Applied Mathematics: For the Managerial, Life, and Social Sciences, Fifth Edition

About the Cover For Mark van der Laan, the beauty of mathematical problems and the journeys he takes on the road to solving them are the driving force behind his work in the field of biostatistics. In particular, he is intrigued by the variety of approaches there may be to solve a problem and the fact that it requires a large diversity of scientists and people working in the field to find the most elegant and satisfying solutions. As he moved from an M.A. in mathematics to a Ph.D. in mathematical statistics from the University of Utrecht to his current position in the Department of Biostatistics at the University of California, Berkeley, Mark has found that the most interesting and creative mathematical problems are present in real-life applications. He says, “I have always realized, and have been told by experienced researchers, that solving these applied problems requires a thorough education in mathematics and that probability theory is fundamental. However, as in real life, the approach taken toward the solution is often by far the most important step and requires philosophical and abstract thinking.” MARK VAN DER LAAN

Every day Mark is engaged in creatively solving mathematical problems that have implications Biostatistician in the fields of medical research, biology, and public health. For example, in collaboration with medical researchers at the University of California, San Francisco, Mark is investigating the effects of antiretroviral treatment (ART) on HIV/AIDS progression. As represented by the images on the cover, he is also involved in establishing the causal effect of air pollution on asthma in children, the causal effect of leisure-time activity and lean-to-fat ratio on health outcomes in the elderly, as well as the identification of regulatory networks in basic biology. Recognized for his progressive work in these fields, Mark van der Laan has received numerous awards. In April 2005, he was awarded the van Dantzig Award for his theoretical and practical contributions made to the fields of operation research and statistics. In August 2005, he received the COPSS (Committee of Presidents of Statistical Societies) Award, which is presented annually to a young researcher in recognition of outstanding contributions to the statistics profession. Mark currently holds the UC Berkeley Chancellor Endowed Chair 2005–2008, as well as the long-term Jiann-Ping Hsu/Karl E. Peace Endowed Chair in Biostatistics at University of California, Berkeley. Look for other featured applied researchers in forthcoming titles in the Tan applied mathematics series:

PETER BLAIR HENRY International Economist Stanford University

CHRIS SHANNON Mathematical Economist University of California, Berkeley

JONATHAN D. FARLEY Applied Mathematician California Institute of Technology

NAVIN KHANEJA Applied Scientist Harvard University

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EDITION

5

APPLIED MATHEMATICS FOR THE MANAGERIAL, LIFE, AND SOCIAL SCIENCES

SOO T. TAN STONEHILL COLLEGE

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©2010, 2007 Brooks/Cole, Cengage Learning

Applied Mathematics: For the Managerial, Life, and Social Sciences, Fifth Edition Soo T. Tan

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7

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TO PAT, BILL, AND MICHAEL

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CONTENTS

Preface xi

CHAPTER 1

Fundamentals of Algebra 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9

CHAPTER 2

1

Real Numbers 2 Polynomials 7 Factoring Polynomials 14 Rational Expressions 20 Integral Exponents 26 Solving Equations 30 Rational Exponents and Radicals 36 Quadratic Equations 44 Inequalities and Absolute Value 53 Chapter 1 Summary of Principal Formulas and Terms 62 Chapter 1 Concept Review Questions 63 Chapter 1 Review Exercises 63 Chapter 1 Before Moving On 65

Functions and Their Graphs 2.1 2.2 2.3 2.4 2.5

The Cartesian Coordinate System and Straight Lines 68 Equations of Lines 74 Using Technology: Graphing a Straight Line 84 Functions and Their Graphs 87 Using Technology: Graphing a Function 100 The Algebra of Functions 103 Linear Functions 111 PORTFOLIO: Esteban Silva

2.6

67

115

Using Technology: Linear Functions 120 Quadratic Functions 123 PORTFOLIO: Deb Farace 128

2.7

Using Technology: Finding the Points of Intersection of Two Graphs 132 Functions and Mathematical Models 134 Using Technology: Constructing Mathematical Models from Raw Data 144 Chapter 2 Summary of Principal Formulas and Terms 148 Chapter 2 Concept Review Questions 149 Chapter 2 Review Exercises 149 Chapter 2 Before Moving On 151

vi

CONTENTS

CHAPTER 3

Exponential and Logarithmic Functions 3.1 3.2 3.3

CHAPTER 4

4.2 4.3 4.4

CHAPTER 5

Exponential Functions 154 Using Technology 160 Logarithmic Functions 162 Exponential Functions as Mathematical Models 171 Using Technology: Analyzing Mathematical Models 180 Chapter 3 Summary of Principal Formulas and Terms 181 Chapter 3 Concept Review Questions 182 Chapter 3 Review Exercises 182 Chapter 3 Before Moving On 183

Mathematics of Finance 4.1

153

185

Compound Interest 186 Using Technology: Finding the Accumulated Amount of an Investment, the Effective Rate of Interest, and the Present Value of an Investment 201 Annuities 204 Using Technology: Finding the Amount of an Annuity 212 Amortization and Sinking Funds 215 Using Technology: Amortizing a Loan 225 Arithmetic and Geometric Progressions 228 Chapter 4 Summary of Principal Formulas and Terms 236 Chapter 4 Concept Review Questions 237 Chapter 4 Review Exercises 238 Chapter 4 Before Moving On 239

Systems of Linear Equations and Matrices 5.1 5.2 5.3

5.4 5.5 5.6

241

Systems of Linear Equations: An Introduction 242 Systems of Linear Equations: Unique Solutions 249 Using Technology: Systems of Linear Equations: Unique Solutions 263 Systems of Linear Equations: Underdetermined and Overdetermined Systems 265 Using Technology: Systems of Linear Equations: Underdetermined and Overdetermined Systems 274 Matrices 275 Using Technology: Matrix Operations 284 Multiplication of Matrices 287 Using Technology: Matrix Multiplication 299 The Inverse of a Square Matrix 301 Using Technology: Finding the Inverse of a Square Matrix 313 Chapter 5 Summary of Principal Formulas and Terms 316 Chapter 5 Concept Review Questions 316 Chapter 5 Review Exercises 317 Chapter 5 Before Moving On 319

CONTENTS

CHAPTER 6

Linear Programming 6.1 6.2 6.3 6.4

321

Graphing Systems of Linear Inequalities in Two Variables 322 Linear Programming Problems 330 Graphical Solution of Linear Programming Problems 338 The Simplex Method: Standard Maximization Problems 351 PORTFOLIO: Morgan Wilson 352

6.5

CHAPTER 7

Using Technology: The Simplex Method: Solving Maximization Problems 372 The Simplex Method: Standard Minimization Problems 376 Using Technology: The Simplex Method: Solving Minimization Problems 387 Chapter 6 Summary of Principal Terms 390 Chapter 6 Concept Review Questions 390 Chapter 6 Review Exercises 391 Chapter 6 Before Moving On 393

Sets and Probability

395

7.1 7.2 7.3

Sets and Set Operations 396 The Number of Elements in a Finite Set 405 The Multiplication Principle 411

7.4

Permutations and Combinations 417 Using Technology: Evaluating n!, P(n, r), and C(n, r) Experiments, Sample Spaces, and Events 431 Definition of Probability 439 Rules of Probability 449

PORTFOLIO: Stephanie Molina 413

7.5 7.6 7.7

430

PORTFOLIO: Todd Good 451

Chapter 7 Summary of Principal Formulas and Terms 459 Chapter 7 Concept Review Questions 460 Chapter 7 Review Exercises 460 Chapter 7 Before Moving On 462

CHAPTER 8

Additional Topics in Probability 8.1 8.2 8.3 8.4 8.5

463

Use of Counting Techniques in Probability 464 Conditional Probability and Independent Events 471 Bayes’ Theorem 485 Distributions of Random Variables 494 Using Technology: Graphing a Histogram 502 Expected Value 504 PORTFOLIO: Ann-Marie Martz 510

8.6

Variance and Standard Deviation 516 Using Technology: Finding the Mean and Standard Deviation 527 Chapter 8 Summary of Principal Formulas and Terms 528 Chapter 8 Concept Review Questions 529 Chapter 8 Review Exercises 530 Chapter 8 Before Moving On 531

vii

viii

CONTENTS

CHAPTER 9

The Derivative 9.1 9.2 9.3 9.4 9.5 9.6 9.7 9.8

533

Limits 534 Using Technology: Finding the Limit of a Function 552 One-Sided Limits and Continuity 554 Using Technology: Finding the Points of Discontinuity of a Function 568 The Derivative 570 Using Technology: Graphing a Function and Its Tangent Line 586 Basic Rules of Differentiation 589 Using Technology: Finding the Rate of Change of a Function 600 The Product and Quotient Rules; Higher-Order Derivatives 602 Using Technology: The Product and Quotient Rules 615 The Chain Rule 618 Using Technology: Finding the Derivative of a Composite Function 629 Differentiation of Exponential and Logarithmic Functions 630 Using Technology 640 Marginal Functions in Economics 642 PORTFOLIO: Richard Mizak 647

Chapter 9 Summary of Principal Formulas and Terms 651 Chapter 9 Concept Review Questions 653 Chapter 9 Review Exercises 653 Chapter 9 Before Moving On 656

CHAPTER 10

Applications of the Derivative 10.1 10.2 10.3 10.4 10.5

657

Applications of the First Derivative 658 Using Technology: Using the First Derivative to Analyze a Function 675 Applications of the Second Derivative 678 Using Technology: Finding the Inflection Points of a Function 695 Curve Sketching 697 Using Technology: Analyzing the Properties of a Function 709 Optimization I 711 Using Technology: Finding the Absolute Extrema of a Function 724 Optimization II 726 PORTFOLIO: Gary Li 731

Chapter 10 Summary of Principal Terms 738 Chapter 10 Concept Review Questions 738 Chapter 10 Review Exercises 738 Chapter 10 Before Moving On 740

CHAPTER 11

Integration 11.1 11.2 11.3 11.4

741

Antiderivatives and the Rules of Integration 742 Integration by Substitution 755 Area and the Definite Integral 765 The Fundamental Theorem of Calculus 774 Using Technology: Evaluating Definite Integrals 784

CONTENTS

11.5 11.6 11.7

CHAPTER 12

Evaluating Definite Integrals 785 Using Technology: Evaluating Definite Integrals for Piecewise-Defined Functions 795 Area between Two Curves 797 Using Technology: Finding the Area between Two Curves 807 Applications of the Definite Integral to Business and Economics 808 Using Technology: Business and Economic Applications/Technology Exercises 820 Chapter 11 Summary of Principal Formulas and Terms 821 Chapter 11 Concept Review Questions 822 Chapter 11 Review Exercises 823 Chapter 11 Before Moving On 826

Calculus of Several Variables 12.1 12.2 12.3

827

Functions of Several Variables 828 Partial Derivatives 837 Using Technology: Finding Partial Derivatives at a Given Point 849 Maxima and Minima of Functions of Several Variables 850 PORTFOLIO: Kirk Hoiberg 852

Chapter 12 Summary of Principal Terms 860 Chapter 12 Concept Review Questions 860 Chapter 12 Review Exercises 861 Chapter 12 Before Moving On 862

Answers to Odd-Numbered Exercises 863 Index 915 How-To Technology Index 920

ix

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PREFACE

M

ath is an integral part of our increasingly complex daily life. Applied Mathematics for the Managerial, Life, and Social Sciences, Fifth Edition, attempts to illustrate this point with its applied approach to mathematics. Our objective for this Fifth Edition is threefold: (1) to write an applied text that motivates students while providing the background in the quantitative techniques necessary to better understand and appreciate the courses normally taken in undergraduate training, (2) to lay the foundation for more advanced courses, such as statistics and operations research, and (3) to make the text a useful tool for instructors. Since the book contains more than enough material for the usual two-semester or three-semester course, the instructor may be flexible in choosing the topics most suitable for his or her course. The following chart on chapter dependency is provided to help the instructor design a course that is most suitable for the intended audience.

1

2

3

7

Fundamentals of Algebra

Functions and Their Graphs

Exponential and Logarithmic Functions

Sets and Probability

4

5

9

8

Mathematics of Finance

Systems of Linear Equations and Matrices

The Derivative

Additional Topics in Probability

6

10

Linear Programming

Applications of the Derivative

11

12

Integration

Calculus of Several Variables

xii

PREFACE

THE APPROACH Level of Presentation My approach is intuitive, and I state the results informally. However, I have taken special care to ensure that this approach does not compromise the mathematical content and accuracy.

Problem-Solving Approach A problem-solving approach is stressed throughout the book. Numerous examples and applications illustrate each new concept and result. Special emphasis is placed on helping students formulate, solve, and interpret the results of the problems involving applications. Because students often have difficulty setting up and solving word problems, extra care has been taken to help students master these skills: ■

■

■

■

Very early on in the text students are given practice in solving word problems (see Example 7, Section 1.8). Guidelines are given to help students formulate and solve word problems (see Section 2.7). One entire section is devoted to modeling and setting up linear programming problems (see Section 6.2). Optimization problems are covered in two sections. In Section 10.4 students are asked to solve problems in which the objective function to be optimized is given, and in Section 10.5 students are asked to solve problems in which the optimization problems must first be formulated.

Intuitive Introduction to Concepts Mathematical concepts are introduced with concrete, real-life examples wherever appropriate. An illustrative list of some of the topics introduced in this manner follows: ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

The algebra of functions: The U.S. Budget Deficit Mathematical modeling: Social Security Trust Fund Assets Limits: The Motion of a Maglev The chain rule: The Population of Americans Age 55 and Older Increasing and decreasing functions: The Fuel Economy of a Car Concavity: U.S. and World Population Growth Inflection points: The Point of Diminishing Returns Curve sketching: The Dow Jones Industrial Average on “Black Monday” Exponential functions: Income Distribution of American Families Area between two curves: Petroleum Saved with Conservation Measures

Connections One example (the maglev) is used as a common thread throughout the development of calculus—from limits through integration. The goal here is to show students the connections between the concepts presented—limits, continuity, rates of change, the derivative, the definite integral, and so on.

Motivation Illustrating the practical value of mathematics in applied areas is an important objective of my approach. Many of the applications are based on mathematical models (functions) that I have constructed using data drawn from various sources, including current newspapers, magazines, and the Internet. Sources are given in the text for these applied problems.

xiii

PREFACE

Modeling I believe that one of the important skills that a student should acquire is the ability to translate a real problem into a mathematical model that can provide insight into the problem. In Section 2.7, the modeling process is discussed, and students are asked to use models (functions) constructed from real-life data to answer questions. Students get hands-on experience constructing these models in the Using Technology sections.

NEW TO THIS EDITION Algebra Review Where Students Need It Most Well-placed algebra review notes, keyed to the early algebra review chapters, appear where students often need help in the calculus portion of the text. These are indicated by the (x ) icon. See this feature in action on pages 542 and 577. 2

EXAMPLE 6 Evaluate: lim

hS0

11 ⫹ h ⫺ 1 h

Letting h approach zero, we obtain the indeterminate form 0/0. Next, we rationalize the numerator of the quotient by multiplying both the numerator and the denominator by the expression 1 11 ⫹ h ⫹ 12 , obtaining

Solution

1 11 ⫹ h ⫺ 12 1 11 ⫹ h ⫹ 12 11 ⫹ h ⫺ 1 ⫽ * (x ) See page 41. h h1 11 ⫹ h ⫹ 12 1⫹h⫺1 ⫽ 1 1a ⫺ 1b 2 1 1a ⫹ 1b 2 ⫽ a ⫺ b h1 11 ⫹ h ⫹ 12 2

h h1 11 ⫹ h ⫹ 12 1 ⫽ 11 ⫹ h ⫹ 1 ⫽

Motivating Real-World Applications More than 220 new applications have been added to the Applied Examples and Exercises. Among these applications are global warming, depletion of Social Security trust fund assets, driving costs for a 2008 medium-sized sedan, hedge fund investments, mobile instant messaging accounts, hiring lobbyists, Web conferencing, the autistic brain, the revenue of Polo Ralph Lauren, U.S. health-care IT spending, and consumption of bottled water.

APPLIED EXAMPLE 1 Global Warming The increase in carbon dioxide (CO2) in the atmosphere is a major cause of global warming. The Keeling curve, named after Charles David Keeling, a professor at Scripps Institution of Oceanography, gives the average amount of CO2, measured in parts per million volume (ppmv), in the atmosphere from the beginning of 1958 through 2007. Even though data were available for every year in this time interval, we’ll construct the curve based only on the following randomly selected data points. Year Amount

1958

1970

1974

1978

1985

1991

1998

2003

2007

315

325

330

335

345

355

365

375

380

The scatter plot associated with these data is shown in Figure 54a. A mathematical model giving the approximate amount of CO2 in the atmosphere during this period is given by A(t) ⫽ 0.010716t 2 ⫹ 0.8212t ⫹ 313.4

(1 ⱕ t ⱕ 50)

xiv

PREFACE

Modeling with Data Modeling with Data exercises are now found in many of the Using Technology sections throughout the text. Students can actually see how some of the functions found in the exercises are constructed. (See Internet Users in China, Exercise 40, page 159, and the corresponding exercise where the model is derived in Exercise 14, page 161.)

40. INTERNET USERS IN CHINA The number of Internet users in China is projected to be N(t) ⫽ 94.5e0.2t

(1 ⱕ t ⱕ 6)

where N(t) is measured in millions andDtATA is measured in of Internet users in 14. MODELING WITH The number years, with t ⫽ 1 corresponding the beginning of 2005. China (in to millions) from the beginning of 2005 through a. How many Internet 2010 usersare were thereinat the the following beginningtable: of shown 2005? At the beginning of 2006? b. How many Internet users are there expected to be at the 2005 2006 2007 2008 2009 2010 beginning of 2010? Year Number 116.1 141.9 169.0 209.0 258.1 314.8 c. Sketch the graph of N. Source: C. E. Unterberg

a. Use ExpReg to find an exponential regression model for the data. Let t ⫽ 1 correspond to the beginning of 2005. Hint: a x ⫽ e x ln a.

b. Plot the scatter diagram and the graph of the function f found in part (a).

Making Connections with Technology Many Using Technology sections have been updated. A new example—Market for CholesterolReducing Drugs—has been added to Using Technology 2.5. Using Technology 3.3 includes a new example in which an exponential model is constructed—Internet Gaming Sales—using the logistic function of a graphing utility. Another new example—TV Mobile Phones—has been added to Using Technology 10.3. Additional graphing calculator screens in some sections and Exploring with Technology examples illustrating the use of the graphing calculator to solve inequalities and to generate random numbers have been added throughout.

APPLIED EXAMPLE 2 Market for Cholesterol-Reducing Drugs In a study conducted in early 2000, experts projected a rise in the market for cholesterol-reducing drugs. The U.S. market (in billions of dollars) for such drugs from 1999 through 2004 is approximated by M(t) ⫽ 1.95t ⫹ 12.19

where t is measured in years, with t ⫽ 0 corresponding to 1999. a. Plot the graph of the function M in the viewing window [0, 5] ⫻ [0, 25]. b. Assuming that the projection held and the trend continued, what was the market for cholesterol-reducing drugs in 2005 (t ⫽ 6)? APPLIED EXAMPLE 1 Internet Gaming Sales The estimated growth c. What was the rate of increase of the market for cholesterol-reducing drugs in global Internet-gaming revenue (in billions of dollars), as predicted by over the period in question? industry analysts, is given in the following table:

Source: S. G. Cowen Year Revenue

2001

2002

2003

2004

2005

2006

2007

2008

2009

2010

3.1

3.9

5.6

8.0

11.8

15.2

18.2

20.4

22.7

24.5

a. Use Logistic to find a regression model for the data. Let t ⫽ 0 correspond to 2001. b. Plot the scatter diagram and the graph of the function f found in part (a) using the viewing window [0, 9] ⫻ [0, 30]. Source: Christiansen Capital/Advisors

PREFACE

Variety of Problem Types Additional rote questions, true or false questions, and concept questions have been added throughout the text to enhance the exercise sets. (See, for example, the graphical questions added to Concept Questions 2.3, page 95.)

2.3 Concept Questions 1. a. What is a function? b. What is the domain of a function? The range of a function? c. What is an independent variable? A dependent variable?

c.

d.

y

2. a. What is the graph of a function? Use a drawing to illustrate the graph, the domain, and the range of a function. b. If you are given a curve in the xy-plane, how can you tell if the graph is that of a function f defined by y ⫽ f(x)?

y

y

x

0 x

0

3. Are the following graphs of functions? Explain. a. b.

y

4. What are the domain and range of the function f with the following graph? y 4

0

x

0

x

3 2 1

(2, 12 ) 1

Action-Oriented Study Tabs Convenient color-coded study tabs, similar to Post-it® flags, make it easy for students to tab pages that they want to return to later, whether it be for additional review, exam preparation, online exploration, or identifying a topic to be discussed with the instructor.

xv

2

3

x 4

5

xvi

PREFACE

Specific Content Changes More applications have been added to the algebra review chapters. The discussion of mortgages has been enhanced with a new example on adjustable-rate mortgages and the addition of many new applied exercises. Section 2.7, on functions and mathematical models, has been reorganized and new models have been introduced. Here, students are now asked to use a model describing global warming to predict the amount of carbon dioxide (CO2) that will be present in the atmosphere in 2010, and a model describing the assets of the Social Security trust fund to determine when those assets are expected to be depleted. The chain rule in Section 9.6 is now introduced with an application: the population of Americans aged 55 years and older. A How-To Technology Index has been added for easy reference. New Using Technology Excel sections for Microsoft Office 2007 are now available on the Web.

■ ■

■

■

■ ■

TRUSTED FEATURES In addition to the new features, we have retained many of the following hallmarks that have made this series so usable and well-received in past editions: ■ ■ ■ ■

Self-Check Exercises Offering students immediate feedback on key concepts, these exercises begin each end-ofsection exercise set. Fully workedout solutions can be found at the end of each exercise section.

Section exercises to help students understand and apply concepts Optional technology sections to explore mathematical ideas and solve problems End-of-chapter review sections to assess understanding and problem-solving skills Features to motivate further exploration

2.5 Self-Check Exercises A manufacturer has a monthly fixed cost of $60,000 and a production cost of $10 for each unit produced. The product sells for $15/unit. 1. What is the cost function? 2. What is the revenue function?

Concept Questions

2.5 Concept Questions

Designed to test students’ understanding of the basic concepts discussed in the section, these questions encourage students to explain learned concepts in their own words.

1. a. What is a linear function? Give an example. b. What is the domain of a linear function? The range? c. What is the graph of a linear function?

Exercises Each exercise section contains an ample set of problems of a routine computational nature followed by an extensive set of application-oriented problems.

2. What is the general form of a linear cost function? A linear revenue function? A linear profit function?

3. What is the profit function? 4. Compute the profit (loss) corresponding to production levels of 10,000 and 14,000 units/month. Solutions to Self-Check Exercises 2.5 can be found on page 120.

3. Explain the meaning of each term: a. Break-even point b. Break-even quantity c. Break-even revenue

2.5 Exercises In Exercises 1–10, determine whether the equation defines y as a linear function of x. If so, write it in the form y ⴝ mx ⴙ b.

1. 2x ⫹ 3y ⫽ 6

2. ⫺2x ⫹ 4y ⫽ 7

3. x ⫽ 2y ⫺ 4

4. 2x ⫽ 3y ⫹ 8

5. 2x ⫺ 4y ⫹ 9 ⫽ 0

6. 3x ⫺ 6y ⫹ 7 ⫽ 0

7. 2 x 2 ⫺ 8y ⫹ 4 ⫽ 0 9. 2x ⫺ 3y2 ⫹ 8 ⫽ 0

8. 3 1x ⫹ 4y ⫽ 0 10. 2x ⫹ 1y ⫺ 4 ⫽ 0

11. A manufacturer has a monthly fixed cost of $40,000 and a production cost of $8 for each unit produced. The product sells for $12/unit.

In Exercises 15–20, find the point of intersection of each pair of straight lines.

15. y ⫽ 3 x ⫹ 4 y ⫽ ⫺2 x ⫹ 14

16.

y ⫽ ⫺4x ⫺ 7 ⫺y ⫽ 5x ⫹ 10

17. 2x ⫺ 3y ⫽ 6 3x ⫹ 6y ⫽ 16

18.

2 x ⫹ 4y ⫽ 11 ⫺5x ⫹ 3y ⫽ 5

19.

1 x⫺5 4 3 2x ⫺ y ⫽ 1 2 y⫽

20. y ⫽

2 x⫺4 3

x ⫹ 3y ⫹ 3 ⫽ 0

PREFACE

Using Technology These optional features appear after the section exercises. They can be used in the classroom if desired or as material for self-study by the student. Here, the graphing calculator and Microsoft Excel 2003 are used as a tool to solve problems. (Instructions for Microsoft Excel 2007 are given at the Companion Website.) These sections are written in the traditional example–exercise format, with answers given at the back of the book. Illustrations showing graphing calculator screens are extensively used. In keeping with the theme of motivation through real-life examples, many sourced applications are again included. Students can construct their own models using real-life data in many of the Using Technology sections. These include models for the growth of the Indian gaming industry, TIVO owners, nicotine content of cigarettes, computer security, and online gaming, among others.

USING

TECHNOLOGY

xvii

Finding the Accumulated Amount of an Investment, the Effective Rate of Interest, and the Present Value of an Investment Graphing Utility Some graphing utilities have built-in routines for solving problems involving the mathematics of finance. For example, the TI-83/84 TVM SOLVER function incorporates several functions that can be used to solve the problems that are encountered in Sections 4.1–4.3. To access the TVM SOLVER on the TI-83 press 2nd , press FINANCE , and then select 1: TVM Solver . To access the TVM Solver on the TI-83 plus and the TI-84, press APPS , press 1: Finance , and then select 1: TVM Solver . Step-by-step procedures for using these functions can be found on our Companion Web site.

EXAMPLE 1 Finding the Accumulated Amount of an Investment Find the accumulated amount after 10 years if $5000 is invested at a rate of 10% per year compounded monthly. Solution

Using the TI-83/84 TVM SOLVER with the following inputs, N ⫽ 120

N = 120 I% = 10 PV = −5000 PMT = 0 FV = 13535.20745 P/Y = 12 C/Y = 12 PMT : END BEGIN

I% ⫽ 10 PV ⫽ ⫺5000 PMT ⫽ 0

(10)(12)

Recall that an investment is an outflow.

FV ⫽ 0 P/Y ⫽ 12 The number of payments each year C/Y ⫽ 12 The number of conversion periods each year PMT:END BEGIN

FIGURE T1

The TI-83/84 screen showing the future value (FV) of an investment

we obtain the display shown in Figure T1. We conclude that the required accumulated amount is $13,535.21. EXAMPLE 2 Finding the Effective Rate of Interest Find the effective rate of interest corresponding to a nominal rate of 10% per year compounded quarterly.

Eff (10, 4) Excel 10.38128906

Excel has many built-in functions for solving problems involving the mathematics of SolutiontheHere functionvalue), of the TI-83/84 calculator to obtain the finance. Here we illustrate usewe of use thethe FVEff(future EFFECT (effective rate), result shown in Figure T2. The required effective rate is approximately 10.38% per and the PV (presentyear. value) functions to solve problems of the type that we have encountered in Section 4.1. FIGURE T2

EXAMPLE 3 Finding the Present Value of an Investment Find the present value the of $20,000 due in 5 years if the interest rateInvestment is 7.5% per year compounded EXAMPLE 4 Finding Accumulated Amount of an Find the accumulated amountdaily. after 10 years if $5000 is invested at a rate of 10% per year compounded monthly.l i Ui h TI 83/84 i h h f ll i i

The TI-83/84 screen showing the effective rate of interest (Eff)

Exploring with Technology Designed to explore mathematical concepts and to shed further light on examples in the text, these optional questions appear throughout the main body of the text and serve to enhance the student’s understanding of the concepts and theory presented. Often the solution of an example in the text is augmented with a graphical or numerical solution. Complete solutions to these exercises are given in the Instructor’s Solutions Manual.

Exploring with

TECHNOLOGY In the opening paragraph of Section 3.1, we pointed out that the accumulated amount of an account earning interest compounded continuously will eventually outgrow by far the accumulated amount of an account earning interest at the same nominal rate but earning simple interest. Illustrate this fact using the following example. Suppose you deposit $1000 in account I, earning interest at the rate of 10% per year compounded continuously so that the accumulated amount at the end of t years is A1(t) ⫽ 1000e0.1t. Suppose you also deposit $1000 in account II, earning simple interest at the rate of 10% per year so that the accumulated amount at the end of t years is A2(t) ⫽ 1000(1 ⫹ 0.1t). Use a graphing utility to sketch the graphs of the functions A1 and A2 in the viewing window [0, 20] ⫻ [0, 10,000] to see the accumulated amounts A1(t) and A2(t) over a 20-year period.

xviii

PREFACE

Summary of Principal Formulas and Terms Each review section begins with the Summary highlighting important equations and terms with page numbers given for quick review.

CHAPTER 5 Summary of Principal Formulas and Terms FORMULAS 1. Laws for matrix addition a. Commutative law

A⫹B⫽B⫹A

b. Associative law

(A ⫹ B) ⫹ C ⫽ A ⫹ (B ⫹ C )

2. Laws for matrix multiplication a. Associative law

(AB)C ⫽ A(BC )

b. Distributive law

A(B ⫹ C ) ⫽ AB ⫹ AC

3. Inverse of a 2 ⫻ 2 matrix

If

A⫽ c

and

D ⫽ ad ⫺ bc ⫽ 0

then

A⫺1 ⫽

a c

b d d

1 d c D ⫺c

⫺b d a

X ⫽ A⫺1B

4. Solution of system AX ⫽ B (A nonsingular)

TERMS system of linear equations (242) solution of a system of linear equations (242) parameter (243) dependent system (244) inconsistent system (244) Gauss–Jordan elimination method (250) equivalent system (250) coefficient matrix (252)

Concept Review Questions These questions give students a chance to check their knowledge of the basic definitions and concepts given in each chapter.

Review Exercises Offering a solid review of the chapter material, the Review Exercises contain routine computational exercises followed by applied problems.

Found at the end of each chapter review, these exercises give students a chance to see if they have mastered the basic computational skills developed in each chapter. If they solve a problem incorrectly, they can go to the Companion Website and try again. In fact, they can keep on trying until they get it right. If students need step-by-step help, they can use the CengageNOW Tutorials that are keyed to the text and work out similar problems at their own pace.

square matrix (276) transpose of a matrix (280) scalar (280) scalar product (280) matrix product (288) identity matrix (291) inverse of a matrix (302) nonsingular matrix (302) singular matrix (302)

CHAPTER 5 Concept Review Questions b. A system of linear equations with at least as many equations as variables may have _____ solution, _____ _____ solutions, or a _____ solution.

Fill in the blanks.

1. a. Two lines in the plane can intersect at (a) exactly _____ point, (b) infinitely _____ points, or (c) _____ point. b. A system of two linear equations in two variables can have (a) exactly _____ solution, (b) infinitely _____ solutions, or (c) _____ solution.

5. Two matrices are equal provided they have the same _____ and their corresponding _____ are equal.

2. To find the point(s) of intersection of two lines, we solve the system of _____ describing the two lines.

6. Two matrices may be added (subtracted) if they both have the same _____. To add or subtract two matrices, we add or subtract their _____ entries.

3. The row operations used in the Gauss–Jordan elimination method are denoted by _____, _____, and _____. The use of each of these operations does not alter the of the

7. The transpose of a/an _____ matrix with elements aij is the matrix of size _____ with entries _____.

CHAPTER 5 Review Exercises In Exercises 1–4, perform the operations if possible.

9. 2 A ⫹ 3B

10. 3A ⫺ 2 B

1 1. £ ⫺1 2

2 1 3§ ⫹ £0 1 1

0 1§ 2

11. 2(3A)

12. 2(3A ⫺ 4B)

13. A(B ⫺ C)

14. AB ⫹ AC

⫺1 2. c 3

2 1 d ⫺ c 4 5

2 d ⫺2

15. A(BC )

16.

3. 3 ⫺3

2

2 14 £ ⫺1 2

1 ⫺1

3 2

1 2 d £4§ 3 2

4. c

Before Moving On . . .

augmented matrix (252) row-reduced form of a matrix (253) row operations (254) unit column (254) pivoting (255) size of a matrix (276) matrix (276) row matrix (276) column matrix (276)

1 1CA ⫺ CB2 2

In Exercises 17–24, solve the system of linear equations using the Gauss–Jordan elimination method.

1 0§ 1

17. 2x ⫺ 3y ⫽ 5 3x ⫹ 4y ⫽ ⫺1

18. 3x ⫹ 2y ⫽ 3 2x ⫺ 4y ⫽ ⫺14

19.

20. 3x ⫺ 2y ⫹ 4z ⫽ 16 2x ⫹ y ⫺ 2z ⫽ ⫺1 x ⫹ 4y ⫺ 8z ⫽ ⫺18

x ⫺ y ⫹ 2z ⫽ 5 3x ⫹ 2y ⫹ z ⫽ 10 2x ⫺ 3y ⫺ 2z ⫽ ⫺10

CHAPTER 5 Before Moving On . . . 1. Solve the following system of linear equations, using the Gauss–Jordan elimination method:

A⫽ c

2x ⫹ y ⫺ z ⫽ ⫺1 x ⫹ 3y ⫹ 2z ⫽

4. Let

2

3x ⫹ 3y ⫺ 3z ⫽ ⫺5

2. Find the solution(s), if it exists, of the system of linear equations whose augmented matrix in reduced form follows. 1 a. £ 0 0

0 1 0

0 2 0 † ⫺3 § 1 1

1 b. £ 0 0

0 1 0

0 3 0 † 0§ 0 1

1 c. £ 0 0

0 1 0

0 2 3 † 1§ 0 0

d. ≥

1 0 0 0

0 1 0 0

0 0 1 0

0 0 0 0 ∞ ¥ 0 0 1 0

1 3

2 C ⫽ £1 3

⫺2 0

4 d 1

1 B ⫽ £3 2

⫺1 1 1

2 ⫺1 § 0

⫺2 1§ 4

Find (a) AB, (b) (A ⫹ CT )B, and (c) CTB ⫺ ABT. 5. Find A⫺1 if 2 A ⫽ £0 1

1 ⫺1 1

2 3§ 0

⫹z⫽

4

6. Solve the system 2x

PREFACE

These optional questions can be discussed in class or assigned as homework. These questions generally require more thought and effort than the usual exercises. They may also be used to add a writing component to the class or as team projects. Complete solutions to these exercises are given in the Instructor’s Solutions Manual.

Portfolios The real-life experiences of a variety of professionals who use mathematics in the workplace are related in these interviews. Among those interviewed are a senior account manager at PepsiCo and an associate on Wall Street who uses statistics and calculus in writing options.

Example Videos Available through the Online Resource Center and Enhanced WebAssign, these video examples offer hours of instruction from award-winning teacher Deborah Upton of Stonehill College. Watch as she walks students through key examples from the text, step by step—giving them a foundation in the skills that they need to know. Each example available online is identified by the video icon located in the margin.

Explore & Discuss 1. Consider a system composed of two linear equations in two variables. Can the system have exactly two solutions? Exactly three solutions? Exactly a finite number of solutions? 2. Suppose at least one of the equations in a system composed of two equations in two variables is nonlinear. Can the system have no solution? Exactly one solution? Exactly two solutions? Exactly a finite number of solutions? Infinitely many solutions? Illustrate each answer with a sketch.

PORTFOLIO

Deb Farace TITLE Sr. National Accounts Manager INSTITUTION PepsiCo Beverages & Foods

W

orking for the national accounts division for PepsiCo Beverages & Foods, I need to understand applied mathematics in order to control the variables associated with making a profit, manufacturing, production, and most importantly selling our products to mass club channels. Examples of these large, “quality product at great value” outlets are Wal*Mart, Costco and Target. The types of products I handle include Gatorade, Tropicana, and Quaker foods. Our studies show that the grocery store channels’ sales are flattening or declining as a whole in lieu of large, national outlets like the above. So in order to maximize growth in this segment of our business, I meet with regional buying offices of these chains and discuss various packaging, pricing, product, promotional and shipping options so that we can successfully compete in the market. A number of factors must be taken into consideration in order to meet my company’s financial forecasts. Precision using mathematical models is key here, since so many vari-

ables can impact last-minute decision making. Extended variables of supply-and-demand include time of year, competitive landscape, special coupon distribution and other promotions, selling cycles and holidays, size of the outlets, and yes—even the weather. For example, it’s natural to assume that when it’s hot outside people will buy more thirst-quenching products like Gatorade. But since our business is so precise, we need to understand mathematically how the weather affects sales. A mathematical model developed by Gatorade analyzes long-term data that impact sales by geographic market due to the weather. Its findings include exponentially increased sales of Gatorade for each degree above 90 degrees. I share our mathematical analysis like this study with buyers and negotiate larger orders based on up-to-theminute weather forecasts. The result: increased sales of product based on math.

© kolvenbach/Alamy

Explore & Discuss

xix

APPLIED EXAMPLE 3 Consumer Surveys In a survey of 100 coffee drinkers, it was found that 70 take sugar, 60 take cream, and 50 take both sugar and cream with their coffee. How many coffee drinkers take sugar or cream with their coffee? Solution

Let U denote the set of 100 coffee drinkers surveyed, and let A ⫽ {x 僆 U 0 x takes sugar} B ⫽ {x 僆 U 0 x takes cream}

Then, n(A) ⫽ 70, n(B) ⫽ 60, and n(A 傽 B) ⫽ 50. The set of coffee drinkers who take sugar or cream with their coffee is given by A 傼 B. Using Equation (4), we find n(A 傼 B) ⫽ n(A) ⫹ n(B) ⫺ n(A 傽 B) ⫽ 70 ⫹ 60 ⫺ 50 ⫽ 80

Thus, 80 out of the 100 coffee drinkers surveyed take cream or sugar with their coffee.

xx

PREFACE

TEACHING AIDS INSTRUCTOR’S SOLUTIONS MANUAL (ISBN 0-495-55998-9) by Soo T. Tan The complete solutions manual provides worked out solutions to all problems in the text, as well as “Exploring with Technology” and “Explore & Discuss” questions. POWERLECTURE (ISBN 0-495-56002-2) This comprehensive CD-ROM includes the Instructor’s Solutions Manual, PowerPoint Slides, and ExamView® Computerized Testing featuring algorithmically generated questions to create, deliver, and customize tests. ENHANCED WEBASSIGN Instant feedback and ease of use are just two reasons why WebAssign is the most widely used homework system in higher education. WebAssign allows you to assign, collect, grade, and record homework assignments via the Web. Now this proven homework system has been enhanced to include links to textbook sections, video examples, and problem-specific tutorials. Enhanced WebAssign is more than a homework system—it is a complete learning system for math students.

LEARNING AIDS STUDENT SOLUTIONS MANUAL (ISBN 0-495-55997-0) by Soo T. Tan Giving you more in-depth explanations, this insightful resource includes fully worked-out solutions for the answers to select exercises included at the back of the textbook, as well as problem-solving strategies, additional algebra steps, and review for selected problems. ONLINE RESOURCE CENTER (ISBN 0-495-56037-5) Sign in, save time, and get the grade you want! One code will give you access to great tools for Applied Mathematics for the Managerial, Life, and Social Sciences, Fifth Edition. It includes Personal Tutor (online tutoring with an expert that offers help right now) and access to new Solution Videos on the password-protected Premium Website.

ACKNOWLEDGMENTS I wish to express my personal appreciation to each of the following reviewers of the Fifth Edition, whose many suggestions have helped make a much improved book. Paul Abraham Kent State University—Stark

Andrew Diener Christian Brothers University

James Adair Missouri Valley College

Mike Everett Santa Ana College

Jill Britton Camosun College

Kevin Ferland Bloomsburg University

Debra D. Bryant Tennessee Technological University

Tao Guo Rock Valley College

Michelle Dedeo University of North Florida

Mark Jacobson Montana State University—Billings

Scott L. Dennison University of Wisconsin—Oshkosh

Sarah Kilby North Country Community College

Christine Devena Miles Community College

Murray Lieb New Jersey Institute of Technology

PREFACE

Lia Liu University of Illinois at Chicago

Brian Rodas Santa Monica College

Rebecca Lynn Colorado State University

Dr. Arthur Rosenthal Salem State College

Mary T. McMahon North Central College

Abdelrida Saleh Miami Dade College

Daniela Mihai University of Pittsburgh

Stephanie Anne Salomone University of Portland

Kathy Nickell College of DuPage

Mohammad Siddique Virginia Union University

Carol Overdeep Saint Martin’s University

Jennifer Strehler Oakton Community College

Mohammed Rajah Miracosta College

Ray Toland Clarkson University

Dennis H. Risher Loras College

Justin Wyss-Gallifent University of Maryland at College Park

xxi

I also thank the previous edition reviewers whose comments and suggestions have greatly shaped the current edition. Faiz Al-Rubaee University of North Florida

Joyce Longman Villanova University

Jose F. Alvarado University of Texas, Pan American

C. D. Luning Sam Houston State University

Ronald Barnes University of Houston

Joseph Macaluso DeSales University

Larry Blaine Plymouth State College

Donald K. Mason Elmhurst College

Albert Bronstein Purdue University

Dean Moore Florida Community College at Jacksonville

Kimberly Jordan Burch Montclair State University

Marna Mozeff Drexel University

Peter Casazza University of Missouri—Columbia

James Olsen North Dakota State University

J. Curtis Chipman Oakland University

Wayne B. Powell Oklahoma State University

Lisa Cox Texas A&M University

Deborah Primm Jacksonville State University

Candy Giovanni Michigan State University

Virginia Puckett Miami Dade College

Harvey Greenwald California Polytechnic State University— San Luis Obispo

Geetha Ramachandran California State University, Sacramento

Mohammed Kazemi University of North Carolina—Charlotte Rasul Khan Cleveland State University Daniel Lee Southwest Texas State University Jeffrey Lee Texas Tech University

Mary E. Rerick University of North Dakota Allan Silberger Cleveland State University Mehrdad Simkani University of Michigan, Flint Anne Siswanto East Los Angeles College

xxii

PREFACE

Laurence Small L. A. Pierce College

Joyce Vilseck Texas A&M University, Kingston

Ray Stanton Fresno City College

Hiroko K. Warshauer Texas State University—San Marcos

Michael Sterner University of Montevallo

Jennifer Whitfield Texas A&M University

Giovanni Viglino Ramapo College of New Jersey

Hing-Sing Yu University of Texas, San Antonio

I also wish to thank Jerrold Grossman and Tao Guo for their many helpful suggestions for improving the text. A special thanks goes to Jill Britton for contributing some of the new linear programming problems for this edition. I also thank the editorial, production, and marketing staffs of Cengage Learning: Carolyn Crockett, Danielle Derbenti, Catie Ronquillo, Rebecca Dashiell, Jeannine Lawless, Cheryll Linthicum, Ashley Pickering, Joe Rogove, Angela Kim, and Sam Subity for all of their help and support during the development and production of this edition. I also thank Martha Emry and Betty Duncan who both did an excellent job of ensuring the accuracy and readability of this edition. Simply stated, the team I have been working with is outstanding, and I truly appreciate all their hard work and efforts. Finally, a special thanks to the mathematicians—Chris Shannon and Mark van der Lann at UC Berkeley, Peter Blair Henry at Stanford, Jonathan D. Farley at Cal Tech, and Navin Khaneja at Harvard—for taking time off from their busy schedules to describe how mathematics is used in their research. Their pictures and applications of their research appear on the covers of my applied mathematics series. S. T. Tan

A BOUT THE A UTHOR SOO T. TAN received his S.B. degree from Massachusetts Institute of Technology, his M.S. degree from the University of Wisconsin–Madison, and his Ph.D. from the University of California at Los Angeles. He has published numerous papers in Optimal Control Theory, Numerical Analysis, and Mathematics of Finance. He is currently Professor Emeritus of Mathematics at Stonehill College.

By the time I started writing the first of what turned out to be a series of textbooks in mathematics for students in the managerial, life, and social sciences, I had quite a few years of experience teaching mathematics to non-mathematics majors. One of the most important lessons I learned from my early experience teaching these courses is that many of the students come into these courses with some degree of apprehension. This awareness led to the intuitive approach I have adopted in all of my texts. As you will see, I try to introduce each abstract mathematical concept through an example drawn from a common, real-life experience. Once the idea has been conveyed, I then proceed to make it precise, thereby assuring that no mathematical rigor is lost in this intuitive treatment of the subject. Another lesson I learned from my students is that they have a much greater appreciation of the material if the applications are drawn from their fields of interest and from situations that occur in the real world. This is one reason you will see so many exercises in my texts that are modeled on data gathered from newspapers, magazines, journals, and other media. Whether it be the market for cholesterol-reducing drugs, financing a home, bidding for cable rights, broadband Internet households, or Starbucks’ annual sales, I weave topics of current interest into my examples and exercises to keep the book relevant to all of my readers.

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1

FUNDAMENTALS OF ALGEBRA

T

HIS CHAPTER CONTAINS a brief review of the algebra you

will use in this course. In the process of solving many

practical problems, you will need to solve algebraic equations. You will also need to simplify algebraic expressions. This chapter also contains a short review of inequalities and absolute value; their uses range from describing the domains of functions to

© AEP/Alamy

formulating practical problems.

Based on current projections for the gross domestic product (GDP) of a certain country, when will the GDP of the country first equal or exceed $58 billion? In Example 7, page 57, we will learn how to solve this problem.

2

1 FUNDAMENTALS OF ALGEBRA

1.1 Real Numbers The Set of Real Numbers We use real numbers every day to describe various quantities such as temperature, salary, annual percentage rate, shoe size, grade point average, and so on. Some of the symbols we use to represent real numbers are 3,

17,

22,

0.666. . . ,

113,

3.9,

0.12875

To construct the set of real numbers, we start with the set of natural numbers (also called counting numbers) N  {1, 2, 3, . . .}

and adjoin other numbers to it. The set W  {0, 1, 2, 3, . . .}

of whole numbers is obtained by adjoining the single number 0 to N. By adjoining the negatives of the natural numbers to the set W, we obtain the set of integers I  {. . . , 3, 2, 1, 0, 1, 2, 3, . . .}

Next, we consider the set Q of rational numbers, numbers of the form ab, where a and b are integers, with b  0. Using set notation, we write Q  {ab  a and b are integers, b  0}

Observe that I is contained in Q since each integer may be written in the form ab, with b  1. For example, the integer 6 may be written in the form 61. Symbolically, we express the fact that I is contained in Q by writing IQ 23 However, Q is not contained in I since fractions such as 12 and 25 are not integers. To show the relationships of the sets N, W, I, and Q, we write

NWIQ

This says that N is a proper subset of W, W is a proper subset of I, and so on.* Finally, we obtain the set of real numbers by adjoining the set of rational numbers to the set of irrational numbers (Ir)—numbers that cannot be expressed in the form a b , where a, b are integers (b  0). Examples of irrational numbers are 22, 23, ␲, and so on. Thus, the set R  Q  Ir

comprising all rational numbers and irrational numbers is called the set of real numbers. (See Figure 1.)

Q

FIGURE 1 The set of all real numbers consists of the set of rational numbers plus the set of irrational numbers.

W N

Ir

Q = Rationals I = Integers W = Whole numbers N = Natural numbers Ir = Irrationals

*A set A is a proper subset of a set B if every element of a set A is also an element of a set B and there exists at least one element in B that is not in A.

1.1 REAL NUMBERS

3

Representing Real Numbers as Decimals Every real number can be written as a decimal. A rational number can be represented as either a repeating or terminating decimal. For example, 32 is represented by the repeating decimal 0.66666666. . .

Repeating decimal—note that the integer 6 repeats.

which may also be written 0.6, where the bar above the 6 indicates that the 6 repeats indefinitely. The number 12 is represented by the terminating decimal 0.5

Terminating decimal

When an irrational number is represented as a decimal, it neither terminates nor repeats. For example, 22  1.41421. . .

and ␲  3.14159. . .

Table 1 summarizes this classification of real numbers. TABLE 1 The Set of Real Numbers

Set

Natural numbers Whole numbers Integers Rational numbers

Irrational numbers

Real numbers

Description

Examples

Decimal Representation

Counting numbers Counting numbers and 0 Natural numbers, their negatives, and 0 Numbers that can be written in the form ab, where a and b are integers and b ⬆ 0 Numbers that cannot be written in the form ab, where a and b are integers and b ⬆ 0 Rational and irrational numbers

1, 2, 3, . . . 0, 1, 2, 3, . . . . . . , 3, 2, 1, 0, 1, 2, 3, . . . 3, 43, 0.222 , 0, 56,  2, 4.3111

Terminating decimals Terminating decimals Terminating decimals

22, 23, ␲ 1.414213. . . , 1.732050. . . All of the above

Nonterminating, nonrepeating decimals

Terminating or repeating decimals

All types of decimals

Representing Real Numbers on a Number Line Real numbers may be represented geometrically by points on a line. This real number, or coordinate, line is constructed as follows: Arbitrarily select a point on a straight line to represent the number 0. This point is called the origin. If the line is horizontal, then choose a point at a convenient distance to the right of the origin to represent the number 1. This determines the scale for the number line. The point representing each positive real number x lies x units to the right of 0, and the point representing each negative real number x lies x units to the left of 0. Thus, real numbers may be represented by points on a line in such a way that corresponding to each real number there is exactly one point on a line, and vice versa. In this way, a one-to-one correspondence is set up between the set of real numbers and the set of points on the number line, with all the positive numbers lying to the right of the origin and all the negative numbers lying to the left of the origin (Figure 2). Origin Negative direction –4 FIGURE 2 The real number line

–3

–2

 2

–1

0

1 1 2

2

3

3



4

x

4

1 FUNDAMENTALS OF ALGEBRA

Operations with Real Numbers Two real numbers may be combined to obtain a real number. The operation of addition, written , enables us to combine any two numbers a and b to obtain their sum, denoted by a  b. Another operation, multiplication, written , enables us to combine any two real numbers a and b to form their product, the number a  b (more simply written ab). These two operations are subject to the rules of operation given in Table 2. TABLE 2 Rules of Operation for Real Numbers

Rule

Illustration

Under addition 1. a  b  b  a 2. a  (b  c)  (a  b)  c 3. a  0  a 4. a  (a)  0 Under multiplication 1. ab  ba 2. a(bc)  (ab)c 3. a  1  1  a

2332 4  (2  3)  (4  2)  3 606 5  (5)  0

Commutative law of addition Associative law of addition Identity law of addition Inverse law of addition

3223 4(3  2)  (4  3)2 4114

Commutative law of multiplication Associative law of multiplication Identity law of multiplication

1 4. a a b  1 (a  0) a Under addition and multiplication 1. a(b  c)  ab  ac

Inverse law of multiplication

1 3a b  1 3

Distributive law for multiplication with respect to addition

3(4  5)  3  4  3  5

The operation of subtraction is defined in terms of addition. Thus, a  (b)

where b is the additive inverse of b, may be written in the more familiar form a  b, and we say that b is subtracted from a. Similarly, the operation of division is defined in terms of multiplication. Recall that the multiplicative inverse of a nonzero real number b is 1b, also written b1. Then, 1 aa b b

is written ab, and we say that a is divided by b. Thus, 4 1 13 2  43. Remember, zero does not have a multiplicative inverse since division by zero is not defined. Do the operations of associativity and commutativity hold for subtraction and division? Looking first at associativity, we see that the answer is no since a  (b  c)  (a  b)  c

7  (4  2)  (7  4)  2, or 5  1

a  (b  c)  (a  b)  c

8  (4  2)  (8  4)  2, or 4  1

and

Similarly, commutativity does not hold because abba

7  4  4  7, or 3  3

abba

8  4  4  8, or 2 

and 1 2

1.1 REAL NUMBERS

5

EXAMPLE 1 State the real number property that justifies each statement. Statement

a. b. c. d. e.

Property

4  (x  2)  4  (2  x) (a  2b)  c  a  (2b  c) x( y  z  2)  ( y  z  2)x 4(xy2)  (4x)y2 x( y  2)  xy  2x

Commutative law of addition Associative law of addition Commutative law of multiplication Associative law of multiplication Distributive law for multiplication under addition

Using the properties of real numbers listed earlier, we can derive all other algebraic properties of real numbers. Some of the more important properties are given in Tables 3–5.

TABLE 3 Properties of Negatives

Property

1. 2. 3. 4.

TABLE 4

Illustration

(a)  a (a)b  (ab)  a(b) (a)(b)  ab (1)a  a

(6)  6 (3)4  (3  4)  3(4) (3)(4)  3  4 (1)5  5

TABLE 5

Properties Involving Zero

Properties of Quotients

Property

1. a  0  0 2. If ab  0, then a  0, b  0, or both.

Property

a c  if ad  bc b d ca a 2.  cb b

1.

3. 4. 5. 6. 7.

a a a   b b b a # c ac  b d bd ad a c a d   #  b d b c bc a c ad  bc   b d bd a c ad  bc   b d bd

Illustration

(b, d  0) (b, c  0) (b  0) (b, d  0) (b, c, d  0) (b, d  0) (b, d  0)

3 9  because 3  12  9  4 4 12 4 # 3 3  # 4 8 8 4 4 4   3 3 3 3 # 5 15  4 2 8 3 5 3 2 3   #  4 2 4 5 10 3 5 3 # 24 # 5 13    4 2 8 4 # # 5 3 24 5 7 3    4 2 8 4

In the rest of this book, we will assume that all variables are restricted so that division by zero is excluded. Note

6

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 2 State the real number property that justifies each statement. Statement

Property

a. (4)  4

Property 1 of negatives

b. c. d. e.

1 If (4x  1)(x  3)  0, then x  or x  3. 4 1x  1 2 1x  1 2 x1  x3 1x  1 2 1x  3 2 x1x  1 2 y1 x1 x1 # x    y x y y1 y1y  1 2 x1y  1 2  xy x x   y y1 y1y  1 2 

2xy  x xy  x  xy  y1y  1 2 y1y  1 2

Property 2 of zero properties Property 2 of quotients Property 5 of quotients Property 6 of quotients Distributive law

1.1 Self-Check Exercises State the property (or properties) that justify each statement.

3. (s  t)  s  t

1. (3√  2)  w  3√  (2  w)

4.

2. (3s)(4t)  3[s(4t)]

2 2  u√ 1u  √2

Solutions to Self-Check Exercises 1.1 can be found on page 7.

1.1 Concept Questions 1. What is a natural number? A whole number? An integer? A rational number? An irrational number? A real number? Give examples of each. 2. a. The associative law of addition states that a  (b  c)  . b. The distributive law states that ab  ac 

3. What can you say about a and b if ab ⬆ 0? How about a, b, and c if abc ⬆ 0?

.

1.1 Exercises In Exercises 1–10, classify the number as to type. (For example, 12 is rational and real, whereas 25 is irrational and real.)

1. 3 5. 211 21 9. 2.4

2. 420

3 3. 8

4 4.  125

6.  25

p 7. 2

2 8. p

10. 2.71828. . .

In Exercises 11–16, indicate whether the statement is true or false.

11. Every integer is a whole number. 12. Every integer is a rational number. 13. Every natural number is an integer. 14. Every rational number is a real number. 15. Every natural number is an irrational number. 16. Every irrational number is a real number.

7

1.2 POLYNOMIALS

In Exercises 17–36, state the real number property that justifies the statement.

21. u(2√  w)  2u√  uw

2x  1 2x  1

33.

a1a  b2 ab ab   b ab ab

34.

x  2y x  2y x   3x  y 6x  2y 3x  y

35.

c ab  bc  c a   bc b b1b  c2

36.

y x2  y xy   x1 x x1x  12

19. u(3√  w)  (3√  w)u 20. a2(b2c)  (a2b2)c



12x  12 1x  32

17. (2x  y)  z  z  (2x  y) 18. 3x  (2y  z)  (3x  2y)  z

12x  12 1x  32

32.

#

213x  y 2 x



21x  2y 2 x

2

22. (2u  √)w  2uw  √w 23. (2x  3y)  (x  4y)  2x  [3y  (x  4y)] 24. (a  2b)(a  3b)  a(a  3b)  2b(a  3b) 25. a  [(c  d )]  a  (c  d) 26. (2x  y)[(3x  2y)]  (2x  y)(3x  2y) 27. 0(2a  3b)  0 28. If (x  y)(x  y)  0, then x  y or x  y. 29. If (x  2)(2x  5)  0, then x  2 or x  52 . 30. If x(2x  9)  0, then x  0 or x  92 . 1x  1 2 1x  3 2

x1  31. 2x  1 12x  1 2 1x  32

In Exercises 37–42, indicate whether the statement is true or false.

37. If ab  1, then a  1 or b  1. 38. If ab  0 and a  0, then b  0. 39. a  b  b  a 40. a  b  b  a 41. (a  b)  c  a  (b  c) 42. a  (b  c)  (a  b)  c

1.1 Solutions to Self-Check Exercises 1. Associative law of addition: a  (b  c)  (a  b)  c

4. Property 3 of quotients:

2. Associative law of multiplication: a(bc)  (ab)c

a a a   b b b

3. Distributive law for multiplication: a(b  c)  ab  ac Properties 1 and 4 of negatives: (a)  a; (1)a  a

1.2 Polynomials Exponents

Expressions such as 25, (3)2, and 1 14 2 4 are exponential expressions. More generally, if n is a natural number and a is a real number, then an represents the product of the real number a and itself n times.

Exponential Notation

If a is a real number and n is a natural number, then an  a  a  a  . . .  a 34  3  3  3  3  n factors

 4 factors

The natural number n is called the exponent, and the real number a is called the base.

8

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 1 a. 44  (4)(4)(4)(4)  256 b. (5)3  (5)(5)(5)  125 1 1 1 1 1 3 c. a b  a b a b a b  2 2 2 2 8 2 1 1 1 1 d. a b  a b a b  3 3 3 9 When we evaluate expressions such as 32  33, we use the following property of exponents to write the product in exponential form.

Property 1

If m and n are natural numbers and a is any real number, then a m  a n  a mn

32  33  323  35

To verify that Property 1 follows from the definition of an exponential expression, we note that the total number of factors in the exponential expression am  an  a  a  a      a  m factors



aaaa  n factors

is m  n. EXAMPLE 2 a. 32  33  323  35  243 b. (2)2  (2)5  (2)25  (2)7  128 c. (3x)  (3x)3  (3x)13  (3x)4  81x 4 Be careful to apply the exponent to the indicated base only. Note that — The exponent applies to 4x. 앗

4  x  4x  (4x)2  42  x 2  16x 2 2

2

앖— The exponent applies only to the base x.

and — The exponent applies to 3. 앗

32  9  (3)2  9

앖— The exponent applies only to the base 3.

Polynomials Recall that a variable is a letter that is used to represent any element of a given set. However, unless specified otherwise, variables in this text will represent real numbers. Sometimes physical considerations impose restrictions on the values a variable may assume. For example, if the variable x denotes the number of television sets sold daily in an appliance store, then x must be a nonnegative integer. At other times, restrictions must be imposed on x in order for an expression to make sense. For example, in the expression x 1 2, x cannot take on the value 2 since division by 0 is not permitted. We call the set of all real numbers that a variable is allowed to assume the domain of the variable.

1.2 POLYNOMIALS

9

In contrast to a variable, a constant is a fixed number or letter whose value remains fixed throughout a particular discussion. For example, in the expression 12 tt2, which gives the distance in feet covered by a free-falling body near the surface of Earth, t seconds from rest, the letter t represents the constant of acceleration due to gravity (approximately 32 feet/second/second), whereas the letter t is a variable with domain consisting of nonnegative real numbers. By combining constants and variables through the use of addition, subtraction, multiplication, division, exponentiation, and root extraction, we obtain algebraic expressions. Examples of algebraic expressions are 3x  4y

2x 2  y 

1 xy

ax  b 1  x2

3xy2  p x2  y2  z2

where a and b are constants and x, y, and z are variables. Intimidating as some of these expressions might be, remember that they are just real numbers. For example, if x  1 and y  4, then the second expression represents the number 2(1)2  4 

1 112 142

or 74, obtained by replacing x and y in the expression by the appropriate values. Polynomials are an important class of algebraic expressions. The simplest polynomials are those involving one variable.

Polynomial in One Variable

A polynomial in x is an expression of the form an x n  an1x n1      a1x  a0

where n is a nonnegative integer and a0, a1, . . . , an are real numbers, with an  0. The expressions ak x k in the sum are called the terms of the polynomial. The numbers a0, a1, . . . , an are called the coefficients of 1, x, x 2, . . . , x n, respectively. The coefficient an of x n (the highest power in x) is called the leading coefficient of the polynomial. The nonnegative integer n gives the degree of the polynomial. For example, consider the polynomial 2x 5  8x 3  6x 2  3x  1

1. 2. 3. 4.

The terms of the polynomial are 2x 5, 8x 3, 6x 2, 3x, and 1. The coefficients of 1, x, x 2, x 3, x 4, and x 5 are 1, 3, 6, 8, 0, and 2, respectively. The leading coefficient of the polynomial is 2. The degree of the polynomial is 5.

A polynomial having just one term (such as 2x 3) is called a monomial; a polynomial having exactly two terms (such as x 3  x) is called a binomial; and a polynomial having only three terms (such as 2x 3  x  8) is called a trinomial. Also, a polynomial consisting of one (constant) term a0 (such as the monomial 8) is called a constant polynomial. Observe that the degree of a constant polynomial a0, with a0  0, is 0 because we can write a0  a0 x 0 and see that n  0 in this situation. If all the coefficients of a polynomial are 0, it is called the zero polynomial and is denoted by 0. The zero polynomial is not assigned a degree.

10

1 FUNDAMENTALS OF ALGEBRA

Most of the terminology used for a polynomial in one variable carries over to the discussion of polynomials in several variables. But the degree of a term in a polynomial in several variables is obtained by adding the powers of all variables in the term, and the degree of the polynomial is given by the highest degree of all its terms. For example, the polynomial 2x 2y 5  3xy 3  8xy 2  3y  4

is a polynomial in the two variables x and y. It has five terms with degrees 7, 4, 3, 1, and 0, respectively. Accordingly, the degree of the polynomial is 7.

Adding and Subtracting Polynomials Constant terms and terms having the same variable and exponent are called like or similar terms. Like terms may be combined by adding or subtracting their numerical coefficients. For example, 3x  7x  (3  7)x  10x

Add like terms.

and 1 2 1 5 m  3m2  a  3 b m2   m2 2 2 2

Subtract like terms.

The distributive property of the real number system, ab  ac  a(b  c)

is used to justify this procedure. To add or subtract two or more polynomials, first remove the parentheses and then combine like terms. The resulting expression is then written in order of decreasing degree from left to right. EXAMPLE 3 a. (3x 3  2x 2  4x  5)  (2x 3  2x 2  2)  3x 3  2x 2  4x  5  2x 3  2x2  2  3x 3  2x 3  2x2  2x 2  4x  5  2  x 3  4x  3 b. (2x 4  3x 3  4x  6)  (3x 4  9x 3  3x 2)  2x 4  3x 3  4x  6  3x 4  9x 3  3x 2

 2x 4  3x 4  3x 3  9x 3  3x 2  4x  6  x 4  6x 3  3x 2  4x  6

Remove parentheses. Group like terms together. Combine like terms.

Remove parentheses. Note that the minus sign preceding the second polynomial changes the sign of each term of that polynomial. Group like terms. Combine like terms.

Multiplying Polynomials To find the product of two polynomials, we again use the distributive property for real numbers. For example, to compute the product 3x(4x  2), we use the distributive law to obtain 3x(4x  2)  (3x)(4x)  (3x)(2)  12x 2  6x

a(b  c)  ab  ac

Observe that each term of one polynomial is multiplied by each term of the other. The resulting expression is then simplified by combining like terms. In general, an algebraic expression is simplified if none of its terms are similar.

1.2 POLYNOMIALS

11

EXAMPLE 4 Find the product of (3x  5)(2x  3). Solution

(3x  5)(2x  3)  3x(2x  3)  5(2x  3)  (3x)(2x)  (3x)(3)  (5)(2x)  (5)(3)  6x 2  9x  10x  15  6x 2  x  15

Distributive property Distributive property Multiply terms. Combine like terms.

EXAMPLE 5 Find the product of (2t 2  t  3)(2t 2  1). Solution

(2t 2  t  3)(2t 2  1)  2t 2(2t 2  1)  t(2t 2  1)  3(2t 2  1)  (2t 2)(2t 2)  (2t 2)(1)  (t)(2t 2)  (t)(1)  (3)(2t 2)  (3)(1)  4t 4  2t 2  2t 3  t  6t 2  3  4t 4  2t 3  4t 2  t  3

Distributive property Distributive property Multiply terms. Combine terms.

Alternate Solution We can also find the product by arranging the polynomials vertically and multiplying: 2t 2  t  3 2t 2  1 4t 4  2t 3  6t 2  2t 2  t  3 4t 4  2t 3  4t 2  t  3

The polynomials in Examples 4 and 5 are polynomials in one variable. The operations of addition, subtraction, and multiplication are performed on polynomials of more than one variable in the same way as they are for polynomials in one variable. EXAMPLE 6 Multiply (3x  y)(4x 2  2y). Solution

(3x  y)(4x 2  2y)  3x(4x 2  2y)  y(4x 2  2y)  12x 3  6xy  4x 2y  2y 2  12x 3  4x 2y  6xy  2y 2

Distributive property Distributive property Arrange terms in order of descending powers of x.

Several commonly used products of polynomials are summarized in Table 6. Since products of this type occur so frequently, you will find it helpful to memorize these formulas. TABLE 6 Special Products

Formula

1. (a  b)2  a2  2ab  b2 2. (a  b)2  a2  2ab  b2 3. (a  b)(a  b)  a2  b2

Illustration

(2x  3y)2  (2x)2  2(2x)(3y)  (3y)2  4x 2  12xy  9y 2 2 (4x  2y)  (4x)2  2(4x)(2y)  (2y)2  16x 2  16xy  4y 2 (2x  y)(2x  y)  (2x)2  ( y)2  4x 2  y2

12

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 7 Use the special product formulas to compute: a. (2x  y)2

b. (3a  4b)2

1 1 c. a x  1 b a x  1 b 2 2

Solution

a. (2x  y)2  (2x)2  2(2x)( y)  y 2  4x 2  4xy  y 2 b. (3a  4b)2  (3a)2  2(3a)(4b)  (4b)2  9a2  24ab  16b2 2 1 1 1 1 c. a x  1 b a x  1 b  a x b  1  x 2  1 2 2 2 4

Formula 1 Formula 2

Formula 3

Order of Operations The common steps in Examples 1–7 have been to remove parentheses and combine like terms. If more than one grouping symbol is present, the innermost symbols are removed first. As you work through Examples 8 and 9, note the order in which the grouping symbols are removed: parentheses ( ) first, brackets [ ] second, and finally braces { }. Also, note that the operations of multiplication and division take precedence over addition and subtraction. EXAMPLE 8 Perform the indicated operations: 2t 3  {t 2  [t  (2t  1)]  4} Solution

2t 3  {t 2  [t  (2t  1)]  4}  2t 3  {t 2  [t  2t  1]  4}  2t 3  {t 2  [t  1]  4}  2t 3  {t 2  t  1  4}  2t 3  {t 2  t  3}  2t 3  t 2  t  3

Remove parentheses. Combine like terms within the brackets. Remove brackets. Combine like terms within the braces. Remove braces.

EXAMPLE 9 Simplify 2{3  2[x  2x(3  x)]}. Solution

2{3  2[x  2x(3  x)]}  2{3  2[x  6x  2x 2]}  2{3  2[5x  2x 2]}  2{3  10x  4x 2}  6  20x  8x 2  8x 2  20x  6

Remove parentheses. Combine like terms. Remove brackets. Remove braces. Write answer in order of descending powers of x.

1.2 Self-Check Exercises 1. Find the product of (2x  3y)(3x  2y).

2. Simplify 3x  2{2x  [x  2(x  2)]  1}. Solutions to Self-Check Exercises 1.2 can be found on page 14.

1.2 POLYNOMIALS

13

1.2 Concept Questions 1. Describe a polynomial of degree n in x. Give an example of a polynomial of degree 4 in x.

2. Without looking at the text, complete the following formulas: a. (1  b)2  ______ b. (a  b)2  ______ c. (a  b)(a  b)  ______

1.2 Exercises 41. (2u  √)(2u  √)

In Exercises 1–12, evaluate the expression.

1. 34 2 3. a b 3

2. (2)5 3 4. a b 4

3

3 7. 2 a b 5

2

9. 23  25 11. (3y)2(3y)3

44. (3m  2)2  2m(1  m)  4 3

2 3 8. a b a b 3 4

3

2

46. (x  2y)( y  3x)  2xy  3(x  y  1) 3

10. (3)2  (3)3 12. (2x)3(2x)2

In Exercises 13–56, perform the indicated operations and simplify.

13. (2x  3)  (4x  6)

2

45. (2x  3y)2  (2y  1)(3x  2)  2(x  y)

4 6.  a b 5

5. 43

42. (3r  4s)(3r  4s)

43. (2x  1)  3x  2(x  1)  3 2

14. (3x  2)  (4x  3)

47. (t 2  2t  4)(2t 2  1)

48. (3m 2  1)(2m 2  3m  4)

49. 2x  {3x  [x  (2x  1)]} 50. 3m  2{m  3[2m  (m  5)]  4} 51. x  {2x  [x  (1  x)]} 52. 3x 2  {x 2  1  x[x  (2x  1)]}  2 53. (2x  3)2  3(x  4)(x  4)  2(x  4)  1 54. (x  2y)2  2(x  y)(x  3y)  x(2x  3y  2)

15. (7x 2  2x  5)  (2x 2  5x  4)

55. 2x{3x[2x  (3  x)]  (x  1)(2x  3)}

16. (3x 2  5xy  2y)  (4  3xy  2x 2)

56. 3[(x  2y)2  (3x  2y)2  (2x  y)(2x  y)]

17. (5y 2  2y  1)  (y 2  3y  7)

57. MANUFACTURING PROFIT The total revenue realized in the sale of x units of the LectroCopy photocopying machine is

18. (2x 2  3x  4)  (x 2  2x  6) 19. (2.4x 3  3x 2  1.7x  6.2)  (1.2x 3  1.2x 2  0.8x  2) 20. (1.4x 3  1.2x 2  3.2)  (0.8x 3  2.1x  1.8) 21. (3x 2)(2x 3)

22. (2rs 2)(4r 2s 2)(2s)

23. 2x(x 2  2)  4x 3

24. xy(2y  3x)

25. 2m(3m  4)  m(m  1)

0.04x 2  2000x

dollars/week, and the total cost incurred in manufacturing x units of the machines is 0.000002x 3  0.02x 2  1000x  120,000

dollars/week (0 x 50,000). Find an expression giving the total weekly profit of the company. Hint: The profit is revenue minus cost.

26. 3x(2x 2  3x  5)  2x(x 2  3) 27. 3(2a  b)  4(b  2a) 28. 2(3m  1)  3(4m  2n) 29. (2x  3)(3x  2)

30. (3r  1)(2r  5)

31. (2x  3y)(3x  2y)

32. (5m  2n)(5m  3n)

33. (3r  2s)(4r  3s)

34. (2m  3n)(3m  2n)

35. (0.2x  1.2y)(0.3x  2.1y) 36. (3.2m  1.7n)(4.2m  1.3n) 37. (2x  y)(3x 2  2y)

38. (3m  2n 2)(2m 2  3n)

39. (2x  3y)2

40. (3m  2n)2

58. MANUFACTURING PROFIT A manufacturer of tennis rackets finds that the total cost of manufacturing x rackets/day is given by 0.0001x 2  4x  400

dollars. Each racket can be sold at a price of p dollars, where p  0.0004x  10

Find an expression giving the daily profit for the manufacturer, assuming that all the rackets manufactured can be sold. Hint: The total revenue is given by the total number of rackets sold multiplied by the price of each racket. The profit is given by revenue minus cost.

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1 FUNDAMENTALS OF ALGEBRA

59. PRISON OVERCROWDING The 1980s saw a trend toward old-fashioned punitive deterrence as opposed to the more liberal penal policies and community-based corrections popular in the 1960s and early 1970s. As a result, prisons became more crowded, and the gap between the number of people in prison and prison capacity widened. Based on figures from the U.S. Department of Justice, the number of prisoners (in thousands) in federal and state prisons is approximately 3.5t 2  26.7t  436.2

(0 t 10)

and the number of inmates (in thousands) for which prisons were designed is given by 24.3t  365

(0 t 10)

where t is measured in years and t  0 corresponds to 1984. Find an expression giving the gap between the number of prisoners and the number for which the prisons were designed at any time t.

1.1t 2  29.1t  429

(0 t 6)

where t has the same meaning as before. Find an expression for the difference between private and government expenditures per person at any time t. What was the difference between private and government expenditures per person at the beginning of 1998? At the beginning of 2000? Source: Health Care Financing Administration

In Exercises 61–64, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

61. If m and n are natural numbers and a and b are real numbers, then am  bn  (ab)mn. 62. a16  b16  (a8  b8)(a4  b4)(a2  b2)(a  b)(a  b)

Source: U.S. Dept. of Justice

60. HEALTH-CARE SPENDING Health-care spending per person (in dollars) by the private sector includes payments by individuals, corporations, and their insurance companies and is approximated by 2.5t 2  18.5t  509

ing (in dollars), including expenditures for Medicaid and other federal, state, and local government public health care, is

(0 t 6)

where t is measured in years and t  0 corresponds to the beginning of 1994. The corresponding government spend-

63. The degree of the product of a polynomial of degree m and a polynomial of degree n is mn. 64. Suppose p and q are polynomials of degree n. Then p  q is a polynomial of degree n. 65. Suppose p is a polynomial of degree m and q is a polynomial of degree n, where m  n. What is the degree of p  q?

1.2 Solutions to Self-Check Exercises 1. (2x  3y)(3x  2y)  2x(3x  2y)  3y(3x  2y)  6x 2  4xy  9xy  6y 2  6x 2  5xy  6y 2

2. 3x  2{2x  [x  2(x  2)]  1}  3x  2{2x  [x  2x  4]  1}  3x  2{2x  [x  4]  1}  3x  2{2x  x  4  1}  3x  2{3x  3}  3x  6x  6  3x  6

1.3 Factoring Polynomials Factoring Factoring a polynomial is the process of expressing it as a product of two or more polynomials. For example, by applying the distributive property we may write 3x 2  x  x(3x  1)

and we say that x and 3x  1 are factors of 3x 2  x. How do we know if a polynomial is completely factored? Recall that an integer greater than 1 is prime if its only positive integer factors are itself and 1. For example, the number 3 is prime because its only factors are 3 and 1. In the same way, a polynomial is said to be prime over the set of integral coefficients if it cannot be expressed as a product of two or more polynomials of positive degree with integral coefficients.

1.3 FACTORING POLYNOMIALS

15

For example, x 2  2x  2 is a prime polynomial relative to the set of integers, whereas x 2  9 is not a prime polynomial, since x 2  9  (x  3)(x  3). Finally, a polynomial is said to be completely factored over the set of integers if it is expressed as a product of prime polynomials with integral coefficients. Note Unless otherwise mentioned, we will only consider factorization over the set of integers in this text. Hence, when the term factor is used, it will be understood that the factorization is to be completed over the set of integers.

Common Factors The first step in factoring a polynomial is to check to see if it contains any common factors. If it does, the common factor of highest degree is then factored out. For example, the greatest common factor of 2a2x  4ax  6a is 2a because 2a2x  4ax  6a  2a  ax  2a  2x  2a  3  2a(ax  2x  3)

EXAMPLE 1 Factor out the greatest common factor. a. 3t 2  3t

b. 6a4b4c  9a2b2

Solution

a. Since 3t is a common factor of each term, we have 3t 2  3t  3t(t  1)  3t(1  t)

b. Since 3a2b2 is the common factor of highest degree, we have 6a4b4c  9a2b2  3a2b2(2a2b2c  3)

Some Important Formulas Having checked for common factors, the next step in factoring a polynomial is to express the polynomial as the product of a constant and/or one or more prime polynomials. The formulas given in Table 7 for factoring polynomials should be memorized. TABLE 7 Factoring Formulas

Formula

Difference of two squares a2  b2  (a  b)(a  b)

Perfect square trinomial a2  2ab  b2  (a  b)2 a2  2ab  b2  (a  b)2 Sum of two cubes a3  b3  (a  b)(a2  ab  b2) Difference of two cubes a3  b3  (a  b)(a2  ab  b2)

Illustration

x 2  36  (x  6)(x  6) 8x 2  2y 2  2(4x 2  y 2)  2[(2x)2  y 2]  2(2x  y)(2x  y) 9  a6  32  (a3)2  (3  a3)(3  a3) x 2  8x  16  (x  4)2 4x 2  4xy  y 2  (2x)2  2(2x)(y)  y 2  (2x  y)2 z 3  27  z 3  (3)3  (z  3)(z 2  3z  9) 8x 3  y 6  (2x)3  ( y 2)3  (2x  y 2)(4x 2  2xy 2  y 4)

16

1 FUNDAMENTALS OF ALGEBRA

Note Observe that a formula is given for factoring the sum of two cubes, but none is given for factoring the sum of two squares since x 2  a 2 is prime over the set of integers.

EXAMPLE 2 Factor: a. x 2  9

b. 16x 2  81y 4

c. (a  b)2  (a2  b)2

Solution Observe that each of the polynomials in parts (a)–(c) is the difference of two squares. Using the formula given in Table 7, we have

a. x 2  9  x 2  32  (x  3)(x  3) b. 16x 2  81y 4  (4x)2  (9y 2)2  (4x  9y 2)(4x  9y 2) c. (a  b)2  (a2  b)2  [(a  b)  (a2  b)][(a  b)  (a2  b)]  [a  b  a2  b][a  b  a2  b] Remove parentheses.  (a  a2)(a2  a  2b) Combine like terms.  a(1  a)(a2  a  2b)

EXAMPLE 3 Factor: a. x 2  4xy  4y 2

b. 4a2  12ab  9b2

Recognizing each of these polynomials as a perfect square trinomial, we use the formula given in Table 7 to factor each polynomial. Thus, Solution

a. x 2  4xy  4y 2  x 2  2x(2y)  (2y)2  (x  2y)(x  2y)  (x  2y)2 b. 4a2  12ab  9b2  (2a)2  2(2a)(3b)  (3b)2  (2a  3b)(2a  3b)  (2a  3b)2

EXAMPLE 4 Factor: a. x 3  8y 3

b. 27a3  64b3

Solution

a. This polynomial is the sum of two cubes. Using the formula given in Table 7, we have x 3  8y 3  x 3  (2y)3  (x  2y)[x 2  x(2y)  (2y)2]  (x  2y)(x 2  2xy  4y 2)

b. Using the formula for the difference of two cubes, we have 27a3  64b3  [(3a)3  (4b)3]  (3a  4b)[(3a)2  (3a)(4b)  (4b)2]  (3a  4b)(9a2  12ab  16b2)

Trial-and-Error Factorization The factors of the second-degree polynomial px 2  qx  r, where p, q, and r are integers, have the form (ax  b)(cx  d )

where ac  p, ad  bc  q, and bd  r. Since only a limited number of choices are possible, we use a trial-and-error method to factor polynomials having this form. For example, to factor x 2  2x  3, we first observe that the only possible firstdegree terms are (x

)(x

)

Since the coefficient of x 2 is 1

1.3 FACTORING POLYNOMIALS

17

Next, we observe that the product of the constant terms is (3). This gives us the following possible factors: (x  1)(x  3) (x  1)(x  3) Looking once again at the polynomial x 2  2x  3, we see that the coefficient of x is 2. Checking to see which set of factors yields 2 for the coefficient of x, we find that Coefficients of inner terms 앚 Coefficients of outer terms 앗 앗

(1)(1)  (1)(3)  2 Coefficients of inner terms 앚 Coefficients of outer terms 앗 앗

(1)(1)  (1)(3)  2

Factors Outer terms 앗 앗 (x  1)(x  3) 앖앖 Inner terms Outer terms 앗 앗 (x  1)(x  3) 앖앖 Inner terms

and we conclude that the correct factorization is x 2  2x  3  (x  1)(x  3)

With practice, you will soon find that you can perform many of these steps mentally, and you will no longer need to write out each step. EXAMPLE 5 Factor: a. 3x 2  4x  4

b. 3x 2  6x  24

Solution

a. Using trial and error, we find that the correct factorization is 3x 2  4x  4  (3x  2)(x  2)

b. Since each term has the common factor 3, we have 3x 2  6x  24  3(x 2  2x  8)

Using the trial-and-error method of factorization, we find that x 2  2x  8  (x  4)(x  2)

Thus, we have 3x 2  6x  24  3(x  4)(x  2)

Factoring by Regrouping Sometimes a polynomial may be factored by regrouping and rearranging terms so that a common term can be factored out. This technique is illustrated in Example 6. EXAMPLE 6 Factor: a. x 3  x  x 2  1

b. 2ax  2ay  bx  by

Solution

a. We begin by rearranging the terms in order of descending powers of x. Thus, x3  x  x2  1  x3  x2  x  1  x 2(x  1)  x  1  (x  1)(x 2  1)

Factor the first two terms. Factor the common term x  1.

18

1 FUNDAMENTALS OF ALGEBRA

b. First, factor the common term 2a from the first two terms and the common term b from the last two terms. Thus, 2ax  2ay  bx  by  2a(x  y)  b(x  y) Since (x  y) is common to both terms of the polynomial on the right, we can factor it out. Hence, 2a(x  y)  b(x  y)  (x  y)(2a  b)

More Examples on Factoring EXAMPLE 7 Factor: a. 4x 6  4x 2

b. 18x 4  3x 3  6x 2

Solution

a. 4x 6  4x 2  4x 2(x4  1)  4 x2(x2  1)(x 2  1)  4x 2(x  1)(x  1)(x 2  1) 4 3 b. 18x  3x  6x 2  3x 2(6x 2  x  2)  3x 2(3x  2)(2x  1)

Common factor Difference of two squares Difference of two squares Common factor Trial-and-error factorization

EXAMPLE 8 Factor: a. 3x 2y  9x 2  12y  36

b. (x  at)3  (x  at)3

Solution

a. 3x 2y  9x 2  12y  36  3(x 2y  3x 2  4y  12) Common factor  3[x 2(y  3)  4( y  3)] Regrouping  3(y  3)(x2  4) Common factor  3(y  3)(x  2)(x  2) Difference of two squares b. (x  at)3  (x  at)3  [(x  at)  (x  at)]  [(x  at)2  (x  at)(x  at)  (x  at)2] Difference of two cubes  2at(x 2  2atx  a2t 2  x 2  a2t 2  x 2  2atx  a2t 2)  2at(3x 2  a2t 2) Be sure you become familiar with the factorization methods discussed in this chapter because we will be using them throughout the text. As with many other algebraic techniques, you will find yourself becoming more proficient at factoring as you work through the exercises.

1.3 Self-Check Exercises 1. Factor: a. 4x 3  2x 2

b. 3(a2  2b2)  4(a2  2b2)2

2. Factor: a. 6x 2  x  12

b. 4x 2  10x  6

Solutions to Self-Check Exercises 1.3 can be found on page 19.

1.3 Concept Questions 1. What is meant by the expression “factor a polynomial”? Illustrate the process with an example.

2. Without looking at the text, complete the following formulas: a. a 3  b3  ______ b. a 3  b3  ______

1.3 FACTORING POLYNOMIALS

19

1.3 Exercises 37. 8m3  1

38. 27m3  8

39. 8r 3  27s 3

40. x 3  64y 3

41. u 2√ 6  8u 2

42. r 6s 6  8s 3

5. 10m n  15mn  20mn

43. 2x 3  6x  x 2  3

44. 2u 4  4u2  2u2  4

6. 6x 4y  4x 2y 2  2x 2y 3

45. 3ax  6ay  bx  2by

46. 6ux  4uy  3√x  2√y

7. 3x(2x  1)  5(2x  1)

47. u  √

48. u 4  u 2√ 2  6√ 4

In Exercises 1–10, factor out the greatest common factor.

1. 6m  2m

2. 4t  12t

3. 9ab2  6a2b

4. 12x 3y 5  16x 2y 3

2

4

2

3

2

4

8. 2u(3√ 2  w)  5√(3√ 2  w)

4

49. 4x 3  9xy 2  4x 2y  9y 3 50. 4u 4  11u 2√ 2  3√ 4

9. (3a  b)(2c  d)  2a(2c  d )

2

51. x 4  3x 3  2x  6

52. a 2  b2  a  b

10. 4u√ 2(2u  √)  6u 2√(√  2u)

53. au 2  (a  c)u  c

54. ax 2  (1  ab)xy  by 2

In Exercises 11–54, factor the polynomial. If the polynomial is prime, state it.

55. SIMPLE INTEREST The accumulated amount after t yr when a deposit of P dollars is made in a bank and earning interest at the rate of r/year is A  P  Prt. Factor the expression on the right-hand side of this equation.

11. 2m2  11m  6

12. 6x 2  x  1

13. x 2  xy  6y 2

14. 2u 2  5u√  12√ 2

15. x 2  3x  1

16. m2  2m  3

17. 4a2  b2

18. 12x 2  3y 2

19. u 2√ 2  w 2

20. 4a2b2  25c2

21. z 2  4

22. u 2  25√ 2

23. x 2  6xy  y 2

24. 4u 2  12u√  9√ 2

25. x 2  3x  4

26. 3m3  3m2  18m

27. 12x y  10xy  12y

28. 12x y  2xy  24y

29. 35r  r  12

30. 6u√ 2  9u√  6√

31. 9x 3y  xy 3

32. 4u 4√  9u2√ 3

33. x  16y

34. 16u √  9√

2

57. REACTION TO A DRUG The strength of a human body’s reaction to a dosage D of a certain drug, where k is a positive constant, is given by D3 kD2  2 3

2

2

4

56. SPREAD OF AN EPIDEMIC The incidence (number of new cases/day) of a contagious disease spreading in a population of M people, where k is a positive constant and x denotes the number of people already infected, is given by kMx  kx 2. Factor this expression.

2

4

35. (a  2b)2  (a  2b)2

Factor this expression.

3

36. 2x(x  y)2  8x(x  y 2)2

58. REVENUE The total revenue realized by the Apollo Company from the sale of x PDAs is given by R(x)  0.1x 2  500x dollars. Factor the expression on the right-hand side of this equation.

1.3 Solutions to Self-Check Exercises 1. a. The common factor is 2x 2. Therefore,

b. We first factor out the common factor 2. Thus, 4x 2  10x  6  2(2x 2  5x  3)

4x  2x  2x (2x  1) 3

2

2

b. The common factor is a2  2b2. Therefore, 3(a  2b )  4(a  2b )  (a  2b )[3  4(a  2b )] 2

2

2

2 2

2

2

2

2

 (a2  2b2)(3  4a2  8b2)

2. a. Using the trial-and-error method of factorization, we find that 6x 2  x  12  (3x  4)(2x  3)

Using the trial-and-error method of factorization, we find that 2x 2  5x  3  (2x  1)(x  3)

and, consequently, 4x 2  10x  6  2(2x  1)(x  3)

20

1 FUNDAMENTALS OF ALGEBRA

1.4 Rational Expressions Quotients of polynomials are called rational expressions. Examples of rational expressions are 6x  1 2x  3

and

3x 2y 3  2xy 4x  y

Because division by zero is not allowed, the denominator of a rational expression must not be equal to zero. Thus, in the first example, x  32, and in the second example, y  4x. Since rational expressions are quotients in which the variables represent real numbers, the properties of real numbers apply to rational expressions as well. For this reason, operations with rational fractions are performed in the same way as operations with arithmetic fractions.

Simplifying Rational Expressions A rational expression is simplified, or reduced to lowest terms, if its numerator and denominator have no common factors other than 1 and 1. If a rational expression does contain common factors, we use the properties of the real number system to write ac a  bc b

# ca # 1a c

b

b

(a, b, c are real numbers, and bc  0.)

This process is often called “canceling common factors.” To indicate this process, we often write ac a  bc b

where a slash is shown through the common factors. As another example, the rational expression 1x  22 1x  32

(x  2, 3)

1x  22 1x  32

is simplified by canceling the common factors (x  3) and writing 1x  22 1x  32 1x  22 1x  32



x2 x2

3  4x  1  4x is an example of incorrect cancellation. Instead we write 3 3  4x 3 4x 4x   1 3 3 3 3

EXAMPLE 1 Simplify: a.

x 2  2x  3 x 2  4x  3

b.

3  4x  4x2 2x  1

c.

1k  4 2 2 1k  1 2 k 2  16

Solution

a.

1x  3 2 1x  1 2 x1 x 2  2x  3   2 x1 1x  3 2 1x  1 2 x  4x  3

Factor numerator and denominator and cancel common factors.

1.4 RATIONAL EXPRESSIONS

b.

11  2x 2 13  2x 2 3  4x  4x 2  2x  1 2x  1 

12x  1 2 12x  3 2

Rewrite the term 1  2x in the equivalent form (2x  1).

2x  1

 (2x  3)

1k  42 1k  1 2 2

c.

21

k  16 2

1k  4 2 1k  1 2

Cancel common factors.

2



1k  4 2 1k  4 2



1k  4 2 1k  12 k4

Multiplication and Division The operations of multiplication and division are performed with rational expressions in the same way they are with arithmetic fractions (Table 8).

TABLE 8 Multiplication and Division of Rational Expressions

Operation

Illustration

If P, Q, R, and S are polynomials, then Multiplication P # R PR  Q S QS Division P R P   Q S Q

#

2x y

(Q, S  0)

S PS  R QR

#

1x  12

1y  12



2x1x  12 y1y  12

y2  1 x2  3 x2  3   y x y

(Q, R, S  0)

#

x1x 2  32 x  y2  1 y1y 2  12

When rational expressions are multiplied and divided, the resulting expressions should be simplified. EXAMPLE 2 Perform the indicated operations and simplify. a.

2x  8 x2

#

x 2  4x  4 x 2  16

#

x 2  4x  4 x 2  16

b.

x2  9 x 2  6x  9  2 3x  12 6x  18x

Solution

a.

2x  8 x2   

21x  4 2 x2

#

1x  2 2 2

1x  4 2 1x  4 2

Factor numerators and denominators.

21x  4 2 1x  22 1x  2 2 1x  2 2 1x  42 1x  4 2

21x  2 2 x4

Cancel the common factors (x  2)(x  4).

22

1 FUNDAMENTALS OF ALGEBRA

b.

x 2  6x  9 x 2  6x  9 x2  9  2  3x  12 3x  12 6x  18x 2 1x  32 # 6x1x  32  31x  4 2 1x  3 2 1x  3 2 1x  32 1x  3 2 16x 2 1x  3 2  31x  4 2 1x  3 2 1x  3 2 2x1x  3 2  x4

#

6x 2  18x x2  9

Addition and Subtraction For rational expressions the operations of addition and subtraction are performed by finding a common denominator for the fractions and then adding or subtracting the fractions. Table 9 shows the rules for fractions with common denominators. TABLE 9 Adding and Subtracting Fractions with Common Denominators

Operation

Illustration

If P, Q, and R are polynomials, then Addition Q PQ P   R R R Subtraction Q PQ P   R R R

(R  0)

2x 6x 2x  6x 8x    x2 x2 x2 x2

(R  0)

3y y 3y  y 2y    yx yx yx yx

To add or subtract fractions that have different denominators, first find a common denominator, preferably the least common denominator (LCD). To find the LCD of two or more rational expressions, follow these steps: 1. Find the prime factors of each denominator. 2. Form the product of the different prime factors that occur in the denominators. Raise each prime factor in this product to the highest power of that factor appearing in the denominators. After finding the LCD, carry out the indicated operations following the procedure for adding and subtracting fractions with common denominators. EXAMPLE 3 Simplify: a.

4y  2 3x  4  4x 3y

b.

3x  1 2x  2 x 1 2x  x  1 2

c.

1 1  x xh

Solution

a.

4y  2 3x  4 3y 3x  4 #  4y  2 # 4x   4x 3y 4x 3y 3y 4x 16xy  8x 9xy  12y   12xy 12xy 25xy  8x  12y  12xy

LCD  (4x)(3y)  12xy

1.4 RATIONAL EXPRESSIONS

b.

23

3x  1 2x 3x  1 2x  2   1x  1 2 1x  12 12x  1 2 1x  1 2 x 1 2x  x  1 LCD  2x12x  1 2  13x  1 2 1x  12 (2x  1)   1x  1 2 1x  1 2 12x  1 2 (x  1)(x  1) 2

4x 2  2x  3x 2  3x  x  1 1x  1 2 1x  1 2 12x  1 2 7x 2  6x  1  1x  1 2 1x  1 2 12x  12 

c.

1 1 1 # x 1 xh    # x x x xh xh xh xh x   x1x  h 2 x1x  h 2

LCD  x(x  h)

xxh x1x  h 2 h  x1x  h 2 

Compound Fractions A fractional expression that contains fractions in its numerator and/or denominator is called a compound fraction. The techniques used to simplify rational expressions may be used to simplify these fractions. EXAMPLE 4 Simplify: 1 x1 4 x x

1 a.

1 1  x y b. 1 1  2 x2 y

Solution

a. We first express the numerator and denominator of the given expression as a single quotient. Thus, x 1 1# x1 x  4 x x # x

1

1 1  1 x1 x 4  x x

x11 x1  x2  4 x x2 x1  2 x 4 x

The LCD for the fraction in the numerator is x  1, and the LCD for the fraction in the denominator is x.

24

1 FUNDAMENTALS OF ALGEBRA

We then invert the denominator and multiply, obtaining x2 x1

#

x2 x  x 1 x 4 2



#

x 1x  2 2 1x  2 2

Factor the denominator of the second fraction.

x 1x  1 2 1x  22

Cancel the common factors.

b. As before, we first write the numerator and denominator of the given expression as a single quotient and then simplify the resulting fraction. yx 1 1  x y xy  2 1 1 y  x2  2 2 x y x 2y 2 2 2 yx # 2x y 2  xy y x 

yx xy



xy yx

#

The LCD for the fraction in the numerator is xy, and the LCD for the fraction in the denominator is x2y2.

Invert the fraction in the denominator and multiply.

x 2y 2 1y  x 2 1y  x 2 Cancel common factors.

1.4 Self-Check Exercises 2 3

1. Simplify

3a b

2ab  4ab 2

#b

2

 4b  4 6a2b5

2. Simplify

.

y x  y x x 2  2xy  y 2

.

x2  y2 Solutions to Self-Check Exercises 1.4 can be found on page 25.

1.4 Concept Questions 1. a. What is a rational expression? Give an example. b. Explain why a polynomial is a rational expression but not vice versa.

2. a. If P, Q, R, and S are polynomials and Q ⬆ 0 and S ⬆ 0, what is 1 QP 2 1 RS 2 ? What is 1 QP 2  1 RS 2 if Q ⬆ 0, R ⬆ 0, and S ⬆ 0? b. If P, Q, and R are polynomials with R ⬆ 0, what is 1 PR 2  1 QR 2 and 1 PR 2  1 QR 2 ?

1.4 Exercises In Exercises 1–12, simplify the expression.

1. 3.

28x 2 7x 3 4x  12 3x  9 6x  3x

2. 4.

2

5.

6x 2

6.

3y 4

7.

x2  x  2 x 2  3x  2

18y 2 12m  6 18m  9 8y

2

4y 3  4y 2  8y

9.

11.

x2  4 2x 2  x  6 x3  y3 x  xy  y 2

2

8.

10.

12.

2y 2  y  3 2y 2  y  1 6y 2  11y  3 4y 2  9 8r 3  s 3 2r  rs  s 2 2

1.4 RATIONAL EXPRESSIONS

In Exercises 13–46, perform the indicated operations and simplify.

13. 15.

6x 3 32 3x

#

8 3x

3

8x 2



3x 17. x  2y

14.

2

15x

4

16.

16x 5

#

22. 23.

24. 25. 27. 28. 29. 30.

6r 2  r  2 2r  4

k k6

# 2x2

2



4 x 9 2



35.

3y  6 6y  24 20.  4y  6 8y  12

36.

37.

x6

y



y 1 2

x x  5x  6 2x  1 2x 2  x  1

 

2 x 4 2

26.

x3 2x  1  x2 x1

y x  ax  ay by  bx

1

x x2 2

2

43.

5



3 x  3x  2 2

x1

38.

t t2  t  2





3 2m 2  3m  3

45.

2t  1

ax  by ay  bx  ax  bx by  ay

42. 1

1

1

2

3

x y xy

x y

1

44.

x  6x  9

2m

4 x 2  2x  3

2 x 40. 2 x x

2

2m 2  2m  1



2

1 1  x y 41. 1 1 xy

9y 2  12y  4



2x 2  3x  1

1 x 39. 1 1 x

6y 2  13y  6

2 x2  x2 x2

33. x 

y1 2y  y1 1y

2

2



1 2a  a2 a2

1

k 2  2k  8

2 3  2x  3 2x  1 x x6

3y  6 2y  1

k 2  6k  8



6y 2  13y  6

3

#

34.

x x6

6y 2  5y  6

2

4x 7x3

4r  2

2x 2  7x  6 2



# 6r  12

x2  x  6 k 2  2k  3

6x

32. 2 

5y

5

21x 2

x 2x  3  2 1x x 1

2

# 3y 3

4y  12 18. y2

5x  10y 6

2m  6 3m  9 19.  3 6 21.

25y 4 12y

31.

25

x2 y2



1

x y3 1 1  x y 1

1 1  2x 21x  h 2

46.

h

1x  h2

2



1 x2

h

2t 2  3t  2

1.4 Solutions to Self-Check Exercises 1. Factoring the numerator and denominator of each expression, we have 3a 2b 3 2ab 2  4ab

#b

2

 4b  4 3a 2b 3  2 5 2ab1b  2 2 6a b b2  2ab12b 2 2 

#

1b  2 2 2

2. Writing the numerator of the given expression as a single quotient, we have y x  y x

13a b 2 12b 2 2 3

2

Cancel common factors.

x 2  2xy  y 2



x2  y2 xy x 2  2xy  y 2

x2  y2

1x  y2 1x  y2

b2 4ab 3 

xy

1x  y2 1x  y2 1x  y2 1x  y2





x2  y2

The LCD for the fraction in the numerator is xy.

1x  y 2 1x  y 2 xy

1x  y 2 2 xy

#

Factor.

1x  y2 1x  y 2 1x  y2 1x  y 2

Invert the fraction in the denominator and multiply. Cancel common factors.

26

1 FUNDAMENTALS OF ALGEBRA

1.5 Integral Exponents Exponents We begin by recalling the definition of the exponential expression an, where a is a real number and n is a positive integer.

Exponential Expressions

If a is any real number and n is a natural number, then the expression an (read “a to the power n”) is defined as the number an  a aaa n factors

Recall that the number a is the base and the superscript n is the exponent, or power, to which the base is raised.

EXAMPLE 1 Write each of the following numbers without using exponents. a. 25

2 3 b. a b 3

Solution

a. 25  2  2  2  2  2  32 2 3 2 2 2 8 b. a b  a b a b a b  3 3 3 3 27 Next, we extend our definition of an to include n  0; that is, we define the expression a0. Observe that if a is any real number and m and n are positive integers, then we have the rule aman  (a  a      a)(a  a      a)  a  a      a  amn   m factors n factors

  (m  n) factors

Now, if we require that this rule hold for the zero exponent as well, then we must have, upon setting m  0, a0an  a0n  an

or

a0an  an

Therefore, if a  0, we can divide both sides of this last equation by an to obtain a0  1. This motivates the following definition.

Zero Exponent

For any nonzero real number a, a0  1

The expression 00 is not defined.

EXAMPLE 2 a. 20  1

b. (2)0  1

c. (␲)0  1

1 0 d. a b  1 3

1.5 INTEGRAL EXPONENTS

27

Next, we extend our definition to include expressions of the form an, where the exponent is a negative integer. Once again we use the rule aman  amn

where n is a positive integer. Now, if we require that this rule hold for negative integral exponents as well, upon setting m  n, we have anan  ann  a0  1

or

anan  1

Therefore, if a  0, we can divide both sides of this last equation by an to obtain an  1/an. This motivates the following definition. Exponential Expressions with Negative Exponents

If a is any nonzero real number and n is a positive integer, then an 

1 an

EXAMPLE 3 Write each of the following numbers without using exponents. a. 42

b. 31

c. 23

2 1 d. a b 3

3 3 e. a b 2

Solution

1 1 1 1 1 1  b. 31  1  c. 23   3   2 16 3 8 4 3 2 1 3 3 2 1 1 3 3 1 2 8 d. a b  2 1  2  e. a b  3 3  3  3 2 2 27 3 13 2 12 2 3 a. 42 

In Example 3d and 3e, the intermediate steps may be omitted by observing that

Note

a n b n a b  a b a b

2 1 3 1 For example, a b  a b 3 2

since a n a b  b

1 1 n  n  1 a a a b bn b

# bn  n

a

b n a b a

Five basic properties of exponents are given in Table 10. TABLE 10 Properties of Exponents

Property

1. a  a  a am 2. n  a mn a 3. (am)n  a mn m

n

mn

4. (ab)n  an  bn a n an 5. a b  n (b  0) b b

Illustration

x  x  x23  x 5 x7  x74  x 3 x4 (x 4)3  x 4⭈3  x12 2

3

(2x)4  24  x 4  16x 4 x 3 x3 x3 a b  3 2 8 2

It can be shown that these laws are valid for any real numbers a and b and any integers m and n.

28

1 FUNDAMENTALS OF ALGEBRA

Simplifying Exponential Expressions The next two examples illustrate the use of the laws of exponents. EXAMPLE 4 Simplify the expression, writing your answer using positive exponents only. a. (2x 3)(3x 5)

b.

2x 5 3x 4

c. (x2)3

e. a

d. (2u1√ 3)3

2m 3n 4 1 b m 5n 3

Solution

a. (2x 3)(3x 5)  6x 35  6x 8 2x 5 2 2 b.  x 54  x 3 3 3x 4 c. (x2)3  x(2)(3)  x 6

Property 1 Property 2 Property 3

d. (2u1√ 3)3  23u(1)(3)√ 3(3)  8u3√ 9  e. a

9

8√ u3

Property 4

2m 3n 4 1 b  (2m35n43)1 m 5n 3  (2m2n)1 m2 1  2  2n 2m n

Property 2 Property 1

EXAMPLE 5 Simplify the expression, writing your result using positive exponents only. a. (22)3  (32)2

b. (x1  y1)1

c.

24

#

121 2 2

120  12 1

Solution

a. (22)3  (32)2  26  34  64  81  17 y  x 1 xy 1 1 1 b. (x1  y1)1  a  b  a b  x y xy yx 24 # 121 2 2 24 # 22 1 1 c.  2421  25  5   0 1 1 32 12  12 12 2 2

1.5 Self-Check Exercises 1. Simplify the expression, writing your result using positive exponents only. a. (3a4)(4a3)

b. a

u3 u

5

b

2

2. Simplify the expression, writing your result using positive exponents only. a. (x 2 y 3)3(x 5y)2

b. a

a2b1c3 3 2

ab

b

2

Solutions to Self-Check Exercises 1.5 can be found on page 29.

1.5 Concept Questions 1. Explain the meaning of the expression an. What restrictions, if any, are placed on a and n? What is a0 if a is a nonzero real number? What is a n if n is a positive integer and a ⬆ 0?

2. Write all the properties of exponents and illustrate with examples.

1.5 INTEGRAL EXPONENTS

29

1.5 Exercises In Exercises 1–20, rewrite the number without using exponents.

33. a

2u 2 √ 3 1 b 3u√

34. a

a2 2

2b

b

3

1. (2)3

2 4 2. a b 3

35. (3x2)3(2x 2)5

3. 72

3 2 4. a b 4

37.

1 2 5.  a b 4

6. 4

39.

7. 22  31

2 2 8. 32  a b 3

41. (2x)2(3y)3(4z)2

42. (3x1)2(4y1)3(2z)2

43. (a2b3)2(a2b2)3

44. (5u2 √3)1  3(2u2 √ 2)2

2

10. (0.3)2

9. (0.02)2

12. (18  25)0

13. (ab2)0, where a, b  0

14. (3x 2y 3)0, where x, y  0

15. 17.

23 # 25 24 # 29

16.

23 # 24 25 # 22

19. a

18.

34 # 33 32

b

1

6 # 104 3 # 102

2 # 42

52 # 52 55

51. b

2

23.

22. (2x 2)(3x4)

3x 3 2x

24.

4

13x 2 2 14x 3 2 2x

27. (2x2 y 2)3

28. (3u1√2)3

29. (4x 2y3)(2x3 y 2)

1 30. a u2 √ 3 b (4√ 3) 2

2y

x4

b

a2b2

2 1

b d 2

b 22u 3√3

2

1 32. a x 2 y b 2

1. a. (3a )(4a )  3  a b. a

3

u3

2

u5

b

4



4a

u132 122

u152 122

3



u6 u10

 12a

43

u1  √1 √u 1

b

b

y7 x4

1

x2y1z

48. c a

52.

a1  b1 a

2

50.

x1  1

1

b

x 2y3z4

b 2

22x2 y 0

2 3

b 32x 3y2

d

2 2

d

x1  y1 x1  y1 1u√ 2 1

u1  √1

54. [(a1  b1)(a1  b1)]2

In Exercises 55–57, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

57. If a and b are real numbers and n is a natural number, then (a  b)n  an  bn.

2

b. a

 12a

7

1 u4

2. a. (x 2y 3)3(x 5y)2  x 23y 33x5(2)y2  x 6y 9x10y2



42u

12a2b1 2 3

am a mn b  a bn b

 u610  u4 

 x 610 y 92  x4y 7

32√ 5

x1  1

1.5 Solutions to Self-Check Exercises 4

a

13a1b2 2 2

46. c a

3a1b

32u2√ 2

14x1 2 1x 3 2 2

56. If a and b are real numbers (b  0) and m and n are natural numbers, then

26. (a2)3

31. (x 2 y)3 a

22u2 1√1 2 3

5x 2 13x2 2

55. If a and b are real numbers and m and n are natural numbers, then ambn  (ab)mn.

4

25. (a2)3

2

32 1u3√2 2

40.

16

53. a

In Exercises 21–54, simplify the expression, writing your answer using positive exponents only.

1 21. (2x 3) a x 2 b 4

# 1x 2 2 3

38.

47. a 49.

4 # 23

20. a

30 # 4x2

45. c a

11. 19960

36. (21r 3)2(3s1)2

a2b1c3 a3b2

b  2

# # a2 2b112 122c3 2 a4b2c6  6 4 3 # 2 122 122 a b ab

 a46b24c6  a2b2c6 

b2c6 a2

30

1 FUNDAMENTALS OF ALGEBRA

1.6 Solving Equations Equations An equation is a statement that two mathematical expressions are equal. EXAMPLE 1 The following are examples of equations. a. 2x  3  7 c.

y 3y  1  y2 3y  4

b. 3(2x  3)  4(x  1)  4 d. 2z  1  2

In Example 1 the letters x, y, and z are called variables. A variable is a letter that stands for a number belonging to a set of (real) numbers. A solution of an equation involving one variable is a number that renders the equation a true statement when it is substituted for the variable. For example, replacing the variable x in the equation 2x  3  7 by the number 2 gives 2(2)  3  7 437

which is true. This shows that the number 2 is a solution of 2x  3  7. The set of all solutions of an equation is called the solution set. To solve an equation is synonymous with finding its solution set. The standard procedure for solving an equation is to transform the given equation, using an appropriate operation, into an equivalent equation—that is, one having exactly the same solution(s) as the original equation. The transformations are repeated if necessary until the solution(s) are easily read off. The following properties of real numbers can be used to produce equivalent equations.

Equality Properties of Real Numbers

Let a, b, and c be real numbers. 1. If a  b, then a  c  b  c and a  c  b  c. a b 2. If a  b and c  0, then ca  cb and  . c c

Addition and subtraction properties Multiplication and division properties

Thus, adding or subtracting the same number to both sides of an equation leads to an equivalent equation. Also, multiplying or dividing both sides of an equation by a nonzero number leads to an equivalent equation. Let’s apply the procedure to the solution of some linear equations.

Linear Equations A linear equation in the variable x is an equation that can be written in the form ax  b  0, where a and b are constants with a  0. A linear equation in x is also called a first-degree equation in x or an equation of degree 1 in x.

1.6 SOLVING EQUATIONS

EXAMPLE 2 Solve the linear equation 8x  3  2x  9. Solution We use the equality properties of real numbers to obtain the following equivalent equations in which the aim is to isolate x.

8x  3  2x  9 8x  3  2x  2x  9  2x

Subtract 2x from both sides.

6x  3  9 6x  3  3  9  3

Add 3 to both sides.

6x  12 1 1 (6x)  (12) 6 6 x2

Multiply both sides by

1 . 6

and so the required solution is 2. EXAMPLE 3 Solve the linear equation 3p  2( p  1)  2p  4. Solution

3p  2( p  1)  2p  4 3p  2p  2  2p  4

Use the distributive property.

5p  2  2p  4

Simplify.

5p  2  2p  2p  4  2p

Add 2p to both sides.

7p  2  4 7p  2  2  4  2

Add 2 to both sides.

7p  2 1 1 (7p)  (2) 7 7 p

1 Multiply both sides by . 7

2 7

EXAMPLE 4 Solve the linear equation Solution

2k  1 k1   1. 3 4

First multiply both sides of the given equation by 12, the LCD. Thus, 12 a 12

2k  1 k1  b  12(1) 3 4

# 2k  1  12 # k  1  12 3

4

4(2k  1)  3(k  1)  12 8k  4  3k  3  12 5k  7  12 5k  5 k1

Use the distributive property. Simplify. Use the distributive property. Simplify. Subtract 7 from both sides. 1 Multiply both sides by . 5

31

32

1 FUNDAMENTALS OF ALGEBRA

Some Special Nonlinear Equations The solution(s) of some nonlinear equations are found by solving a related linear equation as the following examples show. EXAMPLE 5 Solve Solution

x 1 2   . 3 31x  1 2 21x  12

We multiply both sides of the given equation by 6(x  1), the LCD.

Thus, 61x  12

#

2  61x  12 31x  12

#

x  61x  12 21x  12

#1 3

which upon simplification yields 4  3x  2(x  1) 4  3x  2x  2 4  3x  2x  2x  2  2x 4  5x  2 4  5x  4  2  4 5x  2 2 x 5

Subtract 2x from both sides.

Subtract 4 from both sides.

1 Multiply both sides by  . 5

We can verify that x  25 is a solution of the original equation by substituting 25 into the left-hand side of the equation. Thus, 2 31 25  12



2 5

21 25  12



2



2 5 21 75 2

31 75 2 10 1 7 1     21 7 21 3

which is equal to the right-hand side. When we solve an equation in x, we sometimes multiply both sides of the equation by an expression in x. The resulting equation may contain solution(s) that are not solution(s) of the original equation. Such a solution is called an extraneous solution. For example, the solution of the equation 3x  0 is of course 0. But, multiplying both sides of this equation by the expression (x  2) leads to the equation 3x(x  2)  0 whose solutions are 0 and 2. The solution 2 is not a solution of the original equation. Thus, whenever you need to multiply both sides of an equation by an expression that involves a variable, it is a good idea to check whether each solution of the modified equation is indeed a solution of the given equation. EXAMPLE 6 Solve Solution

x1 1 x1  2 .  x x1 x x

Multiplying both sides of the equation by the LCD, x(x  1), we obtain (x  1)2  x(x  1)  1 x  2x  1  x 2  x  1 3x  1  1 3x  0 x0 2

Note: x 2  x  x(x  1)

1.6 SOLVING EQUATIONS

33

Since the original equation is not defined for x  0 (division by 0 is not permitted), we see that 0 is an extraneous solution of the given equation and conclude, accordingly, that the given equation has no solution. EXAMPLE 7 Solve 22x  5  3. This equation is not a linear equation. To solve it, we square both sides of the equation, obtaining Solution

1 22x  52 2  32 2x  5  9 2x  4 x2

Substituting x  2 into the left-hand side of the original equation yields 22122  5  29  3 which is the same as the number on the right-hand side of the equation. Therefore, the required solution is 3. EXAMPLE 8 Solve 2k2  4  k  4. Solution

Squaring both sides of the equation leads to k 2  4  (k  4)2 k 2  4  k 2  8k  16 4  8k  16 20  8k 5 k 2

Substituting this value of k into the left-hand side of the original equation gives 5 2 25 9 3 a b 4 4  B 2 B4 B4 2

But this is not equal to 52  4  32, which is the result obtained if the value of k is substituted into the right-hand side of the original equation. We conclude that the given equation has no solution.

Solving for a Specified Variable Equations involving more than one variable occur frequently in practical applications. In these situations we may be interested in solving for one of the variables in terms of the others. To obtain such a solution, we think of all the variables other than the one we are solving for as constants. This technique is illustrated in the next example. EXAMPLE 9 The equation A  P  Prt gives the relationship between the value A of an investment of P dollars after t years when the investment earns simple interest at the rate of r percent per year. Solve the equation for (a) P, (b) t, and (c) r. Solution

a.

A  P  Prt A  P(1  rt) A P 1  rt

Factor. Multiply both sides by

1 . 1  rt

34

1 FUNDAMENTALS OF ALGEBRA

b.

c.

A  P  Prt A  P  Prt AP t Pr

Subtract P from both sides. Multiply both sides by

1 . Pr

A  P  Prt A  P  Prt AP r Pt

1.6 Self-Check Exercises 1. Solve 2 a

x1 2x 4  3x b   . 4 3 12

2. Solve

k 3  . 2k  1 8

Solutions to Self-Check Exercises 1.6 can be found on page 35.

1.6 Concept Questions 1. What is an equation? What is the solution of an equation? What is the solution set of an equation? Give examples.

3. What is a linear equation in x? Give an example of one and solve it.

2. Write the equality properties of real numbers. Illustrate with examples.

1.6 Exercises In Exercises 1–38, solve the given equation.

1. 3x  12

2. 2x  0

3. 0.3y  4

4. 2x  5  11

5. 3x  4  2

6. 2  3y  8

7. 2y  3  7

8.

1 1 9. p  3   p  5 5 3

10. 3.1m  2  3  0.2m

17.

1 2 [2x  3(x  4)]  (x  5) 2 3

18.

1 1 1 [2  3(x  2)]  (3x  1)  x 3 4 2





19. (2x  1)2  (3x  2)2  5x(2  x) 20. x[(2x  3)2  5x 2]  3x 2(3x  4)  18 8  16 x

22.

1 2  6 x x

23.

2 4 y1

24.

1 0 x3

3m m 42  m  1b   4 5 4

25.

2x  3 2  x1 5

26.

r 4 3r  1

71x  32 3x  4 2x  1   3 4 10

27.

2 3  q1 q2

28.

y 2 1   1y  3 2 3 y1 3

3 1 1k  1 2  12k  3 2 5 4

14. 3 a 15.

1 1 k  4  2 a k  b 3 3

w1 w1 w1   3 4 6

21.

11. 0.4  0.3p  0.1( p  4) 12. 13.

1 1 k1 k2 3 4

16.

1.6 SOLVING EQUATIONS

35

29.

3k  2 3k k3   4 4 k

30.

2x  1 2x  1  3x  2 3x  1

terms of F. Then use the result to find the temperature in degrees Celsius corresponding to a temperature of 70 °F.

31.

m2 2 m3   m m m3

32.

2 4  x  2 x1x  2 2

49. LINEAR DEPRECIATION Suppose an asset has an original value of $C and is depreciated linearly over N yr with a scrap value of $S. Then the book value V (in dollars) of the asset at the end of t yr is given by

33. 23x  1  2

34. 22x  3  3  0

35. 2k 2  4  4  k

36. 24k 2  3  2k  1

37. 2k  1  2k  3 2k 38. 2x  1  2x  24x  3 In Exercises 39–46, solve the equation for the indicated variable.

39. I  Prt; r

40. ax  by  c  0; y

41. p  3q  1; q

s2

;u

ax ;x xb

44. V  C a 1 

2mI ;m B1n  12

46. r 

43. V  45. r 

42. w 

ku√

n b; n N

2mI ;n B1n  12

47. SIMPLE INTEREST The simple interest I (in dollars) earned when P dollars is invested for a term of t yr is given by I  Prt, where r is the (simple) interest rate/year. Solve for t in terms of I, P, and r. If Susan invests $1000 in a bank paying interest at the rate of 6%/year, how long must she leave it in the bank before it earns an interest of $90? 48. TEMPERATURE CONVERSION The relationship between the temperature in degrees Fahrenheit (°F) and the temperature in degrees Celsius (°C) is F  95C  32. Solve for C in

VC a

CS bt N

a. Solve for C in terms of V, S, N, and t. b. A speed boat is being depreciated linearly over 5 yr. If the scrap value of the boat is $40,000 and the book value of the boat at the end of 3 yr is $70,000, what was its original value? 50. MOTION OF A CAR The distance s (in feet) covered by a car traveling along a straight road is related to its initial speed u (in ft/sec), its final speed √ (in ft/sec), and its (constant) acceleration a (in ft/sec2) by the equation √ 2  u 2  2as. a. Solve the equation for a in terms of the other variables. b. A car starting from rest and accelerating at a constant rate reaches a speed of 88 ft/sec after traveling 14 mile (1320 ft). What is its acceleration? 51. COWLING’S RULE Cowling’s rule is a method for calculating pediatric drug dosages. If a denotes the adult dosage (in milligrams) and if t is the child’s age (in years), then the child’s dosage is given by c a

t1 ba 24

a. Solve the equation for t in terms of a and c. b. If the adult dose of a drug is 500 mg and a child received a dose of 125 mg, how old was the child?

1.6 Solutions to Self-Check Exercises 1. 2 a

2x 4  3x x1 b   4 3 12 6(x  1)  8x  4  3x 6x  6  8x  4  3x

If we substitute this value of k into the original equation, we find Multiply both sides by 12, the LCD.

6  2x  4  3x 6  x  4

Add 3x to both sides.

x  10 2.

3 k  2k  1 8 8k  3(2k  1) 8k  6k  3 2k  3 k

3 2

Multiply both sides by 8(2k  1), the LCD.

3 2

21 32 2  1



3 2

31



3 8

which is equal to the right-hand side. So k  32 is the solution of the given equation.

36

1 FUNDAMENTALS OF ALGEBRA

1.7 Rational Exponents and Radicals nth Roots of Real Numbers Thus far we have described the expression an, where a is a real number and n is an integer. We now direct our attention to a closely related topic: roots of real numbers. As we will soon see, expressions of the form an for fractional (rational) powers of n may be defined in terms of the roots of a.

nth Root of a Real Number

If n is a natural number and a and b are real numbers such that an  b

then we say that a is the nth root of b. For n  2 and n  3, the roots are commonly referred to as the square roots and cube roots, respectively. Some examples of roots follow: ■ ■ ■ ■

2 and 2 are square roots of 4 because (2)2  4 and 22  4. 3 and 3 are fourth roots of 81 because (3)4  81 and 34  81. 4 is a cube root of 64 because (4)3  64. 1 1 1 5 1 2 is a fifth root of 32 because 1 2 2  32 . How many real roots does a real number b have?

1. When n is even, the real nth roots of a positive real number b must come in pairs— one positive and the other negative. For example, the real fourth roots of 81 include 3 and 3. 2. When n is even and b is a negative real number, there are no real nth roots of b. For example, if b  9 and the real number a is a square root of b, then by definition a2  9. But this is a contradiction since the square of a real number cannot be negative, and we conclude that b has no real roots in this case. 3. When n is odd, then there is only one real nth root of b. For example, the cube root of 64 is 4. As you can see from the first statement, given a number b, there might be more than one real root. So, to avoid ambiguity, we define the principal nth root of a positive real number, when n is even, to be the positive root. Thus, the principal square root of a real number, when n is even, is the positive root. For example, the principal square root of 4 is 2, and the principal fourth root of 81 is 3. Of course, the principal nth root of any real number b, when n is odd, is given by the (unique) nth root of b. For example, the principal cube root of 64 is 4, and the principal fifth root of 321 is 12. A summary of the number of roots of a real number b is given in Table 11. TABLE 11 Number of Roots of a Real Number b

Index

b

Number of Roots

n even

b0 b 0 b0 b0 b 0 b0

Two real roots (one principal root) No real roots One real root One real root One real root One real root

n odd

1.7 RATIONAL EXPONENTS AND RADICALS

37

n

We use the notation 2b, called a radical, to denote the principal nth root of b. The symbol 2 is called a radical sign, and the number b within the radical sign is called the radicand. The positive integer n is called the index of the radical. For 2 square roots (n  2), we write 2b instead of 2b. 4

4

A common mistake is to write 216  2. This is wrong because 216 denotes the principal fourth root of 16, which is the positive root 2. Of course, the nega4 tive of the fourth root of 16 is  216  (2)  2. EXAMPLE 1 Determine the number of roots of each real number. a. 225

5 b. 2 0

3 c. 2 27

d. 227

Solution

a. b. c. d.

Here b  0, n is even, and there is one principal root. Thus, 225  5. 5 Here b  0, n is odd, and there is one root. Thus, 2 0  0. 3 Here b 0, n is odd, and there is one root. Thus, 227  3. Here b 0, n is even, and no real root exists. Thus, 227 is not defined. Note that (81)1/4 does not exist because n is even and b 0, but 811/4  (81)1/4  3. The first expression is “the fourth root of 81,” whereas the second expression is “the negative of the fourth root of 81.”

EXAMPLE 2 Evaluate the following radicals. 6

a. 264

5

b. 232

c.

3 8 B 27

4 B 25

d. 

Solution 6

a. 264  2 because 26  64. 5 b. 232  2 because (2)5  32. 2 3 2 8 3 8  because a b  . c. B 27 3 3 27 4 2 4 2 4 2   because  , so   . d.  B 25 5 B 25 5 5 B 25

Rational Exponents and Radicals

In Section 1.5 we defined expressions such as 23, 1 12 2 2, and 1/␲ 3 involving integral exponents. But how do we evaluate expressions such as 81/3, where the exponent is a rational number? From the definition of the nth root of a real number, we know that 3 28  2. Using rational exponents, we write this same result in the form 81/3  2. More generally, we have the following definitions.

Rational Exponents

1. If n is a natural number and b is a real number, then

Illustration 91/2  29  3 3 (8)1/3  28  2

n

b1/n  2b

(If b 0 and n is even, b1/n is not defined.) (continued)

38

1 FUNDAMENTALS OF ALGEBRA

Rational Exponents

Illustration

2. If m/n is a rational number reduced to lowest terms (m, n natural numbers), then

(27)2/3  (271/3)2  32  9 (27)2/3  [(272)]1/3  (729)1/3  9 (27)2/3  (271/3)2  (3)2  9

bm/n  (b1/n)m or, equivalently, n

bm/n  2bm whenever it exists. EXAMPLE 3 3 a. (64)1/3  264  4 b. (81)3/4  (811/4)3  33  27 c. (8)5/3  (81/3)5  (2)5  32 1 2/3 1 1/3 2 1 2 1 d. a b  c a b d  a b  27 27 3 9

Expressions involving negative rational exponents are taken care of by the following definition. Negative Exponents am/n 

1 a m/n

(a  0)

EXAMPLE 4 a. 45/2 

1 1 1 1  1/2 5  5  5/2 32 4 14 2 2

b. 182 1/3 

1 1 1   1/3 2 2 18 2

All the properties of integral exponents listed in Table 10 (on page 27) hold for rational exponents. Examples 5 and 6 illustrate the use of these properties. EXAMPLE 5 165/4  165/41/2  165/42/4  163/4  (161/4)3  23  8 161/2 b. (62/3)3  6(2/3)3  66/3  62  36 16 3/4 16 1/4 3 161/4 3 2 3 8 c. a b  c a b d  a 1/4 b  a b  81 81 3 27 81

a.

EXAMPLE 6 Evaluate: a. 2x 1/2(x 2/3  x 1/4)

b. (x 1/3  y 2/3)2

Solution

a. 2x 1/2(x 2/3  x 1/4)  2x 1/2(x 2/3)  2x 1/2(x 1/4)  2x 1/22/3  2x 1/21/4  2x 3/64/6  2x 2/41/4  2x 7/6  2x 3/4 1/3 2/3 2 b. (x  y )  (x 1/3)2  2x 1/3y 2/3  ( y 2/3)2  x 2/3  2x 1/3y 2/3  y 4/3

1.7 RATIONAL EXPONENTS AND RADICALS

39

Simplifying Radicals The properties of radicals given in Table 12 follow directly from the properties of exponents discussed earlier (Table 10, page 27).

TABLE 12 Properties of Radicals

Property

Illustration

If m and n are natural numbers and a and b are real numbers for which the indicated roots exist, then 1. 1 2a 2 n  a

3 12 22 3  121/3 2 3  21  2

n

n

n

2. 2ab  2a

#

3 3 3 2 216  2 27 # 8  2 27

n

2b

n

a 2a 3.  n Bb 2b n

m

n

#

3 2 83 # 26

3 8 2 8 2 1  3   B 64 4 2 264 2#3 3 6 64  2 3 264  264  2 3

(b  0)

mn

4. 3 2a  2 a n

5. If n is even: 2an   a .

2132 2   3   3

n

3 28  2

If n is odd: 2an  a.

n

A common error is to write 2an  a. This is not true if a is negative (see Illustration 5 in Table 12). Thus, unless the variable a is known to be nonnegative, the correct equation is given by Property 5. When we work with algebraic expressions involving radicals, we usually express the radical in simplified form.

Simplifying Radicals

An expression involving radicals is simplified if the following conditions are satisfied: 1. The powers of all factors under the radical sign are less than the index of the radical. 2. The index of the radical has been reduced as far as possible. 3. No radical appears in a denominator. 4. No fraction appears within a radical.

EXAMPLE 7 Determine whether each radical is in simplified form. If not, state which condition is violated. a.

1 2x 4

5

6 2 y b. 2

c.

5 B4

Solution None of the three radicals are in simplified form. The radical in part (a) violates Conditions 1 and 3; that is, the power of x is 5, which is greater than 4, the index of the radical, and a radical appears in the denominator. The radical in part (b) violates Condition 2 since the index of the radical can be reduced; that is, 3#2 3 6 2 2 y  2y 2  2 y

40

1 FUNDAMENTALS OF ALGEBRA

The radical in part (c) violates Condition 4 since there is a fraction within the radical. Rewriting the radical, we see that 5 25 25 1    25 B4 2 2 24

EXAMPLE 8 Simplify: 3 a. 2 375

3 b. 2 8x 3y 6z 9

6 c. 2 81x 4y 2

Solution

3 3 3 a. 2 375  2 3 # 125  2 3

#

3 3 3 2 5  52 3

# 1xy 2z 3 2 3 3  223 # 2 1xy 2z 3 2 3

3

253  5

3 3 3 b. 2 8x 3y 6z 9  2 2

 2xy 2z 3

3

223  2,

6 6 2 2 2 c. 2 81x 4y 2 2 9 1x y 2 3#2 3#2  292 # 2 1x 2y 2 2

#

3 2 9

3#2

3 2 2 x y

3

21xy 2z 3 2 3  xy 2z 3

292  29,

3

3#2

2 1x 2y 2 2  2x 2y 3

3 2 9x 2y

As mentioned earlier, a simplified rational expression should not have radicals in its denominator. For example, 3/ 15 is not in simplified form, whereas 3 15/5 is since the denominator of the latter is free of radicals. How do we get rid of the radical 15 in the fraction 3/ 15? Obviously, multiplying by 15 does the job since ( 15)( 15)  125  5! But we cannot multiply the denominator of a fraction by any number other than 1 without changing the fraction. So, the solution is to multiply both the numerator and the denominator of 3/ 15 by 15. Equivalently, we multiply 3/ 15 by 15/ 15 (which is equal to 1). Thus, 3 3  15 15

#

15 315 315   5 15 125

This process of eliminating a radical from the denominator of an algebraic expression is referred to as rationalizing the denominator and is illustrated in Examples 9 and 10. EXAMPLE 9 Rationalize the denominator. a.

1

b.

22

3x 2 2x

c.

x 3

2y

Solution

1 # 12 12 1   12 2 2 12 12 3x 1x 3 3x # 1x   1x b. 2x 2 2 1x 1x a.

c.

x 3 2 y

#

3 2 2 y 3 2 2 y



3 2 x2 y 3 3 2 y



3 2 x2 y y

1.7 RATIONAL EXPONENTS AND RADICALS

41

3 Note that in Example 9c we multiplied the denominator by 2y 2 so that we would 3 3 obtain 2y , which is equal to y. In general, to rationalize a denominator involving an nth root, we multiply the numerator and the denominator by a factor that will yield a product in the denominator involving an nth power. For example,

1 5 3 2 x

#

1



5 3 2 x

5 2 2 x



5 2 2 x

5 2 2 x 5 5 2 x



5 2 2 x x

#

5

Since 2x 3

2x 2  x 3/5 # x 2/5  x 5/5  x 5

EXAMPLE 10 Rationalize the denominator. a.

8 B3 3

b.

x By2 3

Solution

a.

3 8 2 8 2  3  3 B3 23 23

b.

3 2 x x   3 2 3 By 2y 2 2y 2

3

#

3 2 2 3 3



232 3 3 2 x 2y

3

#

3 2 y

3 2 22 3 2 3  2 9 3 3 3



2xy 3 3 2 y

3



2xy y

How do we rationalize the denominator of a fraction like multiplying by

23

1 1  23

? Rather than

(which does not eliminate the radical in the denominator), we 23 1  23 multiply by , obtaining 1  23 1 1  23

#

1  23 1  23



1  23

1  1 232 2

(a  b)(a  b)  a 2  b 2

1  23 1  23  13 2 1  23  2 

In general, to rationalize a denominator of the form a  1b, we multiply by Similarly, to rationalize a denominator of the form a  1b, we multiply by We refer to the quantities a  1b and a  1b as conjugates of each other. EXAMPLE 11 Rationalize the denominator in the expression

3 2  25

a  2b a  2b a  2b a  2b

.

The conjugate of 2  15 is 2  15. Therefore, we multiply the given 2  25 fraction by , obtaining 2  25

Solution

3 2  15

# 2  15  2  15



312  152

12  152 12  152 312  152

1  312  15 2



312  152

22  1 152 2

. .

42

1 FUNDAMENTALS OF ALGEBRA

Sometimes you may find it easier to convert an expression containing a radical to one involving rational exponents before evaluating the expression. EXAMPLE 12 Evaluate: 3 2 a. 2 3  293 4

3 2 b. 2 x y  2xy

Solution 3 2 a. 2 3  293  32/3  93/4  32/3  36/4  32/33/2  34/69/6  313/6 3 2 b. 2x y  2xy  x 2/3y 1/3  x 1/2y 1/2  x 2/31/2y 1/31/2  x 4/63/6y 2/63/6  x7/6y 5/6 4

Note how much easier it is to work with rational exponents in this case.

1.7 Self-Check Exercises 1. Simplify:

2. Rationalize the denominator:

8 #8 a. 3/2 8 2/3

4/3

b. a

4 4

3y y 2

z

b

3

c. 15

#

145

1

a.

b.

3

2xy

4 3  28

Solutions to Self-Check Exercises 1.7 can be found on page 43.

1.7 Concept Questions 1. What is the nth root of a real number? Give an example. 2. What is the principal nth root of a positive real number? Give an example.

3. What is meant by the expression “rationalize the denominator of an algebraic expression”? Illustrate the process with an example.

1.7 Exercises In Exercises 1–20, rewrite the number without radicals or exponents.

In Exercises 21–40, carry out the indicated operation and write your answer using positive exponents only.

1. 281

3 2. 2 27

21. 31/3  35/3

4 256 3. 2

5 4. 232

23.

5. 91/2

6. 6251/4

7. 82/3

8. 322/5

9. 251/2 2/3

11. (8)

4 13. a b 9

1/2

27 2/3 15. a b 8

25.

10. 163/2 3/5

12. (32)

9 3/2 14. a b 25 8 1/3 16. a b 125

17. 82/3

18. 811/4

27 1/3 19.  a b 8

8 2/3 20.  a b 27

22. 26/5  21/5

41/2

24.

45/2 21/2 # 32/3

23/2 # 31/3

26.

35/4 31/4 41/3 # 42/5 42/3

27. (23/2)4

28. [(3)1/3]2

29. x2/5  x1/5

30. y3/8  y1/4

31.

x 3/4

32.

1/4

x

33. a 35. a

x3 6

27x x3

b y2

1/2

b

2/3

y 3/2 a b x

x 7/3 x2

34. a

27x3y 2

36. a

b 52n

2 5

8x y rn

r

4

b

1/3

43

1.7 RATIONAL EXPONENTS AND RADICALS

37. x 2/5(x 2  2x 3)

38. s1/3(2s  s1/4)

39. 2p3/2(2p1/2  p1/2)

40. 3y1/3( y2/3  1)2

In Exercises 41–52, write the expression in simplest radical form.

41. 232

42. 245

3

44. 248

45. 216x 2y 3

46. 240a 3b4 48. 227p 2q 3r 4

49. 329

3

50. 329

3 51. 32x

3 4 3 x 52. 3 2

3

5

63.

65.

67.

2

54.

23 3

57.

2xy 1

60.

3

2x 2

62.

1  23 1  22

64.

1  22 q

66.

2q  1 y 3

3

74.

B 2x

2

68.

2x z 2

3

79.

82.

22x

2y

5x2

58.

23y

83.

23x

2x By

84.

3

71.

3 2 B3

72.

x 3y 5 B 4

75.

2y 2 B 3

76.

3

3 81 B4 3

3a3

B b2

9  22

2x

78. 

2x  2y

2y 2x  2y

80.

x 2x  y

 2x  y

a 2a2  b2



2a2  b2 a

1 x(x  1)1/2 2

1 1/2 1 x (x  y)1/3  x1/2(x  y)2/3 2 3 1 2 11

1 2

 x1/3 2 x1/2  13 x1/2 # x2/3 11  x1/3 2 2

x1/2 1x  y2 1/2  12 x1/2 1x  y2 1/2 xy

85. If a is a real number, then 2a2   a .

3  22

86. If a is a real number, then (a2)1/4 is not defined.

xy

87. If n is a natural number and a is a positive real number, then (a1/n )n  a.

2x  2y 2x 2xy

2a

 2a

In Exercises 85–88, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.

1  22

3

1

81. (x  1)1/2 

3

55.

25

77.

3

In Exercises 53–68, rationalize the denominator of the expression.

61.

8 B3

70. 

In Exercises 77–84, simplify the expression.

3

59.

16 B 3

4

47. 2m 6n 3p12

56.

69. 73.

43. 254

53.

In Exercises 69–76, write the expression in simplest radical form.

88. If a and b are positive real numbers, then 2a 2  b 2  a  b.

2

1.7 Solutions to Self-Check Exercises 1. a.

82/3 # 84/3 83/2

b. a

4 4

3y y 2

z

8

2/34/33/2

b  a 3

44

3y

2

z

c.

b  a 3

3 23

 (3z )  3 z 2 3

25 #

8

6/33/2

8

1/2

0

3y

2

z

b

 27z

 28  222

2. a.

3

b.

1 3 2 xy

#

3 2x 2y 2 3 2 2 2 x y

4 3  28



3 2x 2y 2 3 3 3 2 x y

3 2x 2y 2 xy

# 3  28  413  282

32  1 282 2

3  28

6

245  25 # 45  2225  15





413  282 98

 413  282

44

1 FUNDAMENTALS OF ALGEBRA

1.8 Quadratic Equations The equation 2x 2  3x  1  0

is an example of a quadratic equation. In general, a quadratic equation in the variable x is any equation that can be written in the form ax 2  bx  c  0

where a, b, and c are constants and a  0. We refer to this form as the standard form. Equations such as 3x 2  4x  1 and 2t 2  t  1

are quadratic equations in nonstandard form, but they can be easily transformed into standard form. For example, adding 1 to both sides of the first equation leads to 3x 2  4x  1  0, which is in standard form. Similarly, by subtracting (t  1) from both sides of the second equation, we obtain 2t 2  t  1  0, which is also in standard form.

Solving by Factoring We solve a quadratic equation in x by finding its roots. The roots of a quadratic equation in x are precisely the values of x that satisfy the equation. The method of solving quadratic equations by factoring relies on the following zero-product property of real numbers, which we restate here.

Zero-Product Property of Real Numbers

If a and b are real numbers and ab  0, then a  0, or b  0, or both a, b  0. Simply stated, this property says that the product of two real numbers is equal to zero if and only if one (or both) of the factors is equal to zero. EXAMPLE 1 Solve x 2  3x  2  0 by factoring. Solution

Factoring the given equation, we find that x 2  3x  2  (x  2)(x  1)  0

By the zero-product property of real numbers, we have x20

or

x10

from which we see that x  2 or x  1 are the roots of the equation. If a quadratic equation is not in standard form, we first rewrite it in standard form and then factor the equation to find its roots. EXAMPLE 2 Solve by factoring. a. 2x 2  7x  6

b. 4x 2  3x

c. 2x 2  6x  4

Solution

a. Rewriting the equation in standard form, we have 2x 2  7x  6  0

1.8 QUADRATIC EQUATIONS

45

Factoring this equation, we obtain (2x  3)(x  2)  0

Therefore, 2x  3  0 or 3 x 2

x20 x2

b. We first write the equation in standard form: 4x 2  3x  0

Factoring this equation, we have x(4x  3)  0

Therefore, x0

4x  3  0 3 x 4

or

x0

(Observe that if we had divided 4x 2  3x  0 by x before factoring the original equation, we would have lost the solution x  0.) c. Rewriting the equation in standard form, we have 2x 2  6x  4  0

Factoring, we have 2(x 2  3x  2)  0 2(x  2)(x  1)  0

2 is a common factor.

and x2

or

x1

Solving by Completing the Square The method of solution by factoring works well for equations that are easily factored. But what about equations such as x 2  2x  2  0 that are not easily factored? Equations of this type may be solved by using the method of completing the square.

The Method of Completing the Square

Illustration

1. Write the equation ax  bx  c  0 in the form b c x 2  x   a a

x 2  2x  2  0

2

앖 Coefficient of x —

앖 — Constant term

where the coefficient of x 2 is 1 and the constant term is on the right side of the equation. 2. Square half of the coefficient of x. 3. Add the number obtained in step 2 to both sides of the equation, factor, and solve for x.

x 2  2x  2

앖 Coefficient — of x

앖 — Constant term

2 2 a b  1 2 x 2  2x  1  2  1 (x  1)2  3 x  1  13 x  1 13

46

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 3 Solve by completing the square. a. 4x 2  3x  2  0

b. 6x 2  27  0

Solution

a.

Step 1

First write x2 

3 1 x 0 4 2

x2  Step 2

Divide the original equation by 4, the coefficient of x 2.

3 1 x 4 2

1 to both sides so that the 2 constant term is on the right side.

Add

Square half of the coefficient of x, obtaining a

Step 3

34 2 3 2 9 b  a b  2 8 64

Add 649 to both sides of the equation: x2 

3 9 1 9 x   4 64 2 64 41  64

Factoring, we have ax 

3 2 41 b  8 64 3 241 x  8 8 3 241 1 x  (3 241) 8 8 8

b. This equation is much easier to solve because the coefficient of x is 0. As before, we write the equation in the form 6x 2  27 or

x2 

9 2

Taking the square root of both sides, we have 9 3 322 x   B2 2 22

Using the Quadratic Formula By using the method of completing the square to solve the general quadratic equation ax 2  bx  c  0

(a  0)

we obtain the quadratic formula (but we will not derive the formula here). This formula can be used to solve any quadratic equation. The Quadratic Formula

The solutions of ax2  bx  c  0 (a  0) are given by x

b 2b 2  4ac 2a

1.8 QUADRATIC EQUATIONS

47

EXAMPLE 4 Use the quadratic formula to solve the following: a. 2x 2  5x  12  0

b. x 2  165x  6624  0

c. x 2  3x  8

Solution

a. The equation is in standard form, with a  2, b  5, and c  12. Using the quadratic formula, we find x

5 252  4122 1122 b 2b 2  4ac  2a 2122 

5 11 5 2121  4 4

 4

or

3 2

Observe that this equation can also be solved by factoring. Thus, 2x 2  5x  12  (2x  3)(x  4)  0

from which we see that the desired roots are x  32 or x  4, as obtained earlier. b. The equation is in standard form, with a  1, b  165, and c  6624. Using the quadratic formula, we find x

165 21652  4112 166242 b 2b 2  4ac  2a 2112 

165 2729 2



165 27  96 2

or

69

In this case, using the quadratic formula is preferable to factoring the quadratic equation. c. We first rewrite the given equation in the standard form x 2  3x  8  0, from which we see that a  1, b  3, and c  8. Using the quadratic formula, we find x

3 232  4112 182 3 241 b 2b 2  4ac   2a 2112 2

That is, the solutions are 3  241  1.7 2

or

3  241  4.7 2

In this case, the quadratic formula proves quite handy! EXAMPLE 5 Use the quadratic formula to solve 9x 2  12x  4  0. Solution

Using the quadratic formula with a  9, b  12, and c  4, we find

that x 

1122 21122 2  4192 142 b 2b2  4ac  2a 2192 12 2144  144 12 2   18 18 3

Here the only solution is x  23. We refer to 23 as a double root. (This equation could also be solved by factoring. Try it!)

48

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 6 Solve the equation 22x  1  2x  3  1  0. Solution

We proceed as follows:

22x  1  2x  3  1 2x  1  ( 2x  3  1)2 2x  1  x  3  2 2x  3  1 x  5  2 2x  3 (x  5)2  (2 2x  3)2 x 2  10x  25  4x  12 x 2  14x  13  0 (x  1)(x  13)  0 x  1 or 13

Add 2x  3  1 to both sides. Square both sides.

Simplify. Square both sides.

Next, we need to verify that these solutions of the quadratic equation are indeed the solutions of the original equation. Recall that squaring an equation could introduce extraneous solutions. Now, substituting x  1 into the original equation gives 22  1  21  3  1  1  2  1  0

and so x  1 is a solution. On the other hand, if x  13, we have 226  1  216  1  5  4  1  2  0

and so x  13 is an extraneous solution. Therefore, the required solution is x  1. The following example gives an application involving quadratic equations. APPLIED EXAMPLE 7 Book Design A production editor at a textbook publishing house decided that the pages of a book should have 1-inch margins at the top and bottom and 12 -inch margins on the sides. She further stipulated that the length of a page should be 121 times its width and have a printed area of exactly 51 square inches. Find the dimensions of a page of the book. Let x denote the width of a page of the book (Figure 3). Then the length of the page is 32 x. The dimensions of the printed area of the page are 1 32 x  2 2 inches by (x  1) inches, and so its area is 1 32 x  2 2 1x  1 2 square inches. Since the printed area is to be exactly 51 square inches, we must have Solution

1 2

in.

3 a x  2 b 1x  12  51 2

1 in.

Expanding the left-hand side of the equation gives

3 x 2

3 2 3 x  x  2x  2  51 2 2 3 2 7 x  x  49  0 2 2 2 3x  7x  98  0

–2 3 x 2

Multiply both sides by 2.

Factoring, we have (3x  14)(x  7)  0 x–1 x FIGURE 3

143

and so x  or x  7. Since x must be positive, we reject the negative root and conclude that the required solution is x  7. Therefore, the dimensions of the page are 7 inches by 32 (7), or 1012 , inches.

1.8 QUADRATIC EQUATIONS TABLE 13 Solutions to a Quadratic Equation

Discriminant b2  4ac

Positive Equal to 0 Negative

Number of Solutions

Two real and distinct solutions One real solution No real solution

49

The quantity b2  4ac, which appears under the radical sign in the quadratic formula, is called the discriminant. We use the discriminant to determine the number of solutions of a quadratic equation. If the discriminant is positive, the equation has two real and distinct roots (Example 4a–c). If the discriminant is equal to 0, the equation has one double root (Example 5). Finally, if the discriminant is negative, the equation has no real roots. These results are summarized in Table 13. EXAMPLE 8 Use the discriminant to determine the number of real solutions of each equation. a. x 2  7x  4  0

b. 2x 2  3x  4  0

Solution

a. Here a  1, b  7, and c  4. Therefore, b2  4ac  (7)2  4(1)(4)  49  16  33

and we conclude that the equation has two real and distinct solutions. b. Here a  2, b  3, and c  4. Therefore, b2  4ac  (3)2  4(2)(4)  9  32  23

Since the discriminant is negative, we conclude that the equation has no real solution.

1.8 Self-Check Exercises 2. Solve the equation 2x 2  4x  8  0 a. By completing the square b. By using the quadratic formula

1. Solve by factoring: a. x 2  5x  6  0 b. 4t 2  4t  3

Solutions to Self-Check Exercises 1.8 can be found on page 52.

1.8 Concept Questions 1. What is a quadratic equation in x? Give an example.

3. State the quadratic formula. Illustrate its use with an example.

2. Explain the method of completing the square. Illustrate with an example.

1.8 Exercises In Exercises 1–16, solve the equation by factoring, if required.

1. (x  3)(x  2)  0

2. ( y  3)(y  4)  0

3. x 2  4  0

4. 2m2  32  0

5. x  x  12  0

6. 3x  x  4  0

2

2

7. 4t 2  2t  2  0 9.

1 2 x x10 4

11. 2m2  m  6

8. 6x 2  x  12  0 10.

1 2 a  a  12  0 2

12. 6x 2  5x  6

50

1 FUNDAMENTALS OF ALGEBRA

13. 4x 2  9  0

14. 8m2  64m  0

15. z(2z  1)  6

16. 13m  5  6m2

In Exercises 17–26, solve the equation by completing the square.

17. x 2  2x  8  0

18. x 2  x  6  0

19. 6x 2  12x  3

20. 2x 2  6x  20

21. m2  3  m

22. p2  4  2p

23. 3x  4  2x 2

24. 10x  5  4x 2

25. 4x  13  0

26. 7p  20  0

2

2

In Exercises 27–36, solve the equation by using the quadratic formula.

27. 2x 2  x  6  0

28. 6x 2  7x  3  0

29. m2  4m  1

30. 2x 2  8x  3

31. 8x  3  8x 2

32. 6p  6  p2

33. 4x  2x 2  3

34. 15  2y 2  7y

35. 2.1x 2  4.7x  6.2  0

36. 0.2m2  1.6m  1.2  0

In Exercises 37–44, solve the equation.

37. x 4  5x 2  6  0

Hint: Let m  x 2. Then solve the quadratic equation in m.

38. m4  13m2  36  0

Hint: Let x  m2. Then solve the quadratic equation in x.

39. y 4  5y 2  6  0

49. 1  51.

40. 4x  21x  5  0 Hint: Let y  x 2.

41. 6(x  2)2  7(x  2)  3  0 Hint: Let y  x  2.

42. 8(2m  3)2  14(2m  3)  15  0 Hint: Let x  2m  3.

43. 6w  13 1w  6  0 Hint: Let x  1w.

44. a

t 2t b  30 t1 t1

53.

4 24 3x   2 x2 x2 x 4

54.

2 3 3x  5 2 x1 x x x

55.

2t  1 t   1 t2 t1

56.

x 3 2 0   2 x1 x2 x x2

57. 2u 2  u  5  1

58. 26x 2  5x  2  0

59. 22r  3  r

60. 23  4x  2x  0

61. 2s  2  2s  3  1  0 62. 2x  1  22x  5  1  0 In Exercises 63–70, use the discriminant to determine the number of real solutions of the equation.

63. x 2  6x  5  0

64. 2m2  5m  3  0

65. 3y 2  4y  5  0

66. 2p2  5p  6  0

67. 4x 2  12x  9  0

68. 25x 2  80x  64  0

Hint: Be sure to check for extraneous solutions.

2 4  4 x3 x

47. x  2 

3 0 2x  1

6 k

2



1 20 k

70. (2p  1)2  3(2p  1)  4  0 71. MOTION OF A BALL A person standing on the balcony of a building throws a ball directly upward. The height of the ball as measured from the ground after t sec is given by h  16t 2  64t  768. When does the ball reach the ground?

h(t)  16t 2  384t  4

t . t1

In Exercises 45–62, solve the equation.

45.

2x 7  x1 3

72. MOTION OF A MODEL ROCKET A model rocket is launched vertically upward so that its height (measured in feet) t sec after launch is given by

2

Hint: Let x 

x 1



1 2  20 k k

m 27 2   2 m2 7 m m2

69.

2

3 2

50. 6 

52.

Hint: Let x  y 2. 4

5 6  20 2y y

46.

3y  1 4 5   4 y1 2

48.

3  2x x2  x1 x1

a. Find the time(s) when the rocket is at a height of 1284 ft. b. How long is the rocket in flight? 73. MOTION OF A CYCLIST A cyclist riding along a straight path has a speed of u ft/sec as she passes a tree. Accelerating at a ft/sec2, she reaches a speed of √ ft/sec t sec later, where √  ut  at 2. If the cyclist was traveling at 10 ft/sec and she began accelerating at a rate of 4 ft/sec2 as she passed the tree, how long did it take her to reach a speed of 22 ft/sec?

1.8 QUADRATIC EQUATIONS

74. PROFIT OF A VINEYARD Phillip, the proprietor of a vineyard estimates that the profit from producing and selling (x  10,000) bottles of wine is P  0.0002x 2  3x  50,000. Find the level(s) of production that will yield a profit of $60,800.

is called the golden ratio. Show that 1 r  a b 11  252  1.6 2

75. DEMAND FOR SMOKE ALARMS The quantity demanded x (measured in units of a thousand) of the Sentinel smoke alarm/week is related to its unit price p (in dollars) by the equation p

30 0.02x 2  1

51

y

x

(0 x 10)

Note: A structure or a picture with a ratio of width to height equal to the golden ratio is especially pleasing to the eye. In fact, this golden ratio was used by the ancient Greeks in designing their beautiful temples and public buildings such as the Parthenon (see photo below).

