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. Since p is a point of E4 and E , E4 and E intersect in a line L containing p. Because of p 6 N , N # L. Assurre by way of contradiction that L3 and M intersect in a point. q. Then =(L~ ,N>, a contradiction. Consequently, N and L are disjoint. Because N has degree n , there is a unique line in < p , N > , which is disjoint to N and contains p. Hence, L=L4 so that LLI and L4 are coplanar.. LEMMA 3. Suppose LI , LZ and N are three distinct, mu%ually coplanar lines. Suppose furthermore that L is a line disjoint and coplanar to LI and LZ , disjoint to N , and not contained in n < p , L ~ > Set . E= . If pe = are distinct planes and intersect therefore in a line Hj, which contains p. We have H j f l N = 0 (if HJ and N would intersect in a point q , then we would get the conSince N has degree n , tradiction p ~ < p , L>== =
Cl
= L , and L is therefore coplanar to N.. LEMMA 4 . Suppose LI and LZ are disjoint and coplanar gree at most n-1. If S has at least n3 points, then line N of degree n , which is disjoint and coplanar to PROOF. Set EI=
lines of deit exists a Li and Lz. other planes
I F is a plane containing LZ and with Ej nF # 01
Embedding Planar Spaces into Projective Spaces
295
is a p2rallel class of E l , which contains L I and has at post n+l elerrents. Let G2 be a line other than L I of MZ , and set MI : = ( E l flF
I F is a plane containing
G Z and with E l O F f 81 .
Then M I is a parallel class of El, which contains L I and LZ and has .at r:ost n+l elements. Hence, M:=MI I J . . . U M o ? I is .a parallsl class of S with at most n2+n+l lines. Since no line of M can have degree n+l, and because S has at l e a s t n3 points, M contains a line N of degree n. By the construction of M , N is disjoint and coplanar to LI and LZ .m PROPOSITION 5. If S has at least n3 points, then it satisfies the Bundle Theorem. PEOOF. Let ( L I ,Lz, L J , L 4 ) bz a bundle. We have to show that L3 and L4 are coplanar. If LI or LZ has degree n , this follows frcn Lemma 2. Sincce LI and L 2 can have degree at most n , we y a y therefore a s sume that they have degree at most n-1. By Lemma 4, it exists a line €J of degree n, which i.s disjoint and coplanar to LI and Lz. If N is disjoint to L3 and L 4 , then Lemma 3 shows that N is coplanar to L3 and L I , so that L3 and L4 are coplanar by Lemma 2. Thus, it is no loss of generality to assup.+ that N and L3 have a point p in common. Because ( L I ,Lz , L J ,LI) is a bundle, p is not contained in the plane < L I , L z > . Consequently, it exists just one line through p, which is coplanar to LI and Lz. Hence, PJ = L3, and now Lemma 3 shows that L3 and L4 are coplanar.. In view of Proposition 5, our theorem follows at once frorn the Ti?sult of Kahn [a] xentioned in the introduction. REMARK. If S has at least n3 points, then it is easy to see that S is either a 3-dimensional affine plane of order n, or it has ex-actly nR+nz + n + l planes. Thus, in the preceeding proof we only need a quite special c a s e of the theorem of Kahn. REFERENCES Ill
Beutelspacher, A.: Embedding finite planar spaces in projective spaces. Finite Geometries (C.A. Baker and L.M. Batten ed.), papers presented at a conference held in Winnipeg at Saint John's College, July 9-18, 1984. M. Dekker 1985.
[21
Kahn, J . : Locally projective-planar lattices which satisfy the Bundle Theorem. Math. 2 . 175 (1980), 219-247.
[31
Kantor, W.M.: Dimension and embedding theorems for geometric lattices. J. Comb. Theory (A) 17 (1974), 173-195.
[41
Witt, E.: Die 5-fach transitiven Gruppen von Mathieu. Math. Sem. Univ. Hamburg 13 (19381, 256-264.
Abh.
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Annals of Discrete Mathematics 37 (1988) 297-300 0 Elsevier Science Publishers B.V. (North-Holland)
297
ON TOPOLOGICAL INCIDENCE GROUPOIDS
Rita MEYER, Jiirgen MISFELD, Elena ZIZIOLI* Universitat Hannover, Institut fur Mathematik Welfengarten 1 3000 Hannover 1, Germany Universith Cattolica del Sacro Cuore Dipartimento di Matematica via Trieste 17 25121 Brescia, Italy
In this note the notion of a topological incidence groupoid is introduced. We prove an algebraic representation theorem and characterize the classical incidence loops over the quaternions and the octonions.
1.
INTRODUCTION
The rotation group 0' of the real space fixing 0 is an example of a topological 3 incidence group,that means 0' is a group which carries a geometric structure 3 (projective space of dimension 3 ) and a topological structure such that suitable compatibility conditions hold.This group is isomorphic to the factor group H*/R* of the real quaternions over the reals. Starting with the real octonions 0 one observes that,due to the lack of the associative law,the factor structure leads to a topological incidence groupoid. In this note the notion of a topological incidence groupoid is introduced and these structures are represented by topological algebras.
2.
PROJECTIVE INCIDENCE GROUPOIDS
E. Ellers and H. Karzel [l] defined the notion of an incidence group in order to give a foundation of the theory of motion groups of absolute planes. It is shown that these groups can be described by near-fields. Later on this theory was extended to the more general sliced spaces;the algebraic structure was extended to groupoids ( see H.Wahling [ A ] )
.
Definition. A triple ( G , . , II ) is called a (left-) incidence groupoid following holds: (i) (G,.) is a group0id.i.e. " - " is a binary operation on G, (ii) ( G , n ) is a projective space, (iii) for each aaG the left translation
if the
G--cG a 9, : l X-ax
* Research supported in part by the Italian Ministry of the Education
(40% M.P.I.)
R.Meyer et al.
298
is a collineation of ( G , li). If the right translations a are also collineations then (G,., TI ) is called R two-sided (G,.,TI) is called r i g h t r e g u l a r if every a is injective.
.
9.
Examples were constructed by H . Wahling 141 from (left-) near-algebras. Let (F,K) be a (left-) near-algebra ;i.e. F is a near-ring,K is a field, (F,K) is a (left-) vector space of rank at least 2 , K is normal in F (K*(ab) = (k*a)b = a(K'b) for every a,b€F ) , then Wahling [ a ] has shown: (2.1) If (F,K) is a near-algebra without zero divisors,then the factor strucis a right regular desarguesian projective incidence groupoid,where ture F"/K* the groupoid operation is defined by (K*a).(K*b) = K*(ab) and the projective
structure is given in the usual way by the vector space (F,K). ( 2 . 2 ) If (G,., l i ) is a right regular desarguesian projective incidence groupoid,then there exists a near-algebra (F,K) without zero divisors such that F*/K* and G are isomorphic (with respect to the binary operation and the projective structure).
Remarks. 1. (2.1) and (2.2) are generalizations of the results in [l] ,where is shown that every desarguesian projective incidence group can be represented by a normal near-field. 2. Taking a two-sided loop instead of a groupoid, Wahling has shown that there is a corresponding division algebra (A,K). If,in addition, the left cancellation law holds, ( A , K ) is a normal alternative field.
3.
TOPOLOGICAL PROJECTIVE SPACES
In the mentioned classical example of an incidence groupoid the underlying projective space carries topologies such that the space is a topological projective space. This notion is introduced in [ 3 ] . Let (G, a ) be a desarguesian projective space of dimension n and let 7 be kthe set of k-dimensional subspaces , O 5 k cn-1 We assume that every 1 is a k topological space with topology T~ (the trivial topologies, i.e. the discrete and indiscrete topology,are always excluded). ( G , n ) is called a topoZogica2 projective space if joining of point and subspace:
.
K
(where
( Tox ik)* : =
T
o
x
T
k
\
,
l(To,Tk)
1
T,'Tk:
Olk
)
,
and intersection of hyperplane and subspace:
1
( T
n-1
Tk)*+
i
k- 1
are continuous with respect to the topologies defined in an obvious way.
On Topological Incidence Groupoids
299
In [2] ,theorem 2, is shown that the topologies T~ are defined in a unique way by the point set topology T Therefore we can write ((G,n ) , T ~ ) or shorter 0
((G,
.
T ~ ) , T ) .
Here and in the following is always assumed that the dimension of the projective space and the vector space is finite. The representation theorem in [3] states: (3.1) Let (V,K) be a topological vector space.Then V*/K* is a desarguesian topological projective space with respect to the projective structure of (V,K) and the quotient topology. (3.2) Let ( G , n , T ) be a desarguesian topological projective space.Then there exists(up to isomorphism) an unique topological vector space (V,K) such that G and V*/K* are isomorphic (with respect to the geometric and topological structure).
Further it is shown that every locally compact connected topological projective space is isomorphic to a projective space over the field of real numbers,complex numbers or the quaternions.
4. TOPOLOGICAL INCIDENCE GROUPOIDS
Definition. A quadruple(G,., , T ) is called a topoZogicaZ i n c i d e n c e groupoid if G is a groupoid,a projective space and a topological space with respect to TI and T ,such that holds: (i) ( G , . , n ) is an incidence groupoid, (ii) (G,., ) is a topological groupoid , i.e. the multiplication is continuous, (iii) ( G , TI , T ) is a topological projective space.
".",
Examples can be constructed from topological near-algebras. A near-algebra (F,K) is called a topologicaZ near-aZgebra if (F,K) is a topological vector space, such that the topology in F is the product topology of the field topology in K (canonical vector space topology),and if the mapping
I
(F*/K*) x (F*/K*) (K*a
,
K*b)
+
F*/K*
--.
K*ab
is continuous with respect to the quotient topology induced by the canonical 'p : F F*/K* . surjection We remark that (F,K) is not assumed to be a topological algebra,i.e. the multiplication in the algebra F may not be continuous. Obviously we can prove
-
(4.1) If (F,K) is a topological near-algebra without zero divisors then F*/K* is a right regular topological desarguesian projsctive incidence groupoid. To every right regular topological desarguesian projective incidence groupoid exists a topological near-algebra wich represents this groupoid.
The proof is the same case o f groups. The multiplication in factor group F*/K* is it can be shown that
as that for a theorem given by Karzel 121 in the special
F need not be continuous,only the multiplication in the continuous. But for the spacial case of two-sided loop there is a corresponding topoZogicaZ division aLgebra
R. Meyer e l al.
300
(see remark 2 in 2. 1,i.e. that the multiplication in F is continuous and that xa = b have continuous solutions. the equations ax = b and Here we need the following Lemma: (4.2) Let (V,K) be a topological vector space over a commutative field with the canonical vector space topology. Then every bilinear mapping 6 : V xV - V is continuous.
Proof. b is continuous if the coordinates of b(x,y)~V are continuous functions of (x,y)EVx V Therefore it must be shown that every bilinear form f : V x V - K is continuous. Such a bilinear form f is a polynomial in the coordinates of (x,yr)lEV.Now K is a topological field. So for x,yeV with n n c xiei , Y= yiei we have f(x,y) = . 2 x Y a. with x= i=l i,k=l i k i,k ai,k= f(ei,ek) E K , from which follows that f i s continuous.
.
?,
From (4.1) , (4.2) and remark 2 in 2. follows the Theorem. Let (G,., I , 7 ) be a two-sided topological desarguesian projective incidence loop. Then there exists (up to isomorphism) exactly one topological division algebra (A,K) such that G and A*/K* are isomorphic (with respect to the loop structure,to the projective structure and to the topological structure). If the topologies are locally compact and connected the underlying field is either isomorphic to the reals,the complex numbers or the quaternions (see [3] ) As we assume the dimension of the projective space to be at least two,such topological incidence loops are isomorphic to those over the quaternions H or the octonions O.Being more exact we have the Corollary. Every locally compact connected two-sided topological desarguesian projective incidence loop with left cancellation law is either isomorphic to H*/R* (in the group case) or to O*/R* (in the loop case)
.
ACKNOWLEDGEMENTS This note has been carried out while the third named author was visiting the Mathematics Institute of the University of Hannover; she wishes to thank the whole staff for their hospitality.
REFERENCES [l] Ellers,E. and Karzel H., Kennzeichnung elliptischer Gruppenraume, Abh. Math. Sem. Univ. Hamburg 26 (1963) , 55-77. [2] Karze1,H. , Beziehungen zwischen topologischen Inzidenzgruppen und topologischen Fastkorpern, in: Celebrazioni archimedee del secolo XX , Simposio di topologia , Gubbio (19641, 75-84 [3] Misfeld,J. , Topologische projektive Raume , Abh.Math. Sem. Univ. Hamburg 32 (1968), 232-262. [ a ] W&ling,H. , Projektive Inzidenzgruppoide und Fastalgebren, J.of Geometry 9 (1977) , 109-126.
.
Annals of Discrete Mathematics 37 (1988) 301-310 0 Elsevier Science Publishers B.V. (North-Holland)
301
ISO~ORPHISMSOF FINITE HYPERGROUWIDS Renato MIGLIORATO
(it)
We characterize a particular class of finite commutative hypergroupoids, calledminimal hypergroupoids, such that for every finite commutative hypergroupoid H, there exists one and only one minimal hypergroupoid isomorphic to H. We denote it with MIN(H). We utilize the concept of minimal hypergroupoid in the study of two problems on the isomorphisms of finite hypergroupoids. INTRODUCTION The content of this paper owes its origin to two problems which are of particular interest in the electronic elaboration on finite hypergroupoids. It should be noted that a hypergroupoid is a non-empty set H structured by a hyperoperation o (i.e. an application a:H x H + W H ) where M H ) = P(H) - $). A hypergroupoid H is called a semi-hypergroup if W x,y,z EH, (x.y)uz = xo(y~z)~ a semi-hypergroup H is called hypergroup if, we have
Some methods have been given for the construction of a hypergroup starting from a known hypergroup of minor cardinality [4], but, generally speaking, the construction of examples of hypergroups is very difficult, above all as regards the verifying of the associative propertiy. This is one reason because electronic elaboration can be useful. However, electronic elaboration can also produce serious problems because of the large number of hypergroups that can be constructed on one set, even when it is of small cardinality [ 3 ] , [s]. The first problem regards the proof of possible isomorphisms between two given hypergroupoids H and HI. Since the isomorphisms f:
R. Migliorato
302 1. MINIMAL HYPERGROUPOIDS
...
If H = { O , 1, n-l] let us define the application V: H H ) d N the set of the subsets of H into the set of natural numbers) such that
V(0) YAEWH),
(from
= 0,
V(A) = 2 2 ' xEA
It follows immediately that
n- 1
V(H)
=
2
Zi = 2" - 1,
1= 1
...,
and that the application V: W H ) --9 10, 1, Zn-1} is bijective. If H is a finite commutative hypergroupoid of cardinality n, we can indicate with 0, 1, n-1 the elements of H; therefore in the rest we will suppose that the support of H is the set {O, 1, n-1). By commutativity it i s sufficient, to consider only the hyperproducts xay with .y'x We give therefore the following
...,
...,
H Lanotes t h e s e t of t h e pairs (x,y) EH' DEFINITION 1.1. : < denotes t h e r e l a t i o n suck t h a t
e,
(1.2)
(x,y)
<(X',Y)WX
such t h a ty'x
:In
<x'
The relation thus defined is clearly a relation of strict total order in H : . DEFINITION 1.2. W ~ E H t h e evaZuation of y in H, denoted b y V, (y), -Is here def i n e d as t h e number
V,(Y)
= E2
n(y-x)
V(x0 Y).
x= u
It follows immediately that V (y) identifies univocally all the hyperprodH ucts x a y with .y'x
...,
DEFINITION 1.3. I f H and H'are t v o hypergroupoids on t h e same support ( 0 , n-l}, H is said t o be H
From definitions 1.2 and 1 . 3 if 3 7 ~ such H that
it immediately follows that H < H ' if and only
Isomorphisms of Finite Hypergroupoids
303
From definition 1 . 2 and from the bijectivity of the application V, it furthermore follows that if H # H I , then H < H ' o r H'< H. The relationtis therefore a relation of total order in the set of the hyn-11. In particular it is a relapergroupoids with the same support 10, tion of total order in the class of all the hypergroupoids isomorphic to a given hypergroupoid H. Then, the following, definition can be given:
...,
DEFINITION 1.4. k hypergroupoid H i s called minimal i f and only i f for every HI isomorphic t o H, it i s H'H'. M I N ( K ) denotes t h e minimal hypergroupoid i s o morphic t o a hypergroupoid K . From the fact that MIN(H) diately,
is unique the following proposition derives imme-
PROPOSITION 1.1. If H and K are two f i n i t e c o m u t a t i v e are isomorphic i f and only i f MIN(H)
=
hypergroupoids,
they
MIN(K)
A t this point we are faced with the following problems: to recognize whether H is minimal without com-
I. Given a hypergroupoid H,
paring it with all the n! hypergroupoids isomorphic to H. an algorithm that, given H, allows the construction of M I N ( H ) without having to construct all the n! hypergroupoids isomorphic to H. The rest of this paper aims at the study of these two problems.
11. To find
2.
cuss c ( x , y )
DEFINITION 2.1.
v(x,y) E q , N,,(X,y)
denotes t h e subset of H such t h a t
The elements of N H ( x , ; ) are c a l l e d new elements of
G o y .
From definition 2.1 it follows immediately that
ZENH(X,Y)3 z > y.
(2.2)
In fact if z z y , then x c z , z~xoyu{x,yk. "fLEOREM 2.1.
- -
- -
- -
If ( x , y ) ~ H : and z ~ x o y u { x , y ? ,t h e n 3(x,y)t(G,;)
such t h a t
zEN~(x,y) u W,Y?
(2.3)
ZL
- -
PROOF. If v(x,Y) E H:, (x,Y) 5 (x,y)= z 6 xoyy{x,y~,- then clearly and therefore by the definition 2 . 1 , we have zE%((x,y)u(x,y}. On the other hand, if (x,y) is the first pair of :H such that Z E X yu[x,y}, then zENH(x,y)u WX,Y1
-
E
R.Migliorato
304
where is
PROOF.
I. The condition is sufficient . I If r 0, then NH(x,y) f and therefore (2.4) is obviously true, Let r f 0 and suppose that (2.5) is valid. :i
If 1,
7
=
0,
..., r).
(2.8)
~
(2.4) follows immediately from (2.5) and fromN,,(X,Y)u{x,).}= (0, Let us suppose that 7 # 0. Let z~N~(x,y),z'
V(x,y)EH::(x,y)
<
(x,?),
z ' $ N H (x,y)uIx,yl.
Immediately we have z ' '7 because otherwise z'EIx,z') and (2.8) could not subsist. If z ' = m, by (2.61, since # 0, 3(x,y) <(%,?) such that z'Exoyw{yl and therefore (2.8) i s false. From (2.8) and (2.5) it follows that
7
(2.9)
< z ' < m.
(x,?)
From (2.6), since 7 f 0, it follows also that 3(x,y) < such that m = max (xoy u tyj). But y < y < m and therefore m # y, thus m = max (x~y), and indeed, by (2.9) and theorem 2.1,
=
From (2.5) we have
N,,(X,,Y~) =
U
{ m l + i},
m, + rl
=
m,
rI
#
0,
i=i,....r
where m , and rl are defined by (2.6) and (2.7), where ( x l , y l ) is in the place of (X,?). If 21 is one of the numbers m, + 1, m, + r, = m, then Z ' E ~ Q Band consequently, from theorem 2.1, (2.8) is absurd. Let z ' < m l . Then
...,
T < z l < m , <m.
Isomorphisms of Finite Hypergroupoids
305
Repeating the preceding reasoning we find that I(% ,y2 ) such that = max NH(x2,y2) and that
J~(~~, = YU ~ ) tm, i=l,.
.., r
m e + r? = m l ,
i),
+
...,
If z ' is one o f the numbers m2 + 1, m2 + r 2 (2.8) is absurd from theorem 2.1. If z ' < m , proceding in the same way, we find that yc
...
... < m 2 < m , <
m2<
=
r2
f
m,
=
0.
m L , then z'fx;y2
and
m.
Since it is not possible to proceed indefinitely, we must conclude that (2.8) is absurd. From (2.5) therefore. It follows (2.4). 11. The condition i s necessary. Let us suppose (2.4). From (2.2) we have that z € N , ( E , ~ z) >~ j ; and, so, from definition of N , ( T , y ) and (2.51,
z >m.
It follows from this that z = m
z~N,,(%,y)-
(2.10)
Z
I f b = max NH(X,f), and
=
m
+
p, p
-> 1.
+ p , from (2.4) we have
P , 3(x,y)5(?,7)
WP' : l ( p ' <
: m +
P'EN~(X,Y)UIX,Y},
...,
and therefore f o r any number ae{m + 1, m + j},3(x,y)~(G,y) such that acNH (x,y)u{x,y], but a > m and than (X,y); indeed, from (2.10), NH(a,T) = { m + 1, m + ;I. In the rest we will callsegment every subset A E H such that
...,
A
=
{xEH
:
min A< x t m a x A].
Now theorem 2.2 can be enunciated as follows.
H EC(;,;)
THEOREM 2.2.1.
if and on2y if V(E,y)
- _
(x,?)
impZies t h a t H,: (Z,?) 5 t h e s e t Nb(%,y), when z t i s not empty, is a segment w i t h minimm m + l , where m i s defined by (2.6). E
THEOREM 2.3. If H E C ( ; , i ) and (k,?) i s t h e pair successive t o t h e r e e x i s t s an isomorphism f : H-> H i such t h a t a) H'E C (;,y=) EH :,
b) W(X,Y) where
{t
(x,?)
:H then
iyL
, ( x , Y )c ( R , y )
=, X"Y
=
x y. 0
denotes the hyperoperation in HI.
PROOF. If N H ( % , ~ = ) fl, the statement is obviously true because it is enough to assume f as the identity. Let f l ~ ( ; , T ) = { a l , arl, and let m be the number defined hy (2.6) when
...,
R. Migliorato
306
(x,?)
i s substituted by (%,F). Then it i s sufficient to consider any permutation f : H + H I that leaves every z t m unvaried and such that
...,
~ i = l ,
r,
f(a.)=m+i.
q;,;, .
Besides, It follows immediately therefore from theorem 2.2 that H' E since f leaves every z c r n unvaried, the hyperproducts x o y with (x,y) < (E,;), do not vary.
3. CLASS
q;,;,
DEFINITION 3.1.
If(;,;)€ H:,
A,,
*
DEFINITION 3.2. (3.2) H
z
__
LI x'y
Z'
(x,;)
indicates t h e s e t such t h a t
-
denotes t h e r e l a t i o n in A,,(;,;) <e (v(x,~)<
(x,?),
mod [XkY],
then 'Ji= 1,
...,
ri]
zExoyuz'~xay).
Sz(x,y) denotes t h e c l a s s of equivalmce mod
DEFINITION 3.3. If H E C ( ; , ; ) , .we can w(%,yLCH:: (x,?) t(?,?), ?-fA , , ...,
such t h a t
t o with z belongs
if and only if say t h n t H E W ( ; , ; ) denote t h e classes of equivalence r, A ; n < ~ yi s segment and m i n ( q n ? o ? ) = min Ai t$
(z,?)
THEOREM 3.1. I f HeC'.'(;;,y) , and i s t h e pair successive t o t h e n t h e r e e x i s t s an isomorphism f : H-> H ' such t h a t i ) H I E C%
ii) v(x,y)c
(x,?)
in H:,
' (k,?), x'>y
=
xoy,
.
where 35 denotes the hyperoperation in H ' We prove the following two lemmas before the proof of theorem 3.1.
m
I.
rf
(xo,yo1 < ( x , , ~ 1 < (xz ,y2 1 and H
szo(x2'Yz 1
( 3 ,yo 1,
then
H
sz, (x, 'X 1 -
PROOF. From definitions 3.1 and 3.2 it follows immediately that
3
Isomorphisms of Finife Hypergroupoids
11. In t h e hypothesis of theorem
307
H = =
321.7,
zo€A (x,y), S,"
(g,?)
is a
seg-
0
ment
PROOF. Let (xo ,yo) < ( x , , ~) < (x,y)c (g,?), with (x, ,y2 ) successive to (x, ,yl) and let Z$#~(X~,yo ). We prove that if SH(xl,y, ) is a segment, then StCx, ,y,) 6. is also a segment. We can ignore the trivia' case i n which SH 5 (x, ,y, ) = 9. In these hypothesis, by lemma I, we have
sz",(x, ,Y2 1 c_
$o
,$
(XI
and therefore S \ (x, ,y, ) can be obtained from oS : sary some of its elements. If z E S\ (x,,yl) - Sz", (x, ,y, )j we have that
(3.3)
zES:,
(xl,y, ) eliminating if neces-
(xl,Y, )
(X,Y) < (X1,YI)=9(z€x.y-
Zo€XOY),
and besides, since zESH$ ( 4 ,y, 1,
zoE x o y Taking into consideration (3.3) and (3.4) simultaneously, it follows that zESy (x,,y,) - S k (x,,y2) if and only if at least one of the following condition; is satisfied.
c ) "4XI0Yl, ZoEx,.Y1.
Applying to S:o (x,,yl) the condition (a) (as explained previously to obtain (x,,y, )), this implies at the most the elimination of the element y, j this, if y, is contained in S L (x,,y, ), then it is the minimum of this set, because S\
308
R . Migliora to
, z >y, and from the fact that (x, ,y, ) is the by definiction, z ESZ", (xl ,y?)= pair successive to (xl,yl), it follows that y , ' L y , + 1. Therefore if, as supposed, Sy (x,,y,) is a segment, then (a), transforms it again into a seg0 ment. In the case (b), since Z E So! (x,,yl 1, we have Z E X , ~ ~ Z , E.S ~ ; ~(xl,y1) n x l o y
and therefore
q0(x, ,Y1 )nx,.y,
c_ s; (X,,Y,) - sz",
According to the hypothesis that (x, ,yl)c(g,T) and supposing that H E W - = (X,Y)' the set Sy (x, ,yl ) n x l a is a segment such that its minimum coincides with the minim& of S! (x,,yl) j therefore in the passage from S: (x, ,y,) to Syo (x,, y2 ), the condic2ion (b) implies the elimination from S l (x,,yl), at the most, of the above mentioned segment. What remains is still a segment. In the case (c), since z o E S$ (x,,y, ), 0
Z o E x , o Y , ~ z , Es; (X*,Y2)nx,oY1, and therefore, since z o E
From
%,
(3 ,yz),
this and from lemma I it follows that
s! (x,,Y, 1 5
~'1, (x,,~,I n 4 "Y,.
In any case, Y z E S y (xl,yl)nq.y,,
(3.3) is satisfied and indeed,
(x,Y) <(x,,Y,) = > ( ~ E x o Y -
V(X,Y)EH:,
4
E XOY).
Hence if z = y, , then z E S l ( 5 ,y, ). Therefore in the case (c) the set SH (xi?,yz) either coincides with Sz", (x,, z, y1 )nxloyl or is obtained from this by eliminating every element less or equal to yz. Since SH, (x,,y,)~x,~y,oris a segment whose minimum is larger than y,, it follows immeaiately that S! (x, ,y2 ) is also a segment. With an analogous procedure 'it can be proved that if (x, ,yl ) is the successive pair of (xo ,yo) and if NH(xo,yo ) is a segment whose minimum is larger or equal to y o , then S: (x, ,yl is also a segment. ButNH(xo,yo) has always the minimum larger o r equal to y~ besides, from hypothesis that H E C and from theorem 2.2, NH(x0 ,yo ) is a segment. The thesis follows by induction.
PROOF OF THMlRM 3.1. By theorem 2 . 3 , there exists an isomorphism f : H-fi such that fi€C(;,;)and for which the property (ii) is true. We can therefore suppose that H € C ( x , ; , Let A , , A,, represent the classes of equivalence mod Vk = 1, r, if Z k E A k , then
...,
...,
.
Isomorphisms of Finite Hypergroupoids
309
By lemma I,
(3.5)
Ak = .
U
i=l,..,r
where mk If Ak that
=
min A k ,
n G - 7 f y,
[ml( + i - I}
,
k
rk
=
lAk/*
put Ak n%.f= {a!,
..., :a },
f:H ->HI
be a permutation such
k
i) W k : A k " z o 7 == q, the elements of A k are permuted in such a way thatWi= I j % , f(ak) = mk + i - 1.
...,
ii) Yx which does not betong to any A k , f(x) = x. HI, thus obtained, satisfies the condition (i) and (ii) of the proposition. The condition (i) follows immediately from the construction of f and from ( 3 . 5 ) . As regards to the condition (ii), this is guaranted, as well as by (ii), by the fact W(x,y) EHf: (x,y) < (g,?), x.ynAkfe(-&gx oy, hence a permutation on the elements of A; does not alter the hyperproducts xo y if (x,y) < <
(=x, y=) .
If H is a finite comutative hypergroupoid, and (x,y) EH:, there exists an isomorphism f : H-H' such that l I ' E C ; t ( x , Y ) .
THEOREM 3.2.
then
PROOF. Let (x,y) = ( 0 , O ) . If 0 0 0 = { O l , the proposition is trivial because it is sufficient to assume as f the identity. ar), it is enough to assume as f an application such If N,(O,O) = {a,, r, f(ai) = i. that f(0) = 0 and Yi = 1, From this and from theorems 2.3 and 3.1, the proposition follows by induction.
...,
...,
4. Q U A S I - M I N I M HYPERGROUPOID Let H be a hypergroupoid on the set
{O,l,
..., n -
I}.
D E F I N I T I O N 4.1. H is said to be 0-minimal (zero-minimal) if and only if H E W (0 0) E H 2s' and WH'EC+[QO) such that H' is isomorphic to H, VH ( 0 ) ( V H I ( 0 ) . If O < ~ H, said to be p-minimal if and onty if
(i) HEC+c-(Y,Y)
(ii) H G
(iii)
(7
'
- 1)-minimal,
(F)
(y).
HI satisfactory to (i) and (ii), V,, 'VHI His said to be quasi-minimal if and only if it is (n-l)-minimal.
Y
THEOREM 4.1.
Every minimal hypergroupoid is quasi-minimal.
F
PROOF. Let H be minimal and not quasi-minimal. Let be the - minimum element of H such that H is not y-minimal. i.e. that V ~ E H: y < y , H is y-minimal, but
not $-minimal.
310
R. Migliorato
If H€C+k(%T), then there exists an isomorphism f:H ->HI which leaves unchanV ( 7 ) . But that ged all hyperproducts x o y with x’y
This As only If into
(x,y)
<(X,y), x
-:t
y
=
xoy
(it =
hyperoperation in HI)?
is absurd since H is supposed to be minimal. a consequence of the theorem just now proved, WH, MIN(H) is to be sought among the hypergroupoids which are quasi-minimal and isomorphic to H. we call minimal isomorphism of H every isomorphism which transforms H a quasi-minimal HI, from theor. 4.1 it follows that
COR0LLARY.A quasi-minimal hypergroupoid H is minimal if and only if every minimal isomorphism transforms H i n a hypergroupoid H i such that HIHI.
REFERENCES [l] M. KOSKAS, Groupoides, demi-hypergroupes et hypergroupes et Appl., 49 (19701, pp. 155-192.
, J. Math. Pures
[2] p. CORSINI, Ipergruppi semiregozari e regolari,Rend. Sem. Mat. Univ. Torino, (1982), pp. 35-46.
[3] R. MICLIORATO, Una c l a s s e di semi-ipergruppi e di ipergruppi, Mat. Fis. Univ. Modena, XXXI, (1982), pp. 123-141.
Atti Sem.
[4] R. MIGLIORATO, Ipergruppi d i cardinalitd 3
P isornorfisrni d’ipergruppoidi Atti Convegno s u Ipergruppi, semi-ipergruppi e altre strutture multivoche, Udine (19851, pp. 131-136.
t..r.‘,
[ g M. DE SALVO, Ipergruppi finiti di lunghezaa costante, Rend. 1st. Lomhardo, Accad. Sci. Lett. Sez. A, 120, (1986), pp. 41-56.
Annals of Discrete Mathematics 37 (1988) 311-314 0 Elsevier Science Publishers B.V. (North-Holland)
311
S E M I N V E R S I V E PLANES
Domenico Olanda D i p a r t i m e n t o d i Matematica ed a p p l i c a z i o n i " R . C a c c i o p p o l i " Via Mezzocannone ,8 - 80134 N a p o l i (ITALY):
,
Seminversive p l a n e s a r e d e f i n e d and i n v e s t i g a t e d . I n t h e f i n i t e case such a p l a n e i s e i t h e r an i n v e r s i v e p l a n e o r a p u n c t u r e d i n v e r s i v e plane.
1. INTRODUCTION An H - s e m i a f f i n e p l a n e C11, where H i s a f i n i t e s e t o f non-negative i n t e g e r s , i s a f i n i t e l i n e a r space (P,L) such t h a t f o r any n o n - i n c i d e n t p o i n t - l i n e p a i r t h e number T(~,II) of l i n e s on p n o t m e e t i n g a belongs t o H.Suppose ( p , II) ( P , l ) i s an H-semiaffine p l a n e and n + l i s t h e maximum number o f l i n e s on a p o i n t . Then t h e i n t e g e r n i s c a l l e d t h e order of t h e p1ane.H-semiaffine p l a n e s have been i n v e s t i g a t e d by s e v e r a l a u t h o r s ; here i t t u r n s o u t u s e f u l t o r e c a l l t h e f o l l o w i n g theorem due t o O e h l e r [31 c o n c e r n i n g { 1 , 2 } - s e m i a f f i n e p l a n e s . THEOREM 1.1. Suppose ( P , l ) i s a I 1 , Z I - s e m i a f f i n e p l a n e o f o r d e r 1125. Then one the f o l l o w i n g holds : ( i ) (P,L) i s an a f f i n e p l a n e o f o r d e r n ; ( i i ) ( P , l ) i s a p u n c t u r e d a f f i n e p l a n e of o r d e r n ( i . e . an a f f i n e p l a n e w i t h one o f i t s p o i n t s d e l e t e d ) ; ( i i i ) ( P , L ) i s an a f f i n e p l a n e o f o r d e r n from which one l i n e and a l l t h e p o i n t s on i t have been d e l e t e d . T h i s paper p r o v i d e s an a p p l i c a t i o n o f t h e above theorem. We s t a r t w i t h t h e following D E F I N I T I O N . An H - i n v e r s i v e p l a n e , H a s e t of p o s i t i v e i n t e g e r s , i s a p a i r (n,C) where n i s a s e t o f points and C a f a m i l y o f s u b s e t s o f Q , c a l l e d circZes such t h a t 1.1. any t h r e e d i s t i n c t p o i n t s l i e on a unique c i r c l e ; 1.2. g i v e n a c i r c l e B , a p o i n t X E B and a p o i n t y e B , t h e number o f c i r c l e s t h r o u g h x and y m e e t i n g B j u s t a t t h e p o i n t x belongs t o H. 1.3. t h e r e e x i s t a t l e a s t two c i r c l e s and e v e r y c i r c l e c o n t a i n s a t l e a s t t h r e e points.
O b v i o u s l y , when H = {l} i n v e r s i v e p l a n e a r e recovered. I n t h i s paper we s h a l l i n v e s t i g a t e t h e { 1 , 2 l - i n v e r s i v e planes, we c a l l seminversive pZanes under t h e assumption Q i s f i n i t e .
*
Work supported by N a t i o n a l Research P r o j e c t on " S t r u t t u r e Geometriche, o f C.N.R. Combinatoria l o r o a p p l i c a z i o n i " o f I t a l i a n M . P . I . and by G.N.S.A.G.A.
D.Olundu
312
Suppose (n , C) i s a f i n i t e s e m i n v e r s i v e p l a n e and s e t n + l = I ( B I , B E C l T h e n t h e i n t e g e r n i s d e f i n e d t o be t h e order o f t h e p l a n e . C l e a r l y , t h e removing o f one p o i n t f r o m a f i n i t e i n v e r s i v e p l a n e o f o r d e r n r e s u l t s i n a s e m i n v e r s i v e p l a n e o f o r d e r n. We s h a l l show t h a t t h e converse i s a l s o t r u e ; namely we s h a l l prove t h e n e x t
THEOREM 1.2. Suppose ( 0, C ) i s a f i n i t e s e m i n v e r s i v e p l a n e o f o r d e r n >5.Then, ( a, C ) i s e i t h e r an i n v e r s i v e p l a n e o r a p u n c t u r e d i n v e r s i v e p l a n e o f o r d e r n. 2. SOME PROPERTIES OF THE FINITE SEMINVERSIVE PLANES.
( n, C ) always denotes a f i n i t e s e m i n v e r s i v e p l a n e o f o r d e r n >5. For any p o i n t , l e t a x = ( nX, C, ) be d e f i n e d a s f o l l o w s : R X =n - { X,Cx I =t B - { X I , B E C , X E B } T a k i n g i n t o account 1.1 and 1.2 , a x i s a { 1 , 2 } - s e m i a f f i n e p l a n e f o r any p o i n t x . L e t B, be a c i r c l e w i t h n + l p o i n t s and x, one o f them.
XER
.
has o r d e r n. L e t y be a p o i n t o t h e r Obviously, the {1,2}-serniaffine plane a XO t h a n x, s i n c e t h e c i r c l e s t h r o u g h x, and y correspond t o t h e l i n e s on y i n t h e p l a n e a x , whose o r d e r i s n t h r o u g h y t h e r e passes a t l e a s t one c i r c l e o f l e n g t h n + l . Consequently , a l s o t h e p l a n e a y has o r d e r n. Hence, t h e i l , 2 1 - s e m i a f f i n e planes a x a l l have t h e same o r d e r n when x ranges o v e r ; furthermore, a l l those p l a n e s a r e o f t h e same t y p e ( i ) , ( i i ) o r ( i i i ) ( c f r . t h e o r e m l . l ) , as / n / = / a X /+1 O b v i o u s l y , t h e n e x t r e s u l t h o l d s .
.
PROPOSITION 2.1. Iff o r any X E , ~ a x i s an a f f i n e p l a n e o f o r d e r n ( R, C) i s a f i n i t e i n v e r s i v e p l a n e o f o r d e r n.
,
then
T h e r e f o r e , assume ( n, C ) i s n o t an i n v e r s i v e p l a n e t h a t i s , f o r any p o i n t x , t h e p l a n e a x i s e i t h e r a p u n c t u r e d a f f i n e p l a n e o r an a f f i n e p l a n e w i t h one o f i t s l i n e s d e l e t e d . Under these assumptions, s i n c e ax i s a { 1,2 } - s e m i a f f i n e p l a n e o f o r d e r n , a l l t h e c i r c l e s t h r o u g h x , w i t h x d e l e t e d , have e i t h e r n - 1 o r n p o i n t s . Consequently, P R O P O S I T I O N 2.2. On a c i r c l e o f ( n, C ) e i t h e r n o r n + l p o i n t s l i e . I n what f o l l o w s a c i r c l e w i l l be r e f e r r e d t o as a short o r a long c i r c l e according t o i t s having s i z e n o r n+l. L e t x and y be any two d i s t i n c t p o i n t s . The c i r c l e s on x and y a r e p r e c i s e l y t h e l i n e s on y i n t h e p l a n e e x ; t h u s t h e y number n + l . By ( 1 . 1 ) these c i r c l e s w i t h t h e p o i n t s x and y d e l e t e d , p a r t i t i o n n - { x , y } . Denote A and A t h e number o f s h o r t and l o n g c i r c l e s on x and y r e s p e c t i v e l y ; t h e n
I n case / R / = n (2.2)
2
I f / n / = n -n+l , i . e . l i n e s deleted , then
(2.3)
+ A = n+l.
A
, i . e . f o r any A = 1
x
, ax i s a punctured , A=n.
f o r any p o i n t x
A = n
,
,
ax
a f f i n e plane,
i s an a f f i n e p l a n e w i t h one o f i t s
A = 1.
2 Assume In I = n - n + l and c o u n t i n two ways t h e p a i r s ( {x,y) x , y ~ L , L a long c i r c l e ; then ,
,L
) , xfy,
Sem inversive Planes
313
(2.4) 2 where 2 ' i s t h e s e t o f a l l l o n g c i r c l e s . By ( 2 . 4 ) , n + l d i v i d e s ( n - l ) ( n - n + l ) hence n55. S i n c e n>5 i s supposed, t h e f o l l o w i n g i s proved.
PROPOSITION 2.3. 1. 2.
I
I=
If
(a, C )
i s a f i n i t e seminversive plane o f order n
,
, then
n
nL , t h r o u g h any two d i s t i n c t p o i n t s a u n i q u e s h o r t c i r c l e passes.
n
PROPOSITION 2.4. Through any p o i n t n + l s h o r t c i r c l e s pass. P r o o f . F i x any p o i n t y and c o u n t i n two ways t h e p a i r s ({x,y}, S ) , x f y , x , y ~ S , S a s h o r t c i r c l e . Thus n2 -1 = I B y l ( n - l ) where B~ i s t h e s e t o f a l l s h o r t c i r c l e s on y. The statement f o l l o w s . L e t A denote any symbol and (no C), be d e f i n e d by a,= a u I A } , C, c o n s i s t s o f a l l l o n g c i r c l e s o f C and a l l t h e s h o r t ones t o which A has been added. PROPOSITION 2.5. (a,, C), i s an i n v e r s i v e p l a n e o f o r d e r n. P r o o f . Through any t h r e e p o i n t s i n a, t h e r e passes a unique c i r c l e as a XEB, y @ B . consequence o f 1.1 and p r o p o s i t i o n 2.3 , 2. L e t B be a c i r c l e o f C, We must show t h a t t h e r e e x i s t s a u n i q u e c i r c l e , say D, t h r o u g h x and y which meets B e x a c t l y a t t h e p o i n t x. Assume B i s l o n g and f o r any X ~ E B, x j # x , denote L j t h e unique c i r c l e s t h r o u g h y, x, x j . Such c i r c l e s number n , any two o f them a r e d i s t i n c t and a l l meet B a t two p o i n t s . S i n c e n + l c i r c l e s pass t h r o u g h x and y (even i f y=a, c f r . p r o p o s i t i o n 2.4) , t h e s t a t e m e n t i s t r u e . I f B i s s h o r t and xf A t h e same argument a p p l i e s . I f x=A , then, f o r any x j # A , t h e unique s h o r t c i r c l e L j t h r o u g h y and x j meets B a t two p o i n t s . S i n c e t h e r e a r e n + l s h o r t c i r c l e s on y , n o f which a r e secant, t h e s t a t e m e n t f o l l o w s . S i n c e t h e p l a n e (n , C) i s o b t a i n e d d e l e t i n g one p o i n t f r o m t h e i n v e r s i v e p l a n e (a,, C,) , theorem 1.2 i s proved. REFERENCES Beutelspacher, A. and Meinhardt,J., On f i n i t e h - s e m i a f f i n e planes, Europ.J.Comb. 5,(1984) pp. 113-122. C21 Dembowski,P. , F i n i t e geometries, S p r i n g e r V e r l a g (1968). 131 Oehler, M., E n d l i c h e b i a f f i n e inzidenzebenen , i n : Geom.Ded.4,(1975
[13
n
This Page Intentionally Left Blank
Annals of Discrete Mathematics 37 (1988) 315-356 0 Elsevier Science Publishers B.V. (North-Holland)
315
GEOMETRIC AND ALGEBRAIC HETHODS IN THE CLASSIFICATION OF GEOMETRIES BELONGING TO LIE DIAGRAMS
Antonio PASINI University of Siena. Department of Mathematics. Siena. ITALY. In this paper we qive a survey of what is presently known on Tits geometries with Lie diaqrams.
1.
INTRODUCTION
The paper is divided into two Darts.In Part I no finiteness or thickness assumption is made. This part does not contain any new result other than those qiven in [481 and121 .But we have tried to exploit elementary methods as far as we could. In particular, we use coverings only for E 6 , E 7 and E
8'
We avoid them for all other
diagrams. Part I1 is devoted to the finite thick case and mainly to the As to A ,D and E all seometries belonging diaqrams C and F n 4' n n 6' to any of these diaqrams are buildings ( P a r t I of this uaper), so we have nothinq else to say about them in Part TI. Some problems are proposed at the end. The reader is referred to 1 4 8 ~and 141 for all definitions and basic results concerning Tits-Buekenhout qeometries, diagrams, chamber systems and coverings. All geometries considered here are residually connected (hence, stronqly connected by L71). Given a qeometry
r
,we denote the incidence relation and the tyne function
of T by the symbols :: and 0 and an element x of
r
T
respectively, as in L481. Given a type
,the svmbolo
0
(x) denotes the 0-shadow of
x (see L41). Here is the list of irreducible Lie diaarams:
A . Pasini
3 16
-----a
(n nodes, n 2 1 )
An
--
‘n D n E 6 E
(n nodes, n 2 2 )
b---o----d (n nodes, n 2 4 )
7
E
8
F
4
G2 ( 6 )
G2 (8) Lie diaqrams are joins of irreducible Lie diaarams. They correspond to finite thick buildinas (see C471 and “lo]).
We recall
that a qeometry with a disconnected diaqram is the direct sum of irreducible subaeometries correspondina to the connected components of its diaaram (see [41 and C481). S o only irreducible diaqrams are worthy to be studied,in a qeometric approach. We are not interested in the rank 2 case here. So, we shall not consider the diagrams G (6) and G2 (8). 2
2.
PART I. THE GENERAL CASE
Exploitinq elementary methods we shall deal with linear spaces and some other qeometries which are not of Coxeter type. So,we have to recall some conventions and definitions on those qeometries.
-
We use the symbols L and as in r31 and [41 to denote the class of linear spaces and the class of partial planes,respectivelv. Given a aartial plane P, a set X of points of P is a s u b s p a c e if every line which is not contained in X meets X in at most one aoint. Given a set X of points of P, the subspace
2
s p a n n e d by X is the smallest subspace
of P containing X. A linear space L is a l i n e a r p l a n e if, given any three non collinear points of L , they span the set of all
317
Classification of Geometries Belonging to Lie Diagrams
points of L . F7e denote the class of linear planes by the symbol
LO
Affine Dlanes of order qreater than 2 and projective planes (even degenerate ones) are obvious examples of linear planes, whereas affine planes of order 2 (i.e. complete qraphs on 4 vertices) are not such. Still, the system of points and lines of a matroid o f dimension > 2 is a linear space but not a linear Dlane. Given a qeometry L
r
belonqins to the followina diaaram
L
L -.c o -..
0
0 (n
> -
2
1 3;
3
O,l,
- - -- -
. . .n - 1
L ~
T
I
7T
. Q :
n-4
n-3
n-2
n-1
denote types)
elements of type 0 are called p o i n t s , those of type I l i n e s acd those of type 2 p l a n e s . TWO points are c o l l i n e a r if there is a line incident with both of them. If two points a and b are collinear then we write a
1 b.
If n
>
3 , then elements of type n-1 are cal-
led m a x i m a l s u b s p a c e s if their residuesbelona to the diagram L
L
0
0
1
-
L _. -----o---o
2
n-3
n-2
otherwise they are called h y p e r l i n e s . This terminoloqy is a mixture of that used in r481 and the one that is usual for polar spaces. In particular, in the case of C those elements called hyperlines n in C481 are called maximal subspaces here. In the case of a geometry r belonging to D the hyperlines of r in the meaning of t481 n ::0 are the maximal subspaces of the 0-linearization r of I'. In the case of F4,E6,E C481. If
r
7
and E8 our terminoloav is consistent with that of
is a aeometry belongins to E6,E7 or E 8 , the hvperlines
and the maximal subspaces of
r
in the usual meaninq (that of 1481)
are precisely the hyperlines and the maximal subspaces of the 0-linearization
r
::0
of
r,
in our meaninq.
We have mentioned 0-1inearizations.The reader is referred to E251 for the definition of the 0 - l i n e a r i z a t i o n
r
::0
o f a geometry
r.
We
warn that the Intersection Property of C41 is assumed in 1257, but it has not any essential role in that definition (see c261). Let
r
be still a qeometry belonqins to the above diaqram.Let us
assume that the I n t e r s e c t i o n P r o p e r t y
(IP) holds in
(the reader
A . Pasini
318
can see 141 for the satement of that property). Then it is easily seen that the following Droperties hold in (LL) G i v e n a n y t w o p o i n t s ,
r:
t h e r e is a t m o s t o n e l i n e t h r o u g h t h e m .
(LH) G i v e n a l i n e x a n d a h y p e r l i n e u, . i f /oo(x)nuo(u)1 > - 2,
then
we h a v e x :: u.
(HH) G i v e n h y p e r l i n e s u,v a n d p o i n t s a,b s u c h t h a t a ::
a, i f a # b a n d u # v, t k e n a
::
u
::
b
::
v
::
1 b.
(we note that Theorem 7 of [31 is needed in order to prove (HH); see also Proposition 1 of the next paraqraph).
2.1.
The diaqram A
n
.
The followinq result is well known
THEOREM1, ( T i t s
C481,Proposition 6 ) . G e o m e t r i e s b e l o n g i n g
to A
n
a r e p r e c i s e l y n-dimensional g e n e r a l i z e d p r o j e c t i v e g e o m e t r i e s ( h e n c e , b u i l d i n g s of t y p e A 1 . n The proof of this statement is quite elementary. It essentially
consists of two steps. We briefly recall them.
.
Given any two points of r there is n just one line through them. This is proved by induction on n. So,
F i r s t s t e p . Let
r
r
belonq to A
forms a linear space. Moreover, 0-shadows are subspaces. This is
proved aqain by induction on n. At this stage it is easily seen that 0-shadows uniquely determine those elements of which they are shadows and that incidences between elements of
r
can be viewed as
inclusions of shadows as follows: qiven two elements x and y, we have u (x)C a ( y ) iff x 0
0
::
y and
T
(x) 5
T
.
(y) Moreover, intersections
of shadows are still shadows. So ‘I can be viewed as a system of subspaces of a linear space, closed under arbitrary intersections. S e c o n d s t e p . Now we can easily see that the system of subspaces
constructed above is actually the system of all proper nonempty subspaces of an n-dimensional qeneralized projective geometry G . Showing this amounts to prove that the so-called ‘trianqle axiom’ holds and that all subspaces of S actuallv occur as 0-shadows in
r.
All details of this proof are left to the reader.
n
Classification of Geometries Belonging to Lie Diagrams
3 19
It is worthy of mention that we can Drove the followinq more qeneral result by almost the same araument:
~RoposITIoN 1,
(Buekenhout C31,Theorem
t h e f o l l o w i n g diagram
L
L 0-
----
7 ) . Geometries belonging
-
to
L
__o
are p r e c i s e l y n-dimensional matroids.
Actually Theorem 1 is a trivial corollary of this Proposition. We warn that the Intersection Property is assumed in 1 3 3 . But the proof of Theorem 7 of 131 does not make any essential use of that property. The diagram C n'
2.2.
Let us start from a more qeneral diagram related to b o u q u e t s of matroids
r
Let
(in the meaninq of Deza and Laurent C91) L L L T - __--- * 0 1 2 n-3 n-2 n-1
be a qeometry belonqing to the diaaram above. Let us consi-
der the followinq property (LL) res
The property
(LL) h o l d s i n
r
f o r e v e r y f 2 a g F of
r
and i n t h e r e s i d u e T F of F,
...ij
of t y p e { O , l ,
(1
5
i 5 n-4).
We have the followinq
PROPOSITION2 ,
The g e o m e t r y
r
i s a b o u q u e t of m a t r o i d s
Ihence,ihe
I n t e r s e c t i o n P r o p e r t y h o Z d s i n i t ) if and onZy i f t h e p r o p e r t y
(LL)res h o l d s i n
r.
The "only if" part is trivial.The "if" part can be moved by induction on n exploitinq Proposition 1 and mimicking the first step of the proof of Theorem 1 . The main point of the proof is to show that, qiven any two elements x,y of
5
T
r,
we have x :: y and
(y) if u o (x)& u 0 (y). Assume that uo(x)
c u 0 (Y) . -
T ( X )
5
Take a point a
in u0(x). Given a line z incident with a and x and a point b in z , we have b
r
::
y because b
::
x and
IJ
0
.
(x)c u 0 (y) Let z ' be the line
incident with both b and a (see Proposition 1 ) . We have z = Y = z ' by (LL). Then z :: y. So u (a,x)( l u l (a,y). Solwe can apply the 1 in
A . Pasini
320
induction hypothesis on
ra
(by (LL)res) and we have the conclusion.
From now on everything is easy. All details are left to the reader. U
Proposition 2 already appears for C in C251 (Lemma 2) and C271 n (Proposition 4 ) . It appears also in C91 in a sliqhtly different does not form (with (IP) instead of (LL)res). The property (LL) res appear in L 4 8 1 . Instead of it,the followinq property is considered there : (0)L e t x,y b e e l e m e n t s of t y p e i
x
< n-1 .If a o ( x )
= o
0
(v),then - .
= y.
(note that also this property is a consequence of the Intersection Property). Anyway,we have the following
1, L e t r
LEfnfnA
be a geometry belonging t o t h e f o l l o w i n g diagram
L I T
Lo
0
0
_ _ . ."_
a,
0 The p r o p e r t y
1
(LL),es
2 holds i n
n-3
r
0
n-2
n-I
i f and a n l y i f b o t h t h e p r c p e r t i e s
(LL) a n d (0)h o l d i n it. The property (LL) implies ((LL) and) ( 0 ) because it implies res (IP) by Proposition 2. Conversely,the properties (LL) and ( 0 ) imply (LL)res. This can be proved mimickina the arqument used in C81 (Section 6) to show that,if (LL) and (0)hold in a qeornetry type Cn,then they hold in the residue
ra
7 of
for every point a of
-
r.
Then an obvious inductive arqument qives the conclusion. We have only to be careful in lifting (LL) from I' to residues of points (the property (0)can be lifted to residues of points just as in C481).
Let us see this in detail. Let u,v be planes and x,y dis-
tinct lines through a point a and such that x
::
u
::
y
::
v
::
x.Let
b,c be points on x and y respectively, different from a. Let d be any point in u. The lower part of I'
is a linear plane.So we can find a sequence do,dl,...d = d of points in u such that d 0rd1 m = a,b or c and d belongs to the line in u through d . and d for i 7 k suitable indices j,k < i (this for i = 2,3,...m).we can prove that
di
::
v for i = 2,3,.
U
..m by induction on i. Then v
::
d = d .Indeed, m
Classification of Geometries Belonging to Lie Diagrams
321
let j,k be as above. Let z be the line in u throuah d . and d We 1 k' have d :: v and d :: v by the inductive hypothesis. So,let z' be j k We have z = z ' by (LL). Then di :: the line in v throuah d and d j k' :: v because d :: z = z ' . We are done. Then d :: v. So we have u (u) i 0 U = u o (v). Then u = v by ( 0 ) .Hence, (LL) holds in r . a Let us come to C now. The followinq lemma has been proved in 1 2 8 1 n (Lemmas 1 and 2 of 128'1).
LEMVA2, L e t r
be a g e o m e t r y b e l o n g i n g t o c n _ . . . - _n
0
1
2
n-3
n-2
n-1
Then t h e f o l l o w i n g h o l d :
fi) G i v e n e l e m e n t s x,y o f t y p e i and j r e s p e c t i v e l y , if j
> i+l
t h e n t h e r e a r e a n e l e m e n t u o f t y p e j and an e l e m e n t v of t y p e
j-i-1 s u c h t h a t x
::
u
::
v
:: y .
( i i l G i v e n t w o d i s t i n c t mazimal s u b s p a c e s , t h e r e i s a t m o s t one e l e m e n t o f t y p e n-2 i n c i d e n t w i t h b o t h of t h e m .
Now we are close to get the characterization of polar spaces given in Proposition 9 of C481. But we shall not follow the methods of C481 and we avoid coverings. The followina elementarv lemma allows us to do that. We note that this lemma already appears in L481 (Section 6) for the rank 3 case.
LEMMA3 ,
polar spaces o f rank n are p r e c i s e l y bouquets o f matroids
belonging t o C
.
n Of courserevery polar m a c e is a bouquet of matroids.Conversely,
.
r
be a bouquet of matroids belonainq to C We must show that n I' is a polar space.We have to check axioms (P.I)-(P.4) of Chp.7 of let
1477. Axioms (P.1) and (P.2) are trivial by Theorem 1, The existential part of (P.3) readily follows from (i) of Lemma 3. Let us prove the uniqueness part of (P.3). Let a be a point, u a maximal subspace and v,v' and w,w' maximal subspaces and elements of type n-2 respectively, such that a
::
v
::
w
::
u and a
::
v'
::
w'
::
u. Let us
assume that (v,w) # (v',w'). Then v # v' by Lemma 2,fi.i). If w = =
w' , then a
::
w by the Intersection Property.So a :: u and we are
done. If w # w', let y be the element of type n-3 incident with both w and w' (y is uniquely determined in the residue of u).Let z
A . Pasini
322
be the element of
rV
of tvpe n-2 incident with both a and y and
r V'
let z ' be the analoaous of z in
If z # z ' , then a
::
y by the
Intersection Property. So a :: u and we are done. If z = z ' , then z,w,w' and v,v',u form a proper trianale in the upper part of the residue of y. This is impossible because that part is a qeneralized quadranqle. Axiom (P.3) is proved. We have still to prove Axiom (P.4). We need some preliminary steps. S t e p I . Let a,b,c be pairwise distinct points and x,y,z pairwise
distinct lines such that a
:: z
::
b
::
x
::
c
::
y
::
a. Then there is
a plane incident with all of x,y,z and a,b,c (provided that n
2,
3.
of course). Indeed,let u be a maximal subspace incident with x. If a
::
u, then both y and
z
are incident with u, by the Intersection
Property. So we find a plane as above in
rU .
Let us assume that a
# uo(u). In r
we find a maximal subspace v and an element w of b type n-2 such that z :: v :: w :: u. Similarly we find a maximal subspace v' and an element w' of type n-2 in i"
such y
C
::
v'
::
w'
::
u.
We have v = v' and w = w' by Axiom (P.3) on the pair (a,u). Then x
::
rU .
w in
Then x
::
v. In Tv we find that Dlane which we are
looking for. S t e p 2. Let u be a maximal subspace and let a be a point not inci-
dent with u. Let v and w be the maximal subspace and the element of type n-2,respectively, such that a
Then
uo(w) =
5
0
( u ) n a l , where a1 = {b
The inclusion u (w)C o ( u ) ?I 0
0
v
::
I
::
b
w
1a
::
u (Axiom (P.3)).
and b is a point}.
a1 is trivial. Let us prove the con-
verse inclusion. Let b f oo(u)nal .Let c f u (w). Assume that b # 0
# c . Let x,y,z be the lines throuqh b and c , through c and a and through a and b respectively. If two of them coincide, then they are all equal by the Intersection Property, so we have the contradiction a
::
u. Then they are pairwise distinct. Then there is a
plane p incident with all of x,y,z and a,b,c (Step 1 ) . If n then p = v and w = x by Axiom (P.3). S o b
::
be a maximal subspace and an element of type n-2 in p
::
v'
::
w'
We have a x
::
::
::
u (recall that x
v'. Then v
w. Then b
::
=
::
=
rX
such that
u by the Intersection Property).
v' and w = w' by Axiom (P.3). We have
w. We are done.
3,
w. If n > 3, let v',w'
Classification of Geometries Belonging to Lie Diagrams
3 23
Now we can prove Axiom (P.4). By induction on n. If n = 2 we have nothing to prove. Assume that n > 2.Assume that any two maximal subspaces meet in some point,by way of contradiction. Let u be any maximal subspace and let a be a point in u. By the inductive hypo-
ra
some maximal subspace v such that u (u)nu (v) 0 0 = {a}. Let us assume that there is some point b such that b 1 a. thesis we find in
Then b # u (u)u u o (v). Let u' ,v' and x,y be maximal subspaces and 0
elements of type n-2 respectively such that b ::
=
v'
::
y
::
u (v)flbl (Step 2). Then a 0
because x n u (u) 0
c
v (Axiom (P.3)).We have u (x) =
1 b.
::
u, y
::
4
::
u'
::
uo(u)Abl
0
x
::
u and b
::
and u,(y)
=
uo(x) U a o ( y ) . S o u ( x ) r \ u ( v ) = $3 0
0 -
u and u o ( ~ ) ~ a o ( ~ 1aI.But ) we have u ( v ' ) A 2
0
# @ according to our hypotheses. Let c f u ( v ' ) A u (u).Then 0
0
Then c f u o (x) (Step 2 ) . Let z be the line throuqh b and c.
The line z is incident with both u' and v', by the Intersection Property. Then it meets u (y) in a point d , different from both b 0
and c (recall that u ( x ) r \ u ( y ) = @ and c :: x) . Of course, we have 0 0 both a c and a d. Then (Step 1 ) there is a plane w incident
1
1
with z and with the lines z d. So b
::
w because b
::
throush a and c and z through a and d z : we have b a in r . But this contra-
dicts the assumption that a
1
b. Then a
1b
W
for every point b.
But the point a ktas arbitrarily chosen. Then any two points are collinear. Then all maximal subspaces are incident with the same set of points, by Step 2 . Then there is just one maximal subspace, by the Intersection Property. We have the final contradiction.
n
Now we can state the followinq
THE ORE^ 2 ,
(Tits C 4 8 1 , P r o p o s i t i o n 9 ) .
g i n g t o C .The geometry
n
properties
(LL) and
r
Let
r
be a g e o m e t r y b e l o n -
i s a p o l a r s p a c e if a n d o n l y if b o t h t h e
(0) h o l d i n i t .
Trivia1,by Proposition 2 and Lemmas 1 and 3.
n
2.3. Non-buildinq qeometries of tyne C and qeometries 2-covered n by polar spaces.
Several examples are known of qeometries of type C which are not n buildings. Some of them are got by free constructions (see r481).
A . Pasini
3 24
Geometries constructed in that way are infinite. A lot of finite non thick examples can be found in 1341 and C391. A l l of them have some thin lines (i.e. lines with exactly 2 points). Geometries of type Cn with some thin lines can be provided also by the construction of 1401. They are not buildinqs provided that some of the qeometries from which we start is not such. Here is another non-buildinq non thick example. It is infinite, but it has thick lines. Example 1. Let
r be
a thick buildinq of type Dn. Here n = 3 is al-
lowed. In that case D
3
is the same as A
3
o<;
Let y be a non special involutory automorphism of fix any flaq of
r
-
r
that does not
(when n = 3 the automorphism y is an involutory
polarity without any absolute element). It is clear that y exists only if the ground field of
r
the ground division ring of
r is
-:: 0
r
be the 0-linearization of
is infinite when n > 3,and only if -
r
an infinite field when n = 3 . Let .The quotient
r
-,.
