a2 + . . . + an = 1} (a set of so-called idempotent functions) of LM . It is easy to check that LM ;id = LM ∩ P olM {(x, x + 1) | x ∈ M } holds. By Theorem 8.3.2 and with the aid of the bijective mapping α : f n −→ F n−1 from LM ;id := LM ;id \L1M onto LM , where F (x1 , . . . , xn−1 ) := f (0, x1 , . . . , xn−1 ), we can characterize the subclasses of LM ;id and receive as a consequence of Theorem 9.4.5: Theorem 9.6.6 Let A (= ∅) be a subclass of LM ;id , let κ be a congruence on A and let α(κ) be a relation on α(A) defined by (F, G) ∈ α(κ) :⇐⇒ (α−1 F, α−1 G) ∈ κ. Then: (a) α(κ) is a congruence on A; (b) α(κ)/A = κ, i.e., by means of restriction on A one can get the congruences on A from the congruences on α(A). From Theorems 9.6.5 and 9.6.6 some consequences can be drawn (with the aid of known properties of the groups, fields and vector spaces) for the classes from Chapter 13 and from [Sze 80] and [Sza-S 81]. Here only a few examples are given without proof.
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Corollary 9.6.7 (1) Let R = M and let R be a finite field. Then, by [Sze 80], each subclass A of LM with r ∈ A and A ⊆ LM ;id has the form (up to isomorphic) LW ∩P ol V ( = n≥1 {f n | ∃ a0 ∈ V ∃ a1 , . . . , an ∈ W : f (x) = a0 + a1 x1 + . . . + an xn }), where W is a subfield of R and V is a subspace of the vector space R on W . Then, for every nontrivial congruence κ on A there are an I ∈ {{0}, W } and a subspace U of V with the property ∀ α − β ∈ I ∀ a − b ∈ U : a · α − b · β ∈ U, and it holds that κ=
n n + i=1 ai xi , b0 + i=1 bi xi ) | a0 − b0 ∈ U ∧ ∀ i ∈ {1, . . . , n} : ai − bi ∈ I}.
n≥1 {(a0
In particular, κc := {(f, g) ∈ κa | ∃ a ∈ M : f = g + a} is the only nontrivial congruence on LM . (2) Let L be a maximal class of quasi-linear functions of Pk with k = pm , p prime, m ≥ 1. Then κc is the only nontrivial congruence on L (see Section 5.2.4 and [Lau 81]). By Lemma 5.2.4.3, L is isomorphic to a certain set LM , where R is the ring of all m × m–matrices on Ep and M is the vector space of all m × 1–matrices on Ep . (3) Choosing R = M = (Ek ; + mod k, · mod k), so there are only the following arity congruences on LM : n n κs,t := n≥1 {(a0 + i=1 ai xi , b0 + i=1 bi xi ) | s |a0 − b0 ∧ ∀ i ∈ {1, . . . , n} : t | ai − bi }, where s and t are arbitrary divisors of k with s | t. Notice that Con A is not a finite set for every subclass A of LM . If, for example, one finds an element z in R\{0} with z 2 = 0, then the closed set Z := {f n ∈ LM | ∃ a1 , . . . , an ∈ [{0, z}]+ : f (x) = a1 x1 + . . . + an xn } n≥1
has infinite-many congruences. For the purpose of describing of some of these relations, let vare (f ) be the number of the essential variables of f ∈ Z and let
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255
(f n , g n ) ∈ χi :⇐⇒ f = g ∨ (n = m ∧ vare (f ) ≤ i ∧ vare (g) ≤ i) (f, g ∈ Z, i ∈ N). It is easy to check that, for every i ∈ N, the relation χi is a congruence on Z. With the aid of Theorem 9.3.4 and Theorem 9.5.1, |Con Z| = ℵ0 results from that. Finally, we determine all congruences on the subclasses of Lk (see Chapter 13) for k ∈ P. We start with the determining of the congruences on certain subclasses of [Pk1 ] for arbitrary k. The following lemma is easily provable: Lemma 9.6.8 Let C ⊆ {c10 , c11 , ..., c1k−1 }, let G be a subgroup of Sk := (Pk1 [k]; ), whose elements preserve C, let U be a normal subgroup of the group G and let µ be an equivalence relation on C, which is preserved from all functions of G. Then the relation κU,µ on [G ∪ C] defined by f n ∼ g m (κU,µ ) :⇐⇒ n = m ∧ (∃i ∃f , g ∈ C ∪ G : f (x) = f (xi ) ∧ g(x) = g (xi ) ∧ (f U = g U ∨ (f , g ) ∈ µ)) is a congruence on [G ∪ C]. Theorem 9.6.9 Let C ⊆ {c10 , c11 , ..., c1k−1 }, let G be a subgroup of Sk := (Pk1 [k]; ) and let G ⊆ P olk {a | ca ∈ C}. Then, there are except for κ1 and κa only the congruences of the type κU,µ on [C ∪ G], where U is an arbitrary normal subgroup of G and µ is an arbitrary equivalence relation on C, which is preserved from the functions of G. Proof. Let κ be a nontrivial congruence on [C ∪ G]. Because of Lemma 9.2.1, κ ⊆ κa . Discussing the following three cases suffices: Case 1: There exist κ-congruent functions f n and g n with ∆n−1 f ∈ G and ∆n−1 g ∈ C. Then, ∆n−1 f ∼ ∆n−1 g (κ) and thus e11 ∼ c1a := ∆n−1 g (κ). Consequently, we 1 have for every function hm ∈ [C ∪ G]: e11 h = h ∼ cm a = ca h (κ). Hence, κ = κa , in contradiction to the assumption. Case 2: There exist κ-congruent functions f n and g n , which essentially depend on different variables. W.l.o.g. let f (x1 , ..., xn ) = f1 (x1 ), g(x1 , ..., xn ) = g1 (x2 ), {f1 , g1 } ⊆ G and (f, g) ∈ κ. For the inverse functions f1−1 and g1−1 appertaining to the functions f1 and g1 is valid then: f (f1−1 (x1 ), g1−1 (x2 ), x2 , ..., x2 ) = e21 (x1 , x2 )
∼ g(f1−1 (x1 ), g1−1 (x2 ), x2 , ..., x2 ) = e22 (x1 , x2 ) (κ).
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Therefore, for arbitrary m-ary functions s and t ∈ [C ∪ G]: e21 (s(x), t(x)) = s(x) ∼ t(x) = e22 (s(x), t(x)) (κ); i.e., in this case, we have also κ = κa , in contradiction to the assumption. Case 3: Two arbitrary κ-congruent functions of [C ∪ G] are both either constant functions or the functions depend of the same variables essentially. In this case, the congruence κ is uniquely determined by κ/G and κ/C . As is generally known, a congruence of a group G causes a partition of this group in cosets, which can be formed with the aid of a normal subgroup U of this group, i.e., f, g ∈ G are congruent iff f U = g U . Obviously, κ/C is an equivalence relation on C, which is preserved by G. Consequently, we have κ = κU,κ/C . Theorem 9.6.10 Let k ∈ P and let A ⊆ Lk (see Chapter 13). Then there are only finite-many congruences on A. The nontrivial congruences on A are (1) κc , if A ∈ { Lk , Lk ∩ P olk {(x, x + 1) | x ∈ Ek } }, (2) κµ := {(f n , g m ) ∈ A × A | (∆n−1 f, ∆m−1 g) ∈ µ} and κµa := {(f n , g m ) ∈ A × A | n = m ∧ (∆n−1 f, ∆n−1 g) ∈ µ} for each equivalence relation µ on A1 , if A ⊆ [{c0 , c1 , ..., ck−1 }]; (3) congruences of the type κU,µ (see Lemma 9.6.8), if A ⊆ [L1k ] and A ⊆ [{c0 , c1 , ..., ck−1 }]. Proof. Our theorem results from the description of the subclasses of Lk (see Chapter 13) and from Theorems 9.6.5, 9.6.6 and 9.6.9.
9.7 Congruences on the Maximal Classes of Pk The following two lemmas are auxiliary statements to the proof of Theorem 9.7.3, in which all maximal classes are given that have only trivial congruences. Not only do results on the congruences of certain maximal classes follow from Lemma 9.7.1, but also those on further classes (see for example Theorem 9.10.8). The statement (a) of the following lemma was already proven by A. I. Mal’tsev in [Mal 66]. Lemma 9.7.1 For ω, u ∈ Ek and ∈ Mk , where o is the smallest element of Ek in respect to and e is the greatest element of Ek in respect to , let 1 , m1,u and t2ω be functions defined by c1ω,u , qω,u ω if x = ω, u if x = u, cω,u (x) := qω,u (x) := u otherwise, ω otherwise, o if ω if x = ω, x ≤ u, m,u (x) := tω (x, y) := y otherwise. e otherwise,
9.7 Congruences on the Maximal Classes of Pk
257
Furthermore, let A be a subclass of Pk , which fulfills the following two conditions: (a) ∃ω ∈ Ek : ( u∈Ek {cω,u , qω,u }) ∪ {tω } ⊆ A; (b) ∃ ∈ Mk ∃ω ∈ {o , e } : ( u∈Ek {cu , m,u }) ∪ {tω } ⊆ A. Then, A has only trivial arity congruences. Proof. Denote κ an arbitrary congruence on A with κ0 ⊂ κ ⊆ κa . Then there exist two different functions rn , sn ∈ A and a tuple a := (a1 , ..., an ) ∈ Ekn with r(a) = s(a) and (r, s) ∈ κ. First, assume A fulfills (a). We distinguish two cases for A: Case 1: A ⊆ P olk {ω}. Then there is a function f 1 ∈ A with f (ω) := α = ω and we have f cω,ω = cα ∈ A. Thus because of cω,u cα = cu (u ∈ Ek ), all constant functions of Pk belong to A. Consequently, (r, s) ∈ κ implies the κ-congruence of certain constant functions c1a , c1b with a = b and a = ω. Thus we obtain ca = qω,a ca ∼ qω,a cb = cω (κ) and
∀g n ∈ A : tω (ca (x1 ), g(x1 , ..., xn )) = g(x1 , ..., xn ) ∼ tω (cω (x1 ), g(x1 , ..., xn )) = cnω (x1 , ..., xn ) (κ).
(9.16)
Hence κ = κa . Case 2: A ⊆ P olk {ω}. In this case, we obtain r(cω,a1 (x1 ), ..., cω,an (xn )) = cω,a ∼ s(cω,a1 (x1 ), ..., cω,an (xn )) = cω,b (κ), qω,a cω,a = cω,a ∼ qω,a cω,b = cω (κ) and
tω (cω,a (x), x) = x ∼ tω (cω (x), x) = cω (x) (κ).
Hence κ = κa is also valid in Case 2. Finally, assume A fulfills the condition (b) for a certain ∈ Mk . Since the constant functions belong to A, (r, s) ∈ κ implies (c1a , c1b ) ∈ κ for certain a = b. If b = ω ∈ {o , e }, one obtains κ = κa by means of (9.16). Then one can reduce the remaining cases to the case already handled through m,α ca ∼ m,α cb (κ) with suitably chosen α. Lemma 9.7.2 Let s ∈ Sk and let κ be a congruence on P olk s . If there are certain κ-congruent functions f n , g n ∈ P olk s with f = g, then κa ⊆ κ. Proof. Define the relation s as in Section 5.2.2. Then the functions f , g have representations of the form (5.4) (see Chapter 5). Since f = g, we can assume
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w.l.o.g. that F1 = G1 holds for the components F1 , G1 , i.e., there exists an (n − 1)-tuple a := (a2 , ..., an ) with F1 (a) =: c = d := G1 (a). Let qa (x) :=
p−1 l
jar,i (x) · si (a),
r=1 i=0
u(x) :=
p−1 l
jar,i (x) · si (a1,i )
r=1 i=0
and h(x1 , ..., xm+1 ) :=
p−1 l
jar,i (xi ) · si (Hr (sp−i (x2 ), ..., sp−i (xm+1 ))),
r=1 i=0
where Hr (c, x1 , ..., xm ) = H1,r (x1 , ..., xm ), Hr (d, x1 , ..., xm ) = H2,r (x1 , ..., xm ), r = 1, 2, ..., l, and H1,1 , H1,1 , ..., H1,l , H2,1 , ..., H2,l are arbitrary functions of Pk . Since (f, g) ∈ κ, we have f (u(x), qa2 (x), ..., qan )) = qc (x) ∼ g(u(x), qa2 (x), ..., qan )) = qd (x) (κ) so that h(x1 , qc (x1 ), x2 , ..., xm ) = l p−1 i p−i (x2 ), ..., sp−i (xm ))) r=1 i=0 jr,i (x1 ) · s (H1,r (s ∼ h(x1 , qd (x1 ), x2 , ..., xm ) = l p−1 i p−i (x2 ), ..., sp−i (xm ))) (κ). r=1 i=0 jr,i (x1 ) · s (H2,r (s Therefore κ = κa . Theorem 9.7.3 ([Mal 66], [Kol 74], [Lau 79a;81]) Let ∈ (Ck \{ ∈ C1k | || ≥ 2}) ∪ Mk ∪ Sk . Then, the maximal class P olk has only trivial congruences. Proof. Because of Lemma 9.2.1, every nontrivial congruence of a maximal class is an arity congruence. With that, our theorem results for ∈ Ck \{ ∈ C1k | || ≥ 2} from Lemma 9.7.1, when one chooses ω as a central element of and one proves that A := P olk fulfills the condition (a) of Lemma 9.7.1. If ∈ Mk then our assertion also results of Lemma 9.7.1, since P olk fulfills the condition (b) of Lemma 9.7.1. If ∈ Sk then we obtain |Con P olk | = 3 from Lemma 9.7.2. Subsequently, we will prove that, in Theorem 9.7.4, all maximal classes with only trivial congruences were determined. We begin with determining the congruences on the remaining maximal classes of the type C.
9.7 Congruences on the Maximal Classes of Pk
259
Theorem 9.7.4 Let be a unary relation on Ek with 2 ≤ || ≤ k − 1. Then the equivalence relation κ0, defined by f n ∼ g m (κ0, ) ⇐⇒ n = m ∧ {f, g} ⊂ P olk ∧ ( ∀x ∈ n : f (x) = g(x) ), is the only nontrivial congruence on P olk . Proof. W.l.o.g. let := El , where 2 ≤ l ≤ k − 1. Since A := P olk El is a clone, the nontrivial congruences on A are arity congruences. Let κ ∈ Cona A\{κ0 }. Then the following two cases are possible: Case 1: κ0 ⊂ κ ⊆ κ0,El . Then there exist κ-congruent functions f n , g n ∈ P olk El , which are identical on tuples of Eln and which have different values on a certain tuple a := (a1 , a2 , ..., an ) ∈ Ekn \Eln . Elements of P olk El are certain unary functions pa,b with pa,b (a) = b, a ∈ Ek \El , b ∈ Ek . Also elements of P olk El are the functions cai (x) if ai ∈ El , hi (x) := pa,ai (x) if ai ∈ Ek \El (i = 1, 2, ..., n; a ∈ Ek \El ). Consequently, it holds fa (x) := f (h1 (x), ..., hn (x)) ∼ ga (x) := g(h1 (x), ..., hn (x)) (κ), where fa (a) = ga (a) for all a ∈ Ek \El . For arbitrary κ0,El -congruent functions rm and sm of P olk El , there exists an (m + (k − l) · m)-ary function t with t(x1 , ..., xm , fl (x1 ), fl+1 (x1 ), ..., fk−1 (x1 ), ..., fl (xm ), fl+1 (xm ), ..., fk−1 (xm )) = r(x1 , ..., xm ) and t(x1 , ..., xm , gl (x1 ), gl+1 (x1 ), ..., gk−1 (x1 ), ..., gl (xm ), gl+1 (xm ), ..., gk−1 (xm )) = s(x1 , ..., xm ). Consequently, we have (r, s) ∈ κ and hence κ = κ0,El . Case 2: κ ⊆ κ0,El and κ ⊆ κa . In this case, there are certain κ-congruent functions that have different values on a certain tuple of Eln . It is easy to show that this implies two different constants ca and cb of P olk El are κ-congruent. Further, for arbitrary m-ary functions u and v of P olk El one can find an (m + 1)-ary function w ∈ P olk El , for which w(x1 , ..., xm , a) = u(x1 , ..., xm ) and w(x1 , ..., xm , b) = v(x1 , ..., xm ) hold. Consequently, we have u(x) = w(x, ca (x1 )) ∼ v(x) = w(x, cb (x1 )) (κ), i.e., κ = κa holds. Thus P olk El has only four different congruences.
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Theorem 9.7.5 Let ∈ Uk and let Z := {ε1 , ..., εr } be the set of all equivalence classes of the equivalence relation . Then P olk has exactly four different congruences. The only nontrivial congruence on P olk is the congruence κZ defined by f n ∼ g m κZ :⇐⇒ n = m ∧ {f, g} ⊂ P olk ∧ (∀a ∈ Ekn ∃i ∈ {1, 2, ..., r} : {f (a), g(a)} ⊆ εi ). Proof. Denote κ be an arbitrary nontrivial congruence on P olk . Then, by Lemma 9.2.1, κ0 ⊂ κ ⊆ κa . Our theorem is proven if we can show the following facts: (∃f n , g n ∈ P olk ∃a ∈ Ekn : (f, g) ∈ κ ∧ (f (a), g(a)) ∈ \ι2k ) =⇒ κZ ⊆ κ, (∃f n , g n ∈ P olk ∃a ∈ Ekn : (f, g) ∈ κ ∧ (f (a), g(a)) ∈ ) =⇒ κ = κa . (9.17) If two different functions f n , g n of P olk are κ-congruent, then it is easy to see that two different constant functions ca , cb are also κ-congruent. For these constant functions, the following two cases are possible: Case 1: (a, b) ∈ \ι2k . Denote s and t two arbitrary m-ary functions of P olk with the property ∀a ∈ Ekm ∃i ∈ {1, 2, ..., r} : {s(a), t(a)} ⊆ ε. The following (m + 1)-ary function h with s(x1 , ..., xm ) if xm+1 = a, h(x1 , ..., xm+1 ) := t(x1 , ..., xm ) otherwise belongs to P olk . Thus h(x1 , ..., xm , ca (x1 )) = s(x) ∼ t(x) = h(x1 , ..., xm , cb (x1 )) (κ)
(9.18)
is valid. Hence, κZ ⊆ κ. Case 2: (a, b) ∈ . In this case, let s and t be two arbitrary m-ary functions of P olk . Then, a certain (m + 1)-ary function h with h(x1 , ..., xm , a) = s(x1 , ..., xm ) and h(x1 , ..., xm , b) = t(x1 , ..., xm ) belongs to P olk . Consequently, we obtain (s, t) ∈ κ as in (9.18). Thus κ = κa and (9.17) hold. The following theorem was already proven in Section 9.6 (see Corollary 9.6.7, (2).):
9.7 Congruences on the Maximal Classes of Pk
261
Theorem 9.7.6 Let k be a prime number power and λ ∈ Lk . Then {(f n , g n ) | ∃a ∈ Ek : f (x) = g(x) + a} κc := n≥1
is the only nontrivial congruence on P olk λ. Finally, denote an h-ary relation on Ek , which is a homomorphic inverse image of an elementary h-ary relation ξm ⊆ Ehm (h ≥ 3, m ≥ 1, k ≥ hm ). We use the same notations and representations for the functions of P olk as in Section 5.2.6. In addition, one can use Lemma 5.2.6.1 to define the following equivalence relation κN on P olk : Definition Let N be a normal subgroup of the symmetric group (Sh ; ). For arbitrary f n , g m ∈ P olk let (f n , g m ) ∈ κN if and only if n = m and for each i ∈ Em at least one of the following conditions is fulfilled: (a) |Im(fi )| ≤ h − 1 and |Im(gi )| ≤ h − 1; (b) there exist s1 , s2 ∈ Sh , j ∈ {1, 2, ..., n} and t ∈ Em so that fi (x1 , ..., xn ) = s1 ((q(xj ))(t) ), gi (x1 , ..., xn ) = s2 ((q(xj ))(t) ) and s1 N = s2 N. Lemma 9.7.7 The above-defined equivalence relation κN is a congruence on P olk . Proof. Let (f n , g n ), (rm , sm ) ∈ κN be arbitrary. Obviously, (αf, αg) ∈ κN holds for every α ∈ {ζ, τ, ∆, ∇}. It remains to show that u := f s ∼ g t =: v (κN ), i.e., ui = fi r and vi := gi s satisfy (a) or (b) from the definition of κN for each i ∈ Em . By Lemma 5.2.6.1 the following cases are possible: Case 1: |Im(fi )| ≤ h − 1 and |Im(gi )| ≤ h − 1. Then |Im(ui )| ≤ h − 1 and |Im(vi )| ≤ h − 1, i.e., (a) is satisfied. Case 2: fi (x1 , ..., xn ) = s1 ((q(xj ))(t) ), gi (x1 , ..., xn ) = s2 ((q(xj ))(t) ), where s1 , s2 ∈ Sh , s1 N = s2 N , j ∈ {1, 2, ..., n} and t ∈ Em . Case 2.1: j = 1. Then ui (x1 , ..., xn+m−1 ) = s1 ((q(xj+m−1 ))(t) ) and vi (x1 , ..., xm+n−1 ) = s2 ((q(xj+m−1 ))(t) ), i.e., (b) is satisfied. Case 2.2: j = 1. Then ui (x1 , ..., xm+n−1 ) = s1 (rt (x1 , ..., xm ) and vi (x1 , ..., xm+n−1 ) = s2 (st (x1 , ..., xm )). Case 2.2.1: |Im(rt )| ≤ h − 1 and |Im(st )| ≤ h − 1. Then |Im(ut )| ≤ h − 1 and |Im(vt )| ≤ h − 1, i.e., (a) is satisfied. Case 2.2.2: rt (x1 , ..., xm ) = s3 ((q(xl ))(p) , st (x1 , ..., xm ) = s4 ((q(xl ))(p) , {s3 , s4 } ∈ Sh , s3 N = s4 N , l ∈ {1, 2, ..., m} and p ∈ Em . Then we have ui (x1 , ..., xm+n−1 ) = s1 (s3 (q(xl ))(p) )) and vi (x1 , ..., xm+n−1 ) =
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s2 (s4 (q(xl ))(p) )). Moreover, from the assumptions and from the well-known properties of normal subgroups we know that (s1 s3 ) N = (s1 (s3 N ) = (s1 (s4 N ) = s1 (N s4 ) = (s1 N ) s4 = (s2 N ) s4 = (s2 s4 ) N. Hence (b) is satisfied. Lemma 9.7.8 Let κ be a congruence on P olk and let e denote the unit of the symmetric group Sh . Then κ0 ⊂ κ ⊆ κa =⇒ κ{e} ⊆ κ. Proof. Let κ0 ⊂ κ ⊆ κa . Clearly, T := {f ∈ Pk | |Im(q(f ))| ≤ h − 1} ⊆ P olk . It is easy to see that we have only trivial congruences on T . From κ ⊂ κ ⊆ κa we get the existence of two different unary constants that are κ-congruent. Consequently, all functions of the same arity of T are mutually κ-congruent. Then, with the help of Section 5.2.6, we have κ{e} ⊆ κ. Lemma 9.7.9 Let κ be a congruence on P olk , let N be a normal subgroup of the symmetric group Sh and let κN ⊂ κ ⊆ κSh . Then there exists a normal subgroup N of Sh with N ⊂ N ⊆ Sh so that κN ⊆ κ. Proof. W.l.o.g. we can assume that = ξm , i.e., k = hm and q is the identity mapping. Because of κN ⊂ κ ⊆ κSh there exist certain κ-congruent n-ary functions f , g with (t) (t) fi (x1 , ..., xn ) = s1 (xj ), gi (x1 , ..., xn ) = s2 (xj ) for certain i, t ∈ Em , j ∈ {1, 2, ..., n} and s1 , s2 ∈ Sh with s1 N = s2 N . The functions u(x) := x(i) and v(x) := x(0) ·ht belong to P olξm . Consequently, since (f, g) ∈ κ, we have: ((∆n−1 (u f )) v)(x) = s1 (x(0) ) ∼ ((∆n−1 (u g)) v)(x) = s2 (x(0) ) (κ).
(9.19)
It is well-known that the symmetric group Sh has only congruences of type κN , where N is a normal subgroup of Sh . Therefore (9.19) together with s1 N = s2 N imply the existence of a normal subgroup N so that N ⊂ N ⊆ Sh and ∀s, s ∈ Sh : (s N = s N =⇒ s(x(0) ) ∼ s (x(0) ) (κ) ). Then, by replacing the variable x by the function x(t) ∈ P ol ξm and with the aid of the operations ∇, ζ, τ , we get: (t)
(t)
s N = s N =⇒ a(x1 , ..., xr ) := s(xj ) ∼ s (xj ) =: b(x1 , ..., xr ) (κ) for every r ≥ 1, j ∈ {1, 2, ..., r}, t ∈ Em and s, s ∈ Sh . Hence κN ⊆ κ.
9.7 Congruences on the Maximal Classes of Pk
263
Lemma 9.7.10 Let κ be a congruence on P olk with the properties κ ⊆ κSh and κ ⊆ κa . Then κ = κa . Proof. W.l.o.g. let = ξm . Since κ ⊆ κSh and κ ⊆ κa , there exist κcongruent functions f n , g n with (f, g) ∈ κSh , i.e., there exists an i ∈ Em with (fi , gi ) ∈ κSh . We distinguish the following cases: Case 1: |Im(fi )| ≤ h − 1 and |Im(gi )| = h. Then by Lemma 9.7.8 we have (fi , cna ) ∈ κ for every a ∈ Ek . Hence gi (x, ..., x) =: s1 (x(t) ) ∼ ca (x) (κ) and (r) · ht )(t) ))) = s2 (x(r) ) s2 (s1 (s−1 1 ((x (r) ∼ ca (s1 (s−1 · ht )(t) ))) = ca (x) (κ) 1 ((x
for every s2 ∈ Sh , r ∈ Em and a ∈ Ek . Using the operations ∇, τ , ζ we get ∀s ∈ Sh ∀j ∈ {1, ..., n} ∀t ∈ Em ∀a ∈ Ek : (t)
p(x1 , ..., xn ) := s(xj ) ∼ cna (x1 , ..., xn ) (κ).
(9.20)
Moreover, since all n-ary functions f with |Im(f )| ≤ h − 1 are mutually κcongruent, κ = κa follows from (9.20) in the first case. (t) (t) Case 2: fi (x1 , ..., xn ) = s1 (xj ), gi (x1 , ..., xn ) = s2 (xl ) and (j, t) = (l, r) (j, l ∈ {1, 2, ..., n}; s1 , s2 ∈ Sh ; t, r ∈ Em ). Case 2.1: j = l. Then, because of (fi , gi ) ∈ κ, fi (x, ..., x, c0 (x), x, ..., x) = s1 (x(t) ) l−1
∼ fi (x, ..., x, c0 (x), x, ..., x) = cs2 (0) (x) (κ) l−1
and thus by Case 1: κ = κa . Case 2.2: t = r. Since (fi , gi ) ∈ κ, we have (s1 (x(t) ), s2 (x(r) )) ∈ κ. Therefore s1 ((x(0) · ht )(t) ) = s1 (x(0) ) ∼ s2 ((x(0) · hr )(t) ) = cs2 (0) (x) (κ). Hence, again by Case 1, κ = κa .
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9 Congruences and Automorphisms on Function Algebras
Theorem 9.7.11 Let V be the four group in S4 and let Ah be the alternating group of Sh . Furthermore, let e be the unit of Sh . For h = 3 and h ≥ 5 the maximal class P olk with ∈ Bhk has only the nontrivial congruences κ{e} , κAh and κSh . A maximal class P olk with ∈ B4k has the nontrivial congruences κ{e} , κA4 , κS4 and, in addition, the nontrivial congruence κV on P olk . Proof. Our claim follows from Lemmas 9.7.7–9.7.10 and from well-known theorems in group theory.
κ1 κa if ∈ Ck \{ ∈ C1k | || ≥ 2} ∪ Mk ∪ Sk κ0
κa κ0,
κ1
κ1
κ1 if ∈ { ∈ C1k | || ≥ 2}
κa κZ
κ0
κ0
κ1
κ1
κa
κa
κa κc
if ∈ Lk
κ0
κS4
κSh κAh if ∈
if ∈ Uk
k
h=3,h =4
Bhk
κA4 if ∈ B4k
κ{e}
κV
κ0
κ{e} κ0
Fig. 9.2. Congruence lattices of the maximal classes P olk of Pk
9.8 Congruences on Subclasses of [Pk1 ]
265
When one summarizes the above Theorems 9.7.3–9.7.6 and 9.7.11, one sees that Theorem 9.7.12 (Congruence Theorem for Maximal Clones; [Lau 79a;81]) For a maximal class A := P olk , ∈ Rmax (Pk ) (see Chapter 5 and 6) of Pk it holds |Con A| ∈ {3, 4, 6, 7} and |Con A| = 3 ⇐⇒ ∈ (Ck \{ ∈ C1k | || ≥ 2}) ∪ Mk ∪ Sk |Con A| = 4 ⇐⇒ ∈ { ∈ C1k | || ≥ 2} ∪ Uk ∪ Lk k |Con A| = 6 ⇐⇒ ∈ h=3, h=4 Bhk |Con A| = 7 ⇐⇒ ∈ B4k . The possible congruence lattices of a maximal class P olk of Pk are given in Figure 9.2.
9.8 Congruences on Subclasses of [Pk1 ] In this section, we describe the unary functions f ∈ Pk as follows: Let κf := {(a, b) ∈ Ek2 | f (a) = f (b)}
(9.21)
be the mapping equivalence of f . Denote F1 , ..., Fr the equivalence classes of this equivalence relation. Then there are some a1 , ..., ar ∈ Ek with ∀i ∈ {1, 2, ..., r} : ∀x ∈ Fi : f (x) = ai , and we write:
f=
F1 F2 ... Fr a1 a2 ... ar
.
Before we consider some general properties of the congruences on subclasses of [Pk1 ], we deal first with the congruences of the semigroup (Pk1 ; ). We will see later that these congruences induce the congruences on the class [Pk1 ] (see Theorem 9.8.4). Definition
Let r ∈ {2, 3, ..., k} and
µr (k) := {(f, g) ∈ Pk1 × Pk1 | f = g ∨ (|Im(f )| < r ∧ |Im(g)| < r }. (9.22) Furthermore, let N be a normal subgroup of the symmetric group S{1,2,...,r} . For arbitrary f, g ∈ Pk1 let (f, g) ∈ µr,N (k) if and only if the functions f and g fulfill the following conditions:
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9 Congruences and Automorphisms on Function Algebras
(1) (f, g) ∈ µr (k). (2) |Im(f )| = |Im(g)| = r and f , g are defined by F1 F2 ... Fr F1 F2 ... Fr f= ,g= , a1 a2 ... ar ai1 ai2 ... air where
1 2 ... r i1 i2 ... ir
∈N
holds. If k results from the context, we only write µr (or µr,N ) instead of µr (k) (or µr,N (k)). We remark that µr = µr,{e} holds, where e is the unit of the group S{1,2,...,r} . Lemma 9.8.1 The above-defined relation µr,N (k) is a congruence on the semigroup (Pk1 ; ). Proof. With the help of the group properties of N one can see that µr,N is an equivalence relation. To prove the compatibility of µr,N with , it suffices to prove the statement ∀(f, g) ∈ µr,N ∀h ∈ Pk1 : (h f, h g) ∈ µr,N ∧ (f h, g h) ∈ µr,N (9.23) (see Lemma 9.1.1). If (f, g) ∈ µr or |Im(h)| < r, then (9.23) is obviously valid. Let (f, g) ∈ µr,N \µr and |Im(h)| ≥ r in the following. Consequently, we can assume F1 F2 ... Fr F1 F2 ... Fr 1 2 ... r f= ,g= , ∈ N. a1 a2 ... ar ai1 ai2 ... air i1 i2 ... ir If bi := h(ai ), i = 1, 2, ..., r, then F1 F2 ... Fr F1 F2 ... Fr and h g = . hf = b1 b2 ... br bi1 bi2 ... bir Thus (h f, h g) ∈ µr,N . Let Hi := {x ∈ Ek | f (h(x)) = ai }, i = 1, 2, ..., r. If there exists i with Hi = ∅, then we have (f h, g h) ∈ µr . If Hi = ∅ for all i, then H1 H2 ... Hr H1 H2 ... Hr and g h = , f h= a1 a2 ... ar ai1 ai2 ... air whereby (f h, g h) ∈ µr,N holds.
9.8 Congruences on Subclasses of [Pk1 ]
267
The next lemma gives some properties of congruences of (Pk1 ; ) that we need, to prove Theorem 9.8.3. Lemma 9.8.2 Let κ be a congruence of the semigroup (Pk1 ; ). Then: (a) κ = κ0 =⇒ (∀a, b ∈ Ek : (ca , cb ) ∈ κ); (b) ( (f, ca ) ∈ κ ∧ |Im(f )| ≥ 2 ) =⇒ µ|Im(f )|+1 ⊆ κ; (c) ( (f, g) ∈ κ ∧ |Im(f )| > |Im(g)| ) =⇒ µ|Im(f )|+1 ⊆ κ; (d) ( (f, g) ∈ κ ∧ |Im(f )| = |Im(g)| ≥ 2 ∧ Im(f ) = Im(g) ) µ|Im(f )|+1 ⊆ κ; (e) ( (f, g) ∈ κ ∧ Im(f ) = Im(g) ∧ κf = κg ) =⇒ µ|Im(f )|+1 ⊆ κ;
=⇒
3
(f ) ( (f, g) ∈ κ ∧ Im(f ) = Im(g) ≥ 2 ∧ κf = κg ∧f = g ) =⇒ µ|Im(f )| ⊆ κ; Proof. (a) and (b) are easy to check. (c): Let (f, g) ∈ κ and |Im(f )| > |Im(g)|. If |Im(g)| = 1, (c) follows from (b). Therefore we can assume |Im(g)| ≥ 2. In addition, consider only the case Im(g) ⊂ Im(f ) suffices, since one can find an h ∈ Pk1 with h f = f , h g =: g and Im(f ) ⊂ Im(g ). Therefore, let Im(g) = {a1 , ..., au } and Im(f ) = {a1 , ..., au , ..., ar }. Then, with the help of the functions x ∈ {au+1 , ..., ar }, au+1 if p(x) := x otherwise and
tj (x) :=
we obtain
a1 if x ∈ {a1 , ..., aj }, x otherwise,
fu+1 := p f ∼ p g = g (κ) fu+2−j := tj fu+1 ∼ tj g =: gu+1−j (κ),
for j = 2, 3, ..., u, where the indices of the functions agree with the cardinalities of their ranges of values. We can rewrite the above as follows: g1 ∼ f2 , g2 ∼ f3 , g3 ∼ f4 , ... gu ∼ fu+1 , fu+1 ∼ f (κ). This, (b) and the transitivity of κ imply our assertion (c). (d): Let a ∈ Im(g), b ∈ Im(g)\Im(f ) and a if x = b, q(x) := x otherwise. Then (f, g) ∈ κ implies q f = f ∼ q g =: g (κ), where |Im(g )| < |Im(f )|. Thus, (d) follows from (c). (e): If Im(f ) = Im(g) and κf = κg , there exist a, b ∈ Ek with (a, b) ∈ κf and (a, b) ∈ κg . Then, with the help of the above defined function q, we have 3
κf , κg denote the mapping equivalences of f or g, respectively (see (9.21)).
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9 Congruences and Automorphisms on Function Algebras
f q = f ∼ g q =: g (κ) with |Im(g )| < |Im(f )|. Hence (e) follows from (c). (f): Let (f, g) ∈ κ, f = g, r ≥ 2 and F1 F2 ... Fr Fi1 Fi2 ... Fir f= and g = , a1 a2 ... ar a1 a2 ... ar 1 2 ... r where denotes a certain permutation. If r = 2 then (f) follows i1 i2 ... ir from that because of (a). If r > 2 then there exist indices u, v with {u, v} = {iu , iv } so that Fu ∪ Fv = Fiu ∪ Fiv holds. Then, with the help of the function au if x ∈ {au , av }, w(x) := x otherwise. and through f1 := w f ∼ w g =: g1 (κ), one gets that two functions f1 , g1 are κ-congruent, where |Im(f1 )| = |Im(g1 )| = r − 1 and the mapping equivalences κf1 and κg1 are different. Consequently, (f) follows from (e). Theorem 9.8.3 (A. I. Mal’tsev’s Theorem; [Mal 52]) (a) The only nontrivial congruences on (Pk1 ; ) are congruences of the form κr,N , where r ∈ {2, 3, ..., k} and N is an arbitrary normal subgroup of the symmetric group S{1,2,...,r} . (b) Let Sr be the group of all permutations on the set {1, 2, ..., r}, and let Ar (⊂ Sr , r ≥ 2) be the alternating group and let V (⊂ S4 ) be the four group. Furthermore, denote Con(k) the set of all congruences of the semigroup (Pk1 ; ). Then: Con(2) = {κ0 , µ2 , µ2,S2 , κ1 }; Con(3) = {κ0 , µ2 , µ2,S2 , µ3 , µ3,A3 , µ3,S3 , κ1 }; Con(4) = {κ0 , µ2 , µ2,S2 , µ3 , µ3,A3 , µ3,S3 , µ4 , µ4,V , µ4,A4 , µ3,S4 , κ1 }; Con(k) = {κ0 , µ2 , µ2,S2 , µ4,V , κ1 } ∪ r∈{3,4,5,...,k} {µr , µr,Ar , µr,Sr } for k ≥ 5. Proof. (a): Let κ (= κ0 ) be a congruence of the semigroup (Pk1 ; ). Then, by Lemma 9.8.2, (b)–(f), we have an r ∈ {2, ..., k − 1} with µr ⊆ κ ⊂ µr+1 . To prove that a normal subgroup N with κ = µr,N exists, we consider the functions F1 F2 ... Fr F1 F2 ... Fr f := f := a1 a2 ... ar aα(1) aα(2) ... aα(r) F1 F2 ... Fr F1 F2 ... Fr g := g := b1 b2 ... br bβ(1) bβ(2) ... bβ(r) of Pk1 . Further, let
h1 (x) :=
9.8 Congruences on Subclasses of [Pk1 ]
bi if ∃i : x = ai , h2 (x) := x otherwise,
269
aγ(i) if ∃i : x = ai , x otherwise,
where γ is an arbitrary permutation from Sr . Now, let F1 , ..., Fr be a partition of Ek and let N be the set of all permutations α ∈ Sr for which (f, f ) ∈ κ holds. If α, β ∈ N , then we have (f, f ), (g, g ) ∈ κ and therefore also g = h1 f ∼ h1 f (κ) and (because of transitivity) h1 f ∼ g (κ); thus, according to the definition of N the following is valid: α(1) α(2) ... α(r) = β α−1 ∈ N. β(1) β(2) ... β(r) Therefore N is a group. The fact that N is a normal group results from (f, f ) ∈ κ =⇒ h2 f ∼ h2 f (κ) γ(1) ... γ(r) =⇒ = γ α γ −1 ∈ N. γ(α(1)) ... γ(α(r)) For another partition Q1 , ..., Qr of Ek and for arbitrary functions Q1 Q2 ... Qr Q1 Q2 ... Qr g := , q := d1 d2 ... dr dδ(1) dδ(2) ... dδ(r) with δ ∈ Sr we must still show that (q, q ) ∈ κ if and only if δ ∈ N . If (q, q ) ∈ κ then δ ∈ N follows from (q h3 , q h3 ) ∈ κ, where h3 (Fi ) ∈ Qi (i = 1, ..., r). If δ ∈ N then there are κ-congruent functions h and h with F1 F2 ... Fr F1 F2 ... Fr h := , h := d1 d2 ... dr dδ(1) dδ(2) ... dδ(r) and (q, q ) ∈ κ follows from (h h4 , h h4 ) ∈ κ, where h4 (Qi ) ∈ Fi (i = 1, 2, ..., r). (b) follows from well-known results over the normal subgroups of the symmetric group. The following concept comes from the paper [Mal 76] by I. A. Mal’tsev. Definitions Let A be a subclass of [Pk1 ], which contains a certain constant ca . Furthermore, let α be a congruence on the semigroup (A1 ; ). Then, the α-induced relation κα is defined as follows: For arbitrary (f n , g m ) ∈ A × A let (f n , g m ) ∈ κα iff n = m and the functions f and g fulfill one of the two following conditions: (1) (∆n−1 f, ca ) ∈ α (or (∆n−1 g, ca ) ∈ α); (2) ∃i ∈ {1, ..., n} ∃f1 , g1 ∈ A1 : ( f (x1 , ..., xn ) = f1 (xi ) ∧ g(x1 , ..., xn ) = g1 (xi ) ∧ (f1 , g1 ) ∈ α ). We say that the congruence κ on A is induced from the congruence α on Pk1 iff κ = κα . The following theorem is a special case of Theorem 9.8.8:
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9 Congruences and Automorphisms on Function Algebras
Theorem 9.8.4 ([Mal 76]) Let ca ∈ A = [A] ⊆ [Pk1 ]. Then (a) Each relation, induced from a congruence on the semigroup (A1 ; ), is a congruence on A. (b) All nontrivial arity congruences on A are given from the nontrivial congruences on A1 . The next theorem is a consequence from the above theorem and Theorem 9.8.3: Theorem 9.8.5 ([Mal 76]) On [Pk1 ] there are exactly
⎧ if k = 2, ⎨5 8 if k = 3, ⎩ 3 · k if k ≥ 4
different congruences. The nontrivial congruences on [Pk1 ] are induced from the congruences of the type µr,N (k) (see Lemma 9.8.1) on Pk1 . The rest of this section is the summary of an unpublished manuscript by B. Strauch. Definition and Declarations Let H be a subsemigroup of (Pk1 ; ) and let µ be a congruence on H. Further, let {H1 , ..., Hl } be the partition correlated to the relation µ, where the indexes of the blocks Hi are so chosen that the following is valid:
and
∀i ∈ {1, 2, ..., s} ∀h ∈ H : Hi h ⊆ Hi
(9.24)
∀i ∈ {s + 1, ..., l} ∃h ∈ H : Hi h ⊆ Hi .
(9.25)
We set s = 0 if there is not any block with the property (9.24). For functions f n ∈ [Pk1 ], we also write f instead of ∆n−1 f and put ess(f ) := i, if f (x1 , ..., xn ) = f (xi ) with f ∈ Pk1 [1]. If f n is a constant, then let ess(f ) := 0. With the help of µ, one can define the following relations on [H]:
9.8 Congruences on Subclasses of [Pk1 ]
271
αµ := µ ∪ {(f n , g m ) ∈ [H] × [H] | n = m ∧ (f , g ) ∈ µ ∧ (ess(f ) = ess(g) ∨ ∃i ∈ {1, ..., s} : {f , g } ⊆ Hi ) }, βµ := µ ∪ {(f n , g m ) ∈ [H] × [H] | n = m ∧ (f , g ) ∈ µ ∧ ess(f ) = ess(g)}, γµ := {(f n , g m ) ∈ [H] × [H] | n = m ∧ (f , g ) ∈ µ }. Lemma 9.8.6 Let H and µ be defined as above. Then (a) ∀f ∈ Hs+1 ∪ ... ∪ Hl : ∀g ∈ H1 ∪ ... ∪ Hs : f g ∈ H1 ∪ ... ∪ Hs ; (b) (∃t ∈ {1, ..., l} ∃a ∈ Ek : ca ∈ Ht ) =⇒ t ∈ {1, 2, ..., s}. Proof. (a): Let f and g be given as in (a) and let (q, f g) ∈ µ. (a) is proven if we can show ∀h ∈ H : (q h, q) ∈ µ. (9.26) (9.26) results, however, from q h ∼ f (g h) ∼ f g ∼ q (µ) because of g ∈ H1 ∪ ... ∪ Hs . (b): If {ca , f } ⊆ Hi then for every h ∈ H: ca h = ca ∼ f h (µ). Therefore, f h ∈ Hi and thus i ∈ {1, 2, ..., s}. Lemma 9.8.7 Let H and µ be defined as above. Then (a) αµ is a congruence on [H] with α|H = µ. (b) βµ is a congruence on [H] with β|H = µ, iff H does not contain any constant function or the blocks H1 , ..., Hs of µ consist only of constant functions. (c) αµ = βµ iff s = 0 or the blocks H1 , ..., Hs of µ consist only of constant functions. (d) γµ is a congruence on [H] with γ|H = µ, iff s = l holds, i.e., iff every block Hi of µ fulfills the condition (9.24). Proof. (a): We start with proof that αµ is an equivalence relation on [H]. The reflexivity and the symmetry of αµ result immediately from the definition of αµ . One can prove the transitivity of αµ as follows: Let (f n , g n ), (g n , hn ) ∈ αµ be arbitrary. Then (f , g ), (g , h ) ∈ µ and (by the transitivity of µ) (f , h ) ∈ µ. In the case ess(f ) = ess(g) = ess(h) we have (f, h) ∈ αµ . Otherwise, we have s ≥ 1 and there exists an i ∈ {1, ..., s} with {f , g } ⊆ Hi or {g , h } ⊆ Hi . As already was proven, the functions f , g , h are µ-equivalent. Therefore {f , g , h } ⊆ Hi and thus (f n , hn ) ∈ αµ . Next we show the compatibility of αµ with the superposition operations. For the unary operations, this is clear. Let (f, g) ∈ αµ and t ∈ [H] be arbitrary. To prove the compatibility of αµ with , it is sufficient to show that (tf, tg), (f t, g t) ∈ αµ holds. One can check (f t, g t) ∈ αµ easily by defining αµ . If t is a constant function or ess(t) ≥ 2 holds, then also (t f, t g) ∈ αµ . Therefore, we can assume ess(t) = 1. Then (t f ) = t f ∼ (t g) = t g (µ). If ess(f ) = ess(g) then also ess(t f ) = ess(t g). This implies (t f, t g) ∈ αµ . In the case ess(f ) = ess(g), there is an i ∈ {1, ..., s} with {f , g } ⊆ Hi .
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9 Congruences and Automorphisms on Function Algebras
Let Hr be the block to which the functions t f and t g belong. Then, r ≤ s and thus (t f, t g) ∈ αµ follows from the following: Let q ∈ Hr and h ∈ H be arbitrary. Because of {q, t f } ⊆ Hr and {f h, f } ⊆ Hi it holds: q h ∼ (t f ) h = t (f h) ∼ t f ∼ q (µ). Consequently, we have Hr h ⊆ Hr for arbitrary h ∈ H. Hence, αµ is a congruence on [H]. One checks the remaining statements of the lemma by means of Lemmas 9.8.6 and 9.3.8. Theorem 9.8.8 Let H := (H; ) be a semigroup with H ⊆ Pk1 . Then, one can describe the congruences on [H] as follows: (1) αµ with µ ∈ Con H; (2) βµ with µ ∈ Con H, if H does not contain any constant function or the equivalence classes of µ, which (9.24) fulfills, consist only of constant functions; (3) γµ with µ ∈ Con H and every equivalence class of µ fulfills the condition (9.24). Proof. First, let κ be an arbitrary arity congruence on [H] and let µ := κ ∩ (H × H). Obviously, µ is a congruence of the semigroup (H; ) and we have (by the compatibility of κ with the operations ∇, ζ, τ ) βµ ⊆ κ. If βµ = κ, then, by Lemma 9.8.7, µ and H fulfill the conditions given in (2). Therefore, let βµ ⊂ κ. Then there are some κ-congruent functions f n , g n with f (x1 , ..., xn ) = f (xi ), g(x1 , ..., xn ) = g (xj ) and i < j. Consequently, it holds f1 (x, y) := f (x, ..., x, y, y, ..., y) = f (x) ∼ i
g1 (x, y) := g(x, ..., x, y, y, ..., y) = g (y)
(κ)
i
Then, for arbitrary q ∈ H with (q, f ) ∈ κ, we have q1 (x, y) := q(x) ∼ f1 (x, y) ∼ g1 (x, y) (κ). Thus
q h = ∆(q1 h) ∼ ∆(g1 h) = g (κ)
for every h ∈ H. Consequently, the equivalence class (in respect to µ), to which the functions f and g belong, fulfills the condition (9.24). Thus κ ⊆ αµ holds. To prove αµ ⊆ κ let (rm , sm ) ∈ αµ . If ess(r) = ess(s) then obviously, (r, s) ∈ κ. In the case ess(r) = ess(s), it is sufficient to consider (w.l.o.g.) m = 2, r(x, y) = r (x) and s(x, y) = s (y). By definition of the relation αµ the equivalence class F of µ, to which r and s belong, has the property F H ⊆ F.
(9.27)
9.9 Congruences on Some Subclasses of Pk,l
273
With the help of the κ-congruent functions f1 , g1 we have r f1 ∼ s g1 (κ). Because of (9.27), {(r f , r ), (s g , s )} ⊆ µ is valid. Thus {(r f1 , r), (s g1 , s)} ⊆ κ. Then, the transitivity of κ implies (r, s) ∈ κ. Therefore αµ ⊆ κ and our statement on the arity congruences on [H] was proven. Finally, let κ be an arbitrary non-arity congruence on [H] and let µ be the restriction of κ onto H. Then, because of Lemma 9.3.8, the inclusion κ ⊆ γµ is valid and the relation µ has the properties mentioned in our theorem. To prove γµ ⊆ κ, it is sufficient to show that an arbitrary function hnn ∈ [H] with hnn (x1 , ..., xn ) = h (xn ) is κ-congruent to h (= h11 ) . If κ ⊆ κa there are κ-congruent functions f 2 , g 1 ∈ [H]. Consequently, we have h2 = ∆((∇h ) f ) ∼ ∆((∇h ) g) = h1 (κ), ∇h2 = h3 ∼ ∇h1 = h2 (κ), etc. Thus hn ∼ h (κ) and our theorem was proven.
9.9 Congruences on Some Subclasses of Pk,l In this section, we determine all congruences on a class A of Pk,l , which can be described with the aid of the homomorphism pr−1 (see Chapter 12): ∃B ∈ L↑l (Jl ) : A = pr−1 B,
(9.28)
i.e., A is an inverse image of a clone of Pl . Denote A the set of the subclasses of Pk,l of the form (9.28). Definition Let U1 , U2 , ..., Ut be some nonempty subsets of Ek \El and Tn (U1 , U2 , ..., Ut ) := {(a1 , a2 , ..., an ) ∈ Ekn | ∃ i ∈ {1, 2, ..., t} : Ui ⊆ {a1 , ..., an }}. Let κU1 ,...,Ut be a relation on a subclass of Pk,l defined by (f n , g m ) ∈ κU1 ,...,Ut :⇐⇒ n = m ∧ (∀a ∈ Ekn \Tn (U1 , ..., Ut ) : f (a) = g(a) ). If U = {U1 , ..., Ut } we write briefly κU instead of κU1 ,...,Ut . One can prove the following lemma easily.
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9 Congruences and Automorphisms on Function Algebras
Lemma 9.9.1 (a) The above-defined relation κU is a congruence on an arbitrary subclass of Pk,l . (b) Let U1 , U2 and U3 subsets of Ek \El . Then (1) κU1 ⊆ κU1 ,U2 , (2) κU1 ⊆ κU2 ⇐⇒ U2 ⊆ U1 , (3) κU1 ,U2 ⊆ κU3 ⇐⇒ U3 ⊆ U1 ∩ U2 , (4) (κU1 ⊆ κU2 ∧ κU2 ⊆ κU1 ) ⇐⇒ (U1 ⊆ U2 ∧ U2 ⊆ U1 ), (5) κU1 ,U2 = κU1 ⇐⇒ U1 ⊆ U2 . Theorem 9.9.2 ([Mal 79]) Let A ∈ A and let L be the set of all congruences of the form κU on A (see above). Then, (L; ⊆) is a free distributive lattice with k − l generators. Proof. For i = 1, 2 let Ui := {Ui1 , Ui2 , ..., Uiti } and let κUi be a congruence on A ∈ A. We write κU1 ≤ κU2 , if U1 ⊆ U2 and if for every U2i ∈ U2 there exists a certain U1j ∈ U1 with U1j ⊆ U2i . It results from the definition of the congruences of the type κU that U1 ≤ U2 implies κU1 = κU2 . Consequently, during the description of the congruences of the form κU , we can restrict ourselves to such sets U with the following property: ∀U ∀U ((U ∈ U ∧ U ⊆ U ⊆ Ek \El ) =⇒ U ∈ U). We call such sets J-closed. The set of all J-closed subsets of P(Ek \El ) forms a lattice. Consequently, because of (U1 ≤ U2 ∧ U2 ≤ U1 ) =⇒ κU1 = κU2 , and
(U1 , U2 are J-closed ∧ U1 ⊆ U2 ) =⇒ κU1 ⊆ κU2
there is an isomorphism from the lattice of the congruences of the type κU onto the lattice of the J-closed subsets of Ek \El . Hence, our theorem follows from [Bir 48] (p. 146, Theorem 13). As a direct consequence of Lemma 9.3.5, we get: Lemma 9.9.3 Let A ∈ A. Then, congruence κ1 is the only non-arity congruence on A. Lemma 9.9.4 Let A ∈ A, ∅ = U ⊆ Ek \El , κ a congruence on A and let f n , g n be κ-congruent functions of A, for which there exists an a ∈ (U ∪ El )n ∩ Tn (U ) with f (a) = g(a). Then, κU ⊆ κ. Proof. Let a := (a1 , a2 , ..., an ). We can assume w.l.o.g. {a1 , a2 , ..., ar } = U , |U | = r and {ar+1 , ..., an } ⊆ El . The functions x if x ∈ El , ta (x) := a otherwise
9.9 Congruences on Some Subclasses of Pk,l
275
(a ∈ El ) belong to A. Consequently, we have f (x1 , ..., xr , tar+1 (x1 ), ..., tan (x1 )) =: f (x1 , ..., xr ) ∼ g(x1 , ..., xr , tar+1 (x1 ), ..., tan (x1 )) =: g (x1 , ..., xr ) (κ) and
f (a1 , ..., ar ) = g (a1 , ..., ar ).
Let f1 and f2 be arbitrary m-ary functions of A, which are identical on tuples of Ekm \Tm (U ), m ≥ r. We have to show that (f1 , f2 ) ∈ κ holds. We start with same notations: Let I = (i1 , ..., ir ) be a variation4 of the numbers 1, 2, ..., m, xi := (xi1 , ..., xir ) and let I1 , I2 , ..., It be all possible variations of the numbers 1, 2, ..., m taken m! ). r at a time (i.e., t = (m−r)! The function h(x1 , ..., xm , z1 , ..., zt ) := (x1 , ..., xm ) ∈ Tm (U ) ∧ (∀i : zi = f (xIi )), f1 (x1 , ..., xm ) if f2 (x1 , ..., xm ) otherwise. belongs to A. Consequently, we have h(x1 , ..., xm , f (xI1 ), ..., f (xIt )) = f1 (x1 , ..., xm ) ∼ h(x1 , ..., xm , g (xI1 ), ..., g (xIt )) = f2 (x1 , ..., xm ) (κ). Thus κU ⊆ κ. Lemma 9.9.5 Let A ∈ A, let κ be a congruence on A and let U1 , U2 , ..., Ut , Ut+1 ⊆ Ek \El . Then (κU1 ,U2 ,...,Ut ⊆ κ ∧ κUt+1 ⊆ κ) =⇒ κU1 ,U2 ,...,Ut ,Ut+1 ⊆ κ. Proof. If there is an i ∈ {1, ..., t} with Ai ⊆ At+1 , then by Lemma 9.9.1, (b) we have: κU1 ,U2 ,...,Ut = κU1 ,U2 ,...,Ut ,Ut+1 ⊆ κ. Therefore, we can assume that no U ∈ {U1 , ..., Ut } is a subset of At+1 . Furthermore, let f n and g n be arbitrary functions of A, which are identical on all tuples of Ekn \Tn (U1 , ..., Ut , Ut+1 ). Because of κU1 ,...,Ut ⊆ κ we have f (x1 , ..., xn ) ∼ f (x1 , ..., xn ) := (κ).
g(x1 , ..., xn ) if (x1 , ..., xn ) ∈ Tn (U1 , ..., Ut ), f (x1 , ..., xn ) otherwise
Since κUt+1 ⊆ κ, it holds further that f ∼ g (κ). 4
Each arrangement of r different objects of a set with n different elements into a particular order is called a variation of n elements taken r at a time.
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Thus (f, g) ∈ κ. Consequently, κU1 ,...,Ut ,Ut+1 ⊆ κ. We come now to the congruences on A ∈ A which are completely determined by the congruences on prl A. So that we can better distinguish the congruences on prl A from the congruences on A, we denote the congruences on prl A with large Greek alphabetic characters. In particular, let K0 , Ka and K1 be the trivial congruences on prl A. One can check the following lemma easily. Lemma 9.9.6 Let A ∈ A and let K be a congruence on prl A. Then the relation defined by (f, g) ∈ prl−1 K :⇐⇒ (prl f, prl g) ∈ K is a congruence on A. In particular, it holds: prl−1 K1 = κ1 and prl−1 Ka = κa . Lemma 9.9.7 Let A ∈ A and let κ be a congruence on A. If there exist κ-congruent functions f n , g n ∈ A, for which there is a tuple a := (a1 , a2 , ..., an ) ∈ Eln with f (a) = g(a), then prl−1 K0 ⊆ κ. Proof. The functions ta , a ∈ El , which we have defined in the proof of Lemma 9.9.4, belong to A. Consequently, (f, g) ∈ κ implies f (x) := f (ta1 (x), ..., tan (x)) ∼ g(ta1 (x), ..., tan (x)) =: g (x) (κ). Because of f (a) = g(a) we have f (c) = g (c) for all c ∈ Ek \El . With the aid of Lemma 9.9.4 it follows that κ{l} , κ{l+1} , ..., κ{k−1} ⊆ κ. Then, by Theorem 9.8.4, we have: κ{l},{l+1},...,{k−1} = prl−1 K0 ⊆ κ. Lemma 9.9.8 Let κ be a congruence on A ∈ A. Then prl κ = K0 =⇒ κ = prl−1 (prl κ). Proof. Obviously, K := prl κ is a congruence on prl A and we have κ ⊆ prl−1 K. If prl κ = K1 then there exists some functions f n , g m ∈ A with (f, g) ∈ κ and n = m. Thus, by Lemma 9.9.3, κ = κ1 (= prl−1 K1 ). If prl κ = K1 then κ ⊆ κa and because of prl κ = K0 there exist some κ-congruent functions rt , st , which are not identical to a certain tuple of Elt . Then, by Lemma 9.9.7, we have prl−1 K0 ⊆ κ. One can deduce prl−1 K ⊆ κ from that and from prl κ = K easy. Hence prl−1 K = κ. The above lemmas can be summarized as follows: Theorem 9.9.9 ([Lau 77]) Let A ∈ A. Then, a nontrivial congruence on A is either of the type prl−1 K, where K is a congruence on prl A, or it has the form κU1 ,U2 ,...,Ut , where U1 , ..., Ut are some nonempty subsets of Ek \El , which are pairwise incomparable (in respect to the inclusion). 5
9.9 Congruences on Some Subclasses of Pk,l
277
Since we determined all congruences on subclasses of P2 in Section 9.2, can also characterize all congruences on A ∈ A for l = 2 with the aid of the above theorem. As examples, we give only the congruence lattices of Pk,2 for k ∈ {3, 4, 5}, subsequently (in the Figures 9.3–9.5). κ1 κa κ{2} κ0 Fig. 9.3. Congruence lattice of P3,2
κ1 κa κ{2},{3}
κ{2}
κ {3}
κ{2,3}
κ0 Fig. 9.4. Congruence lattice of P4,2
5
See also Theorem 9.9.2.
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κ1 κa κ{2},{3},{4} κ κ κ {2},{3} {2},{4} {3},{4} κ κ{4},{2,3} κ {2},{3,4} {3},{2,4} κ{2}
κ{3}
κ{4}
κ κ{2,3},{2,4} κ {2,3},{3,4} {2,4},{3,4} κ{3,4} κ{2,3} κ{2,4} κ{2,3,4} κ0 Fig. 9.5. Congruence lattice of P5,2
9.10 Some Further General Properties of the Congruences and the l-Classes In this section, we derive conditions with which one can realize whether a subclass of Pk has only trivial congruences. During the derivation of these conditions, we receive some general properties of the congruences as by-products. Most of the following lemmas and theorems were published by V. V. Gorlov in [Gor 77;1,2] and [Gor 79]. In the quoted papers by Gorlov proofs can be found that are excluded subsequently. Lemma 9.10.1 Let κ be a nontrivial congruence of the class A of Pk . Then (a) e11 ∈ A =⇒ κ0 ⊂ κ ⊂ κa , (k) (b) κ ∈ Cona A =⇒ κ(k) = κ0 , (k) (c) (κ ∈ Con1 A ∧ (∃f, g ∈ A1 : f g = f )) =⇒ κ(k) = κ0 , (n) 1 (n) (d) e1 ∈ A =⇒ (∀n ≥ 2 : κ = κa ). Proof. (a) follows from Lemma 9.2.1. (b): Because of (a) there are two different κ-congruent functions f n , g n ∈ A.
9.10 Some Further General Properties of the Congruences and the l-Classes
279
By using of the superposition operations ζ, τ , ∆, ∇ one receives obviously k-ary functions f , g with (f , g ) ∈ κ and f = g . Consequently, (b) holds. (c) follows from Theorem 9.3.4 and Lemma 9.3.7. (2) (d) Proving the contention for n = 2 suffices. Suppose κa = κ(2) . Then we 2 2 have (e1 , e2 ) ∈ κ. Therefore, by Lemma 9.2.2, κ = κa . This is, however, a contradiction to our assumption. With the help of an arbitrary arity congruence κ of a subclass A ⊆ Pk one can define two further arity congruences: µ (9.29) σn,κ := µ∈Cona A; κ(n) =µ(n)
and πn,κ := {(f p , g q ) ∈ A2 | p = q ∧ ∀(f1 , g1 ), ..., (fp , gp ) ∈ κ(n) ∪ {(eni , eni ) | i ∈ {1, 2, ..., n}} : (f (f1 , ..., fp ), g(g1 , ..., gp )) ∈ κ(n) }, (9.30) which are completely defined through κ(n) , n ∈ N. Some properties of these relations that are easily proven are summarized in the following lemma. Lemma 9.10.2 Let A be a subclass of Pk and let κ ∈ Cona A. Then (n) (n) (a) σn,κ = πn,κ = κ(n) , ⊆ σn+1,κ ⊆ κ ⊆ πn+1,κ ⊆ πn,κ , (b) σn,κ (c) κ = r≥1 πr,κ . The following lemma is a consequence of the above and of Lemma 9.10.1. Lemma 9.10.3 For every nontrivial arity congruence κ of a subclass A of Pk , it holds: κ0 ⊂ σk,κ ⊆ κ ⊆ πk,κ ⊂ κa . If A is in addition a clone, then κ0 ⊂ σk,κ ⊆ κ ⊆ π2,κ ⊂ κa .
Since there are only finitely many possibilities for σk,κ and πk,κ , we obtain the following theorem as a consequence of Lemma 9.10.3 and Theorem 9.3.4: Theorem 9.10.4 The congruence lattice (or the lattice of the arity congruences) of a subclass of Pk has only finitely many atoms and dual atoms. Definition Let A be a subclass of Pk . An equivalence relation µ on An , n ∈ N, is called an n-congruence, iff there exists a congruence relation κ ∈ Cona A with κ(n) = µ.
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Lemma 9.10.5 Let A be a subclass of Pk and let µ an equivalence relation on An . Then µ is an n-congruence if and only if µ fulfills the following condition: ∀ f m ∈ A ∀ (u0 , v0 ), ..., (un , vn ), .., (um , vm ) ∈ µ ∪ {(eni , eni ) | i ∈ {1, 2, ..., n}} : (f (u1 , ..., um ), f (v1 , ..., vm )) ∈ µ ∧ (u0 (u1 , ..., un ), v0 (v1 , ..., vn )) ∈ µ. (9.31) Proof. If µ is a congruence, then (9.31) obviously holds. Assume µ fulfills (9.31). The equivalence relation πµ defined by (f r , g s ) ∈ πµ :⇐⇒ r = s ∧ ∀(u1 , v1 ), ..., (ur , vr ) ∈ µ ∪ {(eni , eni ) | i ∈ {1, 2, ..., n}} : (f (u1 , ..., ur ), g(v1 , ..., vr )) ∈ µ) (n)
is a congruence on A with πµ = µ (see [Gor 77a]). Thus, µ is an n-congruence on A. With the help of Theorem 9.3.4, Lemma 9.3.7, and Lemma 9.10.5, easily one can prove the following theorem. Theorem 9.10.6 (k)
(a) A subclass A of Pk has only trivial congruences if and only if κ0 and (k) κa are the only k-congruences on A and there exist some f, g ∈ A1 with f g = f . (k) (k) (b) A clone A of Pk has only trivial congruences if and only if κ0 and κa are the only k-congruences on A. Next, we introduce a notation for classes that are minimal classes concerning the following property: Each class B, which fulfills A ⊂ B, has only trivial congruences. Definition A subclass A of Pk is called a limit class (briefly: l-class6 ), if it fulfills the following two conditions: (1) ∀B ∈ Lk : (A ⊂ B =⇒ Con B = {κ0 , κa , κ1 }); (2) ∀C ∈ Lk : (C ⊂ A =⇒ ∃C ∈ L↑k (C) : Con C = {κ0 , κa , κ1 }). Lemma 9.10.7 ([Gor 77]) (a) Let A be a subclass of Pk , which is not a clone. Then the clone A ∪ Jk has some nontrivial congruences. (b) Each l-class is a clone. Proof. (a): Since there are maximal classes (clones) with nontrivial congruences, which contain all constant functions, we can assume that |An | ≥ 2 for n ≥ 2 holds. Then, one can check that the equivalence relation 6
In [Gor 77] the notation M -class was used instead of l-class.
9.10 Some Further General Properties of the Congruences and the l-Classes
281
κ := {(f, f ) | f ∈ Jk } ∪ {(f n , g n ) | {f, g} ⊂ A} is a nontrivial congruence on A. (b) follows directly from (a). The following theorem gives some examples of l-classes. Theorem 9.10.8 (a) For k = 2 there are exactly four l-classes. These classes are L, K, D and M ∩ S. (b) A maximal class P olk of Pk is an l-class if and only if ∈ { ∈ C1k | || ≥ 2} ∪ Uk ∪ Lk ∪ Bk . (c) The class [Uω ∪ {e11 }] with ω ∈ Ek and Uω := {f n ∈ Pk | ∀a ∈ Ekn \(Ek \{ω})n ) : f (a) = ω} n≥1
is an l-class. (d) Among the submaximal classes of P3 no l-classes exist. Proof. (a) follows from Section 9.2. The statements (b) and (c) can be proven with the aid of the Theorems of Section 9.7, the Lemmas 9.7.1 and 9.10.1, and Theorem 9.10.9. One can find a proof for (d) in [Gor-L 82].
Theorem 9.10.9 (Gorlov’s Theorem; [Gor 77]) (1) Let A ⊆ Pk be an l-class. Then A fulfills one of the following conditions: (a) |Con A| ≥ 4 and there exists a 2 · k k -ary relation on Ek with A = P olk . k (b) |Con A| = 3 and ord A ≤ k 2·k . (2) For every k ≥ 2 there are only finitely many l-classes in Lk . Proof. (1): For A, the following two cases are possible: Case 1: A has a nontrivial congruence κ. Then, by Theorem 9.10.6, κ(k) is a nontrivial equivalence relation on Ak . If one now forms the 2 · k k -ary relation := {(Gk (f ), Gk (g)) | (f, g) ∈ κ(k) }
(9.32)
(see Chapter 2), then one can see that A ⊆ P olk holds and that there exists the nontrivial congruence {(f r , g s ) ∈ (P ol ) × (P ol ) | r = s ∧ ∀(u1 , v1 ), ..., (ur , vr ) ∈ κ(k) : (f (u1 , ....ur ), g(v1 , ..., vr )) ∈ κ(n) } on P olk (see also Lemma 9.10.5). Since A is an l-class, this is only possible for A = P olk . Thus A fulfills the condition (a).
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Case 2: A has only trivial congruences. k Suppose, we have A := [A2·k ] ⊂ A. Since A is an l-class, there exists a class B ⊆ Pk with A ⊂ B and |Con B| ≥ 4. Consequently, there is a nontrivial equivalence relation of the form κ(k) on B k . This relation defines a 2 · k k -ary relation , given by (9.32), with B ⊆ P olk . In addition, because of A ⊂ B, one can prove A ⊆ P olk as follows: Suppose, there is a function f n ∈ A k that does not preserve (n > k (2k ) ). Then there is some r1 , ..., rn ∈ with f (r1 , ..., rn ) ∈ . We form the function f (x) := f (xi1 , ..., xin ) ∈ [f ] with ∀j, l ∈ {1, ..., n} : (ij = il ⇐⇒ rj = rl ). k
Then, because || ≤ k 2k , f belongs indeed to A , however, it does not preserve the relation , in contradiction to A ⊂ B ⊆ P olk . Consequently, A ⊆ P olk . But this is a contradiction to our assumption “A is an l-class and has only trivial congruences”. Thus A fulfills the condition (b) and, therefore, (1) is proven. (2) is a consequence of (1).
9.11 The Connection Between Clone Congruences and Fully Invariant Congruences Let A = (A; W ), W ⊆ PA , be an algebra, let VA be the variety generated by A and let F(X) (:= (F (X); W )) be the free algebra with countable ranges 7 of VA (see Part I). For F (X) we use the following model: X := {x1 , x2 , ...}, F (X) := n≥1 {f (xi1 , ..., xin ) | f ∈ T (n) (A) ∧ {xi1 , ..., xin } ⊆ X} (Therefore, F (X) consists of all terms that can be formed from X and the functional symbols of (T(A) = [W ∪ JA ]) and for arbitrary wn ∈ W and arbitrary fi (xi,1 , ..., xi,mi ) ∈ F (X), i = 1, ..., n + 1, it holds f1 (x1,1 , ..., x1,m1 ) = f2 (x2,1 , ..., x2,m2 ) :⇐⇒ ∀ a1,1 , ..., a2,m2 ∈ A : f1 (a1,1 , ..., a1,m1 ) = f2 (a2,1 , ..., a2,m2 )
(9.33)
and w(f1 (x1,1 , ..., x1,m1 ), ..., fn (xn,1 , ..., xn,mn )) = fn+1 (xn+1,1 , ..., xn+1,mn+1 ) :⇐⇒ ∀a1,1 , ..., an+1,mn+1 ∈ A : w(f1 (a1,1 , ..., a1,m1 ), ..., fn (an,1 , ..., an,mn )) = fn+1 (an+1,1 , ..., an+1,mn+1 ), 7
For example, X is countably infinite.
9.11 The Connection Between Clone Congruences and Fully Invariant Congruences
where
ai,j = al,k ⇐⇒ xi,j = xl,k
(see Chapter 6 of Part I). The fully invariant congruences8 of F (X) are of interest to us here, since the lattice of these congruences is anti-isomorphic to the lattice of the subvarieties of VA . The following theorem is a well-known result of the category theory, which follows from the representation of a variety by an algebraic theory (a certain category). One finds complete information on this category-theory background in [Vog 85]. Theorem 9.11.1 ([Schw 84]) Through (t(x1 , ..., xn ), u(x1 , ..., xn )) ∈ κF ⇐⇒ (t, u) ∈ κ
(9.34)
every binary relation κF on F(X) (∈ VA ) is assigned to a relation κ ⊆ κa on T (A) and vice versa. A binary relation κF is a fully invariant congruence F(X) if and only if the relation κ on T (A) is an arity congruence of T (A); i.e., the lattice of the fully invariant congruences of F(X) is isomorphic to the lattice of the arity congruences of T (A) or antiisomorphic to the subvariety lattice of VA . Proof. Since f ∈ T (A) implies ∇f ∈ T (A) and because of (9.34), every relation on F (X) is completely characterized through the tuples (t(x1 , ..., xn ), u(x1 , ..., xn )) (t, u ∈ T (n) (A), n = 1, 2, ...). Thus (9.34) describes a bijection between binary relations on F (X) and arity relations on T (A). Let κ ⊆ κa be a congruence relation on T (A) and let κF be the relation on F (X) defined by (9.34). Because of (w(t1 , ..., tr ), w(u1 , ..., ur )) ∈ κ for (ti , ui ) ∈ κ, i = 1, 2, ..., r, and arbitrary w ∈ W , κF is compatible with the operations of W , i.e., κF is a congruence relation on F (X). κF would be fully invariant if in addition (t(x1 , ..., xn ), u(x1 , ..., xn )) ∈ κF implies (ϕ(t(x1 , ..., xn )), ϕ(u(x1 , ..., xn ))) ∈ κF for every endomorphism ϕ on F (X). Let ϕ be an endomorphism on F (X) with ϕ(xi ) = ti (x1 , ..., xri ), i = 1, 2, ..., and (t(x1 , ..., xn ), u(x1 , ..., xn )) ∈ κF . Then (ϕ(t(x1 , ..., xn ), ϕ(u(x1 , ..., xn ))) = (t(ϕ(x1 ), ..., ϕ(xn )), u(ϕ(x1 ), ..., ϕ(xn ))) = (t(t1 (x1 , ..., xr1 ), ..., tn (x1 , ..., xrn )), u(t1 (x1 , ..., xr1 ), ..., tn (x1 , ..., xrn ))) ∈ κF , since (t, u) ∈ κ implies (t(t1 , ..., tn ), u(t1 , ..., tn )) ∈ κ. Thus κF is a fully invariant congruence on F(X) if κ is a congruence on T (A). 8
These are equivalence relations on F(X), which are compatible not only with the operations of the algebra F(X) but also with every endomorphism of F(X).
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Let κF be a fully invariant congruence on F(X) and let (f n , g n ), (um , v m ) ∈ κ in the following. We have to prove that (f u, g v) ∈ κ and (αf, αg) ∈ κ for α ∈ {ζ, τ, ∆}. Obviously, one can continue every mapping from X into F (X) to an endomorphism on F (X). We consider the endomorphisms ϕ1 , ..., ϕ4 with ϕ1 (x1 ) = x2 , ϕ1 (x2 ) = x3 , ..., ϕ1 (xn−1 ) = xn , ϕ1 (xn ) = x1 ϕ2 (x1 ) = x2 , ϕ2 (x2 ) = x1 , ϕ2 (x3 ) = x3 , ..., ϕ2 (xn ) = xn , ϕ3 (x1 ) = ϕ3 (x2 ) = x1 , ϕ1 (x3 ) = x2 , ..., ϕ3 (xn ) = xn−1 , ϕ4 (x1 ) = u(x1 , ..., xm ), ϕ4 (x2 ) = xm+1 , ..., ϕ4 (xn ) = xm+n−1 . Since, by assumption, (f (x1 , ..., xn ), g(x1 , ..., xn )) ∈ κF and κF is fully invariant, for i = 1, 2, 3, 4 the tuples (ϕi (f (x1 , ..., xn )), ϕi (g(x1 , ..., xn ))) = (f (ϕi (x1 ), ..., ϕi (xn ), g(ϕi (x1 ), ..., ϕi (xn ))) ⎧ (f (x2 , ..., xn , x1 ), g(x2 , ..., xn , x1 )) if i = 1, ⎪ ⎪ ⎪ ⎪ if i = 2, ⎨ (f (x2 , x1 , x3 , ..., xn ), g(x2 , x1 , x3 , ..., xn )) = (f (x1 , x1 , x2 , ..., xn−1 ), g(x1 , x1 , x2 , ..., xn−1 )) if i = 3, ⎪ ⎪ (f (u(x1 , ..., xm ), xm+1 , ..., xm+n−1 ), ⎪ ⎪ ⎩ if i = 4, g(u(x1 , ..., xm ), xm+1 , ..., xm+n−1 )) belong to κF and, therefore, {(ζf, ζg), (τ f, τ g), (∆f, ∆g), (f u, g u)} ⊆ κ. In addition, since κF is compatible with the operations of W , we have (because of (u(x1 , ..., xm ), v(x1 , ..., xm )) ∈ κF ) (g(u(x1 , ..., xm ), xm+1 , ..., xm+n−1 ), g(v(x1 , ..., xm ), xm+1 , ..., xm+n−1 )) ∈ κF and (by transitivity) (f (u(x1 , ..., xm ), xm+1 , ..., xm+n−1 ), g(v(x1 , ..., xm ), xm+1 , ..., xm+n−1 )) ∈ κF . Thus (f u, g v) ∈ κ. From this, together with the above considerations, we get that κ is a congruence on T (A). The remaining statements of the theorem are obvious or result from Part I. Analogous to the above proof and with the aid of Lemma 9.10.5, the following theorem can be proven. Lemma 9.11.2 Let F (n) be the free algebra with n generators of VA . Through (f (x1 , ..., xn ), g(x1 , ..., xn )) ∈ µF (n) ⇐⇒ (f, g) ∈ µ (f, g ∈ T (n) (A) ) every fully invariant congruence on F (n) corresponds unambiguously with an n-congruence on T (A) and conversely.
9.12 Automorphisms of Function Algebras
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9.12 Automorphisms of Function Algebras An automorphism of an algebra A is an isomorphic mapping from A onto A. In this section, we denote the image α(f ) of a function f ∈ A, where α denotes a mapping on A, with f α . An automorphism α of a subclass A ⊆ Pk is called an inner automorphism onto A, if there exists a bijective mapping ϕ from Ek onto Ek with the following property: ∀f n ∈ A : f α (x1 , ..., xn ) = ϕ(f (ϕ−1 (x1 ), ..., ϕ−1 (xn )) or
f α (ϕ(x1 ), ..., ϕ(xn )) = ϕ(f (x1 , ..., xn )).
In the following, we put together some properties of automorphisms of subclasses of Pk , and we prove, for some classes, that they have only inner automorphisms. In particular, we prove that all automorphisms of subclasses of P2 are inner automorphisms. This is not valid anymore for classes Pk , however, for k ≥ 3. The basis of these proofs is [Mal 66], from which we use many details here. In addition, we generalize some results of [Mal 66]. Lemma 9.12.1 Let A be a subclass of Pk and let α be an automorphism onto A. Then for arbitrary f ∈ A it holds: (a) (b) (c) (d)
a f = a (f α ). xi is a fictitious variable of f iff xi is a fictitious variable of f α . f is a constant function iff f α is a constant function. f is a permutation iff f α is a permutation.
Proof. (a): Suppose there exists a function f ∈ A with a(f ) = a(f α ). We distinguish two cases. Case 1: n := a f < a(f α ) =: m. Then ∆n−1 f = ∆n f . Consequently, ∆n−1 f α = ∆n f α . The last equation is not, however, possible because of a(∆n−1 f α ) = m − n + 1 and a(∆n f α ) = m − n. Case 2: a f > a(f α ) =: m. In this case, we have ∆m−1 f α = ∆m f α and thus (∆m−1 f )α = (∆m f )α , in contradiction to the bijectivity of the mapping α. Therefore, a(f ) = a(f α ) for all f ∈ A. (b): W.l.o.g. let i = 1. Obviously, x1 is a fictitious variable of f iff ∇(∆f ) = f . The equation ∇(∆f ) = f holds iff ∇(∆f α ) = f α . Hence (b) is right. (c) follows directly from (b). (d): If A contains a permutation, then all projections belong to A. The function e := e11 is the only function of A, for which f e = e f holds for all f ∈ A1 . Consequently, we have also f α eα = eα f α for all f ∈ A1 . Thus eα = e.
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9 Congruences and Automorphisms on Function Algebras
Since for every permutation s ∈ A there exists a t with s s ... s = e, it t times holds sα sα ... sα = e, whereby sα is a permutation. t times Theorem 9.12.2 Let A be a subclass of Pk and let T be a subset of Ar , r ≥ 1, which has the following three properties: (1) Every function of A preserves the functions of T . (2) There exists a c ∈ Ekr and some functions g0 , g1 , ..., gk−1 ∈ T with gi (c) = i for every i ∈ Ek . (3) For each automorphism α onto A it holds T α = T and α|T is an inner automorphism onto T . Then each automorphism onto A is an inner automorphism. Proof. Let α be an automorphism onto A. By assumption (3), we have T α = T and that α|T is an inner automorphism onto T . The permutation ϕ appertaining to this inner automorphism defines an isomorphism βϕ from A onto Aβϕ : ∀f n ∈ A : f βϕ (x) = ϕ−1 (f (ϕ(x1 ), ..., ϕ(xn ))). We show that the mapping γ := αβϕ−1 is the identical mapping, whereby βϕ = α is valid and the claim “α is an inner automorphism” follows: Let f n ∈ A and let a = (a1 , ..., an ) ∈ Ekn be arbitrary. By assumption (2), for every ai ∈ Ek , there exists a function gai ∈ T with gai (c) = ai , i = 1, ..., n. Because of (1) there is a function g ∈ T with the properties: f (ga1 (x), ..., gan (x)) = g(x) and g(c) = f (a). Consequently, we have g γ = f γ (gaγ1 , ..., gaγn ). Because the functions of T are fixed points of the mapping γ, this implies g = f γ (ga1 , ..., gan ). Thus we have f γ (a) = g(c) = f (a) for arbitrary a ∈ Ekn , i.e., f = f γ holds for every f ∈ A. With the aid of the above theorem, we can prove the three following theorems. Theorem 9.12.3 ([Mal 72b]) If a subclass A ⊆ Pk contains all constants of Pk , then each automorphism onto A is an inner automorphism. Proof. The claim follows from Theorem 9.12.2, if one chooses T = {c0 , c1 , ..., ck−1 } and uses Lemma 9.12.1, (c). The following theorem generalizes Theorem 2 from [Mal 66].
9.12 Automorphisms of Function Algebras
287
Theorem 9.12.4 Let ∅ = E ⊆ Ek , a if x ∈ E, ta,b (x) := b otherwise, T := {ta,b | a ∈ E ∧ b ∈ Ek }, S := Pk1 [k]∩P olk E and let A be a subclass of Pk with S ∪T ⊆ A . Then, each automorphism onto A is an inner automorphism. Proof. If |E| = 1 then Theorem 9.12.4 follows from the proof of Theorem 2 in [Mal 66]. If A ⊆ P olk E, then by S ∪ T ⊆ A, we have that A contains all constant functions of Pk . Consequently, by Theorem 9.12.3, A has only inner automorphisms in this case. Thus we can assume A ⊆ P olk E in the following. Let α be an automorphism onto A. We show that T fulfills the assumptions (1)–(3) of Theorem 9.12.2. Because of A ⊆ P olk E, it holds (1). (2) is also valid. Further, we have for arbitrary g ∈ A1 (∀s ∈ S : g s = g) ⇐⇒ g ∈ T.
(9.35)
Thus g ∈ T implies g s = g for all s ∈ S and therefore also g α sα = g α . Because the function sα belongs to S because of Lemma 9.12.1, (d), we obtain g α ∈ T from (9.35) Consequently, T = T α . Next we show that, for the set T1 := {ta,b | a ∈ E ∧ b ∈ Ek \E}, the equation T1α = T1 holds. Obviously, we have for all ta,b ∈ T : ta,b ta,b = tc,c ⇐⇒ a = c ∧ {a, b} ⊆ E.
(9.36)
α α Therefore, ta,b ∈ T \T1 implies ta,b ta,b = ta,a and then tα a,b ta,b = ta,a . Since is a constant by Lemma 9.12.1, we have t ∈ T \T because of (9.36). tα a,b 1 a,a Consequently, T1α = T1 . If one restricts the functions of T1 ∪ S to E or Ek \E, one obtains the sets (T1 ∪S)|E ⊆ PE or (T1 ∪S)|Ek \E ⊆ PEk \E , respectively. Since the set (T1 ∪S)|E or (T1 ∪ S)|Ek \E contains all constant functions of PE or PEk \E , respectively, α|(T1 ∪S)|E or α|(T1 ∪S)|(Ek \E) is an inner automorphism onto the semigroup (T1 ∪ S; ), respectively. Thus there exists a permutation ϕ onto Ek with
∀h ∈ T1 ∪ S : hα = ϕ−1 h ϕ.
(9.37)
Finally we show that (9.37) also holds for every function h ∈ T \T1 , whereby the condition (3) of Theorem 9.12.2 and then our theorem are proven: Let ta,b ∈ T \T1 , tα a,b = ta ,b and let s ∈ S, where s has only the fixed points a and b. Then s ta,b = ta,b and sα ta ,b = ta ,b .
(9.38)
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9 Congruences and Automorphisms on Function Algebras
(9.38) implies that a and b are fixed points of the permutation sα . Because of sα = ϕ−1 s ϕ the permutation sα has only the fixed points ϕ−1 (a) and ϕ−1 (b). Consequently, {a , b } = {ϕ−1 (a), ϕ−1 (b)}. Thus for a = b, we have −1 ta,a ϕ is valid. From that and from ta,b ta,a = ta,a shown that tα a,a = ϕ α α and ta ,b ta,a = ta,a , then, a = ϕ−1 (a) and b = ϕ−1 (b) hold. Consequently, we have ta ,b = ϕ−1 ta,b ϕ. Theorem 9.12.5 ([Lau 79;b]) All automorphisms on a maximal class of Pk are inner automorphisms. Proof. With the aid of Theorems 9.12.3 and 9.12.4, it is easy to see that all maximal classes of Pk have only inner automorphisms, except for the maximal classes of the type S. Let A ⊆ Pk be a maximal class of type S, i.e., it holds A = P olk s , where s, s and the functions of A are defined as in Section 5.2.2 in the following. Denote T the set of all functions of the form fa (x) :=
p−1 l
jar,i (x) · si (a), (a ∈ Ek ).
r=1 i=0
Our theorem is proven if we can show that T fulfills the assumptions of Theorem 9.12.2. Obviously, T fulfills the first two conditions of Theorem 9.12.2. To prove (3) from Theorem 9.12.2 denote α an automorphism onto P olk s . First we prove T α = T . Obviously, for every function g ∈ (P olk s )1 and every function fa ∈ T there exists a function h ∈ (P olk s )1 with fa = h g. Consequently, we have (9.39) faα = hα g α . If the function also fulfills the condition g α ∈ T , then we have hα g α ∈ T and (by (9.39)) faα ∈ T for arbitrary a ∈ Ek . Thus T α = T . Next we derive some properties of the function fa : For all r ∈ {1, 2, ..., l} and i ∈ Ep we have far,0 far,i = far,i and thus faαr,0 faαr,i = faαr,i , i.e., for every r there exists an r with faαr,0 = far,0 . Further, it holds far,i = (...((far,1 far,1 ) far,1 )... far,1 ). i times For faαr,1 = far,br (br ∈ Ep \{0}) this implies faαr,i = far,i·br (mod p) . Because of far,0 fa1,1 = far,1 we have faαr,0 faα1,1 = faαr,1 = far,br = far,0 = far,b1 , i.e., br = b1 =: b holds for arbitrary r ∈ {1, 2, ..., l}. In summary fa1,b 1 we get: (9.40) faαr,i = far,i·b (mod p) ,
9.12 Automorphisms of Function Algebras
289
where r, r ∈ {1, 2, ..., l}, i ∈ Ep and b ∈ Ep \{0}. Because of (9.40), one can define a permutation ϕ onto Ek as follows: ϕ(ar,i ) := ar,i·b (mod p) . This permutation has the property ∀au,v ∈ Ek : faαu,v (ϕ(x)) = ϕ(fau,v (x)), which one can prove as follows: Let x = ar,i (r ∈ {1, 2, ..., l}, i ∈ Ep ). Then we have (ar,i·b (mod p) ) = si·b (au ,v·b (mod p) ) = faαu,v (ϕ(ar,i )) = fau,v·b (mod p) au ,(v+i)·b (mod p) and ϕ(fau,v (ar,i )) = ϕ(si (au,v )) = ϕ(au,v+i (mod p) ) = au ,(v+i)·b (mod p) . Hence α is an inner automorphism onto T , and Theorem 9.12.2 implies that P olk s has only inner automorphisms. Theorem 9.12.6 ([Gor-L 83a]) Each automorphism on a subclass of P2 is an inner automorphism. Proof. Let A = [A] ⊆ P2 . By Chapter 4, the following cases are possible: Case 1: A1 = {ca }. Then A is the class [ca ], which has obviously only inner automorphisms. Case 2: {c0 , c1 } ⊆ A1 . In this case, our theorem follows from Theorem 9.12.3. Case 3: A1 ∈ {{c0 , e11 }, {c1 , e11 }, {e11 , e11 }}. In this case, we obtain our claim from Theorem 9.12.2, when we elect T = A1 and when we use Lemma 9.12.1, (d). Case 4: A1 = {e11 }. By Chapter 3, considering only the following possibilities for A suffices: Case 4.1: A ∈ {I, K, L ∩ T0 ∩ S, S ∩ M }. In this case, there exists a function f n ∈ A with [f ] = A and n = ord A (see Chapter 3). Then, with the help of Lemma 9.12.1, (b) and by the properties of the functions of A, one can prove that f α = f holds for each automorphism α onto A. Because of [f ] = A this implies that α is the identical mapping, which is obviously an inner automorphism. Case 4.2: A ∈ {S ∩ T0 , M ∩ T0 ∩ T1 , T0 ∩ T1 } ∪ m∈{2,3,...,∞} {T0,m ∩ T1 ∩ M, T0,m ∩ T1 }. Choosing T = A2 , A fulfills the conditions (1) and (2) of Theorem 9.12.2. We prove that T = A2 also fulfills condition (3): If A ∈ {M ∩ T0 ∩ T1 , T0 ∩ T1 } then A2 = {∧, ∨, e21 , e22 }; if A = S ∩ T0 then A2 = {e21 , e22 } and if A ∈ {T0,m ∩ T1 ∩ M, T0,m ∩ T1 } then A2 = {∧, e21 , e22 }. By Lemma 9.12.1, (b) we have (e2i )α = e2i , i ∈ {1, 2}, for each automorphism
290
9 Congruences and Automorphisms on Function Algebras
α onto A. When one considers this, one convinces oneself that α|A2 is an inner automorphism onto T for each automorphism α onto A. Consequently, A fulfills every condition of Theorem 9.12.2 in Case 4.2. Thus A has only inner automorphisms. Theorem 9.12.7 ([Gor-L 83a]) If k ≥ 3 then there are subclasses of Pk , whose automorphisms are not all inner automorphisms. Proof. Here is an example: Let x if x ∈ E2 , x if x ∈ E2 , u(x) := and v(x) := 0 otherwise, 1 otherwise. By Lemma 9.12.1, (a), (b) and Theorem 9.8.4, all automorphisms onto the set A := [u, v, c0 ] are induced by the automorphisms of the semigroup (A1 ; ). It is easy to check that the mapping α : u → v, v → u, c0 → c0 is an automorphism of (A1 ; ). Suppose α is an inner automorphism. Then there is a permutation ϕ onto Ek with ∀g ∈ {u, v, c0 } : g α = ϕ−1 g ϕ.
(9.41)
Because of cα 0 = c0 we have ϕ(0) = 0. (9.41) implies ϕ u = v ϕ and then ϕ(0) = v(ϕ(0)) and ϕ(0) = v(ϕ(2)). Because of definitions of ϕ and v this is only possible if ϕ(0) = 1, in contrary to the above statement ϕ(0) = 0. Thus α is not an inner automorphism.
10 The Relation Degree and the Dimension of Subclasses of Pk
This chapter deals with the relation degree and the dimension of subclasses A of Pk . The relation degree of A is the smallest number h so that class A is unambiguously described by a relation set whose elements have the arity h at most. The dimension of A is the smallest arity of a relation that characterizes class A unambiguously. We begin with investigating the connections between these two complexity measures of the relational description of classes. Then we prove the relation degrees and dimensions of Post’s classes, which were found by G. N. Blochina in [Blo 70]. In Section 10.3, there are further classes for which is known the relation degree or the dimension.
10.1 The Definition of the Relation Degree and of the Dimension of a Subclass of Pk In this section we deal with two possibilities for evaluating the complexity of relational descriptions of subclasses of Pk . Denote ar(), ∈ Rkh \{∅}, the arity h of the relation . Further, for Q ⊆ Rk , let ⎧ if Q = ∅, ⎪ ⎨ 0, armax (Q) := max{ar() | ∈ Q}, if the maximum exists, ⎪ ⎩ ∞ otherwise. The relation degree d(A) of a subclass A of Pk is the smallest of the possible numbers armax (Q) with A = P olk Q, i.e., ⎧ ⎨ min{armax (Q) | Q ⊆ Rk ∧ P ol Q = A} if ∃h ∈ N ∃Q ⊆ Rkh : P ol Q = A, d(A) := ⎩ ∞ otherwise. If one complements the above definition with the demand |Q| = 1, the result is the definition of the dimension of a subclass A of Pk :
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10 The Relation Degree and the Dimension of Subclasses of Pk
dim A :=
min{ar() | ∈ Rk ∧ P ol = A} if ∃ ∈ Rk : P ol = A, ∞ otherwise.
The following lemma gives some elementary connections from d and dim. Lemma 10.1.1 Let A be a subclass of Pk . Then (a) d(A) = dim A = 0 ⇐⇒ A = Pk . (b) d(A) ≤ dim A. (c) d(A) < ∞ ⇐⇒ dim A < ∞. (d) If ∞ = d(A) < dim A, then there are certain proper predecessors A1 , ..., Ar of A, which are pairwise not contained in each other (i.e., A ⊂ Ai , Ai = [Ai ] and Ai ⊆ Aj for i = j and i, j = 1, 2, ..., r), with the following properties: A = A1 ∩ A2 ∩ ... ∩ Ar , r ≥ 2 and d(A) = max{d(Ai ) | i = 1, ..., r}. (e) If A has exactly a direct predecessor B (i.e., A ⊂ B = [B] and no subclass B exists with A ⊂ B ⊂ B), then d(A) = dim A. Proof. (a) follows from P ol ∅ = Pk and (b) results immediately from the definitions of d and dim. (c) follows from P ol{1 , 2 , ..., t } = P ol 1 × 2 × ... × t . (d): If d(A) = ∞ and d(A) < dim A, there are certain relations 1 , ..., r with the properties r A = P ol {1 , ..., r } = i=1 P ol i , r ≥ 2, ∀i ∈ {1, .., r} : A = P ol {1 , ..., r }\{i } and d(A) = armax {1 , ..., r }. If one now sets Ai := P ol i (i = 1, .., r), most of the properties of the sets Ai mentioned in the lemma are immediately clear. The rest results from A ⊂ Ai for all i = 1, ..., r because of d(A) < dim A. (e) follows from (b) and (d).
10.2 The Dimensions and Relation Degrees of Post’s Classes
293
10.2 The Dimensions and Relation Degrees of Post’s Classes The basic results of this section come from the paper [Blo 70] by G. N. Blochina. Our aim is to prove the values given in Table 10.1. In the first column, all subclasses A of P2 are listed (except for the isomorphic classes). Next to the values d(A) and dim(A), which we will subsequently prove, one can also find some descriptive relations for subclasses A. The correctness of these statements can easily be proven in the following manner: First, A ⊆ P ol holds for the corresponding of the third column. (For most classes this is clear according to definition. For every remaining class, the statement is a conclusion from the given construction of with the aid of a certain n-ary graphic Gn (A) 1 .) Then, one proves that for every direct predecessor B of A there exists an f ∈ B 2 with f ∈ P ol . The equation P ol = A and an upper bound for dim A (≥ d(A)) result from the proven facts. After Table 10.1, one finds the lower bounds for dim A, which are identical to the upper bounds and the proofs for the remaining statements of this table. Table 10.1
A P2 T0 S M T0,2 T0 ∩ T1
1 2
dim A with A = P ol 0 ∅ 1 {0} # $ 0 1 2 1 0 # $ 0 0 1 2 0 1 1 # $ 0 0 1 2 0 1 0 # $ 0 2 1
d(A) 0 1
E23 \{1} 0 0 0 0 0 1 0 1 1 0 0 0 1 1 0 0 0 1 0 1 1 1 0 0
3
T0,3
3
M ∩ T0
3
S ∩ T0
3
S∩M
3
See Section 2.7. It is sufficient to consider a basis of B instead of B.
2 2 2 1 2 2 2
294
10 The Relation Degree and the Dimension of Subclasses of Pk
A M ∩ T0,2 T1 ∩ T0,2 L ∩ T0 K ∪C M ∩ T0,2 T1 ∩ T0,2 L ∩ T0 K ∪C I I ∩ C0 I [P21 ] I ∪C M ∩ T0 ∩ T1 L L∩S L ∩ S ∩ T0 K ∪ C0
dim A with A = P ol d(A) 0 0 0 1 0 0 1 0 3 2 0 1 1 1 0 0 1 0 1 0 3 2 1 1 1 0 0 1 1 0 1 0 1 = pr2,3,4 G2 (A) 3 3 0 1 1 0 0 1 0 1 0 0 0 1 = pr2,1,3 G2 (A) 3 3 0 0 1 1 0 0 0 1 0 0 1 0 3 2 0 1 1 1 0 0 1 0 1 0 3 2 1 1 1 0 0 1 1 0 1 0 1 = pr2,3,4 G2 (A) 3 3 0 1 1 0 0 1 0 1 0 0 0 1 = pr2,1,3 G2 (A) 3 3 0 0 1 1 0 1 1 1 0 1 = pr4,6,7 G3 (A) 3 3 1 1 0 0 0 0 1 1 1 0 0 1 0 1 0 3 3 0 1 1 0 0 1 0 1 1 0 0 1 1 0 1 0 1 0 = pr4,6,7 G3 (A) 3 3 1 1 0 1 0 0 0 0 0 1 1 1 0 0 1 1 0 1 = pr1,2,3 G2 (A) 3 3 1 1 ⎛0 1 0 0 ⎞ 0 0 0 1 ⎝ 0 1 0 1 ⎠ = G2 (A) 4 3 1 0 0 1 1 1 0 1 ⎛ ⎞ 0 0 0 ⎝0 0 1⎠ 4 2 0 1 1 1 1 1 ⎛ ⎞ 0 0 0 1 1 0 1 1 ⎝ 0 0 1 1 0 1 0 1 ⎠ = G2 (A) 4 4 0 1 0 0 1 1 0 1 0 1 1 0 0 0 1 1 ⎛ ⎞ 1 0 0 0 0 1 1 1 ⎝ 0 1 0 0 1 0 1 1 ⎠ = pr1,2,3,5 G3 (A) 4 4 0 0 1 0 1 1 0 1 1 1 1 0 ⎛0 0 0 1⎞ 0 0 0 0 ⎝ 0 0 1 1 ⎠ = pr1,2,4,6 G3 (A) 4 3 0 1 1 0 1 0 1 0 ⎛ ⎞ 0 0 0 0 ⎝ 0 1 0 0 ⎠ = pr1,5,6,7 G3 (A) 4 3 0 1 1 0 0 1 0 1
10.2 The Dimensions and Relation Degrees of Post’s Classes
A K ∪ C1 T0,4 T0,3 ∩ T1 T0,3 ∩ M T0,2 ∩ M ∩ T1
K T0,t (t ≥ 5)
295
dim A ⎛ with A = P d(A) ⎞ol 0 0 0 1 ⎝ 0 1 0 1 ⎠ = G2 (A) 4 3 1 0 0 1 1 1 1 1 4 E24 \{(1, 1, 1, 1)} 4 ⎛ ⎞ 0 0 0 1 0 1 1 ⎝ 0 0 1 0 1 0 1 ⎠ = pr4,6,7,8 G3 (A) 4 3 0 1 0 0 1 1 0 1 1 1 1 1 1 1 ⎛ ⎞ 0 0 0 0 1 0 1 1 ⎝ 0 0 0 1 0 1 0 1 ⎠ = pr4,6,7,8 G3 (A) 3 4 0 0 1 0 0 1 1 0 1 1 1 1 ⎛0 1 1 1⎞ 0 0 0 1 ⎝ 0 0 1 0 ⎠ = pr3,5,7,8 G3 (A) 4 2 0 1 1 1 1 1 1 1 ⎛ ⎞ 0 0 0 0 ⎜1 0 0 0⎟ 5 3 ⎝ 1 0 1 0 ⎠ = pr1,5,6,7,8 G3 (A) 1 1 0 0 1 1 1 1 t E2t \{(1, 1, ..., 1)} =: αt t
T0,t−1 ∩ T1
t
αt−1 × (1) =: βt
t−1
T0,t−1 ∩ M
t
βt ∪ {(0, 0, ..., 0)} =: γt
t−1
T0,t−2 ∩ M ∩ T1 (t ≥ 5)
t
γt−1 × (1)
t−2
T0,∞
∞
∞
T0,∞ ∩ T1
∞
∞
T0,∞ ∩ M
∞
∞
T0,∞ ∩ M ∩ T1
∞
∞
C0
∞
∞
C
∞
∞
Lemma 10.2.1 Let M := {Ca , C, Ta,∞ , Ta,∞ ∩ Ta , Ta,∞ ∩ M, Ta,∞ ∩ M ∩ Ta | a ∈ E2 }. Then dim A = ∞ for every A ∈ M. Proof. Since e11 ∈ P ol holds for arbitrary , the contention is valid apparently for sets Ca and C. Assume for A ∈ M\{C0 , C1 , C} there is an h-ary relation with r columns, for which A = P ol holds. If one identifies the variable xi with the variable xj (i = j) in the function , one receives a function of the form hr+1 r
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10 The Relation Degree and the Dimension of Subclasses of Pk
xi ∧ g(x1 , ..., xi−1 , xi+1 , ..., xr )
(10.1)
with g ∈ M ∩ T0 ∩ T1 . Since all functions of the form (10.1) belong to A, hr preserves the relation , in contradiction to hr ∈ A. Lemma 10.2.2 Let (a) dim A = 0 ⇐⇒ (b) dim A = 1 ⇐⇒ (c) dim A = 2 ⇐⇒
A be a subclass of P2 . Then A = P2 ; A ∈ {T0 , T1 }; A ∈ {M, S, T0 ∩ T1 , T0.2 , T1,2 }.
Proof. The statements (a) and (b) are trivial. One easily checks that only classes of the set {P2 , Ta , M, S, T0 ∩ T1 , Ta,2 |a ∈ E2 } are describable through binary relations on E2 . As a direct consequence from Lemma 10.2.2 and the remarks before Table 10.1, we see that Lemma 10.2.3 If A ∈ {M ∩ Ta , S ∩ Ta , S ∩ M, L ∩ Ta , K ∪ C, I, I ∪ I, I ∪ Ca , [P21 ], M ∩ Ta,2 , Ta ∩ Ta,2 |a ∈ E2 }, then dim A = 3. Lemma 10.2.4 If b ≥ 2 then dim T0,b ≥ b. Proof. Let b ≥ 2. Assume there is an h-ary relation with T0,b = P ol , 1 ≤ h < b and does not contain any double rows. Because of c0 ∈ T0,b , has not an 1-column. Since [{x ∧ y}] = n≥1 {f n ∈ P2 | ∃i ∃g n−1 ∈ P2 : f (x1 , ..., xn ) = xi ∧ g(x1 , ..., xi−1 , xi−1 , ..., xn )} ⊆ T0,b , is valid in addition apparently: ⎛ ⎞ a1 ⎜ a2 ⎟ ⎜ ⎟ ⎝ ... ⎠ ∈ =⇒ (∀b1 , ..., bh ∈ E2 ah
⎞ ⎛ a1 b1 ⎜ b2 ⎟ ⎜ a2 ⎟ ⎜ :⎜ ⎝ ... ⎠ ≤ ⎝ ... bh ah ⎛
⎞
⎛
⎞ b1 ⎜ ⎟ ⎟ ⎟ =⇒ ⎜ b2 ⎟ ∈ ) ⎝ ... ⎠ ⎠ bh (10.2) ∈ T0,b−1 \T0,b , there is certain r1 , ..., rb ∈
Since T0,b−1 ⊇ T0,b = P ol and hb−1 with hb−1 (r1 , ..., rb ) ∈ . Denote z1 , ..., zt exactly the rows of (r1 ..., rb ) on which hb−1 takes the value 1. Because of definition of the class T0,b−1 , the matrix ⎛ ⎞ z1 ⎜ z2 ⎟ ⎜ ⎟ ⎝ ... ⎠ zt contains an 1-column. Thus (r1 , ..., rb ) has a column ≥ hb−1 (r1 , ..., rb ), in contradiction to (10.2) and hb−1 (r1 , ..., rb ) ∈ .
10.2 The Dimensions and Relation Degrees of Post’s Classes
297
Lemma 10.2.5 If b ≥ 2 and a ∈ {0, 1} then dim M ∩ Ta,b ≥ b + 1. Proof. Let b ≥ 2 and w.l.o.g. let a = 0. Further, let := {(x1 , ..., xb+1 ) ∈ E2b+1 \{(1, 1, ...1)} | xb+1 = 1} ∪ {(0, 0, ..., 0)} Then M ∩ T0,b = P ol . Assume there is an r-ary relation ‘ with 1 ≤ r ≤ b and P ol‘ = M ∩ T0,b . Since hb−1 ∈ M ∩ T0,b , there exists some aij ∈ E2 with ⎛ ⎞ ⎛ ⎞ a11 a12 ... a1b d1 ⎜ a21 a22 ... a2b ⎟ ⎜ d2 ⎟ ⎟ ⎜ ⎟ hb−1 (A) := hb−1 ⎜ ⎝ ... ... ... ... ⎠ = ⎝ ... ⎠ ∈ . ar1 ar2 ... arb dr W.l.o.g. let d1 = ... = ds = 0 and ds+1 = ... = db = 1. Since (0, ..., 0) ∈ , only the following two cases are possible: Case 1: s = 0. Since hb−1 (x1 , ..., xb ) = 1 ⇐⇒ (∃i : xi ∈ E2 ∧ (∀j = i : xj = 1))
(10.3)
and (1, ..., 1) ∈ (because of c1 ∈ M ∩ T0,b ), we have ⎛ ⎞ 0 1 ... 1 1 ⎜ 1 0 ... 1 1 ⎟ ⎜ ⎟ ⎜ . . . . . . . . . . . ⎟ ⊆ A ⊆ . ⎜ ⎟ ⎝ 1 1 ... 0 1 ⎠ 1 1 ... 1 0 With the help of xy ∈ M ∩ T0,b this implies = E2r \{(1, ..., 1)}, in contradiction to P ol = M ∩ T0,b . Case 2: 1 ≤ s ≤ b − 1. Because of (10.3), w.l.o.g., we can assume ⎛ ⎞ a11 a12 ... a1s a1,s +1 ... a1b ⎜ ............................. ⎟ ⎜ ⎟ ⎜ as1 as2 ... ass as,s +1 ... asb ⎟ ⎜ ⎟ 1 ... 1 ⎟ A=⎜ ⎜ 0 1 ... 1 ⎟. ⎜ 1 0 ... 1 ⎟ 1 ... 1 ⎜ ⎟ ⎝ ............................. ⎠ 1 1 ... 0 1 ... 1 This yields
⎛
a1b ⎜ ... ⎜ ⎜ asb hb (A, ⎜ ⎜ 1 ⎜ ⎝ ... 1
⎞
⎛
d1 ⎜ ... ⎟ ⎜ ⎟ ⎜ ⎟ ⎟) = ⎜ ds ⎜ ds+1 ⎟ ⎜ ⎟ ⎝ ... ⎠ dr
⎞ ⎟ ⎟ ⎟ ⎟, ⎟ ⎟ ⎠
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10 The Relation Degree and the Dimension of Subclasses of Pk
in contradiction to hb ∈ P ol and (d1 , ..., dr ) ∈ . Lemma 10.2.6 Let A = [A] ⊂ T1 and x ∧ y ∈ A. If A = P ol , then contains an 1-row. Proof. The relation cannot contain a 0-column because of A ⊂ T1 . If does not contain a 1-row then there are certain aij ∈ E2 with ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ 0 a12 a1h ⎜ a21 ⎟ ⎜ 0 ⎟ ⎜ a2h ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ a31 ⎟ , ⎜ a32 ⎟ , ..., ⎜ a3h ⎟ ∈ . ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎝ ... ⎠ ⎝ ... ⎠ ⎝ ... ⎠ ah1 ah2 0 Since x ∧ y ∈ A, contains then a 0-column, however, contrary to the above remark. Lemma 10.2.7 dim T0,b ∩ T1 ≥ b + 1 for b ≥ 2. Proof. Denote a relation of smallest arity with P ol = T0,b ∩ T1 . W.l.o.g., by Lemma 10.2.6, we can assume = (1) × , where obviously T0,b ∩ T1 ⊂ P ol and P ol ⊆ T1 hold. It results, then, from the structure of Post’s graph that P ol = T0,b holds. This and Lemma 8.2.4 imply dim T0,b ∩ T1 ≥ b + 1. Analogously, one can prove the following lemma. Lemma 10.2.8 dim T0,b ∩ M ∩ T1 ≥ b + 2 for b ≥ 2. Lemma 10.2.9 dim K ∪ C1 ≥ 4. Proof. By Lemma 10.2.6, every relation with P ol = K ∪ C1 contains an 1-row. If one scrutinizes the possibilities for the h-ary relations with h ≤ 3, one receives P ol = K ∪ C1 . Lemma 10.2.10 dim K ∪ C0 ≥ 4. Proof. dim K ∪ C0 ≥ 3 follows from Lemma 10.2.2. Assume that P ol = K ∪ C0 holds for a certain ternary relation . Obviously, cannot contain an 1-column. Hence, one also does not find any r1 , r2 , r3 ∈ with r1 (r2 ∨r3 ) ∈ . Thus, T0,∞ ∩M ∩T1 ⊆ P ol holds, in contradiction to K ∪C0 ⊂ T0,∞ ∩M ∩T1 . Lemma 10.2.11 dim K ≥ 5. Proof. Obviously, dim K ≥ 3. Assume an h-ary relation (h ∈ {3, 4}) exists without double rows and with P ol = K. The relation does not contain certainly a 0-column nor an 1-column. Furthermore, w.l.o.g. by Lemma 10.2.6, we have = (1) × , where P ol ⊃ K. If one scrutinizes the possibilities for P ol with the aid of the Post’s graph and of Lemma 10.1.1, one receives a contradiction.
10.2 The Dimensions and Relation Degrees of Post’s Classes
299
Lemma 10.2.12 dim L ≥ 4. Proof. Because of Lemma 10.2.2, class L cannot be described with the aid of a unary or binary relation. Assume there is a ternary relation with L = P ol . Because of c0 , c1 , x ∈ L we have ⎛ ⎞ 0 1 ⎝0 1⎠⊆ 0 1 and
⎛
⎞ ⎛ ⎞ a a ⎝ b ⎠ ∈ =⇒ ⎝ b ⎠ ∈ . c c
Furthermore, can not contain any double rows. This implies that the relation has three linearly independent columns. Hence, because of x + y ∈ L, we have = E23 , in contradiction to L = P ol . Lemma 10.2.13 dim L ∩ S ≥ 4. Proof. Proving dim L ∩ S = 3 suffices. Assume that L ∩ S = P ol holds for a certain ternary relation . Because of c0 , c1 ∈ L ∩ S and x ∈ L ∩ S we have (a, a, a) ∈ for a ∈ E2 and ⎛ ⎞ ⎛ ⎞ a a ⎝ b ⎠ ∈ =⇒ ⎝ b ⎠ ∈ . c c Then, w.l.o.g., has the form ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ 1 0 1 0 0 1 1 0 0 1 0 1 1 = ⎝ 0 1 ⎠ , 2 = ⎝ 0 1 1 0 ⎠ or 3 = ⎝ 0 1 1 0 0 1 ⎠ . 0 1 0 1 0 1 0 1 0 1 1 0 Since P ol 1 = P ol 2 = S and P ol 3 = [{x}], we obtain a contradiction to the supposition. Lemma 10.2.14 dim L ∩ S ∩ T1 ≥ 4. Proof. Since x + y + z ∈ L ∩ S ∩ T1 , for all columns s of the relation with P ol = L ∩ S ∩ T1 we have: s, s + 1 ∈ =⇒ ∀t ∈ : s + t + (s + 1) = t + 1 ∈ (s + 1 := (s1 + 1, ..., sh + 1) if s := (s1 , ..., sh )). Because of x + 1 ∈ L ∩ S ∩ T1 this implies s ∈ =⇒ s + 1 ∈ . By this and by (a, a, a) ∈ (a ∈ E2 ), if is ternary, then can have at most three different columns. Now one easily checks that the clone L∩S ∩T1 cannot be described by a such ternary relation.
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10 The Relation Degree and the Dimension of Subclasses of Pk
Lemma 10.2.15 dim I ∪ C ≥ 4. Proof. Because of Lemma 10.2.2, it is sufficient to show that dim I ∪ C = 3 holds. Since the classes [P21 ], K ∪ C and D ∪ C are the direct predecessors of I ∪ C, every ternary relation with P ol = I ∪ C has w.l.o.g. the following four properties: ⎛ ⎞ 0 1 ⎝ 0 1 ⎠ ⊆ ⊂ E23 , 0 1 ⎛ ⎞ ⎛ ⎞ a a ∃a, b, c ∈ E2 : ⎝ b ⎠ ∈ ∧ ⎝ b ⎠ ∈ (by x ∈ P ol ), c ⎞ c ⎛ ⎞ ⎛ 0 1 0 ⎝ 1 0 ⎠ ⊆ ∧ ⎝ 0 ⎠ ∈ (by x ∧ y ∈ P ol ), ⎛1 1⎞ ⎛1⎞ 1 0 1 ⎝ 0 1 ⎠ ⊆ ∧ ⎝ 1 ⎠ ∈ (by x ∨ y ∈ P ol ). 0 0 0 Apparently there is no relation that fulfills all four of these conditions. Thus dim I ∪ C ≥ 4. Now, in summarizing, we obtain the statements of the following theorem as consequences of Lemmas 10.2.1–10.2.15 and from the above remarks (before Table 10.1).
Theorem 10.2.16 For an arbitrary subclass A of P2 and t ≥ 6 the following holds: dim(A) = 0 ⇐⇒ A = P2 , dim(A) = 1 ⇐⇒ A ∈ {T0 , T1 }, dim(A) = 2 ⇐⇒ A ∈ {M, S, Ta,2 , T0 ∩ T1 | a ∈ E2 }, dim(A) = 3 ⇐⇒ A ∈ { M ∩ Ta , S ∩ T0 , S ∩ M, M ∩ Ta,2 , Ta ∩ Ta,2 , L ∩ Ta , K ∩ C, I, I ∪ Ca , I, [P21 ]}, dim(A) = 4 ⇐⇒ A ∈ { I ∪ C, M ∩ T0 ∩ T1 , L, L ∩ S, L ∩ S ∩ T0 , K ∪ Ca , Ta,4 , Ta ∩ Ta,3 , M ∩ Ta,4 , Ta ∩ M ∩ Ta,2 | a ∈ E2 }, dim(A) = 5 ⇐⇒ A ∈ {K, Ta,5 , Ta ∩ Ta,4 , M ∩ Ta,4 , Ta ∩ M ∩ Ta,3 | a ∈ E2 }, dim(A) = t ⇐⇒ A ∈ {Ta,t , Ta,t−1 ∩ Ta , Ta,t−1 ∩ M, Ta,t−2 ∩ M ∩ Ta | a ∈ E2 }, dim(A) = ∞ ⇐⇒ A ∈ {C, Ca , Ta,∞ , Ta,∞ ∩ Ta , Ta,∞ ∩ M, Ta,∞ ∩ M ∩ Ta | a ∈ E2 }.
10.3 Further Examples of the Dimension and Relation Degree of Classes
301
Theorem 10.2.17 For an arbitrary subclass A of P2 and t ≥ 5 the following holds: (a) d(A) = 0 ⇐⇒ A = P2 , d(A) = 1 ⇐⇒ A ∈ {T0 , T1 , T0 ∩ T1 }, d(A) = 2 ⇐⇒ A ∈ { M, S, Ta,2 , S ∩ T0 , M ∩ Ta , S ∩ M, Ta,2 ∩ Ta , Ta,2 ∩ M, M ∩ T0 ∩ T1 , Ta,2 ∩ M ∩ Ta | a ∈ E2 }, (b) d(A) = 3 ⇐⇒ A ∈ { L ∩ Ta , K ∪ C, D ∪ C, I, I ∪ I, I ∪ Ca , [P21 ], Ta,3 , I ∪ C, K ∪ Ca , D ∪ Ca , Ta,3 ∩ M, Ta,3 ∩ Ta , Ta,3 ∩ M ∩ Ta , L ∩ S ∩ T0 , K, D | a ∈ E2 }, (c) d(A) = 4 ⇐⇒ A ∈ {L, L ∩ S, Ta,4 , Ta,4 ∩ M, Ta,4 ∩ Ta , Ta,4 ∩ M ∩ Ta | a ∈ E2 }, (d) d(A) = t ⇐⇒ A ∈ {Ta,t , Ta,t ∩ Ta , Ta,t ∩ M, Ta,t ∩ M ∩ Ta | a ∈ E2 }, (e) d(A) = ∞ ⇐⇒ A ∈ {C, Ca , Ta,∞ , Ta,∞ ∩Ta , Ta,∞ ∩M, Ta,∞ ∩M ∩Ta | a ∈ E2 }. Proof. It is easy to check that the functions of M ∩ S preserve every unary and binary relation on E2 . Consequently, we have for an arbitrary subclass A of P2 : d(A) ≤ 2 ⇐⇒ S ∩ M ⊆ A. Thus, (a) follows from the definitions of the given classes, and d(A) ≥ 3 holds for the remaining classes A. (b) results from the descriptive relations of the classes given in Table 10.1 or from their definitions, with the aid of P ol ∩ P ol = P ol × = P ol {, }. (c) and (d) one can easy prove by means of the Post’ graph and with the aid of (a), (b) and Lemma 10.1.1. (e) follows from Lemma 10.1.1, (c) and Theorem 10.2.16.
10.3 Further Examples of the Dimension and Relation Degree of Classes We come now to the dimensions and relation degrees of some subclasses of Pk . The following theorem supplies simple examples first. Theorem 10.3.1 ([Ros 70;a]) Let A be a maximal class of Pk (k ≥ 2), i.e., there exists a ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk with A = P ol (see Chapter 5). Then (a) d(A) = dim A;
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10 The Relation Degree and the Dimension of Subclasses of Pk
(b) d(A) = 1, if ∈ C1k ; d(A) = 2, if ∈ C2k ∪ Mk ∪ Sk ∪ Uk ; (c) d(A) = h, d(A) = k, (d) d(A) = 3, d(A) = 4,
if if if if
h ∈ {3, 4, ..., k − 1} and ∈ Chk ∪ Bhk ; A = P olιkk and k ≥ 3; ∈ Lk , k = pm and p = 2; ∈ Lk , k = pm and p = 2.
Proof. (a) follows from Lemma 10.1.1, (e). (b) results immediately from the definitions of the corresponding classes P ol . (c): Since every h-ary relation with ∈ Chk ∪ Bhk for h ≤ k − 1 and = ιkk for h = k contains the set ιhk , all functions, which take at most h − 1 different values, belong to P ol. Consequently, one cannot describe the class P ol in this case with the aid of (h − 1)-ary relations. (d): Let k = pm (p prime, m ≥ 1), (Ek , +, ·) a field with the zero element 0 and the unit element 1, = {(a, b, c, d) ∈ Ek4 | a + b = c + d} (i.e. ∈ Lk ), A := P ol, dim A = q and denote λ a certain q-ary relation with P olλ = A. Let be given the relation λ in the form of a matrix, whose rows are denoted with z1 , ..., zq . Obviously, λ does not have any double rows and q ≥ 2 holds. Further, we can interpret the rows (and/or the columns) of λ in natural manner as elements of a vector space V|λ| (or Vq ) over the field (Ek , +, ·), where the operations are defined as usual in matrix vector spaces. First we prove that dimA ≥ 3 for p = 2 and dim A = 4 for p = 2. Obviously, all q-ary functions f of the form f (x1 , ..., xq ) = a1 x1 + ... + aq xq belong to A for arbitrary a1 , a2 , ..., aq ∈ Ek . If the rows z1 , ..., zq are linear independent (i.e., there exist certain q linear independent columns s1 , ..., sq ∈ λ ⊆ Ekq ), then for every s ∈ Ekq there is a certain function f ∈ A with f (x1 , ..., xn ) = a1 x1 + ... + aq xq and f (s1 , ..., sq ) = s. Hence, λ = Ekq holds, in contradiction to A = P olλ ⊂ Pk . For the proof of dim A ≥ 3, if p = 2, and dim A = 4, if p = 2, we have only to show that the rows z1 , ..., zq (q = 2 for p = 2, q ∈ {2, 3} for p = 2) are linear independent. If q = 2 and if we assume that z1 = α · z2 (for certain α ∈ Ek \{0}), then a contradiction follows from g(x) := x + 1 ∈ A and from a 0 a a+1 ∀ ∈ λ\ :g = ∈ λ. α·a 0 α·a α·a+1 Consequently, for arbitrary p, we have dim A ≥ 3 and pri,j λ = Ek2 for all i, j ∈ {1, 2, ..., q} with i = j. Now let q = 3 and p = 2. Obviously, the columns
10.3 Further Examples of the Dimension and Relation Degree of Classes
⎛
⎞
⎛
⎞
⎛
⎞
303
1 1 c s1 := ⎝ 0 ⎠ s2 := ⎝ b ⎠ s3 := ⎝ 1 ⎠ a 0 0 belong to λ for certain a, b, c ∈ Ek . Then, because of x + 1, x2 ∈ A, we have ⎞ ⎛ ⎞ ⎛ 0 1 s4 := ⎝ 1 ⎠ ∈ λ, s5 := ⎝ 0 ⎠ ∈ λ. a+1 a2 Now one easily checks that s1 , s4 , s3 if a = 0, s1 , s4 , s2 if a = 1 and s1 , s5 , s3 if a ∈ {0, 1} are linear independent. Consequently, dim A = 4 holds in the case p = 2. Since ∆λ = {(a, b, c) ∈ Ek3 | a + a = b + c} obviously is not a diagonal relation, for p = 2, A ⊆ P ol∆λ and A is maximal in Pk , we have dimA = 3 in the case p = 2. It is surely a hopeless venture to determine the relation degree for all subclasses of Pk . Nevertheless, there are rather precise estimates for d(A) or dim(A) if A is an element of a certain sublattice of Lk . Subsequently, two examples are given for this fact. The following theorem is a direct consequence of generalizing the Baker-Pixley Theorem (see Theorem 8.3.1). Theorem 10.3.2 If a subclass A of Pk contains a certain n-ary function h with the properties h(x, y, ..., y) = h(y, x, y, ..., y) = ... = h(y, ..., y, x) = y for arbitrary x, y ∈ Ek and n ≥ 3, then d(A) ≤ n − 1 holds. As a consequence of theorems on linear and quasi-linear functions from Chapter 13 we get: Theorem 10.3.3 Let k = pm (p prime, m ≥ 1), (Ek , +, ·) a field and λ := {(a, b, c, d) ∈ Ek4 | a + b = c + d}. Then, for every subclass A ⊆ P olk λ, which contains the function r with r(x, y, z) = x + y − z, the following holds: d(A) = 3 for p = 2, 3 ≤ d(A) ≤ 4 for p = 2, 3 ≤ dimA ≤ 6 for p = 2 and 3 ≤ dimA ≤ 7 for p = 2.
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10 The Relation Degree and the Dimension of Subclasses of Pk
In preparation for Theorem 10.3.7 with statements about subclasses of [Pk1 ], we subsequently prove three lemmas. 3 3 Lemma 10.3.4 Let µ := δ{1,2} ∪ δ{2,3} . Then P olµ = [Pk1 ].
Proof. Obviously, P olµ ⊆ [Pk1 ]. “=” follows from Theorem 1.4.4, (a), (c). Lemma 10.3.5 Let
ν := {(x, y) ∈ Ek2 | x = y}.
Then P olν = [Pk1 [k]]. Proof. Obviously, (P olν)1 = Pk1 [k]. Assume there exists an n-ary function f ∈ P ol = ν that depends on at least two variables essentially. Then f takes exactly k different values and, by Theorem 1.4.4, (c) one can find certain ri := (r1i , ..., rki ) ∈ ιkk (i = 1, ..., n) with f (r1 , ..., rn ) ∈ Ekk \ιkk . If one chooses ai ∈ Ek \{r1i , ..., rki } (i = 1, ..., n) now, there is so a j ∈ {1, ..., k} with f (rj1 , ..., rjn ) = f (a1 , ..., an ). Since (rji , ai ) ∈ ν for all i ∈ {1, ..., n}, f does not preserve the relation ν, contrary to the assumption. Thus P olν = [Pk1 [k]]. Lemma 10.3.6 Let k ≥ 3 and denote ω the binary relation {(0, 1), (1, 0), (0, x), (x, 1), (y, y + 1) | x ∈ Ek \{0, 1} ∧ y ∈ Ek \{0, 1, k − 1}}. Then for an arbitrary function f n ∈ Pk the following holds: f n ∈ P olω =⇒ ∃i : f n = eni .