If the unit price is set at $10, what is the quantity demanded? 76. DEMAND FOR COMMODITIES The quantity demanded x (measured in units of a thousand) of a certain commodity when the unit price is set at $p is given by the equation p  2x 2  100

77. SUPPLY OF SATELLITE RADIOS The quantity x of satellite radios that a manufacturer will make available in the marketplace is related to the unit price p (in dollars) by the equation p

1 2x  10 10

How many satellite radios will the manufacturer make available in the marketplace if the unit price is $30? 78. SUPPLY OF DESK LAMPS The supplier of the Luminar desk lamp will make x thousand units of the lamp available in the marketplace if its unit price is p dollars, where p and x are related by the equation p  0.1x 2  0.5x  15

If the unit price of the lamp is set at $20, how many units will the supplier make available in the marketplace? 79. OXYGEN CONTENT OF A POND When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. Suppose the oxygen content t days after organic waste has been dumped into the pond is given by P  100 a

© Jim Winkley/Ecoscene/Corbis

If the unit price is set at $6, what is the quantity demanded?

81. CONSTRUCTING A BOX By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made (see the accompanying figure). If the cardboard is 16 in. long and 10 in. wide, find the dimensions of the resulting box if it is to have a total surface area of 144 in.2. x

x

x

x

10 10 – 2x

x

x x

t  10t  100 b t 2  20t  100 2

x

16 – 2x 16

percent of its normal level. Find t corresponding to an oxygen content of 80% and interpret your results. 80. THE GOLDEN RATIO Consider a rectangle of width x and height y (see the accompanying figure). The ratio r  xy satisfying the equation – 10 2x

xy x  y x

x

– 16

2x

52

1 FUNDAMENTALS OF ALGEBRA

82. ENCLOSING AN AREA Carmen wishes to put up a fence around a proposed rectangular garden in her backyard. The length of the garden is to be twice its width, and the area of the garden is to be 200 ft2. How many feet of fencing does she need? 83. ENCLOSING AN AREA George has 120 ft of fencing. He wishes to cut it into two pieces, with the purpose of enclosing two square regions. If the sum of the areas of the regions enclosed is 562.5 ft2, how long should each piece of fencing be?

87. DESIGNING A METAL CONTAINER A metal container consists of a right circular cylinder with hemispherical ends. The surface area of the container is S  2␲rl  4␲r 2, where l is the length of the cylinder and r is the radius of the hemisphere. If the length of the cylinder is 4 ft and the surface area of the container is 28␲ ft2, what is the radius of each hemisphere? r

84. WIDTH OF A SIDEWALK A rectangular garden of length 40 ft and width 20 ft is surrounded by a path of uniform width. If the area of the walkway is 325 ft2, what is its width? 85. ENCLOSING AN AREA The owner of the Rancho los Feliz has 3000 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river. What are the dimensions of the largest area that can be enclosed?

l

88. OIL SPILLS In calm waters the oil spilling from the ruptured hull of a grounded oil tanker spreads in all directions. The area polluted at a certain instant of time was circular with a radius of 100 ft. A little later, the area, still circular, had increased by 4400␲ ft2. By how much had the radius increased? In Exercises 89–92, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.

89. If a and b are real numbers and ab  0, then a  0 or b  0. 86. RADIUS OF A CYLINDRICAL CAN The surface area of a right circular cylinder is given by S  2␲r 2  2␲rh, where r is the radius of the cylinder and h is its height. What is the radius of a cylinder of surface area 100 in.2 and height 3 in.? r

90. If a, b, and c are real numbers and abc  0, then a real number but b a c may not be a real number.

 b c

91. If b2  4ac  0 and a  0, then the roots of ax 2  bx  c  0 are the negatives of the roots of ax 2  bx  c  0. 92. If b2  4ac  0 and a  0, then ax 2  bx  c  0 has two distinct real roots, or it has no real roots at all.

h

1.8 Solutions to Self-Check Exercises 1. a. Factoring the given equation, we have x 2  5x  6  (x  3)(x  2) 0

and x  3 or x  2.

4t  4t  3  0

and t  32 or t   12. 2. a. Step 1

First write

x 2  2x  4  0

b. Rewriting the given equation, we have 2

is a

Add 3 to both sides of the equation.

Factoring this equation gives (2t  3)(2t  1)  0

Divide the original equation by 2, the coefficient of x 2.

x2  2x  4 Step 2

Add 4 to both sides so that the constant term is on the right side.

Square half of the coefficient of x, obtaining a

2 2 b 1 2

53

1.9 INEQUALITIES AND ABSOLUTE VALUE

b. Using the quadratic formula, with a  2, b  4, and c  8, we obtain

Add 1 to both sides of the equation:

Step 3

x 2  2x  1  5

x

Factoring, we have (x  1)2  5



x  1  15

14 2 2142 2  4122 18 2 b 2b2  4ac  2a 2122

4 280 4 425  4 4

 1 25

x  1 15

1.9 Inequalities and Absolute Value Intervals We described the system of real numbers and its properties in Section 1.1. Often we will restrict our attention to certain subsets of the set of real numbers. For example, if x denotes the number of cars rolling off an assembly line each day in an automobile assembly plant, then x must be nonnegative; that is, x  0. Taking this example one step further, suppose management decides that the daily production must not exceed 200 cars. Then x must satisfy the inequality 0 x 200. More generally, we will be interested in certain subsets of real numbers called finite intervals and infinite intervals. Finite intervals are open, closed, or half-open. The set of all real numbers that lie strictly between two fixed numbers a and b is called an open interval (a, b). It consists of all real numbers x that satisfy the inequalities a x b; it is called “open” because neither of its endpoints is included in the interval. A closed interval contains both of its endpoints. Thus, the set of all real numbers x that satisfy the inequalities a x b is the closed interval [a, b]. Notice that brackets are used to indicate that the endpoints are included in this interval. Half-open intervals (also called half-closed intervals) contain only one of their endpoints. The interval [a, b) is the set of all real numbers x that satisfy a x b, whereas the interval (a, b] is described by the inequalities a x b. Examples of these finite intervals are illustrated in Table 14. TABLE 14 Finite Intervals

Interval

Open Closed

Graph

Example

(a, b)

x a

b

a

b

a

b

[a, b]

x

Half-open (a, b]

x

Half-open [a, b) b

x –3 –2 –1

0

1

2

3

–1

0

1

2

1

2

3

1

2

3

[1, 2]

x

1 12, 34

x 0

x a

(2, 1)

312, 32

1 2

x – 12 0

Infinite intervals include the half lines (a, ), [a, ), (, a), and (, a], defined by the set of all real numbers that satisfy x  a, x  a, x a, and x a, respectively. The symbol , called infinity, is not a real number. It is used here only for notational purposes in conjunction with the definition of infinite intervals. The

54

1 FUNDAMENTALS OF ALGEBRA

notation (, ) is used for the set of real numbers x, since, by definition, the inequalities  x  hold for any real number x. These infinite intervals are illustrated in Table 15. TABLE 15 Infinite Intervals

Interval

Graph

Example

(a, )

(2, )

x

x 0

a

[a, )

x –1

0

(, 1)

x a

(, a]

2

[1, )

x a

(, a)

1

x 0

1

– 12 0

1

1 Ó,  2 

x a

x 2

Inequalities In practical applications, intervals are often found by solving one or more inequalities involving a variable. To solve these inequalities, we use the properties listed in Table 16. TABLE 16 Properties of Inequalities

Property

Illustration

Let a, b, and c be any real numbers. 1. If a b and b c, then a c. 2. If a b, then a  c b  c. 3. If a b and c  0, then ac bc.

4. If a b and c 0, then ac  bc.

2 3 and 3 8, so 2 8. 5 3, so 5  2 3  2; that is, 3 1. 5 3 and 2  0, so (5)(2) (3)(2); that is, 10 6. 2 4 and 3 0, so (2)(3)  (4)(3); that is, 6  12.

Similar properties hold if each inequality sign, , between a and b is replaced by , , or . A real number is a solution of an inequality involving a variable if a true statement is obtained when the variable is replaced by that number. The set of all real numbers satisfying the inequality is called the solution set. EXAMPLE 1 Solve 3x  2 7. Solution

Add 2 to each side of the inequality, obtaining 3x  2  2 7  2 3x 9

1.9 INEQUALITIES AND ABSOLUTE VALUE

55

Next, multiply each side of the inequality by 13, obtaining 1 1 13x2 192 3 3 x 3

The solution is the set of all values of x in the interval (, 3). EXAMPLE 2 Solve 1 2x  5 7 and graph the solution set. Solution

Add 5 to each member of the double inequality, obtaining 4 2x 12

Next multiply each member of the resulting double inequality by 12, yielding x 0

2

2 x 6

6

FIGURE 4 The graph of the solution set for 1 2x  5 7

Thus, the solution is the set of all values of x lying in the interval [2, 6). The graph of the solution set is shown in Figure 4.

Solving Inequalities by Factoring The method of factoring can be used to solve inequalities that involve polynomials of degree 2 or higher. This method relies on the principle that a polynomial changes sign only at a point where its value is 0. To find the values of x where the polynomial is equal to 0, we set the polynomial equal to 0 and then solve for x. The values obtained can then be used to help us solve the given inequality. In Example 3 detailed steps are provided for this technique. EXAMPLE 3 Solve x 2  5x  6  0. Solution Step 1

Set the polynomial in the inequality equal to 0: x2  5x  6  0

Step 2

Factor the polynomial: (x  3)(x  2)  0

Step 3

Construct a sign diagram for the factors of the polynomial. We use a  to indicate that a factor is positive for a given value of x, a  to indicate that it is negative, and a 0 to indicate that it is equal to 0. Now, x  3 0 if x 3, x  3  0 if x  3, and x  3  0 if x  3. Similarly, x  2 0 if x 2, x  2  0 if x  2, and x  2  0 if x  2. Using this information, we construct the sign diagram shown in Figure 5.

Sign of (x  3) _ _ _ _ _ _ _ _ _ _ _ 0 + + + + (x  2) _ _ _ _ _ _ _ _ _ 0 + + + + + +

x 0

FIGURE 5 Step 4

2

3

Determine the intervals that satisfy the given inequality. Since x 2  5x  6  0, we require that the product of the two factors be positive—that is, that both factors have the same sign. From the sign diagram, we see that the two factors have the same sign when x 2 or x  3. Thus, the solution set is (, 2)  (3, ).

56

1 FUNDAMENTALS OF ALGEBRA

EXAMPLE 4 Solve x 2  2x  8 0. Solution Step 1 Step 2 Step 3

x 2  2x  8  0 (x  4)(x  2)  0, so x  4 or x  2. x  4  0 when x  4, x  4 0 when x 4, and x  4  0 when x  4. Similarly, x  2  0 when x  2, x  2 0 when x 2, and x  2  0 when x  2. Using these results, we construct the sign diagram for the factors of x 2  2x  8 (Figure 6).

Sign of (x  4) _ _ 0 + + + + + + + + + + + + + + + + + + (x  2) _ _ _ _ _ _ _ _ _ _ _ _ _ _ 0 + + + + + + FIGURE 6

5 4 3 2 1 Step 4

x 0

1

2

3

4

5

Since x 2  2x  8 0, the product of the two factors must be negative; that is, the signs of the two factors must differ. From the sign diagram, we see that the two factors x  4 and x  2 have opposite signs when x lies strictly between 4 and 2. Therefore, the required solution is the interval (4, 2).

Solving Inequalities Involving a Quotient The next two examples show how an inequality involving the quotient of two algebraic expressions is solved. EXAMPLE 5 Solve

x1  0. x1

The quotient (x  1)/(x  1) is positive (greater than 0) when the numerator and denominator have the same sign. The signs of x  1 and x  1 are shown in Figure 7.

Solution

Sign of (x  1) _ _ _ _ _ _ 0 + + + + + + + + + + (x  1) _ _ _ _ _ _ _ _ _ _ 0 + + + + + + FIGURE 7

4 3 2 1

x 0

1

2

3

4

From the sign diagram, we see that x  1 and x  1 have the same sign when x 1 or x  1. The quotient (x  1)/(x  1) is equal to 0 when x  1. It is undefined at x  1 since the denominator is 0 at that point. Therefore, the required solution is the set of all x in the intervals (, 1] and (1, ). EXAMPLE 6 Solve Solution

2x  1  1. x2

We rewrite the given inequality so that the right side is equal to 0: 2x  1 10 x2 2x  1  1x  22 0 x2 2x  1  x  2 0 x2 x1 0 x2

1.9 INEQUALITIES AND ABSOLUTE VALUE

57

Next we construct the sign diagram for the factors in the numerator and the denominator (Figure 8). Sign of (x  1) _ _ _ _ 0 + + + + + + + + + + (x  2) _ _ _ _ _ _ _ _ _ _ 0 + + + + FIGURE 8

1

x 0

2

Since the quotient of these two factors must be positive or equal to 0, we require that the sign of each factor be the same or that the quotient of the two factors be equal to 0. From the sign diagram, we see that the solution set is given by (, 1] and (2, ). Note that x  2 is not included in the second interval since division by 0 is not allowed. APPLIED EXAMPLE 7 Gross Domestic Product The gross domestic product (GDP) of a certain country is projected to be t 2  2t  50 billion dollars t years from now. Find the time t when the GDP of the country will first equal or exceed $58 billion. Solution

The GDP of the country will equal or exceed $58 billion when t 2  2t  50  58

To solve this inequality for t, we first write it in the form t 2  2t  8  0 (t  4)(t  2)  0

The sign diagram for the factors of t 2  2t  8 is shown in Figure 9. Sign of (t  4) _ _ _ 0 + + + + + + + + + + + (t  2) _ _ _ _ _ _ _ _ _ _ 0 + + + + 4

FIGURE 9

t 0

2

From the sign diagram, we see that the required solution set is (, 4]  [2, ). Since t must be nonnegative for the problem to be meaningful, we see that the GDP of the country is greater than or equal to $58 billion when t  2; that is, the GDP will first equal or exceed $58 billion when t  2, or 2 years from now. APPLIED EXAMPLE 8 Stock Purchase The management of Corbyco, a giant conglomerate, has estimated that x thousand dollars is needed to purchase 100,000(1  21  0.001x)

shares of common stock of the Starr Communications Company. Determine how much money Corbyco needs in order to purchase at least 100,000 shares of Starr’s stock. The amount of cash Corbyco needs to purchase at least 100,000 shares is found by solving the inequality

Solution

100,000(1  21  0.001x)  100,000

58

1 FUNDAMENTALS OF ALGEBRA

Proceeding, we find 1  21  0.001x  1 21  0.001x  2 1  0.001x  4 Square both sides. 0.001x  3 x  3000

so Corbyco needs at least $3,000,000. (Remember, x is measured in thousands of dollars.)

Absolute Value

5

Absolute Value

5

The absolute value of a number a is denoted by  a  and is defined by x

–5

a 

5

0

(a)  a

 a x

–a 0 (b) FIGURE 10

a

aa

if a  0 if a 0

Since a is a positive number when a is negative, it follows that the absolute value of a number is always nonnegative. For example,  5   5 and 5   (5)  5. Geometrically,  a  is the distance between the origin and the point on the number line that represents the number a (Figure 10a and b). The absolute value properties are given in Table 17. Property 4 is called the triangle inequality. TABLE 17 Absolute Value Properties

Property

If a and b are any real numbers, then 1.  a    a  2.  ab    a  b 

3.

 3   (3)  3   3   (2)(3)    6   6   2  3  132

a

b  b a

Illustration

 3 

142  4  4   4 

4.  a  b   a    b 

3

 8  (5)    3   3

 8    5   13

EXAMPLE 9 Evaluate: a.  ␲  5   3

3

b.  13  2    2  13 

Solution

a. Since ␲  5 0, we see that  ␲  5   (␲  5). Therefore,  ␲  5   3  (␲  5)  3  ␲  5  3  8  ␲

1.9 INEQUALITIES AND ABSOLUTE VALUE

59

b. Since 13  2 0, we see that  13  2   ( 13  2). Next observe that 2  13  0, so  2  13   2  13 . Therefore,  13  2    2  13   ( 13  2)  (2  13 )   13  2  2  13  4  2 13  2(2  13 )

EXAMPLE 10 Solve the inequalities  x  5 and  x   5. Solution We first consider the inequality  x  5. If x  0, then  x   x, so  x  5 implies x 5 in this case. However, if x 0, then  x   x, so  x  5 implies x 5, or x  5. Thus,  x  5 means 5 x 5 (Figure 11a). Alternatively, observe that  x  is the distance from the point x to 0, so the inequality  x  5 implies immediately that 5 x 5. Next, the inequality  x   5 states that the distance from x to 0 is greater than or equal to 5. This observation yields the result x  5 or x 5 (Figure 11b). x –5

x –5

5

0

(a)  x  5

FIGURE 11

0

5

(b)  x   5

The results of Example 10 may be generalized. Thus, if k  0, then  x  k is equivalent to k x k and  x   k is equivalent to x  k or x k. EXAMPLE 11 Solve the inequality  2x  3  1. Solution The inequality  2x  3  1 is equivalent to the inequalities 1 2x  3 1 (see Example 10). Then

2 2x 4 x 0 1 FIGURE 12

and

2

1 x 2

 2x  3  1

Add 3 to each member of the inequality.

1 Multiply each member of the inequality by . 2

Therefore, the solution is given by the set of all x in the interval [1, 2] (Figure 12). EXAMPLE 12 Solve the inequality  5x  7   18. Solution

Referring to Example 10 once again, we see that  5x  7   18 is equiv-

alent to 5x  7 18 or 5x  7  18

That is,

5 FIGURE 13

 5x  7   18

5x 25 or 5x  11 11 x 5 x 5

x 0

11 5

Therefore, the solution is given by the set of all x in the interval (, 5] or the interval 3 115,  2 (Figure 13).

1.9 Self-Check Exercises 1. Solve 1 2x  1 5 and graph the solution set.

2. Solve 6x 2  5x  4 0. Solutions to Self-Check Exercises 1.9 can be found on page 62.

60

1 FUNDAMENTALS OF ALGEBRA

1.9 Concept Questions 1. State the properties of inequalities. Illustrate with examples.

3. State the absolute value properties. Illustrate with examples.

2. What is the absolute value of a number a? Can  a  be negative? Explain.

1.9 Exercises In Exercises 1–4, determine whether the statement is true or false.

1. 3 20 3.

2 5  3 6

2. 5 5 11 5 4.   6 12

In Exercises 5–10, show the interval on a number line.

5. (3, 6)

6. (2, 5]

7. [1, 4)

6 1 8. c  ,  d 5 2

9. (0, )

10. (, 5]

In Exercises 11–28, find the values of x that satisfy the inequalities.

11. 2x  4 8

12. 6  4  5x

13. 4x  20

14. 12 3x

15. 6 x  2 4

16. 0 x  1 4

35.  ␲  1   2

36.  ␲  6   3

37.  22  1    3  22 

38.  2 23  3    23  4 

In Exercises 39–44, suppose a and b are real numbers other than 0 and a ⬎ b. State whether the inequality is true or false.

39. b  a  0

40.

a 1 b

41. a2  b2

42.

1 1  a b

43. a3  b3

44. a b

45. Write the inequality  x  a  b without using absolute values. 46. Write the inequality  x  a   b without using absolute values. In Exercises 47–52, determine whether the statement is true for all real numbers a and b.

17. x  1  4 or x  2 1

47.  a   a

48.  b2   b2

18. x  1  2 or x  1 2

49.  a  4    4  a 

50.  a  1    a   1

19. x  3  1 and x  2 1

51.  a  b    a    b 

52.  a  b    a    b 

20. x  4 1 and x  3  2

53. Find the minimum cost C (in dollars) given that

21. (x  3)(x  5) 0

22. (2x  4)(x  2)  0

23. (2x  3)(x  1)  0

24. (3x  4)(2x  2) 0

25.

x3 0 x2

x2 27.

2 x1

26.

2x  3 4 x1

2x  1 28.

4 x2

In Exercises 29–38, evaluate the expression.

29.  6  2  31.

 12  4   16  12 

33. 23  2   3   23 

30. 4   4  32.

 1.4

0.2 1.6  2.4

34.  1   22  2 

5(C  25)  1.75  2.5C

54. Find the maximum profit P (in dollars) given that 6(P  2500) 4(P  2400)

55. DRIVING RANGE OF A CAR An advertisement for a certain car states that the EPA fuel economy is 20 mpg city and 27 mpg highway and that the car’s fuel-tank capacity is 18.1 gal. Assuming ideal driving conditions, determine the driving range for the car from the foregoing data. 56. CELSIUS AND FAHRENHEIT TEMPERATURES The relationship between Celsius (°C) and Fahrenheit (°F) temperatures is given by the formula 5 C  (F  32) 9

1.9 INEQUALITIES AND ABSOLUTE VALUE

61

a. If the temperature range for Montreal during the month of January is 15° C° 5°, find the range in degrees Fahrenheit in Montreal for the same period. b. If the temperature range for New York City during the month of June is 63° F° 80°, find the range in degrees Celsius in New York City for the same period.

63. EFFECT OF BACTERICIDE The number of bacteria in a certain culture t min after an experimental bactericide is introduced is given by

57. MEETING SALES TARGETS A salesman’s monthly commission is 15% on all sales over $12,000. If his goal is to make a commission of at least $3000/mo, what minimum monthly sales figures must he attain?

Find the time when the number of bacteria will have dropped below 4000.

58. MARKUP ON A CAR The markup on a used car was at least 30% of its current wholesale price. If the car was sold for $6500, what was the maximum wholesale price? 59. MEETING PROFIT GOALS A manufacturer of a certain commodity has estimated that her profit (in thousands of dollars) is given by the expression 6x 2  30x  10

where x (in thousands) is the number of units produced. What production range will enable the manufacturer to realize a profit of at least $14,000 on the commodity? 60. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration (in milligrams/cubic centimeter) of a certain drug in a patient’s bloodstream t hr after injection is given by 0.2t t2  1

Find the interval of time when the concentration of the drug is greater than or equal to 0.08 mg/cc. 61. COST OF REMOVING TOXIC POLLUTANTS A city’s main well was recently found to be contaminated with trichloroethylene (a cancer-causing chemical) as a result of an abandoned chemical dump that leached chemicals into the water. A proposal submitted to the city council indicated that the cost, in millions of dollars, of removing x% of the toxic pollutants is 0.5x 100  x

If the city could raise between $25 and $30 million inclusive for the purpose of removing the toxic pollutants, what is the range of pollutants that could be expected to be removed? 62. AVERAGE SPEED OF A VEHICLE The average speed of a vehicle in miles per hour on a stretch of route 134 between 6 a.m. and 10 a.m. on a typical weekday is approximated by the expression 20t  402t  50

10 t 42

where t is measured in hours, with t  0 corresponding to 6 a.m. Over what interval of time is the average speed of a vehicle less than or equal to 35 mph?

10,000 t2  1

 2000

64. AIR POLLUTION Nitrogen dioxide is a brown gas that impairs breathing. The amount of nitrogen dioxide present in the atmosphere on a certain May day in the city of Long Beach measured in PSI (pollutant standard index) at time t, where t is measured in hours, and t  0 corresponds to 7 a.m., is approximated by 136  28 1  0.251t  4.52 2

10 t 112

Find the time of the day when the amount of nitrogen dioxide is greater than or equal to 128 PSI. Source: Los Angeles Times

65. A ball is thrown straight up so that its height after t sec is 128t  16t 2  4

ft. Determine the length of time the ball stays above a height of 196 ft. 66. DISTRIBUTION OF INCOME The distribution of income in a certain city can be described by the mathematical model y  (2.8  1011)(x)1.5, where y is the number of families with an income of x or more dollars. a. How many families in this city have an income of $20,000 or more? b. How many families have an income of $40,000 or more? c. How many families have an income of $100,000 or more? 67. QUALITY CONTROL PAR Manufacturing Company manufactures steel rods. Suppose the rods ordered by a customer are manufactured to a specification of 0.5 in. and are acceptable only if they are within the tolerance limits of 0.49 in. and 0.51 in. Letting x denote the diameter of a rod, write an inequality using absolute value to express a criterion involving x that must be satisfied in order for a rod to be acceptable. 68. QUALITY CONTROL The diameter x (in inches) of a batch of ball bearings manufactured by PAR Manufacturing satisfies the inequality  x  0.1 0.01

What is the smallest diameter a ball bearing in the batch can have? The largest diameter?

62

1 FUNDAMENTALS OF ALGEBRA

1.9 Solutions to Self-Check Exercises 1.

1 2x  1 5 1  1 2x  1  1 5  1 0 2x 6 0 x 3

2x  1 0 when x 12. Using these results, we construct the following sign diagram for the factors of 6x 2  5x  4:

Add 1 to each member of the inequality. Combine like terms. Multiply each member of the inequality by 2 1 .

Sign of (3x  4) _ _ _ _ _ _ _ _ _ _ 0 + + + + (2x  1) _ _ _ _ 0 + + + + + + + + + +

We conclude that the solution set is (0, 3]. The graph of the solution set is shown in the following figure:

x  12

x 0

2. Step 1 Step 2 Step 3

0

4 3

3

6x 2  5x  4 0 (3x  4)(2x  1) 0 3x  4  0 when x  34, 3x  4  0 when x  43, and 3x  4 0 when x 43. Similarly, 2x  1  0 when x  21, 2x  1  0 when x  12, and

Step 4

Since 6x 2  5x  4 0, the signs of the two factors must differ or be equal to 0. From the sign diagram, we see that x must lie between 12 and 43, inclusive. Therefore, the required solution is 312, 43 4 .

CHAPTER 1 Summary of Principal Formulas and Terms FORMULAS 1. Product formula

(a  b)2  a2  2ab  b2 (a  b)2  a2  2ab  b2 (a  b)(a  b)  a2  b2

2. Quadratic formula

x

3. Difference of two squares

a 2  b 2  (a  b)(a  b)

4. Perfect square trinomial

a 2  2ab  b 2  (a  b)2 a 2  2ab  b 2  (a  b)2

5. Sum of two cubes

a 3  b 3  (a  b)(a 2  ab  b 2)

6. Difference of two cubes

a3  b3  (a  b)(a2  ab  b2)

b 2b2  4ac 2a

TERMS natural number (2) whole number (2) integer (2) rational number (2) irrational number (2) real number (2) exponent (7) base (7) polynomial (9) rational expression (20) compound fraction (23) equation (30)

variable (30) solution of an equation (30) solution set (30) linear equation (30) extraneous solution (32) nth root (36) square root (36) cube root (36) radical (37) radical sign (37) radicand (37)

index (37) conjugate (41) quadratic equation (44) discriminant (49) finite interval (53) open interval (53) closed interval (53) half-open interval (53) infinite interval (53) absolute value (58) triangle inequality (58)

REVIEW EXERCISES

63

CHAPTER 1 Concept Review Questions Fill in the blanks. a b,

1. a. A number of the form where a and b are integers, with b ⬆ 0 is called a/an _____ number. A rational number can be represented by either a/an _____ or _____ decimal. b. A real number that is not rational is called _____ . When such a number is represented by a decimal, it neither _____ nor _____ . 2. a. Under addition, we have a  b  _____ , a  (b  c)  _____ , a  0  _____ , and a  (a)  _____ . b. Under multiplication, we have ab  _____ , a(bc)  _____ , a  1  _____ , and a 1 1a 2  _____ (a ⬆ 0). c. Under addition and multiplication, we have a(b  c)  _____ . 3. a. If a and b are numbers, then (a)  _____ , (a)b  _____ , (a)(b)  _____ , (1)a  a, and a  0  0. b. If ab  0, then a  _____ , or b  _____ , or both. 4. a. An expression of the form an x n  an1 x n1  . . .  a0 is called a/an _____ in _____ ; the nonnegative integer n is called its _____ ; the expression ak x k is called the _____ of the _____ ; and ak is called the _____ of x k. b. To add or subtract two polynomials, we add or subtract _____ terms. 5. To factor a polynomial, we express it as a/an _____ of two or more _____ polynomials. For example, x 3  x 2  2x  _____ . 6. a. A rational expression is a quotient of _____ . b. A rational expression is simplified or reduced to lowest terms if the _____ and the _____ have no common _____ other than _____ and _____ . c. To add or subtract rational expressions, first find the least common _____ of the expressions, if necessary. Then follow the procedure for adding and subtracting _____ with common denominators.

7. A rational expression that contains fractions in its numerator or denominator is called a/an _____ fraction. An example of a compound fraction is _____ . 8. a. If a is any real number and n is a natural number, then an  _____ . The number a is the _____ , and the superscript n is called the _____ , or _____ . b. For any nonzero real number a, a0  _____ . The expression 00 is _____ _____ . c. If a is any nonzero number and n is a positive integer, then an  _____ . 9. a. A statement that two mathematical statements are equal is called a/an _____ . b. A variable is a letter that stands for a/an _____ belonging to a set of real numbers. c. A linear equation in the variable x is an equation that can be written in the form _____ ; a linear equation in x has degree _____ in x. 10. a. If n is a natural number and a and b are real numbers, we say that a is the nth root of b if _____ . b. If n is even, the real nth roots of a positive number b must come in _____ . c. If n is even and b is negative, then there are _____ real roots. d. If n is odd, then there is only one _____ _____ of b. n

11. a. If n is a natural number and b is a real number, then 2b n is called a/an _____ ; also, 2b  _____ . b. To rationalize a denominator of an algebraic expression means to eliminate a/an _____ from the denominator. 12. a. A quadratic equation is an equation in x that can be written in the form _____ . b. A quadratic equation can be solved by _____ , by _____ _____ _____ , or by using the quadratic formula. The quadratic formula is _____ .

CHAPTER 1 Review Exercises In Exercises 1–6, classify the number as to type.

1.

7 8

4. 0

2. 213

3. 2␲

5. 2.71

6. 3.14159. . .

In Exercises 7–14, evaluate the expression.

9 3/2 7. a b 4

8.

56 54

9. (3  4)2 11. a 13.

16 3/2 b 9

27 B 125 3

10. (8)5/3 12.

13 # 23 2 14 # 35 2 2 # 93

3

14.

3 254 3 2 18

64

1 FUNDAMENTALS OF ALGEBRA

In Exercises 15–22, simplify the expression.

41x  y2 2

15.

16.

x y 216x yz 5

19. a

3xy 3

4x y

b

ab

1a b 2

2

a

3xy

3

b

2x 2

3

47. 8x 2  2x  3  0

48. 6x 2  10x  4  0

49. 2x 2  3x  4  0

50. x 2  5x  3  0

20. (3a2b3)2(2a1b2)1

51. 2y 2  3y  1  0

52. 0.3m2  2.1m  3.2  0

53. x 3  2x 2  3x  0

54. 2x 4  x 2  1

x 1/2y 2/3 1/3 3/4

x y

b

6

In Exercises 55–62, solve the equation.

In Exercises 23–30, perform the indicated operations and simplify the expression.

23. (3x  10x  6x  10x  3)  (2x  10x  6x  4x) 3

x1x  12 13x 2  1 2 1/2

In Exercises 47–54, solve the equation. 2

55.

4

x1

3x 3  5x 2  x

#

1 18. (2x )(3x ) a x1/2 b 6

22. a

3 3 21. 2 81x 5y10 2 9xy 2

x13x 2  1 2

3 2 3

3

4 2 81xyz 5 2

46.

6 5

2

4

17.

3

2

4

3

1 3 x2 x5 4 4

56.

57. (x  2)2  3x(1  x)  (x  2)2

2

312q  1 2



3q  1 2q  1

59. 2k  1  22k  3

24. (3x  4)(3x 2  2x  3)

58.

25. (2x  3y)2  (3x  1)(2x  3)

60. 2x  2x  1  24x  3

26. 2(3a  b)  3[(2a  3b)  (a  2b)] 27.

28.

1t  6 2 160 2  160t  180 2 1t  62 2

6x

213x  2 2 2



1 41x  2 2

2x 2x  1

31. 2␲ r  100␲r

3

35. 2x 2  4x  6

36. 12x 2  92x  120

37. 9a2  25b2

38. 8u6√3  27u3

2

39. 6a4b4c  3a3b2c  9a2b2 40. 6x 2  xy  y 2 In Exercises 41–46, perform the indicated operations and simplify the expression.

2x  3x  2 2

3 1t 2  42 12t  42 4  1t 2  4t  42 12t2 1t 2  42 2

44.

3x x 2 2

# 

x2  9 3x 2 x 1

5  12

4  3

67.  5  7    2 

68.

69.  2␲  6   ␲

70.  13  4    4  2 13 

In Exercises 71–76, find the value(s) of x that satisfy the expression.

71. 2x 2  3x  2 0 73.

72. x 2  x  12 0

1 2 x2

74.  2x  3  5 76.

1 x2 9 x x

1

77. Rationalize the numerator:

45.

78. Rationalize the numerator: x2 B yz 3 3

x1

x  1  5

2x  1 x1

x 2  6x  9

3

64. 2 3x  1 7

75.  3x  4  2

2x 2  5x  3

2x  6 43. x3

2mI for I. B1n  1 2

In Exercises 67–70, evaluate the expression.

32. 2√ w  2√w  2u √w 3

34. 12t 3  6t 2  18t

42.

62. Solve r 

66. 2x 2  50

33. 16  x 2

41.

20x for x. 100  x

65. x  3  2 or x  3 1

In Exercises 31–40, factor the expression. 2

61. Solve C 

63. x  3 2x  9

 4 2x  1

2 3

4q  3

In Exercises 63–66, find the values of x that satisfy the inequalities.

3 4x 2 b  3a b 29. a 2 3 2x  1 3x  1 30.

3p  1 2p  1 5p   2 3 12

BEFORE MOVING ON . . .

79. Rationalize the denominator: 2x  1 22x 80. Rationalize the denominator:

65

In Exercises 81 and 82, use the quadratic formula to solve the quadratic equation.

81. x 2  2x  5  0

82. 2x 2  8x  7  0

83. Find the minimum cost C (in dollars) given that 2(1.5C  80) 2(2.5C  20)

3 1  22x

84. Find the maximum revenue R (in dollars) given that 12(2R  320) 4(3R  240)

The problem-solving skills that you learn in each chapter are building blocks for the rest of the course. Therefore, it is a good idea to make sure that you have mastered these skills before moving on to the next chapter. The Before Moving On exercises that follow are designed for that purpose. After taking this test, you can see where your weaknesses, if any, are. Then you can log in at http://academic.cengage.com/login where you will find a link to our Companion Web site. Here, you can click on the Before Moving On button, which will lead you to other versions of these tests. There you can retest yourself on those exercises that you solved incorrectly. (You can also test yourself on these basic skills before taking your course quizzes and exams.) If you feel that you need additional help with these exercises, at this Web site you can also use the CengageNOW tutorials, and get live online tutoring help with PersonalTutor.

CHAPTER 1 Before Moving On . . . 1. Perform the indicated operations and simplify: 2(3x  2)2  3x(x  1)  4

2. Factor: a. x 4  x 3  6x 2 b. (a  b)2  (a 2  b)2

3 2

9x y

b

1

a

2x 2 3y

6. Rationalize the denominator in the expression 2  23

x1 2x  2 3x 2  5x  2 x x2

8x 2y3

r for r. sr

2  23

3. Perform the indicated operation and simplify:

4. Simplify a

5. Solve 2s 

3

b . 2

7. a. Solve 2x 2  5x  12  0 by factoring. b. Solve m2  3m  2  0. 8. Solve 2x  4  2x  5  1  0. 9. Find the values of x that satisfy (3x  2)(2x  3) 0. 10. Find the values of x that satisfy  2x  3  1.

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2

FUNCTIONS AND THEIR GRAPHS

T

HIS CHAPTER INTRODUCES the Cartesian coordinate system, a system that allows us to represent points in the

plane in terms of ordered pairs of real numbers. This in turn enables us to study geometry, using algebraic methods.

represented by algebraic equations. Next, we study functions, which are special relationships between two quantities. These relationships, or mathematical models, can be found in fields of study as diverse as business, economics, the social sciences, physics, and medicine. We study in detail two special classes of functions: linear and quadratic functions. More general functions require the use of the tools of calculus and will be studied in later chapters. Finally, we look at the process of solving real-world problems using mathematics, a process called mathematical modeling.

© B2M Productions/Getty Images

Specifically, we will see how straight lines in the plane can be

Unless changes are made, when is the current Social Security system expected to go broke? In Example 2, page 136, we use a mathematical model constructed from data from the Social Security Administration to predict the year in which the assets of the current system will be depleted.

68

2 FUNCTIONS AND THEIR GRAPHS

2.1 The Cartesian Coordinate System and Straight Lines In Section 1.1 we saw how a one-to-one correspondence between the set of real numbers and the points on a straight line leads to a coordinate system on a line (a onedimensional space). A similar representation for points in a plane (a two-dimensional space) is realized through the Cartesian coordinate system, which we construct as follows: Take two perpendicular lines, one of which is normally chosen to be horizontal. These lines intersect at a point O, called the origin (Figure 1). The horizontal line is called the x-axis, and the vertical line is called the y-axis. A number scale is set up along the x-axis, with the positive numbers lying to the right of the origin and the negative numbers lying to the left of it. Similarly, a number scale is set up along the y-axis, with the positive numbers lying above the origin and the negative numbers lying below it. y

y-axis Origin O

x-axis

x

FIGURE 1 The Cartesian coordinate system

The number scales on the two axes need not be the same. Indeed, in many applications different quantities are represented by x and y. For example, x may represent the number of cell phones sold and y the total revenue resulting from the sales. In such cases it is often desirable to choose different number scales to represent the different quantities. Note, however, that the zeros of both number scales coincide at the origin of the two-dimensional coordinate system. Note

y P(x, y)

y

O

x

x

FIGURE 2 An ordered pair in the coordinate plane

We can represent a point in the plane uniquely in this coordinate system by an ordered pair of numbers—that is, a pair (x, y), where x is the first number and y the second. To see this, let P be any point in the plane (Figure 2). Draw perpendiculars from P to the x-axis and y-axis, respectively. Then the number x is precisely the number that corresponds to the point on the x-axis at which the perpendicular through P hits the x-axis. Similarly, y is the number that corresponds to the point on the y-axis at which the perpendicular through P crosses the y-axis. Conversely, given an ordered pair (x, y) with x as the first number and y the second, a point P in the plane is uniquely determined as follows: Locate the point on the x-axis represented by the number x and draw a line through that point perpendicular to the x-axis. Next, locate the point on the y-axis represented by the number y and draw a line through that point perpendicular to the y-axis. The point of intersection of these two lines is the point P (Figure 2). In the ordered pair (x, y), x is called the abscissa, or x-coordinate, y is called the ordinate, or y-coordinate, and x and y together are referred to as the coordinates of the point P. The point P with x-coordinate equal to a and y-coordinate equal to b is often written P(a, b). The points A(2, 3), B(2, 3), C(2, 3), D(2, 3), E(3, 2), F(4, 0), and G(0, 5) are plotted in Figure 3.

2.1 THE CARTESIAN COORDINATE SYSTEM AND STRAIGHT LINES

Note

69

In general, (x, y)  (y, x). This is illustrated by the points A and E in Figure 3. y 4

B(–2, 3)

A(2, 3) E(3, 2)

2

F(4, 0) –3

1

–1

3

x

5

–2 C(–2, –3)

D(2, – 3) –4 G(0, – 5)

FIGURE 3 Several points in the coordinate plane

–6

The axes divide the plane into four quadrants. Quadrant I consists of the points P with coordinates x and y, denoted by P(x, y), satisfying x  0 and y  0; Quadrant II, the points P(x, y) where x 0 and y  0; Quadrant III, the points P(x, y) where x 0 and y 0; and Quadrant IV, the points P(x, y) where x  0 and y 0 (Figure 4). y

Quadrant II (–, +)

Quadrant I (+, +) x

O

FIGURE 4

Quadrant III (–, –)

Quadrant IV (+, –)

The four quadrants in the coordinate plane

Straight Lines In computing income tax, business firms are allowed by law to depreciate certain assets such as buildings, machines, furniture, automobiles, and so on over a period of time. Linear depreciation, or the straight-line method, is often used for this purpose. The graph of the straight line shown in Figure 5 describes the book value V of a Web server that has an initial value of $10,000 and that is being depreciated linearly over 5 years with a scrap value of $3,000. Note that only the solid portion of the straight line is of interest here.

V ($) 10,000

(5, 3000)

3000

t 1

FIGURE 5 Linear depreciation of an asset

2

3 4 Years

5

70

2 FUNCTIONS AND THEIR GRAPHS

The book value of the server at the end of year t, where t lies between 0 and 5, can be read directly from the graph. But there is one shortcoming in this approach: The result depends on how accurately you draw and read the graph. A better and more accurate method is based on finding an algebraic representation of the depreciation line. (We continue our discussion of the linear depreciation problem in Section 2.5.) To see how a straight line in the xy-plane may be described algebraically, we need first to recall certain properties of straight lines. y

Slope of a Line

L

Let L denote the unique straight line that passes through the two distinct points (x1, y1) and (x2, y2). If x1  x2, then L is a vertical line, and the slope is undefined (Figure 6). If x1  x2, then we define the slope of L as follows.

(x1, y1 )

(x 2, y 2 )

Slope of a Nonvertical Line x

If (x1, y1) and (x2, y2) are any two distinct points on a nonvertical line L, then the slope m of L is given by

FIGURE 6

m

The slope is undefined if x1  x2.

¢y y2  y1  x2  x1 ¢x

(1)

(Figure 7). y

L (x 2, y2 ) y2 – y 1 = Δy

(x1, y1) x2 – x1 = Δ x x FIGURE 7

Observe that the slope of a straight line is a constant whenever it is defined. The number y  y2  y1 (y is read “delta y”) is a measure of the vertical change in y, and  x  x2  x1 is a measure of the horizontal change in x as shown in Figure 7. From this figure we can see that the slope m of a straight line L is a measure of the rate of change of y with respect to x. Furthermore, the slope of a nonvertical straight line is constant, and this tells us that this rate of change is constant. Figure 8a shows a straight line L1 with slope 2. Observe that L1 has the property that a 1-unit increase in x results in a 2-unit increase in y. To see this, let  x  1 in y

y L1 L2

m=2

m = –1

1

2

–1 1 x

x

FIGURE 8

(a) The line rises (m  0).

(b) The line falls (m 0).

2.1 THE CARTESIAN COORDINATE SYSTEM AND STRAIGHT LINES y

m = –2 m = –1

Equation (1) so that m  y. Since m  2, we conclude that y  2. Similarly, Figure 8b shows a line L2 with slope 1. Observe that a straight line with positive slope slants upward from left to right (y increases as x increases), whereas a line with negative slope slants downward from left to right (y decreases as x increases). Finally, Figure 9 shows a family of straight lines passing through the origin with indicated slopes.

m=2 m=1 m = 21 x

m = – 12

71

Explore & Discuss

FIGURE 9 A family of straight lines

Show that the slope of a nonvertical line is independent of the two distinct points used to compute it. Hint: Suppose we pick two other distinct points, P3(x3, y3) and P4(x4, y4) lying on L. Draw a picture and use similar triangles to demonstrate that using P3 and P4 gives the same value as that obtained using P1 and P2.

EXAMPLE 1 Sketch the straight line that passes through the point (2, 5) and has slope 43. First, plot the point (2, 5) (Figure 10). Next, recall that a slope of 43 indicates that an increase of 1 unit in the x-direction produces a decrease of 43 units in the y-direction, or equivalently, a 3-unit increase in the x-direction produces a 31 43 2 , or 4-unit, decrease in the y-direction. Using this information, we plot the point (1, 1) and draw the line through the two points. Solution

y L Δx = 3 5 (–2, 5) Δy = – 4 (1, 1)

FIGURE 10 L has slope (2, 5).

43

and passes through

–5

5

x

EXAMPLE 2 Find the slope m of the line that passes through the points (1, 1) and (5, 3).

y 5

Choose (x1, y1) to be the point (1, 1) and (x2, y2) to be the point (5, 3). Then, with x1  1, y1  1, x2  5, and y2  3, we find, using Equation (1),

Solution

(5, 3) L

3 (–1, 1)

m

x –3

–1

1

3

5

FIGURE 11 L passes through (5, 3) and (1, 1).

y2  y1 31 2 1    x2  x1 5  11 2 6 3

(Figure 11). You may verify that the result obtained would be the same had we chosen the point (1, 1) to be (x2, y2) and the point (5, 3) to be (x1, y1). EXAMPLE 3 Find the slope of the line that passes through the points (2, 5) and (3, 5). Solution

The slope of the required line is given by m

(Figure 12).

55 0  0 3  122 5

72

2 FUNCTIONS AND THEIR GRAPHS y (– 2, 5)

6

(3, 5) L

4

2 x

FIGURE 12

–2

The slope of the horizontal line L is zero.

Note

2

4

The slope of a horizontal line is zero.

We can use the slope of a straight line to determine whether a line is parallel to another line.

Parallel Lines

Two distinct lines are parallel if and only if their slopes are equal or their slopes are undefined. y L2

L1

EXAMPLE 4 Let L1 be a line that passes through the points (2, 9) and (1, 3), and let L2 be the line that passes through the points (4, 10) and (3, 4). Determine whether L1 and L2 are parallel.

12

(– 4, 10) (– 2, 9)

8

Solution

The slope m1 of L1 is given by

(1, 3) 2

m1 

39  2 1  122

m2 

4  10  2 3  142

x –6

–2 –2

–6

4

The slope m2 of L2 is given by

(3, – 4)

FIGURE 13

Since m1  m2, the lines L1 and L2 are in fact parallel (Figure 13).

L1 and L2 have the same slope and hence are parallel.

2.1 Self-Check Exercise Determine the number a such that the line passing through the points (a, 2) and (3, 6) is parallel to a line with slope 4.

The solution to Self-Check Exercise 2.1 can be found on page 74.

2.1 Concept Questions 1. What can you say about the signs of a and b if the point P(a, b) lies in (a) the second quadrant? (b) The third quadrant? (c) The fourth quadrant?

2. What is the slope of a nonvertical line? What can you say about the slope of a vertical line?

2.1 THE CARTESIAN COORDINATE SYSTEM

73

2.1 Exercises In Exercises 1–6, refer to the accompanying figure and determine the coordinates of the point and the quadrant in which it is located.

In Exercises 21– 24, find the slope of the line shown in each figure.

21.

y

y

4

D 3

A x

B

–4

1

–2

2

x –5

–3

–1

1

3

5

7 F

C

–3

–2

9

y

22. 4

–5 E –7

2

1. A

2. B

3. C

4. D

5. E

6. F

x –2

2

4

–2

In Exercises 7–12, refer to the accompanying figure. y

23. B

2 C –6

y

4 A

2

D –4

x –2

2

4

–2 F

6

x

G

–4

–2

2

E –4

–2

7. Which point has coordinates (4, 2)? 8. What are the coordinates of point B? 9. Which points have negative y-coordinates?

24.

y 5

10. Which point has a negative x-coordinate and a negative y-coordinate?

3

11. Which point has an x-coordinate that is equal to zero? 12. Which point has a y-coordinate that is equal to zero?

1 x

In Exercises 13–20, sketch a set of coordinate axes and then plot the point.

–3

–1

1

3

13. (2, 5)

14. (1, 3)

15. (3, 1)

16. (3, 4)

In Exercises 25–30, find the slope of the line that passes through the given pair of points.

17. (8, 27)

18. (52, 32)

25. (4, 3) and (5, 8)

26. (4, 5) and (3, 8)

19. (4.5, 4.5)

20. (1.2, 3.4)

27. (2, 3) and (4, 8)

28. (2, 2) and (4, 4)

74

2 FUNCTIONS AND THEIR GRAPHS

29. (a, b) and (c, d ) 30. (a  1, b  1) and (a  1, b) 31. Given the equation y  4x  3, answer the following questions. a. If x increases by 1 unit, what is the corresponding change in y? b. If x decreases by 2 units, what is the corresponding change in y? 32. Given the equation 2x  3y  4, answer the following questions. a. Is the slope of the line described by this equation positive or negative? b. As x increases in value, does y increase or decrease? c. If x decreases by 2 units, what is the corresponding change in y?

In Exercises 33 and 34, determine whether the lines through the pairs of points are parallel.

33. A(1, 2), B(3, 10) and C(1, 5), D(1, 1) 34. A(2, 3), B(2, 2) and C(2, 4), D(2, 5) 35. If the line passing through the points (1, a) and (4, 2) is parallel to the line passing through the points (2, 8) and (7, a  4), what is the value of a? 36. If the line passing through the points (a, 1) and (5, 8) is parallel to the line passing through the points (4, 9) and (a  2, 1), what is the value of a? 37. Is there a difference between the statements “The slope of a straight line is zero” and “The slope of a straight line does not exist (is not defined)”? Explain your answer.

2.1 Solution to Self-Check Exercise The slope of the line that passes through the points (a, 2) and (3, 6) is

or, upon multiplying both sides of the equation by 3  a, 4  413  a2

62 4 m  3a 3a

4  12  4a 4a  8

Since this line is parallel to a line with slope 4, m must be equal to 4; that is,

a2

4 4 3a

2.2 Equations of Lines Point-Slope Form We now show that every straight line lying in the xy-plane may be represented by an equation involving the variables x and y. One immediate benefit of this is that problems involving straight lines may be solved algebraically. Let L be a straight line parallel to the y-axis (perpendicular to the x-axis) (Figure 14). Then L crosses the x-axis at some point (a, 0) with the x-coordinate given by x  a, where a is some real number. Any other point on L has the form (a, y ), where y is an appropriate number. Therefore, the vertical line L is described by the sole condition xa

and this is accordingly an equation of L. For example, the equation x  2 represents a vertical line 2 units to the left of the y-axis, and the equation x  3 represents a vertical line 3 units to the right of the y-axis (Figure 15).

75

2.2 EQUATIONS OF LINES y

y L

5

(a, y) 3

x = –2

x=3

1 (a, 0)

x

x –3

(x, y)

(x1, y1) x

5

The vertical lines x  2 and x  3

The vertical line x  a

L

1

FIGURE 15

FIGURE 14

y

–1

Next, suppose L is a nonvertical line, so that it has a well-defined slope m. Suppose (x1, y1) is a fixed point lying on L and (x, y) is a variable point on L distinct from (x1, y1) (Figure 16). Using Equation (1) with the point (x2, y2)  (x, y), we find that the slope of L is given by y  y1 m x  x1 Upon multiplying both sides of the equation by x  x1, we obtain Equation (2).

FIGURE 16 L passes through (x1, y1) and has slope m.

Point-Slope Form

An equation of the line that has slope m and passes through the point (x1, y1) is given by y  y1  m(x  x1)

(2)

Equation (2) is called the point-slope form of an equation of a line because it uses a given point (x1, y1) on a line and the slope m of the line. EXAMPLE 1 Find an equation of the line that passes through the point (1, 3) and has slope 2. Solution Using the point-slope form of the equation of a line with the point (1, 3) and m  2, we obtain

y  3  2(x  1)

y  y 1  m (x  x 1)

which, when simplified, becomes 2x  y  1  0

(Figure 17). y L 4 (1, 3) 2 FIGURE 17 L passes through (1, 3) and has slope 2.

x –2

2

76

2 FUNCTIONS AND THEIR GRAPHS

EXAMPLE 2 Find an equation of the line that passes through the points (3, 2) and (4, 1). Solution

The slope of the line is given by m

1  2 3  4  132 7

Using the point-slope form of the equation of a line with the point (4, 1) and the slope m  37, we have 3 y  1   1x  42 7 7y  7  3x  12 3x  7y  5  0

y  y1  m (x  x1 )

(Figure 18). y 4 L

(–3, 2) 2

–4

–2 –2

FIGURE 18

2 4 (4, –1)

x

L passes through (3, 2) and (4, 1).

We can use the slope of a straight line to determine whether a line is perpendicular to another line.

Perpendicular Lines

If L1 and L 2 are two distinct nonvertical lines that have slopes m1 and m2, respectively, then L1 is perpendicular to L 2 (written L1 ⊥ L 2) if and only if m1  

1 m2

If the line L1 is vertical (so that its slope is undefined), then L1 is perpendicular to another line, L2, if and only if L2 is horizontal (so that its slope is zero). For a proof of these results, see Exercise 74, page 83. EXAMPLE 3 Find an equation of the line that passes through the point (3, 1) and is perpendicular to the line of Example 1.

y 5

L1

L2

Solution Since the slope of the line in Example 1 is 2, it follows that the slope of the required line is given by m  12, the negative reciprocal of 2. Using the pointslope form of the equation of a line, we obtain

(1, 3)

1 y  1   1x  32 2 2y  2  x  3 x  2y  5  0

(3, 1)

1

x 1

3

5

FIGURE 19 L2 is perpendicular to L1 and passes through (3, 1).

(Figure 19).

y  y1  m (x  x1)

77

2.2 EQUATIONS OF LINES

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the straight lines L1 and L2 with equations 2x  y  5  0 and 41x  20y  11  0 on the same set of axes, using the standard viewing window. a. Can you tell if the lines L1 and L2 are parallel to each other? b. Verify your observations by computing the slopes of L1 and L2 algebraically. 2. Use a graphing utility to plot the straight lines L1 and L2 with equations x  2y  5  0 and 5x  y  5  0 on the same set of axes, using the standard viewing window. a. Can you tell if the lines L1 and L2 are perpendicular to each other? b. Verify your observation by computing the slopes of L1 and L2 algebraically.

Slope-Intercept Form

y L (0, b)

(a, 0)

x

A straight line L that is neither horizontal nor vertical cuts the x-axis and the y-axis at, say, points (a, 0) and (0, b), respectively (Figure 20). The numbers a and b are called the x-intercept and y-intercept, respectively, of L. Now, let L be a line with slope m and y-intercept b. Using Equation (2), the pointslope form of the equation of a line, with the point given by (0, b) and slope m, we have y  b  m1x  02 y  mx  b

FIGURE 20 The line L has x-intercept a and y-intercept b.

This is called the slope-intercept form of an equation of a line.

Slope-Intercept Form

The equation of the line that has slope m and intersects the y-axis at the point (0, b) is given by y  mx  b

(3)

EXAMPLE 4 Find an equation of the line that has slope 3 and y-intercept 4. Solution

Using Equation (3) with m  3 and b  4, we obtain the required

equation: y  3x  4

EXAMPLE 5 Determine the slope and y-intercept of the line whose equation is 3x  4y  8. Solution

Rewrite the given equation in the slope-intercept form and obtain y

3 x2 4

Comparing this result with Equation (3), we find m  34 and b  2, and we conclude that the slope and y-intercept of the given line are 34 and 2, respectively.

78

2 FUNCTIONS AND THEIR GRAPHS

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the straight lines with equations y  2x  3, y  x  3, y  x  3, and y  2.5x  3 on the same set of axes, using the standard viewing window. What effect does changing the coefficient m of x in the equation y  mx  b have on its graph? 2. Use a graphing utility to plot the straight lines with equations y  2x  2, y  2x  1, y  2x, y  2x  1, and y  2x  4 on the same set of axes, using the standard viewing window. What effect does changing the constant b in the equation y  mx  b have on its graph? 3. Describe in words the effect of changing both m and b in the equation y  mx  b.

Sales in thousands of dollars

y

APPLIED EXAMPLE 6 Sales of a Sporting Goods Store The sales manager of a local sporting goods store plotted sales versus time for the last 5 years and found the points to lie approximately along a straight line (Figure 21). By using the points corresponding to the first and fifth years, find an equation of the trend line. What sales figure can be predicted for the sixth year?

70 60 50 40 30

Solution Using Equation (1) with the points (1, 20) and (5, 60), we find that the slope of the required line is given by

20 10 1

2

3 4 Years

5

6

FIGURE 21 Sales of a sporting goods store

m

x

60  20  10 51

Next, using the point-slope form of the equation of a line with the point (1, 20) and m  10, we obtain y  20  101x  12 y  10x  10 as the required equation. The sales figure for the sixth year is obtained by letting x  6 in the last equation, giving y  10(6)  10  70 or $70,000. APPLIED EXAMPLE 7 Predicting the Value of Art Suppose an art object purchased for $50,000 is expected to appreciate in value at a constant rate of $5000 per year for the next 5 years. Use Equation (3) to write an equation predicting the value of the art object in the next several years. What will be its value 3 years from the purchase date?

Explore & Discuss Refer to Example 7. Can the equation predicting the value of the art object be used to predict long-term growth?

Let x denote the time (in years) that has elapsed since the purchase date and let y denote the object’s value (in dollars). Then, y  50,000 when x  0. Furthermore, the slope of the required equation is given by m  5000 since each unit increase in x (1 year) implies an increase of 5000 units (dollars) in y. Using Equation (3) with m  5000 and b  50,000, we obtain Solution

y  5000x  50,000

Three years from the purchase date, the value of the object will be given by y  5000(3)  50,000

or $65,000.

79

2.2 EQUATIONS OF LINES

General Form of an Equation of a Line We have considered several forms of the equation of a straight line in the plane. These different forms of the equation are equivalent to each other. In fact, each is a special case of the following equation. General Form of a Linear Equation

The equation Ax  By  C  0

(4)

where A, B, and C are constants and A and B are not both zero, is called the general form of a linear equation in the variables x and y. We now state (without proof) an important result concerning the algebraic representation of straight lines in the plane. An equation of a straight line is a linear equation; conversely, every linear equation represents a straight line. This result justifies the use of the adjective linear in describing Equation (4). EXAMPLE 8 Sketch the straight line represented by the equation 3x  4y  12  0 Solution Since every straight line is uniquely determined by two distinct points, we need find only two points through which the line passes in order to sketch it. For convenience, let’s compute the points at which the line crosses the x- and y-axes. Setting y  0, we find x  4, the x-intercept, so the line crosses the x-axis at the point (4, 0). Setting x  0 gives y  3, the y-intercept, so the line crosses the y-axis at the point (0, 3). A sketch of the line appears in Figure 22. y 2 (4, 0) x –2

2 –2

FIGURE 22

(0, – 3)

The straight line 3x  4y  12

Here is a summary of the common forms of the equations of straight lines discussed in this section. Equations of Straight Lines

Vertical line: Horizontal line: Point-slope form: Slope-intercept form: General form:

xa yb y  y1  m(x  x1) y  mx  b Ax  By  C  0

80

2 FUNCTIONS AND THEIR GRAPHS

2.2 Self-Check Exercises 1. Find an equation of the line that passes through the point (3, 1) and is perpendicular to a line with slope 12. 2. Does the point (3, 3) lie on the line with equation 2x  3y  12  0? Sketch the graph of the line. 3. SATELLITE TV SUBSCRIBERS The following table gives the number of satellite TV subscribers in the United States (in millions) from 1998 through 2005 (x  0 corresponds to 1998): x, year y, number

0 8.5

1 11.1

2 15.0

3 17.0

4 18.9

5 21.5

6 24.8

7 27.4

a. Plot the number of satellite TV subscribers in the United States (y) versus the year (x). b. Draw the line L through the points (0, 8.5) and (7, 27.4). c. Find an equation of the line L. d. Assuming that this trend continued, estimate the number of satellite TV subscribers in the United States in 2006. Sources: National Cable & Telecommunications Association and the Federal Communications Commission

Solutions to Self-Check Exercises 2.2 can be found on page 84.

2.2 Concept Questions 1. Give (a) the point-slope form, (b) the slope-intercept form, and (c) the general form of an equation of a line.

2. Let L1 have slope m1 and let L2 have slope m2. State the conditions on m1 and m2 if (a) L1 is parallel to L2 and (b) L1 is perpendicular to L2.

2.2 Exercises In Exercises 1–6, match the statement with one of the graphs (a)– (f).

(b)

y 4

1. The slope of the line is zero. 2. The slope of the line is undefined. 3. The slope of the line is positive, and its y-intercept is positive.

x 4

4. The slope of the line is positive, and its y-intercept is negative. 5. The slope of the line is negative, and its x-intercept is negative.

(c)

y 3

6. The slope of the line is negative, and its x-intercept is positive. (a) y

x

4

–3

x –4

2

(d)

y 4

2 x –2

2 –2

4

2.2 EQUATIONS OF LINES

(e)

29. Find an equation of the line that passes through the point (2, 2) and is parallel to the line 2x  4y  8  0.

y

30. Find an equation of the line that passes through the point (1, 3) and is parallel to the line passing through the points (2, 3) and (2, 5).

4

x 4

(f)

81

31. Find an equation of the line that passes through the point (2, 4) and is perpendicular to the line 3x  4y  22  0. 32. Find an equation of the line that passes through the point (1, 2) and is perpendicular to the line passing through the points (2, 1) and (4, 3).

y 3

In Exercises 33–38, find an equation of the line that satisfies the given condition.

33. The line parallel to the x-axis and 6 units below it x –3

3

34. The line passing through the origin and parallel to the line passing through the points (2, 4) and (4, 7)

–2

35. The line passing through the point (a, b) with slope equal to zero In Exercises 7 and 8, determine whether the lines through the pairs of points are perpendicular.

36. The line passing through (3, 4) and parallel to the x-axis

7. A(2, 5), B(4, 2) and C(1, 2), D(3, 6)

37. The line passing through (5, 4) and parallel to the line passing through (3, 2) and (6, 8)

8. A(2, 0), B(1, 2) and C(4, 2), D(8, 4)

38. The line passing through (a, b) with undefined slope

9. Find an equation of the horizontal line that passes through (4, 3).

39. Given that the point P(3, 5) lies on the line kx  3y  9  0, find k.

10. Find an equation of the vertical line that passes through (0, 5).

40. Given that the point P(2, 3) lies on the line 2x  ky  10  0, find k.

In Exercises 11–14, find an equation of the line that passes through the point and has the indicated slope m.

In Exercises 41–46, sketch the straight line defined by the linear equation by finding the x- and y-intercepts.

11. (3, 4); m  2

12. (2, 4); m  1

Hint: See Example 8.

13. (3, 2); m  0

14. 11, 22; m  

1 2

In Exercises 15–18, find an equation of the line that passes through the given points.

15. (2, 4) and (3, 7)

16. (2, 1) and (2, 5)

17. (1, 2) and (3, 2)

18. (1, 2) and (3, 4)

In Exercises 19–22, find an equation of the line that has slope m and y-intercept b.

19. m  3; b  4

20. m  2; b  1

21. m  0; b  5

22. m   ; b 

1 2

3 4

In Exercises 23–28, write the equation in the slopeintercept form and then find the slope and y-intercept of the corresponding line.

23. x  2y  0

24. y  2  0

25. 2x  3y  9  0

26. 3x  4y  8  0

27. 2x  4y  14

28. 5x  8y  24  0

41. 3x  2y  6  0

42. 2x  5y  10  0

43. x  2y  4  0

44. 2x  3y  15  0

45. y  5  0

46. 2x  8y  24  0

47. Show that an equation of a line through the points (a, 0) and (0, b) with a  0 and b  0 can be written in the form y x  1 a b

(Recall that the numbers a and b are the x- and y-intercepts, respectively, of the line. This form of an equation of a line is called the intercept form.) In Exercises 48–51, use the results of Exercise 47 to find an equation of a line with the x- and y-intercepts.

48. x-intercept 3; y-intercept 4 49. x-intercept 2; y-intercept 4 3 1 50. x-intercept  ; y-intercept 2 4 51. x-intercept 4; y-intercept 

1 2

82

2 FUNCTIONS AND THEIR GRAPHS

In Exercises 52 and 53, determine whether the points lie on a straight line.

52. A(1, 7), B(2, 2), and C(5, 9) 53. A(2, 1), B(1, 7), and C(4, 13) 54. TEMPERATURE CONVERSION The relationship between the temperature in degrees Fahrenheit (°F) and the temperature in degrees Celsius (°C) is F

9 C  32 5

a. Sketch the line with the given equation. b. What is the slope of the line? What does it represent? c. What is the F-intercept of the line? What does it represent? 55. NUCLEAR PLANT UTILIZATION The United States is not building many nuclear plants, but the ones it has are running at nearly full capacity. The output (as a percent of total capacity) of nuclear plants is described by the equation y  1.9467t  70.082

where t is measured in years, with t  0 corresponding to the beginning of 1990. a. Sketch the line with the given equation. b. What are the slope and the y-intercept of the line found in part (a)? c. Give an interpretation of the slope and the y-intercept of the line found in part (a). d. If the utilization of nuclear power continues to grow at the same rate and the total capacity of nuclear plants in the United States remains constant, by what year can the plants be expected to be generating at maximum capacity? Source: Nuclear Energy Institute

56. SOCIAL SECURITY CONTRIBUTIONS For wages less than the maximum taxable wage base, Social Security contributions by employees are 7.65% of the employee’s wages. a. Find an equation that expresses the relationship between the wages earned (x) and the Social Security taxes paid ( y) by an employee who earns less than the maximum taxable wage base. b. For each additional dollar that an employee earns, by how much is his or her Social Security contribution increased? (Assume that the employee’s wages are less than the maximum taxable wage base.) c. What Social Security contributions will an employee who earns $65,000 (which is less than the maximum taxable wage base) be required to make? Source: Social Security Administration

57. COLLEGE ADMISSIONS Using data compiled by the Admissions Office at Faber University, college admissions officers estimate that 55% of the students who are offered admission to the freshman class at the university will actually enroll. a. Find an equation that expresses the relationship between the number of students who actually enroll ( y) and the

number of students who are offered admission to the university (x). b. If the desired freshman class size for the upcoming academic year is 1100 students, how many students should be admitted? 58. WEIGHT OF WHALES The equation W  3.51L  192, expressing the relationship between the length L (in feet) and the expected weight W (in British tons) of adult blue whales, was adopted in the late 1960s by the International Whaling Commission. a. What is the expected weight of an 80-ft blue whale? b. Sketch the straight line that represents the equation. 59. THE NARROWING GENDER GAP Since the founding of the Equal Employment Opportunity Commission and the passage of equal-pay laws, the gulf between men’s and women’s earnings has continued to close gradually. At the beginning of 1990 (t  0), women’s wages were 68% of men’s wages, and by the beginning of 2000 (t  10), women’s wages were 80% of men’s wages. If this gap between women’s and men’s wages continued to narrow linearly, then women’s wages were what percentage of men’s wages at the beginning of 2004? Source: Journal of Economic Perspectives

60. SALES OF NAVIGATION SYSTEMS The projected number of navigation systems (in millions) installed in vehicles in North America, Europe, and Japan from 2002 through 2006 are shown in the following table (x  0 corresponds to 2002): Year, x Systems Installed, y

0 3.9

1 4.7

2 5.8

3 6.8

4 7.8

a. Plot the annual sales ( y) versus the year (x). b. Draw a straight line L through the points corresponding to 2002 and 2006. c. Derive an equation of the line L. d. Use the equation found in part (c) to estimate the number of navigation systems installed in 2005. Compare this figure with the sales for that year. Source: ABI Research

61. SALES OF GPS EQUIPMENT The annual sales (in billions of dollars) of global positioning systems (GPS) equipment from 2000 through 2006 are shown in the following table (x  0 corresponds to 2000): Year, x Annual Sales, y

0 7.9

1 9.6

2 11.5

3 13.3

4 15.2

5 17

6 18.8

a. Plot the annual sales ( y) versus the year (x). b. Draw a straight line L through the points corresponding to 2000 and 2006. c. Derive an equation of the line L. d. Use the equation found in part (c) to estimate the annual sales of GPS equipment in 2005. Compare this figure with the projected sales for that year. Source: ABI Research

2.2 EQUATIONS OF LINES

62. IDEAL HEIGHTS AND WEIGHTS FOR WOMEN The Venus Health Club for Women provides its members with the following table, which gives the average desirable weight (in pounds) for women of a given height (in inches): Height, x Weight, y

60 108

63 118

66 129

69 140

72 152

a. Plot the weight ( y) versus the height (x). b. Draw a straight line L through the points corresponding to heights of 5 ft and 6 ft. c. Derive an equation of the line L. d. Using the equation of part (c), estimate the average desirable weight for a woman who is 5 ft, 5 in. tall. 63. COST OF A COMMODITY A manufacturer obtained the following data relating the cost y (in dollars) to the number of units (x) of a commodity produced: Units Produced, x Cost in Dollars, y

0

20

40

60

80

100

200

208

222

230

242

250

a. Plot the cost ( y) versus the quantity produced (x). b. Draw a straight line through the points (0, 200) and (100, 250). c. Derive an equation of the straight line of part (b). d. Taking this equation to be an approximation of the relationship between the cost and the level of production, estimate the cost of producing 54 units of the commodity. 64. DIGITAL TV SERVICES The percentage of homes with digital TV services stood at 5% at the beginning of 1999 (t  0) and was projected to grow linearly so that, at the beginning of 2003 (t  4), the percentage of such homes was 25%. a. Derive an equation of the line passing through the points A(0, 5) and B(4, 25). b. Plot the line with the equation found in part (a). c. Using the equation found in part (a), find the percentage of homes with digital TV services at the beginning of 2001.

In Exercises 66–72, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

66. Suppose the slope of a line L is 12 and P is a given point on L. If Q is the point on L lying 4 units to the left of P, then Q lies 2 units above P. 67. The point (1, 1) lies on the line with equation 3x  7y  5. 68. The point (1, k) lies on the line with equation 3x  4y  12 if and only if k  94. 69. The line with equation Ax  By  C  0 (B  0) and the line with equation ax  by  c  0 (b  0) are parallel if Ab  aB  0. 70. If the slope of the line L1 is positive, then the slope of a line L2 perpendicular to L1 may be positive or negative. 71. The lines with equations ax  by  c1  0 and bx  ay  c2  0, where a  0 and b  0, are perpendicular to each other. 72. If L is the line with equation Ax  By  C  0, where A  0, then L crosses the x-axis at the point (C/A, 0). 73. Show that two distinct lines with equations a1x  b1y  c1  0 and a2 x  b2 y  c2  0, respectively, are parallel if and only if a1b2  b1a2  0. Hint: Write each equation in the slope-intercept form and compare.

74. Prove that if a line L1 with slope m1 is perpendicular to a line L2 with slope m2, then m1m2  1. Hint: Refer to the accompanying figure. Show that m1  b and m2  c. Next, apply the Pythagorean theorem and the distance formula to the triangles OAC, OCB, and OBA to show that 1  bc. y

L1 A(1, b)

Source: Paul Kagan Associates

C(1, 0)

65. SALES GROWTH Metro Department Store’s annual sales (in millions of dollars) during the past 5 yr were Annual Sales, y Year, x

5.8 1

6.2 2

7.2 3

8.4 4

9.0 5

a. Plot the annual sales ( y) versus the year (x). b. Draw a straight line L through the points corresponding to the first and fifth years. c. Derive an equation of the line L. d. Using the equation found in part (c), estimate Metro’s annual sales 4 yr from now (x  9).

83

O

B(1, c) L2

x

84

2 FUNCTIONS AND THEIR GRAPHS

2.2 Solutions to Self-Check Exercises 1. Since the required line L is perpendicular to a line with slope 12, the slope of L is 12

y 30

2

Millions of subscribers

m

1

3. a. and b. See the following figure.

Next, using the point-slope form of the equation of a line, we have y  11 2  21x  32 y  1  2x  6 y  2x  7

25 20 15 10 5 0

2. Substituting x  3 and y  3 into the left-hand side of the given equation, we find

0

1

2

3 4 Year

5

6

7

x

c. The slope of L is

2(3)  3(3)  12  3 m

which is not equal to zero (the right-hand side). Therefore, (3, 3) does not lie on the line with equation 2x  3y  12  0. Setting x  0, we find y  4, the y-intercept. Next, setting y  0 gives x  6, the x-intercept. We now draw the line passing through the points (0, 4) and (6, 0), as shown in the following figure.

27.4  8.5  2.7 70

Using the point-slope form of the equation of a line with the point (0, 8.5), we find y  8.5  2.7(x  0) y  2.7x  8.5

d. The estimated number of satellite TV subscribers in the United States in 2006 is

y 2x – 3y – 12 = 0

L

y  2.7(8)  8.5  30.1

x

or 30.1 million.

6 (3, – 3) –4

USING

TECHNOLOGY

Graphing a Straight Line Graphing Utility

The first step in plotting a straight line with a graphing utility is to select a suitable viewing window. We usually do this by experimenting. For example, you might first plot the straight line using the standard viewing window [10, 10]  [10, 10]. If necessary, you then might adjust the viewing window by enlarging it or reducing it to obtain a sufficiently complete view of the line or at least the portion of the line that is of interest. EXAMPLE 1 Plot the straight line 2x  3y  6  0 in the standard viewing window. Solution

FIGURE T1

The straight line 2x  3y  6  0 in the standard viewing window

The straight line in the standard viewing window is shown in Figure T1.

2.2 EQUATIONS OF LINES

85

EXAMPLE 2 Plot the straight line 2x  3y  30  0 in (a) the standard viewing window and (b) the viewing window [5, 20]  [5, 20]. Solution

a. The straight line in the standard viewing window is shown in Figure T2a. b. The straight line in the viewing window [5, 20]  [5, 20] is shown in Figure T2b. This figure certainly gives a more complete view of the straight line.

(a) The graph of 2x  3y  30  0 in the standard viewing window

FIGURE T2

(b) The graph of 2x  3y  30  0 in the viewing window [5, 20]  [5, 20]

Excel

In the examples and exercises that follow, we assume that you are familiar with the basic features of Microsoft Excel. Please consult your Excel manual or use Excel’s Help features to answer questions regarding the standard commands and operating instructions for Excel.* EXAMPLE 3 Plot the graph of the straight line 2 x  3y  6  0 over the interval [10, 10]. Solution

1. Write the equation in the slope-intercept form: 2 y x2 3

2. Create a table of values. First, enter the input values: Enter the values of the endpoints of the interval over which you are graphing the straight line. (Recall that we need only two distinct data points to draw the graph of a straight line. In general, we select the endpoints of the interval over which the straight line is to be drawn as our data points.) In this case, we enter —10 in cell A2 and 10 in cell A3. Second, enter the formula for computing the y-values: Here we enter = —(2/3)*A2+2 A 1

B

x

y

2

−10

8.666667

3

10

−4.66667

FIGURE T3 Table of values for x and y

in cell B2 and then press Enter . Third, evaluate the function at the other input value: To extend the formula to cell B3, move the pointer to the small black box at the lower right corner of cell B2 (the cell containing the formula). Observe that the pointer now appears as a black  (plus sign). Drag this pointer through cell B3 and then release it. The yvalue, – 4.66667, corresponding to the x-value in cell A3(10) will appear in cell B3 (Figure T3).

*Instructions for solving these examples and exercises using Microsoft Excel 2007 are given on our Companion Web site. Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart Type) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

(continued)

86

2 FUNCTIONS AND THEIR GRAPHS

3. Graph the straight line determined by these points. First, highlight the numerical values in the table. Here we highlight cells A2:A3 and B2:B3. Next, click the Chart Wizard button on the toolbar. Step 1

In the Chart Type dialog box that appears, select XY(Scatter) . Next, select the second chart in the first column under Chart sub-type. Then click Next at the bottom of the dialog box.

Step 2

Click Columns next to Series in: Then click Next at the bottom of the dialog box.

Step 3

Click the Titles tab. In the Chart title: box, enter y = —(2/3)x + 2. In the Value (X) axis: box, type x. In the Value (Y) axis: box, type y. Click the Legend tab. Next, click the Show Legend box to remove the check mark. Click Finish at the bottom of the dialog box.

The graph shown in Figure T4 will appear. y = −(2/3)x + 2

y

10 8 6 4 2 0 0 −2 −4 −6

−15

−10

−5

FIGURE T4

The graph of y  23 x  2 over the interval 310, 104

5

10

15

x

If the interval over which the straight line is to be plotted is not specified, then you may have to experiment to find an appropriate interval for the x-values in your graph. For example, you might first plot the straight line over the interval [10, 10]. If necessary you then might adjust the interval by enlarging it or reducing it to obtain a sufficiently complete view of the line or at least the portion of the line that is of interest. EXAMPLE 4 Plot the straight line 2x  3y  30  0 over the intervals (a) [10, 10] and (b) [5, 20]. a and b. We first cast the equation in the slope-intercept form, obtaining y x  10. Following the procedure given in Example 3, we obtain the graphs shown in Figure T5. Solution

−15 −10 (a) FIGURE T5

y = −(2/3)x + 10 18 16 14 12 10 8 6 4 2 0 −5 0 5 x

y = −(2/3)x + 10

y

y

23

−10 10

15 (b)

−5

16 14 12 10 8 6 4 2 0 −2 0 −4 −6

5

10

15

20

25

x

The graph of y  23 x  10 over the intervals (a) [10, 10] and (b) [5, 20]

Observe that the graph in Figure T5b includes the x- and y-intercepts. This figure certainly gives a more complete view of the straight line.

2.3 FUNCTIONS AND THEIR GRAPHS

87

TECHNOLOGY EXERCISES Graphing Utility

Excel

In Exercises 1–4, plot the straight line with the equation in the standard viewing window.

In Exercises 1–4, plot the straight line with the equation over the interval [10, 10].

1. 3.2x  2.1y  6.72  0

2. 2.3x  4.1y  9.43  0

1. 3.2x  2.1y  6.72  0

2. 2.3x  4.1y  9.43  0

3. 1.6x  5.1y  8.16

4. 3.2x  2.1y  6.72

3. 1.6x  5.1y  8.16

4. 3.2x  2.1y  6.72

In Exercises 5–8, plot the straight line with the equation in (a) the standard viewing window and (b) the indicated viewing window.

5. 12.1x  4.1y  49.61  0; [10, 10]  [10, 20] 6. 4.1x  15.2y  62.32  0; [10, 20]  [10, 10] 7. 20x  16y  300; [10, 20]  [10, 30] 8. 32.2x  21y  676.2; [10, 30]  [10, 40] In Exercises 9–12, plot the straight line with the equation in an appropriate viewing window. (Note: The answer is not unique.)

9. 20x  30y  600

In Exercises 5–8, plot the straight line with the equation over the given interval.

5. 12.1x  4.1y  49.61  0; [10, 10] 6. 4.1x  15.2y  62.32  0; [10, 20] 7. 20x  16y  300; [10, 20] 8. 32.2x  21y  676.2; [10, 30] In Exercises 9–12, plot the straight line with the equation. (Note: The answer is not unique.)

9. 20x  30y  600

10. 30x  20y  600

11. 22.4x  16.1y  352  0 12. 18.2x  15.1y  274.8

10. 30x  20y  600 11. 22.4x  16.1y  352  0 12. 18.2x  15.1y  274.8

2.3 Functions and Their Graphs Functions A manufacturer would like to know how his company’s profit is related to its production level; a biologist would like to know how the size of the population of a certain culture of bacteria will change over time; a psychologist would like to know the relationship between the learning time of an individual and the length of a vocabulary list; and a chemist would like to know how the initial speed of a chemical reaction is related to the amount of substrate used. In each instance, we are concerned with the same question: How does one quantity depend upon another? The relationship between two quantities is conveniently described in mathematics by using the concept of a function.

Function

A function is a rule that assigns to each element in a set A one and only one element in a set B.

The set A is called the domain of the function. It is customary to denote a function by a letter of the alphabet, such as the letter f. If x is an element in the domain of a func-

88

2 FUNCTIONS AND THEIR GRAPHS

tion f, then the element in B that f associates with x is written f(x) (read “f of x”) and is called the value of f at x. The set comprising all the values assumed by y  f(x) as x takes on all possible values in its domain is called the range of the function f. We can think of a function f as a machine. The domain is the set of inputs (raw material) for the machine, the rule describes how the input is to be processed, and the value(s) of the function are the outputs of the machine (Figure 23). We can also think of a function f as a mapping in which an element x in the domain of f is mapped onto a unique element f (x) in B (Figure 24). Notes FIGURE 23 A function machine

FIGURE 24 The function f viewed as a mapping

1. The output f(x) associated with an input x is unique. To appreciate the importance of this uniqueness property, consider a rule that associates with each item x in a department store its selling price y. Then, each x must correspond to one and only one y. Notice, however, that different x’s may be associated with the same y. In the context of the present example, this says that different items may have the same price. 2. Although the sets A and B that appear in the definition of a function may be quite arbitrary, in this book they will denote sets of real numbers. An example of a function may be taken from the familiar relationship between the area of a circle and its radius. Letting x and y denote the radius and area of a circle, respectively, we have, from elementary geometry, y  px 2

(5)

Equation (5) defines y as a function of x since for each admissible value of x (that is, for each nonnegative number representing the radius of a certain circle) there corresponds precisely one number y  px2 that gives the area of the circle. The rule defining this “area function” may be written as f(x)  px 2

(6)

To compute the area of a circle of radius 5 inches, we simply replace x in Equation (6) with the number 5. Thus, the area of the circle is f(5)  p 52  25p

or 25p square inches. In general, to evaluate a function at a specific value of x, we replace x with that value, as illustrated in Examples 1 and 2. EXAMPLE 1 Let the function f be defined by the rule f (x)  2x 2  x  1. Find: a. f(1)

b. f(2)

c. f (a)

d. f (a  h)

Solution

a. b. c. d.

f(1)  2(1)2  (1)  1  2  1  1  2 f(2)  2(2)2  (2)  1  8  2  1  11 f(a)  2(a)2  (a)  1  2a2  a  1 f(a  h)  2(a  h)2  (a  h)  1  2a2  4ah  2h2  a  h  1 APPLIED EXAMPLE 2 Profit Functions ThermoMaster manufactures an indoor–outdoor thermometer at its Mexican subsidiary. Management estimates that the profit (in dollars) realizable by ThermoMaster in the manufacture and sale of x thermometers per week is P(x)  0.001x 2  8x  5000

2.3 FUNCTIONS AND THEIR GRAPHS

89

Find ThermoMaster’s weekly profit if its level of production is (a) 1000 thermometers per week and (b) 2000 thermometers per week. Solution

a. The weekly profit when the level of production is 1000 units per week is found by evaluating the profit function P at x  1000. Thus, P(1000)  0.001(1000)2  8(1000)  5000  2000

or $2000. b. When the level of production is 2000 units per week, the weekly profit is given by P(2000)  0.001(2000)2  8(2000)  5000  7000

or $7000.

Determining the Domain of a Function Suppose we are given the function y  f(x).* Then, the variable x is called the independent variable. The variable y, whose value depends on x, is called the dependent variable. To determine the domain of a function, we need to find what restrictions, if any, are to be placed on the independent variable x. In many practical applications, the domain of a function is dictated by the nature of the problem, as illustrated in Example 3. APPLIED EXAMPLE 3 Packaging An open box is to be made from a

rectangular piece of cardboard 16 inches long and 10 inches wide by cutting away identical squares (x inches by x inches) from each corner and folding up the resulting flaps (Figure 25). Find an expression that gives the volume V of the box as a function of x. What is the domain of the function? x

x

x

x

10 10 – 2x

x

x

x 16 – 2x

x

– 10

x

2x

– 16

2x

16 (a) The box is constructed by cutting x by x squares from each corner.

(b) The dimensions of the resulting box are (10  2x) by (16  2x) by x.

FIGURE 25

Solution The dimensions of the box are (16  2x) inches by (10  2x) inches by x inches, so its volume (in cubic inches) is given by

V  f(x)  (16  2x)(10  2x)x

Length  width  height

 (160  52x  4x )x 2

 4x 3  52x 2  160x

*It is customary to refer to a function f as f(x) or by the equation y  f(x) defining it.

90

2 FUNCTIONS AND THEIR GRAPHS

Since the length of each side of the box must be greater than or equal to zero, we see that 16  2x  0

10  2x  0

x0

simultaneously; that is, x 8

x 5

x0

All three inequalities are satisfied simultaneously provided that 0 x 5. Thus, the domain of the function f is the interval [0, 5]. In general, if a function is defined by a rule relating x to f (x) without specific mention of its domain, it is understood that the domain will consist of all values of x for which f (x) is a real number. In this connection, you should keep in mind that (1) division by zero is not permitted and (2) the even root of a negative number is not a real number. EXAMPLE 4 Find the domain of each function. a. f 1x2  1x  1

b. f 1x 2 

1 x 4 2

c. f (x)  x 2  3

Solution

a. Since the square root of a negative number is not a real number, it is necessary that x  1  0. The inequality is satisfied by the set of real numbers x  1. Thus, the domain of f is the interval [1, ). b. The only restriction on x is that x 2  4 be different from zero since division by zero is not allowed. But (x 2  4)  (x  2)(x  2)  0 if x  2 or x  2. Thus, the domain of f in this case consists of the intervals (, 2), (2, 2), and (2, ). c. Here, any real number satisfies the equation, so the domain of f is the set of all real numbers.

Graphs of Functions If f is a function with domain A, then corresponding to each real number x in A there is precisely one real number f(x). We can also express this fact by using ordered pairs of real numbers. Write each number x in A as the first member of an ordered pair and each number f (x) corresponding to x as the second member of the ordered pair. This gives exactly one ordered pair (x, f (x)) for each x in A. This observation leads to an alternative definition of a function f :

Function (Alternative Definition)

A function f with domain A is the set of all ordered pairs (x, f (x)) where x belongs to A.

Observe that the condition that there be one and only one number f (x) corresponding to each number x in A translates into the requirement that no two ordered pairs have the same first number. Since ordered pairs of real numbers correspond to points in the plane, we have found a way to exhibit a function graphically.

91

2.3 FUNCTIONS AND THEIR GRAPHS

Graph of a Function of One Variable

The graph of a function f is the set of all points (x, y) in the xy-plane such that x is in the domain of f and y  f(x).

Figure 26 shows the graph of a function f. Observe that the y-coordinate of the point (x, y) on the graph of f gives the height of that point (the distance above the x-axis), if f(x) is positive. If f(x) is negative, then f(x) gives the depth of the point (x, y) (the distance below the x-axis). Also, observe that the domain of f is a set of real numbers lying on the x-axis, whereas the range of f lies on the y-axis. y y

y

y = f (x)

7 6 5 4 3

x

1

(x, y)

Range x

–2

Domain

–1 –2 –3 –4 –5

FIGURE 26

FIGURE 27

The graph of f

The graph of f

y = f (x)

1

3

5

7

x

EXAMPLE 5 The graph of a function f is shown in Figure 27. a. What is the value of f(3)? The value of f(5)? b. What is the height or depth of the point (3, f(3)) from the x-axis? The point (5, f(5)) from the x-axis? c. What is the domain of f ? The range of f ? Solution

a. From the graph of f, we see that y  2 when x  3 and conclude that f(3)  2. Similarly, we see that f(5)  3. b. Since the point (3, 2) lies below the x-axis, we see that the depth of the point (3, f(3)) is f(3)  (2)  2 units below the x-axis. The point (5, f(5)) lies above the x-axis and is located at a height of f(5), or 3 units above the x-axis. c. Observe that x may take on all values between x  1 and x  7, inclusive, and so the domain of f is [1, 7]. Next, observe that as x takes on all values in the domain of f, f(x) takes on all values between 2 and 7, inclusive. (You can easily see this by running your index finger along the x-axis from x  1 to x  7 and observing the corresponding values assumed by the y-coordinate of each point of the graph of f.) Therefore, the range of f is [2, 7]. Much information about the graph of a function can be gained by plotting a few points on its graph. Later on we will develop more systematic and sophisticated techniques for graphing functions.

92

2 FUNCTIONS AND THEIR GRAPHS

EXAMPLE 6 Sketch the graph of the function defined by the equation y  x 2  1. What is the range of f ? Solution The domain of the function is the set of all real numbers. By assigning several values to the variable x and computing the corresponding values for y, we obtain the following solutions to the equation y  x 2  1:

y 12 (–3, 10)

(3, 10)

10 8

(– 2, 5)

6

(2, 5)

4

(–1, 2)

(1, 2)

3

2

1

0

1

2

3

y

10

5

2

1

2

5

10

By plotting these points and then connecting them with a smooth curve, we obtain the graph of y  f(x), which is a parabola (Figure 28). To determine the range of f, we observe that x 2  0 if x is any real number, and so x 2  1  1 for all real numbers x. We conclude that the range of f is [1, ). The graph of f confirms this result visually.

x –4

x

4

FIGURE 28

The graph of y  x2  1 is a parabola.

Exploring with

TECHNOLOGY Let f(x)  x 2. 1. Plot the graphs of F(x)  x2  c on the same set of axes for c  2, 1, 12, 0, 1 2 , 1, 2. 2. Plot the graphs of G(x)  (x  c)2 on the same set of axes for c  2, 1, 12, 0, 21, 1, 2. 3. Plot the graphs of H(x)  cx2 on the same set of axes for c  2, 1, 12, 14, 0, 41, 12, 1, 2. 4. Study the family of graphs in parts 1–3 and describe the relationship between the graph of a function f and the graphs of the functions defined by (a) y  f(x)  c, (b) y  f(x  c), and (c) y  cf(x), where c is a constant. A function that is defined by more than one rule is called a piecewise-defined function. EXAMPLE 7 Sketch the graph of the function f defined by f 1x2  e

4 2 x –2

if x 0 if x  0

Solution The function f is defined in a piecewise fashion on the set of all real numbers. In the subdomain (, 0), the rule for f is given by f(x)  x. The equation y  x is a linear equation in the slope-intercept form (with slope 1 and intercept 0). Therefore, the graph of f corresponding to the subdomain (, 0) is the half line shown in Figure 29. Next, in the subdomain [0, ), the rule for f is given by f 1x2  1x. The values of f(x) corresponding to x  0, 1, 2, 3, 4, 9, and 16 are shown in the following table:

y

–4

x 1x

2

4

FIGURE 29 The graph of y  f (x) is obtained by graphing y  x over (, 0) and y  1x over [0, ).

x

0

1

2

3

4

9

16

f(x)

0

1

12

13

2

3

4

Using these values, we sketch the graph of the function f as shown in Figure 29.

2.3 FUNCTIONS AND THEIR GRAPHS

93

APPLIED EXAMPLE 8 Bank Deposits Madison Finance Company plans to open two branch offices 2 years from now in two separate locations: an industrial complex and a newly developed commercial center in the city. As a result of these expansion plans, Madison’s total deposits during the next 5 years are expected to grow in accordance with the rule 12x  20 f 1x2  c 1 2 x  20 2

if 0 x 2 if 2 x 5

where y  f(x) gives the total amount of money (in millions of dollars) on deposit with Madison in year x (x  0 corresponds to the present). Sketch the graph of the function f. Solution The function f is defined in a piecewise fashion on the interval [0, 5]. In the subdomain [0, 2], the rule for f is given by f 1x2  12x  20. The values of f(x) corresponding to x  0, 1, and 2 may be tabulated as follows:

x y Million dollars

f(x)

0

1

2

20

21.4

22

35 30

1

Next, in the subdomain (2, 5], the rule for f is given by f(x)  2 x 2  20. The values of f(x) corresponding to x  3, 4, and 5 are shown in the following table:

25 20 2

1

3 4 Years

5

6

x

x f(x)

FIGURE 30 We obtain the graph of the function y  f(x) by graphing y  12x  20 over [0, 2] and y  12 x 2  20 over (2, 5].

3

4

5

24.5

28

32.5

Using the values of f(x) in this table, we sketch the graph of the function f as shown in Figure 30.

The Vertical-Line Test y x=9

8

4

(9, 3) x 4

–4

8

12

(9, – 3)

–8 FIGURE 31 Since a vertical line passes through the curve at more than one point, we deduce that it is not the graph of a function.

Although it is true that every function f of a variable x has a graph in the xy-plane, it is not true that every curve in the xy-plane is the graph of a function. For example, consider the curve depicted in Figure 31. This is the graph of the equation y 2  x. In general, the graph of an equation is the set of all ordered pairs (x, y) that satisfy the given equation. Observe that the points (9, 3) and (9, 3) both lie on the curve. This implies that the number x  9 is associated with two numbers: y  3 and y  3. But this clearly violates the uniqueness property of a function. Thus, we conclude that the curve under consideration cannot be the graph of a function. This example suggests the following vertical-line test for determining whether a curve is the graph of a function.

Vertical-Line Test

A curve in the xy-plane is the graph of a function y  f(x) if and only if each vertical line intersects it in at most one point.

94

2 FUNCTIONS AND THEIR GRAPHS

EXAMPLE 9 Determine which of the curves shown in Figure 32 are the graphs of functions of x. Solution The curves depicted in Figure 32a, c, and d are graphs of functions because each curve satisfies the requirement that each vertical line intersects the curve in at most one point. Note that the vertical line shown in Figure 32c does not intersect the graph because the point on the x-axis through which this line passes does not lie in the domain of the function. The curve depicted in Figure 32b is not the graph of a function of x because the vertical line shown there intersects the graph at three points.

y

y

x

x

(a)

(b) y

y

x

x

FIGURE 32 The vertical-line test can be used to determine which of these curves are graphs of functions.

(c)

(d)

2.3 Self-Check Exercises 1. Let f be the function defined by f 1x2 

a. Find the domain of f. c. Compute f (a  h).

1x  1 x

b. Compute f (3).

Source: Amoco Corporation

2. Statistics show that more and more motorists are pumping their own gas. The following function gives self-serve sales as a percentage of all U.S. gas sales: 6t  17 f 1t2  e 15.981t  62 1/4  53

Here t is measured in years, with t  0 corresponding to the beginning of 1974. a. Sketch the graph of the function f. b. What percentage of all gas sales at the beginning of 1978 were self-serve? At the beginning of 1994?

if 0 t 6 if 6 t 20

3. Let f 1x2  12x  1  2. Determine whether the point (4, 6) lies on the graph of f. Solutions to Self-Check Exercises 2.3 can be found on page 99.

2.3 FUNCTIONS AND THEIR GRAPHS

95

2.3 Concept Questions 1. a. What is a function? b. What is the domain of a function? The range of a function? c. What is an independent variable? A dependent variable?

c.

d. y

y

2. a. What is the graph of a function? Use a drawing to illustrate the graph, the domain, and the range of a function. b. If you are given a curve in the xy-plane, how can you tell if the graph is that of a function f defined by y  f(x)?

y

y

x

0

3. Are the following graphs of functions? Explain. a. b.

x

0

4. What are the domain and range of the function f with the following graph? y 4

0

x

0

x

3 2 1

(2, 12 ) 1

2

3

x 4

5

2.3 Exercises 1. Let f be the function defined by f(x)  5x  6. Find f(3), f(3), f(a), f(a), and f(a  3).

2t 2 9. Let f be the function defined by f 1t2  . Find f (2), 1t  1 f(a), f(x  1), and f(x  1).

2. Let f be the function defined by f(x)  4x  3. Find f(4), f Ó 14 Ô, f(0), f(a), and f(a  1).

10. Let f be the function defined by f 1x2  2  2 15  x. Find f(4), f(1), f 1 114 2 , and f(x  5).

3. Let t be the function defined by t(x)  3x 2  6x  3. Find t(0), t(1), t(a), t(a), and t(x  1).

11. Let f be the function defined by

4. Let h be the function defined by h(x)  x 3  x 2  x  1. Find h(5), h(0), h(a), and h(a). 5. Let f be the function defined by f(x)  2x  5. Find f(a  h), f(a), f(a2), f(a  2h), and f(2a  h). 6. Let t be the function defined by t(x)  x 2  2x. Find 1 t1a  h2, t1a 2, t1 1a 2, a  t1a 2, and . t 1a2 2t . 2 t 1 Find s(4), s(0), s(a), s(2  a), and s(t  1).

7. Let s be the function defined by s1t2 

8. Let t be the function defined by t(u)  (3u  2)3/2. Find t(1), t(6), t 1 113 2 , and t(u  1).

f 1x2  e

x2  1 1x

if x 0 if x  0

Find f(2), f(0), and f(1). 12. Let t be the function defined by 1  x1 2 t 1x2  c 1x  2

if x 2 if x  2

Find t(2), t(0), t(2), and t(4). 13. Let f be the function defined by 1  x2  3 f 1x2  c 2 2x2  1

Find f(1), f(0), f(1), and f(2).

if x 1 if x  1

96

2 FUNCTIONS AND THEIR GRAPHS

In Exercises 17–20, determine whether the point lies on the graph of the function.

14. Let f be the function defined by if x 1

2  11  x f 1x2  c 1 1x

17. 12, 23 2; t1x2  2x2  1

if x  1

18. 13, 32 ; f 1x2 

Find f(0), f(1), and f(2). 15. Refer to the graph of the function f in the following figure.

6

2x2  7

19. 12, 3 2; f 1t2  20. a 3, 

y

x1

2

| t  1| t1

| t  1| 1 b ; h1t2  3 13 t 1

y = f (x)

5 4

In Exercises 21 and 22, find the value of c such that the point P(a, b) lies on the graph of the function f.

3

21. f(x)  2x 2  4x  c; P(1, 5)

2

22. f(x)  x29  x 2  c; P(2, 4)

1

In Exercises 23–36, find the domain of the function.

x 1

–1

2

3

4

5

6

23. f(x)  x 2  3

–2

25. f 1x2 

a. Find the value of f(0). b. Find the value of x for which (i) f(x)  3 and (ii) f (x)  0. c. Find the domain of f. d. Find the range of f. 16. Refer to the graph of the function f in the following figure.

29. f 1x2  15  x 31. f 1x2 

6 y = f (x)

5 4 3 2 1

x 1

3

4

5

6

7

8

x x 1 2

33. f(x)  (x  3)3/2 11  x x2  4

26. t1x2 

2x  1 x1

28. f 1x2  1x  5 30. t1x2  22x 2  3 32. f 1x2 

1 x x2 2

34. t(x)  2(x  1)5/2 36. f 1x2 

1x  1 1x  22 1x  3 2

37. Let f be a function defined by the rule f(x)  x 2  x  6. a. Find the domain of f. b. Compute f(x) for x  3, 2, 1, 0, 12, 1, 2, 3. c. Use the results obtained in parts (a) and (b) to sketch the graph of f.

7

−3 −2

27. f 1x2  2x 2  1

35. f 1x2 

y

3x  1 x2

24. f(x)  7  x 2

9

10

−3

a. Find the value of f(7). b. Find the values of x corresponding to the point(s) on the graph of f located at a height of 5 units from the x-axis. c. Find the point on the x-axis at which the graph of f crosses it. What is the value of f (x) at this point? d. Find the domain and range of f.

38. Let f be a function defined by the rule f(x)  2x 2  x  3. a. Find the domain of f. b. Compute f(x) for x  3, 2, 1, 12, 0, 1, 2, 3. c. Use the results obtained in parts (a) and (b) to sketch the graph of f. In Exercises 39–50, sketch the graph of the function with the given rule. Find the domain and range of the function.

39. f(x)  2x 2  1

40. f(x)  9  x 2

41. f 1x2  2  1x

42. t 1x2  4  1x

45. f 1x2  | x|  1

46. f 1x2  | x|  1

43. f 1x2  11  x

44. f 1x2  1x  1

2.3 FUNCTIONS AND THEIR GRAPHS

47. f 1x2  e

x 2x  1

if x 0 if x  0

48. f 1x2  e

4x 2x  2

if x 2 if x  2

49. f 1x2  e

x  1 x2  1

x  1 50. f 1x2  c0 x1

60. The volume of a sphere of radius r is given by V1r2  43 pr .3 Compute V(2.1) and V(2). What does the quantity V(2.1)  V(2) measure? 61. GROWTH OF A CANCEROUS TUMOR The volume of a spherical cancerous tumor is given by the function

if x 1 if x  1

4 V1r2  pr 3 3

if x 1 if 1 x 1 if x  1

where r is the radius of the tumor in centimeters. By what factor is the volume of the tumor increased if its radius is doubled?

In Exercises 51–58, use the vertical-line test to determine whether the graph represents y as a function of x.

51.

y

52.

y

62. LIFE EXPECTANCY AFTER AGE 65 The average life expectancy after age 65 is soaring, putting pressure on the Social Security Administration’s resources. According to the Social Security Trustees, the average life expectancy after age 65 is given by L(t)  0.056t  18.1

x

x

53.

54.

y

97

(0 t 7)

where t is measured in years, with t  0 corresponding to 2003. a. How fast is the average life expectancy after age 65 changing at any time during the period under consideration? b. What will the average life expectancy be after age 65 in 2010?

y

Source: Social Security Trustees

63. CLOSING THE GENDER GAP IN EDUCATION The following graph shows the ratio of the number of bachelor’s degrees earned by women to that of men from 1960 through 1990.

x

x y (ratio of degrees earned)

55.

56.

y

1.2

y

(30, 1.1)

1.0 (20, 0.95) x

x

0.8 0.6

(0, 0.58) 10

57.

58.

y

x

20

30

t (years)

y

x

59. The circumference of a circle is given by C(r)  2pr, where r is the radius of the circle. What is the circumference of a circle with a 5-in. radius?

a. Write the rule for the function f giving the ratio of the number of bachelor’s degrees earned by women to that of men in year t, with t  0 corresponding to 1960. Hint: The function f is defined piecewise and is linear over each of two subintervals.

b. How fast was the ratio changing in the period from 1960 to 1980? From 1980 to 1990? c. In what year (approximately) was the number of bachelor’s degrees earned by women equal for the first time to that earned by men? Source: Department of Education

98

2 FUNCTIONS AND THEIR GRAPHS

64. THE GENDER GAP The following graph shows the ratio of women’s earnings to men’s from 1960 through 2000. y (ratio of women’s to men’s earnings)

0.8

(40, 0.78)

where S(t) is measured in billions of dollars and t is measured in years, with t  0 corresponding to 2004. What was the amount spent by payers on health-care IT in 2004? Assuming the projection held true, what amount was spent by payers in 2008? Source: U.S. Department of Commerce

0.75

68. HOTEL RATES The average daily rate of U.S. hotels from 2001 through 2006 is approximated by the function

0.7 0.65

(30, 0.66)

f 1t2  e

(0, 0.61) 0.6 (10, 0.59)

(20, 0.60)

10

20

0.55 30

40

t (years)

a. Write the rule for the function f giving the ratio of women’s earnings to men’s in year t, with t  0 corresponding to 1960. Hint: The function f is defined piecewise and is linear over each of four subintervals.

b. In what decade(s) was the gender gap expanding? Shrinking? c. Refer to part (b). How fast was the gender gap (the ratio/year) expanding or shrinking in each of these decades? Source: U.S. Bureau of Labor Statistics

65. WORKER EFFICIENCY An efficiency study conducted for Elektra Electronics showed that the number of “Space Commander” walkie-talkies assembled by the average worker t hr after starting work at 8:00 a.m. is given by N(t)  t 3  6t 2  15t

(0 t 4)

How many walkie-talkies can an average worker be expected to assemble between 8:00 and 9:00 a.m.? Between 9:00 and 10:00 a.m.? 66. POLITICS Political scientists have discovered the following empirical rule, known as the “cube rule,” which gives the relationship between the proportion of seats in the House of Representatives won by Democratic candidates s(x) and the proportion of popular votes x received by the Democratic presidential candidate: s1x2 

x3 3 x  11  x2 3

10 x 1 2

Compute s(0.6) and interpret your result. 67. U.S. HEALTH-CARE INFORMATION TECHNOLOGY (IT) SPENDING As health-care costs increase, payers are turning to technology and outsourced services to keep a lid on expenses. The amount of health-care IT spending by payer is projected to be S(t)  0.03t3  0.2t2  0.23t  5.6

(0 t 4)

82.95 0.95t 2  3.95t  86.25

if 1 t 3 if 3 t 6

where f(t) is measured in dollars, with t  1 corresponding to 2001. a. What was the average daily rate of U.S. hotels from 2001 through 2003? b. What was the average daily rate of U.S. hotels in 2004? In 2005? In 2006? c. Sketch the graph of f. Source: Smith Travel Research

69. INVESTMENTS IN HEDGE FUNDS Investments in hedge funds have increased along with their popularity. The assets of hedge funds (in trillions of dollars) from 2002 through 2007 are modeled by the function f 1t2  e

0.6 0.6t 0.43

if 0 t 1 if 1 t 5

where t is measured in years, with t  0 corresponding to the beginning of 2002. a. What were the assets in hedge funds at the beginning of 2002? At the beginning of 2003? b. What were the assets in hedge funds at the beginning of 2005? At the beginning of 2007? Source: Hennessee Group

70. RISING MEDIAN AGE Increased longevity and the aging of the baby boom generation—those born between 1946 and 1965— are the primary reasons for a rising median age. The median age (in years) of the U.S. population from 1900 through 2000 is approximated by the function 1.3t  22.9 f 1t2  c 0.7t 2  7.2t  11.5 2.6t  9.4

if 0 t 3 if 3 t 7 if 7 t 10

where t is measured in decades, with t  0 corresponding to the beginning of 1900. a. What was the median age of the U.S. population at the beginning of 1900? At the beginning of 1950? At the beginning of 1990? b. Sketch the graph of f. Source: U.S. Census Bureau

71. HARBOR CLEANUP The amount of solids discharged from the MWRA (Massachusetts Water Resources Authority) sewage treatment plant on Deer Island (near Boston Harbor) is given by the function

99

2.3 FUNCTIONS AND THEIR GRAPHS

130 30t  160 f 1t2  e 100 5t 2  25t  80 1.25t 2  26.25t  162.5

In Exercises 72–76, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

if 0 t 1 if 1 t 2 if 2 t 4 if 4 t 6 if 6 t 10

72. If a  b, then f(a)  f(b). 73. If f(a)  f(b), then a  b.

where f(t) is measured in tons/day and t is measured in years, with t  0 corresponding to 1989. a. What amount of solids were discharged per day in 1989? In 1992? In 1996? b. Sketch the graph of f.

74. If f is a function, then f(a  b)  f(a)  f(b). 75. A vertical line must intersect the graph of y  f(x) at exactly one point. 76. The domain of f 1x2  2x  2  22  x is [2, 2].

Source: Metropolitan District Commission

2.3 Solutions to Self-Check Exercises 1. a. The expression under the radical sign must be nonnegative, so x  1  0 or x  1. Also, x  0 because division by zero is not permitted. Therefore, the domain of f is [1, 0)  (0, ).

c. f 1a  h2 

11a  h2  1 ah



1a  h  1 ah

6 53

8 72

10 75.6

12 78

80

14 79.9

16 81.4

18 82.7

60 40

2. a. For t in the subdomain [0, 6], the rule for f is given by f (t)  6t  17. The equation y  6t  17 is a linear equation, so that portion of the graph of f is the line segment joining the points (0, 17) and (6, 53). Next, in the subdomain (6, 20], the rule for f is given by f (t)  15.98(t  6)1/4  53. Using a calculator, we construct the following table of values of f (t) for selected values of t. t f(t)

100

Percent

14 2 13  1 b. f 13 2    3 3 3

y

20 83.9

We have included t  6 in the table, although it does not lie in the subdomain of the function under consideration, in order to help us obtain a better sketch of that portion of the graph of f in the subdomain (6, 20]. The graph of f follows:

20

2

4

6

8

10 12 Years

14

16

18

20

t

b. The percentage of all self-serve gas sales at the beginning of 1978 is found by evaluating f at t  4. Since this point lies in the interval [0, 6], we use the rule f(t)  6t  17 and find f(4)  6(4)  17  41

giving 41% as the required figure. The percentage of all self-serve gas sales at the beginning of 1994 is given by f(20)  15.98(20  6)1/4  53  83.9

or approximately 83.9%. 3. A point (x, y) lies on the graph of the function f if and only if the coordinates satisfy the equation y  f(x). Now, f 14 2  12142  1  2  19  2  5  6

and we conclude that the given point does not lie on the graph of f.

100

2 FUNCTIONS AND THEIR GRAPHS

USING

TECHNOLOGY

Graphing a Function Most of the graphs of functions in this book can be plotted with the help of a graphing utility. Furthermore, a graphing utility can be used to analyze the nature of a function. However, the amount and accuracy of the information obtained using a graphing utility depend on the experience and sophistication of the user. As you progress through this book, you will see that the more knowledge of calculus you gain, the more effective the graphing utility will prove to be as a tool in problem solving. EXAMPLE 1 Plot the graph of f(x)  2x 2  4x  5 in the standard viewing window. Solution

The graph of f, shown in Figure T1a, is a parabola. From our previous work (Example 6, Section 2.3), we know that the figure does give a good view of the graph. WINDOW Xmin = Xmax = Xsc1 = Ymin = Ymax = Ysc1 = Xres = (a)

Plot1 Plot2 Plot3 \Y1 = 2X^2 − 4X − 5 \Y2 = \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

−10 10 1 −10 10 1 1

(b)

(c)

FIGURE T1

(a) The graph of f (x)  2x2  4x  5 on [10, 10]  [10, 10]; (b) the TI-83/84 window screen for (a); (c) the TI-83/84 equation screen

EXAMPLE 2 Let f(x)  x 3(x  3)4. a. Plot the graph of f in the standard viewing window. b. Plot the graph of f in the window [1, 5]  [40, 40]. Solution

a. The graph of f in the standard viewing window is shown in Figure T2a. Since the graph does not appear to be complete, we need to adjust the viewing window. Plot1 Plot2 Plot3 \Y1 = X^3(X − 3)^4 \Y2 = \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

FIGURE T2 (a) An incomplete sketch of f(x)  x3(x  3)4 on [10, 10]  [10, 10]; (b) the TI-83/84 equation screen

(a)

(b)

b. The graph of f in the window [1, 5]  [40, 40], shown in Figure T3a, is an improvement over the previous graph. (Later we will be able to show that the figure does in fact give a rather complete view of the graph of f.) WINDOW Xmin = Xmax = Xsc1 = Ymin = Ymax = Ysc1 = Xres =

FIGURE T3

(a) A complete sketch of f(x)  x3(x  3)4 is shown using the window [1, 5]  [40, 40]; (b) the TI-83/84 window screen

(a)

(b)

−1 5 1 −40 40 1 1

2.3 FUNCTIONS AND THEIR GRAPHS

101

Evaluating a Function

A graphing utility can be used to find the value of a function with minimal effort, as the next example shows. EXAMPLE 3 Let f(x)  x 3  4x 2  4x  2. a. Plot the graph of f in the standard viewing window. b. Find f(3) and verify your result by direct computation. c. Find f(4.215). Solution

a. The graph of f is shown in Figure T4a. Plot1 Plot2 Plot3 \Y1 = X^3 − 4X^2 + 4X + 2 \Y2 = \Y3 = \Y4 = \Y5 = \Y6 =

FIGURE T4

(a) The graph of f(x)  x3  4x2  4x  2 in the standard viewing window; (b) the TI-83/84 equation screen

(a)

(b)

b. Using the evaluation function of the graphing utility and the value 3 for x, we find y  5. This result is verified by computing f(3)  33  4(32)  4(3)  2  27  36  12  2  5

c. Using the evaluation function of the graphing utility and the value 4.215 for x, we find y  22.679738375. Thus, f(4.215)  22.679738375. The efficacy of the graphing utility is clearly demonstrated here! APPLIED EXAMPLE 4 Number of Alzheimer’s Patients The number of Alzheimer’s patients in the United States is approximated by f(t)  0.0277t 4  0.3346t 3  1.1261t 2  1.7575t  3.7745

(0 t 6)

where f(t) is measured in millions and t is measured in decades, with t  0 corresponding to the beginning of 1990. a. Use a graphing utility to plot the graph of f in the viewing window [0, 7]  [0, 12]. b. What is the anticipated number of Alzheimer’s patients in the United States at the beginning of 2010 (t  2)? At the beginning of 2030 (t  4)? Source: Alzheimer’s Association Solution

a. The graph of f in the viewing window [0, 7]  [0, 12] is shown in Figure T5a. Plot1 Plot2 Plot3 \Y1 = −.0277X^4 + .3346X^3 − 1.1261X^2 + 1.7575X + 3.7745 \Y2 = \Y3 = \Y4 = \Y5 =

FIGURE T5 (a) The graph of f in the viewing window [0, 7]  [0, 12]; (b) the TI-83/84 equation screen

(a)

(b) (continued)

102

2 FUNCTIONS AND THEIR GRAPHS

b. Using the evaluation function of the graphing utility and the value 2 for x, we see that the anticipated number of Alzheimer’s patients at the beginning of 2010 is given by f(2)  5.0187, or approximately 5 million. The anticipated number of Alzheimer’s patients at the beginning of 2030 is given by f(4)  7.1101 or approximately 7.1 million.

TECHNOLOGY EXERCISES In Exercises 1–4, plot the graph of the function f in (a) the standard viewing window and (b) the indicated window.

1. f 1x2  x 4  2x 2  8; 32, 24  3 6, 104

2. f 1x2  x 3  20x 2  8x  10; 320, 20 4  31200, 1004 3. f 1x 2  x24  x2; 33, 3 4  32, 2 4 4. f 1x 2 

4 ; 3 5, 54  3 5, 54 x2  8

N(t)  6.08t 3  26.79t 2  53.06t  69.5

In Exercises 5–8, plot the graph of the function f in an appropriate viewing window. (Note: The answer is not unique.)

5. f (x)  2x 4  3x 3  5x 2  20x  40 6. f(x)  2x 4  5x 2  4 7. f 1x 2 

8. f 1x 2 

x3 x 1 3

2x4  3x x2  1

In Exercises 9–12, use the evaluation function of your graphing utility to find the value of f at the indicated value of x. Express your answer accurate to four decimal places.

9. f (x)  3x 3  2x 2  x  4; x  2.145 2x3  3x  1 ; x  2.41 3x  2

12. f 1x 2  22x2  1  23x2  1; x  0.62 13. HIRING LOBBYISTS Many public entities like cities, counties, states, utilities, and Indian tribes are hiring firms to lobby Congress. One goal of such lobbying is to place earmarks—money directed at a specific project—into appropriation bills. The amount (in millions of dollars) spent by public entities on lobbying from 1998 through 2004, where t  0 corresponds to 1998, is given by f(t)  0.425t  3.6571t  4.018t  43.7 3

2

(0 t 6)

(0 t 4)

gives the number, N(t), of U.S. communities using surveillance cameras at intersections in year t, with t  0 corresponding to 2003. a. Plot the graph of N in the viewing window [0, 4]  [0, 250]. b. How many communities used surveillance cameras at intersections in 2004? In 2006? Source: Insurance Institute for Highway Safety

15. KEEPING WITH THE TRAFFIC FLOW By driving at a speed to match the prevailing traffic speed, you decrease the chances of an accident. According to data obtained in a university study, the number of accidents/100 million vehicle miles, y, is related to the deviation from the mean speed, x, in mph by y  1.05x 3  21.95x 2  155.9x  327.3

10. f(x)  5x 4  2x 2  8x  3; x  1.28 11. f 1x 2 

14. SURVEILLANCE CAMERAS Research reports indicate that surveillance cameras at major intersections dramatically reduce the number of drivers who barrel through red lights. The cameras automatically photograph vehicles that drive into intersections after the light turns red. Vehicle owners are then mailed citations instructing them to pay a fine or sign an affidavit that they weren’t driving at the time. The function

(6 x 11)

a. Plot the graph of y in the viewing window [6, 11]  [20, 150]. b. What is the number of accidents/100 million vehicle miles if the deviation from the mean speed is 6 mph, 8 mph, and 11 mph? Source: University of Virginia School of Engineering and Applied Science

16. SAFE DRIVERS The fatality rate in the United States (per 100 million miles traveled) by age of driver (in years) is given by the function f(x)  0.00000304x 4  0.0005764x 3  0.04105x 2  1.30366x  16.579

(18 x 82)

a. Plot the graph of f in the viewing window [0, 6]  [0, 110]. b. What amount was spent by public entities on lobbying in the year 2000? In 2004?

a. Plot the graph of f in the viewing window [18, 82]  [0, 8]. b. What is the fatality rate for 18-yr-old drivers? For 50-yrold drivers? For 80-yr-old drivers?

Source: Center for Public Integrity

Source: National Highway Traffic Safety Administration

103

2.4 THE ALGEBRA OF FUNCTIONS

2.4 The Algebra of Functions The Sum, Difference, Product, and Quotient of Functions Let S(t) and R(t) denote, respectively, the federal government’s spending and revenue at any time t, measured in billions of dollars. The graphs of these functions for the period between 1990 and 2000 are shown in Figure 33.

y 2000 y = R(t)

Billions of dollars

1800 y = S(t)

Spending

1600 S(t)

D(t) = R(t)

S(t)

R(t) 1200 Revenue

1000

1992

1994

1996

1998

2000

t

Year

FIGURE 33

R(t)  S(t) gives the federal budget deficit (surplus) at any time t.

t

Source: Office of Management and Budget

The difference R(t)  S(t) gives the deficit (surplus) in billions of dollars at any time t if R(t)  S(t) is negative (positive). This observation suggests that we can define a function D whose value at any time t is given by R(t)  S(t). The function D, the difference of the two functions R and S, is written D  R  S and may be called the “deficit (surplus) function” since it gives the budget deficit or surplus at any time t. It has the same domain as the functions S and R. The graph of the function D is shown in Figure 34.

y

Billions of dollars

400 200

y = D(t)

1992

1994

t

1996

t 1998

2000

D(t) Year –400

FIGURE 34 The graph of D(t)

Source: Office of Management and Budget

Most functions are built up from other, generally simpler functions. For example, we may view the function f(x)  2x  4 as the sum of the two functions t(x)  2x

104

2 FUNCTIONS AND THEIR GRAPHS

and h(x)  4. The function t(x)  2x may in turn be viewed as the product of the functions p(x)  2 and q(x)  x. In general, given the functions f and t, we define the sum f  t, the difference f  t, the product ft, and the quotient f/t of f and t as follows.

The Sum, Difference, Product, and Quotient of Functions

Let f and t be functions with domains A and B, respectively. Then the sum f  t, difference f  t, and product ft of f and t are functions with domain A  B* and rule given by ( f  t)(x)  f (x)  t(x)

Sum

( f  t)(x)  f (x)  t(x)

Difference

( ft)(x)  f(x)t(x)

Product

The quotient f /t of f and t has domain A  B excluding all numbers x such that t(x)  0 and rule given by f 1x2 f a b 1x2  t t1x2

Quotient

*A  B is read “A intersected with B” and denotes the set of all points common to both A and B.

EXAMPLE 1 Let f (x)  1x  1 and t(x)  2x  1. Find the sum s, the difference d, the product p, and the quotient q of the functions f and t. Since the domain of f is A  [1, ) and the domain of t is B  (, ), we see that the domain of s, d, and p is A  B  [1, ). The rules follow.

Solution

s1x2  1 f  t2 1x2  f 1x 2  t 1x2  1x  1  2x  1 d1x2  1 f  t2 1x2  f 1x 2  t 1x2  1x  1  12x  12  1x  1  2x  1 p1x2  1 ft2 1x 2  f 1x2t 1x 2  1x  112x  12  12x  12 1x  1

The quotient function q has rule

f 1x2 f 1x  1 q1x2  a b 1x2   t t 1x2 2x  1

Its domain is [1, ) together with the restriction x  12. We denote this by [1, 12 Ô  Ó12 , Ô. The mathematical formulation of a problem arising from a practical situation often leads to an expression that involves the combination of functions. Consider, for example, the costs incurred in operating a business. Costs that remain more or less constant regardless of the firm’s level of activity are called fixed costs. Examples of fixed costs are rental fees and executive salaries. On the other hand, costs that vary with production or sales are called variable costs. Examples of variable costs are wages and costs of raw materials. The total cost of operating a business is thus given by the sum of the variable costs and the fixed costs, as illustrated in the next example. APPLIED EXAMPLE 2 Cost Functions Suppose Puritron, a manufacturer

of water filters, has a monthly fixed cost of $10,000 and a variable cost of 0.0001x 2  10x

(0 x 40,000)

2.4 THE ALGEBRA OF FUNCTIONS

105

dollars, where x denotes the number of filters manufactured per month. Find a function C that gives the total monthly cost incurred by Puritron in the manufacture of x filters. Solution Puritron’s monthly fixed cost is always $10,000, regardless of the level of production, and it is described by the constant function F(x)  10,000. Next, the variable cost is described by the function V(x)  0.0001x 2  10x. Since the total cost incurred by Puritron at any level of production is the sum of the variable cost and the fixed cost, we see that the required total cost function is given by

C(x)  V(x)  F(x)  0.0001x 2  10x  10,000

(0 x 40,000)

Next, the total profit realized by a firm in operating a business is the difference between the total revenue realized and the total cost incurred; that is, P(x)  R(x)  C(x) APPLIED EXAMPLE 3 Profit Functions Refer to Example 2. Suppose

the total revenue realized by Puritron from the sale of x water filters is given by the total revenue function R(x)  0.0005x 2  20x

(0 x 40,000)

a. Find the total profit function—that is, the function that describes the total profit Puritron realizes in manufacturing and selling x water filters per month. b. What is the profit when the level of production is 10,000 filters per month? Solution

a. The total profit realized by Puritron in manufacturing and selling x water filters per month is the difference between the total revenue realized and the total cost incurred. Thus, the required total profit function is given by P(x)  R(x)  C(x)  (0.0005x 2  20x)  (0.0001x 2  10x  10,000)  0.0004x 2  10x  10,000

b. The profit realized by Puritron when the level of production is 10,000 filters per month is P(10,000)  0.0004(10,000)2  10(10,000)  10,000  50,000

or $50,000 per month.

Composition of Functions Another way to build up a function from other functions is through a process known as the composition of functions. Consider, for example, the function h, whose rule is given by h(x)  2x2  1. Let f and t be functions defined by the rules f(x)  x 2  1 and t(x)  1x. Evaluating the function t at the point f (x) [remember that for each real number x in the domain of f, f (x) is simply a real number], we find that t 1 f 1x22  2f 1x2  2x2  1

which is just the rule defining the function h!

106

2 FUNCTIONS AND THEIR GRAPHS

In general, the composition of a function t with a function f is defined as follows. The Composition of Two Functions

Let f and t be functions. Then the composition of t and f is the function t 폶 f defined by (t 폶 f )(x)  t( f(x))

The domain of t 폶 f is the set of all x in the domain of f such that f(x) lies in the domain of t. The function t 폶 f (read “t circle f ”) is also called a composite function. The interpretation of the function h  t 폶 f as a machine is illustrated in Figure 35 and its interpretation as a mapping is shown in Figure 36. g

f g

x

f(x)

g FIGURE 36

FIGURE 35

h(x) = g(f(x))

h = g° f

The function h  g 폶 f viewed as a mapping

The composite function h  g 폶 f viewed as a machine

EXAMPLE 4 Let f(x)  x 2  1 and t 1x2  1x  1. Find: a. The rule for the composite function t 폶 f. b. The rule for the composite function f 폶 t. Solution

a. To find the rule for the composite function t 폶 f, evaluate the function t at f(x). We obtain 1t ⴰ f 2 1x2  t1 f 1x22  2f 1x2  1  2x2  1  1

b. To find the rule for the composite function f 폶 t, evaluate the function f at t(x). Thus, 1 f ⴰ t2 1x2  f 1t 1x22  1t 1x22 2  1  1 1x  12 2  1  x  21x  1  1  x  21x

Example 4 reminds us that in general t 폶 f is different from f 폶 t, so care must be taken when finding the rule for a composite function.

Explore & Discuss

Let f 1x2  1x  1 for x  0 and let t(x)  (x  1)2 for x  1. 1. Show that (t 폶 f )(x) and ( f 폶 t)(x)  x. (Note: The function t is said to be the inverse of f and vice versa.) 2. Plot the graphs of f and t together with the straight line y  x. Describe the relationship between the graphs of f and t.

APPLIED EXAMPLE 5 Automobile Pollution An environmental

impact study conducted for the city of Oxnard indicates that, under existing environmental protection laws, the level of carbon monoxide (CO) present in the air due to pollution from automobile exhaust will be 0.01x2/3 parts per million

2.4 THE ALGEBRA OF FUNCTIONS

107

when the number of motor vehicles is x thousand. A separate study conducted by a state government agency estimates that t years from now the number of motor vehicles in Oxnard will be 0.2t 2  4t  64 thousand. a. Find an expression for the concentration of CO in the air due to automobile exhaust t years from now. b. What will be the level of concentration 5 years from now? Solution

a. The level of CO present in the air due to pollution from automobile exhaust is described by the function t(x)  0.01x 2/3, where x is the number (in thousands) of motor vehicles. But the number of motor vehicles x (in thousands) t years from now may be estimated by the rule f(t)  0.2t 2  4t  64. Therefore, the concentration of CO due to automobile exhaust t years from now is given by C(t)  (t 폶 f )(t)  t( f(t))  0.01(0.2t 2  4t  64)2/3

parts per million. b. The level of concentration 5 years from now will be C(5)  0.01[0.2(5)2  4(5)  64]2/3  (0.01)892/3  0.20

or approximately 0.20 parts per million.

2.4 Self-Check Exercises 1. Let f and t be functions defined by the rules f 1x2  1x  1 and t 1x 2 

x 1x

respectively. Find the rules for a. The sum s, the difference d, the product p, and the quotient q of f and t. b. The composite functions f 폶 t and t 폶 f. 2. Health-care spending per person by the private sector includes payments by individuals, corporations, and their insurance companies and is approximated by the function f (t)  2.48t 2  18.47t  509

(0 t 6)

where f (t) is measured in dollars and t is measured in years, with t  0 corresponding to the beginning of 1994. The

corresponding government spending—including expenditures for Medicaid, Medicare, and other federal, state, and local government public health care—is t(t)  1.12t 2  29.09t  429

(0 t 6)

where t has the same meaning as before. a. Find a function that gives the difference between private and government health-care spending per person at any time t. b. What was the difference between private and government expenditures per person at the beginning of 1995? At the beginning of 2000? Source: Health Care Financing Administration

Solutions to Self-Check Exercises 2.4 can be found on page 110.

2.4 Concept Questions 1. a. Explain what is meant by the sum, difference, product, and quotient of the functions f and t with domains A and B, respectively. b. If f (2)  3 and t(2)  2, what is ( f  t)(2)? ( f  t)(2)? ( ft)(2)? ( f/t)(2)?

3. a. What is the composition of the functions f and t? The functions t and f ? b. If f (2)  3 and t(3)  8, what is (t 폶 f )(2)? Can you conclude from the given information what ( f 폶 t)(3) is? Explain.

2. Let f and t be functions and suppose that (x, y) is a point on the graph of h. What is the value of y for h  f  t? h  f  t? h  ft? h  f/t?

4. Let f be a function with domain A and let t be a function whose domain contains the range of f. If a is any number in A, must (t 폶 f)(a) be defined? Explain with an example.

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2 FUNCTIONS AND THEIR GRAPHS

2.4 Exercises In Exercises 1–8, let f (x)  x3  5, g(x)  x2  2, and h(x)  2x  4. Find the rule for each function.

1. f  t 5.

2. f  t

f t

6.

3. ft

ft

7.

h

ft h

4. t f 8. fth

In Exercises 9–18, let f (x)  x  1, g(x)  1x  1, and h(x)  2x3  1. Find the rule for each function.

9. f  t 13. 17.

10. t  f

t

14.

h fh t

18.

11. ft

h t

15.

ft h

12. t f 16.

fh t

th

In Exercises 35–42, find functions f and g such that h  g 폶 f. (Note: The answer is not unique.)

35. h(x)  (2x 3  x 2  1)5 36. h(x)  (3x 2  4)3 37. h1x2  2x2  1

38. h(x)  (2x  3)3/2

39. h1x2 

1 x 1

41. h1x2 

13x2  22 3/2

42. h1x2 

1  12x  1 12x  1

40. h1x2 

2

1 2x  4 2

1

In Exercises 43–46, find f(a  h)  f(a) for each function. Simplify your answer.

tf

In Exercises 19–24, find the functions f  g, f  g, fg, and f/g.

19. f 1x 2  x2  5; t1x 2  1x  2 20. f 1x 2  1x  1; t1x 2  x3  1 21. f 1x2  1x  3; t 1x2 

43. f(x)  3x  4

1 44. f 1x2   x  3 2

45. f(x)  4  x 2

46. f(x)  x 2  2x  1

In Exercises 47–52, find and simplify f(a  h)  f(a)

1 x1

h

(h  0)

22. f 1x 2 

1 1 ; t 1x2  2 x 1 x 1

for each function.

47. f(x)  x 2  1

48. f(x)  2x 2  x  1

23. f 1x2 

x1 x2 ; t 1x 2  x1 x2

49. f(x)  x 3  x

50. f(x)  2x 3  x 2  1

51. f 1x2 

52. f 1x2  1x

2

24. f 1x 2  x2  1; t 1x 2  1x  1 In Exercises 25–30, find the rules for the composite functions f 폶 g and g 폶 f.

25. f (x)  x 2  x  1; t(x)  x 2 26. f (x)  3x 2  2x  1; t(x)  x  3 27. f 1x 2  1x  1; t 1x2  x2  1

28. f 1x2  2 1x  3; t 1x 2  x2  1 29. f 1x 2 

x 1 ; t 1x2  x x2  1

30. f 1x2  1x  1; t1x 2 

1 x1

In Exercises 31–34, evaluate h(2), where h  g 폶 f.

31. f (x)  x 2  x  1; t(x)  x 2

3 2 32. f 1x2  2 x  1; t1x 2  3x3  1

1 33. f 1x 2  ; t1x 2  1x 2x  1 34. f 1x 2 

1 ; t1x 2  x2  1 x1

1 x

53. RESTAURANT REVENUE Nicole owns and operates two restaurants. The revenue of the first restaurant at time t is f (t) dollars, and the revenue of the second restaurant at time t is t(t) dollars. What does the function F(t)  f (t)  t(t) represent? 54. BIRTHRATE OF ENDANGERED SPECIES The birthrate of an endangered species of whales in year t is f(t) whales/year. This species of whales is dying at the rate of t(t) whales/year in year t. What does the function F(t)  f(t)  t(t) represent? 55. VALUE OF AN INVESTMENT The number of IBM shares that Nancy owns is given by f(t). The price per share of the stock of IBM at time t is t(t) dollars. What does the function f(t)t(t) represent? 56. PRODUCTION COSTS The total cost incurred by time t in the production of a certain commodity is f(t) dollars. The number of products produced by time t is t(t) units. What does the function f(t)/t(t) represent? 57. CARBON MONOXIDE POLLUTION The number of cars running in the business district of a town at time t is given by f(t). Carbon monoxide pollution coming from these cars is given by t(x) parts per million, where x is the number of cars being operated in the district. What does the function t 폶 f represent?

2.4 THE ALGEBRA OF FUNCTIONS

58. EFFECT OF ADVERTISING ON REVENUE The revenue of Leisure Travel is given by f(x) dollars, where x is the dollar amount spent by the company on advertising. The amount spent by Leisure at time t on advertising is given by t(t) dollars. What does the function f 폶 t represent? 59. MANUFACTURING COSTS TMI, a manufacturer of blank audiocassette tapes, has a monthly fixed cost of $12,100 and a variable cost of $.60/tape. Find a function C that gives the total cost incurred by TMI in the manufacture of x tapes/month. 60. SPAM MESSAGES The total number of email messages per day (in billions) between 2003 and 2007 is approximated by f (t )  1.54t 2  7.1t  31.4

(0 t 4)

where t is measured in years, with t  0 corresponding to 2003. Over the same period, the total number of spam messages per day (in billions) is approximated by t(t )  1.21t 2  6t  14.5

(0 t 4)

a. Find the rule for the function D  f  t. Compute D(4) and explain what it measures. b. Find the rule for the function P  f /t. Compute P(4) and explain what it means. Source: Technology Review

61. GLOBAL SUPPLY OF PLUTONIUM The global stockpile of plutonium for military applications between 1990 (t  0) and 2003 (t  13) stood at a constant 267 tons. On the other hand, the global stockpile of plutonium for civilian use was 2t  46t  733 2

tons in year t over the same period. a. Find the function f giving the global stockpile of plutonium for military use from 1990 through 2003 and the function t giving the global stockpile of plutonium for civilian use over the same period. b. Find the function h giving the total global stockpile of plutonium between 1990 and 2003. c. What was the total global stockpile of plutonium in 2003? Source: Institute for Science and International Security

62. MOTORCYCLE DEATHS Suppose the fatality rate (deaths/100 million miles traveled) of motorcyclists is given by t(x), where x is the percentage of motorcyclists who wear helmets. Next, suppose the percentage of motorcyclists who wear helmets at time t (t measured in years) is f(t), with t  0 corresponding to 2000. a. If f(0)  0.64 and t(0.64)  26 find ( t 폶 f )(0) and interpret your result. b. If f(6)  0.51 and t(0.51)  42 find ( t 폶 f )(6) and interpret your result. c. Comment on the results of parts (a) and (b). Source: National Highway Traffic Safety Administration

63. FIGHTING CRIME Suppose the reported serious crimes (crimes that include homicide, rape, robbery, aggravated assault, burglary, and car theft) that end in arrests or in the identification of suspects is t(x) percent, where x denotes the total number of detectives. Next, suppose the total number of detectives in year t is f(t), with t  0 corresponding to 2001. a. If f(1)  406 and t(406)  23, find (t 폶 f )(1) and interpret your result.

109

b. If f(6)  326 and t(326)  18, find (t 폶 f )(6) and interpret your result. c. Comment on the results of parts (a) and (b). Source: Boston Police Department

64. COST OF PRODUCING PDAS Apollo manufactures PDAs at a variable cost of V(x)  0.000003x 3  0.03x 2  200x

dollars, where x denotes the number of units manufactured per month. The monthly fixed cost attributable to the division that produces these PDAs is $100,000. Find a function C that gives the total cost incurred by the manufacture of x PDAs. What is the total cost incurred in producing 2000 units/month? 65. PROFIT FROM SALE OF PDAS Refer to Exercise 64. Suppose the total revenue realized by Apollo from the sale of x PDAs is given by the total revenue function R(x)  0.1x 2  500x

(0 x 5000)

where R(x) is measured in dollars. a. Find the total profit function. b. What is the profit when 1500 units are produced and sold each month? 66. PROFIT FROM SALE OF PAGERS A division of Chapman Corporation manufactures a pager. The weekly fixed cost for the division is $20,000, and the variable cost for producing x pagers/week is V(x)  0.000001x 3  0.01x 2  50x

dollars. The company realizes a revenue of R(x)  0.02x 2  150x

(0 x 7500)

dollars from the sale of x pagers/week. a. Find the total cost function. b. Find the total profit function. c. What is the profit for the company if 2000 units are produced and sold each week? 67. OVERCROWDING OF PRISONS The 1980s saw a trend toward old-fashioned punitive deterrence as opposed to the more liberal penal policies and community-based corrections popular in the 1960s and early 1970s. As a result, prisons became more crowded, and the gap between the number of people in prison and the prison capacity widened. The number of prisoners (in thousands) in federal and state prisons is approximated by the function N(t)  3.5t 2  26.7t  436.2

(0 t 10)

where t is measured in years, with t  0 corresponding to 1983. The number of inmates for which prisons were designed is given by C(t)  24.3t  365

(0 t 10)

where C(t) is measured in thousands and t has the same meaning as before. a. Find an expression that shows the gap between the number of prisoners and the number of inmates for which the prisons were designed at any time t. b. Find the gap at the beginning of 1983 and at the beginning of 1986. Source: U.S. Department of Justice

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2 FUNCTIONS AND THEIR GRAPHS

68. EFFECT OF MORTGAGE RATES ON HOUSING STARTS A study prepared for the National Association of Realtors estimated that the number of housing starts per year over the next 5 yr will be N1r2 

7 1  0.02r 2

million units, where r (percent) is the mortgage rate. Suppose the mortgage rate over the next t mo is r1t 2 

10t  150 t  10

10 t 242

Hint: Compute R(r (0)) and R(r(5)).

70. HOUSING STARTS AND CONSTRUCTION JOBS The president of a major housing construction firm reports that the number of construction jobs (in millions) created is given by N(x)  1.42x

where x denotes the number of housing starts. Suppose the number of housing starts in the next t mo is expected to be x1t2 

percent/year. a. Find an expression for the number of housing starts per year as a function of t, t mo from now. b. Using the result from part (a), determine the number of housing starts at present, 12 mo from now, and 18 mo from now. 69. HOTEL OCCUPANCY RATE The occupancy rate of the allsuite Wonderland Hotel, located near an amusement park, is given by the function 10 3 10 2 200 r1t 2  t  t  t  55 81 3 9

10 t 112

where t is measured in months and t  0 corresponds to the beginning of January. Management has estimated that the monthly revenue (in thousands of dollars) is approximated by the function R1r2  

b. What is the hotel’s monthly revenue at the beginning of January? At the beginning of June?

10 r 100 2

3 3 9 r  r2 5000 50

where r (percent) is the occupancy rate. a. What is the hotel’s occupancy rate at the beginning of January? At the beginning of June?

71t  102 2

1t  10 2 2  21t  15 2 2

million units/year. Find an expression for the number of jobs created per month in the next t mo. How many jobs will have been created 6 mo and 12 mo from now? 71. a. Let f, t, and h be functions. How would you define the “sum” of f, t, and h? b. Give a real-life example involving the sum of three functions. (Note: The answer is not unique.) 72. a. Let f, t, and h be functions. How would you define the “composition” of h, t, and f, in that order? b. Give a real-life example involving the composition of these functions. (Note: The answer is not unique.) In Exercises 73–76, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

73. If f and t are functions with domain D, then f  t  t  f. 74. If t 폶 f is defined at x  a, then f 폶 t must also be defined at x  a. 75. If f and t are functions, then f 폶 t  t 폶 f. 76. If f is a function, then f 폶 f  f 2.

2.4 Solutions to Self-Check Exercises 1. a. s1x 2  f 1x 2  t1x 2  1x  1 

x 1x

d1x 2  f 1x2  t1x 2  1x  1 

x 1x

p1x 2  f 1x 2t1x 2  1 1x  12 q1x2 

f 1x 2 t1x2



#

x  1x

2. a. The difference between private and government healthcare spending per person at any time t is given by the function d with the rule x1 1x  1 2 1x

1 1x  12 11  x 2 1x  1  x x 1x

x b. 1 f ⴰ t 2 1x 2  f 1t1x 22  1 A1  x 1t ⴰ f 2 1x 2  t1 f 1x 22 

1x  1 1x  1  1  1 1x  12 1x  2

d1t2  f 1t 2  t1t2  12.48t 2  18.47t  5092  11.12t 2  29.09t  4292

 3.6t 2  10.62t  80

b. The difference between private and government expenditures per person at the beginning of 1995 is given by d(1)  3.6(1)2  10.62(1)  80

or $72.98/person. The difference between private and government expenditures per person at the beginning of 2000 is given by d(6)  3.6(6)2  10.62(6)  80

or $145.88/person.

2.5 LINEAR FUNCTIONS

111

2.5 Linear Functions We now focus our attention on an important class of functions known as linear functions. Recall that a linear equation in x and y has the form Ax  By  C  0, where A, B, and C are constants and A and B are not both zero. If B  0, the equation can always be solved for y in terms of x; in fact, as we saw in Section 2.2, the equation may be cast in the slope-intercept form: y  mx  b

(m, b constants)

(7)

Equation (7) defines y as a function of x. The domain and range of this function is the set of all real numbers. Furthermore, the graph of this function, as we saw in Section 2.2, is a straight line in the plane. For this reason, the function f (x)  mx  b is called a linear function.

Linear Function

The function f defined by f(x)  mx  b

where m and b are constants, is called a linear function.

Linear functions play an important role in the quantitative analysis of business and economic problems. First, many problems arising in these and other fields are linear in nature or are linear in the intervals of interest and thus can be formulated in terms of linear functions. Second, because linear functions are relatively easy to work with, assumptions involving linearity are often made in the formulation of problems. In many cases these assumptions are justified, and acceptable mathematical models are obtained that approximate real-life situations. In the rest of this section, we look at several applications that can be modeled using linear functions.

Simple Depreciation We first discussed linear depreciation in Section 2.1 as a real-world application of straight lines. The following example illustrates how to derive an equation describing the book value of an asset that is being depreciated linearly. APPLIED EXAMPLE 1 Linear Depreciation A Web server has an original value of $10,000 and is to be depreciated linearly over 5 years with a $3000 scrap value. Find an expression giving the book value at the end of year t. What will be the book value of the server at the end of the second year? What is the rate of depreciation of the server? Solution Let V(t) denote the Web server’s book value at the end of the t th year. Since the depreciation is linear, V is a linear function of t. Equivalently, the graph of the function is a straight line. Now, to find an equation of the straight line, observe that V  10,000 when t  0; this tells us that the line passes through the point (0, 10,000). Similarly, the condition that V  3000 when t  5 says that the line also passes through the point (5, 3000). The slope of the line is given by

m

10,000  3000 7000   1400 05 5

112

2 FUNCTIONS AND THEIR GRAPHS

Using the point-slope form of the equation of a line with the point (0, 10,000) and the slope m  1400, we have

V ($) 10,000

V  10,000  14001t  02 V  1400t  10,000

the required expression. The book value at the end of the second year is given by (5, 3000)

3000

V(2)  1400(2)  10,000  7200 t

1

2

3 4 Years

5

FIGURE 37 Linear depreciation of an asset

or $7200. The rate of depreciation of the server is given by the negative of the slope of the depreciation line. Since the slope of the line is m  1400, the rate of depreciation is $1400 per year. The graph of V  1400t  10,000 is sketched in Figure 37.

Linear Cost, Revenue, and Profit Functions Whether a business is a sole proprietorship or a large corporation, the owner or chief executive must constantly keep track of operating costs, revenue resulting from the sale of products or services, and, perhaps most important, the profits realized. Three functions provide management with a measure of these quantities: the total cost function, the revenue function, and the profit function. Cost, Revenue, and Profit Functions

Let x denote the number of units of a product manufactured or sold. Then, the total cost function is C(x)  Total cost of manufacturing x units of the product

The revenue function is R(x)  Total revenue realized from the sale of x units of the product

The profit function is P(x)  Total profit realized from manufacturing and selling x units of the product

Generally speaking, the total cost, revenue, and profit functions associated with a company will probably be nonlinear (these functions are best studied using the tools of calculus). But linear cost, revenue, and profit functions do arise in practice, and we will consider such functions in this section. Before deriving explicit forms of these functions, we need to recall some common terminology. The costs incurred in operating a business are usually classified into two categories. Costs that remain more or less constant regardless of the firm’s activity level are called fixed costs. Examples of fixed costs are rental fees and executive salaries. Costs that vary with production or sales are called variable costs. Examples of variable costs are wages and costs for raw materials. Suppose a firm has a fixed cost of F dollars, a production cost of c dollars per unit, and a selling price of s dollars per unit. Then the cost function C(x), the revenue function R(x), and the profit function P(x) for the firm are given by C1x2  cx  F R1x2  sx P1x2  R1x2  C1x2  1s  c2x  F

Revenue  cost

where x denotes the number of units of the commodity produced and sold. The functions C, R, and P are linear functions of x.

2.5 LINEAR FUNCTIONS

113

APPLIED EXAMPLE 2 Profit Functions Puritron, a manufacturer of water filters, has a monthly fixed cost of $20,000, a production cost of $20 per unit, and a selling price of $30 per unit. Find the cost function, the revenue function, and the profit function for Puritron. Solution

Let x denote the number of units produced and sold. Then C1x2  20x  20,000 R1x2  30x P1x2  R1x2  C1x2  30x  120x  20,0002  10x  20,000

Intersection of Straight Lines y

The solution of certain practical problems involves finding the point of intersection of two straight lines. To see how such a problem may be solved algebraically, suppose we are given two straight lines L1 and L 2 with equations y  m1x  b1

L1

and y  m2x  b2

(where m1, b1, m2, and b2 are constants) that intersect at the point P(x0, y0) (Figure 38). The point P(x0, y0) lies on the line L1 and so satisfies the equation y  m1x  b1. It also lies on the line L2 and so satisfies the equation y  m2x  b2. Therefore, to find the point of intersection P(x0, y0) of the lines L1 and L2, we solve the system composed of the two equations

P(x0, y0) x L2

y  m1x  b1

FIGURE 38 L1 and L2 intersect at the point P(x0, y0).

and y  m2x  b2

for x and y. EXAMPLE 3 Find the point of intersection of the straight lines that have equations y  x  1 and y  2x  4.

y

y = – 2x + 4

We solve the given simultaneous equations. Substituting the value y as given in the first equation into the second, we obtain

Solution

L1

L2 5

y=x+1

x  1  2x  4 3x  3 x1

(1, 2)

–5

5

FIGURE 39

x

Substituting this value of x into either one of the given equations yields y  2. Therefore, the required point of intersection is (1, 2) (Figure 39).

The point of intersection of L1 and L2 is (1, 2).

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the straight lines L1 and L2 with equations y  3x  2 and y  2x  3, respectively, on the same set of axes in the standard viewing window. Then use TRACE and ZOOM to find the point of intersection of L1 and L2. Repeat using the “intersection” function of your graphing utility. 2. Find the point of intersection of L1 and L2 algebraically. 3. Comment on the effectiveness of each method.

114

2 FUNCTIONS AND THEIR GRAPHS

We now turn to some applications involving the intersections of pairs of straight lines.

Break-Even Analysis Consider a firm with (linear) cost function C(x), revenue function R(x), and profit function P(x) given by C1x2  cx  F R1x2  sx P1x2  R1x2  C1x2  1s  c2x  F

where c denotes the unit cost of production, s the selling price per unit, F the fixed cost incurred by the firm, and x the level of production and sales. The level of production at which the firm neither makes a profit nor sustains a loss is called the breakeven level of operation and may be determined by solving the equations y  C(x) and y  R(x) simultaneously. At the level of production x0, the profit is zero and so

y

y = R(x)

P1x0 2  R1x0 2  C1x0 2  0 R1x0 2  C1x0 2

Profit P0(x 0, y0) y = C(x) Loss x

FIGURE 40 P0 is the break-even point.

The point P0(x0, y0), the solution of the simultaneous equations y  R(x) and y  C(x), is referred to as the break-even point; the number x0 and the number y0 are called the break-even quantity and the break-even revenue, respectively. Geometrically, the break-even point P0(x0, y0) is just the point of intersection of the straight lines representing the cost and revenue functions, respectively. This follows because P0(x0, y0), being the solution of the simultaneous equations y  R(x) and y  C(x), must lie on both these lines simultaneously (Figure 40). Note that if x x0, then R(x) C(x) so that P(x)  R(x)  C(x) 0, and thus the firm sustains a loss at this level of production. On the other hand, if x  x0, then P(x)  0 and the firm operates at a profitable level. APPLIED EXAMPLE 4 Break-Even Level Prescott manufactures its products at a cost of $4 per unit and sells them for $10 per unit. If the firm’s fixed cost is $12,000 per month, determine the firm’s break-even point. The cost function C and the revenue function R are given by C(x)  4x  12,000 and R(x)  10x, respectively (Figure 41). Setting R(x)  C(x), we obtain

Thousands of dollars

y

Solution R(x) = 10x

30 20

C(x) = 4x + 12,000

10

Substituting this value of x into R(x)  10x gives x 1 2 3 4 Units of a thousand

FIGURE 41

10x  4x  12,000 6x  12,000 x  2000

The point at which R(x)  C(x) is the break-even point.

R(2000)  (10)(2000)  20,000

So, for a break-even operation, the firm should manufacture 2000 units of its product, resulting in a break-even revenue of $20,000 per month. APPLIED EXAMPLE 5 Break-Even Analysis Using the data given in Example 4, answer the following questions: a. What is the loss sustained by the firm if only 1500 units are produced and sold each month? b. What is the profit if 3000 units are produced and sold each month? c. How many units should the firm produce in order to realize a minimum monthly profit of $9000?

2.5 LINEAR FUNCTIONS

PORTFOLIO

115

Esteban Silva

R

egimen is a retail shop and online merchant of high-end men’s grooming products, a small business venture under my development. I came up with this concept in order to fill the growing demand for men’s grooming products from both graying baby boomers wanting to retain their competitive edge and young men who are increasingly accepting the idea that it is essential to be well styled and well groomed. The currently $3.5 billion a year men’s grooming market is ever-expanding and there is tremendous opportunity for Regimen to take advantage of this untapped potential. In the initial stages of this business venture I have relied on math to calculate the amount of capital needed to launch and sustain the business until it becomes profitable. Using spreadsheets I input projected sales figures and estimated monthly expenses to formulate if it is possible to realistically meet targets and achieve break-even in a timely manner. With assistance from a professional interior designer, I have drawn up plans which include space acqui-

Solution

sition, contracting, and construction costs in order to budget for build-out expenses. I have teamed up with Yahoo! Small Business Solutions and devised an online advertising strategy which allows me to reach out to the niche customers my company’s products are geared towards. Using a sponsored search method of advertising I pre-determine how much I am willing to spend for each combination of keywords which drive traffic onto my website via Yahoo! I can track on a daily basis the number of matches each combination of keywords are receiving and, therefore, determine if any of them need to be altered. It’s very important that I analyze these figures frequently so that I can redirect the limited marketing resources of this start-up company into the most effective channels available. Thankfully, the applied mathematics techniques I learned in college have helped me live the dream of owning my own business and being my own boss.

The profit function P is given by the rule P1x 2  R1x2  C1x2  10x  14x  12,0002  6x  12,000

a. If 1500 units are produced and sold each month, we have P(1500)  6(1500)  12,000  3000

so the firm will sustain a loss of $3000 per month. b. If 3000 units are produced and sold each month, we have P(3000)  6(3000)  12,000  6000

or a monthly profit of $6000. c. Substituting 9000 for P(x) in the equation P(x)  6x  12,000, we obtain 9000  6x  12,000 6x  21,000 x  3500

Thus, the firm should produce at least 3500 units in order to realize a $9000 minimum monthly profit. APPLIED EXAMPLE 6 Decision Analysis The management of Robertson Controls must decide between two manufacturing processes for its model C electronic thermostat. The monthly cost of the first process is given by C1(x)  20x  10,000 dollars, where x is the number of thermostats

© PSL Images/Alamy

TITLE Owner INSTITUTION Regimen

116

2 FUNCTIONS AND THEIR GRAPHS

produced; the monthly cost of the second process is given by C2(x)  10x  30,000 dollars. If the projected monthly sales are 800 thermostats at a unit price of $40, which process should management choose in order to maximize the company’s profit? Solution The break-even level of operation using the first process is obtained by solving the equation

40x  20x  10,000 20x  10,000 x  500

giving an output of 500 units. Next, we solve the equation 40x  10x  30,000 30x  30,000 x  1000

giving an output of 1000 units for a break-even operation using the second process. Since the projected sales are 800 units, we conclude that management should choose the first process, which will give the firm a profit. APPLIED EXAMPLE 7 Decision Analysis Referring to Example 6, decide which process Robertson’s management should choose if the projected monthly sales are (a) 1500 units and (b) 3000 units. In both cases, the production is past the break-even level. Since the revenue is the same regardless of which process is employed, the decision will be based on how much each process costs. Solution

a. If x  1500, then

C1 1x2  1202 115002  10,000  40,000 C2 1x2  1102 115002  30,000  45,000

Hence, management should choose the first process. b. If x  3000, then

C1 1x2  1202 130002  10,000  70,000

C2 1x2  1102 130002  30,000  60,000

In this case, management should choose the second process.