= r"'/y
is a geo-
metry of type C
that is not a polar space. Anyway, it is covered n -2: 0 by a polar space, namely by the polar space r . Example 2. The construction described above works even if we start
from the Coxeter complex of type D
instead of thick buildings of n that type. In that case we find thin qeometries of tvpe Cn which are proper quotients of Coxeter complexes of type Cn. For instance in the case of n = 3 we qet the quotient of the octohedron by the antipodality relation. This small C 3 qeometry has the followinq feature, which will turn out to be fairly interesting in the forthcoming: all of its points are incident with all of its planes. E x a m p l e 3. A nice thick but infinite example of a non-buildinq C 3
geometry
r
is given in C371,startinq from a hyperbolic quadric Q
in PG(5,R) (where R is an ordered field) and a plane P exterior to Q. The set of planes of
r
is one of the two families of planes of
Q. We take the points of Q as lines of
r
and the points of P as
r . Incidences are defined as follows. A point of Q of r ) and a point of P (point of r ) are incident if
points of
(i.
e. line
they
Classification of Geometries Belonging to Lie Diagrams
325
are orthogonal in the bilinear form defininq Q. Lines and planes
of
r
are incident if they are incident as points and ?lanes of Q.
Every point of
r
is incident with all planes of
r
.Solwe get a C
3 geometry which is not a buildinq: indeed all of its points are incident with all of its planes. Anyway, it can be shown that
r
is
covered by a buildina (see t371). Example 4 ( t h e A - g e o m e t r y ) . 7
The construction described in Example
3 can be rearranqed to aet aeometries of type C
over any field F, 3 replacinq the plane P with a suitable set of points X 'exterior' to Q (see E371),wrovided that such a set exists.We warn that X cannot be a plane if F is not ordered.Lunardon t171 has proved that such sets do not exist when F is a finite field of order # 2 (see also C81 for the case of even characteristic; other partial results in the same direction of 1173 appeared in 1371 and t 4 9 1 . But,when F = GF(Z),such an 'exterior' set actually exists (see
-
1371). In that case we qet a finite thick C3-geometry meters
r
with para-
2 2 2 . The geometry I' constructed in this way has still the pronerty that
each of its points is incident with all of its planes. It is simply connected. So it is not covered by a buildinq.The full automorphism group of A7-geometry.
r
is the alternatinq qroup A
7'
So
j?
is called
It is the only finite thick example of non-buildinq
C -geometry presently known.It apneared firstly in 1191. It can be n characterized in several ways. A uroup theoretic construction can be found in E l l . From that construction we get the followina elementary description. The alternatina aroup has two orbits, each of size 1 5 , on the set of 30 planes that can be drawn on a given set
S of 7 objects. Take one of those two orbits as set of planes, S as set of points and all 3-subsets of S as lines. Define incidences in the natural way. We aet the A -qeometry. 7
We have met the followina property very often in the examples of non-buildinq C3-geometries given above: all points are incident with all planes. More remarkably, that property holds in the only known example of finite thick non-buildina ueometry of tyne C3. So
A . Pasini
326
it deserves a name. We say that a aeometry --,-- - . c.0 1 n-3 n-2 n-I is f l a t if all elements of
r
r
belonaina to C
n
of type less than n-2 are incident
with all maximal subspaces of
r.
aeometries qiven above are so n far from polar spaces. Indeed some of them are quotients of polar Not all examples of non-buildina C
spaces. The following proposition aives us a practical criterion to check whether a C
n
qeometry is a quotient of a polar space
OL
not. b e a g e o m e t r y of t y p e Cn . :"he u n i v e r s a l 2 - c o v e r i n g of T is a b u i l d i n g if and o n l y if all C -2-ePROPOSITION
sidues o f
r
3,
r
( T i t s L481). L e t
3
a r e c o v e r e d by b u i l d i n g s .
This proposition is a specialization of Theorem 1 of C481. The proof is long and hard and it is not possible to qive even a sketch of it here. We prefer to mention two results which can be proved
with the aid of Proposition 3 .
PROPosITIoN
4,
1341). L e t
(Pasini and Rees
Cn and l e t u s a s s u m e t h a t a l l l i n e s of due o f
r
2-covered
r
r
b e a g e o m e t r g o f type
a r e t h i c k and e v e r y r e s i -
of t y p e C 3 i s e i t h e r a b u i l d i n g o r f l a t . T h e n e < t h e r
r
is
by a p o l a r space or i t i s f l a t .
PROPOSITION
5,
(Rees
1381).
r
Let
be a geometry o f t y p e C
n
admit-
t i n g parameters as below
- ---
0-3-
x l'hen
r
is
2-covered
x
x
x
l
(x
=
m
is allowed)
by a p o l a r a p a c e .
Proposition 4 is proved in the followinq way.If all C
3
residues of
r are flat,then r is flat. Otherwise,if there is some C3 residue r ' which is a polar space, then, qiven any flat residue r",we can construct a covering from r ' to r " inside r . So we can apply Proposition 3 and we have the conclusion.
-
Proposition 5 is proved showinq firstly that every C 3 qeometry is a quotient of a polar space as in Exx x l amples 1 and 2 (Rees C381). Then the conclusion follows from
with parameters
Classification of Geometries Belonging to Lie Diagrams
327
Proposition 3. 2.4. The diaqram D . n We give an elementary proof of the followinq result
THEOREM3 ,
(Timmesfeld L461,Lemma
3.3).
A l l g e o m e t r i e s belonging
t o Dn a r e b u i l d i n g s .
r
Let
be a qeometry belonainq to the diagram ---.-
0
1
The C-linearization (LL)res holds in
.* 0 I"'
r"'.
n-I
of
r
belonqs to C - .
I1
Let us prove that
Havinu proved that (LL) holds will be enough
(by an easy inductive argument: indeed we have every point a of of
::0
r
r
(r".,0 ) a
(Ta)::' for
=
).So,let a,b be distinct points and x,y lines
incident with both a and b. In
r'' 0
we can take a maximal
subspace u incident with y. By Lemma 2 there are a maximal subspace v and an element w of type n-2 in the residue
r::O
such that x
::
v
::
w
(r" 0 ) a
of a in
u. But elements of type n-2 of I-''
I'
::
r
is a projective aeometry by Theorem 1. Then x
::
are
rV
of v
u in T
be-
flags of type In-2,n-11 in T.Then v :: u in T.The residue in
0
V
cause both x and u are incident with both a and b and a # b. Then we have x Then
r':'
=
rU.
y in the projective aeometry
So (LL) holds in
is a polar space by Proposition 2 and Lemma 3, and
r" 0
the oriflamme complex of the polar space Hence
r
2.5.
The diagram F
r
r'. 0 . is
(see [471,Chp.7).
is a buildinq.
U
4'
We can still avoid coverinqs. Let us start from the following
LEMMA4,
Let
r
be a g e o m e t r y b e l o n g i n g t o t h e f o l l o w i n g d i a g r a m r
The Intersection Property p r o p e r t i e s (LL), (LH) a n d
L
0 1 2 3 (IP) h o l d s i n r if a n d o n l y if a l l t h e (HH)
hold in
r
.
The "only if" Dart is trivia1.A~ for the "if" part,first of all we observe that (IP) holds in a qeometryr with strinq basic diaqram
328
A . Pasini
if and only if the statement of (IP) holds with respect to the initial node of the diaaram. The proof of this fact is implicit in Theorem 6 of 131. So we have to prove only that the statement of (IP) holds with respect to the type 0. This can be done by elemen-
tary arquments. They are left to the reader.
U
So we have the followinq
THE ORE^ 4,
(Tits 1 4 8 7 , P r o p o s i t i o n 9). A g e o m e t r y
r
of t y p e F 4 is a
m e t a s y m p l e c t i c s p a c e i h e n c e , a b u i l d i n g ) if and o n l y if a22 t h e p r o p e r t i e s (LL), (LH) and (HH) h o l d i n i t .
The "only if" part is well known.Let us prove the "if" part.Assume
r
that (LL),(LH) and (HH) hold.Then (IP) holds by Lemma 4 . Then
is
a system of subspaces in the meaninq of Theorem 6 of 131.It is ea-
sily seen that all axioms qiven in Chp.10 of [471 hold. Then
r
a metasymplectic space by 11.10.3 of L471.
is U
Few examples are presently known of non-buildinq F
aeometries. 4 Some of them are constructed takinq proper quotients of the Coxeter complex of type F
4'
They are thin. Other examples can be con-
-
structed startinq from a non-buildinq qeometry 0
1
and takina the I-linearization
2
r
::1
that 2-coverinqs (or quotients) of
r
of type
C4
3
of
r
::1
r.
It is worth observing
are precisely l-lineariza-
tions of 2-coverinqs (quotients,respectively) of
r.
So,geometries
of type F4 constructed in this way are 2-covered by buildinqs precisely when the C4 qeometry from which we start is such. Of course if we start from polar spaces then we qet metasymplectic spaces. For instance,let
Let -
r ).
r
=
-:: 0
Then
ce of
T
r:'
r
be a buildina of type D
4
r
be the polar space of (i.e.,the 0-linearization of -1 , = . That is, r" is the usual metasimplectic spa-
r. Assume
r':'
that
-
r
admits a non special involutorir automor-
phism y as in Example 3 of 92.3 of this paper. Let us now set r = -., 0 ::1 - --I -::I . = r'. /y . Then r - r'' / y . S o r 1 s the universal 2-covering of
Classification of Geometries Belonging to Lie Diagrams
329
r'. 1 . .I
Anyway,only non thick examples can be constructed in this way.It is worth remarkinq that no finite thick non-building F4 aeometry is presently known. As in the case of C it is interesting to know if a qiven F4 geon' metry is a quotient of a metasymplectic space or not. The following specialization of Theorem 1 of t481 gives us a practical criterion to test that.
PROPOSITION
6, ( T i t s
n i v e r s a l 2 - c o v e r i n g of dues o f
2.6.
r
r
r
be a g e o m e t r y o f t y p e F 4' The ui s a b u i l d i n g i f and o n l y i f a l l C 3 r e s i -
t481).
Let
a r e c o v e r e d by b u i l d i n g s .
The diaqrams E 6,E7 and E8.
We mark types as below n-I
-
o
0
a
n-5
1
n-4
n-3
(n = 6, 7 or 8)
n-2
If
r
is a aeometry belonaina to the diaqram above, then elements
of
r
are said to be p o i n t s , l i n e s , p l a n e s , h y p e r l i n e s
or maximal sub-
spaces accordinq to whether they are such in the 0-linearization
r':'
We say that the proDerties (LL), (LH) or (HH) hold in
of I'.
if they hold in
THEOREM5,
r
r"'.
(Brouwer and Cohen
r21).
A l l geometries o f type E
6 are b u i l d i n g s . A g e o m e t r y o f t y p e E 7 i s a b u i l d i n g if and o n Z y i f t h e
property
(LH)hoZds i n it. A g e o m e t r y of t y p e E8 i s a b u i l d i n g if
and o n l y i f b o t h t h e p r o p e r t i e s
(LH) and (HH) h o l d i n i t .
The proof criven in 121 essentially exploits the fact that the uni-
r
of type E6,E7 or E
is a buil8 dinq (Tits L481,Theorem 1 ) . So,let r be a qeometry of type E 6IE7 or E and let f: r -+ r be 'the' universal 2-coverinq of r. The ae8 ometry 7 is a buildinq. If F is of type E 7 we assume (LH) on r.If
versal 2-coverinq of a qeometry
r
is of type E8 we assume both (LH) and (HH). Let us see the proof
of C21 in detail. First of all we must prove that f induces isomorphisms on the
A . Pasini
330
residues of elements of
r
.This follows from Theorems 1 and 3 and
from the fact that buildinas are 2-connected (Tits L481,Theorem 1 ) in the case of E
6'
The same arqument works in the case of E 7 , pro-
vided that we assume to have alreadv proved that all ueometries of type E 6 are buildinqs. In the case of E8 we must in advance prove that (LH) holds in the residue of every point of r.This can be done exploitina (LH) in I'.Indeed,let a be a point of r,let x,y be distinct lines through a and p and u a plane and a hyperline respectively, both incident with both of x and y. In
r
we see that P every point of x is collinear with all points of y. So the same is true in
rU
by (LH) in T.Then there is a nlane u in
with both of x and y, because residue
r a,x
rU
rU
incident
is a buildinq by Theorem 3. The
of the flaq [a,x} is a building of t p e E 6 (assume to
have already nroved our statement on E ).Then,by a well known pro6
perty of such buildinqs,there is a hvperline v incident with both p and q . But Tv is a buildinq,by Theorem 3. Then we have p
Tv.
So p
::
u. Then (LH) holds in
=
q in
ra.
By the way, the last part of this argument actually proves a little bit more than what we have explicitly stated: namely,it proves that ( L L ) holds in all E7 qeometries. As (LH; holds in r by assumption, f indu8' ces isomorphisms on residues of elements of r,because all buil-
Let us come back to E
dings are 2-connected and all residues of elements of
r
are buil-
dings,either by Theorem 1,or by Theorem 3 , or by that part of the statement of the present theorem that is related to E7, because (LH) holds in residues of points of
r.
So,f is an isomorphism if it is injective on the set of points of r .Now everythinq is as in 5 6 of C481.In the case of E the injec6
tivity readily follows from the fact that,qiven any two points in a building of type E 6 , there is always some hyperline incident with both of them.The 2-covering f induces isomorphisms on residues of hyperlines and we have the conclusion. Let
r
be of type
r
E .Assume that there are two points a,b in such that f(a) = f(b) 7 but a # b. There is not anv hyperline in r incident with both a
and b, because f induces isomorphisms on residues of hyperlines of
Classification of Geometries Belonging to Lie Diagrams ~
r .
33 1
Anyway,taken any hyperline u incident with b, there is a point
c such that a
1c
::
U, by a well known property of E
::
buildings.
f (c) in r u because f induces an isomorphism on I' . Then
Let x be the line in by ( L H ) . Then x
7 throuah
7
a and c. We have f (u)
::
C
both a and b are incident with u. We have a contradiction. A similar argument works in the case of E 8 .
Now we should exploit
the following property of E
buildinqs: qiven a noint a and a hy8 perline u,there are a point b and a hyperline v such that a :: v :: ::
b
::
u. All details are left to the reader. Anyway,the reader can
find them in 5 6 of C 4 8 1 . So far as to the "if" part in the cases of E
7
and E
8'
The "only
if" part follows from the fact that the Intersection Property holds in all buildinqs (Tits C471 ,ChD.l2). An example of a qeometry 7 of type E of a buildinq
r
7
n
that is a proper quotient
is qiven in L 2 1 . The buildinq
the field of complex numbers.Hence,
r
7 is
defined over
is infinite.
The followinq proposition has already been used in the proof of Theorem 5. But we shall need it aqain later.So,we mention it explicitly.
PROPOSITION
D
E E E
( T i t s L481).
,422 g e o m e t r i e s of t y p e E
by buiZdings.
2-covered
A
7,
n n 6 7
8
C
n
F
4
building building building building iff
(LH)
building iff
(LH)
and
(HH)
building iff
(LL)
and
(0)
building iff
( L L ) , (LH)
and
(HH)
7
o r E8 a r e
A . Pasini
332
2.7.
Comments and remarks.
2.7.1.
Attempts have lately been done to describe qeometries of
spherical type with some thin lines in terms of 'products' of small geometries whose types are involved in the diagram of the geometry that has to be described (see C437 and r411). Those attempts develope ideas which already appear in C61 and C401 for Cn geometries. 2.7.2. An approach different from those followed here (namely,the elementary one,for A n,Dn,Cn and F4,and that one which exploits coverings,for E 6,E7 and E ) is used by Ott in t231,and developed by 8
Hillebrandt in 1111. It still uses coverings, but it focuses onto apartments. 2.7.3. Many people will object that we have been wrong in chosing not to put enough emphasis on coverinqs and in particular on Tits' celebrated Theorem 1 of L481. We miqht answer that we just wanted to point out that qeometries with Lie diagrams have so particular properties (because of the very features of their diaqrams) that even the most significant results in diagran qeometry can sorretimes be left in the backaround when we deal with such qeometries.
3.
PART 11. THE FINITE THICK CASE
We recall that a qeometry is t h i c k if each of its flaqs of corank 1 is contained in at least three chambers. Polar spaces qot from
thick buildings of type Dn are not thick in this sense. Anyway, they are 'almost thick': all of their lines are thick (contain at least 3 points).And they are not so much different from thick polar spaces.
So,C
n
geometries with thick lines will be included in
this section.
3.1.
The work by Brouwer and Cohen. The diaqrams E7 and E
THEOREM6,
(Brouwer and Cohen
t y p e E7 o r E8 a r e b u i l d i n g s .
r23).
8'
A Z Z f i n i t e t h i c k geometries o f
Classification of Geometries Belonging to Lie Diagrams
333
The proof depends on a nice result on reqular graphs. Brouwer and Cohen consider finite regular graphs G with certain additional reqularity properties (the reader is referred to C21 for all details). They prove that every fixed-point-free automorphism of G maps some vertex onto a vertex adjacent with it. The methods used by Brouwer and Cohen are similar to those employed by Feit and Higmann in [loll and remind us the usual way to prove that every polarity in a finite projective plane admits some absolute elements. Actually, this latter statement is a corollary of that proved by Brouwer and Cohen. Indeed, if we take points and lines of a finite projective plane and define the adjacency by means of incidences in the projective plane, we get a qraph satisfyinq all properties assumed in ( 2 3 . A polarity of the projective plane is a non identical automorphism of this qraph. Then it maps some vertex onto a vertex adjacent with it. That is, it has some absolute elements. In the case of a finite thick qeometry
r
of type E
7
or E8,the
graph G is the collinearity graph of the universal 2-covering
r
.We already know that
7 is
7
of
a (finite,thick) building (Proposi-
tion 7). Then G has all properties assumed in 121.Then every fixed -point-free deck transformation f o r a 2-coverinq f:
-
r
-t
r
(see
C481) identifies a pair of collinear points. But f cannot identify collinear points. Then every deck transformation for f fixes some points. But f is a 6-coverina in the case of E,,
by Theorems
1,3 and 5 and because buildinqs are 2-connected (L481,Theorem 1 ) .
It is a 7-coverinq in the case of E8, bv Theorems 1,3 and by the statement on E7 of the present theorem (assume to have already proved it at this stage) and because buildinqs are 2-connected. Then a deck transformation is the identity if it fixes some point. Then there is just one deck transformation, namely the identity.So f is an isomorphism. By methods similar to those sketched above for E and Cohen get also the following
0
7
and E e l Brouwer
A . Pasini
334
PRoposITIoN 8 ,
(Brouwer and Cohen
r21).
Let
r
be a f i n i t e geometry
o f t y p e Cn w i t h t h i c k l i n e s o r o f i n i t e t h i c k g e o m e t r y o f t y p e F 4 ' T h e g e o m e t r y r is a b u i Z d i n g i f f i t i s 2 - c o v e r e d by a b u i l d i n g .
In the case of C
it is possible to qive a proof easier than that n exvloitinq only the fact that every sketched above for E 7 and E 8'
polarity in a finite projective qeometry admits some absolute points.Brouwer and Cohen used this arqument in an earlier version of C27.By the way,it will be clear that the same arqument can work even if we replace the finiteness assumption with other assumptions (for instance,that the qeometry is 2-covered by a buildinq defined over an algebraic extension of a finite field),Drovided that they are sufficent to qet the same conclusion on polarities. The proof is by induction on n. If n = 2 there is nothinq to prove. Assume n > 2. Let us assume that we have a 2-coverinq f : r from a buildinq
7 to
r
+
r.Assume that f is not an isomorphism. Then
f must identify two maximal subsnaces u,v of
r, because
f induces
isomorphisms on residues of maximal subspaces (by Theorem 1 and because all buildinqs are 2-connected) .We have
5
0
(u)n ao(v) = @
by the inductive hypothesis and because buildings are 2-connected. such that For every element x of r let @(x) be that element of
Tv
U'
f (x) = f (@(x)) (the element
-
(x) is uniquely determined because f
induces isomorphisms fromr and lement of
7U
U
that the mapping a : x metry
rU .
to Tf (u)). Let a ( x ) be that e-
such that o o ( a ( x ) ) = o0(u)A(@(x))l.The element a(x)
is uniquely determined because
-
7V
+
7 is
a building. It is easily seen
a ( x ) is a polarity in the projective qeo-
It admits some absolute point a. We have a
1 $(a) by
the
definition of a.Then f identifies two collinear points, namely a and @(a). This is impossible. Then f must he an isomorphism.
n
Proposition 8 potentially has a lot of conseuuences. Here are two
of them. CoRoLLARV
1, ( P a s i n i
t281).
Let
r
(n >_ 4 ) w i t h t h i c k l i n e s . L e t u s a s s u m e t h a t is e i t h e r a b u i l d i n g or f l a t . T h e n
cn e v e r y ~ ~ r e s i d uof e r
b e a f i n i t e g e o m e t r y of t y p e
r
i s a polar space.
This result follows from Propositions 4 and 8 and from the fact
Classification of Geometries Belonging to Lie Diagrams
335
that finite flat qeometries of type C with thick lines cannot en xist if n 3.
COROLLARV 2,
r
be a f i n i t e g e o m e t r y of t y p e C w i t h t h i c k l i n n e s and l e t u s assume t h a t e u e q e l e m e n t o f r of t y p e n-2 i s i n c i Let
d e n t w i t h e x a c t Z y two maximal s u b s p a c e s . Then
r
i s a polar space.
Trivia1,by Propositions 5 and 8. 3.2.
The work by Aschbacher. Flaq-transitive locally classical geometries of type Cn and F 4 .
A finite qeometry
r
of type C
3
0
points
lines
planes
is l o c a l l y c l a s s i c a l (or of c l a s s i c a l t y p e ) if residues of planes of
r
r
are desarquesian and residues of points of
are generalized
quadrangles of one of the followinq Chevalley qroupsI or dual of
+
such generalized quadranqles.We include also PR (q)*2 in the fol4
lowing list, even if it is not a Chevalley group (actually,it is not included in the list of tII).Ye do not qive dual examples. Group
parameters
In those cases of isomorphism quoted above,the two isomorphic gruups qive rise to the same generalized quadrangle (up to duality). It is worth mentioning also another (exceptional) isomorphism L
PSp4(3) = PSU4(2 ) . But in this case we qet non isomorphic generalized quadrangles,with parameters (3,3) and (4,2) respectively (the group PSp (3) 4
2
2
PSU (2 ) admits two non isomorphic BN-uairs). 4
A finite geometry of type C
or F 4 is l o c a l l y c l a s s i c a l (or of n c l a s s i c a l t y p e ) if all of its C3 residues are such. Of course,all locally classical finite geometries of type
C
n
have thick lines
A . Pasini
336
and those of type F 4 are thick. In detail, the followina table aives the parameters that can occur toqether with the Chevalley groups that qive rise to buildinqs with those parameters,if such buildings exist. We list also parameters for which no building exists. In that case we write NOTHING in the group column. We shall see later that in those cases no geometry exist at all. We have inserted also the qroup PR
+
2n
( q ) . 2 in this list, even if it is not
a Chevalley group. We omit dual cases for F 4 . By the way, the followinq list gives all finite buildings of type C (n n thick lines and all finite thick buildinqs of type F 1477)
4
.
3 ) with
(by Tits
TP.ELE 2 parameters
(q
is a p r i m e power).
group.
PSU
2n
(q2) 2
PSU2n+l(q
1
NOTHING
PR+ ( q ) * 2 2n
2
2 Eg(q
)
NOTHING
We warn that locallv classical aeometries are usually defined in a way more general than here. But the previous definition is sufficent here, in view of Theorems 7 , 2, 3 and 6.
Classification of Geometries Belonging to Lie Diagrams
337
We have the following
THE ORE^ 7 ,
(Aschbacher 1 1 1 ) . L e t
I? be a f i n i t e 2oca22y c Z a s s i c a 2
g e o m e t r y of t y p e C o r F a n d L e t u s assume t h a t Aut(r) is f 2 a g n 4 - t r a n s i t i v e . Then r i s e i t h e r a b u i l d i n g o r t h e A7-geometry.
The reader is referred to Example 4 of Section 2.3 for the definition of the A -aeometry. Aut(r) denotes the aroup of all special 7
(i.e. type preservinq) automornhisms of .'I
"Flas-transitive" is
the usual way to say 'transitive on the set of chmabers'. The main step of the proof is to prove the statement on C
3'
Asch-
bacher does it considering a counterexample to that statement and getting a contradiction exploiting the classification of flag-transitive subgroups of Chevalley groups by Seitz C441. He exploits that classification several times and his proof is not completely elementary. I aive a sketch of a more elementary proof here. The reader can find all details in 1331. Given a point a and a line or a plane x, let B(a,x) be the set of all lines (planes,respectively) in linear) with x in (::)
ra .
The stabilizer G
ra
that are not coplanar (col-
We have the followinq
a
of a in Aut(r) acts transitively on B(a,x).
We can prove this usinq Seitz's Theorem t441 (and this is the only step where we really need that theorem).Here are the only two exceptional cases to examine (by 1441) : ( 1 ) The residue
ra
of a is of type PSD4(2) and Ga acts as A 6 on it.
(2) The residue Fa of a is of type Psp ( 3 ) and the action of Ga on 4 2 it is either that of the stabilizer L in PSU (2 ) of a line of 4 2 the polar space of PSU ( 2 ) , or that of L . 2 . 4 In all other cases (::)
follows from the fact that all classical
generalized quadrangles are Moufang. In Case ( 1 ) the statement follows from the action of A
6
(::)
on residues of points in the A -qeo-
metry. In Case ( 2 ) the actions on
ra
7
and Tu of the stabilizer in
Aut(T) of a point-plane flaa (a,u) do not fit toqether. Then, Case (2) cannot occur.Then (::)
holds. Now, by elementary qeometric
arguments, we can prove the followinq:
A . Pasini
338 (::::)
Let
r
be a finite ueometry of type C3 with thick 1ines.Let us
assume that Aut(T) is flaq-transitive and that
(::)
holds.Then
either T is a buildina or it is flat with unifor Farameter 2 0 -
2
2
2
Now we can aet the conclusion in two ways.Either we recoqnize the
A -qeometry inside our qeometry exploitinq the flaq-transitivity 7
of Aut ( r ) ,or we use the followinq result by Rees C361 : the A. -qeo7
metry is the only flat qeometry with uniform parameter 2. Aschbacher uses aaain Seitz's Theorem in the case of C (n L 4 ) n and F 4 . Anyway, the statement on C (n 4 ) easily follows from n that on C and Corollary 1 of 93.1 of this paper. The statement on
>
3
F
4
can be proved exploitinq that on C
proved in L271
( 5 5 ) : let
and the following statement 3 be a finite thick peometrv of type F
r
4
with uniform parameter 0-
x
0
x
x
x
Then there is a point-hyperline flaq {a,uj such that both
ra
and
Tu are buildinus. Then all C residues of r are buildinqs bv the 3 flag-transitivity of Aut(r). Then r is covered by a buildinq by Proposition 6. So,it is a buildinq, by Proposition 8.
+
The case related to PR2n(u).2 is not considered in C11,and it cannot be settled by Seitz's Theorem. Anyway,it has already been settled in Corollary 2 of this paper.
I 3
3.3. The diaaram C3. Representation theory. Propositions 3, 6 and 8, Corollary 1 , the proof of Corollary 2 and that of Theorem 7 show that havina qot information about C3 residues is often enough to describe qeometries of type C
or F 4 . So, n we will focus ourselves onto C3 seometries.we have already observed that the A -qeometry is flat. So, Theorem 7 and the fact that 7
the A -qeometry is the onlv example of non-buildinq finite thick 7 geometry presently known suaaest the followinq conjecture: CONJECTURE
1, E v e r y
f i n i t e g e o m e t r y of t y p e C3 w i t h t h i c k Z i n e s i s
e i t h e r a b u i l d i n g o r flat.
Classification of Geometries Belonging to Lie Diagrams
339
If this conjecture were true,then all finite qeometries of type C n (n 2 4 ) with thick lines would be buildinqs,by Corollary 1. A concrete araument in support of Conjecture 1 is given by Ott in 1221. He proves that Conjecture 1 is true in the case of finite
-
geometries of type C3 admittinq uniform parameter x
x
x
(x a n y p o s i t i v e i n t e g e r )
Unfortunately we are not yet able to prove Conjecture 1 in the qeneral case. Representation theory has been reqarded as the main instrument to use in this inquiry. Anyway, it is the only one that we have nowadays, beside all kinds of seometric tools that we are able to invent,of course. That theorv has been developed by Hoefsmit 1121, Ott I201 and C211 and Liebler [I51 (and Curtis,Iwahori, Steinberg and others,before them).Here we recall only its basic ideas. The reader is referred to C201, C211, C221, [I51 and I123 for all details. Given a finite qeometry 'I over a set of types I, admitting parameters x
i
( i r I ) and belonginu to a Coxeter diagram of matrix
let us take the set C of all chambers of
r
as a basis for a vector
space V over the field of complex numbers. For every type i f 1 , l e t of V defined as below: i means 'i-adjacent')
us consider the endomorphism @ Qi(C) =
>z.
D
(C*C,
D k c (ifI) toqether with the identitv matrix 1 i qenerate a subalqebra E ( r ) of Hom(V,V),called Hecke a l g e b r a of r .
The endomorphisms @
It is worth observinq that the followinq relations hold in H(T):
(1)
We have
=
x.1 1-
+
(xi-l)bi
(for every i f I ) .
(2) We have (@.@,)mij = 1 (for every choice of i , j e I , i # j). 1 1 The Hecke alqebra of r is semisimDle (see C201).In the case of C
-
X
X
Y
(x,y
3
are parameters)
it is possible to compute all multiplicities of irreducible representations of H ( r ) explicitly,startina from the Darameters x,y and another number a ,called O t t - L i e b l e r number of
r,
which we shall
describe in a moment. Ten distinct possible irreducible
A . Pasini
3 40
representations of H(T) exist. They correspond to double partitions of the set [0,1,2) of types of
r
(see El51 and C121).Here is
the complete list of their multiplicities.It has been found by Hoefsmit 1121 at first,althouqh not exactly in the form qiven here, but in an equivalent form.
TABLE 3 Representation (shortened name)
Multiplicity
3/ O
1 2 3 (l+x y) (l+x) (x + a ) x (x+y)f l+a) 6 2 (l+xy) (l+x y ) (x + a )
13 / 0
2/1
12/1
1/12 1/2
o/ 1
3
0 / 3
2
(x +y) (x+y) (l+a) 2 2 (l+x+x ) (l+xy)(x y-a) x tx+y) (l+a) 2 2 4 ( I + X y) (l+x+x ) (x y-a) 2 x(x +y) ( l + a ) 4 2 2 (l+xy) (l+x+x ) ( x y + a ) x(x+y) ( l + U ) 2 2 2 2 (l+x y) (l+x+x ) (x y + a ) 2 x(x +y) ( l + a ) 6 3 x y -a 1 +a 2 3 3 (l+x)(l+x y ) (x y - a ) x (x+y) f l+a) 2 3 (l+xy) (l+x y) (y - a ) 2 (x+y)(x +y) (l+a)
Of course,some representation could disanpear in some concrete ex-
amples, that is,it could have multiplicity 0. This hapnens if and only if the set of relations ( 1 ) and ( 2 ) above does not give a presentation of H ( r ) in those cases.Some of the representations listed above are better known under special names.So, 3/0 is the 3 i n d e x r e p r e s e n t a t i o n , 1 / O is the S t e i n b e r g r e p r e s e n t a t i o n and 2/1 is the r e f l e c t i o n r e p r e s e n t a t i o n . Multiplicities have to be nonneqative inteqers.So,we qet relations
Classification of Geometries Belonging to Lie Diagrams
34 1
between x,y and a which are sometimes sufficent to aet strona conclusions.Unfortunate1y they do not qive us so much in qeneral (see Lemma 6 below). Let us qive the definition of the Ott-Liebler number cx,now.Let I' be any C
3
geometry.Neither the finiteness nor the thickness nor
parameters are assumed for the moment.Let (a,u) be an incident po-
r
int-plane pair in
and let a(a,u) be the number of planes v dis-
tinct from u and such that the line z incident with both u and v does not pass through a (that line is uniquely determined by (ii) of Lemma 2).In 1291 it is proved that the number a(a,u) does not depend on the choice of the incident point-plane pair (a,u).We set cx = a ( a , u ) . c x is the Ott-Liebler number of T.We observe that a has
other interestinq properties. For instance,qiven a non incident point-plane pair (b,v),the number of planes w incident with b and collinear with v is equal to a+l (see 1281; of course,we have cx = =
a+l if a is infinite).Here is another propertv of cx.Given an in-
cident point-line pair (a,z),let b be anv Doint of z distinct from a and let L(a,b) be the number of lines incident with both a and b
and different from z . Then we have (see 1 3 0 1 ) :
a
=
>
R(a,b)
b:: z b#a
More remarkably:
LEMMA5 ,
(Pasini ,1297).
a = 0 i f and o n l y i f L e t u s assume t h a t
T h e n we have a number c x + l
5
r
r
Let
r
b e a g e o m e t r y of t y p e C 3 .We have
i s a building.
-
i s f i n i t e and a d m i t s p a r a m e t e r s X
X
Y
2
x y .We have cx = x y if and o n l y i f 2
2
r
i s fZat.The
2
d i v i d e s b o t h (l+x+x ) (X V+l) and (x y+l) (xy+l)(y+l) and 2
2
2
t h e r e a r e e x a c t l y (l+x+x ) (x y+l)/(a+l), fx.y+l) (xy+l)(y+l)/(a+l) and (l+x+xL)(xLv+l)(xy+l)/(a+l) p o i n t s , p l a n e s
and l i n e s , r e s p e c t i -
vely.
The reader can see C291 for the proof: it is auite elementary (in particular,no use of representation theory is made).The restriction a
5
2
x y can be improved by representation theory.
A . Pasin i
342
L E M ~6, A Let r
be c f i n i t e C
Geometry admitting parameter: 3 "
-0
X
X
Y
and let d be t h e greatest commGn d i v i s o r of x2 and y , a n d m t ; e mi.Then xd d i v i d e s
nirnuv of y3 and x2y
c1
and
CY
;m
.
The first relation is aot by the formulas for the multiplicities
of the representations 1'/1
or 1/2 of Table 3.The second relation
follows from the formula for 0/3 of Table 3.
I1
Lemmas 5 and 6 enable us to settle the case of finite C 3 qeometries with known parameters. It turns out that Conjecture 1 cannot be proved by representation theory even in this case.We recall that a
-
finite C3 geometry has known parameters if it admits parameters X
X
Y
and one of the followinq relations holds between them (i)
x
=
y
(ii)
y
=
x2 or (dually) x
=
(iii) y 2 = x3 or (dually) x2
y2 =
(iv)
y
=
x+2 or (dually) x =
(v)
x
=
1 or (dually) y = 1
y3 17+2
A motivation for this definition is qiven by the fact that,in each of the known examples of finite aeneralized quadranales admittinq
parameters,the parameters satisfy one of the relations listed above (Case (iv) occurs only in non classical examples).We warn that x and y are prime nowers in all known examples satisfying (i),(ii) or (iii) and (x+y)/2 is a prime power in all known examples satisfying (iv).But we do not make such assumptions here.
THEOREM8 , a finite C
(Ott 1221,Rees and S c h a r l a u
3
L421,Pasini
L291). ,et
r
be
geometry with thick lines and known parameters. T h e n
one of the following occurs: (i)
T h e geometry
(ii)
The geometry either
(iiii
x
The geometry
r r x
r
meters as below
is a building.
-
is flat w i t h parameters as below: x
or
t2 t * t3
is neither a building n o r flat,it has p a r a -
Classification of Geometries Belonging to Lie Diagrams
-
343
Y 2 Y2 Y
and we h a v e a = y3.
The proof is nothing but a computation exploiting the information given by Lemmas 5 and 6 on CX,Xand ?.See L291 for all details.The case of x = y has been settled by Ott L221 at first.The cases of 2 2 y = x , y2 = x3 and x = y3 have been examined by Rees and Scharlau L421. The case of y = 1 is alreadv covered by Corollary 1.All other cases are settled in 1221. We warn that no contradiction arises in Case (iii) of Theorem 8 with the formulas of Table 3 : each of them qives us a nice inteqer,whatever y is.We observe also that Theorem 8, toqether with the classification of finite thick
> 3 qiven in L471,im~liesthat no seometry exbuildings of rank ists with parameters x,x,y such that either y = x+2 and x > 2,0r x = y i 2 and y > 2 or x2 = y3 and 1 # x,y.Then,'a fortiori',no qeometry of type C (n 1 3 ) or F 4 exists with parameters as below n
0
0
t-1
t-1
t+l
t+l
( o r dually)
(t
>
3)
Examininq Table 3 we see that,if T is a finite C tinq parameters
2
xTy, then a = x v
3
aeometry admit-
(flat case) and ci = y3 are
the only possibilities to lose some renresentation of H ( r ) . Actu3 ally, a = y is Case (iii) of Theorem 8. We have already observed that no representation is lost if and onlv if the set of relations ( 1 ) and (2) given before presents H ( T ) .Then we have:
COROLLARY 3,
Let
r
b e a f i n i t e C3 g e o m e t r y w i t h t h i c k l i n e s and
known p a r a m e t e r s
The geometry
r
i s a b u i l d i n g i f and onZy i f i t s Hecke a l g e b r a H ( ? )
i s p r e s e n t e d b y t h e f o l l o w i n g s e t of r e l a t i o n s :
2 $i =
xl
+ (x-l)~$~ (i = 0 1 1 ) 1
m22
=
YL +
(~-l)@~,
A . Pasini
344
We have already observed (Lemma 6) that a cannot exceed the mini2
is the minimum of x and y, then xv m2 y is the maximal value for a . Then Theorem 8 can be restated so: XY mum of x y and y 3 . That is, if m
COROLLARY 4 ,
Let
r
be a f i n i t e C
-
known p a r a m e t e r s
X
X
Then e i t h e r a = 0 o r
ci =
g e o m e t r y w i t h t h i c k l i n e s and
3
Y
m2 v ( m a x i m a l v a l u e ) . XY-
The followina lemma gives two geometric characterizations of the class of finite C
geometries that are either buildinqs or flat
3
(that is,where either a = 0 or a = x2y). The first of them will be necessary in the proof of Proposition 9. The other one may be fairly interestinq in itself. It is worth observina that no geometric pro?erty is presently known that is equivalent to the condition a = y3 or to the condition that either
m2 y or a = 0. XY We need some preliminary definiti0ns.A point a of a C geometry ci =
3
r
is homogeneous if,aiven any point b collinear with a and different from a , the number R(a,b)+l of lines through a and b does not depend on the choice of the point b as above. Let us consider also the following weaker versions of (LL) and (LH): (LLl0
Two l i n e s h a v e t h e same s e t of p o i n t s if t h e y h a v e more t h a n o n e p o i n t i n common.
(LH)O If a l i n e z m e e t s a p l a n e u i n more t h a n o n e p o i n t , a l l p o i n t s of z b e l o n g t o u
then
.
We observe that ( L H ) ~is a conseauence of (LL) .We shall not use 0
(LL)* now (we shall refer to it later).
LEMMA7 ,
( P a s i n i ~ 3 0 1 ) .L e t
l i n e s . The g e o m e t r y
r
r
be a f i n i t e C 3 g e o m e t r y w i t h t h i c k
is e i t h e r a b u i l d i n g o r f l a t if and o n l y if
one o f t h e f o l l o w i n g h o l d s :
(i) The g e o m e t r y ( i i l The p r o p e r t y
r
p o s s e s s e s some homogeneous p o i n t . (LH)
0
holds i n
r.
The reader is referred to C301 for the proof.
345
Classification of Geometries Belonging to Lie Diagrams
Trustinq Conjecture 1, we say that a finite
seometry with thick
C3
lines is anomalous if it is neither a buildina nor flat.
PROPPSITION 9,
(Pasini C 3 2 1 ) .
metry a d m i t t i n g parameters be f l a g - t r a n s i t i v e . (il
Let
r
be a n anomalous f i n i t e C3 g e o -
( w h ey re x > xX
I ) and l e t Aut(r)
Then t h e f o l l o w i n g h o l d :
The number x i s e v e n , 1+x+x2 i s p r i m e and x+l
0 (mod.3).
?
L e t d be t h e g r e a t e s t common d i v i s o r of x2 and y . T h e n we have x2-x > y > x > d 2 .y
(ii)
(x-l)d2+d and dx d i v i d e s a.Wo-
r e o v e r , a+
, (x+y)(a+l) and (x2+y)( a + l )
(l+xy)(xy
-
Given a p ane u bilizer G order
,let
-
d
rU
GU be t h e a c t i o n o v e r
o f u in Aut(r).Then
U
-
dx ' a/x) r e s p e c t i v e l y .
-
a/x) and (1+x2y)(x3v
d i v i d e E!L
of t h e s t a -
i s a F r o b e n i u s g r o u p of
(1+x+x2)(1+x) w i t h F r o b e n i u s k e r n e l c y c l i c of o r d e r
1+x+x2 and c y c l i c F r o b e n i u s c o m p l e m e n t s of o r d e r l+x. a c t s r e g u l a r l y o v e r t h e s e t of f l a g s of
rU
and t h o Frobe-
n i u s c o m p l e m e n t s a r e s t a b i l i z e r s of a n t i f z a g s of (iiil
-
GU
rU .
E i t h e r Aut(r) a c t s i m p r i m i t i v e l y o v e r t h e s e t of p o i n t s of
r
or y i s odd.
The reader is referred to [321 for all details of the proof.Here we mention onlv its main ideas. Let GU and
U
be definer5 as above.
By the classification of flas-transitive projective nlanes by Kantor 1141, we qet that either
U
2
PSL(3,x) or (ii) holds, x is
even, 1+x+x2 is prime and x+l : 0 (mod.3). In the earlier case, every point of
r
is homoqeneous.Then that case cannot occur,by
Lemma 7. In the latter case, most of the remaininq part of (i) is got via Table 3, exploitinq the fact that 1+x+x2 is prime.And (i) collects all that Table 3 provides. A s for (iii), it follows from the well known theorem by O'Nan and Scott on Drimitive groupsffrom an analysis of elements of order l+x+x2 and of involutions and Sylow 2-subgroups of Aut(T), from theorems on stronq embeddings of subgroups of finite simple qroups and from the classification of primitive qroups of odd desree (Theorem
C
of t 1 4 1 ) .
It is worth observinq that the arithmetical conditions listed in (i) above seem to be actually incompatible with the well known Bruck-Ryser condition on finite projective ulanes and with the
3 46
A . Pasini
condition that x+y divides xy(xy+l) (see r351). I have tested them by a computer and it has turned out that they never hold toqether if x
5
1 0 0 0 (I stopped computations at x = 1000). We recall also
that it is well known that the statement of (ii) holds on a finite projective plane P of order x < 1600 where 1+x+x2 is prime, only if x is a prime power and either or x
=
P
is non desarguesian or x = 2
8.
The following proposition completes Proposition 9.
PROPOSITION
10, ( P a s i n i
fZag-transitive
x
i
Let
r
be a f i n i t e C3 a u t o m o r p h i s m g r o u p and p a r a m e t e r s 1321).
geometry w i t h ghere
1 . T h e n o n e of the foZLowing h o l d s :
(i)
The g e o m e t r y
(iil
r
iiii)
The g e o m e t r y
r is a b u i l d i n g .
i s t h e A -geometry. 7
r
i s f l a t , x is a p r i m e power p r o p e r l y divi-
d i n g y and e i t h e r y2= x3 or y4= x5
3
w e r . We h a v e x2-x sidue
rU
y i n any c a s e .
or y is not a p r i m e p o -
G i v e n a p l a n e u, t h e r e -
of u is d e s a r g u e s i a n and t h e act-ion on Tu of t h e
s t a b i l i z e r of u i n Aut(T) c o n t a i n s PSL(3,x).
iiv)
?he g e o m e t r y
r
i s a n o m a l o u s a s in P r o p o s i t i o n 9 .
The reader is referred to c321 for the proof and to t 1 8 7 €or all details in the case of x = y. We qive only the main ideas here. Kantor's classification of flaa-transitive projective planes I141 still plays the central role in the proof. Only the flat case has to be examined,of course, and it is proved that the Frobenius case o f Theorem A of [ I 4 1 cannot occur, both if x
=
y and if x
iy
(the
classification of primitive aroups of odd deqree is used aqain here).Then only the PSL(3,x) case survives. Now,if x = y , a Klein quadric and an exterior set can be recognized from
r.
That is,T is
constructed as in Example 4 of 92.3 of this paper. S o , C 1 7 1 can be applied. Then x = 2 and
r
is the A -qeometry by a result of Rees 7
1361. In the case of x < y, it is easily seen that x divides y (this fact has been discovered by Ott 1241 at first,by representation theoretic methods; but it can be proved by elementary methods).From this the remaining part of (iii) easily follows by Table 3.
Classification o j Geometries Belonging to Lie Diagrams
347
The followinq corollaries are trivial consequences of Propositions
9 and 10.
COROLLARV 5 ,
Let T be a finite C 3 geometry with flag-transitive , , w h e r e x > 1 and x y. automorphism group and parameters
>
Y
Then
r
is either a building or the A -geometry. 7
COROLLARV 6, . k t 'I be a finite C 3 geometry with thick Zines,known parameters and flag-transitive automorphism group. Then one of the fo L lowing h o I d s :
(il
T h e geometry
(ii)
r
r
is a building.
is the A -geometry. 7
l i i i l The geometry
r
is fLat and we have x = q 2 and y = q3 where
q is a prime p o w e r . T h e residue
guesian and the action on
ru
of
rU
of any pLane u is desar-
t h e stabilizer in Aut(r) of
u contains P S T , ( ~ , $ ) .
3.4. The diaqrams C
( n _> 4) and F 4 . Known parameters.
n
r
of type C
or F 4 admits known paramen ters if all of its C 3 residues have known parameters.
We recall that a qeometry
PFOPOSITION Cn in
2
11, ( P a s i n i
Let
C311).
r
b e a f i n i t e geometry of type
4 1 with thick lines and known parameters. Then either
-
r
is
a buiZding o r it has parameters as below I - - -3-
Y2 and the relation of
Y2
Y2
c1 = y 3
Y2
Y
holds in at least o n e of the C 3 residues
r.
The proof is trivia1,by Theorem 8 and Corollary 1
PROPOSITION12, ( P a s i n i
~ 2 7 1 ~, 3 1 1 ) .Let
r
be a finite thick geome-
try of type F 4 with known parameters. Then one of t h e following
ho Ids : (i)
The geometry
(iil
The geometry
r r
is a building. has parameters as below
points'2 Y
-
Y 2 Y
Y
hyperlines
( o r dually)
it is n o t a buiZding,aZl residues of points are buildings
A . Pasini
348
and the relation a (iii)
The geometry
r
=
for some hyperline u.
has uniform parameter
I; x-x
points
rU
y3 holds in
hyperlines
it is not a building and all the following hold: (iii.a) Every C
3
residue is either a building or flat and some C
3
residue is flat. (iii.b) Giuen a point-hyperline flag (a,u},at least one of
'I
U
(iii.c) If
ra
and
is a building. V
and w are distinct collinear points or distinct co-
planar hyperlines, then at least o n e of bui lding .
rV
rW
and
is a
The reader is referred to L271 for the proof.It uses Propositions 6 and 8,Theorem 8 and some elementary lemmas stated in L271.
Remark. Because of a mistake made in C151,Liebler excluded Case (iii) of Theorem 8 in L151, so he excluded also the exceptional case of Proposition 1 1 and Case (ii) of Proposition 12. Actually, there is not any way to exclude them by merely rearranqinq arquments from C151,avoidinq that mistake.Liebler Droved in C151 also a relation between parameters of an F
aeometrv, usina the assum-
4 -
ption that all C3 residues were either buildinas or flat (he believed that this was a theorem,as we have remarked above).That relation would force x = 2, if it were true. Unfortunately,the proof by Liebler seems to be wronq. 3.5.
The diaqrams C (n 2 4) and F4. Flaq-transitivity. n
THEOREM9, ( P a s i n i (n L 4 ) with thick geometry
r
Let
r
be a finite geometry of type Cn lines o r a finite thick geometry of type F The ~311).
4'
is a building iff Aut(r) is flag-transitive.
The "only if" part is well known. Anvway, it follows from the classification of finite thick buildings of rank
L
3 by Tits C471. Let
us prove the "if" Dart. Let us see the case of C for the first, n Let u be a maximal subspace of r and let G be the stabilizer of U
u in Aut(r). By Seitz i441 ,either the action of G
U
on
ru
PSL(n,x), where x is the first parameter of r,or n = 4,
contains
r
has
Classification of Geometries Belonging to Lie Diagrams
-
349
parameters as below 2
2
2
(where y
y
=
1,2 o r 4 )
.
on r Anyway, in the latter case the stabilizer 7 U in Aut(T) of a flaa F consistina of point and a maximal subspace
and G
acts as A
U
acts on the projective plane 'I tion 9 fails to hold in C
r
3
as PSL(3,2). Then (ii) of ProposiF residues of T. Then every C residue of 3
is either a buildina or flat, bv Proposition 9 . Then I7 is a buil-
ding by Corollary 1.
r
The case of F4 is even easier. Let x,x,y,y be the parameters of points
,"
hyperlines
Let us assume that all C
residues of
3
r
are either buildings or
flat. They cannot be all flat. Indeed in that case we have x = y by Lemma 6 and we qet a contradiction with Proposition 12. Then some C
3
r
residues of
are buildinqs. Then
r
has known parameters.
Solwe can apply Proposition 12 and,by it and Corollary 6, we get
r
that
is a building.
Let us assume that some C
3
let
rU
residue of T is anomalous.For instance,
be anomalous for some hyperline u. Then we have x < y by
Proposition 9 . Then lary 5 . Then
r
ra
is a buildina for every point a, by Corol-
has known parameters and we contradict Corollary 6.
We are done.
4. 1.
U
PROBLEMS Is there any finite thick flat C
3
qeometry different from the
A -qeometry ? No effort has been made up to now to construct exam7
-
ples with parameters
t 2 t2 t3
and we have not even much information about how such a geometry should be done. We know much more about the case of uniform parameter
-
x
x
x
If a flat geometry existed different from the A -geometry and with 7
uniform parameter x # 1 , then x > 2 (by C363) ,Aut (r) could not be flag-transitive (by [I81 ;see Proposition 1 0 of this paper) and the
350
A . Pasini
qeometry could not be constructed as in Examples 3 and 4 of 52.3 (by t 1 7 1 and 1 8 1 ) . However, this does not yet answer our question completely, even in this case. Phat about the case of parameters
-
as below (see Proposition 10) ? t4 t 4 t 5
What about the qeneral case ? (n 2 4) with thick lin Can we construct such a aeometry as a auotient of a polar
2.
Is there any flat geometry of type C
nes
?
space ? We warn that such a qeometry should be infinite (Corollary 1 ) and its 0-shadow space should coincide with the projective geo-
metry
rU,
where u is any maximal subspace of the geometry. In par-
ticular, Property (LL)o (see 53.3) should hold in it. Actuallv, this very feature leads to a contradiction in the finite thick case (but non thick examples can easily be constructed; see L 3 4 1 ) . Anyway, if we consider also the case of n = 3 , then we find at least one (infinite, but thick) example of a flat C3 aeometry which is done in that way (i.e.:(LL)O holds in it): namely, Example 3 of 92.3 (we recall that it is a quotient of a polar space). 3.
Is it possible to construct a finite thick flat C3-qeometry
where (LL) holds ? We sometimes meet qeometries of that kind as 0
last possibilities in arquments by contradiction, just a moment before to get a final contradiction. But that is always got using also other facts. We observe that a lot of finite non thick examples of flat C
4.
3
geometries exist where (LL)o holds (see C391).
Try to construct a non flat proper quotient of a polar space
of rank n
3
4, with thick lines and such that all of its
C3
resi-
dues are either buildings or flat. Such a aeometry should be infinite, by Corollary 1 . Moreover, the polar space, which we start from, could not be defined over an algebraic extension of a finite field, because polar spaces defined over such fields do not admit prcper quotients (see the nroof of Proposition 8 ) . 5.
Which relations hold between the properties of the field over
which a classical polar space
r
is defined and the properties of
Cfassificationof Geometries Belonging to Lie Diagrams
the class of all proper quotients of I'?
35 1
(Of course, to be empty is
a possible property of that class. To contain flat aeometries
would be another interestinq property. By the way, the only infinite thick flat C
geometries presently known are got from polar 3 spaces over ordered fields: see Example 3 of 92.3). 6.
Let
r
be a finite thick non-buildinq C
-
3
geometry with parame-
ters as below (Theorem 8 , (iii)) Y2 Y2 Y
(provided that such a qeometry exists).Corollarv 5 states that Aut(T) cannot be flaq-transitive.Lemma 7 imDlies that
r
is fairly
'irregular'. Liebler C161 has considered the case of y = 2. He takes the qraph G defined over the set of planes of
r
by the col-
linearity relation and shows that certain irreqularities must occur in G. So,
r
cannot be reqular in standard ways. Can we find
any trick to construct such an irreqular example ? Can we do that when y = 2, for instance ?
7.
Corollaries 3 and 4 and Theorem 8 sugqest to consider also the
following conjecture (weaker than Conjecture 1 ) :
CONJECTURE 2, L e t r
-
be a f i n i t e
X
X
where x > 1 . T h e n e i t h e r ther
ci =
c3
geometry w i t h parameters
Y
ci
= 0 or ci =
0 o r c1 = m2 y ; t h a t i s , t h e
XY
x2y o r
ci =
geometry
r
y3 ( t h a t i s , e i i s a buiZding iff
i t s H e c k e a l g e b r a H ( T ) i s p r e s e n t e d by t h e s e t of r e l a t i o n s g i v e n i n Corollary 2 ) .
Conjecture 2 would look rather sensible if we had to rely mainly on algebraic methods (i.e.,on representation theory). We might have better reasons to trust Conjecture 2 instead of Conjecture 1 if we were able to prove the followinq qeneralization of Corollary 1: let
r
be a finite geometry of type Cn (n L 4 ) with thick lines and
let us assume that, for every Cj residue of maximal value or the null one. Then
r
r ,
ci
takes either the
is a buildinq. We observe
that,if this claim were true, than the exceptional case of Proposition 1 1 would be ruled out immediately. Try to prove that claim.
A . Pasini
3 52
8.
The followinq problem is deeply related to Conjecture 2. Note L
that the equalities a = 0 and a = x y have a clear qeometric meaninq, as well as the condition that one of the previous equalities holds (see Lemma 7 of this paper and the results of I291 and r301). Can we find a qeometric pronerty that is equivalent to the condior to the conxyy dition that either a = 0 or c1 = m2 y ? Succeeding in this would XY give us one more reason to trust Conjecture 2. tion that a = y3 or to the condition that
9.
c1 =
m
Prove that the exceptional case of Proposition 11 is impossi-
ble. As for this, I have recently qot a proof of the following statement (provided that nothins is wrong with my proof): if such an exceptional geometry exists in the rank 4 case, then its collinearity qraph is complete. This is not yet a non-exsistence proof, of course, but it smells like that. Can we find any number that can play in the C case (n n the same role as a plays in the C case ? What about F 4 ? 3 10.
2
4)
11.
Improve Proposition 1 2 .
12.
Improve Propositions 9 and 1 0 . The reader can find hints for
this job in C321. It would be too lonu to explain them here. 13.
Several results listed in this paper qive us the impression
that proper quotients of buildinqs of Lie type are not so frequent. Anyway,they do not exist at all in the finite thick case. Probably the same is true if we consider also non-building geometries. For instance: is there any finite C
3
qeometry with thick lines and ad-
mitting proper quotients ? By the wav, the answer is "no" if we consider only qeometries whith known parameters. Observe that, on the contrary, a lot of finite non thick quotients (see 1391 and 1291).
C
3
geometries admit proper
Classification of Geometries Belonging to Lie Diagrams
353
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26.
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27.
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28.
A.PASINI, On Tits geometries 45-54.
29.
A . P A S I N 1 , O n q e o m e t r i e s of type C 3 t h a t are e i t h e r b u i l d i n g s or flat, to appear i n Bull.Soc.Math. de Belaique.
30.
A . P A S I N I , O n f i n i t e g e o m e t r i e s of type C 3 w i t h thick l i n e s , to a p p e a r i n N o t e d i Matematica.
31.
A . P A S I N 1 , G e o m e t r i e s of t y p e C n and Fq w i t h flag-transitive a u t o m o r p h i s m g r o u p s , t o a p p e a r in t h e P r o c e e d i n g s of t h e W o r k s h o p " G e o m e t r i e s a n d G r o u p s , F i n i t e and A l g e b r a i c " , L e e u w e n h o r s t , M a r c h 1986.
32.
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A . P A S I N 1 , O n a t h e o r e m by A s c h b a c h e r , t o a p p e a r i n J . G e o m e t r y
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A . P A S I N I and S.REES, A theorem o n T i t s g e o m e t r i e s of type C n t o a p p e a r i n J.Geometry.
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S.PAYNE and J.THAS, " F i n i t e G e n e r a l i z e d Q u a d r a n g l e s " , P i t m a n 1984.
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S.REES, O n d i a g r a m g e o m e t r y ,
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38.
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S.REES, F i n i t e C 3 g e o m e t r i s i n w h i c h a l l l i n e s a r e t h i n , M a t h . Z e i t . , l 8 9 (1985),263-271.
40.
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type C
n
, Eur.J.Comb.,8 (1987)
Ph.D.Thesis, O x f o r d 1983.
(1985),77-
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355
41.
S. RE ES , Weak b u i l d i n g s o f s p h e r ical type, to appear.
4 2.
S. RE ES and R.SCARLAU, p e r s o n a l c ommunication (March 1985).
4 3.
R.SCHARLAU, A s t r u c t u r e t h e o r e m for weak buildinqs o f spherical t y p e , t o appear.
4 4.
G.SEITZ, F l a g - t r a n s i t i v e s u b g r o u ps of Chevalley q r o u p s , Ann. Math. , 9 7 ( 1 9 7 3 ), 2 7 - 5 6 .
45.
J.THAS, l e c t u r e g i v e n a t t h e W o r kshop "Geometries and G r o u p s , F in it e and A l g e b r a i c " , L e e u w e n h o r s t , M a r c h 1 9 8 6 .
46.
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47.
J.TITS, " B u i l d i n g s of S p h e r i c a l T y p e and Finite BN-pairs", L.N.386, S p r i n g e r 1974.
48.
J . T I T S , A l o c a l a p p r o a c h t o b u i ldings, i n "The Geometric Ve in ", Sp r i n g e r 1 9 8 1 , 519-547.
49.
P .Z IE SC H A N G , T h e n o n e x i s t e n c e o f certain geometries o f type C 3 , to a p p e a r .
ADDED IN PROOF. A mistake has lately been found in C171. So, the
problem to prove that the A7-geometry is the only finite non-building example that can be got starting from sets of points exterior to Klein quadrics (see this paper,§2.3,Example 4 and f4,Problem I), is still open. Anyway, F.De Clerck and J.Thas have got interestinq partial results on this problem, which might lead to a proof of the previous claim in a short time.
This Page Intentionally Left Blank
Annals of Discrete Mathematics 37 (1988) 357-366 0 Elsevier Science Publishers B.V. (North-Holland)
357
THE THAS-FISHER GENERALIZED QUADRANGLES Stanley E. PAYNE Department of Mathematics University of Colorado at Denver 1100 14th Street, Campus Box 170 Denver, CD 80202 Using a flock of a quadratic cone discovered by J. C. Fisher, J. A. Thas has recently shown the existence of a new generalized quadrangle Here we give a very of order (q2,q), q an odd prime power, q 2 5. explicit description of Fisher's flock and show that up to isomorphism there arises just one new generalized quadrangle for each q.
1.
INTRODUCTION
During the past few years, work of W. M. Kantor (cf. C2,3,41) and S. E. Payne (cf. C5,6,71) has led to a recipe for the construction of generalized quadrangles (GO) of order (q2 ,q) beginning with a family M of 2 x 2 upper triangular matrices satisfying certain conditions. Recently, 3. A. Thas C9] has shown that such a family M is equivalent to a flock o f a quadratic cone in PG(3,q). He studied the known flocks and the known GQ of the corresponding type and discovered that previously there was not known a GQ corresponding to the flock discovered by J. C. Fisher and first described in [l]. Thedescriptions of Fisher's flock given previouslyseemto us to lack the necessary explicitness needed to facilitate a study of the corresponding GQ. Moreover, W. M. Kantor C41 has brought to our attention other reasons that a computationally explicit study of these flocks and the corresponding family M would be of interest Hence we feel justified i n presenting here one more treatment of Fisher's flocks The geometrical connection between a flock and its corresponding GQ is not at a1 well understood. For example, it is not even known whether or not an automorphis of the flock corresponds to an automorphism of the GQ! It i s partly for this reason that we have had as one main goal in this essay to show that just one new GQ is obtained for each q. To begin, let q be any prime power, let F = GF(q), and let K be the cone
S.E. Pa)*ne
358
u {(l,c
2 ,c,d)
PG(3,q):
E
c,d
{(O,l,O,O)}
So K i s t h e cone over t h e c o n i c V = (0,0,0,1).
T
[a,b,c,O]
F} u {(O,l,O,d):
E
.
ITi
n
IT.
M = {nl
( J . A. Thas [ ? I ) .
i
(i)
J
For odd g,
1
-
(ci-c.)' J
E
F},
with vertex
none o f which c o n t a i n s
K-{V}
i n t o d i s j o i n t ovals)
A f l o c k F i s l i n e a r provided a l l
vi = [ai,bi,ci,l]'
W
J
-
y i e l d s a f l o c k of
i s i r r e d u c i b l e , o v e r F whenever
bj
i s a nonsquare i n F whenever
4(ai-a.)(bi-b.) J J
(ai-a.)(bi-b.)(ci-c.)-' J J J
Associated w i t h
1 ii1 i1 .