(10.4)
(I.e., the projections are the only functions of Pk , which preserve ω.) Proof. We write a ≺ b instead of (a, b) ∈ ω. Furthermore, for arbitrary a, b ∈ Ekn let be: a ≺ b :⇐⇒ ∀i ∈ {1, ..., n} : ai ≺ bi . Denote f an arbitrary n-ary function of P olω in the following. Then the function f|{0,1} belongs to M ∩ S, since one can derive the relations 0 1 0 0 1 and 1 0 0 1 1 from ω as follows: 0 0 1 0 1 2 ω ∩ (τ ω) = , pr1 (ω ∩ (τ ω)) = E2 , (ω ◦ ω) ∩ E2 = 0 1 1 1 0 Because of f|{0,1} ∈ M ∩ S one can find (w.l.o.g.) two tuples a := (0, 0, ..., 0, 1 , 1, ..., 1) and i
b := (1, 0, ..., 0, 1 , 1, ..., 1) i
10.3 Further Examples of the Dimension and Relation Degree of Classes
305
with f (a) = 0 and f (b) = 1. Now we want to prove the following statements: f|{0,1} = en1 ,
(10.5)
∀α ∈ {0, 1} : f (α, x2 , ..., xn ) = α,
(10.6)
∀β ∈ Ek \{0, 1} : f (β, x2 , ..., xn ) = β.
(10.7)
For this purpose we consider the tuples u := (d, 1, ..., 1, 0 , 0, ..., 0), i
v := (1, 0, ..., 0, d , d, ..., d), i
w := (0, d, ..., d, 1 , 1, ..., 1) i
for a certain d ∈ Ek \{0, 1} and z := (0, 1, 1, 1, ..., 1). Then a ≺ u ≺ b and u ≺ v ≺ w ≺ u. Consequently, we have f (u) ∈ Ek \{0, 1}, f (v) = 1 and f (w) = 0. Then, by v ≺ z, f (z) = 0 holds. Since f|{0,1} ∈ S ∩ M , (10.5) follows obviously from f (z) = 0. Furthermore, for an arbitrary tuple x ∈ Ekn there are tuples y, y with y ≺ x ≺ y and ⎧ ⎨ (1, 1) if x1 = 0, (y1 , y1 ) = (0, 0) if x1 = 1, ⎩ (0, 1) if x1 ∈ Ek \{0, 1}. Because of f (y) ≺ f (x) ≺ f (y ) and by (10.5) the statement (10.6) and f (x) ∈ Ek \{0, 1} if x1 ∈ Ek \{0, 1}
(10.8)
result from that. For every tuple x ∈ Ekn with x1 ∈ Ek \{0, 1} one can find k − 2 tuples x2 , x3 , ..., xk−1 with the properties xi = (i, xi2 , ..., xin ) (i = 2, 3, ..., k − 1), xx1 = x and x2 ≺ x3 ≺ ... ≺ xk−1 . (To a given tuple x one can construct the tuples xi as follows, for example, xx1 −1,j := xj =: xx1 +1,j for xj ∈ {0, 1}, xx1 −1,j = 0 and xx1 +1,j = 1 for xj ∈ Ek \{0, 1} (j = 2, ..., n), etc.) Then f (x2 ) ≺ f (x3 ) ≺ ... ≺ f (xk−1 ) and f (xi ) ∈ Ek \{0, 1} (i = 2, ..., k − 1) because of (8). This is, however, possible only for f (xi ) = i for all i ∈ {2, ..., k− 1}. Thus (10.4) is right and our lemma was proven.
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10 The Relation Degree and the Dimension of Subclasses of Pk
Theorem 10.3.7 (1) Let A be a subclass of [Pk1 ] with e11 ∈ A. Then (a) d(A) = 3 and 3 ≤ dimA ≤ 4 for k = 2; (b) 2 ≤ d(A) ≤ k and 2 ≤ dimA ≤ k + 3 for k ≥ 3. (2) dim[Pk1 ] = d([Pk1 ]) = 3 and d(A) = dimA =
3 if k = 2, 2 if k ≥ 3
for every A ∈ {[Pk1 [k]], [e11 ]}. Proof. For k = 2, we have the statements of the theorem already proven (see Theorems 10.2.16 and 10.2.17). Let k ≥ 3 in the following. Then, obviously, d(A) ≥ 2 for all classes A ⊆ [Pk1 ] with e11 ∈ A. By Lemma 10.3.4 and because of A1 = (P olG1 (A))1 we have, furthermore, for every A ∈ Vk (e11 , [Pk1 ]): A = P ol{G1 (A), µ} = P olG1 (A) × µ. Thus (b) holds. The statements of (2) follow from Lemmas 10.3.5 and 10.3.6 and from the fact that only the diagonal relations of the binary relations preserve all functions of Pk1 .
11 On Generating Systems and Orders of the Subclasses of Pk
If A = [A] ⊆ Pk is finitely generated, we call the smallest number r with [Ar ] = A the order of A. In the case that the subclass A ⊆ Pk is not finitely generated, we write ord A = ∞. During the study of subclasses of Pk or during the solution of problems in the multi-valued logics, one often deals with constructing generating systems for the considered classes. Statements about the order of the considered classes often result from these investigations. Therefore, one finds results about the order of subclasses of Pk not only in this chapter, but also in other chapters of this book. First, some general statements about the orders of subclasses of Pk are declared in this chapter. Then we occupy ourselves with the orders of the maximal classes of Pk . It turns out, in this case, that only certain maximal classes of the type M do not have any finite order. If ∈ Mk , we can prove ord P olk = 2 only for k ≤ 7 and for the case where (Ek ; ) is a lattice. By means of an example proven by G. Tardos in [Tar 86], we will be able to show, however, that for k ≥ 8 there are classes of the type M with the order ∞. If one has a finite generating class A, it is an interesting problem to clear which cardinalities are possible for the bases of this class A. In Section 11.2, we show only that the proof for ord P olk ≤ 3, where ∈ C1k ∪ Uk ∪ Sk , implies the existence of functions f with [f ] = P olk . Following corresponding notation for functions from Pk , such function f is called a Sheffer-function for P olk . We notice, through the theorems of Section 12.2, Schofield’s Theorem 7.1.4 is also proven. The last section explains shortly, as one can determine the cardinalities of the possible bases of the class A, if ord A < ∞. Further, some basic ideas of [Miy 71], [Miy-S-L-R 86], [Miy 88] and [Sto 87] are explained about basis classifications. For more information on the topic, refer to the books [Miy 88] and [Sto 87] by M. Miyakawa and I. Stojmenovic.
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11 On Generating Systems and Orders of the Subclasses of Pk
11.1 Some General Properties of Generating Systems and Bases The following theorem is a consequence of [Coh 65, Th. 5.4]: Theorem 11.1.1 ([Jab 74]) Let A be a subclass of Pk . Then the following conditions are equivalent: (1) A is finitely generated. (2) A has only finitely many maximal classes (with other words: The lattice L↓k (A) is dualatomar). (3) For every chain of the form A1 ⊆ A2 ⊆ A3 ⊆ ... ⊆ An ⊆ ... ⊆ A with ∪n≥1 An = A there exists an n ∈ N with An = A. Theorem 11.1.2 (a) Each subclass of P2 is finitely generated. For every n ∈ N exists a subclass A ⊆ P2 with ord A = n. (b) For k ≥ 3 there are subclasses of Pk that do not have any basis or have an infinite basis ([Jan-M 59]). Proof. (a) follows from Chapter 3. (b): Let k ≥ 3. One can find a subclass of Pk with an infinite basis in Lemma 8.1.1. The set A := [{f1 , f2 , f3 , ...}], where 1 if x1 = ... = xn = 2, fn (x1 , ..., xn ) := 0 otherwise, is an example of a class without basis, since fn fm = cm+n−1 and ∆fn+1 = fn 0 for arbitrary m, n ∈ N. The following theorem is easy to check. Theorem 11.1.3 (a) If A is a maximal class of B ⊆ Pk , then ord A < ∞ =⇒ ord B < ∞. (b) For arbitrary subclasses A, B of Pk it holds: ord[A ∪ B] ≤ max{ord A, ord B}.
11.1 Some General Properties of Generating Systems and Bases
309
As the following theorem shows, no connection exists between the existence of a finite relation degree (see Chapter 10) and the existence of a finite order of a subclass of Pk . Theorem 11.1.4 ([P¨ os-K 79]) There are subclasses A, B, C of Pk with the properties: (a) d(A) = ∞ and ord A < ∞. (b) d(B) < ∞ and ord B = ∞. (c) d(C) = ∞ and ord C = ∞. Proof. An example for a class A is the set T0,∞ (see Chapter 3). (b) follows from Theorem 11.5.5. One can find an example of a class C in the book [P¨ os-K 79], p. 97. Despite the above theorem, the juxtaposition of the orders and the relation degrees of classes is quite interesting (see [P¨os-K 79], p. 94–97). The main aim of the following sections is to prove the following theorem. Theorem 11.1.5 (Theorem on the Orders of the Maximal Classes) (1) Let ∈ Mk . If 2 ≤ k ≤ 7 and (Ek ; ) is a lattice, then ord P olk = 2. For k ≥ 8 there is a certain ∈ Mk with ord P olk = ∞. (2) For every ∈ Sk it holds: ord P olk :=
3 if k = 2, 2 otherwise.
(3) If ∈ Uk ∪ Lk ∪ Bk , then P olk = 2. (4) Let γ be an h-ary relation of Ck . Then 2 ≤ ord P olk γ ≤ max(2, h). For k = 3, this theorem, already, was proven in 1962 by M. N. Gnidenko (see e.g. [Gni 65]). We need the following theorem for proof of Theorem 11.1.5. Theorem 11.1.6 Let T ⊆ Ek with |T | ≥ 2, Pk,T := {f ∈ Pk | W (f ) ⊆ T } and 2 ≤ l ≤ k. Then (a) ord Pk,T = 2, (b) ∃f ∈ Pk,T : [f ] = Pk,T ,
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(c) ord Pk (l) = 2. Proof. In the case that T = Ek is valid, the above theorem is, already, proven(see Theorems 1.4.2 and 7.1.6). If |T | ≤ k − 1, then we can assume T = El w.l.o.g., through which the statement (a) follows from Lemma 12.2.1 and (b) from Theorems 12.2.7 and 7.1.6. (c) follows from (a).
11.2 The Orders and Sheffer-Functions of the Classes of Type C1 , S or U The aim of this section is to prove that all maximal classes of type X ∈ {C1 , S, U} have the order 2 for k ≥ 3 and that for every one of these classes, Sheffer-functions exist. We remark that all other maximal classes do not have any Sheffer-functions (see Theorem 7.1.4). Theorem 11.2.1 ([Sch 69], [Kud 70]) Let ∈ C1k . Then (a) ord P olk = 2 (b) ∃f : [f ] = P olk . Proof. W.l.o.g. let = El with 1 ≤ l ≤ k − 1. Further, let A := P olk El . We distinguish two cases: Case 1: l = 1. In this case, A is the set of all 0-preserving functions of Pk , and it is possible to describe an arbitrary function f n ∈ A with the help of functions x ∨ y := max(x, y), x · y := min(x, y) (in respect to the order relation 0 < 1 < ... < k − 1), b if x = a, ja;b (x) := 0 otherwise (a, b ∈ Ek ) as follows: f (x1 , x2 , ..., xn ) =
ja1 ;f (a) (x1 )·ja2 ;f (a) (x2 )·...·jan ;f (a) (xn ).
a = (a1 , ..., an ) ∈ Ekn \{(0, 0, ..., 0)} f (a) = 0
Consequently, B := {∨, ·} ∪
{ja;b (x) · jc;b (y)} (⊆ A)
a,b∈{1,2,...,k−1}, c∈Ek
is a generating system for A and hence ord A = 2. To prove (b) for the first case let
11.2 The Orders and Sheffer-Functions of the Classes of Type C1 , S or U
ja,b;t (x, y) := ja;t (x) · jb;t (y) = and
t if (x, y) = (a, b), 0 otherwise,
la;t (x, y, z) := j0;k−1 (x) · ja;t (y) · ja;t (z) =
311
t if (x, y, z) = (0, a, a), 0 otherwise.
With the help of these functions, a function g ∈ A can be described as follows: g(..., xa,b;t , ya,b;t , ..., ua;t , va;t , wa;t , ...) :=
ja,b;t (xa,b;t , ya,b;t ) (a, b, t) 2 ∈ Ek ×{1, 2, ..., k −1} a = b
∨
la;t (ua;t , va;t , wa;t ). (a, t) 2 ∈ {1, 2, ..., k − 1}
If one identifies all variables in the function g, then one obtains the constant function c0 . One obtains an arbitrary binary function of A if one replaces certain variables of the form ua;t by c0 in g and identifies certain other variables of g. Thus ord A in Case 1. Case 2: l ≥ 2. Let f n be an arbitrary function of A and let f1n ∈ Pk,l with f (a) = f1 (a) for all a ∈ Eln . With the help of f1 , the above-defined functions ∨, ·, ja,b and the function l − 1 if x ∈ El , l(x) := 0 otherwise, one can describe f as follows: f (x1 , x2 , ..., xn ) = f1 (x1 , ..., xn ) · l(x1 ) · ... · l(xn ) ∨ ja1 ;f (a) (x1 ) · ja2 ;f (a) (x2 ) · ... · jan ;f (a) (xn ). a = (a1 , ..., an ) ∈ Ekn \Eln f (a) = 0
Consequently, for every set B1 ⊆ Pk,l ⊂ A with [prl B1 ] = Pl , the set B := B1 ∪ {∨, ·, l} ∪ {ja;b (x) · jc;b (y)} (⊆ A) a∈Ek \El , b,c∈Ek
is a generating system for A. From this, Lemma 12.2.1 and Theorem 1.4.2 it follows that ord A = 2. Since Pk,l has a Sheffer-function tm (see Theorems 12.2.7 and 7.1.6), one can prove analogously to the first case that the function h with
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h(x1 , ...., xm , xm+1 , ..., xa,b;t , ya,b;t , ..., ua;t , va;t , wa;t , ...) := t(x1 , ..., xm ) · l(xm+1 ) ∨ g(..., xa,b;t , ya,b;t , ..., ua;t , va;t , wa;t , ...) is a Sheffer-function for A. Theorem 11.2.2 ([Sch 69]) Let k ≥ 3 and ∈ Uk . Then (a) ord P olk = 2 (b) ∃f : [f ] = P olk . Proof. The nontrivial equivalence relation on Ek decomposes the set Ek in the (pairwise distinct) equivalence classes A0 , A1 , ..., Ak −1 (k < k). We select a representative ai from every equivalence class Ai and define the function q ∈ Pk1 by ∀i ∈ Ek : q(x) = ai :⇐⇒ x ∈ Ai . Let now f n be an arbitrary function of P olk . With the help of functions z, fi , gf ∈ P olk defined in Lemma 1.4.6, one can describe f as follows: f (x) = ((...((gf (x) f0 (x)) f1 (x))... fk −1 (x))
(11.1)
Furthermore, by Section 5.2.3, there exists a function h ∈ P{a0 ,a1 ,...,ak } with gf (x) = h(q(x1 ), ..., q(xn )).
(11.2)
It is easy to check that the set of all functions of the form (11.2) is isomorphic to Pk ; thus the functions of this set are superpositions over the binary functions of this set. Consequently, (11.1) and ord Pk,Ai = 2 (see Theorem 11.1.6) implies ord P olk = 2. Let p2 be a Sheffer-function for P{a0 ,a1 ,...,ak −1 } and let rim be a Shefferfunktion for Pk,Ai (i = 0, 1, ..., k − 1) 1 . Then one can form the functions p(q(x), q(y)), ri (x1 , ..., xm ) (i = 0, 1, ..., k − 1) and z as superpositions over the function s(x, y, x0,1 , x0,2 , ..., x0,m , x1,1 , ..., x1,m , ..., xk −1,1 , ..., xk −1,m ) := (...((p(q(x), q(y)) r0 (x0,1 , ..., x0,m )) r0 (x1,1 , ..., x1,m ))...
as follows: 1
rk −1 (xk −1,1 , ..., xk −1,m )) (11.3)
See Theorem 12.2.7 for the existence of such Sheffer-functions.
11.2 The Orders and Sheffer-Functions of the Classes of Type C1 , S or U
313
When one carries out only replacements of the variables x or y, one can copy the formation of superpositions in P{a0 ,a1 ,...,ak −1 } over s. Therefore one obtains functions of the form (11.3) as superpositions over s, where p is an 2 arbitrary function of P{a } . Because of 0 ,a1 ...,a k −1
(...((cai (q(x1 ), q(x2 )) r0 (x1 , ..., xm )) r0 (x1 , ..., xm ))... rk −1 (x1 , ..., xm )) = ri (x1 , ..., xm ) k −1 in particular Pk,Ai ⊆ [s] results. If one inserts functions of i=0 Pk,Ai into the function s, one also obtains the functions z and p(q(x), q(y)) as superpositions over s. Thus we have [s] = P olk and (b) holds. Theorem 11.2.3 ([Sch 69], [Lau 78a]) For arbitrary s ∈ Sk is valid: (a) 3 if k = 2, ord P olk s = 2 otherwise. (b) ∃f : [f ] = P olk s . Proof. Let s ∈ Sk be defined as in Section 5.2.2. Since our assertion was prove in Chapter 3 for k = 2, we can assume k ≥ 3 in the following. (a): Because of Chapter 7, all functions g(x1 , x2 ) :=
p−1 l
jar,i (x1 ) · si (G(sp−i (x2 )) (mod k),
r=1 i=0
with G ∈ Pk1 and a function h(x1 , x2 , x3 ) :=
p−1 l
jar,i (x1 ) · si (H(sp−i (x2 ), sp−i (x3 ))) (mod k),
r=1 i=0
where H ∈ Pk \[Pk1 ] and |Im(H)| = k, form a generating system for the functions of the form u(x1 , x2 , ..., xm ) :=
p−1 l r=1 i=0
jar,i (x1 ) · si (U (sp−i (x2 ), ..., sp−i (xm ))) (mod k)
(11.4) (U ∈ Pkm−1 , m ≥ 2). Let now f n be an arbitrary function of P olk s (n ≥ 3). We show that f ∈ [(P olk 3 )2 ] is valid. For this purpose, we choose in (11.4) the function U as follows: Fr (x2 , ..., xn ) if x1 = ar,0 , r = 1, 2, ..., l, U (x1 , ..., xm ) := 0 otherwise,
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11 On Generating Systems and Orders of the Subclasses of Pk
where F1 , ..., Fl are the components of f from (5.4). Furthermore, let the function v be defined by v(x) :=
p−1 l
jar,i (x) · si (ar,0 ) ∈ (P olk s )1 .
r=1 i=0
Then
u(x1 , v(x1 ), x2 , ..., xn ) = f (x1 , ..., xn )
holds. Consequently, we have [(P olk s )2 ∪ {h}] = P olk s . Next we give a function that is a superposition over (P olk s )2 and which fulfills the conditions listed above for the function h. For this purpose, we choose a binary function w with the components ⎧ x = a1,0 ∧ p > 2, ⎪ ⎪ a1,1 if ⎨ x = a1,0 ∧ p = 2, a2,0 if W1 (x) = ... = Wl (x) = W (x) := if x = a1,1 , a ⎪ 1,0 ⎪ ⎩ x otherwise. One now easily checks that W w ∈ Pk \ [Pk1 ] and |Im(W w)| = k are valid. (b): With the aid of the above considerations, we can easily prove that the function t(x, x1 , y1 , x2 , y2 , ...xl , yl ) :=
p−1 l
jar,i (x)·si (T (sp−i (xr ), sp−i (yr ))) (mod k),
r=1 i=0
where [T ] = Pk , is a Sheffer-function for P olk s .
11.3 Orders of the Classes of Type L, C, B The following theorem results immediately from Section 5.2.4: Theorem 11.3.1 ([Ros 70a]) For every ∈ Lk is valid ord P olk = 2.
Theorem 11.3.2 ([Lau 78a]) For every ∈ Bk is valid ord P olk = 2. Proof. Subsequently, we describe the functions from the clone P olk ( ∈ Bk ) as in Section 5.2.6. Because of (5.14) and (5.16), an arbitrary function f n ∈ P olk is a superposition over the functions r(fi ), z, fj (i = 0, 1, ..., m−1, j = 0, 1, 2, ..., hm − 1) and m H(x1 , ..., xm ) := r( q(xi ))(0) · hm−i ). i=1
11.3 Orders of the Classes of Type L, C, B
315
Every function of the form r(fi ) or fj belongs either to [(P olk )1 ] or to [(P olk )2 ] because of Theorem 11.1.6. Consequently, we must still prove H ∈ [(P olk )2 ]. The following functions belong to P olk : t Ht (x1 , ..., xt ) := r( i=1 q(xi ))(0) · hm−i ) t Ht (x1 , x2 )) := r( i=1 q(x1 ))(m−i) · hm−i + (q(x2 ))(0) · hm−t−1 ) (1 ≤ t ≤ m − 1). Because of Ht Ht = Ht+1 the function H (= Hm ) is a superposition over (P olk )2 . For the rest of this section, let γ be an h-ary central relation on Ek with 2 ≤ h < k, and let C be the set of the central elements of γ. The short proof of the following theorem comes from R. P¨ oschel. Theorem 11.3.3 The clone P olk γ has a finite generating system. ! " Proof. Let c ∈ C. The following ( |γ|+1 + |γ| + 1)-ary function belongs to 2 P olk γ: h(x1 , x2 , ..., x|γ|+1 , (yij )i,j=1,2...,|γ|+1;i<j ) ⎧ ∃i, j : ((i < j) ∧ (xi = xj ) ∧ ⎨ yij if (∀s, t : ((s < t ∧ xs = xt ) ⇒ yst = yij ))), = ⎩ c otherwise. We prove by induction on the arity n of an arbitrary function f n ∈ P olk γ that [(P olk γ)|γ| ∪ {h}] = P olk γ holds. Obviously, our assertion is valid for all functions f n with n ≤ |γ|. Assume the assertion holds for all m-ary function of P olk γ, where m ≥ |γ|. Let f m+1 ∈ P olk γ be arbitrary. Denote fij the function, which can be formed from f by identifying of the i-th variable with the j-th variable, i = j, i = 1, 2, .., |γ| + 1. By induction assumption, we have fij ∈ [(P olk γ)|γ| ∪ {h}]. It is easy to check that f (x1 , x2 , ..., xm+1 ) = h(x1 , ..., x|γ|+1 , (fij (x))i,j=1,2,...,|γ|+1;i|j ). Thus f ∈ [(P olk γ)|γ| ∪ {h}]. Theorem 11.3.4 ([Lau 78a]) It holds = 2 if k − |C| ≤ h, ord P olk γ ≤ h otherwise. If γ fulfills the conditions k − |C| > h and (a0 , ..., ah−1 ) ∈ γ =⇒ ((a0 , ..., ah−1 ) ∈ ιhk ∨ (∃i ∈ Eh : ai ∈ C)), then ord P olk γ = # h2 $ + 1.
2
(11.5)
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11 On Generating Systems and Orders of the Subclasses of Pk
Proof. Below is a procedure comprising three steps. This procedure shows that an arbitrary function, which takes q ≥ 2 different values, is a superposition over the set (P olk γ)h ∪ (P olk γ ∩ (Pk (q − 1))). The iteration of this procedure takes back the construction of an arbitrary function to the construction of functions that take at most h − 1 different values. Since all such functions preserve the relation γ, we have ord P olk γ ≤ h by Theorem 11.1.6, (c). Let f n be an arbitrary function of P olk γ with n > 2 and let c be any fixed element of the set C, i.e., c is a central element of the relation γ. 1.) To dismantle o f , we need the n-ary functions f1 , f2 and the binary function g of P olk γ: f (x1 , ..., xn ) if f (x1 , ..., xn ) ∈ C, f1 (x1 , ..., xn ) := c otherwise, c if f (x1 , ..., xn ) ∈ C, f2 (x1 , ..., xn ) := f (x1 , ..., xn ) otherwise, ⎧ x1 ∈ C ∧ x2 = c, ⎨ x1 if x1 = c ∧ x2 ∈ C, x2 if g(x1 , x2 ) := ⎩ c otherwise. We get: f (x) = g(f1 (x), f2 (x)), where f2 ∈ Pk,C ⊂ [(P olk γ)2 ] by Theorem 11.1.6, (a). 2.) In the second step the function f1 is dismantled, where we use functions ha ∈ (P olk γ)2 , a ∈ Ek \C, defined as follows: ⎧ (x1 = c ∧ x2 = a) ∨ (x1 = a ∧ x2 = c), ⎨ a if x1 = x2 , ha (x1 , x2 ) := x1 if ⎩ c otherwise. Let Ea := {a ∈ Ekn | f1 (a) = a}. Further, for a ∈ Ea we put: ⎧ if x = a, ⎨a if x ∈ Ea \{a}, fa (x1 , ..., xn ) := c ⎩ f1 (x) otherwise. If Ea = {a1 , ..., as }, then there exists the following representation for f1 : f1 (x) = ha (...ha (ha (fa1 (x), fa2 (x)), fa2 (x))..., fas (x)). Similar to f1 , one can dismantle the functions fa . In this case, we choose a b ∈ Ek \(C ∪ {a}), put Eb := {b1 , ..., bt } and for b ∈ Eb we define ⎧ if x = b, ⎨b if x ∈ Eb \{b}, fa,b (x1 , ..., xn ) := c ⎩ fa (x) otherwise. 2
x denotes the greatest integer z with z ≤ x.
11.3 Orders of the Classes of Type L, C, B
317
Then the function fa has the representation fa (x) = hb (...hb (hb (fa,b1 (x), fa,b2 (x)), fa,b3 (x))...fa,bt (x)). Then, one dismantles the functions in analogous manner fa,b , and so forth. As a result, the function f1 is dismantled in certain functions ha;α ∈ P olk γ defined by α if x = a, ha;α (x1 , ..., xn ) := c otherwise, where α ∈ (Ek \C) ∪ {c} and a ∈ Ekn . 3.) In this step, we construct representations for the n-ary functions u ∈ P olk γ, which are defined by di if x = di , i = 1, 2, ..., q, u(x1 , ..., xn ) := c otherwise, where {d1 , ..., dq } ⊆ Ek \C, di = dj for i = j and di = (di1 , ..., dim ); i, j = 1, 2, ..., q. If q ≤ h − 1 and for the case that q = h and (d1 , ..., dq ) ∈ γ, we have u ∈ [(P olk γ)2 ]. Consequently, the following three cases must still be examined: Case 1: q = h and (d1 , ..., dq ) ∈ γ. In this case, there exists a j (1 ≤ j ≤ n) with (d1j , d2j , ..., dhj ) ∈ γ, since u ∈ P olk γ. Put d1 if x ∈ {d1 , d2 , ..., dh }, u1 (x1 , .., xn ) := c otherwise, and
u2 (x1 , x2 ) :=
di if x1 = dij ∧ x2 = d1 , i = 1, 2, ..., h, c otherwise.
Because of u1 , u2 ∈ P olk kγ and u(x) = u2 (xj , u1 (x)) we have u ∈ [(P olk γ)2 ]. Case 2: There is a set {e1 , e2 , ..., eh } ⊆ {d1 , ..., dq } with (e1 , ..., eh ) ∈ γ\ιhk . The functions ⎧ ei if x1 = ... = xi−1 = xi+1 = ... = xh = ei , ⎪ ⎪ ⎨ xi = c, i = 1, 2, ..., h, v(x1 , ..., xh ) := if x x ⎪ 1 1 = ... = xh ∈ {d1 , .., dq }\{e1 , ..., eh } ⎪ ⎩ c otherwise, and
vi (x1 , ..., xn ) :=
c if u(x1 , ..., xn ) = ei , u(x1 , ..., xn ) otherwise
(i = 1, 2, ..., h) belong to P olk γ. It is easy to check that u(x) = v(v1 (x), v2 (x), ..., vh (x)) holds, where |Im(vi )| < |Im(u)|.
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11 On Generating Systems and Orders of the Subclasses of Pk
Case 3: q > h and for an arbitrary set {e1 , e2 , ..., eh } ⊆ {d1 , ..., dq } it holds: (e1 , e2 , ..., eh ) ∈ γ \ ιhk . We need the functions ⎧ d2i−1 if x1 = ... = x[ h +1 = d2i−1 , i = 1, 2, .., # h2 $, ⎪ ⎪ 2 ⎪ ⎪ ⎪ d2i if x1 = ...xi−1 = xi+1 = ... = x h +1 = d2i , ⎪ 2 ⎪ ⎪ ⎪ xi = d2i−1 , i = 1, 2, .., # h2 $, ⎨ if h odd ∧ x1 = ... = x h +1 = dh , w(x1 , ..., x h +1 ) := dh 2 2 ⎪ ⎪ ⎪ d h+1 if x1 = ... = x h = dh+1 ∧ x h +1 = dh , ⎪ 2 2 ⎪ ⎪ ⎪ if x1 = ... = x h +1 ∈ {dh+2 , ..., dq }, x1 ⎪ ⎪ 2 ⎩ c otherwise, d2i−1 if u(x) ∈ {d2i−1 , d2i }, wi (x1 , ..., xn ) := u(x) otherwise (i = 1, 2, ..., # h2 $) and w h +1 (x1 , ..., xn ) := 2
dh if u(x) ∈ {dh , dh+1 }, u(x) otherwise,
of P olk γ for the dismantling of the function u. It holds: u(x) = w(w1 (x), w2 (x), ..., w h +1 (x)), 2
where |Im(wi )| < |Im(u)|. The iteration of the above procedure proves the contention 2 if k − |C| ≤ k, ord P olk γ = ≤ h otherwise. If k − |C| > h and the second case is not possible for any function f ∈ P olk γ,i.e., γ fulfills the condition (11.1), it results from the above procedure then that ord P olk γ ≤ # h2 $ + 1 is valid. We still have to show that w ∈ h [(P olk γ) 2 holds, if γ fulfills the condition (11.1). h +1
Denote A a matrix whose rows are just the tuples of Ek 2 on which the function w takes the values d1 , d2 , ..., dh+1 . It is easy to check that certain rows a1 , ..., ah (ai := (ai1 , ..., air ), i = 1, 2, ..., h, r ≤ # h2 $) are found in every matrix, which can be formed from the matrix A by deleting at least a column, so that is valid for every i ∈ {1, 2, ..., r}: (ai1 , a2i , ..., air ) ∈ ιhk . Consequently, an arbitrary ( h2 + 1)-ary function of P olk γ, which depends on at most # h2 $ places essentially, takes either a value from the set C on at least a tuple of A or two different rows of A, on which the function takes the very same value, exist. Further, every # h2 $-ary function of P olk γ can take only then h + 1 different values from the set Ek \C on different tuples b1 , ...,bh+1 , if there is at least a column that contains h+1 different values of the set Ek \C among the columns of the matrix
11.4 The Order of P olk for ∈ Mk and k ≤ 7
⎛
⎞
319
b1 ⎜ b2 ⎟ ⎜ ⎟. ⎝ ... ⎠ bh+1 h
Consequently, we have w ∈ (P olk γ) 2 and ord P olk γ = # h2 $ + 1, if γ fulfills the condition (11.1).
11.4 The Order of P olk for ∈ Mk and k ≤ 7 In this section let be a relation of Mk . The following lemma generalizes a theorem from [Jab 58], p. 83. Lemma 11.4.1 Let E ⊆ Ek with |E| ≥ 2. Further, let be a partial order relation on E with the following properties: ⊆ and (E; ) is a lattice. Then {f ∈ P olk | Im(f ) ⊆ E} ⊆ [(P olk )2 ]. Proof. Obviously, has a least element o and has a greatest element e. It is easy to check that there exists a unary function i with Im(i) = E and i(a) = a for all a ∈ E. We show that an arbitrary n-ary function f ∈ Pk,E ∩ P olk is a superposition over (sup (i(x1 ), i(x2 ))), (inf (i(x1 ), i(x2 ))) and the functions a if x ≥ b, mb,a (x) := o otherwise (a ∈ E, b ∈ Ek ). For all a := (a1 , a2 , ..., an ) ∈ Ekn is valid: f (a) if x ≥ a, fa (x1 , ..., xn ) := o otherwise, = inf (ma1 ,f (a) (x), ma2 ,f (a) (x), ..., man ,f (a) (x)) ∈ [(P olk )2 ]. Then one can represent the function f n as follows: f (x) = sup (fa1 (x), fa2 (x), ..., fakn (x)), where {a1 , ..., akn } = Ekn . Consequently, f ∈ [(P olk )2 ]. A consequence of Lemma 11.4.1 is Theorem 11.4.2 If (E; ) a lattice then ord P olk = 2.
Theorem 11.4.3 If k ≤ 7 then ord P olk = 2.
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Proof. Let k = 6 and the partial order relation defined by Figure 11.1. We will prove the theorem only for this relation. In the remaining cases, the relation fulfills the conditions of Theorem 11.4.2 or one can lead the proof similarly to the proof which is subsequently given. 5
3 4 1 2 0 Fig. 11.1
We start with the definitions of some functions of (P olk )2 : 0 if x ∈ E3 , x if x ∈ E3 , i1 (x) := i2 (x) := x otherwise, 5 otherwise, ⎧ x = 1, ⎨ 2 if x = 2, e1 (x) := 1 if ⎩ otherwise,
⎧ x = 3, ⎨ 4 if x = 4, e2 (x) := 3 if ⎩ x otherwise,
supi (x1 , x2 ), i = 0, 1, 2 and infj (x1 , x2 ), j = 3, 4, 5, where the relations i and j are defined in Figure 11.2. 0 :
5 3 4 0 2 1
3 :
4 5
3 1 2 0
1 :
5 3 4 1
4 :
2 :
5 3 4 2
0
0
2
1
3
5 :
5
3
4 1 2 0 Fig. 11.2
4 5 2 1 0
11.4 The Order of P olk for ∈ Mk and k ≤ 7
321
Let f n ∈ P ol6 be arbitrary. We prove by induction on n that f n ∈ [(P ol6 )2 ] holds. For n = 1, 2 our assertion is trivial. Assume the assertion is valid for n − 1 ≥ 2 and we show that it is valid for n. If |Im(f )| ≤ 5, then, by Lemma 11.4.1, f ∈ [(P ol6 )2 ]. Let |Im(f )| = 6 in the following. We show through a dismantling procedure that f n is a superposition over certain binary functions and certain functions g m with |Im(g)| ≤ 5 or m ≤ n − 1. Because of induction assumption and Lemma 11.4.1, our theorem would then be proven. 1.) During the first dismantling of function f , we use, the following functions of P ol6 : sup (x1 , i1 (x2 )), = f (x) if f (x) ∈ E3 , f1n (x) ≤ f (x) otherwise, where we assume the validity of ¬∃f1 ∈ P ol6 : = f (x) if f (x) ∈ E3 , ∃a : f1 (a) < f1 (a) ∧ f1 ((x) , ≤ f (x) otherwise, and f2n (x) We get
:=
0 if f (x) ∈ E3 , f (x) otherwise.
f (x) = sup (f1 (x), i1 (f2 (x))).
2.) Because of f2 ∈ [(P ol6 )2 ] we must still find only a dismantling of the kind described above for the function f1 . Let Ni := {a ∈ E6n | f1 (a) = i ∧ ¬∃a ∈ E6n : a < a ∧ f1 (a ) = i} (i = 1, 2), N1 := {a1 , a2 , ..., as },
N2 := {b1 , b2 , ..., bt },
N := N1 ∪ N2 ,
and for N ⊂ N let fN be an n-ary function of P ol6 with ⎧ if (∃a ∈ N ∩ N1 : x ≥ a) ∧ (¬∃b ∈ N ∩ N2 : x ≥ b), ⎪ ⎪=1 ⎪ ⎪ ⎪ ⎪ ⎨=2 if (¬∃a ∈ N ∩ N1 : x ≥ a) ∧ (∃b ∈ N ∩ N2 : x ≥ b), fN (x) : ⎪ ⎪ ≤ f1 (x) if (∃a ∈ N ∩ N1 : x ≥ a) ∧ (∃b ∈ N ∩ N2 : x ≥ b), ⎪ ⎪ ⎪ ⎪ ⎩ =0 otherwise, where for an arbitrary a ∈ E6n we assume that fN (a) = 5 is valid if and only if there is not any function fN ∈ P ol6 with fN (a) ∈ {3, 4}. We get the following description for f1 : f1 (x) = sup1 (fN (1) (x), fN (2) (x), ..., fN (1) (x))
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fN (i) (x) = sup2 (fN (i,1) (x), fN (i,2) (x), ..., fN (i,t) (x))
(i = 1, 2, ..., s). 3.) We search dismantling for the functions fi,j := fN (i,j) , 1 ≤ i ≤ s, 1 ≤ j ≤ t. Let Si,j := {c ∈ E6n | ai < c ∧ bj < c ∧ (¬∃c : ai < c < c ∧ bj < c < c)}. Case 1: |Si,j | = 1 or |{fi,j (a) | a ∈ Si,j | = 1. In this case, we have |Im(fi,j )| ≤ 5. Then by Lemma 11.4.1: fi,j ∈ [(P olk )2 ]. Case 2: |Si,j | > 1 and |{fi,j (a) | a ∈ Si,j }| > 1. Let ai = (ai1 , ai2 , ..., ain ) and bj := (bj1 , bj2 , ..., bjn ). W.l.o.g. we can assume that ⎧ if p = 1, 2, ..., u, ⎪ ⎪ = (1, 2) ⎨ if p = u, u + 1, ..., u + v, (aip , bjp ) = (2, 1) ⎪ ⎪ ⎩ ∈ {(1, 2), (2, 1)} if p = u + v + 1, ..., n, where u ≥ 1 or v ≥ 1 because of |Si,j | > 1. Case 2.1: u + v =: m < n. Let c := (sup (ai,m+1 , bj,m+1 ), sup (ai,m+2 , bj,m+2 ), ..., sup (ai,n , bj,n )), ⎧ 1 if x ∈ {1, 3, 4, 5}m \{3, 4, 5}m , ⎪ ⎪ ⎨ 2 if x ∈ {2, 3, 4, 5}m \{3, 4, 5}m , g(x1 , ..., xm ) :=
x ∈ {1, 3, 4, 5}m , fi,j (x1 , ..., xm , c ) if ⎪ ⎪ ⎩ 0 otherwise, and
⎧ 1 ⎪ ⎪ ⎨ 2 h(x1 , ..., xn ) := 4 ⎪ ⎪ ⎩ 0
if x ≥ ai ∧ x ≥ bj , if x≥ ai ∧ x ≥ bj , if x ≥ ai ∧ x ≥ bj , otherwise.
We get fi,j (x) = inf3 (g(x1 , ..., xu , e1 (xu+1 , ..., e1 (xm ), h(x1 , ..., xn )), i.e., fi,j ∈ [(P ol6 )2 ] by induction assumption and Lemma 11.4.1. Case 2.2: u + v = n. Let Ti,j := {a ∈ E6n | fi,j (a) ∈ {3, 4} ∧ (¬∃a ∈ E6n : a > a ∧ fi,j (a ∈ {3, 4}}. Case 2.2.1: Ti,j ⊆ {3, 4}n . For
11.4 The Order of P olk for ∈ Mk and k ≤ 7
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{d ∈ Ti,j | fi,j (d) = 4} =: {d1 , ..., dl }, with dr := (dr1 , ..., drn ), r = 1, 2, ..., l and x if a = 4, qa (x) := e2 (x) if a = 3, we obtain fi,j (x) = inf4 (inf3 (qd11 (x1 ), ..., qd1u (xu ), qd1,u+1 (e1 (xu+1 ), ..., qd1n (e1 (xn ))), inf3 (qd21 (x1 ), ..., qd2u (xu ), qd2,u+1 (e1 (xu+1 ), ..., qd2n (e1 (xn ))), ..., ................................... inf3 (qdl1 (x1 ), ..., qdlu (xu ), qdl,u+1 (e1 (xu+1 ), ..., qdln (e1 (xn )))), i.e., fi,j ∈ [(P ol6 )2 ]. Case 2.2.2: Ti,j ⊆ {3, 4}n . Case 2.2.2.1: ¬(∃a := (a1 , ..., an ), (b1 , ..., bn ) ∈ Ti,j : fi,j (a) = 3 ∧ fi,j (b) = 4 ∧ (∀p ∈ {1, ..., n} : (ap , bq ) ∈ {(3, 4), (4, 3)}). Here one can show fi,j ∈ [P ol ]n−1 when one uses a procedure that results from the construction steps 1.), 2.) and 3.) (including Case 2.1) listed above, when one the following replacements are carried out: f through fi,j , 0 through 5, 1 through 3, 2 through 4, 3 through 2, 4 through 2, 5 through 0, ≤ through ≥ , i1 through i2 , e1 through e2 , inf through sup ... . Case 2.2.2.2: ∃a := (a1 , ..., an ), (b1 , ..., bn ) ∈ Ti,j : fi,j (a) = 3 ∧ fi,j (b) = 4 ∧ (∀p ∈ {1, ..., n} : (ap , bq ) ∈ {(3, 4), (4, 3)}. W.l.o.g. let u = n and (3, 4) if p = 1, 2, ..., y, (ap , bq ) = (4, 3) if p = y + 1, ..., n. We need the following functions of P ol6 : 5 if x = a, z1 (x1 , ..., xn ) := fi,j (x) otherwise, 5 if x = a ∧ fi,j (x) = 3, z2 (x1 , ..., xn ) := fi,j (x) otherwise, 5 if x = b, z3 (x1 , ..., xn ) := z2 (x) otherwise, and
z4 (x1 , ..., xn ) :=
5 if x = b ∧ z2 (x) = 4, z2 (x) otherwise,
= inf5 (x1 , ..., xy , e2 (xy+1 ), ..., e2 (xn )). We get
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fi,j (x) = inf3 (z1 (x), z2 x)) and
z2 (x) = inf4 (z3 (x), z4 (x)).
Then, for the functions z1 and z3 , one can distinguish cases as above and repeat the constructions where appropriate. Therefore, one can reduce the Case 2.2.2.2 to the previous cases. Thus f ∈ [(P ol6 )2 ] holds. We still notice that one cannot transfer the methods from the proof of Theorem 11.4.3 for arbitrary relations ∈ Mk , since there are no binary functions in P ol8 with the properties used of function sup1 for k = 8 and for the relation , which is defined in Figure 11.3. Suppose there exists a function f 2 ∈ P ol8 with f (1, 0) = f (0, 1) = 1 and f (x, x) = x for all x ∈ E8 . Then, f (1, 0) = 1, f (2, 2) = 2 and f (3, 3) = 3 implies f (3, 2) = 3. Further, f (0, 1) = 1, f (2, 2) = 2 and f (4, 4) = 4 implies f (2, 4) = 4. Consequently, we have f (3, 4) ∈ {5, 6, 7}. This is, however, a contradiction to f (5, 5) = 5, f (6, 6) = 6 and f ∈ P ol8 . 7
6 5 3 4 1 2 0 Fig. 11.3
In the next section, we show that the above-described class does not have a finite order.
11.5 A Maximal Clone of Monotone Functions That Is Not Finitely Generated This section basically displays the content of the paper [Tar 86] by G. Tardos. The set E8 is written down in this section in the form: {0, α, α , β, β , γ, γ , 1}, On E8 we consider the partial order relation which is defined by Figure 11.4. If from monotone functions the speech is subsequently, only functions are with that meant from P ol8 .
11.5 A Maximal Clone of Monotone Functions That Is Not Finitely Generated
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1
γ γ β β α α 0 Fig. 11.4
The signs <, >, ≥, ≤ refer to this order relation or are explained for tuples from E8n , on which the relation works coordinate wisely. The following definition is clarified by means of Figure 11.5 which indicates a Hasse-diagram for certain n-tuples. A denotation of the form x; a at a knot of this diagram means that f (x) = a is valid for a corresponding n-ary function f. ;γ
xm ; β
......
; γ
;γ
; γ
x12 ; x10 ; ...... xm ; β ; x11 x13 ; ; α
;α
;α
; α
Fig. 11.5
Definition Let ∅ = Q ⊆ E8n and f1 : Q −→ E8 . We call a sequence xm , ..., xm of pairwise distinct elements from the set E8n a zigzag for f1 if the following seven conditions hold: (a) m = 0 or m = 1 and m > m + 2. (b) xm , xm ∈ Q and xi ∈ E8n \Q for all i ∈ {m + 1, ..., m − 1}. (c) f1 (xm ) = β and f1 (xm ) = β . (d) ∀ 2i ∈ {m + 1, ..., m } : x2i > x2i−1 .
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(e) ∀ 2i ∈ {m, m + 1, ..., m − 1} : x2i > x2i+1 . (f) ∀ 2i + 1 ∈ {m + 1, ..., m − 1} ∃y, y ∈ Q : α ∧ f1 (y ) = α .
y, y > x2i+1 ∧ f1 (y) =
(g) ∀ 2i ∈ {m+1, ..., m −1} ∃z, z ∈ Q : z, z > x2i ∧ f1 (z) = γ ∧ f1 (z ) = γ . Lemma 11.5.1 Let ∅ = Q ⊆ E8n and let f1 : Q −→ E8 be a mapping. Then there is a monotone function f : E8n −→ E8 with f|Q = f1 if and only if the following two conditions hold: (1) f1 is monotone; (2) there is no zigzag in Q for f1 . Proof. “=⇒”: The condition (1) is trivial. To prove (2) we assume by way of contradiction that xm , ..., xm ∈ Q is a zigzag for f1 according to the above definition and that f : E8n −→ E8 is a monotone extension of f1 . First, let m = 0 and m = 2q + 1, q ∈ N in the zigzag (see Figure 11.6). ; γ
;γ
;γ
; γ
x0 ; β x2q ; x2 ; .. . x2q+1 ; β x1 ; x3 ; ;α
; α
;α
; α
Fig. 11.6
Since x1 , ..., x2q ∈ E8n and f1 preserves on these tuples, we have f1 (x1 ) = β. Continuation of this consideration supplies f1 (x2q ) = β, which is not possible because of x2q+1 < x2q and f1 (x2q+1 ) = β . For the other possibilities for m and m one shows in analog mode that the assumption of the existence of a zigzag for f1 supplies a contradiction. “⇐=”: Assume that the conditions (1) and (2) are satisfied. We construct a monotone function f : E8n −→ E8 extending the function f1 by defining of the following sets Hx := f −1 (x) for each x ∈ E8 . For q ∈ E8n let f (q) := {f1 (y) | y ∈ Q ∧ y ≤ q}, f (q) := {f1 (z) | z ∈ Q ∧ z ≥ q}.
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327
Furthermore, let H0 := {q ∈ E8n | f (q) ⊆ {0}}, H1 := {q ∈ E8n | f (q) ⊆ {1}}\H0 , Hα := {q ∈ E8n | f (q) ⊆ {0, α}}\(H0 ∪ H1 ), Hα := {q ∈ E8n | f (q) ⊆ {0, α }}\(H0 ∪ H1 ∪ Hα ), Hγ := {q ∈ E8n | f (q) ⊆ {1, γ}}\(H0 ∪ H1 ∪ Hα ∪ Hα ), Hγ := {q ∈ E8n | f (q) ⊆ {1, γ }}\(H0 ∪ H1 ∪ Hα ∪ Hα ∪ Hγ ) and
H := E8n \(H0 ∪ H1 ∪ Hα ∪ Hα ∪ Hγ ∪ Hγ ).
To partition the set H, we consider the elements of H as vertices of a nondirectional graph in which an edge joins the vertices x, y ∈ H if and only if x < y or y < x in E8n is valid. Then, graph G consists of certain connected maximal subgraphs (the so-called components) K1 ..., Kt , with which we define the sets Hβ and Hβ as follows: Hβ := {x ∈ H | ∃i ∈ {1, ..., t} : x ∈ Ki ∧ β ∈ {f1 (a) | a ∈ Ki }}, Hβ := H\Hβ . The subsets Hx for x ∈ E8 now form a partition of E8n , so they really determine a function f : E8n −→ E8 satisfying ∀x ∈ E8n ∀e ∈ E8 : f (x) = e :⇐⇒ x ∈ He . We prove that this function preserves the relation and that it agrees with the function f1 on E8n . One can check the monotony from f easily, using the following implications, which result from the definitions of the sets He , e ∈ E8 and which are valid for every a ∈ E8n : ∀e ∈ {α, α } : f (a) = e =⇒ e ∈ f (a) ∀e ∈ {γ, γ } : f (a) = e =⇒ e ∈ f (a). Finally we show f|Q = f1 . Obviously, for arbitrary z ∈ Q with f1 (z) = β we have f (z) = f1 (z). To show that f (z) = f1 (z) holds for elements z ∈ Q with f1 (z) = β as well, we must prove that no component G contains elements from both f1−1 (β) and f1−1 (β ). We use here the complicated condition (2). By the definition of H for every z ∈ H, we have f (z) ⊆ {0, α}, f (z) ⊆ {0, α }, f (z) ⊆ {1, γ}, f (z) ⊆ {1, γ }. By condition (1) these conditions are equivalent to
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β ∈ f (z) or β ∈ f (z) or {α, α } ⊆ f (z)
(11.6)
β ∈ f (z) or β ∈ f (z) or {γ, γ } ⊆ f (z).
(11.7)
Suppose a component K of the graph G contains a xm ∈ f1−1 (β) and a xm ∈ f −1 (β ). We choose xm and xm so that are the least distance among the possible vertices. So, there is a path between xm and xm . Take the shortest path. If x, y and z are three consecutive elements of this path then neither x < y < z nor x > y > z can hold since y would then be redundant. Thus, we can choose the indices so that the path be xm , ..., xm satisfies the conditions (a), (c), (d), and (e) in the definition of a zigzag. If m < 2i < m then there is no z ∈ Q with f1 (z) = β or f1 (z) = β and z ≥ x2i , since otherwise either z, x2i+1 , ..., xm or xm , ..., x2i−1 , z would be a shorter path in K from a element of f −1 (β) to an element f −1 (β ). Consequently, (b) holds. Condition (f) also holds because for x2i only {γ, γ } ⊆ f (x2i ) can occur among the possibilities in (11.3). Similarly, condition (g) holds. Hence xm , ..., xm is a zigzag for f1 contrary to (2). Next, for n ≥ 3, we shall define (n + 5)-ary relations µ0 , µ1 , ..., µn and µ on E8 , which we need to prove the following lemmas. C1
C2
Cn−2
C
B D2 D4 B D2n−4 D D D ..... D2n−5 D2n−3 1 3 5 A
A
Fig. 11.7. Poset Q0
Definitions Let n ≥ 3. Let Q0 (⊆ E8t ) Further, we take
3
the poset defined by Figure 11.7.
Q0 := {A, A , B, B , C1 , C2 , ..., Cn−2 , C }, Q1 := Q0 \{B} and Q2 := Q0 \{B }. Let 3
Later we choose t = 2 · n.
11.5 A Maximal Clone of Monotone Functions That Is Not Finitely Generated
329
T := (a, a , b, b , c1 , c2 , ..., cn , c ) ∈ E8n+5 . The index of c is always understood modulo n. Let fi : Q0 −→ E8 (i = 1, ..., n) be the following mapping: fi (A) := a,
fi (A ) := a ,
fi (B) := b,
fi (B ) := b ,
fi (Cj ) := ci+j (j = 1, ..., n − 2) and fi (C ) := c . (Clearly, the mapping fi depends on the choice of the tuple T .) We declare T ∈ µ0 iff for each i ∈ {1, ..., n} both (fi )|Q1 and (fi )|Q2 can be extended monotonously to Q0 . Furthermore, for j ∈ {1, ..., n} let T ∈ µj iff T ∈ µ0 and fj can be extended monotonously to a monotone mapping on Q0 . Finally, let n µj . (11.8) µ := j=1
Lemma 11.5.2 If T ∈ µ then T belongs to at least n − 2 of the relations µj with 1 ≤ j ≤ n. Proof. Let T := (a, a , b, b , c1 , ..., cn , c ) and l := |{i ∈ {1, ..., n} | T ∈ µi }|. T ∈ µ implies T ∈ µ0 . If T ∈ µi for all i ∈ {1, ..., n} then l = n. Thus, it is enough to consider the case T ∈ µ0 but T ∈ µi for some i ∈ {1, ..., n}. By the cyclical nature of the relations µi , we may assume T ∈ µ1 . It means that f1 cannot be extended monotonously to Q0 . Because of T ∈ µ0 both (f1 )|Q1 and (f1 )|Q2 have monotone extensions to Q0 . Therefore, f1 is monotone. So by Lemma 11.5.1, there is a zigzag xm , ..., xm in Q0 for f1 . Let H be the set of all elements of Q0 comparable with some xi (m < i < m ). Since xm , ...xm is a zigzag for (f1 )|(Q0 ∩H) as well, it follows that (f1 )|(Q0 ∩H) cannot be extended monotonously to Q0 . This implies that both B and B are in H. But xm+1 , ..., xm −1 is a series of distinct elements in Q0 \ Q0 such that every two consecutive elements are comparable. These two properties imply that {xi | m < i < m } = {Dj | 1 ≤ j ≤ 2n − 3}, where the correspondence is either in direct or reverse order depending on whether f1 (B) = β or f1 (B) = β . So, by condition (g) in the definition of a zigzag {a, a } = {fi (A), fi (A )} = {α, α }, and by condition (f) we have {ci , c } = {fi (Ci−1 ), fi (C )} = {γ, γ } for i = 2, ..., n − 1. W.l.o.g. we may assume that c = γ and ci = γ for all i = 2, ..., n − 1. Because of condition (c) of the definition of a zigzag we have
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{b, b } = {fi (B), fi (B )} = {β, β }. Using the fact that T ∈ µ0 , one can show that {c1 , cn } ⊆ {γ, γ , 1}. So, we have determined all tuples T ∈ µ0 \µ1 . By symmetry, we get similar characterizations for µ0 \µi for i = 2, ..., n. Applying them, we obtain: c1 = c2 = γ =⇒ l = 0 =⇒ T ∈ µ, ((c1 = γ ∧ cn = γ) ∨ (c1 = γ ∧ cn = γ)) =⇒ l = n − 2, (c1 = γ ∧ cn = γ) =⇒ l = n − 1. Lemma 11.5.3 Let n ≥ 3. For every l < E8 preserve the relation µ.
n 2
the l-ary monotone functions on
Proof. Let g be an l-ary function of P ol8 and let Ti ∈ µ for i = 1, 2, ..., l. Then by Lemma 11.5.2 we have ∀i ∈ {1, 2, ..., l} : |{j ∈ {1, ..., n} | Ti ∈ µj }| ≤ 2. Thus there is an index j ∈ {1, ..., n} with Ti ∈ µj for all i = 1, 2, ..., l. Since one can derive the relations µi (1 ≤ i ≤ n) from the t-th graphic Gt (P ol8 ) by means of the operation pr (projection), the relations mi belong to Inv8 (P ol8 ) (see Chapter 2). Therefore, function g preserves the relation µj , from which we receive g(T1 ..., Tl ) ∈ µj ⊆ µ. Lemma 11.5.4 For n ≥ 3 there exist 2n-ary monotone functions on E8 , which do not preserve the relation µ. Proof. We consider a matrix A of the type (n + 5, 2n), whose construction is given in the following table, where a, a , b, b , c1 , ..., cn , c are the rows of A and T1 , T2 , ..., T2n are the columns of A. Furthermore, let T := (α, α , β, β , γ, γ, ..., γ, γ )T be a column matrix of length n + 5, which is also defined in the following table. a a b b c1 c2 c3 c4 . . . cn c
T1 α α β β 1 γ γ γ . . . γ γ
T2 α α β β γ 1 γ γ . . . γ γ
T3 α α β β γ γ 1 γ . . . γ γ
T4 α α β β γ γ γ 1 . . . γ γ
... ... ... ... ... ... ... ... ... ... ... ... ... ...
Tn Tn+1 Tn+2 Tn+3 Tn+4 α α α α α α α α α α β 1 1 1 1 β 1 1 1 1 γ 1 β γ γ γ β 1 β γ γ γ β 1 β γ γ γ β 1 . . . . . . . . . . . . . . . 1 β γ γ γ γ γ γ γ γ
... ... ... ... ... ... ... ... ... ... ... ... ... ...
T2n α α 1 1 β γ γ γ . . . 1 γ
T α α β β γ γ γ γ . . . γ γ
11.5 A Maximal Clone of Monotone Functions That Is Not Finitely Generated
Let
331
Q := {a, a , b, b , c1 , ..., cn , c } ⊆ E82n
and f1 : Q −→ E8 be a function defined by f1 (A) = f1 (T1 , T2 , ..., T2n ) := T. Clearly, f1 is monotone. Suppose that there is a zigzag xm , ..., xm ∈ E82n for f1 . Thus we have xm = b, xm = b , m < 2i + 1 < m =⇒ a < x2i+1 ∧ a < x2n+1 m < 2i < m =⇒ c > x2i ∧ (∃qi ∈ {1, 2, ..., n} : cqi > x2i ). Let p := % 12 (m − 1)&.4 Each j ∈ {1, ..., n} appears among the numbers q1 , ..., qp , since we could not otherwise choose the j-th coordinates of xm , ..., xm to satisfy the above conditions. Let l (1 ≤ l ≤ n) be the number that appears last from the beginning in the sequence q1 , ..., qp . Then there is an interval in this sequence with first last element l − 1 and l + 1 or the reverse and containing no other element equal to l − 1, l or l + 1 considered again modulo n. However, in this case, we cannot choose the (n + l)-th coordinates of xm+1 , ..., xm −1 to satisfy the above conditions. The contradiction proves that there is no zigzag in E82n for f1 . So, by Lemma 11.5.1, we can extend f1 to a 2n-ary monotone function h with h(T1 , ..., Tn ) = T. Using that {T1 , ..., Tn , T } ⊆ µ0 and the characterization of µ0 \µi (1 ≤ i ≤ n) one can easily check that T1 , ..., Tn belong to µ but T ∈ µ. Thus the 2n-ary monotone function h does not preserve µ. Theorem 11.5.5 ([Tar 86]) does not have a finite order.
For k ≥ 8 there is a ∈ Mk , so that P olk
Proof. Let ∈ Mk defined by the Hasse-diagram of Figure 11.4. Choosing a finite set A ⊂ P ol8 we have a number l, such that every element of A is at most l-ary. Taking n ≥ 2 · l and defining µ corresponding to this n, we get that A ⊆ P ol8 {µ, } ⊆ P ol8 by Lemma 11.5.3, but (P ol8 )n ⊆ P ol8 {µ, } by Lemma 11.5.4. So the finite set A does not generate the whole clone. Presumably ord P olk = ∞ is valid for every relation , in whose diagram one can embed the diagram given in Figure 11.4. 4
x denotes the floor of x ∈ R, i.e., the largest integer which is ≤ x.
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11.6 Classifications and Basis Enumerations in Pk Let A be a class of Pk that is finitely generating. Then, A has only finite many A-maximal classes M1 , M2 , ..., Mt and it is valid for all B ⊆ A: [B] = A ⇐⇒ (∀i ∈ {1, ..., t} : B ⊆ Mi ). A generating system B := {f1 , ..., fr } of A with the following property is especially interesting: [B \ {fi }] = A for every i ∈ {1, ..., r}. Such a set B is called basis of A and the number r is the rank of B. It is briefly explained in this section, as one can classify the bases of A and one can also determine, then, the ranks of the bases. With all maximal classes M1 , ..., Mt of the class A, can be classified the functions, by their membership in the A-maximal sets as follows: For f ∈ A we put 0 if f ∈ Mi , χi (f ) := 1 if f ∈ Mi (i = 1, 2, ..., t) and χ(f ) := (χ1 (f ), χ2 (f ), ..., χt (f )). We call χ(f ) the characteristic vector of f . We put f ≡ g iff f, g ∈ A and χ(f ) = χ(g). Obviously, ≡ is an equivalence relation on A, and so it partitions A into pairwise disjoint nonempty sets (called equivalence classes or blocks). Let f ∈ A with χ(f ) = (a1 , ..., at ). Then, it is easy to see that the block [f ]≡ of ≡ has the form Ta1 ∩ Ta2 ∩ .... ∩ Tat , where, for i ∈ {1, ..., t}, Tai :=
Mi if ai = 0, A \ Mi for ai = 1.
If f ∈ B ⊆ A and χ(f ) = χ(g), then we have [B] = A ⇐⇒ [{g} ∪ (B \ {f })] = A. In other words, it suffices to study the completeness in A up to the equivalence relation ≡. Further, it is easy to see that ∀B ⊆ A : ([B] = A ⇐⇒ ( χ(f )) = (1, 1, 1, ..., 1)), f ∈B
where is the usual componentwise logical ∨ of the tuples (∈ E2t ). A set B := {f1 , ..., fr } ⊆ A is a basis of A iff [B] = A and
11.6 Classifications and Basis Enumerations in Pk
∀j ∈ {1, ..., r} : (
χ(f )) = (1, 1, 1, ..., 1))
333
(11.9)
f ∈B\{fj }
Once we know all the characteristic vectors, we can find all complete sets in A and all bases by a direct combinatorial check (which may be done by a simple computer program, provided t is not large (see [Sto 87])). If to α := (α1 , ..., αt ) ∈ E2t we associate the set Iα := {i | αi = 1} and if I1 , ..., Im are the subsets of {1, 2, ..., t} corresponding to the characteristic vectors, the completeness problem is reduced to listing irredundant coverings (i.e., no proper subset covers {1, 2, ..., t}). The study of classes also provides information on the classes of Pk , which are the intersections of families of A-maximal sets, which is of independent interest.5 The characteristic vectors can also be applied to seek the set of classes of functions that make an incomplete set complete. One finds many results above characteristic vectors and basis enumerations in the books [Mas 88] and [Sto 87]; e.g., classification of A ∈ {P2 , P3 , Pk,2 , Lp }, p ∈ P, and classifications of the maximal classes of P3 and of Pk,2 . Subsequently, the concepts and ideas introduced above are only explained as an example. Let A = P2 . Then, by Theorem 3.2.4.2, we can say M1 := T0 , M2 := T1 , M3 := S, M4 := L, M5 := M. Then there are exactly 15 characteristic vectors (a1 , ..., a5 ) for P2 ([Jab 52], [Ibu-N-N 63], [Kri 65]): number of (a1 , ..., a5 ) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 5
a1 a2 a3 a4 a5 example for f with χ(f ) = (a1 , ..., a5 ) 1 1 1 1 1 x∧y 1 1 0 1 1 (x ∧ y) ∨ (x ∧ z) ∨ (y ∧ z) 0 1 1 1 1 x∧y 1 0 1 1 1 x∨y 1 1 0 0 1 x 1 0 1 0 1 x+y+1 0 1 1 0 1 x+y 0 0 1 1 1 x ∧ (y ∨ z) 1 0 1 0 0 c1 0 1 1 0 0 c0 0 0 1 1 0 x∨y 0 0 0 1 1 (x ∧ (y ∨ z)) ∨ (x ∧ y ∧ z) 0 0 0 1 0 (x ∧ y) ∨ (x ∧ z) ∨ (y ∧ z) 0 0 0 0 1 x+y+z 0 0 0 0 0 e11
E.g., for A = P3 with one exception the least nontrivial intersections are all minimal clones.
334
11 On Generating Systems and Orders of the Subclasses of Pk
With the aid of the above, one can classify the bases of P2 as follows: Theorem 11.6.1 ( [Ibu-N-N 63], [Kri 65]; without proof ) Let B := {f1 , ..., fr } be an arbitrary basis of P2 . Then r ∈ {1, 2, 3, 4} and for χ(B) := {χ(f1 ), ..., χ(fr )} is valid: |B| the sets of the numbers of the lements of χ(B) 1 {1} 2 {2, x}, where x ∈ {3, 4, 6, 7, 8, 9, 10, 11} {3, x}, where x ∈ {4, 5, 6, 9} {4, x}, where x ∈ {5, 7, 10} {5, x}, where x ∈ {8, 11} 3 {5, x, y}, where x ∈ {6, 7, 9, 10} and y ∈ {12, 13} {6, 7, x}, where x ∈ {8, 11, 12, 13} {6, 6, 10} {6, 10, x}, where x ∈ {11, 12, 13} {7, 8, 9} {7, 9, x}, where x ∈ {11, 12, 13} {9, 10, x}, where x ∈ {8, 12} 4 {9, 10, 11, 14}, {9, 10, 13, 14} In other words: There are exactly 42 aggregates6 for P2 . 1 aggregate has the rank 1, 17 aggregates have the rank 2, 22 aggregates have the rank 3 and 2 aggregates have the rank 4.
6
An aggregate is the set of all bases having the the same set of characteristic vectors.
12 Subclasses of Pk,2
In this chapter, we will to deal with subclasses of the class Pk,2 := {f ∈ Pk | W (f ) ⊆ {0, 1}}. When one restricts the domain of a function f n ∈ Pk,2 to the set E2n , a homomorphic mapping pr (”projection”) from Pk,2 onto P2 can be defined. Since the image prA of a subclass A of Pk,2 is a subclass of P2 and the subclasses of P2 are known, one can hope +to find certain properties of the inverse images (⊆ Pk,2 ) through the known properties of the images (⊆ P2 ). This hope confirmed itself in a certain sense (see e.g. Theorem 12.2.5 and Theorem 9.7.6). On the other hand, Pk,2 , k ≥ 3 also reflects the negative properties of Pk because the examples of classes from Section 8.1.1 with infinite and without bases are subclasses of Pk,2 . Further, the functions of Pk,2 are important since they can be interpreted as predicates. Some further applications are subsequently mentioned: Functions of P3,2 permit the description of a decision (values 0, 1) with abstention from voting (value 2). Special functions of P3,2 are of interest in the theory of noncorrect algorithms (see e.g. [Sch 78]). In [Eps-F-R 74] G. Epstein, G. Frieder and D. C. Rine mention that functions of Pk,2 are useful for describing logico-arithmetical branchings in programs where the arithmetical constants (mostly k > 2) are arguments and the two logical constants form the range. They also give a function of P3,2 which is used in control of real-time processes and in aeronautics. In 1973/1974 G. Burosch dealt with the set Pk,2 . Some years later he, J. Dassow, W. Harnau and the authoress continued the study of the subclasses of Pk,2 . The investigations of Pk,2 concerned the following problems:
336
12 Subclasses of Pk,2
(1) For a given subclass B of P2 determine the set of all subclasses of Pk,2 , which can be projected to B, i.e., the restrictions of the functions to arguments of E2 gives a function of B. (2) As completely as possible, construct the lattice of the subclasses of P3,2 . (3) For a given subclass of Pk,2 , decide whether it is finitely generated and construct a system of generators (if possible). A summary of the achieved results on the closed subsets of Pk,2 was published in [Bur-D-H-L 85]. Unfortunately, a proof could not be given in [Bur-D-H-L 85] for every theorem, since the extent of this proof was too great. After B. Cs´ak´ any showed the author how the Theorem of Baker and Pixley can be generalized (see Theorems 8.3.1 and 12.3.1), she found new and shorter proofs. The subsequently proofs to the theorems and lemmas without reference come mostly from the papers [Lau 88;a;b] (or [Lau 84c]) but also from [Bur-D-H-L 85] and [Lau 77;a;b]. In addition, the results of N. Gr¨ unwald from [Gr¨ u 83;a;b]which continued the investigations of the team Burosch-Dassow-Harnau-Lau. The chapter is organized as follows: Section 12.1 contains the basic concepts and notations. In Section 12.2, one can find results on inverse images of subclasses of P2 (with respect to the above projection). The remaining sections deal with the determination of the cardinality and with the determination of the elements of the set Nk (B) := {A ∈ L↓k (Pk,2 ) | pr A = B} for subclasses B of P2 . In Section 12.3, one can find some structure statements about L↓k (Pk,2 ). In addition, this section clarifies whether the set Nk (B) is finite or infinite or has the cardinality of continuum. In Section 12.4, one can find all subclasses A of Pk,l whose projection is the class Pl or P oll {α} (α ∈ El , 2 ≤ l < k). After that, in Section 12.5, the maximal and the submaximal classes of Pk,2 are determined. Then, the investigations are continued from Section 12.3 for k = 3, i.e., for many classes B ⊆ P2 with |N3 (B)| ≤ ℵ0 the elements of the set N3 (B) are determined.
12.1 Notations In this chapter, let 2 ≤ l < k and Pk,l as defined in Section 1.1. In general, we define functions of Pk,l by formulae over an alphabet X := {x, x1 , x2 , ...}. In contrast, we define the Boolean functions over the alphabet Y := {y, y1 , y2 , ...}, and we use the notations for functions and closed sets of P2 from Chapter 3. By k1 and ja , where a ∈ Ek , we denote the unary functions of Pk,l given by
k1 (x) :=
12.2 Some Properties of the Inverse Images
1 if x ∈ E2 , 0 otherwise,
ja (x) :=
337
1 if x = a, 0 otherwise,
respectively. To characterize the subclasses of Pk,l we need the following homomorphism of Pk,l onto Pl , which we denote by prl or only with pr and which we call “projection” 1 ): For f n ∈ Pk,l and g m ∈ Pl let pr f n = g m if and only if n = m and f (a) = g(a) for all a ∈ Eln . If B ⊆ Pl , we call the subset pr−1 B := {f ∈ Pk,l | pr f ∈ B} of Pk,l inverse image of B. We say a subclass A of Pk,l is B-projectable iff prl A = B. Denote Nk (B) the set of all B-projectable subclasses of Pk,l . By P olPk,l := Pk,2 ∩ P olk one can describe subclasses of Pk,l . If the index Pk,l can be seen from the context, we write only P ol instead of P olPk,l . . If B = P oll (⊆ Pl ), ⊆ Elh and a1 , ..., ar are some tuples of Ekh \Elh , then we also denote the closed set P olPk,l ( ∪ {a1 , ..., ar )} with B a1 ,...,ar . In particular, these notations will be used in Section 12.6 for l = 2 and B ∈ {T0 , T1 , M }. Furthermore, let 0 1 ... l − 1 a {a, b} ⊆ Ek . Za,b := P olPk,l 0 1 ... l − 1 b
12.2 Some Properties of the Inverse Images With the mapping pr, we can prove that some properties of the subclasses of Pl are transmitted to their inverse images in Pk,l . 1
n To avoid confusion with the notation for functions en i , the functions ei are called selectors at some places of this chapter.
338
12 Subclasses of Pk,2
Lemma 12.2.1 (a) Let A ⊆ Pk,l , [pr A] = Pl and b ∈ Ek . Then, the set A ∪ {ja | a ∈ Ek \{b}} is a generating system for Pk,l . (b) ord Pk,l = 2. Proof. (a): Since pr A is a generating system for Pl , there are binary functions h and g of [A] with (pr h)(y1 , y2 ) = y1 + y2 (mod l) and (pr g)(y1 , y2 ) = y1 · y2 (mod l). Furthermore, the constant functions c0 , c1 , ..., cl−1 and the function k−1 jb (x) = 1 + (l − 1) · ja (x) (mod l) a=0, a=b
belong to [A]. Further, any function f n of Pk,l has a representation of the form f (x1 , ..., xn ) = f (a1 , ..., an ) · ja1 (x1 ) · ja2 (x2 ) · ... · jan (xn ) (mod l), (a1 ,...,an )∈Ekn
i.e., f belongs to [{g, h, c0 , ..., cl−1 , j0 , ..., jk−1 }] ⊆ [A]. (b) follows from (a) and Theorem 1.4.2, (b).
(12.1)
Lemma 12.2.2 Let B be a subclass of Pl , which contains the set Jl of all projections (selectors) of Pl . Then, for every set A ⊆ Pk,l with [pr A] = pr B, the set A ∪ pr−1 Jl is a generating system for pr−1 B. Proof. Let f n ∈ pr−1 B. Since [pr A] = B, there exists a function f1n ∈ [A] with pr f1 = pr f . In pr−1 Jl one can find the (n + 1)-ary function xn+1 if x ∈ Eln+1 , h(x) := f (x1 , ..., xn ) otherwise. Consequently, f (x1 , ..., xn ) = h(x1 , ..., xn , f1 (x1 , ..., xn )) is a superposition over A ∪ pr−1 Jl . By the above lemma, we obtain the following theorem. Theorem 12.2.3 If Jl ⊆ B ⊂ B ⊆ Pl and B is a maximal class of the class B then is also pr−1 B maximal in pr−1 B. It is easy to see that the above theorem does not hold if B does not contain Jl (see also Theorem 12.2.6). Lemma 12.2.4 The order of pr−1 Jl is 3.
12.2 Some Properties of the Inverse Images
Proof. Let
i(x) :=
339
x if x ∈ El , 0 otherwise.
Every n-ary function f of pr−1 Jl with pr f = eni can be represented in the following manner: f (x1 , ..., xn ) = i(xi ) · k1 (x1 ) · ... · k1 (xn )+ a∈Ekn \Eln f (a1 , ..., an ) · ja1 (x1 ) · ... · jan (xn ) (mod l). (12.2) We prove that (12.2) is a superposition over i(x1 ) · k1 (x2 ) (mod l), i(x1 ) + a · jq (x2 ) (mod l), i(x1 ) + i(x2 ) · jq (x3 ) (mod l),
(12.3)
i(x3 ) + i(x1 ) · jp (x2 ) · jq (x3 ) (mod l), (p, q ∈ Ek ; q > 1, a ∈ El ). First, we construct the function i(x) + a · ja1 (x1 ) · ja2 (x2 ) · ... · jan (xn ) (mod l)
(12.4)
for (a1 , ..., an ) ∈ Ekn \Eln , a ∈ El . W.l.o.g. let a1 ∈ Ek \El . The function i(x)+(i(x1 )+i(x3 ))ja2 (x2 )ja1 (x1 )ja1 (x1 ) = i(x) + i(x3 )ja1 (x1 )ja2 (x2 ) (mod l) is obtained from i(x) + i(x2 )ja1 (x1 ) if we substitute the variable x2 by i(x1 )+i(x3 )ja2 (x2 )ja1 (x1 ). By substitution of x3 by i(x1 ) + i(x4 )ja3 (x3 )ja1 (x1 ) we generate the function i(x) + i(x4 )ja1 (x1 )ja2 (x2 )ja3 (x3 ) (mod l). By iterated application of these constructions we obtain the function i(x) + i(xn+1 )ja1 (x1 )ja2 (x2 )...jan (xn ) (mod l).
(12.5)
The function (12.4) is generated from (12.5) by substituting xn+1 by i(x1 ) + a · ja1 (x1 ). Obviously, i(x) + f (a1 , ..., an )ja1 (x1 )ja2 (x2 )...jan (xn ) (mod l) (12.6) a∈Ekn \Eln
is a superposition of functions of type (12.4). If we substitute x in (12.6) by i(xi ) · k1 (x1 ) · ... · k1 (xn ) ∈ [i(x) · k1 (x1 )] we obtain the function (12.2); i.e., (12.3) is a generating system for pr−1 Jl and ord pr−1 Jl ≤ 3. Since the functions of (pr−1 Jl )2 preserve the relation
340
12 Subclasses of Pk,2
λl ∪ {(2, 2, 2, 2)} (see Lemma 4.1), the function i(x1 ) + j1 (x1 )j1 (x2 )j2 (x3 ) ∈ pr−1 Jl does not preserve this relation, however, we have ord pr−1 Jl = 3. Theorem 12.2.5 Let B ⊆ Pl be a clone. Then ord B ≤ ord pr−1 B ≤ max(3, ord B). Every inverse image (⊆ Pk,2 ) of a clone B ⊆ P2 is finitely generated. Proof. The statements of the theorem are consequences of Theorems 12.3.2 and 12.3.4 and of Chapter 3. The following theorem gives information on the order of the remaining inverse images (⊆ Pk,2 ) of subclasses (⊆ P2 ). Theorem 12.2.6 The inverse images pr−1 C0 , pr−1 C1 and pr−1 C have no finite basis. Proof. Let A be an inverse image of Pk,2 whose projection is generated by {ca , cb }, {a, b} ⊆ E2 . Then A contains the functions ⎧ ∃i, α : xi = 2 ∧ ⎨ α if x1 = ... = xi−1 = xi+1 = ... = xn = α ∈ E2 , f n (x1 , ..., xn ) := ⎩ a otherwise for all n ∈ N. A has no finite basis if we can prove that, for each n, the function f n is not a superposition of the (n − 1)-ary functions of A. It suffices to prove that f n has no representation by a formula h(x1 , ..., xn ) := g0 (g1 (x1 , ..., xn ), ..., gn−1 (x1 , ..., xn )),
(12.7)
where gi (0 ≤ i ≤ n) is a function of A or gi (1 ≤ i ≤ n) is defined by gi (x1 , ..., xn ) = xj
(12.8)
for some j ∈ {1, 2, ..., n}. W.l.o.g. we can assume that g1 is not a function of form (12.8). Then, for α ∈ E2 βα := (g1 (2, α, ..., α), ..., gn−1 (2, α, ..., α)) is a tuple of E2n and thus g0 (β0 ) = g0 (β1 ). However by definition f n (2, α, ..., α) = α for every α ∈ E2 . Therefore, formula (12.7) does not define the function f n.
12.2 Some Properties of the Inverse Images
341
Theorem 12.2.7 (a) Let A ⊆ Pk,l be an inverse image whose projection prl A is a clone. Then A has a basis with exactly r elements if and only if pr A has such a basis. (b) ∃f ∈ Pk,l : [f ] = Pk,l . Proof. (a): If [{f1 , ..., fr }] = A then [{pr f1 , pr f2 , ..., pr fr }] = pr A holds. Let pr A = [{g1 , ..., gr }], where g1 denotes a function that stands in the construction formula of e11 “outside”; i.e., we have e11 (x) = g1 (t1 (x), ..., tn (x)) for certain t1 , ..., tn of [{g1 , ..., gr }]. Further, denote f1 , ..., fr certain functions of A with pr fi = gi , i = 1, ..., r and let IV f (x1 , ..., xn , x, ..., xp,q , ..., xp,q , ..., xp,q , ..., x p,q , ..., xp,q , ...) i(xp,q ) · jp (xp,q ) · jq (xp,q ) := f1 (x1 , ..., xn ) · k1 (x) + p, q
q≥l 0 ≤ p < q ≤ k−1
+
IV jp (x p,q ) · jq (xp,q ) (mod l). p, q q≥l 0 ≤ p < q ≤ k−1
We prove that {f, f2 , ..., fr } is a generating system for A. By Lemmas 12.2.2 and 12.2.4, it is sufficient to show that the function system (12.3) belongs to [{f, f2 , ..., fr }]. Due to the choice of the function f1 and by e11 ∈ prl A, the function IV (i(xp,q )jp (xp,q )jq (xp,q ) + jp (x i (x1 )k1 (x) + p,q )jq (xp,q )) p, q q≥l 0≤p
(12.9) with pr i = pr i is a superposition over the functions f, f2 , ..., fn . If one identifies all variables = x1 and = x in (12.9) with x, one receives the function i (x1 )k1 (x). Therefore, the functions i(x) = i (x)k1 (x) and i(x1 )k1 (x2 ) = i (i(x1 ))k1 (x2 ) are also superpositions over f, f2 , ..., fn . By identifying certain variables and by substituting x1 by i(x) in (12.9), we obtain the functions i(x) + i(x1 )jp (x2 )jq (x3 ) and i(x) + jp (x1 )jq (x2 ), where q ≥ l and 0 ≤ p < q ≤ k − 1. This implies that the functions
342
12 Subclasses of Pk,2
i(x3 ) + i(x1 )jp (x2 )jq (x3 ), i(x1 ) + j0 (i(x2 ))jq (x2 ) = i(x1 ) + jq (x2 ) =: g(x1 , x2 ), g(...g(g(g (x1 , x2 ), x2 ), x2 )..., x2 ) = i(x1 ) + a · jq (x2 ) and a times i(x1 ) + i(x2 )j0 (i(x3 ))jq (x3 ) = i(x1 ) + i(x2 )jq (x3 ) for q ≥ l, 0 ≤ p < q ≤ k − 1 and a ∈ El are superpositions over {f, f2 , ..., fr }. Hence all functions of the system (12.3) belong to [{f, f2 , ..., fr }], and our theorem was proven. (b) follows from (a) with the aid of Theorem 7.1.6.
12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2 In this section, dm denotes an (m + 1)-ary function with the property dm (x2 , x1 , ..., x1 ) = dm (x1 , x2 , x1 , ..., x1 ) = ... = dm (x1 , ..., x1 , x2 ) = x1 , where m ≥ 2. We call such a function a near unanimity function. Examples of P2 are the functions hm with m ≥ 2 (see Chapter 3). To generalize Theorem 8.3.1, we get: Theorem 12.3.1 Let A be a subclass of Pk,l whose projection prl A contains a “near unanimity function” dm for a certain m ≥ 2. Then A = P olPk,l Inv m A, i.e., for a fixed m and for a fixed k there exist only finite many subclasses A ⊆ Pk,l with dm ∈ prl A. Proof.2
Obviously,
A ⊆ P ol(Inv m A).
Let f n ∈ P ol(Inv m A) be arbitrary. Further, denote fT for T ⊆ Ekn a function of Pk,l which is identical to f on tuples of T . We prove through induction on |T | =: t ≥ m that there is a certain function fT in A for every T ⊆ Ekn . f ∈ A for t = k m , with which A = P ol(Inv m A) would be proven. I) t = m: Let T = {(ai1 , ai2 , ..., ain ) | i = 1, 2, ..., m}, ⎛ ⎞ a11 a12 ... a1n ⎜ a21 a22 ... a2n ⎟ ⎟ := ⎜ ⎝ ................. ⎠ am1 am2 ... amn and let be the smallest relation of Inv m A with ⊆ , i.e., we have 2
The proof goes back to a manuscript by B. Cs´ ak´ any.
12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2
⎛
⎛
⎞
⎞
⎛
⎞
343
a1 a11 a12 ... a1n a1 ⎜ a21 a22 ... a2n ⎟ ⎜ a2 ⎟ ⎜ a2 ⎟ n ⎜ ⎜ ⎟ ⎟ ⎜ ⎟ ⎝ ... ⎠ ∈ \ ⇐⇒ ∃q ∈ A : q ⎝ . . . . . . . . . . . . . . . . . ⎠ = ⎝ ... ⎠ . am am1 am2 ... amn am (12.10) Since f n preserves the m-ary invariants of A, f () ∈ holds. If f () belongs to , a certain function of A ∩ pr−1 [e11 ] agrees with the function f on tuples of T . On the other hand, if f () ∈ \, then there is also a function fT in A.Consequently, our assertion is proven for t = m. II) t −→ t + 1: Assume for every T ⊆ Ekn with |T | = t, t ≥ m, one can find a function fT ∈ A with fT (a) = f (a) for all a ∈ T . Now, let T = {a1 , a2 , ..., at+1 } and |T | = t + 1. Because of our assumption, there are functions fi ∈ An with fi (a) = f (a) for all a ∈ T \{ai }, i = 1, 2, ..., m + 1. Since there is also a function dm ∈ A with prl dm = dm , the function dm (f1 (x), f2 (x), ..., fm+1 (x)) belongs to A. It is obvious that this function agrees with f on all tuples of T . As a direct consequence of the above proven theorem and Chapter 3, we get: Theorem 12.3.2 Let A be a clone of P2 with S∩M ⊆ A or Ta,m ∩Ta ∩M ⊆ A for certain m ∈ N \ {1} and a ∈ E2 . Then there are only finite many Aprojectable subclasses of Pk,2 . One can find the exact description of the A-projectable classes from Theorem 12.3.2 in Sections 12.6 and 12.7. To prepare for the proofs in these sections, we derive some properties of the subclasses of Pk,2 , whose projections contain a certain function hm . m Lemma 12.3.3 Let A = i=1 P olPk,l i and i ⊆ Ekhi , i = 1, 2, ..., m. Then the following statements are equivalent: (1) prl A contains the selectors of Pl . (2) There exists a mapping t from Ek onto El with the fixed points 0, 1, ..., l−1 and the property t(i ) := {(t(a1 ), t(a2 ), ..., t(aht )) | (a1 , ..., ahi ) ∈ i } . = i ∩ Elhi for every i ∈ {1, 2, ..., m}. (3) prl A =
m
i=1
P oll (i ∩ Elhi ).
Proof. Obviously, if prl A contains the selectors, there is an e11 -projectable function t ∈ A (e11 ∈ Pl ) that has the properties given in (2). Thus (1) implies (2). The implication “(3) =⇒ (1)” is trivial. It remains to be proven “(2) =⇒ (3)”: Obviously, the relations i ∩ Elhi (i = 1, 2, ..., m) can be derived from the relations 1 , ..., m and the invariants of Pk,l . This implies m m A ⊆ i=1 P olPk,l (i ∩ Elhi ). Thus, prl A ⊆ i=1 P oll (i ∩ Elhi ).
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12 Subclasses of Pk,2
m Now let g n ∈ i=1 (P oll i ∩ Elhi ) be arbitrary. The function f (x1 , ..., xn ) := g(t(x1 ), ..., t(xn )), where t fulfills the conditions from (2), m preserves all relations 1 , ..., m and has the projection g. Consequently, i=1 P oll (i ∩ Elhi ) ⊆ prl A. Hence “(2) =⇒ (3)” is proven. Theorem 12.3.4 Let A be a subclass of Pk,2 , whose projection pr2 A (⊆ P2 ) is an intersection of at least two classes that are incomparable (with respect to inclusion) and for which there exists a certain m ∈ N \ {1} with hm ∈ pr2 A. Then, A can be described as an intersection of at least two incomparable classes of Pk,2 whose projections are different from pr A. Proof. Let r ≥ 2 be the smallest number for which the function hr belongs to prA. By Theorem 12.3.1, there are certain r-ary relations 1 , ..., m with m A = i=1 P olPk,2 i . For proof of the theorem, it suffices that pr A ⊂ P olPk,2 i is correct for every i ∈ {1, 2, ..., m}. Obviously, A contains an e11 -projectable function. Consequently, by Lemma 12.3.3, pr P ol i = P ol2 (i ∩ E2r ). Further, one receives by scrutinizing the possibilities for pr A, where hr ∈ pr A, and considering the results (about the smallest arities of relations with pr A = P ol ) from Section 11.2 that pr A and P ol2 (i ∩ E2r ) are different. Hence, it holds pr A ⊂ P oli , i = 1, 2, ..., m. The following procedure for the determination of all subclasses A ⊆ Pk,2 with M ∩ S ⊆ pr2 A or Ta,m ∩ Ta ∩ M ⊆ pr2 A (a ∈ E2 , m ∈ N\{1}) results from Theorems 3.1, 12.3.1, and 12.3.4 : (1) Determination of all A-projectable subclasses of Pk,2 , where A is P2 , T0 , T1 , M , S or Ta,m (a ∈ E2 , m ∈ N\{1}). (2) Formation of “permissible” intersections that is, only formation of such intersections whose projections contain a function hm . In the first step of this procedure, because of Theorem r 12.3.1, one has to find all hi -ary relations i , i = 1, 2, ..., r, with pr i=1 P ol i ⊇ B, B ∈ {T0 , T1 , M, S, T0,m , T1,m }. The following Lemma 12.3.5 and Theorem 12.3.6 give some helpful considerations for this purpose. hi Lemma 12.3.5 Let B be a clone of P l and let i be an hi -ary relation (⊆ Ek ) r for all i ∈ {1, ..., r}. Then B ⊆ pr i=1 P olPk,l i if and only if there is a mapping t from Ek onto El with the fixed points 0, 1, ..., l − 1 and with the properties t(i ) = i ∩ Elhi and i ∩ Elhi ∈ Inv B for all i ∈ {1, ..., r}. r Proof. If B ⊆ pr i=1 P ol i , then there is an e11 -projectable function t ∈ r hi i=1 P ol i with the properties t(a) = a for all a ∈ El , t(i ) = i ∩ El hi and i ∩ El ∈ Inv B for all i ∈ {1, 2, ..., r}. Conversely, ifa mapping t r exists with these properties, then by Lemma 12.3.3, we have pr i=1 P ol i = r r r hi hi i=1 P ol (i ∩ El ). Thus, B ⊆ i=1 P ol (i ∩ El ) = pr i=1 P ol i holds hi because of i ∩ El ∈ Inv B, i = 1, ..., r.
12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2
345
Theorem 12.3.6 Let 1 , ..., r be subsets of Ek2 \E22 , ⊆ E22 , = ∅ and P ol ∈ {P2 , T0 , T1 , S, M, T0,2 , T1,2 }, i.e., w.l.o.g. let 0 0 1 1 0 1 0 0 1 0 0 1 0 1 ∈ , , , , , , , 1 0 1 0 1 0 1 1 0 0 1 0 1 1 0 0 1 0 1 0 1 0 1 , , . 0 1 1 0 0 1 1 1 0 r Then pr( i=1 P ol (∪i )) = P ol2 iff fulfills one of the following conditions: 0 0 1 1 0 1 0 1 0 1 (1) ∈ , ; 0 1 0 1 0 0 1 1 1 0 0 0 (2) = and there are no elements a1 , ..., aq , b1 , .., bq (q ≥ 2) with 0 ∈ 1 1 {a1 , b1 }, 1 ∈ {aq , bq }, {ai , bi } ∩ {ai+1 , bi+1 } = ∅ for all i ∈ {1, 2, ..., q − 1} and a1 a2 ... aq ⊆ 1 ∪ 2 ∪ ... ∪ r ; b1 b2 ... bq a (3) = , a ∈ E2 and 1 ∪ 2 ∪ ... ∪ r ⊆ (Ek \{a})2 ; a a a a a ... a (4) = , a ∈ E2 and 1 ∪ 2 ∪ ... ∪ r ⊆ Ek2 \ ; a a 2 3 ... k − 1 0 1 (5) = , (1 ∪ 2 ∪ ... ∪ r ) ∩ {(a, a) | a ∈ Ek } = ∅ and there are no 1 0 elements a1 , ..., aq , b1 , ..., bq , q ≥ 2, with the properties a1 ... aq ⊆ 1 ∪ 2 ∪ ... ∪ r ∧ b1 ... bq (∀i ∈ {1, ..., q − 1} : {ai , bi } = {ai+1 , bi+1 } ∧ {ai , bi } ∩ {ai+1 , bi+1 } = ∅) ∧ ((0 ∈ {a1 , b1 } ∧ 1 ∈ {aq , bq } ∧ q is even ∨ ({a1 , b1 } ∩ {aq , bq } = ∅ ∧ q is odd )); 0 0 1 (6) = and there are no elements a1 , ..., aq of Ek \E2 with 0 1 1 1 a1 a2 ... aq−2 aq−1 aq ⊆ 1 ∪ ... ∪ r . a1 a2 a3 ... aq−1 aq 0 Proof. One easily proves the above statements with the aid of Lemma 12.3.5. Subsequently, we deal with subclasses of Pk,2 , whose projection classes comprise linear functions. Theorem 12.3.7 Let L∩T0 ∩S ⊆ B ⊆ L. Then there exists at least countableinfinite-many B-projectable subclasses of Pk,2 for every k ≥ 3, i.e., |Nk (B)| ≥ ℵ0 . Further, for every B-projectable class A of Pk,2 and for every n ≥ 1, An has a generating system that consists of at most |A1 | + 2 functions of A.
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12 Subclasses of Pk,2
Proof. |Nk (B)| ≥ ℵ0 for L ∩ T0 ∩ S ⊆ B ⊆ L follows from the fact that the sets n LB,r := n≥1 {f n ∈ Pk,2 | (∃ai , aI : f (x) = a0 + i=1 ai · j1 (xi )+ aI · i∈I j2 (xi ) ) ∧ pr f ∈ B} + I I ⊆ {1, ..., n} |I| ≤ r
for r = 1, 2, ... are closed and LB,r = LB,r holds for r = r . Now, let A ⊆ Pk,2 and L ∩ T0 ∩ S ⊆ pr A. Then there is a function g ∈ A with (pr g)(y1 , y2 , y3 ) = y1 + y2 + y3 . Thus the function r(x1 , x2 , x3 ) := i(x1 ) + i(x2 ) + i(x3 ) with i(x) := g(x, x, x) and pr i = e11 belongs to A. We will show that for every n ≥ 1 that An has a generating system of at most |A1 | + 2 functions of A. Let An = {f1 , f2 , ..., ft }. Then, by r ∈ A, the functions q(x1 , x2 , ..., xn·t , x) :=
t
ft (x(j−1)·n+1 , ..., xj·n ) + a · i(x)
j=1
and ps (x) :=
t
fj (x, x, ..., x) + (a + 1) · i(x),
j=1 j = s
belong to A, where
a=
0, if t odd, 1, if t even.
Then we have fs (x1 , ..., xn ) = r(q(x1 , ..., x1 ,
x1
((s − 1) · n + 1)-th place
, x2 , ...,
xn
, x1 , ..., x1 , ps (x1 ), x1 )
((s · n)-th place
for s = 1, 2, ..., t. Hence, every function of An is a superposition over A1 ∪{r, q}. Theorem 12.3.7 will be specified for k = 3 through Theorem 12.6.9. The following theorem states something about the cardinality Nk (B) of the remaining classes B ⊆ L. Theorem 12.3.8 Let ∅ = B ⊆ [P21 ] and k ≥ 3. Then there are continuummany B-projectable subclasses of Pk,2 .
12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2
347
Proof. Denote N a subset of N\{1}. For every N , one can define a certain [P21 ]-projectable subset QN of Pk,2 , as follows inductively: 1 and QnN (n ≥ 2) be the set of all functions f n ∈ Pk,2 , which Let Q1N = Pk,2 fulfill the following conditions: (1) f ∈ [Qn−1 N ]ζ,τ,∇,∆ . (2) There exists a nonempty subset I of {1, 2, ..., n}, an a ∈ E2 , an n-ary function f1 ∈ [Qn−1 N ]ζ,τ,∇,∆ which depends on at least |I| variables fictin with tiously, and a function t ∈ Pk,2 f (x) = (f1 (x) ·
k1 (xi ) ∨ t(x) ·
i∈I
where a
j2 (xi ))a ,
i∈I
g :=
g if a = 1, g if a = 0.
(3) If n ∈ N , there are an h ∈ Q1N , an i of {1, ..., n} and an a ∈ E2 with f (x) = (h(xi )·
n
q=1
k1 (xq ) ∨
n
j2 (x1 )...j2 (xq−1 )j1 (xq )j2 (xq+1 )...f2 (xn ))a .
q=1
By (1), the set QN is a closed set with respect to the unary operations ζ, τ, ∇, ∆. One can show that the set QN is also closed with respect to the operation as follows: Let f n and g m be arbitrary functions of QN . Through induction on r := n+m, r ≥ 2, we will show that f g ∈ QN . If r = 2 (n = m = 1) then f g ∈ QN is obvious. Suppose for all n + m ≤ r − 1, f n g m ∈ QN holds for arbitrary f and g of QN . Now let n + m = r. f g ∈ QN is surely valid for n = 1. If n ≥ 2, then, by (1), it is sufficient to study the following cases: Case 1: f fulfills (2). In this case, the function f g is not essentially dependent from all their variables or it also fulfills the condition (2). Consequently, f g belongs to QN . Case 2: f fulfills (3) and w.l.o.g. let be a = 1. In this case, we have for i = 1: (f g)(x) = (h g)(x1 , ..., xm )k1 (xm+1 )...k1 (xm+n−1 ) ∨ g(x1 , ..., xm )j2 (xm+1 )...j2 (xm+n−1 ). For i = 1 it holds: (f g)(x) = h(xi+m−1 )k1 (xm+1 )...k1 (xm+n−1 ) ∨ g(x)j2 (xm+1 )...j2 (xm+n−1 ). Hence, the function f g has the property (2) both for i = 1 and for i = 1 . Consequently, QN is closed. It follows from the definition of the sets of type QN and from the above proof
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12 Subclasses of Pk,2
(for QN = [QN ]) that the sets QN , QN are pairwise different for N = N . Therefore, there are continuum-many [P21 ]-projectable subclasses of Pk,2 . The following facts are easy to check: For every B with ∅ = B ⊆ [P21 ] and for arbitrary N ⊆ N\{1}, the set QN ∩ pr−1 B is a B-projectable subclass of Pk,2 and it holds QN ∩ pr−1 B = QN ∩ pr−1 B for all N = N with N, N ⊆ N\{1}. This implies Theorem 12.3.8. One can deal with the infinite-digit relations defined in the following lemma as with the finite-digit relations. Further, analogously to Chapter 2, one can introduce the same concepts as in Chapter 2 for the infinite-digit relations. Lemma 12.3.9 ([Gr¨ u 84]) Let be E2∞ \{1} := {(a1 , a2 , a3 , ...) | ∀i ∈ N : ai ∈ {0, 1} ∧ ∃j ∈ N : aj = 0}, t := {(a1 , a2 , ..., at+1 , 2, 2, 2, ...) | ∃i ∈ {1, 2, ..., t + 1} : (ai = 2 ∧ ∀j ∈ {1, 2, ..., t + 1}\{i} : aj = 0)}, (t ∈ N), (q+1)
, q ∈ N, defined by 1 if x ∈ {(2, 0, ..., 0),(0, 2, 0, ..., 0),...,(0, 0, ..., 0, 2)}, fq (x) := 0 otherwise; fq
At := P olPk,2 (E2∞ \{1}) ∪ t , (t ∈ N) and
AT :=
Ai if T ⊆ N.
i∈T
Then (a) ∀i ∈ N : fi ∈ Ai ; (b) ∀i ∈ N ∀j ∈ N\{i} : fj ∈ Ai ; (c) ∀T, T ⊆ N : T = T =⇒ AT = AT . Proof. (a) follows directly from the definition of the functions fi and (c) is a conclusion from (b). Therefore, we only have to prove (b). Suppose for certain i, j ∈ N with i = j it holds fj ∈ Ai . Then there are some columns s1 , s2 , ..., sj+1 ∈ E2∞ \{1} ∪ i with fj (s1 , s2 , ..., sj+1 ) = 1.
(12.11)
Obviously, this is only valid if {s1 , ..., sj+1 } ⊆ E2∞ \{1}. The case i ⊆ {s1 , ..., sj+1 } is not possible, since in this case, the matrix (s1 , ..., sj+1 ) would have a row with at least a zero and no two, what (12.11) contradicts. Therefore we can presuppose i ⊆ {s1 , ..., sj+1 }. Then, because of i = j we have either
12.3 On the Number of the B-projectable Subclasses of Pk,2 , B ⊆ P2
349
{s1 , ..., sj+1 } ∩ (E2∞ \{1}) = ∅ or sq = sr for a certain q = r. In the first case, one finds in (s1 ..., sj+1 ) (infinite many) rows with the element 2 in at least two places and with an element of E2 . In the second case, there is a row with the element 2 in at least two places and with an element 0. In every one of these cases, a contradiction to (12.11) results with that from the definition of the functions fj . Theorem 12.3.10 ([Gr¨ u 84]) For every a ∈ E2 and every B ∈ {K, K ∪ C0 , D, D ∪ C1 , Ta,∞ ∩ Ta ∩ M, Ta,∞ ∩ M, Ta,∞ ∩ Ta , Ta,∞ } it holds |Nk (B)| = c. Proof. W.l.o.g. let a = 0 and K ⊆ B. Obviously, the sets AT , T ⊆ N, defined in Lemma 12.3.9, belong to Nk (T0,∞ ). |Nk (T0,∞ )| = c results from that then because of Lemma 12.3.9, (c). Since pr fq ∈ K ⊆ B, statements analogous to (c) of Lemma 12.3.9 are valid for the sets AT ∩ pr−1 B with B ∈ {K, K ∪ C0 , T1 , M, M ∩ T1 }. This implies the remaining assertions of our theorem result. Theorem 12.3.11 For every B ∈ {K ∪ C, K ∪ C1 , D ∪ C, D ∪ C0 } it holds |Nk (B)| = c. Proof. Let n fn (x1 , ..., xn ) = i=1 j2 (x1 )...j2 (xi−1 )j1 (xi )j2 (xi+1 )...j2 (xn ), gn (x1 , ..., xn ) = j2 (x1 )j2 (x2 )...j2 (xn ), N ⊆ N\{1} AN := [{j1 (x1 )j1 (x2 )} ∪ {fi , gj | i ∈ N\(N ∪ {1}) ∧ j ∈ N\{1}}] and ⎛ ⎞ 1 2 ... 2 ⎜ 2 1 ... 2 ⎟ i i ⎟ i := ⎜ i ∈ N\{1}. ⎝ . . . . . . . . . ⎠ ∪ Ek \{1, 2, ...k − 1} , 2 2 ... 1 It is easy to check that the functions of A{j} preserve the relations i for all i ∈ N\{1, j}. On the other hand, the function fi does not preserve the relation j . Due to this property, there are continuum-many subclasses of the type AN with the projection K ∪ C0 . Since [AN ∪ {c1 }] = [{c1 }] ∪ AN is obviously valid, we have |Nk (K ∪ C)| = c too. Since the sets K ∪ C, D ∪ C and K ∪ C1 , D ∪ C0 are isomorphic, respectively, only the proof for |Nk (K ∪ C1 )| = c is still missing. Denote fn and gn functions defined by fn (x) := fn (x) ∨ j1 (x1 )j1 (x2 )...j1 (xn )
350
or
12 Subclasses of Pk,2
gn (x) := gn (x) ∨ j1 (x1 )j1 (x2 )...j1 (xn )
and let AN := [{fi , gj | i ∈ N\(N ∪ {1}) ∧ j ∈ N}]
if N ⊆ N.
Obviously, all functions fn for n = i preserve the relation i := {1} × i ,
i ∈ N\{1}.
Furthermore, we have [AN ∪{c1 }] = [{c1 }]∪AN and pr([{c1 }]∪AN ) = K ∪C1 . Consequently, there are continuum-many K ∪ C1 -projectable subclasses of Pk,2 . With the above theorem, we are ready with a first coarse survey over |Nk (B)| for all subclasses B of P2 . One finds more precise statements over |Nk (B)| for certain B in the following section and for k = 3 in Sections 12.6 and 12.7.
12.4 The Pl-projectable and the P oll{α}-projectable Subclasses of Pk,l Let R be the set of all relations of the form 0 1 2 ... l − 1 ∪ 0 1 2 ... l − 1 with ⊆ Ek2 \El2 and R(α) := {{α} ∪ | ⊆ Ek \El }. A subset Q of R is called permissible, iff no elements a1 , ..., ar , b1 , ..., br with a1 ... ar ⊆ σ∈Q σ, {a1 , br } ⊆ El , a1 = br and {ai , bi } ∩ {ai+1 , bi+1 } = ∅ b1 ... br for all i ∈ {1, 2, ..., r} exist. Furthermore, a subset Q of R ∪ R(α) is called α-permissible, iff Q ∩ R(α) = ∅, Q ∩ R is permissible and no elements a1 , ..., ar , b1 , ..., br and no relation a1 ... ar ∈ Q ∩ R(α) with ⊆ σ∈R∩Q σ, a1 ∈ El \{α}, br ∈ \{α} and b1 ... br {ai , bi } ∩ {ai+1 , bi+1 } = ∅ for all i ∈ {1, 2, ..., r} exist. With the help of Lemma 12.3.5, it is easy to prove that P olPk,l Q for Q ⊆ R is Pl -projectable iff Q is permissible. Obviously, for Q ⊆ R ∪ R(α) we have pr(P olPk,l Q) = P oll {α} iff Q is αpermissible. Denote Tn (Q) the set of all tuples of Ekn , on which all functions of P ol Q have the value α.
12.4 The Pl -projectable and the P oll {α}-projectable Subclasses of Pk,l
351
With the help of Q ⊆ R ∪ R(α), where Q is permissible or α-permissible, one can define an equivalence relation Eq(Q) on the set of all tuples with elements of Ek as follows: (a, b) ∈ Eq(Q) :⇐⇒ ∃n : {a, b} ⊆ Ekn ∧ ({a, b} ⊆ Tn (Q)∨ ({a, b} ⊆ Tn (Q) ∧ ∀f ∈ P ol Q : f (a) = f (b))). Let σ1 , σ2 be two equivalence relations. Then σ1 is finer than σ2 , if (a, b) ∈ σ1 implies (a, b) ∈ σ2 for all a, b. We write for that σ1 σ2 For two permissible (or α-permissible) sets Q1 , Q2 , we call Q2 a minimal coarsening of Q1 , if Eq(Q1 ) Eq(Q2 ) holds and no permissible (or αpermissible) relation set Q exists with Eq(Q1 ) Eq(Q ) Eq(Q2 ). Theorem 12.4.1 Let Q be a permissible relation set. Then (1) The only maximal classes of P olPk,l Q are the following classes: (a) P olPk,l Q , where Q is an arbitrary minimal coarsening of Q, (b) prl−1 B ∩ P olPk,l Q, where B is an arbitrary maximal class of Pl . (2) The classes, defined in (a) and (b), with different definitions are pairwise incomparable (with respect to inclusion). (3) A set A ⊆ P olPk,l Q is P ol Q-complete if and only if A ⊆ M holds for every class M defined above in (a) or (b). Proof. The second statement is easy to check and (1) follows from (2) and (3). Consequently, it is sufficient to prove the statement (3). A P ol Q-complete set A is obviously no subset of an arbitrary class defined in (a) or (b). Let A ⊆ P ol Q be an arbitrary set with A ⊆ M for every class M , which is defined in (a) or (b). We consider two n-tuples a := (a1 , a2 , ..., an ), b := (b1 , b2 , ..., bn ) with (a, b) ∈ Eq(Q) and we choose a minimal j, for which there exists i1 , ..., ij ∈ {1, 2, ..., n} with ((ai1 , ..., aij ), (bi1 , ..., bij )) ∈ Eq(Q). Now, 0 1 ... l − 1 ai1 ... aij := 0 1 ... l − 1 bi1 ... bij and Q := Q ∪ {}. If Q is permissible, then Q is a minimal coarsening of Q, and thus there is a function f ∈ A with f ∈ P ol Q . If Q is not permissible, pr P ol Q = Pl holds. Hence, one can find a maximal class B of Pl with P ol Q ⊆ P ol Q ∩ pr−1 B. Therefore, there exists a function f ∈ A with f ∈ P ol Q . Obviously, for all a ∈ El , there is a ca -projectable function pa ∈ [A]. Because of pa pa = ca , all constant functions c0 , c1 , ..., cl−1 belong to [A]. Hence there is a j-ary function f1 ∈ [A] with f1 (ai1 , ..., aij ) = f1 (bi1 , ..., bij ) and, by this, there is a function f2 ∈ [A] with f2 (a1 , ..., an ) = f2 (b1 , ..., bn ). n ∈ [A] with the Now let n ≥ 1. We showed that there are functions g1n ..., gw
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12 Subclasses of Pk,2
following property: for every pair (a, b) ∈ Eq(Q) of tuples, there is a function gi with gi (a) = gi (b). Hence, for an arbitrary function f n ∈ P ol Q one can find a function g ∈ Pl with g(g1 (x), ..., gw (x)) = f (x). Since A ⊆ prl−1 B∩P olPk,l Q, where B is an arbitrary maximal class of Pl , there is a g-projectable function in [A]. Consequently, f ∈ [A]. Thus A is P ol Q-complete. As a direct consequence of Theorem 12.4.1, we get: Theorem 12.4.2 The set of the closed sets A ⊆ Pk,l with prl A = Pl is identical with the set of all classes of the form P olPk,l Q with permissible Q.
Theorem 12.4.3 (Completeness Criterion for Pk,l , [Lau 75]) For all l with 2 ≤ l ≤ k − 1 it holds: (1) The maximal classes of Pk,l are exactly the following sets: (a) prl−1B, where B is anarbitrary maximal class of Pl ; 0 1 .. l − 1 i , 0 ≤ t ≤ k − 2, l ≤ i ≤ k − 1, t < i. (b) P ol 0 1 .. l − 1 t (2) A set T ⊆ Pk,l is Pk,l -complete if and only if T ⊆ B for all classes B defined in (1). Proof. The statements (1) and (2) are consequences of Theorem 12.4.1. A proof that does not use Theorem 12.4.1 can be found in [Lau 75]. As we will see below, one can prove the following theorem similar to the above theorem. Theorem 12.4.4 Let Q be an α-permissible subset of R ∪ R(α). Then: (1) The only maximal classes of P olPk,l Q are sets of the type (a) P olPk,l Q , where Q is a minimal α-permissible coarsening of Q, and (b) pr−1 B ∩ P olPk,l Q, where B is a maximal class of P oll {α}. (2) The sets, defined in (a) and (b), with different definitions are pairwise incomparable (with respect to inclusion). (3) A set A ⊆ P olPk,l Q is P ol Q-complete if and only if A ⊆ M holds for every class M which is defined above in (a) or (b). Proof. We prove only (3), “⇐=” here. The remaining statements of the theorem are either obvious or easily provable. Let A ⊆ P olPk,l Q and A ⊆ M for every class M which is defined above in (a) or (b). Denote a := (a1 , ..., an ) an n-tuple, which does not belong to Tn (Q). Then there is a minimal j for i1 , ..., ij ∈ {1, 2, ..., n} with (ai1 , ..., aij ) ∈ Tj (Q). Now
12.4 The Pl -projectable and the P oll {α}-projectable Subclasses of Pk,l
353
we put := {α, ai1 , ..., aij } and Q := Q ∪ {}. If Q is α-permissible, then Q is a minimal coarsening of Q; thus in A there is a function f with f ∈ P ol Q . If Q is not permissible, then pr P ol Q = P oll {α}. Therefore, there exists a maximal class B of P ol {α} with P ol Q ⊆ P ol Q ∩ pr−1 B and, hence, there exists a function f ∈ A with f ∈ P ol Q in this case. Since cα ∈ [A], there is in [A] a j-ary function f1 with f1 (ai1 , ..., aij ) = α; thus there is also an n-ary function f2 ∈ [A] with f2 (a1 , ..., an ) = α. Next we consider two n-tuples a := (a1 , ..., an ), b := (b1 , ..., bn ) with (a, b) ∈ Eq(Q) and {a, b} ⊆ Tn (Q). Analogous to the considerations from proof of Theorem 12.3.1, one can prove that there is a function r ∈ [A] and that there are certain i1 , ..., ij ∈ {1, ..., n} with 0 1 ... l − 1 ai1 ... aij 0 1 ... l − 1 r ∈ . 0 1 ... l − 1 bi1 ... bij 0 1 ... l − 1 Because – as already was proven – functions s and t with s(ai1 , ..., aij ) = α and t(bi1 , ..., bij ) = α exist and because certain functions uβ with ai1 ... aij ai1 ... aij β uβ s ,t = , β ∈ El , bi1 ... aij bi1 ... aij β belong to [A], a certain function r with ai1 ... aij 0 1 ... l − 1 ∈ r bi1 ... bij 0 1 ... l − 1 is a superposition over r, u0 , ..., ul−1 . Consequently, there exists an n-ary function r ∈ [A] with r (a) = r (b). Now, let n ≥ 1. As proven above, there are functions q1 , ..., qv , g1 , ..., gw ∈ [A] with the following property: for every a ∈ Ekn \Tn (Q) there exists a qi with qi (a) = α and for every pair c, d ∈ Ekn \Tn (Q) with (c, d) ∈ Eq(Q) there exists a function gj with gj (c) = gj (d). Let f n ∈ P ol Q be arbitrary. Then one can find a function g ∈ P oll {α} with g(q1 (x), ..., qv (x), g1 (x), ..., gw (x)) = f (x). Since pr[A] = P oll {α}, there exists in [A] a g-projectable function. Consequently, f ∈ [A] holds. Hence the set A is P ol Q-complete. As a consequence of Theorem 12.4.4, we get: Theorem 12.4.5 The only P oll {α}-projectable subclasses of Pk,l with α ∈ El are sets of the form P olPk,l Q, where Q are α-permissible subsets Q of R∪R(α).
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12 Subclasses of Pk,2
12.5 The Maximal and the Submaximal Classes of Pk,2 A direct consequence of Theorem 12.4.1 is the following theorem, already proven in [Bur 74]. Theorem 12.5.1 The maximal classes of Pk,2 are exactly the following sets: (1) pr−1 B, where in P2 ; B is maximal 0 1 i (2) Zi,t := P ol , 0 ≤ t ≤ k − 2, 2 ≤ i ≤ k − 1, t < i. 0 1 t The above sets are all pairwise incomparable (with respect to ⊆), so that there are exactly 1 · (k − 2) · (k + 1) + 5 2 maximal classes of Pk,2 . Next we determine the submaximal classes of Pk,2 , i.e., we determine the maximal classes of the classes of Theorem 12.4.1. The following theorem is a special case of Theorem 12.4.1. This is easy to see considering the following facts: 0 1 i r 0 1 i 0 1 r P ol ⊆ P ol ∩ P ol 0 1 t s 0 1 t 0 1 s and
P ol
0 1 i i 0 1 t i
= P ol
0 1 i t 0 1 t t
for 0 ≤ t ≤ k − 2, 2 ≤ i ≤ k − 1, t < i. Theorem 12.5.2 (1) The maximal classes of Zi,t (0 ≤ t ≤ k − 2, 2 ≤ i ≤ k − 1, t < i) are exactly the following sets (a) Zi,t ∩ Zj,l , 0 ≤ l ≤ k − 2, 2 ≤ j ≤ k − 1, l < j, l = t or i = j, {0, 1} = {t, l} for i = j; 0 1 i j (b) P ol , 2 ≤ j ≤ k − 1, j = i for t ∈ E2 ; 0 1 t j −1 (c) Zi,t ∩ pr B, where B is a maximal class of P2 . (2) Zi,t has exactly 12 · (k − 1) · k + 2 maximal classes. A consequence from Theorem 12.4.4 is
12.5 The Maximal and the Submaximal Classes of Pk,2
355
Theorem 12.5.3 (1) pr−1 Tα (α ∈ E2 ) has exactly the following maximal classes: (a) pr−1 Tα ∩ pr−1 B, where B is Tα -maximal; (b) Zi,t ∩ pr−1 Tα , 0 ≤ t ≤ k − 2, 2 ≤ i ≤ k − 1, t < i, t = α; (c) P olPk,2 {α, i}, 2 ≤ i ≤ k − 1. (2) The classes listed in (a)– (c) are pairwise incomparable with respect to the inclusion, so that there are exactly 4 + 12 · (k − 2) · (k + 1) in pr−1 Tα maximal classes. (3) A set A ⊆ pr−1 Tα is pr−1 Tα -complete if and only if A ⊆ C holds for all classes C listed in (a)–(c).
Theorem 12.5.4 (1) pr−1 S has exactly the following maximal classes: (a) pr−1 B, where B is a maximal of S; (b) Zi,t ∩ pr−1 S,0 ≤ t <i < k, i ≥ 2; 0 1 i , 2 ≤ t < i < k. (c) S (i,t) := P ol 1 0 t (2) The classes listed in (a)– (c) are pairwise incomparable with respect to the inclusion, so that there are exactly 2 + (k − 1) · (k − 2) in pr−1 S maximal classes. (3) A set A ⊆ pr−1 S is pr−1 S-complete if and only if A ⊆ C holds for all classes C listed in (a)–(c). Proof. Let A be an arbitrary subset of pr−1 S with A ⊆ C for all classes C listed in (a)–(c). Then pr[A] = S holds. Now let f n ∈ pr−1 S be arbitrary. We show that f ∈ [A]. Let hi,t ∈ A\S (i,t) and fi,t ∈ A\Zi,t . Then, superpositions over these functions and over (suitably chosen) inverse images (∈ [A]) of functions of S are the of [A] with binary functions hi,t and fi,t
hi,t (1, i) hi,t (0, t)
=
1 1
and
(1, i) fi,t fi,t (1, t)
=
1 0
.
In [A] there is a inverse image l(x) of e11 ∈ S. It holds l(i) c l(i) c , = or = c l(t) c l(t) l(i) 1 W.l.o.g. we can assume that c = 1. In the first case = we have l(t) 1
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12 Subclasses of Pk,2
fi,t (x)
:=
fi,t (l(x), x)
∈ [A] and
(i) fi,t fi,t (t)
=
1 0
.
This implies (x), x) ∈ [A] and hi,t (x) := hi,t (fi,t
In the second case
l(i) l(t)
=
1 0
hi,t (i) hi,t (t)
=
1 1
.
we put
hi,t (x) := hi,t (l(x), x) and fi,t (x) := fi,t (hi,t (x), x),
where the above functions have the same properties as the functions in the i first case. Therefore, there are certain functions of [A], which have on t 1 1 the values or . 0 1 Now we assign a tuple of the form w := (..., hi,t (a1 ), ..., hi,t (an ), ..., fi,t (a1 ), ..., fi,t (an ), ...)
to every n-tuple a := (a1 , ..., an ) ∈ Ekn , where i, t take all possible values with 0 ≤ t ≤ k − 2, 2 ≤ i ≤ k − 1, i > t (in a fixed order). All tuples of the form w belong to a certain Cartesian product E2σ . Denote W the set of all tuples w defined above. Next we prove: If w, w ∈ W were assigned to a, a ∈ Ekn (a := (a1 , ..., an )), respectively, then it holds:
and
a = a =⇒ w = w
(12.12)
a = a ⇐⇒ w = w ,
(12.13)
where a := (a1 , ..., an ), 0 := 1, 1 := 0, a := a for all a ∈ Ek \E2 . ..., a ). Then Let a = a , where a := (a1 , n ) and a:= (a 1 , ..., an there exists a c 0 c 1 j with c := aj = aj =: d. If , (12.12) is valid = or = d 1 d 0 certainly. If {c, d} = {0, 1} and w.l.o.g. c > d, then by definition of fc,d the statement (12.12) holds. If a = a then w = w , since all considered functions belong to pr−1 S. For a = a the two cases are possible:
12.5 The Maximal and the Submaximal Classes of Pk,2
357
a p has a column with a q p 0 0 1 1 ∈ , , , . 1 0 1 q 0 a q Case 2: The matrix has a column with q ∈ E2 . a q In the second case, w = w holds. In the first case, one can w= w easily prove hi,t (i) 1 = . when one one assumes p > q considering the condition hi,t (t) 1 Case 1: The matrix
Let h be a mapping from W onto E2 defined by h(w) = h(w1 , ..., wσ ) := f (a). Because of (12.12) and (12.13), an α-ary function h1 ∈ S can be found, whose restriction onto W is identical with h. Hence there is an inverse image h of h and hi,t . Thus in [A], and, by construction, f is a superposition over h , fi,t −1 f ∈ [A] and [A] = pr S; i.e., the third statement of Theorem 12.5.4 was proven. One checks the remaining statements of the theorem easily. Lemma 12.5.5 Let A ⊆ pr−1 M , [pr M ] = M and {k1 , j0 (x1 ) · ji (x2 ) | i = 2, 3, ..., k − 1} ⊆ [A]. Then [A] = pr−1 M . Proof. Obviously, for every function g ∈ M there exists a function g ∈ [A] with pr g = g. Consequently, certain inverse images of the conjunction, disjunction, n n = c0 (n ∈ [A], pr n = c0 ), i(x) · k1 (x) = j1 (x) (i ∈ [A], pr i = pr j1 ) and j0 (c0 (x)) · jp (x) = jp (x), 2 ≤ p ≤ k − 1 are superpositions over A. One can describe every function f n = cn0 of pr−1 M by f (x1 , .., xn ) = f1 (x1 , ..., xn ) · k1 (x1 ) · ... · k1 (xn ) ∨ (a1 , ..., an ) ja1 (x1 ) · ja2 (x2 ) · ... · jan (xn ), ∈ Ekn \E2n f (a1 , ..., an ) = 1
(12.14)
where f1 ∈ [A] and pr f1 = pr f . (12.14) is obvious a superposition over A and thus [A] = pr−1 M .
Theorem 12.5.6 (1) pr−1 M has exactly the following maximal classes: (a) pr−1 B, where B is maximal in M ; (b) Zi,t ∩ pr−1 M , 2 ≤ t < i < k;
358
12 Subclasses of Pk,2
(0,r) (c) M , M (r,s) , 1≤ s < k, 2 ≤ r < k; 0 1 0 a (a,b) := P ol . M 0 1 1 b (2) The sets, defined in a)–(c), with different definitions are pairwise incomparable (with respect to inclusion) so that pr−1 M has exactly 4 + 32 (k − 1) · (k − 2) maximal classes. (3) A set A ⊆ pr−1 M is pr−1 M -complete if and only if A ⊆ T holds for every class T which is defined in (a)–(c).
Proof. Obviously, if [A] = pr−1 M , then A is not a subset of the sets (a)–(c). Now let A be subset of pr−1 M with A ⊆ T for every class T defined in (a)–(c). Then we have [pr A] = M and c0 , c1 ∈ [A]. Further, [A] contains functions fi,t , gr,s , qr and pr with the properties: fi,t ∈ Zi,t ,
gr,s ∈ M (r,s) ,
qr ∈ M (r,r) ,
pr ∈ M (0.r) .
, gr,s , qr and pr with Then certain unary or binary functions fi,t (i) = fi,t (t), fi,t 0 r 1 gr,s , = 1 s 0
qr
0 r 1 r
=
1 0
and
pr
0 0 1 r
=
1 0
,
2 ≤ t < i ≤ k − 1, 1 ≤ s ≤ k − 1, 2 ≤ r ≤ k − 1 are obvious superpositions over {c0 , c1 , fi,t , gr,s , qr , pr }. For the function (x), x), if fi,t (i) = 0, gi,t (fi,t fi,t (x) := gt,i (fi,t (x), x), if fi,t (i) = 1, (a) for a ∈ {i, t}. Thus w.l.o.g. we can assume for all (a) = fi,t it holds fi,t (i) = 1 and fi,t (i) = 0. permissible i, t in the following: fi,t Let i ∈ [A], pr i = pr j1 and let E be the set of all A ∈ Ek \E2 with i(a) = 0. (i(x), x) =: gr,1 (x), we have gr,1 (r) = 1 and gr,1 (1) = Then, for r ∈ E and gr,1 0. Consequently, i(x) ∨ gr,1 (x) = j0 (x) r∈E
and r−1
qr (i(x1 ), x2 )·gr,1 (i(x1 ), x2 )·(
fr,t (x2 ))·(
t=2
k−1
fi,r (x2 )) = j0 (x1 )·jr (x2 ) ∈ [A]
i=r+1
for r ≥ 2. Furthermore, it holds k−1
r=2
pr (j0 (c0 (x)) · jr (x), x) = k1 (x) ∈ [A].
12.5 The Maximal and the Submaximal Classes of Pk,2
359
Thus, we showed that the generating system for pr−1 M of Lemma 12.5.5 belongs to [A]. Therefore, the set A is pr−1 M -complete. One checks the remaining statements of the theorem easily. We come now to the maximal classes of pr−1 L. First we give some remarks on a possible description of functions of pr−1 L. Because of j0 = 1 + j1 (x) + ... + jk−1 (x) it follows from Section 12.1 that every function f n ∈ Pk,2 has an unambiguous description (up to the order of the summands) of the form aI1 ,...,Ik−1 · kI1 ,...,Ik−1 (x), (12.15) f (x) = a + I1 , ..., Ik−1 ⊆ {1, 2, ..., n}
where aI1 ,...,Ik−1 ∈ E2 , kI1 ,...,Ik−1 (x1 , ..., xn ) :=
k−1
ji (xq )
(12.16)
i=1 q∈Ii
and the sets I1 , ..., Ik−1 in (12.15) are pairwise disjunct. The functions kI1 ,...,Ik−1 with aI1 ,...,Ik−1 = 1 in (12.15) are called components of f . Let Kf be the set of all components of f . Denote kf,I an n-ary function of the form kI1 ,...,Ik−1 (x), kf,I (x) := I1 , ..., Ik−1 I1 ∪ ... ∪ Ik−1 = I kI1 ,...,Ik−1 ∈ Kf
where I ⊆ {1, 2, ..., n}. Lemma 12.5.7 Let {f, g, h} ⊆ pr−1 L, (pr g)(y1 , y2 ) = y1 + y2 and (pr h)(y) = y. Then every function of the form kf,I is a superposition over {c0 , f, g, h}. Proof. It is easy to see that the function f (x) := f (x) + f (0, 0, ..., 0) is a superposition over the functions f and h. Denote r the smallest number, for which f has a component with r essential variables. W.l.o.g. let f (x) = kf,{1,2,...,r} + f (x). Then it holds f (x1 , ..., xr , c0 , ..., c0 ) = kf,{1,2,...,r} (x) ∈ [{c0 , f, g, h}] and
f (x) = g(f (x), kf,{1,2,...,r} (x)) ∈ [{c0 , f, g, h}],
where Kf ⊂ Kf ⊆ Kf and every component of f has at least r essential variables. Through repetition of this construction, one receives the statement of the lemma.