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the straight lines L1 and L2 with equations y  2x  1 and y  2.1x  3, respectively, on the same set of axes, using the standard viewing window. Do the lines appear to intersect? 2. Plot the straight lines L1 and L2, using the viewing window [100, 100]  [100, 100]. Do the lines appear to intersect? Can you find the point of intersection using TRACE and ZOOM? Using the “intersection” function of your graphing utility? 3. Find the point of intersection of L1 and L2 algebraically. 4. Comment on the effectiveness of the solution methods in parts 2 and 3.

2.5 LINEAR FUNCTIONS

117

2.5 Self-Check Exercises A manufacturer has a monthly fixed cost of $60,000 and a production cost of $10 for each unit produced. The product sells for $15/unit. 1. What is the cost function? 2. What is the revenue function?

3. What is the profit function? 4. Compute the profit (loss) corresponding to production levels of 10,000 and 14,000 units/month. Solutions to Self-Check Exercises 2.5 can be found on page 120.

2.5 Concept Questions 1. a. What is a linear function? Give an example. b. What is the domain of a linear function? The range? c. What is the graph of a linear function? 2. What is the general form of a linear cost function? A linear revenue function? A linear profit function?

3. Explain the meaning of each term: a. Break-even point b. Break-even quantity c. Break-even revenue

2.5 Exercises In Exercises 1–10, determine whether the equation defines y as a linear function of x. If so, write it in the form y  mx  b.

1. 2x  3y  6

2. 2x  4y  7

3. x  2y  4

4. 2x  3y  8

5. 2x  4y  9  0

6. 3x  6y  7  0

7. 2 x 2  8y  4  0

8. 31x  4y  0

9. 2x  3y  8  0 2

10. 2x  1y  4  0

11. A manufacturer has a monthly fixed cost of $40,000 and a production cost of $8 for each unit produced. The product sells for $12/unit. a. What is the cost function? b. What is the revenue function? c. What is the profit function? d. Compute the profit (loss) corresponding to production levels of 8000 and 12,000 units. 12. A manufacturer has a monthly fixed cost of $100,000 and a production cost of $14 for each unit produced. The product sells for $20/unit. a. What is the cost function? b. What is the revenue function? c. What is the profit function? d. Compute the profit (loss) corresponding to production levels of 12,000 and 20,000 units. 13. Find the constants m and b in the linear function f(x)  mx  b such that f (0)  2 and f (3)  1. 14. Find the constants m and b in the linear function f(x)  mx  b such that f (2)  4 and the straight line represented by f has slope 1.

In Exercises 15–20, find the point of intersection of each pair of straight lines.

15. y  3 x  4 y  2x  14

16.

y  4x  7 y  5x  10

17. 2x  3y  6 3x  6y  16

18.

2x  4y  11 5x  3y  5

19.

1 x5 4 3 2x  y  1 2 y

20. y 

2 x4 3

x  3y  3  0

In Exercises 21–24, find the break-even point for the firm whose cost function C and revenue function R are given.

21. C(x)  5x  10,000; R(x)  15x 22. C(x)  15x  12,000; R(x)  21x 23. C(x)  0.2x  120; R(x)  0.4x 24. C(x)  150x  20,000; R(x)  270 x 25. LINEAR DEPRECIATION An office building worth $1 million when completed in 2005 is being depreciated linearly over 50 yr. What will be the book value of the building in 2010? In 2015? (Assume the scrap value is $0.) 26. LINEAR DEPRECIATION An automobile purchased for use by the manager of a firm at a price of $24,000 is to be depreciated using the straight-line method over 5 yr. What will be the book value of the automobile at the end of 3 yr? (Assume the scrap value is $0.)

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1 STRAIGHT LINES AND LINEAR FUNCTIONS

27. SOCIAL SECURITY BENEFITS Social Security recipients receive an automatic cost-of-living adjustment (COLA) once each year. Their monthly benefit is increased by the same percentage that consumer prices have increased during the preceding year. Suppose consumer prices have increased by 5.3% during the preceding year. a. Express the adjusted monthly benefit of a Social Security recipient as a function of his or her current monthly benefit. b. If Carlos Garcia’s monthly Social Security benefit is now $1020, what will be his adjusted monthly benefit? 28. PROFIT FUNCTIONS AutoTime, a manufacturer of 24-hr variable timers, has a monthly fixed cost of $48,000 and a production cost of $8 for each timer manufactured. The timers sell for $14 each. a. What is the cost function? b. What is the revenue function? c. What is the profit function? d. Compute the profit (loss) corresponding to production levels of 4000, 6000, and 10,000 timers, respectively. 29. PROFIT FUNCTIONS The management of TMI finds that the monthly fixed costs attributable to the production of their 100-watt light bulbs is $12,100.00. If the cost of producing each twin-pack of light bulbs is $.60 and each twin-pack sells for $1.15, find the company’s cost function, revenue function, and profit function. 30. LINEAR DEPRECIATION In 2005, National Textile installed a new machine in one of its factories at a cost of $250,000. The machine is depreciated linearly over 10 yr with a scrap value of $10,000. a. Find an expression for the machine’s book value in the t th year of use (0 t 10). b. Sketch the graph of the function of part (a). c. Find the machine’s book value in 2009. d. Find the rate at which the machine is being depreciated. 31. LINEAR DEPRECIATION A workcenter system purchased at a cost of $60,000 in 2007 has a scrap value of $12,000 at the end of 4 yr. If the straight-line method of depreciation is used, a. Find the rate of depreciation. b. Find the linear equation expressing the system’s book value at the end of t yr. c. Sketch the graph of the function of part (b). d. Find the system’s book value at the end of the third year. 32. LINEAR DEPRECIATION Suppose an asset has an original value of $C and is depreciated linearly over N yr with a scrap value of $S. Show that the asset’s book value at the end of the t th year is described by the function CS V1t 2  C  a bt N Hint: Find an equation of the straight line passing through the points (0, C) and (N, S). (Why?)

33. Rework Exercise 25 using the formula derived in Exercise 32. 34. Rework Exercise 26 using the formula derived in Exercise 32. 35. DRUG DOSAGES A method sometimes used by pediatricians to calculate the dosage of medicine for children is based on the child’s surface area. If a denotes the adult dosage (in milligrams) and if S is the child’s surface area (in square meters), then the child’s dosage is given by D1S 2 

Sa 1.7

a. Show that D is a linear function of S. Hint: Think of D as having the form D(S)  mS  b. What are the slope m and the y-intercept b?

b. If the adult dose of a drug is 500 mg, how much should a child whose surface area is 0.4 m2 receive? 36. DRUG DOSAGES Cowling’s rule is a method for calculating pediatric drug dosages. If a denotes the adult dosage (in milligrams) and if t is the child’s age (in years), then the child’s dosage is given by D 1t2  a

t1 ba 24

a. Show that D is a linear function of t. Hint: Think of D(t) as having the form D(t)  mt  b. What is the slope m and the y-intercept b?

b. If the adult dose of a drug is 500 mg, how much should a 4-yr-old child receive? 37. BROADBAND INTERNET HOUSEHOLDS The number of U.S. broadband Internet households stood at 20 million at the beginning of 2002 and was projected to grow at the rate of 6.5 million households per year for the next 8 yr. a. Find a linear function f (t) giving the projected number of U.S. broadband Internet households (in millions) in year t, where t  0 corresponds to the beginning of 2002. b. What is the projected number of U.S. broadband Internet households at the beginning of 2010? Source: Jupiter Research

38. DIAL-UP INTERNET HOUSEHOLDS The number of U.S. dialup Internet households stood at 42.5 million at the beginning of 2004 and was projected to decline at the rate of 3.9 million households per year for the next 6 yr. a. Find a linear function f giving the projected U.S. dial-up Internet households (in millions) in year t, where t  0 corresponds to the beginning of 2004. b. What is the projected number of U.S. dial-up Internet households at the beginning of 2010? Source: Strategy Analytics Inc.

39. CELSIUS AND FAHRENHEIT TEMPERATURES The relationship between temperature measured in the Celsius scale and the Fahrenheit scale is linear. The freezing point is 0°C and 32°F, and the boiling point is 100°C and 212°F.

2.5 LINEAR FUNCTIONS

a. Find an equation giving the relationship between the temperature F measured in the Fahrenheit scale and the temperature C measured in the Celsius scale. b. Find F as a function of C and use this formula to determine the temperature in Fahrenheit corresponding to a temperature of 20°C. c. Find C as a function of F and use this formula to determine the temperature in Celsius corresponding to a temperature of 70°F. 40. CRICKET CHIRPING AND TEMPERATURE Entomologists have discovered that a linear relationship exists between the rate of chirping of crickets of a certain species and the air temperature. When the temperature is 70°F, the crickets chirp at the rate of 120 chirps/min, and when the temperature is 80°F, they chirp at the rate of 160 chirps/min. a. Find an equation giving the relationship between the air temperature T and the number of chirps/min N of the crickets. b. Find N as a function of T and use this formula to determine the rate at which the crickets chirp when the temperature is 102°F. 41. BREAK-EVEN ANALYSIS AutoTime, a manufacturer of 24-hr variable timers, has a monthly fixed cost of $48,000 and a production cost of $8 for each timer manufactured. The units sell for $14 each. a. Sketch the graphs of the cost function and the revenue function and thereby find the break-even point graphically. b. Find the break-even point algebraically. c. Sketch the graph of the profit function. d. At what point does the graph of the profit function cross the x-axis? Interpret your result. 42. BREAK-EVEN ANALYSIS A division of Carter Enterprises produces “Personal Income Tax” diaries. Each diary sells for $8. The monthly fixed costs incurred by the division are $25,000, and the variable cost of producing each diary is $3. a. Find the break-even point for the division. b. What should be the level of sales in order for the division to realize a 15% profit over the cost of making the diaries? 43. BREAK-EVEN ANALYSIS A division of the Gibson Corporation manufactures bicycle pumps. Each pump sells for $9, and the variable cost of producing each unit is 40% of the selling price. The monthly fixed costs incurred by the division are $50,000. What is the break-even point for the division? 44. LEASING Ace Truck Leasing Company leases a certain size truck for $30/day and $.15/mi, whereas Acme Truck Leasing Company leases the same size truck for $25/day and $.20/mi. a. Find the functions describing the daily cost of leasing from each company. b. Sketch the graphs of the two functions on the same set of axes. c. If a customer plans to drive at most 70 mi, from which company should he rent a truck for a single day?

119

45. DECISION ANALYSIS A product may be made using machine I or machine II. The manufacturer estimates that the monthly fixed costs of using machine I are $18,000, whereas the monthly fixed costs of using machine II are $15,000. The variable costs of manufacturing 1 unit of the product using machine I and machine II are $15 and $20, respectively. The product sells for $50 each. a. Find the cost functions associated with using each machine. b. Sketch the graphs of the cost functions of part (a) and the revenue functions on the same set of axes. c. Which machine should management choose in order to maximize their profit if the projected sales are 450 units? 550 units? 650 units? d. What is the profit for each case in part (c)? 46. ANNUAL SALES The annual sales of Crimson Drug Store are expected to be given by S  2.3  0.4t million dollars t yr from now, whereas the annual sales of Cambridge Drug Store are expected to be given by S  1.2  0.6t million dollars t yr from now. When will Cambridge’s annual sales first surpass Crimson’s annual sales? 47. LCDs VERSUS CRTs The global shipments of traditional cathode-ray tube monitors (CRTs) is approximated by the equation y  12t  88

(0 t 3)

where y is measured in millions and t in years, with t  0 corresponding to the beginning of 2001. The equation y  18t  13.4

(0 t 3)

gives the approximate number (in millions) of liquid crystal displays (LCDs) over the same period. When did the global shipments of LCDs first overtake the global shipments of CRTs? Source: International Data Corporation

48. DIGITAL VERSUS FILM CAMERAS The sales of digital cameras (in millions of units) in year t is given by the function f(t)  3.05t  6.85

(0 t 3)

where t  0 corresponds to 2001. Over that same period, the sales of film cameras (in millions of units) is given by t(t)  1.85t  16.58

(0 t 3)

a. Show that more film cameras than digital cameras were sold in 2001. b. When did the sales of digital cameras first exceed those of film cameras? Source: Popular Science

49. U.S. FINANCIAL TRANSACTIONS The percentage of U.S. transactions by check between the beginning of 2001 (t  0) and the beginning of 2010 (t  9) is projected to be f 1t2  

11 t  43 9

10 t 92

whereas the percentage of transactions done electronically

120

1 STRAIGHT LINES AND LINEAR FUNCTIONS

during the same period is projected to be t1t 2 

11 t  23 3

10 t 9 2

a. Sketch the graphs of f and t on the same set of axes. b. Find the time when transactions done electronically first exceeded those done by check. Source: Foreign Policy

50. BROADBAND VERSUS DIAL-UP The number of U.S. broadband Internet households (in millions) between the beginning of 2004 (t  0) and the beginning of 2008 (t  4) was estimated to be f (t)  6.5t  33

(0 t 4)

Over the same period, the number of U.S. dial-up Internet households (in millions) was estimated to be t(t)  3.9t  42.5

a. Sketch the graphs of f and t on the same set of axes. b. Solve the equation f (t)  t(t) and interpret your result. Source: Strategic Analytics Inc.

In Exercises 51 and 52, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

51. If the book value V at the end of the year t of an asset being depreciated linearly is given by V  at  b where a and b are positive constants, then the rate of depreciation of the asset is a units per year. 52. Suppose C(x)  cx  F and R(x)  sx are the cost and revenue functions of a certain firm. Then, the firm is operating at a break-even level of production if its level of production is F/(s  c).

(0 t 4)

2.5 Solutions to Self-Check Exercises Let x denote the number of units produced and sold. Then 1. C(x)  10x  60,000 2. R(x)  15x 3. P(x)  R(x)  C(x)  15x  (10x  60,000)  5x  60,000

USING

TECHNOLOGY

4. P(10,000)  5(10,000)  60,000  10,000 or a loss of $10,000. P(14,000)  5(14,000)  60,000  10,000 or a profit of $10,000.

Linear Functions Graphing Utility

A graphing utility can be used to find the value of a function f at a given point with minimal effort. However, to find the value of y for a given value of x in a linear equation such as Ax  By  C  0, the equation must first be cast in the slope-intercept form y  mx  b, thus revealing the desired rule f(x)  mx  b for y as a function of x. EXAMPLE 1 Consider the equation 2x  5y  7. a. Plot the straight line with the given equation in the standard viewing window. b. Find the value of y when x  2 and verify your result by direct computation. c. Find the value of y when x  1.732. Solution FIGURE T1

The straight line 2x  5y  7 in the standard viewing window

a. The straight line with equation 2x  5y  7 or, equivalently, y  25 x  75 in the standard viewing window is shown in Figure T1.

2.5 LINEAR FUNCTIONS

121

b. Using the evaluation function of the graphing utility and the value of 2 for x, we find y  0.6. This result is verified by computing 2 7 4 7 3 y   122       0.6 5 5 5 5 5

when x  2. c. Once again using the evaluation function of the graphing utility, this time with the value 1.732 for x, we find y  0.7072. When evaluating f (x) at x  a, remember that the number a must lie between xMin and xMax. APPLIED EXAMPLE 2 Market for Cholesterol-Reducing Drugs In a study conducted in early 2000, experts projected a rise in the market for cholesterol-reducing drugs. The U.S. market (in billions of dollars) for such drugs from 1999 through 2004 is approximated by M(t)  1.95t  12.19

where t is measured in years, with t  0 corresponding to 1999. a. Plot the graph of the function M in the viewing window [0, 5]  [0, 25]. b. Assuming that the projection held and the trend continued, what was the market for cholesterol-reducing drugs in 2005 (t  6)? c. What was the rate of increase of the market for cholesterol-reducing drugs over the period in question? Source: S. G. Cowen

Solution

a. The graph of M is shown in Figure T2.

FIGURE T2 The graph of M in the viewing window [0, 5]  [0, 25]

b. The projected market in 2005 for cholesterol-reducing drugs was approximately M(6)  1.95(6)  12.19  23.89

or $23.89 billion. c. The function M is linear; hence, we see that the rate of increase of the market for cholesterol-reducing drugs is given by the slope of the straight line represented by M, which is approximately $1.95 billion per year. Excel

Excel can be used to find the value of a function at a given value with minimal effort. However, to find the value of y for a given value of x in a linear equation such as Ax  By  C  0, the equation must first be cast in the slope-intercept form y  mx  b, thus revealing the desired rule f (x)  mx  b for y as a function of x. (continued)

122

1 STRAIGHT LINES AND LINEAR FUNCTIONS

EXAMPLE 3 Consider the equation 2x  5y  7. a. Find the value of y for x  0, 5, and 10. b. Plot the straight line with the given equation over the interval [0, 10]. Solution A 1 2 3 4

a. Since this is a linear equation, we first cast the equation in slope-intercept form:

B

x

2 7 y x 5 5

y 0 5 10

1.4 −0.6 −2.6

FIGURE T3 Table of values for x and y

Next, we create a table of values (Figure T3), following the same procedure outlined in Example 3, pages 85–86. In this case we use the formula =(—2/5)*A2+7/5 for the y-values. b. Following the procedure outlined in Example 3, we obtain the graph shown in Figure T4.

y

y = −(2/5)x + 7/5

FIGURE T4

The graph of y  25 x  75 over the interval [0, 10]

2 1.5 1 0.5 0 −0.5 0 −1 −1.5 −2 −2.5 −3

2

4

6

8

10

12

x

APPLIED EXAMPLE 4 Market for Cholesterol-Reducing Drugs In a study conducted in early 2000, experts projected a rise in the market for cholesterol-reducing drugs. The U.S. market (in billions of dollars) for such drugs from 1999 through 2004 is approximated by M(t)  1.95t  12.19

where t is measured in years, with t  0 corresponding to 1999. a. Plot the graph of the function M over the interval [0, 6]. b. Assuming that the projection held and the trend continued, what was the market for cholesterol-reducing drugs in 2005 (t  6)? c. What was the rate of increase of the market for cholesterol-reducing drugs over the period in question? Source: S. G. Cowen

Solution

a. Following the instructions given in Example 3, pages 85–86, we obtain the spreadsheet and graph shown in Figure T5. [Note: We have made the appropriate entries for the title and x- and y-axis labels.]

Note: Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

123

2.6 QUADRATIC FUNCTIONS

A 1

B

t

M(t)

2

0

12.19

FIGURE T5

3

5

21.94

(a) The table of values for t and M(t) and (b) the graph showing the demand for cholesterol-reducing drugs

4

6

23.89

(a)

M(t) in billions of dollars

M(t)  1.95t  12.19 30 25 20 15 10 5 0 0

2

4 t in years

6

8

(b)

b. From the table of values, we see that M(6)  1.95(6)  12.19  23.89

or $23.89 billion. c. The function M is linear; hence, we see that the rate of increase of the market for cholesterol-reducing drugs is given by the slope of the straight line represented by M, which is approximately $1.95 billion per year.

TECHNOLOGY EXERCISES Find the value of y corresponding to the given value of x.

5. 22.1x  18.2y  400  0; x  12.1

1. 3.1x  2.4y  12  0; x  2.1

6. 17.1x  24.31y  512  0; x  8.2

2. 1.2x  3.2y  8.2  0; x  1.2

7. 2.8x  1.41y  2.64; x  0.3

3. 2.8x  4.2y  16.3; x  1.5

8. 0.8x  3.2y  4.3; x  0.4

4. 1.8x  3.2y  6.3  0; x  2.1

2.6 Quadratic Functions Quadratic Functions A quadratic function is one of the form f(x)  ax 2  bx  c

y 12 (–3, 10)

10

(3, 10)

8 (– 2, 5) (–1, 2)

6 4

(2, 5) (1, 2) x

–4 FIGURE 42

4

The graph of f(x)  x 2  1 is a parabola.

where a, b, and c are constants and a  0. For example, the function f(x)  2x 2  3x  4 is quadratic (here, a  2, b  3, and c  4). Also, the function f(x)  x 2  1 of Example 6, Section 2.3, is quadratic (here a  1, b  0, and c  1). Its graph illustrates the general shape of the graph of a quadratic function, which is called a parabola (Figure 42). In general, the graph of a quadratic function is a parabola that opens upward or downward (Figure 43). Furthermore, the parabola is symmetric with respect to a vertical line called the axis of symmetry (shown dotted in Figure 43). This line also passes through the lowest point or the highest point of the parabola. The point of intersection of the parabola with its axis of symmetry is called the vertex of the parabola.

124

2 FUNCTIONS AND THEIR GRAPHS y

y

Vertex

Vertex

FIGURE 43 Graphs of quadratic functions are parabolas.

Axis of symmetry

Axis of symmetry x

x

We can use these properties to help us sketch the graph of a quadratic function. For example, suppose we want to sketch the graph of f(x)  2x 2  4x  1

If we complete the square in x, we obtain f(x)  2(x 2  2x)  1

Factor out the coefficient of x 2 from the first two terms.

Adding and subtracting 2 앗 앗

 2[x 2  2x  (1)2]  1  2

Because of the 2 outside the brackets, we have added 2(1) and must therefore subtract 2.

 2(x  1)2  1

Factor the terms within the brackets.

Observe that the first term, 2(x  1) , is nonnegative. In fact, it is equal to zero when x  1 and is greater than zero if x  1. Consequently, we see that f (x)  1 for all values of x. This tells us that the vertex (in this case, the lowest point) of the parabola is the point (1, 1). The axis of symmetry of the parabola is the vertical line x  1. Finally, plotting the vertex and a few additional points on either side of the axes of symmetry of the parabola, we obtain the graph shown in Figure 44. 2

y 8 6 4

x

y

1 0 2 3

7 1 1 7

2

FIGURE 44

x

2

2 (1, 1)

The graph of f(x)  2x 2  4x  1

4

The x-intercepts of f, the x-coordinates of the points at which the parabola intersects the x-axis, can be found by solving the equation f (x)  0. Here we use the quadratic formula with a  2, b  4, and c  1 to find that x

14 2 214 2 2  412 2 11 2 212 2



4 28 4 2 22 22  1 4 4 2

Therefore, the x-intercepts are 1  22/2  1.71 and 1  22/2  0.29. The y-intercept of f (obtained by setting x  0) is f (0)  1. The technique that we used to analyze f(x)  2 x 2  4x  1 can be used to study the general quadratic function f(x)  ax 2  bx  c

(a  0)

If we complete the square in x, we find f(x)  a a x 

b 2 4ac  b 2 b  2a 4a

See Exercise 56.

2.6 QUADRATIC FUNCTIONS

125

From this equation we obtain the following properties of the quadratic function f.

Properties of the Quadratic Function f (x)  ax 2  bx  c

(a  0)

1. The domain of f is the set of all real numbers, and the graph of f is a parabola. 2. If a  0, the parabola opens upward, and if a 0, it opens downward. b b 3. The vertex of the parabola is a  , f a  b b . 2a 2a b 4. The axis of symmetry of the parabola is x   . 2a 5. The x-intercepts (if any) are found by solving f (x)  0. The y-intercept is f(0)  c.

EXAMPLE 1 Given the quadratic function f (x)  2x 2  5x  2 a. Find the vertex of the parabola. b. Find the x-intercepts (if any) of the parabola. c. Sketch the parabola. Solution

a. Comparing f (x)  2x 2  5x  2 with the general form of the quadratic equation, we find that a  2, b  5, and c  2. Therefore, the x-coordinate of the vertex of the parabola is 

b 5 5   2a 2122 4

Next, to find the y-coordinate of the vertex, we evaluate f at x  54, obtaining 5 5 5 2 f a b  2 a b  5 a b  2 4 4 4 25 25   2 8 4 9  8

2 a 

25 25 b  16 8

25 50 16 9    8 8 8 8

b. To find the x-intercepts of the parabola, we solve the equation 2x 2  5x  2  0

using the quadratic formula with a  2, b  5, and c  2. We find x

5 225  4122 122 2122



5 29 4



5 3 4



1 or 2 2

Thus, the x-intercepts of the parabola are 12 and 2.

126

2 FUNCTIONS AND THEIR GRAPHS

c. Since a  2 0, the parabola opens downward. The vertex of the parabola 1 54, 98 2 is therefore the highest point on the curve. The parabola crosses the x-axis at the points 1 12, 0 2 and (2, 0). Setting x  0 gives 2 as the y-intercept of the curve. Finally, using this information, we sketch the parabola shown in Figure 45.

y 2 Vertex 1

( 54 , 98 ) x-intercepts

1 2

APPLIED EXAMPLE 2 Effect of Advertising on Profit The quarterly profit (in thousands of dollars) of Cunningham Realty is given by

x 1

2

1 y-intercept

1 P(x)   x 2  7x  30 3

2 FIGURE 45

The graph of f(x)  2x 2  5x  2

(0 x 50)

where x (in thousands of dollars) is the amount of money Cunningham spends on advertising per quarter. Find the amount of money Cunningham should spend on advertising in order to realize a maximum quarterly profit. What is the maximum quarterly profit realizable by Cunningham? Solution The profit function P is a quadratic function, and so its graph is a parabola. Furthermore, the coefficient of x 2 is a  13 0, and so the parabola opens downward. The x-coordinate of the vertex of the parabola is



b 7 21   10.5  1 2a 2 213 2

The corresponding y-coordinate is fa

21 1 21 2 21 267 b   a b  7 a b  30   66.75 2 3 2 2 4

Therefore, the vertex of the parabola is 1 212, 267 4 2 . Since the parabola opens downward, the vertex of the parabola is the highest point on the parabola. Accordingly, the y-coordinate of the vertex gives the maximum value of P. This implies that the maximum quarterly profit of $66,750 [remember that P(x) is measured in thousands of dollars] is realized if Cunningham spends $10,500 per quarter on advertising. The graph of P is shown in Figure 46.

Thousands of dollars

P

FIGURE 46 The graph of the profit function P(x)  13 x 2  7x  30

70 60 50 40 30 20 10

5 10

x 5

10 15 20 Thousands of dollars

25

Demand and Supply Curves p

p = f (x )

x FIGURE 47 A demand curve

In a free-market economy, consumer demand for a particular commodity depends on the commodity’s unit price. A demand equation expresses the relationship between the unit price and the quantity demanded. The graph of a demand equation is called a demand curve. In general, the quantity demanded of a commodity decreases as the commodity’s unit price increases, and vice versa. Accordingly, a demand function, defined by p  f (x), where p measures the unit price and x measures the number of units of the commodity in question, is generally characterized as a decreasing function of x; that is, p  f(x) decreases as x increases. Since both x and p assume only nonnegative values, the demand curve is that part of the graph of f(x) that lies in the first quadrant (Figure 47).

2.6 QUADRATIC FUNCTIONS

127

APPLIED EXAMPLE 3 Demand for Bluetooth Headsets The demand function for a certain brand of bluetooth wireless headsets is given by p  d(x)  0.025x 2  0.5x  60 p ($)

60

where p is the wholesale unit price in dollars and x is the quantity demanded each month, measured in units of a thousand. Sketch the corresponding demand curve. Above what price will there be no demand? What is the maximum quantity demanded per month?

p  d(x)

40 20 x

60 40 20

20

40

Solution The given function is quadratic, and its graph may be sketched using the methods just developed (Figure 48). The p-intercept, 60, gives the wholesale unit price above which there will be no demand. To obtain the maximum quantity demanded, set p  0, which gives

0.025x2  0.5x  60  0 x2  20x  2400  0

Units of a thousand FIGURE 48

The demand curve p  d(x)

Upon multiplying both sides of the equation by 40

(x  60)(x  40)  0

That is, x  60 or x  40. Since x must be nonnegative, we reject the root x  60. Thus, the maximum number of headsets demanded per month is 40,000. p

p = f (x)

x FIGURE 49 A supply curve

In a competitive market, a relationship also exists between the unit price of a commodity and the commodity’s availability in the market. In general, an increase in the commodity’s unit price induces the producer to increase the supply of the commodity. Conversely, a decrease in the unit price generally leads to a drop in the supply. The equation that expresses the relation between the unit price and the quantity supplied is called a supply equation, and its graph is called a supply curve. A supply function, defined by p  f (x), is generally characterized as an increasing function of x; that is, p  f (x) increases as x increases. Since both x and p assume only nonnegative values, the supply curve is that part of the graph of f (x) that lies in the first quadrant (Figure 49). APPLIED EXAMPLE 4 Supply of Bluetooth Headsets The supply function for a certain brand of bluetooth wireless headsets is given by p  s(x)  0.02x 2  0.6x  20

where p is the unit wholesale price in dollars and x stands for the quantity (in units of a thousand) that will be made available in the market by the supplier. Sketch the corresponding supply curve. What is the lowest price at which the supplier will make the headsets available in the market? A sketch of the supply curve appears in Figure 50. The p-intercept, 20, gives the lowest price at which the supplier will make the headsets available in the market.

Solution

p ($) 60 40

p  s(x)

20

FIGURE 50 A supply curve

80 60 40 20 20 Units of a thousand

x 30

128

2 FUNCTIONS AND THEIR GRAPHS

PORTFOLIO

Deb Farace

W

orking for the national accounts division for PepsiCo Beverages & Foods, I need to understand applied mathematics in order to control the variables associated with making a profit, manufacturing, production, and most importantly selling our products to mass club channels. Examples of these large, “quality product at great value” outlets are Wal*Mart, Costco and Target. The types of products I handle include Gatorade, Tropicana, and Quaker foods. Our studies show that the grocery store channels’ sales are flattening or declining as a whole in lieu of large, national outlets like the above. So in order to maximize growth in this segment of our business, I meet with regional buying offices of these chains and discuss various packaging, pricing, product, promotional and shipping options so that we can successfully compete in the market. A number of factors must be taken into consideration in order to meet my company’s financial forecasts. Precision using mathematical models is key here, since so many vari-

ables can impact last-minute decision making. Extended variables of supply-and-demand include time of year, competitive landscape, special coupon distribution and other promotions, selling cycles and holidays, size of the outlets, and yes—even the weather. For example, it’s natural to assume that when it’s hot outside people will buy more thirst-quenching products like Gatorade. But since our business is so precise, we need to understand mathematically how the weather affects sales. A mathematical model developed by Gatorade analyzes long-term data that impact sales by geographic market due to the weather. Its findings include exponentially increased sales of Gatorade for each degree above 90 degrees. I share our mathematical analysis like this study with buyers and negotiate larger orders based on up-to-theminute weather forecasts. The result: increased sales of product based on math.

© kolvenbach/Alamy

TITLE Sr. National Accounts Manager INSTITUTION PepsiCo Beverages & Foods

Market Equilibrium p Demand curve

p0

Supply curve

(x0 , p0)

x0 FIGURE 51 Market equilibrium corresponds to (x0, p0), the point at which the supply and demand curves intersect.

x

Under pure competition the price of a commodity will eventually settle at a level dictated by the following condition: the supply of the commodity will be equal to the demand for it. If the price is too high, the consumer will not buy, and if the price is too low, the supplier will not produce. Market equilibrium prevails when the quantity produced is equal to the quantity demanded. The quantity produced at market equilibrium is called the equilibrium quantity, and the corresponding price is called the equilibrium price. Market equilibrium corresponds to the point at which the demand curve and the supply curve intersect. In Figure 51, x0 represents the equilibrium quantity and p0 the equilibrium price. The point (x0, p0) lies on the supply curve and therefore satisfies the supply equation. At the same time, it also lies on the demand curve and therefore satisfies the demand equation. Thus, to find the point (x0, p0), and hence the equilibrium quantity and price, we solve the demand and supply equations simultaneously for x and p. For meaningful solutions, x and p must both be positive. APPLIED EXAMPLE 5 Market Equilibrium Refer to Examples 3 and 4. The demand function for a certain brand of bluetooth wireless headsets is given by p  d(x)  0.025x 2  0.5x  60

and the corresponding supply function is given by p  s(x)  0.02x 2  0.6x  20

where p is expressed in dollars and x is measured in units of a thousand. Find the equilibrium quantity and price.

2.6 QUADRATIC FUNCTIONS

Solution

129

We solve the following system of equations: p  0.025x 2  0.5x  60 p  0.02x 2  0.6x  20

Substituting the first equation into the second yields 0.025x 2  0.5x  60  0.02x 2  0.6x  20

which is equivalent to p ($)

0.045x 2  1.1x  40  0 45x 2  1100x  40,000  0 9x 2  220x  8000  0 (9x  400)(x  20)  0

80 70 60 50 40 30 20 10 10 20 30 Units of a thousand

40

x

Divide by 5.

400 Thus, x  400 9 or x  20. Since x must be nonnegative, the root x   9 is rejected. Therefore, the equilibrium quantity is 20,000 headsets. The equilibrium price is given by

p  0.02(20)2  0.6(20)  20  40

FIGURE 52 The supply curve and the demand curve intersect at the point (20, 40).

Multiply by 1000.

or $40 per headset (Figure 52).

2.6 Self-Check Exercises Given the quadratic function

2. Find the x-intercepts (if any) of the parabola. 3. Sketch the parabola.

f(x)  2 x  3x  3 2

Solutions to Self-Check Exercises 2.6 can be found on page 132.

1. Find the vertex of the parabola.

2.6 Concept Questions 1. Consider the quadratic function f(x)  ax2  bx  c (a  0). a. What is the domain of f ? b. What can you say about the parabola if a  0? c. What is the vertex of the parabola in terms of a and b? d. What is the axis of symmetry of the parabola?

2. a. What is a demand function? A supply function? b. What is market equilibrium? c. What are the equilibrium quantity and equilibrium price? How do you determine these quantities?

2.6 Exercises In Exercises 1–18, find the vertex, the x-intercepts (if any), and sketch the parabola.

11. f(x)  x 2  4

12. f(x)  2x 2  3

13. f(x)  16  x2

14. f(x)  5  x2

1. f(x)  x 2  x  6

2. f(x)  3x 2  5x  2

3. f(x)  x 2  4x  4

4. f(x)  x 2  6x  9

15. f(x) 

5. f(x)  x 2  5x  6

6. f(x)  4x 2  4x  3

17. f(x)  1.2x2  3.2x  1.2

7. f(x)  3x 2  5x  1

8. f(x)  2x 2  6x  3

18. f(x)  2.3x2  4.1x  3

9. f(x)  2x  3x  3 2

10. f(x)  3x  4x  2 2

3 2 x  2x  2 8

16. f(x) 

3 2 1 x  x1 4 2

130

2 FUNCTIONS AND THEIR GRAPHS

In Exercises 19–24, find the points of intersection of the graphs of the functions.

19. f (x)  x 2  4; t(x)  x  2 20. f (x)  x 2  5x  6; t(x) 

h(t)  16t 2  64t  80

3 1 x 2 2

a. Sketch the graph of h. b. At what time does the stone reach the highest point?

21. f (x)  x 2  2 x  6; t(x)  x 2  6 22. f (x)  x 2  2 x  2; t(x)  x 2  x  1 23. f (x)  2x 2  5x  8; t(x)  3x 2  x  5 24. f (x)  0.2 x 2  1.2 x  4; t(x)  0.3x 2  0.7x  8.2 For the demand equations in Exercises 25 and 26, where x represents the quantity demanded in units of a thousand and p is the unit price in dollars, (a) sketch the demand curve and (b) determine the quantity demanded when the unit price is set at $p.

25. p  x 2  36; p  11

26. p  x2  16; p  7

For the supply equations in Exercises 27 and 28, where x is the quantity supplied in units of a thousand and p is the unit price in dollars, (a) sketch the supply curve and (b) determine the price at which the supplier will make 2000 units of the commodity available in the market.

27. p  2x 2  18

28. p  x 2  16x  40

In Exercises 29–32, for each pair of supply and demand equations where x represents the quantity demanded in units of a thousand and p the unit price in dollars, find the equilibrium quantity and the equilibrium price.

30. p  x 2  2x  100 and p  8x  25 31. 11p  3x  66  0 and 2p 2  p  x  10 32. p  60  2x 2 and p  x 2  9x  30 33. CANCER SURVIVORS The number of living Americans who have had a cancer diagnosis has increased drastically since 1971. In part, this is due to more testing for cancer and better treatment for some cancers. In part, it is because the population is older, and cancer is largely a disease of the elderly. The number of cancer survivors (in millions) between 1975 (t  0) and 2000 (t  25) is approximately (0 t 25)

a. How many living Americans had a cancer diagnosis in 1975? In 2000? b. Assuming the trend continued, how many cancer survivors were there in 2005? Source: National Cancer Institute

34. PREVALENCE OF ALZHEIMER’S PATIENTS Based on a study conducted in 1997, the percent of the U.S. population by age afflicted with Alzheimer’s disease is given by the function P(x)  0.0726x 2  0.7902x  4.9623

(0 x 25)

where x is measured in years, with x  0 corresponding to age 65. What percent of the U.S. population at age 65 is expected to have Alzheimer’s disease? At age 90? Source: Alzheimer’s Association

What is the stone’s maximum height from the ground? 36. MAXIMIZING PROFIT Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit realized from renting out x apartments is given by P(x)  10 x 2  1760 x  50,000

dollars. How many units should be rented out in order to maximize the monthly rental profit? What is the maximum monthly profit realizable? 37. MAXIMIZING PROFIT The estimated monthly profit realizable by the Cannon Precision Instruments Corporation for manufacturing and selling x units of its model M1 cameras is P(x)  0.04 x 2  240 x  10,000

dollars. Determine how many cameras Cannon should produce per month in order to maximize its profits. 38. EFFECT OF ADVERTISING ON PROFIT The relationship between Cunningham Realty’s quarterly profit, P(x), and the amount of money x spent on advertising per quarter is described by the function 1 8

P(x)   x 2  7x  30

29. p  2x 2  80 and p  15x  30

N(t)  0.0031t 2  0.16t  3.6

35. MOTION OF A STONE A stone is thrown straight up from the roof of an 80-ft building. The distance of the stone from the ground at any time t (in seconds) is given by

(0 x 50)

where both P(x) and x are measured in thousands of dollars. a. Sketch the graph of P. b. Find the amount of money the company should spend on advertising per quarter in order to maximize its quarterly profits. 39. MAXIMIZING REVENUE The monthly revenue R (in hundreds of dollars) realized in the sale of Royal electric shavers is related to the unit price p (in dollars) by the equation 1 2

R(p)   p 2  30 p a. Sketch the graph of R. b. At what unit price is the monthly revenue maximized?

40. INSTANT MESSAGING ACCOUNTS The number of enterprise instant messaging (IM) accounts is projected to grow according to the function N(t)  2.96t 2  11.37t  59.7

(0 t 5)

where N(t) is measured in millions and t in years, with t  0 corresponding to the beginning of 2006. a. How many enterprise IM accounts were there at the beginning of 2006? b. What is the number of enterprise IM accounts expected to be at the beginning of 2010? Source: The Radical Group

2.6 QUADRATIC FUNCTIONS

41. SOLAR POWER More and more businesses and homeowners are installing solar panels on their roofs to draw energy from the Sun’s rays. According to the U.S. Department of Energy, the solar cell kilowatt-hour use in the United States (in millions) is projected to be S(t)  0.73t 2  15.8t  2.7

(0 t 8)

in year t, with t  0 corresponding to the beginning of 2000. What was the projected solar cell kilowatt-hours used in the United States at the beginning of 2006? At the beginning of 2008? Source: U.S. Department of Energy

42. AVERAGE SINGLE-FAMILY PROPERTY TAX Based on data from 298 of 351 cities and towns in Massachusetts, the average single-family tax bill from 1997 through 2007 is approximated by the function T(t)  7.26t 2  91.7t  2360

(0 t 10)

where T(t) is measured in dollars and t in years, with t  0 corresponding to 1997. a. What was the property tax on a single-family home in Massachusetts in 1997? b. If the trend continues, what will be the property tax in 2010? Source: Massachusetts Department of Revenue

43. REVENUE OF POLO RALPH LAUREN Citing strong sales and benefits from a new arm that will design lifestyle brands for department and specialty stores, the company projects revenue (in billions of dollars) to be R(t)  0.06t 2  0.69t  3.25

131

respectively, where p is measured in dollars and x is measured in units of a thousand. Find the equilibrium quantity and price. 47. POISEUILLE’S LAW According to a law discovered by the 19thcentury physician Poiseuille, the velocity (in centimeters/ second) of blood r cm from the central axis of an artery is given by √(r)  k(R 2  r 2) where k is a constant and R is the radius of the artery. Suppose that for a certain artery, k  1000 and R  0.2 so that √(r)  1000(0.04  r 2). a. Sketch the graph of √ . b. For what value of r is √(r) largest? Smallest? Interpret your results. 48. MOTION OF A BALL A ball is thrown straight upward from the ground and attains a height of s(t)  16t 2  128t  4 ft above the ground after t sec. When does the ball reach the maximum height? What is the maximum height? 49. DESIGNING A NORMAN WINDOW A Norman window has the shape of a rectangle surmounted by a semicircle (see the accompanying figure). If a Norman window is to have a perimeter of 28 ft, what should be its dimensions in order to allow the maximum amount of light through the window?

x

(0 t 3)

in year t, where t  0 corresponds to 2005. a. What was the revenue of the company in 2005? b. Find R(1), R(2), and R(3) and interpret your results.

y

Source: Company reports

44. SUPPLY FUNCTIONS The supply function for the Luminar desk lamp is given by p  0.1x 2  0.5x  15

where x is the quantity supplied (in thousands) and p is the unit price in dollars. Sketch the graph of the supply function. What unit price will induce the supplier to make 5000 lamps available in the marketplace?

50. DISTANCE OF WATER FLOW A cylindrical tank of height h ft is filled to the top with water. If a hole is punched into the lateral side of the tank, the stream of water flowing out of the tank will reach the ground at a distance of x ft from the base of the tank where x  22y1h  y2 (see the accompanying figure). Find the location of the hole so that x is a maximum. What is this maximum value of x? Hint: It suffices to maximize the expression for x 2. (Why?)

45. MARKET EQUILIBRIUM The weekly demand and supply functions for Sportsman 5  7 tents are given by p  0.1x 2  x  40 p  0.1x 2  2x  20

respectively, where p is measured in dollars and x is measured in units of a hundred. Find the equilibrium quantity and price. 46. MARKET EQUILIBRIUM The management of the Titan Tire Company has determined that the weekly demand and supply functions for their Super Titan tires are given by p  144  x 2 p  48 

1 2 x 2

y

h

x

132

2 FUNCTIONS AND THEIR GRAPHS

In Exercises 51–55, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.

51. If f(x)  ax2  bx  c (a  0), then fa

b  2b2  4ac b 0 2a

52. The quadratic function f(x)  ax2  bx  c (a  0) has no x-intercepts if b2  4ac  0.

54. If b2  4ac, then the graph of the quadratic function f(x)  ax2  bx  c (a  0) touches the x-axis at exactly one point. 55. If the profit function is given by P(x)  ax2  bx  c, where x is the number of units produced and sold, then the level of production that yields a maximum profit is 2ab units. 56. Let f(x)  ax2  bx  c (a  0). By completing the square in x, show that f 1x2  a a x 

53. If a and c have opposite signs, then the parabola with equation y  ax2  bx  c intersects the x-axis at two distinct points.

b 2 4ac  b2 b  2a 4a

2.6 Solutions to Self-Check Exercises 1. Here, a  2, b  3, and c  3. The x-coordinate of the vertex is 

is 3. The graph of the parabola is shown in the accompanying figure.

132 3 b   2a 4 2122

y

The corresponding y-coordinate is

20

3 2 9 9 33 3 3 f a b  2a b  3a b  3    3   4 4 4 8 4 8

15 10

Therefore, the vertex of the parabola is 1 34,  338 2 .

5

2. Solving the equation 2 x 2  3x  3  0, we find x

13 2 2132 2  412 2 13 2 212 2

So the x-intercepts are 34 

133 4

3 233  4

 0.7 and 34 

133 4

 2.2.

4

x

2

2

4

The graph of f(x)  2x 2  3x  3

3. Since a  2  0, the parabola opens upward. The y-intercept

USING

TECHNOLOGY

Finding the Points of Intersection of Two Graphs A graphing utility can be used to find the point(s) of intersection of the graphs of two functions. EXAMPLE 1 Find the points of intersection of the graphs of f(x)  0.3x 2  1.4x  3 and

t(x)  0.4x 2  0.8x  6.4

The graphs of both f and t in the standard viewing window are shown in Figure T1a. Using TRACE and ZOOM or the function for finding the points of intersection of two graphs on your graphing utility, we find the point(s) of intersection, accurate to four decimal places, to be (2.4158, 2.1329) (Figure T1b) and (5.5587, 1.5125) (Figure T1c). Solution

2.6 QUADRATIC FUNCTIONS

Intersection X = −2.415796 (a) FIGURE T1

(b)

Y = 2.1329353

Intersection X = 5.5586531

133

Y = −1.512527

(c)

(a) The graphs of f and g in the standard viewing window; (b) and (c) the TI-83/84 intersection screens

EXAMPLE 2 Consider the demand and supply functions p  d(x)  0.01x 2  0.2x  8 and

p  s(x)  0.01x 2  0.1x  3

a. Plot the graphs of d and s in the viewing window [0, 15]  [0, 10]. b. Verify that the equilibrium point is (10, 5). Solution

a. The graphs of d and s are shown in Figure T2a.

Intersection X = 10 (a) FIGURE T2

Y=5

(b)

(a) The graphs of d and s in the window [0, 15]  [0, 10]; (b) the TI-83/84 intersection screen

b. Using TRACE and ZOOM or the function for finding the point of intersection of two graphs, we see that x  10 and y  5 (Figure T2b), so the equilibrium point is (10, 5), as obtained before.

TECHNOLOGY EXERCISES In Exercises 1–6, find the points of intersection of the graphs of the functions. Express your answer accurate to four decimal places.

1. f(x)  1.2x  3.8; t(x)  0.4x 2  1.2x  7.5 2. f(x)  0.2x 2  1.3x  3; t(x)  1.3x  2.8 3. f(x)  0.3x 2  1.7x  3.2; t(x)  0.4x 2  0.9x  6.7 4. f(x)  0.3x 2  0.6x  3.2; t(x)  0.2x 2  1.2x  4.8 5. f(x)  1.8x 2  2.1x  2; t(x)  2.1x  4.2 6. f(x)  1.2x 2  1.2x  2; t(x)  0.2x 2  0.8x  2.1 7. MARKET EQUILIBRIUM The monthly demand and supply functions for a certain brand of wall clock are given by p  0.2x  1.2x  50 2

p

0.1x 2  3.2x  25

respectively, where p is measured in dollars and x is measured in units of a hundred. a. Plot the graphs of both functions in an appropriate viewing window. b. Find the equilibrium quantity and price. 8. MARKET EQUILIBRIUM The quantity demanded x (in units of a hundred) of Mikado miniature cameras/week is related to the unit price p (in dollars) by p  0.2x 2  80 The quantity x (in units of a hundred) that the supplier is willing to make available in the market is related to the unit price p (in dollars) by p  0.1x 2  x  40 a. Plot the graphs of both functions in an appropriate viewing window. b. Find the equilibrium quantity and price.

134

2 FUNCTIONS AND THEIR GRAPHS

2.7 Functions and Mathematical Models Mathematical Models One of the fundamental goals in this book is to show how mathematics and, in particular, calculus can be used to solve real-world problems such as those arising from the world of business and the social, life, and physical sciences. You have already seen some of these problems earlier. Here are a few more examples of real-world phenomena that we will analyze in this and ensuing chapters. ■ ■ ■ ■ ■ ■

Global warming (p. 135) The solvency of the U.S. Social Security trust fund (p. 136) The number of Internet users in China (p. 159) The growth in the number of mobile instant messaging accounts (p. 597) Investments in hedge funds (p. 602) The projected U.S. gasoline usage (p. 793)

Regardless of the field from which the real-world problem is drawn, the problem is analyzed using a process called mathematical modeling. The four steps in this process, as illustrated in Figure 53, follow. Real-world problem

Formulate

Solve

Test

FIGURE 53

Solution of real-world problem

Mathematical model

Interpret

Solution of mathematical model

1. Formulate Given a real-world problem, our first task is to formulate the problem, using the language of mathematics. The many techniques used in constructing mathematical models range from theoretical consideration of the problem on the one extreme to an interpretation of data associated with the problem on the other. For example, the mathematical model giving the accumulated amount at any time when a certain sum of money is deposited in the bank can be derived theoretically (see Chapter 4). On the other hand, many of the mathematical models in this book are constructed by studying the data associated with the problem (see Using Technology, pages 144–148). In calculus, we are primarily concerned with how one (dependent) variable depends on one or more (independent) variables. Consequently, most of our mathematical models will involve functions of one or more variables or equations defining these functions (implicitly). 2. Solve Once a mathematical model has been constructed, we can use the appropriate mathematical techniques, which we will develop throughout the book, to solve the problem. 3. Interpret Bearing in mind that the solution obtained in step 2 is just the solution of the mathematical model, we need to interpret these results in the context of the original real-world problem. 4. Test Some mathematical models of real-world applications describe the situations with complete accuracy. For example, the model describing a deposit in a bank account gives the exact accumulated amount in the account at any time. But other mathematical models give, at best, an approximate description of the real-world problem. In this case we need to test the accuracy of the model by observing how well it describes the original real-world problem and how well it predicts past and/or future behavior. If the results are unsatisfactory, then we may have to reconsider the assumptions made in the construction of the model or, in the worst case, return to step 1.

2.7 FUNCTIONS AND MATHEMATICAL MODELS

135

Many real-world phenomena including those mentioned at the beginning of this section are modeled by an appropriate function. In what follows, we will recall some familiar functions and give examples of realworld phenomena that are modeled using these functions.

Polynomial Functions A polynomial function of degree n is a function of the form f(x)  an x n  an1x n1  . . .  a2 x 2  a1 x  a0

(an ⬆ 0)

where n is a nonnegative integer and the numbers a0, a1 , . . . , an are constants called the coefficients of the polynomial function. For example, the functions 1 f 1x2  2x5  3x 4  x 3  22x 2  6 2 3 t(x)  0.001x  0.2x 2  10x  200

are polynomial functions of degrees 5 and 3, respectively. Observe that a polynomial function is defined for every value of x and so its domain is (, ). A polynomial function of degree 1 (n  1) has the form y  f (x)  a1x  a0

(a1 ⬆ 0)

and is an equation of a straight line in the slope-intercept form with slope m  a1 and y-intercept b  a0 (see Section 2.2). For this reason, a polynomial function of degree 1 is called a linear function. Linear functions are used extensively in mathematical modeling for two important reasons. First, some models are linear by nature. For example, the formula for converting temperature from Celsius (°C) to Fahrenheit (°F) is F  95 C  32, and F is a linear function of C. Second, some natural phenomena exhibit linear characteristics over a small range of values and can therefore be modeled by a linear function restricted to a small interval. A polynomial function of degree 2 has the form y  f (x)  a2x 2  a1x  a0

(a2 苷 0)

or more simply, y  ax  bx  c, and is called a quadratic function. Quadratic functions serve as mathematical models for many phenomena, as Example 1 shows. 2

APPLIED EXAMPLE 1 Global Warming The increase in carbon dioxide (CO2) in the atmosphere is a major cause of global warming. The Keeling curve, named after Charles David Keeling, a professor at Scripps Institution of Oceanography, gives the average amount of CO2, measured in parts per million volume (ppmv), in the atmosphere from the beginning of 1958 through 2007. Even though data were available for every year in this time interval, we’ll construct the curve based only on the following randomly selected data points. Year Amount

1958

1970

1974

1978

1985

1991

1998

2003

2007

315

325

330

335

345

355

365

375

380

The scatter plot associated with these data is shown in Figure 54a. A mathematical model giving the approximate amount of CO2 in the atmosphere during this period is given by A(t)  0.010716t 2  0.8212t  313.4

(1 t 50)

136

2 FUNCTIONS AND THEIR GRAPHS

where t is measured in years, with t  1 corresponding to the beginning of 1958. The graph of A is shown in Figure 54b. y (ppmv)

y (ppmv) 380

380

360

360

340

340

320

320 10

FIGURE 54

20

30

40

50

t (years)

10

(a) Scatter plot

20

30

40

50

t (years)

(b) Graph of A

a. Use the model to estimate the average amount of atmospheric CO2 at the beginning of 1980 (t  23). b. Assume that the trend continued and use the model to predict the average amount of atmospheric CO2 at the beginning of 2010. Source: Scripps Institution of Oceanography Solution

a. The average amount of atmospheric carbon dioxide at the beginning of 1980 is given by A(23)  0.010716(23)2  0.8212(23)  313.4  337.96

or approximately 338 ppmv. b. Assuming that the trend continued, the average amount of atmospheric CO2 at the beginning of 2010 will be A(53)  0.010716(53)2  0.8212(53)  313.4  387.02

or approximately 387 ppmv. The next example uses a polynomial of degree 4 to help us construct a model that describes the projected assets of the Social Security trust fund. APPLIED EXAMPLE 2 Social Security Trust Fund Assets The projected assets of the Social Security trust fund (in trillions of dollars) from 2008 through 2040 are given in the following table:

Year

2008

2011

2014

2017

2020

2023

2026

2029

2032

2035

2038

2040

Assets

2.4

3.2

4.0

4.7

5.3

5.7

5.9

5.6

4.9

3.6

1.7

0

The scatter plot associated with these data are shown in Figure 55a, where t  0 corresponds to 2008. A mathematical model giving the approximate value of the assets in the trust fund A(t), (in trillions of dollars) in year t is A(t)  0.00000268t 4  0.000356t3  0.00393t 2  0.2514t  2.4094

(0 t 32)

The graph of A(t) is shown in Figure 55b. (You will be asked to construct this model in Exercise 22, Using Technology Exercises 2.7.)

2.7 FUNCTIONS AND MATHEMATICAL MODELS A(t) ($ trillion)

FIGURE 55

A(t) ($ trillion)

6

6

4

4

2

2

5

10

137

15

20

25

30

t (years)

5

10

2

2

(a) Scatter plot

(b) Graph of A

15

20

25

30

t (years)

a. The first baby boomers will turn 65 in 2011. What will be the assets of the Social Security system trust fund at that time? The last of the baby boomers will turn 65 in 2029. What will the assets of the trust fund be at that time? b. Unless payroll taxes are increased significantly and/or benefits are scaled back dramatically, it is a matter of time before the assets of the current system are depleted. Use the graph of the function A(t) to estimate the year in which the current Social Security system is projected to go broke. Source: Social Security Administration Solution

a. The assets of the Social Security trust fund in 2011 (t  3) will be A(3)  0.00000268(3)4  0.000356(3)3  0.00393(3)2  0.2514(3)  2.4094  3.19

or approximately $3.19 trillion. The assets of the trust fund in 2029 (t  21) will be A(21)  0.00000268(21)4  0.000356(21)3  0.00393(21)2  0.2514(21)  2.4094  5.60

or approximately $5.60 trillion. b. From Figure 55b, we see that the graph of A crosses the t-axis at approximately t  32. So unless the current system is changed, it is projected to go broke in 2040. (At this time the first of the baby boomers would be 94 and the last of the baby boomers would be 76.)

Rational and Power Functions Another important class of functions is rational functions. A rational function is simply the quotient of two polynomials. Examples of rational functions are 3x 3  x 2  x  1 x2 2 x 1 G1x2  2 x 1 F1x2 

In general, a rational function has the form R1x2 

f 1x2 t1x2

where f(x) and t(x) are polynomial functions. Since division by zero is not allowed, we conclude that the domain of a rational function is the set of all real numbers except the zeros of t—that is, the roots of the equation t(x)  0. Thus, the domain of the

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2 FUNCTIONS AND THEIR GRAPHS

function F is the set of all numbers except x  2, whereas the domain of the function G is the set of all numbers except those that satisfy x 2  1  0, or x  1. Functions of the form f(x)  x r where r is any real number, are called power functions. We encountered examples of power functions earlier in our work. For example, the functions f 1x2  1x  x1/2

and t1x2 

1  x 2 x2

are power functions. Many of the functions that we encounter later will involve combinations of the functions introduced here. For example, the following functions may be viewed as combinations of such functions: f 1x2 

1  x2 B 1  x2

t1x2  2x2  3x  4 h1x2  11  2x2 1/2 

1 1x 2  2 2 3/2

As with polynomials of degree 3 or greater, analyzing the properties of these functions is facilitated by using the tools of calculus, to be developed later. In the next example, we use a power function to construct a model that describes the driving costs of a car. APPLIED EXAMPLE 3 Driving Costs A study of driving costs based on

a 2008 medium-sized sedan found the following average costs (car payments, gas, insurance, upkeep, and depreciation), measured in cents per mile. Miles/year Cost/mile, y (¢)

5000

10,000

15,000

20,000

147.52

71.90

55.20

46.90

A mathematical model (using least-squares techniques) giving the average cost in cents per mile is 1735.2 C1x2  1.72  38.6 x where x (in thousands) denotes the number of miles the car is driven in 1 year. The scatter plot associated with this data and the graph of C are shown in Figure 56. Using this model, estimate the average cost of driving a 2008 medium-sized sedan 8000 miles per year and 18,000 miles per year. Source: American Automobile Association

FIGURE 56 (a) The scatter plot and (b) the graph of the model for driving costs

C(x)

160 140 120 100 80 60 40 20

Cents

Cents

C(x)

5 (a) Scatter plot

10 15 Thousands of miles

20

x

160 140 120 100 80 60 40 20 5

10 15 20 Thousands of miles (b) Thousands of miles

x

2.7 FUNCTIONS AND MATHEMATICAL MODELS

Solution

139

The average cost for driving a car 8000 miles per year is 1735.2  38.6  87.1 81.72

C182 

or approximately 87.1¢/mile. The average cost for driving it 18,000 miles per year is C1182 

1735.2  38.6  50.6 181.72

or approximately 50.6¢/mile.

Constructing Mathematical Models We close this section by showing how some mathematical models can be constructed using elementary geometric and algebraic arguments. The following guidelines can be used to construct mathematical models.

Guidelines for Constructing Mathematical Models

1. Assign a letter to each variable mentioned in the problem. If appropriate, draw and label a figure. 2. Find an expression for the quantity sought. 3. Use the conditions given in the problem to write the quantity sought as a function f of one variable. Note any restrictions to be placed on the domain of f from physical considerations of the problem.

APPLIED EXAMPLE 4 Enclosing an Area The owner of the Rancho Los Feliz has 3000 yards of fencing with which to enclose a rectangular piece y

x

FIGURE 57 The rectangular grazing land has width x and length y.

of grazing land along the straight portion of a river. Fencing is not required along the river. Letting x denote the width of the rectangle, find a function f in the variable x giving the area of the grazing land if she uses all of the fencing (Figure 57). Solution

1. This information was given. 2. The area of the rectangular grazing land is A  xy. Next, observe that the amount of fencing is 2x  y and this must be equal to 3000 since all the fencing is used; that is, 2x  y  3000

3. From the equation we see that y  3000  2x. Substituting this value of y into the expression for A gives A  xy  x(3000  2x)  3000x  2x 2 Finally, observe that both x and y must be nonnegative since they represent the width and length of a rectangle, respectively. Thus, x  0 and y  0. But the latter is equivalent to 3000  2x  0, or x 1500. So the required function is f (x)  3000x  2x 2 with domain 0 x 1500. Observe that if we view the function f(x)  3000x  2x 2 strictly as a mathematical entity, then its domain is the set of all real numbers. But physical considerations dictate that its domain should be restricted to the interval [0, 1500]. Note

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2 FUNCTIONS AND THEIR GRAPHS

APPLIED EXAMPLE 5 Charter-Flight Revenue If exactly 200 people

sign up for a charter flight, Leisure World Travel Agency charges $300 per person. However, if more than 200 people sign up for the flight (assume this is the case), then each fare is reduced by $1 for each additional person. Letting x denote the number of passengers above 200, find a function giving the revenue realized by the company. Solution

1. This information was given. 2. If there are x passengers above 200, then the number of passengers signing up for the flight is 200  x. Furthermore, the fare will be (300  x) dollars per passenger. 3. The revenue will be R  (200  x)(300  x)  x 2  100x  60,000

Number of passengers  the fare per passenger

Clearly, x must be nonnegative, and 300  x  0, or x 300. So the required function is f(x)  x 2  100x  60,000 with domain [0, 300].

2.7 Self-Check Exercise The Cunningham Day Care Center wants to enclose a playground of rectangular shape having an area of 500 ft2 with a wooden fence. Find a function f giving the amount of fencing required in terms of the width x of the rectangular playground.

The solution to Self-Check Exercise 2.7 can be found on page 144.

2.7 Concept Questions 1. Describe mathematical modeling in your own words.

2. Define (a) a polynomial function and (b) a rational function. Give an example of each.

2.7 Exercises In Exercises 1–6, determine whether the given function is a polynomial function, a rational function, or some other function. State the degree of each polynomial function.

x2  9 x3

1. f (x)  3x 6  2x 2  1

2. f(x) 

3. G(x)  2(x 2  3)3

4. H(x)  2x3  5x2  6

5. f(t)  2 t  3 2t

6r

2

6. f (r) 

1r 3  82

7. REACTION OF A FROG TO A DRUG Experiments conducted by A. J. Clark suggest that the response R(x) of a frog’s heart muscle to the injection of x units of acetylcholine (as a percent of the maximum possible effect of the drug) may be approximated by the rational function 100x R(x)  bx

(x  0)

where b is a positive constant that depends on the particular frog.

a. If a concentration of 40 units of acetylcholine produces a response of 50% for a certain frog, find the “response function” for this frog. b. Using the model found in part (a), find the response of the frog’s heart muscle when 60 units of acetylcholine are administered. 8. AGING DRIVERS The number of fatalities due to car crashes, based on the number of miles driven, begins to climb after the driver is past age 65. Aside from declining ability as one ages, the older driver is more fragile. The number of fatalities per 100 million vehicle miles driven is approximately N(x)  0.0336x 3  0.118x 2  0.215x  0.7

(0 x 7)

where x denotes the age group of drivers, with x  0 corresponding to those aged 50–54, x  1 corresponding to those aged 55–59, x  2 corresponding to those aged 60–64, . . . , and x  7 corresponding to those aged 85–89. What is the fatality rate per 100 million vehicle miles

2.7 FUNCTIONS AND MATHEMATICAL MODELS

driven for an average driver in the 50–54 age group? In the 85–89 age group? Source: U.S. Department of Transportation

9. RISING WATER RATES Based on records from 2001 through 2006, services paid for by households in 60 Boston-area communities that use an average of 90,000 gal of water a year are given by C(t)  2.16t3  40t  751.5

Source: Massachusetts Water Resources Authority

10. GIFT CARDS Gift cards have increased in popularity in recent years. Consumers appreciate gift cards because they get to select the present they like. The U.S. sales of gift cards (in billions of dollars) is approximated by S(t)  0.6204t 3  4.671t 2  3.354t  47.4

(0 t 5)

in year t, where t  0 corresponds to 2003. a. What were the sales of gift cards for 2003? b. What were the sales of gift cards in 2008? Source: The Tower Group

11. BLACKBERRY SUBSCRIBERS According to a study conducted in 2004, the number of subscribers of BlackBerry, the handheld email devices manufactured by Research in Motion Ltd., is approximated by N(t )  0.0675t 4  0.5083t 3  0.893t 2  0.66t  0.32 (0 t 4)

where N(t ) is measured in millions and t in years, with t  0 corresponding to the beginning of 2002. a. How many BlackBerry subscribers were there at the beginning of 2002? b. How many BlackBerry subscribers were there at the beginning of 2006? Source: ThinkEquity Partners

12. INFANT MORTALITY RATES IN MASSACHUSETTS The deaths of children less than 1 yr old per 1000 live births is modeled by the function R(t)  162.8t3.025

(1 t 3)

where t is measured in 50-yr intervals, with t  1 corresponding to 1900. a. Find R(1), R(2), and R(3) and use your result to sketch the graph of the function R over the domain [1, 3]. b. What was the infant mortality rate in 1900? In 1950? In 2000? Source: Massachusetts Department of Public Health

13. ONLINE VIDEO VIEWERS As broadband Internet grows more popular, video services such as YouTube will continue to expand. The number of online video viewers (in millions) is projected to grow according to the rule N(t)  52t 0.531

where t  1 corresponds to the beginning of 2003. a. Sketch the graph of N. b. How many online video viewers will there be at the beginning of 2010? Source: eMarketer.com

14. CHIP SALES The worldwide flash memory chip sales (in billions of dollars) is projected to be

(0 t 6)

Here t  0 corresponds to 2001, and C(t) is measured in dollars/year. What was the average amount paid by a household in 2001 for water and sewer services? If the trend continued, what was the average amount paid in 2008?

(1 t 10)

141

S(t)  4.3(t  2)0.94

(0 t 6)

where t is measured in years, with t  0 corresponding to 2002. Flash chips are used in cell phones, digital cameras, and other products. a. What were the worldwide flash memory chip sales in 2002? b. What were the sales for 2008? Source: Web-Feet Research Inc.

15. OUTSOURCING OF JOBS According to a study conducted in 2003, the total number of U.S. jobs (in millions) that are projected to leave the country by year t, where t  0 corresponds to the beginning of 2000, is N(t)  0.0018425(t  5)2.5

(0 t 15)

What was the projected number of outsourced jobs for 2005 (t  5)? For 2010 (t  10)? Source: Forrester Research

16. IMMIGRATION TO THE UNITED STATES The immigration to the United States from Europe, as a percentage of the total immigration, is approximately P(t)  0.767t 3  0.636t 2  19.17t  52.7

(0 t 4)

where t is measured in decades, with t  0 corresponding to the decade of the 1950s. a. Complete the table: t P(t)

0

1

2

3

4

b. Use the result of part (a) to sketch the graph of P. c. Use the result of part (b) to estimate the decade when the immigration, as a percentage of the total immigration, was the greatest and the smallest. Source: Jeffrey Williamson, Harvard University

17. SELLING PRICE OF DVD RECORDERS The rise of digital music and the improvement to the DVD format are part of the reasons why the average selling price of standalone DVD recorders will drop in the coming years. The function A1t2 

699 1t  1 2 0.94

10 t 52

gives the projected average selling price (in dollars) of standalone DVD recorders in year t, where t  0 corresponds to the beginning of 2002. What was the average selling price of standalone DVD recorders at the beginning of 2002? At the beginning of 2007? Source: Consumer Electronics Association

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2 FUNCTIONS AND THEIR GRAPHS

18. WALKING VERSUS RUNNING The oxygen consumption (in milliliter/pound/minute) for a person walking at x mph is approximated by the function f 1x 2 

10 x 92

5 2 5 x  x  10 3 3

whereas the oxygen consumption for a runner at x mph is approximated by the function t(x)  11x  10

(4 x 9)

a. Sketch the graphs of f and t. b. At what speed is the oxygen consumption the same for a walker as it is for a runner? What is the level of oxygen consumption at that speed? c. What happens to the oxygen consumption of the walker and the runner at speeds beyond that found in part (b)? Source: William McArdley, Frank Katch, and Victor Katch, Exercise Physiology

19. PRICE OF AUTOMOBILE PARTS For years, automobile manufacturers had a monopoly on the replacement-parts market, particularly for sheet metal parts such as fenders, doors, and hoods, the parts most often damaged in a crash. Beginning in the late 1970s, however, competition appeared on the scene. In a report conducted by an insurance company to study the effects of the competition, the price of an OEM (original equipment manufacturer) fender for a particular 1983 model car was found to be f 1t2 

110 1 2t

1

10 t 22

where f (t) is measured in dollars and t is in years. Over the same period of time, the price of a non-OEM fender for the car was found to be 2 1 t1t 2  26 a t 2  1 b  52 4

10 t 2 2

where t(t) is also measured in dollars. Find a function h(t) that gives the difference in price between an OEM fender and a non-OEM fender. Compute h(0), h(1), and h(2). What does the result of your computation seem to say about the price gap between OEM and non-OEM fenders over the 2 yr? 20. OBESE CHILDREN IN THE UNITED STATES The percentage of obese children aged 12–19 in the United States is approximately 0.04t  4.6 P1t 2  e 0.01005t 2  0.945t  3.4

if 0 t 10 if 10 t 30

where t is measured in years, with t  0 corresponding to the beginning of 1970. What was the percentage of obese children aged 12–19 at the beginning of 1970? At the beginning of 1985? At the beginning of 2000? Source: Centers for Disease Control

21. PRICE OF IVORY According to the World Wildlife Fund, a group in the forefront of the fight against illegal ivory

trade, the price of ivory (in dollars/kilo) compiled from a variety of legal and black market sources is approximated by the function f 1t2  e

8.37t  7.44 2.84t  51.68

if 0 t 8 if 8 t 30

where t is measured in years, with t  0 corresponding to the beginning of 1970. a. Sketch the graph of the function f. b. What was the price of ivory at the beginning of 1970? At the beginning of 1990? Source: World Wildlife Fund

22. CREDIT CARD DEBT Following the introduction in 1950 of the nation’s first credit card, the Diners Club Card, credit cards have proliferated over the years. More than 720 different cards are now used at more than 4 million locations in the United States. The average U.S. credit card debt (per household) in thousands of dollars is approximately given by D1t2  e

4.7711  t2 0.2676 5.6423t 0.1818

if 0 t 2 if 2 t 6

where t is measured in years, with t  0 corresponding to the beginning of 1994. What was the average U.S. credit card debt (per household) at the beginning of 1994? At the beginning of 1996? At the beginning of 1999? Source: David Evans and Richard Schmalensee, Paying with Plastic: The Digital Revolution in Buying and Borrowing

23. SENIOR CITIZENS’ HEALTH CARE According to a study, the outof-pocket cost to senior citizens for health care, f(t) (as a percentage of income), in year t where t  0 corresponds to 1977, is given by 2 t  12 7 f 1t2  e t  7 1 41 t 3 3

if 0 t 7 if 7 t 10 if 10 t 25

a. Sketch the graph of f. b. What was the out-of-pocket cost, as a percentage of income, to senior citizens for health care in 1982? In 1992? Source: Senate Select Committee on Aging, AARP

24. WORKING-AGE POPULATION The ratio of working-age population to the elderly in the United States (including projections after 2000) is given by 4.1 f 1t 2  c 0.03t  4.25 0.075t  4.925

if 0 t 5 if 5 t 15 if 15 t 35

with t  0 corresponding to the beginning of 1995. a. Sketch the graph of f. b. What was the ratio at the beginning of 2005? What will be the ratio at the beginning of 2020? c. Over what years is the ratio constant? d. Over what years is the decline of the ratio greatest? Source: U.S. Census Bureau

2.7 FUNCTIONS AND MATHEMATICAL MODELS

25. SALES OF DVD PLAYERS VS. VCRS The sales of DVD players in year t (in millions of units) is given by the function f (t)  5.6(1  t)

(0 t 3)

where t  0 corresponds to 2001. Over the same period, the sales of VCRs (in millions of units) is given by 9.6t  22.5 t1t2  c 0.5t  13.4 7.8t  28

143

29. CONSTRUCTION COSTS A rectangular box is to have a square base and a volume of 20 ft3. The material for the base costs 30¢/ft2, the material for the sides costs 10¢/ft2, and the material for the top costs 20¢/ft2. Letting x denote the length of one side of the base, find a function in the variable x giving the cost of constructing the box.

if 0 t 1 if 1 t 2 if 2 t 3

y

a. Show that more VCRs than DVD players were sold in 2001. b. When did the sales of DVD players first exceed those of VCRs?

x

Source: Popular Science

x

26. ENCLOSING AN AREA Patricia wishes to have a rectangularshaped garden in her backyard. She has 80 ft of fencing with which to enclose her garden. Letting x denote the width of the garden, find a function f in the variable x giving the area of the garden. What is its domain?

30. BOOK DESIGN A book designer has decided that the pages of a book should have 1-in. margins at the top and bottom and 12 -in. margins on the sides. She further stipulated that each page should have an area of 50 in.2. Find a function in the variable x, giving the area of the printed page. What is the domain of the function? x

x

1 2

y

27. ENCLOSING AN AREA Patricia’s neighbor, Juanita, also wishes to have a rectangular-shaped garden in her backyard. But Juanita wants her garden to have an area of 250 ft2. Letting x denote the width of the garden, find a function f in the variable x giving the length of the fencing required to construct the garden. What is the domain of the function? Hint: Refer to the figure for Exercise 26. The amount of fencing required is equal to the perimeter of the rectangle, which is twice the width plus twice the length of the rectangle.

28. PACKAGING By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. If the cardboard is 15 in. long and 8 in. wide and the square cutaways have dimensions of x in. by x in., find a function giving the volume of the resulting box. x

x

x

x 8 8 – 2x

x

x x

15 – 2x 15

x

y

in.

1 in.

31. YIELD OF AN APPLE ORCHARD An apple orchard has an average yield of 36 bushels of apples/tree if tree density is 22 trees/acre. For each unit increase in tree density, the yield decreases by 2 bushels/tree. Letting x denote the number of trees beyond 22/acre, find a function in x that gives the yield of apples. 32. CHARTER REVENUE The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $600/person/ day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then each fare is reduced by $4 for each additional passenger. Assume at least 20 people sign up for the cruise and let x denote the number of passengers above 20. a. Find a function R giving the revenue/day realized from the charter. b. What is the revenue/day if 60 people sign up for the cruise? c. What is the revenue/day if 80 people sign up for the cruise?

144

2 FUNCTIONS AND THEIR GRAPHS

33. PROFIT OF A VINEYARD Phillip, the proprietor of a vineyard, estimates that if 10,000 bottles of wine were produced this season, then the profit would be $5/bottle. But if more than 10,000 bottles were produced, then the profit/bottle for the entire lot would drop by $0.0002 for each additional bottle sold. Assume at least 10,000 bottles of wine are produced and sold and let x denote the number of bottles produced and sold above 10,000. a. Find a function P giving the profit in terms of x. b. What is the profit Phillip can expect from the sale of 16,000 bottles of wine from his vineyard?

c. Find a function h giving the area polluted in terms of t. d. What is the size of the polluted area 30 sec after the hull was ruptured? In Exercises 35–38, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

35. A polynomial function is a sum of constant multiples of power functions. 36. A polynomial function is a rational function, but the converse is false.

34. OIL SPILLS The oil spilling from the ruptured hull of a grounded tanker spreads in all directions in calm waters. Suppose the area polluted is a circle of radius r and the radius is increasing at the rate of 2 ft/sec. a. Find a function f giving the area polluted in terms of r. b. Find a function t giving the radius of the polluted area in terms of t.

37. If r  0, then the power function f(x)  x r is defined for all values of x. 38. The function f(x)  2 x is a power function.

2.7 Solution to Self-Check Exercise Then, the amount of fencing required is L  2x  2y. But the requirement that the area of the rectangular playground be 500 ft2 implies that xy  500, or upon solving for y, y  500/x. Therefore, the amount of fencing required is

Let the length of the rectangular playground be y ft (see the figure).

L  f(x)  2x  2 a

x

1000 500 b  2x  x x

with domain (0, ). y

USING

TECHNOLOGY

Constructing Mathematical Models from Raw Data A graphing utility can sometimes be used to construct mathematical models from sets of data. For example, if the points corresponding to the given data are scattered about a straight line, then use LinReg(ax⫹b) (linear regression) from the statistical calculation menu of the graphing utility to obtain a function (model) that approximates the data at hand. If the points seem to be scattered along a parabola (the graph of a quadratic function), then use QuadReg (second-degree polynomial regression), and so on. (These are functions on the TI-83/84 calculator.) APPLIED EXAMPLE 1 Indian Gaming Industry The following data gives the estimated gross revenues (in billions of dollars) from the Indian gaming industries from 2000 (t  0) to 2005 (t  5). Year Revenue

0

1

2

3

4

5

11.0

12.8

14.7

16.8

19.5

22.7

145

2.7 FUNCTIONS AND MATHEMATICAL MODELS

a. Use a graphing utility to find a polynomial function f of degree 4 that models the data. b. Plot the graph of the function f, using the viewing window [0, 6]  [0, 30]. c. Use the function evaluation capability of the graphing utility to compute f(0), f(1), . . . , f(5) and compare these values with the original data. d. If the trend continued, what was the gross revenue for 2006 (t  6)? Source: National Indian Gaming Association

Solution

a. Choosing QuartReg (fourth-degree polynomial regression) from the statistical calculations menu of a graphing utility, we find f(t)  0.00417t 4  0.0713t 3  0.168t 2  1.920t  11

FIGURE T1 The graph of f in the viewing window [0, 6]  [0, 30]

b. The graph of f is shown in Figure T1. c. The required values, which compare favorably with the given data, follow: t f(t)

0

1

2

3

4

5

11.0

12.8

14.7

16.8

19.5

22.7

d. The gross revenue for 2006 (t  6) is given by f(6)  0.00417(6)4  0.0713(6)3  0.168(6)2  1.920(6)  11  26.469

or $26.5 billion.

TECHNOLOGY EXERCISES In Exercises 1–16, use the statistical calculations menu to construct a mathematical model associated with the given data.

1. SALES OF DSPS The projected sales (in billions of dollars) of digital signal processors (DSPs) and the scatter plot for these data follow: Year Sales

1997 3.1

1998 4

1999 5

2000 6.2

2001 8

2002 10

y ($ billion) 10 9 8 7 6 5 4 3 2 1 1

2

3

4

5

t (year)

a. Use P2Reg to find a second-degree polynomial regression model for the data. Let t  0 correspond to 1997.

b. Plot the graph of the function f found in part (a), using the viewing window [0, 5]  [0, 12]. c. Compute the values of f(t) for t  0, 1, 2, 3, 4, and 5. How does your model compare with the given data? Source: A. G. Edwards & Sons, Inc.

2. ANNUAL RETAIL SALES Annual retail sales in the United States from the beginning of 1990 through the year 2000 (in billions of dollars) are given in the following table: Year Sales

1990 471.6

1991 485.4

1992 519.2

1993 553.4

1994 595

Year Sales

1996 656.6

1997 685.6

1998 727.2

1999 781.7

2000 877.7

1995 625.5

a. Let t  0 correspond to 1990 and use P2Reg to find a second-degree polynomial regression model based on the given data. b. Plot the graph of the function f found in part (a) using the viewing window [0, 10]  [0, 1000]. c. Compute f(0), f(5), and f(10). Compare these values with the given data. Source: National Retail Federation (continued)

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2 FUNCTIONS AND THEIR GRAPHS

3. CONSUMPTION OF BOTTLED WATER The annual per-capita consumption of bottled water (in gallons) and the scatter plot for these data follow: y (gallons) 30 28 26 24 22 20 18

1

2

Year Consumption

3

2001 18.8

4

2002 20.9

5

2003 22.4

6

2004 24

Year

1995

2000

2005

2010

2015

Number

64.8

68.7

72.6

74.8

78

a. Use QuadReg to find a second-degree polynomial regression model for the data. Let t be measured in 5-yr intervals, with t  0 corresponding to the beginning of 1995. b. Plot the graph of the function f found in part (a), using the viewing window [0, 4]  [0, 85]. c. Using the model found in part (a), what will be the projected total number of students (all categories) enrolled at the beginning of 2015?

t (year)

2005 26.1

5. STUDENT POPULATION The projected total number of students in elementary schools, secondary schools, and colleges (in millions) from the beginning of 1995 through 2015 is given in the following table:

2006 28.3

a. Use LinReg(ax ⫹ b) to find a first-degree (linear) polynomial regression model for the data. Let t  1 correspond to 2001. b. Plot the graph of the function f found in part (a), using the viewing window [1, 6]  [0, 30]. c. Compute the values for t = 1, 2, 3, 4, 5, and 6. How do your figures compare with the given data? d. If the trend continued, what will be the annual per-capita consumption of bottled water in 2008 (t  8)?

Source: U.S. National Center for Education Statistics

6. DIGITAL TV SHIPMENTS The estimated number of digital TV shipments between 2000 and 2006 (in millions of units) and the scatter plot for these data follow: Year Units Shipped

2000

2001

2002

2003

2004

2005

2006

0.63

1.43

2.57

4.1

6

8.1

10

y (million) 10 8

Source: Beverage Marketing Corporation

4. WEB CONFERENCING Web conferencing is a big business, and it’s growing rapidly. The amount (in billions of dol-

lars) spent on Web conferencing from the beginning of 2003 through 2010, and the scatter diagram for these data follow: Year Amount

2003 0.50

2004 0.63

2005 0.78

2006 0.92

2007 1.16

2008 1.38

2009 1.60

2010 1.90

y ($ billion) 2.5 2

6 4 2 1

2

3

4

5

6

t (year)

a. Use CubicReg to find a third-degree polynomial regression model for the data. Let t  0 correspond to the beginning of 2000. b. Plot the graph of the function f found in part (a), using the viewing window [0, 6]  [0, 11]. c. Compute the values of f(t) for t  0, 1, 2, 3, 4, 5, and 6. Source: Consumer Electronics Manufacturers Association

1.5

7. HEALTH-CARE SPENDING Health-care spending by business (in billions of dollars) from the beginning of 2000 through 2006 is summarized below:

1 0.5 1

2

3

4

5

6

7

t (year)

Year 2000 Number 185

2001 235

2002 278

2003 333

2004 389

2005 450

2006 531

a. Let t  0 correspond to the beginning of 2003 and use QuadReg to find a second-degree polynomial regression model based on the given data. b. Plot the graph of the function f found in part (a) using the window [0, 7]  [0, 2]. c. Compute f(0), f(3), f(6), and f(7). Compare these values with the given data.

a. Plot the scatter diagram for the above data. Let t  0 correspond to the beginning of 2000. b. Use QuadReg to find a second-degree polynomial regression model for the data. c. If the trend continued, what was the spending at the beginning of 2007?

Source: Gartner Dataquest

Source: Centers for Medicine and Medicaid Services

2.7 FUNCTIONS AND MATHEMATICAL MODELS

8. TIVO OWNERS The projected number of households (in millions) with digital video recorders that allow viewers to record shows onto a server and skip commercials are given in the following table:

147

b. Plot the graph of the function f found in part (a), using the viewing window [0, 3]  [0, 1,500,000]. c. Compare the values of f at t  0, 1, 2, and 3, with the given data. Source: U.S. Census Bureau

Year 2006 Households 31.2

2007 49.0

2008 71.6

2009 97.0

2010 130.2

a. Let t  0 correspond to the beginning of 2006 and use QuadReg to find a second-degree polynomial regression model based on the given data. b. Obtain the scatter plot and the graph of the function f found in part (a), using the viewing window [0, 4]  [0, 140]. Source: Strategy Analytics

9. TELECOMMUNICATIONS INDUSTRY REVENUE The telecommunications industry revenue is expected to grow in the coming years, fueled by the demand for broadband and highspeed data services. The worldwide revenue for the industry (in trillions of dollars) and the scatter diagram for these data follow: Year Revenue

2000 1.7

2002 2.0

2004 2.5

2006 3.0

2008 3.6

2010 4.2

11. HIRING LOBBYISTS Many public entities like cities, counties, states, utilities, and Indian tribes are hiring firms to lobby Congress. One goal of such lobbying is to place earmarks—money directed at a specific project—into appropriation bills. The amount (in millions of dollars) spent by public entities on lobbying from the beginning of 1998 through 2004 is shown in the following table: Year Amount

1998 43.4

1999 51.7

2000 62.5

2001 76.3

2002 92.3

2003 2004 101.5 107.7

a. Use CubicReg to find a third-degree polynomial regression model for the data, letting t  0 correspond to the beginning of 1998. b. Plot the scatter diagram and the graph of the function f found in part (a), using the viewing window [0, 6]  [0, 120]. c. Compare the values of f at t  0, 3, and 6 with the given data. Source: Center for Public Integrity

12. MOBILE ENTERPRISE IM ACCOUNTS The projected number of mobile enterprise instant messaging accounts (in millions) from 2006 through 2010 is given in the following table (t  0 corresponds to the beginning of 2006):

y ($ trillion) 5 4 3

Year Accounts

2 1 2

4

6

8

10

t (year)

a. Let t  0 correspond to the beginning of 2000 and use CubicReg to find a third-degree polynomial regression model based on the given data. b. Plot the graph of the function f found in part (a), using the viewing window [0, 10]  [0, 5]. c. Find the worldwide revenue for the industry at the beginning of 2001 and at the beginning of 2010. Source: Telecommunication Industry Association

10. POPULATION GROWTH IN CLARK COUNTY Clark County in Nevada—dominated by greater Las Vegas—is the fastestgrowing metropolitan area in the United States. The population of the county from 1970 through 2000 is given in the following table: Year Population

1970 273,288

1980 463,087

1990 741,459

2000 1,375,765

a. Use CubicReg to find a third-degree polynomial regression model for the data. Let t be measured in decades, with t  0 corresponding to the beginning of 1970.

0 2.3

1 3.6

2 5.8

3 8.7

4 14.9

a. Use CubicReg to find a third-degree polynomial regression model based on the given data. b. Plot the graph of the function f found in part (a), using the viewing window [0, 5]  [0, 16]. c. Compute f(0), f(1), f(2), f(3), and f(4). Source: The Radical Group

13. MEASLES DEATHS Measles is still a leading cause of vaccinepreventable death among children, but due to improvements in immunizations, measles deaths have dropped globally. The following table gives the number of measles deaths (in thousands) in sub-Saharan Africa from the beginning of 1999 through 2005: Year Amount

1999 506

2001 338

2003 250

2005 126

a. Use CubicReg to find a third-degree polynomial regression model for the data, letting t  0 correspond to the beginning of 1999. b. Plot the scatter diagram and the graph of the function f found in part (a). c. Compute the values of f for t  0, 2, and 6. Source: Centers for Disease Control and World Health Organization

148

2 FUNCTIONS AND THEIR GRAPHS

14. OFFICE VACANCY RATE The total vacancy rate of offices in Manhattan from the beginning of 2000 through 2006 is shown in the following table. Year Vacancy Rate

2000 3.8

2001 8.9

2002 12

2003 12.5

2004 11

2005 8.4

a. Use QuartReg to find a fourth-degree polynomial regression model for the data. Let t  0 correspond to the beginning of 1999. b. Plot the graph of the function f found in part (a), using the viewing window [0, 5]  [0, 2]. c. Compute the values of f(t) for t  0, 1, 2, 3, 4, and 5. d. If the trend continued, what would have been the average amount of nicotine in cigarettes at the beginning of 2005?

2006 6.7

a. Use CubicReg to find a third-degree polynomial regression model for the data, letting t  0 correspond to the beginning of 2000. b. Plot the scatter diagram and the graph of the function f found in part (a). c. Compute the values for t  1, 2, 3, 4, 5, and 6. Source: Cushman and Wakefield

15. NICOTINE CONTENT OF CIGARETTES Even as measures to discourage smoking have been growing more stringent in recent years, the nicotine content of cigarettes has been rising, making it more difficult for smokers to quit. The following table gives the average amount of nicotine in cigarette smoke from the beginning of 1999 through 2004:

Source: Massachusetts Tobacco Control Program

16. SOCIAL SECURITY TRUST FUND ASSETS The projected assets of the Social Security trust fund (in trillions of dollars) from 2008 through 2040 are given in the following table: Year

2008

2011

2014

Assets

2.4

3.2

4.0

2017 2020 4.7

5.3

2023

2026

2029

2032

2035

5.7

5.9

5.6

4.9

3.6

1999

2000

2001

2002

2003

2004

1.71

1.81

1.85

1.84

1.83

1.89

CHAPTER 2 Summary of Principal Formulas and Terms FORMULAS 1. Slope of a line

y2  y1 m x2  x1

2. Equation of a vertical line

xa

3. Equation of a horizontal line

yb

4. Point-slope form of the equation of a line

y  y1  m(x  x1)

5. Slope-intercept form of the equation of a line

y  mx  b

6. General equation of a line

Ax  By  C  0

TERMS Cartesian coordinate system (68) origin (68) ordered pair (68) coordinates (68) parallel lines (72) perpendicular lines (76) x-intercept (77) y-intercept (77) function 87) domain (87) range (88)

1.7

0

Use QuartReg to find a fourth-degree polynomial regression model for the data. Let t  0 correspond to the beginning of 2008. Source: Social Security Administration

Year Yield per Cigarette (mg)

2038 2040

independent variable (89) dependent variable (89) ordered pairs (90) function (alternative definition) (90) graph of a function (91) piecewise-defined function (92) graph of an equation (93) vertical-line test (93) composite function (106) linear function (111) total cost function (112)

revenue function (112) profit function (112) break-even point (114) quadratic function (123) demand function (126) supply function (127) market equilibrium (128) polynomial function (135) rational function (137) power function (138)

REVIEW EXERCISES

149

CHAPTER 2 Concept Review Questions Fill in the blanks.

on all possible values in A is called the ______ of f. The range of f is contained in the set ______.

1. A point in the plane can be represented uniquely by a/an

______ pair of numbers. The first number of the pair is called the ______ and the second number of the pair is called the ______. 2. a. The point P(a, 0) lies on the ______-axis, and the point P(0, b) lies on the ______-axis. b. If the point P(a, b) lies in the fourth quadrant, then the point P(a, b) lies in the ______ quadrant. 3. a. If P1(x1, y1) and P2(x2, y2) are any two distinct points on a nonvertical line L, then the slope of L is m = ______. b. The slope of a vertical line is ______. c. The slope of a horizontal line is ______. d. The slope of a line that slants upward is ______. 4. If L1 and L2 are nonvertical lines with slopes m1 and m2, respectively, then L1 is parallel to L2 if and only if ______ and L1 is perpendicular to L2 if and only if ______. 5. a. An equation of the line passing through the point P(x1, y1) and having slope m is ______. This form of the

equation of a line is called the ______ ______. b. An equation of the line that has slope m and y-intercept b is ______. It is called the ______ form of an equation

of a line. 6. a. The general form of an equation of a line is ______. b. If a line has equation ax  by  c  0 (b  0), then its

slope is ______. 7. If f is a function from the set A to the set B, then A is called the ______ of f, and the set of all values of f(x) as x takes

8. The graph of a function is the set of all points (x, y) in the xy-plane such that x is in the ______ of f and y  ______. The vertical-line test states that a curve in the xy-plane is the graph of a function y  f(x) if and only if each ______ line intersects it in at most one ______. 9. If f and t are functions with domains A and B, respectively, then (a) ( f t)(x)  ______, (b) ( ft)(x)  ______, and f (c) a b (x)  ______. The domain of f  t is ______. The t f domain of is ______ with the additional condition that t t(x) is never ______. 10. The composition of t and f is the function with rule (t 폶 f )(x)  ______. Its domain is the set of all x in the domain of ______ such that ______ lies in the domain of ______. 11. A quadratic function has the form f (x)  ______. Its graph is a/an ______ that opens ______ if a  0 and ______ if a 0. Its highest point or lowest point is called its ______. The x-coordinate of its vertex is ______, and its axis of symmetry is ______. 12. a. A polynomial function of degree n is a function of the form ______. b. A polynomial function of degree 1 is called a/an ______ function; one of degree 2 is called a/an ______ function. c. A rational function is a/an ______ of two ______. d. A power function has the form f(x)  ______.

CHAPTER 2 Review Exercises In Exercises 1–6, find an equation of the line L that passes through the point (⫺2, 4) and satisfies the given condition.

1. L is a vertical line. 2. L is a horizontal line. 3. L passes through the point 13, 72 2 .

9. Find an equation of the line passing through the point (2, 3) and parallel to the line with equation 3x  4y  8  0. 10. Find an equation of the line passing through the point (1, 3) and parallel to the line joining the points (3, 4) and (2, 1).

4. The x-intercept of L is 3.

11. Find an equation of the line passing through the point (2, 4) that is perpendicular to the line with equation 2 x  3y  24  0.

5. L is parallel to the line 5x  2y  6.

In Exercises 12 and 13, sketch the graph of the equation.

6. L is perpendicular to the line 4x  3y  6. 7. Find an equation of the line with slope cept 3.

12

12. 3x  4y  24 and y-inter-

8. Find the slope and y-intercept of the line with equation 3x  5y  6.

13. 2x  5y  15

In Exercises 14 and 15, find the domain of the function.

14. f(x)  29  x 15. f(x) 

x3 2x  x  3 2

150

2 FUNCTIONS AND THEIR GRAPHS

16. Let f(x)  3x 2  5x  2. Find: a. f(2) b. f(a  2) c. f(2a) d. f(a  h)

27. DEMAND FOR CLOCK RADIOS In the accompanying figure, L 1 is the demand curve for the model A clock radios manufactured by Ace Radio, and L 2 is the demand curve for their model B clock radios. Which line has the greater slope? Interpret your results.

17. SALES OF PRERECORDED MUSIC The following graphs show the sales y of prerecorded music (in billions of dollars) by format as a function of time t (in years), with t  0 corresponding to 1985.

p L1

L2

y (billions of dollars) CDs

8 7 6 5 4 3 2 1

x

Cassettes

t (years) 0

1

2

3

4

5

6

7

8

9

a. In what years were the sales of prerecorded cassettes greater than those of prerecorded CDs? b. In what years were the sales of prerecorded CDs greater than those of prerecorded cassettes? c. In what year were the sales of prerecorded cassettes the same as those of prerecorded CDs? Estimate the level of sales in each format at that time.

28. SUPPLY OF CLOCK RADIOS In the accompanying figure, L 1 is the supply curve for the model A clock radios manufactured by Ace Radio, and L 2 is the supply curve for their model B clock radios. Which line has the greater slope? Interpret your results. p L2 L1

Source: Recording Industry Association of America

18. Let y  2x  1. a. Sketch the graph of this equation. b. Is y a function of x? Why? c. Is x a function of y? Why?

x

2

19. Sketch the graph of the function defined by f(x)

x1

x

2

if x 1

 4x  1 if x  1

20. Let f(x)  1x and t(x)  2x  3. Find: a. f(x)t(x) b. f(x)/t(x) c. f(t(x)) d. t( f(x)) In Exercises 21 and 22, find the vertex and the x-intercepts and sketch the parabola.

21. 6x 2  11x  10  0

22. 4x 2  4x  3  0

In Exercises 23 and 24, find the point of intersection of the lines with the given equations.

23. 3x  4y  6 and 2x  5y  11 3 24. y  x  6 and 3x  2y  3  0 4 25. Find the point of intersection of the two straight lines having the equations 7x  9y  11 and 3x  6y  8. 26. The cost and revenue functions for a certain firm are given by C(x)  12x  20,000 and R(x)  20x, respectively. Find the company’s break-even point.

29. SALES OF MP3 PLAYERS Sales of a certain brand of MP3 player are approximated by the relationship S(x)  6000x  30,000

(0 x 5)

where S(x) denotes the number of MP3 players sold in year x (x  0 corresponds to 2005). Find the number of MP3 players expected to be sold in 2010. 30. COMPANY SALES A company’s total sales (in millions of dollars) are approximately linear as a function of time (in years). Sales in 2004 were $2.4 million, whereas sales in 2009 amounted to $7.4 million. a. Find an equation giving the company’s sales as a function of time. b. What were the sales in 2007? 31. PROFIT FUNCTIONS A company has a fixed cost of $30,000 and a production cost of $6 for each CD it manufactures. Each CD sells for $10. a. What is the cost function? b. What is the revenue function? c. What is the profit function? d. Compute the profit (loss) corresponding to production levels of 6000, 8000, and 12,000 units, respectively. 32. LINEAR DEPRECIATION An office building worth $6 million when it was completed in 2005 is being depreciated linearly over 30 years. a. What is the rate of depreciation? b. What will be the book value of the building in 2015?

BEFORE MOVING ON . . .

33. DEMAND EQUATIONS There is no demand for a certain commodity when the unit price is $200 or more, but for each $10 decrease in price below $200, the quantity demanded increases by 200 units. Find the demand equation and sketch its graph. 34. SUPPLY EQUATIONS Bicycle suppliers will make 200 bicycles available in the market per month when the unit price is $50 and 2000 bicycles available per month when the unit price is $100. Find the supply equation if it is known to be linear. 35. CLARK’S RULE Clark’s rule is a method for calculating pediatric drug dosages based on a child’s weight. If a denotes the adult dosage (in milligrams) and if w is the weight of the child (in pounds), then the child’s dosage is given by aw D(w)  150

If the adult dose of a substance is 500 mg, how much should a child who weighs 35 lb receive? 36. COLLEGE ADMISSIONS The accompanying data were compiled by the Admissions Office of Carter College during the past 5 yr. The data relate the number of college brochures and follow-up letters (x) sent to a preselected list of high school juniors who took the PSAT and the number of completed applications (y) received from these students (both measured in thousands). Brochures Sent, x Applications Completed, y

1.8 0.4

2 0.5

3.2 0.7

4 1

4.8 1.3

a. Derive an equation of the straight line L that passes through the points (2, 0.5) and (4, 1). b. Use this equation to predict the number of completed applications that might be expected if 6400 brochures and follow-up letters are sent out during the next year. 37. REVENUE FUNCTIONS The monthly revenue R (in hundreds of dollars) realized in the sale of Royal electric shavers is related to the unit price p (in dollars) by the equation

151

1 R(p)   p2  30p 2

Find the revenue when an electric shaver is priced at $30. 38. HEALTH CLUB MEMBERSHIP The membership of the newly opened Venus Health Club is approximated by the function N(x)  200(4  x)1/2

(1 x 24)

where N(x) denotes the number of members x mo after the club’s grand opening. Find N(0) and N(12) and interpret your results. 39. THURSTONE LEARNING CURVE Psychologist L. L. Thurstone discovered the following model for the relationship between the learning time T and the length of a list n: T  f(n)  An 2n  b

where A and b are constants that depend on the person and the task. Suppose that, for a certain person and a certain task, A  4 and b  4. Compute f(4), f(5), . . . , f(12) and use this information to sketch the graph of the function f. Interpret your results. 40. MARKET EQUILIBRIUM The monthly demand and supply functions for the Luminar desk lamp are given by p  d(x)  1.1x 2  1.5x  40 p  s(x)  0.1x 2  0.5x  15

respectively, where p is measured in dollars and x in units of a thousand. Find the equilibrium quantity and price. 41. INFLATING A BALLOON A spherical balloon is being inflated at a rate of 92␲ ft3/min. a. Find a function f giving the radius r of the balloon in terms of its volume V. 4

Hint: V  3␲ r 3.

b. Find a function t giving the volume of the balloon in terms of time t. c. Find a function h giving the radius of the balloon in terms of time. d. What is the radius of the balloon after 8 min?

CHAPTER 2 Before Moving On . . . 1. Find an equation of the line that passes through (1, 2) and (4, 5). 2. Find an equation of the line that has slope 31 and y-intercept 4 3. 3. Let f(x) 

2x  1 2 2

x

1 x 0 0 x 2

Find (a) f(1), (b) f(0), and (c) f 1 32 2 .

4. Let f(x)  x 1 1 and t(x)  x 2  1. Find the rules for (a) f  t, (b) ft, (c) f 폶 t, and (d) t 폶 f.

5. Postal regulations specify that a parcel sent by parcel post may have a combined length and girth of no more than 108 in. Suppose a rectangular package that has a square cross section of x in.  x in. is to have a combined length and girth of exactly 108 in. Find a function in terms of x giving the volume of the package. Hint: The length plus the girth is 4x  h (see the accompanying figure). x x

h

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3

EXPONENTIAL AND LOGARITHMIC FUNCTIONS

T

HE EXPONENTIAL FUNCTION is without doubt the most important function in mathematics and its applications.

After a brief introduction to the exponential function and its

inverse, the logarithmic function, we explore some of the many applications involving exponential functions, such as the growth

radioactive matter decays, the rate at which a factory worker learns a certain process, and the rate at which a communicable disease is spread over time. Exponential functions also play an important role in computing interest earned in a bank account, a topic to be discussed in Chapter 4.

© Hugh Threlfall/Alamy

rate of a bacteria population in the laboratory, the way

How many cameras can a new employee at Eastman Optical assemble after completing the basic training program, and how many cameras can he assemble after being on the job for 6 months? In Example 5, page 174, you will see how to answer these questions.

154

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

3.1 Exponential Functions Exponential Functions and Their Graphs Suppose you deposit a sum of $1000 in an account earning interest at the rate of 10% per year compounded continuously (the way most financial institutions compute interest). Then, the accumulated amount at the end of t years (0 t 20) is described by the function f, whose graph appears in Figure 1.* This function is called an exponential function. Observe that the graph of f rises rather slowly at first but very rapidly as time goes by. For purposes of comparison, we have also shown the graph of the function y  t(t)  1000(1  0.10t), giving the accumulated amount for the same principal ($1000) but earning simple interest at the rate of 10% per year. The moral of the story: It is never too early to save.

y 7000

y = f(t)

Dollars

6000 5000 4000 3000

y = g(t)

2000 1000

t 5

FIGURE 1 Under continuous compounding, a sum of money grows exponentially.

10 Years

15

20

Exponential functions play an important role in many real-world applications, as you will see throughout this chapter. Observe that whenever b is a positive number and n is any real number, the expression bn is a real number. This enables us to define an exponential function as follows:

Exponential Function

The function defined by f(x)  b x

(b  0, b  1)

is called an exponential function with base b and exponent x. The domain of f is the set of all real numbers.

For example, the exponential function with base 2 is the function f(x)  2 x

with domain (, ). The values of f(x) for selected values of x follow: 3 f a b  23/2  2 # 21/2  2 12 f 102  20  1 2 1 2 1 1 f 112  21  f a  b  22/3  2/3  3 2 3 2 24 f 132  23  8

*We will derive the rule for f in Section 4.1.

3.1 EXPONENTIAL FUNCTIONS

155

Computations involving exponentials are facilitated by the laws of exponents. These laws were stated in Section 1.5, and you might want to review the material there. For convenience, however, we will restate these laws. Laws of Exponents

Let a and b be positive numbers and let x and y be real numbers. Then, 1. b x  b y  b xy

4. (ab)x  axbx

bx  b xy by

a x ax 5. a b  x b b

2.

3. (b x ) y  b xy

The use of the laws of exponents is illustrated in the next two examples. EXAMPLE 1 a. 16 7/4  161/2  16 7/41/2  165/4  25  32 Law 1 85/3 b. 1/3  85/3 11/32  82  64 Law 2 8 c. 1644/3 2 1/2  6414/3211/22  642/3 1 1 1 1  2 Law 3  2/3  16 64 1641/3 2 2 4 1 1 1 1 1 d. 116 # 812 1/4  161/4 # 811/4  1/4 # 1/4  #  2 3 6 16 81 1/2 4 4/2 3 3 9 e. a 1/3 b  4/3  4/3 Law 5 2 2 2

Law 4

EXAMPLE 2 Let f (x)  22x1. Find the value of x for which f (x)  16. Solution

We want to solve the equation 22x1  16  24

But this equation holds if and only if 2x  1  4

bm  bn ⇒ m  n

giving x  52 . Exponential functions play an important role in mathematical analysis. Because of their special characteristics, they are some of the most useful functions and are found in virtually every field where mathematics is applied. To mention a few examples: Under ideal conditions, the number of bacteria present at any time t in a culture may be described by an exponential function of t; radioactive substances decay over time in accordance with an “exponential” law of decay; money left on fixed deposit and earning compound interest grows exponentially; and some of the most important distribution functions encountered in statistics are exponential. Let’s begin our investigation into the properties of exponential functions by studying their graphs. EXAMPLE 3 Sketch the graph of the exponential function y  2 x. Solution First, as discussed earlier, the domain of the exponential function y  f(x)  2 x is the set of real numbers. Next, putting x  0 gives y  20  1, the

156

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

y-intercept of f. There is no x-intercept since there is no value of x for which y  0. To find the range of f, consider the following table of values:

y

4

2

x –2

2

FIGURE 2

The graph of y  2 x

x

5

4

3

2

1

0

1

2

3

4

5

y

1 32

1 16

1 8

1 4

1 2

1

2

4

8

16

32

We see from these computations that 2x decreases and approaches zero as x decreases without bound and that 2 x increases without bound as x increases without bound. Thus, the range of f is the interval (0, )—that is, the set of positive real numbers. Finally, we sketch the graph of y  f(x)  2 x in Figure 2. EXAMPLE 4 Sketch the graph of the exponential function y  (1/2)x.

y

The domain of the exponential function y  (1/2)x is the set of all real numbers. The y-intercept is (1/2)0  1; there is no x-intercept since there is no value of x for which y  0. From the following table of values Solution

4

5

x

2

32

y

4 16

3 8

2 4

1 2

0

1

2

3

4

5

1

1 2

1 4

1 8

1 16

1 32

x –2

2

we deduce that (1/2) x  1/2x increases without bound as x decreases without bound and that (1/2) x decreases and approaches zero as x increases without bound. Thus, the range of f is the interval (0, ). The graph of y  f(x)  (1/2) x is sketched in Figure 3.

FIGURE 3

The graph of y  (1/2) x

y

y = bx (0 < b < 1)

y = bx (b > 1) y =1

The functions y  2 x and y  (1/2) x, whose graphs you studied in Examples 3 and 4, are special cases of the exponential function y  f(x)  b x, obtained by setting b  2 and b  1/2, respectively. In general, the exponential function y  b x with b  1 has a graph similar to y  2 x, whereas the graph of y  b x for 0 b 1 is similar to that of y  (1/2)x (Exercises 23 and 24 on page 158). When b  1, the function y  b x reduces to the constant function y  1. For comparison, the graphs of all three functions are sketched in Figure 4.

x

Properties of the Exponential Function FIGURE 4

y  b x is an increasing function of x if b  1, a constant function if b  1, and a decreasing function if 0 b 1.

The exponential function y  b x (b  0, b  1) has the following properties: 1. 2. 3. 4. 5.

Its domain is (, ). Its range is (0, ). Its graph passes through the point (0, 1). Its graph is an unbroken curve devoid of holes or jumps. Its graph rises from left to right if b  1 and falls from left to right if b 1.

The Base e It can be shown, although we will not do so here, that as m gets larger and larger, the value of the expression a1 

1 m b m

3.1 EXPONENTIAL FUNCTIONS

approaches the irrational number 2.7182818, which we denote by e. You may convince yourself of the plausibility of this definition of the number e by examining Table 1, which may be constructed with the help of a calculator. (Also, see the Exploring with Technology exercise that follows.)

TABLE 1 a1 

m

10 100 1000 10,000 100,000 1,000,000

157

1 m b m

2.59374 2.70481 2.71692 2.71815 2.71827 2.71828

Exploring with

TECHNOLOGY To obtain a visual confirmation of the fact that the expression (1  1/m)m approaches the number e  2.71828. . . as m gets larger and larger, plot the graph of f(x)  (1  1/x)x in a suitable viewing window and observe that f(x) approaches 2.71828. . . as x gets larger and larger. Use ZOOM and TRACE to find the value of f(x) for large values of x.

EXAMPLE 5 Sketch the graph of the function y  e x. y

Since e  1, it follows from our previous discussion that the graph of y  e x is similar to the graph of y  2 x (see Figure 2). With the aid of a calculator, we obtain the following table:

Solution 5

3

1

x

3

2

1

0

1

2

3

y

0.05

0.14

0.37

1

2.72

7.39

20.09

x –3

–1

1

3

The graph of y  e x is sketched in Figure 5.

FIGURE 5

The graph of y  e x

Next, we consider another exponential function to the base e that is closely related to the previous function and is particularly useful in constructing models that describe “exponential decay.” EXAMPLE 6 Sketch the graph of the function y  ex.

y

Since e  1, it follows that 0 1/e 1, so f(x)  ex  1/e x  (1/e)x is an exponential function with base less than 1. Therefore, it has a graph similar to that of the exponential function y  (1/2)x. As before, we construct the following table of values of y  ex for selected values of x: Solution

5

3

1 x –3

–1

1

3

FIGURE 6

The graph of y  ex

x

3

2

1

0

1

2

3

y

20.09

7.39

2.72

1

0.37

0.14

0.05

Using this table, we sketch the graph of y  ex in Figure 6.

3.1 Self-Check Exercises 1. Solve the equation 22x1  23  2 x1. 2. Sketch the graph of y  e0.4x.

Solutions to Self-Check Exercises 3.1 can be found on page 160.

158

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

3.1 Concept Questions 1. Define the exponential function f with base b and exponent x. What restrictions, if any, are placed on b?

2. For the exponential function y  b x (b  0, b  1), state (a) its domain and range, (b) its y-intercept, (c) where its graph rises and where it falls for the case b  1 and the case b 1.

3.1 Exercises In Exercises 1–8, evaluate the expression.

1. a. 43  45

b. 33  36

2. a. (21)3

b. (32)3

3. a. 9(9)1/2

b. 5(5)1/2

1 3 2 4. a. c a  b d 2

1 2 3 b. ca b d 3

132 4 132 5 5. a. 8 132

124 2 126 2 b. 1 2

6. a. 31/4  95/8

b. 23/4  43/2

25. y  2x, y  3x, and y  4x 26. y  40.5x and y  40.5x

7. a. (64x 9)1/3

b. (25x 3y 4)1/2

8. a. (2x 3)(4x2)

b. (4x2)(3x 5)

6a5 3a3 3/2

10. a. y

4b4 b. 6 12b y

5/3

11. a. (2x 3y 2)3 5 12. a. 3 3 2 2 12 x y 2

b.

1x  y 2 1x  y 2 1x  y 2 0

13. 6 2x  64

14. 5x  53

15. 33x4  35

16. 102x1  10 x3

17. (2.1) x2  (2.1)5

18. (1.3)x2  (1.3)2x1

19. 8x  a

20. 3xx 

2

31. y  0.5ex, y  ex, and y  2ex 32. y  1  ex and y  1  e0.5x 33. A function f has the form f(x)  Ae kx. Find f if it is known that f(0)  100 and f(1)  120.

Hint: e kx  (e k )x.

x

In Exercises 13–22, solve the equation for x.

1 x2 b 32

30. y  e0.5x, y  ex, and y  e1.5x

34. If f(x)  Axe kx, find f(3) if f(1)  5 and f(2)  7.

b. (4x 2y 2z 3)2

0

28. y  e x, y  2e x, and y  3e x

Hint: e kx  (e k )x.

3/5 8/3

b. x

27. y  40.5x, y  4x, and y  42x

29. y  e0.5x, y  e x, and y  e1.5x

In Exercises 7–12, simplify the expression.

9. a.

1 x 1 x 1 x 24. y  a b , y  a b , and y  a b 2 3 4

1 9x

21. 32x  12  3 x  27  0

35. If f 1t2 

1000 1  Be kt

find f(5) given that f (0)  20 and f(2)  30.

Hint: e kx  (e k )x.

36. TRACKING WITH GPS Employers are increasingly turning to GPS (global positioning system) technology to keep track of their fleet vehicles. The estimated number of automatic vehicle trackers installed on fleet vehicles in the United States is approximated by N(t)  0.6e0.17t

(0 t 5)

In Exercises 23–32, sketch the graphs of the given functions on the same axes.

where N(t) is measured in millions and t is measured in years, with t  0 corresponding to 2000. a. What was the number of automatic vehicle trackers installed in the year 2000? How many were projected to be installed in 2005? b. Sketch the graph of N.

23. y  2x, y  3x, and y  4x

Source: C. J. Driscoll Associates

22. 22x  4  2x  4  0

3.1 EXPONENTIAL FUNCTIONS

37. DISABILITY RATES Because of medical technology advances, the disability rates for people over 65 yr old have been dropping rather dramatically. The function R(t)  26.3e0.016t

(0 t 18)

gives the disability rate R(t), in percent, for people over age 65 from 1982 (t  0) through 2000, where t is measured in years. a. What was the disability rate in 1982? In 1986? In 1994? In 2000? b. Sketch the graph of R. Source: Frost and Sullivan

38. MARRIED HOUSEHOLDS The percentage of families that were married households between 1970 and 2000 is approximately P(t)  86.9e0.05t

(0 t 3)

where t is measured in decades, with t  0 corresponding to the beginning of 1970. a. What percentage of families were married households at the beginning of 1970, 1980, 1990, and 2000? b. Sketch the graph of P. Source: U.S. Census Bureau

39. GROWTH OF WEB SITES According to a study conducted in 2000, the projected number of Web addresses (in billions) is approximated by the function N(t)  0.45e0.5696t

(0 t 5)

where t is measured in years, with t  0 corresponding to the beginning of 1997. a. Complete the following table by finding the number of Web addresses in each year: Year Number of Web Addresses (billions)

0

1

2

3

4

5

40. INTERNET USERS IN CHINA The number of Internet users in China is projected to be (1 t 6)

where N(t) is measured in millions and t is measured in years, with t  1 corresponding to the beginning of 2005. a. How many Internet users were there at the beginning of 2005? At the beginning of 2006? b. How many Internet users are there expected to be at the beginning of 2010? c. Sketch the graph of N. Source: C. E. Unterberg

41. ALTERNATIVE MINIMUM TAX The alternative minimum tax was created in 1969 to prevent the very wealthy from using creative deductions and shelters to avoid having to pay anything to the Internal Revenue Service. But it has increasingly hit the middle class. The number of taxpayers subjected to an alternative minimum tax is projected to be N 1t 2 

35.5 1  6.89e 0.8674t

10 t 62

where N(t) is measured in millions and t is measured in years, with t  0 corresponding to 2004. What is the projected number of taxpayers subjected to an alternative minimum tax in 2010? Source: Brookings Institution

42. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by C 1t2  e

0.3t  1811  e t/60 2 18e t/60  12e 1t202/60

if 0 t 20 if t  20

where C(t) is measured in grams/cubic centimeter (g/cm3). a. What is the initial concentration of the drug in the organ? b. What is the concentration of the drug in the organ after 10 sec? c. What is the concentration of the drug in the organ after 30 sec? 43. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by x(t)  0.08  0.12(1  e0.02t )

where x(t) is measured in grams/cubic centimeter (g/cm3). a. What is the initial concentration of the drug in the organ? b. What is the concentration of the drug in the organ after 20 sec? 44. ABSORPTION OF DRUGS Jane took 100 mg of a drug in the morning and another 100 mg of the same drug at the same time the following morning. The amount of the drug in her body t days after the first dosage was taken is given by

b. Sketch the graph of N.

N(t)  94.5e0.2t

159

A 1t 2  e

100e1.4t 10011  e1.4 2e1.4t

if 0 t 1 if t  1

What was the amount of drug in Jane’s body immediately after taking the second dose? After 2 days? In Exercises 45–48, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

45. (x 2  1)3  x 6  1

46. e xy  e xe y

47. If x y, then e x e y. 48. If 0 b 1 and x y, then b x  b y.

160

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

3.1 Solutions to Self-Check Exercises 1.

22x1  23  2x1 22x1 # 3 2 1 2x1

Next, we plot these points and join them by a smooth curve to obtain the graph of f shown in the accompanying figure. Divide both sides by 2 x1.

y

212x12  1x12 3  1 2x1  1

This is true if and only if x  1  0 or x  1. y = e 0.4 x

2. We first construct the following table of values: 1

x y ⫽ e0.4x

3 0.3

USING

2 0.4

1 0.7

TECHNOLOGY

0 1

1 1.5

2 2.2

3 3.3

4 5

x –4 –3 –2 –1

1

2

3

4

Although the proof is outside the scope of this book, it can be proved that an exponential function of the form f(x)  b x, where b  1, will ultimately grow faster than the power function t(x)  x n for any positive real number n. To give a visual demonstration of this result for the special case of the exponential function f(x)  e x, we can use a graphing utility to plot the graphs of both f and t (for selected values of n) on the same set of axes in an appropriate viewing window and observe that the graph of f ultimately lies above that of t. EXAMPLE 1 Use a graphing utility to plot the graphs of (a) f(x)  e x and t(x)  x 3 on the same set of axes in the viewing window [0, 6]  [0, 250] and (b) f(x)  e x and t(x)  x 5 in the viewing window [0, 20]  [0, 1,000,000]. Solution

a. The graphs of f(x)  e x and t(x)  x 3 in the viewing window [0, 6]  [0, 250] are shown in Figure T1a. b. The graphs of f(x)  e x and t(x)  x 5 in the viewing window [0, 20]  [0, 1,000,000] are shown in Figure T1b.

FIGURE T1

(a) The graphs of f(x)  e x and g(x)  x 3 in the viewing window [0, 6]  [0, 250]

(b) The graphs of f(x)  e x and g(x)  x 5 in the viewing window [0, 20]  [0, 1,000,000]

In the exercises that follow, you are asked to use a graphing utility to reveal the properties of exponential functions.

3.1 EXPONENTIAL FUNCTIONS

161

TECHNOLOGY EXERCISES In Exercises 1 and 2, plot the graphs of the functions f and g on the same set of axes in the specified viewing window.

1. f (x)  e x and t(x)  x 2; [0, 4]  [0, 30] 2. f(x)  e x and t(x)  x 4; [0, 15]  [0, 20,000] In Exercises 3 and 4, plot the graphs of the functions f and g on the same set of axes in an appropriate viewing window to demonstrate that f ultimately grows faster than g. (Note: Your answer will not be unique.)

3. f (x)  2 and t(x)  x x

2.5

4. f (x)  3 x and t(x)  x 3 5. Plot the graphs of f (x)  2 x, t(x)  3x, and h(x)  4x on the same set of axes in the viewing window [0, 5]  [0, 100]. Comment on the relationship between the base b and the growth of the function f(x)  b x. 6. Plot the graphs of f (x)  (1/2) x, t(x)  (1/3) x, and h(x)  (1/4) x on the same set of axes in the viewing window [0, 4]  [0, 1]. Comment on the relationship between the base b and the growth of the function f (x)  b x. 7. Plot the graphs of f(x)  e x, t(x)  2e x, and h(x)  3e x on the same set of axes in the viewing window [3, 3]  [0, 10]. Comment on the role played by the constant k in the graph of f (x)  ke x. 8. Plot the graphs of f (x)  e x, t(x)  2e x, and h(x)  3e x on the same set of axes in the viewing window [3, 3]  [10, 0]. Comment on the role played by the constant k in the graph of f(x)  ke x. 9. Plot the graphs of f(x)  e , t(x)  e , and h(x)  e on the same set of axes in the viewing window [2, 2]  [0, 4]. Comment on the role played by the constant k in the graph of f (x)  e kx. 0.5x

x

1.5x

10. Plot the graphs of f (x)  e0.5x, t(x)  ex, and h(x)  e1.5x on the same set of axes in the viewing window [2, 2]  [0, 4]. Comment on the role played by the constant k in the graph of f (x)  e kx. 11. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by x(t)  0.08  0.12(1  e0.02t )

where x(t) is measured in grams/cubic centimeter (g/cm3). a. Plot the graph of the function x in the viewing window [0, 200]  [0, 0.2].

b. What is the initial concentration of the drug in the organ? c. What is the concentration of the drug in the organ after 20 sec? 12. ABSORPTION OF DRUGS Jane took 100 mg of a drug in the morning and another 100 mg of the same drug at the same time the following morning. The amount of the drug in her body t days after the first dosage was taken is given by A 1t2  e

100e1.4t 10011  e1.4 2e1.4t

if 0 t 1 if t  1

a. Plot the graph of the function A in the viewing window [0, 5]  [0, 140]. b. Verify the results of Exercise 44, page 159. 13. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by C 1t2  e

0.3t  1811  e t/60 2 18e t/60  12e 1t202/60

if 0 t 20 if t  20

where C(t) is measured in grams/cubic centimeter (g/cm3). a. Plot the graph of the function C in the viewing window [0, 120]  [0, 1]. b. How long after the drug is first introduced will it take for the concentration of the drug to reach a peak? c. How long after the concentration of the drug has peaked will it take for the concentration of the drug to fall back to 0.5 g/cm3? Hint: Plot the graphs of y1  C(x) and y2  0.5 and use the ISECT function of your graphing utility.

14. MODELING WITH DATA The number of Internet users in China (in millions) from the beginning of 2005 through 2010 are shown in the following table: Year Number

2005 116.1

2006 141.9

2007 169.0

2008 209.0

2009 258.1

2010 314.8

a. Use ExpReg to find an exponential regression model for the data. Let t  1 correspond to the beginning of 2005. Hint: a x  e x ln a.

b. Plot the scatter diagram and the graph of the function f found in part (a).

162

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

3.2 Logarithmic Functions Logarithms You are already familiar with exponential equations of the form by  x

(b  0, b  1)

where the variable x is expressed in terms of a real number b and a variable y. But what about solving this same equation for y? You may recall from your study of algebra that the number y is called the logarithm of x to the base b and is denoted by logb x. It is the power to which the base b must be raised in order to obtain the number x. Logarithm of x to the Base b y  logb x if and only if

x  by

(x  0)

Observe that the logarithm logb x is defined only for positive values of x. EXAMPLE 1 a. log10 100  2 since 100  102 b. log5 125  3 since 125  53 1 1 1  3 since  3  33 c. log3 27 27 3 d. log20 20  1 since 20  201 EXAMPLE 2 a. log3 x  4

Solve each of the following equations for x. b. log16 4  x

c. log x 8  3

Solution

a. By definition, log3 x  4 implies x  34  81. b. log16 4  x is equivalent to 4  16 x  (42 ) x  42x, or 41  42x, from which we deduce that 2x  1 1 x 2

bm  bn 1 m  n

c. Referring once again to the definition, we see that the equation log x 8  3 is equivalent to 8  23  x 3 x2 am  bm 1 a  b

The two most widely used systems of logarithms are the system of common logarithms, which uses the number 10 as its base, and the system of natural logarithms, which uses the irrational number e  2.71828. . . as its base. Also, it is standard practice to write log for log10 and ln for loge. Logarithmic Notation log x  log10 x ln x  loge x

Common logarithm Natural logarithm

3.2 LOGARITHMIC FUNCTIONS

163

The system of natural logarithms is widely used in theoretical work. Using natural logarithms rather than logarithms to other bases often leads to simpler expressions.

Laws of Logarithms Computations involving logarithms are facilitated by the following laws of logarithms.

Laws of Logarithms

If m and n are positive numbers (b  0, b ⬆ 1), then 1. log b mn  log b m  log b n

m  logb m  logb n n 3. log b m n  n log b m 4. log b 1  0 5. log b b  1 2. logb

log m m Do not confuse the expression log (Law 2) with the expression . For n log n example, log

log 100 100 2  log 100  log 10  2  1  1   2 10 log 10 1

You will be asked to prove these laws in Exercises 74–76 on page 170. Their derivations are based on the definition of a logarithm and the corresponding laws of exponents. The following examples illustrate the properties of logarithms. EXAMPLE 3 a. log(2  3)  log 2  log 3 c. log 17  log 71/2 

b. ln

1 log 7 2

5  ln 5  ln 3 3

d. log 5 1  0

e. log 45 45  1 EXAMPLE 4 Given that log 2  0.3010, log 3  0.4771, and log 5  0.6990, use the laws of logarithms to find a. log 15

b. log 7.5

c. log 81

d. log 50

Solution

a. Note that 15  3  5, so by Law 1 for logarithms,

log 15  log 3 # 5  log 3  log 5  0.4771  0.6990  1.1761

164

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

b. Observing that 7.5  15/2  (3  5)/2, we apply Laws 1 and 2, obtaining log 7.5  log

132 152

2  log 3  log 5  log 2  0.4771  0.6990  0.3010  0.8751

c. Since 81  34, we apply Law 3 to obtain log 81    

log 34 4 log 3 410.47712 1.9084

d. We write 50  5  10 and find log 50  log(5)(10)  log 5  log 10 Use Law 5  0.6990  1  1.6990

EXAMPLE 5 Expand and simplify the following expressions: a. log3 x 2y 3

b. log2

x2  1 2x

c. ln

x 2 2x 2  1 ex

Solution

a. log3 x 2y 3  log3 x 2  log3 y 3  2 log3 x  3 log3 y b. log2

c. ln

Law 1 Law 3

x2  1  log2 1x 2  12  log2 2x 2x  log2 1x 2  1 2  x log2 2  log2 1x 2  1 2  x

Law 2 Law 3 Law 5

x 2 1x 2  12 1/2 x 2 2x 2  1  ln Rewrite ex ex  ln x 2  ln1x 2  12 1/2  ln e x 1  2 ln x  ln1x 2  12  x ln e 2 1  2 ln x  ln1x 2  12  x 2

Laws 1 and 2 Law 3

Law 5

Examples 6 and 7 illustrate how the properties of logarithms are used to solve equations. EXAMPLE 6 Solve log3(x  1)  log3(x  1)  1 for x. Solution

Using the properties of logarithms, we obtain log3(x  1)  log3(x  1)  1 x1 1 log3 x1 x1  31  3 x1

Law 2

Definition of logarithms

3.2 LOGARITHMIC FUNCTIONS

165

So, x  1  3(x  1) x  1  3x  3 4  2x x2 EXAMPLE 7 Solve log x  log(2x  1)  log 6. Solution

We have log x  log(2x  1)  log 6 log x  log(2x  1)  log 6  0 log c

x12x  1 2

6 x12x  1 2 6

d 0

Laws 1 and 2

 100  1

Definition of logarithms

So, x(2x  1)  6 2x  x  6  0 (2x  3)(x  2)  0 2

x

3 2

or 2

Since the domain of log(2x  1) is the interval 1 12,  2 (because 2x  1 must be positive), we reject the root 32 of the quadratic equation and conclude that the solution of the given equation is x  2. Using the fact that log a  log b if and only if a  b, we can also solve the equation of Example 7:

Note

log x  log(2x  1)  log 6 log x(2x  1)  log 6 x(2x  1)  6

The rest of the solution is the same as that in Example 7.

Logarithmic Functions and Their Graphs The definition of a logarithm implies that if b and n are positive numbers and b is different from 1, then the expression logb n is a real number. This enables us to define a logarithmic function as follows.

Logarithmic Function

The function defined by f(x)  logb x

(b  0, b  1)

is called the logarithmic function with base b. The domain of f is the set of all positive numbers.

166

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

One easy way to obtain the graph of the logarithmic function y  log b x is to construct a table of values of the logarithm (base b). However, another method—and a more instructive one—is based on exploiting the intimate relationship between logarithmic and exponential functions. If a point (u, √) lies on the graph of y  log b x, then

y y=x

(√, u) u

(u, √ )

√

√  log b u

But we can also write this equation in exponential form as √

x

u

FIGURE 7 The points (u, v) and (v, u) are mirror reflections of each other.

y

y = bx y=x

1

y = log bx x 1

u  b√

So the point (√, u) also lies on the graph of the function y  b x. Let’s look at the relationship between the points (u, √) and (√, u) and the line y  x (Figure 7). If we think of the line y  x as a mirror, then the point (√, u) is the mirror reflection of the point (u, √). Similarly, the point (u, √) is a mirror reflection of the point (√, u). We can take advantage of this relationship to help us draw the graph of logarithmic functions. For example, if we wish to draw the graph of y  log b x, where b  1, then we need only draw the mirror reflection of the graph of y  b x with respect to the line y  x (Figure 8). You may discover the following properties of the logarithmic function by taking the reflection of the graph of an appropriate exponential function (Exercises 47 and 48 on page 169). Properties of the Logarithmic Function

The logarithmic function y  log b x (b  0, b  1) has the following properties:

FIGURE 8

The graphs of y  b x and y  log b x are mirror reflections of each other.

y

1. 2. 3. 4. 5.

Its domain is (0, ). Its range is (, ). Its graph passes through the point (1, 0). Its graph is an unbroken curve devoid of holes or jumps. Its graph rises from left to right if b  1 and falls from left to right if b 1.

EXAMPLE 8 Sketch the graph of the function y  ln x.

y = ex y=x

We first sketch the graph of y  e x. Then, the required graph is obtained by tracing the mirror reflection of the graph of y  e x with respect to the line y  x (Figure 9).

Solution 1

y = ln x x 1

Properties Relating the Exponential and Logarithmic Functions FIGURE 9

The graph of y  ln x is the mirror reflection of the graph of y  e x.

We made use of the relationship that exists between the exponential function f (x)  e x and the logarithmic function t(x)  ln x when we sketched the graph of t in Example 8. This relationship is further described by the following properties, which are an immediate consequence of the definition of the logarithm of a number. Properties Relating e x and ln x eln x  x ln e x  x

(Try to verify these properties.)

(x  0) (for any real number x)

(1) (2)

3.2 LOGARITHMIC FUNCTIONS

167

From Properties 1 and 2, we conclude that the composite function 1 f ⴰ t2 1x2  f 3t 1x2 4  e ln x  x 1t ⴰ f 2 1x2  t3 f 1x2 4  ln e x  x

Thus, f [t(x)]  t[ f (x)] x

Any two functions f and t that satisfy this relationship are said to be inverses of each other. Note that the function f undoes what the function t does, and vice versa, so the composition of the two functions in any order results in the identity function F(x)  x. The relationships expressed in Equations (1) and (2) are useful in solving equations that involve exponentials and logarithms.

Exploring with

TECHNOLOGY You can demonstrate the validity of Properties 1 and 2, which state that the exponential function f (x)  e x and the logarithmic function t(x)  ln x are inverses of each other, as follows: 1. Sketch the graph of ( f 폶 t)(x)  eln x, using the viewing window [0, 10]  [0, 10]. Interpret the result. 2. Sketch the graph of ( t 폶 f )(x)  ln e x, using the standard viewing window. Interpret the result. EXAMPLE 9 Solve the equation 2e x2  5. Solution

We first divide both sides of the equation by 2 to obtain e x2 

5  2.5 2

Next, taking the natural logarithm of each side of the equation and using Equation (2), we have ln e x2  ln 2.5 x  2  ln 2.5 x  2  ln 2.5  1.08

Explore & Discuss Consider the equation y  y0 b kx, where y0 and k are positive constants and b  0, b  1. Suppose we want to express y in the form y  y0 e px. Use the laws of logarithms to show that p  k ln b and hence that y  y0 e (k ln b)x is an alternative form of y  y 0 b kx using the base e.

EXAMPLE 10 Solve the equation 5 ln x  3  0. Solution

Adding 3 to both sides of the equation leads to 5 ln x  3 3 ln x    0.6 5

and so e ln x  e 0.6

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3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

Using Equation (1), we conclude that x  e 0.6  0.55

3.2 Self-Check Exercises 1. Sketch the graph of y  3x and y  log 3 x on the same set of axes.

Solutions to Self-Check Exercises 3.2 can be found on page 170.

2. Solve the equation 3e x1  2  4.

3.2 Concept Questions 1. a. Define y  logb x. b. Define the logarithmic function f with base b. What restrictions, if any, are placed on b?

3. a. If x  0, what is eln x ? b. If x is any real number, what is ln ex ?

2. For the logarithmic function y  logb x (b  0, b  1), state (a) its domain and range, (b) its x-intercept, (c) where its graph rises and where it falls for the case b  1 and the case b 1.

3.2 Exercises In Exercises 1–10, express each equation in logarithmic form.

1. 26  64 3. 32 

1 9

2. 35  243 4. 53 

1 125

1 1 1 5. a b  3 3

1 4 6. a b  16 2

7. 323/5  8

8. 813/4  27

9. 103  0.001

10. 161/4  0.5

In Exercises 11–16, given that log 3 ⬇ 0.4771 and log 4 ⬇ 0.6021, find the value of each logarithm.

3 4

19. ln 3 

1 1 ln x  ln y  ln z 2 3

20. ln 2 

1 ln1x  1 2  2 ln11  1x2 2

In Exercises 21–28, use the laws of logarithms to expand and simplify the expression.

21. log x(x  1)4 23. log

1x  1 x2  1

25. ln xex

x

24. ln

ex 1  ex

26. ln x(x  1)(x  2)

2

27. ln

22. log x(x 2  1)1/2

1/2

x 2 21  x 2

28. ln

x2 1x11  x2 2

In Exercises 29–42, use the laws of logarithms to solve the equation.

11. log 12

12. log

13. log 16

14. log 13

29. log2 x  3

30. log3 x  2

15. log 48

16. log

1 300

31. log2 8  x

32. log3 27  2x

33. logx 103  3

34. logx

In Exercises 17–20, write the expression as the logarithm of a single quantity.

17. 2 ln a  3 ln b

1 18. ln x  2 ln y  3 ln z 2

35. log2(2x  5)  3 36. log4(5x  4)  2

1  2 16

3.2 LOGARITHMIC FUNCTIONS

37. log2 x  log2(x  2)  3

62. MAGNITUDE OF EARTHQUAKES On the Richter scale, the magnitude R of an earthquake is given by the formula

38. log x  log(x  6)  1

R  log

39. log5(2x  1)  log5(x  2)  1 40. log(x  7)  log(x  2)  1 41. log x  log(2 x  5)  log 3 42. log3(x  1)  log3(2x  3)  1 In Exercises 43–46, sketch the graph of the equation.

43. y  log 3 x

44. y  log 1/3 x

45. y  ln 2x

46. y  ln

1 x 2

In Exercises 47 and 48, sketch the graphs of the equations on the same coordinate axes.

47. y  2 x and y  log2 x

48. y  e 3x and y 

1 ln x 3

In Exercises 49–58, use logarithms to solve the equation for t. 0.4t

49. e

8

1 50. e3t  0.9 3

51. 5e2t  6

52. 4e t1  4

53. 2e0.2t  4  6

54. 12  e0.4t  3

55.

50  20 1  4e 0.2t

57. A  Bet/2

169

56.

200  100 1  3e0.3t

A 58. t/2  C 1  Be

59. A function f has the form f (x)  a  b ln x. Find f if it is known that f(1)  2 and f(2)  4. 60. AVERAGE LIFE SPAN One reason for the increase in the life span over the years has been the advances in medical technology. The average life span for American women from 1907 through 2007 is given by W(t)  49.9  17.1 ln t

(1 t 6)

where W(t) is measured in years and t is measured in 20-yr intervals, with t  1 corresponding to 1907. a. What was the average life expectancy for women in 1907? b. If the trend continues, what will be the average life expectancy for women in 2027? Source: American Association of Retired People

61. BLOOD PRESSURE A normal child’s systolic blood pressure may be approximated by the function p(x)  m(ln x)  b

where p(x) is measured in millimeters of mercury, x is measured in pounds, and m and b are constants. Given that m  19.4 and b  18, determine the systolic blood pressure of a child who weighs 92 lb.

I I0

where I is the intensity of the earthquake being measured and I0 is the standard reference intensity. a. Express the intensity I of an earthquake of magnitude R  5 in terms of the standard intensity I0. b. Express the intensity I of an earthquake of magnitude R  8 in terms of the standard intensity I0. How many times greater is the intensity of an earthquake of magnitude 8 than one of magnitude 5? c. In modern times, the greatest loss of life attributable to an earthquake occurred in eastern China in 1976. Known as the Tangshan earthquake, it registered 8.2 on the Richter scale. How does the intensity of this earthquake compare with the intensity of an earthquake of magnitude R  5? 63. SOUND INTENSITY The relative loudness of a sound D of intensity I is measured in decibels (db), where D  10 log

I I0

and I0 is the standard threshold of audibility. a. Express the intensity I of a 30-db sound (the sound level of normal conversation) in terms of I0. b. Determine how many times greater the intensity of an 80-db sound (rock music) is than that of a 30-db sound. c. Prolonged noise above 150 db causes permanent deafness. How does the intensity of a 150-db sound compare with the intensity of an 80-db sound? 64. BAROMETRIC PRESSURE Halley’s law states that the barometric pressure (in inches of mercury) at an altitude of x mi above sea level is approximated by the equation p(x)  29.92e0.2x

(x  0)

If the barometric pressure as measured by a hot-air balloonist is 20 in. of mercury, what is the balloonist’s altitude? 65. HEIGHT OF TREES The height (in feet) of a certain kind of tree is approximated by h 1t2 

160 1  240e0.2t

where t is the age of the tree in years. Estimate the age of an 80-ft tree. 66. NEWTON’S LAW OF COOLING The temperature of a cup of coffee t min after it is poured is given by T  70  100e0.0446t

where T is measured in degrees Fahrenheit. a. What was the temperature of the coffee when it was poured? b. When will the coffee be cool enough to drink (say, 120°F)?

170

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

67. LENGTHS OF FISH The length (in centimeters) of a typical Pacific halibut t yr old is approximately f(t)  200(1  0.956e0.18t )

Suppose a Pacific halibut caught by Mike measures 140 cm. What is its approximate age? 68. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by x(t)  0.08(1  e0.02t )

where T0 is the air temperature and T1 is the body temperature at the time of death. John Doe was found murdered at midnight in his house, when the room temperature was 70°F and his body temperature was 80°F. When was he killed? Assume that the normal body temperature is 98.6°F. In Exercises 71 and 72, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

71. (ln x)3  3 ln x for all x in (0, ).

where x(t) is measured in grams/cubic centimeter (g/cm3). a. How long would it take for the concentration of the drug in the organ to reach 0.02 g/cm3? b. How long would it take for the concentration of the drug in the organ to reach 0.04 g/cm3? 69. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by x(t)  0.08  0.12e0.02t

where x(t) is measured in grams/cubic centimeter (g/cm3). a. How long would it take for the concentration of the drug in the organ to reach 0.18 g/cm3? b. How long would it take for the concentration of the drug in the organ to reach 0.16 g/cm3? 70. FORENSIC SCIENCE Forensic scientists use the following law to determine the time of death of accident or murder victims. If T denotes the temperature of a body t hr after death, then

72. ln a  ln b  ln(a  b) for all positive real numbers a and b. 73. a. Given that 2 x  e kx, find k. b. Show that, in general, if b is a nonnegative real number, then any equation of the form y  b x may be written in the form y  e kx, for some real number k. 74. Use the definition of a logarithm to prove a. logb mn  logb m  logb n m b. logb  logb m  logb n n Hint: Let log b m  p and logb n  q. Then, b p  m and b q  n.

75. Use the definition of a logarithm to prove logb m n  n log b m

76. Use the definition of a logarithm to prove a. log b 1  0 b. log b b  1

T  T0  (T1  T0)(0.97)t

3.2 Solutions to Self-Check Exercises 1. First, sketch the graph of y  3x with the help of the following table of values: x y  3x

3 1/27

2 1/9

1 1/3

0 0

1 3

2 9

3 27

Next, take the mirror reflection of this graph with respect to the line y  x to obtain the graph of y  log3 x. 2. 3e x1  2  4 3e x1  6 e x1  2 ln e x1  ln 2

Take the logarithm of both sides.

(x  1)ln e  ln 2

Law 3

x  1  ln 2

Law 5

x  ln 2  1  0.3069

y y=x

y = 3x 6 4

y = log 3 x

2 x 2

4

6

8

3.3 EXPONENTIAL FUNCTIONS AS MATHEMATICAL MODELS

171

3.3 Exponential Functions as Mathematical Models Exponential Growth

Q

Q = Q0ekt

Q0 t FIGURE 10 Exponential growth

Many problems arising from practical situations can be described mathematically in terms of exponential functions or functions closely related to the exponential function. In this section, we look at some applications involving exponential functions from the fields of the life and social sciences. In Section 3.1, we saw that the exponential function f(x)  b x is an increasing function when b  1. In particular, the function f(x)  e x shares this property. From this result, one may deduce that the function Q(t)  Q0 e kt, where Q0 and k are positive constants, has the following properties: 1. Q(0)  Q0 2. Q(t) increases “rapidly” without bound as t increases without bound (Figure 10). Property 1 follows from the computation Q(0)  Q0 e 0  Q0

The exponential function Q(t)  Q0 e kt

(0 t )

(3)

provides us with a mathematical model of a quantity Q(t) that is initially present in the amount of Q(0)  Q0 and whose rate of growth at any time t is directly proportional to the amount of the quantity present at time t (see Example 5, Section 9.7). Such a quantity is said to exhibit exponential growth, and the constant k of proportionality is called the growth constant. Interest earned on a fixed deposit when compounded continuously exhibits exponential growth (Chapter 4). Other examples of unrestricted exponential growth follow.

APPLIED EXAMPLE 1 Growth of Bacteria Under ideal laboratory conditions, the number of bacteria in a culture grows in accordance with the law Q(t)  Q0 e kt, where Q0 denotes the number of bacteria initially present in the culture, k is a constant determined by the strain of bacteria under consideration, and t is the elapsed time measured in hours. Suppose 10,000 bacteria are present initially in the culture and 60,000 present 2 hours later. How many bacteria will there be in the culture at the end of 4 hours? Solution

We are given that Q(0)  Q0  10,000, so Q(t)  10,000e kt. Next, the fact that 60,000 bacteria are present 2 hours later translates into Q(2)  60,000. Thus, 60,000  10,000e 2k e 2k  6

Taking the natural logarithm on both sides of the equation, we obtain ln e 2k  ln 6 2k  ln 6 k  0.8959

Since ln e  1

Thus, the number of bacteria present at any time t is given by Q(t)  10,000e0.8959t

172

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

In particular, the number of bacteria present in the culture at the end of 4 hours is given by Q(4)  10,000e0.8959(4)  360,029

Exponential Decay In contrast to exponential growth, a quantity exhibits exponential decay if it decreases at a rate that is directly proportional to its size. Such a quantity may be described by the exponential function

Q

Q(t)  Q0ekt

Q = Q 0 e –kt Q0 t

FIGURE 11 Exponential decay

(0 t )

(4)

where the positive constant Q0 measures the amount present initially (t  0) and k is some suitable positive number, called the decay constant. The choice of this number is determined by the nature of the substance under consideration. The graph of this function is sketched in Figure 11. APPLIED EXAMPLE 2 Radioactive Decay Radioactive substances decay exponentially. For example, the amount of radium present at any time t obeys the law Q(t)  Q0 ekt, where Q0 is the initial amount present and k is a suitable positive constant. The half-life of a radioactive substance is the time required for a given amount to be reduced by one-half. Now, it is known that the half-life of radium is approximately 1600 years. Suppose initially there are 200 milligrams of pure radium. Find the amount left after t years. What is the amount left after 800 years? Solution The initial amount of radium present is 200 milligrams, so Q(0)  Q0  200. Thus, Q(t)  200ekt. Next, the datum concerning the half-life of radium implies that Q(1600)  100, and this gives

100  200e 1600k e 1600k 

1 2

Taking the natural logarithm on both sides of this equation yields 1 2 1 1600k  ln 2

1600k ln e  ln

k

ln e  1

1 1 ln a b  0.0004332 1600 2

Therefore, the amount of radium left after t years is Q(t)  200e0.0004332t

In particular, the amount of radium left after 800 years is Q(800)  200e0.0004332(800)  141.42

or approximately 141 milligrams.

3.3 EXPONENTIAL FUNCTIONS AS MATHEMATICAL MODELS

173

APPLIED EXAMPLE 3 Radioactive Decay Carbon 14, a radioactive isotope of carbon, has a half-life of 5770 years. What is its decay constant? We have Q(t)  Q0 ekt. Since the half-life of the element is 5770 years, half of the substance is left at the end of that period; that is,

Solution

1 Q 157702  Q0e 5770k  Q0 2 1 e 5770k  2

Taking the natural logarithm on both sides of this equation, we have ln e 5770k  ln

1 2

5770k  0.693147 k  0.00012

Carbon-14 dating is a well-known method used by anthropologists to establish the age of animal and plant fossils. This method assumes that the proportion of carbon 14 (C-14) present in the atmosphere has remained constant over the past 50,000 years. Professor Willard Libby, recipient of the Nobel Prize in chemistry in 1960, proposed this theory. The amount of C-14 in the tissues of a living plant or animal is constant. However, when an organism dies, it stops absorbing new quantities of C-14, and the amount of C-14 in the remains diminishes because of the natural decay of the radioactive substance. Thus, the approximate age of a plant or animal fossil can be determined by measuring the amount of C-14 present in the remains. APPLIED EXAMPLE 4 Carbon-14 Dating A skull from an archeological site has one-tenth the amount of C-14 that it originally contained. Determine the approximate age of the skull. Solution

Here, Q(t)  Q0ekt  Q0e0.00012t

where Q0 is the amount of C-14 present originally and k, the decay constant, is equal to 0.00012 (see Example 3). Since Q(t)  (1/10)Q0, we have 1 Q  Q0e 0.00012t 10 0 1 ln  0.00012t 10 ln 101 0.00012  19,200

t

or approximately 19,200 years.

Take the natural logarithm on both sides.

174

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

Learning Curves The next example shows how the exponential function may be applied to describe certain types of learning processes. Consider the function Q(t)  C  Aekt y

y =C Q(t) = C – Ae –kt C–A t FIGURE 12 A learning curve

where C, A, and k are positive constants. The graph of the function Q is shown in Figure 12, where that part of the graph corresponding to the negative values of t is drawn with a gray line since, in practice, one normally restricts the domain of the function to the interval [0, ). Observe that Q(t) (t  0) increases rather rapidly initially but that the rate of increase slows down considerably after a while. The value of Q(t) never exceeds C. This behavior of the graph of the function Q closely resembles the learning pattern experienced by workers engaged in highly repetitive work. For example, the productivity of an assembly-line worker increases very rapidly in the early stages of the training period. This productivity increase is a direct result of the worker’s training and accumulated experience. But the rate of increase of productivity slows as time goes by, and the worker’s productivity level approaches some fixed level due to the limitations of the worker and the machine. Because of this characteristic, the graph of the function Q(t)  C  Aekt is often called a learning curve. APPLIED EXAMPLE 5 Assembly Time The Camera Division of Eastman Optical produces a 35-mm single-lens reflex camera. Eastman’s training department determines that after completing the basic training program, a new, previously inexperienced employee will be able to assemble Q(t)  50  30e0.5t

model F cameras per day, t months after the employee starts work on the assembly line. a. How many model F cameras can a new employee assemble per day after basic training? b. How many model F cameras can an employee with 1 month of experience assemble per day? An employee with 2 months of experience? An employee with 6 months of experience? c. How many model F cameras can the average experienced employee assemble per day? Solution

a. The number of model F cameras a new employee can assemble is given by Q(0)  50  30  20

b. The number of model F cameras that an employee with 1 month of experience, 2 months of experience, and 6 months of experience can assemble per day is given by Q(1)  50  30e0.5  31.80 Q(2)  50  30e1  38.96 Q(6)  50  30e3  48.51

or approximately 32, 39, and 49, respectively. c. As t gets larger and larger, Q(t) approaches 50. Hence, the average experienced employee can ultimately be expected to assemble 50 model F cameras per day.

3.3 EXPONENTIAL FUNCTIONS AS MATHEMATICAL MODELS

175

Other applications of the learning curve are found in models that describe the dissemination of information about a product or the velocity of an object dropped into a viscous medium. y

Logistic Growth Functions Our last example of an application of exponential functions to the description of natural phenomena involves the logistic (also called the S-shaped, or sigmoidal) curve, which is the graph of the function

y=A y=

A 1 + Be –kt

Q 1t2 

A 1+B t FIGURE 13 A logistic curve

A 1  Bekt

where A, B, and k are positive constants. The function Q is called a logistic growth function, and the graph of the function Q is sketched in Figure 13. Observe that Q(t) increases rather rapidly for small values of t. In fact, for small values of t, the logistic curve resembles an exponential growth curve. However, the rate of growth of Q(t) decreases quite rapidly as t increases and Q(t) approaches the number A as t gets larger and larger, but Q(t) never exceeds A. Thus, the logistic curve exhibits both the property of rapid growth of the exponential growth curve as well as the “saturation” property of the learning curve. Because of these characteristics, the logistic curve serves as a suitable mathematical model for describing many natural phenomena. For example, if a small number of rabbits were introduced to a tiny island in the South Pacific, the rabbit population might be expected to grow very rapidly at first, but the growth rate would decrease quickly as overcrowding, scarcity of food, and other environmental factors affected it. The population would eventually stabilize at a level compatible with the life-support capacity of the environment. This level, given by A, is called the carrying capacity of the environment. Models describing the spread of rumors and epidemics are other examples of the application of the logistic curve. APPLIED EXAMPLE 6 Spread of Flu The number of soldiers at Fort MacArthur who contracted influenza after t days during a flu epidemic is approximated by the exponential model Q 1t2 

5000 1  1249ekt

If 40 soldiers contracted the flu by day 7, find how many soldiers contracted the flu by day 15. Solution

The given information implies that Q 172 

Thus,

5000  40 1  1249e 7k

4011  1249e 7k 2  5000 5000 1  1249e 7k   125 40 e 7k 

124 1249

7k  ln k

124 1249 124 ln 1249  0.33 7

176

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

Therefore, the number of soldiers who contracted the flu after t days is given by Q 1t2 

5000 1  1249e 0.33t

In particular, the number of soldiers who contracted the flu by day 15 is given by Q 1152 

5000 1  1249e 1510.332  508

or approximately 508 soldiers.

Exploring with

TECHNOLOGY Refer to Example 6. 1. Use a graphing utility to plot the graph of the function Q, using the viewing window [0, 40]  [0, 5000]. 2. How long will it take for the first 1000 soldiers to contract the flu? Hint: Plot the graphs of y1  Q(t) and y2  1000 and find the point of intersection of the two graphs.

3.3 Self-Check Exercise Suppose the population (in millions) of a country at any time t grows in accordance with the rule I I P  a P0  b e kt  k k

where P denotes the population at any time t, k is a constant reflecting the natural growth rate of the population, I is a constant giving the (constant) rate of immigration into the country,

and P0 is the total population of the country at time t  0. The population of the United States in 1980 (t  0) was 226.5 million. If the natural growth rate is 0.8% annually (k  0.008) and net immigration is allowed at the rate of half a million people per year (I  0.5), what is the expected population of the United States in 2010? The solution to Self-Check Exercise 3.3 can be found on page 179.