= [a.,b.,c.,l]'
ITi
1
1
has t r a c e is a
1
2 x 7
1
whenever
# j.
The c o n d i t i o n i n 1.1 i s t h e n i n t e r p r e t e d as f o l l o w s , where " A = 0
i f and o n l y i f
= (0,O).
,AaT
1.2. F = {$,, ...,@ 9 } -
y i e l d s a f l o c k o f K i f and o n l y i f
whenever
i
i # j.
upper t r i a n g u l a r m a t r i x
i s a n i s o t r o p i c " means
Let
c
T h i s c o n d i t i o n i s e a s i l y i n t e r p r e t e d f o r odd o r even q as f o l l o w s :
(ii) F o r even q,
Ai =
,..., & nJ } I 9
# j.
+ ( c . - c . ) x + bi
K if and o n l y if (ai-a.)x2
i= 1
a partition of
n K = $ whenever
J i t s p l a n e s c o n t a i n a same l i n e .
i # j.
(1)
F}.
2,c,O):
,...,q,
Consider a s e t F o f q p l a n e s IT^,
provided t h a t
1.1.
u {(l,,c
E
A p l a n e n i n PG(3,q) c o n t a i n s V p r e c i s e l y when i t has c o o r d i n a t e s
F determines a f l o c k o f K (i.e.,
V.
d
CI
Ai-A.
i # j.
K = {(a,c,R):
a,R
F
E
2
,
c
E
J
i s anisotropic
Then K is t u r n e d i n t o a group w i t h t h e
F}.
b i n a r y operation defined by
where 0-a'
A(-)
K.
i s t h e usual d o t p r o d u c t . C = {(O,c,O) E K: c E F } i s t h e c e n t e r of 2 2 E K: L 3 E F } i s a subgroup o f K h a v i n g o r d e r q
I I ai
Now suppose Ai = Put Ki=Ai+Ai.
i
E
T
,...,q,m)}.
(1
.
= ((0,O.D)
ci bi
,
15 i 5 q,
Put A ( i ) = { ( a , W p For
A
E
subgroups o f K, each o f o r d e r
J,
T
put
2 s = q
w i t h Ai-A
j
a n i s o t r o p i c whenever
2 , c Y K ~ ) E K : ~ E F), A*
.
=
AC.
l$i
i
# j.
Put J = { A ( i ) :
Then J i s a f a m i l y o f
l+t = l+q
W. M. K a n t o r C31 ( f o r odd q ) and S. E.
Payne C71 ( f o r even q ) used computations worked o u t in C51 t o p r o v e t h e f o l l o w i n g :
The Thas-Fisher Generalized Quadrangles The f a m i l y
1.3. i.e.,
K1. K2.
-
J i s a 4-gonal f a m i l y f o r K g i v i n g r i s e t o a
3 59 GQ o f o r d e r ( q 2 ,q);
J s a t i s f i e s t h e , f o l l o w i n g axioms of K a n t o r C21: A . A . n Ak = 1 i f i, j, and k a r e d i s t i n c t . 1 J A* n A . = 1 if i # j.
l
J
F o r t h e a c t u a l c o n s t r u c t i o n of t h e 64 and s e v e r a l r e l a t e d d e f i n i t i o n s and r e s u l t s , we suggest t h e monograph 181. I n S e c t i o n 2 we d e r i v e an e x p l i c i t d e s c r i p t i o n o f F i s h e r ' s f l o c k s f o r a cone p r o j e c t i v e l y e q u i v a l e n t t o b u t d i f f e r e n t f r o m K. i s t r a n s f e r r e d t o a f l o c k o f K.
GQ f i r s t d i s c o v e r e d by J. A.
k
Then i n S e c t i o n 3 t h i s f l o c k
I n S e c t i o n 4 we i n i t i a t e s t u d y o f t h e a s s o c i a t e d Thas [9].
The r e a d e r s h o u l d n o t e t h a t we have
borrowed q u i t e f r e e l y f r o m t h e work o f F i s h e r , Thas and K a n t o r i n d e r i v i n g t h e present d e s c r i p t i o n o f F i s h e r ' s flocks.
2.
FLOCKS BY FISHER
and l e t L e t q be an odd p r i m e power, l e t - a be a nonsquare o f F = GF(q), = a+bi, E = F ( i ) , where i2 = -a. L e t 5 be a p r i m i t i v e r o o t o f E and p u t z = z i s an a r b i t r a r y g e n e r a t o r o f t h e c y c l i c group o f E* h a v i n g o r d e r q+l. For so
F,
-
the conjugate o f x + i y i s x+iy ( x + i y ) ( x - i y ) = x 2+ a y2 , so y = x + i y s a t i s f i e s
x,y
E
=
In p a r t i c u l a r ,
E q u a t i o n 6 i s e s p e c i a l l y i m p o r t a n t f o r what f o l l o w s !
x-iy
=
(x+iyIq.
And
S.E. Payne
360
For each integer k , put
Similarly, put
We now collect several observations concerning the ais and bjs, none of whose proofs i s especially complicated.
C.1.
(i) (ii) (iii)
(iv) (v)
.
.
-(J-q ...
+ + (-1)J. a - (zJ+l+z-j)/(z+l) = (zJ+z-J)- (zJ- +z j aj # ak for 0 5 j < k < (q-1)/2. -a. = a so aj = 0 for some j (specifically for j = (q-1)/4) J (Cl-1)/(2-J)' if,and only if q :1 (mod 4). a = 3 {a2j: 0 5 j 5 (q-1)/2} = {aj: 0 5 1 5 (q-1)/2}. j .a = 1; %-1),2 = -1; a-j = ajml.
(vi) bk = i(zk+l-z-k)/(z+l) (vii) (viii)
= i(z-l)Xk/(z+l) = (a-l)Ak/b = -clbbo/(a+l). aa.+bb. j j = aj+$j = (aj+l-aj-l)/2b and aa.-bbj J = aj-l\aj = (aj+l+aj-l)/2a. bk = -bq-k; bk = b (q-1)/(2-k 1.
Put At =
1 O
0 a
0 O
0 0
0 - 1 0 0
0 O 0
'
0
and let k be the cone defined by { V ) u {(Y,l,t): Y E E, YU = 1). Hence,
-
K =
- -
{x: xAiYT = 0)
=
{Y: x
t E F, all meet in the line N = {(x,y,O,O): The planes ?(t) = [O,O,t,-lIT, x,y E F ; (x,y) # (0,O)). Fix j modulo q + l . Then for 0 5 k 5 (q-1)/2, in the plane %(t) we have (using Equation 6):
The Thas-Fisher Generalized Quadrangles
I t i s clear that {G(t): t
E F} determines a l i n e a r f l o c k o f
l e t ;*(j) be t h e p l a n e spanned by
2.2.
-
The p l a n e s
Proof: -
5
k
G(ak),O
j
5
(q-1)/2,
i. F o r 05 j 5 ( q - l ) / Z , and P1,2j+l.
P1,2j,
a l l meet each of
eact) t i m e i n a , s e c a n t l i n e o f
t h e planes
2.
An easy c o m p u t a t i o n shows t h a t
-
k+l
P
5
a*(j),O
(q-1)/2,
0 = (0,0,1,0),
361
ak,2j-k
Z
= (l-ak)O +
Z-(k+l)
2 - 2
-
and
As j v a r i e s w i t h k f i x e d , Pak 2.-k and Pak 2.+k+l y i e l d a l l q + l p o i n t s o f k n G ( a k ) . , J $ 3 Hence,
u{kak) n
?:
0
-< k -< (q-1)/2}
i:0 5 j 5 (q-1)/2}.
= u{G-(j) n
E q u a t i o n 13 p r o v i d e s us w i t h F i s h e r ' s f l o c k f o r
2.3.
{G*(j): 0 5 j 5
(q-1)/21 u{G(t):
of k , ( w h i c h i s n o n l i n e a r f o r
A point of (0,0,1,0)
+
2 n ;(j) Y(Z2j+1,0,1)
w i t h zk = t z 2 j
some
y E F
+
q
t E F
2 5;
2.
- {ao,al,
...,@-g2))
+ y(z2j+l-z2j).
F o r a g i v e n t EF, k module q+l.
t h i s may o r may n o t h o l d f o r
(Of c o u r s e we a l r e a d y know t h a t i t
h o l d s p r e c i s e l y f o r t o f t h e f o r m ai f o r some i.) But t
+
y(z-1)
y2N(z-1)
E
-
t2(N(z-1))2
zk-2j
yields a flock
see C91).
o t h e r t h a n P 1,2j Or '1,2j+l must have t h e f o r m (t-y)(22j,O,l) = (tz2j+y(z2j+l-Z2j),l,t) = ( 2k ,l,t),
and some i n t e g e r
i f and o n l y i f
(13)
= t
+ y(z-l),
zk = t z 2 j + y ( ~ ~ j + ~ - z ~ j )
which has a s o l u t i o n i f and o n l y i f
i f and o n l y i f
-
(Here N(y) means t h e 'norm' o f r, i.e., t h i s i s i f and o n l y i f
t2
- 2/(l+a)
N(z-1) = ( z - l ) ( z - ' - l ) . ) = t2
-
4/N(l+z)
After simplifying,
i s a nonsquare i n F ( s i n c e
362
S.E. Payne
a2 - 1 = -ab2 is a nonsquare). flock.
This gives us a revised description of Fisher's
Fisher's flock of k is determined by {G*(j): 0 5 j t2 - 4/N(l+z) is a (necessarily nonzero) square in F ) .
2.4.. {{(t.):
5
(q-1)/2}
u
Let
and define a collineation T of PG(3,q) by
T: X
+
?[TI,
for each point X
E
PG(3,q).
(14)
T(x) = (axo- abxl,axl+bxo,x2,x3). Since (xo+xli)(a+bi) = Note that (axo-abxl) t (axl+bxo)i, it follows that T leaves invariant each point of the line VO, each plane n(t) through N, and maps Pt,j to Pt,j+l. It follows that T2: G*(j) * G*(j+l), 0 5 j 5 (q-1)/2 and A
It seems quite remarkable to us that we cannot seem to find a way to transfer the action o f TL to the corresponding GQ! (The missing collineation has been found and will appear in a later paper.)
3. THE TRANSFER FROM Put
Then
k
TO K
The Thus-Fisher Generalized Quadrangles
363
P A t P T = -4nAK. So K i s r e l a t e d t o
r?
7
by:
E
K
i f and o n l y i f
y
E
k,
where
x =
YP.
So we
t r a n s f e r f r o m I? t o K by mapping a p o i n t 7 t o 7 P - I and a p l a n e TT t o PYT. p a r t i c u l a r , f o r t 2 2 / ( l + a ) a ( n o n z e r o ) square i n F, t h e p l a n e %(t) = [0,0,t,-l]
-
In T
i s mapped t o n ( t ) = PCO,O,t,-lIT
= C-t,-ta,O,ll
T
.
-
For t 2 2 / ( l + a ) a nonsquare, say t = aj,
117)
05 j 5 (q-1)/2,
G * ( j ) =
i s mapped ( a f t e r some c o m p u t a t i o n ) t o
A f t e r more c o m p u t a t i o n we see t h a t r’(j)
T
= C-a2j,a2j,2b2j,l]
.
T h i s completes a proof of t h e f o l l o w i n g :
3.1.
The se,t M o f
2 x 2
upper t r i a n q u l a r m a t r i c e s c o r r e s p o n d i n g t o F i s h e r ’ s
f l o c k f o r t h e s t a n d a r d cone K c o n s i s t s o f a l l t h e - m a t r i c e s o f t h e f o l l o w i n g two
types:
In 3.1 i t would be q u i t e c o n v e n i e n t t o have a f o r m u l a f o r bk in t e r m s o f ak alone. So g i v e n a v a l u e t (=ak) I t i s easy t o see t h a t bk = +ila:(z+l) 2- 4 z / ( l + z ) . such t h a t t 2 - 2/(l+a) i s a nonsquare i n F, t h e c o r r e s p o n d i n g bk i s
-+iJ t 2 ( z + 1 ) 2 - 4 z / ( l + z ) ,
l e a s t +t i s p a i r e d w i t h
b u t we do n o t see how t o d e t e r m i n e t h e s i g n o f bk. +iJ t 2 ( z + 1 ) 2 - 4 z / ( l + z ) .
At
S.E. Payne
364 The cone
r?
i s i n v a r i a n t under t h e p r o j e c t i v e c o l l i n e a t i o n T, so we may c o n s i d e r
what happens t o F i s h e r ' s f l o c k under T. TI
i s a p l a n e i n F i s h e r ' s f l o c k f o r K,
= [a,b,c,llT
PCTl-lP-l[
T r a n s f e r r i n g t o K,
a, b, c ,1IT.
0
-ab2 = a2 -l,a2j-l
But
= (a2j+2-a2j)/2b.)
-
j,
and f o r t h a t k we have
a r i s e s f r o m F i s h e r ' s f l o c k F f o r K (as i n 3.1) i f and o n l y a r i s e s f r o m t h e image o f F under t h e a c t i o n o f P[T]-'P-'.
How i s t h e s e t M of 3.1 a f f e c t e d by r e p l a c i n g z w i t h some o t h e r
NOW we ask:
generator z
= 2aa2j-a2j+lyb2j+l
T h i s proves the following.
1;
ift h e m a t r i x
we o b t a i n
if and o n l y if k = ( q - 1 ) / 2
1;
3 . 2 . The m a t r i x
i s replaced b y
'I
O
M u l t i p l y i n g t h i s m a t r i x t i m e s C-a2j,aa2j,2b2j,l]T,
a2j = aq-2j = a2k+l b 2 j = -bqmZj = -b2k+l.
71
So compute :
l o
(Here we use
then
we see t h a t i f
r of
gcd(r,q+l)
= 1,
so
r = 2j+1 f o r some j?
From E q u a t i o n 22, we have
So t 2 square.
- 4/N(l+z)
i s a square i n F i f and o n l y i f
This implies t h a t
nonsquare i n F )
to the set
t -+ t / a j
{t
E
F: t 2
We c o n t i n u e t o use t h e n o t a t i o n ak,bk
-
{t
4/N(l+z2j+l)
modulo (q+1)/2.
E
-
i s a nonsquare i n F).
i s replaced with 1
So i f t = aZi, t h e n t / a j = a2k A f t e r some c o m p u t a t i o n we see t h a t
= 1.
4/N(l+z2j+l) is a F: t 2 4 / N ( l + z ) i s a
as a g i v e n i n S e c t i o n 2 , and l e t
t h e c o r r e s p o n d i n g elements o f F o b t a i n e d when z gcd(Zj+l,q+l)
-
(t/aj)'
maps t h e s e t
:k,6k
be
z 2 j + l,
f o r some k determined
The Thas-Fisher Generalized Quadrangles
aZi
* = 'ja2k
iff
(,2k
p 3 (Zj+l)-'
Put
12j+1)+2i+j+l-l)
(mod q+l).
( 2 j + 1 ) + 2 i -j-l) =
(,-2k
365
o,
(24)
Then the l e f t f a c t o r i s zero i f and o n l y i f
And t h e r i g h t f a c t o r i s zero i f and o n l y i f
k
[i-j/Z]p
(mod (q+1)/2),
i f j i s even.
(26)
A s i m i l a r computation shows t h a t bZi
=
2
.
aj-bZk
i f f (z
2k (2J+1 )+2i+j+l+l
-
(,-2k ( 2j + l ) + 2 i -jq) =
I t now f o l l o w s t h a t
-6,,, bZi/aj
=
bZk,
j odd j even.
This e s s e n t i a l l y completes a p r o o f o f the f o l l o w i n g . L e t M,be the,s,et o f m a t r i c e s a r i s i n g from F i s h e r ' s f l o c k f o r K s t a r t i n g
3.3.
w i t h the generator z (as i n 3.1).
Let
obtained when z i s replaced w i t h i?j*',
4.
THE
ii be
the corresponding s e t o f m a t r i c e s
gcd(2j+l,q+l)
= 1.
Then
GQ OF THAS
Most o f the d e t a i l s needed t o prove t h e theorem o f t h i s s e c t i o n have a l r e a d y been given.
4.1.
For each odd prime power q o n l y one GQ a r i s e s from F i s h e r ' s f l o c k .
Proof: The idea i s t h a t n e i t h e r r e p l a c i n g t h e o r i g i n a l f l o c k w i t h i t s image under y i e l d s d i f f e r e n t GQ. I n view o f 3.2 gcd(r,q+l) = 1, T nor r e p l a c i n g z w i t h zr, and 3.3, t h e f o l l o w i n g r e s u l t s complete t h e p r o o f .
S.E. Payne
366
;1 1;
and define 0: K + K by 0: (a,c,O) + (aQ,c,BQ). Then 0 is Put Q = an automorphism of K for which 8: (apAaT ,a(A+AT)) -t~QPQ(QAQ)(o(4)T,aQ(QAQ+(QAQ)T)). Since Q
Q
=
1; -:I
, A
=
1;
is replaced with Q A Q =
For t EF, t # 0, define 0: K-tK by $(o,c,B)+ (a,tc,tR). @ is an automorphism of K that replaces A with tA.
I -:I.
It is easy to check that
REFERENCES
c11 Fisher, 3. C. and Thas, J. A., Flocks in PG(3,q), Math. Z. 169 (1979) 1-11. C21 Kantor, W. M., Generalized quadrangles associated with G2(q), dour. Combin. Theory (A) 29 (1980) 212-219. 2 C3l Kantor, W. M., Some generalized quadrangles with parameters (q ,q), Math. Z. 192 (1986) 45-50.
C41 Kantor, W. M., Generalized quadrangles and translation planes, Algebras, Groups and Geometries 3 (1985) 313-322. C51 Payne, S. E., Generalized quadrangles as group coset geometries, Congressus Numerantium 29 (1980) 717-734. C61 Payne, S. E., A garden of generalized quadrangles, Algebras, Groups and Geometries 3 (1985) 323-354. C71 Payne, S . E., A new infinite family of generalized quadrangles, Congressus Numerantium 49 (1985) 115-128.
C81 Payne, S. E. and Thas, J. A., Finite Generalized Quadrangles, Research Notes in Mathematics No. 110 (Pitman Pub. Inc., 1984). C91 Thas, J. A., Generalized quadrangles and flocks of cones, preprint.
Annals of Discrete Mathematics 3 7 (1988) 367-374 0 Elsevier Science Publishers B.V. (North-Holland)
367
ON GROUP SPACES DEFINED BY SEMIDIRECT PRODUCTS OF GROUPS J . Pfalzgraf
Fachbere i c h Mathemat i k U n i v e r s i t a t des Saarlandes D-6600 Saarbrikken Fed. Rep. Germany
0 . INTRODUCTION
The " c l a s s i c a l " examples of noncomutative geometric spaces such a s ray s p a c e s , c i r c l e spaces, d i s c spaces, n e a r f i e l spaces, spaces defined by t h e more general F-groups, a l l t u r n out t o be group spaces with r e s p e c t t o s p e c i a l semidirect products of groups. W e introduce t h e concept of a semidirect product space (SPS) induced by t h e " a f f i n e action" of a semidirect product of groups ( c f . 1 . 2 ) . I t is p o s s i b l e t o make e x p l i c i t constructions of spaces with prescribed properties. This p o s s i b i l i t y is indicated by examples using f r e e groups t o show t h a t t h e equivalence of t h e p r o p e r t i e s "semiaffine" and " t a c t i c a l " , i n [A21 Satz 2 . 1 , is t y p i c a l f o r f i n i t e spaces ( i t does not hold f o r i n f i n i t e spaces, i n g e n e r a l , c f . 3.6). As another a p p l i c a t i o n of SPS we present a geometric version of Witt's cancell a t i o n theorem f o r q u a d r a t i c forms over f i e l d s ( c h a r a c t e r i s t i c not 2) involving two geometric i n v a r i a n t s which can be defined f o r a q u a d r a t i c form ( c f . 4 . 5 ) . F i n a l l y w e mention t h a t with respect t o a r b i t r a r y group extensions 1 + N E G + 1 f u r t h e r n a t u r a l questions of geometric type a r i s e . +
1.
+
NOTATION
Noncommutative geometric spaces (X,U ,I1 ) a s introduced by J.Andr& ( c f . A1 1 [A4]) can be described by t h e i r p a r a l l e l s t r u c t u r e ( c f . [Pl I): each map <,>:X2 + R , defining a p a r a l l e l i s m on t h e p o i n t set X ( R i s t h e set of d i r e c _ t i o n_ s o r_i d e_ a l p o i n t s ) , leads t o a so-called LP1'-space (X,<,>,R), i . e . t h e axioms ( L l ) , ( L Z ) , ( P l ' ) hold, and v i c e versa (see [ P l l f o r more d e t a i l s ) . are defined by x 0 y : = x U y"[<x,y>} ; x U y := { X ) U {zi <x,z>=<x,y>} i s t h e set of proper p o i n t s of x 1 y ; <x,y> i s t h e i d e a l p o i n t ( d i r e c t i o n ) of the line.
x
0y
is parallel t o u
0v ,
iff
< x , y > = < u , v > .Further axioms of a
space X a r e expressed by corresponding equations i n t h a t "<,>-calculus" cf. [Pll 2.5.
,
Now l e t G x X + X be t h e a c t i o n of a group G on a p o i n t set X . Then t h e group space ( c f . [All,[A21), denoted by V(G,X), i s defined by t h e p a r a l l e l map ( c f . [PZI): <,>:X2 R , with R := G \ X 2 , < x , y > : = G(x,y) t h e o r b i t of ( x , y ) . (1.1) -f
G a c t s componentwise on each p a i r of X z . For l i n e s we o b t a i n x u y = { x } u Gx.y.
J. Pfalzgraf
368
V( ,
) i s a covariant functor from "Group Operations" t o "Noncommutative
Geometric Spaces". For more information about group spaces see [All
-
[A41 and
[PZ]. Our i n t e r e s t here is concerned with group spaces associated with semid i r e c t products of groups. 1.2
Definition
Let G , N be groups ( m u l t i p l i c a t i v e l y w r i t t e n ) , G a c t s on N: gx := T ~ ( x ), x E N , g E G. E := N M G with respect t o t h a t a c t i o n . This gives rise t o t h e " a f f i n e action" of E on N , defined a s E x N -L N with T:
G
+
Aut(N), denoted by
W e obtain t h e semidirect product [ a , g ] . x : = a.gx
,
[a,gl
E
E, x
E
N
,
leading t o t h e group space V(E,N). W e call
t h i s a semidirect product space (SPS f o r s h o r t ) . W e note here t h a t a l l t h e 1-point s t a b i l i z e r s Ex , x because we know t h e s t a b i l i z e r group of 1
Ex = [ x , l l E1[x,ll-l
=
E
E
N which i s
N , can be c a l c u l a t e d
El
=
(1 ,GI, hence
{ [ ~ . ~ x - ' , g l/ g E G}.
I t t u r n s out t h a t a l l t h e following " c l a s s i c a l " examples of noncommutative geometric spaces a r e s p e c i a l SPS.
2.
EXAMPLES
2.1
Ray Space SIRn
n- 1 S u { O } , <x,y> : = (y-x)/ IIy-d1 y i s t h e ray x + IR otherwise. Then f o r x # y , x
X
:= IRn
,R
:=
,
if x # y
and <x,y> = 0
u
20(y-x) . We have t h e following p r e s e n t a t i o n of the ray space SRn a s SPS: SIRn = V ( I R n ~ I R , O , I R n ) , with r e s p e c t t o t h e n a t u r a l a c t i o n of TR,o on Rn. 2 . 2 Affine Space AG(n,JR) AG(n,IR) is obtained from SIRn by i d e n t i f i c a t i o n of antipodal d i r e c t i o n s , t h u s
R :=
d-'" { O } and <,>
x # y and <x,y> 2.3
:=
is defined on X : = Rn by <x,y> := [t (y-x)/ i~y-xll}, 0 , x = y. Then AG(n,IR) = ~ ( R n X , I R * , I R n ) , IR* := IR \ { O } .
C i r c l e Space
x U y i s t h e c i r c l e with radius IIx-yII : = IR2 , R : = IR 20 , <x,y> := / / x - y / (; and i t s midpoint x a s basepoint of t h e l i n e . X can be described by
X
IR')
o r by V(IR2xlSO(2,1R),IRz), a l t e r n a t i v e l y . Thus we see t h a t t h e covariant functor , ) i s not f a i t h f u l .
V(IR2X,0(2,1R),
V(
There i s an obvious g e n e r a l i z a t i o n of t h e above d e f i n i t i o n of c i r c l e space t o IRn leading t o spheres a s l i n e s .
On Group Spaces Defined by Semidirect Products of Groups
<x,y>:=
m
f o r x = y. Then x u y = { x l } x IR
{ x ) (~ {y,}
"=I(,
,
i f x1 = y, and
IR), i f x1 # y , . I t holds ( X , < , > , R )
x 7
a
E
IR,a
=
XU y
369 =
V(IR2xrH, IR2) with
IR*} IGL(2,IR).
E
Of course, t h i s d e f i n i t i o n can be g en er al i zed ( c f . [ P11,[ P21). 2.5
Remark
A l o t of f u r t h e r examples can be co n s t r u ct ed i n t h i s way ( f o r example
using IRn %I G , G a subgroup of GL(n,IR), e t c . ) Evidently one can d e f i n e t h e above spaces over more ge ne ra l c o e f f i c i e n t domains. In t h i s context we mention t h e following observation.
Consider t h e d i s c space 2.4 over a r i n g A with u n i t 1 , inste a d of a f i e l d . Then, using t h e analogous d e f i n i t i o n s (A* denotes t h e group of i n v e r t i b l e elements ( u n i t s ) of A) we o b t a i n t h e following r e s u l t
(X,<,>,R)
(2.6)
=
\I(AZ+H,A2) i f , a n d only i f , A is a f i e l d .
Proof: I f A is a f i e l d , then t h e e q u a l i t y holds ( c f . [PZ]). Conversely assume t h a t A i s n o t a f i e l d . Then t h e r e e x i s t s c
E A, c # 0 , which is n o t a u n i t . Now consider t h e p o i n t s x = (O,O), y = (O,c), u = ( l , l ) , v = (1,O) i n X = A' and show t h a t t h e p a r a l l e l classes (AZ- H). (x,y) and P < X ,Y> { ( x ' , y ' ) I < x ' , y'> = < x , y > } are d i s t i n c t (hence t h e spaces a r e d i s t i n c t , having d i f f e r e n t p a r a l l e l i s m s ) : obviously ( u , v ) E P s i n c e = 0 = < x , y > , but <X,Y> ( A 2 ~ H ) . ( x , y ) ,otherwise t h e r e were [z ,h] E A2*H such t h a t [ z , h ] . ( x , y ) (u,v) 1 0 = ( u , v ) , t h i s means u = z+ h ( x ) , v = z+ h ( y ) , f o r s u i t a b l e h =(, a ) , a E A, a E A*, and we o b t a i n f o r t h e second coordinates: u2 = z 2 + ax1 + a x and v2 = z 2 + ayl + a y 2 , s u b s t i t u t i n g t h e o r i g i n a l
4
values y i e l d s t h e equation 2.7
0 = 1 + a c , hence c
E
A*, a c ontra dic tion.
F-Groups and Near f i el d Spaces
As mentioned i n [ A41 93, t h e n e a r f i e l d spaces ( t h e s e are re gula r desarguesian n e a r a f f i n e spaces and v i c e v er s a) are SPS. I t t u r n s out t h a t even t h e more g e n e r a l F-groups ( c f . [A31 ) lead t o SPS.
For convenience we r e c a l l t h e d e f i n i t i o n of a F-group and adopt t h e n o t a t i o n of [ M I ( t h i s work i s a w e l l w r i t t e n co n t i n u a tion of [A31 de a ling w ith se ve ra l f u r t h e r t o p i c s of l i n e a r al g eb r a over n e a r f i e l d s ) . ( 1 ) A p a i r (F,V) i s c a l l e d F-group ( c f . [A31 ,[MI) i f t h e following four c o n d i t i o n s hold: (F1) (V,+) i s a group and ( F , , ) a monoid.
(F2) (F3) (F4)
F o p e r a t e s on V, i . e . (aB) . x = a(f3.x) and 1 .x = x and t h e r e e x i s t 0,-1 E F such t h a t 0.x = 0 , (-11.x = -x and furthermore a (x+y)= ax+cly. F* = F { O } i s a ( m u l t i p l i c a t i v e ) group. Cancellation: ax = Bx implies x = 0 o r a = .
370
J. Pfalzgrrsf
These conditions imply t h e following: (V,+) i s a b e l i a n ;
a.Ov
=
Ov ; a(-x) = - a x ; ( a ( - 1 ) ) x = ( ( - 1 ) a ) x = -ax ;
F* a c t s l i k e a group of automorphisms on ( V , + ) . The geometric spaces A(F,V) = (V,U
(1)
,I]
) i n [A31 p.295 ( f o r more d e t a i l s
see J.Andr6, Affine Geometrien uber Fastkorpem. Mitt.Math.Sem.Giefien x ( 1 9 7 5 ) ) , a r e defined by L := {Fx + y 1 x E V 1 { 0 } , y E V } a s set of lines and x U y = x = x + F(y-x) and p a r a l l e l i s m x 0 y I( x ' U y ' , i f f F(y-x) In terms of t h e <,>-model we can d e s c r i b e A(F,V) as follows:
F(y-x)
<,>
+
: Vz
f
R
,
R := {F*.x
and < x , y > : = 0 , x Note:
=
I
x
[O}}
V \
E
{ O } ; Cx,y>:= F*(y-x)
,
F(y'-x').
=
if x # y
y.
obviously F*v
=
F*w, i f f [ t h e r e e x i s t s a f 0: v = a w l
,
iff
Fv
=
Fw.
Since F* a c t s like automorphisms on ( V , + ) we can d e f i n e t h e semidirect product V
A
y(VH F* ,V).
F* and t h e SPS
Now w e s t a t e
A(F,V) = y(VMF*,V)
(3) Proof:
I t i s r e a d i l y seen t h a t < x , y > = < u , v > i s equivalent t o ( V M F * ) ( x , y )
=
( V d F * ) ( u , v ) , s i n c e the l a t t e r equation means [ t h e r e e x i s t s [ w , ~ ]E V M F * : ( x , y ) = [ w , a l ( u , v ) l , i f f [ x = w + clu , y a(v-u)] , i f f
F*(y-x) = F*(v-u) , i f f
=
w
+
a v l , i f f [y-x = av - au
=
<x,y> = .
Thus t h e p a r a l l e l s t r u c t u r e s of both spaces are e q u a l , hence ( 3 ) h o l d s . Remark
2.8
S(F,U),
The group spaces
F a n e a r f i e l d , U*
<
F*
,U
= U * u
[ O ] , a s mentioned
i n [A41 Prop.5.3 ( t h e y were o r i g i n a l l y s t u d i e d by K.P. Rofiler i n h i s Diploma r b e i t , Saarbriicken 1985) t u r n out t o be SPS, t o o . Namely with respect t o t h e semidirect product
FWU*.
With a f f i n e a c t i o n s of semidirect products one can make e x p l i c i t c o n s t r u c t i o n s of spaces with p r e s c r i b e d p r o p e r t i e s ( e x p l o i t i n g t h e knowledge of t h e 1-point s t a b i l i z e r s ) . This p o s s i b i l i t y w i l l be i n d i c a t e d i n t h e next s e c t i o n . 3.
A CONSTRUCTION WITH FREE GROUPS
L e t Fn = F ( a l ,..., an) be t h e f r e e group of rank n ( n 2 2 ) with b a s i s { a,,..., an}
and
'p
t h e automorphism defined by ' p ( a . ) = a i + l
,
1 5 i < n
, 'p(an)
=
a l , then
G : = { i d , ' p , . . . ,(pn-l} < Aut(Fn) is c y c i i c and we o b t a i n t h e SPS
, we r e c a l l from [PZ] 3.5
(3.1)
V(Fn=4G,Fn)
(3.2)
f o r 1 5 t 5 n-1 :
(3.3)
for x
[ 1 ,x,(px,. (3.4)
E
Fn\
. . ,,pn-lx] /x
u yl
'pt
{l} :
has no f i x e d p o i n t s # 1
1 U x = [ I } u ( Fn X I G ) ~ X = [ l } (1,GI.x ~
and t h i s implies t h e g e n e r a l case =
n+l
,
x f y
E
Fn
.
=
On Group Spaces Defined by Semidirect Products of Groups
371
We make the following 3.5
Remark
y ( F n w G,Fn) a r e examples of ( n + l ) - t a c t i c a l desarguesian skewaffine spaces with Pappos-condition ( c f . [PZ]). (1)
( 2 ) By the way we note t h a t these examples serve t o show t h e independence of the parallelogram-condition (Pgm). Indeed, the commutator c r i t e r i o n f o r (Pgm) does not h,,ld ( c f . [P2] 3.6). Satz 2 . 1 of [A21 shows t h a t a f i n i t e imprimitive skewaffine space i s k - t a c t i c a l (i.e. ( x
y(
k f o r a l l l i n e s x u y , x # y) i f , and only i f , it i s a
=
a f f i n e space ( i . e . the Def. 2 . 2
, conditions
flat conditions
(Fl),(F2) f o r subspaces hold, c f . [A21
(Sl),(SZ)).
In the desarguesian case such a space is a group space with respect t o an imprimitive Frobenius group and vice versa ([A21 Satz 4.1,4.2). Subsequently we show t h a t [A21 Satz 2 . 1 is a " f i n i t e space result", it does not remain t r u e , i n general, i f X is an i n f i n i t e point s e t . To see t h i s , we take the t a c t i c a l spaces V(Fn*G,Fn)
and show t h a t ( F l ) does not hold, hence they a r e
not semiaffine. 3.6
Example
F l a t condition ( F l ) says: then
if U
<
X i s a subspace of a space X and L $ U
I U n LI 2 1 .
For V(Fn%IG,Fn) we s h a l l now construct a subspace 1
E
U
<
Fn and x
4U
a line, such
that I(xu 1 ) n U l > 1 : ( 1 ) I f U < Fn is a subgroup on which G a c t s (by r e s t r i c t i o n ) , then we obtain the subgroup U X G < FnMG and the corresponding subspace ( U H G I . 1 , c f . [P21 1 . 7 . Obviously
(2)
For 1
# x
(UHGl.1 E
Fn
= U.
the 1-point s t a b i l i z e r is (F X G ) = {[x.gx-l,gl ! g c G), -1" x- 1 = {x} u {l,x'p(x ),xcp'(x ) , ...,X ' ~ " - ~ ( X - ' ) ] .
hence x u 1 = { x } (Fn>dG)x.l ~ With t h i s notation:
(3) Let U be the subgroup of Fn generated by the elements -1 n- 1 -1 ( s ) = anal . Then G a c t s on U and x := a l a2a3 ,...,'p On the other hand: 1 E U and s E (x 1) n U , hence I ( x U Therefore (Fl) does not hold f o r U and V(Fn'>OG,Fn) i s not
u
s : = ala;'
4 U.
, cp(s)
1) n U [ b 2. semiaffine.
Another application of semidirect product spaces i s presented i n t h e next s e c t ion.
=
J. Pfalzgraf
372
4.
TWO GIDETRIC INVARIANTS FOR QUADRATIC FORMS
F i r s t we f i x t h e g e n e r a l n o t a t i o n s . Let A be a commutative r i n g with 1 , M an A-module and q : M form ( c f . [ B ] ) .
-f
A
a quadratic
For a q u a d r a t i c module (M,q) we can d e f i n e t h e following
geometric space (X,<,> ,R) a s a geometric i n v a r i a n t : 9 q(x-y) f o r x # y and X := M , R : = A u {m} , m (4.1) A , < x 7 y > q:= < x , y > := m , x = y. 9 Let O(M,q) o r O(q), f o r s h o r t , denote t h e orthogonal group c o n s i s t i n g of a l l
4
isometries u : M 4.2
+
M ( i . e . u i s a l i n e a r isomorphism with
q(ux) = q ( x ) ) .
Remark
(1) Obviously O(q) i s t h e group of a l l d i l a t a t i o n s of t h e geometric space ( X , < , > q ) which are l i n e a r isomorphisms. (2) I f we had defined < x , y > : = q(x-y) f o r x , y E M , then it i s r e a d i l y 9 seen t h a t q is a n i s o t r o p i c i f , and only i f , (LO) holds f o r (X,<,> 1 . 9 With r e s p e c t t o t h e n a t u r a l a c t i o n of O(M,q) on M we o b t a i n t h e SPS (4.3) V(MMO(q),M) a s another geometric i n v a r i a n t of t h e q u a d r a t i c module (M,q).
Subsequently w e show f o r q u a d r a t i c forms over f i e l d s of c h a r a c t e r i s t i c not 2 t h a t Witt's c a n c e l l a t i o n theorem can be expressed by t h e e q u a l i t y r e l a t i o n o f both geometric i n v a r i a n t s f o r a l l q u a d r a t i c forms over t h a t f i e l d . In [PZ] 3 . 9 , 3.10 t h e following i s mentioned without proof. 4 . 4 Notations ( 1 ) Let A = K be a f i e l d of c h a r a c t e r i s t i c # 2 . X = M a f i n i t e dimensional v e c t o r space over K . We s h a l l r e s t r i c t our c o n s i d e r a t i o n s t o nondegenerate q u a d r a t i c forms q : X cancelled).
+
K ( n o t e t h a t r a d i c a l s of q u a d r a t i c forms always can be
e say "The c a n c e l l a t i o n theorem holds over K" i f t h e following i s t r u e (2) W f o r q u a d r a t i c forms q , p 1 , p 2 over K: q I p1 = q 1- p2 implies p 1 1 pz . 4.5 Theorem With t h e above n o t a t i o n s t h e following is equivalent (1) (2)
The c a n c e l l a t i o n theorem holds over K For a l l q u a d r a t i c forms (X,q) over K t h e geometric space ( X , < , > 9 is equal t o t h e semidirect product space v(X -24 O(q) , X I .
Proof: ( 1 ) + ( 2 ) : Let (X,q) be a q u a d r a t i c form. We s h a l l show t h a t t h e parallel classes of both geometric spaces are i d e n t i c a l . This i s t r i v i a l f o r
On Group Spaces Defined by Semidirect Products of Groups
3 73
diagonal elements ( x , x ) . Therefore l e t x # y, then obviously (X>aO(q)).(x,y) E = { ( u , v ) 1 , i . e . q(u-v) = q(x-y)}. Now we prove the p<x,y>9 9 = <x,y'q
, we s e t w:= u-v (hence w # 0) and <x,Y'q then q(w) = q ( z ) . Now we show the existence of a u E O(q) such t h a t
reverse inclusion: l e t (u,v)
z : = x-y , u ( z ) = w.
E
P
i ) q(w)=q(z)#0 : f o r a:= q(w) = q(z) the two nondegenerate subspaces (K.z,(a))
and (K.w,(a)) of X lead t o orthogonal decompositions of (X,q): (K.z I Xl,(a) 1 q l ) and (K.w I X2,(a) I q2) with q1,q2 nondegenerate. From the isometry (a) I q1 = ( a ) I q2 we obtain by the cancellation theorem an isometry 'p
: q1 = q 2 . Let uo : K.z
K.z
I
X1 = K.w
+ K.w be defined by uo(z):= w, then u := uo X 2 is an element of O(X,q) such t h a t u ( z ) = w.
I 'p
:
ii) q(w)=q(z)=0 : i t follows t h a t dim(X) > 1 and there a r e two hyperbolic
planes H1 = (K.z @ KI. z l , h l ) , H2 = (K.w 8 K.w',h2) belonging t o z,w respectively ( c f . [L] chI 3.2,3.4), with h l ( z ) = h l ( z l ) = 0, Bh ( z , z ' ) = 1 , Bhl being the 1 corresponding b i l i n e a r form of hl (similar with h 2 ) . In the case dim(X) = 2 , i . e . X = H 1 = H 2 there e x i s t s obviously the isometry u ( z ) : = w , u ( z ' ) : = w'. I f dim(X) > 2 , then (X,q) = H1 I (X1,ql) and we can apply lemma 4 . 2 of [B] chIII 54 t o H2 c (X,q), implying the existence of an isometry u ~ 0 ( q )such t h a t ~ ( z )= w (and ~ ( z ' )= w ' ) . Altogether we have proved the existence of a u E O(q) with a(z) = w and w e continue the proof: taking such an isometry u the following holds f o r [v- u y, u] (2)3(1):
E
X 9 O(q): [v-uy,u]. (x,y)= (v+u(x-y) ,v)=(u,v).
Let q,p1,p2 be (nondegenerate) quadratic forms, q = ( a l ) i
...I
(an),
a . # 0 , such t h a t q 1 p1 = q I p2 . By induction we may r e s t r i c t ourselves t o 3 the case n = 1 ( c f . a l s o the remark i n [L] ch1,thm 4 . 2 , s t e p 3 and 4 . 7 ) . Therefore we s h a l l prove f o r 0 # a E K: ( a ) I p1 = ( a ) I p2 implies p1 = p2. Now let ' p : (K.x,(a)) I (Xl,pl) = (K.x,(a)) I (X2,p2) be an isometry. We s e t , y := ~ ( x ) then , q(y) = a = q ( x ) , hence
p
a r e equal, therefore [ t , u ]
9 [t,o].(O,x) which implies t
'p
-1
u : K.x
Cf. a l s o 4.6
I
X2 = K.x
I
X1
E
X >QO(q) e x i s t s such t h a t (0,)')
=
= 0 and u(x) = y = 'p(x). For the resulting isometry we obtain 'p-'o(x) = x and f i n a l l y (X2,p2) = ( X l , p l ) .
[ B l c h I I I 5 4 , Cor. ( 4 . 3 ) .
Remark
The foregoing theorem suggests an a l t e r n a t i v e formulation of cancellation in terms of the two geometric invariants which might be convenient f o r more general s i t u a t i o n s .
3 74
J. Pfalzgraf
5. REMARKS ON GROUP EXTENSIONS
We close with some final remarks on group extensions (5.1) 1 -N-E-tG+l The classification of group extensions involves the first three cohomology functors Hi(G,-), i = 1,2,3 (cf. e.g. [Br] chIV). Let us restrict to the case N = (A,+) a G-module and (5.2) O+A+E+G+l an extension which gives rise to the given G-action (cf. [Brl loc.cit.1, then the second cohomology group HZ(G,A) describes the equivalence classes of extensions (5.2). Such an extension is split if, and only if, E is the semidirect product A-G. The classification of all conjugacy classes of splitting homomorphisms s:G E involves H 1(G,A) = Der(G,A)/Ider(G,A). From a geometric point of view it would be natural to generalize SPSs in passing to arbitrary group extensions. In the case of (5.2) we have the group spaces V(G,A), V(E,A), E acting by conjugation (this is compatible with the original action of G on A). J.Andrk suggested to express the splitting of an extension in geometric terms. This finallv leads to characterize geometrically when a group space is a SPS. Since in the characterization of split extensions derivations and inner derivations play an essential role, it might be very interesting to study these objects from the geometric point of view. Moreover, these observations together with results on simplicia1 structures of geometric spaces give a motivation to try to introduce (co-)homological methods for our geometric spaces. +
REFERENCES ( ,159-168 Andrk ,J.,Zur Geometrie der Frobeniusgruppen. Math.2 .=1977) AndrC ,J.,Eine geometrische Kennzeichnung imprimitiver Frobeniusgruppen. 1981) ,120-135 Abhandlungen Math.Sem.Univ.Hamburg Andr6,J. ,Lineare Algebra uber Fastkorpern.Math.Z.E(1974) ,295-313 Andr6,J.,Noncommutative geometry, nearrings and nearfields. Proceedings of a Conference on Nearrings and Nearfields, Tubingen 1985. Baeza,R.,Quadratic Forms Over Semilocal Rings. Springer Lecture Notes in Mathematics 655, Springer Verlag 1978 Brown,K.S.,Cohomology of Groups. Graduate Text in Math. 87, Springer Verlag 1982 Lam,T.Y.,The Algebraic Theory of Quadratic Forms. W.A.Benjmin, 1973 Wller,K.,Lineare Algebra uber Fastkorpern.Diplomarbeit,Universitat des Saarlandes, Saarbriicken 1984 Pfalzgraf,J.,On a model for noncommutative geometric spaces. J.Geometry g(1985) ,147-163 Pfalzgraf,J.,On geometries associated with group operations. Geometriae Dedicata 2J( 1986) ,193-203
x(
Annals of Discrete Mathematics 37 (1988) 375-376 0 Elsevier Science Publishers B.V. (North-Holland)
375
ON PERMUTATION PROPERTIES FOR FINITELY GENERATED SEMIGROUPS
Giuseppe P i r i l l o I.A.G.A. - I.A.M.I. C o n s i g l i o Nazionale d e l l e Ricerche
Viale Morgagni 67/A Firenze ( I t a l i a )
Summary. we p r e s e n t a f i n i t e l y g e n e r a t e d semigroup which does not have t h e p r o p e r t y
P
d e f i n e d by R e s t i v o and Reutenauer, b u t s a -
t i s f i e s a weaker permutation p r o p e r t y
11
I n t h i s p a p e r , we improve a r e s u l t of
1,
P*.
t o which we r e f e r f o r d e f i n i t i o n s of
p r o p e r t i e s P n , P*, P and P* concerning semigroups. n More p r e c i s e l y , we prove t h a t P i s s t r o n g e r t h a n P*, even upon r e s t r i c t i o n t o f i n i t e l y g e n e r a t e d semigroups.
I n f a c t , we have t h e f o l l o w i n g p r o p o s i t i o n .
P r o p o s i t i o n 1. There e x i s t s a f i n i t e l y g e n e r a t e d semigroup which has t h e property
-
5
and does n o t have t h e p r o p e r t y
P*
Proof. _ _ Let
a
semigroup
and
Let t h e s u b s e t
/
The s u b s e t
I
be two l e t t e r s and
( r e s p e c t i v e l y , f r e e monoid
A+
I = { W 6 A+
b
W
I
of
= U vu2 ;
of A+
A={a, b}
t h e a l p h a b e t of t h e
free
A*).
be d e f i n e d as follows
A+
1
P.
x i y
u l , u2 ~ A * ; v = b a b a ; x L y , l ; i L 1 1
i s an i d e a l of
and t h e Rees q u o t i e n t
A+
S = A+ / I
has t h e r e q u i r e d p r o p e r t i e s . I n f a c t , we can show:
1) S
has t h e p r o p e r t y P
2 ) f o r each 1. Let
n
1. 2 ,
u 1 ' u 2 , u ~,u 4 and u
i) If there e x i s t s a l e t t e r ces
i
and
j
t h e words
* 5;
S does n o t have t h e p r o p e r t y P
5
.
be a r b i t r a r y words of A+.
c €{a, b}
u
1
and
such t h a t f o r a s u i t a b l e p a i r of i n d i u
j
Without l o s s of g e n e r a l i t y , we can suppose ul. and
n
a r e powers
of
c , then
i = 1 and j = 2 .
u2. u3. u 4 . u5
US t h e words
G. Pirillo
376
u 2 . u l . u3. u 4 . u 5 coincide.
Hence, i n t h i s c a s e t h e r e s u l t f o l l o w s .
ii) I f a l e t t e r with t h e p r o p e r t y considered i n i ) does not e x i s t , t h e n f o u r
words among them c o n t a i n
ul, u2, u3, u 4 a
and
u
and
5
c o n t a i n t h e l e t t e r a and t h r e e o f
b.
But i n t h i s c a s e , from t h e d e f i n i t i o n of tations
f
and
g
of
{ l , 2, 3 , 4 , 5)
I , t h e r e a r e two d i f f e r e n t permu-
such t h a t
u f ( 1 ) . u f ( 2 ) . Uf ( 3 ) . uf ( 4 ) . U f (5) and
u g ( l ) . ug(2). ug(3)- u9(4)- ug(5) b e l o n g t o I , i . e . t h e y r e p r e s e n t t h e same e l e m e n t of t h e R e e s q u o t i e n t S = A+ /I.
2. C o n s i d e r t h e f o l l o w i n g n - t u p l e ab, ab
2
,
...,
abn
of words o f A+.
I t i s easy t o see t h a t
2 (ab) (ab )
.... ( a b n ) Z I
( a b f (I) ) ( a E ( 2 ))
.. .. ( a b f ( n ) )
and, f o r every f # i d ,
So, f o r e a c h n > 2 , S d o e s n o t have t h e p r o p e r t y
6
P
n
I
.
REFERENCE
1. G. PIRILLO, On p e r m u t a t i o n p r o p e r t i e s f o r s e m i g r o u p s , P r o c e e d i n g s of t h e I n t e r n a t i o n a l Conference on Group Theory, Bressanone - B r i x e n , May 1986 ( t o appear i n Springer Lecture N o t e s ) .
Annals of Discrete Mathematics 37 (1988) 377-384 0 Elsevier Science Publishers B.V. (North-Holland)
ON k-SETS OF TYPE (O,m,%)
377
IN S 21,
Rita PROCESI CIAMPI
-
q
WITH THREE EXTERIOR HYPERPLANES
Rosaria ROTA
Dipartimento di Matematica, UniversitP degli Studi di Roma "La Sapienza", Piazzale Aldo Moro 5, 00185 Roma, Italia
It is well known that the study of k-sets of type (m,n) in an affine space is equivalent to the study of kcsets of type (O,m,n) in a projective space such that their exterior lines are only those belonging to a fixed hyperplane. This consideration suggested us the problem of studying the k-sets of type (O,m,n) such that the exterior lines are exactly those belonging to two [l] or three hyperplanes. In this paper we present the results concerning the case of three exterior hyperplanes either belonging or not belonging to the same pencil. In the first case necessary conditions are stated for the existence of such k-sets. In the second case we obtain a non existence theorem for r25.
1. INTRODUCTION with three exterior hyperplanes S1 Let K be a k-set of type (0,m,n) in S r-1 ' r>9 i S2 , S:-l not belonging to the same pencil and let S t - 2 = Sp-ln$-l , i,j,
.
r-1
h E C 1,2,3} and not in S
; such subspaces intersect in a
i
^sr-3
,K
-
For an S'
r-2
containing S
r-3
with exactly one n S k 2 is a k'-set of type (0,m,n) in S ' r-1 r-2 exterior hyperplane. Furthermore for S" containing S and different from r-1 r-2 Si and S' , KnSi-l is a k"-set of type (0,m,n) in S"r-1 with two exterior r-1 r-1 hyperplanes. Therefore [l] : 1.1. There does not exist in S , r25,a k-set of type (O,m,%) r>4 exterior hyperplanes not belonging to the same pencil.
with three
-..IS1r-I' Sr-I' 2 S3 is a k-set of type (O,q-d,q-l,q). r,q r-1 If we now consider the case in which the three exterior hyperplanes belong to
We first observe that K
the same pencil, K
= S
this case, for any S '
=
S
ISr-]
' Sr-1
'Sr-l
r>4 containing the
r-1
. S
1 is of type (O,q-2,q).
r-2
Furthermore in
intersection of the three exterior
hyperplanes and different from them, K n S ' is a k'-set of type (O,m,n) with r-1 exactly one exterior hyperplane, thus, for r > 3 , [ 3 ] only three cases are possible for (m,n) : (0,I), (q-l,q) and ( ( q - i q l / Z , (q+dql/d) q odd square, therefore: O
Research supported by G.N.S.A.G.A.
-
C.N.R.
R. Procesi Ciampi and R . Rota
378
1.2. If a k-set of type (U,m,n)
with three exterior hyperplanes belonging to a
-
-
,r>3, then q must be an odd square and rn=fq-Jq)/Z,n=(q+Jq)/2.
pencil exists in S
TJ9
To study the cases r = 3 , r=4, we will need the results concerning the case r=2.
k-SETS OF TYPE (O,m,n)
2.
IN
TI
4
L e t K be a k-set of type (O,rn,n) in
with exactly three exterior lines not 4 belonging to a pencil. A s in L21 we can obtain for k the equation: TI
o
k ' - k L ~ + i q + ~in+m-lI i I+rnn~q'+q-~i =
(2.1)
We must observe thatK
n..{r r } is a k-set of type (O,q-Z,q-I), k=q'-2q+l q 17rz>3 and this is the only possible case for n-m=I . In fact for 7FQ-2, n=q-:, k = =
q'-2q+I
=
i s the only acceptable solution of ( 2 . 1 )
( 2 . 1 ) we obtain A = 4(n-1) [n(q+3)-q(q+l)/+I
if and only if n l q ( q + l ) / ( q + 3 )
,
ing t o a pencil and n-m=l, thenK =
in TI
Li
7~
1
J
,
3
for P.
in
with three exterior lines not belong-
9
{rl,r2,r3 I .
represent the numbers of um,un,uA,u',w n m ,wn,vm,vn
m-secants and n-secants respectively for: = r . n r . , R#P.=rinrh
. Otherwise, for m=n-1
wich is greater or equal to zero
and thus n=q-1. Therefore:
2.1. If K is a k-set o f type (O,m,n)
We shall now recall that [l]
,
,
Q E ~ -bY,rl,r2,r3},
4 i=1,2,3 , and for TEK
.
for REr. and RfP = h Since the values of such
numbers do not change in this case, we have:
, k must satisfy 1 2 . 2 ) 9 and m ( q t l ) ~ k ~ ? l i n ( n ( q - l ) , n ( q + l / - q;) furthermore m=s(n-m) , n = I s + l )(n-m) and 2.2. For the existence of a k-set of type (U,m,n)
n-m divides q and k
in
TI
.
2.3. If .Y is a k-set of type (O,m,n)
in
TI
ing to a pencil and K is prime then K =
with three exterior lines not belong-
4 7~
~
4
h1,r2,r3}
.
We must now observe that: u
=
0
implies
k = m(q+l) , k 1
2
= n ( q + l l - q , n = q ( q + l ) / ( q + 3 ) ; such value
of n is an integer only for q = 3, from which rn
w rn
=
0
implies
k
v
=
0
implies
q = 3
m
1
= n(q-I)
,n
, k 2 = miq+l)-q+2n , m = 2n-q 2
,m =
1 which implies vm
=
=
1
,n
=
. 1 (impossible).
From these and the analogues for the other values rl] we obtain:
2
On k-Sets of Type fO,m,nl 2 . 4 . Through any P#Ph, h=1,2,3
379
, at least one m-secant and one n-secant must
pass. Through Ph at least one n-secant must pass, but not necessarily one msecant. In fact w =O implies m=Zn-q, k = n(q-I), m 1 The equality m=2n-q
k
2
=
m(q+2).
, m=q-Za
can also be expressed as n=q-a
, a ( q , and
we have: 2.5. The values m=q-2a , n=q-a lead to integers solutions of ( 2 . 1 ) for any a dividing
4.
Furthermore from 2 . 4 .
the following is also true:
2.6. If K is a k-set of type (O,m,q-2)
then m=q-2 and K=II \ I r r r 1 1' 2' 3 q
.
Let now n=q-2 and then liu 2 3 . The first case u =I is easily excluded. For 9-2 9-2 u =2 then k =2q+mq-m-4 and k =q2-4q+Zm+2 , thus: 9-2 1 2 m'iq-11-m(2q~-7q+7)+q3-6q'+~oq-4 =o, of which the only possible integer solution is m=q-4 and u
2=2 give u s k=(q-4)(q+2/
9-
2.7. If a k-set of type (O,m,q-2)
. The values m=q-4, n=q-2 . Thus:
=(q-4)/2 which implies u 9-2 with u
k=(q-4)(q+2l.
=2 exists in II
4
q-2
, then q=8, m=4 and
.
For u and k =q2-5q+3m+4 With the same tecnique as =3 , then k =(m+3)(q-2) q-2 1 2 before, together with the condition w 20 , we obtain:
m
2.8. If a k-set of type (O,m,q-2)
with u =3 exists in II then only two cases 9-2 9 are possible: 1) m=q-4, k=(q-lI(q-Z) or 2) q=10 , m=q-4 , k=(q+/(q+Z/
.
The following proposition gives the only possible example f o r case 1) in 2.8. 2.9. If K is a k-set of type (O,q-4,q-2)
where
r
.
and k=(q-Zl(q-2)
thenK=n \{T,rl,r2,r3} 4 is an oval passing through the three intersecting points of r l,r2,r3 and
vice versa.
Proof. Let r"={Q, is an oval in
II
. 9
,...,Qq-?}
, Qi&KU{r1,r2,r3). We prove that r=r"u{P ,P ,P 1 1
Let us consider a line r different from r l,r2,r3
2
3
. If P . E ~ 1
then r is a (q-Z)-secant since w =0, thus r must contain exactly one Q.EI'' . q-4 J If P.dr and r is a (q-Z)-secant, then r is exterior to T ; otherwise rnr={Q.,Q.}. Thus
r
1
is an oval; the vice versa is obvious.
Let u s now consider some special cases. If.n-m=2
, thus 7'9
discriminant of (2.I) is A=4m2(q+3)-4m(q2-q41+(q+2)'
and q even, the
and A 2 0 if and only if
J
R.Procesi Ciampi and R.Rota
3 80
mB where: A=(q2-q-6-Jq4-3q3-18q2-4q+24)/2(q+3)
.
B=(q’-q-6+Jq4-3q3-18q2-4q+24)/2(q+3)
2.10. If.? is a k-set of type (O,m,n)
and
It is easy to verify that A C 2 , B>q+;thus: and n-m=2,
then m=q-4, n=q-2.
Similarly for n-m=3, q>8 : 2 . 1 1 . If K is a k-set of type (O,m,n)
and n-m=3 , then m=q+,
n=q-3.
In general for n-m=a we obtain A20 if and only if m
,
.
~=(q‘+q-aq-3a+Jq4+q3-2qZ,2q3-4a~q~-a~q~a~)/2(q+3)
For a=4 and q > 2 3 is A<4; thus: 2.12.
If K is a k-set of type (O,m,n)
and n-m=4, q > 2 3 , then m,B
.
The cases q=16, q=20 give respectively the pairs ( 4 , 8 ) or (8,lZ) and (12,16). At this point let u s consider the case in which the exterior lines belong to a pencil. We must observe that the (2.1) does not change in this case as the formulas for u , u ,u’,u’,v ,v , while it results: w =( n ( q - 2 ) - k) / ( n - m ) and w m n m n m n m =(k-m(q-Z))/(n-m) Proposition 2 . 4 . thus becomes:
=
.
2.13. Through any P#Ph
,
h=1,2,3
,
at least one m-secant and one n-secant must
pass. Through Ph at least one n-secant must pass, but not necessarily one msecant. In fact w =O implies k = n ( q - 2 ) , k =3n+m(q+l)-q, m 1 2
m=/3nq+n-q2+2q)/2q
.
Because of the different formula for w we also obtain a different limitation m for k ; namely m ( q + l ) ~ k ~ m i n ( n ( q - 2 ) , n ( q + l ) - q thus ), proposition 2.5. becomes: 2 . 1 4 . The values m=q-Za, n=q-a give kq(q-2)
for any a dividing q
as only possible solution of (2.1),
.
Following the previous results we obtain: 2.15. I f K is a k-set of type (O,m,q)
with three exterior lines belonging to a
pencil, then m=q-2 and K = T I ,{rl,r2,r3}. 9 2 . 1 6 . There does not exist any k-set of type (O,m,q-l)
with three exterior lines
belonging to a pencil. Proof. Let PET \&,rl,r2,r31
4
and PEr which i s a Iq-1)-secant;
then r n r n r = 1 2 3 k =q2-2q+m and thus
=1, from which we have k =(m+l)q-I, 1 2 q-1 m2q-m(2q2-4q+3)+lq3-3q2+2ql=0 with non acceptable solutions. Similarly:
=Ssr. This implies u
On k-Sets of Type (0,m.n)
381
There are no k-sets of type (O,m,q-2) with three exterior lines belonging
2.17.
to a pencil.
From these results and those obtained in the case of the exterior lines not belonging to a pencil we have: 2.18. I f a non trivial k-set of type (O,m,n) with three exterior lines belong-
ing to a pencil exists, then n-m>2. For n-m=3 must be m=q-6, n=q-3. there are no non trivial k-sets of type (O,m,n) 4 with three exterior lines belonging to a pencil. 2.19.
3.
I f q is a prime, in
i l
k-SETS OF TYPE (O,m,n) I N S
Let K be a k-set o f type (O,rn,n)
3,q
AND S
4,q
in S 7
'J4
with three exterior planes
i11,i12
,i13
not belonging to a pencil. I f we consider the points o f K distributed over the
.
.
planes of the pencil through an n-secant t intersecting the line rh= n l n n J , we obtain the following relation: IKI=k+Nk +(q-N)k2-/q, where k k are the s o l u 1 I' 2 tions of ( 2 . 1 1 , ;=I?[ , where I?=Kn;i,and ii=tUrh , moreover N is the number of those planes through t intersectingli in a kl-set. Similarly for an rn-secant in ii
, we obtain: IK [=i+Mk 1+(q-M)k2m q . Thus N-M=(n-mlq/& where
-
A is the discrimi-
h nant of (2.1). Since n-m divides n,m then N-M=q/JA',A'=A/(n-mlL and, as q=p , A ' = p Z 2 , l
.
The case A ' = l is easily excluded. We will also need the relation
, where
A
is the discriminant of ( 9 . 1 ) in [l].
results of 1 2 . and those obtained in
ill
Summarizing the
we get:
3.1. The necessary conditions for the existence in S
o f a k-set o f type 339 (U,m,n) with three exterior planes not belonging to a pencil are: n-rn divides
q,m,n,k
, 5<m
. Furthermore if n-m=3
then rn=q+, n=q-3. If q is
a prime there are no k-sets of type (O,m,n) with three exterior planes not belonging to a pencil in S
3,q
.
Moreover the number k=IKI must satisfy: (3.1)
(n+m-l)]+mn(q4+q3-q2-2q+l) k2-k[l+(q2+q+l)
=0
.