360
12 Subclasses of Pk,2
Theorem 12.5.8 (1) pr−1 L has exactly the following maximal classes: (a) pr−1 B, where B is a maximal class of L; (b) Zi,t ∩ pr−1 L, 2 ≤ t < i < k; (c) Lq := P olPk,l {(q, q, q, q), (a, b, c, d) | {a, b, c, d} ⊆ E2 ∧ a + b = c + d (mod 2)}, 2 ≤ q < k. (2) The classes listed in (a)–(c) are pairwise incomparable (with respect to the inclusion) so that there are exactly 4+ 12 (k−1)·(k−2) pr−1 L-maximal classes. (3) A set A ⊆ pr−1 L is pr−1 L-complete if and only if A ⊆ Q holds for all classes Q listed in (a)–(c). Proof. The statements (1) and (2) are consequences from (3). Since “=⇒” of (3) is trivial, we prove only (3), “⇐=”. Let A be a subset of pr−1 L with A ⊆ Q for all classes Q which are defined in (a)–(c). Because of A ⊆ pr−1 B, B maximal in L, pr [A] = L holds. Consequently, c0 , c1 ∈ [A] and one can find functions g, h ∈ [A] with (pr g)(y1 , y2 ) = y1 +y2 and (pr h)(y) = y. Since A is, in addition, not a subset of the sets Zi,t , 2 ≤ t < i ≤ k − 1, there are unary functions gi,t ∈ [A] with gi,t (i) = 1 and gi,t (t) = 0, t = i, 2 ≤ i ≤ k − 1, 2 ≤ t ≤ k − 1. Let now q ∈ {2, 3, ..., k − 1}. Since the functions of A not all preserve the relation ⎛ ⎞ 0 0 0 1 1 0 1 1 q ⎜0 0 1 1 0 1 0 1 q⎟ ⎜ ⎟ ⎝ 0 1 0 0 1 1 0 1 q ⎠, 0 1 1 0 0 0 1 1 q a function f with pr(f (x1 , ..., xn , q)) ∈ L belongs to [A]. Then by the maximality of L in P2 and by pr[A] = L, for every function um ∈ P2 there is a (m + 1)-ary function u ∈ [A] with u (y1 , ..., ym , q) = u(y1 , ..., ym ). Consequently, a function of the form k v(x1 , ..., xk ) = a + i=1 ai ji (xi ) + j1 (x1 ) · ... · j1 (xk−1 ) · jq (xk ) + k−1 p=2,p=q vp (x1 , ..., xk−1 ) · jp (xk ) belongs to [A] for some a, ai ∈ E2 and some functions vp ∈ Pk,2 . By Lemma 12.5.7 the functions of the type kv,I , I ⊆ {1, 2, ..., k}, are superpositions over A. If one adds all functions of the form kv,I with |I| ≤ k − 1 to v, one receives so the function
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
361
v(x1 , ..., xk ) := j1 (x1 ) · ... · j1 (xk−1 ) · jq (xk ) + aI1 ,...,Ik−1 · kI1 ,...,Ik−1 (x) · jp (xk ), I1 , ..., Ik−1 , p I1 ∪...∪Ik−1 = {1, ..., k−1} p ∈ {2, 3, ..., k − 1}\{q}
which also belongs to [A] and for which v (x1 , x2 , gq,2 (x3 ), gq,3 (x3 ), ..., gq,q−1 (x3 ), gq,q+1 (x3 ), ..., gq,k−1 (x3 ), x3 ) = j1 (x1 ) · j1 (x2 ) · jq (x3 ) ∈ [A] holds. With the help of (12.15) it is easy to see that every function of pr−1 L is a superposition over {c0 , c1 , g, h} ∪ {j1 (x1 )j1 (x2 )jq (x3 ) | q ∈ {2, 3, ..., k − 1}}. Thus, [A] = pr−1 L.
12.6 The Classes A with M ∩ T0 ∩ T1 ⊆ prA or L ∩ T0 ∩ S ⊆ prA or prA = M ∩ S In this and in the following section, we specify the cardinality statements of Section 12.3 about Nk (A) (A ∈ L2 ) for k = 3. In addition, we provide a concrete description of the elements of N3 (A) if |N3 (A)| ≤ ℵ0 is valid. Table 12.1 gives a first survey of these statements. The statements of the last three rows of Table 12.1 were proven already in Theorems 12.3.8, 12.3.10, and 12.3.11. The cardinality statements of the eighth row are a consequence of Theorem 12.3.1. The remaining statements in the table result from the following theorems. Theorem 12.6.1 It holds: (1) (2) (3) (4)
N3 (P2 ) = {P3,2 , Z2,0 , Z2,1 }; N3 (S) = {pr−1 S, pr−1 S ∩ Z2,0 , pr−1 S ∩ Z2,1 }; (2) N3 (Ta ) = {pr−1 Ta , Ta , pr−1 Ta ∩ Z2,0 , pr−1 Ta ∩ Z2,1 } (a ∈ E2 ); (2) (2) N3 (T0 ∩ T1 ) = {pr−1 (T0 ∩ T1 ), T0 ∩ pr−1 (T0 ∩ T1 ), T1 ∩ pr−1 (T0 ∩ T1 ), Z2,0 ∩ pr−1 (T0 ∩ T1 ), Z2,1 ∩ pr−1 (T0 ∩ T1 )}; (2) (2) (5) N3 (T0 ∩ S) = {pr−1 (T0 ∩ S), T0 ∩ pr−1 (T0 ∩ S), T1 ∩ pr−1 (T0 ∩ S), −1 −1 Z2,0 ∩ pr (T0 ∩ S), Z2,1 ∩ pr (T0 ∩ S)}.
(One finds Hasse diagrams of some of the sets listed above in the Figure 12.1.)
362
12 Subclasses of Pk,2 Table 12.1 B P2 , S
|N3 (B)| 3
Ta (a ∈ E2 )
4
T0 ∩ T1 , T0 ∩ S
5
M
23
M ∩ Ta (a ∈ E2 )
36
M ∩ T0 ∩ T1
49
Ta,2 (a ∈ E2 )
148
Ta,m , Ta,m ∩ Ta , Ta,m ∩ M, Ta,m ∩ Ta ∩ M, S ∩ M
< ℵ0
(a ∈ E2 , m ∈ {2, 3, ...}) L, L ∩ T0 , L ∩ T1 , L ∩ S, L ∩ T0 ∩ S Ta,∞ , Ta,∞ ∩ Ta , Ta,∞ ∩ M, Ta,∞ ∩ Ta ∩ M (a ∈ E2 )
c
K ∪ C, K ∪ Ca , K, D ∪ C, D ∪ Ca , D (a ∈ E2 )
c
[P21 ],
c
I ∪ C, I, I ∪ Ca , I, C, Ca (a ∈ E2 )
pr −1 P2
pr −1 T0
Z2,0
ℵ0
Z2,1
(2) T0
pr −1 T0 ∩ T1
pr
−1
T0 ∩ Z2,1
pr−1 T0 ∩ Z2,0
(2) pr −1 T0 ∩ T1 ∩ T0 (2) −1 pr
T0 ∩ T1 ∩ T1
pr −1 T0 ∩ T1 ∩ Z2,0
pr −1 T0 ∩ T1 ∩ Z2,1
Fig. 12.1
Proof. The intersections of pr−1 B, B ⊆ P2 , with Z2,0 or Z2,1 are always the smallest B-projectable subclasses of P3,2 . Thus, (1) is a consequence from Theorem 12.5.1 and (2) is a consequence from Theorem 12.5.4. By Theorem 12.5.3, the maximal classes of pr−1 Ta belonging to N3 (Ta ) are just the sets (2) Z2,a ∩ pr−1 Ta and Ta = P olP3,2 {a, 2}. With the aid of Theorem 12.4.4, it is easy to see that Z2,a ∩ pr−1 Ta is the only Ta -projectable maximal class of (2) Ta . From that and from the above remarks, (3) follows. By Theorem 12.3.4, the statements (4) and (5) are consequences from (1)–(3).
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
363
We come now to the M -projectable subclasses A of P3,2 . Because of h2 ∈ M , Theorem 12.3.1, and Lemma 12.3.5 one can find some 1 , ..., m ⊆ E32 \E22 and an A with pr A = P2 for such class A so that & %m 0 0 1 P ol ∪ i ∩ A (12.17) A= 0 1 1 i=1
holds. Because of Theorem 12.3.6, (6) must be valid for the relations 1 , ..., m in addition: 2 1 (12.18) ⊆ 1 ∪ 2 ∪ ... ∪ m . 0 2 We call relations 1 , ..., m with the above property (12.18) M -permissible. The following lemma gives some properties of M -projectable subclasses of P3,2 , which we need to prove Theorem 12.6.3. Lemma 12.6.2 Let be the relations 1 , ..., m ⊆ E32 \E22 M -permissible and let a ∈ E2 . Then: 0 0 1 0 0 1 (1) 1 ⊆ 2 =⇒ P ol ∪ 2 ⊆ P ol ∪ 1 ; 0 1 1 0 1 1 m a 2 0 0 1 (2) ⊆ 1 ∪ ... ∪ m =⇒ i=1 P ol ∪ i ⊆ pr−1 M ∩ Z2,a ; 2 a 0 1 1 0 0 1 1 0 0 1 0 1 (3) P ol = P ol ; 0 1 1 2 2 0 1 1 2 0 0 1 0 2 0 0 1 0 0 0 1 2 (4) P ol = P ol ∩ P ol ; 0 1 1 1 0 1 1 2 1 0 1 1 2 0 0 1 1 2 0 0 1 0 1 2 (5) P ol = P ol ; 0 1 1 2 2 0 1 1 2 2 2 0 0 1 2 2 0 0 1 2 0 0 1 2 (6) P ol = P ol ∩ P ol ; 0 1 1 0 1 0 1 1 0 0 1 1 1 0 0 1 2 2 0 0 1 2 2 2 (7) P ol = P ol ; 0 1 1 0 2 0 1 1 0 1 2 0 0 1 0 2 2 0 0 1 0 2 0 0 1 2 2 (8) P ol = P ol ∩ P ol . 0 1 1 2 1 2 0 1 1 2 2 0 1 1 1 2 Proof. The statement (1) is trivial. Since ⎧ 0 0 1 0 2 ⎪ ⎪ ⎨ 0 1 1 2 0 0 0 1 2 0 0 1 a ◦ =: = 0 1 1 a 0 1 1 2 ⎪ 0 0 1 1 2 ⎪ ⎩ 0 1 1 2 1 0 1 0 1 2 and ( ∩ τ ) ◦ = , we have 0 1 0 1 a 0 0 1 2 0 0 1 a P ol ∩ ⊆ pr−1 M 0 1 1 a 0 1 1 2
2 2 2 2
2 if a = 0, 1 0 if a = 1 2
∩ Z2,a .
364
12 Subclasses of Pk,2
With the aid of (1), statement (2) results. (3) follows from (1) and 0 0 1 0 0 1 1 0 0 1 0 1 ◦ = . 0 1 1 0 1 1 2 0 1 1 2 2 Because of (1) and 0 0 1 2 0 0 1 0 0 0 1 2 0 ◦ = 0 1 1 1 0 1 1 2 0 1 1 1 2 (4) holds. (5) follows from (1) and 0 0 1 1 2 0 0 1 1 2 0 0 1 0 1 2 ◦ = . 0 1 1 2 2 0 1 1 2 2 0 1 1 2 2 2 The classes from (6) 1, 1 → 0, 2 → 2). The last statement of 0 0 1 0 0 1 1 2
or (7) are isomorphic to those from (3) or (4) (0 → the lemma follows from (1) and 2 0 0 1 2 2 0 0 1 0 2 2 ◦ = . 2 0 1 1 1 2 0 1 1 2 1 2
Theorem 12.6.3 The M -projectable subclasses of P3,2 are exactly the following: (1) pr−1 M , (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12)
0 0 1 0 M := P ol , 0 1 1 2 0 0 1 2 M (22) := P ol , 0 1 1 2 0 0 1 2 M (21) := P ol , 0 1 1 1 0 0 1 1 M (12) := P ol , 0 1 1 2 M (02) ∩ M (22) , M (02) ∩ M (21) , M (21) ∩ M (22), 0 0 1 2 (20) M := P ol , 0 1 1 0 M (12) ∩ M (22) , 0 0 1 0 2 M (02)(22) := P ol , 0 1 1 2 2 M (02) ∩ M (22) ∩ M (21) , (02)
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
(13) M (21)(22) := P ol (14) (15) (16) (17) (18) (19) (20) (21) (22) (23)
0 0 1 2 2 0 1 1 1 2
M (20) ∩ M (22) , M (12) ∩ M (02)(22) , M (21) ∩ M (02)(22) , M (02) ∩ M (21)(22) , M (20) ∩ M (21)(22) , 0 M (02)(12)(22) := P ol 0 0 M (02)(21)(22) := P ol 0 0 M (20)(21)(22) := P ol 0 −1 pr M ∩ Z2,1 , pr−1 M ∩ Z2,0
0 1 0 1 0 1
1 1 1 1 1 1
0 2 0 2 2 0
,
1 2 2 1 2 1
2 , 2 2 , 2 2 , 2
(see Figure 12.2).
pr−1 M
M (2,1) M M (2,0) M (1,2) M (2,1),(2,2) (0,2),(2,2) M M M (0,2),(2,1),(2,2) M (2,1),(2,0),(2,2) M (0,2),(1,2),(2,2) (0,2)
(2,2)
pr−1 M ∩ Z2,1
pr−1 M ∩ Z2,0
Fig. 12.2
365
366
12 Subclasses of Pk,2
Proof. Because of Lemma 12.6.2 (1), 0 0 1 0 0 1 1 0 0 1 0 1 ◦ = 0 1 1 0 1 1 2 0 1 1 2 2 or
0 0 1 2 0 1 1 0
0 0 1 0 0 1 2 2 ◦ = 0 1 1 0 1 1 0 1
we have M (12) ⊆ M (02) or M (20) ⊆ M (21) . With the help of Table 12.2 one can prove the other inclusions (non-inclusions) of the classes (1) - (23). In Table 12.2, the sign + (or −) shows whether a function fi (i = 1, ..., 10) belongs (or does not belong) to a class of the left column of the table, respectively.
1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23.
pr−1 M M (02) M (22) M (21) M (12) M (02) ∩ M (22) M (02) ∩ M (21) M (21) ∩ M (22) M (20) M (12) ∩ M (22) M (02)(22) M (02) ∩ M (22) ∩ M (21) M (21)(22) M (20) ∩ M (22) M (12) ∩ M (02)(22) M (21) ∩ M (02)(22) M (02) ∩ M (21)(22) M (20) ∩ M (21)(22) M (02)(12)(22) M (02)(21)(22) M (20)(21)(22) pr−1 M ∩ Z21 pr−1 M ∩ Z20
j1 + + + + − + + + + − + + + + − + + + − + + − +
Table 12.2 j0 j2 k1 f1 + + + + + + − + + + + − + − + − + + − + + + − − + − − − + − + − − − + − + + − − + + − − + − − − + − + − − − + − + + − − + − − − + − − − − − + − + + − − + − − − − − + − + − − − − − − −
f2 + − − + − − − − + − − − − − − − − − − − − − −
f3 + + + − + + − − − + − − − − − − − − − − − − −
f4 + + − + − − + − − − − − − − − − − − − − − − −
f5 + + + + − + + + − − + + − − − + − − − − − − −
f6 + + + + + + + + − + − + + − − − + − − − − − −
f7 + + + + − + + + + − − + − + − − − − − − − − −
f8 + + + + − + + + − − − + + − − − + − − − − − −
The functions f1 –f10 from the above table are defined as follows: f1 (x1 , x2 ) := j0 (x1 )j2 (x2 ), f2 (x1 , x2 ) := j1 (x1 )j2 (x2 ), f3 (x1 , x2 ) := k1 (x1 )j2 (x2 ), f4 (x1 , x2 ) := j0 (x1 )j2 (x2 ) ∨ j1 (x2 ),
f9 + + + − + + − − − + + − − − + − − − − − − − −
f10 + − + + − − − + + − − − + + − − − + − − − − −
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
367
f5 (x1 , x2 ) := j1 (x1 )j1 (x2 ) ∨ j2 (x1 )j2 (x2 ), f6 (x1 , x2 ) := k1 (x1 )j0 (x2 ) ∨ j2 (x1 )j1 (x2 ), f7 (x1 , x2 ) := k1 (x1 )k1 (x2 ) ∨ j2 (x1 )j2 (x2 ), f8 (x1 , x2 ) := k1 (x1 )j2 (x2 ) ∨ j1 (x2 ), f9 (x1 , x2 ) := j1 (x1 )j2 (x2 ), f10 (x1 , x2 ) := j0 (x1 )j2 (x2 ).
Thus it remains to show that no further classes are described by (12.17) than the ones listed above. By Theorem 12.6.1, only the sets P3,2 , Z2,0 , and Z2,1 are possible for A in (12.17). Since pr−1 M ∩ Z2,0 and pr−1 M ∩ Z2,1 are minimal M -projectable classes of P3,2 , the M -projectable classes different from these classes are described as follows m 0 0 1 P ol ∪ i , (12.19) 0 1 1 i=1
where the relations 1 , ..., m are M -permissible subsets of E32 \E22 . With the aid of the statement (2) of Lemma 12.6.2 and considering (12.18), one can be convinced that the relations i , i = 1, ..., m, must be from the set
0 1 2 2 2 0 1 0 2 0 2 1 2 , , , , , , , , , 1 2 21 2 2 2 2 2 2 0 2 2 2 2 2 2 2 2 0 1 2 0 2 2 2 2 2 , , , , , . 0 1 0 2 1 2 2 2 2 2 1 2 0 1 2
Because of Lemma 12.6.2, (3)–(8) we can assume that the relations 1 , ..., m belong to
0 2
1 2 2 2 0 2 2 2 0 1 2 2 2 2 , , , , , , , , . 2 0 1 2 2 2 1 2 2 2 2 0 1 2
Now it is not difficult to find all classes, which are describable through (12.19), in a step-by-step way. Because of Lemma 12.6.2, (1) or Theorem 12.5.6, the largest M -projectable classes lying below pr−1 M are the sets M (02) , M (22) and M (21) . Then (with the help of Lemma 12.6.2, (2)) possible intersections of these sets and the next largest classes of the form (12.19) with m = 1 belong to layers 1–4 in Figure 12.2. As intersections of classes of the fourth layer (i.e., as next classes of the form (3) with m = 1), only the classes of the fifth layer are possible, and so forth. Theorem 12.6.4 Let a ∈ E2 . Then N3 (M ∩ Ta ) = {A ∩ pr−1 M ∩ Ta | A ∈ N3 (M )}∪ (2) ∪{A ∩ Ta | A ∈ N3 (M ) ∧ A ⊆ M (12) ∧ A ⊆ M (20) } and
|N3 (M ∩ Ta )| = 36.
368
12 Subclasses of Pk,2
Proof. W.l.o.g. let a = 0. Put A3 := M ∩ T0 . It is easy to check that the 36 sets given in the theorem are all A3 -projectable and pairwise different (see Figure 12.3). By Theorem 12.3.4, for every class A of N3 (A3 ) there are certain sets A1 , A2 with A = A1 ∩ A2 , A1 ∈ N3 (M ), and A2 ∈ N3 (T0 ). Because of Theorem 12.3.6, (3) the sets of N3 (A3 ) different from Z2,0 ∩ pr−1 A3 and Z2,1 ∩ pr−1 A3 belong to the set (2)
{A ∩ pr−1 A3 , A ∩ T0
| A ∈ N3 (M )\{Z2,0 ∩ pr−1 M, Z2,1 ∩ pr−1 M }}
(2)
(20)
(2)
Since pr(T0 ∩ M (12) ) = M ∩ T0 and pr(M0 ∩ pr−1 (M ∩ T0 )) ⊆ T0 is obviously valid, the set N3 (A3 ) agrees with the set given in Theorem 12.6.4, and it holds |N3 (A3 )| = 36 by Theorem 12.6.3.
Theorem 12.6.5 Exactly 49 subclasses of P3,2 are M ∩ T0 ∩ T1 -projectable, and it holds N3 (M ∩ T0 ∩ T1 ) = {A ∩ pr−1 (M ∩ T0 ∩ T1 ) | A ∈ N3 (M )}∪ (2)
{A ∩ Ta
| a ∈ E2 ∧ A ∈ N3 (M ) ∧ A ⊆ M (12) ∧ A ⊆ M (20) }
(see Figure 12.4, where A4 := M ∩ T0 ∩ T1 ). Proof. Analogous to the considerations in the proof of Theorem 12.6.4 the statements from Theorem 12.6.5 are a consequence of Theorems 12.3.4, 12.6.1, and 12.6.3, where one must consider that (2)
∩ M (12) ∩ pr−1 T1 ) = M ∩ T0 ∩ T1
(2)
∩ M (20) ∩ pr−1 T0 ) = M ∩ T0 ∩ T1 .
pr(T0 and
pr(T1
Fig. 12.3
pr−1 A3 ∩ Z2,0
(2) −1 −1 (0,2) −1 (2,2) −1 (2,1) pr A3 ∩ M pr A ∩ M pr A 3 3 ∩M pr A3 ∩ T0 −1 (1,2) pr A3 ∩ M (2,1),(2,2) −1 (0,2),(2,2) −1 pr A3 ∩ M pr A3 ∩ M pr−1 A3 ∩ M (2,0) pr−1 A3 ∩ M (0,2),(2,1),(2,2) pr−1 A3 ∩ M (0,2),(1,2),(2,2) pr−1 A3 ∩ M (2,0),(2,1),(2,2) pr−1 A3 ∩ Z2,1
pr−1 A3
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S 369
−1
pr −1 A4 ∩ Z2,1
Fig. 12.4
pr −1 A4 ∩ Z2,0
pr A4 −1 −1 −1 (2) (2) (0,2) (2,2) pr −1 A4 ∩ T pr −1 A4 ∩ T0 pr A4 ∩ M pr A4 ∩ M pr A4 ∩ M (2,1) 1 −1 (0,2),(2,2) −1 (2,1),(2,2) ∩M ∩M pr−1 A4 ∩ M (2,0) pr A4 pr A4 pr −1 A4 ∩ M (1,2) (0,2),(2,1),(2,2) pr −1 A 4 ∩M pr−1 A4 ∩ M (2,0),(2,1),(2,2) pr −1 A4 ∩ M (0,2),(1,2),(2,2)
370 12 Subclasses of Pk,2
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
371
Now we come to the determining of sets N3 (A) with A ∈ {L, L ∩ T0 , L ∩ T1 , L ∩ S, L ∩ T0 ∩ S}. As already shown in Section 12.5 while preparing proof of Theorem 12.5.8, there are some a, ai , aI,J of E2 with f (x) = a +
n i=1
ai j1 (xi ) +
aI,J · kI,J (x)
(12.20)
I, J I ∪ J ⊆ {1, ..., n} I ∩J =∅ J = ∅
for every function f n ∈ pr−1 L. The functions
kI,J (x) := ( j1 (xi )) · ( j2 (xj )) i∈I
j∈J
with aI,J = 1 in (12.20) are called components of f . Let Kf bethe set of all components of f . Further, let K := f ∈pr−1 L Kf and KM := f ∈M Kf , M ⊆ P3,2 . It is easy to check that the subsequently defined subsets of pr−1 L are closed and are finitely generated by the given subsets: ⎛ ⎞ 0 0 0 1 1 0 1 1 2 ⎜0 0 1 1 0 1 0 1 2⎟ ⎟ L2 := P ol ⎜ ⎝0 1 0 0 1 1 0 1 2⎠ 0 1 1 0 0 0 1 1 2 = {f ∈ pr−1 L | Kf ⊆ {kI,J ∈ K | |I| ≤ 1}} = [j1 (x1 ) + j1 (x2 ), c1 , j1 (x1 ) · j2 (x2 )], L2,r := {f ∈ pr−1 L | Kf ⊆ {kI,J ∈ K | I = ∅ ∧ |J| ≤ 4}} if r < ∞, [j1 (x1 ) + j1 (x2 ), c1 , j2 (x1 ) · ... · j2 (xr )] ' ( = {j1 (x1 ) + j1 (x2 ), c1 } ∪ q≥1 j2 (x1 ) · ... · j2 (xq )} if r = ∞ (1 ≤ r ≤ ∞), Z2,0 ∩ pr−1 L n = n≥1 {f n ∈ P3,2 | ∃a, a1 , ..., an ∈ E2 : f (x) = a + i=1 ai · j1 (xi )}, = [j1 (x1 ) + j1 (x2 ), c1 ], Z2,1 ∩ pr−1 L = n≥1 {f n ∈ P3,2 | ∃a, a1 , ..., an ∈ E2 : n f (x) = a + i=1 ai · (j1 (xi ) + j2 (xi ))}, = [j0 (x1 ) + j0 (x2 ), c1 ].
372
12 Subclasses of Pk,2
Further put K := {kI,J ∈ K | J = ∅ ∧ I ∩ J = ∅}, K1 := {kI,J ∈ K | |I| ≥ 1}, K2 := {kI,J ∈ K | |I| ≤ 1}, K3 := K1 ∩ K2 = {kI,J ∈ K | |I| = 1}, K0,r := {k∅,J ∈ K | |J| ≤ r},
1 ≤ r ≤ ∞.
Lemma 12.6.6 Let f n ∈ P3,2 , pr f n = cn0 , f n = cn0 and Kf ⊆ K0,∞ . Further, let r be the smallest number for which there is a function k∅,J ∈ Kf with |J| = r. Then k∅,{1,...,r} (x) = j2 (x1 ) · ... · j2 (xr ) ∈ [f, j1 ]. Proof. By assumption, in Kf there is a function k∅,J with J ⊆ J for all k∅,J ∈ Kf \{k∅,J }. Consequently, we have f (h1 (x1 ), ..., hn (xn )) = k∅,J (x), if
hi (x) :=
j1 (x) if i ∈ J, x if i ∈ J
and i = 1, ..., n. Lemma 12.6.7 Let f n ∈ P3,2 , pr f n = cn0 and Kf ⊆ K0,∞ . Then there is an a ∈ E2 with (1) j1 (x1 )j2 (x2 ) + a · j2 (x2 ) ∈ [f, j1 ]; (2) j1 (x1 )j1 (x2 )j2 (x3 ) + a · j2 (x3 ) ∈ [f, j1 ], if furthermore Kf ∩ (K1 \K2 ) = ∅ holds. Proof. First we prove (1) through induction on the arity n of f . n = 2: Since Kf ⊆ K0,∞ we can assume w.l.o.g. f 2 (x1 , x2 ) = j1 (x1 )j2 (x2 ) + α · j2 (x1 )j1 (x2 ) + β · j2 (x1 ) + γ · j2 (x2 )+ (α, β, γ, δ ∈ E2 ). +δ · j2 (x1 )j2 (x2 ) Thus we have f (j1 (x1 ), x2 ) = j1 (x1 )j2 (x2 ) + γ · j2 (x2 ), i.e., (1) is right for n = 2. n − 1 −→ n: Suppose (1) holds for all (n − 1)-ary functions f with pr f = cn−1 0 and Kf ⊆ K0,∞ , n > 2. Now let f be an arbitrary n-ary function with pr f = cn0 and Kf ⊆ K0,∞ . Then there are (n − 1)-ary functions g, h and q with (w.l.o.g.) f (x) = j1 (x1 ) · g(x2 , ..., xn ) + j2 (x1 ) · h(x2 , ..., xn ) + q(x2 , ..., xn ),
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
373
where g = cn−1 . Consequently, 0 f (j1 (x1 ), x2 , ..., xn ) = j1 (x1 ) · g(x2 , ..., xn ) + q(x2 , ..., xn ) =: f (x). Case 1: Kg ⊆ K0,∞ . With the aid of the proof of Lemma 12.6.6, it is easy to see that j1 (x1 )j2 (x2 )+ a · j2 (x2 ) is a superposition over {f , j1 } for certain a ∈ E2 . Case 2: Kg ⊆ K0,∞ . By induction assumption, the function j1 (x2 )j2 (x3 ) + b · j2 (x3 ) is a superposition on g and j1 for certain b ∈ E2 . Thus we can construct the function f (x1 , x2 , x3 ) := j1 (x1 )(j1 (x2 )j2 (x3 ) + b · j2 (x3 )) + q (x2 , x3 ), where q denotes a c0 -projectable function, as a superposition over f and j1 (under the given conditions). For b = 1 we have f (x1 , x2 , x2 ) = j1 (x1 )j2 (x2 ) + a · j2 (x2 ),
a := q (2, 2).
If b = 0 then we construct the function f (x1 , x2 , x3 ) := f (x1 , j1 (x2 ), x3 ) = j1 (x1 )j1 (x2 )j2 (x3 ) + α · j1 (x2 )j2 (x3 ) + β · j2 (x3 ) first. Consequently, f (x2 , x1 , x2 ) = j1 (x1 )j2 (x2 ) + β · j2 (x2 ) if α = 1, and
f (x1 , x1 , x2 ) = j1 (x1 )j2 (x2 ) + β · j2 (x2 )
in the case α = 0. Hence (1) holds for each n-ary function f ∈ P3,2 with pr f = cn0 and Kf ⊆ K0,∞ . Proof for (2) is obtained through the transfer of proof for (1). Lemma 12.6.8 Let B ∈ {L, L ∩ T0 , L ∩ S, L ∩ T0 ∩ S}, A ⊆ Z2,0 ∩ pr−1 B and [pr A] = B. Then (1) (2) (3) (4) (5) (6) (7)
pr−1 B = [A ∪ {j1 (x) + j1 (x1 )j1 (x2 )j2 (x3 ), j1 (x) + j2 (x1 )}], L2 ∩ pr−1 B = [A ∪ {j1 (x) + j1 (x1 )j2 (x2 ), j1 (x) + j2 (x1 )}], (2) T0 ∩ pr−1 B = [A ∪ {j1 (x) + j1 (x1 )j1 (x2 )j2 (x3 )}], (2) T0 ∩ L2 ∩ pr−1 B = [A ∪ {j1 (x) + j1 (x1 )j2 (x2 )}], L2,r ∩ pr−1 B = [A ∪ {j 1 (x) + j2 (x1 )j2 (x2 )...j2 (xr )}], r ≥ 1, L2,∞ ∩ pr−1 B = [A ∪ q≥1 {j1 (x) + j2 (x1 )j2 (x2 )...j2 (xq )}], Z2,0 ∩ pr−1 B = [A].
Proof. The proof results from definitions of the considered classes.
374
12 Subclasses of Pk,2
Theorem 12.6.9 Let B ∈ {L, L ∩ T0 , L ∩ S, L ∩ T0 ∩ S}. Then the following B-projectable classes (⊆ P3,2 ) only exist: (1) (2) (3) (4) (5) (6) (7)
pr−1 B, L2 ∩ pr−1 B, L2,r ∩ pr−1 B, r = 1, 2, ..., L2,∞ ∩ pr−1 B, Z2,a ∩ pr−1 B, a ∈ E2 , (2) Ta ∩ pr−1 B, a ∈ E2 , if B ∩ Ta = B, (2) Ta ∩ L2 ∩ pr−1 B, a ∈ E2 , if B ∩ Ta = B
(see Figure 12.5).
pr −1 L
L2 L2,∞ L2,r L2,2 L2,1 pr −1 L ∩ Z pr −1 L ∩ Z 2,0
2,1
Fig. 12.5
Proof. Let A be a B-projectable subclass of P3,2 . Then, j1 or j1 + j2 belongs to A. W.l.o.g. we can assume j1 ∈ A, since s j1 s = j1 + j2 holds for s(x) := 2x+1 (mod 3) and thus all considerations are in the case j1 ∈ A isomorphically to those of the case j1 + j2 ∈ A. Consequently, we have Z2,0 ∩ pr−1 B ⊆ A and j1 (x1 ) + j1 (x 2 ) + j1 (x3 ) ∈ A. For KA (= f ∈A Kf ) the following cases are possible: Case 1: KA ⊆ K0,∞ (i.e., A ⊆ L2,∞ ). Case 1.1: KA = ∅. In this case we have: A = Z2,0 ∩ pr−1 B. Case 1.2: It exists an r ≥ 1 with KA ⊆ K0,r−1 and KA ⊆ K0,r . Then, there is a function f n ∈ A with Kf ∩ K0,r = ∅. Consequently, the function f1 (x, x) := j1 (x) + f (j1 (x1 ), ..., j1 (xn )) + f (x) = j1 (x) + f1 (x) with
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
f1 (x) :=
375
k∅,J (x).
k∅,J ∈Kf
belongs to A. By Lemma 12.6.6, one can construct the function j2 (x1 )...j2 (xt ), where t := min |J|, k∅,J ∈Kf
f1
and j1 . Consequently, j1 (x) + j2 (x1 )....j2 (xt ) ∈ A as a superposition over for t ≤ t. A superposition over these functions and f1 is also f2 (x, x) := j1 (x) + f1 (x) + k∅,J ∈ Kf k∅,J (x) |J| ≤ t
= j1 (x) +
f2 (x)
with f2 (x) :=
k∅,J ∈ Kf k∅,J (x). |J| > t
If f2 = cn0 , then we have the function j2 (x1 )...j2 (xs ), where s :=
min
k∅,J ∈Kf , |J|>t
|J|,
by substituting certain variables by j1 and by possibly changing the numbering of the variables from f2 . Consequently, the function k∅,J (x) f3 (x, x) := j1 (x) + k∅,J ∈ Kf |J| > s
belongs to A, etc. By iterated application of these constructions we obtain the function j1 (x) + j2 (x1 )...j2 (xr ) ∈ A. Hence, by Lemma 12.6.8, (5), we have A = L2,r ∩ pr−1 B. Case 1.3: KA ∩ K0,r = ∅ for all r ≥ 1. Because of the considerations from Case 1.2 and Lemma 12.6.8, (6) is valid: A = L2,∞ ∩−1 B. A = L2,∞ ∩−1 B. Case 2: KA ⊆ K2,∞ . In this case, there is a function f n ∈ A with Kf ∩ K1 = ∅. Then, the function f1 (x, x) := j1 (x) + f (x) + f (j1 (x1 ), ..., j1 (xn )) = j1 (x) + f1 (x) with
f1 (x) := j1 (x) +
kI,J (x)
kI,J ∈Kf
belongs to A. With the aid of Lemma 12.6.6, it is easy to see that the function
376
12 Subclasses of Pk,2
f1 (x1 , x2 ) := j1 (x1 )j2 (x2 ) + a · j2 (x2 ), a ∈ E2 is a superposition over {j1 , f1 }. Therefore, the function g(x, x1 , x2 ) := j1 (x) + j1 (x1 )j2 (x2 ) + a · j2 (x2 ) is a superposition on {f1 , j1 }, i.e., g ∈ A. Consequently, g(g(x, x1 , x2 ), x2 , x2 ) = j1 (x) + j1 (x1 )j2 (x2 ) (2)
belongs to A. Then, by Lemma 12.6.8, we have T0 ∩ L2 ∩ pr−1 B ⊆ A. If (2) A = T0 ∩ L2 ∩ pr−1 B then the following three cases are possible: Case 2.1: A ⊆ L2 and pr A ⊆ T0 . In this case, there is a function p ∈ A with p(0) = 1. For (pr p)(y) = y it holds j1 (x) + j1 (x1 )j2 (x1 ) = j1 (x) + j2 (x1 ) ∈ A. If pr p = c1 then we also obtain j1 (x) + j2 (x1 ) = j1 (x) + p(p(x1 ))j2 (x1 ) ∈ A. Consequently, by Lemma 12.6.8, A = L2 ∩ pr−1 B. (2)
Case 2.2: A ⊆ L2 , pr A ⊆ T0 and pr A ⊆ T0 . In this case, there is a function r2 ∈ A with r(0, 0) = 0 and r(0, 2) = 1, and it holds that j1 (x) + r(j1 (x1 ), x1 ) + r(j1 (x1 ), j1 (x1 )) = j1 (x) + j2 (x1 ) ∈ A. Therefore, by Lemma 12.6.8, A = L2 ∩ pr−1 B. Case 2.3: A ⊆ L2 . Denote q an n-ary function of A, which does not belong to L2 . Then, q1 (x, x) := j1 (x) + q(x) + q(j1 (x1 ), ..., j1 (xn )) = j1 (x) + q1 (x), where
q1 (x) :=
kI,j (x),
kI,J ∈Kq
is a function of A. By Lemma 12.6.6, a function of the form j1 (x1 )j1 (x2 )j2 (x3 ) + a · j2 (x3 ) is a superposition over {q1 , j1 }. Thus, q2 (x, x1 , x2 , x3 ) := j1 (x) + j1 (x1 )j1 (x2 )j2 (x3 ) + a · j2 (x3 ) ∈ A and therefore q2 (q2 (x, x1 , x2 , x3 ), x3 , x3 ) := j1 (x) + j1 (x1 )j1 (x2 )j2 (x3 ) ∈ A.
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S (2)
377
(2)
Thus by Lemma 12.6.8, we have T0 ∩ pr−1 B ⊆ A. If a = T0 ∩ pr−1 B, then there is either a function p ∈ A with p(0) = 1, or a function r ∈ A with r(0, 0) = 0 and r(0, 2) = 1. As already shown in the above Case 2.1 or 2.2, j1 (x) + j2 (x1 ) ∈ A results. Thus by Lemma 12.6.8, (1), A = pr−1 B holds. Next we study the set N3 (T0,m ) with m ∈ N\{1}. By Theorem 12.3.1 (or 12.3.2), for every m ∈ N\{1}, we know that N3 (T0,m ) is a finite set. In the following, we determine the elements of N3 (T0,m ) and we show that |N3 (T0,2 )| = 148 holds. Since the description of the elements of the other sets N3 (A) with S ∩ M ⊆ A or Ta,m ∩ Ta ∩ M ⊆ A requires a lot of place, we must renounce this description here and refer the reader to the dissertation by N. Gr¨ unwald (see [Gr¨ u 84]). In the dissertation by N. Gr¨ unwald, one also finds the proofs left out in the following. Lemma 12.6.10 For every set P olP3,2 (E2m \{1} ∪ j )) T := A ∩ ( j∈J (2)
with A ∈ {T0 , P3,2 }, j ⊆ E3m \E2m , and every set B := {g ∈ K | g has the value 1 on at most m tuples} ∪ {g1m+1 } with pr g1m+1 = hm (∈ P2 ; see Chapter 3) it holds [B] = T . Proof. Let f n ∈ T and let a1 , ..., ar be the tuples of E3n , on which the function f n has the value 1. By induction on r, we prove f n ∈ [B]: For r ≤ m the assertion is obviously right. For r > m we assume that all functions of T , which have the value 1 on less than r tuples, belong to [B]. By definition of T , the functions 0 if x = ai , n fi (x) := f n (x) otherwise (i = 1, ..., m + 1) belong to T . Thus, by assumption, we have f1 , ..., fn ∈ [B]. Then our assertion follows from f n (x) = g1 (f1 (x), f2 (x), ..., fm+1 (x)) ∈ [B]. Lemma 12.6.11 Let W1,m := P olP3,2 (E3m \{1}), W2,m := P olP3,2 (E3m \{1, 2}m ). Then (a) For arbitrary sets Ai ⊆ Wi,m (i ∈ {1, 2}) with [pr Ai ] = T0,m the set B1 := A1 ∪ {j1 (x1 ) · j2 (x2 ), j1 (x), j1 (x1 ) · j0 (x2 )}
378
12 Subclasses of Pk,2
is a generating system for W1,m and B2 := A2 ∪ {j1 (x1 ) · j2 (x2 ), j1 (x), j1 (x1 ) · j0 (x2 )} is a generating system for W2,m . (b) The set pr−1 T0,2 ∩ Z2,0 is maximal in W1,m . (c) The set pr−1 T0,2 ∩ Z2,1 is maximal in W2,m . (d) For all A ∈ N3 (T0,m )\{pr−1 T0,2 ∩Z2,0 , pr−1 T0,2 ∩Z2,1 } it holds W1,n ⊆ A. Proof. See [Gr¨ u 84]. Lemma 12.6.12 Let A be a set of the following form P ol ((E2m \{1}) ∪ i ) mit i ⊆ (E3m \(E2m ∪ {2})), m ≥ 2.
(12.21)
i∈I
Then (1) A is T0,m -projectable and the only maximal classes of A that belong to N3 (T0,m ) are the following classes: (2) (a) A ∩ T0 ; (b) A ∩ P ol ((E2m \{1} ∪ δ), where δ fulfills the following conditions: δ ⊆ (E3m \(E2m ∪ {2}, ∃i ∈ I : δ ⊆ i , ∀ε ⊂ δ∃i ∈ I : εi . (2) If B ⊆ A, [pr B] = T0,m , B ⊆ Z2,i ∩ pr−1 T0,m , i = 0, 1, and if B is not contained in the sets of the above type (a) or (b), then [B] = A holds. (3) If special A = W2,m , then Z2,1 ∩ pr−1 T0,m is the only T0,m -projectable maximal class of W2,m . Proof. See [Gr¨ u 84]. Lemma 12.6.13 Denote A a set of the form (2) P ol ((E2m \{1}) ∪ i ) mit i ⊆ (E3m \E2m , m ≥ 2. T0 ∩
(12.22)
i∈I
Then: (1) A is T0,m -projectable, and the only maximal classes of A, which belong to N3 (T0,m ), are classes of the following form: A ∩ P ol ((E2m \{1} ∪ δ), where δ fulfills the following conditions: δ ⊆ E3m \E2m , ∃i ∈ I : δ ⊆ i , ∀ε ⊂ δ∃i ∈ I : εi .
(12.23)
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S
379
(2) If B ⊆ A, [pr B] = T0,m , B ⊆ Z2,i ∩ pr−1 T0,m , i = 0, 1, and B ⊆ C for every class C that was described in (1), then it holds [B] = A. (3) If in particular A = W1,m then Z2,0 ∩pr−1 T0,m is the only T0,m -projectable maximal class of W1,m . Proof. See [Gr¨ u 84]. Theorem 12.6.14 ([Gr¨ u 84]) There are only finitely many subclasses of P3,2 , which are T0,m -projectable. One receives a concrete description of these subclasses with the aid of Lemmas 12.6.12 and 12.6.13. Proof. See [Gr¨ u 84]. In the following table are explanations to notations that we need to describe the T0,2 -projectable subclasses of P3,2 .
i 1 2 3 4 5 6 7 8 9
Table 12.3
τi 1 2 0 2 2 2 1 2 2 1 1 2 2 2 1 0 2 2 1 2 2 0 2 2 0 2 2 0 0 2
i
10 11 12 13 14 15 16 17 18 19
1 2 1 2 2 1 2 1 2 1 0 2 1 2 2 1 1 2 2 1 2 2 1 0 1 2 0 2 1 2
2 1 2 1 2 0 0 2 2 0 2 0 0 2 0 2 0 2 2 0
τi
0 2 2 2 2 2 2 2 0 2 2 2 2 0 2 2 2 2 2 2
Theorem 12.6.15 ([Gr¨ u 83;a;b]) 0 0 1 ∪ τi for i = 1, 2, ..., 19. Let τ0 := {0, 2} and τi := 0 1 0
380
12 Subclasses of Pk,2
There are exactly 148 T0,2 -projectable subclasses of P3,2 that can be described as follows: 1): pr−1 T0,2 , 2)–5): P ol τi with i ∈ {0, 1, 2, 3}, 6)–10): P ol {τi , τj } with (i, j) ∈ {(1, 3), (1, 2), (2, 3), (1, 0), (2, 0)}; 11)–12): P ol {τi , τj , τk } with (i, j, k) ∈ {(1, 2, 3), (1, 2, 0)}; 13)–18): P ol τi with i ∈ {4, 5, 6, 7, 8, 9}; 19)–30): P ol {τi , τj } with (i, j) ∈ {(4, 3), (4, 2), (4, 0), (5, 2), (6, 3), (6, 0), (7, 3), (7, 0), (8, 1), (9, 0), (9, 1), (9, 3)}; 31)–34): P ol {τi , τj , τk } with (i, j, k) ∈ {(4, 2, 3), (4, 2, 0), (9, 1, 3), (9, 1, 0)}; 35)–49): P ol {τi , τj } with (i, j) ∈ {(4, 5), ((4, 6), (4, 7), (4, 8), (4, 9), (5, 6), (5, 7), (5, 8), (5, 9), ((6, 7), (6, 8), (6, 9), (7, 8), (7, 9), (8, 9)}; 50)–63): P ol {τi , τj , τk } with (i, j, k) ∈ {(4, 5, 2), (4, 6, 0), (4, 7, 0), (4, 6, 3), (4, 7, 3), (4, 9, 0), (4, 9, 3), (6, 7, 0), (6, 7, 3), (6, 9, 4), (6, 9, 3), (7, 9, 0), (7, 9, 3), (8, 9, 1)}; 64)–69): P ol τi with i ∈ {10, 11, 12, 13, 14, 15}; 70)–75): P ol {τi , τj } with (i, j) ∈ {(10, 0), (10, 3), (11, 2), (14, 0), (14, 3), (15, 1)}; 76)–95): P ol {τi , τj } with (i, j) ∈ {(10, 5), (10, 8), (10, 9), (14, 0), (11, 6), (11, 7), (11, 9), (12, 4), (12, 7), (12, 9), (13, 4), (13, 7), (13, 9), (14, 4), (14, 5), (14, 8), (15, 4), (15, 5), (15, 7)}; 96)–99): P ol {τi , τj , τk } with (i, j, k) ∈ {((10, 9, 0), (10, 9, 3), (14, 4, 0), (14, 4, 3)}; 100)–114): P ol {τi , τj } with (i, j) ∈ {(10, 11), (10, 12), (10, 13), (10, 14), (10, 15), (11, 12), (11, 13), (11, 14), (11, 15), (12, 13), (12, 14), (12, 15), (13, 14), (13, 15), (14, 15)}; 115)–117): P ol τi with i ∈ {16, 17, 18}; 118)–119): P ol {τi , τj } with (i, j) ∈ {(16, 0), (16, 3)}; 120)–123): P ol {τi , τj } with (i, j) ∈ {(16, 8), (16, 5), (17, 9), (18, 4)}; 124): P ol {τ16 , τ8 , τ5 }; 125)–132): P ol {τi , τj } with (i, j) ∈ {(16, 15), (16, 12), (16, 13), (16, 11), (17, 15), (17, 14), (18, 11), (18, 10)}; 133)–134): P ol {τi , τj , τk } with (i, j, k) ∈ {(16, 15, 5), (16, 11, 8)}; ∈ {(16, 15, 12), (16, 15, 14), 135)–142): P ol {τi , τj , τk } with (i, j, k) (16, 15, 11), (16, 12, 13), (16, 12, 11), (16, 13, 11), (17, 15, 14), (18, 11, 10)}; 143)–144): P ol {τi , τj } with (i, j) ∈ {(16, 17), (16, 18), (17, 18)}; 146): P ol τ19 ; 147)–148): Z2,1 ∩ pr−1 T0,2 , Z2,0 ∩ pr−1 T0,2 . Proof. The following five statements are direct consequences from Lemmas 12.6.12 and 12.6.13:
12.6 The Classes A with M ∩T0 ∩T1 ⊆ prA or L∩T0 ∩S ⊆ prA or prA = M ∩S (02)(20)
(1) T0,2
:= P ol
0 1 0 0 2 0 0 1 2 0
381
has exactly the following T0,2 -projectable
maximal classes: (2) (02)(20) a) T0 ∩ T0,2 ; 0 1 0 1 (02)(20) b) T0,2 ∩ P ol ; 0 0 1 2 c) Z2,1 ∩ pr−1 T 0,2 . 2 0 2 1 0 1 0 and A = (2) If A := P ol ∪ i with i ⊆ 0 2 1 2 0 0 1 0 1 0 0 2 P ol , then A has exactly the following T0,2 -projectable 0 0 1 2 0 maximal classes: (2) a) T0 ∩ A; 0 1 0 b) A ∩ P ol ∪ δ , where δ fulfills the conditions 0 0 1 2 0 2 1 δ⊆ 0 2 1 2 ∃i ∈ I : δ ⊆ i ∀ε ⊂ δ ∃i ∈ I : ε ⊆ i . 0 1 0 2 0 2 1 2 (2) then Z2,0 ∩ pr−1 T0,2 is the only (3) If A = T0 ∩ P ol 0 0 1 0 2 1 2 2 maximal class of A, which is T0,2 -projectable. 0 1 0 2 0 2 1 2 (2) ∪ i with i ⊆ and (4) If A := T0 ∩ P ol 0 0 1 0 2 1 2 2 0 1 0 2 0 2 1 2 A = P ol , then A has exactly the following T0,2 0 0 1 0 2 1 2 2 projectable maximal classes: 0 1 0 A ∩ P ol ∪ δ , where δ fulfills the following conditions: 0 0 1
2 0 2 1 2 0 2 1 2 2 ∃i ∈ I : δ ⊆ i ∀ε ⊂ δ ∃i ∈ I : ε ⊆ i . δ⊆
(5) There is not any proper subset of Z2,i ∩ pr−1 T0,2 , i = 0, 1, whose projection agrees with T0,2 . With the aid of the above statements, our theorem can be proven as follows: 0 0 1 −1 One obtains the T0,2 -projectable maximal classes of pr T0,2 = P ol 0 1 0 by means of (2). Then, one obtains the T0,2 -projectable maximal classes of these classes by means of (1)–(4), etc.
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13 Classes of Linear Functions
In this chapter, the elements of the clone Lk :=
n≥1
n
{f ∈ Pk | ∃a0 , ..., an ∈ Ek : f (x) = a0 +
n
ai · xi (mod k)}.
i=1
and the elements of a generalization of the set Lk are called linear functions. The lattice of the subclasses of Lk belongs to the earliest and best investigated sublattices of Lk . For the case that k is a prime number, all subclasses, which are no subsets of [L1k ], were determined by A. A. Salomaa in [Sal 64]. The results of [Sal 64] were also proven by J. Bagyinszki and J. Demetrovics in [Bag-D 82] and complemented with the remaining subclasses of [L1k ], p ∈ P. ´ Szendrei. For examMany results about linear functions were obtained by A. ple, she proven in [Sze 78] that Lk has only finitely many subclasses, if k is square-free.1 In addition, she showed in [Sze 78] that an arbitrary class has at most the order 2 (or 3), if k is square-free and k is an odd number (or an even number), respectively. One finds in [Sze 80] a short and fine determination of the subclasses not contained in [L1p ] of Lp (p prime). Similarly Theorem 13.2.1 is proven here. For the case that k is not square-free one easily find a class that does not have any finite basis (see Lemma 13.3.7). In Section 13.1, we start with properties of certain subclasses of the set Ud := n≥1 {f n ∈ Lk | ∃a0 , ..., an ∈ Ek ∃j ∈ {1, ..., n} : f (x) = a0 + aj · xj + d · i=1,i=j ai · xi }. This set is closed, if d is a divisor of k (notation: d | k). Then, with the aid of the results from the first section new proofs are given for the theorems of [Sal 64] and [Bag-D 82]. Section 13.3 gives a survey of further results, which were ´ Szendrei and the author, to classes from linear found by A. A. Bulatov, A. functions. 1
Through that, a presumption of A. A. Salomaa from [Sal 64] was confirmed.
384
13 Classes of Linear Functions
13.1 Some Properties of the Subclasses of Ud That Contain rd In this section, let d ∈ Ek be a divisor of k. Further, the ternary function rd is defined by rd (x, y, z) := x + d · y − d · z (mod k). Lemma 13.1.1 For every subclass T of Ud , which contains the function rd , it holds: (a) T = [T 1 ∪ {rd }], (b) T = Lk ∩ P olk {(a, a + b) | a + bx ∈ T 1 }. Proof. (a): Let f n ∈ T be arbitrary and w.l.o.g. f (x1 , ..., xn ) = a0 + a1 x1 + d ·
n
ai xi .
i=2
Obviously, one can obtain every function of the type g(x1 , ..., xm ) := x1 + d ·
m
bi xi with b2 + ... + bm = 0 (mod k)
i=2
by identifying variables of a function of the form rd rd ... rd . In particular, the function f (x, y, x1 , ..., xn ) := x + d(−(a2 + ... + am )y +
n
ai xi )
i=1
is a superposition over rd . Consequently, by f (x1 , ..., xn ) = f (f (x1 , ..., x1 ), x1 , x2 , ..., xn ), we have f ∈ [T 1 ∪ {rd }]. (b): Because of (a), T = Lk ∩P olk G1 (T ) holds. The matrix G1 (T ) is, however, unambiguously determined by the first two rows (x = 0, x = 1). Thus we have T = Lk ∩ pr0,1 G1 (T ), where pr0,1 G1 (T ) = {(a, a + b) | a + bx ∈ T 1 }. n Lemma 13.1.2 Let f (x1 , ..., xn ) = a0 + a1 x1 + d · i=2 ai xi and a1 ' k = a2 ' k = 1. Then, the function rd is a superposition over f . Proof. Let f1 (x, y, z) := f (x1 , x2 , x3 , ..., x3 ). Then, the functions fi (x, y, z) := fi−1 (f1 (x, z, z), y, z), i = 2, 3, ... are superpositions over f . Since a2 ' k = 1, there exists a t with at1 = 1 (mod k). Consequently, ft (x, y, z) = a + x + a2 dy + bdz for certain a, b ∈ Ek .
13.1 Some Properties of the Subclasses of Ud That Contain rd
385
The functions ft,1 := ft and ft,i (x, y, z) := ft,i−1 (ft (x, y, z), y, z), i = 2, 3, ... belong to [{f }]. Since a2 ' k = 1, there exists an s with a2 s = 1 (mod k). Consequently, ft,s (x, y, z) = as + x + dy + sbdz is valid. Next we form the superpositions ft,s,1 := ft,s and ft,s,i (x, y, z) := ft,s,i−1 (ft,s (x, y, z), y, z), i = 2, 3, ... For i = k we obtain ft,s,k (x, y, z) = x+dy +(k−1)dz, i.e., rd is a superposition over f . Subsequently, the subclasses of Lk that contain the function r1 are determined. Obviously, a subset A ⊆ L1k determines a subclass T of the form T = [T 1 ∪{r1 }] if and only if [A ∪ {r1 }]1 = A holds. Further we have: Lemma 13.1.3 (a) If [A ∪ {r1 }]1 = A for a subset A of L1k , then the binary relation A := {(a, a + b − 1) | a + bx ∈ A} is a subgroup of the direct product (Ek ; +)2 . (b) Conversely, if γ is a subgroup of (Ek ; +)2 , then [Aγ ∪ {r1 }]1 = A, where Aγ := {a + bx ∈ L1k | (a, a + b − 1) ∈ γ}. Proof. (a): Let (a, a + b − 1), (a , a + b − 1) ∈ A be arbitrary, i.e., the functions a + bx and a + b x belong to A. Then, by assumption, r1 preserves the functions x, a + bx and a + b x of A. Consequently, r1 (a + bx, a + b x, x) = a + a + (b + b − 1)x ∈ A holds and therefore (a + a , a + a + b + b − 2) ∈ A . Thus, by definition of , we have (a, a + b − 1) + (a , a + b − 1) ∈ A for arbitrary (a, a + b − 1), (a , a + b − 1) ∈ A . Hence, A is a subgroup of (Ek ; +)2 . (b): We have to show that Aγ is closed in respect to the operation and that the function r1 preserves the functions of Aγ . Let f (x) := a + bx, g(x) := a + b x and h(x) := a + b x be arbitrary of Aγ . Then the function (f g)(x) = a + a b + bb x belongs to Aγ , since (a, a + b − 1) ∈ γ, (a , a + b − 1) ∈ γ and (a, a + b − 1) + b · (a , a + b − 1) = (a + a b, a + a b + bb − 1) ∈ γ.
386
13 Classes of Linear Functions
Further r1 (a + bx, a + b x, a + b x) = (a + a − a ) + (b + b − b )x holds. Since (a + a − a , a + a − a + b + b − b − 1) = (a, a + b − 1) + (a , a + b − 1) − (a , a + b − 1) and γ is a group, the function (a + a − a ) + (b + b − b )x belongs to Aγ . Consequently, we have [Aγ ∪ {r1 }]1 = Aγ . When we summarize Lemmas 13.1.1–13.1.3, or as a consequence of [Sze 80], Lemma 4.3, we obtain: Theorem 13.1.4 The lattice of the closed subsets of Ud (d|k), which contain the function rd , is finite for arbitrary k ∈ N and is isomorphic to the subgroup lattice of the group (Ek ; +)2 for d = 1. One can describe the subgroups of the group (Ek ; +)2 easily. The subsequently given description is a special case of Theorem 4.3.1 from [Sco 64], p. 71: Theorem 13.1.5 (a) Let γ be a subgroup of (Ek ; +)2 . Then γ1 := {a | ∃b ∈ Ek : (a, b) ∈ γ}, γ2 := {b | ∃a ∈ Ek : (a, b) ∈ γ}, N2 := {b | (0, b) ∈ γ} N1 := {a | (a, 0) ∈ γ}, are subgroups of (Ek ; +), Ni ⊆ γi (i = 1, 2) and the mapping α from the factor set γ1 /N1 onto the factor set γ2 /N2 with α(a + N1 ) = b + N2 :⇐⇒ (a, b) ∈ γ is an isomorphism from γ1 /N1 onto γ2 /N2 . (b) Conversely: Let γ1 , γ2 , N1 , N2 be subgroups of (Ek ; +) with Ni ⊆ γi (i = 1, 2) and let α be an isomorphism from γ1 /N1 onto γ2 /N2 . Then γ := {(a, b) | a ∈ γ1 ∧ b ∈ γ2 ∧ α(a + N1 ) = b + N2 } is a universe of a subgroup of (Ek ; +)2 . With the help of Theorem 13.1.5 and with well-known theorems about cyclic groups, one can easily determine the cardinality of Lk ([{r1 }], Lk ). For this purpose, let ϕ be the Euler function (i.e., ϕ(n) is the number of all q ∈ {1, 2, ..., n − 1} with n ' q = 1) and let t(q, k) be the number of all n ∈ N with n|k and q|n.
13.2 The Subclasses of Linear Functions of Pk with k ∈ P
Theorem 13.1.6 It holds: |Lk ([{r1 }], Lk )| =
387
ϕ(q) · (t(q, k))2 .
q q ∈ N, q|k
Proof. Because of Theorem 13.1.4, we have to determine only the number of the subgroups of (Ek ; +)2 to the proof. Let γ ⊆ Ek2 be a subgroup of (Ek ; +)2 . This holds (by Theorem 13.1.5) if and only if there exist subgroups γi , Ni (Ni ⊆ γi , i = 1, 2) of (Ek ; +) and an isomorphism α from γ1 /N1 onto γ2 /N2 with γ = {(a, b) | α(a+N1 ) = b+N2 }. Moreover, it holds |γ1 /N1 | = |γ2 /N2 | =: q and q|k. Since (Ek ; +) is a cyclic group, the groups γi , Ni and γi /Ni (i = 1, 2) are cyclic. Therefore, for fixed q and k, there are exactly t(q, k) possibilities for the choice of γi /Ni (i ∈ {1, 2}). Further, if g is a generating element of γ1 /N1 , then the mapping α is completely determined by α(g), where α(g) is a generating element of γ2 /N2 . As is generally known, a cyclic group of the order q has exactly ϕ(q) generating elements. Thus, for determining the mapping α there are exactly ϕ(q) possibilities. Consequently, for γ with |γ1 /N1 | = |γ2 /N2 | = q there are exactly ϕ(q) · (t(q, k))2 possibilities, whereby our assertion is proven. We notice that one can prove further properties of the elements of Lk ([{r1 }], Lk ) with the aid of Lemma 13.1.1. For example, every subclass T of Lk with r1 ∈ T is finitely axiomatizable (see [McK 78]) and such a class has only finite many congruences, which are determined through the congruences on [{r1 }] and of (T 1 ; ) (see Chapter 9).
13.2 The Subclasses of Linear Functions of Pk with k ∈ P In this section, let p be an arbitrary prime number. Because of Lemma 13.1.2, every class A ⊆ Lp with A ⊆ [L1p ] contains the function r1 . Therefore, by Lemma 13.1.3 and Theorem 13.1.4, such a class A is determined by a certain subgroup of the group (Ek ; +)2 . Obviously, by Theorem 13.1.5, there are only the following p + 3 subgroups of (Ek ; +)2 : Ep2 , {(0, 0)}, {(0, x) | x ∈ Ep }, and {(x, t · x) | x ∈ Ep }, if t ∈ Ep . Consequently, by Section 13.1, we have
Theorem 13.2.1 ([Sal 64], [Bag-D 82], [Sze 80]) Lp has exactly p + 3 subclasses which are not subsets of [L1p ]:
388
13 Classes of Linear Functions
Lp Lp ∩ P olp {(0, 1)} n (= n≥1 {f n ∈ Lp | f (x1 , ..., xn ) = i=1 ai xi ∧ a1 + ... + an = 1 } = [r1 ]), Lp ∩ n P olp {(x, x + 1) | x ∈ Ep } (= n≥1 {f n ∈ Lp | f (x1 , ..., xn ) = a0 + i=1 ai xi ∧ a1 + ... + an = 1 }), Lp ∩ P olp {0} and Lp ∩ P olp {(x, tx + 1) | x ∈ Ep } (= Lp ∩ P olp {(1 − t)−1 }), where t ∈ Ep \{1}. Since one obtains an arbitrary subclass A of [L1p ] from a subsemigroup A1 of (L1p ; ) by means of [A1 ]ζ,τ,∇ , it is sufficient to determine the subsemigroups of (L1p ; ) for the description of the remaining subclasses of Lp . Let A be an arbitrary subsemigroup of (L1p ; ). Then A = A ∪ CA , where A is either the empty set or a subgroup of the group S := ({ax+b | a ∈ Ep \{0}}; ) and CA ⊆ {ca | a ∈ Ep } =: C. If A = ∅ then the set Ua := {a | ∃b : ax + b ∈ A } is a subgroup of the group G := (Ep \{0}; ·). Now, one can easily see that for an arbitrary subgroup U of G, G/U =: {N1 , N2 , ..., Np−1 }, α ∈ Ep and 1 I ⊆ {1, 2, ..., p−1 |U | } the following subsets of Lp are closed in respect to : Tα,U := {ax + (1 − a)α | a ∈ U } (⊆ L1p ∩ P olp {α}), SU := {ax + b | a ∈ U ∧ b ∈ Ep }, Tα,U ∪ Cα,U,I with Cα,U,I := {cα+n (mod p) | n ∈ i∈N Ni } and Cα,U,∅ := {cα }, Tα,U ∪ Cα,U,I ∪ {cα } and SU ∪ C. Theorem 13.2.2 ([Bag-D 82]) An arbitrary subsemigroup of (L1p ; ) is either a subset of C or has the form Tα,U , SU , Tα,U ∪ Cα,U,I , Tα,U ∪ Cα,U,I ∪ {cα } or SU ∪ C. Proof. Let A be an arbitrary subsemigroup of (L1p ; ) with A = A ∪ CA (A ⊆ S, CA ⊆ C). The following cases are possible: Case 1: CA = ∅. 1.1.: A ⊆ L1p ∩ P ol{α} for a certain α ∈ Ep . In this case, A has the form Tα,U , since L1p ∩ P ol{α} is a cyclic group. 1.2.: For all α ∈ Ep it holds A ⊆ L1p ∩ {α}. Then A = {x} and A contains a function x + a (a = 0) or at least two functions of the form f (x) := bx + (1 − b)β, g(x) := cx + (1 − c)γ with c, b ∈ Ep \{0, 1} and β = γ, since a function ax + b with a ∈ Ep \{0, 1} has exactly a fixed point. Then, in the first case, all functions x, x + 1, ..., x + p − 1 belong to A , and in the second case, (f −1 g f g −1 )(x) = x + d ∈ A with
13.2 The Subclasses of Linear Functions of Pk with k ∈ P
389
d = 0 (because of β = γ). Thus, A = SU for certain U ≤ G. Case 2: CA = ∅. Because of considerations for Case 1, set A is either a subset of C or of the form SU ∪C or Tα,U ∪CA , where the functions of Tα,U preserve CA . The latter is valid if and only if CA has the form Cα,U ;I or Cα,U ;I ∪ {cα } for certain I. Theorem 13.2.3 ([Bag-D 82]) Lp has exactly 2 · t(p − 1) + 2p · (2 − p) + p + 3 + 2 · p ·
2h
h h | (p − 1)
closed subsets (including ∅), where t(p − 1) is the number of all divisors n ∈ N of p − 1. Proof. Because of Theorem 13.2.1, we only have to determine the number of all subsemigroups which were described in Theorem 13.2.2. Since Tα,U ⊆ L1p ∩P ol{α}, L1p ∩P ol{α}∩P ol{β} = {x} for α = β and U is a subgroup of the cyclic group G = (Ep \{0}; ·), there is exactly p · t(p − 1) − p + 1 subsemigroups of the form Tα,U . Obviously, there exist 2·t(p−1) sets of the form SU and SU ∪C (U ≤ G). Since there are exactly 2h possibilities for the choice of I (⊆ {1, 2, ..., h}, h := p−1 |U | ), one receives (considering the equivalence Tα,U ∪ Cα,U,I = Tβ,V,J ∪ Cβ,V,J ⇐⇒ (α, U, I) = (β, V, J) ∨ (U = V = {1} ∧ I = J) the following number of the subsemigroups of (L1p ; ) of the form Tα,U ∪Cα,U,I or Tα,U ∪ Cα,U,I ∪ {cα }: (2h+1 − 1) − (p + 1) · (2p − 1) p· h h | (p − 1)
= 2 · p · ((
h h | (p − 1)
2h ) − p · t(p − 1) − (p − 1) · (2p − 1).
By adding, one immediately obtains the number given in our theorem. Next, we provide some statements about the order of the subclasses of Lp . One finds generating systems for these classes in [Bag-D 82]. Theorem 13.2.4 ([Bag-D 82]) For an arbitrary subclass A ⊆ Lp it holds:
390
13 Classes of Linear Functions
⎧ 1, if A ⊆ L1p , ⎪ ⎪ ⎨ 0 1 ord A = 3, if p = 2 and A ∈ {L2 , L2 ∩ P ol2 , [r1 ]}, 1 0 ⎪ ⎪ ⎩ 2 otherwise.
Proof. For p = 2 the above statements were proven in Chapter 3. Because of Lemmas 13.1.1 and 13.1.2, we have [A1 ∪{r1 }] = A and therefore 1 < ord A ≤ 3 for arbitrary A ∈ L↓p (Lp ) with A ⊆ [L1p ]. If p = 2 then (by Lemma 13.1.2) r1 ∈ [∆r1 ]. This implies our theorem.
13.3 A Survey of Further Results on Linear Functions In this section, k ≥ 2 is arbitrary. Let n n { ai xi ∈ Lk | ai = 1} Lk,id := n≥1 i=1
i=1
the set of all idempotent functions of Lk . For d|k we set Ik,d := n≥1 {f n ∈ Lk,id | ∃i ∈ {1, ..., n} ∃a1 , ..., an ∈ Ek : f (x) = ai xi + d · j∈{1,...,i−1,i+1,...n} aj xj } Theorem 13.3.1 ([Sze 76], [Sze 82]; without proof ) Any non-trivial closed subset A of Lk,id has a unique representation of the form m Ik,di , (13.1) A= i=1
where m ≥ 1 and d1 , ..., dm (> 1) are pairwise relatively prime proper divisors of k. If k is odd, then any subclass of Lk,id has a order ≤ 2. If, in turn, k is even, then the order of any subclass is at most 3 and is equal to 3 if and only if in the representation (13.1) of A d1 · ... · dm is odd. To determine subclasses of Lk , the following lemmas are useful. We notice that the proof (in [Sze 78]) for Lemma 13.3.2 uses Theorem 13.3.1 and that the proof (in [Lau 88a]) for Lemma 13.3.3 requires Lemma 13.3.2, so that the proof of Theorem 13.3.1 forms the basis of the proofs for most statements of this section. Lemma 13.3.2 ([Sze 78]; without proof ) Let f (x) := a0 +
n
ai xi (mod k) ∈ Lk
i=1
with 0 ∈ {a1 , ..., an }, n ≥ 2 and a1 ' ... ' an ' k = 1. Then
13.3 A Survey of Further Results on Linear Functions
391
(a) rq1 ·...·qn ∈ [{f }], where qi := a1 ' a2 ' ... ' ai−1 ' ai+1 ' ... ' an ' k, i = 1, 2, ... ([Sze 78], Basic Lemma); (b) f ∈ [[f ]id ∪ [f ]1 ], where [A]id := [A] ∩ Lk,id for arbitrary A ⊆ Lk ([Sze 78], Corollary 3.1). Lemma 13.3.3 ([Lau 88a]; without proof ) Let A be a subclass of Lk which is no subset of Wq := Uq ∪ Qt t;t|q;t=1
for every divisor q = 1 of k. Then the function r1 belongs to A. For every k, d ∈ N
d||k
is a short notation for “d|k and d ' kd = 1”. For lack of a better name, d will be called a full divisor of k. The following lemma is easy to prove. Lemma 13.3.4 Let k, d ∈ N with d||k. Furthermore dZk denotes the set {d · z (mod k) | z ∈ Zk }. Then: (a) dZk := (dZk ; + (mod k), · (mod k)) is a ring which is isomorphic to Zk/d . (b) dZk has a unit which will be denoted by ed . (c) ed + en/d = 1 (mod k). For α, d ∈ Ek with d|k let Qd,α :=
{a0 · α +
n≥1
n
ai xi (mod k) | a0 +
i=1
n
ai xi ∈ Qd }.
i=1
Lemma 13.3.5 ([Sze 78]) Let k, d ∈ N with d||k. Then: (a) The mapping ψd : Lk/d −→ Qd,ed , a0 +
n
ai xi → ed · (a0 +
i=1
n
ai xi )
i=1
is an isomorphism. (b) The mapping ϕd : Qd −→ Qd,ed , a0 +
n i=1
is a homomorphism.
ai xi → ed · a0 +
n i=1
ai xi
392
13 Classes of Linear Functions
(c) For any f ∈ Qd there exists a unique constant cd (f ) such that f = ϕd (f ) + cd (f ) (mod k). Moreover, if f, g ∈ Qd , the constant cd (f ) has the following properties: ∀α ∈ {ζ, τ, ∆, ∇} : cd (αf ) = cd (f ) cd (f g) = cd (f ). Proof. (a), (b), and (c) are easy to check with the aid of Lemma 13.3.4. Theorem 13.3.6 ([Sze 78]) Let k ∈ N\{1} be square-free. Then, for arbitrary subclass of Lk , 2 if k is odd, ord A ≤ 3 otherwise, i.e., there are only a finite number of subclasses of Lk . Proof. Let f n ∈ Lk \ [L1k ] be arbitrary. Set A := [f ]. To show our theorem, it suffices to prove the following statement: k is odd, [A2 ] if f∈ (13.2) 3 [A ] otherwise. W.l.o.g. we can assume that f is an n-ary function with n ≥ 4 and defined by f (x) := a0 +
n
ai · xi (mod k),
i=1
where 0 ∈ {a1 , a2 , ..., an }. For q := a1 ' a2 ' ... ' an ' k the following two cases are possible: Case 1: q = 1. In this case, we have [f ] = [[f ]id ∪ [{f }]1 ] by Lemma 13.3.2, (b), whereby our theorem follows from Theorem 13.3.1. Case 2: q = 1. With the aid of Lemma 13.3.5, one can reduce this case to the first case (see [Sze 78] for details). We notice that the paper [Sze 78] contains precise representations of the subclasses of Lk , where k is square-free. Lemma 13.3.7 If k ∈ N is not square-free, then there exists a subclass of Lk that is not finitely generated and does not have a basis. Proof. If k can not be represented as a product of different prime numbers, then there is a t ∈ Ek \{0} with t2 = 0 (mod k). Then, the set
13.3 A Survey of Further Results on Linear Functions
Qt :=
{f n ∈ Lk | ∃a0 , ..., an ∈ Ek : f (x) = a0 + t ·
n
393
ai · xi (mod k)}
i=1
n≥1
is a subclass of Lk , whose functions f n , g m for arbitrary n, m have the property that the number of the essential variables of f g is at most n−1. Therefore, Qt does not have a finite generating system. Since by Theorem 8.1.6 |L↓k (Lk )| ≤ ℵ0 holds, every class of linear functions that does not have a finite generating system, does not have a basis. The following theorem is a consequence of Theorems 13.3.6, 3.2.2.2, 13.2.3, and 8.1.6, Lemma 13.3.7, and [Lau-S 90] (for k = 6): Theorem 13.3.8 For arbitrary k ∈ N \ {1} it holds: < ℵ0 if k is square-free, |Lk (Lk )| = ℵ0 otherwise. In particular, we have: k 2 3 4 5 6 7 8 9 |L↓k (Lk )| 15 38 ℵ0 319 7524 470 ℵ0 ℵ0
A solution for the completeness problem for Lk , where k ∈ N is arbitrary, follows from αs 1 α2 Theorem 13.3.9 ([Lau 88a]; without proof ) Let k = pα (pi = 1 p2 ...ps j; pi ∈ P, αi ∈ N for i = 1, ..., s). Then, Lk has exactly pj for i = s s + 2s − 1 + i=1 pi pairwise different maximal classes: n (1) Sp := n≥1 {f n ∈ Lk | ∃a0 , ..., an ∈ Ek : f (x) = a0 + i=1 ai xi (mod k) ∧ n i=1 ai = 1 (mod p)}, where p ∈ {p1 , ..., ps }; (2) Wq := Uq ∪ t|q,t=1 Qt , where q is a square-free divisor of k;
(3) Ta,p := Lk ∩ P olk {x ∈ Ek | p|(x − a)}, where a ∈ Ek and p ∈ {p1 , ..., ps }. As a consequence from the above theorem and from Lemma 13.3.3 we get: Lemma 13.3.10 Let A be an subclass of Lk . Then either r1 ∈ A or there exists a square-free divisor q of k with A ⊆ Wq . Since all subclasses of Lk that contain r1 were determined in Section 13.1, we need all subclasses of the maximal classes of the type Wq for a complete description of L↓k (Lk ). For k = 4 the following theorem gives a rough description of the missing classes.
394
13 Classes of Linear Functions
Theorem 13.3.11 ([Lau 88a]; without proof ) It holds: (a) |L↓4 ([L14 ])| = 189. (b) |L4 ([r1 ], L4 )| = 15. (c) Exactly 20 subclasses of L4 contain the function r2 , but not the function r1 . (d) A subclass of L4 , which contains neither r1 nor r2 , is a subset of Q2 ∪[L14 ] and there exist a subclass B of [L14 ] and some t0 , t1 , t2 , t3 ∈ N ∪ {∞} with A = B ∪ K0,t0 ∪ K1,t1 ∪ K2,t2 ∪ K3,t3 , where
Ka,r :=
∅
r
if r = 1,
[{a + 2 · i=1 xi (mod 4)}] if r > 1 (a ∈ E4 , r ∈ N) and Ka,∞ := r≥2 Ka,r . We notice that the lattice Lk (Lk ) for k = p2 (p prime) was studied in detail in [Bul-I 2002] and [Bul 2002]. To describe further results about classes of linear function, we generalize the set Lk as follows: Let R = (R; +, ·, −, 0, 1) be a finite unitary ring and let M := (M ; +, −, (r)r∈R , 0) be a finite faithful2 module over R. Further, we consider the mapping defined by : R × M −→ M, (r, x) → r x := r(x), which fulfills the axioms (M1 )–(M4 ) (see Part I, Section 1.2.8). Then one can define a closed subset LM of PM as follows: LM :=
n≥1
{f n ∈ PM | ∃ a0 ∈ M ∃ a1 , . . . , an ∈ R : f (x) = a0 +
n
ai xi }.
i=1
It is usual to call the elements of LM also linear functions over the (left) module M. We remark that one can define analogously a set LM for the case that M is a right module. (the ring of all (m, m)-matrices over the field Zp ; p If one sets R = Zm×m p (the module of all (m, 1)-matrices over R), then LM prime) and M = Zm×1 p is isomorphic to the set of all quasi-linear functions of Ppm (see Section 5.2.4). This matrix representation of the quasi-linear function was used in [Sze-S 81] to describe all subclasses that contain certain sets of unary quasi-linear functions: 2
A module M over a ring R is faithful iff {r ∈ R | ∀m ∈ M : r(m) = 0} = {0}.
13.3 A Survey of Further Results on Linear Functions
395
Theorem 13.3.12 ([Sze-S 81]; without proof ) Let p prime, m ∈ N, pm ≥ 3, and M = Zm×1 . Moreover, set R = Zm×m p p I := {(i, j) ∈ N20 | 0 ≤ j ≤ i ≤ k − 1} ∪ {(−1, 0), (k − 1, k)}, H(r,s) := [{A · x ∈ L1M | rg(A) ≤ r ∨ rg(A) = k}] ∪ n≥2 {f n ∈ LM ∩ P olM {0} | dim(Im(f )) ≤ s}, where (r, s) ∈ I; 3 H(r,s) ; c := {f + c ∈ LM | f ∈ H(r,s) ∧ c ∈ M }, where (r, s) ∈ I. Then: (a) H(r,s) ⊆ H(r ,s ) iff r ≤ r and s≤ s . n } (b) H(k−1,k) = LM ∩ P olM {0} = n≥1 { i=1 Ai · xi | A1 , ..., An ∈ Zm×m p and H(k−1,k);c = LM . (c) The sets H(r,s) , (r, s) ∈ I, are the only subclasses of LM ∩ P olM {0} containing (LM ∩ P olM {0})1 . (d) The sets H(r,s);c , (r, s) ∈ I, are the only subclasses of LM containing L1M . For the case p = m = 2, one can find in [Kro-R 2003] all subclasses of quasi-linear selfdual4 functions, which contain all unary quasi-linear selfdual functions. In the case that R = M is a finite field F, one can find results on L↓F (LF ) in [Sze 80]. Among other things, the following theorem was proven in [Sze 80]: Theorem 13.3.13 (without proof ) For any finite field F, the class LF has only finitely many subclasses. Every subclass A of LF with A ⊆ [L1F ] contains the function x + y − z and is a class of the following form (a) or (b): n (a) I(E, S) := n≥1 {a0 + i=1 ai xi | {a1 , ..., an } ⊆ E ∧ (∃s, s ∈ S : n a0 = s − ( i=1 ai ) s }, where E is a universe of a subfield of F and S = V + a for an a ∈ F and a subspace V of F, considered as a vector space over E. n n (b) I(E, S0 ) := n≥1 {a0 + i=1 ai xi | {a1 , ..., an } ⊆ E ∧ i=1 ai = 1 ∧ a0 ∈ S0 }, where E is a universe of a subfield of F and S0 is a subspace of F, considered as a vector space over E. Theorem 13.3.14 ([Sze 80], without proof ) Let k = pm (p prime, m ≥ 1), F := (Ek ; +, ·) a field and let QLF be the set of all quasi-linear functions of Pk (see Section 5.2.4). Further, we set n LF := n≥1 {f n ∈ QLk | ∃a0 , ..., an ∈ Ek : f (x) = a0 + i=1 ai · xi }, d
LF ;d := [LF ∪ {xp }] where d ∈ N is a divisor of k. 3 4
rg(A) denotes the range of the matrix A and dim V is the dimension of the vector space V . We remark that Im(f ) is a vector space, if f (x) = n i=1 Ai · xi . with respect to a fixed-point-free permutation π of order p
396
13 Classes of Linear Functions
(In particular, LF ;1 = QLk and LF ;k = LF .) Then for any subclass A ⊂ Pk with LF ⊆ A, there exists a divisor d of k such that A = LF ;d . Theorem 13.3.15 ([Sze 80], without proof ) Let M be a faithful unitary module over a unitary ring R. Then for any subclass A of LM containing the operation x+y −z there exists a unique subring T of R and a unique T-submodule N of T × M such that A=
n≥1
{m +
n i=1
ri xi | {r1 , ..., rn } ⊆ T ∧ (1 −
n
ri , m) ∈ N }
i=1
(see also Section 9.6). Next we give some results by A. A. Bulatov about the elements of L↓M (LM ), where the unitary ring R is commutative (i.e., · is kommutative). The following theorem is the basis for a classification of the elements of L↓M (LM ). Theorem 13.3.16 ([Bul 98a]; without proof ) Let R be kommutative. Then: (1) The minimal classes 5 of L↓M (LM ) are exactly the following classes: (a) JM ; (b) [ca ], where a ∈ M ; (c) [ε x + (1 − ε) b], where b ∈ M , ε ∈ R \ {0, 1} and ε · ε = ε (e.g., ε is an idempotent of the ring R). (2) The minimal clones, which are elements of L↓M (LM ), are exactly the following clones: (a) JM ∪ A, where A is a minimal class of the form (b) or (c) (see (1)); (b) [x + b], where b ∈ M is of prime additive order; (c) [α x + b], where b ∈ M , α ∈ R \ {1} and there exists a prime number p with αp = 1 and (1 + α + α2 + ... + αp−1 ) b = 0; (d) [x − r y + r z], where r ∈ R \ {0} with r2 = 0 and r is of prime additive order; (e) [x + y − z], if char R is a prime number.6 In [Bul 98b], it was shown that any element of L↓M (LM ) can be assigned to one of four types, defined below. The definitions of these types use properties of coefficients of functions and, in addition, some special functions. Classes of the first type are those containing a function ε x + (1 − ε) y where ε is an idempotent of R (ε = 0, 1). Similarily, classes of the second type are those not of the first type and containing the function ε x + (1 − ε) b where ε is n an idempotent of R (ε = 0, 1) and b ∈ M . A function f = i=1 αi xi + a is called primitive, if there exists j ∈ {1, ..., n} such that αj is an invertible 5 6
See Chapter 19. If there is a least positive integer n with x + x + ... + x = 0 for all x ∈ R, then n times the ring R is said to have characteristic n (notation char R).
13.3 A Survey of Further Results on Linear Functions
397
element and αi is a nilpotent element7 whenever i = j. Classes of the third type consist of primitive functions and functions whose coefficients are nilpotent elements. Finally, a class belongs to the fourth type if it contains the Mal’tsev function x + y − z and is not of the first type. ´ Szendrei in [Sze 80] (see The classes of the forth type were described by A. Theorem 13.3.15). Classes of the first and second type were studied in [Bul 98a]. The paper [Bul 98b] deals with the classes of primitive functions and with the lattice of classes of the third type. In particular, A. A. Bulatov completely describes the lattice of classes of primitive functions in [Bul 98b]. We need the following notations for the last theorem of this section: In [P¨ os-K 79], the direct product of functions and subclasses of Pk was defined in the following way. Let a set A := A1 ×A2 be Cartesian product of the sets A1 (n) (n) and A2 . The direct product of the functions f1 ∈ PA1 and f2 ∈ PA2 is (n)
the function f ∈ PA
defined by the equality
f ((b1 , c1 ), ..., (bn , cn )) = (f (b1 , ..., bn ), f (c1 , ..., cn )) for arbitrary b1 , ..., bn ∈ A1 , c1 , ..., cn ∈ A2 . In this case, we shall write f = f1 ⊗ f2 . The set (n)
(n)
C = {f1 ⊗ f2 | f1 ∈ C1 , f2 ∈ C2 , n ∈ N} is the direct product of the classes C1 ⊆ PA1 , C2 ⊆ PA2 and is denoted by C1 ⊗ C2 . It is well known that, for any idempotent ε ∈ R \ {0, 1}, we can represent the module M as the direct sum of two submodules (ε M) ⊕ ((1 − ε) M) (this is the so-called Peirce decomposition). Further, each function f (x) := n a + i=1 f = f1 ⊗ f2 where f1 (x) = nαi xi ∈ LM can be representedas n ε a + i=1 αi xi and f2 (x) = (1 − ε) a + i=1 αi xi are functions on the sets εM and (1−ε)M , respectively. To show this take (b1 , c1 ), . . . , (bn , cn ) ∈ M = (ε M ) × ((1 − ε) M ). Then f ((b1 , c1 ), . . . , (bn , cn )) = f (b1 + c1 , . . . , bn + cn ) n = a+ αi (bi + ci ) i=1
= εa+
n i=1
7
εαi (bi + ci ) + (1 − ε) a +
n
(1 − ε)αi (bi + ci )
i=1
An element a of a ring R = (R; +, ·, −, 0) is called nilpotent iff there exists an n ∈ N with an = 0.
398
13 Classes of Linear Functions
= εa+
n
αi bi + (1 − ε) a +
i=1
n
αi ci
i=1
= (f1 (b1 , . . . , bn ), f2 (c1 , . . . , cn )). n Conversely, the function f = f1 ⊗ f2 = (b + c) + i=1 i + (1 − ε)ζi ) xi (εγ n corresponds to the given pair of functions f = b + γi xi ∈ LεM , 1 i=1 n f2 = c + i=1 ζi xi ∈ L(1−ε)M . The modules ε M , (1 − ε) M can be considered as εR- and (1 − ε)R-modules, respectively. So, LM = LM1 × LM2 where M1 = ε M is an εR-module and M2 = (1 − ε) M is an (1 − ε)Rmodule. Let C be a class of all functions preserving the kernels of projections os-K 79] (3.3.4, 3.3.5, p. 85) it was noted that from A onto A1 and A2 . In [P¨ the interval LA1 ×A2 (JA1 × JA2 , C) can be decomposed into the direct product [JA1 , PA1 ]×[JA2 , PA2 ]. Using this decomposition we obtain the next statement. Theorem 13.3.17 ([Bul 98a]; without proof ) For any idempotent ε ∈ R, (a) if the function ε x + (1 − ε) y belongs to a subclass C of LM , then C = C1 ⊗ C2 where C1 , C2 are subclasses of LεM and L(1−ε)M , respectively and L1 , L2 both contain all projections; (b) LM ([ε x + (1 − ε) y], LM ) ∼ = LεM (JεM , LεM ) × L(1−ε)M (J(1−ε)M , L(1−ε)M ). For a proper ideal I of R, let LIM be the set of all functions f ∈ LM whose coefficients belong to I. Further, let LP M be the set of all primitive functions of LM . For a ring R let idemp(R) be the set of all idempotents = 0. Moreover, put n n KM (R , M ) = { i xi + a | n ≥ 1, 1 , . . . , n ∈ R , (1 − i , a) ∈ M } i=1
i=1
where R is a unitary subring of R and M is a submodule of R -module R × M . Theorem 13.3.18 ([Bul 98a]; without proof ) The set of all maximal clones of LM comprise exactly the following clones: (a) (LIεM ∪ LP εM ) ⊗ L(1−ε)M where ε ∈ idemp(R); (b) KεM (R , R × ε M ) ⊗ L(1−ε)M where ε ∈ idemp(R), R is a maximal unitary subring of εR without proper idempotents; (c) KεM (εR, M ) ⊗ L(1−ε)M where ε ∈ idemp(R) is a minimal idempotent and M is a maximal submodule of εR × εM .
14 Submaximal Classes of P3
A subclass (or a subclone) of Pk is called submaximal if it is covered by a maximal class (clone).1 The concept submaximal class was introduced of I. G. Rosenberg in [Ros 74]. In [Ros 74] one also finds the first results about submaximal classes of Pk (see Chapter 17 for details). In general, the submaximal classes seem to be interesting for the following reasons.2 The largely unknown lattice Lk has intervals with antichains of cardinality c situated far down from the top. It is not unreasonable to assume that the lattice Lk is nicer near the top, and therefore the submaximal clones are good candidates. The problem of determining certain submaximal clones also came up in the study of shortest maximal chains in the lattice (see [Sze 83]). Given a maximal clone M , one can ask for a completeness criterion for M : under what conditions does the clone [F ] generated by some F ⊆ M coincide with M ? In the case that M is finitely generated, a full list of clones maximal in M would provide a general criterion, because then [F ] if and only if F is contained in no clone maximal in M . An application could be a characterization of Sheffer functions for M . V. B. Kudrjavcev and P. Schofield proven that they exist exactly for maximal clones of the form P olk with ∈ C1k ∪ Sk ∪ Uk (see Chapter 7), but the examples in the proofs have many variables. It would be interesting to have simple criteria of type Theorem 7.1.3, which, in its turn, could lead to the question: what is the minimum number of functional values 1
2
It is easy to see that every submaximal class is a clone: Assume there is a maximal class M ⊂ Pk and a submaximal class S ⊂ M with Jk ∩ S = ∅ and [S ∪ {f }] = M for all f ∈ M \ S. Then, M = S ∪ Jk , since M is a clone (see Theorem 5.1.1) and Jk = [e] for all e ∈ Jk . However, M = S ∪ Jk with S ∩ Jk = ∅ is not possible, since S ∪ Jk = Pk (k − 1) ∪ [Pk1 ] and every maximal class A (= Pk (k − 1) ∪ [Pk1 ]) of Pk contains an idempotent function g with g ∈ Jk . For example, if ∈ Mk and o is the smallest element of , then the function f 2 , defined by f (o, x) = f (x, o) = o for all x ∈ Ek and f (x, y) = x otherwise, is idempotent and belongs to (P olk ) \ Jk . With the help of the theorems from Chapter 5, one can easily find idempotent functions for the other possible cases. The following is an indirect quotation from [Ros-S 85].
400
14 Submaximal Classes of P3
whose knowledge can guarantee that a function is a Sheffer function? Finally, the submaximal clones may be of interest on their own, e.g., as a source of examples and counter-examples. For arbitrary k, the full list of the maximal classes of a maximal class A of Pk is only known, if A has the type S ([Ros-S 84], see Section 18.1), C1 (see 2 ∪ {(k − 1, k − 1)} (see Chapters 16 and 17) or A = P olk , where := Ek−1 Section 18.3). There are, however, some papers in which one finds submaximal classes for specific k or only such submaximal classes that contain certain functions. In Section 14.1, one finds a complete description of all submaximal classes of P3 and some remarks about generalization of the given theorems. The papers [Mac 79], [Mar-D-H 80], [Sal 64], [Bag-D 82], and [Lau 82a] form the basis of this description. The theorems from the first section are proven then in Sections 14.2–14.9. In Section 14.10, we will prove that there are 5 submaximal classes with finitely many subclasses, 7 with countably many subclasses, and the remaining 146 with uncountably many subclasses. All elements of the lattices L↓3 (A), where A is a submaximal class with|L↓3 (A)| ≤ ℵ0 are determined in Chapter 15.
14.1 A Survey of the Submaximal Classes of P3 The following theorem was proven 1958 by Jablonskij and is a special case of Rosenberg’s Theorem 6.1. Theorem 14.1.1 ([Jab 58]) P3 has exactly 18 maximal classes: (1) P ol3 {0}
(2) P ol3 {1}
(3) P ol3 {2}
(4) P ol3 {0, 1}
(5) P ol3 {0, 2} 0 1 (7) P ol3 1 2 0 1 (9) P ol3 0 1 0 1 (11) P ol3 0 1 0 1 (13) P ol3 0 1 0 1 (15) P ol3 0 1
2 0 2 2 2 2 2 2 2 2
0 2 0 1 1 0 1 0
2 0 0 2 1 2 0 1
1 2 0 2 1 2 2 1
(6) P ol3 {1, 2} 0 1 (8) P ol3 0 1 0 1 (10) P ol3 0 1 0 1 (12) P ol3 0 1 0 1 (14) P ol3 0 1 0 1 (16) P ol3 0 1
(17) P ol3 {(a, b, c, d) ∈ E34 | a + b = c + d (mod 3)} (18) P ol3 {(a, b, c) ∈ E33 | |{a, b, c}| ≤ 2}
2 2 2 2 2 2 2 2 2 2
0 1 1 2 0 2 0 1 2 0
1 0 2 1 0 1 1 0 0 2
2 1 0 2 2 1
2 0 1 2
14.1 A Survey of the Submaximal Classes of P3
401
In the following theorems, one finds all A-maximal classes for every maximal class A from Theorem 14.1.1. The next two theorems are special cases of general statements about the maximal classes of P olk E with 1 ≤ |E| ≤ k − 1 (see Chapters 16 and 17). Theorem 14.1.2 ([Lau 82a]) Let {a, b, c} := E3 . Then Ta := P ol3 {a} has exactly the following 12 maximal classes: (1) Ta ∩ P ol3 {b}
(2) Ta ∩ P ol3 {c}
(3) Ta ∩ P ol3 {a, b} (5) Ta ∩ P ol3 {b, c} a b (7) Ta ∩ P ol3 a b a b (9) Ta ∩ P ol3 a b a a b a (11) P ol3 a b a c
c c c c c a
a b a c
b a a b
a c c a c b
(4) Ta ∩ P ol3 {a, c} a b c b c (6) T ∩ P ol3 a b c c b a b c a a b (8) Ta ∩ P ol3 a b c b c c a b c (10) P ol3 a c b a a b a c b c (12) P ol3 a b a c a c b
Theorem 14.1.3 ([Lau 82a]) Let {a, b, c} := E3 . Then Ta,b := P ol3 {a, b} has exactly the following 15 maximal classes: (1) Ta,b ∩ P ol3 {a} (2) Ta,b ∩ P ol3 {b} a b a (3) Ta,b ∩ P ol3 a b b a b (4) Ta,b ∩ P ol3 ⎛b a a a a b ⎜a a b b ⎜ (5) Ta,b ∩ P ol3 ⎝ a b a a a b b a (6) Ta,b ∩ P ol3 {c} 0 1 2 a (7) Ta,b ∩ P ol3 0 1 2 b 0 1 2 a (8) Ta,b ∩ P ol3 0 1 2 c a b a (9) P ol3 a b c a b b (10) P ol3 a b c a a b b a (11) P ol3 a b a b c a a b b b (12) P ol3 a b a b c
b a b a
a b b a
b a a b
b a c b c a c b
⎞ b b⎟ ⎟ b⎠ b
402
14 Submaximal a a b (13) P ol3 ⎛a b a a b a (14) P ol3 ⎝ a b a ⎛a b b a b b (15) P ol3 ⎝ a b a a b a
Classes of P3 b a c b c b c a c b ⎞ b a b a b b b a a b⎠ a c c c c ⎞ a a b b a a b b a b a b a b⎠ a b a b b c c
The following theorem is a special case of a theorem from [Lar 93], in which B. Larose determined all maximal classes of P olk , where is a total order on Ek and 2 ≤ k ≤ 5. Theorem 14.1.4 ([Mac 79]) Let E3 := {a, b, c} and let min, max be defined by x a a a b b b c c c Then O := P ol classes:
y max(x, y) min(x, y) a a a b b a c c a a b a . b b b c c b a c a b c b c c c
0 1 2 a a b 0 1 2 b c c
(1) O ∩ P ol{a}
(11) O ∩ P ol3 ι33
has exactly the following 13 maximal (2) O ∩ P ol{c}
(3) O ∩ P ol{a, b} (5) O ∩ P ol{b, c} 0 (7) O ∩ P ol3 0 0 (9) O ∩ P ol3 0
1 2 b c 1 2 c b
1 2 b b b c 1 2 a b c b
(4) O ∩ P ol{a, c} 0 (6) O ∩ P ol3 0 0 (8) O ∩ P ol3 0 0 (10) O ∩ P ol3 0
1 2 a b 1 2 b a
1 2 a b a c 1 2 b a c a 1 2 c a c b 1 2 a c b c
⎛
0 (12) P ol3 ⎝ 0 0 ⎛ 0 (13) P ol3 ⎝ 0 0
1 2 0 0 1 2 0 0 1 2 1 2 1 2 0 0 1 2 1 2 1 2 1 2
14.1 A Survey of the Submaximal Classes of P3 ⎞ 1 0 0 1 1 1 2 2 ⎠ = [{min} ∪ O1 ] 3 2 0 0 1 ⎞ 1 1 2 2 2 0 0 1 ⎠ = [{max} ∪ O1 ] 4 2 1 2 2
403
The following theorem is a special case of theorems from [Ros-S 84] and [Lau 84]: Theorem 14.1.5 ([Mar-D-H 80]) 0 1 2 S := P ol3 has exactly two maximal classes: 1 2 0 (1) S ∩ P ol3 {0} (2) S ∩ P ol3 λ3 . The following theorem follows from Section 13.2: Theorem 14.1.6 ([Bag-D 82]) L3 := P ol3 λ3 has exactly 5 maximal classes: (1) L3 ∩ P ol{0}. (2) L3 ∩ P ol{1}. (3) L3 ∩ P ol{2}. 0 1 2 (4) L3 ∩ P ol3 1 2 0 (5) [(L3 )1 ].
Theorem 14.1.7 ([Lau 82a]) Let E3 := {a, b, c}. Then C := P ol3 lowing 7 maximal classes:
0 1 2 a b a c 0 1 2 b a c a
has exactly the fol-
(1) C ∩ P ol{a} (2) C ∩ P ol{a, b} 3
4
The equality of these two sets can be proven as follows: It is easily checked that [{min} ∪ O1 ] ⊆ P ol3 (...) is valid. Then one proves that [{min} ∪ O1 ] is maximal in O (see for this purpose also [Mac 79]). The equality of these two sets results from the considerations to the statement (12) and the fact that the classes (12) and (13) are isomorphic.
404
14 Submaximal Classes of P3
(3) C ∩ P ol{a, c} (4) C ∩ P ol{b, c} 0 (5) C ∩ P ol3 0 0 (6) C ∩ P ol3 0 ⎛ a (7) C ∩ P ol3 ⎝ b c
1 2 a a 1 2 b c
1 2 a b a c b 1 2 b a c a c
⎞ b a c a b a a b b a b c a a c c a c a c a a a b a b a b b a c a c a c c⎠ c b b a a a b a b b b a a c a c c c
Theorem 14.1.8 ([Lau 82a])
Let E3 := {a, b, c}. Then U := P ol3 13 maximal classes:
0 1 2 a b 0 1 2 b a
(1) U ∩ P ol{c} (2) U ∩ P ol{a, b} (3) U ∩ P ol{a, c} (4) U ∩ P ol{b, c} 0 1 2 a b a c (5) U ∩ P ol3 0 1 2 b a c a 0 1 2 b a b c (6) U ∩ P ol3 0 1 2 a b c b 0 1 2 a (7) P ol3 0 1 2 b a c b c (8) P ol3 c a c b 0 1 2 a b a b (9) P ol3 0 1 2 b a c c ⎛ 0 1 2 a a b b c c a (10) P ol3 ⎝ 0 1 2 a a b b c c b 0 1 2 b c a c a b c ⎛ a a a a b b b b a b (11) P ol3 ⎝ a a b b a a b b a b a b a b a b a b c c ⎛ ⎞ a a a b b a b b c ⎜a a b b a b a b c⎟ ⎟ (12) P ol3 ⎜ ⎝a b a a b b a b c⎠ a b b a a a b b c
⎞ b a⎠ c
⎞ c c c c c c⎠ a b c
has exactly the following
14.1 A Survey of the Submaximal Classes of P3 ⎛ (13)
a ⎜a c c
P ol3 E24 ∪ ⎜ ⎝
a b c c
b a c c
b b c c
a c a c
a c b c
b c a c
b c b c
a c c a
a c c b
b c c a
b c c b
c a a c
c a b c
c b a c
c b b c
c a c a
c a c b
c b c a
c b c b
c c a a
c c a b
c c b a
c c b b
405 ⎞ c c⎟ ⎟. c⎠ c
Theorem 14.1.9 ([Lau 82a]) Let P3 (2) := {f ∈ P3 | |Im(f )| ≤ 2}. The set P ol3 ι33 (= P3 (2) ∪ [P31 ]) has exactly 5 maximal classes: (1) P3 (2) ∪ [{s1 , s2 }] (2) P3 (2) ∪ [{s1 , s3 }] (3) P3 (2) ∪ [{s1 , s6 }] (4) P3 (2) ∪ [{s1 , s4 , s5 }] (5) n≥1 {f n ∈ P3 |∃fi ∈ P31 : f (x1 , ..., xn ) = f0 (f1 (x1 ) + ... + fn (xn )) (mod 2)} ∪ [P31 ]. (The definitions of the functions s1 , ..., s6 are given in Section 15.2, Table 15.1.)
Table 14.1 gives a summary of the above-described submaximal classes, where {a, b, c} := E3 and {α, β, γ} := E3 . The submaximal classes that can be described as intersections of maximal clones are labelled with numbers 1–17. The other classes are labelled with numbers 18–43 in the order that they occur in Theorems 14.1.2–14.1.9. With the aid of Table 14.1 and with a b a 0 1 2 a c = P ol{a, b} ∩ P ol3 , 5 {a, b, c} = E3 , P ol3 a b c 0 1 2 c a one can prove the following theorem: Theorem 14.1.10 P3 has exactly 158 submaximal classes. 5
This equationcan be proven as follows: a b a Because of ∆ = {a, b} and a b c a b c a b a 0 1 2 a c ◦ = it holds a b a a b c 0 1 2 c a a b a 0 1 2 a c ⊆ P ol{a, b} ∩ P ol3 . P ol3 a b c 0 1 2 c a a b a 0 1 2 a c is valid, we Since, in addition, ∆ {a, b} × = P ol3 a b c 0 1 2 c a have also 0 1 2 a c a b a P ol{a, b} ∩ P ol3 ⊆ P ol3 . 0 1 2 c a a b c
406
14 Submaximal Classes of P3 Table 14.1 Submaximal classes of P3
i
A
1 P ol{a} ∩ P ol{b} 2 P ol{a} ∩ P ol{a, b} 3 P ol{a} ∩ P ol{b, c} # $ 4 P ol{a} ∩ P ol 00 11 22 cb cb # $ 5 P ol{a} ∩ P ol 00 11 22 ab ab ac ac # $ 6 P ol{a} ∩ P ol 00 11 22 ab ac cb 7 P ol{a} ∩ P olλ3 # $ 2 8 P ol{0} ∩ 01 1 2 #0 $ 9 P ol{a, b} ∩ P ol 00 11 22 ab ab # $ 10 P ol{a, b} ∩ P ol 00 11 22 ac ac # $ α β 11 P ol{a, b} ∩ P ol 00 11 22 α β γ γ # $ β α γ 12 P ol{a, b} ∩ P ol 00 11 22 α β# α γ α # $ 1 2 a b ∩ P ol 0 1 2 a a 13 P ol 0 #0 1 2 b a$ #0 1 2 b c 1 2 a b ∩ P ol 0 1 2 a b 14 P ol 0 0# 1 2 b a #0 1 2 b a $ 1 2 a a b ∩ P ol 0 1 2 α 15 P ol 0 0 1 2 β 0 1 2 b c c 0 1 2 a a b 3 16 P ol 0 1 2 b c c ∩ P olι3 # $ 1 2 ∩ P olλ 17 P ol 0 3 1 2 0 # $ a b c 18 P ol a c b # $ a b a c 19 P ol a #a b a c a $ a b a c b c 20 P ol a # a b a $c a c b b a 21 P ol a # a b $b 22 P ol ab ab ⎛ ⎞ a a a b b a b b a b b a b a b⎠ 23 P ol ⎝ a a b a a b b a b # a b b a a$ a b b a b b a 24 P ol a #a b a b c $ a b b a c b c 25 P ol a a b a b c a c b 6
6
ni (A) 3 6 3 3 3 6 3 1 3 6 9 b c a c β α
$ $ c a $ α γ γ α
ni (A) denotes the number of possibilities for A in case i.
9 6 6 9 3 1 3 3 3 3 3 3 6 3
14.1 A Survey of the Submaximal Classes of P3
i 26 27 28 29 30 31 32 33 34 35 36
%
a b a b a b a b P ol a b a b b a a b %a b b a c c c c a b b a a b b a P ol a b a b a b a b a b a a b a b b [{max} ∪ O1 ] [{min} ∪ O1 ] [(L3 )1 ] # $ 1 2 a P ol 0 #0 1 2 b$ P ol ac ac cb cb # $ 1 2 a b a b P ol 0 %0 1 2 b a c c 0 1 2 a a b b c P ol 0 1 2 a a b b c %0 1 2 b c a c a a a a a b b b b P ol a a b b a a b b ⎛a b a b a b a b a a a b b a b b a b b a b a b ⎝ P ol a a b a a b b a b a b b a a a b b
37 ⎛P olE24 ∪ a ⎜ a ⎜ ⎝ c c
38 P ol 39 P ol 40 P ol
a b c c
# #
b a c c
b b c c
a c a c
a c b c
b c a c
b c b c
0 1 2 a a 0 1 2 b c
a c c a
$
a c c b
b c c a
b c
b a c
a c b
c a b
a a a
b a a
a b a
a b a b c c
ni (A) 3
&
3 3 3 1 3 3
c a c b b c a b a b c⎞ c c c⎠ c c b c c b
c a a c
c a b c
3
&
b a c & c c c c c c a b c
3 3 3
c b a c
c b b c
c a c a
c a c b
c b c a
c b c b
c c a a
c c a b
c c b a
c c b b
⎞ c ⎟ c ⎟ c ⎠ c
3 3
0 1 2 a b a c b 0 1 2 b a c a c
#a
A
&
407
a a b
b b a
$ b a b
3 a b b
b b b
c a a
a c a
a a c
c c a
c a c
a c c
$ c c c
3
41 P3 (2) ∪ [X], X ∈ {{s1 , s2 }, {s1 , s3 }, {s1 , s6 }}
3
42 P3 (2) ∪ [{s1 , s4 , s5 }]
1
43
n≥1 {f
n
∈ P3 |∃fi ∈ P31 : f (x1 , ..., xn ) = f0 (f1 (x1 ) + f2 (x2 ) + ... + fn (xn )) (mod 2)} ∪ [P31 ]
1
408
14 Submaximal Classes of P3
14.2 Some Declarations and Lemmas for Sections 14.3–14.9 In this chapter, we use the notations from Chapter 15, Table 15.1 for the unary functions of P3 . We prove Theorems 14.1.2–14.1.9 as follows in the next sections: Suppose in the theorem a list is indicated with subclasses (1), (2), ..., (rT ) for the class T . To prove that this list indicates all submaximal classes of T , we will show that every subset A ⊆ T , which is not contained in any subclass of the list, is a generating system for T . Then, it remains to show that the listed classes (1), (2), ..., (rT ) are proper subsets of the set T , and the set of all these classes is an antichain; i.e., in this set, no two elements are comparable in respect to ⊆. For this purpose, we give some functions (∈ T ) and a table that shows whether any function of these functions belongs to the indicated class. The sign + stands for “the function belongs to the class”. If the considered function does not belong to the class, we write -. We leave the readers to check the given table and, with the aid of the table, to prove that the classes (1), (2), ..., (rT ) are incomparable. If we assume in the proof that A ⊆ T and A is not a subset of the class (i), then there exists a function fi ∈ A which does not belong to the class (i). Since we can choose [A] instead of A, we can assume w.l.o.g. that the following holds: (∗ ):
If the class (i) is given in the form T ∩ P ol3 or P ol3 , where := (σ1 , σ2 , ..., σm ), then fi (σ1 , σ2 , ..., σm ) ∈ /.
Now some lemmas are given that we subsequently need more often and which are consequences from some theorems of Chapters 3 and 12. Already in Chapter 3 (see Theorem 3.3.1) the following was proven: Lemma 14.2.1 Let A be an arbitrary subset of P2 . Then, [A] = P2 if and only if A ⊆ B for every class B of the following list: (1) P ol2 {0} (2) P ol2 {1} 0 1 (3) P ol2 1 0 0 0 1 (4) P ol2 0 1 1 ⎛ ⎞ 0 0 0 1 1 0 1 1 ⎜0 0 1 1 0 1 0 1⎟ ⎟ (5) P ol2 ⎜ ⎝ 0 1 0 0 1 1 0 1 ⎠. 0 1 1 0 0 0 1 1 Lemma 14.2.2 Let A be an arbitrary subset of T0 := P ol2 {0} ⊂ P2 . Then, [A] = T0 if and only if A ⊆ B for every class B of the following list: (1) T0 ∩ P ol2 {1}
14.2 Some Declarations and Lemmas for Sections 14.3–14.9
0 0 0 (3) T0 ∩ P ol2 0 ⎛ 0 ⎜0 (4) T0 ∩ P ol2 ⎜ ⎝0 0 (2) T0 ∩ P ol2
0 1 1 0 0 0 1 1
1 1 0 1 0 1 1 1 0 0 1 0
1 0 1 0
0 1 1 0
1 0 0 1
409
⎞ 1 1⎟ ⎟. 1⎠ 1
As a consequence of Theorem 12.4.3, we get: Lemma 14.2.3 Let A be an only if A ⊆ B for every class (1) P3,2 ∩ P ol3 {0} (2) P3,2 ∩ P ol3 {1} 0 1 (3) P3,2 ∩ P ol3 1 0 0 0 1 (4) P3,2 ∩ P ol ⎛0 1 1 0 0 0 1 1 ⎜0 0 1 1 0 (5) P3,2 ∩ P ol3 ⎜ ⎝0 1 0 0 1 0 1 1 0 0 0 1 0 (6) P3,2 ∩ P ol3 0 1 2 0 1 1 (7) P3,2 ∩ P ol3 . 0 1 2
arbitrary subset of P3,2 . Then [A] = P3,2 if and B of the following list:
0 1 1 0
1 0 0 1
⎞ 1 1⎟ ⎟ 1⎠ 1
The next lemma follows from Theorem 12.5.3: Lemma 14.2.4 Let A be an arbitrary subset of pr−1 T0 := P3,2 ∩ P ol3 {0} ⊂ P3 . Then [A] = pr−1 T0 if and only if A ⊆ B for every class B of the following list: (1) pr−1 T0 ∩ P ol3 {1} 0 0 1 −1 (2) pr T0 ∩ P ol3 0 1 1 0 1 0 (3) pr−1 T0 ∩ P ol3 0 0 1 ⎛ ⎞ 0 0 0 1 1 0 1 1 ⎜0 0 1 1 0 1 0 1⎟ ⎟ (4) pr−1 T0 ∩ P ol3 ⎜ ⎝0 1 0 0 1 1 0 1⎠ 0 1 1 0 0 0 1 1 (5) pr−1 T0 ∩ P ol3 {0, 2} 0 1 1 (6) pr−1 T0 ∩ P ol3 . 0 1 2
410
14 Submaximal Classes of P3
14.3 Proof of Theorem 14.1.2 W.l.o.g. we assume a = 0, b = 1 and c = 2. Further, in this proof, let A be an arbitrary subset of P ol{0}, which is not contained in any class ((1)–(12)) from the above list, which is given in Theorem 14.1.2. Then, there are some functions f1 , f2 , ..., f12 ∈ [A] with the above property (∗ ). First we prove that (P ol3 {0})1 ⊆ [A]. The function f1 belongs to {c0 , j2 , u2 , u1 , s2 , u5 }. If f1 ∈ {j2 , u1 } then c0 = f1 f1 ∈ [A]. If f1 = u2 then f2 f1 ∈ {c0 , j2 }. For f1 ∈ {s2 , u5 } we have f5 (x, f1 (x)) ∈ {c0 , j2 , u2 }. Therefore, c0 is a superposition over A. The function f3 (x) := f3 (co , x) ∈ {u1 , s2 , u5 } also belongs to [A]. Thus we have to distinguish three cases: Case 1: f3 = u1 . In this case j1 = f4 (c0 , u1 ) and a function f4 (x) = f4 (c0 , x) ∈ {j2 , j5 , s2 } belongs to [A]. Case 1.1: f4 = j2 . (x) := f11 (c0 , j2 , j1 , u2 , u1 ) ∈ [A] and f11 (x) := Then u1 j2 = u2 ∈ [A], f11 f11 (co , j1 , j2 , u1 , u2 ) ∈ [A], where {f11 , f11 } ∩ {s2 , j5 , u5 } = ∅. Because of f12 (c0 , j2 , j1 , u2 , u1 , x, s2 ) ∈ {j5 , u5 } and j2 u5 = j5 we can assume j5 ∈ [A]. Then j2 j5 = u5 and {f7 (c0 , j5 , u5 , j2 , j1 , u2 , u1 ), f7 (c0 , j5 , u5 , j1 , j2 , u1 , u2 )} = {s1 , s2 } ⊆ [A]. Therefore, (P ol3 {0})1 ⊆ [A] in Case 1.1. Case 1.2: f4 = s2 . Because of j1 s2 = j2 one can reduce this case to Case 1.1. Case 1.3: f4 = j5 . In this case, functions u5 = u1 j5 and f9 (c0 , j5 , u5 , u1 , j1 , x) ∈ {j2 , u2 , s2 } are superpositions over A. Therefore, because of j5 u2 = j2 , we have given either Case 1.1 or Case 1.2. Case 2: f3 = u5 . Here we can form the superpositions j5 = f4 (c0 , u5 ) and f6 (x1 , x2 ) := j5 (f6 (c0 , j5 (x1 ), u5 (x1 ), x1 , x2 )) 1 2 0 1 1 2 0 over A, where f6 ∈ . W.l.o.g. let f6 = . If 2 1 1 0 2 1 1 f6 (1, 1) = 1 we obtain Case 1 because of u5 (f6 (j5 (x), x)) = u1 . If f6 (1, 1) = 0 then it holds f6 (x, j5 (x)) = j2 , u5 j2 = u2 and f8 (c0 , j5 , u5 , j2 , u2 , x) ∈ {j1 , u1 , s2 }. Since u5 j1 = u1 and u2 s2 = u1 , we have also u1 ∈ [A] if f6 (1, 1) = 0, i.e., one can reduce Case 2 to Case 1. Case 3: f3 = s2 . Because of f10 (c0 , s2 , x) ∈ {j1 , j2 , j5 , u1 , u2 , u5 }, s2 ji = ui , i ∈ {1, 2, 5}, and u2 s2 = u1 , we obtain either Case 1 or Case 2. Consequently, (P ol{0})1 ⊆ [A] is proven. Next we prove that P3,2 ∩ P ol3 {0} is a subset of [A]. Since (P3,2 ∩ P ol3 {0})1 ⊆ [A] was already shown, we have to find a subset of [A] ∩ P3,2 that is not a
14.3 Proof of Theorem 14.1.2
subset of P ol
0 0 1 0 1 0
, P ol
0 0 1 0 1 1
411
and P olλ2 := {(a, b, c, d) ∈ E24 | a+b =
c + d (mod 2)}, to be able to use Lemma 14.2.4. Obviously, the function f11 (x1 , x2 ) := j5 (f11 (c0 , x1 , x2 , u1 (x1 ), u1 (x2 ))) ∈ [A] ∩ P3,2 0 0 1 does not preserve the relation . For the function 0 1 0 f7 (x1 , x2 ) := f7 (c0 , f11 (x1 , x2 ), u1 (f11 (x1 , x2 )), x1 , x2 , u1 (x1 ), u1 (x2 )) ∈ [A] 1 0 1 we can assume w.l.o.g. that f7 = . If f7 (1, 1) ∈ {0, 2} we have 1 0 0 0 0 1 j1 f7 ∈ P ol3 ∪ P ol3 λ2 . If f7 (1, 1) = 1 then this is valid for j2 f7 0 1 1 instead of j1 f7 . Thus by Lemma 14.2.4, we have P3,2 ∩ P ol3 {0} ⊆ [A]. After these preparations we can easily show that an arbitrary function f n ∈ P ol3 {0} is a superposition over A. For this purpose, we need the functions q1 , q2 ∈ P3,2 defined by 0 if f (x) ∈ {0, 1}, q1 (x) := 1 if f (x) = 2, 0 if f (x) ∈ {0, 2}, q2 (x) := 1 if f (x) = 1, Then f7 (q1 (x), q2 (x)) = f (x) ∈ [A] holds. Consequently, [A] = P ol3 {0}. As explained in Section 14.2, our theorem results from Table 14.2, where the binary functions h1 , h2 ,..., h8 are defined in Table 14.3.
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12)
c0 − − + + − + + + + + + +
j1 + − + + − − + − + − + +
s2 − − − − + + + − − + + +
u5 − + − + + + + + + − + −
Table 14.2 h1 h2 h3 + + + + + − − + − + − − − + + − − + − − − − − − − − + − − − − − − − − −
h4 − − − − − − − − − + − −
h5 + + + + + + − + − − − −
h6 − − + − − − + + − − − −
h7 + − − + − − − − − − + +
h8 − − − + − − − − − − − +
412
14 Submaximal Classes of P3 x1 0 0 0 1 1 1 2 2 2
x2 0 1 2 0 1 2 0 1 2
h1 0 1 2 2 1 0 2 0 2
Table 14.3 h2 h3 h4 h5 0 0 0 0 1 1 1 1 1 1 2 2 1 2 1 1 1 1 2 1 1 1 0 2 0 1 2 2 1 1 0 2 2 1 1 2
h6 0 0 1 0 0 1 1 1 1
h7 0 0 0 2 1 0 0 0 0
h8 0 1 0 2 0 0 0 0 0
14.4 Proof of Theorem 14.1.3 W.l.o.g. we assume a = 0, b = 1 and c = 2. Further, in this proof let A be an arbitrary subset of P ol{0, 1}, which is not contained in any class ((1)–(15)) from the above list, which is given in Theorem 14.1.3. Then there are some functions f1 , f2 , ..., f15 ∈ [A] with the above property (∗ ). With the help of Lemma 14.2.1, one can easily prove that every function of P2 is a restriction of a function of [A]. Therefore, a function g ∈ {c0 , j2 , u2 } and a function h ∈ {j0 , j4 , s3 } are superpositions over A. If g ∈ {c0 , j2 } then the functions g g = c0 and h c0 = c1 belong to [A]. If g = u2 then f6 := f6 g ∈ {c0 , c1 , j2 , j3 } and {f6 f6 , h f6 f6 } = {c0 , c1 }. Thus the constant functions c0 and c1 are superpositions over A. Next we prove that the remaining unary functions of P ol3 {0, 1} and all functions of P3,2 are also superpositions over A. For this purpose, we distinguish two cases for the function h: Case 1: h ∈ {j0 , j4 }. Then h := h h ∈ {j1 , j5 } and the functions fi := h fi , i ∈ {1, 2, 3, 4, 5} belong to [A], where fi ∈ P3,2 and fi does not belong to the class (i). Further, := h(f10 (c0 , c1 , x)) belong to [A]. the functions f9 := h(f9 (c0 , c1 , x)) and f10 } ⊆ P3,2 and that It is easy to check that {h, f9 , f10 {h, f9 , f10 } is no subset 0 1 0 0 1 1 and P ol3 . Consequently, by Lemma of the classes P ol3 0 1 2 1 1 2 14.2.3, every function of P3,2 is a superposition over A. := f11 (c0 , j2 , j0 , c1 , x) ∈ {v2 , s3 }. A function of [A] is also f11 Case 1.1: f11 = v2 . := f12 (c0 , j2 , j3 , c1 , v2 ) = u2 ∈ [A] and In this case, we have f12 {f15 (c0 , c1 , j0 , j1 , j2 , j3 , j4 , j5 , u2 , v2 ), f15 (c0 , c1 , j1 , j0 , j2 , j3 , j5 , j4 , u2 , v2 )} = {s1 , s2 }. Consequently, (P ol3 {0, 1})1 ⊆ [A]. = s2 . Case 1.2: f11
14.4 Proof of Theorem 14.1.3
First we form a ternary function f) 15 which ⎛ 0 0 ⎝1 0 f) 15 0 2
413
as a superposition over P3,2 ∪ {f15 }, for ⎞ ⎛ ⎞ 1 0 1⎠=⎝1⎠ 2 2
) ) holds. If f) 15 (0, 1, 0) = 0 then s3 (f15 (c0 , x, s3 )) = v2 ∈ [A]. If f15 (0, 1, 0) = 1 ) then f15 (j0 , x, s3 ) = v2 ∈ [A]. Consequently, we can reduce Case 1.2 to Case 1.1. Consequently, P3,2 ∪ (P ol3 {0, 1})1 ⊆ [A] was proven in Case 1. Case 2: h = s3 .
0 0 1 2 0 2 1 2 W.l.o.g. we can assume f8 = . Consequently, 0 1 2 2 0 2 1 1 f8 (x1 , x2, x3 ) :=f8 (c0 , c1, x1 , x2 , x3 , s3 (x2 ), s3 (x3 )) belongs to [A], and we 0 2 0 2 have f8 = . Then the functions f8 := f8 (s3 , c0 , x) and f8 := 2 2 0 1 f8 (x, s3 , c0 ) are superpositions over A, where {f8 , f8 } ∩ {j0 , j3 , j2 , j4 } = ∅. Thus, we have either Case 1 or j2 = s3 j3 and j3 = s3 j2 belong to [A]. A superposition over A is also a certain binary function q with the property ⎛ ⎞ ⎛ ⎞ 0 0 1 ⎜0 1⎟ ⎜0⎟ ⎟ ⎜ ⎟ q⎜ ⎝ 1 0 ⎠ = ⎝ 0 ⎠. 1 1 0 If {q(0, 2), q(2, 0), q(1, 2), q(2, 1), q(2, 2)} ∩ {0, 1} = ∅ then {q(c0 , x), q(x, c0 ), q(j2 , x), q(x, j2 ), q(x, x)} ∩ {j0 , j4 } = ∅, i.e., one can reduce Case 2 to Case 1 here. Therefore, we can assume q(a) = 2 for every a ∈ E32 \E22 in the following. := f14 (c0 , c1 , j2 , j3 , x, s3 , u2 , v2 ) ∈ Then q(j3 , x) = u2 , s3 u2 = v2 and f14 {j0 , j1 , j4 , j5 } belong to [A]. Since s3 j1 = j4 and s3 j5 = j0 , we have again Case 1. Hence P3,2 ∪ (P ol3 {0, 1})1 ⊆ [A]. 0 1 2 0 1 0 W.l.o.g. we can assume f7 = . Then f7 (x1 , x2 ) := 0 1 2 1 0 2 u2 (f7 (c0 , c1 , x1 , x2 , j0 (x2 ))) ∈ [A], where ⎞ ⎛ ⎞ ⎛ 0 0 0 ⎜0 1⎟ ⎜0⎟ ⎟ ⎜ ⎟ ⎜ ⎜1 0⎟ ⎜0⎟ ⎟ ⎜ ⎟ f7 ⎜ ⎜ 1 1 ⎟ = ⎜ 0 ⎟. ⎟ ⎜ ⎟ ⎜ ⎝2 0⎠ ⎝0⎠ 2 2 1
414
14 Submaximal Classes of P3
Further, f13 (x1 , x2 ) := u2 (f13 (c0 , j2 (x1 ), j2 (x2 ), c1 , x1 , x2 , s3 (x1 ), s3 (x2 ))) ∈ [A], where ⎛ ⎞ ⎛ ⎞ 0 0 0 ⎝ 0 2 ⎠ = ⎝ 2 ⎠. f13 2 0 2 It is easy to see that one obtains a binary function f15 with ⎛ ⎞ ⎛ ⎞ 0 0 0 ⎝ 1 0⎠=⎝1⎠ f15 2 0 2
as a superposition over P3,2 ∪ (P ol3 {0, 1})1 ∪ {f15 }. Let f n be an arbitrary function of P ol3 {0, 1}. We show f ∈ [A]. For this α1 , ..., α r ∈ E3n , β ∈ E3 ) be an n-ary function defined purpose, let fα 1 ,...,αr ;β ( by β if x ∈ { α1 , ..., α r }, fα1 ,..., (x) := αr ;β 0 otherwise. Obviously, the functions of the type fα ;1 are superpositions over A for every = (α1 , ..., αn ) ∈ E3n and αi = 2 then fα ;2 ∈ [A] follows from α ∈ E3n . If α fα ;2 = f7 (xi , fα ;1 (x)). Furthermore, we have fα1 ,..., αr ;2 (x) = f13 (fα 1 ;2 (x), fα 2 , α3 ,..., αr ;2 (x)).
Consequently, all functions of the type fα1 ,..., α1 , ..., α r } ⊆ E3n \E2n αr ;2 with { are superpositions over A. Then f ∈ [A] follows from f (x) = f15 (fβ1 ,...,βs ;1 (x), fγ1 ,...,γt ;2 (x)),
1 , ..., βs } := {x ∈ E n | f (x) = 1} and {γ1 , ..., γt } := {x ∈ where {β 3 n E3 | f (x) = 2}. Consequently, [A] = P ol3 {0, 1}. Then our theorem follows from Table 14.4. The functions g1 , ..., g10 of Table 14.4 are defined in Table 14.5. The function h3 is defined by ⎧ x ∈ E33 \E23 , ⎨ 2 if x ∈ {(0, 1, 1), (1, 0, 1), (1, 1, 0), (1, 1, 1)}, h(x) := 1 if ⎩ 0 otherwise.