3.3 Concept Questions 1. Give the model for unrestricted exponential growth and the model for exponential decay. What effect does the magnitude of the growth (decay) constant have on the growth (decay) of a quantity?

2. What is the half-life of a radioactive substance? 3. What is the logistic growth function? What are its characteristics?

3.3 EXPONENTIAL FUNCTIONS AS MATHEMATICAL MODELS

177

3.3 Exercises 1. EXPONENTIAL GROWTH Given that a quantity Q(t) is described by the exponential growth function Q(t)  400e0.05t

where t is measured in minutes, answer the following questions: a. What is the growth constant? b. What quantity is present initially? c. Complete the following table of values: t Q

0

10

20

100

1000

2. EXPONENTIAL DECAY Given that a quantity Q(t) exhibiting exponential decay is described by the function 0.06t

Q(t)  2000e

where t is measured in years, answer the following questions: a. What is the decay constant? b. What quantity is present initially? c. Complete the following table of values: t Q

0

5

10

20

100

3. GROWTH OF BACTERIA The growth rate of Escherichia coli, a common bacterium found in the human intestine, is proportional to its size. Under ideal laboratory conditions, when this bacterium is grown in a nutrient broth medium, the number of cells in a culture doubles approximately every 20 min. a. If the initial cell population is 100, determine the function Q(t) that expresses the exponential growth of the number of cells of this bacterium as a function of time t (in minutes). b. How long will it take for a colony of 100 cells to increase to a population of 1 million? c. If the initial cell population were 1000, how would this alter our model? 4. WORLD POPULATION The world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t  0 corresponding to the beginning of 1990. Using this function, complete the following table of values and sketch the graph of the function Q. Year World Population

1990

1995

2000

2005

Year World Population

2010

2015

2020

2025

5. WORLD POPULATION Refer to Exercise 4. a. If the world population continues to grow at the rate of approximately 2%/year, find the length of time t0 required for the world population to triple in size. b. Using the time t0 found in part (a), what would be the world population if the growth rate were reduced to 1.8%/year? 6. RESALE VALUE A certain piece of machinery was purchased 3 yr ago by Garland Mills for $500,000. Its present resale value is $320,000. Assuming that the machine’s resale value decreases exponentially, what will it be 4 yr from now? 7. ATMOSPHERIC PRESSURE If the temperature is constant, then the atmospheric pressure P (in pounds/square inch) varies with the altitude above sea level h in accordance with the law P  p0ekh

where p0 is the atmospheric pressure at sea level and k is a constant. If the atmospheric pressure is 15 lb/in.2 at sea level and 12.5 lb/in.2 at 4000 ft, find the atmospheric pressure at an altitude of 12,000 ft. 8. RADIOACTIVE DECAY The radioactive element polonium decays according to the law Q(t)  Q0  2(t /140)

where Q0 is the initial amount and the time t is measured in days. If the amount of polonium left after 280 days is 20 mg, what was the initial amount present? 9. RADIOACTIVE DECAY Phosphorus 32 (P-32) has a half-life of 14.2 days. If 100 g of this substance are present initially, find the amount present after t days. What amount will be left after 7.1 days? 10. NUCLEAR FALLOUT Strontium 90 (Sr-90), a radioactive isotope of strontium, is present in the fallout resulting from nuclear explosions. It is especially hazardous to animal life, including humans, because, upon ingestion of contaminated food, it is absorbed into the bone structure. Its half-life is 27 yr. If the amount of Sr-90 in a certain area is found to be four times the “safe” level, find how much time must elapse before an “acceptable level” is reached. 11. CARBON-14 DATING Wood deposits recovered from an archeological site contain 20% of the C-14 they originally contained. How long ago did the tree from which the wood was obtained die? 12. CARBON-14 DATING Skeletal remains of the so-called Pittsburgh Man, unearthed in Pennsylvania, had lost 82% of the C-14 they originally contained. Determine the approximate age of the bones.

178

5 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

13. LEARNING CURVES The American Court Reporting Institute finds that the average student taking Advanced Machine Shorthand, an intensive 20-wk course, progresses according to the function Q(t)  120(1  e0.05t )  60

(0 t 20)

where Q(t) measures the number of words (per minute) of dictation that the student can take in machine shorthand after t wk in the course. Sketch the graph of the function Q and answer the following questions: a. What is the beginning shorthand speed for the average student in this course? b. What shorthand speed does the average student attain halfway through the course? c. How many words per minute can the average student take after completing this course? 14. PEOPLE LIVING WITH HIV Based on data compiled by WHO, the number of people living with HIV (human immunodeficiency virus) worldwide from 1985 through 2006 is estimated to be N1t 2 

39.88 1  18.94e0.2957t

10 t 21 2

where N(t) is measured in millions and t in years, with t  0 corresponding to the beginning of 1985. a. How many people were living with HIV worldwide at the beginning of 1985? At the beginning of 2005? b. Assuming that the trend continued, how many people were living with HIV worldwide at the beginning of 2008? Source: World Health Organization

15. FEDERAL DEBT According to data obtained from the CBO, the total federal debt (in trillions of dollars) from 2001 through 2006 is given by f 1t 2  5.37e0.078t

11 t 6 2

where t is measured in years, with t  1 corresponding to 2001. What was the total federal debt in 2001? In 2006? Source: Congressional Budget Office

16. EFFECT OF ADVERTISING ON SALES Metro Department Store found that t wk after the end of a sales promotion the volume of sales was given by S(t)  B  Aekt

(0 t 4)

where B  50,000 and is equal to the average weekly volume of sales before the promotion. The sales volumes at the end of the first and third weeks were $83,515 and $65,055, respectively. Assume that the sales volume is decreasing exponentially. a. Find the decay constant k. b. Find the sales volume at the end of the fourth week. 17. DEMAND FOR COMPUTERS Universal Instruments found that the monthly demand for its new line of Galaxy Home Computers t mo after placing the line on the market was given by

D(t)  2000  1500e0.05t

(t  0)

Graph this function and answer the following questions: a. What is the demand after 1 mo? After 1 yr? After 2 yr? After 5 yr? b. At what level is the demand expected to stabilize? 18. RELIABILITY OF COMPUTER CHIPS The percentage of a certain brand of computer chips that will fail after t yr of use is estimated to be P(t)  100(1  e0.1t )

What percentage of this brand of computer chips are expected to be usable after 3 yr? 19. LENGTHS OF FISH The length (in centimeters) of a typical Pacific halibut t yr old is approximately f(t)  200(1  0.956e0.18t )

What is the length of a typical 5-yr-old Pacific halibut? 20. SPREAD OF AN EPIDEMIC During a flu epidemic, the number of children in the Woodbridge Community School System who contracted influenza after t days was given by Q 1t2 

1000 1  199e 0.8t

a. How many children were stricken by the flu after the first day? b. How many children had the flu after 10 days? 21. LAY TEACHERS AT ROMAN CATHOLIC SCHOOLS The change from religious to lay teachers at Roman Catholic schools has been partly attributed to the decline in the number of women and men entering religious orders. The percentage of teachers who are lay teachers is given by f 1t2 

98 1  2.77et

10 t 4 2

where t is measured in decades, with t  0 corresponding to the beginning of 1960. What percentage of teachers were lay teachers at the beginning of 1990? Sources: National Catholic Education Association and the Department of Education

22. GROWTH OF A FRUIT FLY POPULATION On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly (Drosophila) with a limited food supply could be approximated by the exponential model N 1t2 

400 1  39e 0.16t

where t denotes the number of days since the beginning of the experiment. a. What was the initial fruit fly population in the experiment? b. What was the population of the fruit fly colony on the 20th day?

3.3 EXPONENTIAL FUNCTIONS AS MATHEMATICAL MODELS

23. DEMOGRAPHICS The number of citizens aged 45–64 yr is projected to be P 1t 2 

197.9 1  3.274e 0.0361t

26. RADIOACTIVE DECAY A radioactive substance decays according to the formula Q(t)  Q0ekt

10 t 202

where P(t) is measured in millions and t is measured in years, with t  0 corresponding to the beginning of 1990. People belonging to this age group are the targets of insurance companies that want to sell them annuities. What is the projected population of citizens aged 45–64 yr in 2010?

where Q(t) denotes the amount of the substance present at time t (measured in years), Q0 denotes the amount of the substance present initially, and k (a positive constant) is the decay constant. a. Show that half-life of the substance is t  ln 2/k. b. Suppose a radioactive substance decays according to the formula

Source: K. G. Securities

Q(t)  20e0.0001238t

24. POPULATION GROWTH IN THE 21ST CENTURY The U.S. population is approximated by the function P 1t2 

616.5 1  4.02e 0.5t

where P(t) is measured in millions of people and t is measured in 30-yr intervals, with t  0 corresponding to 1930. What is the expected population of the United States in 2020 (t  3)? 25. DISSEMINATION OF INFORMATION Three hundred students attended the dedication ceremony of a new building on a college campus. The president of the traditionally female college announced a new expansion program, which included plans to make the college coeducational. The number of students who learned of the new program t hr later is given by the function f 1t 2 

3000 1  Be kt

How long will it take for the substance to decay to half the original amount? 27. LOGISTIC GROWTH FUNCTION Consider the logistic growth function Q1t2 

A 1  Bekt

Suppose the population is Q1 when t  t1 and Q2 when t  t2. Show that the value of k is k

Q2 1A  Q1 2 1 ln c d t2  t1 Q1 1A  Q2 2

28. LOGISTIC GROWTH FUNCTION The carrying capacity of a colony of fruit flies (Drosophila) is 600. The population of fruit flies after 14 days is 76, and the population after 21 days is 167. What is the value of the growth constant k? Hint: Use the result of Exercise 27.

If 600 students on campus had heard about the new program 2 hr after the ceremony, how many students had heard about the policy after 4 hr?

3.3 Solution to Self-Check Exercise We are given that P0  226.5, k  0.008, and I  0.5. So P  a 226.5   289e

0.008t

179

0.5 0.5 b e 0.008t  0.008 0.008

 62.5

Therefore, the expected population in 2010 is given by P(30)  289e0.24  62.5  304.9

or approximately 304.9 million.

180

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

USING

TECHNOLOGY

Analyzing Mathematical Models We can use a graphing utility to analyze the mathematical models encountered in this section. APPLIED EXAMPLE 1 Internet Gaming Sales The estimated growth in global Internet-gaming revenue (in billions of dollars), as predicted by industry analysts, is given in the following table: Year Revenue

2001

2002

2003

2004

2005

2006

2007

2008

2009

2010

3.1

3.9

5.6

8.0

11.8

15.2

18.2

20.4

22.7

24.5

a. Use Logistic to find a regression model for the data. Let t  0 correspond to 2001. b. Plot the scatter diagram and the graph of the function f found in part (a) using the viewing window [0, 9]  [0, 30]. Source: Christiansen Capital/Advisors Solution

a. Using Logistic we find f 1t 2  FIGURE T1

27.11 1  9.64e0.49t

10 t 92

b. The scatter plot for the data, and the graph of f in the viewing window [0, 9]  [0, 30] are shown in Figure T1.

The graph of f in the viewing window [0, 9]  [0, 30]

TECHNOLOGY EXERCISES 1. ONLINE BANKING In a study prepared in 2000, the percentage of households using online banking was projected to be f (t)  1.5e0.78t

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 2000. Plot the graph of f, using the viewing window [0, 4]  [0, 40]. Source: Online Banking Report

2. NEWTON’S LAW OF COOLING The temperature of a cup of coffee t min after it is poured is given by T  70  100e0.0446t

where T is measured in degrees Fahrenheit. a. Plot the graph of T, using the viewing window [0, 30]  [0, 200]. b. When will the coffee be cool enough to drink (say, 120°)? Hint: Use the ISECT function.

3. AIR TRAVEL Air travel has been rising dramatically in the past 30 yr. In a study conducted in 2000, the FAA projected further exponential growth for air travel through 2010. The function

f(t)  666e0.0413t

(0 t 10)

gives the number of passengers (in millions) in year t, with t  0 corresponding to 2000. a. Plot the graph of f, using the viewing window [0, 10]  [0, 1000]. b. How many air passengers were there in 2000? What was the projected number of air passengers for 2008? Source: Federal Aviation Administration

4. COMPUTER GAME SALES The total number of Starr Communication’s newest game, Laser Beams, sold t mo after its release is given by N(t)  20(t  20)e0.05t  400

thousand units. Plot the graph of N, using the viewing window [0, 500]  [0, 500]. 5. POPULATION GROWTH IN THE 21ST CENTURY The U.S. population is approximated by the function P 1t2 

616.5 1  4.02e 0.5t

SUMMARY OF PRINCIPAL FORMULAS AND TERMS

Here, t  0 corresponds to noon of February 6. a. Use Logistic to find a regression model for the data. b. Plot the scatter diagram and the graph of the function f found in part (a), using the viewing window [0, 33]  [0, 30].

where P(t) is measured in millions of people and t is measured in 30-yr intervals, with t  0 corresponding to 1930. a. Plot the graph of f, using the viewing window [0, 4]  [0, 650]. b. What is the expected population of the United States in 2020 (t  3)?

Source: Boston Globe

Source: U.S. Census Bureau

9. WORLDWIDE PC SHIPMENTS According to an IDC forecast made in 2007, worldwide PC shipments (in millions of units) from 2005 through 2009 is given in the following table:

6. TIME RATE OF GROWTH OF A TUMOR The rate at which a tumor grows, with respect to time, is given by 1for 0 x B 2

B x

R  Ax ln

where A and B are positive constants and x is the radius of the tumor. Plot the graph of R for the case A  B  10.

0.3t  1811  e t/60 2 18e t/60  12e 1t202/60

if 0 t 20 if t  20

where C(t) is measured in grams/cubic centimeter (g/cm ). a. Plot the graph of C, using the viewing window [0, 120]  [0, 1]. b. What is the initial concentration of the drug in the organ? c. What is the concentration of the drug in the organ after 10 sec? d. What is the concentration of the drug in the organ after 30 sec?

3

6

9

12

15

18 21

24

27

2006

2007

2008

2009

PCs

207.1

226.2

252.9

283.3

302.4

10. FEDERAL DEBT According to data obtained from the CBO, the total federal debt (in trillions of dollars) from 2001 through 2006 is given in the following table: Year

2001

2002

2003

2004

2005

2006

Debt

5.81

6.23

6.78

7.40

7.93

8.51

a. Use ExpReg to find a regression model for the data. Let t  1 correspond to 2001. b. Plot the graph of the function f found in part (a), using the viewing window [1, 6]  [4, 10].

8. MODELING WITH DATA The snowfall accumulation at Logan Airport (in inches), t hr after a 33-hr snowstorm in Boston in 1995, follows: 0

2005

Source: International Data Corporation 3

Hour

Year

a. Use Logistic to find a regression model for the data. Let t  0 correspond to 2005. b. Plot the graph of the function f found in part (a), using the viewing window [0, 4]  [200, 300].

7. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by C 1t 2  e

181

Source: Congressional Budget Office

30 33

Inches 0.1 0.4 3.6 6.5 9.1 14.4 19.5 22 23.6 24.8 26.6 27

CHAPTER 3 Summary of Principal Formulas and Terms FORMULAS 1. Exponential function with base b

y  bx

2. Exponential function with base e

y  ex

3. Logarithmic function with base b

y  log b x

4. Logarithmic function with base e

y  ln x

5. Inverse properties of ln x and e

x

ln e x  x

and

eln x  x

TERMS common logarithm (162) natural logarithm (162) exponential growth (171)

growth constant (171) exponential decay (172) decay constant (172)

half-life of a radioactive substance (172) logistic growth function (175)

182

3 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

CHAPTER 3 Concept Review Questions Fill in the blanks.

1. The function f (x)  x (b, a real number) is called a/an _____ function, whereas the function t(x)  bx, where b  _____ and b  _____, is called a/an _____ function. b

2. a. The domain of the function y  3x is _____, and its range is _____. b. The graph of the function y  0.3x passes through the point _____ and falls from _____ to _____. 3. a. If b  0 and b  1, then the logarithmic function y  logb x has domain _____ and range _____; its graph passes through the point _____. b. The graph of y  logb x _____ from left to right if b 1 and _____ from left to right if b  1. 4. a. If x  0, then eln x  _____. b. If x is any real number, then ln ex  _____.

5. a. In the unrestricted exponential growth model Q  Q0ekt, Q0 represents the quantity present _____, and k is called the _____ constant. b. In the exponential decay model Q  Q0ekt, k is called the _____ constant. c. The half-life of a radioactive substance is the _____ required for a substance to decay to _____ _____ of its original amount. 6. a. The model Q(t)  C  Aekt is called a/an _____ _____. The value of Q(t) never exceeds _____. A b. The model Q 1t2  , y  A, is called a/an _____ 1  Bekt _____ _____ of the graph of Q. If the quantity Q(t) is initially smaller than A, then Q(t) will eventually approach _____ as t increases; the number A, represents the lifesupport capacity of the environment and is called the _____ _____ of the environment.

CHAPTER 3 Review Exercises In Exercises 1–4, sketch the graph of the function.

1. f (x)  5x

1 2. y  a b 5

3. f(x)  log4 x

4. y  log1/4 x

x

21. ln(x  1)  ln 4  ln(2 x  4)  ln 2

In Exercises 5–8, express each equation in logarithmic form.

5. 3  81 4

2 7. a b 3

3

1/2

6. 9 27  8

20. log 4(2 x  1)  2

3

8. 163/4  0.125

In Exercises 22–35, solve for x, giving your answer accurate to four decimal places.

22. 4x  5

23. 32x  8

24. 3  2x  17

25. 2ex  7

26. 0.2ex  3.4

27. e2x1  14

28. 53x1  16

29. 23x1  32x3

30. 2x  12

31. 3e2x  15

32. 4e0.1x  2  8

33. 8  e0.2x  2

2

In Exercises 9–12, given that ln 2 ⬇ 0.6931, ln 3 ⬇1.0986, and ln 5 ⬇ 1.6094, find the value of the expression.

9. ln 30

10. ln 9

11. ln 3.6

12. ln 75

34.

In Exercises 13–15, given that ln 2  x, ln 3  y, and ln 5  z, express each of the given logarithmic values in terms of x, y, and z.

13. ln 30

14. ln 3.6

15. ln 75

In Exercises 16–21, solve for x without using a calculator.

16. 22 x3  8

17. e x

2x

 e2

18. 3x1  9 x2

19. 2x

2x

 4x

23

20 4 1  2e0.2x

35.

30 5 1  2e0.1x

36. Sketch the graph of the function y  log 2(x  3). 37. Sketch the graph of the function y  log 3(x  1). 38. GROWTH OF BACTERIA A culture of bacteria that initially contained 2000 bacteria has a count of 18,000 bacteria after 2 hr. a. Determine the function Q(t) that expresses the exponential growth of the number of cells of this bacterium as a function of time t (in minutes). b. Find the number of bacteria present after 4 hr.

BEFORE MOVING ON . . .

39. RADIOACTIVE DECAY The radioactive element radium has a half-life of 1600 yr. What is its decay constant? 40. DEMAND FOR DVD PLAYERS VCA Television found that the monthly demand for its new line of DVD players t mo after placing the players on the market is given by: D(t)  4000  3000e0.06t

(t  0)

Graph this function and answer the following questions: a. What was the demand after 1 mo? After 1 yr? After 2 yr? b. At what level is the demand expected to stabilize? 41. FLU EPIDEMIC During a flu epidemic, the number of students at a certain university who contracted influenza after t days could be approximated by the exponential model Q(t) 

3000 1  499ekt

183

42. U.S. INFANT MORTALITY RATE The U.S. infant mortality rate (per 1000 live births) is approximated by the function N(t)  12.5e0.0294t

(0 t 21)

where t is measured in years, with t  0 corresponding to 1980. What was the mortality rate in 1980? In 1990? In 2000? Source: U.S. Department of Health and Human Services

43. ABSORPTION

OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by

x(t)  0.08(1  e0.02t)

where x(t) is measured in grams/cubic centimeter (g/cm3). a. What is the initial concentration of the drug in the organ? b. What is the concentration of the drug in the organ after 30 sec?

If 90 students contracted the flu by day 10, how many students contracted the flu by day 20?

CHAPTER 3 Before Moving On . . . 1. Simplify the expression (2x2)2(9x4)1/2. 2. Solve e  e  6  0 for x. 2x

x

Hint: Let u  e .

5. The temperature of a cup of coffee at time t (in minutes) is T(t)  70  cekt

x

3. Solve log2(x 2  8x  1)  0. 4. Solve the equation

100  40 for t. 1  2e0.3t

Initially, the temperature of the coffee was 200°F. Three minutes later, it was 180°. When will the temperature of the coffee be 150°F?

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4

MATHEMATICS OF FINANCE

I

NTEREST THAT IS periodically added to the principal and thereafter itself earns interest is called compound interest. We

begin this chapter by deriving the compound interest formula, which gives the amount of money accumulated when an initial

earns compound interest. An annuity is a sequence of payments made at regular intervals. We derive formulas giving the future value of an annuity (what you end up with) and the present value of an annuity (the lump sum that, when invested now, will yield the same future value as that of the annuity). Then, using these formulas, we answer questions involving the amortization of certain types of installment loans and questions involving sinking funds (funds that are set up to be used for a specific purpose at a future date).

© Thomas Barwick/Getty Images

amount of money is invested in an account for a fixed term and

How much can the Jacksons afford to borrow from the bank for the purchase of a home? They have determined that after making a down payment they can afford a monthly payment of $2000. In Example 4, page 218, we learn how to determine the maximum amount they can afford to borrow if they secure a 30-year fixed mortgage at the current rate.

186

4 MATHEMATICS OF FINANCE

4.1 Compound Interest Simple Interest A natural application of linear functions to the business world is found in the computation of simple interest—interest that is computed on the original principal only. Thus, if I denotes the interest on a principal P (in dollars) at an interest rate of r per year for t years, then we have I  Prt A

The accumulated amount A, the sum of the principal and interest after t years, is given by A  P  I  P  Prt  P11  rt2

A = P + Prt P

t

FIGURE 1

and is a linear function of t (see Exercise 44). In business applications, we are normally interested only in the case where t is positive, so only that part of the line that lies in Quadrant I is of interest to us (Figure 1).

Simple Interest Formulas

The accumulated amount is a linear function of t .

Interest: I  Prt Accumulated amount: A  P11  rt2

(1a) (1b)

EXAMPLE 1 A bank pays simple interest at the rate of 8% per year for certain deposits. If a customer deposits $1000 and makes no withdrawals for 3 years, what is the total amount on deposit at the end of 3 years? What is the interest earned in that period of time? Solution Using Equation (1b) with P  1000, r  0.08, and t  3, we see that the total amount on deposit at the end of 3 years is given by

A  P11  rt2  1000 31  10.08 2 132 4  1240

or $1240. The interest earned over the 3-year period is given by I  Prt Use (1a).  1000(0.08)(3)  240

or $240.

Exploring with

TECHNOLOGY Refer to Example 1. Use a graphing utility to plot the graph of the function A  1000(1  0.08t), using the viewing window [0, 10]  [0, 2000]. 1. What is the A-intercept of the straight line, and what does it represent? 2. What is the slope of the straight line, and what does it represent? (See Exercise 44.)

4.1 COMPOUND INTEREST

187

APPLIED EXAMPLE 2 Trust Funds An amount of $2000 is invested in a 10-year trust fund that pays 6% annual simple interest. What is the total amount of the trust fund at the end of 10 years? Solution

The total amount of the trust fund at the end of 10 years is given by A  P11  rt 2  200031  10.062 1102 4  3200

or $3200.

Compound Interest In contrast to simple interest, compound interest is earned interest that is periodically added to the principal and thereafter itself earns interest at the same rate. To find a formula for the accumulated amount, let’s consider a numerical example. Suppose $1000 (the principal) is deposited in a bank for a term of 3 years, earning interest at the rate of 8% per year (called the nominal, or stated, rate) compounded annually. Then, using Equation (1b) with P  1000, r  0.08, and t  1, we see that the accumulated amount at the end of the first year is A1  P11  rt 2  100031  10.082 112 4  100011.082  1080

or $1080. To find the accumulated amount A2 at the end of the second year, we use (1b) once again, this time with P  A1. (Remember, the principal and interest now earn interest over the second year.) We obtain A2  P11  rt 2  A1 11  rt 2  100031  0.08112 4 31  0.08112 4  100031  0.084 2  100011.082 2  1166.40

or $1166.40. Finally, the accumulated amount A3 at the end of the third year is found using (1b) with P  A2, giving A3  P11  rt 2  A2 11  rt 2  100031  0.08112 4 2 31  0.08112 4  100031  0.084 3  100011.082 3  1259.71

or approximately $1259.71. If you reexamine our calculations, you will see that the accumulated amounts at the end of each year have the following form. A1  100011  0.082, or A1  P11  r2 First year: Second year: A2  100011  0.082 2, or A2  P11  r2 2 Third year: A3  100011  0.082 3, or A3  P11  r2 3

These observations suggest the following general result: If P dollars is invested over a term of t years, earning interest at the rate of r per year compounded annually, then the accumulated amount is A  P11  r2 t (2) Formula (2) was derived under the assumption that interest was compounded annually. In practice, however, interest is usually compounded more than once a year. The interval of time between successive interest calculations is called the conversion period.

188

4 MATHEMATICS OF FINANCE

If interest at a nominal rate of r per year is compounded m times a year on a principal of P dollars, then the simple interest rate per conversion period is i

r m

Annual interest rate Periods per year

For example, if the nominal interest rate is 8% per year (r  0.08) and interest is compounded quarterly (m  4), then i

r 0.08   0.02 m 4

or 2% per period. To find a general formula for the accumulated amount when a principal of P dollars is deposited in a bank for a term of t years and earns interest at the (nominal) rate of r per year compounded m times per year, we proceed as before, using (1b) repeatedly with the interest rate i  mr . We see that the accumulated amount at the end of each period is A1  P11  i2 First period: Second period: A2  A1 11  i 2 Third period: A3  A2 11  i 2 o nth period:

 3P11  i 2 4 11  i2  P11  i2 2  3P11  i 2 2 4 11  i2  P11  i 2 3

o An  An1 11  i 2  3P11  i 2 n1 4 11  i2  P11  i 2 n

There are n  mt periods in t years (number of conversion periods per year times the term in years). Hence the accumulated amount at the end of t years is given by A  P11  i2 n

Compound Interest Formula (Accumulated Amount) A  P11  i2 n

where i 

(3)

r , n  mt, and m

A  Accumulated amount at the end of n conversion periods P  Principal r  Nominal interest rate per year m  Number of conversion periods per year t  Term (number of years)

Exploring with

TECHNOLOGY Let A1(t) denote the accumulated amount of $100 earning simple interest at the rate of 10% per year over t years, and let A2(t) denote the accumulated amount of $100 earning interest at the rate of 10% per year compounded monthly over t years. 1. Find expressions for A1(t) and A2(t). 2. Use a graphing utility to plot the graphs of A1 and A2 on the same set of axes, using the viewing window [0, 20]  [0, 800]. 3. Comment on the growth of A1(t) and A2(t) by referring to the graphs of A1 and A2.

4.1 COMPOUND INTEREST

189

EXAMPLE 3 Find the accumulated amount after 3 years if $1000 is invested at 8% per year compounded (a) annually, (b) semiannually, (c) quarterly, (d) monthly, and (e) daily (assume a 365-day year). Solution

a. Here, P  1000, r  0.08, and m  1. Thus, i  r  0.08 and n  3, so Equation (3) gives A  100011  0.082 3  1259.71

or $1259.71. b. Here, P  1000, r  0.08, and m  2. Thus, i  0.08 2 and n  (3)(2)  6, so Equation (3) gives A  1000 a 1 

0.08 6 b 2

 1265.32

or $1265.32. c. In this case, P  1000, r  0.08, and m  4. Thus, i  0.08 4 and n  (3)(4)  12, so Equation (3) gives A  1000 a 1 

0.08 12 b 4

 1268.24

or $1268.24 d. Here, P  1000, r  0.08, and m  12. Thus, i  0.08 12 and n  (3)(12)  36, so Equation (3) gives A  1000 a 1 

0.08 36 b 12

 1270.24

or $1270.24. e. Here, P  1000, r  0.08, m  365, and t  3. Thus, i  0.08 365 and n  (3)(365)  1095, so Equation (3) gives A  1000 a 1 

0.08 1095 b 365

 1271.22

or $1271.22. These results are summarized in Table 1. TABLE 1 Nominal Rate, r

Conversion Period

Interest Rate/ Conversion Period

Initial Investment

Accumulated Amount

8% 8 8 8 8

Annually (m  1) Semiannually (m  2) Quarterly (m  4) Monthly (m  12) Daily (m  365)

8% 4 2 2/3 8/365

$1000 1000 1000 1000 1000

$1259.71 1265.32 1268.24 1270.24 1271.22

190

4 MATHEMATICS OF FINANCE

Exploring with

TECHNOLOGY Investments that are allowed to grow over time can increase in value surprisingly fast. Consider the potential growth of $10,000 if earnings are reinvested. More specifically, suppose A1(t), A2(t), A3(t), A4(t), and A5(t) denote the accumulated values of an investment of $10,000 over a term of t years and earning interest at the rate of 4%, 6%, 8%, 10%, and 12% per year compounded annually. 1. Find expressions for A1(t), A2(t), . . . , A5(t). 2. Use a graphing utility to plot the graphs of A1, A2, . . . , A5 on the same set of axes, using the viewing window [0, 20]  [0, 100,000]. 3. Use TRACE to find A1(20), A2(20), . . . , A5(20) and then interpret your results.

Continuous Compounding of Interest One question that arises naturally in the study of compound interest is: What happens to the accumulated amount over a fixed period of time if the interest is computed more and more frequently? Intuition suggests that the more often interest is compounded, the larger the accumulated amount will be. This is confirmed by the results of Example 3, where we found that the accumulated amounts did in fact increase when we increased the number of conversion periods per year. This leads us to another question: Does the accumulated amount keep growing without bound, or does it approach a fixed number when the interest is computed more and more frequently over a fixed period of time? To answer this question, let’s look again at the compound interest formula: A  P11  i2 n  P a 1 

r mt b m

(4)

Recall that m is the number of conversion periods per year. So to find an answer to our question, we should let m get larger and larger in (4). If we let u  mr so that m  ru, then (4) becomes 1 urt b u 1 u rt  Pc a1  b d u

A  Pa1 

r 1  m u Since a xy  (a x )y

Now observe that u gets larger and larger as m gets larger and larger. But, from our work in Section 3.1, we know that (1 + 1/u)u approaches e as u gets larger and larger. Using this result, we can see that, as m gets larger and larger, A approaches P(e)rt  Pert. In this situation, we say that interest is compounded continuously. Let’s summarize this important result. Continuous Compound Interest Formula A  Pert

where P  Principal r  Nominal interest rate compounded continuously t  Time in years A  Accumulated amount at the end of t years

(5)

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191

EXAMPLE 4 Find the accumulated amount after 3 years if $1000 is invested at 8% per year compounded (a) daily (assume a 365-day year) and (b) continuously. Solution

a. Use Formula (3) with P  1000, r  0.08, m  365, and t  3. Thus, i  0.08 365 and n  (365)(3)  1095, so A  1000 a 1 

0.08 13652132  1271.22 b 365

or $1271.22. b. Here we use Formula (5) with P  1000, r  0.08, and t  3, obtaining A  1000e10.082132  1271.25

or $1271.25. Observe that the accumulated amounts corresponding to interest compounded daily and interest compounded continuously differ by very little. The continuous compound interest formula is a very important tool in theoretical work in financial analysis.

Exploring with

TECHNOLOGY In the opening paragraph of Section 3.1, we pointed out that the accumulated amount of an account earning interest compounded continuously will eventually outgrow by far the accumulated amount of an account earning interest at the same nominal rate but earning simple interest. Illustrate this fact using the following example. Suppose you deposit $1000 in account I, earning interest at the rate of 10% per year compounded continuously so that the accumulated amount at the end of t years is A1(t)  1000e0.1t. Suppose you also deposit $1000 in account II, earning simple interest at the rate of 10% per year so that the accumulated amount at the end of t years is A2(t)  1000(1  0.1t). Use a graphing utility to sketch the graphs of the functions A1 and A2 in the viewing window [0, 20]  [0, 10,000] to see the accumulated amounts A1(t) and A2(t) over a 20-year period.

Effective Rate of Interest Examples 3 and 4 showed that the interest actually earned on an investment depends on the frequency with which the interest is compounded. Thus the stated, or nominal, rate of 8% per year does not reflect the actual rate at which interest is earned. This suggests that we need to find a common basis for comparing interest rates. One such way of comparing interest rates is provided by the use of the effective rate. The effective rate is the simple interest rate that would produce the same accumulated amount in 1 year as the nominal rate compounded m times a year. The effective rate is also called the annual percentage yield. To derive a relationship between the nominal interest rate, r per year compounded m times, and its corresponding effective rate, R per year, let’s assume an initial investment of P dollars. Then the accumulated amount after 1 year at a simple interest rate of R per year is A  P(1  R)

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Also, the accumulated amount after 1 year at an interest rate of r per year compounded m times a year is A  P11  i 2 n  P a 1 

r m b m

Since i 

r and t  1 m

Equating the two expressions gives P11  R2  P a 1  1  R  a1 

r m b m

r m b m

Divide both sides by P.

If we solve the preceding equation for R, we obtain the following formula for computing the effective rate of interest.

Effective Rate of Interest Formula reff  a 1 

r m b 1 m

(6)

where reff  Effective rate of interest r  Nominal interest rate per year m  Number of conversion periods per year

EXAMPLE 5 Find the effective rate of interest corresponding to a nominal rate of 8% per year compounded (a) annually, (b) semiannually, (c) quarterly, (d) monthly, and (e) daily. Solution

a. The effective rate of interest corresponding to a nominal rate of 8% per year compounded annually is, of course, given by 8% per year. This result is also confirmed by using Equation (6) with r  0.08 and m  1. Thus, reff  11  0.082  1  0.08

b. Let r  0.08 and m  2. Then Equation (6) yields reff  a 1 

0.08 2 b 1 2  11.042 2  1  0.0816

so the effective rate is 8.16% per year. c. Let r  0.08 and m  4. Then Equation (6) yields reff  a 1 

0.08 4 b 1 4  11.022 4  1  0.08243

so the corresponding effective rate in this case is 8.243% per year.

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193

d. Let r  0.08 and m  12. Then Equation (6) yields reff  a 1 

0.08 12 b 1 12  0.08300

so the corresponding effective rate in this case is 8.3% per year. e. Let r  0.08 and m  365. Then Equation (6) yields reff  a 1 

0.08 365 b 1 365  0.08328

Explore & Discuss Recall the effective rate of interest formula: reff  a 1 

r m b 1 m

1. Show that

so the corresponding effective rate in this case is 8.328% per year. If the effective rate of interest reff is known, then the accumulated amount after t years on an investment of P dollars may be more readily computed by using the formula

r  m[(1  reff)1/m  1]

A  P(1  reff)t

2. A certificate of deposit (CD) is known to have an effective rate of 5.3%. If interest is compounded monthly, find the nominal rate of interest by using the result of part 1.

The 1968 Truth in Lending Act passed by Congress requires that the effective rate of interest be disclosed in all contracts involving interest charges. The passage of this act has benefited consumers because they now have a common basis for comparing the various nominal rates quoted by different financial institutions. Furthermore, knowing the effective rate enables consumers to compute the actual charges involved in a transaction. Thus, if the effective rates of interest found in Example 5 were known, then the accumulated values of Example 3 could have been readily found (see Table 2).

TABLE 2 Nominal Rate, r

8% 8 8 8 8

Frequency of Interest Payment

Annually Semiannually Quarterly Monthly Daily

Effective Rate

Initial Investment

Accumulated Amount after 3 Years

8% 8.16 8.243 8.300 8.328

$1000 1000 1000 1000 1000

1000(1  0.08)3  $1259.71 1000(1  0.0816)3  1265.32 1000(1  0.08243)3  1268.23 1000(1  0.08300)3  1270.24 1000(1  0.08328)3  1271.22

Present Value Let’s return to the compound interest Formula (3), which expresses the accumulated amount at the end of n periods when interest at the rate of r is compounded m times a year. The principal P in (3) is often referred to as the present value, and the accumulated value A is called the future value, since it is realized at a future date. In certain instances an investor may wish to determine how much money he should invest now, at a fixed rate of interest, so that he will realize a certain sum at some future date. This problem may be solved by expressing P in terms of A. Thus, from Equation (3) we find P  A(1  i)n

Here, as before, i  mr , where m is the number of conversion periods per year.

Present Value Formula for Compound Interest P  A(1  i)n

(7)

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EXAMPLE 6 How much money should be deposited in a bank paying interest at the rate of 6% per year compounded monthly so that, at the end of 3 years, the accumulated amount will be $20,000? Here, r  0.06 and m  12, so i  0.06 12 and n  (3)(12)  36. Thus, the problem is to determine P given that A  20,000. Using Equation (7), we obtain

Solution

0.06 36 b 12

P  20,000 a 1   16,713

or $16,713. EXAMPLE 7 Find the present value of $49,158.60 due in 5 years at an interest rate of 10% per year compounded quarterly. Using (7) with r  0.1 and m  4, so that i  0.1 4 , n  (4)(5)  20, and A  49,158.6, we obtain

Solution

P  149,158.62 a 1 

0.1 20 b  30,000.07 4

or approximately $30,000. If we solve Formula (5) for P, we have A  Pert

and P  Aert

(8)

which gives the present value in terms of the future (accumulated) value for the case of continuous compounding.

Using Logarithms to Solve Problems in Finance The next two examples show how logarithms can be used to solve problems involving compound interest. EXAMPLE 8 How long will it take $10,000 to grow to $15,000 if the investment earns an interest rate of 12% per year compounded quarterly? Solution

Using Formula (3) with A  15,000, P  10,000, r  0.12, and m  4,

we obtain 15,000  10,000 a 1  (1.03)4t 

0.12 4t b 4

15,000  1.5 10,000

Taking the logarithm on each side of the equation gives ln(1.03)4t  ln 1.5 4t ln 1.03  ln 1.5 ln 1.5 4t  ln 1.03

logb mn  n logb m

4.1 COMPOUND INTEREST

t

195

ln 1.5  3.43 4 ln 1.03

So it will take approximately 3.4 years for the investment to grow from $10,000 to $15,000. EXAMPLE 9 Find the interest rate needed for an investment of $10,000 to grow to an amount of $18,000 in 5 years if the interest is compounded monthly. Use Formula (3) with A  18,000, P  10,000, m  12, and t  5. Thus i  12r and n  (12)(5)  60, so

Solution

18,000  10,000 a 1 

r 12152 b 12

Dividing both sides of the equation by 10,000 gives 18,000 r 60 b  a1  10,000 12

or, upon simplification, a1 

r 60 b  1.8 12

Now, we take the logarithm on each side of the equation, obtaining ln a 1 

r 60 b  ln 1.8 12 r 60 ln a 1  b  ln 1.8 12 r ln 1.8 ln a 1  b   0.009796 12 60 a1 

r b  e0.009796 12  1.009844

ln e x  x

and r  1.009844  1 12 r  0.1181

or 11.81% per year. APPLIED EXAMPLE 10 Real Estate Investment Blakely Investment Company owns an office building located in the commercial district of a city. As a result of the continued success of an urban renewal program, local business is enjoying a miniboom. The market value of Blakely’s property is V1t 2  300,000e1t/2

where V(t) is measured in dollars and t is the time in years from the present. If the expected rate of appreciation is 9% compounded continuously for the next 10 years, find an expression for the present value P(t) of the market price of the property that will be valid for the next 10 years. Compute P(7), P(8), and P(9), and then interpret your results.

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Using Formula (8) with A  V(t) and r  0.09, we find that the present value of the market price of the property t years from now is

Solution

P1t2  V1t 2e 0.09t  300,000e0.09t 1t/2

10 t 102

Letting t  7, 8, and 9, respectively, we find that P172  300,000e 0.09172  17/2  599,837, or $599,837 P182  300,000e 0.09182  18/2  600,640, or $600,640 P19 2  300,000e 0.09192  19/2  598,115, or $598,115

From the results of these computations, we see that the present value of the property’s market price seems to decrease after a certain period of growth. This suggests that there is an optimal time for the owners to sell. Later, we will show that the highest present value of the property’s market value is approximately $600,779, and that it occurs at time t  7.72 years. The returns on certain investments such as zero coupon certificates of deposit (CDs) and zero coupon bonds are compared by quoting the time it takes for each investment to triple, or even quadruple. These calculations make use of the compound interest Formula (3). APPLIED EXAMPLE 11 Investment Options Jane has narrowed her investment options down to two: 1. Purchase a CD that matures in 12 years and pays interest upon maturity at the rate of 10% per year compounded daily (assume 365 days in a year). 2. Purchase a zero coupon CD that will triple her investment in the same period. Which option will optimize her investment? Solution

Let’s compute the accumulated amount under option 1. Here, r  0.10

m  365

t  12

so n  12(365)  4380 and i  The accumulated amount at the end of 12 years (after 4380 conversion periods) is 0.10 365 .

A  Pa1 

0.10 4380 b  3.32P 365

or $3.32P. If Jane chooses option 2, the accumulated amount of her investment after 12 years will be $3P. Therefore, she should choose option 1. APPLIED EXAMPLE 12 IRAs Moesha has an Individual Retirement Account (IRA) with a brokerage firm. Her money is invested in a money market mutual fund that pays interest on a daily basis. Over a 2-year period in which no deposits or withdrawals were made, her account grew from $4500 to $5268.24. Find the effective rate at which Moesha’s account was earning interest over that period (assume 365 days in a year). Solution

Let reff denote the required effective rate of interest. We have 5268.24  4500(1  reff)2 (1  reff)2  1.17072 1  reff  1.081998 Take the square root on both sides.

or reff  0.081998. Therefore, the effective rate was 8.20% per year.

4.1 COMPOUND INTEREST

197

4.1 Self-Check Exercises 1. Find the present value of $20,000 due in 3 yr at an interest rate of 12%/year compounded monthly. 2. Paul is a retiree living on Social Security and the income from his investment. Currently, his $100,000 investment in a 1-yr CD is yielding 4.6% interest compounded daily. If he reinvests the principal ($100,000) on the due date of the

CD in another 1-yr CD paying 3.2% interest compounded daily, find the net decrease in his yearly income from his investment. Solutions to Self-Check Exercises 4.1 can be found on page 200.

4.1 Concept Questions 1. Explain the difference between simple interest and compound interest.

3. What is the effective rate of interest?

2. What is the difference between the accumulated amount (future value) and the present value of an investment?

4.1 Exercises 1. Find the simple interest on a $500 investment made for 2 yr at an interest rate of 8%/year. What is the accumulated amount? 2. Find the simple interest on a $1000 investment made for 3 yr at an interest rate of 5%/year. What is the accumulated amount? 3. Find the accumulated amount at the end of 9 mo on an $800 deposit in a bank paying simple interest at a rate of 6%/year. 4. Find the accumulated amount at the end of 8 mo on a $1200 bank deposit paying simple interest at a rate of 7%/year. 5. If the accumulated amount is $1160 at the end of 2 yr and the simple rate of interest is 8%/year, then what is the principal? 6. A bank deposit paying simple interest at the rate of 5%/year grew to a sum of $3100 in 10 mo. Find the principal. 7. How many days will it take for a sum of $1000 to earn $20 interest if it is deposited in a bank paying ordinary simple interest at the rate of 5%/year? (Use a 365-day year.) 8. How many days will it take for a sum of $1500 to earn $25 interest if it is deposited in a bank paying 5%/year? (Use a 365-day year.) 9. A bank deposit paying simple interest grew from an initial sum of $1000 to a sum of $1075 in 9 mo. Find the interest rate. 10. Determine the simple interest rate at which $1200 will grow to $1250 in 8 mo.

In Exercises 11–20, find the accumulated amount A if the principal P is invested at the interest rate of r/year for t yr.

11. P  $1000, r  7%, t  8, compounded annually 12. P  $1000, r  812%, t  6, compounded annually 13. P  $2500, r  7%, t  10, compounded semiannually 14. P  $2500, r  9%, t  10 12, compounded semiannually 15. P  $12,000, r  8%, t  10 12, compounded quarterly 16. P  $42,000, r  734 %, t  8, compounded quarterly 17. P  $150,000, r  14%, t  4, compounded monthly 18. P  $180,000, r  9%, t  614 , compounded monthly 19. P  $150,000, r  12%, t  3, compounded daily 20. P  $200,000, r  8%, t  4, compounded daily In Exercises 21–24, find the effective rate corresponding to the given nominal rate.

21. 10%/year compounded semiannually 22. 9%/year compounded quarterly 23. 8%/year compounded monthly 24. 8%/year compounded daily In Exercises 25–28, find the present value of $40,000 due in 4 yr at the given rate of interest.

25. 8%/year compounded semiannually 26. 8%/year compounded quarterly

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4 MATHEMATICS OF FINANCE

27. 7%/year compounded monthly 28. 9%/year compounded daily 29. Find the accumulated amount after 4 yr if $5000 is invested at 8%/year compounded continuously. 30. Find the accumulated amount after 6 yr if $6500 is invested at 7%/year compounded continuously. In Exercises 31–38, use logarithms to solve each problem.

31. How long will it take $5000 to grow to $6500 if the investment earns interest at the rate of 12%/year compounded monthly? 32. How long will it take $12,000 to grow to $15,000 if the investment earns interest at the rate of 8%/year compounded monthly? 33. How long will it take an investment of $2000 to double if the investment earns interest at the rate of 9%/year compounded monthly? 34. How long will it take an investment of $5000 to triple if the investment earns interest at the rate of 8%/year compounded daily? 35. Find the interest rate needed for an investment of $5000 to grow to an amount of $6000 in 3 yr if interest is compounded continuously. 36. Find the interest rate needed for an investment of $4000 to double in 5 yr if interest is compounded continuously. 37. How long will it take an investment of $6000 to grow to $7000 if the investment earns interest at the rate of 712% compounded continuously? 38. How long will it take an investment of $8000 to double if the investment earns interest at the rate of 8% compounded continuously? 39. CONSUMER DECISIONS Mitchell has been given the option of either paying his $300 bill now or settling it for $306 after 1 mo (30 days). If he chooses to pay after 1 mo, find the simple interest rate at which he would be charged. 40. COURT JUDGMENT Jennifer was awarded damages of $150,000 in a successful lawsuit she brought against her employer 5 yr ago. Interest (simple) on the judgment accrues at the rate of 12%/year from the date of filing. If the case were settled today, how much would Jennifer receive in the final judgment? 41. BRIDGE LOANS To help finance the purchase of a new house, the Abdullahs have decided to apply for a shortterm loan (a bridge loan) in the amount of $120,000 for a term of 3 mo. If the bank charges simple interest at the rate of 12%/year, how much will the Abdullahs owe the bank at the end of the term? 42. CORPORATE BONDS David owns $20,000 worth of 10-yr bonds of Ace Corporation. These bonds pay interest every 6 mo at the rate of 7%/year (simple interest). How much

income will David receive from this investment every 6 mo? How much interest will David receive over the life of the bonds? 43. MUNICIPAL BONDS Maya paid $10,000 for a 7-yr bond issued by a city. She received interest amounting to $3500 over the life of the bonds. What rate of (simple) interest did the bond pay? 44. Write Equation (1b) in the slope-intercept form and interpret the meaning of the slope and the A-intercept in terms of r and P. Hint: Refer to Figure 1.

45. HOSPITAL COSTS If the cost of a semiprivate room in a hospital was $580/day 5 yr ago and hospital costs have risen at the rate of 8%/year since that time, what rate would you expect to pay for a semiprivate room today? 46. FAMILY FOOD EXPENDITURE Today a typical family of four spends $600/month for food. If inflation occurs at the rate of 5%/year over the next 6 yr, how much should the typical family of four expect to spend for food 6 yr from now? 47. HOUSING APPRECIATION The Kwans are planning to buy a house 4 yr from now. Housing experts in their area have estimated that the cost of a home will increase at a rate of 5%/year during that period. If this economic prediction holds true, how much can the Kwans expect to pay for a house that currently costs $210,000? 48. ELECTRICITY CONSUMPTION A utility company in a western city of the United States expects the consumption of electricity to increase by 8%/year during the next decade, due mainly to the expected increase in population. If consumption does increase at this rate, find the amount by which the utility company will have to increase its generating capacity in order to meet the needs of the area at the end of the decade. 49. PENSION FUNDS The managers of a pension fund have invested $1.5 million in U.S. government certificates of deposit that pay interest at the rate of 5.5%/year compounded semiannually over a period of 10 yr. At the end of this period, how much will the investment be worth? 50. RETIREMENT FUNDS Five and a half years ago, Chris invested $10,000 in a retirement fund that grew at the rate of 10.82%/year compounded quarterly. What is his account worth today? 51. MUTUAL FUNDS Jodie invested $15,000 in a mutual fund 4 yr ago. If the fund grew at the rate of 9.8%/year compounded monthly, what would Jodie’s account be worth today? 52. TRUST FUNDS A young man is the beneficiary of a trust fund established for him 21 yr ago at his birth. If the original amount placed in trust was $10,000, how much will he receive if the money has earned interest at the rate of 8%/year compounded annually? Compounded quarterly? Compounded monthly?

4.1 COMPOUND INTEREST

199

53. INVESTMENT PLANNING Find how much money should be deposited in a bank paying interest at the rate of 8.5%/year compounded quarterly so that, at the end of 5 yr, the accumulated amount will be $40,000.

33.2% and 27.8% per year, respectively. For the next 6 yr, online retail sales were projected to grow at 30.5%, 19.9%, 24.3%, 14.0%, 17.6%, and 10.5% per year, respectively. What were the projected online sales for 2008?

54. PROMISSORY NOTES An individual purchased a 4-yr, $10,000 promissory note with an interest rate of 8.5%/year compounded semiannually. How much did the note cost?

Source: Jupiter Research

55. FINANCING A COLLEGE EDUCATION The parents of a child have just come into a large inheritance and wish to establish a trust fund for her college education. If they estimate that they will need $100,000 in 13 yr, how much should they set aside in the trust now if they can invest the money at 812%/year compounded (a) annually, (b) semiannually, and (c) quarterly? 56. INVESTMENTS Anthony invested a sum of money 5 yr ago in a savings account that has since paid interest at the rate of 8%/year compounded quarterly. His investment is now worth $22,289.22. How much did he originally invest? 57. RATE COMPARISONS In the last 5 yr, Bendix Mutual Fund grew at the rate of 10.4%/year compounded quarterly. Over the same period, Acme Mutual Fund grew at the rate of 10.6%/year compounded semiannually. Which mutual fund has a better rate of return? 58. RATE COMPARISONS Fleet Street Savings Bank pays interest at the rate of 4.25%/year compounded weekly in a savings account, whereas Washington Bank pays interest at the rate of 4.125%/year compounded daily (assume a 365day year). Which bank offers a better rate of interest? 59. LOAN CONSOLIDATION The proprietors of The Coachmen Inn secured two loans from Union Bank: one for $8000 due in 3 yr and one for $15,000 due in 6 yr, both at an interest rate of 10%/year compounded semiannually. The bank has agreed to allow the two loans to be consolidated into one loan payable in 5 yr at the same interest rate. What amount will the proprietors of the inn be required to pay the bank at the end of 5 yr? Hint: Find the present value of the first two loans.

60. EFFECTIVE RATE OF INTEREST Find the effective rate of interest corresponding to a nominal rate of 9%/year compounded annually, semiannually, quarterly, and monthly. 61. ZERO COUPON BONDS Juan is contemplating buying a zero coupon bond that matures in 10 yr and has a face value of $10,000. If the bond yields a return of 5.25%/year, how much should Juan pay for the bond? 62. REVENUE GROWTH OF A HOME THEATER BUSINESS Maxwell started a home theater business in 2005. The revenue of his company for that year was $240,000. The revenue grew by 20% in 2006 and by 30% in 2007. Maxwell projected that the revenue growth for his company in the next 3 yr will be at least 25%/year. How much does Maxwell expect his minimum revenue to be for 2010? 63. ONLINE RETAIL SALES Online retail sales stood at $23.5 billion for the year 2000. For the next 2 yr, they grew by

64. PURCHASING POWER The inflation rates in the U.S. economy for 2003 through 2006 are 1.6%, 2.3%, 2.7%, and 3.4%, respectively. What was the purchasing power of a dollar at the beginning of 2007 compared to that at the beginning of 2003? Source: U.S. Census Bureau

65. INVESTMENT OPTIONS Investment A offers a 10% return compounded semiannually, and investment B offers a 9.75% return compounded continuously. Which investment has a higher rate of return over a 4-yr period? 66. EFFECT OF INFLATION ON SALARIES Leonard’s current annual salary is $45,000. Ten yr from now, how much will he need to earn in order to retain his present purchasing power if the rate of inflation over that period is 3%/year compounded continuously? 67. SAVING FOR COLLEGE Having received a large inheritance, Jing-mei’s parents wish to establish a trust for her college education. If 7 yr from now they need an estimated $70,000, how much should they set aside in trust now, if they invest the money at 10.5% compounded quarterly? Continuously? 68. PENSIONS Maria, who is now 50 yr old, is employed by a firm that guarantees her a pension of $40,000/year at age 65. What is the present value of her first year’s pension if the inflation rate over the next 15 yr is 6%/year compounded continuously? 8%/year compounded continuously? 12%/year compounded continuously? 69. REAL ESTATE INVESTMENTS An investor purchased a piece of waterfront property. Because of the development of a marina in the vicinity, the market value of the property is expected to increase according to the rule V 1t2  80,000e1t/2

where V(t) is measured in dollars and t is the time (in yr) from the present. If the rate of appreciation is expected to be 9% compounded continuously for the next 8 yr, find an expression for the present value P(t) of the property’s market price valid for the next 8 yr. What is P(t) expected to be in 4 yr? 70. The simple interest formula A  P(1  rt) [Formula (1b)] can be written in the form A  Prt  P, which is the slope-intercept form of a straight line with slope Pr and A-intercept P. a. Describe the family of straight lines obtained by keeping the value of r fixed and allowing the value of P to vary. Interpret your results. b. Describe the family of straight lines obtained by keeping the value of P fixed and allowing the value of r to vary. Interpret your results.

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4 MATHEMATICS OF FINANCE

71. EFFECTIVE RATE OF INTEREST Suppose an initial investment of $P grows to an accumulated amount of $A in t yr. Show that the effective rate (annual effective yield) is reff  (A/P)1/t  1

Use the formula given in Exercise 71 to solve Exercises 72–76. 72. EFFECTIVE RATE OF INTEREST Martha invested $40,000 in a boutique 5 yr ago. Her investment is worth $70,000 today. What is the effective rate (annual effective yield) of her investment? 73. HOUSING APPRECIATION Georgia purchased a house in January 2000 for $200,000. In January 2006 she sold the house and made a net profit of $56,000. Find the effective annual rate of return on her investment over the 6-yr period. 74. COMMON STOCK TRANSACTION Steven purchased 1000 shares of a certain stock for $25,250 (including commissions). He sold the shares 2 yr later and received $32,100 after deducting commissions. Find the effective annual rate of return on his investment over the 2-yr period.

76. MONEY MARKET MUTUAL FUNDS Carlos invested $5000 in a money market mutual fund that pays interest on a daily basis. The balance in his account at the end of 8 mo (245 days) was $5170.42. Find the effective rate at which Carlos’s account earned interest over this period (assume a 365-day year). In Exercises 77–80, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

77. When simple interest is used, the accumulated amount is a linear function of t. 78. If interest is compounded annually, then the accumulated amount after t yr is the same as the accumulated amount under simple interest over t yr. 79. If interest is compounded annually, then the effective rate is the same as the nominal rate. 80. Susan’s salary increased from $50,000/year to $60,000/year over a 4-yr period. Therefore, Susan received annual increases of 5% over that period.

75. ZERO COUPON BONDS Nina purchased a zero coupon bond for $6724.53. The bond matures in 7 yr and has a face value of $10,000. Find the effective annual rate of interest for the bond. Hint: Assume that the purchase price of the bond is the initial investment and that the face value of the bond is the accumulated amount.

4.1 Solutions to Self-Check Exercises 1. Using Equation (7) with A  20,000, r  0.12, and m  12 so that i  0.12 12 and n  (3)(12)  36, we find the required present value to be P  20,000 a 1 

0.12 36 b  13,978.50 12

or $13,978.50 2. The accumulated amount of Paul’s current investment is found by using Equation (3) with P  100,000, r  0.046, and m  365. Thus, i  0.046 365 and n  365, so the required accumulated amount is given by A  100,000 a 1 

0.046 365 b  104,707 365

or $104,707. Next, we compute the accumulated amount of Paul’s reinvestment. Now using (3) with P  100,000, r  0.032, and m  365 so that i  0.032 365 and n  365, we find the required accumulated amount in this case to be A  100,000 a 1 

0.032 365 b  103,252 365

or $103,252. Therefore, Paul can expect to experience a net decrease in yearly income of 104,707  103,252, or $1455.

4.1 COMPOUND INTEREST

USING

TECHNOLOGY

201

Finding the Accumulated Amount of an Investment, the Effective Rate of Interest, and the Present Value of an Investment Graphing Utility

Some graphing utilities have built-in routines for solving problems involving the mathematics of finance. For example, the TI-83/84 TVM SOLVER function incorporates several functions that can be used to solve the problems that are encountered in Sections 4.1–4.3. To access the TVM SOLVER on the TI-83 press 2nd , press FINANCE , and then select 1: TVM Solver . To access the TVM Solver on the TI-83 plus and the TI-84, press APPS , press 1: Finance , and then select 1: TVM Solver . Step-by-step procedures for using these functions can be found on our Companion Web site. EXAMPLE 1 Finding the Accumulated Amount of an Investment Find the accumulated amount after 10 years if $5000 is invested at a rate of 10% per year compounded monthly. Solution

Using the TI-83/84 TVM SOLVER with the following inputs, N  120 I%  10 PV  5000 PMT  0 FV  0 P/Y  12 C/Y  12

N = 120 I% = 10 PV = −5000 PMT = 0 FV = 13535.20745 P/Y = 12 C/Y = 12 PMT : END BEGIN FIGURE T1 The TI-83/84 screen showing the future value (FV) of an investment

(10)(12)

Recall that an investment is an outflow.

The number of payments each year The number of conversion periods each year

PMT:END BEGIN we obtain the display shown in Figure T1. We conclude that the required accumulated amount is $13,535.21.

Eff (10, 4) 10.38128906

EXAMPLE 2 Finding the Effective Rate of Interest Find the effective rate of interest corresponding to a nominal rate of 10% per year compounded quarterly. Solution Here we use the Eff function of the TI-83/84 calculator to obtain the result shown in Figure T2. The required effective rate is approximately 10.38% per year.

FIGURE T2 The TI-83/84 screen showing the effective rate of interest (Eff)

EXAMPLE 3 Finding the Present Value of an Investment Find the present value of $20,000 due in 5 years if the interest rate is 7.5% per year compounded daily. Solution

Using the TI-83/84 TVM SOLVER with the following inputs, N  1825 I%  7.5 PV  0 PMT  0 FV  20000 P/Y  365 C/Y  365

(5)(365)

The number of payments each year The number of conversions each year

PMT:END BEGIN (continued)

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4 MATHEMATICS OF FINANCE

we obtain the display shown in Figure T3. We see that the required present value is approximately $13,746.32. Note that PV is negative because an investment is an outflow (money is paid out).

FIGURE T3 The TI-83/84 screen showing the present value (PV) of an investment

N = 1825 I% = 7.5 PV = −13746.3151 PMT = 0 FV = 20000 P/Y = 365 C/Y = 365 PMT : END BEGIN

Excel

Excel has many built-in functions for solving problems involving the mathematics of finance. Here we illustrate the use of the FV (future value), EFFECT (effective rate), and the PV (present value) functions to solve problems of the type that we have encountered in Section 4.1. EXAMPLE 4 Finding the Accumulated Amount of an Investment Find the accumulated amount after 10 years if $5000 is invested at a rate of 10% per year compounded monthly. Solution Here we are computing the future value of a lump-sum investment, so we use the FV (future value) function. Select fx from the toolbar to obtain the Insert Function dialog box. Then select Financial from the Or select a category: list box. Next, select FV under Select a function: and click OK . The Function Arguments dialog box will appear (see Figure T4). In our example, the mouse cursor is in the edit box headed by Type, so a definition of that term appears near the bottom of the box. Figure T4 shows the entries for each edit box in our example.

Edit box

Definition of function Definition of term FIGURE T4 Excel’s dialog box for computing the future value (FV) of an investment

Note that the entry for Nper is given by the total number of periods for which the investment earns interest. The Pmt box is left blank since no money is added to the original investment. The Pv entry is 5000. The entry for Type is a 1 because the

Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters appearing on the screen.

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203

lump-sum payment is made at the beginning of the investment period. The answer, $13,535.21, is shown at the bottom of the dialog box. It is negative because an investment is considered to be an outflow of money (money is paid out). (Click OK and the answer will also appear on your spreadsheet.) EXAMPLE 5 Finding the Effective Rate of Interest Find the effective rate of interest corresponding to a nominal rate of 10% per year compounded quarterly. Solution Here we use the EFFECT function to compute the effective rate of interest. Accessing this function from the Insert Function dialog box and making the required entries, we obtain the Function Arguments dialog box shown in Figure T5. The required effective rate is approximately 10.38% per year.

FIGURE T5 Excel’s dialog box for the effective rate of interest function (EFFECT)

EXAMPLE 6 Finding the Present Value of an Investment Find the present value of $20,000 due in 5 years if the interest rate is 7.5% per year compounded daily. Solution We use the PV function to compute the present value of a lump-sum investment. Accessing this function from the Insert Function dialog box and making the required entries, we obtain the PV dialog box shown in Figure T6. Once again, the Pmt edit box is left blank since no additional money is added to the original investment. The Fv entry is 20000. The answer is negative because an investment is considered to be an outflow of money (money is paid out). We deduce that the required amount is $13,746.32.

FIGURE T6 Excel dialog box for the present value function (PV)

(continued)

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4 MATHEMATICS OF FINANCE

TECHNOLOGY EXERCISES 1. Find the accumulated amount A if $5000 is invested at the interest rate of 5 38%/year compounded monthly for 3 yr.

7. Find the effective rate corresponding to 9 34%/year compounded monthly.

2. Find the accumulated amount A if $2850 is invested at the interest rate of 6 58%/year compounded monthly for 4 yr.

8. Find the effective rate corresponding to 4 38%/year compounded quarterly.

3. Find the accumulated amount A if $327.35 is invested at the interest rate of 5 13%/year compounded daily for 7 yr.

9. Find the present value of $38,000 due in 3 yr at 8 14%/year compounded quarterly.

4. Find the accumulated amount A if $327.35 is invested at the interest rate of 6 78%/year compounded daily for 8 yr.

10. Find the present value of $150,000 due in 5 yr at 9 38%/year compounded monthly.

5. Find the effective rate corresponding to 8 23%/year compounded quarterly.

11. Find the present value of $67,456 due in 3 yr at 7 78%/year compounded monthly.

6. Find the effective rate corresponding to 10 58%/year compounded monthly.

12. Find the present value of $111,000 due in 5 yr at 11 58%/year compounded monthly.

4.2 Annuities Future Value of an Annuity An annuity is a sequence of payments made at regular time intervals. The time period in which these payments are made is called the term of the annuity. Depending on whether the term is given by a fixed time interval, a time interval that begins at a definite date but extends indefinitely, or one that is not fixed in advance, an annuity is called an annuity certain, a perpetuity, or a contingent annuity, respectively. In general, the payments in an annuity need not be equal, but in many important applications they are equal. In this section we assume that annuity payments are equal. Examples of annuities are regular deposits to a savings account, monthly home mortgage payments, and monthly insurance payments. Annuities are also classified by payment dates. An annuity in which the payments are made at the end of each payment period is called an ordinary annuity, whereas an annuity in which the payments are made at the beginning of each period is called an annuity due. Furthermore, an annuity in which the payment period coincides with the interest conversion period is called a simple annuity, whereas an annuity in which the payment period differs from the interest conversion period is called a complex annuity. In this section, we consider ordinary annuities that are certain and simple, with periodic payments that are equal in size. In other words, we study annuities that are subject to the following conditions: 1. 2. 3. 4.

The terms are given by fixed time intervals. The periodic payments are equal in size. The payments are made at the end of the payment periods. The payment periods coincide with the interest conversion periods.

To find a formula for the accumulated amount S of an annuity, suppose a sum of $100 is paid into an account at the end of each quarter over a period of 3 years. Furthermore, suppose the account earns interest on the deposit at the rate of 8% per year, compounded quarterly. Then, the first payment of $100 made at the end of the first

4.2 ANNUITIES

205

quarter earns interest at the rate of 8% per year compounded four times a year (or 8/4  2% per quarter) over the remaining 11 quarters and therefore, by the compound interest formula, has an accumulated amount of 100 a 1 

0.08 11 b 4

or

10011  0.022 11

dollars at the end of the term of the annuity (Figure 2). The second payment of $100 made at the end of the second quarter earns interest at the same rate over the remaining 10 quarters and therefore has an accumulated amount of 10011  0.022 10

dollars at the end of the term of the annuity, and so on. The last payment earns no interest because it is due at the end of the term. The amount of the annuity is obtained by adding all the terms in Figure 2. Thus, S  100  100(1  0.02)  100(1  0.02)2      100(1  0.02)11 Payments

$100

$100

$100

$100

$100

$100

$100

Periods 0

1

2

3

9

10

11

12

Quarters Accumulated amounts 100 100 (1 + 0.02) 100 (1 + 0.02)2 • • • 100 (1 + 0.02) 9 100 (1 + 0.02)10 100 (1 + 0.02)11

FIGURE 2 The sum of the accumulated amounts is the amount of the annuity.

The sum on the right is the sum of the first n terms of a geometric progression with first term 100 and common ratio (1  0.02). We show in Section 4.4 that the sum S can be written in the more compact form S  100 c

11  0.022 12  1 0.02

d

 1341.21

or approximately $1341.21. To find a general formula for the accumulated amount S of an annuity, suppose a sum of $R is paid into an account at the end of each period for n periods and that the account earns interest at the rate of i per period. Then, proceeding as we did with the numerical example, we obtain S  R  R11  i2  R11  i2 2      R11  i2 n1 11  i2 n  1  Rc d i

(9)

The expression inside the brackets is commonly denoted by sn|i (read “s angle n at i”) and is called the compound-amount factor. Extensive tables have been constructed that give values of sn|i for different values of i and n (see, for example, Table 1 on our Companion Web site). In terms of the compound-amount factor, S  Rsn|i

(10)

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4 MATHEMATICS OF FINANCE

The quantity S in Equations (9) and (10) is realizable at some future date and is accordingly called the future value of an annuity. Future Value of an Annuity

The future value S of an annuity of n payments of R dollars each, paid at the end of each investment period into an account that earns interest at the rate of i per period, is 11  i2 n  1 S  Rc d i EXAMPLE 1 Find the amount of an ordinary annuity consisting of 12 monthly payments of $100 that earn interest at 12% per year compounded monthly. Solution Since i is the interest rate per period and since interest is compounded monthly in this case, we have i  0.12 12  0.01. Using Equation (9) with R  100, n  12, and i  0.01, we have

S

1003 11.012 12  14

0.01  1268.25 Use a calculator.

or $1268.25. The same result is obtained by observing that S  100s 12|0.01  100112.68252  1268.25 Use Table 1 from the Companion Web site.

Explore & Discuss Future Value S of an Annuity Due 1. Consider an annuity satisfying conditions 1, 2, and 4 on page 204 but with condition 3 replaced by the condition that payments are made at the beginning of the payment periods. By using an argument similar to that used to establish Formula (9), show that the future value S of an annuity due of n payments of R dollars each, paid at the beginning of each investment into an account that earns interest at the rate of i per period, is S  R11  i2 c

11  i 2 n  1 i

d

2. Use the result of part 1 to see how large your nest egg will be at age 65 if you start saving $4000 annually at age 30, assuming a 10% average annual return; if you start saving at 35; if you start saving at 40. [Moral of the story: It is never too early to start saving!]

Exploring with

TECHNOLOGY Refer to the preceding Explore & Discuss problem. 1. Show that if R  4000 and i  0.1, then S  44,000[(1.1)n  1]. Using a graphing utility, plot the graph of f (x)  44,000[(1.1)x  1], using the viewing window [0, 40]  [0, 1,200,000]. 2. Verify the results of part 1 by evaluating f (35), f (30), and f (25) using the EVAL function.

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4.2 ANNUITIES

Present Value of an Annuity In certain instances, you may want to determine the current value P of a sequence of equal periodic payments that will be made over a certain period of time. After each payment is made, the new balance continues to earn interest at some nominal rate. The amount P is referred to as the present value of an annuity. To derive a formula for determining the present value P of an annuity, we may argue as follows. The amount P invested now and earning interest at the rate of i per period will have an accumulated value of P(1  i )n at the end of n periods. But this must be equal to the future value of the annuity S given by Formula (9). Therefore, equating the two expressions, we have P11  i 2 n  R c

11  i2 n  1 i

d

Multiplying both sides of this equation by (1  i )n gives P  R11  i 2 n c  Rc  Rc

11  i2 n  1 i

d

11  i2 n 11  i2 n  11  i 2 n 1  11  i 2 n i

i

d

(1  i )n(1  i )n  1

d

 Ran|i

where the factor an|i (read “a angle n at i”) represents the expression inside the brackets. Extensive tables have also been constructed giving values of an|i for different values of i and n (see Table 1 on the Companion Web site).

Present Value of an Annuity

The present value P of an annuity consisting of n payments of R dollars each, paid at the end of each investment period into an account that earns interest at the rate of i per period, is P  Rc

1  11  i 2 n i

d

(11)

EXAMPLE 2 Find the present value of an ordinary annuity consisting of 24 monthly payments of $100 each and earning interest at 9% per year compounded monthly. Solution

Here, R  100, i  mr  0.09 12  0.0075, and n  24, so by Formula (11)

we have P

10031  11.00752 24 4

0.0075  2188.91

or $2188.91. The same result may be obtained by using Table 1 from the Companion Web site. Thus, P  100a 24|0.0075  100121.88912  2188.91

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4 MATHEMATICS OF FINANCE

APPLIED EXAMPLE 3 Saving for a College Education As a savings program toward Alberto’s college education, his parents decide to deposit $100 at the end of every month into a bank account paying interest at the rate of 6% per year compounded monthly. If the savings program began when Alberto was 6 years old, how much money would have accumulated by the time he turns 18? Solution By the time the child turns 18, the parents would have made 144 deposits into the account. Thus, n  144. Furthermore, we have R  100, r  0.06, and m  12, so i  0.06 12  0.005. Using Equation (9), we find that the amount of money that would have accumulated is given by

S

1003 11.0052 144  14 0.005

 21,015

or $21,015. APPLIED EXAMPLE 4 Financing a Car After making a down payment of $4000 for an automobile, Murphy paid $400 per month for 36 months with interest charged at 12% per year compounded monthly on the unpaid balance. What was the original cost of the car? What portion of Murphy’s total car payments went toward interest charges? Solution

The loan taken up by Murphy is given by the present value of the

annuity P

40031  11.012 36 4 0.01

 400a 36| 0.01

 12,043

or $12,043. Therefore, the original cost of the automobile is $16,043 ($12,043 plus the $4000 down payment). The interest charges paid by Murphy are given by (36)(400)  12,043, or $2,357. One important application of annuities arises in the area of tax planning. During the 1980s, Congress created many tax-sheltered retirement savings plans, such as Individual Retirement Accounts (IRAs), Keogh plans, and Simplified Employee Pension (SEP) plans. These plans are examples of annuities in which the individual is allowed to make contributions (which are often tax deductible) to an investment account. The amount of the contribution is limited by congressional legislation. The taxes on the contributions and/or the interest accumulated in these accounts are deferred until the money is withdrawn—ideally during retirement, when tax brackets should be lower. In the interim period, the individual has the benefit of tax-free growth on his or her investment. Suppose, for example, you are eligible to make a fully deductible contribution to an IRA and you are in a marginal tax bracket of 28%. Additionally, suppose you receive a year-end bonus of $2000 from your employer and have the option of depositing the $2000 into either an IRA or a regular savings account, where both accounts earn interest at an effective annual rate of 8% per year. If you choose to invest your bonus in a regular savings account, you will first have to pay taxes on the $2000, leaving $1440 to invest. At the end of 1 year, you will also have to pay taxes on the interest earned, leaving you with

4.2 ANNUITIES

209

Accumulated Tax on Net   amount interest amount 1555.20

 32.26  1522.94

or $1522.94. On the other hand, if you put the money into the IRA, the entire sum will earn interest, and at the end of 1 year you will have (1.08)($2000), or $2160, in your account. Of course, you will still have to pay taxes on this money when you withdraw it, but you will have gained the advantage of tax-free growth of the larger principal over the years. The disadvantage of this option is that if you withdraw the money before you reach the age of 59 12, you will be liable for taxes on both your contributions and the interest earned, and you will also have to pay a 10% penalty. In practice, the size of the contributions an individual might make to the various retirement plans might vary from year to year. Also, he or she might make the contributions at different payment periods. To simplify our discussion, we will consider examples in which fixed payments are made at regular intervals. Note

APPLIED EXAMPLE 5 IRAs Caroline is planning to make a contribution of $2000 on January 31 of each year into an IRA earning interest at an effective rate of 9% per year. After she makes her 25th payment on January 31 of the year following her retirement, how much will she have in her IRA? Solution The amount of money Caroline will have after her 25th payment into her account is found by using Equation (9) with R  2000, r  0.09, m  1, and t  25, so that i  mr  0.09 and n  mt  25. The required amount is given by

S

20003 11.092 25  14

0.09  169,401.79

or $169,401.79. After-tax-deferred annuities are another type of investment vehicle that allows an individual to build assets for retirement, college funds, or other future needs. The advantage gained in this type of investment is that the tax on the accumulated interest is deferred to a later date. Note that in this type of investment the contributions themselves are not tax deductible. At first glance, the advantage thus gained may seem to be relatively inconsequential, but its true effect is illustrated by the next example. APPLIED EXAMPLE 6 Investment Analysis Both Clark and Colby are salaried individuals, 45 years of age, who are saving for their retirement 20 years from now. Both Clark and Colby are also in the 28% marginal tax bracket. Clark makes a $1000 contribution annually on December 31 into a savings account earning an effective rate of 8% per year. At the same time, Colby makes a $1000 annual payment to an insurance company for an after-tax-deferred annuity. The annuity also earns interest at an effective rate of 8% per year. (Assume that both men remain in the same tax bracket throughout this period, and disregard state income taxes.) a. Calculate how much each man will have in his investment account at the end of 20 years.

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4 MATHEMATICS OF FINANCE

b. Compute the interest earned on each account. c. Show that even if the interest on Colby’s investment were subjected to a tax of 28% upon withdrawal of his investment at the end of 20 years, the net accumulated amount of his investment would still be greater than that of Clark’s. Solution

a. Because Clark is in the 28% marginal tax bracket, the net yield for his investment is (0.72)(8), or 5.76%, per year. Using Formula (9) with R  1000, r  0.0576, m  1, and t  20, so that i  0.0576 and n  mt  20, we see that Clark’s investment will be worth S

10003 11  0.05762 20  14 0.0576

 35,850.49

or $35,850.49 at his retirement. Colby has a tax-sheltered investment with an effective yield of 8% per year. Using Formula (9) with R  1000, r  0.08, m  1, and t  20, so that i  0.08 and n  mt  20, we see that Colby’s investment will be worth S

10003 11  0.082 20  14 0.08

 45,761.96

or $45,761.96 at his retirement. b. Each man will have paid 20(1000), or $20,000, into his account. Therefore, the total interest earned in Clark’s account will be (35,850.49  20,000), or $15,850.49, whereas the total interest earned in Colby’s account will be (45,761.96  20,000), or $25,761.96. c. From part (b) we see that the total interest earned in Colby’s account will be $25,761.96. If it were taxed at 28%, he would still end up with (0.72)(25,761.96), or $18,548.61. This is larger than the total interest of $15,850.49 earned by Clark.

4.2 Self-Check Exercises 1. Phyliss opened an IRA on January 31, 1993, with a contribution of $2000. She plans to make a contribution of $2000 thereafter on January 31 of each year until her retirement in the year 2012 (20 payments). If the account earns interest at the rate of 8%/year compounded yearly, how much will Phyliss have in her account when she retires? 2. Denver Wildcatting Company has an immediate need for a loan. In an agreement worked out with its banker, Denver

assigns its royalty income of $4800/month for the next 3 yr from certain oil properties to the bank, with the first payment due at the end of the first month. If the bank charges interest at the rate of 9%/year compounded monthly, what is the amount of the loan negotiated between the parties? Solutions to Self-Check Exercises 4.2 can be found on page 212.

4.2 Concept Questions 1. In an ordinary annuity, is the term fixed or variable? Are the periodic payments all of the same size, or do they vary in size? Are the payments made at the beginning or the end of the payment period? Do the payment periods coincide with the interest conversion periods?

2. What is the difference between an ordinary annuity and an annuity due? 3. What is the future value of an annuity? Give an example. 4. What is the present value of an annuity? Give an example.

4.2 ANNUITIES

211

4.2 Exercises In Exercises 1–8, find the amount (future value) of each ordinary annuity.

1. $1000/year for 10 yr at 10%/year compounded annually 2. $1500/semiannual period for 8 yr at 9%/year compounded semiannually 3. $1800/quarter for 6 yr at 8%/year compounded quarterly 4. $500/semiannual period for 12 yr at 11%/year compounded semiannually 5. $600/quarter for 9 yr at 12%/year compounded quarterly 6. $150/month for 15 yr at 10%/year compounded monthly 7. $200/month for 20 14 yr at 9%/year compounded monthly 8. $100/week for 7 12 yr at 7.5%/year compounded weekly In Exercises 9–14, find the present value of each ordinary annuity.

9. $5000/year for 8 yr at 8%/year compounded annually 10. $1200/semiannual period for 6 yr at 10%/year compounded semiannually 11. $4000/year for 5 yr at 9%/year compounded yearly 12. $3000/semiannual period for 6 yr at 11%/year compounded semiannually 13. $800/quarter for 7 yr at 12%/year compounded quarterly 14. $150/month for 10 yr at 8%/year compounded monthly 15. IRAS If a merchant deposits $1500 at the end of each tax year in an IRA paying interest at the rate of 8%/year compounded annually, how much will she have in her account at the end of 25 yr? 16. SAVINGS ACCOUNTS If Jackson deposits $100 at the end of each month in a savings account earning interest at the rate of 8%/year compounded monthly, how much will he have on deposit in his savings account at the end of 6 yr, assuming that he makes no withdrawals during that period? 17. SAVINGS ACCOUNTS Linda has joined a “Christmas Fund Club” at her bank. At the end of every month, December through October inclusive, she will make a deposit of $40 in her fund. If the money earns interest at the rate of 7%/year compounded monthly, how much will she have in her account on December 1 of the following year? 18. KEOGH ACCOUNTS Robin, who is self-employed, contributes $5000/year into a Keogh account. How much will he have in the account after 25 yr if the account earns interest at the rate of 8.5%/year compounded yearly? 19. RETIREMENT PLANNING As a fringe benefit for the past 12 yr, Colin’s employer has contributed $100 at the end of each month into an employee retirement account for Colin that pays interest at the rate of 7%/year compounded monthly. Colin has also contributed $2000 at the end of

each of the last 8 yr into an IRA that pays interest at the rate of 9%/year compounded yearly. How much does Colin have in his retirement fund at this time? 20. SAVINGS ACCOUNTS The Pirerras are planning to go to Europe 3 yr from now and have agreed to set aside $150/month for their trip. If they deposit this money at the end of each month into a savings account paying interest at the rate of 8%/year compounded monthly, how much money will be in their travel fund at the end of the third year? 21. INVESTMENT ANALYSIS Karen has been depositing $150 at the end of each month in a tax-free retirement account since she was 25. Matt, who is the same age as Karen, started depositing $250 at the end of each month in a taxfree retirement account when he was 35. Assuming that both accounts have been and will be earning interest at the rate of 5%/year compounded monthly, who will end up with the larger retirement account at the age of 65? 22. INVESTMENT ANALYSIS Luis has $150,000 in his retirement account at his present company. Because he is assuming a position with another company, Luis is planning to “roll over” his assets to a new account. Luis also plans to put $3000/quarter into the new account until his retirement 20 yr from now. If the account earns interest at the rate of 8%/year compounded quarterly, how much will Luis have in his account at the time of his retirement? Hint: Use the compound interest formula and the annuity formula.

23. AUTO LEASING The Betzes have leased an auto for 2 yr at $450/month. If money is worth 9%/year compounded monthly, what is the equivalent cash payment (present value) of this annuity? 24. AUTO FINANCING Lupé made a down payment of $4000 toward the purchase of a new car. To pay the balance of the purchase price, she has secured a loan from her bank at the rate of 12%/year compounded monthly. Under the terms of her finance agreement, she is required to make payments of $420/month for 36 mo. What is the cash price of the car? 25. INSTALLMENT PLANS Mike’s Sporting Goods sells elliptical trainers under two payment plans: cash or installment. Under the installment plan, the customer pays $22/month over 3 yr with interest charged on the balance at a rate of 18%/year compounded monthly. Find the cash price for an elliptical trainer if it is equivalent to the price paid by a customer using the installment plan. 26. LOTTERY PAYOUTS A state lottery commission pays the winner of the “Million Dollar” lottery 20 installments of $50,000/year. The commission makes the first payment of $50,000 immediately and the other n  19 payments at the end of each of the next 19 yr. Determine how much money the commission should have in the bank initially to guarantee the payments, assuming that the balance on deposit with the bank earns interest at the rate of 8%/year compounded yearly. Hint: Find the present value of an annuity.

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4 MATHEMATICS OF FINANCE

27. PURCHASING A HOME The Johnsons have accumulated a nest egg of $40,000 that they intend to use as a down payment toward the purchase of a new house. Because their present gross income has placed them in a relatively high tax bracket, they have decided to invest a minimum of $2400/month in monthly payments (to take advantage of the tax deduction) toward the purchase of their house. However, because of other financial obligations, their monthly payments should not exceed $3000. If local mortgage rates are 7.5%/year compounded monthly for a conventional 30-yr mortgage, what is the price range of houses that they should consider? 28. PURCHASING A HOME Refer to Exercise 27. If local mortgage rates were increased to 8%, how would this affect the price range of houses that the Johnsons should consider? 29. PURCHASING A HOME Refer to Exercise 27. If the Johnsons decide to secure a 15-yr mortgage instead of a 30-yr mortgage, what is the price range of houses they should consider when the local mortgage rate for this type of loan is 7%? 30. SAVINGS PLAN Lauren plans to deposit $5000 into a bank account at the beginning of next month and $200/month into the same account at the end of that month and at the end of each subsequent month for the next 5 yr. If her bank pays interest at the rate of 6%/year compounded monthly, how much will Lauren have in her account at the end of 5 yr? (Assume she makes no withdrawals during the 5-yr period.)

31. FINANCIAL PLANNING Joe plans to deposit $200 at the end of each month into a bank account for a period of 2 yr, after which he plans to deposit $300 at the end of each month into the same account for another 3 yr. If the bank pays interest at the rate of 6%/year compounded monthly, how much will Joe have in his account by the end of 5 yr? (Assume no withdrawals are made during the 5-yr period.) 32. INVESTMENT ANALYSIS From age 25 to age 40, Jessica deposited $200 at the end of each month into a tax-free retirement account. She made no withdrawals or further contributions until age 65. Alex made deposits of $300 into his tax-free retirement account from age 40 to age 65. If both accounts earned interest at the rate of 5%/year compounded monthly, who ends up with a bigger nest egg upon reaching the age of 65? Hint: Use both the annuity formula and the compound interest formula.

In Exercises 33 and 34, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

33. The future value of an annuity can be found by adding together all the payments that are paid into the account. 34. If the future value of an annuity consisting of n payments of R dollars each—paid at the end of each investment period into an account that earns interest at the rate of i per period—is S dollars, then R

iS 11  i 2 n  1

4.2 Solutions to Self-Check Exercises 1. The amount Phyliss will have in her account when she retires may be found by using Formula (9) with R  2000, r  0.08, m  1, and t  20, so that i  r  0.08 and n  mt  20. Thus, S

2000 3 11.08 2 20  1 4 0.08

P

 91,523.93

TECHNOLOGY

4800 31  11.00752 36 4 0.0075

 150,944.67

or $150,944.67, the amount of the loan negotiated.

or $91,523.93.

USING

2. We want to find the present value of an ordinary annuity consisting of 36 monthly payments of $4800 each and earning interest at 9%/year compounded monthly. Using Formula (11) with R  4800, m  12, and t  3, so that i  mr  0.09 12  0.0075 and n  (12)(3)  36, we find

Finding the Amount of an Annuity Graphing Utility

As mentioned in Using Technology, Section 4.1, the TI-83/84 can facilitate the solution of problems in finance. We continue to exploit its versatility in this section. EXAMPLE 1 Finding the Future Value of an Annuity Find the amount of an ordinary annuity of 36 quarterly payments of $220 each that earn interest at the rate of 10% per year compounded quarterly.

4.2 ANNUITIES

Solution

213

We use the TI-83/84 TVM SOLVER with the following inputs: N  36 I%  10 PV  0 Recall that a payment is an outflow. PMT  220 FV  0 The number of payments each year P/Y  4 C/Y  4 The number of conversion periods each year PMT:END BEGIN

The result is displayed in Figure T1. We deduce that the desired amount is $12,606.31.

FIGURE T1 The TI-83/84 screen showing the future value (FV) of an annuity

N = 36 I% = 10 PV = 0 PMT = −220 FV = 12606.31078 P/Y = 4 C/Y = 4 PMT : END BEGIN

EXAMPLE 2 Finding the Present Value of an Annuity Find the present value of an ordinary annuity consisting of 48 monthly payments of $300 each and earning interest at the rate of 9% per year compounded monthly. Solution

We use the TI-83/84 TVM SOLVER with the following inputs: N  48 I%  9 PV  0 A payment is an outflow. PMT  300 FV  0 The number of payments each year P/Y  12 C/Y  12 The number of conversion periods each year PMT:END BEGIN

The output is displayed in Figure T2. We see that the required present value of the annuity is $12,055.43.

FIGURE T2 The TI-83/84 screen showing the present value (PV) of an ordinary annuity

N = 48 I% = 9 PV = 12055.43457 PMT = −300 FV = 0 P/Y = 12 C/Y = 12 PMT : END BEGIN

Excel

Now we show how Excel can be used to solve financial problems involving annuities. EXAMPLE 3 Finding the Future Value of an Annuity Find the amount of an ordinary annuity of 36 quarterly payments of $220 each that earn interest at the rate of 10% per year compounded quarterly.

(continued)

214

4 MATHEMATICS OF FINANCE

Solution Here we are computing the future value of a series of equal payments, so we use the FV (future value) function. As before, we access the Insert Function dialog box to obtain the Function Arguments dialog box. After making each of the required entries, we obtain the dialog box shown in Figure T3.

FIGURE T3 Excel’s dialog box for the future value (FV) of an annuity

Note that a 0 is entered in the Type edit box because payments are made at the end of each payment period. Once again, the answer is negative because cash is paid out. We deduce that the desired amount is $12,606.31. EXAMPLE 4 Finding the Present Value of an Annuity Find the present value of an ordinary annuity consisting of 48 monthly payments of $300 each and earning interest at the rate of 9% per year compounded monthly. Here we use the PV function to compute the present value of an annuity. Accessing the PV (present value) function from the Insert Function dialog box and making the required entries, we obtain the PV dialog box shown in Figure T4. We see that the required present value of the annuity is $12,055.43.

Solution

FIGURE T4 Excel’s dialog box for computing the present value (PV) of an annuity

Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen.

215

4.3 AMORTIZATION AND SINKING FUNDS

TECHNOLOGY EXERCISES 1. Find the amount of an ordinary annuity of 20 payments of $2500/quarter at 714%/year compounded quarterly.

8. Find the present value of an ordinary annuity of $185/month for 12 yr earning interest at 658%/year compounded monthly.

2. Find the amount of an ordinary annuity of 24 payments of $1790/quarter at 834%/year compounded quarterly.

9. ANNUITIES At the time of retirement, Christine expects to have a sum of $500,000 in her retirement account. Assuming that the account pays interest at the rate of 5%/year compounded continuously, her accountant pointed out to her that if she made withdrawals amounting to x dollars per year (x  25,000), then the time required to deplete her savings would be T years, where

3. Find the amount of an ordinary annuity of $120/month for 5 yr at 638%/year compounded monthly. 4. Find the amount of an ordinary annuity of $225/month for 6 yr at 758%/year compounded monthly.

T  f 1x 2  20 ln a

5. Find the present value of an ordinary annuity of $4500/ semiannual period for 5 yr earning interest at 9%/year compounded semiannually.

x b x  25,000

1x  25,0002

a. Plot the graph of f, using the viewing window [25,000, 50,000]  [0, 100]. b. How much should Christine plan to withdraw from her retirement account each year if she wants it to last for 25 yr?

6. Find the present value of an ordinary annuity of $2100/ quarter for 7 yr earning interest at 718%/year compounded quarterly. 7. Find the present value of an ordinary annuity of $245/month for 6 yr earning interest at 838%/year compounded monthly.

4.3 Amortization and Sinking Funds Amortization of Loans The annuity formulas derived in Section 4.2 may be used to answer questions involving the amortization of certain types of installment loans. For example, in a typical housing loan the mortgagor makes periodic payments toward reducing his indebtedness to the lender, who charges interest at a fixed rate on the unpaid portion of the debt. In practice, the borrower is required to repay the lender in periodic installments, usually of the same size and over a fixed term, so that the loan (principal plus interest charges) is amortized at the end of the term. By thinking of the monthly loan repayments R as the payments in an annuity, we see that the original amount of the loan is given by P, the present value of the annuity. From Equation (11), Section 4.2, we have P  Rc

1  11  i2 n i

d  Ran|i

(12)

A question a financier might ask is: How much should the monthly installment be so that a loan will be amortized at the end of the term of the loan? To answer this question, we simply solve (12) for R in terms of P, obtaining R

Pi P  an|i 1  11  i 2 n

Amortization Formula

The periodic payment R on a loan of P dollars to be amortized over n periods with interest charged at the rate of i per period is R

Pi 1  11  i 2 n

(13)

216

4 MATHEMATICS OF FINANCE

APPLIED EXAMPLE 1 Amortization Schedule A sum of $50,000 is to be repaid over a 5-year period through equal installments made at the end of each year. If an interest rate of 8% per year is charged on the unpaid balance and interest calculations are made at the end of each year, determine the size of each installment so that the loan (principal plus interest charges) is amortized at the end of 5 years. Verify the result by displaying the amortization schedule. Substituting P  50,000, i  r  0.08 (here, m  1), and n  5 into Formula (13), we obtain

Solution

R

150,0002 10.082 1  11.082 5

 12,522.82

giving the required yearly installment as $12,522.82. The amortization schedule is presented in Table 3. The outstanding principal at the end of 5 years is, of course, zero. (The figure of $.01 in Table 3 is the result of round-off errors.) Observe that initially the larger portion of the repayment goes toward payment of interest charges, but as time goes by more and more of the payment goes toward repayment of the principal.

TABLE 3 An Amortization Schedule

End of Period

Interest Charged

Repayment Made

Payment Toward Principal

Outstanding Principal

0 1 2 3 4 5

— $4,000.00 3,318.17 2,581.80 1,786.52 927.62

— $12,522.82 12,522.82 12,522.82 12,522.82 12,522.82

— $ 8,522.82 9,204.65 9,941.02 10,736.30 11,595.20

$50,000.00 41,477.18 32,272.53 22,331.51 11,595.21 0.01

Financing a Home APPLIED EXAMPLE 2 Home Mortgage Payments The Blakelys borrowed $120,000 from a bank to help finance the purchase of a house. The bank charges interest at a rate of 9% per year on the unpaid balance, with interest computations made at the end of each month. The Blakelys have agreed to repay the loan in equal monthly installments over 30 years. How much should each payment be if the loan is to be amortized at the end of the term? Here, P  120,000, i  mr  0.09 12  0.0075, and n  (30)(12)  360. Using Formula (13) we find that the size of each monthly installment required is given by Solution

R

1120,0002 10.00752

1  11.00752 360  965.55

or $965.55.

4.3 AMORTIZATION AND SINKING FUNDS

217

APPLIED EXAMPLE 3 Home Equity Teresa and Raul purchased a house 10 years ago for $200,000. They made a down payment of 20% of the purchase price and secured a 30-year conventional home mortgage at 9% per year on the unpaid balance. The house is now worth $380,000. How much equity do Teresa and Raul have in their house now (after making 120 monthly payments)? Solution Since the down payment was 20%, we know that they secured a loan of 80% of $200,000, or $160,000. Furthermore, using Formula (13) with P  160,000, i  mr  0.09 12  0.0075 and n  (30)(12)  360, we determine that their monthly installment is

R

1160,0002 10.00752 1  11.00752 360

 1287.40

or $1287.40. After 120 monthly payments have been made, the outstanding principal is given by the sum of the present values of the remaining installments (that is, 360  120  240 installments). But this sum is just the present value of an annuity with n  240, R  1287.40, and i  0.0075. Using Formula (11), we find P  1287.40 c

1  11  0.00752 240 0.0075

d

 143,088.01

or approximately $143,088. Therefore, Teresa and Raul have an equity of 380,000  143,088, that is, $236,912.

Explore & Discuss and Exploring with Technology 1. Consider the amortization Formula (13): R

Pi 1  11  i2 n

Suppose you know the values of R, P, and n and you wish to determine i. Explain why you can accomplish this task by finding the point of intersection of the graphs of the functions y1  R and

y2 

Pi 1  11  i2 n

2. Thalia knows that her monthly repayment on her 30-year conventional home loan of $150,000 is $1100.65 per month. Help Thalia determine the interest rate for her loan by verifying or executing the following steps: a. Plot the graphs of y1  1100.65

and y2 

150,000x

1  11  x 2 360

using the viewing window [0, 0.01]  [0, 1200]. b. Use the ISECT (intersection) function of the graphing utility to find the point of intersection of the graphs of part (a). Explain why this gives the value of i. c. Compute r from the relationship r  12i.

218

4 MATHEMATICS OF FINANCE

Explore & Discuss and Exploring with Technology 1. Suppose you secure a home mortgage loan of $P with an interest rate of r per year to be amortized over t years through monthly installments of $R. Show that, after N installments, your outstanding principal is given by B1N 2  P c Hint: B1N 2  R c

11  i2 n  11  i2 N 11  i 2 n  1

1  11  i2 nN i

d

(0 N n)

d . To see this, study Example 3, page 217. Replace R using

Formula (13).

2. Refer to Example 3, page 217. Using the result of part 1, show that Teresa and Raul’s outstanding balance after making N payments is E1N 2 

160,00011.0075360  1.0075N 2

(0 N 360)

1.0075360  1

3. Using a graphing utility, plot the graph of E1x 2 

160,00011.0075360  1.0075x 2 1.0075360  1

using the viewing window [0, 360]  [0, 160,000]. 4. Referring to the graph in part 3, observe that the outstanding principal drops off slowly in the early years and accelerates quickly to zero toward the end of the loan. Can you explain why? 5. How long does it take Teresa and Raul to repay half of the loan of $160,000? Hint: See the previous Explore & Discuss and Exploring with Technology box.

APPLIED EXAMPLE 4 Home Affordability The Jacksons have determined that, after making a down payment, they could afford at most $2000 for a monthly house payment. The bank charges interest at the rate of 7.2% per year on the unpaid balance, with interest computations made at the end of each month. If the loan is to be amortized in equal monthly installments over 30 years, what is the maximum amount that the Jacksons can borrow from the bank? Here, i  mr  0.072 12  0.006, n  (30)(12)  360, and R  2000; we are required to find P. From Equation (12), we have

Solution

P

R31  11  i2 n 4 i

Substituting the numerical values for R, n, and i into this expression for P, we obtain P

200031  11.0062 360 4 0.006

 294,643

Therefore, the Jacksons can borrow at most $294,643. An adjustable-rate mortgage (ARM) is a home loan in which the interest rate is changed periodically based on a financial index. For example, a 5/1 ARM is one that

4.3 AMORTIZATION AND SINKING FUNDS

219

has an initial rate for the first 5 years, and thereafter is adjusted every year for the remaining term of the loan. APPLIED EXAMPLE 5 Adjustable Rate Mortgages Five years ago, the Campbells secured a 5/1 ARM to help finance the purchase of their home. The amount of the original loan was $350,000 for a term of 30 years, with interest at the rate of 5.76% per year, compounded monthly. The Campbells’ mortgage is due to reset next month and the new interest rate will be 6.96% per year, compounded monthly. a. What was the Campbells’ monthly mortgage payment for the first 5 years? b. What will the Campbells’ new monthly mortgage payment be (after the reset)? By how much will the monthly payment increase? Solution

a. First, we find the Campbells’ monthly payment on the original loan amount. Using Formula (13) with P  350,000, i  mr  0.0576 12 , and n  mt  (12)(30)  360, we find that the monthly payment was R

350,0001 0.0576 12 2

360 1  11  0.0576 12 2

 2044.729

or $2044.73 for the first 5 years. b. In order to find the amount of the Campbells’ new mortgage payment, we first need to find their outstanding principal. This is given by the present value of their remaining mortgage payments. Using Formula (11), with R  2044.729, i  mr  0.0576 12 , and n  mt  360  5(12)  300, we find that their outstanding principal is P  2044.729 c

300 1  11  0.0576 12 2 0.0576 12

d  324,709.194

or $324,709.19. Next, we compute the amount of their new mortgage payment for the remaining term (300 months). Using Formula (13) with P  324,709.194, i  mr  0.0696 12 , and n  mt  300, we find that the monthly payment is R

324,709.1941 0.0696 12 2

300 1  11  0.0696 12 2

 2286.698

or $2286.70—an increase of $241.97.

Sinking Funds Sinking funds are another important application of the annuity formulas. Simply stated, a sinking fund is an account that is set up for a specific purpose at some future date. For example, an individual might establish a sinking fund for the purpose of discharging a debt at a future date. A corporation might establish a sinking fund in order to accumulate sufficient capital to replace equipment that is expected to be obsolete at some future date. By thinking of the amount to be accumulated by a specific date in the future as the future value of an annuity [Equation (9), Section 4.2], we can answer questions about a large class of sinking fund problems.

220

4 MATHEMATICS OF FINANCE

APPLIED EXAMPLE 6 Sinking Fund The proprietor of Carson Hardware has decided to set up a sinking fund for the purpose of purchasing a truck in 2 years’ time. It is expected that the truck will cost $30,000. If the fund earns 10% interest per year compounded quarterly, determine the size of each (equal) quarterly installment the proprietor should pay into the fund. Verify the result by displaying the schedule. Solution The problem at hand is to find the size of each quarterly payment R of an annuity given that its future value is S  30,000, the interest earned per conversion period is i  mr  0.1 4  0.025, and the number of payments is n  (2)(4)  8. The formula for an annuity,

S  Rc

11  i2 n  1 i

d

when solved for R yields R

iS 11  i2 n  1

(14)

or, equivalently, R

S sn|i

Substituting the appropriate numerical values for i, S, and n into Equation (14), we obtain the desired quarterly payment R

10.0252 130,0002 11.0252 8  1

 3434.02

or $3434.02. Table 4 shows the required schedule. TABLE 4 A Sinking Fund Schedule

End of Period

Deposit Made

Interest Earned

Addition to Fund

Accumulated Amount in Fund

1 2 3 4 5 6 7 8

$3,434.02 3,434.02 3,434.02 3,434.02 3,434.02 3,434.02 3,434.02 3,434.02

0 $ 85.85 173.85 264.04 356.50 451.26 548.39 647.95

$3,434.02 3,519.87 3,607.87 3,698.06 3,790.52 3,885.28 3,982.41 4,081.97

$ 3,434.02 6,953.89 10,561.76 14,259.82 18,050.34 21,935.62 25,918.03 30,000.00

The formula derived in this last example is restated as follows.

Sinking Fund Payment

The periodic payment R required to accumulate a sum of S dollars over n periods with interest charged at the rate of i per period is R

iS 11  i2 n  1

(15)

221

4.3 AMORTIZATION AND SINKING FUNDS

Here is a summary of the formulas developed thus far in this chapter: 1. Simple and compound interest; annuities One deposit

Simple interest

A  P11  rt 2 I  Prt

Periodic deposits

Compound interest

Future value of an annuity

A  P11  i 2 n S  Rc n P  A11  i2 A  Pe rt Continuous compounding rt P  Ae Continuous compounding

11  i 2 n  1 i

Present value of an annuity

d

P  Rc

1  11  i2 n i

d

2. Effective rate of interest reff  a 1 

r m b 1 m

3. Amortization R

Pi 1  11  i 2 n

P  Rc

Periodic payment

1  11  i 2 n i

d

Amount amortized

4. Sinking fund R

iS 11  i2 n  1

Periodic payment taken out

4.3 Self-Check Exercises 1. The Mendozas wish to borrow $300,000 from a bank to help finance the purchase of a house. Their banker has offered the following plans for their consideration. In plan I, the Mendozas have 30 yr to repay the loan in monthly installments with interest on the unpaid balance charged at 6.09%/year compounded monthly. In plan II, the loan is to be repaid in monthly installments over 15 yr with interest on the unpaid balance charged at 5.76%/year compounded monthly. a. Find the monthly repayment for each plan. b. What is the difference in total payments made under each plan?

2. Harris, a self-employed individual who is 46 yr old, is setting up a defined-benefit retirement plan. If he wishes to have $250,000 in this retirement account by age 65, what is the size of each yearly installment he will be required to make into a savings account earning interest at 814%/year? Solutions to Self-Check Exercises 4.3 can be found on page 225.

4.3 Concept Questions 1. Write the amortization formula. a. If P and i are fixed and n is allowed to increase, what will happen to R? b. Interpret the result of part (a).

2. Using the formula for computing a sinking fund payment, show that if the number of payments into a sinking fund increases, then the size of the periodic payment into the sinking fund decreases.

222

4 MATHEMATICS OF FINANCE

4.3 Exercises In Exercises 1–8, find the periodic payment R required to amortize a loan of P dollars over t yr with interest charged at the rate of r %/year compounded m times a year.

1. P  100,000, r  8, t  10, m  1 2. P  40,000, r  3, t  15, m  2 3. P  5000, r  4, t  3, m  4 4. P  16,000, r  9, t  4, m  12 5. P  25,000, r  3, t  12, m  4 6. P  80,000, r  10.5, t  15, m  12 7. P  80,000, r  10.5, t  30, m  12 8. P  100,000, r  10.5, t  25, m  12 In Exercises 9–14, find the periodic payment R required to accumulate a sum of S dollars over t yr with interest earned at the rate of r %/year compounded m times a year.

9. S  20,000, r  4, t  6, m  2 10. S  40,000, r  4, t  9, m  4 11. S  100,000, r  4.5, t  20, m  6 12. S  120,000, r  4.5, t  30, m  6 13. S  250,000, r  10.5, t  25, m  12 14. S  350,000, r  7.5, t  10, m  12 15. Suppose payments were made at the end of each quarter into an ordinary annuity earning interest at the rate of 10%/year compounded quarterly. If the future value of the annuity after 5 yr is $50,000, what was the size of each payment? 16. Suppose payments were made at the end of each month into an ordinary annuity earning interest at the rate of 9%/year compounded monthly. If the future value of the annuity after 10 yr is $60,000, what was the size of each payment? 17. Suppose payments will be made for 612 yr at the end of each semiannual period into an ordinary annuity earning interest at the rate of 7.5%/year compounded semiannually. If the present value of the annuity is $35,000, what should be the size of each payment? 18. Suppose payments will be made for 914 yr at the end of each month into an ordinary annuity earning interest at the rate of 6.25%/year compounded monthly. If the present value of the annuity is $42,000, what should be the size of each payment? 19. LOAN AMORTIZATION A sum of $100,000 is to be repaid over a 10-yr period through equal installments made at the end of each year. If an interest rate of 10%/year is charged

on the unpaid balance and interest calculations are made at the end of each year, determine the size of each installment so that the loan (principal plus interest charges) is amortized at the end of 10 yr. 20. LOAN AMORTIZATION What monthly payment is required to amortize a loan of $30,000 over 10 yr if interest at the rate of 12%/year is charged on the unpaid balance and interest calculations are made at the end of each month? 21. HOME MORTGAGES Complete the following table, which shows the monthly payments on a $100,000, 30-yr mortgage at the interest rates shown. Use this information to answer the following questions. Amount of Mortgage, $ 100,000 100,000 100,000 100,000 100,000 100,000

Interest Rate, % 7 8 9 10 11 12

Monthly Payment, $ 665.30     1028.61

a. What is the difference in monthly payments between a $100,000, 30-yr mortgage secured at 7%/year and one secured at 10%/year? b. Use the table to calculate the monthly mortgage payments on a $150,000 mortgage at 10%/year over 30 yr and a $50,000 mortgage at 10%/year over 30 yr. 22. FINANCING A HOME The Flemings secured a bank loan of $288,000 to help finance the purchase of a house. The bank charges interest at a rate of 9%/year on the unpaid balance, and interest computations are made at the end of each month. The Flemings have agreed to repay the loan in equal monthly installments over 25 yr. What should be the size of each repayment if the loan is to be amortized at the end of the term? 23. FINANCING A CAR The price of a new car is $16,000. Assume that an individual makes a down payment of 25% toward the purchase of the car and secures financing for the balance at the rate of 10%/year compounded monthly. a. What monthly payment will she be required to make if the car is financed over a period of 36 mo? Over a period of 48 mo? b. What will the interest charges be if she elects the 36-mo plan? The 48-mo plan? 24. FINANCIAL ANALYSIS A group of private investors purchased a condominium complex for $2 million. They made an initial down payment of 10% and obtained financing for the balance. If the loan is to be amortized over 15 yr at an interest rate of 12%/year compounded quarterly, find the required quarterly payment. 25. FINANCING A HOME The Taylors have purchased a $270,000 house. They made an initial down payment of $30,000 and secured a mortgage with interest charged at

4.3 AMORTIZATION AND SINKING FUNDS

the rate of 8%/year on the unpaid balance. Interest computations are made at the end of each month. If the loan is to be amortized over 30 yr, what monthly payment will the Taylors be required to make? What is their equity (disregarding appreciation) after 5 yr? After 10 yr? After 20 yr? 26. FINANCIAL PLANNING Jessica wants to accumulate $10,000 by the end of 5 yr in a special bank account, which she had opened for this purpose. To achieve this goal, Jessica plans to deposit a fixed sum of money into the account at the end of each month over the 5-yr period. If the bank pays interest at the rate of 5%/year compounded monthly, how much does she have to deposit each month into her account? 27. SINKING FUNDS A city has $2.5 million worth of school bonds that are due in 20 yr and has established a sinking fund to retire this debt. If the fund earns interest at the rate of 7%/year compounded annually, what amount must be deposited annually in this fund? 28. TRUST FUNDS Carl is the beneficiary of a $20,000 trust fund set up for him by his grandparents. Under the terms of the trust, he is to receive the money over a 5-yr period in equal installments at the end of each year. If the fund earns interest at the rate of 9%/year compounded annually, what amount will he receive each year? 29. SINKING FUNDS Lowell Corporation wishes to establish a sinking fund to retire a $200,000 debt that is due in 10 yr. If the investment will earn interest at the rate of 9%/year compounded quarterly, find the amount of the quarterly deposit that must be made in order to accumulate the required sum. 30. SINKING FUNDS The management of Gibraltar Brokerage Services anticipates a capital expenditure of $20,000 in 3 yr for the purchase of new computers and has decided to set up a sinking fund to finance this purchase. If the fund earns interest at the rate of 10%/year compounded quarterly, determine the size of each (equal) quarterly installment that should be deposited in the fund. 31. RETIREMENT ACCOUNTS Andrea, a self-employed individual, wishes to accumulate a retirement fund of $250,000. How much should she deposit each month into her retirement account, which pays interest at the rate of 8.5%/year compounded monthly, to reach her goal upon retirement 25 yr from now? 32. STUDENT LOANS Joe secured a loan of $12,000 3 yr ago from a bank for use toward his college expenses. The bank charged interest at the rate of 4%/year compounded monthly on his loan. Now that he has graduated from college, Joe wishes to repay the loan by amortizing it through monthly payments over 10 yr at the same interest rate. Find the size of the monthly payments he will be required to make. 33. RETIREMENT ACCOUNTS Robin wishes to accumulate a sum of $450,000 in a retirement account by the time of her retirement 30 yr from now. If she wishes to do this through monthly payments into the account that earn interest at the rate of 10%/year compounded monthly, what should be the size of each payment?

223

34. FINANCING COLLEGE EXPENSES Yumi’s grandparents presented her with a gift of $20,000 when she was 10 yr old to be used for her college education. Over the next 7 yr, until she turned 17, Yumi’s parents had invested her money in a tax-free account that had yielded interest at the rate of 5.5%/year compounded monthly. Upon turning 17, Yumi now plans to withdraw her funds in equal annual installments over the next 4 yr, starting at age 18. If the college fund is expected to earn interest at the rate of 6%/year, compounded annually, what will be the size of each installment? 35. IRAS Martin has deposited $375 in his IRA at the end of each quarter for the past 20 yr. His investment has earned interest at the rate of 8%/year compounded quarterly over this period. Now, at age 60, he is considering retirement. What quarterly payment will he receive over the next 15 yr? (Assume that the money is earning interest at the same rate and that payments are made at the end of each quarter.) If he continues working and makes quarterly payments of the same amount in his IRA until age 65, what quarterly payment will he receive from his fund upon retirement over the following 10 yr? 36. FINANCING A CAR Darla purchased a new car during a special sales promotion by the manufacturer. She secured a loan from the manufacturer in the amount of $16,000 at a rate of 7.9%/year compounded monthly. Her bank is now charging 11.5%/year compounded monthly for new car loans. Assuming that each loan would be amortized by 36 equal monthly installments, determine the amount of interest she would have paid at the end of 3 yr for each loan. How much less will she have paid in interest payments over the life of the loan by borrowing from the manufacturer instead of her bank? 37. AUTO FINANCING Dan is contemplating trading in his car for a new one. He can afford a monthly payment of at most $400. If the prevailing interest rate is 7.2%/year compounded monthly for a 48-mo loan, what is the most expensive car that Dan can afford, assuming that he will receive $8000 for the trade-in? 38. AUTO FINANCING Paula is considering the purchase of a new car. She has narrowed her search to two cars that are equally appealing to her. Car A costs $28,000, and car B costs $28,200. The manufacturer of car A is offering 0% financing for 48 months with zero down, while the manufacturer of car B is offering a rebate of $2000 at the time of purchase plus financing at the rate of 3%/year compounded monthly over 48 mo with zero down. If Paula has decided to buy the car with the lower net cost to her, which car should she purchase? 39. FINANCING A HOME The Sandersons are planning to refinance their home. The outstanding principal on their original loan is $100,000 and was to be amortized in 240 equal monthly installments at an interest rate of 10%/year compounded monthly. The new loan they expect to secure is to be amortized over the same period at an interest rate of 7.8%/year compounded monthly. How much less can they expect to pay over the life of the loan in interest payments by refinancing the loan at this time?

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4 MATHEMATICS OF FINANCE

40. INVESTMENT ANALYSIS Since he was 22 years old, Ben has been depositing $200 at the end of each month into a taxfree retirement account earning interest at the rate of 6.5%/year compounded monthly. Larry, who is the same age as Ben, decided to open a tax-free retirement account 5 yr after Ben opened his. If Larry’s account earns interest at the same rate as Ben’s, determine how much Larry should deposit each month into his account so that both men will have the same amount of money in their accounts at age 65. 41. PERSONAL LOANS Two years ago, Paul borrowed $10,000 from his sister Gerri to start a business. Paul agreed to pay Gerri interest for the loan at the rate of 6%/year, compounded continuously. Paul will now begin repaying the amount he owes by amortizing the loan (plus the interest that has accrued over the past 2 yr) through monthly payments over the next 5 yr at an interest rate of 5%/year compounded monthly. Find the size of the monthly payments Paul will be required to make. 42. REFINANCING A HOME Josh purchased a condominium 5 yr ago for $180,000. He made a down payment of 20% and financed the balance with a 30-yr conventional mortgage to be amortized through monthly payments with an interest rate of 7%/year compounded monthly on the unpaid balance. The condominium is now appraised at $250,000. Josh plans to start his own business and wishes to tap into the equity that he has in the condominium. If Josh can secure a new mortgage to refinance his condominium based on a loan of 80% of the appraised value, how much cash can Josh muster for his business? (Disregard taxes.) 43. FINANCING A HOME Eight years ago, Kim secured a bank loan of $180,000 to help finance the purchase of a house. The mortgage was for a term of 30 yr, with an interest rate of 9.5%/year compounded monthly on the unpaid balance to be amortized through monthly payments. What is the outstanding principal on Kim’s house now? 44. BALLOON PAYMENT MORTGAGES Olivia plans to secure a 5-yr balloon mortgage of $200,000 toward the purchase of a condominium. Her monthly payment for the 5 yr is calculated on the basis of a 30-yr conventional mortgage at the rate of 6%/year compounded monthly. At the end of the 5 yr, Olivia is required to pay the balance owed (the “balloon” payment). What will be her monthly payment, and what will be her balloon payment? 45. BALLOON PAYMENT MORTGAGES Emilio is securing a 7-yr Fannie Mae “balloon” mortgage for $280,000 to finance the purchase of his first home. The monthly payments are based on a 30-yr amortization. If the prevailing interest rate is 7.5%/year compounded monthly, what will be Emilio’s monthly payment? What will be his “balloon” payment at the end of 7 yr? 46. FINANCING A HOME Sarah secured a bank loan of $200,000 for the purchase of a house. The mortgage is to be amortized through monthly payments for a term of 15 yr, with

an interest rate of 6%/year compounded monthly on the unpaid balance. She plans to sell her house in 5 yr. How much will Sarah still owe on her house? 47. HOME REFINANCING Four years ago, Emily secured a bank loan of $200,000 to help finance the purchase of an apartment in Boston. The term of the mortgage is 30 yr, and the interest rate is 9.5%/year compounded monthly. Because the interest rate for a conventional 30-yr home mortgage has now dropped to 6.75%/year compounded monthly, Emily is thinking of refinancing her property. a. What is Emily’s current monthly mortgage payment? b. What is Emily’s current outstanding principal? c. If Emily decides to refinance her property by securing a 30-yr home mortgage loan in the amount of the current outstanding principal at the prevailing interest rate of 6.75%/year compounded monthly, what will be her monthly mortgage payment? d. How much less would Emily’s monthly mortgage payment be if she refinances? 48. HOME REFINANCING Five years ago, Diane secured a bank loan of $300,000 to help finance the purchase of a loft in the San Francisco Bay area. The term of the mortgage was 30 yr, and the interest rate was 9%/year compounded monthly on the unpaid balance. Because the interest rate for a conventional 30-yr home mortgage has now dropped to 7%/year compounded monthly, Diane is thinking of refinancing her property. a. What is Diane’s current monthly mortgage payment? b. What is Diane’s current outstanding principal? c. If Diane decides to refinance her property by securing a 30-yr home mortgage loan in the amount of the current outstanding principal at the prevailing interest rate of 7%/year compounded monthly, what will be her monthly mortgage payment? d. How much less would Diane’s monthly mortgage payment be if she refinances? 49. ADJUSTABLE-RATE MORTGAGES Three years ago, Samantha secured an adjustable-rate mortgage (ARM) loan to help finance the purchase of a house. The amount of the original loan was $150,000 for a term of 30 yr, with interest at the rate of 7.5%/year compounded monthly. Currently the interest rate is 7%/year compounded monthly, and Samantha’s monthly payments are due to be recalculated. What will be her new monthly payment? Hint: Calculate her current outstanding principal. Then, to amortize the loan in the next 27 yr, determine the monthly payment based on the current interest rate.

50. ADJUSTABLE-RATE MORTGAGES George secured an adjustablerate mortgage (ARM) loan to help finance the purchase of his home 5 yr ago. The amount of the loan was $300,000 for a term of 30 yr, with interest at the rate of 8%/year compounded monthly. Currently, the interest rate for his ARM is 6.5%/year compounded monthly, and George’s monthly payments are due to be reset. What will be the new monthly payment?

4.3 AMORTIZATION AND SINKING FUNDS

51. FINANCING A HOME After making a down payment of $25,000, the Meyers need to secure a loan of $280,000 to purchase a certain house. Their bank’s current rate for 25-yr home loans is 11%/year compounded monthly. The owner has offered to finance the loan at 9.8%/year compounded monthly. Assuming that both loans would be amortized over a 25-yr period by 300 equal monthly installments, determine the difference in the amount of interest the Meyers would pay by choosing the seller’s financing rather than their bank’s. 52. REFINANCING A HOME The Martinezes are planning to refinance their home. The outstanding balance on their original loan is $150,000. Their finance company has offered them two options:

225

Option A: A fixed-rate mortgage at an interest rate of 7.5%/year compounded monthly, payable over a 30-yr period in 360 equal monthly installments. Option B: A fixed-rate mortgage at an interest rate of 7.25%/year compounded monthly, payable over a 15-yr period in 180 equal monthly installments. a. Find the monthly payment required to amortize each of these loans over the life of the loan. b. How much interest would the Martinezes save if they chose the 15-yr mortgage instead of the 30-yr mortgage?

4.3 Solutions to Self-Check Exercises 1. a. We use Equation (13) in each instance. Under plan I, P  300,000

i

n  130 2 1122  360

r 0.0609   0.005075 m 12

Therefore, the size of each monthly repayment under plan I is R

300,00010.005075 2

1  11.005075 2 360

 1816.05

n  115 2 1122  180

r 0.0576   0.0048 m 12

or $653,778. Under plan II, the total amount of repayments will be (180)(2492.84)  448,711.20

or $448,711.20. Therefore, the difference in payments is

S  250,000 i  r  0.0825

giving the required size of each installment as

300,00010.0048 2

1  11.0048 2

R

180

10.08252 1250,0002 11.0825 2 20  1

 5313.59

 2492.84

or $5313.59.

or $2492.84.

TECHNOLOGY

Since m  1

n  20

Therefore, the size of each monthly repayment under plan II is

USING

Number of payments  the size of each installment

or $205,066.80. 2. We use Equation (15) with i

R

(360)(1816.05)  653,778

653,778  448,711.20  205,066.80

or $1816.05. Under plan II, P  300,000

b. Under plan I, the total amount of repayments will be

Amortizing a Loan Graphing Utility

Here we use the TI-83/84 TVM SOLVER function to help us solve problems involving amortization and sinking funds. APPLIED EXAMPLE 1 Finding the Payment to Amortize a Loan The Wongs are considering obtaining a preapproved 30-year loan of $120,000 to help finance the purchase of a house. The mortgage company (continued)

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charges interest at the rate of 8% per year on the unpaid balance, with interest computations made at the end of each month. What will be the monthly installments if the loan is amortized? Solution

N  360 (30)(12) I%  8 PV  120000 PMT  0 FV  0 The number of payments each year P/Y  12 C/Y  12 The number of conversion periods each year PMT:END BEGIN

N = 360 I% = 8 PV = 120000 PMT = −880.51748... FV = 0 P/Y = 12 C/Y = 12 PMT : END BEGIN FIGURE T1 The TI-83/84 screen showing the monthly installment, PMT

We use the TI-83/84 TVM SOLVER with the following inputs:

From the output shown in Figure T1, we see that the required payment is $880.52. APPLIED EXAMPLE 2 Finding the Payment in a Sinking Fund Heidi wishes to establish a retirement account that will be worth $500,000 in 20 years’ time. She expects that the account will earn interest at the rate of 11% per year compounded monthly. What should be the monthly contribution into her account each month? Solution

N  240 (20)(12) I%  11 PV  0 PMT  0 FV  500000 The number of payments each year P/Y  12 C/Y  12 The number of conversion periods each year PMT:END BEGIN

N = 240 I% = 11 PV = 0 PMT = −577.60862... FV = 500000 P/Y = 12 C/Y = 12 PMT : END BEGIN FIGURE T2 The TI-83/84 screen showing the monthly payment, PMT

We use the TI-83/84 TVM SOLVER with the following inputs:

The result is displayed in Figure T2. We see that Heidi’s monthly contribution should be $577.61. (Note: The display for PMT is negative because it is an outflow.) Excel

Here we use Excel to help us solve problems involving amortization and sinking funds. APPLIED EXAMPLE 3 Finding the Payment to Amortize a Loan The Wongs are considering a preapproved 30-year loan of $120,000 to help finance the purchase of a house. The mortgage company charges interest at the rate of 8% per year on the unpaid balance, with interest computations made at the end of each month. What will be the monthly installments if the loan is amortized at the end of the term? We use the PMT function to solve this problem. Accessing this function from the Insert Function dialog box and making the required entries, we obtain the Function Arguments dialog box shown in Figure T3. We see that the desired result is $880.52. (Recall that cash you pay out is represented by a negative number.) Solution

Note: Words/characters printed blue (for example, Chart sub-type:) indicate words/characters on the screen.

4.3 AMORTIZATION AND SINKING FUNDS

227

FIGURE T3 Excel’s dialog box giving the payment function, PMT

APPLIED EXAMPLE 4 Finding the Payment in a Sinking Fund Heidi wishes to establish a retirement account that will be worth $500,000 in 20 years’ time. She expects that the account will earn interest at the rate of 11% per year compounded monthly. What should be the monthly contribution into her account each month? Solution As in Example 3, we use the PMT function, but this time we are given the future value of the investment. Accessing the PMT function from the Insert Function dialog box and making the required entries, we obtain the Function Arguments dialog box shown in Figure T4. We see that Heidi’s monthly contribution should be $577.61. (Note that the value for PMT is negative because it is an outflow.)

FIGURE T4 Excel’s dialog box giving the payment function, PMT

TECHNOLOGY EXERCISES 1. Find the periodic payment required to amortize a loan of $55,000 over 120 mo with interest charged at the rate of 658 %/ year compounded monthly.

2. Find the periodic payment required to amortize a loan of $178,000 over 180 mo with interest charged at the rate of 718 %/year compounded monthly.

(continued)

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4 MATHEMATICS OF FINANCE

3. Find the periodic payment required to amortize a loan of $227,000 over 360 mo with interest charged at the rate of 818 %/year compounded monthly.

8. Find the periodic payment required to accumulate $144,000 over 120 mo with interest earned at the rate of 4 58%/year compounded monthly.

4. Find the periodic payment required to amortize a loan of $150,000 over 360 mo with interest charged at the rate of 738 %/year compounded monthly.

9. A loan of $120,000 is to be repaid over a 10-yr period through equal installments made at the end of each year. If an interest rate of 8.5%/year is charged on the unpaid balance and interest calculations are made at the end of each year, determine the size of each installment such that the loan is amortized at the end of 10 yr. Verify the result by displaying the amortization schedule.

5. Find the periodic payment required to accumulate $25,000 over 12 quarters with interest earned at the rate of 4 38%/year compounded quarterly. 6. Find the periodic payment required to accumulate $50,000 over 36 quarters with interest earned at the rate of 3 78%/year compounded quarterly. 7. Find the periodic payment required to accumulate $137,000 over 120 mo with interest earned at the rate of 4 34%/year compounded monthly.

10. A loan of $265,000 is to be repaid over an 8-yr period through equal installments made at the end of each year. If an interest rate of 7.4%/year is charged on the unpaid balance and interest calculations are made at the end of each year, determine the size of each installment so that the loan is amortized at the end of 8 yr. Verify the result by displaying the amortization schedule.

4.4 Arithmetic and Geometric Progressions Arithmetic Progressions An arithmetic progression is a sequence of numbers in which each term after the first is obtained by adding a constant d to the preceding term. The constant d is called the common difference. For example, the sequence 2, 5, 8, 11, . . .

is an arithmetic progression with common difference equal to 3. Observe that an arithmetic progression is completely determined if the first term and the common difference are known. In fact, if a1, a2, a3, . . . , an, . . .

is an arithmetic progression with the first term given by a and common difference given by d, then by definition we have a1 a2 a3 a4

   

a a1  d  a  d a2  d  1a  d2  d  a  2d a3  d  1a  2d2  d  a  3d

o an  an1  d  a  1n  22 d  d  a  1n  12d

Thus, we have the following formula for finding the nth term of an arithmetic progression with first term a and common difference:

nth Term of an Arithmetic Progression

The nth term of an arithmetic progression with first term a and common difference d is given by an  a  (n  1)d

(16)

4.4 ARITHMETIC AND GEOMETRIC PROGRESSIONS

229

EXAMPLE 1 Find the twelfth term of the arithmetic progression 2, 7, 12, 17, 22, . . .

The first term of the arithmetic progression is a1  a  2, and the common difference is d  5; so, upon setting n  12 in Equation (16), we find

Solution

a12  2  (12  1)5  57

EXAMPLE 2 Write the first five terms of an arithmetic progression whose third and eleventh terms are 21 and 85, respectively. Solution

Using Equation (16), we obtain a3  a  2d  21 a11  a  10d  85

Subtracting the first equation from the second gives 8d  64, or d  8. Substituting this value of d into the first equation yields a  16  21, or a  5. Thus, the required arithmetic progression is given by the sequence 5, 13, 21, 29, 37, . . .

Let Sn denote the sum of the first n terms of an arithmetic progression with first term a1  a and common difference d. Then Sn  a  (a  d )  (a  2d )      [a  (n  1)d]

(17)

Rewriting the expression for Sn with the terms in reverse order gives Sn  [a  (n  1)d]  [a  (n  2)d]      (a  d )  a

(18)

Adding Equations (17) and (18), we obtain 2Sn  32a  1n  12d4  32a  1n  12d4      32a  1n  12d4  n32a  1n  12d4 n Sn  32a  1n  12d4 2

Sum of Terms in an Arithmetic Progression

The sum of the first n terms of an arithmetic progression with first term a and common difference d is given by Sn 

n 32a  1n  12d4 2

(19)

EXAMPLE 3 Find the sum of the first 20 terms of the arithmetic progression of Example 1. Solution

Letting a  2, d  5, and n  20 in Equation (19), we obtain S20 

20 # 32 2  19 # 54  990 2

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4 MATHEMATICS OF FINANCE

APPLIED EXAMPLE 4 Company Sales Madison Electric Company had sales of $200,000 in its first year of operation. If the sales increased by $30,000 per year thereafter, find Madison’s sales in the fifth year and its total sales over the first 5 years of operation. Solution Madison’s yearly sales follow an arithmetic progression, with the first term given by a  200,000 and the common difference given by d  30,000. The sales in the fifth year are found by using Equation (16) with n  5. Thus,

a5  200,000  (5  1)30,000  320,000

or $320,000. Madison’s total sales over the first 5 years of operation are found by using Equation (19) with n  5. Thus, 5 321200,0002  15  1230,0004 2  1,300,000

S5 

or $1,300,000.

Geometric Progressions A geometric progression is a sequence of numbers in which each term after the first is obtained by multiplying the preceding term by a constant r. The constant r is called the common ratio. A geometric progression is completely determined if the first term and the common ratio are known. Thus, if a1, a2, a3, . . . , an, . . .

is a geometric progression with the first term given by a and common ratio given by r, then by definition we have a1  a2  a3  a4 

a a1r  ar a2r  ar2 a3r  ar3

o an  an1r  arn1

This gives the following:

nth Term of a Geometric Progression

The nth term of a geometric progression with first term a and common ratio r is given by an  ar n1 (20)

EXAMPLE 5 Find the eighth term of a geometric progression whose first five terms are 162, 54, 18, 6, and 2. The common ratio is found by taking the ratio of any term other than the first to the preceding term. Taking the ratio of the fourth term to the third term, for Solution

4.4 ARITHMETIC AND GEOMETRIC PROGRESSIONS

231

example, gives r  186  13. To find the eighth term of the geometric progression, use Formula (20) with a  162, r  13, and n  8, obtaining 1 7 a8  162 a b 3 

2 27

EXAMPLE 6 Find the tenth term of a geometric progression with positive terms and third term equal to 16 and seventh term equal to 1. Solution

Using Equation (20) with n  3 and n  7, respectively, yields a3  ar2  16 a7  ar6  1

Dividing a7 by a3 gives ar6 1  ar 2 16

from which we obtain r4  161 , or r  12. Substituting this value of r into the expression for a3, we obtain 1 2 a a b  16 2

or a  64

Finally, using (20) once again with a  64, r  12, and n  10 gives 1 9 1 a10  64 a b  2 8

To find the sum of the first n terms of a geometric progression with the first term a1  a and common ratio r, denote the required sum by Sn. Then, Sn  a  ar  ar 2      ar n2  ar n1

(21)

Upon multiplying (21) by r, we obtain rSn  ar  ar 2  ar 3      ar n1  ar n

Subtracting (22) from (21) gives Sn  rSn  a  ar n 11  r2Sn  a11  r n 2

If r  1, we may divide both sides of the last equation by (1  r), obtaining Sn 

a11  r n 2 1r

If r  1, then (21) gives Sn  a  a  a      a  na

n terms

Thus, Sn  •

a11  r n 2 1r na

if r  1 if r  1

(22)

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4 MATHEMATICS OF FINANCE

Sum of Terms in a Geometric Progression

The sum of the first n terms of a geometric progression with first term a and common ratio r is given by Sn  •

a11  r n 2 1r na

if r  1

(23)

if r  1

EXAMPLE 7 Find the sum of the first six terms of the following geometric progression: 3, 6, 12, 24, . . . Solution

Here, a  3, r  63  2, and n  6, so Formula (23) gives S6 

311  26 2 12

 189

APPLIED EXAMPLE 8 Company Sales Michaelson Land Development Company had sales of $1 million in its first year of operation. If sales increased by 10% per year thereafter, find Michaelson’s sales in the fifth year and its total sales over the first 5 years of operation. Solution Michaelson’s yearly sales follow a geometric progression, with the first term given by a  1,000,000 and the common ratio given by r  1.1. The sales in the fifth year are found by using Formula (20) with n  5. Thus,

a5  1,000,000(1.1)4  1,464,100

or $1,464,100. Michaelson’s total sales over the first 5 years of operation are found by using Equation (23) with n  5. Thus, S5 

1,000,00031  11.12 5 4

1  1.1  6,105,100

or $6,105,100.

Double Declining-Balance Method of Depreciation In Section 2.5, we discussed the straight-line, or linear, method of depreciating an asset. Linear depreciation assumes that the asset depreciates at a constant rate. For certain assets (such as machines) whose market values drop rapidly in the early years of usage and thereafter less rapidly, another method of depreciation called the double declining-balance method is often used. In practice, a business firm normally employs the double declining-balance method for depreciating such assets for a certain number of years and then switches over to the linear method. To derive an expression for the book value of an asset being depreciated by the double declining-balance method, let C (in dollars) denote the original cost of the asset and let the asset be depreciated over N years. Using this method, the

4.4 ARITHMETIC AND GEOMETRIC PROGRESSIONS

233

amount depreciated each year is N2 times the value of the asset at the beginning of that year. Thus, the amount by which the asset is depreciated in its first year of use is given by 2C N , so if V(1) denotes the book value of the asset at the end of the first year then V112  C 

2C 2  Ca1  b N N

Next, if V(2) denotes the book value of the asset at the end of the second year, then a similar argument leads to V122  C a 1 

2 2 2 b  Ca1  b N N N 2 2  Ca1  b a1  b N N 2 2  Ca1  b N

Continuing, we find that if V(n) denotes the book value of the asset at the end of n years, then the terms C, V(1), V(2), . . . , V(N ) form a geometric progression with first term C and common ratio 11  N2 2 . Consequently, the nth term, V(n), is given by V1n2  C a 1 

2 n b N

(1 n N)

(24)

Also, if D(n) denotes the amount by which the asset has been depreciated by the end of the nth year, then D1n2  C  C a 1 

2 n b N 2 n  Cc1  a1  b d N

(25)

APPLIED EXAMPLE 9 Depreciation of Equipment A tractor purchased at a cost of $60,000 is to be depreciated by the double decliningbalance method over 10 years. What is the book value of the tractor at the end of 5 years? By what amount has the tractor been depreciated by the end of the fifth year? Solution We have C  60,000 and N  10. Thus, using Formula (24) with n  5 gives the book value of the tractor at the end of 5 years as

V152  60,000 a 1 

2 5 b 10

4 5  60,000 a b  19,660.80 5

or $19,660.80. The amount by which the tractor has been depreciated by the end of the fifth year is given by 60,000  19,660.80  40,339.20

or $40,339.20. You may verify the last result by using Equation (25) directly.

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4 MATHEMATICS OF FINANCE

Exploring with

TECHNOLOGY A tractor purchased at a cost of $60,000 is to be depreciated over 10 years with a residual value of $0. Using the double declining-balance method, its value at the end of n years is V1(n)  60,000(0.8)n dollars. Using straight-line depreciation, its value at the end of n years is V2(n)  60,000  6000n. Use a graphing utility to sketch the graphs of V1 and V2 in the viewing window [0, 10]  [0, 70,000]. Comment on the relative merits of each method of depreciation.

4.4 Self-Check Exercises 1. Find the sum of the first five terms of the geometric progression with first term 24 and common ratio 12.

3. Derive the formula for the future value of an annuity [Equation (9), Section 4.2].

2. Office equipment purchased for $75,000 is to be depreciated by the double declining-balance method over 5 yr. Find the book value at the end of 3 yr.

Solutions to Self-Check Exercises 4.4 can be found on page 236.

4.4 Concept Questions 1. Suppose an arithmetic progression has first term a and common difference d. a. What is the formula for the nth term of this progression? b. What is the formula for the sum of the first n terms of this progression?

2. Suppose a geometric progression has first term a and common ratio r. a. What is the formula for the nth term of this progression? b. What is the formula for the sum of the first n terms of this progression?

4.4 Exercises In Exercises 1–4, find the nth term of the arithmetic progression that has the given values of a, d, and n.

1. a  6, d  3, n  9

2. a  5, d  3, n  7

3 3. a  15, d  , n  8 2

4. a  1.2, d  0.4, n  98

5. Find the first five terms of the arithmetic progression whose fourth and eleventh terms are 30 and 107, respectively. 6. Find the first five terms of the arithmetic progression whose seventh and twenty-third terms are 5 and 29, respectively.

11. Find the sum of the odd integers between 14 and 58. 12. Find the sum of the even integers between 21 and 99. 13. Find f(1)  f(2)  f(3)      f(20), given that f (x)  3x  4. 14. Find t(1)  t(2)  t(3)      t(50), given that t(x)  12  4x. 15. Show that Equation (19) can be written as Sn 

n 1a  an 2 2

9. Find the sum of the first 15 terms of the arithmetic progression 4, 11, 18, . . . .

where an represents the last term of an arithmetic progression. Use this formula to find: a. The sum of the first 11 terms of the arithmetic progression whose first and eleventh terms are 3 and 47, respectively. b. The sum of the first 20 terms of the arithmetic progression whose first and twentieth terms are 5 and 33, respectively.

10. Find the sum of the first 20 terms of the arithmetic progression 5, 1, 7, . . . .

16. SALES GROWTH Moderne Furniture Company had sales of $1,500,000 during its first year of operation. If the sales

7. Find the seventh term of the arithmetic progression x, x  y, x  2y, . . . . 8. Find the eleventh term of the arithmetic progression a  b, 2a, 3a  b, . . . .

4.4 ARITHMETIC AND GEOMETRIC PROGRESSIONS

increased by $160,000/year thereafter, find Moderne’s sales in the fifth year and its total sales over the first 5 yr of operation. 17. EXERCISE PROGRAM As part of her fitness program, Karen has taken up jogging. If she jogs 1 mi the first day and increases her daily run by 14 mi every week, when will she reach her goal of 10 mi/day? 18. COST OF DRILLING A 100-ft oil well is to be drilled. The cost of drilling the first foot is $10.00, and the cost of drilling each additional foot is $4.50 more than that of the preceding foot. Find the cost of drilling the entire 100 ft. 19. CONSUMER DECISIONS Kunwoo wishes to go from the airport to his hotel, which is 25 mi away. The taxi rate is $2.00 for the first mile and $1.20 for each additional mile. The airport limousine also goes to his hotel and charges a flat rate of $15.00. How much money will the tourist save by taking the airport limousine? 20. SALARY COMPARISONS Markeeta, a recent college graduate, received two job offers. Company A offered her an initial salary of $48,800 with guaranteed annual increases of $2000/year for the first 5 yr. Company B offered an initial salary of $50,400 with guaranteed annual increases of $1500/year for the first 5 yr. a. Which company is offering a higher salary for the fifth year of employment? b. Which company is offering more money for the first 5 yr of employment? 21. SUM-OF-THE-YEARS’-DIGITS METHOD OF DEPRECIATION One of the methods that the Internal Revenue Service allows for computing depreciation of certain business property is the sum-of-the-years’-digits method. If a property valued at C dollars has an estimated useful life of N years and a salvage value of S dollars, then the amount of depreciation Dn allowed during the nth year is given by Dn  1C  S 2

N  1n  12 SN

(0 n N)

where SN is the sum of the first N positive integers. Thus, SN  1  2      N 

N1N  12 2

a. Verify that the sum of the arithmetic progression SN  1  2      N is given by N1N  1 2 2

b. If office furniture worth $6000 is to be depreciated by this method over N  10 years and the salvage value of the furniture is $500, find the depreciation for the third year by computing D3. 22. SUM-OF-THE-YEARS’-DIGITS METHOD OF DEPRECIATION Refer to Example 1, Section 2.5. The amount of depreciation allowed for a printing machine, which has an esti-

235

mated useful life of 5 yr and an initial value of $100,000 (with no salvage value), was $20,000/year using the straight-line method of depreciation. Determine the amount of depreciation that would be allowed for the first year if the printing machine were depreciated using the sum-of-the-years’-digits method described in Exercise 21. Which method would result in a larger depreciation of the asset in its first year of use?

In Exercises 23–28, determine which of the sequences are geometric progressions. For each geometric progression, find the seventh term and the sum of the first seven terms.

23. 4, 8, 16, 32, . . .

1 1 1 24. 1,  , ,  , . . . 2 4 8

1 3 1 9 25. ,  , ,  , . . . 2 8 4 64

26. 0.004, 0.04, 0.4, 4, . . .

27. 243, 81, 27, 9, . . .

28. 1, 1, 3, 5, . . .

29. Find the twentieth term and sum of the first 20 terms of the geometric progression 3, 3, 3, 3, . . . . 30. Find the twenty-third term in a geometric progression having the first term a  0.1 and ratio r  2. 31. POPULATION GROWTH It has been projected that the population of a certain city in the southwest will increase by 8% during each of the next 5 yr. If the current population is 200,000, what is the expected population after 5 yr? 32. SALES GROWTH Metro Cable TV had sales of $2,500,000 in its first year of operation. If thereafter the sales increased by 12% of the previous year, find the sales of the company in the fifth year and the total sales over the first 5 yr of operation. 33. COLAS Suppose the cost-of-living index had increased by 3% during each of the past 6 yr and that a member of the EUW Union had been guaranteed an annual increase equal to 2% above the increase in the cost-of-living index over that period. What would be the present salary of a union member whose salary 6 yr ago was $42,000? 34. SAVINGS PLANS The parents of a 9-yr-old boy have agreed to deposit $10 in their son’s bank account on his 10th birthday and to double the size of their deposit every year thereafter until his 18th birthday. a. How much will they have to deposit on his 18th birthday? b. How much will they have deposited by his 18th birthday? 35. SALARY COMPARISONS A Stenton Printing Co. employee whose current annual salary is $48,000 has the option of taking an annual raise of 8%/year for the next 4 yr or a fixed annual raise of $4000/year. Which option would be more profitable to him considering his total earnings over the 4-yr period?

236

4 MATHEMATICS OF FINANCE

36. BACTERIA GROWTH A culture of a certain bacteria is known to double in number every 3 hr. If the culture has an initial count of 20, what will be the population of the culture at the end of 24 hr? 37. TRUST FUNDS Sarah is the recipient of a trust fund that she will receive over a period of 6 yr. Under the terms of the trust, she is to receive $10,000 the first year and each succeeding annual payment is to be increased by 15%. a. How much will she receive during the sixth year? b. What is the total amount of the six payments she will receive? In Exercises 38–40, find the book value of office equipment purchased at a cost C at the end of the nth year if it is to be depreciated by the double declining-balance method over 10 yr.

38. C  $20,000, n  4

39. C  $150,000, n  8

40. C  $80,000, n  7 41. DOUBLE DECLINING-BALANCE METHOD OF DEPRECIATION Restaurant equipment purchased at a cost of $150,000 is to be depreciated by the double declining-balance method over 10 yr. What is the book value of the equipment at the end of 6 yr? By what amount has the equipment been depreciated at the end of the sixth year?

42. DOUBLE DECLINING-BALANCE METHOD OF DEPRECIATION Refer to Exercise 22. Recall that a printing machine with an estimated useful life of 5 yr and an initial value of $100,000 (and no salvage value) was to be depreciated. At the end of the first year, the amount of depreciation allowed was $20,000 using the straight-line method and $33,333 using the sum-of-the-years’-digits method. Determine the amount of depreciation that would be allowed for the first year if the printing machine were depreciated by the double declining-balance method. Which of these three methods would result in the largest depreciation of the printing machine at the end of its first year of use? In Exercises 43 and 44, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

43. If a1, a2, a3, . . . , an and b1, b2, b3, . . . , bn are arithmetic progressions, then a1  b1, a2  b2, a3  b3, . . . , an  bn is also an arithmetic progression. 44. If a1, a2, a3, . . . , an and b1, b2, b3, . . . , bn are geometric progressions, then a1b1, a2b2, a3b3, . . . , anbn is also a geometric progression.

4.4 Solutions to Self-Check Exercises 1. Use Equation (23) with a  24 and r  12, obtaining S5  

24 31  112 2 5 4

S  R  R(1  i)  R(1  i)2      R(1  i)n1

1  112 2

2411  321 2 3 2



33 2

2. Use Equation (24) with C  75,000, N  5, and n  3, giving the book value of the office equipment at the end of 3 yr as V13 2  75,000 a 1 

3. We have

The sum on the right is easily seen to be the sum of the first n terms of a geometric progression with first term R and common ratio (1  i), so by virtue of Formula (23) we obtain S

R31  11  i2 n 4 1  11  i2

2 3 b  16,200 5

or $16,200.

CHAPTER 4 Summary of Principal Formulas and Terms FORMULAS 1. Simple interest (accumulated amount)

A  P11  rt 2

2. Compound interest a. Accumulated amount

A  P11  i2 n

b. Present value

P  A11  i2 n

 Rc

11  i2 n  1 i

d

CONCEPT REVIEW QUESTIONS

c. Interest rate per conversion period d. Number of conversion periods

237

r m n  mt i

3. Continuous compound interest a. Accumulated amount

A  Pert

b. Present value

P  Aert

4. Effective rate of interest

reff  a 1 

5. Annuities a. Future value

S  Rc

b. Present value

P  Rc

6. Amortization payment 7. Amount amortized 8. Sinking fund payment

r m b 1 m

11  i2 n  1

d i n 1  11  i2 i

d

Pi 1  11  i2 n 1  11  i2 n PR c d i iS R 11  i 2 n  1 R

TERMS simple interest (186) accumulated amount (186) compound interest (187) nominal rate (stated rate) (187) conversion period (187)

effective rate (191) present value (193) future value (193) annuity (204) annuity certain (204)

ordinary annuity (204) simple annuity (204) future value of an annuity (206) present value of an annuity (207) sinking fund (219)

CHAPTER 4 Concept Review Questions Fill in the blanks.

1. a. Simple interest is computed on the _____ principal only. The formula for the accumulated amount using simple interest is A  _____ . b. In calculations using compound interest, earned interest is periodically added to the principal and thereafter itself earns _____ . The formula for the accumulated amount using compound interest is A  _____ . Solving this equation for P gives the present value formula using compound interest as P  _____ .

4. The formula for the future value of an annuity is S  _____ ; The formula for the present value of an annuity is P  _____ . 5. The periodic payment R on a loan of P dollars to be amortized over n periods with interest charged at the rate of i per period is R  _____ . 6. A sinking fund is an account that is set up for a specific purpose at some _____ date. The periodic payment R required to accumulate a sum of S dollars over n periods with interest charged at the rate of i per period is R  _____ .

2. The effective rate of interest is the _____ interest rate that would produce the same accumulated amount in _____ year as the _____ rate compounded _____ times a year. The formula for calculating the effective rate is reff  _____ .

7. An arithmetic progression is a sequence of numbers in which each term after the first is obtained by adding a/an _____ _____ to the preceding term. The nth term of an arithmetic progression is an  _____ . The sum of the first n terms of an arithmetic progression is Sn  _____ .

3. A sequence of payments made at regular time intervals is called a/an _____ ; if the payments are made at the end of each payment period, then it is called a/an _____ _____ ; if the payment period coincides with the interest conversion period, then it is called a/an _____ _____ .

8. A geometric progression is a sequence of numbers in which each term after the first is obtained by multiplying the preceding term by a/an _____ _____ . The nth term of a geometric progression is an  _____ . If r  1, the sum of the first n terms of a geometric progression is Sn  _____ .

238

4 MATHEMATICS OF FINANCE

CHAPTER 4 Review Exercises 1. Find the accumulated amount after 4 yr if $5000 is invested at 10%/year compounded (a) annually, (b) semiannually, (c) quarterly, and (d) monthly. 2. Find the accumulated amount after 8 yr if $12,000 is invested at 6.5%/year compounded (a) annually, (b) semiannually, (c) quarterly, and (d) monthly. 3. Find the effective rate of interest corresponding to a nominal rate of 12%/year compounded (a) annually, (b) semiannually, (c) quarterly, and (d) monthly. 4. Find the effective rate of interest corresponding to a nominal rate of 11.5%/year compounded (a) annually, (b) semiannually, (c) quarterly, and (d) monthly. 5. Find the present value of $41,413 due in 5 yr at an interest rate of 6.5%/year compounded quarterly. 6. Find the present value of $64,540 due in 6 yr at an interest rate of 8%/year compounded monthly. 7. Find the amount (future value) of an ordinary annuity of $150/quarter for 7 yr at 8%/year compounded quarterly. 8. Find the future value of an ordinary annuity of $120/month for 10 yr at 9%/year compounded monthly. 9. Find the present value of an ordinary annuity of 36 payments of $250 each made monthly and earning interest at 9%/year compounded monthly. 10. Find the present value of an ordinary annuity of 60 payments of $5000 each made quarterly and earning interest at 8%/year compounded quarterly. 11. Find the payment R needed to amortize a loan of $22,000 at 8.5%/year compounded monthly with 36 monthly installments over a period of 3 yr. 12. Find the payment R needed to amortize a loan of $10,000 at 9.2%/year compounded monthly with 36 monthly installments over a period of 3 yr. 13. Find the payment R needed to accumulate $18,000 with 48 monthly installments over a period of 4 yr at an interest rate of 6%/year compounded monthly. 14. Find the payment R needed to accumulate $15,000 with 60 monthly installments over a period of 5 yr at an interest rate of 7.2%/year compounded monthly. 15. Find the effective rate of interest corresponding to a nominal rate of 7.2%/year compounded monthly. 16. Find the effective rate of interest corresponding to a nominal rate of 9.6%/year compounded monthly. 17. Find the present value of $119,346 due in 4 yr at an interest rate of 10%/year compounded continuously. 18. COMPANY SALES JCN Media had sales of $1,750,000 in the first year of operation. If the sales increased by 14%/year

thereafter, find the company’s sales in the fourth year and the total sales over the first 4 yr of operation. 19. CDS The manager of a money market fund has invested $4.2 million in certificates of deposit that pay interest at the rate of 5.4%/year compounded quarterly over a period of 5 yr. How much will the investment be worth at the end of 5 yr? 20. SAVINGS ACCOUNTS Emily deposited $2000 into a bank account 5 yr ago. The bank paid interest at the rate of 8%/year compounded weekly. What is Emily’s account worth today? 21. SAVINGS ACCOUNTS Kim invested a sum of money 4 yr ago in a savings account that has since paid interest at the rate of 6.5%/year compounded monthly. Her investment is now worth $19,440.31. How much did she originally invest? 22. SAVINGS ACCOUNTS Andrew withdrew $5986.09 from a savings account, which he closed this morning. The account had earned interest at the rate of 6%/year compounded continuously during the 3-yr period that the money was on deposit. How much did Andrew originally deposit into the account? 23. MUTUAL FUNDS Juan invested $24,000 in a mutual fund 5 yr ago. Today his investment is worth $34,616. Find the effective annual rate of return on his investment over the 5-yr period. 24. COLLEGE SAVINGS PROGRAM The Blakes have decided to start a monthly savings program in order to provide for their son’s college education. How much should they deposit at the end of each month in a savings account earning interest at the rate of 8%/year compounded monthly so that, at the end of the tenth year, the accumulated amount will be $40,000? 25. RETIREMENT ACCOUNTS Mai Lee has contributed $200 at the end of each month into her company’s employee retirement account for the past 10 yr. Her employer has matched her contribution each month. If the account has earned interest at the rate of 8%/year compounded monthly over the 10-yr period, determine how much Mai Lee now has in her retirement account. 26. AUTOMOBILE LEASING Maria has leased an auto for 4 yr at $300/month. If money is worth 5%/year compounded monthly, what is the equivalent cash payment (present value) of this annuity? (Assume that the payments are made at the end of each month.) 27. INSTALLMENT FINANCING Peggy made a down payment of $400 toward the purchase of new furniture. To pay the balance of the purchase price, she has secured a loan from her bank at 12%/year compounded monthly. Under the terms of her finance agreement, she is required to make payments of $75.32 at the end of each month for 24 mo. What was the purchase price of the furniture?