-
We now consider the following four cases: (a) q odd square, m=(q-/q)/2, n= h =(q+/T)/Z; ( 8 ) q=zh; (Y) q=p2, p # 2 ; ( 6 ) q=p p > 2 , h>2
-
(a) Solving ( 2 . 1 ) , ( 3 . 1 ) and ( 3 . 1 ) of [l],
i = ( q z & q d w ) / 2, k=(q3f_i;;JZq3+qL-3q+l)/2
Thus the following must be true: 2q-I=U2
we get:
, k '=(q+,qi-)/2
.
, 3q-2=b2 , 2q3+qL-3q+I=cL, which
R . Procesi Ciampi and R . Rota
382
proves to be impossible, then: -
-.
,q
3.2. In S
odd square, there are no k-sets of type ( O , ( q - J q l / 2 , f q + J ~ ) / 2 )
3,q with three exterior planes not belonging to a pencil.
(13)
Since A ' = ~ + 4 ~ ( s + l ) = 2 ~, ~and
a
is odd (see Ill),
it results:
h
3.3. In S , q=2 , there are no k-sets of type (O,m,n) 334 planes not belonging to a pencil.
with three exterior
az
(2~+1)+2IZs+l)~-2+p~-7, ,
(y) In this case a ' = ( p ' + l ) p L + ( 2 s + l ) 2 ( p ' + l ) - 2 p i p ' + l /
with z=1 or 2=2. The value z=1 is easily excluded; for 2=2 we obtain:
( 2 ~ + 1 / ~ ( p ~ + 3 ) - 2 p ( p (2s+1)+2p'-2 ~+l) t/pG-3pL+5)/(p3+3)
.
=
D
,
from which 2 s + ! = f p ( p L + 1 ) +
Since ( p ' - 1 ) L < p 6 - 3 p L ~ < ( p ' ) L , we get:
, q = p L , p # 2 , there are no k-sets of type (O,m,n) 3,q rior planes not belonging to a pencil.
3.4. In S
with three exte-
(6) Finally in this case the study of A ' leads to the condition: p -P 3h+P 2h-2a P 2h+P 2z+k<0, where l < z i h and n-m=pa.
4k-2a
+p
3h-2a
-
Thus:
3.5. If a k-set of type (U,m,n) pencil exists in S 3,9
,
with three exterior planes not belonging to a 22 q=ph, k # 2 , then a W 2 , 2,h-a In-m=pa, A'=p ) .
Since proposition 1.1. denies the existence of k-sets of the aforesaid type for
r>4 , we only have to consider r=4. In this case summarizing the previous results we obtain:
3.6. In
a k-set of type (U,m,n) with three hyperplanes not belonging to a 4,q h pencil can not exist if: q is prime, q=2 , q=p2, q odd square and m = ( q - / q ) / 2 , h n=(q+/q)/Z Furthermore if q=p , h#2 , a necessary condition for the existence 22 1. of such a k-set is: a < h / 2 , z>h-a fn-m=pa,A'=p S
.
We can now consider the case in which r=3 and the three exterior planes belong to a pencil. In this case k=lKl must satisfy:
k'-k
(3 . 2 )
[Z
+ I q'+qtl ) (n+m-l
)I tmn (q'+q
-4' - 2 q ) =U
.
Furthermore the general condition for the existence of such k-sets are the f o l lowing:
, q prime, the only possible k-set of type (O,m,n) with three ex3,q [r1,n2,n3}. Moreover if a non terior planes belonging to a pencil is K = S 3,q k trivial k-set of the aforesaid type exists in S , q=p , then n5q-3, n-m divides 394
3.7.
In S
'
On k-Sets of Type (0.m.n) m,n,q
3 83
.
and n-m#1,2
Since the proofs of 3 . 3 . , 3 . 4 . and 3.5. are based on equation ( 2 . 1 ) , the analogous propositions are still true when the three planes pass through a line r.
-
-.
If q is an odd square m=(q-Jq)/Z, +qJ2qz+q-2)/2
n=(q+Jq)/2,
from
and (q3+qJ2q2+q-2)/2=dq+(q-2) (q2-q)/2,
planes through r intersecting K in a fq2+q)/2-set
where
d
is the number of
(see r31). Therefore: 7q2-
.
from which q=(12d+23~J3Zd2+88d+1)/14 Moreover, if rln,
-q(12d+13)+4d2+8dt6=
0,
then n ( ) K is a &set
of type (O,(q-Jql/Z,fq+Jqi/d)
-
-
-__
belonging to a pencil, thus ;=(q2+JqJ3q-2)/2. 3 . 8 . If
(3.21 we have k=(q3+
with three exterior lines
From these observations follows:
I< is a k-set of type (O,(q-JSi/Z,fq+J~)/Z)
in S , q odd square, with 3,9 three exterior planes passing through a line r, the following integers must be perfect squares: 2q +q-2,
3q-2,
32d +88d+I, where d is the number of planes
through r intersecting K in a (q2+q,J/2-set. Finally, for r > 3 3.9.
, proposition 1.2.
can be extended as follows:
If K is a k-set of type (0,(q-&)/2,
planes belonging to a pencil in S for any t such that 2
Proof. For every S
.
PJ
,
4
fq+JG)/2) with three exterior hyper-
t-1 +q-2=aL t’
r23, q odd square, then Zq
s
I
in S non containing k =kf\S must satisfy the r,q r-2’ t $9 9 , whose discriminant must then be a equation: k2-k qt+qt-’/q(qt’’-2qt-’-q+2)=0 t,q
t
t
perfect square.
REFERENCES
111 r21
L31
Procesi, R. and Rota, R . , Sui k-insiemi di tipo (O,m,n) di uno spazio di Galois Sr,q, in print. Tallini Scafati, M., Calotte di tipo (m,n) in uno spazio di Galois Sr,q. Rend.Acc.Naz.Lincei (8) 53 1972, pp. 71-81. Tallini Scafati, M., I k-insiemi di tipa (m,n) di uno spazio affine Rend.Mat. (1) 1981, vol. 1, Serie VII, pp. 63-79.
This Page Intentionally Left Blank
385
Annals of Discrete Mathematics 37 (1988) 385-390 0 Elsevier Science Publishers B.V. (North-Holland)
AN ALGORITHM FOR L
S
-
COLOURATIONS
Luigia PUCCIO Dipartimento di Matematica 1-98100 Messina, Italy *
-
Universitg di Messina
An algorithm for L - colourations of undirected graphs is described. This algorithm gua:antees an optimal colouration and the correct value of the s-chromatic number for an arbitrary graph. Moreover, it can be used in case of directed graphs too.
1. INTRODUCTION Let G=(V,E) be an undirected graph and K a mapping of V into a set C whose elements are called colours. K is an L - colouration of G if for any x,y E V, x # y , K(x) = K(y) implies d(x,y) > s,swhere d(x,y) is the distance of y from x in G [lo, 1 7 1 , i.e. the minimum length of all chains from x to y. When s = 1 an L - colouration is the usual colouration. If K ( x ) # K(y) for all x,y E V, then 1 K is called an L m - colouration. Unless otherwise stated, by a graph we always mean a simple, i.e. without loops and multiple edges, connected and undirected graph. The s-chromatic number is defined as the minimum number of colours, y s ( G ) , such that G has an L - colouration. S
The determination of the s-chromatic number and some related parameters has been the subject of a good amount of research papers (see references). It is well known that classical colourations have many applications. The same is true for L - colourations. Since their definition implies the idea of distance betwEen vertices, a graph with an L - colouration can provide an S . interesting model to solve typical problems i n Operations Research, e.g. the location of emergency centres, or medians, and transportation and assignment problems. Let G=(V,E) be a graph; for any s E X , s > 1, and x E V, define Fs(x) = { Y E V : d(x,y) T (x) =
{y
gs(x) =
*
E V : d(x,y)
{X
:
>
s
}
< =
s + l },
V\c(x),
X CV, d i d < s+l } , G
Research supported by the Community of Mediterranean Universities.
L. Puccio
386 where X
G
is the subgraph of G whose vertices art. in X ;
d (G) =
max
1X1
x €gS
,
d (G) is called the s-density of G ; S
As(G) = obviously, d s ( G )
2
Y s ( G ) - ds(G) ;
0.
The most important result is that, for every s > 1 and any h E W , there exists a planar graph such that d (G) = h. Therefore, As(G) : s
sup (
>
1, G t .? ) =
00
,
where 9 is the set of all planar graphs. Fig. 1 shows such a planar graph; the black vertices yield the minimal configuration for s = 2 and k = 2h - I .
In [8] the problem is posed of finding the values for the following parameters: v (h) = min { n S
d s ( h ) = min { n
€
N
€
:
m (h) = min {n E W
N
:
3
G = (V,E) 3 '
3G
=
(V,E) 3'
:
3
G = (V,E)
IVI= n
=>
1 V 1 = n + d (G) 3' I E 1 = n =>
As(G) = h )
=> A
,
( G ) = h}
As(G) = h }
,
,
where s, h are positive integers. The values for those parameters are known just in very few cases. In general, upper bounds are known [13] which might be improved. The facts we just recalled seem to provide a good motivation for the research of an efficient algorithm for such L - colourations. Here we present an algorithm which guarantees both an o&imal L - colouration and the correct value of the s-chromatic number for an arbitrary graph. Furthermore, this algorithm applies also to directed graphs for which L - colourations can be S defined in a similar way [IS].
2.
DESCRIPTION OF THE ALGORITHM
There are many algorithms for the classical colouration. They are based on different procedure such as formulation as a zero-one programing [2] , sequential methods based on vertex ordering [ 141, backtrack methods [ 151 , optimal independent colourings [ 19 ] , formulation as a set covering problem [ 31. Our algorithm is an appropriate combination of the last two ones. In fact, its procedure is a formulation as a set covering problem, where the sets of the coverings are maximal independent 1-chromatic sets, called maximal 1-subgraphs. Recall the following definitions and theorem. An independent set of a graph G=(V,E) is a subset of V such that no two of its vertices are adjacent in G. An independent set is maximal when there is no independent set containing it. THEOREM [ 3 ] - If a graph is r-chromatic then it can be coloured with r (or
A n Algorithm for L,-colourations
387
L. Puccio
388
fewer) colours first colouring with one colour a maximal indepentent set S [GI, 1 Sl[G]>] and so on, until
next colouring with another colour a set S [
-
colourations as we next show. For a graph
G=(V,E) define the graph GS=(Vt,E') as follows. V' = V and for any x,y E V, ( x , y )E E' if and only if dG (x,y) < s + l . Thus in GS=(V',E') there is a link between x and every element in the set $(x).
PROPOSITION - A classical colouration of G'=(V?,E') G=(V,E), and conversely.
is an L - colouration of
Clearly, this result plays a fundamental role in the realization on our algorithm.. We try to find an optimal colouration of G S = ( V ' ,E' ) whit the help of the above mentioned theorem; consequentely, we get an optimal L S colouration for G = ( V , E ) and its s-chromatic number. 2.1. Steps of the algorithm
We just outline the procedure. The program of its implementation is written in FORTRAN 77 and was tested on several graphs. Such directed and undirected graphs were constructed by means of a random generator program [ b ] Details of the programs are available from the author.
.
STEP 1 - INPUT:
n = number of vertices of G=(V,E),
A = incidence matrix of G, s = kind of colouration. STEP 2:
Calculate the incidence matrix B of GS=(V',E'). By definition, GS has no loop. Then , from the classical formula to calculate the reachability matrix it follows
STEP 3: Find all maximal 1-subgraph of G. Consider T (x) €or every x E V=V'. Maximal independent sets are subsets of TS(xj u {x) They are found by depth-first search.
.
STEP 4: Store all maximal 1-subgraphs in an array Q in decreasing order of their numbers of vertices. Such an ordering turns out to be useful to find the optimal colouration. All maximal 1-subgraphs yield a covering of the vertex set V=V'. We have to find a partition with the minimum number of elements since we want an optimal colouration. Thus, the element number of the partition is the s-chromatic number 7, (G)
.
STEP 5:
Assign the first colour to the vertices of the first maximal 1subgraph in 9, i.e. the 1-subgraph with the maximum vertex number.
STEP 6: Consider the sequential next maximal 1-subgraph in the array 9.
An Algorithm for Ls-colourations
389
Three cases may occur: (a) All its vertices are coloured. Return to step 6. (b) No vertex is coloured. Assign to all vertices another colour. Return to step 6. (c) Some vertices are not coloured. Put them in a list L with pointer. Return to step 6. When all maximal 1-subgraphs are investigated, look at the list L. If L is empty, go to step 8. Colour vertices o f list L which are distinct and not coloured. There is a different colour for every not vanished pointer.
STEP 7: a) b)
STEP 8 - OUTPUT:
3.
List vertices of G with their own colours and the schromatic number Ys(G).
COMMENTS
We have the best implementation of the algorithm if the incidence matrices of G=(V,E) and GS=(V' ,E' ) , and the maximal 1-subgraphs storage array are logical. Obviously, the algorithm efficiency depends on the dimension of these matrices. However, if we use the algorithm to improve the first values of the parametres vs(h), ds(h), ms(h),then the incidence matrices of considered graphs are not too big. When the graph G is the model for a problem in operations research its incidence matrix can be very big but,usually, it is a sparse matrix. Therefore, we can use sparse matrix techniques. In the wrost cases, we can -S consider the complement G of GS. Then an L - colouration of G is obtained s -s assign the same colour to adjacent vertices of G If this is the case, we (G) instead o f T (G). consider the set
r
In [18] M
-
.
S
colourations are defined for directed graphs.
Let G=(V,E) be a directed graph and K a mapping of B into a set C of colours. - colouration o f G if for any x,y E V, x # y , K(x) = K(y) implies there is zo path from x to y with length less than s+l. 0 (G) is the schromatic number.
K is an M
In case of directed graphs the incidence matrices are not symmetric. Nonetheless, our algorithm can be used, with no changes, also for M S colourations.
REFERENCES [l] (21
[3]
[41
Antonucci, S., Generalizzazioni del concetto di cromatismo d'un grafo, Boll. Un. Mat. Ital., (5) 15-B (1978) 20-31. Berge, C. Graphes et hypergraphes, (Dunond, Paris, 1970). Christofides, N . , Graph Theory, an algorithmic approach, (Academic Press, 1975). Gallo, G., Pallottino, S., Ruggeri, C. and Storchi, G., Metodi ed algoritmi per la determinazione di cammini minimi, Monografie di Software
390
L. Puccio
Matematico N.29, I.A.C. (1984). Gionfriddo, M., Sulle colorazioni L d'un grafo finito, Boll. Un. Mat. S Ital., (5) 15-A (1978) 444-454. Gionfriddo, M., Su un problema relativo alle colorazioni L, d'un grafo planare e colorazioni L , Riv. Mat. Univ. Parma, (4) 6 (1980)151-160. [71 Gionfriddo, M., Alcuni risultati relativi alle colorazioni Ls d'un grafo, Riv. Mat. Univ. Parma, (4) 6 (1980) 125-133. Gionfriddo, M., Sul parametro A s d'un grafo Ls- colorabile e problemi i8 relativi, Riv. Mat. Univ. Parma, (4) 8 (1982) 1-7. Harary, F., Graph Theory, (Addison-Wesley, 1960). Kramer, F. and Kramer, H., Un problsme de colrolation des sommets d ' u n graphe, C.R. Acad. Science Paris Ser. A 2 8 (1969) 46-48. [ 11-1 IAzzio, A. and Milici, S., Determinazione di v3(i), v3(2), v4(;) in un grafo e condizioni sufficienti per A = 0 , Riv. Mat. Univ. Parma. Marino, M.C. and Puccio, I $ . , Su alcuni parametri associati a colorazioni L,, in un grafo finito non orientato, Le Matematiche, vol. XXXV, fasc. 1-11 (1980) 301-310. [13 Marino, M.C. and Puccio, L., Sul parametro d,(G) d'un grafo planare, Riv. Mat. Univ. Parma, (4) 9 (1983) 9-13. Matula, D.W., Marble, G. and Isaacson, J.D., Graph colouring algirithms, from Graph Theory and Computing, (Ed. Read, R.C., Academic Press, 1972). I15 1 Nijenhuis, A. and Wilf, E., Combinatorial Algorithms, (I1 Ed., Academic Press, 1978). Sedgewick, R., Algorithms, (Addison-Wesley, 1984). Speranza, F., Colorazioni di specie superiore d'un grafo, Boll. Un. Mat. Ital., (4) 12, supp. fasc. 3 (1975) 53-62. Speranza F., Sur les colorations des graphes orientgs, Boll. Un. Mat. Ital., (5) 1 6 - ~(1979) 517-522. 1191 gang, J., ACM 21, (1974), 385.
I
I
39 1
Annals of Discrete Mathematics 37 (1988) 39 1-394 0 Elsevier Science Publishers B.V. (North-Holland)
A BLOCKING SET
IN PG(3,q),
q
2
5
Sandro Rajola Dipartimento di Matematica Ist ituto “G. Cas telnuovo” Universitl degli Studi di Roma “La Sapienza” 1-00185 Rome, Italy
z
A blocking set i s constructed in PG(3,q), q 5, which turns out to be the first example of a blocking set when q = 5.
1. INTRODUCTION A blocking set S in PG(3,q), GF(q),
the 3-dimensional projective space over the field
is a set of points meeting all lines and containing none.
In [2] it was proved that, for any prime power q , there exists an integer b(q)
< b(q), such that blocking sets exist in PG(r,q) provided that r -
whereas r>b(q)
rules out their existence. Furthermore, in [61 it was shown that b(2) =1,b(3)= 2, and b(q)
2
3 f o r any q > 7 . The last result was achieved producing examples of blocking sets in PG(3,q), q 2 7.
=
Therefore, the existence of blocking sets in P G ( 3 , 5 ) was an open problem. Here
> 5. Consequently, b(q) 2 3 , a blocking set is constructed in PG(3,q) for any q q
2
5.
In sect. 3 it is shown that a blocking set exhibited in [ 6 ] is reducible and an irreducible one is constructed starting from it.
2. THE CONSTRUCTION Let 01,02,03, and V be four independent points in PG(3,q), vertices of
a
q
2
5, i.e. the four
thetrahedron T . Take a point O4 on the edge OIV of T , other than
O1 and V, which is possible as q
5. The plane through 0203and 04 meets the
faces 0 0 V and 0 0 V in the lines 0204 and 0304,respectively. Next, take any 1 2 1 3 point A1 on 0102\ {01,02] and this is possible by the previous remark. Similarly, take any point B1 on 0204\ {02,04}. Let Z = AIBl n 0 V and C be a point on 2 1 0 2 V \ {Z,02,V]. Next, take A2 on 0103\ {O ,O } and B2 on 0304\ {O ,O 1. Let 1 3 3 4 T = A2B2 n 0 V and C2 be a point on 0 V \ {T,O ,V}. Finally, choose a point D on 3 3 3 the line 0203 other than O2 and O3 and non-collinear with any of the pairs A1A2, B1B2, and C1C2. Such a choice is possible by the following argument.
S. Rajolu
392
Denote by A ' , B', and C ' the points on 0203 collinear with the pairs A A 1 2' B1B23 and ClC2, respectively. Even if the five points 02, 0 3 , A ' , B', C' are all distinct, at least one point remains on 0203to be taken as D. Denote by E
1' the points on 0 V \ {O ,O ,V}, and n(L,M,N) the plane spanned by the 1 1 4 three independent points L, M, and N; whenever it is the case, the plane is
E2,
...,Eq-2
considered only as the set of its points. Define the set S by
\(O 10 2 u 0203u 0301u U {A , A
1
2
, B , B ,C
1
2
1
olv u
02v
u 03v u
0204
" 0304))
,..., Eq-2 1 .
, C ,D,E1,E2
2
Notice some symmetries in S: the faces 0 0 V and 0 0 V are similarly constructed, 1 2 1 3 as well as 0203V, 020304, and 0 0 0 1 2 3' We claim that S is a blocking set. Firstly, we prove that S contains no line. Since the points of S on the faces V and 0 0 V are distributed in a similar way, it suffices to show that one 1 2 1 3 of them contains no line. A line Q on n ( 0 ,O ,V), (1 # 0102,OIV, 02V, 0204, is 1 2 contained in S iff it passes through A 1, B1, C1, a contradiction as thosepoints
0 0
L # 0203,02V, 03V, belongs to S iff it is on C1, C2 and D which is impossible since such points are not collinear. The same argument proves that neither the face 020304nor the are not collinear. Similarly, a line R on r(02,03,V),
face 0 0 0 contains lines. 2 3 1 Next, any line R in PG(3,q), not on a face of T, meets S at five points at most since R\
S
consists of points on five planes; thus, there is at least one point on
s.
Finally, we show that any line R meets S. This is obviously true for the sides of the triangle 0 0 V and for the lines on E j 1 2 j'
=
1,2,. . . , q - 2, as well as for
0 0 on n ( 0 ,O ,V). On the other hand, by the construction o f S , on any other 2 4 1 2 line of n ( 0 ,O ,V) at most three points lie off S. The same argument applies to
1 2 n(01,03 ,V). Next, we turn to n(02,03,V).
Of course, the lines 0203, 02V and 03V meet S and
the same occurs for the lines on Cl, C2 and D, respectively. Keeping in mind the construction of S , on any other line of n(0 0 ,V) three points at most lie 2' 3 off S. Similarly, all lines on n(02,03,04)and n(02,03,01) meet S. Since S consists of points on five suitable planes, any line Q meeting those planes off the lines O.O., 0 V meets S , (i,j) 1 J
S
=
(1,2),(1,3),(2,3),(2,4),(3,4),
s = 1,2,3. On the other hand, it is easy to check that all lines incident with
both VOi and ojoh meet S , (i,j,h) a permutation of (1,2,3) or (i,j,h)=(3,2,4),
A Blocking Set in PG(3,q), 4 2 5
393
(2,4,3). F i n a l l y , i f R i s a l i n e i n c i d e n t w i t h 0102 and 0304, t h e n e i t h e r R i s on one of and n(01,03,V),
t h e p l a n e s T I ( O ~ , O ~ , OT~ I)(, O ~ , O ~ , O n(Ol,02,V), ~), meets S , o r R meets t h e p l a n e n(02,03,V)
so t h a t R
a t a p o i n t on S. (Take i n t o account
t h a t S i s c o n s t r u c t e d by d e l e t i n g some p o i n t s from t h e edges of T . ) The same argument shows t h a t any l i n e meets S which meets b o t h 0103 and 0204. Obviously, any l i n e on a v e r t e x of T meets S. F i n a l l y , a l i n e R n o t on any v e r t e x of T and i n c i d e n t w i t h one edge of T meets one f a c e of T a t a p o i n t on S . Thus, S i s a b l o c k i n g set i n PG(3,q) f o r ’ a n y q > 5.
3. AN IRREDUCIBLE BLOCKING SET F i r s t of a l l , o b s e r v e t h a t t h e b l o c k i n g s e t c o n s t r u c t e d i n s e c t . 2 may be red u c i b l e . I n [ 6 ] a b l o c k i n g s e t was e x h i b i t e d i n PG(3,q)
f o r any even q
2
8.
Here we show t h a t such a b l o c k i n g s e t i s r e d u c i b l e and produce a n i r r e d u c i b l e
one s i t t i n g i n i t . The c o n s t r u c t i o n i n [ 6 ] i s a s f o l l o w s . Take a p l a n e TI and a h y p e r o v a l on n, s a y
C. Denote by 0
j’
j = 1,2,3,
any t h r e e p o i n t s on
c
and d e l e t e from ?r t h e p o i n t s
on O . O . \ {Oi,O.}, i , j = 1,2,3; t h i s y i e l d s a b l o c k i n g s e t S on n. L e t O4 be any 1 J J p o i n t o f f TI and r t h e cone p r o j e c t i n g c from 0 4 . D e l e t e from r the p o i n t s on
r*.
0.0 \ { O . } ; t h i s gives a s e t C a l l nT t h e p l a n e OiOh04, ( i , j , h ) a permutaJ 4 J I t i o n of ( 1 , 2 , 3 ) , from which t h e above mentioned p o i n t s have been removed. The
T
*U ( n * .
j = 1,2,3) i s a b l o c k i n g s e t i n PG(3,q). j’ T h i s b l o c k i n g s e t i s r e d u c i b l e ; namely, w e can d e l e t e from K t h e p o i n t s on set K = S U
* and s t i l l have a b l o c k i n g s e t , s a y K*. * * Obviously, S \ C = S i s a b l o c k i n g s e t on n. S i n c e K w a s a b l o c k i n g s e t , i t * * s u f f i c e s t o show t h a t any l i n e R o f f n and T and m e e t i n g IT on C a c t u a l l y * * * meets K . S i n c e R meets a t most one of 040j, i t m e e t s n. f o r some i. Hence, K C\
( 0 ,O
I
Z
,O
3
} = C
i s a blocking set. F i n a l l y , we show t h a t K
*
is irreducible, i.e. that there is at least onetangent
* , PO4
a t each p o i n t . For any p o i n t P on S
n;;
t h e p l a n e w = P040j meets
r*
i s a t a n g e n t a t P. Next, t a k e P on
a t a g e n e r a t o r g . L e t G = g n C*.
t o check t h a t GP i s a t a n g e n t a t P. Now suppose P i s on P040j, any j; w . l . o . g . , A =
R n 0203 #
02,03;
assume j = 1. This p l a n e meets
AP i s a t a n g e n t a t P.
It i s e a s y
T*; t a k e t h e p l a n e i n a l i n e R on O1 and
IT
394
S. Rajola
REFERENCES Bruen, A.A., Blocking sets in finite projective planes, S I A M J . Appl. Math. 21 (19711, 380-392. Mazzocca, F., and Tallini, G., On the non-existence of blocking sets in PG(n,q) and AG(n,q) f o r all large enough n, Simon Stevin 59 (1985), 43-50. Rajola, S . , Un esempio di blocking set in PG(3,q) per ogni q > 5, Quad. Sem. Geometrie Comb. n. 57, Nov. 1985, Dipart. Mat. Univ. Romz, "La Sap ienza" . Rajola, S., Blocking sets, k-insiemi e fibrazioni i n PG(r,q), Tesi, Univ. Roma "La Sapienza", a.a. 1985-86. Tallini, G., Problemi e risultati sulle geometrie d i Galois, Kelaz. n . 30, 1st. Mat.,Univ. Napoli, 1973. Tallini, G., k-insiemi e blocking sets in PG(r,q) ed in AG(r,q), 1st. Mat., Univ. L'Aquila, 1982.
Annals of Discrete Mathematics 37 (1988) 395-398 0 Elsevier Science Publishers B.V. (North-Holland)
395
A CHARACTERIZATION OF ALL ABELIAN GROUPS WHOSE LATTICE OF PRECOMPACl GROUP TOPOLOGIES REPRESENTS A PROJECTIVE GEOMETRY Dieter Remus c/o Institut fur Mathematik, Lehrgebiet D Universitat Hannover, Welfengarten 1, 0-3000 Hannover, F.R.G. First, two structure theorems in the sense of the title are proved. Then all projective spaces are characterized for which the correspondent lattice of subspaces can be embedded in the lattice of precompact group topologies of some abelian group. AMS Subject Classification. Primary 52 A05; Secondary 06 CIO, 22 A99. 1.
NOTATION AND CONVENTIONS
For lattices notation and definitions are used as in L4] . The order relation on a lattice L is denoted by I If equality does not hold, one writes < .vX means the supremum for every Xc L. For X = {x,, x2) one writes x, v x2 instead o f VX. Let a, beL. Then a
.
2.
RESULTS
DEFINITION 1. A topological group is said to be precompact if it is precompact with respect to its left (right) uniformity. REMARK. A Hausdorff precompact topological group is isomorphic to a dense subgroup of a compact group.
D.Remus
396
It is easy to show that the set of (not necessarily Hausdorff) precompact group topologies on a group G forms a complete lattice PK(G) with respect to In this paper some results of geometrical nature on the strucinclusion [5] ture of the lattice PK(G) and an embedding theorem for the lattice o f subspaces of Desarguesian projective spaces are stated. From lattice theory one needs - see 14) -
.
DEFINITION 2. Let L be a lattice. (a) arL is called cmpact iff a i V X for some X c L implies a< VX, for some f i nite X1 c x. (b) L is called ( 1 ) semimodular iff it satisfies the upper covering condition, that is, a
.
To get a relation with projective spaces one needs from [4] , P. 204 3 - A geometry is called projective if the associated geometric lattice is modular.
Precompact Group Topologies
391
Observe that the notion "projective space" in [4] , Def. 3, p. 202 includes the degenerated case "a line has exactly two points". Then one has a one-to-one correspondence between projective spaces, defined by points and lines, and projective geometries, defined by modular geometric lattices ( 143 , Theorem 6, p. 204). Since the lattice PK(G) is modular, one obtains from Theorem 1 COROLLARY. Let G be an abelian group. The lattice PK(G) represents a projective geometry iff G is an elementary group of bounded order. Now it suggests itself to examine the existence of a class of groups G with the property that the lattice PK(G) represents a nondegenerated projective space for which a coordinatization by some vector space is possible. Theorem 2 gives an answer. For the proof one uses LEMMA 2 ( [5] , (2.9)(b), p.40). For every abelian group G the lattice PK(G) is isomorphic to the lattice of subgroups of the (algebraic) dual group G* o f G. THEOREM 2. Let G be an abelian group of cardinality m. The lattice PK(G) represents a Oesarguesian nondegenerated projective space of dimension at least two iff G is an elementary p-group with m2p3. Then the coordinatizing vector space equals Z(P)~if m is infinite, and Z(pIn if m is finite, where pn=m with some natural number n13.
PROOF. (a) If PK(G) represents a projective space, then PK(G) is geometric. By Theorem 1 G is an elementary group of bounded order. Let L be a lattice which is isomorphic to the lattice of subspaces of a vector space. Then it holds ( [2] , p.108): For distinct atoms p,, p2cL there is an atom pfL being distinct from p,, p2 such that p, vp2+. If G is not a p-group, then it is easy to see by the aid of Lemma 2 that PK(G) does not fulfil the quoted property. Therefore, G is an elementary p-group if PK(G) possesses a representation described in the assertion. (b) Let G be an elementary p-group. Then G ?' @Z(p) for m2%, and for m<%, , where pn=m with some some & ( [3] , Theorem 8.5, p.43). G = @Z(p) G for ~ m>%, and G* the dual group G* of G one infers G* 2 Z ( P ) for For m< h, . [3] , Theorem 8.5, p.43 implies that every subgroup of G* is also a subspace of the vector space G* over the field Z(p). Combining this with Lemma 2 one concludes that PK(G) i s isomorphic to the lattice of subspaces of the vector space G*. Since only nondegenerated projective spaces o f dimension at least 2 are considered, one gets the condition m>p3. 0 Theorem 2 shows that the lattice of subspaces of a Desarguesian nondegenerated space can be identified with the lattice of precompact group topologies
D.Remus
398
of an abelian group only in a special case. In general, one has THEOREM 3. Let P be a (not necessarily nondegenerated) projective space and L the lattice of subspaces of P. Then L can be embedded in the lattice of P P precompact group topologies of some abelian group iff P is Desarguesian. PROOF. From [4] one needs the following results: (1) Let L be a complemented modular lattice. Then L can be embedded in the lattice of subgroups of an abelian group iff L is arguesian ( Theorem 20, p.213). (2) Let L be a modular geometric lattice. Then L satisfies the arguesian identity iff Desargues' Theorem holds in the associated projective geometry ( Theorem 8, p.205).
(a) If P is Desarguesian, then ( l ) , (2) imply that L can be embedded in P the lattice L(G) of subgroups of some abelian group G. By [5] , (2.52), p.59 the lattice L(G) is isomorphic to a sublattice of PK(H) of some abelian group H. (b) Let L be isomorphic to a sublattice o f PK(H) of some abelian group H. P Using Lemma 2, L can be embedded in the lattice of subgroups of the dual group P H*. NOW apply (l), (2) to complete the proof. 0 REFERENCES [I]
N. Bourbaki: General Topology, Part 1. Addi son-Wesley Pub1 i shing Company, Reading , 1966
[23
P. Crawley, R.P. Dilworth: Algebraic Theory of Lattices. Prentice-Hall, Englewood Cliffs, N.Y., 1973
]3[
L. Fuchs: Infinite Abelian Groups, Vol. I Academic Press, New York, 1970
[4]
G. Gratzer: General Lattice Theory. Birkhauser-Verlag, Basel, 1978
]5[
D. Remus: Zur Struktur des Verbandes der Gruppentopologien. Dissertation, Universitat Hannover, 1983. English summary: Resultate Math. 6 ( 1983), 151-152
.
Annals of Discrete Mathematics 37 (1988) 399-404 0 Elsevier Science Publishers B.V. (North-Holland)
3 99
Hans-Peter SEIDEL Mathematisches Institut der Universitat Tiibingen Auf der Morgenstelle 10
D-7400 Tubingen. W-Germany
It is shown that in a 4-dimensional stable plane (M.9) every group of r with common center c E M and common axis A E Se is CC.Al
homologies
isomorphic to a closed subgroup of the multiplicative group Cx of
complex numbers. 1. DEFINITIWS
AND STAlElIEHF OF RESULTS
1.1.Definition
A stable plane is a pair (M,Y) consisting of two locally compact Hausdorff topological spaces M and 9 of finite positive topological dimension, the point space M and the line space Y , respectively, such that the following axioms hold: (u)
Any two distinct points x,y E M are on a unique line x
u
y E 9, and the
maPP ing u:
M
x
M
\ {(x.x):xEM}
+ 9: (x,y)
--f
x
u
y
is continuous. (n)
Any two distinct lines K.L E 9 contain at most one common point K
the set 9):= {(K,L)€S?x%:KflL#0}
0
L E M.
of pairs of intersecting lines is nonempty and
open in 9 x 9. and the mapping J W: (K,L) * K n L 0:
is continuous.0 Classical examples of locally compact stable planes are the projective planes over IR. C , M. 0 and their open subsets like the classical affine or hyperbolic planes. But there also exists a variety of nonclassical stable planes and even planes that cannot be embedded in any topological projective plane at all. For further information see e.g. [14].[4]
and references given there.
It is known in general that the point space of a stable plane can only have the classical dimensions 2. 4.
8. 16 and that
the group of all continuous
collineations of (M.9). if endowed with the compact open topology, is a locally
H-P. Seidel
400
compact topological group, see [6],[4].
If dim M
<4
then M and all its lines
L E Y are topological manifolds. In this paper we shall study groups of homologies
r CC*Al consisting
of all
collineations of (M.9) having a comon center c E M and a common axis A E Y with c
e
A . It is easy to see and well known that in a locally compact stable plane
with dim M = 2 every such homology group
r cc.A1
is isomorphic to a closed
subgroup of the multiplicative group Rx of the reals. In this paper we shall study the case dim M = 4 and prove the following theorem: 1.2.Theorem Let (M.9) be a stable plane with dim M = 4 and consider c E M, A E Y with
e A.
r[c.Al
is isomorphic to a closed subgroup of the is multiplicative group C" of complex numbers. More precisely, Cc.al isomorphic to one of the groups Z. %. Z x %, R . S0,R. R x SOJR x Z, C x . where k is any integer.0 c
Then the homology group
4.
The following example shows that there are in fact nonprojective 4-dimensional stable planes (M.9) admitting a nontrivial group of homologies c E M and A E 9:
r [..A1
with
1.3.kample
Let P,C be the classical projective plane over the complex numbers and consider a point
c and a line A with c k? A. Let I: Au= t(P,C)
denote the full
automorphism group of P,C and let Z be any nontrivial compact subgroup of the homology group I
[..A1
= C". Consider the orbit K of a point x E P2C\(A U {c})
under I:. Define M:= PzCW and let 9 denote the lineset that is induced on M by PzC.
Then (M,Y) is a 4-dimensional nonprojective stable plane with c E M and
A E 3, and the group of homologies
given group Z . 0
r
Cc.Al
< r:=Aut(M.2)
is isomorphic to the
It is an open question to what extent the analogue to Theorem 1.2 remains true for 8- and 16-dimensional planes. There are however some partial results which indicate that this m y be the case at least for topological translation planes
PI. 2. DISCXEIE SWXIUPS
OF
r
[CAI
2.1 .w
discrete subgroup of
r [c,A]'
<
r[c * A1 be a closed Furthermore let a be a point on A. and define
Let (M.9) be a positive dimensional stable plane and let C
Groups of Homologies in 4-Dimensional Stable Planes
L:= c
u
40 1
a. Then the following holds:
(1) Z acts properly discontinuously on X:= L\{c,a}. (2) The orbit space Y:= x/c is a locally compact Hausdorff space. (3) The canonical projection p: X + Y is a regular covering with group C. Proof: We only have to prove (1)
and (2). Since C operates freely on L,
according to a criterion given in [lO:p.166,Ex.8.5] it suffices to check that for every compact subset S of X the set R:= {u€C:u(S)fE#0} is finite. Otherwise R contains a sequence tun} such that {un(x)}
converges to c for every
X, see [5:3.12]. Now consider points xn E S with un(xn) E un(S) n S # 0 . Since S is compact we may assume xn + y , un(xn) + z with y,z E S. But since C operates equicontinuously on X [5:3.13] this would imply that u (y) cannot n x
E
converge to c, a contradiction.0 2.2.Proposition
Let (M.9) be a 4-dimensional stable plane and let Z
< r cc.'41
be a closed
subgroup with dim C = 0. Then C is either cyclic or isomorphic to the direct product Z x
% of
the group of integers Z with some finite cyclic group
% of
order k. Proof: (1) Consider a and L as in Lemma 2.1 above. According to [4]. L is homeomorphic to an open submanifold of the 2-sphere S,, and since effectively on L, both
r
CC.Al
r [c.A]
and C are Lie groups, i.e. C is discrete. If C is
finite, the assertion follows by a theorem of P. A. Smith [15] (Consider the is homeomorphic to action of Z on the line pencil Y ). Otherwise X:= L\{c.a} a Rz\{O}, see [5:3.18], and Lemma 2.1 above implies that the fundamental group r(Y)
of the surface Y:= x/c contains an infinite cyclic normal subgroup
(7)=
p,(r(X))
<
r(Y) such that 2 is isomorphic to the quotient group ~(Y)/(T).
(2) I f Y is noncompact. its fundamental group r(Y) is free [l].
hand r(Y) operates on the cyclic normal subgroup relation a - 2 v - a 2 =
7
(7)
On the other
of r(Y) and we get the
for every a E r ( Y ) . Together this implies that r ( Y ) must
be infinite cyclic itself, and we obtain that Z = r(Y)/(7)
is cyclic of finite
order. (3) We are left with the case that the surface Y is compact. Since according to
[5:3.0]
the action of Z on L is orientation preserving Y is an orientable
surface, of genus g. say. We claim that Y is homeomorphic to the torus T: The
....ag'PJ3 :r) where r is the fundamental group r(Y) is given by r(Y) = (a,,P,, [ai.Pi]. If Y has genus g 2 2. then the Freiheitssatz [9:p.252]
relation r =
implies that the subgroup 3:= (ai.Pi)of H(Y)
is freely generated by ai and
and the Same argument as in (2) above shows that the generator infinite
cyclic
normal
subgroup
(7)
<
r(Y)
satisfies
the
7
pi
of the relation
H. -P.Seidel
402
a,-2*7*a12= -r = pl-2-~*p,2.Thus -r cannot be contained in 3 . But then nE according to a theorem of G. H. Bagherzadeh [8:p.203] the group 8:= T-Z-T-' is cyclic and contains both a,' and Pl2.Hence E cannot be generated freely by a, and p , , a contradiction. Therefore Y is in fact homeomorphic to the torus T and our group Z = r ( Y ) / ( - r )
= (Z x Z)/(T)
i s isomorphic to a subgroup
of Z x %.O
3. PROOF OF THE MAIN THEORM We now complete the proof of Theorem 1.2:
Proof: (1)
r [c.A].
Throughout this section C will denote the full homology group
E A and define L:= c u a. We consider the action of C on X:= L\{c,a}. According to section 2 and since C acts freely on X we are left with the case that C is a Lie group of dimension 1 or 2. (2) Case 1: dim 2 = 2. It is easily seen that in this case 2 is noncompact. Thus according to [5:3.18]
Take a point a
the set X:=L\(c,a} must be homeomorphic to IR2\{O}.
Therefore Z is isomorphic to
Ex and the assertion follows.
(3) Case 2: dim Z = 1. Let C1 denote the identity component of Z. Then both C and Ci act freely and equicontinuously on X and have closed orbits [5:3.8].
A criterion given in
[3:p.140.1.6] thus implies that the quotient space Y:= X/C'
is a locally
mi also
operates freely
compact Hausdorff space and since the quotient group
on Y we obtain that V C 1 is homeomorphic to each of its orbits C(x)fl'.
C' is isomorphic to the circle group S O . $ . Since the isotropy groups :C are all trivial it follows from a result of Mostert [ll] that 2' has no singular orbit on X. Hence Y must be homeomorphic to the open unit interval (0.1). But then, according to a theorem of Holder [12:p.8].[13]. the group is isomorphic t o some subgroup of the additive group IR of the real numbers and, since V C i has closed orbits, a result of (4) We first consider the case where
mi = ( j i ) is infinite cyclic. It is now easy is isomorphic to the semidirect product of its
R. Lowen [7:Th.2.6] implies that to check that C = Z'
x
connected component Z' Proposition 2.2
p
(ji)
with an infinite cyclic group (p). According
to
commutes with every element 6 E Z1 = SOJR of finite order,
hence this product must be even direct, and C = S02R x Z is isomorphic to a closed subgroup of C x . (5) We are left with the case that 1% is isomorphic to the additive group IR of the reals. Since Z'
X:= L\{c.a}
is noncompact. i t follows again from [5:3.12.3.18] that
is homeomorphic to R2\{O}
and that the connected orbits Z'(x)
(x E X) have nontrivial intersection with every neighbourhood of c or a. The
Groups of Homologies in 4-Dimensional Stable PIanes
403
restriction of the canonical projection p: X +EL to the standard unit is therefore surjective and Y:= E' is compact. Hence the
sphere St of IR2\{O}
discrete quotient group Z/Z' finite, and
it
being homeomorphic to each of ist orbits is
follows e.g. from a theorem of Gaschiitz [16:p.231]
that
F is a semidirect product of Z' with some finite group F. According to section 2, F is cyclic and centralizes every 6 E 2 ' . Therefore Z is isomorphic
X = Z'
x
to the direct product IR x Q of the additive group of reals with some finite cyclic subgroup
% and Theorem 2.1
is proved.0
c11 Ahlfors, L.V. and Sario. L . , Riemann Surfaces (Princeton University Press, Princeton N.J.. 1960)
PI
Buchanan, T. and HZhl. H., On the nuclei of 8-dimensional locally compact quasifields. Arch. Math. 24 (1977) 472-480
c31 Dugundji, J., Topology (Allyn and Bacon, Boston, 1970) c41 Lowen. R.. Vierdimensionale stabile Ebenen. Geom. Ded. 5 (1976) 239-294
c51 Lb'wen, R., Central collineations and the parallel axiom in stable planes, Geom. Ded. 10 (1981) 283-315 [GI
Lb'wen,R., Topology and dimension of stable planes: On a conjecture of H. Freudenthal, Journ. reine u. angew. Math. 343 (1983) 108-122
c71 Lowen, R., Lacunary free actions on the real line, Topol. Appl. 20 (1985) 135-141
PI
Lyndon, R.C. and Schupp, P.E., Combinatorial Group Theory
(Springer,
Berlin, Heidelberg, New York, 1977)
191 Magnus, W.,
Karrass. A.
and
Solitar, D., Combinatorial
Group Theory
(Interscience Publishers, New York. London, Sydney, 1966)
[lo]
Massey. W.S.,
Algebraic Topology: A n
Introduction (Springer, Berlin,
Heidelberg. New York. 1977) [ll] Mostert. P.S.,On a compact Lie group acting on a mifold. Ann. Math. 65 (1957) 447-455;Errata. Ann. Math. 66 (1957). 589
[12] Priess-Crampe. S . . Angeordnete Strukturen (Springer. Berlin, Heidelberg, New York, 1983) [13] Salzmann. H.. Kompakte zweidimensionale projektive Ebenen. Arch. Math. 9 (1958) 447-454 [14] Salzmann, H., Topological planes, Adv. Math. 2 (1967) 1-60
[15] Smith, P.A., New results and old problems in finite transformation groups, Bull. Am. Math. SOC.66 (1960) 401-415 [l6] Suzuki, 8 . . Group Theory I (Springer, Berlin. Heidelberg. New York, 1982)
This Page Intentionally Left Blank
Annab of Discrete Mathematics37 (1988) 405-412 0 Elsevier Science Publishers B.V. (North-Holland)
405
POLYNOMIAL SPECIES AND CONNECTIONS AMONG BASES OF THE SYMMETRIC POLYNOMIALS
Domenico SENATO A n t o n i e t t a M. V E N E Z I A
1.
U n i v e r s i t h di N a p o l i Univ. d i R o m a "La S a p i e n z a "
INTRODUCTION
I n t w o p a p e r s p u b l i s h e d in 1968 ( s e e [S] ) G . C . R o t a , c a r r y i n g t o the limit the a l g e b r a i c p r o c e s s e s w h i c h B a x t e r a n d o t h e r s introd u c e d for t h e r e s o l u t i o n of p r o b l e m s g e n e r a t e d by t h e o r y of p r o b a b i l i t y , s h o w s that e v e r y i d e n t i t y in a B a x t e r a l g e b r a is e q u i v a l e n t to a n i d e n t i t y b e t w e e n s y m m e t r i c f u n c t i o n s . I n h i s s e c o n d p a p e r t h e Author proves,through combinatorial methods, classical identities b e t w e e n s y m m e t r i c f u n c t i o n s w h i c h t r a n s l a t e i d e n t i t i e s in B a x t e r a l g e b r a s of p r o b a b i l i t y i n t e r e s t . T h e c o n c e p t of g e n e r a t i n g f u n c t i o n o f a f u n c t i o n s e t , c o n v e y e d in these p a p e r s , is d e v e l o p e d later by D o u b i l e t , R o t a a n d S t a n l e y (see [ 4 ] , [9]).These A u t h o r s i n t r o d u c e a p r o c e s s f o r t h e c o n s t r u c t i o n o f a l g e b r a s of g e n e r a t i n g f u n c t i o n s , b o t h c l a s s i c a l a n d innov a t i v e , for the r e s o l u t i o n of e n u m e r a t i v e problems. U s i n g the c o n c e p t of g e n e r a t i n g f u n c t i o n of a f u n c t i o n s e t a n d t e c h n i q u e s i n v o l v i n g the l a t t i c e o f p a r t i t i o n of a s e t , D o u b i l e t (see [ 3 ] ) d e r i v e s m a n y of t h e k n o w n r e s u l t s a n d n e w o n e s a b o u t s y m m e t r i c f u n c t i o n s . I n m a n y c a s e s D o u b i l e t u t i l i z e s the M o b i u s i n v e r s i o n f o r m u l a , but h e a l s o s u c c e d s in g i v i n g b i j e c t i v e p r o o f s of i d e n t i t i e s b e t w e e n s y m m e t r i c functions. T h e s e p r o o f s c o n s i s t e s s e n t i a l l y i n a n i n t e r p r e t a t i o n o f t h e f u n c t i o n s t h a t o c c u r in t h e i,dentities i n t e r m s of s e t s a n d i n f i n d i n g a b i j e c t i o n s b e t w e e n them.
I n t h i s p a p e r w e u s e t h e t h e o r y of p o l y n o m i a l s p e c i e s (see [ l ] ) w h i c h g i v e s a s y s t e m a t i c a p p r o a c h to t h i s k i n d o f proof. We p r o v e with bijective arguments, some identities which occur among the c l a s s i c a l b a s e s of s y m m e t r i c p o l y n o m i a l s of d e g r e e n. T h e l a n g u a g e is t h a t o f c a t e g o r i e s t h e o r y a n d t h i s e m p h a s i z e s t h e g e n e r a l i t y d e g r e e of the c o n c e p t of species.
2. Let
POLYNOMIAL SPECIES
9
ApecieA
be the c a t e g o r y of f i n i t e s e t s a n d b i j e c t i o n s . A , L i n i f e ( s e e [ 5 ] ) is a f u n c t o r M f r o m 9 to
L e t E , F E Ob( @ ) , w e s h a l l d e n o t e by t u r e s o n E a n d by M[u], uEHom(E,F),
.
t h e s e t of M-structhe bijection between
M[E]
D. Senato and A.M. Venezia
406 N[E] on
, ~ n d M[F]
obtained "transforming i n t o a n M-structur? on F.
E
via
u
"
every M-structure
The c o n c e p t of p o l y n o m i a l s p e c i e s i s a g e n e r a l i z a t i o n of f i n i t e species i n the sense t h a t the polynomial species f in addition t o carrying the structures, defines a subset t i o n s from a f i n i t e set t o a set of v a r i a b l e s as s p e c i f i e following.
t h a t of unctor,
ot d
tunciri
the'
X = { x . : i E y } b e a f a m i l y o f v a r i a b l e s w i t h i n d i c e s i i i il non e m p t y aAd t o t a l l y o r d e r e d s e t 3 Let I b e t h e f u n c t o r From t c the category Ens o t sets and f u n c t i o n s d e f i n e d by: Let
.
and,
for
A 5 E
each
dnd
I [ u ] ( t ) Let M from
be
9 to
a
U
ttom(~,x) A L E f : A + X ,
I[EJ=
=
fou
-1
: u ( A ) +
f i n i t e s p e c i e s . We s h a l l Ens defined as follows:
denote
M[E]
x I[E]
Pol(M)[E]
~
X.
by
Pol(M)
the
functor
pu4ynurnia~! 4 p e c i e 4 i s a n y s u b f u n c t o r P of Pol(M), i.e. for each E O b ( @ ) , P[E] i s a s u b s e t of Pol(M)[E] s u c h t h a t i f u€llom(E,t') (s,f)EP[F:] t h e n (M[u](s), I [ u ] ( f ) ) E P[F]. I t P i s a s u b t u n c t o r and of Pol(M) we s h a l l write P c Pol(M).
A
E
The
c a t e g o r y of
polynomial
species
is
defined as
follows.
Let
M
and N be f i n i t e species, and let y be a natural transformation of M t o N . We d e f i n e a n a t u r a l t r a n s f o r m a t i o n of t h e polynom i a l species Pol(M) t o the polynomial species Pol(N) as follows. Pol(M)[E] is the set (YE(s),f) , a5 (s,f) The image of t h e s e t ranges over Pol(M)[E]. It P and Q a r e polynomial species, we define Horn( P , Q ) t o b e t h e s e t of n a t u r a l t r a n s f o r m a t i o n s of P t o Q which are r e s t r i c t i o n s t o P and 0. o f s o m e n a t u r a l t r a n s t o r Y : Pol(M) Pol(N), where P E Pol(M) and Q c _ Pol(N). In mation particular, we w r i t e P=a , when P a n d a r e naturally equivalent i n t h i s category.
-
a s s o c i a t e t o each polynomial species d generating function which c o n s i d e r s b o t h t h e s t r ~ c t u r ea n d t h e s u b s e t o f f u n c t i o n s d e t e r m i n e d by t h e s p e c i e s .
We
.
Let C b e a c o f i n i t e s u b s e t of X We w r i t e , i f t o denote t h e polynomial obtained from p by s e t t x E C. I f p E Z[X] we let N(p,C) b e t h e s e t of such t h a t L qIc=". T h i s d e f i n e s a topology Let Z[(X)] the completion ot Z[X] and al(X)
P/~,"
p 6 Z[X], PIC=" ing t o 0 a l l a l l q E Z[X] on the ring the algebra
Z[X]. over
Polynomial Species 2
P:
g e n e r a t e d by X. A f u n c t i o n E +al(X) d e f i n e d by: ice)
f: =
407
E-+ X determines a function for each e E E .
f ( e )
We shall call genenafuzy monomial of the f u n c t i o n of Z[(X)] d e f i n e d by:
Let
P
C_
be a polynomial
Pol(M)
gen(PIE1)
=
f
the element
s p e c i e s . W e set:
c
p[E]se"(s>f)
( S , f )
g e n ( s , f ) = genif). W e note that gen( P[E]) depends o n the where cardinality of E a l o n e a n d so w e set: gen(P[E]) = gen( P , n ) for E such that / E l = n . We shall call gen( P , n ) n t h - c o e f each s e t
ficienf
poiynomial uf
P.
.the 4 p e c i e 4
T h e y e n e n a t i n g f u n c f i o n Gen( P , z ) o f t h e p o l y n o m i a l s p e c i e s the formal power series Gen( P , z ) with
coefficients in
=
gen( P , n )
n 2 0
p is
X:
2 [(X)].
T H E O R E M 2.1. P o i y n o m i a l 4 p e c i e 4 i 4 o m u n p h i c h a v e t h e 4ume y e n e n u f A n g Luncfion.
3.
THE S P E C I E S OF THE A S S E M B L I E S
W e i n t r o d u c e n o w t h e n o t i o n of a s s e m b l y of f i n i t e s p e c i e s . L e t N "01 = 0. W e s h a l l b e a f i n i t e s p e c i e s w i t h o u t c o n s t a n t t e r m , i.e. c a l l a44em64y o f 4 f / r u c L u n e 4 o f 4 p e c i e 4 N o n the finite set E a E o n every block of w h i c h a s t r u c t u r e of species N partition of is d e f i n e d . F r m a l l y a n a s s e m b l y is a p a i r (",SJ where n=(B: B S E } is a p a r t i t i o n o f E and S,= ( s : s E N[B]}. B
{assemblies
Expk(N)[E]
B
Exp (N) og f h e a 4 4 e m b 4 i e 4 is i e f i n e d a s follows:
The 4pecie.l of onden k :
T h e 4pecie.1
Exp(N)
(.Z
on
,SJ
01 4 f n u c f u n e 4 og
E
1x1
{assemblies on
Let
be the set of the partitions of
E }
4pecie4 N
.
=
with
E
k
block and
a p o l y n o m i a l s p e c i e s w i t h o u t c o n s t a n t t e r m (i.e.P[@]= P C POl(F1) 0 ) . A n a44embly o n E o f onden k o{ o p e c i e d p is every pair (s,f) s i) Sa
where: =
( a , S a )
={
sg:
is a n a s s e m b l y of species
B € a
,
sB E
M[B]
),
M
with
N
k).
=
or f h e a 4 4 e m b l i e . 1 o,f 4 f n u c t u n e 4 o f
Exp(N)[E] P/k/
with
4pecie4
Z E $(k)
and
is
D.Senato and A.M. Venezia
408
there exist, for every B f n, a function f B (sB,fB) E p[B], f is defined o n a set A n B , then f i i i ) if A = u ( A n B) and f/A A = fB. B E Jc ii)
The 4pecie4 uc a44emhiie4 uc polynomial species Exp ( P ) k Expk( P)[E] = { assemblies o f T H E O R E M 3.1.
{-on a n y
Gen(Exp(
P K O P O S I T I O N 3.1.
is defined o n
k is the defined a s follows: k P - s t r u c t u r e s of o r d e r k). k Cen( P , z ) k E N id: Gen(Exp ( P ) , z ) = k k !
P - d n u c t u a e 4 0; Pol(Exp (M))
P),z)
uaden
C_
T h e ~ i i p e c i e i u f -the u 4 4 e r n 6 l i e d o c 4 p e c i e 4 Exp( €')[El s p e c i e s Exp( P ) d e f i n e d b y T H E O R E M 3.2.
that
e
=
is the polynomial Expk( P)[E]. = k
P
Gen( P , z )
yf P and Q a n e i 4 o , n o / c p h i c , i h e n ~ x p( P ) = ~ x p ~ ( t
a).
an isomorphism between P and a . An a s s e m b l y of structures of species p is a partition n such that o n each block B f n a structure ( s , f ) EP[B] is d e f i n e d . The bijection associates to PE: E x p ( P)[E] E x p ( aB[Ef the assembly of species a t r e l a t e d to partition n s u c h ( ( n ,Sn),f) that o n each B the structure eg(s fB) is defined. The bijection Q E determines the requested natural flomorphism. Proof. (
Let
@
( n, S n , f )
-
4.
Let
C O N N E C T I O N S A M O N G B A S E S OF S Y M M E T R I C P O L Y N O M I A L S n
be a n i n t e g e r . A p a n f i t i o n o f
ri
is any sequence ( h )
( A , , . . . I , ) o f n o n n e g a t i v e i n t e g e r s i n d e c r e a s i n g o r d e r A,
T
> ...> . L q
s u c h t h a t t h e i r s u m i s n. T h e n o n - z e r o h i a r e c a l l e d t h e p a n 2 4 of ( h ) and the number of the parts is the l e n g t h o f ( A ) . S o m e t i m e it is convenient to u s e a n o t a t i o n which indicates the n u m b e r s of time ) means that exactly e a c h i n t e g e r o c c u r a s p a r t : ( A ) = (I" 2r2 ri o f t h e p a r t of ( A ) a r e e q u a l t o i.
...
ile n o t e t h a t e v e r y p a r t i t i o n n o f a s e t B w i t h / E l = n d e t e r m i n e s ) o f n , w h e r e ri is the number of t h e p a r t i t i o n ( n ) = (Ir]2r'2 blocks of w i t h i e l e m e n t s . W e s h a l l c a l l ( n ) c l a s s of n .
...
The symmetric polynomials of degree n in the variables x 1 w i t h r a t i o n a l c o e f f i c i e n t s h a v e f o u r c l a s s i c a l bases.
T h e e i e m e n t a a g o y r n n e f n LC { u n c t c o n 4 :
...
Let p E N and a = 2 x i sequences i, i p p s u c h t'hat
,...
b e set:
ah
=
aA,
aA2...aAs
x
i
, . . .x t
aL
w h e r e the sum is over a l l the < il, I t.
i,<
...
Polynomial Species
The m o n o m i a l 4 y m m e f n i c L u n c L i o n 4 :
409
kA
w h e r e the s u m is o v e r a l l d i s t i n c t m o n o m i a l s w i t h d i s t i n c t indices.
The homogeneun
elementafiy f u n c t i o n 4 :
Ex il...xit 1
L e t P E N and h p = il, i such that
...
i
hA
w h e r e the s u m is o v e r all the s e q u e n c e s = p. W e set:
+.t.+it 1 hA
h4".hAq
=
The p o w e n 4 u m , l u t z c t i 0 ~ 4 : s1 t
L e t P E N and
s
p
=
2
.
xp
i=l
I
s
1.
We set: =
s
1,
... A, 5
When(A)ranges o v e r all p a r t i t i o n s of t h e i n t e g e r n , the s e t s {aA}, {kA}, {hA}, { s A } a r e the c l a s s i c a l b a s e s of the s y m m e t r i c p o l y n o m i a l s of d e g r e e n. Let be the f i n i t e s p e c i e s d e f i n e d by I[E]={E}. We d e n o t e w i t h S G P o l ( T ) the p o w e n 4 u m d p e c i e d defined by f:E-X constant]. T h e n t h - c o e f f i c i e n t of the g e n e r a t i n g S[E]= {(E,f): f u n c t i o n of S is:
L e t t E N and P t h e f i n i t e s p e c i e s d e f i n e d by t P t [ E ] = { p a r t i t i o n s of E w i t h t blocks}. W e d e n o t e w i t h K t t h e polynom i a l s p e c i e s K t [E]={(n,f): In( = t , f:E--X, k e r f 2 IT} C Pol(Pt)(E]. T h e n t h - c o e f f i c i e n t of the g e n e r a t i n g f u n c t i o n s of K t is: gen(Kt,n) T h e o t h e r hand:
c
=
E P t [El
kerfBII
w h e r e ( a ) = (1" 2 " . alone, hence setting
sl!
=
s2!
O P n
.. ) . bA=
gen(Kt,n) =
k e r f ? II
gen(n,f)
...k
(0)
T h e s u m o n the r i g t h d e p e n d s o n s2!. .kg), w e h a v e
,EF[E]
sl!
b.,=
.
j,,+'.+At
=n
(Ai...Lt)
(A)=
(I)
!at !
from which
THEOREM 4 . 1 .
Expt(S)
=
Kt
P r o o f . T h e b i j e c t i o n t h a t t o any p a i r ((n,Sn),f) EExpt(S)[E] assoc i a t e s the p a i r (n,f)EKt[E] d e t e r m i n e s the r e q u e s t e d i s o m o r p h i s m .
D. Senato and A.M. Venezia
410
COROLLAKY
4 . 1.
yf!
4e.t ( n ) = ( I ) , w e h u v c :
CJ@
Proof.
3.1,
F r o m t.he t h e o r e m s
5 be
We s h a l l ned b y :
sl!
s*!
...k 2.1
and
4.1
sum F u n c t i o n s
‘The ( i ) g i v e s t h e p o w e r metric functions. Let
E
sA-
( i )
in
(0 )
we
have:
terms
t h e kiriite s p e c i e s defined by: S[E]={permutations u n E}. denote w i t h H C _ P o l ( E x p ( S ) ) t h e d i 4 p u 4 i i i u n 4 p ~ ~ i e d- ei t i -
H[E]= { ( s , f ) : s = ( x , S n ) E E x p ( S ) [ E ] arid f : E 4 X s u c h t h a t The n t h - c o e f f i c i e n t o f t h e g e n e r a t i n g f u n c t i o n of H i s :
hence
gen(H,n)
=
Gen(H,z)
.=
11
n!
23
n>,O
(see
n n!
h ri
kerf
zn 11 !
1.
gen(c,ri)
We
Geri(C,z)
shall
any
L
c
that
now for
n
partition
xn
i e 3
n b a (n-1):
calculate
Expt(Exp(C)) 3 . 1 we h a v e :
For
(n-l)!
=
the
i
E
(n-l)!
he
sIl,
11
-L
s
n
n!
11th-coefficient
b r e v i t y we
of
:
=a
[l]
‘The cyciic 4 p e c i e 4 C C_ Pol(S) i s d e f i n e d b y C[L] = { ( / L , f ) : 11 c y c l i c p e r m u t a t i o n (it E , ~ : E + x c o n s t a n t 11th-coefficient of t h e g e n e r a t i n g f u n c t i o n of s p e c i e s C i s :
hence:
sym-
t h e monomial
nf
of
t h e
s h a l l d e n o t e by
( \ E / = n )s u c h L h a t
( n ) :=
C
species
.
From
theorem
().,,...A[)
we
1-1 ii v e :
wliere
,... ) .