14.5 Proof of Theorem 14.1.4
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12) (13) (14) (15)
j0 − − − + + − + − − + + + + − +
j4 − − − + + − + − + − + + + − + x1 0 0 1 1 0 1 2 2 2
u2 + − + − + + + + + − + − + + + x2 0 1 0 1 2 2 0 1 2
s3 − − − + + + + + − − − − + + + g1 0 0 0 0 0 2 0 2 0
g1 + − + − + − − + + − + − − + + g2 1 1 1 1 1 2 1 1 1
Table g2 g3 − + + − + − − − + − − + − − + − − − + − − − + − + − + − + −
14.4 g4 g5 − + − + − + + + + + − + − − − − + − − + − − − − + + − − − −
Table 14.5 g3 g4 g5 g6 0 1 0 1 1 1 0 0 0 0 1 1 0 0 1 1 0 1 0 1 2 2 2 0 1 1 1 2 2 1 1 2 2 1 2 2
g6 − + − − − + + − − − − + + − − g7 0 1 1 1 2 2 2 2 2
g7 + + + − − + + + − + − + − + − g8 0 0 0 0 2 2 2 2 2
g8 + − + − + + + + + − + − − + −
g9 + + + + + + − − − − − − − + −
g10 + + + − − − + − + − + + + − +
415
h + + + + − + + + − − − − − + −
g9 g10 0 0 0 0 1 0 1 1 1 0 2 0 2 0 2 0 2 0
14.5 Proof of Theorem 14.1.4 W.l.o.g. we assume a = 0, b = 1 and c = 2. Further, in this proof, let A be an arbitrary subset of O, which is not contained in any class ((1)–(13)) from the above list, given in Theorem 14.1.4. Then, there are some functions f1 , ..., f13 ∈ [A] with the above property ( ). First we prove that O1 \{x} ⊆ [A] holds. For the unary function f1 , we have f1 (0) ∈ {1, 2}. Then, either f1 = c2 or we obtain c2 by forming f3 (x, f1 (x)). Consequently, {c0 , c1 , c2 } ⊆ [{f2 , f4 , f5 , c2 }] ⊆ [A]. W.l.o.g. we can assume 0 1 2 2 0 2 1 0 ∈ . f8 0 1 2 0 2 1 2 1 Since f8 is monotone, we have 0 1 2 0 0 1 0 0 ∈ . f8 0 1 2 0 2 1 2 1
416
14 Submaximal Classes of P3
Therefore, f8 (c0 , c1 , c2 , c0 , x, c1 , x) ∈ {j2 , j5 } is valid. Since we can assume w.l.o.g. 0 1 2 1 2 0 0 f10 ∈ , 0 1 2 2 1 1 2 and since f10 ∈ O, we have f10 (0, 1, 2, 0, 2) = 0 and f10 (0, 1, 2, 2, 2) ∈ {1, 2}. Thus f10 (c0 , c1 , c2 , x, c2 ) ∈ {j2 , u2 }. Since j5 u2 = j2 , j2 ∈ [A] holds. With the aid of functions f6 and f9 one can show analogously that v5 ∈ [A] also holds. Because of j5 = j2 v5 and v2 = v5 j2 we have j5 , v2 ∈ [A]. W.l.o.g. let 0 0 1 2 1 0 1 2 f7 ∈ . 0 1 2 0 1 2 1 2 Thus,
f7
0 1 2 1 0 1 1 0 1 2 1 1 2 1
∈
0 2
and therefore f7 (c0 , c1 , c2 , c1 , j5 , v5 , c1 ) = u5 ∈ [A]. Consequently, by u5 j2 = u2 , we have O1 \{x} ⊆ [A]. A conclusion of the Fundamental Lemma of Jablonskij (see Theorem 1.4.4, (a)) is the following fact: For the function f11 , there are some a, b, c ∈ E3 with the property (w.l.o.g.): ⎛ ⎞ ⎛ ⎞ 0 a c f11 ⎝ b c ⎠ ∈ ⎝ 1 ⎠ , 2 b d where (because of f11 ∈ O) (a, c) < (b, c) and (b, c) < (b, d). If one replaces the variables of function f11 by certain functions from O1 \{x}, one obtains a ∈ [A] with function f11 ⎛ ⎞ ⎛ ⎞ 0 0 0 ⎝ 2 0 ⎠ ∈ ⎝ 1 ⎠. f11 2 2 2 Now we can form gα (x, y) := f11 (u5 (x), u2 (y)), where ⎧ if (x, y) = (0, 2), ⎨α x ∈ {1, 2}, gα (x, y) = v2 (y) if ⎩ 0 otherwise.
Next, with the help of the function gα , we show that [A] ∩ {min, max} = ∅
(14.1)
is valid, where we use the notation x ∨ y := max(x, y) and x ∧ y := min(x, y). We distinguish three cases: Case 1: α = 0. In this case, we have g0 (x, y) = u5 (x) ∧ v2 (y) and
14.5 Proof of Theorem 14.1.4
417
g0 (u5 (g0 (x, v5 (y))), v2 (g0 (u2 (x), y))) = x ∧ y ∈ [A] holds. Case 2: a = 1. Then g1 (x, y) = (u5 (x) ∧ v2 (y)) ∨ j2 (y), whereby g1 (u5 (g1 (u2 (x), u2 (y))), u5 (j5 (g1 (x, u5 (y))))) = x ∨ y ∈ [A] holds. Case 3: a = 2. Since g2 (x, y) = (u5 (x) ∧ v2 (y)) ∨ u2 (y) is valid in this case, we have g2 (u5 (g2 (x, u5 (y))), v2 (g2 (u2 (x), y))) = x ∨ y ∈ [A] Thus (14.1) is proven. Since the classes (12) and (13) are isomorphic, we can assume w.l.o.g. that min ∈ [A]. The function f12 has the property ⎛ ⎞ ⎛ ⎞ 0 1 2 0 0 1 0 0 1 0 0 0 0 1 f12 ⎝ 0 1 2 0 0 1 1 2 2 ⎠ ∈ ⎝ 1 2 1 2 2 ⎠ . 0 1 2 1 2 2 0 0 1 1 1 2 2 2 (x, y) := f12 (c0 , c1 , c2 , x, u2 (x), v2 (x), y, u5 (y), v5 (y)), either If one forms f12 (x, y)) or the function u2 (f12 (x, y)) is identical to the the function u5 (f12 function g(x, y) := u5 (x) ∨ u5 (y). Therefore, we get x ∨ y = g(x, y) ∧ (v5 (g(u2 (x), u2 (y)))) ∈ [A]. Since (O1 \{x}) ∪ {∧, ∨} is a generating system of O (see Section 11.4), we have shown [A] = O. Then our theorem follows from Table 14.6, where g1 := ∧, g2 := ∨, g3 (x, y) := (j5 (x) ∧ j5 (y)) ∨ j2 (y) and g4 := u5 g3 .
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12) (13)
c0 + − + + − + + + + + + + +
c1 − − + − + + + + + + + + +
c2 − + − + + + + + + + + + +
j2 + − + − − + + − + − + + +
Table j 5 u2 + + − + + + − + + − + + + − − + + + + − + + + + + +
14.6 u5 v2 + − + + − + + − + + + − − + + + − + + + + + + + + +
v5 − + − − + − + + − + + + +
g1 + + + + + + + − + + − + −
g2 + + + + + − + + + + − − +
g3 + − + − + + + − + − + − −
g4 + + − + + + − + − + + − −
418
14 Submaximal Classes of P3
14.6 Proof of Theorem 14.1.5 Let A be an arbitrary subset of S, which is no subset of P ol3 {0} and no subset of L. Then there are two functions f1 , f2 ∈ [A] with the above property (∗ ). To prove [A] = S it is sufficient to show that α([A]) := {f c0 | f ∈ [A]} = P3 holds (see Theorem 8.3.2). α([A]) = P3 is proven, if one can show that α([A]) ⊆ B for every class B from the list of Theorem 14.1.1. Obviously, we have f11 ∈ {s4 , s5 }, S 1 = {s4 , s5 , e11 } ⊆ [f1 ] and f1 is no element of a maximal class of P3 with the marking (1), ..., (6), (8), ..., (16) of Theorem 14.1.1. Because of α(e21 ) = c10 , α([A]) is no subset of a maximal class of P3 with the marking (7). Further, α(f2 ) ∈ B for each maximal class B of P3 with the marking (17) or (18). Consequently, α([A]) = P3 and therefore [A] = S. Then, our Theorem 14.1.5 follows from S ∩L ⊆ S ∩P ol3 {0} and S ∩L S ∩P ol3 {0}.
14.7 Proof of Theorem 14.1.7 W.l.o.g. we assume a = 0, b = 1 and c = 2. Further, in this proof, let A be an arbitrary subset of C, which is not contained in any class with the marking (1)–(7) from the above list, which is given in Theorem 14.1.7. Then there are some functions f1 , ..., f7 ∈ [A] with the above property ( ). First we show that {c0 , c1 , c2 } ⊂ [A]. Obviously, f1 ∈ {j0 , j4 , j3 , c1 , u0 , u4 , u3 , c2 }. We distinguish the following three cases: Case 1: f1 ∈ {c1 , c2 , j3 , u4 }. In this case f1 := f1 f1 = cα , α ∈ {1, 2} holds. Since f2 , f3 ∈ C and f2 (0, 1) = 2 or f3 (0, 2) = 1, we have f2 (1, 1) ∈ {0, 2} or f3 (2, 2) ∈ {0, 1}. Therefore, {c1 , c2 } or {c0 , cα } is a subset of [A]. With the aid of functions f2 , f3 , f4 (∈ [A]) one can prove {c0 , c1 , c2 } ⊂ [A] easily. Case 2: f1 = j0 . In this case, the functions j0 j0 = j5 and f2 (x) := f2 (j5 , j0 ) ∈ {c2 , u2 } belong to [A]. If f2 = c2 , then we obtain by Case 1 that {c0 , c1 , c2 } ⊂ [A]. If f2 = u0 then u5 = u0 u0 ∈ [A]. For the function f7 is valid: ⎛ ⎞ ⎛ ⎞ 0 1 0 2 0 1 0 0 1 1 0 1 2 0 0 2 2 0 2 1 2 f7 ⎝ 1 0 2 0 0 0 1 0 1 0 0 1 0 2 0 2 0 2 2 ⎠ ∈ ⎝ 1 2 ⎠ . 2 2 1 1 0 0 0 1 0 1 1 1 0 0 2 0 2 2 2 2 1 0 1 2 0 1 0 2 Since f7 preserves the relation , we have 0 1 2 1 0 2 0 f7 Consequently,
0 2 0 1 0 0 . . . . . 0 0 0 . . . . 0 2 0 1 0 1 1 . . . . . 1 2 2 . . . . 2
=
0 0
.
14.7 Proof of Theorem 14.1.7
419
j0 (f7 (u5 , u0 , j5 , j0 , j5 , j5 , ....., j5 , u5 , u5 , ...., u5 ) = c0 ∈ [A]. Therefore, one can reduce Case 2 to Case 1. Case 3: f1 ∈ {j4 , u0 , u3 }. It is easy to check that one can also reduce this case to the first case analogously to Case 2. Thus
{c0 , c1 , c2 } ⊂ [A]
is proven. Since f6 ∈ C and
f6
holds, we have
f6
0 1 2 0 1 0 2 1 0 1 2 1 0 2 2 2 0 1 2 0 1 0 2 0 0 1 2 1 0 2 2 0
Consequently, the functions f6 (x)
=
=
2 1 0 0
.
:=
f6 (c0 , c1 , c2 , c0 , c1 , c0 , c2 , x) and 0 0 := f6 (c0 , c1 , c2 , c0 , c1 , c2 , c0 , x) belong to [A], where f6 = 1 2 0 0 0 1 2 0 0 and f6 . Therefore, we can assume w.l.o.g. f5 = = 2 1 0 1 2 1 2 1 . Then 0 p(x) := f5 (c0 , c1 , c2 , x, f6 (x)) ∈ {j0 , j4 }. f6 (x)
It is easy to check that f6 (0, 1, 2, 1, 0, 2, 0, 1) ∈ {0, 2}. Consequently, f6 (x) := f6 (c0 , c1 , c2 , c1 , c0 , c2 , c0 , x) ∈ {j2 , s2 }. Therefore, we have to distinguish the following two cases for f6 : Case 1: f6 = j2 . Then, the functions p j2 = j3 , f6 j2 = u2 , f6 j3 = u3 , f6 (c0 , c1 , c2 , j2 , j3 , u2 , u3 , x) = s2 , j2 s2 = j1 , j3 s2 = j4 , s2 j1 = u1 and s2 j4 = u4 are superpositions over A. Consequently, the function f7 (x1 , x2 ) := f7 (x1 , x2 , s2 (x1 ), s2 (x2 ), c0 , j1 (x2 ), j1 (x1 ), j2 (x1 ), j3 (x1 ), j4 (x1 ), j4 (x2 ), c1 , u1 (x1 ), u2 (x1 ), u3 (x1 ), j4 (x1 ), j4 (x2 ), c2 ) belongs to [A], where
⎛
⎞ ⎛ ⎞ 0 1 α f7 ⎝ 1 0 ⎠ = ⎝ α ⎠ 2 2 β
and {α, β} = {1, 2}. Since s2 ∈ [A], we can assume α = 1 and β = 2. Because of f7 ∈ C, we have f7 (0, 0) = f7 (0, 2) = f7 (2, 0) = 0 and {f7 (1, 2), f7 (2, 1)} ⊆
420
14 Submaximal Classes of P3
{0, 1}. Consequently, the function f7 (x1 , x2 ) := j2 (f7 (u1 (x1 ), u1 (x2 ))) ∈ [A] has the properties ⎛ ⎞ ⎛ ⎞ 0 0 0 ⎜ ⎟ ⎜ ⎟ 0 1 ⎟ ⎜0⎟ f7 ⎜ ⎝1 0⎠=⎝0⎠ 1 1 1 and f7 ∈ P3,2 . Obviously, the set {j2 , p, c0 , c1 , f7 } is a subset of P3,2 , however no subset of the maximal classes of P3,2 (see Lemma 14.2.3). Consequently, the sets P3,2 and {s2 r | r ∈ P3,2 } = {r ∈ P3 | Im(r ) ⊆ {0, 2} } are subsets of [A]. With the aid of the functions 2 if (2, i) = (x1 , x2 ), ti (x1 , x2 ) := 0 otherwise, i ∈ {1, 2}, of [A] we can form a function t ∈ [A] by t(x1 , x2 ) := f7 (s2 (f7 (s2 (x2 ), t1 (x1 , x2 ))), t2 (x1 , x2 )) ⎧ (x1 , x2 ) = (2, 1), ⎨ 1 if 2 if (x1 , x2 ) = (2, 2), = ⎩ 0 otherwise. Let S and T be nonempty disjoint subsets of E3n with the property that for different arbitrary tuples σ := (σ1 , ..., σn ) ∈ T and τ := (τ1 , ..., τn ) ∈ T there exists an i with {σi , τi } = {1, 2}. Then the function ⎧ x ∈ S, ⎨ 1 if x ∈ T, fS,T (x) := 2 if ⎩ 0 otherwise, belongs to C. [A] = C would be proven in Case 1, if we could show that every function of the form fS,T is an element of [A]. For σ := (σ1 , ..., σn ), τ := (τ1 , ..., τn ), {σi , τi } = {1, 2} and 2 if x ∈ {σ, τ }, gσ,τ (x) := 0 otherwise, we have
f{σ},{τ } (x) :=
t(g{σ},{τ } (x), xi ) if (σi , τi ) = (1, 2), t(g{σ},{τ } (x), s2 (xi )) if (σi , τi ) = (2, 1),
i.e., f{σ},{τ } ∈ [A]. Furthermore, fS,T (x) = f7 (f{σ},T (x), fS\{σ},T (x)), fS,T (x) = s2 (f7 (s2 (f{σ},T (x)), s2 (fS\{σ},T (x))))
14.8 Proof of Theorem 14.1.8
421
is valid. Consequently, the functions of the type fS,T are superpositions over A (see Section 11.2). Thus, [A] = C holds in Case 1. Case 2: f6 = s2 . If the above function p is the function j4 , then we can reduce Case 2 to Case 1 because of j4 j4 s2 = j2 . Consequently, we can assume p = j0 ∈ [A]. Then we have {j0 j0 = j5 , s2 j0 = u0 , s2 j5 = u5 } ⊆ A. Further, a function of [A] is also the function f7 (x1 , x2 , x3 ) := f7 (x1 , x2 , s2 (x1 ), s2 (x2 ), c0 , j0 (x1 ), j0 (x2 ), x3 , j0 (x3 ), j5 (x2 ), j5 (x1 ), c1 , u0 (x1 ), u0 (x2 ), u5 (x3 ), u0 (x3 ), u5 (x2 ), u5 (x1 ), c2 ), where
⎛
⎞ ⎛ ⎞ 0 1 0 1 2 f7 ⎝ 1 0 0 ⎠ ∈ ⎝ 1 2 ⎠ . 2 2 1 2 1
Since f7 ∈ C, we have f7 (2, 0, 0) = 0. Thus j0 (f7 (x, j0 , c0 )) = j2 ∈ [A], i.e., one can reduce Case 2 to Case 1. We have proven [A] = C with that. Then our theorem follows from Table 14.7 and Table 14.8. Table 14.8
Table 14.7 (1) (2) (3) (4) (5) (6) (7)
c1 − + − + + + +
p1 + − − − − − −
p2 + + − − − − −
p3 + − + + + − −
p4 − − + + − + +
p5 + + + − + + −
p6 + + − − + − +
x1 0 0 0 1 1 1 2 2 2
x2 0 1 2 0 1 2 0 1 2
p1 0 0 1 0 2 0 1 0 0
p2 0 1 0 0 0 2 1 0 0
p3 0 2 0 0 2 1 2 2 2
p4 2 0 0 2 2 2 0 2 2
p5 0 1 0 1 1 0 0 0 2
p6 0 0 0 0 0 0 0 2 1
14.8 Proof of Theorem 14.1.8 7
W.l.o.g. we can assume a = 0, b = 1, and c = 2. Further, in this proof let A be an arbitrary subset of U , which is not contained in any class from the above list, which is given in Theorem 14.1.8. Then there are some functions f1 , ..., f13 ∈ [A] with the above property ( ). First we show {c0 , c1 , c2 } ⊂ [A]. 7
Essential parts of this proof come from the proof of the following theorem, found by W. Harnau: Let A ⊆ U be arbitrary. Then [A] = U if and only if U 1 \{u3 , v3 } ⊆ [A] and A ⊆ B for every class B with the marking (9), (11), (12), (13) in Theorem 14.1.8.
422
14 Submaximal Classes of P3
Because of f2 (0, 1) = 2 and f2 ∈ U we have f2 (x, x) ∈ {u3 , v3 , c2 }. Obviously, c0 , c1 and c2 are superpositions over {c2 , f1 , f3 , f4 }. If f2 (x, x) = c2 then we can assume either {c1 , u2 } ⊆ [A] or {co , v2 } ⊆ [A] because of u3 u3 = u2 , v3 v3 = v2 , f3 (u2 , u3 ) ∈ {j3 , c1 , v2 }, f4 (v2 , v3 ) ∈ {c0 , j2 , u2 }, j3 j3 = c1 , j2 j2 = c0 , v2 u3 = v3 , u2 v3 = u3 , f8 (u2 , u3 , v2 , v3 ) ∈ {c0 , c1 , c2 , j2 , j3 } and u3 c2 = c0 . Since u2 c1 = c0 , v2 c0 = c1 and f2 (c0 , c1 ) = c2 , we have {c0 , c1 , c2 } ⊂ [A]. Next we prove U 1 ∪ P3,2 ⊆ [A]. By definition of f9 we have 0 1 2 0 1 0 1 2 2 ∈ , f9 0 1 2 1 0 2 2 0 1 i.e.,
f9
0 1 2 1 0 1 1 0 1 2 1 0 0 0
=
2 2
and therefore f9 (c0 , c1 , c2 , c1 , c0 , x, x) ∈ {u3 , v3 }. Since v3 v3 = v2 , we have that either {u2 , u3 } or {v2 , v3 } is a subset of [A]. W.l.o.g. let 0 1 2 0 1 0 2 1 f5 = 0 1 2 1 0 2 0 2 and
f6
0 1 2 1 0 1 2 0 1 2 1 0 2 1
=
0 2
,
i.e., we have f5 (c0 , c1 , c2 , c0 , c1 , u2 , u3 ) = v2 and f6 (c0 , c1 , c2 , c1 , c0 , v2 , v3 ) = u2 . Thus, because of v2 u3 = v3 and u2 v3 = u3 , the set {u2 , u3 , v2 , v3 } is a subset of [A]. Further, the function f7 with f7 (x) := f7 (c0 , c1 , c2 , x) ∈ {j0 , j4 , s3 } belongs to [A]. We distinguish two cases for f7 : Case 1: f7 ∈ {j0 , j4 }. In this case, the set {f7 , c0 , c1 , f7 (v2 ), f7 (f12 (x1 , ..., x8 , c2 ))} is a subset of [A] ∩ P3,2 , however, no subset of a maximal class of P3,2 (see Lemma 14.2.3). Consequently, P3,2 is a subset of [A]. Obviously, the functions s1 and s3 are superpositions over {f11 , c2 , u2 , u3 , v2 , v3 } ∪ P3,2 . Therefore, P3,2 ∪ U 1 ⊆ [A] in Case 1. Case 2: f7 = s3 . W.l.o.g. we can assume ⎛ ⎞ ⎛ ⎞ 0 1 2 0 0 1 1 2 2 0 1 1 1 f10 ⎝ 0 1 2 0 0 1 1 2 2 1 0 ⎠ ∈ ⎝ 0 0 ⎠ . 0 1 2 1 2 0 2 0 1 2 2 0 1 Since f10 ∈ U , we have f10 (0, 1, 2, 0, 2, 1, 2, 0, 1, 2, 2) ∈ {0, 1}, i.e.,
14.8 Proof of Theorem 14.1.8
423
f10 (c0 , c1 , c2 , c0 , u2 , c1 , u2 , c1 , v2 , u3 , v3 , x, s3 ) ∈ {j0 , j4 }. Therefore, one can reduce Case 2 to Case 1. Thus P3,2 ∪ U 1 ⊆ [A]. with Then, a binary function f11 ⎛ ⎞ ⎛ ⎞ 0 0 0 ⎝ 1 0⎠=⎝1⎠ f11 2 0 2 is a superposition over A. It is ⎛ 0 ⎜ ⎜ 1 f13 ⎝ 2 2
easy to prove that a 6-ary function f13 with ⎞ ⎛ ⎞ 0 0 2 2 2 0 ⎜2⎟ 2 2 0 0 2⎟ ⎟=⎜ ⎟ 1 2 1 2 0⎠ ⎝2⎠ 2 1 2 1 1 2
∈ U , we have is a superposition over P3,2 ∪ U 1 ∪ {f13 }. Since f13 ⎛ ⎞ ⎛ ⎞ 0 0 0 2 2 2 0 ⎜ ⎟ ⎜2⎟ ⎜ 0 2 2 0 0 2 ⎟ f13 ⎝ = ⎜ ⎟. 2 0 2 0 2 0⎠ ⎝2⎠ 2 2 0 2 0 0 2
We form (x1 , x2 , x3 ) := u2 (f13 (x1 , x2 , x3 , u3 (x3 ), u3 (x2 ), u3 (x1 ))) ∈ [A]. f13 Because of {f13 (0, 0, 2), f13 (0, 2, 0), f13 (2, 0, 0)} ⊆ {0, 2} we can assume w.l.o.g. f13 (0, 2, 0) = f13 (2, 0, 0). Then: f13 (x1 , x2 , c0 ) ∈ {d1 , d2 }, where d1 and d2 are defined in Table 14.9.
x1 0 0 1 1 0 1 2 2 2
Thus because of and
x2 0 1 0 1 2 2 0 1 1
d1 0 0 0 0 0 0 0 0 2
d2 0 0 0 0 2 2 2 2 2
d3 0 0 0 1 0 1 0 1 0
Table 14.9 d4 min max 0 0 0 1 0 1 1 0 1 1 1 1 0 0 2 0 1 2 0 0 2 0 1 2 0 2 2
d5 0 1 1 0 2 2 2 2 0
d6 0 1 0 0 0 2 1 1 2
d7 2 2 2 2 0 1 2 2 2
u5 (d2 (u3 (x1 ), u3 (x2 ))) = d1 (x1 , x2 )
d8 1 0 0 1 1 1 1 1 1
d9 0 0 0 1 2 2 2 2 2
424
14 Submaximal Classes of P3
u3 (d1 (u3 (x1 ), u3 (x2 ))) = d2 (x1 , x2 ), the functions d1 and d2 are superpositions over A. Further, we have min(x1 , x2 ) = f11 (d3 (x1 , x2 ), d1 (x1 , x2 )) ∈ [A]
and
max(x1 , x2 ) = f11 (d4 (x1 , x2 ), d2 (x1 , x2 )) ∈ [A]
(see Table 14.9). With that, it was shown that the basis functions, determined in [Gni 65] 8 for the class U , belong to [A]. Therefore, [A] = U . Then, our theorem follows from Tables 14.9 and 14.10, where the ternary function d ∈ U is defined by 2 if x1 = x2 = 2 ∨ x1 = x3 = 2 ∨ x2 = x3 = 2, d(x1 , x2 , x3 ) := 0 otherwise.
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12) (13)
c1 − + − + + + + − + + + + +
c2 + − + + + + + − + + + + +
j2 − + − − + + + − + + + + +
u3 − − + − + − + + − + + + +
v3 − − − + − + + + − + + + +
Table s3 d5 + − + + − + − − − − − − − − + − + − + − + − + + + +
14.10 d6 d7 + + + − − + − + − − − − − + + − + − − + − − − + + −
d8 − + − + + + − − + − + + +
d9 + + + + + − + − + + − − −
d max min + + + + + + + + + − + + + − + − + + + + + + − − + + + + + − + − + + − − − − −
14.9 Proof of Theorem 14.1.9 Let A be an arbitrary subset of B := P olι33 , which is not contained in any class from the list, which is given in Theorem 14.1.9. Then, for each i ∈ {1, 2, ..., 5} there is a function fi ∈ A which does not belong to the class with marking (i). Obviously, S := {s1 , s2 , ..., s6 } is a subset of [{f1 , f2 , f3 , f4 }]. For the function f5 (x) := f (x, x, ..., x) ∈ [A], the following cases are possible: Case 1: f5 ∈ B 1 \{c0 , c1 , c2 }. In this case, one can easily prove (P3 (2))1 ⊆ [A] when one forms the superpositions of the form sf5 s and sf5 f5 s , where {s, s } ⊂ S. Consequently, P31 ⊆ [A]. Then, by Theorem 4.3, we have [P31 ∪ {f5 }] = P olι33 = [A]. 8
See Chapter 11.
14.10 On the Cardinality of L↓3 (A) for Submaximal Clones A
425
Case 2: f5 ∈ {c0 , c1 , c2 }. Obviously, we have {co , c1 , c2 } ⊆ [S ∪{f5 }] in this case. Since f5 ∈ P3 (2)\[P31 ], there exist some tuples a := (a1 , ..., an ) and a := (a1 , ..., ai−1 , ai , ai+1 , ..., an ) with ai = ai and f5 (a) = f5 (a ). Therefore, a unary function of B 1 \{c0 , c1 , c2 } belongs to [A]. Hence, one can reduce Case 2 to Case 1. Consequently, [A] = P olι33 is proven. Since one can easily prove that the classes with the marking (1)–(5) are Bmaximal, our theorem holds.
14.10 On the Cardinality of L↓3 (A) for Submaximal Clones A The aim of this section is to prove Theorem 14.10.1 ([Bul-L-S 96]) There are 5 submaximal clones (⊂ P3 ) with finitely many subclasses and 7 submaximal clones (⊂ P3 ) whose subclass lattice is infinite but countable. The subclass lattices of the remaining 146 submaximal clones of P3 have the cardinality of continuum. More precise: Let F1 , ...., F43 be the 43 families of submaximal clones of P3 given in Table 14.1 and let A ∈ Fi with i ∈ {1, 2, ..., 43}. Then ⎧ 5 if ⎪ ⎪ ⎪ ⎪ ⎪ 8 if ⎪ ⎪ ⎨ ↓ 32 if |L3 (A)| = ⎪ ⎪ ⎪ ⎪ ℵ0 if ⎪ ⎪ ⎪ ⎩ c otherwise.
i = 17, i = 7, i = 30, i ∈ {28, 29, 43},
We need the following lemmas for proof of the above theorem. Lemma 14.10.2 Let n ∈ N \ {1, 2} and pn ∈ P3n be defined by 1 if ∃i : (xi = 1 ∧ ∀i = j : xi = 2), pn (x1 , ..., xn ) := 0 otherwise. Let πn be the n-ary relation αn := {(1, 2, 2, ..., 2), (2, 1, 2, ..., 2), ..., (2, 2, , ..., 2, 1)} ∪ (E3n \{1, 2}n ). Then (a) ∀n ≥ 3 : pn ∈ P ol3 αn .
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14 Submaximal Classes of P3
(b) ∀m = n : pm ∈ P ol3 αn . (c) (pi )i≥3 is an infinite basis for the clone [{pi | i ≥ 3}]. Proof. (a) follows from ⎛
⎞ ⎛ ⎞ 1 2 2 ... 2 1 ⎜ 2 1 2 ... 2 ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ pn ⎜ ⎝ . . . . . . . . . . . ⎠ = ⎝ ... ⎠ ∈ αn . 2 2 2 ... 1 1
(b) is easy to check by considering the two cases m < n and m > n. (c) Let j ≥ 3. By (b), we have that pi ∈ P ol3 αj for all i ≥ 3, i = j, and thus [{p3 , p4 , ..., }\{pj }] ⊆ P ol3 αj . Since pj ∈ P ol3 αj , we deduce that pj ∈ [{p3 , p4 , ..., }\{pj }]. Consequently, {p3 , p4 , ...} is an independent set of operations, proving (c). Lemma 14.10.3 Let n ∈ N \ {1} and qn ∈ P3n be defined by 1 if ∀i : xi = 2, qn (x1 , ..., xn ) := pn (x) otherwise. Then {qi | i ≥ 2} is an infinite basis for the clone [{qi | i ≥ 2}]. Proof. The proof can be found in [Jan-M 59] (see also Lemma 8.1.1). Lemma 14.10.4 Let n ∈ N \ {1} and rn ∈ P3n be defined by ⎧ ∃i : (xi = 2 ∧ ∀j = i : xj = 1), ⎨ 1 if 2 if x1 = ... = xn = 2, rn (x1 , ..., xn ) := ⎩ 0 otherwise. Let n be the n-ary relation n := {(a1 , ..., an ) ∈ E3n | (∃i : ai = 2 ∧ ∀j = i : aj = 1) ∨ (∃i : ai = 0)}. Then (a) ∀n ≥ 2 : rn ∈ P ol3 n . (b) ∀n = m : rm ∈ P ol3 n . (c) {ri | i ≥ 2} is an infinite basis for [{ri | i ≥ 2}]. Proof. (a) follows from
⎛
⎞ ⎛ ⎞ 2 1 1 ... 1 1 ⎜ 1 2 1 ... 1 ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ rn ⎜ ⎝ ...................... ⎠ = ⎝ ... ⎠ . 1 1 1 ... 2 1
(b): Let m = n, m, n ≥ 2, A = (aij )n,m be an n×m matrix on E3 with columns a1 , ..., am ∈ n , where ai = (a1i , ..., ani ) (i = 1, ..., n). If aij = 0 for some i, j
14.10 On the Cardinality of L↓3 (A) for Submaximal Clones A
427
then rm (ai1 , ..., aim ) = 0 and by definition of n , rn (A) = rn (a1 , ..., an ) ∈ . So assume that a1 , ..., am ∈ {1, 2}n . We distinguish two cases: Case 1: m < n. At least one row of the matrix A consists of 1s, hence rm (A) ∈ n . Case 2: m > n. In this case, there are i = j with ai = aj . Hence, one row of the matrix A consists of 1s or contains at least two 2s, and so rm (A) ∈ n . Therefore (b) holds. (c) follows straightforward from (a) and (b). Lemma 14.10.5 Let n ∈ N \ {1, 2} and sn ∈ P3n be defined by sn (x1 , ..., xn ) := x1 if ∃i : (xi = 1 ∧ ∀j = i : xj = 0) ∨ (xi = 0 ∧ ∀j = i : xj = 1), 2 otherwise. Let σn be the n-ary relation σn := {(a1 , ..., an , an+1 ) ∈ E3n | (∃i ∈ {1, 2, ..., n} : (xi = 1 ∧ ∀j = i : xi = 0) ∨ ai = 2}. Then (a) ∀n ≥ 3 : sn ∈ P ol3 σn . (b) ∀n = m : sm ∈ P ol3 σn . (c) {si | i ≥ 3} is an infinite basis for [{si | i ≥ 3}]. Proof. (a) follows from ⎞ ⎛ ⎞ 1 1 0 0 ... 0 ⎜ 0 1 0 ... 0 ⎟ ⎜ 0 ⎟ ⎜ ⎟ ⎜ ⎟ ⎟ ⎜ ⎟ sn ⎜ ⎜ ...................... ⎟ = ⎜ ... ⎟ . ⎝ 0 0 0 ... 1 ⎠ ⎝ 0 ⎠ 2 0 0 0 ... 0 ⎛
(b) and (c) are easy to verify. The following lemma was found by B. Strauch. Lemma 14.10.6 Let n ∈ N \ {1, 2} and let the n-ary function tn ∈ P3n be defined by ⎧ ∃i : (xi ∈ E2 ∧ ∀j = i : xj = 0), ⎨ 0 if x = 1 ∨ (∃i : xi = 2), tn (x1 , ..., xn ) := 2 if ⎩ 1 otherwise. Moreover, let
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14 Submaximal Classes of P3
αm := {(a1 , ..., am , a1 , ..., am ) ∈ E22·m | (∃i : ai = 1) ∧ ∀j = i : aj = 0)}, x := x + 1 (mod 2), βm := (E2m \{0}m ) × {1}m , γm := E32·m \E22·m , τm := αm ∪ βm ∪ γm . Then (a) ∀n ≥ 3 : tn ∈ P ol3 τn . (b) ∀m = n : tn ∈ P ol3 τm . (c) {tn | n ≥ 3} is an infinite basis for [{tn | s ≥ 3}]. Proof. (a) follows from ⎛
⎞ ⎛ ⎞ 0 1 0 0 ... 0 0 ⎜ 0 1 0 ... 0 0 ⎟ ⎜ 0 ⎟ ⎟ ⎜ ⎟ ⎜ ⎜ . . . . . . . . . . . . . . ⎟ ⎜ ... ⎟ ⎟ ⎜ ⎟ ⎜ ⎜ 0 0 0 ... 0 1 ⎟ ⎜ 0 ⎟ ⎟ = ⎜ ⎟ ∈ τn . ⎜ sn ⎜ ⎟ ⎜ ⎟ ⎜ 0 1 1 ... 1 1 ⎟ ⎜ 1 ⎟ ⎜ 1 0 1 ... 1 1 ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ ⎜ ⎝ . . . . . . . . . . . . . . ⎠ ⎝ ... ⎠ 1 1 1 1 ... 1 0
(b): Let m, n ≥ 3, m = n and r1 , ..., rn ∈ τm . If {r1 , ..., rn } ⊆ αm ∪ βm or {r1 , ..., rn } ⊆ βm , we have tn (r1 , ..., rn ) ∈ τm . So assume {r1 , ..., rn } ⊆ αm ∪βm and {r1 , ..., rn } ⊆ βm . It is easy to see that ri = rj for some i = j implies tn (r1 , ..., rn ) ∈ τm . Further, by the definition of tn tn (r1 , ..., rn ) = {o}m × {1}m
(14.2)
is possible only if tn (r1 , ..., rn ) ∈ τm . For pairwise distinct r1 , ..., rn ∈ αm ∪βm , the condition (14.2) can be valid only if m = n. Since we assume m = n, tn (r1 , ..., rn ) ∈ τm holds. (c) follows from (a) and (b). The following two lemmas were found by A. Bulatov. For these lemmas, we need some notations. For every n ∈ N let n := {1, 2, ..., n}. Furthermore, let
:=
and for n ≥ 3
0 1 0 2 1 0 2 0
(14.3)
14.10 On the Cardinality of L↓3 (A) for Submaximal Clones A
429
n := {(a1 , a2 , ..., an ) | ∃i : (ai ∈ {1, 2} ∧ (∀j = i : aj = 0)}∪({1, 2}n \{2}n ). (14.4) We want to prove that the co-clone [{} ∪ {m | m ≥ 3}]
(14.5)
has an infinite basis. Lemma 14.10.7 For a finite index-set I and every i ∈ I let πi be an mi -ary relation of {} ∪ {m | m ≥ 3}. Moreover, let ϕi be a mapping of mi in n, i ∈ I. If the relation l , l ≥ 3 has the form l = {(a1 , ...., al ) ∈ E3l | ∃al+1 , ..., an ∈ E3 : ∀i ∈ I : (aϕi (1) , aϕi (2) , ..., aϕi (mi ) ) ∈ πi }
(14.6)
for a some n and if there exists an i ∈ I with πi = , then: (a) If a tuple (a1 , ..., an ) ∈ E3n fulfills the condition ∀i ∈ I : (aϕi (1) , aϕi (2) , ..., aϕi (mi ) ) ∈ πi
(14.7)
(we say : “(a1 , ..., an ) is permissible”) and if aj = 2 for a some j ∈ n, then the n-tuple (a1 , ..., aj−1 , 1, aj+1 , .., an ) is also permissible. (b) ∃α ∈ I : ϕα (mα ) ⊆ l ∧ πα = . (c) Let ϕα (mα ) ⊆ l and πα = . Then ϕα is bijective and πα = l holds. Proof. (a) follows straightforwad from the observation that, if we replace a 2 with a 1 in a tuple of l or , we obtain again a tuple from l or , respectively. (b): Suppose that ∀i ∈ I : (πi = =⇒ ϕi (mi ) ⊆ l).
(14.8)
Because of (14.4) and (14.6), there exists a permissible n-tuple of the form a := (a1 , ..., al , al+1 , ..., an ) with a1 = 1 and a2 = ... = al = 2; i.e., ∀i ∈ I : (aϕi (1) , ..., aϕi (mi ) ) ∈ πi .
(14.9)
By (a) we can suppose w.l.o.g. that ∀i ∈ {l + 1, l + 2, ..., n} : ai ∈ {0, 1}. We now show that (14.8) and (14.9) imply the permissibility of the tuple b := (b1 , ..., bn ), where b1 = ... = bl = 2 and bi = ai for all i ∈ {l+1, l+2, ..., n}, which leads to the contradiction (2, 2, ..., 2) ∈ l . The following cases are possible for α ∈ I:
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14 Submaximal Classes of P3
Case 1: 1 ∈ ϕα (mα ). In this case, the permissibility of b follows from (14.9). Case 2: 1 ∈ ϕα (mα ); i.e., there exists an i ≤ mα with ϕα (i) = 1. Case 2.1: πα = . W.l.o.g. let ϕα (1) = 1. By (14.8) we have ϕα (2) ∈ {3, ..., n}, hence (bϕα (1) , bϕα (2) ) ∈ {(2, 1), (2, 0)} ⊆ . Case 2.2: πα = s . Case 2.2.1: 0 ∈ {aϕα (1) , ..., aϕα (1) }. By (14.8) and the definition of s we obtain (aϕα (1) , ..., aϕα (i−1) , a1 , aϕα (i+1) , ..., aϕα (s) ) = (0, ..., 0, 1, 0, ..., 0).
(14.10)
Since ak = bk for all k ≥ 2 and b1 = 2, the inclusion (bϕα (1) , ..., bϕα (s) ) ∈ s follows from (14.10). Case 2.2.2: {aϕα (1) , ..., aϕα (s) } ⊆ {1, 2}. Since ϕα (mα ) ⊆ m there exists a j such that ϕα (j) ∈ m, bϕα (j) = aϕα (j) = 1 and {bϕα (1) , ..., bϕα (s) } ⊆ {1, 2}, hence (bϕα (1) , ..., bϕα (s) ) belongs to πα and therefore b is permissible as required. (c): By assumption, there is an s ≥ 3 with πα = s . Then mα = s. First we prove that ϕα is injective. Suppose ϕα is not injective. Then the following two cases are possible: Case 1: |ϕα (mα )| = 1, i.e., ϕα (s) = {j} for a some j ≤ m. Then for every permissible tuple a := (a1 , ..., as ) we have (aϕα (1) , aϕα (2) , ..., aϕα (s) ) = (aj , aj , ..., aj ) = (1, 1, ..., 1) which contradicts (14.6) because all elements of {0, 1, 2} occur in every row of the relation l . Case 2: ∃i1 , i2 , i3 ∈ s : i1 = i2 ∧ ϕα (i1 ) = ϕα (i2 ) ∧ ϕα (i3 ) = ϕα (i1 ). W.l.o.g. let ϕ(i1 ) = 1. Then for the tuple (a1 , ..., al ) := (1, 0, 0, ..., 0) ∈ l we obtain (aϕα (1) , aϕα (2) , ..., aϕα (s) ) ∈ s , which is not possible, because of aϕ(i1 ) = aϕα (i2 ) = 1 and aϕα (i3 ) = 0. Consequently, ϕα is injective. We now show that ϕα is surjective. Suppose that ϕα (mα ) ⊂ m. We may assume w.l.o.g. that 1 ∈ ϕα (mα ). Consider the tuple a := (a1 , a2 , ..., al ) = (1, 2, 2, ..., 2) ∈ l . Then (aϕα (1) , ..., aϕα (s) ) = (2, 2, 2, ..., 2) ∈ s , in contradiction with (14.6). We have shown that ϕα is a bijection. Combining this with the properties of l , we deduce that πα = l . Lemma 14.10.8 Let n ∈ N \ {1, 2} and let and n be as in (14.3) and (14.4). Then: (a) ∈ [{n | n ≥ 3}]. (b) ∀l ≥ 3 : l ∈ [{} ∪ {n | n ∈ N\{1, 2, l}}]. (c) The co-clone [{} ∪ {n | n ≥ 3}] has the infinite basis {, 3 , 4 , ...}. Proof. (a) follows from the fact that the constant function c1 preserves the relation n for all n ≥ 3 but does not preserve the relation .
14.10 On the Cardinality of L↓3 (A) for Submaximal Clones A
431
(b): Suppose for an l ≥ 3 we have l ∈ [{} ∪ {n | n ∈ N\{1, 2, l}}]. Then, by Theorem 2.11.2,(a),(b) l = {(aϕ(1) , , ...., aϕ(l) ) ∈ E3l | ∃al+1 , ..., an ∈ E3 : ∀i ∈ I : (aϕi (1) , aϕi (2) , ..., aϕi (mi ) ) ∈ πi },
(14.11)
holds, where I is an index-set, πi are some mi -ary relations of {}∪{m | m ≥ 3, m = l} for all i ∈ I and ϕ : l −→ n and ϕi : mi −→ n are mappings. There must be at least a relation under the relations πi , which is different from the relation , since in the opposite case, l ∈ [{}] holds and this implies P ol3 ∪ {c1 } ⊆ P ol 3 l , which by means of Theorem 14.1.8 0 1 2 1 2 [P ol3 ∪ {c1 }] = P ol3 ⊆ P ol3 l results from, which contra0 1 2 2 1 0 1 2 1 2 dicts c2 ∈ P ol3 l and c2 ∈ P ol3 . 0 1 2 2 1 It results now from the definition of the relation l that ϕ is an injective mapping. W.l.o.g. we can assume that ϕ(x) = x for all x ∈ l. Therefore (14.11) agrees with (14.6) and, with the help of Lemma 14.10.7, we have a contradiction to our assumption. (c) follows directly from (a) and (b). Proof of Theorem 14.10.1: The statements for the classes with the numbers 7, 17, or 30 of Table 14.1 are consequences from Chapter 13 (see also Theorem 15.1.1). For the classes with the number 28, 29, or 43, our assertion follows from Theorem 8.1.6 and Sections 15.3 and 15.4. 0 1 2 Since the class of Theorem 8.2.2 is a subclass of A8 = P ol3 {0}∩P ol3 1 2 0 we have |L↓ (A8 )| = c. The clones A ∈ Fj with j ∈ J := {9, 14, 24, 25, 27, 33, 35, 37, 39, 40, 41, 42} obviously satisfy the condition ∃a, b ∈ E3 : a = b ∧ P3,{a,b} ⊆ Ai . Hence for every j ∈ J there exists a subclass of A with infinite basis such that the range of its functions is a 2-element set (see for instance Lemma 14.10.2). An example of a subclass of A ∈ F22 with infinite basis is given in the proof of Theorem 12.3.8. Let A ∈ F32 with a = 1, b = 2 and c = 0. We have shown in Lemma 14.10.8 that there are uncountable many co-clones containing Inv3 A. This means that |L3 (J3 , A32 )| = c (see Chapter 2).
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14 Submaximal Classes of P3
Finally, we use constructions given in Lemmas 14.10.2–14.10.6 to show that |L↓3 (A)| = c with A ∈ Fi for the remaining i. All results are presented in Table 14.11. Table 14.11 Let A ∈ Fi , where Considered cases Use the construci= for a, b, c, α, β, γ tion given in Lemma 14.10.j, where j = (w.l.o.g.)
1 2,4 3 5,19,20,21,23,26,31 6,13,16,36,38 10 11 11 11 12 12 15 18 34
a 0 0 2 0 0 0 0 0 0 0 0 0 2 0
b 2 1 0 1 1 2 1 2 1 1 2 1 0 1
c α 1 2 1 2 2 1 0 0 2 2 0 1 1 2 0 1 2
β γ
1 1 1 1 0 1
2 2 0 2 2 2
4 4 4 2 3 2 3 8 3 2 2 3 5 5
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
We say that the class A ∈ Lk (or the lattice L↓k (A) of subclasses of A = [A] ⊆ Pk ) has the depth t, if t is the least integer for which there are some classes A1 , ..., At−1 ∈ Lk with A ⊂ A1 ⊂ A2 ⊂ ... ⊂ At−1 ⊂ Pk . In particular, it holds that the maximal classes of Pk have the depth 1 and the submaximal classes of Pk have the depth 2. For k = 3 by Theorems 13.2.3 and 8.1.6, there are finite and countably infinite sublattices of depth 1 or 2. In this chapter, these sublattices will be determined. The finite lattice L↓3 (L3 ) of depth 1 can be found in Section 15.1. This lattice is a conclusion from Chapter 13. In addition, by Section 14.10, this lattice is the only finite lattice of depth 1, and furthermore, this lattice contains all finite sublattices of L3 of depth 2. In Section 15.2 is a description of all subsemigroups (or subclasses) of (Ps1 ; ) (or [P31 ]), respectively. These subclasses are also subclasses of the submaximal class L of all quasilinear functions of P3 . The list of all subsemigroups of (Ps1 ; ) is then an important aid in Section 15.3 during the determination of the remaining elements of lattice L↓3 (L). Because of Theorem 8.1.6, a further countable sublattice of depth 2 is L↓3 ([O1 ∪ {max}]). This sublattice is given in Section 15.4. Except for isomorphic lattices, all countable sublattices of L3 of depth 2 are traced with that (see Section 14.10).
15.1 The Lattice of Subclasses of P3 of Linear Functions Let L3 be the set of all linear functions of P3 . As a consequence of Theorem 13.2.1, one can see that L↓3 (L3 ) has exactly 6 elements, which are not subsets of [L13 ]. The subclasses of [L13 ] is obtained from Theorem 13.2.2 or from Section 15.2. Thus it holds:
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Theorem 15.1.1 The class L3 of all linear functions of P3 has exactly 38 subclasses: 012 0 , L3 ∩ , [Hi ], L3 , L3 ∩ P ol3 {a}(a ∈ E3 ), L3 ∩ 120 1 where i ∈ {1, 2, 3, 4, 5, 6, 7, 8, 601, 602, 603, 604, 605, 606, 607, 608, 1201, 1202, 1203, 1204, 1232, 1233, 1234, 1235, 1263, 1264, 1265, 1266, 1294, 1295, 1297, 1298} (see Table 15.10 of Section 15.2).
15.2 The Subsemigroups of (P31 ; ) In this section, we determine the subclasses of [P31 ]. It suffices to describe all subsemigroups of (P31 ; ) for this. Since the subsemigroups of (P31 ; ) play a role in many investigations of P3 , it is particularly a question of clarifying the construction of these subsemigroups. To facilitate checking the following considerations without a lot of expenditure also by hand, some tables are given at the end of this section. The functions of P31 and their notations are given in Table 15.1. As usual the operation is defined by (f g)(x) := f (g(x)) P31
(see Table 15.2). for all f, g ∈ The number statement of the following theorem was published by G. Wilde and Sh. Raney in 1972 without proof (as a result of a computer calculation). Theorem 15.2.1 ([Wil-R 72], [Lau 84a]) (P31 ; ∗) has exactly 1299 subsemigroups (including ∅), which are listed in Table 15.10. Proof.1 In preparation for the proof of the above theorem, some notations, which we use during the description of the subsemigroups of (P31 , ∗), are given. Let C := {c0 , c1 , c2 }, J := {c0 , c1 , j0 , j1 , j2 , j3 , j4 , j5 }, U := {c0 , c2 , u0 , u1 , u2 , u3 , u4 , u5 }, V := {c1 , c2 , v0 , v1 , v2 , v3 , v4 , v5 }, S := {s1 , s2 , s3 , s4 , s5 , s6 }. Starting from the possible subsemigroups Ji (i ∈ {−3, −2, −1, 0, 1, 2, ..., 41}) of J (= J41 ), given in Table 15.4, one can construct, with the aid of the following mappings, 1
Basically, the following proof comes from [Lau 84a], which required correction in some places. I owe K. Todorov (Sofia) and Anne Fearnley (Montreal) indications of the mistakes.
15.2 The Subsemigroups of (P31 ; )
435
ϕi : f → s−1 i ∗ f ∗ si (i ∈ {2, 3, ..., 6}) and the notation 1 ϕi (A) := { s−1 i ∗ f ∗ si | f ∈ A } (A ⊆ P3 )
the classes isomorphic to Ji . These isomorphic classes are given in Tables 15.5–15.9, where we use the notations Ui := ϕ2 (Ji ) and Vi := ϕ6 (Ji ) (i ∈ {−3, −2, −1, 0, 1, 2, ..., 41}). Furthermore we use the notations: S0 := ∅, S1 := {s1 }, S2 := {s1 , s3 }, S3 := {s1 , s2 }, S4 := {s1 , s6 }, S5 := {s1 , s4 , s5 }, S6 := S. To make the structure of the subsemigroups recognizable short, we assign a tuple τ (H) as follows to every subsemigroup H: τ (H) := (a, b, c, d) :⇐⇒ H ∩ J = Ja ∧ H ∩ U = Ub ∧ H ∩ V = Vc ∧ H ∩ S = Sd . Obviously, it holds H = H ⇐⇒ τ (H) = τ (H ). H always denotes an arbitrary subsemigroup of (P31 ; ∗). The number of possibilities for H in one of the below cases i for H is denoted with ni . In Cases 4.1 and 4.2 some possibilities are already included in other cases for H, so that we must change the number ni into the number ni , i.e., ni denotes the number of possibilities for H in Case i, which were not included in the preceded cases. In most of the following cases i for H, the numbers ni or/and ni and the possibilities for H are given. To check the following proof is an arduous matter that should be carried out only with the aid of a computer. A summary of all possibilities for H together with the corresponding characteristic tuples τ (H) can be found in Table 15.10. Case 1: H ⊆ C. Obviously, n1 = 8 and H = Hi (i = 1, ..., 8; see Table 15.10) is an arbitrary subset of C. Case 2: H ⊆ C and H ⊆ A ∈ {J, U, V }. Case 2.1: H ⊆ J. It is not hard to check that n2.1 = 41 and H ∈ {J1 , J2 , ..., J41 } (or H = Ht , t ∈ {9, 10, ..., 49}, see Table 15.10).
436
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Case 2.2: H ⊆ U . By ϕ2 (J) = U and by Case 2.1, we have n2.2 = 41, and H is one of the following sets: Ui := ϕ2 (Ji ) with i ∈ {1, 2, ..., 41} (or H = Ht for t ∈ {50, 51, ..., 90}). Case 2.3: H ⊆ V . By ϕ6 (J) = V and by Case 2.1, we have n2.3 = 41, and for H only, the following sets are possible: Vi := ϕ6 (Ji ) with i ∈ {1, 2, ..., 41} (or H = Hi , i ∈ {91, 92, ..., 131}). Case 3: H ⊆ J ∪ U , H ⊆ J and H ⊆ U . Case 3.1: H ⊆ C ∪ {j1 , j4 , u2 , u3 } = J25 ∪ U25 . The possibilities for H are: J3 ∪ {c0 , c2 }, {c0 , c1 } ∪ U3 , J12 ∪ {c0 , c2 }, {c0 , c1 } ∪ U12 , J25 ∪ {c0 , c2 }, {c0 , c1 } ∪ U25 and Jp ∪ Uq , where (p, q) ∈ {(3, 3), (3, 12), (12, 3), (12, 12), (3, 25), (25, 3), (12, 25), (25, 12), (25, 25)} (or H = Hi with i ∈ {132, 133, ..., 146}); i.e., we have n3.1 = 15. Case 3.2: H ∩ J ⊆ {c0 , c1 , j1 , j4 } and H ∩ U ⊆ {c0 , c2 , u2 , u3 }. For H ∩ U only the following sets are possible: {c2 }, {c0 , c2 }, {c0 , u2 } = U3 , {c0 , c2 , u2 } = U12 and {c0 , c2 , u2 , u3 } = U25 . Case 3.2.1: H ∩ U = {c2 }. Obviously, H = J8 ∪ {c2 } ( = H147 ). Case 3.2.2: H ∩ U = {c0 , c2 }. In this case, H ∩ J is an arbitrary subsemigroup of J, which contains {c0 , c1 }, but no subset is of J25 , i.e., it holds n3.2.2 = 19 and H = {c0 , c2 } ∪ Ji with i ∈ {13, 14, 15, 22, 23, 24, 26, 27, 28, 29, 33, 34, 35, 36, 37, 38, 39, 40, 41} (or H = Ht with t ∈ {148, 149, ..., 166}). Case 3.2.3: H ∩ U = U3 . In this case, we have n3.2.3 = 17 and H = U3 ∪ Ji with i ∈ {4, 13, 14, 16, 18, 23, 24, 27, 28, 30, 33, 34, 36, 38, 39, 40, 41} (or H = Ht with t ∈ {167, 168, ..., 183}). Case 3.2.4: H ∩ U = U12 . It is easy to check that n3.2.4 = 13 and H = U12 ∪ Ji with i ∈ {13, 14, 23, 24, 27, 28, 33, 34, 36, 38, 39, 40, 41} (or H = Ht with t ∈ {184, 185, ..., 196}). Case 3.2.5: H ∩ U = U25 . In this case, H ∩ J is an arbitrary subsemigroup of J, which contains {j2 , j3 }. Thus, we have n3.2.5 = 7 and H = U25 ∪ Ji with i ∈ {27, 33, 36, 38, 39, 40, 41} (or H = Ht with t ∈ {197, 198, ..., 203}). In summary, we get: n3.2 = 57. Case 3.3: H ∩ J ⊆ {c0 , c1 , j1 , j4 } and H ∩ U ⊆ {c0 , c1 , u2 , u3 }. In this case, H is isomorphic to a subsemigroup of J ∪ U which fulfills the conditions of Case 3.2. Consequently, we have n3.3 = 57 and H = ϕ2 (Hi ) with i ∈ {147, 148, ..., 203} (or H = Ht with t ∈ {204, 205, ..., 260}). We remark that ϕ2 (Ja ∪ Ub ) = Jb ∪ Ua . Case 3.4: H ∩ J ⊆ {c0 , c1 , j1 , j4 } and H ∩ U ⊆ {c0 , c1 , u2 , u3 }. Then there are two functions f and g of H with 0 02 0 01 f ∈ and g ∈ . 1 20 2 10
15.2 The Subsemigroups of (P31 ; )
437
This implies |H ∩ J| = |H ∩ U | and, if (H\C) ∩ J = {ji | i ∈ I} with I ⊆ {0, 1, ..., 5}, (H\C)∩U ∈ {{ui | i ∈ I}, {u5−i | i ∈ I}}. Examining the possible cases yields n3.4 = 19 and H = Jp ∪ Uq with (p, q) ∈ {(2, 2), (5, 5), (8, 8), (9, 9), (15, 15), (16, 16), (17, 18, (18, 17), (22, 22), (23, 23), (24, 24), (26, 28), (28, 26), (30, 30), (34, 34), (37, 38), (38, 37), (39, 39), (41, 41)} . Summing up, we get n3 = 148. Case 4: H ⊆ A ∪ B ∈ {J ∪ V, U ∪ V }, H ⊆ A and H ⊆ B. Case 4.1: A = J and B = V . By ϕ3 (J ∪ U ) = J ∪ V we have n4.1 = 148, and H is isomorphic to a subsemigroup which we have already determined in Case 3. Hence, one receives a list of the subsemigroups with the aid of the results from the third case, where one has to consider ϕ3 (Ja ∪ Ub ) = ϕ3 (Ja ) ∪ ϕ5 (Jb ) (see Table 15.7 and 15.9). Twenty-three of the 148 subsemigroups were already determined, so that we have n4.1 = 125. 2 In Table 15.10 (for the Case 4.1), 148 sets are given, where every already listed set, is characterized by their first number; this first number is given in bold point. Case 4.2: A = U and B = V . By ϕ4 (J ∪ U ) = U ∪ V , we have n4.2 = 148 and H is isomorphic to a subsemigroup that we have already determined in Case 3. While listing the subsemigroups, one notices that ϕ4 (Ja ∪ Ub ) = ϕ4 (Ja ) ∪ Vb holds. With the aid of Table 15.10 one sees that 48 of the subsemigroups were determined in previous cases. Thus n4.2 = 102. Case 5: H ⊆ J ∪ U ∪ V , H ⊆ J ∪ U , H ⊆ J ∪ V and H ⊆ U ∪ V . Case 5.1: H ∩ (U ∪ V ) ⊆ C ∪ {u2 , u3 , v2 , v3 }. For H ∩ (U ∪ V ), only the sets U3 ∪ V8 = {c0 , c1 , u2 , v2 }, U12 ∪ V15 = {c0 , c1 , c2 , u2 , v2 } and U25 ∪ V22 = {c0 , c1 , c2 , u2 , u3 , v2 , v3 } come into consideration. Case 5.1.1: H ∩ (U ∪ V ) = U3 ∪ V8 . Then, all the subsets Ji of J which contain the two functions c0 , c1 and which have the properties j0 ∈ Ji ∨ j4 ∈ Ji =⇒ {j2 , j3 } ⊆ Ji , j1 ∈ Ji =⇒ j3 ∈ Ji , j5 ∈ Ji =⇒ j2 ∈ Ji . are possible for H ∩ J. Thus n5.1.1 = 11 and H = Ji ∪ U3 ∪ V8 with i ∈ {13, 14, 24, 27, 28, 33, 36, 38, 39, 40, 41}. Case 5.1.2: H ∩ (U ∪ V ) = U12 ∪ V15 . With the aid of Case 5.1.1, we obtain n5.1.2 = 11 and H = Ji ∪ U12 ∪ V15 , i ∈ {13, 14, 24, 27, 28, 33, 36, 38, 39, 40, 41}. Case 5.1.3: H ∩ (U ∪ V ) = U25 ∪ V22 . Then H ∩ J is a subsemigroup of J, which contains j2 and j3 . Consequently, n5.1.3 = 7 and H = Ji ∪ U25 ∪ V22 , i ∈ {27, 33, 36, 38, 39, 40, 41}. In summary, we obtain n5.1 = 29. 2
This was not taken into account in [Lau 84a]!
438
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Case 5.2: H ∩ (J ∪ V ) ⊆ C ∪ {j1 , j4 , v1 , v4 }. Because of ϕ2 (C ∪ {j1 , j4 , v1 , v4 }) = U25 ∪ V22 , we have n5.2 = 29 and H = ϕ2 (A), where A is a set which we have already determined in Case 5.1. More exactly: If A = Ja ∪ Ub ∪ Vc then ϕ2 (A) = Jb ∪ Ua ∪ ϕ5 (Jc ). Case 5.3: H ∩ (J ∪ U ) ⊆ C ∪ {j0 , j5 , u0 , u5 }. This case is also isomorphic to Case 5.1. One can obtain all 29 possibilities for H with the aid of the mapping ϕ6 from the sets determined in Case 5.1, where ϕ6 (Ja ∪ Ub ∪ Vc ) = Jc ∪ ϕ4 (Jb ) ∪ Va must be pointed out. Case 5.4: H fulfills none of the conditions from Cases 5.1, 5.2, or 5.3. In this case, there are functions f, g, h ∈ H with 0 0212 0 0112 1 0102 f ∈ ,g ∈ and h ∈ . 1 2021 2 1021 2 1020 Since certain functions ja , ub , vc for certain a, b, c belong to H, one easily checks that C ⊂ H and, if (H\C) ∩ J = {ji | i ∈ I}, it holds (H\C) ∩ U ∈ {{ui | i ∈ I}, {u5−i | i ∈ I}} and (H\C) ∩ V ∈ {{vi | i ∈ I}, {v5−i | i ∈ I}}. Examining the possible cases using the results of Case 2 yields n5.4 = 7 and H = Jp ∪ Uq ∪ Vr with (p, q, r) ∈ {(24, 24, 26), (26, 28, 24), (28, 26, 28), (37, 38, 39), (38, 37, 38), (39, 39, 37), (41, 41, 41)}. Consequently, n5 = 94. Case 6: S ∩ H = ∅. Since S as is well-known has 6 subgroups, the following cases are possible: Case 6.1: S ∩ H = {s1 }. Then we have H = A ∪ {s1 }, where A is one of the 600 subsemigroups of J ∪ U ∪ V determined above. Case 6.2: S ∩ H = {s1 , s3 }. In this case, H\S is one of the following 31 sets: ∅, {c2 }, {c0 , c1 }, C, J27 , J32 , J37 , J, J27 ∪ {c2 }, J37 ∪ {c2 }, C ∪ J, U1 ∪ V2 , U3 ∪ V8 , U6 ∪ V5 , U12 ∪ V15 , U10 ∪ V9 , U25 ∪ V22 , U21 ∪ V16 , U29 ∪ V23 , U31 ∪ V30 , U35 ∪ V34 , U38 ∪ V39 , U ∪ V , J27 ∪ U3 ∪ V8 , J27 ∪ U12 ∪ V15 , J27 ∪ U25 ∪ V22 , J37 ∪ U38 ∪ V39 , J ∪ U12 ∪ V15 , J ∪ U3 ∪ V8 , J ∪ U25 ∪ V22 , J ∪ U ∪ V . Case 6.3: S ∩ H = {s1 , s2 }. In this case, n6.3 = 31 and the possibilities for H be determined with the results from Case 6.2 and with the mapping ϕ6 . Case 6.4: S ∩ H = {s1 , s6 }. In this case, n6.4 = 31 and one can determine the possibilities for H, using Case 6.2 and the mapping ϕ2 . Case 6.5: S ∩ H ∈ {{s1 , s4 , s5 }, S}. For H\S only the sets ∅, C and J ∪ U ∪ V are possible, whereby n6.5 = 6. Consequently, we have n6 = 699. In summary, we get that (P31 ; ∗) has exactly 1299 different subsemigroups. We remark that one finds further information about the given subsemigroups in [Bij-T 91].
15.2 The Subsemigroups of (P31 ; )
Table 15.1
439
x j0 (x) j1 (x) j2 (x) j3 (x) j4 (x) j5 (x) u0 (x) u1 (x) u2 (x) u3 (x) u4 (x) u5 (x) 0 1 0 0 1 1 0 2 0 0 2 2 0 1 0 1 0 1 0 1 0 2 0 2 0 2 2 0 0 1 0 1 1 0 0 2 0 2 2 x v0 (x) v1 (x) v2 (x) v3 (x) v4 (x) v5 (x) s1 (x) s2 (x) s3 (x) s4 (x) s5 (x) s6 (x) 0 2 1 1 2 2 1 0 0 1 1 2 2 1 1 2 1 2 1 2 1 2 0 2 0 1 2 1 1 2 1 2 2 2 1 2 0 1 0
f ∗g j0 j1 j2 j3 j4 j5 u0 u1 u2 u3 u4 u5 v0 v1 v2 v3 v4 v5 s2 s3 s4 s5 s6
ji j5−i ji c0 c1 j5−i ji u5−i ui c0 c2 u5−i ui v5−i vi c1 c2 v5−i vi ui j5−i vi u5−i v5−i
Table 15.2
ui j5−i c0 ji j5−i c1 ji u5−i c0 ui u5−i c2 ui v5−i c1 vi v5−i c2 vi ji vi j5−i v5−i u5−i
vi s2 s3 c0 j0 j1 j5−i j2 j0 ji j1 j2 j5−i j4 j3 ji j3 j5 c1 j5 j4 c0 u0 u1 u5−i u2 u0 ui u1 u2 u5−i u4 u3 ui u3 u5 c2 u5 u4 c1 v0 v1 v5−i v2 v0 vi v1 v2 v5−i v4 v3 vi v3 v5 c2 v5 v4 v5−i s1 s5 ui s4 s1 u5−i s3 s6 ji s6 s2 j5−i s5 s4
s4 j2 j0 j1 j4 j5 j3 u2 u0 u1 u4 u5 u3 v2 v0 v1 v4 v5 v3 s6 s2 s5 s1 s3
s5 j1 j2 j0 j5 j3 j4 u1 u2 u0 u5 u3 u4 v1 v2 v0 v5 v3 v4 s3 s6 s1 s4 s2
s6 j2 j1 j0 j5 j4 j3 u2 u1 u0 u5 u4 u3 v2 v1 v0 v5 v4 v3 s4 s5 s2 s3 s1
440
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 Table 15.3
ϕ2 (f ) = ϕ3 (f ) = ϕ5 (f ) = ϕ4 (f ) = ϕ6 (f ) = f s2 ∗ f ∗ s2 s3 ∗ f ∗ s3 s4 ∗ f ∗ s5 s5 ∗ f ∗ s4 s6 ∗ f ∗ s6 c0 c0 c1 c1 c2 c2 c1 c2 c0 c2 c0 c1 c2 c1 c2 c0 c1 c0 j0 u0 j4 v1 u3 v3 j1 u2 j5 v2 u5 v4 j2 u1 j3 v0 u4 v5 j3 u4 j2 v5 u1 v0 j4 u3 j0 v3 u0 v1 j5 u5 j1 v4 u2 v2 u0 j0 v1 j4 v3 u3 u1 j2 v0 j3 v5 u4 u2 j1 v2 j5 v4 u5 u3 j4 v3 j0 v1 u0 u4 j3 v5 j2 v0 u1 u5 j5 v4 j1 v2 u2 v0 v5 u1 u4 j2 j3 v1 v3 u0 u3 j0 j4 v2 v4 u2 u5 j1 j5 v3 v1 u3 u0 j4 j0 v4 v2 u5 u2 j5 j1 v5 v0 u4 u1 j3 j2 s1 s1 s1 s1 s1 s1 s2 s2 s6 s6 s3 s3 s3 s6 s3 s2 s6 s2 s4 s5 s5 s4 s4 s5 s5 s4 s4 s5 s5 s4 s6 s3 s2 s3 s2 s6
15.2 The Subsemigroups of (P31 ; ) Table 15.4 i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
Ji {c0 , c1 } {c1 } {c0 } ∅ {j1 } {j5 } {c0 , j1 } {c0 , j2 } {c0 , j5 } {c1 , j1 } {c1 , j3 } {c1 , j5 } {j0 , j5 } {j1 , j4 } {j1 , j5 } {c0 , c1 , j1 } {c0 , c1 , j2 } {c0 , c1 , j3 } {c0 , c1 , j5 } {c0 , j1 , j2 } {c0 , j1 , j5 } {c0 , j2 , j5 } {c1 , j1 , j3 } {c1 , j1 , j5 } {c1 , j3 , j5 } {c0 , c1 , j0 , j5 } {c0 , c1 , j1 , j2 } {c0 , c1 , j1 , j3 } {c0 , c1 , j1 , j4 } {c0 , c1 , j1 , j5 } {c0 , c1 , j2 , j3 } {c0 , c1 , j2 , j5 } {c0 , c1 , j3 , j5 } {c0 , j1 , j2 , j5 } {c1 , j1 , j3 , j5 } {j0 , j1 , j4 , j5 } {c0 , c1 , j1 , j2 , j3 } {c0 , c1 , j1 , j2 , j5 } {c0 , c1 , j1 , j3 , j5 } {c0 , c1 , j2 , j3 , j5 } {c0 , c1 , j0 , j1 , j4 , j5 } {c0 , c1 , j0 , j2 , j3 , j5 } {c0 , c1 , j1 , j2 , j3 , j4 } {c0 , c1 , j1 , j2 , j3 , j5 } {c0 , c1 , j0 , j1 , j2 , j3 , j4 , j5 }
Table 15.5 i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
Ui := ϕ2 (Ji ) {c0 , c2 } {c2 } {c0 } ∅ {u2 } {u5 } {c0 , u2 } {c0 , u1 } {c0 , u5 } {c2 , u2 } {c2 , u4 } {c2 , u5 } {u0 , u5 } {u2 , u3 } {u2 , u5 } {c0 , c2 , u2 } {c0 , c2 , u1 } {c0 , c2 , u4 } {c0 , c2 , u5 } {c0 , u2 , u1 } {c0 , u2 , u5 } {c0 , u1 , u5 } {c2 , u2 , u4 } {c2 , u2 , u5 } {c2 , u4 , u5 } {c0 , c2 , u0 , u5 } {c0 , c2 , u2 , u1 } {c0 , c2 , u2 , u4 } {c0 , c2 , u2 , u3 } {c0 , c2 , u2 , u5 } {c0 , c2 , u1 , u4 } {c0 , c2 , u1 , u5 } {c0 , c2 , u4 , u5 } {c0 , u2 , u1 , u5 } {c2 , u2 , u4 , u5 } {u0 , u2 , u3 , u5 } {c0 , c2 , u2 , u1 , u4 } {c0 , c2 , u2 , u1 , u5 } {c0 , c2 , u2 , u4 , u5 } {c0 , c2 , u1 , u4 , u5 } {c0 , c2 , u0 , u2 , u3 , u5 } {c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c2 , u2 , u1 , u4 , u3 } {c0 , c2 , u2 , u1 , u4 , u5 } {c0 , c2 , u0 , u2 , u1 , u4 , u3 , u5 }
441
442
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 Table 15.6 i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
Vi := ϕ6 (Ji ) {c2 , c1 } {c1 } {c2 } ∅ {v4 } {v2 } {c2 , v4 } {c2 , v5 } {c2 , v2 } {c1 , v4 } {c1 , v0 } {c1 , v2 } {v3 , v2 } {v4 , v1 } {v4 , v2 } {c2 , c1 , v4 } {c2 , c1 , v5 } {c2 , c1 , v0 } {c2 , c1 , v2 } {c2 , v4 , v5 } {c2 , v4 , v2 } {c2 , v5 , v2 } {c1 , v4 , v0 } {c1 , v4 , v2 } {c1 , v0 , v2 } {c2 , c1 , v3 , v2 } {c2 , c1 , v4 , v5 } {c2 , c1 , v4 , v0 } {c2 , c1 , v4 , v1 } {c2 , c1 , v4 , v2 } {c2 , c1 , v5 , v0 } {c2 , c1 , v5 , v2 } {c2 , c1 , v0 , v2 } {c2 , v4 , v5 , v2 } {c1 , v4 , v0 , v2 } {v3 , v4 , v1 , v2 } {c2 , c1 , v4 , v5 , v0 } {c2 , c1 , v4 , v5 , v2 } {c2 , c1 , v4 , v0 , v2 } {c2 , c1 , v5 , v0 , v2 } {c2 , c1 , v3 , v4 , v1 , v2 } {c2 , c1 , v3 , v5 , v0 , v2 } {c2 , c1 , v4 , v5 , v0 , v1 } {c2 , c1 , v4 , v5 , v0 , v2 } {c2 , c1 , v3 , v4 , v5 , v0 , v1 , v2 }
Table 15.7 i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
ϕ3 (Ji ) = Jt {c1 , c0 } {c0 } {c1 } ∅ {j5 } {j1 } {c1 , j5 } {c1 , j3 } {c1 , j1 } {c0 , j5 } {c0 , j2 } {c0 , j1 } {j4 , j1 } {j5 , j0 } {j5 , j1 } {c1 , c0 , j5 } {c1 , c0 , j3 } {c1 , c0 , j2 } {c1 , c0 , j1 } {c1 , j5 , j3 } {c1 , j5 , j1 } {c1 , j3 , j1 } {c0 , j5 , j2 } {c0 , j5 , j1 } {c0 , j2 , j1 } {c1 , c0 , j4 , j1 } {c1 , c0 , j5 , j3 } {c1 , c0 , j5 , j2 } {c1 , c0 , j5 , j0 } {c1 , c0 , j5 , j1 } {c1 , c0 , j3 , j2 } {c1 , c0 , j3 , j1 } {c1 , c0 , j2 , j1 } {c1 , j5 , j3 , j1 } {c0 , j5 , j2 , j1 } {j4 , j5 , j0 , j1 } {c1 , c0 , j5 , j3 , j2 } {c1 , c0 , j5 , j3 , j1 } {c1 , c0 , j5 , j2 , j1 } {c1 , c0 , j3 , j2 , j1 } {c1 , c0 , j4 , j5 , j0 , j1 } {c1 , c0 , j4 , j3 , j2 , j1 } {c1 , c0 , j5 , j3 , j2 , j0 } {c1 , c0 , j5 , j3 , j2 , j1 } {c1 , c0 , j4 , j5 , j3 , j2 , j0 , j1 }
t −3 −1 −2 0 2 1 8 7 6 5 4 3 10 9 11 15 14 13 12 21 20 19 18 17 16 25 29 28 22 26 27 24 23 31 30 32 36 35 34 33 37 39 38 40 41
15.2 The Subsemigroups of (P31 ; ) Table 15.8 i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
ϕ4 (Ji ) = Ut {c2 , c0 } {c0 } {c2 } ∅ {u5 } {u2 } {c2 , u5 } {c2 , u4 } {c2 , u2 } {c0 , u5 } {c0 , u1 } {c0 , u2 } {u3 , u2 } {u5 , u0 } {u5 , u2 } {c2 , c0 , u5 } {c2 , c0 , u4 } {c2 , c0 , u1 } {c2 , c0 , u2 } {c2 , u5 , u4 } {c2 , u5 , u2 } {c2 , u4 , u2 } {c0 , u5 , u1 } {c0 , u5 , u2 } {c0 , u1 , u2 } {c2 , c0 , u3 , u2 } {c2 , c0 , u5 , u4 } {c2 , c0 , u5 , u1 } {c2 , c0 , u5 , u0 } {c2 , c0 , u5 , u2 } {c2 , c0 , u4 , u1 } {c2 , c0 , u4 , u2 } {c2 , c0 , u1 , u2 } {c2 , u5 , u4 , u2 } {c0 , u5 , u1 , u2 } {u3 , u5 , u0 , u2 } {c2 , c0 , u5 , u4 , u1 } {c2 , c0 , u5 , u4 , u2 } {c2 , c0 , u5 , u1 , u2 } {c2 , c0 , u4 , u1 , u2 } {c2 , c0 , u3 , u5 , u0 , u2 } {c2 , c0 , u3 , u4 , u1 , u2 } {c2 , c0 , u5 , u4 , u1 , u0 } {c2 , c0 , u5 , u4 , u1 , u2 } {c2 , c0 , u3 , u5 , u4 , u1 , u0 , u2 }
Table 15.9 t −3 −1 −2 0 2 1 8 7 6 5 4 3 10 9 11 15 14 13 12 21 20 19 18 17 16 25 29 28 22 26 27 24 23 31 30 32 36 35 34 33 37 39 38 40 41
i −3 −2 −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41
ϕ5 (Ji ) = Vt {c1 , c2 } {c2 } {c1 } ∅ {v2 } {v4 } {c1 , v2 } {c1 , v0 } {c1 , v4 } {c2 , v2 } {c2 , v5 } {c2 , v4 } {v1 , v4 } {v2 , v3 } {v2 , v4 } {c1 , c2 , v2 } {c1 , c2 , v0 } {c1 , c2 , v5 } {c1 , c2 , v4 } {c1 , v2 , v0 } {c1 , v2 , v4 } {c1 , v0 , v4 } {c2 , v2 , v5 } {c2 , v2 , v4 } {c2 , v5 , v4 } {c1 , c2 , v1 , v4 } {c1 , c2 , v2 , v0 } {c1 , c2 , v2 , v5 } {c1 , c2 , v2 , v3 } {c1 , c2 , v2 , v4 } {c1 , c2 , v0 , v5 } {c1 , c2 , v0 , v4 } {c1 , c2 , v5 , v4 } {c1 , v2 , v0 , v4 } {c2 , v2 , v5 , v4 } {v1 , v2 , v3 , v4 } {c1 , c2 , v2 , v0 , v5 } {c1 , c2 , v2 , v0 , v4 } {c1 , c2 , v2 , v5 , v4 } {c1 , c2 , v0 , v5 , v4 } {c1 , c2 , v1 , v2 , v3 , v4 } {c1 , c2 , v1 , v0 , v5 , v4 } {c1 , c2 , v2 , v0 , v5 , v3 } {c1 , c2 , v2 , v0 , v5 , v4 } {c1 , c2 , v1 , v2 , v0 , v5 , v3 , v4 }
t −3 −1 −2 0 2 1 8 7 6 5 4 3 10 9 11 15 14 13 12 21 20 19 18 17 16 25 29 28 22 26 27 24 23 31 30 32 36 35 34 33 37 39 38 40 41
443
444
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 Table 15.103 i 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
3
τ (Hi ) (0, 0, 0, 0) (−1, −1, 0, 0) (−1, 0, −1, 0) (0, −2, −2, 0) (−3, −1, −1, 0) (−1, −3, −2, 0) (−2, −2, −3, 0) (−3, −3, −3, 0) (1, 0, 0, 0) (2, 0, 0, 0) (3, −1, 0, 0) (4, −1, 0, 0) (5, −1, 0, 0) (6, 0, −2, 0) (7, 0, −2, 0) (8, 0, −2, 0) (9, 0, 0, 0) (10, 0, 0, 0) (11, 0, 0, 0) (12, −1, −2, 0) (13, −1, −2, 0) (14, −1, −2, 0) (15, −1, −2, 0) (16, −1, −2, 0) (17, −1, −2, 0) (18, −1, 0, 0) (19, 0, −2, 0) (20, 0, −2, 0) (21, 0, −2, 0) (22, −1, −2, 0) (23, −1, −2, 0) (24, −1, −2, 0) (25, −1, −2, 0) (26, −1, −2, 0) (27, −1, −2, 0) (28, −1, −2, 0) (29, −1, −2, 0) (30, −1, −2, 0) (31, 0, −2, 0) (32, 0, 0, 0) (33, −1, −2, 0) (34, −1, −2, 0) (35, −1, −2, 0) (36, −1, −2, 0) (37, −1, −2, 0) (38, −1, −2, 0) (39, −1, −2, 0) (40, −1, −2, 0) (41, −1, −2, 0) (0, 1, 0, 0) (0, 2, 0, 0) (−1, 3, 0, 0) (−1, 4, 0, 0) (−1, 5, 0, 0) (0, 6, −1, 0) (0, 7, −1, 0) (0, 8, −1, 0) (0, 9, 0, 0) (0, 10, 0, 0) (0, 11, 0, 0)
Hi ∅ {c0 } {c1 } {c2 } {c0 , c1 } {c0 , c2 } {c1 , c2 } {c0 , c1 , c2 } {j1 } {j5 } {c0 , j1 } {c0 , j2 } {c0 , j5 } {c1 , j1 } {c1 , j3 } {c1 , j5 } {j0 , j5 } {j1 , j4 } {j1 , j5 } {c0 , c1 , j1 } {c0 , c1 , j2 } {c0 , c1 , j3 } {c0 , c1 , j5 } {c0 , j1 , j2 } {c0 , j1 , j5 } {c0 , j2 , j5 } {c1 , j1 , j3 } {c1 , j1 , j5 } {c1 , j3 , j5 } {c0 , c1 , j0 , j5 } {c0 , c1 , j1 , j2 } {c0 , c1 , j1 , j3 } {c0 , c1 , j1 , j4 } {c0 , c1 , j1 , j5 } {c0 , c1 , j2 , j3 } {c0 , c1 , j2 , j5 } {c0 , c1 , j3 , j5 } {c0 , j1 , j2 , j5 } {c1 , j1 , j3 , j5 } {j0 , j1 , j4 , j5 } {c0 , c1 , j1 , j2 , j3 } {c0 , c1 , j1 , j2 , j5 } {c0 , c1 , j1 , j3 , j5 } {c0 , c1 , j2 , j3 , j5 } {c0 , c1 , j0 , j1 , j4 , j5 } {c0 , c1 , j0 , j2 , j3 , j5 } {c0 , c1 , j1 , j2 , j3 , j4 } {c0 , c1 , j1 , j2 , j3 , j5 } {c0 , c1 , j0 , j1 , j2 , j3 , j4 , j5 } {u2 } {u5 } {c0 , u2 } {c0 , u1 } {c0 , u5 } {c2 , u2 } {c2 , u4 } {c2 , u5 } {u0 , u5 } {u2 , u3 } {u2 , u5 }
Case 1
2.1
2.2
If the sets Hi are unions of certain sets, repeated constants are not removed in the descriptions of the sets to make the construction of the sets Hi recognizable.
15.2 The Subsemigroups of (P31 ; ) i 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125
τ (Hi ) (−1, 12, −1, 0) (−1, 13, −1, 0) (−1, 14, −1, 0) (−1, 15, −1, 0) (−1, 16, −1, 0) (−1, 17, −1, 0) (−1, 18, 0, 0) (0, 19, −1, 0) (0, 20, −1, 0) (0, 21, −1, 0) (−1, 22, −1, 0) (−1, 23, −1, 0) (−1, 24, −1, 0) (−1, 25, −1, 0) (−1, 26, −1, 0) (−1, 27, −1, 0) (−1, 28, −1, 0) (−1, 29, −1, 0) (−1, 30, −1, 0) (0, 31, −1, 0) (0, 32, 0, 0) (−1, 33, −1, 0) (−1, 34, −1, 0) (−1, 35, −1, 0) (−1, 36, −1, 0) (−1, 37, −1, 0) (−1, 38, −1, 0) (−1, 39, −1, 0) (−1, 40, −1, 0) (−1, 41, −1, 0) (0, 0, 1, 0) (0, 0, 2, 0) (0, −2, 3, 0) (0, −2, 4, 0) (0, −2, 5, 0) (−2, 0, 6, 0) (−2, 0, 7, 0) (−2, 0, 8, 0) (0, 0, 9, 0) (0, 0, 10, 0) (0, 0, 11, 0) (−2, −2, 12, 0) (−2, −2, 13, 0) (−2, −2, 14, 0) (−2, −2, 15, 0) (0, −2, 16, 0) (0, −2, 17, 0) (0, −2, 18, 0) (−2, 0, 19, 0) (−2, 0, 20, 0) (−2, 0, 21, 0) (−2, −2, 22, 0) (−2, −2, 23, 0) (−2, −2, 24, 0) (−2, −2, 25, 0) (−2, −2, 26, 0) (−2, −2, 27, 0) (−2, −2, 28, 0) (−2, −2, 29, 0) (0, −2, 30, 0) (−2, 0, 31, 0) (0, 0, 32, 0) (−2, −2, 33, 0) (−2, −2, 34, 0) (−2, −2, 35, 0)
Hi {c0 , c2 , u2 } {c0 , c2 , u1 } {c0 , c2 , u4 } {c0 , c2 , u5 } {c0 , u2 , u1 } {c0 , u2 , u5 } {c0 , u1 , u5 } {c2 , u2 , u4 } {c2 , u2 , u5 } {c2 , u4 , u5 } {c0 , c2 , u0 , u5 } {c0 , c2 , u2 , u1 } {c0 , c2 , u2 , u4 } {c0 , c2 , u2 , u3 } {c0 , c2 , u2 , u5 } {c0 , c2 , u1 , u4 } {c0 , c2 , u1 , u5 } {c0 , c2 , u4 , u5 } {c0 , u2 , u1 , u5 } {c2 , u2 , u4 , u5 } {u0 , u2 , u3 , u5 } {c0 , c2 , u2 , u1 , u4 } {c0 , c2 , u2 , u1 , u5 } {c0 , c2 , u2 , u4 , u5 } {c0 , c2 , u1 , u4 , u5 } {c0 , c2 , u0 , u2 , u3 , u5 } {c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c2 , u2 , u1 , u4 , u3 } {c0 , c2 , u2 , u1 , u4 , u5 } {c0 , c2 , u0 , u2 , u1 , u4 , u3 , u5 } {v4 } {v2 } {c2 , v4 } {c2 , v5 } {c2 , v2 } {c1 , v4 } {c1 , v0 } {c1 , v2 } {v3 , v2 } {v4 , v1 } {v4 , v2 } {c2 , c1 , v4 } {c2 , c1 , v5 } {c2 , c1 , v0 } {c2 , c1 , v2 } {c2 , v4 , v5 } {c2 , v4 , v2 } {c2 , v5 , v2 } {c1 , v4 , v0 } {c1 , v4 , v2 } {c1 , v0 , v2 } {c2 , c1 , v3 , v2 } {c2 , c1 , v4 , v5 } {c2 , c1 , v4 , v0 } {c2 , c1 , v4 , v1 } {c2 , c1 , v4 , v2 } {c2 , c1 , v5 , v0 } {c2 , c1 , v5 , v2 } {c2 , c1 , v0 , v2 } {c2 , v4 , v5 , v2 } {c1 , v4 , v0 , v2 } {v3 , v4 , v1 , v2 } {c2 , c1 , v4 , v5 , v0 } {c2 , c1 , v4 , v5 , v2 } {c2 , c1 , v4 , v0 , v2 }
445 Case
2.3
446
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 i 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190
τ (Hi ) (−2, −2, 36, 0) (−2, −2, 37, 0) (−2, −2, 38, 0) (−2, −2, 39, 0) (−2, −2, 40, 0) (−2, −2, 41, 0) (3, −3, −1, 0) (−3, 3, −2, 0) (12, −3, −3, 0) (−3, 12, −3, 0) (25, −3, −3, 0) (−3, 25, −3, 0) (3, 3, 0, 0) (3, 12, −1, 0) (12, 3, −2, 0) (12, 12, −3, 0) (3, 25, −1, 0) (25, 3, −2, 0) (12, 25, −3, 0) (25, 12, −3, 0) (25, 25, −3, 0) (8, −2, −3, 0) (13, −3, −3, 0) (14, −3, −3, 0) (15, −3, −3, 0) (22, −3, −3, 0) (23, −3, −3, 0) (24, −3, −3, 0) (26, −3, −3, 0) (27, −3, −3, 0) (28, −3, −3, 0) (29, −3, −3, 0) (33, −3, −3, 0) (34, −3, −3, 0) (35, −3, −3, 0) (36, −3, −3, 0) (37, −3, −3, 0) (38, −3, −3, 0) (39, −3, −3, 0) (40, −3, −3, 0) (41, −3, −3, 0) (4, 3, 0, 0) (13, 3, −2, 0) (14, 3, −2, 0) (16, 3, 0, 0) (18, 3, 0, 0) (23, 3, −2, 0) (24, 3, −2, 0) (27, 3, −2, 0) (28, 3, −2, 0) (30, 3, 0, 0) (33, 3, −2, 0) (34, 3, −2, 0) (36, 3, −2, 0) (38, 3, −2, 0) (39, 3, −2, 0) (40, 3, −2, 0) (41, 3, −2, 0) (13, 12, −3, 0) (14, 12, −3, 0) (23, 12, −3, 0) (24, 12, −3, 0) (27, 12, −3, 0) (28, 12, −3, 0) (33, 12, −3, 0)
Hi {c2 , c1 , v5 , v0 , v2 } {c2 , c1 , v3 , v4 , v1 , v2 } {c2 , c1 , v3 , v5 , v0 , v2 } {c2 , c1 , v4 , v5 , v0 , v1 } {c2 , c1 , v4 , v5 , v0 , v2 } {c2 , c1 , v3 , v4 , v5 , v0 , v1 , v2 } {c0 , j1 , c2 } {c0 , c1 , c0 , u2 } {c0 , c1 , j1 , c0 , c2 } {c0 , c1 , c0 , c2 , u2 } {c0 , c1 , j1 , j4 , c0 , c2 } {c0 , c1 , c0 , c2 , u2 , u3 } {c0 , j1 , c0 , u2 } {c0 , j1 , c0 , c2 , u2 } {c0 , c1 , j1 , c0 , u2 } {c0 , c1 , j1 , c0 , c2 , u2 } {c0 , j1 , c0 , c2 , u2 , u3 } {c0 , c1 , j1 , j4 , c0 , u2 } {c0 , c1 , j1 , c0 , c2 , u2 , u3 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u3 } {c1 , j5 , c2 } {c0 , c1 , j2 , c0 , c2 } {c0 , c1 , j3 , c0 , c2 } {c0 , c1 , j5 , c0 , c2 } {c0 , c1 , j0 , j5 , c0 , c2 } {c0 , c1 , j1 , j2 , c0 , c2 } {c0 , c1 , j1 , j3 , c0 , c2 } {c0 , c1 , j1 , j5 , c0 , c2 } {c0 , c1 , j2 , j3 , c0 , c2 } {c0 , c1 , j2 , j5 , c0 , c2 } {c0 , c1 , j3 , j5 , c0 , c2 } {c0 , c1 , j1 , j2 , j3 , c0 , c2 } {c0 , c1 , j1 , j2 , j5 , c0 , c2 } {c0 , c1 , j1 , j3 , j5 , c0 , c2 } {c0 , c1 , j2 , j3 , j5 , c0 , c2 } {c0 , c1 , j0 , j1 , j4 , j5 , c0 , c2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , c2 } J ∪ {c0 , c2 } {c0 , j2 , c0 , u2 } {c0 , c1 , j2 , c0 , u2 } {c0 , c1 , j3 , c0 , u2 } {c0 , j1 , j2 , c0 , u2 } {c0 , j2 , j5 , c0 , u2 } {c0 , c1 , j1 , j2 , c0 , u2 } {c0 , c1 , j1 , j3 , c0 , u2 } {c0 , c1 , j2 , j3 , c0 , u2 } {c0 , c1 , j2 , j5 , c0 , u2 } {c0 , j1 , j2 , j5 , c0 , u2 } {c0 , c1 , j1 , j2 , j3 , c0 , u2 } {c0 , c1 , j1 , j2 , j5 , c0 , u2 } {c0 , c1 , j2 , j3 , j5 , c0 , u2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , u2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , u2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , u2 } J ∪ {c0 , u2 } {c0 , c1 , j2 , c0 , c2 , u2 } {c0 , c1 , j3 , c0 , c2 , u2 } {c0 , c1 , j1 , j2 , c0 , c2 , u2 } {c0 , c1 , j1 , j3 , c0 , c2 , u2 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 } {c0 , c1 , j2 , j5 , c0 , c2 , u2 } {c0 , c1 , j1 , j2 , j3 , c0 , c2 , u2 }
Case
3.1
3.2.1 3.2.2
3.2.3
3.2.4
15.2 The Subsemigroups of (P31 ; ) i 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255
τ (Hi ) (34, 12, −3, 0) (36, 12, −3, 0) (38, 12, −3, 0) (39, 12, −3, 0) (40, 12, −3, 0) (41, 12, −3, 0) (27, 25, −3, 0) (33, 25, −3, 0) (36, 25, −3, 0) (38, 25, −3, 0) (39, 25, −3, 0) (40, 25, −3, 0) (41, 25, −3, 0) (−2, 8, −3, 0) (−3, 13, −3, 0) (−3, 14, −3, 0) (−3, 15, −3, 0) (−3, 22, −3, 0) (−3, 23, −3, 0) (−3, 24, −3, 0) (−3, 26, −3, 0) (−3, 27, −3, 0) (−3, 28, −3, 0) (−3, 29, −3, 0) (−3, 33, −3, 0) (−3, 34, −3, 0) (−3, 35, −3, 0) (−3, 36, −3, 0) (−3, 37, −3, 0) (−3, 38, −3, 0) (−3, 39, −3, 0) (−3, 40, −3, 0) (−3, 41, −3, 0) (3, 4, 0, 0) (3, 13, −1, 0) (3, 14, −1, 0) (3, 16, 0, 0) (3, 18, 0, 0) (3, 23, −1, 0) (3, 24, −1, 0) (3, 27, −1, 0) (3, 28, −1, 0) (3, 30, 0, 0) (3, 33, −1, 0) (3, 34, −1, 0) (3, 36, −1, 0) (3, 38, −1, 0) (3, 39, −1, 0) (3, 40, −1, 0) (3, 41, −1, 0) (12, 13, −3, 0) (12, 14, −3, 0) (12, 23, −3, 0) (12, 24, −3, 0) (12, 27, −3, 0) (12, 28, −3, 0) (12, 33, −3, 0) (12, 34, −3, 0) (12, 36, −3, 0) (12, 38, −3, 0) (12, 39, −3, 0) (12, 40, −3, 0) (12, 41, −3, 0) (25, 27, −3, 0) (25, 33, −3, 0)
Hi {c0 , c1 , j1 , j2 , j5 , c0 , c2 , u2 } {c0 , c1 , j2 , j3 , j5 , c0 , c2 , u2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , c2 , u2 } J ∪ {c0 , c2 , u2 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 , u3 } {c0 , c1 , j1 , j2 , j3 , c0 , c2 , u2 , u3 } {c0 , c1 , j2 , j3 , j5 , c0 , c2 , u2 , u3 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u2 , u3 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u3 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , c2 , u2 , u3 } J ∪ {c0 , c2 , u2 , u3 } {c1 , c2 , u5 } {c0 , c1 , c0 , c2 , u1 } {c0 , c1 , c0 , c2 , u4 } {c0 , c1 , c0 , c2 , u5 } {c0 , c1 , c0 , c2 , u0 , u5 } {c0 , c1 , c0 , c2 , u2 , u1 } {c0 , c1 , c0 , c2 , u2 , u4 } {c0 , c1 , c0 , c2 , u2 , u5 } {c0 , c1 , c0 , c2 , u1 , u4 } {c0 , c1 , c0 , c2 , u1 , u5 } {c0 , c1 , c0 , c2 , u4 , u5 } {c0 , c1 , c0 , c2 , u2 , u1 , u4 } {c0 , c1 , c0 , c2 , u2 , u1 , u5 } {c0 , c1 , c0 , c2 , u2 , u4 , u5 } {c0 , c1 , c0 , c2 , u1 , u4 , u5 } {c0 , c1 , c0 , c2 , u0 , u2 , u3 , u5 } {c0 , c1 , c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c1 , c0 , c2 , u2 , u1 , u4 , u3 } {c0 , c1 , c0 , c2 , u2 , u1 , u4 , u5 } {c0 , c1 } ∪ U {c0 , j1 , c0 , u1 } {c0 , j1 , c0 , c2 , u1 } {c0 , j1 , c0 , c2 , u4 } {c0 , j1 , c0 , u2 , u1 } {c0 , j1 , c0 , u1 , u5 } {c0 , j1 , c0 , c2 , u2 , u1 } {c0 , j1 , c0 , c2 , u2 , u4 } {c0 , j1 , c0 , c2 , u1 , u4 } {c0 , j1 , c0 , c2 , u1 , u5 } {c0 , j1 , c0 , u2 , u1 , u5 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 } {c0 , j1 , c0 , c2 , u2 , u1 , u5 } {c0 , j1 , c0 , c2 , u1 , u4 , u5 } {c0 , j1 , c0 , c2 , u0 , u1 , u4 , u5 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 , u3 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 , u5 } {c0 , j1 } ∪ U {c0 , c1 , j1 , c0 , c2 , u1 } {c0 , c1 , j1 , c0 , c2 , u4 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 } {c0 , c1 , j1 , c0 , c2 , u2 , u4 } {c0 , c1 , j1 , c0 , c2 , u1 , u4 } {c0 , c1 , j1 , c0 , c2 , u1 , u5 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u5 } {c0 , c1 , j1 , c0 , c2 , u1 , u4 , u5 } {c0 , c1 , j1 , c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 , u3 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 , u5 } {c0 , c1 , j1 } ∪ U {c0 , c1 , j1 , j4 , c0 , c2 , u1 , u4 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 }
447 Case
3.2.5
3.3
448
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 i 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 147 280 150 281 151 282 283 284 285 286 287 288 289 290 291 132 149 148 134 136 157 156 154 155 153 152 161 160 159 158 162 164 163 165 166 292 293 294 295 296 297
τ (Hi ) (25, 36, −3, 0) (25, 38, −3, 0) (25, 39, −3, 0) (25, 40, −3, 0) (25, 41, −3, 0) (2, 2, 0, 0) (5, 5, 0, 0) (8, 8, −3, 0) (9, 9, 0, 0) (15, 15, −2, 0) (16, 16, 0, 0) (17, 18, 0, 0) (18, 17, 0, 0) (22, 22, −3, 0) (23, 23, −3, 0) (24, 24, −3, 0) (26, 28, −3, 0) (28, 26, −3, 0) (30, 30, 0, 0) (34, 34, −3, 0) (37, 38, −3, 0) (38, 37, −3, 0) (39, 39, −3, 0) (41, 41, −3, 0) (8, −2, −3, 0) (−3, −1, 8, 0) (15, −3, −3, 0) (−3, −3, 15, 0) (22, −3, −3, 0) (−3, −3, 22, 0) (8, 0, 8, 0) (8, −1, 15, 0) (15, −2, 8, 0) (15, −3, 15, 0) (8, −1, 22, 0) (22, −2, 8, 0) (15, −3, 22, 0) (22, −3, 15, 0) (22, −3, 22, 0) (3, −3, −1, 0) (14, −3, −3, 0) (13, −3, −3, 0) (12, −3, −3, 0) (25, −3, −3, 0) (29, −3, −3, 0) (28, −3, −3, 0) (26, −3, −3, 0) (27, −3, −3, 0) (24, −3, −3, 0) (23, −3, −3, 0) (36, −3, −3, 0) (35, −3, −3, 0) (34, −3, −3, 0) (33, −3, −3, 0) (37, −3, −3, 0) (39, −3, −3, 0) (38, −3, −3, 0) (40, −3, −3, 0) (41, −3, −3, 0) (7, 0, 8, 0) (14, −2, 8, 0) (13, −2, 8, 0) (21, 0, 8, 0) (19, 0, 8, 0) (29, −2, 8, 0)
Hi {c0 , c1 , j1 , j4 , c0 , c2 , u1 , u4 , u5 } {c0 , c1 , j1 , j4 , c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 , u3 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 , u5 } {c0 , c1 , j1 , j4 } ∪ U {j5 , u5 } {c0 , j5 , c0 , u5 } {c1 , j5 , c2 , u5 } {j0 , j5 , u0 , u5 } {c0 , c1 , j5 , c0 , c2 , u5 } {c0 , j1 , j2 , c0 , u2 , u1 } {c0 , j1 , j5 , c0 , u1 , u5 } {c0 , j2 , j5 , c0 , u2 , u5 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 } {c0 , c1 , j1 , j2 , c0 , c2 , u2 , u1 } {c0 , c1 , j1 , j3 , c0 , c2 , u2 , u4 } {c0 , c1 , j1 , j5 , c0 , c2 , u1 , u5 } {c0 , c1 , j2 , j5 , c0 , c2 , u2 , u5 } {c0 , j1 , j2 , j5 , c0 , u2 , u1 , u5 } {c0 , c1 , j1 , j2 , j5 , c0 , c2 , u2 , u1 , u5 } {c0 , c1 , j0 , j1 , j4 , j5 , c0 , c2 , u0 , u1 , u4 , u5 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u0 , u2 , u3 , u5 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u1 , u4 , u3 } J ∪U {c1 , j5 , c2 , c1 } {c0 , c1 , c1 , v2 } {c0 , c1 , j5 , c2 , c1 } {c0 , c1 , c2 , c1 , v2 } {c0 , c1 , j0 , j5 , c2 , c1 } {c0 , c1 , c2 , c1 , v3 , v2 } {c1 , j5 , c1 , v2 } {c1 , j5 , c2 , c1 , v2 } {c0 , c1 , j5 , c1 , v2 } {c0 , c1 , j5 , c2 , c1 , v2 } {c1 , j5 , c2 , c1 , v3 , v2 } {c0 , c1 , j0 , j5 , c1 , v2 } {c0 , c1 , j5 , c2 , c1 , v3 , v2 } {c0 , c1 , j0 , j5 , c2 , c1 , v2 } {c0 , c1 , j0 , j5 , c2 , c1 , v3 , v2 } {c0 , j1 , c2 } {c0 , c1 , j3 , c2 , c1 } {c0 , c1 , j2 , c2 , c1 } {c0 , c1 , j1 , c2 , c1 } {c0 , c1 , j1 , j4 , c2 , c1 } {c0 , c1 , j3 , j5 , c2 , c1 } {c0 , c1 , j2 , j5 , c2 , c1 } {c0 , c1 , j1 , j5 , c2 , c1 } {c0 , c1 , j2 , j3 , c2 , c1 } {c0 , c1 , j1 , j3 , c2 , c1 } {c0 , c1 , j1 , j2 , c2 , c1 } {c0 , c1 , j2 , j3 , j5 , c2 , c1 } {c0 , c1 , j1 , j3 , j5 , c2 , c1 } {c0 , c1 , j1 , j2 , j5 , c2 , c1 } {c0 , c1 , j1 , j2 , j3 , c2 , c1 } {c0 , c1 , j0 , j1 , j4 , j5 , c2 , c1 } {c0 , c1 , j1 , j2 , j3 , j4 , c2 , c1 } {c0 , c1 , j0 , j2 , j3 , j5 , c2 , c1 } {c0 , c1 , j1 , j2 , j3 , j5 , c2 , c1 } J ∪ {c2 , c1 } {c1 , j3 , c1 , v2 } {c0 , c1 , j3 , c1 , v2 } {c0 , c1 , j2 , c1 , v2 } {c1 , j3 , j5 , c1 , v2 } {c1 , j1 , j3 , c1 , v2 } {c0 , c1 , j3 , j5 , c1 , v2 }
Case
3.4
4.1
15.2 The Subsemigroups of (P31 ; ) i 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362
τ (Hi ) (28, −2, 8, 0) (27, −2, 8, 0) (24, −2, 8, 0) (31, 0, 8, 0) (36, −2, 8, 0) (35, −2, 8, 0) (33, −2, 8, 0) (39, −2, 8, 0) (38, −2, 8, 0) (40, −2, 8, 0) (41, −2, 8, 0) (14, −3, 15, 0) (13, −3, 15, 0) (29, −3, 15, 0) (28, −3, 15, 0) (27, −3, 15, 0) (24, −3, 15, 0) (36, −3, 15, 0) (35, −3, 15, 0) (33, −3, 15, 0) (39, −3, 15, 0) (38, −3, 15, 0) (40, −3, 15, 0) (41, −3, 15, 0) (27, −3, 22, 0) (36, −3, 22, 0) (33, −3, 22, 0) (39, −3, 22, 0) (38, −3, 22, 0) (40, −3, 22, 0) (41, −3, 22, 0) (−1, −3, 3, 0) (−3, −3, 14, 0) (−3, −3, 13, 0) (−3, −3, 12, 0) (−3, −3, 25, 0) (−3, −3, 29, 0) (−3, −3, 28, 0) (−3, −3, 26, 0) (−3, −3, 27, 0) (−3, −3, 24, 0) (−3, −3, 23, 0) (−3, −3, 36, 0) (−3, −3, 35, 0) (−3, −3, 34, 0) (−3, −3, 33, 0) (−3, −3, 37, 0) (−3, −3, 39, 0) (−3, −3, 38, 0) (−3, −3, 40, 0) (−3, −3, 41, 0) (8, 0, 7, 0) (8, −1, 14, 0) (8, −1, 13, 0) (8, 0, 21, 0) (8, 0, 19, 0) (8, −1, 29, 0) (8, −1, 28, 0) (8, −1, 27, 0) (8, −1, 24, 0) (8, 0, 31, 0) (8, −1, 36, 0) (8, −1, 35, 0) (8, −1, 33, 0) (8, −1, 39, 0)
Hi {c0 , c1 , j2 , j5 , c1 , v2 } {c0 , c1 , j2 , j3 , c1 , v2 } {c0 , c1 , j1 , j3 , c1 , v2 } {c1 , j1 , j3 , j5 , c1 , v2 } {c0 , c1 , j2 , j3 , j5 , c1 , v2 } {c0 , c1 , j1 , j3 , j5 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c1 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c1 , v2 } J ∪ {c1 , v2 } {c0 , c1 , j3 , c2 , c1 , v2 } {c0 , c1 , j2 , c2 , c1 , v2 } {c0 , c1 , j3 , j5 , c2 , c1 , v2 } {c0 , c1 , j2 , j5 , c2 , c1 , v2 } {c0 , c1 , j2 , j3 , c2 , c1 , v2 } {c0 , c1 , j1 , j3 , c2 , c1 , v2 } {c0 , c1 , j2 , j3 , j5 , c2 , c1 , v2 } {c0 , c1 , j1 , j3 , j5 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c2 , c1 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c2 , c1 , v2 } J ∪ {c2 , c1 , v2 } {c0 , c1 , j2 , j3 , c2 , c1 , v3 , v2 } {c0 , c1 , j2 , j3 , j5 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c2 , c1 , v3 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c2 , c1 , v3 , v2 } J ∪ {c2 , c1 , v3 , v2 } {c0 , c2 , v4 } {c0 , c1 , c2 , c1 , v0 } {c0 , c1 , c2 , c1 , v5 } {c0 , c1 , c2 , c1 , v4 } {c0 , c1 , c2 , c1 , v4 , v1 } {c0 , c1 , c2 , c1 , v0 , v2 } {c0 , c1 , c2 , c1 , v5 , v2 } {c0 , c1 , c2 , c1 , v4 , v2 } {c0 , c1 , c2 , c1 , v5 , v0 } {c0 , c1 , c2 , c1 , v4 , v0 } {c0 , c1 , c2 , c1 , v4 , v5 } {c0 , c1 , c2 , c1 , v5 , v0 , v2 } {c0 , c1 , c2 , c1 , v4 , v0 , v2 } {c0 , c1 , c2 , c1 , v4 , v5 , v2 } {c0 , c1 , c2 , c1 , v4 , v5 , v0 } {c0 , c1 , c2 , c1 , v3 , v4 , v1 , v2 } {c0 , c1 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c1 } ∪ V {c1 , j5 , c1 , v0 } {c1 , j5 , c2 , c1 , v0 } {c1 , j5 , c2 , c1 , v5 } {c1 , j5 , c1 , v0 , v2 } {c1 , j5 , c1 , v4 , v0 } {c1 , j5 , c2 , c1 , v0 , v2 } {c1 , j5 , c2 , c1 , v5 , v2 } {c1 , j5 , c2 , c1 , v5 , v0 } {c1 , j5 , c2 , c1 , v4 , v0 } {c1 , j5 , c1 , v4 , v0 , v2 } {c1 , j5 , c2 , c1 , v5 , v0 , v2 } {c1 , j5 , c2 , c1 , v4 , v0 , v2 } {c1 , j5 , c2 , c1 , v4 , v5 , v0 } {c1 , j5 , c2 , c1 , v4 , v5 , v0 , v1 }
449 Case
450
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 i 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 204 352 207 355 208 356 405 406 407 408 409 410 411 412 413 414 206 205 135 137 214 213 211
τ (Hi ) (8, −1, 38, 0) (8, −1, 40, 0) (8, −1, 41, 0) (15, −3, 14, 0) (15, −3, 13, 0) (15, −3, 29, 0) (15, −3, 28, 0) (15, −3, 27, 0) (15, −3, 24, 0) (15, −3, 36, 0) (15, −3, 35, 0) (15, −3, 33, 0) (15, −3, 39, 0) (15, −3, 38, 0) (15, −3, 40, 0) (15, −3, 41, 0) (22, −3, 27, 0) (22, −3, 36, 0) (22, −3, 33, 0) (22, −3, 39, 0) (22, −3, 38, 0) (22, −3, 40, 0) (22, −3, 41, 0) (1, 0, 1, 0) (6, 0, 6, 0) (3, −3, 3, 0) (10, 0, 10, 0) (12, −3, 12, 0) (21, 0, 21, 0) (20, 0, 19, 0) (19, 0, 20, 0) (25, −3, 25, 0) (29, −3, 29, 0) (28, −3, 28, 0) (26, −3, 24, 0) (24, −3, 26, 0) (31, 0, 31, 0) (35, −3, 35, 0) (37, −3, 39, 0) (39, −3, 37, 0) (38, −3, 38, 0) (41, −3, 41, 0) (−2, 8, −3, 0) (−1, −3, 3, 0) (−3, 15, −3, 0) (−3, −3, 12, 0) (−3, 22, −3, 0) (−3, −3, 25, 0) (0, 8, 3, 0) (−2, 8, 12, 0) (−1, 15, 3, 0) (−3, 15, 12, 0) (−2, 8, 25, 0) (−1, 22, 3, 0) (−3, 15, 25, 0) (−3, 22, 12, 0) (−3, 22, 25, 0) (−2, 3, −2, 0) (−3, 14, −3, 0) (−3, 13, −3, 0) (−3, 12, −3, 0) (−3, 25, −3, 0) (−3, 29, −3, 0) (−3, 28, −3, 0) (−3, 26, −3, 0)
Hi {c1 , j5 , c2 , c1 , v3 , v5 , v0 , v2 } {c1 , j5 , c2 , c1 , v4 , v5 , v0 , v2 } {c1 , j5 } ∪ V {c0 , c1 , j5 , c2 , c1 , v0 } {c0 , c1 , j5 , c2 , c1 , v5 } {c0 , c1 , j5 , c2 , c1 , v0 , v2 } {c0 , c1 , j5 , c2 , c1 , v5 , v2 } {c0 , c1 , j5 , c2 , c1 , v5 , v0 } {c0 , c1 , j5 , c2 , c1 , v4 , v0 } {c0 , c1 , j5 , c2 , c1 , v5 , v0 , v2 } {c0 , c1 , j5 , c2 , c1 , v4 , v0 , v2 } {c0 , c1 , j5 , c2 , c1 , v4 , v5 , v0 } {c0 , c1 , j5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , j5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c1 , j5 } ∪ V {c0 , c1 , j0 , j5 , c2 , c1 , v5 , v0 } {c0 , c1 , j0 , j5 , c2 , c1 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 , c2 , c1 , v4 , v5 , v0 } {c0 , c1 , j0 , j5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j0 , j5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 } ∪ V {j1 , v4 } {c1 , j1 , c1 , v4 } {c0 , j1 , c2 , v4 } {j1 , j4 , v4 , v1 } {c0 , c1 , j1 , c2 , c1 , v4 } {c1 , j3 , j5 , c1 , v0 , v2 } {c1 , j1 , j5 , c1 , v4 , v0 } {c1 , j1 , j3 , c1 , v4 , v2 } {c0 , c1 , j1 , j4 , c2 , c1 , v4 , v1 } {c0 , c1 , j3 , j5 , c2 , c1 , v0 , v2 } {c0 , c1 , j2 , j5 , c2 , c1 , v5 , v2 } {c0 , c1 , j1 , j5 , c2 , c1 , v4 , v0 } {c0 , c1 , j1 , j3 , c2 , c1 , v4 , v2 } {c1 , j1 , j3 , j5 , c1 , v4 , v0 , v2 } {c0 , c1 , j1 , j3 , j5 , c2 , c1 , v4 , v0 , v2 } {c0 , c1 , j0 , j1 , j4 , j5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j1 , j2 , j3 , j4 , c2 , c1 , v3 , v4 , v1 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c2 , c1 , v3 , v5 , v0 , v2 } J ∪V {c2 , u5 , c2 , c1 } {c0 , c2 , c2 , v4 } {c0 , c2 , u5 , c2 , c1 } {c0 , c2 , c2 , c1 , v4 } {c0 , c2 , u0 , u5 , c2 , c1 } {c0 , c2 , c2 , c1 , v4 , v1 } {c2 , u5 , c2 , v4 } {c2 , u5 , c2 , c1 , v4 } {c0 , c2 , u5 , c2 , v4 } {c0 , c2 , u5 , c2 , c1 , v4 } {c2 , u5 , c2 , c1 , v4 , v1 } {c0 , c2 , u0 , u5 , c2 , v4 } {c0 , c2 , u5 , c2 , c1 , v4 , v1 } {c0 , c2 , u0 , u5 , c2 , c1 , v4 } {c0 , c2 , u0 , u5 , c2 , c1 , v4 , v1 } {c2 , u2 , c1 } {c0 , c2 , u4 , c2 , c1 } {c0 , c2 , u1 , c2 , c1 } {c0 , c2 , u2 , c2 , c1 } {c0 , c2 , u2 , u3 , c2 , c1 } {c0 , c2 , u4 , u5 , c2 , c1 } {c0 , c2 , u1 , u5 , c2 , c1 } {c0 , c2 , u2 , u5 , c2 , c1 }
Case
4.2
15.2 The Subsemigroups of (P31 ; ) i 212 210 209 218 217 216 215 219 221 220 222 223 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 281 354 353 283 285 362 361 359 360 358 357 366 365 364 363 367
τ (Hi ) (−3, 27, −3, 0) (−3, 24, −3, 0) (−3, 23, −3, 0) (−3, 36, −3, 0) (−3, 35, −3, 0) (−3, 34, −3, 0) (−3, 33, −3, 0) (−3, 37, −3, 0) (−3, 39, −3, 0) (−3, 38, −3, 0) (−3, 40, −3, 0) (−3, 41, −3, 0) (0, 7, 3, 0) (−1, 14, 3, 0) (−1, 13, 3, 0) (0, 21, 3, 0) (0, 19, 3, 0) (−1, 29, 3, 0) (−1, 28, 3, 0) (−1, 27, 3, 0) (−1, 24, 3, 0) (0, 31, 3, 0) (−1, 36, 3, 0) (−1, 35, 3, 0) (−1, 33, 3, 0) (−1, 39, 3, 0) (−1, 38, 3, 0) (−1, 40, 3, 0) (−1, 41, 3, 0) (−3, 14, 12, 0) (−3, 13, 12, 0) (−3, 29, 12, 0) (−3, 28, 12, 0) (−3, 27, 12, 0) (−3, 24, 12, 0) (−3, 36, 12, 0) (−3, 35, 12, 0) (−3, 33, 12, 0) (−3, 39, 12, 0) (−3, 38, 12, 0) (−3, 40, 12, 0) (−3, 41, 12, 0) (−3, 27, 25, 0) (−3, 36, 25, 0) (−3, 33, 25, 0) (−3, 39, 25, 0) (−3, 38, 25, 0) (−3, 40, 25, 0) (−3, 41, 25, 0) (−3, −1, 8, 0) (−3, −3, 13, 0) (−3, −3, 14, 0) (−3, −3, 15, 0) (−3, −3, 22, 0) (−3, −3, 23, 0) (−3, −3, 24, 0) (−3, −3, 26, 0) (−3, −3, 27, 0) (−3, −3, 28, 0) (−3, −3, 29, 0) (−3, −3, 33, 0) (−3, −3, 34, 0) (−3, −3, 35, 0) (−3, −3, 36, 0) (−3, −3, 37, 0)
Hi {c0 , c2 , u1 , u4 , c2 , c1 } {c0 , c2 , u2 , u4 , c2 , c1 } {c0 , c2 , u2 , u1 , c2 , c1 } {c0 , c2 , u1 , u4 , u5 , c2 , c1 } {c0 , c2 , u2 , u4 , u5 , c2 , c1 } {c0 , c2 , u2 , u1 , u5 , c2 , c1 } {c0 , c2 , u2 , u1 , u4 , c2 , c1 } {c2 , c1 , v3 , v4 , v1 , v2 , c2 , c1 } {c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 } {c0 , c2 , u2 , u1 , u4 , u5 , c2 , c1 } U ∪ {c2 , c1 } {c2 , u4 , c2 , v4 } {c0 , c2 , u4 , c2 , v4 } {c0 , c2 , u1 , c2 , v4 } {c2 , u4 , u5 , c2 , v4 } {c2 , u2 , u4 , c2 , v4 } {c0 , c2 , u4 , u5 , c2 , v4 } {c0 , c2 , u1 , u5 , c2 , v4 } {c0 , c2 , u1 , u4 , c2 , v4 } {c0 , c2 , u2 , u4 , c2 , v4 } {c2 , u2 , u4 , u5 , c2 , v4 } {c0 , c2 , u1 , u4 , u5 , c2 , v4 } {c0 , c2 , u2 , u4 , u5 , c2 , v4 } {c0 , c2 , u2 , u1 , u4 , c2 , v4 } {c0 , c2 , u2 , u1 , u4 , u3 , c2 , v4 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , v4 } {c0 , c2 , u2 , u1 , u4 , u5 , c2 , v4 } U ∪ {c2 , v4 } {c0 , c2 , u4 , c2 , c1 , v4 } {c0 , c2 , u1 , c2 , c1 , v4 } {c0 , c2 , u4 , u5 , c2 , c1 , v4 } {c0 , c2 , u1 , u5 , c2 , c1 , v4 } {c0 , c2 , u1 , u4 , c2 , c1 , v4 } {c0 , c2 , u2 , u4 , c2 , c1 , v4 } {c0 , c2 , u1 , u4 , u5 , c2 , c1 , v4 } {c0 , c2 , u2 , u4 , u5 , c2 , c1 , v4 } {c0 , c2 , u2 , u1 , u4 , c2 , c1 , v4 } {c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v4 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 } {c0 , c2 , u2 , u1 , u4 , u5 , c2 , c1 , v4 } U ∪ {c2 , c1 , v4 } {c0 , c2 , u1 , u4 , c2 , c1 , v4 , v1 } {c0 , c2 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } {c0 , c2 , u2 , u1 , u4 , c2 , c1 , v4 , v1 } {c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v4 , v1 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } {c0 , c2 , u2 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } U ∪ {c2 , c1 , v4 , v1 } {c0 , c1 , v2 } {c0 , c2 , c2 , c1 , v5 } {c0 , c2 , c2 , c1 , v0 } {c0 , c2 , c2 , c1 , v2 } {c0 , c2 , c2 , c1 , v3 , v2 } {c0 , c2 , c2 , c1 , v4 , v5 } {c0 , c2 , c2 , c1 , v4 , v0 } {c0 , c2 , c2 , c1 , v4 , v2 } {c0 , c2 , c2 , c1 , v5 , v0 } {c0 , c2 , c2 , c1 , v5 , v2 } {c0 , c2 , c2 , c1 , v0 , v2 } {c0 , c2 , c2 , c1 , v4 , v5 , v0 } {c0 , c2 , c2 , c1 , v4 , v5 , v2 } {c0 , c2 , c2 , c1 , v4 , v0 , v2 } {c0 , c2 , c2 , c1 , v5 , v0 , v2 } {c0 , c2 , c2 , c1 , v3 , v4 , v1 , v2 }
451 Case
452
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 i 369 368 370 371 452 453 454 455 456 457 458 459 450 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512
τ (Hi ) (−3, −3, 38, 0) (−3, −3, 39, 0) (−3, −3, 40, 0) (−3, −3, 41, 0) (0, 8, 4, 0) (−2, 8, 13, 0) (−2, 8, 14, 0) (0, 8, 16, 0) (0, 8, 18, 0) (−2, 8, 23, 0) (−2, 8, 24, 0) (−2, 8, 27, 0) (−2, 8, 28, 0) (0, 8, 30, 0) (−2, 8, 33, 0) (−2, 8, 34, 0) (−2, 8, 36, 0) (−2, 8, 38, 0) (−2, 8, 39, 0) (−2, 8, 40, 0) (−2, 8, 41, 0) (−3, 15, 13, 0) (−3, 15, 14, 0) (−3, 15, 23, 0) (−3, 15, 24, 0) (−3, 15, 27, 0) (−3, 15, 28, 0) (−3, 15, 33, 0) (−3, 15, 34, 0) (−3, 15, 36, 0) (−3, 15, 38, 0) (−3, 15, 39, 0) (−3, 15, 40, 0) (−3, 15, 41, 0) (−3, 22, 27, 0) (−3, 22, 33, 0) (−3, 22, 36, 0) (−3, 22, 38, 0) (−3, 22, 39, 0) (−3, 22, 40, 0) (−3, 22, 41, 0) (0, 1, 2, 0) (0, 6, 5, 0) (−3, 3, 8, 0) (0, 10, 9, 0) (−3, 12, 15, 0) (0, 21, 16, 0) (0, 20, 18, 0) (0, 19, 17, 0) (−3, 25, 22, 0) (−3, 29, 23, 0) (−3, 28, 24, 0) (−3, 26, 28, 0) (−3, 24, 26, 0) (0, 31, 30, 0) (−3, 35, 34, 0) (−3, 37, 38, 0) (−3, 39, 37, 0) (−3, 38, 39, 0) (−3, 41, 41, 0) (13, 3, 8, 0) (14, 3, 8, 0) (24, 3, 8, 0) (27, 3, 8, 0) (28, 3, 8, 0)
Hi {c0 , c2 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c2 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c2 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c2 } ∪ V {c2 , u5 , c2 , v5 } {c2 , u5 , c2 , c1 , v5 } {c2 , u5 , c2 , c1 , v0 } {c2 , u5 , c2 , v4 , v5 } {c2 , u5 , c2 , v5 , v2 } {c2 , u5 , c2 , c1 , v4 , v5 } {c2 , u5 , c2 , c1 , v4 , v0 } {c2 , u5 , c2 , c1 , v5 , v0 } {c2 , u5 , c2 , c1 , v5 , v2 } {c2 , u5 , c2 , v4 , v5 , v2 } {c2 , u5 , c2 , c1 , v4 , v5 , v0 } {c2 , u5 , c2 , c1 , v4 , v5 , v2 } {c2 , u5 , c2 , c1 , v5 , v0 , v2 } {c2 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c2 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c2 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c2 , u5 } ∪ V {c0 , c2 , u5 , c2 , c1 , v5 } {c0 , c2 , u5 , c2 , c1 , v0 } {c0 , c2 , u5 , c2 , c1 , v4 , v5 } {c0 , c2 , u5 , c2 , c1 , v4 , v0 } {c0 , c2 , u5 , c2 , c1 , v5 , v0 } {c0 , c2 , u5 , c2 , c1 , v5 , v2 } {c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 } {c0 , c2 , u5 , c2 , c1 , v4 , v5 , v2 } {c0 , c2 , u5 , c2 , c1 , v5 , v0 , v2 } {c0 , c2 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c2 , u5 } ∪ V {c0 , c2 , u0 , u5 , c2 , c1 , v5 , v0 } {c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 } {c0 , c2 , u0 , u5 , c2 , c1 , v5 , v0 , v2 } {c0 , c2 , u0 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c2 , u0 , u5 } ∪ V {u2 , v2 } {c2 , u2 , c2 , v2 } {c0 , u2 , c1 , v2 } {u2 , u3 , v3 , v2 } {c0 , c2 , u2 , c2 , c1 , v2 } {c2 , u4 , u5 , c2 , v4 , v5 } {c2 , u2 , u5 , c2 , v5 , v2 } {c2 , u2 , u4 , c2 , v4 , v2 } {c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c2 , u4 , u5 , c2 , c1 , v4 , v5 } {c0 , c2 , u1 , u5 , c2 , c1 , v4 , v0 } {c0 , c2 , u2 , u5 , c2 , c1 , v5 , v2 } {c0 , c2 , u2 , u4 , c2 , c1 , v4 , v2 } {c2 , u2 , u4 , u5 , c2 , v4 , v5 , v2 } {c0 , c2 , u2 , u4 , u5 , c2 , c1 , v4 , v5 , v2 } {c2 , c1 , v3 , v4 , v1 , v2 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v3 , v4 , v1 , v2 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } U ∪V {c0 , c1 , j2 , c0 , u2 , c1 , v2 } {c0 , c1 , j3 , c0 , u2 , c1 , v2 } {c0 , c1 , j1 , j3 , c0 , u2 , c1 , v2 } {c0 , c1 , j2 , j3 , c0 , u2 , c1 , v2 } {c0 , c1 , j2 , j5 , c0 , u2 , c1 , v2 }
Case
5.1.1
15.2 The Subsemigroups of (P31 ; ) i 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576
τ (Hi ) (33, 3, 8, 0) (36, 3, 8, 0) (38, 3, 8, 0) (39, 3, 8, 0) (40, 3, 8, 0) (41, 3, 8, 0) (13, 12, 15, 0) (14, 12, 15, 0) (24, 12, 15, 0) (27, 12, 15, 0) (28, 12, 15, 0) (33, 12, 15, 0) (36, 12, 15, 0) (38, 12, 15, 0) (39, 12, 15, 0) (40, 12, 15, 0) (41, 12, 15, 0) (27, 25, 22, 0) (33, 25, 22, 0) (36, 25, 22, 0) (38, 25, 22, 0) (39, 25, 22, 0) (40, 25, 22, 0) (41, 25, 22, 0) (3, 13, 3, 0) (3, 14, 3, 0) (3, 24, 3, 0) (3, 27, 3, 0) (3, 28, 3, 0) (3, 33, 3, 0) (3, 36, 3, 0) (3, 38, 3, 0) (3, 39, 3, 0) (3, 40, 3, 0) (3, 41, 3, 0) (12, 13, 12, 0) (12, 14, 12, 0) (12, 24, 12, 0) (12, 27, 12, 0) (12, 28, 12, 0) (12, 33, 12, 0) (12, 36, 12, 0) (12, 38, 12, 0) (12, 39, 12, 0) (12, 40, 12, 0) (12, 41, 12, 0) (25, 27, 25, 0) (25, 33, 25, 0) (25, 36, 25, 0) (25, 38, 25, 0) (25, 39, 25, 0) (25, 40, 25, 0) (25, 41, 25, 0) (8, 8, 13, 0) (8, 8, 14, 0) (8, 8, 24, 0) (8, 8, 27, 0) (8, 8, 28, 0) (8, 8, 33, 0) (8, 8, 36, 0) (8, 8, 38, 0) (8, 8, 39, 0) (8, 8, 40, 0) (8, 8, 41, 0) (15, 15, 13, 0)
Hi {c0 , c1 , j1 , j2 , j3 , c0 , u2 , c1 , v2 } {c0 , c1 , j2 , j3 , j5 , c0 , u2 , c1 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , u2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , u2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , u2 , c1 , v2 } J ∪ {c0 , u2 , c1 , v2 } {c0 , c1 , j2 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j3 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j1 , j3 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j2 , j5 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j2 , j3 , j5 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , c2 , u2 , c2 , c1 , v2 } J ∪ {c0 , c2 , u2 , c2 , c1 , v2 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c1 , j2 , j3 , j5 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , c1 , j1 , j2 , j3 , j5 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } J ∪ {c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 } {c0 , j1 , c0 , c2 , u1 , c2 , v4 } {c0 , j1 , c0 , c2 , u4 , c2 , v4 } {c0 , j1 , c0 , c2 , u2 , u4 , c2 , v4 } {c0 , j1 , c0 , c2 , u1 , u4 , c2 , v4 } {c0 , j1 , c0 , c2 , u1 , u5 , c2 , v4 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 , c2 , v4 } {c0 , j1 , c0 , c2 , u1 , u4 , u5 , c2 , v4 } {c0 , j1 , c0 , c2 , u0 , u1 , u4 , u5 , c2 , v4 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 , u3 , c2 , v4 } {c0 , j1 , c0 , c2 , u2 , u1 , u4 , u5 , c2 , v4 } {c0 , j1 } ∪ U ∪ {c2 , v4 } {c0 , c1 , j1 , c0 , c2 , u1 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u4 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u2 , u4 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u1 , u4 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u1 , u5 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u1 , u4 , u5 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v4 } {c0 , c1 , j1 , c0 , c2 , u2 , u1 , u4 , u5 , c2 , c1 , v4 } {c0 , c1 , j1 } ∪ U ∪ {c2 , c1 , v4 } {c0 , c1 , j1 , j4 , c0 , c2 , u1 , u4 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 , c0 , c2 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 , c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 , c0 , c2 , u2 , u1 , u4 , u5 , c2 , c1 , v4 , v1 } {c0 , c1 , j1 , j4 } ∪ U ∪ {c2 , c1 , v4 , v1 } {c1 , j5 , c2 , u5 , c2 , c1 , v5 } {c1 , j5 , c2 , u5 , c2 , c1 , v0 } {c1 , j5 , c2 , u5 , c2 , c1 , v4 , v0 } {c1 , j5 , c2 , u5 , c2 , c1 , v5 , v0 } {c1 , j5 , c2 , u5 , c2 , c1 , v5 , v2 } {c1 , j5 , c2 , u5 , c2 , c1 , v4 , v5 , v0 } {c1 , j5 , c2 , u5 , c2 , c1 , v5 , v0 , v2 } {c1 , j5 , c2 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c1 , j5 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c1 , j5 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c1 , j5 , c2 , u5 } ∪ V {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v5 }
453 Case
5.1.2
5.1.3
5.2
5.3
454 i 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596 597 598 599 600 600 + t
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3 τ (Hi ) (15, 15, 14, 0) (15, 15, 24, 0) (15, 15, 27, 0) (15, 15, 28, 0) (15, 15, 33, 0) (15, 15, 36, 0) (15, 15, 38, 0) (15, 15, 39, 0) (15, 15, 40, 0) (15, 15, 41, 0) (22, 22, 27, 0) (22, 22, 33, 0) (22, 22, 36, 0) (22, 22, 38, 0) (22, 22, 39, 0) (22, 22, 40, 0) (22, 22, 41, 0) (24, 24, 26, 0) (26, 28, 24, 0) (28, 26, 28, 0) (37, 38, 39, 0) (38, 37, 38, 0) (39, 39, 37, 0) (41, 41, 41, 0) (..., 1)
1201 1202 1203 1204 1205 1206 1207 1208 1209 1210 1211 1212 1213 1214 1215 1216 1217 1218 1219 1220 1221 1222 1223 1224 1225 1226 1227
(0, 0, 0, 2) (0, −2, −1, 2) (−3 − 1, −2, 2) (−3, −3, −3, 2) (27, −1, −2, 2) (32, 0, 0, 2) (37, −1, −2, 2) (41, −1, −2, 2) (27, −3, −3, 2) (37, −3, −3, 2) (41, −3, −3, 2) (0, 1, 2, 2) (−3, 3, 8, 2) (0, 6, 5, 2) (−3, 12, 15, 2) (0, 10, 9, 2) (−3, 25, 22, 2) (0, 21, 16, 2) (−3, 29, 23, 2) (0, 31, 30, 2) (−3, 35, 34, 2) (−3, 38, 39, 2) (−3, 41, 41, 2) (27, 3, 8, 2) (27, 12, 15, 2) (27, 25, 22, 2) (37, 38, 39, 2)
1228 1229 1230 1231 1232 1233 1234 1235 1236 1237 1238
(41, 12, 15, 2) (41, 3, 8, 2) (41, 25, 22, 2) (41, 41, 41, 2) (0, 0, 0, 3) (−1, −1, 0, 3) (−2, −2, −3, 3) (−3, −3, −3, 3) (−2, −2, 27, 3) (0, 0, 32, 3) (−2, −2, 37, 3)
Hi Case {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v0 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v4 , v0 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v5 , v0 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v5 , v2 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v5 , v0 , v2 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c1 , j5 , c0 , c2 , u5 } ∪ V {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v5 , v0 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v4 , v5 , v0 , v2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 } ∪ V {c0 , c1 , j1 , j3 , c0 , c2 , u2 , u4 , c2 , c1 , v4 , v2 } 5.4 {c0 , c1 , j1 , j5 , c0 , c2 , u1 , u5 , c2 , c1 , v4 , v0 } {c0 , c1 , j2 , j5 , c0 , c2 , u2 , u5 , c2 , c1 , v5 , v2 } {c0 , c1 , j0 , j1 , j4 , j5 , c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v5 , v0 , v1 } {c0 , c1 , j0 , j2 , j3 , j5 , c0 , c2 , u0 , u2 , u3 , u5 , c2 , c1 , v3 , v5 , v0 , v2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v3 , v4 , v1 , v2 } J ∪U ∪V Ht ∪ {s1 } 6.1 (t ∈ {1, 2, ..., 600}) {s1 , s3 } 6.2 {c2 , s1 , s3 } {c0 , c1 , s1 , s3 } {c0 , c1 , c2 , s1 , s3 } {c0 , c1 , j2 , j3 , s1 , s3 } {j0 , j1 , j4 , j5 , s1 , s3 } {c0 , c1 , j0 , j1 , j4 , j5 , s1 , s3 } J ∪ {s1 , s3 } {c0 , c1 , j2 , j3 , c2 , s1 , s3 } {c0 , c1 , j0 , j1 , j4 , j5 , c2 , s1 , s3 } J ∪ {c0 , c2 , s1 , s3 } {u2 , v2 , s1 , s3 } {c0 , c1 , u2 , v2 , s1 , s3 } {c2 , u2 , c2 , v2 , s1 , s3 } {c0 , c2 , u2 , c2 , c1 , v2 , s1 , s3 } {u2 , u3 , v3 , v2 , s1 , s3 } {c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 , s1 , s3 } {c2 , u4 , u5 , c2 , v4 , v5 , s1 , s3 } {c0 , c2 , u4 , u5 , c2 , c1 , v4 , v5 , s1 , s3 } {c2 , u2 , u4 , u5 , c2 , v4 , v5 , v2 , s1 , s3 } {c0 , c2 , u2 , u4 , u5 , c2 , c1 , v4 , v5 , v2 , s1 , s3 } {c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v5 , v0 , v1 , s1 , s3 } U ∪ V ∪ {s1 , s3 } {c0 , c1 , j2 , j3 , c0 , u2 , c1 , v2 , s1 , s3 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 , c2 , c1 , v2 , s1 , s3 } {c0 , c1 , j2 , j3 , c0 , c2 , u2 , u3 , c2 , c1 , v3 , v2 , s1 , s3 } {c0 , c1 , j0 , j1 , j4 , j5 , c0 , c2 , u0 , u1 , u4 , u5 , c2 , c1 , v4 , v5 , v 0 , v 1 , s 1 , s 3 } J ∪ {c0 , c2 , u2 , c2 , c1 , v2 , s1 , s3 } J ∪ {c0 , u2 , c1 , v2 , s1 , s3 } J ∪ {c0 , c2 , u2 , u3 , c2 , c1 , v2 , v3 , s1 , s3 } J ∪ U ∪ V ∪ {s1 , s3 } {s1 , s2 } 6.3 {c0 , s1 , s2 } {c2 , c1 , s1 , s2 } {c0 , c1 , c2 , s1 , s2 } {c2 , c1 , v5 , v0 , s1 , s2 } {v3 , v4 , v1 , v2 , s1 , s2 } {c2 , c1 , v3 , v4 , v1 , v2 , s1 , s2 }
15.2 The Subsemigroups of (P31 ; ) i 1239 1240 1241 1242 1243 1244 1245 1246 1247 1248 1249 1250 1251 1252 1253 1254 1255 1256 1257 1258
τ (Hi ) (−2, −2, 41, 3) (−3, −1, 27, 3) (−3, −1, 37, 3) (−3, −3, 41, 3) (2, 2, 0, 3) (8, 8, −3, 3) (5, 5, 0, 3) (15, 15, −3, 3) (9, 9, 0, 3) (22, 22, −3, 3) (16, 16, 0, 3) (23, 23, −3, 3) (30, 30, 0, 3) (34, 34, −3, 3) (39, 39, −3, 3) (41, 41, −3, 3) (8, 8, 27, 3) (15, 15, 27, 3) (22, 22, 27, 3) (39, 39, 37, 3)
1259 1260 1261 1262 1263 1264 1265 1266 1267 1268 1269 1270 1271 1272 1273 1274 1275 1276 1277 1278 1279 1280 1281 1282 1283 1284 1285 1286 1287 1288 1289
(15, 15, 41, 3) (8, 8, 41, 3) (22, 22, 41, 3) (41, 41, 41, 3) (0, 0, 0, 4) (−2, 0, −2, 4) (−1, −3, −1, 4) (−3, −3, −3, 4) (−1, 27, −1, 4) (0, 32, 0, 4) (−1, 37, −1, 4) (−1, 41, −1, 4) (−2, 27, −3, 4) (−2, 37, −3, 4) (−3, 41, −3, 4) (1, 0, 1, 4) (6, 0, 6, 4) (3, −3, 3, 4) (12, −3, 12, 4) (10, 0, 10, 4) (25, −3, 25, 4) (21, 0, 21, 4) (29, −3, 29, 4) (31, 0, 31, 4) (35, −3, 35, 4) (38, −3, 38, 4) (41, −3, 41, 4) (3, 27, 3, 4) (12, 27, 12, 4) (25, 27, 25, 4) (38, 37, 38, 4)
1290 1291 1292 1293 1294 1295 1296 1297 1298 1299
(12, 41, 12, 4) (3, 41, 3, 4) (25, 41, 25, 4) (41, 41, 41, 4) (0, 0, 0, 5) (−3, −3, −3, 5) (41, 41, 41, 5) (0, 0, 0, 6) (−3, −3, −3, 6) (41, 41, 41, 6)
Hi V ∪ {s1 , s2 } {c0 , c2 , c1 , v5 , v0 , s1 , s2 } {c0 , c2 , c1 , v3 , v4 , v1 , v2 , s1 , s2 } {c0 , c2 } ∪ V ∪ {s1 , s2 } {j5 , u5 , s1 , s2 } {c1 , j5 , c2 , u5 , s1 , s2 } {c0 , j5 , c0 , u5 , s1 , s2 } {c0 , c1 , j5 , c0 , c2 , u5 , s1 , s2 } {j0 , j5 , u0 , u5 , s1 , s2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , s1 , s2 } {c0 , j1 , j2 , c0 , u2 , u1 , s1 , s2 } {c0 , c1 , j1 , j2 , c0 , c2 , u2 , u1 , s1 , s2 } {c0 , j1 , j2 , j5 , c0 , u2 , u1 , u5 , s1 , s2 } {c0 , c1 , j1 , j2 , j5 , c0 , c2 , u2 , u1 , u5 , s1 , s2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u1 , u4 , u3 , s1 , s2 } J ∪ U ∪ {s1 , s2 } {c1 , j5 , c2 , u5 , c2 , c1 , v5 , v0 , s1 , s2 } {c0 , c1 , j5 , c0 , c2 , u5 , c2 , c1 , v5 , v0 , s1 , s2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 , c2 , c1 , v5 , v0 , s1 , s2 } {c0 , c1 , j1 , j2 , j3 , j4 , c0 , c2 , u2 , u1 , u4 , u3 , c2 , c1 , v3 , v4 , v 1 , v 2 , s 1 , s 2 } {c0 , c1 , j5 , c0 , c2 , u5 } ∪ V ∪ {s1 , s2 } {c1 , j5 , c2 , u5 } ∪ V ∪ {s1 , s2 } {c0 , c1 , j0 , j5 , c0 , c2 , u0 , u5 } ∪ V ∪ {s1 , s2 } J ∪ U ∪ V ∪ {s1 , s2 } {s1 , s6 } {c1 , s1 , s6 } {c0 , c2 , s1 , s6 } {c0 , c1 , c2 , s1 , s6 } {c0 , c2 , u1 , u4 , s1 , s6 } {u0 , u2 , u3 , u5 , s1 , s6 } {c0 , c2 , u0 , u2 , u3 , u5 , s1 , s6 } U ∪ {s1 , s6 } {c1 , c0 , c2 , u1 , u4 , s1 , s6 } {c1 , c0 , c2 , u0 , u2 , u3 , u5 , s1 , s6 } {c0 , c1 } ∪ U ∪ {s1 , s6 } {j1 , v4 , s1 , s6 } {c1 , j1 , c1 , v4 , s1 , s6 } {c0 , j1 , c2 , v4 , s1 , s6 } {c0 , c1 , j1 , c2 , c1 , v4 , s1 , s6 } {j1 , j4 , v4 , v1 , s1 , s6 } {c0 , c1 , j1 , j4 , c2 , c1 , v4 , v1 , s1 , s6 } {c1 , j3 , j5 , c1 , v0 , v2 , s1 , s6 } {c0 , c1 , j3 , j5 , c2 , c1 , v0 , v2 , s1 , s6 } {c1 , j1 , j3 , j5 , c1 , v4 , v0 , v2 , s1 , s6 } {c0 , c1 , j1 , j3 , j5 , c2 , c1 , v4 , v0 , v2 , s1 , s6 } {c0 , c1 , j0 , j2 , j3 , j5 , c2 , c1 , v3 , v5 , v0 , v2 , s1 , s6 } J ∪ V ∪ {s1 , s6 } {c0 , j1 , c0 , c2 , u1 , u4 , c2 , v4 , s1 , s6 } {c0 , c1 , j1 , c0 , c2 , u1 , u4 , c2 , c1 , v4 , s1 , s6 } {c0 , c1 , j1 , j4 , c0 , c2 , u1 , u4 , c2 , c1 , v4 , v1 , s1 , s6 } {c0 , c1 , j0 , j2 , j3 , j5 , co , c2 , u0 , u2 , u3 , u5 , c2 , c1 , v3 , v5 , v 0 , v 2 , s 1 , s 6 } {c0 , c1 , j1 } ∪ U ∪ {c2 , c1 , v4 , s1 , s6 } {c0 , j1 } ∪ U ∪ {c2 , v4 , s1 , s6 } {c0 , c1 , j1 , j4 } ∪ U ∪ {c2 , c1 , v4 , v1 , s1 , s6 } J ∪ U ∪ V ∪ {s1 , s6 } {s1 , s4 , s5 } {c0 , c1 , c2 , s1 , s4 , s5 } J ∪ U ∪ V ∪ {s1 , s4 , s5 } {s1 , s2 , s3 , s4 , s5 , s6 } {c0 , c1 , c2 , s1 , s2 , s3 , s4 , s5 , s6 } J ∪ U ∪ V ∪ {s1 , s2 , s3 , s4 , s5 , s6 }
455 Case
6.4
6.5 6.6
456
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
15.3 Classes of Quasilinear Functions of P3 that are not Subsets of [P31 ] The elements of the set L := [P31 ] ∪
n≥1 {f
n
1 ∈ P3 | ∃a ∈ E2 ∃f0 ∈ Pk1 ∃f1 , ..., fn ∈ P3,2 : f (x) = f0 (a+f1 (x1 )+f2 (x2 )+...+fn (xn ) (mod 2))},
are called quasilinear functions in this section. The set L agrees with the set L3 from Chapter 4. In Lemma 4.1, it was proven that L = P ol3 λ3 with λ3 := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ E3 } holds and that L is a submaximal class of P3 . L was examined already by I. A. Mal’tsev in [Mal 72] and [Mal 73b]. In [Mal 72], one also finds proof that L has exactly countable-infinite-many subclasses (see Theorem 8.1.5). As in [Lau 85] we will determine all subclasses of L with the aid of the 1299 subsemigroups of (P31 ; ). Further, we determine the order of theses subclasses. After introducing some notations in Section 15.3.1, we determine in Section 15.3.2 the subclasses of L whose functions take only values from the set {0, 1}. With the aid of an isomorphic mapping, we obtain all subclasses of L whose functions take only values from the set {0, 2}. In Section 15.3.3, all subclasses of L, whose functions take only values from {0, 1} or {0, 2}, are determined then as follows: We begin with the proof of certain (necessary and sufficient) criteria with which one can easily determine whether the union of certain classes, which are given in Section 15.3.3, is again a class. Then we determine the remaining classes, which do not fulfill the conditions of the criteria. With the aid of the subclasses of {f ∈ L | Im(f ) ⊆ {0, 1} ∨ Im(f ) ⊆ {0, 2}}, the remaining classes are easily described, as shown in Section 15.3.4. Notably, another kind of derivation of the subclasses of {f ∈ L | Im(f ) ⊆ {0, 1} ∨ Im(f ) ⊆ {0, 2}} in [Dem-M 89] can be found. In [Dem-M 89], one can also find rough drafts of lattices from such classes. 15.3.1 Some Notations We arrange to write only + instead of + (mod 2). Denote L the set of all linear functions of P2 , and let La,b := {f ∈ L | Im(f ) ⊆ {a, b}}, {a, b} ⊆ E3 , a = b. Let pra,b be a mapping from La,b onto L (⊆ P2 ), which is defined by
15.3 Classes of Quasilinear Functions of P3
457
pra,b f n = F n :⇐⇒ ∀x ∈ {a, b}n : g(f (x1 , ..., xn )) = F (g(x1 ), ..., g(xn )), where
a 0 g = , f n ∈ La,b , and F ∈ L. b 1
With the aid of an arbitrary subclass A of L (see Theorem 3.2.2) one can describe a subclass of La,b by −1 pra,b A := {f ∈ La,b | pra,b f ∈ A}.
