VORLESUNGEN Fusdem
FACHBEREICH MATHEMATIK der UNIVERSITAT ESSEN ..
ii
'
Helt7
il-
V. B. Dlab
TO DIAGRAMMATICAL AN,INTRODUCTION METHODS IN REPRESENTATION THqORY' ,]
'
,Ausalbeitung: Riüard Dipper . ,,
l
I
e i f",
,l
1981 ,'
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+'' i/ 4 uu.iqi't i( -
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r
1,,
VORLEST'NGEN aus dem FACHBEREICH UATHEMATIK
der UNIVERSITATESSEN
Iteft
7
V. B. Dlab
AN
INTRODUCTTON TO IN
DIAGRAMI.,IATICAL MEIHoDS
REPRESENTATION TIIEORY
Ausarbeltung:
Rlchard
19 8 1
Dlpper
Acknowledgements
These notes lectures
contaln
addressed
the materlar
to
the
graduate
presented students
rn a serres in
Algebra
of
at
the Essen durlng the surmer semester 1g7g. T should lLke to thank prof. c.o. Mlchler for hls klnd lnvltatlon to vlslt Essen, and the audlence for their partlclpatlon actlve ln the lectures. unlverslty
to
of
The alrn of
thl-s
some baslc
results
and conseguently tensor
algebras
brief of
the
course the
content
was to
expose
the
representatlon
theory
was restrlcted
to
and a few slmple
audience graphs,
of
a study
1llustratlons
of
of
the
theory.
As a result,
the reader finds a major overlap wlth the Me_ the Amer. ltath- society No. 't 73 and an omission of general theory of M. Auslander and I. Reiten.
molrs the
of
My special written tails
notes
are
due to
wLth great
r should
Department
thelr tatlon
excellent of
the
of
lr-ke to
Mathematics
typlng,
p.ichard
Dr. care,
and in many ways improvlng
Pinally, the
thanks
up the
of
contributed
supplylng
the
thank
Digper
original
alr
those the
de_
expositlon. secretalies
Essen University to
who has
missing
formal
who,
of by
presen_
notes.
Vlastimil
B. Dlab
CONTENTS Chapter
f
Valued
graphs
s1
Valued
52
The roots
Sg
Graphs wlth
Chapter
II
PAGE
graphs, of
1
Dynkln
and Euclldlan
graphs
graphs
valued
7
orlentatlon
Reallzatlons
of
1
11
valued
graphs
and its
20
repre9entatlons
s s s
1
X-reallzatlons
2
The Coxeter
3
Prejectlve
Chapter
ffl
Graphs
of
and representations functors
30
modules and extenslons
finlte
and of
The representatlons
of
s2
The non-homogeneous
representations
Dynkin
Euclld1an
Appendlx
graphs
56 of
60
of
85
graphs
'Blmodules Graphs
3f
graphs
The hornogeneous representatlons
s4 Ss
47
tame type
St
Eucll-dlan
20
of
Euclidian
and bimodules
type of
wild
100 type
ru)
A
Applicatlons
118
1
Algebras
118
2
Normal
3
Further
Appendix
B
Exanples
173
Appendlx
C
TabIes
180
form
problems
applicatlons
139 171
-1-
Chapter S 1
graphs,
Valued
graph
A valued rrith
Valued qraphs
r Dynkin
(I,d)
is
and
a finite
a set d ={(dii,dii)lar.
graphs
Euclidian
€N
u
(of
f
set
vertices)
together
€ I}(of
{c},i,j
vaiues)
L J
J L
satisfying i) li)
dlt=oforalli€I For every utj
= di1 fi
tj
Notice that join
€ f there
i
d, : i rJ
exists
for all
o L f a n d o n l y- i f
, If
d,. rl
j 1 Another valued graph ( l',d') (t,d),if Veltices,
( l,d)
is
a sequence 1 = ior that
the fi,
scalar
d:. )L
I o. fn this
i1,
multlples,
if n} c
For the rational
with
ft
g t
is
a subgraph of
(xi)l*iee,
s!'nnetric
bilinear
form
(1) :=
-f .i 'x. . y .
i,j
€ t
, there
ik = i of neighbours in
is
ccnnected.
-
i€r}withn= Bf
- I .
quadratic (r,r)
"l.
all
f
determj.ned up to
Of course we can nrite
=
definethe
lrl
by r (r,j)€f"f
d..f .x..;. rifixiYi
for
y I , I \ , .€ Q '
form tr*r'
,ä.
-
dijrj*i*j .1. ij
,
rvhere in edges
the second term the sum has to be taken over aLl (f,d) - clearly in Br and en der:end on i-;
the choice of the fj.'= , i € f , factors, j-f (i,d) is connected.
is
. Notice
space
{x=
wLth associated
for
neL_qhbours. A
N fo sone n €N.
vector
r ier
if
.i ,d.i i )
:
above are uniguely
A':=0"=
(x,1) =
*!
and wrlte
= 1 = tt... l1
....,
( frd)
case, we (di
(dii,dii)
connected,
I € f, 1n ii)
| = {1, ....r
Qf
-
d t.t l, = d , . ft ot r af lol ri , i a€ l l i , j € f lr c f . _. which are joindd by an edge, are called
valued graph
Br
€ f
i'j
i and j by an edge of value
or simply
€ N such that
fl
but are unique up to scalar
-2-
Eor k€I
let
= (k.)
k
€ 0f
definedby
k,
= o for
k I
I
€ f
and k* = 1.
1.1.1
Definition:
(trd)
a) Let
be one of
the
following
valued
sraPhs (lrl= n)' Arr: *o......a.1 1, 2 ) Brr:ffi......H
(2,1) C: n
o--O......H
\ )--......a---a
/ ? n=6
E.: o
E7'
? n=8
3r;
n=4
tt.
I
( 1, 2 ) '4'
(1,3) Gr: o---<
n=2 then
(f,d)
b) Let n=2
is called Dynkin (graph).
(I,9)
be one of the following (1,4) H 7-: tl
valued graphs. (lfl
= n1'
-3-
Är,
n=2
n>
3
( 2, 2 ) F
ärr-t
n:3
!rr-t
na3
7-n - 1
n>3
ft'-t
n>4
Sn-t
n>4
örr-t
n> 5
örr-
t
( 1, 2 1
(2t1)
(2r1)
( 1. 2 ' , )
( 2, 1 1
(2t1)
.E---{-_o.....H
\
-7-n=7
E6
n=8
Ej
-/'
\
-4-
n=9
-8
n=5
x "41
n=5
-F 4 2
n=3
dr.,
n=3
"22
( f ,d)
Chen vre call
1.1.2
Lemma:
( f ,{)
Let
of the followlng
(rr,4r,,
i)
(i,j)
(r
ii)
Proof:
a
If
i,j
( | ,d) contains
one
dijdji
> 5 for a pair
x I
a triple
(i,j,k)
Euclldian
graph.
there are i,j
€ f.
Then
graphs as a subgraph:
€
ijk
d . . d . . -> 4 , rl lr.
Ä,,.,' or Ä,,r. thus F I
= 3 for
lä) ,
€ fxlxf
€ I with
(f1,d1),
Let i,j
,@w*h
= 2 for t r(resP.
= 3 and djrd*j
a subgraph of type for all
be Dynkin.
(resp. ( | i,gä)
urjuj,
iii)
not
.
:&+'i.h
€ f
2,9)
for
(graph)
Euclj.dian
. . i ! L W f L r r
I I u . . s . i i ' )
-J -
2 J .
( f ,d)
contains
a s s u m e d .r l . d .1 1 . -< 3 Because (f,d)
is
-t-
not
Dynkln,
i or j must have a nej_ghbour k € I
above dildkj
< 3. It
graph of type utjdjtg there
is
( tz,lzl
S t
a subgraph of type Et, all
{1,j}
with
€t
Ct or 60a,lrl
;
{k,f}
g I
F41 ot Fnr,
or it
must havg 6 branching
ls
of
type 0a
l,j
not Dynkln.
€ I
type Äa,
rrr
If
or !r,
because it
has only
branchlng point,
A bilinear vector
it
Leumas tet
varued graph
Proof:
(r,g).
Clearly
and take x'=
lt
Brr
(f',d')
is
the vector
it
a subgraph type agaJ-n because
lt
if
contalns
positive.
lrl
2 t €N.
if
O(I)
all
I
> o for
aII
€ en and positive definite.
the connected
then Brrispositivedefinite.
Assrxle B.
minimal hrith this
defined
E,
form o on the rational
a proper subgraph of
is
one branching
more then one
but not positlve
B, is positive,
ar1
a subgraph of type Er,
> o for
rf
a subgraph = 1 for
at reast
quadratic
g(x)
positive,
€ Of'
= 1 for
contaj,ns a subgraph of
is called. positive,
(f,d)
dttdtx
a subgraph of type ö,,
5 (xi) € QI' b" with er,(x,) z =(?t)
If
associated
(f',$')
contatns
contains
contalns
1t contains
contains
definite,
lf
it
not Dynkln.
space en, n €N,
senldeflnlte,
1.1.3
one,
form B wlth
€ 0n, positive
. rf
2. rf
( I,d)
Thus assurne drjdj,
a circle,
Otherwise
is
now
polnt,
( f,d)
case
t € N.
contalns
t €N.
I
Po1nt.
it
lf | :
( f,4)
If
thus.assume
, our graph must contaln
fn the latter
or döa,
a sub-
= 2, then t €N
By the
contains
withdlidir=
dXtdtt
I
it
I
Leti,j
, say j.
(f,{)
Er., or örr.
i,di'),
e r
{k,1}
I
( f
,
2foral1l,j 1s {i,j}
easy to see, that
is
not positive
property.
Let
= o. since for arbitrary by z., = iyrl
for
all
definite,
I
€ eI,
i € f,
-o-
always
satisfj-es
for
i
f
all is
Qr, (z) < er, (1)we can assume
€ f'.
In view of minimality
connected,
d., 'oJo I
there
o. oefine
d. ].'l o-o x+ *.. ro2'or
x
e ef Uy
l',
f'
all
xi
+ fi -o
-.
x?
-o
*i
for
dr.
f.
x.x.,
with
€ I,,
i
E
-Jo
Jo
a
Jo
'
di s f* x] lo lo
> o
I o. Because
and io € lr = *i
,a-oJo i€f
-
xi
= o othenrj.se.
and x.
Then Qf (x) = Qr, (I')
jo € f -
exists
= (*i)
of
that
= f., (x. d' .i f+ x., X+ roJo Jo r.o Jo Jo Jo
d. d. ro lo
i
39
x' ,2Lo
2
!
_r
' o 'i o * ?
=-
acontradiction.
4rot 1.1.4
Proposition:
Let
(f,{)
a)
(f,d)
is
Dynkin'
b)
(f,d)
is
Euclidian,
be a connected va}ued graph
and only
if
if
if
and only
Qa is if
positive
Q.
is
definite-
positive
semi-
definite.
Proof:
First,
calculation
shows, that
Now let
in
(I,d)
defined as in rf
(fl,d.')s
*i
= 1 for
is Qf
(The quadratic
semidefinite. are listed
( f,d)
if
tables,
Dynkinrresp. is
positive
Euclidj.an, definite
forms Q, for
a direct
resp.
positive
graphs
Euclidian
Appendix C).
be not Dynkin. Let
(t1,d1),
(f2,d)
and (ri,dj)
(1.1.2) . (l,d)
{i, j}
=
definex=
(xr)i61€Q^
f ,, and *k = o othervrise.
r
byx.:
= ä 1d .i j ,
f
*2 rc
-7-
rhenQ. (x) = rr - lrurjtjuj, * u3r * t) = ujrtr,
because utjtj If
(tZ,d)
*i
= diidti,
= 2dki,
*j
dijdjr
"td wlth I,
(f,d)
c
=
* rr(a diidii) < o,
2 5. Thus e, is not positive
= {i,j,k}
S I define I
*k = 1 and xl
= o otherbrise.
Qr(x) = ridii dxl * lrra*j * rk - 2diiridiidrjdrj = fk(3dkjdjr = f*fi Thus Qf is
-
* 4 drjdjk
+ 1 - udjrd*j
not positive. (r;,qä)
Euclidian
subgraph, e, is not positive
= (f,d).
Of be posltive
(f,d)
is not Dynkin. er,
Let
The roots (l,d)
)
and (l,d)
"X IrI
Bl is
(f,Ä)
cannot
(ri,dä).
Thus
hence (f,d)
=
is Euclidian. This proves b).
graph
valued
ef . For k € f ,2Br(x,k)
= x --Effik
(s*><.)i = xi
= t.
groves 6;.
This
subgraph 11,,g, ), by (t .1 .21 , because
the
with
linei .tt
for
k I
invariant
bllinear *un
sk
form
I : @' -
Bf and P Q' defined
for x e Ql is called simple reflection
( f o r k € r ) . v r eh a v e f o r x = l x r ) e q r , and
or
j.s not
ef
contaj.ns a
definite.
(t2,d)
that
of valued sraphs
form
:
(r,4)
if
is not posj.tive definite,
be a connected
quadratic
by s1x
Euclidian
by (t.1.3),
- 2djkdkj)
As above,
a subgraph of type(It,d1),
contains a
S 2
clearly,
sernldefinite.
(I,d)
(f',d')
Then
- 2dirrrdri
The same argurnent shows
if
contai.n
UV
< o.
\idis)
Positive,
Norr let
€ @r
i
€ |
under's*,
(s1{)
1
particul.,,"
fn
i.
e. Br(x;1)
= _*k * ,!r n"a
s*k
= efs*!,
r € Q:.
The group tti of automorphism of @I, generated by the sk, is calledtrlevl groupof
f
. ilet Itl
= . . . n . a n d I '_ { k t ,
:,.,
dit*i_
= -
k and
sif)
foi"
k € f, krr}-;t .,
-8-
Then c = su. .^n^nrl
of ql'.
If
su
s. € lv-- is (xe
wx=x
x = (xr) € d
called
forallw€
d)
Coxeter transformatlon wF
, thenxls
stable.
- l
is positive
x. > o resp. xi5
(x
o) resp.
;
o for aLl i € f
(x S o),
neqatlve
. For x,I€
QI let
I:
lf lf
Ir
x-r>o, = iwllw
The set Rf t;
the si:nple posltlve
1.2."1. let
€ Wf, k e f) ale
statenents
are
x is
ii)
cx=I
v)
transformatlon
= o for
Bt (x,1) ff
moreover
Let
f = {k1,
alr
of
k € I.
th"n
Qr
the
follonhg
...,
and c = s* .
kr}
I € f.
follows
With thls
using s*x = I equivalence
-
implications
then the above to Qp (x) = o.
are equivalent
'"*1O,*.
The other
1 € 0' positive,
Q, is
xka = (c:!)*a = ("k;
fhe
of
stable
statements
iii).
the k with
roots
skä=Iforallk€I
iv)
sr,
the set of
equivalent:
i)
iii)
of
is
Leluna: Let (t,d)be a connected v a L u e d g r a p h , x € Q f , a n d
c be a Coxeter
Proof:
roots
c e'
in
for
...
15
' sk1. Nort
t s n by definition
inductively,
that
(i) C)(fi)(=)(1i1)
11) jrnplies are tlivial.
28- (x,k) diEE
(iv) (+
(v)
set Nf of vectors
( ' l . 2 . 1) , i s c a l l e d
k , we see (iii)
(=) (iv).
(rrtith QI pos j-tive) in Q' , which
the radical
of
satisfy
(f,d) .
is
rhe last
well-known. the conditj.ons
of
-9-
1.2.2
Lema: If
(f,d)
is Dynkin, then Na = (o).
b)
If
(f,d)
is
integrer
The proof
of
in Appendlx
C.
also
satisfles
, and nf
this nf
Notice
Euclidian,
for
that
the
set
the definrng
Rn generat,es Of .
root
rf
. *rr3*!()
x € R- ,
them equal
to one.
(1,y)
then
A list
t23l
of
but
in
a valued
the
the
graph
finiteness
of tables
( frd)
conditlon
:
Rf mapsRrintoR'
is
an inteser
.
2x ( Ra .
This
is
easT to prove.
that
root
is
a linear
every
As a
combination
l.
!,s
Furthermore,
e e',
result,
This
well-known
| 22 , 23
I
k € l,
with integer coefficients.
as an inEnediate consequence of
general is
roots
[ 3 ]
forl€
consequence \^/e get, the
positive
Ls contained
1f,dy
Rf of
system of
28. (x,I) I-x--re;;"
iv)
chosen with
one of
properties
1)
For I,I
can be
least
Euclldian
a reduced
iii)
€ NI
one_dimensional;,
lermna can be found in
for
li)
then Nf is
componeits,at
the vectors
to
be a connected valued graph
a)
Nf =
,
(I,d)
Let
one of the
x or
and can be proved
We will
E. Scherzler.
roots
give
-x using
the
is
following
always positive.
Kac-Moody Lie
a ne\d, pure combinatorialr
argebras
proof,
due
of
-10-
1.2.3 ä
Lemma:
t € O-
or
-
x
(f,
Let
1s a positi.ve k
root
and k € J.,
valued
then
graph.
either
If
sk I
O
:
(and s,-x = -k). K_
3 For x,I € gr with B'(I,I) I O let <x,L>: = -rff#.
Proof
Thus skx = x + <xrk> b Furthermor" Let
be a connected
9)
I
qi,i>
e Qf, k,i
€ l,
by direct
calculation
(1)
- -2Yk *
(2) sr
"i =k si
I
= I
and either
= -2,
and
t x or
I "k = dik
€ N
for
i,k
L * k. We get the following from the definition ur* yjr
rä, +
= s. sk if
sk x < x.
i
if
+ dik
formulas
o, )k;
= dki
i
I k. easily
Bf,
hence for 1:
+ (.I,kr
and only
of
€ r,
+ 2yk > o hence
= O
(3) sr"ksi"kL-sksiI= (.1 ,i> <1,k> (4) If "i
1) (.I,\>
d.* = d*. = 1 "k
I
"k
I
k +
+
i
i
then
= (
+ <1,k>)i
"k"i"kI-si"kI=k - sk =i sk - <1rk> i 1 = "j. "k "i "k I (5) From (3) we conclude easily: rf
sk I
f
yor
sil
I I,
only if dir = tri Define
"k "i
I
= 1.
Ru S Rf , -1
now
then
I
v € Z,
= "i
"k "i
if "k L
and
by
R_1,={-xeerlk€r} Ro,=ireErlk€r] Rv+1: = Rv U {skIlx Let v > O, I an I
s1ts>I},
€ Ru, x e Rv_1. Then, by definition
€ Ru_,|and some
O < x - I
€ Rv, k € f,
=
i,
i
€ f , such that
hence
> O.
* =
"i
!
v > O. of > I,
Rv, there i.e.
is
- 11 -
Let
i
f k € r
o t
sk x - x =
on \,, that trivj.al. of 1.
So 1et lf
by lnductlon induction
v:1.
= (
sil
x*
Norr s.
on
v,
that
again.Ifv=1then =*tI=I.
y=f
X =
i>
k>)k,
show now by induction v = o this
changes only
the
i-th
o.
Thus il.*
Next
we will
forsome
ls
and
by
trj.vial
LfI,
inplies
]="kI..y=l "f * dff i > k,
5 1
show again
I€f
is
component
:: 1 and drr
€ Rv_1. For v = O this
sk I
Nord
+.I,
kt
For
< I.
s* I
(2),
Then, by
I o.
yk I
o also
I
because
"if Because si
sk x < x.
I . L. We will "k 5 1 and d*, < 1, if x*
dif
Thusr
-
L
"k "i !> < O and
hence
be such that
because
k=1.
we get dki t O. On the ! = ! "i other hand, by above, hence dti = dik = 1. Now by (2) tf:1, sk k =k + i - k = i € Ro. So let v:2. "k*= "iI= "k "i By the above di:. = O = dki_ or dik = 1 = dX:.. In the first case = hence sk ä = I = L. By induction "i "k "k "1, "k "i "j. "k s* I € Rv_2.Thus -k I € Rrr with u = v- 3 (> - 1), I = "k "i if s. s* I < sk 1by induction, u = v - 2, Lf s. sk I = skI and p = v- 1, if y t I. Thus, in every case, "i "k "k s* x € Ru-r. Let
now dik
= 1 = dki.
o > skl
"k "i this implies O > "i again by lnduction,
"i
"k s.
E> < O we conclude "i
"k
I
"i I
By induction -
f !-, thus
€ Ru_2. Furthermore
+
i>)
I = ( +
I
frorn
I t =k =i "k "i "k =k I € Ru_2 atd =i = \
= (
I
"i -
s* I
we get
(4)
sk I, =k
k by \>)
i,
i> > O,
that "i
"i "k frorn (5)
=k I
Therefore
I € Ru_1. of
(4) and
course
hence
-12-
=
sk I
=
si I
"k
"i
Let now n: = V
"k "i
€ Ru_l, as desired.
I
"k
R,,. By construction
R = R. and all
v>ov-l
positivel
R are
Now every
... x = s. t*t1{ now by that
s.
i
induction
either
with on m, -
Ä or
x
root it
I
€ f,
that
O j
either
is -
€ R or
From this
in
as
be written
< m. It
t I
positlve.
ls
can
€ Rf
roots
easy
ä € R,
prove
to
hence
lemma follows
the
easily. '|.2.4. bilinear l*n/ H r _
(f,d)
Lemrna: Let from induced
B
. Then
be a connected group
the
fr,
of
all
is
finite.
P r o o f : W e c a n a s s u m ef = t 1 , . . . , n 1 .
l,et
by
elements
of
wr
graph
valued
positive
with
of
transformations
I
M: = {x e Q'I Qr(x) < 1, *i there
tauschsatz {nr, k
h.z
2 S k < lrl.
matrix
i
a basis
2 < k < lrl,
generated
of
the entries linear
of the
i =: v and Q.
fr, . v
€ v. thus Qr/".
product,
transformation
combination of n, and the 1<,
The radical
by !,
of ? and tr ? is
also
is
v/;,=,
c-|
hence atot*i.l
if
Ze
M. Now it
exarnple a suitable
linear
an integer
nultiple
of
it
will
follow
V,
on V. ror L.
combination
is well-known that
From this
hence, r.rith
rational,
e ? denote the image of x in V. rhen 8, 2.
induce the sane topology. for
the base change is
form on v.
and Q, induces and scalar
is
of
q r c a n b e e r n b e d d e di n i l f
clearry
one dimensional,
Aus-
say k = 1, such that
(z€11) is an integer
a quadratic
x € v let
k € f,
conmon denominator
h e 7, the
induces
a
By stelnltzr
is a basis of (D'.
I z < i < n}
The transformation
matrix,
is
€ a (i e r)}.
all
lrl,
of the [,
norms on V easilyr
using
the maximum normon V, that
- 13 -
h maps M nodulo fff (injectively) hence f, = M + N"/p r
lnto
must itself
ttF
a finite
be finite.
subset of
i
,
By the construction
I
of Bf and the ü tnto
itself.
operates of the
of
€ Qr,
of B, under W, r the
ü contains
= I then
element
ä. x is
of x
and if
x € Q has integral
(wlth
€ or deflned
respect
i)
for
quadratic
all
cx I o if
-1
c
I
'x
*
O
er ls positlve
and is
ac x € n.
called
linear
the defect
: =
folloers
the
The vector
€ r 1s carled
I (l^)., x., i€r easily that
Let O S. x e eI
be a root
be a Coxetertransformation.
and only
= 91.:= sn --t
means for
and by
be a connected valued graph with
fonn er.
if
i
the
x € Al.
(t,d)
s,- € W K1
be the orcler of
ln fra. This
= (ac, I) it
positive
Of course äc , ef - e is
= aci for
and only
....-
and
Then
if
2 -. .- .-.-.-x = -DK. t ! = Sk, ]- -sk, _ ii)
graph with
coeffj-cients,
bv (3c)i:
L e r n m a :L e t
c = Su ... .. ^n
as a subgroup
some ac x € e. If
to c).
of Nf under c,
ä" (x) = ä. (cx)
positive
finite
unlqueJ.y determined
Clearly we have ä. I
invariance
1.2.5.
c € t{I
+ (ä. x)n for
defect
the
therefore
be a connected valued
Coxeter
c* I
vector.
of V, the group fia
form Qr. Let fta as above and n the
group fr, transforms
Aroup on li.
(r,d)
semldefinite,
i"
a basls
on !i and is
sltmmetrlc
quadratic
I
since
falthfully
Let again
lnage
invarlance
-sk, a _ t k a f o r s o m e 1 < t < lfl.
if
tt*lka
for some1 :
t:
Itl
-
Proof: tttn
(1'2'3), ii)
< O if
1) c I
t*a-.,
14 -
and only if
sk1 5 > o and
""'
sk1 x = kt,
.....
"*a_,
=
some 1 < t < lrl
is
"
x < o' By
""'
"*a "n., = ---.. hence x "o., "na
"*a_.,Ea.
Similar.
(with
The notation
pkt,
c € Wr) will
be kept throughout
1.2.6.
Lenma: Let
c = sk
.. ...
sk
^1
gkt
(f,9)
Proof:
< n,
have
is
N, cI
=
-u
by I.
the
is
1.2.4). Hence there
.
cr-*r,
,
roots
smallest
(I,d)
Then
r*r,
positive
all
n, a.ta
,:k
-9. -r 2. , . .
Because
saym€
Dynkin graph,lrl=
=K2"
of
transformatj.on
paper,
this
-a^.
c- IK_l
a list
be a
to a Coxeter
!*r,
-a" I ^r:^z^^n^ =*1 ,
'| < i
respect
€ Wf be a Coxeter transformation.
&., ,
is
there
of
integer
Dynkin, Thus for exists
(l,d)
where a.
such
t,hat.-1.-"i
c is
of
< m -
nn,
order
finite
O < x € Rr andy ' 1 < r
€ N,
1
mh E c" x h=l such that =
rre
-
r-'l
= pf<. for
c-'I
some 1 < t
_:,
< n and therefore
x = .-(t-t)n*a
_fe
=c
Letnowa'pk. .*",
1 < s,t
" r*_, '-s
"t o ..2.
15 -
o < 11 Sä1, .-t
and assume 11 Z 12. If
r1 I rr, then O . .1 - 12 - 1 < äar and therefore -f. *r.+1 | ' O
= 12 and so pu
rj
irnplier
= ks.
kr
1'2'7'
Lemma: Let
natural
number 9,
that the
(f,d)
of
the
Io
a posltive
is
x € ef of
easy to
shoe, that
Iemna.
;.orrJ"an.
be Euclidian.
roots
Then there the tier
(f,d)
exists
a
Layzo.Lt
number),
with
such ?uJ_ra.U v ä^ ä = O.re
form
ä=Io+r9gl \rith
It
1 < 9 < 3 (called
the positive vectors
rhi;
= p,_
,r€N root
x
of
u{o} (I,d)
of defect
zero satisfying
. 9 .lr.
t23 l
1.2.9.
Lemma: Let
be a Coxeter if
(r,d) i)
is
(r,d)
be Euclidian
transformation.
and c =
Let c be not
"*r., conjugate
.....
s*,
to sl
€ w,
. .. . sn
of type Ärr. then
the vectors positive to c),
.l = t . n, are just all , O ( r, c of (f,d) of negative defect (\rith respect
.--&.
roots
- 16 -
ii)
iii)
t,
positive
of positive
c*rq,-, O : +t roots of (t,d)
the vectors described all
from i)
positive
mod N, of c.
and ii)
(1.2.7)
in
roots
Let O < x € n, with
Proof
Then for
T h u s x = c - r p-K., -
and the vectors of
zero) form a list
< O, and let
ä" I
m be the order
s € N
all
U toi
with
f o r s o m et € { 1 , . . . , n }
crx>O
and cr+1x < O.
by (1.2.5).
t o r s o m es € N
u {oi,
similarly,
if
t € {t....,n}.
1 < t < n we haveä^(g, ) = ä^(-c p,. ), so we get "^t"*t positive roots of (f,d), if we show r.(p**) . O
Of course for a list
with
a1l
(t,d)
of
o, we gät Ä = cs g*.
t
defect,
together
(of defect
""^I=x+s(ä.x)nr. Therefore there is an r € N
ä" I
< n, are just
1 < t
the vectors
of all
foralll
in wf to the Coxeter element cr
of type An to one of the coxeter in Appendix
C in the
following
s. and s. are adjacent
if
.....
^t-1
sequence sr tt
of
.....
assume thaL ä^,(s,u
^.
-x )
S,
.....
sr
t1
tn
operations
sr tn
Irre get
as c'.
= sk sr t1 k'
cr
= ä^(x) u
is
in the tables
S t - . A s s u m ei , j t1
€ I are not
s. and s. in c doesn't in c, and corresponds to
and s. = s, s., if s. = s. s. = s. s = s. *1 . k1 *., kr, i I I I into can be shown that c can be transformed
c o n i u q a t i o n b 'v s i 4 in it As t I ö = s.
(r,d)
way:
..... Let c = sk ..... s. , c'= s, tr, K1 n joined by an edge. Then interchanging change c,
given
elements)
(if
for
s,
tt
-
comparing
si- = s. *1 K2
..... x € R. r
.
Now bl'
above.
described Therefore
by a
f o r s o m eL € { 1 , . . . , n }
c
Hence if
conjugation
c and ct
s. . Then *'r
-
r.rith
we can
-17-
(pta)
a"
1 < t
< o for
< n and of
(c = sl -n
.....
p, -n
= s. *r
c
if
ä.,(Pf. --t
)
enough
course
a^,
Thus
O for
all
the
the
,
a_ (p, c._k*
= gX
craphs with
An orientation
if are to
i
is .
+.
joined
.
o tor
alt
< n -
1 < i
1 and
each edge
lt
in
(1 < t
is
the
< n)
and 12.2.12) that for
tables.
given
it
arbitrary
s < n) implies
define
arrows
io
resp.
i
o-
there
ls
of
j).
all
resp.
For
in
is
in fact
valued graphs
that
given
(frd)
a given
edges
it
must be of
is
for
an order orientation 0 of
containing
k.
with al1
An orlentation an ordering
by
sk
a source o k
k by an edge. if
-.j
a new orientatj.on
along
k
(f,d)
graph
io ----rr
be a sink
be admissible,
above,
and only
now.
< O. Furthermore,
to
with
< n if
elements
ä"(t)
be proved
(2.2.11)
a valued
and k € f
said
by the
using
) < O can
by an arrow
a1l
So,
1 < t
all
orientatlon
Q of for
by reversj.ng k € f
n - 1.
Coxeter
(some r > O, 1 5 t,
"-t ES Dynkin type.
Prescribing,
the
calculation,
ä. (Lt)
(f,d)
px.)
) .'-Ä.;:-,
for
< n.
lernrna for
enough to prove
0 of
.-t
1 < t
see later in
(indicated
(sL
Oc, ("k.
< O for ä"(pt .-t )
Remark: l{e will
S3
then
= s, pL ^1 *i+1
-Dk-1 -
direct
pk.
n,
-1
By an easy tables
(
1 < t
) pr ^i " t- 1
prove
to
aIL
A vertex
respect
vertices 0 of
k1
(frd)
to i. €f
(t,d) .,
n, , which
is
kn of
said f
such
-
that
a sink
...
s. *i-1 is
is
k1
with
called
admissible admissible
and if
...,k'
k1,
l. 3 .1 .
(i) ii)
+
-
e
is
iii)
(iii)
(ii)
t
i
,
k,
It
sinks,
also
is
for
easy
sources, kr,
,..
to
show
connected
= {1,...,n}.
graph
Then the
\rith
following
cj-rcuj.ts
in
(t,d)
n of
inplj-es
n of n(i)
{1,...,n}
such that
< n(j).
: easy : Choose an admissible
n bY n (kr) :
It
is
= i'
i
easy to
sequence k1r...,k'
= 'l,...,n. see,
that
n(1),..,,n(n)
is
sequence.
alfows
an admissible
orientation
seguence for
sources.
j-s a permutation
(ii)
admissj.ble
(1.3.1
be defined
can also
no oriented
o +o
and define iii)
.....
admissible
There j
Proof:
are
o is
iii)
case k1 ,
equivalent.
There
ii)
respect
with
sinks).
be a valued
and let
are
i)
( f , d)
Let
fl,
statements
this
In
a sink
is
s. 0 = a. K1
I,erq!4.
orientation
(for
for
, and k.
1.
an admissible
sequence
.....
s, *r,
a
1 < n -
sequences
is
an admissible
that
-
to
sequence
Of course,
is
respect
1 < i
n, s. K1
|8 -
us,
to
sequence (f,d).
order of
f
sinks
i-n such a way that for
the
fj.xed
1,...,D
admissible
an
. k.l
to
_ 19 _
Note alsor if
k1,...k.
sequences for
the same admissible
C =
S,-
for
any pair
*r,
...
Ref erences:
sr_
*1
-
Srt
*r,
and kir...,k,
...
of vertices
't I I ] ,
t22l
Sr_r =
ki
i,j
are two adrnissible orientation
Cir
since
s. -i
e, then a---nd
s. -j
c-----ommuce
€ I which are not neighbours.
and [ 23 ]
Realizations
2
Chapter
S 1
K-realizations
2.1.1
Remark: Let K in
a
: =
Proof:
\J
'r (d.,dr) D is
i J
t' \ \.\
the
= t
(drd, )
= tr
dr)
tr(d)
= k+ o,
projection
. Then
€ K1.
the f
"r tp
HomK (
K-Linear.
by the
above property
O +
r
by tr
o and with
d€D
the
by
followed
cases, o + r
both
._HomK
of
DDD)
is
, it
t
(DMF, K)
by
easy
to
of
map is
. This
and'
an F-D-bimodule
is
K)
DMF,
of
HomD (
, f
must be injective, the
(DMF, K)
Thus let
DDD)
DMF, oDo)
see,
are
f
that
Thus Homo (
K-dimensions.
hence
as F-D-bimodule,
also
the
by
DMF, DDD)
Hom" (oM",
similar
and
surjective
bijective
therefore
HomK (DMF, K) as F-D-bimodule. Honk
dZ€D.
K1
tr:D*
D and
of
Hence, in
D onto
of
P 1691 tr+
HonD (DMF,
elements
of
projection
r
then
f inite,
Property.
all
equality
K hrith
homomorphism.
an bimodule
since
dt'
Otu,
19 €
for
K is
126]
Then define
: Horno (
course
is
for
desired
If
center
lsee
K1 on K'k
a map with
: rp l-
be the
Kl
r
be the
t
: D -
naP
d, € D:
Then
as F-D-bimodule'
Homo{DMF'pDD)
K-linear dr,
(d2 dr) k
of
Now define f
let
trace
trtd,
for
on it.
centrally
!
and we let
Other$iise
reduced
is
a nonzero
is
coNnutative
K '1 cD.
\
K acting
Let
K.
over
dimensional
and finite
Homu (oMu,"Fu)
There
containing
D and F skew fields
K be a field,
D-F-bimodule,
( pMr)r
U
and representations
theücenters,
n$f
val
of
:
rFf)
:
HomD (DMF, DDD) =
Hom" (OMU, FFF ) as F-D-bimodule. Let
K be a field,
A K-modulation
and tü of
( f ( f ,
, d) )
be a connected is
a set
of
vaLued graph.
division
rings
Ft'
-21
! € f
, together
nith
an Fr-Fr-bj.module
Ft - Fr-birnodule
.M, for
1) K is contained
rl
F, 1s finite
li)
11i)
-= *
jMi
every edge
the center
dimensional
K operates
centrally
and an
lMj
such that
i.-.ir
of Fi tor
each i €f
airC
over K
on every
as bimodule
iMj
-
for
j
i,
il{i, each
edge
€ f.
.-.
,
. in
(f
, q
)
(compare (2.1 .1) ) . iv)
(ttj)r,.
din
= dij
-)
By iil)
= dinr.
we have also dii I_---..-.--'_choosen byl ff = dlrrk ri
( jMi ). The fr,
1 and
dtj
get
we
i €
= dij
tj
f
can be
= drro*
fi
= dr*x jt;,- l, j € r. A K-realizatlon of
( l,
let
in
d ) the
together
valued
such
1 , .. . ,n
A representation is
a set
together
of
or
finite
with
there
is
Also Lre omit xl a
(I
is
a modulation
ori.entation
, Q ) and let
module
=
X
dirnensional
f
sequence (xi,ro,
right
)
M
n
0 ) be a K-realizati.on
an admissible
Fr-Iinear
jgi
(If
graph
, d )
an admissible
M ,
(
is
(f
e ) of
with
folloning
connected that
M,
(
of
. Thus a
= {1,...,n}
(i€
ordered
sinks
of f)
F.-spaces
(1 .3.1 ) . (
[],
i
€ f,
of Xi,
e )
mappings
t xi "",
*
ttj
*j
for
all
arrows
i
.4.
-J
no arrovr from i to in the following
j F'
(i, in
j € |
) we set
the tensor
irj product:
i.
= O.
iMj. ) X = (Xi,
For two representatlons morphism mapPings oi
( cr)
rMj
: I
: X. + Yr,
*
I
i € f,
and y = (y' jqi ) . ier) is a set of F, - Linear
such
that
the following
diagran
-22comnuces.
oiol ia
M
io
iMj
Il
I
II I
II
.o, l1
II
.tt.
I'r
I
I ,
{/
*j "j
oj
Vte denote
F, = (X1,ior) be the
Fori€flet defined j,
=Fr,Xr=Ofor
xi
by
of
representation
(M,
0 )
rsrth
the
andlqi=Oforall
i+j€f
k€ f.
just
morphisms +L ILI Ii J^
^E Vr s' ^t I' r '
^hiFcf
up
unique
objects.
Proof:
the
is
algebra
follow
as wefl.
Let
the
in
Also unless If I
to
easy
category
Artj-n
let
fr,
lenflth
finite
over
K,
the
t (
€ f
otherwise = 1 , we will
be
stated. also
exclude
iS
Fi,
i€
f,
the
alvrays all this
the
) over
equivafent
is
a certain
proposj-tion
category as dim-
just Fi
in
the
will
defined. (i€
becomes trivial, case
But
directLy-
modules
this
Because
In
indecomposable
l(M,0
that
M , Q )
chosen
ohieet v v J v v
sum if
proposition
from
L ( M , Q) .
objects.
generated ano
p r vr r er Jr v e
anri
sirnple objects
(AppendixA), of
together
category
q r r u
a direct
injective
prove
follo\ring i
=.t
lft
resp.
see later
wewil.l to
Q) has
projective
It
finife
j-somorphisms
to
t(M,
n
and
häs
v u J e v u
an abelian
build
defined
( rll , Q )
of
The rePresentatJ-ons
2.'l .2 Proposition:
-
Y by Hom (X, Y).
set of morphisms X +
the
f) if
following
_23_
2.1.3
Proposition:
In
a)
If
k € f
b)
If
k € l. is
particul-ar
Proof:
of
ßi = O for
then
(cr):
be an epimorphism Xk.
a source,
F*
f beasink,o= in
Bk : Fk -
then
and Fn is
be an epirnorphism
by
a sink,
projective,
F1 is
a) Letk€
is
f
(
M, O ).
vector ß =
Let
k+ l€f
Then
Then for
-
: It j
i,
F*
is
X
-Ef
ok
: Xk r
(>r= (Xj-,jei)),
€ f
, the
Fk
of
defined
I
injective.
injective.
splits
spaces,which
( Br)
projectlve.
is
must
course,
say
by
diagram
81 a1 IF -K'
nitj
\ I
x.
o
I
I I
il
M.