BEFORE MOVING ON . . .

28. HOME FINANCING The Turners have purchased a house for $150,000. They made an initial down payment of $30,000 and secured a mortgage with interest charged at the rate of 9%/year on the unpaid balance. (Interest computations are made at the end of each month.) Assume the loan is amortized over 30 yr. a. What monthly payment will the Turners be required to make? b. What will be their total interest payment? c. What will be their equity (disregard depreciation) after 10 yr? 29. HOME FINANCING Refer to Exercise 28. If the loan is amortized over 15 yr: a. What monthly payment will the Turners be required to make? b. What will be their total interest payment? c. What will be their equity (disregard depreciation) after 10 yr? 30. SINKING FUNDS The management of a corporation anticipates a capital expenditure of $500,000 in 5 yr for the purpose of purchasing replacement machinery. To finance this purchase, a sinking fund that earns interest at the rate of 10%/year compounded quarterly will be set up. Determine the amount of each (equal) quarterly installment that should be deposited in the fund. (Assume that the payments are made at the end of each quarter.)

239

31. SINKING FUNDS The management of a condominium association anticipates a capital expenditure of $120,000 in 2 yr for the purpose of painting the exterior of the condominium. To pay for this maintenance, a sinking fund will be set up that will earn interest at the rate of 5.8%/year compounded monthly. Determine the amount of each (equal) monthly installment the association will be required to deposit into the fund at the end of each month for the next 2 yr. 32. CREDIT CARD PAYMENTS The outstanding balance on Bill’s credit-card account is $3200. The bank issuing the credit card is charging 18.6%/year compounded monthly. If Bill decides to pay off this balance in equal monthly installments at the end of each month for the next 18 mo, how much will be his monthly payment? What is the effective rate of interest the bank is charging Bill? 33. FINANCIAL PLANNING Matt’s parents have agreed to contribute $250/month toward the rent for his apartment in his junior year in college. The plan is for Matt’s parents to deposit a lump sum in Matt’s bank account on August 1 and then have Matt withdraw $250 on the first of each month starting on September 1 and ending on May 1 the following year. If the bank pays interest on the balance at the rate of 5%/year compounded monthly, how much should Matt’s parents deposit into his account?

CHAPTER 4 Before Moving On . . . 1. Find the accumulated amount at the end of 3 yr if $2000 is deposited in an account paying interest at the rate of 8%/year compounded monthly.

5. Find the weekly payment required to accumulate a sum of $15,000 over 6 yr with interest earned at the rate of 10%/year compounded weekly.

2. Find the effective rate of interest corresponding to a nominal rate of 6%/year compounded daily.

6. a. Find the sum of the first ten terms of the arithmetic progression 3, 7, 11, 15, 19, . . . . b. Find the sum of the first eight terms of the geometric progression 12, 1, 2, 4, 8, . . . .

3. Find the future value of an ordinary annuity of $800/week for 10 yr at 6%/year compounded weekly. 4. Find the monthly payment required to amortize a loan of $100,000 over 10 yr with interest earned at the rate of 8%/year compounded monthly.

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5

SYSTEMS OF LINEAR EQUATIONS AND MATRICES

T

HE LINEAR EQUATIONS in two variables studied in

Chapter 2 are readily extended to the case involving more

than two variables. For example, a linear equation in three variables represents a plane in three-dimensional space. In this chapter, we see how some real-world problems can be

develop two methods for solving these equations. In addition, we see how matrices (rectangular arrays of numbers) can be used to write systems of linear equations in compact form. We then go on to consider some real-life applications of matrices.

© Florida Images/Alamy

formulated in terms of systems of linear equations, and we also

Checkers Rent-A-Car is planning to expand its fleet of cars next quarter. How should they use their budget of $12 million to meet the expected additional demand for compact and full-size cars? In Example 5, page 307, we will see how we can find the solution to this problem by solving a system of equations.

242

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

5.1 Systems of Linear Equations: An Introduction Systems of Equations Recall that in Sections 2.4 and 2.5 we had to solve two simultaneous linear equations in order to find the break-even point and the equilibrium point. These are two examples of real-world problems that call for the solution of a system of linear equations in two or more variables. In this chapter we take up a more systematic study of such systems. We begin by considering a system of two linear equations in two variables. Recall that such a system may be written in the general form ax  by  h cx  dy  k

(1)

where a, b, c, d, h, and k are real constants and neither a and b nor c and d are both zero. Now let’s study the nature of the solution of a system of linear equations in more detail. Recall that the graph of each equation in System (1) is a straight line in the plane, so that geometrically the solution to the system is the point(s) of intersection of the two straight lines L1 and L2, represented by the first and second equations of the system. Given two lines L1 and L2, one and only one of the following may occur: a. L1 and L2 intersect at exactly one point. b. L1 and L2 are parallel and coincident. c. L1 and L2 are parallel and distinct. (See Figure 1.) In the first case, the system has a unique solution corresponding to the single point of intersection of the two lines. In the second case, the system has infinitely many solutions corresponding to the points lying on the same line. Finally, in the third case, the system has no solution because the two lines do not intersect. y

y

y L1 L1 L 2

L1

L2

L2 x

x

FIGURE 1 (a) Unique solution

(b) Infinitely many solutions

x

(c) No solution

Explore & Discuss Generalize the discussion on this page to the case where there are three straight lines in the plane defined by three linear equations. What if there are n lines defined by n equations?

5.1 SYSTEMS OF LINEAR EQUATIONS: AN INTRODUCTION

243

Let’s illustrate each of these possibilities by considering some specific examples. 1. A system of equations with exactly one solution Consider the system 2x  y  1 3x  2y  12

Solving the first equation for y in terms of x, we obtain the equation y  2x  1

Substituting this expression for y into the second equation yields

y

3x  212x  12  12 3x  4x  2  12 7x  14 x 2

2x – y = 1 5 (2, 3) 3x + 2y = 12

Finally, substituting this value of x into the expression for y obtained earlier gives y  2(2)  1  3

x 5 FIGURE 2 A system of equations with one solution

Therefore, the unique solution of the system is given by x  2 and y  3. Geometrically, the two lines represented by the two linear equations that make up the system intersect at the point (2, 3) (Figure 2). We can check our result by substituting the values x  2 and y  3 into the equations. Thus,

Note

2122  132  1 3122  2132  12

✓ ✓

From the geometric point of view, we have just verified that the point (2, 3) lies on both lines. 2. A system of equations with infinitely many solutions Consider the system 2x  y  1 6x  3y  3

Solving the first equation for y in terms of x, we obtain the equation y  2x  1

Substituting this expression for y into the second equation gives 6x  312x  12  3 6x  6x  3  3 00

which is a true statement. This result follows from the fact that the second equation is equivalent to the first. (To see this, just multiply both sides of the first equation by 3.) Our computations have revealed that the system of two equations is equivalent to the single equation 2x  y  1. Thus, any ordered pair of numbers (x, y) satisfying the equation 2x  y  1 (or y  2x  1) constitutes a solution to the system. In particular, by assigning the value t to x, where t is any real number, we find that y  2t  1 and so the ordered pair (t, 2t  1) is a solution of the system. The variable t is called a parameter. For example, setting t  0 gives the point (0, 1) as a solution of the system, and setting t  1 gives the point (1, 1) as another solution. Since t represents any real number, there are infinitely many solutions of the

244

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES y

system. Geometrically, the two equations in the system represent the same line, and all solutions of the system are points lying on the line (Figure 3). Such a system is said to be dependent.

2x – y = 1 6x – 3y = 3

5

3. A system of equations that has no solution Consider the system 2x  y  1 6x  3y  12 x

5

The first equation is equivalent to y  2x  1. Substituting this expression for y into the second equation gives 6x  3(2x  1)  12 6x  6x  3  12 0 9

FIGURE 3 A system of equations with infinitely many solutions; each point on the line is a solution.

which is clearly impossible. Thus, there is no solution to the system of equations. To interpret this situation geometrically, cast both equations in the slope-intercept form, obtaining

y 4

2x – y = 1

y  2x  1 y  2x  4

6x – 3y = 12 x 5

FIGURE 4 A system of equations with no solution

We see at once that the lines represented by these equations are parallel (each has slope 2) and distinct since the first has y-intercept 1 and the second has y-intercept 4 (Figure 4). Systems with no solutions, such as this one, are said to be inconsistent.

Explore & Discuss 1. Consider a system composed of two linear equations in two variables. Can the system have exactly two solutions? Exactly three solutions? Exactly a finite number of solutions? 2. Suppose at least one of the equations in a system composed of two equations in two variables is nonlinear. Can the system have no solution? Exactly one solution? Exactly two solutions? Exactly a finite number of solutions? Infinitely many solutions? Illustrate each answer with a sketch.

We have used the method of substitution in solving each of these systems. If you are familiar with the method of elimination, you might want to re-solve each of these systems using this method. We will study the method of elimination in detail in Section 5.2.

Note

In Section 2.5, we presented some real-world applications of systems involving two linear equations in two variables. Here is an example involving a system of three linear equations in three variables. APPLIED EXAMPLE 1 Manufacturing—Production Scheduling Ace Novelty wishes to produce three types of souvenirs: types A, B, and C. To manufacture a type-A souvenir requires 2 minutes on machine I, 1 minute on machine II, and 2 minutes on machine III. A type-B souvenir requires 1 minute on machine I, 3 minutes on machine II, and 1 minute on machine III. A type-C souvenir requires 1 minute on machine I and 2 minutes each on machines II and III. There are 3 hours available on machine I, 5 hours available on machine II, and 4 hours available on machine III for processing the order. How many sou-

5.1 SYSTEMS OF LINEAR EQUATIONS: AN INTRODUCTION

245

venirs of each type should Ace Novelty make in order to use all of the available time? Formulate but do not solve the problem. (We will solve this problem in Example 7, Section 5.2.) Solution

Machine I Machine II Machine III

The given information may be tabulated as follows: Type A

Type B

Type C

Time Available (min)

2 1 2

1 3 1

1 2 2

180 300 240

We have to determine the number of each of three types of souvenirs to be made. So, let x, y, and z denote the respective numbers of type-A, type-B, and type-C souvenirs to be made. The total amount of time that machine I is used is given by 2x  y  z minutes and must equal 180 minutes. This leads to the equation 2x  y  z  180

Time spent on machine I

Similar considerations on the use of machines II and III lead to the following equations: x  3y  2z  300 2x  y  2z  240

Time spent on machine II Time spent on machine III

Since the variables x, y, and z must satisfy simultaneously the three conditions represented by the three equations, the solution to the problem is found by solving the following system of linear equations: 2x  y  z  180 x  3y  2z  300 2x  y  2z  240

Solutions of Systems of Equations We will complete the solution of the problem posed in Example 1 later on (page 258). For the moment, let’s look at the geometric interpretation of a system of linear equations, such as the system in Example 1, in order to gain some insight into the nature of the solution. A linear system composed of three linear equations in three variables x, y, and z has the general form a1 x  b1 y  c1z  d1 a2 x  b2 y  c2 z  d2 a3 x  b3 y  c3 z  d3

(2)

Just as a linear equation in two variables represents a straight line in the plane, it can be shown that a linear equation ax  by  cz  d (a, b, and c not all equal to zero) in three variables represents a plane in three-dimensional space. Thus, each equation in System (2) represents a plane in three-dimensional space, and the solution(s) of the system is precisely the point(s) of intersection of the three planes defined by the three linear equations that make up the system. As before, the system has one and only one solution, infinitely many solutions, or no solution, depending on whether and how the planes intersect one another. Figure 5 illustrates each of these possibilities.

246

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

In Figure 5a, the three planes intersect at a point corresponding to the situation in which System (2) has a unique solution. Figure 5b depicts a situation in which there are infinitely many solutions to the system. Here, the three planes intersect along a line, and the solutions are represented by the infinitely many points lying on this line. In Figure 5c, the three planes are parallel and distinct, so there is no point in common to all three planes; System (2) has no solution in this case. P3 P3 P2 P2

P1

P1 P2 P1

FIGURE 5 (a) A unique solution

(b) Infinitely many solutions

P3

(c) No solution

Note The situations depicted in Figure 5 are by no means exhaustive. You may consider various other orientations of the three planes that would illustrate the three possible outcomes in solving a system of linear equations involving three variables.

Linear Equations in n Variables

A linear equation in n variables, x1, x2, . . . , xn is an equation of the form a1x1  a2x2      anxn  c

where a1, a2, . . . , an (not all zero) and c are constants.

For example, the equation 3x1  2x2  4x3  6x4  8

Explore & Discuss Refer to the Note above. Using the orientation of three planes, illustrate the outcomes in solving a system of three linear equations in three variables that result in no solution or infinitely many solutions.

is a linear equation in the four variables, x1, x2, x3, and x4. When the number of variables involved in a linear equation exceeds three, we no longer have the geometric interpretation we had for the lower-dimensional spaces. Nevertheless, the algebraic concepts of the lower-dimensional spaces generalize to higher dimensions. For this reason, a linear equation in n variables, a1x1  a2x2  . . .  an xn  c, where a1, a2, . . . , an are not all zero, is referred to as an n-dimensional hyperplane. We may interpret the solution(s) to a system comprising a finite number of such linear equations to be the point(s) of intersection of the hyperplanes defined by the equations that make up the system. As in the case of systems involving two or three variables, it can be shown that only three possibilities exist regarding the nature of the solution of such a system: (1) a unique solution, (2) infinitely many solutions, or (3) no solution.

5.1 SYSTEMS OF LINEAR EQUATIONS: AN INTRODUCTION

247

5.1 Self-Check Exercises 1. Determine whether the system of linear equations 2x  3y  12 x  2y  6

has (a) a unique solution, (b) infinitely many solutions, or (c) no solution. Find all solutions whenever they exist. Make a sketch of the set of lines described by the system. 2. A farmer has 200 acres of land suitable for cultivating crops A, B, and C. The cost per acre of cultivating crops A, B, and C is $40, $60, and $80, respectively. The farmer has

$12,600 available for cultivation. Each acre of crop A requires 20 labor-hours, each acre of crop B requires 25 labor-hours, and each acre of crop C requires 40 laborhours. The farmer has a maximum of 5950 labor-hours available. If she wishes to use all of her cultivatable land, the entire budget, and all the labor available, how many acres of each crop should she plant? Formulate but do not solve the problem. Solutions to Self-Check Exercises 5.1 can be found on page 249.

5.1 Concept Questions 1. Suppose you are given a system of two linear equations in two variables. a. What can you say about the solution(s) of the system of equations? b. Give a geometric interpretation of your answers to the question in part (a).

2. Suppose you are given a system of two linear equations in two variables. a. Explain what it means for the system to be dependent. b. Explain what it means for the system to be inconsistent.

5.1 Exercises In Exercises 1–12, determine whether each system of linear equations has (a) one and only one solution, (b) infinitely many solutions, or (c) no solution. Find all solutions whenever they exist.

1. x  3y  1 4x  3y  11

2. 2x  4y  5 3x  2y  6

3.

x  4y  7 1 x  2y  5 2

4. 3x  4y  7 9x  12y  14

5.

x  2y  7 2x  y  4

6.

7. 2x  5y  10 6x  15y  30 9. 4x  5y  14

8. 5x  6y  8 10x  12y  16 10.

2 x  3y  4

11. 2x  3y  6 6x  9y  12

3 x  2y  4 2 1 x y2 3

12.

5 x 4 1 x 4

2 y3 3 5 y6 3

2 x y5 3 3 15 1 x y 2 4 4

13. Determine the value of k for which the system of linear equations 2x  y  3 4x  ky  4

has no solution. 14. Determine the value of k for which the system of linear equations 3x  4y  12 x  ky  4

has infinitely many solutions. Then find all solutions corresponding to this value of k. In Exercises 15–27, formulate but do not solve the problem. You will be asked to solve these problems in the next section.

15. AGRICULTURE The Johnson Farm has 500 acres of land allotted for cultivating corn and wheat. The cost of cultivating corn and wheat (including seeds and labor) is $42 and $30 per acre, respectively. Jacob Johnson has $18,600 available for cultivating these crops. If he wishes to use all the allotted land and his entire budget for cultivating these two crops, how many acres of each crop should he plant?

248

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

16. INVESTMENTS Michael Perez has a total of $2000 on deposit with two savings institutions. One pays interest at the rate of 6%/year, whereas the other pays interest at the rate of 8%/year. If Michael earned a total of $144 in interest during a single year, how much does he have on deposit in each institution? 17. MIXTURES The Coffee Shoppe sells a coffee blend made from two coffees, one costing $5/lb and the other costing $6/lb. If the blended coffee sells for $5.60/lb, find how much of each coffee is used to obtain the desired blend. Assume that the weight of the blended coffee is 100 lb. 18. INVESTMENTS Kelly Fisher has a total of $30,000 invested in two municipal bonds that have yields of 8% and 10% interest per year, respectively. If the interest Kelly receives from the bonds in a year is $2640, how much does she have invested in each bond? 19. RIDERSHIP The total number of passengers riding a certain city bus during the morning shift is 1000. If the child’s fare is $.50, the adult fare is $1.50, and the total revenue from the fares in the morning shift is $1300, how many children and how many adults rode the bus during the morning shift? 20. REAL ESTATE Cantwell Associates, a real estate developer, is planning to build a new apartment complex consisting of one-bedroom units and two- and three-bedroom townhouses. A total of 192 units is planned, and the number of family units (two- and three-bedroom townhouses) will equal the number of one-bedroom units. If the number of one-bedroom units will be 3 times the number of threebedroom units, find how many units of each type will be in the complex. 21. INVESTMENT PLANNING The annual returns on Sid Carrington’s three investments amounted to $21,600: 6% on a savings account, 8% on mutual funds, and 12% on bonds. The amount of Sid’s investment in bonds was twice the amount of his investment in the savings account, and the interest earned from his investment in bonds was equal to the dividends he received from his investment in mutual funds. Find how much money he placed in each type of investment. 22. INVESTMENT CLUB A private investment club has $200,000 earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of 15%/year; medium-risk stocks, 10%/year; and low-risk stocks, 6%/year. The members have decided that the investment in low-risk stocks should be equal to the sum of the investments in the stocks of the other two categories. Determine how much the club should invest in each type of stock if the investment goal is to have a return of $20,000/year on the total investment. (Assume that all the money available for investment is invested.)

23. MIXTURE PROBLEM—FERTILIZER Lawnco produces three grades of commercial fertilizers. A 100-lb bag of grade-A fertilizer contains 18 lb of nitrogen, 4 lb of phosphate, and 5 lb of potassium. A 100-lb bag of grade-B fertilizer contains 20 lb of nitrogen and 4 lb each of phosphate and potassium. A 100-lb bag of grade-C fertilizer contains 24 lb of nitrogen, 3 lb of phosphate, and 6 lb of potassium. How many 100-lb bags of each of the three grades of fertilizers should Lawnco produce if 26,400 lb of nitrogen, 4900 lb of phosphate, and 6200 lb of potassium are available and all the nutrients are used? 24. BOX-OFFICE RECEIPTS A theater has a seating capacity of 900 and charges $4 for children, $6 for students, and $8 for adults. At a certain screening with full attendance, there were half as many adults as children and students combined. The receipts totaled $5600. How many children attended the show? 25. MANAGEMENT DECISIONS The management of Hartman Rent-A-Car has allocated $1.5 million to buy a fleet of new automobiles consisting of compact, intermediate-size, and full-size cars. Compacts cost $12,000 each, intermediatesize cars cost $18,000 each, and full-size cars cost $24,000 each. If Hartman purchases twice as many compacts as intermediate-size cars and the total number of cars to be purchased is 100, determine how many cars of each type will be purchased. (Assume that the entire budget will be used.) 26. INVESTMENT CLUBS The management of a private investment club has a fund of $200,000 earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of 15%/year; medium-risk stocks, 10%/year; and low-risk stocks, 6%/year. The investment in low-risk stocks is to be twice the sum of the investments in stocks of the other two categories. If the investment goal is to have an average rate of return of 9%/year on the total investment, determine how much the club should invest in each type of stock. (Assume that all the money available for investment is invested.) 27. DIET PLANNING A dietitian wishes to plan a meal around three foods. The percentage of the daily requirements of proteins, carbohydrates, and iron contained in each ounce of the three foods is summarized in the following table:

Proteins (%) Carbohydrates (%) Iron (%)

Food I 10 10 5

Food II 6 12 4

Food III 8 6 12

Determine how many ounces of each food the dietitian should include in the meal to meet exactly the daily requirement of proteins, carbohydrates, and iron (100% of each).

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

In Exercises 28–30, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

28. A system composed of two linear equations must have at least one solution if the straight lines represented by these equations are nonparallel.

249

29. Suppose the straight lines represented by a system of three linear equations in two variables are parallel to each other. Then the system has no solution or it has infinitely many solutions. 30. If at least two of the three lines represented by a system composed of three linear equations in two variables are parallel, then the system has no solution.

5.1 Solutions to Self-Check Exercises 1. Solving the first equation for y in terms of x, we obtain y

2 x4 3

2. Let x, y, and z denote the number of acres of crop A, crop B, and crop C, respectively, to be cultivated. Then, the condition that all the cultivatable land be used translates into the equation

Next, substituting this result into the second equation of the system, we find

Next, the total cost incurred in cultivating all three crops is 40x  60y  80z dollars, and since the entire budget is to be expended, we have

2 x  2a x  4b  6 3 x

4 x86 3

40x  60y  80z  12,600

Finally, the amount of labor required to cultivate all three crops is 20 x  25y  40 z hr, and since all the available labor is to be used, we have

7 x  14 3 x6

Substituting this value of x into the expression for y obtained earlier, we have y

x  y  z  200

2 16 2  4  0 3

20x  25y  40 z  5950

Thus, the solution is found by solving the following system of linear equations: x

Therefore, the system has the unique solution x  6 and y  0. Both lines are shown in the accompanying figure.

y

z

200

40x  60y  80z  12,600 20x  25y  40z  5,950

y

x + 2y = 6 (6, 0) x

2x – 3y = 12

5.2 Systems of Linear Equations: Unique Solutions The Gauss–Jordan Method The method of substitution used in Section 5.1 is well suited to solving a system of linear equations when the number of linear equations and variables is small. But for large systems, the steps involved in the procedure become difficult to manage.

250

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

The Gauss–Jordan elimination method is a suitable technique for solving systems of linear equations of any size. One advantage of this technique is its adaptability to the computer. This method involves a sequence of operations on a system of linear equations to obtain at each stage an equivalent system—that is, a system having the same solution as the original system. The reduction is complete when the original system has been transformed so that it is in a certain standard form from which the solution can be easily read. The operations of the Gauss–Jordan elimination method are 1. Interchange any two equations. 2. Replace an equation by a nonzero constant multiple of itself. 3. Replace an equation by the sum of that equation and a constant multiple of any other equation. To illustrate the Gauss–Jordan elimination method for solving systems of linear equations, let’s apply it to the solution of the following system: 2x  4y  8 3x  2y  4

We begin by working with the first, or x, column. First, we transform the system into an equivalent system in which the coefficient of x in the first equation is 1: 2x  4y  8 3x  2y  4 x  2y  4 3x  2y  4

(3a) Multiply the first equation in (3a) by 12 (operation 2).

(3b)

Next, we eliminate x from the second equation: x  2y  4 8y  8

Replace the second equation in (3b) by the sum of 3  the first equation  the second equation (operation 3):

(3c)

3x  6y  12 3x  2y  4 ———————— 8y  8

Then, we obtain the following equivalent system in which the coefficient of y in the second equation is 1: x  2y  4 y1

Multiply the second equation in (3c) by 18 (operation 2).

(3d)

Next, we eliminate y in the first equation: x

2 y1

Replace the first equation in (3d) by the sum of 2  the second equation  the first equation (operation 3):

x  2y  4  2y  2 —————— x  2

This system is now in standard form, and we can read off the solution to System (3a) as x  2 and y  1. We can also express this solution as (2, 1) and interpret it geometrically as the point of intersection of the two lines represented by the two linear equations that make up the given system of equations. Let’s consider another example, involving a system of three linear equations and three variables.

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

251

EXAMPLE 1 Solve the following system of equations: 2x  4y  6z  22 3x  8y  5z  27 x  y  2z  2 Solution First, we transform this system into an equivalent system in which the coefficient of x in the first equation is 1:

2x  4y  6z  22 3x  8y  5z  27 x  y  2z  2 x  2y  3z  11 3x  8y  5z  27 x  y  2z  2

Multiply the first equation in (4a) by 21 .

(4a)

(4b)

Next, we eliminate the variable x from all equations except the first: x  2y  3z  11 2y  4z  6 x  y  2z  2

x  2y  3z  11 2y  4z  6 3y  5z  13

Replace the second equation in (4b) by the sum of 3  the first equation  the second equation:

(4c)

3x  6y  9z  33 3x  8y  5z  27 ——————————— 2y  4z  6 Replace the third equation in (4c) by the sum of the first equation  the third equation:

(4d)

x  2y  3z  1 1 x  y  2 z  2 ————————— 3y  5z  13

Then we transform System (4d) into yet another equivalent system, in which the coefficient of y in the second equation is 1: x  2y  3z  11 y  2z  3 3y  5z  13

Multiply the second equation in (4d) by 21 .

(4e)

We now eliminate y from all equations except the second, using operation 3 of the elimination method: x

x

 7z  17 y  2z  3 3y  5z  13

 7z  17 y  2z  3 11z  22

Replace the first equation in (4e) by the sum of the first equation  (2)  the second equation:

(4f)

x  2y  3 z  11 2y  4 z  6 ———————— x  7 z  17 Replace the third equation in (4f) by the sum of (3)  the second equation  the third equation: 3y  6z  9 3y  5z  13 ——————— 11z  22

(4g)

252

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Multiplying the third equation by 111 in (4g) leads to the system x

 7z  17 y  2z  3 z 2

Eliminating z from all equations except the third (try it!) then leads to the system x y

3 1 z2

(4h)

In its final form, the solution to the given system of equations can be easily read off! We have x  3, y  1, and z  2. Geometrically, the point (3, 1, 2) is the intersection of the three planes described by the three equations comprising the given system.

Augmented Matrices Observe from the preceding example that the variables x, y, and z play no significant role in each step of the reduction process, except as a reminder of the position of each coefficient in the system. With the aid of matrices, which are rectangular arrays of numbers, we can eliminate writing the variables at each step of the reduction and thus save ourselves a great deal of work. For example, the system 2x  4y  6z  22 3x  8y  5z  27 x  y  2z  02

(5)

may be represented by the matrix 2 £ 3 1

4 8 1

6 22 5 † 27 § 2 2

(6)

The augmented matrix representing System (5)

The submatrix consisting of the first three columns of Matrix (6) is called the coefficient matrix of System (5). The matrix itself, (6), is referred to as the augmented matrix of System (5) since it is obtained by joining the matrix of coefficients to the column (matrix) of constants. The vertical line separates the column of constants from the matrix of coefficients. The next example shows how much work you can save by using matrices instead of the standard representation of the systems of linear equations. EXAMPLE 2 Write the augmented matrix corresponding to each equivalent system given in (4a) through (4h). Solution

The required sequence of augmented matrices follows.

Equivalent System

Augmented Matrix

a. 2x  4y  6z  22 3x  8y  5z  27 x  y  2z  2

2 £ 3 1

4 8 1

6 22 5 † 27 § 2 2

(7a)

x  2y  3z  11 3x  8y  5z  27 x  y  2z  2

1 £ 3 1

2 8 1

3 11 5 † 27 § 2 2

(7b)

b.

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

c.

x  2y  3z  11 2y  4z  6 x  y  2z  2

1 £ 0 1

2 2 1

3 11 4 † 6 § 2 2

253

(7c)

d. x  2y  3z  11 2y  4z  6 3y  5z  13

1 £0 0

2 2 3

3 11 4 † 6 § 5 13

(7d)

e. x  2y  3z  11 y  2z  3 3y  5z  13

1 £0 0

2 1 3

3 11 2 † 3 § 5 13

(7e)

 7z  17 y  2z  3 3y  5z  13

1 £0 0

0 1 3

7 17 2 † 3 § 5 13

(7f)

 17z  17 y  12z  3 11z  22

1 £0 0

0 1 0

7 17 2 † 3 § 11 22

(7g)

 3 y  1 z  2

1 £0 0

0 1 0

0 3 0 † 1§ 1 2

(7h)

f. x

g. x

h. x

The augmented matrix in (7h) is an example of a matrix in row-reduced form. In general, an augmented matrix with m rows and n columns (called an m  n matrix) is in row-reduced form if it satisfies the following conditions.

Row-Reduced Form of a Matrix

1. Each row consisting entirely of zeros lies below all rows having nonzero entries. 2. The first nonzero entry in each (nonzero) row is 1 (called a leading 1). 3. In any two successive (nonzero) rows, the leading 1 in the lower row lies to the right of the leading 1 in the upper row. 4. If a column in the coefficient matrix contains a leading 1, then the other entries in that column are zeros.

EXAMPLE 3 Determine which of the following matrices are in row-reduced form. If a matrix is not in row-reduced form, state the condition that is violated. 1 a. £ 0 0

0 1 0

0 0 0 † 0§ 1 3

1 b. £ 0 0

0 1 0

0 4 0 † 3§ 0 0

1 c. £ 0 0

2 0 0

0 0 1 † 0§ 0 1

0 d. £ 1 0

1 0 0

2 2 0 † 3§ 1 2

1 e. £ 0 0

2 0 0

0 0 1 † 3§ 2 1

1 f. £ 0 0

0 4 3 † 0§ 0 0

0 g. £ 1 0

0 0 1

0 0 0 † 3§ 0 2

254

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Solution

The matrices in parts (a)–(c) are in row-reduced form.

d. This matrix is not in row-reduced form. Conditions 3 and 4 are violated: The leading 1 in row 2 lies to the left of the leading 1 in row 1. Also, column 3 contains a leading 1 in row 3 and a nonzero element above it. e. This matrix is not in row-reduced form. Conditions 2 and 4 are violated: The first nonzero entry in row 3 is a 2, not a 1. Also, column 3 contains a leading 1 and has a nonzero entry below it. f. This matrix is not in row-reduced form. Condition 2 is violated: The first nonzero entry in row 2 is not a leading 1. g. This matrix is not in row-reduced form. Condition 1 is violated: Row 1 consists of all zeros and does not lie below the nonzero rows. The foregoing discussion suggests the following adaptation of the Gauss–Jordan elimination method in solving systems of linear equations using matrices. First, the three operations on the equations of a system (see page 250) translate into the following row operations on the corresponding augmented matrices.

Row Operations

1. Interchange any two rows. 2. Replace any row by a nonzero constant multiple of itself. 3. Replace any row by the sum of that row and a constant multiple of any other row.

We obtained the augmented matrices in Example 2 by using the same operations that we used on the equivalent system of equations in Example 1. To help us describe the Gauss–Jordan elimination method using matrices, let’s introduce some terminology. We begin by defining what is meant by a unit column.

Unit Column

A column in a coefficient matrix is called a unit column if one of the entries in the column is a 1 and the other entries are zeros.

For example, in the coefficient matrix of (7d), only the first column is in unit form; in the coefficient matrix of (7h), all three columns are in unit form. Now, the sequence of row operations that transforms the augmented matrix (7a) into the equivalent matrix (7d) in which the first column 2 3 1

of (7a) is transformed into the unit column 1 0 0

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

255

is called pivoting the matrix about the element (number) 2. Similarly, we have pivoted about the element 2 in the second column of (7d), shown circled, 2 2 3

in order to obtain the augmented matrix (7g). Finally, pivoting about the element 11 in column 3 of (7g) 7 2 11

leads to the augmented matrix (7h), in which all columns to the left of the vertical line are in unit form. The element about which a matrix is pivoted is called the pivot element. Before looking at the next example, let’s introduce the following notation for the three types of row operations.

Notation for Row Operations

Letting Ri denote the ith row of a matrix, we write: Operation 1 Ri 4 Rj to mean: Interchange row i with row j. Operation 2 cRi to mean: Replace row i with c times row i. Operation 3 Ri  aRj to mean: Replace row i with the sum of row i and a times row j.

EXAMPLE 4 Pivot the matrix about the circled element. c

Solution

5 9 ` d 3 5

3 2

Using the notation just introduced, we obtain c

3 2

5 9 ` d 3 5

1 3 R1 ⎯→

c

5 3

1 2

`

3

3 d 5

R2  2R1 ⎯⎯⎯⎯→

c

5 3 13

1 0

`

3 d 1

The first column, which originally contained the entry 3, is now in unit form, with a 1 where the pivot element used to be, and we are done. Alternate Solution In the first solution, we used operation 2 to obtain a 1 where the pivot element was originally. Alternatively, we can use operation 3 as follows:

c Note

3 2

5 9 ` d 3 5

R1  R2 ⎯⎯⎯→

c

1 2

2 4 ` d 3 5

R2  2R1 ⎯⎯⎯⎯→

c

1 0

2 4 ` d 1 3

In Example 4, the two matrices c

1 0

5 3 13

`

3 d 1

and

c

1 0

2 4 ` d 1 3

256

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

look quite different, but they are in fact equivalent. You can verify this by observing that they represent the systems of equations x

5 y 3

x  2y 

3

4

and 1  y  1 3

y  3

respectively, and both have the same solution: x  2 and y  3. Example 4 also shows that we can sometimes avoid working with fractions by using an appropriate row operation. A summary of the Gauss–Jordan method follows. The Gauss–Jordan Elimination Method

1. Write the augmented matrix corresponding to the linear system. 2. Interchange rows (operation 1), if necessary, to obtain an augmented matrix in which the first entry in the first row is nonzero. Then pivot the matrix about this entry. 3. Interchange the second row with any row below it, if necessary, to obtain an augmented matrix in which the second entry in the second row is nonzero. Pivot the matrix about this entry. 4. Continue until the final matrix is in row-reduced form. Before writing the augmented matrix, be sure to write all equations with the variables on the left and constant terms on the right of the equal sign. Also, make sure that the variables are in the same order in all equations. EXAMPLE 5 Solve the system of linear equations given by 3x  2y  8z  9 2x  2y  z  3 x  2y  3z  8

(8)

Solution Using the Gauss–Jordan elimination method, we obtain the following sequence of equivalent augmented matrices:

3 £ 2 1

2 2 2

8 9 1 † 3§ 3 8

R1  R2 ⎯⎯⎯→

R2  2R1 ⎯⎯⎯⎯→ R3  R1

R2 4 R3 ⎯⎯⎯⎯→

1 2 R2 ⎯→

1 £ 2 1

0 2 2

9 12 1 † 3§ 3 8

1 £0 0

0 2 2

9 12 19 † 27 § 12 4

1 £0 0

0 2 2

9 12 12 † 4 § 19 27

1 £0 0

0 1 2

9 12 6 † 2 § 19 27

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

R3  2R2 ⎯⎯⎯⎯→

1 31 R3 ⎯→

R1  9R3 ⎯⎯⎯⎯→ R2  6R3

1 £0 0

0 1 0

9 12 6 † 2 § 31 31

1 £0 0

0 1 0

9 12 6 † 2 § 1 1

1 £0 0

0 1 0

0 3 0 † 4§ 1 1

257

The solution to System (8) is given by x  3, y  4, and z  1. This may be verified by substitution into System (8) as follows: 3132  2142  8112  9

✓

2132  2142  1 3 3  2142  3112  8

✓ ✓

When searching for an element to serve as a pivot, it is important to keep in mind that you may work only with the row containing the potential pivot or any row below it. To see what can go wrong if this caution is not heeded, consider the following augmented matrix for some linear system: 1 £0 0

1 0 2

2 3 3 † 1§ 1 2

Observe that column 1 is in unit form. The next step in the Gauss–Jordan elimination procedure calls for obtaining a nonzero element in the second position of row 2. If you use row 1 (which is above the row under consideration) to help you obtain the pivot, you might proceed as follows: 1 £0 0

1 0 2

2 3 3 † 1§ 1 2

R2 4 R1 ⎯⎯⎯⎯→

0 £1 0

0 1 2

3 1 2 † 3§ 1 2

As you can see, not only have we obtained a nonzero element to serve as the next pivot, but it is already a 1, thus obviating the next step. This seems like a good move. But beware, we have undone some of our earlier work: Column 1 is no longer a unit column where a 1 appears first. The correct move in this case is to interchange row 2 with row 3 in the first augmented matrix.

Explore & Discuss 1. Can the phrase “a nonzero constant multiple of itself” in a type-2 row operation be replaced by “a constant multiple of itself”? Explain. 2. Can a row of an augmented matrix be replaced by a row obtained by adding a constant to every element in that row without changing the solution of the system of linear equations? Explain.

The next example illustrates how to handle a situation in which the first entry in row 1 of the augmented matrix is zero.

258

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

EXAMPLE 6 Solve the system of linear equations given by 2y  3z  7 3x  6y  12z  3 5x  2y  2z  7 Solution Using the Gauss–Jordan elimination method, we obtain the following sequence of equivalent augmented matrices:

0 £3 5

2 6 2

3 7 12 † 3 § 2 7

R1 4 R2 ⎯⎯⎯⎯→

1 3 R1 ⎯→

R3  5R1 ⎯⎯⎯⎯→

1 2 R2 ⎯→

R1  2R2 ⎯⎯⎯⎯→ R3  12R2

1 40 R3 ⎯→

R1  7R3 ⎯⎯⎯⎯→ R2  32 R3

3 £0 5

6 2 2

12 3 3 † 7§ 2 7

1 £0 5

2 2 2

4 1 3 † 7§ 2 7

1 £0 0

2 2 12

4 1 3 † 7§ 22 2

1 £0 0

2 1 12

4

1 £0 0

0 1 0

7 40

40

1 £0 0

0 1 0

7

8

1 £0 0

0 1 0

0 1 0 † 2§ 1 1

3 2

1

†

7 2§

2

22

3 2

3 2

1

†

†

8

7 2§

7 2§

1

The solution to the system is given by x  1, y  2, and z  1; this may be verified by substitution into the system. APPLIED EXAMPLE 7 Manufacturing—Production Scheduling Complete the solution to Example 1 in Section 5.1, page 245. Solution To complete the solution of the problem posed in Example 1, recall that the mathematical formulation of the problem led to the following system of linear equations:

2x  y  z  180 x  3y  2z  300 2x  y  2z  240

where x, y, and z denote the respective numbers of type-A, type-B, and type-C souvenirs to be made.

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

259

Solving the foregoing system of linear equations by the Gauss–Jordan elimination method, we obtain the following sequence of equivalent augmented matrices: 2 £1 2

1 3 1

1 180 2 † 300 § 2 240

1 £2 2

3 1 1

1 £0 0

3 5 5

1 £0 0

3 1 5

R1  3R2 ⎯⎯⎯⎯→ R3  5R2

1 £0 0

0 1 0

48 † 84 § 1 60

R1  15 R3 ⎯⎯⎯⎯→ R2  35 R3

1 £0 0

0 1 0

0 36 0 † 48 § 1 60

R1 4 R2 ⎯⎯⎯⎯→

R2  2R1 ⎯⎯⎯⎯→ R3  2R1

15 R2 ⎯⎯→

2 300 1 † 180 § 2 240 2 300 3 † 420 § 2 360 2

300 † 84 § 2 360 3 5

1 5 3 5

Thus, x  36, y  48, and z  60; that is, Ace Novelty should make 36 type-A souvenirs, 48 type-B souvenirs, and 60 type-C souvenirs in order to use all available machine time.

5.2 Self-Check Exercises 1. Solve the system of linear equations 2x  3y  z 

6

x  2y  3z  3 3x  2y  4z  12

using the Gauss–Jordan elimination method. 2. A farmer has 200 acres of land suitable for cultivating crops A, B, and C. The cost per acre of cultivating crop A, crop B, and crop C is $40, $60, and $80, respectively. The

farmer has $12,600 available for land cultivation. Each acre of crop A requires 20 labor-hours, each acre of crop B requires 25 labor-hours, and each acre of crop C requires 40 labor-hours. The farmer has a maximum of 5950 laborhours available. If she wishes to use all of her cultivatable land, the entire budget, and all the labor available, how many acres of each crop should she plant? Solutions to Self-Check Exercises 5.2 can be found on page 263.

5.2 Concept Questions 1. a. Explain what it means for two systems of linear equations to be equivalent to each other. b. Give the meaning of the following notation used for row operations in the Gauss–Jordan elimination method: i. Ri 4 Rj

ii. cRi

iii. Ri  aRj

2. a. What is an augmented matrix? A coefficient matrix? A unit column? b. Explain what is meant by a pivot operation.

3. Suppose that a matrix is in row-reduced form. a. What is the position of a row consisting entirely of zeros relative to the nonzero rows? b. What is the first nonzero entry in each row? c. What is the position of the leading 1s in successive nonzero rows? d. If a column contains a leading 1, then what is the value of the other entries in that column?

260

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

5.2 Exercises In Exercises 1–4, write the augmented matrix corresponding to each system of equations.

1. 2x  3y  7 3x  y  4 3.

 y  2z  6 2x  2y  8z  7 3y  4z  0

2. 3x  7y  8z  5 x  3z  2 4x  3y  7 0 4. 3x1  2x2 x1  x2  2x3  4 2x2  3x3  5

In Exercises 5–8, write the system of equations corresponding to each augmented matrix.

3 5. c 1

2 4 ` d 1 5

0 6. £ 1 4

3 1 0

2 4 2 † 3 § 3 2

1 7. £ 2 3

3 0 3

2 4 0 † 5§ 2 6

0 25. £ 2 5

1 4 6

3 2 1

#

1 2

28. B 2 8. £ 4 0

3 3 0

1 6 2 † 5§ 0 0

10. c

1 0

1 3 ` d 0 0

0 11. c 1

1 3 ` d 0 5

0 12. c 0

1 3 ` d 0 5

1 13. £ 0 0

0 1 0

0 3 0 † 4§ 1 5

1 14. £ 0 0

0 1 0

1 15. £ 0 0

0 1 0

1 3 0 † 4§ 1 6

1 16. £ 0 0

0 10 1 † 2§ 0 0

0 17. £ 0 0

0 1 0

0 0 2 † 4§ 0 0

1 0 18. ≥ 0 0

0 1 0 0

0 1 0 † 2 § 2 3

0 3 0 6 ∞ ¥ 0 4 1 5

1 B#

2 3

21. c

1 6

4 8 ` d 1 2 2 3 ` d 4 2

1 26. £ 0 0

#

#

2

1

2 15 R2 1 R⎯⎯→ B

3

9 6 ` R 1 4 `

3

#

1 3 R1 ⎯→

#

`

2

#

1 #R

3 4 2

2 4 8 † 6§ 3 4

2 3 4

3 5 3 † 2§ 1 3

#

3

#

1

0

9

1

#

#

#

1

£0

0 30. £ 1 1 R3  R1 ⎯⎯⎯→

1 3 3 † 7§ 1 10

#

#

#

0 † 2§

#

1 £0

#

1 £0

#

1

3

# #

1

# #

# #

3

# § ⎯R ⎯→ #

†

2

#

4 3 † 4 §

#

2

1 £0 0

R1 4 R2 ⎯⎯⎯→

0 1

#

1

R3  9R2

R1  R3 ⎯⎯⎯→ R3

1 2

#

£

R2  3R1 ⎯⎯⎯⎯→ R3  2R1

1 7 3 † 4 §

#

1 R2 # R ⎯⎯→

0 5 ` R 1 3

1 0

2 1

#

#

R  3R # § ⎯⎯⎯⎯→

3 4 1 † 7§ 0 1

1 2 2

`

2

B

16

#

0 2 ` R 1 0

2 R1  3R2 1 # R ⎯⎯⎯⎯→ B0

3

†

#

R2  2R1

R ⎯⎯⎯⎯→

4

`

#

R1  2R2 ⎯⎯⎯⎯→

#

`

2 1 R2  2R1 1 ` R⎯⎯⎯⎯→ B # 3 1

1

£

B

#

3 8 3

⎯→

19. c

1 24. £ 2 1

3 4 1 † 3§ 2 4

1 29. £ 3 2

1 11 R3

In Exercises 19–26, pivot the system about the circled element.

6 12 1 † 5§ 2 4

In Exercises 27–30, fill in the missing entries by performing the indicated row operations to obtain the rowreduced matrices.

B

0 3 ` d 1 2

1 0

4 3 1

27. B

In Exercises 9–18, indicate whether the matrix is in rowreduced form.

9. c

2 23. £ 2 3

£

0 1 0 † 2§ 1 2

0 1 0

# #

# #

# #

1

2

0

#

#

#

1

R1  21 R3 ⎯⎯⎯⎯→ R3  4R2

£0

R1  21 R3 ⎯⎯⎯⎯→ R2  3R3

1 £0 0

#

0 1 0

†

# #§ 1

#

#

#

#

3 † 4 § 0 5 0 † 2§ 1 2

20. c

3 4

2 6 ` d 2 5

31. Write a system of linear equations for the augmented matrix of Exercise 27. Using the results of Exercise 27, determine the solution of the system.

22. c

1 2

3 4 ` d 4 6

32. Repeat Exercise 31 for the augmented matrix of Exercise 28.

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

33. Repeat Exercise 31 for the augmented matrix of Exercise 29. 34. Repeat Exercise 31 for the augmented matrix of Exercise 30. In Exercises 35–50, solve the system of linear equations using the Gauss–Jordan elimination method.

35. x  2y  8 3x  4y  4

36.

3x  y  1 7x  2y  1

37. 2x  3y  8 4x  y  2

38.

5x  3y  9 2x  y  8

39. x  y  z  0 2x  y  z  1 x  y  2z  2

40. 2x  y  2z  4 x  3y  z  3 3x  4y  z  7

41. 2x  2y  z  9 x  z 4 4y  3z  17

42. 2x  3y  2z  10 3x  2y  2z  0 4x  y  3z  1

43.

 x2  x3  2 4x1  3x2  2x3  16 3x1  2x2  x3  11

44. 2x  4y  6z  38 x  2y  3z  7 3x  4y  4z  19

45. x1  2x2  x3  6 2x1  x2  3x3  3 x1  3x2  3x3  10

46. 2x  3y  6z  11 x  2y  3z  9 3x  y  7

 3z  1 47. 2x 3x  2y  z  9 x  y  4z  4

48. 2x1  x2  3x3  4 x1  2x2  x3  1 x1  5x2  2x3  3

49.

x1  x2  3x3  14 50. 2x1  x2  x3  0 x1  x2  x3  6 3x1  2x2  x3  7 x1  2x2  2x3  5 2x1  x2  x3  4

The problems in Exercises 51–63 correspond to those in Exercises 15–27, Section 5.1. Use the results of your previous work to help you solve these problems.

51. AGRICULTURE The Johnson Farm has 500 acres of land allotted for cultivating corn and wheat. The cost of cultivating corn and wheat (including seeds and labor) is $42 and $30 per acre, respectively. Jacob Johnson has $18,600 available for cultivating these crops. If he wishes to use all the allotted land and his entire budget for cultivating these two crops, how many acres of each crop should he plant? 52. INVESTMENTS Michael Perez has a total of $2000 on deposit with two savings institutions. One pays interest at the rate of 6%/year, whereas the other pays interest at the rate of 8%/year. If Michael earned a total of $144 in interest during a single year, how much does he have on deposit in each institution? 53. MIXTURES The Coffee Shoppe sells a coffee blend made from two coffees, one costing $5/lb and the other costing $6/lb. If the blended coffee sells for $5.60/lb, find how much of each coffee is used to obtain the desired blend. Assume that the weight of the blended coffee is 100 lb.

261

54. INVESTMENTS Kelly Fisher has a total of $30,000 invested in two municipal bonds that have yields of 8% and 10% interest per year, respectively. If the interest Kelly receives from the bonds in a year is $2640, how much does she have invested in each bond? 55. RIDERSHIP The total number of passengers riding a certain city bus during the morning shift is 1000. If the child’s fare is $.50, the adult fare is $1.50, and the total revenue from the fares in the morning shift is $1300, how many children and how many adults rode the bus during the morning shift? 56. REAL ESTATE Cantwell Associates, a real estate developer, is planning to build a new apartment complex consisting of one-bedroom units and two- and three-bedroom townhouses. A total of 192 units is planned, and the number of family units (two- and three-bedroom townhouses) will equal the number of one-bedroom units. If the number of one-bedroom units will be 3 times the number of threebedroom units, find how many units of each type will be in the complex. 57. INVESTMENT PLANNING The annual returns on Sid Carrington’s three investments amounted to $21,600: 6% on a savings account, 8% on mutual funds, and 12% on bonds. The amount of Sid’s investment in bonds was twice the amount of his investment in the savings account, and the interest earned from his investment in bonds was equal to the dividends he received from his investment in mutual funds. Find how much money he placed in each type of investment. 58. INVESTMENT CLUB A private investment club has $200,000 earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of 15%/year; medium-risk stocks, 10%/year; and low-risk stocks, 6%/year. The members have decided that the investment in low-risk stocks should be equal to the sum of the investments in the stocks of the other two categories. Determine how much the club should invest in each type of stock if the investment goal is to have a return of $20,000/year on the total investment. (Assume that all the money available for investment is invested.) 59. MIXTURE PROBLEM—FERTILIZER Lawnco produces three grades of commercial fertilizers. A 100-lb bag of grade-A fertilizer contains 18 lb of nitrogen, 4 lb of phosphate, and 5 lb of potassium. A 100-lb bag of grade-B fertilizer contains 20 lb of nitrogen and 4 lb each of phosphate and potassium. A 100-lb bag of grade-C fertilizer contains 24 lb of nitrogen, 3 lb of phosphate, and 6 lb of potassium. How many 100-lb bags of each of the three grades of fertilizers should Lawnco produce if 26,400 lb of nitrogen, 4900 lb of phosphate, and 6200 lb of potassium are available and all the nutrients are used?

262

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

60. BOX-OFFICE RECEIPTS A theater has a seating capacity of 900 and charges $4 for children, $6 for students, and $8 for adults. At a certain screening with full attendance, there were half as many adults as children and students combined. The receipts totaled $5600. How many children attended the show? 61. MANAGEMENT DECISIONS The management of Hartman Rent-A-Car has allocated $1.5 million to buy a fleet of new automobiles consisting of compact, intermediate-size, and full-size cars. Compacts cost $12,000 each, intermediatesize cars cost $18,000 each, and full-size cars cost $24,000 each. If Hartman purchases twice as many compacts as intermediate-size cars and the total number of cars to be purchased is 100, determine how many cars of each type will be purchased. (Assume that the entire budget will be used.) 62. INVESTMENT CLUBS The management of a private investment club has a fund of $200,000 earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of 15%/year; medium-risk stocks, 10%/year; and low-risk stocks, 6%/year. The investment in low-risk stocks is to be twice the sum of the investments in stocks of the other two categories. If the investment goal is to have an average rate of return of 9%/year on the total investment, determine how much the club should invest in each type of stock. (Assume that all of the money available for investment is invested.) 63. DIET PLANNING A dietitian wishes to plan a meal around three foods. The percent of the daily requirements of proteins, carbohydrates, and iron contained in each ounce of the three foods is summarized in the following table:

Proteins (%) Carbohydrates (%) Iron (%)

Food I 10 10 5

Food II 6 12 4

Food III 8 6 12

Determine how many ounces of each food the dietitian should include in the meal to meet exactly the daily requirement of proteins, carbohydrates, and iron (100% of each). 64. INVESTMENTS Mr. and Mrs. Garcia have a total of $100,000 to be invested in stocks, bonds, and a money market account. The stocks have a rate of return of 12%/year, while the bonds and the money market account pay 8%/year and 4%/year, respectively. The Garcias have stipulated that the amount invested in the money market account should be equal to the sum of 20% of the amount invested in stocks and 10% of the amount invested in bonds. How should the Garcias allocate their resources if they require an annual income of $10,000 from their investments?

65. BOX-OFFICE RECEIPTS For the opening night at the Opera House, a total of 1000 tickets were sold. Front orchestra seats cost $80 apiece, rear orchestra seats cost $60 apiece, and front balcony seats cost $50 apiece. The combined number of tickets sold for the front orchestra and rear orchestra exceeded twice the number of front balcony tickets sold by 400. The total receipts for the performance were $62,800. Determine how many tickets of each type were sold. 66. PRODUCTION SCHEDULING A manufacturer of women’s blouses makes three types of blouses: sleeveless, shortsleeve, and long-sleeve. The time (in minutes) required by each department to produce a dozen blouses of each type is shown in the following table:

Cutting Sewing Packaging

Sleeveless 9 22 6

ShortSleeve 12 24 8

LongSleeve 15 28 8

The cutting, sewing, and packaging departments have available a maximum of 80, 160, and 48 labor-hours, respectively, per day. How many dozens of each type of blouse can be produced each day if the plant is operated at full capacity? 67. BUSINESS TRAVEL EXPENSES An executive of Trident Communications recently traveled to London, Paris, and Rome. He paid $180, $230, and $160 per night for lodging in London, Paris, and Rome, respectively, and his hotel bills totaled $2660. He spent $110, $120, and $90 per day for his meals in London, Paris, and Rome, respectively, and his expenses for meals totaled $1520. If he spent as many days in London as he did in Paris and Rome combined, how many days did he stay in each city? 68. VACATION COSTS Joan and Dick spent 2 wk (14 nights) touring four cities on the East Coast—Boston, New York, Philadelphia, and Washington. They paid $120, $200, $80, and $100 per night for lodging in each city, respectively, and their total hotel bill came to $2020. The number of days they spent in New York was the same as the total number of days they spent in Boston and Washington, and the couple spent 3 times as many days in New York as they did in Philadelphia. How many days did Joan and Dick stay in each city? In Exercises 69 and 70, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

69. An equivalent system of linear equations can be obtained from a system of equations by replacing one of its equations by any constant multiple of itself. 70. If the augmented matrix corresponding to a system of three linear equations in three variables has a row of the form 3 0 0 0 0 a4 , where a is a nonzero number, then the system has no solution.

5.2 SYSTEMS OF LINEAR EQUATIONS: UNIQUE SOLUTIONS

263

5.2 Solutions to Self-Check Exercises 1. We obtain the following sequence of equivalent augmented matrices: 2 £1 3

3 2 2

R2  2R1 ⎯⎯⎯⎯→ R3  3R1

1 £0 0

2 8 7

1 6 3 † 3 § 4 12 1 £0 0

2 7 8

R1 4 R2 ⎯⎯⎯→

1 £2 3

3 3 5 † 12 § 13 21

3 3 13 † 21 § 5 12

R2  R3 ⎯⎯⎯→

R1  2R2 ⎯⎯⎯⎯→ R3  7R2

1 £0 0

0 1 0

13 15 8 † 9§ 51 51

R1  13R3 ⎯⎯⎯⎯→ R2  8R3

1 £0 0

0 1 0

0 2 0 † 1§ 1 1

2 3 2

1 51 R3 ⎯⎯ →

x

3 3 1 † 6§ 4 12

2 1 7

3 3 8 † 9 § 5 12

1 £0 0

0 1 0

200

Using the Gauss–Jordan elimination method, we have 1 £ 40 20 1 20 R2 ⎯⎯ →

13 15 8 † 9 § 1 1

1 10 R3 ⎯⎯ →

1 60 25

1 200 80 † 12,600 § 40 5,950

R2  40R1 ⎯⎯⎯⎯→ R3  20R1

1 £0 0

1 20 5

1 200 40 † 4600 § 20 1950

1 £0 0

1 1 5

1 200 2 † 230 § 20 1950

R1  R2 ⎯⎯⎯⎯→ R3  5R2

1 £0 0

0 1 0

1 30 2 † 230 § 10 800

1 £0 0

0 1 0

1 30 2 † 230 § 1 80

R1  R3 ⎯⎯⎯⎯→ R  2R3

1 £0 0

0 1 0

0 50 0 † 70 § 1 80

From the last augmented matrix in reduced form, we see that x  50, y  70, and z  80. Therefore, the farmer should plant 50 acres of crop A, 70 acres of crop B, and 80 acres of crop C.

2. Referring to the solution of Exercise 2, Self-Check Exercises 5.1, we see that the problem reduces to solving the

TECHNOLOGY

z

40x  60y  80z  12,600

The solution to the system is x  2, y  1, and z  1.

USING

y

20x  25y  40z  5,950

R2 4 R3 ⎯⎯⎯→

1 £0 0

following system of linear equations:

Systems of Linear Equations: Unique Solutions Solving a System of Linear Equations Using the Gauss–Jordan Method

The three matrix operations can be performed on a matrix using a graphing utility. The commands are summarized in the following table. Calculator Function Operation

TI-83/84

TI-86

Ri 4 Rj cRi Ri  aRj

rowSwap([A], i, j) *row(c, [A], i) *row(a, [A], j, i)

rSwap(A, i, j) multR(c, A, i) mRAdd(a, A, j, i)

or equivalent or equivalent or equivalent

When a row operation is performed on a matrix, the result is stored as an answer in the calculator. If another operation is performed on this matrix, then the matrix is erased. Should a mistake be made in the operation, the previous matrix may be lost. For this reason, you should store the results of each operation. We do this by pressing STO, followed by the name of a matrix, and then ENTER. We use this process in the following example. EXAMPLE 1 Use a graphing utility to solve the following system of linear equations by the Gauss–Jordan method (see Example 5 in Section 5.2): 3x  2y  8z  9 2x  2y  z  3 x  2y  3z  8

(continued)

264

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Solution Using the Gauss–Jordan method, we obtain the following sequence of equivalent matrices.

3 £ 2 1

2 2 2

1 £ 2 1

0 2 2

8 9 1 † 3§ 3 8 9 12 1 † 3§ 3 8

*row (1, [A], 2, 1) 䉴 B ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

*row (2, [B], 1, 2) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

1 £0 1

0 2 2

9 12 19 † 27 § 3 8

1 £0 0

0 2 2

9 12 19 † 27 § 12 4

1 £0 0

0 1 2

9 12 9.5 † 13.5 § 12 4

1 £0 0

0 1 0

9 12 9.5 † 13.5 § 31 31

1 £0 0

0 1 0

9 12 9.5 † 13.5 § 1 1

*row (9, [C], 3, 1) 䉴 B ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

1 £0 0

0 1 0

0 3 9.5 † 13.5 § 1 1

*row (9.5, [B], 3, 2) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

*row (1, [C], 1, 3) 䉴 B ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

*row(12 , [B], 2) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯→

*row (2, [C], 2, 3) 䉴 B ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→

*row(311 , [B], 3) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯⎯→

1 £0 0

0 1 0

0 3 0 † 4§ 1 1

The last matrix is in row-reduced form, and we see that the solution of the system is x  3, y  4, and z  1. Using rref (TI-83/84 and TI-86) to Solve a System of Linear Equations

The operation rref (or equivalent function in your utility, if there is one) will transform an augmented matrix into one that is in row-reduced form. For example, using rref, we find 3 £ 2 1

2 2 2

8 9 1 † 3§ 3 8

rref ⎯→

1 £0 0

0 1 0

0 3 0 † 4§ 1 1

as obtained earlier! Using

SIMULT

(TI-86) to Solve a System of Equations

The operation SIMULT (or equivalent operation on your utility, if there is one) of a graphing utility can be used to solve a system of n linear equations in n variables, where n is an integer between 2 and 30, inclusive.

5.3 SYSTEMS OF LINEAR EQUATIONS: UNDERDETERMINED AND OVERDETERMINED SYSTEMS

265

EXAMPLE 2 Use the SIMULT operation to solve the system of Example 1. Call for the SIMULT operation. Since the system under consideration has three equations in three variables, enter n  3. Next, enter a1, 1  3, a1, 2  2, a1, 3  8, b1  9, a2, 1  2, . . . , b3  8. Select <SOLVE> and the display

Solution

x1 = 3 x2 = 4 x3 = 1

appears on the screen, giving x  3, y  4, and z  1 as the required solution.

TECHNOLOGY EXERCISES Use a graphing utility to solve the system of equations (a) by the Gauss–Jordan method, (b) using the rref operation, and (c) using SIMULT.

1.

2.

x1  2x2  2x3  3x4  7 3x1  2x2  x3  5x4  22 2x1  3x2  4x3  x4  3 3x1  2x2  x3  2x4  12

4.

x1  2x2  2x3  x4  1 2x1  x2  2x3  3x4  2 x1  5x2  7x3  2x4  3 3x1  4x2  3x3  4x4  4

5. 2x1  2x2  3x3  x4  2x5  16 3x1  x2  2x3  x4  3x5  11 x1  3x2  4x3  3x4  x5  13 2x1  x2  3x3  2x4  2x5  15 3x1  4x2  3x3  5x4  x5  10

2x1  x2  3x3  2x4  2 x1  2x2  x3  3x4  2 x1  5x2  2x3  3x4  6 3x1  3x2  4x3  4x4  9

6. 2.1x1  3.2x2  6.4x3  7x4  3.2x5  54.3 4.1x1  2.2x2  3.1x3  4.2x4  3.3x5  20.81 3.4x1  6.2x2  4.7x3  2.1x4  5.3x5  24.7 4.1x1  7.3x2  5.2x3  6.1x4  8.2x5  29.25 2.8x1  5.2x2  3.1x3  5.4x4  3.8x5  43.72

3. 2x1  x2  3x3  x4  9 x1  2x2  3x4  1 x1  3x3  x4  10 x1  x2  x3  x4  8

5.3 Systems of Linear Equations: Underdetermined and Overdetermined Systems In this section, we continue our study of systems of linear equations. More specifically, we look at systems that have infinitely many solutions and those that have no solution. We also study systems of linear equations in which the number of variables is not equal to the number of equations in the system.

Solution(s) of Linear Equations Our first example illustrates the situation in which a system of linear equations has infinitely many solutions. EXAMPLE 1 A System of Equations with an Infinite Number of Solutions Solve the system of linear equations given by x  2y  3z  2 3x  y  2z  1 2x  3y  5z  3

(9)

266

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Solution Using the Gauss–Jordan elimination method, we obtain the following sequence of equivalent augmented matrices:

1 £3 2 1 £0 0

2 1 3 2 1 1

3 2 2 † 1 § 5 3 3 2 1 † 1 § 1 1

R2  3R1 ⎯⎯⎯→ R3  2 R1

R1  2R2 ⎯⎯⎯→ R3  R2

1 £0 0 1 £0 0

2 3 2 7 7 † 7§ 1 1 1 0 1 0 1 1 † 1 § 0 0 0

17 R2 ⎯⎯→

The last augmented matrix is in row-reduced form. Interpreting it as a system of linear equations gives xz 0 y  z  1 a system of two equations in the three variables x, y, and z. Let’s now single out one variable—say, z—and solve for x and y in terms of it. We obtain xz yz1 If we assign a particular value to z—say, z  0—we obtain x  0 and y  1, giving the solution (0, 1, 0) to System (9). By setting z  1, we obtain the solution (1, 0, 1). In general, if we set z  t, where t represents some real number (called a parameter), we obtain a solution given by (t, t  1, t). Since the parameter t may be any real number, we see that System (9) has infinitely many solutions. Geometrically, the solutions of System (9) lie on the straight line in three-dimensional space given by the intersection of the three planes determined by the three equations in the system. Note In Example 1 we chose the parameter to be z because it is more convenient to solve for x and y (both the x- and y-columns are in unit form) in terms of z.

The next example shows what happens in the elimination procedure when the system does not have a solution. EXAMPLE 2 A System of Equations That Has No Solution Solve the system of linear equations given by x y z 1 3x  y  z  4 (10) x  5y  5z  1 Solution Using the Gauss–Jordan elimination method, we obtain the following sequence of equivalent augmented matrices:

1 £3 1

1 1 5

1 1 1 † 4 § 5 1

R2  3R1 ⎯⎯⎯→ R3  R1 R3  R2 ⎯⎯⎯→

1 £0 0 1 £0 0

1 4 4 1 4 0

1 1 4 † 1 § 4 2 1 1 4 † 1 § 0 1

Observe that row 3 in the last matrix reads 0x  0y  0z   1—that is, 0  1! We therefore conclude that System (10) is inconsistent and has no solution. Geometrically, we have a situation in which two of the planes intersect in a straight line but the third plane is parallel to this line of intersection of the two planes and does not intersect it. Consequently, there is no point of intersection of the three planes.

5.3 SYSTEMS OF LINEAR EQUATIONS: UNDERDETERMINED AND OVERDETERMINED SYSTEMS

267

Example 2 illustrates the following more general result of using the Gauss–Jordan elimination procedure. Systems with No Solution

If there is a row in an augmented matrix containing all zeros to the left of the vertical line and a nonzero entry to the right of the line, then the corresponding system of equations has no solution. It may have dawned on you that in all the previous examples we have dealt only with systems involving exactly the same number of linear equations as there are variables. However, systems in which the number of equations is different from the number of variables also occur in practice. Indeed, we will consider such systems in Examples 3 and 4. The following theorem provides us with some preliminary information on a system of linear equations.

THEOREM 1 a. If the number of equations is greater than or equal to the number of variables in a linear system, then one of the following is true: i. The system has no solution. ii. The system has exactly one solution. iii. The system has infinitely many solutions. b. If there are fewer equations than variables in a linear system, then the system either has no solution or it has infinitely many solutions. Theorem 1 may be used to tell us, before we even begin to solve a problem, what the nature of the solution may be.

Note

Although we will not prove this theorem, you should recall that we have illustrated geometrically part (a) for the case in which there are exactly as many equations (three) as there are variables. To show the validity of part (b), let us once again consider the case in which a system has three variables. Now, if there is only one equation in the system, then it is clear that there are infinitely many solutions corresponding geometrically to all the points lying on the plane represented by the equation. Next, if there are two equations in the system, then only the following possibilities exist: 1. The two planes are parallel and distinct. 2. The two planes intersect in a straight line. 3. The two planes are coincident (the two equations define the same plane) (Figure 6). P2

P1

P1

P2 2

P1, P2

(a) No solution FIGURE 6

(b) Infinitely many solutions

(c) Infinitely many solutions

268

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Thus, either there is no solution or there are infinitely many solutions corresponding to the points lying on a line of intersection of the two planes or on a single plane determined by the two equations. In the case where two planes intersect in a straight line, the solutions will involve one parameter, and in the case where the two planes are coincident, the solutions will involve two parameters.

Explore & Discuss Give a geometric interpretation of Theorem 1 for a linear system composed of equations involving two variables. Specifically, illustrate what can happen if there are three linear equations in the system (the case involving two linear equations has already been discussed in Section 5.1). What if there are four linear equations? What if there is only one linear equation in the system?

EXAMPLE 3 A System with More Equations Than Variables Solve the following system of linear equations: x  2y  4 x  2y  0 4x  3y  12 Solution

We obtain the following sequence of equivalent augmented matrices: 1 £1 4

2 4 2 † 0 § 3 12

R2  R1 ⎯⎯⎯→ R3  4R1

1 £0 0

2 4 4 † 4 § 5 4

1 £0 0

2 4 1 † 1§ 5 4

R1  2R2 ⎯⎯⎯→ R3  5R2

1 £0 0

0 2 1 † 1§ 0 1

14 R2 ⎯⎯→

The last row of the row-reduced augmented matrix implies that 0  1, which is impossible, so we conclude that the given system has no solution. Geometrically, the three lines defined by the three equations in the system do not intersect at a point. (To see this for yourself, draw the graphs of these equations.) EXAMPLE 4 A System with More Variables Than Equations Solve the following system of linear equations: x  2y  3z  w  2 3x  y  2z  4w  1 2x  3y  5z  w  3

First, observe that the given system consists of three equations in four variables and so, by Theorem 1b, either the system has no solution or it has infinitely many solutions. To solve it we use the Gauss–Jordan method and obtain the following sequence of equivalent augmented matrices: Solution

1 £3 2

2 1 3

3 2 5

1 2 4 † 1 § 1 3

R2  3R1 ⎯⎯⎯→ R3  2 R1

1 £0 0

2 7 1

1 £0 0

2 1 1

3 1 1

1 2 1 † 1 § 1 1

R1  2R2 ⎯⎯⎯→ R3  R2

1 £0 0

0 1 0

3 7 1 1 1 0

1 2 7 † 7 § 1 1 1 0 1 † 1 § 0 0

17 R2 ⎯⎯→

5.3 SYSTEMS OF LINEAR EQUATIONS: UNDERDETERMINED AND OVERDETERMINED SYSTEMS

269

The last augmented matrix is in row-reduced form. Observe that the given system is equivalent to the system xzw 0 y  z  w  1

of two equations in four variables. Thus, we may solve for two of the variables in terms of the other two. Letting z  s and w  t (where s and t are any real numbers), we find that xst yst1 zs wt

The solutions may be written in the form (s  t, s  t  1, s, t). Geometrically, the three equations in the system represent three hyperplanes in four-dimensional space (since there are four variables) and their “points” of intersection lie in a two-dimensional subspace of four-space (since there are two parameters). In Example 4, we assigned parameters to z and w rather than to x and y because x and y are readily solved in terms of z and w.

Note

The following example illustrates a situation in which a system of linear equations has infinitely many solutions. APPLIED EXAMPLE 5 Traffic Control Figure 7 shows the flow of downtown traffic in a certain city during the rush hours on a typical weekday. The arrows indicate the direction of traffic flow on each one-way road, and the average number of vehicles per hour entering and leaving each intersection appears beside each road. 5th Avenue and 6th Avenue can each handle up to 2000 vehicles per hour without causing congestion, whereas the maximum capacity of both 4th Street and 5th Street is 1000 vehicles per hour. The flow of traffic is controlled by traffic lights installed at each of the four intersections. 4th St. 300 5th Ave.

1200

5th St. 500 x1 x2

x4 6th Ave.

1300

1400 x3

700

FIGURE 7

800

400

a. Write a general expression involving the rates of flow—x1, x2, x3, x4—and suggest two possible flow patterns that will ensure no traffic congestion. b. Suppose the part of 4th Street between 5th Avenue and 6th Avenue is to be resurfaced and that traffic flow between the two junctions must therefore be reduced to at most 300 vehicles per hour. Find two possible flow patterns that will result in a smooth flow of traffic. Solution

a. To avoid congestion, all traffic entering an intersection must also leave that intersection. Applying this condition to each of the four intersections in a

270

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

clockwise direction beginning with the 5th Avenue and 4th Street intersection, we obtain the following equations: 1500  x1  x4 1300  x1  x2 1800  x2  x3 2000  x3  x4

This system of four linear equations in the four variables x1, x2, x3, x4 may be rewritten in the more standard form x1  x4  1500 x1  x2  1300 x2  x3  1800 x3  x4  2000

Using the Gauss–Jordan elimination method to solve the system, we obtain 1 1 ≥ 0 0

0 1 1 0

0 0 1 1

1500 1 0 1300 ∞ ¥ 0 1800 1 2000

R2  R1 ⎯⎯⎯→

1 0 ≥ 0 0

0 1 1 0

0 0 1 1

1500 1 1 200 ∞ ¥ 0 1800 1 2000

R3  R2 ⎯⎯⎯→

1 0 ≥ 0 0

0 1 0 0

0 0 1 1

1 1500 1 200 ∞ ¥ 1 2000 1 2000

1 0 ≥ 0 0

0 1 0 0

0 0 1 0

1 1500 1 200 ∞ ¥ 1 2000 0 0

R4  R3 ⎯⎯⎯→

The last augmented matrix is in row-reduced form and is equivalent to a system of three linear equations in the four variables x1, x2, x3, x4. Thus, we may express three of the variables—say, x1, x2, x3—in terms of x4. Setting x4  t (t a parameter), we may write the infinitely many solutions of the system as x1  1500  t x2  200  t x3  2000  t x4  t

Observe that for a meaningful solution we must have 200 t 1000 since x1, x2, x3, and x4 must all be nonnegative and the maximum capacity of a street is 1000. For example, picking t  300 gives the flow pattern x1  1200

x2  100

x3  1700

x4  300

x3  1500

x4  500

Selecting t  500 gives the flow pattern x1  1000

x2  300

b. In this case, x4 must not exceed 300. Again, using the results of part (a), we find, upon setting x4  t  300, the flow pattern x1  1200

x2  100

x3  1700

x4  300

obtained earlier. Picking t  250 gives the flow pattern x1  1250

x2  50

x3  1750

x4  250

5.3 SYSTEMS OF LINEAR EQUATIONS: UNDERDETERMINED AND OVERDETERMINED SYSTEMS

271

5.3 Self-Check Exercises 1. The following augmented matrix in row-reduced form is equivalent to the augmented matrix of a certain system of linear equations. Use this result to solve the system of equations. 1 £0 0

0 1 0

x  2y  3z  9 2x  3y  z  4 x  5y  4z  2

1 3 5 † 2 § 0 0

using the Gauss–Jordan elimination method. Solutions to Self-Check Exercises 5.3 can be found on page 273.

2. Solve the system of linear equations 2x  3y  z 

3. Solve the system of linear equations

6

x  2y  4z  4 x  5y  3z  10

using the Gauss–Jordan elimination method.

5.3 Concept Questions 1. a. If a system of linear equations has the same number of equations or more equations than variables, what can you say about the nature of its solution(s)? b. If a system of linear equations has fewer equations than variables, what can you say about the nature of its solution(s)?

2. A system consists of three linear equations in four variables. Can the system have a unique solution?

5.3 Exercises In Exercises 1–12, given that the augmented matrix in row-reduced form is equivalent to the augmented matrix of a system of linear equations, (a) determine whether the system has a solution and (b) find the solution or solutions to the system, if they exist.

1 1. £ 0 0

0 1 0

0 3 0 † 1 § 1 2

1 3. £ 0 0

0 2 1 † 4§ 0 0

0 0 1 0

0 1 0 0

3 1 0 0

0 2 0 0 1 0 ∞ ¥ 10. ≥ 1 2 0 0 0 0

1 0 0 0

0 1 0 0

0 2 1 0 0 1 ∞ ¥ 12. ≥ 0 0 0 0 0 0

0 1 0 0

3 2 0 0

1 3 2 4 ∞ ¥ 0 0 0 0 1 4 3 2 ∞ ¥ 0 0 0 0

0 1 0

0 3 0 † 2 § 1 1

1 0 11. ≥ 0 0

1 4. £ 0 0

0 1 0

0 3 0 † 1§ 0 0

In Exercises 13–32, solve the system of linear equations, using the Gauss–Jordan elimination method.

0 1 0

0 1 0

0 1 0 0

0 4 0 1 ∞ ¥ 1 3 0 1

1 0

0 1

1 4 ` d 0 2

1 0 7. ≥ 0 0

0 1 0 0

0 0 1 0

1 0 8. ≥ 0 0

0 2 0 1 ∞ ¥ 0 3 0 1

0 1 0 0

1 2. £ 0 0

1 6. £ 0 0

5. c

1 0 9. ≥ 0 0

0 3 0 † 1 § 1 2

13. 2x  y  3 x  2y  4 2x  3y  7

14.

x  2y  3 2x  3y  8 x  4y  9

15. 3x  2y  3 2x  y  3 x  2y  5

16. 2x  3y  2 x  3y  2 x y 3

17. 3x  2y  5 x  3y  4 2x  4y  6

18. 4x  6y  8 3x  2y  7 x  3y  5

272

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

19. x  2y  2 7x  14y  14 3x  6y  6 21.

23.

3x  2y  4 32 x  y  2 6x  4y  8

20.

x  2y  z  2 2x  3y  z  1 2x  4y  2z  4

22.

3y  2z  4 2x  y  3z  3 2x  2y  z  7

2x1  x2  x3  4 3x1  32 x2  32 x3  6 6x1  3x2  3x3  12

24. x  y  2z  3 2x  y  3z  7 x  2y  5z  0

25. x  2y  3z  4 2x  3y  z  2 x  2y  3z  6

26. x1  2x2  x3  3 2x1  x2  2x3  2 x1  3x2  3x3  5 27. 4x  y  z  4 8x  2y  2z  8

28. x1  2x2  4x3  2 x1  x2  2x3  1

29. 2x  y  3z  1 x  y  2z  1 5x  2y  3z  6

30. 3x  9y  6z  12 x  3y  2z  4 2x  6y  4z  8

31. x  2y  z  4 2x  y  z  7 x  3y  2z  7 x  3y  z  9

32. 3x  2y  z  4 x  3y  4z  3 2x  3y  5z  7 x  8y  9z  10

33. MANAGEMENT DECISIONS The management of Hartman Rent-A-Car has allocated $1,008,000 to purchase 60 new automobiles to add to their existing fleet of rental cars. The company will choose from compact, mid-sized, and fullsized cars costing $12,000, $19,200, and $26,400 each, respectively. Find formulas giving the options available to the company. Give two specific options. (Note: Your answers will not be unique.) 34. NUTRITION A dietitian wishes to plan a meal around three foods. The meal is to include 8800 units of vitamin A, 3380 units of vitamin C, and 1020 units of calcium. The number of units of the vitamins and calcium in each ounce of the foods is summarized in the following table:

Vitamin A Vitamin C Calcium

Food I 400 110 90

Food II 1200 570 30

Food III 800 340 60

Determine the amount of each food the dietitian should include in the meal in order to meet the vitamin and calcium requirements. 35. NUTRITION Refer to Exercise 34. In planning for another meal, the dietitian changes the requirement of vitamin C from 3380 units to 2160 units. All other requirements remain the same. Show that such a meal cannot be planned around the same foods.

36. MANUFACTURING PRODUCTION SCHEDULE Ace Novelty manufactures “Giant Pandas,” “Saint Bernards,” and “Big Birds.” Each Panda requires 1.5 yd2 of plush, 30 ft3 of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 yd2 of plush, 35 ft3 of stuffing, and 8 pieces of trim; and each Big Bird requires 2.5 yd2 of plush, 25 ft3 of stuffing, and 15 pieces of trim. If 4700 yd2 of plush, 65,000 ft3 of stuffing, and 23,400 pieces of trim are available, how many of each of the stuffed animals should the company manufacture if all the material is to be used? Give two specific options. 37. INVESTMENTS Mr. and Mrs. Garcia have a total of $100,000 to be invested in stocks, bonds, and a money market account. The stocks have a rate of return of 12%/year, while the bonds and the money market account pay 8%/year and 4%/year, respectively. The Garcias have stipulated that the amount invested in stocks should be equal to the sum of the amount invested in bonds and 3 times the amount invested in the money market account. How should the Garcias allocate their resources if they require an annual income of $10,000 from their investments? Give two specific options. 38. TRAFFIC CONTROL The accompanying figure shows the flow of traffic near a city’s Civic Center during the rush hours on a typical weekday. Each road can handle a maximum of 1000 cars/hour without causing congestion. The flow of traffic is controlled by traffic lights at each of the five intersections.

3rd St.

6th Ave.

7th Ave.

700

600

500 Ci vi

x2 x1 4th St.

cD

x6

riv e

x3

600

800 x4

x5 700

700

600

a. Set up a system of linear equations describing the traffic flow. b. Solve the system devised in part (a) and suggest two possible traffic-flow patterns that will ensure no traffic congestion. c. Suppose 7th Avenue between 3rd and 4th Streets is soon to be closed for road repairs. Find one possible flow pattern that will result in a smooth flow of traffic. 39. TRAFFIC CONTROL The accompanying figure shows the flow of downtown traffic during the rush hours on a typical weekday. Each avenue can handle up to 1500 vehicles/hour without causing congestion, whereas the maximum capacity of each street is 1000 vehicles/hour. The flow of traffic is controlled by traffic lights at each of the six intersections.

5.3 SYSTEMS OF LINEAR EQUATIONS: UNDERDETERMINED AND OVERDETERMINED SYSTEMS 5th Ave. 900 7th St.

600

600 x3

x2 8th St.

41. Determine the value of k such that the following system of linear equations has infinitely many solutions, and then find the solutions: 3x  2y  4z  12

x4

700

9x  6y  12z  k

700 x7

x1 9th St.

6th Ave. 1000

x5

800

700 x6

900

273

42. Solve the system: 1 1 1    1 x y z

1100

a. Set up a system of linear equations describing the traffic flow. b. Solve the system devised in part (a) and suggest two possible traffic-flow patterns that will ensure no traffic congestion. c. Suppose the traffic flow along 9th Street between 5th and 6th Avenues, x6, is restricted because of sewer construction. What is the minimum permissible traffic flow along this road that will not result in traffic congestion? 40. Determine the value of k such that the following system of linear equations has a solution, and then find the solution:

3 2 2    x y z

3

2 1 2    7 x y z In Exercises 43 and 44, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

43. A system of linear equations having fewer equations than variables has no solution, a unique solution, or infinitely many solutions. 44. A system of linear equations having more equations than variables has no solution, a unique solution, or infinitely many solutions.

2x  3y  2 x  4y  6 5x  ky  2

5.3 Solutions to Self-Check Exercises 1. Let x, y, and z denote the variables. Then, the given rowreduced augmented matrix tells us that the system of linear equations is equivalent to the two equations

1 £0 0

2 7 7

4 4 7 † 14 § 7 14

 z

1 £0 0

2 1 7

4 4 R  2R 1 1 2 ⎯⎯⎯→ 1 † 2 § R3  7R2 £ 0 0 7 14

x

3

y  5z  2

Letting z  t, where t is a parameter, we find the infinitely many solutions given by xt3 y  5t  2 zt

2. We obtain the following sequence of equivalent augmented matrices: 2 £1 1

3 2 5

1 6 4 † 4 § 3 10

1 £2 1

2 3 5

4 4 R  2R 2 1 1 † 6 § ⎯⎯⎯→ R3  R1 3 10

R1 4 R2 ⎯⎯⎯⎯→

17 R2 ⎯⎯→

0 1 0

2 0 1 † 2 § 0 0

The last augmented matrix, which is in row-reduced form, tells us that the given system of linear equations is equivalent to the following system of two equations: x

 2z 

0

y  z  2

Letting z  t, where t is a parameter, we see that the infinitely many solutions are given by x  2t y  t  2 zt

274

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

3. We obtain the following sequence of equivalent augmented matrices: 1 £2 1

2 3 5

3 9 R  2R 2 1 1 † 4 § ⎯⎯⎯→ R3  R1 4 2

1 £0 0

2 7 7

3 9 1 R3  R2 7 † 14 § ⎯⎯→ £ 0 7 7 0

USING

TECHNOLOGY

2 7 0

Since the last row of the final augmented matrix is equivalent to the equation 0  7, a contradiction, we conclude that the given system has no solution.

3 9 7 † 14 § 0 7

Systems of Linear Equations: Underdetermined and Overdetermined Systems We can use the row operations of a graphing utility to solve a system of m linear equations in n unknowns by the Gauss–Jordan method, as we did in the previous technology section. We can also use the rref or equivalent operation to obtain the rowreduced form without going through all the steps of the Gauss–Jordan method. The SIMULT function, however, cannot be used to solve a system where the number of equations and the number of variables are not the same. EXAMPLE 1 Solve the system x1  2x2  2x1  x2  3x1  x2  2x1  6x2  Solution

4x3 2x3 2x3 12x3

 2  1  1  6

First, we enter the augmented matrix A into the calculator as 1 2 A ≥ 3 2

2 1 1 6

4 2 2 1 ∞ ¥ 2 1 12 6

Then using the rref or equivalent operation, we obtain the equivalent matrix 1 0 ≥ 0 0

0 1 0 0

0 0 2 1 ∞ ¥ 0 0 0 0

in reduced form. Thus, the given system is equivalent to x1

 0 x2  2x3  1

If we let x3  t, where t is a parameter, then we find that the solutions are (0, 2t  1, t).

5.4 MATRICES

275

TECHNOLOGY EXERCISES 4.

Use a graphing utility to solve the system of equations using the rref or equivalent operation.

1. 2 x1  x2  x3  0 3x1  2x2  x3  1 x1  2 x2  x3  3 2 x2  2x3  4

x1  x2  3x3  6x4  2 x1  x2  x3  2x4  2 2x1  x2  x3  2x4  0

5. x1  x2  x3  x4  1 x1  x2  x3  4x4  6 3x1  x2  x3  2x4  4 5x1  x2  3x3  x4  9

2. 3x1  x2  4x3  5 2 x1  3 x2  2x3  4 x1  2 x2  4x3  6 4x1  3 x2  5x3  9

6. 1.2x1  2.3x2  4.2x3  5.4x4  1.6x5  4.2 2.3x1  1.4x2  3.1x3  3.3x4  2.4x5  6.3 1.7x1  2.6x2  4.3x3  7.2x4  1.8x5  7.8 2.6x1  4.2x2  8.3x3  1.6x4  2.5x5  6.4

3. 2x1  3x2  2x3  x4  1 x1  x2  x3  2x4  8 5x1  6x2  2x3  2x4  11 x1  3x2  8x3  x4  14

5.4 Matrices Using Matrices to Represent Data Many practical problems are solved by using arithmetic operations on the data associated with the problems. By properly organizing the data into blocks of numbers, we can then carry out these arithmetic operations in an orderly and efficient manner. In particular, this systematic approach enables us to use the computer to full advantage. Let’s begin by considering how the monthly output data of a manufacturer may be organized. The Acrosonic Company manufactures four different loudspeaker systems at three separate locations. The company’s May output is described in Table 1. TABLE 1

Location I Location II Location III

Model A

Model B

Model C

Model D

320 480 540

280 360 420

460 580 200

280 0 880

Now, if we agree to preserve the relative location of each entry in Table 1, we can summarize the set of data as follows: 320 £ 480 540

280 360 420

460 580 200

280 0§ 880

A matrix summarizing the data in Table 1

The array of numbers displayed here is an example of a matrix. Observe that the numbers in row 1 give the output of models A, B, C, and D of Acrosonic loudspeaker systems manufactured at location I; similarly, the numbers in rows 2 and 3 give the respective outputs of these loudspeaker systems at locations II and III. The numbers in each column of the matrix give the outputs of a particular model of loudspeaker system manufactured at each of the company’s three manufacturing locations.

276

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

More generally, a matrix is a rectangular array of real numbers. For example, each of the following arrays is a matrix: 3 A c 2

0 1

1 d 4

3 B £ 0 1

1 2 C ≥ ¥ 4 0

2 1§ 4

D  31 3

0

14

The real numbers that make up the array are called the entries, or elements, of the matrix. The entries in a row in the array are referred to as a row of the matrix, whereas the entries in a column in the array are referred to as a column of the matrix. Matrix A, for example, has two rows and three columns, which may be identified as follows: Column 1 Row 1 Row 2



Column 2

3 2

0 1

Column 3

1 4



A 2  3 matrix

The size, or dimension, of a matrix is described in terms of the number of rows and columns of the matrix. For example, matrix A has two rows and three columns and is said to have size 2 by 3, denoted 2  3. In general, a matrix having m rows and n columns is said to have size m  n. Matrix

A matrix is an ordered rectangular array of numbers. A matrix with m rows and n columns has size m  n. The entry in the ith row and j th column of a matrix A is denoted by aij. A matrix of size 1  n—a matrix having one row and n columns—is referred to as a row matrix, or row vector, of dimension n. For example, the matrix D is a row vector of dimension 4. Similarly, a matrix having m rows and one column is referred to as a column matrix, or column vector, of dimension m. The matrix C is a column vector of dimension 4. Finally, an n  n matrix—that is, a matrix having the same number of rows as columns—is called a square matrix. For example, the matrix 3 £ 2 1

8 1 4

3

6 4§ 2

A 3  3 square matrix

is a square matrix of size 3  3, or simply of size 3. APPLIED EXAMPLE 1 Organizing Production Data Consider the matrix 320 280 460 280 P  £ 480 360 580 0§ 540 420 200 880 representing the output of loudspeaker systems of the Acrosonic Company discussed earlier (see Table 1). a. What is the size of the matrix P? b. Find p24 (the entry in row 2 and column 4 of the matrix P) and give an interpretation of this number.

5.4 MATRICES

277

c. Find the sum of the entries that make up row 1 of P and interpret the result. d. Find the sum of the entries that make up column 4 of P and interpret the result. Solution

a. The matrix P has three rows and four columns and hence has size 3  4. b. The required entry lies in row 2 and column 4, and is the number 0. This means that no model D loudspeaker system was manufactured at location II in May. c. The required sum is given by 320  280  460  280  1340

which gives the total number of loudspeaker systems manufactured at location I in May as 1340 units. d. The required sum is given by 280  0  880  1160

giving the output of model D loudspeaker systems at all locations of the company in May as 1160 units.

Equality of Matrices Two matrices are said to be equal if they have the same size and their corresponding entries are equal. For example, c

2 4

3 6

1 13  12 d  c 4 2

3 14  22

1 d 2

Also, 1 c 2

3 4

1 5 d  £3 3 5

2 4§ 3

since the matrix on the left has size 2  3 whereas the matrix on the right has size 3  2, and c

2 4

3 2 d  c 6 4

3 d 7

since the corresponding elements in row 2 and column 2 of the two matrices are not equal.

Equality of Matrices

Two matrices are equal if they have the same size and their corresponding entries are equal.

EXAMPLE 2 Solve the following matrix equation for x, y, and z: c

1 2

x y1

3 1 d  c 2 2

4 1

z d 2

Solution Since the corresponding elements of the two matrices must be equal, we find that x  4, z  3, and y  1  1, or y  2.

278

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Addition and Subtraction Two matrices A and B of the same size can be added or subtracted to produce a matrix of the same size. This is done by adding or subtracting the corresponding entries in the two matrices. For example, c

1 1

4 1 d  c 0 6

3 2

3 11 d  c 2 1  6

4 1

34 21

43 2 d  c 0  12 2 5

7 d 2

7 3

Adding two matrices of the same size

1 £ 1 4

and

2 2 3§  £ 3 0 1

2  112 1 3  2 §  £ 4 00 5

1 12 2 §  £ 1  3 0 4  11 2

3 1§ 0

Subtracting two matrices of the same size

Addition and Subtraction of Matrices

If A and B are two matrices of the same size, then: 1. The sum A  B is the matrix obtained by adding the corresponding entries in the two matrices. 2. The difference A  B is the matrix obtained by subtracting the corresponding entries in B from those in A.

APPLIED EXAMPLE 3 Organizing Production Data The total output of Acrosonic for June is shown in Table 2.

TABLE 2

Location I Location II Location III

Model A

Model B

Model C

Model D

210 400 420

180 300 280

330 450 180

180 40 740

The output for May was given earlier in Table 1. Find the total output of the company for May and June. Solution

As we saw earlier, the production matrix for Acrosonic in May is

given by 320 A  £ 480 540

280 360 420

460 580 200

280 0§ 880

Next, from Table 2, we see that the production matrix for June is given by 210 B  £ 400 420

180 300 280

330 450 180

180 40 § 740

5.4 MATRICES

279

Finally, the total output of Acrosonic for May and June is given by the matrix 320 A  B  £ 480 540

280 360 420

460 580 200

530  £ 880 960

460 660 700

790 1030 380

280 210 0 §  £ 400 880 420

180 300 280

330 450 180

180 40 § 740

460 40 § 1620

The following laws hold for matrix addition.

Laws for Matrix Addition

If A, B, and C are matrices of the same size, then 1. A  B  B  A 2. (A  B)  C  A  (B  C)

Commutative law Associative law

The commutative law for matrix addition states that the order in which matrix addition is performed is immaterial. The associative law states that, when adding three matrices together, we may first add A and B and then add the resulting sum to C. Equivalently, we can add A to the sum of B and C. A zero matrix is one in which all entries are zero. A zero matrix O has the property that AOOAA

for any matrix A having the same size as that of O. For example, the zero matrix of size 3  2 is 0 O  £0 0

0 0§ 0

If A is any 3  2 matrix, then a11 A  O  £ a21 a31

a12 0 a22 §  £ 0 a32 0

0 a11 0 §  £ a21 0 a31

a12 a22 §  A a32

where aij denotes the entry in the ith row and jth column of the matrix A. The matrix obtained by interchanging the rows and columns of a given matrix A is called the transpose of A and is denoted AT. For example, if 1 A  £4 7

2 5 8

3 6§ 9

1 AT  £ 2 3

4 5 6

7 8§ 9

then

280

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Transpose of a Matrix

If A is an m  n matrix with elements aij, then the transpose of A is the n  m matrix AT with elements aji.

Scalar Multiplication A matrix A may be multiplied by a real number, called a scalar in the context of matrix algebra. The scalar product, denoted by cA, is a matrix obtained by multiplying each entry of A by c. For example, the scalar product of the matrix A c

3 0

1 1

2 d 4

and the scalar 3 is the matrix 3A  3 c

3 0

1 1

2 9 d  c 4 0

3 3

6 d 12

Scalar Product

If A is a matrix and c is a real number, then the scalar product cA is the matrix obtained by multiplying each entry of A by c.

EXAMPLE 4 Given A c

3 1

4 d 2

and

B c

3 1

2 d 2

find the matrix X satisfying the matrix equation 2 X  B  3A. Solution

From the given equation 2 X  B  3A, we find that 2X  3A  B 3 4 3  3c d  c 1 2 1 9 12 3  c d  c 3 6 1 1 6 10 3 X c d  c 2 2 4 1

2 d 2 2 6 d  c 2 2 5 d 2

10 d 4

APPLIED EXAMPLE 5 Production Planning The management of Acrosonic has decided to increase its July production of loudspeaker systems by 10% (over its June output). Find a matrix giving the targeted production for July. Solution From the results of Example 3, we see that Acrosonic’s total output for June may be represented by the matrix

210 B  £ 400 420

180 300 280

330 450 180

180 40 § 740

5.4 MATRICES

281

The required matrix is given by 210 11.12B  1.1 £ 400 420 231  £ 440 462

180 300 280

198 330 308

330 450 180

363 495 198

180 40 § 740

198 44 § 814

and is interpreted in the usual manner.

5.4 Self-Check Exercises 1. Perform the indicated operations: c

1 1

3 4

2 2 d  3c 7 1

and 0 d 4

1 3

2. Solve the following matrix equation for x, y, and z: c

3 2y d  c 2 2z

x z

z 3 d  c x 2

7 d 0

Downtown Wilshire

Regular

Regular plus

Premium

1200

750

650

850

600

 1100

Downtown Wilshire

Regular plus

Premium

1250

825

550

750

750

 1150



Find a matrix representing the total sales of the two gas stations over the 2-day period.

3. Jack owns two gas stations, one downtown and the other in the Wilshire district. Over 2 consecutive days his gas stations recorded gasoline sales represented by the following matrices:

A

B

Regular

Solutions to Self-Check Exercises 5.4 can be found on page 284.



5.4 Concept Questions 1. Define (a) a matrix, (b) the size of a matrix, (c) a row matrix, (d) a column matrix, and (e) a square matrix.

3. Construct a 3  3 matrix A having the property that A  AT. What special characteristic does A have?

2. When are two matrices equal? Give an example of two matrices that are equal.

5.4 Exercises In Exercises 1–6, refer to the following matrices: 2 11 A ≥ 6 5 3 0 B ≥ 3 1

3 2 0 1 1 1 2 0

9 6 2 5 2 4 ¥ 1 8

4 7 ¥ 9 8

C  31

0

3

4

54

1 3 D ≥ ¥ 2 0

1. What is the size of A? Of B? Of C? Of D? 2. Find a14, a21, a31, and a43. 3. Find b13, b31, and b43. 4. Identify the row matrix. What is its transpose?

282

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

5. Identify the column matrix. What is its transpose?

In Exercises 21–24, solve for u, x, y, and z in the given matrix equation.

6. Identify the square matrix. What is its transpose? In Exercises 7–12, refer to the following matrices: 1 A £ 3 4

2 2 § 0 1 2 6

3 C  £2 4

0 3§ 2

2 B £ 3 2

4 1§ 2

2 D £ 3 2

2 6 3

4 2§ 1

21. £

2x  2 2 2z

22. c

x 3

2 2 d  c y 1

23. c

1 2y

x 2 d  4c 3 0

1 24. £ 3 x

7. What is the size of A? Of B? Of C? Of D? 8. Explain why the matrix A  C does not exist. 9. Compute A  B.

10. Compute 2A  3B.

11. Compute C  D.

12. Compute 4D  2C.

3 4 3

8 3 d  c 6 0

2 5

6 4

3 5

14. c

2 3

3 1

4 0

1 15. c 3

4 8

5 4 d  c 6 3

3 2

2 0

1 16. 3 £ 3 7

1 2 1

3 2 3§  4£ 4 6 3

1 2 6

17. c

4.5 6.3

4.2 3.1 d  c 3.2 2.2

1.5 3.3

1.2 8.2

0.06 18. £ 0.43 1.55 1 1 19. £ 3 2 2

0.12 0.77 1.11 §  £ 0.22 0.43 1.09 0 0 1

3 1  £6 3 0 1 20. 0.5 £ 5 2

3 2 0

3  0.6 £ 4 1

0 1 4 9 2 1

1 0 3

1 1§ 0

9 d 5

1 6 0

0 6 § 1 3 1 5

2 3z d  c 3 4

A c

2 4

4 2

3 d 1

C c

1 3

0 2

2 d 1

10 d u

2 4 2 §  2£ 0 2z  1 4

u 1 § 4

B c

4 1

3 0

2 d 4

26. Verify by direct computation the validity of the associative law for matrix addition.

3 A £ 2 4

3.6 d 4.4

0 1 2

2 d 4

In Exercises 27–30, let

4 4 § 5

1 4§ 0

and

1 B  £ 1 3

2 0§ 2

Verify each equation by direct computation.

0.75 0.65 § 0.57

5 2 1 §  0.2 £ 1 1 3 4 5 0

8 2

8 2§ 3

4 3 4 6 §  £ 2 3 2 8

2 5§ 2

25. Verify by direct computation the validity of the commutative law for matrix addition.

4 d 3

2 2 d  c 5 11

0 6

u 4 3

In Exercises 25 and 26, let

1 d 7

1 4 d  c 6 0

z 4 d  c 2 2u

2 y1 4§  3£ 1 1 4

In Exercises 13–20, perform the indicated operations.

13. c

2 3 y  2§  £2 2 4

4 2§ 2

27. (3  5)A  3A  5A

28. 2(4A)  (2  4)A  8A

29. 4(A  B)  4A  4B

30. 2(A  3B)  2A  6B

In Exercises 31–34, find the transpose of each matrix.

31. 3 3

2

1 33. £ 3 0

1 4 1

1

2 2§ 0

54

32. c

4 3

2 4

0 1

1 2 34. ≥ 6 4

2 3 2 5

6 2 3 0

1 d 5 4 5 ¥ 0 2

35. CHOLESTEROL LEVELS Mr. Cross, Mr. Jones, and Mr. Smith each suffer from coronary heart disease. As part of their treatment, they were put on special low-cholesterol diets: Cross on diet I, Jones on diet II, and Smith on diet III. Progressive records of each patient’s cholesterol level were kept. At the beginning of the first, second, third, and fourth months, the cholesterol levels of the three patients were:

283

5.4 MATRICES

Cross: 220, 215, 210, and 205 Jones: 220, 210, 200, and 195 Smith: 215, 205, 195, and 190

What was the percentage increase in the prices of the houses? Hint: Find r such that (1  0.01r)A  B.

Represent this information in a 3  4 matrix. 36. INVESTMENT PORTFOLIOS The following table gives the number of shares of certain corporations held by Leslie and Tom in their respective IRA accounts at the beginning of the year:

Leslie Tom

IBM 500 400

GE 350 450

Ford 200 300

Wal-Mart 400 200

Over the year, they added more shares to their accounts, as shown in the following table:

Leslie Tom

IBM 50 0

GE 50 80

Ford 0 100

Wal-Mart 100 50

a. Write a matrix A giving the holdings of Leslie and Tom at the beginning of the year and a matrix B giving the shares they have added to their portfolios. b. Find a matrix C giving their total holdings at the end of the year. 37. HOME SALES K & R Builders build three models of houses, M1, M2, and M3, in three subdivisions I, II, and III located in three different areas of a city. The prices of the houses (in thousands of dollars) are given in matrix A:



I

A  II III

M1

M2

M3

340

360

380

410

430

440

620

660

700

38. HOME SALES K & R Builders build three models of houses, M1, M2, and M3, in three subdivisions I, II, and III located in three different areas of a city. The prices of the homes (in thousands of dollars) are given in matrix A:



I

A  II III

M3

340

360

380

410

430

440

620

660

700



The new price schedule for next year, reflecting a uniform percentage increase in each house, is given by matrix B:

I

B  II III



M1

M2

Main office

A  Westside branch Eastside branch



2820 1030 1170

Savings accounts

Fixeddeposit accounts

1470 520 540

1120 480 460



The number and types of accounts opened during the first quarter are represented by matrix B, and the number and types of accounts closed during the same period are represented by matrix C. Thus, 260 B  £ 140 120

120 60 70

110 50 § 50

and

120 C  £ 70 60

80 30 20

80 40 § 40

a. Find matrix D, which represents the number of each type of account at the end of the first quarter at each location. b. Because a new manufacturing plant is opening in the immediate area, it is anticipated that there will be a 10% increase in the number of accounts at each location during the second quarter. Write a matrix E  1.1 D to reflect this anticipated increase.

Hardcover: textbooks, 5280; fiction, 1680; nonfiction, 2320; reference, 1890

K & R Builders has decided to raise the price of each house by 3% next year. Write a matrix B giving the new prices of the houses.

M2

Checking accounts

40. BOOKSTORE INVENTORIES The Campus Bookstore’s inventory of books is



M1

39. BANKING The numbers of three types of bank accounts on January 1 at the Central Bank and its branches are represented by matrix A:

M3



357

378

399

430.5

451.5

462

651

693

735

Paperback: fiction, 2810; nonfiction, 1490; reference, 2070; textbooks, 1940 The College Bookstore’s inventory of books is Hardcover: textbooks, 6340; fiction, 2220; nonfiction, 1790; reference, 1980 Paperback: fiction, 3100; nonfiction, 1720; reference, 2710; textbooks, 2050 a. Represent Campus’s inventory as a matrix A. b. Represent College’s inventory as a matrix B. c. The two companies decide to merge, so now write a matrix C that represents the total inventory of the newly amalgamated company. 41. INSURANCE CLAIMS The property damage claim frequencies per 100 cars in Massachusetts in the years 2000, 2001, and 2002 are 6.88, 7.05, and 7.18, respectively. The corresponding claim frequencies in the United States are 4.13, 4.09, and 4.06, respectively. Express this information using a 2  3 matrix. Sources: Registry of Motor Vehicles; Federal Highway Administration

284

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

42. MORTALITY RATES Mortality actuarial tables in the United States were revised in 2001, the fourth time since 1858. Based on the new life insurance mortality rates, 1% of 60-yr-old men, 2.6% of 70-yr-old men, 7% of 80-yr-old men, 18.8% of 90-yr-old men, and 36.3% of 100-yr-old men would die within a year. The corresponding rates for women are 0.8%, 1.8%, 4.4%, 12.2%, and 27.6%, respectively. Express this information using a 2  5 matrix. Source: Society of Actuaries

43. LIFE EXPECTANCY Figures for life expectancy at birth of Massachusetts residents in 2002 are 81.0, 76.1, and 82.2 yr for white, black, and Hispanic women, respectively, and 76.0, 69.9, and 75.9 years for white, black, and Hispanic men, respectively. Express this information using a 2  3 matrix and a 3  2 matrix. Source: Massachusetts Department of Public Health

44. MARKET SHARE OF MOTORCYCLES The market share of motorcycles in the United States in 2001 follows: Honda 27.9%, Harley-Davidson 21.9%, Yamaha 19.2%, Suzuki 11.0%, Kawasaki 9.1%, and others 10.9%. The corre-

sponding figures for 2002 are 27.6%, 23.3%, 18.2%, 10.5%, 8.8%, and 11.6%, respectively. Express this information using a 2  6 matrix. What is the sum of all the elements in the first row? In the second row? Is this expected? Which company gained the most market share between 2001 and 2002? Source: Motorcycle Industry Council

In Exercises 45–48, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

45. If A and B are matrices of the same size and c is a scalar, then c(A  B)  cA  cB. 46. If A and B are matrices of the same size, then A  B  A  (1)B. 47. If A is a matrix and c is a nonzero scalar, then (cA)T  (1/c)AT. 48. If A is a matrix, then (AT )T  A.

5.4 Solutions to Self-Check Exercises 1. c

1 1

3 4

2 2 d  3c 7 1

1 3

0 1 d  c 4 1 5  c 4

2 6 d  c 7 3 0 2 d 5 5 3 4

3 9

0 d 12

By the equality of matrices, we have 2xy3 3z7 2x0

2. We are given 3 2y d  c 2 2z

x c z

z 3 d  c x 2

from which we deduce that x  2, y  1, and z  4.

7 d 0

3. The required matrix is

Performing the indicated operation on the left-hand side, we obtain c

2xy 2

USING

3z 3 d  c 2x 2

TECHNOLOGY

7 d 0

AB c

1200 1100

750 850

 c

2450 2250

1575 1600

650 1250 d  c 600 1150

825 750

550 d 750

1200 d 1350

Matrix Operations Graphing Utility

A graphing utility can be used to perform matrix addition, matrix subtraction, and scalar multiplication. It can also be used to find the transpose of a matrix. EXAMPLE 1 Let 1.2 A  £ 2.1 3.1

3.1 4.2 § 4.8

4.1 and B  £ 1.3 1.7

Find (a) A  B, (b) 2.1A  3.2B, and (c) (2.1A  3.2B)T.

3.2 6.4 § 0.8

285

5.4 MATRICES

Solution

We first enter the matrices A and B into the calculator.

a. Using matrix operations, we enter the expression A  B and obtain 5.3 A  B  £ 0.8 4.8

6.3 10.6 § 5.6

b. Using matrix operations, we enter the expression 2.1A  3.2B and obtain 10.6 2.1A  3.2B  £ 8.57 1.07

3.73 11.66 § 7.52

c. Using matrix operations, we enter the expression (2.1A  3.2B)T and obtain 12.1A  3.2B2 T  c

15.64 16.75

0.25 29.3

11.95 d 12.64

APPLIED EXAMPLE 2 John operates three gas stations at three locations, I, II, and III. Over 2 consecutive days, his gas stations recorded the following fuel sales (in gallons): Regular Location I Location II Location III

1400 1600 1200 Regular

Location I Location II Location III

1000 1800 800

Day 1 Regular Plus Premium

1200 900 1500

1100 1200 800

Day 2 Regular Plus Premium

900 1200 1000

800 1100 700

Diesel

200 300 500 Diesel

150 250 400

Find a matrix representing the total fuel sales at John’s gas stations. Solution

The fuel sales can be represented by the matrix A (day 1) and matrix

B (day 2): 1400 A  £ 1600 1200

1200 900 1500

1100 1200 800

200 300 § 500

and

1000 B  £ 1800 800

900 1200 1000

800 1100 700

150 250 § 400

We enter the matrices A and B into the calculator. Using matrix operations, we enter the expression A  B and obtain 2400 A  B  £ 3400 2000

2100 2100 2500

1900 2300 1500

350 550 § 900

Excel

First, we show how basic operations on matrices can be carried out using Excel. EXAMPLE 3 Given the following matrices, 1.2 A  £ 2.1 3.1

a. Compute A  B.

3.1 4.2 § 4.8

4.1 and B  £ 1.3 1.7

b. Compute 2.1A  3.2B.

3.2 6.4 § 0.8 (continued)

286

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Solution

a. First, represent the matrices A and B in a spreadsheet. Enter the elements of each matrix in a block of cells as shown in Figure T1. A FIGURE T1 The elements of matrix A and matrix B in a spreadsheet

1 2 3 4

B A

1.2 −2.1 3.1

C

D

3.1 4.2 4.8

E B 4.1 1.3 1.7

3.2 6.4 0.8

Second, compute the sum of matrix A and matrix B. Highlight the cells that will contain matrix A  B, type =, highlight the cells in matrix A, type +, highlight the cells in matrix B, and press Ctrl-Shift-Enter . The resulting matrix A  B is shown in Figure T2. A

FIGURE T2

The matrix A  B

8 9 10 11

B A+B 5.3 −0.8 4.8

6.3 10.6 5.6

b. Highlight the cells that will contain matrix 2.1A  3.2B. Type  2.1*, highlight matrix A, type 3.2*, highlight the cells in matrix B, and press Ctrl-Shift-Enter . The resulting matrix 2.1A  3.2B is shown in Figure T3. A

FIGURE T3

The matrix 2.1A  3.2B

B 2.1A - 3.2B

13 14

−10.6

−3.73

15

−8.57

−11.66

16

1.07

7.52

APPLIED EXAMPLE 4 John operates three gas stations at three locations I, II, and III. Over 2 consecutive days, his gas stations recorded the following fuel sales (in gallons): Regular

1400 1600 1200

Location I Location II Location III

Regular

1000 1800 800

Location I Location II Location III

Day 1 Regular Plus Premium

1200 900 1500

1100 1200 800

Day 2 Regular Plus Premium

900 1200 1000

800 1100 700

Diesel

200 300 500 Diesel

150 250 400

Find a matrix representing the total fuel sales at John’s gas stations. Solution

The fuel sales can be represented by the matrices A (day 1) and B

(day 2): 1400 A  £ 1600 1200

1200 900 1500

1100 1200 800

200 300 § 500

and

1000 B  £ 1800 800

900 1200 1000

800 1100 700

150 250 § 400

Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

5.5 MULTIPLICATION OF MATRICES

287

We first enter the elements of the matrices A and B onto a spreadsheet. Next, we highlight the cells that will contain the matrix A  B, type =, highlight A, type +, highlight B, and then press Ctrl-Shift-Enter . The resulting matrix A  B is shown in Figure T4. A 23 24 25 26

FIGURE T4

The matrix A  B

2400 3400 2000

B A+B 2100 2100 2500

C

D 1900 2300 1500

350 550 900

TECHNOLOGY EXERCISES Refer to the following matrices and perform the indicated operations. 1.2 A  £ 4.1 1.7

3.1 3.2 2.8

6.2 B  £ 3.1 1.2

3.2 2.7 1.4

5.4 4.2 5.2

2.7 3.1 § 8.4

1.4 1.2 1.7

1. 12.5A

2. 8.4B

3. A  B

4. B  A

5. 1.3A  2.4B

6. 2.1A  1.7B

7. 3(A  B)

8. 1.3(4.1A  2.3B)

1.2 1.7 § 2.8

5.5 Multiplication of Matrices Matrix Product In Section 5.4, we saw how matrices of the same size may be added or subtracted and how a matrix may be multiplied by a scalar (real number), an operation referred to as scalar multiplication. In this section we see how, with certain restrictions, one matrix may be multiplied by another matrix. To define matrix multiplication, let’s consider the following problem. On a certain day, Al’s Service Station sold 1600 gallons of regular, 1000 gallons of regular plus, and 800 gallons of premium gasoline. If the price of gasoline on this day was $3.09 for regular, $3.29 for regular plus, and $3.45 for premium gasoline, find the total revenue realized by Al’s for that day. The day’s sale of gasoline may be represented by the matrix A  31600

1000

8004

Row matrix (1  3)

Next, we let the unit selling price of regular, regular plus, and premium gasoline be the entries in the matrix 3.09 B  £ 3.29 § 3.45

Column matrix (3  1)

The first entry in matrix A gives the number of gallons of regular gasoline sold, and the first entry in matrix B gives the selling price for each gallon of regular gasoline, so their product (1600)(3.09) gives the revenue realized from the sale of regular gaso-

288

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

line for the day. A similar interpretation of the second and third entries in the two matrices suggests that we multiply the corresponding entries to obtain the respective revenues realized from the sale of regular, regular plus, and premium gasoline. Finally, the total revenue realized by Al’s from the sale of gasoline is given by adding these products to obtain (1600)(3.09)  (1000)(3.29)  (800)(3.45)  10,994

or $10,994. This example suggests that if we have a row matrix of size 1  n, A  3a1

a2

p an 4

a3

and a column matrix of size n  1, b1 b2 B  Eb3U o bn

then we may define the matrix product of A and B, written AB, by b1 b2 p an 4 Eb3U  a1b1  a2b2  a3b3  p  anbn AB  3a1 a2 a3 o bn

(11)

EXAMPLE 1 Let A  31 2 3

54

and

2 3 B ≥ ¥ 0 1

Then AB  3 1

2

3

2 3 54 ≥ ¥  112 122  12 2 132  13 2 102  152 11 2  9 0 1

APPLIED EXAMPLE 2 Stock Transactions Judy’s stock holdings are given by the matrix GM

IBM

BAC

A  ”700

400

200’

At the close of trading on a certain day, the prices (in dollars per share) of these stocks are GM

B  IBM BAC

  50 120 42

What is the total value of Judy’s holdings as of that day?

5.5 MULTIPLICATION OF MATRICES

Solution

289

Judy’s holdings are worth

AB  3700

50 2004 £ 120 §  17002 1502  1400 2 1120 2  12002 1422 42

400

or $91,400. Returning once again to the matrix product AB in Equation (11), observe that the number of columns of the row matrix A is equal to the number of rows of the column matrix B. Observe further that the product matrix AB has size 1  1 (a real number may be thought of as a 1  1 matrix). Schematically, Size of A

Size of B

1n

n1

앖——————— (1  1) ——————— 앖 Size of AB

More generally, if A is a matrix of size m  n and B is a matrix of size n  p (the number of columns of A equals the numbers of rows of B), then the matrix product of A and B, AB, is defined and is a matrix of size m  p. Schematically, Size of A

Size of B

mn

np

앖——————— (m  p) ——————— 앖 Size of AB

Next, let’s illustrate the mechanics of matrix multiplication by computing the product of a 2  3 matrix A and a 3  4 matrix B. Suppose A c

a11 a21

a12 a22

a13 d a23

b11 B  £ b21 b31

b12 b22 b32

b13 b23 b33

b14 b24 § b34

From the schematic —— —— Same —— —— 앗 앗 Size of A

23

34

앖————— (2  4) —————앖 Size of AB

Size of B

we see that the matrix product C  AB is defined (since the number of columns of A equals the number of rows of B) and has size 2  4. Thus, C c

c11 c21

c12 c22

c13 c23

c14 d c24

The entries of C are computed as follows: The entry c11 (the entry in the first row, first column of C) is the product of the row matrix composed of the entries from the first row of A and the column matrix composed of the first column of B. Thus, c11  3a11

a12

b11 a13 4 £ b21 §  a11b11  a12b21  a13b31 b31

290

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

The entry c12 (the entry in the first row, second column of C) is the product of the row matrix composed of the first row of A and the column matrix composed of the second column of B. Thus, c12  3a11

b12 a13 4 £ b22 §  a11b12  a12b22  a13b32 b32

a12

The other entries in C are computed in a similar manner. EXAMPLE 3 Let A c

3 1

1 2

4 d 3

and

1 B  £4 2

3 1 4

3 2§ 1

Compute AB. The size of matrix A is 2  3, and the size of matrix B is 3  3. Since the number of columns of matrix A is equal to the number of rows of matrix B, the matrix product C  AB is defined. Furthermore, the size of matrix C is 2  3. Thus,

Solution

c

3 1

1 2

1 4 d £4 3 2

3 1 4

3 c 2 §  c 11 c21 1

c12 c22

c13 d c23

It remains now to determine the entries c11, c12, c13, c21, c22, and c23. We have 1

1 44 £ 4 §  132 112  112 142  142 12 2  15 2

c12  33

1

3 44 £ 1 §  132 132  112 112  142 14 2  24 4

c13  33

1

3 44 £ 2 §  132 132  112 122  142 11 2  3 1

c11  33

c21  31

2

1 34 £ 4 §  112 112  122 142  132 12 2  13 2

c22  31

2

3 34 £ 1 §  112 132  122 112  132 142  7 4

2

3 34 £ 2 §  112 132  122 122  13 2 11 2  10 1

c23  31

so the required product AB is given by AB  c

15 13

24 7

3 d 10

5.5 MULTIPLICATION OF MATRICES

291

EXAMPLE 4 Let 3 A  £ 1 3

2 2 1

1 3§ 4

1 B £ 2 1

and

3 4 2

4 1§ 3

Then 3 1  2 2  1 112 AB  £ 11 2 1  2 2  3 112 3 1  1 2  4 112 6  £0 1

19 11 21

12 13 5

3 4 2 11 3 112 4  2 1  3 3 § 3 4 1 14 3

1 2 3 24 1 2 2 4 21 1 11 2 2  2 2  3 1

1 1 3 34 4 2 1  4 3  1 4§ 112 1  2 3  3 4

17 7§ 25

1 3  3 112  4 3 BA  £ 2 3  4 112  1 3 112 3  2 112  3 3 12  £ 5 4

3 3 2 41 2 112 3  2 4  3 2 3 3 1 44 2

26 18 § 17

The preceding example shows that, in general, AB  BA for two square matrices A and B. However, the following laws are valid for matrix multiplication.

Laws for Matrix Multiplication

If the products and sums are defined for the matrices A, B, and C, then 1. (AB)C  A(BC) 2. A(B  C)  AB  AC

Associative law Distributive law

The square matrix of size n having 1s along the main diagonal and 0s elsewhere is called the identity matrix of size n.

Identity Matrix

The identity matrix of size n is given by 1 0 In  F 0

0 1 0







0 0 V 1

n rows

n columns

The identity matrix has the properties that In A  A for every n  r matrix A and BIn  B for every s  n matrix B. In particular, if A is a square matrix of size n, then In A  AIn  A

292

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

EXAMPLE 5 Let 1 A  £ 4 1

3 3 0

1 2§ 1

Then 1 I3 A  £ 0 0

0 1 0

1 AI3  £ 4 1

0 1 0 § £ 4 1 1

3 3 0

1 1 2 §  £ 4 1 1

3 3 0

1 2§  A 1

1 1 2§ £0 1 0

0 1 0

0 1 0 §  £ 4 1 1

3 3 0

1 2§  A 1

3 3 0

so I3 A  AI3  A, confirming our result for this special case. APPLIED EXAMPLE 6 Production Planning Ace Novelty received an order from Magic World Amusement Park for 900 “Giant Pandas,” 1200 “Saint Bernards,” and 2000 “Big Birds.” Ace’s management decided that 500 Giant Pandas, 800 Saint Bernards, and 1300 Big Birds could be manufactured in their Los Angeles plant, and the balance of the order could be filled by their Seattle plant. Each Panda requires 1.5 square yards of plush, 30 cubic feet of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 square yards of plush, 35 cubic feet of stuffing, and 8 pieces of trim; and each Big Bird requires 2.5 square yards of plush, 25 cubic feet of stuffing, and 15 pieces of trim. The plush costs $4.50 per square yard, the stuffing costs 10 cents per cubic foot, and the trim costs 25 cents per unit. a. Find how much of each type of material must be purchased for each plant. b. What is the total cost of materials incurred by each plant and the total cost of materials incurred by Ace Novelty in filling the order? Solution The quantities of each type of stuffed animal to be produced at each plant location may be expressed as a 2  3 production matrix P. Thus, Pandas

P

c

L.A. Seattle

St. Bernards

500 400

800 400

Birds

1300 d 700

Similarly, we may represent the amount and type of material required to manufacture each type of animal by a 3  3 activity matrix A. Thus, Plush Pandas

A  St. Bernards Birds

1.5 £2 2.5

Stuffing

30 35 25

Trim

5 8§ 15

Finally, the unit cost for each type of material may be represented by the 3  1 cost matrix C. Plush

C  Stuffing Trim

4.50 £ 0.10 § 0.25

a. The amount of each type of material required for each plant is given by the matrix PA. Thus,

5.5 MULTIPLICATION OF MATRICES

PA  c



500 400

1.5 1300 d £2 700 2.5

30 35 25

Plush

Stuffing

Trim

5600 3150

75,500 43,500

28,400 d 15,700

800 400

c

L.A. Seattle

293

5 8§ 15

b. The total cost of materials for each plant is given by the matrix PAC: 5600 PAC  c 3150 

L.A. Seattle

75,500 43,500 c

4.50 28,400 d £ 0.10 § 15,700 0.25

39,850 d 22,450

or $39,850 for the L.A. plant and $22,450 for the Seattle plant. Thus, the total cost of materials incurred by Ace Novelty is $62,300.

Matrix Representation Example 7 shows how a system of linear equations may be written in a compact form with the help of matrices. (We will use this matrix equation representation in Section 5.6.) EXAMPLE 7 Write the following system of linear equations in matrix form. 2x  4y  z  6 3x  6y  5z  1 x  3y  7z  0 Solution

Let’s write 2 A  £ 3 1

4 6 3

1 5 § 7

x X  £y§ z

6 B  £ 1 § 0

Note that A is just the 3  3 matrix of coefficients of the system, X is the 3  1 column matrix of unknowns (variables), and B is the 3  1 column matrix of constants. We now show that the required matrix representation of the system of linear equations is AX  B To see this, observe that 2 AX  £ 3 1

4 6 3

1 x 2x  4y  z 5 § £ y §  £ 3x  6y  5z § 7 z x  3y  7z

Equating this 3  1 matrix with matrix B now gives 2x  4y  z 6 £ 3x  6y  5z §  £ 1 § x  3y  7z 0

which, by matrix equality, is easily seen to be equivalent to the given system of linear equations.

294

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

5.5 Self-Check Exercises 1. Compute

3. On June 1, the stock holdings of Ash and Joan Robinson were given by the matrix c

1 2

3 0 d £2 1 1

3 4

1 0 2

4 3§ 1

A

2. Write the following system of linear equations in matrix form: y  2z  1 2x  y  3z  0 x

 4z  7

Ash Joan

AT&T

TWX

IBM

GM

c

1000 2500

500 2000

5000 d 0

2000 1000

and the closing prices of AT&T, TWX, IBM, and GM were $54, $113, $112, and $70 per share, respectively. Use matrix multiplication to determine the separate values of Ash’s and Joan’s stock holdings as of that date. Solutions to Self-Check Exercises 5.5 can be found on page 298.

5.5 Concept Questions 1. What is the difference between scalar multiplication and matrix multiplication? Give examples of each operation. 2. a. Suppose A and B are matrices whose products AB and BA are both defined. What can you say about the sizes of A and B?

b. If A, B, and C are matrices such that A(B  C) is defined, what can you say about the relationship between the number of columns of A and the number of rows of C? Explain.

5.5 Exercises In Exercises 1– 4, the sizes of matrices A and B are given. Find the size of AB and BA whenever they are defined.

1. A is of size 2  3, and B is of size 3  5.

15. c

2. A is of size 3  4, and B is of size 4  3. 3. A is of size 1  7, and B is of size 7  1. 4. A is of size 4  4, and B is of size 4  4. 5. Let A be a matrix of size m  n and B be a matrix of size s  t. Find conditions on m, n, s, and t such that both matrix products AB and BA are defined. 6. Find condition(s) on the size of a matrix A such that A2 (that is, AA) is defined. In Exercises 7–24, compute the indicated products.

7. c

1 3

3 9. c 1 11. c

1 3

2 1 dc d 0 1 1 2

8. c

4 2 d £ 1§ 4 2

2 2 dc 1 3

4 d 1

1 5

3 7 dc d 0 2

3 10. £ 4 5

2 1 2

12. c

3 1 dc 2 3

1 1

2 13. c 3

1 3 0 § £ 2 § 1 0 3 0

0 d 2

1 2

1 2 d£ 4 4 0 0.9 1.2 dc 0.8 0.5

0.1 0.2

6 17. £ 2 4

3 1 4

2 18. £ 1 3

4 2 5 § c 1 1

3 19. c 1

2 20. £ 4 1 1 21. 4 £ 2 3

0 2

2 0

1 2 2 2 1 0

1 14. £ 4 0

2 3§ 1

0.4 1.2 d 16. c 2.1 0.4

0 1 8 § £ 0 9 0 2 3

0 1 0

2 0 1 1§ ≥ 3 1 0

0 1 1§ £1 1 0

0 0§ 1

3 4 1

1 2 0 2 1 4 ¥ 3 5 1 0§ 2

1 2

0.3 0.2 dc 0.5 0.4

4 d 1

2 1 1 d≥ 1 0 1 3 1 0

2 2 3§ c 3 1

1 0 ¥ 1 2

2 d 4 0.6 d 0.5

5.5 MULTIPLICATION OF MATRICES

2 22. 3 £ 2 1

1 1 0

0 2 2§ £3 1 0

3 3 1

1 2 d £0 5 0

1 23. c 0

0 4 dc 1 7

3 1

3 24. 2 £ 0 2

2 1 0

1 1 3§ £0 3 0

0 1 0

31. Find the matrix A such that

1 0§ 1 0 1 0

Ac Hint: Let A  c

0 0§ 1

0 1 0§ £0 1 1

2 C  £1 3

2 2§ 1

0 3 1 1 1 2

2 1 3

0 2 § 1

3 B  £2 1

1 2 3

0 0§ 1

0 2§ 1

25. Verify the validity of the associative law for matrix multiplication. 26. Verify the validity of the distributive law for matrix multiplication. 2 d 4

1 3

and B  c

2 4

1 d 3

Compute AB and BA and hence deduce that matrix multiplication is, in general, not commutative. 28. Let 0 A  £1 0

3 0 2

4 C  £3 2

5 1 2

2 B  £3 4

0 1§ 0

a c

b d. d

A c

1 d 2

4 1 3

5 6 § 4

6 6 § 3

a. Compute AB. b. Compute AC. c. Using the results of parts (a) and (b), conclude that AB  AC does not imply that B  C.

3 0

3 8

0 d 0

and B  c

0 4

0 d 5

Show that AB  0, thereby demonstrating that for matrix multiplication the equation AB  0 does not imply that one or both of the matrices A and B must be the zero matrix. 30. Let A c

2 2

3 d 6

B c

and

2 d 1

4 2

a. Compute (A  B)2. b. Compute A2  2AB  B2. c. From the results of parts (a) and (b), show that in general (A  B)2  A2  2AB  B2. 33. Let A c

4 d 6

2 5

and B  c

4 7

8 d 3

a. Find AT and show that (AT)T  A. b. Show that (A  B)T  AT  BT. c. Show that (AB)T  BTAT. 34. Let A c

3 d 1

1 2

and

B c

3 2

4 d 2

In Exercises 35–40, write the given system of linear equations in matrix form.

35. 2x  3y  7 3x  4y  8

 7 36. 2x 3x  2y  12

37. 2x  3y  4z  6 2y  3z  7 x  y  2z  4

38.

39. x1  x2  x3  0 2x1  x2  x3  2 3x1  2x2  4x3  4

40. 3x1  5x2  4x3  10 4x1  2x2  3x3  12 x1  x3  2

2 d 2

Show that A2  0. Compare this with the equation a2  0, where a is a real number.

x  2y  3z  1 3x  4y  2z  1 2x  3y  7z  6

41. INVESTMENTS William’s and Michael’s stock holdings are given by the matrix

29. Let A c

0 1 d  c 3 3

a. Find AT and show that (AT)T  A. b. Show that (A  B)T  AT  BT. c. Show that (AB)T  BTAT.

27. Let A c

1 1

32. Let

In Exercises 25 and 26, let 1 A £ 1 2

295

A

William Michael

BAC

GM

IBM TRW

200 c 100

300 200

100 400

200 d 0

At the close of trading on a certain day, the prices (in dollars per share) of the stocks are given by the matrix BAC GM B IBM TRW

54 48 ≥ ¥ 98 82

a. Find AB. b. Explain the meaning of the entries in the matrix AB.

296

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

42. FOREIGN EXCHANGE Ethan just returned to the United States from a Southeast Asian trip and wishes to exchange the various foreign currencies that he has accumulated for U.S. dollars. He has 1200 Thai bahts, 80,000 Indonesian rupiahs, 42 Malaysian ringgits, and 36 Singapore dollars. Suppose the foreign exchange rates are U.S. $0.03 for one baht, U.S. $0.00011 for one rupiah, U.S. $0.294 for one Malaysian ringgit, and U.S. $0.656 for one Singapore dollar. a. Write a row matrix A giving the value of the various currencies that Ethan holds. (Note: The answer is not unique.) b. Write a column matrix B giving the exchange rates for the various currencies. c. If Ethan exchanges all of his foreign currencies for U.S. dollars, how many dollars will he have? 43. FOREIGN EXCHANGE Kaitlin and her friend Emma returned to the United States from a tour of four cities: Oslo, Stockholm, Copenhagen, and Saint Petersburg. They now wish to exchange the various foreign currencies that they have accumulated for U.S. dollars. Kaitlin has 82 Norwegian krones, 68 Swedish krones, 62 Danish krones, and 1200 Russian rubles. Emma has 64 Norwegian krones, 74 Swedish krones, 44 Danish krones, and 1600 Russian rubles. Suppose the exchange rates are U.S. $0.1651 for one Norwegian krone, U.S. $0.1462 for one Swedish krone, U.S. $0.1811 for one Danish krone, and U.S. $0.0387 for one Russian ruble. a. Write a 2  4 matrix A giving the values of the various foreign currencies held by Kaitlin and Emma. (Note: The answer is not unique.) b. Write a column matrix B giving the exchange rate for the various currencies. c. If both Kaitlin and Emma exchange all their foreign currencies for U.S. dollars, how many dollars will each have? 44. REAL ESTATE Bond Brothers, a real estate developer, builds houses in three states. The projected number of units of each model to be built in each state is given by the matrix I NY

A  CT MA

60 £ 20 10

Model II III

IV

80 30 15

40 10 § 5

120 60 30

The profits to be realized are $20,000, $22,000, $25,000, and $30,000, respectively, for each model I, II, III, and IV house sold. a. Write a column matrix B representing the profit for each type of house. b. Find the total profit Bond Brothers expects to earn in each state if all the houses are sold. 45. CHARITIES The amount of money raised by charity I, charity II, and charity III (in millions of dollars) in each of the years 2006, 2007, and 2008 is represented by the matrix A:

I 2006

A  2007 2008

Charity II

III

28.2 28.6 30.4

40.5 42.6 § 46.4

18.2 £ 19.6 20.8

On average, charity I puts 78% toward program cost, charity II puts 88% toward program cost, and charity III puts 80% toward program cost. Write a 3  1 matrix B reflecting the percentage put toward program cost by the charities. Then use matrix multiplication to find the total amount of money put toward program cost in each of the 3 yr by the charities under consideration. 46. BOX-OFFICE RECEIPTS The Cinema Center consists of four theaters: cinemas I, II, III, and IV. The admission price for one feature at the Center is $4 for children, $6 for students, and $8 for adults. The attendance for the Sunday matinee is given by the matrix Children Students Adults Cinema I

A

Cinema II Cinema III Cinema IV

110 180 85 250

225 75 ≥ 280 0

50 225 ¥ 110 225

Write a column vector B representing the admission prices. Then compute AB, the column vector showing the gross receipts for each theater. Finally, find the total revenue collected at the Cinema Center for admission that Sunday afternoon. 47. POLITICS: VOTER AFFILIATION Matrix A gives the percentage of eligible voters in the city of Newton, classified according to party affiliation and age group.

Under 30

A  30 to 50 Over 50

Dem.

Rep.

Ind.

0.50 £ 0.45 0.40

0.30 0.40 0.50

0.20 0.15 § 0.10

The population of eligible voters in the city by age group is given by the matrix B: Under 30

B  ”30,000

30 to 50

Over 50

40,000

20,000’

Find a matrix giving the total number of eligible voters in the city who will vote Democratic, Republican, and Independent. 48. 401(K) RETIREMENT PLANS Three network consultants, Alan, Maria, and Steven, each received a year-end bonus of $10,000, which they decided to invest in a 401(k) retirement plan sponsored by their employer. Under this plan, employees are allowed to place their investments in three funds: an equity index fund (I), a growth fund (II), and a global equity fund (III). The allocations of the investments (in dollars) of the three employees at the beginning of the year are summarized in the matrix

297

5.5 MULTIPLICATION OF MATRICES

Alan

A  Maria Steven

I

II

4000 £ 2000 2000

3000 5000 3000

c. What is the total cost of materials incurred by Ace Novelty in filling the order?

III

3000 3000 § 5000

The returns of the three funds after 1 yr are given in the matrix 0.18 £ 0.24 § 0.12

I

B  II III

London

Which employee realized the best return on his or her investment for the year in question? The worst return? 49. COLLEGE ADMISSIONS A university admissions committee anticipates an enrollment of 8000 students in its freshman class next year. To satisfy admission quotas, incoming students have been categorized according to their sex and place of residence. The number of students in each category is given by the matrix

In-state

A  Out-of-state Foreign

Male

Female

2700 £ 800 500

3000 700 § 300

B

Female

Fine Arts

Bus. Ad.

Eng.

0.20 0.35

0.30 0.25

0.25 d 0.10

Find the matrix AB that shows the number of in-state, outof-state, and foreign students expected to enter each discipline. 50. PRODUCTION PLANNING Refer to Example 6 in this section. Suppose Ace Novelty received an order from another amusement park for 1200 Pink Panthers, 1800 Giant Pandas, and 1400 Big Birds. The quantity of each type of stuffed animal to be produced at each plant is shown in the following production matrix: Panthers Pandas Birds

P

L.A. Seattle

c

700 500

1000 800

London

B  ” 300

40

Tokyo

Hong Kong

150

250

’

’

 .34 .42 .48

London

D  Tokyo

and

Hong Kong

 .24 .31 .35

Compute the matrix AC  BD and explain what it represents. 52. PRODUCTION PLANNING The total output of loudspeaker systems of the Acrosonic Company at their three production facilities for May and June is given by the matrices A and B, respectively, where Model A Location I

A  Location II Location III

Location I

B  Location II Location III

Model B

Model C

Model D

320 480 540

280 360 420

460 580 200

280 0 880

Model A

Model B

Model C

Model D

180 300 280

330 450 180

180 40 740

 

210 400 420

 

The unit production costs and selling prices for these loudspeakers are given by matrices C and D, respectively, where

800 d 600

Each Panther requires 1.3 yd2 of plush, 20 ft3 of stuffing, and 12 pieces of trim. Assume the materials required to produce the other two stuffed animals and the unit cost for each type of material are as given in Example 6. a. How much of each type of material must be purchased for each plant? b. What is the total cost of materials that will be incurred at each plant?

60

The costs for the calls (in dollars per minute) for the peak and nonpeak periods in the month in question are given, respectively, by the matrices

Hong Kong

0.25 c 0.30

Hong Kong

and

London

L. & S.

Tokyo

A  ” 80

C  Tokyo

By using data accumulated in previous years, the admissions committee has determined that these students will elect to enter the College of Letters and Science, the College of Fine Arts, the School of Business Administration, and the School of Engineering according to the percentages that appear in the following matrix:

Male

51. COMPUTING PHONE BILLS Cindy regularly makes longdistance phone calls to three foreign cities—London, Tokyo, and Hong Kong. The matrices A and B give the lengths (in minutes) of her calls during peak and nonpeak hours, respectively, to each of these three cities during the month of June.

Model A

C

Model B Model C Model D

 120 180 260 500

Model A

and

D

Model B Model C Model D

 160 250 350 700

Compute the following matrices and explain the meaning of the entries in each matrix. a. AC b. AD c. BC d. BD e. (A  B)C f. (A  B)D g. A(D  C ) h. B(D  C) i. (A  B)(D  C )

298

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

53. DIET PLANNING A dietitian plans a meal around three foods. The number of units of vitamin A, vitamin C, and calcium in each ounce of these foods is represented by the matrix M, where Food I



400 110 90

Vitamin A

M  Vitamin C Calcium

Food II

Food III

1200 570 30

800 340 60



A c

Food II

Food III

”7

1

6’

Food I

Food II

Food III

”9

3

2’

A

0 d 1.15

Compute AB. b. Hartman has m branches nationwide, and the sales of n of its products (in thousands of dollars) last year are represented by the matrix

The matrices A and B represent the amount of each food (in ounces) consumed by a girl at two different meals, where Food I

1.1 0

Branch 1

B

Branch 2

. . . Branch m

Product 3 

1

2

a11

a12



a13



n

a1n

a21 a22 a23    a2n . . . . . . . . . . . . am1 am2 am3    amn



Calculate the following matrices and explain the meaning of the entries in each matrix. a. MAT b. MBT c. M(A  B)T

Also, management has projected that the sales of the n products in branch 1, branch 2, . . . , branch m will be r1%, r2%, . . . , rm%, respectively, more than the corresponding sales for last year. Write the matrix A such that AB gives the sales of the n products in the m branches for the current year.

54. PRODUCTION PLANNING Hartman Lumber Company has two branches in the city. The sales of four of its products for the last year (in thousands of dollars) are represented by the matrix

In Exercises 55–58, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

B

Product A B C D

B

Branch I Branch II

3

5

2 8 4 6



10 8

For the present year, management has projected that the sales of the four products in branch I will be 10% more than the corresponding sales for last year and the sales of the four products in branch II will be 15% more than the corresponding sales for last year. a. Show that the sales of the four products in the two branches for the current year are given by the matrix AB, where

55. If A and B are matrices such that AB and BA are both defined, then A and B must be square matrices of the same order. 56. If A and B are matrices such that AB is defined and if c is a scalar, then (cA)B  A(cB)  cAB. 57. If A, B, and C are matrices and A(B  C) is defined, then B must have the same size as C and the number of columns of A must be equal to the number of rows of B. 58. If A is a 2  4 matrix and B is a matrix such that ABA is defined, then the size of B must be 4  2.

5.5 Solutions to Self-Check Exercises 1. We compute 1 c 2

3 4



c

 c

3 0 d £2 1 1

2. Let 1 0 2

1132  3122  0112 2132  4122  1112

9 13

1 0

13 d 21

4 3§ 1 1112  3102  0122 2112  4102  1122

0 A  £2 1 1142  3132  0112 d 2142  4132  1112

1 1 0

2 3§ 4

x X  £y§ z

1 B  £0§ 7

Then the given system may be written as the matrix equation AX  B

5.5 MULTIPLICATION OF MATRICES

3. Write

B

 54 113 112 70

Ash AB  Joan

AT&T TWX IBM GM



and compute the following:



2000 1000

 627,000 560,500 

1000 2500

500 2000



5000 0

299

 54 113 112 70

Ash Joan

We conclude that Ash’s stock holdings were worth $627,000 and Joan’s stock holdings were worth $560,500 on June 1.

USING

TECHNOLOGY

Matrix Multiplication Graphing Utility

A graphing utility can be used to perform matrix multiplication. EXAMPLE 1 Let A c

1.2 2.7

3.1 4.2

1.4 d 3.4

B c

0.8 6.2

1.2 0.4

3.7 d 3.3

1.2 C  £ 4.2 1.4

2.1 1.2 3.2

1.3 0.6 § 0.7

Find (a) AC and (b) (1.1A  2.3B)C. Solution

First, we enter the matrices A, B, and C into the calculator.

a. Using matrix operations, we enter the expression A* C. We obtain the matrix c

12.5 25.64

5.68 11.51

2.44 d 8.41

(You may need to scroll the display on the screen to obtain the complete matrix.) b. Using matrix operations, we enter the expression (1.1A  2.3B)C. We obtain the matrix c

39.464 52.078

21.536 67.999

12.689 d 32.55

Excel

We use the MMULT function in Excel to perform matrix multiplication.

Note: Boldfaced words/characters in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

(continued)

300

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

EXAMPLE 2 Let 1.2 A c 2.7

1.4 d 3.4

3.1 4.2

0.8 B c 6.2

1.2 0.4

3.7 d 3.3

1.2 C  £ 4.2 1.4

2.1 1.2 3.2

1.3 0.6 § 0.7

Find (a) AC and (b) (1.1A  2.3B)C. Solution

a. First, enter the matrices A, B, and C onto a spreadsheet (Figure T1). A 1 2 3 4 5 6 7 8

FIGURE T1 Spreadsheet showing the matrices A, B, and C

1.2 2.7

B A 3.1 4.2

C

D

−1.4 3.4

1.2 4.2 1.4

C 2.1 −1.2 3.2

1.3 0.6 0.7

E 0.8 6.2

F B 1.2 − 0.4

G 3.7 3.3

Second, compute AC. Highlight the cells that will contain the matrix product AC, which has order 2  3. Type =MMULT(, highlight the cells in matrix A, type ,, highlight the cells in matrix C, type ), and press Ctrl-Shift-Enter . The matrix product AC shown in Figure T2 will appear on your spreadsheet. A 10 11 12

FIGURE T2 The matrix product AC

12.5 25.64

B AC −5.68 11.51

C 2.44 8.41

b. Compute (1.1A  2.3B)C. Highlight the cells that will contain the matrix product (1.1A  2.3B)C. Next, type =MMULT(1.1*, highlight the cells in matrix A, type +2.3*, highlight the cells in matrix B, type ,, highlight the cells in matrix C, type ), and then press Ctrl-Shift-Enter . The matrix product shown in Figure T3 will appear on your spreadsheet. A

13 14 15

FIGURE T3

The matrix product (1.1A  2.3B)C

B (1.1A+2.3B)C 39.464 21.536 52.078 67.999

C 12.689 32.55

TECHNOLOGY EXERCISES In Exercises 1–8, refer to the following matrices and perform the indicated operations. Round your answers to two decimal places. 1.2 A  £ 7.2 0.8 0.7 B  £ 1.2 3.3

3.1 6.3 3.2

1.2 1.8 1.3

0.3 1.7 1.2

1.2 3.5 4.2

4.3 2.1 § 2.8 0.8 4.2 § 3.2

0.8 3.3 C ≥ 1.3 2.1

7.1 1.2 2.8 3.2

6.2 4.8 ¥ 1.5 8.4

1. AC

2. CB

3. (A  B)C

4. (2A  3B)C

5. (2A  3.1B)C

6. C(2.1A  3.2B)

7. (4.1A  2.7B)1.6C

8. 2.5C(1.8A  4.3B)

5.6 THE INVERSE OF A SQUARE MATRIX

In Exercises 9–12, refer to the following matrices and perform the indicated operations. Round your answers to two decimal places. 2 6 A ≥ 4 9

5 7 5 6

6.2 4.8 C  E 5.4 8.2 10.3

4 2 4 8 7.3 6.5 3.2 7.3 6.8

2 9 4 3

8 6 ¥ 4 2

4.0 8.4 6.3 6.5 4.8

2 3 B  E5 8 4 7.1 6.3 9.1 4.1 9.1

6 4 8 6 7

7 6 4 9 8

5 2 3U 5 8

9.3 8.4 2.8 U 9.8 20.4

4.6 2.4 D  E7.1 3.4 7.1

3.9 6.8 9.4 6.1 4.2

8.4 7.9 6.3 5.3 3.9

6.1 11.4 5.7 8.4 6.4

301

9.8 2.9 4.2 U 6.3 7.1

9. Find AB and BA. 10. Find CD and DC. Is CD  DC? 11. Find AC  AD. 12. Find a. AC b. AD c. A(C  D) d. Is A(C  D)  AC  AD?

5.6 The Inverse of a Square Matrix The Inverse of a Square Matrix In this section, we discuss a procedure for finding the inverse of a matrix and show how the inverse can be used to help us solve a system of linear equations. Recall that if a is a nonzero real number, then there exists a unique real number a1 Óthat is, 1a Ô such that 1 a 1a  a b 1a2  1 a

The use of the (multiplicative) inverse of a real number enables us to solve algebraic equations of the form ax  b

(12)

1

Multiplying both sides of (12) by a , we have a 1 1ax2  a 1b 1 1 a b 1ax 2  1b2 a a x

b a

For example, since the inverse of 2 is 21  12, we can solve the equation 2x  5

by multiplying both sides of the equation by 21  12, giving 21 12x2  21 # 5 x

5 2

We can use a similar procedure to solve the matrix equation AX  B

302

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

where A, X, and B are matrices of the proper sizes. To do this we need the matrix equivalent of the inverse of a real number. Such a matrix, whenever it exists, is called the inverse of a matrix.

Inverse of a Matrix

Let A be a square matrix of size n. A square matrix A1 of size n such that A1A  AA1  In

is called the inverse of A.

Let’s show that the matrix A c

Explore & Discuss

2 d 4

1 3

has the matrix

In defining the inverse of a matrix A, why is it necessary to require that A be a square matrix?

A1  c

2 3 2

1 d 12

as its inverse. Since 2 2 dc 3 4 2

AA1  c

1 3

A1A  c

2 3 2

1 1 1d  c 2 0

0 d I 1

2 1 d  c 4 0

0 d I 1

1 1 dc 12 3

we see that A1 is the inverse of A, as asserted. Not every square matrix has an inverse. A square matrix that has an inverse is said to be nonsingular. A matrix that does not have an inverse is said to be singular. An example of a singular matrix is given by B c

0 0

1 d 0

If B had an inverse given by B1  c

a c

b d d

where a, b, c, and d are some appropriate numbers, then by the definition of an inverse we would have BB1  I; that is, c

0 0

1 a dc 0 c

b 1 d  c d 0

0 d 1

c

d 1 d  c 0 0

0 d 1

c 0

which implies that 0  1—an impossibility! This contradiction shows that B does not have an inverse.

5.6 THE INVERSE OF A SQUARE MATRIX

303

A Method for Finding the Inverse of a Square Matrix The methods of Section 5.5 can be used to find the inverse of a nonsingular matrix. To discover such an algorithm, let’s find the inverse of the matrix A c

2 d 3

1 1

Suppose A1 exists and is given by A1  c

b d d

a c

where a, b, c, and d are to be determined. By the definition of an inverse, we have AA1  I; that is, 1 2 a b 1 0 c dc d  c d 1 3 c d 0 1 which simplifies to c

a  2c a  3c

b  2d 1 d  c b  3d 0

0 d 1

But this matrix equation is equivalent to the two systems of linear equations a  2c  1 f a  3c  0

and

b  2d  0 f b  3d  1

and

c

with augmented matrices given by c

1 1

2 1 ` d 3 0

1 1

2 0 ` d 3 1

Note that the matrices of coefficients of the two systems are identical. This suggests that we solve the two systems of simultaneous linear equations by writing the following augmented matrix, which we obtain by joining the coefficient matrix and the two columns of constants: c

1 1

2 1 ` 3 0

0 d 1

Using the Gauss–Jordan elimination method, we obtain the following sequence of equivalent matrices: c

1 2 1 0 R2  R1 1 2 1 0 ` d ————씮 c ` d 1 3 0 1 0 5 1 1 3 1 2 1 0 R1  2R2 1 0 25 c ` 1 1 d ————씮 c ` 15 1d 0 1 0 1 5 5 5 5

1 5 R2 —— 씮

Thus, a  35, b  25, c  15, and d  15, giving 3

A1  c 15 5

25

1d 5

The following computations verify that A1 is indeed the inverse of A: c

1 1

2 35 dc 3 15

25

1d 5

 c

1 0

3 0 d  c 15 1 5

25

1d 5

c

1 1

2 d 3

The preceding example suggests a general algorithm for computing the inverse of a square matrix of size n when it exists.

304

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Finding the Inverse of a Matrix

Given the n  n matrix A: 1. Adjoin the n  n identity matrix I to obtain the augmented matrix [A  I ’

2. Use a sequence of row operations to reduce [A  I’ to the form [I  B’

if possible. Then the matrix B is the inverse of A. Note Although matrix multiplication is not generally commutative, it is possible to prove that if A has an inverse and AB  I, then BA  I also. Hence, to verify that B is the inverse of A, it suffices to show that AB  I.

EXAMPLE 1 Find the inverse of the matrix 2 A  £3 2 Solution

1 2 1

1 1§ 2

We form the augmented matrix 2 £3 2

1 2 1

1 1 1 † 0 2 0

0 1 0

0 0§ 1

and use the Gauss–Jordan elimination method to reduce it to the form [I  B]: 2 £3 2

1 2 1

1 1 1 † 0 2 0

0 1 0

0 0§ 1

R1  R2 ⎯⎯→

1 £ 3 2

1 2 1

0 1 1 † 0 2 0

1 1 0

0 0§ 1

0 1 1 † 3 2 2

1 2 2

0 0§ 1

1 2 0

0 0§ 1

R1 ⎯⎯⎯→ R2  3R1 R3  2R1

1 £0 0

1 1 1

R1  R2 ⎯⎯→ R2 R3  R2

1 £0 0

0 1 0

1 2 1 † 3 1 1

R1  R3 ⎯⎯→ R2  R3

1 £0 0

0 1 0

0 3 0 † 4 1 1

1 2 0

1 1§ 1

The inverse of A is the matrix 3 A1  £ 4 1

1 2 0

1 1§ 1

We leave it to you to verify these results. Example 2 illustrates what happens to the reduction process when a matrix A does not have an inverse.

5.6 THE INVERSE OF A SQUARE MATRIX

305

EXAMPLE 2 Find the inverse of the matrix 1 A  £2 3 Solution

2 1 3

3 2§ 5

We form the augmented matrix 1 £2 3

2 1 3

3 1 2 † 0 5 0

0 1 0

0 0§ 1

and use the Gauss–Jordan elimination method: 1 £2 3

Explore & Discuss Explain in terms of solutions to systems of linear equations why the final augmented matrix in Example 2 implies that A has no inverse. Hint: See the discussion on page 302.

2 1 3

3 1 2 † 0 5 0

0 1 0

0 0§ 1

R2  2R1 ⎯⎯⎯→ R3  3R1

1 £0 0

2 3 3

R2 ⎯⎯→ R3  R2

1 £0 0

2 3 0

3 1 4 † 2 4 3 3 1 4 † 2 0 1

0 1 1

0 1 0

0 0§ 1 0 0§ 1

Since the entries in the last row of the 3  3 submatrix that comprises the left-hand side of the augmented matrix just obtained are all equal to zero, the latter cannot be reduced to the form [I  B]. Accordingly, we draw the conclusion that A is singular— that is, does not have an inverse. More generally, we have the following criterion for determining when the inverse of a matrix does not exist.

Matrices That Have No Inverses

If there is a row to the left of the vertical line in the augmented matrix containing all zeros, then the matrix does not have an inverse.

A Formula for the Inverse of a 2 2 Matrix Before turning to some applications, we show an alternative method that employs a formula for finding the inverse of a 2  2 matrix. This method will prove useful in many situations; we will see an application in Example 5. The derivation of this formula is left as an exercise (Exercise 50).