Further, let Za,b be the notation for the set bcb P ol3 , {a, b, c} = E3 . bca For the description of certain isomorphic classes, we use the automorphisms ϕi : L −→ L, f n → s−1 i (f (si (x1 ), ..., si (xn ))), (i = 1, 2, ..., 6) from Section 15.2. Obviously, one can describes every subclass A of L in the form A = (A ∩ L0,1 ) ∪ (A ∩ L0,2 ) ∪ (A ∩ L1,2 ) ∪ (A ∩ [P31 [3]]). We determine, therefore, the subclasses of L0,1 in Section 15.3.2 and then in Section 15.3.3 the subclasses of L0,1 ∪ L0,2 that are not contained in L0,1 or L0,2 . With the aid of these results, it is easy to determine the remaining subclasses of L in Section 15.3.4. 15.3.2 Subclasses of L0,1 The following lemma results from the definition of the class L0,1 and the facts j0 = 1 + j1 + j2 , j3 = 1 + j2 , j4 = 1 + j1 , j5 = j1 + j2 immediately. Lemma 15.3.2.1 It holds: L0,1 = n≥1 {f n ∈ P3 | ∃a0 , ..., an , b1 , ..., bn ∈ E2 : n f (x) = a0 + i=1 (ai j1 (xi ) + bi j2 (xi ))}. With the aid of this lemma, one can see that the identities −1 A= {f n ∈ L0,1 | ∃a0 , ..., an , b1 , ..., bn ∈ E2 : pr0,1 n n≥1 f (x) = a0 + i=1 (a i j1 (xi ) + bi j2 (xi )) ∧ n (pr0,1 f )(y) = a0 + i=1 ai yi ∈ A}
458
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
and −1 Z2,c ∩pr0,1 A=
{f n ∈ L0,1 | ∃a0 , ..., an , c ∈ 2 : E n n≥1 f (x) = a0 + i=1 (a i (j1 (xi ) + cj2 (xi ))) ∧ n (pr0,1 f )(y) = a0 + i=1 ai yi ∈ A}
hold, where c ∈ E2 and A denotes a closed subset of L. The sets {f n ∈ L0,1 | ∃a1 , ..., an ∈E2 : Bc,r := n n≥1 f (x) = c + i=1 ai j2 (xi ) ∧ (at most r of the ai are 1) } and
Br := B0,r ∪ B1,r ,
where r ∈ {∞, 1, 2, ...}, are also subclasses of L0,1 . Obviously, Bc,∞ and B∞ do not have any basis. Therefore, they are also not finitely generated. Lemma 15.3.2.2 Let A be a subclass of L0,1 , which contains a function −1 (pr0,1 A) and i(x1 ) + j2 (x2 ) with i ∈ {j1 , j5 }. Then, it holds that A = pr0,1 A = [A ∪ {j1 (x1 ) + j2 (x2 )}] for every A with A ⊆ A and [pr0,1 A ] = pr0,1 A. −1 −1 Proof. Obviously, A ⊆ pr0,1 (pr0,1 A). Let f n ∈ pr0,1 (pr0,1 A) and f (x) = n a0 + i=1 (ai j1 (xi ) + bi j2 (xi )). We want to show that f belongs to A. Be cause n of pr0,1 f ∈ pr0,1 A there is a function f ∈ A with f (x) = a0 + (a j (x ) + b j (x )). A superposition over i(x ) + j (x ) 1 2 2 is obviously i 2 i i=1 i 1 i n the function q(x, x1 , ..., xn ) = i(x) + i=1 (bi + bi )j2 (xi ). Consequently, we −1 (pr0,1 A). have f (x) = q(f (x), x1 , ..., xn ) ∈ A and therefore A = pr0,1 Since f ∈ [A ] holds for every A with [pr0,1 A ] = pr0,1 A, the equation A = [A ∪ {j1 (x1 ) + j2 (x2 )}] also results from the one shown above.
Lemma 15.3.2.3 Let A be a subclass of L0,1 and pr0,1 A ⊆ [L1 ]. Then, −1 −1 (pr0,1 A) or Z2,0 ∩ pr0,1 (pr0,1 A) or the set Z2,1 ∩ A is either the set pr0,1 −1 pr0,1 (pr0,1 A). n Proof. For f (x) = a0 + i=1 (ai j1 (xi ) + bi j2 (xi )) denote Ch(f ) the set {(ai , bi ) | i = 1, 2, ..., n}. We distinguish the following three cases for A: Case 1: There exists an a ∈ E2 so that Ch(f ) ⊆ {(1, a), (0, 0)} for every f ∈ A holds. 01a In this case, f ∈ A preserves the relation , and we have A = 012 −1 pr0,1 (pr0,1 A) ∩ Z2,a . Case 2: A contains a function f with (0, 1) ∈ Ch(f ). W.l.o.g. let (a1 , b1 ) = (0, 1). Then, f (x1 , x2 ) := f (x1 , x2 , ..., x2 ) = a0 + j2 (x1 ) + r(x2 ), where r ∈ {c0 , j1 , j2 , j5 }. If r ∈ {j1 , j5 } then we have f (x1 , f (x2 , x2 )) = j2 (x1 ) + i(x2 ) ∈ A, i ∈ {j1 , j5 }; thus Lemma 15.3.2.3 follows from Lemma 15.3.2.2. If r ∈ {c0 , j2 } then we obtain f (x) :=
15.3 Classes of Quasilinear Functions of P3
459
f (x, f (x, x)) ∈ {j2 , j3 }. Since pr0,1 A ⊆ [L1 ], an inverse image h of the function H with H(y1 , y2 , y3 ) = y1 + y2 + y3 belongs to A because of Lemma 3.2.2.1. Consequently, h(x1 , f (x2 ), f (f (x2 ))) = i(x1 ) + j2 (x2 ), i ∈ {j1 , j5 }, is a function of A. Therefore, Lemma 15.3.2.3 also follows from Lemma 15.3.2.2 for r ∈ {c0 , j2 }. Case 3: A contains a function f with {(1, 0), (1, 1)} ⊆ Ch(f ). W.l.o.g. let (a1 , b1 ) = (1, 0) and (a2 , b2 ) = (1, 1). Then the function f (x1 , x1 , x2 , ..., x2 ) fulfills the condition of Case 2. Theorem 15.3.2.4 Let A be a subclass of L0,1 with A ⊆ [L10,1 ] ∪ B∞ . Then −1 −1 −1 A ∈ {pr0,1 (pr0,1 A), Z2,0 ∩ pr0,1 (pr0,1 A), Z2,1 ∩ pr0,1 (pr0,1 A)}.
Proof. If A ⊆ [L10,1 ] ∪ B∞ , there is a function f ∈ A with pr0,1 f ∈ [P21 ]. Let w.l.o.g. n (ai j1 (xi ) + bi j2 (xi )) ∈ A, f (x) = a0 + i=1
where a1 = 1 and (a2 , b2 ) = (0, 0). The following two cases are possible: Case 1: (a2 , b2 ) = (0, 1). One can obtain the function f (x1 , x2 , x3 ) = a0 + j1 (x1 ) + b1 j2 (x1 ) + j2 (x2 ) + p(x3 ) with p ∈ {c0 , j1 , j2 , j5 } by identifying the variables x3 , ..., xn from f . Then f (f (x1 , x2 , x2 ), x1 , x2 ) = i(x1 ) + j2 (x2 ), i ∈ {j1 , j5 }. −1 Thus by Lemma 15.3.2.2, A = pr0,1 (pr0,1 A). Case 1: a2 = 1. In this case, we have pr0,1 A ⊆ [L1 ] and our theorem follows from Lemma 15.3.2.3.
Theorem 15.3.2.5 The subclasses (= ∅) of [L10,1 ] ∪ B∞ are exactly [c0 ], [c1 ], [c0 , c1 ], [Ji ], [Ja ] ∪ Br , [Jb ] ∪ B0,r ∪ B1,s , [Jc ] ∪ B0,r , [Jd ] ∪ B1,r , where {r, s} ⊂ {∞, 2, 3, ...}, 1 ≤ i ≤ 41, a ∈ {27, 33, 36, 38, 39, 40, 41}, b ∈ {27, 33, 36, 40}, c ∈ {4, 13, 16, 18, 23, 27, 28, 30, 33, 34, 36, 40} and d ∈ {7, 14, 19, 21, 24, 27, 29, 31, 33, 35, 36, 40}. Proof. One obtains the statements of the theorem easily by means of the properties of the functions of [L10,1 ] ∪ B∞ and the results from Section 15.2 about the subsemigroups of (P31 ; ). Lemma 15.3.2.6 Let A be a subclass of L0,1 and pr0,1 A ⊆ [L1 ]. Then there is a function h3 ∈ A with h(x1 , x2 , x3 ) := i(x1 ) + i(x2 ) + i(x3 ), i ∈ {j1 , j5 }, and it holds A = [A1 ∪ {h}].
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Proof. By Lemma 3.2.2.1 we have pr0,1 A = [(pr0,1 A)1 ∪ {pr0,1 h}]. If A = −1 −1 (pr0,1 A), a ∈ E2 , then Lemma 15.3.2.6 holds. If A = pr0,1 (pr0,1 A) Z2,a ∩ pr0,1 then j1 (x1 ) + j2 (x2 ) ∈ A. By Lemma 15.3.2.2 and the above remark, we have A = [A1 ∪ {h, j1 (x1 ) + j2 (x2 )}], where h ∈ A is an inverse image of the function H 3 with H(y1 , y2 , y3 ) = y1 + y2 + y3 . Because of {j1 , j5 } ⊆ A, we can assume h(x1 , x2 , x3 ) = j1 (x1 ) + j1 (x2 ) + j1 (x3 ), and it holds h(x1 , x2 , j5 (x2 )) = j1 (x1 ) + j1 (x2 ) ∈ [A1 ∪ {h}]; i.e., we have A = [A1 ∪ {h}] −1 (pr0,1 A). Since there are no other possibilities because in the case A = pr0,1 of Theorem 15.3.2.4, our Lemma 15.3.2.6 is valid. Theorem 15.3.2.7 Let A be a subclass of L0,1 . Then ⎧ 2, if A ⊆ [L10,1 ] ∪ B∞ ∧ (C ∩ A1 = ∅ ∨ pr0,1 A ⊆ [L1 ]), ⎪ ⎪ ⎨ 3, if pr0,1 A ⊆ [L1 ] ∧ C ∩ A1 = ∅, ord A = 1 1 ⎪ ⎪ ⎩ t, if A ⊆ [L0,1 ] ∪ B∞ ∧ A ∩ (Bt \[A ]) = ∅ ∧ 1 (∀ r ≥ t : A ∩ (Br \[A ]) = ∅). Proof. By Theorem 15.3.2.4, the following three cases are possible for A: −1 Case 1: A = Z2,a ∩ pr0,1 (pr0,1 A), a ∈ E2 . In this case, ord A = ord pr0,1 A. Then, the statements of the theorem follow from Theorem 3.1.1. −1 (pr0,1 A) and A ⊆ [L10,1 ] ∪ B∞ . Case 2: A = pr0,1 By Lemma 15.3.2.6 and 15.3.2.2, it holds in this case: ≤ 3 if pr0,1 A ⊆ [L1 ], ord pr0,1 A ≤ ord A = 2 if pr0,1 A ⊆ [L1 ]. As is generally known, only the classes of L, which do not contain any constant functions and which are not subsets of [L1 ], have the order 3. If a constant function belongs to pr0,1 A then the function h from Lemma 15.3.2.6 is obviously a superposition over binary functions of A. Thus the statements of the theorem hold in Case 2. Case 3: A ⊆ [L10,1 ∪ B∞ . In this case, the order of A follows from Theorem 15.3.2.5 and from [L10,1 ] ∪ Br ⊂ [L10,1 ] ∪ Br+1 , 2 ≤ r ≤ ∞. One can obtain the following lemma as a direct consequence from Theorem 15.3.2.7: Theorem 15.3.2.8 The only finitely generated subclasses of L0,1 are the classes [Ja ]∪B∞ , [Jb ]∪B0,∞ , [Jc ]∪B1,∞ , [Jd ]∪B0,∞ ∪B1,s and [Jd ]∪B0,s ∪B1,∞ , where a ∈ {27, 33, 36, 38, 39, 40, 41}, b ∈ {4, 13, 16, 18, 23, 27, 28, 30, 33, 34, 36, 40}, c ∈ {7, 14, 19, 21, 24, 27, 29, 31, 33, 35, 36, 40}, d ∈ {27, 33, 36, 40} and 2 ≤ r, s ≤ ∞.
15.3 Classes of Quasilinear Functions of P3
461
15.3.3 The Subclasses of L0,1 ∪ L0,2 That Are Not Subclasses of L0,1 or L0,2 The aim of this section is first of all the derivation of a necessary and sufficient criterion with which one can find out whether a set A1 ∪ A2 (A1 ⊆ L0,1 , A2 ⊆ L0,2 ) is closed. Put A A := {f g | f ∈ A ∧ g ∈ A }. Obviously, it holds: Lemma 15.3.3.1 Let A1 and A2 be subclasses of L with A1 ⊆ L0,1 and A2 ⊆ L0,2 . Then, A1 ∪ A2 is closed if and only if A1 A2 ⊆ A1 and A2 A1 ⊆ A2 . Lemma 15.3.3.2 Let A1 and A2 be subclasses of L, A1 ⊆ L0,1 , A2 ⊆ L0,2 , (A1 ∪ A2 )1 a subsemigroup of (P31 ; ) and {i, j} = {1, 2}. Then (a) A11 ⊆ {c0 , c1 , j1 , j4 } =⇒ A1 A2 ⊆ A1 , (b) A12 ⊆ {c0 , c2 , u2 , u3 } =⇒ A2 A1 ⊆ A2 , (c) pr0,i Ai ⊆ [L1 ] =⇒ Ai Aj ⊆ Ai , (d) (pr0,1 A1 ⊆ [L1 ] ∧ j1 (x1 ) + j2 (x2 ) ∈ A1 ∧ A12 ⊆ {c0 , c2 , u2 , u3 }) =⇒ A1 A2 ⊆ A1 . Proof. (a): By Section 15.3.2 and by the assumptions over A1, A 1 is asub 0 0 class of Z2,0 ∩ L0,1 = [c1 , j1 (x1 ) + j1 (x2 )]. Thus, because of j1 , = 2 0 we have A1 A2 = A1 . (b): By assumption 15.3.2, A2 is a subset of ϕ2 (Z2,0 ∩L0,1 ). Thus, and Section 0 0 , we have A2 A1 ⊆ A2 . = because of u2 1 0 (c): Let w.l.o.g. pr0,1 A1 ⊆ [L1 ]. Then, because of Lemma 15.3.2.6, A1 = [A11 ∪ {h}], where h ∈ A1 is an arbitrary inverse image of the function H(y1 , y2 , y3 ) = y1 + y2 + y3 . Suppose, A1 A2 ⊆ A1 holds. Then, A1 := [A1 ∪ (A1 A2 )] is a closed set with A1 ⊃ A1 and A1 = [(A1 )1 ∪ {h}]. Consequently, we have (A1 )1 ⊃ A11 , i.e., there is a function g ∈ A1 and there are certain functions p1 , ..., pn ∈ (A1 ∪ A2 )1 with g (x) := g(p1 (x), p2 (x), ..., pn (x)) ∈ A11 . However, we have also g(x1 , ..., xn ) = g0 (g1 (x1 ), g2 (x2 ), ..., gn (xn )) for certain functions g0 ∈ [{h}] and g1 , ..., gn ∈ A11 . Therefore, we obtain g = g0 (g1 p1 , g2 p2 , ..., gn pn ). Moreover, by assumption, gi pi ∈ (A1 ∪A2 )1 , i = 1, 2, ..., n, and A1 = [A1 ]. Therefore, we have g ∈ A1 , contrary to the assumption. (d): Let pr0,1 A1 ⊆ [L1 ], j1 (x1 ) + j2 (x2 ) ∈ A1 and A12 ⊆ {c0 , c2 , u2 , u3 }. Then, by Section 15.3.2, A1 = [A11 ∪ {j1 (x1 ) + j2 (x2 )}] and A2 ⊆ ϕ2 (Z2,0 ∩ L0,1 ) = [c2 , u2 (x1 ) ⊕ u2 (x2 )] with xy x⊕y 00 0 02 2 . 20 2 22 0
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
0 0 = , j2 (a ⊕ u2 (x1 ) ⊕ u2 (x2 ) ⊕ ... ⊕ um (xm )) = 2 0 j2 (a) + j2 (x1 ) + j2 (x2 ) + ... + j2 (xm ) and (A1 ∪ A2 )1 is closed in respect to , it follows A1 A2 ⊆ A1 .
Since j1
Theorem 15.3.3.3 Let A1 and A2 be subclasses of L, A1 ⊆ L0,1 , A2 ⊆ L0,2 , A1 ⊆ [L10,1 ] ∪ B∞ ∪ ϕ2 (Z2,0 ∩ L0,1 ), A2 ⊆ ϕ2 ([L10,1 ] ∪ B∞ ) ∪ (Z2,0 ∩ L0,1 ) and A11 ⊆ {c0 , c1 , j1 , j4 } or A12 ⊆ {c0 , c1 , u2 , u3 }. Then, A1 ∪ A2 is closed if and only if (A1 ∪ A2 )1 is a subsemigroup of (P31 ; ). Proof. If A1 ∪ A2 is closed, then (A1 ∪ A2 )1 is obviously a subsemigroup of (P31 ; ). Let (A1 ∪ A2 )1 be a closed set in respect to . Then the following three cases are possible: Case 1: (A1 ∪ A2 )1 ⊆ {c0 , c1 , c2 , j1 , j4 , u2 , u3 }. In this case, by Lemma 15.3.3.2, (a), (b), and Lemma 15.3.3.1, A1 ∪ A2 is closed. Case 2: A11 ⊆ {c0 , c1 , j1 , j4 } and A12 ⊆ {c0 , c2 , u2 , u3 }. Because of Lemma 15.3.3.2, (b) it holds that A2 A1 ⊆ A2 . Since A1 is not a subset of [L10,1 ] ∪ B∞ , we have pr0,1 A1 ⊆ [L1 ] or pr0,1 A1 ⊆ [L1 ] and j1 (x1 ) + j2 (x2 ) ∈ A1 . With the aid of Lemma 15.3.3.2, (c), (d): A1 A2 ⊆ A1 . Thus, because of Lemma 15.3.3.1, A1 A2 is closed. Case 3: (A11 ⊆ {c0 , c1 , j1 , j4 } and (A12 ⊆ {c0 , c2 , u2 , u3 }. Because of ϕ2 ({c0 , c1 , j1 , j4 }) = {c0 , c2 , u2 , u3 } the classes that fulfill the conditions of the third case are isomorphic to such classes that fulfill the conditions of the second case. Therefore, Theorem 15.3.3.3 is also valid in the third case. Theorem 15.3.3.4 Let A1 and A2 be subclasses of L, A1 ⊆ L0,1 , A2 ⊆ L0,2 , A1 ∪ A2 ⊆ [L1 ], A11 ⊆ {c0 , c1 , j1 , j4 } and A12 ⊆ {c0 , c2 , u2 , u3 }. Then, A1 ∪ A2 is closed if and only if pr0,1 A1 ⊆ [L1 ] and pr0,2 A2 ⊆ [L1 ] hold and (A1 ∪ A2 )1 is closed in respect to . Proof. If pr0,i Ai ⊆ [L1 ] for i = 1, 2 and (A1 ∪ A2 )1 is a subsemigroup of (P31 ; ), then Theorem 15.3.3.2, (c) and Lemma 15.3.3.1 imply that A1 ∪ A2 is closed. } Let A1 ∪ A2 be a subclass of L. Since, by assumption, A11 ⊆ {c0 , c1 ,j1 , j4 0 0 1 and A12 ⊆ {c0 , c2 , u2 , u3 }, there is a function p1 ∈ A11 with p ∈ 2 10 0 0 2 and a function q ∈ A12 with p ∈ . Because A1 ∪ A2 is closed, we 1 20 have p A2 ⊆ A1 and q A1 ⊆ A2 . Obviously, from this and the assumption A1 ∪ A2 ⊆ [L1 ], it follows that A1 ⊆ [L1 ] and A2 ⊆ [L1 ]. Suppose pr0,1 A1 ⊆
15.3 Classes of Quasilinear Functions of P3
463
[L1 ]. Then, by Section 15.3.2, a function t(x1 , x2 ) = g(x1 )+j2 (x2 ) with g ∈ A11 belongs to A1 . Therefore the function if g ∈ {j0 , j1 , j4 , j5 }, t(x1 , q(x2 )) t (x1 , x2 ) := t(q(x1 ), q(x2 )) if g ∈ {j2 , j3 }, belongs to A1 and it holds pr0,1 t ∈ [L1 ] obviously, contrary to the assumption. Consequently, pr0,1 A1 ⊆ [L1 ]. Similarly, one can show that pr0,2 A2 ⊆ [L1 ]. To complete the description of all subclasses of L0,1 ∪ L0,2 , which are not subclasses of L0,1 , L0,2 or [L1 ], we are only still missing the subclasses of [L10,1 ] ∪ B∞ ∪ ϕ2 (Z2,0 ∩ L0,1 ) and of ϕ2 (L10,1 ∪ B∞ ) ∪ (Z2,0 ∩ L0,1 ) because of Theorems 15.3.3.3 and 15.3.3.4. Since the two sets to be examined are isomorphic, determining only the subclasses of one suffices, as in the following theorem. Theorem 15.3.3.5 The subclasses of [L10,1 ] ∪ B∞ ∪ ϕ2 (Z2,0 ∩ L0,1 ), which are not subclasses of [L1 ], L0,1 or L0,2 , are the following classes: A ∪ A , where A ∈ {[c0 , c1 ], [Ja ] ∪ B∞ , [Jb ] | a ∈ {27, 33, 36, 38, 39, 40, 41}, b ∈ {3, 12, 25} } and A ∈ { ϕ2 (Z2,0 ∩ L0,1 ), ϕ2 ([c0 , j1 (x1 ) + j1 (x2 )]) }, [Jc ] ∪ B0,∞ ∪ ϕ([c0 , j1 (x1 ) + j1 (x2 )]), c ∈ {4, 13, 16, 18, 23, 28, 30, 34}, [Jd ] ∪ B1,∞ ∪ ϕ2 ([c0 , j1 (x1 ) + j1 (x2 )]), d ∈ {14, 24}, and [A1 ] ∪ Br , [Je ] ∪ B0,r ∪ [c0 , u2 ], [Jf ] ∪ B1,r ∪ [c0 , u2 ], [Jg ] ∪ Bα,r ∪ Bβ,r−1 ∪ [A2 ], [Jg ] ∪ B0,r ∪ B1,s ∪ [c0 , u2 ], where e ∈ {4, 13, 16, 18, 23, 27, 28, 30, 33, 34, 36, 40}, f ∈ {7, 14, 19, 21, 24, 27, 29, 31, 33, 35, 36, 40}, g ∈ {27, 33, 36, 40}, 2 ≤ r, s ≤ ∞, {α, β} = E2 , A1 is a subsemigroup of J ∪ U25 with (A1 \{c0 }) ∩ U25 = ∅, which contains {j2 , j3 }, and A2 ∈ { [c2 ], [c0 , c2 , u2 ] }. Proof. The theorem follows from Sections 15.2 and 15.3.2. 15.3.4 The Remaining Subclasses of L Obviously, Lemma 15.3.3.1 implies the following Lemma 15.3.4.1 Let A1 , A2 and A3 be subclasses of L with A1 ⊆ L0,1 , A2 ⊆ L0,2 and A3 ⊆ L1,2 . Then A1 ∪ A2 ∪ A3 is closed if and only if A1 ∪ A2 , A1 ∪ A3 and A2 ∪ A3 are closed sets and (A1 ∪ A2 ∪ A3 )1 is a semigroup. Since the sets L0,1 ∪L0,2 , L0,1 ∪L1,2 , L0,2 ∪L1,2 are isomorphic, one has a complete description of the subclasses of L0,1 ∪L0,2 ∪L1,2 through Lemma 15.3.4.1
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
and Sections 15.3.2 and 15.3.3. The following theorem now gives information about the missing subclasses of L. Theorem 15.3.4.2 The subclasses of L, which are not subsets of [L]1 and which contain at least a permutation, are A1 ∪ [s1 ] (A1 is a subclass of L0,1 ∪ L0,2 ∪ L1,2 ), A2 ∪[s1 , si ] (i ∈ {2, 3, 6}, A2 is a subclass of L0,1 ∪L0,2 ∪L1,2 with si A2 ⊆ A2 , A12 ∪ {s1 , si } is a subsemigroup of (P31 ; ), L0,1 ∪ L0,2 ∪ L1,2 ∪ [s1 , s4 , s5 ] and L. Proof. The theorem follows from Section 15.2 and from the properties of the functions of L.
15.4 The Subclasses of [O 1 ∪ {max}] 15.4.1 Some Descriptions of the Class M Some functions of P3 , which are used in Sections 15.4.2–15.4.6, are defined in the following two tables (see also Table 15.1). Table 15.12 Table 15.11 x 0 1 2
j2 0 0 1
j5 0 1 1
u2 0 0 2
u5 0 2 2
v2 1 1 2
v5 1 2 2
s1 0 1 2
x 0 0 0 1 1 1 2 2 2
y x ∨ y := max(x, y) 0 0 1 1 2 2 0 1 1 1 2 2 0 2 1 2 2 2
Our object of investigation is the set M := [{c0 , c1 , c2 , j2 , j5 , u2 , u5 , v2 , v5 , max}], which, by [Mac 79] (see Theorem 14.1.4), is a maximal class of the class 012001 O := P ol3 . 012122 M can also be described in the form [O1 ∪ {max}] or
n≥1
{f n ∈ P3 | ∃f1 , ..., fn ∈ O1 : f (x1 , ..., xn ) = f1 (x1 ) ∨ ... ∨ fn (xn )}.
15.4 The Subclasses of [O1 ∪ {max}]
465
15.4.2 Some Lemmas and a Rough Partition of the Subclasses of M One checks the following lemma easily: Lemma 15.4.2.1 (a) For every function f n ∈ M there is exactly a representation of the following form:
with
f (x1 , ..., xn ) = f1 (x1 ) ∨ ... ∨ fn (xn )
(15.1)
fi (x) := f (0, ..., 0, x, 0, ..., 0)
(15.2)
i−1
(i = 1, ..., n). (b) If the function f is given in the form (15.1) with (15.2), for every g ∈ M 1 it holds: (g f )(x1 , ..., xn ) = (g f1 )(x1 ) ∨ ... ∨ (g fn )(xn ). We agree to represent functions f n of M in the form (15.1) in which the functions fi are given by (15.2). Further, denote F (f ) the set of all functions fi of (15.2) that describe the function f . Let numf (fi ) be the number of occurrence of function fi in (15.1) for f , where fi is defined by (15.2). If f arises from the context, instead of F (f ), we will write only F , and instead of numf (fi ), we will write only num(fi ). Lemma 15.4.2.2 is the basis for the following theorems about bases and generating systems for subclasses of M . Lemma 15.4.2.2 Let f n ∈ M , n ≥ 2, f (x1 , ..., xn ) := f1 (x1 ) ∨ ... ∨ fn (xn ),
(15.3)
F := {f1 , ..., fn }, {c0 , c1 , c2 } ∩ F = ∅ (i.e., all variables of f are essential) and denote num(g) the number of functions g ∈ F that occur in (15.3). Then (a) f ∈ [[{f }]2 ] if and only if the function f fulfills at least one of the following conditions: 1) s1 ∈ F and u5 ∈ F ; 2) num(s1 ) = 1 and F ∈ {{s1 , u5 }, {s1 , u2 , u5 }}; 3) F ⊆ {u2 , u5 }; 4) F ∈ {{j5 }, {j2 , u5 }, {j5 , u2 }, {j5 , u5 }, {j2 , j5 , u2 }, {j2 , j5 , u5 }, {j2 , u2 , u5 }, {j5 , u2 , u5 }, {j2 , j5 , u2 , u5 }}; 5) num(j5 ) = 1 and F = {j2 , j5 }; 6) num(v2 ) = 1 and F = {v2 , v5 }; 7) num(u2 ) ≥ 2 and F = {j2 , u2 }; 8) n = 2 and F ∈ {{j2 }, {v5 }, {j2 , u2 }}.
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
(b) f ∈ [[{f }]3 ] and f ∈ [[{f }]2 ] if and only if the function f fulfills at least one of the following conditions: 1) num(s1 ) ≥ 2 and u5 ∈ F ; 2) num(s1 ) = 1, u5 ∈ F and F ∈ {{s1 , u5 }, {s1 , u2 , u5 }}; 3) num(j5 ) ≥ 2 and F = {j2 , j5 }; 4) num(u2 ) = 1 and F = {j2 , u2 }; 5) num(v2 ) ≥ 2 and F = {v2 , v5 }; 6) n = 3 and F ∈ {{j2 }, {v5 }}. (c) f ∈ [[{f }]n−1 ] and n ≥ 4 if and only if F ∈ {{j2 }, {v5 }, {j2 , u2 }} and num(u2 ) ≤ 1. Proof. Since, by assumption, all variables of f are essential, we have F ⊆ {j2 , j5 , u2 , u5 , v2 , v5 }. If {v2 , v5 } ∩ F = ∅ then F ⊆ {v2 , v5 }. Thus for f the following cases are possible: Case 1: s1 ∈ F . Case 1.1: u5 ∈ F . Let w.l.o.g. f1 = s1 . The functions ht (x, y) := f (x, ..., x, y, x, ..., x) = x ∨ ft (y) t−1
are superpositions over f for every t ∈ {2, 3, ..., n}. Then one can obtain function f as a superposition over these functions as follows: (...((hn hn−1 ) hn−2 )... h3 ) h2 . Therefore, f ∈ [[{f }]2 ] in Case 1. Case 1.2: u5 ∈ F . Let w.l.o.g. f1 = s1 and f2 = u5 . Then the ternary functions x ∨ u5 (y) ∨ fi (z) (i = 3, ..., n) are superpositions over f , and these functions form a generating system for f . Therefore, f ∈ [[{f }]3 ]. This is reducible to f ∈ [[{f }]2 ] iff num(s1 ) = 1 and F ∈ {{s1 , u5 }, {s1 , u2 , u5 }}. Case 2: F ⊆ {j2 , j5 , u2 , u5 }. Case 2.1: F = {j2 }. Because of j2 j2 = c0 , we have j2 (x1 ) ∨ ... ∨ j2 (xr ) ∈ [{j2 (x1 ) ∨ ... ∨ j2 (xr−1 )}] for all r ≥ 2. Case 2.2: F = {j5 }. In this case, we have f ∈ [{j5 (x) ∨ j5 (x2 )}], i.e., f ∈ [[{f }]2 ]. Case 2.3: F = {j2 , j5 }. By (...((g g) g)...) g, where g(x, y) := j5 (x) ∨ j2 (y), one can obtain all functions of the form j5 (x1 ) ∨ j2 (x2 ) ∨ ... ∨ j2 (xt ) for t ≥ 2. Thus f ∈ [[{f }]2 ], if num(j5 ) = 1. If num(j5 ) ≥ 2 then j5 (x) ∨ j5 (y) ∨ j2 (z) belongs to [{f }]3 and we have f ∈ [[{f }]3 ] and f ∈ [[{f }]2 ]. Case 2.4: F ⊆ {u2 , u5 }.
15.4 The Subclasses of [O1 ∪ {max}]
467
Since up uq = uq for all p, q ∈ {2, 5}, it follows from Lemma 15.4.2.1, (b) that f ∈ [[{f }]2 ]. Case 2.5: F = {j2 , u2 }. Because of j2 u2 = j2 , u2 j2 = c0 , u2 u2 = u2 and u2 (x) ∨ j2 (x) = u2 we have in this case: num(u2 ) ≥ 2 =⇒ {j2 (x) ∨ u2 (y), u2 (x) ∨ u2 (y)} ⊆ [{f }]2 =⇒ f ∈ [[{f }]2 ] and
num(u2 ) = 1 =⇒ f ∈ [[{f }]n−1 ].
Case 2.6: F = {j2 , u5 }. Since ∆n−1 f = u5 , the functions u5 and j2 (u5 (x)) ∨ u5 (y) = j5 (x) ∨ u5 (y) belong to [{f }]2 . Thus by j5 u5 = j5 and u5 j5 = u5 , functions of the form j5 (x1 ) ∨ ... ∨ j5 (xr ) ∨ u5 (xr+1 ) ∨ ... ∨ u5 (xm ) are superpositions over [{f }]2 for arbitrary m > r ≥ 1. From this and by j5 (j2 (x1 ) ∨ u5 (x2 )) ∨ u5 (x2 ) = j2 (x1 ) ∨ u5 (x2 ) ) follows then that f ∈ [[{f }]2 ]. Case 2.7: F = {j5 , u2 }. If num(u2 ) = 1 or num(j5 ) ≥ 2, we have n = 2 or h(x, y) := j5 (x) ∨ j5 (y) ∨ u2 (z) ∈ [{f }]3 . Thus, h(x, y, y) = j5 (x) ∨ y ∈ [{f }]2 . Then functions of the form x1 ∨j5 (x2 )∨...∨j5 (xt ) (t ≥ 2) are superpositions over h. Replacing x1 by j5 (x1 ) ∨ u2 (x2 ) ∈ [{f }]2 and then identifying variables shows that f ∈ [[{f }]2 ] in the case num(u2 ) = 1. If we have num(u2 ) ≥ 2 and num(j5 ) = 1, then the function j5 (x) ∨ u2 (y) ∨ u2 (z) belongs to [{f }]3 and, therefore, the function x ∨ u2 (y) also belongs to [{f }]3 . From this, f ∈ [[{f }]2 ]. Case 2.8: F = {j5 , u5 }. Because of j5 (j5 (x1 )∨u5 (x2 ))∨u5 (j5 (x3 )∨u5 (x4 )) = j5 (x1 )∨j5 (x2 )∨u5 (x3 )∨ u5 (x4 ) we have f ∈ [[{f }]2 ]. Case 2.9: F = {j2 , j5 , u2 }. In this case, j2 (x) ∨ y and j5 (x) ∨ u2 (y) are some superpositions over f . Thus f ∈ [[{f }]2 ] is an easy conclusion from our considerations of Cases 1 and 2.7. Case 2.10: F = {j2 , j5 , u5 }. Some superpositions over f are u5 = ∆n−1 f , j2 (x) ∨ u5 (y) and j5 (x) ∨ u5 (y). Hence, and by Case 2.8, we have f ∈ [[{f }]2 ]. Case 2.11: F = {j2 , u2 , u5 }. Then, the functions u5 = ∆n−1 f , u2 (x) ∨ u5 (y), j2 (x) ∨ u5 (y) and j2 (u5 (x)) ∨ u5 (y) = j5 (x) ∨ u5 (y) are superpositions over f . Using considerations from Cases 2.4, 2.6, and 2.8, we obtain f ∈ [[{f }]2 ]. Case 2.12: F = {j5 , u2 , u5 }. Then the functions x∨u5 (y), u2 (x)∨u5 (y) and j5 (x)∨u5 (y) are superpositions over f . By Cases 2.4 and 2.8, we get f ∈ [[{f }]2 ]. Case 2.13: F = {j2 , j5 , u2 , u5 }. Since j2 (x) ∨ u5 (y), j5 (x) ∨ u5 (y), u2 (x) ∨ u5 (y) ∈ [{f }]2 , one can obtain f ∈ [[{f }]2 ] by proceeding to the above cases analogously. Case 3: F ⊆ {v2 , v5 }.
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Case 3.1: F = {v2 }. Obviously, f ∈ [{v2 (x) ∨ v2 (y)}], i.e., f ∈ [[{f }]2 ]. Case 3.2: F = {v5 }. Because of v5 v5 = c2 we have f ∈ [[{f }]n−1 ]. Case 3.3: F = {v2 , v5 }. This case resembles Case 2.3. Thus we have: num(v2 ) = 1 =⇒ f ∈ [[{f }]2 ] and
num(v2 ) ≥ 2 =⇒ f ∈ [[{f }]3 ] ∧ f ∈ [[{f }]2 ].
Next, we want to consider a rough partition of the lattice L3 (M ). Let R := {f ∈ M | |Im(f )| ≤ 2}. Then every subclass T of M has the form (T ∩ R) ∪ (T ∩ P ol3
0 ), 2
(15.4)
since all functions of M with |Im(f )| ≥ 3 have the property f (0, ..., 0) = 0 and f (2, ..., 2) = 2. Thus one can obtain all subclasses of M if every subclass T that fulfills exactly one of the following conditions (I)–(IV ) is determined: (I) T ⊆ [M 1 ]; (II) T ⊆ R and T ⊆ [M1 ]; 0 , T ⊆ R and T ⊆ [M 1 ]; (III) T ⊆ M ∩ P ol3 2 0 (IV ) ∃T1 ∈ L3 (R)\{∅} ∃T2 ∈ L3 (M ∩ P ol3 )\L3 (R) : 2 1 T = T1 ∪ T2 ∧ T ⊆ [M ]. We determine the subclasses of M in Sections 15.4.3–15.4.6, in compliance with the above partition (I)–(IV) of the subclasses. First, we determine the maximal classes of M . Theorem 15.4.2.3 M has exactly 8 maximal classes. These classes are: (1) M ∩ P ol{0} = {f ∈ M | F (f ) ⊆ {c0 , j2 , j5 , u2 , u5 , s1 }}; (2) M ∩ P ol{2} = {f ∈ M | F (f ) ∩ {c2 , u2 , u5 , v2 , v5 , s1 } = ∅}; (3) M ∩ P ol{1, 2} = {f ∈ M | F (f ) ∩ {c1 , c2 , j5 , u5 , v2 , v5 , s1 } = ∅};
(4) M ∩ P ol
0120 0121
15.4 The Subclasses of [O1 ∪ {max}]
469
= {f ∈ M | F (f ) ⊆ {c0 , c1 , j2 , j5 , u2 , s1 } ∨ F (f ) ⊆ {c1 , c2 , v2 }}; 0121 (5) M ∩ P ol 0122 = {f ∈ M |F (f ) ⊆ {c0 , c1 , j5 , u5 , s1 } ∨ F (f ) ⊆ {c1 , c2 , v2 , v5 }}; 01201 (6) M ∩ P ol 01222 = {f ∈ M |F (f ) ⊆ {c0 , c2 , u2 , u5 , s1 } ∨ F (f ) ⊆ {c1 , v2 , v5 }}; 01201 (7) M ∩ P ol 01212 = {f ∈ M | F (f ) ⊆ {c0 , c1 , j2 , j5 , s1 } ∨ F (f ) ⊆ {c1 , c2 , v2 , v5 }}; (8) [{s1 }] ∪ R := [{s1 }] ∪ {f ∈ M | |Im(f )| ≤ 2}. Proof. Since M = [M 1 ∪ {max}] and max ∈ T for all classes T , which are defined by (1)–(7), it is easy to prove that the classes (1)–(7) are M -maximal. One can show the M -maximality of [{s1 }] ∪ R as follows: Let f ∈ M \([{s1 }] ∪ R). Since c0 ∈ R, one of the following 9 functions is a superposition over R ∪ {f }: x ∨ y, x ∨ g(y) (g ∈ {j2 , j5 , u2 , u5 }), h1 (x) ∨ h2 (y) (h1 ∈ {j2 , j5 }, h2 ∈ {u2 , u3 }). Through substitution of x, y by certain functions of {j2 , j5 , u2 , u5 }, one can reduce these 9 cases to the case: t(x, y) := j5 (x)∨u2 (y) ∈ [R∪{f }]. Because of j5 (t(x, u5 (y)) = j5 (x)∨j5 (y) and u5 (j2 (x)∨j2 (y)) = u2 (x)∨u2 (y) it holds x∨y = t(j5 (x)∨j5 (y), u2 (x)∨u2 (y)). Hence [R ∪ {f }] = M and [{s1 }] ∪ R is M -maximal. We still have to show that the class M does not have any further maximal classes. Suppose T ⊂ M is an M -maximal class that is different from the 8 M -maximal classes listed above. Then, there is for every i ∈ {1, 2, ..., 8}, a certain function fi ∈ T that does not belong to the class (i). Consequently, it holds f2 ∈ {c0 , c1 , j2 , j5 } for f2 (x) := f2 (x, x, ..., x), and f3 (a1 , a2 , ..., an ) = 0 for certain a1 , a2 , ..., an ∈ {1, 2}. Hence, c0 ∈ T , since j2 j2 = c0 and f3 (g1 (x), ..., gn (x)) = c0 , if f2 ∈ {c1 , j5 } and x if ai = 2, gi (x) := f2 (x) if ai = 1 (i = 1, 2, ..., n). Some unary functions ft with f4 ∈ {u5 , v5 }, f5 ∈ {j2 , u2 }, f6 ∈ {j2 , j5 } and f7 ∈ {u2 , u5 } are superpositions over {ft , c0 } (t = 4, 5, 6, 7). It is easy to check that {j2 , j5 , u2 , u5 } ⊂ [{f4 , f5 , f6 , f7 }] holds. In the above proof of the M -maximality of [{s1 }] ∪ R, we have shown already that max ∈ [{j2 , j5 , u2 , u5 , f8 }] holds. Since in addition ui ∨ c1 = vi (i = 2, 5), v2 (c0 ) = c1 and v5 (c1 ) = c2 , we have M 1 ∪{max} ⊆ T . Consequently, T = M , in contradiction to T ⊂ M .
470
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
15.4.3 The Subclasses of [M 1 ] Since all subclasses of [P31 ] were already determined in Section 15.2, one obtains the following theorem as a consequence of Theorem 15.2.1: Theorem 15.4.3.1 [M 1 ] has exactly 190 pairwise distinct subclasses Hi . These classes Hi are defined in Table 15.13 through Hi1 for i ∈ {1, 2, ..., 95}, and through H95+i := Hi ∪ [{s1 }] for i = 1, 2, ..., 95.
i 1 4 7 10 13 16 19 22 25 28 31 34 37 40 43 46 49 52 55 58 61 64 67 7O 73 76 79 82 85 88 91 94
Hi1 ∅ {c2 } {c1 , c2 } {j2 , c0 } {j2 , c0 , c1 } {j2 , j5 , c0 , c1 } {u2 , c0 } {u5 , c2 } {u5 , c0 , c2 } {u2 , u5 , c0 , c2 } {v2 , c2 } {v2 , c1 , c2 } {j5 , c1 , c2 } {j2 , j5 , c0 , c1 , c2 } {u2 , c0 , c1 , c2 } {v2 , c0 , c1 } {v2 , v5 , c0 , c1 , c2 } {j5 , u5 , c0 } {j5 , u5 , c0 , c1 , c2 } {j2 , j5 , u2 , c0 , c1 } {j2 , j5 , u2 , u5 , c0 , c1 , c2 } {j5 , v2 , c1 } {j5 , v2 , c0 , c1 , c2 } {j2 , j5 , v2 , c0 , c1 } {j5 , v2 , v5 , c0 , c1 , c2 } {u2 , v2 , c0 , c1 } {u5 , v5 , c2 } {u5 , v2 , v5 , c2 } {u2 , u5 , v2 , v5 , c2 } {j2 , u2 , v2 , c0 , c1 , c2 } {j2 , j5 , u2 , v2 , c0 , c1 } {j5 , u5 , v2 , v5 , c0 , c1 , c2 }
i 2 5 8 11 14 17 20 23 26 29 32 35 38 41 44 47 50 53 56 59 62 65 68 71 74 77 80 83 86 89 92 95
Table 15.13 Hi1 {c0 } {c0 , c1 } {c0 , c1 , c2 } {j5 , c0 } {j5 , c0 , c1 } {u2 } {u5 , c0 } {u2 , u5 } {u2 , u5 , c0 } {v2 } {v2 , c1 } {v2 , v5 , c2 } {j2 , c0 , c1 , c2 } {u2 , c0 , c1 } {u5 , c0 , c1 , c2 } {v5 , c0 , c1 , c2 } {j5 , u5 } {j2 , u2 , c0 , c1 } {j2 , u2 , c0 , c1 , c2 } {j2 , j5 , u2 , c0 , c1 , c2 } {j2 , v2 , c0 , c1 } {j5 , v2 , c0 , c1 } {j5 , v5 , c1 , c2 } {j2 , j5 , v2 , c0 , c1 , c2 } {j2 , j5 , v2 , v5 , c0 , c1 , c2 } {u2 , v2 , c2 } {u5 , v5 , c1 , c2 } {u5 , v2 , v5 , c1 , c2 } {u2 , u5 , v2 , v5 , c0 , c1 , c2 } {j5 , u5 , v5 , c1 , c2 } {j2 , j5 , u2 , v2 , c0 , c1 , c2 } {j2 , j5 , u2 , u5 , v2 , v5 } ∪ H81
i 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60 63 66 69 72 75 78 81 84 87 90 93
Hi1 {c1 } {c0 , c2 } {j5 } {j5 , c1 } {j2 , j5 , c0 } {u5 } {u2 , c2 } {u2 , c0 , c2 } {u2 , u5 , c2 } {v5 , c2 } {v5 , c1 , c2 } {v2 , v5 , c1 , c2 } {j5 , c0 , c1 , c2 } {u5 , c1 , c2 } {u2 , u5 , c0 , c1 , c2 } {v2 , c0 , c1 , c2 } {j2 , u2 , c0 } {j5 , u5 , c1 , c2 } {j2 , j5 , u2 , c0 } {j2 , j5 , u2 , u5 , c0 } {j2 , v2 , c0 , c1 , c2 } {j5 , v2 , c1 , c2 } {j5 , v5 , c0 , c1 , c2 } {j5 , v2 , v5 , c1 , c2 } {u2 , v2 } {u2 , v2 , c0 , c1 , c2 } {u5 , v5 , c0 , c1 , c2 } {u5 , v2 , v5 , c0 , c1 , c2 } {j2 , u2 , v2 , c0 , c1 } {j5 , u5 , v5 , c0 , c1 , c2 } {j5 , u5 , v2 , v5 , c1 , c2 }
15.4 The Subclasses of [O1 ∪ {max}]
471
15.4.4 The Subclasses of R
Theorem 15.4.4.1 The class J1 := {f ∈ M | Im(f ) ⊆ {0, 1}} has exactly the following (countable infinite-many) subclasses, which are not subclasses of [M 1 ]: J1 , J2 := J1 ∩ P ol{0} = {f ∈ J1 | f ∈ [{c1 }]}, J3 := J1 ∩ P ol{1} = {f ∈ J1 | f ∈ [{c0 }]}, J4 := J1 ∩ P ol{0} ∩ P ol{1}, J5 := {f ∈ J1 | numf (j5 ) ≤ 1}, J6 := J2 ∩ J5 , J7 := J3 ∩ J5 , J8 := J4 ∩ J5 , J9 := {f ∈ J1 | f ∈ [{j5 }] ∨ numf (j5 ) = 0}, J10 := {f ∈ J9 | f ∈ [{c1 }]}, J11 := {f ∈ J9 | f ∈ [{j5 }]}, J12 := {f ∈ J9 | f ∈ [{c1 , j5 }], J9,r := {f ∈ J9 | numf (j2 ) ≤ r}, J10,r := J10 ∩ J9,r , J11,r := J11 ∩ J9,r , J12,r := J12 ∩ J9,r , J13 := {f ∈ J1 | numf (j2 ) = 0}, J14 := J13 ∩ J2 , J15 := J13 ∩ J3 , J16 := J13 ∩ J4 , where r = 1, 2, 3, 4, .... . Proof. With the aid of the Hasse diagram of the above classes (see Figure 15.1) and the generating systems of these classes (see Table 15.14), one can prove the theorem.
472
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
J1 J 3
J2
J5
J4
J6
J7 J8 J9
J10
J11 J12 J9,r
J10,r
J11,r J12,r H16
J13 J15
J14 J16
H14 H13
H15 H11
H10 H5 H12
H9
H2 ∅ = H1
Fig. 15.1. The subclasses of J1
H3
15.4 The Subclasses of [O1 ∪ {max}]
473
Table 15.14 A J1 J2 J3 J4 J5 J6 J7 J8 J9 J10 J11 J12 J9,r J10,r J11,r J12,r J13 J14 J15 J16
generating system (or basis, if it exists) for A {j5 (x) ∨ j5 (y), j2 , c1 } {j5 (x) ∨ j5 (y), j2 } {j5 (x) ∨ j5 (y), j2 (x) ∨ j5 (y), c1 } {j5 (x) ∨ j5 (y), j2 (x) ∨ j5 (y)} {j5 (x) ∨ j2 (y), c0 , c1 } {j5 (x) ∨ j2 (y), c0 } {j5 (x) ∨ j2 (y), c1 } {j5 (x) ∨ j2 (y)} {j5 , c1 , j2 (x1 ) ∨ ... ∨ j2 (xr ) | r ∈ N} {j5 , j2 (x1 ) ∨ ... ∨ j2 (xr ) | r ∈ N} {c1 , j2 (x1 ) ∨ ... ∨ j2 (xr ) | r ∈ N} {j2 (x1 ) ∨ ... ∨ j2 (xr ) | r ∈ N} {j5 , c1 , j2 (x1 ) ∨ ... ∨ j2 (xr )} {j5 , j2 (x1 ) ∨ ... ∨ j2 (xr )} {c1 , j2 (x1 ) ∨ ... ∨ j2 (xr )} {j2 (x1 ) ∨ ... ∨ j2 (xr )} {j5 (x) ∨ j5 (y), c0 , c1 } {j5 (x) ∨ j5 (y), c0 } {j5 (x) ∨ j5 (y), c1 } {j5 (x) ∨ j5 (y)}
A1 {j2 , j5 , c0 , c1 } {j2 , j5 , c0 } {j5 , c1 } {j5 } {j2 , j5 , c0 , c1 } {j2 , j5 , c0 } {j5 , c1 } {j5 } {j2 , j5 , c0 , c1 } {j2 , j5 , c0 } {j2 , c0 , c1 } {j2 , c0 } {j2 , j5 , c0 , c1 } {j2 , j5 , c0 } {j2 , c0 , c1 } {j2 , c0 } {j5 , c0 , c1 } {j5 , c0 } {j5 , c1 } {j5 }
In analog mode, the following two theorems can be proven when one uses Figures 15.2 and 15.3 and Tables 15.15 and 15.16. Theorem 15.4.4.2 The class U1 := {f ∈ M | Im(f ) ⊆ {0, 2}} has exactly the following 14 pairwise different subclasses, which are not subclasses of [M 1 ]: U1 , U2 := U1 ∩ P ol{0} = {f ∈ U1 | f ∈ [{c2 }]}, U3 := {f ∈ U1 | F (f ) ⊆ {c0 , c2 , u2 }}, U4 := {f ∈ U1 | F (f ) ⊆ {c0 , c2 , u5 }}, U5 := U1 ∩ P ol{2} = {f ∈ U1 | f ∈ [{c0 }]}, U6 := {f ∈ U3 | f ∈ [{c2 }]}, U7 := {f ∈ U4 | f ∈ [{c2 }]}, U8 := {f ∈ U3 | f ∈ [{c0 }]}, U9 := {f ∈ U1 | f ∈ [{c2 }] ∨ numf (u5 ) ≥ 1}, U10 := {f ∈ U4 | f ∈ [{c0 }]}, U11 := {f ∈ U1 | f ∈ [{c0 , c2 }]}, U12 := {f ∈ U3 | f ∈ [{c0 , c2 }]}, U13 := {f ∈ U9 | f ∈ [{c2 }]}, U14 := {f ∈ U4 | f ∈ [{c0 , c2 }]}.
H4
H22
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
U10
474
H6
H26
U12
H17
∅
U13
U11
H24 H25
H28
H20
U7
U3
Fig. 15.2. The subclasses of U1
H2
H19
U6
U2
U1
U14
H18
H27
H23
U4
U8
H21
U5
U9
$!! # # # $ ! $ ! # $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! $ # ! ! $ # $ # ! $ # ! $ # ! $ # ! $ " " $ " $ " $ " $ " $ " $ " " " " " " " " " " " " "
15.4 The Subclasses of [O1 ∪ {max}]
475
Table 15.15 A U1 U2 U3 U4 U5 U6 U7 U8 U9 U10 U11 U12 U13 U14
Basis for A {u2 (x) ∨ u2 (y), u5 , c0 , c1 } {u2 (x) ∨ u2 (y), u5 , c0 } {u2 (x) ∨ u2 (y), c0 , c2 } {u5 (x) ∨ u5 (y), c0 , c2 } {u2 (x) ∨ u2 (y), u5 , c2 } {u2 (x) ∨ u2 (y), c0 } {u5 (x) ∨ u5 (y), c0 } {u2 (x) ∨ u2 (y), c2 } {u2 (x) ∨ u5 (y), c2 } {u5 (x) ∨ u5 (y), c2 } {u2 (x) ∨ u2 (y), u5 } {u2 (x) ∨ u2 (y)} {u2 (x) ∨ u5 (y)} {u5 (x) ∨ u5 (y)}
A1 {u2 , u5 , c0 , c2 } {u2 , u5 , c0 } {u2 , c0 , c2 } {u5 , c0 , c2 } {u2 , u5 , c2 } {u2 , c0 } {u5 , c0 } {u2 , c2 } {u5 , c2 } {u5 , c2 } {u2 , u5 } {u2 } {u5 } {u5 }
Theorem 15.4.4.3 The class V1 := {f ∈ M | Im(f ) ⊆ {1, 2}} has exactly the following (countable infinite-many) subclasses, which are not subclasses of [M 1 ] : V1 , V2 := V1 ∩ P ol(2) = {f ∈ V1 | f ∈ [{c1 }]}, V3 := {f ∈ V1 | f ∈ [{c1 , c2 , v2 }] ∨ numf (v5 ) ≥ 1}, V4 := {f ∈ V3 | f ∈ [{c1 }]}, V5 := {f ∈ V1 | f ∈ [{c1 , c2 , v2 }] ∨ numf (v2 ) ≤ 1}, V6 := {f ∈ V5 | f ∈ [{c1 }]}, V7 := {f ∈ V1 | f ∈ [{c2 , v2 }] ∨ F (f ) ⊆ {c1 , v5 }}, V8 := {f ∈ V7 | f ∈ [{c1 }]}, V9 := {f ∈ V7 | f ∈ [{v2 }]}, V10 := {f ∈ V7 | f ∈ [{c1 , v2 }]}, V7,r := {f ∈ V7 | numf (v5 ) ≤ r}, V8,r := {f ∈ V7,r | f ∈ [{c1 }]}, V9,r := {f ∈ V7,r | f ∈ [{v2 }]}, V10,r := {f ∈ V7,r | f ∈ [{c1 , v2 }]}, V11 := {f ∈ V3 | f ∈ [{v2 }]}, V12 := V5 ∩ V11 , V13 := {f ∈ V11 | f ∈ [{c1 }]}, V14 := {f ∈ V12 | f ∈ [{c1 }]}, V15 := {f ∈ V1 | F (f ) ⊆ {c1 , c2 , v2 }}, V16 := {f ∈ V15 | f ∈ [{c1 }]}, V17 := {f ∈ V15 | f ∈ [{c2 }]}, V18 := {f ∈ V15 | f ∈ [{c1 , c2 }]}, where r = 1, 2, 3, 4, ... .
476
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
V1 V3
V2
V11
V5
V4 V6
V7
V8
V12 V9
V10
V7,r+1 V8,r+1
V9,r+1 V10,r+1 V7,r
V8,r
V9,r V10,r
V15 V16
H36
V17 H35 V18
H31 H29
H30
H4
H33 H7 H3
∅ Fig. 15.3. The subclasses of V1
V13 V14
15.4 The Subclasses of [O1 ∪ {max}]
477
Table 15.16 A V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V7,r V8,r V9,r V10,r V11 V12 V13 V14 V15 V16 V17 V18
Generating system (or basis, if it exists) for A {v2 (x) ∨ v2 (y), v5 , c1 } {v2 (x) ∨ v2 (y), v5 } {v2 (x) ∨ v2 (y) ∨ v5 (z), v2 , c1 } {v2 (x) ∨ v2 (y) ∨ v5 (z), v5 } {v2 (x) ∨ v5 (y), v2 , c1 } {v2 (x) ∨ v5 (y), v2 } {v2 , c1 , v5 (x1 ) ∨ ... ∨ v5 (xr ) | r ∈ N} {v2 , v5 (x1 ) ∨ ... ∨ v5 (xr ) | r ∈ N} {c1 , v5 (x1 ) ∨ ... ∨ v5 (xr ) | r ∈ N} {v5 (x1 ) ∨ ... ∨ v5 (xr ) | r ∈ N} {v2 , c1 , v5 (x1 ) ∨ ... ∨ v5 (xr )} {v2 , v5 (x1 ) ∨ ... ∨ v5 (xr )} {c1 , v5 (x1 ) ∨ ... ∨ v5 (xr )} {v5 (x1 ) ∨ ... ∨ v5 (xr )} {v2 (x) ∨ v2 (y) ∨ v5 (z), c1 } {v2 (x) ∨ v5 (y), c1 } {v2 (x) ∨ v2 (y) ∨ v5 (z)} {v2 (x) ∨ v5 (y)} {v2 (x) ∨ v2 (y), c1 , c2 } {v2 (x) ∨ v2 (y), c2 } {v2 (x) ∨ v2 (y), c1 } {v2 (x) ∨ v2 (y)}
A1 {v2 , v5 , c1 , c2 } {v2 , v5 , c2 } {v2 , v5 , c1 , c2 } {v2 , v5 , c2 } {v2 , v5 , c1 , c2 } {v2 , v5 , c2 } {v2 , v5 , c1 , c2 } {v2 , v5 , c2 } {v5 , c1 , c2 } {v5 , c2 } {v2 , v5 , c1 , c2 } {v2 , v5 , c2 } {v5 , c1 , c2 } {v5 , c2 } {v5 , c1 , c2 } {v5 , c1 , c2 } {v5 , c2 } {v5 , c2 } {v2 , c1 , c2 } {v2 , c2 } {v2 , c1 } {v2 }
Theorem 15.4.4.4 Class J1 ∪U1 has exactly the following subclasses (ordered with respect to equality of the unary functions), which are not subclasses of J1 or U1 or [(J1 ∪ U1 )1 ]: J3 ∪ H4 , J7 ∪ H4 , J15 ∪ H4 ; J11 ∪ H6 , J11,r ∪ H6 ; J13 ∪ H6 ; J1 ∪ H6 , J5 ∪ H6 , J9 ∪ H6 , J9,r ∪ H6 ; H5 ∪ U6 ; H3 ∪ U9 , H3 ∪ U10 ; H5 ∪ U3 ; H5 ∪ U4 ; H5 ∪ U1 ; J4 ∪ U13 , J16 ∪ U14 ; J12 ∪ H19 , J12 ∪ U6 , J12,r ∪ H19 ; J14 ∪ U7 ; J11 ∪ H19 , J11 ∪ U6 , J11,r ∪ H19 ; J3 ∪ U9 ; J13 ∪ U4 ; J11 ∪ H24 , J11,r ∪ H24 , J11 ∪ U3 ; J10 ∪ H19 , J10,r ∪ H19 , J10 ∪ U6 , J6 ∪ H19 , J6 ∪ U6 , J2 ∪ H19 , J2 ∪ U6 ;
478
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
J9 ∪ H19 , J9,r ∪ H19 , J5 ∪ H19 , J1 ∪ H19 , J9 ∪ U6 , J5 ∪ U6 , J1 ∪ U6 ; J9 ∪ H24 , J9,r ∪ H24 , J5 ∪ H24 , J1 ∪ H24 , J5 ∪ U3 , J9 ∪ U3 , J1 ∪ U3 ; J2 ∪ U2 ; J1 ∪ U1 ; where r = 1, 2, 3, .... Proof. Let T be an arbitrary subclass of J1 ∪ U1 , which was not described in Theorems 15.4.3.1, 15.4.4.1, or 15.4.4.2. Then, obviously T1 := T ∩ J1 and T2 := T ∩ U1 are subclasses of J1 or U1 with T = T1 ∪ T2 . Further, [T 1 ] is a subclass H of [M 1 ] with H 1 = T 1 . The possibilities for H follow from Theorems 15.4.3.1, 15.4.4.1, and 15.4.4.2. These possibilities imply the possibilities for T1 and T2 , which are given in Table 15.17. When one selects the sets T1 ∪ T2 ⊆ [M 1 ], which are closed, one receives the statement of the theorem.
Table 15.17 [T 1 ] H37 H38 H39 H40 H41 H42 H43 H44 H45 H50 H51 H52 H53 H54 H55 H56 H57 H58 H59 H60 H61
Possibilities for T ∩ J1 T ∩ U1 J3 , J7 , J15 H4 J11 , J11,r H6 J13 H6 J1 , J5 , J9 , J9,r H6 H5 U6 H3 U9 , U10 H5 U3 H5 U4 H5 U1 H9 , J4 , J8 , J16 H18 , U13 , U14 H10 , J12 , J12,r H19 , U6 H11 , J14 H20 , U7 H13 , J11 , J11,r H19 , U6 H12 , J3 , J7 , J15 H22 , U9 H14 , J13 H25 , U4 H13 , J11 , J11,r H24 , U3 H15 , J2 , J6 , J10 , J10,r H19 , U6 H16 , J1 , J5 , J9 , J9,r H19 , U6 H16 , J1 , J5 , J9 , J9,r H24 , U3 H15 , J2 , J6 , J10 , J10,r H26 , U2 H16 , J1 , J5 , J9 , J9,r H28 , U1
Theorem 15.4.4.5 Class J1 ∪ V1 has exactly the following subclasses, which are not subclasses of J1 or V1 or [(J1 ∪ V1 )1 ]: J3 ∪ H7 , J7 ∪ H7 , J15 ∪ H7 ; J11 ∪ H7 , J11,r ∪ H7 ; J13 ∪ H7 ; J1 ∪ H7 , J5 ∪ H7 , J9 ∪ H7 , J9,r ∪ H7 ;
15.4 The Subclasses of [O1 ∪ {max}]
479
H5 ∪ V17 ; H5 ∪ V9 , H5 ∪ V9,r , H5 ∪ V11 , H5 ∪ V12 ; H5 ∪ V15 ; H5 ∪ V1 , H5 ∪ V3 , H5 ∪ V5 , H5 ∪ V7 , H5 ∪ V7,r ; J11 ∪ H32 , J11 ∪ V17 , J11,r ∪ H32 ; J11 ∪ H34 , J11 ∪ V15 , J11,r ∪ H34 ; H12 ∪ V17 , J3 ∪ H32 , J3 ∪ V17 , J7 ∪ H32 , J7 ∪ V17 , J15 ∪ H32 , J15 ∪ V17 ; H14 ∪ V17 , J13 ∪ H32 , J13 ∪ V17 ; H12 ∪ V15 , J3 ∪ H34 , J3 ∪ V15 , J7 ∪ H34 , J7 ∪ V15 , J15 ∪ H34 , J15 ∪ V15 ; H14 ∪ V15 , J13 ∪ H34 , J13 ∪ V15 ; H12 ∪V9 , H12 ∪V11 , H12 ∪V12 , H12 ∪V9,r , J15 ∪V9 , J15 ∪V12 , J15 ∪V11 , J7 ∪V12 , J7 ∪ V11 , J3 ∪ V11 ; H14 ∪ V9 , H14 ∪ V11 , H14 ∪ V12 , H14 ∪ V9,r , J13 ∪ V9 , J13 ∪ V11 , J13 ∪ V12 ; J1 ∪ H32 , J1 ∪ V17 , J5 ∪ H32 , J5 ∪ V17 , J9 ∪ H32 , J9 ∪ V17 , J9,r ∪ H32 ; J1 ∪ H34 , J1 ∪ V15 , J5 ∪ H34 , J5 ∪ V15 , J9 ∪ H34 , J9 ∪ V15 , J9,r ∪ H34 ; H12 ∪ V1 , H12 ∪ V3 , H12 ∪ V5 , H12 ∪ V7 , H12 ∪ V7,r , J15 ∪ V7 , J15 ∪ V5 , J15 ∪ V3 , J15 ∪ V1 , J7 ∪ V5 , J7 ∪ V3 , J7 ∪ V1 , J3 ∪ V3 , J3 ∪ V1 ; H14 ∪ V1 , H14 ∪ V3 , H14 ∪ V5 , H14 ∪ V7 , H14 ∪ V7,r , J13 ∪ V1 , J13 ∪ V3 , J13 ∪ V5 , J13 ∪ V7 ; J1 ∪ V1 ; where r = 1, 2, 3, ... . Table 15.18 [T 1 ] H37 H38 H39 H40 H46 H47 H48 H49 H62 H63 H64 H65 H66 H67 H68 H69 H70 H71 H72 H73 H74
Possibilities for T ∩ J1 T ∩ V1 H12 , J3 , J7 , J15 H7 H13 , J11 , J11,r H7 H14 , J13 H7 H16 , J1 , J5 , J9 , J9,r H7 H5 H32 , V17 H5 H33 , V9 , V9,r , V11 , V12 H5 H34 , V15 H5 H36 , V1 , V3 , V5 , V7 , V7,r H13 , J11 , J11,r H32 , V17 H13 , J11 , J11,r H34 , V15 H12 , J3 , J7 , J15 H32 , V17 H14 , J13 H32 , V17 H12 , J3 , J7 , J15 H34 , V15 H14 , J13 H34 , V15 H12 , J3 , J7 , J15 H33 , V9 , V9,r , V11 , V12 H14 , J13 H33 , V9 , V9,r , V11 , V12 H16 , J1 , J5 , J9 , J9,r H32 , V17 H16 , J1 , J5 , J9 , J9,r H34 , V15 H12 , J3 , J7 , J15 H36 , V1 , V3 , V5 , V7 , V7,r H14 , J13 H36 , V1 , V3 , V5 , V7 , V7,r H16 , J1 , J5 , J9 , J9,r H36 , V1 , V3 , V5 , V7 , V7,r
480
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Proof. Let T be an arbitrary subclass of J1 ∪ V1 , which was not described in Theorems 15.4.3.1, 15.4.4.1, or 15.4.4.3. Then obviously T1 := T ∩ J1 and T2 := T ∩ V1 are subclasses of J1 or V1 with T = T1 ∪ T2 . Further, [T 1 ] is a subclass H of [M 1 ] with H 1 = T 1 . The possibilities for H follow from Theorems 15.4.3.1, 15.4.4.1, and 15.4.4.3. These possibilities imply the possibilities for T1 and T2 , which are given in Table 15.18. When one selects the sets T1 ∪ T2 ⊆ [M 1 ], which are closed, one receives the statement of the theorem.
Theorem 15.4.4.6 Class U1 ∪ V1 has exactly the following subclasses, which are not subclasses of U1 or V1 or [(U1 ∪ V1 )1 ]: U6 ∪ H3 ; U9 ∪ H7 ; U3 ∪ H7 ; U4 ∪ H7 ; U1 ∪ H7 ; H2 ∪ V17 ; H6 ∪ V9 , H6 ∪ V9,r , H6 ∪ V11 , H6 ∪ V12 ; H6 ∪ V15 ; H6 ∪ V1 , H6 ∪ V3 , H6 ∪ V5 , H6 ∪ V7 , H6 ∪ V7,r ; U12 ∪ V18 ; U6 ∪ V17 ; U8 ∪ V16 ; U3 ∪ V15 ; H22 ∪ V10 , H22 ∪ V10,r , H22 ∪ V13 , H22 ∪ V14 , U9 ∪ V13 ; H22 ∪ V9 , H22 ∪ V9,r , H22 ∪ V11 , H22 ∪ V12 , U9 ∪ V11 ; H25 ∪ V9 , H25 ∪ V9,r , H25 ∪ V11 , H25 ∪ V12 , U4 ∪ V9 ; H22 ∪ V2 , H22 ∪ V4 , H22 ∪ V6 , H22 ∪ V8 , H22 ∪ V8,r , U9 ∪ V2 , U9 ∪ V4 ; H22 ∪ V1 , H22 ∪ V3 , H22 ∪ V5 , H22 ∪ V7 , H22 ∪ V7,r , U9 ∪ V1 , U9 ∪ V3 ; H25 ∪V1 , H25 ∪V3 , H25 ∪V5 , H25 ∪V7 , H25 ∪V7,r , U4 ∪V1 , U4 ∪V3 , U4 ∪V5 , U4 ∪V7 ; U5 ∪ V2 ; U1 ∪ V1 ; where r = 1, 2, 3, ... . Proof. Let T be an arbitrary subclass of U1 ∪ V1 , which was not described in Theorems 15.4.3.1, 15.4.4.2, or 15.4.4.3. Then obviously T1 := T ∩ U1 and T2 := T ∩ V1 are subclasses of U1 or V1 with T = T1 ∪ T2 . Further, [T 1 ] is a subclass H of [M 1 ] with H 1 = T 1 . The possibilities for H follow from Theorems 15.4.3.1, 15.4.4.2, and 15.4.4.5, which are given in Table 15.19. When one selects the sets T1 ∪ T2 ⊆ [M 1 ], which are closed, one receives the statement of the theorem.
15.4 The Subclasses of [O1 ∪ {max}]
481
Table 15.19 [T 1 ] H41 H42 H43 H44 H45 H46 H47 H48 H49 H75 H76 H77 H78 H79 H80 H81 H82 H83 H84 H85 H86
Possibilities for T ∩ U1 T ∩ V1 H19 , U6 H3 H22 , U9 H7 H24 , U3 H7 H25 , U4 H7 H28 , U1 H7 H2 H32 , V17 H6 H33 , V9 , V9,r , V11 , V12 H6 H34 , V15 H6 H36 , V1 , V3 , V5 , V7 , V7,r H17 , U12 H29 , V18 H19 , U6 H32 , V17 H21 , U8 H31 , V16 H24 , U3 H34 , V15 H22 , U9 H30 , V10 , V10,r , V13 , V14 H22 , U9 H33 , V9 , V9,r , V11 , V12 H25 , U4 H33 , V9 , V9,r , V11 , V12 H22 , U9 H35 , V2 , V4 , V6 , V8 , V8,r H22 , U9 H36 , V1 , V3 , V5 , V7 , V7,r H25 , U4 H36 , V1 , V3 , V5 , V7 , V7,r H27 , U5 H35 , V2 , V4 , V6 , V8 , V8,r H28 , U1 H36 , V1 , V3 , V5 , V7 , V7,r
Theorem 15.4.4.7 Class J1 ∪ U1 ∪ V1 has the following subclasses, which are not subclasses of J1 ∪ U1 , J1 ∪ V1 , U1 ∪ V1 or [M 1 ]: J11 ∪ H19 ∪ H32 , J11,r ∪ H19 ∪ H32 , J11,r ∪ U6 ∪ V17 ; J11 ∪ H24 ∪ H34 , J11,r ∪ H24 ∪ H34 , J11 ∪ U3 ∪ V15 ; H12 ∪ H22 ∪ V9 , H12 ∪ H22 ∪ V9,r , H12 ∪ H22 ∪ V11 , H12 ∪ H22 ∪ V12 , J3 ∪ U9 ∪ V11 ; H14 ∪ H25 ∪ V9 , H14 ∪ H25 ∪ V9,r , H14 ∪ H25 ∪ V11 , H14 ∪ H25 ∪ V12 , J13 ∪ U4 ∪ V9 ; J9 ∪ H19 ∪ H32 , J9,r ∪ H19 ∪ H32 , J5 ∪ H19 ∪ H32 , J1 ∪ H19 ∪ H32 , J5 ∪ U6 ∪ V17 , J1 ∪ U6 ∪ V17 , J9 ∪ U6 ∪ V17 ; J9 ∪ H24 ∪ H34 , J9,r ∪ H24 ∪ H34 , J5 ∪ H24 ∪ H34 , J1 ∪ H24 ∪ H34 , J1 ∪ U3 ∪ V15 , J5 ∪ U3 ∪ V15 , J9 ∪ U3 ∪ V15 ; H12 ∪ H22 ∪ V1 , H12 ∪ H22 ∪ V3 , H12 ∪ H22 ∪ V5 , H12 ∪ H22 ∪ V7 , H12 ∪ H22 ∪ V7,r , J3 ∪ U9 ∪ V3 , J3 ∪ U9 ∪ V1 ; H14 ∪ H25 ∪ V1 , H14 ∪ H25 ∪ V3 , H14 ∪ H25 ∪ V5 , H14 ∪ H25 ∪ V7 , H14 ∪ H25 ∪ V7,r , J13 ∪ U4 ∪ V1 , J13 ∪ U4 ∪ V3 , J13 ∪ U4 ∪ V5 , J13 ∪ U4 ∪ V7 ; J1 ∪ U1 ∪ V1 ; where r = 1, 2, 3, .... Proof. It is easy to check that a class T of the form T1 ∪ T2 ∪ T3 with T1 ∈ L3 (J1 )\{∅}, T2 ∈ L3 (U1 )\{∅} and T3 ∈ L3 (V1 )\{∅} is closed if and only if the sets Ti ∪ Tj are closed for all i, j ∈ {1, 2, 3} and i = j. Thus, our theorem
482
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
follows from Theorems 15.4.4.4–15.4.4.6 with the aid of Theorem 15.4.3.1, in which one can find the possibilities for T 1 . 15.4.5 The Subclasses of M ∩ P ol3 {(0, 2)} To receive a coarse partition of the lattice of the subclasses of 0 A1 := M ∩ P ol3 2 = {f ∈ M | f ∈ [{c0 , c1 , c2 }] ∧ F (f ) ∩ {v2 , v5 } = ∅ ∧ ({j2 , j5 } ∩ F (f ) = ∅ =⇒ {s1 , u2 , u5 } ∩ F (f ) = ∅)}, we determine the maximal classes of A1 first. Lemma 15.4.5.1 A1 has exactly three maximal classes: (1) A2 := A1 ∩ P ol3 {0, 1} = {f ∈ A1 | u5 ∈ F (f )}; (2) A3 := A1 ∩ P ol3 {1, 2} = {f ∈ A1 | {j2 , u2 } ∩ F (f ) = ∅ =⇒ {s1 , j5 , u5 } ∩ F (f ) = ∅}; (3) B1 := {f ∈ A1 | F (f ) ⊆ {c0 , u2 , u5 , s1 }}. Proof. One can conclude from Theorem 15.4.2.2 that A1 A2 A3 B1
= [{max, x ∨ j2 (y), u2 , u5 }], = [{max, x ∨ j5 (y), u2 }], = [{max, x ∨ j2 (y), x ∨ u2 (y), u5 }], = [{max, u2 , u5 }].
With the aid of the above statements, it is easy to prove the A1 -maximality of A2 , A3 , and B. Denote now T an arbitrary subset of A1 , which is not a subset of X for all X ∈ {A2 , A3 , B}. Then there are some functions qi (i = 1, 2, 3) with q1 ∈ T \ B1 , q2 ∈ T \ A2 and q3 ∈ T \ A3 . By identifying the variables in the functions q2 and q3 , one obtains the functions u5 and u2 . The function q1 has at least two essential variables and it holds that F (q1 )∩{j2 , j5 } = ∅. By identifying certain variables of q1 and substituting certain variables of q1 through the functions u2 , u5 we obtain the functions j5 (x) ∨ u2 (y) and j5 (x) ∨ u5 (y). In the proof of Lemma 15.4.2.2, we showed that an arbitrary function t ∈ M with F (t) ∈ {{j5 , u2 }, {j5 , u5 }} is a superposition over the above-constructed functions. Then, by identifying variables in a function t4 ∈ M with F (t) = {j5 , u2 } and numt (j5 ) = numt (u2 ) = 2, we obtain max ∈ [{q1 , q2 , q3 }]. Since in addition x ∨ (j5 (u2 (y)) ∨ u2 (x)) = x ∨ j2 (y) holds, we have [{q1 , q2 , q3 }] = A3 , whereby our lemma is proven. Obviously, it holds I1 := A2 ∩ A3 = A1 ∩ P ol3 {1},
15.4 The Subclasses of [O1 ∪ {max}]
483
and the functions f of I1 are idempotent; i.e., f (x, x, ..., x) = x. Subsequently, we determine the elements of L3 (A1 )\(L3 (R) ∪ L3 ([M 1 ]), which belong to B1 and I1 , and then the remaining elements of L3 (A1 )\(L3 (R) ∪ L3 ([M 1 ]) (see Figure 15.4). With the aid of Theorems 15.4.3.1 and 15.4.4.2, one obtains a complete description of L3 (A1 ).
Theorem 15.4.5.2 B1 has exactly the following 20 subclasses, which are not subsets of [M 1 ] or U1 : B1 = [{max, u2 , u5 }], B2 := {f ∈ B1 | F (f ) ∩ {s1 , u5 } = ∅} = [{max, x ∨ u2 (y), u5 }], B3 := {f ∈ B1 | numf (s1 ) ≤ 1} = [{x ∨ u2 (y), x ∨ u5 (y), u2 }], B4 := {f ∈ B1 | u5 ∈ F (f )} = [{max, u2 }], B5 := {f ∈ B2 | numf (s1 ) ≥ 2 =⇒ u5 ∈ F (f )} = [{x ∨ y ∨ u5 (z), x ∨ u2 (y)}], B6 := {f ∈ B2 | u2 ∈ F (f ) =⇒ u5 ∈ F (f )} = [{max, u2 (x) ∨ u5 (y)}], B7 := B5 ∩ B6 = [{x ∨ y ∨ u5 (z), u2 (x) ∨ u5 (y), s1 }], B8 := {f ∈ B1 | u2 ∈ F (f )} = [{max, u5 }], B9 := B2 ∩ B3 = [{x ∨ u2 (y), u5 }], B10 := B2 ∩ B4 = [{max, x ∨ u2 (y)}], B11 := B7 \[{s1 }], B12 := B7 ∩ B8 = [{x ∨ y ∨ u5 (z), s1 }], B13 := B7 ∩ B3 = [{x ∨ u5 (y), u2 (x) ∨ u5 (y), s1 }], B14 := B3 ∩ B4 = [{x ∨ u2 (y), u2 }], B15 := B11 ∩ B12 = [{x ∨ y ∨ u5 (z)}], B16 := B12 ∩ B13 = [{x ∨ u5 (y), s1 }], B17 := B9 ∩ B13 = [{x ∨ u5 (y), u2 (x) ∨ u5 (y)}], B18 := B9 ∩ B14 = [{x ∨ u2 (y)}], B19 := [{max}], B20 := [{x ∨ u5 (y)}] (See Figure 15.5). Proof. Except for the functions f with u5 ∈ F (f ) and numf (s1 ) ≥ 2, for which f ∈ [[{f }]3 ] is valid, we have by Lemma 15.4.2.2 f ∈ [{f }]2 for all other functions f ∈ B1 \[M 1 ]. Consequently, one can describe an arbitrary subclass B of B1 in the form of a closure of a certain subset of {x ∨ y ∨ u5 (z), max, x ∨ u2 (y), x ∨ u5 , u2 (y) ∨ u5 (y), u2 , u5 , s1 }. When one examines the possible cases for B (⊆ U1 or ⊆ [M 1 ]) with the aid of Figure 15.5, one obtains our theorem.
A15,r−1
A15,r
A14
Fig. 15.4
A37
A17 A18 A19
A25
A24
A23
A16
A20
A14,1
A22
A15,1
A21
A36
A14,r−1
A35
A34
A14,r
see Figure 15.5
A33
A32
A31
A15
B1
A30
A29
A28
A27
A13
A12
see Figure 15.6
A26
A11
A10
A9
A8
I1
A7
A6
A5
A3
A4
A2
A1
484 15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
15.4 The Subclasses of [O1 ∪ {max}]
485
B1
B4 B2 B3 " # B # " B5 6 # " " # # " B7 B8 B9 B10 " # " # " # B B13# B11 12 14 "B " % # % % %%% % % %%% B B16 %%% B17 B B19 18 % 15 % B20
Fig. 15.5
Theorem 15.4.5.3 I1 has exactly 17 subclasses, which are not subsets of [M 1 ]: I1 = [{max, u2 (x) ∨ j5 (y)}], I2 := [{max, x ∨ j5 (y), x ∨ u2 (y)}], I3 := [{x ∨ j5 (y), j5 (x) ∨ u2 (y)}], I4 := [{x ∨ u2 (y), j5 (x) ∨ u2 (y)}], I5 := [{max, x ∨ j2 (y), x ∨ j5 (y)}], I6 := [{max, x ∨ j2 (y), x ∨ u2 (y)}], I7 := [{x ∨ j2 (y), j5 (y) ∨ u2 (y)}], I8 := [{x ∨ j5 (y), x ∨ j2 (y)}], I9 := [{x ∨ j2 (y), x ∨ u2 (y)}], I10 := [{max, x ∨ j5 (y)}], I11 := [{max, x ∨ j2 (y)}], B10 = [{max, x ∨ u2 (y)}], I12 := [{j5 (x) ∨ u2 (y)}], I13 := [{x ∨ j5 (y)}], I14 := [{x ∨ j2 (y)}], B18 = [{x ∨ u2 (y)}], B19 = [{max}]. Proof. Because of Theorem 15.4.2.2, every subclass of I1 has a generating system from binary functions of I1 . Consequently, one obtains the subclasses
486
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
of I1 , which are not subclasses of [M 1 ], through closure of the subsets of {max, x ∨ j2 (y), x ∨ j5 (y), x ∨ u2 (y), j5 (x) ∨ u2 (y)}. (During the forming of these classes one notices that the equations x ∨ j5 (j5 (x) ∨ u2 (y)) = x ∨ j2 (y) and
u2 (x) ∨ j5 (x ∨ u2 (y)) = x ∨ j2 (y)
are valid.) The Figure 15.6 gives the Hasse diagram of the classes constructed in this manner. I1
I2 I6 I3 I4 I5 I7 I11 B10 I10 I8 I9 I12
I13
I14
B18
B19
Fig. 15.6
Theorem 15.4.5.4 The following classes are the only subclasses of A2 that are not contained in I1 , B1 or [M 1 ]: A2 = [{max, x ∨ j5 (y), u2 }], A4 := [{max, j2 (x) ∨ u2 (y)}], A5 := [{x ∨ u2 (y), j5 (x) ∨ u2 (y), u2 }], A6 := [{x ∨ j5 (y), u2 }], A7 := [{x ∨ j2 (y), x ∨ u2 (y), u2 }], A8 := [{j5 (x) ∨ u2 (y), u2 }], A9 := [{x ∨ u2 (y), j2 (x) ∨ u2 (y)}], A10 := [{x ∨ j2 (y), u2 (x) ∨ u2 (y)}], A11 := [{s1 , j2 (x) ∨ u2 (y), u2 (x) ∨ u2 (y)}], A12 := [{x ∨ j2 (y), u2 }], A13 := A11 \[{s1 }], A14 := [{u2 (x1 ) ∨ j2 (x2 ) ∨ ... ∨ j2 (xn ) | n ∈ N\{1}}],
15.4 The Subclasses of [O1 ∪ {max}]
487
A14,r := [{f ∈ A10 | numf (j2 ) ≤ r}], A15 := A14 ∪ [{s1 }], A15,r := A14,r ∪ [{s1 }], where r = 1, 2, ... . Proof. Let A be a subclass of A2 , which is not a subset of I1 , B1 or [M 1 ]. Because of A ⊆ I1 = A2 ∩ A3 , u2 belongs to A. Then, by A ⊆ [M 1 ] and A ⊆ B1 , we have j2 (x) ∨ u2 (y) ∈ A. Thus A contains the class A14,1 . One can verify the remaining statements of our theorem easily with the aid of the above-noted generating systems of the classes, Figure 15.4, and Theorem 15.4.2.2. Theorem 15.4.5.5 The following classes are the only subclasses of A3 that are not contained in I1 , B1 or [M 1 ]: A3 = [{max, j5 (x) ∨ u2 (y), u5 }], A16 := {f ∈ A1 | u5 ∈ F (f )} = [{j5 (x) ∨ u5 (y), j2 (x) ∨ u5 (y)}], A17 := {f ∈ A16 | {j2 , u2 } ∩ F (f ) = ∅} = [{u5 (x) ∨ j5 (y), x ∨ y ∨ u5 (z)}], A18 := {f ∈ A17 | numf (s1 ) ≤ 1} = [{x ∨ j5 (y) ∨ u5 (z)}], A19 := {f ∈ A18 | numf (s1 ) = 1 =⇒ j5 ∈ F (f )} = [{x∨u5 (y), j5 (x)∨u5 (y)}], A20 := {f ∈ A19 | numf (s1 ) = 0} = [{j5 (x) ∨ u5 (y)}], A21 := A16 ∪ [{s1 }], A22 := A17 ∪ [{s1 }], A23 := A18 ∪ [{s1 }], A24 := A19 ∪ [{s1 }], A25 := A20 ∪ [{s1 }], A26 := I3 ∪ A16 , A27 := I2 ∪ A16 , A28 := I5 ∪ A16 , A29 := B10 ∪ A16 , A30 := I8 ∪ A16 , A31 := I10 ∪ A17 , A32 := B19 ∪ A16 , A33 := I13 ∪ A17 , A34 := B18 ∪ A16 , A35 := B19 ∪ A17 , A36 := I13 ∪ A18 , A37 := I13 ∪ A20 . Proof. Let T be a subclass of A3 with T ⊆ I1 , T ⊆ B1 and T ⊆ [M 1 ]. It follows from T ⊆ I1 , T ⊆ B1 , T ⊆ [M 1 ] and j2 u5 = j5 that the functions u5 and j5 (x) ∨ u5 (y) belong to T . Hence we have A20 ⊆ T . Since for an arbitrary function f ∈ A3 either f (1, ..., 1) = 1 or f (1, ..., 1) = 2 holds, and the case f (1, ..., 1) = 2 and f ∈ A3 is only possible, if u5 ∈ F (f ),
488
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
the class T has the form (T ∩ I1 ) ∪ (T ∩ A16 ).
(15.5)
First we show the possibilities for T ∩ A16 . Because of j2 (u5 (y)) ∨ u5 (j2 (x) ∨ u5 (y)) = u2 (x) ∨ u5 (y) and we have
j5 (u2 (x) ∨ u5 (y)) ∨ u5 (y) = j2 (x) ∨ u5 (y) j2 (x) ∨ u5 (y) ∈ T ⇐⇒ u2 (x) ∨ u5 (y) ∈ T.
(15.6)
Further, it holds that: j5 (x1 ) ∨ j5 (x2 ) ∨ u5 (x3 ) ∨ u5 (x4 ) ∈ [{j5 (x) ∨ u5 (y)}] This implies x ∨ y ∨ u5 (z) = j5 (g(z, x)) ∨ j5 (g(z, y)) ∨ u5 (g(x, z)) ∨ u5 (g(y, z)) ∈ [{j5 (x) ∨ u5 (y), g}]
(15.7)
for every g(x, y) ∈ {j2 (x) ∨ u5 (y), u2 (x) ∨ u5 (y)}. With the aid of (15.6) and (15.7), it is easy to check that the classes A16 , ..., A20 are the only possibilities for T if T ⊆ A16 holds. The remaining possibilities for T can be obtained with the help of (15.5) and Theorem 15.4.5.3, when one determines the classes I ∈ L3 (I1 )\{∅} and A ∈ {A16 , ..., A20 } with I ∪ A = [I ∪ A].
15.4.6 The Remaining Subclasses of M The following lemma is the basis for determining the subclasses of M that are still missing. Lemma 15.4.6.1 Let T be a subclass of M , which is not a subset of [M 1 ], R or A1 . Furthermore, let T1 := T ∩ R and T2 := T ∩ P ol
0 . 2
Then T fulfills one of the two following conditions: (a) T ∈ {T1 ∪ [{s1 }] | T1 ∈ L3 (R)\L3 ([M 1 ])}. (b) T2 ∩ {max, x ∨ j2 (y), x ∨ j5 (y), x ∨ u2 (y), x ∨ u5 (y), j2 (x) ∨ u2 (y), j5 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} = ∅.
15.4 The Subclasses of [O1 ∪ {max}]
489
Proof. For T the following two cases are possible: Case 1: T2 ⊆ [M 1 ]. 0 1 Because of T ⊆ R and (T ∩P ol ) ⊆ {u2 , u5 , s1 }, this case is only possible 2 for s1 ∈ T2 . Since T2 \[{s1 }] ⊆ R and classes of the form T1 ∪ [{s1 }] are closed for all T1 ∈ L3 (R), T fulfills the condition (a). Case 2: T2 ⊆ [M 1 ]. By Section 15.4.5, T fulfills the condition (b). In the following, denote T a subclass of M with the properties: T ∩ R = ∅ and T ∩ {max, x ∨ j2 (y), x ∨ j5 (y), x ∨ u2 (y), x ∨ u5 (y), j2 (x) ∨ u2 (y), = ∅. j5 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} Furthermore, we use the notations: T1 := T ∩ R and T2 := T ∩ P ol
0 (= T ∩ A1 ). 2
Theorem 15.4.6.2 If T ⊆ J1 ∪ A1 then T is one of the following classes: 1) H2 ∪ B19 , J12 ∪ I11 , J14 ∪ I10 , J2 ∪ I5 (classes that contain the set {c0 , max}); 2) J2 ∪ I8 , J14 ∪ I13 , Ji ∪ I14 (i ∈ {1, 2, 5, 6, 11, 12}) (classes T with c0 ∈ T , max ∈ T and {x∨j5 (y), x∨j2 (y)}∩T = ∅); 3) H3 ∪ I14 , J7 ∪ I14 , J3 ∪ I14 (classes T with c1 ∈ T and c0 ∈ T ); 4) J16 ∪ I13 , J16 ∪ I10 , J8 ∪ I4 , J8 ∪ I7 , J8 ∪ I14 , J4 ∪ I5 , J4 ∪ I1 , J4 ∪ I8 , J4 ∪ I3 , J4 ∪ I14 (classes that do not contain constant functions). Proof. Because of x∨c1 (x) = v2 (x) the set J1 ∪A1 is not closed. To determine all closed subsets T of J1 ∪ A1 , we distinguish the following cases: Case 1: c0 ∈ T1 . Then for every function f ∈ T , we have F (f ) ⊆ T 1 . Thus T2 is a subset of I1 , and we have {max, x ∨ j5 (y), x ∨ j2 (y)} ∩ T = ∅ and {j5 (x) ∨ u2 (y), x ∨ u2 (y)} ∩ T = ∅. If {max, x ∨ j5 (y)} ∩ T = ∅, T does not contain c1 , since x ∨ c1 (x) = v2 (x) ∈ T . Case 1.1: max ∈ T2 . In this case, the class T is also describable in the form T = [T 1 ∪[max}]. With
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
the aid of Theorems 15.4.3.1, 15.4.4.1, 15.4.5.3 and Table 15.14, one obtains the classes given in 1). Case 1.2: max ∈ T2 . Case 1.2.1: x ∨ j5 (y) ∈ T2 . If one examines the possibilities that arise from Theorems 15.4.4.1 and 15.4.5.3 for T , then one sees that only the sets J14 ∪ I13 and J2 ∪ I8 are closed. Case 1.2.2: x ∨ j5 (y) ∈ T2 and x ∨ j2 (y) ∈ T2 . In this case, we have T2 = I14 and T1 contains J12 . Then, the possibilities for T are: Ji ∪ I14 , where i ∈ {1, 2, 5, 6, 11, 12}). Case 2: c0 ∈ T1 and c1 ∈ T1 . Because of x ∨ c1 (x) = v2 (x), c1 ∨ ui = vi (i = 2, 5) and j2 (c1 ) ∨ u2 = u2 , only classes T are possible with {max, x ∨ j5 (y), x ∨ u2 (y), x ∨ u5 (y), j2 (x) ∨ u2 (y), j5 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} ∩ T = ∅. Hence, by Theorem 15.4.4.1 and Section 15.4.5, T1 ∈ {H3 , J7 , J3 } and T2 = I14 , where every possibility supplies a closed class, which is given in 3). Case 3: {c0 , c1 } ∩ T = ∅. In this case, by Theorem 15.4.4.1, T1 ∈ {H9 , J16 , J8 , J4 }. Further, we have {max, x ∨ j2 (y), x ∨ j5 (y), x ∨ u2 (y), j5 (x) ∨ u2 (y)} ∩ T = ∅ and
{x ∨ u5 (y), j2 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} ∩ T = ∅.
Thus T1 = H9 is not possible. We must only continue to examine, therefore, the following three cases: Case 3.1: T1 = J16 . Then, T can not contain the functions x ∨ j2 (y), x ∨ u2 (y) and j5 (x) ∨ u2 (y); thus T2 ∈ {I13 , B19 , I10 } and T ∈ {J16 ∪ I13 , J16 ∪ I10 }. Case 3.2: T1 = J8 . In this case, we have T ∩ {max, x ∨ j5 (y)} = ∅ and T2 ⊆ I4 . By scrutinizing the possibilities that result, one receives T ∈ {J8 ∪ I4 , J8 ∪ I7 , J8 ∪ I14 }. Case 3.3: T1 = J4 . The following cases are still possible, then: Case 3.3.1: max ∈ T2 . Then T contains the class J4 ∪ I5 . Because of j5 (x) ∨ u2 (y) ∈ [{j5 , x ∨ u2 (y)}] the set J4 ∪ I2 is not closed, and only the classes T with T = J4 ∪ I5 or T = J4 ∪ I1 fulfill the conditions of this case. Case 3.3.2: max ∈ T2 . Case 3.3.2.1: x ∨ j5 (y) ∈ T . Since x ∨ j5 (j5 (x) ∨ j2 (y)) = x ∨ j2 (y), T contains the class I8 and it holds that T ∈ {J4 ∪ I8 , J4 ∪ I3 }. Case 3.3.2.2: {j5 (x) ∨ u2 (y), x ∨ u2 (y)} ∩ T = ∅ and x ∨ j5 (y) ∈ T . Because of (j5 (x) ∨ j5 (y)) ∨ u2 (x) = x ∨ j5 (y), this case is not possible. Case 3.3.2.3: x ∨ j2 (y) ∈ T and {x ∨ j5 (y), x ∨ u2 (y), j5 (x) ∨ u2 (y)} ∩ T = ∅. Only the class J4 ∪ I14 can be T in this case.
15.4 The Subclasses of [O1 ∪ {max}]
491
Theorem 15.4.6.3 If T ⊆ U1 ∪ A1 , then T is exactly one of the following classes: 1) H2 ∪ B19 , H6 ∪ B19 , U6 ∪ B4 , U7 ∪ B8 , U3 ∪ B4 , U4 ∪ B8 , U2 ∪ B1 , U1 ∪ B1 (classes that contain {c0 , max}; 2) U1 ∪ B3 , U2 ∪ B3 , U3 ∪ B14 , U6 ∪ B14 , U4 ∪ B16 , U7 ∪ B16 (classes T with c0 ∈ T and max ∈ T ); 3) H4 ∪ B19 , H4 ∪ B10 , U5 ∪ B1 , U8 ∪ B4 , U9 ∪ B2 , U9 ∪ B6 , U10 ∪ B8 (classes T with {c2 , max} ⊆ T and c0 ∈ T ); 4) H4 ∪ B18 , U5 ∪ B3 , U8 ∪ B14 , U9 ∪ B5 , U9 ∪ B9 (classes T with {c2 , x ∨ u2 (y)}, c0 ∈ T and max ∈ T ); 5) U9 ∪ Bi (i ∈ {7, 11, 13, 17}), U10 ∪ Bt (t ∈ {12, 15, 16, 20}) (classes T with {c2 , x ∨ u5 (y)} ⊆ T and {c0 , max, x ∨ u2 (y)} ∩ T = ∅). Proof. Since U1 \[{c0 , c1 }] ⊆ A1 , we have T ∩ {c0 , c2 } = ∅. Case 1: c0 ∈ T1 . In this case, it holds that F (f ) ⊆ T 1 for all f ∈ T . Because of Section 15.4.5, then, we have either B18 or B19 or B20 as a subset of T . Case 1.1: max ∈ T2 (B19 ⊆ T ). Then [T 1 ∪ {max}] = T , and because of Theorems 15.4.3.1, 15.4.4.2, and 15.4.5.2, for T there are only the possibilities given in 1). Case 1.2: max ∈ T2 . If x ∨ u2 (y) ∈ T2 (i.e., B18 ⊆ T2 ) then u2 belongs to T1 , and by Theorem 15.4.5.2, we have T2 ∈ {B3 , B14 }. Thus T ∈ {U6 ∪ B14 , U3 ∪ B14 , U2 ∪ B3 , U1 ∪ B3 }. In the case x∨u5 (y) ∈ T2 (i.e., B20 ⊆ T2 ) and x∨u2 (y) ∈ T , only T1 ∈ {U4 , U7 } and T2 = B16 are possible (because of c0 ∈ T ). Therefore, in Case 1.2, only the classes given in 2) are possible. Case 2: c0 ∈ T1 and c2 ∈ T1 . Since jr (c2 ) ∨ us = vs and x ∨ jr (c2 ) = v2 (r, s ∈ {2, 5}), we have T ∩ {jr (x) ∨ us (y), x ∨ jr (y) | r, s ∈ {2, 5}} = ∅ and, by Section 15.4.5, T contains either B18 , B19 or B20 . Case 2.1: max ∈ T2 . Then T1 belongs to {H4 , U5 , U8 , U9 , U10 } and T2 belongs to {B1 , B2 , B4 , B6 , B8 , B10 , B19 }. In 3) those classes of the form T1 ∪ T2 are given, which are closed. Case 2.2: max ∈ T and x ∨ u2 (y) ∈ T . In this case, by Theorem 15.4.5.2, we have T2 ∈ {B3 , B5 , B9 , B14 , B18 }. Then T1 belongs to the set {H4 , U5 , U8 , U9 }. When one considers the possible cases, one receives the classes given in 4). Case 2.3: {max, x ∨ u2 (y)} ∩ T = ∅ and x ∨ u5 (y) ∈ T .
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
Then it holds that T2 ∈ {U9 , U10 } and T2 ∈ {B7 , B11 , B12 , B13 , B15 , B16 , B17 , B20 }. The closed sets of the form T1 ∪ T2 are given in 5). Theorem 15.4.6.4 If T ⊆ V1 ∪ A1 , then T is exactly one of the following classes: 1) V1 ∪ I5 , V1 ∪ I12 , V1 ∪ B19 , V15 ∪ Is (s ∈ {2, 5, 6, 10, 11}), V15 ∪ B10 , V15 ∪ B19 , V17 ∪ It (t ∈ {2, 5, 6, 10, 11}), V17 ∪ B10 , V17 ∪ B19 (classes that belong {c1 , max}); 2) V15 ∪ B18 , V15 ∪ I9 , V17 ∪ B18 , V17 ∪ I9 (classes T with {c1 , x ∨ u2 (y)} ⊂ T and {max, x ∨ j5 (y)} ∩ T = ∅); 3) V ∪ I8 (V ∈ {H32 , H34 , V1 , V3 , V15 , V17 }), V ∪ I13 (V ∈ {H32 , H34 , V1 , V3 , V5 , V7 , V15 , V17 }) (classes T with {c1 , x ∨ j5 (y)} ⊂ T and {max, x ∨ u2 (y)} ∩ T = ∅); 4) V ∪ I14 (V ∈ {H3 , H32 , H34 , V15 , V17 }) (classes T with x ∨ j2 (y) ∈ T and {max, x ∨ u2 (y), x ∨ j5 (y)} ∩ T = ∅); 5) V2 ∪ B19 , V10 ∪ B19 , V13 ∪ B19 , V2 ∪ I13 , V4 ∪ I13 , V8 ∪ I13 , V2 ∪ I8 , V4 ∪ I8 , V2 ∪ I10 , V2 ∪ I5 (classes T with {c2 , v5 } ⊂ T and c1 ∈ T ); 6) H4 ∪ B10 , H4 ∪ B19 , H31 ∪ Ir (r ∈ {3, 7, 8, 12, 13, 14}), V16 ∪ Bs (s ∈ {10, 18, 19}), V16 ∪ It (t ∈ {1, 2, 4, 5, 6, 9, 10, 11}) (classes T with c2 ∈ T and T ∩ {c1 , v5 } = ∅); 7) H29 ∪ Ir (r ∈ {3, 7, 8, 12, 13, 14}), V18 ∪ Bs (s ∈ {10, 18, 19}), V18 ∪ It (t ∈ {1, 2, 4, 5, 6, 9, 10, 11}) (classes T with T ∩ {c1 , c2 } = ∅). Proof. Because of U1 ∩ A1 = ∅, the set A1 ∪ V1 is not closed and, therefore, T ⊂ V1 ∪ A1 . Since u5 ∈ A for every A ∈ {B20 , A20 }, u2 ∈ A14,1 and u2 ∈ B14 , T2 is a certain subclass of I1 . Case 1: c1 ∈ T1 . Then, because of j5 ∨ u2 (c1 ) = j5 , we have j5 (x) ∨ u2 (y) ∈ T2 . Case 1.1: max ∈ T2 . Since x∨c1 = v2 (x), it holds that V17 ⊆ T1 . With the aid of Theorems 15.4.4.3 and 15.4.5.3, one obtains only the possibilities given in 1) for T .
15.4 The Subclasses of [O1 ∪ {max}]
493
Case 1.2: max ∈ T2 . By Theorem 15.4.5.3 and because of j5 (x) ∨ u2 (y) ∈ T , only the following three cases are possible: Case 1.2.1: x ∨ u2 (y) ∈ T2 . Because of c1 ∨u2 = v2 it holds V17 ⊆ T1 . Further, because x∨u2 (v5 ) = u5 (x), v5 ∈ T . Hence, T ∈ {V15 ∪ B18 , V15 ∪ I9 , V17 ∪ B18 , V17 ∪ I9 }. Case 1.2.2: x ∨ u2 (y) ∈ T2 and x ∨ j5 (y) ∈ T2 . Because of Theorem 15.4.5.3, this case is only possible for T2 ∈ {I8 , I13 }. With the aid of Theorem 15.4.4.3, this implies that T is a class given in 3). Case 1.2.3: T2 = I14 (= [{x ∨ j2 (y)}]). Because of x ∨ j2 (v5 (y)) = x ∨ j5 (y), the function v5 does not belong to T1 . With the aid of Theorem 15.4.4.3 this implies that T is a class which is given in 4). Case 2: c1 ∈ T1 and c2 ∈ T1 . We distinguish two cases: Case 2.1: v5 ∈ T1 . Because of j5 (x) ∨ u2 (v5 (x)) = u5 (x) ∈ T and x ∨ u2 (v5 (x)) = u5 (x) ∈ T , T2 cannot contain j5 (x) ∨ u2 (y) or x ∨ u2 (y). Further, we have: x ∨ j2 (y) ∈ T =⇒ x ∨ j2 (v5 (y)) = x ∨ j5 (y) ∈ T. Thus T2 ∈ {B19 , I5 , I8 , I10 , I13 } and V10 ⊆ T1 . Because of c1 ∈ T , this implies T1 ∈ {V2 , V4 , V6 , V8 , V10 , V13 , V14 }. The possibilities resulting for T are given in 5). Case 2.2: v5 ∈ T1 . Then, because of Theorem 15.4.4.3, T1 ∈ {H4 , H31 , V16 }. The possibilities resulting for T are given in 6). Case 3: {c1 , c2 } ∩ T = ∅. Because of v5 v5 = c2 , v5 ∈ T . Thus, either T1 = H29 = [{v2 }] or T1 = V18 = [{v2 (x) ∨ v2 (y)}]. With the aid of Theorem 15.4.5.3, this implies that T is a class which is given in 7).
Theorem 15.4.6.5 If T ⊆ (J1 ∪ U1 ) ∪ A1 , T1 ⊆ J1 ∪ A1 and T1 ⊆ U1 ∪ A1 , then T is exactly one of the following classes: 1) (J4 ∪ U13 ) ∪ Ai (i ∈ {3, 16, 21, 26, 30}), (J16 ∪ U14 ) ∪ Am (m ∈ {17, 18, 19, 20, 22, 23, 24, 25, 33, 35, 36, 37}), (J12 ∪ U6 ) ∪ Ap (p ∈ {4, 7, 9, 10, 11, 13}), (J12 ∪ H19 ) ∪ An (n ∈ {12, 14, 15}), (J12 ∪ H19 ) ∪ As,r (s ∈ {14, 15}), r ∈ N), (J12,r ∪ H19 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (J14 ∪ U7 ) ∪ Aq (q ∈ {17, 18, 19, 20, 22, 23, 24, 25, 33, 35, 36, 37}),
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
(J10,r ∪ H19 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (J10 ∪ H19 ) ∪ At (t ∈ {12, 14, 15}), (J10 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J16 ∪ H19 ) ∪ Ai (i ∈ {8, 12, 14, 15}), (J16 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J10 ∪ U6 ) ∪ Am (m ∈ {11, 13}), (J6 ∪ U6 ) ∪ An (n ∈ {5, 10, 11, 13}), (J2 ∪ H19 ) ∪ Ap (p ∈ {6, 12, 14, 15}), (J2 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J2 ∪ U6 ) ∪ Aq (q ∈ {2, 10, 11, 13}), (J2 ∪ U2 ) ∪ A1 (classes T with {c0 , c1 } ∩ T = ∅); 2) (J11 ∪ H19 ) ∪ Ai (i ∈ {12, 14, 15}), (J11 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J11 ∪ U6 ) ∪ Am (m ∈ {10, 11, 13}), (J11,r ∪ H19 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (J9 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J9,r ∪ H19 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (J5 ∪ H19 ) ∪ An (n ∈ {12, 14, 15}), (J5 ∪ H19 ) ∪ As,r (s ∈ {14, 15}; r ∈ N), (J1 ∪ H19 ) ∪ Ap (p ∈ {12, 14, 15}), (J1 ∪ H19 ) ∪ As,r (s ∈ {14, 15}, r ∈ N), (J9 ∪ U6 ) ∪ Aq (q ∈ {11, 13}), (Ji ∪ U6 ) ∪ At (i ∈ {1, 5}, t ∈ {10, 11, 13}) (classes T with c1 ∈ T and c2 ∈ T ). Proof. Case 1: c2 ∈ T1 . Case 1.1: c1 ∈ T1 . In this case, T is a subset of (J2 ∪ U2 ) ∪ A1 . Table 15.20 indicates the possibilities for T1 that result from Theorem 15.4.4.4: Table 15.20 T11 1 H50 1 H51 1 H52 1 H57 1 H60
T1 J4 ∪ U13 , J16 ∪ U14 J12 ∪ H19 , J12 ∪ U6 , J12,r ∪ H19 J14 ∪ U7 J10 ∪ H19 , J10,r ∪ H19 , J10 ∪ U6 , J6 ∪ H19 , J6 ∪ U6 , J2 ∪ H19 , J2 ∪ U6 J2 ∪ U2
Then, by Section 14.4.5, we have T ∩ {j2 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} = ∅.