I
.(r. Ir-
lI o I
I I
$ (I x)j
€nmutes: are
This arrotrs
only
diagram then
trlvial,
to
i +k
and
therefore
k,
if
that in
i+
k +j.
the
j- = k.
case
1 = O, and the
ß, O
splitsr
( U,
L
and F* is
Because k is = O for
means jqk
a morphism in o
x. l
commutes aLso
Hence B is
b)
is
'1
Final_ly,
diagram
0 ).
all
j
a sink, € f
if
j
and the = 1,
commutes in
Of course
there
this
car_c.
Sg = ig
Ik,
Fk is
always
projective.
SirnlLar
Remark:1.)
The proof
a submodule of
X =
of (Xr,
(2.1.3) .q.)€
shows also, L(M,n),i.f
that k€f
isasink
JL
and xk k €| 2.)
is
+ (O) . Sijnilar a source
Simil-ar
Fk is
and Xn
arguments
always
a homomorphic
image of
X ,
+(o).
as t h e s e
Qne used in
(2.1.31, show that
it
-24-
k j.s a sink
respectivöIy
respectively
injective
Themap trith
= din
of
X,
0)
into
therefore the
OP
Let
ao
for
x =
all
arrows
Of course, but
5 i€r
(xr),
1
I,
I
€
the
slgE&l
(9im
X),
is
just
the
isomorphic
to
F,
in
can be considered
=
o BI""
y, ^
(Vr)€
qf (f
in
depends
L( [{,
e! taim X,dim
Y) ,'
respectively
Qt
-
0),
again
(with
Q^
chosen 8"0
xi
to
choice
of
f.
= dim*
( x,
Y )
Otp
Yi
sum is
respect
on the
Y) und
fi
second
, d ) with
we write
B (x,
d..
E i.-r.j
, where
we have
that
of
).
by
x,
f;
as map from
form
bilinear
number
a composition
L ( M,0
group of
crothendieck
i.--t.j
remember,
x
dim
0 ) defined
o Br""(x,1) = ^
called
is
0)
x:. =
(non-slrmmetric)
Br'" be the
.."n""a
of
projective
Fk is
if
QloefiniedbydimX=(xi)
L( M,
e
course
factors
of
L ( M,
x
0) . Of
composition
series
rf
(xr)o , , ri
L ( M,
map of
*
l(M,0)
dim:
x. .
a source,
taken
over
0 the
F,
fi,
for
i€
f
i- € f
instead B (dim X, dim Y)
t"r
(dim Y ).
!-
2.1.4i
Proposition: 'o1 (x, Y) iB-'" lrAProof:
Let
=
dittt j X =
Y € L( M
X,
Let
Hom(X,Y
(Xi
,
igi),
rJIJL
Then define Ä*,y t
.9.
aci
)
, -
Y
0) .
Then (x,
di-ttL, ext =
(Yi
,iüi).
(Xr,Yr)" o * " .t
tet
-a =
I i€f
o","
cr. € e i€l
(cr) = ö=
HomF. (Xi,Yi) r
,.1.r
:6i
with
€
,*t O iMj,Yj)
o i't'j
as follows: If
Y).
cj '
" o * " .) € HomF ^i
,.3.j ""*rj
(Xi,
Yi)
(xi e il'{j,Yi)
_25_ with j6i = jtr Now t=
( c. o 1) - oj jr,
oi € ker o","
,ä,
Letö= an
E iI ö i '€ i.-.i exact sequence E
6 + (Y with to
,,
O -.j ( ö ) by i.
canonical that
every
extension
and U and e
are morphisms in
Now E([
) and E( 6'),
ir,{., "j). is ln Hom (x, y).
(X.e.M.,y.).Define ----. r l' l''
is
they if
!
is
(
+
\Yio
6' =
term
xi'
€ . It
is
E
-(,
@ X1r
ri:YiOx.+YiExi
" (lll,:;l
rdith
Because in & ttre squares
by such t (,U , 0)
* ö r .L a r e e q u i v a l e n t ,
same eläment
in
Extl (x,
y),
if
diagram
('l: :l: ) + rr 1= (ri)
(irr,,u'i)\ \o tai //
-X
can be written
.{ä'l
in
easv
J
j
J
il
given
is
o
t ( M,A )).
a commutative
\-
tl I
the middle
defi-ne t h e
there
( Xr ,,ar ) -
y by X is
i.-.
and only
O-
HomF tj
of
(Obviously
@
ana onty ot i
.U and projection
injection
a sequence.
O-
"o\j
, j v i ) - I r - (" , ' *r, (3*o ;;i l )-
see,
(that
(xl o
a
x+ il tl :
+
in matrix
form:
'' 1( 1i )
Yi-Yi
(i) "' 1 2
"'i
-' 2( 1i )
Yi._xi
(i) "' 2 2
: X 1. + X .
conmute,
it
follovrs that
-Yi
1
-26-
?r.l\
lt
t- t = \-o |
be a morphism
Now r must the
' ' i 7' X i - Y i
i)
diagram
following
(Y. o Xi
- - ))
l-
o
L ( M ,
in
means,
Q) that
that
colunutes :
(Y. O xi)
iM.,
irj
"
('o
tl
tt:,
I
tl
\o (Yi e
M i ".i
o
)e(xt
(Yi e
iMj)
I,
II ti,*' o i\
t.
l
,tr)
\(r, jui\
:*t l
\
o x. /r
nontriv
jVi
( ?:- o
are
equivalent,
This
If
is
term
iai
1) +
=
Extl
r t.-.1 (x,Y):
nov, dim X = 5 = (xr),
x
I
-i " i l I o.e,/
-tt' 1/\
/\/\"l th respect
to
n.
is
and only
uch that
proves
,,,)
"
I ' i l \l i y/ i, ' .
.' t/ _ - \to
=j6i*?j
j6i if
-q- _q'
\rt/\ \ /. I l'
i.+.jinfwi
ri:Xi-Yi" that
)
\
,',/\" .l '
[ , V^, that means: l' \o \
The only
?'
j I tl j -^ , i\l l/,Ä ;' i \l I', \o
arrows
iMj
Y . O ) {j l-
l
for all
e (xi o
iMj)
.to.. Thus, E(6) and E(ö')
t1
if
t here exists
a family
?= (?i) ,
o 1) -?r't'or, :*r(ri (.6.-.6: ) =a.,(i),i= tji. r, j6i
-
j6
i
=
I-
i€l
coker \ -x,y,'
dim Y = a = (V1), then the K-dimensicn
- zt of
O Hom* (X., yi) eguals whereas the ti : ,I- fi *i yi, i€f i€f K-dimension of O Homt,. ( x r o Yr) is given by -i rMj, i€ r E i'--'j of
dij
-.
the
fi,
f1 xi i
€f
( here we need the
Yi,
special
choice
).
Now we have y)
Bao {x,
= climx ( domain of
= din*
(ker
= dim*
and the
2.1.5
proposition
Corollary:
Let
i,
A
Hom ( X , Y )
proved.
j€
f
i+
,
-
)
X,Y
is
on,"
j.
-
)
dim^
dim*
-
(range
dtux
(coker
uxtl
o","
of
)
1x y1
Then
1 t'l
i fl-1 I t
url =
dimExr'( F'
di:. =
dim". I
Proof:
This
o Bt"" (Fi,
Ei)
a) X
Then
(s*
b) has
= -
Let
F.i) '
from
drjfj
Hom (F.,
2.'l .6 Corollarv: that
Ext, (Fi, -
follows
because
E-i . . )1u .
.)
(2.1.4)
and
= -
fi
dii
= -
f be a sink
k€
has no direct
and X €
l(
summands isomorphic
i , l, e
)
such
ao Ek.
(dirn x
= dim",- Extl (X, Ef ) )) * f be a source e ) a L( M, ""ä a no direct summand.s isomorphic ao If. (dim X ))u
o
= dim"
Extl
such,
that
( -Fl k , X )
"k
Proof:
a)
Fi),
F'r) = O.
r,et k€
Then (sk
(Fi,
dim* Extl
By
(2.1.3)
Fk is
projective
slmple.
Therefore
x
o*,")
-28H o m ( x | F ' -^ -)=o,becauseXhasnodirectsumrnandsisomorphic to
So we get
F-.
A-I
X = x =
dirn
fk *k -
{x, rO) =
Br"
with
(x,) :
= -fn
diL fk *i
E
(-xn
:
1.r.1 = -f,-
(s,-
^ ^ ^ ^ - ^( d i m
x
= -
)),-
E
*i)
.dit
I.+.K
(X , F,-) and the
dim,- Extl
resuft
follows. b)
Sirnilar
Remark:
If
(dim x then
of
k €f
is
a sink,
) ,*- = d i m o .k
then
H o m ( -! [u ,
x),
course and if
= di^f,_
(dfun X)k
course
of
k€
Hom (X,
|
is
a source, (see also
F*),
(2.1 .3) ) . The following
is
simplicity,
b-"ß.
in
abelian
we formulate
(M,0)
X€ t
valid
is
called
it
for
categories, the
a component,
category
if
for
but,
End X is
L(M,O). a dj-vision
r r-ng .
v.-\L1o*J
Tv,ro components
X,Y
L( M ,
€
0 ) are
incongruous,.
called
if
Hom(x,Y)=Hom(Y,x)=o. Let
XqL
X€
t( M,0
( lvl,0 ) be a set
asequence such
2.'1.7
that
Theorem:
is
)
9=Io
Let
all
X < t
The simple
Proof: Let
of
Y€
X
for
L(
gIa_f
have
an
j-n L 1 X )
L ( X ) X )
and
is q
there
is
Io€L(^l,n),
components, L ( X
X-filtration, closed are
closed : X
if
SId=I,
of
subcategory
e ),
incongruous.
1< q< d.
all
full
M,
mutually
X-filtration,
be a set
which
objects
Obviously x,
c
(M,n)
L (
components,
have an
cx1
Then the
objects,
subcategory
to
X-ly 6 : ::o- 1
incongruous. of
said
of
-
with just
under t
L( M,O )
) of is
respect the
mutually
a ful-I to
elements
extensions.
be a morphi.srn.
exact
extension.;. of
X
_29_ Let
o=ä.Ir
c
X -flltrat1ons on d that tbe
the
is
o. Let
we get Yi = tor
1 5i5
i
Y
Let
of
If
and yi,/y. -:i-1
because Xl
-
S :i_t.
belong
to
X
.
= o(x,1) + yi_t
settins "j i
O=I;
+ 1 <j:n =
Ii
we ger
c
the morphism induced
!/y2
9!m_tcy-=y
by q. Then, by
- l
t( X ) . Because im q is
\de get
!n a€
an extension
r( X ) . Because coker ä = coker
X., c ker q
we have by in induction ker q €
then,
as above, we can assume q(Xl)
Äf = !f , and c restrj.cted
to xl
is
contained
in
X.,f1ker q = (O) . But ker s = ker är{ä
t(X). = y.,, hence
E n d ( X 1) , as above).
we ge: again by induction ker o € t(X). It in
is
now obvious, l(X).
q,
coker q € l( X ) .
ker q >11,
therefore
o(xt)
a(X.) = Y:
in ä by Ir,
Now if
we can assume, that
canonlcar projection " rrr,uI r _ t homomorphlsm from 11 to therefore lrl!r_1,
i:n ä e
we get also
For d = o
( with
and Yj = Y, for
- l
induction,
Syn=I
by induction
q (x1) 5 !1 ,
such that
a (Ät) o !r_t.
witir
g , I/r.
S .,.
x -firtratlon.
has an
9
anotherX-filtration of
I
prove
By induction
1s 15 n
_r ". 1s a nonzero )
an lsomorphism,
o =%SIr
We nill
a also
trlvial.
j-
Then _ x ,r
X resp.
image of
state$ent
q (It)+
!
of
=Iand
cä
...
that
X is
just
the set of
simple objects
arrd
-30Let X€
2.1.8 Proposition: L(x) : =
L( M,n ) be a conponent, and ( 2 . 1 . 1 1 ) . S u p p o s eK t o b e
) as in
L( {I}
Then
lnfinite.
, =
Qr(x) = Q" (dim t
> O
r
L(X)
is
semisimple
= O
€
t (!)
is
uniserial
\;
1^
< o
r
t,
It
Proof:
if
object,
must
@
(!)
then
on both
sides.
if
in
true length
full tt
-!.
E" + E^lq tz
nonisomorphic
with
is
x)
is
The Coxeter
(Xr,
respect
(X,X),
Extl
lengths
2
a subcategory'
forn of
not
finite tYPe.
an End(X)-binodule.
(X,
This
x)
-having
is
E1,
over
({)
E2 are
of
End
€ End
(x)
(x)
}
two
is
indecomposable
all
on
the
objects of
over
be uniserial.
to
set of
This
Ext'(X,X) is
also
L (X)
of X by
is
with
X linearly
then
left,
a infinite objects
dimensions
the
(X, X),then
extensions
say
If
simple
one dimensional
some m > 1.
for
subcategory
11
one
only
L (x)
implies
End(X)-binodule
the
semisimple.
is
Extl
End
over
j-ndependent
LetX=
(x,
End (x)< dimK Ext'
dr\
the
-
(2.1.7\
equal,
are
rn-dimensional
S 2
l( X )
of
representation
B (X)
and
be zero,
narnely X
FinaIIy,
{s
in which
Ext'
(x) > dirn*
dirnK End
Ext'(XrX)
End
that
objects
, ef (x) = Br0(x, x) = di^x End(!)- dim* Extl (x, x).
Hence,
in
known,
the
(2.1 .4)
No\"r, by
I
nell
is
and
non-serhisimple
of
length
nutually 2 in
t (x) -
functors
(f , d) i.---+.jbeanarrowin € t( rll , 0)and rOr) to Q . By the definj-ti-on of ,t{ we have jMi = ,"i =
- 31 H o m E , ( i M i , F i ) . B y trne he w werr e l l kKnown n o w n iisomorphism s (rtjrxj) g no\. _j , = xj qFj Ho*Fj (rtj'"j) ! x, e, u, and rhe adjotni.ness of rhe tensor product and the Hom-functor we get , gi Mj, Xj)g "orr.(Xi ! Hom". (Xr, ttorn,. (iMi, Xi)) : HorrF 4r Er(*i'*jQrMr)canonicalrY' r r I Thus,
for
attach
every
Fr-linear
canonically
and conversly an unique
a Fr-linear
to an Fi-linear
Fr-linear
map
6 =.0 .na F = ,f,. Especially .+*j
, *i-
j6j
map tp : xi
tr.
oi
Mj - xj
nap 6' : X. + V, Xi .+
map
ü , Xf ei for
we can *j
Aj ,i,
Uj tj corresponds "j X' such that
.+ "j , Xi Ei Mj ._xj
,o, Thj,s notation
wlll
"j
tire qet
be used throughout
paper.
this
Let k € | be a sink, X = (Xr, € L( M, n ). Then define ior) + = st I tYi, t ( rq, sn ) as follows: iVg)€ " First, if i+ k +j, i, j€f , then we set y. = X. and jvi
=
jei.
Yn is
ilefined
o i€f
as the kernel
xi 6i LL J r ^
enbedding
E j€f
of
the Fu-Iinear
.o. ^ I
, xk
i-n
O Mk. Let j€f "j "j by the projection tto.
U
u followed
with
j{r<
=
xj
.fl irr.). Then define l€f' " -t tt tj Yj = X, for "k
jix
an arrow in arrow in
If
(sj)
( f,
=a
(f
,d)
with
respect
to fl
d ) $rith respect to su e
: X
-Ir
= (Xi,
iai)
natural
t yk .+Xl
1rk rp,
(Thus p =
map
tt
"I onto xl
k:+ j€f
(rf
"j
, then
k.-J.j
Mk ol
be \,
j . --r. k is
l€f
is
an
(see 1.3)).
is amorphism in
L(.M ,0),
-32define and (sl
s)
is
*
u
.
tl ':?, *t
** - -
"
becomes a functor
Zi = Xi
=jei
, jni
For zk hre take the cokernel TI i€r
.O. I rK
let -r?,
xI s t{k . set
=
kti
Ifo:
nn,
.2.2.1
Lenma:
+
j€f
o'
by
followed
n (r =
,n*
,ä,
(
Zi = t Si x')t
-
,
"ru
i€f
q 1. In this was sf, .!_ oi i€f !6 l(M,s*0). rt is easy to see, ttrat sl right
11g,sno).
the diagram
Mk
"i
i,
jti ) isagainamorPhismin "i, then define sf S = ß = (ß1) by ß, = c, for
and ßn : Zn
and sl
i+ k+ j,
injection
for
[+I'=
q = (si)r
tr
= (zr'jni)€t1rtr,s*a)
= !
be the natural Xi
kni
in
for
uk gzk
xk .--.....-"..-.-_r3,xi ti
For I€f
k +i€f
r ?, "i "j
L ( M, n)into
from
Let now k be a source. Then define s; I as follows,
for
):lr*irj*x.
way s[
rn this
o )r= o,
tsl
of
the restriction
j ?.(oj " royk
i.e.
by restriction,
tig
L(
M, Q ),
i+ k
to be the map induced by
also becomes a functor
and sf,
are additive
from l(M,O)
and sf, is
left
exact.
a) Let k€f
Tiren canonically sum of copies
be a sink. Let o + X € 8( M, x = a* ti I
o1 If.
e !,
More exactly,
0 ).
where P is a finite' if
either I = Ex (i.e. s; ti I = o) or x:
x is
direct
indecomPosable'
then
s* sl x+o,(i.e. si x+o,
- 33 -
and lt
indecomposable).In
(sf x) = nnd (!)
rnd b) If
the latter
case also
x) = sk (di.,n x ) .
and dilu (si
k is a source. we ger Ä = Si S; ö O f,
finite
direct
of a) will
Proof:
is
sum
of copi.es of F*.
The
j.s a
where.r
analogous statements
hold also.
a) It
is
definition
enough to consider
the k-th
component. By the
of Sl and Sl we have the fotlowing
(notation
as above):
o+(s;I)k
-J-
o
exact
dlagram
*j e jtr
j€f
Il '
7
.t
/
-+
(sk sk x )k
I
I
o with
o: =
we have ker o= ker t(= imu), kej. .,ta, there exisfs pk Xkhrith p1t = o. tS* Si I)k -
Let a € fs* si { )* wirh ek a = o and rer o.:?, with
t(b)
define
then p = ( or) Now, if that
=3= q. 5o = . gi
tU", r
ti
ti
X +
o is not surjective,
I=LOP,
r,rherey=
for k +i € f , P€ L (
": " :\
= a. Then o(b) = pkr (b) =pk (a) = o, hence
b€ im U=11sr ,ire.t(b) k + i€r
so
t xi
= (si
X is
a monomorphism.
then it (yi,
Yk = i*o,
M ,e ) is a finite
pk is monomorphj-c.For
direct
=
-+
Xi,
can be seen as in
jti)€
jüi
s; I)i
jQi
t( (i,
(2..l.3)
r 1 ,{ A ) w i t h y i = X i j€ 1), and
surn of copies of Fn, in
34 -
particular
projective.
is
, then
-K
indecornposable,
K
then
of
composition
=o.
o=oandslsln. o
has
any
two
maps
be surjective
is bijective,
is
I
Finalfy,
ls
rhus trre
+
ena(si s* si lt Iil snd (S-x)
e n c l( x )
ti
-K
in
K' E"d1s+x1 -5- nnd(si si ll-5 Iil
is a Iocal
hence
and
s[s; sf, I.
{l:
qcq
Endx
rfx+F.
K-K
to
x.rhen we have arso
ti
l:ti
p= Y,
im
op.
x = y o p d t s f s l^ xK -) I f x =_ F .
By construction
End x !
therefore ring,
nrrd (s+ x ) . Nott End (x)
and so the same is
true
for
nnd tsl
and
!)
indecomposabre. the exact
sequence
.----_ x,- x )t ---------.9_ (xi. a.r Mn)r ^ tk K
o -tsf
o
i€f
yields
dim
the
( ( s i -I ^
formula
) k ) F' k. ^
=
L i€f
=
_
dim
dim
(x.
(Xr.)r.
.- -k
Ei
+
Mu)^ !',.
E
i€r
ä di in^
ilim
(xk)F. " 'k
(I i "Mx )\ r i . . roi n*
=
,(!x i ) F i
(sn ($m I ))k, h e n c ed i m ( s i I ) = s k d i m ( x ) . b)
The proof
will
be analogous
/l
to
a)
considering
the
diagran
/xx
/l o -(si
t/+ s; I )n -r:r*i
Ei Mk +
(s; I )k -
o.
-35-
Remark:
It
is
easy to
indecomposable
prove
brith
as above,
that
Stx + O + Si y
for
there
y€
I,
[ ( M , e )
holds
Hom (X, y) = Hom (StX, Sry).
2.2.2 Lernna:
a) Let k€f
be a sink,
X, Xi €
indecornposable, and assume Sf, X, +1O1 Then S[
induces
sl
X, ? t*1 .
extltsl x, si x,).
be a source, X, I,€
indecomposabte, and assume s* I sf, induces
(i.e.
an isomorphisn
sf,: extl (X,x, ) b) Let k€f
L( M , e ) be
t(
M ,
+ o (i.e.
0 ) Ue I
* f*1.
Then
an isomorphisn
: extl
(x, X, 1 ....-..._
(s; I,
s;gl
s; I,
).
X = Ek , then X is projective by (2.2.1), so Extl (x,x')=(o)= Exrl (s+x,ri",), because ,i I = o by (z.2.11. so let s[ 1 +o ). let
Proof: a)(If
Ue O-Xt
irith
U =
+E
(Ur),
Obviously,
e =
rde need
(e.)be only
r
+O
X
an extension
to
verify
that
of the
X by X,. k_th
component
of
'\a,r; s l r ' ) * . " * " , * , ( s ;E ) n r)k tcl
o -+(
,.t
is exact.
Let x = (xi, jpi), I'=
Then
the
we get
following
conmutative
,^+
o
(xi , jei ) and E = (Errrtr). diagrarn
o
U
I
+
o
I (s; I)k -
(s;I')k e
O -'O
xi r
acl
I
U. q 1
siMr
: ä9 r- -*-j j
I
I I
I
.t
o-
xi I
I
and the
third
first
to
see
middle
that
exact.
Finally,
shows
ttrat
are
the the
middle
has to
tsf, e)*
and the
column of
the
Nol.t it
uPPer
row
b)
with
f
the
the
similar
diagram
right
= t1,...,n of
sequence
dimensions
involved
Extl(six,si
x'),
map.
exactness
of
the
sf, is
vtith
resPect
L(Il
c-:=s]sl
...s":
L(M,0)-L(
functors.
and C-
sequence particular
Simj.lar,
do notdepend with
on the
respect
to
of
the
choice
as
1,...,n (1.3.1).
(1.3)
specj.al
Q . obviously, bimodule
Sf,
and
is
an admissible
Then the
functors
Il,o)
,Q)+L(
in
of
proved.
easily
e
to
...si:
Coxeter
exactness
left
ordered such that
)
sinks
above,
c+,=tltl-.'
C-
are
Stunilar
Remark:
Let
is
be surjective.
an inverse
S-* induces
are
).
rn this way, sf, inducesa mapfrom Extl(x, X') and obviously
The
exact.
X and X'
since
(see 2.2.1)
X
caLculation
are
rows
exact,
+ 9 n s;
I
+o
o
Iower
and the
columns
and si
indecomposable easy
II I
n
the
o
I
.t,
t
-
ojtj
J x,x
By assumption,
o
M,Q) it
can be
choice they
mappings
of
arecalled
seen.
that
an admissible
depend
on a
-37-
Itonr, (iMj, Fl) =
jni:
hosever, '
(itj,
the
cholce
For .l
theory.
:t_<
L( g, sa...
of
these
n , I*
is
sn a ) = [(
s!.mple module in
= t(
sa...s., 0 ).
M,
implies
sa...srr0
"t_l O= st
... s' "t_1 (1.3))r(t-1)€ r is a sink,
Dr_t rnen sr_2 etc.and a module in
'(
SturilarIt,
= s;
This notatl_on will following
c woll
c = sn...sl
b)
...
, = s;
O ) "r, = sn ...
denote the Coxeter
L(M,
sr,0) =
this
sl_r
It, g( M , n ).
B( M, 0 ).
paper.
In the
transformation
O ) beindecomposable.
statements
X 3 P* r-or some 1< t< n.
iii)
c+X=o.
lv)
c ( d t u nI
Dually X is
t{
some 't< t
c-I=9. -1
equivalent
injective for
are equivalent:
o.
rde get the following
X = It
(dim x) I o.
"t0
e = c-1fl
...
is a nodule in
ii)
lv) c
!t
st_1 st
X is projective.
iii)
...
e ) . rn st ... srrn (Uy "1 therefore we can apply first
,i)
if)
=t Q) and an
s1 0 and sirnilar
be used throughout
LetX6
the
...
r1*r I.
Then the following
i)
...
€Stl.
2.2.3proposition: a)
...
for
simple module in
"t_2 L ( M, sa*'
get finalty
l/, s1 ... ...
a projective
but
irrelevant
"t+2 (Notlce, that 0 = c e
=
implles
mappings ls
M , st_1
lnieccive
( 2.1.t),
rjl
"o*,
statements:
-
-
Jö
We prove b):
Proof:
-
ii)
iii)
= s:
t I
...
c x = s;.-. ."ri ..... + ii)
iii1
r s;
t"
...
tl*,
"i*,
imPlies
I.
= o implies that there is a 11 t1 n
I
... t" I = sl I = o.
with sl*, ... s" x = y +9 uut sl ti*, Hence by iii)r r
ii):
they
are
i!
I.a ,
11 t
annihilated
by
All
indecomposable
by
vre get
modules,
hetrce all
...
11++-1
Extr(x',rr)
-
...
Q.2.2) 1++
we sho\rl, that
If
inlective
Ea.
because
non isomorphlc,
functors.
different
are
AIso
they
this
modules
are
injective
indecomposable
indecomposable
L
s;
(
M,
+ o.
I'
nonisomorphic
Sn
-X ' =
First
Q ) be indecomposable. Then we get
= Extl(I', sl ...ri*, is lnjective in
b e c a u s eI a tft
pairwise
n nonisomorphic
n and X'€
assurne s!*'
S:
are
ti*r
...
(2.1.21 .
modules by 1 sts
Q.2.1).
injective,
Let
X = si
= Et , and therefore " Obvious by (2.2.1).
12.2.1,
(iv):
that
l. = ri ... s. Et = 9 by (2.2.1).
(2.2.2)
"t+l...sr,
for
and
(2.2-'l);
nxtl (s.*r...s; I',Fa)=o
r.)!
L ( M,
O . t h e n X = -I^, -
by
0 ). If
some n> k >t.
Again by
and (2.2.'l ) we get
E x t r ( t ; . . . s l * r l r . , s i . . . t l * r E . ) ! e * t 1( E r . s, i . . . s l * . , r . ) , Er., ti
...t1*,
Ft€ [ (M,s1+1...sn Q). rr
source. of course, 11 is not a direct
"k*1...s. s u m m a n do f s l
(2.2.i\ rherefore by (2.1 .6 b) ) din
r*+1 re
(x',
2.2.4
Proposition:
"*
...s|*f
It)
= o and rt
Let
X€
_ I
a)X=CC'xeP,whereP€
L (
is
injective.
M , 0 ) . Then
L
(M,Q)isprojective.
Ea
sl+1 !r)
s ; + 1 E r ) r=* r " n - f 1 . : = . . ; ; - . ; - " . ; ; - =
= ( s k ( d t usn; . . . Hence Extl
Q,k is a
"
=
-
Thus,
lf
1< t5i n,
39 -
X ls
lndecomposahle,
i.e.
c* I
1 < t
Proof:
2.2.5
either
i.e.
C- X = O, or I
= C* C
Ext'
Proof:
a)
( c
b) If
If
k €f
=
a sink,
t*
(dirn X ) .
F* as bimodule.
enough to prove a).
choice
of
Because C- döesnrt
an admissible
(2.2.4).
Also C- lf
(2.2.3),
and. it
because 1 € f By (2.1.6)
is is
sequence with
k = 1. Clearfy
C
* O, otherrrise
refrections
of
in
f
sequence for
,It
respect
f.,,
{
depend to
0
oth.rwise
( 2.2.3)
and
F1 vrould. be injective this
is
impossible,
>1 by general
assurnptlon.
E x t l ( C - F 1, F 1 ) = ( s 1 ( d i m C - F 1 ) ) = 1 ("2 ..."r, ( gjr F1))., = 1, s; F1))1 =
d\,
because the a vector
and lll
El
= O by
easy to see, that
a sink
( dtun (s;...
O
X, and then
then
we woul.d have F1 = C' C= C* E1 Ir
exact
some
r* t* r* as bimodure.
,*
we can assume, that
(sl
for
It
is a source, then
is
on the
=
I
(C- X) = c-1
is
=
(Fk, ctk)
It
) tsinjectlve.
(2.2.1'!.
Et'Et'
k€f
1a
l v l, 0
indeconposable,
Lemma: 1-
(
t
some
(dirn x )
X is
Inunediate by
Ext'
€
= End X and dir
End C- I
I
) = c
(c+x
b) X=C'C-XOf,whereI if
=
!a for g = o, or x c-c+ x,rand then
End C+ )i = End x and dim
Thus,
either
for
s,
donrt
2< L< n.
some E €
+E
L(
change the
first
component
Thus \"re have a non split l/,
0 ):
+ "-1Er
q.
-40and we get an exact Hom (E, It)
sequence of F.-bimodules.
-
Hom (F1, Et ) -
Extl
But Hom (E, 11) = o, because the extension
split
doesn't 't
pro jective.
and
Fl
is
and
by
dimension
this
-'r
r Ext'(
C
Et,
)
Et
=
said
Hom(F1 , F1 )
must -F' .
be an
I'
c-4
Ext'
(C
- 1' F l
, It )
Thus
isomorphism.
as bimodule.
Er
L ( M,
Let x € X is
Thus
F1).
,q- Ef,
0 ) indecomposable. Then
to be
a) präprojectir.'e s o m er > o
(indecomposable),
if
x = c-r
Pr for
x = Cr I*
for
and 1
b) preinjective
(indecomposable) , if
some r> O and 1< t< n.
a) If
2.2.5 Proposition: 1< t< n, and C
1 (
M, n )l
c+ x+ o,
of
FaFt
F*
x = c+tJt,
as bimodule r>o,
13t
5n, and
then
nxtl
This
Proof:
= C-t 31, 12 or
X + O, then
extl ( c- x, x) ! b) rf
( M,Q )l I
L
(X, c+ x ) =
statements
Ft F. r .c c
as bimodule.
are straightforvtard
consequences
(2.2.3) and (2.2.5).
Let r:'O,
t (
M,
0) ) x = c-r
Pa (or
1 1t< n. Then the position
by : pos ({)
= n.r
+ t.
If
x is
cr ra ) with pos (X) is
a fi.nite
defined
direct
-41
of preprojective
sum
nodules
(or prelnjectl_ve)
[ ( lr,l, 0 ),
Xt €
preprojectlve
-
(resp.
then X will
preinjective)
indeconposable be called
also
and pos X is deflned
by pos (x) = max pos (Ii)
2.2.7LeIuta:
a) LetX,
Y€
Then Y ls preprojective €
I
of position
L ( M , A ), I
preinjecitve
of positlon
a) First
and Horn (!,
let
< p.
preinjective
of posltion
p,
< p.
X be indecomposable,
o< t
X)+ O.
and Hom (X, y) +O. Then y is
Y indecomposable,
Proof:
e ) andXbepreprojective
p. Let y be indecomposable,
of position
b) Let I,
L( M,
X = a-tgt, Hom (c*ry,
p*)
c+r y +o .
N o w -PE. = s :
- .. St-.! Ig, thus we get O+ Hom (Y, X) = , n o r n ( s - a _ . , . . .s ; c*t !, Fr), in [ ( M, sa...sr, 0 ) (in which Fr is projective
simpte) , if
But then every homomorphism is
si_r
...
an epimorphism and splits,
hence - by the indecomposability
of y - is
and Y I
= o, then ir,s
that
x.
rf
s;_l
...
S;
c*t I
Y has to be preprojectlve
For arbitrary
preprojective
S; c+ry + o.
of position
X the proof
an isomorphisn easy ro see,
< pos (!).
is
now obvious.
b) Analogous
2.2.8
Corollary:
a) Every subrepresentation
representation
in
b) Every quotient is
t
( M,
e ) is projective.
of an injective
ln jectj-ve.
Proof:
of a projective
Obvious by (2.2.7)
representation
in
L( l.{,0)
-42-
2.2.9 Proposition: for
only
a) Let x €
a finite (M,
modules Y€L b)
Let
t(
X €
number
of
we prove
(2.2.4)
Let
c+qI+o
€lN
0 )
nonisomorhic
Then X is
t
a).
and Hom (X, Y)+ O onLy for indecomposable
clearl-y
X be not all
für
such that
q,
is
r
a finite L (M , Q ).
Y €
modules
a sink.
PreProjective. q>o.
Changing
€ IN, q >r
x to
be inde-
Then by
(2'2'3)
vtecansuPPose
Therefore
(dj.n c+qx)a+o
Coxetertransformation Let
indecomposable
preprojective.
for
there
exists
q>k'
all
and
1
Nor"
in L( M, st-l...s., Q ), in
o + c + c + 9 xi m p t i e s t l - . , . . . t i " * n l + o which
0 ) and Hon (Y, I)+
preinjective.
composable.
o
M,
0).
nonisomorphic
Then X is
Proof:
number of
Al,
t(
orientations
we may assulD.e that
t
= 1'
c-lr.,
:
c-tqt'
and assume that
the
and analogous
Then
t g = c'Et Z g- r9-r- t +
N
-ln-r-l)
b y ( 2 , 2 . 3 ) . T h i s s h o $ r st h a t "., g = c - * F t + o b u t C z = o f o r s o m em € I N ' B y ( 2 . 1 . 3 ) a n d +k+1 +k+1 o' Let o+ d € ( 2 . 2 . 1 ) H o m ( z , c ' - I ) ! u o m ( ! 1, c - ^ - ' x ) * + L +l Hom(z,c*^t' I). By (2.2.3)z is injective, hence also being injective c*k*lx must be itserf im a < c*k*1 I, "o indecomposabl-e. But c-c+k+'l x = c*kx *o, a contradiction ro (2.2.3). so{ lc-qr, I q t x} is a infinite
set of pair\tise
non
iso-
I nom(c-9p,'x) morphic modules. Furthermore o +Hom(Fl, c*9 x) by (2.1.3) and (2.2.1' for q:
k. This proves the Proposition'
-43-
2.2.'lO Proposltlon:
LetX€
a) Then the
following
X is preprojectlve.
li)
There is a g>O
indecomposable ! the
are equivalent:
C+q X = O.
such that
Horn (Y, X)+ O only
Dually
).
statements
i)
ili)
b)
l , l, 0
[(
for
(M,
€ t
following
a finite
number of
n ).
statements
are eguivalent:
1) X I-s preinjectj-ve. ii)
= o for
c-ql I
someo< g.
Hon (X, Y ) + O only
iii)
for
a finite
number of
inde-
conposable Ye L (M'0).
Proof: i)
ä) We can assume that r
ii):
iilr
i)
Let x = c-r
'
preprojective
are only
modules of ii)
i):
2.2.11 Proposition:
pt,
r:o,
= nr+ t = : p>O.
then Y is there
+ 1 will
Et for do it
some o< r,
by (2.2.3).
: Trivial
i) riii) pos (I)
x = c-r
By definition
n. Then q : = r
1 :ti
X is.indecomposable.
finitely
position
of
1
By (2.2.7),
if
H o m ( y , Ä )+ O ,
positj.on < p. Of course
rnany non isomorphic
< p in
preprojective
! ( i,{ ,n ) .
(2.2.9)
a) Let,
for
some r >O and 1< t< n
= o for all 1< s< n. 3t = O. Then C-(r+n-l't" "-r b) Let, for some r > O and 1
-44r+h-1
C- "
'I_
= O for
_S
Proof:
all
= (t;
...
exists
11 s< n be a neighbour of t
= (si
then (!")t
-f
such that x = C-(r-1)pa+ o, but
a) Choose r>o
C-I = q. Let
in
11 s 1n.
...s;_1ls)r+
tr.,t., ...
o, if
t"_., E")a+ o,
e€ {o,1}
in |
t> s, i.e.
if
, (c-ps)t=
t< s and
there
(C-egs)t+ O. By the remarks
such that
(2.1.3) and (2.2.1) Hom (par c-t!")+ o. Assume F - I' 3 " * o. with the remark in (2.2.'l) we get
r-1+ C '- "
t'!",+
Hom (x, c-(r-1* and therefore
o. NowX is i.njective (2.2.3\,
every epimorphic
every image of X in i.e.
e)n.=g-a-(r-1*t
indecomposabre. This implies a-(r+ by (2.2.3),
it*1)!"
thus in every case c
proceed with
hence
must be injective, "-(r-1* *,r"a be j.njective, because it is
'!"
C-(r-1+e
image of X (2.2.8),
t'E"
s instead
This shows finally
t considering
c*(r+n-1't"
'r"
= o. Now
neighbours
= O for all
of
s in
1< s1n.
b) Similar.
2.2.12 Corollary: and J=
( f,
b)
P=
c)
statements
1
Jc [(
M,
Ä . ,{ 0
)cL( O )
)
. Then the
are equivalent.
J is
)
d)
t ni
e)
Pc J (resp.
are
< t
rtO,'l
d ) is Dynkin
P (resp.J
Proof :
P= tC-3rl r>O,
{C+r ltl
following a)
Let
linite
+ Q
wj-th
J cP )
(2.2-11')
equivalent,
irnplies
a*tf"
it
is
becaus" = o
for
easy to a-r
Bt
see, = o
b)
= o,
c)
(some r>
some 1< s< n and vj.ce
d) o,
and e) 1< t-< n)
versa.
f
.
-45_
11.2.6)
shows, that
e) r a)
: Let
(f,
( f
a)
implies
e) .
, d) not be Dynkln. Then, by (1.1.2),
d) contalns a subgraph ( f,,
Euclldlan
or one of
the
following
(dt2,dzt (r1 ,91 ) = 1t -
r)
(12, 92) =1.
ii)
d.tZ dZ.t = 3
)
'3
(d12' d21)
whlch is
graphs:
wlrh d1
zdz.t25
(d23,d32)
. ,
.,
wirh
d32 = 2
and dra
(d12'd,1).
(13, g:
rir)
d'),
1 =',.
(dzy
dgz).,
r.
with
dtZ dZt = 3=d23 d32
Let Q'be
the restriction
be the restrictlon L (M there
"
1s a full 0')
(*, (e x) . =1 ' '
e
exact +
L ( M ,0
is
true
0').
clearly
L ( l/',
We will
1gi.-.j
) rr , , . o . =G l'1
0')
e and consider
L( M', 0').
inf,
otherwise
/o L
and similar
for morphisms.
L ( M' ,
as subcategory
show, that
modure, which for
(M,,
and
) by setting
otherlvise ,
).
d,)
( Ä{,,0,)
ernbedding
fori€r'
a preprojective this
( f',
ft A ) to
L(l{,0
X = (Xr,ror)€
Thus we omit of
( 1,, d'),
to
Q',) the rnodulecategory of
e: L(M',
for
(
of
of 0
is
O' )
L (M , e) contains
not preinjective.
Then, by d),
Assume
no preprojective
- 46 (M',
[
module ln
(l
be the Coxeter element of
, d) with
1 is a sink with projective
respect L'( lll',
in
F1 is not preinjective
resPect
to
and'
O
we can assume u = 1. Thus
ay changing orientation
u € f'.