( o ) = ( V , , v2
The
sum
-7
THEOKEM
4.3.
yr
(X) =
(
A,,
...A, )
011
the
right
depends
on(n)alone,
1.
Polynomial Species
L,!
( i i )
P r o o f . From t h e t h u s , using t h e
1
..hi
A,!.
t h e o r e m s 4.2 theorem 2.1,
ocn
41 1 -1)!
( Y
1
a n d 3 . 3 , we we o b t a i n :
( Y , - l ) ! . .
*
have:
s(o)
Expt(Exp(C))=Exp
The ( i i ) g i v e s t h e homogeneus e l e m e n t a r y f u n c t i o n s power-sum f u n c t i o n s .
i n
terms
of
t
(H)
the
We d e n o t e w i t l i A c _ P o l ( ~ ) t h e e4er;2en.:ufly ~ g m m e t n i4 ~ pecieo d e f i n e d A[E] = { ( i < , f ) : f : 1.: + X m o n o m o r p h i s ~ i i The c o e f f i c i e n t of t h e by: g e n e r a t i n g [ u n c t i o n o t t h e s p e c i e s A i s : g e n ( A , n ) = n! a herice:
}.
n
Let
t EN.
he
{
n,t)
A,[k] =o f At i s :
denote
=
c
gen(n,f)
s u m on t h e s, ! s2! n=O
The OA
t ,
f :
C P o l ( P ) t h e s p e c i e s defined by: E +X}tand k e r f A IT=; The c o e f f i c i e n t
.
-
gen(n,f).
k e r f An=O
nEPt[E]
=
At
by
:
uAn-O
=
s, !
d e p e n d s on we h a v e :
right
...ktu)
gen(A1,n)
s*!.
. .k(o)
(n)a l o n e .
The
other hand:
where
( 0 )
:
Hence s e t t i n g
(1s12s2 di
... ) .
=
=
from which
1HEOREM 4.4.
Exp
(A) = A ,
P r o o f . The b i j e c t i o n t h a t t o any p a i r ( ( u , S U ) , f ) E Expt(A)[E] t h e r e q u e s t e d isomora s s o c i a t e s the p a i r ( 0 , f ) E At[E]determindtes phism. C O R O L L A R Y 4.2.
( i i i )
ill!
Poof.
From t h e
The
( i i i )
gives
.?f
(n)=(i),w e h a v e :
,I2!. . . ai
=
aAn=O
theorem 3.1,
the
4.4
s1 ! and
s2'!.
2.1
elementary symmetric
..k(u)
follows:
functions
in
terms
of
the
D. Senato and A.M. Venezia
412
monomial symmetric functions.
REFERENCES
B o n e t t i , Y., R o t a , G.C., S e n a t o , D., V e n e z i a , A.M., O n t h e f o u n d a t i o n of C o m b i n a t o r i a l T h e o r y , X: a c a t e g o r i c a l s e t t i n g f o r S y m m e t r i c F u n c t i o n s . To a p p e a r B o n e t t i , F . , K o t a , G.C., S e n a t o , D., V e n e z i a , A.M., S y m m e t r i c Functions and Symmetric S p e c i e s , A n n a l s of Discrete Math. 30 (1986)
~4
1
107-114.
D o u b i l e t , P., O n t h e f o u n d a t i o n o f L o m b i n a t o r i a l T h e o r y , VII: S y m m e t r i c F u n c t i o n s t h r o u g h t h e T h e o r y of D i s t r i b u t i o n a n d O c c u p a n c y , S t u d i e s i n App. M a t h . v. 51 ( 1 9 7 2 ) D o u b i l e t , P., R o t a , G.C., S t a n l e y , R., O n t h e f o u n d a t i o n of C o m b i n a t o r i a l T h e o r y , VI: T h e i d e a o f G e n e r a t i n g F u n c t i o n , Sixth Berkeley Symposium on Math. Statistic and Probability, V. 2 , B e r k e l e y U n i v . P r e s s ( 1 9 7 2 ) . J o y a l , A., U n e T h e o r i e C o m b i n a t o i r e d e s s b r i e s f o r m e l l e s , A d v . i n M a t h . V. 4 2 n.1 ( 1 9 8 1 ) M a c d o n a l d , I.G., S y m m e t r i c F u n c t i o n s a n d H a l l p o l y n o m i a l s , ( C l a r e n d o n p r e s s , O x f o r d , 1979) Mac L a n e , S . , Categories for the Working Mathematician, 1971) (Springer, New York, Heidelber, Berlin, Rota, G . C . , Baxter Algebras and combinatorial identities I and 1 1 , B u l l . A m e r . M a t h . Soc. 7 5 ( 1 9 6 9 ) S t a n l e y , R., T h e o r y a n d A p p l i c a t i o n o f P l a n e P a r t i t i o n , p a r t 1 a n d 2 , S t u d i e s i n App. M a t h . V. L , n. 2 a n d 3 ( 1 9 7 1 )
Annals of Discrete Mathematics 37 (1988) 413-420 0 Elsevier Science Publishers B.V. (North-Holland)
SET AND
SEQUENCE CLOSURE FOR
413
PERMUTATION GROUPS
FINITE
Johannes Siemons"
INTRODUCTION
1. A
k
permutation group
<
In1
G
has a natural faithful action on
k-element subsets of n. G(k)
of
G
n
acting on a finite set
for each integer
n(k), the collection of all
We now define (see p.399 in [81) the (k)-closure
to be the largest subgroup in Sym(n) which has the same
as G. Thus G is a subgroup of G(k) and the map orbits on n(k) G G{k) satisfies the usual properties of a closure operator as we
-
shall see in Section 2.
Set closure is relevant for automorphism groups of
incidence structures:
if
(G,n)
denotes the point action of some
automorphism group G of an incidence structure S
-
(n,B) with block set B contained in n{k) (i.e. all blocks are incident with precisely k points) then G { k ) in particular preserves the blocks of S and hence consists of automorphisns. For this reason the full automorphism group of S coincides with its {k)-closure. This can be interpreted as a A group for which completeness property of full automorphism groups. G G(k) will becalled (k)-closed. Such groups are the subject of Section 3 .
-
By analogy we may consider the action of a group of k-element sequences of distinct points of (k)-closure
G(k)
G
n.
on the collection n ( k ) Here we define the
of G to be the largest permutation group on n
-
that has
Then G G(k) is also a closure the same orbits on n ( k ) as G . operator in the usual sense. Sequence closure was first investigated by The definition of k-closure Uielandt in the Ohio Lecture Notes (111. there, given In terms of the action on the Cartesian product of k copies of n , does agree uith the definition given above.
*
Financial support from SERC through grant GR/D/30181 is acknowledged.
414
J. Siemons
In [ll] the completeness properties of G(2) formed an important step in the classification of uni-primitive groups of degree p2. In Section 2 we review the basic properties of closure groups such as inclusions in general, primitivity and permutation rank, both for set and for sequence closure. In Section 3 we shall deal with conditions for a group to be {k)-closed for some k. A useful criterion (Result 4 ) depends on the existence of regular sets for closed over-groups. This problem has been investigated in collaboration with Jennifer Key, a survey [ 7 1 will be given at this conference. 2. GENERAL PROPERTIES OF CLOSURE
For the remainder of this note we shall use the following notation. G is a permutation group on a finite set n of n elements. The orbits The orbitals of G, denoted by r l , . . ..rr , are of G are n,, . . . ,nt. Uhen G is transitive, then there is j u s t the orbits of G acting on n x n. one diagonal orbital, say T i = I ( u , u ) ~ u E ~ ) so that r 2 ,... ,rr are the In this case r(G) = r is the rank of G. When orbits of G on O('). r 1. = ( ( a g , B g ) l g E GI is an orbital then (Bg,ag)lg E G) is the orbital paired to r j , denoted by r j f . If r . = rjt then r j is said to be 1 self-paired. In the transitive case the number of self-paired orbitals is given by the Frobenius-Schur indicator V G = IGI-'EgE~ n ( g 2 ) where n denotes the permutation character of G. As a reference to these facts see for instance Chapter 1 in Cameron's article [ 3 1 . A non-diagonal orbital r . may J be viewed as a directed graph with vertex set n and (a.13) an edge if and only if ( a , O ) belongs to r j . Its full automorphism group is denoted by Aut(r.1 ). The undirected graph underlying r j will be denoted by ( r j t r j t with automorphism group Aut(T. tr.1 1. Thus r j and ( r j t r j t ) represent 1 1 the same graph if and only if r j is self-paired. Let F be a field and H some subgroup of Sym(n). Then the centralizer algebra Cn(H) over F consists of all nxn matrices A (with entries in F) for which AM,, = MhA for all h in H where M is the permutation matrix representing h. As a vector space the centralizer algebra is spanned by the adjacency matrices associated to the orbitals of H , including diagonal orbitals. In For a particular, if H is transitive, then the dimension of Cn(H) is r(H).
Set and Sequence Closure far Finite Permutation Groups
415
reference see for instance Chapter V in Uielandt's book [lo 1. All the remaining notation is standard. Comparing the actions of G on n(k) and nk, the Cartesian product of k copies of 0 , it is clear that G-orbits on n ( k ) determine G-orbits on nk and vice versa. This shows that our definition of (k)-closure agrees with the definition of k-closure given by Wielandt in [111. The first result to be stated now shows that both set- and sequence-closure satisfy the usual properties of a closure operator, RESULT 1:
PROOF: (1) follows directly from the definitions. The second statement is theorem 5.10, page 16 in [ll], while ( 3 ) follows from theorem 5.1 in [81.U The next theorem is concerned with the lattice of closure groups in general. RESULT 2: Let G f Sym(n), let n* be the integer with n - 1 E 2n* < n and suppose that 2 E k 4 1 < n - k. Then
(4)
PROOFt The inclusions in (1) and (2) are theorem 5.8, page 15 in [ll] and The equations in ( 3 ) and ( 4 ) can be established theorem 5.1 in 181. directly from the definitions.0 REMARKS: A. It is worthwhile to comment on the inclusions in Result 2.U) and 2.(2). While 2.(1) is straightforward to establish due to the inductive nature of sequence closure the inclusions in 2.(2) are due to rather different arguments: no obvious inductive arguments apply. The proof given
J. Siemons
416
in [ 8 ] relies upon the fact that the incidence matrix of k-element subsets versus I-element subsets of s l has maximal linear rank. Note also that 2.(2) remains true for infinite permutation groups. This result, relying on a weak form of Ramsey's theorem, is due to Bercov and Hobby [l]. No information in general seems to be known about the index of G ( k ) in G(k). Its range can be seen from the following two examples. The cyclic group G = Cn , generated by an n-cycle, has G(' ) G 4 G( = D zn' the dihedral group of order 2n , while G = PSL(2,q) , acting on the q t l points of the projective line, leads to G G ( ' ) c G(') = Sym(qt1) if q E 3 mod 4 .
B.
-
-
As a consequence of Result 2.(2) the group G(n*) has the same orbits as G when acting on the collection of subsets of any size and it is the largest group with this property. In [ a ] , page 401, I have conjectured that, under suitable general hypotheses, G should coincide with G("*). In this direction theorem A in [ 9 1 shows that a primitive group G for which some prime divides the order of G("*) but not that of G must be one of seven groups of degree at 'most nine. Result 4 in Section 3 will give more information about this question.
C.
We now turn to the questions of primitivity and permutation rank of the closure groups.
RESULT 3:
Let G be a transitive group on n and suppose that 2 6 k < n - 2. and G(k) all share the same block systems of imprimitivity. Thus G is primitive if and only if any of its closure groups (1 < k < n - 1 ) is primitive. (2) For the centralizer algebras we have Cn(G) Cn(G(k)) and in particular r(G) r(G(k)). ( 3 ) When OG denotes the Frobenius-Schur indicator of G then r(G) 3 r(G(k)) 3 2-' (r(G) t OG). (1) The groups G , G(k)
-
-
PROOF: (1). As G c G(k) c G(k) c G(') by Result l . ( 1 ) and 2.(2), this follows from theorem 5.2 in [ a ] where it is shown that G and G(') have the same block systems of imprimitivity. See also theorem 4.10, page 10 in [ll]. ( 2 ) . As G H implies Cn(H) c C,(G) in general, by Result 2(1) we only have to show that C,(G) C,(G(')). By definition G and G(')
-
Set and Sequence Closurefor Finite Permutation Groups
417
have the same orbitals, and hence, by the remark in the introduction of this section, their centralizer algebras coincide. (3). As G c G(k) c G('), the rank of these groups satisfies r(C) > r(G( k, ) 3 r(G( ) ) so that only the lower bound for r(G( * needs to be established. Hence compare orbitals of G with orbitals of G(*). An orbital of G t Z J can be the union of at most two G-orbitals and this happens is at least the only if they are paired orbitals for G. Thus r(G(')) number of self paired G-orbitals plus the number of orbital pairs of G. This number is 2-' (r(G)tnG) by the remarks zt the beginning of this Section.0
3.
CLOSED
GROUPS
-
-
A group G on fl is (k)-closed or (k)-closed if G G(k) or G G(k) As a consequence of Results 1 . ( 1 ) , 2 . ( 1 ) and 2 . ( 2 ) a respectively. (k)-closed group is also (k)-, and (&)-closed for k d P < n - k is always (k)-closed. In this section we are concerned and of course G(k) with conditions for a group to be (k)-closed for some k. As already mentioned in the introduction, examples of (k)-closed groups are provided by full automorphism groups of structures on n in which blocks have constant size k. Our main criterion in general is Let G c Sym(n) be given and suppose that some permutation group H on n containing G satisfies I : H is (k)-closed for some k , 2 d k d n - 2 , and 11: for some subset A C n of size 1 , k 6 1 S n - k, the set stabilizer of A in H is the identity on n . Then G is (n)-closed and a group on n having the same orbits on n(') as G coincides with C.
RESULT 4:
-
Then G c K c G(k) E H(k) H by Results I. Therefore K ( A ) 1 = G(A) by hypothesis I1 and as AG AL we have G = K . Suppose now that some group L has the same orbits on n(') as G. Thus, by definition, G(') L(') so that But then, as above, L L(') so that L G.0 L is a subgroup of H. PROOF:
Let
K = GI1).
l . ( l ) , 2.(1) and hypothesis
-
-
-
-
-
Hypothesls I in Result 4 in itself can be satisfied quite easily by choosing H to be the (k)-closure of any group Containing G. The relevant
418
J . Siemons
requirement now is the existence of a subset A as in hypothesis 11. Such a set is said to be a regular set for H. In the survey [ 7 1 by J.Key the existence of regular sets for several infinite families of groups will be discussed, including ArL(d,q), PrL(d,q), the Ree groups R(q) and Pru(3,q2 ) in their natural representations. These groups generally are (3)or {4)-closed and are shown to have regular sets of sufficiently small size. These results are independent of the For details see also [ 6 1 and [ 5 ] . classification theorem of finite simple groups. A theorem in [41 which however does depend on the classification shows that all primitive groups of sufficiently large degree not containing the alternating group of the same degree have regular sets. Note finally that a group G as in Result 4 is uniquely identified through its orbits on the power set over n. A strengthening of the notion of {k)-closure is that of a k-geometric action, Here a permutation group G on f2 is said to be due to Betten [ 2 ] . k-geometric if there is a system B of k-element subsets of n such that G is the full automorphism group of the structure (n,B). Clearly a k-geometric group is (kl-closed but the converse does not hold in general.
RESULT 5: Let G be a subgroup of ArL(d,q) or PTL(d+l,q) where d > 2 if q > 3 and d 3 6 if q = 2. Then G acts k-geometrically for some k on the points of the corresponding affine or projective space. The values for k are given in [ 6 1 and [ 5 1 but are too cumbersome to reproduce here. Ue give an indication of the PROOF : There is a regular set A for ArL(d,q) or PrL(d+l,q) Now let 9, AG and let B, be the respectively, say of size k. collection of all k-element subsets of points in the corresponding affine (projective) space that are contained in a do-dimensional coset (subspace), where do < d is taken to be minimal. Setting B = B, u B, and A = Aut(n,B) it can be shown that BZA = B, so that A is a group of collineations. As A{A) = 1 = G{A) and AA = AG it follows that G = A. For the details of this proof see theorems 3.1 and 3.2 in [ 5 ] and theorem 5.1 in [61.0
-
Set and Sequence Closure for Finite Permutation Groups
419
BIBLIOGRAPHY [l] R.D.Bercov and C.R.Hobby, 'Permutation groups on unordered sets', Math. 2 . 1 1 5 , 165-168,
(1970).
[ 2 ] D. Betten, 'Geometrische Permutationsgruppen', Mitt. Math. Gesel lschaft
Hamburg, 1 0 , 317-324, ( 1 9 7 7 ) . 'Suborbits in transitive permutation groups', "Combinatorics", Part 3 , Mathematical Centre Tracts, Amsterdam, 1975. P.J. Cameron, P.M. Neumann and J.Saxl, 'On groups with no regular orbits on the set of subsets', Arch. Math. 43, 295-296, ( 1 9 8 4 ) . F. Dalla Volta, 'Regular sets for the affine and projective groups over the field of two elements', to appear in Journal of Gnometry. J.D. Key and I.J. Siemons, 'Regular sets and geometric groups', Resultate der Hathematik, 11, 97-116 ( 1 9 8 7 ) . J.D.Key, 'Regular sets in Geometries', Proceedings of this conference. I.J.Siemons,'On partitions and permutation groups on unordered sets', Arch. Math. 38 391-403, ( 1 9 8 2 ) . 1.J.Siemons and A.Wagner, 'On finite permutation groups with the same orbits on unordered sets', Arch. Math. 45, 492-500, ( 1 9 8 5 ) . H.Wielandt, "Finite permutation groups", New York 1984. H.Wielandt, "Permutation groups through invariant relations and invariant functions", Lecture Notes, Ohio State University, Ohio 1969.
[ 3 1 P.J.Cameron,
[41 [5] 161
[71 [81 [91
[lo
111
Department of Mathematics, University of Birmingham, Birmingham 815 2TT United K ingdom
School of Mathematics and Physics, University of East Anglia, Norwich NR4 7TJ United Kingdom
This Page Intentionally Left Blank
Annals of Discrete Mathematics 37 (1988) 421-426 0 Elsevier Science Publishers B.V. (North-Holland)
42 1
P-CYCLIC HYPERGROUPS WITH THREE CHARACTERISTIC ELEMENTS Thomas N.VOUGIOUKLIS and Stefanos H.SPARTALIS Democritus University of Thrace, 67100 Xanthi, Greece. Let (G;) be a group and P a non-empty subset of G. The set G with hyperoperation P* given by the relation xP*y=xPy becomes a hypergroup. These hypergroups have been introduced by the first author and have been called P-hypergroups. In this paper we study the simplest case of 3-dimensional P-hypergroups.
5 1. Let (G;) be a group and can define hyperoperation P*:GxG
P
a non-empty subset of
B(G):(x,y) >-
G.
In
G
we
xP*y=xPy.
becomes a hypergroup in the sense of Marty (1934), i.e. Then G associative and the reproduction axiom xP*G=GP*x=G, [6y :Ad The above hypergroup denoted
P* is is valid. generalized P* are
In this paper we focus our attention on P-hypergroups when G is a finite cyclic group, say (H,,.). The hypergroup
Hn
such that
Hn=h[llU...Uh[vl.
The minimal such number
v
is
called the period of h and if all generators have the same period then we call the
if we can write
H = h [vl;
see
[6 and 21.
is a singleton then P* becomes an operation. The simplest case If P of P-hypergroups with two elements is P = {e,x], e#x and this case In this paper we study the for cyclic hypergroups was studied in [61. simplest case of 3-dimensional P-cyclic hypergroups
5 2. Henceforth we denote a generator of elements of
~€{ ...,[: l,
n
Hn
1)
are ;
as,
s E{0,1,.
(Hn,-)
. .,n-l).
so we study the hypergroups
where
is an even, we take
The powers of the element
by
notation
a; therefore
the
We observe that
is the integer part of
>
.
with Obviously
if
...,[$] -1).
~€{1,
as
with respect to the hyperoperation
a:
are
T.N. Vougiouklis and S.H. Spartalis
472
The s e t of u n i t elements (two-sided) of i.e.
if
P = te,aw,a-'I,
is
<~,,a:>
we have
xEP
as E Hn with r e s p e c t The s e t of i n v e r s e elements (two-sided) of -s -1 unit xEP is a x P and t h e s e t of i n v e r s e elements of -sp2 r e s p e c t t o some u n i t i s a . F i n a l l y , t h e only t o t a l i n v e r s e -S
of as is a , see [7]. We note t h a t every and r i g h t i n v e r s i b l e i n i t s e l f ; s e e [ 3 and 71.
A subset X
{e,a ,a
--W
H
of
is a
i s called a
Hn
}CHCHn
Hn
then
S
of
Hn
is a
element left
< H n , a:>
if
i s a subgroup of
P-subhypergroup of a hypergroup i s
PROPOSITION 1 The union of t h e powers, with r e s p e c t t o t h e a
H
with
I t i s obvious t h a t
i s a hypergroup.
P-subhypergroup of
F i n a l l y w e n o t e t h a t every see [7 and 51.
the
as
P-hypergroup i s
P-subhypergroup o f
and
to
if
(H,,.).
ultraclosed;
P-hyperoperation, of an element
P-subhypergroup of
<~,,ai>.
Pro0f
The union of t h e powers of S=aS[11"a"[21"...={a
For
t = n
Now l e t
and
atos+vo-W E S;
r =0
(ii)i f
I
0
for
(to+t)S+(Vo+V)-W ~
tErn0,
V E X } . W
--W
we o b t a i n
{e,a ,a
such t h a t
to romodn,
}CS.
then
at o S + V o M
obviously
r i 0 ,
is
v~{-l,O,l}
Moreover when we t a k e ( i )i f
as
t S+VW
t E{n-r,+l,
aSf(Y~+Y)-W
,
a:S=S, n-ro+2,
and
...I
.
a 2 ~ + ( v ~ +,v , ). ~ ;
Therefore from t h e commutativity of axiom i s v a l i d .
a:
then
we have .toS+VOX
s o again
we conclude t h a t
the
a H* S = S .
reproduction
PROPOSITION 2 In
i f t h e r e e x i s t s an element
as
and a number
t>2
such
P-Cyclic Hypergroups with Three Characteristic Elements
that
It],
as
[llu...uaS[t-ll
‘
I;
s t+l
Let y€a We have two c a s e s . ts+s+vw ( i )y = a
then
with
ats+(v-l)wS a s [ t 1 ts+(v-I)-H
y=a
O
-r < u < r .
with
for
l < r gt-1
where
r
si t-11
the
element
-t < v < t .
where
From t h e hypothesis
t h e r e e x i s t s an
rs+uw = a
...
a s [ t + l l ~ a S ~ l lu ya
then
( t + lS+VH )
423
such
Consequently
... U a sit-11-
y = ats+(v-l)w+s+w= a(r+l)s+(u+l)wE , s [ l ]
V
ts+s+vw ( i i )y = a
Then i n a s i m i l a r way we have
with
a t s + ( v + l ) w€ a s [ t l ; =
Therefore
so
ats+ ( u + l )H-
-t
at s + ( v + l ) w
rs+uw
= a
H+
that
s = a ( r+1) s+ ( u-I ) w
,
lbr4t-1,
as [ 11
-r
...u a s [ t - 1 ]
5 3. THEOREM 1 The
P-cyclic
hypergroup
i s single-power c y c l i c
and i n t h i s c a s e every element of
Hn
iff
(k,n) = 1
[9]+1.
i s a g e n e r a t o r with period
Proof t o be a g e n e r a t o r of t h e single-power i t must s a t i s f y t h e r e l a t i o n
We observe t h a t f o r an element as c y c l i c hypergroup Hn of period
Ias[tli
=n.
For
= {atS+vw
But, s i n c e l a s [ t l 1G2t-1
we have
t = [+]+1,
t,
I
-t
t 2[$1+1.
so
we have
21:)~
Now, i f
2’:’’
=a
n=2w (n-l)w
Also, f o r every
;
we have
therefore
rETiNo,
T h i s means t h a t t h e element hypergroup Hn
= e,
a
and i f
=a
a
n = 2w+l
te,aH,.
we
have
. .,a (n-1) n 1.
we have
as
i s a g e n e r a t o r o f t h e single-power
cyclic
T.N. Yougiouklis and S.H. Spartaris
4 24
We conclude t h a t every element
as
rq1 +l.
5 4. THEOREM 2 In t h e P-cyclic
(s,-H,n) =I.
iff
hypergroup
of
i s a generator
Hn
t h e element
with
period
i s a generator
as
Pro0 f We observe t h a t if a v € a[*] a
Therefore
I
as.
power of
as
iff
THEOREM 3
(x,n) = 1
Pro0f a “t’
We have
a-H[tl
=aH
= tar’
a
[z]
for
P-cyclic
n
But
.I:[
n=2w,
w2 - w + l
H =a
of t h e
{e,a
aw ( w - 1 )
a(2t-1)-H}
so and
...,I:[
+I}.
t E ~ 2 ,
“[;I
w e deduce t h a t a
--H
+
13 = Hm.
a
has p e r i o d
hypergroup
[z]
w>2, 2
‘w,
i.e.
aw
)..., E1w[w-l]
;
so
[Wj
n>5,
I:[
+1.
t h e generator
But
aw ( w - 1 ) - 1
, a
w(w-1)
!21
a
has
then
u{aW -w-1+2w-1 Hn=aw [ w l u
1.
...u aw i l l .
..
aw[wlyI$w-l)-l
tEINo,
P-cyclic hypergroup
( i i )I f n=2w+l, i.e. [k]=w, w>2, then ,an-ll = ,w[w] uIaw2-w+1+2w-~ w2 -w+1+2w W2-W 1 H =a te,a,. , a I =
we can f i n d
h
p e r i o d a t most
( i )If
aH,a-’
r = 1,
I n a s i m i l a r way we deduce t h a t T’HEORFM In t h e
belongs t o
a iff
t s + vw :Imodn,
iff
...,2t-11;
1
(-H,n) = 1,
Moreover, s i n c e
we have
+l.
[t-l]u{a(2t-2)H,
aH’t-l’gax‘tl
iff
Hn
i s a generator
as
then t h e g e n e r a t o r s
have p e r i o d
v€Wo
t h e n f o r every
i s a generator of
That means t h a t
VEX such t h a t ( s , H , n ) = 1.
tEBo,
If
t€Bo,
a€aS[tl,
=
1.
, aw ( w - l ) E a W [ w - l ]
, ,
so
H n = a w [ W l u . . . uw a[ 1 1
Therefore t h i s theorem i s v a l i d for n>5. N o t i c e t h a t t h i s theorem i s also v a l i d f o r n-4. i t i s not v a l i d a r e n~{3,5}.
.
So t h e o n l y cases f o r w h i c h
P-Cyclic Hypergroups with Three Characteristic Elements
425
THEOREM 5 n >5,
If
a’
then t h e p e r i o d of t h e g e n e r a t o r
>1,
H
of t h e
P-cyclic
[I:.
< ~ ~ , a z >is a t most
hypergroup
Proof
W e have t h e following four cases. ( i )n > 9
and
.
1
a[11ua[21u.. u a
..
r E {I[:
for
+ 1,. , n ) ,
if
r-[”]=wd, 2
if
I--[”]2 ]:[
and
r€{l
Also, f o r
1.
-t
Moreover, with t h e above assumptions
a =a
then
151 +Hd
arE a
implies
and
then
- w+u+(d+l)n
x=[:]
,..,[$I
n
then
arEa”];
even, we have
,
( i i i )n > 9
-1.
1,
n
n-1 a €a
if
and
=a
( i i )n > 9
even
.I[:,
O
]:[
+xd+u
t = l,. .,[:I
we observe t h a t
d€Mo
= Hd+u,
a =a
If
r €{l,. ,
for
a r E a[.]
So
We o b t a i n
1<~<[:] -1.
and
an€a
“$1
a
n
odd,
we
have
-11 We examine t h i s c a s e o n l y f o r odd
H=[:].
we have a degenerate case f o r
r€{[g]+1,
and f o r
2 [ $ ] +l),
then
n,
since f o r
P.
ar€ a
“Yl
I n t h e above t h r e e cases we can s e e t h a t t h e p e r i o d of
a’
(iv) We can s e e by i n s p e c t i o n t h a t t h e theorem i s v a l i d f o r
i s a t most
[$I.
nE{6,7,8,91.
5 5 . THEOREM 6 If (H,n) = 1 then t h e c y c l i c with p e r i o d (c.f.
P-cyclic hypergroup
<~,,a:>,
n>5,
is
not
[4]).
Proof From theorem 3 we d e r i v e t h a t , s i n c e
( x , n ) = 1,
t h e generator
ax
has
T.N. Vougiouklis and S.H. Spartalis
426
period
+l.
generator
a
I;[
the generator Therefore
In theorem
4 it was shown that, for
has period at most
n’
]:[
also has period at most
a
;
.I:[
for
the
n = l , H>I,
from theorem 5
is not cyclic with period.
Remark
If (n,n)= 1, then the only hypergroups are for n E {3,51.
cyclic with
period
REFERENCES Corsini,P., Sur les homomorphismes d’hypergroupes, Rend. Sem. Mat. Univ. Padova, V o l . p.p. 117-140 (1974). De Salvo, M.-Freni,D., Semi-ipergruppi ciclici, Atti Sem. Mat. Fis. Univ. Modena, XXX,- P- . P- . 44-59 . . (1981). . Dresher,M.-Ore,O., Theory of Multigroups, h e r . J. Math. V . p.p. 705733 (1938). Konguetsof,L.-Vougiouklis,T.-Kessoglides,M.-Spartalis,S., On cyclic hypergroups with period, to appear in Acta Un. Carolinae - Math. et Physica. Sureau,Y., Sous-hypergroupe engendr’e par d e w sous-hypergroupes et soushypergroupe ultra-clos d’un hypergroupe, C.R.Acad. Sc. Paris, t . a (2Mai 1977) S’erie A. p.p. 983-984. Un. Vougiouklis,T., Cyclicity in a Special Class of Hypergroups, Acta NO I, p.p. 3-6 (1981). Carolinae-Math. et Physica, Vol. g, Vougiouklis,T., Generalization of P-hypergroups, to appear in Rendiconti del Circolo Matematico di Palermo. Wall,H.S., Hypergroups, American Journal of Mathematics, V o l . p.p.7798 (1937).
z,
a,
z,
Annals of Discrete Mathematics 37 (1988) 427-432
0 Elsevier Science Publishers B.V. (North-Holland)
427
ORDER AND UNIFORM STRUCTURE IN PROJECTIVE GEOMETRY Horst SZAMBIEN Kaiser Wilhelms Gymnasium See lhorststraRe 52 D-3000 Hannover 1 Fed. Rep. of Germany Riassunto. In questa nota studieremo uno spazio proiettivo ordinato: Esiste una struttura uniforme compatibile. I1 complementamento di questo spazio 6 strutturabile a sopraspazio proiettivo ordinato. AMS-Subject-Classification: Primary 51H05, secondary 54E15, 06B30.
1.
INTRODUCTION
Uniform structures have been studied in planar geometry by Guggenheimer [Gu 591, Breitsprecher [Br 671 and Szambien [ S z 811, [ S z 861 mainly in the context of projective planes. In this paper the notion of uniform projective geometry is defined for the case of arbitrary dimension. It shall be a projective geometry (i. e. subspace lattice of some vector space) provided with a uniformity, such that the following condition and its dual hold: Joining of skew subspaces is uniformly continuous outside an arbitrary uniform neighbourhood of the closed set of non-skew pairs of subspaces. Any uniform projective geometry becomes a topological projective geometry when it is provided with the uniform topology, [ S z 861. Proposition 1 shows that every finite-dimensional projective geometry over a topological field is a topological projective geometry. So, in this class the converse problem arises: For which topological projective geometries does there exist a compatible uniformity, which turns it into a uniform projective geometry? The problem will be solved for ordered geometries: In a projective space (i. e. the set of I-dimensional subspaces of some vector space) one can consider an order structure for instance in terms of a 4-ary separation relation or some equivalent concept; cf. [Le 651 . The so-called special separation relations are then equivalent to orderings of the coordinatizing division ring. In this paper finite-dimensional pappian projective geometries, whose correspondent spaces carry an order structure, are considered. They are of course topological projective geometries w. r. to their order topology, [Mi 68;S.5IlSatz11]. It is shown that they can be provided with a uniformity derived from the order structure to become uniform projective geometries. The construction of this uniformity is carried out using the well known Grassmann-mapping. This mapping embeds the set of subspaces of a given vector space into the point set of some projective space of higher dimension. It then suffices to define a suitable uniformity on this projective space. This is done in proposition 2 . In proposition 3 the existence of the Weil-completion is proved for any ordered pappian projective geometry; as a corollary to this one recognizes in proposition 4 the Dedekind-completion and the Weil-completion as isomorphic objects.
H. Szambien
428
2.
RESULTS
[Bo 661, [ L e 6 5 1 , and [ B i 7 9 1 a r e t a k e n as g e n e r a l r e f e r e n c e s f o r n o t i o n s o f g e n e r a l t o p o l o g y , a l g e b r a , geometry, and l a t t i c e t h e o r y , Throughout t h i s p a p e r " I " w i l l d e n o t e t h e r e s t r i c t i o n of resp. mappings, t o p o l o g i e s , and u n i f o r m i t i e s , Mn t h e n - f o l d C a r t e s i a n p r o d u c t of t h e s e t M; f u r t h e r m o r e L i s a l a t t i c e , where s+t and s a t denote t h e j o i n , r e s p . m e e t o f l a t t i c e e l e m e n t s s and t . If L i s an i r r e d u c i b l e , meet-continuous, a t o m i s t i c , modular l a t t i c e , t h e n it w i l l be termed p r o j e c t i v e geometry. The l e n g t h of t h i s l a t t i c e minus 1 w i l l a s u s u a l be c a l l e d t h e dimension of t h e geometry. I f L h a s bottom 0 and t o p then S:={(s,t)EL2: s * t = O } is the set of s k e w p a i r s and d u a l l y S : = { ( s , t ) E L 2 : s + t = l } . L e t CJ be a t o p o l o g y on L. ( L , o ) i s c a l l e d a t o p o l o g i c a l p r o j e c t i v e geometry (TPG) i f f L i s a p r o j e c t i v e geometry, and + IS and * I S * are c o n t i n u o u s mapp i n g s w i t h open domains. Examples of T P G s are c o n s t r u c t e d as f o l lows : L e t ( K , R ) be a c o m m u t a t i v e , t o p o l o q i c a l f i e l d w i t h t o p o l o g y R , r t h e e x t e r i o r a l g e b r a on K n l t h e n-dimensional v e c t o r s p a c e o v e r K , n a n a t u r a l number 2 3 , rk t h e (:)-dimensional K-vector s p a c e of k v e c t o r s : t h u s r i s t h e d i r e c t sum of i r k : OSkSn) L e t O k c r be t h e s e t of decomposable k - v e c t o r s f o r l s k l n , O0:= K\ 1 0 ) , O:=U{0 k :Olksn} Now t a k e t h e l a t t i c e L r = L ( K ) of s u b s p a c e s of K , L := { s E L : dim s = k ] , P t h e s e t of I-dimensional s u b s p a c e s of t k e v e c t o r s p a c e r;rx:= r\{o}, K X : = K \ { O } ,r X / K X : = iKXg : g E 1-1 , D := O;/KX, D : = O X / K X . P w i l l be i d e n t i f i e d w i t h T*/KKX L e t r carry t k e p r o d u c t t o p o l o g y of R . P r o v i d e P w i t h t h e t o p o l o g y 7 1 , t h e f i n e s t t o p o l o g y which r e n d e r s t h e c a n o n i c a l p r o j e c t i o n r + T X / K X cont i n u o u s . S i n c e t h e r e e x i s t s a b i j e c t i o n between L and D, one g e t s an embedding a : L + P ; p r o v i d e L w i t h 0 , t h e i n i t i a l t o p o l o g y w. r . t o @. u i s c a l l e d t h e coordinate topology.
.
A,
.
.
( L , o ) i s a TPG.
PROPOSITION 1 .
d e n o t e t h e e x t e r i o r m u l t i p l i c a t i o n on , and 0 ) ; then A maps C i n t o 0 ; furthermore it i s c o n t i n u o u s w i t h C open, because t h e c o o r d i n a t e s of s A t are c a l c u l a t e d by r a t i o n a l o p e r a t i o n s from t h e c o o r d i n a t e s of s and t . Hence i t i n d u c e s a c o n t i n u o u s mapping S + L , which c o i n c i d e s w i t h t h e l a t t i c e - j o i n +, making t h e f o l l o w i n g diagram commutative: Proof. C:=
Let
A
{ ( s , t ) E 02 : s A t f.
c s
2 0
+
Z L
T h e r e i n a i s t h e map, which a s s o c i a t e s w i t h e a c h a E 0 t h e subspace o f K d e t e r m i n e d by it. + becomes c o n t i n u o u s , b e c a u s e a , and a l s o a x a I C are q u o t i e n t mappings. The c o n t i n u i t y of remains t o be shown. T o t h i s end c o n s i d e r I ? ' , t h e e x t e r i o r a l g e b r a on t h e d u a l v e c t o r s p a c e of K : l i k e w i s e i n r ' , mapping t r o d u c e A ' , L ' , s ' , E', 0 ' a s b e f o r e . Now 6 : ra m u l t i v e c t o r t o i t s d u a l , i s a homeomorphism and i n d u c e s a n o t h e r homeomorphism L __.z L ' , mapping a subspace t o i t s a n n u l l a t o r . D e f i n e C*:= (6X6)-'[E'] Now t h e f o l l o w i n g diagram commutes - making t h e lower row mapping S* d L c o n t i n u o u s . T h i s i n t u r n c o i n cides with IS*
-
.
.
Order and Uniform Structure in Projective Geometry
c*
XI--------,
0'
S-------,S'-----+-L'-------+
------+>
1
A'
429
L
+'
q . e . d.
L e t 1-1 be a u n i f o r m i t y on L , N E 1-1 an e n t o u r a g e ; S N : = L Z \ N o ( L Z \ S ) O N , SN*:= L2\No(L2\S*)oN ( L , p ) i s c a l l e d a uniform p r o j e c t i v e geometry (UPG) i f f L i s a p r o j e c t i v e geometry such t h a t f o r e v e r y N E )-1 t h e mappings + I S and a r e uniformly c o n t i n u o u s , and furthermore S and S* are open'wSN*r. t o t h e uniform topology T ( p ) . A c l a s s of examples i s f u r n i s h e d by
.
-
L e t L be an o r d e r e d pappian p r o j e c t i v e geometry of f i n i t e dimension a t l e a s t two. Then t h e r e can be c o n s t r u c t e d a uniform s t r u c t u r e 1-1 on L i n d u c i n g t h e c o o r d i n a t e topology, such t h a t ( L , u ) i s a UPG. 1-1 i s c a l l e d t h e c o o r d i n a t e u n i f o r m i t y on L.
PROPOSITION 2.
Proof. With t h e n o t a t i o n s of p r o p o s i t i o n 1 one c o n s i d e r s t h e t o t a l l y o r d e r e d c o o r d i n a t e f i e l d ( K , < ) of L which of c o u r s e is a t o p o l o g i c a l f i e l d w. r . t o i t s o r d e r topology Take a n a t u r a l numb e r n 2 3 , m:= 2n, g : = ( g , , . . . , g ,) E Km; Ri:= {g : -1 Sg < 1 f o r 1 5 j S i - I , g i = l , -1 < g < 1 f o r i+l<j<m] and There i s a b i j e 2 t i o n r : R --+ P R:=R(K):=U{Ri :'T=l,...,m] whose i n v e r s e a s s i g n s t o each KXg E P t h e v e c t o r
.
.
(*I
sgn(g) max(lgli , . . . , l g m l ) - ' g
where s g n ( g ) d e n o t e s t h e
E R,
s i g n of t h e component g . of h i g h e s t index j such t h a t t h e e q u a t i o n lg I = max( I g I , . ,1g '1) h o l d s . r I R n 0 t h e r e f o r e maps o n t o L. O n j t h e t o p o l a g i c a l gr8up Km t h e r e i s g i v e n t h e l e f t ( o r r i g h t ) u n i f o r m i t y w. r. t o a d d i t i o n ; r e s t r i c t t h i s u n i f o r m i t y t o R n O and t a k e on L t h e f i n a l u n i f o r m i t y w. r. t o r I R fl 0 ; c a l l t h i s p, t h e c o o r d i n a t e u n i f o r m i t y on L. Since t h e c o o r d i n a t e s a r e taken o n l y from a bounded s u b s e t of K , t h e e x t e r i o r product s A t of s and t depends on ( s , t ) E ( R II E l l 2 i n a uniformly continuous manner. Take an entourage N i n ( R n C~:={(s,t)€(Rno)~:N(s)AN(t) # 01, SN:= ( r x r ) [ C ~ ] : then c e r t a i n l y t h e r e e x i s t s a neighbourhood V of z e r o i n I' , such t h a t EN i s mapped by A i n t o B \ V; any image m u l t i v e c t o r g can be normed as i n d i c a t e d by ( * ) above; t h e combined mappingEN __t R n 0 i s uniformly continuous and induces a uniformly continuous mapping SN L , which c o i n c i d e s w i t h + :
..
-
1 EN
rxr
+
sN
*
r
R
~
O
L
One now proceeds a l o n g t h e l i n e s of t h e proof i n p r o p o s i t i o n 1 t o show t h e uniform c o n t i n u i t y of t h e m e e t : Define E N ' , R ' , S N ' a s above, and CN := (6k6)-'[cN'] S i n c e 6 [ R ] c R ' , w e have t h e f o l l o w i n g commutative diagram:
.
430
H. Szam bien
S"
'N
+
>-
L'
___)
L
f'
By the same arguments as above it contains a uniformly continuous upper row mapping. Now r is uniformly continuous and rxr is a quotient mapping; hence the lower row mapping which coincides with is continuous, too. Finally, p induces the coordinate topology, because scalar multiplication is continuous. 4 - e. d.
-
Any uniform space can be densely embedded into a unique complete uniform space, called its Weil-completion; continuation of the geometric structure is possible for UPGs, as is shown by PROPOSITION 3. The Weil-completion (w. r. to its coordinate uniformity) of an ordered pappian projective geometry of finite dimension at least two is again a UPG. Proof. Let (K,<) be the coordinatizing, field, K ^ its Weil-completion, which again carries the structure of an ordered field by fNi 65;p.14,Thm.2]. L" will denote the lattice of subspaces of (K^)" , n t 3, m:= 2 " ; Lc, R" : = R ( K " ) , and PA are used analogously to the notations in the proof of proposition 2. (KA)m is certainly complete, R" as a closed subset as well. Thus P"carries a complete uniform structure. Since the Grassmann-manifolds Lc are Zariskiclosed projective varieties in P , they are closed in the projective coordinate topology as well, [Le 65;~.337,Satz 1.21; thus they are complete. Hence L A is complete, and it is a UPG by proposition 2. Since it contains L densely, L A is uniformly isomorphic to the q . e. d. Weil-completion of L. It is shown by Massaza that the Dedekind-completion by cuts of an ordered field is an extension field K- of K. Furthermore K- is isomorphic to the Weil-completion K A of K; [Ma 69;p.331,3331 or [Pri 83;p.72,Satz 91. Considering ordered projective geometries L and L- of finite dimension over K resp. K-, one terms L the Dedekind-completion of L. Then propositiom 3 yields an analogue of Massaza's theorem: The Dedekind-completion of an ordered pappian PROPOSITION 4. projective geometry of finite dimension not less than two is isomorphic to its Weil-completion. Proof.
L^
=
L(K^) = L(K") = L".
q . e. d.
From Sz 81;(3.11) one derives that the coordinate field of any pappian UPG is of type V (called locally retrobounded in [Bo 66; TG, Ch.III.6, Exerc.1). Following [Pre 78;(5.4)1 a field of type V is orderable iff the set of all sums of squares is disjoint with some neighbourhood of -1. This condition singles out the orderable UPGs among the pappian UPGs, and it can of course be translated into geometric language.
Order and Uniform Structure in Projective Geometry
43 1
REFERENCES [ B i 791 B i r k h o f f , G.: L a t t i c e t h e o r y , h e r . Math. S o c i e t y C o l l o q . P u b l i c a t i o n s V o l . 25, Providence R I 1960
[Bo 661
Bourbaki, N.:
A l g s b r e , T o p o l o g i e GBnBrale; P a r i s 1966
[ B r 671 B r e i t s p r e c h e r , S . : Uniforme p r o j e k t i v e Ebenen; Mathematis c h e Z e i t s c h r i f t 95 ( 1 9 6 7 ) 139-168
[ G u 591 Guggenheimer, H . : The t o p o l o g y o f e l e m e n t a r y g e o m e t r y ; M a t h e m a t i c a J a p o n i c a e 5 ( 1 9 5 9 ) 1-26
[ L e 651 Lenz, H.: L e i p z i g 1965
V o r l e s u n g e n iiber p r o j e k t i v e G e o m e t r i e ;
[ M a 691 Massaza, C . : S u l completamento d e i campi o r d i n a t i ; R e n d i c o n t i d e l S e m i n a r i o Matematico, U n i v e r s i t 5 e P o l i t e c n i c o d i T o r i n o 2 9 ( 1 9 6 9 / 1 9 7 0 ) 329-348
[Mi 681 Misfeld, J.: Topologische p r o j e k t i v e Raume, D i s s e r t a t i o n Hamburg 1968 [ N i 651 Nieminen, T . : The c o m p l e t i o n s o f o r d e r a b l e t o p o l o g i c a l g r o u p s a n d f i e l d s ; A n n a l e s Academiae S c i e n t i a r w n F e n n i c a e S e r i e s A 365 ( 1 9 6 5 ) 1-15
[ P r e 781 P r e s t e l , A . , Z i e g l e r , M . : Model t h e o r e t i c m e t h o d s i n t h e t h e o r y of t o p o l o g i c a l f i e l d s ; J o u r n a l f i i r R e i n e und Angewandte M a t h e m a t i k 2 9 9 / 3 0 0 ( 1 9 7 8 ) 318-341 [ P r i 831
PrieB-Crampe,
S.:
Angeordnete S t r u k t u r e n ; B e r l i n 1983
Szambien H . : D e s a r g u e s s c h e u n i f o r m e E b e n e n ; Disserta[ S z 811 t i o n , Hannover 1 9 8 ; summary (German) i n R e s u l t a t e der M a t h e m a t i k 5 ( 1 9 8 2 ) 96-98 [ S z 861 Szambien H . : Uniform s t r u c t u r e s i n p r o j e c t i v e g e o m e t r y ; P r o c e e d i n g s of t h e S i x t h P r a g u e T o p o l o g i c a l Symposium 1 9 8 6 , B e r l i n ca. 1987
This Page Intentionally Left Blank
Annals of Discrete Mathematics 37 (1988) 433-450 0 Elsevier Science Publishers B.V. (North-Holland)
433
ON BLOCKING SETS I N FINITE PROJECTIVE AND AFFINE SPACES G i u s e p p e TALLINI D i p a r t i m e n t o d i M a t e m a t i c a , U n i v e r s i t a ' d i Roma,"La
Sapienza" ( I t a l i a )
T h i s p a p e r i s a new v e r s i o n o f t h e f i r s t "Quaderno" [ 9 1 ( w r i t t e n i n i t a l i a n ) of t h e " S e m i n a r i o d i G e o m e t r i a C o m b i n a t o r i a " p u b l i s h e d by t h e U n i v e r s i t y o f L ' A q u i l a i n 1982. I n t h i s Quaderno w e proved s e v e r a l new r e s u l t s f o r b l o c k i n g s e t s ( w i t h r e s p e c t t o l i n e s ) i n P G ( r , q ) and AG(r,q). S i n c e t h i s p a p e r h a s found g r e a t i n t e r e s t (see r e f e r e n c e s [ll], C421). i t seems r e a s o n a b l e t o make i t a v a i l a b l e t o a w i d e r a u d i e n c e . ( N o t e t h a t i n [24] a r e s u l t o f C91 was proved i n a d i f f e r e n t way).
...,
1. k-SETS I N PROJECTIVE GALOIS SPACES L e t S, = P G ( r , q ) b e a p r o j e c t i v e G a l o i s s p a c e o f d i m e n s i o n r _ > 2 and q=ph ( p p r i m e ) . I f Sd d e n o t e s a d - d i m e n s i o n a l s u b s p a c e o f S, , w e have:
order
rl
.
I t i s well-known
.
t h a t t h e number o f d - d i m e n s i o n a l s u b s p a c e s Sd i n Sr i s
n
given
d
by (1.2)
Yr,d
=
;=" ~.
Denote by K a k - s e t o f P G ( r , q ) w i t h K + @ a n d K + P G ( r , q ) . D e n o t e by m and n r e s p e c t i v e l y t h e s m a l l e s t and t h e g r e a t e s t p o s i t i v e number o f p o i n t s i n which K is i n t e r s e c t e d by a d-dimensional s u b s p a c e Sd ( l < d S r ) o f S, In o t h e r words w e s e t :
.
Knsd
# gj}
(1.3)
m=min{lKnSdI
:
(1.4)
n=max{lKnSdI
: Knsd # @
We h a v e , o b v i o u s l y (1.5)
Isrn
}
=Od.
..
I f s=O, I , , ,% , by t,=t! w e d e n o t e t h e number o f d - d i m e n s i o n a l s u b s p a c e s o f S,, e a c h o f which c o n t a i n s e x a c t l y s p o i n t s of a f i x e d k - s e t K . The numbers t, a r e c a l l e d t h e c h a r a c t e r s o f i n d e x s o f s e t K , w i t h r e s p e c t t o d i m e n s i o n d. Fix h+lintegers mo,m, mh w i t h O < m , < m , <...<mh, A k-set K i s s a i d t o be of c l a s s [ m a , ml m,, w i t h r e s p e c t t o t h e d i m e n s i o n d , i f t , =O f o r a n y s d i f f e r e n t from mB,m,, mh.Moreover,a k - s e t K of c l a s s [mg,m,,...,mh]d, w i t h t h e a d d i t i o n a l c o n d i t i o n t,#-0 f o r s=m, ,ml , .mh, i s s a i d t o b e o f t y p e (mo,mI m h ) d , w i t h r e s p e c t t o d i m e n s i o n d , cf. [ 7 ] . Note t h a t , i f m=n,each Sd o f S r i n t e r s e c t s K i n z e r o o r m p o i n t s . S o i f r = 2 , e i t h e r we h a v e K = @ o r K=S2 or K i s a set o f t y p e (O,m), w i t h m=p' ( 0 5 t < h ) (cf. 171). If r 2 3 , w e h a v e two p o s s i b i l i t i e s : ( i ) d - d i m e n s i o n a l s u b s p a c e s e x t e r n a l t o K d o n o t e x i s t . ( I n t h i s case w e know t h a t e i t h e r K = @ o r K=S,). (ii) Suppose t h a t t h e r e i s a n s d w i t h o u t p o i n t s i n common w i t h K . (Then e i t h e r K i s o n e p o i n t o r t h e complement o f a h y p e r p l a n e ( c f . [ 7 ] , Prop. I , XIV)). So. w e suppose:
,...,
,...,
,..., Id,
...,
..
G. Tallini
434 (1.6)
.
l<m
.
Let K be a k-set of S r Denote by m and n , r e s p e c t i v e l y t h e s m a l l e s t and t h e g r e a t e s t c a r d i n a l i t y of t h e set Sd n K , i f Sd n K k $.Then K i s c a l l e d a ( k ; O,m,n)d-set. The c h a r a c t e r s of a k - s e t K o f S, s a t i s f y Lhe f o l l o w i n g c o n d i t i o n s ( c i . [7]) :
(1.7)
(1.7),,
and (1. 7)1,1
imply:
e
(1.8)
S-m
s2 ts =
[(lC-l
r-
2
+ Yr-
,d .
I ,
d-
I
1
F i x two i n t e g e r s M,N. By ( 1 . 7 ) and (1.8) we have: s-m &(N-s)(s-Ff)t,=-F
(1.10)
,
F=F(k,M,N,to,r +
Yr-z.d-
Suppose 14Tn
,
2
d , q ) = Yr-s,d-ok2-
] +MI{( r , d
-to )
k [(M+N-~)Y~-~,~-~+
-
M l m , then F S 0
(1.11)
Moreover, w e claim t h a t
<=>
F=O
(1.12)
N=n, M=m,
t,+,=
...=t
=O.
"-1
I n f a c t N > n i m p l i e s F # 0 ( s i n c e ' t n + 0) and M < m i m p l i e s F#O t o o . So, when F=O i t f o l l o w s N=n and M=in. C o n s e q u e n t l y , w e h a v e t,+, = . . . = tn - i =O. The c o n v e r s e is o b v i o u s . By (1.12) w e h a v e (1.13)
F=O
+>
N=n, M=m,
K i s of c l a s s [O,m,nId
.
S i n c e F L U , i f N a n and M g m i t f o l l o w s
A=
[( M f N - l ) Y r - l , d - l
Then, i f N 2 n and M < m ,
(1.15)
to 2
b r , d -to)
tYr-z,d-~]Z-4MNYr-z,d-Z
w e have:
yr,d - [(M+N-l)yr-t,d-t
+Yr-z,d-z
3'
/4MNyr-z,d-2
I n (1.15) t h e e q u a l i t y h o l d s i f , and o n l y i f , A =O. S i n c e F S O , i n (1.15) h o l d s i f , and o n l y i f , F=O and k=k,:
=
[(m+n-1) yr-
I
,d-,
'Yr-n,d-z]
the
'
equality
I2 Y r - z , d - z
t h a t i s i f , a n d o n l y i f , (1.13) h o l d s w i t h k=ko. C o n d i t i o n (1.15) d o e s n o t depend on k. When
its
right-hand
side
is
On Blocking Sets in Finite Projective and Affine Spaces
.
p o s i t i v e , (1.15) g i v e s u s a l o w e r bound f o r t o s i g n i f i c a n t , w e c a n e x c l u d e t h e e x i s t e n c e o f some I f M=m and N=n, i t f o l l o w s F S O . So w e h a v e a h o l d s and c o n s e q u e n t l y ( 1 . 1 5 ) . Then w e c a n d e d u c e
<
k, I k
(1.16)
43 5
When t h i s l o w e r bound i s k-sets. s p e c i a l case i n which ( 1 . 1 4 ) t h e bound f o r k:
k,
where k, and k, a r e t h e s o l u t i o n s o f t h e e q u a t i o n F=O ( i n which w e p u t M=m, IJ=n). I n ( 1 . 1 6 ) k = k , ( o r k=k,) h o l d s i f , and o n l y i f , F=O. T h a t i s i f , and o n l y i f , (1.13) h o l d s . Moreover, w e n o t e t h a t i f l = n , M=m, ( 1 . 1 5 ) becomes: (1.17)
t o 2 Y r - 2 , d - z {[4mn -
Yr,d/Yr-z.d-2
1
-
/ Y ~ . , , ~ - ~ I ~/4mn. }
[l+(m+n-l)yr-,,d-,
W e set:
(1.18)
D
2
:= 4m-(m+n-l)
By (1. 2 ) , we h a v e : ,
Yr-,,d-, /yr-z,d-z=br-i/6d-i
Yr,d / Y r - z , d - z =
3r6r-i'Gdad-?
So (1.17) c a n b e w r i t t e n i n t h e form: (1.19)
t o 2 Yr-z,d-2
[Dq
2r+d-2
+P(q)
1 /4mn
adai-1
where (1.20)
P(q):=D
6d
+ q d @ r - z (fir-, +2q'-')
-l
- 4mnqd6r-1 6 r -d
-1
-6d 6d
- 1
1
-
[2(m+n-1) f i r - , + 6 d - ,
i s a p o l y n o m i a l f u n c t i o n whose d e g r e e i s less t h a n 2r+d -2. (1.21)
A(q):=D q
zr
+ d--2
I
Now w e set
+ Kq).
So ( 1 . 1 9 ) becomes: (1.22)
t o >Yr-z,d-z
A(q)/4mn +d
*:-1
-
S u p p o s e D=4mn - (m+n-l)'>O. S i n c e A(0)=-(m-njz< 0, t h e r e e x i s t s i n t h e s e t of r e a l p o s i t i v e numbers R f , a t l e a s t o n e s o l u t i o n o f t h e e q u a t i o n A(q)=O. D e n o t e by q, t h e g r e a t e s t s o l u t i o n of t h e e q u a t i o n A(q)=O i n R f We h a v e A(q)>O f o r e a c h q > q o , and
.
D=4mn-(m+n-l)' S i n c e n-( h - 1 ) ' > (1.23)
=- [.-(
.
0 , w e c a n write:
n<(hh+l)'+>D>O
C o n d i t i o n (1.23)
[
h-1j2]. n-( &+1)')
=>
to>O,
W
q>qo.
i m p l i e s t h e f o l l o w i n g theorem:
I. If q > q , i n P G ( r , q ) t h e r e i s no (k;O,m,n)d-set w i t h t,=O and n < ( h h + l ) ' . (We s h o u l d remember t h a t q o is t h e g r e a t e s t real p o s i t i v e s o l u t i o n of t h e e q u a t i o n A(q)=O, w i t h A ( q ) d e f i n e d i n ( 1 . 2 1 ) ) . S u p p o s e r = 2 , d = l . By ( 1 . 2 2 ) ,
we h a v e
G. Tallini
436
The i m p o r t a n c e o f ( 1 . 2 2 ) , (1.23) a n d ( 1 . 2 4 ) c a n b e shown i n s e v e r a l s p e c i a l cases. The f o l l o w i n g are e x a m p l e s of s u c h cases. L e t K b e a k - s e t i n pG(2,q), w i t h m = l and n=3. Then c o n d i t i o n ( 1 . 2 4 ) h o l d s and q:4,309 So t h e f o l l o w i n g i s a C o r o l l a r y o f Theorem I.
... .
11. I n PG(2,q) i f q > 4 , a k - s e t w i t h m = l , n=3, a d m i t s a t l e a s t to e x t e r n a l l i n e s , w i t h to>[3q2-12q-41/12. (Note t h a t a n i r r e d u c i b l e c u b i c i s s u c h ‘.-set. When q 4 , t h e e x i s t e n c e of i r r e d u c i b l e c u b i c s w i t h o u t e x t e r n a l l i n e s i s w e l l known. One o f t h e s e i s t h e u n i t a l of e q u a t i o n x3+y3+z3=~). It f o l l o w s t h a t i n P G ( r , q ) , q > 4 , e a c h k - s e t o f c l a s s [ O , 1 , 2 , 3 I 1 , w i t h r e s p e c t t o l i n e s , always admits e x t e r n a l l i n e s .
<
L e t K b e a k - s e t i n PG(2,q) w i t h m=2 and n < 5 . C o n d i t i o n (1.23) we have qo=11,20 Then
....
holds
and
111. A k - s e t o f PG(2,q) o f class [ 0 , 2 , 3 , 4 , 5 ] , admits a t least t o e x t e r n a l of l i n e s i f q > 11,where t,>[4q2-44q-9]/40,Then i n P G ( r , q ) , q > 11, a k - s e t c l a s s [O,2,3,4,51,a l w a y s a d m i t s e x t e r n a l l i n e s .
Let u s now c o n s i d e r a p a r t i c u l a r case o f Prop.111. Suppose q>:1 and q e v e n i n P G ( 2 , q ) ; l e t K , and K, d e n o t e t w o d i s t i n c t (q+Z)-arcs i n s u c h a p l a n e . S u p p o s e t h a t a n a l g e b r i c c u r v e %‘ o f d e g r e e 5 i n PG(Z,q),q >11, s a t i s f i e s t h e following conditions: ( i ) $9 c o n t a i n s n o l i n e s , ( i i ) $9 h a s n o e x t e r n a l l i n e s . Then % a d m i t s t a n g e n t l i n e s and K , !J K, a d m i t s e x t e r n a l l i n e s . 2 . THE k-SETS OF AG(r,q) L e t A,=AG(r,q) b e a n a f f i n e Galois s p a c e o f d i m e n s i o n r > 2 and o r d e r q. L e t K be a k - s e t of A , w i t h K?$6 and K # A , . Denote by m and n r e s p e c t i v e l y t h e s m a l l e s t , a n d t h e g r e a t e s t p o s i t i v e number of p o i n t s common t o K and a d - s u b s p a c e Ad o f A , , w i t h A d n K= $6 Let u s put t h e r e f o r e
.
{ 41 n=max I K n {
(2.1)
m=min 11: f l
(2.2)
:
Ad(
O b v i o u s l y , we h a v e
l<m
Ad
n K *$6}
Ad
nK
f
$6).
l A d l =qd.
Denote by t,=t: ( s = O , l , . . . , q d ) t h e number of d - d i m e n s i o n a l s u b s p a c e s of A , , e a c h of which c o n t a i n s e x a c t l y s p o i n t s of set K.The numbers t , are c a l l e d t h e c h a r a c t e r s . As w i t h t h e p r o j e c t i v e case, t h e k - s e t K i s s a i d t o b e o f c l a s s Em,, m l mkId, w i t h r e s p e c t t o t h e d i m e n s i o n d , i f t , = O f o r e v e r y s # m , , , m , , ..,mp Suppose K i s o f class[mo,ml , If i n a d d i t i o n tSZ0 when s=mo , m 1 , v , t h e n K i s s a i d to b e of t y p e ( m o , m l , . . . , mejd. If m=n, w e h a v e e i t h e r t O = O o r t o > O . I n t h e case t O = O , K i s o f t y p e (m)d C o n s e q u e n t l y , n e i t h e r K= @ n o r K= AG(r,q) ,a c o n t r a d i c t i o n . Suppose now t o> 0. I n t h i s case K i s o f t y p e (0, m)d.So,if w e h a v e t h e a d d i t i o n a l c o n d i t i o n 1 >3, set K i s o n e p o i n t (cf.[5]). I n t h e sequel l e t u s suppose
,...,
.
.. .,meld.
...,
(2.3)
.
l < m <
n
The c h a r a c t e r s o f a k-set K s a t i s f y t h e f o l l o w i n g e q u a t i o n s , ( t h e p r o o f
is
On Blocking Sets in Finite Projective and Affine Spaces
similar t o t h e p r o j e c t i v e case).