Formula for the Inverse of a 2 2 Matrix

Let A c

a c

b d d

Suppose D  ad  bc is not equal to zero. Then A1 exists and is given by A1 

1 d c D c

b d a

(13)

306

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

Note As an aid to memorizing the formula, note that D is the product of the elements along the main diagonal minus the product of the elements along the other diagonal:

c

Explore & Discuss Suppose A is a square matrix with the property that one of its rows is a nonzero constant multiple of another row. What can you say about the existence or nonexistence of A1? Explain your answer.

b d d :Main diagonal

a c

D  ad  bc

Next, the matrix c

b d a

d c

is obtained by interchanging a and d and reversing the signs of b and c. Finally, A1 is obtained by dividing this matrix by D. EXAMPLE 3 Find the inverse of A c Solution

2 d 4

1 3

We first compute D  (1)(4)  (2)(3)  4  6  2. Next, we write

the matrix c

4 3

2 d 1

Finally, dividing this matrix by D, we obtain A1 

1 4 c 2 3

2 2 d  c 3 1 2

1 d 12

Solving Systems of Equations with Inverses We now show how the inverse of a matrix may be used to solve certain systems of linear equations in which the number of equations in the system is equal to the number of variables. For simplicity, let’s illustrate the process for a system of three linear equations in three variables: a11x1  a12 x2  a13 x3  b1 a21x1  a22 x2  a23 x3  b2

(14)

a31x1  a32 x2  a33 x3  b3

Let’s write a11 A  £ a21 a31

a12 a22 a32

a13 a23 § a33

x1 X  £ x2 § x3

b1 B  £ b2 § b3

You should verify that System (14) of linear equations may be written in the form of the matrix equation AX  B (15) If A is nonsingular, then the method of this section may be used to compute A1. Next, multiplying both sides of Equation (15) by A1 (on the left), we obtain A1AX  A1B

or

IX  A1B

or

X  A1B

the desired solution to the problem. In the case of a system of n equations with n unknowns, we have the following more general result.

5.6 THE INVERSE OF A SQUARE MATRIX

307

Using Inverses to Solve Systems of Equations

If AX  B is a linear system of n equations in n unknowns and if A1 exists, then X  A1B

is the unique solution of the system. The use of inverses to solve systems of equations is particularly advantageous when we are required to solve more than one system of equations, AX  B, involving the same coefficient matrix, A, and different matrices of constants, B. As you will see in Examples 4 and 5, we need to compute A1 just once in each case. EXAMPLE 4 Solve the following systems of linear equations: a. 2x  y  z  1 3x  2y  z  2 2x  y  2z  1 Solution

b. 2x  y  z  2 3x  2y  z  3 2x  y  2z  1

We may write the given systems of equations in the form AX  B

and

AX  C

respectively, where 2 A  £3 2

1 2 1

1 1§ 2

x X  £y§ z

1 B  £ 2§ 1

2 C  £ 3 § 1

The inverse of the matrix A, 1

A

3  £ 4 1

1 2 0

1 1§ 1

was found in Example 1. Using this result, we find that the solution of the first system (a) is 3 X  A B  £ 4 1 1

1 2 0

1 1 1§ £ 2§ 1 1

132 112  112 122  112 112 2  £ 142 112  122 122  112 112 §  £ 1 § 112 112  102 122  112 112 2

or x  2, y  1, and z  2. The solution of the second system (b) is 3 X  A C  £ 4 1 1

1 2 0

1 2 8 1 § £ 3 §  £ 13 § 1 1 1

or x  8, y  13, and z  1. APPLIED EXAMPLE 5 Capital Expenditure Planning The management of Checkers Rent-A-Car plans to expand its fleet of rental cars for the next quarter by purchasing compact and full-size cars. The average cost of a compact car is $10,000, and the average cost of a full-size car is $24,000.

308

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

a. If a total of 800 cars is to be purchased with a budget of $12 million, how many cars of each size will be acquired? b. If the predicted demand calls for a total purchase of 1000 cars with a budget of $14 million, how many cars of each type will be acquired? Solution Let x and y denote the number of compact and full-size cars to be purchased. Furthermore, let n denote the total number of cars to be acquired and b the amount of money budgeted for the purchase of these cars. Then,

x

yn

10,000x  24,000y  b

This system of two equations in two variables may be written in the matrix form AX  B

where A c

1 10,000

x X c d y

1 d 24,000

n B c d b

Therefore, X  A1B

Since A is a 2  2 matrix, its inverse may be found by using Formula (13). We find D  (1)(24,000)  (1)(10,000)  14,000, so A1 

1 24,000 c 14,000 10,000

24,000 1 d  c 14,000 1 10,000 14,000

1 14,000

1 d 14,000

Thus, X c

12 7 57

1 14,000

1 d 14,000

n c d b

a. Here, n  800 and b  12,000,000, so X  A1B  c

12 7 57

1 14,000

1 d 14,000

c

800 514.3 d  c d 12,000,000 285.7

Therefore, 514 compact cars and 286 full-size cars will be acquired in this case. b. Here, n  1000 and b  14,000,000, so X  A1B  c

12 7 57

1 14,000

1 d 14,000

c

1000 714.3 d  c d 14,000,000 285.7

Therefore, 714 compact cars and 286 full-size cars will be purchased in this case.

5.6 Self-Check Exercises 1. Find the inverse of the matrix 2 A £ 1 1

if it exists.

1 1 2

2. Solve the system of linear equations 1 1 § 3

2x  y  z  b1 x  y  z  b2 x  2y  3z  b3

where (a) b1  5, b2  4, b3  8 and (b) b1  2, b2  0, b3  5, by finding the inverse of the coefficient matrix.

5.6 THE INVERSE OF A SQUARE MATRIX

3. Grand Canyon Tours offers air and ground scenic tours of 1 the Grand Canyon. Tickets for the 7 2 -hr tour cost $169 for an adult and $129 for a child, and each tour group is limited to 19 people. On three recent fully booked tours, total receipts were $2931 for the first tour, $3011 for the

309

second tour, and $2771 for the third tour. Determine how many adults and how many children were in each tour. Solutions to Self-Check Exercises 5.6 can be found on page 312.

5.6 Concept Questions 1. What is the inverse of a matrix A? 2. Explain how you would find the inverse of a nonsingular matrix.

4. Explain how the inverse of a matrix can be used to solve a system of n linear equations in n unknowns. Can the method work for a system of m linear equations in n unknowns with m  n? Explain.

3. Give the formula for the inverse of the 2  2 matrix A c

b d d

a c

5.6 Exercises In Exercises 1–4, show that the matrices are inverses of each other by showing that their product is the identity matrix I.

1. c

1 1

3 d 2

2. c

4 2

5 d 3

and

2 2 1

3 1§ 1

3 3. £ 2 2 2 4. £ 4 3

c

and

4 6 5

c

2 1 3 2

1

and

3 d 1

13 1 13

2 3

2 1§ 1

and

£

1 2 12

1

4 3

1 § 23 3 2 1

4 3§ 2

In Exercises 5–16, find the inverse of the matrix, if it exists. Verify your answer.

5. c

2 1

7. c

3 2

2 9. £ 0 1

5 d 3 3 d 2 3 0 2

4 11. £ 1 3

2 3 1

1 13. £ 2 1

4 3 2

6. c

2 3

3 d 5

8. c

4 6

2 d 3

1 1 1 1

1 1 0 1

1 0 ¥ 1 3

1 2 16. ≥ 0 1

1 3 2 2

2 0 1 1

3 1 ¥ 1 1

In Exercises 17–24, (a) write a matrix equation that is equivalent to the system of linear equations and (b) solve the system using the inverses found in Exercises 5–16.

52 d 2 13 £ 0

1 2 15. ≥ 2 2

17. 2x  5y  3 x  3y  2 (See Exercise 5.)

18. 2x  3y  5 3x  5y  8 (See Exercise 6.)

19. 2x  3y  4z  4 z  3 x  2y  z  8 (See Exercise 9.)

20.

x1  x2  3x3  2 2x1  x2  2x3  2 2x1  2x2  x3  3 (See Exercise 10.)

22.

3x1  2x2  7x3  6 2x1  x2  4x3  4 6x1  5x2  8x3  4 (See Exercise 14.)

21.

4 1 § 1

1 10. £ 2 2

1 1 2

2 4§ 6

1 12. £ 3 5

2 4 0

1 2 § 3

3 14. £ 2 6

2 1 5

3 2§ 1 0 2 § 2 7 4§ 8

x  4y  z  3 2x  3y  2z  1 x  2y  3z  7 (See Exercise 13.)

23. x1  x2  x3  x4  6 4 2x1  x2  x3  x4  7 2x1  x2 2x1  x2  x3  3x4  9 (See Exercise 15.) 24. x1  x2  2x3  3x4   x4  2x1  3x2 2x2  x3  x4  x1  2x2  x3  x4  (See Exercise 16.)

4 11 7 6

310

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

In Exercises 25–32, (a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix.

x  2y  b1 2x  y  b2

25.

where (i) b1  14, b2  5 and (ii) b1  4, b2  1

x  2y  z  b1 x  y  z  b2 3x  y  z  b3 where (i) b1  7, b2  4, b3  2 and (ii) b1  5, b2  3, b3  1

28.

x1  x2  x3  b1 x1  x2  x3  b2 x1  2x2  x3  b3 where (i) b1  5, b2  3, b3  1 and (ii) b1  1, b2  4, b3  2 3x  2y  z  b1 2x  3y  z  b2 x  y  z  b3

29.

where (i) b1  2, b2  2, b3  4 and (ii) b1  8, b2  3, b3  6 30.

31.

32.

2x1  x2  x3  b1 x1  3x2  4x3  b2 x1  x3  b3 where (i) b1  1, b2  4, b3  3 and (ii) b1  2, b2  5, b3  0 x1  x2  x3  x4  b1 x1  x2  x3  x4  b2 x2  2x3  2x4  b3 x1  2x2  x3  2x4  b4 where (i) b1  1, b2  1, b3  4, b4  0 and (ii) b1  2, b2  8, b3  4, b4  1 x1  x2  2x3  x4  b1 4x1  5x2  9x3  x4  b2 3x1  4x2  7x3  x4  b3 2x1  3x2  4x3  2x4  b4 where (i) b1  3, b2  6, b3  5, b4  7 and (ii) b1  1, b2  1, b3  0, b4  4

33. Let A c

a. Find A1.

2 4

4 d 3

6 4

B c

and

3 4

5 d 7

a. Find AB, A1, and B1. b. Show that (AB)1  B1A1. A c

2 1

5 d 3

B c

4 1

3 d 1

C c

2 2

3 d 1

a. Find ABC, A1, B1, and C1. b. Show that (ABC )1  C1B1A1.

where (i) b1  6, b2  10 and (ii) b1  3, b2  2 27.

A c

35. Let

3x  2y  b1 4x  3y  b2

26.

34. Let

3 d 5

b. Show that (A1)1  A.

36. Find the matrix A if c

2 1

3 2 d A c 3 1

2 d 4

37. Find the matrix A if Ac

1 3

2 2 d  c 1 3

1 d 2

38. TICKET REVENUES Rainbow Harbor Cruises charges $16/adult and $8/child for a round-trip ticket. The records show that, on a certain weekend, 1000 people took the cruise on Saturday and 800 people took the cruise on Sunday. The total receipts for Saturday were $12,800 and the total receipts for Sunday were $9,600. Determine how many adults and children took the cruise on Saturday and on Sunday. 39. PRICING BelAir Publishing publishes a deluxe leather edition and a standard edition of its Daily Organizer. The company’s marketing department estimates that x copies of the deluxe edition and y copies of the standard edition will be demanded per month when the unit prices are p dollars and q dollars, respectively, where x, y, p, and q are related by the following system of linear equations: 5x  y  1000(70  p) x  3y  1000(40  q)

Find the monthly demand for the deluxe edition and the standard edition when the unit prices are set according to the following schedules: a. p  50 and q  25 b. p  45 and q  25 c. p  45 and q  20 40. NUTRITION/DIET PLANNING Bob, a nutritionist who works for the University Medical Center, has been asked to prepare special diets for two patients, Susan and Tom. Bob has decided that Susan’s meals should contain at least 400 mg of calcium, 20 mg of iron, and 50 mg of vitamin C, whereas Tom’s meals should contain at least 350 mg of calcium, 15 mg of iron, and 40 mg of vitamin C. Bob has also decided that the meals are to be prepared from three basic foods: food A, food B, and food C. The special nutritional contents of these foods are summarized in the accompanying table. Find how many ounces of each type of food should be used in a meal so that the minimum requirements of calcium, iron, and vitamin C are met for each patient’s meals.

5.6 THE INVERSE OF A SQUARE MATRIX

Food A Food B Food C

Calcium 30 25 20

Contents (mg/oz) Iron 1 1 2

Vitamin C 2 5 4

41. AGRICULTURE Jackson Farms has allotted a certain amount of land for cultivating soybeans, corn, and wheat. Cultivating 1 acre of soybeans requires 2 labor-hours, and cultivating 1 acre of corn or wheat requires 6 labor-hours. The cost of seeds for 1 acre of soybeans is $12, for 1 acre of corn is $20, and for 1 acre of wheat is $8. If all resources are to be used, how many acres of each crop should be cultivated if the following hold? a. 1000 acres of land are allotted, 4400 labor-hours are available, and $13,200 is available for seeds. b. 1200 acres of land are allotted, 5200 labor-hours are available, and $16,400 is available for seeds. 42. MIXTURE PROBLEM—FERTILIZER Lawnco produces three grades of commercial fertilizers. A 100-lb bag of grade A fertilizer contains 18 lb of nitrogen, 4 lb of phosphate, and 5 lb of potassium. A 100-lb bag of grade B fertilizer contains 20 lb of nitrogen and 4 lb each of phosphate and potassium. A 100-lb bag of grade C fertilizer contains 24 lb of nitrogen, 3 lb of phosphate, and 6 lb of potassium. How many 100-lb bags of each of the three grades of fertilizers should Lawnco produce if a. 26,400 lb of nitrogen, 4900 lb of phosphate, and 6200 lb of potassium are available and all the nutrients are used? b. 21,800 lb of nitrogen, 4200 lb of phosphate, and 5300 lb of potassium are available and all the nutrients are used? 43. INVESTMENT CLUBS A private investment club has a certain amount of money earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of 15%/year; medium-risk stocks, 10%/year; and low-risk stocks, 6%/year. The members have decided that the investment in low-risk stocks should be equal to the sum of the investments in the stocks of the other two categories. Determine how much the club should invest in each type of stock in each of the following scenarios. (In all cases, assume that the entire sum available for investment is invested.) a. The club has $200,000 to invest, and the investment goal is to have a return of $20,000/year on the total investment. b. The club has $220,000 to invest, and the investment goal is to have a return of $22,000/year on the total investment. c. The club has $240,000 to invest, and the investment goal is to have a return of $22,000/year on the total investment. 44. RESEARCH FUNDING The Carver Foundation funds three nonprofit organizations engaged in alternate-energy research

311

activities. From past data, the proportion of funds spent by each organization in research on solar energy, energy from harnessing the wind, and energy from the motion of ocean tides is given in the accompanying table. Proportion of Money Spent Solar Wind Tides 0.6 0.3 0.1 0.4 0.3 0.3 0.2 0.6 0.2

Organization I Organization II Organization III

Find the amount awarded to each organization if the total amount spent by all three organizations on solar, wind, and tidal research is a. $9.2 million, $9.6 million, and $5.2 million, respectively. b. $8.2 million, $7.2 million, and $3.6 million, respectively. 45. Find the value(s) of k such that A c

2 d 3

1 k

has an inverse. What is the inverse of A? Hint: Use Formula 13.

46. Find the value(s) of k such that 1 A  £ 2 1

0 1 2

1 k § k2

has an inverse. Hint: Find the value(s) of k such that the augmented matrix [A 앚 I] can be reduced to the form [I 앚 B].

In Exercises 47–49, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

47. If A is a square matrix with inverse A1 and c is a nonzero real number, then 1 1cA 2 1  a b A1 c

48. The matrix A c

a c

b d d

has an inverse if and only if ad  bc  0. 49. If A1 does not exist, then the system AX  B of n linear equations in n unknowns does not have a unique solution. 50. Let A c

a c

b d d

a. Find A1 if it exists. b. Find a necessary condition for A to be nonsingular. c. Verify that AA1  A1A  I.

312

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

5.6 Solutions to Self-Check Exercises 1. We form the augmented matrix 2 £ 1 1

1 1 1 † 0 3 0

1 1 2

b. Here A and X are as in part (a), but 0 1 0

0 0§ 1

2 B2  £ 0 § 5

Therefore,

and row-reduce as follows: 2 £ 1 1

1 1 2

1 1 1 † 0 3 0

0 1 0

0 R1 4 R2 0 § ⎯⎯→ 1

1 £ 2 1

1 1 2

1 0 1 † 1 3 0

1 0 0

0 R2  2R1 0§ ⎯ ⎯⎯→ R3  R1 1

1 0 1 † 1 2 0

1 2 1

0 R R 1 2 0 § ⎯⎯→ R2 R3  R2 1

1 2 3

0 2  R3 0 § R⎯⎯→ 1

1 £0 0

1 1 1

1 £0 0

0 1 0

0 1 1 † 1 1 1

1 £0 0

0 1 0

0 1 0 † 2 1 1

1 5 3

0 1§ 1

x 1 X  £ y §  A1B2  £ 2 z 1

1 5 3

3. Let x denote the number of adults and y the number of children on a tour. Since the tours are filled to capacity, we have x  y  19

Next, since the total receipts for the first tour were $2931 we have 169x  129y  2931

Therefore, the number of adults and the number of children in the first tour is found by solving the system of linear equations x

y

19

(a)

169x  129y  2931

Similarly, we see that the number of adults and the number of children in the second and third tours are found by solving the systems

0 1§ 1

2. a. We write the systems of linear equations in the matrix form AX  B1

where 2 A £ 1 1

0 2 2 1§ £0§  £1§ 1 5 3

or x  2, y  1, and z  3.

From the preceding results, we see that 1 A1  £ 2 1

1 5 3

x y  19 169x  129y  3011

(b)

x y  19 169x  129y  2771

(c)

These systems may be written in the form 1 1 2

1 1 § 3

x X  £y§ z

5 B1  £ 4 § 8

Now, using the results of Exercise 1, we have x 1 X  £ y §  A1B1  £ 2 z 1

1 5 3

0 5 1 1§ £ 4§  £ 2§ 1 8 1

Therefore, x  1, y  2, and z  1.

AX  B1

AX  B2

AX  B3

where A c B1  c

1 169 19 d 2931

1 d 129

x X c d y

B2  c

19 d 3011

B3  c

19 d 2771

To solve these systems, we first find A1. Using Formula (13), we obtain A1  c

129 40 169 40

1 40 d 401

5.6 THE INVERSE OF A SQUARE MATRIX

Then, solving each system, we find

x X  c d  A1B3 y

x X  c d  A1B1 y 

129 40 c 169 40

1 40 d 401

 c

19 12 c d  c d 2931 7

(a)

129 40

 c

14 d 5

169 40

USING

1 40 d 401

TECHNOLOGY

c

129 40

1 40 d 401

169 40

c

19 8 d  c d 2771 11

(c)

We conclude that there were a. 12 adults and 7 children on the first tour. b. 14 adults and 5 children on the second tour. c. 8 adults and 11 children on the third tour.

x X  c d  A1B2 y  c

313

19 d 3011 (b)

Finding the Inverse of a Square Matrix Graphing Utility

A graphing utility can be used to find the inverse of a square matrix. EXAMPLE 1 Use a graphing utility to find the inverse of 1 £ 2 5 Solution

3 2 1

5 4§ 3

We first enter the given matrix as 1 A  £ 2 5

3 2 1

5 4§ 3

Then, recalling the matrix A and using the x⫺1 key, we find 0.1 A1  £ 1.3 0.6

0.2 1.1 0.7

0.1 0.7 § 0.4

EXAMPLE 2 Use a graphing utility to solve the system x  3y  5z  4 2x  2y  4z  3 5x  y  3z  2

by using the inverse of the coefficient matrix. Solution

The given system can be written in the matrix form AX  B, where 1 A  £ 2 5

3 2 1

5 4§ 3

x X  £y§ z

4 B  £3§ 2

The solution is X  A1B. Entering the matrices A and B in the graphing utility and using the matrix multiplication capability of the utility gives the output shown in Figure T1—that is, x  0, y  0.5, and z  0.5. (continued)

314

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES [A]−1 [B] [ [0 ] [.5] [.5] ] Ans

FIGURE T1

The TI-83/84 screen showing A1B

Excel

We use the function MINVERSE to find the inverse of a square matrix using Excel. EXAMPLE 3

Find the inverse of 1 A  £ 2 5

3 2 1

5 4§ 3

Solution

1. Enter the elements of matrix A onto a spreadsheet (Figure T2). 2. Compute the inverse of the matrix A: Highlight the cells that will contain the inverse matrix A1, type = MINVERSE(, highlight the cells containing matrix A, type ), and press Ctrl-Shift-Enter . The desired matrix will appear in your spreadsheet (Figure T2). A

FIGURE T2

Matrix A and its inverse, matrix A1

1 2 3 5 6 7 8 9 10

B Matrix A 1 −2 5

C 3 2 1

5 4 3

Matrix A−1 0.1 − 0.2 1.3 −1.1 0.7 −0.6

0.1 − 0.7 0.4

EXAMPLE 4 Solve the system x  3y  5z  4 2x  2y  4z  3 5x  y  3z  2

by using the inverse of the coefficient matrix. Solution

The given system can be written in the matrix form AX  B, where 1 A  £ 2 5

3 2 1

5 4§ 3

x X  £y§ z

4 B  £3§ 2

The solution is X  A1B. Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

5.6 THE INVERSE OF A SQUARE MATRIX

1. Enter the matrix B on a spreadsheet. 2. Compute A1B. Highlight the cells that will contain the matrix X, and then type =MMULT(, highlight the cells in the matrix A1, type ,, highlight the cells in the matrix B, type ), and press Ctrl-Shift-Enter . (Note: The matrix A1 was found in Example 3.) The matrix X shown in Figure T3 will appear on your spreadsheet. Thus, x  0, y  0.5, and z  0.5.

A Matrix X

12 13

5.55112E−17

14

0.5

15

0.5

315

FIGURE T3 Matrix X gives the solution to the problem.

TECHNOLOGY EXERCISES In Exercises 1–6, find the inverse of the matrix. Round your answers to two decimal places. 1. £

1.2 3.4 1.2

1.1 1.6 3. ≥ 4.2 1.6

2.3 3.2 1.6 2.1

2.1 6.2 4. ≥ 2.3 2.1 2 3 5. E3 2 3

1 2 2 1 4

1 6 6. E 4 1 1.1

2.1 7.3 § 1.3

3.1 2.6 3.4

3.1 1.8 1.4 2.8

3.2 7.3 7.1 3.1 3 1 6 1 2 4 2.4 1 2 2.2

4.2

2. £ 2.1

1.8

4.2 2.9 ¥ 3.2 7.2

1.4 8.4 2.4 4.6 2 4 4 4 5 2 5 2 3 3

4.6 2.3 § 2.3

7. 2x  3y  4z  2.4 3 x  2y  7z  8.1 x  4y  2z  10.2 8. 3.2x  4.7y  3.2z  7.1 2.1x  2.6y  6.2z  8.2 5.1 x  3.1y  2.6z  6.5

3.2 1.6 ¥ 1.3 3.7 4 1 1U 2 6 3 1.2 3 4 5.1

3.7 1.3 7.6

In Exercises 7–10, solve the system of linear equations by first writing the system in the form AX  B and then solving the resulting system by using A1. Round your answers to two decimal places.

1.4 3 1.2U 2 4

9. 3x1  2 x2  4 x3  8 x4  8 2x1  3 x2  2 x3  6 x4  4 3 x1  2 x2  6 x3  7 x4  2 4 x1  7 x2  4 x3  6 x4  22 10. 1.2 x1  2.1 x2  3.2 x3  4.6 x4  6.2 3.1x1  1.2 x2  4.1 x3  3.6 x4  2.2 1.8 x1  3.1 x2  2.4 x3  8.1 x4  6.2 2.6 x1  2.4 x2  3.6 x3  4.6 x4  3.6

316

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

CHAPTER 5 Summary of Principal Formulas and Terms FORMULAS 1. Laws for matrix addition a. Commutative law

ABBA

b. Associative law

(A  B)  C  A  (B  C )

2. Laws for matrix multiplication a. Associative law

(AB)C  A(BC )

b. Distributive law

A(B  C)  AB  AC

3. Inverse of a 2  2 matrix

4. Solution of system AX  B (A nonsingular)

If

A c

and

D  ad  bc  0

then

A1 

a c

b d d

1 d c D c

b d a

X  A1B

TERMS system of linear equations (242) solution of a system of linear equations (242) parameter (243) dependent system (244) inconsistent system (244) Gauss–Jordan elimination method (250) equivalent system (250) coefficient matrix (252)

augmented matrix (252) row-reduced form of a matrix (253) row operations (254) unit column (254) pivoting (255) size of a matrix (276) matrix (276) row matrix (276) column matrix (276)

square matrix (276) transpose of a matrix (280) scalar (280) scalar product (280) matrix product (288) identity matrix (291) inverse of a matrix (302) nonsingular matrix (302) singular matrix (302)

CHAPTER 5 Concept Review Questions Fill in the blanks.

1. a. Two lines in the plane can intersect at (a) exactly _____ point, (b) infinitely _____ points, or (c) _____ point. b. A system of two linear equations in two variables can have (a) exactly _____ solution, (b) infinitely _____ solutions, or (c) _____ solution. 2. To find the point(s) of intersection of two lines, we solve the system of _____ describing the two lines. 3. The row operations used in the Gauss–Jordan elimination method are denoted by _____ , _____ , and _____ . The use of each of these operations does not alter the _____ of the system of linear equations. 4. a. A system of linear equations with fewer equations than variables cannot have a/an _____ solution.

b. A system of linear equations with at least as many equations as variables may have _____ solution, _____ _____ solutions, or a _____ solution. 5. Two matrices are equal provided they have the same _____ and their corresponding _____ are equal. 6. Two matrices may be added (subtracted) if they both have the same _____ . To add or subtract two matrices, we add or subtract their _____ entries. 7. The transpose of a/an _____ matrix with elements aij is the matrix of size _____ with entries _____ . 8. The scalar product of a matrix A by the scalar c is the matrix _____ obtained by multiplying each entry of A by _____ .

REVIEW EXERCISES

9. a. For the product AB of two matrices A and B to be defined, the number of _____ of A must be equal to the number of _____ of B. b. If A is an m  n matrix and B is an n  p matrix, then the size of AB is _____ . 10. a. If the products and sums are defined for the matrices A, B, and C, then the associative law states that (AB)C  _____ ; the distributive law states that A(B  C)  _____ .

317

b. If I is an identity matrix of size n, then IA  A if A is any matrix of size _____ . 11. A matrix A is nonsingular if there exists a matrix A1 such that _____  _____  I. If A1 does not exist, then A is said to be _____ . 12. A system of n linear equations in n variables written in the form AX  B has a unique solution given by X  _____ if A has an inverse.

CHAPTER 5 Review Exercises In Exercises 1–4, perform the operations if possible.

1

11. 2(3A)

12. 2(3A  4B)

2

0 1§ 2

13. A(B  C )

14. AB  AC

1 3

2 1 d  c 4 5

2 d 2

15. A(BC )

16.

3. 3 3

2

2 1 4 £ 1 2

4. c

3 2

1 2 d £4§ 3 2

1 1

1 5. c y

x z d  c 3 3

6. c

x 1 7 dc d  c d 3 2 4

3 y

3

7. £ 1

c1 x 0

3 y

17. 2x  3y  5 3x  4y  1 19.

2 d w

6 4§ 2

1 1 d £3 2 4

4 d 2

1 12 z§  c 2 2

3 1 0

2 B  £ 2 1

1 1 4 1 6 1

x  y  2z  5 3x  2y  z  10 2x  3y  2z  10

1 3§ 2 3 1 § 2 2 4§ 3

20. 3x  2y  4z  16 2 x  y  2z  1 x  4y  8z  18

x  2y  3z  4w  17 2 x  y  2z  3w  9 3 x  y  2z  4w  0 4 x  2y  3z  w  2

23. 3 x  2y  z  4 x  3y  4z  3 2x  3y  5z  7 x  8y  9z  10

In Exercises 9–16, compute the expressions if possible, given that 1 A  £ 2 4

18. 3 x  2y  3 2x  4y  14

21. 3x  2y  4z  11 2x  4y  5z  4 x  2y  z  10 22.

a3 3 b §  £e  2 d 1

3 C  £1 2

1 1CA  CB 2 2

In Exercises 17–24, solve the system of linear equations using the Gauss–Jordan elimination method.

1 0§ 1

In Exercises 5–8, find the values of the variables.

8. c

10. 3A  2B

2 1 3§  £0 1 1

1. £ 1 2. c

9. 2A  3 B

24. 2x  3y  z  10 3x  2y  2z  2 x  3y  4z  7 4x  y  z  4

In Exercises 25–32, find the inverse of the matrix (if it exists).

25. A  c

3 1

1 d 2

26. A  c

2 1

4 d 6

27. A  c

3 2

4 d 2

28. A  c

2 1

4 d 2

2 29. A  £ 1 1

3 1 2

1 31. A  £ 3 1

2 1 0

1 2§ 1 4 2§ 6

1 30. A  £ 2 1 2 32. A  £ 1 3

2 1 0 1 2 1

4 3§ 2 3 4 § 2

318

5 SYSTEMS OF LINEAR EQUATIONS AND MATRICES

In Exercises 33–36, compute the value of the expressions if possible, given that A c

1 1

2 d 2

B c

33. (A1B)1

3 4

1 d 2

C c

1 1

1 d 2

34. (ABC )1 1

1

35. (2A  C )

36. (A  B)

In Exercises 37–40, write each system of linear equations in the form AX  C. Find A1 and use the result to solve the system.

37. 2 x  3y  8 x  2y  3 39.

38.

x  2y  4z  13 2x  3y  2z  0 x  4y  6z  15

x  3y  1 2 x  4y  8

42. COMMON STOCK TRANSACTIONS Jack Spaulding bought 10,000 shares of stock X, 20,000 shares of stock Y, and 30,000 shares of stock Z at a unit price of $20, $30, and $50 per share, respectively. Six months later, the closing prices of stocks X, Y, and Z were $22, $35, and $51 per share, respectively. Jack made no other stock transactions during the period in question. Compare the value of Jack’s stock holdings at the time of purchase and 6 months later. 43. INVESTMENTS William’s and Michael’s stock holdings are given in the following table: BAC 800 600

44. INVESTMENT PORTFOLIOS The following table gives the number of shares of certain corporations held by Olivia and Max in their stock portfolios at the beginning of September and at the beginning of October:

Olivia Max

IBM 800 500

September Google 500 600

Boeing 1200 2000

GM 1500 800

Olivia Max

IBM 900 700

October Google 600 500

Boeing 1000 2100

GM 1200 900

40. 2x  3y  4z  17 x  2y  4 z  7 3x  y  2z  14

41. GASOLINE SALES Gloria Newburg operates three selfservice gasoline stations in different parts of town. On a certain day, station A sold 600 gal of premium, 800 gal of super, 1000 gal of regular gasoline, and 700 gal of diesel fuel; station B sold 700 gal of premium, 600 gal of super, 1200 gal of regular gasoline, and 400 gal of diesel fuel; station C sold 900 gal of premium, 700 gal of super, 1400 gal of regular gasoline, and 800 gal of diesel fuel. Assume that the price of gasoline was $3.20/gal for premium, $2.98/gal for super, and $2.80/gal for regular and that diesel fuel sold for $3.10/gal. Use matrix algebra to find the total revenue at each station.

William Michael

b. Write a 4  1 matrix B giving the closing prices of the stocks of BAC, GM, IBM, and TRW. c. Use matrix multiplication to find the total value of the stock holdings of William and Michael at the market close.

GM 1200 1400

IBM 400 600

TRW 1500 2000

The prices (in dollars per share) of the stocks of BAC, GM, IBM, and TRW at the close of the stock market on a certain day are $50.26, $31.00, $103.07 and $38.67, respectively. a. Write a 2  4 matrix A giving the stock holdings of William and Michael.

a. Write matrices A and B giving the stock portfolios of Olivia and Max at the beginning of September and at the beginning of October, respectively. b. Find a matrix C reflecting the change in the stock portfolios of Olivia and Max between the beginning of September and the beginning of October. 45. MACHINE SCHEDULING Desmond Jewelry wishes to produce three types of pendants: type A, type B, and type C. To manufacture a type-A pendant requires 2 min on machines I and II and 3 min on machine III. A type-B pendant requires 2 min on machine I, 3 min on machine II, and 4 min on machine III. A type-C pendant requires 3 min on machine I, 4 min on machine II, and 3 min on machine III. There are 3 12 hr available on machine I, 4 12 hr available on machine II, and 5 hr available on machine III. How many pendants of each type should Desmond make in order to use all the available time? 46. PETROLEUM PRODUCTION Wildcat Oil Company has two refineries, one located in Houston and the other in Tulsa. The Houston refinery ships 60% of its petroleum to a Chicago distributor and 40% of its petroleum to a Los Angeles distributor. The Tulsa refinery ships 30% of its petroleum to the Chicago distributor and 70% of its petroleum to the Los Angeles distributor. Assume that, over the year, the Chicago distributor received 240,000 gal of petroleum and the Los Angeles distributor received 460,000 gal of petroleum. Find the amount of petroleum produced at each of Wildcat’s refineries.

BEFORE MOVING ON . . .

319

CHAPTER 5 Before Moving On . . . 1. Solve the following system of linear equations, using the Gauss–Jordan elimination method:

A c

2x  y  z  1 x  3y  2z 

2. Find the solution(s), if it exists, of the system of linear equations whose augmented matrix in reduced form follows. 1 a. £ 0 0

0 1 0

0 2 0 † 3 § 1 1

1 b. £ 0 0

0 1 0

0 3 0 † 0§ 0 1

1 c. £ 0 0

0 1 0

0 2 3 † 1§ 0 0

1 0 d. ≥ 0 0

0 1 0 0

0 0 1 0

e. c

0 1

1 2 ` d 2 3

0 0 0 0 ∞ ¥ 0 0 1 0

2 0

4 d 1

2 C  £1 3

1 B  £3 2

1 1 1

2 1 § 0

2 1§ 4

Find (a) AB, (b) (A  CT )B, and (c) CTB  ABT. 5. Find A1 if 2 A  £0 1

1 1 1

2 3§ 0

z

4

6. Solve the system 2x

2x  y  z  1 3x  y  z 

3. Solve each system of linear equations using the Gauss– Jordan elimination method. a. x  2y  3 b. x  2y  4z  2 3x  y  5 4x  y  2

1 3

2

3x  3y  3z  5

1 0

4. Let

3x  y  2z  1

0

by first writing it in the matrix form AX  B and then finding A1.

This page intentionally left blank

6

LINEAR PROGRAMMING

M

ANY PRACTICAL PROBLEMS involve maximizing or minimizing a function subject to certain constraints.

For example, we may wish to maximize a profit function subject to certain limitations on the amount of material and labor available. Maximization or minimization problems that can be

in the form of linear inequalities are called linear programming problems. In this chapter, we look at linear programming problems involving two variables. These problems are amenable to geometric analysis, and the method of solution introduced here will shed much light on the basic nature of a linear programming problem. Solving linear programming problems involving more than two variables requires algebraic techniques. One such technique, the simplex method, was developed by

© Christa Knijff/Alamy

formulated in terms of a linear objective function and constraints

How many souvenirs should Ace Novelty make in order to maximize its profit? The company produces two types of souvenirs, each of which requires a certain amount of time on each of two different

George Dantzig in the late 1940s and remains in wide use to

machines. Each machine can be

this day.

operated for only a certain number of hours per day. In Example 1, page 330, we show how this production problem can be formulated as a linear programming problem, and in Example 1, page 341, we solve this linear programming problem.

322

6 LINEAR PROGRAMMING

6.1 Graphing Systems of Linear Inequalities in Two Variables Graphing Linear Inequalities In Chapter 2, we saw that a linear equation in two variables x and y ax  by  c  0

a, b not both equal to zero

has a solution set that may be exhibited graphically as points on a straight line in the xy-plane. We now show that there is also a simple graphical representation for linear inequalities in two variables: ax  by  c 0 ax  by  c  0

ax  by  c 0 ax  by  c  0

Before turning to a general procedure for graphing such inequalities, let’s consider a specific example. Suppose we wish to graph 2x  3y 6

(1)

We first graph the equation 2x  3y  6, which is obtained by replacing the given inequality “ ” with an equality “” (Figure 1). y

L

Upper half-plane 2x + 3y = 6

5 P(x, y) Q x, − 23 x + 2 x

−5 FIGURE 1

x

5

Lower half-plane

A straight line divides the xy-plane into two half-planes.

−5

Observe that this line divides the xy-plane into two half-planes: an upper halfplane and a lower half-plane. Let’s show that the upper half-plane is the graph of the linear inequality 2x  3y  6

(2)

whereas the lower half-plane is the graph of the linear inequality 2x  3y 6

(3)

To see this, let’s write Inequalities (2) and (3) in the equivalent forms 2 y x2 3

(4)

2 y  x2 3

(5)

and

6.1 GRAPHING SYSTEMS OF LINEAR INEQUALITIES IN TWO VARIABLES

323

The equation of the line itself is 2 y x2 3

(6)

Now pick any point P(x, y) lying above the line L. Let Q be the point lying on L and directly below P (see Figure 1). Since Q lies on L, its coordinates must satisfy Equation (6). In other words, Q has representation QÓx,  23 x  2Ô. Comparing the y-coordinates of P and Q and recalling that P lies above Q, so that its y-coordinate must be larger than that of Q, we have 2 y x2 3

But this inequality is just Inequality (4) or, equivalently, Inequality (2). Similarly, we can show that every point lying below L must satisfy Inequality (5) and therefore (3). This analysis shows that the lower half-plane provides a solution to our problem (Figure 2). (By convention, we draw the line as a dashed line to show that the points on L do not belong to the solution set.) Observe that the two half-planes in question are disjoint; that is, they do not have any points in common. y

5

2x + 3y < 6

FIGURE 2 The set of points lying below the dashed line satisfies the given inequality.

−5

2x + 3y = 6

x 5

Alternatively, there is a simpler method for determining the half-plane that provides the solution to the problem. To determine the required half-plane, let’s pick any point lying in one of the half-planes. For simplicity, pick the origin (0, 0), which lies in the lower half-plane. Substituting x  0 and y  0 (the coordinates of this point) into the given Inequality (1), we find 2(0)  3(0) 6

or 0 6, which is certainly true. This tells us that the required half-plane is the one containing the test point—namely, the lower half-plane. Next, let’s see what happens if we choose the point (2, 3), which lies in the upper half-plane. Substituting x  2 and y  3 into the given inequality, we find 2(2)  3(3) 6

or 13 6, which is false. This tells us that the upper half-plane is not the required halfplane, as expected. Note, too, that no point P(x, y) lying on the line constitutes a solution to our problem, given the strict inequality . This discussion suggests the following procedure for graphing a linear inequality in two variables.

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6 LINEAR PROGRAMMING

Procedure for Graphing Linear Inequalities

1. Draw the graph of the equation obtained for the given inequality by replacing the inequality sign with an equal sign. Use a dashed or dotted line if the problem involves a strict inequality, or . Otherwise, use a solid line to indicate that the line itself constitutes part of the solution. 2. Pick a test point lying in one of the half-planes determined by the line sketched in step 1 and substitute the values of x and y into the given inequality. For simplicity, use the origin whenever possible. 3. If the inequality is satisfied, the graph of the solution to the inequality is the half-plane containing the test point. Otherwise, the solution is the half-plane not containing the test point.

EXAMPLE 1 Determine the solution set for the inequality 2x  3y  6. Replacing the inequality  with an equality , we obtain the equation 2x  3y  6, whose graph is the straight line shown in Figure 3.

Solution

y

5 2x + 3y  6 2x + 3y = 6

x

FIGURE 3

–5

The set of points lying on the line and in the upper half-plane satisfies the given inequality.

5

Instead of a dashed line as before, we use a solid line to show that all points on the line are also solutions to the inequality. Picking the origin as our test point, we find 2(0)  3(0)  6, or 0  6, which is false. So we conclude that the solution set is made up of the half-plane not containing the origin, including (in this case) the line given by 2x  3y  6. y

EXAMPLE 2 Graph x 1. The graph of x  1 is the vertical line shown in Figure 4. Picking the origin (0, 0) as a test point, we find 0 1, which is false. Therefore, the required solution is the left half-plane, which does not contain the origin.

Solution

x ≤ –1 x

EXAMPLE 3 Graph x  2y  0. We first graph the equation x  2y  0, or y  12 x (Figure 5). Since the origin lies on the line, we may not use it as a test point. (Why?) Let’s pick (1, 2) as a test point. Substituting x  1 and y  2 into the given inequality, we find 1  2(2)  0, or 3  0, which is false. Therefore, the required solution is the halfplane that does not contain the test point—namely, the lower half-plane.

Solution x = –1 FIGURE 4 The set of points lying on the line x  1 and in the left half-plane satisfies the given inequality.

6.1 GRAPHING SYSTEMS OF LINEAR INEQUALITIES IN TWO VARIABLES

325

y x – 2y = 0

x

FIGURE 5 The set of points in the lower half-plane satisfies x  2y  0.

Exploring with

TECHNOLOGY A graphing utility can be used to plot the graph of a linear inequality. For example, to plot the solution set for Example 1, first rewrite the equation 2x  3y  6 in the form y  2  23 x. Next, enter this expression for Y1 in the calculator and move the cursor to the left of Y1. Then, press ENTER repeatedly and select the icon that indicates the shading option desired (see Figure a). The required graph follows (see Figure b). Plot1 Plot2 Y1 = 2–(2/3)X \Y2 = \Y3 = \Y4 = \Y5 = \Y6 = \Y7 = FIGURE a TI 83/84 screen

Plot3

FIGURE b

Graph of the inequality 2x  3y  6

Graphing Systems of Linear Inequalities By the solution set of a system of linear inequalities in the two variables x and y we mean the set of all points (x, y) satisfying each inequality of the system. The graphical solution of such a system may be obtained by graphing the solution set for each inequality independently and then determining the region in common with each solution set. y

EXAMPLE 4 Determine the solution set for the system 4x  3y  12 x y 0

4x + 3y = 12 x–y=0 P

12 12 7, 7

x –3

3

FIGURE 6 The set of points in the shaded area satisfies the system 4x  3y  12 x y 0

Solution Proceeding as in the previous examples, you should have no difficulty locating the half-planes determined by each of the linear inequalities that make up the system. These half-planes are shown in Figure 6. The intersection of the two half-planes is the shaded region. A point in this region is an element of the solution set for the given system. The point P, the intersection of the two straight lines determined by the equations, is found by solving the simultaneous equations

4x  3y  12 x y 0

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6 LINEAR PROGRAMMING

EXAMPLE 5 Sketch the solution set for the system x0 y0 xy6 0 2x  y  8 0 Solution The first inequality in the system defines the right half-plane—all points to the right of the y-axis plus all points lying on the y-axis itself. The second inequality in the system defines the upper half-plane, including the x-axis. The half-planes defined by the third and fourth inequalities are indicated by arrows in Figure 7. Thus, the required region—the intersection of the four half-planes defined by the four inequalities in the given system of linear inequalities—is the shaded region. The point P is found by solving the simultaneous equations x  y  6  0 and 2x  y  8  0. y

10 x+y–6=0

2x + y – 8 = 0 5 P (2, 4)

FIGURE 7 The set of points in the shaded region, including the x- and y-axes, satisfies the given inequalities.

x –10

–5

5

10

The solution set found in Example 5 is an example of a bounded set. Observe that the set can be enclosed by a circle. For example, if you draw a circle of radius 10 with center at the origin, you will see that the set lies entirely inside the circle. On the other hand, the solution set of Example 4 cannot be enclosed by a circle and is said to be unbounded.

Bounded and Unbounded Solution Sets

The solution set of a system of linear inequalities is bounded if it can be enclosed by a circle. Otherwise, it is unbounded.

EXAMPLE 6 Determine the graphical solution set for the following system of linear inequalities: 2x  y  50 x  2y  40 x0 y0 Solution

The required solution set is the unbounded region shown in Figure 8.

6.1 GRAPHING SYSTEMS OF LINEAR INEQUALITIES IN TWO VARIABLES

327

y

2x + y = 50 50

x + 2y = 40 (20, 10)

10

x FIGURE 8

– 50

– 10

10

50

The solution set is an unbounded region.

6.1 Self-Check Exercises 1. Determine graphically the solution set for the following system of inequalities:

2. Determine graphically the solution set for the following system of inequalities:

x  2y 10

5x  3y  30

5x  3y 30

x  3y 0

x  0, y  0

x 2

Solutions to Self-Check Exercises 6.1 can be found on page 329.

6.1 Concept Questions 1. a. What is the difference, geometrically, between the solution set of ax  by c and the solution set of ax  by c? b. Describe the set that is obtained by intersecting the solution set of ax  by c with the solution set of ax  by  c.

2. a. What is the solution set of a system of linear inequalities? b. How do you find the solution of a system of linear inequalities graphically?

6.1 Exercises In Exercises 1–10, find the graphical solution of each inequality.

1. 4x  8 0

2. 3y  2  0

3. x  y 0

4. 3x  4y 2

5. x 3

6. y  1

7. 2x  y 4

8. 3x  6y  12

9. 4x  3y 24

In Exercises 11–18, write a system of linear inequalities that describes the shaded region.

11.

y

y=4 y=2

10. 5x  3y  15 x x=1

x=5

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6 LINEAR PROGRAMMING

12.

17.

y x+y=3

y

x=2

y=x y=4

y=7

y=3 x x x+y=7

y

13.

2x – y = 2

18.

y 4x + y = 16

x 4 x=4

x

5x + 7y = 35

14.

4

y

x + 5y = 20 5 x + 4y = 4 0

In Exercises 19–36, determine graphically the solution set for each system of inequalities and indicate whether the solution set is bounded or unbounded.

19. 2x  4y  16 x  3y  7

x

21. x  y 0

x + 2y = 8

x  2y 

x – y = –10

3x  y

6

23. x  2y 

24. 2x  y 

25. x  y 6

26. 4x  3y 12

27. 3x  6y 12

28. x  y  20

29. 3x  7y  24

30. 3x  4y  12

31. x  2y  3

32.

33. 6x  5y 30

34. 6x  7y 84

3 2x  4y 2

y

5

22. x  y  2

2x  3y  10

5x + 2y = 20

15.

20. 3x  2y  13

0 x 3 y0

4 4x  2y 2 5x  2y 10 x  0, y  0

20 10 x 10 20

30 x + 3y = 30

7x + 4y = 140

16.

x  2y 4 x  0, y  0

x  3y  8 x  0, y  0

y

5x  4y 16 0 y 2 x 0

2

x 2 3x + 5y = 60 x+y=2 9x + 5y = 90

3x  y  6 x y 4 x  0, y  0

x  2y  40 x  0, y  0

2x  y  2 0 y 3 x 0 xy 4 2x  y 6 2x  y  1 x  0, y  0 12x  11y 18 6x  7y 28 x  0, y  0

6.1 GRAPHING SYSTEMS OF LINEAR INEQUALITIES IN TWO VARIABLES

35. x  y  6

36. x  3y  18

x  2y 2 x  2y  6 x  2y  14 x  0, y  0

3x  2y  2 x  3y 4 3x  2y 16 x  0, y  0

In Exercises 37–40, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

37. The solution set of a linear inequality involving two variables is either a half-plane or a straight line.

329

39. The solution set of a system of linear inequalities in two variables is bounded if it can be enclosed by a rectangle. 40. The solution set of the system ax  by e cx  dy f x  0, y  0

where a, b, c, d, e, and f are positive real numbers, is a bounded set.

38. The solution set of the inequality ax  by  c 0 is either a left half-plane or a lower half-plane.

6.1 Solutions to Self-Check Exercises 1. The required solution set is shown in the following figure:

2. The required solution set is shown in the following figure:

y

y

x=2

5x + 3y = 30 10 5x + 3y = 30

Q 2, 20 3

x + 2y = 10

x − 3y = 0 P 5, 35

P 30 , 20 7 7

10

x 20

x 10

The point P is found by solving the system of equations

To find the coordinates of P, we solve the system

x  2y  10

5x  3y  30

5x  3y  30

x  3y  0

Solving the first equation for x in terms of y gives x  10  2y

Substituting this value of x into the second equation of the system gives 5110  2y2  3y 

30

50  10y  3y 

30

7y  20

so y  207. Substituting this value of y into the expression for x found earlier, we obtain x  10  2 a

20 30 b  7 7

giving the point of intersection as 1 307, 207 2.

Solving the second equation for x in terms of y and substituting this value of x in the first equation gives 5(3y)  3y  30

or y  Substituting this value of y into the second equation gives x  5. Next, the coordinates of Q are found by solving the system 5 3.

5x  3y  30 x2

yielding x  2 and y  203.

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6 LINEAR PROGRAMMING

6.2 Linear Programming Problems In many business and economic problems we are asked to optimize (maximize or minimize) a function subject to a system of equalities or inequalities. The function to be optimized is called the objective function. Profit functions and cost functions are examples of objective functions. The system of equalities or inequalities to which the objective function is subjected reflects the constraints (for example, limitations on resources such as materials and labor) imposed on the solution(s) to the problem. Problems of this nature are called mathematical programming problems. In particular, problems in which both the objective function and the constraints are expressed as linear equations or inequalities are called linear programming problems.

Linear Programming Problem

A linear programming problem consists of a linear objective function to be maximized or minimized subject to certain constraints in the form of linear equations or inequalities.

A Maximization Problem As an example of a linear programming problem in which the objective function is to be maximized, let’s consider the following simplified version of a production problem involving two variables. APPLIED EXAMPLE 1 A Production Problem Ace Novelty wishes to produce two types of souvenirs: type A and type B. Each type-A souvenir will result in a profit of $1, and each type-B souvenir will result in a profit of $1.20. To manufacture a type-A souvenir requires 2 minutes on machine I and 1 minute on machine II. A type-B souvenir requires 1 minute on machine I and 3 minutes on machine II. There are 3 hours available on machine I and 5 hours available on machine II. How many souvenirs of each type should Ace make in order to maximize its profit? Solution As a first step toward the mathematical formulation of this problem, we tabulate the given information (see Table 1). TABLE 1

Machine I Machine II Profit/Unit

Type A

Type B

Time Available

2 min 1 min $1

1 min 3 min $1.20

180 min 300 min

Let x be the number of type-A souvenirs and y the number of type-B souvenirs to be made. Then, the total profit P (in dollars) is given by P  x  1.2y

which is the objective function to be maximized. The total amount of time that machine I is used is given by 2x  y minutes and must not exceed 180 minutes. Thus, we have the inequality 2x  y 180

6.2 LINEAR PROGRAMMING PROBLEMS

331

Similarly, the total amount of time that machine II is used is x  3y minutes and cannot exceed 300 minutes, so we are led to the inequality x  3y 300

Finally, neither x nor y can be negative, so x0 y0

To summarize, the problem at hand is one of maximizing the objective function P  x  1.2y subject to the system of inequalities 2x  y 180 x  3y 300 x0 y0

The solution to this problem will be completed in Example 1, Section 6.3.

Minimization Problems In the following linear programming problem, the objective function is to be minimized. APPLIED EXAMPLE 2 A Nutrition Problem A nutritionist advises an individual who is suffering from iron and vitamin-B deficiency to take at least 2400 milligrams (mg) of iron, 2100 mg of vitamin B1 (thiamine), and 1500 mg of vitamin B2 (riboflavin) over a period of time. Two vitamin pills are suitable, brand A and brand B. Each brand-A pill costs 6 cents and contains 40 mg of iron, 10 mg of vitamin B1, and 5 mg of vitamin B2. Each brand-B pill costs 8 cents and contains 10 mg of iron and 15 mg each of vitamins B1 and B2 (Table 2). What combination of pills should the individual purchase in order to meet the minimum iron and vitamin requirements at the lowest cost? TABLE 2

Iron Vitamin B1 Vitamin B2 Cost/Pill

Brand A

Brand B

Minimum Requirement

40 mg 10 mg 5 mg

10 mg 15 mg 15 mg

2400 mg 2100 mg 1500 mg

6¢

8¢

Solution Let x be the number of brand-A pills and y the number of brand-B pills to be purchased. The cost C (in cents) is given by

C  6x  8y

and is the objective function to be minimized. The amount of iron contained in x brand-A pills and y brand-B pills is given by 40x  10y mg, and this must be greater than or equal to 2400 mg. This translates into the inequality 40x  10y  2400

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6 LINEAR PROGRAMMING

Similar considerations involving the minimum requirements of vitamins B1 and B2 lead to the inequalities 10x  15y  2100 5x  15y  1500

respectively. Thus, the problem here is to minimize C  6x  8y subject to 40x  10y  2400 10x  15y  2100 5x  15y  1500 x  0, y  0

The solution to this problem will be completed in Example 2, Section 6.3. APPLIED EXAMPLE 3 A Transportation Problem Curtis-Roe Aviation Industries has two plants, I and II, that produce the Zephyr jet engines used in their light commercial airplanes. There are 100 units of the engines in plant I and 110 units in plant II. The engines are shipped to two of Curtis-Roe’s main assembly plants, A and B. The shipping costs (in dollars) per engine from plants I and II to the main assembly plants A and B are as follows:

From

To Assembly Plant A B

Plant I Plant II

100 120

60 70

In a certain month, assembly plant A needs 80 engines whereas assembly plant B needs 70 engines. Find how many engines should be shipped from each plant to each main assembly plant if shipping costs are to be kept to a minimum. Plant I x

y

A

B (80 –

– (70

x)

Plant II FIGURE 9

y)

Solution Let x denote the number of engines shipped from plant I to assembly plant A, and let y denote the number of engines shipped from plant I to assembly plant B. Since the requirements of assembly plants A and B are 80 and 70 engines, respectively, the number of engines shipped from plant II to assembly plants A and B are (80  x) and (70  y), respectively. These numbers may be displayed in a schematic. With the aid of the accompanying schematic (Figure 9) and the shipping cost schedule, we find that the total shipping cost incurred by Curtis-Roe is given by

C  100x  60y  120180  x2  70170  y2  14,500  20x  10y

Next, the production constraints on plants I and II lead to the inequalities x  y 100 180  x2  170  y2 110

The last inequality simplifies to x  y  40

Also, the requirements of the two main assembly plants lead to the inequalities x0

y0

80  x  0

The last two may be written as x 80 and y 70.

70  y  0

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6.2 LINEAR PROGRAMMING PROBLEMS

Summarizing, we have the following linear programming problem: Minimize the objective (cost) function C  14,500  20x  10y subject to the constraints x  y  40 x  y 100 x 80 y 70

where x  0 and y  0. You will be asked to complete the solution to this problem in Exercise 47, Section 6.3. APPLIED EXAMPLE 4 A Warehouse Problem Acrosonic manufactures its model F loudspeaker systems in two separate locations, plant I and plant II. The output at plant I is at most 400 per month, whereas the output at plant II is at most 600 per month. These loudspeaker systems are shipped to three warehouses that serve as distribution centers for the company. For the warehouses to meet their orders, the minimum monthly requirements of warehouses A, B, and C are 200, 300, and 400 systems, respectively. Shipping costs from plant I to warehouses A, B, and C are $20, $8, and $10 per loudspeaker system, respectively, and shipping costs from plant II to each of these warehouses are $12, $22, and $18, respectively. What should the shipping schedule be if Acrosonic wishes to meet the requirements of the distribution centers and at the same time keep its shipping costs to a minimum?

TABLE 3 Plant

A

Warehouse B

C

I II

20 12

8 22

10 18

Solution The respective shipping costs (in dollars) per loudspeaker system may be tabulated as in Table 3. Letting x1 denote the number of loudspeaker systems shipped from plant I to warehouse A, x2 the number shipped from plant I to warehouse B, and so on leads to Table 4. TABLE 4 Plant

I II Min. Req.

A

Warehouse B

C

Max. Prod.

x1 x4 200

x2 x5 300

x3 x6 400

400 600

From Tables 3 and 4 we see that the cost of shipping x1 loudspeaker systems from plant I to warehouse A is $20x1, the cost of shipping x2 loudspeaker systems from plant I to warehouse B is $8x2, and so on. Thus, the total monthly shipping cost (in dollars) incurred by Acrosonic is given by C  20x1  8x2  10x3  12x4  22x5  18x6

Next, the production constraints on plants I and II lead to the inequalities x1  x2  x3 400 x4  x5  x6 600

(see Table 4). Also, the minimum requirements of each of the three warehouses lead to the three inequalities x1  x4  200 x2  x5  300 x3  x6  400

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6 LINEAR PROGRAMMING

Summarizing, we have the following linear programming problem: Minimize subject to

C  20x1  8x2  10x3  12x4  22x5  18x6 x1  x2  x3 400 x4  x5  x6 600 x1  x4  200 x2  x5  300 x3  x6  400 x1  0, x2  0, . . . , x6  0

The solution to this problem will be completed in Section 6.5, Example 5.

6.2 Self-Check Exercise Gino Balduzzi, proprietor of Luigi’s Pizza Palace, allocates $9000 a month for advertising in two newspapers, the City Tribune and the Daily News. The City Tribune charges $300 for a certain advertisement, whereas the Daily News charges $100 for the same ad. Gino has stipulated that the ad is to appear in at least 15 but no more than 30 editions of the Daily News per month. The City Tribune has a daily circulation of 50,000, and the Daily News has a circulation of 20,000. Under these condi-

tions, determine how many ads Gino should place in each newspaper in order to reach the largest number of readers. Formulate but do not solve the problem. (The solution to this problem can be found in Exercise 3 of Solutions to Self-Check Exercises 6.3.) The solution to Self-Check Exercise 6.2 can be found on page 338.

6.2 Concept Questions 1. What is a linear programming problem? 2. Suppose you are asked to formulate a linear programming problem in two variables x and y. How would you express the fact that x and y are nonnegative? Why are these conditions often required in practical problems?

3. What is the difference between a maximization linear programming problem and a minimization linear programming problem?

6.2 Exercises Formulate but do not solve each of the following exercises as a linear programming problem. You will be asked to solve these problems later.

1. MANUFACTURING—PRODUCTION SCHEDULING A company manufactures two products, A and B, on two machines, I and II. It has been determined that the company will realize a profit of $3 on each unit of product A and a profit of $4 on each unit of product B. To manufacture a unit of product A requires 6 min on machine I and 5 min on machine II. To manufacture a unit of product B requires 9 min on machine I and 4 min on machine II. There are 5 hr of machine time available on machine I and 3 hr of machine time available on machine II in each work shift. How many units of each product should be produced in each shift to maximize the company’s profit?

2. MANUFACTURING—PRODUCTION SCHEDULING National Business Machines manufactures two models of fax machines: A and B. Each model A costs $100 to make, and each model B costs $150. The profits are $30 for each model A and $40 for each model B fax machine. If the total number of fax machines demanded per month does not exceed 2500 and the company has earmarked no more than $600,000/month for manufacturing costs, how many units of each model should National make each month in order to maximize its monthly profit? 3. MANUFACTURING—PRODUCTION SCHEDULING Kane Manufacturing has a division that produces two models of fireplace grates, model A and model B. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To pro-

6.2 LINEAR PROGRAMMING PROBLEMS

duce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $2.00, and the profit for each model B grate is $1.50. If 1000 lb of cast iron and 20 hr of labor are available for the production of grates per day, how many grates of each model should the division produce per day in order to maximize Kane’s profits? 4. MANUFACTURING—PRODUCTION SCHEDULING Refer to Exercise 3. Because of a backlog of orders on model A grates, the manager of Kane Manufacturing has decided to produce at least 150 of these models a day. Operating under this additional constraint, how many grates of each model should Kane produce to maximize profit? 5. MANUFACTURING—PRODUCTION SCHEDULING A division of the Winston Furniture Company manufactures dining tables and chairs. Each table requires 40 board feet of wood and 3 labor-hours. Each chair requires 16 board feet of wood and 4 labor-hours. The profit for each table is $45, and the profit for each chair is $20. In a certain week, the company has 3200 board feet of wood available, and 520 labor-hours. How many tables and chairs should Winston manufacture in order to maximize its profits? 6. MANUFACTURING—PRODUCTION SCHEDULING Refer to Exercise 5. If the profit for each table is $50 and the profit for each chair is $18, how many tables and chairs should Winston manufacture in order to maximize its profits? 7. FINANCE—ALLOCATION OF FUNDS Madison Finance has a total of $20 million earmarked for homeowner and auto loans. On the average, homeowner loans have a 10% annual rate of return whereas auto loans yield a 12% annual rate of return. Management has also stipulated that the total amount of homeowner loans should be greater than or equal to 4 times the total amount of automobile loans. Determine the total amount of loans of each type Madison should extend to each category in order to maximize its returns. 8. INVESTMENTS—ASSET ALLOCATION A financier plans to invest up to $500,000 in two projects. Project A yields a return of 10% on the investment whereas project B yields a return of 15% on the investment. Because the investment in project B is riskier than the investment in project A, the financier has decided that the investment in project B should not exceed 40% of the total investment. How much should she invest in each project in order to maximize the return on her investment? 9. MANUFACTURING—PRODUCTION SCHEDULING Acoustical Company manufactures a CD storage cabinet that can be bought fully assembled or as a kit. Each cabinet is processed in the fabrications department and the assembly department. If the fabrication department only manufactures fully assembled cabinets, then it can produce 200 units/day; and if it only manufactures kits, it can produce 200 units/day. If the assembly department only produces fully assembled cabinets, then it can produce 100 units/day; but if it only produces kits, then it can produce 300 units/day. Each fully assembled cabinet con-

335

tributes $50 to the profits of the company whereas each kit contributes $40 to its profits. How many fully assembled units and how many kits should the company produce per day in order to maximize its profits? 10. AGRICULTURE—CROP PLANNING A farmer plans to plant two crops, A and B. The cost of cultivating crop A is $40/acre whereas that of crop B is $60/acre. The farmer has a maximum of $7400 available for land cultivation. Each acre of crop A requires 20 labor-hours, and each acre of crop B requires 25 labor-hours. The farmer has a maximum of 3300 labor-hours available. If she expects to make a profit of $150/acre on crop A and $200/acre on crop B, how many acres of each crop should she plant in order to maximize her profit? 11. MINING—PRODUCTION Perth Mining Company operates two mines for the purpose of extracting gold and silver. The Saddle Mine costs $14,000/day to operate, and it yields 50 oz of gold and 3000 oz of silver each day. The Horseshoe Mine costs $16,000/day to operate, and it yields 75 oz of gold and 1000 oz of silver each day. Company management has set a target of at least 650 oz of gold and 18,000 oz of silver. How many days should each mine be operated so that the target can be met at a minimum cost? 12. TRANSPORTATION Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins and 160 standard cabins, whereas a type-B vessel has 80 deluxe cabins and 120 standard cabins. Under a charter agreement with Odyssey Travel Agency, Deluxe River Cruises is to provide Odyssey with a minimum of 360 deluxe and 680 standard cabins for their 15-day cruise in May. It costs $44,000 to operate a type-A vessel and $54,000 to operate a type-B vessel for that period. How many of each type vessel should be used in order to keep the operating costs to a minimum? 13. WATER SUPPLY The water-supply manager for a Midwest city needs to supply the city with at least 10 million gal of potable (drinkable) water per day. The supply may be drawn from the local reservoir or from a pipeline to an adjacent town. The local reservoir has a maximum daily yield of 5 million gallons of potable water, and the pipeline has a maximum daily yield of 10 million gallons. By contract, the pipeline is required to supply a minimum of 6 million gallons/day. If the cost for 1 million gallons of reservoir water is $300 and that for pipeline water is $500, how much water should the manager get from each source to minimize daily water costs for the city? 14. MANUFACTURING—PRODUCTION SCHEDULING Ace Novelty manufactures “Giant Pandas” and “Saint Bernards.” Each Panda requires 1.5 yd2 of plush, 30 ft3 of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 yd2 of plush, 35 ft3 of stuffing, and 8 pieces of trim. The profit for each Panda is $10 and the profit for each Saint Bernard is $15. If 3600 yd2 of plush, 66,000 ft3 of stuffing and 13,600 pieces of trim are available, how many of each of the stuffed animals should the company manufacture to maximize profit?

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6 LINEAR PROGRAMMING

15. NUTRITION—DIET PLANNING A nutritionist at the Medical Center has been asked to prepare a special diet for certain patients. She has decided that the meals should contain a minimum of 400 mg of calcium, 10 mg of iron, and 40 mg of vitamin C. She has further decided that the meals are to be prepared from foods A and B. Each ounce of food A contains 30 mg of calcium, 1 mg of iron, 2 mg of vitamin C, and 2 mg of cholesterol. Each ounce of food B contains 25 mg of calcium, 0.5 mg of iron, 5 mg of vitamin C, and 5 mg of cholesterol. Find how many ounces of each type of food should be used in a meal so that the cholesterol content is minimized and the minimum requirements of calcium, iron, and vitamin C are met. 16. SOCIAL PROGRAMS PLANNING AntiFam, a hunger-relief organization, has earmarked between $2 and $2.5 million (inclusive) for aid to two African countries, country A and country B. Country A is to receive between $1 million and $1.5 million (inclusive), and country B is to receive at least $0.75 million. It has been estimated that each dollar spent in country A will yield an effective return of $.60, whereas a dollar spent in country B will yield an effective return of $.80. How should the aid be allocated if the money is to be utilized most effectively according to these criteria? Hint: If x and y denote the amount of money to be given to country A and country B, respectively, then the objective function to be maximized is P  0.6x  0.8y.

17. ADVERTISING Everest Deluxe World Travel has decided to advertise in the Sunday editions of two major newspapers in town. These advertisements are directed at three groups of potential customers. Each advertisement in newspaper I is seen by 70,000 group-A customers, 40,000 group-B customers, and 20,000 group-C customers. Each advertisement in newspaper II is seen by 10,000 group-A, 20,000 group-B, and 40,000 group-C customers. Each advertisement in newspaper I costs $1000, and each advertisement in newspaper II costs $800. Everest would like their advertisements to be read by at least 2 million people from group A, 1.4 million people from group B, and 1 million people from group C. How many advertisements should Everest place in each newspaper to achieve its advertisement goals at a minimum cost? 18. MANUFACTURING—SHIPPING COSTS TMA manufactures 37-in. high-definition LCD televisions in two separate locations, location I and location II. The output at location I is at most 6000 televisions/month, whereas the output at location II is at most 5000 televisions/month. TMA is the main supplier of televisions to Pulsar Corporation, its holding company, which has priority in having all its requirements met. In a certain month, Pulsar placed orders for 3000 and 4000 televisions to be shipped to two of its factories located in city A and city B, respectively. The shipping costs (in dollars) per television from the two TMA plants to the two Pulsar factories are as follows: From TMA Location I Location II

To Pulsar Factories City A City B $6 $8

$4 $10

Find a shipping schedule that meets the requirements of both companies while keeping costs to a minimum. 19. INVESTMENTS—ASSET ALLOCATION A financier plans to invest up to $2 million in three projects. She estimates that project A will yield a return of 10% on her investment, project B will yield a return of 15% on her investment, and project C will yield a return of 20% on her investment. Because of the risks associated with the investments, she decided to put not more than 20% of her total investment in project C. She also decided that her investments in projects B and C should not exceed 60% of her total investment. Finally, she decided that her investment in project A should be at least 60% of her investments in projects B and C. How much should the financier invest in each project if she wishes to maximize the total returns on her investments? 20. INVESTMENTS—ASSET ALLOCATION Ashley has earmarked at most $250,000 for investment in three mutual funds: a money market fund, an international equity fund, and a growth-and-income fund. The money market fund has a rate of return of 6%/year, the international equity fund has a rate of return of 10%/year, and the growth-and-income fund has a rate of return of 15%/year. Ashley has stipulated that no more than 25% of her total portfolio should be in the growth-and-income fund and that no more than 50% of her total portfolio should be in the international equity fund. To maximize the return on her investment, how much should Ashley invest in each type of fund? 21. MANUFACTURING—PRODUCTION SCHEDULING A company manufactures products A, B, and C. Each product is processed in three departments: I, II, and III. The total available labor-hours per week for departments I, II, and III are 900, 1080, and 840, respectively. The time requirements (in hours per unit) and profit per unit for each product are as follows:

Dept. I Dept. II Dept. III Profit

Product A 2 3 2 $18

Product B 1 1 2 $12

Product C 2 2 1 $15

How many units of each product should the company produce in order to maximize its profit? 22. ADVERTISING As part of a campaign to promote its annual clearance sale, the Excelsior Company decided to buy television advertising time on Station KAOS. Excelsior’s advertising budget is $102,000. Morning time costs $3000/minute, afternoon time costs $1000/minute, and evening (prime) time costs $12,000/minute. Because of previous commitments, KAOS cannot offer Excelsior more than 6 min of prime time or more than a total of 25 min of advertising time over the 2 weeks in which the commercials are to be run. KAOS estimates that morning commercials are seen by 200,000 people, afternoon commercials are seen by 100,000 people, and evening com-

6.2 LINEAR PROGRAMMING PROBLEMS

mercials are seen by 600,000 people. How much morning, afternoon, and evening advertising time should Excelsior buy in order to maximize exposure of its commercials? 23. MANUFACTURING—PRODUCTION SCHEDULING Custom Office Furniture Company is introducing a new line of executive desks made from a specially selected grade of walnut. Initially, three different models—A, B, and C—are to be marketed. Each model A desk requires 1 14 hr for fabrication, 1 hr for assembly, and 1 hr for finishing; each model B desk requires 1 12 hr for fabrication, 1 hr for assembly, and 1 hr for finishing; each model C desk requires 1 12 hr, 34 hr, and 12 hr for fabrication, assembly, and finishing, respectively. The profit on each model A desk is $26, the profit on each model B desk is $28, and the profit on each model C desk is $24. The total time available in the fabrication department, the assembly department, and the finishing department in the first month of production is 310 hr, 205 hr, and 190 hr, respectively. To maximize Custom’s profit, how many desks of each model should be made in the month? 24. MANUFACTURING—SHIPPING COSTS Acrosonic of Example 4 also manufactures a model G loudspeaker system in plants I and II. The output at plant I is at most 800 systems/month whereas the output at plant II is at most 600/month. These loudspeaker systems are also shipped to the three warehouses—A, B, and C—whose minimum monthly requirements are 500, 400, and 400, respectively. Shipping costs from plant I to warehouse A, warehouse B, and warehouse C are $16, $20, and $22 per system, respectively, and shipping costs from plant II to each of these warehouses are $18, $16, and $14 per system, respectively. What shipping schedule will enable Acrosonic to meet the warehouses’ requirements and at the same time keep its shipping costs to a minimum? 25. MANUFACTURING—SHIPPING COSTS Steinwelt Piano manufactures uprights and consoles in two plants, plant I and plant II. The output of plant I is at most 300/month, whereas the output of plant II is at most 250/month. These pianos are shipped to three warehouses that serve as distribution centers for the company. To fill current and projected future orders, warehouse A requires a minimum of 200 pianos/month, warehouse B requires at least 150 pianos/month, and warehouse C requires at least 200 pianos/month. The shipping cost of each piano from plant I to warehouse A, warehouse B, and warehouse C is $60, $60, and $80, respectively, and the shipping cost of each piano from plant II to warehouse A, warehouse B, and warehouse C is $80, $70, and $50, respectively. What shipping schedule will enable Steinwelt to meet the warehouses’ requirements while keeping shipping costs to a minimum? 26. MANUFACTURING—PREFABRICATED HOUSING PRODUCTION Boise Lumber has decided to enter the lucrative prefabricated housing business. Initially, it plans to offer three models: standard, deluxe, and luxury. Each house is prefabricated and partially assembled in the factory, and the

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final assembly is completed on site. The dollar amount of building material required, the amount of labor required in the factory for prefabrication and partial assembly, the amount of on-site labor required, and the profit per unit are as follows:

Material Factory Labor (hr) On-site Labor (hr) Profit

Standard Model $6,000 240 180 $3,400

Deluxe Model $8,000 220 210 $4,000

Luxury Model $10,000 200 300 $5,000

For the first year’s production, a sum of $8.2 million is budgeted for the building material; the number of laborhours available for work in the factory (for prefabrication and partial assembly) is not to exceed 218,000 hr; and the amount of labor for on-site work is to be less than or equal to 237,000 labor-hours. Determine how many houses of each type Boise should produce (market research has confirmed that there should be no problems with sales) in order to maximize its profit from this new venture. 27. PRODUCTION—JUICE PRODUCTS CalJuice Company has decided to introduce three fruit juices made from blending two or more concentrates. These juices will be packaged in 2-qt (64-oz) cartons. One carton of pineapple–orange juice requires 8 oz each of pineapple and orange juice concentrates. One carton of orange–banana juice requires 12 oz of orange juice concentrate and 4 oz of banana pulp concentrate. Finally, one carton of pineapple–orange–banana juice requires 4 oz of pineapple juice concentrate, 8 oz of orange juice concentrate, and 4 oz of banana pulp. The company has decided to allot 16,000 oz of pineapple juice concentrate, 24,000 oz of orange juice concentrate, and 5000 oz of banana pulp concentrate for the initial production run. The company has also stipulated that the production of pineapple–orange–banana juice should not exceed 800 cartons. Its profit on one carton of pineapple–orange juice is $1.00, its profit on one carton of orange–banana juice is $.80, and its profit on one carton of pineapple– orange–banana juice is $.90. To realize a maximum profit, how many cartons of each blend should the company produce? 28. MANUFACTURING—COLD FORMULA PRODUCTION Beyer Pharmaceutical produces three kinds of cold formulas: formula I, formula II, and formula III. It takes 2.5 hr to produce 1000 bottles of formula I, 3 hr to produce 1000 bottles of formula II, and 4 hr to produce 1000 bottles of formula III. The profits for each 1000 bottles of formula I, formula II, and formula III are $180, $200, and $300, respectively. For a certain production run, there are enough ingredients on hand to make at most 9000 bottles of formula I, 12,000 bottles of formula II, and 6000 bottles of formula III. Furthermore, the time for the production run is limited to a maximum of 70 hr. How many bottles of each formula should be produced in this production run so that the profit is maximized?

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In Exercises 29 and 30, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

30. The problem Minimize C  2x  3y 2x  3y 6

subject to

29. The problem

x y0

Maximize P  xy subject to

x  0, y  0

2x  3y 12

is a linear programming problem.

2x  y 8 x  0, y  0

is a linear programming problem.

6.2 Solution to Self-Check Exercise Let x denote the number of ads to be placed in the City Tribune and y the number to be placed in the Daily News. The total cost for placing x ads in the City Tribune and y ads in the Daily News is 300x  100y dollars, and since the monthly budget is $9000, we must have

Finally, the objective function to be maximized is P  50,000x  20,000y

To summarize, we have the following linear programming problem:

300x  100y 9000

Next, the condition that the ad must appear in at least 15 but no more than 30 editions of the Daily News translates into the inequalities

Maximize P  50,000x  20,000y subject to

300x  100y 9000 y  15 y 30

y  15

x  0, y  0

y 30

6.3 Graphical Solution of Linear Programming Problems The Graphical Method Linear programming problems in two variables have relatively simple geometric interpretations. For example, the system of linear constraints associated with a twodimensional linear programming problem, unless it is inconsistent, defines a planar region or a line segment whose boundary is composed of straight-line segments and/or half-lines. Such problems are therefore amenable to graphical analysis. Consider the following two-dimensional linear programming problem: Maximize P  3x  2y subject to 2x  3y 12 2x  y 8 x  0, y  0

(7)

The system of linear inequalities in (7) defines the planar region S shown in Figure 10. Each point in S is a candidate for the solution of the problem at hand and is referred to as a feasible solution. The set S itself is referred to as a feasible set. Our goal is to find, from among all the points in the set S, the point(s) that optimizes the objective function P. Such a feasible solution is called an optimal solution and constitutes the solution to the linear programming problem under consideration.

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

339

y 10 2x + y = 8 5 P(3, 2) S

2x + 3y = 12

FIGURE 10

x

Each point in the feasible set S is a candidate for the optimal solution.

5

10

As noted earlier, each point P(x, y) in S is a candidate for the optimal solution to the problem at hand. For example, the point (1, 3) is easily seen to lie in S and is therefore in the running. The value of the objective function P at the point (1, 3) is given by P  3(1)  2(3)  9. Now, if we could compute the value of P corresponding to each point in S, then the point(s) in S that gave the largest value to P would constitute the solution set sought. Unfortunately, in most problems the number of candidates either is too large or, as in this problem, is infinite. Thus, this method is at best unwieldy and at worst impractical. Let’s turn the question around. Instead of asking for the value of the objective function P at a feasible point, let’s assign a value to the objective function P and ask whether there are feasible points that would correspond to the given value of P. Toward this end, suppose we assign a value of 6 to P. Then the objective function P becomes 3x  2y  6, a linear equation in x and y, and thus it has a graph that is a straight line L1 in the plane. In Figure 11, we have drawn the graph of this straight line superimposed on the feasible set S. y L2 L1

The line farthest from the origin that intersects S

5

P(3, 2) S FIGURE 11 A family of parallel lines that intersect the feasible set S

x 5

It is clear that each point on the straight-line segment given by the intersection of the straight line L1 and the feasible set S corresponds to the given value, 6, of P. For this reason the line L1 is called an isoprofit line. Let’s repeat the process, this time assigning a value of 10 to P. We obtain the equation 3x  2y  10 and the line L2 (see Figure 11), which suggests that there are feasible points that correspond to a larger value of P. Observe that the line L2 is parallel to the line L1 because both lines have slope equal to 32, which is easily seen by casting the corresponding equations in the slope-intercept form. In general, by assigning different values to the objective function, we obtain a family of parallel lines, each with slope equal to 32. Furthermore, a line corresponding to a larger value of P lies farther away from the origin than one with a smaller value of P. The implication is clear. To obtain the optimal solution(s) to the problem at hand, find the straight line, from this family of straight lines, that is farthest from the origin and still intersects the feasible set S. The required line is the one that

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6 LINEAR PROGRAMMING

passes through the point P(3, 2) (see Figure 11), so the solution to the problem is given by x  3, y  2, resulting in a maximum value of P  3(3)  2(2)  13. That the optimal solution to this problem was found to occur at a vertex of the feasible set S is no accident. In fact, the result is a consequence of the following basic theorem on linear programming, which we state without proof.

THEOREM 1 Linear Programming

If a linear programming problem has a solution then it must occur at a vertex, or corner point, of the feasible set S associated with the problem. Furthermore, if the objective function P is optimized at two adjacent vertices of S, then it is optimized at every point on the line segment joining these vertices, in which case there are infinitely many solutions to the problem. Theorem 1 tells us that our search for the solution(s) to a linear programming problem may be restricted to the examination of the set of vertices of the feasible set S associated with the problem. Since a feasible set S has finitely many vertices, the theorem suggests that the solution(s) to the linear programming problem may be found by inspecting the values of the objective function P at these vertices. Although Theorem 1 sheds some light on the nature of the solution of a linear programming problem, it does not tell us when a linear programming problem has a solution. The following theorem states some conditions that guarantee when a linear programming problem has a solution.

THEOREM 2 Existence of a Solution

Suppose we are given a linear programming problem with a feasible set S and an objective function P  ax  by. a. If S is bounded, then P has both a maximum and a minimum value on S. b. If S is unbounded and both a and b are nonnegative, then P has a minimum value on S provided that the constraints defining S include the inequalities x  0 and y  0. c. If S is the empty set, then the linear programming problem has no solution; that is, P has neither a maximum nor a minimum value. The method of corners, a simple procedure for solving linear programming problems based on Theorem 1, follows. The Method of Corners

1. 2. 3. 4.

Graph the feasible set. Find the coordinates of all corner points (vertices) of the feasible set. Evaluate the objective function at each corner point. Find the vertex that renders the objective function a maximum (minimum). If there is only one such vertex, then this vertex constitutes a unique solution to the problem. If the objective function is maximized (minimized) at two adjacent corner points of S, there are infinitely many optimal solutions given by the points on the line segment determined by these two vertices.

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

341

APPLIED EXAMPLE 1 Maximizing Profit We are now in a position to complete the solution to the production problem posed in Example 1, Section 6.2. Recall that the mathematical formulation led to the following linear programming problem: Maximize P  x  1.2y subject to 2x  y 180 x  3y 300 x  0, y  0

The feasible set S for the problem is shown in Figure 12.

Solution y

C(48, 84)

100 D(0, 100)

x + 3y = 300

S B (90, 0)

x FIGURE 12

A(0, 0)

The corner point that yields the maximum profit is C(48, 84).

100

200

300

2x + y = 180

The vertices of the feasible set are A(0, 0), B(90, 0), C(48, 84), and D(0, 100). The values of P at these vertices may be tabulated as follows: Vertex

A(0, 0) B(90, 0) C(48, 84) D(0, 100)

P  x  1.2y

0 90 148.8 120

From the table, we see that the maximum of P  x  1.2y occurs at the vertex (48, 84) and has a value of 148.8. Recalling what the symbols x, y, and P represent, we conclude that Ace Novelty would maximize its profit (a figure of $148.80) by producing 48 type-A souvenirs and 84 type-B souvenirs.

Explore & Discuss Consider the linear programming problem Maximize P  4x  3y subject to

2x  y 10 2x  3y 18 x  0, y  0

1. Sketch the feasible set S for the linear programming problem. 2. Draw the isoprofit lines superimposed on S corresponding to P  12, 16, 20, and 24, and show that these lines are parallel to each other. 3. Show that the solution to the linear programming problem is x  3 and y  4. Is this result the same as that found using the method of corners?

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6 LINEAR PROGRAMMING

APPLIED EXAMPLE 2 A Nutrition Problem Complete the solution of the nutrition problem posed in Example 2, Section 6.2. Solution Recall that the mathematical formulation of the problem led to the following linear programming problem in two variables:

Minimize C  6x  8y subject to 40x  10y  2400 10x  15y  2100 5x  15y  1500 x  0, y  0

The feasible set S defined by the system of constraints is shown in Figure 13. 40x + 10y = 2400

y

300 A(0, 240) S

200 10x + 15y = 2100 5x + 15y = 1500 100

B(30, 120) C(120, 60) D(300, 0)

FIGURE 13

100

The corner point that yields the minimum cost is B(30, 120).

200

300

x

The vertices of the feasible set S are A(0, 240), B(30, 120), C(120, 60), and D(300, 0). The values of the objective function C at these vertices are given in the following table: Vertex

A(0, 240) B(30, 120) C(120, 60) D(300, 0)

C  6x  8y

1920 1140 1200 1800

From the table, we can see that the minimum for the objective function C  6x  8y occurs at the vertex B(30, 120) and has a value of 1140. Thus, the individual should purchase 30 brand-A pills and 120 brand-B pills at a minimum cost of $11.40. EXAMPLE 3 A Linear Programming Problem with Multiple Solutions Find the maximum and minimum of P  2x  3y subject to the following system of linear inequalities: 2x  3y 30 x  y 5 x y 5 x 10 x  0, y  0

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

343

The feasible set S is shown in Figure 14. The vertices of the feasible set S are A(5, 0), B(10, 0), C110, 103 2, D(3, 8), and E(0, 5). The values of the objective function P at these vertices are given in the following table: Solution

P  2x  3y

Vertex

A(5, 0) B(10, 0) C110, 103 2 D(3, 8) E(0, 5)

10 20 30 30 15

From the table, we see that the maximum for the objective function P  2x  3y occurs at the vertices C110, 103 2 and D(3, 8). This tells us that every point on the line segment joining the points C110, 103 2 and D(3, 8) maximizes P, giving it a value of 30 at each of these points. From the table, it is also clear that P is minimized at the point (5, 0), where it attains a value of 10. y 2x + 3y = 30 –x + y = 5

x = 10

10 x+y=5

D(3, 8) 5

E(0, 5) S

C 10, 103

A(5, 0) x FIGURE 14

5

B(10, 0) 15

Every point lying on the line segment joining C and D maximizes P.

Explore & Discuss Consider the linear programming problem Maximize P  2x  3y subject to

2x  y 10 2x  3y 18 x  0, y  0

1. Sketch the feasible set S for the linear programming problem. 2. Draw the isoprofit lines superimposed on S corresponding to P  6, 8, 12, and 18, and show that these lines are parallel to each other. 3. Show that there are infinitely many solutions to the problem. Is this result as predicted by the method of corners?

We close this section by examining two situations in which a linear programming problem may have no solution.

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6 LINEAR PROGRAMMING

EXAMPLE 4 An Unbounded Linear Programming Problem with No Solution Solve the following linear programming problem:

y −2x + y = 4

Maximize P  x  2y subject to 2x  y 4 x  3y 3 x  0, y  0

S C(0, 4)

x − 3y = 3

The feasible set S for this problem is shown in Figure 15. Since the set S is unbounded (both x and y can take on arbitrarily large positive values), we see that we can make P as large as we please by making x and y large enough. This problem has no solution. The problem is said to be unbounded.

Solution A(0, 0) x B (3, 0) FIGURE 15 This maximization problem has no solution because the feasible set is unbounded.

EXAMPLE 5 An Infeasible Linear Programming Problem Solve the following linear programming problem: Maximize subject to

P  x  2y x  2y 4 2x  3y  12 x  0, y  0

y

Solution The half-planes described by the constraints (inequalities) have no points in common (Figure 16). Hence there are no feasible points and the problem has no solution. In this situation, we say that the problem is infeasible, or inconsistent. 2 x + 3y = 12

x x + 2y = 4 FIGURE 16 This problem is inconsistent because there is no point that satisfies all of the given inequalities.

The situations described in Examples 5 and 6 are unlikely to occur in well-posed problems arising from practical applications of linear programming. The method of corners is particularly effective in solving two-variable linear programming problems with a small number of constraints, as the preceding examples have amply demonstrated. Its effectiveness, however, decreases rapidly as the number of variables and/or constraints increases. For example, it may be shown that a linear programming problem in three variables and five constraints may have up to ten feasible corner points. The determination of the feasible corner points calls for the solution of ten 3  3 systems of linear equations and then the verification—by the substitution of each of these solutions into the system of constraints—to see if it is, in fact, a feasible point. When the number of variables and constraints goes up to five and ten, respectively (still a very small system from the standpoint of applications in economics), the number of vertices to be found and checked for feasible corner points increases dramatically to 252, and each of these vertices is found by solving a 5  5 linear system! For this reason, the method of corners is seldom used to solve linear programming problems; its redeeming value lies in the fact that much insight is gained into the nature of the solutions of linear programming problems through its use in solving two-variable problems.

6.3 Self-Check Exercises 1. Use the method of corners to solve the following linear programming problem: Maximize subject to

P  4x  5y x  2y 10 5x  3y 30 x  0, y  0

2. Use the method of corners to solve the following linear programming problem: Minimize

C  5x  3y

subject to

5x  3y  30 x  3y 0 x 2

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

3. Gino Balduzzi, proprietor of Luigi’s Pizza Palace, allocates $9000 a month for advertising in two newspapers, the City Tribune and the Daily News. The City Tribune charges $300 for a certain advertisement, whereas the Daily News charges $100 for the same ad. Gino has stipulated that the ad is to appear in at least 15 but no more than 30 editions of the Daily News per month. The City Tribune has a daily

345

circulation of 50,000, and the Daily News has a circulation of 20,000. Under these conditions, determine how many ads Gino should place in each newspaper in order to reach the largest number of readers. Solutions to Self-Check Exercises 6.3 can be found on page 350.

6.3 Concept Questions 1. a. What is the feasible set associated with a linear programming problem? b. What is a feasible solution of a linear programming problem?

c. What is an optimal solution of a linear programming problem? 2. Describe the method of corners.

6.3 Exercises In Exercises 1–6, find the maximum and/or minimum value(s) of the objective function on the feasible set S.

3. Z  3x  4y y (0, 20)

1. Z  2x  3y y

(4, 9)

(2, 8)

S (3, 10) S

(8, 5)

(4, 6)

(9, 0)

(1, 1)

x

x

4. Z  7x  9y 2. Z  3x  y

y y (0, 7)

(7, 9)

(1, 5) (2, 6)

S

S (4, 2) x

(2, 2) (10, 1)

(8, 0) x

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6 LINEAR PROGRAMMING

5. Z  x  4y

13. Maximize P  x  3y subject to 2x  y 6

y

xy 4 x 1 x  0, y  0

14. Maximize P  2x  5y subject to 2x  y 16

(4, 10) (12, 8)

2x  3y 24 y 6 x  0, y  0

S

(0, 6)

x (15, 0)

15. Minimize C  3x  4y subject to x  y  3 x  2y  4 x  0, y  0

6. Z  3x  2y y

16. Minimize C  2x  4y subject to the constraints of Exercise 15.

(3, 6)

17. Minimize C  3x  6y subject to x  2y  40 (1, 4)

S

x  y  30 x  0, y  0

(5, 4)

18. Minimize C  3x  y subject to the constraints of Exercise 17.

(3, 1) x

In Exercises 7–28, solve each linear programming problem by the method of corners.

7. Maximize P  2x  3y xy 6 subject to x 3 x  0, y  0

8. Maximize P  x  2y subject to xy 4 2x  y 5 x  0, y  0

9. Maximize P  2x  y subject to the constraints of Exercise 8. 10. Maximize P  4x  2y subject to xy 8 2x  y 10 x  0, y  0

11. Maximize P  x  8y subject to the constraints of Exercise 10. 12. Maximize P  3x  4y subject to x  3y 15 4x  y 16 x  0, y  0

19. Minimize C  2x  10y subject to 5x  2y  40 x  2y  20 y  3, x  0

20. Minimize C  2x  5y subject to 4x  y  40 2x  y  30 x  3y  30 x  0, y  0

21. Minimize C  10x  15y subject to x  y 10 3x  y  12 2x  3y  3 x  0, y  0

22. Maximize P  2x  5y subject to the constraints of Exercise 21. 23. Maximize P  3x  4y subject to x  2y 50 5x  4y 145 2x  y  25 y  5, x  0

24. Maximize P  4x  3y subject to the constraints of Exercise 23. 25. Maximize P  2x  3y subject to x  y 48 x  3y  60 9x  5y 320 x  10, y  0

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

26. Minimize C  5x  3y subject to the constraints of Exercise 25. 27. Find the maximum and minimum of P  10x  12y subject to 5x  2y  63 x  y  18 3x  2y 51 x  0, y  0

28. Find the maximum and minimum of P  4x  3y subject to 3x  5y  20 3x  y 16 2x  y 1 x  0, y  0 The problems in Exercises 29–46 correspond to those in Exercises 1–18, Section 6.2. Use the results of your previous work to help you solve these problems.

29. MANUFACTURING—PRODUCTION SCHEDULING A company manufactures two products, A and B, on two machines, I and II. It has been determined that the company will realize a profit of $3/unit of product A and a profit of $4/unit of product B. To manufacture a unit of product A requires 6 min on machine I and 5 min on machine II. To manufacture a unit of product B requires 9 min on machine I and 4 min on machine II. There are 5 hr of machine time available on machine I and 3 hr of machine time available on machine II in each work shift. How many units of each product should be produced in each shift to maximize the company’s profit? What is the optimal profit? 30. MANUFACTURING—PRODUCTION SCHEDULING National Business Machines manufactures two models of fax machines: A and B. Each model A costs $100 to make, and each model B costs $150. The profits are $30 for each model A and $40 for each model B fax machine. If the total number of fax machines demanded per month does not exceed 2500 and the company has earmarked no more than $600,000/month for manufacturing costs, how many units of each model should National make each month in order to maximize its monthly profit? What is the optimal profit? 31. MANUFACTURING—PRODUCTION SCHEDULING Kane Manufacturing has a division that produces two models of fireplace grates, model A and model B. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $2.00, and the profit for each model B grate is $1.50. If 1000 lb of cast iron and 20 labor-hours are available for the production of fireplace grates per day, how many grates of each model should the division produce in order to maximize Kane’s profit? What is the optimal profit?

347

32. MANUFACTURING—PRODUCTION SCHEDULING Refer to Exercise 31. Because of a backlog of orders for model A grates, Kane’s manager had decided to produce at least 150 of these models a day. Operating under this additional constraint, how many grates of each model should Kane produce to maximize profit? What is the optimal profit? 33. MANUFACTURING—PRODUCTION SCHEDULING A division of the Winston Furniture Company manufactures dining tables and chairs. Each table requires 40 board feet of wood and 3 labor-hours. Each chair requires 16 board feet of wood and 4 labor-hours. The profit for each table is $45, and the profit for each chair is $20. In a certain week, the company has 3200 board feet of wood available and 520 labor-hours available. How many tables and chairs should Winston manufacture in order to maximize its profit? What is the maximum profit? 34. MANUFACTURING—PRODUCTION SCHEDULING Refer to Exercise 33. If the profit for each table is $50 and the profit for each chair is $18, how many tables and chairs should Winston manufacture in order to maximize its profit? What is the maximum profit? 35. FINANCE—ALLOCATION OF FUNDS Madison Finance has a total of $20 million earmarked for homeowner and auto loans. On the average, homeowner loans have a 10% annual rate of return, whereas auto loans yield a 12% annual rate of return. Management has also stipulated that the total amount of homeowner loans should be greater than or equal to 4 times the total amount of automobile loans. Determine the total amount of loans of each type that Madison should extend to each category in order to maximize its returns. What are the optimal returns? 36. INVESTMENTS—ASSET ALLOCATION A financier plans to invest up to $500,000 in two projects. Project A yields a return of 10% on the investment whereas project B yields a return of 15% on the investment. Because the investment in project B is riskier than the investment in project A, the financier has decided that the investment in project B should not exceed 40% of the total investment. How much should she invest in each project in order to maximize the return on her investment? What is the maximum return? 37. MANUFACTURING—PRODUCTION SCHEDULING Acoustical manufactures a CD storage cabinet that can be bought fully assembled or as a kit. Each cabinet is processed in the fabrications department and the assembly department. If the fabrication department only manufactures fully assembled cabinets, then it can produce 200 units/day; and if it only manufactures kits, it can produce 200 units/day. If the assembly department produces only fully assembled cabinets, then it can produce 100 units/day; but if it produces only kits, then it can produce 300 units/day. Each fully assembled cabinet contributes $50 to the profits of the company whereas each kit contributes $40 to its profits. How many fully assembled units and how many kits should the company produce per day in order to maximize its profit? What is the optimal profit?

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6 LINEAR PROGRAMMING

38. AGRICULTURE—CROP PLANNING A farmer plans to plant two crops, A and B. The cost of cultivating crop A is $40/acre whereas that of crop B is $60/acre. The farmer has a maximum of $7400 available for land cultivation. Each acre of crop A requires 20 labor-hours, and each acre of crop B requires 25 labor-hours. The farmer has a maximum of 3300 labor-hours available. If she expects to make a profit of $150/acre on crop A and $200/acre on crop B, how many acres of each crop should she plant in order to maximize her profit? What is the optimal profit? 39. MINING—PRODUCTION Perth Mining Company operates two mines for the purpose of extracting gold and silver. The Saddle Mine costs $14,000/day to operate, and it yields 50 oz of gold and 3000 oz of silver each day. The Horseshoe Mine costs $16,000/day to operate, and it yields 75 oz of gold and 1000 oz of silver each day. Company management has set a target of at least 650 oz of gold and 18,000 oz of silver. How many days should each mine be operated so that the target can be met at a minimum cost? What is the minimum cost? 40. TRANSPORTATION Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins and 160 standard cabins, whereas a type-B vessel has 80 deluxe cabins and 120 standard cabins. Under a charter agreement with Odyssey Travel Agency, Deluxe River Cruises is to provide Odyssey with a minimum of 360 deluxe and 680 standard cabins for their 15-day cruise in May. It costs $44,000 to operate a type-A vessel and $54,000 to operate a type-B vessel for that period. How many of each type vessel should be used in order to keep the operating costs to a minimum? What is the minimum cost? 41. WATER SUPPLY The water-supply manager for a Midwest city needs to supply the city with at least 10 million gal of potable (drinkable) water per day. The supply may be drawn from the local reservoir or from a pipeline to an adjacent town. The local reservoir has a maximum daily yield of 5 million gal of potable water, and the pipeline has a maximum daily yield of 10 million gallons. By contract, the pipeline is required to supply a minimum of 6 million gallons/day. If the cost for 1 million gallons of reservoir water is $300 and that for pipeline water is $500, how much water should the manager get from each source to minimize daily water costs for the city? What is the minimum daily cost? 42. MANUFACTURING—PRODUCTION SCHEDULING Ace Novelty manufactures “Giant Pandas” and “Saint Bernards.” Each Panda requires 1.5 yd2 of plush, 30 ft3 of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 yd2 of plush, 35 ft3 of stuffing, and 8 pieces of trim. The profit for each Panda is $10, and the profit for each Saint Bernard is $15. If 3600 yd2 of plush, 66,000 ft3 of stuffing and 13,600 pieces of trim are available, how many of each of the stuffed animals should the company manufacture to maximize profit? What is the maximum profit? 43. NUTRITION—DIET PLANNING A nutritionist at the Medical Center has been asked to prepare a special diet for certain patients. She has decided that the meals should contain a minimum of 400 mg of calcium, 10 mg of iron, and 40 mg

of vitamin C. She has further decided that the meals are to be prepared from foods A and B. Each ounce of food A contains 30 mg of calcium, 1 mg of iron, 2 mg of vitamin C, and 2 mg of cholesterol. Each ounce of food B contains 25 mg of calcium, 0.5 mg of iron, 5 mg of vitamin C, and 5 mg of cholesterol. Find how many ounces of each type of food should be used in a meal so that the cholesterol content is minimized and the minimum requirements of calcium, iron, and vitamin C are met. 44. SOCIAL PROGRAMS PLANNING AntiFam, a hunger-relief organization, has earmarked between $2 and $2.5 million (inclusive) for aid to two African countries, country A and country B. Country A is to receive between $1 million and $1.5 million (inclusive), and country B is to receive at least $0.75 million. It has been estimated that each dollar spent in country A will yield an effective return of $.60, whereas a dollar spent in country B will yield an effective return of $.80. How should the aid be allocated if the money is to be utilized most effectively according to these criteria? Hint: If x and y denote the amount of money to be given to country A and country B, respectively, then the objective function to be maximized is P  0.6x  0.8y.

45. ADVERTISING Everest Deluxe World Travel has decided to advertise in the Sunday editions of two major newspapers in town. These advertisements are directed at three groups of potential customers. Each advertisement in newspaper I is seen by 70,000 group-A customers, 40,000 group-B customers, and 20,000 group-C customers. Each advertisement in newspaper II is seen by 10,000 group-A, 20,000 group-B, and 40,000 group-C customers. Each advertisement in newspaper I costs $1000, and each advertisement in newspaper II costs $800. Everest would like their advertisements to be read by at least 2 million people from group A, 1.4 million people from group B, and 1 million people from group C. How many advertisements should Everest place in each newspaper to achieve its advertising goals at a minimum cost? What is the minimum cost? Hint: Use different scales for drawing the feasible set.

46. MANUFACTURING—SHIPPING COSTS TMA manufactures 37-in. high-definition LCD televisions in two separate locations, locations I and II. The output at location I is at most 6000 televisions/month, whereas the output at location II is at most 5000 televisions/month. TMA is the main supplier of televisions to the Pulsar Corporation, its holding company, which has priority in having all its requirements met. In a certain month, Pulsar placed orders for 3000 and 4000 televisions to be shipped to two of its factories located in city A and city B, respectively. The shipping costs (in dollars) per television from the two TMA plants to the two Pulsar factories are as follows: From TMA Location I Location II

To Pulsar Factories City A City B $6 $4 $8 $10

Find a shipping schedule that meets the requirements of both companies while keeping costs to a minimum.

6.3 GRAPHICAL SOLUTION OF LINEAR PROGRAMMING PROBLEMS

47. Complete the solution to Example 3, Section 6.2. 48. MANUFACTURING—PRODUCTION SCHEDULING Bata Aerobics manufactures two models of steppers used for aerobic exercises. Manufacturing each luxury model requires 10 lb of plastic and 10 min of labor. Manufacturing each standard model requires 16 lb of plastic and 8 min of labor. The profit for each luxury model is $40, and the profit for each standard model is $30. If 6000 lb of plastic and 60 laborhours are available for the production of the steppers per day, how many steppers of each model should Bata produce each day in order to maximize its profit? What is the optimal profit? 49. INVESTMENT PLANNING Patricia has at most $30,000 to invest in securities in the form of corporate stocks. She has narrowed her choices to two groups of stocks: growth stocks that she assumes will yield a 15% return (dividends and capital appreciation) within a year and speculative stocks that she assumes will yield a 25% return (mainly in capital appreciation) within a year. Determine how much she should invest in each group of stocks in order to maximize the return on her investments within a year if she has decided to invest at least 3 times as much in growth stocks as in speculative stocks. 50. VETERINARY SCIENCE A veterinarian has been asked to prepare a diet for a group of dogs to be used in a nutrition study at the School of Animal Science. It has been stipulated that each serving should be no larger than 8 oz and must contain at least 29 units of nutrient I and 20 units of nutrient II. The vet has decided that the diet may be prepared from two brands of dog food: brand A and brand B. Each ounce of brand A contains 3 units of nutrient I and 4 units of nutrient II. Each ounce of brand B contains 5 units of nutrient I and 2 units of nutrient II. Brand A costs 3 cents/ounce and brand B costs 4 cents/ounce. Determine how many ounces of each brand of dog food should be used per serving to meet the given requirements at a minimum cost. 51. MARKET RESEARCH Trendex, a telephone survey company, has been hired to conduct a television-viewing poll among urban and suburban families in the Los Angeles area. The client has stipulated that a maximum of 1500 families is to be interviewed. At least 500 urban families must be interviewed, and at least half of the total number of families interviewed must be from the suburban area. For this service, Trendex will be paid $6000 plus $8 for each completed interview. From previous experience, Trendex has determined that it will incur an expense of $4.40 for each successful interview with an urban family and $5 for each successful interview with a suburban family. How many urban and suburban families should Trendex interview in order to maximize its profit?

349

53. An optimal solution of a linear programming problem can occur inside the feasible set of the problem. 54. If a maximization problem has no solution, then the feasible set associated with the linear programming problem must be unbounded. 55. Suppose you are given the following linear programming problem: Maximize P  ax  by on the unbounded feasible set S shown in the accompanying figure. y

S

x

a. If a  0 or b  0, then the linear programming problem has no optimal solution. b. If a 0 and b 0, then the linear programming problem has at least one optimal solution. 56. Suppose you are given the following linear programming problem: Maximize P  ax  by, where a  0 and b  0, on the feasible set S shown in the accompanying figure. y

Q S x

Explain, without using Theorem 1, why the optimal solution of the linear programming problem cannot occur at the point Q. 57. Suppose you are given the following linear programming problem: Maximize P  ax  by, where a  0 and b  0, on the feasible set S shown in the accompanying figure. y A Q B S x

In Exercises 52–55, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

Explain, without using Theorem 1, why the optimal solution of the linear programming problem cannot occur at the point Q unless the problem has infinitely many solutions lying along the line segment joining the vertices A and B.

52. An optimal solution of a linear programming problem is a feasible solution, but a feasible solution of a linear programming problem need not be an optimal solution.

Hint: Let A(x1, y1) and B(x2, y2). Then Q1x, y2, where x  x1  1x2  x1 2t and y  y1  1y2  y1 2t with 0 t 1. Study the value of P at and near Q.

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6 LINEAR PROGRAMMING

58. Consider the linear programming problem

59. Consider the linear programming problem

Maximize

P  2x  7y

Minimize

C  2x  5y

subject to

2x  y  8

subject to

x y 3

xy6

2x  y 4

x  0, y  0

5x  8y  40

a. Sketch the feasible set S. b. Find the corner points of S. c. Find the values of P at the corner points of S found in part (b). d. Show that the linear programming problem has no (optimal) solution. Does this contradict Theorem 1?

x  0, y  0

a. Sketch the feasible set. b. Find the solution(s) of the linear programming problem, if it exists.

6.3 Solutions to Self-Check Exercises y

1. The feasible set S for the problem was graphed in the solution to Exercise 1, Self-Check Exercises 6.1. It is reproduced in the following figure.

10 S 20 3

B 2, y D(0, 5) A 5, C S

30 20 7, 7

5 3

x 10 x

A(0, 0)

B(6, 0)

Evaluating the objective function C  5x  3y at each corner point, we obtain the table The values of the objective function P at the vertices of S are summarized in the following table. Vertex A(0, 0)

P  4 x  5y 0

B(6, 0)

C1 307 , 207 2 D(0, 5)

24 220 7

 3137 25

From the table, we see that the maximum for the objective function P is attained at the vertex C1 307, 207 2. Therefore, the solution to the problem is x  307, y  207, and P  3137. 2. The feasible set S for the problem was graphed in the solution to Exercise 2, Self-Check Exercises 6.1. It is reproduced in the following figure.

Vertex

C  5x  3y

A15, 53 2

30

B12,

30

20 3 2

We conclude that (i) the objective function is minimized at every point on the line segment joining the points 15, 53 2 and 12, 203 2, and (ii) the minimum value of C is 30. 3. Refer to Self-Check Exercise 6.2. The problem is to maximize P  50,000x  20,000y subject to 300x  100y 9000 y  15 y 30 x  0, y  0

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

The feasible set S for the problem is shown in the following figure.

351

Evaluating the objective function P  50,000x  20,000y at each vertex of S, we obtain

y

D (0, 30)

C(20, 30)

y = 30

Vertex A(0, 15) B(25, 15) C(20, 30) D(0, 30)

P  50,000x  20,000y 300,000 1,550,000 1,600,000 600,000

S A(0, 15)

B(25, 15)

y = 15

From the table, we see that P is maximized when x  20 and y  30. Therefore, Gino should place 20 ads in the City Tribune and 30 in the Daily News.

x 10

20

30

6.4 The Simplex Method: Standard Maximization Problems The Simplex Method As mentioned earlier, the method of corners is not suitable for solving linear programming problems when the number of variables or constraints is large. Its major shortcoming is that a knowledge of all the corner points of the feasible set S associated with the problem is required. What we need is a method of solution that is based on a judicious selection of the corner points of the feasible set S, thereby reducing the number of points to be inspected. One such technique, called the simplex method, was developed in the late 1940s by George Dantzig and is based on the Gauss–Jordan elimination method. The simplex method is readily adaptable to the computer, which makes it ideally suitable for solving linear programming problems involving large numbers of variables and constraints. Basically, the simplex method is an iterative procedure; that is, it is repeated over and over again. Beginning at some initial feasible solution (a corner point of the feasible set S, usually the origin), each iteration brings us to another corner point of S, usually with an improved (but certainly no worse) value of the objective function. The iteration is terminated when the optimal solution is reached (if it exists). In this section, we describe the simplex method for solving a large class of problems that are referred to as standard maximization problems. Before stating a formal procedure for solving standard linear programming problems based on the simplex method, let’s consider the following analysis of a twovariable problem. The ensuing discussion will clarify the general procedure and at the same time enhance our understanding of the simplex method by examining the motivation that led to the steps of the procedure.

A Standard Linear Programming Problem

A standard maximization problem is one in which 1. The objective function is to be maximized. 2. All the variables involved in the problem are nonnegative. 3. All other linear constraints may be written so that the expression involving the variables is less than or equal to a nonnegative constant.

352

6 LINEAR PROGRAMMING

Morgan Wilson

PORTFOLIO

A

s a land use planner for the city of Burien, Washington, I assist property owners every day in the development of their land. By definition, land use planners develop plans and recommend policies for managing land use. To do this, I must take into account many existing and potential factors such as public transportation, zoning laws, and other municipal laws. By using the basic ideas of linear programming, I work with the property owners to figure out maximum and minimum use requirements for each individual situation. Then, I am able to review and evaluate proposals for land use plans and prepare recommendations. All this is necessary to process an application for a land development permit. Here’s how it works. A property owner who wants to start a business on a vacant commercially zoned piece of property comes to me. We have a discussion to find out what type of commercial zone the property is in and whether the use is permitted or would require additional land use review. If the use is permitted and no further land use review is required, I let the applicant know what criteria have to be met and shown on the building plans. At this point, the applicant begins working with his or her building contractor, architect, or engineer and landscape architect to meet the zoning code criteria. Once the applicant has worked with one or more of these professionals, building

plans can be submitted for review. The plans are routed to several different departments (building, engineer, public works, and the fire department). Because I am the land use planner for the project, one set of plans is routed to my desk for review. During this review, I determine whether or not the zoning requirements have been met in order to make a final determination of the application. These zoning requirements are assessed by asking the applicant to give us a site plan showing lot area measurements, building and impervious surface coverage calculations, and building setbacks, just to name a few. Additionally, I have to determine the parking requirements. How many off-street parking spaces are required? What are the isle widths? Is there enough room for backing up? Then, I look at the landscaping requirements. Plans need to be drawn up by a landscape architect and list specifics about the location, size, and types of plants that will be used. By weighing all these factors and measurements, I can determine the viability of a land development project. The basic ideas of linear programming are fundamentally at the heart of this determination and are key to the day-to-day choices that I must make in my profession.

© Martin Shields/Alamy

TITLE Land Use Planner INSTITUTION City of Burien

Consider the linear programming problem presented at the beginning of Section 6.3:

y

Maximize P  3x  2y subject to 2x  3y 12 2x  y 8 x  0, y  0

D(0, 4)

C (3, 2) S B(4, 0) A(0, 0) FIGURE 17 The optimal solution occurs at C(3, 2).

x

(8) (9)

You can easily verify that this is a standard maximization problem. The feasible set S associated with this problem is reproduced in Figure 17, where we have labeled the four feasible corner points A(0, 0), B(4, 0), C(3, 2), and D(0, 4). Recall that the optimal solution to the problem occurs at the corner point C(3, 2). To solve this problem using the simplex method, we first replace the system of inequality constraints (9) with a system of equality constraints. This may be accomplished by using nonnegative variables called slack variables. Let’s begin by considering the inequality 2x  3y 12

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

353

Observe that the left-hand side of this equation is always less than or equal to the righthand side. Therefore, by adding a nonnegative variable u to the left-hand side to compensate for this difference, we obtain the equality 2x  3y  u  12

For example, if x  1 and y  1 [you can see by referring to Figure 17 that the point (1, 1) is a feasible point of S], then u  7, because 2(1)  3(1)  7  12

If x  2 and y  1 [the point (2, 1) is also a feasible point of S], then u  5, because 2(2)  3(1)  5  12

The variable u is a slack variable. Similarly, the inequality 2x  y 8 is converted into the equation 2x  y  √  8 through the introduction of the slack variable √. System (9) of linear inequalities may now be viewed as the system of linear equations 2x  3y  u 2x  y

 12 √ 8

where x, y, u, and √ are all nonnegative. Finally, rewriting the objective function (8) in the form 3x  2y  P  0, where the coefficient of P is 1, we are led to the following system of linear equations: 2x  3y  u 2x  y

 12 √

3x  2y

 8

(10)

P 0

Since System (10) consists of three linear equations in the five variables x, y, u, √, and P, we may solve for three of the variables in terms of the other two. Thus, there are infinitely many solutions to this system expressible in terms of two parameters. Our linear programming problem is now seen to be equivalent to the following: From among all the solutions of System (10) for which x, y, u, and √ are nonnegative (such solutions are called feasible solutions), determine the solution(s) that maximizes P. The augmented matrix associated with System (10) is Nonbasic variables



앗

앗 앗 앗 앗

x

y

2 2 3

u

√

Basic variables Column of constants 앗

P

3 1 0 0 1 0 1 0 2 0 0 1

 12 8 0

(11)

Observe that each of the u-, √-, and P-columns of the augmented matrix (11) is a unit column (see page 254). The variables associated with unit columns are called basic variables; all other variables are called nonbasic variables. Now, the configuration of the augmented matrix (11) suggests that we solve for the basic variables u, √, and P in terms of the nonbasic variables x and y, obtaining u  12  2x  3y √  8  2x  y P

3x  2y

(12)

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6 LINEAR PROGRAMMING

Of the infinitely many feasible solutions obtainable by assigning arbitrary nonnegative values to the parameters x and y, a particular solution is obtained by letting x  0 and y  0. In fact, this solution is given by x0

y0

u  12

√8

P0

Such a solution, obtained by setting the nonbasic variables equal to zero, is called a basic solution of the system. This particular solution corresponds to the corner point A(0, 0) of the feasible set associated with the linear programming problem (see Figure 17). Observe that P  0 at this point. Now, if the value of P cannot be increased, we have found the optimal solution to the problem at hand. To determine whether the value of P can in fact be improved, let’s turn our attention to the objective function in (8). Since the coefficients of both x and y are positive, the value of P can be improved by increasing x and/or y—that is, by moving away from the origin. Note that we arrive at the same conclusion by observing that the last row of the augmented matrix (11) contains entries that are negative. (Compare the original objective function, P  3x  2y, with the rewritten objective function, 3x  2y  P  0.) Continuing our quest for an optimal solution, our next task is to determine whether it is more profitable to increase the value of x or that of y (increasing x and y simultaneously is more difficult). Since the coefficient of x is greater than that of y, a unit increase in the x-direction will result in a greater increase in the value of the objective function P than a unit increase in the y-direction. Thus, we should increase the value of x while holding y constant. How much can x be increased while holding y  0? Upon setting y  0 in the first two equations of System (12), we see that u  12  2x √  8  2x

(13)

Since u must be nonnegative, the first equation of System (13) implies that x cannot exceed 122, or 6. The second equation of System (13) and the nonnegativity of √ implies that x cannot exceed 82, or 4. Thus, we conclude that x can be increased by at most 4. Now, if we set y  0 and x  4 in System (12), we obtain the solution x4

y0

u4

√0

P  12

which is a basic solution to System (10), this time with y and √ as nonbasic variables. (Recall that the nonbasic variables are precisely the variables that are set equal to zero.) Let’s see how this basic solution may be found by working with the augmented matrix of the system. Since x is to replace √ as a basic variable, our aim is to find an augmented matrix that is equivalent to the matrix (11) and has a configuration in which the x-column is in the unit form

 0 1 0

replacing what is presently the form of the √-column in augmented matrix (11). This may be accomplished by pivoting about the circled number 2. x 2 £ 2 3

y 3 1 2

u 1 0 0

√ 0 1 0

P Const. x 0 12 2 1 2 R2 0 † 8 § ⎯→ £ 1 1 0 3

y 3 1 2

2

u 1 0 0

√ 0 1 2

0

P Const. 0 12 0 † 4§ 1 0

(14)

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

R1  2R2 ⎯⎯⎯→ R3  3R2

x y u √ 0 2 1 1 1 1 £1 0 2 2 1 3 0 2 0 2

P 0 0 1

Const. 4 3 4§ 12

355

(15)

Using System (15), we now solve for the basic variables x, u, and P in terms of the nonbasic variables y and √, obtaining 1 x 4 y 2 u  4  2y  1 P  12  y  2

1 √ 2 √ 3 √ 2

Setting the nonbasic variables y and √ equal to zero gives x4 y D(0, 4)

C (3, 2) S B(4, 0) A(0, 0) FIGURE 18 One iteration has taken us from A(0, 0), where P  0, to B(4, 0), where P  12.

x

y0

u4

√0

P  12

as before. We have now completed one iteration of the simplex procedure, and our search has brought us from the feasible corner point A(0, 0), where P  0, to the feasible corner point B(4, 0), where P attained a value of 12, which is certainly an improvement! (See Figure 18.) Before going on, let’s introduce the following terminology. The circled element 2 in the first augmented matrix of (14), which was to be converted into a 1, is called a pivot element. The column containing the pivot element is called the pivot column. The pivot column is associated with a nonbasic variable that is to be converted to a basic variable. Note that the last entry in the pivot column is the negative number with the largest absolute value to the left of the vertical line in the last row—precisely the criterion for choosing the direction of maximum increase in P. The row containing the pivot element is called the pivot row. The pivot row can also be found by dividing each positive number in the pivot column into the corresponding number in the last column (the column of constants). The pivot row is the one with the smallest ratio. In the augmented matrix (14), the pivot row is the second row because the ratio 28, or 4, is less than the ratio 122, or 6. (Compare this with the earlier analysis pertaining to the determination of the largest permissible increase in the value of x.) The following is a summary of the procedure for selecting the pivot element.

Selecting the Pivot Element

1. Select the pivot column: Locate the most negative entry to the left of the vertical line in the last row. The column containing this entry is the pivot column. (If there is more than one such column, choose any one.) 2. Select the pivot row: Divide each positive entry in the pivot column into its corresponding entry in the column of constants. The pivot row is the row corresponding to the smallest ratio thus obtained. (If there is more than one such entry, choose any one.) 3. The pivot element is the element common to both the pivot column and the pivot row.

Continuing with the solution to our problem, we observe that the last row of the augmented matrix (15) contains a negative number—namely, 12. This indicates that

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6 LINEAR PROGRAMMING

P is not maximized at the feasible corner point B(4, 0), so another iteration is required. Without once again going into a detailed analysis, we proceed immediately to the selection of a pivot element. In accordance with the rules, we perform the necessary row operations as follows: Pivot row 씮

1 2 R1

⎯→

 

x y u √ P 1 0 1 2  12 0 1 1 0 0 1 2 2 3 1 0  12 0 2

2 4 12



x y u √ P 1  1 0 0 1 2 2 3 0 1 0  14 4 1 5 1 0 0 4 4

2 3 13

y R2  12 R1 ⎯⎯⎯→ R3  12 R1

D(0, 4)

C (3, 2) S B(4, 0)

x

A(0, 0) FIGURE 19 The next iteration has taken us from B(4, 0), where P  12, to C(3, 2), where P  13.

y u √ P 2 1 1 0 1 1 0 0 2 2 1 3 1  2 0 2

x 0 1 0

앖 Pivot column

Ratio



4 4 12

4 2  2 4 1/2  8

 

Interpreting the last augmented matrix in the usual fashion, we find the basic solution x  3, y  2, and P  13. Since there are no negative entries in the last row, the solution is optimal and P cannot be increased further. The optimal solution is the feasible corner point C(3, 2) (Figure 19). Observe that this agrees with the solution we found using the method of corners in Section 6.3. Having seen how the simplex method works, let’s list the steps involved in the procedure. The first step is to set up the initial simplex tableau. Setting Up the Initial Simplex Tableau

1. Transform the system of linear inequalities into a system of linear equations by introducing slack variables. 2. Rewrite the objective function P  c1x1  c2x2      cn xn

in the form c1x1  c2x2      cn xn  P  0

where all the variables are on the left and the coefficient of P is 1. Write this equation below the equations of step 1. 3. Write the tableau associated with this system of linear equations.

EXAMPLE 1 Set up the initial simplex tableau for the linear programming problem posed in Example 1, Section 6.2. Solution

The problem at hand is to maximize P  x  1.2y

or, equivalently, Px

6 y 5

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

357

subject to 2x  y 180 x  3y 300 x  0, y  0

(16)

This is a standard maximization problem and may be solved by the simplex method. Since System (16) has two linear inequalities (other than x  0, y  0), we introduce the two slack variables u and √ to convert it to a system of linear equations: 2x  y  u  180 x  3y  √  300

Next, by rewriting the objective function in the form x 

6 5

yP0

where the coefficient of P is 1, and placing it below the system of equations, we obtain the system of linear equations 2x  y  u  180 x  3y √  300 6 x  y P 0 5

The initial simplex tableau associated with this system is y

2 1

1 1 0 0 3 0 1 0

1

 65

u

√

x

0

0

P

1

Constant 180 300 0

Before completing the solution to the problem posed in Example 1, let’s summarize the main steps of the simplex method.

The Simplex Method

1. Set up the initial simplex tableau. 2. Determine whether the optimal solution has been reached by examining all entries in the last row to the left of the vertical line. a. If all the entries are nonnegative, the optimal solution has been reached. Proceed to step 4. b. If there are one or more negative entries, the optimal solution has not been reached. Proceed to step 3. 3. Perform the pivot operation. Locate the pivot element and convert it to a 1 by dividing all the elements in the pivot row by the pivot element. Using row operations, convert the pivot column into a unit column by adding suitable multiples of the pivot row to each of the other rows as required. Return to step 2. 4. Determine the optimal solution(s). The value of the variable heading each unit column is given by the entry lying in the column of constants in the row containing the 1. The variables heading columns not in unit form are assigned the value zero.

358

6 LINEAR PROGRAMMING

EXAMPLE 2 Complete the solution to the problem discussed in Example 1. Solution The first step in our procedure, setting up the initial simplex tableau, was completed in Example 1. We continue with Step 2. Step 2

Determine whether the optimal solution has been reached. First, refer to the initial simplex tableau: y

2 1

1 1 0 0 3 0 1 0

1

u

√

x

 65

0

0

P

1

Constant 180 300

(17)

0

Since there are negative entries in the last row of the initial simplex tableau, the initial solution is not optimal. We proceed to Step 3. Step 3

Perform the following iterations. First, locate the pivot element: a. Since the entry 65 is the most negative entry to the left of the vertical line in the last row of the initial simplex tableau, the second column in the tableau is the pivot column. b. Divide each positive number of the pivot column into the corresponding entry in the column of constants and compare the ratios thus obtained. We 180 see that the ratio 300 3 is less than the ratio 1 , so row 2 is the pivot row. c. The entry 3 lying in the pivot column and the pivot row is the pivot element. Next, we convert this pivot element into a 1 by multiplying all the entries in the pivot row by 13. Then, using elementary row operations, we complete the conversion of the pivot column into a unit column. The details of the iteration follow:

Pivot row 씮

y

2 1

1 1 0 0 3 0 1 0

1

1 3 R2 ⎯→

P

 65

0

0

1

x

y

u

√

P

2

1 1 0 0 1 0 13 0

x 5 3 1 3

 35

Constant 180 300

Ratio 180 1

 180

300 3

 100

0

앖 Pivot column

1 3

1

R1  R2 ⎯⎯⎯→ R3  65 R2

u

√

x

 65

180 100

0

1

u

√

P

Constant

0 1 1 0

 13 1 3

0 0

80 100

2 5

1

120

y

0

0

Constant

0

0

(18)

This completes one iteration. The last row of the simplex tableau contains a negative number, so an optimal solution has not been reached. Therefore, we repeat the iterative step once again, as follows:

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

x y 5 3 1 3

Pivot row 씮

u

0 1 1 0

√ P  13

Constant

1 3

0 0

80 100

0

2 5

1

120

y

u

√

P

Constant

1 3

0 1

3 5

0

 15 1 3

0 0

48 100

 35

0

0

2 5

1

120

u

√

P

Constant

 35 0

359

Ratio  48

80 5/3 100 1/3

 300

앖 Pivot column

x 1

3 5 R1 ⎯→

x R2  13 R1 ⎯⎯⎯→ R3  35 R1

y

3 1 0 5 1 0 1  5

0

0

9 25

 15 0 2 0 5 7 25

1

48 84

(19)

148 45

The last row of the simplex tableau (19) contains no negative numbers, so we conclude that the optimal solution has been reached. Step 4

Determine the optimal solution. Locate the basic variables in the final tableau. In this case the basic variables (those heading unit columns) are x, y, and P. The value assigned to the basic variable x is the number 48, which is the entry lying in the column of constants and in row 1 (the row that contains the 1). x y u 3 1 0 5 0 1  15 0

0

9 25

√ P  15 0 2 0 5 7 25

1

Constant 48 씯— — 84 씯 148 45 씯

Similarly, we conclude that y  84 and P  148.8. Next, we note that the variables u and √ are nonbasic and are accordingly assigned the values u  0 and √  0. These results agree with those obtained in Example 1, Section 6.3. EXAMPLE 3 Maximize subject to

P  2x  2y  z 2x  y  2z 14 2x  4y  z 26 x  2y  3z 28 x  0, y  0, z  0

Solution Introducing the slack variables u, √, and w and rewriting the objective function in the standard form gives the system of linear equations

2x  y  2z  u  14 2x  4y  z √  26 x  2y  3z w  28 2x  2y  z P 0

360

6 LINEAR PROGRAMMING

The initial simplex tableau is given by x

y

z

u

√ w P

2 1 2 1 0 0 0 2 4 1 0 1 0 0 1 2 3 0 0 1 0 2 2 1 0 0 0 1

Constant 14 26 28 0

Since the most negative entry in the last row (2) occurs twice, we may choose either the x- or the y-column as the pivot column. Choosing the x-column as the pivot column and proceeding with the first iteration, we obtain the following sequence of tableaus: x Pivot row 씮

y

x

R2  2R1 ⎯⎯⎯→ R3  R1 R4  2R1

u

√ w P

2 1 2 1 0 0 0 2 4 1 0 1 0 0 1 2 3 0 0 1 0 2 2 1 0 0 0 1

앖 Pivot column

1 2 R1 ⎯→

z

y

z

u

1 2

√ w P

1 2

1 1 0 0 0 2 4 1 0 1 0 0 1 2 3 0 0 1 0 2 2 1 0 0 0 1 x

y

1 0 0 0

1 2

z

u

√ w P

1 2

1 0 0 0 3 1 1 1 0 0 3 2  12 0 1 0 2 1 1 1 0 0 1

Constant 14 26 28 0

Ratio 14 2

7

26 2

 13

28 1

 28

Constant 7 26 28 0 Constant 7 12 21 14

Since there is a negative number in the last row of the simplex tableau, we perform another iteration, as follows:

Pivot row 씮

x

y

1 0 0

1 2

⎯→

R1  12 R2 ⎯⎯⎯→ R3  32 R2 R4  R2

u 1 2

1 3 1 1 3 2  12 2

√ w P 0 0 1

0 0 0

7 12 21

0

1

14

1

1 0

x

y

z

u

1 0 0

1 2

1

0

1

x

y

z

u

1 0 0 1 0 0

7 6  13 5 2

2 3  13

0

1 3  12

2 3

2 3

1 3

0

앖 Pivot column

3 2

0

√ w P

1 0 1 2  13  13 13 2  12 0

1

1

Constant

0 1 0

1

0

1 3 R2

z

0

0 0 1

0 0 0

7 4 21

0 1

14

√ w P  16

Constant

0 0 1

Constant

0 0 0

5 4 15

0 1

18

Ratio 7 1/2 12 3 21 3/2

 14 4  14

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

361

All entries in the last row are nonnegative, so we have reached the optimal solution. We conclude that x  5, y  4, z  0, u  0, √  0, w  15, and P  18.

Explore & Discuss Consider the linear programming problem Maximize P  x  2y subject to

2x  y 4 x  3y 3 x  0, y  0

1. Sketch the feasible set S for the linear programming problem and explain why the problem has an unbounded solution. 2. Use the simplex method to solve the problem as follows: a. Perform one iteration on the initial simplex tableau. Interpret your result. Indicate the point on S corresponding to this (nonoptimal) solution. b. Show that the simplex procedure breaks down when you attempt to perform another iteration by demonstrating that there is no pivot element. c. Describe what happens if you violate the rule for finding the pivot element by allowing the ratios to be negative and proceeding with the iteration.

The following example is constructed to illustrate the geometry associated with the simplex method when used to solve a problem in three-dimensional space. We sketch the feasible set for the problem and show the path dictated by the simplex method in arriving at the optimal solution for the problem. The use of a calculator will help in the arithmetic operations if you wish to verify the steps. EXAMPLE 4 Geometric Illustration of Simplex Method in 3-Space Maximize P  20x  12y  18z subject to 3x  y  2z 9 2x  3y  z 8 x  2y  3z 7 x  0, y  0, z  0 Solution Introducing the slack variables u, √, and w and rewriting the objective function in standard form gives the following system of linear equations:

3x  y  2z  u 9 2x  3y  z √ 8 x  2y  3z w 7 20x  12y  18z P0

The initial simplex tableau is given by y

z

3 2 1

1 3 2

2 1 0 0 0 1 0 1 0 0 3 0 0 1 0

20

12

18

u

√ w P

x

0

0

0

1

Constant 9 8 7 0

362

6 LINEAR PROGRAMMING

Since the most negative entry in the last row (20) occurs in the x-column, we choose the x-column as the pivot column. Proceeding with the first iteration, we obtain the following sequence of tableaus: x Pivot row 씮

y

u

√ w P

1 3 2

20

12

18

0

0

x

y

z

u

√ w P

1 2 1

1 3

2 3

1 3

3 2

1 3

0 0

0 1 0

0 0 1

0 0 0

3 8 7

20

12

18

0

0

0

1

0

x

y

z

u

√ w P

1 씮 0 Pivot 0

1 3 7 3 5 3

2 3  13 7 3

1 3  23  13

0 1 0

0 0 1

0 0 0

3 2 4

 136

 134

20 3

0

0

1

60

1 3 R1 ⎯→

row

0

2 1 0 0 0 1 0 1 0 0 3 0 0 1 0

Constant

3 2 1 앖 Pivot column

R2  2R1 ⎯⎯⎯⎯→ R3  R1 R4  20R1

z

0

1

9 8 7

Ratio 9 3

3

8 2

4

7 1

7

0

Constant

Constant

Ratio 9 6 7 12 5

앖 Pivot column

After one iteration we are at the point (3, 0, 0) with P  60. (See Figure 20.) Since the most negative entry in the last row is 163, we choose the y-column as the pivot column. Proceeding with this iteration, we obtain

3 7 R2

⎯→

√ w P

x

y

z

u

1

1 3

3

1

3 7

6 7

5 3

1 3  27  13

0

0 0

2 3  17 7 3

0

 136

 134

20 3

0

y

z

u

√ w P

1 0 0 1 0 0

5 7  17 18 7

3 7  27 1 7

 17 0 0 3 0 0 7  57 1 0

 378

6 3 7

x

0 0 0 0 0 1 0 0

1

Constant

4 60 Constant Ratio

R1  ⎯⎯⎯⎯→ R3  53 R2 1 3 R2

R4  163 R2

0

0

앖 Pivot column

16 7

0

1

19 7 6 7 18 7

64 47

19 5

— 1

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

363

The second iteration brings us to the point Ó197, 67, 0Ô with P  64 47. (See Figure 20.) z

7 3

F 0, 0,

E 0, 17 , 7 G

13 , 7

5 7

S

0, 12 7

A(0, 0, 0)

D 0,

8, 3

y

0

H(2, 1, 1)

B (3, 0, 0)

C

FIGURE 20 The simplex method brings us from the point A to the point H, at which the objective function is maximized.

19 , 6 , 7 7

0

x

Since there is a negative number in the last row of the simplex tableau, we perform another iteration, as follows:

7 18 R3

⎯→

x y

z

u

√

w P

1 0 0 1 0 0

5 7  17

 17

1

3 7  27 1 18

3 7  15 8

0 0 0 0 7 0 18

0 0  378

36 7

16 7

x R1  57 R3 ⎯⎯⎯⎯→ R2  17 R3 R4  387 R3

y z

u

√

49 9

7 9

19 7 6 7

1

0

1

64 47

w

P

Constant

7 1 5  0 1 0 0 18 18 18 7 1 0 0 1 0  15 8 18 18 1  5 7 0 0 0 1 18 18 18

0 0 0

Constant

19 9

1

2 1 1 70

All entries in the last row are nonnegative, so we have reached the optimal solution. We conclude that x  2, y  1, z  1, u  0, √  0, w  0, and P  70. The feasible set S for the problem is the hexahedron shown in Figure 21 on page 364. It is the intersection of the half-spaces determined by the planes P1, P2, and P3 with equations 3x  y  2z  9, 2x  3y  z  8, x  2y  3z  7, respectively, and the coordinate planes x  0, y  0, and z  0. That portion of the figure showing the feasible set S is shown in Figure 20. Observe that the first iteration of the simplex method brings us from A(0, 0, 0) with P  0 to B(3, 0, 0) with P  60. The second iteration brings us from B(3, 0, 0) to C Ó 197 , 67 , 0Ô with P  64 47 , and the third iteration brings us from C Ó197 , 67 , 0Ô to the point H(2, 1, 1) with an optimal value of 70 for P.

364

6 LINEAR PROGRAMMING

z

P2(2x + 3y + z = 8) F 0, 0,

G

13 7,

B(3, 0, 0) P3(x + 2y + 3z = 7)

5 P1(3x + y + 2z = 9) E 0, 17 7, 7 D 0, 83 , 0

S

0, 127

7 3

y H(2, 1, 1) C

19 , 6 , 7 7

0

FIGURE 21 The feasible set S is obtained from the intersection of the half-spaces determined by P1, P2, and P3 with the coordinate planes x  0, y  0, and z  0.

x

APPLIED EXAMPLE 5 Production Planning Ace Novelty Company has determined that the profit for each type-A, type-B, and type-C souvenir that it plans to produce is $6, $5, and $4, respectively. To manufacture a type-A souvenir requires 2 minutes on machine I, 1 minute on machine II, and 2 minutes on machine III. A type-B souvenir requires 1 minute on machine I, 3 minutes on machine II, and 1 minute on machine III. A type-C souvenir requires 1 minute on machine I and 2 minutes on each of machines II and III. Each day there are 3 hours available on machine I, 5 hours available on machine II, and 4 hours available on machine III for manufacturing these souvenirs. How many souvenirs of each type should Ace Novelty make per day in order to maximize its profit? (Compare with Example 1, Section 5.1.) Solution

The given information is tabulated as follows:

Type A

Type B

Type C

Time Available (min)

Machine I Machine II Machine III

$2 $1 $2

$1 $3 $1

$1 $2 $2

180 300 240

Profit per Unit

$6

$5

$4

Let x, y, and z denote the respective numbers of type-A, type-B, and type-C souvenirs to be made. The total amount of time that machine I is used is given by 2x  y  z minutes and must not exceed 180 minutes. Thus, we have the inequality 2x  y  z 180

Similar considerations on the use of machines II and III lead to the inequalities x  3y  2z 300 2x  y  2z 240

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

365

The profit resulting from the sale of the souvenirs produced is given by P  6x  5y  4z

The mathematical formulation of this problem leads to the following standard linear programming problem: Maximize the objective (profit) function P  6x  5y  4z subject to 2x  y  z 180 x  3y  2z 300 2x  y  2z 240 x  0, y  0, z  0

Introducing the slack variables u, √, and w gives the system of linear equations 2x  y  z  u  180 x  3y  2z √  300 2x  y  2z w  240 6x  5y  4z P 0

The tableaus resulting from the use of the simplex algorithm are u

√ w P

x

y

z

2 1 2

1 3 1

1 1 0 0 0 2 0 1 0 0 2 0 0 1 0

6

5

4

0

0

x

y

z

u

√ w P

1 1 2

1 2

1 2

1 2

3 1

6

5

4

0

0

x

y

z

u

√ w P

1 0 0

1 2

1 2

1 2

5 2

3 2

 12

0

1

1

0

2

1

Pivot row 씮

0

1

Constant 180 300 240

Ratio 180 2

 90

300 1

 300

240 2

 120

0

앖 Pivot column

1 2 R1

⎯→

R2  R1 ⎯⎯⎯→ R3  2R1 R4  6R1

씮 Pivot row

0 0 0 2 0 1 0 0 2 0 0 1 0 0

1

Constant 90 300 240 0 Constant

0 0 0 1 0 0 0 1 0

90 210 60

3

0

540

√ w P

0

1

앖 Pivot column

2 5 R2 ⎯→

x

y

z

u

1 0 0

1 2

1 2  15

0

1 0

1 2 3 5

1

1

0

0 0 0 0 1 0

0

2

1

3

0

0

2 5

1

Constant 90 84 60 540

Ratio 90 1/2

 180

210 5/2

 84

366

6 LINEAR PROGRAMMING

R1  12 R2 ⎯⎯⎯→ R4  2R2

√ w P

x

y

z

u

1 0 0

0 15 1 35 0 1

3 5 1  5

 15

1

0

0 0 0 0 1 0

0

0

1 5

13 5

4 5

0

2 5

Constant

1

48 84 60 708

From the final simplex tableau, we read off the solution x  48

y  84

z0

u0

√0

w  60

P  708

Thus, in order to maximize its profit, Ace Novelty should produce 48 type-A souvenirs, 84 type-B souvenirs, and no type-C souvenirs. The resulting profit is $708 per day. The value of the slack variable w  60 tells us that 1 hour of the available time on machine III is left unused. Interpreting Our Results Let’s compare the results obtained here with those

obtained in Example 7, Section 5.2. Recall that, to use all available machine time on each of the three machines, Ace Novelty had to produce 36 type-A, 48 type-B, and 60 type-C souvenirs. This would have resulted in a profit of $696. Example 5 shows how, through the optimal use of equipment, a company can boost its profit while reducing machine wear!

Problems with Multiple Solutions and Problems with No Solutions As we saw in Section 6.3, a linear programming problem may have infinitely many solutions. We also saw that a linear programming problem may have no solution. How do we spot each of these phenomena when using the simplex method to solve a problem? A linear programming problem will have infinitely many solutions if and only if the last row to the left of the vertical line of the final simplex tableau has a zero in a column that is not a unit column. Also, a linear programming problem will have no solution if the simplex method breaks down at some stage. For example, if at some stage there are no nonnegative ratios in our computation, then the linear programming problem has no solution (see Exercise 44).

Explore & Discuss Consider the linear programming problem Maximize P  4x  6y subject to

2 x  y 10 2 x  3y 18 x  0, y  0

1. Sketch the feasible set for the linear programming problem. 2. Use the method of corners to show that there are infinitely many optimal solutions. What are they? 3. Use the simplex method to solve the problem as follows. a. Perform one iteration on the initial simplex tableau and conclude that you have arrived at an optimal solution. What is the value of P, and where is it attained? Compare this result with that obtained in step 2. b. Observe that the tableau obtained in part (a) indicates that there are infinitely many solutions (see the comment above on multiple solutions). Now perform another iteration on the simplex tableau using the x-column as the pivot column. Interpret the final tableau.

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

367

6.4 Self-Check Exercises labor, whereas producing one model-B grate requires 30 lb of cast iron and 15 min of labor. The profit for a model-A grate is $6, and the profit for a model-B grate is $8. There are 7200 lb of cast iron and 100 labor-hours available each week. Because of a surplus from the previous week, the proprietor has decided that he should make no more than 150 units of model-A grates this week. Determine how many of each model he should make in order to maximize his profit.

1. Solve the following linear programming problem by the simplex method: Maximize P  2x  3y  6z subject to

2x  3y  z 10 x  y  2z 8 2y  3z 6 x  0, y  0, z  0

2. The LaCrosse Iron Works makes two models of cast-iron fireplace grates, model A and model B. Producing one model-A grate requires 20 lb of cast iron and 20 min of

Solutions to Self-Check Exercises 6.4 can be found on page 371.

6.4 Concept Questions 1. Give the three characteristics of a standard maximization linear programming problem.

b. If you are given a simplex tableau, how do you determine whether the optimal solution has been reached?

2. a. When the initial simplex tableau is set up, how is the system of linear inequalities transformed into a system of linear equations? How is the objective function P  c1x1  c2 x2      cn xn rewritten?

3. In the simplex method, how is a pivot column selected? A pivot row? A pivot element?

6.4 Exercises In Exercises 1–10, determine whether the given simplex tableau is in final form. If so, find the solution to the associated regular linear programming problem. If not, find the pivot element to be used in the next iteration of the simplex method.

1. x y 1

0

0

0

13 7

0

√ P

u 5 7  37

1

0 0

20 7 30 7

3 7

1

22 0 7

u

√ P

1

1

1

0

0

6

1

0

1

1

0

2

0

5

0

y

z u

1

 13

0

1 3

0

2

0

2 3

0

Constant

 17 2 7

2. x y

3

5. x

6.

Constant

1

3. x

y

u

√

P

Constant

0

1

 12

0

2

1

1 2 1 2

0

1 2

0

4

0

 12

0

3 2

1

12

8.

Constant

0

0

0

0 1

1

0

6

1

1 3

0

1 3

0

13 3

4 0

1

0

2

1

17

y

z

1 2 1 2

0

1

1

1 4 3 4

2

0

3

0

 12

1

30

w P  23

x

7.

√

1 3

√ w P

u

 14 1 4

Constant

0

0

0

0

19 2 21 2

0

0 1

0

30

6

3 2

0

1

63

0

x

y

z

s

t

u

√

P

Constant

5 2

3

0

1

0

0

4

0

46

1

0

0

0 1

0

0

0

9

0

1

0

0

0 1

0

0

12

0

0 1

0

0

0

1

0

6

0

0

0

300

1

1800

180

200

0

x

z

t

u

√

P

0

 85 8 5

4

1

 65 6 5

0

0

2 5  25

0

5

1

0

0

0

1

0

0

12

0

1

0

0

0

1

0

6

0

0

72

0

16

12

1

4920

y

4. x y

z

u √

P

Constant

1

0

0

3

0

5

1

1

0

28

0

0

2

1

3

0

1

0

16

0

2

0

8

0

3

1

48

0 0

s

Constant

368

6 LINEAR PROGRAMMING

9. x y

10.

z

1

0

0

1

3 5 19  5

0

0

26 5

0

0

1

x

y

0

0

1

1

0

2

1 2 1 2 1 2

0

1

3

0

1

z

u

u

√ P 1 5 3  5

Constant

0

30

0

10

0 1

60

√ w P

Constant

0

0

2

0

0

13

0

 12 1 2  32

1

0

4

0

1

0

1

26

In Exercises 11–25, solve each linear programming problem by the simplex method.

11. Maximize P  3x  4y subject to xy 4 2x  y 5 x  0, y  0 12. Maximize P  5x  3y subject to x  y 80 3x

90 x  0, y  0 13. Maximize P  10x  12y subject to x  2y 12 3x  2y 24 x  0, y  0 14. Maximize P  5x  4y subject to 3x  5y 78 4x  y 36 x  0, y  0 15. Maximize P  4x  6y subject to 3x  y 24 2x  y 18 x  3y 24 x  0, y  0 16. Maximize subject to

P  15x  12y x  y 12 3x  y 30 10x  7y 70 x  0, y  0

17. Maximize P  3x  4y  5z subject to x y z 8 3x  2y  4z 24 x  0, y  0, z  0 18. Maximize P  3x  3y  4z subject to x  y  3z 15 4x  4y  3z 65 x  0, y  0, z  0

19. Maximize P  3x  4y  z subject to 3x  10y  5z 120 5x  2y  8z 6 8x  10y  3z 105 x  0, y  0, z  0 20. Maximize P  x  2y  z subject to 2x  y  z 14 4x  2y  3z 28 2x  5y  5z 30 x  0, y  0, z  0 21. Maximize P  4x  6y  5z subject to x  y  z 20 2x  4y  3z 42 2x  3z 30 x  0, y  0, z  0 22. Maximize P  x  4y  2z subject to 3x  y  z 80 2x  y  z 40 x  y  z 80 x  0, y  0, z  0 23. Maximize P  12x  10y  5z subject to 2x  y  z 10 3x  5y  z 45 2x  5y  z 40 x  0, y  0, z  0 24. Maximize P  2x  6y  6z subject to 2x  y  3z 10 4x  y  2z 56 6x  4y  3z 126 2x  y  z 32 x  0, y  0, z  0 25. Maximize P  24x  16y  23z subject to 2x  y  2z 7 2x  3y  z 8 x  2y  3z 7 x  0, y  0, z  0 26. Rework Example 3 using the y-column as the pivot column in the first iteration of the simplex method. 27. Show that the following linear programming problem Maximize P  2x  2y  4z subject to 3x  3y  2z 100 5x  5y  3z 150 x  0, y  0, z  0

has optimal solutions x  30, y  0, z  0, P  60 and x  0, y  30, z  0, P  60.

369

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

28. MANUFACTURING—PRODUCTION SCHEDULING A company manufactures two products, A and B, on two machines, I and II. It has been determined that the company will realize a profit of $3/unit of product A and a profit of $4/unit of product B. To manufacture 1 unit of product A requires 6 min on machine I and 5 min on machine II. To manufacture 1 unit of product B requires 9 min on machine I and 4 min on machine II. There are 5 hr of machine time available on machine I and 3 hr of machine time available on machine II in each work shift. How many units of each product should be produced in each shift to maximize the company’s profit? What is the largest profit the company can realize? Is there any time left unused on the machines? 29. M ANUFACTURING —P RODUCTION S CHEDULING National Business Machines Corporation manufactures two models of fax machines: A and B. Each model A costs $100 to make, and each model B costs $150. The profits are $30 for each model-A and $40 for each model-B fax machine. If the total number of fax machines demanded each month does not exceed 2500 and the company has earmarked no more than $600,000/month for manufacturing costs, find how many units of each model National should make each month in order to maximize its monthly profit. What is the largest monthly profit the company can make? 30. MANUFACTURING—PRODUCTION SCHEDULING Kane Manufacturing has a division that produces two models of hibachis, model A and model B. To produce each model-A hibachi requires 3 lb of cast iron and 6 min of labor. To produce each model-B hibachi requires 4 lb of cast iron and 3 min of labor. The profit for each modelA hibachi is $2, and the profit for each model-B hibachi is $1.50. If 1000 lb of cast iron and 20 labor-hours are available for the production of hibachis each day, how many hibachis of each model should the division produce in order to maximize Kane’s profit? What is the largest profit the company can realize? Is there any raw material left over? 31. AGRICULTURE—CROP PLANNING A farmer has 150 acres of land suitable for cultivating crops A and B. The cost of cultivating crop A is $40/acre whereas that of crop B is $60/acre. The farmer has a maximum of $7400 available for land cultivation. Each acre of crop A requires 20 labor-hours, and each acre of crop B requires 25 laborhours. The farmer has a maximum of 3300 labor-hours available. If he expects to make a profit of $150/acre on crop A and $200/acre on crop B, how many acres of each crop should he plant in order to maximize his profit? What is the largest profit the farmer can realize? Are there any resources left over? 32. INVESTMENTS—ASSET ALLOCATION A financier plans to invest up to $500,000 in two projects. Project A yields a return of 10% on the investment whereas project B yields a return of 15% on the investment. Because the investment in project B is riskier than the investment in project A, the financier has decided that the investment in project B

should not exceed 40% of the total investment. How much should she invest in each project in order to maximize the return on her investment? What is the maximum return? 33. INVESTMENTS—ASSET ALLOCATION Ashley has earmarked at most $250,000 for investment in three mutual funds: a money market fund, an international equity fund, and a growth-and-income fund. The money market fund has a rate of return of 6%/year, the international equity fund has a rate of return of 10%/year, and the growth-andincome fund has a rate of return of 15%/year. Ashley has stipulated that no more than 25% of her total portfolio should be in the growth-and-income fund and that no more than 50% of her total portfolio should be in the international equity fund. To maximize the return on her investment, how much should Ashley invest in each type of fund? What is the maximum return? 34. MANUFACTURING—PRODUCTION SCHEDULING A division of the Winston Furniture Company manufactures dining tables and chairs. Each table requires 40 board feet of wood and 3 labor-hours. Each chair requires 16 board feet of wood and 4 labor-hours. The profit for each table is $45, and the profit for each chair is $20. In a certain week, the company has 3200 board feet of wood available and 520 labor-hours available. How many tables and chairs should Winston manufacture in order to maximize its profit? What is the maximum profit? 35. MANUFACTURING—PRODUCTION SCHEDULING A company manufactures products A, B, and C. Each product is processed in three departments: I, II, and III. The total available labor-hours per week for departments I, II, and III are 900, 1080, and 840, respectively. The time requirements (in hours per unit) and profit per unit for each product are as follows:

Dept. I Dept. II Dept. III Profit

Product A $ 2 $ 3 $ 2

Product B $ 1 $ 1 $ 2

Product C $ 2 $ 2 $ 1

$18

$12

$15

How many units of each product should the company produce in order to maximize its profit? What is the largest profit the company can realize? Are there any resources left over? 36. MANUFACTURING—PRODUCTION SCHEDULING Ace Novelty manufactures “Giant Pandas” and “Saint Bernards.” Each Panda requires 1.5 yd2 of plush, 30 ft3 of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 yd2 of plush, 35 ft3 of stuffing, and 8 pieces of trim. The profit for each Panda is $10, and the profit for each Saint Bernard is $15. If 3600 yd2 of plush, 66,000 ft3 of stuffing, and 13,600 pieces of trim are available, how many of each of the stuffed animals should the company manufacture to maximize its profit? What is the maximum profit?

370

6 LINEAR PROGRAMMING

37. ADVERTISING—TELEVISION COMMERCIALS As part of a campaign to promote its annual clearance sale, Excelsior Company decided to buy television advertising time on Station KAOS. Excelsior’s television advertising budget is $102,000. Morning time costs $3000/minute, afternoon time costs $1000/minute, and evening (prime) time costs $12,000/minute. Because of previous commitments, KAOS cannot offer Excelsior more than 6 min of prime time or more than a total of 25 min of advertising time over the 2 weeks in which the commercials are to be run. KAOS estimates that morning commercials are seen by 200,000 people, afternoon commercials are seen by 100,000 people, and evening commercials are seen by 600,000 people. How much morning, afternoon, and evening advertising time should Excelsior buy to maximize exposure of its commercials? 38. INVESTMENTS—ASSET ALLOCATION Sharon has a total of $200,000 to invest in three types of mutual funds: growth, balanced, and income funds. Growth funds have a rate of return of 12%/year, balanced funds have a rate of return of 10%/year, and income funds have a return of 6%/year. The growth, balanced, and income mutual funds are assigned risk factors of 0.1, 0.06, and 0.02, respectively. Sharon has decided that at least 50% of her total portfolio is to be in income funds and at least 25% in balanced funds. She has also decided that the average risk factor for her investment should not exceed 0.05. How much should Sharon invest in each type of fund in order to realize a maximum return on her investment? What is the maximum return? Hint: The constraint for the average risk factor for the investment is given by 0.1x  0.06y  0.02z 0.05(x  y  z).