Let c = sn...s.l
is preinjective.
0')
and
to
0
0')
and
in
L ( M ',
and F1 is
Q',
L( l\{ , 0 ) . By assumPtion, by
therefore,
0'),
(2.2.1O) Hom (Et, !) + O for infinite many nonisomorphic modules Y.€ L(l'l ', Q'), hence the same is true in L( M, 0 ) and F., is not preinjective by (2.2.10).
Therefore
Thus hre can assume ( f, the projective
that
= Ct Ia
assumeIt
by (2.2.3).
(1.2.7)
"-r1 given
all
in
the tables
(f
For x = (x.,, xr)€
formula
(s-(r'+1){,)), r foraU.
{o
for
i = 1,2,3').
di),
the Euclidian
graphs, that orj-entation
d1). Let l € f be a sink, c-1 =s1s2.
O2 we get
it
1)x., - d'rax., dt2x1-x2). is
(c-r(t))r>
easy to prove by induction, o for all
r > o,
that
hence c-r !
r:o.
Assume ( f,
d) = ( t 2 ' 42) wittr
(d23' d32) = (2,1\. source.
t
in Appendix C) .
'(1) = (( dztdt2-
Vtith this
, d) = ( f i,
(with the special
rio
d) = ( ft,
Assume(f,
Thus
we can choose a special orientation
we have seen for for
show
is not preinjective.
is enough to prove c-r
(1.2.8)
{ o
we will
d').
some r> O, 1< t< n. Then c-(r+1)1< O
for
(of course also, if
In
c
d) = ( f',
module Fl
Hence it As in
r:O.
Q
is not contained in J also for
P
Q).
l(M,
all
L (M ,0 ) again
in
Then
1€l
(d12'
d21) = (3 ' 1) aPd
beasinkand3€f
a-1 = - 1 s, s, and
bea
/o
-47(x) = (2xt * *2
c
xr, 3x1 * *2 - x3,2x, - x3),
I = (x1 t x2t x3) € e3. now it .
(c
-1
this
x)3 1t
<
(c
of
easily
let
if
modules in
cases
. Call
is
to give
Let x,
fleld,
and ( M , e ) be
a connection
( f,
d) with X€
l(
M,9 )
Our purpose
between the additive
as dirnension types of
subject
between the corresponding crucial,
of argebraic
z et
groups. (for
lemma we need some For this
ex. [2O] or
sre refer tll).
( It{ ,0 ) be indecomposable prejective,
and dirn Z = a::n X + k. k € f
is a sink, o-IL-z
b) rf
<
similarly.
or preinjective.
For the first,
to the standard books in this
a) If
O<1
proved
( M, e ) and extensions
of
arguments from the theory
k € fr
are
From
a representation
considered
| ( M , O ).
2.3.1 Lemma:
that
connected graph
X is preprojective
of the roots
representation
induction,
of a valued
paragraph
structure
x3 <xr
K be an lnfinite
orientation
prelective,
if
modules and extensions
a K-realization
in this
by
The other
paragraph
adnissible
<2(c-'3)1
x),
roots.
S 3 Prejective
ls easy to show, that
-.1
follows
sequence
In this
-1'
k€ f
then there exists -X
an exact sequence +
is a source, then there exists O
-X-Z
o an exact sequenc,-
t Ek.+O
-48-
a)
Proof:
=
Letlfl
n and 1 €
(yi)€Dln.
variety
affine
-) , . . H o m " .( F r - o i M j , F j
n-.-Yi^Y;
v y = i.
Then every v = (rer) = i.l.j i.dentified
,
course
because grouP c =
.fl
of
ditnension
as variety
irreducible over
space
size
of
Fi
GL(Yit
Yi
acting
( direct
Fr)
GL( Yr,
so open
K' Let
infinite.
K is
over
can be
€uX
jei
tyPe
I.
K being
over
a
I
vector
full
t ( M r0)
i(pj)€
is
U
=
,iiläil.,.
the module
wlth
v (Fi
Of
the
consider
sets
ln
UI
are
be the full Y. and let on F '' Fr)
on
acting
Product)
dense' linear
'y
as follows:
(si)
r,wi for
= si
jVt)
.
in
Y = (Yr,
with
j
(ei s 1)-1r ( i'
an isomorphism between (FiYi, [ ( M , o ).
,or)€ ident j"f ied wl-th (
modules in
,,0,
(j{,,i)€ur
in l) '
Vy, g = (E.)€ G'
( jai) €
Then g defines (F'i,
=
'(jei)
i9r)
ancl
on the other hand
11 l'{, 0 ) },ith dim Y = I
can be
describes all U e Uy, "o I ,tor) of di:nension tyPe I' Furthermore' L( M , 0)
Y , x € L ( M . ; ,0 ) , 1 (dirn 4 = djrn !
= !)Fre
(Yi,
191),
isomorphic
= (xr,
x if
1 Ü i )'
and only
if
_49_
(ta.
(
U--and
)€
€Uv
i ü iJ) L
.x.
under the action
of
l1e in
the action
of
G and the
modules y €Lttt{ , 0) with Let fl
be the
extended
action
between the orbits
9f
isomorphi_sn classes =
dim I
algebraic
by base extension
of U v ! ,. , vr
G.
So we qfet an 1-1 correspondence under
the same o Y -rvb - Li t
X.
closure
Uv
of
I. of
K let
of
(, and G. Then [. LY of ö on 7..*, defined "."
tu,
E, defined
ana G and the over K.
F
Let
v € Uy
ö v is
be K-rational.
defined
open in
itrs
over K. It closure,
Then by [Humphreys, p. is
well
known that
hence ö v n U' is
öv
21gl
is
open therefore
dense in
U.,,if the closure of ö ,r-i" V,r. this happens, rof course, if dim ö v = dim 7rr. Furthermore if v = (iei) €q,, L JL )L then ö.v ftUu - G.v. This can be seen in the following way. Let
M(k,F)
i.r,ot"
enbed G in M =
the kxk-matrix n
i€r
I'{(yifi2,
of F. over K. Letn of
c in Ivl is
over
a field
K) by a regular
EK M and notj_ce that
the closure
space of
(which also
defin.
d r., M). For
jti
( m i o ' l) f o r a l l
€ ö.v
F and
representation
a subvector
polynomials, w = (;t.)
=?
ring
M defined
d
by linear
tet
JL
t
= {rn= (ri)e
then Norr i
the
üt m, jet=
transporter
Trans6
j,s a subvector
et €G. v implies subvector nt(]),..., the
v to v/ in ö is
by the equations
inf}, fn ö.
by the
linear
*j
=
j"i
,rlr(mro are contained in K. because w€U . Now i Transc (v,w) +9, hence tnö :.s a nontrivial
space of ü containing m(1)e fi ot tnö
defining
of
space of fi defined
polynomj.als determined whose coefficient
(v,w)
i .-.j
linear
- \ ,T r a n s F ( v , w )
, and a basis
can be choosen in M,
polynomials
because
of i n ö have coefficients
1),
,.
-50-
polynornlal in Transc
*
det(1., .(1)
in K. consi-der K
t11,...,
(v,w)+ 0,
thts
rrlcR
polynomial
+ ...+
det(t1mut rl t
t1*"' i.e.
ll l
trm''')+ al I
+ ...*
alrt''
. Because zero.
cannot be identically
so
o, becauseK is infinite. G = Trans"(vrw),
€ Trans6(v,w)n
w€G.v. E f. j.€f
NowdimG-dimU.,= L
e!
trl ]
[ 1 . ,, . . . ,
K such that
Therefore there are t1r...rtl€ , r\
+ l,rn(r) ) as
...
= Or (I) ,
t1,1)
so let
yr2-
(dimension as varleties)
Y = (Yrtror)€
and indecomposable.
and the definition
of prejectives
End I
Of course
Assume
Then by (2-2-1)
there
such
1o€l
is
= ft = Fi Iclentify Y with (iqi)€U and - o ' - o J r IQ . ( 1 ) the unit group of End (!) is nothing else the (Y ) of Y j.n G, and there C^ g-
centralizer of varieties
1f Y ind
orbit
)
.
dim Y = y.
with
L (M,O)
Y to be prejective
that
f.dliyqyi= ' rr
E i.-.j
"/c"tg)
+
is
an isomorphism
G 'Y, where G' Y
denotes the
Ur.
Hence dim
G/c"{Y) = dim G . Y as varieties,
i.e.
dim G. y = dirn c - dim co(Y) = dimK G -di\
Fi -o
- fr + dimU., - fi 'oL'o = dim u!, thus the closure hence dense in
of G
Y in
U" is
U". In Particular
t/,
and G
thj-s is
Y Is oPen
true
for
Y in
Ux
the groups also write in the V To distinguish z. following G = Gy. z,x Now write tn * Tr the natural projection -.=f'n'k e f'O and let z'-x n for + , Vz -Vx o. Define o rkk n : F*
and Z in
v = (ator) €U" Jr4)L
by o(v) = w = (iVi)€
U*, where
-
=
jti and in
f,(
" iMk we represent
if
with
respect
l'*xk
= F*xk n F*,
to bases of acting
f and j +k
in .-
Fkxk, for (ror)
(ie
from the
left,
to
.k
i.-
as family
the f.zi
the rrow corresponding
l)
of matrices
conFatible
with
then we
the direct
summand
Fkzk = Fkxk o F*).
Fk of Clearly
c is
epimorphism. q
-.j
i.
: F.xi
i.e.
delete
if
jei
=nipi
*ti
51 -
a morphism of varieties, Consider
is continuous,
in particular
the preirnage
o-1 {G* x;
GU z n o,
in
fact
(cx.
a-l
an
X)c [/r.
is open h"r,.u d.rr"e
-' -{ c *
I)
+ e,
L.e.
there
Va,
ln is
some
= trli, L ( M,o) fsornorphic to z such rhat jai); fu = (Fii', q ( is i.somorphic to x. jqi) ) € L( M , a) Of course we can assume I
= Io
B = (Bi)
. L-
= id(Fizi)
Bk = n.
Let
that
X
Uy 8i
i'.+.k
followlng F.zi
a
.
|
id
.Mu
^
,
o
l*'
of
foand äin
k €f
is
a sink,
L (il , 0).
j. + k and
I and remember
Then for
i.+.k
in
diamgrarn F.xi lI
e .\
Ja(*or)
',*
tn*k
by the definition the
o .t"t, = F.zi 1 K
I
-
t*'*
commutative
for
be an arrow in
| . (r.
is
L
and Z = go. Oefine
we assumed k € f to be a sink.
f the
Because
isomorphie
this
Of course
class
means that ß_is
of
c , and the choice of
B is
Z resp.
X. Because
a morphism in
a epimorphism with
kernel
T h u s w e g e t t h e d e s i r e d e x a c t s e u q e n c eO - E r - Z - \ - O .
FO-
-
b) Here we consider
the variety
H o r n o (. F i Y i , -i
ul = II I i.-.j where G" acts
on U!
(FiYi,
t(M,0
jei)€
with
(
modules in
betvreen the
its
module
I
in V*, I
isomorphic
of
classes
and the orbits is
is dense
= dim Y.
. -x, i : Fk^k
o rx
and define
with
and jüx = jqf
embedding
wj.th natural
' -Fzk ' k
c* (ror)=( j,li) in f,
€ u * a n d \ , r eg e t a g a i n a n
L (M , 0 ) the correspondj-nq orbit
ir
rf,k = rfr.
wrl-te
identify
an indecomposable prejective
and for
closure
s;l
of Gr. As in a) such an orbit
t/i under the action
open in
2.2.)l
,oal,t"..
(2.2)
O) of dirnension types I
L(M,
I
jt,
= (si e 1)jai
iüi
) vrith(j(9i)
1-'l correspondence
i
=joi ,ü1 : F*xk ._
s*2 V* for Fjxj
-
UI j,
i'+'
bY
i+ k
a jMk for
k'-...._'j
.
inf
q* is a surjective
Again
as above go = Zo
jtti)
the convention of the beginning of
with
of
FjYj I
by the rule
= (rtr)
s.(jai)
-
32
=-
Z, Io
:I
so we find
morphism of varieties,
1trzL, jqi) , Io =(Fixi,.Ü.)€ (pt)
o*
such that
= (;E)
L( M, Q), . Asain we
can
assume X^= X and Z^ = Z. Now define ß* =(gt): and Sfi. = i diagram
: F*xk -
Snxp
is cornmutative,
rrecauseo*
(]l)
z by Si = id(F.zi)
+
x
for
= (rVr).
"
Fk = F*zk. ali'
for
i+ k
Then the following
arrows lq '+'
i
in
f, again
-53-
t*"*
t***
I
I
t_ t**
t_
"'r"*'
l
|
Y
^I . z . I
E
Because k € f is homomorphism in exact
-;-
t\
rrxi
a source this fact
B* is
e ,n*
lmplies
injectlve
that
ß*
and we get
is
a
the desired
sequence
o-
Let X, y, Z€
2.3.2 Proposition: indeconposable, Then there
-Fk---€.
\-L
and assume dim Z = dim X + dim y.
exists
O-X+Z<
an exact
Y+Oor
Proof:
L ( M, fl) be prejective
sequence 9-y-?-
I-<1. Let y be
We may assume pos(I) <pos(X).
preinjective. r]
= Then Sl IX for suitable ^ r . . . S'r1- I ' l < O, iu € f , is a source in u <'r, where k €f
s1.... -r 9+X' Si..... -P tiu' * si.. si...
-u
= : 0 r . B e c a u s ep o s ( y ) < p o s ( X ) ,
" i-_10 t = s;
...s, rr
S . ,! * -1
9
ti., ! ...
dim
such rhat
Z = O. Then
S.
henQe iu+r =
(din Y ) , whi-ch is
'1
-1
but Sr ." S, ... 'U+ | Iil,+l,
s.i
s.-
. x. Let u € {1,...,r't
X >O and si
...
u
.. . s., (dim x) "ru impossibJ.e, because s.
y
^1 -
> O. Thus
Z ' = s-;r . . . s-]1 z + o . Consequently
(2.3.1)
yields
an exact
sesuence
-54-
O+4,-
sl- ... ^1
si,by -r
and,applying
(2.2.112
Z_ +1.
Comparison of Iast
q
exactness of s1 (i €r )
refr
-X
I
-
!'-Ek
the invoLved
dimension
the
shows that
thus we get the exact
homomorphism must be onto,
sequence
-L
9
If
preprojective,
Y is
-
o
-
we get
X +
I
L-
References:
Most of
$ 1 is
The Coxeter
functorshave
I.M,
valued for
and V.A.
celfand
all
graphs i.
algebraically 5 3 is
(f,
-.j
9.
been defined
Ponomarev in
[1]
vrithoriencation"l,
in
i), field
Ringel
done by C.M.
d)
closed
done by V.
simiJ.arly
where K.
the
I.N.
by
for
quivers
modulation
Rj-ngel in
t251.
Bernstein,
where d..
Furthermore
Dlab and C.M.
in
for [15].
(j-.e. = t
j.s given $ 2 see
= dli by an [11]
-
Chapter
fII
Graphs of
An abelian tion
category
series
A
A
and is
has only
objects, (il,o), if
for
then
of all
is
for
Artin
K',
K'
finite
to the
L(M'o)
denotes the category
type,
generated
exact
to
the
is
free x
assoy.
and if
A
modules over
an
so,
subcategorles
them .
l(M,n)
type,
embedding
one has to consider
also
of those which
L( M,0)
If
said to be of
if
in this
(f,d)
and only
(f,g)
again that
Our purpose in this q'peif
finite
and only
full
typs,
is
neither
tame (repre-
tvpe.
valued graph.
if
(representation)
modules over
finite
in-
K-realization
would be too special;
of
surn of
indecomposable
turo non commuting variables
Assume notr in the following
is of
direct
composi-
(representation)
exact
mod* Kcx,y>
equivalent
nor of wild
sentation)
unique
finite
a full
dirnensional
mod* Kr<x,y>
are representatj_on
is
definition
in addition to
has a finite
said to be of wild
example the category
isomorphic
of
said to be of
where
in
above, this
ring
object
isomorphisms)
there
finite
K'-algebra A
every
number of non isomorphi.c
is
-L(M,A),
over
tame tvpe
be again a valued graph with
sarne field
ciative (For
a finite
L(i,{,0)
mod* Kr<xry>
in which
is
(r,g)
Let
and of
an (up to
decomposable objects, if
finite
55 -
if
chapter (r,g)
is Euclj-dian.
cases more in detail.
is
is
a connected
to show that
L(M,n)
is Dynkin and of tame type
Furthermore we will
describe
-55-
s1
The representation
3.1.1
Theorem: Dynkin.
of Dvnkin graphs
L ( / l ,, ln )
Moreover
is
sable representations (f,g)
(f,d)
lndecomporoots
and the PosLtive
is not Dynkin, then, by
non-isomorphic
preprgective
non-isomorphic
preinjective
f (M,n)
therefore (f,g)
Let
L (M,0)
of
is
of
given by the dim function.
If
Proof:
between the
a bijection
is
there
(r,d)
if
and only
type lf
finite
of
qfldimX=x2o.
(M,0)
modules) in
c
the
is
set
of and
infinite' tyPe'
rePresentation
finite
x € L (M,0)
Let
the set of
(and equivalently
modules
cannot be of
be Dynkin,
Q-2.12)
be indecomposable'
Then
m-
haveorder
--,1
r . l l r f
hence I = o by c' under is invariant E crx € 0t r=O tt*1* ' o (1.2.1). Therefore there is an r > o with "t*' is projective' for some 1 < t < n = ltl crx ! 9t By (2.2.3)
Then
v :=
x=c-tBt
hence L{M,n)
is
is preprojective.
Again by Q.2.12)
L ( l ' ', lo )
preprojective,
nunber of non-isomorphj-c
a finite
module in
Thus every
preprojective.
has only
hence indecom-
posable modules. Now the second assertion
give
we will (f,d) of
will
now some applications
be Dynkin,
K
an infinite
by (1'2'5)'
follow
of
Q.3)
field
and
to Dynkin graphs. (M,o)
a
so let
K.realisation
(f,d) .
3.1.2 Proposition: in
L ( M ,o ) ,
Let
{t,-..,Ia
such that
and
Z
be indecomposable modules
-57-
J
dimZ= Then there
is
a sequence
o = Zo c 21 c tion
n
of
-..
3 x- T r ( t )
t !t-1
there
is
{k1,.
Proof:
Lt,
all
for
...
s kd_t S kd.
ld s 1d_t
, 1 < t < d.,
/2. / lkt
are indecomposable
d ='1,
assertion
the proposltion for
to € {t r...,dl
aLl natural ,
rrithout
dim Z - dim X1 = 1 indecomposable with Then, by
of root
is
system of Dynkin graphs says, as sum of roots, also
trivial.
numbers
hence
By above we find to = 1,
holds
d I dim Xt, t=2 Y, i.e. there
O = Yr c
r
of
t2,3,...,d,)
y € l(,!{,n)
a
is an exact sequence O - Il
dim Y = for
such that
dim Z = dim y + dim X1
O r Now
Y a c- - {. . .
hence, is
by assumption,
Y the
+ I + t + e -
Z a X] +O
propositl,on
a sequence
c
such that
Y,
= 7
lr/\-r
is
Assume we have proved the
Therefore there is
di-n y = I,
there
a root.
Less of generalety
is a root.
(2.3.21 there
and
= {O,1,...,d}.
.,kd,11,...,Id}
if
an
and a permuta-
1 < t < d;
all
= is root \"rritten " afrla I S to S d such that is Z-%
that
Z
such that
An elementary property
If
of submodules of
!
a sequence
o = kt . k2 . such that
=Za=
{ 1, 2 , . . . , d }
lr/_ moreover,
I dimX. t=1
:nd
!
a rermutaLrcn
x;(t)
2 I r <,l
or .
-58-
and
a sequence
o = Ez s [3 s ,.. = [a < Td < ia-r = ... s T, = 6 vl =Ir/y.,
that
such
2 < t
< d
are
If
indecomposable.
there
is
Kt an exact
o = n:
% azt
E...
tl,...,d]
-
O = kl
O -
sequence
.-zd=
3 < t s d.
If
then define l sts
there
is
O s t
r-'(rt), 13t < d, ?-o= o, Lr= = ?, and n(1) = '1, nl{2,...,d}
3 < t s d, lt
< 12 '
r
d - ' 1, 4 = 2 ,
and
k1=O,kt=[a,lt=]a
see,
that
by
by
d, la = Ta, S z - x.,, - 9,
= 9, Zt = v(Yt+1),
lo
for
definitions
O - I
n(d) = 1, n(t)
by
11 = d
= IZ =iZ=
sequence
an exact s d
define
then
9,
s kd < Id s dd-1 s ...
Zt,
this
by by
1, kt = [a,
kZ=
Z 1 Y -
z
{1,...rd}
S k2....
k1 = o,
-
11
2
=?(t+t),
d.
the assertions
satisfy
1st
Itiseasyto of the ProPo-
sition.
If
we apply
a root
j-n particular
the proposition
as sum of
3.1.3 Coroll-ary:
simple
roots,
to the rePresentation
of
lre get:
Every indecomposible module
Z €. L(M,a)
has
series
a composition
and
O=Z_cZ.c-..cZa=Z n--l--ru
a sequence O = kt . k2
...
< kd .
Id .
1d-t s ...
{kt,...,kd,11'...,ldJ
= {o,1,...,d}
for every
1 < t < u, Lrrl
such that,
posable module in
L(M,0)
of length
Ln. t.c
is
s 12 s 1.,= 6
an i.ndecom-
- 59 -
Applying
this
to
the
3.'1.4 Corollary:
Let
decomposable series
root
,ä"(Ut* module I
(t,d),
of
Z €. L(M,n)
(i.e.
module,
be the is
Z), in
\de get
largest
maximal).
L(M,A),
k2 =
=
.,kd,11,...,ld}
{k.,,. /
tt s t
,
z,
s
iO,1,...,d}
for
exist
of
< kd < 1d < ld_t
...
indecomposable
Then,
there
o=%c...-!a-r-%=Z_
O = kt
-2t t1/
maximal
Z.
andasequence
such that
s d,
are
indecomposable
,
for
a suitable
t1
* |
So we can tor
of
the
Remark: tion,
find
that
?r,,
every
/,
-K- r
indecomposabre
indecomposable
We will K
see has
to
an example with
finite
(3.1.2)-(3.1.4)
fails.
module
later be
modul-e in X € l(il,A),
[Appendix infinite,
K'
in
B], is
which
that
real (2.3.1)
= d,
all
modules
-K!
and
in_
a composition
= 12 .
...
every
in
t(M,n)
t,.
L(M,a) with
in
as a subfac-
highest
(3.1.2)
necessary,
dimension.
the
r.,e will
and therefore
as'sump_ give
arso
-60-
The non
S 2
homogeneous
(r,d)
paragraph let
In this
K-realization
(M,n).
the defect of
X
3.2.1
The dimension
function
representations
non-zero
defect
positive
and all
defect-
Moreover
jective
modules in
Let
X €
a(X)
< O.
order
definition
Let
ax < o
(f,d)
the
indecomPosable
of
non-zero pre-
N -
c Q'
be
Q'
= A'ln.
non
radical
the
zero
(2.2.4)
Then, by
I
of
defect, and
and the
defect
the
di.m(c+r\) Because
of
having
b e indecomposable
on
c
just
are
nodules
with
L(M,e).
L(l{,4)
of of
this
t(M,n)
of
roots
bet-
a bljection
induces
indecomposable
the
a(x) = a^ (dim X)'
we rrrite
X € L(M,a),
rveen all
say
graph rrith
be a connected Euclidian
(Fee 1.2).
Proposition:
Proof:
m
If
graphs
Euclidian
of
representations
= din x + ra (x) . n, an
is
there
to
t
o
c*tmx y o.
if
such
that
!^R
(dim X)
c' r
such that c * t 1 x- - K = B u projective
C
'x
,"; of
O,
I
hence there r
I O ";.
and
an
)
r.
O
rl
X = O,
C
k € rr,...,.r,
dimension
is
that rhus
is by (2.2.3) tlgr * = . is pre-
-1pk. a f)
similar, if preinjective clear
with
a(x) > o, x = c'rI r -^ _ 1 .
of
dimens:on
(1. 2. 8) .
.
(b € {1,...,n}, Now the
rest
of
some r, > o) the
proof
is
-
Now it
i-s crear
L(M,a)
that
arl
have defect
describe
3.2-2
such
indecomposable
The next
representations
proposition
says,
in
how we can
modules.
Proposition: are
other
zero.
-
ol
x € L (M,n).
Let
Then the
following
statements
equivalent.
(i)
X
is
of
defect
aI
= o
and for
aI
= O
and
(ii) (iii)
a direct
surn of
indecomposable
representations
every
subobject
X,
of
every
epimorphic
image
zero.
for
X
holds
ax'
s o
ex'>o Proof:
i)
Because
-
ii):
c
is
(with
hence
crease
r
j.i)
would
iii)
the
note
by
t,
preserves
it
embeddings
. n S airn{C+r\)
= din
dim(C+rmx,)
which
is
X
s dim X
would
in_
impossible.
-
SimiLar
i)
resp.
proposition R(M,a)
representations
-
iii)
x € L (M,a)
A representation in
ä
be positj_ve,
increasing
Remark),
o_n 0'l*)
aX' < O.
Thus i
of
= dim X'+räX,
aX' for
(2.2.2
exact
m = order
dim(C+mx')
Now, if
reft
above is the
.
full
i)
is
which said
to
trivial
satisfies
by additivety
the
be a regular
subcategory
of
t(M,a)
of
properties
described
representation. of
all
a
regular
De-
-62-
3.2.3
R(M,o)
Proposition: t (M,a)
Let
Proof:
of
closed under extensions.
O-X+Z+Y+
a! = ax+aY,
Then
zero defect,
of
thus,
beanexactsequencein
if
any two of the representations
are quotients
of subobjects
of
subobjects
X
of
Z
of
of
Y
of
by subobjects
quotients
L,
Z- are extensions
of
and subobiects
the
so ist
are subobjects
{
will
and the assertion
äz = aX+aY and (3.2.21. In particular
follow again by
are
any two of the
if
one. In fact,
in the above sequence are regular,
one; for, I
l(Mra).
O
the third
so is
representations third
subcategory of
exact abelian
a full
is
R(M,0)
i.s closed under extensions. X,Y € R(M,a)
Let nort the exact
and
a : X + Y
sequences and
O-kerc+X-imO-O, O-im
by
that
im q
a(im is
rn
im c
the
following
detail.
For
(3.2.2). of
Y,
non
it
(3.2.2.
we divide
presentations.
First
R(M,0),
in
the
called we will next
the
homogeneous treat
Tbis
the
paragraPh'
and non
Therethe
R (M'0) into
part
homogeneous one.
proof.
more two
homogeneous
non homogeneous the
im o
defect-
once more
Thus
s O.
o)
comPletes
category
R(M,a)
hence
!,
submodule of
Positive
i1-).
describe
Purpose so
has
of
a (in
hence
thus
to
the
y,
of
we show,
if
regular,
a quotient
is
every
we v'ant
subcategories'
are
Furthermore
by
regular
is
this
then,
im s
but
regular;
a submodule
q
and coker
and a submodule
= O
fore
q
ker
is
2 O,
q)
O-Y+COkerO*O.
above,
Then,
ä (im o)
be a morphism. Consider
reof
in
-
Notice
that
modules,
now simple
63 -
modules,
decomposition
series
decomposition etc.
as objects
seri-es
etc.
of
abelian
the
means simpre catesorv
R(M,o).
First
us give
l-et
is
called
in
lt's
Nf
of
conpositlon Bf .
=
X
l (M,A)
for
X €
acts
naturally '
=
(tr)
easy
to
see that
a coxeter the =
hrith
A regular
ii)
= x}
is
0",
and
= Nt,
the
to
of
simple the
radical
a1l, homogeneous
H(M,a).
of
the
all
dual
linear
forms
basis
{i*l(i
=
I
, ef
e rl
of
x =
(wx) (x)
rule
= x1w-11)
k€f,f,,=(Xr)eef*
= x.i
a one dimensional {x e efl
(cx) (x)
radical
of
E € R(l/,0)
r.
S ef*,
= x(x)
w € Wr, skx=E=
Al-soitis
where space
c € tl]f
generated for
all
(
O
for
sorn
X € R(lt{,O),
Ä€ef*J
ei.
is
said
to
possess
an equatJ-on
then
there
is
an embeddins
E9I iii)
if
nX
phism
( X *
O
for C-E.
sorne
X € R([{,a),
is
by
> O nX
e
Wl
for
weget k+i€
=,t.
-
(xr) € ef .
for xi"., ! f ' ' r. € ( d i m X) . The !,Ieyl group x
,*
factor
if
nE if
{-L g eFlcx
representation
.!. € Qr* i)
For
representation
every
belongs
61=-x1,6i=Xi+dikxk,
vector
{x e Qflc*
to
XX ,=
transformation,
defect
by
of
R (it{,a)
of
0f"
by the
eft
type
R (M,a) )
i.".
Or,
rr X€Q'-.
eQI'
space
we write an
and
(in
respect
of
A regurar
dimension
be denoted
with
basis
the
subcategory
vector
(Xi)
defi.nitions.
series
will
the
natural
x€0'
if
The full
Now consider
the
basic
homogeneous,
representations
wrlte
the
then
there
is
an epimor_
=
-64-
equation
be non homogeneous possessing
E € R(M,o)
Lenrma: Let
3.2.4
L>2
and
i)
c+rE :
o < r < r
c+rE,
and all
E
the
of
orbit Then
be 1'
c
transformation
under the Coxeter
dim E
in
the elements
the number of
Let
n.
an
non-
are mutualry
isomorphic,sirnpleregularnon-honogeneousrePresentatj.ons. nX = O
il)
for
and x7c+e.
x7E,
Extl (C+rE, x) = o
iii)
with
there
Because
only
I
- {,
Let
I
this
q
has to be simple
E g Nf,
din
= n (E) > o,
there
is
that
there
is
E + X,
which must be an j-somorphism, because
By (2.2.2) x I
E, I
nX
(O
implies
we can assume, that
7 C*E
and consider
obvious. by defi-
a monomorphism
nX ) O
simil-ar
is
thus,
nition,
regular;
implies,
the orbit
by (2.2.'t\,
Now i)
representation;
regular
thus
a monomorphisrn
E) = dim E
must be an lsomorphism.
be a simple
!'
elements) '
number of
a finite
of
of an equation for
hence
not homogeneous,
factors'
(as element
q
of
Now dim c+le = cr(S
therefore
iii)
factor
on composition
(CIearIy, because E € R(itl,a)'
n (c+In)
Because s - c+lg.
ii)
additive
so by definition
is
E'
by (1.2.1).
can contain i)
is
n
must be a monomorphj-sm E
regular. I > 2
and
) o,
nX
representations
simpre regular
all
for
must be an composition
R(M,a))
representations
si-mple regular
all
x7c*t*ln-
and
nE ) O
Because
there
= o
Extl (4,c+rs) x7c+rn
Proof:
for
x7c+r+1n-
xlc+rE, iv)
with
X,
representations
regular
sinple
all
I
is
XsC+E.
r = O.
Thus assume
an extension
simple
_ 55 _
-O.
O-I-3-E and
Z_ contains
Now
X7y,
E 3 Y lv)
hence
a subrepresentation
because
Z *E
nX = O,
By ii)
is
the
identity
isomorphic
I
XlE,hence
=nX+nE=nE
nZ
Xfly=O on
E,
to
)O E.
andso
i,e.
the
sequence
splits.
Similar.
Now given is
which
E,
an equation
orbit
of
of
possesses
C+rE.
dim E,
an equation 2 < l- (
If
-
is
!r
observe
the
cardinality
crn
that of
the
put
n Kercrl=KnO
By
A finite is
said i)
(ii)
set to
the
tE
iii) iv)
(t)
Kn r
I 1 s t
be a generating
orbits
of
and fi-nite, ii)
always
dim
i.e.
any two
dim n(t)
distinct
orbj-ts
each
E(t)
there
exists
of
following theorem
3.2.5
set
possesses a source
the
acti,on
regular,
in
for
of
c
are
nontrivial
t
t,
I
belong
ro
01.
an equatj,on i
( j ! t, n )
of
non-homogeneous.
dim E(t')
with
property
lemma provj-des
representations
if
is
and c
of
under
E(t)
each E(t) has the /1 rvr l v = Nr . ) 1< t < h K n ( t )
The
s hl
(t)
n
of
Nr.
n(t)
respect
to
it
such
that
= o.
that "lt)
now the
final
argument
in
the
(3.2.71 :
Lemma: Let
i
X € L(M,a)
be indecomposable
be a source
srith
respect
such that
to
..
Let
C-X + O
and
proof
-66'
= O.
Then
k € f
exists
thele
such
that
"i End X = Fo,
Proof:
Of
course
subcategory In
we can assume t (M,a)
of
= o
(X,x)
Extl
= n.
i all
of
Extl
and
x
X
that
such
rnFkr* full
b e the
Ln(M,a)
Let
modules
=
1x,c+x1
= O.
n
particular
: = sl-r ... til € Ln(M,a) is
C-X
and
of
an extension
a dj.rect
by
I
Z_ of
sum
copies
o f F -n O+Y+C+X-Z-O.
So we get
the
exact
1"1 Ext' (x,Y)
Hom(X,Z) -
in
which
= o,
Xi
the
+1 Ext'(X,C'X)
-
first
the
both,
because
sequence
and last
second
+ Ext'(X,Z)
vanishi
terms
injectivity
one by
the
first
of
Z-.
one, Thus
1+-1
Ext' (X,C'X) = Ext' (I,I) Now, there
is
a canonic
isomorphisrn
:
Ln(M,a) -
L (M',Q')
T
( M' ,0' )
where
the
is
(I',d'),
whereas r'
observe,
that
Now
hence also
I,
same is
true
(f',d')
of the
is
a disjoint
i.e.
one connected
resul-ts
of
is
union
(3.1)
TX
to
graph
Dynkin graphs.
of
(2.2-1 ),
and
component
the
induced valuation.
the
indecomposable
TY,
and
g'
and
are
I,
Tx
for
representatrons we can apply
= i\{n}
( M,0)
of
restriction
TY
of
combined with
are
thus in
( | ' , d' ) , (2.2.12).
the fact and In
-
particular
t+
-
with
L(M',Or),
= sl:,. . sf,
C
for some k € f' " ( 2 . 2 . 4 ' ) ( 2 . 2.5) we get By and
r(Y) =c'r(x).
E n d -XK = F ,
(2.2.2)
and the
1
= O
Ext'(x,x)
nxtl{F*,F*) = o
=
fact,
that
2k
a n d t h e Iemma is
3.2.6 Corollarv:
E € | (M,A)
Let
possessrng an equation € f.
i
cannot
Thus there
is
an
(3.2.4)
(3.2.5).
Theorem:
Let
1g(t)
[(M,n).
Then the
H (M,0)
and
h
o(t)
-
orbits equals
the
R
in ordered
(t) in
the
action
of
its
simple
socle
and
are a
C':
going each
and
its
of
R
is
(tl
X = C-E.
if
the
set
product
corresponding
< h.
with
whil-e of
composition
them is
of to
the
r_+.1 in
factors
correspondlng
fu11y
wltich
c
in
OI
The indecomposable
down sequence
length
some source
be a generating
1 < t
serial
for
and only
1e(t) ,c+E(t),...,c-'t"{t)r, j,n the orbit of elements
objects 0
if
number
dirn f(t)
(t)
^ tk
R(M,n)
subcaregories
containing
Thus
and Exrl (E,x) + o
( F u) , "k
s h]
category
fr.
non-homogeneous
= O ", such that
k € f
I 1 < t
for
be a root
Assume
X € R(,U,4)
module
and
Proof:
3.2.7
a simole
by
proved.
E n d( E ) = F k , E x t l 1 n , c + r , c + e 1 = for
(Fk) E,r'. ^K
( F k € L ( M ,, n ' ) ) ,
be regular
n.
and
r*(Fk)ru ,
nxtl (x,c+x) = Extl (x,Y) =
and
(Tx,rx)
Extl
rxtl (t(x),c'+T(x)) =
= Fk,
End t(x)
Finally
the coxeter functor on
''Ix
Itr
T(x) =
we have tf
hence
-
o/
both
determinded
from co by
can be arbitrarv.
68-
,rrdlf* Remark: An abelian sition
serj,es,
is
called
serial,
has an unique composition categories
Proof: Let Then by
if
series.
every indecomposable object of such
A characterization
t19l).
X € R(M,A)
be slmple and assume, that
ii).
1
forall
"rn(t)(dirnx)=o
(:.2.4
Hence
.,.a.nKn
dim X €
sJ.rnpJ-eregular
ti.on is
O(t)
contained
Let now of all
i.n
be the fuII
R(t)
regular
1 s 1
1 s t s h
is
that either
and uniserial
every
= Nr,
R(lr{,0)
of
regular
x € R(r',t ,n)
Let
composition factors be simple.
(t)
0
in
factors
composition
R(t)
in
O
from
some (t)
to the action
of
be indecomposable non homogeneous rrith (t) E,...,c+18, (n e 0 and let ), I € R(M,n) n! t4,11 = dimx Hom(X,Y) - dimKExtl (x,Y)
Non calculate
lo4r
=
I
(2.1.4).
B;(C'-E,Y).
' r=O and only
if
zero if
I
= E €
!
E(t),
() (t)
Nos,
.
k € r,
all
terms
in
the
sum are
(3.2.5).
Fn-algebra,
sition
Floreover
if
by (3.2.6). Hence Ext'(x,Y) = o in this (t) Y € 0 . Let Fk be the endomorphismring of
Then the endornorphismring of an
Hon(X,Y) = Hom(E,Y) + O
g O(tl
case. Thus let
factor
I
is
also
Fk,
and
End(X)
is
because the endomorphj.smring of every compoof
X
.
module of compositlon
in a going down sequence corresponding
ordered
is
consisting
compositionfactors
homogeneous or contained with
x
i'e'
1 < t < h.
subcategory with
o
nonhomogeneous representa-
some
representations
Assurne by induction Iength
for
C U lstsh0(t)
I
andaII a ' -+' l
homogeneous. So every
C'.
has a compo-
1s due to T. Nakayama (in the case of a module cate-
(see e.g.
gory).
in which every fobject
category,
is
Fk.
By definition
[Fn : XJ = fn
_ 69 _ and by (3.2.6)
nftc+ts,v) - ft = -aftc*t-le,Il
y 3 c*"s
for
(1 s r
Y!8,
aft4,It otherwlse
= af te,gt - fr = dinK Hom(E,!) = dj.m* Hom (x,y) aftx,Yl
= o = d\
Hon(x,y)
hence, in both
cases, Extl (x,y) = o 2.) case: y3g+l+1". Then, if
Y3E=
fk - dinK Extl(x,y)
= dhx Hom(x,y)- di\
=
nxtl{x,I;
a ! t x , v l = s l t e , c r + 1 g l* " ! { c l e , c l * 1 g ) = f * - f = o * If
y 7 g,
then, because uorn(x,y) = Hom(E,y) = o,
-dim* extl (x,y) = sf t4,gl = slrcru,cr+1e = -fk. ) Thus, in both cases, extl(x,y)
=
.
f*(Ff)f*
Thj.s shows, that there is just one extension slnple regular module, and U € R(t).
q
of
I
Thus R(i,{,n) is the
direct product R(1), ...rR(h)xH(M,o),i.e.
there are no nonsplit
extensions betvreen indecomposable modules of different By Nakayama's theorem R(t) there are modules in structure.