(2.4)
C o n d i t i o n s (2.4)11 and (2.4),11 i m p l y :
(2.5) Now we f i x two i n t e g e r s P4 and N. We have:
I n t h e s e q u e l , w e suppose N z n and M s m . These c o n d i t i o n s imply 0
<
n
2
(N-s)(s-M)ts
=-Yr-23d-2
F
I
s=m
So, i t f o l l o w s F <_ 0.
(2.8)
We h a v e ( a s w i t h (1.12)):
(2.9)
F=O
N=n,
M=m,
tm+l=...=tn-l=O
t h a t is,
(2.10) As F
F=O
5 0,
N=n, M a , and K is e i t h e r of t y p e (O,m,n)d or of t y p e (m,n)d a c c o r d i n g t o t o >0, o r t o = 0.
<=3
we have
C o n d i t i o n s (2.11) and (2.12) h o l d i n t h e case M=mand N=n, t o o . I n (2.12) e q u a l i t y h o l d s i f , and o n l y i f , A=O. A s F G O , w e have: In
(2.12)
e q u a l i t y h o l d s i f , a n d o n l y i f , F=O w i t h k=k,
:=
t h a t i s i f , and o n l y i f ,
[ l+(m+n-l)$r,_l / G - , ] /2; (2.10) h o l d s w i t h k=k, .
437
438
G. TaElirzi
I f t h e right:-hand s i d e o f ( 2 . 1 2 ) i s p o s i t i v e , we g e t a l o w e r bound f o r t o . I n t h i s c a s e we can exclude t h e e x i s t e n c e of p a r t i c u l a r k-sets. I f M=m a n d N=n, i t f o l l o w s F < 0 a n d e i t h e r c o n d i t i o n ( 2 . 1 1 ) o r (2.12) h o l d s . So, w e c a n d e d u c e t h e b o u n d s f o r k
kl 5 k I k ,
(2.13)
w h e r e k, a n d kZ a r e t h e s o l u t i o n s o f ( t h e e q u a t i o n ) N=n)
F=O
M=m
and
I n ( 2 . 1 3 ) w e h a v e k=k, or k=k, i f , and o n l y i f , F=O; t h a t i s i f , a n d o n l y (2.10) holds. W e o b s e r v e a g a i n t h a t , i f N=n a n d M=m, ( 2 . 1 2 ) becomes
if,
.
(in
which
By ( 1 . 1 8 ) a n d ( 2 . 1 4 ) w e h a v e :
where P ' ( q ) is t h e f o l l o w i n g polynomial o f q w i t h
d e g r e e l e s s t h a n 2r-2:
8
Put
,
B ( q ) := D q 2 ' - * + P ' ( q )
(2.17)
D :=4mn-(m+n-1) 2
.
So ( 2 . 1 5 ) becomes t o >/
(2.18)
.
2
Y ~ d -- 2 ~B ( q ) / 4 m n a d - ,
I f r = 2 a n d d = l , ( 2 . 1 8 ) becomes t o >B(q)l4mn=
(2.19)
{
Dqa, -
9,
[ (mtn)
2
-11 -1
j
/4mn.
S i n c e B(O)=-(n-m)'< 0 , i f D > C ) , t h e e q u a t i o n B(q)=O h 2 s r e a l p o s i t i v e s o l u t i o n s . D e n o t e by qb t h e g r e a t e s t p o s i t i v e s o l u t i o n o f B(q)=O. Then B ( q ) > O f o r e a c h q>qA We h a v e :
.
D=4mn-( m+n-1 S i n c e n-(Cn-l)
(2.20)
2
)2= -
[n-( d'T1-1)~].[n-(
> 0, by p r e v i o u s e q u a l i t y
e> D
n<(h+1)'
> O
=>
fit1 ) 2
].
it follows:
to>3,
v
q>qb
.
By ( 2 . 2 0 ) w e o b t a i n
I V . I f q>qA
,
t h e n i n AG(r,q)
t h e r e i s no k - s e t w i t h t , = O
and n < ( h + l )
2
.
3. SPREADS WITH LINES I N P G ( r , q ) L e t S , = P G ( r , q ) b e a p r o j e c t i v e G a l o i s s p a c e o f d i m e n s i o n r a n d o r d e r q=ph ( p p r i m e ) . A f a m i l y y ( # @) of l i n e s o f P G ( r , q ) m u t u a l l y skew i s c a l l e d a s p r e a d i n P G ( r , q ) . If t h e u n i o n S o f t h e l i n e s o f 9 c o i n c i d e s w i t h P G ( r , q ) ,
On Blocking Sets in Finite Projective arid Affine Spaces
439
t.he s p r e a d 9 i s s a i d 1.0 b e 1.ot.al or a s p r e a d o f P G ( r , q ) ; i f i t is not^, Y i s s a i d 1.0 b e p a r t i a l . A s p r e a d .v i n P G ( r , q ) i s s a i d 1.0 b e m a x i m a l i f i n P G ( r , q ) t . h e r e e x i s t ~ sn o s p r e a d .’f‘ s u c h t.hai. ,Y’ C .Y’: L?t. b e a s p r e a d i n P G ( r , q ) , r r 4 . C o n s i d e r t.he s u b s p a c e s S , o f P G ( r , q ) t h a t c o n t . a i n at. least. o n e l i n e o f .Y.Den0t.e by m a n d n r e s p e c t i v e l y t h e T h a t is, s m a l l e s t . a n d t.he g r e a l . e s t number o f l i n e s o f .Y c o n t a i n e d i n a S , i f Y‘nS, dcnot.es t h e set of l i n e s of Y c o n t a i n e d i n S, , t.hen:
.
ii.yns,i
(3.1)
m=min
(3.2)
n=max{i
~ , n g~} z
:
ms, I
S,
n ,Y i’. @
}.
Obviously, it h o l d s
(3.3)
.
1rin1nsl+q 2
...,
We d e f i n e c h a r a c t e r t , (s=O,l, I+q2) of a spread Y i n PG(r,q) with r e s p e c t . 1.0 d i m e n s i o n 3 , t.he number of s u b s p a c e s S , of P G ( r , q ) c o n t a i n i n g e x a c t l y s l i n e s of c Y ( c f . [ 8 ] ) . A s p r e a d .Y is s a i d t o b e o f c l a s s [m,,m, , .,m,] w h e r e O S ! J , < ~ ~ < < m e-; mo,m,,. ,mp.1fgy 5 q%l , w i t h r e s p e c t . t o t h e d i m e n s i o n 3 , i f t,=O f o r e a c h s . , m p , t.he:l :/is s a i d i s of c l a s s [m,,m, meland m o r e o v e r t , f O V s = m o , m l t o b e of t y p e (mo,m,,.-.,mg) w i t h r e s p e c t t o dimension 3. I f m=n i n ( 3 . 3 ) , n e c e s s a r i l y .Y i s of c l a s s [0,m] w i t h r e s p e c t t o d i m e n s i o n 3. I n P G ( r , q ) t h e r e a r e n o s p r e a d s wit-h a s i n g l e c h a r a c t . e r d i f f e r e n t f r o m z e r o . M o r e o v e r , s p r e a d s of t y p e ( 0 , m ) e x i s t o n l y i.f r=4 ( c f . [ 8 ] ) . Consequent . ] ~ , i f r s 5 , then rncn i n (3.3). I< The c h a r a c t e r s o f a s p r e a d Y s a t i s f y t h e f o l l o w i n g e q u a t i o n s , w h e r e (cf. [Sl):
..
..
,..
,...,
...
lyl=
(3.4)
1 stm
s(s-l)t,=
Conditions (3.4)
(3.5)
and (3.4),,
k(k-1)
imply
s-m
However we f i x t w o i n t e g e r s 1l. a n d N , i t h o l d s
z n
(3.6)
5-m
t, =
(h-S)(S-!l)
-9
where
(3.7)
! P = 91 ( k , M , N , q , r , t ,
) = k 2 - k [l+(M+N-l)Yr-z,~
]
I n t h e s e q u e l , we s u p p o s e N T n , b k m . T h e c o n d i t i o n s i m p l y So, i t f o l l o w s
z (N-s)
s-m
(s-Pl)
spco.
(3.8) Suppose m
(3.9) that is
t,lO.
A s w i t h (1.12) and ( 2 . 9 ) ,
9, =O
e
N=n,
M=m,
we have
tm+,=. ..=t,-,=0
+ MlV(
Yr.3 -to
)
.
440
C. Tallini
If N=n and M=m, (3.11)
to
N=n, M=m, Y o f t y p e (O,m,n) i f t o > O , o r Y o f t y p e (m,n) i f t o = O , b e i n g r = 4 , 5 n e c e s s a r i l y , [81.
<=>
y=0
(3.10)
( 3 . 6 ) and (3.8) imply:
> {
k2-k Ll+(m+n-l)yr-2s, A
+my,,,}
/mn,
where t h e e q u a l i t y h o l d s i f , and o n l y i f , ( 3 . 1 0 ) h o l d s . Since
I p l O , w e have 2
(3.12)
A
=
- 4 m ( Y , , ~ - t o )2 0 ,
[(MtN-1) 7, - ~ , , +1]
which i m p l i e s
(3.13)
t o2
{ 4Mi y r , 3 -
[lt(M+N-l) y r - 2 , 1
]'} /4MN.
I n p a r t i c u l a r ( 3 . 1 2 ) and ( 3 . 1 3 ) h o l d i f M=m and N=n. I n (3.13) t h e e q u a l i t y h o l d s i f , and o n l y i f , A=O. S i n c e that : e q u a l i t y h o l d s i n (3.13) i f , and o n l y i f , Tp=O w i t h (3.14)
k=
l+(mtn-1)
)'r-2,
11 2
k,
I
we
and
(3.12)
,
t h a t i s i f , and o n l y i f , ( 3 . 1 0 ) and ( 3 . 1 4 ) h o l d . I f , i n p a r t i c u l a r , w e p u t N=n, M=m i n ( 3 . 7 ) , since (3.13) are s a t i s f i e d , w e o b t a i n t h e bounds (3.15)
k <
Ips0
or
k , ,
where k, and k, a r e t h e s o l u t i o n s o f Sp =O. I t r e s u l t s k=k, or k=k2 i f , and o n l y i f , (3.10) h o l d s . Moreover, w e n o t e t h a t , i f N=n, M=m, m < n , r 2 4 , (3.13) becomes (3.16)
have
y C 0,
t o 2{4mnyr,, - [l+(m+n-l)yr-2,,
in
(3.15)
I
I }
/4m.
Condition (3.16) is s i g n i f i c a n t , i f its right-hand s i d e i s p o s i t i v e . I t can b e w r i t t e n ( c f . (1.18)):
ED
q 4 r - 6 + F ( ~ ) I /4nn
6,q26,
where F ( q ) i s a p o l y n o m i a l i n q w i t h a degre'e l e s s t h a n determined e a s i l y ) . I f w e p u t
C( q )=Dq'
(3.17)
r-
4r-6
(which
can
be
+P( q ) ,
we obtain to 2
(3.18)
c(q)/4m6$6263
,
Since C(q)= 6, 6,6,
{
4mnyr,, - [ I + ~ m + n - i J . y , . 2 , , J2}
2
2
,
t h e n C(O)=-(n-m)< 0. So, i f D=4mn-(m+n-l) > 0, t h e e q u a t i o n C ( q ) = 0 h a s r e a l p o s i t i v e s o l u t i o n s . Denote by T o t h e g r e a t e s t r e a l p o s i t i v e s o l u t i o n o f 2 C(q)=O. Then C ( q ) > O f o r e a c h q > ? O . We h a v e D=4mn-(m+n-l) = [n-(6-1)2f* .[n-(h+l)*]
. By
t h i s , s i n c e n-(&l)'
>
0, w e o b t a i n
On Blocking Sets in Finite Projective and Affine Spaces (3.19)
n<
(&n+l)
2
G> D > 0
=>
to
4,
, there
v
q>;io
44 1
.
By (3.19) i t f o l l o w s : q >
V. I n PG(r q ) w i t h r > 4 , f o r e a c h and n < ( S m + l ) j
.
are no s p r e a d s w i t h t,=O
4. BLOCKING SETS I N P G ( r , q ) A s u b s e t S o f P G ( r , q ) is c a l l e d a b l o c k i n g s e t w i t h r e s p e c t t o l i n e s , i f i t s a t i s f i e s the following conditions. ( i ) Each l i n e o f P G ( r , q ) i n t e r s e c t s S. ( i i ) S c o n t a i n s n o l i n e s of P G ( r , q ) . It f o l l o w s i m m e d i a t e l y t h a t :
V I . The complement o f a b l o c k i n g set i s a b l o c k i n g set. The s e t H n S i s a b l o c k i n g set of
V I I . Let H be any subspace of PG(r,q). w i t h r e s p e c t t o t h e l i n e s o f H.
H
A b l o c k i n g s e t S i s s a i d t o b e i r r e d u c i b l e i f f o r a n y p o i n t P E S t h e set S - ( P l i s n o t a b l o c k i n g set, i . e . i f a t l e a s t o n e t a n g e n t p a s s e s t h r o u g h each p o i n t P of S. C l e a r l y , e a c h b l o c k i n g set S c o n t a i n s some i r r e d u c i b l e b l o c k i n g set.
VIII. I n PG(2,q) t h e r e d u c i b l e b l o c k i n g set.
complement
of
an
irreducible
blocking
set
is
a
PROOF. Let S be a n i r r e d u c i b l e b l o c k i n g set of PG(2,q), s u c h t h a t i t s complement S' is i r r e d u c i b l e t o o . I f P E S , t h e r e e x i s t s a t l e a s t o n e t a n g e n t t of S t h r o u g h P. Denote by Q , , Q z two p o i n t s w i t h Q,$ Q2 and Q , , Q z E t - { P I A t a n g e n t ri t o S ' n e c e s s a r i l y p a s s e s t h r o u g h Q , ( i = l , Z ) , i . e . a q - s e c a n t of s. Moreover, r , # r 2 and ri + t. S i n c e S i s i r r e d u c i b l e , n e c e s s a r i l y S = ( r , - ( Q , l ) U U(r2 - ( G 2 ) ) U ( P ) ( I f w e add a p o i n t , w e h a v e a c o n t r a d i c t i o n ) . Then q > 2 and S'=PG(2,q)-S. Hence, S' i s r e d u c i b l e , a c o n t r a d i c t i o n . Another p r o o f o f VIII i s t h e f o l l o w i n g , L e t S and S'=PG(Z,q)-S b e i r r e d u c i b l e b l o c k i n g sets of PG(2,q). Through e a c h p o i n t P o f S t h e r e i s a t l e a s t o n e t a n g e n t t o S and t h r o u g h e a c h p o i n t P' of S' t h e r e i s a t l e a s t a q - s e c a n t S Moreover, t h e l i n e s p a s s i n g t h r o u g h d i s t i n c t p o i n t s o f t h e s e l i n e s are d i s t i n c t . Denote by t S t h e c h a r a c t e r of i n d e x s of S (Cf.R.1). Then t1+tq>az2. S i n c e t , t ...+t q = Q 2 , w e h a v e t , + t q = Q 2 , t 2 = = t q - l = O , t h a t i s S i s of t y p e ( 1 , q ) . T h i s i s a c o n t r a d i c t i o n , s i n c e s e t s of t y p e ( 1 , q ) d o n o t e x i s t ( c f . [ 7 ] ).
.
.
.
...
Problem. I n P G ( r , q ) , 9 2 3 , are t h e r e i r r e d u c i b l e b l o c k i n g sets whose comp l e m e n t s are i r r e d u c i b l e ? A n example o f i r r e d u c i b l e b l o c k i n g s e t i n P G ( 2 , q ) , w i t h q s q u a r e , is t h e Baer s u b p l a n e . I n f a c t , P G ( 2 , G ) i s a ( q + q t l ) - s e t o f t y p e (l,l+ Q). O t h e r e x a m p l e s c a n b e found i n t h e p r o o f o f X I I . The f o l l o w i n g t h e o r e m o f Bruen ( [ 2 ] , [ 3 ] ) c o n c e r n s t h e b l o c k i n g sets of PG( 2 ,q 1. I X . Let S be a b l o c k i n g s e t of PG(2,q).
(4.1)
q+dj+l
<
I SI <
Then q2-
sq
.
The e q u a l i t y h o l d s o n t h e l e f t - h a n d s i d e i f , and o n l y i f , S i s a B a e r s u b p l a n e ( t h a t on t h e r i g h t - h a n d s i d e h o l d s i f , and o n l y i f , S i s a complement o f a
G. Tallbzi
442 Baer s u b p l a n e ) .
No b l o c k i n g set. e x i s t s i n P G ( 2 , 2 ) . From V I I i t l o l l o w s
I t . can b e p r o v e d d i r e c t . l y o r by ( 4 . 1 ) .
X. No b l o c k i n g set. e x i s t s i n P C ( r , Z ) , r 2 2 . Now w e p r o v e t h a t
X I . I n PG(2,3) t h e r e a r e e x a c t l y two b l o c k i n g t h e s e h a s 6 p o i n t s , t.he o t h e r h a s 7 p 0 i n t . s .
set.s,
u p t.o i s o m o r p h i s m s . O n e o f
PROOF. Each b l o c k i n g set. o f P C ( 2 , 3 ) h a s 6 or 7 p o i n t s by ( 4 . 1 ) . S i n c e P C ( 2 , 3 ) h a s 13 p o i n t s , i f S i s a b l o c k i n g set. w i t h I S I = 6 , t h e comSlemen1 S ' o f S i s a b l o c k i n g s e t . wit.h 7 p o i n t s , a n d v i c e v e r s a . T h e f o l l o w i n g e x a m p l e p r o v e s t.he C o n s i d e r tthe p o i n t s e x i s t e n c e o f a b l o c k i n g s e t . S w i t h ISI=6 (see a l s o [ l ] ) . U, ( O , l , l ) , ( u s i n g homogeneous c o o r d i n a t . e s ) : O , ( l , O , O ) , 0, (0,1,0),0,(0,0,1), U,(l,O,l), U , ( l , l , O ) , V ( O , l , - 1 ) , W ( l , O , - 1 ) . I t . i s v e r y e a s y t o v e r i f y t h a t t h e s e t { O,, U , , U , , U,, V,W i s a n i r r e d u c i b l e b l o c k i n g set. w i t h 6 p o i n t - s . N o w w e p r o v e t h a t a n y ot.hcr b l o c k i n g set. wit.h 6 p 0 i n t . s is p r o j e c t i v e l y e q u i v a l e n t t o t h e p r e v i o u s b l o c k i n g s e t . I t i s s u f f i c i e n t t.0 p r o v e that. e a c h b l o c k i n g s e t S w i t h 6 p o i n t s n e c e s s a r i l y h a s t.wo 3 - s e c a n t l i n e s , w h i c h mret. at. a p o i n t o f S. S i n c e S h a s t h e s m a l l e s t . c a r d i n a l i t y , S i s i r r e d u c i b l e . Then t - h r o u g h e a c h p o i n t O3 t h e r e i s a t l e a s t . o n e Langent t.o S. Two t . a n g e n t s t o S c a n n o t p a s s t.hrough 0, , b e c a u s e t.he ot.her 5 p o i n t s o f S s h o u l d l i e on t.he o t h e r two l i n e s t-hrough 0,. T h i s i s a c o n t r a d i c t i o n , b e c a u s e a l i n e s h o u l d b e c o n t a i n e d i n S. H e n c e , e v e r y l i n e t h r o u g h 0, , d i f f e r e n t . f r o m t.he ttangenl:, c o n t . a i n s a t least a f u r t . h e r p o i n t o f S a n d at. l e a s t o n e p o i n t . o f t h e complement of S. Then t h e r e m a i n i n g t w o p o i n t s of S l i e n e c e s s a r i l y on two d i s t i n c t . l i n e s t h r o u g h 0, , w h i c h a r e 3 - s e c a n t o f S. Let. 0, b e ( 0 , 0 , 1 ) . Assume t.he t.wo Moreover, p o i n t s o f t h e 3 - s e c a n t a n d o u t s i d e S a s O t = ( l , O > O ) and 0 , = ( O , l , O ) . l e t U , = ( l , 1 , O ) b e t h e point: common t o S arid tto a l i n e t h r o u g h 0, , w h i c h i s n o t a 3 - s e c a n t o f S. So w e o b t a i n e x a c t l y t.he b l o c k i n g s e t o f t h e p r e v i o u s example. A d i i f e r e n t . p r o o f of t h i s t h e o r e m c a n b e f o u n d i n H i r s c h f e l d [5). We r e c a l l t.he f o l l o w i n g :
1
THEORZM ( M a z z o c c a - T a l l i n i [6]). For a n y p r i m e power q t h e r e e x i s t s a n i n t - e g e r b = b p ( q ) , which d e p e n d s o n l y on q s u c h t h a t i n P G ( r , q ) no b l o c k i n g s e t e x i s t s i f , and o n l y i f , r i s great-er t h a n b .
By X a n d XI1 i t . is:
No\" w e p r o v e t h e f o l l o w i n g X I I . In a n y P G ( 2 , q ) w i t h q 2 3 , t h e r e a r e b l o c k i n g s e t s . PROOF. W e g i v e s e v e r a l e x a m p l e s of b l o c k i n g s e t s f o r e v e r y 4 2 3 . a ) D e n o t e by 0 , , 0 , , 0, t h r e e i n d e p e n d e n t p o i n t s o f P G ( 2 , q ) . Define t h e set
I t . i s e a s y t o v e r i f y t h a t S i s a b l o c k i n g set. w i t h lSl=qz -2q+4. The complement of S is a n i r r e d u c i b l e b l o c k i n g set. b ) Let C b e a c o n i c , T a p o i n t o f C a n d t t h e t a n g e n t on T t.o C. The set S=Cu L - { T } , i f q i s o d d , i s a n i r r e d u c i b l e b l o c k i n g s e t w i t h ISI=2q. S e t S is of t y p e (1,2,3,q) with r e s p e c t t o t h e l i n e s .
On Blocking Sets in Finite Projective and Affine Spaces
443
c ) Suppose q odd. L e t C be a c o n i c o f PG(2,q). d e n o t e by S t h e set o f e x t e r n a l p o i n t s o f C. C i s o f t y p e ( ( q - l ) / Z , ( q + I ) / Z , q ) . Then S i s a b l o c k i n g set w i t h IS1 =q(q+1)/2. d ) Suppose q s q u a r e . I n PG(2,q) a h e r m i t i a n form H and a B a e r s u b p l a n e S a r e b l o c k i n g sets w i t h IHI=qJ-+l and / S I = q + @ + l . They a r e i r r e d u c i b l e . e ) L e t T be t h e p o i n t - s e t of t h e s i d e s o f a t r i a n g l e i n PG(2,q). Let u s c o n s i d e r T-IVl, V 2 l , where VI , V2are two o f t h e t h r e e v e r t i c e s o f T, t h i s i s a b l o c k i n g set w i t h 3q-2 p o i n t s . From Prop. X I 1 i t f o l l o w s t h a t (4.3)
q23
bp(q)>2.
Now w e p r o v e t h a t
XIII. I f 1-23, t h e r e i s no b l o c k i n g s e t i n P G ( r , 3 ) . Hence, w e h a v e bp(3) = 2
(4.4)
.
PROOF. By VII, i t i s s u f f i c i e n t t o p r o v e t h a t no b l o c k i n g s e t e x i s t s i n PG(3,3). Suppose t h a t S is a b l o c k i n g set i n PG(3.3). By VII, i f ?G i s a p l a n e Then S i s of t y p e ( 6 , 7 ) w i t h o f P G ( 3 , 3 ) , rC ll S i s a b l o c k i n g set o f rC r e s p e c t t o t h e p l a n e s , a s a c o n s e q u e n c e of X I . Denote by t s , t7 t h e c h a r a c t e r s of S w i t h r e s p e c t t o t h e p l a n e s . W e have
.
I
(4.5)
By (4.5),
1
tY3
t g + t7=
=
40
6 t , + 7 t 7 = IS1tY2= 13151 3 0 t 6 + 4 2 t , = 4 IS1 ( I S 1 -1)
we obtain
and ( 4 . 5 ) , 1
,
t,= 280 - 13 IS(
(4.6)
I f w e s u b s t i t u t e t h e s e i n (4.5)lll I S 1 2 - 4 0 IS1
(4.7)
, we
+
t, = 13 ( S I - 240
.
have
420 = 0
.
So w e o b t a i n a c o n t r a d i c t i o n , s i n c e ( 4 . 7 ) h a s n o r e a l
solution
Consequently
t h e a s s e r t i o n i s proved.
We n o t e t h a t e a c h b l o c k i n g set S o f PG(2,4) i s s u c h t h a t 7 < I S ( I 1 4 . Moreover t h e p r o o f of X I 1 i m p l i e s t h e e x i s t e n c e o f a b l o c k i n g s e t f o r e a c h possible cardinality
.
X I V . I n P G ( 3 , q ) , w i t h q e v e n and q > 4 , t h e r e a r e b l o c k i n g sets. Hence, (4.8)
q>4,
q even
=>
b p ( 9 ) 2 3.
PROSF. The f o l l o w i n g i s a n example of a b l o c k i n g set i n PG(3,q) w i t h q e v e n and q > 4 . L e t W b e a ( q + 2 ) - a r c i n a p l a n e n a n d O , , 0, , 0, t h r e e of i t s t h e c o n e p r o j e c t i n g %? froin p o i n t s . L e t 0, b e a p 0 i r . t o u t s i d e $ Z . Denote by U 0,3,) and 0, C o n s i d e r t h e s u b s e t K g i v e n by -(O,O, u a ) t h e p o i n t s of n o u t s i d e l i n e s Ol 0,, O,O,, U301 and i n a d d i t i o n t h e p o i n t s 0, I 02, 0, ; b ) t h e p o i n t s o f p l a n e s 0, 020,, 02030,, O,O, 0, d e p r i v e d of t h e p o i n t s o f t h e e d g e s o f t h e t e t r a h e d r o n 0, O,O,O,, e x c l u d e d a b o v e . I f n, i s t h e face of t e t r a h e d r o n 0, 02030, o p p o s i t e t o 0, , K c a n b e w r i t t e n a s
.
r
r
444
G. Tallini
K:=[
rL'mlun2V",
u m4 - ~ o , o , u o 2 0 3 u 0 3 0 1 u o , o l u o 4 0 ~ u o , 0 3 ) l u {o,, 0 1 ,0 3 } ,
Now w e p r o v e t h a t K i s a b l o c k i n g set i f q.4. We b e g i n by o b s e r v i n g t h a t no l i n e i s c o n t a i n e d i n K . T h i s ' i s t r i v i a l f o r t h e l i n e s of t h e f a c e s of t h e t e t r a h e d r o n 0,0,030, and f o r t h e l i n e s o f t h e c o n e . The o t h e r l i n e s h a v e a t most s i x p o i n t , i n common w i t h K . So no l i n e i s c o n t a i n e d i n K , s i n c e q 2 8. Moreover, e a c h l i n e i n t e r s e c t s K . T h i s i s o b v i o u s f o r t h e l i n e s o f t h e f a c e s of t h e t e t r a h e d r o n , f o r t h o s e o f t h e c o n e and a l s o f o r t h e l i n e s which i n t e r sect t h e f a c e s o f t h e t e t r a h e d r o n o u t s i d e t h e e d g e s . Now s u p p o s e t h a t f i s a l i n e t h r o u g h a p o i n t o f t h e e d g e 0102 and a p o i n t o f t h e e d g e 0, (diffe. r e n t from O4 ). The p l a n e s p a n n e d by O , , and f c o n t a i n s a l i n e f o f Then f ' - { 0 1 ) i s c o n t a i n e d i n K , and so f n f ' € K . The same a r g u m e n t s h o l d f o r O,O, , O,O,. So, t h e a s s e r t i o n f o l l o w s . t h e p a i r of e d g e s O,O,, 0, 0, and
p,
XV.
r
I n P G ( 3 , q ) , w i t h q odd and q 3 7 , t h e r e a r e b l o c k i n g sets. Hence,
(4.9)
,
q 2 7
q
odd
=>
bp(q)
2 3.
PROOF. We g i v e a n example o f a b l o c k i n g set i n PG(3,q) w i t h q odd and q 2 7 . Let b e a p l a n e o f P G ( 3 , q ) , '$ a c o n i c o f n , 0, , O,, 03 t h r e e p o i n t s on v Denote by t,.,t 2 , t, t h e t a n g e n t s t o V on 0 , . O , , 03 r e s p e c t i v e l y . Put TI = t2n , t 3 , T, = t, n t, , T , = t , n t , . L e t 0, b e a p o i n t o u t s i d e m C o n s i d e r t h e set K g i v e n by: a ) t h e p o i n t s o f m o u t s i d e t h e l i n e s O,O, , 02g,O, 0, b u t w i t h t h e p o i n t s 0 1 . 02, 0 3 ; b ) t h e p o i n t s d i f f e r e n t from O4 o f t h e c o n e f! p r o j e c t i n g from 0, t h e s e t ( W U { T , t T,, T3 1 ) - { O l , 0 2 , 031. c ) The p o i n t s of t h e p l a n e s Ol O,O, , 0 1 0 ~ 0 ,, O,O,O, which a r e n o t o n t h e e d g e s b u t w i t h t h e p o i n t s 3,. O , , 0,. o f t h e t e t r a h e d r o n O,O,O,O,,
.
.
The p r o o f t h a t I! i s a b l o c k i n g set i s similar t o t h e p r o o f o f X I V .
5. BLOCKING SETS I N A G ( r , q ) Let AG(r,q) b e a n a f f i n e Galois s p a c e o f d i m e n s i o n r and o r d e r q. A
subset if
S of AG(r,q) i s c a l l e d a b l o c k i n g s e t w i t h r e s p e c t t o t h e l i n e s of AG(r,q) it s a t i s f i e s t h e following conditions: ( i ) Each l i n e o f AG(r,q) i n t e r s e c t s S.
( i i ) No l i n e of AG(r,q) i s c o n t a i n e d i n S. T h e M a z z o c c a - T a l l i n i Theorem a l s o h o l d s i n t h e
a f f i n e case: f o r any q , t h e r e e x i s t s a p o s i t i v e i n t e g e r b,(q) s u c h t h a t i n AG(r,q) no b l o c k i n g s e t e x i s t s i f , and o n l y i f , r i s g r e a t e r t h a n b,(q). ( c f . [ 6 ] ) . I t i s easy t o p r o v e t h a t
X V I . Let S r - , b e a AG(r,q)=PG(r,q)-S,-l set o f P G ( r , q ) .
h y p e r p l a n e of P G ( r , q ) . I f K i s a blocking set o f and K , i s a b l o c k i n g set of S , - , , t h e n K U K O i s a b l o c k i n g
Now w e p r o v e t h a t
X V I I . L e t bp(q) b e t h e g r e a t e s t v a l u e of r f o r which t h e r e i s a i n P G ( r , q ) ( c f . n . 4 ) . Then (5.1)
b,(q)
I bp(q)
blocking
set
.
PROOF. Suppose b,(q) > b p ( q ) . C o n s i d e r a h y p e r p l a n e S ( b p ( q ) ) = P G ( b p ( q ) , q ) of PG(bp(q)+l,q). L e t K ' be a b l o c k i n g s e t o f S ( b p ( q ) ) . I n AG(bp ( q ) + l , q ) = PC(b,(q)+l,q)-S(b,(q)) t h e r e i s a b l o c k i n g set K , s i n c e b p ( q ) + l l b , ( q ) . So, by X V I , K U K ' i s a blocking n e t of PG(bp(q)+l,q). T h i s i s a c o n t r a d i c t i o n , s i n c e
On Blocking Sets in Finite Projective and Affine Spaces b,(q)+l
445
'> b p ( q ) . Then t h e a s s e r t i o n i s proved.
It is easy t o prove t h a t
X V I I I . No b l o ck i n g set e x i s t s i n AG(2,q) w it h q=2,3. Hence
(5.2) Now w e prove t h a t
X I X . I n AG(2,q), w i t h q 2 5 , t h e r e are blocking sets. PROOF. W e prove t h e e x i s t e n c e w i t h t h e f o ll ow i n g example. Denote by ( x , y ) t h e a f f i n e c o o r d i n a t e s i n AG(2,q). Consider t h e set K whose p o i n t s a r e on t h e l i n e s of eq u at i o n s : x=O, y=O, x+y=l r e s p e c t i v e l y , e x c e p t t h e p o i n t s (0.0) ,(O, I), ( 1 , O ) and i n a d d i t i o n t h e p o i n t s ( 1 , l ) . (-1,l). ( 1 , - I ) . I f q i s odd, K i s a (3q-3)-set, w h i l e i f q i s even, K i s a (3q-5)-set. I t is easy t o prove t h a t i f q > 4 , K is a b l o c k in g set. I f q=4, K i s a 7 - set , which i s n o t a blocking set s i n c e , f o r example, i t c o n t a i n s t h e l i n e y = i x t i + l (where i i s such t h a t i2 +i+l=O).
XX. I n AG(Z,q), w i t h q t 4 , t h e r e are blocking sets. PROOF. We prove t h e e x i s t e n c e w i t h t h e f o ll ow i n g example. Denote p a r a l l e l l i n e s . L e t A,B be two p o i n t s w it h AEa, B E b . S e t
by
a,b
two
K :=(a- ( A 1 ) u ( b - ( B t ) u ( A B - ( A , B ) ). K i s a blocking set w i t h 3q-4 p o i n t s . P r o p o s i t i o n s X I X and XX imply t h a t ba(q) 2 2
(5.3)
if q > 4
.
X X I . Each blocking set of A G ( 2 . 4 ) h a s e i g h t p o i n t s .
.
PROOF. L e t K be a b l o c k i n g set of AG(2,4), t h e n K i s of c l a s s C1 ,2 ,3 ] Necessarily t 3 f 0, o t h e r w i s e K would b e a n arc, which a l w a y s h a s e x t e r n a l l i n e s . Moreover, t l P 0 s i n c e t h e complement of K h a s a l s o 3-secant l i n e s (it i s a blocking set t o o ) . P u t I K I =k. Then by (2.8) and (2.10) w e have kz-16k+60 I 0
=>
6 g k S 10
and k = 6
Moreover,we have ( K ' k = 6 k = 7 k = 8
K i s o f t y p e (1.3).
o r k = l O
i s t h e complement o f K ) :
I K'I 1 K'f I K'I
= 10
(K of t y p e ( 1 , 3 ) )
=
9
( K of t y p e ( 1 , 2 , 3 ) )
=
8
(K of t y p e ( 1 , 2 , 3 ) )
Hence, w e can suppose k = 6,7,8; i n f a c t , w e o b t a i n c a r d i n a l i t i e s b y c o n s i d e r i n g t h e complements. We have
.
the
other
possible
G. TaNini
446
\ t, + (5.4)
I
tl
+
t2
+
t3
=
20
2 t , t 3t3 = 5k t 2 + 3t3 = k ( L 1 ) / 2 .
I f k=6, f r o m ( 5 . 4 ) w e h a v e t , = 5 , t , = O , t l = 1 5 . L e t a , b b e two l i n e s w h i c h are 3 - s e c a n t o f K . N e c e s s a r i l y t h e y meet a t a p o i n t o f K , o t h e r w i s e t h e l i n e s t h r o u g h t h e i r common p o i n t would b e e x t e r n a l t o K. Then t h e p o i n t s of K a r e t h o s e o n two 3 - s e c a n t a , b a n d a n o t h e r p o i n t P , w h i c h n e c e s s a r i l y l i e s o n l i n e AB, where { A ) = a \ K , {B) = b \ K . S e t C : = a f l b , t h e n CP i s a 2 - s e c a n t o f K , a c o n t r a d i c t i o n (K is o f t y p e ( 1 , 3 ) ) . So K c a n n o t h a v e 6 p o i n t s . I f k=7, f r o m (5.4) w e h a v e t 3 =6, t 2 = 3 , t , = l l . L e t a , b b e two l i n e s whi.ch are 3 - s e c a n t o f K . They meet n e c e s s a r i l y a t a p o i n t 0 of K . S e t I A ) := a \ K , l a ) := b \ K , d e n o t e by a ' t h e l i n e t h r o u g h B a n d p a r a l l e l t o a , a n d by b ' t.he l i n e t h r o u g h A p a r a l l e l t o b. F i n a l l y p u t C : = a ' n b ' . F i v e p o i n t s o f K l i e on a U b. N e c e s s a r i l y o n e o f t h e r e m a i n i n g two p o i n t s o f K , s a y D , l i e s o n AB, a n d t h e o t h e r l i e s on a ' a n d b ' n a m e l y it i s p o i n t C. CD i s d i f f e r e n t f r o m t h e l i n e s a ' , b ' a n d f r o m OC t o o . ( I t i s p o s s i b l e t o c h o o s e O=(O,O), A=(l,O),B=(O,l) and C = ( l , l ) , w h e r e ( x , y ) a r e a f f i n e c o o r d i n a t e s i n AG(2,4). I t f o l l o w s t h a t A B a n d CC h a v e e q u a t i o n s x+y=l a n d x-y=x+y=O, r e s p e c t i v e l y ) . T h e n CD i n t e r s e c t s a a n d b a t two d i s t i n c t . p o i n t s , w h i c h are d i f f e r e n t from A a n d B, namely a t two p o i n t s of K . So CD i s c o n t a i n e d i n K , a c o n t r a d i c t i o n . So, K c a n n o t h a v e 7 p o i n t s . F i n a l l y , i f k = 8 , t h e e x i s t e n c e o f b l o c k i n g s e t s i s p r o v e d by t h e e x a m p l e g i v e n i n t h e proof of XX. From p r o p o s i t i o n X V I , i t f o l l o w s t h a t
X X I I . No b l o c k i n g s e t e x i s t s i n A G ( r , 4 ) , w i t h r 2 3 . H e n c e ,
(5.5)
ba ( 4 ) = 2
PROOF. S u p p o s e t h a t K i s a b l o c k i n g s e t o f A G ( r , 4 ) w i t h r 2 3 . Each p l a n e a i n t e r s e c t s K i n a b l o c k i n g s e t . Hence Ian K l =8, by X X I . Then K would h a v e a u n i q u e c h a r a c t e r d i f f e r e n t from 0 w i t h r e s p e c t t o t h e p l a n e s . Consequently,we h a v e K = @ or K=AG(r,4) ( c f . [ 7 ] ), a c o n t r a d i c t i o n .
Now we p r o v e :
XXIII. S u p p o s e t h a t i n AG(2,q) t h e r e e x i s t s a b l o c k i n g s e t K s u c h Then l i n e h a s a t l e a s t t w o p o i n t s i n K a n d two p o i n t s o u t s i d e K . s e t e x i s t s i n A G ( r + l , q ) . C o n s e q u e n t l y , e a c h bloc!cing s e t o f s u c h t h a t e i t . h e r t , # 0, o r t q - , $0. PROOF. L e t n = A G ( r , q ) b e a
hyperplane
o f AG(r+l,q),
t h a t every a blocking AG(b,(q),q) is
and K a
b l o c k i n g set i n
.
a , h a v i n g t , = O a n d t,-,=O. Fix a direction 6 , non-parallel to n For each p o i n t P E 7G -K c o n s i d e r t h e l i n e rp t h r o u g h P , p a r a l l e l t o 6 Define the set
.
K'
KU(
(J
(rp -(P))). P€n-K We p r o v e t h a t K ' i s a b l o c k i n g s e t . Each l i n e p a r a l l e l t o 6 i n t e r s e c t s e i t h e r K ' o r i t s complement i n a t l e a s t one p o i n t . L e t S b e any l i n e of AG(r+l,q) n o n - p a r a l l e l t o 6 D e n o t e by a the plane through S p a r a l l e l t o 6 Obviously a i s n o t p a r a l l e l t o n and Ft t h e p o i n t s common t o S' a n d L n t e r s e c t s rC i n a l i n e S ' . D e n o t e by Pl ,P2 K is t h e complement of K ) , d e n o t e by Q t + l , Q, +2 , ,Q, t h e p o i n t s comiilon t o S' a n d K , w i t h 2 It < q-2. =
.
(z
Then w e h a v e
.
,...,
.. .
On Blocking Sets in Finite Projective and Affine Spaces
447
S i n c e 2 5 t l q-2, K ' f l a i s a b l o c k i n g s e t o f a , and s o S ( c a ) i n t e r s e c t s e i t h e r K ' o r i t s complement; namely K ' i s a b l o c k i n g set o f AG(r+l,q). So, t h e a s s e r t i o n follows. Now w e c o n s t r u c t a n example o f b l o c k i n g s e t i n AG(2,q), where q 2 7 , w i t h t,=O, tq-l=O. F i x i n AG(2,q), f o u r d i s t i n c t l i n e s a , b , c , d w i t h a // c , b /I d and a n o n - p a r a l l e l l i n e t o b. S e t A : = a n d , B : = a n b , C : = c n b , D : = c n d , E:=DBnAC. F i x a l i n e b' // b w i t h E # b ' , b'S- b, b'S: d. F i n a l l y s e t F : = B D n b ' , G:=AC n b ' . It is easy t o v e r i f y t h a t
K
=
a u b u c u d u{E.F,G}-{A,B,C,D]
i s a blocking set with t h e required property.
By t h e p r e v i o u s p r o p o s i t i o n i t f o l l o w s t h a t
(5.6)
b,(q)
2
C o n d i t i o n s (5.6) and ( 5 . 1 )
3
if
q r 7
a g a i n imply ( 4 . 8 ) , ( 4 . 9 ) .
6. A CHARACTERIZATION OF HERMITIAN ARCS I n t h i s s e c t i o n w e c h a r a c t e r i z e h e r m i t i a n arcs. So, w e g e n e r a l i z e a r e s u l t o f Bruen and T h a s which i s a b o u t i r r e d u c i b l e b l o c k i n g sets ( c f . C4I). L e t nq be a p r o j e c t i v e p l a n e o f o r d e r q , d e s a r g u e s i a n o r n o t . Denote by S a s-set o f Sq w i t h t,=O and tl 2 IS I (Each i r r e d u c i b l e b l o c k i n g set. o f nq i s a n example o f s u c h a s e t ) . C o n s i d e r t h e c h a r a c t e r s t , o f s e t S. Denote by n Then t h e c h a r a c t e r s s a t i s f y t h e maximum o f Ir n S I , where r i s a l i n e o f rCq ( 1 . 7 ) . I f w e m u l t i p l y ( 1 . 7 ) j by n a n d s u b t r a c t (1.7)llfrom i t , w e o b t a i n
.
.
n- 1
(6.1)
E2 (n-i)t,=n(q2+q+l)-s(q+1)-(n-l)tl
1-
,
where IS I =s. The r i g h t - h a n d s i d e o f ( 6 . 1 ) is n e v e r l e s s t h a n 0; b u t i t i s 0 i f , a n d o n l y i f , t2=...=tn-2=0, namely i f , and o n l y i f , S i s o f t y p e ( 1 , n ) . It f o l l o w s t h a t
(6.2)
t, < ; n ( q Z + q + l ) - s ( q + l ) 1
/ (n-l),
where e q u a l i t y h o l d s i f , and o n l y i f , S i s o f t y p e ( 1 . n ) . i s t , 2 s a n d by ( 6 . 2 ) w e h a v e (6.3)
s 5
By o u r a s s u m p t i o n i t
n(q*+q+l)/(q+n),
where e q u a l i t y h o l d s i f , and o n l y i f , s = t , and e q u a l i t y h o l d s i n ( 6 . 2 ) , i s o f t y p e ( 1 , n ) ; i n t h i s case, f r o m ( 1 . 7 ) w e h a v e t h a t t,= q 2 + q + I - s
=
then S
sq/n = s(s-I)/n(n-l),
by which w e o b t a i n s=qJ-+1, n=Fq+l, namely S i s a ( q J - + l ) - s e t S i s a h e r m i t i a n arc. Then w e proved
of t y p e (l,l+Q),
i.e.
X X I V . L e t S a s-set of nq w i t h o u t e x t e r n a l l i n e s and s u c h t h a t t h e number t l of 1 - s e c a n t l i n e s o f S i s g r e a t e r o r e q u a l t o t h e c a r d i n a l i t y s of S. Denote by n t h e g r e a t e s t number o f p o i n t s common t o S and a l i n e . Then i t f o l l o w s t h a t
(6.4)
s
I n(q2+q+l)/(q+n).
E q u a l i t y h o l d s i f , a n d only i f , S i s a h e r m i t i a n arc.
448
G. Tallini
I t i s easy t o prove t h a t
n(q*+q+l)/(q+n) 5 qG+1
(6.5)
<=>
n <Sqtl
From X X I V w e o b t a i n
XXV. L e t S be a s-set o f PG(2,q) w i t h o u t e x t e r n a l l i n e s and such t h a t s 5 tl and n 5 q+l. Then i t i s :
s
(6.6)
5
qh+l
,
where e q u a l i t y h o l d s i f , and o n l y i f , S i s a h e r m i t i a n arc. W e c o n c l u d e t h i s paper w i t h t h e f o l l o w i n g t a b l e s a b o u t blocking sets (y=yes).
the
existence
of
W r , 4)
Y
Y
Y
Y
?
?
?
?
~
3
4 -
8
9,.
. ., I 3
16
_e
NO
Y
Y
Y
NO
NO
Y
Y
NO
NO
?
Y
NO
NO
?
7
REFERENCES [l]
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[2]
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[33
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643
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[5l
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449
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G. T a l l i n i , F i b r a z i o n i i n r e t t e d i PG(r , q ) , "Le
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37 ( 1 9 8 2 ) , 8 -27. [93
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Quaderno L'Aquila
d i un p i a n o g r a f i c o f i n i t o , con 1103 M . T a l l i n i S c a f a t i , S u i { k ; n j - a r c h i p a r t i c o l a r e r i g u a r d o a q u e l i i con due c a r a t t e r i , n o t a I e I1 Rend. Acc. Naz. L i n c e i , 8 , 4 0 (1966) 812-818 and 1020-1025.
REFERENCE I1 [l;j L.M. B a t t e n , Embedding t h e complement of a minimal p r o j e c t i v e p l a n e , t o appear i n Discrete Math.
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[12]
L.Berardi, I r r e d u c i b l e b l o c k i n g s e t s i n a Mat. I t a l . 1-A (1987), 39-47.
1131
L . B e r a r d i and A . B e u t e l s p a c h e r , B l o c k i n g s e t s of t h e known appear.
symmetric
in
set
design,
Boll.
biplanes,
a
Un. to
114) L. B e r a r d i , A.Beutelspacher and F. Eugeni, On ( s , t ; h ) - b l o c k i n g sets i n F i n i t e P r o j e c t i v e and A f f i n e S p a c e s , A t t i Sem. Mat. F i s . Univ. Modena, 32 (1983). 130-157.
[151 L.Berardi and F.Eugeni, On t h e c a r d i n a l i t y of b l o c k i n g sets J. Geom. 22 (1984), 5-14.
in
[16] L. B e r a r d i and F. Eugeni, On Blocking sets i n a f f i n e p l a n e s , (1984), 167-177.
PG(2,q),
J.Geom.
C17] L. B e r a r d i , F.Eugeni and 0. F e r r i , S u i b l o c k i n g sets n e i sistemi S t e i n e r , B o l l . Un. Mat. I t a l . Algebra e Geometria 1 (1984). 141-164.
22 di
[18] L . B e r a r d i and F. Eugeni, Blocking sets i n p r o j e c t i v e p l a n e of o r d e r f o u r , I n these Proceedings. 1193 L. B e r c r d i , Blocking s e t s i n t h e S(3,6,22), I n t h e s e Proceedings. E203 L. B e r a r d i , Blocking s e t s i n t h e S ( 4 , 7 , 2 3 ) , P r e p r i n t 1986.
large large
Mathieu Mathieu
design, design,
I:
the
case
11:
the
case
1211 L. B e r a r d i and F. Eugeni, Blocking sets i n t h e l a r g e Mathieu d e s i g n , 111: t h e c a s e S ( 5 , 8 , 2 4 ) , P r e p r i n t 1986. 8221 A.Beutelspacher and F.Eugeni, On t h e t y p e of p a r t i a l t - s p r e a d s i n p r o j e c t i v e s p a c e s , Discrete Math. 54 (1985), 241-257.
finite
t231 A. B e u t e l s p a c h e r and F. Eugeni, S u i b l o c k i n g s e t s d i d a t o i n d i c e con p a r t i c o l a r e r i g u a r d o a l l ' i n d i c e t r e , B o l l . Un. Mat. I t a l . 4-A (1985), 441-450.
G. Tallini
450 [24]
A . B e u t e l s p a c h e r and F. Eugeni, A l o w e r bound f o r p a r t i a l t - s p r e a d s o f l e v e l t-1 i n P G ( 2 t + l , q ) , A t t i Sem. Mat. F i s . Univ. Modena, 33 (1984),1-8.
[25] A . B e u t e l s p a c h e r and F. E u g e n i , On n - f o l d blocking sets, Proceedings " C o m b i n a t o r i c s 84" Bari, i n A n n a l s of Discrete Math. 30 (1986), 31-38. [26]
A. B e u t e l s p a c h e r and F. E u g e n i , On b l o c k i n g sets i n p r o j e c t i v e and a f f i n e s p a c e s o f l a r g e order,Communicated i n O b e r w o l f a c h , O c t o b e r 1985, Rend. Mat. (Roma), t o a p p e a r .
r271 A. B e u t e l s p a c h e r and F. Mazzocca, B l o c k i n g s e t s i n i n f i n i t e and a f f i n e s p a c e s , J. o f Geometry, 2 8 ( 1 9 8 7 ) , 111-116.
projective
[ 2 8 ] T.C. Brown, Monocromatic a f f i n e l i n e s i n f i n i t e v e c t o r s p a c e , J. Combinat o r i a l Theory (A), 39 ( 1 9 8 5 ) , 35-41.
[29] P. Cameron and F. Mazzocca, B i j e c t i o n s which p r e s e r v e b l o c k i n g a p p e a r on G e o m e t r i a e D e d i c a t a .
1303 M . J . d e R e s m i n i , On b l o c k i n g s e t s i n Geometry 18 ( 1 9 8 2 ) , 194-198.
C311 M.J. d e R e s m i n i , On 2 - b l o c k i n g sets n a t o r i a 20-B ( 1 9 8 5 ) , 59-69.
symmetric in
BIBD's
projective
with
planes,
sets,
to
I, 2 2 ,
J.
Combi-
Ars
[323 M.J. d e Resmini, On 3 - b l o c k i n g sets i n p r o j e c t i v e p l a n e s , P r e p r i n t 1987.
C331 D . A . Drake, B l o c k i n g sets i n ( 1 9 8 5 ) , 459-462.
block
designs,
J. Combin.
Theory
[341 F. E u g e n i , S u l l a e s i s t e n z a d i t - f i b r a z i o n i i n P G ( r , q ) d i B o l l . Un. Mat. 1 t a l . A l g e b r a e Geometria, 1 ( 1 9 8 4 ) , 19-43.
1351
F. E u g e n i a n d Proceedings.
E.
Mayer,
On
blocking
sets
of
index
fissato two,
In
A,
2
tipo, these
1361 F. Eugeni a n d S. I n n a m o r a t i , On f i x e d p a r i t y sets, I n t h e s e P r o c e e d i n g s .
1373 F. Eugeni and S. I n n a m o r a t i , Arcs a n d b l o c k i n g s e t s i n s y m m e t r i c d e s i g n s , P r e p r i n t 1987. C383 M.Huber, A c h a r a c t e r i z a t i o n o f Baer c o n e s i n G e o m e t r i a e D e d i c a t a . To a p p e a r .
finite
projective
spaces,
1393 F. Mazzocca, Some r e s u l t s o n b l o c k i n g s e t s , Announcements a t C o n f e r e n c e " C o m b i n a t o r i c s 84" Bari ( 1 9 8 4 ) and " F i n i t e Geometries" Oberwolfach (1985). C401 C. O'Keefe, A . V e n e z i a , B l o c k i n g sets i n A G ( r , 5 ) , Roma "La S a p i e n z a " n. 56 (1983).
Sem Geom.
Comb.
Univ.
r411 S. R a j o l a , Un esempio d i b l o c k i n g set i n PG(3,q) p e r o g n i q 2 5 , I n Proceedings.
these
c421 G. T a l l i n i , B l o c k i n g s e t s n e i sistemi d i S t e i n e r e d - b l o c k i n g P G ( r , q ) , Quaderno n. 3, Sem. Geom. Comb. 1st. Mat. Appl. Univ. (1983).
sets i n L'Aquila
45 1
Annals of Discrete Mathematics 37 (1988) 451-458 0 Elsevier Science Publishers B.V. (North-Holland)
SYMMETRIC DESIGNS WITHOUT OVALS AND EXTREMAL SELF-DUAL CODES
Vladimir D . Tonchev* I n s t i t u t e of Mathematics, S o f i a 1090, P. 0. Box 373, Bulgaria
ABSTRACT. Constructions of doubly-even s e l f - d u a l codes from symmetric d e s i g n s a r e discussed. I t i s shown t h a t t h e absence of o v a l s i n a design i s u s u a l l y necessary, and sometimes even s u f f i c i e n t c o n d i t i o n f o r t h e corresponding code t o be extremal.
1. INTRODUCTION The terminology and n o t a t i o n s from design and coding theory used i n t h i s paper a r e i n accordance with those from [ 3 A binary
t o r space V
1,
[ 5 1, and L8] r e s p e c t i v e l y .
(n,k) code C is a k-dimensional subspace of t h e n-dimensional vec-
1
Over GF(2). Given an ( n , k ) code C , t h e (n,n-k) code C
= {xeVn:
yx = 0 f o r each F C ) i s c a l l e d t h e orthogonal, o r dual of C. A matrix with t h e p r o p e r t y t h a t t h e l i n e a r span of i t s rows g e n e r a t e s t h e code C , i s a g e n e r a t o r
1 m a t r i x of C. The g e n e r a t o r m a t r i c e s of t h e d u a l code C a r e c a l l e d p a r i t y check matrices of C. We s h a l l o f t e n r e f f e r t o t h e elements of a code a s codewords, o r words only. The weight of a codeword i s t h e number of i t s nonzero p o s i t i o n s , and t h e minimum weight of a code i s t h e weight of a l i g h t e s t nonzero codeword. An
( n , k , d ) code i s an ( n , k ) code with minimum weight d. A code C i s self-orthogonal
(resp. self-dual)
i f CCC'
(resp. C =
2 ) . The
weights of a l l words i n a s e l f - o r t h o g o n a l code a r e even. I f i n a d d i t i o n a l l weights a r e d i v i s i b l e by 4 , t h e code i s c a l l e d doubly-even. d u a l ( n , n / 2 ) code e x i s t s i f and only if n
=
0 (mod
a),
A doubly-even
self-
and t h e minimum weight
d of such a code i s bounded by
(1)
d S 4[ 11/24] + 4 , (cf.
[a]).
A code s a t i s f y i n g t h e e q u a l i t y i n (1) is c a l l e d extremal. The code-
words of minimum weight i n an extremal doubly-even s e l f - d u a l code y i e l d o r 5-design provided t h a t
I-, 3-,
n 5 16, 8 , o r 0 (mod 2 4 ) .
The number of extremal codes i s f i n i t e ( b u t unknown), t h e s m a l l e s t open c a s e being f o r n = 7 2 . The following theorem d e s c r i b e s a c o n s t r u c t i o n of doubly-even s e l f - d u a l
CO-
d e s from symmetric d e s i g n s . THEOREM 1.1. Let A be an incidence matrix of a symmetric 2-(v,k,k)
of an odd o r d e r k-A.
Then
( i )If k E 3 (mod 4 ) , t h e code generated by t h e matrix
*Research p a r t i a l l y supported by t h e
cscMBunder
contract
37/1987-
design
V.D. Tonchev
452
i s a doubly-even s e l f - d u a l
(2v,v) code.
(ii) I f k Z 2 (mod 4 ) , then t h e code generated by t h e matrix
(3)
i s a doubly-even s e l f - d u a l
(2v+2, v + l ) code.
This statement i s a v a r i a n t of a m r e g e n e r a l c o n s t r u c t i o n ( c f . [ 21
,[
4) )
.
I n t h i s paper we a r e i n t e r e s t e d i n necessary and s u f f i c i e n t c o n d i t i o n s f o r a code c o n s t r u c t e d i n t h i s way t o be extremal.
In o t h e r words, what combinato-
r i a l p r o p e r t i e s should a design possess i n o r d e r t o produce an extremal code? A notion p l a y i n g an important r o l e i n t h e study of symmetric d e s i g n s , espe-
c i a l l y p r o j e c t i v e p l a n e s and b i p l a n e s , is t h a t of "arc" o r "oval". An a r c i n a design i s a s u b s e t S of p o i n t s such t h a t each block i n t e r s e c t s S i n a t most 2 p o i n t s . The c a r d i n a l i t y of an a r c S i n a n o n t r i v i a l symmetric 2-(v,k,h)
design
of an odd o r d e r k-h i s bounded by
IS/ S (k+h-l)/h.
(4)
An a r c with maximum number of p o i n t s i n t h e sense of bound
( 4 ) i s c a l l e d an
oval [ 2 ] . I t w i l l be seen by t h e next e x p o s i t i o n t h a t t h e absence of o v a l s i n a sym-
m e t r i c design i s u s u a l l y necessary, and sometimes even s u f f i c i e n t c o n d i t i o n f o r t h e corresponding s e l f - d u a l code t o be extremal. 2 . ARCS AND CODES
Let D be a symmetric 2-(v,k,h) Denoting by ni
design with an a r c S of s i z e s , i . e .
IS/ =s.
( i = 0,1,2) t h e number of blocks having e x a c t l y i common p o i n t s
w i t h S , w e have:
no
+
nl
+
*2 =
vt
Consider t h e code with g e n e r a t o r matrix ( 2 ) defined by D . C l e a r l y , t h e weight of t h e sum (over GF(2)) of s rows of t h e g e n e r a t o r matrix ( 2 ) indexed by t h e p o i n t s of an a r c of s i z e s i s s + n l = s(k+l)-(s-l)A). S i m i l a r l y , t h e sum of s
r o w s of t h e matrix ( 3 ) , indexed by t h e p o i n t s of an a r c of s i z e s has weight
n+ 1 s+nl+(l+(-l) ) /2
=
s ( k + l - ( s - l ) h ) + (1+(-1)'+l) / 2 .
Thus we have t h e following THEOREM
2.1.
Let D be a symmetric 2-(v,k,h)
design s a t i s f y i n g t h e assump-
453
Symmetric Designs without Ovals
t i o n of Theorem 1.1, and admitting an a r c S of s i z e s . Then t h e minimum weight of t h e code d e f i n e d by D a s i n Theorem 1.1 i s bounded a s follows: s ( k + l - ( s - l ) h i n c a s e (i); d S {
s (k+l- (s-1)h ) + ( l + ( - l'+') )
(6)
/2 i n case (ii).
I t t u r n s o u t t h a t i f t h e a r c S i n an o v a l , t h e i n e q u a l i t i e s (6) a r e o f t e n
s h a r p e r than ( 1 ) . Thus a code a r i s i n g from a design with o v a l s i s u s u a l l y n o t extremal. We s h a l l i l l u s t r a t e t h i s by some examples. In Table 1 t h e parameters of symmetric 2-(v,k,A)
d e s i g n s with k - h S 9 ,
y i e l d i n g doubly-even codes by t h e c o n s t r u c t i o n of Theorem 1.1. a r e l i s t e d . TABLE 1 NO.
k-h
1
1
k
v 3
h
2
1
Codes Extended Hamming ( 8 , 4 , 4 ) code; extremal.
2
3
3
Extended Golay (24,12,8) code; extremal.
3
5
19
10
5
Three extremal (40,20,8) codes.
4
7
31
10
3
Extremal (64,32,12) code from any design without o v a l s (Theorem 2 . 5 ) .
5
7
27
14
7
An extremal
6
9
35
18
9
7
9
36
15
6
8
9
40
27
18
1
1
6
Parameters N o . 2-(4t-l,2t,t). 2t-1.t-1))
(56,28,12) code from t h e q u a d r a t i c r e s i d u e design.
Is t h e r e any extremal (72,36,16) code? ( 8 0 , 4 0 , d > l 2 ) code from any design without ovals.
A
1 , 2 , 3 , 5 , 6 i n Table 1 a r e of Hadamard t y p e , i . e .
The s i z e of an o v a l i n a Hadamard 2 - ( 4 t - l , 2 t , t )
design i s 3 , t h u s t h e bound from Theorem 2.1 f o r t h e minimum weigth
of a code of type (ii) i s 4. However, a Hadamard 2 - ( 4 t - l , 2 t , t ) t
of t h e form
( o r 2-(4t-1,
design with odd
> 1 does n o t admit any o v a l s ; t h i s follows from a r e s u l t of Morgan [ 9 1 , and
can be a l s o e a s i l y seen d i r e c t l y . For, i f a 2 - ( 4 t - l , 2 t , t )
design p o s s e s s e s an
a r c of s i z e 3, then t h e sum of t h r e e rows of i t s incidence matrix A indexed by t h e p o i n t s of t h e a r c , as w e l l as t h e sum of a l l remaining rows over GF(2) is t h e z e r o v e c t o r . Consequently, t h e rank of t h e incidence matrix over GF(2) must be l e s s o r equal t o 4t-3. (I,J-A),
where J.denotes
On t h e o t h e r hand, s i n c e t i s odd, t h e matrix
t h e a l l - o n e m a t r i x , g e n e r a t e s a s e l f - d u a l code. Thus
t h e rank of J-A over G F ( 2 ) i s 4t-1, whence t h e rank of A i s 4t-2,
a contradic-
t ion. Estimating t h e weight of a sum of a t most 4 rows of a matrix of t h e form ( 3 ) , where A i s an incidence matrix of a Hadamard 2 - ( 4 t - l , 2 t , t )
odd t , say t = 2 m + l , THEOREM 2 . 2 .
design with
t h e following can be proved:
[13
1.
The minimum weight of a (16m+8,8m+4) code with genera-
V.D. Torichav
454
t o r m a t r i x ( 3 ) d e f i n e d by a Hadamard 2-(8m+3,4m+2,2m+l) d e s i g n i s e q u a l t o 4 if m=O,
and i s a t l e a s t 8 i f m
> 0.