39. MANUFACTURING—PRODUCTION CONTROL Custom Office Furniture is introducing a new line of executive desks made from a specially selected grade of walnut. Initially, three models—A, B, and C—are to be marketed. Each model-A desk requires 114 hr for fabrication, 1 hr for assembly, and 1 hr for finishing; each model-B desk requires 121 hr for fabrication, 1 hr for assembly, and 1 hr for finishing; each modelC desk requires 112 hr, 43 hr, and 12 hr for fabrication, assembly, and finishing, respectively. The profit on each model-A desk is $26, the profit on each model-B desk is $28, and the profit on each model-C desk is $24. The total time available in the fabrication department, the assembly department, and the finishing department in the first month of production is 310 hr, 205 hr, and 190 hr, respectively. To maximize Custom’s profit, how many desks of each model should be made in the month? What is the largest profit the company can realize? Are there any resources left over? 40. MANUFACTURING—PREFABRICATED HOUSING PRODUCTION Boise Lumber has decided to enter the lucrative prefabricated housing business. Initially, it plans to offer three models: standard, deluxe, and luxury. Each house is prefabricated and partially assembled in the factory, and the final assembly is completed on site. The dollar amount of building material required, the amount of labor required in the factory for prefabrication and partial assembly, the amount of on-site labor required, and the profit per unit are as follows:

Material Factory Labor (hr) On-site Labor (hr) Profit

Standard Model $6,000 $ 240 $ 180

Deluxe Model $8,000 $ 220 $ 210

Luxury Model $10,000 $ 200 $ 300

$3,400

$4,000

$5,000

For the first year’s production, a sum of $8,200,000 is budgeted for the building material; the number of labor-hours available for work in the factory (for prefabrication and partial assembly) is not to exceed 218,000 hr; and the amount of labor for on-site work is to be less than or equal to 237,000 labor-hours. Determine how many houses of each type Boise should produce (market research has confirmed that there should be no problems with sales) to maximize its profit from this new venture. 41. MANUFACTURING—COLD FORMULA PRODUCTION Beyer Pharmaceutical produces three kinds of cold formulas: I, II, and III. It takes 2.5 hr to produce 1000 bottles of formula I, 3 hr to produce 1000 bottles of formula II, and 4 hr to produce 1000 bottles of formula III. The profits for each 1000 bottles of formula I, formula II, and formula III are $180, $200, and $300, respectively. Suppose, for a certain production run, there are enough ingredients on hand to make at most 9000 bottles of formula I, 12,000 bottles of formula II, and 6000 bottles of formula III. Furthermore, suppose the time for the production run is limited to a maximum of 70 hr. How many bottles of each formula should be produced in this production run so that the profit is maximized? What is the maximum profit realizable by the company? Are there any resources left over? 42. PRODUCTION—JUICE PRODUCTS CalJuice Company has decided to introduce three fruit juices made from blending two or more concentrates. These juices will be packaged in 2-qt (64-oz) cartons. One carton of pineapple–orange juice requires 8 oz each of pineapple and orange juice concentrates. One carton of orange–banana juice requires 12 oz of orange juice concentrate and 4 oz of banana pulp concentrate. Finally, one carton of pineapple–orange–banana juice requires 4 oz of pineapple juice concentrate, 8 oz of orange juice concentrate, and 4 oz of banana pulp. The company has decided to allot 16,000 oz of pineapple juice concentrate, 24,000 oz of orange juice concentrate, and 5000 oz of banana pulp concentrate for the initial production run. The company has also stipulated that the production of pineapple– orange–banana juice should not exceed 800 cartons. Its profit on one carton of pineapple–orange juice is $1.00, its profit on one carton of orange–banana juice is $.80, and its profit on one carton of pineapple–orange–banana juice is $.90. To realize a maximum profit, how many cartons of each blend should the company produce? What is the largest profit it can realize? Are there any concentrates left over? 43. INVESTMENTS—ASSET ALLOCATION A financier plans to invest up to $2 million in three projects. She estimates that project A will yield a return of 10% on her investment, project B will yield a return of 15% on her investment, and project C

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

will yield a return of 20% on her investment. Because of the risks associated with the investments, she decided to put not more than 20% of her total investment in project C. She also decided that her investments in projects B and C should not exceed 60% of her total investment. Finally, she decided that her investment in project A should be at least 60% of her investments in projects B and C. How much should the financier invest in each project if she wishes to maximize the total returns on her investments? What is the maximum amount she can expect to make from her investments? 44. Consider the linear programming problem

d. Explain why the result in part (c) implies that no solution exists for the linear programming problem. In Exercises 45–48, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

45. If at least one of the coefficients a1, a2, . . . , an of the objective function P  a1 x1  a2 x2      an xn is positive, then (0, 0, . . . , 0) cannot be the optimal solution of the standard (maximization) linear programming problem. 46. Choosing the pivot row by requiring that the ratio associated with that row be the smallest ensures that the iteration will not take us from a feasible point to a nonfeasible point.

Maximize P  3x  2y xy 3

subject to

371

x 2 x  0, y  0

a. Sketch the feasible set for the linear programming problem. b. Show that the linear programming problem is unbounded. c. Solve the linear programming problem using the simplex method. How does the method break down?

47. Choosing the pivot column by requiring that it be the column associated with the most negative entry to the left of the vertical line in the last row of the simplex tableau ensures that the iteration will result in the greatest increase or, at worse, no decrease in the objective function. 48. If, at any stage of an iteration of the simplex method, it is not possible to compute the ratios (division by zero) or the ratios are negative, then we can conclude that the standard linear programming problem has no solution.

6.4 Solutions to Self-Check Exercises 1. Introducing the slack variables u, √, and w, we obtain the system of linear equations 2 x  3y  z  u  10 x  y  2z √  8 2y  3z w  6 2 x  3y  6z P 0

The initial simplex tableau and the successive tableaus resulting from the use of the simplex procedure follow: x

y

2 1 Pivot 씮 0 row 2

3 1 2 3

x

z

u

√

w

P

1 1 0 0 0 2 0 1 0 0 3 0 0 1 0 6 0 0 0 1 앖 Pivot column y

z

u

√

w P

2 3 1 1 0 0 0 1 1 2 0 1 0 0 2 0 1 0 0 13 0 3 2 3 6 0 0 0 1 x

y

7 2 3 Pivot 1  13 씮 row 2 0 3 2 1 앖 Pivot column

z

u √

w

P

0 1 0  13 0 0 0 1  23 0 1 0 1 0 0 3 0 0 0 2 1

Ratio  10

Constant

10 1 8 2 6 3

10 8 6 0

4

1 3 R3 ⎯→

2

x 0 1 0 0

u

√

y

z

w

P

Constant

3

0 1 2 1 1  23 1 1 0 0 3 2 0 0 2 3

0 0 0 1

0 4 2 20

 13 0 0 2 3 1 3

All entries in the last row are nonnegative, and the tableau is final. We conclude that x  4, y  0, z  2, and P  20. 2. Let x denote the number of model-A grates and y the number of model-B grates to be made this week. Then the profit function to be maximized is given by P  6x  8y

The limitations on the availability of material and labor may be expressed by the linear inequalities 20x  30y 7200 or 2x  3y 720 20x  15y 6000 or 4x  3y 1200

Constant 10 8 2 0

Constant 8 4 2 12

R1  R3 ⎯⎯⎯→ R2  2R3 R4  6R3

Finally, the condition that no more than 150 units of model-A grates be made this week may be expressed by the linear inequality x 150

Ratio 8 2  4 4 1

4 —

Thus, we are led to the following linear programming problem: R1  2R2 ⎯⎯⎯→ R4  2R2

Maximize P  6x  8y subject to 2x  3y 720 4x  3y 1200 x

150 x  0, y  0

372

6 LINEAR PROGRAMMING

To solve this problem, we introduce slack variables u, √, and w and use the simplex method, obtaining the following sequence of simplex tableaus: x Pivot row 씮

⎯→

√ w

P

Constant 720

 240

0

1200

1200 3

 400

1 0 0 0 1 0 6 8 0 0 0 1 앖 Pivot column x y u √ w P

150 0

2

3 3

1 0

0 1

0 0

0

1

1 3

0

0

0

240

4

3

0

1

0

0

1200

1 0 0 0 1 0 6 8 0 0 0 1

150 0

USING

TECHNOLOGY

√ w

P

Constant

0

0

0

240

0

0

480

1 0 0 1

150 1920

앖 Pivot column x y u √

—

240 2/3 480 2 150 1

w

P

Constant

0  R1  32 R3 0 1 ⎯⎯⎯→ 0 0 1 1 2 R2  2R3 0 0 1 R4  23 R3 1 0 8 2 0 0 0 3 3

0

140

1 3

Constant

2 3

1

u 1 3

R2  3R1 ⎯⎯⎯→ 2 0 1 1 R4  8R1 Pivot row 씮 1 0 0 0 8 0  23 0 3

Ratio 720 3

4

1 3 R1

y u

x y 2 3

2 3

0

180

0 1

150 2020

Ratio  360  240  150

The last tableau is final, and we see that x  150, y  140, and P  2020. Therefore, LaCrosse should make 150 model-A grates and 140 model-B grates this week. The profit will be $2020.

The Simplex Method: Solving Maximization Problems Graphing Utility

A graphing utility can be used to solve a linear programming problem by the simplex method, as illustrated in Example 1. EXAMPLE 1 (Refer to Example 5, Section 6.4.) The problem reduces to the following linear programming problem: Maximize

P  6x  5y  4z

subject to

2x  y  z 180 x  3y  2z 300 2x  y  2z 240 x  0, y  0, z  0

With u, √, and w as slack variables, we are led to the following sequence of simplex tableaus, where the first tableau is entered as the matrix A: Pivot row 씮

u

√ w P

x

y

z

2 1 2

1 3 1

1 1 0 0 0 2 0 1 0 0 2 0 0 1 0

6

5

4

0

0 0

1

Constant 180 300 240

Ratio 180 2

 90

300 1

 300

240 2

 120

*rowÓ 12 , A, 1Ô 䉴 B ⎯⎯⎯⎯⎯⎯⎯→

0

앖 Pivot column

x

y

z

u

√ w P

Constant

1 1 2

0.5 3 1

0.5 2 2

0.5 0 0

0 0 0 1 0 0 0 1 0

90 300 240

0

0 0

6

5

4

1

0

*row(1, B, 1, 2) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→ *row(2, C, 1, 3) 䉴 B *row(6, B, 1, 4) 䉴 C

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

x Pivot row 씮

y

1 0 0

z

0.5 2.5 0

0.5 0.5 0 0 0 1.5 0.5 1 0 0 1 1 0 1 0

2

0

√ w P

u

1

3

0 0

1

Constant 90 210 60

373

Ratio 90 0.5

 180

210 2.5

 84

*rowÓ 21.5 , C, 2Ô 䉴 B ⎯⎯⎯⎯⎯⎯⎯→

540

앖 Pivot column

x

y

1 0 0

0.5 1 0

0

z

2 x

u

0.5 0.5 0 0.6 0.2 0.4 1 1 0 1

y

√

z

3 u

0 √

w P

Constant

0 0 0 0 1 0

90 84 60

0

1

w P

1 0 0.2 0.6 0.2 0 0 0 1 0.6 0.2 0.4 0 0 0 0 1 1 0 1 0 0

0

0.2

2.6

0.8

0

1

*row(0.5, B, 2, 1) 䉴 C ———————————씮 *row(2, C, 2, 4) 䉴B

540 Constant 48 84 60 708

The final simplex tableau is the same as the one obtained earlier. We see that x  48, y  84, z  0, and P  708. Hence, Ace Novelty should produce 48 type-A souvenirs, 84 type-B souvenirs, and no type-C souvenirs—resulting in a profit of $708 per day. Excel

Solver is an Excel add-in that is used to solve linear programming problems. When you start the Excel program, check the Tools menu for the Solver command. If it is not there, you will need to install it. (Check your manual for installation instructions.) EXAMPLE 2 Solve the following linear programming problem: Maximize P  6x  5y  4z subject to 2x  y  z 180 x  3y  2z 300 2x  y  2z 240 x  0, y  0, z  0 Solution

1. Enter the data for the linear programming problem onto a spreadsheet. Enter the labels shown in column A and the variables with which we are working under Decision Variables in cells B4:B6, as shown in Figure T1. This optional step will help us organize our work. Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

(continued)

374

6 LINEAR PROGRAMMING

FIGURE T1 Setting up the spreadsheet for Solver

1 2 3 4 5 6 7 8 9 10 11 12 13

A Maximization Problem

B

C

D

F

G

H

I

Formulas for indicated cells C8: = 6*C4 + 5*C5 + 4*C6 C11: = 2*C4 + C5 + C6 C12: = C4 + 3*C5 + 2*C6 C13: = 2*C4 + C5 + 2*C6

Decision Variables x y z Objective Function

E

0

Constraints 0 <= 0 <= 0 <=

180 300 240

For the moment, the cells that will contain the values of the variables (C4:C6) are left blank. In C8 type the formula for the objective function: =6*C4+5*C5+ 4*C6. In C11 type the formula for the left-hand side of the first constraint: =2*C4+C5+C6. In C12 type the formula for the left-hand side of the second constraint: =C4+3*C5+2*C6. In C13 type the formula for the left-hand side of the third constraint: =2*C4+C5+2*C6. Zeros will then appear in cell B8 and cells C11:C13. In cells D11:D13, type <= to indicate that each constraint is of the form . Finally, in cells E11:E13, type the right-hand value of each constraint— in this case, 180, 300, and 240, respectively. Note that we need not enter the nonnegativity constraints x  0, y  0, and z  0. The resulting spreadsheet is shown in Figure T1, where the formulas that were entered for the objective function and the constraints are shown in the comment box. 2. Use Solver to solve the problem. Click Tools on the menu bar and then click Solver . The Solver Parameters dialog box will appear. a. The pointer will be in the Set Target Cell: box (refer to Figure T2). Highlight the cell on your spreadsheet containing the formula for the objective function—in this case, C8.

FIGURE T2 The completed Solver Parameters dialog box

Then, next to Equal To: select Max . Select the By Changing Cells: box and highlight the cells in your spreadsheet that will contain the values of the variables—in this case, C4:C6. Select the Subject to the Constraints: box and then click Add . The Add Constraint dialog box will appear (Figure T3).

6.4 THE SIMPLEX METHOD: STANDARD MAXIMIZATION PROBLEMS

375

FIGURE T3 The Add Constraint dialog box

b. The pointer will appear in the Cell Reference: box. Highlight the cells on your spreadsheet that contain the formula for the left-hand side of the first constraint— in this case, C11. Next, select the symbol for the appropriate constraint—in this case, <= . Select the Constraint: box and highlight the value of the right-hand side of the first constraint on your spreadsheet—in this case, 180. Click Add and then follow the same procedure to enter the second and third constraint. Click OK . The resulting Solver Parameters dialog box shown in Figure T2 will appear. c. In the Solver Parameters dialog box, click Options (see Figure T2). In the Solver Options dialog box that appears, select Assume Linear Model and Assume Non-Negative constraints (Figure T4). Click OK .

FIGURE T4 The Solver Options dialog box

d. In the Solver Parameters dialog box that appears (see Figure T2), click Solve . A Solver Results dialog box will then appear and at the same time the answers will appear on your spreadsheet (Figure T5). A 1 2 3

FIGURE T5 Completed spreadsheet after using Solver

4 5 6 7 8 9 10 11 12 13

B

C

D

E

Maximization Problem Decision Variables x y z Objective Function

48 84 0 708

Constraints 180 <= 300 <= 240 <=

180 300 240

(continued)

376

6 LINEAR PROGRAMMING

3. Read off your answers. From the spreadsheet, we see that the objective function attains a maximum value of 708 (cell C8) when x  48, y  84, and z  0 (cells C4:C6).

TECHNOLOGY EXERCISES Solve the linear programming problems.

1. Maximize subject to

P  2x  3y  4z  2w x  2y  3z  2w 6 2 x  4y  z  w 4 3x  2y  2z  3w 12 x  0, y  0, z  0, w  0

2. Maximize P  3x  2y  2z  w subject to 2 x  y  z  2w 8 2 x  y  2z  3w 20 x  y  z  2w 8 4 x  2y  z  3w 24 x  0, y  0, z  0, w  0

3. Maximize P  x  y  2z  3w subject to 3x  6y  4z  2w 12 x  4y  8z  4w 16 2x  y  4z  w 10 x  0, y  0, z  0, w  0 4. Maximize P  2x  4y  3z  5w subject to x  2y  3z  4w 8 2x  2y  4z  6w 12 3x  2y  z  5w 10 2x  8y  2z  6w 24 x  0, y  0, z  0, w  0

6.5 The Simplex Method: Standard Minimization Problems Minimization with ⱕ Constraints In the last section, we developed a procedure, called the simplex method, for solving standard linear programming problems. Recall that a standard maximization problem satisfies three conditions: 1. The objective function is to be maximized. 2. All the variables involved are nonnegative. 3. Each linear constraint may be written so that the expression involving the variables is less than or equal to a nonnegative constant. In this section, we see how the simplex method may be used to solve certain classes of problems that are not necessarily standard maximization problems. In particular, we see how a modified procedure may be used to solve problems involving the minimization of objective functions. We begin by considering the class of linear programming problems that calls for the minimization of objective functions but otherwise satisfies Conditions 2 and 3 for standard maximization problems. The method used to solve these problems is illustrated in the following example. EXAMPLE 1 Minimize subject to

C  2x  3y 5x  4y 32 x  2y 10 x  0, y  0

Solution This problem involves the minimization of the objective function and is accordingly not a standard maximization problem. Note, however, that all other

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

377

conditions for a standard maximization problem hold true. To solve a problem of this type, we observe that minimizing the objective function C is equivalent to maximizing the objective function P  C. Thus, the solution to this problem may be found by solving the following associated standard maximization problem: Maximize P  2x  3y subject to the given constraints. Using the simplex method with u and √ as slack variables, we obtain the following sequence of simplex tableaus: x y u √ P Constant Ratio

5 1

Pivot row 씮

4 1 0 0 2 0 1 0

2

Refer to Example 1. 1. Sketch the feasible set S for the linear programming problem.

0

0

1

u √ P

5

4 1 1 0

0

1 2

1 2

0 0

32 5

2

3 0

0

1

0

x

y u

√ P

0 1 2 0 1 0 1 0 2

—씮 3

R1  4R2 ⎯⎯⎯→ R3  3R2

8 5

0

y

Pivot row

32 4 10 2

앖 Pivot column

x 1 2 R2 ⎯→

Explore & Discuss

3

32 10

1 2

 12

Constant

Constant 12 5

0 0

3 2

1

15

x

y u

√

P

Constant

1

0 13  23 0 1 0 1 0 2

Ratio 12 3 5 1/2

4  10

앖

Pivot column

2. Solve the problem using the method of corners. 3. Indicate on S the corner points corresponding to each iteration of the simplex procedure and trace the path leading to the optimal solution.

1 3 R1

⎯→

1 2

 12

0 0

3 2

1

15

u

√

P

Constant

1 2  1 0 3 3 1 5 0 1  6 6

0 0

4 3

1

17

x R2  R1 ⎯⎯⎯→ R3  12 R1 1 2

4 5

0

y

0

1 6

7 6

The last tableau is in final form. The solution to the standard maximization problem associated with the given linear programming problem is x  4, y  3, and P  17, so the required solution is given by x  4, y  3, and C  17. You may verify that the solution is correct by using the method of corners.

The Dual Problem Another special class of linear programming problems we encounter in practical applications is characterized by the following conditions: 1. The objective function is to be minimized. 2. All the variables involved are nonnegative. 3. All other linear constraints may be written so that the expression involving the variables is greater than or equal to a constant. Such problems are called standard minimization problems.

378

6 LINEAR PROGRAMMING

A convenient method for solving this type of problem is based on the following observation. Each maximization linear programming problem is associated with a minimization problem, and vice versa. For the purpose of identification, the given problem is called the primal problem; the problem related to it is called the dual problem. The following example illustrates the technique for constructing the dual of a given linear programming problem. EXAMPLE 2 Write the dual problem associated with the following problem: Minimize the objective function C  6x  8y subject to 40x  10y  2400 10x  15y  2100 5x  15y  1500 x  0, y  0000 Solution

⎫ ⎪ ⎪ ⎬ ⎪ ⎪ ⎭

Primal problem

We first write down the following tableau for the given primal problem: x y 40 10 10 15 5 15 6 8

Constant 2400 2100 1500

Next, we interchange the columns and rows of the foregoing tableau and head the three columns of the resulting array with the three variables u, √, and w, obtaining the tableau u √ w 40 10 5 10 15 15 2400 2100 1500

Constant 6 8

Interpreting the last tableau as if it were part of the initial simplex tableau for a standard maximization problem—with the exception that the signs of the coefficients pertaining to the objective function are not reversed—we construct the required dual problem as follows: Maximize the objective function P  2400u  2100√  1500w subject to 40u  10√  5w 6 10u  15√  15w 8

u  0, √  0, w  0

⎫ ⎪ ⎪ Dual ⎬ problem ⎪ ⎪ ⎭

The connection between the solution of the primal problem and that of the dual problem is given by the following theorem. The theorem, attributed to John von Neumann (1903–1957), is stated without proof.

THEOREM 3 The Fundamental Theorem of Duality

A primal problem has a solution if and only if the corresponding dual problem has a solution. Furthermore, if a solution exists, then: a. The objective functions of both the primal and the dual problem attain the same optimal value. b. The optimal solution to the primal problem appears under the slack variables in the last row of the final simplex tableau associated with the dual problem.

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

379

Armed with this theorem, we will solve the problem posed in Example 2. EXAMPLE 3 Complete the solution to the problem posed in Example 2. Solution Observe that the dual problem associated with the given (primal) problem is a standard maximization problem. The solution may thus be found using the simplex algorithm. Introducing the slack variables x and y, we obtain the system of linear equations 40u  10√  5w  x 6 10u  15√  15w y 8 2400u  2100√  1500w P0

Continuing with the simplex algorithm, we obtain the following sequence of simplex tableaus: u √ w x y P Constant Pivot row 씮

40 10

10 15

2400

2100

앖 Pivot column

1

x

y

P

1 4

1 8

1 40

15

15

0

0 0 1 0

2400

2100

1500

0

0

y P

1

u

√

w

x

1

1 4

1 8

1 40

0

0

씮 0

5 2 2

55 4

 14

1

0

0

1500

1200

60

0

1

Pivot row

⎯→

w

0 0

1 10

1 40 R1 ⎯→

2 25 R2

1500

√

u

R2  10R1 ⎯⎯⎯⎯⎯→ R3  2400R1

5 1 0 0 15 0 1 0

앖 Pivot column

u

√

w

x

y P

1

1 4

1 8

1 40

0

0

0

1

11 10

 51 0

2 25

0

0

1500

1200

60

0

1

R1  14 R2 ⎯⎯⎯⎯⎯→ R3  1500R2

u

√

w

x

y

P

1

0

 23 0

3 100

 51 0

0

0

1

1 1 10

 510

2 25

0

0

0

450

30

120

1

 Solution for the primal problem



6 8

Ratio  203

6 40 8 10

 45

0



Constant



Constant



Constant



Constant

3 20

8 0

3 20 13 2

Ratio 3/20 1/4 13/2 25/2

 35  13 25

360

3 20 3 1 25

360

1 50 13 25

1140

The last tableau is final. The fundamental theorem of duality tells us that the solution to the primal problem is x  30 and y  120 with a minimum value for C of 1140. Observe that the solution to the dual (maximization) problem may be read from the simplex tableau in the usual manner: u  501 , √  13 25 , w  0, and P  1140.

380

6 LINEAR PROGRAMMING

Note that the maximum value of P is equal to the minimum value of C, as guaranteed by the fundamental theorem of duality. The solution to the primal problem agrees with the solution of the same problem solved in Section 6.3, Example 2, using the method of corners. Notes

1. We leave it to you to demonstrate that the dual of a standard minimization problem is always a standard maximization problem provided that the coefficients of the objective function in the primal problem are all nonnegative. Such problems can always be solved by applying the simplex method to solve the dual problem. 2. Standard minimization problems in which the coefficients of the objective function are not all nonnegative do not necessarily have a dual problem that is a standard maximization problem. EXAMPLE 4 Minimize subject to

C  3x  2y 8x  y  80 8x  5y  240 x  5y  100 x  0, y  0

We begin by writing the dual problem associated with the given primal problem. First, we write down the following tableau for the primal problem: Solution

x y 8 1 8 5 1 5 3 2

Constant 80 240 100

Next, interchanging the columns and rows of this tableau and heading the three columns of the resulting array with the three variables, u, √, and w, we obtain the tableau u √ 8 8 1 5 80 240

w 1 5 100

Constant 3 2

Interpreting the last tableau as if it were part of the initial simplex tableau for a standard maximization problem—with the exception that the signs of the coefficients pertaining to the objective function are not reversed—we construct the dual problem as follows: Maximize the objective function P  80u  240√  100w subject to the constraints 8u  8√  w 3 u  5√  5w 2

where u  0, √  0, and w  0. Having constructed the dual problem, which is a standard maximization problem, we now solve it using the simplex method. Introducing the slack variables x and y, we obtain the system of linear equations 8u  8√  wx 3 u  5√  5w y 2 80u  240√  100w P0

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

381

Continuing with the simplex algorithm, we obtain the following sequence of simplex tableaus: u √ w x y P Constant Ratio Pivot row 씮

8 1

8 5

80

240

0

1

0

√

w x

y

P

Constant

1 1

1 5

1 8

0 0 1

0 0

3 8

2

80

240

100

0

0

1

0

y

P

Constant

앖 Pivot column

u ⎯→

1 8

5

√

w

x

1 1

1 8  58

u 씮 4

0

1 8 35 8

160

0

70

30

0

1

90

u √

w

x

y

P

Constant

1 1 0

1 8

0

1

1 8 1  7

8 35

0 0

3 8 1 35

70

30

0

1

90

√ w

x

y

P

Constant

1 0 0 1

1 7  17

 31 5 8 35

0 0

13 35 1 35

20

16

1

92

Pivot row

8 35 R2

⎯→

앖 Pivot column

 332 5

160

0

u R1  18 R2 ⎯⎯⎯⎯→ R3  70R2

100

3 2

0

1 8 R1

R2  5R1 ⎯⎯⎯⎯→ R3  240R1

1 1 0 0 5 0 1 0

39 35  33 25

96

0

0

3 8 1 8

0 0 1 0

 Solution for the primal problem

3 8 2 5

Ratio 3 1 35

The last tableau is final. The fundamental theorem of duality tells us that the solution to the primal problem is x  20 and y  16 with a minimum value for C of 92. Our last example illustrates how the warehouse problem posed in Section 6.2 may be solved by duality. APPLIED EXAMPLE 5 A Warehouse Problem Complete the solution to the warehouse problem given in Section 6.2, Example 4 (page 333). Minimize C  20x1  8x2  10x3  12x4  22x5  18x6

(20)

subject to x1  x2  x3 x1 x2

400 x4  x5  x6 600  x4  200  x5  300 x3  x6  400

x1  0, x2  0, . . . , x6  0

(21)

382

6 LINEAR PROGRAMMING

Upon multiplying each of the first two inequalities of (21) by 1, we obtain the following equivalent system of constraints in which each of the expressions involving the variables is greater than or equal to a constant:

Solution

x1  x2  x3

 400  x4  x5  x6  600  x4

x1



200



300

 x6 

400

 x5

x2 x3

x1  0, x2  0, . . . , x6  000

The problem may now be solved by duality. First, we write the tableau: x1 x2 x3 x4 x5 x6 1 1 1 0 0 0 0 0 0 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 0 20

0 8

1 10

0 12

0 22

Constant 400 600 200 300

1 18

400

Interchanging the rows and columns of this tableau and heading the five columns of the resulting array of numbers by the variables u1, u2, u3, u4, and u5, we obtain the tableau: u1 u2 u3 u4 u5 1 0 1 0 0 1 0 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 0 1 0 0 1 0 0 1 400 600 200 300 400

Constant 20 8 10 12 22 18

from which we construct the associated dual problem: Maximize P  400u1  600u2  200u3  300u4  400u5 subject to  u1

 u3

 u1

20  u4

 u1

8  u5 10

 u2  u3  u2  u2

12  u4

22  u5 18

u1  0, u2  0, . . . , u5  00

Solving the standard maximization problem by the simplex algorithm, we obtain the following sequence of tableaus (x1, x2, . . . , x6 are slack variables):

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

u1 u2 u3 u4 u5 1 0 1 0 0 1 0 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 0 1 0 0 1 0 0 1 400 600 200 300 400

Pivot row 씮

x1 1 0 0 0 0 0 0

앖 Pivot column

Pivot row 씮

R6  R3 ⎯⎯⎯⎯→ R7  400R3

u1 u2 u3 u4 1 0 1 0 1 0 0 1 1 0 0 0 0 1 1 0 0 1 0 1 1 1 0 0 0 600 200 300

u5 0 0 1 0 0 0 0

R5  R2 ⎯⎯⎯⎯→ R7  300R2

Pivot row 씮

u1 1 1 1 0 1 1 300

u2 u3 0 1 0 0 0 0 1 1 1 0 1 0 600 200

u4 0 1 0 0 0 0 0

앖 Pivot column

R1  R6 R2  R6 ⎯⎯⎯⎯→ R3  R6 씮 R5  R6 R7  300R6 Pivot row

R1  R4 ⎯⎯⎯⎯→ R7  200R4

u1 0 0 0 0 0 1 0

u2 u3 1 1 1 0 1 0 1 1 0 0 1 0 300 200

u4 0 1 0 0 0 0 0

앖 Pivot column

u1 u2 0 0 0 1 0 1 0 1 0 0 1 1 0 100

u3 0 0 0 1 0 0 0

u4 0 1 0 0 0 0 0

u5 0 0 1 0 0 0 0

u5 0 0 1 0 0 0 0

u5 0 0 1 0 0 0 0

x3 0 0 1 0 0 0 0

x4 0 0 0 1 0 0 0

x5 0 0 0 0 1 0 0

x6 0 0 0 0 0 1 0

P 0 0 0 0 0 0 1

Constant 20 8 10 12 22 18 0

Ratio —

Ratio —

x2 x3 0 0 1 0 0 1 0 0 0 0 0 1 0 400

x4 0 0 0 1 0 0 0

x5 0 0 0 0 1 0 0

x6 0 0 0 0 0 1 0

P 0 0 0 0 0 0 1

Constant 20 8 10 12 22 8 4000

x1 x2 x3 1 0 0 0 1 0 0 0 1 0 0 0 0 1 0 0 0 1 0 300 400

x4 0 0 0 1 0 0 0

x5 0 0 0 0 1 0 0

x6 0 0 0 0 0 1 0

P 0 0 0 0 0 0 1

Constant 20 8 10 12 14 8 6400

x5 x6 0 1 0 1 0 1 0 0 1 1 0 1 0 300

P 0 0 0 0 0 0 1

Constant 28 16 18 12 6 8 8800

x5 x6 P 0 1 0 0 1 0 0 1 0 0 0 0 1 1 0 0 1 0 0 300 1

Constant 16 16 18 12 6 8 11,200

앖 Pivot column

x1 1 0 0 0 0 0 0

x2 0 1 0 0 0 0 0

x1 x2 x3 1 0 1 0 1 1 0 0 0 0 0 0 0 1 1 0 0 1 0 300 100

x4 0 0 0 1 0 0 0

x1 x2 x3 x4 1 0 1 1 0 1 1 0 0 0 0 0 0 0 0 1 0 1 1 0 0 0 1 0 0 300 100 200

383

— 10 — — 18

8 — — 22 —

Ratio — — — — 14 8

Ratio 28 — — 12 — —

384

6 LINEAR PROGRAMMING

The last tableau is final, and we find that x1  0

x2  300

x3  100

x5  0

x6  300

P  11,200

x4  200

Thus, to minimize shipping costs, Acrosonic should ship 300 loudspeaker systems from plant I to warehouse B, 100 systems from plant I to warehouse C, 200 systems from plant II to warehouse A, and 300 systems from plant II to warehouse C. The company’s total shipping cost is $11,200.

6.5 Self-Check Exercises 1. Write the dual problem associated with the following problem: Minimize C  2x  5y 4x  y  40

subject to

2. Solve the primal problem posed in Exercise 1. Solutions to Self-Check Exercises 6.5 can be found on page 386.

2x  y  30 x  3y  30 x  0, y  0

6.5 Concept Questions 1. Suppose you are given the linear programming problem Minimize C  3x  5y subject to 5x  2y 30 x  3y 21 x  0, y  0

Give the associated standard maximization problem that you would use to solve this linear programming problem via the simplex method.

3. What is the primal problem associated with a standard minimization linear programming problem? The dual problem? 4. a. What does the fundamental theorem of duality tell us about the existence of a solution to a primal problem? b. How are the optimal values of the primal and dual problems related? c. Given the final simplex tableau associated with a dual problem, how would you determine the optimal solution to the associated primal problem?

2. Give three characteristics of a standard minimization linear programming problem.

6.5 Exercises In Exercises 1–6, use the technique developed in this section to solve the minimization problem.

1. Minimize subject to

C  2x  y

4. Minimize subject to

2. Minimize

x  2y 6

subject to

C  2x  3y 3x  4y 24 7x  4y 16 x  0, y  0

3. Minimize C  3x  2y subject to the constraints of Exercise 2.

x  2y  3z 10 2x  y  2z 15 2x  y  3z 20

3x  2y 12 x  0, y  0

C  x  2y  z

x  0, y  0, z  0 5. Minimize subject to

C  2x  3y  4z x  2y  z 8 x  2y  2z 10 2x  4y  3z 12 x  0, y  0, z  0

6. Minimize C  3x  2y  z subject to the constraints of Exercise 5.

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

In Exercises 7–10, you are given the final simplex tableau for the dual problem. Give the solution to the primal problem and the solution to the associated dual problem.

C  8x  12y

7. Problem: Minimize

In Exercises 11–20, construct the dual problem associated with the primal problem. Solve the primal problem.

11. Minimize subject to

x  3y  2

subject to

2x  2y  3 x  0, y  0

13. Minimize

Final tableau:

385

subject to

C  2x  5y 12. Minimize

C  3x  2y

x  2y  4

subject to 2x  3y  90

3x  2y  6

3x  2y  120

x  0, y  0

x  0, y  0

C  6x  4y 14. Minimize

C  10x  y

6x  y  60

4x  y  16

subject to

u

√

x

y

P

Constant

0

1

3 4

 14

0

3

1 2

x 2

0

 12

x  y  30

1

0

2

x  0, y  0

x  0, y  00

0

0

5 4

1 4

1

13

2x  y  40

15. Minimize

8. Problem: Minimize C  3x  2y

subject to

subject to 5x  y  10

y  2z  20

x  0, y  0, z  0

x  4y  12 16. Minimize

x  0, y  0

subject to

Final tableau:

C  40x  30y  11z 2x  y  z  8 xyz6

u

√

w

x

y P

1

0

 34

1 4

 14 0

0

1

19 8

 18

5 8

0

7 8

0

0

9

1

5

1

13

Constant 1 4

x  0, y  0, z  0 17. Minimize subject to

4x  y  z  30 x  0, y  0, z  00

x  2y  2z  10 x  y  z  16 x  0, y  0, z  0

2x  y  5z  20

subject to

C  6x  8y  4z 2x  y  z  24

9. Problem: Minimize C  10x  3y  10z

18. Minimize subject to

C  12x  4y  8z 2x  4y  z  6 3x  2y  2z  2

Final tableau: y

z

4x  y  z  2

√

x

0

1

1 2

1

0

0

2

1

0

 12

2

0

0

1

19. Minimize

0

0

2

9 1

0

3

subject to

0

0

5

10

1

80

P

0

Constant

x  0, y  0, z  0 2x  4y  3z  6  z2 6 y  2z  4 x  0, y  0, z  0

x  4y  8

subject to

C  30x  12y  20z 6x

10. Problem: Minimize C  2x  3y x y5

20. Minimize

C  8x  6y  4z

2x  y  7

subject to

2x  3y  z  6 x  2y  2z  4

x  0, y  0 Final tableau:

x  y  2z  2 √

w

x

0

1

7 3

4 3

 13

0

5 3

1

0

 13  13

1 3

0

1 3

u

20x  10y  z  10 x

2x  2y  12

u

C  200x  150y  120z

0 0

2

4

y P

1 1

Constant

11

x  0, y  0, z  0

x  2y  12

386

6 LINEAR PROGRAMMING

21. TRANSPORTATION Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins and 160 standard cabins, whereas a type-B vessel has 80 deluxe cabins and 120 standard cabins. Under a charter agreement with Odyssey Travel Agency, Deluxe River Cruises is to provide Odyssey with a minimum of 360 deluxe and 680 standard cabins for their 15-day cruise in May. It costs $44,000 to operate a type-A vessel and $54,000 to operate a type-B vessel for that period. How many of each type vessel should be used in order to keep the operating costs to a minimum? What is the minimum cost? 22. SHIPPING COSTS Acrosonic manufactures a model-G loudspeaker system in plants I and II. The output at plant I is at most 800/month, and the output at plant II is at most 600/month. Model-G loudspeaker systems are also shipped to the three warehouses—A, B, and C—whose minimum monthly requirements are 500, 400, and 400 systems, respectively. Shipping costs from plant I to warehouse A, warehouse B, and warehouse C are $16, $20, and $22 per loudspeaker system, respectively, and shipping costs from plant II to each of these warehouses are $18, $16, and $14, respectively. What shipping schedule will enable Acrosonic to meet the requirements of the warehouses while keeping its shipping costs to a minimum? What is the minimum cost? 23. ADVERTISING Everest Deluxe World Travel has decided to advertise in the Sunday editions of two major newspapers in town. These advertisements are directed at three groups of potential customers. Each advertisement in newspaper I is seen by 70,000 group-A customers, 40,000 group-B customers, and 20,000 group-C customers. Each advertisement in newspaper II is seen by 10,000 group-A, 20,000 group-B, and 40,000 group-C customers. Each advertisement in newspaper I costs $1000, and each advertisement in newspaper II costs $800. Everest would like their advertisements to be read by at least 2 million people from group A, 1.4 million people from group B, and 1 million people from group C. How many advertisements should Everest place in each newspaper to achieve its advertising goals at a minimum cost? What is the minimum cost? 24. SHIPPING COSTS Steinwelt Piano manufactures uprights and consoles in two plants, plant I and plant II. The output of plant I is at most 300/month, and the output of plant II is at most 250/month. These pianos are shipped to three warehouses that serve as distribution centers for Steinwelt. To fill current and projected future orders, warehouse A requires a

minimum of 200 pianos/month, warehouse B requires at least 150 pianos/month, and warehouse C requires at least 200 pianos/month. The shipping cost of each piano from plant I to warehouse A, warehouse B, and warehouse C is $60, $60, and $80, respectively, and the shipping cost of each piano from plant II to warehouse A, warehouse B, and warehouse C is $80, $70, and $50, respectively. What shipping schedule will enable Steinwelt to meet the requirements of the warehouses while keeping the shipping costs to a minimum? What is the minimum cost? 25. NUTRITION—DIET PLANNING The owner of the Health JuiceBar wishes to prepare a low-calorie fruit juice with a high vitamin A and vitamin C content by blending orange juice and pink grapefruit juice. Each glass of the blended juice is to contain at least 1200 International Units (IU) of vitamin A and 200 IU of vitamin C. One ounce of orange juice contains 60 IU of vitamin A, 16 IU of vitamin C, and 14 calories; each ounce of pink grapefruit juice contains 120 IU of vitamin A, 12 IU of vitamin C, and 11 calories. How many ounces of each juice should a glass of the blend contain if it is to meet the minimum vitamin requirements while containing a minimum number of calories? 26. PRODUCTION CONTROL An oil company operates two refineries in a certain city. Refinery I has an output of 200, 100, and 100 barrels of low-, medium-, and high-grade oil per day, respectively. Refinery II has an output of 100, 200, and 600 barrels of low-, medium-, and high-grade oil per day, respectively. The company wishes to produce at least 1000, 1400, and 3000 barrels of low-, medium-, and highgrade oil to fill an order. If it costs $200/day to operate refinery I and $300/day to operate refinery II, determine how many days each refinery should be operated in order to meet the production requirements at minimum cost to the company. What is the minimum cost? In Exercises 27 and 28, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

27. If a standard minimization linear programming problem has a unique solution, then so does the corresponding maximization problem with objective function P  C, where C  a1x1  a2x2      anxn is the objective function for the minimization problem. 28. The optimal value attained by the objective function of the primal problem may be different from that attained by the objective function of the dual problem.

6.5 Solutions to Self-Check Exercises 1. We first write down the following tableau for the given (primal) problem: x y 4 1 2 1 1 3 2 5

Constant 40 30 30 0

Next, we interchange the columns and rows of the tableau and head the three columns of the resulting array with the three variables, u, √, and w, obtaining the tableau u √ w 4 2 1 1 1 3 40 30 30

Constant 2 5 0

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

Interpreting the last tableau as if it were the initial tableau for a standard linear programming problem—with the exception that the signs of the coefficients pertaining to the objective function are not reversed—we construct the required dual problem as follows: P  40u  30√  30w 4u  2√  w 2 u  √  3w 5 u  0, √  0, w  0

Maximize subject to

u

√

w

x

y P

1 0

1 2

1 4

1 4

0

2 11

1

 111

0

10

20

10

Pivot row 씮

u

√

1 0

5 11 2 11

0

 71 01

2. We introduce slack variables x and y to obtain the system of linear equations 4u  2√  w  x 2 u  √  3w y 5 40u  30√  30w P0

Using the simplex algorithm, we obtain the sequence of simplex tableaus Pivot row 씮

u

√

w x

y P

4

2

1

0

0

2

1 1 3 0 1 0 40 30 30 0 0 1 앖 Pivot column

5 0

u

√

1

1 2

1 40 u

1

Constant

w x 1 4

1 4

y P

1 2

1 3 0 1 0 30 30 0 0 1

5 0

√

w

x y P

1 2

1 4

1 4

1 Pivot 1 11 씮 0 2 4 row 0 10 20



0 0 1 0

10

0

1 4

1

5 1

5

⎯→

Constant 1 2 9 2

Ratio 2

9/2 11/4

 18 11

1 2 1 8 11

0

1

20

w

x

y

P

Constant

0 1

3 11 1  11

 111

0 0

1 11 18 11

0

90 11

80 11

1

580 11

R1  14 R2 ———씮 R3  20R2

Ratio 1/11 5/11

 15

18/11 2/11

9

11 5 R1 ⎯→

u

√

11 5

1

0

2 11

w

 710 1 0

0

11 5

√

x

y

P

3 1  0 5 5 1 4 1  1 1 11 90 11

80 11

w

x 3 5

 15

 15

2 5

2 5



1 0

0 1

14

0

0

y P 0 0

12 6 1  Solution for the primal problem

Constant

0 0

1 5 18 11

1

580 11

R2  112 R1 ⎯⎯⎯→ R3  70 11 R1

Constant 1 5 8 5

54

The last tableau is final, and the solution to the primal problem is x  12 and y  6 with a minimum value for C of 54.

R2  R1 ————씮 R3  40R1

1/2 1/4

0 0

앖 Pivot column

u 1 4 R1

Constant

0

0

Ratio 2 1 4  2

Constant

4 11

4 11

387

4 11 R2 ⎯→

20

앖 Pivot column

USING

TECHNOLOGY

The Simplex Method: Solving Minimization Problems Graphing Utility

A graphing utility can be used to solve minimization problems using the simplex method. EXAMPLE 1 Minimize C  2x  3y subject to 8x  y  80 3x  2y  100 x  4y  80 x  0, y  0 (continued)

388

6 LINEAR PROGRAMMING

Solution We begin by writing the dual problem associated with the given primal problem. From the tableau for the primal problem

x y 8 1 3 2 1 4 2 3

Constant 80 100 80

we obtain—upon interchanging the columns and rows of this tableau and heading the three columns of the resulting array with the variables u, √, and w—the tableau √ 3 2 100

u 8 1 80

w 1 4 80

Constant 2 3

This tells us that the dual problem is Maximize

P  80u  100√  80w

subject to

8u  3√  w 2 u  2√  4w 3 u  0, √  0, w  0

To solve this standard maximization problem, we proceed as follows:

Pivot row 씮

u

√

w x

8 1

3 2

1 1 0 0 4 0 1 0

80 100

80

y

0

P

0

1

y

P

Constant 2 3

Ratio 2 3 3 2

*rowÓ 13 , A, 1Ô 䉴 B ⎯⎯⎯⎯⎯⎯⎯→

0

앖 Pivot column

√

u 2.67 1 80

1 2 100

x

0.33 4 80

√

w

2.67 4.33

1 0

0.33 3.33

186.67

0

46.67

u Pivot row 씮

w

Constant

0.33 0 0 0 1 0

0.67 3

0

0

0 x

1

y P

0.33 0 0 0.67 1 0 33.33

0

Constant 0.67 1.67

1

66.67

Constant

*row(2, B, 1, 2) 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→ *row(100, C, 1, 3) 䉴 B

Ratio 2 0.5

1 *rowÓ 3.33 , B, 2Ô 䉴 C ⎯⎯⎯⎯⎯⎯⎯⎯→

앖 Pivot column

u

√

w

x

y

P

2.67 1.30

1 0

0.33 1

0.33 0.2

0 0.3

0 0

0.67 0.5

186.67

0 46.67

33.33

0

1

66.67

*row(0.33, C, 2, 1) 䉴 B ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→ *row(46.67, B, 2, 3) 䉴 C

6.5 THE SIMPLEX METHOD: STANDARD MINIMIZATION PROBLEMS

u

√ w

3.1 1.3

1 0 0 1

125.93

0

x

y 0.1 0.3

0.4 0.2

0.05

P

23.99

14.02

 Solution for the primal problem

389

Constant

0 0

0.50 0.50

1

90.03

From the last tableau, we see that x  23.99, y  14.02, and the minimum value of C is 90.03. Excel

EXAMPLE 2 Minimize subject to

C  2x  3y 8x  y  80 3x  2y  100 x  4y  80 x  0, y  0

We use Solver as outlined in Example 2, pages 373–376, to obtain the spreadsheet shown in Figure T1. (In this case, select Min next to Equal to: instead of Max because this is a minimization problem. Also select >= in the Add Constraint dialog box because the inequalities in the problem are of the form .) From the spreadsheet, we read off the solution: x  24, y  14, and C  90. Solution

1 2 3 4 5 6 7 8 9 10 11 12 13

A Minimization Problem

B

C

D

Decision Variables x y

Objective Function

24 14

E

F

G

H

I

Formulas for indicated cells C8: = 2*C4 + 3*C5 C11: = 8*C4 + C5 C12: = 3*C4 + 2*C5 C13: = C4 + 4*C5

90

Constraints 206 >= 100 >= 80 >=

80 100 80

FIGURE T1 Completed spreadsheet after using Solver

Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicate words/characters that need to be typed and entered.

(continued)

390

6 LINEAR PROGRAMMING

TECHNOLOGY EXERCISES In Exercises 1–4, solve the linear programming problem by the simplex method.

1. Minimize subject to

3. Minimize subject to

C  x  y  3z 2x  y  3z  6

1.2x 

3y 

5z  12

3y  1.8z  14

x  0, y  0, z  0

3x  y  2z  4 4. Minimize

x  0, y  0, z  0

subject to subject to

2x 

3x  1.2y  2.2z  8

x  2y  4z  8

2. Minimize

C  x  1.2y  3.5z

C  2x  4y  z

C  2.1x  1.2y  z x

y

z  5.2

x  2.1y  4.2z  8.4

x  2y  4z  7

x  0, y  0, z  0

3x  y  z  6 x  4y  2z  24 x  0, y  0, z  0

CHAPTER 6 Summary of Principal Terms TERMS solution set of a system of linear inequalities (325) bounded solution set (326) unbounded solution set (326) objective function (330) linear programming problem (330) feasible solution (338) feasible set (338)

optimal solution (338) isoprofit line (339) method of corners (340) standard maximization problem (351) slack variable (352) basic variable (353) nonbasic variable (353) basic solution (354)

pivot column (355) pivot row (355) pivot element (355) simplex tableau (356) simplex method (357) standard minimization problem (377) primal problem (378) dual problem (378)

CHAPTER 6 Concept Review Questions Fill in the blanks.

1. a. The solution set of the inequality ax  by c is a/an _____ _____ that does not include the _____ with equation ax  by  c. b. If ax  by c describes the lower half plane, then the inequality _____ describes the lower half plane together with the line having equation _____ . 2. a. The solution set of a system of linear inequalities in the two variables x and y is the set of all _____ satisfying _____ inequality of the system. b. The solution set of a system of linear inequalities is _____ if it can be _____ by a circle. 3. A linear programming problem consists of a linear function, called a/an _____ _____ to be _____ or _____ subject to constraints in the form of _____ equations or _____ . 4. a. If a linear programming problem has a solution, then it must occur at a/an _____ _____ of the feasible set.

b. If the objective function of a linear programming problem is optimized at two adjacent vertices of the feasible set, then it is optimized at every point on the _____ segment joining these vertices. 5. In a standard maximization problem: the objective function is to be _____ ; all the variables involved in the problem are _____ ; and each linear constraint may be written so that the expression involving the variables is _____ _____ or _____ _____ a nonnegative constant. 6. In setting up the initial simplex tableau, we first transform the system of linear inequalities into a system of linear _____ , using _____ _____ ; the objective function is rewritten so that it has the form _____ and then is placed _____ the system of linear equations obtained earlier. Finally, the initial simplex tableau is the _____ matrix associated with this system of linear equations.

REVIEW EXERCISES

7. In a standard minimization problem: the objective function is to be _____; all the variables involved in the problem are _____; and each linear constraint may be written so that the expression involving the variables is _____ _____ or _____ _____ a constant.

391

8. The fundamental theorem of duality states that a primal problem has a solution if and only if the corresponding _____ problem has a solution. If a solution exists, then the _____ functions of both the primal and the dual problem attain the same _____ _____.

CHAPTER 6 Review Exercises In Exercises 1 and 2, find the optimal value(s) of the given objective function on the feasible set S.

1. Z  2x  3y y

8. Maximize P  6x  2y subject to x  2y 12 x y 8 2x  3y  6 x  0, y  0

(0, 6) (3, 4)

x (0, 0)

(5, 0)

2. Z  4x  3y

(3, 5)

(1, 3)

11. Find the maximum and minimum of Q  x  y subject to

S (1, 6) x

In Exercises 3–12, use the method of corners to solve the given linear programming problem.

3. Maximize subject to

P  3x  5y 2x  3y 12 x y 5 x  0, y  0

4. Maximize P  2x  3y subject to 2x  y 12 x  2y 1 x  0, y  0 5. Minimize C  2x  5y subject to x  3y  15 4x  y  16 x  0, y  0 6. Minimize C  3x  4y subject to 2x  y  4 2x  5y  10 x  0, y  0

9. Minimize C  2x  7y subject to 3x  5y  45 3x  10y  60 x  0, y  0 10. Minimize C  4x  y subject to 6x  y  18 2x  y  10 x  4y  12 x  0, y  0

y

(1, 1)

7. Maximize P  3x  2y subject to 2x  y 16 2x  3y 36 4x  5y  28 x  0, y  0

5x  2y  20 x  2y  8 x  4y 22 x  0, y  0 12. Find the maximum and minimum of Q  2x  5y subject to x y 4 x  y 6 x  3y 30 x 12 x  0, y  0 In Exercises 13–20, use the simplex method to solve the linear programming problem.

13. Maximize P  3x  4y subject to x  3y 15 4x  y 16 x  0, y  0

14. Maximize P  2x  5y subject to 2x  y 16 2x  3y 24 y 6 x  0, y  0

15. Maximize P  2x  3y  5z subject to x  2y  3z 12 x  3y  2z 10 x  0, y  0, z  0

392

6 LINEAR PROGRAMMING

16. Maximize P  x  2y  3z subject to 2x  y  z 14 3x  2y  4z 24 2x  5y  2z 10 x  0, y  0, z  0 17. Minimize C  3x  2y 18. Minimize subject to 2x  3y  6 subject to 2x  y  4 x  0, y  0

C  x  2y 3x  y  12 x  4y  16 x  0, y  0

19. Minimize C  24x  18y  24z subject to 3x  2y  z  4 x  y  3z  6 x  0, y  0, z  0 20. Minimize C  4x  2y  6z subject to x  2y  z  4 2x  y  2z  2 3x  2y  z  3 x  0, y  0, z  0 In Exercises 21–23, use the method of corners to solve the linear programming problem.

21. FINANCIAL ANALYSIS An investor has decided to commit no more than $80,000 to the purchase of the common stocks of two companies, company A and company B. He has also estimated that there is a chance of at most a 1% capital loss on his investment in company A and a chance of at most a 4% loss on his investment in company B, and he has decided that these losses should not exceed $2000. On the other hand, he expects to make a 14% profit from his investment in company A and a 20% profit from his investment in company B. Determine how much he should invest in the stock of each company in order to maximize his investment returns. 22. MANUFACTURING—PRODUCTION SCHEDULING Soundex produces two models of clock radios. Model A requires 15 min of work on assembly line I and 10 min of work on assembly line II. Model B requires 10 min of work on assembly line I and 12 min of work on assembly line II. At most, 25 labor-hours of assembly time on line I and 22 labor-hours of assembly time on line II are available each day. It is anticipated that Soundex will realize a profit of $12 on model A and $10 on model B. How many clock radios of each model should be produced each day in order to maximize Soundex’s profit? 23. MANUFACTURING—PRODUCTION SCHEDULING Kane Manufacturing has a division that produces two models of grates, model A and model B. To produce each model A grate

requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $2.00, and the profit for each model B grate is $1.50. Available for grate production each day are 1000 lb of cast iron and 20 laborhours. Because of a backlog of orders for model B grates, Kane’s manager has decided to produce at least 180 model B grates/day. How many grates of each model should Kane produce to maximize its profits? In Exercises 24–26, use the simplex method to solve the linear programming problem.

24. MINING—PRODUCTION Perth Mining Company operates two mines for the purpose of extracting gold and silver. The Saddle Mine costs $14,000/day to operate, and it yields 50 oz of gold and 3000 oz of silver each day. The Horseshoe Mine costs $16,000/day to operate and it yields 75 oz of gold and 1000 oz of silver each day. Company management has set a target of at least 650 oz of gold and 18,000 oz of silver. How many days should each mine be operated at so that the target can be met at a minimum cost to the company? What is the minimum cost? 25. INVESTMENT ANALYSIS Jorge has decided to invest at most $100,000 in securities in the form of corporate stocks. He has classified his options into three groups of stocks: bluechip stocks that he assumes will yield a 10% return (dividends and capital appreciation) within a year, growth stocks that he assumes will yield a 15% return within a year, and speculative stocks that he assumes will yield a 20% return (mainly due to capital appreciation) within a year. Because of the relative risks involved in his investment, Jorge has further decided that no more than 30% of his investment should be in growth and speculative stocks and at least 50% of his investment should be in blue-chip and speculative stocks. Determine how much Jorge should invest in each group of stocks in the hope of maximizing the return on his investments. 26. MAXIMIZING PROFIT A company manufactures three products, A, B, and C, on two machines, I and II. It has been determined that the company will realize a profit of $4/unit of product A, $6/unit of product B, and $8/unit of product C. Manufacturing a unit of product A requires 9 min on machine I and 6 min on machine II; manufacturing a unit of product B requires 12 min on machine I and 6 min on machine II; manufacturing a unit of product C requires 18 min on machine I and 10 min on machine II. There are 6 hr of machine time available on machine I and 4 hr of machine time available on machine II in each work shift. How many units of each product should be produced in each shift in order to maximize the company’s profit?

BEFORE MOVING ON . . .

393

CHAPTER 6 Before Moving On . . . 1. Find the maximum and minimum values of Z  3x  y on the following feasible set. y

Write the initial simplex tableau for the problem and identify the pivot element to be used in the first iteration of the simplex method. 4. The following simplex tableau is in final form. Find the solution to the linear programming problem associated with this tableau.

(16, 24)

(3, 16) (28, 8) (8, 2)

x

2. Use the method of corners to solve the following linear programming problem: Maximize P  x  3y subject to 2x  3y 11 3x  7y 24 x  0, y  0 3. Consider the following linear programming problem: Maximize

P  x  2y  3z

subject to 2x  y  z 3 x  2y  3z 1 3x  2y  4z 17 x  0, y  0, z  0

x

y

z

u

√

w

P

0

0

1

21

0

0

2

1

0 0

12 1 2

11

0

5 4 34

0

1

1 2 1 4 1 4

0

2

0

13 4

0

1 4

1 2

1

28

0

0

Constant

5. Using the simplex method, solve the following linear programming problem: Maximize

P  5x  2y

subject to 4x  3y 30 2x  3y 6 x  0, y  0

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7

SETS AND PROBABILITY

W

E OFTEN DEAL with well-defined collections of objects

called sets. In this chapter, we see how sets can be

combined algebraically to yield other sets. We also look at some techniques for determining the number of elements in a set and

arranged or combined. After giving the technical meaning of the term probability, we see how the rules of probability are applied to many real-life situations to compute the probability of the occurrence of certain events.

© Photodisc/Getty Images

for determining the number of ways the elements of a set can be

In how many ways can the Futurists (a rock group) plan their concert tour to San Francisco, Los Angeles, San Diego, Denver, and Las Vegas if the three performances in California must be given consecutively? In Example 13, page 425, we will show how to determine the number of possible different itineraries.

396

7 SETS AND PROBABILITY

7.1 Sets and Set Operations Set Terminology and Notation We often deal with collections of different kinds of objects. For example, in conducting a study of the distribution of the weights of newborn infants, we might consider the collection of all infants born in Massachusetts General Hospital during 2008. In a study of the fuel consumption of compact cars, we might be interested in the collection of compact cars manufactured by General Motors in the 2008 model year. Such collections are examples of sets. More specifically, a set is a well-defined collection of objects. Thus, a set is not just any collection of objects; a set must be well defined in the sense that if we are given an object, then we should be able to determine whether or not it belongs to the collection. The objects of a set are called the elements, or members, of a set and are usually denoted by lowercase letters a, b, c, . . . ; the sets themselves are usually denoted by uppercase letters A, B, C, . . . . The elements of a set can be displayed by listing all the elements between braces. For example, using roster notation, the set A consisting of the first three letters of the English alphabet is written A  {a, b, c}

The set B of all letters of the alphabet can be written B  {a, b, c, . . . , z}

Another notation commonly used is set-builder notation. Here, a rule is given that describes the definite property or properties an object x must satisfy to qualify for membership in the set. Using this notation, the set B is written as B  {x 0 x is a letter of the English alphabet}

and is read “B is the set of all elements x such that x is a letter of the English alphabet.” If a is an element of a set A, we write a  A and read “a belongs to A” or “a is an element of A.” If, however, the element a does not belong to the set A, then we write a A and read “a does not belong to A.” For example, if A  {1, 2, 3, 4, 5}, then 3  A but 6 A.

Explore & Discuss 1. Let A denote the collection of all the days in August 2008 in which the average daily temperature at the San Francisco International Airport was approximately 75°F. Is A a set? Explain your answer. 2. Let B denote the collection of all the days in August 2008 in which the average daily temperature at the San Francisco International Airport was between 73.5°F and 81.2°F, inclusive. Is B a set? Explain your answer.

Set Equality

Two sets A and B are equal, written A  B, if and only if they have exactly the same elements. EXAMPLE 1 Let A, B, and C be the sets A  {a, e, i, o, u} B  {a, i, o, e, u} C  {a, e, i, o}

7.1 SETS AND SET OPERATIONS

397

Then, A  B since they both contain exactly the same elements. Note that the order in which the elements are displayed is immaterial. Also, A  C since u  A but u C. Similarly, we conclude that B  C. Subset

If every element of a set A is also an element of a set B, then we say that A is a subset of B and write A B. By this definition, two sets A and B are equal if and only if (1) A B and (2) B A. You can verify this (see Exercise 66). EXAMPLE 2 Referring to Example 1, we find that C B since every element of C is also an element of B. Also, if D is the set D  {a, e, i, o, x}

then D is not a subset of A, written D  A, since x  D but x A. Observe that A  D as well, since u  A but u D. If A and B are sets such that A B but A  B, then we say that A is a proper subset of B. In other words, a set A is a proper subset of a set B, written A  B, if (1) A B and (2) there exists at least one element in B that is not in A. The second condition states that the set A is properly “smaller” than the set B. EXAMPLE 3 Let A  {1, 2, 3, 4, 5, 6} and B  {2, 4, 6}. Then B is a proper subset of A because (1) B A, which is easily verified, and (2) there exists at least one element in A that is not in B—for example, the element 1. When we refer to sets and subsets we use the symbols , , , and  to express the idea of “containment.” However, when we wish to show that an element is contained in a set, we use the symbol  to express the idea of “membership.” Thus, in Example 3, we would write 1  A and not {1}  A. Empty Set

The set that contains no elements is called the empty set and is denoted by . The empty set, , is a subset of every set. To see this, observe that  has no elements. Thus it contains no element that is not also in any set A. EXAMPLE 4 List all subsets of the set A  {a, b, c}. There is one subset consisting of no elements—namely, the empty set . Next, observe that there are three subsets consisting of one element,

Solution

{a}, {b}, {c}

three subsets consisting of two elements, {a, b}, {a, c}, {b, c}

and one subset consisting of three elements, the set A itself. Therefore, the subsets of A are , {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c}

398

7 SETS AND PROBABILITY

In contrast with the empty set, we have, at the other extreme, the notion of a largest, or universal, set. A universal set is the set of all elements of interest in a particular discussion. It is the largest in the sense that all sets considered in the discussion of the problem are subsets of the universal set. Of course, different universal sets are associated with different problems, as shown in Example 5. EXAMPLE 5 a. If the problem at hand is to determine the ratio of female to male students in a college, then a logical choice of a universal set is the set consisting of the whole student body of the college. b. If the problem is to determine the ratio of female to male students in the business department of the college in part (a), then the set of all students in the business department can be chosen as the universal set. A visual representation of sets is realized through the use of Venn diagrams, which are of considerable help in understanding the concepts introduced earlier as well as in solving problems involving sets. The universal set U is represented by a rectangle, and subsets of U are represented by regions lying inside the rectangle. EXAMPLE 6 Use Venn diagrams to illustrate the following statements: a. The sets A and B are equal. b. The set A is a proper subset of the set B. c. The sets A and B are not subsets of each other. Solution

The respective Venn diagrams are shown in Figure 1a–c.

U

U

A, B

B

(a) A  B

A

(b) A  B

U

A

FIGURE 1

B

U

or

A

B

(c) A  B and B  A

Set Operations Having introduced the concept of a set, our next task is to consider operations on sets—that is, to consider ways in which sets can be combined to yield other sets. These operations enable us to combine sets in much the same way the operations of addition and multiplication enable us to combine numbers to obtain other numbers. In what follows, all sets are assumed to be subsets of a given universal set U.

7.1 SETS AND SET OPERATIONS

399

Set Union

Let A and B be sets. The union of A and B, written A  B, is the set of all elements that belong to either A or B or both. A  B  5x 0 x  A or x  B or both6

U

The shaded portion of the Venn diagram (Figure 2) depicts the set A  B. EXAMPLE 7 If A  {a, b, c} and B  {a, c, d}, then A  B  {a, b, c, d}.

A

U

B

Set Intersection

Let A and B be sets. The set of elements common to the sets A and B, written A  B, is called the intersection of A and B.

FIGURE 2

Set union A  B

A  B  5x 0 x  A and x  B6

U

A

The shaded portion of the Venn diagram (Figure 3) depicts the set A  B. EXAMPLE 8 Let A  {a, b, c} and B  {a, c, d}. Then A  B  {a, c}. (Compare this result with Example 7.)

B

EXAMPLE 9 Let A  {1, 3, 5, 7, 9} and B  {2, 4, 6, 8, 10}. Then A  B  . FIGURE 3

The two sets of Example 9 have empty, or null, intersection. In general, the sets A and B are said to be disjoint if they have no elements in common—that is, if A  B  .

Set intersection A  B

EXAMPLE 10 Let U be the set of all students in the classroom. If M  {x  U 0 x is male} and F  {x  U 0 x is female}, then F  M   and so F and M are disjoint.

Complement of a Set

If U is a universal set and A is a subset of U, then the set of all elements in U that are not in A is called the complement of A and is denoted Ac. Ac  5x 0 x  U and x A6

U

The shaded portion of the Venn diagram (Figure 4) shows the set Ac. EXAMPLE 11 Let U  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and A  {2, 4, 6, 8, 10}. Then Ac  {1, 3, 5, 7, 9}.

A Ac

FIGURE 4

Explore & Discuss

Set complementation

Let A, B, and C be nonempty subsets of a set U. 1. Suppose A  B  , A  C  , and B  C  . Can you conclude that A  B  C  ? Explain your answer with an example. 2. Suppose A  B  C  . Can you conclude that A  B  , A  C  , and B  C  ? Explain your answer.

400

7 SETS AND PROBABILITY

The following rules hold for the operation of complementation. See whether you can verify them.

Set Complementation

If U is a universal set and A is a subset of U, then a. U c   d. A  Ac  U

b.  c  U e. A  Ac  

c. (Ac )c  A

The operations on sets satisfy the following properties.

Properties of Set Operations

Let U be a universal set. If A, B, and C are arbitrary subsets of U, then ABBA

Commutative law for union

ABBA

Commutative law for intersection

A  (B  C )  (A  B)  C

Associative law for union

A  (B  C )  (A  B)  C

Associative law for intersection

A  (B  C )  (A  B)  (A  C )

Distributive law for union

A  (B  C )  (A  B)  (A  C )

Distributive law for intersection

Two additional properties, referred to as De Morgan’s laws, hold for the operations on sets.

De Morgan’s Laws

Let A and B be sets. Then (A  B)c  Ac  Bc (A  B)c  Ac  Bc

(1) (2)

Equation (1) states that the complement of the union of two sets is equal to the intersection of their complements. Equation (2) states that the complement of the intersection of two sets is equal to the union of their complements. We will not prove De Morgan’s laws here, but we will demonstrate the validity of (2) in the following example. U

EXAMPLE 12 Using Venn diagrams, show that A

B

(A  B)c  Ac  Bc

(A  B)c is the set of elements in U but not in A  B and is thus the shaded region shown in Figure 5. Next, Ac and Bc are shown in Figure 6a–b. Their union, Ac  Bc, is easily seen to be equal to (A  B)c by referring once again to Figure 5. Solution

FIGURE 5 (A  B)c

7.1 SETS AND SET OPERATIONS

U

U

A

A  B is the set obtained by joining (a) and (b). c

B Ac

FIGURE 6

401

Bc

c

(a)

(b)

EXAMPLE 13 Let U  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A  {1, 2, 4, 8, 9}, and B  {3, 4, 5, 6, 8}. Verify by direct computation that (A  B)c  Ac  Bc. A  B  {1, 2, 3, 4, 5, 6, 8, 9}, so (A  B)c  {7, 10}. Moreover, A  {3, 5, 6, 7, 10} and Bc  {1, 2, 7, 9, 10}, so Ac  Bc  {7, 10}. The required result follows. Solution c

APPLIED EXAMPLE 14 Automobile Options Let U denote the set of all cars in a dealer’s lot, and let A  {x  U 0 x is equipped with automatic transmission} B  {x  U 0 x is equipped with air conditioning} C  {x  U 0 x is equipped with side air bags}

Find an expression in terms of A, B, and C for each of the following sets: a. The set of cars with at least one of the given options b. The set of cars with exactly one of the given options c. The set of cars with automatic transmission and side air bags but no air conditioning Solution

a. The set of cars with at least one of the given options is A  B  C (Figure 7a). b. The set of cars with automatic transmission only is given by A  Bc  C c. Similarly, we find that the set of cars with air conditioning only is given by B  C c  Ac, while the set of cars with side air bags only is given by C  Ac  Bc. Thus, the set of cars with exactly one of the given options is (A  Bc  Cc)  (B  Cc  Ac)  (C  Ac  Bc) (Figure 7b). c. The set of cars with automatic transmission and side air bags but no air conditioning is given by A  C  Bc (Figure 7c).

U A

B C

(a) The set of cars with at least one option FIGURE 7

U A

B C

(b) The set of cars with exactly one option

U B

A C

(c) The set of cars with automatic transmission and side air bags but no air conditioning

402

7 SETS AND PROBABILITY

7.1 Self-Check Exercises 1. Let U  {1, 2, 3, 4, 5, 6, 7}, A  {1, 2, 3}, B  {3, 4, 5, 6}, and C  {2, 3, 4}. Find the following sets: a. Ac b. A  B c. B  C d. (A  B)  C e. (A  B)  C f. Ac  (B  C)c 2. Let U denote the set of all members of the House of Representatives. Let D  {x  U 0 x is a Democrat}

F  {x  U 0 x is a female}

L  {x  U 0 x is a lawyer by training}

Describe each of the following sets in words. a. D  F b. Fc  R c. D  F  Lc Solutions to Self-Check Exercises 7.1 can be found on page 405.

R  {x  U 0 x is a Republican}

7.1 Concept Questions 1. a. What is a set? Give an example. b. When are two sets equal? Give an example of two equal sets. c. What is the empty set?

3. a. If A  B, what can you say about the relationship between Ac and Bc? b. If Ac  , what can you say about A?

2. What can you say about two sets A and B such that a. A  B A b. A  B   c. A  B  B d. A  B  

7.1 Exercises In Exercises 1–4, write the set in set-builder notation.

1. The set of gold medalists in the 2010 Winter Olympic Games

In Exercises 15 and 16, let A  {1, 2, 3, 4, 5}. Determine whether the statements are true or false.

15. a. 2  A

b. A {2, 4, 6}

2. The set of football teams in the NFL

16. a. 0  A

b. {1, 3, 5}  A

3. {3, 4, 5, 6, 7}

17. Let A  {1, 2, 3}. Which of the following sets are equal to A? a. {2, 1, 3} b. {3, 2, 1} c. {0, 1, 2, 3}

4. {1, 3, 5, 7, 9, 11, . . . , 39} In Exercises 5–8, list the elements of the set in roster notation.

5. {x 0 x is a digit in the number 352,646}

6. {x 0 x is a letter in the word HIPPOPOTAMUS}

7. {x 0 2  x  4 and x is an integer} 8. {x 0 2  x  4 and x is a fraction}

In Exercises 9–14, state whether the statements are true or false.

9. a. {a, b, c}  {c, a, b}

b. A  A

10. a.   A

b. A  A

11. a. 0  

b. 0  

12. a. {}  

b. {a, b}  {a, b, c}

13. {Chevrolet, Pontiac, Buick}  {x 0 x is a division of General Motors}

14. {x 0 x is a silver medalist in the 2010 Winter Olympic Games}  

18. Let A  {a, e, l, t, r}. Which of the following sets are equal to A? a. {x 0 x is a letter of the word later} b. {x 0 x is a letter of the word latter} c. {x 0 x is a letter of the word relate} 19. List all subsets of the following sets: a. {1, 2} b. {1, 2, 3}

c. {1, 2, 3, 4}

20. List all subsets of the set A  {IBM, U.S. Steel, Union Carbide, Boeing}. Which of these are proper subsets of A? In Exercises 21–24, find the smallest possible set (i.e., the set with the least number of elements) that contains the given sets as subsets.

21. {1, 2}, {1, 3, 4}, {4, 6, 8, 10} 22. {1, 2, 4}, {a, b} 23. {Jill, John, Jack}, {Susan, Sharon} 24. {GM, Ford, Chrysler}, {Daimler-Benz, Volkswagen}, {Toyota, Nissan}

7.1 SETS AND SET OPERATIONS

25. Use Venn diagrams to represent the following relationships: a. A  B and B  C b. A  U and B  U, where A and B have no elements in common c. The sets A, B, and C are equal. 26. Let U denote the set of all students who applied for admission to the freshman class at Faber College for the upcoming academic year, and let A  {x  U 0 x is a successful applicant}

In Exercises 37 and 38, determine whether the pairs of sets are disjoint.

37. a. {1, 2, 3, 4}, {4, 5, 6, 7} b. {a, c, e, t}, {b, d, f } 38. a. , {1, 3, 5} b. {0, 1, 3, 4}, {0, 2, 5, 7}

In Exercises 39–42, let U denote the set of all employees at Universal Life Insurance Company and let

B  {x  U 0 x is a female student who enrolled in the freshman class}

T  {x 苸 U 兩 x drinks tea}

C  {x  U 0 x is a male student who enrolled in the freshman class}

C  {x 苸 U 兩 x drinks coffee}

a. Use Venn diagrams to represent the sets U, A, B, and C. b. Determine whether the following statements are true or false. i. A B ii. B  A iii. C  B In Exercises 27 and 28, shade the portion of the accompanying figure that represents each set.

27. a. A  Bc b. Ac  B

U

28. a. A  B b. (A  B)c c

c

A

403

Describe each set in words.

39. a. T c

b. C c

40. a. T  C 41. a. T  C

b. T  C c

42. a. T c  C c

b. T c  C b. (T  C )c

In Exercises 43–46, let U denote the set of all employees in a hospital. Let

B

N  {x 苸 U 兩 x is a nurse}

D  {x 苸 U 兩 x is a doctor}

A  {x 苸 U 兩 x is an administrator}

M  {x 苸 U 兩 x is a male}

In Exercises 29–32, shade the portion of the accompanying figure that represents each set. U A

B C

29. a. A  B  C

b. A  B  C

30. a. A  B  Cc

b. Ac  B  C

31. a. Ac  Bc  Cc

b. (A  B)c  C

32. a. A  (B  C)c

b. (A  B  C)c

In Exercises 33–36, let U  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A  {1, 3, 5, 7, 9}, B  {2, 4, 6, 8, 10}, and C  {1, 2, 4, 5, 8, 9}. List the elements of each set.

F  {x 苸 U 兩 x is a female}

Describe each set in words.

43. a. Dc

b. Nc

44. a. N  D

b. N  M

45. a. D  Mc

b. D  A

46. a. N  F

b. (D  N)c

In Exercises 47 and 48, let U denote the set of all senators in Congress and let D  {x 苸 U 兩 x is a Democrat}

R  {x 苸 U 兩 x is a Republican} F  {x 苸 U 兩 x is a female}

L  {x 苸 U 兩 x is a lawyer}

33. a. Ac

b. B  C

c. C  Cc

Write the set that represents each statement.

34. a. C  Cc

b. (A  C)c

c. A  (B  C )

47. a. The set of all Democrats who are female b. The set of all Republicans who are male and are not lawyers

35. a. (A  B)  C c. (A  B  C )c

b. (A  B  C)c

36. a. Ac  (B  Cc) c. (A  B)c  Cc

b. (A  Bc)  (B  Cc)

48. a. The set of all Democrats who are female or are lawyers b. The set of all senators who are not Democrats or are lawyers

404

7 SETS AND PROBABILITY

In Exercises 49 and 50, let U denote the set of all students in the business college of a certain university. Let

57. A  (B  C )  (A  B)  (A  C ) 58. (A  B)c  Ac  Bc

A  {x 苸 U 兩 x had taken a course in accounting}

B  {x 苸 U 兩 x had taken a course in economics} C  {x 苸 U 兩 x had taken a course in marketing}

In Exercises 59 and 60, let U  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Write the set that represents each statement.

A  {1, 3, 5, 7, 9}

49. a. The set of students who have not had a course in economics b. The set of students who have had courses in accounting and economics c. The set of students who have had courses in accounting and economics but not marketing

B  {1, 2, 4, 7, 8}

50. a. The set of students who have had courses in economics but not courses in accounting or marketing b. The set of students who have had at least one of the three courses c. The set of students who have had all three courses

C  {2, 4, 6, 8} Verify each equation by direct computation.

59. a. A  (B  C)  (A  B)  C b. A  (B  C)  (A  B)  C 60. a. A  (B  C )  (A  B)  (A  C ) b. (A  B)c  Ac  Bc In Exercises 61–64, refer to the accompanying figure and list the points that belong to each set.

In Exercises 51 and 52, refer to the following diagram, where U is the set of all tourists surveyed over a 1-week period in London and where

U t x

A  {x 苸 U 兩 x has taken the underground [subway]}

4

u C

U 3 1

s y

z

C  {x 苸 U 兩 x has taken a bus}

A

A

√ r

w

B  {x 苸 U 兩 x has taken a cab}

7

B

6 B 2

C 5

8

61. a. A  B

b. A  B

62. a. A  (B  C )

b. (B  C)c

63. a. (B  C)c

b. Ac

64. a. (A  B)  Cc

b. (A  B  C)c

65. Suppose A  B and B  C, where A and B are any two sets. What conclusion can be drawn regarding the sets A and C? Express the indicated regions in set notation and in words.

51. a. Region 1 b. Regions 1 and 4 together c. Regions 4, 5, 7, and 8 together 52. a. Region 3 b. Regions 4 and 6 together c. Regions 5, 6, and 7 together

66. Verify the assertion that two sets A and B are equal if and only if (1) A B and (2) B A. In Exercises 67–72, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

67. A set is never a subset of itself. 68. A proper subset of a set is itself a subset of the set but not necessarily vice versa.

In Exercises 53–58, use Venn diagrams to illustrate each statement.

69. If A  B  , then A   and B  .

53. A A  B; B A  B

70. If A  B  , then either A   or B  .

54. A  B A; A  B B

55. A  (B  C )  (A  B)  C

71. (A  Ac)c  

56. A  (B  C )  (A  B)  C

72. If A B, then A  B  A.

7.2 THE NUMBER OF ELEMENTS IN A FINITE SET

405

7.1 Solutions to Self-Check Exercises 1. a. Ac is the set of all elements in U but not in A. Therefore, Ac  {4, 5, 6, 7}

f. From part (a), we have Ac  {4, 5, 6, 7}. Next, we compute B  C  {3, 4, 5, 6}  {2, 3, 4}

b. A  B consists of all elements in A and/or B. Hence, A  B  {1, 2, 3, 4, 5, 6}

c. B  C is the set of all elements in both B and C. Therefore, B  C  {3, 4}

 {2, 3, 4, 5, 6}

from which we deduce that (B  C )c  {1, 7}

Finally, using these results, we obtain

d. Using the result from part (b), we find

Ac  (B  C)c  {4, 5, 6, 7}  {1, 7}  {7}

(A  B)  C  {1, 2, 3, 4, 5, 6}  {2, 3, 4}  {2, 3, 4}

e. First, we compute A  B  {3}

Next, since (A  B)  C is the set of all elements in (A  B) and/or C, we conclude that (A  B)  C  {3}  {2, 3, 4}  {2, 3, 4}

The set of elements in U but not in B  C

2. a. D  F denotes the set of all elements in both D and F. Since an element in D is a Democrat and an element in F is a female representative, we see that D  F is the set of all female Democrats in the House of Representatives. b. Since Fc is the set of male representatives and R is the set of Republicans, it follows that F c  R is the set of male Republicans in the House of Representatives. c. Lc is the set of representatives who are not lawyers by training. Therefore, D  F  Lc is the set of female Democratic representatives who are not lawyers by training.

7.2 The Number of Elements in a Finite Set Counting the Elements in a Set The solution to some problems in mathematics calls for finding the number of elements in a set. Such problems are called counting problems and constitute a field of study known as combinatorics. Our study of combinatorics is restricted to the results that will be required for our work in probability later on. The number of elements in a finite set is determined by simply counting the elements in the set. If A is a set, then n(A) denotes the number of elements in A. For example, if A  {1, 2, 3, . . . , 20}

B  {a, b}

C  {8}

then n(A)  20, n(B)  2, and n(C )  1. The empty set has no elements in it, so n()  0. Another result that is easily seen to be true is the following: If A and B are disjoint sets, then n(A  B)  n(A)  n(B)

(3)

EXAMPLE 1 If A  {a, c, d} and B  {b, e, f, t}, then n(A)  3 and n(B)  4, so n(A)  n(B)  7. Moreover, A  B  {a, b, c, d, e, f, t} and n(A  B)  7. Thus, Equation (3) holds true in this case. Note that A  B  . In the general case, A and B need not be disjoint, which leads us to the formula n1A  B2  n1A2  n1B2  n1A  B2

(4)

406

7 SETS AND PROBABILITY

B

A x

y

To see this, we observe that the set A  B may be viewed as the union of three mutually disjoint sets with x, y, and z elements, respectively (Figure 8). This figure shows that

z

n(A  B)  x  y  z

Also, FIGURE 8

n(A  B)  x  y  z

n(A)  x  y and

so

n(B)  y  z

n1A2  n1B2  1x  y2  1y  z 2

 1x  y  z2  y  n1A  B2  n1A  B2

n(A  B)  y

Solving for n(A  B), we obtain n(A  B)  n(A)  n(B)  n(A  B)

which is the desired result. EXAMPLE 2 Let A  {a, b, c, d, e} and B  {b, d, f, h}. Verify Equation (4) directly. Solution

A  B  {a, b, c, d, e, f, h} so n(A  B)  7 A  B  {b, d} so n(A  B)  2

Furthermore, n(A)  5 and

n(B)  4

so n(A)  n(B)  n(A  B)  5  4  2  7  n(A  B)

APPLIED EXAMPLE 3 Consumer Surveys In a survey of 100 coffee drinkers, it was found that 70 take sugar, 60 take cream, and 50 take both sugar and cream with their coffee. How many coffee drinkers take sugar or cream with their coffee? Solution

Let U denote the set of 100 coffee drinkers surveyed, and let A  {x  U 0 x takes sugar} B  {x  U 0 x takes cream}

Then, n(A)  70, n(B)  60, and n(A  B)  50. The set of coffee drinkers who take sugar or cream with their coffee is given by A  B. Using Equation (4), we find n(A  B)  n(A)  n(B)  n(A  B)  70  60  50  80

Thus, 80 out of the 100 coffee drinkers surveyed take cream or sugar with their coffee.

Explore & Discuss Prove Formula (5), using an argument similar to that used to prove Formula (4). Another proof is outlined in Exercise 41 on page 411.

An equation similar to (4) can be derived for the case that involves any finite number of finite sets. For example, a relationship involving the number of elements in the sets A, B, and C is given by n1A  B  C2  n1A2  n1B2  n1C2  n1A  B2  n1A  C2  n1B  C2  n1A  B  C2

(5)

7.2 THE NUMBER OF ELEMENTS IN A FINITE SET

407

As useful as equations such as (5) are, in practice it is often easier to attack a problem directly with the aid of Venn diagrams, as shown by the following example. APPLIED EXAMPLE 4 Marketing Surveys A leading cosmetics manufacturer advertises its products in three magazines: Allure, Cosmopolitan, and the Ladies Home Journal. A survey of 500 customers by the manufacturer reveals the following information: 180 learned of its products from Allure. 200 learned of its products from Cosmopolitan. 192 learned of its products from the Ladies Home Journal. 84 learned of its products from Allure and Cosmopolitan. 52 learned of its products from Allure and the Ladies Home Journal. 64 learned of its products from Cosmopolitan and the Ladies Home Journal. 38 learned of its products from all three magazines. How many of the customers saw the manufacturer’s advertisement in a. At least one magazine? b. Exactly one magazine? Solution

Let U denote the set of all customers surveyed, and let

A  {x  U 0 x learned of the products from Allure} C  {x  U 0 x learned of the products from Cosmopolitan} L  {x  U 0 x learned of the products from the Ladies Home Journal}

The result that 38 customers learned of the products from all three magazines translates into n(A  C  L)  38 (Figure 9a). Next, the result that 64 learned of the products from Cosmopolitan and the Ladies Home Journal translates into n(C  L)  64. This leaves 64  38  26

who learned of the products from only Cosmopolitan and the Ladies Home Journal (Figure 9b). Similarly, n(A  L)  52, so 52  38  14

learned of the products from only Allure and the Ladies Home Journal, and n(A  C)  84, so 84  38  46

learned of the products from only Allure and Cosmopolitan. These numbers appear in the appropriate regions in Figure 9b. U A

C 38

U A 14

46 38

C 26

L FIGURE 9

(a) All three magazines

L (b) Two or more magazines

Continuing, we have n(L)  192, so the number who learned of the products from the Ladies Home Journal only is given by 192  14  38  26  114

408

7 SETS AND PROBABILITY

U A

82 14

46 38

90

(Figure 10). Similarly, n(C )  200, so 200  46  38  26  90

C

learned of the products from only Cosmopolitan, and n(A)  180, so

26

180  14  38  46  82

114 L

90

learned of the products from only Allure. Finally, 500  (90  26  114  14  82  46  38)  90

FIGURE 10 The completed Venn diagram

learned of the products from other sources. We are now in a position to answer questions (a) and (b). a. Referring to Figure 10, we see that the number of customers who learned of the products from at least one magazine is given by n(A  C  L)  500  90  410

b. The number of customers who learned of the products from exactly one magazine (Figure 11) is given by n(L  Ac  C c )  n(C  Ac  Lc )  n(A  Lc  C c)  114  90  82  286 U A

82

90

C

114 FIGURE 11

L

Exactly one magazine

7.2 Self-Check Exercises 1. Let A and B be subsets of a universal set U and suppose that n(U)  100, n(A)  60, n(B)  40, and n(A  B)  20. Compute: a. n(A  B) b. n(A  Bc) c. n(Ac  B) 2. In a survey of 1000 readers of Video Magazine, it was found that 166 own at least one HD player in the HD-DVD format, 161 own at least one HD player in the Blu-ray

format, and 22 own HD players in both formats. How many of the readers surveyed own a HD player in the HDDVD format only? How many of the readers surveyed do not own a HD-player in either format? Solutions to Self-Check Exercises 7.2 can be found on page 411.

7.2 Concept Questions 1. a. If A and B are sets with A  B  , what can you say about n(A)  n(B)? Explain. b. If A and B are sets satisfying n(A  B)  n(A)  n(B), what can you say about A  B? Explain.

2. Let A and B be subsets of U, the universal set, and suppose A  B  . Is it true that n(A)  n(B)  n(Bc)  n(Ac)? Explain.

7.2 Exercises In Exercises 1 and 2, verify the equation n(A  B)  n(A)  n(B) for the given disjoint sets.

1. A  {a, e, i, o, u} and B  {t, h, k, l, m}

2. A  {x 0 x is a whole number between 0 and 4} B  {x 0 x is a negative integer greater than 4} 3. Let A  {2, 4, 6, 8} and B  {6, 7, 8, 9, 10}. Compute: a. n(A) b. n(B) c. n(A  B) d. n(A  B)

7.2 THE NUMBER OF ELEMENTS IN A FINITE SET

4. Let U  {1, 2, 3, 4, 5, 6, 7, a, b, c, d, e}. If A  {1, 2, a, e} and B  {1, 2, 3, 4, a, b, c}, find: a. n(Ac) b. n(A  Bc) c c. n(A  B ) d. n(Ac  Bc) 5. Verify directly that n(A  B)  n(A)  n(B)  n(A  B) for the sets in Exercise 3. 6. Let A  {a, e, i, o, u} and B  {b, d, e, o, u}. Verify by direct computation that n(A  B)  n(A)  n(B)  n(A  B). 7. If n(A)  15, n(A  B)  5, and n(A  B)  30, then what is n(B)? 8. If n(A)  10, n(A  B)  15, and n(B)  8, then what is n(A  B)? In Exercises 9 and 10, let A and B be subsets of a universal set U and suppose n(U)  200, n(A)  100, n(B)  80,  and n(A B)  40. Compute:

9. a. n(A  B)

b. n(Ac)

c. n(A  Bc)

409

20. CONSUMER SURVEYS In a survey of 200 members of a local sports club, 100 members indicated that they plan to attend the next Summer Olympic Games, 60 indicated that they plan to attend the next Winter Olympic Games, and 40 indicated that they plan to attend both games. How many members of the club plan to attend a. At least one of the two games? b. Exactly one of the games? c. The Summer Olympic Games only? d. None of the games? 21. INVESTING In a poll conducted among 200 active investors, it was found that 120 use discount brokers, 126 use fullservice brokers, and 64 use both discount and full-service brokers. How many investors a. Use at least one kind of broker? b. Use exactly one kind of broker? c. Use only discount brokers? d. Don’t use a broker?

13. If n(A)  4, n(B)  5, and n(A  B)  9, find n(A  B).

22. COMMUTER TRENDS Of 50 employees of a store located in downtown Boston, 18 people take the subway to work, 12 take the bus, and 7 take both the subway and the bus. How many employees a. Take the subway or the bus to work? b. Take only the bus to work? c. Take either the bus or the subway to work? d. Get to work by some other means?

14. If n(A)  16, n(B)  16, n(C)  14, n(A  B)  6, n(A  C)  5, n(B  C )  6, and n(A  B  C)  31, find n(A  B  C).

23. CONSUMER SURVEYS In a survey of 200 households regarding the ownership of desktop and laptop computers, the following information was obtained:

10. a. n(A  B) c

c

b. n(B )

c. n(A  B ) c

c

11. Find n(A  B) given that n(A)  6, n(B)  10, and n(A  B)  3. 12. If n(B)  6, n(A  B)  14, and n(A  B)  3, find n(A).

15. If n(A)  12, n(B)  12, n(A  B)  5, n(A  C )  5, n(B  C)  4, n(A  B  C )  2, and n(A  B  C)  25, find n(C ). 16. A survey of 1000 subscribers to the Los Angeles Times revealed that 900 people subscribe to the daily morning edition and 500 subscribe to both the daily morning and the Sunday editions. How many subscribe to the Sunday edition? How many subscribe to the Sunday edition only? 17. On a certain day, the Wilton County Jail held 190 prisoners accused of a crime (felony and/or misdemeanor). Of these, 130 were accused of felonies and 121 were accused of misdemeanors. How many prisoners were accused of both a felony and a misdemeanor? 18. Of 100 clock radios with digital tuners and/or CD players sold recently in a department store, 70 had digital tuners and 90 had CD players. How many radios had both digital tuners and CD players? 19. CONSUMER SURVEYS In a survey of 120 consumers conducted in a shopping mall, 80 consumers indicated that they buy brand A of a certain product, 68 buy brand B, and 42 buy both brands. How many consumers participating in the survey buy a. At least one of these brands? b. Exactly one of these brands? c. Only brand A? d. None of these brands?

120 households own only desktop computers. 10 households own only laptop computers. 40 households own neither desktop nor laptop computers. How many households own both desktop and laptop computers? 24. CONSUMER SURVEYS In a survey of 400 households regarding the ownership of VCRs and DVD players, the following data were obtained: 360 households own one or more VCRs. 170 households own one or more VCRs and one or more DVD players. 19 households do not own a VCR or a DVD player. How many households own only one or more DVD players? In Exercises 25–28, let A, B, and C be subsets of a universal set U and suppose n(U)  100, n(A)  28, n(B)  30,    n(C)  34, n(A B)  8, n(A C)  10, n(B C)  15,   and n(A B C)  5. Compute:

25. a. n(A  B  C )

b. n(Ac  B  C)

26. a. n[A  (B  C )]

b. n[A  (B  C )c]

27. a. n(Ac  Bc  Cc)

b. n[Ac  (B  C )]

28. a. n[A  (B  C )]

b. n[(Ac  Bc  C c )c]

410

7 SETS AND PROBABILITY

29. ECONOMIC SURVEYS A survey of the opinions of 10 leading economists in a certain country showed that, because oil prices were expected to drop in that country over the next 12 months, 7 had lowered their estimate of the consumer inflation rate. 8 had raised their estimate of the gross national product (GNP) growth rate. 2 had lowered their estimate of the consumer inflation rate but had not raised their estimate of the GNP growth rate. How many economists had both lowered their estimate of the consumer inflation rate and raised their estimate of the GNP growth rate for that period? 30. STUDENT DROPOUT RATE Data released by the Department of Education regarding the rate (percentage) of ninth-grade students who don’t graduate showed that, out of 50 states, 12 states had an increase in the dropout rate during the past 2 yr. 15 states had a dropout rate of at least 30% during the past 2 yr. 21 states had an increase in the dropout rate and/or a dropout rate of at least 30% during the past 2 yr. a. How many states had both a dropout rate of at least 30% and an increase in the dropout rate over the 2-yr period? b. How many states had a dropout rate that was less than 30% but that had increased over the 2-yr period? 31. STUDENT READING HABITS A survey of 100 college students who frequent the reading lounge of a university revealed the following results: 40 read Time. 30 read Newsweek. 25 read U.S. News & World Report. 15 read Time and Newsweek. 12 read Time and U.S. News & World Report. 10 read Newsweek and U.S. News & World Report. 4 read all three magazines. How many of the students surveyed read a. At least one of these magazines? b. Exactly one of these magazines? c. Exactly two of these magazines? d. None of these magazines? 32. SAT SCORES Results of a Department of Education survey of SAT test scores in 22 states showed that 10 states had an average composite SAT score of at least 1000 during the past 3 yr. 15 states had an increase of at least 10 points in the average composite SAT score during the past 3 yr. 8 states had both an average composite SAT score of at least 1000 and an increase in the average composite SAT score of at least 10 points during the past 3 yr.

a. How many of the 22 states had composite SAT scores of less than 1000 and showed an increase of at least 10 points over the 3-yr period? b. How many of the 22 states had composite SAT scores of at least 1000 and did not show an increase of at least 10 points over the 3-yr period? 33. CONSUMER SURVEYS The 120 consumers of Exercise 19 were also asked about their buying preferences concerning another product that is sold in the market under three labels. The results were 12 buy only those sold under label A. 25 buy only those sold under label B. 26 buy only those sold under label C. 15 buy only those sold under labels A and B. 10 buy only those sold under labels A and C. 12 buy only those sold under labels B and C. 8 buy the product sold under all three labels. How many of the consumers surveyed buy the product sold under a. At least one of the three labels? b. Labels A and B but not C? c. Label A? d. None of these labels? 34. STUDENT SURVEYS To help plan the number of meals (breakfast, lunch, and dinner) to be prepared in a college cafeteria, a survey was conducted and the following data were obtained: 130 students ate breakfast. 180 students ate lunch. 275 students ate dinner. 68 students ate breakfast and lunch. 112 students ate breakfast and dinner. 90 students ate lunch and dinner. 58 students ate all three meals. How many of the students ate a. At least one meal in the cafeteria? b. Exactly one meal in the cafeteria? c. Only dinner in the cafeteria? d. Exactly two meals in the cafeteria? 35. INVESTMENTS In a survey of 200 employees of a company regarding their 401(k) investments, the following data were obtained: 141 had investments in stock funds. 91 had investments in bond funds. 60 had investments in money market funds. 47 had investments in stock funds and bond funds. 36 had investments in stock funds and money market funds. 36 had investments in bond funds and money market funds. 5 had investments only in some other vehicle.

7.3 THE MULTIPLICATION PRINCIPLE

a. How many of the employees surveyed had investments in all three types of funds? b. How many of the employees had investments in stock funds only? 36. NEWSPAPER SUBSCRIPTIONS In a survey of 300 individual investors regarding subscriptions to the New York Times (NYT ), Wall Street Journal (WSJ), and USA Today (UST ), the following data were obtained: 122 subscribe to the NYT. 150 subscribe to the WSJ. 62 subscribe to the UST. 38 subscribe to the NYT and WSJ. 20 subscribe to the NYT and UST. 28 subscribe to the WSJ and UST. 36 do not subscribe to any of these newspapers.

411

In Exercises 37–40, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

37. If A  B  , then n(A  B)  n(A)  n(B). 38. If A B, then n(B)  n(A)  n(Ac  B). 39. If n(A  B)  n(A)  n(B), then A  B  . 40. If n(A  B)  0, then A  . 41. Derive Equation (5). Hint: Equation (4) can be written as n(D  E)  n(D)  n(E)  n(D  E). Now, put D  A  B and E  C. Use (4) again if necessary.

42. Find conditions on the sets A, B, and C so that n(A  B  C)  n(A)  n(B)  n(C).

a. How many of the individual investors surveyed subscribe to all three newspapers? b. How many subscribe to only one of these newspapers?

7.2 Solutions to Self-Check Exercises 1. Use the given information to construct the following Venn diagram: U A

Then, the fact that 22 of the readers own HD-players in both formats means that n(A  B)  22. Also, n(A)  166 and n(B)  161. Using this information, we obtain the following Venn diagram:

B U 40

20

20

A

B 144

22

139

20

Using this diagram we see that a. n(A  B)  40  20  20  80 b. n(A  Bc)  40 c. n(Ac  B)  20 2. Let U denote the set of all readers surveyed, and let A  {x  U 0 x owns at least one HD-player in the HD-DVD format} B  {x  U 0 x owns at least one HD-player in the Blu-ray format}

695

From the Venn diagram, we see that the number of readers who own a HD-player in the HD-DVD format only is given by n(A  B c)  144

The number of readers who do not own a HD-player in either format is given by n(Ac  B c)  695

7.3 The Multiplication Principle The Fundamental Principle of Counting The solution of certain problems requires more sophisticated counting techniques than those developed in the previous section. We look at some such techniques in this and the following section. We begin by stating a fundamental principle of counting called the multiplication principle.

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7 SETS AND PROBABILITY

The Multiplication Principle

Suppose there are m ways of performing a task T1 and n ways of performing a task T2. Then, there are mn ways of performing the task T1 followed by the task T2. EXAMPLE 1 Three trunk roads connect town A and town B, and two trunk roads connect town B and town C. a. Use the multiplication principle to find the number of ways a journey from town A to town C via town B can be completed. b. Verify part (a) directly by exhibiting all possible routes. Solution

a. Since there are three ways of performing the first task (going from town A to town B) followed by two ways of performing the second task (going from town B to town C), the multiplication principle says that there are 3  2, or 6, ways to complete a journey from town A to town C via town B. b. Label the trunk roads connecting town A and town B with the Roman numerals I, II, and III, and label the trunk roads connecting town B and town C with the lowercase letters a and b. A schematic of this is shown in Figure 12. Then the routes from town A to town C via town B can be exhibited with the aid of a tree diagram (Figure 13). I

A FIGURE 12

II

a B C b

III

Roads from town A to town C

If we follow all of the branches from the initial point A to the right-hand edge of the tree, we obtain the six routes represented by six ordered pairs: (I, a), (I, b), (II, a), (II, b), (III, a), (III, b)

where (I, a) means that the journey from town A to town B is made on trunk road I with the rest of the journey, from town B to town C, completed on trunk road a, and so forth.

B

C

Combined outcomes

a

(I, a)

b

(I, b)

a

(II, a)

b

(II, b)

a

(III, a)

b

(III, b)

I

A

FIGURE 13 Tree diagram displaying the possible routes from town A to town C

II

III

7.3 THE MULTIPLICATION PRINCIPLE

PORTFOLIO

413

Stephanie Molina

W

orking as a detective in the computer crimes division of the Maricopa County Sheriff’s Office, I find applied mathematics techniques play a significant role in my job when I search for evidence contained on computer hard drives and other forms of media. To obtain evidence, I am required to have a working knowledge of certain applied mathematics skills so that I can effectively communicate with the computer forensic analyst who will be decoding the evidence. To conduct an effective investigation, I am also required to understand these data in a wide variety of formats. With this information, I can work with the analyst to reconstruct data that may play a significant roll in determining events that occurred pertaining to a crime. During the course of an investigation, I have to look at the data not only in text but also in code. Using this view, the analyst can decipher different file types and possible evidence in unallocated space throughout the hard drive. This unallocated space can contain deleted files that may contain potential evidence. The analyst also has to decode files by hand, and at this point, recognizing patterns among

the files becomes very important. From here, we can derive an algorithm to define those patterns. By producing an algorithm, it makes it possible to write a program that will decode the files. For example, there was a case that involved a suspect who was receiving files through a mail server. This suspect was then opening the files and deleting the email. Members of my computer forensic laboratory and I viewed these files in their original code to try to discover any patterns or inconsistencies within the code to find a solution to the problem. We did find a clue buried within the code. We then derived an algorithm defining its pattern. By inputting the algorithm, we could then extract the files from the coded data. Although I do not have a solid background in computer science or even mathematics, my knowledge of applied mathematics helps me understand the procedures involved in obtaining evidence. Best of all, I am able to clearly convey my needs to the forensic analysts in my department.

© Beaconstox/Alamy

TITLE Computer Crimes Detective INSTITUTION Maricopa County Sheriff’s Office

Explore & Discuss One way of gauging the performance of an airline is to track the arrival times of its flights. Suppose we denote by E, O, and L a flight that arrives early, on time, or late, respectively. 1. Use a tree diagram to exhibit the possible outcomes when you track two successive flights of the airline. How many outcomes are there? 2. How many outcomes are there if you track three successive flights? Justify your answer.

APPLIED EXAMPLE 2 Menu Choices Diners at Angelo’s Spaghetti Bar can select their entree from 6 varieties of pasta and 28 choices of sauce. How many such combinations are there that consist of 1 variety of pasta and 1 kind of sauce? There are 6 ways of choosing a pasta followed by 28 ways of choosing a sauce, so by the multiplication principle, there are 6  28, or 168, combinations of this pasta dish. Solution

The multiplication principle can be easily extended, which leads to the generalized multiplication principle.

414

7 SETS AND PROBABILITY

Generalized Multiplication Principle

Suppose a task T1 can be performed in N1 ways, a task T2 can be performed in N2 ways, . . . , and, finally, a task Tm can be performed in Nm ways. Then, the number of ways of performing the tasks T1, T2, . . . , Tm in succession is given by the product N1N2    Nm

We now illustrate the application of the generalized multiplication principle to several diverse situations. EXAMPLE 3 A coin is tossed 3 times, and the sequence of heads and tails is recorded. a. Use the generalized multiplication principle to determine the number of possible outcomes of this activity. b. Exhibit all the sequences by means of a tree diagram. Solution

a. The coin may land in two ways. Therefore, in three tosses the number of outcomes (sequences) is given by 2  2  2, or 8. b. Let H and T denote the outcomes “a head” and “a tail,” respectively. Then the required sequences may be obtained as shown in Figure 14, giving the sequence as HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT.

First toss

Second toss

Third toss

Combined outcomes

H

(H, H, H)

T H

(H, H, T) (H, T, H)

H

H T

T

(H, T, T)

H

(T, H, H)

T H

(T, H, T) (T, T, H)

T

(T, T, T)

H FIGURE 14 Tree diagram displaying possible outcomes of three consecutive coin tosses

T T

APPLIED EXAMPLE 4 Combination Locks A combination lock is unlocked by dialing a sequence of numbers: first to the left, then to the right, and to the left again. If there are ten digits on the dial, determine the number of possible combinations. Solution There are ten choices for the first number, followed by ten for the second and ten for the third, so by the generalized multiplication principle there are 10  10  10, or 1000, possible combinations.

APPLIED EXAMPLE 5 Investment Options An investor has decided to purchase shares in the stock of three companies: one engaged in aerospace activities, one involved in energy development, and one involved in electronics. After some research, the account executive of a brokerage firm has recommended that the investor consider stock from five aerospace companies, three

7.3 THE MULTIPLICATION PRINCIPLE

415

energy development companies, and four electronics companies. In how many ways can the investor select the group of three companies from the executive’s list? Solution The investor has five choices for selecting an aerospace company, three choices for selecting an energy development company, and four choices for selecting an electronics company. Therefore, by the generalized multiplication principle, there are 5  3  4, or 60, ways in which she can select a group of three companies, one from each industry group.

APPLIED EXAMPLE 6 Travel Options Tom is planning to leave for New York City from Washington, D.C., on Monday morning and has decided that he will either fly or take the train. There are five flights and two trains departing for New York City from Washington that morning. When he returns on Sunday afternoon, Tom plans to either fly or hitch a ride with a friend. There are two flights departing from New York City to Washington that afternoon. In how many ways can Tom complete this round trip? Solution There are seven ways Tom can go from Washington, D.C., to New York City (five by plane and two by train). On the return trip, Tom can travel in three ways (two by plane and one by car). Therefore, by the multiplication principle, Tom can complete the round trip in 7  3, or 21, ways.

7.3 Self-Check Exercises 1. Encore Travel offers a “Theater Week in London” package originating from New York City. There is a choice of eight flights departing from New York City each week, a choice of five hotel accommodations, and a choice of one complimentary ticket to one of eight shows. How many such travel packages can one choose from? 2. The Café Napolean offers a dinner special on Wednesdays consisting of a choice of two entrées (beef bourguignon

and chicken basquaise); one dinner salad; one French roll; a choice of three vegetables; a choice of a carafe of burgundy, rosé, or chablis wine; a choice of coffee or tea; and a choice of six french pastries for dessert. How many combinations of dinner specials are there? Solutions to Self-Check Exercises 7.3 can be found on page 417.

7.3 Concept Questions 1. Explain the multiplication principle and illustrate it with a diagram.

I A

2. Given the following tree diagram for an activity, what are the possible outcomes?

II I B II

7.3 Exercises 1. RENTAL RATES Lynbrook West, an apartment complex financed by the State Housing Finance Agency, consists of one-, two-, three-, and four-bedroom units. The rental rate

for each type of unit—low, moderate, or market—is determined by the income of the tenant. How many different rates are there?

416

7 SETS AND PROBABILITY

2. COMMUTER PASSES Five different types of monthly commuter passes are offered by a city’s local transit authority for each of three different groups of passengers: youths, adults, and senior citizens. How many different kinds of passes must be printed each month? 3. BLACKJACK In the game of blackjack, a 2-card hand consisting of an ace and either a face card or a 10 is called a “blackjack.” If a standard 52-card deck is used, determine how many blackjack hands can be dealt. (A “face card” is a jack, queen, or king.) 4. COIN TOSSES A coin is tossed 4 times and the sequence of heads and tails is recorded. a. Use the generalized multiplication principle to determine the number of outcomes of this activity. b. Exhibit all the sequences by means of a tree diagram.

plans, and two vision care plans. How many different health-care plans are there to choose from if one plan is selected from each category? 10. CODE WORDS How many three-letter code words can be constructed from the first ten letters of the Greek alphabet if no repetitions are allowed? 11. SOCIAL SECURITY NUMBERS A Social Security number has nine digits. How many Social Security numbers are possible? 12. SERIAL NUMBERS Computers manufactured by a certain company have a serial number consisting of a letter of the alphabet followed by a four-digit number. If all the serial numbers of this type have been used, how many sets have already been manufactured?

5. WARDROBE SELECTION A female executive selecting her wardrobe purchased two blazers, four blouses, and three skirts in coordinating colors. How many ensembles consisting of a blazer, a blouse, and a skirt can she create from this collection?

13. COMPUTER DATING A computer dating service uses the results of its compatibility survey for arranging dates. The survey consists of 50 questions, each having five possible answers. How many different responses are possible if every question is answered?

6. COMMUTER OPTIONS Four commuter trains and three express buses depart from city A to city B in the morning, and three commuter trains and three express buses operate on the return trip in the evening. In how many ways can a commuter from city A to city B complete a daily round trip via bus and/or train?

14. AUTOMOBILE COLORS The 2007 BMW 335i Coupe is offered with a choice of 14 exterior colors (11 metallic and 3 standard), 5 interior colors, and 4 trims. How many combinations involving color and trim are available for the model?

7. PSYCHOLOGY EXPERIMENTS A psychologist has constructed the following maze for use in an experiment. The maze is constructed so that a rat must pass through a series of oneway doors. How many different paths are there from start to finish?

15. AUTOMOBILE COLORS The 2007 Toyota Camry comes with 5 grades of models, 2 sizes of engines, 4 choices of transmissions, 5 exterior colors, and 2 interior colors. How many choices of the Camry are available for a prospective buyer?

Source: BMW

Source: Toyota

16. TELEVISION-VIEWING POLLS An opinion poll is to be conducted among cable TV viewers. Six multiple-choice questions, each with four possible answers, will be asked. In how many different ways can a viewer complete the poll if exactly one response is given to each question?

Start Finish

Maze

8. UNION BARGAINING ISSUES In a survey conducted by a union, members were asked to rate the importance of the following issues: (1) job security, (2) increased fringe benefits, and (3) improved working conditions. Five different responses were allowed for each issue. Among completed surveys, how many different responses to this survey were possible? 9. HEALTH-CARE PLAN OPTIONS A new state employee is offered a choice of ten basic health plans, three dental

17. ATM CARDS To gain access to his account, a customer using an automatic teller machine (ATM) must enter a four-digit code. If repetition of the same four digits is not allowed (for example, 5555), how many possible combinations are there? 18. POLITICAL POLLS An opinion poll was conducted by the Morris Polling Group. Respondents were classified according to their sex (M or F), political affiliation (D, I, R), and the region of the country in which they reside (NW, W, C, S, E, NE). a. Use the generalized multiplication principle to determine the number of possible classifications. b. Construct a tree diagram to exhibit all possible classifications of females. 19. LICENSE PLATE NUMBERS Over the years, the state of California has used different combinations of letters of the alphabet and digits on its automobile license plates.

7.4 PERMUTATIONS AND COMBINATIONS

a. At one time, license plates were issued that consisted of three letters followed by three digits. How many different license plates can be issued under this arrangement? b. Later on, license plates were issued that consisted of three digits followed by three letters. How many different license plates can be issued under this arrangement? 20. LICENSE PLATE NUMBERS In recent years, the state of California issued license plates using a combination of one letter of the alphabet followed by three digits, followed by another three letters of the alphabet. How many different license plates can be issued using this configuration? 21. EXAMS An exam consists of ten true-or-false questions. Assuming that every question is answered, in how many different ways can a student complete the exam? In how many ways can the exam be completed if a student can leave some questions unanswered because, say, a penalty is assessed for each incorrect answer? 22. WARRANTY NUMBERS A warranty identification number for a certain product consists of a letter of the alphabet followed by a five-digit number. How many possible identification numbers are there if the first digit of the five-digit number must be nonzero? 23. LOTTERIES In a state lottery, there are 15 finalists eligible for the Big Money Draw. In how many ways can the first, second, and third prizes be awarded if no ticket holder can win more than one prize? 24. TELEPHONE NUMBERS a. How many seven-digit telephone numbers are possible if the first digit must be nonzero? b. How many direct-dialing numbers for calls within the United States and Canada are possible if each number

417

consists of a 1 plus a three-digit area code (the first digit of which must be nonzero) and a number of the type described in part (a)? 25. SLOT MACHINES A “lucky dollar” is one of the nine symbols printed on each reel of a slot machine with three reels. A player receives one of various payouts whenever one or more “lucky dollars” appear in the window of the machine. Find the number of winning combinations for which the machine gives a payoff. Hint: (a) Compute the number of ways in which the nine symbols on the first, second, and third wheels can appear in the window slot and (b) compute the number of ways in which the eight symbols other than the “lucky dollar” can appear in the window slot. The difference (a  b) is the number of ways in which the “lucky dollar” can appear in the window slot. Why?

26. STAFFING Student Painters, which specializes in painting the exterior of residential buildings, has five people available to be organized into two-person and three-person teams. a. In how many ways can a two-person team be formed? b. In how many ways can a three-person team be formed? c. In how many ways can the company organize the available people into either two-person teams or threeperson teams? In Exercises 27 and 28, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

27. There are 32 three-digit odd numbers that can be formed from the digits 1, 2, 3, and 4. 28. If there are six toppings available, then the number of different pizzas that can be made is 25, or 32, pizzas.

7.3 Solutions to Self-Check Exercises 1. A tourist has a choice of eight flights, five hotel accommodations, and eight tickets. By the generalized multiplication principle, there are 8  5  8, or 320, travel packages.

beverages, and six pastries. Therefore, by the generalized multiplication principle, there are 2  1  1  3  3  2  6, or 216, combinations of dinner specials.

2. There is a choice of two entrées, one dinner salad, one French roll, three vegetables, three wines, two nonalcoholic

7.4 Permutations and Combinations Permutations In this section, we apply the generalized multiplication principle to the solution of two types of counting problems. Both types involve determining the number of ways the elements of a set can be arranged, and both play an important role in the solution of problems in probability. We begin by considering the permutations of a set. Specifically, given a set of distinct objects, a permutation of the set is an arrangement of these objects in a definite

418

7 SETS AND PROBABILITY

order. To see why the order in which objects are arranged is important in certain practical situations, suppose the winning number for the first prize in a raffle is 9237. Then the number 2973, although it contains the same digits as the winning number, cannot be the first-prize winner (Figure 15). Here, the four objects—the digits 9, 2, 3, and 7— are arranged in a different order; one arrangement is associated with the winning number for the first prize, and the other is not.

Non

et tick

win

ning

2973

The same digits appear on each ticket, but the order of the digits is different.

OM NI RAF CLUB FLE

7

ning Win

FIGURE 15

923

LUB NI C OM FFLE RA

tick et

EXAMPLE 1 Let A  {a, b, c}. a. Find the number of permutations of A. b. List all the permutations of A with the aid of a tree diagram. Solution

a. Each permutation of A consists of a sequence of the three letters a, b, c. Therefore, we may think of such a sequence as being constructed by filling in each of the three blanks __

__

__

with one of the three letters. Now, there are three ways in which we can fill the first blank—we can choose a, b, or c. Having selected a letter for the first blank, there are two letters left for the second blank. Finally, there is but one way left to fill the third blank. Schematically, we have 3

2

1

Invoking the generalized multiplication principle, we conclude that there are 3  2  1, or 6, permutations of the set A. b. The tree diagram associated with this problem appears in Figure 16, and the six permutations of A are abc, acb, bac, bca, cab, and cba. Combined outcomes b

c (a, b, c)

c a

b (a, c, b) c (b, a, c)

c a

a (b, c, a) b (c, a, b)

b

a (c, b, a)

a

b

FIGURE 16

c

Permutations of three objects

Notice that, when the possible outcomes are listed in the tree diagram in Example 1, order is taken into account. Thus, (a, b, c) and (a, c, b) are two different arrangements. Note

7.4 PERMUTATIONS AND COMBINATIONS

419

EXAMPLE 2 Find the number of ways a baseball team consisting of nine people can arrange themselves in a line for a group picture. Solution We want to determine the number of permutations of the nine members of the baseball team. Each permutation in this situation consists of an arrangement of the nine team members in a line. The nine positions can be represented by nine blanks. Thus, Position

1

2

3

4

5

6

7

8

9

There are nine ways to choose from among the nine players to fill the first position. When that position is filled, eight players are left, which gives us eight ways to fill the second position. Proceeding in a similar manner, we find that there are seven ways to fill the third position, and so on. Schematically, we have Number of ways to fill each position

9

8

7

6

5

4

3

2

1

Invoking the generalized multiplication principle, we conclude that there are 9 # 8 # 7 # 6 # 5 # 4 # 3 # 2 # 1, or 362,880, ways the baseball team can be arranged for the picture. Whenever we are asked to determine the number of ways the objects of a set can be arranged in a line, order is important. For example, if we take a picture of two baseball players, A and B, then the two players can line up for the picture in two ways, AB or BA, and the two pictures will be different. Pursuing the same line of argument used in solving the problems in the last two examples, we can derive an expression for the number of ways of permuting a set A of n distinct objects taken n at a time. In fact, each permutation may be viewed as being obtained by filling each of n blanks with one and only one element from the set. There are n ways of filling the first blank, followed by (n  1) ways of filling the second blank, and so on. Thus, by the generalized multiplication principle, there are n(n  1)(n  2) # p # 3 # 2 # 1 ways of permuting the elements of the set A. Before stating this result formally, let’s introduce a notation that will enable us to write in a compact form many of the expressions that follow. We use the symbol n! (read “n-factorial”) to denote the product of the first n positive integers. n-Factorial

For any natural number n,

n!  n1n  12 1n  22 # p # 3 # 2 # 1 0!  1

For example, 1!  1 2!  2 # 1  2 3!  3 # 2 # 1  6 4!  4 # 3 # 2 # 1  24 5!  5 # 4 # 3 # 2 # 1  120 o 10!  10 # 9 # 8 # 7 # 6 # 5 # 4 # 3 # 2 # 1  3,628,800

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7 SETS AND PROBABILITY

Using this notation, we can express the number of permutations of n distinct objects taken n at a time, denoted by P(n, n), as P(n, n)  n!

In many situations, we are interested in determining the number of ways of permuting n distinct objects taken r at a time, where r n. To derive a formula for computing the number of ways of permuting a set consisting of n distinct objects taken r at a time, we observe that each such permutation may be viewed as being obtained by filling each of r blanks with precisely one element from the set. Now there are n ways of filling the first blank, followed by (n  1) ways of filling the second blank, and so on. Finally, there are (n  r  1) ways of filling the rth blank. We can represent this argument schematically: Number of ways

n

n1

Position

1st

2nd

n2pnr1 3rd

rth

Using the generalized multiplication principle, we conclude that the number of ways of permuting n distinct objects taken r at a time, denoted by P(n, r), is given by P1n, r2  n1n  12 1n  22 p 1n  r  12

  r factors

Since n1n  12 1n  22 p 1n  r  1 2  3n1n  1 2 1n  22 p 1n  r  12 4

# # 1n  r2 1n  r  12 # 1n  r2 1n  r  12

p #3#2#1 p #3#2#1



Here we are multiplying by 1.



3n1n  12 1n  22 p 1n  r  12 4 3 1n  r2 1n  r  12 1n  r2 1n  r  12 # p # 3 # 2 # 1



n! 1n  r2 !

#

p # 3 # 2 # 14

we have the following formula. Permutations of n Distinct Objects

The number of permutations of n distinct objects taken r at a time is P1n, r2  Note

n! 1n  r2!

(6)

When r  n, Equation (6) reduces to P1n, n 2 

n! n!   n! 0! 1

Note that 0!  1.

In other words, the number of permutations of a set of n distinct objects, taken all together, is n!. EXAMPLE 3 Compute (a) P(4, 4) and (b) P(4, 2), and interpret your results. Solution

a. P14, 42 

4! 4! 4! 4#3#2#1     24 14  42! 0! 1 1

Note that 0!  1.

421

7.4 PERMUTATIONS AND COMBINATIONS

This gives the number of permutations of four objects taken four at a time. b. P14, 2 2  Combined outcomes b a

c d

(a, b) (a, c) (a, d)

a c d

(b, a) (b, c) (c, a)

c

a b d

d

a b c

b

(b, d) (c, b) (c, d) (d, a) (d, b) (d, c)

FIGURE 17 Permutations of four objects taken two at a time

4! 4! 4#3#2#1    4 # 3  12 14  22! 2! 2#1

This is the number of permutations of four objects taken two at a time. EXAMPLE 4 Let A  {a, b, c, d}. a. Use Equation (6) to compute the number of permutations of the set A taken two at a time. b. Display the permutations of part (a) with the aid of a tree diagram. Solution

a. Here, n  4 and r  2, so the required number of permutations is given by 4! 4! 4#3#2#1   4#3 14  22! 2! 2#1  12

P14, 22 

b. The tree diagram associated with the problem is shown in Figure 17, and the permutations of A taken two at a time are ab, ac, ad, ba, bc, bd, ca, cb, cd, da, db, dc

EXAMPLE 5 Find the number of ways a chairman, a vice-chairman, a secretary, and a treasurer can be chosen from a committee of eight members. Solution The problem is equivalent to finding the number of permutations of eight distinct objects taken four at a time. Therefore, there are

P18, 42 

8! 8!   8 # 7 # 6 # 5  1680 18  42! 4!

ways of choosing the four officials from the committee of eight members. The permutations considered thus far have been those involving sets of distinct objects. In many situations we are interested in finding the number of permutations of a set of objects in which not all of the objects are distinct.

Permutations of n Objects, Not All Distinct

Given a set of n objects in which n1 objects are alike and of one kind, n2 objects are alike and of another kind, . . . , and nm objects are alike and of yet another kind, so that n1  n2  p  nm  n then the number of permutations of these n objects taken n at a time is given by n! n1! n2! p nm!

(7)

To establish Equation (7), let’s denote the number of such permutations by x. Now, if we think of the n1 objects as being distinct, then they can be permuted in n1! ways. Similarly, if we think of the n2 objects as being distinct, then they can be permuted in n2! ways, and so on. Therefore, if we think of the n objects as being distinct, then, by the generalized multiplication principle, there are x  n1!  n2!  p  nm! per-

422

7 SETS AND PROBABILITY

mutations of these objects. But, the number of permutations of a set of n distinct objects taken n at a time is just equal to n!. Therefore, we have x(n1!  n2!  p  nm!)  n! from which we deduce that x

n! n1! n2! p nm!

EXAMPLE 6 Find the number of permutations that can be formed from all the letters in the word ATLANTA. There are seven objects (letters) involved, so n  7. However, three of them are alike and of one kind (the three As), while two of them are alike and of another kind (the two Ts); hence, in this case we have n1  3, n2  2, n3  1 (the one L), and n4  1 (the one N). Therefore, using Formula (7), there are

Solution

7! 7#6#5#4#3#2#1  # # # # # #  420 3! 2! 1! 1! 3 2 1 2 1 1 1

permutations. APPLIED EXAMPLE 7 Management Decisions Weaver and Kline, a stock brokerage firm, has received nine inquiries regarding new accounts. In how many ways can these inquiries be directed to any three of the firm’s account executives if each account executive is to handle three inquiries? Solution If we think of the nine inquiries as being slots arranged in a row with inquiry 1 on the left and inquiry 9 on the right, then the problem can be thought of as one of filling each slot with a business card from an account executive. Then nine business cards would be used, of which three are alike and of one kind, three are alike and of another kind, and three are alike and of yet another kind. Thus, using Equation (7) with n  9 and n1  n2  n3  3, there are

9! 9#8#7#6#5#4#3#2#1  # # # # # # # #  1680 3! 3! 3! 3 2 1 3 2 1 3 2 1

ways of assigning the inquiries.

Combinations Until now we have dealt with permutations of a set—that is, with arrangements of the objects of the set in which the order of the elements is taken into consideration. In many situations one is interested in determining the number of ways of selecting r objects from a set of n objects without any regard to the order in which the objects are selected. Such a subset is called a combination. For example, if one is interested in knowing the number of 5-card poker hands that can be dealt from a standard deck of 52 cards, then the order in which the poker hand is dealt is unimportant (Figure 18). In this situation, we are interested in determining the number of combinations of 5 cards (objects) selected from a deck (set) of 52 cards (objects). (We will solve this problem in Example 10.)

A A A K K

K K A A A is considered the same hand as

A

A

K

FIGURE 18

423

7.4 PERMUTATIONS AND COMBINATIONS

To derive a formula for determining the number of combinations of n objects taken r at a time, written C1n, r2

or

n a b r

we observe that each of the C(n, r) combinations of r objects can be permuted in r! ways (Figure 19). r! permutations r objects FIGURE 19

r objects

...

r objects

C(n, r) boxes

Thus, by the multiplication principle, the product r! C(n, r) gives the number of permutations of n objects taken r at a time; that is, r! C(n, r)  P(n, r)

from which we find C1n, r2 

P1n, r2 r!

or, using Equation (6), C1n, r2 

n! r! 1n  r2!

Combinations of n Objects

The number of combinations of n distinct objects taken r at a time is given by C1n, r 2 

n! r! 1n  r2!

(where r n)

(8)

EXAMPLE 8 Compute and interpret the results of (a) C(4, 4) and (b) C(4, 2). Solution

a. C14, 42 

4! 4!  1 4! 14  42! 4! 0!

Recall that 0!  1.

This gives 1 as the number of combinations of four distinct objects taken four at a time. b. C14, 22 

4! 4! 4#3#2#1   6 2! 14  22! 2! 2! 2#2

This gives 6 as the number of combinations of four distinct objects taken two at a time. APPLIED EXAMPLE 9 Committee Selection A Senate investigation subcommittee of four members is to be selected from a Senate committee of ten members. Determine the number of ways this can be done. Solution The order in which the members of the subcommittee are selected is unimportant, and so the number of ways of choosing the subcommittee is given

424

7 SETS AND PROBABILITY

by C(10, 4), the number of combinations of ten objects taken four at a time. Hence, there are C110, 42 

10! 10! 10 # 9 # 8 # 7   # # #  210 4! 110  42! 4! 6! 4 3 2 1

ways of choosing such a subcommittee. Note Remember, a combination is a selection of objects without regard to order. Thus, in Example 9, we used a combination formula rather than a permutation formula to solve the problem because the order of selection was not important; that is, it did not matter whether a member of the subcommittee was selected first, second, third, or fourth.

APPLIED EXAMPLE 10 Poker How many poker hands of 5 cards can be dealt from a standard deck of 52 cards? Solution The order in which the 5 cards are dealt is not important. The number of ways of dealing a poker hand of 5 cards from a standard deck of 52 cards is given by C(52, 5), the number of combinations of 52 objects taken five at a time. Thus, there are

52! 52!  5! 152  52! 5! 47! 52 # 51 # 50 # 49 # 48  5#4#3#2#1  2,598,960

C152, 52 

ways of dealing such a poker hand. The next several examples show that solving a counting problem often involves the repeated application of Equation (6) and/or (8), possibly in conjunction with the multiplication principle. APPLIED EXAMPLE 11 Selecting Members of a Group The members of a string quartet consisting of two violinists, a violist, and a cellist are to be selected from a group of six violinists, three violists, and two cellists. a. In how many ways can the string quartet be formed? b. In how many ways can the string quartet be formed if one of the violinists is to be designated as the first violinist and the other is to be designated as the second violinist? Solution

a. Since the order in which each musician is selected is not important, we use combinations. The violinists can be selected in C(6, 2), or 15, ways; the violist can be selected in C(3, 1), or 3, ways; and the cellist can be selected in C(2, 1), or 2, ways. By the multiplication principle, there are 15  3  2, or 90, ways of forming the string quartet. b. The order in which the violinists are selected is important here. Consequently, the number of ways of selecting the violinists is given by P(6, 2), or 30, ways. The number of ways of selecting the violist and the cellist remain, of course, 3 and 2, respectively. Therefore, the number of ways in which the string quartet can be formed is given by 30  3  2, or 180, ways.

7.4 PERMUTATIONS AND COMBINATIONS

425

Note The solution of Example 11 involves both a permutation and a combination. When we select two violinists from six violinists, order is not important, and we use a combination formula to solve the problem. However, when one of the violinists is designated as a first violinist, order is important, and we use a permutation formula to solve the problem.

APPLIED EXAMPLE 12 Investment Options Refer to Example 5, page 414. Suppose the investor has decided to purchase shares in the stocks of two aerospace companies, two energy development companies, and two electronics companies. In how many ways can the investor select the group of six companies for the investment from the recommended list of five aerospace companies, three energy development companies, and four electronics companies? Solution There are C(5, 2) ways in which the investor can select the aerospace companies, C(3, 2) ways in which she can select the companies involved in energy development, and C(4, 2) ways in which she can select the electronics companies as investments. By the generalized multiplication principle, there are

5! # 3! # 4! 2! 3! 2! 1! 2! 2! 5#4# #4#3  3  180 2 2

C15, 22C13, 22C14, 22 

ways of selecting the group of six companies for her investment. APPLIED EXAMPLE 13 Scheduling Performances The Futurists, a rock group, are planning a concert tour with performances to be given in five cities: San Francisco, Los Angeles, San Diego, Denver, and Las Vegas. In how many ways can they arrange their itinerary if a. There are no restrictions? b. The three performances in California must be given consecutively? Solution

a. The order is important here, and we see that there are P(5, 5)  5!  120

ways of arranging their itinerary. b. First, note that there are P(3, 3) ways of choosing between performing in California and in the two cities outside that state. Next, there are P(3, 3) ways of arranging their itinerary in the three cities in California. Therefore, by the multiplication principle, there are P13, 3 2P13, 32 

3! # 3!  6 # 6  36 13  32! 13  32!

ways of arranging their itinerary. APPLIED EXAMPLE 14 U.N. Security Council Voting The United Nations Security Council consists of 5 permanent members and 10 nonpermanent members. Decisions made by the council require 9 votes for passage. However, any permanent member may veto a measure and thus block its passage. Assuming there are no abstentions, in how many ways can a measure be passed if all 15 members of the Council vote?

426

7 SETS AND PROBABILITY

Solution If a measure is to be passed, then all 5 permanent members must vote for passage of that measure. This can be done in C(5, 5), or 1, way. Next, observe that since 9 votes are required for passage of a measure, at least 4 of the 10 nonpermanent members must also vote for its passage. To determine the number of ways this can be done, notice that there are C(10, 4) ways in which exactly 4 of the nonpermanent members can vote for passage of a measure, C(10, 5) ways in which exactly 5 of them can vote for passage of a measure, and so on. Finally, there are C(10, 10) ways in which all 10 nonpermanent members can vote for passage of a measure. Hence, there are C(10, 4)  C(10, 5)  p  C(10, 10)

ways in which at least 4 of the 10 nonpermanent members can vote for a measure. So, by the multiplication principle, there are C15, 52 3 C110, 42  C110, 52  p  C110, 102 4  112 c

10! 10! 10!   p d 4! 6! 5! 5! 10! 0!  112 1210  252  210  120  45  10  12  848

ways a measure can be passed.

7.4 Self-Check Exercises 1. Evaluate: a. 5!

b. C(7, 4)

c. P(6, 2)

2. A space shuttle crew consists of a shuttle commander, a pilot, three engineers, a scientist, and a civilian. The shuttle commander and pilot are to be chosen from 8 candi-

dates, the three engineers from 12 candidates, the scientist from 5 candidates, and the civilian from 2 candidates. How many such space shuttle crews can be formed? Solutions to Self-Check Exercises 7.4 can be found on page 430.

7.4 Concept Questions 1. a. What is a permutation of a set of distinct objects? b. How many permutations of a set of five distinct objects taken three at a time are there? 2. Given a set of ten objects in which three are alike and of one kind, three are alike and of another kind, and four are alike and of yet another kind, what is the formula for com-

puting the permutation of these ten objects taken ten at a time? 3. a. What is a combination of a set of n distinct objects taken r at a time? b. How many combinations are there of six distinct objects taken three at a time?

7.4 Exercises In Exercises 1–22, evaluate the given expression.

16. C(6, 5)

17. C(9, 6)

18. C(10, 3)

5! 2! 3!

19. C(n, 2)

20. C(7, r)

21. P(n, n  2)

1. 3  5!

2. 2  7!

3.

6! 4! 2!

5. P(5, 5)

6. P(6, 6)

7. P(5, 2)

8. P(5, 3)

9. P(n, 1)

10. P(k, 2)

11. C(6, 6)

12. C(8, 8)

13. C(7, 4)

14. C(9, 3)

15. C(5, 0)

4.

22. C(n, n  2) In Exercises 23–30, classify each problem according to whether it involves a permutation or a combination.

23. In how many ways can the letters of the word GLACIER be arranged?

7.4 PERMUTATIONS AND COMBINATIONS

24. A four-member executive committee is to be formed from a twelve-member board of directors. In how many ways can it be formed? 25. As part of a quality-control program, 3 cell phones are selected at random for testing from 100 cell phones produced by the manufacturer. In how many ways can this test batch be chosen? 26. How many three-digit numbers can be formed using the numerals in the set {3, 2, 7, 9} if repetition is not allowed? 27. In how many ways can nine different books be arranged on a shelf? 28. A member of a book club wishes to purchase two books from a selection of eight books recommended for a certain month. In how many ways can she choose them? 29. How many five-card poker hands can be dealt consisting of three queens and a pair? 30. In how many ways can a six-letter security password be formed from letters of the alphabet if no letter is repeated? 31. How many four-letter permutations can be formed from the first four letters of the alphabet? 32. How many three-letter permutations can be formed from the first five letters of the alphabet? 33. In how many ways can four students be seated in a row of four seats? 34. In how many ways can five people line up at a checkout counter in a supermarket? 35. How many different batting orders can be formed for a nine-member baseball team? 36. In how many ways can the names of six candidates for political office be listed on a ballot? 37. In how many ways can a member of a hiring committee select 3 of 12 job applicants for further consideration? 38. In how many ways can an investor select four mutual funds for his investment portfolio from a recommended list of eight mutual funds? 39. Find the number of distinguishable permutations that can be formed from the letters of the word ANTARCTICA. 40. Find the number of distinguishable permutations that can be formed from the letters of the word PHILIPPINES. 41. In how many ways can the letters of the Web site MySpace be arranged if all of the letters are used and the vowels a and e must always stay in the order ae? 42. In how many ways can five people boarding a bus be seated if the bus has eight vacant seats?

427

43. How many distinct five-digit numbers can be made using the digits 1, 2, 2, 2, 7? 44. How many different signals can be made by hoisting two yellow flags, four green flags, and three red flags on a ship’s mast at the same time? 45. MANAGEMENT DECISIONS In how many ways can a supermarket chain select 3 out of 12 possible sites for the construction of new supermarkets? 46. BOOK SELECTIONS A student is given a reading list of ten books from which he must select two for an outside reading requirement. In how many ways can he make his selections? 47. QUALITY CONTROL In how many ways can a quality-control engineer select a sample of 3 microprocessors for testing from a batch of 100 microprocessors? 48. STUDY GROUPS A group of five students studying for a bar exam has formed a study group. Each member of the group will be responsible for preparing a study outline for one of five courses. In how many different ways can the five courses be assigned to the members of the group? 49. TELEVISION PROGRAMMING In how many ways can a television-programming director schedule six different commercials in the six time slots allocated to commercials during a 1-hr program? 50. WAITING LINES Seven people arrive at the ticket counter of a cinema at the same time. In how many ways can they line up to purchase their tickets? 51. MANAGEMENT DECISIONS Weaver and Kline, a stock brokerage firm, has received six inquiries regarding new accounts. In how many ways can these inquiries be directed to its 12 account executives if each executive handles no more than one inquiry? 52. CAR POOLS A company car that has a seating capacity of six is to be used by six employees who have formed a car pool. If only four of these employees can drive, how many possible seating arrangements are there for the group? 53. BOOK DISPLAYS At a college library exhibition of faculty publications, three mathematics books, four social science books, and three biology books will be displayed on a shelf. (Assume that none of the books is alike.) a. In how many ways can the ten books be arranged on the shelf? b. In how many ways can the ten books be arranged on the shelf if books on the same subject matter are placed together? 54. SEATING In how many ways can four married couples attending a concert be seated in a row of eight seats if a. There are no restrictions? b. Each married couple is seated together? c. The members of each sex are seated together?

428

7 SETS AND PROBABILITY

55. NEWSPAPER ADVERTISEMENTS Four items from five different departments of Metro Department Store will be featured in a one-page newspaper advertisement, as shown in the following diagram: Advertisement 1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

a. In how many different ways can the 20 featured items be arranged on the page? b. If items from the same department must be in the same row, how many arrangements are possible? 56. MANAGEMENT DECISIONS C & J Realty has received 12 inquiries from prospective home buyers. In how many ways can the inquiries be directed to any four of the firm’s real estate agents if each agent handles three inquiries? 57. SPORTS A Little League baseball team has 12 players available for a 9-member team (no designated team positions). a. How many different 9-person batting orders are possible? b. How many different 9-member teams are possible? c. How many different 9-member teams and 2 alternates are possible? 58. SPORTS In the men’s tennis tournament at Wimbledon, two finalists, A and B, are competing for the title, which will be awarded to the first player to win three sets. In how many different ways can the match be completed? 59. SPORTS In the women’s tennis tournament at Wimbledon, two finalists, A and B, are competing for the title, which will be awarded to the first player to win two sets. In how many different ways can the match be completed? 60. JURY SELECTION In how many different ways can a panel of 12 jurors and 2 alternate jurors be chosen from a group of 30 prospective jurors? 61. U.N. VOTING Refer to Example 14. In how many ways can a measure be passed if two particular permanent and two particular nonpermanent members of the Council abstain from voting? 62. EXAMS A student taking an examination is required to answer exactly 10 out of 15 questions.

a. In how many ways can the 10 questions be selected? b. In how many ways can the 10 questions be selected if exactly 2 of the first 3 questions must be answered? 63. TEACHING ASSISTANTSHIPS Twelve graduate students have applied for three available teaching assistantships. In how many ways can the assistantships be awarded among these applicants if a. No preference is given to any student? b. One particular student must be awarded an assistantship? c. The group of applicants includes seven men and five women and it is stipulated that at least one woman must be awarded an assistantship? 64. SENATE COMMITTEES In how many ways can a subcommittee of four be chosen from a Senate committee of five Democrats and four Republicans if a. All members are eligible? b. The subcommittee must consist of two Republicans and two Democrats? 65. CONTRACT BIDDING UBS Television Company is considering bids submitted by seven different firms for each of three different contracts. In how many ways can the contracts be awarded among these firms if no firm is to receive more than two contracts? 66. PERSONNEL SELECTION JCL Computers has five vacancies in its executive trainee program. In how many ways can the company select five trainees from a group of ten female and ten male applicants if the vacancies a. Can be filled by any combination of men and women? b. Must be filled by two men and three women? 67. COURSE SELECTION A student planning her curriculum for the upcoming year must select one of five business courses, one of three mathematics courses, two of six elective courses, and either one of four history courses or one of three social science courses. How many different curricula are available for her consideration? 68. DRIVERS’ TESTS A state Motor Vehicle Department requires learners to pass a written test on the motor vehicle laws of the state. The exam consists of ten true-or-false questions, of which eight must be answered correctly to qualify for a permit. In how many different ways can a learner who answers all the questions on the exam qualify for a permit? A list of poker hands ranked in order from the highest to the lowest is shown in the following table, along with a description and example of each hand. Use the table to answer Exercises 69–74.

Hand

Description

Straight flush

5 cards in sequence in the same suit

Example A

2

3

4

5

7.4 PERMUTATIONS AND COMBINATIONS

Four of a kind

4 cards of the same rank and any other card

K

K

K

K

2

Full house

3 of a kind and a pair

3

3

3

7

7

Flush

5 cards of the same suit that are not all in sequence

5

6

9

J

Straight

5 cards in sequence but not all of the same suit

10

J

Q

K

Three of a kind

3 cards of the same rank and 2 unmatched cards

K

K

K

2

4

Two pair

2 cards of the same rank and 2 cards of any other rank with an unmatched card

K

K

2

2

4

2 cards of the same rank and 3 unmatched cards

K

One pair

K

76. SPORTS In the World Series, one National League team and one American League team compete for the title, which is awarded to the first team to win four games. In how many different ways can the series be completed? 77. VOTING QUORUMS A quorum (minimum) of 6 voting members is required at all meetings of the Curtis Townhomes Owners Association. If there is a total of 12 voting members in the group, find the number of ways this quorum can be formed.

A

78. CIRCULAR PERMUTATIONS Suppose n distinct objects are arranged in a circle. Show that the number of (different) circular arrangements of the n objects is (n  1)!. Hint: Consider the arrangement of the five letters A, B, C, D, and E in the accompanying figure. The permutations ABCDE, BCDEA, CDEAB, DEABC, and EABCD are not distinguishable. Generalize this observation to the case of n objects. A

E

B K

5

2

429

D

4 C

If a 5-card poker hand is dealt from a well-shuffled deck of 52 cards, how many different hands consist of the following:

69. A straight flush? (Note that an ace may be played as either a high or a low card in a straight sequence—that is, A, 2, 3, 4, 5 or 10, J, Q, K, A. Hence, there are ten possible sequences for a straight in one suit.) 70. A straight (but not a straight flush)? 71. A flush (but not a straight flush)?

79. Refer to Exercise 78. In how many ways can five TV commentators be seated at a round table for a discussion? 80. Refer to Exercise 78. In how many ways can four men and four women be seated at a round table at a dinner party if each guest is seated between members of the opposite sex? 81. At the end of Section 6.3, we mentioned that solving a linear programming problem in three variables and five constraints by the methods of corners requires that we solve 56 3  3 systems of linear equations. Verify this assertion. 82. Refer to Exercise 81. Show that, in order to solve a linear programming problem in five variables and ten constraints, we must solve 3003 5  5 systems of linear equations. This assertion was also made at the end of Section 6.3.

72. Four of a kind? 73. A full house? 74. Two pair? 75. BUS ROUTING The following is a schematic diagram of a city’s street system between the points A and B. The City Transit Authority is in the process of selecting a route from A to B along which to provide bus service. If the company’s intention is to keep the route as short as possible, how many routes must be considered? B

A Street system

In Exercises 83–86, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

83. The number of permutations of n distinct objects taken all together is n! 84. P(n, r)  r! C(n, r) 85. The number of combinations of n objects taken n  r at a time is the same as the number taken r at a time. 86. If a set of n objects consists of r elements of one kind and n  r elements of another kind, then the number of permutations of the n objects taken all together is P(n, r).

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7 SETS AND PROBABILITY

7.4 Solutions to Self-Check Exercises 1. a. 5!  5  4  3  2  1  120 b.

7! 7#6#5 C17, 42   # #  35 4! 3! 3 2 1

civilian. By the multiplication principle, there are P18, 2 2 # C112, 32 # C15, 12 # C12,12 

6! c. P16, 2 2   6 # 5  30 4!

2. There are P(8, 2) ways of picking the shuttle commander and pilot (the order is important here), C(12, 3) ways of picking the engineers (the order is not important here), C(5, 1) ways of picking the scientist, and C(2, 1) ways of picking the

USING

TECHNOLOGY



8! # 12! # 5! # 2! 6! 9! 3! 4! 1! 1! 1!

8 # 7 # 12 # 11 # 10 # 5 # 2 3#2

 123,200

ways a crew can be selected.

Evaluating n!, P(n, r), and C(n, r) Graphing Utility

A graphing utility can be used to calculate factorials, permutations, and combinations with relative ease. A graphing utility is therefore an indispensable tool in solving counting problems involving large numbers of objects. Here we use the nPr (permutation) and nCr (combination) functions of a graphing utility. EXAMPLE 1 Use a graphing utility to find (a) 12!, (b) P(52, 5), and (c) C(38, 10). Solution

a. Using the factorial function, we find that 12!  479,001,600. b. Using the nPr function, we have P(52, 5)  52 nPr 5  311,875,200

c. Using the nCr function, we obtain C(38, 10)  38 nCr 10  472,733,756 Excel Excel has built-in functions for calculating factorials, permutations, and combinations.

EXAMPLE 2 Use Excel to calculate a. 12! b. P(52, 5) c. C(38, 10) Solution

a. In cell A1, enter =FACT(12) and press Shift-Enter . The number 479001600 will appear. b. In cell A2, enter =PERMUT(52,5) and press Shift-Enter . The number 311875200 will appear. c. In cell A3, enter =COMBIN(38,10) and press Shift-Enter . The number 472733756 will appear. Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate that an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2)) indicate words/characters that need to be typed and entered.

7.5 EXPERIMENTS, SAMPLE SPACES, AND EVENTS

431

TECHNOLOGY EXERCISES In Exercises 1–10, evaluate the expression.

1. 15!

2. 20!

3. 4(18!)

4.

5. P(52, 7)

6. P(24, 8)

7. C(52, 7)

8. C(26, 8)

9. P(10, 4)C(12, 6)

30! 18!

10. P(20, 5)C(9, 3)C(8, 4)

11. A mathematics professor uses a computerized test bank to prepare her final exam. If 25 different problems are avail-

able for the first three exam questions, 40 different problems available for the next five questions, and 30 different problems available for the last two questions, how many different ten-question exams can she prepare? (Assume that the order of the questions within each group is not important.) 12. S & S Brokerage has received 100 inquiries from prospective clients. In how many ways can the inquiries be directed to any five of the firm’s brokers if each broker handles 20 inquiries?

7.5 Experiments, Sample Spaces, and Events Terminology A number of specialized terms are used in the study of probability. We begin by defining the term experiment.

Experiment

An experiment is an activity with observable results. The results of the experiment are called the outcomes of the experiment. Three examples of experiments are the following: ■ ■ ■

Tossing a coin and observing whether it falls heads or tails Rolling a die and observing which of the numbers 1, 2, 3, 4, 5, or 6 shows up Testing a spark plug from a batch of 100 spark plugs and observing whether or not it is defective In our discussion of experiments, we use the following terms: Sample Point, Sample Space, and Event

Sample point: An outcome of an experiment Sample space: The set consisting of all possible sample points of an experiment Event: A subset of a sample space of an experiment The sample space of an experiment is a universal set whose elements are precisely the outcomes, or the sample points, of the experiment; the events of the experiment are the subsets of the universal set. A sample space associated with an experiment that has a finite number of possible outcomes (sample points) is called a finite sample space. Since the events of an experiment are subsets of a universal set (the sample space of the experiment), we may use the results for set theory given earlier to help us study probability. The event B is said to occur in a trial of an experiment whenever B con-

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7 SETS AND PROBABILITY

tains the observed outcome. We begin by explaining the roles played by the empty set and a universal set when viewed as events associated with an experiment. The empty set, , is called the impossible event; it cannot occur because  has no elements (outcomes). Next, the universal set S is referred to as the certain event; it must occur because S contains all the outcomes of the experiment. This terminology is illustrated in the next several examples. EXAMPLE 1 Describe the sample space associated with the experiment of tossing a coin and observing whether it falls heads or tails. What are the events of this experiment? Solution The two outcomes are heads and tails, and the required sample space is given by S  {H, T}, where H denotes the outcome heads and T denotes the outcome tails. The events of the experiment, the subsets of S, are

, {H}, {T}, S

Note that we have included the impossible event, , and the certain event, S. Since the events of an experiment are subsets of the sample space of the experiment, we may talk about the union and intersection of any two events; we can also consider the complement of an event with respect to the sample space. Union of Two Events

The union of two events E and F is the event E  F. Thus, the event E  F contains the set of outcomes of E and/or F. Intersection of Two Events

The intersection of two events E and F is the event E  F. Thus, the event E  F contains the set of outcomes common to E and F. Complement of an Event

The complement of event E is the event E c. Thus, the event E c is the set containing all the outcomes in the sample space S that are not in E. Venn diagrams depicting the union, intersection, and complement of events are shown in Figure 20. These concepts are illustrated in the following example. S

S

E

F

E

F

(a) The union of two events FIGURE 20

E

F

E

F

(b) The intersection of two events

S

E

Ec (c) The complement of the event E

7.5 EXPERIMENTS, SAMPLE SPACES, AND EVENTS

433

EXAMPLE 2 Consider the experiment of rolling a die and observing the number that falls uppermost. Let S  {1, 2, 3, 4, 5, 6} denote the sample space of the experiment and E  {2, 4, 6} and F  {1, 3} be events of this experiment. Compute (a) E  F, (b) E  F, and (c) F c. Interpret your results. Solution

a. E  F  {1, 2, 3, 4, 6} and is the event that the outcome of the experiment is a 1, a 2, a 3, a 4, or a 6. b. E  F   is the impossible event; the number appearing uppermost when a die is rolled cannot be both even and odd at the same time. c. F c  {2, 4, 5, 6} is precisely the event that the event F does not occur. If two events cannot occur at the same time, they are said to be mutually exclusive. Using set notation, we have the following definition.

Mutually Exclusive Events

E and F are mutually exclusive if E  F  . As before, we may use Venn diagrams to illustrate these events. In this case, the two mutually exclusive events are depicted as two nonintersecting circles (Figure 21). S

F

E FIGURE 21 Mutually exclusive events

EXAMPLE 3 An experiment consists of tossing a coin three times and observing the resulting sequence of heads and tails.

Explore & Discuss 1. Suppose E and F are two complementary events. Must E and F be mutually exclusive? Explain your answer. 2. Suppose E and F are mutually exclusive events. Must E and F be complementary? Explain your answer.

a. Describe the sample space S of the experiment. b. Determine the event E that exactly two heads appear. c. Determine the event F that at least one head appears. Solution

a. The sample points may be obtained with the aid of a tree diagram (Figure 22). First toss

Second toss

Third toss

Sample points

H

(H, H, H)

T H

(H, H, T) (H, T, H)

T

(H, T, T)

H

(T, H, H)

T H

(T, H, T) (T, T, H)

T

(T, T, T)

H H T

H T FIGURE 22

T

The required sample space S is given by S  {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

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7 SETS AND PROBABILITY

b. By scanning the sample space S obtained in part (a), we see that the outcomes in which exactly two heads appear are given by the event E  {HHT, HTH, THH}

c. Proceeding as in part (b), we find F  {HHH, HHT, HTH, HTT, THH, THT, TTH}

EXAMPLE 4 An experiment consists of rolling a pair of dice and observing the number that falls uppermost on each die. a. Describe an appropriate sample space S for this experiment. b. Determine the events E2, E3, E4, . . . , E12 that the sum of the numbers falling uppermost is 2, 3, 4, . . . , 12, respectively. Solution

a. We may represent each outcome of the experiment by an ordered pair of numbers, the first representing the number that appears uppermost on the first die and the second representing the number that appears uppermost on the second die. To distinguish between the two dice, think of the first die as being red and the second as being green. Since there are six possible outcomes for each die, the multiplication principle implies that there are 6  6, or 36, elements in the sample space: S  {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

b. With the aid of the results of part (a), we obtain the required list of events, shown in Table 1. TABLE 1 Sum of Uppermost Numbers

Event

2 3 4 5 6 7 8 9 10 11 12

E2  {(1, 1)} E3  {(1, 2), (2, 1)} E4  {(1, 3), (2, 2), (3, 1)} E5  {(1, 4), (2, 3), (3, 2), (4, 1)} E6  {(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)} E7  {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)} E8  {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)} E9  {(3, 6), (4, 5), (5, 4), (6, 3)} E10  {(4, 6), (5, 5), (6, 4)} E11  {(5, 6), (6, 5)} E12  {(6, 6)}

APPLIED EXAMPLE 5 Movie Attendance The manager of a local cinema records the number of patrons attending a first-run movie at the 1 p.m. screening. The theater has a seating capacity of 500. a. What is an appropriate sample space for this experiment? b. Describe the event E that fewer than 50 people attend the screening. c. Describe the event F that the theater is more than half full at the screening.