0.
must be uniserial of arbitrary
factors.
and by above
length of the descrlbed
This proves the theorem.
Let no\"r (l,d) tation
R(t)
by a
b e an Euclidean
In the p r o o f
of
valued
(1.2.8)
graph with
adnissible
we showed, that
orien-
the Coxerer
-70-
c
transformation
the Coxeter
to one of (Appendix there is
in fact
S r,
"*, Let
in the tables. S = S;
,-,|
...
S;
(2.2.1)
With
..,
is
morphism bethreen
R (M, a)
0 = 0r,
of regular tion
M
(f,d).
of
tractlon, graphs.
is
in
outline
(M' , Q' )
A reallzation a contraction
and
T
and
induce an iso-
S
(f,g)
graph
for
general,
o = o'
with 1r(t) 11st
set
s hJ
K-modula-
an arbitrary
if
{vertices
for
valued
arbitrary
(I,d).
of a valued graph
of a valued graph
(M,01,
of
"1Q, described
purpose we need the concept of con-
(M,n) be a realization
So let
.
L(M,n')
a generatlng
L(M,o)
in
For this
which we will
"*r_' the orientation
R (i,1,o' ) . Thus \de can assume
there
representations
.
in
the corresponding functors.
each Euclidian
that
shovrs that
of simple re-
€ f
ki
Wf
tables
in the
= L(M,fl) sl *1
L(M,o)
and
for
under
look to the proof
easy to see, that
and we have to prove orientation
-
conjugated
described
is
Sl ... *a
: L(M,0')
ist
= Q'
s*r0
T =
is
"*r,...,"*., ki_ is a sink
such that
and
$
A closer
a sequence
Wt
in
to
transformations (f,d).
for
C)
flections 1 < i
corresponding
of
(l' ,d' ) rr}
c
is
said to be
{vertices
of
I}
and i)
If
krl
€ l',
and there
- in = 1
k = io - i1 -... n
where in
ii)
If
is a sequence of arrows
i1r...,Lq_,'
(q > 1)
g t',
iii) iv)
(r,q)
with respect to
then there is an arrow
k + I
(f,,q,). k..+
.1
in
(f',d')
with respect to
an unique sequence of arrows in
in
L*,
0',
= (k = io -
then there is il
*
...
-
in = 1)
(r,d).
Lkl n Lk,lt Fk = Ft< for
= 0
for
every
{k,IJ fl {k'rL'} k € l' ,
and
= Q,
(1,kr1'rk'
€ l')
-
v)
=
kMi
...
"k M-i 1. "
(f' ,d')
in
with
L*t = (k -
Now, for
i1 -
each
for
" i- q - 1- M-1
-
tt
every oriented
orientation
where
- 1).
...'in_'
k € f,
e, ,
define
+* := {i € Ili=
-...
io-i1
-in=k
with all
r*
:= {i€
flk=
-...
io-i1
-tn=
Let
X = (Xr,rOr)
be an arbitrary
a contraction
R(x) = u = (uk,t
t
with
for
ipg
r'
for
O
representation
( M , A ).
of
of
(Ä.{,a) and
Define the representatron
where
k),
Uk = Xk
for
all
k € r'
I
lvk
defined
t UX skMI - Ul
for
k -
1
'e; ....'ei '2
- q - 1- " ' i
L*t = (k = io-
^p+1 -p
-
i1-...
(pi rp+19i =i tp 'p+1 'p o I s,.. t"
-
On the
all
(wj.th respect
Q')
to
is
by
r ü r = i ,^eqi
of
f,
k€+k0tk.
(M',O')
and
ipF
o
all Thus
k + 1
edge
other
U = R(X)
Xi - p +.1-
hand, with
ri
if
-p+1
where
' 1 '.1, o rl o ',
ip - tn*., + ...
+ in = l)
and
6.1 : x. 6i M, 8...8. t p " i M^ p t q _ l M,,q_ , i *p+1 -p+1 ^p+2
Mi -p+2
V € l(M',a')
X € L(M,A),
E ...
a. .q_1
such
Mr rq
that
we can define
for
V
is
a]t
O
a subobject
canoni_callv
rwo
-72-
subobjects
of
T (V)
T' (V) .
and
X:
given
first,
=
v
(v*,ftX)
€ I (M',Q')
introduce
the
= io'i.l
-
following
notation. ff
i
€ f
belongs
a path
is
satj-sfying
Vi r. '"k
as
the
mapping
the
ip
inverse
LX =
and g lr
image
for
(i
Vk oi
of
- l
...
-i q - 1
where
-i P
-, p, + 1 6 '- p
(i =iMi Mi -p -p+1 ^p _ l
Mi e tq- _ 1
- l
..
-P-1
: Xi -p
-
i
(0
', o
-
! X, 'o
X. 'q
-
...
q,
. . . oi t . l- Mti o
e
= k)
in
define
...
under
e. M: '1'o
as in
(2.2)
€. M, 'p 'p-1
e
X, Mi ei ^p+1 'p+1 ^p
and
'p+1 )
(pi (! 'l e ^i p + 1 ^ p
=
-i p + 1- 9 -i p
(9
O < p (
aLl
q
- l
;- q I
{k
to
...
: X, -p
e1
-
X, tp*l
...
o,,Mi -o '
+
ei r p + 1l-{-i r p e- ri n -M- ri n - 1 e . . . i . , M i o , (Osp
put
y..+ = fl v. r.K r, tk "k
possible
paths
Similar,
if
i
is a path with the,image -i q 9 i- q - 1
"'
of
S Xi,
Lk
where the
described
€ f
uT oto"t.,o
run through
tk,
and
O ( p.
for
al1
"'
orr_r"rn
l,k = (k = io-i.,+...+in q,
define
Ua"O
under the mapping
(p. -i 1 ' o
(., e' O ( -p *p-1 ,
p < er
Uri
defined
= t-V._t iL" Lk
all-
above.
belongs to
ip g f'
indices
!
as
above).
xt
where
And again,
the
indices
put
run
as
= i)
-
through
possible
all
Now, we def ine v
for
all
k € fr
exists, by
=
t(!)
= Xi.
where
€ +k.
i
Vi
g r')
(i
u.,u*
such that
Vi
Lk.
(Vr,rtOr) ,
v. = rkrk |
€ rt,
i
paths
-
t5
is
determined
and the
indices
As particular,
As indicated
by the
if
by
run
through
no such
notation,
is
iqi
k
induced
I.
Similary
we define
=
T'(V)
by
tVi ,.'orl
and
=
Vi
Vit
I
for
g f' ,
i
€ f '
ua = u,
for
indices
run
through
= O.
Again
L J L
where
the
k
exists,
i
a1l
K
k
such is
.9.
JL
It
that
is
i
€ +k.
lnduced
easy
to
bv
no such
Ui
X.
verify
that
of
I.
of
U = R(X) €t(M,0),
X
If
Furthermore,
both
if
and a quotient
y
is
then
r" (vJ:=
T(y)
and
f(y)
are
an indecomposable
V
subobjects
direct
summand
determines a subobject
-x/ , rt l ] v i ' l ,
where
w
is
T'(V)
a complement
of of
Yinq. fn
the
graphs (with given (1)
-
other
a genrating respect
to
certain
a generating
(v)
of
the
prove,
and iii)
It
is
prove
to
n(t)
from the
s hl
in
to
of
order verify
enaough to by direct
an equation
definition
type
of
Euclidian
r^rith equations
rn
we have
set,
easy
that
every
orientations).
deflnition. are
for
1 I < t
1n(t)
is
conditions
C) we give
set
set
have to ii)
(Appendix
tables
to
sho'
the
prove
(iii),
n(t),
an equation,
a
condj-tions
calculations.
for
!(t) that
all So rrre
i.u.
(n(t)
1B(t,1 >g
can be seen directly).
So let for
X € R(M,e).
each Euclidian
(M',4')
of
(M,n1
Now, our graph
proof
and for
defined
will
each
by the
consist ,,
(t)
non zero
,
of
considering,
a contraction components of
n
(t)
,
- 74 -
and in decornposing
R(X)
into
indecornposable representations
of
( M ', a ' ) . /+I n'-'X
that
Note,
i.e.
R(x) ,
(t)x
n of
restriction
are
the
positive that
composition similar, direct the
notation,
contraction F * F),
-
2*-l*
or
llorv if
n(1)
nt5)
contaj.ns rf
n
(1)*
N o \ , ra s i n
for of
a Dynkingraoh,
must
% is
thus
(3.1), that
occur
in
to
the
and these
show,
isomorphic
isomorphic
t
n(t)x the
nonhomogeneous
E(t).
to
c+E(t)
for
some
for
graph
1 -
R(X)
into
the
types
set
p < n).
if
A2 t
representations.
a generating
is
Ep+1)
g(1),
direct of
consider
(wj.th
2
the
the
realizatj-on
sum of direct
type the
there
(o,j),
indecomposable summands are
('l,o).
of
of
I,
T' (yo) )
must be a direct (2.2.1)
n(1)'
we see,
!
is
summand
additve
( 1 , . 1)
and
T'(y-ol
= g(1).
type
Evidently
(namely
must be a direct
because
surnnands v
there proof
o,
isomorphic
to
summand Vl that
and
n(1)u
E of
a o
Thus
( 1)
o
de-
tables.
the
an equation
= n(1)x,
a submodule
the
to
defined
Dynkin
type
a o,
natural
(1,'l).
dimension
those
is
The dimension
{O,1),
the
of
R(X).
is
and decompose
components
denotes
we will
s x
on1y,
to the
= o
T' (yo)
E(2)
(1,o)
n(1)'v
summand
no regular
is
the
dimension
di.agram.
T" (!t)
of
of
their
=
representations,
of
by
the
and
< o,
are
n
11) t)\ = {E'" LZ, E'-'
:
n(1)
of
we refer
There
by
(t)'
a realization
particular
V1
if
,
determined
n(t)x
course,
First,
for
is
R(x),
summand
determined
(M' , e' ) .
to
roots
of
Ar, (n > 2)
%
(t)
one
if
Ä . , . ,, Ä . , r :
(of
= n
(t)'R(x)
summands are
implies,
For
uniquely
(M'rQ')
Furthermore direct
n
is
x
.
type
(1,O).
-75-
+ im19n+1 = x1
imtQ2 module
Ft
would
(x =
be a direct
be regular
(3.2.2
sunmand of
type
(1,O),
preimage
of
fore
the
From this
it
i).
{E = IZ}
ConsiCer
the
dlmension (o' l),
types
(1'1)
must occur
would by
d.
(2,1).
type
hence
(2,'l) .
type
be surjective,
xt
of
set the
with
82.
summands of n x > o,
rf
n x
or
(2,1) .
cannot
be of
would
negative
I
R(I)
2.
of
%
The
(o,1)
type
has a direct must
1q2
(1,O).
X
*.
(.1,O),
are
isomorphic
and
E(2).
,(1,Z'l
As above,
type
Xp+l.
n = 2*-.1
R(X)
< o,
be not
defect
for
a summand
If
be
g+S(1).
!
equatj_on
diagramm
there_
cannot
an equation
(1,o)
T' (v1 )
be a module
is
n(2)
not
has a direct
tqp+1
T"(yj)
3 n.
Vl
If
under
that
direct
T,(yo)
of
sur]ective,
the
or
sununand v1
cannot
shorrs that
of
and
ipZ f
to
would
R(x)
easily,
contraction
X
hand,
a generating
is
and
I,
projective
the
other
thus i*tqz
othen"rj,se
summand of
on the
follows
The same argument Err
(xi,iaj).
So
Vl
to
C+E,
be
is
wour.d be not
of it
regular
(3.2.2).
and
Ecnt
similar
-
/ tl 8D,.,: {E*" = l,
to case
8..
EQl = Frr";
..Fn-2(l
l r" a s'enerarins "n
set
$tith
equations
The proof For
for
E(2)
= 2*-1*
n(l)
E(1)
is
conslder
the
similar
and to
contraction
=
I(2) gn.
case to
2n*-1*.
11,2)
1<
n.
rf
()l
n'-'X
> O,
The type tive type
a summand (O,1)
defect, (1,1)
would
thus, by
% lead
because
(3.2.2').
of
type
(O,1)
to
a submodule
x
i.s regular,
or of y-
( . 1, t ) X
occurs.
of
posl_
must
be of
- 76 -
Therefore
=t.,
T'(Yo)
o
*o,..+Fp.,.
f.,_Z(
p+2,
ft
^n O +
the modul,e would
o *
...
be a submodule
woul-dn't
of
be regular
_
Fp...".-r(;
by
T,(Vo)
of n hence
,
(3.2.2).
oosirive
of
defecr
and
I,
X
p = 2 and
Therefore
t2l
r'(v^) = E' If
(
n I
O,
( 1 , o ).
of type
T"(Vl)
cDn:
is
to
= -2
n'-' Di--!
F2 ...
r,
p + n-1,
If and
X
is
a direct
then
not
Vl
summand
'o * o ... odo for
"p
the
defect
regular.
of p = n-'l
Hence
BDn
C^ <e
set
*
+n
^i .-t
with
/1\
= -l
nt"'
,
^^-^'der
'i-. r
P4
äö-F: F"FO*.F Inn
a generatj.ng *
have
-
3g+u(2).
f,in t , I' , !n ( 1 ) = 1 r .3 , !F ( 2 ) =
t)\
must
so r" (vl)
negative
r'(v1)
simil_ar
is
R(X)
1 < p < n-1.
some
and
then
tLhr reE
6-0 7 rn_2_ld
...
equations *
F:2* "^^:; id = E ,L "(3)= o,, 3
n(1)
-
. . . . tnr_ 2
O-O /
-1*-2*+3*
*
+n
cu vor nr Ltrraa9cL tr ivol l n
tLoU
tLhr reE udrioaygt dr ranm
the
dimension
orf u
tL-y'lhJ ca
^a3 -
'\
1
/ 2lz In
the
decomposition
direct nF
t.,ri+i-^\.
e! wrrLrrrgl;
rf and
n(l)x
> o,
T,(V^) !
summand vt
1
(using O
^
R(X),
of
summands are
.
O O, ö t,
O
the ^
natural
1
of type
rt I
n ( 1 ) : << o , o
or
!
o
^
1,
i O, j
there mustbe a direct r(l).
JO
I
types
suggestive
1
or
s u m m a n d .V o
1
i
of
the
kind
1
of type
!
r
there must be a direct or
]
r.
But the fi"rst
two
'
cases lead t o a is
of
quotient
lr
type
of
of negative
I
and, as above,
T" (V1)
defect.
Hence
Vl
must be isomorphic
to
c+E(1). For
E
(2)
For the
and
E(3)
renaining
the proof
diagrams
choose the orientatlon j6i
easy (contraction
lre use also
0
in
(x = (xi,j i)) "jMi we wouLd get a subobject
othenrise
the
of
I
o + F
E(1)-o+F2-it*F6-o
o + o + *F6*FU v
+ ',4
r is
(3)
=O+O-F.*F-*F_ tbt
a generating
set with
eguations
o ( 1' '1 nr
=
-2.1
1
* +2
+4 +6
* l
=O
1-2
o l)\
n'-'
/1)
n'-'
- - 1 * + 2* + 7*
A |
-l
,l
*
= -1 +4
=O
o-1
to type
that aII
r.re can
mappings
are monomorphisms: for,
easy to see.
gtt'=O-F2-F1
fact,
such a way, that
- Xj
t xi
j.t is
is
O
of positive
defect,
Ar).
-78-
Da
to the diagram of type
the contraction
consider
First,
9
+ 1
2+ rf
rlr lt'llto,Yo
or
1
hasdimensiontype The first
1
i
positive
+6
defect.
1 o
o
o o
o,1
o'o
o o
1
4 of types determj.ne subobjects of 1 r1l 'l 1 1 ' E" and T'(yo) is of tyPe
three
Thus
%
/1\
< O, then there must be a summand Yr of type n("x ö1oe1 Again'the 1 2 1 o,o 1 1 or 1 1 o,1 1 o,o
If o
four
first vr
cases lead
is of type
)
of
defect'
of negative
I
r" (v1) !
and
1
(all
6+9(1),
would lead to quotients
T" (yl )
for
bilities
1
to quotients
of
other possiof negative
I
defect) . The proof case
ör,
t1\
E\'/
for
and
E(2)
(contraction
= O * Or
A3
to type
F.+
F"
the same Lines as the
follows
E(3)
lo
Az).
resp-
E.
*
o*
F6
*
F7+ o,
o,
t-
E(2) - o + o + o
+
F1 r(
( 1' 4 , q- '
/?f
E(',' = o * F: -F2
is
a generating /1\
n"'= /a\
t\o' /?\
r tt ' '
For - v \
E(1)
=
-2.1
= -1
*
*
*
*
+2 +5 +6 :i
+5 +7
= -2.2
*
*
1 = C
*
1-2
o-1 *
the
O
1
0
0
I
I
U
1
*
+3 +5 +6+8
consider
F7 * FB
equations
with
set
1 ' -or,"' l )
:;(1'1)-2 F i * F;
=O',l
contraction
1 V
-z
of type
D4,
Thus
1
i 2*1*
-19-
for
the contraction
E(zl
of type
5 +
A3,
t+t
and argue For
E(3)
as
in
case
consider
the
E6 . contraction
of
rype
D5,
5 + 3+1+6+8
1
o,
n(3)* t
If
o o o
1, o
1 1
O,
1
of
all
1
mination
phic
,"
-
1
1
1
types
1
or
with
= E(3),
T'(vo)
clude
'l
has dirnension Type % 'tol o o o, o o 1 't,
the
2
rf
1.
a o,
n(3),
thedimensiontypes
O
11 1 o
O
Vl
of
R(x)
tient would
and of
T" (Vl ) : determine
1
2
1
O O
dimension c+E
(3)
a quotient
O
O,
1
1
1,
one,
are
we con-
monomor-
again
a1r but
1
O,O
O
eli-
the
1
1
last O,
canbeelimi,nated.Adirectsummand
type all
,
1
1
last
eEl
'l
0,
by routine
the
then
ooo
oneof
1t
Again,
and
zdl
1
o
1
of
o
o,oo
O
o
exception
because
txi'jei)).
2
o
1
other of
X
;
1
o
determines
possibilities of
negative
the
quo-
T" (v1 )
for defect.
F
r11
E.''=o-)
o
---)o
-
o -J
17 Fz €
Fl -
FB-
r)
'1
Ei2) - o ------'o --J
Fa €
F: *
rr!D+
t' t (1,1) u1 F3€/l-
'o
_2
E(3) = o -----,Fs ----, F4113,"3_-wittr
to= (1'1'O)+(O'1,1)
I' üe
r! €_1)r rf o(o,t,t) ,t (1,1,o\
-80-
with
equations I1l
n\"
n n is
*
(2)
-4.
(3)
E(1)
|
**)t +9
tl
oooo
-z
|
1 u -z
oo10
+9
+ö
z
*+ - 3 . ' l + 3 + 5 + 2 . 7* + 8 +9
a generating
For
1
:t
*
= -2.'l +2 +7 +8
= O
0
1
0-3
1
set.
and
E(2)
to diagrams of
leads
the contraction
type
D4, D5 For
resp., and we argue as in case 87. r1) to the diagram of consider the contraction !'"',
EG,
type
7 .t
5---)3J1(-8(-9 If
r 1l n'''X
< O,
the
R(X).
of
would be positive. zi,
L € {5,3,8,9}
woufd be positive main the
also
1,
2
1
direct
of
positive.
is
,1 ) O,
Then
,7 = 1.
So
the dimension
11 2 1
inde-
If z7 = O' Assume zj = 1. o 1 1 1 1 and the defect of
in these cases.
2
Let
otherwise
1,
1
two of
Then at least
must be one and the defect of
1 v:ltz --€
Hence
cases for
followlng
1
type
must be of dimension
T'(yo)
value
n(3)
would have negative defect.
T'(Vo)
types
dimenslon
be the dimension type of an direct
=9 t1 "5 "3 "g composable summand %
Vo
possible
which the
for
R(x), of z-t
"r,,**-rra.
18
are
there
2., > 2 type
2
2
2
T'(Vo)
and there
re-
of 1
and
to
submodules
2 1.
tz5z
The
first
three
defect.
So
cases
vroul-d lead
a
of
I
and
of r'(v^)
positive :
E(3).
rf
has dimensJ.on type
Vo
n(3)x a o,
indecompcsable summands vl
value
Again,
by simple
2
3
2
1
there are 10 possj-ble dimension
types of ilt..a negative.
1
elimination,
of
R(X) havins
we conclude that
n(3)
- 81 -
I1
must have dinension
F4l,
First Fl
notlce via
Let
that
E2
Et_ -F 1 ' ? 2 )
is
.r
,rr.,) = 1.
such rhat
",
an isomorphisrn of
{r")=o-o-r3,-Fr*Fs,l = L q r t l o - F 3 -F 2- F l - r , set nith
First
- 2 . 1 +* 2 +*5
(21
t
%
of
I -
*
R(X)
E(1)
to
t
rf
n(1)x a o,
and
T"(vl)
Fo!
e(z)
:
'2 "
vector
F1" '1
M F1 F2
spaces.
Then
ft
1 -2
1
= o
1
o
t.
2
1
,r(1,2)
then there is (2,1 ,1) .
So
83.
a di.rect summand dlm(T' (%)
1.
Of course the restrictions
1 -
5
=
of T,(%)
remain indecomposable, hence are
Hence T,(Vo) :
there is c+E(1)
and
to the diagram of type
o,
n(1)x,
isomorphic by (3.1.1). rf
=
a generating
O
o f d i m e n sj . o n t y p e O
2Ml
o , rf, - F, E z I
F1
=O
the contraction
5.
dlm E(1) = O and
*
-2.1 +3 +2.5
2l(1'2)
So
of
equations
(1)
consider
T" (Vt ) 3 g+n (3)
can be considered as subfield
-
tr, " "" 2
(=
and
2M.t, because Ut*1 , . E;
I
type
a summand Vt
E(1). of dimension type
as above.
we argue similar.
Jutt'=o-F2*Fr-"n*rsJ [eQl-o-F2-Fr9ri-")
with
eguations
(2,2,1)
-82-
n(1) -
-2.1*+2.2*+5*=o
2-2
o
1
and
=o
1-2
1
o
isagenerating
n(2)--2.1*+2+4' set,
)-)
(, : F;6nM., - F1
srhere
(3 t.,
The proof
with
type
rr = -2 1* + 2t = O
equation
Fn.,.
E = (Etrrer)
is a generating set,
rt}
tMn
Fn-rnodules.
an isomorphisrn of
goes now as in the case of
{E = o - Fj'
dz,t,
is
F.,-module)
as
(p ! F; + F1€
is such that
1 -2,
the map
while
+ F1 is defined as dual maP to an isomorphism ,e'rz EiOrM1 (:o F1, ). . E 3 z- F 1 o ltz zil ltz! '1 '2 Consider (1,3),
t
If
R(x)
T'(v-;
If
nX
% 3 g.
(3,2) and of course
G2.
and
there is a summand V.
of
3 c+e.
T"(yl)
Sinilar.
l{e have proved now that K-modulation set
(3,1)
of dimension tyge ( O,
type
then there nust be a direct
> o,
nx
of
type
GzZt
1.
summand ru
to the Dynkin graph of
the contraction
in
M
tion
Direct
every Euclidian o
and orientation
there
Thus we can formulate
!([,1,n).
3.2.8 Theorem:
for
(r,il)
Let
the product of
H(M,0)
R(t) , d.""tibed
in
calculation
orientation and
ß.2.7) .
shows also:
h
exists
theorem.
graph with n.
uniserial
with
a generating
the following
be an Euclidian
rtt and admissible
(l,g)
graph
Then
K-modula-
R(M,o)
subcategories
is
- 83 -
3.2.9
Coro1lar: h
Let
n
the nunber of
be the number of vertices elements
representations.Then all .
slmple
glven
regular
by the
L "
a generating
in
OShS3
(f,d)
of
set
and
of regular
andthenumber
non homogeneous representations
I
of is
formula
L = n+h_2 The number
h
is
the graph
of If
0a
is
Ärrtn > l)
an orbit
representatlon
vrhere
Let
1-
independent
of
of
a simple
x € l(M,n).
sion type, if
the
length
or
regular of
of
in
the case
2. nonhomogeneous
C.,
then
0+.
T h e n I € l(M,a)
dim X € N.,
except
h = 1
when
under the action
denotes
O
otherwise
is
of continuous of discrete
dimen-
di.mension
type. 3.2.10 Corollar:
The mapping
between all
indecomposable
mension type and all Proof: Iar Ler
dirn : L(M,n1 - qf
By (3.2.1) representations {s(t) llsr
dirn of
representations
positive
induces L(M,a)
c L(M,0)
induces a bijection
roots
a bijection and all
of
of discrete
di-
(f,d). between all
non regu-
roots of non-zero defect.
be a generating
set of regular
-84-
No!,, it
representations. rooot
of defect
%
E ."*(t) rlss
< h
contained
in the orbit
rn fact, module just type.
type if R
(t)
x(t)
- aim e(t)
for
the number of elernents
o.rd"r the action
the notion
€ R
(t)
,
for
once as composition
of c. From (1.2.7)
of nodules
and of homogeneous representations
E(t) €R(M,n)
some
foll-ows now easily.
in general
that
as
can be ldritten
< !r
ä
r1+r2<1t,
of *(t)
ttre Corollar
Note,
dimension
where
and 11 'r2 €II with
and (3.2.8)
Remark:
,
zero with
every
I that
can be seen lsee
is
of continous
doesn't
an element of a generating
which every factor,
is
of
element of continuous
o
(t)
coincide.
set,
then the
appears
dimension
-
85-
S 3
The homoqeneous representatlons
Let
(r,1)
and let
be again an Euclidian H(M,n)
be the full
honogeneous representations
3.3.1.
Proposltion:
graph with
subcategory of of
H(M,a) is
of all
Proof: Ler in
simple
Let
Et,
Qo
(E1Ezl
Now Hon(81,H) dlnl of
H(i,l,n)
that
(M,n)
of all
subcategory of
Furthermore
subcategory
fi(M,o) =
indexed by the sät " I r US ",
homogeneous representations.
EZ € H(rtt,n) be simple,
= Bf"
(kl
Ir,
dirn (Hr) = ki
(non-symnetric)
!z !1)
lr
,rrrj:;:';:rm
- di*x
Hom(El ,EZ)
dirn* Extl (Et,EZ) .
I O if
and only
Ef
if
are mutually
jrcongruous
(2.1) and the proposition
It
is
easy to see
K
is
infini_te.
that
defined
= o
g
{2,
Horn(H,,Ez) - dim* extl (g1,H2) . Therefore
sence of
Remark:
L(M,n)
an exact abelian
an uniserial
Qr r Qr * g be the "rn (2.1). Then, by (2.1.4) Br"
K-realizatlon
(Jt{rO).
L(ü,0) closed under extensions. irhere UH is
qraphs
öf Euclidtan
and then the simple
components in
objects
L(M,0) in
the
follov/s from (2.1.7t.
we don't
need here the assumption,
-
3.3.2
a) Let x € l(lt{,n)
Corollary:
morphism ring R
an
is
F-bimodule over
b)
is
L(M,a)
a) rf
some
k € f.
If
is
I
by its
b) Suppose there
is
a full
a)
and regrrlar,
"/.ltnl
= F = Kr,
di-mensional over above
embedding
T
Next we will Thus let central over
[(M,n)
and
G, as which
K
(R) and
x ring.
T(R)
of
R
y.
and
Consider
is
indecomporing.
By
have to be one
J(R)/,
= J(R). But by J- (R) cannot exist such an
of tame type.
rings
and 1et
of
a local
there
the notation
be division K
is
Loewy factors
is
uniquely
Kr . Consider
cannot be a division
in particular
introduce
F,G
action
R
= 2, therefore
and
subfield F
and all
K',
(J(R))
di\,
R
fron
length'
R = End*, (xry)
R = End (T(R)), hence
because
easily
folLows
and by its
some f ield
then
hence
for
embedding
wi-th trivial
= K',
T(R) e L(M,o). Then sable
exact
L(tt{,C) for
soc R = J(R) = K' 6 K', *r",*,
socle
regular
sinple
* ! tk
and
rnodule is
because every regular
/$2,yz,xyryx),
Furthermore
the statement
regular,
T : rnod*K' < x,y > <4 R = K'(xry)
".
is prejective
x
then
t
type.
of tame representation
(3.2.'1) and (3.3.1), determined
*r",",
F. In particular
R are one
of
Loewy factors
such that
F
ring
a division
is
and all
x d R(M,o)
endo-
be lndecomposablewith
R. Then there
dimensional
Proof:
85-
of
finite
representations dimenslonal
fMG
be a bimodule,
acts
centrally.
Let
= dim"(r,r")
and
of
a bimodule.
over a cornmon finite
dirnensional
(dn"rd.n.
(I,d)
'a
= 1 .
"rra-.noo".
the
''t
.2
modulation
with M
d., , of
(1,a1
5y
setting
dr''
= din,("M)
F1 =
,82 "
= G,
'
-
=
rM2
rMc
and
=
Zut
87-
I{o*F(FIi{,FF). Choose the orientation
f,MC-
o
(d12'd21) (f,d)
of i.e.
1 .
by
. . 2. Then define
a representation
spaces
Vl
over
F
,p : V1 O,1,1"-Vr. (v1,v2,6;
to
v2 I
and Let
, where
-
6 : vl
(v1rv2ra)
V1
and
? ^12
a
is
v2
erith
cNF
defined
over
cNF
=
as in
tations
are homogeneous. We will
L*(FMc). Notice
for
we will
an arbitrary
S
orientation
is
type,
of wild
following
bimodules. give
So we will
partially
3.3.3
Lemma: Let lation
is
will
of
(r,d)
of
neither
i"
of triples
.r, F-linear
Ln (FMc)
is
with
isomorphic ( V 1, V 2 d ) ,
is
Ä.,.'
of type
regular
or
H(FMG)
First
resp.
we will
modulati-on
show that
in
the next
orientation
H,r-(FMc).
try in
M
to H(M,0)
and
L(M,ny
situati_on
The
of
to the case of
paragraphs
and will
above.
components done in
be an arbitrary
of
represen-
Dynkin nor Euclidian.
the problems
incongruous
map
(V1,V2,a)*
case arl
the more general
components and let
u.H^r1o^*,1t"n&l \
consisting
reduce these questions
M and admissible
rncongruous
this
,(f,d)
treat bimodules
solutions
Remember the notation
in
e , second we witl
categories,
map
homogeneous representations
lemma, which hrorks in
Grothendleck
of two vector
hornogeneous representations
denote them by
graph
(f,d)
if
(f ,d)
tvro guestions.
sinple
Euclidi.an
adnissible
that
treat
of
q
given by
resp.
to be. L(M,n),
G-linear
FMcn. Note that
(2.2) . So, if
resp.
the set
and a
isomorphisrn is
[(F!'lc)
classify
G
are above and
we can speak about regular
rn the forrowi-ng
consists
rMG
Lrt(FMG) be the category
l(FI,tG), where this
where
v2
of
l(FMc)
(2.j).
valued graph with
modu_
e. Let X,y e L(M,0) be
End X = F, End y = G. Let
GNf
-
be a submodule of =
FMc
GNro
following i)
L(M,o)
with
Then there
with
bimodule
dual
a full
is
ernbedding
T(o,GG,o) = y,
= x,
T(Fr,o,o)
exact
and with
properties:
Every
ii)
Extl (x,y)
= lIorF(NF,FF).
T : L*(rM") -
88-
If
image under
GNF
of
all
= Extl (X,y)
modules
Every
T
has an
{X,y}-filtration.
U € L({x.y})
monomorphisrn
T
then the irnage of
X <+ U
consists
the following
with
and every
property:
epimorphisrn
U ->> Y
splits
Proof:
By definition
where I
VF,WG are vector
: VF -
Because
spaces over
of
triples
F
resp.
(Vr, W",e), G, and
g is an F-Iinear mapi (notice that ON,, GNäri cNF). (FF,o,o) is injective L*(FMc), the module in Wn O
(ker q,O,O) is (ker q,O,O)
a direct
is
O = alh
with
L,!(FMc) consists
nothing *ur
T(vF,wc,a) = 3
I
= t
Let di\
,
a r(
s u m m a n do f
(V',W",O).
than a direct
,r"*ands, '/kera,wc,
Of course
sum of copies of
(FF,O,O)
hence ).
so let
e
be iniective.
and assume the extensions
"U O-
Y..*2.
-r
fornr an F-basis o l
y.-y_ -a
-
-r
of
X. +O,
Y , = Y , -rX , = X a n d 1 S i S
-I
NF. Let andlet
-r
g. z=(
be the kernel O zr)Ä1. lsisl-'/Y
of
I
the canonical
nap
89
Because
p
is
lnjective,
ur 4wc
trae have
o cNr = I o*"
an
injective
F-linear
(l = dimc(vc)), i.e.
rnap
we have
a commutative diagram with exact columns:
I
I
I .l
t vr.$
w^ o ^N-
il
I
tl ll o (c^ a ^N-)
.'
3"r+
"T ul g !
I
J
+ 3tr-
o I
I
I
J
o
with
L = J. di\(NF)
A = (VF,Wc,o)
is
- di\,(vF)
the kernel
O (NF,cc,id) * J'-Lr such a map is (f.i..ir) rJ r
given
(1
tttir, But this
by its
13j<J,.1
= J.
r _ di\(vF),
i.e.
of a map
O ( F F , O , O ).
first
component,
which
is
of
' o J o r F 5 .-
o" F".
can be also be considered as a map (ttir)
, oJ @r X ._ol
x,
since
F = End x.
the
form
-90-
Consider
following
the
conunutative
and exact
diagram:
oo
tt ll
,t
O _______>
U -___> ,
O 1
y _______--_____) y* ________--___) O
o 1
!.t
(E 1
-Xr .
tt
JT
o --_____+
o zr _ 'l
________>
o
an epimorphism
L
ll
tl t3t z .......>
Ir
.t
i,
oo
By the usual
arguments there
exists
ttith
Y, embedded in
Z.
kernel <--*
I
by the
usual
---a=it=,
connecting
I,
homomorphism
Z. So we have an epimorphism I\ F _i-il, \
@ -z
-->>sL/vle
J
Define !,4'
T(VF,WG,q)
e
resP.
be defined
(fii,
: 0-
L)
)
be the
[t'(Fltc) Lt , )
a homomorphism. (h1I,
to
t
Ff 9 L.L
Jr
(A'= (vi,wi,o')):
.
J
as kernels O
t,
(o,ß) Ff
Ns, a
induces such
_ I 'I- ä e I -
1
kernel
Lr
Then -
Nn -
o
.
J
that
of
this of
epimorphism. (fiif) -J-
and let
Let
: O N" ._..' J (c,ß) : A -
an F-linear the
L
following
0 Fr. ' L A, be
mapping diagram
conmutes
_ 91 _
-
vr tl" +(r,'l
___* rn.order
vf *
of
the module
notice,
operation dte 1
S ""
that
on
"1,nrr,,
ll.iltJ
?
Z-r J a
O --------+
which
1si
-z' .
o __________)
f,",
T ( A r ) w e n e e d t h e following
Z:
the operation
g,
------+
,,,
to define T(cr,ß) : T(a) -
propertj,es Flrst
*, 54
? "1,,,
leaves robe
g € G
of
on
GNf
6
g, invarianr: Define i in the followj,ng push out diagram,
e Ii '|
so
way, as left i'e'
il
I
OY'
o xi+o 1< i < r
a g?t = , 1< i s r I si
acts on
$
Z, hence on
nultiplication
the folroning
plication
by
g
2j, r
because
Z/t -. soc z_ by
g
acts
N is G-module.
in
fact
,=?=ft' on
NF
in the same
as F_endomorphism,
diagram conmutes, where we denote the left on
Z lle
.tr
-----------+ o
I
lq
{,
and note that
an
U =
0Y*
o -_+
induces
z. ---
NF
by
9 o 1 € End"(Gn I
, Z / u 3 s -xrt f.icr I o t ls
g/l = r, .,=?=.
cNF):
rnulti-
-92-
So we get as J'
a connutative
x J-matrix
O
lrr",or
',
!
T(4') --->
lr
(c,3)
for
map
u , 3
is
T(A')
is
Z J'
easy to see that
ß and
(h11,).
s o c T ( A ) = e -y J
.L (hrl,) L'
of course
X ----+
o
T(c,ß)
I O
t(4)/_^^ ' s o c -r,(^Ar , , = ( E -X S
and
a homomorphism then
T
r
is
exact,
T ( O , G G , O )= I ,
For the proof
of
(orcc,o)
ii)
property,then L(ix,Y])). in
i)
a is and
note that
projecti-ve.
the property in ii). If
so
to the whole of
construction
steps
L !j-:Ly,e,
O o
A = (V",W",ro), where
tations
(in
(f'...-.',
s
induces a c-linear
by resrricrion to soc T(A), rhis induces 3,", and we can go backwards, i.e. T is ful-L.
(the extensj-on of
and
gX__-_-_____)o
J'.I
induced by
-
!
ß : @ _Z J rt
considered
J-L=di,nVF, T(A) -{
c:
is
L
lunt
o Z ->
I O. Obviousl-y
withS=I If
is
(f..,) Xr -r4
O
ü
JtT(a,B)
Wä
J ',lsisr *
"l
I
where
g : Wc -
over G):
----------> gZ------->
O-->T(A)
o ------)
(where
diagram
is
an exact
Lr,(rM"),
i.e.
furl
also
not monomorphic, is
ernbedding;
to represen_
trivial).
By
im T c l(tx,y]). (FF,O,O)
Therefore
u e [({X,y})
T
every
is
injective
erement of
in irn T
is indecomposable satisfying
In(FttO), must have this
a n d V 'ts^o^ c- ,ur i O X forsome J,L€N JiThis means that g c a n b e e m b e d d e di n o z. Now arrsocUIOy
can be reversed
and we get a preimage of
U."
-93-
Renark:
Of course
submodules
modulation f{(l{,a) glven
image of
T
can be deterroined
cNr
be an Euclidian
i{ and admissible
graph not of type
orientation
we can assume of course that in
radical
the tables. of
also
for
proper
or
i'
wlth
of Extl (x,y) .
(f,d)
Let now
the
Let
nf
Q. rn order is
ö
to investigate
one of the orientatlons
be the generatj_ng element of
rrith r resDect respect
Of
i.,.,
to
.Qa. Let r-a+
5
N-,
the
i F L^ the !L^ source -^a fF b. io
E. o
8
(t,d)
if
6
is
of
-7 E^
ö
type
4
-41 F.
'42 'l
G" n
3
G2z
and
,
n.t 1 Notice
that
restricted Ii
= tt,i
otherwise
to
f'.
is
otherwise
short
to
root
the maximal
First,
non negative
for
in
the
of
Now the Lermnafollows
is
by
rirhere di = o
,r^
investigatiän
a root
cases
of
=d
and
shows,
(f',d),
in
fact
Fery
Bn, CDn, Fn1 and GI r
root. I,I
€ Of'
components. This
For the notation
case by case.
f,
(1,,d,)
defined
rhen a direct
restricted
the maximal
a Dynkin graph
= (yi) €or
Let I
(4f = (.t,i)).