In f a c t , t h e codes d e r i v e d from Hadamard 2-(8m+3,4m+2,2m+l) d e s i g n s f o r
m S 2 a r e a l l e x t r e m a l . I t i s worth n o t i n g t h a t Hadamard 2 - ( 4 t - l , 2 t , t ) d e s i g n s which a r e e x t e n d a b l e i n t o isomorphic Hadamard 3 - ( 4 t , 2 t , t - l )
designs, y i e l d
e q u i v a l e n t codes. For i n s t a n c e , t h e r e e x i s t e x a c t l y 6 nonisomorphic 2 - ( 1 9 , 1 0 , 5 ) d e s i g n s and 3 nonisomorphic 3 - ( 2 0 , 1 0 , 4 ) d e s i g n s , producing 3 i n e q u i v a l e n t extremal (40,20,8) codes [ 1 3 ) . The absence of o v a l s i n a 2-(8m+3,4m+2,2m+l) design with m > 2 i s n o t a s u f f i c i e n t c o n d i t i o n f o r t h e e x t r e m a l i t y of t h e r e l a t e d code.
In t h i s case
some a d d i t i o n a l c o n d i t i o n s are t o be f u l f i l e d , i n c l u d i n g t h e absence of o v a l s i n t h e complementary 2-(8m+3,4m+1,2m) d e s i g n a s w e l l . THEOREM 2.3.
[ 1 3 1 . 3 n e c e s s a r y c o n d i t i o n f o r an (16+8,8m+4) code d e f i n e d
by a Hadamard 2-(8m+3,4m+2,2m+l) d e s i g n D t o have minimum weight d 2 12 i s any t r i p l e of pOints of D t o be c o n t a i n e d i n a t l e a s t 2 b l o c k s , and a t most 2m-1 b l o c k s of D .
-
Formulated f o r t h e complementary 2-(8m+3,4m+2,2m) design D , t h i s c o n d i t i o n s t a t e s t h a t each t r i p l e of p o i n t s must occur i n a t most 2m-2 l e a s t one block of
D.
In particular,
-
b l o c k s , and a t
D cannot have gny o v a l s .
The enumeration of a l l 2-(27,14,7)
ciesigns up t o isomorphism i s n o t y e t
completed. However, t h e only primes which can d i v i d e t h e o r d e r of t h e automorphism group of a Hadamard m a t r i x of o r d e r 28 a r e 13, 7 , 3 and 2 , and t h e m a t r i c e s p o s s e s s i n g automorphisms of o r d e r 13 o r 7 a r e a l r e a d y known [ 1 4 ] , [ 1 5 ] . Among t h e d e s i g n s a r i s i n g from Hadamard m a t r i c e s of o r d e r 28 w i t h automorphisms
of o r d e r 13 o r 7 , only t h o s e r e l a t e d t o t h e Hadamard m a t r i x of q u a d r a t i c r e s i due type y i e l d an extremal (56,28,12) code. Any 2 - ( 3 5 , 1 8 , 9 ) d e s i g n d e f i n e s a doubly-even
(72,36) code with minimum
weight d 2 8. Although t h e e x i s t e n c e of an extremal (72,36,16) code i s s t i l l i n doubt, i t i s known t h a t such a code cannot be o b t a i n e d from a 2 - ( 3 5 , 1 8 , 9 ) des i g n w i t h an automorphism of o r d e r 17 [ 1 6 ] . More g e n e r a l l y , such a code cannot p o s s e s s automorphisms of o r d e r 17 or any l a r g e r prime o r d e r 161, 1111, 1121. Another approach f o r c o n s t r u c t i o n of doubly-even of symmetric 2-(36,15,6)
d e s i g n s ( s e e Theorem 1 . 1 ,
(72,36) codes i s by means
( i ) ) In . t h i s c a s e Theorem
2.1 g i v e s t h e f o l l o w i n g r e s u l t : THEOREM 2.4.
A necessary condition f o r a 2-(36,15,6)
design t o y i e l d a
( 7 2 , 3 6 , d 2 1 2 ) code i s t h e absence of any a r c s of s i z e 3 . The n e x t theorem i s an example of a better-behaved
THEOREM 2.5. A doubly-even s e l f - d u a l
situation.
(64,32) code d e f i n e d by a 2 - ( 3 1 , 1 0 , 3 )
d e s i g n D i s e x t r e m a l ( i . e . has minimum weight 12) i f and only i f D does n o t p o s s e s s any o v a l s . Proof. The f i r s t row of t h e g e n e r a t o r m a t r i x ( 3 1 , where A i s now an i n c i -
S.ririitzetric Dcsigrrs without Ovals
455
d e s i g n D , h a s w e i g h t 32, w h i l e a l l re-
dence m a t r i x of a symmetric 2 - ( 3 1 , 1 0 , 3 )
maining rows a r e of weight. 12. The w e i g h t o f a sum of t w o rows of ( 3 ) i s 24 p r o v i d e d t h a t one of t h e rows i s t h e f i r s t row of
( 3 ) , or 16 i f b o t h rows are
o t h e r t h a n t h e f i r s t row of ( 3 ) . The sum of 3 r o w s of
(3) including t h e f i r s t
row i s 20. C o n s i d e r now t h e s u m of a t r i p l e of rows n o t i n c l u d i n g t h e f i r s t
row. L e t n . d e n o t e t h e number of b l o c k s c o n t a i n i n g e x a c t l y i p o i n t s of t h e t r i p l e of p o i . n t s o f D c o r r e s p o n d i n g t o t h e choosen t r i p l e of rows. W e have:
no + n l +
n2 +
n3
=
31,
n l + 2n2 + 3n3
=
3.10,
n2 + 3n3 = 3.3. T h i s system h a s t h e f o l l o w i n g s o l u t i o n s :
no
nl
10
n2
n3 0
12
9
9 1 5
6
1
8 1 8
3
2
7 2 1
0
3
E v i d e n t l y , t h e w e i g h t o f t h e sum o f t h e c o n s i d e r e d t r i p l e o f r o w s i s 4 + n l + n 3 2 16. F u r t h e r m o r e , t h e w e i g h t of a sum of 4 rows of
(3) including t h e f i r s t r o w
i s 4+n +n +1 2 12. 0 2 Now w e e s t i m a t e t h e w e i g h t of t h e sum of a q u a d r u p l e of rows of ( 3 ) n o t i n c l u d i n g t h e f i r s t row. Denoting by n , ( 0 S i S 4 ) t h e number of b l o c k s of D c o n t a i n i n g e x a c t l y i p o i n t s from t h e q u a d r u p l e of p o i n t s c o r r e s p o n d i n g t o t h e choosen q u a d r u p l e of rows, one h a s : no + n l + n
1
n2 +
n3 +
+ 2n2 + 3n
n4 = 31,
+ 4n
= 4.10, 3 4 n 2 + 3n3 + 6n4 = 6 . 3 ,
= 3n + 8n4 + 4 . 3 The w e i g h t of t h e c o n s i d e r e d sum i s 4+n +n = 8+4n +en4. By o u r a s s u m p t i o n 1 3 3 D d o e s n o t p o s s e s s any o v a l s , hence n +n > 0 , and c o n s e q u e n t l y t h e w e i g h t of
whence n l
t h e sum of f o u r rows i s a t l e a s t 12. Thus t h e w e i g h t of any l i n e a r c o m b i n a t i o n of a t m o s t 4 rows of t h e g e n e r a -
tor m a t r i x ( 3 ) is a t l e a s t 12. A
symmetric d e s i g n of an odd o r d e r k-X c o n t a i n s a n o v a l if a n d o n l y i f t h e
d u a l d e s i g n c o n t a i n s an o v a l ( 2 1 . The f o l l o w i n g m a t r i x
1 At
1 01...1
I
(7)
V.D. Tonchev
456
i s a p a r i t y check matrix of t h e code generated by ( 3 ) , and s i n c e t h e code is s e l f - d u a l , t h e matrix ( 7 ) is a l s o a generator matrix of t h e same code. Since t . is an incidence matrix of t h e d u a l design of D , we can apply t h e same argu-
A
ments f o r t h e weight of t h e sum of a t most 4 rows of ( 7 ) . Since a codeword of weight 8 o r less must be sum of a t most 4 rows of one of t h e matrices ( 3 ) o r
( 7 1 , t h i s completes t h e proof. The 2-(31,10,3)
design l i s t e d i n H a l l book ( 7 1 possesses o v a l s . Since t h e r e
a r e no c y c l i c d i f f e r e n c e - s e t s with parameters ( 3 1 , 1 0 , 3 ) , it can be e a s i l y seen by use a r e s u l t of Aschbacher [ l ] t h a t t h e g r e a t e s t prime which can be an o r d e r of an automorphism of a 2-(31,10,3) design i s 7. We enumerated a l l such designs f i n d i n g e x a c t l y 4 nonisomorphic s o l u t i o n s , one of them being without o v a l s [17]
-
A s s u m e t h a t an automorphism 5 of o r d e r 7 a c t s on t h e p o i n t s and blocks a s follows :
B = (1,2
,...,7 ) ( 8 , 9 ,...,14) (15,16 ,..., 21) (22,23 ,...,28) (29) (30)( 3 1 ) .
Then a 2-(31,10,3)
design without o v a l s i s defined by t h e following base
blocks : B1 = (1,8,13,14,15,18,21,22,25,27),
B22 = (1,4,6,10,14,19,20,22,28,31) I
B8 = (1,6,7,8,11,16,18,24,28,29), B15
= (1,4,7,9,11,15,20,26,27,30),
B29 = (8,9,10,11,12,13,14,29,30,31), B30 = (15,16,17,18,19,20,21,29,30,31), B g l = (22,23,24,25,26,27,28,29,30,31).
The f u l l automorphism group of t h i s design i s of o r d e r 42. We do n o t know whether
t h e code obtained from t h e above design is e q u i v a l e n t t o t h e extremal (64,
32) code c o n s t r u c t e d by Pasquier 1101. F i n a l l y , l e t us consider t h e parameters 2-(40,27,18).
By arguments s i m i l a r
t o those from t h e proof of t h e preceding theorem t h e following p r o p o s i t i o n can be proved. THEOREM 2.6.
The minimum weight d of a doubly-even
(80,401
code obtained
from a 2-(40,27,18) design D i s 8 i f and only i f t h e complementary 2-(40,13,4) design D p o s s e s s e s an oval. Otherwise, d 2 1 2 . L e t us remark t h a t f o r e x t r e m a l i t y one needs d = 16. As a f i r s t c a n d i d a t e ,
w e checked t h e complement of t h e 2-(40,13,4) design formed by t h e hyperplanes i n PG(3,3). However, it t u r n s o u t t h a t t h e r e s u l t i n g code has minimum weight d = 12.
REFERENCES [ l ] M. Aschbacher, On c o l l i n e a t i o n groups of symmetric block d e s i g n s , J. Combin. Theory, A 11 (19711, 272-281. [ 2 1 E.F. Assmus, J r . , and J . H . van L i n t , Ovals i n p r o j e c t i v e d e s i g n s , J . Combin. Theory, A 27 (19791, 307-324. 31 Th. Beth, D. Jungnickel, H. Lenz, "Design Theory", B.I. Wissenschaftsverlag,
Symmetric Designs without Ovals
457
Ztirich 1 9 8 5 . Bhargava, J . M . S t e i n , ( v , k , h ) c o n f i g u r a t i o n s and s e l f - d u a l codes, Information and C o n t r o l , 28 ( 1 9 7 5 ) , 352-355. P . J . Cameron and J . H . van L i n t , "Graphs, Codes and Designs", London Math. SOC. L e c t u r e Note Ser. 4 3 , Cambridge U n i v e s s i t y P r e s s , Cambridge 1 9 8 0 . J . H . Conway, V . P l e s s , On primes d i v i d i n g t h e group o r d e r of a doubly-even ( 7 2 , 3 6 , 1 6 ) code and t h e group o r d e r of a q u a t e r n a r y ( 2 4 , 1 2 , 1 0 ) code, D i s c r e t e Math. 38 ( 1 9 8 2 ) , 143-156. M. H a l l , Jr., "Combinatorial Theory", Ginn ( b l a i s d e l l ) , Boston 1967. F.J. MacWilliams and N . J . A . Sloane, "The Theory of E r r o r - C o r r e c t i n g Codes", Noth-Holland, Amsterdam 1 9 7 7 . E . J . Morgan, Arcs i n block d e s i g n s , A r s Combinatoria 4 ( 1 9 7 7 ) , 3-16. G. P a s q u i e r , A b i n a r y extremal doubly even s e l f - d u a l code ( 6 4 , 3 2 , 1 2 ) obt a i n e d from an extended Reed-Solomon code over F 1 6 , IEEE T r a n s , Inform. Theory, 27 ( 1 9 8 1 ) , 807-808. V . P l e s s , 2 3 does n o t d i v i d e t h e o r d e r of t h e group of a ( 7 2 , 3 6 , 1 6 ) doubly even code, IEEE T r a n s . Inform. Theory, 2 8 ( 1 9 8 2 ) , 113-117. V. P l e s s , J . G . Thompson, 17 does n o t d i v i d e t h e o r d e r of t h e group of a ( 7 2 , 3 6 , 1 6 ) doubly even code, IEEE T r a n s , Inform. Theory, 28 ( 1 9 8 2 ) , 537-
[ 41 V.K.
i
51
1
61
1
91 [lo1
[ll] [ 121
541. V.D. Tonchev, Block d e s i g n s of Hadamard t y p e and s e l f - d u a l codes, Problemi p e r e d a t c h i i n f o r m a t s i i , 19 ( 1 9 8 3 ) , No. 4 , 25-30. V.D. Tonchev, Hadamard m a t r i c e s of o r d e r 2 8 w i t h automorphisms of o r d e r 1 3 , J . Combin. Theory, A 35 ( 1 9 8 3 ) , 4 3 - 5 7 . V.D. Tonchev, Hadamard m a t r i c e s of o r d e r 28 w i t h automorphisms of o r d e r 7 , J. Combin. Theory, A 40 ( 1 9 8 5 ) , 62-81. V . D . Tonchev, R.V. Raev, C y c l i c 2 - ( 1 7 , 8 , 7 ) d e s i g n s and r e l a t e d doubly-even codes, Compt. rend. Acad. bulg. S c i . , 35 ( 1 9 8 2 1 , 1367-1370. V.D. Tonchev, Symmetric 2 - ( 3 1 , 1 0 , 3 ) d e s i g n s with automorphisms of o r d e r 7 , Annals of D i s c r e t e Math. ( t o a p p e a r ) .
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Annals of Discrete Mathematics 37 (1988) 459-468 0 Elsevier Science Publishers B.V. (North-Holland)
459
GROUPS IN HYPERGROUPS Thomas VOUGIOUKLIS Democritus University of Thrace, 67100 Xanthi, Greece. We study the fundamental relation introduced by Koskas as the transitive closure of a basic relation in a given hypergroup. We use the quotient set, which is a group, in order to define a semi-direct hyperproduct of two hypergroups. We obtain an extension of hypergroups by hypergroups. Moreover we reveal some hypergroups in a given hypergroup. 1. INTRODUCTION
-
of The class of hypergroups in the sense of Marty [8] is the largest class multivalued systems that satisfies group-like axioms:
if we can find I1’.
. .,I
In H
the fudarnentai! equivaZcnce
relation
X~,X~,...,X,,-~, hi , hi ,....hi E H 1 2 H
finite sets of indices, such that
The fundamental relation introduced by Koskas in [7,p.167] was defined the transitive closure of the relation BH defined by setting
as
T. Vougiouklis
460
The fundamental r e l a t i o n
which i s a two-sided s t r o n g r e g u l a r r e l a t i o n ,
,B;
has been s t u d i e d i n s e v e r a l papers such as [ 3 ] , [ 51, 161 and many i n t e r e s t i n g r e s u l t s have been obtained. The most u s e f u l result remains that i s a group; t h a t i s why 6; i s c a l l e d t h e fundamental r e l a t i o n . W e HI84
-
H/Bi
shall call
fundumental
the
L e t us denote by
FH(x), x E H
c l a s s e s has t h e simple form
group
t h e elements
H.
of
H/Bi.
of
F H ( a )*FH(b)= FH(ab) = F H ( x ) ,
The product
of
Vx Eab, ( s e e [ 3 1 ) ,
i n s t e a d of t h e u s u a l form:
1
F H ( a ) * F H ( b ){FH(x) = xEa'b',
a'Bga,
b'Bib}
fulzdamentaZ property.
it i s c a l l e d t h e
An element x of H w i l l be c a l l e d a fundamental element w e have a b = {XI or FH(x)={x}; i.e f o r any a,bEH
iff x$ab.
If
H i s a group then a l l elements a r e fundamental; t h e r e f o r e i n t h i s case the H. The fundamental elements are t h e unique fundamental group c o i n c i d e s w i t h images of t h e same p a i r s f o r e v e r y fundamental map needed f o r t h e d e f i n i t i o n of a hypergroup a l g e b r a ; s e e [13]. A l l u n i t elements of
H,
i f they e x i s t
rp:H
H/BC
Remark 2 . 1
If
is called t h e h
nucleus
Let h relation
H
of
i s a subhypergroup of Fhfx)CFH(x),
H/Bi
belong t o t h e i d e n t i t y of
because i f , for example, e is a l e f t unit i n H F H ( e ) - F H ( x=) FH(ex)= F H ( x ) . The k e r n e l of and so
H
then the
x €ex, VxEH, canonical map
w
and denoted by
H'
then
VxEh.
be a subhypergroup of H; then we do not n e c e s s a r i l y have Example: I n [ 4 1 a g e n e r a l i z a t i o n of Ih/B;
I<
I.
the the
canonical hypergroups, t h e f e e b l y canonical hypergroups, have been introduced and proved t o be j o i n spaces [ll]. A n example of t h o s e i s t h e following one [ L I : Let G be an a b e l i a n group and S a s e t . One supposes that IGI>l
Y(s1,s2)ES
hypergroup.
2
,
PROPOSITION 1 Let
w e have
s1-s2=G.
IGI > 2
For
Then
be a hypergroup and
j E {l,.. ..s}.
becomes a
feebly
canonical
we o b t a i n
hl,...yhs,kl,...,ks€
Then, f o r every
clE hl.. .h
H
such and
clBic2.
proof It i s enough t o prove t h i s p r o p o s i t i o n f o r
h, = k , , j E {2,.
.. ,s).
that
c 2 € k l'. .ks'
Groups in Hypergroups
n
Therefore ( hlh2.
. hs ) u ( z
(zx-l h 2 . . .hs) U(klh2.. .hs)
so i f we choose
c
n
ixE
I
and
h2.. .h
pi
h
A
r E {l,.
y I' E z I'h2 . . .hs,
c l € h l h 2...h
..,
I ui h2. . . h s , . 1 1
h 2.. . h s ) C ilE
46 1
c2Eklh 2...h
.. ,?,-l}
o b t a i n t h a t for every
we
c16Ec2.
we have
P-hypergroups introduced i n [12] and g e n e r a l i z e d (G,.) and a i n [I&], [151. They a r e defined as follows. Given a group non-empty subset P of G then G becomes a hypergroup w i t h hyperP* such t h a t xP*y=xPy ; we denote t h i s by
L e t u s now consider t h e
THEOREM 1 Let Z be t h e c e n t e r of t h e group
Proof Let us denote by in
(G,-).
t h e r e exist
aB:b
1
a =x
*11 Then
...
1
n-1
then
2 G/Z.
t h e hyperproduct i n
xi,hi
n
i E I H
H-l.b
.II
and
t h e product
such t h a t
1
~ z ,~ ,,x ~ = bzx 1
G ;
-
a=bz xH-l,b
h H
1 H
.
...za , x l
Z
4
-
a=bz'-
a 5 bmod 2 .
A polygroup
[2]
i s a system A=<M,.,e,-'>
u n i t a r y o p e r a t i o n on M, .maps M2 x,y.z following axioms hold for all (x*y).z=x*(y.z) , x ~ y * z implies
where
eEM,
i n t o nonempty s u b s e t s of in M:
e*x=x=x.e y E x . 2 -1
,
and
-1
My
is and
a the
and z~y-lx.
In [l] an extension of polygroups by polygroups have been introduced i n t h e following way: that Suppose @ and g a r e polygroups whose elements have been renamed so AnB=Ce) where e i s t h e i d e n t i t y of both and g. A new system
46 2
T. Vougioukiis
% [ g =] <M,*,e,’>,
called the extension of
3,
% by
is formed in
the
following way: Set M = {xEA:x#e}U{xEB:x# e}u{e} and let el= e, I -1 x =x , e*x=x*e=x for all xEM, and for all x,yE{xE M:x#e} , x,yE A
if
x.yUA The extension
if
xEB, Y E A
if
xEA, ~
if
x , y ~ ~y#x-’ ,
if
x,yEB
E
B
-1 y=x
and
%[31 is a polygroup which preserves being chromatic.
THEOREM 2
Proof -1 -1 We have by definition: x*x = x - x uA belong to the fundamental class we have
bf3&[g,bl
”5;
iff
therefore all the elements of A Moreover f o r the elements of B
bl ;
that is because two elements of B can be contained only in the hyperproducts of elements of B. Therefore the extension has in the unit fundamental class all the elements of A and the other classes have exactly the elements of B/Bi
‘&[%?I
3.
THE FUNDAMENTAL HYPERGROUPS
DEFINITION 2 Let
aLib {a,z,} Then
.
be a hypergroup.
LEI
R i - fundamental
us denote by
Li(a)
[lo1
fundamental
such
x
of
H.
One
that
can a l s o
using right multiplication by a,
then
x.,Let
the hyperproduct
is given in the same way as in any
H/Li
relation
equivalence
i.e.
LE( a) *Li(b = {Li(c) The quotient
relation
the equivalence class of
in the quotient set relation
-
. . . , {~,,-~,b} C Xh,, .
,
{z1,z2}Cxh2
is an equivalence relation for every
define the
Li
zl,z2 ,...,~ ~ - ,h ~ , h ,h E H 1 2’”. n
if we can find C x h1’
We define the
H/Li
fundamental hypergroup
1
cea‘b’
where
a’Lia,
becomes a hypergroup which
of
H
we
shall
corresponding to the element
Remark 3 . 1 G(h)cFH(h),
b’Lib 1
Vx,hEH.
x.
call
the
Groups in Hypergroups
463
Remark 3.2 Given a reproductive generalized permutation
f:H
-
q(H),
uH
with
f(h)=H,
see
[13],
we obtain a similar definition as for the fundamental hypergroups by afb if we can find zl,...,zH-l, hl,...,hH€H such that
setting
)C {a,zljcf(hl) ,..., { Z ~ - ~ , ~ f(hH).
LX
- fundamental relations correspond to H generalized permutations of H. In this sense the
Remark 3.3 For every left scalar element
THEOREM 3 For every hypergroup
H
x
H
of
and every
x
2 (H/Lz)/%filL;
H/B:
we have of
H
the
inner
H/Li 2 H.
we have
.
Pro0 f We consider the mapping
s:H/BC >-
(H/Li)/BiiL;
We have for
:
hl,h2EH
FH(h)
c--3
and for every
FHlLx (L;(h)) H z Ehlh2
x s(FH(hl)-FH(h2))= s(FH(hlh2)) = s ( F ~ ( z ) ) = F ~ / ~(Li(z)). H On the other hand we have
From the first inclusion we obtain
but by remark 3.1 SO we can take
L; ( z , ) = L E we obtain similarly
ki L; kil 1
c1,c2
such that
(c2)CFH(c2). clbg c2
-
ki 5* k 1 il
LE (hl)=
.
$ (cl)CFH(cl)
and
From the construction of c1 and c2 and propositionl,
and
FH(~H-l)= FH(h2);
FH(cl) = FH(c2). so
Therefore FH(hl) = FH(zl)
FH(hl)=FH(h2)
and
which is a contradiction.
T. Vougiouklis
464
COROLLARY For every element
h
of a hypergroup
H
we have
4. THE SEMIDIRECT HYPERPRODUCT DEFINITION 3 Let A,B be hypergroups. We consider the group and the fundamental group B/f3; Let
.
":B/B;( >-
AutA:FB(b) >-
be a homomorphism.
Then in
(a,b)(al,bl) = {(x,y)
AxB
[16])
(see WALL
denote
FB (b) = i; A
we can define a hyperproduct as follows:
xEat(a 1) , yEbblj= (ac(al),bbl)
~
and we shall call this the
of
semidirect hyperproduct
the fundamental property we have for every x,y E B The semidirect hyperproduct is associative, since
=I
Aut A
J {(z,w) lzEa6(x),
A
and
x^y= G o $ =
that
B.
2,
From
siz Exy.
w~by}=
x E a1L1(a2) Y E blb2
={(z,w)
={(z,w)
I I
z
Eat(altl(a2)), A
w E b b 1b 2}={(z,w)lzEat(al)
A
A
b(bl(a2)),
wEbblb2j=
h
zEa6(al)bob 1(a2),wEbblb2}={(z,w)/zEat(al) $b 1(a2) , wEbblb2}.
It is also easy to see that the reproduction axiom is valid in AxB ; 'therefore AxB equipped with the semidirect hyperproduct becomes a group which we denote AQB.
hyper-
Remark 4.1 Using the fundamental group one can define the wreath product as well. Remark 4.2 In case that in
A
there exists an absolute unit element
ea
then
for
Groups in Hypergroups every eb
b
of
B
which
6(ea)=ea
i s any u n i t element of
B
465
we o b t a i n
{e }gBZB.
e e = eb ,
such t h a t
Similarly i f
Ac{e
then
This remark can b e a p p l i e d , f o r example, f o r r e v e r s i b l e hypergroups [lo], and polygroups [1,2]. n o n i c a l hypergroups Now l e t us consider i n
b = b 1.
( a , b ) d (al,bl) by
AxB
( A + b ) ={ ( a , b )
1 aEA}.
A
and
[ 9 ] , ca-
such t h a t
Let us denote t h e equivalence c l a s s of Then w e o b t a i n t h a t t h e map
i s a hyperisomorphism between t h e hypergroups Therefore we have t h e following. THEOREM 4 For every hypergroup
d
t h e equivalence r e l a t i o n
Z A.
b
B,
bEB
s:(A,b) -b
(AGB)/d
and
B.
B.
(A;B)/SLIZ
Remark 4.3 The above theorem allows us t o say t h a t group A by t h e hypergroup B. LEMMA 4 . 1 Let A,B
be hypergroups and
i s an extension of t h e
A h
a€A,
bEB;
hyper-
6 ( F A ( a ) )= F A ( $ ( & ) ) .
then
Proof Let
xE$(FA(a));
x=k(c).
i.e.
then t h e r e e x i s t s
c
in
6(c)
Conversely, l e t
(a).
x E FA(%( a ) )
Therefore
x€FA(k(a))
or
xBi$(a).
I f w e now apply t h e i n v e r s e autornorphism
so
f~-’(x)B;a
LEMMA 4.2 Let A,B
Pro0f W e have
or
6-l(x)€FA(a),
be hypergroups and
{(a,bf,(al,bl)} {a,al)Ch;
FA(&)
such t h a t
so
...h ’
C (hl,kl)
and
a,al€A,
...(hv,kv)
Then
of
$,
we o b t a i n
and t h e r e f o r e
b,blEB.
f o r some
{b,bl) C kl...kv
.
xE6(FA(a)).
Then hiEA,
f o r some
k.EB h i € A , ki€B.
-
T. Vougiouklis
466
(hl,kl).
.. (hv,kv)= (hl*f$(h2). ..klk2.. .kv-l(hv), kl.. . .
Therefore 11
<=
TI
" is clear. is also clear because for given
kV)
"
{a,a,)
h:
such that
C hi.. .h'
we can take the elements
iff
aB*a A
and
bB$bl
REFERENCES [l] Comer,S. , Extension of polygroups by polygroups and their representations Algebra using color schemes, Lecture notes in Math., no 1004, Universal and Lattice Theory, p.p. 91-103 (1984). [2) Comer,S., Polygroups Derived from Cogroups, Journal of Algebra, V . 8 9 , No 4, P.P. 397-405 (1984). [ 31 Corsini ,P. , Contributo alla teoria degli ipergruppi , Atti SOC. Pelor. Sc. Mat. Fis. Nat., Messina, (1980). [4] Corsini,P., Feebly Canonical and 1-Hypergroups, Acta Universitatis Carolinae - Mathematica et Physica, V. 24(2), p.p. 49-56 (1983). [5] De Salvo, M., Sugli ipergruppi completi finiti, Riv. Mat. Univ. Parma (4)8, P.P. 269-280 (1982). [6i De Salvo,M.-Freni , D . , Ipergruppi finitamente generati, Bolletino U.M.I.
(1984).
46 7
Groups in Hypergroups
[ 71 Koskas ,M., Groupoides, demi-hypergroupes et hypergroupes, J. Math. pures et appl., V. 49, p.p. 155-192 (1970).
[8i Marty,F., Sur une g&&alisation
de la notion de groupe, Huitisme congrss de mathgmaticiens Scandinaves, Stockholm, p.p. 45-49 (1934). [ 93 McMullen,J.R.-Price,J.F., Reversible hypergroups, Rendiconti del Seminark Matematico e Fisico di Milano, V.XLVII (1977), p . p . 67-85 (1979). [lo] Mittas,J., Hypergroupes canoniques, Mathematica Balkanica, V.2, p.p. 165-
179 (1972). [ll] Prenowitz,W.-Jantosciak,J., Join Geometries, U.T.M., Springer ( 1979) .
-
Verlag
[12] Vougiouklis,T., Cyclicity in a special class of hypergroups, Acta Univ. Carolinae Mathematica et Physica, V. 22(1), p.p. 3-6 (1981). [13] Vougiouklis ,T., Representations o f hypergroups. Hypergroup algebra, Proceedings in: Convegno su: Ipergruppi, altre strutture multivoche eloro appl. Udine (1985) p.p. 59-73. [14] Vougiouklis ,T., Generalization of P-Hypergroups , to appear in Rend. Circolo Mat. di Palermo. [IF] Vougiouklis ,T.-Konguetsof,L., P-Hypergroupes, to appear in Acta Univ. Carolinae Math. et Physica. [16] Wall,H., Hypergroups, American Journal of Mathematics, V. 59, p.p. 77-98
-
-
(1937).
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Annals of Discrete Mathematics 37 (1988) 469-478 0 Elsevier Science Publishers B.V. (North-Holland)
469
THE PERRON-FROBENIUS PROJECT ON I N THE THEORY OF GRAPHS, DIGRAPHS, DESIGNS AND STOCHASTIC PROCE SES K a r l E r i c h WOLFF Fachhochschule Darmstadt, F a c h b e r e i c h Mathematik und Naturwissens c h a f t e n , S c h o f f e r s t r . 3, D-6100 Darmstadt, FRG. Problem 5 i n " S p e c t r a o f graphs" by CVETKOVIC, DOOB, SACHS [2,p.266] says: " F i n d t h e r e l a t i o n between t h e t h e o r y o f Markov c h a i n s and t h e t h e o r y o f graph s p e c t r a . " We show t h a t t h e i n v e s t i g a t i o n o f s p e c t r a l p r o p e r t i e s o f graphs, d i g r a p h s , d e s i g n s and s t o c h a s t i c m a t r i c e s a r e r u l e d by t h e PERRONFROBENIUS p r o j e c t i o n and t h r e e m a t r i x r e p r e s e n t a t i o n s o f it, w h i c h y i e l d a common g e n e r a l i z a t i o n o f t h e HOFFMAN theorems f o r graphs [ 4 ] , d i r e c t e d graphs [ 5 ] and p o i n t s t a b l e d e s i g n s [ 9 ] as w e l l as t h e e r g o d i c theorem [ 3 ] f o r s t o c h a s t i c m a t r i c e s and t h e r a n k i n g procedure o f WE1 [ 8 ] and KENDALL [ 6 ] f o r tournaments.
1. THE PERRON-FROBENIUS PROJECTION I n t h e HOFFMAN theorems
[4,5,9],
i n t h e e r g o d i c theorem and i n t h e r a n k i n g
procedure o f WE1 [ 8 ] and KENDALL [ 6 ] t h e r e appears a n o n - n e g a t i v e
a and a p r o j e c t i o n m a t r i x
i t s PERRON-FROBENIUS e i g e n v a l u e
MP = aP = PM
P
n x n - m a t r i x M,
such t h a t
.
F o r a more g e n e r a l d e s c r i p t i o n o f t h i s s i t u a t i o n we need t h e f o l l o w i n g n o t a t i o n s : Let
(F),
denote t h e s e t o f
For
E specM
plicity of
nxn-matrices over a f i e l d
M E (F),
m a t r i x i n (F)n. For
let
we denote by
a. For
z
,
E F.
E Fn
a ( a ) t h e a l g e b r a i c , by let
d > :=
F , E
the identity
be t h e s e t o f e i g e n v a l u e s o f M.
speeM {
tz I
g(a) t h e geometric m u l t i -
t E F }.
Def in i t i on : Let
M E (F),
if
ker(M
(hence
ker(M
-
M
i s called
a-quasi-opthogonat
aE) n Im(M
-
aE) =
aE) IB Im(M
-
BE) =
{
5
,
}
Fn ) .
Lemma 1: Let
M E (F),
(0)
and
(0)
M
,
E specM.
Then f o r any
P
E (F),
the following conditions
(1) a r e e q u i v a l e n t :
is
a - q u a s i - o r t h o g o n a l and
P
i s the matrix o f the projection
o n t o ker(M - aE) a l o n g Im(M - aE), 2 (1) P = P , MP = aP = PM , r a n k ( P ) 2 g ( a ) . The p r o o f i s obvious.
If
( 1 ) h o l d s , we say: P
i s the (matrix of the)
(~,a)-projection.
470
K.E. Wolff
Lemma 2:
,
M E (F),
For
E specM
the following properties are equivalent:
,
a)
M
b) c)
a(.) = g(a) 9 ker(M - aE) = ker(M
d)
t h e r e e x i s t s a polynomial
is
a-quasi-orthogonal
-
aE)
minimal polynomial o f
2
, S(X) E F[X] and
M
4
S(a)
T h i s u n i q u e l y determined polynomial
such t h a t
S(X)
(X
-
a)S(X)
i s the
.
0
i s called the
IM,~l-poZynorniaZ
.
Proof: Let x(X)
,a
M E (F),
a ) ==> b ) :
M
of
,
E specM
Since
is
M
(2
f ( z ) := MZ
E Fn).
a-quasi-orthogonal,
satisfies
x(X) = (X
-
t h e c h a r a c t e r i s t i c polynomial
+6
s i n c e o t h e r w i s e t h e r e would e x i s t a v e c t o r E ker(M
- d) n
b ) ==> c ) : f/El,
where
xl(X)
= (X
Im(M
-
-
, hence x (X) a(.)
equivalent t o c). Clearly ker(M
-
(a)
+0,
a(.)
= g(a).
of the r e s t r i c t i o n
, satisfies
decomposes i n t o l i n e a r f a c t o r s . Therefore
= g ( a ) . Hence
c)
The main examples o f
-
= ker(M
-
aE) , which i s
+ {z}2 i s e q u i v a l e n t t o
aE)
aE) < ker(M
-
a-quasi-orthogonal
Any symmetric m a t r i x
El
i s equivalent t o d).
aE) n I m ( M
{ 6 } < ker(M -
Ex.1:
2
i s s i m i l a r t o a Jordan m a t r i x , and t h e r e f o r e s i m i l a r t o a
diagonal m a t r i x , s i n c e c ) ==> a ) :
x
aE). Then
x 1 (X)
i s t h e g e n e r a l i z e d eigenspace o f a
t h e m a t r i x of f l E l
i s the
such t h a t
aE), c o n t r a d i c t i n g a). Hence
C l e a r l y t h e c h a r a c t e r i s t i c polynomial El
-
f IIm(M
c h a r a c t e r i s t i c polynomial of t h e r e s t r i c t i o n
2
, where x,(X)
a)g(a)~,(X)
M
is
aE)
.
r e a l m a t r i c e s are:
a-quasi-orthogonal
Ex.2:
Any s t o c h a s t i c m a t r i x i s
Ex.3:
Any i r r e d u c i b l e non-negative m a t r i x i s
1-quasi-orthogonal
PERRON-FROBENIUS eigenvalue
a
(since
f o r any eigenvalue a o f M.
(cf.[2],2.6.d).
a-quasi-orthogonal = 1 = g(a),
a(.)
for i t s
cf.[71).
Definition: Let
M
be
a-quasi-orthogonal.
PE&?ON-F8OBENIUS
Then t h e (M,a)-projection
projection ofM , i f
M
i s c a l l e d the
i s non-negative and
a
i s the
PERRON-FROBENIUS eigenvalue o f M. 2. THE POLYNOMIAL REPRESENTATION OF THE (M,a)-PROJECTION THEOREM 1: Let Then
M E (F),
, a
E specM
P :=
8
,M
a-quasi-orthogonal
i s the
and
(M,a)-projection.
S(X) t h e ( M a ) - p o l y n o m i a l .
The Perron-Frobenius Projection
47 1
Main case:
If
S(X) =
-
(X
(e.g.
F = t ), then
for
A+a
AEspecM
AispecM Proof: Let
P = S(M)/S(a)
(3)
P? =
hence
2
.
From
2
for a l l
ker(M
-
(M
aE) 6 I m ( P ) .
Im(P) = Im(S(M)) s ker(M
-
P
i s the
aE)S(M) = 0
MP = aP = PM. C l e a r l y
we g e t
- aE),
On t h e o t h e r s i d e we o b t a i n from
(M
-
aE)S(M) = 0
aE), hence
( 4 ) Im(P) = ker(M - aE). From ( 4 ) and ( 3 ) we g e t Hence
-
E ker(M
P
2
and t h e r e f o r e
= P
(1) because o f
(4).
according t o Lemma 1.
(M,a)-projection
3. THE DYADIC REPRESENTATION OF THE (Mya)-PROJECTION
,
Let
M E (F),
R(a) L(a)
:= {
;E
:= {
2
a E specM
Fn
1
M2
=
E Fn IMTx' =
,
a; }
t h e righteigenspace o f a
ax'
the lefteigenspace o f
}
a
.
THEOREM 2: Let
M E (F),
,
Then t h e r e e x i s t such t h a t
R(a) =
E specM
and
a(.)
= 1.
f = (rl ,..., r n ) T , tf> , L ( a ) =
1=
(R1
,..., Rn) T
E
and f o r any such
Fn
,
FYI
i s t h e (M,a)-projection. Proof: Since Let
= 1
a(.)
P
we have
a ( a ) = g(a)
M
is
denote the m a t r i x o f t h e ( M y @ ) - p r o j e c t i o n . From
hence the columns o f
P
,...,
6 9
xT = l T P
,
(1) we have MP = aP,
R(a) = c h , s i n c e g(a) = 1. Hence n cn)T E F such t h a t P = ( r . c . ) = ? tT
.
1 J
dimL(a) = dimR(a) = 1. Hence from
0 f R . = xTc.F , hence 3 J t h e r e f o r e ( 5 ) holds.
a-quasi-orthogonal.
a r e elements o f
there e x i s t s a vector = (c Since PM = aP , t h e rows o f P obtain
hence
a r e elements o f L(a) = P2 = P
0
(by
,...
,
K.E. Wolff
472
P
4. WHEN I S
Let
Jn,l
A MULTIPLE OF
T ( 1 ,..., 1 )
:=
J
,
E Fn
?
J := J
I f i n t h e dyadic representation
(5)
( t h e all-one-matrix). 1 , then P = J
J
n , l ;,l = II = Jn,l
The f o l l o w i n g simple, b u t u s e f u l theorem answers t h e q u e s t i o n :
,
J ?"
a multiple of
i.e.
P E tJ> :=
{tJ
1
"
.
When i s
P
.
t E F}
THEOREM 3: M E (F), , a E specM, (M,a)- p r o j e c t i o n . Then
Let
M
a-quasi-orthogonal,
P
the matrix o f the
a)
P E
t ~ ~ , ~ , fao r~ some > a
E F"
iff
~ ( a = ) < J ~ , ~ ,>
b) c)
P E
?
E Fn
iff
L ( a ) = tJn,l>
- JnT1>
f o r some
P E <J>
iff
<Jn,l>
R(a) =
,
= L(a).
Proof: Since some
a E Fn
, then
, hence
rank(P) 2 1
s i n c e t h e columns o f
a
r a n k ( P ) = g ( a ) L 1. I f
i s the (M,a)-projection,
P
P
generate
r a n k ( P ) = 1 and
P E tJn,ld
-1 > f o r
R(a) = CJ,,~>
R ( a ) . F o r t h e converse t a k e
a E L(a)
, ,
and use Theorem 2. T h i s proves a ) .
f 5
b ) The rows o f
P
generate
L(a), since
PM = aP
and
rank(P) = g(a) = dimL(a).
Hence t h e " l e f t v e r s i o n " o f t h e p r o o f o f a ) shows b ) . c ) f o l l o w s f r o m a ) and b ) . 5. APPLICATION OF THE POLYNOMIAL AND D Y A D I C REPRESENTATION I n t h i s s e c t i o n we i n t r o d u c e t h e HOFFMAN e q u a t i o n f o r connected d e s i g n s and show how t h r e e well-known theorems o f HOFFMAN, HOFFMAN-McANDREW and t h e a u t h o r can be d e r i v e d e a s i l y f r o m o u r p r e v i o u s r e s u l t s . 5.1. The HOFFMAN e q u a t i o n o f a connected d e s i g n Let
D
d e n o t e a connected d e s i g n ( = i n c i d e n c e s t r u c t u r e ) ,
dence m a t r i x , N := AAT FROBENIUS e i g e n v a l u e o f (since
N
E (R),
i t s connection m a t r i x
N. Then t h e r i g h t e i g e n s p a c e
i s i r r e d u c i b l e , because
L ( a ) = R(a) =
th
f o r some
E
pv
and R(a)
A
its
a
t h e PERRON-
i s one-dimensional
D i s connected). From N
.
vxb-inci-
= NT
we have
Hence we o b t a i n f r o m Theorem 1 and
Theorem 2 t h e f o l l o w i n g HOFFMAN e q u a t i o n f o r connected d e s i g n s
XEspecN s i n c e b o t h s i d e s o f t h i s e q u a t i o n r e p r e s e n t t h e PERRON-FROBENIUS p r o j e c t i o n T N = N .
of
The Perron -Frobenius Projection
473
5.2. POINT STABLE DESIGNS From Theorem 3c) we o b t a i n COROLLARY 1: Let
N
denote t h e connection m a t r i x o f a design
N
N I U S eigenvalue. Then E
a-quasi-orthogonal
and
i t s PERRON-FROBE-
and t h e PERRON-FROBENIUS
P satisfies
projection
P
is
D
<J>
NJ = aJ
iff
and
D
i s connected.
Proof: Because o f t h e symmetry o f
N, N i s
Theorem 3c) i s e q u i v a l e n t t o connected i f f a(.)
=
a-quasi-orthogonal
"NJ=aJ
and
D
and t h e r i g h t s i d e o f
i s connected",
since
D
is
1.
The f o l l o w i n g d e f i n i t i o n was i n t r o d u c e d by t h e a u t h o r i n 191. Def in i t i o n A design w i t h connection m a t r i x f o r some
a
E
N
i s called
p o i n t stubZe
,
NJ = aJ
R.
The most i m p o r t a n t examples o f p o i n t s t a b l e designs a r e t h e the
if
(r,X)-designs,
I-designs and t h e r e f o r e a l s o t h e r e g u l a r graphs.
The d i r e c t g e n e r a l i z a t i o n o f t h e HOFFMAN theorem f o r connected r e g u l a r graphs t o connected p o i n t s t a b l e designs i s t h e f o l l o w i n g (cf.191) THEOREM 4: a) A design
D w i t h connection m a t r i x
t h e r e e x i s t s a polynomial
N
i s connected and p o i n t s t a b l e
f ( X ) E R[X] such t h a t
f(N) = J
iff
.
D i s connected and p o i n t s t a b l e , then t h e r e e x i s t s e x a c t l y one p o l y nomial h(X) o f minimal degree such t h a t h(N) = J ,
b) I f
namely t h e HOFFMAN polynomial
EspecN Remark: The HOFFMAN e q u a t i o n s p e c i a l case o f
h(N) = J
(6), where
of a connected p o i n t s t a b l e d e s i g n i s j u s t t h e = Jv,l
. Note
t h a t C o r o l l a r y 1 g i v e s a charac-
t e r i z a t i o n o f t h e connected p o i n t s t a b l e designs i n terms o f t h e PERRON-FROBEP = v- 1h(N). T h e r e f o r e we c a l l C o r o l l a r y 1 t h e " p r o j e c t i o n
NIUS p r o j e c t i o n
v e r s i o n " o f Theorem 4.
5.3. GRAPHS AND DIGRAPHS Now we g i v e t h e p r o j e c t i o n v e r s i o n s o f t h e HOFFMAN theorem f o r connected r e g u l a r graphs
[4] and o f t h e HOFFMAN-McANDREW theorem f o r s t r o n g l y connected
r e g u l a r digraphs [ 5 ] .
K.E. Wouj
474
__ COROLLARY ..__ 2: ( , p r o j e c t i o n v e r s i o r . o f t h e HOFFMAN theorem)
P
Let
eigenvalue. Then
F
G
denoce t h e adjacency m a t r i x o f a graph
A
is
AJ
=
and
d
i t s PERRON-FROBENIUS
d - q u a s i - o r t h o g o n a l and t h e PERRON-FROBENIUS p r o j e c t i o n
satisfies
P E <J>
iff
dJ
and
i s connected ( i . e . G i s r e g u l a r and connected).
G
The p r o o f i s t h e "same" a s t h e p r o o f o f C o r o l l a r y 1. COROLLARY 3: ( p r o j e c t i o n -_ ~-
A E (R),
Let
v e r s i o n of t h e HOFFMAN-McANDREW theorem)
denote t h e adjacency m a t r i x o f a d i g r a p h
G,
d
i t s PERRON-FRO-
BENIUS e i g e n v a l u e . Then t h e f o l l o w i n g c o n d i t i o n s a ) and b ) a r e e q u i v a l e n t :
A
a)
is
o f t h e PEKRON-FROBENIUS p r o -
P E d> ,
jection satisfies bl
P
d - q u a s i - o r t h o g o n a l and t h e m a t r i x
i s s t r o n g l y connected and r e g u l a r .
G
Proof.
7
G
, hence G i s r e g u l a r .
AJ = d J = A J
a ) ==> b ) : By Theorem 3 c ) we o b t a i n
a ( d ) = g ( d ) = r a n k ( P ) = 1 and
i s s t r o n g l y connected, s i n c e
AJ
=
T dJ = A J
(cf.[Z],p.lS,Th.0.4). b ) ==> a ) : S i n c e g(d)
G
i s s t r o n g l y connected, A i s i r r e d u c i b l e , hence a ( d ) = 1 =
by t h e PERRON-FROBENIUS theorem [ 7 ] ,
From t h e r e g u l a r i t y we o b t a i n R(d) If
<Jn,l>
=
G
= L(d),
since
,
A
is
d-quasi-orthogonal.
d , hence d
f o r some
, hence
g(d) = 1
i s a s t r o n g l y connected and
A E (R),
hence
AJ = a J = AT J
P E <J>
= d
and
by Theorem 3 c ) .
d - r e g u l a r d i g r a p h w i t h adjacency m a t r i x
t h e n we o b t a i n f r o m Theorem 1 and Theorem 2 t h e
HOFFMAN-McANDREW e q u a t i o n
where
i s the (A,d)-polynomial.
S(X)
6. THE LIMIT REPRESENTATION OF THE (M,a)-PROJECTION
The e r g o d i c theorem ( c f . [ 3 ] ) m a i n l y says t h a t t h e l i m i t matrix
S
i s a special dyadic m a t r i x o f the form ( 5 )
LigMk
More g e n e r a l l y we c o n s i d e r t h e l i m i t
for
$i!Sk
with
M E (t),
o f a stochastic = Jn,l.
and use t h e
f o l 1owing we1 1 -known Lemma 3:
M E (t)n
For any m a t r i x !A/ < 1
X
for all
the l i m i t
t specM\{lI
,llgMk and
M
exists i f f is
1-quasi-orthogonal.
THEOREM 5: Let P
M E (E)n i s the
.
If
P : = $',iMk
(M,a)-projection
e x i s t s , then (with
CY
=
1 )
or
P = 0
.
The Perron-Frobenius Projection
475
Proof: Let
k
P := J&M
f
P 2 = P , MP = P = PM
0. Then
E x a c t l y as i n [ 3 , p.17,371 Lemma 1 we o b t a i n t h a t
therefore
1 E specM.
one can p r o v e t h a t r a n k ( P ) = g ( 1 ) . Hence f r o m
P
i s the (M,1)-projection.
and Theorem 5
From Theorem 2
, and
we g e t
THEOREM 6:
.
M 6 (a),
Let
eigenvalue
1 of limM k-
BIMk
If
k
e x i s t s and t h e g e o m e t r i c m u l t i p l i c i t y o f t h e g(1)
=
1
,
then
7 IT
E '
=
where
0
satisfies
M
& ,
R(l) =
L(l) =
Remarks : (i)
S i n c e any s t o c h a s t i c m a t r i x
is
S
1-quasi-orthogonal,
we o b t a i n f r o m
t h e e r g o d i c theorem and Lemma 1 t h a t t h e PERRON-FROBENIUS p r o j e c t i o n of
F o r s t o c h a s t i c m a t r i c e s we o b t a i n f r o m
(ii)
P
satisfies
S
(8)
;. =
with
Jn,l
t h e main
s t a t e m e n t o f t h e e r g o d i c theorem. T h i s c e n t r a l p a r t o f t h e e r g o d i c theorem i s g e n e r a l i z e d by t h e f o l l o w i n g c o r o l l a r y . COROLLARY 4: Let
M E (E)n
, 1E
A E specM\{l}.
limM
k
J
spec#,
M
1 - q u a s i - o r t h o g o n a l and
1x1 <
a
aT
f o r some E En i f f MJ = J and a ( 1 ) = 1 n,l The p r o o f r e s u l t s f r o m Lemma 3 and Theorem 3 a ) .
k+m
=
1 for all
Then
.
F i n a l l y we m e n t i o n as a consequence of Theorem 1 and Theorem 5 a n o t h e r a l g e b r a i c k p o s s i b i l i t y t o c a l c u l a t e t h e l i m i t Jj&M . THEOREM 7: Let
M E (E)n
k
.
I f $j&M
S(M)
k
40
e x i s t s , then
-
( MI-h AE)
-
( n o t a t i o n s as i n ( 2 ) ) .
kspecM 7. THE PERRON-FROBENIUS PROJECTION I N THE RANKING PROCEDURE OF WE1 AND KENDALL For t h e c a l c u l a t i o n o f a "meaningful" ranking o f t h e p a r t i c i p a n t s o f a tournament f i r s t d e t e r m i n e (cf.[1,6,8]) o f t h e tournament d i g r a p h
t h e l i n e a r o r d e r o f t h e s t r o n g components
T. I n each s t r o n g component o f
p a r t i c i p a n t s i n t h e f o l l o w i n g way:
T
rank t h e
m (#)
K.E. Wolff
416
If If
m
, ,
= 3 m > 3
a l l t h r e e p a r t i c i p a n t s g e t t h e same r a n k . t h e n t h e adjacency m a t r i x A o f t h e g i v e n s t r o n g component
primitiv (cf.[ll).
a is t h e PERRON-FROBENIUS e i g e n v a l u e o f
If
A1 :=
C
is
A, t h e n f o r
aA
k
P := l i m A1 0 e x i s t s a c c o r d i n g t o Lemma 3, s i n c e / A ] < 1 f o r kX E specA1\{13 and a ( 1 ) = 1 = g ( 1 ) by t h e PERRON-FROBENIUS theorem
the l i m i t a1 1
F u r t h e r , f r o m Theorem 5
f o r p r i m i t i v e matrices (cf.[7]).
t h e PERRON-FROBENIUS p r o j e c t i o n o n t o t h e one-dimensional
-
ker(A1
E)
= ker(A
- aE).
follows that
P
is
kernel
Hence t h e r e e x i s t s e x a c t l y one p o s i t i v e v e c t o r
such t h a t
<&
= ker(A
-
aE)
is t a k e n as
This vector
t r i = l . i=1
and
"ranking vector":
j , if ri > r j ' The c o m b i n a t o r i a l meaning o f t h i s r a n k i n g procedure o f WE1 and KENDALL can be
i i s ranked h i g h e r t h a n p a r t i c i p a n t
Participant
e x p l a i n e d e a s i l y u s i n g Theorem 2: k ) . be t h e i - c o o r d i n a t e o f A Jm,l , hence ski is t h e m,l 1 number o f p a t h s o f l e n g t h k s t a r t i n g a t v e r t e x i ( i n t h e g i v e n s t r o n g Let
ski
: = (AkJ
C ) . Then
component
Proof:
lim
Clearly
k-
lT/(xTF)
P = S
lim
k-r-
'ki
a
ki
=
:m)il, = ( l i m AJ
,
(PJ, l)i
hence =
cri
= c':
PJml,
,
. According
= (PJm,l)i
k-
hence
,
where
(10)
Remark: The c o r r e s p o n d i n g r e s u l t o f WE1
c:=
t o Theorem 2
we have
> 0 . Therefore f T Jm , l /(IT;)
holds.
[81 f o r graphs ( c f . [ Z ] , p.104)
can be proved w i t h Theorem 2 i n t h e same way. ACKNOWLEDGEMENT I w i s h t o thank
A.W.M.
DRESS
( B i e l e f e l d ) f o r h i s v a l u a b l e comments on
quasi-orthogonal matrices. REFERENCES
[l]Bondy, J.A. and Murty, U.R.S., Graph t h e o r y w i t h a p p l i c a t i o n s (Amer. E l s e v i e r Publ. Co. , I n c . , New York, 1976) [ 2 ] CvetkoviE, D.M. and Doob, M. and Sachs, H., S p e c t r a o f graphs (Academic Press, New York, 1979) [33 F r i t z , F.J. and Huppert, B . and Willems, W., S t o c h a s t i s c h e M a t r i z e n ( S p r i n g e r Verlag, B e r l i n , 1979) [ 4 ] Hoffman, A.J., On t h e p o l y n o m i a l o f a graph, h e r . Math. Monthley 70 (1963) 30-36.
The Perron-Frobenius Projection
477
[51 Hoffman, A.J. and McAndrew, M.H., The polynomial o f a directed graph, Proc. Amer. Math. SOC. 16 (1965) 303-309. [61 Kendall, M.G., Further contributions to the theory of paired comparisons, Biometrics 11 (1955) 43-62. [71 Seneta, E., Non-negative matrices (George Allen and Unwin Ltd., London, 1973) [83 Wei, T.H., The algebraic foundations of ranking theory (Thesis, Cambridge, 1952) [91 Wolff, K.E., Punkt-stabile und s e m i - p a r t i a l - g e o m e t r i s c h e Inzidenzstrukturen Mitt. math. Sem. GieBen 121 (1976). [I01 Wolff, K.E., Punkt-stabile Inzidenzstrukturen und stochastische Matrizen in: Grabmeier, J. and Kerber, A., (eds.), Shinaire lotharingien de combinatoire (Publ. IRMA, Strasbourg, 1985) pp. 124-126. [ll] Wolff, K.E., Zur kombinatorischen Bedeutung der PERRON-FROBENIUS-Projektion in: Strehl, V . , (ed.), SGminaire lotharingien de combinatoire (Publ. IRMA, Strasbourg, 1986) pp. 153-162.
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Annals of Discrete Mathematics 37 (1988) 479-484 Elsevier Science Publishers B.V. (North-Holland)
479
ON THE NON-EXISTENCE OF CERTAIN DIFFERENCE SETS
N. Zagaglia S a l v i D i p a r t i m e n t o d i Matematica P o l i t e c n i c o d i Milano P.za L. d a V i n c i 3 2 , M i l a n o , I t a l y *
SUMMARY- I n t h i s p a p e r we d e t e r m i n e some p r o p e r t i e s c o n c e r n i n g a ( v , k , A ) - d i f f e r e n c e s e t when v i s even. I n p a r t i c u l a r i t i s proved i n c e r t a i n c a s e s t h e n o n - e x i s t e n c e of c i r c u l a n t Hadamard m a t r i c e s .
INTRODUCTION
Recall t h a t a subset
of Z
i s a (v,k,X)-difference
set if
\@I k =
and t h e
d i f f e r e n c e d.-d ( di,djem , d . # d . ) t a k e s each non-zero v a l u e i n Z A l j 1 J times. A m a t r i x i s c i r c u l a n t i f e a c h row d i f f e r i n g from t h e f i r s t i s d e r i v e d from i t s p r e v i o u s row by s h i f t i n g i t c y c l i c a l l y o n e p o s i t i o n t o t h e r i g h t . An Hadamard m a t r i x h a s e v e r y e n t r y 1 and i t s rows are o r t h o g o n a l t o each other. 2 It i s proved t h a t a c i r c u l a n t Hada a r d a t r i x b a s o r d e r 4N and c o r r e s p o n d s t o a d i f f e r e n c e s e t of p a r a m e t e r s (4N', 2N-' N , N - N). I t h a s been c o n j e c t u r e d t h e n o n - e x i s t e n c e of c i r c u l a n t Hadamard m a t r i c e s of o r d e r v > 4. Up t o now Turyn [6] proved t h e c o n j e c t u r e f o r N even; moreover i t i s proved f o r e v e r y odd N < 55. was a b l e t o p r o v e t h e n o n - e x i s t e n c e of symmetric c i r c u l a n t HadaB r u a l d i [3] mard m a t r i x . I n i t s p a p e r it w a s i m p l i c i t e l y proved t h e c o n j e c t u r e f o r r e f l e c t i v e c i r c u l a n t , where we c a l l a c i r c u l a n t ( 0 , l ) m a t r i x r e f l e c t i v e i f , a r ranged t h e e l e m e n t s of t h e f i r s t row r e g u l a r l y on a c i r c l e , t h e r e e x i s t s a d i a m e t e r of t h e c i r c l e w i t h r e s p e c t t o which 1 ' s a r e symmetric. I n t h i s p a p e r we d e t e r m i n e some p r o p e r t i e s c o n c e r n i n g a ( v , k , X ) - d i f f e r e n c e s e t , when v i s even. I n p a r t i c u l a r w e d e t e r m i n e i n c e r t a i n c a s e s t h e n o n - e x i s t e n c e of a 2 2 (4N2, 2N -N, N - N ) - d i f f e r e n c e s e t . F i n a l l y w e g i v e a c o n s t r u c t i o n of a s u b s e t of Z s a t i s f y i n g t h e p r o p e r t y of a d i f f e r e n c e s e t o n l y f o r odd v a l u e s .
1 . F i r s t w e d e t e r m i n e t h e f o l l o w i n g p r o p e r t y of a d i f f e r e n c e s e t . PROPOSITION 1 . 1
is even and or
-
Let 8
k-A= N
2
= {dl ,d2,.
. Then
. ., d d
be a (v,k,),)-
difference s e t where v
the number of the odd elements of
1
is Z(k + N)
i(k-N).
T h i s r e s e a r c h was s u p p o r t e d by t h e M i n i s t e r 0 d e l l a P u b b l i c a I s t r u z i o n e .
4 80
N. Zagaglia Salvi
Proof. Let r and s be the numbers of the even and odd elements of A s v i s even, the d i f f e r e n c e a = d . - d mod v , where d , d . e@ 1 j i J and only i f d i s even and d odd o r conversely.
i
@
,
. i s odd i f
j
Moreover i f a i s odd, a l s o -a i s odd. V So the number of odd d i f f e r e n c e s i s 2rs and i t has t o c o i n c i d e with 2 A. Then t h e parameters r , s s a t i s f y t h e r e l a t i o n s r+s = k and r s = v / 4 . 1 1 So we o b t a i n t h a t r = -(k + N) and s = -(k - N) o r conversely.<> 2 2 2 We n o t e t h a t i n the case of a (4N2, 2 N - N , N 2 7 N) - d i f f e r e n c e s e t we have t h a t t h e numbers of odd and even elements a r e N and N - N o r conversely.
2 . 1 - Let
2. DEFINITION
2
=k
c2
... cvJ
a sequence of v numbers
, with
v = hk. We s a i d g has period h i f t h e fikst h elements of g a r e repeated consecutively k times. I f h i s t h e minimum i n t e g e r t h a t s a t i s f i e s t h i s r e l a t i o n , we c a l l h real period.
-If L , 1 5 i 5 v , are the rows of a circuZunt mutrix
PROPOSITION 2 . 2
order v= hk, then the vector r -1
Proof. Denoted
1 5 i 5 k-1. If 5 =(a1 a 2 a1 .
=
-1r +-h+l r +. . +-(k-l)h+l r
= ~ l c 2 . . . c v ] , we have r -ih+l
... av]
c1 . + cv-h+i+
.
has period
i s the vector
...+ cv-(k-l)h+i,
=p
v-ih+l 'v-ih+Z..
... ah
.C?ih+v
]
'
' '
...= a l + ( k - l ) h and
2 5 j 5 h . Then the sequence a l a2
of
I - ~ + & + ~ + . . . + L - ( ~ - ~ ) ~ we + ~ ,have v'
So we o b t a i n a 1+rh = Cl+rh+cv-h+l+rh+"'+Cv - ( k - l ) h + l + r h , f o r 0 It follows a =a
C
h'
,
analogously, a j = a j + h =
is repeated k t i m e s and
0~
5 r 5 k-1.
...=
a
j + (k-I ) h '
has period h . < >
3 . Denoted y H a c i r c u l a n t Hadamard m a t r i x , we consider t h e ( 0 , l ) - c i r c u l a n t matrix K = - ( H + J ) , where J i s a l l one matrix. It is well t h a t the p o s i t i o n s of t h e e l y e n t ? 1 on f i r s t row of K determine a d i f f e r e n c e s e t of parameters (4N , 2 N + N , N 2 N). Since the d i f f e r e n t values of k and A correspond t o Fomplementary d i f f e r e n c e s e t s , t h e r e i s n o t l o s s of g e n e r a l i t y i n assuming t h a t (v,k,A)= 2 2 (4N2, 2% - N, N -N)
9 hewn
odd
tp
. even
We c a l l or an element of a sequence if i t i s i n odd o r even p o s i t i o n . Let C be t h e l i n e a r code over Z 2 generated by t h e rows of K. Let r .