15.4 The Subclasses of [O1 ∪ {max}]
495
Consequently, with the aid of Theorems 15.4.5.4 and 15.4.5.5, one obtains the classes of 1) as possibilities for T , where these classes are sorted after the cases that result from Table 15.20. Case 1.2: c1 ∈ T1 . Because of T ∩ R ⊆ V1 , this case is only possible for T ∩ {max, x ∨ u2 (y), x ∨ u5 (y), x ∨ j5 (y), j5 (x) ∨ u2 (y), j5 (x) ∨ u5 (y)} = ∅. Consequently, we have A14,1 ⊆ T2 ⊆ A10 or T2 = A16 . Because of Theorem 15.4.4.4, T1 can be only a class from Table 15.21. Table 15.21 T21 1 H14 1 H53 1 H58
T2 H5 ∪ U6 J11 ∪ H19 , J11 ∪ U6 , J11,r ∪ H19 J9 ∪ H19 , J9,r ∪ H19 , J5 ∪ H19 , J1 ∪ H19 , J9 ∪ U6 , J5 ∪ U6 , J1 ∪ U6
When one scrutinizes the cases resulting from that, one receives the classes of 2). Case 2: c2 ∈ T1 . Then, by T ∩ R ⊆ V1 , we have {j2 (x) ∨ u2 (y), j5 (x) ∨ u2 (y), j5 (x) ∨ u5 (y), x ∨ j5 (y)} ∩ T = ∅ and T2 ⊆ B1 . Thus T contains x ∨ u2 (y) or x ∨ u5 (y). If T ∩ J1 = [{c1 }], then we have T ∩ {j2 , j5 } = ∅. However, by T2 ⊆ B1 , this cannot be possible. Equally, the case T ∩ J1 = [{c1 }] is not possible, since v2 ∈ [{c1 , x ∨ u2 (y)}] and v5 ∈ [{c1 , x ∨ u5 (y)}]. Thus the second case cannot occur.
Theorem 15.4.6.6 If T ⊆ (J1 ∪ V1 ) ∪ A1 , T1 ⊆ J1 ∪ A1 and T1 ⊆ V1 ∪ A1 , then T is exactly one of the following classes: 1) (H14 ∪ Vi ) ∪ B19 (i ∈ {1, 15, 17}), (J11 ∪ Vm ) ∪ I11 (m ∈ {15, 17}), (J13 ∪ Vn ) ∪ I10 (n ∈ {1, 15, 17}), (J1 ∪ Vp ) ∪ I5 (p ∈ {1, 15, 17}) (classes that contain {c0 , max}); 2) (J13 ∪ V ) ∪ I13 (V ∈ {H32 , H34 , V1 , V3 , V5 , V7 , V17 }), (J11 ∪ V ) ∪ I14 (V ∈ {H32 , V17 , H34 , V15 }), (Ji ∪ V ) ∪ I14 (i ∈ {1, 5}, V ∈ {H32 , V17 , H34 , V15 }), (J1 ∪ V ) ∪ I8 (V ∈ {H32 , V17 , H34 , V15 , V1 }) (classes that contain c0 but not max); 3) (J15 ∪ V15 ) ∪ I10 , (J3 ∪ V15 ) ∪ I5 , J3 ∪ V15 ) ∪ I1 , (J7 ∪ V15 ) ∪ I4 ,
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15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
(J15 ∪ H34 ) ∪ I15 , (J15 ∪ V15 ) ∪ I15 , (J3 ∪ H34 ) ∪ I10 , (J3 ∪ V15 ) ∪ I10 , (J7 ∪ H34 ) ∪ I7 , (J7 ∪ V15 ) ∪ I7 , (J3 ∪ H34 ) ∪ I14 , (J3 ∪ V15 ) ∪ I14 , (J7 ∪ H34 ) ∪ I14 , (J7 ∪ V15 ) ∪ I14 , (J15 ∪ V1 ) ∪ I10 , (J3 ∪ V1 ) ∪ I5 , (J3 ∪ V1 ) ∪ I1 , (J3 ∪ V1 ) ∪ I8 , (J15 ∪ V7 ) ∪ I13 , (J15 ∪ V5 ) ∪ I13 , (J15 ∪ V3 ) ∪ I13 , (J15 ∪ V1 ) ∪ I13 (classes that contain c2 but not c0 ); 4) (J15 ∪ V17 ) ∪ I10 , (J15 ∪ V17 ) ∪ I5 , (J15 ∪ V17 ) ∪ I1 , (J7 ∪ V17 ) ∪ I4 , (J7 ∪ V17 ) ∪ I1 , (J15 ∪ H32 ) ∪ I13 , (J15 ∪ V17 ) ∪ I13 , (J3 ∪ H32 ) ∪ I8 , (J3 ∪ V17 ) ∪ I3 , (J7 ∪ H32 ) ∪ I12 , (J7 ∪ H32 ) ∪ I7 , (J7 ∪ H32 ) ∪ I14 , (J7 ∪ V17 ) ∪ I14 , (J3 ∪ H32 ) ∪ I14 , (J3 ∪ V17 ) ∪ I14 (classes T with {c0 , c1 , c2 } ∩ T = {c1 }). Proof. Because of T ∩ U1 = ∅, we have {j2 (x) ∨ u2 (y), j5 (x) ∨ u5 (y), x ∨ u5 (y)} ∩ T = ∅, Thus T2 ⊆ I1 . Then the following cases are possible: Case 1: c0 ∈ T1 . Then {j5 (x) ∨ u2 (y), x ∨ u2 (y)} ∩ T = ∅. Case 1.1: max ∈ T2 . Because of T = [T 1 ∪ {max}], T is one of the classes given in 1) (see also Theorems 15.4.3.1 and 15.4.5.3). Case 1.2: max ∈ T2 . In this case, by Theorem 15.4.5.3, T2 belongs to {I13 , I8 , I14 } and it holds that 1 1 1 , H67 , H73 }, T2 = I13 =⇒ T11 ∈ {H65 1 1 1 1 1 T2 = I14 =⇒ T1 ∈ {H62 , H63 , H70 , H71 }, 1 1 1 1 T2 = I8 =⇒ T1 ∈ {H70 , H71 , H74 }.
From this and from Theorem 15.4.4.5, we get the possibilities given in 2) for T. Case 2: c0 ∈ T1 . Then, because of T ∩ J1 = ∅ and T ∩ V1 = ∅, the function c1 belongs to T . Case 2.1: c2 ∈ T1 . 1 1 , H72 }. Because of Theorems 15.4.4.5 and 15.4.5.3, the possiThen T11 ∈ {H66 bilities 3) for T follow. Case 2.2: c2 ∈ T1 . 1 . Then, with the help of Theorems 15.4.4.5 and In this case, we have T11 = H64 15.4.5.3, one obtains the possibilities given in 4) for T .
15.4 The Subclasses of [O1 ∪ {max}]
497
Theorem 15.4.6.7 If T ⊆ (U1 ∪ V1 ) ∪ A1 , T1 ⊆ U1 ∪ A1 and T1 ⊆ V1 ∪ A1 , then T is exactly one of the following classes: 1) (H2 ∪ V17 ) ∪ B19 , (H6 ∪ V15 ) ∪ B19 , (H6 ∪ V1 ) ∪ B19 , (U6 ∪ V17 ) ∪ B4 , (U3 ∪ V15 ) ∪ B4 , (U4 ∪ V1 ) ∪ B8 , (U1 ∪ V1 ) ∪ B1 (classes that contain max); 2) (U6 ∪ V17 ) ∪ B14 , (U3 ∪ V15 ) ∪ B14 , (U1 ∪ V1 ) ∪ B3 (classes that contain x ∨ u2 (y) but not max); 3) A ∪ Bi (A ∈ {U4 ∪ V9 , U4 ∪ V1 , U4 ∪ V3 , U4 ∪ V5 , U4 ∪ V7 }, i ∈ {16, 20}) (classes T with T ∩ {max, x ∨ u2 (y)} = ∅ and x ∨ j5 (y) ∈ T ). Proof. Because of T ⊆ V1 ∪ A1 , we have c0 ∈ T1 . T ∩ V1 = [{c2 }] implies c1 ∈ T1 . Hence, T2 ⊆ B1 . By Theorem 15.4.5.2, only the following cases are possible: Case 1: max ∈ T2 . Then T = [T 1 ∪ {max}] and one obtains the possibilities given in 1) of T with the aid of Theorems 15.4.3.1, 15.4.4.6, and 15.4.5.2. Case 2: max ∈ T2 . Then {x ∨ u2 (y), x ∨ u5 (y)} ∩ T = ∅. Case 2.1: x ∨ u2 (y) ∈ T2 . Every class T that satisfies this condition is given in 2). Case 2.2: x ∨ u5 (y) ∈ T and x ∨ u2 (y) ∈ T . 1 1 1 , H84 , H86 } and the possibilities for T are given Then T11 is an element of {H81 in 3). Theorem 15.4.6.8 If T ⊆ R ∪ A1 , T1 ⊆ J1 ∪ U1 ∪ A1 , T1 ⊆ J1 ∪ V1 ∪ A1 and T1 ⊆ U1 ∪ V1 ∪ A1 , then T is exactly one of the following classes: 1) (J11 ∪ U6 ∪ V17 ) ∪ A4 , (J11 ∪ U3 ∪ V5 ) ∪ A4 , (J1 ∪ U6 ∪ V17 ) ∪ A2 , (J1 ∪ U3 ∪ V15 ) ∪ A2 , (J13 ∪ U4 ∪ V1 ) ∪ A31 , (J1 ∪ U1 ∪ V1 ) ∪ A1 (classes that contain {c0 , max}); 2) (J11 ∪ U6 ∪ V17 ) ∪ A7 , (J11 ∪ H19 ∪ H32 ) ∪ A12 , (J11 ∪ U6 ∪ V17 ) ∪ A10 , (J11 ∪ H19 ∪ H32 ) ∪ A (A ∈ {A14 , A15 , A14,r , A15,r | r ∈ N}), (J11 ∪ U6 ∪ V17 ) ∪ Ai (i ∈ {11, 13}), (J11,r ∪ H19 ∪ H32 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r) 1 ); (classes T with max ∈ T and T11 = H87 3) (J11 ∪ U3 ∪ V15 ) ∪ A7 , (J11 ∪ H24 ∪ H34 ) ∪ A12 , (J11 ∪ U3 ∪ V17 ) ∪ A10 , (J11 ∪ H24 ∪ H34 ) ∪ A (A ∈ {A14 , A15 , A14,r , A15,r | r ∈ N}), (J11 ∪ U3 ∪ V15 ) ∪ Ai (i ∈ {11, 13}),
498
4) 5)
6)
7) 8)
15 Finite and Countably Infinite Sublattices of Depth 1 or 2 of L3
(J11,r ∪ H24 ∪ H34 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r) 1 ); (classes T with max ∈ T and T11 = H88 (J13 ∪ U4 ∪ V9 ) ∪ Ai (i ∈ {19, 20, 24, 25, 36, 37}) 1 ); (classes T with max ∈ T and T11 = H90 (J5 ∪ U6 ∪ V17 ) ∪ A5 , (J1 ∪ H19 ∪ H32 ) ∪ A6 , (J5 ∪ H19 ∪ H32 ) ∪ A12 , (J1 ∪ H19 ∪ H32 ) ∪ A12 , (J5 ∪ U6 ∪ V17 ) ∪ A10 , (J1 ∪ U6 ∪ V17 ) ∪ A10 , (J5 ∪ H19 ∪ H32 ) ∪ A8 , (Ji ∪ U6 ∪ V17 ) ∪ At (i ∈ {1, 5, 9}, t ∈ {11, 13}), (Ji ∪ H19 ∪ H32 ) ∪ At (i ∈ {1, 5, 9}, t ∈ {14, 15}), (J9,r ∪ H19 ∪ H32 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (Ji ∪ H19 ∪ H32 ) ∪ As,r (i ∈ {1, 5, 9}, s ∈ {14, 15}, r ∈ N) 1 ); (classes T with max ∈ T and T11 = H91 (J5 ∪ U3 ∪ V15 ) ∪ A5 , (J1 ∪ H24 ∪ H34 ) ∪ A6 , (Ji ∪ H24 ∪ H34 ) ∪ A12 (i ∈ {1, 5}), (Ji ∪ U3 ∪ V15 ) ∪ A10 (i ∈ {1, 5}), (J5 ∪ H24 ∪ H34 ) ∪ A8 , (Ji ∪ U3 ∪ V15 ) ∪ At (i ∈ {1, 5, 9}, t ∈ {11, 13}), (Ji ∪ H24 ∪ H34 ) ∪ At (i ∈ {1, 5, 9}, t ∈ {14, 15}), (J9,r ∪ H24 ∪ H34 ) ∪ As,r (s ∈ {14, 15}; r, r ∈ N; r ≤ r), (Ji ∪ H24 ∪ H34 ) ∪ As,r (i ∈ {1, 5, 9}, s ∈ {14, 15}, r ∈ N) 1 ); (classes T with max ∈ T and T11 = H94 (J13 ∪ U4 ∪ Vi ) ∪ At (i ∈ {1, 3, 5}, t ∈ {18, 19, 23, 24, 36}), (J13 ∪ U4 ∪ Vi ) ∪ At (i ∈ {1, 3, 5, 7}, t ∈ {20, 25, 37}) 1 ); (classes T with max ∈ T and T11 = H94 M 1 ). (class T with max ∈ T and T11 = H91
Proof. Because of T ⊆ (J1 ∪ V1 ) ∪ A1 , we have c0 ∈ T1 . Case 1: max ∈ T2 . Then T = [T 1 ∪ {max}] and one obtains the possibilities for T given in 1) with the aid of Theorem 15.4.3.1. Case 2: max ∈ T2 . Since c0 ∈ T , we have T11 = Hi1 with i ∈ {87, 88, 90, 91, 92, 94, 95} by Theorems 15.4.3.1 and 15.4.4.7. With the aid of Theorems 15.4..4.7, 15.4.5.2– 15.4.5.5, one obtains the possibilities given in 2)–8) for T .
16 The Maximal Classes of Q ⊆ Ek
a∈Q
P olk {a} for
In this section we describe all maximal classes of the subclass TQ := P olk {a} a∈Q
of Pk for arbitrary Q with ∅ = Q ⊆ Ek , k ≥ 2. With the aid of these classes, a completeness criterion for TQ can easily be formulated. This criterion implies necessary and sufficient conditions regarding whether a finite algebra is semiprimal and has only trivial subalgebras. Moreover, if |Q| ≥ 2, we prove that every maximal class of TQ is an intersection of TQ with a certain maximal classes of Pk or P olk {a} (a ∈ Q).Presumably, something similar is valid for the maximal classes of TQ := ∈Q P olk , where Q ⊆ P(Ek ) and |Q | ≥ 2. For k = 3 this presumption was proven in [Lau 95b].
16.1 Notations We say that a relation is derivable from the relation with the aid of Invk TQ (or briefly is -derivable), if ∈ [{} ∪ Invk TQ ] (see Section 2.4). In this case we also write {} ∪ TQ or briefly
.
The following lemma provides the basis of later proofs and summarizes some well-known statements that can easily be checked. Lemma 16.1.1 (a) ∀, ∈ Rk : (P ol ⊆ TQ ∧ ({} ∪ Invk TQ ) =⇒ P ol ⊆ TQ ∩ P ol ); (b) Invk Pk = Dk (see Chapter 2);
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16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
(c) For every relation ∈ Invk TQ there are some relations 1 , ..., r ∈ {{a} | a ∈ Q} ∪ Dk and a relation ∈ Dk with = (1 × 2 × ... × r ) ∩ . Next we define some relation sets that we need to describe of the maximal classes of TQ (Q ⊆ Ek ). In this case, we also use the notations from Chapter 5. ⎧ { ∈ Mk | a is greatest or smallest element of Ek in respect to ⎪ ⎪ ⎪ ⎪ }, ⎪ ⎪ ⎪ ⎪ ⎨ if Q = {a}, Mk;Q := { ∈ Mk | a is greatest (smallest) and b is smallest (greatest) ⎪ ⎪ ⎪ element of Ek in respect to }, if Q = {a} and ⎪ ⎪ ⎪ ⎪ a = b, ⎪ ⎩ ∅ otherwise; ⎧ ⎪ ⎨ { ∈ Uk | ∀x ∈ Ek ∀q ∈ Q : (x, q) ∈ =⇒ x = q}, Uk;Q := if |Q| ≤ k − 2, ⎪ ⎩ ∅ otherwise; ⎧ ⎪ ⎨ { ∈ Sk | ∀x, y ∈ Ek : (x, y) ∈ ∧ x ∈ Q =⇒ y ∈ Q}, if |Q| = s · p, k = t · p, p prime, Sk;Q := ⎪ ⎩ ∅ otherwise; Pk,Q := { {(x, s(x)) | x ∈ Ek } | s is a permutation on Ek with exactly one fixed point (∈ Q); all proper cycles of s have the same prime number length, and s preserves Q }; ⎧ 3 { {(a, b, c) ∈ Ek | a +G b = c} | (Ek ; +G ) is an elementar Abelean ⎪ ⎪ ⎪ 2-group with the neutral element ⎨ Lk;Q := q }, ⎪ ⎪ if k = 2m , m ≥ 1 and Q = {q}, ⎪ ⎩ ∅ otherwise; Ck;Q := (C1k \{{q} | q ∈ Q}) ∪
k−1
h=2 {
∈ Chk | ∀q ∈ Q : q is a central element of }
(in particular, we have Ck;Ek = C1k \{{q} | q ∈ Ek }) and ⎧ 2 2 2 ⎪ ⎨ { (\ιk ) ∪ {(q, q)} | ∈ Ck;Q ∪ {Ek }}, if Q = {q}, Nk;Q := { ⊆ E 2 |∃q ∈ Q : {(x, q), (q, x) | x ∈ Ek } ⊆ ∧ τ ρ = ρ ∧ k ⎪ ⎩ ∩ ι2k = {(q, q)} ∧ ∩ ((Q\{q}) × (Ek \{q})) = ∅} , if 2 ≤ |Q|. Obviously, Nk;Q ⊆ a∈Q Nk;{a} . An element c ∈ Q with {(x, c), (c, x) | x ∈ Ek \{c}} ⊆ (∈ Nk;Q ) is called central element of . If one considers an arbitrary other finite set A instead of Ek , then the relation
16.2 Results of Chapter 16
501
sets MA , MA;Q , UA , UA;Q , SA , SA;Q , PA;Q , LA , LA;Q , CA , CA;Q , NA;Q and BA for Q ⊆ A can be defined when one replaces the set Ek by A in the above definitions or in the definitions of Chapter 5.
16.2 Results of Chapter 16 Our aim is to prove the following Theorem 16.2.1 ( [Sze 91], [Lau 82b], [[Lau 95a]) Let Rmax (TQ ) := Mk;Q ∪ Uk;Q ∪ Sk;Q ∪ Lk;Q ∪ Ck;Q ∪ Nk;Q ∪ Pk;Q . Then {TQ ∩ P olk | ∈ Rmax (TQ )} is the set of all maximal classes of TQ for ∅ = Q ⊆ Ek . The following theorem is a direct conclusion from the above theorem and from the fact that TQ is finitely generating (see Lemma 16.3.1): Theorem 16.2.2 (Completeness Criterion for TQ ) For an arbitrary subset M of TQ is valid: [M ] = TQ ⇐⇒ ∀ ∈ Rmax (TQ ) : M ⊆ TQ ∩ P olk .
The next theorem is a special case of Theorem 16.2.2: Theorem 16.2.3 (Completeness Criterion for the Class of all Idempotent Functions of Pk ) For an arbitrary subset M of TEk ( = n≥1 {f n ∈ Pk | f (x, ..., x) = x}) with k ≥ 3 is valid: [M ] = TEk ⇐⇒ ∀ ∈ C1k;Ek ∪ Sk;Ek ∪ Pk;Ek ∪ Nk;Ek : M ⊆ TEk ∩ P olk . Theorem 16.2.1 can also be formulated in the language of the Universal Algebra: 1 F A finite algebra (A; F ) (F ⊆ PA ) is called semi-primal, if [F ] = P olA InvA holds (see [Fos-P 64], [Den 82], [P¨ os-K 79], p. 143) or [Den-W 2002]. Let 1 F is the set of all uniSub(A) be the set of all subalgebras of A. Then InvA verses of algebras of Sub(A). If Sub(A)\{A} contains only 1-element algebras and Q := {a | ({a}; F ) ∈ Sub(A)} holds, then every ∈ Inv F ∩(PA;Q ∪Sk;Q )
502
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
defines a non-trivial automorphism s (s(a) = b :⇐⇒ (a, b) ∈ ) of the algebra A and the relations of Uk;Q are some non-trivial congruences of A. Then the following theorem follows from Theorem 16.2.1: Theorem 16.2.4 ([Sze 91]) Let A = (A; F ) be a finite algebra with the property that (SubA)\{A} contains only 1-element algebras. Then the following conditions are equivalent: (a) (A; F ) is semi-primal with {a ∈ A | ({a}; F ) ∈ SubA} = Q. (b) A has no proper automorphisms, is simple (i.e., A has only trivial congruences) and the direct product Ah of A for h = 2, 3, ..., |A|−1 has no subalgebra whose universe is an element of the set MA;Q ∪LA;Q ∪NA;Q ∪CA;Q .
16.3 Some Lemmas Lemma 16.3.1 TQ = [TQ3 ] for all Q with ∅ = Q ⊆ Ek . Proof. For k = 2, our assertion is valid by Chapter 3. Let k ≥ 3. Then the below-defined functions ∨, ·, w, ra;b , if {a, b} ⊂ Ek , qa,b;c , if a = b or {a, b} ⊆ Q and {a, b, c} ⊆ Ek , belong to TQ : x ∨ y := max(x, y), x · y := min(x, y) in respect to the total order 0 < 1 < 2 < . . . < k − 1; x if x = y ∈ Q, w(x, y) := 0 otherwise; b if x = a, ja;b (x) := 0 otherwise; ra;b (x, y, z) := x ∨ ja;b (y) · z; qa,b;c (x, y, z) := x ∨ ja;c (y) · jb;c (z). We show that the above-defined functions form a generating system for TQ . ... w with The function wn := w w n − 1 times x if x1 = x2 = ... = xn = x ∈ Q , wn (x1 , ..., xn ) = 0 otherwise
(n ≥ 1) is a superposition over w. Let f n be an arbitrary function of TQ , which is different from wn . Then one can represent f as follows:
16.3 Some Lemmas
f (x1 , ..., xn ) = wn (x1 , ..., xn )∨ ∈
a = (a1 , ..., an ) Ekn \{(q, q, ..., q) | q f (a) = 0
503
ja1 ;f (a) (x1 ) · ... · jan ;f (a) (xn ). ∈ Q}
Therefore, f is a superposition over the set B := {wn } ∪ {x ∨ ja1 ;b (x1 ) · ... · jan ;b (xn ) | (a1 , ..., an ) ∈ Ekn \{(q, q, ..., q) | q ∈ Q} ∧ b ∈ Ek }. An arbitrary function of B\{wn } is generated from functions of the type ra;b and qa,b;c , since ra1 ,...,ai ,ai+1 ;b (x, x1 , ..., xi , xi+1 , y) := ra1 ,...,ai ;b (x, x1 , ..., xi , rai+1 ;b (x, xi+1 , y)) = x ∨ ja1 ;b (x1 ) · ... · jan ;b (xn ) · y (i = 1, ..., n) and ra1 ,...,an ;b (x, x1 , ..., xn , qai ,aj ;b (x, xi , xj )) = x ∨ ja1 ;b (x1 ) · ... · jan ;b (xn ). Consequently, [T 3 ] = T. The next lemma is a conclusion of the above lemma: Lemma 16.3.2 For every Q with ∅ = Q ⊆ Ek , the lattice of the subclasses of TQ is dual atomar and TQ has only finite-many maximal classes. Since the maximal classes of TQ are clones1 , one can easily show the following Lemma 16.3.3 For every maximal class M of TQ there exists an h-ary relation M with M = P olk M and 1 ≤ h ≤ k 3 . Lemma 16.3.4 Let ∅ = Q ⊆ Ek . Then (a) ∀ ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Bk ∪ (Ck \{{q} | q ∈ Q}) : TQ ⊆ P olk ; (b) Vk↑ (TQ ) = {TQ | Q ⊆ Q} (T∅ := Pk ); (c) ∀ ∈ a∈Q (Pk;{a} ∪ Nk;{a} ) : TQ ∩ P olk ⊂ TQ . Proof. (a) and (c) are easy to check. (b): It is sufficient to prove the following statement for ∅ = Q ⊆ Ek and f ∈ Pk : (a ∈ Q ∧ f (a, a, ..., a) = a) =⇒ TQ\{a} ⊆ [TQ ∪ {f }]. Let f (a, a, ..., a) = a for a certain a ∈ Q, Q ⊆ Ek and f (x) := f (x, x, ..., x). To prove TQ\{a} ⊆ [TQ ∪{f }], let g m ∈ TQ\{a} be arbitrary. Then the function hm+1 defined by g 1
One can prove this analogous to the proof of footnote 1 of Chapter 14.
504
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
⎧ x, if x1 = ... = xm+1 = x ∈ Q, ⎪ ⎪ ⎨ u, if x1 = ... = xm = u ∈ Q\{a} ∧ hg (x1 , .., xm+1 ) := xm+1 = f (u), ⎪ ⎪ ⎩ g(x1 , ..., xm ) otherwise,
belongs to TQ and g(x1 , ..., xm ) = hg (x1 , ..., xm , f (x1 )) is valid. Therefore, g ∈ [TQ ∪ {f }] holds. Lemma 16.3.5 For every relation γ ∈ R := Mk ∪ Uk ∪ Sk ∪ Lk ∪ Bk ∪ (Ck \{{q} | q ∈ Q}) there exists a γ ∈ [{γ} ∪ Invk TQ ], which belongs to Mk;Q ∪ Uk;Q ∪ Sk;Q ∪ Lk;Q ∪ Ck;Q ∪ (Pk;{q} ∪ Nk;{q} ). q∈Q
Proof. Examining the case γ ∈ R\(Mk;Q ∪ Uk;Q ∪ Sk;Q ∪ Ck;Q )
(16.1)
suffices. Further, we can assume that γ is h-ary, where h ≥ 2 because of (16.1). First we form the (h − 1)-ary relation γa := pr1,2,...,h−1 (∆({a} × γ))
(16.2)
for a ∈ Q. If h = 2 (i.e., γ ∈ (C2k \C2k;Q )∪(Mk \Mk;Q )∪(Uk \Uk;Q )∪(Sk \Sk;Q )), then we have (16.3) γa = {x ∈ Ek | (a, x) ∈ γ}. Because of (16.1), it is easy to check that there is an a ∈ Q such that the relation γa belongs to C1k;Q = {E ⊂ Ek | |E| ≥ 2 ∨ ∃b ∈ Ek \Q : E = {b}}: If γ ∈ Mk \Mk;Q , then for this purpose, one can choose a ∈ Q \ {o, e}, where o is the smallest element and e is the greatest element of Ek in respect to γ. If γ ∈ Uk \Uk;Q , then an a ∈ Q of an at least 2-element equivalence class of γ fulfills the above condition. If γ ∈ Sk \Sk;Q , then there exists an a ∈ Q and a b ∈ Ek \Q with (a, b) ∈ γ; thus γa = {b} ∈ C1k;Q . If γ ∈ C2k \C2k;Q , there is an a ∈ Q, which is no central element of γ. Consequently, we also have γa ∈ C1k;Q in this case. Now, let h ≥ 3 and γ ∈ Lk , i.e., γ ∈ Chk ∪ Bhk . Choose a ∈ Q \ C, if γ ∈ Ck and C is the set of all central elements of γ. For γ ∈ Bhk let a ∈ Q be arbitrary. Then the relation γa defined by (16.2) is an (h − 1)-ary reflexive, totally symmetric relation with the same central elements as γ and the new central element a. Since a is no central element of γ, there exist d1 , ..., dh−1 ∈ Ek with (a, d1 , ..., dh−1 ) ∈ γ. Consequently, we have γa = Ekh−1 and γa is a central relation. Through repetitions of the above construction, one obtains a γ-derivable relation of Ck;Q . Finally, let γ ∈ Lk , where k = pm , p prime and m ≥ 1. Then there is an elementar Abelean p-group (Ek ; +) with γ = {(x, y, u, v) ∈ Ek4 | x+y = u+v}. By Lemma 5.2.4.2, we can assume w.l.o.g. that the neutral element o of the p-group (Ek ; +) belongs to Q. For p = 2 we now form the γ-derivable relation
16.3 Some Lemmas
505
5 γ := pr3,4 (δ{0,1,2} ∩ ({o} × γ)) = {(x, y) ∈ Ek2 | x + y = o}.
Obviously, γ ∈ Pk;{o} , since for p = 2 the equation x + x = o is valid only if x = o. If p = 2, then one can form the relation γ := pr1,2,3 (∆({o} × γ)) = {(x, y, z) ∈ Ek3 | x + y = z} ∈ [{γ} ∪ Invk TQ ]. Thus γ ∈ Lk;{o} in the case {o} = Q. If |Q| ≥ 2 there is an a ∈ Q\{o} and the γ-derivable relation 4 γ := pr0,1 ((γ × {a}) ∩ δ{2,3} ) = {(x, a − x) | x ∈ Ek }
belongs to Sk . Further, we have that either γ ∈ Sk;Q is valid or (see above) it is possible to derive from γ a relation of C1k;Q . Lemma 16.3.6 Let |Q| ≥ 2 and γ ∈ a∈Q Pk;{a} ∪ Nk;{a} . Then there exists a ∈ [{γ} ∪ Invk TQ ] with ∈ Pk;Q ∪ Nk;Q ∪ C1k;Q . Proof. First let γ ∈ ( a∈Q Pk;{a} )\Pk;Q . Then there is (b, c) ∈ γ with b ∈ Q and c ∈ Ek \Q. The γ-derivable relation γb := pr1 (∆({b} × γ)) = {x ∈ Ek | (b, x) ∈ γ}
(16.4)
belong to Ck;Q (because of γb = {c}). Finally, let γ ∈ ( a∈Q Nk;{a} )\Nk;Q ; i.e., γ has the following properties: • ∃q ∈ Q : ι2k ∩ γ = {(q, q)} ∧ {(x, q), (q, x) | x ∈ Ek } ⊆ γ; • γ is symmetric and • ∃b ∈ Q \ {q} ∃c ∈ Ek \{b, q} : (b, c) ∈ γ. We form the γ-derivable relation γb (see (16.4)). Then we have {q, c} ⊆ γb and b ∈ γb . Thus γb ∈ C1k;Q . Lemma 16.3.7 Let A := P olk be TQ -maximal, where ∈ Rkt . Moreover, Vk↑ (A)\{A} = Vk↑ (TQ ). Then |Q| = 1 is valid and there exists a relation γ ∈ Pk;Q ∪ Nk;Q with A ⊆ P olk γ. Proof. Because of Lemma 16.3.4, the relation has the following properties: (I) If |Q| ≥ 2, then there is a relation γ ∈ [{} ∪ Invk TQ ] with γ ∈ (Rmax (Pk )\{{q} | q ∈ Q}) ∪ Rmax (T{a} ). a∈Q
In particular, it follows from (I) that t ≥ 2. W.l.o.g. we can assume the following three properties of :
506
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
(II) does not have any double rows. (III) Every -derivable (t−1)-ary relation belongs to Invk TQ (see 16.1.1,(c)). (IV) No -derivable t-ary relation with the properties P olk ⊂ TQ and | | < || exists. From assumptions (II) - (IV), some further properties of the relation follow: (V) does not have a constant row. (Suppose, has a constant row (a, a, ..., a). Because of (I) we have a ∈ Q and it is valid = pr0,...,i−1 × {a} × pri+1,...,t−1 for certain i ∈ Et . Then, with the help of (III) and 16.1.1,(c) one can prove that is an invariant of TQ , contrary to our assumptions about .) A direct consequence from (V) and (III) is: (VI) ∀i ∈ Et : pr0,...,i−1,i+1,...,t−1 = Ekt−1 . Next we show that t (VII) (t ≥ 3 ∨ |Q| = 1) =⇒ ∩ δ{0,1,...,t−1} ∈ {{(q, q, ..., q)} | q ∈ Q}; t (t = 2) =⇒ ∩ δ{0,1} ∈ {∅, {(q, q)} | q ∈ Q}
holds. By (III) we have t t ∩ δ{0,1,...,t−1} ∈ {∅, {(q, q, ..., q)}, δ{0,1,...,t−1} | q ∈ Q}. t t ∩ δ{0,1,...,t−1} = δ{0,1,...,t−1} is not possible, since A = P olk ⊂ TQ and TQ contains at most a constant. t = ∅, the equation pr0,...,t−2 = Ekt−1 (see (VI)) If Q = {a} and ∩ δ{0,1,...,t−1} t+1 implies prt (({a} × ) ∩ δ{0,...,t−1} ∈ C1k;{a} , a contradiction to (I). t = ∅ that prt−2,t−1 ( ∩ In the case that t ≥ 3, it follows from ∩ δ{0,1,...,t−1} t δ{0,...,t−2} ) ∈ Invk TQ , which contradicts (III). Therefore (VII) holds.
As generally known (see Chapter 6), the relation σi () := {(a1 , ..., ai ) ∈ Eki | ∃u ∈ Ek : {(a1 , u), ..., (ai , u)} ⊆ } is derivable from the relation for t = 2, and it is valid that (VIII) (t = 2 ∧ ◦ (τ ) = Ek2 ) =⇒ ∀i ≥ 2 : σi () = Eki . For the relation , the following three cases are possible: Case 1: t = 2. We consider the -derivable relation ∩ (τ ). Case 1.1: ∩ (τ ) ∈ {∅, {(q, q)}} for a certain q ∈ Q. Then is antisymmetric. Because of (VI) the relation ◦(τ ) has the property ι2k ⊆ ◦ (τ ). Case 1.1.1: ◦ (τ ) = ι2k . Because of pr0 = pr1 = Ek (see (VI)) we have || ≥ k. If || > k, there exists a, b, c ∈ Ek with (a, c), (b, c) ∈ and a = b. Thus (a, b) ∈ ◦ (τ ),
16.3 Some Lemmas
507
which is not possible because of ◦ (τ ) = ι2k . Therefore || = k, and has the form {(x, s(x)) | x ∈ Ek }, where s = e11 is a permutation on Ek , which has at most a fixed point (namely q). Assume the permutation has proper cycles of different length. Let r (≥ 2) be the length of a smallest proper cycle. Then we have pr0 (( ◦ ◦ ... ◦ ) ∩ ι2k ) ∈ C1k;Q , r times a contradiction to (I). Therefore, all proper cycles of s have the very same length l. Suppose l = p · m, p prime and m ≥ 2. Then ◦ ◦ ... ◦ has proper m times cycles of the length p; i.e., a relation of the set Sk ∪ Pk;{q} is derivable from the relation . But, this contradicts the condition (I) for |Q| ≥ 2 or ∈ Sk . Therefore, Q = {q} and A ⊆ P olk γ for a certain γ ∈ Pk;{q} in Case 1.1.1. Case 1.1.2: ι2k ⊂ ◦ (τ ) ⊂ Ek2 . In this case, we see that the relation = ◦ (τ ) is not an invariant of TQ and that P olk ⊆ TQ holds, which is not possible because of Vk↑ (A)\{A} = Vk↑ (TQ ). Case 1.1.3: ◦ (τ ) = Ek2 . By (VIII) we have σk () = Ekk . Consequently, there exists a u ∈ Ek with (x, u) ∈ for all x ∈ Ek . Because of ∩ ι2k ∈ {∅, {(q, q)}} (q ∈ Q), this is only possible for ∩ ι2k = {(q, q)} and u = q. If (τ ) ◦ = Ek2 is valid, we can prove {(x, q) | x ∈ Ek } ⊆ τ in analog mode too, through which we receive a contradiction to the antisymmetry of the relation . Therefore ι2k ⊆ (τ ) ◦ ⊂ Ek2 . Consequently, Case 1.1.3 is reducible to Cases 1.1.1 and 1.1.2. Case 1.2: {(q, q)} ⊂ ∩ (τ ) ⊂ . Because of condition (III) this case is not possible. Case 1.3: ∩ (τ ) = . In this case, is symmetric. Further, we have ι2k ⊆ ◦ . We distinguish three cases: Case 1.3.1: ◦ = ι2k . Then is a permutation with at most a fixed point q (if ∩ ι2k = {(q, q)}), and every proper cycle of has the length 2 because of symmetry of , i.e., ∈ Sk ∪ Pk;{q} . Thus, as in Case 1.1.1, we obtain a contradiction to the condition (I) either or |Q| = 1 and A ⊆ P olk γ for certain γ ∈ Pk;Q are valid. Case 1.3.2: ι2k ⊂ ◦ ⊂ Ek2 . This case can be excluded as Case 1.1.2. Case 1.3.3: ◦ = Ek2 . Because of ◦ = ◦ (τ ) = Ek2 and by (VIII), we have σk () = Ekk ,; i.e., there is u ∈ Ek with {(x, u) | x ∈ Ek } ⊆ . Consequently, ∩ ι2k = {(q, q)} and u = q. This and the symmetry of implies that q is a central element of . Therefore, belongs to Nk;{q} . Because of (I), this is only possible for |Q| = 1.
508
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
Case 2: t = 3. 3 = {(q, q, q)} for certain q ∈ Q (see Since pr0,1 = Ek2 (by (VI)), ∩ δ{0,1,2} (VII)) and (III) is valid, we have ∆ = Ek ×{q}, i.e., (a, a, q) ∈ for all a ∈ Ek . Analogously, one can prove that the tuples (a, q, a) and (q, a, a) belong to for every a ∈ Ek . Next we prove that is totally symmetric. Assume the relation is not totally symmetric. Then the -derivable relation {(as(0) , as(1) , as(2) ) | (a0 , a1 , a2 ) ∈ } := s s is permutation on E3 is totally symmetric. Because of ⎛ ⎞ a a q ⎝ a q a ⎠ ⊆ ⊂ (a = q) q a a the relation is not, however, an invariant of TQ . This is a contradiction to the condition (IV). Next we prove (IX) ∀a, b ∈ Ek : {(a, b, c), (a, b, c )} ⊆ =⇒ c = c . Suppose there are a, b, c, c with {(a, b, c), (a, b, c )} ⊆ , and c = c . Then the -derivable relation 6 ) 1 := pr0,2,5 (( × ) ∩ δ{0,3},{1,4} = {(x, y, z) | ∃u ∈ Ek : {(x, u, y), (x, u, z)} ⊆ } 3 has the property P olk 1 ⊆ TQ because of δ{0,1,2} ⊆ 1 . Consequently, 1 is a diagonal relation. Further, it is easy to check that (a, c, c ) ∈ 1 and (d, q, q) ∈ 1 for all d ∈ Ek hold. Therefore, 1 is the diagonal relation Ek3 . For our relation , this means that for arbitrary (x, y, z) ∈ Ek3 there is a u with (x, u, y) ∈ and (x, u, z) ∈ . Then, when one chooses x = y = q and z = q and considers the total symmetry of the relation , there exists an r with r = q and (q, q, r) ∈ . Above ∆ = Ek × {q} was, however, proven. Therefore, our assumption c = c was false. With that, (IX) is valid. Now we consider the -derivable relation
2 := ◦ = {(a, b, c, d) | ∃u ∈ Ek : {(a, b, u), (u, c, d)} ⊆ }. 4 Because of {(a, a, q), (q, a, a) | a ∈ Ek } ⊆ we have δ{0,1,2,3} ⊆ 2 and thus P olk 2 ⊆ TQ . Obviously, the relation 2 does not have any double rows. Because of our assumptions about the relation , however, this is possible only for 2 = Ek4 . Then, by definition of 2 , we have {(a, b, u), (u, c, a)} ⊆ for arbitrary a, b, c ∈ Ek , and certain u. Since is totally symmetric, however,
16.3 Some Lemmas
509
{(a, u, b), (a, u, c)} ⊆ , where b = c is possible, contrary to (IX). Therefore, Case 2 is not possible. Case 3: t ≥ 4. Because of pr0,1,...,t−2 = Ekt−1 (see (VI)), (II), (III) and (VII) we have ∩ t−1 t = δ{0,...,h−3} × {q} for certain q ∈ Q. Since pr0,...,h−3,h−1 = Ekt−1 δ{0,...,h−3} t−2 t is also valid, one can analogously prove ∩ δ{0,...,h−3} = δ{0,..,h−3} × {q} × Ek , contrary to that just shown. Therefore, there is no t-ary relation with the above-demanded properties and t ≥ 4. An equivalence relation ∼ is defined by ∼ :⇐⇒ TQ ∩ P olk = TQ ∩ P olk on a set A ⊆ Rk . We select a representative from every equivalence class of ∼ now and obtain a certain subset of A, which we denote with A∼ , where A ∈ {Pk;Q , Mk;Q , Sk;Q } in the following. Lemma 16.3.8 Let ∅ = Q ⊆ Ek . Then (a) ∀, ∈ Mk;Q : ∼ ⇐⇒ ( = τ ∨ = ); (b) ∀, ∈ Pk;Q ∪ Sk;Q : ∼ ⇐⇒ (∃t : = ◦ ◦ ... ◦ ); t times ∼ ∼ (c) ∀, ∈ M∼ k;Q ∪Sk;Q ∪Pk;Q ∪Uk;Q ∪Nk;Q ∪Lk;Q ∪Ck;Q : ∼ ⇐⇒ = . Proof. The statements (a) and (b) are direct conclusions from the proof of corresponding statements about relations of Mk ∪ Sk (see Chapter 5). To prove (c), we agree that o denotes the smallest element of Ek and that e denotes the greatest element of Ek (in respect to ∈ Mk;Q ). Because of (a), we can assume w.l.o.g. that o ∈ Q. Now, let and be two different relations ∼ ∼ of M∼ k;Q ∪ Sk;Q ∪ Pk;Q ∪ Uk;Q ∪ Nk;Q ∪ Lk;Q ∪ Ck;Q . To prove TQ ∩ P olk ⊆ TQ ∩ P olk
(16.5)
we distinguish the following 9 cases: ∼ Case 1: {, } ⊆ C1k;Q ∪ Uk;Q ∪ P∼ k;Q ∪ Sk;Q . If |Q| ≥ k − 1 then Uk;Q = Pk;Q = Sk;Q = ∅ and (16.5) is obviously valid for the relations , . Let now |Q| ≤ k − 2. Denote ω the relation {(q, q) | q ∈ Q} ∪ (Ek \Q)2 of Uk;Q . It is easy to check that the set A(γ) := {f n ∈ PEk \Q | ∃f ∈ TQ ∩P olk γ : (∀a ∈ (Ek \Q)n : f (a) = f (a))} n≥1
is a maximal class of PEk \Q for γ ∈ (C1k;Q \{γ | γ ⊆ Q ∨ γ = Ek \Q}) ∪ ∼ 1 (Uk;Q \{ω}) ∪ P∼ k;Q ∪ Sk;Q and that A(γ) = PEk \Q holds for γ ∈ {γ ∈ Ck | γ ⊆ Q ∨ γ = Ek \Q} ∪ {ω}. With the aid of Chapters 5 and 6, our assertion (16.5) results from that for ∈ {γ ∈ C1k | γ ⊆ Q ∨ γ = Ek \Q} ∪ {ω}. If ∈ {γ ∈ C1k | γ ⊆ Q ∨ γ = Ek \Q} ∪ {ω}, then it is also easy to prove that
510
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
there is a | |-ary function f1 ∈ TQ ∩ P olk with f1 ( ) ∈ . Consequently, (16.5) is also valid for the remaining relations of the Case 1. 1 Case 2: ∈ C1k;Q and ∈ M∼ k;Q ∪ (Ck;Q \Ck;Q ) ∪ Nk;Q ∪ Lk;Q . The following | |-ary function f2 with the properties f2 ( ) ∈ , f2 (q, ..., q) = q for all q ∈ Q and
f2 (a) = c for the remaining tuples a, where c ∈ ,
belongs to TQ ∩ P olk . Thus (16.5) holds. ∼ ∼ 1 Case 3: ∈ M∼ k;Q ∪ Uk;Q ∪ Pk;Q ∪ Sk;Q and ∈ (Ck;Q \Ck;Q ) ∪ Nk;Q ∪ Lk;Q . Let be an h -ary relation. Further, let q ∈ Q and a ∈ Ek \Q. In addition, if ∈ Nk;Q , then we choose q ∈ Q so that (q, q) ∈ holds. Then the h -tuples (q, a, a, . . . , a), (a, q, a, . . . , a), . . . , (a, a, . . . , a, q) belong to , though not all belong to . Consequently, there exists an h -ary function f3 ∈ TQ ∩ P olk with ⎞ ⎛ q a a . . . a ⎟ ⎜ ⎜a q a . . . a⎟ ⎟∈ ⎜ f3 ⎜ ⎟ / . . . . . . . . ⎠ ⎝ a a a . . . q Hence (16.5) holds in Case 3. ∼ ∼ Case 4: ∈ P∼ k;Q ∪ Sk;Q and ∈ Mk;Q . This case can occur only for |Q| ≤ 2. Further, we have S∼ k;Q = ∅, if |Q| = 1 or k = 3. It is easy to check that (TQ ∩ P olk ) ⊆ (TQ ∩ P olk )1 is valid for k ≥ 3. Case 5: ∈ Uk;Q and ∈ M∼ k;Q . For o ∈ Q the binary function f4 defined by y if x = o , f4 (x, y) := o otherwise, belongs to TQ ∩ P olk . However, f4 does not preserve the relation with the smallest element o , since (f4 (o , e ), f (α, e )) = (e , o ) if α ∈ Ek \{o , e } . 1 Case 6: ∈ M∼ k;Q and ∈ Ck;Q . Let a ∈ Ek \ and
ta (x, y) :=
x if x = y ∈ Q, a otherwise.
The function ta ∈ TQ preserves and does not preserve . Therefore, (16.5) holds.
16.3 Some Lemmas
511
∼ ∼ Case 7: ∈ M∼ and ∈ M∼ k;Q ∪ Uk;Q ∪ Pk;Q ∪ Sk;Q . k;Q r | | , {r, s} ⊂ Ek and f5 a | |-ary function defined by Let = s if ⊆ , ∈ α f5 ( ) := β ∈ \ if ⊂
and, if r < s and hence α < ⎧ o ⎪ ⎪ ⎪ ⎨ α f5 (a) := ⎪ β ⎪ ⎪ ⎩ e
β, if a = (o , o , ..., o ), if o < a < s, if a = s, otherwise,
and, if s and r are incomparable in respect to , ⎧ o if a < r ∨ a < s, ⎪ ⎪ ⎪ ⎨ α if a = r, f5 (a) := ⎪ β if a = s, ⎪ ⎪ ⎩ e otherwise. It is easy to check that f5 ∈ TQ ∩ P olk and f5 ∈ TQ ∩ P olk . ∼ Case 8: ∈ (Ck;Q \C1k;Q ) ∪ Nk;Q and ∈ Uk;Q ∪ M∼ k;Q ∪ Ck;Q ∪ Pk;Q ∪ Sk;Q ∪ Nk;Q ∪ Lk;Q . Let c be a central element of . Further, let f6 be an | |-ary function defined by if ⊆ , ∈ f6 ( ) ∈ \ if ⊂ and f6 (q, q, ..., q) = q for all q ∈ Q and f6 (a) = c for the remaining tuples | | a ∈ Ek . Then f6 ∈ TQ ∩ P olk and f6 ∈ TQ ∩ P olk . Therefore, (16.5) holds. Case 9: ∈ Lk;Q . Then |Q| = 1 and k = 2m , m ≥ 1. W.l.o.g. let Q = {0}. As shown in Chapter 5, one can define the relation with the aid of an elementary Abelean 2-group G, where 0 is the neutral element of G. It follows from the proof of the Lemma 16.3.5 that the relation is derivable from a relation {0} × λ, where λ ∈ L2m . Since ◦ = λ is in addition valid, we have T{0} ∩ P olk λ = P olk . Therefore, by Chapter 5, every n-ary function f ∈ P olk is a quasi-linear function of the form n m−1 j ai,j · x2i , f (x1 , ..., xn ) = i=1 j=0
where a1,0 , ..., an,m−1 ∈ E2m and +(= +G ) and · are the operations of a certain field (E2m ; +, ·) with G = (E2m ; +).
512
16 The Maximal Classes of
a∈Q
P olk {a} for Q ⊆ Ek
Case 9.1: ∈ C1k;Q . Let a ∈ and b ∈ . Then the quasi-linear unary function f7 defined by f7 (x) := (a · b−1 ) · x does not preserve because of f7 (b) = a, i.e., (16.5) holds. Case 9.2: ∈ P∼ k;Q . Let 1 the unit of the multiplicative group of the field (E2m ; +, ·). Since the order of this group is odd, we have a2 = 1 for all a ∈ E2m \{0, 1}. The unary function f8 defined by f8 (x) := x2 belongs to P olk , but it does not preserve , since (by definition of ) there is an a ∈ Ek \{1} with (1, a) ∈ and (f8 (1), f8 (a)) = (1, a2 ) ∈ because of a2 = a and because of the above. Case 9.3: ∈ Uk;Q . The binary function f9 with f9 (x, y) : = x + y belongs to P olk . One can prove f9 ∈ P olk as follows: Let (a, b) ∈ and a = b. Then 0 a a f9 = ∈ , b a a+b since a = b implies a + b = 0. Case 9.4: ∈ M∼ k;Q . In this case, the above-defined function f9 does not preserve the relation , since 0 a a f9 = ∈ / e e 0 holds for a ∈ Ek \{0}. Case 9.5: ∈ Lk;Q . For arbitrary λ ∈ L22 ,0 we have {(0, x, x), (x, 0, x), (x, x, 0) | x ∈ Ek } ⊆ λ. Because of = , there are certain a and b of Ek with (a, b, a +G b) ∈ and (a, b, a +G b) ∈ . Consequently, the ternary function f10 ∈ P olk defined by f10 (x, y, z) := x +G y +G z does not preserve the relation , since ⎞ ⎛ ⎛ ⎞ 0 a 0 a ⎜a a b⎟ f10 ⎝ ⎠ = ⎝ b ⎠ a 0 b a +G b holds. Case 9.6: ∈ (Ck;Q \C1k;Q ) ∪ Nk;Q . Let be an h -ary relation and (a1 , . . . , ah ) ∈ . Then the h -ary function f11 defined by f11 (x1 , . . . , xh ) := a1 · x1 +G a2 · x2 +G · · · +G ah · xh does not preserve the relation , ⎛ 1 0 0 ⎜ ⎜0 1 0 f11 ⎜ ⎜. . . ⎝ 0 0 0
since, if 1 is the unit ⎞ ⎛ . . . 0 a1 ⎟ ⎜ . . . 0⎟ a2 ⎟ = ⎜ ⎜ . . . .⎟ ⎝ · ⎠ . . . 1 ah
of the field (Ek ; +G , ·), ⎞ ⎟ ⎟ ⎟ ⎠
16.4 Proof of Theorem 16.2.1
513
holds and because 0 is a central element of . Therefore, (16.5) holds in Case 9.6. Since TQ ∩ P olk ⊆ TQ ∩ P olk implies = , (c) is proven.
16.4 Proof of Theorem 16.2.1 Put Rmax (TQ ) := Mk;Q ∪ Uk;Q ∪ Sk;Q ∪ Lk;Q ∪ Ck;Q ∪ Pk;Q ∪ Nk;Q . Let A be an arbitrary maximal class of TQ with ∅ = Q ⊆ Ek . We will prove by induction on r := |Q| that ∃ ∈ Rmax (TQ ) : A ⊆ TQ ∩ P olk
(16.6)
holds. r = 1 : If Vk↑ (A)\{A} = Vk↑ (TQ ), then (16.6) follows from Lemma 16.3.7. If Vk↑ (A)\{A} = Vk↑ (TQ ), then there exists a maximal class B1 of Pk with B1 = P olk and A = TQ ∩ B1 because of Lemma 16.3.4, (b). Then, by Chapter 6, there is a relation γ ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Bk ∪ Ck \{Q} with γ ∈ Invk A. Therefore, (16.6) follows from Lemma 16.3.5. r − 1 −→ r : Suppose, (16.6) holds for all Q ⊆ Ek with 1 ≤ |Q | ≤ r − 1. Let Q (⊆ Ek ) be an r-element set. Because of r = |Q| ≥ 2 and Lemma 16.3.7, we have Vk↑ (A)\{A} = Vk↑ (TQ ). Consequently, there exists a subclass B of Pk with (16.7) A = B ∩ TQ and B ⊆ TQ . We distinguish two cases for B: Case 1: ∀a ∈ Q : B ⊆ P olk {a}. Since A = Pk and because of Chapter 6, there is a γ ∈ Rmax (Pk )\{{a} | a ∈ Q} with B ⊆ P olk γ. Then this, (16.7), and Lemma 16.3.4, (a) imply A = B ∩ TQ ⊆ TQ ∩ P olk γ ⊂ TQ . Because γ ∈ Invk A, the statement (16.6) results through Lemmas 16.3.5 and 16.3.6. Case 2: ∃Q ⊂ Q : B ⊆ TQ ∧ (∀b ∈ Q\Q : B ⊆ P olk {b}). Because of B ∈ Vk↑ (TQ ), we have B ⊂ TQ . Thus there exists a maximal class B2 of TQ with B ⊆ B2 (see Lemma 16.3.2). By induction assumption, there is a ∈ Rmax (TQ ) with B2 ⊆ TQ ∩ P olk . Because of Lemma 16.3.4, (a), (c) the we have TQ ∩ P olk = TQ . This implies B2 = TQ ∩ P olk . Furthermore, following is valid: ∈ Mk ∪ Sk ∪ Uk ∪ (Ck \{{q} | q ∈ Q}) ∪ a∈Q (Pk;{a} ∪ Nk;{a} ) (notice ∀b ∈ Q\Q : B ⊆ P olk {b}). This and Lemmas 16.3.5 and 16.3.6 imply (16.6). Consequently, (16.6) is proven. It is easy to see that TQ ∩ P olk = TQ holds for every ∈ Rmax (TQ ). Therefore, Theorem 16.2.1 follows from (16.6) and Lemma 16.3.7.
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17 Maximal Classes of P olk El for 2 ≤ l < k
This chapter continues the investigations of Chapter 16 and generalizes Theorem 14.1.3. For arbitrary k, l ∈ N with 2≤l ≤k−1 all maximal classes of P olk El are determined. With the help of these maximal classes, one can easily give a completeness criterion for P olk El . The proofs given in this chapter resemble those ones from Chapter 6; that is, the results of this chapter were achieved with the means which were developed by I. G. Rosenberg in [Ros 70a].
17.1 Notations, Definitions, and Some Lemmas A relation , for which there are certain t1 , ..., tn ∈ {l, k} and a relation δ ∈ Dk with = (Et1 × Et2 × ... × Eth ) ∩ δ, is called El -diagonal. For relations ∈ Dk ∪ {ιhk }, we agree with the following brief notations: (t1 , t2 , ..., tn ) := ∩ (Et1 × Et2 × ... × Eth ) (t1 , ..., th ∈ {l, k}) and
[t] := (l, l, ..., l, k, k, ..., k). t times
In this chapter, we say that a relation is -derivable if one can receive by a finite number of applications of the relation operations (see Section 2.3) from the relations of {} ∪ Invk P olk El . In this case, we also write {} ∪ Invk P olk El
516
17 Maximal Classes of P olk El for 2 ≤ l < k
or
∈ [{} ∪ Invk P olk El ].
In the following proofs of this chapter, we assume that the reader knows the statements of the following lemma. The lemma contains statements that were already proven or can easily be proven. Lemma 17.1.1 It holds: (a) ∀ ∈ Rk : P olk El ∩ P olk = P olk El × ; (b) (∃i ∈ El : pri = El ) =⇒ P olk El × = P olk ; (c) ∀, ∈ Rk : ((P olk ⊆ P olk El ∧ ({} ∪ Invk P olk El )) =⇒ P olk ⊆ P olk El ∩ P olk ); (d) Invk Pk = Dk (see Theorem 2.6.2); (e) A relation belongs to Invk P olk El if and only if is El -diagonal. In addition to those notations introduced in Chapter 5, we need the following for relations and relation sets: Uk;El := { ∈ Uk | ∩ El2 ∈ {ι2l , El2 } ∧ a∈El {x | (a, x) ∈ } ∈ {El , Ek }}. Sk;El := {{(x, s(x)) | x ∈ Ek } | s is a permutation on Ek with exactly l fixed points (∈ El ), and all proper cycles of s have the same prime length }; Put (1)
Ck;El := { ∈ C1k | ∩ El ∈ {∅, El } ∧ = El }, Chk;El := { ∈ Chk | each element of El is a central element of } (2 ≤ h ≤ k − 1); ZC2k;El := { ∈ C2k | ∩ El2 = ι2l ∧ (∀x ∈ Ek ∃αx ∈ El : (x, αx ) ∈ ) ∧ (∀a, b ∈ Ek \El : ((∃u ∈ El : {(a, u), (u, b)} ⊆ ) =⇒ (a, b) ∈ )))} 0 1 2 2 2 0 1 (For example: If k = 3 and l = 2 then belongs to ZCk;El .) 0 1 2 0 1 2 2 and Ck;El := ZC2k;El ∪
k−1
h=1
Chk;El .
Let Zk;El be the set of all binary relations that fulfill the following four conditions: 1) ⊂ El × Ek ; 2) ∩ El2 = ι2l ;
17.1 Notations, Definitions, and Some Lemmas
517
3) {x | ∃y : (x, y) ∈ } = El ∧ {y | ∃x : (x, y) ∈ } = Ek ; 4) ∃c ∈ Ek \El : El × {c} ⊆ . One finds connections between the sets ZCk;El and Zk;El explained in Lemma 17.3.5. Let Nk;El be the set of all binary relations of the form (\ι2k ) ∪ El2 , where either = Ek2 or ∈ C2k;El 1 holds. An h-ary relation is called (l; r)-central if fulfills the following five conditions: 1) ⊂ Elr × Ekh−r , 2 ≤ h ≤ k − 1, 1 ≤ r ≤ h − 1; 2) is totally (l; r)-reflexive, i.e., ιhk [r] ⊆ ; 3) is totally (l; r)-symmetric, i.e., for every permutation s ∈ Sh [r] := {f | f is permutation on Eh ∧ ∀a ∈ Er : f (a) ∈ Er } it holds: (a0 , a1 , ..., ah−1 ) ∈ =⇒ (as(0) , as(1) , ..., as(h−1) ) ∈ . 4) is a weakly (l; r)-central relation, i.e., {(a1 , ..., ar , b1 , ..., bh−r ) ∈ Elr × Ekh−r | ∃i ∈ {1, ..., h − r} : bi ∈ El } ⊆ ; 5) has a central element c ∈ El , i.e., for arbitrary a1 , ..., ar ∈ El and arbitrary b1 , ..., bh−r ∈ Ek it holds: c ∈ {a1 , ..., ar } =⇒ (a1 , ..., ar , b1 , ..., bh−r ) ∈ . h We denote the set of all h-ary (l; r)-central relations with Ck;E [r]. l Further, let k−1 h−1 h Ck;E [r]. Ck;El := l h=2 r=1
Let Hk;El be the set of all ternary relations with the following six properties: 1) 2) 3) 4) 5) 6)
⊆ El2 × Ek ; ∩ El3 = {(x, x, y) | x, y ∈ El }; ∩ ι3k = {(x, x, z) | x ∈ El ∧ z ∈ Ek }; ∃u ∈ Ek \El : El2 × {u} ⊆ ; is totally (l; 2)-symmetric; is strongly (l; 2)-homogeneous, i.e., ∀x, y ∈ El ∀z ∈ Ek : (∃α, β ∈ El : {(x, α, z), (β, y, z), (α, β, z)} ⊆ ) =⇒ (x, y, z) ∈ .
1
I.e., is symmetric and ι2k ∪ (El × Ek ) ∪ (Ek × El ) ⊆ .
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17 Maximal Classes of P olk El for 2 ≤ l < k
With the help of the notations given in the definition of an (l; r)-central relation and with γr,s := {(a1 , ..., ar , b1 , ..., bs ) ∈ Elr × Eks | (∃i ∈ {1, ..., s} : bi ∈ El ) ∨ (a1 , ..., ar , b1 , ..., bs ) ∈ ιhk [r]} one can define the following relations: An h-ary relation is called (l; 2)-universal relation (3 ≤ h ≤ k − l + 2) if fulfills the following six conditions: 1) 2) 3) 4) 5)
⊂ El2 × Eks , s := h − 2, 3 ≤ h ≤ k − l + 2. is totally (l; 2)-reflexive. is totally (l; 2)-symmetric. is a weakly (l; 2)-central relation. The relation b := {(a1 , a2 ) | (a1 , a2 , b1 , ..., bs ) ∈ }
is an equivalence relation for every b := (b1 , ..., bs ) ∈ (Ek \El )s \ιsk . 6) s ∈ {1, k − l} and = γ2;s or γ2;s ⊂ . Let
h Bk;E [2] l
be the set of all h-ary (l; 2)-universal relations. In the following definitions, we use notations introduced in Section 5.2.6. An h-ary relation is called an (l; r)-universal if fulfills the following six conditions: 1) 2) 3) 4) 5)
⊂ Elr × Eks , s := h − r, 3 ≤ r ≤ l, 1 ≤ s ≤ k − l. is totally (l; r)-reflexive. is totally (l; r)-symmetric. is a weakly (l; r)-central relation. For every b := (b1 , ..., bs ) ∈ (Ek \El )s \ιsk with Elr × {b} ⊆ it holds b := {(a1 , ..., ar ) | (a1 , ..., ar , b1 , ..., bs ) ∈ } ∈ Bl , i.e., there exists an m[b] ∈ N and a mapping qb : El −→ Erm[b] with the property ∀a1 , ..., ar ∈ El : ((a1 , ..., ar , b1 , ..., bs ) ∈ ⇐⇒ ∀i ∈ Em[b] : ((qb (a1 ))(i) , ..., (qb (ar ))(i) ) ∈ ιrr ).
17.2 Results of Chapter 17
519
6) If s ≥ 2 then: For every tuple (α, β) := (α1 , ..., αr , β1 , ..., βs ) ∈ (Elr × Eks )\ there is an n-ary function f(α,β) that preserves the relation , and there is a matrix A(α,β) of the type k ×n, whose columns belong to {α1 , ..., αr }l × {β1 , ..., βs }k−l with the property ⎛ ⎞ qβ (0) ⎜ qβ (1) ⎟ ⎜ ⎟ ⎜ ⎟ ... ⎜ ⎟ ⎜ qβ (l − 1) ⎟ ⎜ ⎟. f(α,β) (A(α,β )) := ⎜ ⎟ l ⎜ ⎟ ⎜ l+1 ⎟ ⎜ ⎟ ⎝ ⎠ ... k−1 The simplest relations, which fulfill the above six conditions, are the abovedefined relations γr;s with (r, s) ∈ {(l, 1), (l, k − l)} (see also the Lemmas 17.5.13 and 17.5.14). Let Bk;El [r] be the set of all h-ary (l; r)-universal relations for r ≥ 3 and put h Bk;El := Bk;E [r]. l 3 ≤ h ≤ k, 2 ≤ r ≤ l 1≤h−r ≤k−l
17.2 Results of Chapter 17 The aim of Chapter 17 is to prove the following theorem: Theorem 17.2.1 Let 2 ≤ l ≤ k − 1, Rmax (Pl ) := Ml ∪ Sl ∪ Ul ∪ Ll ∪ Cl ∪ Bl and Rmax (P olk El ) := Rmax (Pl ) ∪ Uk;El ∪ Ck;El ∪ Sk;El ∪ Nk;El ∪ Zk;El ∪ Ck;Ek ∪ Hk;El ∪ Bk;El . Then
{P olk El × | ∈ Rmax (P olk El )}
is the set of all maximal classes of P olk El . The next theorem follows from the above theorem and from the fact that P olk El is finitely generated (see Lemma 17.4.1).
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17 Maximal Classes of P olk El for 2 ≤ l < k
Theorem 17.2.2 (Completeness Criterion for P olk El ) For an arbitrary subset M of P olk El it holds: [M ] = P olk El ⇐⇒ ∀ ∈ Rmax (P olk El ) : M ⊆ P olk × El .
The following theorem (basically given in [Ros 74]) is also a conclusion from Theorem 17.2.1. Theorem 17.2.3 Let M be an arbitrary subset of P olk El with (P olk El )1 ⊆ M . Then, [M ] = P olk El if and only if M ⊆ P olk for all of the following list: {(a, b, c, d) ∈ E24 | a + b = c + d (mod 2)} if l = 2, λl := ιll if l ≥ 3, µ := {(x, y) ∈ Ek2 | {x, y} ⊆ El ∨ x = y} (∈ Uk;El ), κh := ιhk ∪ {(a1 , ..., ah ) ∈ Ekh | ∃i ∈ {1, ..., h} : ai ∈ El } (∈ Ck;El ) if 2 ≤ h ≤ k − l and κh = Ekh , κ∗ := (El × Ek ) ∪ (Ek × El ), γr,s if (s, t) ∈ {(2, 1), (l, 1), (2, k − l), (l, k − l)}. In other words: P olk El ⎧ ⎨4 nk,l := k − l + 4 ⎩ k−l+6
has exactly if (k, l) = (3, 2), if (k, l) ∈ {(k, 2), (k, k − 1)} and k ≥ 4, otherwise,
maximal classes that contain (P olk El )(1) : P olk 1 (1 ∈ {λl , κ∗ , γ2,1 , γl,1 , γ2,k−l , γl,k−l }), P olk 2 × El (2 ∈ {µ, κh | κh = Ekh ∧ 2 ≤ h ≤ k − l}).
17.3 Maximality Proofs The following lemma is a conclusion of Chapter 6: Lemma 17.3.1 For every ∈ Rmax (Pl ) the clone P olk is a maximal clone of P olk El , 2 ≤ l ≤ k − 1. Lemma 17.3.2 Let ∈ C1k;El \C1l , i.e., ∅ ⊂ ⊂ Ek , \El = ∅ and ∩ El ∈ {∅, El }. Then, P olk × El is maximal in P olk El .
17.3 Maximality Proofs
521
Proof. The unary functions fa (a ∈ ) with 0 if x ∈ El , fa (x) := a otherwise, belong to P olk × El . Let now f n ∈ P olk El \P olk be arbitrary. Then there exist certain a1 , ..., an ∈ with f (a1 , ..., an ) =: α ∈ Ek \. Consequently, we have f∗ (x) := f (fa1 (x), ..., fan (x)) ∈ [P olk × El ∪ {f }], where f∗ (β) ∈ for every β ∈ \El . For every function g m ∈ P olk El , one finds a 2 · m-ary function hg with ⎧ g(x1 , ..., xm ) if (xm+1 , ..., x2·m ) = (f∗ (x1 ), ..., f∗ (xm )), ⎪ ⎪ ⎪ ⎨0 if (xm+1 , ..., x2·m ) ∈ Elm and hg (x1 , ..., x2·m ) := (xm+1 , ..., x2·m ) = (f∗ (x1 ), ..., f∗ (xm )), ⎪ ⎪ ⎪ ⎩ a otherwise (a ∈ ) in P olk × El . Consequently, g(x1 , ..., xm ) = hg (x1 , ..., xm , f∗ (x1 ), ..., f∗ (xm )) is a superposition over P olk × El ∪ {f }. Lemma 17.3.3 Let be a relation of Uk;El and let [a] be the equivalence class {x ∈ Ek | (a, x) ∈ }, a ∈ Ek . Then is valid: (1) fulfills exactly one of the following conditions: (a) ∩ El2 = ι2l ∧ a∈El [a] = El ; (b) ∩ El2 = ι2l ∧ a∈El [a] = Ek ; (c) ∩ El2 = El2 ∧ a∈El [a] = El . (2) P olk × El is maximal in P olk El . Proof. (1) follows from the definition of the set Uk;El and from the fact that the conditions ∩ El2 = ι2l and a∈El [a] = Ek only of the relation Ek2 , which does not belong to Uk , are fulfilled. (2): Let := ∩ (Ek \El )2 and := ∩ (El × (Ek \El )). If fulfills (a) or (b) of (1), then = ∅ and for arbitrary a := (a1 , a2 ) ∈ and b := (b1 , b2 ) ∈ we have that the function ⎧ x ∈ El , ⎨ 0 if x = a1 , fa;b (x) := b1 if ⎩ b2 otherwise, belongs to P olk × El . If fulfills the condition (c), then one can find exactly an element of El in each equivalence class of , through which, for every a := (a1 , a2 ) ∈ ∪ and all b ∈ , the function
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17 Maximal Classes of P olk El for 2 ≤ l < k
⎧ x ∈ El ∧ [α] = [a1 ] ∧ α ∈ El , ⎨ α if x = a1 , fa;b (x) := b1 if ⎩ b2 otherwise,
preserves the relation . Let f ∈ P olk El \P olk be arbitrary. Then, certain unary functions ha with ha (a) ∈ for all a ∈ ∪ are superpositions over f and functions of the . We briefly denote all functions of this form with h1 , ..., form fa;b or fa;b ht . If one considers a matrix of the type (k m , t · (m + 1)), whose rows are (in arbitrary sequence) of the form y := (x1 ..., xm , h1 (x1 )..., h1 (xm )..., ht (x1 )..., ht (xm )) (x1 ..., xm ∈ Ek ), then one sees that each two rows that are different and do not consist only of elements of the set El , contain at least a column of Ek2 \. In analogous mode to the proof of the maximality of P olk in Pk (see Theorem 5.3.2) one can easily prove that, for every m-ary function g ∈ P olk El , there is a function hg ∈ P olk ×El with hg (y) = g(x1 ..., xm ), whereby [P olk × El ∪ {f }] = P olk El is valid. Analogous to the proof of Lemma 17.3.3 or analogous to the proof of similar statements about maximal classes (see Section 5.3) one can prove the following lemma. 2 [1] ∪ C2k;El then P olk × El is Lemma 17.3.4 If ∈ Sk;El ∪ Nk;El ∪ Ck;E l maximal in P olk El .
Lemma 17.3.5 (1) Let be a relation of ZC2k;El ; i.e., it holds that (a) ι2k ⊆ ⊂ Ek2 and is symmetric; (b) ∩ El2 = ι2l ; (c) ∃c ∈ Ek \El : Ek × {c} ⊆ ; (d) ∀x, y, z ∈ Ek : {(x, z), (y, z)} ⊆ =⇒ (x, y) ∈ . Then := ∩ (El × Ek ) belongs to Zk;El , i.e., has the following properties: (e) ⊂ El × Ek , pr0 = El and pr1 = Ek ; (f ) ∩ El2 = ι2l ; (g) ∃c ∈ Ek \El : El × {c} ⊆ . (2) P olk × El = P olk ∩ (El × Ek ) is valid for every ∈ ZC2k;El . Proof. (1) one can easily check. (2): Because of (1), we have P olk × El ⊆ P olk ∩ (El × Ek ) for every ∈ ZCk;El l . To prove the reverse inclusion, we show = (τ ) ◦ , where := ∩ (El × Ek ): Let (a, b) ∈ (τ ) ◦ . Then there exists a c ∈ El with (a, c) ∈ τ and (c, b) ∈ . Therefore, (a, b) ∈ because of (d) and the symmetry of . Thus we have (τ ) ◦ ⊆ .
17.3 Maximality Proofs
523
Let (a, b) ∈ . Because of (e) there exist certain xa , xb ∈ El with (xa , a) ∈ and (xb , b) ∈ . Moreover, because of (g) we have (xa , c) ∈ and (xb , c) ∈ , through what (xa , xb ) ∈ holds because of (d). However, this is only possible for xa = xb because of (b). Therefore we have (a, xa ) ∈ τ and (xa , b) ∈ through what (a, b) ∈ (τ ) ◦ holds. One can describe classes of the form P olk × El with ∈ ZCk;El through relations of the set Zk;El . Consequently, the P olk El -maximality of these classes surrenders through the following lemma. Lemma 17.3.6 Let ∈ Zk;El . Then P olk is maximal in P olk El . Proof. The following unary functions belong to P olk : α if x ∈ El , f(α,β) := β otherwise ((α, β) ∈ ),
⎧ x = c, ⎨ 0 if x ∈ (El \{c}) ∪ {d}, g(c,d) (x) := 1 if ⎩ c otherwise
((c, d) ∈ (El × Ek )\) and h(u,v) (x) :=
0 if u ∈ El ∪ {u}, w otherwise
((u, v) ∈ Ek2 ; u = v; v, w ∈ El and (0, w) ∈ ). Further, P olk has the following property: For every set T of t-tuples with ∀a := (a1 , ..., at ), b := (b1 , ..., bt ) ∈ T : a = b =⇒ ∃i ∈ {1, ..., n} : (ai , bi ) ∈ {(0, 1), (1, 0)}
(17.1)
and for every determination f (a) ∈ Ek for the t-tuples a of T , where a ∈ T ∩ Eln implies f (a) ∈ El , there is a certain determination for the remaining tuples x of Ekn , so that f belongs to P olk . If x ∈ Eln then one can set f (x) = w, where El × {w} ⊆ , with that f ∈ P olk . If x ∈ Elt , then (because of El2 ∩ = ι2k ) maximally a tuple of T can influence the value f (x), with which the value f (x) is also easily defined in this case. Let now f n ∈ P olk El \P olk be arbitrary. Then there are certain (a1 , ..., an ), (b1 , ..., bn ) with (ai , bi ) ∈ for all i ∈ {1, ..., n} and (f (a1 , ..., an ), f (b1 , ..., bn )) ∈ . Thus a unary function f1 with c α := f1 ∈ (El × Ek )\, d β where (α, β) ∈ \ι2l is arbitrary, is a superposition over the functions f(αi ,βi ) and f .
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17 Maximal Classes of P olk El for 2 ≤ l < k
Further, if one forms f2 (x) := g(c,d) (f1 (x)), then the function f2 has the property α 0 f2 = . β 1 Consequently, the unary functions of the form f2 h(u,v) belong to [P olk ∪ {f }], where {(f2 h(u,v) (u), (f2 h(u,v) (v)} = E2 for arbitrary u, v ∈ Ek with u = v and v ∈ El . Let {r1 , ..., rq } := {(u, v) ∈ Ek2 | u = v ∧ v ∈El }and denote sr1 ,..., srq 0 certain functions of [P olk ∪ {f }] with sri (ri ) = . Then 1 T := {(x1 , ..., xm , sr1 (x1 ), ..., sr1 (xm ), ..., srq (x1 ), ..., srq (xm )) | x1 , ..., xm ∈ Ek } is a set of tuples with the property (17.1). Thus, by our above considerations, for each m-ary function g ∈ P olk El there is a certain function hg ∈ P olk with g(x1 , ..., xm ) = hg (x1 , ..., xm , sr1 (x1 ), ..., srq (xm )), whereby [P olk ∪ {f }] = P olk El is proven. Lemma 17.3.7 For every ∈ Hk;El , P olk is a maximal class of P olk El . Proof. Let ∈ Hk;El . Then fulfills the conditions 1)–6) of the definition of the elements of Hk;El , which we refer more often to in the following considerations. We begin with some easily proven auxiliary statements: 1) Let (a, b, c) ∈ (El2 × Ek )\ with c ∈ El . Then, because of 6), there exists a unary function fa,b,c ∈ P olk with ⎛ ⎞ ⎛ ⎞ a 0 fa,b,c ⎝ b ⎠ = ⎝ 1 ⎠ c 0 (for x ∈ Ek \(El ∪ {c}) one can set f (x) = u, where {u} ⊆ (see 4)); for E l × a 0 x ∈ El , the value f (x) is determined either by f = or is arbitrary b 1 of El ). 2) For every a ∈ Ekn , the n-ary function ga defined by ⎧ x = a, ⎨ 1 if x ∈ Eln \{a}, ga (x1 , ..., xn ) := 0 if ⎩ u otherwise, where u fulfills 4), belongs to P olk . 3 with c ∈ Ek \El and for each α := 3) For each α := (a, b, c) ∈ \δk;{0,1} (a , b , c ) ∈ there is a unary function tα;α ∈ P olk with ⎛ ⎞ ⎛ ⎞ a a tα;α ⎝ b ⎠ = ⎝ b ⎠ . c c
17.3 Maximality Proofs
525
Let now f n ∈ P olk El \P olk be arbitrary. Then there are certain a := (a1 , ..., an ), b := (b1 , ..., bn ), c := (c1 , ..., cn ) ∈ Ekn with (ai , bi , ci ) ∈ for i = 1, ..., n and ⎛ ⎞ ⎛ ⎞ a a f ⎝ b ⎠ = ⎝ b ⎠ ∈ . c c By replacing certain variables of f through functions defined in 3), one obtains a unary function f with ⎛ ⎞ ⎛ ⎞ a a f ⎝ b ⎠ = ⎝ b ⎠ c c 3 for arbitrary (a, b, c) ∈ \δk;{0,1} with c ∈ El . If c ∈ Ek \El , then the function f := f(a ,b ,c ) f has the property ⎛ ⎞ ⎛ ⎞ a 0 f ⎝ b ⎠ = ⎝ 1 ⎠ . c 0
If c ∈ El , then w.l.o.g. we can assume (a , b , c ) = (0, 1, 0). Thus with the help of functions defined in 2), we obtain functions of the form 1 if x = a, qan (x) := 0 otherwise, for every a ∈ Ekn , n ∈ N. Let now g m ∈ P olk El be arbitrary. To prove gm ∈ [P olk ∪ {f }], we set Ekm = {a1 , ..., akm } and consider the (m + k m )-tuples of the form yi := (ai , 0, ..., 0,
1 , 0, ..., 0) (m+1)-th place
for i = 1, ..., km . Then, because of 4) and 6), there is an (m + k m )-ary function hg ∈ P olk with hg (yi ) = g(ai ) for each i ∈ {1, ..., km }. Consequently, g is a superposition over {hg } ∪ {qa | a ∈ Ekm } and therefore also over P olk ∪ {f }. h Lemma 17.3.8 For every ∈ Ck;E [r] ∪ Chk;El (3 ≤ h ≤ k − 1, 1 ≤ r ≤ h − 1) l the clone P olk × El is maximal in P olk El . h Proof. First let ∈ Ck;E [r] and let f ∈ P olk El \P olk be arbitrary. l Every function f1 of P olk El with Im(f1 ) = {a1 , ..., ah } and (a1 , ..., ah ) ∈ belongs to P olk . Hence, for a certain b := (b1 , ..., bh ) ∈ (Elr × Eks )\, where s := h−r, each function of P olk El with the image {b1 , ..., bh } is a superposition m ∩ P olk El and let c ∈ El over P olk ∪ {f }. Let {h1 , h2 , ..., hq } := Pk;{b 1 ,...,bh } be a central element of . We choose an m-ary function g ∈ P olk El arbitrary
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17 Maximal Classes of P olk El for 2 ≤ l < k
and put y := (x1 , ..., xm , h1 (x1 , ..., xm ), ..., hq (x1 , ..., xm )). Obviously, the (m · (q + 1))-ary function hg defined by and hg (y) := g(x1 , ..., xm ) hg (y ) := c for the remaining tuples y preserves the relation . Thus the function g is a superposition over P olk ∪ {f }, whereby our Lemma is proven for (l; r)-central relations . Analogously, one can lead the proof for the central relations of Chk;El . h Lemma 17.3.9 For every ∈ Bk;E [2] with 3 ≤ h ≤ k − l + 2 the clone P olk l is maximal in P olk El .
Proof. Let f ∈ P olk El \P olk be arbitrary. To prove [P olk ∪{f }] = P olk El , we distinguish the following cases: Case 1: = γ2,1 . Each unary function of P olk El and each function f1 with Im(f1 ) = {a, b, c}, where (a, b, c) ∈ γ2,1 , preserves the relation γ2,1 . Thus each function of P olk El with the image {0, 1, l} is a superposition over P olk ∪ {f }. Let now g m ∈ P olk El be arbitrary. Set Elm = {a1 , ..., alm }. The (m + lm )-ary function hg with hg (x1 , ..., xm , 0, ..., 0,
1 , 0, ..., 0) := g(ai ) (i+m)-th place for all x1 , ..., xm ∈ El , i = 1, 2, .., lm , hg (y1 , ..., ym , l, l, ..., l) := g(y1 , ..., ym ) for all (y1 , ..., ym ) ∈ Ekm \Elm , m and hg (z) := 0 for the remaining tuples z ∈ Ekm+l
belongs to P olk . By replacing certain variables of the function fg through certain functions with the image {0, 1, l}, one obtains the function g; that is, g ∈ [P olk ∪ {f }] is proven. Case 2: = γ2,k−l and k − l ≥ 2. Clearly, each unary function of P olk El and each function h ∈ P olk El with |Im(h)| ≤ k − l + 1 preserves . Thus {g ∈ P olk El | |Im(g)| ≤ h − l + 2} ⊆ [P olk ∪ {f }]. Consequently, [P olk ∪ {f }] = P olk El for l = 2. If l ≥ 3, one can prove the P olk El -maximality of P olk with the help of the l-ary function t ∈ P olk defined by ⎞ ⎞ ⎛ ⎛ 0 1 0 0 ... 0 ⎟ ⎜ ⎜ 0 1 0 ... 0 ⎟ ⎟ ⎜ 1 ⎟ ⎜ ⎜ . . . . . . . . . . . . . . . . . . . . . . . . . . . ⎟ ⎜ ... ⎟ ⎟ ⎟ ⎜ ⎜ ⎟ ⎜ 0 0 ... 1 ⎟ t⎜ ⎟=⎜ l−1 ⎟ ⎜ 0 ⎜ ⎟ ⎜ l l l ... l ⎟ ⎜ l ⎟ ⎟ ⎜ ⎝ . . . . . . . . . . . . . . . . . . . . . . . . . . . ⎠ ⎝ ... ⎠ k−1 k − 1 k − 1 k − 1 ... k − 1 and t(x) = 0 otherwise.
17.3 Maximality Proofs
527
Case 3: γr,s ⊆ ⊂ El2 × Eks . If s = 1, one can similar to Case 1 prove [P olk ∪{f }] = P olk El , when w.l.o.g. one assumes El2 × {l} ⊆ and (0, 1) ∈ εl := {(a, b) | (a, b, l) ∈ } and if one changes the definition of the function hg as follows: m
∀(x, y) := (x1 , .., xm , y1 , ..., ylm ) ∈ Elm+l ∀i : ((∀j ∈ {1, .., lm }\{i} : (yj , 0) ∈ εl ) ∧ (yi , 1) ∈ εl ) =⇒ hg (x, y) := g(ai ). Let s ≥ 2. Because of assumption, for every b := (b1 , ..., bs ) ∈ (Ek \El )s \, we have that εb := {(x, y) | (x, y, b1 , ..., bs ) ∈ } is an equivalence relation on El with at least two equivalence classes. For tuples yi := (yi1 , ..., yit ) ∈ Elt (i = 1, 2), we define: y1 ∼εb y2 :⇐⇒ ∀j : (y1j , y2j ) ∈ εb . Since f does not preserve the relation , there are certain r1 , ...rn ∈ and an α := (a1 , a2 , b1 , ..., bs ) ∈ (El2 × Eks )\ with f (r1 , ..., rn ) = α. Hence, each function h ∈ P olk with Im(h) ⊆ {a1 , a2 , b1 , ..., bs } is a superposition over P olk ∪ {f }. Let the m-ary function g ∈ P olk El be arbitrary. Then the m · (q + 1)-ary function hg defined by y := (x1 , ..., xm ), h1 (x1 , ..., xm ), ..., hq (x1 , ..., xm )) ({h1 , ..., hq } := {h ∈ (P olk El )m | Im(f ) = {a1 , a2 , b1 , ..., bs }}, hg (y) := g(x1 , ..., xm ), ∀y ∈ Elm : (y ∼εb y =⇒ hg (y ) = hg (y), h(y ) := 0 for the remaining tuples y preserves . Therefore, g(x) = hg (x, h1 (x), ..., hq (x)) ∈ [P olk ∪ {f }] holds. h Lemma 17.3.10 For every ∈ Bk;E [r] with 3 ≤ r ≤ l and 1 ≤ s := h − r ≤ l k − l, the clone P olk is maximal in P olk El .
Proof. Let f n ∈ P olk El \P olk be arbitrary. Then, there are some r1 , ..., rn ∈ and an α := (a1 , ..., ar , b1 , ..., bs ) ∈ (Elr × Eks )\ with f (r1 , ..., rn ) = α. Consequently, each function h ∈ P olk El with Im(h) ⊆ {a1 , ..., ar , b1 , ..., bs } is a superposition over P olk ∪ {f }. We distinguish the following two cases: Case 1: s = 1. Because of (a1 , ..., ar , b1 ) ∈ , the relation b1 := {(x1 , ..., xr ) | (x1 , ..., xr , b1 ) ∈ } belongs to Brl . First let (a1 , ..., ar ) := (0, 1, ..., r − 1), l := rq and (i)
(i)
b1 := {(x1 , ..., xr ) | ∀i ∈ Eq : (a1 , ..., ar ) ∈ ιrr }
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17 Maximal Classes of P olk El for 2 ≤ l < k
(notations: see Section 5.2.6). Let the m-ary function g ∈ P olk El be arbitrary. Then the (q + m)-ary function hg defined by (0)
q−1 yi+1 · hq−i hg (y1 , ..., yq , x1 , ..., xm ) := Σi=0
if (y1 , ..., ym , x1 , ..., xm ) ∈ Elq+m , hg (b1 , b1 , ..., b1 , x1 , ..., xm ) := g(x1 , ..., xm ) if (x1 , ..., xm ) ∈ Ekm \Elm and
hg (z) := 0 for the remaining tuples z ∈ Ekq+m preserves . Moreover, the functions gj (j ∈ Eq ) defined by (g(x1 , ..., xm ))(j) if (x1 , ..., xm ) ∈ Elm , gf (x1 , ..., xm ) := otherwise, b1 are superpositions over P olk ∪ {f }, since the images of these functions are subsets of {0, 1, ..., r −1, b1 }. Thus, because of g(x) = hg (gq−1 (x), ..., g0 (x), x), x := (x1 , ..., xm ), g is a superposition over P olk ∪ {f } in the above case. If b is a homomorphic inverse image of an r-ary elementary relation, then this case can be reduced to the above case, using the constructions from Section 5.2.6. Case 2: s ≥ 2. Since fulfills the condition 6) of the definition of the elements of Bhk;El [r] in this case, an arbitrary function of P olk is a superposition over {f(a1 ,...,as ,b1 ,...bs ) } ∪ Pk;{a1 ,...,ar ,b1 ,...,bs } ⊆ [P olk ∪ {f }] (see also Lemma 1.4.6).
17.4 Some Lemmas It is subsequently shown in analog mode to corresponding statements about Pk that every maximal class A of Pk can be described with the aid of a relation A in the form P olk A . Lemma 17.4.1 P olk El has a generating system of functions of (P olk El )2 . Proof. For a, b ∈ Ek let ja;b be a unary function of Pk defined by b if x = a, ja;b (x) := 0 otherwise. The function ja;b preserves El (i.e., ja;b ∈ P olk El ) iff b ∈ El or a ∈ Ek \El . Also, the following functions belong to P olk El :
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
529
x ∨ y := max(x, y), x · y := min(x, y) (in respect to the total order 0 < 1 < 2 < ... < k − 1) and ra;b (x, y) := ja;b (x) · y. Then one can describe an arbitrary function f n ∈ P olk El as follows: f (x1 , ..., xn ) = ja1 ;f (a) (x1 ) · ... · jan ;f (a) (xn ) n a = (a1 , ..., an ) ∈ Ek where f (a) ∈ El , if (a1 , ..., an ) ∈ Eln . Consequently, {∨, ·} ∪ {ja;b | a ∈ Ek \El ∧ b ∈ El } ∪ {ra;b | a, b ∈ Ek } is a generating system for P olk El . The following lemma is a conclusion of the above lemma. Lemma 17.4.2 The lattice of the subclasses of P olk El is dual atomar, and P olk El has only finitely many maximal classes. Since one can easily prove that all maximal classes of P olk El are clones, the following is also valid: Lemma 17.4.3 For every maximal class M of P olk El there exists at most a k 2 -ary relation M with M = P olk M . Obviously, the only maximal classes of P olk El describable through relations from Rl are the classes of the form P olk with ∈ Rmax (Pl ). Possible descriptive relations for the maximal classes of P olk El are relations of the set Rmax (Pl ) ∪ Rmax (Pk ), which we will scrutinize in Section 17.6. We begin, however, by determining those maximal classes A of P olk El , which are not representable in the form P olk × El with ∈ Rmax (Pl ) ∪ Rmax (Pk ).
17.5 Not Through Relations of Rmax(Pl) ∪ Rmax(Pk) Describable Classes In this section, let A be an arbitrary maximal class of P olk El with prl A = Pl L↑k (A)
and
= {A, P olk El , Pk }.
Then, by Lemma 17.4.2, there is a relation ∈ Rkh with h ≤ k 2 and A = P olk El ∩ P olk . The assumptions above A and are equivalent to
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17 Maximal Classes of P olk El for 2 ≤ l < k
(I)
A ∈ {P olk γ ∩ P olk El | γ ∈ Rmax (Pl ) ∪ Rmax (Pk )}
(I )
No relation from the set Rmax (Pl ) ∪ Rmax (Pk ) is derivable from relations of {} ∪ Invk P olk El .
or
Since Rk1 \{El } ⊆ Rmax (Pk ), (I ) implies (I )
h ≥ 2 holds and no relation of the set C1k \{El } is derivable from .
W.l.o.g. we can assume the following properties of the relation : (II)
⊆ Elr × Eks (r + s = h; 0 ≤ r ≤ h; 1 ≤ s ≤ h).
(III)
A is not describable through a relation ⊆ Elr × Ekh−r with r > r. In other words: Every relation ∈ [{} ∪ Invk P olk El ] with ⊆ Elr × Ekh−r and r > r belongs to Invk P olk El .
(IV )
Every h -ary relation ∈ [{} ∪ Invk P olk El ] with h < h belongs to Invk P olk El .
(V )
If possible, choose a symmetric relation for the description of A, i.e., for every permutation s ∈ Sh and
s := {(as(0) , as(1) , ..., as(h−1) ) | (a0 , ..., ah−1 ) ∈ } is valid: ∩ s ∈ {} ∪ Invk P olk El . (V I)
From the possible (l; r)-symmetric, h-ary relations , which describe A, the relation is that relation with the greatest cardinality, i.e., ∀ ⊆ Elr × Eks : (A = P olk El × ∧ ( is (l; r)-symmetric)) =⇒ | | ≤ ||.
The following is a conclusion from (II)–(IV):
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
(V II)
531
∀i ∈ {0, 1, ..., h − 1} : pr0,1,...,i−1,i+1,...,h−1 = pr0,1,...,i−1,i+1,...,h−1 Elr × Eks . (In particular, has no double rows.)
h h Lemma 17.5.1 ∩ δk;{0,1,...,h−1} = δl;{0,1,...,h−1} . h h h Proof. By (IV ) we have ∩ δk;{0,1,...,h−1} ∈ {∅, δl;{0,1,...,h−1} , δk;{0,1,...,h−1} }. h h ∩ δk;{0,1,...,h−1} = δk;{0,1,...,h−1} cannot occur, since A ⊂ P olk El and P olk El h does not contain all constant functions of Pk . If ∩ δk;{0,1,...,h−1} = ∅, then
h+1 the -derivable relation := pr0,h (El × ) ∩ δk;{0,1,...,h−1} = {(x, y) ∈ El × Ek | (x, x, ..., x, y) ∈ El × } has the following properties: – ∩ ι2k = ∅; – ∩ El2 = ∅ =⇒ ∩ El2 ∈ Invk P olk El ; – ∩ El2 = ∅ =⇒ pr1 ∈ C1k \{El }. Thus because of our assumptions (I ) and (I ), the case just seen cannot h occur for ∩ δk;{0,...,h−1} . Hence our assertion is valid.
In the following, we distinguish two cases for , and we start with
Case 1: h = 2. Because of (I ) we have pr0 ∈ {El , Ek } and pr1 = Ek in this case. As is generally accepted, the relations σi () := {(a1 , ..., ai ) | ∃u ∈ Ek : {(u, a1 ), ..., (u, ai )} ⊆ } (i = 2, 3, ...) are -derivable for h = 2. Lemma 17.5.2 Let (τ ) ◦ = Ek2 . Then σi () = Eki for all i ≥ 2. Proof. We prove the statement by induction on i ≥ 2. For i = 2 the statement holds by assumption, since σ2 () = (τ ) ◦ . Assume, σi () = Eki , i ≥ 2. ⊆ σi+1 (). The case σi+1 () = Then, by definition of σi+1 (), we have ιi+1 k Eki+1 implies P olk ∩ P olk El ⊂ P olk σi+1 () ∈ {P olk El , Pk }, contrary to (I). Therefore, we have σi+1 () = Eki+1 . By Lemma 17.5.1, the -derivable relation ∩ (τ ) has the property ι2l = ι2k ∩ ∩ (τ ). Thus, by (V ), ∈ {ι2l , , El2 } holds; i.e., we must examine three cases for , and do so in the following three lemmas. Lemma 17.5.3 Let ∩ (τ ) = ι2l . Then there exists a -derivable relation γ ∈ Sk;El whose proper cycles have a length ≥ 3.
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17 Maximal Classes of P olk El for 2 ≤ l < k
Proof. First we form the -derivable relation := (τ ) ◦ = {(x, y) | ∃u ∈ Ek : {(u, x), (u, y)} ⊆ }. Because of pr1 = Ek , we have ι2k ⊆ and || ≥ k. The following two cases are possible: Case 1: = ι2k . If || > k or pr0 = El , there exist a, b, c ∈ Ek with (c, a), (c, b) ∈ and a = b, whereby (a, b) ∈ with a = b follows, contrary to our assumption in the first case. Therefore || = k, and it holds that = {(x, s(x)) | x ∈ Ek } for a certain permutation s ∈ Sk \{id} with the fixed points 0, 1, ..., l − 1 (Sk denotes the set of all permutations on Ek and id is the identity permutation). Because of ∩ (τ ) = ι2k , every proper cycle of has at least the length 3. If has proper cycles with different lengths, and if r ≥ 3 is the smallest length of the proper cycles, then the relation ∆(( ◦ ◦ ... ◦ ) ∩ ι2k ) is a -derivable relation of C1k \{El }, contrary to (I ). Therefore, all proper cycles of have the same length q ≥ 3. The length q is a prime number, since for q = p · m (p prime, m ≥ 2), the -derivable relation ◦ ◦ ... ◦ m times has only proper cycles of the length p. Consequently, it is possible to derive from a relation of Sk;El , which has proper cycles of the length ≥ 3. Case 2: ι2k ⊂ . In this case, we have {c0 , c1 , ..., ck−1 } ⊆ P olk , whereby = Ek2 is valid because of (I ). With the aid of Lemma 17.5.2, this implies σk () = Ek2 . Therefore, has a central element u, i.e., {(u, x) | x ∈ Ek } ⊆ . Because of ∩ ι2k = ι2l , u belongs to El . Consequently, ι2l ⊂ ∩ El2 and hence (by(I )) ∩ El2 = El2 , contrary to our assumption ∩ (τ ) = ι2l . Thus Case 2 is not possible. Lemma 17.5.4 If ∩ (τ ) = , then either ∈ Nk;El or it is possible derive from a permutation of the set Sk;El , whose proper cycles have the same length 2. Proof. The symmetry of and pr1 = Ek imply pr0 = Ek . Consequently, ι2k ⊆ ◦ . Because of (I ), this is only possible if ◦ ∈ {ι2k , Ek2 }; i.e., we have to distinguish the following two cases. Case 1: ◦ = ι2k . Since ◦ = (τ ) ◦ , one can show (analogous to the proof of Lemma 17.5.3, Case 1) that there is a -derivable relation γ ∈ Sk;El . Because of the symmetry of , every proper cycle of has the length 2.
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Case 2: ◦ = Ek2 . Since ◦ = (τ ) ◦ , Lemma 17.5.2 implies σk () = Ek2 . Therefore, there is a u ∈ Ek with {(u, x) | x ∈ Ek } ⊆ . Because of ∩ ι2k = ι2l (see Lemma 17.5.1) u belongs to El . Hence ι2l ⊂ ∩ El2 , whereby El2 ⊆ (because of our assumptions in this section). Now, if one forms := ∩ (El × Ek ), then El2 ⊂ ⊆ El × Ek . Since the case ⊂ El × Ek is a contradiction to our assumption (III), we have El × Ek ⊆ and then (because of symmetry of ) ∈ Nk;El . 2 Lemma 17.5.5 If ∩ (τ ) = El2 , then r = 1 and ∈ Ck;E . l
Proof. Suppose, r = 0. By (III) and by ∩(τ ) = El2 , for 0 := ∩(El ×Ek ) and 1 := ∩(Ek ×El ) the following cases are to study (w.l.o.g.): 0 = 1 = El2 or 0 = El × Ek and 1 = El2 . In both cases, the -derivable relation i := ◦ ◦ ... ◦ for every i ∈ N has the property that i ∩ (Ek × (Ek × El )) = El2 i times holds. Furthermore, there is an i with ι2l ⊂ i ∩ ι2k . Consequently, if r = 0, then there is a -derivable relation that describes a class B with B ⊆ P olk El and B = Pk . This is, however, excluded from this section. Therefore, we can set r = 1 in the following; i.e., ⊆ El × Ek holds. If one forms the relation (τ ) ◦ , one can see that Ek × El ⊆ (τ ) ◦ and ι2k ⊆ (τ ) ◦ are valid. By our assumptions over , this is only possible if (τ ) ◦ = Ek2 holds. Because of Lemma 17.5.2, this implies that there is a u ∈ El with {(u, x) | x ∈ Ek } ⊆ . 2 . Consequently, ∈ Ck;E l Let’s summarize: In Case 1 our maximal class A has the form: 2 P olk with ∈ Sk;El ∪ Nk;El ∪ Ck;E . l
Case 2: h ≥ 3. Lemma 17.5.6 Let s ≥ 2 and Elh ⊆ . Then s−1 i=0
Elr × Eki × El × Eks−i−1 ⊆ .
Proof. First let r = 0, i.e., pri = Ek for every i ∈ Eh . Because of Lemma 17.5.1 and (V II), we have ∩ δk;{1,2,...,h−1} = δk;{1,2,...,h−1} [1] and therefore pri ( ∩ (El × Ekh−1 )) = Ek for every i ∈ {1, 2, ..., h − 1}. Consequently, by (III), ∩ (El × Ekh−1 ) can be only the relation El × Ekh−1 . Analogously, one can prove Eki × El × Ekh−i−1 ⊆ for i ∈ {1, ..., s − 1}. Thus our assertion is valid for r = 0. Let now r ≥ 1. Because of (V II), we have pri ( ∩ (Elr+1 × Ekh−r−1 )) = Ek for i ∈ {r + 1, ..., h − 1}. In analog mode, one can prove that our assertion for r ≥ 1 and h − r ≥ 2 follows.
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17 Maximal Classes of P olk El for 2 ≤ l < k
Lemma 17.5.7 Let h = 3. Then for is valid either (a) r = 2 and ∩ ι3k = δk;{0,1} [2] or (b) r ∈ {1, 2} and is (l; r)-reflexive, i.e., ι3k [r] := ι3k ∩ (Elr × Ek3−r ) ⊆ . Proof. We must study the following three cases: Case 1: r = 0. (V II) and Lemma 17.5.1 imply ∩ δk;{1,2} = δk;{0,1} [1].
(17.2)
Analogously, one can show δk;{0,1} (k, k, l) ∪ δk;{0,2} (k, l, k) ⊆ . Consequently, we have ι3l ⊆ ∩Elh , which can be possible because of (I ) only for ∩El3 = El3 . With the help of Lemma 17.5.6, this implies El × Ek2 ∪ Ek × El × Ek ∪ Ek2 × El ⊆ .
(17.3)
Now, if one forms the relation := ∆, then this relation has the properties El × Ek ∪ Ek × El ⊆ and
= Ek2
(by (17.3))
(by (17.2)),
whereby is no invariant of P olk El , contrary to (IV ). Therefore, the case r = 0 does not occur. Case 2: r = 1. Since by (V I) pr1,2 = Ek2 is valid, we have 3 3 ∩ E33 ∈ {El3 , δl;{0,1} , δl;{0,2} }.
(17.4)
In addition, as in Case 1, (17.2) is valid. Because of (17.2) and (17.4), the relation ∩ El3 does not have any double rows. Hence, by (I ), ∩ El3 = El3 follows. Then with the help of Lemma 17.5.6 and (17.2), it follows that ι3k [1] ⊆ . Case 3: r = 2. Because of pr1,2 = El × Ek , we have that (17.4) is valid and, in addition, that (17.5) δk;{0,1} [2] ⊆ holds. In analog mode to the considerations from Case 2, either ∩ El3 = El3 3 or ∩ El3 = δl;{0,1} results. If El3 ⊆ then, because of (17.5), the relation 3 3 then ∩ ι3k = δk;{0,1} [2] must be valid, is (l; 2)-reflexive. If ∩ El3 = δl;{0,1} whereby our Lemma is proven. Lemma 17.5.8 For h ≥ 4, ιhk ∩ (Elr × Eks ) ⊆ holds, i.e., is (l; r)-reflexive.
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Proof. One can lead the proof analogously to the proof of Lemma 6.1.8: Because of (V II), for arbitrary (a, b), (b, c), (c, d) ∈ Eh2 \ι2h with |{a, b, c, d}| = 4 the following implications are not valid: (h ≥ 4 ∧ (x0 , ..., xh−1 ) ∈ ∧ xa = xb ) =⇒ xb = xc (h ≥ 5 ∧ (x0 , ..., xh−1 ) ∈ ∧ xa = xb ) =⇒ xc = xd .
(17.6) (17.7)
Next we prove ∃(a, b) ∈ Eh2 \ι2h : δ{a,b} [r] ⊆ =⇒ (∀(c, d) ∈ Eh2 \ι2h : δ{c,d} [r] ⊆ ). (17.8) Let δ{a,b} [r] ⊆ ({a, b} ⊆ Ek , a = b), {b, c} ⊆ Ek and c ∈ {a, b}. To prove (17.8), it is sufficient to show that δ{b,c} [r] ⊆ is valid. Because of δ{a,b} [r] ⊆ , we have δ{a,b,c} [r] ⊆ . The assumption (IV ) implies that ∩ δ{b,c} [r] is El diagonal. Consequently, we have ∩ δ{b,c} [r] ∈ {δ{a,b,c} [r], δ{b,c} [r]}. The case ∩ δ{b,c} [r] = δ{a,b,c} [r] leads to an implication of the form (17.6). Therefore, ∩ δ{b,c} [r] = δ{b,c} [r] is only possible, whereby (17.8) is right. Hence, it remains to show that δ{a,b} [r] ⊆ holds. W.l.o.g. let (a, b) = (0, 1). Set 1 := ∩δ{0,1} [r]. Because of (V II) and (IV ), the relation 1 is a nonempty El -diagonal relation. Consequently, since implications (5) and (6) are false, we have: if h ≥ 5, = δ{0,1} [r] ∈ {δ{0,1},{2,3} [r], δ{0,1} [r]} if h = 4. Thus, because of (17.8), our Lemma were proven for h ≥ 5 or h = 4 and 1 = δ{0,1},{2,3} [r]. Hence only the case h = 4 and ∩ δ{a,b} [r] ∈ {δ{0,1},{2,3} [r], δ{0,2},{1,3} [r], δ{0,3},{1,2} [r]}.
(17.9)
must still be examined. Because of pr0,1,2 = pr0,1,2 Elr × Eks and because of (IV ) we have || > |Elr × Eks−1 |. Consequently, there are certain a0 , a1 , a2 , a3 , a3 ∈ Ek with (a0 , a1 , a2 , a3 ), (a0 , a1 , a2 , a3 ) ∈ and a3 = a3 .
(17.10)
Then, the relation 2 := {(x1 , x2 , x3 , x3 ) ∈ Elr × Ek4−s | ∃x0 ∈ Ek : (x0 , x1 , x2 , x3 ) ∈ ∧ (x0 , x1 , x2 , x3 ) ∈ }, which is derivable from and El , has the properties: 2 ∩ δ{2,3} [r] = δ{2,3} [r] (since pr1,2,3 = pr1,2,3 Elr × Ek4−r ), δ{2,3} [r] ⊂ 2 (because of (17.10)) and
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17 Maximal Classes of P olk El for 2 ≤ l < k
2 ⊂ Elr × Ek4−r (By assumption (IV) we have: (a0 , a1 , a1 , a3 ) ∈ =⇒ a0 = a3 . Consequently: ((a1 , a2 , a3 , a3 ) ∈ 2 ∧ a1 = a2 ) =⇒ a3 = a3 .) Thus is no invariant of P olk El . In addition, because of the above facts, 2 is a totally (l; r)-reflexive relation. Then, by definition of 2 , we have ∩δ{1,2} [r] = δ{0,3},{1,2} [r], contrary to (17.9). Because of Lemmas 17.5.7 and 17.5.8, the following three cases are possible for h ≥ 3: 3 3 Case 2.1: h = 3, ∩ El3 = δl;{0,1} and ∩ ι3k = δk;{0,1} [2].
The investigation of this case concludes with minimal expenditure, with the aid of the following lemma. Lemma 17.5.9 In Case 2.1, relation has the following properties: (a) ∃u ∈ Ek \El : El2 × {u} ⊆ ; (b) is (l; 2)-symmetric; (c) is strongly (l; 2)-homogeneous, i.e., ∀x, y ∈ El ∀z ∈ Ek : (∃α, β ∈ El : {(x, α, z), (β, y, z), (α, β, z)} ⊆ ) =⇒ (x, y, z) ∈ . Proof. (a): The relation γt := {(a1 , b1 , a2 , b2 , ..., at , bt ) ∈ El2·t | ∃u ∈ Ek : {(a1 , b1 , u), (a2 , b2 , u), ..., (at , bt , u)} ⊆ } 3 [2] ⊆ , we have is a -derivable relation. Because of δk;{0,1}
{(x1 , x1 , x2 , x2 , ..., xt , xt ) ∈ El2·t | x1 , ..., xt ∈ El } ⊆ γt . Further, {(y1 , y2 , y1 , y2 , ..., y1 , y2 ) ∈ El2·t | y1 , y2 ∈ El } ⊆ γt holds, since pr0,1 = El2 . Consequently, the relation γt does not have any double rows, which is possible according to the assumption only for γt = El2·t . For t = l · (l − 1), this implies that there exists a u ∈ Ek with Ek × {u} ⊆ . The element u belongs to Ek \El , since the opposite case u ∈ El supplies a 3 . contradiction to ∩ El3 = δl;{0,1} (b): Let := {(x, y, z) ∈ El2 × Ek | {(x, y, z), (y, x, z)} ⊆ }. Obviously, the 3 ∪ (El2 × {u}), which is not El -diagonal, is a subset of . By relation δl;{0,1} (V ) this is only possible for = , whereby is (l; 2)-symmetric. (c): If one forms the -derivable relation 1 := {(a1 , a2 , b) ∈ El2 × Ek | ∃x1 , x2 ∈ El : {(a1 , x1 , b), (x2 , a2 , b), (x1 , x2 , b)} ⊆ },
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then one can see that 1 is an (l; 2)-symmetric relation with ⊆ 1 because of (b). By (V I) this is only possible for 1 ∈ {, El2 ×Ek }. Suppose, 1 = El2 ×Ek . Then, in particular, (0, 1, 0) ∈ 1 \. This implies the existence of certain 3 x1 , x2 ∈ El with (0, x1 , 0), (x2 , 1, 0), (x1 , x2 , 0) ∈ . Because of ∩El3 = δl;{0,1} the first two conditions are only fulfilled for x1 = 0 and x2 = 1, contrary to (0, 1, 0) ∈ . Consequently, 1 = and, therefore (c) is valid. Hence in Case 2.1 we have
3 . ∈ Hk;E l
Case 2.2.: h ≥ 3 and is (l; r)-reflexive. The following lemma summarizes some consequences from our assumptions in this case and from the properties obtained from . Lemma 17.5.10 (a) is (l; r)-symmetric. (b) Elh ⊆ . (c) For s ≥ 2, is a weakly (l; r)-central relation, i.e., s−1 i=0
Elr × Eki × El × Eks−i−1 ⊆ .
(d) r ≥ 1. Proof. (a): We consider the -derivable relation s , := s∈Sh [r]
where s := {(as(0) , as(1) , ..., as(h−1) ) | (a0 , a1 , ..., ah−1 ) ∈ }. By assumption, ιhk [r] ⊆ , where ιhk [r] is not El -diagonal. By (V ) this is only possible if = , whereby is (l; r)-symmetric. (b) follows from ιhl ⊆ and (I ). (c) follows from (b) and Lemma 17.5.6. (d): The case r = 0 (and therefore ιhk ⊆ ) cannot occur because of Lemma 17.5.1. Subsequently, we need the following property of set A more often. Lemma 17.5.11 It is not possible that the maximal class A (= P olk El × ) is describable with the aid of an h -ary totally (l; r)-reflexive and totally (l; r)symmetric relation with h > h. Proof. Let be an h -ary totally (l; r)-reflexive and totally (l; r)-symmetric relation, where h > h. Set A = P olk El × . Then A contains every function f ∈ P olk El with
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17 Maximal Classes of P olk El for 2 ≤ l < k
Im(f ) ⊆ T ∈ {{a1 , .., ar , b1 , ..., bh −r } | (a1 , ..., ar , b1 , ..., bh −r ) ∈ }. Then, because of h < h , it is not possible to describe A by a relation ⊆ Elr × Ekh−1 , contrary to our assumptions. Case r = 1 cannot occur, as shown by the following lemma: h Lemma 17.5.12 If r = 1 then ∈ Ck;E [1]. l
Proof. Because of Lemma 17.5.10,(a),(c) we must only show that has an (l; 1)-central element of El . The following relation is a -derivable relation: γt := {(a1 , ..., at ) ∈ El × Ekt−1 | ∃c ∈ El : ∀i1 , ..., ih−1 ∈ {1, ..., t} : (c, ai1 , ..., aih−1 ) ∈ }. First we show that γh = El × Ekh−1 holds. For this purpose, let (a1 , ..., ah ) be an arbitrary element of El × Ekh−1 . By (V II) for (a2 , ..., ah ) there is a certain α ∈ El with (α, a2 , ..., ah ) ∈ . Since is weakly (l, 1)-central because of Lemma 17.5.10,(c), we have (α, ai−1 , ..., aih−1 ) ∈ for all {i1 , ..., ih−1 } ⊆ {1, 2, ..., h} and 1 ∈ {i1 , ..., ih−1 }. Consequently, (a1 , ..., ah ) belongs to γh , whereby γh = El × Ekh−1 holds. Because of γh = El × Ekh−1 it is easy to prove that the relation γh+1 is (l; 1)-reflexive, which is valid only for γh+1 = El × Ekh because of Lemma 17.5.11. Therefore, by induction, we have γk = El × Ekk−1 . The existence of an (l; 1)-central element follows immediately from that. We can, therefore, always presuppose that r ≥ 2. By Lemma 17.5.10, the relation γr,s := {(a1 , ..., ar , b1 , ..., bs ) ∈ Elr × Eks | (∃i ∈ {1, ..., s} : bi ∈ El ) ∨ (a1 , ..., ar , b1 , ..., bs ) ∈ ιr+s k [r]}
is a subset of . Next we clarify for which r, s the equation = γr,s is valid. Lemma 17.5.13 The relation γr,s has the following properties: (a) (4 ≤ r ≤ l ∧ 1 ≤ s ≤ k − l) =⇒ γr,s ∈ [{γr−1,s } ∪ Invk P olk El ]; (b) (2 ≤ r ≤ l ∧ 3 ≤ s ≤ k − l) =⇒ γr,s ∈ [{γr,s−1 } ∪ Invk P olk El ]; (c) (3 ≤ r ≤ l ∧ s = 1) =⇒ γl,1 ∈ [{γr,1 } ∪ Invk P olk El ]; (d) (r = 2 ∧ 2 ≤ s ≤ k − l) =⇒ γ2,k−l ∈ [{γ2,s } ∪ Invk P olk El ]; (e) (3 ≤ r ≤ l ∧ 2 ≤ s ≤ k − l) =⇒ γl,k−l ∈ [{γr,s } ∪ Invk P olk El ]; Proof. (a): Obviously, the (r + s)-ary relation α1 := {(a1 , ..., ar , b1 , ..., bs ) ∈ Elr × Eks | ∃u ∈ El : (a1 , a2 , ..., ar−2 , u, b1 , ..., bs ) ∈ γr−1,s ∧ (∀j1 , ..., jr−4 ∈ {1, 2, .., r − 2} : (u, aj1 , aj2 , ..., ajr−4 , ar−1 , ar , b1 , ..., bs ) ∈ γr−1,s )}
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is γr−1,s -derivable. Consequently, to prove (a), it suffices to show the equation α1 = γr,s : Let x := (a1 , ..., ar , b1 , ..., bs ) ∈ γr,s be arbitrary. The following table shows that γr,s ⊆ α1 . i 1 2 2.1 2.2 2.3 3
Case i for x ∃i ∈ {1, ..., s} : bi ∈ El ∃{i, j} ⊆ {1, ..., r} : i < j ∧ ai = aj {i, j} ⊆ {1, 2, ..., r − 2} i ∈ {1, 2, ..., r − 2} ∧ j ∈ {r − 1, r} i=r−1 ∧ j =r ∃{i, j} ⊆ {1, ..., s} : i < j ∧ bi = bj
u ∈ El such that x ∈ α1 u ∈ El u = ar−1 u = aj u = a1 u ∈ El
Suppose there is a tuple (x1 , ..., xr , y1 , ..., ys ) ∈ α1 \γr,s . Since the elements of this tuple are pairwise different, an element u ∈ El , for which (x1 , x2 ..., xr−2 , u, y1 ...ys ) ∈ γr−1,s holds, must belong to the set {x1 ..., xr−2 }. Analogously, one can show that the remaining conditions of the definition of α1 are only fulfilled if u ∈ {xr−1 , xr }. Therefore, no element u that fulfills all conditions from the definition of α1 exists, whereby α1 = γr,s is proven. (b): The relation α2 := {(a1 , ..., ar , b1 , ..., bs ) ∈ Elr × Eks | ∃u1 , u2 ∈ El : ∀i1 , ..., ir−2 ∈ {1, ..., r} : (u1 , a1 , ai1 , ..., air−2 , b1 , ..., bs−2 , bs−1 ) ∈ γr,s−1 ∧ (u2 , a2 , a11 , ..., air−2 , b1 , ..., bs−2 , bs ) ∈ γr,s−1 ∧ (u1 , u2 , ai1 , ..., air−2 , b2 , b3 , ..., bs−1 , bs ) ∈ γr,s−1 } is an γr,s−1 -derivable relation. Analogous to the proof of (a), one can show that α2 = γr,s . We only prove here that γr,s ⊆ α2 is valid. However, this follows from the following table, where x := (a1 , ..., ar , b1 , ..., bs ) ∈ γr,s is arbitrary. i 1 2 3 4 4.1 4.2 4.3 5
Case i for x ∃i ∈ {1, ..., s − 2} : bi ∈ El bs−1 ∈ El bs ∈ El ∃{i, j} ⊆ {1, ..., s} : i < j ∧ bi = bj {i, j} ⊆ {1, 2, ..., s − 2, s − 1} {i, j} ⊆ {1, 2, ..., s − 2, s} {i, j} ⊆ {2, 3, ..., s − 1, s} ∃{i, j} ⊆ {1, ..., r} : i < j ∧ ai = aj
u1 , u2 ∈ El such that x ∈ α1 u1 = u2 u2 = a2 u1 = a1 u1 u1 u1 u1
= u2 = a2 = u2 = a1 = a1 , u2 = a2 = a1 , u2 = a2
The statements (c)–(e) follow from (a) and (b). Then Lemma 17.5.13, (c)–(e) implies Lemma 17.5.14 If = γr,s then (r, s) ∈ {(2, 1), (l, 1), (2, k − l), (l, k − l)}.
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17 Maximal Classes of P olk El for 2 ≤ l < k
Note: As is generally known, every relation that is preserved from all unary functions of Pk , is representable through the union of certain diagonal relations on Ek . Then, as one can easily prove, every relation that is preserved from all unary functions of P olk El is representable through the union of certain El -diagonal relations on Ek . Consequently, because of Lemma 17.5.14 (and Lemmas 17.3.9 and 17.3.10) all maximal classes of P olk El , which all functions of (P olk El )1 contain and fulfill the conditions of this section and of Case 2, were determined. We say that an h-ary, totally reflexive and totally symmetric relation γ (⊆ Elr × Eks ) is strongly (l; r)-homogeneous, if the following is valid: ∀a0 , ..., ar−1 ∈ El ∀b0 , ..., bs−1 ∈ Ek : ( (∃v0 , ..., vr−1 ∈ El : (v0 , ..., vr−1 , b0 , ..., bs−1 ) ∈ ∧ (∀i ∈ Er ∀j ∈ Er \{i} : (a0 , ..., aj−1 , vi , aj+1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ )) =⇒ (a0 , ..., ar−1 , b0 , ..., bs−1 ) ∈ ) Lemma 17.5.15 is either an (l; r)-central or a strong (l; r)-homogeneous relation. Proof. First, for t ∈ {r, r + 1, ..., l}, we consider the -derivable relation t := {(a0 , ..., at−1 , b0 , ..., bs−1 ) ∈ Elt × Eks | ∃c ∈ El : (∀i0 , ..., ir−2 ∈ Et : (ai0 , ..., air−2 , c, b0 , ..., bs−1 ) ∈ ))}. Since is totally (l; r)-symmetric, this relation is also totally (l; r)-symmetric. If one put c = a0 for t = r, then one can see that ⊆ r holds. Therefore, because of our assumption (V I), the following two cases are possible: Case 1: r = Elr × Eks . This case is only possible for r < l, since, in the opposite case, the definition of t implies = Ell × Eks . For r < l the -derivable relation r+1 is obvious totally (l; r + 1)-reflexive, whereby r+1 = Elr+1 × Eks follows with the aid of Lemma 17.5.11. One easily shows by induction that i = Eli × Eks is valid for h [r]. every i ∈ {r + 1, ..., l}. Then, l = Ell × Eks implies ∈ Ck;E l Case 2: = r . In this case, the relation is (l; r)-homogeneous; that is, it fulfills the condition (∃v ∈ El : ∀i ∈ Er : (a0 , ..., ai−1 , v, ai+1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ ) =⇒ (a0 , a1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ for arbitrary a0 , a1 , ..., ar−1 ∈ El and arbitrary b0 , ..., bs−1 ∈ Ek . The total (l; r)-symmetric relation
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
541
γt := {(a0 , ..., at−1 , b0 , ..., bs−1 ) | ∃v0 , v1 , ..., vt−1 ∈ El : (∀i1 , ..., ir ∈ Et : (vi1 , ..., vir , b0 , ..., bs−1 ) ∈ ) ∧ (∀n ∈ Et ∀j1 , ..., jr−2 ∈ Et \{n} : (aj1 , ..., ajr−2 , an , vn , b0 , ..., bs−1 ) ∈ )} (t ∈ {r, r + 1, ..., l}) is -derivable and, if γt−1 = Elt−1 × Eks , totally (l; t)reflexive. In particular, for r = t we have ⊆ γr . (To see this, one chooses vα = aα in the definition of γr for every α ∈ Er .) And = γr means that is strongly (l; r)-homogeneous. Now, by assumption (V I), we have that γr ∈ {, Elr × Eks } holds. Thus our lemma would be proven, if we could show that the case γr = Elr × Eks does not occur. Suppose γr = Elr × Eks and r < l. Then γr+1 is totally (l; r + 1)-reflexive and therefore γr+1 = Elr+1 × Eks because of Lemma 17.5.11. Thus, one can prove by induction that γl = Ell × Eks . Therefore, for arbitrary a0 , ..., ar−1 ∈ El and b0 , ..., bs−1 ∈ Ek , there are certain v0 , ..., vr−1 ∈ El with (v0 , v1 , ..., vr−1 , b0 , ..., bs−1 ) ∈
(17.11)
and ∀n ∈ Er ∀α1 , ..., αh−2 ∈ El \{an } : (α1 , ..., αr−2 , an , vn , b0 , ..., bs−1 ) ∈ . (17.12) By induction we show that for arbitrary a0 , ..., ar−1 ∈ El and b0 , ..., bs−1 ∈ Ek is valid: ∀t ≥ 0 : (a0 , ..., at−1 , vt , vt+1 , ..., vr−1 , b0 , ..., bs−1 ) ∈ .
(17.13)
For t = 0, (17.13) holds because of (17.11). Assume (17.13) is valid for t = n. Then, for t = n + 1 the statement (17.13) follows from this assumption, from the (l; r)-homogeneousness of (considering (17.12)) and from the total (l; r)-symmetry of , when one chooses v = vn for the tuple (a0 , ..., an , vn+1 , ..., vr−1 , b0 , ..., bs−1 ). (17.13) implies (a0 , ..., ar−1 , b0 , ..., bs−1 ) ∈ for arbitrary a0 , ..., ar−1 ∈ El and b0 , ..., bs−1 ∈ Ek , contrary to ⊂ Elr × Eks . Consequently, our assumption γr = Elr × Eks is false and therefore is strongly (l; r)-homogeneous. To conclude our proof in this section, because of Lemma 17.5.15, it remains to show that if is strongly (l; r)-homogeneous the relation or a relation derivable from belongs to Bk;El [r]. Because of Lemma 17.5.10, we have only to prove conditions 5)–6) from the definition of an (l; r)-universal relation. Thus we can assume that is a strong (l; r)-homogeneous relation in the following. Lemma 17.5.16 For every b := (b0 , ..., bs−1 ) ∈ (Ek \El )s the relation εb := {(a, b) ∈ El2 | ∀a0 , ..., ar−3 ∈ El : (a0 , a1 , ..., ar−3 , a, b, b0 , ..., bs−1 ) ∈ } is an equivalence relation on El .
542
17 Maximal Classes of P olk El for 2 ≤ l < k
Proof. By the total (l; r)-reflexivity and total (l; r)-symmetry of , the reflexivity and symmetry of εb follows directly. To prove the transitivity of εb let {(a, b), (b, c)} ⊆ εb . Choosing v0 = α0 , v1 = α1 , ..., vr−3 = αr−3 , vr−2 = b and vr−1 = b in the definition of a strong (l; r)-homogeneous relation for the tuple (α0 , α1 , ..., αh−3 , a, c, b0 , ..., bs−1 ) we get (α0 , ...., αr−3 , a, c, b0 , ..., bs−1 ) ∈ for arbitrary α0 , ..., αr−3 ∈ El , whereby (a, c) ∈ εb . The following lemma is a direct consequence from Lemmas 17.5.10, 17.5.14, and 17.5.16: Lemma 17.5.17 If r = 2 then the strong (l; 2)-homogeneous relation beh longs to Bk;E [2]. l From the above lemma, we can assume that r≥3 in our further considerations. By the equivalence relation εb , the set El is partitioned into certain (nonempty) equivalence classes Ai [b] (i = 1, 2, ..., t[b]), from which we choose a representative αi [b]. With the help of the representative set Vb := {α1 [b], ..., αt[b] [b]}, we can define a mapping Fb : El −→ Vb by Fb (a) = αi [b] :⇐⇒ {a, αi [b]} ⊆ Ai [b]. Lemma 17.5.18 Let be strongly (l; r)-homogeneous. Then for every b := (b0 , ..., bs−1 ) ∈ (Ek \El )s \ιsk is valid: (a) (a0 , ...., ar−1 , b0 , ..., bs−1 ) ∈ ⇐⇒ (Fb (a0 ), ..., Fb (ar−1 ), b0 , ..., bs−1 ) ∈ ; (b) ((∀a0 , ..., ar−3 ∈ Vb : Vb ) =⇒ a = b.
(a0 , ..., ar−3 , a, b, b0 , ..., bs−1 ) ∈ ) ∧ {a, b} ⊆
Proof. (a): First we show that the equivalence (a, a1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ ⇐⇒ (b, a1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ (17.14) is valid for (a, b) ∈ εb and for arbitrary a0 , ..., ar−1 ∈ El . If (a, a1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ , then (b, a1 , ...., ar−1 , b0 , ..., bs−1 ) ∈ follows from the strong (l; r)-homogeneousness of , choosing v0 = v1 = .... = vr−1 = a. Since εb is symmetric, we have also proven “⇐=” of (17.14). Now (a) follows from (ai , Fb (ai )) ∈ εb (i ∈ Er ), (17.14), Lemma 17.5.16 and of the total (l; r)-symmetry of :
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
543
(a0 , ...., ar−1 , b0 , ..., bs−1 ) ∈ ⇐⇒ ⇐⇒ (Fb (a0 ), a1 , ..., ar−1 , b0 , ..., bs−1 ) ∈ (Fb (a0 ), Fb (a1 ), a2 , ..., ar−1 , b0 , ..., bs−1 ) ∈ ⇐⇒ .. . (Fb (a0 ), ..., Fb (ar−1 ), b0 , ..., bs−1 ) ∈ .