3.3.4 Lenrna: I
Proof:
= f
f\{io}
long
say gives
and short
easily
x 2 1, a partial roots
inspecting
if
x _ I
ordering
see for
has on
ef'
example [ 4 | .
the Euclidian
graphs
-
(M',o')
Define the K-realizatlon let
yr = (Yir
y
to
restriction
of
defined by
Yi = Yi
{i,i}cr'g
f
(l',d')
of
!r r where
tyPe
of dimension
Y = (Yrrrar)
(3.1 -1) . Let
l',
and
by restriction
be the up to isomorphism uniquely
e L(M',Q')
i9'r)
rePresentation
deternined
94-
is
L'
the
€ t(M,a)
= O, j(9i = j9r. tf "ro is an inand .t0t= o otherwise. Then of course ! i € f'
if
of
(M,O).
we will
appty
(3.3.3)
= X
injective,
decomposable representation In the
following
Notice
that
F.
-i-
and
I
is
with
because
L(M,n).
F,
, Ye
i
€lisasource
_I
o (2.1.3) .
3.3.5 Lemma: i) ii)
Hom(X,Y)= O = Hom(Y,I). =F
EndX=F. 10P
iii)
Ext'(x,Y)
= ^N-
and
aredi-visionrings-
EndY=G
except if
A..,
is a bimodule of type
( r , g ) l = or" .l n. dö rr.H .t" cNr ," "r .r n" Proof:
i)
factor
of
morphic ii)
Because
Of
!.
End Y 3 End v',
= Ei -o
In particular
image of course
= O, I Yi ^o
it
be a submodule or
an ePi-
Y.
End X = F,^ th"
t""oit
= F
a division
is
for
follows
g Fi for G ancl (2 .2.4) . In fact 'o r | jo a 0' must have the sarne length
iii)
as composition
c a n n o t occur
cannot
{ .,-
!
as
=
; iö*.j
d.,
J'o
y' € of
y;. r
Because
from (3.1.1) '
some j o e f ' ,
By i) and (2.1.4)
d i n ^, , E x r 1- ( x- , y ) = - n Il t x- , v- l
ring.
'.
(2.2.12)
where the root
-9s-
Inspectlng (f ,d)
every
is
= tt^
of
case it
type
iCrr, h"r"
I'
is
of
e Q'
of
gives
this
of
) = 1, therefore EndY=EndYr
Let
This
is
fir.,
T:
type
= ,ro, c'
and But
some O < r € N, therefore
is
the maxirnal
is
the unlque
w €
wn, implies
i.e.
dim,ON) = 1, and
d"=ir"a.
""
tells
us that
there
of course
T
is a furl
is described
(3.3.3
in
we can speak about
exact
is of the same type
rMc
ii).
Because all
modules of
if
A e g*(füC).
and only
if
Then
T(A)
is
A
is
of
continuous
of continuous
continuous
L = dln
ker
(f ,d) of
be not of
continuous
type
4
is
V, - dim ker or) 6örr. fh.r,
dimension
nf = x + I
that
Therefore
pF + (din
type
because
of continuous
if
of
is
of
and only
if
dimension
T
type.
in (3.3.3)
= dirn V".
rüC
(f ,d)
dimension
dimension
Let A = (V,W, q) . Then by the construction dtun ( T A ) = d t u n w c . d i r X rrith ! + L.din
Notice
1
j € fr
l,=w(i),
Proof:
is
I,
(f,d)
type.
type
A
length
except j_f
o
are Eucridian
3.3.6 ternma: Let
Let
if
=
dim(cN)
a rong root.
for
L*(FMG) -!(M,o).
graphs
di.mension
except
the knowredge ot tt"
tro
=F1 . Now f,t=4.fr,
GNF. AIso the funageof
involved
of
hence
11r,4,),
(3.3.3) cNFo. Then
enbedding as
is
Y' = C-rrF,
type
=
#c
as above).
11',g')
Dynkln graph.
simple long root
CNf
NF = 4. Now
now ln every case
6örr. H"."
Is of
= 2
dllr(NF)
,Jo
type
root
that
dln
(jo e f '
uth(Nr),/f*
of
follows
is type
type
dim V, = dim !tO.
not of if
and
4,
type
ftrr.
and onLy if
-
96-
ditn(TA) = dln
W - ( d l n _f + d f u o X ) = d l n W ^ . _nl-- , u
i.e.
lf
contlnuous
(fral)
f4
u.
Is of
iCrr.
fh.r,
type,
if
ls
flC
and only
of
dlmenslon
type
i.,,,
Let
type.
and
of
ls
A
d1n VF = 2 dim WG. But thls
if
and only type
be of
continuous
= dlm WC(+E Y + 2 dtn x) = dim wc.lr,
din(rA)
lf
ls
dimenslon to
equivalent
because here
9r = 2 x + YNotice
that
A€ I-*(E$G)
r(A) ls
€ t(M,o)
lndecomposable,
composable, 1f and only
lf
lndecomposable,
ls
because
resp.
A
End(A) 3 Sna(f(a))
lf
and only
are lnde-
T(A) is
lf
a local
ring.
3 . . 3 . 7L e m m a : T ( f l * ( E J , ! G ) 1c R ( M , n ) .
Proof: Recall in
the
R(M,a)
functor o(t)
there
- up to
+ 1
of
the
in orbits
(3.2.7).
A, direct
(see 2.1.7) extensions.
(1 < t s h)
0(t)
inspection
(o s r(t)
isomorphisms dlrnension
(in
sion ring
non homogeneous representations
regular
is a unigue representatlon
type
R(M,o)),
as composition factor '
slmple
dlvided
n.lt) ) e p(t) r, l
continuous lt
notion
Ct
= (' A l Jt), the
(3.3.6).
Obvious by
H is
and
uniquely with
B(t)
- regular
Then
nxt(e(t) rg(t) ) = i.e. !rHH,
a fu1l
exact
o(t)
subcategory of
closed
be
of
length
occurs just
L11e(t) i) [(M,0)
B(t)
rp.dule
ena(g(t) )
4
orbit
-
= A(t)
and cornposition
4(t)
ß.2.7).
in every
A{ + o. Let ao
determined
socle
E(t)
hrlth
every element of
i.e. of
shows that a+r(t)
< r*) c
under the coxeter
once
is a dlvi= 3(t) under
+
-97-
3.3.8
Theoren: T induces an equivalence. between (1) (h) A *. . .* e x f l ( M , 0 ) = : C ( r r , t , e. )
Proof :
We have to shobr T(H,t(F!Ic))= C(M,a). By (3.3.7), (3.3.6)
and (3'3'3
ii)
it
is
enough to show thatanindecornposabre
ä € R(M,a)
of continuous
if
and only
if
ls
J.somorphic to a dj.rect
dlrnZ ="=
contains
sum of
sum of .
let
copies
"! E fr
sabLe direct
direct
=o
q.
of
itri) ) , hence
hence Z, contains
some simple
I t s t < h),
so every
direct
with
as above,
E
Furthermore every
because jo
restricted
= a"(z) j e r
Z_ is of to
image of regular io
u.
defect W is
and
is
all
Let
zero.
i€r.
submodules of thj-s j-s true
Then
q
is
has negati.ve defect.
-
,o.
öc(l{) *j^
*
w,
c(M,n).
rn particular,
can be seen.
ac(Z/u) - - z. of
regurar,
non homogeneous module
z cannot be contained in q
for
be a indecompo-
E
non homogeneous. But then
regular
Z, but this
such that
19",9'),
ur=i,
forall
In particular
W1 * O, as easily
neishbour
an epimorphic
i.e.
summand of
ö"(u)
by
isomorphictoa
regular,
summands of
nto = O,1w = (W1,
e1a(t)
is
!-
(3.2.2).
defect
s'nmand of
,
. ttoiice that di.m U = J.I o n, = (nr)eqr, because dim z eN.nf.
Z e C(M,n). Because
indecomposabre
bour
z = (zt,iq:1
* = Ei
of
where
Z_ have non positive
ZrU
such that
".a € L(M,n)
,/u"L"
and
C(M,0),
"]
=o,iti
usz
g
of
U = (Ui,iüj)
andU,
isasource,
2, wltnJ=_:,
for
?
-otr^
direct
g
copies
modure
contaj_ned in
g =
a submodule
fQrio+jer
Because io
First
g-
dimension type is
(zil , anddefine
1ti=iei
all
flnhUC)
,nur, is
öc(L). ;r.;, -o
;",
< O. So there
is
O. Note that
!'
of
-o
*j
hence
= o w
is
by (3.2.2),
impossible
always a root
Ler
at
least
neigh_
= dim W
the Dynkin diagrarn
-
98 -
Nou we have to dlstlnguish
11',9').
cases:
several
/
BDrrr Drrr E5' E.7, Eg, F42 and G22.
a) Type
Here y'
dim u = z, - o - - oI
hence
are at most
zi -o
sumnands in
=,,
tro
rmPlies
- Tnis
that
of
g.
into
By maximality
of
I'
all
gher:e
a direct these equals
restrlcted
to
I'
Furthermore
the
first
dim U
Y, because
= 1r
ö"(io)
a decornposltion
modules.
to
must be isomorphic
Also
ac(U) = - z.
and
indecomposabele
sum of
Rr,.
the maximal root of
is
z. . vr. to ör, ana 6örr.
fr,
b) Type Again
is
I'
the maxlmal root
component of every
root
(w' = (wi) € Rf ,),
because
there
just
are
be isomorphic
Here
at most
is
to
and again
U' which
must
Y' € Rf,.
of
by maximality
!
y,
of
summands i.n a decomposition
,j
*.i = t
1, hence
din U - 21
+ O. llow
ri
-
vn-1 3 1
1, and
= 1, because only
ti-r
for
n-1
dim U = 2.,
= 1, hence
JO
JO
roots of
(f',d'),
1. All
first
component
d) Type Again
' I
U. But
*l'=
2. So lt'
all is
of
a decomposition
gSI
root
the maximal short
is
I'
jo = t
in
Rf,
g'n.
c) Type
t.i
in
Rr,.
in
< I'
(f',d').
of
v = (vr)
roots joined
t
are just
= 1, hence
,l_
Therefore
Rr,'
by an edge with
and there tl
Furthermore
")- O = ,1,
1o' Now summands therefore
Jo
which are greater than g'
and therefore
= L',
I'r
have
i.€.
asdesired. io.r. I'
is
the maximal short
.1 = 1, therefore
dim U = zl'
root
of
(f',d').
L. As above
*i
Furthermore = 1, hence there
are
I
-99-
just is
z, only
dlrect one root
has defect e) Type
surulands in greater
zero.
a decomposition
than
U. In
namely the naximal
I, W g y.
As above
of
R, r there root,
which
F4t. that
-Notice
every
root in Rf, greäter than has defect <_2. L, N o w :d: i m U = l and ac(U) = -rL , so there are at most 2 z.t,\ _ 1 0 tto = t"t direct sunmands in a decomposition i of u. Furthermore 23 = 21 but u2 . 2 ior all roots v = (vi) . Rf,. This implies *ä = z' Therefore the nurnber of indecomposable summands occuring in a decomposltion of 1 just g is zio = Z 21 and the defect of every such summand is - 1. Again we conclude W g y.
f) rype drr. (a,b) -
write
ac(w) < o
* bit. Then !' "iZ a n d \ , r 2+ o . B u t J . I '
withOSk.l
,k2et
shows so far
I{ = y
forces
or
s z'
k,=k,=O
Z'e
c f i , l, a ) I
because
t(fin(Fttc) ).
B(1) c c(M,o)
and E s z
for
with
lt
Er = O ^o
(E = (E.. r. iej)). g=?y,rhen
Z'.lf
(3.2.7,
u s z
r,et
so let
2y.l=yZ.This
z rF C(M,o). But
din z = dim 2,.
ugg,
of
Y,, the
i.e. theorem.
in
of course
sirapre non homogeneous modure as above, then
U' < z'
byabovehence R(M,o), so
y G T(fl,r(F,Ftc) )
E < u
because
be the corresponding
J
soc Z, = A(1) g E
of copies of the proof
some regurar
< t < h).' Define
E e ta(tl
of
because
= k1 (2,1) + kz(1,1) + k3(3,2)
llt
A''',
(3,2)
as desired.
we have shown
then there is
= (1,1),(2,1)
u
E<2,.
submodule
Burby
cannot be a direct
uy (:.3.3
sum
ii) . This finishes
-100-
We have reduced
nohr our
case of Euclidian
graphs of
paragraph
investigate
Bimodules
S 4
let
it
of
din
FM
il" = 1
tatj-ons.
Recall
which acts
that
F
centrally
on
dim I G : K] = g < -. geometry,
K
finite
fields
resp.
n = (1,1) root
c
contain
of
rMG.
using
(If
FMG,
rM = 4,
rn general
K,
subfield
: K] = f ( - and
counting
similar
frorn algebraic can be
results Let
arguments.
N
be the
forrn
Q(x) = (x., -2xr)', n = (2,'l).
resp.
dir
a conmon central
but
quadratic
A11, i.e.
or
homogeneous represen-
simple
dirn [F
to be infinite,
the corresponding
an imaginary
AtZ
functors.)
coxeter
all
pl"lc, with
radical
generated by
bimodule"
= 1, dim MO = 4.
rM
the partial
and
for
Q ( x ) = ( x . , '- x r ) -
dim
to classify
found also
)))
Euclidian
Because we wi.1l use here arguments
we suppose
of
in the next
t"
{r.
be a birnodule of type
one of hard
for
fl(M,a)) to the
tvpe
= 2 = ilim MC or
seems to be very
resp.
t (FMc)
fMC
we apply
i., .,
type
Euclidian
paragraph let
In this
din
we w-ill
(to desribe
problem
first
a positive
X=
(x.,,xr) €lR-,
CaIl an element frorn N.n
element
of
Ri
a !{ql.gg
of
M
F..G'
3.4.1
Proposition:
Let
Then
din
X
there
is
just
and for
every
isomorphic type is
is
I.
X -
(xl ,xr,to) € L(f"[G)
a imaginary
or Weyl root.
one indecomposable imagj.nary
representations
y
root i.n
be indecomposable. For every Weyl root
X € L(E.MG) with there
are
infinite
x
dim X = xr many non
H (FMG) = R (FMc) , whose dimension
-101
Proof:
We have only
(Notice if
that
dim X
I
X = n
with
I
Uq
that
G
G
G
has dimension
infinitelVlorbits
in
modules
dim X = n- Let
direct
r
with
summand of
the
smallest
dln
x = n
slmple
inag:.nary root is
on
than
As remarked earlier,
it
of
dln
G:Choose It
is
Let define
dim
,.x O+xo€Fxc
Now xo -
n e M\X. nappings
Urr, so every orbit
= 1 = din
F
Of course from
is
but
there
,, are
j.s _ up to
there
Because
n
is
x srith
a well
defines xo,m
treat
f.XC X"r
n
is
gJ,!", which
be a proper
deflned
by
of
subbirnodule
by
F
Irith
xo.9=go.*o.
isomorphj.sm of skew
an isomorphism
F
case,
forces
and we can identify o:c.*F
51 aII
noe, a speciar
is a basis of
Finto
infinite.
hard to describe
bimodule
anddefine o
of
non isomorphic
type
seems to be very
1
6re
dim G - dim Ur, =e(n) = O.
homogeneous module
= 2 = dlm MG. Let f"t{
easy to see that
fields.
Urr, where the orbits
so the number of non isomorphic
case of a non simple
F"Mc. Then
with
K, together
such modures.
simple honogeneous modures- so we wilr
course
is
be not hornogeneous. Then every
number of
srmpre regular.
Ä
dirn un. Therefore
{
every
it
the non isomorph!-c modules
honogeneous modules of dimension
nannely the
over
on
must be a WeyI root,
a finite
and only
by (3.3.1)
U,.,, hence infinit{many
I
isomorphi.sm - only
Ug
(2.3.2)
trivlally
smarler
if
of modules
wlth
n . N o e ra s i n acts
type
homogeneous modures of dimensioa
acting
are in bijection
r*1c+61
by (3.2.10).
Furthernore
a variety
Aroup
of dlmension type
under
dimension
to the class
corresponds
algebraic
under
statement
many simpre
(2.3)
there
of course
^^1
infinite
a llnear
of
of continuous
is an imaginary root.)
g. Recall
äir
to prove the last ls
enough to find type
-
FxF-
rFr.
and we may "Mr
-
102
mf=fo*o*ft.*
Obviously,
and
6
both
e
G1
are
*o
f)o
forf€F.
additive,
*
(f1
and
the
m = m(f1
f2)e
equality
=
fr)
=
(mf.,)f,
-_ r' .' 16 f 2 + r ) r ) l * o + ( f i r l l . m shows that vation.
e is
Fxo * Fem
AIso
M. Thus
e is
right
is
F. Conversely,
(e,1)-derivation given
F-structure
of
F. Let
F O O fixes
and
3.4.2
Lemma: The non simple
Euclidian
bimodules of the form
M(e,ö),
6 annihilates
of
Iet
hence equal
to
e be an auto-
aM(erö)
: =
uF
oI|F
a,b, f € F.
K.)
e
so we have shown:
bimodules
are just
e € Aut F, ö an
tile
(e,1)-derivation
F.
Remark:
The representation
choice
-x-- o €
of
o ' G -F. e is
f.
above depends of as M(e,6) fMC ^€ +}.ö ^hoice of the isomorphism
s
fixes
an automorphisrn and
T',
with
ring fi
Lhe
of
Y ^i ' -ö' F"G'
Of course
skew polynomial .i-
\,
an (e,1)-deri-
= 2- AIso e i s a n a u t o r n o r p h i s m d i . r nM ( e , ö ) " = d i m FM(e,ö) is an F. F submodule, so I"1(e,6) is not simple. (Of course
Since
i - ^
is
by
(a,b) . f = (af + bf ö, bf e) for
If
6
F-subspace of
a right
an automorphism of
morphism and 6 an with
F and that
an endomorphism of
K. 6 an
R = F[T;e,61 a F, n €X{,
(e,1)-derivation
of
F, the
has as elements the formal
and the multiplication
is
sums
induced
-103-
by ruultlplication
ln
F
and the
Tf=fer+f6 Let
mod R
denote
finite
dimensional
3.4.3.
Theorem:
rule
for
the
FCE
category
over
of
all
right
R-modules
$rhich are
F.
H(r.M(e,6)r)
j-s an uniserial
is
category
equivalent with
to
objects
nod R x U
of
arbitrary
where
U
length
with
one sirnple object.
Proof:
= (1,O),
Letel
=FOFr
(O,1) €l'i(e,6)
=",|t,
N=Fel
"Z=
-(M/N)F, (trt= M(e,6)), the canocical projection. E-t!, s = (Fp, of "/", n ) is a simple hornogeneous representation
n : Fr, O Then
r
because
,,!t,,
subcategory
of
sition
factors
direct
factor
(3.3.1)
is
surjectlve
and
H(FMF)
of all
isomorphic
to
of
S. Then
show mod R =
theorem. If
(Xr,Y"rc)
A=
{a€Xle(a3er)
s=
{b€Xl3a€x:
F-subspaces (aoe.,
of
Xr:
This
V = (\,Yr,
of
9, )
is
i.e.
U
be the
is
uniserial,
all
of
E!1,,
compo-
and a
So using the notation T,
full
of
in order to prove the
let
and
e(aeel is
+b6e2)=o}. obvlous
for
Note that
A and B are
A. With a g el + b I
e,
also
1u, +bf(t with
b
no\., a simple
+bf ""., also bf
oe2
belonqs to
belongs B.
homogeneous representati_on
= (aF, a(aF O ,,\),c,) q to aF, satisfies a^ V' > O, where
O + a e A, then !' of
=O}
U
[ UH =, H€ S H+S
a representation
+boer)r{"-le)=(a
to the kernel If
is
Let
homogeneous modules with
by (:.3.1).
H(FMF)
we will
dfun S = n.
with a^
and
denotes the defect
- 1 0 4-
with y
respect
to
the
Coxeter
ä. Vr = O
is regular,
slmple.
Obviously
morphic
to
Vr
by surjectivity
and
Xf,
=
XF. If
q(bOel),
g -
c defines A*r
€ L(F\')
where
o(a O er)
= aT
and that
ö
finite
that
all
T
r\,
-bOe.,
defined
into
is
for
is
!Z
onto
D:
F, define
Because of
T
R
V-X*r an e
o e1) = a
tp ls
such that
given
= (\,\,o)
6ta*l
easy to see that
Yr
a hornomorphism,
is given by,p(a
\
and
indeed F-linear Dö :
lmod
R,
some cases,
so
(see Appendix A).
But it
becornes
it
is
to give
classiflcation
C,
hopeless
polynonials
fields
(setting
very
This
usefull
{ t , 1)
0
there
in
a general would lead
in one variable
are simple
also
of
to a classification over arbitrary
F = K, a commutative
homoqeneous representations *02
and
provided
€ kere.
e = 6 = 1 in the theoren above). In particular, sinple
Xp
mod R. Conversely
over
-
of
module operation
r Yt*
from mod R into
K = 1R or
irreducible
comnutative
lso-
= dim Y,
\,
aT = b
p(aO 11 = 99. So
the sj-mple homogeneous modules: of
not
mod n a T.
example if
now clear
diln
an isonorphism
aOe2
The theorem above is
1.)
ls
n X O e1 = O, hence
kero
c = (c,B)
a € A. It
functor
is
a well
of
o
\
for
" Therefore
is
dimenslonal
e,
ir
y
S. So, if
where we set
because
a functor
R-module
Remarks:
is
T , and
!,t,YZ.
c isR-linear,
öo 1 1r.
that
action
then
for
p(? 6 e1)
then
A = A(V) = Or this on
Vr because V is
B = Xr because
becomes an R-module,
ro(aOer)
Because
I .
of
y € T,
if
to
A = O, i.e. thus
fMf
as usual.
hence V'=
lsomorphic
g. we conclude
ker g + X Q e1 = X O
Thus,
(3.2.2),
is
c
transformation
for
have dimension
fj-eld,
and
CC(1,1)C type ('1,1),
honogeneous representations
all whereas of
-105-
dimension 2.1 lf
(n,n)
tytrre FcGcE
are skew fields
dim Itc = illn -andif
CH
there are
then a sfunilar
= dirn
K
the
element of
H.
Appendix
g€H\G
theorem holds factor
flelcl
B we w1ll
treat
ring
of
of tarne representatlon
step ure w111 reduce this
Lernna:
Let
fonn and
(I,d)
(M,A)
on which ,J.1", (dirn,"!t) (dirn t* (E!{c) -
F, which
graphs
K
this
are of
rn the
the free F, where
over
corußute with
every
2., and 22.)
Tn
type.
finite
following
form are of wild
and Eulclidian ne vrilr
type.
show that
In a first
problem to the case of bimodules,
be a valued
graph with
be a K-realization
dimensional
has to be
type
type.
quadratic
z.1,22
K commutes with
of wild
graphs
indeflnite
of
R
FK("1,22),
an ex.rmple of
we have shorrn that. Dynkin
finite
H (FHH) . Eere
(In partlcular
so far
3.5.'t
o2 a F, ß2 e G,
with
for
of elements
Graphs and bimodules
graphs with
= dim cF = 2,
ln two non comnuting varlables
denotes
S 5
with
rG
c€G\Fr
replaced by a certain K-algebra
O
for each
skewfields acts
F
centrally,
Z 5, such that \) [ ( M 1 a ).
(f,d).
of and
G
quadratic
indefinlte
Then there exist
over
K, a blmodule
and which satisfies there
is
a fu1l
exact
embedding
-
Proof:
Iisted
In the
there.
(M,0) to
(1,{)
is
t(tr,{,0),
so *"
i.
(i.{,0) itself
second case we have an obvious
<--+
ltfi,äl
connected. By (1.1.2)
is
graph as submodule or a valued
an Eucli-dian
embedding
(fr,ä)
where
FMG
(dim
hrith
,"t't)
(f,q)
graph
the
ti,ä'l
exact
full
aenotes
(r,Q) = (i,d),
can assume
a bimodule
restriction
but this
means
(dim M") > 5
or
has the fonn (a,b)
There are three
(c,d) 2_3
different
1 ----->2
is
51 : L(M,0t) -
und
F2
t(1M2 O ZM:)
that
the compositions ab = 3 (that
dimensional
as a left
embeddinq
= (X,X &
(x,Y,q)
because
one indecomposable represen-
L(M'Oj)
given by also
and
respectively.
full
an obvious
l(M,ft2)
just
L(M,n3) kill Ft
cd=2or3.
0.1
o
namely
Now there
------> 3
1 _____-___>2<_ 3
-
and
orientations
92
z L(M,ar)
tation,
hrithab=3
1(-2--------+3
Also the functors SZ
(f,d)
We nay assume that
contains
of
106
with
means, vector
lM,
lM'2,y'id,,p), Sl
and 1s not
and it
tZ ti
is
easy to see
are embeddings,
at the same time
space and as a right
vector
onespace) .
-107
Because
abcd > 6, thls (frdr)
so let
we may also (M,O)
proves
be a proper
assume that
restricted
to
-
the
lemma in
(r,A)
subgraph of is
11"4')
of Euclidian
connected. i e f,,
l,et
11',4').
the second case. type.
(M"Q,)
Let
j € I\f,
be
be neighbours.
Conqider
pi € L( l,{', e, ) _c L( /t{,a) . of course (din pr) o, i * "-r so *i = (Qim a-t !i). is arbitrarily large, because = dirn p. -. p r ) dlm C-r *E, ö.(dim nf, where m denotes the order of
c
modulo the radical
By (2.2.4)
End (c-r
= Fi,
so "-r
polnts.
(note that and
Bi
or
di\
depending
= -eltc-t
!i,gj)
Exr(Fj,
c-r
= -"ltgl,
Ei)
on the orientation
respectj-vely.
pi,Fj)
o, and this
We consider
only
so we have to prove (din
,M)
the
dim
acts
"lA centrally K
is
the graph
assume in
(f,4):
to be infinite.
with
are arbitrarily F = Frr
!,Iith
we get a full
exact
representatj.on
a common subfield dj-m and
of
*G
type
of
realization
F and
= g < -.
G, whiihIn parti-
G.
For finite
must be rnodified
than the category
(a,b)
xr
we need some notation.
paragraph
this
now nothing
K
fi
case.
of wird
pM6, and dirn *F = f ( -, contained in the center of F
ments and proofs is
K
is
"i
= dii
first
on
$ 4 we wilr
[ (FMG)
t(rMc)
(dirn Mc) > S. First = b, dim MG = u,
Let
As in
noer' that
fj
dimensions
=extl(c-r pi,Fj) = ll,, and GNF rgc "j, enbedding [,r(FMc) <-+ L(M,a) by (3.3.3).
cular
< o).
are orthogonar
= dij pi)
c-.
O =
if
F.i
pi)
a"(gi!
Hence we get by (2.1.4) dirn* Exr(c-r
large,
pi)
(f',d');
Nr, of
K
the
s1i9ht1y.
the representations F
state-
Fo4G.
of
G. The corres-
-
ponding
Coxeter
108 -
transformation t\ -'1 , f ab
-a
tl
-11
u,
\\ / The nonsyrnmetric
bilinear
given
is
C
by the matrix
\
B = B?
form
given
is
by the matrix
-a'g) (t
B=
sI (x
\o
I
''x2) (:
ef t5,1) = x aIt =
i.e.
= (xl ,Y2), y = Q1,yZ)
r.r
;X)
€ Oz. The corresponding quadratic
form
Qf
is denoted by Q and i5 given also by B of course. As in $ 4 we call :a positiv root in element x = (x1 ,xr)e;2 Q2 weyl root and a positive än irnaginary
root,
In the following T : mod
if
we will
construct
K <21,22>
T consists
< O.
e(x)
the composition
T
wj-th a partial
(2.2)
set
Lefiuna:
Proof: Then
ä=(1,1),if
B(nx_,x_) nru
Of course it B(IorIo)
for
all
let
imaginary
only functor
loss
the image of roots.
simple rnodules, is
still
of generality
a that
full a>b.
5=(1,2).
1 < n e U.
is enough to prove
< -1 . Let
B(5,ä)
b = 1.
= f + 49 - 2ag = ag + 49 - 2ag = 49 - 2ag =
= 2S(2 - a) < -1, Then a >3
S -n
b=1
are
kilf
Coxeter
ernbedding, so ere can assume lrithout
b+|
3.5.2
of
functors
embedding
see that
of modules whose di.mension vectors Coxeter
If
exact
L(FtlG), and we will
Because the partial
exact
a ful-l
because
and, b7 fb=ag,
f = fb = a9 and f >g. Sc
B(ä,Io)
a > 5. Next let =
f +9-fb
b = 2. (2-b) =O.
-
If
b)2,
f >g
and
Thus in every case We vrill
consider
connutative copies ing
of
B(%,ä)=f
B(ä,-o)
field,
and let
a sinple
+9-fbsfe-
b)
< -t.
now a special
proposj.tlon
3.5.3
109-
case.
be a direct
K,MK,
one dimensional
K, = F = G
Assume that
is
a
sum of a number of
bimodule
K,NK,.
Then the
follow-
holds:
Proposition:
There is
an exact
T : m o d * K r1 " 1 r r |
full
ernbedding
(K,MK,).
Proof:LetdimK,It1=m(=a=b).Thenm)3,becauseK.MX,is neither
Dynkin nor Euclidian.
lsomorphic but
fixed
for
any vector
Of course,
space
x
over
Xm = X e ...
isomorphism
X
and
K'.
O X +
X 6
K,NK,
chooslng Xd
'
an arbitrary for
*,\r
ur"
every
m-times vector
space
equivalent
to
j.n a natural over ,1,"2
K',
over
K,
way. Let X is
it
where
[(K'm),
then
is
easy t,o see that
K'm
X be a
is
if
X
a K'-vector
is
a finite
,L*=
X, also
dimensional X, then
Ar(x) e X
K,-vector X
(i = j,2i
€ m o d ' !K ' (
2 1, r 2 ) ,
id)
: xm = X E
and if
c
K'(
z1rz2> -.
x € X), because
T(X) = X = (X,X,,p) e L(K,m), where
as algebra over
with
space and
beconres a
Now define
1,2u,id,...
dimensional
denoted by zr,zr.
is
a | = (2
is
as K'-K'-bimodure
> -module finite
F-'1z1rz2)
free
L(*,\,)
space, where multiplication
are two endomorphisms of
rnodulesetting
considered
K' a ,1,2,
induces two endomorphisms of
Conversely, q1ra2
X
K'.
------) x. rf x,x' K,K,m*, : X ..._Xr is a Rt
e Iinear
l
_ 110 -
g = (crcr)
maP, then (o,ß)
: X -ä
Xr
diagrarn a third
X O
defines
an homomorphisn
be an homornorphlsm. Now m 2 3, so in component exlsts,
forcing
shor/rs that
the proposition
is
is
F
full.
of
course
above we used that
because the corresponding
be a skewfield
Assume
fNf
the Euclidian
(i,,a) ,
T
is
an exact
embedding,
and
fNF
L(K,!,!K,) = !(K'n).
graph is
be a bimodule
a tree.
Consider the K-realizations
+ FFf. graph
Ä2,
,'/
\t
rFr F
\
,tr./ (l/',o), v,/
r,Fr \"
rNr L(M,o) and
L(/l',a)
ar:e not
This
For example,
one dj.mensional
\l
Then
following
and
proved.
Remark: In the proof true,
the
x'
-rIIl
T
Let
I Is
1""' _
Xr.
c = ß.
*,M6r
xt et*,q, This
C : I -
equivalent.
(M,o),
is let
over
F.
(M',0)
of
- 111 -
Let
norr
imply
3.5.4
be again
FM,
Note that
a > b
and
ag = bf
f 2 g.
Proposltion:
i)
components ii)
Let
slonal
of
Proof:
dim
Let
a : FF O
following
o -_+
f,Mc
for
a comrnutatlve fielil. of
L
dj_mension type
just
isomorphism every
Weyl root
are Weyl roots,
e [(fMc)
if
and
one indecomposable qos, al1
x.
fMC
of
I of
------)
surjective. dimension
Note
that
So, taking type
codirnension
1
*
are
1o resp.
I
--------+ o
____>
rMc
. t1u __________+
indecompo_
2. Consider
lnr*", I' ll .r t "-*
o
is
gj.ven just
_____> o
u
let
ker rg , the
yG
rMc
i.e.
%,
b=1,andtet
diagram
kere
4:
< O, so we
0(5)
be of dinension type
be G-li.near. a is
Irr-
o ------+
up to
-yc
modules
G-subspaces of
sqme one dlmen_
< f .
andy=c!,ir
and only
composable
is
of
(3.4.1).
b+1 f.MC
copies
one component
x < xo
X = (Fr,y,e)
=
F = c = K,,
X = x
din
as in
Y=Gorif
if
least
incongruous
ä. sum of
*(End Io)
with
can argue
if
at
with
I
O<4e22
sable
is
type
many mutuarry
a direct
K,NK,,
B y ( 2 . 2 ) there
i)
module
be not
bimodule
wirh
ä
There are infinite
dimension
Ft{C
Then there
ii)
arbltrary.
inde_ by the
the
-112-
Where
f
denotes
nultiplicatj-on (FF,Y,e)
the
vrith (FF,
and
G-linear
he F, and I ls the natural -!,t^ "/u,n) are isomorphic
between tvro such modules that
the
non isomorphic just
correspond sions
1
to
resp.
End X = E
if
29.
din
*End X < f
for
all
in
this
indecomposable
enbedded in
c,
K = {h€
equivalent
is
mod (F
the
F\'
so also
the
of
all
h € F,
of
dim X = xo.
U
is
fMC. has
has K-codimension
FI1G
End X < F
Because
implies
So
and therefore End X = F
End X
can be also
F = c. We can assume of F-F-bimodules
is
rnaximal Fright: of all
subspaces
F-subbinodules, with
of
Flb
therefore
basis
is F\,
V.',r...rv"
= Nr o...O Na = v.,F O...e taF.
(U + 191, because. a > 3). Then
vlF e v2F O U. Now
Of course
of
%
codimen-
kere}.
b + 1. Assume that
f 2 g, this
intersection
h.v,
of
means, =
I
Furthermore kerrp
sum of one dj-mensional bimodules,
h . 11 = r.lho,
Let
X with
U - v3 F O...O vaF =
an F-c-subbinodule
F-subspace
Nosr let
This
gS
nith
of
cannot be F-invariant, case.
F.
, where FoP is the opposite skewfield of " *FoP) the theory of Artin rnodul-es over an Artin algebra.
insection
Cb Let
is
Then
lsornorphism
of
I
F lhm = mh Ym € M}, so the category
to
a direct
modules
f-ag>59.
and because
F, and we can apply
zero,
and every
fMC End X = {h € Fl h'.kerqS
But a proper
ker rp
epimorphism.
of G-subspaces
ker q
if
j_nduced by
fMC
by some element
indecomposable
2. Of course
> 59. Therefore
Of course
induced
1. Thena>5,
K-codimensi.on
that
is
the F::-orbits
and only
Firstletb=
endornorphism of
= vrhr
v1F, and vrF induces
a subbimodule
u € U, then u'
of
are F-bimodules,
two automorphisms
Consider F\. : = hu € U', So
i.e.
o and
t
U O (v1 + vr)F
of F. S
f\..
- 113-
+vr)
h.(u+v,
=u'+
(v.,+vr)f,=u,
forcjlg o= r.
Similar
and consider
U O (v.,+vliro)
forcing
d = ho, hence
copies
of
f o r s c n r af , e r
l s i < a. Now Iet
forall
F < FMF. Then,
for
a certain
ho€
F,
fr e Fr
+ (v., + vrho)fi = u, + v.,ho + vrhoho
nono - hoho.
F = K'
was arbltrary, of
= u'
+ v., + vrho)
h.(u
=v.ho
h.v.
+v.rho +vrht
Therefore,
must be comnutative,
sorne one dlmensionar
because
and
F-F-bimodule.
ho.
is
FltF
a direct
proves
This
F sum
the
propositlon.
3.5-5
corollarv:
rf
ab > 5, then
t(Fl'rc)
is
of wird
representation
tyPe.
Proof:
F = G = K'
Tf
sum of
copies
proved in
is
of some one dimensional
(3.5.3).
In particular
F = G = K, because
if
fy the assumptions of induction
K
enbedding from some wird
4,8 i) ii)
and with
category if
e L(FMG) vrith the following
true,
it
N^ : = Extl(B,A). ro. l . 1
For, by induction, by (:.3.3) L(Fnc).
this
if
is
into
is
a direct
has been pro
f = S = 1, i.e. let
fMG
prove the corollary enough to find
a full
satis_ by exact
L(FMG). so we are finished
we find
two incongruous
components
properties:
L e t E n d o = F . l. E n d B = G . , , t h e n d i r n Let
Flb
on M. So
we will
Of course
(3.3.3),
is
centrally
ii).
and if
F-bimodule,
this
acts
(:.5.4
over max {f,g}.
by induction
a commutative field,
*F.,,
dim
*G.,
< max{f,g}.
T h e n d i n. . _ FrN .' > - 5 - ..
L ( c N ^ ) i s of wild representation type, and '1 "t t h e r e i s a f u l l e x a c t enbedding from t,r.,*n., ) into
114 -
-
L (X) , $rhere X
purpose consider
For this
componentsof dlrnension type infinite.
By changing
a > b, hence < -1,
sion
of
so
E
End E
then
is
X3
by induction serial
composition )(o
An factors
is
L(fl'tc) i.e.
t (X)
and
all
A'
rhar B.,
und
is
a subfield
bounded.
So we can choose
End -n A
(rxt11e-,A. ^'o "o ) )
din
3.5.6
This
proves
Theorem: orientation
o. Let
a K-realization i) ii)
of finite
non isomorphic
with
order < f
*(End L)
an uni-
downwards),
(3.5.4) . Let in
extension
components in
B(Brr,Ar,) = B(2 Io,n.
-2n,
<
ä) large.
becomes arbitrarly
End -n A
such that
ao
> 5. Now set
satisfy
4
=
\, "o
B = B-, "o
the conditions
i)
and
and ii)
the corollary.
(r,d)
Let
n + 1
n
End -o' X , the K-dim'ension of
of
o End An = F.,, then A, B and Fl above.
number
are incongruous
B'
X3€X\ {X1,X2},
L (E!{G) . Proceeding
in
be a non trivial
n > 1. Furthermore
End -n A
(in L(X)),
E
(in this din
of type if
of tame type if
be a connected valued graph utith admissible K
be an infinite
(f,d).
Then
and only and only
if
if
field
and
(M,o)
be
L(M,tl) is (r,q) (f,9)
.
exten-
a non trivial
natural
length
of
ehe K-dimension of nxtl (En,An)
Because is
for
every
is
X
e X. Then
It,Iz
components
for
incongruous
By (3.5.4)
the socle of
In,In_j,...,X1,ä
I"
of
End X2. Furthermore if
of
choosen such
* t {L,...,In} -a bct'(Yn,Xo). Again
is
incongruous
in
Let
there exists
X2. Now X2
are
set
we can assume that
necessary,
max{fr9J = f.
we can construct
object
where
by
a subfield
and
E
if
hence, by (2.1.4)
X1
the
(see (2.1.7) ).
*o
orientation
f > g, L.e.
B(I1,I2)
is
is
a Dynkin graph,
is an Euclidian
graph,
4
- 115 -
and iii)
of wild
type,
Dynkln Finally 1.)
-of
graph
course
it
nor
fleld
and
is
a
graph.
remarks: the
L(M,o)
process in
whlch satisfy
K,NK,
i-s an extension
is
resurts
to the
case,
a K-reari-zation
comes in
(3.5.5)
of
where
same varued
of
----)
(3.5.3).
of
K, and we get
[(M,n).
of course, K,
a full
exact
Here an extension
embedding
field
of
K
play.
some words seem to be in $reen tame and wild
do this
gories
this
cation
of
in
order
categories.
some chance to crassify
all
some speciar
concerning
all
finitely
category
indecomposabre
embeclding.