-1'
1 5 i 6 v and r
-1
=El c 2 ... c v ] ,
Consider t h e word e = r +r +...+ r -1 -1 -3 Y-1By Prop. 2.1 has period 2. The f i r s t
el
be the rows of K.
Pecond]
element c o i n c i d e s with t h e
sum of elements of r i n odd P v e n J p o s i t i o n . -1 4s k i s odd, one number i s odd and t h e o t h e r even. So -1e is obtained by repeao r [OI] Suppose e = [ I O I O IOJ ting -1 Then t h e word = r +r +. . . + r coincides w i t h 0101 011 -2 -4 Y
001
e2
.
...
.
I: ...
.
On the Non-Existence of Certain Difference Sets
Ll
A s , by Prop. 2 . 1 ,
+
48 1
fl+v/2 = a has period 2N2, consider t h e p o s s i b i l i t y
t h a t a has r e a l period 2 , t h a t i s a = e - -1
or a = e - -2'
a = -1 e Without loss of g e n e r a l i t y , we can suppose REMARK 3.1 - The condition
rl + rl+v12
=
-le
-
conmdicts the existence of K.
Proof. A s detK = k(k-A) ( v - 1 ) / 2 5 1 mod 2 , t h e rows of K a r e l i n e a r l y independent i n Z is e f o r odd i and e The condigion f1 + v12 = e implies -i r + r -i + v / 2 -1 -2 -1 f o r even i. 1 ,C j g v / 2 , depent on rj, 1 6 j < v / 2 , and e2. So the rows r . -J + v / 2 ' Then t h e number of l i n e a r l y independent rows of K i s L V/2 + 2 , a contra-
.
rl+
el,
diction.
<>
= 1 f o r odd i and ci + ci+ v12 = o The c o n d i t i o n s = e implies c + c -1 i i+v/2 f o r even i. [even3 elements a t d i s t a n c e v / 2 a r e d i s t i n c t F o i n c i d e n t ] It follows odd
NL
.
So half of t h e odd elements a r e equal t o 1 , t h a t i s i s t h e number of c . = l f o r odd i. = 1. So t h i s element t h e c o n t r a r y , i f i i s even and c . = l , a l s o c . 1 + v/2 determines a d i f f e r e n c e equal t o v/2.
d
As t h e s e d i f f e r e n c e s a r e
A
= N
2
-
i t follows t h e number of t h e even e l e -
N,
ments equal t o 1 i s N2 - N.These numbers agree with those of Prop. 1 . 1 . However t h e following Theorem 3.5 proves t h i s s i t u a t i o n i s impossible. LEMMA 3.2 - Let
a
c4 c6
=
... c4q]
be, where c i E
Z2,
mod 2 , f o r 2 5 i & 4q. Moreover, l e t 8 = positions of 1 ' s i n a. mod bq, where d i , d . E @ Then every difference a= d.-d. 1 J J ber of times.
c i + ci+2q = -0
be the s e t of the
, occurs
an even n m -
0 mod 2 , we o b t a i n t h a t , i f Proof. From t h e condibion ci + ci+2 c d . = cdj = 1 , a l s o t h e elements cogresponding t o di' = di+2q and d 1
coincide t o 1 . Denoted a =d.-d
a l s o t h e d i f f e r e n c e di'- d ' c o i n c i d e s with j' j So every d i f f e r e n c e occurs an even number of t i m e s . <> 1
LEMMA 3.3 -
ci + c
Let
=
[c1c3c5.. .c4q-l]
be, where
q is odd, c . e
'
j~
=d.+2q
a mod 4q.
z2 and
~ 2 1+ mod~ 2 , ~1 L i $ 4q-1.
Moreover l e t @ =id d2...dk] be t h e s e t of the positions of 1's i n b. Then the number 4 occurs An odd nwnber of times as difference di-d. J where d G d3. t @ .
=kl
. ..
Proof. Let v=4q be, hl c5 c 9 cv-3] We n o t e t h a t d.-d. E 4 mod v , where d . , d j e 1
3
and h2 @ , if
=p3 c7
mod v , t h a t i s c d . = c d . = 1 a r e two a d j a c e n t elements i n -1 h As it i s c
to h
-1'
+
1
ci+
... o r -2 h -
c11 Cv-lI * d.+4 and only i f d . 1
J
J
v12s 1 mod
2 and q i s odd, i t follows t h a t , i f c . = l belongs
then c i+ v12 = 0 belongs t o h
-2
and conversely.
N. Zugugliu Sulvi
482
,
[1,1]
L e t r , s r e s p e c t i v e l y t h e numbers of o r d e r e d c o u p l e s i n hl. number of o r d e r e d c o u p l e s [l ,O] o r [O,lJ
I t i s c l e a r t h a t whenever t h e r e i s an o r d e r e d c o u p l e [ l , O ] an o r d e r e d c o u p l e LO,l]. So m i s even. Denote by r ' , s ' , m ' t h e analogous v a l u e s f o r -2' h We n o t e t h a t f o r every c o u p l e
ciJ
=
of
,l]
[O,OIof h2 [hi]
couple
[ c .l+4+v/2' ~ i + ~ / 2 J =
[O,Oj
,
and m t h e
t h e r e is a l s o
hl [h2]
there is the
.
S o r l = s and s l = r , w h i l e c l e a r l y i t i s m'=m. We n o t e t h a t t h e number of o r d e r e d c o u p l e s [ 1 , 1 ] , L O , O J , [l ,O] and [ O , l ] i n h c o i n c i d e s w i t h t h e number of elements of h t h a t i s r+s+m=q. -1 -1 ' i s r + r l = r+s Moreover t h e number of c o u p l e s c i ] =[1,1] of hl and -2 h
pi+4,
and t h i s number i s odd b e c a u s e q i s odd and m e v e n . L >
THEOREM 3.4 - L e t
v
=
4N
2
z n t h odd
p o s i t i o n s of
r
-1
1's i n r -1.
z1 s a t i s f i e s rl
Then, Lf
( O , l ) - r n a t r i x of order
be t h e J'irst roij of a c i r c u l a n t
N. Moreoiier, l e t m = i d l , d 2 ,
+
..., dk)
-,, where t h e s m
r-l+v12= e
Is
he t h e set of
mod 2 ,
I ; not
a difference set.
rl+v,2
at distance v/2 a r e = e , t h e n t h e odd e l e m e n t s of r Proof. If r + -1 -1 d i f f e r e n t , while t h e evenlelements coincide. Suppose Q i s a d i f f e r e n c e s e t w i t h t h e p a r a m e t e r s ( v , k , h ) . A s k(k-1) = (v-l)X , A is even. Denoted by D and P t h e s e t s of odd and even e l e m e n t s , w e n o t e t h a t a d i f f e rence a = di - d where d i , d . & @ , i s even i f and o n l y i f b o t h d i , d . b e l o n g j' 1 J t o D o r t o P. P , a o c c u r s an even number of t i m e s . By Lemma 3 . 2 , i f di,d j By Lemma 3 . 3 , i f d . , d . e D , we c a n n o t e t h a t t h e number 4 o c c u r s an odd number 1 J of t i m e s . So 4 o c c u r s a n odd number of t i m e s , w h i l e h i s e v e n . < >
4. I f 2 i s a ( 0 , l ) - s e q u e n c e
, we d e n o t e by -h a
t h e sequence o b t a i n e d by s h i f -
t i n g c y c l i c a l l y e v e r y element of h p o s i t i o n s t o t h e r i g h t .
THEOREM 4 . 1 - L e t
a b e a (0,l)-sequence of l e n g t h
the s e t of t h e p o s i t i o n s o f 5 satisfies a + 5iI2 =
in
1's i n
el, where
If
Z
occurs
v=4q and @ = [ d l , d 2 , . .
5. t k e sum is mod
h = k - q times as d i f f e r e n c e
2 , then e v e r y odd value
d . - d . , where d . , d . t 1 J 1 3
a.
P r o o f . L e t D and P be t h e s e t s of odd and even elements of As v i s e v e n , t h e d i f f e r e n c e d i - d . , where d i , d j 6 @ , i s odd i f and only J i f an i n t e g e r belongs t o D and t h e o t h e r t o P. Let
a =
~ l c 2 . . . c v ] be
.
.
On the Non-Existence of Certain Difference Sets If 5 + a
lr/2
=
e
the odd even]
-1'
483
elements of 5 at distance v/2 are different
.
[coincident)
This implies the odd elements are v/4
=
q and hence k
2
q.
Let c. be, where i is odd, an element of a. We have two possibilities: 1)
ci = 1
2)
ci = 0.
In the first case, let d. be an element of P; so also d J
Denoted c1 = i - d
we have also
c1' =
i
-
+ v/2 t P. i (d.+v/2) = a +v/2.
j' J = 1 , we obtain the differences = i+v/2 - d = In the second case, as c. l+V/2 j = c1 + v/2 and 6' = i+v/2 -(d + v/2) = a . j Hence, for every d. & P, we have the same differences in both of the cases. 1 J
and 2. Then, in order to calculate all the odd differences, we can suppose ci for every
odd i
e
,
[1,v/2]
that is
D =i1,3
=
1
,...,
Now, consider an element d; 6 P. J
We determine the differences
a. 1
=
d.
where i 6 D and also
1
-
a. + v/2
i =
(d. + v/2) J
-
i.
(2)
So for every d. t P, the differences ( 1 ) and ( 2 ) give every odd number in
[I ,v]
J
exactly once.
As there are also the differences -ai, - ( ai+v/2), that determine again every odd number of C1,vJ exactly once, we note that for every couple
d., d . + v/2 J
J
belonging to P, we obtain every odd number exactly twice. 1
As the couples d., d.+v/2 of P are -(k - q ) , we have proved that every odd J I 2 number in Z occurs exactly k - q times as difference di - d., where di,d. t J
0
J
.<>
REFERENCES
p]
Baumert, L.D., Cyclic Difference Sets, Lecture Notes in Mathematics n. 182 (Springer Verlag, 1971).
[2]
Biggs, N., Discrete Mathematics (Clarendon Press, 1985).
D]
Brualdi, R.A., A note
on
multipliers of difference sets, J. of Res. Nat.
B. of Standards, vol. 69 B ( 1 9 6 5 ) , pp. 87-89. Davis, P.J.,
61
Circulant matrices ( A Wiley-Interscience Publication, 1979).
Van Lint, J . H . ,
Coding Theory, Lecture Notes in Mathematics n.201
(Springer Verlag, 1971).
N . Zagaglia Salvi
484
[6]
Turyn, R., Character Sums and Difference
Sets, Pacific J. Math. 15 (1965)
pp. 319-346.
P]
Zagaglia Salvi, ti., Combinatorial structures corresponding to reflective circulant (O,l)-matrices, Annals of Discrete Mathematics 30 (1986), pp. 363-372.
Annals of Discrete Mathematics 37 (1988) 485-492 0 Elsevier Science Publishers B.V. (North-Holland)
ON COMPLETE 12-ARCS
485
I N PROJECTIVE PLANES OF ORDER 1 2
Corrado Zanella Dipartimento d i Matematica, UniversitB d i Roma "La Sapienza", 1-00185 Roma, I t a l y .
Let K be a complete 12-arc i n a p r o j e c t i v e plane 8 1 2 of Extending a r e s u l t i n [61 we show t h a t ~ 1 1 2has no point Moreover, there a r e a t most two p o i n t s of index 8. This i n v e s t i g a t e a l l p o s s i b l e c o n f i g u r a t i o n s of the tangents may occur e x a c t l y 1 7 c a s e s . 1. ON q-ARCS
IN
T
9'
order 12. of index 10. enables u s t o to K ; there
q EVEN
In a p r o j e c t i v e plane TI^ of even o r d e r q , l e t K be a q-arc, i . e . a s e t of q p o i n t s no t h r e e of which are c o l l i n e a r . On any p o i n t of K there a r e e x a c t l y two tangents. Thus K has e x a c t l y 2q tangents and q(q-1)/2 s e c a n t s . Furthermore, through any p o i n t o f nq there i s an even number of tangents. A p o i n t P E rq i s s a i d to be of index j , b r i e f l y a j - p d n t , i f t h e r e are e x a c t l y j tangents t o K through i t . L e t t j ( j = O , l , . . . , q ) be the number of j - p o i n t s i n TI^. Then t2h+l= = 0 f o r every h. Moreover [ 61 ,
Obviously, = 0 iff K i s complete. (1.2) q If TI i s Desarguesian, then K i s never complete [ 1 , 4 ] . In what follows, K i s 9 always supposed t o be complete; t h e r e f o r e , rq i s n o t Desarguesian. Whenever K i s incomplete, i t i s contained i n a (q+Z)-arc. Hence, i f TI c o n t a i n s no (q+2)a r c ( a s i t happens f o r q = 10, [ 21) then any q-arc i s c m p q e t e . Therefore
t
q > 10. Let
R
(1.3)
be a non-tangent l i n e and denote by u j the number of j - p o i n t s
412
1u
j=o
. 'J
on it. Then
412 =q+1,
1juZj =q.
j =O
I f t i s a tangent t o K , and v j i s the number o f j - p o
n t s on t, then
In [ 61 the following r e s u l t s a r e proved. I. Any conplete q-arc admits a t most one ( q - 2 ) p o i n t .
11. If t i s a tangent to K through a ( q - 2 ) p o i n t P then there e x i s t s a 4 p o i n t Q (PP) on t and any p o i n t on t , o t h e r than P m d Q , is of i n & x 2.CmseqwntZy
C. Zanella
486
t
q-2
=
1, t
> q-2,
t2
4 -
1. ( q - l ) ( q - 2 ) .
111. If t i s a tangent to K through a ( q - 4 ) p o i n t P , then e i t h e r a 6-point Q ( # P ) e x i s t s on t and m y o t h e r p o i n t on t i s of index 2, or t h e r e are two d i s t i n c t 4-points on t m d any o t h c r p o i n t on t is of index 2 .
I V . Assme K
is a
complete q-arc a d n i t t i n g a ( q - 2 ) p o i n i . P . %en,
Moreover, on m y tangent through P a 4-point l i e s , the remaining points being o f index 2; any tangent n o t un P &s (q-2)/2 4-points and ( q + 4 ) / 2 2-points. On any n m - t a n g e n t not on P there l i e v4 < 2 4-points and vo = l+v4 0-points. The r e m i n i n g p o i n t s have i n & x 2. V.
If a corrplete q-arc a h i t s a (q-Z)-point,
Therefore, the case q deal with it.
=
then q
=
12.
1 2 seems to be i n t e r e s t i n g . The aim o f t h i s n o t e i s t o
2 . ON COMPLETE 12-ARCS I N n12 V I . k t K be a complete 12-arc
Proof.
in n12. T?en t h e m is no l o p o i n t .
Suppose t h a t P i s a 1 0 - p o i n t . Then, by I V , t10 = 1,
t
t6 = t = O ,
8
0
=25,
t 2 =111,
t
4
=20.
Again by I V , on any of t h e t e n t a n g e n t s on P t h e r e i s e x a c t l y one 4-point, t h e remaining ones b e i n g 2 - p o i n t s . L e t r be t h e unique s e c a n t t h r o u g h P . From ( 1 . 4 ) , s i n c e ul0 = 1, u4 = uo - 5
(2.1)
f o l l o w s . Since u2 > 2 , we have ~0 + u4 < 10. T h i s , t o g e t h e r w i t h (2.1), g i v e s u4 5 2. On t h e o t h F r hand, t 4 = 20 and o n any t a n g e n t through P t h e r e i s exa c t l y one 4-point. T h e r e f o r e , on t h e remaining ( e x t e r n a l ) l i n e s t h r o u g h P t h e r e l i e a t l e a s t e i g h t 4 - p o i n t s . Thus, t h e r e i s a l i n e R on P which i s e x t e r n a l t o K and c o n t a i n s a t l e a s t f o u r 4 - p o i n t s , a c o n t r a d i c t i o n ( u s e ( 1 . 4 ) ) . 0 From V and V I i t f o l l o w s t h a t V I I . ."tocomplete q-arc i n
VIII.
nq, m y even q , admits a (q-Z)-point. 0
A corrphtte 12-arc K in n12 admits a t most tuo 8-points.
proof. Suppose A, B , C a r e t h r e e d i s t i n c t 8 - p o i n t s . F i r s t l y , assume t h a t A, B, and C a r e n o n - c o l l i n e a r . By 111, t h e l i n e s AB, AC, BC a r e non-tangents. Thus t h e 8 t a n g e n t s through C meet t h e l i n e AB i n 8 p o i n t s o t h e r than A and B.Hence, e a c h of them i s o f p o s i t i v e index. S i n c e U8 2 2, ( 1 . 4 ) ~i m p l i e s t h a t t h e r e a r e a t most f o u r p o i n t s d i s t i n c t from A and B, which a r e of p o s i t i v e i n d e x , a cont r a d i c t ion. Next, assume t h a t A, B, C l i e on the l i n e R. ( 1 . 4 ) h o l d ; hence, u =3, 8 Consider a p o i n t Q
Again
u = O for j # 0,8. (2.2) j AB o f i n d e x a t l e a s t 4 . Then t h e t a n g e n t s t h r o u g h Q meet
uo=lO,
4
By 111, R i s non-tangent.
On Complete 12-Arcs in Projective Planes of Order 12
487
AB i n f o u r d i s t i n c t p o i n t s of p o s i t i v e index. T h i s c o n t r a d i c t s ( 2 . 2 ) .
E l
L e t K be a complete l z - a r c , and suppose t 8 = 2. The l i n e j o i n i n g A w i t h B i s non-tangent (by 1 1 1 ) . From (1.1) we g e t t0=25-t6 , I X . I f t8 = 2 ,
then t
t 2 = 112+3t6
, t4
=
18-3t6,
t 8 = 2.
(2.3)
> 23.
0 -
Proof. L e t A and B be t h e two % p o i n t s , and r one of t h e f o u r non-tangents through A and n o t through B. Then U 8 = 1, and, by ( 1 . 4 ) , uo
=
4+u4+2u
=+
uo
2 4.
The e i g h t t a n g e n t s through B m e e t r i n e i g h t p o i n t s (#A) of p o s i t i v e i n d e x , hence uo = 4.
(2.4)
L e t n b e t h e number of 0 - p o i n t s on AB. By ( 1 . 4 ) , n h a s a 0 - p o i n t , by ( 2 . 4 ) , co = 16+n,
7. S i n c e no t a n g e n t on A
n > 7. 0
(2.5)
X . I f t 8 = 2, then e i t h e r t o = 25, and the Line joining the two 8-points i s external t o K, or to = 23.
to 5 25. I f to 7 24, t h e n ( 2 . 5 ) i m p l i e s n = 8 (n i s d e f i n e d i n t h e proof t o IX), and ( 2 . 3 ) 1 i m p l i e s t 6 = 1. C a l l P t h e unique 6-point. I f P E AB, t h e n n = 9. I f P 4 AB, t h e n t h e t a n g e n t s on P meet AB i n s i x d i s t i n c t p o i n t s of p o s i t i v e index; s o , n 5 7. Ia b o t h c a s e s we g e t a c o n t r a d i c t i o n . T h e r e f o r e , to # 24.
Proof. By ( 2 . 3 ) and I X , 23 <
I f t o = 25, t h e n from ( 2 . 3 ) t 6 = 0 f o l l o w s . By ( 2 . 5 ) , n = 9 , and ( 1 . 4 ) g i v e u2 = 0 f o r t h e l i n e AB. Since t h e p o i n t s on K have index 2 , AB i s e x t e r n a l t o K. 0 X I . I f t 8 = 2 and t 23, then, denoting by A mrd B the 8-points, any nontangent through A, ~ L L ; not through B, has e i g h t 2-points and four 0-points ( t h i s 7:s a l s o true i f to = 2 5 ) . The line AB has seven 0-points and four 2-
points. Through A there are eight tangents, two o f them have m e 6-point each, whereas the remaining Ones are o f index 2. f i e remaining s i x t m g e n t s have two 4-points each, a l l other points being o f index 2 . Proof. The f i r s t a s s e r t i o n immediately f o l l o w s from t h e proof t o I X and ( 1 . 4 ) . I f to = 23, t h e n n = 7 and t 6 = 2. The remaining s t a t e m e n t s can b e o b t a i n e d w i t h t h e h e l p of e q u a t i o n s ( 1 . 4 ) and ( 1 . 5 ) . 0
I f t 8 = 2 and tangent to K.
XII.
to
=
23, then the line through the two 6-points
is non-
Proof. L e t A and B be t h e 8 - p o i n t s , and C and D t h e 6 - p o i n t s . By X I , P = A B n CD i s d i s t i n c t from A, B, C , D. I f CP i s a t a n g e n t , t h e n P , a g a i n by X I , i s of i n d e x 2 . By (1.5), v2 = 10,
v 4 = 1,
V6
=
2.
B e s i d e s P , on t h e l i n e AB t h e r e are f i v e o t h e r p o i n t s of p o s i t i v e index.Through C t h e r e a r e f i v e t a n g e n t s b e s i d e s CD; e a c h of them i n t e r s e c t s AB i n a p o i n t of p o s i t i v e index. T h e r e f o r e , t h e l i n e s j o i n i n g e a c h of t h e s e p o i n t s w i t h C are t a n g e n t . The same argument a p p l i e s t o D. Consequently, t h e t a n g e n t s through t h e
C. Zanelta
488
2-points o t h e r than P on AB, meet CD i n C and D. CD h a s one 4-point Q . The t h r e e t a n g e n t s t h r o u g h Q, o t h e r t h a n CD, must i n t e r s e c t AB i n t h r e e p o i n t s of p o s i t i v e i n d e x d i f f e r e n t from 2 , by t h e p r e v i o u s argument. Since j u s t two such points e x i s t , we get a contradiction. 0 Next, a more d e t a i l e d i n v e s t i g a t i o n i s c a r r i e d o u t i n c a s e to = 23. L e t A, B be t h e 8 - p o i n t s , and C , D t h e 6 - p o i n t s . L e t S be t h e s e t c o n s i s t i n g o f t h e f o u r 2-points on AB. W.1.o.g. w e may suppose t h a t A # P = AB n CD. L e t u ' be the number of j - p o i n t s on CD. By X I , CD c o n t a i n s n e i t h e r A n o r B; t h u s , U8'= 0 . The e i g h t t a n g e n t s on A m e e t CD i n p o i n t s of p o s i t i v e index. Thus, u2 + u
> 6. 4 -
(2.6)
With t h e h e l p of ( 1 . 4 ) we o b t a i n uo = 5 ,
u 2 = 6,
u4 = 0 , u6 = 2 ,
u8 = 0.
(2.7)
Notice t h a t CD h a s e i g h t p o i n t s o f p o s i t i v e index, namely t h e i n t e r s e c t i o n s w i t h CD o f t h e t a n g e n t s t h r o u g h A. Hence, P = AB n CD i s of index z e r o .
(2.8)
The s i x t a n g e n t s through C i n t e r s e c t AB i n p o i n t s of p o s i t i v e index. Since on AB t h e r e l i e e x a c t l y s i x p o i n t s of p o s i t i v e index, t h e l i n e j o i n i n g each of them w i t h C i s a t a n g e n t . The same argument a p p l i e s t o D. I n p a r t i c u l a r , The t a n g e n t s through any 2-point on AB are t h e l i n e s j o i n i n g i t w i t h C and D. L e t t be any of such t a n g e n t s . By ( l . 5 ) , v2 = 9,
v4
3,
=
V6
=
1.
(2.10)
Consequently, a l l t h e twelve 4 - p o i n t s l i e on t h e union of t h e t a n g e n t s on C. Since t h e same argument a p p l i e s a l s o t o D , w e conclude t h a t any 4-point i s t h e i n t e r s e c t i o n of two t a n g e n t s , CSi and DSj, S = { S 1 , S 2 , S ,S$, i # j . On t h e o t h e r hand, t h e e i g h t l i n e s CSj, DSj, meet o f f S U {C,D? i n p r e c i s e l y twelve po i n t s . The r e f o re, X I I I . Suppose t o = 23; k t A and B be t h e two 8-points, C and D the tw o 6p o i n t s , S the s e t of t h e four 2 p o i n t s on AB. Then t h e r e are p r e c i s e l y twelve 4 p o i n t s , namely the p o i n t s i n t h e set X = i C Q n DR
I
Q , R E S, Q
# R}.
0
3. THE CASE t8 = 1 Throughout t h i s s e c t i o n we denote by K a complete 12-arc i n "12, By (1.1), to = 28-t6,
t2 = 104+3t6,
t4 = 24-3t6.
such t h a t t a = l .
(3.1)
X I V . The 6 - p o i n t s form a t 6 - a r c H .
p r o o f . L e t R be a non-tangent; by ( 1 . 4 ) 2 , U6 < 4. Moreover, i f U6 = 4, then u j = 0 f o r j # 0,6. Denote by P t h e unique 8-point. Then P 4 R and t h e e i g h t t a n g e n t s on P m e e t R i n p o i n t s o f p o s i t i v e index, a c o n t r a d i c t i o n . I f U6 = 3 , t h e n a g a i n P 4 R. Indeed, by eq. ( 1 . 4 ) 2 , 4u8 (12-3u6. T h e r e f o r e R has a t most
On Complete 12-Arcs in Projective Planes of Order I2
489
s i x points of p o s i t i v e index, a c o n t r a d i c t i o n . Thus, II has a t most two 6 - p o i n t s . Next, assume t h a t t i s a tangent. By ( 1 . 5 ) , v6
xv.
If t 8
=
1, then t6
5 6.
5
2. 0
( P r o p o s i t i o n X I X y i e l d s a better r e s u l t . )
P r o o f . Suppose Q i s any 6-point. Then rhere a r e a t l e a s t f i v e tangents through Q which a r e n o t on the 8-point P. By (1.5), according to the p o s s i b l e values f o r V6 (v6 = 1 or v6 = 2 ) , we have v4 = 3 or v4 = 1. In any case, a tangent t , on Q and not on P, contains a &-point; t h e r e f o r e , t 4 2 5. The statement follows from ( 3 . 1 ) . 0 X V I . Let P be the Lmique 8-point m d H the s e t of a l l 6 p o i n t s . H u {PI i s a (t6+1)-arc.
If t 6 f 2 , then
proof. In case t 6
3, we prove t h a t on any l i n e on P one 6-point l i e s a t m s t . Let A be a 6-point. I f PA i s a tangent, then 111 implies t h a t A i s the unique 6-point on PA. I f PA i s non-tangent, by ( 1 . 4 ) , U6 5 2 . Suppose u6 = 2 , then (1.4) imply (3.2) u 0 -> 8 .
Let B be a 6-point n o t on PA. The s i x tangents through B must meet P A i n p o i n t s of p o s i t i v e index. T h i s c o n t r a d i c t s (3.2). C i We were n o t able to prove X V I when t6 = 2 . Thus, we i n v e s t i g a t e the case i n which P and the two 6-points A, B l i e on a l i n e , say R . F i r s t l y , R i s nontangent (by 111). Next, from (1.4) e i t h e r
9,
u2 = 0,
u4 = 1,
u6 = 2 ,
u0 = 8,
u2 = 2,
u4 = 0,
U6
u0
=
=
2,
u8 = 1, o r U8
=
1
(3.3) (3.4)
follow. By (1.5) A tangent t without 6-points and 8-points has e x a c t l y f i v e 4-points,
(3.5)
t h e remaining ones being of index 2.
I f (3.3) holds, then I? has f o u r p o i n t s of p o s i t i v e index. Denote by C the 4p o i n t on R. By (3.5), t h e union of the tangents through C c o n t a i n s 1 7 4-points. From ( 3 . 1 ) t 4 = 18 follows; thus another 4-point e x i s t s , say Q. The tangents on Q meet R i n f o u r p o i n t s of p o s i t i v e index o t h e r than C , a c o n t r a d i c t i o n . Theref o r e , (3.4) m u s t hold. Denote by C and D the two 2-points on R, and by S the s e t of t h e 18 4-points. I f Q E S, then the tangents through Q i n t e r s e c t II i n p o i n t s of p o s i t i v e index. Consequently, a t l e a s t one tangent through Q contains e i t h e r C or D. By ( 3 . 5 ) , on t h e union of the tangents on C ( o r D) t h e r e a r e ten 4p o i n t s ; hence, t h e r e a r e e x a c t l y two p o i n t s U,V E S such t h a t U C , U D , V C , V D a r e tangents. W e c l a i m that
The tangents on U ( o r V) meet
L
in A,B,C,D.
If
(3.6)
Q E S-{U,V}, then PQ i s a tangent.
I f t i s a tangent through A ( o r B ) , then by (1.5) t has t h r e e 4-points. Thus S is contained i n t h e union of the s i x tangents through A (or B) and the f i r s t statement follows. Next, by 111, on any of the e i g h t tangents on P t h e r e l i e two 4-points. Therefore, t h e remaining two 4-points must coincide w i t h U andV. Next, we i n v e s t i g a t e , i n m r e d e t a i l , t h e (t6+1)-arc
M = {P E IT 4
I
P of index a t l e a s t 6 ) .
C. Zanellu
490
Unless otherwise s t a t e d , t 6 > 3 up t o t h e end o f t h i s s e c t i o n .
X V I I . k t A be a 6-point.
If t 6 > 3 , then t h e m i s no &-point on PA.
8 . Then PA i s non-tangent and ( 1 . 4 ) h o l d . Since t h e t a n g e n t s on any 6 - p o i n t C ( # A) i n t e r s e c t PA i n p o i n t s o f p o s i t i v e i n d e x , e q s . ( 1 . 4 ) have t h e unique s o l u t i o n uo = 7 , u2 = 3, u4 = 1, u 6 = 1 , u g = 1 . There a r e e x a c t l y s i x p o i n t s of p o s i t i v e i n d e x on PA. T h e r e f o r e ,
Proof. Suppose t h a t PA h a s a 4-point
I f C i s any 6 - p o i n t ,
then AC i s a t a n g e n t .
(3.7)
N o t i c e t h a t , by (1.5), I f t i s a t a n g e n t t h r o u g h two 6 - p o i n t s , t h e n t h a s e x a c t l y one 4-point. I f on a t a n g e n t s t h e r e i s j u s t one 6 - p o i n t and no 8 - p o i n t , then s h a s e x a c t l y t h r e e 4 - p o i n t s .
(3.8)
On A t h e r e a r e t6-1 t a n g e n t s , e a c h o f them j o i n i n g i t w i t h a 6 - p o i n t . None of t h e remaining 7-t6 t a n g e n t s c o n t a i n s a p o i n t ( # A) of index 8 o r 6 . S i n c e B i s > (th-l)+ a &-point t h a t does n o t l i e on a t a n g e n t through A, (3.8) i m p l i e s t 4 < 3, a c o n t r a d i c t i o n . + 3 ( 7 - t 6 ) + 1 = 2 1 - 2 t 6 . Eq. ( 3 . 1 ) 3 g i v e s t 6 I f t i s a t a n g e n t on P w i t h o u t 6 - p o i n t s , t h e n by 111 t h a s two & - p o i n t s . I f any t a n g e n t on P h a s no 6 - p o i n t , t h e n t 4 > 1 6 and ( 3 . 1 ) 3 y i e l d s t 6 2 . S i n c e , by assumption, t 6 L 3,
5
A 6-point
A e x i s t s such t h a t PA i s a t a n g e n t .
L e t A and B b e two 6 - p o i n t s . Then, e i t h e r AB i s a t a n g e n t , i n which c a s e AB c o n t a i n s e x a c t l y one 4-point, o r it i s a non-tangent and c o n t a i n s no 4-point.
(3.9) (3.10)
The f i r s t s t a t e m e n t i s a consequence of ( 3 . 8 ) . I f AE i s non-tangent, t h e n P F A B (by XVI) and t h e t a n g e n t s on P m e e t AB i n p o i n t s of p o s i t i v e i n d e x . Hence, e q s . ( 1 . 4 ) have t h e unique s o l u t i o n uo = 5, u2 = 6, u4 = 0 , U6 = 2, u8 = 0 . Now assume t 6 > 3 , and c o n s i d e r a 6 - p o i n t A. I f t i s a t a n g e n t on A w i t h n e i t h e r 6 - p o i n t s ( o t h e r than A) n o r tl-points, t h e n , by ( 3 . 8 ) , t h a s t h r e e 4 - p o i n t s . I f any t a n g e n t on A h a s no o t h e r 6 - p o i n t , t h e n t 4 > 15 a s a t l e a s t f i v e o f such t a n g e n t s a r e n o t on P. Thus eq. ( 3 . 1 ) 3 g i v e s t6-5 3. Hence, I f t 6 > 3 and A i s a 6 - p o i n t , t h a t AB i s a t a n g e n t .
X V I I I . If t 6
=
6, then each secant t o M
t h e n a 6 - p o i n t B e x i s t s such
(3.11)
is a t a n g en t t o K .
Proof. By ( 3 . 1 ) , t 4
= 6. F i x any 6 - p o i n t A , and denote by x t h e number o f tang e n t s t o K t h r o u g h A e a c h o f which c o n t a i n s a n o t h e r 6 - p o i n t . Thus, x < 5. By ( 3 . 8 ) , on t h e union o f t h e s e t a n g e n t s t h e r e a r e x 4 - p o i n t s . On A t h e r e a r e a t l e a s t 5-x t a n g e n t s t o K h a v i n g no p o i n t of index 8 o r 6 o t h e r t h a n A . By ( 3 . 8 ) ,
6 = t4
2 x+3(5-x)
=
15-2x
=)
x = 5.
T h e r e f o r e , a l l l i n e s which j o i n A w i t h any o t h e r 6 - p o i n t a r e t a n g e n t t o K . Now suppose PA i s non-tangent. Thus t h r o u g h A t h e r e e x i s t s a t a n g e n t t t o K, on which A i s t h e unique p o i n t of i n d e x > 4. by ( 3 . 8 ) , t has t h r e e 4 - p o i n t s . S i n c e on t h e union o f t h e above c o n s i d e r e d t a n g e n t s t o K on A t h e r e a r e f i v e 4-points, w e g e t t 4 2 8, a c o n t r a d i c t i o n . 0 XIX.
If t 8
=
1, then t 6
5
5.
Proof. Suppose t 6 = 6. A s a consequence of t h e proof t o X V I I I , A t a n g e n t j o i n i n g a 4 - p o i n t w i t h a 6-point c o n t a i n s a n o t h e r 6 - p o i n t , t h e remaining o n e s b e i n g of i n d e x 2 .
(3.12)
On Complete 12-Arcs in Projective Planes of Order 12
49 1
Indeed, i f t i s a t a n g e n t through a 6-point A, then e i t h e r t c o n t a i n s P, i n which c a s e i t h a s no 4-point, o r t h a s a n o t h e r 6-point and p r e c i s e l y one 4 - p o i n t Now f i x a 6 - p o i n t A. There a r e f i v e t a n g e n t s t h r o u g h i t and n o t t h r o u g h P, e a c h of them h a s one 4 - p o i n t . There a r e e x a c t l y two t a n g e n t s on P c o n t a i n i n g 4-points; namely, t h o s e t a n g e n t t o M t o o . Each of such t a n g e n t s h a s two 4 - p o i n t s (by X V I I I and 1 1 1 ) . T h e r e f o r e , a 4-point Q e x i s t s , such t h a t AQ i s t a n g e n t and PQ i s n o t . Suppose t h a t a t a n g e n t t e x i s t s t h r o u g h Q. such t h a t on t t h e r e i s no p o i n t of i n d e x > 4 . By ( 3 . 5 ) , t h a s f i v e 4 - p o i n t s . There a r e two t a n g e n t s on P c o n t a i n i n g 4 - p o i n t s . Each o f them h a s a t l e a s t one 4-point n o t on t . Hence, t 4 7 , a cont r a d i c t i o n . Consequently, s i n c e (3.12) h o l d s , any t a n g e n t t h r o u g h Q h a s e x a c t l y two 6 - p o i n t s . T h e r e f o r e , on t h e union of t h e t a n g e n t s on Q t h e r e a r e e i g h t 6p o i n t s . T h i s c o n t r a d i c t i o n and XV prove t h e s t a t e m e n t . 0
4 . THE CASE t 8 = 0 In t h i s s e c t i o n K d e n o t e s a complete 12-arc i n 7 ~ 1 2w i t h t 8 = 0 . By (l.l), to = 31-t6,
t 2 = 96+3t6,
t 4 = 30-3t6.
(4.1)
Under t h e s e assumptions, by ( 1 . 5 ) , Suppose t h a t t i s a t a n g e n t through a 6 - p o i n t A. Then e i t h e r t h a s e x a c t l y two 6 - p o i n t s and one 4 - p o i n t , t h e remaining ones b e i n g of i n d e x 2 , o r t h a s one 6 - p o i n t (A) and t h r e e 4 - p o i n t s , t h e remaining p o i n t s b e i n g of i n d e x 2 .
u.If
t g = 0, then t 6
5 8.
Proof. By ( 4 . 2 ) , on any t a n g e n t t h r o u g h a 6 - p o i n t A t h e r e i s a t l e a s t one 4point. Therefore, t 4
2 6.
The s t a t e m e n t f o l l o w s ( t a k e i n t o a c c o u n t ( 4 . 1 ) 3 ) .
XXI. Denote by H t h e s e t of al?, 6-points.
If t 6
2
7 , then H i s an incomp&?t&
t6-al"C.
Proof. Assume t h a t A , B and C a r e t h r e e c o l l i n e a r 6 - p o i n t s . L e t x be t h e number of t a n g e n t s t h r o u g h A c o n t a i n i n g no f u r t h e r 6-point. Since AB i s non-tangent and t h e 6 - p o i n t s , d i s t i n c t from A,B,C, number t6-3, we have x 2 6-(t6-3) = + t 6 . 24-2t6 4 - p o i n t s . Thus, on t h e t a n g e n t s through A t h e r e are 3x+(6-x) = 2x+6 By (4.1)3, 24-2t6 5 30-3t6 * t 6 5 6. To prove t h a t H i s i n c o m p l e t e , we d i s t i n g u i s h two cases, a c c o r d i n g t o t h e v a l u e of t 6 . t 6-= 8. Let A be a 6 - p o i n t . By ( 4 . 2 ) , on t h e t a n g e n t s through A t h e r e a r e 3x+(6-x) = 6+2x 4 - p o i n t s . A has another 6-point.
By ( 4 . 1 ) , t 4 = 6; hence, x = 0, i . e .
any t a n g e n t on
N o t i c e t h a t t h e number of t a n g e n t s t o K h a v i n g two 6 - p o i n t s e q u a l s the h a l f of t h e c a r d i n a l i t y of t h e s e t {(P,Q)
1
P,Q E H and PQ i s t a n g e n t t o K}.
Indeed, l e t t be t h e t a n g e n t t o K t h r o u g h P,Q E H. With t t h e two o r d e r e d p a i r s (P,Q) and (Q,P) are a s s o c i a t e d . S i n c e t h e r e are e i g h t p o s s i b l e c h o i c e s f o r P and j u s t s i x f o r Q, t h e t a n g e n t s t o K number 8 * 6 / 2 = 24 which a r e a l s o s e c a n t t o H . Consequently, t h e y e x h a u s t all t a n g e n t s t o K. Hence, Any t a n g e n t t o K i s s e c a n t t o H. As a consequence- of ( 4 . 3 ) , t a n g e n t t o K.
(4.3)
t h e r e a r e p r e c i s e l y f o u r s e c a n t s t o H which are non-
L e t Q be one o f the s i x t a n g e n t s t o H through a n a r b i t r a r y 6 - p o i n t , s a y A. By ( 4 . 3 ) , R i s non-tangent t o K. Hence, by ( 1 . 4 ) , uo = 3, u2 = 9, u6 = 1. Denote by S t h e s e t o f t h o s e 0 - p o i n t s which l i e on t h e t a n g e n t s t o H t h r o u g h A; t h u s ,
492
C. Zunellu
I S \ = 18. L e t r be a s e c a n t t o H which i s non-tangent t o K . There a r e f o u r such l i n e s . By ( 1 . 4 ) w i t h u4 = 0 , we g e t uo = 5 , u2 = 6 , U6 = 2 . I f A € r , t h e n r n S = 0. On t h e o t h e r hand, i f A @ r, t h e n r n S I 5 5 . Since t h e r e are prec i s e l y t h r e e l i n e s which are s e c a n t t o H, non-tangent t o K and n o t on A, a p o i n t P E S e x i s t s , such t h a t t h e r e i s no s e c a n t t o H through i t . Hence, H i s incomplete .
I
t 6- = 7. F i r s t of a l l , w e prove t h a t There e x i s t a t most t h r e e l i n e s which a r e s e c a n t t o H and non-tangent t o K.(4.4) F i x a p o i n t A E H, and d e n o t e by x t h e number of l i n e s through A and t a n g e n t t o b o t h H and K. By ( 4 . 2 ) , on t h e union of t h e t a n g e n t s t o K on A t h e r e a r e 6+2x 4 - p o i n t s . Eqs. ( 4 . 1 ) imply t 4 = 9; t h u s , x < 1. Obviously, x i s a l s o t h e number of those l i n e s on A which are s e c a n t t o H &d non-tangent t o K . T h e r e f o r e , through any p o i n t of H a t most one l i n e p a s s e s s e c a n t t o H and non-tangent t o K . Hence, ( 4 . 4 ) f o l l o w s . A s a consequence of ( 4 . 4 ) , a p o i n t Q e x i s t s i n H, such t h a t any s e c a n t t o H on Q i s a t a n g e n t t o K, and v i c e - v e r s a . L e t r be a t a n g e n t t o H a t Q . There are seven s u c h t a n g e n t s . Since r i s non-tangent t o K, by ( l . 4 ) , u2+u4 5 u2+2u4 = 9 which, t o g e t h e r w i t h eq. (1.4)1, i m p l i e s u O L 3 . u2+2u4 = 9 Next, denote by S ' t h e s e t o f t h o s e 0-points l y i n g on t h e t a n g e n t s t o H a t Q . Thus, S'I 21. Assume a s e c a n t , s a y p, e x i s t s t o H, which i s non-tangent t o K . T a k e X E p n H, t h e n X Q . F i v e o f t h e s i x t a n g e n t s t o K on X a r e s e c a n t t o H, whereas t h e remaining one i s t a n g e n t t o H. Hence on t h e union of t h e t a n g e n t s t o K through X t h e r e are e i g h t 4 - p o i n t s . Since t 4 = 9, t h e r e i s a t most one 4-point on p. T h e r e f o r e , by ( 1 . 4 ) , e i t h e r uo = 5 o r uo = 6 , which i m p l i e s Ip n S ' / '6. Thus, t h e same argument a s i n case t 6 = 8 y i e l d s t h e e x i s t e n c e of a p o i n t P E S such t h a t H U { P I i s an a r c .
1
5. CONCLUSION X X I I . E q u a t i o n s (1.1) have a t most 1 7 s o l u t i o n s w i t h
a s s o c i a t e d w i t h a c o n p k t e 12-arc Proof.
in ~ 1 2 ) .
a geometrical rneming-(i.e.
The s t a t e m e n t f o l l o w s from p r o p s . VI,VIII,X,XIX,
and XX. 0
REFERENCES H i r s c h f e l d , J.W.P., P r o j e c t i v e geometry o v e r f i n i t e f i e l d s , Clarendon P r e s s , Oxford 1979. Lam, C.W.H., T h i e l , L . , Swiercz, S . , M c Kay, J . , The non-existence o f o v a l s i n a p r o j e c t i v e p l a n e of o r d e r 10, Discrete Math. 45 (1983), 319-321. M a r t i n , G.E., On a r c s i n a f i n i t e p r o j e c t i v e p l a n e , Canad. J . Math. 19 (1967), 376-393. T a l l i n i , G . , S u i q - a r c h i d i un piano l i n e a r e f i n i t o d i c a r a t t e r i s t i c a p=2, Rend. Accad. L i n c e i ( 8 ) 23 (1957), 242-245. T a l l i n i , C., L e z i o n i d i Geometria 111, anno ace. 1983-84, Dip. Mat. Univ. Roma "La Sapienza", 1984. T a l l i n i , G . , Sui q-archi c o m p l e t i d i un p i a n o p r o i e t t i v o non d e s a r g u e s i a n o d i o r d i n e q p a r i , Quaderni Sem. Geom. Comb. 54, Marzo 1985, Dip. M a t . Univ. Roma "La Sapienza". Z a n e l l a , C . , S u i 1 2 - a r c h i c o m p l e t i d i un piano p r o i e t t i v o d i o r d i n e 1 2 , Quaderni Sem. Geom. Comb. 58, Dicembre 1985, Dip. Mat. Lhiv. Roma "La Sapienza".
Annals of Discrete Mathematics 37 (1988) 493-496 0 Elsevier Science Publishers B.V. (North-Holland)
493
BLOCK DESIGNS ADMITTING FLAG TRANSITIVE GROUPS OF AUTOMOFWHISMS
Paul-Hermann Zieschang Mathematisches Seminar der Universitlt Kiel OlshausenstraRe 40 D-2300 Kiel 1 West Germany
In recent years, a large number of papers (e. g. [ 2 1 , [ 31, [S], [lo]) has been investigating finite block designs with 1 = 1 admitting flag transitive groups of automorphisms. Most of these papers consider additional assumptions which restrict either the structure of the design or that of the acting group. In the following we will discuss finite block designs with )r = 1 admitting a flag transitive group G of automorphisms such that [S],
(*) each two point stabilizer Gxy unique block determined by x and y.
acts trivially on the
The following proposition is the main result of
[9].
PROPOSITION 1. Let D be a block design with A = 1 and point set x and let G be a flag transitive group of automorphisme of D that satisfies ( * ) . Let x E x and let A be a non trivial normal p-subgroup of G , . Then each one point stabilizer Gr contains exactly one conjugate Ar of A and the family of fixed point sets {Fix(Arn Gs) i r,s E X I rPs) forms a block design with A = 1 on X on which G acts as a group of automorphisms.
P.-H. Zieschang
494
Proposition 1
is needed to prove the following result of
191.
THEOREM 2. Let D be a block design with A = 1 and point set X and let G be a flag transitive group of automorphisms of D that satisfies ( * ) . Let x E X and assume that Gx has an abelian normal subgroup which is not semiregular on X - {x}. Then, for some integer n 2 3 and some prime power q, we PrL(n,q). have PSL(n,q) 5 G
Theorem 2 generalizes Theorem A of O'Nan's paper [6]. It is crucial in the proof of the following theorem [lo].
THEOREM 3 . Let D be a block design with A = 1 and point set X and let G be a flag transitive group of automorphisms of D that satisfies ( * ) . Let x E X and assume that Gx has a normal subgroup which is a T.I. set in G and not semiregular on X - (x}. Then the conclusion of Theorem 2 holds.
Theorem 3 is a generalization of Theorem A of [ 7 ] . The following result 181 is similar to Bender's theorem [l]. Its proof uses complex character theory and a lot of results due to Hiller [ 4 ] .
THEOREM 4. Let D be a block design with X = 1 and point set X and let G be a flag transitive group of automorphisms of D that satisfies ( * ) . Assume that the one point stabilizers of G have odd order and that the two point stabilizers are cyclic. Then either G is solvable or G acts doubly transitively
on X.
Block Designs Admitting Flag Transitive Groups
49 5
REFERENCES H. Bender, Endliche zweifach transitive Permutationsgruppen, deren Involutionen keine Fixpunkte haben, Math. Z. 104 (1968), 175 - 204. F. Buekenhout, A . Delandtsheer, J. Doyen, Finite linear spaces with flag-transitive and locally primitive groups. To appear. A. R. Camina, Groups acting flag-transitively on designs, Arch. Math. 32 (1979), 424 - 430. W. Hiller, 7/4-transitive Permutationsgruppen, Dissertation, Math. Sem. der Univ. Kiel, 1980.
W. M. Kantor, Primitive permutation groups of odd degree, and an application to finite projective planes, J. Algebra 106 (1987), 15 - 45.
M. O'Nan, A characterization of Ln(q) group, Math. Z. 127 (1972), 426 - 439.
as a permutation
M. OrNan, Normal structure of the one-point stabilizer of a doubly-transitive permutation group. I., Trans. Amer. Math. SOC. 214 (1975), 1 - 42. P.-H. Zieschang, Uber eine Klasse von Permutationsgruppen, Dissertation, Math. Sem. der Univ. Xiel, 1983.
P.-H. Zieschang, Fahnentransitive Automorphismengruppen von Blockplanen, Geom. Dedicata 18 (1985), 173 - 180. Zieschang, A spaces. To appear.
[lo] P.-H.
theorem of
O'Nan
for finite
linear
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Annals of Discrete Mathematics 37 (1988) 497-502 0 Elsevier Science Publishers B.V. (North-Holland)
497
AN INDEPENDENCE THEOREM ON THE CONDITIONS FOR INCIDENCE LOOPS
Elena ZIZIOLI Dipartimento di Matematica, Universith Cattolica via Trieste 17 25121 Brescia. Italia *
1.
INTRODUCTION
A fibered Zoop ( P , p , - ) is a loop (P..) together with a set 9 (191>1 of ) subloops of (P,.) such that for any atP\(ll there is exactly an element F t s with atF. In the recent paper [51 ,we have stated algebraic conditions in order to provide a fibered loop (P,@,.) with a geometric structure either of an incidence loop or of an incidence space with parallelism or of a kinematic loop. In this note we prove (Theorem 1) that the conditions stated there are orderly independent.
2. PRELIMINARY NOTIONS First of all we recall some definitions and properties. An inci.dence space is a pair ( P , g ) where: is a set of subset of P i) ii) v a , b o P , a f b g1R09 such that a,bcR iii) V R E . ~ 1~122 In an incidence space ( P , g ) let us assume the set P to be a loop (P,.) and let us consider the following properties: (L) V a t P the map a , : P - P ; x -ax is an element of Aut(P,.%); (R) V a s P the map a, : P-P; x -xa is an element of Aut(P,W); (K) VXoW with 1 t X (X,.) is a subloop of (P,.); then we shall say (cf. [2] $ 7 ) that (P,w,.) is: an incidence Zoop if (L) holds ; a 2-s7:ded incidence Zoop if (L) and (R) hold ; a kinematic loop if (L),(R) and ( K ) hold
a
.
.
fibered loop (P,@,-) is a loop (P,.) together with a subset 9 of the powerset of P such that: i) V F E ~ (F,.) is a subloop of (P,.) and I p l > 1 , ii) VaoP\111 3 , F ~ s such that aoF ; the set .Fwill be called a fibration of (P,.) A
.
By definition a kinematic loop ( P , g ,- ) to the fibration $:= 1x09 I lox) .
is always a fibered loop with respect
An incidence space ( P , g ) is called an
incidence space with paralZelism
-
* Research supported by the Italian Ministry of Education (M.P.I.
40%)
.
E. Zizioli
498
(P.2,
11)
if there is a relation
" / I t ' on 3
(E) ( t / I ' ' is an equivalence relation (P) V X E P , V Y E B glZE 98 with In an incidence space with parallelism que element ZE.%? such that XEZ and
such that:
XEZ IIY . (P,B,
Z IIY
.
11)
we denote by
{xllY ithe uni-
From now on let ( P , F , . ) be a fibered loop and let %:=tax 1 a E P , X E , 1~ Moreover we define the relation ' l / l r l on .% in the following way: aX /IbY : t) 3 a ' , b ' ~ P, 3 Z ~ 2such that aX = a'Z , bY =b'Z . In [5] we introduced the following conditions for a fibered loop ( P , 9 , * ) : (Fl) !ax 1 aEP , X E F ) = iYb I beP , YE 9 I ; (F2) ~ B E F: x(yA) = (xy)B ; ~ A F E VX,YEP AX)^ = C(xy) ; (F2') VAEF \ d x , y ~ P ~ C E S: (F3) VAEF , VaEA , V X E P (xa)A = xA and we proved (see [ 5 ] (9)c),(16),(10)): (1) (P,!%,.) is an incidence loop if and only if ( F 2 ) holds. ( 2 ) ( P , g , - ) is a kinematic loop if and only if (Fl,2,2') hold. ( 3 ) (P,.%, I / ) is an incidence space with parallelism if and only if ( F 3 ) holds. the foll.owing condition as well: We now consider for the loop (P, g,.) (F3') VAEF , VaEA , V X E P A(ax) = Ax ; and we define on 2 the following relation (right-parallelism): aX /I,bY 3 a ' , b ' E P , 3 2 ~ 9such that aX = Za' , bY = Zb' , then we have: (4) (P,2,11, 11, ) is an incidence space with parallelism if for the fibered loop ( P , F , . ) the conditions ( F l ) and ( F 3 ' ) hold. Proof. By (F1) % = IYb 1 YE 9 , bEP 1 , hence the proof follows from prop. (10) of is] .
:*
Therefore from a fibered loop (P,9, verifying (F1,3,3') we can obtain an incidence space with two parallelisms (P,.G@, 11, 11, 1 . A doubZe space (cf. [ 3 ] ) is an incidence space (P,,%) with two parallelisms 11 , 1 1 , such that the following condition holds: (D) let A,BE%', let asA , bEB and let B':=tal/B1 , A':AblI,AI then A'?B' f if AnB f @ . But our fibered loop ( P , F , - )fulfilling (F1,3,3') is not a double space because the condition D) is only proved if (P,.) is a fibered group such that for any aEP a 9 a c 9 (cf. [3] ) . Otherwise,for a proper fibered loop (i.e. a loop which is not a group),we have only the specialization of (D) where 1 EAQB . a )
-4
Let tpl,p2,...,p 1 be a set of conditions in a given structure.We recall the following definitfons: i ) the conditions p1,p2, ...pn are abso1uteZy independent if for any iE{l,2,. ..,n 1 the condition p . cannot be proved by means of the remaining p l , ..., 1 P i - l p P i + l , - .'Pn . I ii) the conditions P1,P2,. . .pn are o r d e r l y independent i f for any idl,2,.. .,ni the condition p.cannot be proved by means of the previous p . . ,Pi-l 1 ones. The definition i ) implies ii).Viceversa B.Levi proved '1 that if ; p ,p 1 2"'
A n Independence Theorem for Incidence Loops
499
.,pm} are orderly independent it is always possible to find a set of condiabsolutely independent and equivalent to the set tioEs { p;,p;, . . . ,p; } tP1'P 2*...9Pn 1 . In $4 we shall prove the following main Theorem: Theorem 1 . There exist proper fibered loops (P,@,-) fulfilling the conditions (Fl,2,3,3');moreoverthese conditions are orderly independent.
3. FIBERED LOOPS AND TACTICAL CONFIGURATIONS
In order to prove Theorem 1 we recall the following notions
(cf. [ 11):
A tactical COnfi@YatiOn is a pair ( p . 3 ) where: i) is a subset of the powerset of P , ii) V X , Y E ~ 3 k E N : IXI=IYI=k, iii) 3 r E K such that for all PEP r = I { XE 9
}
I
PEX
I .
We now assume that the fibered loop ( P , y , - ) has all the fibers of the same cardinality and we introduce the following numerical constants.Let v:=[PI , n:=191 , k:=IXI for XE@. Then v = n(k-l)+l and n 2 3 . If we set Y : = [al 1 aEP 1 and &':=
.
.
4. PROOF OF THEOREM 1
In this section we shall prove Theorem 1 in four steps by showing at each step that there exist fibered loops fulfilling the first n but not the last (4-n) conditions of Theorem 1 (with n = 1,2,3,4 ) .
I Case
n
=
1
.
We consider the set P = l,a,b,c,ab,bc,ca,(ab)c,(bc)a,(ca)bl with the composition law defined by the following multiplication table: b ab
ab c ca b bc a 1 1 (ab)c bc a (ab)c 1 C b (ca)b (ca)b a (bc)a (bc)a ab c (ab)c (ca)b ca ca (bc)a bc
bc ca (bc)a c c (ca)b b a (ca)b (bc)a 1 (ab)c (ab)c 1 ca bc a ab ab b
E. Zizioli
5 00
It is easy to verify that ( P , . ) is a commutative loop of order 10 with the fibration g:={{l,a,b,abl , {l,c,(bc)a,(ca)b) , {l,bc,ca,(ab)c)l and k = 4. Then this loop fulfils (Fl) but since 10/4 and (10*3)/4 are not integers ( P , p , .) fulfils neither (F2) nor (F3) nor ( F 3 ' ) In a subsequent note we shall introduce a constructive method to obtain finite fibered loops (in general non commutative) with all the fibers of the same cardinality such that only the condition (Fl) holds for k>2.
.
I1
Case
n = 2
.
To obtain fibered loops verifying ( F 1 ) and (F2) but not the remaining conditions, it is enough to choose k z 2 and v odd.The smallest example is the set P = {l,a,b,c,d} where the multiplication table is given by:
d b c
l d a
a l b
c a 1
(tab. 2)
Moreover we have also other examples with k > 2 :e.g. the remark 6 of theorem (18) in (51 gives us a class of examples of kinematic loops ( P , g , - ) where the fibration 9 violates the laws (F3) and (F3') and where ( P , . % ) is an affine space of dimension 5. I11
Case
n = 3
Now we show that there are examples of fibered loops which are not groups but where (Fl),(F2) and (F3) are valid. Since v/k has to be integer and since any loop with four elements is a group the smallest order f o r such a possible loop is at least 6 .The following multiplication table gives us such an example:
e
a
b
l
c
Here p:=I{l,a) ,tl,b) ,tl,c) , {l,dl ,tl,ell and one has (xy)y = x for if Y = t 1 , y ) all x,y~P.Therefore (xy)Y = txy,x) = XY But il,aF-(ab) = id,cl f (b,d) = i1,aI.b , hence (F3') is not valid.
.
IV Case n
=
4
.
A large class of examples of proper fibered loops with (F1,2,3,3')can be obtained in the following way.By remark 3 of $6 in [5] (see also [2]) we know that there are proper fibered loops ( P , F , - ) for any k = pn , p f 2 a prime, 7 nEM and IPI = k such that all the four conditions of theorem 1 hold and ( P , $ % ) is an affine space of dimension 7.
This achieves the proof of Theorem 1.
An Independence Theorem for Incidence Loops
50 1
We may investigate the case of the smallest cardinality for the loop (P,$F,.) 2 fulfilling the conditions (F1,2,3,3').Hence let k = 2 (i.e. x = 1 for all xeP ).Then we have: Let (P,$F,.) be a fibered loop with k = 2.Then (F3) is equivalent to : t/a,bpP (ab)b = a; a(ab) = b ; (F3') is equivalent to : v a , b c P the conditions (F3) and (F3') hold if and only if for all a,beP\{l) ,a f b the subloop is a Klein 4-group; d) the conditions (F3) and (F3') imply that (P,.) is a commutative loop. Proof. c) Let us assume (F3) and (F3') and let c:=ab .Then ac = a(ab) = b and bc = = (ac)c = a , ba = b(bc) = c and so ab = c = ba Conversely for any a,bcP\{l) , a f b, we have = {l,a,b,ab} where a(ab) = b and (ab)b = a that is,by a) and b) , (F3') and (F3) (5)
a) b) c)
.
.
With these observations one recognizes that the smallest proper loop with (F3) and (F3') and k = 2 (hence with (Fl) and (F2)) is the set P = {l,a,b,c,ab, bc,ca,(ab)c,(bc)a,(ca)b} with the fibration y*:={ {l,x) I xEP\{l) } and the multiplication table of (tab.1). Hence IPI = 10
.
If we set now k = 3 ,the smallest cardinality for a fibered loop ( P , g , * )with (F1,2,3,3') can be only 9.But for v = 9 the corresponding incidence loop with two parallelisms (P,.@, ) I , I I r ) can be only the affine plane (cf. [4] ) and the loop (P,.) is the abelian group n 3 x n3 . Therefore we have the smallest proper fibered loop ( P , g , - ) fulfilling (F1,2,3, 3') for k = 2 and IPI = 10
.
Remark.
.
In this note we did not consider the independence of the condition (F2') Actually we don't possess examples of loops verifying the conditions ( F 1 , 2 ) but not (F2') . In this context we can only prove the absolute independence of (F3) and (F3') from (Fl),(FZ),(FZ'),as the following examples show. 2 2 Let P:= {l,a,a2,b,b2,c,c,d,d ).We consider the composition law 'i.l' defined on P by the following multiplication table: 1 l a a' a Ia21 2 l a a c2 dZ c2
C C
d
2
1
d d b
d2
b b c2
b c c2 bZ 1 d d2 a
bZ
d d2 1 b a a'
c
c b b', d d c 1 a'
c2 d2 d a a2 1 c bZ
d d2 b2c2 b c 2 c a 2 c a 2 a b a b2 d2 1
Then (P,- ) is a proper loop with a fibration 9:= { {l,a,a2) , {l,b,b2} , {l,c, c2) , {l,d,d2}} of 4 subgroup of order 3.It is easy to verify that in this fibered loop (Fl),(F2),(FZt) and (F3') are not valid but (F3) is fulfilled. If we consider now the new operation ' t o ' ' defined on the same set P as follows: xoy:= yx for all ' x,ycP
502
E. Zizioli
the multiplication table of (P,o) is given by transposing the matrix of (tab.4); hence ( P , ~ , o )is a fibered loop and in this case only the condition ( F 3 ' ) is fulfilled.
NOTES AND REFERENCES Atti dell'Accademia delle Scienze - Torino. ( 2 ) 54 (1904) p.284 DEMBOWSK1,H.P. : Finite geometries . Berlin-Heidelberg-New York 1968 KARZEL,H. and KIST,G.P. : Kinematic algebras and their geometries. Rings and geometry (Kaya et al. eds.) NATO AS1 series - C (1985), 437-509 ,KROLL,H.J. and SORENSEN,K. : Invariante Gruppenpartitionen und Doppelraume. J. reine angew. Math. 2 6 2 / 2 6 3 (1973) 153-157 KARZEL,H. and PIEPER.1. : Bericht iiber geschlitzte Inzidenzgruppen. Jahresber. Deutsch. Math. Verein 3 (1970) 70-114 ZIZIOL1,E. : Fibered incidence loops and kinematic loops. J.of Geometry (to appear)