⇐⇒
(b) is a conclusion from the definitions of εb and Vb and from (a). Now put ξb := Fb (b ) := {(Fb (a0 ), ..., Fb (ar−1 )) | (a0 , ..., ar−1 , b0 , ..., bs−1 ) ∈ }. By Lemma 17.5.18, (a) b is a homomorphic inverse image of this relation; i.e., it holds that b = {(a0 , ..., ar−1 ) ∈ Elr × Eks | (Fb (a0 ), ..., Fb (ar−1 )) ∈ ξb }. Because of = Elr ×Eks there is at least a b ∈ (Ek \El )s \ιsk with Elr ×{b} ⊆ . Thus w.l.o.g. we can assume Vb = Et[b] and (0, 1, ..., r − 1, b0 , ..., bs−1 ) ∈ (Vbr × {b})\ξb . To prove that has the properties 5) and (only for s ≥ 2) 6) from the definition of an (l; r)-universal relation, we consider the -derivable q-ary graphic Gq (P ol) := χq ∪ {g(κ1 , ..., κq ) | g ∈ (P ol)q }, where χq := (κ1 , ..., κq ) is the q-ary abscissa over Ek (in matrix form, see Section 2.7) and q ∈ N. Let m1 , ..., mi , n1 , ..., nj be the numbers of those rows of χri ·sj for which Ai,j := prm1 ,...,mi ,n1 ,...,nj χri ·sj is a matrix form of the relation Eri × {b0 , ..., bs−1 }j (r ≤ i ≤ l; s ≤ j ≤ k − l). Further, let µi,j := prm1 ,...,mi ,n1 ,...,nj Gri ·sj (P ol). Lemma 17.5.19 If is strongly (l; r)-homogeneous and (0, 1, 2, ..., r−1, b0 , ..., bs−1 ) ∈ , then µi,j = Eli × Ekj for all i, j with r ≤ i ≤ l and j = 1, if s = 1, and s ≤ j ≤ k − l. Proof. First we remark that = (Elr × Eks )\{(a0 , ..., ar−1 , b0 , ..., bs−1 ) | {a0 , ..., ar−1 } = Er }
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17 Maximal Classes of P olk El for 2 ≤ l < k
h because of ∈ Ck;E [r]. Furthermore, if (β0 , ..., βr−1 ) ∈ , every function g l with Im(g) = {β0 , ..., βh−1 } belongs to P ol. Suppose the lemma is false for (i, j) = (r, s). Then we can form an h-ary relation with ⊂ ⊂ Elr × Eks with the help of the rr · ss -ary graphic of P ol by projection, contradicting (V I). Since all functions of P ol with at most ri · sj essential variables belong to i+1 j i j+1 (P ol)r ·s or (P ol)r ·s , it is easy to show by induction that the following holds:
∀i ∈ {r, ..., l − 1} : µi,j = Eli × Ekj =⇒ ιki+j+1 [i + 1] ⊆ µi+1,j and ∀i ∈ {s, ..., k − l − 1} : µi,j = Eli × Ekj =⇒ ιki+j+1 [i] ⊆ µi,j+1 , if s > 1. Consequently, our lemma follows from Lemma 17.5.11. Let
νs :=
rl if s = 1, rl · sk−l if s ≥ 2.
Because of Lemma 17.5.19, we can find a νs -ary function fb ∈ P ol for s ≥ 2 with den properties Im(fb ) = Vb ∪ (Ek \El ) and
⎛
⎞ Fb (0) ⎜ Fb (1) ⎟ ⎜ ⎟ ⎜ ⎟ ... ⎜ ⎟ ⎜ Fb (l − 1) ⎟ ⎜ ⎟. fb (Al,k−l ) = ⎜ ⎟ l ⎜ ⎟ ⎜ l+1 ⎟ ⎜ ⎟ ⎝ ⎠ ... k−1
In the case that s = 1, an analogous statement is valid for the matrix Al,1 : ⎞ ⎛ Fb (0) ⎜ Fb (1) ⎟ ⎟ ⎜ ⎟. ... fb (Al,1 ) = ⎜ ⎟ ⎜ ⎝ Fb (l − 1) ⎠ b0 Therefore, fulfills condition 6) of the definition of an (l; r)-universal relation. Let w0 , ..., ws−1 be certain rows of Al,k−l or Al,1 with f (wi ) = bi (i = 0, ..., s − 1).
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
545
Next we give some properties of the function fb on νs -ary tuples of Erνs , from h [r]. which will follow that ∈ Bk;E l We also give elements z of Erνs in the form (z[1], z[2], ..., z[νs ]) and, for every z ∈ Erνs , denote z t,a
(t ∈ {1, 2, ..., νs }, a ∈ Er )
an element of Erνs , which is defined by a, if i = t, z t,a [i] := z[i] otherwise (i ∈ {1, 2, ..., νs }). Lemma 17.5.20 Let t ∈ {1, 2, ..., νs }, z ∈ Erνs and (fb (z t,0 ), ..., fb (z t,r−1 )) ∈ ξb . Then (a) fb (z t,0 ) = ... = fb (z t,r−1 ), (b) ∀w ∈ Erνs : fb (wt,0 ) = ... = fb (wt,r−1 ). Proof. (a): For proof, it is sufficient to show that w.l.o.g. fb (z t,r−2 ) = fb (z t,r−1 ). First we prove ∀β0 , ..., βr−3 ∈ Erνs : (fb (β0 ), ..., fb (βr−3 ), fb (z t,r−2 ), fb (z t,r−1 )) ∈ ξb . (17.15) If {β0 [t], β1 [t], ..., βr−3 [t]} = {0, 1, ..., r − 3}, then (17.15) holds, since in this case all columns of the matrix ⎞ ⎛ β0 ⎜ β1 ⎟ ⎟ ⎜ ⎜ ... ⎟ ⎟ ⎜ ⎜ βr−3 ⎟ ⎜ t,r−2 ⎟ ⎟ B := ⎜ ⎜ z t,r−1 ⎟ ⎟ ⎜z ⎟ ⎜ ⎜ w0 ⎟ ⎟ ⎜ ⎝ ... ⎠ ws−1 belong to ιhk [r] and fb preserves the relation . Let w.l.o.g. βi [t] = i for i ∈ Er−2 . Substituting the i-th row of B by z t,j , where i = j, we obtain a matrix Bi,j the columns of which belong to ιhk [r], whereby fb (Bi,j ) ∈ ξb × {b} holds. Consequently, by the strong (l; r)-homogeneousness of , choosing vj = fb (z t,j ) (j ∈ Er ) for the tuple (fb (β0 ), ..., fb (βr−3 ), fb (z t,r−2 ), fb (z t,r−1 ), b0 , ..., bs−1 ), we get (17.15). Since {fb (x) | x ∈ Erνs } = Vb , there are certain β0 , ..., βr−3 ∈ Erνs with fb (βi ) = ai (i ∈ Er−2 ) for arbitrary a0 , ..., ar−3 ∈ Vb . Consequently, by (17.15) we have
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17 Maximal Classes of P olk El for 2 ≤ l < k
∀a0 , ..., ar−2 ∈ Vb : (a0 , ..., ar−3 , fb (z t,r−2 ), fb (z t,r−1 ), b0 , ..., bs−1 ) ∈ ξb × {b}. Because of Lemma 17.5.18, (b), this implies fb (z t,r−2 ) = fb (z t,r−1 ). (b): Because of (a), it is sufficient to show that (fb (wt,0 ), ...., fb (wt,r−1 )) ∈ ξb
(17.16)
holds. (17.15) implies (fb (wt,0 ), ..., fb (wt,r−3 ), fb (z t,r−2 ), fb (z t,r−1 )) ∈ ξb . Now it is easy to check that any exchange of an i-th row in ⎛ ⎞ wt,0 ⎜ ... ⎟ ⎜ t,r−1 ⎟ ⎜w ⎟ ⎜ ⎟ ⎜ w0 ⎟ ⎜ ⎟ ⎝ ... ⎠ ws−1 by wt,j for i ∈ Er−3 or by z t,j for i ∈ {r − 2, r − 1} and i = j gives a matrix M, whose columns belong to ιhk [r] and it holds f (M) ∈ ξb × {b}. Hence, by the strong (l; r)-homogeneousness of , choosing v0 = fb (wt,0 ), ..., vr−3 = fb (wt,r−3 ), vr−2 = fb (z t,r−2 ), vr−1 = fb (z t,r−1 ), we get (17.16). Lemma 17.5.21 For the function fb , there are certain digits t1 , ..., tm[b] that are exactly the essential digits of (fb )|Erνs (restriction of fb to Erνs ); i.e., it holds that ∀z, w ∈ Erνs : fb (z) = fb (w) ⇐⇒ ∀i ∈ {t1 , ..., tm[b] } : z[i] = w[i]. (17.17) Furthermore, f has the properties |Im(fb )| = rm[b] and ∀r1 , ..., rνs ∈ Err × {b} : ({rt1 , ..., rtm[b] } ⊆ ιhk [r] =⇒ fb (r1 , ..., rνs ) ∈ ) (17.18) Proof. For every t ∈ {1, 2, ..., νs }, we have either fb (z t,0 ) = fb (z t,1 ) = ... = fb (z t,r−1 ) for every z ∈ Erνs or (fb (z t,0 ), fb (z t,1 ), ..., fb (z t,r−1 ), b0 , ..., bs−1 ) ∈
17.5 Not Through Relations of Rmax (Pl ) ∪ Rmax (Pk ) Describable Classes
547
for all z ∈ Erνs by Lemma 17.5.20. Let T := {t1 , ..., tm[b] } be the set of all t ∈ {1, 2, ..., νs }, for which (fb (z t,0 ), ..., fb (z t,r−1 ), b0 , ..., bs−1 ) ∈ holds. Now we will show that the digits ti ∈ T of fb have the properties of Lemma 17.5.21. First let fb (z) = fb (w) for certain z, w ∈ Erνs and assume there exists an i ∈ T with α := z[i] = w[i]. Then the columns of the matrix ⎛ i,0 ⎞ z ⎜ ... ⎟ ⎜ i,α−1 ⎟ ⎟ ⎜z ⎟ ⎜ ⎜ w ⎟ ⎜ i,α+1 ⎟ ⎟ ⎜z ⎟ A := ⎜ ⎜ ... ⎟ ⎜ i,r−1 ⎟ ⎟ ⎜z ⎟ ⎜ ⎜ w0 ⎟ ⎟ ⎜ ⎝ ... ⎠ ws−1 belong to ιhk [r], whereby fb (A) ∈ ξb × {b} holds. Because of fb (w) = fb (z) = fb (z i,α ) follows (fb (z i,0 ), ..., fb (z i,r−1 ), b0 , ..., bs−1 ) ∈ ξb , contrary to i ∈ T and the definition of T . Therefore “=⇒” in (17.17) holds. Let now z[i] = w[i] for every i ∈ T and w.l.o.g. T = {1, 2, ..., m[b]}. fb (w) = fb (z) is proven if we can show that fb (un−1 ) = fb (un )
(17.19)
holds for every tuple un := (z[1], ..., z[n], w[n + 1], w[n + 2], ..., w[νs ]) and all n ∈ {m + 1, m + 2, ..., νs }, since fb (um ) = fb (w) and fb (uνs ) = fb (z). n,j By n > m[b] and the definition of T , we have fb (un,i n−1 ) = fb (un−1 ) for arbin,w[n] n,z[n] trary i, j ∈ Er . As un−1 = un−1 and un−1 = un , we have (17.19), whereby (17.17) is proven. From (17.17) and {fb (x) | x ∈ Erνs } = Vb follows |Vb | = rm[b] . Finally we prove (17.18). Assume (17.18) is false. Then there are certain z0 , z1 , ..., zr−1 ∈ Erνs with (fb (z0 ), fb (z1 ), ..., fb (zr−1 ), b0 , ..., bs−1 ) ∈ ξb × {b} and (w.l.o.g.) zi [1] = i for every i ∈ Er and 1 ∈ T . Let w, z ∈ Erνs be arbitrary. Then each column of the matrix
548
17 Maximal Classes of P olk El for 2 ≤ l < k
⎛
Ci,j
w1,0 ⎜ ... ⎜ 1,j−1 ⎜w ⎜ 1,i ⎜ z ⎜ 1,j+1 ⎜w := ⎜ ⎜ ... ⎜ 1,r−1 ⎜w ⎜ ⎜ w0 ⎜ ⎝ ... ws−1
⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠
belongs to ιhk [r] for i = j. Thus fb (Ci,j ) ∈ ξb × {b}. By choosing vi = fb (z 1,i ) for the tuple (fb (w1,0 ), ..., fb (w1,r−1 ), b0 , ..., bs−1 ) and i ∈ Er , (fb (w1,0 ), ..., fb (w1,r−1 ), b0 , ..., bs−1 ) ∈ ξb × {b} follows from this and the strong (l; r)-homogeneousness of , contrary to the definition of T and 1 ∈ T . Lemma 17.5.22 Let be strongly (l; r)-homogeneous, b ∈ (Ek \El )s \ιsk and Elr × {b} ⊆ . Then for certain m[b] ∈ N there is a bijective mapping ϕb from Erm[b] onto Vb with ξb = ϕb (ξm[b] ) := {(ϕb (a0 ), ..., ϕb (ar−1 )) | (a0 , ..., ar−1 ) ∈ ξm[b] } (ξm[b] denotes an r–ary elementary relation) and it holds that −1 b = {(a0 , ..., ar−1 ) ∈ Elr | (ϕ−1 b (F (a0 )), ..., ϕb (F (ar−1 ))) ∈ ξm[b] }; h i.e., ∈ Bk;E [r]. l
Proof. Subsequently, we denote m[b] with m. Because of Lemma 17.5.21, a bijective mapping from Erm onto Vb is defined by ϕb (a(m−1) hm−1 + a(m−2) hm−2 + ... + a(1) h + a(0) ) = fb (z) :⇐⇒ (z[t1 ], z[t2 ], ..., z[tm ]) = (a(m−1) , a(m−2) , ..., a(0) ), where a ∈ Erm . Let now (a0 , ..., ar−1 ) ∈ ξm . Then there are certain z0 , ..., zr−1 ∈ Erνs with the following properties: (z0 [i], ..., zr−1 [i]) ∈ ιrr for every i ∈ {1, 2, ..., νs } and (ϕb (a0 ), ϕb (a1 ), ..., ϕb (ar−1 )) = (fb (z0 ), fb (z1 ), ..., fb (zr−1 )). Then, because of fb ∈ P ol, we have (ϕb (a0 ), ..., ϕb (ar−1 ), b0 , ..., bs−1 ) ∈ ξb × {b} and therefore ϕb (ξm ) ⊆ ξb . Suppose there exists
17.6 Classes Describable by Relations of Rmax (Pl ) ∪ Rmax (Pk )
549
(a0 , ..., ar−1 ) ∈ ξb \ϕb (ξm ). Then, by definition of ϕb , there exist certain z0 , ..., zr−1 ∈ Erνs and an i ∈ {t1 , ..., tm } with (fb (z0 ), ..., fb (zr−1 )) = (a0 , ..., ar−1 ) and (z0 [i], ..., zr−1 [i]) ∈ ιrr . But this is contrary to (17.18). Thus ξb = ϕb (ξm ). The remaining assertions follow from Lemma 17.5.18, (a) and the definition of ξb . Summing up, we obtain in Case 2.2, h h ∈ Ck;E [r] ∪ Bk;E . l l
17.6 Classes Describable by Relations of Rmax(Pl) ∪ Rmax(Pk) The aim of this section is to prove the following: Theorem 17.6.1 Let be an h-ary relation of Rmax (Pl ) ∪ Rmax (Pk ). Then P olk × El is a maximal class of P olk El if and only if ∈ Rmax (Pl ) ∪ Uk;El ∪ Ck;El . With the help of Sections 5.2 and 5.4, one can easily prove the following lemma: Lemma 17.6.2 It holds: (a) ∀ ∈ Rmax (Pk )\Rmax (Pl ) : prEl (P olk × El ) = Pl =⇒ P olk × El is not maximal in P olk El . (b) ∀, ∈ Rmax (Pk ) : P olk = P olk ∧ prEl P olk × El = prEl P olk × El = Pl =⇒ P olk × El = P olk × El . Lemma 17.6.3 For every relation ∈ Mk ∪ Sk ∪ Lk , there is a certain -derivable relation which belongs to Rmax (Pl ) ∪ Ck;El . Proof. Let be an arbitrary h-ary relation of Mk ∪ Sk ∪ Lk . Then the following relations are -derivable: := ∩ Elh and
El := pr1,...,h−1 (∆(El × )).
We distinguish two cases for : Case 1: ∈ Mk ∪ Sk . Then the following three cases are possible for the relation : Case 1.1: = ∅. This case is possible only for ∈ Sk and the relation El ( = {x ∈ Ek | ∃a ∈ El : (a, x) ∈ } ) belongs to C1k;El , since (by = ∅) (a, b) ∈ for all a ∈ El implies b ∈ El .
550
17 Maximal Classes of P olk El for 2 ≤ l < k
Case 1.2: ∅ ⊂ ⊂ ι2l or ι2l ⊂ ⊂ El2 . Then, ∈ Rl \Dl , and because of Chapter 6, one can derive a relation of Rmax (Pl ) from the relations of { } ∪ Dl . Case 1.3: = ι2l . This case is possible only for ∈ Mk . Then, all elements of El are incomparable in respect to the partial order relation , and both the smallest element o and the greatest element e of Ek (in respect to ) belong to the set Ek \El . Since e ∈ El and o ∈ El , we have El ⊆ El and El ⊂ El ⊂ Ek for the above defined relation El , obviously. Consequently, El ∈ C1k;El and our assertion also holds in Case 1.3. Case 2: ∈ Lk . In this case, k = pm (p prime, m ≥ 1) and = {(a, b, c, d) ∈ Ek4 | a + b = c + d}, where (Ek ; +) is an elementar Abelean p-group. W.l.o.g. (see Lemma 5.2.4.2) we can assume that the element 0 ∈ El is the neutral element of (Ek ; +). Then the relation is not El -diagonal because of {(a, 0, 0, a), (a, 0, a, 0), (0, a, 0, a), (0, a, a, 0) | a ∈ El } ⊆ ⊆ El4 and (0, 1, 1, 1) ∈ . Consequently, by Chapter 6, one can derive a relation of Rmax (Pl ) from relations of {} ∪ Dl . Lemma 17.6.4 For every ∈ Bhk (3 ≤ h ≤ k) the clone P olk × El is not maximal in P olk El . Proof. Let ∈ Bhk . We consider the -derivable relations r := ∩ (Elr × Ekh−r ) (0 ≤ r ≤ h). Since ιhk ⊆ and h ≥ 3, the sets ιhl and {(x1 , ..., xh ) ∈ Ekh | |{x1 , ..., xh }| ≤ 2} are subsets of . Consequently, the relations r do not have any double rows for every r ∈ {0, 1, ..., h}, and it holds that ∀i ∈ Eh : pri r = pri Elr × Ekh−r . Therefore, r ∈ Invk P olk El implies r = Elr × Ekh−r . Let r∗ be the smallest number, for which is valid r∗ ∈ Invk P olk El and r ∈ Invk P olk El for all r < r∗ . The following cases are possible: Case 1: r∗ = 0. Because of the above remarks, we have 1 = El × Ekh−1 ⊆ , whereby every element c ∈ El is a central element of the relation , which cannot, however, be for the relation ∈ Bk . Case 2: r∗ = 1. In this case, the relation 1 is totally (l; 1)-reflexive, totally (l; 1)-symmetric, weakly (l; 1)-central and different from El × Ekh−1 . In addition, we can assume that for every (a2 , ..., ah ) ∈ Ekh−1 there exists a c ∈ El with (c, a2 , ..., ah ) ∈ 1 .
17.6 Classes Describable by Relations of Rmax (Pl ) ∪ Rmax (Pk )
551
Namely, if this is false, we can derive a relation of Ck by forming pr1,...,h−1 1 , whereby P olk ×El is not a maximal class of P olk El because of Lemma 17.6.2. Let γt := {(a1 , ..., at ) ∈ El × Ekt−1 | ∃c ∈ El : ∀i2 , ..., ih ∈ {1, 2, ..., t} : (c, ai2 , ..., aih ) ∈ 1 }. This relation has the property (γt = El ×Ekt−1 ∧ t ≥ h) =⇒ γt+1 = El ×Ekt ∨ (∃ ∈ Ck : γt ) (17.20) as one can prove: Because of γt = El × Ekt−1 and the above properties of 1 , the relation γt+1 is strongly (l; 1)-reflexive, strongly (l; 1)-symmetric and := pr1,...,t+1 γt+1 = Ekt , then γt+1 ∈ Ck . weakly (l; 1)-central. Thus, if γt+1 t t If γt+1 = Ek , then for every (a2 , ..., at+1 ) ∈ Ek there is an α ∈ El with (α, a2 , ..., at+1 ) ∈ γt+1 and we can show γt+1 = El × Ekt , as follows: Let (a1 , a2 , ..., at+1 ) ∈ El × Ekt . Then there exists an α ∈ El with (α, a2 , ..., at+1 ) ∈ γt+1 . Because of the definition of γt+1 , this implies ∃c ∈ El ∀i2 , ..., ih ∈ {2, ..., t + 1} : (c, ai2 , ...aih ) ∈ 1 . In addition, we have ∀i2 , ..., ih ∈ {1, 2, ..., t+1} : (∃q ∈ {2, ..., h} : iq = 1) =⇒ (c, ai2 , ..., aih ) ∈ 1 , since 1 is a weakly (l; 1)-central relation. Therefore (a1 , a2 , ..., at+1 ) ∈ γt+1 and γt+1 = El × Ekt is proven, i.e., (17.20) holds. Analogous to the just carried out considerations or to the proof of Lemma 17.5.12, one can show γh = El × Ekh−1 . From that and from (17.20), it follows that a relation of Ck is -derivable. Consequently, P olk × El is not maximal in P olk El . Case 3: r∗ ≥ 2. We consider the (proper subclass) A := P olk r∗ of P olk El , where P olk ×El ⊆ A holds, since r∗ is -derivable. Next we show that P olk × El = A (and with that, our assertion) through the construction of a function f ∈ A, which does not preserve. For this purpose, let T be a matrix, which is a matrix representation of the relation \Elh . Then, the |T |-ary function f defined by f (T ) = α for certain α ∈ Ekh \ and |T | f (x) = 0 for the remaining tuples x ∈ Ek preserves r∗ , but does not preserve . Lemma 17.6.5 Let ∈ Uk . Then the class P olk × El is P olk El -maximal if and only if ∈ Uk;El . Proof. Let [a] := {x ∈ Ek | (a, x) ∈ }. If ∈Uk;El , then we have either := ∩ El2 ∈ {ι2l , El2 } (and therefore ∈ Ul ) or a∈El [a] ∈ {El , Ek }. In the first case a relation of Ul ⊆ Rmax (Pl ) is -derivable. In the second case, the -derivable relation El := pr1 (∆(El × )) = {x ∈ Ek | ∃a ∈ El : (a, x) ∈ } belongs to C1k;El . Our assertion results from that and from Lemma 17.3.3.
552
17 Maximal Classes of P olk El for 2 ≤ l < k
Lemma 17.6.6 Let ∈ Ck . Then, P olk × El is P olk El -maximal if and only if ∈ C1l ∪ Ck;El . Proof. If is a unary relation and ∈ C1l ∪C1k;El , then the -derivable relation ∩ El belongs to C1l ∪ C1k;El . Therefore, our assertion for unary relation follows from Lemmas 17.3.1 and 17.3.2. Let now ∈ Chk with 2 ≤ h ≤ k − 1 and let P olk × El be P olk El -maximal, where it is not possible to describe the class P olk × El with the aid of a relation of Rl \Dl . Because of Lemmas 17.3.5, and 17.3.6–17.3.8 it is sufficient proof to show that ∈ Ck;El is valid. Obviously, ∩ El2 ∈ {ι2l , El2 } if h = 2 and
Elh ⊆ if h ≥ 3
result from our assumptions about the relation . Then the following cases are possible: Case 1: h = 2 and ∩ El2 = ι2l . Then every central element of belongs to Ek \El . We form 1 := ∩ (El × Ek ). This relation has the following properties: 1 ∩ El2 = ι2l , pr0 1 = El , 1 ⊂ El × Ek , and ∃c ∈ Ek \El : El × {c} ⊆ 1 {c} ∪ El ⊆ pr1 1 . If pr1 1 = Ek , then one can derive a relation of C1k;El from 1 and therefore from . Consequently, the -derivable relation 1 belongs to Zk;El . If there are a, c ∈ Ek \El and b ∈ El with {(a, b), (b, c)} ⊆ and (a, c) ∈ , then the binary function f defined by ⎧ (x, y) = (a, b), ⎨ a if (x, y) = (b, c), f (x, y) := c if ⎩ b otherwise, preserves 1 , but does not belong to P olk ×El . Since, by assumption, P olk × El is P olk El -maximal, ∀a, c ∈ Ek ∀b ∈ El : {(a, b), (b, c)} ⊆ =⇒ (a, c) ∈ results. Hence ∈ ZC2k;El and our lemma follows from Lemmas 17.3.5 and 17.3.6. Case 2: h ≥ 2 and Elh ⊆ . Case 2.1: has a central element c which belongs to El . For the -derivable relation := ∩ (El × Ekh−1 ) the following two cases are possible: Case 2.1.1: = El × Ekh−1 . Then, ∈ Invk P olk El and it holds
17.6 Classes Describable by Relations of Rmax (Pl ) ∪ Rmax (Pk )
553
P olk × El ⊂ P olk ⊂ P olk El , since one can easily check that the h-ary function f with ⎛ ⎞ ⎛ ⎞ c l l ... l a1 ⎜ l c l ... l ⎟ ⎜ a2 ⎟ ⎟ ⎜ ⎟ f⎜ ⎝ . . . . . . . . . . ⎠ = ⎝ ... ⎠ ∈ l l l ... c ah and
f (x) = c for the remaining tuples x of Ekh
preserves the relation , however f does not preserve the relation . Case 2.1.2: = El × Ekh−1 . In this case, every element of El is a central element of and belongs to Ck;El . Case 2.2: Every central element of belongs to Ek \El . If 1 = El2 × Ekh−2 then the -derivable relation 1 := ∩ (El2 × Ekh−2 ) is not an invariant of P olk El and P olk × El ⊂ P olk 1 ⊂ P olk El , holds, since the h-ary function f with ⎛ ⎛ ⎞ ⎞ c 0 0 ... 0 a1 ⎜ l c 0 ... 0 ⎟ ⎜ a2 ⎟ ⎜ ⎟ ⎟ f⎜ ⎝ . . . . . . . . . . . ⎠ := ⎝ ... ⎠ ∈ l 0 0 ... c ah (c is a central element von ) f (x) := 0 for x ∈ Elh and f (x) := c for the remaining tuples x belongs to P olk 1 \P olk . Therefore, we can assume that El2 × Ekh−2 ⊆ or {(a1 , ..., ah ) ∈ Ekh | ∃i = j : {ai , aj } ⊆ El } ⊆ .
(17.21)
We consider the relation h := {(a0 , ..., ah−1 ) | ∃u ∈ El : ∀i ∈ Eh : (a0 , ..., ai−1 , u, ai+1 , ..., ah−1 ) ∈ }, which is totally symmetric. W.l.o.g. we can assume that for arbitrary a := (a1 , a3 , ..., ah ) ∈ Ekh−1 there is a ua ∈ El with (ua , a1 , a3 , ..., ah ) ∈ . Namely, if this is not valid, we have that the -derivable relation := pr1,...,h−1 ((El × Ekh−1 ) ∩ ) ; i.e., El is the set of all central elements of . belongs to Ch−1 k Because of symmetry of we have in addition (a1 , ua , a3 , ..., ah ) ∈ . Then,
554
17 Maximal Classes of P olk El for 2 ≤ l < k
with the total reflexivity of , (a1 , a1 , a3 , ..., ah ) ∈ h holds. Thus h is totally reflexive. Next we show that each element u ∈ El is a central element of h : Let (α, a2 , ..., ah ) ∈ El × Ekh−1 be arbitrary. Then, as already shown, there is a u ∈ El with (u, a2 , ..., ah ) ∈ . In addition, because of (17.21), we have (α, a2 , ..., ai−1 , u, ai+1 , ..., ah ) ∈ for each i ∈ {2, ..., h}. By definition of h , this implies (α, a2 , ..., ah ) ∈ h . Therefore, h is either a central relation with central elements of El or h = Ekh holds. Because of Lemma 17.6.2, we must continue to examine the case h = Ekh . We form the relation t := {(a1 , ..., at ) | ∃u ∈ El : ∀{i1 , ..., ih−1 } ⊆ {1, ..., t} : (u, ai1 , ..., aih−1 ) ∈ } (h + 1 ≤ t ≤ k). Then, t−1 = Ekt−1 implies ιtk ⊆ t (h + 1 ≤ t ≤ k). Therefore, we have either t = Ekt or t ∈ Invk P olk El . Since does not have any central elements of El , there is a tuple (α1 , α2 , ..., αh ) ∈ (El × Ekh−1 )\. Then the h-ary function g with ⎞ ⎛ ⎞ ⎛ c 0 0 ... 0 α1 ⎜ l c 0 ... 0 ⎟ ⎜ α2 ⎟ ⎟ ⎟ ⎜ g⎜ ⎝ . . . . . . . . . . . ⎠ := ⎝ ... ⎠ ∈ αh l 0 0 ... c (c is a central element of ) g(x) := α1 otherwise, does not preserve . However, g preserves the relation t for t ≥ h + 1. Thus P olk × El is P olk El -maximal only if t = Ekt holds for all t ∈ {h, ..., k}. It results, however, from k = Ekk that has a certain central element of El , which we had excluded in Case 2.2. Therefore, this case cannot occur. A direct conclusion from Lemmas 17.6.2–17.6.6 is Theorem 17.6.1, whereby the theorems of Section 17.2 are also proven.
18 Further Submaximal Classes of Pk
As already indicated in Chapter 14, there are few results about submaximal classes for arbitrary k. Supplementary to Chapters 16 and 17, all submaximal classes of a maximal class of the type S are described in this chapter. It is then shown how one can prove the special case k ∈ P of this general description. The rest of this chapter deals with submaximal classes of Pk which lie below a maximal class of the type U. In Section 18.2, one can find some maximal classes of P olk , where ∈ Uk is arbitrary. Then, in Section 18.3, the list from Section 18.2 is completed to the list of all maximal classes of P olk for 2 = Ek−1 ∪ {(k − 1, k − 1)}.
18.1 The Maximal Classes of P olks for s ∈ Sk In this section, p always denotes a prime number. Further, let k := p · l with l ∈ N. Denote s a fixed point free permutation on the set Ek , whose cycles have the same length p. Furthermore, let s := {(x, s(x)) | x ∈ Ek }. By Chapter 5
S := P olk s
is a maximal class of type S. For a description of the maximal classes of S, we need the following concepts and definitions. Let θs := {(x, y) ∈ Ek2 | ∃i ∈ {0, 1, ..., p − 1} : y = si (x)}. It is easy to see that θs is an equivalence relation on Ek . An h-ary relation γ ∈ Rk is called θs -closed, if ∀(x1 , ..., xh ) ∈ γ ∀(y1 , ..., yh ) ∈ Rkh : (∀i ∈ {1, ..., h} : (xi , yi ) ∈ θs ) =⇒ (y1 , ..., yh ) ∈ γ.
556
18 Further Submaximal Classes of Pk
Obviously, a θs -closed relation ⊆ Ekh is the homomorphic inverse image of an h-ary relation on the factor set (quotient set) (Ek )/θs in respect to the mapping Ek −→ (Ek )/θs , x → x/θs . It is easy to check that the following statements are valid: – An equivalence relation is θs -closed if and only if θs ⊆ . – A central relation is θs -closed if and only if it is the homomorphic inverse image of a central relation defined on (Ek )/θs . – An h-regular relation , which is defined as in Section 5.2.1 1 , is θs -closed if and only if θs ⊆ ϑ0 ∩ ϑ1 ∩ ... ∩ ϑm−1 . An equivalence relation ε on Ek is called transversal to s, if s ∈ P olk ε and ε ∩ θs = ι2k ; i.e., the permutation s maps each equivalence class (block) of ε onto another equivalence class of ε. / µ whenever A unary relation µ on Ek is called transversal to s, if si (x) ∈ i ∈ {1, ..., p − 1} and x ∈ Ek . Let q, r be prime numbers and let n be the least positive integer with q n = 1 (mod r). Moreover, denote GF (q n ) a field with the order q n .2 Let G(q, r) be the set of all mappings of the form GF (q n ) −→ GF (q n ), x → a · x + b with a, b ∈ GF (q n ) and ar = 1. It is easy to see that the algebra G(q, r) := (G(q, r); ) is a group. P. P. Palfy proved the following fact (see [Ros-S 85]): Lemma 18.1.1 (without proof ) A finite group G has a maximal subgroup of order p (p prime) if and only if G is isomorphic to one of the groups listed below: (1) an Abelean group of order p · q, where q ∈ P; (2) G(p, q), where q ∈ P and p = 1 (mod q); (3) G(p, q), where q ∈ P \ {p}. Now we define permutation groups with the aid of groups of Lemma 18.1.1. For a group G := (G; ◦) whose order divides k = |G|·r, we consider a partition of Ek into |G|-element blocks A1 , ..., Ar and select arbitrary bijections ϕi : Ai −→ G, 1 2
See also Lemma 5.2.6.3. As generally known, there is (up to isomorphism) exactly one finite field of order qn .
18.1 The Maximal Classes of P olk s for s ∈ Sk
557
1 ≤ i ≤ r. Then, with the help of the mappings ϕi , for every g ∈ G one can define a permutation πg on Ek as follows: ∀i ∈ {1, ..., r} ∀x ∈ Ai : πg (x) := ϕ−1 (g ◦ (ϕi (x))). It is easy to check that the set of all permutations of the form πg with g ∈ G together with the operation forms a group, which will be called a semiregular representation of the group G. ´ Szendrei. The following theorem was found by I. G. Rosenberg and A. Theorem 18.1.2 (Rosenberg-Szendrei Theorem; [Ros-S 85]; without proof ) The following list describes all maximal classes of S := P olk s : (1) P olk {(x, π(x)) | π ∈ G}, where G is a semiregular representation of a group, which belongs to the ones described in Lemma 18.1.1, (1)–(3) and for which s ∈ G is valid; (2) S ∩ P olk λG , where λG ∈ Lk , G := (Ek , ⊕) is an elementary Abelean p-group (see Section 5.4) and there exists an element c ∈ Ek with s(x) = x ⊕ c; (3) S ∩ P olk ε, where ε ∈ Uk is either θs -closed or transversal to s. (4) S ∩ P olk γ, where γ ∈ Ck and γ is either θs -closed or a nonempty unary relation transversal to s; (5) S ∩ P olk , where ∈ Bk and is θs -closed. There are also certain k for which the description of the maximal classes of S is simple, as the following theorem shows: Theorem 18.1.3 ([Sze 84], [Lau 84b]) Let k = p ∈ P and s ∈ Sp . Then S := P olp s has exactly two maximal classes. One maximal class has the type (2) and the other maximal has the type (4) from Theorem 18.1.2. Choosing s(x) := x + 1 (mod p), one can describe these maximal classes as follows: S ∩ P olp {0} and S ∩ P olp λ with λ := {(a, b, c, d) ∈ Ek4 | a + b = c + d (mod p)}. The above theorem is a special case of the following theorem: Theorem 18.1.4 ([Lau 84b]) Let k ∈ N, s(x) := x + 1 (mod k), S := P olk {(x, s(x)) | x ∈ Ek } 3 and let Tk be the set of all divisors ∈ N of k. Then the following list gives all maximal classes of S: 3
S is a maximal clone of Pk iff k ∈ P. For k ∈ P the set S is a subclone of a certain clone of the type U.
558
18 Further Submaximal Classes of Pk
(1) S ∩ P olk γr , where r ∈ Tk \ {1} and γr := {x ∈ Ek | r divides x}; (2) S ∩ P olk t , if k ∈ P, t ∈ Tk \ {1, k} and t := {(x, y) ∈ Ek | r divides (x − y)}; (3) S ∩ Lk , if k ∈ P and Lk := P olk {(a, b, c, d) ∈ Ek4 | a + b = c + d (mod k)} = n n i=1 ai · xi (mod k)}. n≥1 {f ∈ Pk | ∃a0 , ..., an ∈ Ek : f (x) = a0 + Proof. We prove the above theorem with the aid of Theorem 6.1 and Theorem 8.3.2. Let α be the mapping defined in Theorem 8.3.2. First we prove that the classes described in (1)–(3) are S-maximal. For this purpose, let r ∈ Tk \{1}, t ∈ Tk \{1, k} and A ∈ {P olk γr , P olk t , Lk } be arbitrary. By Chapter 5, the classes P olk γr , P olk t and Lk are maximal in Pk . Consequently, because of Theorem 8.3.2, (a), we have to show that α(S ∩ A) = A holds. Obviously, because of c0 ∈ A, we have α(S ∩ A) ⊆ A. For the proof of A ⊆ α(S ∩ A), we show that every function f n ∈ S with α(f ) ∈ A belongs to A. We distinguish three cases: Case 1: A = P olk γr . Let a1 , ..., an ∈ γr and f n ∈ S with α(f ) ∈ P olk γr be arbitrary. By definition of γr , bi := ai − a1 (mod k) is an element of γr for every i ∈ {1, ..., n}. Thus, because of α(f ) ∈ P olk γr , we have b := f (0, b2 , ..., bn ) ∈ γr and therefore b + a1 (mod k) = f (a1 , ..., an ) ∈ γr . Consequently, f preserves the relation γr , and α(S ∩ P olk γr ) = P olk γr is valid. Case 2: A = P olk t . Let (a1 , b1 ), ..., (an , bn ) ∈ t and f n ∈ S with α(f ) ∈ P olk t be arbitrary. Set ci := ai − a1 (mod k) and di := bi − b1 (mod k) for i = 1, ..., n. Then (ci , di ) ∈ t . Further, because of α(f ) ∈ P olk t , we have u 0 c2 ... cn ∈ t . := f 0 d2 ... dn v Since f ∈ S,
f
a1 a2 ... an b1 b2 ... bn
=
u + a1 (mod k) v + b1 (mod k)
∈ t
results. Consequently, f preserves the relation t and α(S ∩ P olk t ) = P olk t holds. Case 3: A = Lk . It is easy to check that S ∩ Lk = n≥1 {f n ∈ Pk | ∃a0 , ..., an ∈ Ek : f (x) = a0 + n i=1 ai · xi (mod k) ∧ a1 + ... + an = 1 (mod k)}. This implies α(S ∩ Lk ) = Lk . Now we come to the completeness proof. For this purpose, we choose an arbitrary
18.1 The Maximal Classes of P olk s for s ∈ Sk
559
subset M of S with M ⊆ A for every class A defined in (1)–(3). Our theorem is proven if we can show that [M ] = S holds. S 1 = {s, s2 , ..., sk−1 = e11 } ⊆ [M ] follows from the following considerations: Because of M ⊆ S ∩ P olk γk , there is a certain function f n ∈ M with a := f (0, 0, ..., 0) = 0. Consequently, ∆n−1 f = sa belongs to [M ]. If a and k are relatively prime, then [sa ]1 = S 1 . If a and k are not relatively prime, there is a t ∈ Tk \ {1} with [sa ]1 = {sx | x ∈ γt }. Because of M ⊆ S ∩ P olk γt , a certain function gtm with b := gt (a1 , ..., am ) ∈ γt for certain a1 , ..., am ∈ γt belongs to M . Consequently, we have gt (sa1 , ..., sam ) = sb ∈ [M ]. Further, there exists a t ∈ Tk \ {t} with [sa , sb ]1 = {sx | x ∈ γt }. If t = 1, then S 1 ⊆ [M ]. If t = 1, there is a function gt ∈ [M ], which does not preserve γt . Analogous to the above, one can form a function sc ∈ S 1 \ [sa , sb ] as a superposition over {gt , sa , sb }, and two cases are possible. The iteration of the construction above shows S 1 ⊆ [M ]. Because of Theorem 8.3.2, [M ] = S is proven if we can show that α([M ]) = Pk holds. By Theorem 6.1, α([M ]) = Pk is proven if one can show that for every relation ∈ Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk a function f ∈ [M ] that does not preserve the relation exists. Since α(sa ) = a and sa ∈ [M ] for a ∈ Ek , the constants 0, 1, ..., k − 1 belong to α([M ]). Further, [M ] ⊆ α([M ]) by Theorem 8.3.2, (b). Because of {a, sa | a ∈ Ek } ⊆ α([M ]) we have ∀ ∈ C1k ∪ Sk ∪ Mk : α([M ]) ⊆ P olk .
(18.1)
Let ∈ Chk with 2 ≤ h ≤ k−1, let c be a central element of and (a1 , ..., ah ) ∈ Ekh \. Then the function sa1 −c ∈ [M ] does not preserve because of ⎞ ⎛ ⎛ ⎞ a1 c ⎜ a2 − a1 + c (mod k) ⎟ ⎜ a2 ⎟ ⎟ ⎜ ⎜ ⎟ sa1 −c ⎜ ⎟ = ⎜ . ⎟. .. . ⎝ ⎠ ⎝ . ⎠ . ah ah − a1 + c (mod k) Consequently, we have ∀ ∈
k−1
Chk : α([M ]) ⊆ P olk .
(18.2)
h=2
Next we determine all such relations ∈ Uk that are preserved from the permutation s. In the following, let be an arbitrary equivalence relation on Ek and U := {x ∈ Ek | (0, x) ∈ }. Suppose, s ∈ P olk . Then because of (sk−a (a), sk−a (b)) = (0, b − a) and (sa (0), sa (b − a)) = (a, b), we have ∀(a, b) ∈ Ek2 : (a, b) ∈ ⇐⇒ (0, b − a) ∈ ⇐⇒ b − a ∈ U.
(18.3)
With the help of (18.3) and with the properties of equivalence relations, one can easily prove that U is a subgroup of the cyclic group (Ek ; + (mod k)). As is generally known, every subgroup of a cyclic group with k elements can be described with the aid of a divider of k. Hence, there exists a t with t ∈ Tk and U = {x ∈ Ek | t|x}. By (18.3), this implies = t . Consequently, if k ∈ P, s preserves only trivial equivalence relations and, if k ∈ P, s preserves only equivalence relations, defined in (2). Therefore, by our assumptions of M , we have
560
18 Further Submaximal Classes of Pk ∀ ∈ Uk : α([M ]) ⊆ P olk .
(18.4)
Because of |Im(f )| = k for all f ∈ S, S 1 = L1p and M ⊆ S ∩ Lp for p ∈ P and, if k ∈ P, S 1 = (P olk t )1 and M ⊆ S ∩ P olk t for t ∈ Tk \ {1, k} α([M ]) ⊆ P olk ιkk
(18.5)
is obviously valid. Next, let ∈ Bhk be arbitrary with 3 ≤ h ≤ k − 1. Then by definition there is a surjective mapping q : Ek −→ Ehm with m ≥ 1 and (a1 , ..., ah ) ∈ ⇐⇒ (q(a1 ), ..., q(ah )) ∈ ξm , where ξm is an h-ary elementary relation on Ehm (see Chapter 5). If q is a bijective mapping, then with the aid of Theorem 5.2.6.1, one can prove that s does not preserve the relation . If q is not bijective, then the mapping equivalence σ := {(x, y) ∈ Ek2 | q(x) = q(y)} belongs to Uk . We have shown that a function fσn , which does not preserve the relation σ, belongs to α([M ]) ∩ S. Therefore, there are tuples (a1 , b1 ), ..., (an , bn ) ∈ σ with (c, d) := (fσ (a1 , ..., an ), fσ (b1 , ..., bn )) ∈ σ. Because of ιhh ∩ Ehhm ⊆ ξm , we have {(ai , bi , x3 , ..., xh ) | x3 , ..., xh ∈ Ek } ⊆ for all i = 1, ..., n. The definition of and the choice of the elements c and d imply the existence of certain u3 , ..., uh ∈ Ek with (c, d, u3 , ..., uh ) ∈ . Im(fσ ) = Ek holds because of fσ ∈ S. Consequently, there exist certain (ai , bi , ci3 , ..., cin ) ∈ , i = 1, ..., n, with ⎛ ⎞ ⎛ ⎞ c a 1 a2 . . . a n ⎜ b1 b2 . . . b n ⎟ ⎜ d ⎟ ⎜ ⎟ ⎜ ⎟ ⎟ ⎜ ⎟ fσ ⎜ ⎜ c13 c23 . . . cn3 ⎟ = ⎜ u3 ⎟ . ⎝ ................ ⎠ ⎝ ... ⎠ c1h c2h . . . cnh uh Hence, fσ does not preserve the relation ∈ Bhk and ∀ ∈
k−1
Bhk : α([M ]) ⊆ P olk
(18.6)
h=3
is valid. It still remains to be proven that ∀λ ∈ Lk : α([M ]) ⊆ P olk λ.
(18.7)
For this purpose let λ ∈ Lk . Then there exist p ∈ P, m ∈ N with k = pm and an elementary Abelean p-group (Ek ; ⊕) with the property λ := {(a, b, c, d) ∈ Ek4 | a ⊕ b = c ⊕ d}. W.l.o.g.4 let 0 be the neutral element of the group (Ek ; ⊕). If k ∈ P, then either S 1 ⊆ P olk λ or λ = {(a, b, c, d) ∈ Ek4 | a + b = c + d (mod p)}. If k ∈ P, (18.6) results from that and then (with the aid of (18.1), (18.2), (18.4)–(18.6) and Theorems 8.3.2 and 6.1) our theorem. Let k ∈ P in the following. 4
See Section 5.2.4
18.2 Some Maximal Classes of a Maximal Class of Type U
561
To prove (18.7), we show first that there is a relation γ ∈ Uk ∪ Mk ∪ Ck ∪ Bk with S ∩ P olk λ ⊆ S ∩ P olk γ. It is easy to check that the following three relations are invariants of S ∩ P olk λ: λ1 := {(a1 , ..., ap ) ∈ Ekp | a1 ⊕ a2 ⊕ ... ⊕ ap = 0}, λ2 := {(a1 , ..., ap , b1 , ..., bp ) ∈ Ek2·p | a1 ⊕ a2 ⊕ ... ⊕ ap = b1 ⊕ b2 ⊕ ... ⊕ bp } and, where + denotes the addition modulo k, := {(i, i + 1, i + 2, ..., i + p − 1) | i ∈ Ek }. For i ∈ Ek we set: ti := (i ⊕ (i + 1) ⊕ (i + 2) ⊕ ... ⊕ (i + p − 1), where + is the addition modulo k. Because of k = p the equations t0 = t1 = ... = tk−1 are not possible. If there is a j with tj = 0 (this is possible only for p = 2), then pr1 ( ∩λ1 ) ∈ C1k . If ti = 0 for all i ∈ Ek , there are certain r, s with tr = ts and r = s, whereby the relation := pr1,p+1 (( × ) ∩ λ2 ) is a binary reflexive non-diagonal relation. A conclusion of Chapter 6 is the fact that a relation γ ∈ Uk ∪ Mk ∪ Ck ∪ Bk is derivable from . Consequently, we obtain from the assumption α([M ]) ⊆ P olk λ a contradiction to the statements (18.1), (18.2), and (18.4)–(18.6). Our assumption was therefore false, and (18.7) is valid. Thus, the set α([M ]) is no subset of an arbitrary maximal class of Pk . Hence, α([M ]) = Pk is valid. This and Theorem 8.3.2 imply [M ] = S.
18.2 Some Maximal Classes of a Maximal Class of Type U Let
be an arbitrary relation of Uk , where Ai (i ∈ Et ) denote the equivalence classes of this relation. In addition, a/ denotes the equivalence class of , which contains a ∈ Ek . One checks the following lemma easily (see Table 18.1):5 5
See also Lemma 1.4.6.
562
18 Further Submaximal Classes of Pk
Lemma 18.2.1 Let Ai (i ∈ Et ) be a partition the set Ek and ai ∈ Ai (i ∈ Et ). Furthermore let y for ∃i ∈ Et : x = ai and y ∈ Ai , x y := x otherwise. Then, an arbitrary function f n ∈ Pk is a superposition over the functions z, gf , fi (i ∈ Et ), defined by z(x, y) := x y, gf (x1 , ..., xn ) := ai ⇐⇒ f (x1 , ..., xn ) ∈ Ai , f (x1 , ..., xn ) for f (x1 , ..., xn ) ∈ Ai , fi (x1 , ..., xn ) := otherwise ai (i ∈ Et ), and a representation of f is given by f (x) = ((...((gf (x) f0 (x)) f1 (x)) ...) ft−1 (x)).
Table 18.1
x f (x) gf (x) fi (x) gf f0 (gf f0 ) f1 .. }= a0 }= ai }= f (x) }= f (x) . }∈ A0 .. }= a1 }= ai }= a1 }= f (x) . }∈ A1 .. }= a2 }= ai }= a2 }= a2 . }∈ A2 .. .. .. .. .. .. . . . . . . .. }= ai }= f (x) }= ai }= ai . }∈ Ai .. .. .. .. .. .. . . . . . . .. }= at−1 . }∈ At−1 }= at−1 }= ai }= at−1 Remark
(18.8) is also valid, if one defines y for ∃i ∈ Et : {x, y} ⊆ Ai , x y := x otherwise
(18.8)
... ... ... ... .. . ... .. . ...
(18.9)
and if gf fulfills the following condition: ∀x ∈ Ekn : (gf (x), f (x)) ∈ .
Let f n ∈ Pk be arbitrary and let (18.8) be a representation of f . Then f ∈ P olk if and only if gf ∈ P ol , since the functions fi (i ∈ Et ) and
18.2 Some Maximal Classes of a Maximal Class of Type U
563
the function z preserve . Obviously, every function of the form gf (∈ P ol ) is unambiguously characterized through its values on {ai | i ∈ Et }n . Consequently, ({gf | f ∈ P ol }; ζ, τ, ∆, ∇, ) is isomorphic to
(Pt ; ζ, τ, ∆, ∇, ).
Let q a unary function of Pk defined by ∀i ∈ Et : q(x) = ai :⇐⇒ x ∈ Ai . Lemma 18.2.2 follows from the above considerations: Lemma 18.2.2 ∀f n ∈ Pk : f ∈ P ol ⇐⇒ ∃ hn ∈ P{a0 ...,at−1 } : gf (x) = h(q(x1 ), ..., q(xn )). 2 Since [Pk2 ] = Pk and [Pk,A ] = Pk,A , the fact
ord P olk = 2 follows from Lemmas 18.2.1 and 18.2.2 (see also proof of Theorem 11.2.2). In analog mode to a corresponding statement for Pk , the following lemma results from that then: Lemma 18.2.3 For every proper subclone T of P olk there is a maximal clone of P olk , which contains T . P olk has only finite many maximal clones. 2 For every maximal class M of P olk , there is a relation ψ ∈ Rkk with M = P olk ψ. W.l.o.g. let and
|A0 | ≥ |A1 | ≥ ... ≥ |At−1 | A0 := {0, 1, ..., l − 1},
l≥2
in the following. For the purpose of defining a homomorphism αϕ : Pk −→ Pt we need the mapping ϕ defined by ϕ : Ek −→ Et , ∀i ∈ Et ∀x ∈ Ai : ϕ(x) := i. Obviously, αϕ : Pk −→ Pt , f → f αϕ ∀x1 , ..., xn ∈ Ek : f αϕ (ϕ(x1 ), ..., ϕ(xn )) := ϕ(f (x1 , ..., xn )) is a homomorphism. Next we describe maximal clones of
564
18 Further Submaximal Classes of Pk
U := P olk which contain all unary functions of U or which have the form P olk ∩ P olk , where P olk is Pk -maximal. Some of these clones can be described in the form P olk βi for certain indices i. Put λ := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ {0, 1}}, ιhi := {(a1 , ..., ah ) ∈ Eih | |{a1 , ..., ah }| ≤ h − 1}, −1 ϕ (λ) if t = 2, β1 := ϕ−1 (ιtt ) if t ≥ 3, λ := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | ∃i : |Ai | = 2 ∧ {a, b} ⊆ Ai }∪ {(x, x, x, x) | ∃j : Aj = {x}}, λ if l = 2, β2 := ι if l ≥ 3. For the purpose of describing a third type of maximal clones of U , we first define the following relation for i1 , ..., ir ∈ N: γi1 ,...,ir := {(x1,1 , x1,2 , ..., x1,i1 , x2,1 , x2,2 , ..., x2,i2 , ..., xr,1 , xr,2 , ..., xr,ir ) ∈ Eki1 +...+ir | ∀j ∈ {1, ..., r} ∃q : {xj,1 , xj,2 , ..., xj,ij } ⊆ Aq }. Then we can define the relations βi1 ,...,ir , as follows: x := (x1,1 , x1,2 , ..., x1,i1 , x2,1 , x2,2 , ..., x2,i2 , ..., xr,1 , xr,2 , ..., xr,ir ) ∈ βi1 ,...,ir :⇐⇒ x ∈ γi1 ,...,ir ∧ (∃s ∈ {i1 , ..., ir } : |{xs,1 , xs,2 , ..., xs,ij }| ≤ ij − 1). For the case |A2 | = ... = |At | = 1 we need the following relations: σr,s := {(x1 , ..., xr , y1 , ..., ys ) ∈ Ekr+s | x1 = ... = xr ∨ (x1 , ..., xr ) ∈ ιrl ∨ ({x1 , ..., xr } = El =⇒ |{x1 , ..., xr , y1 , ..., ys }| ≤ r + s − 1} (2 ≤ r ≤ l, 1 ≤ s ≤ k − l). Lemma 18.2.4 Let ∅ ⊂ σ ⊂ Ek . Then P olk σ ∩ P olk is a maximal clone of U := P olk if and only if the following condition is valid: (∃I ⊂ {0, 1, ..., t − 1} : σ = Ai ) ∨ (∀j ∈ {0, 1, ..., t − 1} : σ ∩ Aj = ∅). i∈I
(18.10)
18.2 Some Maximal Classes of a Maximal Class of Type U
565
Proof. “=⇒”: Let P olk σ ∩ P olk be U -maximal and let σ := {y ∈ Ek | ∃x ∈ Ek : (x, x, y) ∈ σ × }. The following two cases are possible: Case 1: ∅ ⊂ σ ⊂ Ek . In this case, we have U ∩ P olk σ ⊆ U ∩ P olk σ ⊂ U and σ has the form ∃I ⊆ {1, 2, ..., t} : σ =
Ai ,
i∈I
since
a ∈ σ =⇒ (∀b ∈ a/ : b ∈ σ )
holds (a/ := {x ∈ Ek | (a, x) ∈ }). Case 2: σ = Ek . (Such a case occurs, for example, if k = 3, := {(0, 0), (1, 1), (2, 2), (0, 1), (1, 0)} and σ := {0, 2}.) It is easy to check that σ fulfills the condition ∀j ∈ {0, 1, ..., t − 1} : σ ∩ Aj = ∅ in this case. “⇐=”: Let f n ∈ U \P olk σ, where σ has the property (18.10). Then there are a1 , ..., an ∈ σ with f (a1 , ..., an ) = a ∈ Ek \σ. Since the constant cs with s ∈ σ belongs to U ∩ P olk σ, we have ca ∈ [(U ∩ P olk σ) ∪ {f }]. Let now g m ∈ U be arbitrary. We show that g ∈ [(U ∩ P olk σ) ∪ {f }]. For this purpose, we consider a function hm+1 ∈ U with hg (x1 , ..., xm , a) = g g(x1 , ..., xm ). Our assertion is proven, ifwe can show that there is a such function hg in the set U ∩ P olk σ. If σ = i∈I Ai for a certain I ⊂ Et , we set g(x1 , ..., xm ), if xm+1 ∈ a/, hg (x1 , ..., xm+1 ) := s otherwise, where s ∈ σ. Obviously, hg ∈ U ∩ P olk σ. Let σ ∩ Aj = ∅ for all j ∈ Et . Then one must choose hg (a1 , ..., am , am+1 ) ∈ (b/) ∩ σ, if hg (a1 , ..., am , am+1 ) = b was chosen and (ai , ai ) ∈ for every i ∈ {1, ..., m+1} is valid. For the remaining tuples x, one can set e.g. hg (x) = s, where s ∈ σ, so that hg ∈ U ∩ P olk σ. Lemma 18.2.5 (1) Let γ ⊆ Eth and let P olt γ Pt -maximal. Furthermore, let −1 αϕ (γ) := {(a1 , ..., ah ) ∈ Ekh | (αϕ (a1 ), ..., αϕ (ah )) ∈ γ}. −1 Then P olk αϕ (γ) is U -maximal.
566
18 Further Submaximal Classes of Pk
(2) P olk β1 is U -maximal. (3) Let A be a subset of U with U 1 ⊆ A and A ⊆ P olk β1 . Then ∀f ∈ Pt ∃g ∈ [A] : αϕ (g) = f.
(18.11)
−1 Proof. (1): Let f ∈ U \P olk αϕ (γ) be arbitrary. Then we have obvious −1 [αϕ (P olk αϕ (γ) ∪ {f })] = Pt . Consequently, −1 (γ) : αϕ (g) = h. ∀h ∈ Pt ∃g ∈ P olk αϕ
(18.12)
−1 For arbitrary functions q ∈ U it follows from the definition of P olk αϕ (γ): −1 (γ) ⇐⇒ αϕ (q) ∈ P olt γ. q ∈ P olk αϕ
(18.13)
Case 1: {c0 , c1 , ..., ct−1 } ⊂ P olt γ. With the help of (18.13) and the fact that the constant functions c0 , ..., ct−1 of Pt belong to P olt γ, one gets: {} ∪
t−1
−1 Pk,Ai ⊆ P olk αϕ (γ).
(18.14)
i=0 −1 Then (with the help of Lemma 18.2.1), (18.12), and (18.14) imply [P olk αϕ (γ)∪ −1 {f }] = U , i.e., P olk αϕ (γ) is U -maximal. Case 2: γ ⊂ Et . In this case, our assertion follows from Lemma 18.2.4. Case 3: γ ∈ St . Because of (18.12), one can find a unary function o with αϕ (o) = c0 in −1 (γ) ∪ {f })]. Since a unary function p with [αϕ (P olk αϕ
∀x ∈ A0 : p(x) = 0 −1 belongs to P olk αϕ (γ), the constant c0 = p o is a superposition over −1 P olk αϕ (γ) ∪ {f }. Let g ∈ U m be arbitrary. Then there is an (m + 1)-ary function hg with hg (0, x1 , ..., xm ) = g(x1 , ..., xm ) −1 −1 in P olk αϕ (γ), whereby g = hg c0 ∈ [P olk αϕ (γ)∪{f }] holds. Consequently, −1 P olk αϕ (γ) is U -maximal.
(2) is a special case of (1). (3): A conclusion of Rosenberg’s Theorem is [αϕ (A)] = Pt , i.e., (18.11) holds.
18.2 Some Maximal Classes of a Maximal Class of Type U
567
Lemma 18.2.6 For some i ∈ Et let |Ai | ≥ 2. Furthermore, let γ ⊆ Ahi be a relation that describes a maximal clone P olAi γ in PAi , where all constant functions of PAi belong to P olAi γ. Set t−1
γ := γ ∪
Ahj .
j=1, j=i
Then the clone P olk γ is U -maximal. Proof. W.l.o.g. let Ai := Er with r ≥ 2 and γ ∈ Ur ∪ Mr ∪ Lr ∪ Br ∪
r−1
Chr .
h=2
Obviously, P olk γ ⊂ U and {, c0 , c1 , ..., ck−1 } ∪ U0 ∪
t−1
Pk,Aj ⊆ P olk γ .
j=1, j=i
Elements of P olk γ are also all n-ary functions qg with g(x) if x ∈ Ern , qg (x) := 0 otherwise, for arbitrary g ∈ P olr γ. Moreover, all unary functions pd0 ,...,dr−1 defined by pd0 ,...,dr−1 (x) := dj ⇐⇒ x ∈ Aj (j = 0, 1, ..., t − 1) belong to P olk γ for all d0 , d1 , ..., dt−1 ∈ Ai = Er . Let f ∈ U \P olk γ be arbitrary. To prove [{f } ∪ P olk γ ] = U , we have only to show that Pk,r ⊆ [{f } ∪ P olk γ ] is valid because of Lemma 18.2.2 and because of the above considerations. Obviously, there are certain (a1j , a2j , ..., ahj ) ∈ γ for j = 1, ..., m and certain (b1l , b2l , ..., bhl ) ∈ γ \γ for l = 1, ...n with ⎞ ⎛ ⎞ ⎛ α1 a11 a12 ... a1m b11 b12 ... b1n ⎜ a21 a22 ... a2m b21 b22 ... b2n ⎟ ⎜ α2 ⎟ h ⎟ ⎜ ⎟ f⎜ ⎝ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ⎠ = ⎝ ... ⎠ ∈ Er \γ. ah1 ah2 ... ahm bh1 bh2 ... bhn αh By choosing certain m-ary functions f1 ..., fn from the m-ary function f ∈ Pk,r by means of
t−1
j=1, j=i
Pk,Aj one receives
f (x1 , ..., xm ) := qe11 (f (x1 , ..., xm , f1 (x1 , ..., xm ), ...., fn (x1 , ..., xm ))), 1
where
568
18 Further Submaximal Classes of Pk
⎞ ⎛ α1 a11 a12 ... a1m ⎜ ⎟ ⎜ α2 ⎜ a21 a22 ... a2m ⎟ =⎜ f ⎝ . . . . . . . . . . . . . . . . ⎠ ⎝ ... ah1 ah2 ... ahm αh ⎛
⎞ ⎟ ⎟ ∈ Erh \γ ⎠
holds, as a superposition over P olk γ ∪{f }. With the help of the completeness criterion for Pk,r (see Theorem 12.4.3 or the proof of the following lemma) one can easy prove that {f } ∪ {qg | g ∈ Pr } ∪ {pd0 ,...,dt−1 | d0 , ..., dr−1 ∈ Er } is a generating system for Pk,r , whereby Pk,r ⊆ [{f } ∪ P olk γ ] was shown. With that, a generating system for the clone U was proven in {f } ∪ P olk γ . Therefore, P olk γ is U -maximal. Lemma 18.2.7 (1) P olk β2 is U -maximal. (2) Let A be a subset of U with U 1 ⊆ A and A ⊆ P olk β2 . Furthermore, A fulfills the condition (18.11). Then ∀i ∈ {0, 1, ..., t − 1} : Pk,Ai ⊆ [A].
(18.15)
Proof. (1): For proof, we use the completeness criterion for Pk,s from Chapter 12: Let pr : Pk,s −→ Ps be defined by pr(f n ) = g m :⇐⇒ n = m ∧ ∀x ∈ Esn : f (x) = g(x). With the aid of the mapping pr, one can describe the following maximal classes of Pk,s : pr−1 M := {f ∈ Pk,s | pr(f ) ∈ M }, where M is an arbitrary maximal clone of Ps . Furthermore, let ζi,t := {(x, x) | x ∈ Es } ∪ {(i, t)} for all i, t with i < t ≤ k − 1 and s ≤ t. Then, for all A ⊆ Pk,s is valid: [A] = Pk,s ⇐⇒ A is no subset of every set of the form pr−1 M (where M is a maximal clone of Ps ) and A does not preserve every relation of the form ζi,t . 1 (This means that the set Pk,s ∪ {f }, where f ∈ Pk,s and pr(f ) ∈ L for s = 2 s and pr(f ) ∈ P ols ιs for s ≥ 3, is complete in Pk,s .) Obviously, U 1 ⊂ P olk β2 . Let f ∈ U \P olk β2 be arbitrary. Then a function g ∈ Pk,l with pr(g) ∈ L for l = 2 and with pr(g) ∈ P oll ιll for l ≥ 3 is a superposition over U 1 ∪ {f }. Since U 1 ⊆ P olk β2 in addition, we have
Pk,l ⊆ [P olk β2 ∪ {f }]
18.2 Some Maximal Classes of a Maximal Class of Type U
569
because of the completeness criterion, and also ∀i ∈ Et : Pk,Ai ⊆ [P olk β2 ∪ {f }]. It is easy to check that the function defined in the remark on Lemma 18.2.1 preserves the relation β2 . Moreover, we have ∀h ∈ Pt ∃g ∈ P olk β2 : αϕ (g) = h. Consequently, the clone [P olk β2 ∪ {f }] contains a generating system for U , whereby (1) is proven. (2) follows from the proof for (1). Lemma 18.2.8 Let |A1 | = ... = |At−1 | = 1 (i.e., A0 = El is the only equivalence class of that contains at least two elements). Furthermore, let U0 := {f ∈ U | |Im(f ) ∩ El | ≤ 1}, U1,α := {f ∈ U | Im(f ) ⊆ El ∪ {α}}, U1 := α∈Ek \El U1,α . Then (a) ∀f ∈ U \P olk σl,1 : U1 ⊆ [{f } ∪ U 1 ∪ Pk,l ∪ U0 ]; (b) P olk σl,1 is U -maximal. Proof. The definition of σr,s , which one can find before Lemma 18.2.4, implies σl,1 = {(x1 , ..., xl , y) ∈ Ekl+1 | x1 = ... = xl ∨ {x1 , ..., xl+1 } ⊆ El ∨ ({x1 , ..., xl } ∈ ιll } (a): Let f ∈ U \P olk σl,1 be arbitrary and M := {f } ∪ U 1 ∪ Pk,l ∪ U0 . Then, an n-ary function f1 with the property ⎞ ⎛ ⎞ ⎛ 0 0 0 a13 a14 · · · a1n ⎜ 0 1 a23 a24 · · · a2n ⎟ ⎜ 1 ⎟ ⎟ ⎜ ⎟ ⎜ ⎜ 0 2 a33 a34 · · · a3n ⎟ ⎜ 2 ⎟ ⎟, ⎜ ⎜ ⎟ f1 ⎜ ⎟ ⎟=⎜ ⎜ ........................ ⎟ ⎜ ··· ⎟ ⎝ 0 l − 1 al3 al4 · · · aln ⎠ ⎝ l − 1 ⎠ l l 0 b 3 b4 · · · bn where (a1i , a2i , ..., ali ) (i = 3, 4, ..., n) are certain tuples of ιll and b3 , ..., bn are certain elements of Ek , is a superposition over M . The above property of f1 and f1 ∈ U implies that f1 has only values of El on tuples of Eln . Next we consider the function
570
18 Further Submaximal Classes of Pk
f1 := (f1 c0 )|El ∈ Pl , that is, we consider the restriction of f1 (c0 (x1 ), x2 ..., xn ) on (x1 ..., xn ) ∈ Eln . Then the following cases are possible: Case 1: x2 is the only essential variable of f1 . In this case, we have ⎛
0 0 0 0 ··· 0 ⎜0 1 0 0 ··· 0 ⎜ ⎜0 2 0 0 ··· 0 f1 ⎜ ⎜ ..................... ⎜ ⎝ 0 l − 1 0 0 ··· 0 l 0 b 3 b4 · · · bn
⎞ 0 ⎟ ⎜ 1 ⎟ ⎟ ⎟ ⎜ ⎟ ⎜ 2 ⎟ ⎟ ⎟=⎜ ⎟ ⎜ ··· ⎟ , ⎟ ⎟ ⎜ ⎠ ⎝l−1⎠ l ⎞
⎛
and for every α ∈ Ek \El , a certain binary function fα with the property ⎞ ⎞ ⎛ ⎛ 0 0 0 ⎜0 1 ⎟ ⎜ 1 ⎟ ⎟ ⎟ ⎜ ⎜ ⎜0 2 ⎟ ⎜ 2 ⎟ ⎟ ⎜ ⎟ ⎜ fα ⎜ ⎟ ⎟=⎜ ⎜ ....... ⎟ ⎜ ··· ⎟ ⎝0 l−1⎠ ⎝l−1⎠ α l 0 is a superposition over M . Let g be an arbitrary m-ary function of U1,α with α ∈ Ek \El . The m-ary functions g1 ∈ U0 and g2 ∈ Pk,l defined by 0, if g(x) ∈ El , g1 (x) := l otherwise, and
g2 (x) :=
= f (x), if g(x) ∈ El , 0 otherwise,
belong to M , whereby g ∈ [M ] holds because of g(x) = fα (g1 (x), g2 (x)). Consequently, we have U1,α ⊆ [M ] and (since U 1 ⊆ M ) also U1 ⊆ [M ], i.e., our assertion (a) is proven in Case 1. Case 2: x2 and xi for certain i ∈ {3, .., n} are essential variables of f1 . In this case, the Fundamental Lemma of Jablonskij (see Theorem 1.4.4) implies the existence of some ci , di , eji ∈ El (i = 2, ..., n; j = 4, ..., l) with
18.2 Some Maximal Classes of a Maximal Class of Type U
⎛
0 c2 c3 c4 · · · cn ⎜ 0 c2 d3 d4 · · · dn ⎜ ⎜ 0 d2 d3 d4 · · · dn ⎜ f1 ⎜ ⎜ 0 e42 e43 e44 · · · e4n ⎜ ...................... ⎜ ⎝ 0 el2 el3 el4 · · · eln l 0 b3 b4 · · · bn
⎞
⎛ α0 ⎟ ⎟ ⎜ α1 ⎟ ⎜ ⎟ ⎜ α2 ⎟=⎜ ⎟ ⎜ ··· ⎟ ⎜ ⎟ ⎝ αl−1 ⎠ l
571
⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠
and {α0 , ..., αl−1 } = El . First we show that Uα1 ,α2 ,l := {f ∈ U | Im(f ) ⊆ {α1 , α2 , l} } ⊆ [M ]
(18.16)
holds. For this purpose, we use the property ⎞ ⎛ ⎞ ⎛ 0 c2 d3 d4 · · · dn α1 f1 ⎝ 0 d2 d3 d4 · · · dn ⎠ = ⎝ α2 ⎠ . l 0 b 3 b 4 · · · bn l Let h be an arbitrary m-ary function of Uα1 ,α2 ,l . Then the m-ary functions h1 , h2 , ..., hn defined by 0, if h(x) = α1 , h1 (x) := (∈ U0 ), l otherwise ⎧ h(x) = α1 , ⎨ c2 , if h(x) = α2 , (∈ Pk,l ), h2 (x) := d2 , if ⎩ 0 otherwise di , if h(x) ∈ {α1 , α2 } hi (x) := (∈ U0 ), bi otherwise (i = 3, ..., n), belong to [M ], and we have: h(x) = f1 (h1 (x), h2 (x), ..., hn (x)), whereby (18.16) is proven. Since U 1 ⊆ M , (18.16) implies {f ∈ U | Im(f ) ⊆ {a, b, c} } ⊆ [M ]. a,b∈El , c∈Ek \El
Then, analogously to the above and ⎛ 0 c2 c3 c4 ⎜ 0 c2 d3 d4 f1 ⎜ ⎝ 0 d2 d3 d4 l 0 b 3 b4
with the aid of ⎞ ⎛ · · · cn α0 ⎜ α1 · · · dn ⎟ ⎟=⎜ · · · dn ⎠ ⎝ α2 · · · bn l
⎞ ⎟ ⎟, ⎠
572
18 Further Submaximal Classes of Pk
one can show that {f ∈ U | Im(f ) ⊆ {α0 , α1 , α2 , l} } ⊆ [M ] is valid. Consequently, because of U 1 ⊂ M , we have {f ∈ U | Im(f ) ⊆ {β0 , β1 , β2 , γ} } ⊆ [M ]. β0 ,β1 ,β2 ∈El , γ∈Ek \El
Then (a) results by means of induction from what was shown till now. (b): It is easy to see that the binary function z defined by x if x ∈ El , z(x, y) := y otherwise, preserves the relation σl,1 . Moreover, we obviously have: U 1 ∪ Pk,l ∪ U0 ⊆ P olk σl,1 .
(18.17)
Let f ∈ U \P olk σl,1 be arbitrary. Then, because of (a) and (18.17), U1 ⊆ [{f } ∪ P olk σl,1 ] holds. Let q be an arbitrary m-ary function of U . Then, one can form q as a superposition over z and the m-ary functions q1 , q2 defined by q(x), if q(x) ∈ El , q1 (x) := (∈ U1 ), l otherwise and
q2 (x) :=
as follows:
0, if q(x) ∈ El , (∈ U0 ), q(x) otherwise q(x) = z(q1 (x), q2 (x)).
From that and from what was shown till now [{f } ∪ P olk σl,1 ] = U , through which (b) is proven. Theorem 18.2.9 Let k = l + 1. Then U has exactly three maximal clones that have U 1 as a subset. These clones are P olk β1 , P olk β2 , P olk σl,1 .
(18.18)
Proof. The U -maximality of the given clones was proven in Lemmas 18.2.5, 18.2.7, and 18.2.8. Let A be an arbitrary subset of U which has U 1 as a subset and which is no subset of the clones given in (18.18). To prove our theorem, we have to show that [A] = U . Lemmas 18.2.5 and 18.2.7 and U 1 ⊆ U imply U0 ∪ Pk,l ⊆ A. Consequently, with the aid of Lemma 18.2.8, (a), we have that U1 = U is a subset of [A].
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
573
18.3 The Maximal Classes of P olk(Ek2-1 ∪ {(k-1, k-1)}) In this section let k ≥ 3, 2 := Ek−1 ∪ {(k − 1, k − 1)}
and The sets and
U := P olk . U0 := {f ∈ U | k − 1 ∈ Im(f ) ∧ |Im(f )| ≤ 2} Ua,b,k−1 := {f ∈ U | Im(f ) ⊆ {a, b, k − 1} }.
are subsets of U . 18.3.1 Definitions of the U -Maximal Classes For k = 3, the clone U has exactly 13 maximal classes, which were given in Chapter 13, Theorem 13.1.8. In generalization of these classes (for a = 0 and b = 1), we will define six types of classes from which in the following two sections it is shown that they are the only maximal classes of the clone U . Type I (homomorphic inverse images of the maximal classes of P2 ): With the help of the mapping ϕ : Ek −→ E2 , ∀x ∈ Ek−1 : ϕ(x) := 0, ϕ(k − 1) := 1. −1 one can define a homomorphic inverse image αϕ (γ) of a relation γ ⊆ E2h as follows: −1 αϕ (γ) := {(x1 , ..., xh ) ∈ Ekh | (ϕ(x1 ), ϕ(x2 ), ..., ϕ(xh )) ∈ γ}.
In the case that γ describes a maximal class of P2 , we obtain the following maximal classes of U : −1 U ∩ P olk αϕ ({0}), −1 U ∩ P olk αϕ ({1}), 0 1 −1 U ∩ P olk αϕ , 1 0 0 0 1 −1 , P olk αϕ ⎛0 1 1 0 0 1 1 0 ⎜ −1 ⎜ 0 1 1 0 1 P olk αϕ ⎝ 1 0 0 1 1 1 1 0 0 0
1 0 0 1
0 0 0 0
⎞ 1 1⎟ ⎟. 1⎠ 1
574
18 Further Submaximal Classes of Pk
For k = 3, these are the classes with the numbers (2), (1), (8), (9), and (13) of Theorem 13.1.8. Type II (U -maximal classes described by certain unary relations): Let σ be a subset of Ek , which has one of the following two properties: 1) 2)
σ = Ek−1 , {k − 1} ⊆ σ ⊂ Ek .
Then U ∩ P olk σ is maximal in U (see Lemma 18.2.4). For k = 3 there are exactly four maximal clones that are describable in this manner. Two of these classes were already recorded by means of type I. Type III (U -maximal classes that are determined by the maximal h classes of Pk−1 ; first possibility): Let γ ⊆ Ek−1 , 2 ≤ h ≤ k − 1, be an h-ary relation, which describes by means of P olk−1 γ a maximal class of Pk−1 and which contains all constant functions of Pk−1 . Then P olk (γ ∪ {(k − 1, k − 1, ..., k − 1)}) is U -maximal. For k = 3 there are exactly two U -maximal clones of type III: 0 1 2 0 P ol3 , 0 1 2 1 ⎛ ⎞ 0 0 0 1 1 0 1 1 2 ⎜0 0 1 1 0 1 0 1 2⎟ ⎟ P ol3 ⎜ ⎝ 0 1 0 0 1 1 0 1 2 ⎠. 0 1 1 0 0 0 1 1 2 The U -maximality of the classes of type III follows from Lemma 18.2.6. Type IV (U -maximal classes that are determined by the maximal classes of Pk−1 ; second possibility): This type of U -maximal class occurs only for k ≥ 4, since for k = 3 the conditions (a) and (b) mentioned below h , 2 ≤ h ≤ k − 1, an h-ary relation with the cannot be met. Denote γ ⊆ Ek−1 following properties: (a) P olk−1 γ is a maximal class of Pk−1 ; (b) γ is totally reflexive and totally symmetric, i.e., we can assume γ ∈ Uk−1 ∪
k−2 h=2
Moreover, let
Chk−1 ∪
k−1 h=3
Bhk−1 .
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
575
h+1 γ := Ek−1 ∪ {(x, x, ..., x, y) | x, y ∈ Ek }
∪{(x1 , ..., xh , k − 1) | (x1 , ..., xh ) ∈ γ}. Then P olk γ is U -maximal by Lemma 18.3.2.4. Example Let k = 4 and 0 1 2 3 0 3 γ := . 0 1 2 3 3 0 It is well-known that P ol3 γ is a maximal class of P3 and that γ is a reflexive and symmetric relation, whereby the relation ⎛ ⎞ 0 1 2 3 0 3 γ := E33 ∪ {(x, x, y) | x, y ∈ E4 } ∪ ⎝ 0 1 2 3 3 0 ⎠ 3 3 3 3 3 3 describes a maximal class of U . Type V (U -maximal classes that are described by certain binary 2 central relations): Denote τ a binary central relation ⊆ Ek−1 (i.e., a binary reflexive and symmetric relation, which has at least a central element c ∈ Ek−1 2 with {(c, x) | x ∈ Ek−1 } ⊆ τ and which is different from Ek−1 .) If τ fulfills the two following conditions (a) ⊆ τ , (b) ∃c ∈ Ek−1 : c is central element of τ , then U ∩ P olk τ is U -maximal by Lemma 18.3.2.9. Examples For k = 3 there are exactly two maximal classes of this type: 0 1 2 0 1 0 2 U ∩ P ol3 0 1 2 1 0 2 0 0 1 2 1 0 1 2 U ∩ P ol3 . 0 1 2 0 1 2 1 Type VI (Two U -maximal classes that are described by ternary relations): For A ∈ {Ek−1 , {k − 1}} let 2 σA := (Ek−1 × A) ∪ {(x, x, y) | x, y ∈ Ek }.
The class P olk σEk−1 is U -maximal by Lemma 18.3.2.5 and the class P olk σ{k−1} is U -maximal by Lemma 18.3.2.7. Example For k = 3 these classes have the number (10) and (11) in Theorem 13.3.8.
576
18 Further Submaximal Classes of Pk
18.3.2 Proof of the U -Maximality of the Classes Defined in 18.3.1 The U -maximality of a class of the type I, II or III follows from Lemmas 18.2.4–18.2.6. Lemma 18.3.2.1 Let M be a subset of U which has the two following properties: (1) The set {f n ∈ Pk−1 | ∃g n ∈ M ∩ P olk {k − 1} ∩ P olk Ek−1 : n ∀x ∈ Ek−1 : g(x) = f (x)} is complete in Pk−1 . (2) There are two different elements a, b ∈ Ek−1 with Ua,b,k−1 := {f ∈ U | Im(f ) ⊆ {a, b, k − 1}} ⊆ [M ]. Then M is complete in U . Proof. Because of (1) a (k − 1)-ary function p with the property ⎞ ⎞ ⎛ ⎛ 0 b a a ... a a a ⎟ ⎜ ⎜ a b a ... a a a ⎟ ⎟ ⎜ 1 ⎟ ⎜ ⎟ ⎜ 2 ⎟ ⎜ a a b ... a a a ⎟ ⎟ ⎜ ⎜ ⎜ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ⎟ ⎜ ... ⎟ ⎟ ⎜ ⎟ ⎜ =⎜ p⎜ ⎟ a a ... b a a ⎟ ⎟ ⎜k−4⎟ ⎜ a ⎟ ⎜k−3⎟ ⎜ a a a ... a b a ⎟ ⎟ ⎜ ⎜ ⎝ a a a ... a a b ⎠ ⎝k−2⎠ k−1 k − 1 k − 1 k − 1 ... k − 1 k − 1 k − 1 belongs to [M ]. Then one can form an arbitrary n-ary function u ∈ U as a superposition over {p} ∪ Ua,b,k−1 ⊆ [M ] as follows: The n-ary functions u0 , u1 , ..., uk−2 defined by ⎧ if u(x) = i, ⎨b if u(x) ∈ Ek−1 \{i}, ui (x) := a ⎩ k − 1 if u(x) = k − 1 (i = 0, 1, ..., k − 2) belong to Ua,b,k−1 . Then u = p(u0 , u1 , ..., uk−2 ) ∈ [M ], whereby [M ] = U is proven. Therefore, M is complete in U . Lemma 18.3.2.2 Let M be a subset of U , which has the two following properties:
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
577
(1) The set n : g(x) = f (x)} {f n ∈ Pk−1 | ∃g n ∈ M ∩ P olk Ek−1 : ∀x ∈ Ek−1
is complete in Pk−1 . (2) There are two different elements a, b ∈ Ek−1 with Pk,{a,b} := {f ∈ Pk | Im(f ) ⊆ {a, b} } ⊆ [M ]. Then Pk,k−1 ⊆ [M ]. Proof. The proof is similar to the proof of Lemma 18.3.2.1: Because of (1) a (k − 1)-ary function p with the property ⎞ ⎞ ⎛ ⎛ 0 b a a ... a a a ⎜ a b a ... a a a ⎟ ⎜ 1 ⎟ ⎟ ⎟ ⎜ ⎜ ⎜ a a b ... a a a ⎟ ⎜ 2 ⎟ ⎟ ⎟ ⎜ ⎜ ⎟ ⎟ ⎜ p⎜ ⎜ . . . . . . . . . . . . . . . . ⎟ = ⎜ ... ⎟ ⎜ a a a ... b a a ⎟ ⎜ k − 4 ⎟ ⎟ ⎟ ⎜ ⎜ ⎝ a a a ... a b a ⎠ ⎝ k − 3 ⎠ k−2 a a a ... a a b belongs to [M ]. Then one can form an arbitrary n-ary function u ∈ Pk,k−1 as a superposition over {p} ∪ Pk,{a,b} ⊆ [M ], as follows: The n-ary functions u0 , u1 , ..., uk−2 defined by b if u(x) = i, ui (x) := a if u(x) ∈ Ek−1 \{i} (i = 0, 1, ..., k − 2) belong to Pk,{a,b} . Then u = p(u0 , u1 , ..., uk−2 ) ∈ [M ], whereby Pk,k−1 ⊆ [M ] is proven.
2 2 Lemma 18.3.2.3 For each f ∈ U \P olk (ιk−1 k−1 ) and for each (a, b) ∈ Ek−1 \ιk−1 the set {f } ∪ U 1 ∪ Pk,k−1 ∪ Ua,b,k−1
is complete in U .
Proof. Let f ∈ U \P olk (ιk−1 k−1 ) be arbitrary. Then, w.l.o.g. there are certain k (a1i , a2i , ..., aki ) ∈ Ek−1 (i = 1, ..., m) and (b1j , b2j , ..., bk−1,j ) ∈ ιk−1 k−1 (j = 1, ..., n) with ⎞ ⎛ ⎞ ⎛ 0 a11 a12 ... a1m b11 b12 ... b1n ⎜ ⎟ ⎜ a21 a22 ... a2m b21 b22 ... b2n ⎟ ⎜ ⎟ ⎜ 1 ⎟ ⎜ ⎜ ⎟ f ⎜ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ⎟ = ⎜ ... ⎟ ⎟. ⎝ ak−1,1 ak−2,2 ... ak−1,m bk−1,1 bk−1,2 ... bk−1,n ⎠ ⎝ k − 2 ⎠ k−1 ak1 ak2 ... akm k − 1 k − 1 ... k − 1
578
18 Further Submaximal Classes of Pk
By replacing of some variables of f through certain functions of Pk,k−1 one
can form an n-ary function f ∈ U \P olk (ιk−1 k−1 ) with f (k−1, k−1, ..., k−1) = k − 1. Consequently, the set {f } ∪ {g ∈ U 1 | g(k − 1) = k − 1} fulfills the assumption (1) of Lemma 18.3.2.1. Then with the help of Lemma 18.3.2.1, one can prove [{f } ∪ U 1 ∪ Pk,k−1 ∪ Ua,b,k−1 ] = U . k−2 Lemma 18.3.2.4 Let γ ∈ Uk−1 ∪ Bk−1 ∪ k=2 Chk−1 be an h-ary relation. Then P olk γ is U -maximal. Proof. Clearly, P olk γ is a proper subset of U . For each n-ary function g ∈ P olk−1 γ we define an n-ary function fg ∈ Pk by ⎧ n x ∈ Ek−1 , ⎨ g(x) if x = (k − 1, k − 1, ..., k − 1), fg (x) := k − 1 if ⎩ 0 otherwise. It is easy to check that fg belongs to P olk γ . Moreover, we have Pk,k−1 ⊆ P olk γ and there are two different elements a, b ∈ Ek−1 with Ua,b,k−1 ⊆ P olk γ . More precisely: If γ ∈ Uk−1 ∪ C2k−1 one chooses the elements a and b so that (a, b) ∈ γ\ι2k−1 . If γ has an arity h ≥ 3, then one can choose the elements a and b arbitrary. Now let f ∈ U \P olk γ be arbitrary. Then, w.l.o.g. there are certain tuh+1 (i = 1, ..., n) and (b1j , b2j , ..., bhj ) ∈ γ ples (a1i , a2i , ..., ah+1,i ) ∈ Ek−1 (j = 1, ..., m) with ⎛ ⎞ ⎛ ⎞ a1 a11 a12 ... a1n b11 b12 ... b1m ⎜ ⎜ a21 ⎟ a22 ... a2n b21 b22 ... b2m ⎟ ⎜ ⎟ ⎜ a2 ⎟ ⎜ ⎜ ⎟ ⎟ · f⎜ ⎟ = ⎜ ... ⎟ ⎝ ⎝ ah1 ⎠ ah2 ... ahn bh1 bh2 ... bhm ah ⎠ ah+1,1 ah+1,2 ... ah+1,n k − 1 k − 1 ... k − 1 k−1 h and (a1 , ..., ah ) ∈ Ek−1 \γ. By replacing some variables of f through certain functions of Pk,k−1 ⊆ P olk γ one can form a function f ∈ [{f } ∪ P olk γ ], which preserves the relations {k − 1} and Ek−1 but does not preserve the relation γ. Then, the maximality of P olk−1 γ in Pk−1 implies that the set {f } ∪ {fg | g ∈ P olk γ} fulfills the condition (1) of Lemma 18.3.2.1. Since we have already proven that P olk γ fulfills condition (2) of Lemma 18.3.2.1, the set {f } ∪ P olk γ is complete in U . Hence P olk γ is U -maximal.
Lemma 18.3.2.5 Let 3 σEk−1 := Ek−1 ∪ {(a, a, b) | k − 1 ∈ {a, b} ⊆ Ek }.
Then
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
579
(1) For every function f ∈ U \P olk σEk−1 there are two different elements a, b ∈ Ek−1 with Ua,b,k−1 ⊆ [{f } ∪ Pk,k−1 ∪ U0 ]. (2) P olk σEk−1 is U -maximal. Proof. (1): Let
f ∈ U \P olk σEk−1
be arbitrary. W.l.o.g., we can assume that there are certain (a1j , a2j , a3j ) ∈ 3 3 (j = 1, 2, ..., n) and certain (bi , bi , ci ) ∈ Ek3 \Ek−1 (i = 1, 2, ..., m) with Ek−1 the properties ⎞ ⎛ ⎛ ⎞ a a11 ... a1n b1 ... bm f ⎝ a21 ... a2n b1 ... bm ⎠ = ⎝ b ⎠ , a31 ... a3n c1 ... cm k−1 a = b and {a, b} ⊆ Ek−1 . We choose some functions fi ∈ Pk,k−1 and gj ∈ U0 with the properties ⎛ ⎞ ⎛ ⎞ 0 0 a1i fi ⎝ 0 1 ⎠ = ⎝ a2i ⎠ a3i k−1 0 (i = 1, ..., n) and
⎛
⎞ ⎛ ⎞ 0 0 bj gj ⎝ 0 1 ⎠ = ⎝ bj ⎠ cj k−1 0
(j = 1, ..., m). Thus the binary function f with f := f (f1 , f2 , ..., fn , g1 , ..., gm ) belongs to [{f } ∪ Pk,k−1 ∪ U0 ] and it holds that ⎛ ⎞ ⎛ ⎞ 0 0 a f ⎝ 0 1 ⎠ = ⎝ b ⎠ . k−1 0 k−1 Next we show that every function of Ua,b,k−1 := {q ∈ U | Im(q) ⊆ {a, b, k−1}} is a superposition over {f } ∪ U0 ∪ Pk,k−1 : Let q t ∈ Ua,b,k−1 be arbitrary. Then the t-ary function q1 with 0 if q(x) ∈ {a, b}, q1 (x) := k − 1 otherwise, belongs to U0 and the t-ary function q2 with 1 if q(x) = b, q2 (x) := 0 otherwise, belongs to Pk,k−1 . Because of
580
18 Further Submaximal Classes of Pk
q = f (q1 , q2 ) ∈ [{f } ∪ Pk,k−1 ∪ U0 ] we have Ua,b,k−1 ⊆ [{f } ∪ Pk,k−1 ∪ U0 ]. (2): Clearly, U = P olk σEk−1 . Since from σEk−1 the relation is derivable, P olk σEk−1 ⊂ U holds. Let f ∈ U \P olk σEk−1 be arbitrary. Since Pk,k−1 ∪U0 ⊆ P olk σEk−1 , above statement (1) implies that Ua,b,k−1 ⊆ [{f } ∪ P olk σEk−1 ] is valid for two certain elements a, b ∈ Ek−1 , whereby {f } ∪ P olk σEk−1 fulfills the condition (2) of Lemma 18.3.2.1. Obviously, each n-ary function p ∈ U with ∀x ∈ Ekn : p(x) = k − 1 ⇐⇒ x = (k − 1, k − 1, ..., k − 1) is a function of P olk σEk−1 . Consequently, {f } ∪ P olk σEk−1 also fulfills the condition (1) of Lemma 18.3.2.1. Therefore, the U -maximality of P olk σEk−1 follows from Lemma 18.3.2.1. Lemma 18.3.2.6 Denote max ∈ Pk the binary function that is defined with respect to the order 0 < 1 < 2 < ...k − 1 as usual. Then, the set U := {max} ∪ Pk,k−1 ∪ U0 is complete in U . Proof. Obviously, Pk,k−1 ∪ U0 ⊆ U . Since the function max has the property max(x, y) = k − 1 ⇐⇒ k − 1 ∈ {x, y}, max belongs to U . Consequently, U is a subset of U . Let f n ∈ U be arbitrary. Then, the n-ary functions f1 and f2 defined by f (x), if f (x) ∈ Ek−1 , f1 (x) := 0 otherwise, and
f2 (x) :=
0, if f (x) ∈ Ek−1 , k − 1 otherwise,
belong to U . Hence, the U -completeness of U follows from f = max(f1 , f2 ). Lemma 18.3.2.7 Let 2 × {k − 1}) ∪ {(a, a, b) | {a, b} ⊆ Ek }. σ{k−1} := (Ek−1
Then: (1) For every function f ∈ U \P olk σ{k−1} and every set M ⊆ U with [prEk−1 M ] = Pk−1 , where prEk−1 M := {g n ∈ Pk−1 | ∃g1 ∈ M ∩ P olk Ek−1 : n : g(x) = g1 (x) }, ∀x ∈ Ek−1 is valid:
Pk,k−1 ⊆ [{f } ∪ U0 ∪ M ∪ (U 1 ∩ P olk {k − 1})].
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
581
(2) P olk σ{k−1} is maximal in U . Proof. (1): Let
f ∈ U \P olk σ{k−1}
be arbitrary. W.l.o.g. we can assume that there are certain ai , bi ∈ Ek−1 (i = 1, 2, ..., r), cj ∈ Ek (j = 1, 2, ..., s) and dl , el ∈ Ek−1 (l = 1, ..., t) with the property ⎛ ⎞ ⎛ ⎞ a1 ... ar k − 1 ... k − 1 d1 ... dt a f ⎝ b1 ... br k − 1 ... k − 1 d1 ... dt ⎠ = ⎝ b ⎠ , k − 1 ... k − 1 c1 ... cs e1 ... et c where a = b and {a, b, c} ⊆ Ek−1 . Then, because ⎛ a1 ... ar k − 1 ... k − 1 d1 f ⎝ b1 ... br k − 1 ... k − 1 d1 k − 1 ... k − 1 c1 ... cs d1
of f ∈ U , we have ⎞ ⎛ ⎞ ... dt a ... dt ⎠ = ⎝ b ⎠ ... dt c
for a certain c ∈ Ek−1 . W.l.o.g. let c = a. We choose some unary functions fi ∈ U 1 ∩ P olk {k − 1} (i = 0, 1, ..., r) and gj ∈ U0 with the properties 0 if x = a, f0 (x) = 1 if x ∈ Ek−1 \{a}, ⎞ ⎛ ⎞ ⎛ ai 0 fi ⎝ 1 ⎠ = ⎝ bi ⎠ k−1 k−1 (i = 1, ..., r) and
⎛
⎞ ⎛ ⎞ 0 k−1 gj ⎝ 1 ⎠ = ⎝ k − 1 ⎠ k−1 cj
(j = 1, ..., s). Therefore, the unary function f with f := f0 (f (f1 , f2 , ..., fr , g1 , ..., gs , cd1 , ..., cdt )) belongs to [{f } ∪ (U 1 ∩ P olk {k − 1}) ∪ U0 ], where f ∈ Pk,2 (because of f ∈ U and f (k − 1) = k − 1) and ⎛ ⎞ ⎛ ⎞ 0 0 f ⎝ 1 ⎠ = ⎝ 1 ⎠ k−1 1 are valid. Now it is possible to prove that Pk,2 ⊆ [{f } ∪ U0 ∪ M ] holds with
582
18 Further Submaximal Classes of Pk
the help of the following completeness criterion for Pk,2 (see Theorem 12.4.3): A subset T ⊆ Pk,2 is a generating system for Pk,2 if and only if T fulfills the following two conditions: (i) The set pr{0,1} T := {f n ∈ P2 | ∃f1n ∈ T : ∀x ∈ E2n : f (x) = f1 (x)} is a generating system for P2 . (ii) For each a ∈ Ek−1 and each b ∈ Ek \{0, 1} with a < b it is valid: 0 1 a . T ⊆ Pk,2 ∩ P olk 0 1 b Clearly, the set pr{0,1} {f g | g ∈ M } fulfills the above condition (i) because of our assumption prEk−1 M = Pk−1 . For arbitrary a ∈ Ek−1 , the unary function qa with ⎧ if x = a, ⎨0 x = k − 1, qa (x) := k − 1 if ⎩ 1 otherwise, belongs to U 1 ∩ P olk {k − 1}. Then, for arbitrary a ∈ Ek−1 and b ∈ Ek \{0, 1} with a < b we have a 0 (f qa ) = , b 1 whereby {f } ∪ (U 1 ∩ P olk {k − 1}) also fulfills the conditions of (ii). Thus by the completeness theorem for Pk,2 , Pk,2 ⊆ [{f } ∪ U0 ∪ M ∪ (U 1 ∩ P olk {k − 1})] is valid. This and Lemma 18.3.2.2 imply our assertion (1). (2): Clearly, P olk σ{k−1} = U . Further, it is easy to prove that is derivable from σ{k−1} . Hence P olk σ{k−1} ⊂ U . Let f ∈ U \P olk σ{k−1} be arbitrary. Obviously, U0 ⊆ P olk σ{k−1} and each n-ary function p ∈ U (n ∈ N) with the property n ∀x ∈ Ekn : p(x) = k − 1 ⇐⇒ x ∈ Ekn \Ek−1
belongs to P olk σ{k−1} . In particular, max ∈ P olk σ{k−1} . Then [{f } ∪ P olk σ{k−1} ] = U follows from statement (1) and Lemma 18.3.2.6. Lemma 18.3.2.8 For certain t ∈ {1, 2, ..., k − 2} we set C := {t, t + 1, ..., k − 2}. Furthermore let 2 α := {(x, x) | x ∈ Ek } ∪ Ek−1 ∪ {(x, y), (y, x) | x ∈ Ek , y ∈ C},
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
583
i.e., α is a binary central relation, where C is the set of all central elements of α and α has the property Ek2 \α = {(u, k − 1), (k − 1, u) | u ∈ Et }. Then max ∈ U ∩ P olk α. Proof. Because of Lemma 18.3.2.6, we have max ∈ U . Suppose max does not preserve the relation α. Then there are certain (a, b), (c, d) ∈ α and a u ∈ Et with a c u max = . b d k−1 W.l.o.g. we can assume that a = u and d = k − 1, i.e., c ≤ u and b ≤ k − 1. Then, because of u ∈ Et we have however c ∈ Et , contrary to (c, d) = (c, k − 1) ∈ α. Lemma 18.3.2.9 Let α ∈ C2k be a binary central relation with ⊆ α and the property that at least an element of Ek−1 is a central element of α. Then U ∩ P olk α is U -maximal. Proof. Because of ⊆ α and ∈ Dk , element k − 1 cannot be a central element of α. Therefore, w.l.o.g. we can assume that the set C := {t, t + 1, ..., k − 2} for a certain t ∈ {1, 2, ..., k − 2} is the set of all central elements of α, whereby we have 2 ∪ {(x, y), (y, x) | x ∈ Ek , y ∈ C} α = {(x, x) | x ∈ Ek } ∪ Ek−1
and
Ek2 \α = {(u, k − 1), (k − 1, u) | u ∈ Et }.
Notice that, with that, k − 2 is a central element of α. Let f n ∈ U \P olk α be arbitrary. Then there are certain (a1 , b1 ), ..., (an , bn ) ∈ α with a1 a2 ... an a f = b1 b2 ... bn k−1 and (a, k − 1) ∈ α. Since the functions tr,s (i = 1, ..., n) with (r, s) ∈ α and qa (a ∈ Ek−1 ) with r f¨ u x ∈ Ek−1 , tr,s (x) := s if x = k − 1, and
⎧ f¨ u x = a, ⎨b qa,b (x) := k − 2 if x ∈ Ek−1 \{a}, ⎩ k − 1 if x = k − 1,
for arbitrary b ∈ Ek−1 belong to U ∩ P olk α, the functions
584
18 Further Submaximal Classes of Pk
tb,k−1 = qa,b (f (ta1 ,b1 , ..., tan ,bn )) and
tk−1,b = qa,b (f (tb1 ,a1 , ..., tbn ,an ))
are superpositions over {f } ∪ (U ∩ P olk α) for all b ∈ Ek−1 . Consequently, U0 ⊆ [{f } ∪ (U ∩ P olk α)]. Moreover, max ∈ U ∩ P olk α (see Lemma 18.3.2.8) and (because of ⊆ α) Pk,k−1 ⊆ P olk α. Then the U -completeness of {f } ∪ (U ∩ P olk α) follows from Lemma 18.3.2.6. 18.3.3 Proof of the Completeness Criterion for U Let M be an arbitrary subset of U , which is not contained in any class from type I–VI. We show that U = [M ] results from this assumption when we prove the generating system from Lemma 18.3.2.3 in [M ]. Since M is no subset of a class of type I, it results from the completeness theorem for P2 that the following is valid: ∀g m ∈ P2 ∃g1m ∈ [M ] : αϕ (g1 ) = g.
(18.19)
In particular, (18.19) implies: ck−1 ∈ [M ].
(18.20)
With the aid of the functions of M , which do not belong to the clones of type II, one sees from (18.20) that the constant functions of Pk belong to [M ]: c0 , c1 , ..., ck−1 ∈ [M ].
(18.21)
Because of (18.19), there is a unary function in [M ] that is an inverse image of the function g ∈ [M ] with x g(x) 0 1 . 1 0 Let g be this function with x 0 1 2 . . k−2 k−1 where a is a certain element of Ek−1 . The relation
g (x) k−1 k−1 k−1 , . . k−1 a
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
585
2 Ek−1 ∪ {(k − 1, k − 1), (a, k − 1), (k − 1, a)}
describes a certain class of the type V. Thus there is a function q ∈ M that does not preserve this relation. W.l.o.g. we can assume b a1 a2 ... an k − 1 a k − 1 = , q k−1 b1 b2 ... bn k − 1 k − 1 a where a1 , ..., an , b1 , ..., bn are certain elements of Ek−1 . Because of q ∈ U , we have also b a1 a2 ... an k − 1 a k − 1 = . q k−1 a1 a2 ... an k − 1 k − 1 a Consequently, the functions tb,k−1 (x) := q(ca1 (x), ..., ca2 (x), ck−1 (x), g (g (x)), g (x)) and
tk−1,b (x) := q(ca1 (x), ..., ca2 (x), ck−1 (x), g (x), g (g (x)))
belong to [M ], where
x tb,k−1 (x) 0 b 1 b 2 b . . . . k−2 b k−1 k−1
tk−1,b k−1 k−1 k−1 . . . k−1 b
With the aid of further functions of M , which do not belong to the clones of type V, in analog mode, we see that all functions of the form α if x ∈ Ek−1 , tα,β (x) := β if x = k − 1, belong to [M ] for all α, β ∈ Ek−1 with k − 1 ∈ {α, β}. Next we show that U0 := {f ∈ U | |Im(f )| ≤ 2 ∧ k − 1 ∈ Im(f )} ⊆ [M ]
(18.22)
holds. For this purpose, let f n be an arbitrary function of U0 with Im(f ) = {a, k−1}. Because of (18.19) there is an n-ary function f ∈ [M ] with the property ∀x ∈ Ekn : f (x) = k − 1 ⇐⇒ f (x) = k − 1. With the aid of the above function ta,k−1 ∈ [M ], one can prove that
586
18 Further Submaximal Classes of Pk
ta,k−1 f = f ∈ [M ]. Therefore, and because of (18.21), (18.22) is valid. If one forms superpositions over the constants and the functions of M , which do not belong to the clones of type III, one obtains functions gγm ∈ [M ] with x
gγ (x)
m ∈ Ek−1
}= gγ ∈ P olk−1 γ
otherwise
certain values
for all γ with the properties: (a) P olk−1 γ is maximal in Pk−1 and (b) c0 , ..., ck−1 ∈ P olk−1 γ. Hence, because of (18.21), there are functions gγ ∈ [M ] that do not fulfill (b). This and the completeness criterion for Pk−1 imply that the following function belongs to [M ]: x
y
s(x, y)
2 ∈ Ek−1
}= max(x, y) + 1 (mod k − 1)
k−1 k−1 otherwise
α certain values
We distinguish two cases for α := s(k − 1, k − 1): Case 1: α ∈ Ek−1 . By s ∈ [M ] the functions s := ∆s and
s := (s )k−1 ,
(s (x) = s(x, x))
(s (x) = s (s (s (...s (x)...))) ) k−1
belong to [M ]. Let β := s (k − 1) and γ ∈ Ek−1 \{β}. With the help of the completeness criterion for Pk,k−1 , one can easily prove that the set M1 := {s s, tβ,γ = s tk−1,γ } ⊆ [M ] is a generating system for Pk,k−1 . The completeness criterion for Pk,k−1 is a special case of Theorem 12.4.3 and says: An arbitrary subset T ⊆ Pk,k−1 is a generating system for Pk,k−1 , if and only if T fulfills the following two conditions:
18.3 The Maximal Classes of P olk (Ek2-1 ∪ {(k-1, k-1)})
587
(i) The set n pr T := {f n) ∈ Pk−1 | ∃f1n ∈ T : ∀x ∈ Ek−1 : f (x) = f1 (x)}
is a generating system for Pk−1 . (ii) For all a ∈ Ek : T ⊆ Pk,k−1 ∩ P olk
0 1 ... k − 2 a 0 1 ... k − 2 k − 1
.
Because of s s ∈ Pk,k−1 , ∀x, y ∈ Ek−1 : (s s)(x, y) = max(x, y) + 1 (mod k − 1) and the fact that max(x, y)+1 is a Sheffer function for Pk−1 fulfills (i). Because of a β tβ,γ = k−1 γ
6
the set T := M1
T := M1 also fulfills the condition (ii). Thus Pk,k−1 ⊆ [M ] was proven in Case 1. Then Lemma 18.3.2.5 implies the existence of two different elements a, b ∈ Ek−1 with Ua,b,k−1 ⊆ [M ].
(18.23)
Except for the unary function e ∈ U \U0 with x e(x) 0 1 . ∈ Ek−1 . k−2 k−1 k−1 we have proven that the other unary functions of U belong to [M ]. Next, with the aid of the completeness theorem for Pk−1 , we show that the functions of the form e are superpositions over {c0 , c1 , ..., ck−1 } ∪ U0 ∪ Pk,k−1 ⊆ [M ] and functions of M , which do not belong to the clones of type IV. 6
See Theorem 7.1.5.
588
18 Further Submaximal Classes of Pk
k−2 Let γ ∈ Uk−1 ∪Bk−1 ∪ h=1 Ck−1 be an h-ary relation; i.e., γ is a totally reflexive and totally symmetric relation that describes the maximal class P olk−1 γ of Pk−1 . Then, the relation h+1 ∪ {(x, x, ..., x, y) | x, y ∈ Ek } γ := Ek−1
∪{(x1 , ..., xh , k − 1) | (x1 , ..., xh ) ∈ γ} describes a maximal class of U of type IV. If one replaces the variables of a function fγ ∈ M \P olk γ by certain functions of the set {c0 , c1 , ..., ck−1 } ∪ U0 ∪ Pk,k−1 ⊆ [M ], one receives an n-ary function fγ ∈ [M ] with fγ (x)
x n ∈ Ek−1
*
= fγ (x) ∈ P olk−1 γ
(18.24)
k − 1 k − 1 ... k − 1 k−1 otherwise certain values k−2 for all γ ∈ Uk−1 ∪Bk−1 ∪ h=1 Ck−1 . Since function ta,k−1 belongs to U0 ⊆ [M ] for every a ∈ Ek−1 , there are also functions fγ ∈ [M ] with the property (18.24) for all γ ∈ Sk−1 ∪ C1k−1 . Because of (18.23), there is a function fγ ∈ [M ] with the property (18.24) for every γ ∈ Mk−1 ∪ Lk−1 . With the help of the completeness criterion for Pk−1 and the fact that the function fγ ∈ [M ] k−2 preserves the relation {k −1} for every γ ∈ Mk−1 ∪Sk−1 ∪Uk−1 ∪ h=1 Ck−1 ∪ k−1 1 1 h=3 Bk−1 , one can prove that U ∩ P olk {k − 1} ⊆ [M ]. Consequently, U ⊆ [M ]. To summarize, we have proven Pk,k−1 ∪ U0 ∪ Ua,b,k−1 ∪ U 1 ⊆ [M ] in Case
1. Since a function of U \P olk (ιk−1 k−1 ) belongs to M , this and Lemma 18.3.2.3 implies [M ] = U . Case 2: α = k − 1. Since function s preserves {k − 1} in this case and s is a Sheffer function for 2 Pk−1 on the tuples of Ek−1 , every unary function e with e(k − 1) = k − 1 is a superposition over M . Furthermore, [prEk−1 M ] = Pk−1 . Since we have proven that U0 ⊆ [M ] holds, the first statement of Lemma 18.3.2.7 implies Pk,k−1 ⊆ [M ]. Therefore, there exists a function of [M ] that fulfills the assumption of Case 1. Consequently, [M ] = U in Case 2, and we have proven the following theorem: Theorem 18.3.3.1 (Completeness Theorem for U ) (1) The clones defined in Section 18.3.1 are the only maximal classes of U . (2) An arbitrary set M ⊆ U is U -complete if and only if there exists no class of the type I, II, ... or V I that has M as a subset.
19 Minimal Classes and Minimal Clones of Pk
In this chapter we deal with classes (of Lk ), which are either direct predecessors of the empty set (so-called minimal classes) or which are direct predecessors of the set of all projections (so-called minimal clones). It will turn out that it is not heavy to determine the minimal classes. However, for the minimal clones only partial results can be given.
19.1 Minimal Classes A subclass A of Pk is called a minimal class, if no subclass B = ∅ with B ⊂ A exists. Because of [∆n−1 f ] ⊂ [f ] for every function f ∈ Pk \[Pk1 ], every minimal classes has the order 1. If k = 2 then [c0 ], [c1 ] and [e11 ] are the only minimal classes. For arbitrary k one can easy check that Jk is a minimal class and, for every other minimal class A, there exists a unary function f ∈ Pk1 (k − 1) with the property f f = f and [f ] = A. Then a minimal class of P6 is e.g. x f (x) 0 1 1 1 2 1 3 3 4 4 5 4 By generalizing this example, one obtains the following theorem which is a conclusion from [P¨ os-K 79], Section 4.4.
590
19 Minimal Classes and Minimal Clones of Pk
Theorem 19.1.1 Pk contains exactly 1+
k−1 r=1
k · rk−r r
minimal classes. These are class Jk and the classes of the form [f ] with f ∈ Pk1 (k − 1) and f f = f . One can describe a function f ∈ Pk1 (k − 1) with the property f f = f as follows: Let θ be an equivalence relation on Ek , which is different from ι2k (= κ0 ) and has exactly r equivalence classes. Further, denote a := (a1 , ..., ar ) an r-tuple with elements, which in pairs are not θ-equivalent. For such a θ und such an a, one can define the mapping faθ ∈ Pk by faθ (x) = ai :⇐⇒ x ∈ [ai ]θ . Then, for a function f ∈ Pk1 (k − 1), f f = f holds, if and only if there is an equivalence relation θ and a tuple a of the above form with f = faθ .
19.2 The Five Types of Minimal Clones A clone A ⊆ Pk is called minimal in Pk , iff Jk is a maximal clone of A, i.e., it holds (19.1) ∀f ∈ A \ Jk : [Jk ∪ {f }] = A. Therefore, a basis of a minimal clone has at most two elements. Furthermore, it is easy to see that the following implication holds: (A is a minimal clone with ord A ≥ 2) =⇒ ∀f ∈ A \ Jk : A = [f ].
(19.2)
From Chapter 3 it follows directly: Theorem 19.2.1 P2 has exactly 7 minimal clones. These are the clones I ∪ C0 = [e11 , c0 ], I ∪ C1 = [e11 , c1 ], I = [e11 ], K = [∧], D = [∨], L ∩ S ∩ T0 = [r] and [S ∩ M ∩ T0 ] = [h32 ]. One has solved the problem of describing minimal clones of the form [f n ] ⊆ Pk for arbitrary k thus far only for n = 1. Theorem 19.2.2 ([P¨ os-K 79], [Har 74]; without proof ) Pk has exactly k−1 r=1
k−2 k k · rk−r + · r r r=0
p·t=k−r,p∈P,t∈N
pt
(k − r)! · t! · (p − 1)
19.2 The Five Types of Minimal Clones
591
minimal clones of the order 1. A minimal clone A of the order 1 has either the form A = Jk ∪ [f ], where [f ] is a minimal class different to Jk (see Theorem 19.1.1), or has the form A = [s], where s ∈ Pk1 [k] \ {e11 } is a permutation for which there is a prime number p with sp = e11 . The following theorem supplies the existence of at most finite many minimal clones (for a fixed k) and a coarse division of the minimal clones. Theorem 19.2.3 (Rosenberg’s Classification of the Minimal Clones; [Ros 82]) For every k ∈ N \ {1} there is only finite many minimal clones. If A = [Jk ∪ {f n }] is an arbitrary minimal clone of Pk , where [An−1 ] = Jk , then this clone fulfills one of the following five conditions: (1) n = 1 and A is described in Theorem 19.2.2. (2) n = 2 and f is idempotent, i.e., f (x, x) = x holds for arbitrary x ∈ Ek . (3) n = 3 and ∀x, y ∈ Ek : f (x, x, y) = f (x, y, x) = f (y, x, x) = y,
(19.3)
i.e., f is a so-called ternary minority function. A minority function g 3 of Pk generates a minimal clone if and only if g(x, y, z) = x ⊕ y ⊕ z and (Ek ; ⊕) is an elementary 2-group. (4) n = 3 and ∀x, y ∈ Ek : f (x, x, y) = f (x, y, x) = f (y, x, x) = x, (5)
(19.4)
i.e., f is a so-called ternary majority function. n ∈ {3, 4, ..., k} and f is a semiprojection, i.e., there exists an i ∈ {1, ..., n} with f (a1 , ..., an ) = ai for every tuple (a1 , ..., an ) ∈ Ek with |{x1 , ..., xn }| ≤ n − 1.
1
Proof. Let A be an arbitrary minimal clone of the order n ∈ N. Because of Theorem 19.2.2 and by (19.2), we can assume w.l.o.g. that n ≥ 2 and that A = [f n ] for certain f ∈ Pk . Obviously, because of ord f ≥ 2 and the minimality of the clone A, it holds: ∀i ∈ {1, ..., n − 1} : ∆i f ∈ Jk
(19.5)
In particular this implies f (x, x, ..., x) = x, i.e., f is idempotent. Thus, (2) is proven for n = 2. Because of (19.5) we obtain for n = 3 that 1
´ The following statement is also mentioned Swierczkowski Lemma in the literature. ´ S. Swierczkowski published in [Swi 60] a theorem from which statement (5) of Theorem 19.2.3 results.
592
19 Minimal Classes and Minimal Clones of Pk
{f (x, x, y), f (x, y, x), f (y, x, x)} ⊆ {x, y}. Consequently, the following eight cases are possible: 1 f (x, x, y) = x f (x, y, x) = x f (y, x, x) = x
2 x x y
3 x y x
Case 4 5 x y y x y x
6 y x y
7 y y x
8 y y y
In Case 1, the function f fulfills the condition (19.4). In Cases 2, 3, and 5 the function f is a semiprojection, i.e., f fulfills the condition (5). Case 8 gives the condition (19.3). The remaining cases 4, 6, and 7 cannot occur for a function f which generates a minimal clone. This can be shown as follows: Suppose it holds Case 6; i.e., we have f (x, x, y) = f (y, x, x) = y and f (x, y, x) = x. Then the function g(x, y, z) := f (x, f (x, y, z), z) is a majority function. Since every ternary superposition t ∈ Jk over the majority function f is a majority function, too 2 , this is a contradiction to the minimality of clone A. In analog mode, the other cases can be led to a contradiction. Let now n = 4. Then, by assumption [A3 ] = Jk . Therefore, in particular ∆f ∈ Jk , i.e., we have f (x1 , x1 , x3 , x4 ) ∈ {x1 , x3 , x4 }. Then the following two cases are possible: Case 1: f (x1 , x1 , x3 , x4 ) = x1 . Then, because of [A3 ] = Jk it holds: xa := f (x1 , x2 , x1 , x4 ) ∈ {x1 , x2 , x4 }, xb := f (x1 , x2 , x3 , x1 ) ∈ {x1 , x2 , x3 }, xc := f (x1 , x2 , x2 , x4 ) ∈ {x1 , x2 , x4 }, xd := f (x1 , x2 , x3 , x2 ) ∈ {x1 , x2 , x3 }, xe := f (x1 , x2 , x3 , x3 ) ∈ {x1 , x2 , x3 }. If one puts x1 = x2 in the above equations and if one compares this with f (x1 , x1 , x3 , x4 ) = x1 , it follows {a, b, c, d, e} ⊆ {1, 2}. Since there exists a t ∈ {1, 2} with f (x1 , x2 , x1 , x1 ) = xt in addition, one obtain from the above equations: a = b = c = d = e = t. Thus f is a semiprojection in Case 1. 2
Use induction on the number of occurrences of f in t; see e.g. [Sza 83b] or [Qua 95].
19.2 The Five Types of Minimal Clones
593
Case 2: There exists an i ∈ {3, 4} with f (x1 , x1 , x3 , x4 ) = xi . If i = 3 then f (x1 , x2 , x3 , x3 ) = x3 . Consequently, we can continue analogously to the first case with the proof. If i = 4, then we have f (x1 , x2 , x3 , x1 ) = x1 and one can show (as in the first case) that f is a semiprojection. In analog mode to the case n = 4, one can examine the case n ≥ 5. It remains to show that a minority function g 3 , which generates a minimal clone, fulfills condition (4). One can show this most easily with the aid of the ´ Szendrei in [Sze 87]: following statement, proven by A. Let k ≥ 2 and d ∈ Pk be a ternary function, which fulfills the Mal’tsevcondition d(x, y, y) = d(y, y, x) = x. Then [d] is a minimal clone of Pk if and only if there exists an elementary Abelean p-group (Ek ; ⊕) with d(x, y, z) = x ) y ⊕ z. 3 Since a minority function g fulfills the Mal’tsev-condition according to definition, the function g has the form given in the above statement. However, the function g(x, y, z) = x ) y ⊕ z is a minority function iff p = 2.
Theorem 19.2.4 ([Pal 86]) For every t ∈ {1, 2, ..., k} there is a minimal clone of the order t. Proof. For t = 1 one can find examples for minimal clones of the order 1 in Theorem 19.2.1. In [P¨ os-K 79] one finds proof that the binary function f with f (x, y) = x ◦ y, where the operation ◦ fulfills the equations x ◦ x = x (idempotent law), (x ◦ y) ◦ z = x ◦ (y ◦ z) (associative law), (x ◦ y) ◦ x = x ◦ y (absorption law), generates a minimal clone. Let t ∈ {3, ..., k − 1}. Denote a1 , ..., at+1 pairwise distinct elements of Ek . The t-ary semiprojection f is defined by at+1 if x1 = a1 ∧ {x2 , ..., xt } = {a2 , ..., at }, f (x1 , ..., xt ) := x1 otherwise. In [Pal 86] it was proven that [f ] is a minimal clone of the order t. Put x1 if |{x1 , ..., xk }| ≤ k − 1, g(x1 , ..., xk ) := x2 otherwise. Then it is easy to see that [g] is a minimal clone of the order k. Of the many results found in the literature on minimal clones, only some are given without proof. 3
One finds this statement also proven in [Qua 95].
594
19 Minimal Classes and Minimal Clones of Pk
Theorem 19.2.5 ([Csa 83b]; without proof ) P3 has exactly 84 minimal clones. One obtains every one of these clones by using an inner automorphism of P3 onto exactly one of the 24 following clones (under that 4 of the order 1, 12 of the order 2 and 8 of the order 3): [j2 ], [u2 ], [s2 ], [s4 ] (see Table 15.1), [bi ] and [mj ], where i ∈ {1, 2, ..., 12}, bi idempotent, j ∈ {1, 2, ..., 8}, mj majority function and x 0 1 0 2 1 2
y 1 0 2 0 2 1
b1 0 0 0 0 0 0
b2 0 0 0 2 0 2
x 0 0 1 1 2 2
y 1 2 0 2 0 1
z 2 1 2 0 1 0
b3 0 0 0 0 1 1
b4 0 0 0 0 1 2
b5 0 0 0 2 1 1
b6 0 0 0 2 1 2
b7 0 0 0 2 2 2
b8 0 1 0 2 0 0
b9 b10 b11 b12 0 0 0 2 1 2 0 2 0 0 2 1 2 1 2 1 0 1 1 0 2 2 1 0
m1 m 2 m 3 m 4 m 5 m 6 m 7 m 8 0 0 2 0 0 0 0 1 0 1 1 0 0 0 0 2 0 1 2 0 0 0 2 0 0 0 0 0 0 2 2 2 0 0 1 0 2 2 1 0 0 1 0 0 2 2 1 1
Note that the cardinality of the set of all subclasses of P3 , which contain a fixed minimal clone of the order 1, can be found in [Pan-V 2000]. It was proven by B. Szczepara in his 210-page long Ph.D. thesis that there are exactly 2182 binary minimal clones for k = 4 (see [Szc 95]). All minimal clones, which are generated by majority functions of P4 , were determined by T. Waldhauser in [Wal 2000]. In [Lev-P 96] one can find all minimal clones C of the order 2 with |C 2 | ∈ {3, 4, 6}. Furthermore, one can find examples for minimal clones C of the order 2 with |C 2 | = 2t + 2 (t ≥ 1) or |C 2 | = 3t + 2 (t ≥ 2) in this paper. Up to isomorphic functions, all binary commutative functions, which generate minimal clones of the order 2, were determined in [Kea-S 99]. In [P¨ os-K 79] it was proven that Pk is the smallest clone, which contains all minimal clones of Pk . Further, it was proven that Jk is the intersection of all maximal clones of Pk . The following problem results from that: How many clones M1 , ..., Mt does one need so that at least t minimal (or maximal) t [ i=1 Mi ] = Pk (or i=1 Mi = Jk ) is valid, respectively? In [Zsa 92] it was proven that t ≤ 3 holds. The solution t = 2 for the above problem can be found in [Cz´e-H-K-P-S 2001]. A necessary and sufficient condition for [f, g] = Pk , if [f ] and [g] are minimal clones, can be found in [Ros-M 2001]. The answer 3 for the corresponding problems during the investigation of partial minimal (or maximal) clones was proven in [Had-M-R 2002].
19.2 The Five Types of Minimal Clones
595
One finds supplements to this chapter in the survey articles [Qua 95] and [Csa 2002]. In the next chapter, we deal with partial functions, for which we will handle similar problems as in the previous chapters. The next theorem shows that the problem of determining minimal partial clones can be reduced to the problem of determining minimal clones. Theorem 19.2.6 ([B¨ or-H-P 91]; without proof ) k . Then C is either a minimal clone of Pk or Let C be a partial clone of P C is generated by a partial n-ary projection with a nontrivial totally reflexive and totally symmetric domain D(e) ⊂ Ekn for certain n ≤ k. Denote t(k) the number of all minimal clones of Pk and m(k) the number of k . Then all partial minimal clones of P m(k) = t(k) +
k
k (2( i ) − 1).
i=1
In particular, we have m(2) = 11 and m(3) = 99, where t(2) = 7 and t(3) = 84 (see Theorems 19.2.1 and 19.2.5).
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20 Partial Function Algebras
In Part I, Chapter 1, we introduced the concept of partial operation over a set A. By choosing A = Ek and replacing the concept of “operation” with the concept of “function”, we get the concept “partial function” over Ek . One k of can then introduce certain modified Mal’tsev-operations over the set P all partial functions on Ek . Then the set Pk together with these operations k ; τ, ζ, ∆, ∇, ), which can forms a so-called (full) partial function algebra (P be examined similar to the function algebra (Pk ; τ, ζ, ∆, ∇, ). The choice of results on partial function in this chapter focuses on questions that were already treated for Pk in the previous chapter. After a composition of some basic concepts in Section 20.1, Section 20.2 shows k is isomorphic to a certain sublatthat the lattice of all partial clones of P tice of the lattice of all clones of Pk+1 . Thus, one gets many properties of the partial clones from the properties of the clones that were already found. To find certain partial clones, however, with the aid of the above-mentioned isomorphism, is not possible, because of the absence of results on clones. One k with the help could, for example, not solve the completeness problem for P of isomorphism. In Section 20.3, we show how one can describe partial clones by relations. Sections 20.4 and 20.5 deal with the maximal partial clones with whose aid, analogously to Pk , one can solve the completeness problem of the partial 3 has exactly 58 maximal 2 has exactly 8 and P logic. We will prove that P partial clones. In Section 20.5 one can find the complete list of all maxik for arbitrary k ∈ N, which was found by L. Haddad and mal clones of P I. G. Rosenberg. The list is given without proof. In Section 20.6, we determine the descriptive relations of the maximal clones of Pk that are also k . In addition, a surdescriptive relations of the maximal partial clones of P vey those papers that deal with determining the orders of the maximal partial clones. Section 20.7 deals with determining the cardinality of the set k | C = [C] ∧ C ∩ Pk = A}, where A is an arbitrary maximal I(A) := {C ⊆ P clone of Pk . We prove, that, if A has the type U, S or C, I(A) is a finite set.
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20 Partial Function Algebras
On the other hand, the set I(A) has the cardinality of continuum, if A has the type L or B. For the type M we can give only partial results. Section 20.8 gives a survey on the cardinalities of the sets I(A), where A is an arbitrary subclass of P2 . In last section, we determine the congruences on the maximal partial clones. It k has exactly 4 congruences, whereas a maximal is proven particularly that P partial clone has exactly 4, 8, or 10 pairwise distinct congruences.