11,...,rd
it
l_-_->
K-algebras. over
K, let
modL K
M,- e...O
L__j,
"
t{-
(lh
d+2-times 21
acts
as the
(d+2) x
rn fact
For wird
For let C
we
cate-
(d+2)-matrix
by € nod'i R)
R
be
be an
be a full
Define
T : M-
is
wourd suppose the classifi..
S : m o d * K1 . 1 , " 2 > _ _ - _ > C
T : modt .Rc-->
bet-
there
objects.
cases of bimodures.
dimensional
and
the distlnction
For tame categories
seems to be hopeless,
K-algebra generated by abelian
rnay lead to a bimodule
the condltions
fierd
mod* K' 1"1,"2>
where
neither
(f,d).
The induction
will
(f,d)
if
an Euclidian
i-s easy to extend
finlte
graph
3.)
and only
we urant to make some general
K is
2.)
if
exact
-
/"
11 "r=['1
9J":...
['
is
easy to
have in
o
";,
\o
It
fact
see that a full
T
exact
defines
In particular, is
R, so every ring
4.)
of
if
R
an object finite
For simplicity supposed that
isomorphism
dimensionaL
So we
K, then
over
endomorphism ring K-algebra
here only
i-nvolved
birnodules.
ing binodul.
embedding.
occurs
isomorphic
to
as endomorphisrn
in C.
over a common central involved
with
dimensional
we treated all
exact
c.
1s finite on C
sorne object
full
embeddi-nq
ST : mod't R <+
ST(RR)
-
| lo
FMG between
skewfields
subfj-eld
skewfields
Homr, ("I,la,
defj-ne the Coxeter functors
are
K, which
What we really over
K-realizations,
aF)
finite acts
need is, F,G and
(see (2.2)).
dimensional
centrally
that
there
we
i.e.
for is
on all every
a bimodule
Hom" ("Mar G") So, if
occur-
we define
to a
-
(M,n)
realization fields
r'i, (tMr)
ut\,
i
to
0r then
of
of
graph.
Also there
(3-5.5)
is
F = K(Y) over
that
discrete
R-nodule
true,
dimension
we use arguments
(2.3)
and for
true.
rf
R-module
the
for type,
the
and the of
statements
in
reduc-
course we
K
with
aeopara-
this
(2.1.4).
we take the function field
example
from algebraic
proposition
for
closed
n = F[T,61,
is
infinite
A and B, [ 21 ].
representation and (3-4.3)
type
There_
fierd
usual
deriva-
then Robson and l{acconnell
has
K
as endomorphism
there
is
dimensional This
inplies
(see 13.5.3)).
over K, for
that
ring
have
and
U
is
mod R
any two simpre is
of wild
On the other hand, as in
a non simple Euclidian
,{(FMF) = mod R x U, where
bimodule
an uniserial
such that
Flb
category
(3.4.2t
with
one
object.
Now ret
F
be a di-fferentiarly
closed
field
Then, as Cozzens [ 6 ] has shohm R = FtT,6l module, Euclidian
namely
RF,
bimodule
the number of is
remain
vrlth respect
1
Ext'(A,B)
simple
lecture
(t,q)
in
K, if
no longer
any simple
j
=
(iMj,ti)
Ho\,.
to the case of birnodules.
nor substitute
we set
such that
skew-
r^rith
iMj
non homogeneous modules
an algebraically
6, and if that
for is
this
regular
subfield
in particular
shown,
in
to be a set of
F.-F.-binodule
1.-.
the modules of
the
netry,
tion
arrows
the homogeneous part
need a central
fore
all
of
an
,rt, I = dii
ut\, for
with
many statements
classification tlon
together
= dty
the crassifiction
(f,d)
of a valued graph
e l,
= Hotnn'. (rM.i,Fi)
-
llI
equal to
and this p\,
module is
such that,
indecomposable
for
has just
injective.
L(FMF)
of is
Fl"tF of
6.
one sinple
This
every positive
representations
1 or 2, in particul_ar
vrith derivation
leads
to an
integer of
length
tame type.
n
With other that
is
t(FMc)
dimension of
M
ments
(orß)
in
is
too
not
(3.5.6)
ii) If
of
over
large,
type,
of wild
type,
is
(M,a), if
if
the
involved
if
if
1,1") )
the
the set of ele-
first
bimodules
4,
for
m e M),
all
inaccessible
strongly satisfy
this
condi-
by the following:
if
(t,d)
an Euclidian
References:
(3.1.1)
quivers,
e.
for
The generalj-zation
j-f
and only is
(r,d)
neither
graph
L(M,0) is of wild
i.
(din
cm = mg
than the
snaller
t 25 I
"U) of M (i.e.
F x G, which satisfies namely
has shown in
(din
if
Z, the center
an be replaced
finite
(f,d)
type,
Ringel
r:
l(M,n) i)
of wild
number.'So,
cardinal tion,
than used here,
arguments
it
is
a Dynkin
Euclidian
depends on the
graphs of
to valued
nor Dynkin. reallzation
or tame type.
has been proved by P. Gabriel valued
graph
type
in
$ 1 and $ 2 can be found in
in
[25].
I 11 l,
of
for
Arr, Dn, 86, E7 and Eg.
graphs has been done in
of
I 18 I
[1O].
the remaining
l,tost
paragraphs
.
1.
VORLESUNGEN AUS
DEM FACHBEREICH MATHET'IATIK
DER
ESSEN -
In
I,'NIVERSITAT
this
series
H. Stichtenoth,
already
2.
H. Brückner,
appeared:
Alqebraische einer
GESA"UTHOCHSCHULE
Funktj-onenkörper
Variablen,
Explizites
1918
Reziprozitätsgesetz
und Anwendungen, 3.
M. Chamarie,
Sur les ordres d 'Asano ,
4.
J.C.
Robson,
Some results
5.
L.w.
Small,
Rings satisfying
1979
maximaux au sens 1q7q
on ring
extensions,
a polynomial 19 8 0
identity, 5.
H. Jacobinski,
Maximalordnungen Ordnungen,
1979
und erbliche 19 8 1
118 -
Appendix A:
s1
Applications
Alqebras
Let
(f,d)
the
tensor
Let
F.
be
€ f),
(M,0).
of
bimodules
resp.
and make M into
a
=
write
is
decomposition
form
the
n-fold
in
r
^Ml
the
, wrt A =
via
the
skewfields
defining
O) the
M =
Fi, -
.o_ i€f
construct way:
following
O i.*.j inf
r
1Mi
A + F.
Drojections
because O iM.i, r.+.J of A-A-bimodules.
(i
€ l).
decomposition
this
n > O,
for
llow,
Mn = M O^MA^...8^M,
grroduct
tensor
in
Then set
A-A-bimodule
I{e may also a direct
'j
(M,0).
K-realization
(M,Q)
of
(i't
rMj
IIJ-
wi.th
T(M,A)
algebra
(i
graph
a valued
we
where
@
=
Mo = A, ltl = M, and putT=r(M,O) T through
a multiplication i i i+i Mr * M'-r M'e.
and extending
becomes in this
way a ring,
K-algebra
e Mn. Nowwe define n=O isornorphism the canonical
of
R a tensor
it
(M,Q) of a valued graph (f,d). dimensional oriented
R = f(M,n)
if It
over K, because Q is in
circuits
f.
same K-realization
for
is easy to see that i.e.
admissible,
Furthermore
J(T),
T is
there
i2+...+i*
for
particular
the Loewy-length
one of alL
occurrj-ng
A 1.1
Proof . as
Proposition:
Define follows:
€ f in
some i., ,...,ik of
T is
the Jacobson radical
I with
of
and
respect to 0. In
the maxirnal length
nlus
pathes
oriented
rnod* T and
R : rnod*(T)
just
finite
are no
is given by e ut, more generat .rk(T) is given by o Mi, i=k i=1 . uK + (O) , if and only if there exists an oriented path i1{
a
and we call
or even a K-algebra,
algebra,
T
obviously
by distributivity.
-
L(M,ff)
l(['{,Q)
equivalent
are
and P
:
L(M,Q)
-
categories.
rno
T
-
Flrst,
if
X
ll-module. x^
a rlght
T-module,
n =
Because
is
,-?at decomposes uniguely into
right
F.-vector
Vte define scalar
space, /l-Iinear
the
multiplications
Xr O .M.
tj
is
119 -
into
linear
lnduced by
rl
R(Y) = (Yt,
R(q) =
deflne implies fact
I
:
X8A"^**
m € M (p
is
on
Xn
=
The fact jri
,
that
Fi
,8, The scalar
q(l ) -
o i,j€f
=
(using with If
the
fact
(q.)
P (q) =q= I-1inear.
Ji 9 .
that,
=,p(,p(t) X O oj i€f
Xi
that
is
y
-
Xj
Lw,n) joi),
of
q
is
f-Iinear
R(o)
to
is
Xi
and
in
Mn
define
Xi, h,here r?, the projection 1 -
via
by
on
X
K..
is defined
: X6Mn+Xwith
: x E^ M =
(Xr8o ^ 'i
e i, j€t
q(n+1) o =
on
multiplication ,(n)
right
L(M,n)
operates
inductivelyby
the
maps
because
o
Conversly, given X = (Xr, jef)€ t(M,0), X = P(X) € mod* T addirively by * = n =
by
yrr
a
€ f
g
Then
R(X) = (Xi,
q (Xi)
is
bythe
be the restriction
a h o m o m o r p h i s mi n
+ j
ox, iMj iMi = = R(x) (xl, x j,pi)€
that
q = (ci).
Xi
= xi
in mod* f and
oi
as right
decomposition,
i
determined
x:. on
(oi o 1) = oj
jüi
I
X
where
map
jqi,
Let
Xr,
= O for
j r . l 1 r) n o t i c e
^-1inear.
a is
x = oigt F.
we define
Also given c : X + y
direct
X.
thus
mapping
a ring
and
of
X.,
consider
for o t) rs
,M.)
i :
+ k,
o i,j€f +
e i€f
Xi
i
P(Y)
X.=X )
En r.M.i =
"'-'cool
(X An M..)
a morphism in
: P(X)*
x, o. .M. r- A I l
E.l M L (M,Q),
can easily
-
(O))
and
(9 X 6_r. M + X then
be seen to
be
_120_
Now it
is
between Note,
easy to mod*I
that
1s called (Ieft-)
is
right
exact
semiprimary is
all
are of
equival-ently,
if
any (left-)
right
(i.e.
R
of
. Our aim in
the
J(R)
right
K-algebra,
finite
tame representation
finite
resp.
K
*/"(*)
and
and left to give
type,
hereditary a classificatj.on
(i.e.
in
R,
rings
a commutative fie1d,
tame representation
R
For
Artin
type,
of
Extt (",-)
nilpotent for
called
ideal
functor
in
hereditary or
right
hereditary
paragraph
this
F. is
R-module x. is
is
property
this
a ring
, in particular
being
T-module
each (left-)
if
Artinian)
prcPerties
coincide
of
for
rings
semisimple
the
of
or,
an equj.valence
algebra with
More grenerally,
right-hereditary,
projective
define
a projective
An Artin
hereditary.
is
p
and
submodule of
(2.2.8).
by
R
L (M,0)
and
every
projective
see that
which
mod*
R
is
the sence of
Chapt. 3). Of course to do this K-algebras
R.
basic
B (R)
Pp
rinqr
is
If
o n l yof
course 1f
Morita
equivalent
with
is
an aribitrary is
is
is
Artin
nonisomorphic
a direct
Morita
ring
the
projective
R = B(R)
if
and
sum of skewfields,
equivalent
dimensional
to mod* B(R)
basic
as End (pR) , where
defined
all
a finite
above, is
K-algebras.In
enough to consider
R-module. Of course
resp.,
Of course it
is
sum of
/, / t"ß) r i l o dR is R
is
R
J(Rl
if
defined
R to
the direct
indeconposable
it
and
to mod B(R),
K-algebra,
. Note that
mod* R is
f(M,Q)
,
basic. also
enough to consider
particular,
K-realization
(l{,Q),
if
(f,d) then
is
indecomposable a connected valued graph
T(M,0) is
indecomnosable.
-121-
Note that
an lndecomposable
finite
resp.
valued
graph is
tame type,
heredj-tary
type.
There ls
hereditary
graph
A'
where
F
central
is
of
by
finite
.on"id.t
the following
K, and
way all
type but
tame indecomposable
a skewfield,
subfleld
Euclidian
of
of
the corresponding
which are no tensor
algebr""
trith
if
is
fact we get in this
a class
this
algebra
and only
K-algebras
K-algebras
To deflne
if
Dynkin resp.
(3.5.5) and (A 1.1).In basic
tensor
first
basic
hhe Euclidian (11,0) ,
dimensional is
fNf
tame
alqebras.
K-realization
finite
not of
over
the
a one dimensional
F-F-bimodule:
F'F
rFr
rFr /
\ rNr
We.can identify F
acts
It
is
on
the left
FF
easy to
vector
from right
see that
(n + 1) x (n + 1)-matrix
space
FN
with
by an automorphism -- T (M,0) is
T
isomorphic
ring FF...
FM
; I E i F F
[' Än(s,o):=
F
o
\ \
.FF
I
l I
.:;; .F
\
F
,F, e of
where F.
to the
-122-
M =
with
O
as
"F" "N" be an automorphism and (where
e
fixes of
definition Ärr(e,o) by
€ F)
(3.4). a basic M(e,6 )
is
a tensor
algebra
holds
K).
RecaII
hereditary
indecomposable
= M(e',o)
if
i.e.
We will
graph
if
= T(rM(r,o)r),
see that
we still-
D > 1 ,
argebra
n + 1
t141.
< n ; then we have also (r1,
for
permutation
(1 2 .
(ra, rr,...,
td)
and (rr,...,.d) called .,
Extl
(snrso)
satisfying
a1r
t,
where
n-1 o n).
n
is reqular.
td-2
+ o
for
+ o. A o < rt
:
n
is
the cyclic
Furthermore,
= n -
if
(rj,
is regular. Finally, if
which
11 + n, rd + o
if
is called preprojective
preinjective rd-l )
(Sa,Sr-.,)
regular
is called
ra*1 = n(ra)
Än(e,ö )
Extl
integers
.,rU) of
(1 < t < d €N)
Evidently,
sj.mple modul-es So,...,Srr,
are ordered in such a way that
sequence
For the
is of tame type.
Är, {6,c)
the
in what follows.
In particul-ar
need some notation.
has precisely
(r1,.
of
l,
11 = o, t2 = 1 .,rd-1,
td = n
is
i.nner
tensor
the
n > 1
Ä,,r. so always
proof of the statements see
is
is
6
6
cf
for
. consequently,
5]
describe now mod* Än{6,e).
we will
and
. c -
= et
d
lf
and only
"M(e,ö)"
1 < i
the
K-realization
Euclidian
First
F
of
M (= M(e,O) ) in
and only
if
Är, {e,6)
e
Replacing
F,
of
c € F,[
a suitable
for
n = t the
in
(e,'l)-derivation
Är.r{ö,e)
to
annihilates
Now
t.,O ).
\
an inner
For
6
M(e,d )
no\^r
(e,1)-derivation
arl
ö
M(e,ö ) we get
K-algebra
(f
and
Let
F-F-bimodule.
and
rd)
-
A 1.2 are of i)
Theorem:
The indecomposable objects
the following
in mod* tÄrrte,O;1
types.
For every regular,
preprojective,
(r.,, ...,rU)
is a unique indecomposable module
, there
X € mod* (Ä-(r,6)) n'
xt/"
such that
"t- 1 is an uniserial The'direct
or nrej-njective
sequence
hrith composition series
O = Xo.
ii)
123 -
X., -
c Xd = X,
...
- s't
for
all
t.
Furthermore
End x
ring. j-ndecomposable
sums of the renaininq
m o d u l e s i n m o d * ( A r .(,e , 6 ) ) subcategory which is equivalent (For the definj.tion
of
Flt;
The equivalence
ii)
is
gj_ven in the followinq
is
assoziated with
i_n
The
FIT; s,6 ]-module
W
the
Ä-(e,ö)-module n-
I . Je . . . O W
ärr{e,6)
(arb)
A 1.3
Corollary:
€ M
on which
matrix
operation
with
the additional
and
w € W, we def j_ne r^r(a,b) = hra + rrbT.
condj-tion
that,
Är.,(e,ö) is of tame type
Proof :
B y ( 3 . 4 . 3 ) m o d +( F ( T ; e , 6 ) ) i s e q u i _ v a l e n t r o
a direct
factor
every
of
indecomposable
an uni.serial is
wav.
=
operates. by the ordinary
from the right, for
see (3.4 ) ) .
e,öI
; '
to mod* (FIT;s,ö]).
H(M(r,ö) ),
module in mod* (F (T; e, ö) ) has
endomorphism ring
tame. So End
X
in partj-cular
is
uniserial
m o d u l e i n m o d *{ Ä r . , { c , 6 )) a n d
and mod+ (F (T; e ,6 ) ) for
every lndecomposable
Än(e,6) is tarne (see also
(3.2.)))
-
Rernarks: Coxeter First
1 ) In functors
of
-
the representation play
we constructed
that
tz+
the basic
theory
an importent the partial
role,
but
the
also
situati,on
endofunctors, usually
case,
the elementary
j-n
(A 1.2.i),
that
rnodules
one projective injective or
It
the modules
preinjective
So
f*
the
out
and
f-
are
same way as one
is
6
if
is
a tensor algebra,
that i.e.
the indecomposable (r.,r... rr.) O i
,
r € N,
modules are
End X = F
for
X. Also
is and
just
the
has preci-sely
Är., {e,6)
So, and precisely
modules
1-(n+1)
"116 the preprojective
f-tto
(observe that
indecomposable
Än (€,6),
(n+1)-powers f+(n+1)
indecomposable
in particular
imitates
possible
(In particular,
the
turns
is
for
Är.r{e,6)
sirnple moduLe, namely
Sr,) .
f-
whose corresponding sequence
, o < r €N.
t*ttr,
if
are just
the preinjective
sinilar
them in
X € mod* Ärr(e,6),
are just
preprojective,
i.e.
functors).
indecomposable modules X
this
the Coxeter functors.
then the Coxeter functors of
in
the
and then sre
Now it
is
(e, 1)-derivation,
an inner
(2.2). f+,
and one may work with
does with
group,
"elementary functors" much easier
algebras,
whose behaviour
i.n the rteyl
reflections
tensor
as we have seen before.
functors
composed them to the Coxeter functors to construct
of
one simple preprojective
all
a dimension
vector
h+1
(€ f") for
and the defect
K-realizatj.on
descri.bed regular of
2)
of
in teuns of
the defect.
the
regular
fn particular
Sinilar
modules can be
one get
endomorphism ring.
as
that
all
For details
s e e [ ' 1 4l .
There iE another'way understanding
Consider
graphs,
Euclidian
modules have uniserial
the proof
better
of a module can be defined.
the following
of
to descibe mod* Err(e,6), the
internal
valued
structure
graph lvith
of
which gives
a
the modules.
the K-realization
(t{,4)
-125-
as foIlow:
f,r
FEF
f,F
F-_--> 'n-1 4
----->F
F '2
FEF
M ( e , 6)
Thus X = (Xi,jpi) n linear
naps
€[(M,n)
consists
: Xi - Xi_j
i_.lei
(n+1) F-vector
of
(1 < i
spaces Xrr
< n) and a linear
map
t X' O M(e,6 ) - Xo. o9r, Let
Lc(M,Q) be the full
X = (Xi,rer)
subcategory of
such that
the following
Xr, 6 M(e,6)
where r ,
S
FFf Then Lc (M,Q) is
For the next
*_._
n-19n
M(e,5) is
the natural r^
equivalent
h^^*
lemrna 1et R be an
Suppose that
€ R be orthogonal
F = fRf
R is
basic
primitive
above is
allsays satisfied,
iA n \ rc-r u r r /.
finite
of
(It
is
fR resp.
R-modures. observe if
R is
homomorphism between tsro projective
dlmensional
and indecomposable.
idempotens,
and G = gRg are skew fields.
indecomposabre
embedding (see 3.4).
arbitrary
and G are the endomorphism rings projective
representatj.ons
xn : xnolFF o91'192'
f,9
of all
diagram corunutes:
xo
K-algebra.
L([i,0)
hereditary,
Ler
and. assune thar well
known that
F
gR, the corresponcling that
the assumption
because then every
rnodules must be iniective).
Let
fJ(R)g,
FNc:-
Notice
that
as
considered o fR9
FNc
a full
exact
--+
mod*R
T : t (-N-) rb
Leth=1-f-9,
idempotents. we get
J
R!
form
R with
End(*R)
fJh\
c
q;h
(Note
\
Let Then Set
x
=
M = Mf
(XF, Yo,to) €
define
'r 1
R3r = int-rt li.
'
nJ5r'
to
I(FNG),IP
.i
as
:
XF Q
1n the
f,
because
R is
a direct matrices
sPace.
operate.
Let
\
withrl€Frrr€G,rr€R'
nlag'
nr^n 'l I
)1,.-.,j5€
element of M. Then define
sum of
way:
9Jon 1
@ fjh)'
basic).
+ Y".
r)
m = ( x 1, y , x ,
idempotent
an
those
"N" following
K-vector
= fRh,
contain
into
on which
fJh
exarnple
h cannot
decomposed
O Mg O Mh,
f i h \ -z
' J 1 aa
be
can
(xOF fJh)
€4
for
isomorphic
= M €mod*R
T(X)
M = x 0 Y o
'
ret
M € mod*R
spaces
orthogonal
= Rf O Rg O Rh
and using
that
because
l;"t hrs "* ,}
K-vector
way.
"R
fJg
Any module
of
set
a complete
= J(R)
E I / o.rf
natural
embedding
so f,gfrh
Identifying
srith
the
o Horn*(9R,fR).
A 1.4 Lemma: There is
Proof:
in
F-G-bimodule
(x,,xr€X,
Y€Y,
J(R),
and
j €J(R))'be a generatj-ng
-127-
m.r
= *1
t1
= *1
r
the
onto
m2 = yr2+9(x1
11 € x,
and.m,
I
(m1,mr,mr) €M by setting
:=
f)rh+
whole
x,
of
of jls)+o(xrotihjrg)
O fjhrrh€X
M by
AFfJh.
linearity.
= O and gJh.h.Jg
= O, because
fields.
usi-ng
easy
in
this
way,
If
(c,B)
shovr that
Of T is
Xi€L(FNG),
i
So let
c
Let
x€Xr
, 11 -
course
A 1.5
Lemma:
K-algebra,
is
f
is
=
r
out
A.T-A.T R:=^/t Then R
So r
A be an
an ideal
J.I
of
=oO
gFfJh)
C (Xi
remains
F-,
to
map. Now
and 3
x2 @FfJh is
= o(x).fjh,
T(q,B)
= T(Ii),
and sinilar
c is
be
c y2.
o(yt) is
G-linear.
hRh-linear.
because o is
R-linear
1 and it
is
easy to
see that
L(FNG), i.e.
o=
T(o,3).
So t
finite
arbitrarv
A contai-ned
in
is
dimensional
Jz(A),
If
A/_
is
(O).
_
we can assume first
-/tL>^/I=R,
hereditary.
e y.
-
to
shows that It
: X1 8"fJh
Then o(x-fjh)
Let
then
Factoring
t
skew
a R-module
T(q,B)
embedding.
. Obviously
a morphism in
[17]
define
m e a n s o ( X . ,) c X ,
As above
=(O),
fJf
becomes
M1 * M2 be an R-linear
B := olr,
c
of
= X OF fJh.
verification
Mi = Xi
action
f.Jg.gJf
M = T(x)
L(FN.),
an exact
So let
= c(x)Ofjh.
hereditary,
because
T is
this
= F and gRg = G are
that
in
A direct
c M2f that
X,
see
a morphism
and j €J(R).
(q,ß)
to
that
fRf
M9 = y and llh
T(Yr).
ol*r""f"n.
t(xefjh)
Let
-
:= ol*_ and "1
hence
Proof :
is
full.
= o(Mt).f
:=
is
= 1,2 and leto:
s(M1f)
t
x,
: T(x.,)
R-Iinear.
Let
i.t
and Mf = X,
: x,' r
(o,B,oo1 ) is
thls
Extend
Notice
fJh.hJf
€ Y,
Notice
hence that
I,J
"/, and
J.I
=
(O).
isprojective, 12 = I
are
ful1.
-123-
= J/,
.l(n)
Also
pJ91.r -fo
be a projectlve rn
rl
.1
.r -\"7,
eJf
sider
ker g c ,.J/I -1 q- | (r)
, .t
because
= P." /t tr,
is
hence
ker(rlo)
projective.
R
cause
is
with
R-module.
Let
J
as
R-module,
and con-
F{
+ (o)
rf
hence
Qü,
means
this
an
is t/".,
= {o),
lndecomposable
basic
be a complete set of = erRer(=
Fi
Set (f,d)
a valued graph
define
Be-
End etR)'
a skew field.
to be the graph with
n
Ütp splits'
by the Nakayama lemma.
is
,n."
.
Also
PBut
.
Then
epimorSrhism'
in
small
J'I
idempotents,
heredj-tary,
orienlation
^=
€1r...r€r,
Let
r= ei(J(R)/"21n))"j
iMj
/,
dimensional
a finite
primitJ-ve
of
f
I = (O)
K-algebra.
hereditary
the radical
E P'" /t
If
the
is
the natural
is
= (o))'
(t2 =- l'r
'
/,
consequently
1 = (9). hence
r
of
cover
ker g
be again
R
orthogonal
I c J.
o
because ,
I = J.I
Nosr let
t
where , r,fr is
,
isomorphlsrn, i.€. 1.e.
12 = t.
In particular
J.
R-module
hence
,
r
by
are annihilated
because they
R-modules,
1, " '.rr
vertices
'
wherei,j€farejoinedbyanarrowio-)ojrtithresPectto
i
anil on1-y lf
lf
0
M, = (O) ,
d..
Lf
the
iMj
R
because
(note
+ (o); is
hereditary).
Define
g
€ l.
Let
= d i r n o ( . M a ) , d + r = d i m o . ( . , l i t . ' , ), L , j .i ^ :
inplies by (M,0)
be
€ f)'
Then
JL
J
"j
+ (O)
. uj
that
K-realization
of
(l,g)
given by
Fi
,
iMj(i'j
(f,d)togetherwith(M,n)iscalledtheK-realj-zationassociated with tensor
R (or the algebra
K-realization (M,0)
is
a
K-species t(En)
is
associated K-realization
to
R),
denoted by with of
and is I(R) '
the tensor
denoted by obviously
algebra
some valued graph,
ER the
T(M'0)' is
The
again
r"here (l'{'fl) '
- 129 -
n o T(fn)
so
A 1.6 Lenma:
if
and only
R
ls
if
R
a tensor
ls
a tensor
algebra
)
if
and only
--t
O + e, J- e, + ei J e. - er(-/"2)". Fl-Fj-btuoodule sequence for
Proof:
Obvlously
a tensor
algebra.
all
the condition Furthermore
* O
i;j
if
splits
as
€ {1,...,n}
above is
the
algebra.
, nhere
satisfied
condition
is
if
R
equivalent
J = J(R).
is to
the
(J = J(R)):
follottlng,
).a -/r2 O + J- + J +
+ Q
splits
as
Ä-bimodule
sequence, rjrhere
nn
A = .O- Ft = .O- e.,. R e. i=1 i=l
.
So we can assume that
= nRA rrArrsA e /Jiln o ^J2n Conslder
Of course
T(R).
pl
is given by
h
, iüj
, i,j
€ {1,...,n}.
In partlcular r(R) =
^NA r
t
=.o^
Mk , M =
-"
k>2
nÄl ä
ri i { iJ
i,j=l
by
^NA-AJ-^
Novr rre extend
r
e,L (/Jül =
where
nN^,
in1l J / .ur i l ^
= R.
Define
=m1 .-.mk,
t(mr8...om*) to a bimodule
o
homomorphism
(mreMcR)-
- ,Rn. Af(R)n Of course r is onto and rnultiplicative. Furthermore ker t c nNn ) = and = (o) and J- (T(R) ). B e c a u s e R i s h e r e d i t a r y , k e r r ANn r
ls
an lsomorphisrn by
The next fact
it
Leruna makes sho!,ts that
from tensor
algebras.
(A 1.5).
(A 1.6)
basic
r ,
a little
hereditary
Artin
bit
more reasonable. alqebras
In
are not so far
-
A 1.7 Lemma: i)
e.lr...r€r,
3,
Let
There is
Let
onto
(o) e, lJ / ,2) er 'v+1 + ^v "
.,ia}
{i1,.
(1:vSt-1) :=e.
I 1
T =
Proof :
Je.
)2
.
Assume that
Let
12 e. J e. e. ... ru_1 rv+1 .u
e. tt_1
J...ei
Ju-1
...e. J2a-, Je. rr-1 lu lu+1
r-1 S . , < e -i 1 a l e . I v=1
...
r-'l ... E T . , -< e . J e . 11 r2 U=1 Y S+Ul
First
note that
Ut\i(en
r
such that
the direct a submodule. P
of
.kR
sum of
Ja.i tr
,l er)
,
=: Ur Je. e+ rr-1 Jt
qnd
,I+tJ2
=: Ur
Je. e. 't-1 tt
U1 nU2:SnT:.tJ.j
e k J e j s H o m ( e r R, e * R ) ( j , k € = rjk
is
iust
the
largest
a submodule isomorphic contains "kR To see this let .jR. Q copies of
Obviously
it
isomorphic
to
j-s enough to "j*
is
show that
contained
in
every O
{'l,.'.n}).
natural
J
number
J e, tt
Let
Then
Furthermor"
such that
{ 1 , . . . ,n}
and
(1.u:r-1). S =
by
e* (J/ ,2 )e* + (o) 'u*1 'u
and
+ {j1,...,jr}
S := e. iI e. J ... 11 ,2 v
u
frorn
, 1 a U 1 r-1.
1 I v S t-1
for
given
'-j1,)2,...,ir=)
,
indices
J = J(R).
isomorphisrn from
J ek J ej
ei
i=it,L2,...,ia=i
be sequences of
T
as above and let
Fi-Fj-bimodule
a canonical
J o e* J e, "i "k multiplication. ii)
130 -
to be such
subrnodule
(that
is
-
tJt
-
is "ejR-homogeneous',).l,et M=e+plekR. Then M "kR projective and the canonical epimorphism e O p - M splits. maximality
of
r
novr e : p.
implies
ejR-homogeneous component of rnodute
P
let
the sum of
all
an"
component of
e{
using
the
component of
(e, J eO .r er) = rik multiplication e.
e. (R)(k, j),
J e*
the
l.e.
e*F.-homogeneous
rki
i
map from
J e.
and
comparing
dimensions
ii),
notice
u t * , , . n l J/ , z l . 1 "
that
is
just
the number
summands of
.kJ
be
"iR).
the rank of
dfut
-j
p,
i).
To prove of
just
iruplies
onto
AJ
to
This
canonj.cal
J eL O er- J e.
we get
is
e.R-homogeneous
"iR.
a projective
for
O.
J e* J er)
rank i,
isoroorphic
e
The
the
erR-homogeneous component of
the rank of
Noh, U\,.,.,
thus,
the
(more general,
.kR
submodules of
r = rik
Call
the
P(j),
e = ekR(j)
Call
is
into
isomorphic to in a decomposition "kJ "jR indecomposable modules. Now ii) follows easily.
A 1.8 Theorem:
Let
R
be an hereditary
flnite
of
dirnensional
K-aIgebra. i)
ii)
R
is
of
finite
representation
type if
B(R) o f(M, fr,
where
finite
union of Dynkin graphs.
R
ls
disjoint of
(M,n)
and only
tame representation
type
, ) e A 8 ( R ) g f ( , 1 {Q
(ring
is
of a finite
a K-realizatj.on
Euclldian
graphs,
and
A
is a K-realization
direct
is
if
and only
s u m ), r v h e r e disjoint
a finite
if of a
if (,t{,0y
union of ring
direct
sum
-
of algebras of type defined
Proof:
So let
(A 1 .
\{ith R
R
is
a complete
F. = e. Re.
in
set
of
1 < i
N let
2 .JI €.J*
Thus,
if
there
III
Chapt.
be the
dim- (,N.)
exact
mod* R
of
Because
R,
we can be
€1r...r€r,
idempotents,
< n.
iNj
a full
> 4,
type
primitive
- - ) , (, J- /, , 2^),* €
is
drr(iI)
is
K-algebra.
hereditary
orthogonal
= End(e.R),
LJrJ!uJ
(A 1.4)
in
and indecomposable. Let
+J.i.l.j*,
o +
proved
theorern is
the representation
d.. (N) = dim- (,N-)
*. By
the
dimensional
basic
For each R- bimodule and
Ärr{e,ö)
) and (A 1 .3 ) .
interested
assume that again
of
'l
be a finite
we are only
where
Ärr(e,ö),
as above.
The "if"-part
together
-
tJz
('l < i, j
< n).
r
Consider
O.
of
type
wild
c9
L(iJj)
embedding is
erNei
Fr-Fr-binodule
mod"
(3.5.5),
by
R. and
L )
mod
R
cannot
be of
i)
Let
i,j
€ {1,....,n},
R
be of
In particular, for
i, j
all
i.e.
R o
graph
by
ii) then
Let R e
finite
finite
type.
hence
dimo (iJ*) 'i-r'j'"
= (O)
.1 Ja l €
type,
and
5
dij
(J)
1
or
,tJ / rzl:
By (A 1.5)
{ 1,. ..,n}.
T(R),
Then
or
> 3.
dij(J)
if
I R
1
dim,
tot
aII
(.Ji)
*
and
1
1.
splits
is a tensor algebra,
must be a K-realization
ER
for
3
of a Dynkin
(3. 5.5 ) .
R
be of
T(R)
by
tame
type.
(A 1.6)
splits
If and
K
is
for all-
a K-realization
i,j
€ {1,...,D}, of an
- 133-
Euclidian
graph by (3.5.6 ) .
So let
I,j
drr(J)
= a
in this
jarticufar
r.,
this
inplies
IJet
annihllates i
= i
Because k
1 S t 1 k. ,' sl J / " 2 \ i "
tt
and
such that
using
t
a
....,iki
and
.K-
i '.r - 1- { J / r"Z ) i .' t
OR of
*Jr_
than one. So, changing
t*
to
and restricting {O,1,...,k} 1 ------)
= (O)
+ (o)
implies
o I t:
2
,
Z. k
for
circle
such that
in
or agaj-n
the graph
s=t-1
fR
there
is
. --t
way
the graph of a,. (,f2)
rrith
i=
ER
would be ia
by
orientation
k_l
from
+ (o).
s € {O,...,k}.
(replaclng fp
i.J*
Ire get
no additional
,
Let
for al1
the indices
---)
be
for
,/\
\"there in
F,
we see that
ar.r{,f2) :
could not be nilpotent.
, O s t S k),
for
v 1 k)
+ (O)
L-)
greater
of
6
O!
J, -.,t - 1 - t
(A 1.7 ii)
we would get an orrlrra.a
J(R)
.J, r M(e,ö)
for
,1st5k)
othen"rise
Then again by (e 1.7 li) otherwlse
and
(iv € {i,...,n}
(osssk-l
+(o)
m € {1,...,n}:{i
dij(J2)=arrtJ/"2)=t.
(e,1)-derivatlon
is maximal,
l'urthermore,
s = O , t = k;
or
Of course
K.
a sequence of maxlmaL length k.
F. =; p
F. r
and some
6
= 1o,i1,...,in
1 S t:
does not split.
case. Necessarity we have
some K-automorphisn lrhlch
*
such that
€ {1,...,n}
t'
-134-
O:
"
, t.
By (A 1.7 i)
k.
J
"o
e1 J O ...
I
"1
J.k
e.k-1
eo J2 en . . . e n - . , J e * e r n b e d d sc a n o n i c a l J . y i n t o J J "1 "2 "o = so dt-1,t(J) (note that k > 1, because eo J2 en + (o)). for
In particular,
1 s t S k.
n > k+1 , that
Assrme that complete
set of primitive
an index,
say
(the case
+ (O)
**rJa
be maximal with o: and, to
"
can be treated
and
OR ,
$re qet
1 t, J
and considering
and at most one additional if
oJk
.----_-l
Tf
X =
setting
=4,
OK
T
:
in
k+f
to
kJk+1
(Xo,\,XL41,peor11191) X = Xeo O Xe1 O ...
*
lrtith respect
If
there
ls
no
t = k+1 '
if s r k-1 t = k,
(A 1.7 ii)
to
k+1,
consider
. Fk*1
[ (,u,0)
L(M,Q)c-1mod
by (A 1.7 ii),
fR
see that
all
for
using again
Also'
K
d,(J)
Now define
J e" = (o)
. ------------J
o
Because
O s t : k
= tO) ' *.rf,*, (M,Q)
K-realization
the following
Let
way from some O:
Always holds
t -1 k-1.
s : k-1
O :
similarly).
easy to
is
it
O 1 t 1 k,
circle
cannot be nilpotent. oJk+1 ,
some
dok(J2) > 1
t+1 S s'
is
Then there
for
.k*j
Then
an orj.ented
way from some
additionaf
idempotents.
(O) aJn*., +
property.
this
does not form a
€o,€1,...,€k
orthogonal
otherwlse, if
s S k. if
is
such that
k+1,
F1 .
Fo = Fj *...e
j-s of wild
R
type.
as follows:
€ L(M,a) O Xarr_1 as
define
X = T(I)
K-vector
sPace,
6 mod* R
-
rrith
Xes=Xo
135 -
for
O!sSk-1
for
k+2 a s :
Xen = X* xtk*'r
= xk*l
Xe" =
(O)
necäll
that
O 5 s :
k.
P" e F,
= FF
s_1Js
Now define
n-1. (as
an R-operation
F-vector on
X
space)
using
the
for follor,ring
mappings: id X""
E
(O 5 s :
Xe. "J.----f id
X."
6
Xeo S
oJ;
"Jk+ for
1 :
s S k-1,
r
1 k-l)
181 " C-----+Xeo
where
r ,
o.ff
kgo E
oJ*-----.tXe*
*o"n
is
the
canonical
embedding,
k+19k X.k
a
kJk*1€Xek+1 k9o
Xeo I
Tf
,
oJk---+Xek
all
other
: X + Y
is
a morphism in
can be defined
as
in
is
o
a full
Next
exact
So
R
O S t 5 k-1,
spli.t. by
This
is
cannot
zero.
T(o)
: T(X) -
easy
to
be
tame
see that in
thls
T(y) T case.
and that
)r
not
L(M,Q),
and it
o+tJi*rltJk*r
{O,k,k+l} this
embedding.
assume that
** does
(A 1.4),
maps being
1{"/J2)k*.tlo
reduces
to
{t,k+1,t+l}
,
and if
**
the
and
case R
above,
cannot
i.f. we replace
be tame aLso in
case.
If
O S t
for
alL
I
k-1,
O < s < k
the
splits,
secrrFn.F
it
is
easy to
see thar
136 -
-
4"Jk*1 --+,{J/ ,z)k*1 {
o -""i*., In particular
wild
of
spl its .
s = o.
for
(M,0),
K-reaLj-zation
following
the
Consider
o
which
is
of
to
be
course
type:
FA
o
K
Notice
that
tame.
Define x =
For
setting xes
= xo
X"k
= Xk
do,k+1(J) :
T
4,
1
)mod*
L(M,A)t
€
X = Xeo O ...
as
,
o < s :
as
X
on
=
space,
with
J
+
"k*1
""
(O)
€ mod* R
(o), the
Define
otherlvise. mapPings
following
the
by
above
J
Xe"
and
K-vector
"o
x = T(x)
def ine
L(,U,4)
if
or
k-1,
= Xk*l
X"k*l
R-operatj-on
e Xen-1
was assumed
follows:
as
R
(xorXn,Xk+1,keo,k+leo)
for
R
because
id Xe"
(O S s < r
I "Jr---------äxer id
xe"
k-1 ) k9o
181
^ e
a
:
I
xeo
oJ;
,
oJp------JXe*
(1 s s 1k-1)
"J;:--)xeo kQo Xeo
@
X""
I
oJn--------)Xen k+1Qo
16'r 6 eo J es J
Xeo @ eo J
.t*f
Xek+1'
et+t+
"Jk*f------+Xeo if
the Note fR
J.k*.1
J "o
canonical that with
+
(o),
where
r
eo J es J
:
"= all
embedding,
either respect
oJk*1 to
=
QR ,
other
joining
zero.
maps being ,
olJ/rZ)k+1 o
(there and
is "t*l+oJ.k*.1
is
k+1,
only
one way in
namely
o + k+1 ) '
-
or
=
oJk*1
respect
.1
to
narnely
h,
at least
one
-2) = odk+1
o
=
oJk+1
"o
)
J t"
J tk*1'
J
J .k*1
r,s
€ {O,...,n-1}
fn
with
-
respect
O + k+1 ,
s).
the
R-operatlon
this
way a full
the assumption that
is
o eo J .1
Remarks:
x
is
exact that
fn
K-argebras.
basic
R
easy to see that
and that
Thus we get n > k+.1.
implies
paragraph
r
defines
in
R = A*(e,6).
we only
treated
course we can generalize or
and left
semi primary J(R)
that
realization
dimen_
the results
to
rings
coincide.
f(M,n) of
Artin
finite
is nilpotent).
hereditary
seen j-n the case of bimodules statenent
is
splits
orthogonal
this
true
,r*
that
one
forms a complete set of primj.tive
semi simple and
j-s an arbitrary
fact
the other
n = k*.1 r
rings,
remains no longer
r,
In al1 cases it
tame and
Artin
hereditary
( t h e r e a r e t \ , r o r . r a y si n
sorne
Therefore
is
R, /.f(n)
is
or
to
R
of
and
a contradiction
Of course this
1.)
one contaj.ning
r + s,
from the
embedding.
with
for
werr-d.efined,
hereditary
Let
,
In
J .k*1
one containing
follows
€or€1,...r€k
idempotents.
sional
on
{o,k,k+l } ,
do,k+1(J-) = 11,
eR,
This
are two ways in
and as additional
, s I
(A 1.4) and (A 1.7 ii).
using
right
j
{Orkrk+1}
to
(there
,
oJi*t
s € io....,n-.l
""
containi.ng
O
o(-/J2)k*1
137 -
is
Of course
always tarne, j.f
remark 4).
(i.e.
For such rings
an Eucli-di.an graph, (3,5.6
R
it (M,e)
as r.re have
gut the follorvln
holds: be an hereditariz
semi primary
and indecomposabre (as ring).
ring.
Then
Assume that R
is
of
finite
R
is
tvoe
138 -
-
and only
if
o f tane
fhere
2.t
then
rr7
K-realizations
of
,r21n1 = q.
B(R)/
again
,J(B(R))
=
(o) iMj +
finite
is
and all
Now define and joining .Mr + (o).
L
is
(lR,dR) -t i i-
.
l<--/L.)JL
reflects hereditary.
j
(if
R.
Then
j
over
by an arrow '
LJ
(rM.) j
-
t
many oriented
But of
course on
K
acts centrally
K,
(comp. (2.1.1 ) ). as vertices, j,
to
if
f rom
i
, dii
= dimF (iMi) -
-i
(Ki,i!4j). just
circles,
of
in
about
of this
R,
if
R
this
'
of course the form
and we cannot exPect that
behaviour
information
in general,
n),
!
{1,...,n}
(MR,QR) we take
the representation
sum of
Note that
sides.
(1 a i,j
QR taking
dlr. = din,
K.
subfield
i.s a direct
on both
because
,
i M i + ( o ) + - ' M ,)
To get
to be the
rp
sum of skew fields,
ä ,tl
= o
jMi
and
K-realization may contain
with
Lrj=1
dimensional
r.rith
Define
o.f
€heory R
define
the central
dimensional
finite
(fR,gR) i
graph-
assumed to be hereditary.
not
)
case. As
t
e Homo (itlirFi)
Homo (iMi'Fi) ^i-r-'j-,
an Euclidian
R
of
over
1e r z ( R { R ) ) =
does not imply R
because
cholce
K-algebras
is a direct
e Fn
\0\Ar
Fi-Fj-bimodules,
algebra
dimensional
J(ß ß))
Furthermore
a suitable
is
:
...
them finite
each of
iMj
II
R
If
the representation
K-algebra
be the basic
F -t
of
dimensional
finite
K-realization
I (R)
Let
to
For an arbitrary
following
of
an applica€ion
is
for
a rea]-lzati-on
is
:R
a Dynkin graph.
of
R e Arr(e,ö)
eithef,
or
also
a realization
is
:R
type,
ö and.
e,
if
is
rR
not
we have to consider
the
-
so-caIled is
separated
defined
There is if
there
we define
=
with
this
notation
= (O)
;2(n)
R
K-realization of
to Artin
MüIler
I 24).
Normal
of
finite
finite
a finite
disjoint
rings
R
(1 s i,j
and no
{f*s,gos)
and
as follows:
;v € {o,1} )
and
s n).
K-algebras
and only
R
\,rith
type can be
if
:i
is
a
Dynkin graphs.
A generalization
,f2 (n) = (O)
with
(j,O),
given
union of
see [ 10].
= u*rr(iMj)),
and
representatj_on
type if
(dii,dii)
, dii
defines
dimensi.onal
be again a valued of
x = (xi)
the skew fields € Qf , o :
how we can interpret x € L(M,o)
finite
the set of vertices.
(i,O)
is
This
of
this
was done bv IaI.
forrn problems
d)
consisting
of value
(o) , iMj +
the proof
theorem
(f,
the
is
of
For details
(j,1)
(i € { 1,...,r}
which are of
classified:
is
This
I*.
resp.
{O,1}
{M*s,ft*s)
if
.
iMi
R,
= Ut*"r,r"r)
(i, 1) .
and
= Fi
F(i,r)
(i,o)M(j,'l)
Let
(dij
Now the K-realization
n*".
Let
to
of
are no edges between (i, 1)
ones between
(i,O) (o)
iMj *
I;
:= f*x
fR
an arrow from
Note that
S 2
K-realization
as follows.
and only if
139 -
of
the
dimension
graph with F.
€ i)
isomorphlsrn classes type
x
(M,s?),
and bimodules (i
x. € z
K-realization
as orbits
(i,j € f). iMj , (2.3) we have seen
rn
of of
representations a certain
varretv
x
under a certain
algebraic
V* = lt : i.i.j
n
group
linear
H o m F .( " r * t -j
I
, Fjxj)
iMj
(i,j
cL(xi,Fi)
G:
f).
€
i€f
fixed
choosing
(j € f) ".,*j (x..d..,1*)-^.trices
as collection
of
L
are called
collections action
c,
of
classes
of
dimension
oriented
similar
of
IJ
and without
normal
possible
forms of
to oriented
graphs without
multiple
edges does not
seem to be
problem
of
the normal
leads to the following
K
all
€ f).
(i,j
F+
similarity
restriction
classical
over a field
matrices
over
for
"rr"n under the
J
circles
the
runs through
J
of vi.ew the
Just
x
the
finding
in
(x,.d.rrx;)-matrices !
are conjugate
words we look
point
desirabLe.
they
if
where
v'Iith other
where ttl
F., J
and we are interested
types.
over
J
such collections,
collections
From this
LJ
U*
we can interpret
bases of
form of
square
K-realization:
t\
K.J is
easy to reduce
But
it
and
multiple
lne
representations
K-realizations
with
oriented
edges to the usual- K-realizations: of
1"2 Fz
'
----------------
-
!'
n-1
o",,,/"1 M
can be identified
with
representations
(Xi,toi)
of
circles
-
t9t
-
M
1"2 F 1* F 2 -
'€Fn-r
n+1Mo
n+1
-_______+
ll F
\M
\F'
n"o
such that (in
particular
Also,'
, Xn+1 O
nen+1
F n
n+lMn
n+lMn
F
= Xn+l -------lXn
is
the
-n
F
identity
di.Frr(x.,*1 ) = dim",r(xn) ) .
the category
of
a1l
representations
of
the K-realization
" 4',) '1'2
F1 '
is
precisely
the
F
category m
of all
e-
Fr -1
L - t
(we already used this, As fj.rst given by
trivial
representations
of
l+\
'2 I
for
-2 example in
(3.5.5) ).
exarnple 1et us consider
the K-realization
(^/,A)
K
K.-b.K.
Then
modules of dimension type
t(iq,A) (1,O) ,
has three (O,1)
and
indecomposable (f,1).
Given a
142 -
-
representation
p : X1 + X2
e1 o ,pz o p3 ,
where
to a direct
corresponds
+O
92rX1
vre can decompose rp into ' - xr' is an isomorphism, 91 : x, sum of
copies
of
id
isadirectsumofcopiesof
and
: K + K, O:K+O'
and
O : O + K.
This
tt
e3 : O + X,
is
sum of
(nrm)-matrix
means every of
a direct
g
rhe form:
there
For the
following
are matrices
we need still
over Droduct
and
A
is
the
zero matrix,
So we can express over
K
is
product of
a)
of
we call
statement
1 x 1-matrices
(1).
KOK K.(-.K
,
indecomposable
Preprojectj-ves: the dirnension sentations
we shall
A
and
B by
understand
the product
a zero-augmentation.
above by saying
(type
every
n x m-matrix direct
to a zero-augmented
AC ).
The possible
dimension
modules are
( k + 1, k )
types
If
the matrix
B
(by two matrices)
similar
Next consider types
the
F,
AtpB = M.
such that
"l Bj
IA
B
A,B
some notation.
some skew field of
to a matrix
similar \
matrices
I lo If
is
/ r..
are two invertible
the direct
K
over
l\o 'll \ \ o'.. 1 \o/ \
M=l
that
of
copies
of
o!k€Ei
the projective
( ' l, o )
,
(2,1)
indecomposable
are
repre-
-
b)
143 -
Preinjectives:
(k,k+1) , O : k € z;
dimenslon
of
types
(k,k)
Homogeneous:
We can interpret
the
injective
(O,l )
( ' l, Z l
lndecomposable
are the
modules
1 < k e Z,
the classification
as normal form problem of
of
the representatlon
(41,A2)
pairs
of
above
1lcx6)matrices
over
l l t l
K,
(41 ,A2 )
where
and. only P
and
if
there over
e
we identify sentations
is
are K
calIed
two invertible
suchthat
K.-.K)
of
indecomposable
to pairs
(k+'l,k)-matrices
pair
is
similar
of
to the pair
is
with
if
size) (where
the repre-
easy to see by induction
over
size satisfies
correspond
and each such indecomoosable (k i O).
(') = nn
.t
t'-'.t,
matrices of correct
(L=1,2),
representations
\ " ":?/
(It
(of correct
K. K.+l-.K
P1,PZ ,
ll ."\
nntt'=
(A1 ,A2 )
to
.
So the preprojective Al,A2
matrices
Ar'p=eAi,
the representat.ions of
to be simllar
(':
r
\1
that a pair (i) (i)o, = ^p k, Pp ' k, k
(P,Q) i
of
= 1,2 ,
and only j.f P ano Q are scalar matrices; therefore the 5rair /'r\ tt\ (P,. is indecomposable and all indecomposable gairs ,t*'-')
if
(A1,Az)
of the same size are similar
(3.2.1O)). Dually to this
every pair
to
,
is
simirar
matrix of
e*(i)
,-o(t',rot'', (i
= 1,2)
where
to
,nott',en(2) )
(A1,A2) trtt'
(The preinjective
of
by
(k,k+1)-matrices
is the transgosed gairs).
-
remains to describe
So lt and to
translate
it
into
to
equivalent
where
(1,1),
in
fact
') n : K O K' is
by (f.4.3).
q
= K O K + O O K = K
indecomposable
with
= (K,K,n) € L(Kt),
!
the corresponding
(k :
R. = K[t],
category
matrlx
elements
is
pair U
in
is
^ \ '.'1 o I
t..l
I |o/
g(x2) over K),
ring
length
objects
of
arbitrary
Now g
is
of dimension
where projection,
the natural just
( (O), (1) ).
that
So the
k x k-matrix
to
correspond
pairs
/ 1. . I t\t
X
'
\ol
be a simple
Then
R-module.
polynomial.
the following
x=(X"rX*,q),where is
d.efined
be
the
by
degree
-/!\ = R '/t, p (E,) \
of
p(t),
and
so
to
in
,
where
/
given
€ R,
P(t)
(3.4.3)
in
L(x2):
e:\gx2=XKOXK+XK = X r Q(o,x)
e(x,O)
/
R//-/+\\ X =
Using the functor
representation
,-"k/
'1
\
an irreducible
we get
v^ \ \
t\t
\P\L'
x
K2
Of course
(the polynornial
/o.1.
is
L(K21,
1).
l \ \ v l
Let
of
(K2 = t"t(1,O)). So
K-K-bimodule
mod* R* U,
one simple object
with
language of matrices.
the
a uniserial
is
U
t h e h o m o g e n e o u sp a r t
H(K2),
is a non-simple Euclidian is
-
t{9
then -x
= 1'g
1,t, -..,tk-1
corresponds
the
for
x € forms
X* a
Let
.
K-basis pair
following
k
of
k x k-matrices:
un= "111,=
('::,)
..(2) p(E,
/olt i : ' o- ,
\
\
o
-a^ -?; \
\
-ux-zl 9' - t t - t /
-
= -(ao + alt
p(t)
whele
To a m-ford
+...*
indecornposable
mkxmk-matrix
pair,
(1)
145 -
where
uk_1tk-])*tk
extension Ek
of
.
x
denotes
corresponds
the
(k,k)_matrix:
the unit
I
",1'J1.,=E,k={o...o ) ""1'31.,={;l:l--" tr ) -"o-\
of
course,
in
ej
= id
* .J
.
matrices
over
with of
we get
the
that
So we also K-
u(*2)
Jordan
Theorem:
get
the
form of
the
they
following
of
1)
if
algebraically
dimension
of matrices
2)
Of course,
for
the
as ring,
if
X
irreducible in
fact
is
is
square
closed
(Kronecker
is
similar
K = €):
for
to a uniquely
of pairs of (1t (?l t (Ul.',rur.-,) and
€N
€ KIt]
r P(t)
corresponds
the
form
irreducible).
to direct
summands
( o , . l) .
resp. a simple
polynomial it
is
form of
product
The zero augimentation type
K
theorem
(k,m,l,r
( 1,O)
representations
rational
zero augmented dlrect ( 1 ) ( 2 (1) , (2), ')), /t D rk , tok , r( r m rta ) r
Remark:
the
canonical
determined
,
xJ.x
just
are
contained
square matrices.
Each pair
1 () a ) , t . ,. (p2( )t ) ) tf tHt (. p
/ "J?1,
which are not
(xK,xK,e)
is
rn particular,
So we have proved
A 2.1
of
the representations : X* + X* r
o-
\
the representations
are just
u
/
p(t),
an extension
R = K[t],
R-module, then fleld
x K'
R/(p(t) X =
can be considered of
K.
So
Kr
is
)
-146-
the endomorphisn corresponding
field
to
of
X; or
arr matrices (p,e) (L = 1,2) ticular,
K = lRr
(8,
and
if
then
g
corresponds
H
(i.e.
""Jil,= "lil,O the
of
simple
H = (1,1)
din
if
of
ring
polynomial),
to a linear
the corresponding
polynomial
quadratic).
is
C,Il
denote
this
the
field
we want to describe type
Ä.',,
Note that
!a
on is
is
namely
two copies
of
acts
of
A,
on
is
ACE
M,
algebra,
a simple
of
lR-realizations
aII
lrh
are
so there
CCC
and
%
lR
is
the center
on which A
which
IR
a product
is
and
where the right
Ä.,,,
lR
Of course
of
on which
G-binodules,
CCd ,
of
acts
t'$to simple
type
lH-----J
K,
F E* Gop-nodule.
as a left
A
given by conjugation.
of
are skew fields, subfield
because
Furthermore,
.
T{ ]IflR
H
F,G
ll-birnodule,
one simple
lR-realizations
rR----)
where
can be considered
dtl 1. )
FMG,
(comp. (3.5.3 remark)).
L(CCEO nA6)
different
Let'
field.
numbers respectively.
some conmon central
namelY
centrally,
O
of
the representations
only
centrally,
R
quaternion
complex'
F-G-bimodule
UoP
so there
the real
;.a
centrally
Novr, n Il,
an
of
dimensiona.L over
finite acts
and
K =IRr
paragraph let
of
For the rest
*
lR
is
X,
End U = K. In par-
Of course
the endomorphism rlng
H = (2,2)
din
pairs;the
to matrix
K'.
E = U, or
either
homogeneous representation
(of correct size) suchthar
homogeneous representations (i.e.
simple
translated
isomorphic to
is if
the
action
L(CCC O CCC) o
So, there are only six and
Ä,,,
:
- 147 rFr o FFr
2.)
F ----_JF
3. )
cac o cacc -----------)c
Problem
2)
F = ü. glven
has been treated
Of course, in
F = tR,
with
the preprojectlve
homogeneous representatl.ons case.
It
renains
the polynomj.al
sequently,
each right
of the form finite R. /p
dlmenslonal
P
just
of
R.
leading
coefficlent
q(t)
of
ideal
€ R.
there
Let
O I k I n-1
b € II
if
deg q(t) is
R.
if
is
1,
z n
of
p(t)
p(t)
€ Rttl
generated. is
ideal
R =It[t], It
R.
Con-
i.e. and
for
f
is
*/,
is
every primitive
of
R
corresponds
narnely just
the
1 = p(x).R
Let
vre can assume that
d.egg(t)
Let
the
O + q(t)
be the degree e f.
Assune
which is not contained a* ( lR.
I ) bp(t)
Then there
- p(r)b
= center of
Of course,
irreducible
the
rn particilar,
H.
p
of
t.
in
€ R,
ring
for all
p(t)
But
U
so assume that
t + ao.
deg q(t)
so
p(t)
are
the comnutatl,ve
is princlpal,
as annihilator.
Of.course
a*b + ba* .
centrally
and only
p
as in
R-modules,
be maximal such that
< n.
factor
space over
simple
+...*.1
Is a coeffi-clent
such that
R
of
parts
algorithrn
hence simple
p(t)
of
Then
that
and
of
= tn + arr-, tn-l
P(t)
vector
R-modules, which have
be a two-slded
R
So, to each prlmitive
one isomorphism class
simple
of
So let
indeterminate
some polynomial
Artinlan,
C.
R-modules with
a central
l
as right
1s a prl-mitive
ideal
of
for
the direct
un.Euclidian
ideaL
p(t).R
Also
is
T there j*
and
and preinjective
the simple
over
1s easy to see that
II
can be determined
to determine
ring
or
F = lR
above for
same tday as above.
the
C
R
1 = p(t)R
as real
in
lR.
exists
=: q(t)
+ (O)
and each ideal is primitive
polynomial.
So there
148 -
-
are
two
classes
p(t)
1. )
-
= t
ideal
of
primi_tive
ä,
a €lR. Here p(t)
S- = R/ u /I
and
The R-operation End-(S Ra
Then
R/ ,I
over
C,
is
and S. -
the
of
ring
to by
m.axirilal as right as
I!, ll
h.t
ig
1$-ulR
R-module
End_ (S ) t{a
= ha
}l-vector for
space.
h € Il,
and
primitive
all
with
the
to
-
the
uf,to
2x2-matrix
isomorphism
corresponding
to
ring uniquely
p(t)R.
= C.
the
ideals (not
R decomooses
now Il
isomorphic
= ^t
simple
As a consequence,
I{e identify
also
R.
f o r s o m ea € C - l R .
a simple
Furthermore
element
given
of
= II.
)
determined
each
.R is
l s o m o r p'h i c
on S^ is
rl p(t) = tt-al tt-äl
2.1
of
is
p(t).p.
ideals
ring
in
R are
uniquely)
of
naxinal
into
linear
2x2-matrices
aII
and factors.
over
C
form
a
b\
\-b
;l
i I
with a,b€C
I
So 1et h
"
=i
a'+b 'i,
/ a+ui,
c+di l
i \-c+di,
a-by t,
I
\-c
r ^ r i t ha r b r c r d r a ' , b ' r c ' , d '
c'+d'il i-
/
'+d' i,
€ lR,
(i2
hr
,
(h,h' € rt)
a'-b'i/ =
-
,?\
Consi-der -c-di ("-ar, c-di, \
h + E, hF e n, so "/(t_h)R i.e.
if
i.e.
a+bt
'l nen
)
(t-rr) (r-h') € R trl.
= ^/(r_h,)*
and only if
)
if
a = a'
and only if
(t-h) (r-f)=(t-h')(t-fr''),
u , - , 65 2 + . 2 + d 2 = b ' 2 * " ' 2 * 6 ' 2 ,
't49 -
-
and then *r,a-nrR
= s* with
With other
if
words,
x=
x €C:lR
there
are
infi.nj-te
ma$/ h € It
R/(t_h)R s* =
such that
Translating
this
to matrix
pairs
A 2.2 Theorem: For each pair there
a+(b2+c2+a2)ieC.
exist
p B e-1)
(pA e-1,
of matrices
of
the
(A,B) over II
p and an invertible
(n,n)-matrix
e such that
product
direct
(n,m) matrices
of
an invertible
(m,m)-matrix
we get
is
a zero ausmented
form
(. ^pk. ( 1 )' ^. p . -r Ä 1 ) , n. (t a2 ) r l , k . ( 2 ,),t . \rr rm( 1 ) .r r. (m2 ) r ., , rr ur rl ! 1 )' 1r 1r ( 2 ) ,1 a r u /t npS( a uniquely
determinded
up to the order,
a = q+iß € O, (i2=-t,o,ßgR), li
and Ui*'
\
(i=1,2)
ß > o , , " t r e r ee { i ) , , (A 2.1),
are defined as in
€ N,
(il and
''.\ o
l 8l \
I
'Jl' =", =f "r.. lo
I
()\
I Io
,)
\
In particular,
1)
k,n,l,r
t
I1
Remarks:
with
\
for
square matrices
over II,
Normalform,
where all
,'glgsnvalues"
are complex numbers !,rith non-negative
imaginary
part,
there
exists
(taking 2)
A = E in the theorem above).
Of course it
to arbj-trary In particular, for
a Jordansche
is
easy to generalize
skew fields, there
square matrices
exists
finite
the statements
dimensional
a canonical
over its
rational
over such skew fields.
above center.
norrnal forrn
-
Next we will
M =
so let
3.)
CGC
O
CA6
t (M). As above we know the PreProjective
consider
preinjective
a uniserial
we can determine over
category
and R = O[t,-],
also)
t vtith
C in one variable
and
object
one simple
with
and
fl(l't) = U x mod*R,
By (3.4.3)
representations.
where U is
ring
problem
treat
150 -
U (which
the skew polynomial to complex conjugation,
resPect
n3
R = { E cutJlcu€O , n€N} with componentltise addition 'r J j=o i.nduced by the rule tc = Et for c € O. Again and multiplication
that
is
each right
that
Let I = p(t).R
be a two sided ideal
of R," ) = r1(t-)+rr(t-)'t D(t)
= tn+cn...tn-1*...to'ltrite
p(t)
(picking
the odd and the
deg q(t)
> deg p(t)
such that
cn (R.
even Posters of all
for
a polynomial rf
n is
degree
€ I has degree k < n,
Let
I
of degr..
= rr 1t2;+irr(t2).t,p(t)i=r1
than n in
smaller
all
prinitive
ideal
= t2-a,
ft)2-ft2(t2)t,
is
i
hence zero.
a polynomial of
is
hence zero-
I,
over
right C so
the annihilator
ideals
as polynomial
of
ideal R,z,
is
only
Thus either
even or
o + a€lR or p(t)
*iah
Artinian
= t or p(t)
a maximal is
€Rlt2l
Therefore
= (t2-a)(t2-ä)
ring,
r.rords,
other
Let p = p(t)R
of R [t2].
it
R. Then "/,
a simple */-.
of
are maximal.
of R. By the above p(t)
irreducible p(t)
- p(t)i
I,
eBtt2i=
t have non zero coefficients.
< R be a maximal
where P denotes
n in
than
"^"tf.t = ip(t)
even 2irr(t2)
dimensional
finite
consequentlY r., (t2),r2(t2)
n is odd, then 2rn (t2)=ip(t)+p(t)
odd poqters of
only
Let O < k < n-1 be maximal
- p(t)'t
center of R. consider ip(t) (i2=-1 ) . rf
Of course
t).
€I.
o < k < n-l.
arl
'
o + g(t)
Then tp(t)
hence c* € lR for
principal-
R is
I of
ideal
hre see easily,
ej-ther 9(t)
for
= t,
somea€c\lR'
or
-
t2 - a€R.
Let a € G and conslder tz-a
= (t-b) (t-c)
for
U+E = o and bc = -a. of
this
equations
same b,c
we see that
p(t)
= t.
and So = "/p
2.1
is
End* (So) = O.
p(t)
= t--a,
right
ideal
)
O < a €R.
tS")
p(t)
= t2-a,
o > a € R. Then (t2-a)
ideal
and
*rn
= (t2-a) (r2-ä),
a maximal'right simple
=
the -
R/o module.
overJR, and
by the
"/p
the
complex
R is
also rnaximal-
R/"-rnodule
The sinple ". Il.
a € 0\lR.
ideal
"P /Dn - m o d u l e .
So we can paranetrlze R-modules
- simple
determined
is
= n.
ena*
p(t)
over O
\,iä).Ris amaxi.mal
R/f and S. =
ring
ideal
dimensional
Then I = (t -
(2,2)-matrix
Sa has endomorphisrn ring 4.)
also maximal as right
R-module,.one
uniquely
'/o = Y!(2,F.), the
as right
is
over p = (t2-a)RcR,
D
part
cases:
a simple
with
and imaginary
O < a € n.
four
up to lsomorphisn
3.)
the real
Then P = p(t).R D
Assume
€ 0. Thi.s forces
Separating
Sd we have to distinguish 1.)
-
Ilt
Then r=(r2-a)R is
over p = p(t)R
R7, and S. = i"
. M(2,C) and End* (S") = C.
isomorphlsm
classes
of
the
simple
numbers a € iD, whose imaginary
j.s non-negative. Again with
(3.4.3)
we can describe
t-lul
(M =
ncn o na6)
Of course
this
can be interpreted
normal form problern of
(n,m)-matrj.x
now fl(M) and therefore
as solution palrs
of
the
(A,B) over {D
part
th"
- 152-
!,/ith
the
definition
followinq
and (A',
Br)
if
similar, (of
comnlex matrices
of
there
correct
But the
(A.B)
Call (P,Q) of
a pair
is
invertible
such that
size)
PAQ-I = Ai and pEO-1 = E', conjugated
sirnilarity:
d e n o t e s t h e complex
where E,E'
to B,Br resoectively.
matrix
interpretation
matrix
following
seems to b e m o r e
interesting. Note that There
CAC
is
all
= COE Ch
a natural
Hon6 (vn 6 for
O
vector
Now L(l,l) is
0-C-bimodule.
"t
Homn (r*Gnrw6) ) " Honn (vAoAh%.CA,
spaces VC, WC over
the categary
of
where g,
tp' : Vn O
if
are automorphisms
there
Ro'
isomorphism.
C*,
A
O
Ah.
O
(VC, .ryC,o) ,
- WC äre called
nAC
,
O .
triples
all
I{A)
equivalent
q of Vn and p of WC
such that
wc
vcoc%encc
I
I s8 1 0I1
lp I
J
vcoch
isomorphism
;"äT" notation Two
of
similarity
lR-Iinear
are calLed
q:VC'VCandP:Wn
(pt
if
wc
onoc
above this in
is
Horn* (Vn I
transformations
similar
.t
there -
exist
ü,ü'.
equivalent Co*, vc o
regular
WC suchthat
to
the
following
Homn(a0n' I{n)) C%
{
C-linear
:
HomC (ncc, wc) transformations
- 153 -
vcoah
"otn,(11cc,
I
I
I
I
I n"'' I
J
(ncc'P) Homc
J
ut
vc e ch.
wc)
Honn (*0n, wn)
conunutes. Identifylns lrith
the
vC o
resbdctLons
the
following
CalI
a real
of
normal
2)-blocks
has the
if
exlst
there
((2n,
2nl
and
real
nurnbers we get
forrnally
1 < I
cornplex if
< n) of
its
every
partition
into
form
tkt'
^*,
\-on. (2n,
(naturally)
on'\
( "*'
Ttro real
the
!{C)
problem:
form
(1 < k < h,
h0a,
Vn, WC to
(2m, 2n)-matrix
(k,l)-block (2,
and Homn
Cf*
2rn)-matrices formatly
bkl
€ R
)
A,Ar
complex
( 2 m , 2 m )) r n a t r i c e s
are
said
regular p,e
to be O-similar square
matrices
such that
PAQ-1 = g' With
other
words we consider
transforrnations
normal
forms
betereen complex vector
of
real
spaces \,ri.th respect
to complex similarity. By the
above it
i.nto matrix
remains
terms.
to
translate
the
results
for
t (M)
154 -
-
by (:.3.1)
Flrst, only
an (2n, 2m) matrix
n = m+l (preprojective
if
matrix),-
- or if
n = m+1, and dually
So, if
matrix)
one indeconposable
(2n,
if
or m = n+1 (preinjective just
is up to sinilarity
in these cases there
indecomposable matrix
can be indecomposable
one
m - n (honogeneous matrix).
m = n*11 we have to find
just
2m)-matrix.
Let
Eo=
(Ä:)
c,ß €R, and consider the
for
?)
"-=(S
(2(m+1), m)-matrix
IE
'
p-
=
\
'-.'.
i
P*
with
space
In that
order there
to
transformation
a
(n+1)-dimensional { v . ' | , v . ,i , v , v r i ,
. . rw6*1 , w,o.,1i} (i2
{w1,.
prove is
I
an lR-linear
V into
{ w . ,r w 1 i , w r t w r i , . .rv*},
I
I
.--
to lR-bases
respect
{v1,.
II
I\ o ".". '.''o
|
describes
C-vector
\
..
\\ ' " o l
Then
\
^u
'.'.
|
(over lR)
\
I rE ' , . ' . /
andEsB=(ä-l)
.rw6*1}
are
no non-trj-vial
c-vector '..,v*,v.i}
= -
of
an m-dimensional sPace W, and
1) , where
C-bases of
indecomposability
g of
P*,
decomposltion
v and w,
we have
respectively'
to
show
VC = Vö e Vö
,
- 155-
WC = Wö O Wf such that
tp decomposes into
gt.
W".
-
Vt
This
is
gt'
Wt,
Vtt +
:
trivial
for
m = 1r for
without
R-linear
loss
maps
of generality
V'
= V,
hence tp" = O, Wn =,OT'!VI O W"C = rp(-V)-O Wf,, where denotes
aWI
subspace of
'l For m > let
generated
,
the
least
C-vecror
indecomposable.
V be the O-subspace (ü = (O), if
m = 2),
of V generated
by
and fr be the O subspace of W
fhen 6 = el?
by w2,...,r^/m.
(by induction,
i.e.
tp(V) . But 6-[VJ- = WC, hence
W contalning
Wö = tOl and g is
u2,...,vm-.'
of p(v),
the O-closure
: V - fr is
indecomposable
m > 2 , a n d b y + _ h eO - d i r i r e n s i o n s , 1 f r n = 2 ) .
if
Now e(V) = e(V')+e(V"),e(V')5W',9(V',)etv" i.mpli-es O(V)= (p(v) n W') O [a(V) n W,']. Nore that lalgest
p(V).
C-subspace of
Let o = o1 + u,
ut € 9(V) nW', 12 €to(V)nW". Then ui and ui
= *1 * x'
with
€p(v) nwr,
t
fr is
rhe € fi c
A(V)
,
= u,,i + uri €ff , x2 €a(v) flwr'
Now'
W = Wr O lrl" and W', W" are O-subspaces of w, hence = x1 , uri
rli
= x, and u.,i,
Thls irnplies fr c the other that
(ffnw')
inclusion
is rl is
injectlve.
(finW"),
e
being
trivial.
in
fact
,p-1 tfi)
is
g-1
(ff) c v,.
p,
Ofcourse
(Vnv"). i.e.
the whole of v,
O (fifl!{,'),
has full e
By induction
rank,
(o-1 (fi)n v.), we nnay
fr c W'. Again by i-njectivity
Now e(v1),
e ff,
a(v*i)
the JR-subspace of V generated
{v,,vrr92ir...,vm-1rv*-1i,v*} ,p-1rfi1 is
o
(say) fr = finW',
of e we see that
so fi = (ffnw')
S o t p - l t f i l = ( , p - 1( f i ) n V ' )
and, as above, ? = tVnV') assume that
u r i € r p ( V ), h e n c e u 1 , u 2 € f r .
by
, so the G-closure q=lfil so y = e-1fi1
w = e T V fS W ' , i . e . v = v ' , w = w ' .
.
v,
,
of
- 156 -
t
Let
I.
= Pfr
I^
is
indecomposable.
(the
transposed
Next vre want to describe H (M), M = that
O
nOC
the elements
generate using simple 1.)
C%.
we get
=
It
C O C - OC C 6 = 1 @ 1 - i
U = (O,O,p) , tp : lI I M -
Corresponding we get
the
9.
a)
t S" O
+ S.
q
c € O
given by =-
(c €c)
R-module S",
given
ä = q+9i €0,ß
> O
homogeneous representations:
by the
mapping
following:
over
C with
basis
xu say:
(x" E e., ) = x.
Q" (x" 6 er) = {ut
b)
= Eer,
of M: C
irreducible
is
O i
the non-isornorphic
H(M), where the O-linear
nM
e.
.2..
of
O < a €JR : S. is one dirnensional Then
= 1 O 1 + i
e,
list
to the simple
(sa,sa,ea) €
in
easy to verify,
particular
e(c6er)
following
. Then an above
representations is
O ir
the following
=o,
P*)
irreducibel
homogeneous ieDresentations
p(c6e1)
2.')
the
"1 the direct summends, in
(3.4.3)
of
matrix
B >O:
Sais
= x"'a
tttodimenslonalover0,
c =. R=, / -) 1 ' )a 2 _ . ) * u t d S
X" = 1+(t--a) R
form a
S".
C-basis
of
Then
oa(XaOej)
=xa
ea(xaEe2)
=ya
ea(yaOe1)
=yu
aa(Ya I
e2) = xa'a
Y"
infact
t+(t--a)R
-
Next we will our
calculate
normal
-
/
the corresponding
real
matrices
for
problem.
form
Let VC, WC be {wr r...,wrr}
lf
C-vector
spaces with
respectively.
Honrn(vn o M, wC)
-
bases {v.,, .. . rvm} ,
Then the isomorphism
Horn' (vC o af',
Hornn(O0n,w.)) I Hon6 (Vo,
\)
i s g l v e n b y g - ö t . pe H o r n n ( v no M , w c ) , w h e r e t h e l R - I i n e a r m a p is defined by ö : v* - 5
ü trrl
=e (v 6 1 e 1)
t9 (vi)
=tp (v O i
So,
the
VC
resDective
matrix
of
O 1)
ö with
resDect
{ w . , r w . ,j ' , . . . , w n , r t n i }
= e(vj I 1 o 1) = ] ö ( v r i l = e ( v , o i o ' lI = j öt"rt
Using
thls
lre get
the
a = c+B i
€ CrB > O,
O-base
Sa is
a)
of
O < a €lR
to
real
choosen
as
of
Mu r correspondinq as
C-sDaces
to
(p.,
and
the
above):
( a = o):
"\ t -
\o < O or
by
JI.J1
vC = wC = S"
( ""=+ s
be calculated
t , o ( v ,o e . , ) - r o ( v , 6 e r ) ) . i
l*"
b)
}ln can
tv., ,v.,i.....o*,.r*i)
t o l , r . ,e e r ) + o ( v . , & e " ) )
matrices
(where
the lR-bases
"/
l
ß > O :
/.
1ln
I'
I'r--l
az1
\o
t
o
q
1
ß-o
1
I
O,
?
o
1/
ß\
I
/Er I
E\
oul
E1
I
of
158 -
g
To
c)
corresponds
o\ -,)
lt \" that
Notlce
from the all
of a)
left
and the
) := "Jt For
€ r ß : o,
€
by
)
(Note that
't
rf
Q : vc + wc
VC
and
respect
is
a
tp
to
mean b7 irreducible series
etc.
Using
(3.3.1)
uniserial and it.s
(Vö,wü)
pair
are
(9(vö) I !'fö
a subtransformation
of
.
I
matrices
two
map betlteen
Vö , wö
if
and if
respectively,
u € H(M)).
to
lR-linear
\.re say the
WC,
or
/
corresponds
"il
B > o
where either
u"u)
("''
_
\"-l
'.c
given
o:
d,<
and
H(2) a
grrr
ls
square matrices
(Normalize r4u by 1fur
-d,
a=ct
ß=O
with
So a llst
frorn the right).
matrix
irreducl.ble
matrices
scalar
c € JR, lol
For
b)
identj-t:'
non-isomorphic
(applylng
matlices
hre can normalize
is
c-vector
a subspace of
C-subspaces In
(This
thls
clear
factors,
(VC'WC)
VC , Wc
case lve also
makes it
and composition
of
spaces
call
what we comPosition
). we know that
uniquely length.
For
an indecomposable
determined
up to similarity
1 : m € 7'
define
square matrix by its
is
simple
socle
-
f ,ttl;
. .( 1 )
/ "a l.'\ t.t
ma
tol
n=
159 -
-o
the
= E_
and'E
t{e will
diagonal
and
l- = I
for
show that
ais
of
factors
slmllar
into
to
f-) r".
are all
"t1) can decompose only
L=2.
.
sirnllar
unj-serial uslng
to
matrices
inductlon
/i
positlon out
I
H;;'
the
an indecomposable
(n-1 )
length uniquely
:
"[i]',"
contains
sirnitar
determlned
with
over
m
(il
)= za
"="jt),a=gi-I C-vector Then
space
VC
ls
an irreduclble
is
decomposable.
WC , i{ö this
on which
VC=VöOvö,
ment with
(2'2r,
if
lY
\o
to
A,
Vö O O
means that i
ln
there = 1,
x\
")
lu
E\
Hl
VC
exist
\"
of
lR-llnear
A.
is
of
com-
factoring of
transformation. ."nd
there
exist
(4,4),
X if
E\
la
v\
")
\"
")
A
has a cornple-
two complements
A}IA =c vIö
C-matrices
vöOO
Nohr, assume that
(Vö O O , Vö e O)
such that
and size
lu
as
A(x,y)=(Hx+y,Hy)
that
rre can assume
anaconsiderthenarural
I acts
pair
composition
m = 2.
subtransfornatlon Then the
and,
subtransformatj_on
t" \o .\
where
respect of
maxlmal
So
subtransformation
" [*]., ,.
we can assumethar
"Jä)
vtrite
ro
.