20.1 Basic Concepts Let A be nonempty sets and let T be a proper subset of An . For an arbitrary mapping f from T into A and for (a1 , ..., an ) ∈ An \T , one can use the notation f (a1 , ..., an ) = ∞ with ∞ ∈ A, to indicate that f (a1 , ..., an ) is not defined. Then D(f ) := {(x1 , ..., xn ) ∈ An | f (a1 , ..., an ) = ∞} is the domain of f . In the following, we use these notations for A = Ek and for functions which are defined over subsets of Ekn . More exact: For a fixated k ∈ N \ {1} let k := Ek ∪ {∞}. E An n-ary mapping f of the form k f : Ekn −→ E is called (n-ary) partial function. and the set of all n-ary partial functions let n k . P Furthermore, we put
k := P
n
k . P
n≥1
By the above definition, the functions of Pk are also partial functions. To k \ Pk , we call these the distinguish these functions from functions of the set P total functions of Pk . n n k , if g(a) ∈ {f (a), ∞} k is called subfunction of f ∈ P A function g ∈ P holds for all a ∈ Ekn . In the following, the notation g ⊆p f is used to indicated the fact that g is a subfunction of f . We take the notations introduced for total functions and we set
20.1 Basic Concepts
599
cn∞ (x1 , ..., xn ) := ∞, i.e., cn∞ is the notation for the n-ary function with empty domain, and C∞ := {cn∞ | n ∈ N}. The reduction of a function f n ∈ Pk to T ⊂ Ekn is a function defined by f (x), if x ∈ T, g(x) := ∞ otherwise, which is also denoted with
f|T .
k . Now we consider the operations over P n m For arbitrary f , g ∈ Pk we define the unary Mal’tsev-operations analogous to Chapter 1 and the binary operation as follows: (ζf )(x1 , x2 , ..., xn ) := f (x2 , x3 , ..., xn , x1 ), (τ f )(x1 , x2 , ..., xn ) := f (x2 , x1 , x3 , ..., xn ), (∆f )(x1 , x2 , ..., xn−1 ) := f (x1 , x1 , x2 , ..., xn−1 ) for n ≥ 2, ζf = τ f = ∆f = f for n = 1, (∇f )(x1 , x2 , ..., xn+1 ) := f (x2 , x3 , ..., xn+1 ) and (f ∗ g)(x1 , ..., xm+n−1 ) := f (g(x1 , ..., xm ), xm+1 , ...., xm+n−1 ) if g(x1 , ..., xm ) ∈ Ek , ∞ otherwise. We adopt the concepts (such as closure, closed set, clone ...) and the notations (such as [...]) coupled with the Mal’tsev-operations from Chapter 1. If distinctions are required, we complete these concepts with the word “partial”. For k , which contains example,“partial clone” instead of “clone” if a closed set of P the set Jk of all projections of Pk , is meant. A partial clone C is called strong if it contains all subfunctions of its functions. If C is a clone of Pk , then let k | ∃g ∈ Pk : g|D(f ) = f }. Str(C) := {f ∈ P It is easy to check that Str(C) is a partial strong clone. As we see in Section 20.3, partial clones, like the clones of Pk , are describable k ) suitably chosen. with the help of relations (on E At first we want to show, however, how one can embed the lattice of the k into the lattice of the subclones of Pk+1 isomorphically. subclones of P
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20 Partial Function Algebras
20.2 One-Point Extension In this section, let
A := Ek and B := Ek ∪ {∞}.
The following mappings establish relations between P A := Pk and PB (isomorphic to Pk+1 ): n n + : P A −→ PB , f → f+ , n n − : PB −→ P A , g → g− n where f+ is the so-called extended function defined by f (x) if x ∈ D(f ), f+ (x) := ∞ otherwise, n and g− , the so-called restricted function, is defined by g(x) if x ∈ Ekn ∧ g(x) ∈ Ek , g− (x) := ∞ otherwise.
Furthermore, for subsets F ⊆ PA and G ⊆ PB we put: F+ := {f+ | f ∈ F } and G− := {g− | g ∈ G}. To distinguish the projections from PA of the projections from PB , we use the notation eni,X with X ∈ {A, B}, i.e., ∀x1 , ..., xn ∈ X : eni,X (x1 , ..., xn ) := xi (i ∈ {1, ..., n}) holds. Let JX be the set of all projections of the form eni,X . One can prove that, if f ∈ P A and D(f ) = ∅, ∇f+ ∈ F+ holds. In the following, the clones (⊆ PB ), which are formed by closing certain subsets of PB , are important to further considerations: k )+ ]. H := [(Jk )+ ] and U := [(P The next Lemma gives properties of the clones defined above. Lemma 20.2.1 ([Ros 88]) (1) A function q t ∈ PB belongs to U , if and only if the following two statements hold: (a) q preserves ∞ and (b) for every essential place i of q and for arbitrary b1 , ..., bn ∈ B it holds q(b1 , ..., bi−1 , ∞, bi+1 , ...,t ) = ∞. (2) H is a minimal clone of PB .
20.2 One-Point Extension
601
Proof. (1): Denote U the set of all functions of PB , which fulfills conditions (a) and (b) above. At first we show that U is a clone. The equation U = U from which the assertion (1) immediately follows is then proven. Let f n , g m ∈ U be arbitrary. Then obviously τ f, ζf, ∇f ∈ U and ∆f ∈ U for n = 1. Let n > 1. If ∆ f depends on the first place essentially, then f depends at least on the places 1 and 2 essentially. Consequently, we have (∆ f )(∞, x3 , ..., xn ) = f (∞, ∞, x3 , ..., xn ) = ∞ for all x3 , ..., xn ∈ B. If ∆f depends on the i-th place with 2 ≤ i ≤ n − 1 essentially, then f depends on the (i + 1)-th place essentially and (∆ f )(x1 , x3 , ..., xi−1 , ∞, xi+1 , ..., xn ) = f (x1 , x1 , x3 , ..., xi−1 , ∞, xi+1 , ..., xn ) =∞ holds for all x1 , x3 , .., , , xn ∈ B. Consequently, the function ∆ f also belongs to U in the case n > 1. To prove f g ∈ U , we put hm+n−1 := f g. Obviously h fulfills the condition (a). Let h be dependent of the i-th place and let x := (x1 , ..., xm+n−1 ) ∈ B m+n−1 be arbitrary, where xi = ∞. Then the following two cases are possible: Case 1: i ∈ {1, ..., m}. In this case, the first place of f and the i-th place of g is essential. Thus by assumption, we have g(x1 , ..., xm ) = ∞ and h(x) = f (∞, xm+1 , ..., xm+n−1 ) = ∞. Case 2: i ∈ {m + 1, ..., m + n − 1}. Since in this case f depends on the (i − m + 1)-th place essentially, h(x) = ∞ holds. It also holds that h = f g ∈ U . Thus U is a closed set. Since the function e21,B fulfills conditions (a) and (b), U is a clone. It is easy to check that (PA )+ ⊆ U and U ⊆ U hold. For the missing proof of U ⊆ U , we consider an arbitrary function q t ∈ U with at least an essential place. Using the operations ζ, τ, ∆ we get from q a function q1 ∈ U that depends on all its places essentially and which belongs to (PA )+ . Since we can get again the function q by using the operations ∇, ζ, τ from q1 , we have q ∈ [(PA )+ ] = U . Thus U = U and (1) is proven. (2): It is easy to check that JB ⊂ [(e21,A )+ ] = H holds. To prove the maximality of JB in H we put b := |B| and := {(x1 , ..., xb ) ∈ B b | |{x1 , ..., xb }| = b}. Since (e21,A )+ ∈ P olB , we have H ⊆ P olB . Let q t ∈ H \JB be arbitrary. Since no constants belong to P olB , the function q has at least an essential place i. Suppose i is the only one essential place of q. Then we have q(x1 , ..., xi−1 , xi , xi+1 , ..., xn ) = g(xi , ..., xi , ..., xi ) = xi , i.e., q t = eti,B , in contradiction to q ∈ JB . Thus the function q has also at least two essential places. Using the operations ζ, τ, ∆ we get from q a binary
602
20 Partial Function Algebras
function g, which depends on both places essentially, preserves all elements of B, and belongs to H ⊂ U ; i.e., for all x ∈ B it holds: g(x, x) = x, g(x, ∞) = g(∞, x) = ∞, g(∞, ∞) = ∞. Consequently, g = (e21,A )+ and therefore H ⊆ [g] ⊆ H. Thus JB is a maximal clone of H. Lemma 20.2.2 For arbitrary f n , g m ∈ U holds: (1) α(f− ) = (α f )− for every operation α ∈ {ζ, τ, ∆, ∇}; (2) f− g− = h− , where hm+n−1 (x1 , ..., xm+n−1 ) := (e21 )+ (f (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ), g(x1 , ..., xm )); (3) f− g− ⊆p (f g)− ; (4) f− g− = (f g)− , if the first place of f is essential; (5) f− g− = (f g)− , if g− ∈ Pk . Proof. (1): For α ∈ {ζ, τ, δ} the assertion is obvious. For arbitrary (x1 , ..., xn+1 ) ∈ A is by definition (∇f )(x1 , ..., xn+1 ) = f (x2 , ..., xn+1 ). Furthermore (x1 , ..., xn+1 ) ∈ D((∇f )− ) holds iff (x2 , ..., xn+1 ) ∈ D(f− ). Consequently, we have (∇f )− (x1 , ..., xn+1 ) = ((∇f )− )(x2 , ..., xn+1 ) for arbitrary (x2 , ..., xn+1 ) ∈ D(f− ). (b2): Let x ∈ Am+n−1 be arbitrary. It is easy to check that h(x) = ∞ iff (f g)(x) = ∞. If h(x) = ∞, then h(x) = (f g)(x). Consequently, D(h− ) = {(x1 , ..., xm+n−1 ) ∈ Am+n−1 | (x1 , ..., xm ) ∈ D(g− ) ∧ (g− (x1 , ..., xm ), xm+1 , ..., xn+m−1 ) ∈ D(f− )} = D(f− g− ). Thus, for x := (x1 , ..., xm+n−1 ) ∈ D(h− ) we have g(x1 , ..., xm ) = g− (x1 , ..., xm ) and h(x) = (f g)(x) ∈ A. Hence h− = f− g− . (3): Let x := (x1 , ..., xm+n−1 ) ∈ D(f− g− ) be arbitrary. Then (x1 , ..., xm ) ∈ D(g− ) and (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ) ∈ D(f− ). Thus (f g)(x) = ∞. Consequently, x belongs to D((f g)− ) and we have (f− g− )(x) = f (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ) = (f g)(x), i.e., f− g− ⊆p (f g)− . (4): Let the first place of f be essential and let x := (x1 , ..., xm+n−1 ) ∈ D((f g)− ) be arbitrary. Because of f ∈ U it follows that g(x1 , ..., xm ) = ∞. Thus (x1 , ..., xm ) ∈ D(g− ) and (g(x1 , ..., xm ), xm+1 , ..., xm+n−1 ) ∈ D(f− ). Hence x ∈ D(f− g− ) and by (3) we have f− g− = (f g)− . (5): Let g ∈ PA and let x := (x1 , ..., xm+n−1 ) ∈ Am+n−1 be arbitrary. Then, (x1 , ..., xm ) ∈ D(g− ) and, because of x ∈ D(f− g− ) ⇐⇒ (g(x − 1, ..., xm ), xm+1 , ..., xm+n−1 ) ∈ D(f− ) ⇐⇒ x ∈ D((f g)− ), the assertion follows with the help of (c).
20.2 One-Point Extension
603
Lemma 20.2.3 For arbitrary f, g ∈ P A it holds: (1) α(f+ ) = (α f )+ for every operation α ∈ {ζ, τ, ∆}; (2) ∇(f+ ) = (∇f )+ , if f ∈ C∞ ; (3) f+ g+ = (f g)+ . Proof. (1) and (3) are immediate conclusions from the definition of the mapping +. (2) is easy to check. Lemma 20.2.4 Let G ⊆ U ⊆ PB be a clone and let F ⊆ P A be a partial clone with G− ⊆ F . Then ([G])− ⊆ F. (20.1) Proof. Let f, g ∈ G be arbitrary. Then by assumption the function f− and g− belong to F . Because of Lemma 20.2.2, (1) it follows that (αf )− = α(f− ) ∈ F for every α ∈ {ζ, τ, ∆, ∇}. Let h := f g ∈ G. If the first place of f is essential, then h− = (f g)− = f− g− ∈ F holds by Lemma 20.2.2, (4). If the first place of f is fictitious, then m m m hm+n−1 = f n g m = f n em 1,B . Since (e1,B )− = e1,A , we have h− = f− e1,A by Lemma 20.2.2, (5). Theorem 20.2.5 ([Ros 88], [B¨ or-P 90], [B¨ or 97]) (1) For every partial clone F ⊆ P A we have F = ([F+ ])− . (2) For every clone G ⊆ PB with H ⊆ G the set G− is a partial clone of P A with the property G = [(G− )]+ . (3) The mapping ϕ : LB (H; U ) −→ LA (JA ; P A ), G → G−
(20.2)
+ is a lattice isomorphism between the lattices LB (H, U) and LA (JA ; P A ), −1 where ϕ (F ) = [F+ ] holds for every F ∈ LA (JA ; PA ). Proof. (1): Because of f = (f+ )− for every f ∈ PA we have F ⊆ ([F ]+ )− . It follows from (F+ )− ⊆ F and Lemma 20.2.4 that ([F+ ])− ⊆ F . (2): Let rn and sm be two arbitrary functions of G− . Then there are two total functions un and v m of G with u− = r and v− = s. Because of Lemma 20.2.1, (a) we have αr = α(u− ) = (αu)− ∈ G− for all α ∈ {ζ, τ, ∆, ∇}. Furthermore, by Lemma 20.2.1, (b) the following is valid: (r s)(x1 , ..., xm+n−1 ) = (u− v)(x1 , ..., xm+n−1 ) = ((e21,A )+ (u(v(x1 , ..., xm ), xm+1 , ..., xm+n−1 ), v(x1 , ..., xm )))− . Thus r s ∈ G− . Consequently, G− is a partial clone. Let hn1 ∈ G ⊆ U be arbitrary. By using the operations ζ, τ, ∆ one can form
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20 Partial Function Algebras
from h1 a function hm 2 , which depends on all its places essentially. Then, for the function h2 and for arbitrary j ∈ {1, ..., m} and arbitrary x1 , ..., xm ∈ B, it holds: h2 (x1 , ..., xj−1 , ∞, xj+1 , ...xm ) = ∞, i.e., h2 = ((h2 )−)+ ∈ (G− )+ . With the help of the operations ζ, τ, ∆, ∇, one can form the function h1 from the function h2 . Consequently, hn1 ∈ [(G− )+ ] and G ⊆ [(G− )+ ] hold. Let ht3 ∈ G− be arbitrary. Then there is a function ht4 ∈ G with (h4 )− = h3 . t Because of H ⊆ G we have (et+1 1,A )+ ∈ G. Then, for the function h5 with t h5 (x1 , ..., xt ) := (et+1 1,A )+ (h4 (x1 , ..., xt ), x1 , ..., xt )
it follows: h5 ∈ G and h5 = (h3 )+ . Thus (G− )+ ⊆ G. (3): Let G1 and G2 be two different clones of PB with H ⊆ G1 ⊂ G2 ⊆ U . By (1) (G1 )− and (G2 )− are partial clones of LA [JA , PA ]. Obviously, (G1 )− ⊆ (G2 )− . Suppose, (G1 )− = (G2 )− . Then, by (2) it follows that G1 = [((G1 )− )+ ] = [((G2 )− )+ ] = G2 , in contradiction to G1 = G2 . Consequently, the mapping ϕ is an order-preserving bijective mapping from LB (H; U ) into LA (JA ; P A ). Let F ∈ LA [JA , PA ] be arbitrary. Then G := [F+ ] is a clone with H ⊆ G ⊆ U , since if e21,A ∈ F , then (e21,A )+ ∈ G and F+ ⊆ (PA )+ ⊆ U also hold. Further, we have ϕ(G) = ([F+ ])− = F by (1). Consequently, ϕ is surjective and ϕ−1 (F ) = [F+ ].
20.3 Description of Partial Clones by Relations h
k , h-ary relations (i.e., subsets of E k ), h ≥ 1, To describe closed subsets of P are suitable. We often write the elements of relations in the form of columns and we often give a relation in the form of a matrix, the columns of which are the elements of the relation. h k let The set of all h-ary relations over E k R and we put
k := R
h
h
k . R
h≥1
k preserves an h-ary relation over E k , iff We say that a function f ∈ P for all r1 , r2 , ..., rn ∈ with ri := (r1i , r2i , ..., rhi ), i = 1, 2, ..., n, it holds ⎛ ⎞ f (r11 , r12 , ..., r1n ) ⎜ f (r21 , r22 , ..., r2n ) ⎟ ⎜ ⎟ f (r1 , ..., rn ) := ⎜ ⎟ ∈ , .. ⎝ ⎠ . f (rh1 , rh2 , ..., rhn )
20.3 Description of Partial Clones by Relations
605
n
k \E h . where f (a) = ∞ is defined for all a ∈ E k Let pP olk h
k . Furtherk that preserve the relation ⊆ E be the set of all functions of P more, h
k \E h )). pP OLk := pP olk ( ∪ (E k The following Lemma is easy to check. Lemma 20.3.1 For every relation ∈ Rkh is valid: (1) pP olk ρ and pP OLk ρ are partial clones. (2) Str(P olk ) ⊆ pP OLk . h
k , the following conditions are equivLemma 20.3.2 For each relation ∈ R alent: (1) pP olk is a partial clone; (2) e21 ∈ pP olk ; (3) If (a1 , . . . , ah ), (b1 , . . . , bh ) ∈ and (c1 , . . . , ch ) is defined by ai if bi ∈ Ek , ci := ∞ if bi = ∞, (i = 1, ..., n), then (c1 , . . . , ch ) ∈ holds. Proof. Obviously, (1) ⇐⇒ (2) holds by definition. (2) ⇐⇒ (3) follows from ⎛ ⎞ ⎛ ⎞ a1 b1 c1 . .. ⎠ ⎝ .. ⎠ = . e21 ⎝ .. . . ah bh ch The following two lemmas give important properties that are needed to determine the maximal partial clones. 1 We need the following concept for the wording of the lemmas: The relation ∈ Rkh is called irredundant, iff it fulfills the following two conditions: 1) for all i, j with 1 ≤ i < j ≤ h, there is a tuple (a1 , ..., ah ) ∈ with ai = aj ; 2) No i ∈ {1, ..., h} exists, such that (a1 , ..., ah ) ∈ implies (a1 , ..., ai−1 , x, ai+1 , ..., ah ) ∈ for all x ∈ Ek . We say that for i = 1, ..., n the relations χi ⊆ {1, ..., t}hi cover the set {1, ..., t}, if for every x ∈ {1, ..., t} there exists an i ∈ {1, ..., n} such that x ∈ {a1 , ..., ahi } holds for at least a tuple (a1 , ..., ahi ) ∈ χi . 1
As one can gather from Sections 20.4 and 20.5, the maximal partial clones are all strong clones, with an exception.
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20 Partial Function Algebras
k be a strong partial Lemma 20.3.3 ([Rom 81], without proof ) Let C ⊆ P of irredundant relations clone. Then there is a certain nonempty set M ⊆ R k with C = ∈M pP OLk . Lemma 20.3.4 (Representation Lemma of B. A. Romov, [Rom 81]; without proof ) Let αi ⊆ Ekhi for i = 1, ..., n and let β ⊆ Ekt be an irredundant relation. Then n pP OLk αi ⊆ pP OLk β i=1
if and only if there are certain (help-)relations χi ⊆ {1, ..., t}hi for i = 1, ..., n that cover the set {1, ..., t} and for which β = {(b1 , ..., bt ) ∈ Ekt | ∀j ∈ {1, ..., n} ∀(ij1 , ..., ijhj ) ∈ χj : (bij , ..., bij ) ∈ αj } 1
hj
holds.
2 and P 3 20.4 The Maximal Partial Classes of P Lemma 20.4.1 Let f be an n-ary function of P3 , which essentially depends on at least two variables (w.l.o.g. let x1 and x2 be the essential variables). Furthermore, let {a, b, c} = E3 and δI := {(a0 , a1 , a2 ) ∈ E33 , | ∀α, β ∈ I : aα = aβ }, I ⊆ Ek . Then 3 3 ∪ δ{1,2} : f (r1 , ..., rn ) ∈ E33 \ι33 ; (a) Im(f ) = E3 ⇒ ∃ r1 , ..., rn ∈ δ{0,1} 3 3 3 3 ∪ δ{b,c} : f (r1 , ..., rn ) ∈ δ{a,c} \δ{0,1,2} ; (b) |Im(f )| = 2 ⇒ ∃ r1 , ..., rn ∈ δ{a,b} 1 (c) Im(f ) = E3 ⇒ [{f } ∪ { g ∈ P3 | g(a) = g(b) ∨ g(b) = g(c) }] = P3 . Proof. (a) is a special case of the “fundamental lemma of Jablonskij” and (b) is an easy conclusion from this lemma (see Theorem 1.4.4). (c): W.l.o.g. let a = 0, b = 1 and c = 2. Obviously, then, we have { g ∈ P31 | g(0) = g(1) ∨ g(1) = g(2) } = {c0 , c1 , c2 , jα , uα , vα | α ∈ {0, 2, 3, 5}}. It is easy to check that this set of unary functions is not a subset of maximal classes of type M, U, S, C and L. Since Im(f ) = E3 and f ∈ P3 \[P31 ] hold, f does not preserve by (a) the relation ι33 . Thus (c) follows from the completeness criterion for P3 . k \(Pk ∪ [{c∞ }]) it holds [Pk ∪ {g}] = P k . Lemma 20.4.2 (a) For every g ∈ P k that contains Pk . (b) Pk ∪ [{c∞ }] is the only maximal class of P k \(Pk ∪ [{c∞ }]). Since the function g := e2 ∗ g has Proof. (a): Let g m ∈ P 2 k . Consequently, k + 1 different values, we can assume w.l.o.g. Im(g) = E
2 and P 3 20.4 The Maximal Partial Classes of P
607
k ). there are k + 1 tuples ai := (ai1 , ai2 , ..., aim ) ∈ Ekm with g(ai ) = i (i ∈ E n Let f be an arbitrary function of Pk . Independently from f , one can define the following functions fj (j = 1, 2, ..., m): fj (b1 , ..., bn ) = aij :⇐⇒ f (b1 , ..., bn ) = i k ). Thus we have f (x) = g(f1 (x), ..., fm (x)). Hence (b1 , ..., bn ∈ Ek ; i ∈ E f ∈ [Pk ∪ {g}]. (b) follows directly from (a). 3 The next four lemmas deal with the maximality of certain subclasses of P (or Pk ) in P3 (or Pk ), respectively. The following statement (a) was proven in [Bur 67] (see also Chapter 4) and (b) of the following lemma was proven in [Rom 80] (or in [Lau 77], [Lau 88]). Lemma 20.4.3 Let 1 := {(a, a, b, b), (a, b, a, b) | a, b ∈ Ek }, 2 := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ Ek }, i := {(a1 , a2 , ..., ai ) ∈ Eki | |{a1 , ..., ai }| ≤ i − 1 } (i = 3, ..., k). Then (a) The classes P olk i (i = 1, 2, ..., k) are the only proper subclasses of Pk that contain Pk1 . Furthermore, it holds that [Pk1 ] = P olk 1 ⊂ P olk 2 ⊂ ... ⊂ P olk k−1 ⊂ P olk k ⊂ Pk . k and the (b) The classes pP OLk i (i = 1, 2, ..., k) are maximal classes of P 1 only maximal classes of Pk that contain Pk . Lemma 20.4.4 Let := δ ∪ σ, where δ denotes a certain h-ary diagonal relation, which is different from Ekh , and σ fulfills the condition ∅ = σ ⊆ {(a1 , ..., ah ) ∈ Ekh | |{a1 , ..., ah }| = h }. There exists to every a := (a1 , ..., ah ) ∈ σ a certain equivalence relation εa on Ek with the following two properties: (1) For every i ∈ {1, ..., h} there exists exactly an equivalence class of εa which contains ai . (2) To every b ∈ one can find in pP OLk a unary function ga,b with ga,b (a) = b and ga,b (x) = ga,b (y) for all (x, y) ∈ εa . k . Then pP OLk is a maximal class of P k . Let f ∈ P k \pP OLk . Since has the Proof. Obviously, pP OLk = P properties (1) and (2), one gets a certain unary function hr with hr (r) ∈ Ekh \ as a superposition over unary functions of pP OLk and f for every r ∈ σ. Let σ = {r1 , ..., rm }. One can find in pP OLk certain functions, which arbitrary k on rows of the form values have of E (x1 , x2 , gr1 (x1 ), gr2 (x1 ), ..., grm (x1 ), gr1 (x2 ), gr2 (x2 ), ..., grm (x2 ))
608
20 Partial Function Algebras
and otherwise only have the value ∞. Consequently, arbitrary functions of Pk2 are superpositions over {f } ∪ pP OLk . Hence (by well-known properties of Pk ) it follows that Pk ⊆ [{f } ∪ pP OLk ]. Since pP OLk obtains functions with exactly k + 1 different values, it follows from Lemma 20.4.2, (a) that k holds. Hence pP OLk is a maximal class of P k . [{f } ∪ pP OLk ] = P Table 20.1 i 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39
τi {0} {2} {0, 2} 0 1 1 2 0 2 2 0 0 0 1 2 0 1 2 2 0 1 1 1 0 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 1 2 ⎛0 ⎞ 0 ⎝1⎠ ⎛2 ⎞ 0 2 ⎝1 1⎠ 2 0
i 2 4 6 8 10 12 14
2 1 0 1 1 2 0 2 0 1 0 2 1 0 0 1 0 1 0 1
16
18
20
2 0 0 2 1 2 2 1 0 2 0 2 1 0
2 1 1 2 1 2 2 1
22 24 26 28 30 32 34 36 38 40
τi {1} {0, 1} {1, 2} 0 2 0 1 1 0 1 2 2 1 0 2 1 1 0 1 0 1 0 2 0 2 1 2 0 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 2 ⎛0 1 ⎞ 0 0 ⎝1 2⎠ ⎛2 1⎞ 0 1 ⎝1 0⎠ 2 2
2 0 2 1 0 2 0 1 1 2 0 1 0 1 2 0 0 1 0 1 0 2
1 0 2 1 2 1 2 0 1 2 2 1 1 0 2 0
2 0 0 2 1 2
2 0 2 1
2 and P 3 20.4 The Maximal Partial Classes of P i τ⎛i 41 ⎝ ⎛ 43 ⎝ ⎛ 45 ⎝ ⎛ 47 ⎝
i 49 50 51 52 53 54 55 56 57
0 1 2 0 0 0 0 0 0 0 0 0
1 2 0 1 1 1 1 1 1 1 1 1
2 0 1 2 2 2 2 2 2 2 2 2
Table 20.2 i τ⎛i ⎞ 0 0 ⎠ 42 ⎝ 1 2 ⎛2 1 ⎞ 0 0 1 1⎠ 44 ⎝ 0 1 2 ⎞ ⎛0 1 0 2 0 1 1 1⎠ 46 ⎝ 0 1 2 0 ⎞ ⎛0 1 0 1 2 0 1 1 2 0 ⎠ 48 ⎝ 0 1 2 0 1 0 1
1 0 2 2 2 2 2 2 2 2 2 2
1 2 0 0 1 2 0 1 2 0 1 2
2 0 1 0 2 1 1 0 2 0 2 1
609
⎞ 2 1⎠ 0 ⎞ ⎠ ⎞ ⎠ ⎞ 1 1 2 2 0 2 0 1⎠ 2 0 1 0
Table 20.3 τi { (0, 1, 2), (a, a, b) | a, b ∈ E3 } { (0, 1, 2), (a, b, a) | a, b ∈ E3 } { (0, 1, 2), (b, a, a) | a, b ∈ E3 } { (0, 1, 2), (1, 0, 2), (a, a, b) | a, b ∈ E3 } { (0, 1, 2), (2, 1, 0), (a, b, a) | a, b ∈ E3 } { (0, 1, 2), (0, 2, 1), (b, a, a) | a, b ∈ E3 } { (a, a, b, b), (a, b, a, b) | a, b ∈ E3 } { (a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ E3 } { (a, b, c) ∈ E33 | |{a, b, c}| ≤ 2 }
Lemma 20.4.5 (1) For every ∈ {{0}, {1}, {(0, 1)}, {(0, 1), (1, 0)}, {(0, 0), (0, 1), (1, 1)}, λ2 := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ E2 }, G2 ([P21 ])}, the set pP Ol2 is 2 . a maximal class of P (2) The classes pP OL3 τi (i ∈ {1, 2, ..., 57}, see Tables 20.1 - 20.3) are maximal classes of P3 . Proof. (1): The maximality of pP OL2 for ∈ {λ2 , G2 ([P21 ])} was proven in Lemma 20.4.3. 2 : Let f n ∈ Next we show that pP OL2 {(0, 1)} is a maximal class of P n−1 1 P2 \ pP OL2 {(0, 1)} be arbitrary. Then ∆ f ∈ {c0 , c1 , e1 }. We distinguish two cases: Case 1: ca ∈ [f ] for certain a ∈ E2 . The unary function g with g(a) = a and g(a) = ∞ belongs to pP OL2 {(0, 1)}, whereby {c0 , c1 } ⊂ [{f } ∪ pP OL2 {(0, 1)}]. With the aid of Theorem 3.2.4.1, it is easy to prove that P2 = [(T0 ∩ T1 ) ∪ {c0 , c1 }] ⊆ [{f } ∪ pP OL2 {(0, 1)}].
610
20 Partial Function Algebras
Further, we have pP OL2 {(0, 1)} ⊆ P2 ∪ [c∞ ]. Therefore, by Lemma 20.4.2, 2 holds, i.e., pP OL2 {(0, 1)} is a maximal class of [{f } ∪ pP OL2 {(0, 1)}] = P P2 . Case 2: e11 ∈ [f ]. In this case, by Theorem 3.2.4.1, P2 = [(T0 ∩T1 )∪{e11 }] ⊆ [{f }∪pP OL2 {(0, 1)}], whereby Case 2 is reducible to Case 1. The maximality of the other classes pP OL2 is easy to check. (2): For i ∈ {1, 2, ..., 54} one can easily prove the lemma with the help of Lemma 20.4.4. If i ∈ {55, 56, 57}, the above statement follows from Lemma 20.4.3. Theorem 20.4.6 ([Fre 66]) 2 has exactly 8 maximal classes: P pP OL2 σi , where σ0 := {0}, σ1 := {1}, σ2 := {(0, 1)}, σ3 := {(0, 1), (1, 0)}, σ4 := {(0, 0), (0, 1), (1, 1)}, σ5 := G2 ([P21 ]) = {(a, a, b, b), (a, b, a, b) | a, b ∈ E2 } and σ6 := {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ E2 }, and P2 ∪ [c∞ ] = pP ol2 (Ek2 ∪ {(∞, ∞)}). Proof. Because of Lemmas 20.4.2 and 20.4.5, we must show that each subset 2 , which fulfills A ⊆ pP OL3 τi for all i ∈ {0, 1, 2, ..., 6} and A ⊆ P2 ∪[c∞ ], A of P 2 . is complete in P Let A ⊆ P2 be an arbitrary set, for which there are f0 , ..., f6 , f7 ∈ A with fi ∈ pP OL2 σi (i = 0, 1, ..., 6) and f7 ∈ P2 ∪ [c∞ ]. 2 defined by g(x) := f2 (x, x, ..., x). Then g ∈ [A] and g ∈ {c0 , c1 , e1 }. Let g ∈ P 1 Consequently, since c1 ∈ [f0 , c0 ], c0 ∈ [f1 , c1 ], {c0 , c1 , e11 } ⊂ [f3 , e11 ] and e11 ∈ [c0 , c1 , f4 ], we have P21 ⊂ [A]. Thus there exists a function h ∈ [{f5 }∪P21 ] ⊆ [A] with h ∈ P2 \ [P21 ]. We distinguish two cases: Case 1: h is non-linear. In this case, by Theorem 3.2.4.1, we have [P21 ∪ {h}] = P2 ⊆ [A]. Because of 2 . A ⊆ P2 ∪ [c∞ ] and Lemma 20.4.2, this implies [A] = P 1 Case 2: h ∈ [P2 ] is a linear function. Then it is easy to check that all binary linear functions belong to [A], whereby (by f6 ∈ A) a non-linear function of P2 is a superposition over A. Thus Case 2 is reducible to Case 1. Theorem 20.4.7 ([Lau 77], [Rom 80]) 3 has exactly 58 maximal classes. These classes are the sets pP OL3 τi (i = P 1, 2, 3, ..., 57), where τi are given in Tables 20.1–20.3, and the set P2 ∪ [c∞ ].
2 and P 3 20.4 The Maximal Partial Classes of P
611
Proof.2 Because of Lemmas 20.4.2 and 20.4.5, we must show that each subset M
3 , which fulfills M ⊆ pP OL3 τi for all i ∈ {1, 2, ..., 57} and M ⊆ P2 ∪ [c∞ ], is of P 3 . complete in P 3 be an arbitrary set that fulfills M ⊆ P2 ∪ [c∞ ] and M ⊆ pP OL3 τi for Let M ⊆ P all i ∈ {1, 2, ..., 57}). Consequently, there are functions fini ∈ M \ pP OL3 τi for all i = 1, 2, ..., 57) and f58 ∈ M \ (P2 ∪ [c∞ ]). If τi = (σ1 σ2 ... σmi ) (i ∈ {1, 2, ..., 57}) is an hi -ary relation, then we can assume w.l.o.g. ni = mi and fi (σ1 , σ2 , ..., σmi ) ∈ E3hi \τi . As already mentioned, we must show that [M ] = P3 . First we prove {c0 , c1 , c2 } ⊆ [M ].
(20.3)
The function f37 is unary and belongs to P31 \{s1 }. Then the following three cases are possible: Case 1: f37 = ca (a ∈ E3 ). Obviously, we have {c0 , c1 , c2 } ⊆ [{f37 , f1 , f2 , ..., f6 }] in this case. Case 2: |Im(f37 )| = 2. W.l.o.g. let Im(f37 ) = {0, 1}, i.e., f37 ∈ {j0 , j1 , ..., j5 }. Because of j2 ∗ j2 = c0 , j0 ∗ j0 = j5 , j3 ∗ j3 = c1 , j4 ∗ j4 = j1 and Case 1 it is sufficient to assume that f37 ∈ {j1 , j5 }. 2.1: f37 = j1 . We form f7 := f7 ∗ j1 ∈ {c0 , c1 , c2 , j4 , u1 , u4 , v1 , v4 }. Because of Case 1, u1 ∗ u1 = c0 , v1 ∗ v1 = v4 and u4 ∗ u4 = c2 , we can confine ourselves to f7 ∈ {j4 , v4 }. 2.1.1: f7 = j4 . Putting the functions f37 (= j1 ) and f7 (= j4 ) into f10 provides a unary function (x) := f10 (j1 (x), j4 (x)) with f10 ∈ {c0 , c1 , c2 , u1 , u4 , v1 , v4 }. Because of u1 ∗ u1 = f10 = v4 . It c0 , u4 ∗ u4 = c2 and v1 ∗ v1 = v4 we still have to examine the case f10 (x) := f17 (j1 (x), j4 (x), v1 (x), v4 (x)), then f17 ∈ holds v4 ∗ j4 = v1 . If we form f17 {c0 , c1 , c2 , u1 , u4 } holds and f17 ∗ f17 is a constant function. With that we have reduced the Case 2.1.1 to the first case. 2.1.2: f7 = v4 . (x) := f14 (j1 (x), v4 (x)) belongs to {c0 , c1 , c2 , j4 , u1 , u4 , v1 }. Because The function f14 of u1 ∗ u1 = c0 , u4 ∗ u4 = c2 , j1 ∗ v1 = j4 and by Case 2.1.1, we reduce Case 2.1.2 to the first case. 2.2: f37 = j5 . In this case, one can proceed to Case 2.1 analogously using the function f16 instead of f17 and f13 instead of f14 . Case 3: |Im(f37 )| = 3 and f37 = s1 . With the help of functions f38 , ..., f42 , this case is reduced at first to Case 1 or 2 and, therefore, to Case 1. Consequently, the constant functions belong to [M ]. Let f43 (x) := f43 (c0 (x), c1 (x), c2 (x), x). This function belongs to P31 ∩ [M ] and has is a permutation, then with the help of functions at least two different values. If f43 2
The definitions of the following unary functions of P3 are in Chapter 15, Table 15.1.
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20 Partial Function Algebras
f44 , ..., f48 , we can form a function with 2-element range. Thus w.l.o.g. we can ) = E2 in the following; i.e., f43 ∈ {j0 , j1 , ..., j5 }. assume Im(f43 Let Ma,b := {f ∈ P31 | f (a) = f (b)}. Next
∃ a, b ∈ E3 : a = b ∧ Ma,b ⊂ [M ]
(20.4)
shall be proven. Because of j0 ∗ j0 = j5 , j4 ∗ j4 = j1 and for reasons of the duality, ∈ {j1 , j2 }. we can assume that f43 Case 1: f43 = j1 . ∈ {j4 , u1 , u4 , v1 , v4 } as a superposition over the constant functions, One receives f19 j1 and f19 . Because of v1 ∗ v1 = v4 and f22 (c0 , c1 , c2 , j1 , j4 ) ∈ {u1 , u4 , v1 , v4 } we can ∈ {u1 , u4 , v4 }. assume f19 = u1 . 1.1: f19 (x) := f25 (c0 (x), c1 (x), c2 (x), j1 (x), u1 (x)) In this case, we can form a function f25 ∈ {j4 , u4 , v4 }. with f25 ∈ {j4 , u4 , v1 , v4 }. Further, we can assume w.l.o.g. f25 1.1.1: f25 = j4 . := f34 (c0 , c1 , c2 , j1 , j4 , It holds that u1 ∗j4 = u4 . Consequently, the unary function f34 u1 , u4 ) ∈ {v1 , v4 } is a superposition over M . Thus by v1 ∗ v1 = v4 and v4 ∗ j4 = v1 it holds: {c0 , c1 , c2 , j1 , j4 , u1 , u4 , v1 , v4 } = {f ∈ P31 | f (0) = f (2)} ⊂ [M ]. = u4 . 1.1.2: f25 := f23 (c0 , c1 , c2 , u1 , u4 ) we have f23 ∈ {j1 , j4 , v1 , v4 }. Because For the function f23 of v1 ∗ v1 = v4 and j4 ∗ j4 = j1 , we can assume f23 ∈ {j1 , v4 }. = j1 . 1.1.2.1: f23 When one substitutes u1 instead of u4 and u4 instead of u1 into f23 , one receives = j4 instead of f23 . Now one can continue the proof as in Case 1.1.1. f23 1.1.2.2: f23 = v4 . When one substitutes u1 instead of u4 and u4 instead of u1 into f23 , one receives the = v1 instead of f23 . Further, we have f36 := f36 (c0 , c1 , c2 , u1 , u4 , v1 , v4 ) ∈ function f23 = j1 , we substitute u1 instead of u4 , u4 instead of u1 , v1 instead of {j1 , j4 }. If f36 = j4 instead of f36 . v4 and v4 instead of v1 into f36 and we receive the function f36 Thus Case 1.1.2.2 was also reduced to Case 1.1.1. = v4 . 1.1.3: f13 := f31 (c0 , c1 , c2 , j1 , u1 , v4 ) ∈ {j4 , u4 , v1 } is a superposition over M . BeThen, f31 cause of j1 ∗ v1 = j4 , this case is reducible to Cases 1.1.1 and 1.1.2. = u4 . 1.2: f19 := f28 (c0 , c1 , c2 , j1 , u4 ) ∈ {j4 , u1 , v1 , v4 } or w.l.o.g. (by v1 ∗ v1 = v4 We can form f28 and u4 ∗ j4 = u1 ) f28 ∈ {u1 , v4 }. 1.2.1: f28 = u1 . In this case, one can continue the proof as in Case 1.1. = v4 . 1.2.2: f28 := f32 (c0 , c1 , c2 , j1 , v4 , u4 ) ∈ {j4 , u1 , v1 }. Because of v4 ∗ j4 = v1 Here we have f32 and u4 ∗ v1 = u1 we can assume f32 = u1 . Thus Case 1.2 is reducible to Case 1.1. 1.3: f19 = v4 . := f26 (c0 , c1 , c2 , j1 , v4 ). Then, f26 ∈ {j4 , u1 , u4 , v1 } or w.l.o.g. (by We form f26 v4 ∗ j4 = v1 ) f26 ∈ {u1 , u4 , v1 }. ∈ {u1 , u4 }. 1.3.1: f26 Continuation of the proof as in Cases 1.1 or 1.2.
2 and P 3 20.4 The Maximal Partial Classes of P
613
1.3.2: f26 = v1 . := f35 (c0 , c1 , c2 , j1 , It holds that j1 ∗v1 = j4 . Consequently, we can form a function f35 j4 , v1 , v4 ) ∈ {u1 , u4 }; i.e., Case 1.3.2 is reducible to Cases 1.1 and 1.2. Hence, we have proven (20.4) in Case 1. = j2 . Case 2: f43 Then f19 := f19 (c0 , c1 , c2 , j2 ) ∈ {j3 , u2 , u3 , v2 , v3 }. Because of u3 ∗ u3 = u2 and ∈ {j3 , u2 , v2 }. v3 ∗ v3 = v2 let w.l.o.g. f19 = j3 . 2.1: f19 := f22 (c0 , c1 , c2 , j2 , j3 ) and f22 := f22 (c0 , c1 , c2 , j3 , j2 ). Then {f22 , f22 } ∈ Set f22 {{u2 , u3 }, {v2 , v3 }} and {u2 , u3 , v2 , v3 } ⊆ [{f22 , f22 , j2 , j3 , f34 , f35 }]. Thus M0,1 ⊆ [M ] is proven. = u2 . 2.2: f19 := f25 (c0 , c1 , c2 , j2 , u2 ) ∈ {j3 , u3 , v2 , v3 }. Because of j2 ∗ u3 = j3 , Here we have f25 = v2 . Since f33 (c0 , c1 , c2 , j2 , u2 , v2 ) ∈ v3 ∗ v3 = v2 and Case 2.1 we can assume f25 {j3 , u3 , v3 }, j2 ∗ u3 = j3 and j2 ∗ v3 = j3 , Case 2.2 is reducible to Case 2.1. = v2 . 2.3: f19 Analogously to 2.2.
Thus (20.4) is proven. Therefore, w.l.o.g. we can assume M0,1 := { f ∈ P31 | f (0) = f (1) } = {c0 , c1 , c2 , j2 , j3 , u2 , u3 , v2 , v3 } ⊂ [M ].
(20.5)
By substituting the functions of M01 and identifying variables in f49 , one can form ∈ P31 with f49 (0) = f49 (1) and f49 = s1 . a function f49 Case 1: |Im(f49 )| = 2. In this case it is easy to check that M0,1 ∪ Ma,b ⊂ [M ] for a certain (a, b) ∈ {(0, 2), (1, 2)}. W.l.o.g. let (a, b) = (1, 2). Further, by (20.4) w.l.o.g. we can assume that, for certain α, β, γ, δ ∈ E3 , ⎛ ⎞ α γ ⎜α δ ⎟ 4 ⎟ f55 ⎜ ⎝ β γ ⎠ ∈ E3 \τ55 β δ holds. Then we can form the function f55 (x, y) := f55 (x), g2 (y)) (g1 g1 ∈ [M ], where 0 0 α and g2 are certain functions of M0,1 ∪ M1,2 with g1 = = and g2 1 1 β γ ∈ P3 \[P31 ]. . Obviously, f55 δ If |Im(f55 )| = 3, then it follows from Lemma 20.4.1, (c) that P3 ⊆ [M ]. This implies 3 with the help of Lemma 20.4.2, (a) and f58 ∈ P 3 \(P3 ∪ [{c∞ }]). [M ] = P Let )| = 2 (20.6) |Im(f55
be in the following. Because of Lemma 20.4.1, (b) there are certain a1 , a2 , a3 , b1 , b2 , b3 ∈ E3 with ⎛ ⎞ ⎛ ⎞ a 1 a2 a3 f55 ⎝ b1 a2 ⎠ = ⎝ b3 ⎠ , a1 b 2 b3
614
20 Partial Function Algebras
where a3 = b3 . By substituting functions of M0,1 ∪ M1,2 (⊂ [M ]) into f55 , one can form a unary function f55 with the property: M0,2 ⊆ [{f55 } ∪ M0,1 ∪ M1,2 ]. Then, with the help of function f57 ∈ M and Lemma 20.4.1, (a), it follows P31 ⊂ [M ]. By Lemma 20.4.3, (a) we have then P ol3 τ56 ⊆ [M ]. With the help of functions f56 and f57 of M , it is easy to prove that all functions of P3 are superpositions on M . Because of f58 ∈ M and Lemma 20.4.2, (a), this implies [M ] = P3 . )| = 3. Case 2: |Im(f49 In this case, f49 is a permutation = s1 . If f49 = s3 , then, because of (20.5), one can form a certain unary function g with g(0) = g(1) as a superposition over M and one continues to be able to use the proof as in the first case. = s3 , then it is possible to form a unary function h ∈ [M0,1 ∪ {f52 }](⊂ [M ]), If f49 which is either a permutation ∈ {s1 , s3 } or h is a function with |Im(h)| = 2 and h ∈ M0,1 . Consequently, one can completely reduce the second case to the first case.
Next, some remarks on partial Sheffer functions: k is called Sheffer iff [f ] = P k . A partial function f ∈ P In [Had-R 91] all partial Sheffer functions for k = 2 and all binary Sheffer function for k = 3 were described. Further, the statement 2 ⇐⇒ [f ] = P (∀A ∈ {pP OL2 {0}, pP OL2 {1}, pP OL2 {(0, 1), (1, 0)}, P2 ∪ [c∞ ]} : f ∈ A) was proven. In [Had-L 2006] one finds the proof of the following criterion: 3 ⇐⇒ [f ] = P (∀A ∈ {pP OL3 τi | i ∈ {1, 2, 3, 4, 5, 6, 10, 11, 12, 16, 17, 18, 19, 20, 21, 22, 23, 24, 41, 42, 47, 48, 55, 56, 57}} ∪ {P2 ∪ [c∞ ]} : f ∈ A), where the relations τi are defined in Tables 20.1–20.3. In [Had-L 2006] one finds also the proof that it is not possible to reduce the conditions from the above criteria; i.e., these conditions are independent of each other.
k 20.5 The Completeness Criterion for P In analog mode to the sixth chapter, one can show that a completeness critek . Subsequently, k can be found using the maximal partial classes of P rion for P the maximal partial classes are described in a form found by L. Haddad and I. G. Rosenberg. The following definitions are needed: Definitions Let Eqh be the set of all equivalence relations over {1, ..., h}. An h-ary relation ⊆ Ekh is called • areflexive, if ∩δε = ∅ for every ε ∈ Eqh , ε = ι2h , i.e., for all (x1 , . . . , xh ) ∈ we have xi = xj for all 1 ≤ i < j ≤ h.
k 20.5 The Completeness Criterion for P
615
• quasi-diagonal, if = σ ∪ δε , where σ is a nonempty areflexive relation, ε ∈ Eqh \ {ι2h } holds, and further = Ek2 for h = 2. Furthermore 1 := = 2 := :=
{(a, a, b, b), (a, b, a, b) | a, b ∈ Ek } δ{1,2},{3,4} ∪ δ{1,3},{2,4} , {(a, a, b, b), (a, b, a, b), (a, b, b, a) | a, b ∈ Ek } δ{1,2},{3,4} ∪ δ{1,3},{2,4} ∪ δ{1,4},{2,3} .
In the following, denote an h-ary relation of the form =σ∪( (δε )), ε∈F
where σ is an areflexive h-ary relation and F ⊂ Eqh . Let Gσ : = {π ∈ Sh | σ ∩ σ (π) = ∅}, where Sh denotes the set of all permutations over the set {1, ..., h} and σ (π) := {(aπ(1) , ..., aπ(h) ) | (a1 , ..., ah ) ∈ σ}. The model of is the h-ary relation M () : = {(π(1), . . . , π(h)) | π ∈ Gσ } ( {(x1 , . . . , xh ) ∈ {1, . . . , h}h | ε∈F
(i, j) ∈ ε ⇒ xi = xj })
on the set {1, . . . , h}.3 Suppose h, F , and σ fulfill exactly one of the following five conditions: i) h ≥ 2, F = ∅ and σ = ∅, i.e., is a nonempty h-ary areflexive relation; ii) h ≥ 2, F = {ε}, where ε = ι2h , σ = ∅ and σ ∪ δε = Ek2 , i.e., is a trivial quasi-diagonale h-ary relation; iii) h = 4 and F = {{{1, 2}, {3, 4}}, {{1, 3}, {2, 4}}, {{1, 4}, {2, 3}}}, i.e., = σ ∪ 2 , where σ is an areflexive 4-ary relation (the empty set is possible); iv) h = 4 and F = {{{1, 2}, {3, 4}}, {{1, 3}, {2, 4}}}, i.e., = σ ∪ 1 , where σ is an areflexive 4-ary relation (= ∅ is possible); v) h = 2, h ≤ k, F = {i, j} and = Ekh , i.e., is a totally reflexive 1≤ij≤h
and totally symmetric not trivial relation.4 We say that is coherent, iff 3 4
In some papers the set Eh is elected instead of {1..., h} in defining the model. For h = 1 we have ∅ ⊂ ⊂ Ek .
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20 Partial Function Algebras
(1) Gσ = {π ∈ Sh | σ (π) = σ} and π(ε) := {(π(x), π(y)) | (x, y) ∈ ε} = ε for all π ∈ Gσ , if fulfills either the above condition i) or ii), Gσ = {π ∈ Sh | σ (π) = σ} ∪ {π ∈ Sh | π(F ) = F }, if fulfills iii) or iv), Gσ = {π ∈ Sh | σ (π) = σ} = Sh , if fulfills the condition v), and (2) for every nonempty subset σ of σ there exists a relational homomorphism γ : Ek → {1, . . . , h} of σ in M (), such that (γ(i1 ), . . . , γ(ih )) = (1, . . . , h) for at least an h-tuple (i1 , . . . , ih ) ∈ σ . Theorem 20.5.1 (Haddad-Rosenberg Theorem; [Had-R 89], [Had-R 92]; without proof) k there is a maximal parLet k ≥ 2. For every proper partial subclass A of P k , then either tial clone that contains A. If C is a maximal partial clone of P 2 C = Pk ∪ {f ∈ Pk | D(f ) = ∅} (= pP olk Ek ∪ {(∞, ∞)}) or C = pP OLk , where is one of the following relations: (1) an h-ary not trivial totally reflexive and totally symmetric relation with 1 ≤ h ≤ k; (2) an h-ary areflexive or quasidiagonal relation with h ≥ 2, which is coherent; (3) a quaternary relation 2 or 1 ; (4) a quaternary coherent relation σ ∪ τi , where i ∈ {1, 2} and σ = ∅ is a quaternary areflexive relation. max be the set of all relations (∈ Rk ) given in the above theorem. Then Let R the following theorem is a consequence of the above: k ; [Had-R 92]) Theorem 20.5.2 (Completeness Criterion for P k if and only if C ⊆ pP OLk for all ∈ R max and k . Then [C] = P Let C ⊆ P C ⊆ Pk ∪ {f ∈ Pk | D(f ) = ∅}.
20.6 Some Properties of the Maximal Partial Clones k of P We show first that each maximal clone of Pk is a subset of exactly a k . Then we specify the relations ∈ Rmax := maximal partial clone of P Mk ∪ Uk ∪ Sk ∪ Lk ∪ Ck ∪ Bk , with the property that pP OLk is a maximal k . partial clone of P A survey of the orders of the maximal partial clones forms the end of this section.
k 20.6 Some Properties of the Maximal Partial Clones of P
617
Next to the notations from the fifth chapter, we still need the following notations for certain relation sets: Let Pk,p be the set of all fixed-point-free permutations on Ek whose cycles have the same prim number length p. Let Sk,p := { {(x, s(x)) | x ∈ Ek } | s ∈ Pk,p } and let M k be the set of all ∈ Mk with the property that (Ek ; ) is a lattice. Theorem 20.6.1 For every maximal clone C ⊆ Pk there is exactly one maxk with C ∩ Pk = C. imal partial clone C ⊆ P k . Put Proof. Let C be a partial clone of P 2 := C n≥1 {f ∈ Pk | ∀f1 , . . . , fn ∈ C ∩ Pk :
(f (f1 , . . . , fn ) ∈ Pk =⇒ f (f1 , . . . , fn ) ∈ C) }. It was already shown Notice that C ∩ Pk2 = ∅. As C is a partial clone, C ⊆ C. is a partial clone with the following property: in [Fre 66] that C = P k . k =⇒ C C = P Consequently, if C is a maximal partial clone, then C = C.
(20.7)
Let M be a maximal clone of Pk and let C1 , C2 be two maximal partial clones )1 and C2 = C )2 . From M = Pk of Pk that contain M . Then, by (20.7) C1 = C 2 and [Pk ] = Pk (see Theorem 1.4.2), we have M 2 = (C1 ∩ Pk )2 = (C2 ∩ P2 )2 ⊂ Pk2 . )2 and by (20.7), C1 = C2 . we have C )1 = C By definition of C, Theorem 20.6.2 ([Had-L 2000]; without proof ) (1) Let M := Ck ∪ Mk ∪ Sk ∪ Uk ∪ Lk ∪ Bk and M1 := Sk \Sk,2 . For every k . ∈ M \ (Lk ∪ M1 ) the set pP OLk is a maximal partial clone of P (2) For s ∈ Pk,p with p ≥ 3 let so := {(x, s(x)) | x ∈ Ek } s := {(x, s(x), s2 (x), . . . , sp−1 (x)) | x ∈ Ek }. Then pP OLk s is a maximal partial clone that properly contains the partial clone pP OLk s0 .
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20 Partial Function Algebras
We need the following notations for the statement still missing on classes of type L. Let p ∈ P, m ∈ N and W := Epm . As shown in Section 5.2.4, a maximal class of Ppm of type L is isomorphic to the set LW . The set LW one can also describe in the form P olW λ with λ := {(a, b, c, d) ∈ (Epm )4 | a ⊕ b = c ⊕ d}, where (a1 , ..., am ) ⊕ (b1 , ..., bm ) := (a1 + b1 , ..., am + bm ) and + is the addition modulo p. With the help of ⊕ and (α(a1 , ..., am ) := (α·a1 (mod p), ..., α·am (mod p)) for α ∈ Ep and (a1 , ..., am ) ∈ W ) we can define the following p-ary relation over W : λp := {(a, a ⊕ b, a ⊕ 2 b, ..., a ⊕ (p − 1) b) | a, b ∈ W }. Theorem 20.6.3 ([Had-L 2000]; without proof ) + For p ∈ P the partial clone pP OLW λp is a maximal clone of P W that properly contains the partial clone pP OLW λ. Now, we come to some theorems that deal with the finite generating of partial clones. 2 has partial subclasses, which are not It was shown already in [Fre 66] that P finitely generating. In [Lau 88], it was proven that there are maximal partial 2 that are not finitely generating. These are exactly the partial clones of P clones pP OL2 with ∈ {λ2 , G2 ([P21 ])} (see also [B¨or-H 97]). The order of 2 agrees with the order of each finite generating maximal partial clone C of P C ∩ P2 . We need the following concept for the following criterion about the finite generating of strong partial clones: Let r > 0 and let C be a clone of Pk . Then C is called r-separable, if for every n > 0 and every b ∈ Ekn there are certain n-ary functions g1 , ..., gr ∈ C such that the mapping g : Ekn −→ Ekr with g(a) := (g1 (a), ..., gr (a)) has the property g −1 (g(b)) = {b} for all b ∈ Ekn . Theorem 20.6.4 ([B¨ or-H 97]; without proof ) Let C ⊆ Pk be a clone. Then the partial clone Str(C) is finitely generated if and only if C is finitely generated and there is an r ∈ N such that C is r-separable. If C r-separable and finitely generated, then ord(Str(C)) ≤ max{ord(C), r}.
Theorem 20.6.5 ([Noz-L 97], [Had-L 2000]; without proof ) Let k ≥ 3. Then (1) For every ∈ Mk ∪ Uk ∪ C1k ∪ C2k it holds ord(pP OLk ) = 2.
20.7 Intervals of Partial Clones That Contain a Maximal Clone
619
(2) For every ∈ Chk with 3 ≤ h ≤ k − 1 it holds ord(pP OLk ) ≤ h. (3) For every ∈ Mk ∪ Bk it holds ord(Str(P ol )) = 2. (4) ord(pP OLk s ) = 2 (see Theorem 20.6.2).
20.7 Intervals of Partial Clones That Contain a Maximal Clone Since there are many results about subclasses of Pk , it is obvious to classify k after Pk ∩ C. For an arbitrary subclass A of Pk : the subclasses C of P k | [F ] = F ∧ F ∩ Pk = A}. I(A) := {F ⊆ P This section aims to obtain cardinality statements over the sets I(A) for the maximal clones A of Pk . First, however, some general properties of the set I(A): Lemma 20.7.1 ([Str 97]; without proof ) Let A ⊆ Pk be a clone. Then (1) I(A) contains the partial clones A ∪ C∞ and Str(A) as well all partial clones of the form pP OLk with P olk = A. (2) If A is finitely generated with ord A = n, then pP OLk Gn (A) is the greatest element in the lattice (I(A); ⊆). Now we obtain from (2) of the above lemma: Theorem 20.7.2 If A is a finitely generated clone on Ek of the order n, then I(A) is exactly the interval [A, pP OLk Gn (A)] of the lattice of all partial k . clones of P Lemma 20.7.3 Let A = [A] ⊆ Pk . Then (1) A is a maximal subclass of A ∪ C∞ . (2) If {c10 , . . . , c1k−1 } ⊂ A then A ∪ C∞ ⊆ B for all B ∈ I(A)\{A}. Proof. (1) is clear. (2): Let B ∈ I(A)\{A}. If B = A ∪ C∞ , we do not have to prove anything. Otherwise, there is a function f n ∈ B \(A ∪ C∞ ). Let f (a1 , . . . , an ) = ∞. Now c1∞ = f (c1a1 , . . . , c1an ) ∈ B and from this one can easily verify that C∞ ⊆ B. Theorem 20.7.4 ([Had-L-R 2002; without proof ) Let ∅ = ⊂ Ek , T := P olk and k | f (n ) = {∞} }. {f n ∈ P T∞ := n≥1
Then I(T ) consists exactly of the partial clones:
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20 Partial Function Algebras
T , T ∪ C∞ , pP olk , T ∪ T∞ , pP olk ∪ C∞ , pP olk ∪ T∞ , pPOL k . The partial clones are pairwise distinct for || > 1 whereas for || = 1 pP olk ∪ T∞ and pP OLk coincide. Their inclusions are shown in Figure 20.1. pP OLk
T ∪ T∞
T ∪ C∞
T
pP olk ∪ T∞ pP olk ∪ C∞ pP olk
Fig. 20.1
Theorem 20.7.5 ([Had-L-R 2002]; without proof ) Let h ≥ 2 and ∈ Chk . Then the set I(P olk ) is a 3-element chain: P olk ⊂ (P olk ) ∪ C∞ ⊂ pP olk .
Theorem 20.7.6 ([Had-L-R 2002]; without proof ) Let ∈ Uk , X := P olk and 1 := ∪ {(∞, ∞)}. Then I(X) is a 4-element chain: X ⊂ X ∪ C∞ ⊂ pP olk 1 ⊂ P OLk . For clones M of type M, there are only partial results over I(M ). The following is one of these results: Theorem 20.7.7 ([Had-L-R 2002]; without proof ) Let ≤ ∈ Mk . Set M := P olk ≤, k }, ≤0 := ≤ ∪ {(∞, x) | x ∈ E k }, ≤1 := ≤ ∪ {(x, ∞) | x ∈ E 3 2 := {(x, y, z) ∈ Ek | x ≤ y ≤ z} ∪ {(∞, x, y), (x, y, ∞) | x, y ∈ Ek , x ≤ y}∪ ({∞} × Ek × {∞}), Mi := pP olk (≤i ) (i = 0, 1) and M2 := pP olk 2 . Then
20.7 Intervals of Partial Clones That Contain a Maximal Clone
621
{M, M ∪ C∞ , M0 , M1 , M2 , Str(M )} is the set of all partial clones from I(M ) included in Str(M ). Their inclusions are shown in Figure 20.2. Str(M ) M 2 M0 M 1 M ∪C
∞
M Because of
Fig. 20.2
Str(P olk ≤) = P olk ≤ ⇐⇒ ≤∈ M k ,
Theorem 20.7.8 follows. Theorem 20.7.8 For every ∈ M k is |I(P olk )| = 6. Next we prove that I(A) is a finite set if A is a maximal class of type S. For this, we need some notations: Let p be a prime factor of k and s ∈ Pk,p a fixed-point-free permutation on Ek comprising of cycles of the same length p. Set so := {(x, s(x)) | x ∈ Ek }, S := P olk so , s := {(x, s(x), . . . , sp−1 (x)) | x ∈ Ek } and Smax := pP OLk s . By Lemma 20.6.2, we have that Smax is the (unique) maximal partial clone containing the maximal clone P olk so . As usual, the powers of s are defined recursively by setting s0 (x) := x and si+1 (x) := s(si (x)) for all x ∈ Ek . To describe functions of Smax , we define the following relations on Ekn : x =s y :⇐⇒ (∃i ∈ {0, 1, ..., p − 1} : si (x) = y), where si (x) = si ((x1 , . . . , xn )) := (si (x1 ), . . . , si (xn )). The relation =s is an equivalence relation of Ekn with rn := k n /p equivalence classes (or blocks) which we denote by U1 , . . . , Urn . Fix vi ∈ Ui (i = 1, . . . , rn ) and set Vn := {v1 , v2 , . . . , vrn }. Since for all f n ∈ S, b ∈ Ekn and i ∈ Ep
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20 Partial Function Algebras
f (si (b)) = si (f (b)), each function f n ∈ S is fully determined by its values on Vn . Set p
k \E p | ∃α ∈ Ek ∀i ∈ Ep (ai = ∞ =⇒ ai = si (α)}. γ := {(a0 , . . . , ap−1 ) ∈ E k For i = 1, 2, . . . , p let the p-ary relation γi consist of all (a0 , a1 , . . . , ap−1 ) ∈ γ with exactly i coordinates ∞. Furthermore, set γ0 := s . For every I ⊆ Ep let τI := {(a0 , a1 , . . . , ap−1 ) ∈ γ | (∀i ∈ I : ai = ∞) ∧ (∀j ∈ Ep : \I aj = ∞)}. For every function f n ∈ Smax set χ (f ) := {(f (a), f (s(a)), . . . , f (sp−1 (a))) | a ∈ Vn } and
χ(f ) := {(f (a), f (s(a)), . . . , f (sp−1 (a))) | a ∈ kn }.
k with χ (f ) ⊆ χ(f ) and Notice that χ (f ) and χ(f ) are p-ary relations on E p
k \E p ) ∪ s , χ(f ) ⊆ (E k
(20.8)
and hence, in general, χ(f ) is not a subrelation of s . It is easy to check that χ(f ) = {(ai , ai+1 , . . . , ap−1 , a0 , a1 , . . . , ai−1 ) | (a0 , a1 , ..., ap−1 ) ∈ χ (f ), i ∈ Ep }. (20.9) p p Moreover, for R ⊆ (Ek \Ek ) ∪ s and α ∈ {χ , χ}, set α−1 (R) := {g ∈ Smax | α(g) ⊆ R}. Then it holds that α−1 (R) = {g ∈ Smax | ∀ r1 , . . . , rn ∈ γ0 g+ (r1 , . . . , rn ) ∈ R}. We start with Lemma 20.7.9 Let f n ∈ Smax and I, I ⊆ Ep . Then (1) Gf := {g n ∈ Str (S) | D(g) = D(f )} ⊆ [S ∪ {f }], (2) χ−1
( χ (f ) ) ⊆ [S ∪ {f }],
20.7 Intervals of Partial Clones That Contain a Maximal Clone
623
(3) (α0 , α1 , . . . , αp−1 ) ∈ χ (f ) =⇒ χ−1
( {(α1 , α2 , . . . , αp−1 , α0 )} ∪ χ (f )) ⊆ [S ∪ {f }], (4) there is a function g ∈ [S ∪ {f }] with χ (g) = χ(f ), (5) χ−1 ( χ(f ) ) ⊆ [S ∪ {f }], (6) χ(f ) ∩ τI = ∅ =⇒ χ−1 (τI ∪ χ(f )) ⊆ [S ∪ {f }], (7) (χ(f ) ∩ τI = ∅ ∧ χ(f ) ∩ τI = ∅) =⇒ χ−1 (τI∪I ∪ χ(f )) ⊆ [S ∪ {f }], p (8) (p ∈ {2, 3} ∧ j ∈ {1, . . . , p} ∧ χ(f )∩γj = ∅) =⇒ χ−1 ( i=j γi ∪χ(f )) ⊆ [S ∪ {f }], 3
3
k \E 3 ∪χ(f )) ⊆ [S∪{f }]. k \(E 3 ∪γ)) = ∅) =⇒ χ−1 (E (9) (p = 3 ∧ χ(f )∩(E k k Proof. (1): Let g n ∈ Gf and g1 ∈ S with g1|D(f ) = g. Then g = e21 (g1 , f ) ∈ [S ∪ {f }]. (2): Let g m ∈ χ−1
(χ (f )) be arbitrary. Then there is for every v ∈ Vm a bv := (bv1 , bv2 , . . . , bvn ) ∈ χ (f ) with (g(v), g(s(v)), . . . , g(sp−1 (v))) = (f (bv ), f (s(bv )), . . . , f (sp−1 (bv ))). It is easy to check that the functions gim ∈ S (i = 1, 2, . . . , n) exist with gi (v) = bvi for all i ∈ {1, . . . , n} and v ∈ Vm . Then we have that g = f (g1 , . . . , gn ) and (2) hold. (3): Let a1 , . . . , aq ∈ Vn with ai = (ai1 , ai2 , . . . , ain ) (i = 1, . . . , q), χ (f ) = {(f (ai ), f (s(ai )), . . . , f (sp−1 (ai ))) | i = 1, . . . , q} and
(f (aq ), f (s(aq )), . . . , f (sp−1 (aq ))) = (α0 , α1 , . . . , αp−1 ).
Then there exists a t ∈ N, b1 , . . . , bq+1 ∈ Vt and functions gjt ∈ S (j = 1, 2, . . . , n) with gj (bi ) := aij (i = 1, 2, ..., q, j = 1, . . . , n) and gj (bq+1 ) := s(aqj ) (j = 1, . . . , n). Let g := f (g1 , . . . , gn ). So we have g ∈ [S ∪ {f }] and it is easy to check that χ (f ) ∪ {(α1 , α2 , . . . , αp−1 , α0 )} ⊆ χ(g). Consequently, (3) follows from (2). (4) follows from (20.9) and (3). (5) follows from (4) and (2). In the following, we can assume χ (f ) = χ(f ). (6): Let (a0 , a1 , . . . , ap−1 ) ∈ χ(f ) ∩ τI . Then there exists an α ∈ Ek with ∀i ∈ Ep (ai = ∞ =⇒ ai = si (α) .
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20 Partial Function Algebras
Obviously, there are a t ∈ N, a function q t ∈ S with χ (q) = γ0 and a function h2 ∈ S with y if x ∈ {α, s(α), . . . , sp−1 (α)}, h(x, y) := x otherwise. Then n+t n+t h1 := h(f (en+t , en+t ..., en+t n ), q(en+1 , . . . , en+t )) ∈ [S ∪ {f }] 1 2
and it is easy to check that τI ∪ χ(f ) ⊆ χ(h1 ). Thus by (5) we have χ−1 (τI ∪ χ(f )) ⊆ χ−1 (χ(h1 )) ⊆ [S ∪ {f }]; i.e., (6) holds. (7): Let a1 , . . . , aq ∈ Vn with ai = (ai1 , ai2 , . . . , ain ) (i = 1, . . . , q), χ(f ) = {(f (ai ), f (s(ai )), . . . , f (sp−1 (ai ))) | i = 1, . . . , q}, (f (aq−1 ), f (s(aq−1 )), . . . , f (sp−1 (aq−1 ))) ∈ τI and
(f (aq ), f (s(aq )), . . . , f (sp−1 (aq ))) ∈ τI .
Then there exists t ∈ N, b1 , . . . , bq+1 ∈ Vt and functions gjt , htj ∈ S (j = 1, 2, . . . , n) with gj (bi ) := hj (bi ) := aij (i = 1, 2, ..., q, j = 1, . . . , n) and gj (bq+1 ) := aq−1,j , hj (bq+1 ) := aq,j (j = 1, . . . , n). Let g := e21 (f (g1 , . . . , gn ), f (h1 , . . . , hn )). Then g ∈ [S ∪{f }], and it is easy to check that χ(f ) ⊆ χ(g) and χ(g)∩τI∪I = ∅. Then, it follows from (6): χ−1 (τI∪I ∪ χ(f )) ⊆ [S ∪ {g}] ⊆ [S ∪ {f }]. (8) follows from (3) and (5)–(7). (9): Let p = 3, (a, b, ∞) ∈ χ(f ), a, b ∈ Ek and s(a) = b. Furthermore, let t ∈ N, k t /3 ≥ k 2 and {(αi , βi ) | i = 1, 2, ..., k2 } := Ek2 . Then there are c1 , . . . , ck2 ∈
:= {(a, ci ), (b, s(ci )) | i = 1, 2, . . . , k2 } with Vt with x =s y for all x, y ∈ Vt+1
⊆ Vt+1 holds, there is a x = y. Since we can choose Vt+1 such that Vt+1 t+1 ∈ S with function g ⎧ ⎨ αi if x = a, x = ci , g(x, x) := βi if x = b, x = ci , ⎩
. x if x ∈ Vt+1 \Vt+1 Then
20.7 Intervals of Partial Clones That Contain a Maximal Clone
625
n+t n+t h := g(f (en+t , . . . , en+t n ), en+1 , . . . , en+t ) ∈ [S ∪ {f }] 1
and it is easy to check that Ek2 × {∞} ∪ χ(f ) ⊆ χ(h). Then by (3) and (8) it follows that (9) holds. Theorem 20.7.10 ([Had-L-R 2002]) The set I(S) is finite. Proof. Obviously, Smax =
χ−1 (R).
(20.10)
k p \E p )∪s R⊆(E k
By Lemma 20.7.9, (5) we have χ−1 (χ(f )) ⊆ [S ∪ {f }]
(20.11)
for every function f n ∈ Smax . Let G := {χ(f ) | f ∈ Smax }. By (20.8) G is a finite set. Let C ∈ I(S). Obviously, H := {χ(f ) | f ∈ C} ⊆ G is finite. Thus H = {χ(1 ), . . . , χ(h )} for certain 1 , . . . h ∈ C. Furthermore, it holds that C ⊆ χ−1 (χ(1 )) ∪ . . . ∪ χ−1 (χ(h )), where, by (20.11), χ−1 (χ(1 ))∪. . .∪χ−1 (χ(h )) ⊆ [S∪{1 }]∪. . .∪[S∪{h }] ⊆ [S∪{1 , . . . , h }] ⊆ C. Thus C = [S ∪ {1 , . . . , h }]. Consequently, the partial clone C ∈ I(S) is generated from S and from not more than |G| functions of Smax \ S. Now we determine exactly the set I(S) for the cases p = 2 and p = 3. We begin with the case p = 2. Str(S) S ∪S 1 2 S1 S 2 S∪C
∞
S Fig. 20.3
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20 Partial Function Algebras
Theorem 20.7.11 ([Had-L-R 2002]; without proof ) Let k ≥ 2, s ∈ Pk,2 and S = P olk so . Furthermore, let S1 := χ−1 (γ0 ∪ γ2 ) and S2 := S ∪ χ−1 (γ1 ∪ γ2 ). Then
I(S) = {S, S ∪ C∞ , S1 , S2 , S1 ∪ S2 , Str(S)},
where Smax = pPOL k so = Str(S). The lattice (I(S)); ⊆) is given in Figure 20.3. Smax
Str(S) ∪ S5
S3 ∪ S5 = S1 ∪ S3 ∪ S5
Str(S)
S1 ∪ S3
S4 ∪ S5 = S 1 ∪ S4 ∪ S5
S ∪ S 1 4 S ∪ S5 = S1 ∪ S5 S1 S2 ∪ S4 S2 S4 S ∪ C∞ S3
S Fig. 20.4
Theorem 20.7.12 ([Had-L-R 2002]; without proof ) Let s ∈ Pk,3 and S = Pol k so . Furthermore, let S1 := S ∪ χ−1 (γ1 ∪ γ2 ∪ γ3 ), S2 := S ∪ χ−1 (γ2 ∪ γ3 ), 3
k \ E 3 ), S3 := χ−1 (γ0 ∪ γ2 ∪ γ3 ), S4 := χ−1 (γ0 ∪ γ3 ) and S5 := χ−1 (E k where Str(S) = χ−1 (γ0 ∪ . . . ∪ γ3 ). Then
20.8 Intervals of Boolean Partial Classes
627
I(S) = {S, S ∪ C∞ , S2 , S4 , S2 ∪ S4 , S1 , S3 , S1 ∪ S4 , S1 ∪ S3 , S ∪ S5 , S4 ∪ S5 , S3 ∪ S5 , Str (S), Str (S) ∪ S5 , Smax }. The lattice (I(S); ⊆) is given in Figure 20.4. Theorem 20.7.13 ([Ale-V 94], [B¨ or-H 98], [Had-L 2003]) For every ∈ Lk ∪ Bk , the set I(P olk ) has the cardinality of continuum. Proof. For k = 2 (and therefore = {(a, b, c, d) | a + b = c + d (mod 2)}) the theorem was proven in [Ale-V 94]. If k is an arbitrary prime number power, then |I(P olk )| = c with ∈ Lk was proven in [Had-L 2003], where the proof of the general result includes the proof from [Ale-V 94]. or-H 98]. This result and Theorem 5.2.6.1 |I(P olk ιkk )| = c was shown in [B¨ were used in [Had-L 2003] to prove the remaining statements of the theorem.
20.8 Intervals of Boolean Partial Classes In continuation of the examinations of Section 20.7, one can find cardinality statements over the set I(A) for arbitrary subclasses A of P2 in the following. For this we use the notations from Chapter 3. Theorem 20.8.1 ([Ale-V 94], [Str 97b]) Let A be a subclass of P2 with A ⊆ L or A ⊆ B ∈ {I ∪ C, D ∪ C, K ∪ C, T0,∞ , T1,∞ }. Then the set I(A) has the cardinality of continuum. Proof. For A = L, the theorem was proven by V. B. Alekzeev and L. L. Voronenko in [Ale-V 94]. By easy modification of the proof from [Ale-V 94], one gets the statements of the theorem for A ∈ {L, L ∩ T0 , L ∩ T1 , L ∩ T0 ∩ T1 }. One finds proof of the remaining statements of the theorem in [Str 97b]. Theorem 20.8.2 ([Ale-V 94], [Str 97a], [Str 95], [Str 96], [Lau 2006]) Let A be a subclass of P2 with T0 ∩ T1 ∩ M ⊆ A or T0 ∩ S ⊆ A (or T1 ∩ S ⊆ A). Then I(A) is a finite set and it holds that
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A |I(A)| P2 3 Ta (a ∈ {0, 1}) 6 M 6 S 6 T0 ∩ T1 30 Ta ∩ M (a ∈ {0, 1}) 15 T0 ∩ T1 ∩ M 101 T0 ∩ S ? < 2000 For the remaining subclasses A of Pk , i.e., M ∩ Ta ∩ Ta,∞ ⊂ A ⊆ Ta,2 for certain a ∈ E2 or A = T0 ∩ M ∩ S, it holds |I(A)| ≥ ℵ0 . 2 } and therefore |I(P2 )| = 3 follows from Proof. I(P2 ) = {P2 , P2 ∪ C∞ , P Lemma 20.4.2. The statements of the theorem over maximal classes of P2 different from L were proven by V. B. Alekzeev and L. L. Voronenko and by B. Strauch independently of each other. (see [Ale-V 94], [Str 94], [Str 97a]). Certain elements of the sets I(A) with A ∈ {T0 , T1 , S, M } were already determined in [Lau 88] 2 . On can find the description at the determination of submaximal classes of P of the elements of I(A) with A ∈ {T0 , T1 , S, M } in Theorems 20.7.4, 20.7.7, and 20.7.11. The sets I(T0 ∩ T1 ) and I(T0 ∩ M ) were determined in [Str 97a]. One can find I(M ∩ T0 ∩ T1 ) in [Str 95]. The finiteness of the set I(S ∩ T0 ∩ T1 ) was proven in [Str 96]. In [Lau 2006] it was proven that every set I(A) with A ⊆ T0,2 has infinitely many elements.
20.9 On Congruences of Partial Clones This section is a revised version of the papers [Lau-D 90] and [Lau-D 91]. For an arbitrary partial clone C, we define the following equivalence relations which – as A. I. Mal’tsev in [Mal 66] was already proving – are congruences k , are the only possible congruences (see Theorem over C and, for C = P 20.9.3): κ0 := {(f, f ) | f ∈ C} κ1 := C × C κa := {(f n , g m ) ∈ C × C | n = m} κ∞ := κ0 ∪ {(f n , g m ) ∈ C × C | D(f ) = D(g) = ∅}
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629
κ1 κa κ∞ κ0 One is easily able to transfer many results from Chapter 9 (because of results of Section 20.2) to partial clones. Therefore, only the congruences on the maximal partial clones shall be determined. For this we need the following notations, which are introduced for relations ∈ Rkh . κ1 () := κ0 ∪ {(f m , g n ) ∈ κ1 | ∀r1 , ..., rmax(m,n) ∈ : k )h \E h }, {f (r1 , ..., rm ), g(r1 , ..., rn )} ⊆ (E k κa () := κ1 () ∩ κa , U () := {α ∈ Ek | ∀(a1 , ..., ah ) ∈ : α ∈ {a1 , ..., ah }}, µ0 () := {(f m , g m ) ∈ κa | ∀a ∈ (Ek \U ())m : f (a) = g(a)}, µ() := {(f m , g m ) ∈ κa | ∀r1 , ..., rm ∈ : k )h \E h ∨ {f (r1 , ..., rm ), g(r1 , ..., rm )} ⊆ (E k f (r1 , ..., rm ) = g(r1 , ..., rm )}. Obviously, the above relations are equivalence relations with the following Hasse-diagram: κ1 κa κ1 () ∪ µ() κa () ∪ µ() κ () ∪ µ0 () 1 κa () ∪ µ0 () κ1 () κa () κ∞ κ0 Since Ek \U () = , if is a unary relation, we have in this case µ() = µ0 (). If U () = ∅, then µ0 () = κ0 . If all constant functions and a function cn∞ belong to the partial clone pP OLk , then we have κ1 () = κ∞ and κa () ∪ µ() = κ0 . The following Lemma is easy to prove.
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Lemma 20.9.1 k . Then the relations κ0 , κa , κ1 , κ∞ are congruences on C. (1) Let C ⊆ P k . Then the relations κa (), κa () ∪ (2) Let ⊆ Ekh and C := pP OLk ⊆ P µ0 (), κa () ∪ µ() κ1 (), κ1 () ∪ µ0 (), κ1 () ∪ µ() are congruences on C. k of the In the following, it shall be proven that a maximal partial clone of P form pP OLk has only those congruences given above. Then, dependently of , one has 4, 8 or 10 pairwise distinct congruences per partial clone pP OLk . Lemma 20.9.2 Let C be a partial clone on Ek and κ a congruence of C. Then (a) κ ∩ (Pk × Pk ) ⊆ κa =⇒ κ = κ1 ; (b) (c1∞ ∈ C ∧ κ ⊆ κa ) =⇒ κ∞ ⊆ κ. Proof. (a): Let κ∩(Pk ×Pk ) ⊆ κa . Then there are functions f m , g n ∈ C ∩Pk with m < n and (f, g) ∈ κ. Consequently, we have f11 := ∆n−2 f ∼ g12 := ∆n−2 g (κ) and
e22 = e22 f1 ∼ e33 = e22 g (κ).
Thus (enn , e11 ) ∈ κ for all n ≥ 1 and e11 h = h ∼ e22 h = et+1 t+1 (κ) for all ht ∈ C, i.e., κ = κ1 . (b): Let κ ⊆ κa and c∞ ∈ C. Then there are two functions f m , g n , m < n, in C with (f, g) ∈ κ. Thus (∆n−2 g) c1∞ = c2∞ ∼ (∆n−2 f ) c1∞ = c1∞ (κ). Consequently, c2∞ er1 = cr+1 ∼ c1∞ er1 = cr∞ (κ) for arbitrary r ∈ N. ∞ Therefore, κ∞ ⊆ κ. Theorem 20.9.3 ([Mal 66]) Let C be a clone with Str({ca | a ∈ Ek }) ⊂ C. Then C has exactly the following four congruences: κa , κa , κ∞ , κ1 . Proof. Let κ = κ0 be a congruence of C. Then the following cases are possible: Case 1: κ0 ⊂ κ ⊆ κa . In this case, there are two functions f m , g n ∈ C and an n-tuple a := (a1 , ..., an ) with f (ca1 , ..., can ) =: cα , g(ca1 , ..., can ) =: g , g ∈ {cβ , c∞ }, {α, β} ⊆ Ek , (cα , g ) ∈ κ and cα = g .
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Since Str({ca | a ∈ Ek }) ⊂ C, there is a function h1 ∈ C with D(h) = {α} and h(α) = α. Thus we have h c1α ∼ h g = c1∞ (κ) and e11 = ∆(e22 cα ) ∼ ∆(e22 c1∞ ) = c1∞ (κ). We obtain e11 t = t ∼ cn∞ (κ) for all tn ∈ C. Thus κa ⊆ κ and κ = κa . Case 2: κ0 ⊂ κa . Since c∞ ∈ C, it follows from Lemma 20.9.2: κ∞ ⊆ κ. Suppose, κ = κ∞ . Then there are two functions f m , g n ∈ C with m = n, {f, g} ⊆ {cn∞ | n ∈ N} and (f, g) ∈ κ. W.l.o.g. we can assume that f = cm ∞ and m < n. Let a := (a1 , ..., am ) ∈ D(f ) and f (a) = α ∈ Ek . Then (...((∆((∆((∆(f ca1 )) ca2 )) ca3 )) ca4 ))... cam = f (ca1 , ..., cam ) = cα ∼ (...((∆((∆((∆(g ca1 )) ca2 )) ca3 )) ca4 ))... cam =: g1r (κ) with r := n − m + 1. W.l.o.g. let r = 2. If g1 = c2∞ , we obtain (c1α , c1∞ ) ∈ κ and analogously to Case 1, κa ⊆ κ. κa ⊆ κ and κ∞ ⊆ κ imply κ = κ1 . If g1 = c2∞ , there exists a (b1 , b2 ) ∈ Ek2 with g1 (b1 , , b2 ) ∈ Ek and thus we have c1α = c1α (τ (cα cb1 ) cb2 ) ∼ c1α (τ (g1 cb1 ) cb2 ) = c2α (κ). By Lemma 20.9.2, (a) we get κ = κ1 . Theorem 20.9.4 ([Lau-D 90]) max \{ ∈ R max | ∅ ⊂ Let C = Pk ∪ {cn∞ | n ∈ N} or C = pP OLk with ∈ R ⊂ Ek or is a coherent areflexive relation}, where Rmax denotes the set of all relations by which a maximal partial clone pP OLk is described (see 20.5). Then C has exactly the following four congruences: κ0 , κa , κ∞ , κ1 . max \{ ∈ R max | ∅ ⊂ ⊂ Ek or is a Proof. If C = pP OLk with ∈ R coherent areflexive relation}, our theorem follows from Theorem 20.9.3. It was proven in Chapter 9 (see Theorem 9.1.2) that Pk has only the congruences κ0 , κa , κ1 . From this and from Lemma 20.9.2 follows our theorem for C = Pk ∪ {cn∞ | n ∈ N}. Lemma 20.9.5 Let κ be a congruence of pP OLk . Then (a) κ0 ⊂ κ ⊆ κa =⇒ κa () ⊆ κ, (b) κ∞ ⊂ κ =⇒ κ1 () ⊆ κ, (c) κa () ⊂ κ ⊆ κ1 () =⇒ κ = κ1 (), (d) κa () ∪ µ0 () ⊂ κ ⊆ κ1 () ∪ µ0 () =⇒ κ = κ1 () ∪ µ0 (), (e) κa () ∪ µ() ⊂ κ ⊆ κ1 () ∪ µ() =⇒ κ = κ1 () ∪ µ(). Proof. (a): Let κ0 ⊂ κ ⊆ κa . Then there are functions f n , g n with (f n , g n ) ∈ κ and certain a := (a1 , ..., an ) ∈ Ekn , a, b ∈ Ek , a = b with f (a) =: a = b := g(a). Furthermore, pP OLk contains functions tα (α ∈ Ek ) and hβ,γ (β, γ ∈ Ek ) with
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tα (x, y) := and
hβ,γ (x) :=
y if x = α, ∞ otherwise, γ if x = β, ∞ otherwise,
where, if is areflexive or {ca | a ∈ Ek } ⊂ pP OLk holds, β and γ are arbitrary elements of Ek ; otherwise we must choose, however, β ∈ {a | (a, a, ..., a) ∈ }. Thus we obtain f (hβ,a1 (x), ..., hβ,an (x)) = hβ,a (x) ∼ g(hβ,a1 (x), ..., hβ,an (x)) = hβ,b (x) (κ) and
ta (hβ,a (x), y) = tβ (x, y) ∼ ta (hβ,b (x), y) = c2∞ (x, y) (κ).
Let um be an arbitrary function from pP OLk with the property ∀(r11 , r21 , ..., rh1 ), ..., (r1n , r2n , ..., rhn ) ∈ ∃i ∈ {1, ..., h} : (ri1 , ri2 , ..., rin ) ∈ D(u). Then the function v m defined by β if u(x) ∈ Ek , v(x) := ∞ otherwise, belongs to pP OLk . Consequently, we have tβ (v(x), u(x)) = u(x) ∼ c2∞ (v(x), u(x)) = cm ∞ (x) (κ), i.e., it holds κa () ⊆ κ. (b): For κ∞ ⊂ κ and κ ∩ κa = κ0 , we have κa () ⊆ κ because of (a), since the inclusion κa () ⊆ κ follows from κ ∩ κa = κ = κ0 and since the inclusion κa () ⊆ κ follows from κ ⊆ κ. κa () ⊆ κ and κ∞ ⊆ κ imply κ1 () ⊆ , since, if (f m , g n ) ∈ κ1 () (m = n), n n the inclusions (f m , cm ∞ ) ∈ κ and (c∞ , g ) ∈ κ follow, because of κa () ⊆ κ m n and (c∞ , c∞ ) ∈ κ by κ∞ ⊆ κ. By the transitivity of κ we get (f m , g n ) ∈ κ. If κ∞ ⊂ κ and κ ∩ κa = κ0 , there are two functions sl , tr (l = r) in pP OLk with (s, t) ∈ κ. We can assume l > r and s = cl∞ , i.e., there exists an element a := (a1 , ..., al ) with s(a) ∈ Ek . We distinguish the following two cases: Case 1: For all i ∈ {1, ..., l} it holds (ai , ..., ai ) ∈ . In this case we have {ca1 , ..., cal } ⊂ pP OLk . From (s, t) ∈ κ and κ∞ ⊆ κ the existence of two κ-kongruent constant functions with different arities follows. Therefore, by Lemma 20.9.2, (a) we get (Pk ∩ pP OLk ) × (Pk ∩ pP OLk ) ⊆ κ, a contradiction to κ ∩ κa = κ0 .
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Case 2: There exists an i ∈ {1, ..., l} with (ai , ..., ai ) ∈ . W.l.o.g. we can assume (a1 , ..., a1 ) ∈ . Then the function h1a1 ,aj belongs to pP OLk for certain aj ∈ Ek , j = 1, ..., n. Further, we can assume a1 = al−r . (If a1 = al−r , then we can choose s := s e22 and t := t e2 and then use the operations ζ and τ to get functions s and t with (s , t ) ∈ κ, s (a) ∈ Ek , (a1 , ..., a1 ) ∈ and a1 = al−r ). Thus s1 := (....(ζ((ζ((ζs) ha1 ,a1 )) ha1 ,al−1 ha1 ,al−2 )) ...) ha1 ,al−r ) ∼ t1 := (....(ζ((ζ((ζt) ha1 ,a1 )) ha1 ,al−1 ha1 ,al−2 )) ...) ha1 ,al−r ) (κ) with s1 (x1 , ..., xl ) = s(xl−r+1 , ..., xl , ha1 ,al−r (x1 ), ..., ha1 ,al (xl−r )) and t1 (x1 , ..., xr ) = t(ha1 ,al−r+1 (x2 ), ..., ha1 ,al−1 (xr ), ha1 ,al (ha1 ,al−r (xl ))) = cr∞ (x), since ha1 ,al ha1 ,al−r = c1∞ and because of a1 = a1−r . From this and from κ∞ ⊆ κ, it follows that κ ∩ κa = κ0 , in contradiction to our assumption. Therefore (b) holds. (c): Let κa () ⊂ κ ⊆ κ1 (). Then κ ⊆ κa . By Lemma 20.9.2, (b) we have κ∞ ⊆ κ. From κ∞ ⊆ κ ⊆ κ1 () it follows that κ = κ∞ or κ = κ1 () (by (b)). Since the first case is not possible, (c) holds. (d) and (e) follow from (c). Lemma 20.9.6 Let ∅ ⊂ ⊂ Ek or let be an h-ary relation on Ek with the properties h ≥ 2 and ∀(a1 , ..., ah ) ∈ ∃t ∈ Pk ∩ pP OLk : Im(t) ⊆ {a1 , ..., ah }.
(20.12)
Then for an arbitrary congruence κ of pP OLk , (a) (κ ⊆ κa () ∪ µ() ∧ κ ⊆ κa ) =⇒ κ = κa , (b) (κ ⊆ κ1 () ∪ µ() ∧ κ ⊆ κa ) =⇒ κ = κ1 . (c) (κ ⊆ κa () ∧ κ ⊆ κa ) =⇒ κa () ∪ µ0 () ⊆ κ. Proof. (a): κ ⊆ κa ∪µ() and κ ⊆ κa imply that there are functions (f n , g n ) ∈ κ and a set R := {(rj1 , rj2 , ..., rjn ) | i = 1, ..., h} with {(r1i , r2i , ..., rhi ) | i = 1, ..., n} ⊆ , and 1) R ⊆ D(f ), R ⊆ D(g) and f (rj1 , rj2 , ..., rjn ) = g(rj1 , rj2 , ..., rjn ) for certain j ∈ {1, ..., h} or 2) R ⊆ D(f ) and R ⊆ D(g). The first case can be reduced to the second case as follows: Let e33 be a ternary function of pP OLk defined by
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e33 (x, y, z) =
z if x = y, ∞ otherwise.
Then e33 (f (x), f (x), f (x)) = f (x) ∼ e33 (f (x), g(x), f (x)) =: g (x) (κ) with R ⊆ D(g ). Consequently, we can assume that R ⊆ D(f ) and R ⊆ D(g). Let (a1 , ..., ah ) ∈ . Then the functions t1 , ..., th with ⎛ ⎞ ⎛ ⎞ r1i a1 ⎜ a2 ⎟ ⎜ r2i ⎟ ⎜ ⎟ ⎜ ⎟ ⎟ ⎜ ⎟ ti ⎜ ⎜ . ⎟=⎜ . ⎟ ⎝ . ⎠ ⎝ . ⎠ ah rhi and ti (x) = ∞ for x ∈ {a1 , ..., ah } (i = 1, 2, ..., n) belong to pP OLk . Then, from (f, g) ∈ κ it follows f (t1 (x), ..., tn (x)) =: f (x) ∼ g(t1 (x), ..., tn (x)) =: g (x) (κ), where {r1 , ..., rh } ⊆ D(g ) and (f (a1 ), ..., f (ah )) ∈ for all (r1 , ..., rh ) ∈ . By Lemma 20.9.2 we have κa () ⊆ κ and thus (g , c1∞ ) ∈ κ and (f , c1∞ ) ∈ κ. (20.12), implies the existence of a function t1 ∈ Pk ∩ pP OLk with Im(t1 ) ⊆ {a1 , ..., ah }. Using this function and the fact that f = f t, we obtain another function of Pk ∩ pP OLk with (f , c1∞ ) ∈ κ. Thus (∆(e22 f ), ∆(e22 c1∞ )) = (e11 , c1∞ ) ∈ κ and κ = κa . (b): It is easy to check that κ ⊆ κ1 () ∪ µ() and κ ⊆ κa imply κ ∩ κa ⊆ κa () ∪ µ(). Hence (b) follows from (a) and κ∞ ⊆ κ. (c): Obviously, (c) holds, if U () = ∅. Thus we can assume U () = ∅. Because of Lemma 20.9.5, (a) we have to show that µ0 () ⊆ κ. Let κ be a congruence of pP OLk with κ ⊆ κa and κ ⊆ κa (). Then there are two different nary functions f, g with (f, g) ∈ κ and ρj := (r1j , r2j , ..., rhj ) ∈ (j = 1, ..., n) with (ri1 , ri2 , ..., rin ) ∈ D(f ) for all i ∈ {1, ..., h} or (ri1 , ri2 , ..., rin ) ∈ D(g) for all i ∈ {1, ..., h}. We can assume that κ = κa . Then by (a) we have κ ⊆ κa () ∪ µ(), i.e., f (r1 , ..., rn ) = g(r1 , ..., rn ) holds. Because of f = g there exists an n-tuple a := (a1 , ..., an ) ∈ Ekn with f (a) = g(a). It was already shown in proof of (a) that we can assume a ∈ D(g) and a ∈ D(f ). Let (α1 , ..., αh ) ∈ and a ∈ U (). Then the functions h1 , ..., hn defined by (hi (α1 ), ...hi (αh )) = ri , hi (a) = ai and hi (x) := ∞ otherwise belong to pP OLk . By this we have f (x) := f (h1 (x), ..., hn (x)) ∼ g(h1 (x), ..., hn (x)) =: g (x) (κ), where f (αi ) = g (αi ), f (a) = f (a1 , ..., an ) and a ∈ D(g ). Obviously, if is a unary relation or because of (20.12) (if is an areflexive relation and
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h ≥ 2) pP OLk contains a function t ∈ Pk with Im(t) ⊆ {α1 , ..., αn }. Thus the function t defined by t(x) if x ∈ U (), t (x) := a otherwise, belongs to pP OLk and we get f t =: f ∼ g := g t (κ) and e22 (f (x), x) = e11 (x) ∼ e11 (x) := e22 (g (x), x) (κ) with x if x ∈ U (), e(x) := ∞ if x ∈ U (). Let pm be an arbitrary function of pP OLk and let p(x) if x ∈ (Ek \U ())m , pa (x) := a otherwise, and
p∞ (x) :=
p(x) if x ∈ (Ek \U ())m , ∞ otherwise.
From (e11 , e11 ) ∈ κ it follows e11 pa = pa ∼ e11 pa = p∞ (κ) and e22 (pa (x), p(x)) = p(x) ∼ e22 (p∞ (x), p(x)) = p∞ (x) (κ). Consequently, two m-ary functions p, q with p(x) = q(x) for x ∈ (Ek \U ())m are κ-kongruent, i.e., µ0 () ⊆ κ. Lemma 20.9.7 Let be an areflexive h-ary relation with h ≥ 2 and let (0, 1, ..., h − 1) ∈ . Further, for every (r1j , r2j , ..., rhj ) ∈ , j = 1, ..., n, there ∈ Pk ∩ pP OLk with are unary functions h1 , ..., hn (h1 (i), h2 (i), ..., hn (i)) = (ri1 , ri2 , ..., rin ) for all i ∈ {0, ..., h − 1}. Then for every congruence κ of pP OLk : (a) µ0 () ⊂ κ\κ1 () ⊆ µ() =⇒ µ() ⊆ κ; (b) κa () ∪ µ0 () ⊂ κ ⊆ κa () ∪ µ() =⇒ κ = κa () ∪ µ(); (c) κ1 () ∪ µ0 () ⊂ κ ⊆ κ1 () ∪ µ() =⇒ κ = κ1 () ∪ µ(). Proof. (a): Let κ be a congruence of pP OLk with µ0 () ⊂ κ\κ1 () ⊆ µ(). Then there are two κ-kongruent functions f n , g n , such that for certain h-tuple (r11 ..., rh1 ), ..., (r1n , ..., rhn ) ∈ there are an n-tuple (α1 , ..., αn ) ∈ Ekn and an element α ∈ Ek with f (α1 , ..., αn ) = α, (α1 , ..., αn ) ∈ D(g) and ⎛ ⎛ ⎞ ⎛ ⎞ ⎞ a1 r11 ... r1n r11 ... r1n ⎜ . ... . ⎟ ⎜ . ... . ⎟ ⎜ . ⎟ ⎜ ⎟ ⎜ ⎟ ⎟ f⎜ ⎝ . ... . ⎠ = ⎝ . ⎠ = g ⎝ . ... . ⎠ . rh1 ... rhn ah rh1 ... rhn By assumption, there are functions h1 , ...., hn ∈ Pk ∩ pP OLk with {(h1 (i), ..., hn (i)) | i ∈ Eh } = {(rj1 , rj2 , ..., rjn ) | j ∈ {1, 2, ..., h}}. Let tm be an arbitrary function of pP OLk . Then, with the help of
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Dt := ⎧ ⎛ a1 ⎪ ⎪ ⎨ ⎜ . m x ∈ Ek | ∃a1 , ..., ah : x ∈ {a1 , ..., ah } ∧ ⎜ ⎝ . ⎪ ⎪ ⎩ ah
⎫ ⎞ a1 ⎪ ⎪ ⎬ ⎜ . ⎟ ⎟ ⎟ ⊆ ∧ t⎜ ⎟∈ ⎝ . ⎠ ⎠ ⎪ ⎪ ⎭ ah ⎞
⎛
one can define the functions ti by ⎧ x ∈ Dt , ⎨ hi (t(x)) if if x∈ Dt ∧ x ∈ D(t), ti (x) := αi ⎩ ∞ otherwise (i = 1, 2, ..., n). These functions belong to pP OLk and we get u(f (t1 (x), ..., tn (x)) = t(x) ∼ t (x) = u(g(t1 (x), ..., tn (x)) (κ) with
u(x, y) :=
y if x ∈ {a1 , ..., ah , α}, ∞ otherwise,
and
t (x) :=
t(x) if x ∈ Dt , ∞ otherwise.
Thus µ() ⊆ κ. (b) and (c) follow from (a). Lemma 20.9.8 Let ⊆ Ekh be an areflexive coherent relation with h ≥ 2. Then (a) ∀(a1 , ..., ah ) ∈ ∃t ∈ Pk ∩ pP OLk : Im(t) ⊆ {a1 , ..., ah } and w.l.o.g. (b) one can assume that fulfills the assumptions of Lemma 20.9.7. Proof. By definition of (see Section 20.5) we can assume that there is a subgroup G of Sh and a surjective function ϕ : Ek −→ {0, 1, ..., h − 1} with the following properties: = {(π(0), π(1), ..., π(h − 1)) | π ∈ G }, is symmetric in respect to every π ∈ G and ∀(a0 , ..., ah−1 ) ∈ : (ϕ(a0 ), ..., ϕ(ah−1 )) ∈ . For an arbitrary a := (a0 , ..., ah−1 ) ∈ we consider the function ϕa : {0, 1, ..., h − 1} −→ {a0 , ..., ah−1 } with ϕa (i) = ai for all i ∈ {0, ..., h − 1}. Further, let ha := ϕa ϕ. Then Im(ha ) = {a0 , ..., ah−1 } and ha ∈ pP OLk , since for every b := (b0 , .., bh−1 ) ∈ there exists a permutation πb ∈ G with ϕ(b) = (ϕ(b0 ), ..., ϕ(bh−1 )). Thus we obtain ha (b) = ϕa (ϕ(b)) = ϕa ((πb (0), ..., πb (h − 1))) = (aπb (0) , ..., aπb (h−1) ) ∈ because of symmetry of with respect to every permutation π ∈ G . Consequently, (a) and (b) hold.
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Theorem 20.9.9 ([Lau-D 91]) Let ∅ ⊂ ⊂ Ek or let ⊆ Ekh an areflexive coherent relation with h ≥ 2 and U () = ∅. Then pP OLk has exactly 8 congruences with the following congruence lattice: κ1 κa κ () ∪ µ() 1 κa () ∪ µ() κ1 () κa () κ∞ κ0
Proof. Since µ() = µ0 () for all with ∅ ⊂ ⊂ Ek and for all areflexive relations with U () = ∅, our theorem follows from Lemmas 20.9.2 and 20.9.5– 20.9.8. The following theorem also follows from Lemmas 20.9.2, 20.9.5–20.9.8: Theorem 20.9.10 ([Lau-D 91]) Let ⊆ Ekh be an areflexive relation with h ≥ 2 and U () = ∅. Then pP OLk has exactly 10 congruences, and the congruence lattice of pP OLk is given by
κa κa () ∪ µ() κa () ∪ µ0 () κa ()
κ1 κ () ∪ µ() 1 κ () ∪ µ0 () 1 κ () 1 κ∞ κ0
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[Wil 2001] Willard, R.: Extending Baker’s theorem. Conference on Lattices and Universal Algebra (Szeged, 1998), Algebra Universalis 45, No. 2–3, 335–344 (2001) [Zak 67] Zakharova, E. Yu.: Criterions of completeness of function systems from Pk (Russian). Problemy Kibernet. 18, 5–10 (1967) Zaharova, E. .: Kriterii polnoty sistem funkci iz Pk . Probl. Kibernet. 18, 5–10 (1967) [Zac-K-J 69] Zakharova, E. Yu.; Kudryavtsev, V. B.; Yablonskij, S. V.: On precomplete classes in k-valued logics (Russian). Dokl. Akad. Nauk SSSR 186, 509–512 (1969). English translation: Soviet Math. Doklady 10, 618–622 (1969) Zaharova, E. .; Kudrvcev, V. B.; blonski , S. V.: O predpolnyh klassah v k-znaqnyh logikah. Dokl. AN SSSR 186, 509–512 (1969) [Zyl 25] Zylinski, M. E.: Some remarks concerning the theory of deduction. Fund. Math. 7, 203–209 (1925)
Glossary
Ud . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 12 ∧ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ∨ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ¬ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 =⇒ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ⇐⇒ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 :=. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .17 :⇐⇒ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ∃ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ∃! . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 ∀ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 af . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 f (n) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 f n . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 D(f, A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 D(f ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 Im(f ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 (n) c∞ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 f g . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26 g1 g2 ...gr . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26 (A; f1 , ..., fr ) . . . . . . . . . . . . . . . . . . . . . . . . 26 (A; (fi )i∈I ) . . . . . . . . . . . . . . . . . . . . . . . . . . 26 τ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 f A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 fA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (C) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (E) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (I) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (D1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (D2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 (M1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 29
(M2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 29 (M3 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 29 (M4 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 29 (L1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (L2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (L3 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (L4 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (L5 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (DL1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (DL2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 (B1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 30 Ek . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 Pkn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 ζ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 τ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 ∆ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 ∇ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 [T ]A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 32 [T ]F . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .32 [T ]f1 ,...,fr . . . . . . . . . . . . . . . . . . . . . . . . . . . 32 [T ] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 32 S(A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 33 (L1 a) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L1 b) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L2 a) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L2 b) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L3 a) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L3 b) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L4 a) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (L4 b) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 (O1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36
656
Glossary
(O2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 (O3 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 (O4 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 sup Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 (S1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 (S2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 inf Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 37 (I1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 37 (I 1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 37 A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 41 A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 41 (E1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42 (E2 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42 (E3 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42 Eq(A). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .42 a = b (mod ) . . . . . . . . . . . . . . . . . . . . . . . 43 a ∼ b (mod ) . . . . . . . . . . . . . . . . . . . . . . . 43 ∇A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .43 κ1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 43 ∆A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .43 κ0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 43 A/ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 43 Π(A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 44 A∼ = B . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52 ∼ = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52 Ker ϕ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52 Con(A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52 κ0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 53 κ1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 53 κ0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 53 κ1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 53 NG . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 57 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 57 ker ϕ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 57 IR . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 58 (σ, τ ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59 (GC1) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59 (GC2) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59 ≤δ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59 pr1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61 pr2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61 S(K). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .71 H(K) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 71 P (K) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 71 I(K) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 71 XY (K) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 72 (F, τ ). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .73 T (X) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 74 T(X) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 74
T F (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 75 t < x1 , ..., xn > . . . . . . . . . . . . . . . . . . . . . . 76 s := t < t1 , ..., tn > . . . . . . . . . . . . . . . . . . 76 s ≈ t . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 76 A |= s ≈ t . . . . . . . . . . . . . . . . . . . . . . . . . . . 76 IdX (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 76 M od(Σ). . . . . . . . . . . . . . . . . . . . . . . . . . . . .77 IdX (K) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 77 ConsX (Σ) . . . . . . . . . . . . . . . . . . . . . . . . . . 77 T(X)/IdX (K) . . . . . . . . . . . . . . . . . . . . . . 79 FK (X) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 79 FK (x1 , ..., xn ) . . . . . . . . . . . . . . . . . . . . . . . 79 FK (n) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 79 FK (x1 , x2 , ...) . . . . . . . . . . . . . . . . . . . . . . . 79 FK (ℵ0 ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 79 FK (ω) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 79 R1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 82 R2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 82 R3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 82 Rep . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 82 Sub . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 82 tˆ, t ∈ P rop . . . . . . . . . . . . . . . . . . . . . . . . . . 86 Ek . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 91 PAn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 91 Pkn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 91 PA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 F n . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 Pk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 PA,B . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 Pk,l . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 PA (l). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .92 Pk (l) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 PA [l] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 Pk [l] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 x(n) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92 x. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .92 JA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 Jk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .93 cn a . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x ∧ y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x ∨ y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x + y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x ⇒ y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x ⇐⇒ y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 x · y . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 xy . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93 πs . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 94 ∆t . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 94
Glossary ∇q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 94 i . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 94 ζ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 95 τ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 95 ∆ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 95 ∇ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 95 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 95 PA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .96 f (g1 , ..., gn ) . . . . . . . . . . . . . . . . . . . . . . . . . 97 [F ] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 LA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 Lk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 L↓A (F ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 L↑A (F ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 L↑k (F ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 L↓k (F ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 LA (F ; G) . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 ord F . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 98 ord F = ∞ . . . . . . . . . . . . . . . . . . . . . . . . . . 98 ja . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 98 ja . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 98 ιhk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 101 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 101 δ{α,β} 3 δ{1,2,3} . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 101 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 103 R . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 104 P rop . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 106 v . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 106 |= . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 106 Cons(Σ) . . . . . . . . . . . . . . . . . . . . . . . . . . . 107 sub . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 107 ! . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 108 V ar . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 111 J . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .111 F ORM . . . . . . . . . . . . . . . . . . . . . . . . . . . . 111 =xk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 112 vA,u . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 112 Rkh . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 Rk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 Qh . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 h . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 δk,ε δε . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 δεh . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .126 Dkh . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 Dk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 h . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 δk;ε 1 ,...,εr δε1 ,...,εr . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 h . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 δk;
657
h δk;E . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 k ζ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 τ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 pr . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 × . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 ∧ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 Rk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 [Q] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 ! . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 127 σs (). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .128 prα1 ,...,αt () . . . . . . . . . . . . . . . . . . . . . . . . 128 ∆i,j () . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 νi () . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 ∇i . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 ◦t . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 o . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 P olk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 130 P ol . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 130 P olk Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 130 Invk f . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 130 Invk A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 131 P oln Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 131 Inv n A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 131 χk;n . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 132 χn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 132 χ(i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 133 Gn (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 133 ΓA (σ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 134 P olA Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 140 Rphk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 140 Rpk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 140 α(, ). . . . . . . . . . . . . . . . . . . . . . . . . . . . .140 ∇(, ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . 140 (, ) × (µ, µ ) . . . . . . . . . . . . . . . . . . . . . 141 E . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 141 ν1,a (, ) . . . . . . . . . . . . . . . . . . . . . . . . . . 141 ν2,a (, ) . . . . . . . . . . . . . . . . . . . . . . . . . . 141 Rpk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 141 ∆ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 142 m(x, y, z) . . . . . . . . . . . . . . . . . . . . . . . . . . 146 t(x, y) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 q(x, y, z) . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 r(x, y, z) . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 hµ (x1 , ..., xµ+1 ) . . . . . . . . . . . . . . . . . . . . 146 xσ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 f δ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 M . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 S . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 146 L . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147
658
Glossary
T0,µ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 T1,µ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 Ta . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 T0,∞ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 T1,∞ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 K . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 D . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 Ca . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 I . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 I . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 ζ. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 155 τ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .155 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 155 ∆ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 155 ∇ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 155 Ut . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 159 Lk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 159 ιhk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 159 λk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 159 prE . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 160 Mk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .165 o . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 165 e . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 165 ≤ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 165 s . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 167 Sk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 167 Skn . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 168 Fr . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 168 ja (x) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 168 Uk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 170 G . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 171 o . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 171 Lk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 171 λG . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 171 (W ; ⊕) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 173 Ln W . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 173 Xi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 173 LW . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 173 Chk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 174 Ck . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 174 a(i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 174 h . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 174 ξm Bhk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 Bk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 Ai . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 ai . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 r . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 z(x, y) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175
gf . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .175 fi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175 Rmax (Pk ) . . . . . . . . . . . . . . . . . . . . . . . . . . 183 ∼ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 183 M∼ k . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 183 S∼ k . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 183 ∼ (Pk ) . . . . . . . . . . . . . . . . . . . . . . . . . . 184 Rmax o(i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 184 z(i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 184 ch (k) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 184 b(k, h) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 184 i . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 193 C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 193 +o . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 201 ε . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 205 Ai . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 205 αi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .205 V . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 205 F . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 205 ξ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 206 µi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 206 z[i] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 207 z t,a . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 207 z t,a [i] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 207 ϕn (k) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 216 n . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 219 gI,J Con A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 234 f ∼ g (κ) . . . . . . . . . . . . . . . . . . . . . . . . . 234 κ(n) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 234 κ0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 234 κ1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 234 κa . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 234 Con1 A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 235 Cona A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 235 κc . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .235 µ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 235 κa . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 235 f g . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 238 κa . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 238 µ(n) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 241 ki (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 243 k(A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 243 α(κ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 247 LM . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 250 r(x, y, z) . . . . . . . . . . . . . . . . . . . . . . . . . . . 250 TA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 250 NA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 250 κ(I, U ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 251 qa (x, y) . . . . . . . . . . . . . . . . . . . . . . . . . . . . 251
Glossary QA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .252 ⊕ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 252 " . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 252 LM ;id . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 253 κc . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .254 κs,t . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 254 κU,µ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 255 κ0, . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 259 κZ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 260 κc . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .261 κN . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 261 κf . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 265 µr (k) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 265 µr . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 266 µr,N . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 266 Con(k). . . . . . . . . . . . . . . . . . . . . . . . . . . . .268 κα . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 269 ess(f ). . . . . . . . . . . . . . . . . . . . . . . . . . . . . .270 αµ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 271 βµ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 271 γµ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 271 A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 273 Tn (U1 , U2 , ..., Ut ) . . . . . . . . . . . . . . . . . . . 273 κU1 ,...,Ut . . . . . . . . . . . . . . . . . . . . . . . . . . . 273 κU . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 273 K0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 276 K1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 276 Ka . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 276 prl−1 K . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 276 σn,κ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 279 πn,κ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 279 F (X) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 282 f α . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 285 ar(). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .291 armax (Q) . . . . . . . . . . . . . . . . . . . . . . . . . . 291 d(A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 291 dim A . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 291 Q0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 328 Q0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 328 Q1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 328 T . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 329 µ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 329 k1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 ja . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 prl . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 pr . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .337 pr−1 B . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 Nk (B) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 P olPk,l . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337
659
P ol . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 B a1 ,...,ar . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 Za,b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 337 dm . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 342 t(i ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 343 R . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 350 R(α) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 350 Tn (Q) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 350 Eq(Q) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 351 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 351 Kf . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 359 kf,I . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 359 Kf . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 371 K . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 371 KM . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 371 K . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 372 K1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 372 K2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 372 K3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 372 K0,r . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 372 Ud . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 383 rd . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 384 ϕ(q) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 386 t(q, k) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 386 Tα,U . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 388 SU . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 388 Cα,U,I . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 388 Cα,U,∅ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 388 Qt . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 393 LM . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 394 ⊗ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 397 Ta . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 401 Ta,b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 401 min . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 402 max . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 402 O . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 402 C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 403 U . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 404 T0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 408 C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 J . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 U . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 V . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 S . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 434 ϕi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .435 ϕi (A) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 Ui . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 Vi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 Si . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435
660
Glossary
τ (H) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 ni . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 ni . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 435 L . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 456 λ3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 456 La,b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 456 pra,b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 457 −1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 457 pra,b Za,b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 457 Bc,r . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 458 Br . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 458 M . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 464 O . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 464 fi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 465 numf (fi ) . . . . . . . . . . . . . . . . . . . . . . . . . . 465 num(fi ) . . . . . . . . . . . . . . . . . . . . . . . . . . . 465 R . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 468 (I) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 468 (II) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 468 (III). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .468 (IV ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 468 Ji . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 471 Ji,r . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 471 Ui . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 473 Vi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 475 A1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 482 A2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 482 A3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 482 B1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 482 I1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 482 Bi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 483 Ij . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 485 Ai . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 486 Aj . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 487 T . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 489 T1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 489 T2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 489 TQ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 499 ! . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 499 Mk;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Uk;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Sk;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Pk,Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Lk;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Ck;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 Nk;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 500 MA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 MA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 UA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501
UA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 SA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 SA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 PA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 LA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 LA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 CA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 CA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 NA;Q . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 BA . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 501 Rmax (TQ ) . . . . . . . . . . . . . . . . . . . . . . . . . . 501 (t1 , t2 , ..., tn ) . . . . . . . . . . . . . . . . . . . . . . 515 [t]. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .515 ! . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 515 Uk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 Sk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 (1) Ck;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 Chk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 ZC2k;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 Ck;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 516 Zk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .516 Nk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 517 h [r] . . . . . . . . . . . . . . . . . . . . . . . . . . . . 517 Ck;E l Ck;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 517 Hk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 517 γr,s . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 518 b . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 518 h Bk;E [2] . . . . . . . . . . . . . . . . . . . . . . . . . . . . 518 l Bk;El [r] . . . . . . . . . . . . . . . . . . . . . . . . . . . . 519 Bk;El . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 519 Rmax (Pl ) . . . . . . . . . . . . . . . . . . . . . . . . . . 519 Rmax (P olk El ) . . . . . . . . . . . . . . . . . . . . . 519 (I) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 530 (I ) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 530 εb . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 541 Ai [b] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 542 αi [b] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 542 Vb . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 542 Fb . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 542 ξb . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .543 Ai,j . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 543 µi,j . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 543 νs . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 544 fb . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 544 wi . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 544 z[i] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 545 z t,a . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 545 un . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 547
Glossary s . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 555 S . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 555 θs .n. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 555 k . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 598 P ⊆p . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 598 f+ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 600 f− . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 600 en i,X . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 600 JX . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 600 k h . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 604 R k . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 604 R
661
pP olk . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 605 pP OLk . . . . . . . . . . . . . . . . . . . . . . . . . . . 605 Eqh . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 614 max . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 616 R κ∞ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .628 κ1 (). . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .629 κa () . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 629 U () . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 629 µ() . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 629 µ0 () . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 629
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Index
A. I. Mal’tsev’s theorem, 268 adding of certain fictitious variables, 94 adding of fictitious coordinates (rows), 129 algebra, 26 semiprimal, 104 axiom of, 27 closed subset, 32 demiprimal, 104 demisemiprimal, 104 directly irreducible, 64 extension of, 31 factor, 55 finite, 26 finitely axiomatizable, 84 finitely based, 84 free, 79 fundamental operations, 26 generating system, 32 hemiprimal, 104 infinite, 26 infraprimal, 104 of finite type, 27 partial, 26 preprimal, 104 primal, 104 quasiprimal, 104 quotient, 55 semiprimal, 501 set of all subalgebras, 33 simple, 53 subalgebra, 31 type, 26, 73
universal, 26 universe, 26 algebras of same type, 27 all relation, 43 all-congruence, see congruence antiisomorphic, 59 antiisomorphism, 59 arity, see operation arity congruence, 235 atom, 112 atomic proposition, 106 automorphism, 52 inner, 285 basis, 98 block, 44 Boolean algebra, 30 Cartesian product, 64 chain, 36 characterization theorem for Shefferfunctions, 215 class, 97 B-projectable, 337 l-class, 280 inverse image, 337 maximal, 98 minimal, 589 of type B, 174 of type C, 173 of type L, 171 of type M, 165 of type U, 170 of type X, 165
664
Index
order, 98 submaximal, 98 class of algebras closed, 72 class of all models of Σ, 77 clone, 97 minimal, 590 strong, 599 closed set system, 45 closure, 97 deductive, 82 closure operator, 45 algebraic, 46 co-class, 141 co-clone, 127 co-group, 138 co-monoid, 138 complete, 98 completeness criterion for P2 , 156 for Pk , 191 for Pk,l , 352 for TQ , 501 for the class of all idempotent functions of Pk , 501 completeness problem, 117 completeness theorem for the equational logic, 84 completeness theorem of proportional logic, 110 composition, 25 general, 129 conclusion, 77 congruence, 52, 234 n-congruence, 279 congruence class, 55 fully invariant, 83 of the first kind, 235 of the second kind, 235 theorem for maximal clones, 265 trivial, 53, 234 congruence relation, see congruence congruence theorem for P2 , 237 constant, 93 countability criterion, 221 cyclical exchanging of the lines, 127 deductive closure, 82 depth of a subclass, 433
diagonal, 126 diagonale, 43 dimension, 291 direct product, 61 of classes, 397 of functions, 397 DNF, 99 domain, see operation doubling of coordinates (rows), 129 dual isomorphic, 59 duality principle of the lattice theory, 36 element central, 174 greatest, 165 inverse, 28 least, 165 neutral, 28 elementary operations, 95 embedding, 67 endomorphism, 52 equation, 76 equational class, 77 equational theory, 77 equivalence class, 43 equivalence relation, 42 equivalence class, 43 finer, 351 permutable, 62 transversal to s, 556 trivial, 43 exchange of the first two rows, 127 factor algebra, 55 factor set, 43 family of sets, 65 fictitious place of a function, 93 field, 29 floor function, 331 free algebra, 79 free generating set, 79 function n-ary on A, 91 r-th component, 168 autoduale, 167 Boolean, 93 component, 371 components of f , 359
Index constant, 93 extended, 600 linear, 171 monotone, 165 near unanimity function, 342 partial, 598 preserves the relation , 130 quasi-linear, 171 quasilinear, 456 reducible, 150 reduction, 599 restricted, 600 semiprojection, 591 subfunction, 598 total, 598 function algebra, 30 full, 96 iterative full, 96 functions κ-congruent, 234 are associated, 238 identity of, 93 fundamental group, 218 fundamental lemma of Jablonskij, 102 fundamental operations, see algebra fundamental semigroup, 218 fundamental set, 218 fuzzy logic, 116 Galois connection, 59 Galois correspondence, 59 generating set, 48 generating system, 48, 98 Gorlov’s tqheorem, 281 graphic n-te of A, 133 group, 28 Abelian, 28 additive notation, 28 commutative, 28 semiregular representation, 557 gruppoid, 27 Haddad-Rosenberg theorem, 616 Hasse diagram, 36 Hilbert-type-calculus, 107 homomorphism, 51 kernel, 52 natural, 55
665
quotient, 55 homomorphism theorem for groups, 57 for rings, 58 general, 55 hull, 45, 97 hull system, 45 I. A. Mal’tsev’s theorem, 241 ideal, 58 identification of certain variables of f , 94 identification of coordinates, 129 identity, 43, 76 inductively set system, 68 information transformer, 116 intersection, 127 inverse element, 28 inverse image homomorphic, 174 isomorphic, 39 isomorphic lattices, 39 isomorphism, 39, 52 anti-, 59 dual, 59 kernel of a group homomorphism, 57 of a homomorphism, 52 of a ring homomorphism, 58 Krasner-algebra of first kind, 138 of second kind, 138 lattice, 30 bounded, 30 complete, 42 distributive, 30 first definition, 35 isomorphic, 39 second definition, 37 sublattice, 41 with 0 and 1, 30 left unit, 241 lexicographical order, 132 limit class, 280 main theorem of the equational theory first, 81 second, 84
666
Index
majority function, 591 Mal’tsev-operations, 31, 95 mapping homomorphic, 51 isomorphic, 52 order-preserving, 39 projection-, 61 minority function, 591 module, 29 R-module, 29 over a unitary ring, 29 over the ring R, 29 modus ponens, 108 monoid, 28 neutral element, 28 normal form disjunctive, 99 normal subgroup, 56 operation n-ary partial, 25 arity, 25 domain, 25 elementary on Rk , 127 nullary, 25 range, 25 operation symbol, 73 order, 98 dual, 59 partial, 36 order diagram, 36 partition, 44 Peirce decomposition, 397 permutation of coordinates, 128 permutation of variables of f , 94 polymorphism, 130 poset, 36 antiisomorphic, 59 complete, 41 dual isomorphic, 59 Post’s theorem, 148 predecessor proper, 292 predicate, 111 preserve a relation pair, 140 preserving of a set, 97
preserving of relations, 130 product Cartesian, 127 projection, 93 onto the α1 -te, ..., αt -te coordinates, 128 onto the i-th coordinate, 127 projection mapping, see mapping proposition, 105 quotient algebra, 55 range, see operation reduct of an algebra, 104 relation (l; r)-homogeneous, 540 M -permissible, 363 θs -closed, 555 -derivable, 127, 499, 515 {ζ, τ, pr, ∧, ×}-derivable, 128 h-ary, 125 h-ary elementary, 174 h-regular, 178 h−universal, 175 (l; 2)-universal, 518 (l; r)-central, 517 (l; r)-universal, 518 areflexive, 614 central, 173 central element c ∈ El , 517 coherent, 615 derivable, 127 diagonal, 126 induced relation, 269 invariant of the function f , 130 irredundant, 605 length, 126 primitive, 197 quasidiagonal, 615 row, 126 strong, 179 strongly (l; r)-homogeneous, 540 strongly (l; 2)-homogeneous, 517 strongly homogeneous, 204 totally (l; r)-reflexive, 517 totally (l; r)-symmetric, 517 totally reflexive, 174 totally symmetric, 174 unary transversal to s, 556
Index
667
weakly (l; r)-central, 517 width, 126 relation algebra on Ek , 127 full, 127 relation degree, 291 relation pair, 140 relation pairalgebra full, 141 relation product, 129 relation set α-permissible, 350 -independent, 179 h-regular, 178 is closed, 127 minimal coarsening, 351 permissible, 350 relation-pair algebras, 141 replacement of the i-th variable of f through the function g and the changing of the denotation of variables, 95 replacement rule, 82 representation theorem for functions of PA , 98 residue class ring, 58 right zero, 241 ring, 28 ideal, 58 with unit element, 28 ring, unitary, 28 Rosenberg’s completeness criterion, 191
infimum of a subset, 37 linearly ordered, 36 of all invariants, 131 of conjunctions, 147 of constant functions of P2 , 147 of diagonal relations, 126 of disjunctions, 147 of linear functions of P2 , 147 of monotone functions of P2 , 146 of projections of P2 , 147 of self-dual functions of P2 , 146 of the h-ary relations on Ek , 126 partially ordered, 36 partition, 44 supremum of a subset, 36 totally ordered, 36 Sheffer-function, 211 Sheffer-function for P olk , 10, 307 subclass, 97 congruence on, 234 depth, 433 dimension, 291 maximal, 98 relation degree, 291 subdirect product, 66 subdirect representation, 67 subdirectly irreducible, 67 substitution rule, 82, 107 superposition operations, 94 superposition over F , 96 Slupecki-function, 211
selector, 93 semigroup, 28 commutative, 28 semilattice, 29 semiprojection, 591 semiring, 28 set CH -basis, 49 CH -independent, 49 J-closed, 274 basis, 49 closed, 46, 97 complete, 98 complete in a class, 98 finitely generated, 48 generated, 46 independent, 49
tautology, 106 term, 74 induces a term function, 75 term algebra, 74 term function, 75 theorem of Webb, 215 theorem on the orders of the maximal classes, 309 theorem over the cardinality of Lk , 221 transitive t-fold, 218 tuple h-tuple, 125 universe, see algebra valuation, 106
668
Index
variable, 74 bound, 112 essential, 93 fictitious, 93 free, 112 variety, 72
vector space over the field K, 29 zero-congruence, see congruence zigzag, 325 Zorn’s Lemma, 68
Springer Monographs in Mathematics This series publishes advanced monographs giving well-written presentations of the “state-of-the-art” in fields of mathematical research that have acquired the maturity needed for such a treatment. They are sufficiently self-contained to be accessible to more than just the intimate specialists of the subject, and sufficiently comprehensive to remain valuable references for many years. Besides the current state of knowledge in its field, an SMM volume should also describe its relevance to and interaction with neighbouring fields of mathematics, and give pointers to future directions of research.
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