"jt)
"jt' that
(L = 1,2) ,
as above
are j-ndecomposable. of course the
"j:' 1r\ H;;'
ri \ H'-'occurs a
where
'
defined
=(:
, E
all.
composition factors
/
a/
\
in
I
.H(i)
\
m times
\
'F
.
|
\
o
and L = 2,
In matrix
y ,
of
terms
sj.ze
such that
= ln lo
o\
"/
,
160 -
-
(r[-rnatrix For
= 1,
i
implies
this
that
01 + o3 =O,
which
is
equations
o1,...'cr4
* u2,
O=cna
in
leads
the
entries
to a non-homogeneous linear of
X
some
to be unsolvable.
there
exists
(3.4.3)
(2n,2m)) matrices il
For every
(non-zero)
(A,B)
a pair
the
(A of is
following
"j:' and (3.3.1) the
to one of
real
(2m,2m)matrix
"j:)
size
(2 (p+t ) ,2p) -matrices
(2n,2n) ' B of
a zero-augmented
(P = t t2,..-)
l Eu-o . " - .
\
o
\
\o'nl
"": I
\o
(p = t,2,---)
(2p,2(p+1))-matrices
/\ I E-Eo
\
le'nl l.i l.'t lr \n.tl \FFI \
\/
a.l "a-o/
D
complex matrices
tyPes:
{l . r l
ii)
So
similar
fornally
of
A D B
such that of
i-n 16
So we can state:
both invertible,
B'
and
is
square matrix
m e E' .
1 t
Theorem:
A
= -1,
system of
( 1 5 equations
Y
and
can be proved
which
indecomposable
A 2.3
such
€ lR
o1a+o3a
indecomposable in every case and again by
every for
crra *o4
this
indeterminants), is
there are
that
Ex + HY = -E.
Consequently
impossible.
! = 2,
For
complex).
means fornally
size
Product
of
-
151 -
square (2P,2P)-matrices
1il )
lr
o
t.l l..l tDl
\
\
o
l"a"-
I.'\ t.'\
(p = t ,2,...)
lat < 1 a €lR
with
\
'."'/
o \ \. e i
ot/
and
(4p,4p)-matrices
square
iv)
and E.
(p=t,2,...)
0
I
O
O
O O O E r. E ^ O 0E E_, E. O
E
O
ctb
E_1Et o o o o
with
I
either
or
ß>O
ß=O
o,߀lR
E O
o
L4 'E
E
I
-t
o o
. ClE
F
U
L
A
A
I
o o
E r. E ^ üb E.E" I
These matrices and,
ln
order)
following:
iii):
of
D,
with
respect
they
are determlned
to
c-sirnirarity (up to their
unlquely.
matrices
il)
lndecomposable
the decomposition
Furthermore,
i)
are
the rlng
which
fix
the
Z
of
all
pairs
indecomposable
of
regular
matrices
is
ztnjl)l
= c
formally given
complex
by the
For case z=C for
0 = 1 ,
0=Ora=g
otherwise
z (Hjl ) ) .o rR. For indecomposable matrices "J:'
of composition tensth
-162-
pairs ls isomorphlc to m the rlng of centralizing *ttl,a^, R =lR resPectivelY c' , with iv) :
respectively
C.
Consj-dering
the
bimodule
of
(2rn,2n) complex matrices
forms
as above normal
Now it
to H-sj.mi1arity. so this Every
is
(non-zero)
(2m+2,2m)
matrices
of
see that
the
of
ls
respect
with
8C I{'
rF
pairs
Kronecker
(2rn,2n)-matrix
complex
hte can determine
SC tff
rfl
to
easy the
can be done using
augmented product i)
. otherwj.se *[t]/.o., rntith R =rI As above z(Hj3)) =
= c.
zß:2))
Remark:
z = z jH!z)) =H
a = g < o:
for
@ 2'2)'
-
O
fh
So we get: to a zero
ll-slmilar tyPes:
following
matrices
-o t.
--,| F
"1 F
transPosed
the
iii)
(2m,2n)-matrices,
ln^ I l-llFl \ \
\ where
""
of
matrices
ii)
'...
o =(tr'
((2rn,2n+2)-matrices)
c = a + bi
etith
E 1' . o
i)
\
l"
\
.Er '. | l '""/ /
I
".
and
"
"
o
\ ,?.)
Er. "
\ \ =ß
a : O
with
€ C,
\
\
Ej I I
"l
?)
These m a t r i c e s a r e t r l - i n d e c o m p o s a b l e a n d , i n t h e d e c o m p o s i t i o n ofa
complex
(2m,2n)-matri-x,
they
are determined
#h
(up to
their
-
order)
It
uniquely.
remaj-ns to examine
uslng
163 -
partial
Coxeter
these bimodules. treat
that
is
M =
is
ue restrict
ourselves
is
we consider
only
to
with
no direct
lR-subspace of (u',V') : V + V'
f
rte get a classlficati.on (Dually
spaces.
subspaces of (U,V)
natural
nunbers
Set
(this
M
is
lH-vector
real
the first
of real
be the pair fact
an
vector
of ar1 quaternion spaces.)
For
(
91 = (4t1r,
vector
of
of
the
c
9r2= (1,O).
i.ndecomposable representation p2 = (2m-1,m) "-m indecomposable pairs in or
j_n the second case by ü
for
Then
denotes the corresponding
C-m p1 = (4m-4,2m-l)
is
is
In other words
vector
the dimension
(where
A(2m-1),
the endomorphism ring
and two
t* (:{) ) .
in
p2 = (111),
= U'.
a crassi.fication
Denote the corresponding
case by
V,
subspaces of guaternion
element) : Every preprojective
( 1 g n e Z, ) .
space
f(U)
representation
has dimension type
(U,V),
palrs
such that
gives
imply
we can
i-somorphic i-f there
arr
in
summand iso-
are calred
dim(u,V)
and (3.4.1)
ooxeter
that
let
P1 = (O,1),
(1.2.8)
of
t*Srh)
the
the quaternionification
a palr
corresponding
of
Deterr,line all
.
(that
A
simple representatlon),
is
t-j.somorphism
(of courseottl-n.]rh)
representations
where
(u,v)
we rvill ({h,E',e),
triples
monomorphic
our problem as follows:
such pairs
one of
L(M)
with
formulate
an
R-linear
of
triples
morphic to the unique injective
U
Instead
.
n*h
the category of all
ff
Of course,
, nILr
#h
i.t 1s enough to treat
rh-\r%Ih=h
e:
!1 =
for
functors,
So let
1t(It),
where
t(M)
A ( 2m-.1)
and
B(n). tR
for
Note B (m) .
-164'
we have two series
Similar
denoted by
lR
(4m,2rn-1) = cm(gt) find
for
V
over
ove!
II.
forms an
we denote by
]R-basis
f
. lR
/
of
NNNNN\N
In
as the the
corresPonding
bottom
row'
and,
finally,
e1in,...,"2ro-1frt in
the
toP rovt
subspaces corresponding
f
as the elements
the
nal which
ll-subspace.
Now, the
are contaj_ned in
in the third
u,
row
to
left
the
indicates
right
; in the
e.,JlR'... 'e^-.tF;
column generate
and the diagonal
the
In Particular,
e1lt,...,e2r-1kR.
shaded area
of
JR-subspace
one-dimensional
sre have from
to a single
t2*-1
t2tn-3 t2.-2
em+1
be considered
should
'a
\
O
,,
I
or
V:
a\
\
er1R,erB,.fl,...,..-fl, e*R,e*+fl,...,"2.-fl,e2m-fl,"2n-fl second row
Il
of
way (n = 2m-1)
\
em-1 en
v,
following
t NN N N
squares
of
basis
the standard
the
/
e2 e3
R-basis
in
/
I
The small
enouqh
be a basis of
{e,t....,err}
{1,iri,k}
is
gair.
above one indeconposable
and let
e(2m-1)
NN\}N N "1
lt
V.
of
I I {
Again
II.
{ e . , , e . ,i , e 1 j , e 1 k , e 2 t e 2 J - ,e 2 j , e r k , . . . r e r r r e r r i , e , , j r e r r k }
We may illustrate
{
type
be a pair,
Then
IR.
endomorghism ring
wlth
with
"*+1(g2) dirnenslon type
of
E(2m-1)
each dimension
(h,h)
So let
and
objects'
indecomposable
(2m+1,m) =
type
of dimension
o(m)
endomorphism ring
to
prelnjectlve
of
the
a one-dimensio-
those
connecting
subspaces the
flR
squares
-
flR
and
neither
f
So for over
f'lR
lndlcates
nor
that
belongs
= t$,ft)
A(2n-1) n'
fr
by the
165 -
to
rhe
1:uSm-1
eul'+ .u*1j ,
1 < u < m-l
em + em+li
and
ep-lj + eul '
B(m)
belongs
to
U;
of
V
but
R-subspace
t6
is
and
n+1Sy!2m-1
m-2ap:2n-1
may be lllustrated
(as above)
by:
k j
1
-1
"2
"3
-m-2 -m-1 -m
AA
o(m):
k j
1 -1
"2
J
that
U.
elements:
tu'
'
f + f'
em-2 em-1
".
generated
-
155 -
E ( 2 m - 1) :
a
1 \
\
N \
N
\
\
\a
\
NN
-
:1.'.rS
\. ).:..
:r\ \
e1 e2 e3
\
/__ /
N
/
em-1 en
\
em+1
e 2 r n - 2e 2 m - 1
"2*-3
that
(A 2.3)
as for
Slmilar
pairs
these
preprojective
are
, hence they
indecomposable preinjective
respectively the proof
detaj.ls of
fact
in
m
over
can be shown by induction
it
N
/
N NN
i.'\
\ t.....
,2
,/
/
__
are
just
pairs.
indecomposable
For
see [13J.
the
Next we want to describe
(homogeneous) pairs
regular
sirnple
(h.,'h). First
consider
the
corresponding
tensor
A = Tffh).
algebra
Obviously
By (A 1.1) where the Let
D
every pair additive
I H/
(Ih'VH)
structure
be the basis
H\
/n I \o
A'
algebra
can be considered
of of
this
is
A-module
B = A @*C.
as
A-module'
given
by
U O V.
Then
/\ a o a \ la. De I I \oa./ is
the
category gory of
tensor of
algebra finite
of
the bimodule
generated
c0c
D-modules is
Kronecker modules described
in
O
CCc ,
equivalent
(A 2.1)
that to
is,
the
the cate-
again by (A 1.1).
_167_
(U,V)
Now let lhen
be a slmple u = 2v,
we knorü that
morPhism ririg
dlmensionar
Let
M
thit
the
so it
(U,V)
of
nlte
regular that
either
u + 4v = 6v
of
M
l,t 9n'C
correspond
Pc--1
ac
(given
t\do vector
pC
and
or
either It
M(2,C).
the
and
of
which
c-rinear
QcoQc=vo*c
ts
or
a fi_
II.
Let
well_known
ring
The
End(MO) OnC
,
R-dimension M gRC
of
and so to Kronecker
over
ee
The endo_
rR, c
is
€-dlmension
D-module,
by a pair
spaces
Pn=uo*c
also
to a
is
ring
(u,v).
type
= (2v,y1.
has endomorphisn
C ORC is
it
A-module.
M gRC A,
dlmenslon
(u,v)
ls
thus
be the correspondlng
is
of
has to be a division
]R-argebra,
B-module
palr
.
Now
module
transformations
A)
satlsfying
so
dlrnPn=u=2v
between
and
dlmQC=2v. Ite have now obtained
a Kronecker
dirn Pc = dlm Qn = 2v , or
M(2,c).
only
with
v = 1-
for
(A 2.1)
it
rndeed,
the
sirnple modules facing
and our
Kronecker
ls
(Pf-1
the
direct
Ql) o
module sum of
(P2-
are lsomorphic
Now' applying always type
exi-st (k+l,k)
the
easy to see that
onry
(then its
its
it
(k,k+1)
(k € N).
c
are
rt
is
modules
the
cannot
happen,
forlows
no non-zero
that
horno-
endomorphism ring is
is
modules
G @* c)
M(2,C) ) .
easy to see that
homomorphisms betvreen Kronecker and
is possible
Kronecker
So thls
endomorphism ring
functors
c aRc
modules
which have either
(and then
is
be indecomposable.
two indecornposable
02)
coxeter
ring
a,
thls
indecomposabre
dirn en = 1.
cannot
morphisms between each other or
is
whose endomorphism
regular
lt
satisfying
eC
whose endomorphism i.s either
dim Pc = dim Qn
with
pC -J
modul"
of
So in both cases
there
dimension
168 -
-
din Pa = din Qt ft This
shows that
type
(2,1).
is
there
(1,o)).
dimenslon type element
h € I{
(h Ih,II)
r
(th,II)
every pair
yields
forsome of
]R' = 1'
h€IIUR.
for
S.
ClR+hR)=a'+hrR
so
End(E + h IR,II) = lR + h lR s C.
morphic given
@ + hR,It)
to
by the
left
Inpartlcula!
if
Next
Then i)
= m is
Uß
,
of
the
follows.
Let
r€4,\{o},
=
t€8,+hß,.
(Ih,Vn)
{e.,,...,e*}
regular
(hrh'
Conpairs
- up
E{ + h 1R,II),
forn
6111
if
and only
s€lR.
(l
s m € Z,h be an
€ II\IR)
ll-basis
of
b:f
and (25u51),
if
hcn+i.R(=a),
if
h€lR+iR(=a).
(1 < u < m)
e..
"1h
c(m,h)
generated
eu_1i+euh ii)
g-1
is
(1 < u < rn)
e., ".th
as
pair
be lso-
g € II.
by an element
@ + h lR,rI) e Et + h' IR,IH)
the
9€]It*hlRr
(R + h lR,fi)
So the simple
the pairs
forsome
Furthermore
Such an isomorphism
Il
and
lsa
lR+hlR
andonlylf
Now let
on
s-'l€n'+h'R',
and
define
if
and
and we get
]R' = Lh
C.
€ Il\ß..
multiplication
h'=h.r+s
dim V,
h,hr
,
to isomorphism - are just h € rl\n
to
9€U
lR + hIR =]R + hr lR.
sequently
b:f a non-zero
Observethat
isornorphic
(2'1)
summands of
an isomorphism betsreen (URÄI)
which is
H
of dimenslon
of dimension type
multiplication
so w€ can assume that
U=lR+hlR
pairs
have direct
we don't
Now left
v = 1.
out that
regular
slmple
(Note that
simple.
turns
and it
are only
Evidently
regular
subfield
= 1,2),
,
and
eu_lj+.uh
(2 1u:m)
,
and
with v.
-
Hele vre can obvLously C(n,h)
assuine
169 h = i
(because
i
€lR + hR).
(as above) by:
can be illustrated
1)
N /
/
J
/
N
{
N
ii)
The dinension = ß
C(l,h)
type
is
+ hR,II).
F u r t h e r m o r e there
C(n-2,h)
cln-'t,h)
obvious
m = 1r
$re get
embeddings
and
= c(1,h)
enough to prove easily
unj.serial, Using
are
For
/ c(m-z,tr) o c(2,h) is
it
= (2n,m).
di:n C(m,h)
follows
where all
(3.3.'l)
we get
that
that
C(2,h) C(n,h)
ls is
indecomposable.
indeconrposable,
in
fact
are j-somorphic to
composition
factors
all
indecomposable pairs
regular
From
in
this
C(1,h). way.
-170-
Now, if
= (U,V)
C(2,h) g C(1,h)
C(1,h)
a subring
is
then
to
of
ejj
hEE+i-n',
then
R + h lR = lR + hIR
(h,h'
€ U).
can be parametrized P
this
is
not
andif
h=1,
simple
regular
+ e2i € U\Ui C(m,h) e C(m,hi)
by
lR + hn.
because
e,|i+erh€U\Uh
As vre have shown,
pairs
(u'v)
of
easy to check that
is
to
isomorphic
U = Uhr
implies
it
However,
is
cornposition factors
This
C(1,h). lH.
If
thecase:
because all
,
are isomorphic
decomposes' then it
a f ixed
set
of
if
words the
In other
by the projective in
representatives
lf
and only
II
of
Denote
P F/R).
space
e FZ*t
for
,
example vre may take p = {ia + jb+k
I a,betR}
U
{ia+
j
u
I a€rR}
{i}
So we have shown
^ 2.4 to
Theorem:
Every pair
the
- uniquelY
orders
(1 1 m € z
pararnetrized Novt P2m)
^
by the is
lR[x,Y,z]/
-IR[xrY]/
'
be endowed with of
i
and
j
direct
sum of and
, D(m) , E(2m-1)
the
points
of
the
projective
)
'
{X-+U2+221
a 1 , r 11.+y-+1 )
one point
with
t o a - up
isomorPhic
pairs
of
C(n,h)
, h € P).
We have seen that
Remark:
is
deterrnined
A(2m-1) , B(n)
the form
rina
(h,h)
omitted. the in
i+a its
the
of
real
variety
paj-rs can be
regular
corresponding
h-ei'5r e hÄ^+rrrm maxj-mal sPectrrm
of
A-module an
plane
projective
Then' consideri-ng
Given an
structure
terms
simple
the
P2B).
to the graded function
narracnnnrr corresPonds
lla,
then
JH-space by defining
to
ring P2 G)
lit O I'1 can the
action
-
/o \ ll,and \-1
induces
Remark:
mod*A
(M O t{h) .
mod*A
and the
(1:m6Z)
c(m,h)
is
of
paragraph
further
applicatlons
we tant
of
treat
real
subfields F;
of
subcategory
h€IR+IRi
subspaces of
is
rather
trivial:
(AAJh)
there (O,C) ,
the pairs
complex
spaces over
Conseguently
nanely
we will
and
filtered F.
containing
F
thus if
the
The corresponare only
three and
%,AA)
@C,%)
some indj_cations
in
its
theory
spaces or,
K
K
there
is is
of
center
more generally,
S called
such that
ordered into a
the
for
graphs.
be a commutative
(partlally)
mapping of
containing i € S,
vector
So let K
A finite
preserving
give
still
the representation
a field
dimensional. an order
of
to define
a skew field
finite
functor
applications
last
K-structures
82.
(O,$) ,
respectively
In this
Flrst
type
objects,
Further
S 3
ful1
category
(3.4.3)).
But here the result
binodule
to the This
with
spaces or complex subspaces of vector
(AR,AA)
of
between
pairs
indecomposable
wlth
from
f
Of course we can also
quaternions.
F
the functor
an equivalence
(see remark 2 in
ding
-x/
r (Mo) = ( (M O o)R ,
by
regular
vector
-)
"/
pairs
of iff
(r t
iJ-
Thus, we can define of all
171
set
field FX
S
lattice
F.
i_s
together of all
K-structure
given a subfield
and
SK(F) of
F
172 -
-
and, moreover, An
(w,wi)
S-space
ove!
F
together
such that is
K g Fi =c Fj
an
gory.
with
an
if
i
The category
= F
a right
Fi-subspace j
:
in
t{i
S.
of
all
i € S,
to be a filtered the
(I{,wi)
(1,dim o li F
i
< j
F)
for
all
k
the
follorving
Ä
(We denote
in
If
a (valued)
fS
full and is
q(w,w1) * for
if
for is
(Vt',Wi) all cateif
and only i
all
€ S.
an
S-space, we
K.
To
SK(I')
-i
Fr)
-k
J- j
_
(f,d),fl
graph
(i,j
€ s)
from
and from
given
i
+^
k
by i
to
nF
o
rr:lrra
of
value
J
.
(1,dim
€ S,
an addltive
space over
where we drarv an arrow if
F*)
w
K-realization
valued oriented
f = {S} ü {O} ,
i
S Wi
e(Wi)
O (wi n wi' ) and
space
each
S-spaces is
vector
f
associated
vector
A morphism
E(SK(F)) = (F,Fi,p.FiF,,r. with
S.
lor
such that
!{, = (w, n wi)
for
vte can associate
is
of
(W,Wi) = (W'',i{i) O (W" ,Vti' )
and
(Vt,Wi)
say
sK(F) )
t(S*(F))
In particular
K = Fi
i 1 j
each
map tpr : Inl + Wr
w = W' O Wir If
(over
wi E wj
F-linear
i € S.
for
is
embedding
€ S
tree,
which
are
in the given
maximal
oriented
then
1t can be shoern that
t(SK(F) ) qt(r(SK(F)
valued
q r a p h b ..Jz
this
there
For example, if
).
order.
f^
.)
l-s a
S = {1 }
lR of I{, then L(SRCI)) is given by the subfield hGI) just the category of lR-subspaces of vector spaces over lH
and is
equivalent
tatidns
of
example also So in
dh
to
the
without
shows that
full
subcategory
t (d[fu) of
subobject
of dimensj.on type
L(SK(F))
is
some cases the knowledge of
classi-fy
of
the indecomposable objects
not abelian
L(I(SK(F)) in
represen-
(1,O).
This
in general-.
can help us to
L ( S n . ( F )) .
Conversely,
_173_
before
the Coxeter
to classify for
t(SK(F))
ls
nunber of
finite
glven
in
be of
finite
filtered
of all
[ 1O].
It
oriented
graph
K
So let the
there
is only a finite
indecomposable
representatlon
that
again
type is.
the property
depends on
fields,
S-spaces.
that
S is
to
and the on the valued
theory of
of bimodules
torsion
we refer
to
free
can be used in
abelian
groups of
fi-
[ 7]
Examples
is is
in a
(3.1.4)
flnite.
graph
the results
K-realizat.ion
K = cF(2)
Dlmkin
if
of finlte
the involved
theory
For details
As indicated (M,fl)
type,
type only
the representation
B
spaces see [ .lg] . ) Of course
can be seen there
of
S-spaces
fS .
the classification
fleld
SK(F)
people used
(For example Gabriel
type.
non-isomorphLc
representation
dimensions
Appendix
finlte
vector
dimensional
reratlve
if
of
sald to be of finite
A classlfication
ni-te rank.
have been founded,
K-reallzations
the case of
Finally
functors
First
type
(2.3) do not hord in general,
some valued give
we will
and consider of
of
of
the
graph,
erhere the
here a counterexample.
following
K-realization
of
D4 ,
1
oK
,2f\ ,/l\ Ko2 Ko3
Ko4
,
(where
all
birnodul-es
are
Just'
xKx)'
-
| Iq
(hereditary)
The correspondlng
/
t .ensor algebr a i s
o
l"
o o K o
K lo o \o \oo First
we will
list
corresponding
c-
i'2 -)
where
C - P .-t'
consider
c
the orblts
dimension
-
of
*\ K] KI Kl
the
'Coxeter
and the
types:
P.
-Pz^
1
,l
:3
=4
1
1
ooo
100
o10
oo1
2 111
1
o11
1 101
1 110
1 111
o 100
010
o oo1
= r -E .
(t = 1,...,4)
P, = x .
functors
Then
I
can be described
as follows:
z*R*\ K@1
Now consider then
dim
= -c - 2
-I r.
(X)=
(r.lrx )tr^
t
O + Fo -
for
it
is
Yf
but
,
X + -fl n + Q
easy to see that
three submodules
(corresponding
:P' l.
+ dfun L-
(1,1 )K denotes the where diagonal enbedding k + (k,k)€ROK for k€K.
lf
(t = 1 , 2 , 3 )
there
to the Iast
exists
row of
no exact
A),
sequence
,
is not a quotient isomorDhic to
of lt
I. ,
I
narnely
has
- 175 -
,t = of f "t", Now lt
is
(1 S t
!
l
K
€
easy to
!2 =or"Et'\o, andy, = x/yt
see that
Of course,
J.f
erlth
O + ), + 1
and we have then
K + cF(2)
is
a field,
4/-rz-
a submodule
g r. -l
The complete
Diagram
(2.3),
(3.1)
Given a Dynkln graph
(f,d)
of
lnfinite
fleld,
consider
to
r
(up to
each
tatlon ls
I.
a sünple
Ir^ -2
,
and
the ,
isomorphic
and for root, X.-)Xr!2
with set
Xr)--lXr-1 lf
such
11,
that
two respectlve
cokernels
!2
graphically.
(Mrfl),
positive
uniguely roots
roots
determined)
r is
an epimorphic
kernels
ls
Ä:1
K r,
represenlZ-Ll
a submodule image of
one may indicate are
an
attach
such that
!1,\2
if
l4oreover, or
as follows:
be illustra.t.ed
all
of
I"_ 11
each other).
Examples:
to
page
of
pair
every
cases excrude
arrows
looks
K-reallzation
j.somorphism
,
X
can easlly
the
draw
:1
of
see next
(the
the
(1,tr)K+KOKr
.
submodule structure
The results
w e can choose
an embedding
y" = - z o r ö . o,/t,ir\
that
/" i
ra e c*1a = C-pa o ^ t 5- 2 t '^
3).
resPectivelv
-4"
isomorphic
the
of -I-! 2 fact
by drawing
parallel. (f,d)
= 1?-2F-3
( 2, 1 )
(type Br),
r.vith K-realization
,
-
| /o
-
A,
(A1A2A3)+
A4 (A1A2o)
A4
jor oA:)
rc-lzolr
.) P,OP.
A4 ( A 1OO ) dP^|EP. -a -L
a1 ( A 1Oo )
A1
(oo-o) e P-t .
where (suggestivelywritten) and
A4=KeX
At =KOO,
A2=
(1,1)K,
A3=OOK
-177t- F u^ FF-F(-
nhere
cEF
such that
G
a r e skew flelds, G.. Ä
and
Ff
are finite
tensor
/\ lc
F
F\
1o
F
\o \/
o
F I F I
\t
of
the Coxeter -p1
functors
'2
^3
100
110
1't1
010
122
0 11
112
o12
001
DD
-) where c-!t=It
(1Sra3).
The correspondence
between the root
is
described
dimensional
(heredj.tary)
t\
-) c-
K
in
their
and
center
dlm3 b
The corresponding
The orbits
containing
by
algebra
= 2.
is
are
system and the module structure
178 -
-
If
we change
and
orientation ^ r
^F"j
the
consider
K-realization
)n
t'
-
tre qet
as
tensor
algebra
(" \"
\o of orbits
and the list
P1
Asain
of
ol 1
c
2^ 1"
o
^ c-z
2, ' 1
c-2qt
= It
The correspondence
F
o
'l
]
functors
D -J
11
o ''t
-1
I I
o^
1
öo
1-
(1 a t
F
the Coxeter
-P2^
o1 o
'\
"
1 3).
between the root
and the module structure
systen a-D
is
described
by
I
II
I
u
-/, ./\
./
t\ lz
,r/'-" ,)l
,/l ,rt t'/
.(" DI :1
I |
Y -?
_179_
References:
Appendix A, $1:
Appendlx B
f'or further includlng
applications in particular
[1O] ,
t14l
52:
l12l
,
[13] ,
tt6l
$3'
[18] ,
[10] ,
[7]
:
t15l
and exanples
vre refer
a famous bibliography.
to
[g]
and [9],
180 -
-
Appendix
C
Tables
The following
tabl-es
following
the
of
on the
information
3 on the
chapter
non-homogeneous representations.
indecomposable provides
summarize the results
Each of
tables
the
valued
resPective
reqular
Euclidian
graph:
1. )
of
The type
the
graph
valued
for
the notation
including
the
vertices. 2.)
The quadratic
3.)
The vector
vector
The defect indicated
5.)
under the action
stable
nt
of
and the tier
Wl ,
g.
number 4. )
the graPh.
form of
is
here. M = (F.'illj)..
A modulation
on both sides,
sional
which
to an orientation
respect
with
ä.
As a rul-e, if = Fj
fi
we can assune
is one-dimen-
illj and
'pi .' Ij 1 r .
=
F - i. F i^F- .i ,
withoneexcePtion'namelyforthediagrami,,,becauseitis< (compare (3.5.3
not a tree F.
= F
for
arJrr
AIso,
if
is
iMi
.M. = oFo
€ f and that
i
all
here ll'e can assume that
remark));
but
all
Fr-moduler
as left
one-dirnensional
for
one edge.
r'te may
L )
assune that slmilarly Fr-module.
tj
for
is the
In the
a subfield
case when tables
Fl
of
is
iMj
we omit
=
and, F.FiF*t rl as right one-dimensional and
ilti
these
bimodules
representations,
divided
to display
explicitly. 6.)
The simple
non-homogeneous regular
the orbits
of
equations
I
C*, r
with
(written
their
dimension
as vector).
types
into
and their
l
-
7.\
The source graph root +^
8.)'
For
fr of
f
io
€ f
= f\iio] (f"g')
such
181 -
that
is
the
where
d'
restricted
nf maximal
denotes
respectively the
to
the
maximal
restriction
l
I : t:
h
the module A(tl
deftned in
Dvnl
(3.3).
of
short d
-t82-
T '^11
(4,1) I-2 =
(x^ -
!r
=
t-2'
-c3
=_2+-L
A - r - (' x - )
2x,)2 L
z
) -l
rU all
=
,--1
/
l_e__?\,,
<-cw:.th[F:G]=4;io=2
f
regular
representations
are homogeneous.
4,. L '
(2'21 L-2 Q, (x) =
{x, - xr)2
1-cA
I'
t1 = ,t IY
=-2<-2 M
itf
all
=
tr4
regular
F, wlth z representations
di-m
', . M I
are
= dim Mr^2
homogeneous.
= 2;
io -
= 2
183 -
n+1.
where
(n > 2)
ä.,
,/2-.....-p\ T. \ / '- p + 1 _ . . . . . . . . - n Q. (x) =
-
t ( x , - x r ) " , where
the
edges
-
i
< p < n+l
I
sumnation
runs
all
through
j
'" '''-t\r, 6---=' 1 ) , lfY
,/'
n -l
\1-1
""'-r'/''
A
"tI"..._,>" =
where riqht
given
N is
of
of
K=center
fixes f
lrl
f
E'-' F O -- . . . O
oo oo-....o
E'-'
to. -.. -o oo o o .- - . . o
o. -. -..o
o-. -. .oF oo o"':
"o
oo o... - -.o
10-....o 1
o o -- - . . o
o 11" "'1
o--.. -.o
o" ".ol oo
o...o-11
u...
- r.9
: oFo" "o
(1)
v f
o. " "'o 1t
FF'.."F
r
{1)
dim C-
o 1 0 .- . ' o oo o......o Z=
ni.,
the
F on
by a field
automorphism
c'
and
UF
"N action
o" ' :"o
F of
(vrhich F).
-184-
if
p
o'.... --o
o---.---o o
FO--....o
10.-....o
10- -
1-- -....1
-rlu
o.---...o
o. - -....o
o-.-
o-----..o
o. -. - -..o
o.-- ...o
o-. - -. -oF
o--....01
o-..
: o--..---o
: o-.-----o
o... ---o
o10-....o
-1 10
F--.....F 1
o
n-p
o
o oFo.... -o f
to
V-II
= n+1
^ ( r ) -- L ^ + -D ( r )
11
A(2) _ c+ E(2)
r
4 n
-. -o
- 185-
(n > 2)
Er,
1
(1'2)
- n (2,1) n+l
3 .....
2-
Qa(x) = (x]. - xr)'* r.alrr_r. tr
=1-1-.
-ac
= - 2+-O+-""'+O--2
,t{
=Fl
-
1-lrS=@
F-F.--..
crE
F-Fn+lwj.th
[F:r, l=
dim cr E
o
oFo.....o
o l o .- . . . o
I
FFF.....FF
2rr.....rL2
oo.....-11
o. - - - -oFo
o.....o10
o.....o-110
o o F o .- . . . o
oo10... -.o
o-110-....o
io=r+l A
(xa - xa*r)2 a (xn - *rr*t)2
=c+E
-110--...o
+ I
f gocr =Osn
lf:rrr*tJ=2.
^r^
r
dim cr E
r
o
o F o .- - - - o
o10-. -. -o
-210--. - -o
1
'
11""'11
o-.. - -o-l2
o. -.. -o10
o. -. - -o-110
o o 1 0 .- . - - o
o-1lo-.. -.o
1-
'^n+1
: ooFo--.-.o
n-l
10 = n+l A
=C
+
L E
=
11p
-t
a -c Ä{
.....
-2+O+-
=
= Fl with
F -
'
F -
o
olo
' 1 "F F . . . . . F
ar.
F
z
o- - -..oFo : o o F o -- - . - o o
n-1
1o = n+l =
dim cr
oFo.....o
I
:
+ C'
oo10
E
= [r:rn*rJ
= 2
r v a
-2IO.
.3t 2 \?
o....
o10
o---- o-110
. -.o
o-110
L __!arE
Fn+l;
Fn+l c F c F, and [rr:fl
crE
f
+-O+--1;
.o
r
-(1)
ct
r
l(r)
oro...-.o!
olo.
. v^o o
-IIU.
"vo
I
l . l ' . . . . . 1 , F. F
2t- .
rl
oo---
^ 11 "-' 1
2
oo --.-or!
oo. -
^- *t oo
oo...
^
oo"ol....oB
oo10
..o!
L
i-o -
L
A(2) _ "+ "(2)
:
-0.
tz t
-ro.---.of
= n+1 -+ - (1)
, ro
-ro.....o!
-o
-1-
=U
EQI
r
Z ^ (1)
ct
din
a)
' 1 'F F
^o
t
c' ^ ( 2 )
5
ct E ( 1 )
dim
E
=
d\_e -'
_189_
(n > 2)
a;"
n-r/n*u
$x)
= 2(xr-2xr)'*
ta.alrr_r(*t-*t-tr2
sr =1-2-2
+ ( 2 x n - * r , - 1 ) 2+ ( 2 * r r * 1 - * n _ 1 ) 2
,
-ac
=
-2 +O1
=Fl -F-'
ff
r
{rl
c- E'^'
t
o
oFo-...-03
I
r1!!""'!F
2
o.--..oF3
o.'
ooFo.....03
oo10.
n-2
-F
.r
cr e(1)
ü
r)
o10
"
(1)
- 2 1 o .--. . 0 3
"o 1
o--.-.o-11
la
o-..-.o-113
.'l^
r1'
=2i
withlFrFl
"<:
-1
at
-o
o-110.....03
L _
-
dim c'
"r "(2) o
-- 1
_o
(2)
,tl
E\''
at
^o
-10.....o?
^2
-1o.....oä
]I
I
1
-f t1
.....F'I
--o
Z = 9*n io = n+1, A(1) = c+ E(1),
A(2) -
t(2) "+
(n z 4)
ö.,
"-'(1.
;>'$a)
2+ ( x 2* = ( 2 x r - x . ) 2+ ( 2 x * r - x3 l ' . r : , : ( x . - x . * , , ) n - r - 2 x .) { * , r - , 2 x n * 1 1 2
ä.=_l>".-o.....*-"
r
ar
E\"
c'
"(1)
o 1
ÖA "Fö.....arv
-o
o--
-F.....FII
2 n-3
n- nr.). . . . ö F "'n
: o^"^.....^o "o o"^" r
-1t.,.....^o
1r.....r1 1^
o^ ^ .I oe" "'e-r1
o^ ^.o ou.....uro
3o--:--o-rr!
ö(.} öolo..-..oö
aro ö-110.....oö
I )\
r
dim c'
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c'
o I
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ooo. I
11.
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r'-'
cF
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cf
(3) -!,
'l^
ot
tl
o r . . . . . r 1' o 1'
(1), A(2) = c+ r(2), A(3) - c+ E(3) io = ,+t, o(1) = c+ e
7=4r.
-
191 -
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II 3-2-1-6-7 $l)
= (6x, -
3xr)2 + (6xz -
+ 3[(3x,
-
3xU)2 + (6x5 -
2xr)2 a (3x6 -
3xn)2 +
2xr)2 + (3xn -
zxrl2);
11 ll 21
| =1-2-3-2-L;ln=.!,
nf
.t !.=1-+1--r-3<-1+1
,-1
F
I F -
rt{
I F-F-F-F-F;
(1)
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(2) "r "
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1
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"r
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(2)
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1 oo111
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1_l
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r cn
to
1
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4_3_2_1_6_7_8
9(o)
? I
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= 1-
tr
2-
3-
2 I
4 _ 3 _ 2 _ 1,8-_:-.il ,.^_*<
2 -a.c
=
1 +
1 ->
t
1 +-4
= F-F-F-F_F_F_F
ll
r
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1 +
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aim cr e(1) l
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o
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.t
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100-1100
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o 3
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r
|
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io
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=$
A(1) _ c+ E(1) A(2) _ "+3 "(2) (3) A(3) _ E
o
r
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=
ll
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ltd
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-L97-
-41
(L'2')
a -
"
1 -
c
$l)
= 3(2xr- *r)2 + (3xn- 2xr)2 + 2(2xr- 3xr)2 + 6(2*r- *1)2
llr
=1-
2_ 3-2-
trn=o
-a.c =1->1+1-+-4+-2 = F-
M
F -
F-
Fl -
F, wirh [Fl:F] = 2;
dim
c'Et"
o I
ooF1FlFl
FOF FeF FeP FloFl
-1
-1
.r
o 1
I
'1
FA
100-1
1
o 2;\t o T j. 2\1-
o10-1
0
r
C-
lll
E'-'
"+,(1) = A(2) c+ E(2)
.r
u
n
r
v
11210
101-2
t'
L
-z
r
(2)
o1111
=t^
a(1) =
(1)
2222r
I
^4 -oA
n
u
"(2)
'1
r
L
oo211
dim
'1
OFF
(1'1)Fl
( 1)
cr
w
- 1a a
a
0
-
-
lvö
F nr. (2,r)
3 _
4 _
1
olx)
= o(2xT
.r
=1-2-i-4-z;s=(il;
*r)2
+ l(2xs-
*12
5;
+ 2(3x2-
2xr)2 + (3xn- 4xr)2,.
\-/ ä"
=1-+1->-3<-1<-1;
M
=Fl
-
-
Ft
-
Fl
F_
Fwith
^r -(1)
r
LE
= 2;
lFl:Fl
oFlFlFF
ol
1
ooFlFlF
ool21
2
PtFlFlFO
oF1F1FlO
1
(1,f)F1 with
(r'f)Fr
l
t
1
11110 )
c. E..,
FroFl FoF FoF
r
ai,n ct n(1)
=
v
-t
(1)
-z
a
u
L
oo-2
11
20-2
Io
t4-
dllt cr r(2)
(2)
a
-!.
o1120
o1-2
TL222
I O -1 0 1
f € rr:F
t=
,
lo
-199-
G,,'
2
(1,3)
1
O-{x) = ( 2 x a - * 2 ) 2 + 3 ( x , l-
-
2xr)2;
=1-2-L;g
-l
=1+1+-3
A :c
=F-F-Flwithlr:Fll=3;
M
o31
FeF+(e,f)r
FoF+(e,f)F
FloFl
where {1, f ,e} form a basis
ro
=l
=
+ C'
E
of
JJZ
F.,
-2oo-
-22
(3.1)
I
2
9(:i)
= 3(2x3 - tr)2 + (zx, - 3xr)2;
tf
=1-2-3;g=1
jc
= 1 -+ -2
= Fl -
M
<-
F1 -
r;
F with
crE
r
oFl with
I
-1 I
-i o
=1
A
=c'E
= 3
dlm cr
t+r-r'
f
[Fr:rJ
E
wLz
w
€ I'- 1 \F '
F
I.LI
t=
ctl]-
an
-5
z
- 20't -
REFERENCES
t ]l
I.N. functors
Bernstein,
V.A. ponomarev, Coxeter theorem, Uspechi Mat. Nauk 2g (1973) , in Math. Surveys 2g (jg73), j7_32. I.M.
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t 3l
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t 4l
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