7.5 EXPERIMENTS, SAMPLE SPACES, AND EVENTS

435

Solution

a. The number of patrons at the screening (the outcome) could run from 0 to 500. Therefore, a sample space for this experiment is S  {0, 1, 2, 3, . . . , 500}

b. E  {0, 1, 2, 3, . . . , 49} c. F  {251, 252, 253, . . . , 500} APPLIED EXAMPLE 6 Family Composition An experiment consists of studying the sex composition of a three-child family in which the children were born at different times. a. b. c. d.

Describe an appropriate sample space S for this experiment. Describe the event E that there are two girls and a boy in the family. Describe the event F that the oldest child is a girl. Describe the event G that the oldest child is a girl and the youngest child is a boy.

Solution

a. The sample points of the experiment may be obtained with the aid of the tree diagram shown in Figure 23, where b denotes a boy and t denotes a girl. First child

Second child b

b g

b g FIGURE 23 Tree diagram for three-child families

g

Third child

Sample points

b

bbb

g b

bbg bgb

g

bgg

b

gbb

g b

gbg

g

ggg

ggb

We see from the tree diagram that the required sample space is given by

Explore & Discuss Think of an experiment. 1. Describe the sample point(s) and sample space of the experiment. 2. Construct two events, E and F, of the experiment. 3. Find the union and intersection of E and F and the complement of E. 4. Are E and F mutually exclusive? Explain your answer.

S  {bbb, bbt, btb, btt, tbb, tbt, ttb, ttt}

Using the tree diagram, we find that: b. E  {btt, tbt, ttb} c. F  {tbb, tbt, ttb, ttt} d. G  {tbb, ttb} The next example shows that sample spaces may be infinite. APPLIED EXAMPLE 7 Testing New Products EverBrite is developing a high-amperage, high-capacity battery as a source for powering electric cars. The battery is tested by installing it in a prototype electric car and running the car with a fully charged battery on a test track at a constant speed of 55 mph until the car runs out of power. The distance covered by the car is then observed. a. What is the sample space for this experiment? b. Describe the event E that the driving range under test conditions is less than 150 miles. c. Describe the event F that the driving range is between 200 and 250 miles, inclusive.

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7 SETS AND PROBABILITY

Solution

a. Since the distance d covered by the car in any run may be given by any nonnegative number, the sample space S is given by S  5d 0 d  06

b. The event E is given by E  5d 0 0 d 1506

c. The event F is given by F  5d 0 200 d 2506

7.5 Self-Check Exercises 1. A sample of three apples taken from Cavallero’s Fruit Stand is examined to determine whether the apples are good or rotten. a. What is an appropriate sample space for this experiment? b. Describe the event E that exactly one of the apples picked is rotten. c. Describe the event F that the first apple picked is rotten.

2. Refer to Self-Check Exercise 1. a. Find E  F. b. Find E  F. c. Find Fc. d. Are the events E and F mutually exclusive? Solutions to Self-Check Exercises 7.5 can be found on page 439.

7.5 Concept Questions 1. Explain what is meant by an experiment. Give an example. For the example you have chosen, describe (a) a sample point, (b) the sample space, and (c) an event of the experiment.

2. What does it mean for two events to be mutually exclusive? Give an example of two mutually exclusive events E and F. How can you prove that they are mutually exclusive?

7.5 Exercises In Exercises 1–6, let S  {a, b, c, d, e, f } be a sample space of an experiment and let E  {a, b }, F  {a, d, f }, and G  {b, c, e } be events of this experiment.

1. Find the events E  F and E  F. 2. Find the events F  G and F  G. 3. Find the events F and E  G . c

c

4. Find the events E and F  G. c

In Exercises 7–14, let S  {1, 2, 3, 4, 5, 6}, E  {2, 4, 6}, F  {1, 3, 5}, and G  {5, 6}.

7. Find the event E  F  G. 8. Find the event E  F  G. 9. Find the event (E  F  G)c. 10. Find the event (E  F  G)c.

c

5. Are the events E and F mutually exclusive? 6. Are the events E  F and E  Fc mutually exclusive?

11. Are the events E and F mutually exclusive? 12. Are the events F and G mutually exclusive? 13. Are the events E and F complementary? 14. Are the events F and G complementary?

7.5 EXPERIMENTS, SAMPLE SPACES, AND EVENTS

In Exercises 15–20, let S be any sample space and let E, F, and G be any three events associated with the experiment. Describe the events using the symbols , , and c.

437

28. An experiment consists of spinning the hand of the numbered disc shown in the following figure and then observing the region in which the pointer stops. (If the needle stops on a line, the result is discounted and the needle is spun again.)

15. The event that E and/or F occurs 16. The event that both E and F occur

5

1

17. The event that G does not occur 4

18. The event that E but not F occurs

2 3

19. The event that none of the events E, F, and G occurs 20. The event that E occurs but neither of the events F or G occurs 21. Consider the sample space S of Example 4, page 434. a. Determine the event that the number that falls uppermost on the first die is greater than the number that falls uppermost on the second die. b. Determine the event that the number that falls uppermost on the second die is double the number that falls uppermost on the first die. 22. Consider the sample space S of Example 4, page 434. a. Determine the event that the sum of the numbers falling uppermost is less than or equal to 7. b. Determine the event that the number falling uppermost on one die is a 4 and the number falling uppermost on the other die is greater than 4. 23. Let S  {a, b, c} be a sample space of an experiment with outcomes a, b, and c. List all the events of this experiment. 24. Let S  {1, 2, 3} be a sample space associated with an experiment. a. List all events of this experiment. b. How many subsets of S contain the number 3? c. How many subsets of S contain either the number 2 or the number 3? 25. An experiment consists of selecting a card from a standard deck of playing cards and noting whether it is black (B) or red (R). a. Describe an appropriate sample space for this experiment. b. What are the events of this experiment? 26. An experiment consists of selecting a letter at random from the letters in the word MASSACHUSETTS and observing the outcomes. a. What is an appropriate sample space for this experiment? b. Describe the event “the letter selected is a vowel.” 27. An experiment consists of tossing a coin, rolling a die, and observing the outcomes. a. Describe an appropriate sample space for this experiment. b. Describe the event “a head is tossed and an even number is rolled.”

a. What is an appropriate sample space for this experiment? b. Describe the event “the spinner points to the number 2.” c. Describe the event “the spinner points to an odd number.” 29. A die is rolled and the number that falls uppermost is observed. Let E denote the event that the number shown is a 2, and let F denote the event that the number shown is an even number. a. Are the events E and F mutually exclusive? b. Are the events E and F complementary? 30. A die is rolled and the number that falls uppermost is observed. Let E denote the event that the number shown is even, and let F denote the event that the number is an odd number. a. Are the events E and F mutually exclusive? b. Are the events E and F complementary? 31. QUALITY CONTROL A sample of three transistors taken from a local electronics store was examined to determine whether the transistors were defective (d) or nondefective (n). What is an appropriate sample space for this experiment? 32. BLOOD TYPING Human blood is classified by the presence or absence of three main antigens (A, B, and Rh). When a blood specimen is typed, the presence of the A and/or B antigen is indicated by listing the letter A and/or the letter B. If neither the A nor B antigen is present, the letter O is used. The presence or absence of the Rh antigen is indicated by the symbols  or , respectively. Thus, if a blood specimen is classified as AB, it contains the A and the B antigens as well as the Rh antigen. Similarly, O blood contains none of the three antigens. Using this information, determine the sample space corresponding to the different blood groups. 33. GAME SHOWS In a television game show, the winner is asked to select three prizes from five different prizes, A, B, C, D, and E. a. Describe a sample space of possible outcomes (order is not important). b. How many points are there in the sample space corresponding to a selection that includes A? c. How many points are there in the sample space corresponding to a selection that includes A and B? d. How many points are there in the sample space corresponding to a selection that includes either A or B?

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7 SETS AND PROBABILITY

34. AUTOMATIC TELLERS The manager of a local bank observes how long it takes a customer to complete his transactions at the automatic bank teller. a. Describe an appropriate sample space for this experiment. b. Describe the event that it takes a customer between 2 and 3 min to complete his transactions at the automatic bank teller. 35. COMMON STOCKS Robin purchased shares of a machine tool company and shares of an airline company. Let E be the event that the shares of the machine tool company increase in value over the next 6 mo, and let F be the event that the shares of the airline company increase in value over the next 6 mo. Using the symbols , , and c, describe the following events. a. The shares in the machine tool company do not increase in value. b. The shares in both the machine tool company and the airline company do not increase in value. c. The shares of at least one of the two companies increase in value. d. The shares of only one of the two companies increase in value. 36. CUSTOMER SERVICE SURVEYS The customer service department of Universal Instruments, manufacturer of the Galaxy home computer, conducted a survey among customers who had returned their purchase registration cards. Purchasers of its deluxe model home computer were asked to report the length of time (t) in days before service was required. a. Describe a sample space corresponding to this survey. b. Describe the event E that a home computer required service before a period of 90 days had elapsed. c. Describe the event F that a home computer did not require service before a period of 1 yr had elapsed. 37. ASSEMBLY-TIME STUDIES A time study was conducted by the production manager of Vista Vision to determine the length of time in minutes required by an assembly worker to complete a certain task during the assembly of its Pulsar color television sets. a. Describe a sample space corresponding to this time study. b. Describe the event E that an assembly worker took 2 min or less to complete the task. c. Describe the event F that an assembly worker took more than 2 min to complete the task. 38. POLITICAL POLLS An opinion poll is conducted among a state’s electorate to determine the relationship between their income levels and their stands on a proposition aimed at reducing state income taxes. Voters are classified as belonging to either the low-, middle-, or upper-income group. They are asked whether they favor, oppose, or are undecided about the proposition. Let the letters L, M, and U represent the low-, middle-, and upper-income groups, respectively, and let the letters f, o, and u represent the responses—favor, oppose, and undecided, respectively. a. Describe a sample space corresponding to this poll. b. Describe the event E1 that a respondent favors the proposition. c. Describe the event E2 that a respondent opposes the proposition and does not belong to the low-income group.

d. Describe the event E3 that a respondent does not favor the proposition and does not belong to the upper-income group. 39. QUALITY CONTROL As part of a quality-control procedure, an inspector at Bristol Farms randomly selects ten eggs from each consignment of eggs he receives and records the number of broken eggs. a. What is an appropriate sample space for this experiment? b. Describe the event E that at most three eggs are broken. c. Describe the event F that at least five eggs are broken. 40. POLITICAL POLLS In the opinion poll of Exercise 38, the voters were also asked to indicate their political affiliations—Democrat, Republican, or Independent. As before, let the letters L, M, and U represent the low-, middle-, and upper-income groups, respectively. Let the letters D, R, and I represent Democrat, Republican, and Independent, respectively. a. Describe a sample space corresponding to this poll. b. Describe the event E1 that a respondent is a Democrat. c. Describe the event E2 that a respondent belongs to the upper-income group and is a Republican. d. Describe the event E3 that a respondent belongs to the middle-income group and is not a Democrat. 41. SHUTTLE BUS USAGE A certain airport hotel operates a shuttle bus service between the hotel and the airport. The maximum capacity of a bus is 20 passengers. On alternate trips of the shuttle bus over a period of 1 wk, the hotel manager kept a record of the number of passengers arriving at the hotel in each bus. a. What is an appropriate sample space for this experiment? b. Describe the event E that a shuttle bus carried fewer than ten passengers. c. Describe the event F that a shuttle bus arrived with a full load. 42. SPORTS Eight players, A, B, C, D, E, F, G, and H, are competing in a series of elimination matches of a tennis tournament in which the winner of each preliminary match will advance to the semifinals and the winners of the semifinals will advance to the finals. An outline of the scheduled matches follows. Describe a sample space listing the possible participants in the finals. Match I A vs. B Match II C vs. D Match III E vs. F Match IV G vs. H

Semifinal match Final match Semifinal match

43. An experiment consists of selecting a card at random from a well-shuffled 52-card deck. Let E denote the event that an ace is drawn and let F denote the event that a spade is drawn. Show that n(E  F)  n(E)  n(F)  n(E  F ).

7.6 DEFINITION OF PROBABILITY

439

44. Let S be a sample space for an experiment. Show that if E is any event of an experiment, then E and Ec are mutually exclusive.

In Exercises 47 and 48, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

45. Let S be a sample space for an experiment, and let E and F be events of this experiment. Show that the events E  F and E c  F c are mutually exclusive.

47. If E and F are mutually exclusive and E and G are mutually exclusive, then F and G are mutually exclusive.

Hint: Use De Morgan’s law.

46. Let S be a sample space of an experiment with n outcomes. Determine the number of events of this experiment.

48. The numbers 1, 2, and 3 are written separately on three pieces of paper. These slips of paper are then placed in a bowl. If you draw two slips from the bowl, one at a time and without replacement, then the sample space for this experiment consists of six elements.

7.5 Solutions to Self-Check Exercises 1. a. Let t denote a good apple and r a rotten apple. Thus, the required sample points may be obtained with the aid of a tree diagram (compare with Example 3). The required sample space is given by S  {ttt, ttr, trt, trr, rtt, rtr, rrt, rrr}

b. By scanning the sample space S obtained in part (a), we identify the outcomes in which exactly one apple is rotten. We find E  {ttr, trt, rtt}

c. Proceeding as in part (b), we find F  {rtt, rtr, rrt, rrr}

2. Using the results of Self-Check Exercise 1, we find: a. E  F  {ttr, trt, rtt, rtr, rrt, rrr} b. E  F  {rtt} c. Fc is the set of outcomes in S but not in F. Thus, F c  {ttt, ttr, trt, trr}

d. Since E  F  , we conclude that E and F are not mutually exclusive.

7.6 Definition of Probability Finding the Probability of an Event Let’s return to the coin-tossing experiment. The sample space of this experiment is given by S  {H, T}, where the sample points H and T correspond to the two possible outcomes, heads and tails. If the coin is unbiased, then there is one chance out of two of obtaining a head (or a tail), and we say that the probability of tossing a head (tail) is 12, abbreviated P1H2 

1 2

and

P1T2 

1 2

An alternative method of obtaining the values of P(H) and P(T) is based on continued experimentation and does not depend on the assumption that the two outcomes are equally likely. Table 2 summarizes the results of such an exercise. TABLE 2 As the Number of Trials Increases, the Relative Frequency Approaches .5

Number of Tosses, n

Number of Heads, m

Relative Frequency of Heads, m/n

10 100 1,000 10,000 20,000 40,000

4 58 492 5,034 10,024 20,032

.4000 .5800 .4920 .5034 .5012 .5008

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7 SETS AND PROBABILITY

Observe that the relative frequencies (column 3) differ considerably when the number of trials is small, but as the number of trials becomes very large, the relative frequency approaches the number .5. This result suggests that we assign to P(H) the value 12, as before. More generally, consider an experiment that may be repeated over and over again under independent and similar conditions. Suppose that in n trials an event E occurs m times. We call the ratio m/n the relative frequency of the event E after n repetitions. If this relative frequency approaches some value P(E ) as n becomes larger and larger, then P(E ) is called the empirical probability of E. Thus, the probability P(E ) of an event occurring is a measure of the proportion of the time that the event E will occur in the long run. Observe that this method of computing the probability of a head occurring is effective even in the case when a biased coin is used in the experiment. The relative frequency distribution is often referred to as an observed or empirical probability distribution. The probability of an event is a number that lies between 0 and 1, inclusive. In general, the larger the probability of an event, the more likely the event will occur. Thus, an event with a probability of .8 is more likely to occur than an event with a probability of .6. An event with a probability of 12, or .5, has a fifty-fifty chance of occurring. Now suppose we are given an experiment and wish to determine the probabilities associated with certain events of the experiment. This problem could be solved by computing P(E ) directly for each event E of interest. In practice, however, the number of events of interest is usually quite large, so this approach is not satisfactory. The following approach is particularly suitable when the sample space of an experiment is finite.* Let S be a finite sample space with n outcomes; that is, S  {s1, s2, s3, . . . , sn}

Then the events {s1}, {s2}, {s3}, . . . , {sn}

TABLE 3 A Probability Distribution

Simple Event

Probability*

{s1} {s2} {s3}

P(s1) P(s2) P(s3)

o

o

{sn}

P(sn)

*For simplicity, we use the notation P(si) instead of the technically more correct P({si}).

that consist of exactly one point are called the elementary, or simple, events of the experiment. They are elementary in the sense that any (nonempty) event of the experiment may be obtained by taking a finite union of suitable elementary events. The simple events of an experiment are also mutually exclusive; that is, given any two simple events of the experiment, only one can occur. By assigning probabilities to each of the simple events, we obtain the results shown in Table 3. This table is called a probability distribution for the experiment. The function P, which assigns a probability to each of the simple events, is called a probability function. The numbers P(s1), P(s2), . . . , P(sn) have the following properties: 1. 0 P(si) 1 i  1, 2, . . . , n 2. P(s1)  P(s2)  . . .  P(sn)  1 3. P({si}  {sj})  P(si)  P(sj) (i  j)

i  1, 2, . . . , n; j  1, 2, . . . , n

The first property simply states that the probability of a simple event must be between 0 and 1, inclusive. The second property states that the sum of the probabilities of all simple events of the sample space is 1. This follows from the fact that the event S is certain to occur. The third property states that the probability of the union of two simple events is given by the sum of their probabilities.

*For the remainder of the chapter, we assume that all sample spaces are finite.

7.6 DEFINITION OF PROBABILITY

441

Exploring with

TECHNOLOGY We can use a graphing calculator to simulate the coin-tossing experiment described earlier. Associate the outcome “a head” with the number 1 and the outcome “a tail” with the number 0. Select the function randInt( of the TI-83/84. (You can find this by pressing MATH and then moving the cursor to PRB.) Enter randInt(0,1) and then press ENTER repeatedly. This generates 0s and 1s randomly, which simulates the results of tossing an unbiased coin.

As we saw earlier, there is no unique method for assigning probabilities to the simple events of an experiment. In practice, the methods used to determine these probabilities may range from theoretical considerations of the problem on the one extreme to the reliance on “educated guesses” on the other. Sample spaces in which the outcomes are equally likely are called uniform sample spaces. Assigning probabilities to the simple events in these spaces is relatively easy.

Probability of an Event in a Uniform Sample Space

If S  {s1, s2, . . . , sn}

is the sample space for an experiment in which the outcomes are equally likely, then we assign the probabilities 1 P1s1 2  P1s2 2  p  P1sn 2  n

to each of the simple events {s1}, {s2}, . . . , {sn}.

EXAMPLE 1 A fair die is rolled, and the number that falls uppermost is observed. Determine the probability distribution for the experiment.

A Probability Distribution

Simple Event

{1} {2} {3} {4} {5} {6}

The sample space for the experiment is S  {1, 2, 3, 4, 5, 6}, and the simple events are accordingly given by the sets {1}, {2}, {3}, {4}, {5}, and {6}. Since the die is assumed to be fair, the six outcomes are equally likely. We therefore assign a probability of 16 to each of the simple events and obtain the probability distribution shown in Table 4.

Solution

TABLE 4

Probability 1 6 1 6 1 6 1 6 1 6 1 6

Explore & Discuss You suspect that a die is biased. 1. Describe a method you might use to show that your assertion is correct. 2. How would you assign the probability to each outcome 1 through 6 of an experiment that consists of rolling the die and observing the number that lands uppermost?

The next example shows how the relative frequency interpretation of probability lends itself to the computation of probabilities.

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7 SETS AND PROBABILITY

TABLE 5 Data Obtained during 200 Test Runs of an Electric Car

Distance Covered in Miles, x

Frequency of Occurrence

0 x 50 50 x 100 100 x 150 150 x 200 200 x 250 250 x

4 10 30 100 40 16

APPLIED EXAMPLE 2 Testing New Products Refer to Example 7, Section 7.5. The data shown in Table 5 were obtained in tests involving 200 test runs. Each run was made with a fully charged battery. a. Describe an appropriate sample space for this experiment. b. Find the empirical probability distribution for this experiment. Solution

a. Let s1 denote the outcome that the distance covered by the car does not exceed 50 miles; let s2 denote the outcome that the distance covered by the car is greater than 50 miles but does not exceed 100 miles, and so on. Finally, let s6 denote the outcome that the distance covered by the car is greater than 250 miles. Then, the required sample space is given by S  {s1, s2, s3, s4, s5, s6}

b. To compute the empirical probability distribution for the experiment, we turn to the relative frequency interpretation of probability. Accepting the inaccuracies inherent in a relatively small number of trials (200 runs), we take the probability of s1 occurring as

TABLE 6 A Probability Distribution

Simple Event

Probability

{s1} {s2} {s3} {s4} {s5} {s6}

.02 .05 .15 .50 .20 .08

P1s1 2 

Number of trials in which s1 occurs Total number of trials 4   .02 200

In a similar manner, we assign probabilities to the other simple events, obtaining the probability distribution shown in Table 6. We are now in a position to give a procedure for computing the probability P(E) of an arbitrary event E of an experiment. Finding the Probability of an Event E

1. Determine a sample space S associated with the experiment. 2. Assign probabilities to the simple events of S. 3. If E  {s1, s2, s3, . . . , sn}, where {s1}, {s2}, {s3}, . . . , {sn} are simple events, then P(E )  P(s1)  P(s2)  P(s3)  . . .  P(sn) If E is the empty set, , then P(E)  0. The principle stated in step 3 is called the addition principle and is a consequence of Property 3 of the probability function (page 440). This principle allows us to find the probabilities of all other events once the probabilities of the simple events are known. The addition rule in step 3 applies only to the addition of probabilities of simple events. APPLIED EXAMPLE 3 Rolling Dice A pair of fair dice is rolled. a. Calculate the probability that the two dice show the same number. b. Calculate the probability that the sum of the numbers of the two dice is 6. Solution From the results of Example 4, page 434, we see that the sample space S of the experiment consists of 36 outcomes:

S  {(1, 1), (1, 2), . . . , (6, 5), (6, 6)}

7.6 DEFINITION OF PROBABILITY

443

Since both dice are fair, each of the 36 outcomes is equally likely. Accordingly, we assign the probability of 361 to each simple event. a. The event that the two dice show the same number is given by E  {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}

(Figure 24). Therefore, by the addition principle, the probability that the two dice show the same number is given by P 1E2  P 3 11, 12 4  P 3 12, 22 4  p  P 3 16, 62 4 1 1 1  p 36 36 36 1  6



Six terms

b. The event that the sum of the numbers of the two dice is 6 is given by E6  {(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)}

(Figure 25). Therefore, the probability that the sum of the numbers on the two dice is 6 is given by P 1E6 2  P 3 11, 52 4  P 3 12, 42 4  P 3 13, 32 4  P 3 14, 22 4  P 3 15, 12 4 1 1 1 Five terms   p 36 36 36 5  36

FIGURE 24

FIGURE 25

The event that the two dice show the same number

The event that the sum of the numbers on the two dice is 6

APPLIED EXAMPLE 4 Testing New Products Consider the experiment by EverBrite in Example 2. What is the probability that the prototype car will travel more than 150 miles on a fully charged battery? Solution Using the results of Example 2, we see that the event that the car will travel more than 150 miles on a fully charged battery is given by E  {s4, s5, s6}. Therefore, the probability that the car will travel more than 150 miles on one charge is given by

P(E )  P(s4)  P(s5)  P(s6)

or, using the probability distribution for the experiment obtained in Example 2, P(E )  .50  .20  .08  .78

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7 SETS AND PROBABILITY

7.6 Self-Check Exercises 1. A biased die was rolled repeatedly, and the results of the experiment are summarized in the following table: Outcome Frequency of Occurrence

1

2

3

4

5

6

142

173

158

175

162

190

Using the relative frequency interpretation of probability, find the empirical probability distribution for this experiment. 2. In an experiment conducted to study the effectiveness of an eye-level third brake light in the prevention of rear-end col-

lisions, 250 of the 500 highway patrol cars of a certain state were equipped with such lights. At the end of the 1-yr trial period, the records revealed that for those equipped with a third brake light there were 14 incidents of rear-end collision. There were 22 such incidents involving the cars not equipped with the accessory. Based on these data, what is the probability that a highway patrol car equipped with a third brake light will be rear-ended within a 1-yr period? What is the probability that a car not so equipped will be rear-ended within a 1-yr period? Solutions to Self-Check Exercises 7.6 can be found on page 448.

7.6 Concept Questions 1. Define (a) a probability distribution and (b) a probability function. Give examples of each. 2. If S  {s1, s2, . . . , sn} is the sample space for an experiment in which the outcomes are equally likely, what is the probability of each of the simple events s1, s2, . . . , sn? What is this type of sample space called?

3. Suppose E  {s1, s2, s3, . . . , sn}, where E is an event of an experiment and {s1}, {s2}, {s3}, . . . , {sn} are simple events. If E is nonempty, what is P(E)? If E is empty, what is P(E)?

7.6 Exercises In Exercises 1–8, list the simple events associated with each experiment.

1. A nickel and a dime are tossed, and the result of heads or tails is recorded for each coin. 2. A card is selected at random from a standard 52-card deck, and its suit—hearts (h), diamonds (d), spades (s), or clubs (c)—is recorded. 3. OPINION POLLS An opinion poll is conducted among a group of registered voters. Their political affiliation— Democrat (D), Republican (R), or Independent (I )—and their sex—male (m) or female ( f )—are recorded. 4. QUALITY CONTROL As part of a quality-control procedure, eight circuit boards are checked, and the number of defective boards is recorded. 5. MOVIE ATTENDANCE In a survey conducted to determine whether movie attendance is increasing (i), decreasing (d), or holding steady (s) among various sectors of the population, participants are classified as follows: Group 1: Those aged 10–19 Group 2: Those aged 20–29

Group 3: Those aged 30–39 Group 4: Those aged 40–49 Group 5: Those aged 50 and older The response and age group of each participant are recorded. 6. DURABLE GOODS ORDERS Data concerning durable goods orders are obtained each month by an economist. A record is kept for a 1-yr period of any increase (i), decrease (d ), or unchanged movement (u) in the number of durable goods orders for each month as compared with the number of such orders in the same month of the previous year. 7. BLOOD TYPES Blood tests are given as a part of the admission procedure at the Monterey Garden Community Hospital. The blood type of each patient (A, B, AB, or O) and the presence or absence of the Rh factor in each patient’s blood (Rh or Rh) are recorded. 8. METEOROLOGY A meteorologist preparing a weather map classifies the expected average temperature in each of five neighboring states (MN, WI, IA, IL, MO) for the upcoming week as follows: a. More than 10° below average b. Normal to 10° below average

445

7.6 DEFINITION OF PROBABILITY

c. Higher than normal to 10° above average d. More than 10° above average Using each state’s abbreviation and the categories—(a), (b), (c), and (d)—the meteorologist records these data. 9. GRADE DISTRIBUTIONS The grade distribution for a certain class is shown in the following table. Find the probability distribution associated with these data. Grade Frequency of Occurrence

A

B

C

D

F

4

10

18

6

2

10. BLOOD TYPES The percentage of the general population that has each blood type is shown in the following table. Determine the probability distribution associated with these data. Blood Type Population, %

A 41

B 12

AB 3

O 44

Day of the Week Average Number of Deaths

Sunday

Monday

Tuesday

Wednesday

132

98

95

98

Day of the Week Average Number of Deaths

Thursday

Friday

Saturday

105

133

158

Find the empirical probability distribution associated with these data. Source: Insurance Institute for Highway Safety

15. POLITICAL VIEWS In a poll conducted among 2000 college freshmen to ascertain the political views of college students, the accompanying data were obtained. Determine the empirical probability distribution associated with these data. Political Views Respondents

A 52

B 398

C 1140

D 386

E 24

A: Far left 11. FIGHTING INFLATION In a survey of 2000 adults 18 yr and older conducted in 2007, the following question was asked: Is your family income keeping pace with the cost of living? The results of the survey follow: Answer Respondents

Falling behind 800

Staying even 880

Increasing faster 240

Don’t know 80

Determine the empirical probability distribution associated with these data. Source: Pew Research Center

12. CONSUMER SURVEY In an online survey of 500 adults living with children under the age of 18 yr, the participants were asked how many days per week they cook at home. The results of the survey are summarized below: Number of Days Respondents

0 25

1 30

2 45

3 75

4 55

5 100

6 85

7 85

Determine the empirical probability distribution associated with these data. Source: Super Target

13. SAME-SEX MARRIAGE In a Los Angeles Times poll of 1936 California residents conducted in February 2004, the following question was asked: Do you favor or oppose an amendment to the U.S. Constitution barring same-sex marriage? The following results were obtained: Opinion Respondents

Favor 910

Oppose 891

Don’t know 135

Determine the empirical probability distribution associated with these data. Source: The Field Poll, Los Angeles Times

14. TRAFFIC DEATHS A study of deaths in car crashes from 1986 to 2002 revealed the following data on deaths in crashes by day of the week.

B: Liberal C: Middle of the road D: Conservative E: Far right 16. PRODUCT SAFETY SURVEYS The accompanying data were obtained from a survey of 1500 Americans who were asked: How safe are American-made consumer products? Determine the empirical probability distribution associated with these data. Rating Respondents

A 285

B 915

C 225

D 30

E 45

A: Very safe B: Somewhat safe C: Not too safe D: Not safe at all E: Don’t know 17. TRAFFIC SURVEYS The number of cars entering a tunnel leading to an airport in a major city over a period of 200 peak hours was observed, and the following data were obtained: Number of Cars, x 0 x 200 200 x 400 400 x 600 600 x 800 800 x 1000 x  1000

Frequency of Occurrence 15 20 35 70 45 15

a. Describe an appropriate sample space for this experiment. b. Find the empirical probability distribution for this experiment.

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7 SETS AND PROBABILITY

18. ARRIVAL TIMES The arrival times of the 8 a.m. Bostonbased commuter train as observed in the suburban town of Sharon over 120 weekdays is summarized below: Arrival Time, x 7:56 a.m. x 7:58 a.m. 7:58 a.m. x 8:00 a.m. 8:00 a.m. x 8:02 a.m. 8:02 a.m. x 8:04 a.m. 8:04 a.m. x 8:06 a.m. 8:06 a.m. x 8:08 a.m. 8:08 a.m. x 8:10 a.m.

Frequency of Occurrence 4 18 50 32 9 4 3

a. Describe an appropriate sample space for this experiment. b. Find the empirical probability distribution for this experiment. 19. CORRECTIVE LENS USE According to Mediamark Research, 84 million out of 179 million adults in the United States correct their vision by using prescription eyeglasses, bifocals, or contact lenses. (Some respondents use more than one type.) What is the probability that an adult selected at random from the adult population uses corrective lenses? Source: Mediamark Research

20. CORRECTIONAL SUPERVISION A study conducted by the Corrections Department of a certain state revealed that 163,605 people out of a total adult population of 1,778,314 were under correctional supervision (on probation, on parole, or in jail). What is the probability that a person selected at random from the adult population in that state is under correctional supervision? 21. LIGHTNING DEATHS According to data obtained from the National Weather Service, 376 of the 439 people killed by lightning in the United States between 1985 and 1992 were men. (Job and recreational habits of men make them more vulnerable to lightning.) Assuming that this trend holds in the future, what is the probability that a person killed by lightning a. Is a male? b. Is a female? Source: National Weather Service

22. QUALITY CONTROL One light bulb is selected at random from a lot of 120 light bulbs, of which 5% are defective. What is the probability that the light bulb selected is defective? 23. EFFORTS TO STOP SHOPLIFTING According to a survey of 176 retailers, 46% of them use electronic tags as protection against shoplifting and employee theft. If one of these retailers is selected at random, what is the probability that he or she uses electronic tags as antitheft devices? 24. If a ball is selected at random from an urn containing three red balls, two white balls, and five blue balls, what is the probability that it will be a white ball?

25. If a card is drawn at random from a standard 52-card deck, what is the probability that the card drawn is a. A diamond? b. A black card? c. An ace? 26. A pair of fair dice is rolled. What is the probability that a. The sum of the numbers shown uppermost is less than 5? b. At least one 6 is rolled? 27. TRAFFIC LIGHTS What is the probability of arriving at a traffic light when it is red if the red signal is lit for 30 sec, the yellow signal for 5 sec, and the green signal for 45 sec? 28. ROULETTE What is the probability that a roulette ball will come to rest on an even number other than 0 or 00? (Assume that there are 38 equally likely outcomes consisting of the numbers 1–36, 0, and 00.) 29. DISPOSITION OF CRIMINAL CASES Of the 98 first-degree murder cases from 2002 through the first half of 2004 in the Suffolk superior court, 9 cases were thrown out of the system, 62 cases were plea-bargained, and 27 cases went to trial. What is the probability that a case selected at random a. Was settled through plea bargaining? b. Went to trial? Source: Boston Globe

30. SWEEPSTAKES In a sweepstakes sponsored by Gemini Paper Products, 100,000 entries have been received. If 1 grand prize, 5 first prizes, 25 second prizes, and 500 third prizes are to be awarded, what is the probability that a person who has submitted one entry will win a. The grand prize? b. A prize? 31. POLITICAL POLLS An opinion poll was conducted among a group of registered voters in a certain state concerning a proposition aimed at limiting state and local taxes. Results of the poll indicated that 35% of the voters favored the proposition, 32% were against it, and the remaining group were undecided. If the results of the poll are assumed to be representative of the opinions of the state’s electorate, what is the probability that a registered voter selected at random from the electorate a. Favors the proposition? b. Is undecided about the proposition? 32. PARENTAL INFLUENCE In an online survey of 1962 executives from 64 countries conducted by Korn/Ferry International between August and October 2006, the executives were asked if they would try to influence their children’s career choices. Their replies: A (to a very great extent), B (to a great extent), C (to some extent), D (to a small extent), and E (not at all) are recorded below: Answer Respondents

A 135

B 404

C 1057

D 211

E 155

What is the probability that a randomly selected respondent’s answer was D (to a small extent) or E (not at all)? Source: Korn/Ferry International

7.6 DEFINITION OF PROBABILITY

33. GREEN COMPANIES In a survey conducted in 2007 of 1004 adults 18 yr and older, the following question was asked: How are American companies doing on protecting the environment compared with companies in other countries? The results are summarized below: Answer Respondents

Behind 382

Equal 281

Ahead 251

Don’t know 90

If an adult in the survey is selected at random, what is the probability that he or she said that American companies are equal or ahead on protecting the environment compared with companies in other countries? Source: GfK Roper

34. STAYING IN TOUCH In a poll conducted in 2007, 2000 adults ages 18 yr and older were asked how frequently they are in touch with their parents by phone. The results of the poll are as follows:

447

a. Had little or no confidence that he or she had detected all significant security breaches in the past year? b. Was very confident that he or she had detected all significant security breaches in the past year? Source: Forsythe Solutions Group

37. MUSIC VENUES In a survey designed to determine where people listen to music in their home, 1000 people were asked in which room at home they were mostly likely to listen to music. The results are tabulated below: Study/ Living Master home Room room bedroom office Kitchen Bathroom Other Respondents 448 169 155 100 22 106

If a respondent is selected at random, what is the probability that he or she most likely listens to music a. In the living room? b. In the study/home office or the kitchen? Source: Phillips Electronics

Answer Respondents, %

Monthly 11

Weekly 47

Daily 32

Don’t know 2

Less 8

If a person who participated in the poll is selected at random, what is the probability that the person said he or she kept in touch with his or her parents a. Once a week? b. At least once a week? Source: Pew Research Center

35. SPENDING METHODS In a survey on consumer-spending methods conducted in 2006, the following results were obtained:

Payment Method Checks Cash Credit cards Transactions, % 37 14 25

Debit/ATM cards Other 15 9

If a transaction tracked in this survey is selected at random, what is the probability that the transaction was paid for a. With a credit card or with a debit/ATM card? b. With cash or some method other than with a check, a credit card, or a debit/ATM card? Source: Minute/Visa USA Research Services

36. SECURITY BREACHES In a survey of 106 senior information technology and data security professionals at major U.S. companies regarding their confidence that they had detected all significant security breaches in the past year, the following responses were obtained. Answer Respondents

Very confident 21

Moderately confident 56

Not very confident 22

Not at all confident 7

What is the probability that a respondent in the survey selected at random

38. RETIREMENT BENEFITS VERSUS SALARY In a survey conducted in 2007 of 1402 workers 18 yr and older regarding their opinion on retirement benefits, the following data were obtained: 827 said that it was better to have excellent retirement benefits with a lower-than-expected salary, 477 said that it was better to have a higher-than-expected salary with poor retirement benefits, 42 said “neither,” and 56 said “not sure.” If a worker in the survey is selected at random, what is the probability that he or she answered that it was better to have a. Excellent retirement benefits with a lower-than-expected salary? b. A higher-than-expected salary with poor retirement benefits? Source: Transamerica Center for Retirement

39. AIRLINE SAFETY In an attempt to study the leading causes of airline crashes, the following data were compiled from records of airline crashes from 1959 to 1994 (excluding sabotage and military action). Primary Factor Pilot Airplane Maintenance Weather Airport/air traffic control Miscellaneous/other

Accidents 327 49 14 22 19 15

Assume that you have just learned of an airline crash and that the data give a generally good indication of the causes of airline crashes. Give an estimate of the probability that the primary cause of the crash was due to pilot error or bad weather. Source: National Transportation Safety Board

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7 SETS AND PROBABILITY

40. HOUSING APPRECIATION In a survey conducted in the fall 2006, 800 homeowners were asked about their expectations regarding the value of their home in the next few years; the results of the survey are summarized below: Expectations

Homeowners

Decrease

48

Stay the same

152

Increase less than 5%

232

Increase 5–10%

240

Increase more than 10%

128

If a homeowner in the survey is chosen at random, what is the probability that he or she expected his or her home to a. Stay the same or decrease in value in the next few years? b. Increase 5% or more in value in the next few years?

44. A ball is selected at random from an urn containing six black balls and six red balls, and the color of the ball is recorded. 45. Let S  {s1, s2, s3, s4, s5, s6} be the sample space associated with an experiment having the following probability distribution: Outcome

s1

s2

s3

s4

s5

s6

Probability

1 12

1 4

1 12

1 6

1 3

1 12

Find the probability of the event: a. A  {s1, s3} b. B  {s2, s4, s5, s6} c. C  S 46. Let S  {s1, s2, s3, s4, s5} be the sample space associated with an experiment having the following probability distribution:

Source: S&P, RBC Capital Markets

41. A pair of fair dice is rolled, and the sum of the two numbers falling uppermost is observed. The probability of obtaining a sum of 2 is the same as that of obtaining a 7 since there is only one way of getting a 2—namely, by each die showing a 1; and there is only one way of obtaining a 7—namely, by one die showing a 3 and the other die showing a 4. What is wrong with this argument?

Outcome

s1

s2

s3

s4

s5

Probability

1 14

3 14

6 14

2 14

2 14

Find the probability of the event: a. A  {s1, s2, s4} b. B  {s1, s5} c. C  S

In Exercises 42–44, determine whether the given experiment has a sample space with equally likely outcomes.

In Exercises 47 and 48, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

42. A loaded die is rolled, and the number appearing uppermost on the die is recorded.

47. If S  {s1, s2, . . . , sn} is a uniform sample space with n outcomes, then 0 P(s1)  P(s2)  . . .  P(sn) 1.

43. Two fair dice are rolled, and the sum of the numbers appearing uppermost is recorded.

48. Let S  {s1, s2, . . . , sn} be a uniform sample space for an experiment. If n  5 and E  {s1, s2, s5}, then P(E)  3/n.

7.6 Solutions to Self-Check Exercises 1.

2. The probability that a highway patrol car equipped with a third brake light will be rear-ended within a 1-yr period is given by

Number of trials in which a 1 appears uppermost P 11 2  Total number of trials 

142 1000

Number of rear៮end collisions involving cars equipped with a third brake light 14   .056 Total number of such cars 250

 .142

Similarly, we compute P(2), . . . , P(6), obtaining the following probability distribution: Outcome Probability

1 .142

2 .173

3 .158

4 .175

5 .162

6 .190

The probability that a highway patrol car not equipped with a third brake light will be rear-ended within a 1-yr period is given by Number of rear៮end collisions involving cars not equipped with a third brake light 22   .088 Total number of such cars 250

7.7 RULES OF PROBABILITY

449

7.7 Rules of Probability Properties of the Probability Function and Their Applications In this section, we examine some of the properties of the probability function and look at the role they play in solving certain problems. We begin by looking at the generalization of the three properties of the probability function, which were stated for simple events in the last section. Let S be a sample space of an experiment and suppose E and F are events of the experiment. We have:

S

E

F

Property 1. P(E )  0 for any E. Property 2. P(S)  1. Property 3. If E and F are mutually exclusive (that is, only one of them can

occur or, equivalently, E  F  ), then P(E  F )  P(E)  P(F )

FIGURE 26 If E and F are mutually exclusive events, then P(E  F )  P(E )  P(F ).

(Figure 26).

Property 3 may be easily extended to the case involving any finite number of mutually exclusive events. Thus, if E1, E2, . . . , En are mutually exclusive events, then P(E1  E2  p  En)  P(E1)  P(E2)  p  P(En) TABLE 7 Probability Distribution

Score, x

x  700 600 x 700 500 x 600 400 x 500 300 x 400 x 300

Probability

.01 .07 .19 .23 .31 .19

APPLIED EXAMPLE 1 SAT Verbal Scores The superintendent of a metropolitan school district has estimated the probabilities associated with the SAT verbal scores of students from that district. The results are shown in Table 7. If a student is selected at random, what is the probability that his or her SAT verbal score will be a. More than 400? b. Less than or equal to 500? c. Greater than 400 but less than or equal to 600? Let A, B, C, D, E, and F denote, respectively, the event that the score is greater than 700, greater than 600 but less than or equal to 700, greater than 500 but less than or equal to 600, and so forth. Then these events are mutually exclusive. Therefore,

Solution

a. The probability that the student’s score will be more than 400 is given by P1D  C  B  A2  P1D2  P1C2  P1B2  P1A2  .23  .19  .07  .01  .5

b. The probability that the student’s score will be less than or equal to 500 is given by P1D  E  F2  P1D2  P1E2  P1F2  .23  .31  .19  .73

450

7 SETS AND PROBABILITY

c. The probability that the student’s score will be greater than 400 but less than or equal to 600 is given by P1C  D2  P1C2  P1D2  .19  .23  .42

Property 3 holds if and only if E and F are mutually exclusive. In the general case, we have the following rule.

Property 4. Addition Rule

If E and F are any two events of an experiment, then P1E  F2  P1E2  P1F2  P1E  F2

E

E

FIGURE 27

c

F

F

S

E

c

F

E  F  (E  F c )  (E  F)  (E c  F )

To derive this property, refer to Figure 27. Observe that we can write E  1E  Fc 2  1E  F2

and

F  1Ec  F2  1E  F2

as a union of disjoint sets. Therefore, P1E2  P1E  F c 2  P1E  F2

or P1E  Fc 2  P1E2  P1E  F2

P1F2  P1Ec  F2  P1E  F2

or P1Ec  F2  P1F2  P1E  F2

and

Finally, since E  F  (E  Fc)  (E  F)  (Ec  F) is a union of disjoint sets, we have P1E  F2  P1E  Fc 2  P1E  F2  P1Ec  F2  P1E2  P1E  F2  P1E  F2  P1F2  P1E  F2  P1E2  P1F2  P1E  F2

Use the earlier results.

Observe that if E and F are mutually exclusive—that is, if E  F  — then the equation of Property 4 reduces to that of Property 3. In other words, if E and F are mutually exclusive events, then P(E  F)  P(E)  P(F). If E and F are not mutually exclusive events, then P(E  F)  P(E)  P(F)  P(E  F). Note

EXAMPLE 2 A card is drawn from a well-shuffled deck of 52 playing cards. What is the probability that it is an ace or a spade? Solution Let E denote the event that the card drawn is an ace and let F denote the event that the card drawn is a spade. Then,

P1E2 

4 52

and

P1F2 

13 52

Furthermore, E and F are not mutually exclusive events. In fact, E  F is the event that the card drawn is the ace of spades. Consequently, P1E  F2 

1 52

7.7 RULES OF PROBABILITY

PORTFOLIO

451

Todd Good TITLE Owner and Broker INSTITUTION Good and Associates

T

In terms of safety statistics, we’ve found that accidents and injuries tend to vary quite a bit from one make and model to another. With other factors being equal, a person who drives a Pontiac Firebird is much more likely to be involved in an accident than someone who drives a Buick Park Avenue. For example, a 23-year-old, unmarried male with a good driving record who uses his Firebird for commuting and pleasure driving in Philadelphia, Pennsylvania, would be charged an annual insurance premium over 30% higher than the same person driving a Buick Park Avenue would pay for the same personal injury and liability coverage. Naturally, we at Good and Associates wish you nothing but the best in terms of avoiding crime, staying healthy, and being accident free. However, we are glad to be here to help you prepare for negative possibilities that might come your way and to help you deal with them if they do.

he insurance business is all about probabilities. Maybe your car will be stolen, maybe it won’t; maybe you’ll be in an accident, maybe you won’t; maybe someone will slip on your steps and sue you; maybe they won’t. Naturally, we hope that nothing bad happens to you or your family, but common sense and historical statistics tell us that it might. All these have probabilities associated with them. For example, if you own a Toyota Camry, there is a much higher probability your car will be stolen than if you drive a Dodge Caravan. As a matter of fact, in recent statistics listing the top ten stolen cars in America, the Toyota Camry was not only in first place; various model years were also in second, third, and eighth place! And the Honda Accord was also pretty popular with thieves— during the same year, different model years of the Accord were in fifth, seventh, ninth, and tenth place on the topten stolen list.

Spades

Ace of spades n(E F) = 1 Aces

E

F

The event that a card drawn is an ace or a spade is E  F, with probability given by P1E  F2  P1E2  P1F2  P1E  F2 4 13 1 16 4      52 52 52 52 13

(Figure 28). This result, of course, can be obtained by arguing that 16 of the 52 cards are either spades or aces of other suits. FIGURE 28

P(E  F )  P(E )  P(F )  P(E  F )

Explore & Discuss Let E, F, and G be any three events of an experiment. Use Formula (5) of Section 7.2 to show that P1E  F  G 2  P1E2  P1F2  P1G2  P1E  F2  P1E  G2  P 1F  G 2  P 1E  F  G 2

If E, F, and G are pairwise mutually exclusive, what is P(E  F  G)?

APPLIED EXAMPLE 3 Quality Control The quality-control department of Vista Vision, manufacturer of the Pulsar 42-inch plasma TV, has determined from records obtained from the company’s service centers that 3% of the sets sold experience video problems, 1% experience audio problems, and 0.1% experience both video and audio problems before the expiration of the 90-day warranty. Find the probability that a plasma TV purchased by a consumer will experience video or audio problems before the warranty expires.

452

7 SETS AND PROBABILITY

P(E

E

P(E) = .03 FIGURE 29

F) = .001

Solution Let E denote the event that a plasma TV purchased will experience video problems within 90 days, and let F denote the event that a plasma TV purchased will experience audio problems within 90 days. Then,

P(E)  .03

F

P(F) = .01

P(F)  .01

P(E  F )  .001

The event that a plasma TV purchased will experience video problems or audio problems before the warranty expires is E  F, and the probability of this event is given by

P(E  F )  P(E)  P(F )  P(E  F )

P1E  F2  P1E2  P1F2  P1E  F2  .03  .01  .001  .039

(Figure 29). Here is another property of a probability function that is of considerable aid in computing the probability of an event.

Property 5. Rule of Complements

If E is an event of an experiment and E c denotes the complement of E, then P(E c)  1  P(E)

Property 5 is an immediate consequence of Properties 2 and 3. Indeed, we have E  E c  S and E  E c  , so 1  P1S2  P 1E  E c 2  P1E2  P1E c 2

and, therefore, P1Ec 2  1  P1E2

APPLIED EXAMPLE 4 Warranties Refer to Example 3. What is the probability that a Pulsar 42-inch plasma TV bought by a consumer will not experience video or audio difficulties before the warranty expires? Solution Let E denote the event that a plasma TV bought by a consumer will experience video or audio difficulties before the warranty expires. Then, the event that the plasma TV will not experience either problem before the warranty expires is given by Ec, with probability

P1Ec 2  1  P1E2  1  .039  .961

Computations Involving the Rules of Probability We close this section by looking at two additional examples that illustrate the rules of probability. EXAMPLE 5 Let E and F be two mutually exclusive events and suppose that P(E)  .1 and P(F)  .6. Compute: a. P(E  F) d. P(E c  F c )

b. P(E  F) e. P(E c  Fc )

c. P(E c )

7.7 RULES OF PROBABILITY

453

Solution

S

E P(E) = .1

a. Since the events E and F are mutually exclusive—that is, E  F  —we have P(E  F)  0. Since E and F are mutually exclusive b. P(E  F)  P(E)  P(F)  .1  .6  .7 Property 5 c. P(Ec )  1  P(E)  1  .1  .9 d. Observe that, by De Morgan’s law, E c  F c  (E  F)c. Hence, P(E c  F c )  P[(E  F)c ]  1  P(E  F)  1  .7  .3

F P(F) = .6

FIGURE 30

See Figure 30. Property 5 Use the result of part (b).

e. Again using De Morgan’s law, we find

P(E c  F c )  P[(E  F )c ]

P(E c  F c )  P[(E  F)c]  1  P(E  F) 10 Use the result of part (a). 1

EXAMPLE 6 Let E and F be two events of an experiment with sample space S. Suppose P(E)  .2, P(F)  .1, and P(E  F)  .05. Compute: a. P(E  F) b. P(E c  F c ) c. P(E c  F)

Hint: Draw a Venn diagram.

Solution

a. P(E  F)  P(E)  P(F)  P(E  F)  .2  .1  .05  .25 b. Using De Morgan’s law, we have P(Ec  F c )  P[(E  F)c]  1  P(E  F)  1  .25  .75 S E

F .15

.05

.05

Property 4

Property 5 Use the result of part (a).

c. From the Venn diagram describing the relationship among E, F, and S (Figure 31), we have P(Ec  F)  .05

The shaded subset is the event Ec  F.

This result may also be obtained by using the relationship P(E) = .2 FIGURE 31

P(F) = .1

P(E c  F ): the probability that the event F, but not the event E, will occur

P(E c  F)  P(F)  P(E  F)  .1  .05  .05

454

7 SETS AND PROBABILITY

7.7 Self-Check Exercises 1. Let E and F be events of an experiment with sample space S. Suppose P(E )  .4, P(F)  .5, and P(E  F)  .1. Compute: a. P(E  F) b. P(E  Fc ) 2. Susan Garcia wishes to sell or lease a condominium through a realty company. The realtor estimates that the probability of finding a buyer within a month of the date

the property is listed for sale or lease is .3, the probability of finding a lessee is .8, and the probability of finding both a buyer and a lessee is .1. Determine the probability that the property will be sold or leased within 1 month from the date the property is listed for sale or lease. Solutions to Self-Check Exercises 7.7 can be found on page 458.

7.7 Concept Questions 1. Suppose S is a sample space of an experiment, E and F are events of the experiment, and P is a probability function. Give the meaning of each of the following statements: a. P(E)  0 b. P(F)  0.5 c. P(S)  1 d. P(E  F )  P(E)  P(F)  P(E  F)

2. Give an example, based on a real-life situation, illustrating the property P(E c )  1  P(E), where E is an event and E c is the complement of E.

7.7 Exercises A pair of dice is rolled, and the number that appears uppermost on each die is observed. In Exercises 1–6, refer to this experiment and find the probability of the given event.

1. The sum of the numbers is an even number. 2. The sum of the numbers is either 7 or 11.

prize? What is the probability that he or she will not win the first prize? 14. TV HOUSEHOLDS The results of a recent television survey of American TV households revealed that 87 out of every 100 TV households have at least one remote control. What is the probability that a randomly selected TV household does not have at least one remote control?

3. A pair of 1s is thrown. 4. A double is thrown.

In Exercises 15–24, explain why the statement is incorrect.

5. One die shows a 6, and the other is a number less than 3.

15. The sample space associated with an experiment is given by S  {a, b, c}, where P(a)  .3, P(b)  .4, and P(c)  .4.

6. The sum of the numbers is at least 4. An experiment consists of selecting a card at random from a 52-card deck. In Exercises 7–12, refer to this experiment and find the probability of the event.

7. A king of diamonds is drawn. 8. A diamond or a king is drawn. 9. A face card (i.e., a jack, queen, or king) is drawn. 10. A red face card is drawn. 11. An ace is not drawn. 12. A black face card is not drawn. 13. Five hundred raffle tickets were sold. What is the probability that a person holding one ticket will win the first

16. The probability that a bus will arrive late at the Civic Center is .35, and the probability that it will be on time or early is .60. 17. A person participates in a weekly office pool in which he has one chance in ten of winning the purse. If he participates for 5 weeks in succession, the probability of winning at least one purse is 105 . 18. The probability that a certain stock will increase in value over a period of 1 week is .6. Therefore, the probability that the stock will decrease in value is .4. 19. A red die and a green die are tossed. The probability that a 6 will appear uppermost on the red die is 61, and the probability that a 1 will appear uppermost on the green die is 1 6 . Hence, the probability that the red die will show a 6 or the green die will show a 1 is 16  16.

7.7 RULES OF PROBABILITY

20. Joanne, a high school senior, has applied for admission to four colleges, A, B, C, and D. She has estimated that the probability that she will be accepted for admission by A, B, C, and D is .5, .3, .1, and .08, respectively. Thus, the probability that she will be accepted for admission by at least one college is P(A)  P(B)  P(C)  P(D)  .5  .3  .1  .08  .98. 21. The sample space associated with an experiment is given by S  {a, b, c, d, e}. The events E  {a, b} and F  {c, d} are mutually exclusive. Hence, the events Ec and Fc are mutually exclusive. 22. A 5-card poker hand is dealt from a 52-card deck. Let A denote the event that a flush is dealt, and let B be the event that a straight is dealt. Then the events A and B are mutually exclusive. 23. RETAIL SALES Mark Owens, an optician, estimates that the probability that a customer coming into his store will purchase one or more pairs of glasses but not contact lenses is .40, and the probability that he will purchase one or more pairs of contact lenses but not glasses is .25. Hence, Owens concludes that the probability that a customer coming into his store will purchase neither a pair of glasses nor a pair of contact lenses is .35. 24. There are eight grades in Garfield Elementary School. If a student is selected at random from the school, then the probability that the student is in the first grade is 18. 25. Let E and F be two events that are mutually exclusive, and suppose P(E )  .2 and P(F)  .5. Compute: a. P(E  F ) b. P(E  F) c. P(Ec ) d. P(Ec  Fc ) 26. Let E and F be two events of an experiment with sample space S. Suppose P(E )  .6, P(F )  .4, and P(E  F)  .2. Compute: a. P(E  F) b. P(Ec ) c. P(Fc ) d. P(Ec  F ) 27. Let S  {s1, s2, s3, s4} be the sample space associated with an experiment having the probability distribution shown in the accompanying table. If A  {s1, s2} and B  {s1, s3}, find a. P(A), P(B) b. P(Ac ), P(Bc ) c. P(A  B) d. P(A  B) Outcome

Probability

s1

1 8

s2

3 8

s3

1 4 1 4

s4

28. Let S  {s1, s2, s3, s4, s5, s6} be the sample space associated with an experiment having the probability distribution shown in the accompanying table. If A  {s1, s2} and B  {s1, s5, s6}, find

455

b. P(Ac), P(Bc ) d. P(A  B) f. P(Ac  Bc )

a. P(A), P(B) c. P(A  B) e. P(Ac  Bc ) Outcome

Probability

s1

1 3

s2

1 8

s3

1 6

s4

1 6

s5

1 12 1 8

s6

29. TEACHER ATTITUDES A nonprofit organization conducted a survey of 2140 metropolitan-area teachers regarding their beliefs about educational problems. The following data were obtained: 900 said that lack of parental support is a problem. 890 said that abused or neglected children are problems. 680 said that malnutrition or students in poor health is a problem. 120 said that lack of parental support and abused or neglected children are problems. 110 said that lack of parental support and malnutrition or poor health are problems. 140 said that abused or neglected children and malnutrition or poor health are problems. 40 said that lack of parental support, abuse or neglect, and malnutrition or poor health are problems. What is the probability that a teacher selected at random from this group said that lack of parental support is the only problem hampering a student’s schooling? Hint: Draw a Venn diagram.

30. INVESTMENTS In a survey of 200 employees of a company regarding their 401(k) investments, the following data were obtained: 141 had investments in stock funds. 91 had investments in bond funds. 60 had investments in money market funds. 47 had investments in stock funds and bond funds. 36 had investments in stock funds and money market funds. 36 had investments in bond funds and money market funds. 22 had investments in stock funds, bond funds, and money market funds. What is the probability that an employee of the company chosen at random a. Had investments in exactly two kinds of investment funds? b. Had investments in exactly one kind of investment fund? c. Had no investment in any of the three types of funds?

456

7 SETS AND PROBABILITY

31. RETAIL SALES The probability that a shopper in a certain boutique will buy a blouse is .35, that she will buy a pair of pants is .30 and that she will buy a skirt is .27. The probability that she will buy both a blouse and a skirt is .15, that she will buy both a skirt and a pair of pants is .19, and that she will buy both a blouse and a pair of pants is .12. Finally, the probability that she will buy all three items is .08. What is the probability that a customer will buy a. Exactly one of these items? b. None of these items? 32. COURSE ENROLLMENTS Among 500 freshmen pursuing a business degree at a university, 320 are enrolled in an economics course, 225 are enrolled in a mathematics course, and 140 are enrolled in both an economics and a mathematics course. What is the probability that a freshman selected at random from this group is enrolled in a. An economics and/or a mathematics course? b. Exactly one of these two courses? c. Neither an economics course nor a mathematics course? 33. CONSUMER SURVEYS A leading manufacturer of kitchen appliances advertised its products in two magazines: Good Housekeeping and the Ladies Home Journal. A survey of 500 customers revealed that 140 learned of its products from Good Housekeeping, 130 learned of its products from the Ladies Home Journal, and 80 learned of its products from both magazines. What is the probability that a person selected at random from this group saw the manufacturer’s advertisement in a. Both magazines? b. At least one of the two magazines? c. Exactly one magazine? 34. ROLLOVER DEATHS The following table gives the number of people killed in rollover crashes in various types of vehicles in 2002: Types of Vehicles Deaths

Cars 4768

Pickups 2742

SUVs 2448

Vans 698

Find the empirical probability distribution associated with these data. If a fatality due to a rollover crash in 2002 is picked at random, what is the probability that the victim was in a. A car? b. An SUV? c. A pickup or an SUV?

What is the probability that a randomly chosen participant in the survey a. Was planning to use an accountant or a tax preparation service to prepare his taxes? b. Was not planning to use computer software to prepare his taxes and was not planning to do his taxes by hand? Source: National Retail Federation

36. WOMEN’S APPAREL In an online survey for Talbots of 1095 women ages 35 yr and older, the participants were asked what article of clothing women most want to fit perfectly. A summary of the results of the survey follows: Article of Clothing Jeans Black Pantsuit Cocktail Dress White Shirt Gown Other

Respondents 470 307 230 22 11 55

If a woman who participated in the survey is chosen at random, what is the probability that she most wants a. Jeans to fit perfectly? b. A black pantsuit or a cocktail dress to fit perfectly? Source: Market Tool’s Zoom Panel

37. SWITCHING JOBS Two hundred workers were asked: Would a better economy lead you to switch jobs? The results of the survey follow:

Answer Respondents

Very likely 40

Somewhat likely 28

Somewhat unlikely 26

Very unlikely 104

Don’t know 2

If a worker is chosen at random, what is the probability that he or she a. Is very unlikely to switch jobs? b. Is somewhat likely or very likely to switch jobs? Source: Accountemps

38. 401(K) INVESTORS According to a study conducted in 2003 concerning the participation, by age, of 401(k) investors, the following data were obtained:

Source: National Highway Traffic Safety Administration

35. TAX PREPARATION A survey in which people were asked how they were planning to prepare their taxes in 2007 revealed the following: Method of Preparation Computer software Accountant Tax preparation service Spouse, friend, or other relative will prepare By hand

Percent 33.9 23.6 17.4 10.8 14.3

Age Percent

20s 11

30s 28

40s 32

50s 22

60s 7

a. What is the probability that a 401(k) investor selected at random is in his or her 20s or 60s? b. What is the probability that a 401(k) investor selected at random is under the age of 50? Source: Investment Company Institute

39. ALTERNATIVE ENERGY SOURCES In a poll conducted among likely voters by Zogby International, voters were asked their opinion on the best alternative to oil and coal. The results are as follows:

7.7 RULES OF PROBABILITY

Fuel Other/ Source Nuclear Wind cells Biofuels Solar no answer Respondents, % 14.2 16.0 3.8 24.3 27.9 13.8

What is the probability that a randomly selected participant in the poll mentioned a. Wind or solar energy sources as the best alternative to oil and coal? b. Nuclear or biofuels as the best alternative to oil and coal? Source: Zogby International

40. ELECTRICITY GENERATION Electricity in the United States is generated from many sources. The following table gives the sources as well as their share in the production of electricity: Source Coal Nuclear Natural gas Hydropower Oil Other Share, % 50.0 19.3 18.7 6.7 3.0 2.3

If a source for generating electricity is picked at random, what is the probability that it comes from a. Coal or natural gas? b. Nonnuclear sources? Source: Energy Information Administration

41. DOWNLOADING MUSIC The following table, compiled in 2004, gives the percentage of music downloaded from the United States and other countries by U.S. users: Country

U.S.

Germany

Canada

Italy

U.K.

France

Japan

Other

Percent

45.1

16.5

6.9

6.1

4.2

3.8

2.5

14.9

a. Verify that the table does give a probability distribution for the experiment. b. What is the probability that a user who downloads music, selected at random, obtained it from either the United States or Canada? c. What is the probability that a U.S. user who downloads music, selected at random, does not obtain it from Italy, the United Kingdom (U.K.), or France? Source: Felix Oberholtzer-Gee and Koleman Strumpf

42. PLANS TO KEEP CARS In a survey conducted to see how long Americans keep their cars, 2000 automobile owners were asked how long they plan to keep their present cars. The results of the survey follow: Years Car Is Kept, x 0 x 1

Respondents 60

1 x 3 3 x 5 5 x 7 7 x 10 10 x

440 360 340 240 560

457

Find the probability distribution associated with these data. What is the probability that an automobile owner selected at random from those surveyed plans to keep his or her present car a. Less than 5 yr? b. 3 yr or more? 43. ASSEMBLY-TIME STUDIES A time study was conducted by the production manager of Universal Instruments to determine how much time it took an assembly worker to complete a certain task during the assembly of its Galaxy home computers. Results of the study indicated that 20% of the workers were able to complete the task in less than 3 min, 60% of the workers were able to complete the task in 4 min or less, and 10% of the workers required more than 5 min to complete the task. If an assembly-line worker is selected at random from this group, what is the probability that a. He or she will be able to complete the task in 5 min or less? b. He or she will not be able to complete the task within 4 min? c. The time taken for the worker to complete the task will be between 3 and 4 min (inclusive)? 44. DISTRACTED DRIVING According to a study of 100 drivers in metropolitan Washington, D.C., whose cars were equipped with cameras with sensors, the distractions and the number of incidents (crashes, near crashes, and situations that require an evasive maneuver after the driver was distracted) caused by these distractions are as follows: Distraction A B C D E Driving Incidents 668 378 194 163 133

F G H I 134 111 111 89

where A  Wireless device (cell phone, PDA) B  Passenger C  Something inside car D  Vehicle E  Personal hygiene F  Eating G  Something outside car H  Talking/singing I  Other If an incident caused by a distraction is picked at random, what is the probability that it was caused by a. The use of a wireless device? b. Something other than personal hygiene or eating? Source: Virginia Tech Transportation Institute and NHTSA

45. GUN-CONTROL LAWS A poll was conducted among 250 residents of a certain city regarding tougher gun-control laws. The results of the poll are shown in the table:

458

7 SETS AND PROBABILITY

Favor Tougher Laws Oppose Tougher Laws No Opinion Total

Own Only a Handgun

Own Only a Rifle

Own a Handgun and a Rifle

0

12

0

138

150

58

5

25

0

88

0 58

0 17

0 25

12 150

12 250

Own Neither Total

If one of the participants in this poll is selected at random, what is the probability that he or she a. Favors tougher gun-control laws? b. Owns a handgun? c. Owns a handgun but not a rifle? d. Favors tougher gun-control laws and does not own a handgun? 46. RISK OF AN AIRPLANE CRASH According to a study of Western-built commercial jets involved in crashes from 1988 to 1998, the percentage of airplane crashes that occur at each stage of flight are as follows: Phase On ground, taxiing During takeoff Climbing to cruise altitude En route Descent and approach Landing

Percent 4 10 19 5 31 31

If one of the doomed flights in the period 1988–1998 is picked at random, what is the probability that it crashed

a. While taxiing on the ground or while en route? b. During takeoff or landing? If the study is indicative of airplane crashes in general, when is the risk of a plane crash the highest? Source: National Transportation Safety Board

47. Suppose the probability that Bill can solve a problem is p1 and the probability that Mike can solve it is p2. Show that the probability that Bill and Mike working independently can solve the problem is p1  p2  p1p2. 48. Fifty raffle tickets are numbered 1 through 50, and one of them is drawn at random. What is the probability that the number is a multiple of 5 or 7? Consider the following “solution”: Since 10 tickets bear numbers that are multiples of 5 and since 7 tickets bear numbers that are multiples of 7, we conclude that the required probability is 10 7 17   50 50 50

What is wrong with this argument? What is the correct answer? In Exercises 49–52, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

49. If A is a subset of B and P(B)  0, then P(A)  0. 50. If A is a subset of B, then P(A) P(B). 51. If E1, E2, . . . , En are events of an experiment, then P(E1  E2  . . .  En)  P(E1)  P(E2)  . . .  P(En). 52. If E is an event of an experiment, then P(E)  P(E c )  1.

7.7 Solutions to Self-Check Exercises 1. a. Using Property 4, we find

The result may also be obtained by using the relationship

P1E  F2  P1E2  P1F2  P1E  F2

P1E  Fc 2  P 1E2  P1E  F2

 .4  .5  .1

 .4  .1  .3

 .8

b. From the accompanying Venn diagram, in which the subset E  Fc is shaded, we see that P(E  Fc )  .3

P(E)  .3 S

E

F .3

.1

.4

2. Let E denote the event that the realtor will find a buyer within 1 month of the date it is listed for sale or lease and let F denote the event that the realtor will find a lessee within the same time period. Then, P(F)  .8

P(E  F)  .1

The probability of the event that the realtor will find a buyer or a lessee within 1 month of the date it is listed for sale or lease is given by P1E  F2  P1E2  P1F2  P1E  F2  .3  .8  .1  1

—that is, a certainty.

SUMMARY OF PRINCIPAL FORMULAS AND TERMS

CHAPTER 7 Summary of Principal Formulas and Terms FORMULAS 1. Commutative laws

ABBA ABBA

2. Associative laws

A  (B  C)  (A  B)  C A  (B  C)  (A  B)  C

3. Distributive laws

A  (B  C)  (A  B)  (A  C) A  (B  C)  (A  B)  (A  C)

4. De Morgan’s laws

(A  B)c  Ac  Bc (A  B)c  Ac  Bc

5. Number of elements in the union of two finite sets

n(A  B)  n(A)  n(B)  n(A  B)

6. Permutation of n distinct objects, taken r at a time

P(n, r) 

7. Permutation of n objects, not all distinct, taken n at a time

n! n1!n2! . . . nm!

8. Combination of n distinct objects, taken r at a time

C(n, r) 

9. Probability of an event in a uniform sample space

P(E) 

n! 1n  r 2!

n! r!1n  r 2!

n1E2 n1S 2

10. Probability of the union of two mutually exclusive events

P(E  F)  P(E)  P(F )

11. Addition rule

P(E  F)  P(E)  P(F)  P(E  F)

12. Rule of complements

P(E c)  1  P(E)

TERMS set (396)

set complementation (399)

union of two events (432)

element of a set (396)

multiplication principle (411)

intersection of two events (432)

roster notation (396)

generalized multiplication principle (413)

complement of an event (432)

set-builder notation (396)

permutation (417)

mutually exclusive events (433)

set equality (396)

n-factorial (419)

relative frequency (440)

subset (397)

combination (422)

empirical probability (440)

empty set (397)

experiment (431)

probability of an event (440)

universal set (398)

outcome (431)

elementary (simple) event (440)

Venn diagram (398)

sample point (431)

probability distribution (440)

set union (399)

sample space (431)

probability function (440)

set intersection (399)

event (431)

uniform sample space (441)

disjoint set (399)

finite sample space (431)

addition principle (442)

459

460

7 SETS AND PROBABILITY

CHAPTER 7 Concept Review Questions Fill in the blanks.

1. A well-defined collection of objects is called a/an ______. These objects are also called ______ of the ______. 2. Two sets having exactly the same elements are said to be ______. 3. If every element of a set A is also an element of a set B, then A is a/an ______ of B. 4. a. The empty set  is the set containing ______ elements. b. The universal set is the set containing ______ elements. 5. a. The set of all elements in A and/or B is called the ______ of A and B. b. The set of all elements in A and B is called the ______ of A and B. 6. The set of all elements in U that are not in A is called the ______ of A.

7. Applying De Morgan’s law, we can write (A  B  C)c  ______. 8. An arrangement of a set of distinct objects in a definite order is called a/an ______; an arrangement in which the order is not important is a/an ______. 9. An activity with observable results is called a/an ______; an outcome of an experiment is called a ______ point, and the set consisting of all possible sample points of an experiment is called a sample ______; a subset of a sample space of an experiment is called a/an ______. 10. The events E and F are mutually exclusive if E  F  ______. 11. A sample space in which the outcomes are equally likely is called a/an ______ sample space; if such a space contains n simple events, then the probability of each simple event is ______.

CHAPTER 7 Review Exercises In Exercises 1–4, list the elements of each set in roster notation.

1. {x  3x  2  7; x, an integer} 2. {x  x is a letter of the word TALLAHASSEE}

11. Ac  Bc  Cc

12. Ac  (Bc  Cc)

Let U  {a, b, c, d, e}, A  {a, b}, B  {b, c, d}, and C  {a, d, e}. In Exercises 13–16, verify the equation by direct computation.

3. The set whose elements are the even numbers between 3 and 11

13. A  (B  C )  (A  B)  C

4. {x  (x  3)(x  4)  0; x, a negative integer}

15. A  (B  C)  (A  B)  (A  C )

Let A  {a, c, e, r }. In Exercises 5–8, determine whether the set is equal to A.

6. {x  x is a letter of the word career}

A  {consumers who avoided buying a product because it is not recyclable}

7. {x  x is a letter of the word racer} 8. {x  x is a letter of the word cares} In Exercises 9–12, shade the portion of the accompanying figure that represents the set. U B C

9. A  (B  C )

16. A  (B  C)  (A  B)  (A  C ) Let U  {all participants in a consumer-behavior survey conducted by a national polling group}

5. {r, e, c, a}

A

14. A  (B  C)  (A  B)  C

10. (A  B  C)c

B  {consumers who used cloth rather than disposable diapers} C  {consumers who boycotted a company’s products because of their record on the environment} D  {consumers who voluntarily recycled their garbage} In Exercises 17–20, describe each set in words.

17. A  C

18. A  D

19. Bc  D

20. Cc  Dc

REVIEW EXERCISES

Let A and B be subsets of a universal set U and suppose n(U)  350, n(A)  120, n(B)  80, and n(A  B)  50. In Exercises 21–26, find the number of elements in each set.

21. n(A  B)

22. n(Ac)

23. n(Bc)

24. n(Ac  B)

25. n(A  Bc)

26. n(Ac  B c)

In Exercises 27–30, evaluate each quantity.

27. C(20, 18)

28. P(9, 7)

29. C(5, 3)  P(4, 2)

30. 4  P(5, 3)  C(7, 4)

31. Let E and F be two mutually exclusive events and suppose P(E)  .4 and P(F )  .2. Compute a. P(E  F) b. P(E  F ) c. P(E c) d. P(E c  F c) e. P(E c  F c) 32. Let E and F be two events of an experiment with sample space S. Suppose P(E)  .3, P(F)  .2, and P(E  F)  .15. Compute a. P(E  F ) b. P(E c  F c) c. P(E c  F) 33. A die is loaded, and it was determined that the probability distribution associated with the experiment of casting the die and observing which number falls uppermost is given by Simple Event {1} {2} {3} {4} {5} {6}

Probability .20 .12 .16 .18 .15 .19

a. What is the probability of the number being even? b. What is the probability of the number being either a 1 or a 6? c. What is the probability of the number being less than 4? 34. An urn contains six red, five black, and four green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? 35. CREDIT CARD COMPARISONS A comparison of five major credit cards showed that 3 offered cash advances. 3 offered extended payments for all goods and services purchased. 2 required an annual fee of less than $35. 2 offered both cash advances and extended payments.

461

1 offered extended payments and had an annual fee less than $35. No card had an annual fee less than $35 and offered both cash advances and extended payments. How many cards had an annual fee less than $35 and offered cash advances? (Assume that every card had at least one of the three mentioned features.) 36. STUDENT SURVEYS The Department of Foreign Languages of a liberal arts college conducted a survey of its recent graduates to determine the foreign language courses they had taken while undergraduates at the college. Of the 480 graduates 200 had at least 1 yr of Spanish. 178 had at least 1 yr of French. 140 had at least 1 yr of German. 33 had at least 1 yr of Spanish and French. 24 had at least 1 yr of Spanish and German. 18 had at least 1 yr of French and German. 3 had at least 1 yr of all three languages. How many of the graduates had a. At least 1 yr of at least one of the three languages? b. At least 1 yr of exactly one of the three languages? c. Less than 1 yr of any of the three languages? 37. In how many ways can six different compact discs be arranged on a shelf? 38. In how many ways can three pictures be selected from a group of six different pictures? 39. Find the number of distinguishable permutations that can be formed from the letters of each word. a. CINCINNATI b. HONOLULU 40. How many three-digit numbers can be formed from the numerals in the set {1, 2, 3, 4, 5} if a. Repetition of digits is not allowed? b. Repetition of digits is allowed? 41. INVESTMENTS In a survey conducted by Helena, a financial consultant, it was revealed that of her 400 clients 300 own stocks. 180 own bonds. 160 own mutual funds. 110 own both stocks and bonds. 120 own both stocks and mutual funds. 90 own both bonds and mutual funds. How many of Helena’s clients own stocks, bonds, and mutual funds? 42. POKER From a standard 52-card deck, how many 5-card poker hands can be dealt consisting of a. Five clubs? b. Three kings and one pair?

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7 SETS AND PROBABILITY

43. ELECTIONS In an election being held by the Associated Students Organization, there are six candidates for president, four for vice-president, five for secretary, and six for treasurer. How many different possible outcomes are there for this election? 44. TEAM SELECTION There are eight seniors and six juniors in the Math Club at Jefferson High School. In how many ways can a math team consisting of four seniors and two juniors be selected from the members of the Math Club? 45. SEATING ARRANGEMENTS In how many ways can seven students be assigned seats in a row containing seven desks if a. There are no restrictions? b. Two of the students must not be seated next to each other? 46. QUALITY CONTROL From a shipment of 60 transistors, 5 of which are defective, a sample of 4 transistors is selected at random.

a. In how many different ways can the sample be selected? b. How many samples contain 3 defective transistors? c. How many samples do not contain any defective transistors? 47. RANDOM SAMPLES A sample of 4 balls is to be selected at random from an urn containing 15 balls numbered 1 to 15. If 6 balls are green, 5 are white, and 4 are black a. How many different samples can be selected? b. How many samples can be selected that contain at least 1 white ball? 48. QUALITY CONTROL The quality-control department of Starr Communications, the manufacturer of video-game cartridges, has determined from records that 1.5% of the cartridges sold have video defects, 0.8% have audio defects, and 0.4% have both audio and video defects. What is the probability that a cartridge purchased by a customer a. Will have a video or audio defect? b. Will not have a video or audio defect?

CHAPTER 7 Before Moving On . . . 1. Let U  {a, b, c, d, e, f, t}, A  {a, d, f, t}, B  {d, f, t}, and C  {b, c, e, f }. Find a. A  (B  C) b. (A  C)  (B  C) c. Ac 2. In how many ways can four compact discs be selected from six different compact discs? 3. There are six seniors and five juniors in the Chess Club at Madison High School. In how many ways can a team consisting of three seniors and two juniors be selected from the members of the Chess Club?

4. Let S  {s1, s2, s3, s4, s5, s6} be the sample space associated with an experiment having the following probability distribution: Outcome

s1

s2

s3

s4

s5

s6

Probability

1 12

2 12

3 12

2 12

3 12

1 12

Find the probability of the event A  {s1, s3, s6}. 5. A card is drawn from a well-shuffled 52-card deck. What is the probability that the card drawn is a deuce or a face card? 6. Let E and F be events of an experiment with sample space S. Suppose P(E)  .5, P(F)  .6, and P(E  F)  .2. Compute: a. P(E  F) b. P(E  Fc)

8

ADDITIONAL TOPICS IN PROBABILITY

I

N THIS CHAPTER, we develop additional techniques for computing the probabilities of certain events, and we take a

look at descriptive statistics. We begin by looking at problems involving large sample spaces. In Section 8.2, we consider the

of an event occurring, and in Section 8.3 we learn how to compute the probabilities of certain events after the occurrence of an event. Throughout our discussion, we will see how these techniques are applied to many practical problems in fields as diverse as quality control and medical research. In the rest of the chapter, we take a glimpse at statistics, the branch of mathematics concerned with the collection, analysis, and interpretation of data.

© Thorsten Henn/Getty Images

effect that the occurrence of prior events has on the probability

What is the probability that a randomly chosen couple from a certain large metropolitan area is in the upper-income bracket if both spouses are working? In Example 2, page 487, we show how the income distribution for that metropolitan area can be used to determine this probability.

464

8 ADDITIONAL TOPICS IN PROBABILITY

8.1 Use of Counting Techniques in Probability Further Applications of Counting Techniques As we have seen many times before, a problem in which the underlying sample space has a small number of elements may be solved by first determining all such sample points. However, for problems involving sample spaces with a large number of sample points, this approach is neither practical nor desirable. In this section, we see how the counting techniques studied in Chapter 7 may be employed to help us solve problems in which the associated sample spaces contain large numbers of sample points. In particular, we restrict our attention to the study of uniform sample spaces—that is, sample spaces in which the outcomes are equally likely. For such spaces we have the following result.

Computing the Probability of an Event in a Uniform Sample Space

Let S be a uniform sample space and let E be any event. Then P1E2 

n1E2 Number of outcomes in E  Number of outcomes in S n1S2

(1)

EXAMPLE 1 An unbiased coin is tossed six times. What is the probability that the coin will land heads a. Exactly three times? b. At most three times? c. On the first and the last toss? Solution

a. Each outcome of the experiment may be represented as a sequence of heads and tails. Using the generalized multiplication principle, we see that the number of outcomes of this experiment is given by 26, or 64. Let E denote the event that the coin lands heads exactly three times. Since there are C(6, 3) ways this can occur, we see that the required probability is

P1E2 

n1E2

C16, 32

6! 3! 3!  64

S is a sample space of  the experiment. n1S2 64 6#5#4 3#2 20 5     .3125 64 64 16

b. Let F denote the event that the coin lands heads at most three times. Then n(F ) is given by the sum of the number of ways the coin lands heads zero times (no heads!), the number of ways it lands heads exactly once, the number of ways it lands heads exactly twice, and the number of ways it lands heads exactly three times. That is, n1F 2  C16, 02  C16, 12  C16, 22  C16, 32 6! 6! 6! 6!     0! 6! 1! 5! 2! 4! 3! 3! 6#5 6#5#4 16   42 2 3#2

8.1 USE OF COUNTING TECHNIQUES IN PROBABILITY

465

Therefore, the required probability is P1F2 

n1F2 n1S2



42 21   .6563 64 32

c. Let F denote the event that the coin lands heads on the first and the last toss. Then n(F )  1  2  2  2  2  1  24, so the probability that this event occurs is 24 26 1  2 2 1  4

P1F2 

EXAMPLE 2 Two cards are selected at random (without replacement) from a well-shuffled deck of 52 playing cards. What is the probability that a. They are both aces?

b. Neither of them is an ace?

Solution

a. The experiment consists of selecting 2 cards from a pack of 52 playing cards. Since the order in which the cards are selected is immaterial, the sample points are combinations of 52 cards taken 2 at a time. Now there are C(52, 2) ways of selecting 52 cards taken 2 at a time, so the number of elements in the sample space S is given by C(52, 2). Next, we observe that there are C(4, 2) ways of selecting 2 aces from the 4 in the deck. Therefore, if E denotes the event that the cards selected are both aces, then n1E2 P1E2  n1S2 4! C14, 22 2! 2 4#3# 2    C152, 22 52! 2 52 # 51 2! 50! 1   .0045 221 b. Let F denote the event that neither of the two cards selected is an ace. Since there are C(48, 2) ways of selecting two cards neither of which is an ace, we find that 48! 2! 46! 48 # 47 # 2 P1F2     n1S2 C152, 22 52! 2 52 # 51 2! 50! 188   .8507 221 n1F2

C148, 22

APPLIED EXAMPLE 3 Quality Control A bin in the hi-fi department of Building 20, a bargain outlet, contains 100 blank cassette tapes, of which 10 are known to be defective. If a customer selects 6 of these cassette tapes at random, determine the probability a. That 2 of them are defective. b. That at least 1 of them is defective.

466

8 ADDITIONAL TOPICS IN PROBABILITY

8 defective tapes Sample 2 4

86 nondefective tapes

FIGURE 1 A sample of 6 tapes selected from 90 nondefective tapes and 10 defective tapes

Solution

a. There are C(100, 6) ways of selecting a set of 6 cassette tapes from the 100, and this gives n(S ), the number of outcomes in the sample space associated with the experiment. Next, we observe that there are C(10, 2) ways of selecting a set of 2 defective cassette tapes from the 10 defective cassette tapes and C(90, 4) ways of selecting a set of 4 nondefective cassette tapes from the 90 nondefective cassette tapes (Figure 1). Thus, by the multiplication principle, there are C(10, 2)  C(90, 4) ways of selecting 2 defective and 4 nondefective cassette tapes. Therefore, the probability of selecting 6 cassette tapes of which 2 are defective is given by C110, 2 2 # C190, 42 C1100, 62

10! 90! 2! 8! 4! 86!  100! 6! 94! 10 # 9 # 90 # 89 # 88 # 87 # 6#5#4#3#2  2 4#3#2 100 # 99 # 98 # 97 # 96 # 95  .096

b. Let E denote the event that none of the cassette tapes selected is defective. Then E c gives the event that at least 1 of the cassette tapes is defective. By the rule of complements, P(E c )  1  P(E)

To compute P(E), we observe that there are C(90, 6) ways of selecting a set of 6 cassette tapes that are nondefective. Therefore, P1E2 

C190, 62 C1100, 62

P1Ec 2  1 

C190, 62 C1100, 62

90! 6! 84! 1 100! 6! 94! 1

90 # 89 # 88 # 87 # 86 # 85 # 6#5#4#3#2 # # # # # 6 5 4 3 2 100 99 # 98 # 97 # 96 # 95

 .478

The Birthday Problem APPLIED EXAMPLE 4 The Birthday Problem A group of five people is selected at random. What is the probability that at least two of them have the same birthday? For simplicity, we assume that none of the five people was born on February 29 of a leap year. Since the five people were selected at random, we also assume that each of them is equally likely to have any of the 365 days of a year as his or her birthday. If we let A, B, C, D, and F represent the five people, then an outcome of the experiment may be represented by (a, b, c, d, f ), Solution

8.1 USE OF COUNTING TECHNIQUES IN PROBABILITY

467

where the dates a, b, c, d, and f give the birthdays of A, B, C, D, and F, respectively. We first observe that since there are 365 possibilities for each of the dates a, b, c, d, and f, the multiplication principle implies that there are 365





365

a

365

b



365

c

d



365 f

5

or 365 outcomes of the experiment. Therefore, n(S)  3655

where S denotes the sample space of the experiment. Next, let E denote the event that two or more of the five people have the same birthday. It is now necessary to compute P(E). However, a direct computation of P(E) is relatively difficult. It is much easier to compute P(Ec ), where Ec is the event that no two of the five people have the same birthday, and then use the relation P(E)  1  P(E c )

To compute P(Ec ), observe that there are 365 ways (corresponding to the 365 dates) on which A’s birthday can occur, followed by 364 ways on which B’s birthday could occur if B were not to have the same birthday as A, and so on. Therefore, by the generalized multiplication principle, n(E c ) 

365 A’s birthday



364 B’s birthday



363 C’s birthday



362 D’s birthday



361 F’s birthday

Thus, P1Ec 2 

n1Ec 2

n1S2 365 # 364 # 363 # 362 # 361  3655 P1E2  1  P1Ec 2 365 # 364 # 363 # 362 # 361 1 3655  .027

TABLE 1 Probability That at Least Two People in a Randomly Selected Group of r People Have the Same Birthday

r

P(E)

5 10 15 20 22 23 25 30 40 50

.027 .117 .253 .411 .476 .507 .569 .706 .891 .970

We can extend the result obtained in Example 4 to the general case involving r people. In fact, if E denotes the event that at least two of the r people have the same birthday, an argument similar to that used in Example 4 leads to the result P1E2  1 

365 # 364 # 363 # p # 1365  r  12 365r

By letting r take on the values 5, 10, 15, 20, . . . , 50, in turn, we obtain the probabilities that at least 2 of 5, 10, 15, 20, . . . , 50 people, respectively, have the same birthday. These results are summarized in Table 1. The results show that, in a group of 23 randomly selected people, the chances are greater than 50% that at least 2 of them will have the same birthday. In a group of 50 people, it is an excellent bet that at least 2 people in the group will have the same birthday.

468

8 ADDITIONAL TOPICS IN PROBABILITY

Explore & Discuss During an episode of the Tonight Show, a talk show host related “The Birthday Problem” to the audience—noting that, in a group of 50 or more people, probabilists have calculated that the probability of at least 2 people having the same birthday is very high. To illustrate this point, he proceeded to conduct his own experiment. A person selected at random from the audience was asked to state his birthday. The host then asked if anyone in the audience had the same birthday. The response was negative. He repeated the experiment. Once again, the response was negative. These results, observed the host, were contrary to expectations. In a later episode of the show, the host explained why this experiment had been improperly conducted. Explain why the host failed to illustrate the point he was trying to make in the earlier episode.

8.1 Self-Check Exercises 1. Four balls are selected at random without replacement from an urn containing 10 white balls and 8 red balls. What is the probability that all the chosen balls are white?

2. A box contains 20 microchips, of which 4 are substandard. If 2 of the chips are taken from the box, what is the probability that they are both substandard? Solutions to Self-Check Exercises 8.1 can be found on page 470.

8.1 Concept Questions 1. What is the probability of an event E in a uniform sample space S? 2. Suppose we want to find the probability that at least two people in a group of six randomly selected people have the same birthday.

a. If S denotes the sample space of this experiment, what is n(S)? b. If E is the event that two or more of the six people in the group have the same birthday, explain how you would use P(E c) to determine P(E).

8.1 Exercises An unbiased coin is tossed five times. In Exercises 1–4, find the probability of the given event.

1. The coin lands heads all five times. 2. The coin lands heads exactly once. 3. The coin lands heads at least once. 4. The coin lands heads more than once. Two cards are selected at random without replacement from a well-shuffled deck of 52 playing cards. In Exercises 5–8, find the probability of the given event.

Four balls are selected at random without replacement from an urn containing three white balls and five blue balls. In Exercises 9–12, find the probability of the given event.

9. Two of the balls are white and two are blue. 10. All of the balls are blue. 11. Exactly three of the balls are blue. 12. Two or three of the balls are white.

6. A pair is not drawn.

Assume that the probability of a boy being born is the same as the probability of a girl being born. In Exercises 13–16, find the probability that a family with three children will have the given composition.

7. Two black cards are drawn.

13. Two boys and one girl

8. Two cards of the same suit are drawn.

14. At least one girl

5. A pair is drawn.

8.1 USE OF COUNTING TECHNIQUES IN PROBABILITY

15. No girls 16. The two oldest children are girls. 17. An exam consists of ten true-or-false questions. If a student guesses at every answer, what is the probability that he or she will answer exactly six questions correctly? 18. PERSONNEL SELECTION Jacobs & Johnson, an accounting firm, employs 14 accountants, of whom 8 are CPAs. If a delegation of 3 accountants is randomly selected from the firm to attend a conference, what is the probability that 3 CPAs will be selected? 19. QUALITY CONTROL Two light bulbs are selected at random from a lot of 24, of which 4 are defective. What is the probability that a. Both of the light bulbs are defective? b. At least 1 of the light bulbs is defective? 20. A customer at Cavallaro’s Fruit Stand picks a sample of 3 oranges at random from a crate containing 60 oranges, of which 4 are rotten. What is the probability that the sample contains 1 or more rotten oranges? 21. QUALITY CONTROL A shelf in the Metro Department Store contains 80 colored ink cartridges for a popular ink-jet printer. Six of the cartridges are defective. If a customer selects 2 cartridges at random from the shelf, what is the probability that a. Both are defective? b. At least 1 is defective? 22. QUALITY CONTROL Electronic baseball games manufactured by Tempco Electronics are shipped in lots of 24. Before shipping, a quality-control inspector randomly selects a sample of 8 from each lot for testing. If the sample contains any defective games, the entire lot is rejected. What is the probability that a lot containing exactly 2 defective games will still be shipped? 23. PERSONNEL SELECTION The City Transit Authority plans to hire 12 new bus drivers. From a group of 100 qualified applicants, of whom 60 are men and 40 are women, 12 names are to be selected by lot. Suppose that Mary and John Lewis are among the 100 qualified applicants. a. What is the probability that Mary’s name will be selected? That both Mary’s and John’s names will be selected? b. If it is stipulated that an equal number of men and women are to be selected (6 men from the group of 60 men and 6 women from the group of 40 women), what is the probability that Mary’s name will be selected? That Mary’s and John’s names will be selected? 24. PUBLIC HOUSING The City Housing Authority has received 50 applications from qualified applicants for eight lowincome apartments. Three of the apartments are on the north side of town, and five are on the south side. If the apartments are to be assigned by means of a lottery, what is the probability that

469

a. A specific qualified applicant will be selected for one of these apartments? b. Two specific qualified applicants will be selected for apartments on the same side of town? 25. A student studying for a vocabulary test knows the meanings of 12 words from a list of 20 words. If the test contains 10 words from the study list, what is the probability that at least 8 of the words on the test are words that the student knows? 26. DRIVING TESTS Four different written driving tests are administered by the Motor Vehicle Department. One of these four tests is selected at random for each applicant for a driver’s license. If a group consisting of two women and three men apply for a license, what is the probability that a. Exactly two of the five will take the same test? b. The two women will take the same test? 27. BRAND SELECTION A druggist wishes to select three brands of aspirin to sell in his store. He has five major brands to choose from: A, B, C, D, and E. If he selects the three brands at random, what is the probability that he will select a. Brand B? b. Brands B and C? c. At least one of the two brands B and C? 28. BLACKJACK In the game of blackjack, a 2-card hand consisting of an ace and a face card or a 10 is called a blackjack. a. If a player is dealt 2 cards from a standard deck of 52 well-shuffled cards, what is the probability that the player will receive a blackjack? b. If a player is dealt 2 cards from 2 well-shuffled standard decks, what is the probability that the player will receive a blackjack? 29. SLOT MACHINES Refer to Exercise 25, Section 7.3, where the “lucky dollar” slot machine was described. What is the probability that the three “lucky dollar” symbols will appear in the window of the slot machine? 30. ROULETTE In 1959 a world record was set for the longest run on an ungaffed (fair) roulette wheel at the El San Juan Hotel in Puerto Rico. The number 10 appeared six times in a row. What is the probability of the occurrence of this event? (Assume that there are 38 equally likely outcomes consisting of the numbers 1–36, 0, and 00.) In “The Numbers Game,” a state lottery, four numbers are drawn with replacement from an urn containing balls numbered 0–9, inclusive. In Exercises 31–34, find the probability that a ticket holder has the indicated winning ticket.

31. All four digits in exact order (the grand prize) 32. Two specified, consecutive digits in exact order (the first two digits, the middle two digits, or the last two digits) 33. One digit (the first, second, third, or fourth digit) 34. Three digits in exact order

470

8 ADDITIONAL TOPICS IN PROBABILITY

A list of poker hands, ranked in order from the highest to the lowest, is shown in the accompanying table along with a description and example of each hand. Use the table to answer Exercises 35–40.

Hand

Description

Example

Straight flush

5 cards in sequence in the same suit

A

Four of a kind

4 cards of the same rank and any other card

K

Full house

3 of a kind and a pair

3

3

3

7

7

Flush

5 cards of the same suit that are not all in sequence

5

6

9

J

K

Straight

5 cards in sequence but not all of the same suit

10

J

Q

K

A

Three of a kind

3 cards of the same rank and 2 unmatched cards

K

K

K

2

4

Two pair

2 cards of the same rank and 2 cards of any other rank with an unmatched card

K

One pair

2 cards of the same rank and 3 unmatched cards

K

2

3

4

5

If a 5-card poker hand is dealt from a well-shuffled deck of 52 cards, what is the probability of being dealt the given hand?

35. A straight flush (Note that an ace may be played as either a high or low card in a straight sequence—that is, A, 2, 3, 4, 5 or 10, J, Q, K, A. Hence, there are ten possible sequences for a straight in one suit.) 36. A straight (but not a straight flush)

K

K

K

2

37. A flush (but not a straight flush) 38. Four of a kind 39. A full house

K

2

2

40. Two pairs

4

41. ZODIAC SIGNS There are 12 signs of the Zodiac: Aries, Taurus, Gemini, Cancer, Leo, Virgo, Libra, Scorpio, Sagittarius, Capricorn, Aquarius, and Pisces. Each sign corresponds to a different calendar period of approximately 1 month. Assuming that a person is just as likely to be born under one sign as another, what is the probability that in a group of five people at least two of them a. Have the same sign? b. Were born under the sign of Aries? 42. BIRTHDAY PROBLEM What is the probability that at least two of the nine justices of the U.S. Supreme Court have the same birthday? 43. BIRTHDAY PROBLEM Fifty people are selected at random. What is the probability that none of the people in this group have the same birthday?

K

5

2

4

44. BIRTHDAY PROBLEM There were 42 different presidents of the United States from 1789 through 2000. What is the probability that at least two of them had the same birthday? Compare your calculation with the facts by checking an almanac or some other source.

8.1 Solutions to Self-Check Exercises 1. The probability that all 4 balls selected are white is given by The number of ways of selecting 4 white balls from the 10 in the urn The number of ways of selecting any 4 balls from the 18 balls in the urn 

C110, 4 2

C118, 4 2

10! 4! 6!  18! 4! 14!

10 # 9 # 8 # 7 4#3#2 #  4#3#2 18 # 17 # 16 # 15  .069

2. The probability that both chips are substandard is given by The number of ways of choosing any 2 of the 4 substandard chips The number of ways of choosing any 2 of the 20 chips 

C14, 22 C120, 22

4! 2! 2!  20! 2! 18! 

4#3 # 2 2 20 # 19

 .032

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

471

8.2 Conditional Probability and Independent Events Conditional Probability Suppose that three cities, A, B, and C, are vying to play host to the Summer Olympic Games in 2016. If each city has the same chance of winning the right to host the Games, then the probability of city A hosting the Games is 31. Now suppose city B decides to pull out of contention because of fiscal problems. Then it would seem that city A’s chances of playing host will increase. In fact, if each of the two remaining cities have equal chances of winning, then the probability of city A playing host to the Games is 12. In general, the probability of an event is affected by the occurrence of other events and/or by the knowledge of information relevant to the event. Basically, the injection of conditions into a problem modifies the underlying sample space of the original problem. This in turn leads to a change in the probability of the event. EXAMPLE 1 Two cards are drawn without replacement from a well-shuffled deck of 52 playing cards. a. What is the probability that the first card drawn is an ace? b. What is the probability that the second card drawn is an ace given that the first card drawn was not an ace? c. What is the probability that the second card drawn is an ace given that the first card drawn was an ace? Solution

a. The sample space here consists of 52 equally likely outcomes, 4 of which are aces. Therefore, the probability that the first card drawn is an ace is 524 , or 131 . b. Having drawn the first card, there are 51 cards left in the deck. In other words, for the second phase of the experiment, we are working in a reduced sample space. If the first card drawn was not an ace, then this modified sample space of 51 points contains 4 “favorable” outcomes (the 4 aces), so the probability that the second card drawn is an ace is given by 514 . c. If the first card drawn was an ace, then there are 3 aces left in the deck of 51 playing cards, so the probability that the second card drawn is an ace is given by 513 , or 171 . Observe that in Example 1 the occurrence of the first event reduces the size of the original sample space. The information concerning the first card drawn also leads us to the consideration of modified sample spaces: In part (b) the deck contained 4 aces, and in part (c) the deck contained 3 aces. The probability found in part (b) or part (c) of Example 1 is known as a conditional probability, since it is the probability of an event occurring given that another event has already occurred. For example, in part (b) we computed the probability of the event that the second card drawn is an ace given that the first card drawn was not an ace. In general, given two events A and B of an experiment, under certain circumstances one may compute the probability of the event B given that the event A has already occurred. This probability, denoted by P(B  A), is called the conditional probability of B given A. A formula for computing the conditional probability of B given A may be discovered with the aid of a Venn diagram. Consider an experiment with a uniform sample space S, and suppose A and B are two events of the experiment (Figure 2).

472

8 ADDITIONAL TOPICS IN PROBABILITY

S

A

FIGURE 2

B

A

(a) Original sample space

(b) Reduced sample space A. The shaded area is A  B.

The condition that the event A has occurred tells us that the possible outcomes of the experiment in the second phase are restricted to those outcomes (elements) in the set A. In other words, we may work with the reduced sample space A instead of the original sample space S in the experiment. Next we observe that, with respect to the reduced sample space A, the outcomes in the event B are precisely those elements in the set A  B. Consequently, the conditional probability of B given A is P1B 0 A2  

Number of elements in A  B Number of elements in A n1A  B2 n(A)  0

n1A2

Dividing the numerator and the denominator by n(S ), the number of elements in S, we have n1A  B2 P1B 0 A2 

n1S2 n1A2 n1S2

which is equivalent to the following formula. Conditional Probability of an Event

If A and B are events in an experiment and P(A)  0, then the conditional probability that the event B will occur given that the event A has already occurred is P1B 0 A2 

P1A  B2

(2)

P1A2

EXAMPLE 2 A pair of fair dice is rolled. What is the probability that the sum of the numbers falling uppermost is 7 if it is known that one of the numbers is a 5? Solution Let A denote the event that the sum of the numbers falling uppermost is 7 and let B denote the event that one of the numbers is a 5. From the results of Example 4, Section 7.5, we find that

A  {(6, 1), (5, 2), (4, 3), (3, 4), (2, 5), (1, 6)} B  {(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (1, 5), (2, 5), (3, 5), (4, 5), (6, 5)}

so that A  B  {(5, 2), (2, 5)}

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

473

(Figure 3). Since the dice are fair, each outcome of the experiment is equally likely; therefore, P1A  B2 

2 36

and P1B2 

11 36

Recall that n(S )  36.

Thus, the probability that the sum of the numbers falling uppermost is 7 given that one of the numbers is a 5 is, by virtue of Equation (2), 2 36 2 P1A 0 B2   11 11 36

FIGURE 3

A  B  {(5, 2), (2, 5)}

APPLIED EXAMPLE 3 Color Blindness In a test conducted by the U.S. Army, it was found that of 1000 new recruits (600 men and 400 women), 50 of the men and 4 of the women were red-green color-blind. Given that a recruit selected at random from this group is red-green color-blind, what is the probability that the recruit is a male? Solution Let C denote the event that a randomly selected subject is red-green color-blind and let M denote the event that the subject is a male recruit. Since 54 out of the 1000 subjects are color-blind, we have

P1C2 

54  .054 1000

Therefore, by Equation (2), the probability that a subject is male given that the subject is red-green color-blind is P1M 0 C2 

P1M  C2

P1C2 .05   .926 .054

Explore & Discuss Let A and B be events in an experiment and suppose P(A)  0. In n trials, the event A occurs m times, the event B occurs k times, and the events A and B occur together l times. 1. Explain why it makes good sense to call the ratio l/m the conditional relative frequency of the event B given the event A. 2. Show that the relative frequencies l/m, m/n, and l/n satisfy the equation l n l  m m n 3. Explain why the result of part 2 suggests that Equation (2) P1B 0 A2  is plausible.

P1A  B2 P1A2

3P1A2  04

474

8 ADDITIONAL TOPICS IN PROBABILITY

In certain problems, the probability of an event B occurring given that A has occurred, written P(B  A), is known, and we wish to find the probability of A and B occurring. The solution to such a problem is facilitated by the use of the following formula:

Product Rule

P1A  B2  P1A2 # P1B 0 A2

(3)

This formula is obtained from Equation (2) by multiplying both sides of the equation by P(A). We illustrate the use of the product rule in the next several examples. APPLIED EXAMPLE 4 Seniors with Driver’s Licenses There are 300 seniors in Jefferson High School, of which 140 are males. It is known that 80% of the males and 60% of the females have their driver’s license. If a student is selected at random from this senior class, what is the probability that the student is a. A male and has a driver’s license? b. A female who does not have a driver’s license? Solution

a. Let M denote the event that the student is a male, and let D denote the event that the student has a driver’s license. Then, P1M2 

140 300

and

P1D 0 M2  .8

The event that the student selected at random is a male and has a driver’s license is M  D, and, by the product rule, the probability of this event occurring is given by P1M  D2  P1M2 # P1D 0 M2 140  a b 1.82  .373 300

b. Let F denote the event that the student is a female. Then D c is the event that the student does not have a driver’s license. We have P1F2 

160 300

and

P1D c 0 F2  1  .6  .4

Note that we have used the rule of complements in the computation of P(D c  F). The event that the student selected at random is a female and does not have a driver’s license is F  D c, and so, by the product rule, the probability of this event occurring is given by P 1F  D c 2  P1F2 # P1D c 0 F2 160  a b 1.42  .213 300

EXAMPLE 5 Two cards are drawn without replacement from a well-shuffled deck of 52 playing cards. What is the probability that the first card drawn is an ace and the second card drawn is a face card?

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

475

Solution Let A denote the event that the first card drawn is an ace, and let F denote the event that the second card drawn is a face card. Then P1A2  524 . After drawing the first card, there are 51 cards left in the deck, of which 12 are face cards. Therefore, the probability of drawing a face card given that the first card drawn was an ace is given by

P1F 0 A2 

12 51

By the product rule, the probability that the first card drawn is an ace and the second card drawn is a face card is given by P1A  F 2  P1A2 # P1F 0 A2 4 # 12 4    .018 52 51 221

Explore & Discuss The product rule can be extended to the case involving three or more events. For example, if A, B, and C are three events in an experiment, then it can be shown that P1A  B  C 2  P1A 2 # P1B 0 A2 # P1C 0 A  B2 1. Explain the formula in words. 2. Suppose 3 cards are drawn without replacement from a well-shuffled deck of 52 playing cards. Use the given formula to find the probability that the 3 cards are aces.

The product rule may be generalized to the case involving any finite number of events. For example, in the case involving the three events E, F, and G, it may be shown that P(E  F  G)  P(E)  P(F  E)  P(G  E  F )

(4)

More on Tree Diagrams

) P(F

/52 = 12

P(F c )=

40/5

2

F

Formula (4) and its generalizations may be used to help us solve problems that involve finite stochastic processes. A finite stochastic process is an experiment consisting of a finite number of stages in which the outcomes and associated probabilities of each stage depend on the outcomes and associated probabilities of the preceding stages. We can use tree diagrams to help us solve problems involving finite stochastic processes. Consider, for example, the experiment consisting of drawing 2 cards without replacement from a well-shuffled deck of 52 playing cards. What is the probability that the second card drawn is a face card? We may think of this experiment as a stochastic process with two stages. The events associated with the first stage are F, that the card drawn is a face card, and Fc, that the card drawn is not a face card. Since there are 12 face cards, we have P1F2 

Fc

FIGURE 4 F is the event that a face card is drawn.

12 52

and

P1F c 2  1 

12 40  52 52

The outcomes of this trial, together with the associated probabilities, may be represented along two branches of a tree diagram as shown in Figure 4. In the second trial, we again have two events: G, that the card drawn is a face card, and G c, that the card drawn is not a face card. But the outcome of the second trial depends on the outcome of the first trial. For example, if the first card drawn was a face

476

8 ADDITIONAL TOPICS IN PROBABILITY

card, then the event G that the second card drawn is a face card has probability given by the conditional probability P(G  F ). Since the occurrence of a face card in the first draw leaves 11 face cards in a deck of 51 cards for the second draw, we see that P1G 0 F2 

| F) P(G ) P(F

P(F c )

/52

= 12

= 40

/52

/51 G = 11

F P (G c | F) = 40 /51

Gc

11 51

The probability of drawing a face card given that a face card has already been drawn

Similarly, the occurrence of a face card in the first draw leaves 40 that are other than face cards in a deck of 51 cards for the second draw. Therefore, the probability of drawing other than a face card in the second draw given that the first card drawn is a face card is P1G c 0 F 2 

Fc

40 51

FIGURE 5 G is the event that the second card drawn is a face card.

Using these results, we extend the tree diagram of Figure 4 by displaying another two branches of the tree growing from its upper branch (Figure 5). To complete the tree diagram, we compute P(G  F c ) and P(G c  F c ), the conditional probabilities that the second card drawn is a face card and other than a face card, respectively, given that the first card drawn is not a face card. We find that P1G 0 F c 2 

|F P(G 2

)= P(F

P(F c )

12/5

= 40 /52

F P (G c |

1/51 )=1

F) = c

40/5 1 = 12/51

(G | F ) Fc P P(G c | Fc )= 39

/51

FIGURE 6 Tree diagram showing the two trials of the experiment

G

Gc G

Gc

12 51

and

P1G c 0 F c 2 

39 51

This leads to the completion of the tree diagram, shown in Figure 6, where the branches of the tree that lead to the two outcomes of interest have been highlighted. Having constructed the tree diagram associated with the problem, we are now in a position to answer the question posed earlier: What is the probability of the second card being a face card? Observe that Figure 6 shows the two ways in which a face card may result in the second draw—namely, the two Gs on the extreme right of the diagram. Now, by the product rule, the probability that the second card drawn is a face card and the first card drawn is a face card (this is represented by the upper branch) is P1G  F 2  P1F 2 # P1G 0 F 2

Similarly, the probability that the second card drawn is a face card and the first card drawn is other than a face card (this corresponds to the other branch) is P1G  F c 2  P1F c 2 # P1G 0 F c 2

Observe that each of these probabilities is obtained by taking the product of the probabilities appearing on the respective branches. Since G  F and G  F c are mutually exclusive events (why?), the probability that the second card drawn is a face card is given by P1G  F2  P1G  F c 2  P1F2 # P1G 0 F2  P1F c 2 # P1G 0 Fc 2

or, upon replacing the probabilities on the right of the expression by their numerical values, 12 # 11 40 # 12  52 51 52 51 3  13

P1G  F2  P1G  F c 2 

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

477

APPLIED EXAMPLE 6 Quality Control The panels for the Pulsar 32-inch widescreen LCD HDTVs are manufactured in three locations and then shipped to the main plant of Vista Vision for final assembly. Plants A, B, and C supply 50%, 30%, and 20%, respectively, of the panels used by the company. The quality-control department of the company has determined that 1% of the panels produced by plant A are defective, whereas 2% of the panels produced by plants B and C are defective. What is the probability that a randomly selected Pulsar 32-inch HDTV will have a defective panel? Plant

.01

D

.99

Dc

.5 .3

.02

D

.98

Dc

.02

D

.98

Dc

B

.2

Let A, B, and C denote the events that the HDTV chosen has a panel manufactured in plant A, plant B, and plant C, respectively. Also, let D denote the event that a HDTV has a defective panel. Using the given information, we draw the tree diagram shown in Figure 7. (The events that result in a HDTV with a defective panel being selected are circled.) Taking the product of the probabilities along each branch leading to such an event and then adding them yields the probability that a HDTV chosen at random has a defective panel. Thus, the required probability is given by Solution

A

C

1.52 1.012  1.32 1.022  1.22 1.022  .005  .006  .004  .015

FIGURE 7 Tree diagram showing the probabilities of producing defective panels at each plant

APPLIED EXAMPLE 7 Quality Control A box contains eight 9-volt batteries, of which two are known to be defective. The batteries are selected one at a time without replacement and tested until a nondefective one is found. What is the probability that the number of batteries tested is (a) one, (b) two, and (c) three? We may view this experiment as a multistage process with up to three stages. In the first stage, a battery is selected with a probability of 68 of being nondefective and a probability of 28 of being defective. If the battery selected is good, the experiment is terminated. Otherwise, a second battery is selected with probability of 76 and 17, respectively, of being nondefective and defective. If the second battery selected is good, the experiment is terminated. Otherwise, a third battery is selected with probability of 1 and 0, respectively, of its being nondefective and defective. The tree diagram associated with this experiment is shown in Figure 8, where N denotes the event that the battery selected is nondefective and D denotes the event that the battery selected is defective. Solution

N 6/8

N 6/ 7

2/8 D

N

FIGURE 8 In this experiment, batteries are selected until a nondefective one is found.

1/ 7

D

1

With the aid of the tree diagram we see that (a) the probability that only one battery is selected is 86  34, (b) the probability that two batteries are selected is 1 28 2 1 67 2, or 143 , and (c) the probability that three batteries are selected is 1 28 2 1 17 2 112  281 .

478

8 ADDITIONAL TOPICS IN PROBABILITY

Independent Events Let’s return to the experiment of drawing 2 cards in succession without replacement from a well-shuffled deck of 52 playing cards as considered in Example 5. Let E denote the event that the first card drawn is not a face card and let F denote the event that the second card drawn is a face card. Intuitively, it is clear that the events E and F are not independent of each other, because whether or not the first card drawn is a face card affects the likelihood that the second card drawn is a face card. Next, let’s consider the experiment of tossing a coin twice and observing the outcomes: If H denotes the event that the first toss produces heads and T denotes the event that the second toss produces tails, then it is intuitively clear that H and T are independent of each other because the outcome of the first toss does not affect the outcome of the second. In general, two events A and B are independent if the outcome of one does not affect the outcome of the other. Thus, we have Independent Events

If A and B are independent events, then P1A 0 B2  P1A2

and

P1B 0 A2  P1B2

Using the product rule, we can find a simple test to determine the independence of two events. Suppose that A and B are independent and that P(A)  0 and P(B)  0. Then P1B 0 A2  P1B2

Thus, by the product rule, we have

P1A  B2  P1A2 # P1B 0 A2  P1A2 # P1B2

Conversely, if this equation holds then it can be seen that P(B  A)  P(B); that is, A and B are independent. Accordingly, we have the following test for the independence of two events. Test for the Independence of Two Events

Two events A and B are independent if and only if P(A  B)  P(A)  P(B)

(5)

Do not confuse independent events with mutually exclusive events. The former pertains to how the occurrence of one event affects the occurrence of another event, whereas the latter pertains to the question of whether the events can occur at the same time. EXAMPLE 8 Consider the experiment consisting of tossing a fair coin twice and observing the outcomes. Show that the event of heads on the first toss and tails on the second toss are independent events. Solution Let A denote the event that the outcome of the first toss is a head, and let B denote the event that the outcome of the second toss is a tail. The sample space of the experiment is

S  {(HH), (HT), (TH), (TT)} A  {(HH), (HT)} B  {(HT), (TT)}

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

479

so that A  B  {(HT)}

Next, we compute P1A  B2 

1 4

P1A2 

1 2

P1B2 

1 2

and observe that Equation (5) is satisfied in this case. Hence, A and B are independent events, as we set out to show. APPLIED EXAMPLE 9 Medical Surveys A survey conducted by an independent agency for the National Lung Society found that, of 2000 women, 680 were heavy smokers and 50 had emphysema. Of those who had emphysema, 42 were also heavy smokers. Using the data in this survey, determine whether the events “being a heavy smoker” and “having emphysema” are independent events. Solution Let A denote the event that a woman chosen at random in this survey is a heavy smoker and let B denote the event that a woman chosen at random in this survey has emphysema. Then, the probability that a woman chosen at random in this survey is a heavy smoker and has emphysema is given by

P1A  B2 

42  .021 2000

Next, P1A2 

so

680  .34 and 2000

P1B2 

50  .025 2000

P1A2 # P1B2  1.342 1.0252  .0085

Since P(A  B)  P(A)  P(B), we conclude that A and B are not independent events. The solution of many practical problems involves more than two independent events. In such cases we use the following result.

Explore & Discuss Let E and F be independent events in a sample space S. Are E c and F c independent?

Independence of More Than Two Events

If E1, E2, . . . , En are independent events, then P(E1  E2      En)  P(E1)  P(E2)      P(En)

(6)

Formula (6) states that the probability of the simultaneous occurrence of n independent events is equal to the product of the probabilities of the n events. It is important to note that the mere requirement that the n events E1, E2, . . . , En satisfy Formula (6) is not sufficient to guarantee that the n events are indeed independent. However, a criterion does exist for determining the independence of n events and may be found in more advanced texts on probability. EXAMPLE 10 It is known that the three events A, B, and C are independent and that P(A)  .2, P(B)  .4, and P(C )  .5. Compute: a. P(A  B)

b. P(A  B  C )

480

8 ADDITIONAL TOPICS IN PROBABILITY

Solution

Using Formulas (5) and (6), we find

a. P(A  B)  P(A)  P(B)  (.2)(.4)  .08 b. P(A  B  C)  P(A)  P(B)  P(C )  (.2)(.4)(.5)  .04 APPLIED EXAMPLE 11 Quality Control The Acrosonic model F loudspeaker system has four loudspeaker components: a woofer, a mid-range, a tweeter, and an electrical crossover. The quality-control manager of Acrosonic has determined that on the average 1% of the woofers, 0.8% of the midranges, and 0.5% of the tweeters are defective, while 1.5% of the electrical crossovers are defective. Determine the probability that a loudspeaker system selected at random as it comes off the assembly line (and before final inspection) is not defective. Assume that the defects in the manufacturing of the components are unrelated. Solution Let A, B, C, and D denote, respectively, the events that the woofer, the midrange, the tweeter, and the electrical crossover are defective. Then,

P(A)  .01

P(B)  .008

P(C )  .005

P(D)  .015

and the probabilities of the corresponding complementary events are P(Ac )  .99

P(B c )  .992

P(C c )  .995

P(D c )  .985

The event that a loudspeaker system selected at random is not defective is given by Ac  Bc  C c  D c. Because the events A, B, C, and D (and therefore also Ac, Bc, C c, and D c) are assumed to be independent, we find that the required probability is given by P1Ac  Bc  Cc  Dc 2  P1Ac 2 # P1B c 2 # P1Cc 2 # P1Dc 2  1.992 1.9922 1.9952 1.9852  .96

8.2 Self-Check Exercises 1. Let A and B be events in a sample space S such that P(A)  .4, P(B)  .8, and P(A  B)  .3. Find: a. P(A  B) b. P(B  A) 2. According to a survey cited in Newsweek, 29.7% of married survey respondents who were married between the ages of 20 and 22 (inclusive), 26.9% of those married between the ages of 23 and 27, and 45.1% of those married at age 28 or older said that “their marriage was less than

‘very happy’.” Suppose that a survey respondent from each of the three age groups was selected at random. What is the probability that all three respondents said that their marriage was “less than very happy”? Source: Marc Bain, Newsweek.

Solutions to Self-Check Exercises 8.2 can be found on page 484.

8.2 Concept Questions 1. What is conditional probability? Illustrate the concept with an example.

used to compute the probability of the event that both A and B will occur.

2. If A and B are events in an experiment and P(A)  0, then what is the formula for computing P(B  A)?

4. a. What is the test for determining the independence of two events? b. What is the difference between mutually exclusive events and independent events?

3. If A and B are events in an experiment and the conditional probability P(B  A) is known, give the formula that can be

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

481

8.2 Exercises 1. Let A and B be two events in a sample space S such that P(A)  .6, P(B)  .5, and P(A  B)  .2. Find a. P(A  B) b. P(B  A)

.5

4. Let A and B be the events described in Exercise 1. Find a. P(A  B c ) b. P(B  Ac ) Hint: (A  B c )  (A  B)  A.

In Exercises 5–8, determine whether the events A and B are independent.

5. P(A)  .3, P(B)  .6, P(A  B)  .18 6. P(A)  .6, P(B)  .8, P(A  B)  .2 7. P(A)  .5, P(B)  .7, P(A  B)  .85 8. P(Ac)  .3, P(Bc )  .4, P(A  B)  .42 9. If A and B are independent events, P(A)  .4, and P(B)  .6, find a. P(A  B) b. P(A  B) 10. If A and B are independent events, P(A)  .35, and P(B)  .45, find a. P(A  B) b. P(A  B) 11. The accompanying tree diagram represents an experiment consisting of two trials: .4

E

A .5

.6

.3

.5

Ec E

B .7

Ec

Use the diagram to find a. P(A) b. P(E  A) c. P(A  E ) d. P(E ) e. Does P(A  E )  P(A)  P(E )? f. Are A and E independent events? 12. The accompanying tree diagram represents an experiment consisting of two trials. Use the diagram to find a. P(A) b. P(E  A) c. P(A  E ) d. P(E ) e. Does P(A  E )  P(A)  P(E )? f. Are A and E independent events?

.5

.4

.3

2. Let A and B be two events in a sample space S such that P(A)  .4, P(B)  .6, and P(A  B)  .3. Find a. P(A  B) b. P(B  A) 3. Let A and B be two events in a sample space S such that P(A)  .6 and P(B  A)  .5. Find P(A  B).

E

A

.4

Ec E

B .7

.2

.4

Ec E

C .6

Ec

13. An experiment consists of two independent trials. The outcomes of the first trial are A and B with probabilities of occurring equal to .4 and .6. There are also two outcomes, C and D, in the second trial with probabilities of .3 and .7. Draw a tree diagram representing this experiment, and use it to find a. P(A) b. P(C  A) c. P(A  C ) d. P(C) e. Does P(A  C)  P(A)  P(C )? f. Are A and C independent events? 14. An experiment consists of two independent trials. The outcomes of the first trial are A, B, and C, with probabilities of occurring equal to .2, .5, and .3, respectively. The outcomes of the second trial are E and F, with probabilities of occurring equal to .6 and .4. Draw a tree diagram representing this experiment. Use this diagram to find a. P(B) b. P(F  B) c. P(B  F) d. P(F) e. Does P(B  F)  P(B)  P(F)? f. Are B and F independent events? 15. A pair of fair dice is rolled. Let E denote the event that the number falling uppermost on the first die is 5, and let F denote the event that the sum of the numbers falling uppermost is 10. a. Compute P(F). b. Compute P(E  F). c. Compute P(F  E). d. Compute P(E). e. Are E and F independent events? 16. A pair of fair dice is rolled. Let E denote the event that the number falling uppermost on the first die is 4, and let F denote the event that the sum of the numbers falling uppermost is 6. a. Compute P(F). b. Compute P(E  F). c. Compute P(F  E). d. Compute P(E ). e. Are E and F independent events? 17. A pair of fair dice is rolled. What is the probability that the sum of the numbers falling uppermost is less than 9, given that at least one of the numbers is a 6? 18. A pair of fair dice is rolled. What is the probability that the number landing uppermost on the first die is a 4 if it is known that the sum of the numbers landing uppermost is 7?

482

8 ADDITIONAL TOPICS IN PROBABILITY

19. A pair of fair dice is rolled. Let E denote the event that the number landing uppermost on the first die is a 3, and let F denote the event that the sum of the numbers landing uppermost is 7. Determine whether E and F are independent events. 20. A pair of fair dice is rolled. Let E denote the event that the number landing uppermost on the first die is a 3, and let F denote the event that the sum of the numbers landing uppermost is 6. Determine whether E and F are independent events. 21. A card is drawn from a well-shuffled deck of 52 playing cards. Let E denote the event that the card drawn is black and let F denote the event that the card drawn is a spade. Determine whether E and F are independent events. Give an intuitive explanation for your answer. 22. A card is drawn from a well-shuffled deck of 52 playing cards. Let E denote the event that the card drawn is an ace and let F denote the event that the card drawn is a diamond. Determine whether E and F are independent events. Give an intuitive explanation for your answer. 23. PRODUCT RELIABILITY The probability that a battery will last 10 hr or more is .80, and the probability that it will last 15 hr or more is .15. Given that a battery has lasted 10 hr, find the probability that it will last 15 hr or more. 24. Two cards are drawn without replacement from a wellshuffled deck of 52 playing cards. a. What is the probability that the first card drawn is a heart? b. What is the probability that the second card drawn is a heart if the first card drawn was not a heart? c. What is the probability that the second card drawn is a heart if the first card drawn was a heart? 25. Five black balls and four white balls are placed in an urn. Two balls are then drawn in succession. What is the probability that the second ball drawn is a white ball if a. The second ball is drawn without replacing the first? b. The first ball is replaced before the second is drawn? 26. AUDITING TAX RETURNS A tax specialist has estimated that the probability that a tax return selected at random will be audited is .02. Furthermore, he estimates that the probability that an audited return will result in additional assessments being levied on the taxpayer is .60. What is the probability that a tax return selected at random will result in additional assessments being levied on the taxpayer? 27. STUDENT ENROLLMENT At a certain medical school, 17 of the students are from a minority group. Of those students who belong to a minority group, 13 are black. a. What is the probability that a student selected at random from this medical school is black? b. What is the probability that a student selected at random from this medical school is black if it is known that the student is a member of a minority group? 28. EDUCATIONAL LEVEL OF VOTERS In a survey of 1000 eligible voters selected at random, it was found that 80 had a college

degree. Additionally, it was found that 80% of those who had a college degree voted in the last presidential election, whereas 55% of the people who did not have a college degree voted in the last presidential election. Assuming that the poll is representative of all eligible voters, find the probability that an eligible voter selected at random a. Had a college degree and voted in the last presidential election. b. Did not have a college degree and did not vote in the last presidential election. c. Voted in the last presidential election. d. Did not vote in the last presidential election. 29. Three cards are drawn without replacement from a wellshuffled deck of 52 playing cards. What is the probability that the third card drawn is a diamond? 30. A coin is tossed three times. What is the probability that the coin will land heads a. At least twice? b. On the second toss, given that heads were thrown on the first toss? c. On the third toss, given that tails were thrown on the first toss? 31. In a three-child family, what is the probability that all three children are girls given that at least one of the children is a girl? (Assume that the probability of a boy being born is the same as the probability of a girl being born.) 32. QUALITY CONTROL An automobile manufacturer obtains the microprocessors used to regulate fuel consumption in its automobiles from three microelectronic firms: A, B, and C. The quality-control department of the company has determined that 1% of the microprocessors produced by firm A are defective, 2% of those produced by firm B are defective, and 1.5% of those produced by firm C are defective. Firms A, B, and C supply 45%, 25%, and 30%, respectively, of the microprocessors used by the company. What is the probability that a randomly selected automobile manufactured by the company will have a defective microprocessor? 33. CAR THEFT Figures obtained from a city’s police department seem to indicate that, of all motor vehicles reported as stolen, 64% were stolen by professionals whereas 36% were stolen by amateurs (primarily for joy rides). Of those vehicles presumed stolen by professionals, 24% were recovered within 48 hr, 16% were recovered after 48 hr, and 60% were never recovered. Of those vehicles presumed stolen by amateurs, 38% were recovered within 48 hr, 58% were recovered after 48 hr, and 4% were never recovered. a. Draw a tree diagram representing these data. b. What is the probability that a vehicle stolen by a professional in this city will be recovered within 48 hr? c. What is the probability that a vehicle stolen in this city will never be recovered? 34. HOUSING LOANS The chief loan officer of La Crosse Home Mortgage Company summarized the housing loans extended by the company in 2007 according to type and

8.2 CONDITIONAL PROBABILITY AND INDEPENDENT EVENTS

term of the loan. Her list shows that 70% of the loans were fixed-rate mortgages (F ), 25% were adjustable-rate mortgages (A), and 5% belong to some other category (O) (mostly second trust-deed loans and loans extended under the graduated payment plan). Of the fixed-rate mortgages, 80% were 30-yr loans and 20% were 15-yr loans; of the adjustable-rate mortgages, 40% were 30-yr loans and 60% were 15-yr loans; finally, of the other loans extended, 30% were 20-yr loans, 60% were 10-yr loans, and 10% were for a term of 5 yr or less. a. Draw a tree diagram representing these data. b. What is the probability that a home loan extended by La Crosse has an adjustable rate and is for a term of 15 yr? c. What is the probability that a home loan extended by La Crosse is for a term of 15 yr? 35. COLLEGE ADMISSIONS The admissions office of a private university released the following admission data for the preceding academic year: From a pool of 3900 male applicants, 40% were accepted by the university and 40% of these subsequently enrolled. Additionally, from a pool of 3600 female applicants, 45% were accepted by the university and 40% of these subsequently enrolled. What is the probability that a. A male applicant will be accepted by and subsequently will enroll in the university? b. A student who applies for admissions will be accepted by the university? c. A student who applies for admission will be accepted by the university and subsequently will enroll? 36. QUALITY CONTROL A box contains two defective Christmas tree lights that have been inadvertently mixed with eight nondefective lights. If the lights are selected one at a time without replacement and tested until both defective lights are found, what is the probability that both defective lights will be found after exactly three trials? 37. QUALITY CONTROL It is estimated that 0.80% of a large consignment of eggs in a certain supermarket is broken. a. What is the probability that a customer who randomly selects a dozen of these eggs receives at least one broken egg? b. What is the probability that a customer who selects these eggs at random will have to check three cartons before finding a carton without any broken eggs? (Each carton contains a dozen eggs.) 38. STUDENT FINANCIAL AID The accompanying data were obtained from the financial aid office of a certain university:

Undergraduates Graduates Total

Receiving Financial Aid 4,222 1,879

Not Receiving Financial Aid 3,898 731

Total 8,120 2,610

6,101

4,629

10,730

483

Let A be the event that a student selected at random from this university is an undergraduate student, and let B be the event that a student selected at random is receiving financial aid. a. Find each of the following probabilities: P(A), P(B ), P(A  B), P(B  A), and P(B  Ac ). b. Are the events A and B independent events? 39. EMPLOYEE EDUCATION AND INCOME The personnel department of Franklin National Life Insurance Company compiled the accompanying data regarding the income and education of its employees:

Noncollege Graduate College Graduate

Income $50,000 or Below 2040 400

Income Above $50,000 840 720

Let A be the event that a randomly chosen employee has a college degree and B the event that the chosen employee’s income is more than $50,000. a. Find each of the following probabilities: P(A), P(B), P(A  B), P(B  A), and P(B  Ac ). b. Are the events A and B independent events? 40. Two cards are drawn without replacement from a wellshuffled deck of 52 cards. Let A be the event that the first card drawn is a heart, and let B be the event that the second card drawn is a red card. Show that the events A and B are dependent events. 41. MEDICAL RESEARCH A nationwide survey conducted by the National Cancer Society revealed the following information. Of 10,000 people surveyed, 3200 were “heavy coffee drinkers” and 160 had cancer of the pancreas. Of those who had cancer of the pancreas, 132 were heavy coffee drinkers. Using the data in this survey, determine whether the events “being a heavy coffee drinker” and “having cancer of the pancreas” are independent events. 42. SWITCHING INTERNET SERVICE PROVIDERS (ISPS) According to a survey conducted in 2004 of 1000 American adults with Internet access, one in four households plans to switch ISPs in the next 6 months. Of those who plan to switch, 1% of the households are likely to switch to a satellite connection, 27% to digital subscriber line (DSL), 28% to cable modem, 35% to dial-up modem, and 9% don’t know what kind of service provider they will switch to. a. What is the probability that a randomly selected survey participant who was planning to switch ISPs will switch to a dial-up modem connection? b. What is the probability that a randomly selected survey participant will upgrade to high-speed service (satellite, DSL, or cable)? Source: Ipsos-Insight

43. RELIABILITY OF SECURITY SYSTEMS Before being allowed to enter a maximum-security area at a military installation, a person must pass three independent identification tests: a voice-pattern test, a fingerprint test, and a handwriting

484

8 ADDITIONAL TOPICS IN PROBABILITY

test. If the reliability of the first test is 97%, the reliability of the second test is 98.5%, and that of the third is 98.5%, what is the probability that this security system will allow an improperly identified person to enter the maximumsecurity area? 44. RELIABILITY OF A HOME THEATER SYSTEM In a home theater system, the probability that the video components need repair within 1 yr is .01, the probability that the electronic components need repair within 1 yr is .005, and the probability that the audio components need repair within 1 yr is .001. Assuming that the events are independent, find the probability that a. At least one of these components will need repair within 1 yr. b. Exactly one of these components will need repair within 1 yr. 45. PROBABILITY OF TRANSPLANT REJECTION The probabilities that the three patients who are scheduled to receive kidney transplants at General Hospital will suffer rejection are 21, 13, and 101 . Assuming that the events (kidney rejection) are independent, find the probability that a. At least one patient will suffer rejection. b. Exactly two patients will suffer rejection. 46. QUALITY CONTROL Copykwik has four photocopy machines: A, B, C, and D. The probability that a given machine will break down on a particular day is P1A2 

P1B 2 

1 50

1 60

P1C 2 

P1D 2 

1 75

1 40

Assuming independence, what is the probability on a particular day that a. All four machines will break down? b. None of the machines will break down? 47. PRODUCT RELIABILITY The proprietor of Cunningham’s Hardware Store has decided to install floodlights on the premises

as a measure against vandalism and theft. If the probability is .01 that a certain brand of floodlight will burn out within a year, find the minimum number of floodlights that must be installed to ensure that the probability that at least one of them will remain functional for the whole year is at least .99999. (Assume that the floodlights operate independently.) 48. Let E be any event in a sample space S. a. Are E and S independent? Explain your answer. b. Are E and  independent? Explain your answer. 49. Suppose the probability that an event will occur in one trial is p. Show that the probability that the event will occur at least once in n independent trials is 1  (1  p)n. 50. Let E and F be mutually exclusive events and suppose P(F )  0. Find P(E  F ) and interpret your result. 51. Let E and F be events such that F  E. Find P(E  F ) and interpret your result. 52. Suppose that A and B are mutually exclusive events and that P(A  B)  0. What is P(A  A  B)? 53. Let E and F be independent events; show that E and F c are independent. In Exercises 54–57, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

54. If A and B are mutually exclusive and P(B)  0, then P(A  B)  0. 55. If A is an event of an experiment, then P(A  Ac )  0. 56. If A and B are events of an experiment, then P(A  B)  P(A  B)  P(B)  P(B  A)  P(A)

57. If A and B are independent events with P(A)  0 and P(B)  0, then A  B  .

8.2 Solutions to Self-Check Exercises 1. a. P1A 0 B 2  

P1A  B 2 P1B 2

.3 3  .8 8

b. P1B 0 A 2  

P1A  B 2 P1A 2

.3 3  .4 4

2. Let A, B, and C denote the events that a respondent who was married between the ages of 20 and 22, between the ages of

23 and 27, and at age 28 or older (respectively) said that his or her marriage was “less than very happy.” Then the probability of each of these events occurring is P(A)  .297, P(B)  .269, and P(C)  .451. So the probability that all three of the respondents said that his or her marriage was “less than very happy” is P1A2 # P1B2 # P1C 2  1.2972 1.2692 1.4512  .036

8.3 BAYES’ THEOREM

485

8.3 Bayes’ Theorem A Posteriori Probabilities Suppose three machines, A, B, and C, produce similar engine components. Machine A produces 45% of the total components, machine B produces 30%, and machine C, 25%. For the usual production schedule, 6% of the components produced by machine A do not meet established specifications; for machine B and machine C, the corresponding figures are 4% and 3%, respectively. One component is selected at random from the total output and is found to be defective. What is the probability that the component selected was produced by machine A? The answer to this question is found by calculating the probability after the outcomes of the experiment have been observed. Such probabilities are called a posteriori probabilities as opposed to a priori probabilities—probabilities that give the likelihood that an event will occur, the subject of the last several sections. Returning to the example under consideration, we need to determine the a posteriori probability for the event that the component selected was produced by machine A. Toward this end, let A, B, and C denote the events that a component is produced by machine A, machine B, and machine C, respectively. We may represent this experiment with a Venn diagram (Figure 9).

A

B

C

S

D A

D

B

D

C

D

FIGURE 9 D is the event that a defective component is produced by machine A, machine B, or machine C.

The three mutually exclusive events A, B, and C form a partition of the sample space S; that is, aside from being mutually exclusive, their union is precisely S. The event D that a component is defective is the shaded area. Again referring to Figure 9, we see that 1. The event D may be expressed as D  1A  D2  1B  D2  1C  D2

2. The event that a component is defective and is produced by machine A is given by A  D. Thus, the a posteriori probability that a defective component selected was produced by machine A is given by P1A 0 D2 

P1A  D2 P1D2

Upon dividing both the numerator and the denominator by P(S ) and observing that the events A  D, B  D, and C  D are mutually exclusive, we obtain P1A 0 D2  

P1A  D2 P1D2 P1A  D2 P1A  D2  P1B  D2  P1C  D2

(7)

486

8 ADDITIONAL TOPICS IN PROBABILITY

Next, using the product rule, we may express P(A  D)  P(A)  P(D  A) P(B  D)  P(B)  P(D  B) P(C  D)  P(C)  P(D  C)

so Equation (7) may be expressed in the form P1A 0 D2 

P1A2 # P1D 0 A2

P1A2 # P1D 0 A2  P1B2 # P1D 0 B2  P1C2 # P1D 0 C2

(8)

which is a special case of a result known as Bayes’ theorem. Observe that the expression on the right of Equation (8) involves the probabilities P(A), P(B), and P(C ) as well as the conditional probabilities P(D  A), P(D  B), and P(D  C). In fact, by displaying these probabilities on a tree diagram, we obtain Figure 10. We may compute the required probability by substituting the relevant quantities into (8), or we may make use of the following device: P1A 0 D2 

Product of probabilities along the branch through A terminating at D Sum of products of the probabilities along each branch terminating at D P(D |

6 A) = .0

D

A

= A) P(

.45

P(B) = .30

FIGURE 10 A tree diagram displaying the probabilities that a defective component is produced by machine A, machine B, or machine C

P(

C) =

P

) = .04 (D | B

P

) = .03 (D | C

Dc D

B

.25

Dc D

C Dc

In either case, we obtain P1A 0 D2 

1.45 2 1.062

1.452 1.062  1.302 1.042  1.25 2 1.032  .58

Before looking at any further examples, let’s state the general form of Bayes’ theorem. Bayes’ Theorem

Let A1, A2, . . . , An be a partition of a sample space S, and let E be an event of the experiment such that P(E )  0 and P(Ai)  0 for 1 i n. Then the a posteriori probability P(Ai  E ) (1 i n) is given by P 1Ai 0 E2 

P 1Ai 2 # P 1E 0 Ai 2

P 1A1 2 # P 1E 0 A1 2  P 1A2 2 # P 1E 0 A2 2  p  P 1An 2 # P 1E 0 An 2

(9)

APPLIED EXAMPLE 1 Quality Control The panels for the Pulsar 32-inch widescreen LCD HDTVs are manufactured in three locations and then shipped to the main plant of Vista Vision for final assembly. Plants A, B, and C supply 50%, 30%, and 20%, respectively, of the panels used by Vista Vision. The quality-control department of the company has determined that 1%

8.3 BAYES’ THEOREM 1 A) = .0 P(D |

D

A

5 =.

) P(A P(B) = .3

2 B) = .0 P(D |

B

P(C

)=

Dc D

.2

P(D

Dc 2 .0 D = | C)

C Dc

FIGURE 11



of the panels produced by plant A are defective, whereas 2% of the panels produced by plants B and C are defective. If a Pulsar 32-inch HDTV is selected at random and the panel is found to be defective, what is the probability that the panel was manufactured in plant C? (Compare with Example 6, page 477.) Solution Let A, B, and C denote the events that the set chosen has a panel manufactured in plant A, plant B, and plant C, respectively. Also, let D denote the event that a set has a defective panel. Using the given information, we may draw the tree diagram shown in Figure 11. Next, using Formula (9), we find that the required a posteriori probability is given by

P1C 0 D2 

P(C  D)

Product of probabilities of branches to D through C

487



Sum of product of probabilities of branches leading to D

P 1C2 # P 1D 0 C2

P 1A2 # P 1D 0 A2  P 1B2 # P 1D 0 B2  P 1C2 # P 1D 0 C 2 1.202 1.022

1.502 1.012  1.302 1.022  1.202 1.022  .27

APPLIED EXAMPLE 2 Income Distributions A study was conducted in a large metropolitan area to determine the annual incomes of married couples in which the husbands were the sole providers and of those in which the husbands and wives were both employed. Table 2 gives the results of this study. TABLE 2 Annual Family Income, $

150,000 and over 100,000–149,999 75,000–99,999 50,000–74,999 30,000–49,999 Under 30,000

Married Couples, %

Income Group with Both Spouses Working, %

4 10 21 24 30 11

65 73 68 63 43 28

a. What is the probability that a couple selected at random from this area has two incomes? b. If a randomly chosen couple has two incomes, what is the probability that the annual income of this couple is $150,000 or more? c. If a randomly chosen couple has two incomes, what is the probability that the annual income of this couple is greater than $49,999?

P(A) = .04

.65

A

P(B) = .10

P(C) = .21

P(D) = .24

P(E) = .30

P(F) = .11

FIGURE 12

T Tc

.35 .73

T

.27 .68

T

.32

Tc

B

C .63

D

Tc

T Tc

.37 .43

T

.57

Tc

E .28

T

.72

Tc

F

Solution Let A denote the event that the annual income of the couple is $150,000 or more; let B denote the event that the annual income is between $100,000 and $149,999; let C denote the event that the annual income is between $75,000 and $99,999; and so on. Finally, let T denote the event that both spouses work. The probabilities of the occurrence of these events are displayed in Figure 12.

a. The probability that a couple selected at random from this group has two incomes is given by P1T2  P1A2 # P1T 0 A2  P1B2 # P1T 0 B2  P1C2 # P1T 0 C2  P1D2 # P1T 0 D2  P1E2 # P1T 0 E2  P1F2 # P1T 0 F2  1.042 1.65 2  1.102 1.732  1.212 1.682  1.242 1.632  1.302 1.432  1.112 1.282  .5528

488

8 ADDITIONAL TOPICS IN PROBABILITY

b. Using the results of part (a) and Bayes’ theorem, we find that the probability that a randomly chosen couple has an annual income of $150,000 or more, given that both spouses are working, is P1A 0 T2 

P1A2 # P1T 0 A2 P1T2



1.042 1.652 .5528

 .047

c. The probability that a randomly chosen couple has an annual income greater than $49,999, given that both spouses are working, is P1A 0 T2  P1B 0 T2  P1C 0 T2  P1D 0 T2 P1A2 # P1T 0 A2  P1B2 # P1T 0 B2  P1C2 # P1T 0 C2  P1D2 # P1T 0 D2  P1T2 1.042 1.652  1.12 1.732  1.212 1.682  1.24 2 1.632  .5528  .711

8.3 Self-Check Exercises 1. The accompanying tree diagram represents a two-stage experiment. Use the diagram to find P(B  D). 1 3

D

A 1 4 1 2

2 3

Dc 1 2

D

1 2

Dc

B

1 4

1 4

D

3 4

Dc

C

2. In a recent presidential election, it was estimated that the probability that the Republican candidate would be elected was 35 and therefore the probability that the Democratic candidate would be elected was 25 (the two Independent candidates were given little chance of being elected). It was also estimated that if the Republican candidate were elected, then the probability that research for a new manned bomber would continue was 45. But if the Democratic candidate were successful, then the probability that the research would continue was 103 . Research was terminated shortly after the successful presidential candidate took office. What is the probability that the Republican candidate won that election? Solutions to Self-Check Exercises 8.3 can be found on page 494.

8.3 Concept Questions 1. What are a priori probabilities and a posteriori probabilities? Give an example of each.

mula for the a posteriori probability P1A 0 E2 . (Assume P(A), P(B), P(C)  0.)

2. Suppose the events A, B, and C form the partition of a sample space S, and suppose E is an event of an experiment such that P(E)  0. Use Bayes’ theorem to write the for-

3. Refer to Question 2. If E is the event that a product was produced in factory A, factory B, or factory C and P(E)  0, what does P1A 0 E2 represent?

8.3 BAYES’ THEOREM

489

8.3 Exercises In Exercises 1–3, refer to the accompanying Venn diagram. An experiment in which the three mutually exclusive events A, B, and C form a partition of the uniform sample space S is depicted in the diagram. A

B

C

8. The accompanying tree diagram represents a two-stage experiment. Use the diagram to find a. P1A2 # P1D 0 A2 b. P1B2 # P1D 0 B2 c. P1A 0 D2

S

.7

D

A .35

20

15

25

b. P1B 0 D c 2

.4

B

C

1 4

20

1 3 1 2

S

3 4

1 2

Dc

1 3

D

2 3

Dc

20

5. Find: a. P(D)

b. P1B 0 D 2

6. Find: a. P(D c )

b. P1B 0 D c 2

.2

.25



P1A  D2 P1D2

P1A2 # P1D 0 A2

P1A2 # P1D 0 A2  P1B2 # P1D 0 B2  P1C2 # P1D 0 C2 1 2

1 5

Dc D

D

A

D

A .8

10. The accompanying tree diagram represents a two-stage experiment. Use this diagram to find a. P(A  D) b. P(B  D) c. P(C  D) d. P(D) e. Verify: P1A 0 D2 

7. The accompanying tree diagram represents a two-stage experiment. Use the diagram to find a. P1A2 # P1D 0 A2 b. P1B2 # P1D 0 B2 c. P1A 0 D2

.6

D

C

4. Using the information given in the Venn diagram, draw a tree diagram illustrating the probabilities of the events A, B, C, and D.

.4

Dc 1 2

B

1 6

15

20

25

D

A

D 25

Dc

9. The accompanying tree diagram represents a two-stage experiment. Use the diagram to find a. P1A2 # P1D 0 A2 b. P1B2 # P1D 0 B2 # c. P1C 2 P1D 0 C 2 d. P1A 0 D2

In Exercises 4–6, refer to the accompanying Venn diagram. An experiment in which the three mutually exclusive events A, B, and C form a partition of the uniform sample space S is depicted in the diagram. A

D

B

b. P1A 0 D 2

3. Find: a. P(D )

Dc

.6

.65

20

1. Using the information given in the Venn diagram, draw a tree diagram illustrating the probabilities of the events A, B, C, and D.

c

.3

10

10

2. Find: a. P(D)

D

2 5

1 2

Dc 1 3

D

2 3

Dc

B

2 5

3 4

D

1 4

Dc

C

B .75

Dc

490

8 ADDITIONAL TOPICS IN PROBABILITY

In Exercises 11–14, refer to the following experiment: Two cards are drawn in succession without replacement from a standard deck of 52 cards.

11. What is the probability that the first card is a heart given that the second card is a heart? 12. What is the probability that the first card is a heart given that the second card is a diamond? 13. What is the probability that the first card is a jack given that the second card is an ace? 14. What is the probability that the first card is a face card given that the second card is an ace? In Exercises 15–18, refer to the following experiment: Urn A contains four white and six black balls. Urn B contains three white and five black balls. A ball is drawn from urn A and then transferred to urn B. A ball is then drawn from urn B.

15. Represent the probabilities associated with this two-stage experiment in the form of a tree diagram. 16. What is the probability that the transferred ball was white given that the second ball drawn was white? 17. What is the probability that the transferred ball was black given that the second ball drawn was white? 18. What is the probability that the transferred ball was black given that the second ball drawn was black? 19. POLITICS The 1992 U.S. Senate was composed of 57 Democrats and 43 Republicans. Of the Democrats, 38 served in the military, whereas 28 of the Republicans had seen military service. If a senator selected at random had served in the military, what is the probability that he or she was Republican? 20. RETIREMENT NEEDS In a survey of 2000 adults 50 yr and older of whom 60% were retired and 40% were preretired, the following question was asked: Do you expect your income needs to vary from year to year in retirement? Of those who were retired, 33% answered no, and 67% answered yes. Of those who were pre-retired, 28% answered no, and 72% answered yes. If a respondent in the survey was selected at random and had answered yes to the question, what is the probability that he or she was retired? Source: Sun Life Financial

21. An experiment consists of randomly selecting one of three coins, tossing it, and observing the outcome—heads or tails. The first coin is a two-headed coin, the second is a biased coin such that P(H)  .75, and the third is a fair coin. a. What is the probability that the coin that is tossed will show heads? b. If the coin selected shows heads, what is the probability that this coin is the fair coin?

22. SEAT-BELT COMPLIANCE Data compiled by the Highway Patrol Department regarding the use of seat belts by drivers in a certain area after the passage of a compulsory seat-belt law are shown in the accompanying table.

Drivers Group I (using seat belts) Group II (not using seat belts)

Percent of Drivers in Group

Percent of Group Stopped for Moving Violation

64

.2

36

.5

If a driver in that area is stopped for a moving violation, what is the probability that he or she a. Will have a seat belt on? b. Will not have a seat belt on? 23. BLOOD TESTS If a certain disease is present, then a blood test will reveal it 95% of the time. But the test will also indicate the presence of the disease 2% of the time when in fact the person tested is free of that disease; that is, the test gives a false positive 2% of the time. If 0.3% of the general population actually has the disease, what is the probability that a person chosen at random from the population has the disease given that he or she tested positive? 24. OPINION POLLS In a survey to determine the opinions of Americans on health insurers, 400 baby boomers and 600 pre-boomers were asked this question: Do you believe that insurers are very responsible for high health costs? Of the baby boomers, 212 answered in the affirmative, whereas 198 of the pre-boomers answered in the affirmative. If a respondent chosen at random from those surveyed answered the question in the affirmative, what is the probability that he or she is a baby boomer? A pre-boomer? Source: GfK Roper Consulting

25. QUALITY CONTROL A halogen desk lamp produced by Luminar was found to be defective. The company has three factories where the lamps are manufactured. The percentage of the total number of halogen desk lamps produced by each factory and the probability that a lamp manufactured by that factory is defective are shown in the accompanying table. What is the probability that the defective lamp was manufactured in factory III?

Factory I II III

Percent of Total Production 35 35 30

Probability of Defective Component .015 .01 .02

26. OPINION POLLS A survey involving 400 likely Democratic voters and 300 likely Republican voters asked the question: Do you support or oppose legislation that would require registration of all handguns? The following results were obtained:

8.3 BAYES’ THEOREM Answer Support Oppose Don’t know/refused

Democrats, % 77 14 9

Republicans, % 59 31 10

If a randomly chosen respondent in the survey answered “oppose,” what is the probability that he or she is a likely Democratic voter? 27. AGE DISTRIBUTION OF RENTERS A study conducted by the Metro Housing Agency in a midwestern city revealed the following information concerning the age distribution of renters within the city. Age 21–44 45–64 65 and over

Adult Population, % 51 31 18

Group Who Are Renters, % 58 45 60

a. What is the probability that an adult selected at random from this population is a renter? b. If a renter is selected at random, what is the probability that he or she is in the 21–44 age bracket? c. If a renter is selected at random, what is the probability that he or she is 45 yr of age or older? 28. PRODUCT RELIABILITY The estimated probability that a brand-A, a brand-B, and a brand-C plasma TV will last at least 30,000 hr is .90, .85, and .80, respectively. Of the 4500 plasma TVs that Ace TV sold in a certain year, 1000 were brand A, 1500 were brand B, and 2000 were brand C. If a plasma TV set sold by Ace TV that year is selected at random and is still working after 30,000 hr of use a. What is the probability that it was a brand-A TV? b. What is the probability that it was not a brand-A TV? 29. OPINION POLLS A survey involving 400 likely Democratic voters and 300 likely Republican voters asked the question: Do you support or oppose legislation that would require trigger locks on guns, to prevent misuse by children? The following results were obtained: Answer Support Oppose Don’t know/refused

Democrats, % 88 7 5

Republicans, % 71 20 9

If a randomly chosen respondent in the survey answered “support,” what is the probability that he or she is a likely Republican voter? 30. QUALITY CONTROL Jansen Electronics has four machines that produce an identical component for use in its DVD players. The proportion of the components produced by each machine and the probability of that component being defective are shown in the accompanying table. What is the probability that a component selected at random

491

a. Is defective? b. Was produced by machine I, given that it is defective? c. Was produced by machine II, given that it is defective?

Machine I II III IV

Proportion of Components Produced .15 .30 .35 .20

Probability of Defective Component .04 .02 .02 .03

31. CRIME RATES Data compiled by the Department of Justice on the number of people arrested in a certain year for serious crimes (murder, forcible rape, robbery, and so on) revealed that 89% were male and 11% were female. Of the males, 30% were under 18, whereas 27% of the females arrested were under 18. a. What is the probability that a person arrested for a serious crime in that year was under 18? b. If a person arrested for a serious crime in that year is known to be under 18, what is the probability that the person is female? Source: Department of Justice

32. RELIABILITY OF MEDICAL TESTS A medical test has been designed to detect the presence of a certain disease. Among those who have the disease, the probability that the disease will be detected by the test is .95. However, the probability that the test will erroneously indicate the presence of the disease in those who do not actually have it is .04. It is estimated that 4% of the population who take this test have the disease. a. If the test administered to an individual is positive, what is the probability that the person actually has the disease? b. If an individual takes the test twice and both times the test is positive, what is the probability that the person actually has the disease? (Assume that the tests are independent.) 33. RELIABILITY OF MEDICAL TESTS Refer to Exercise 32. Suppose 20% of the people who were referred to a clinic for the test did in fact have the disease. If the test administered to an individual from this group is positive, what is the probability that the person actually has the disease? 34. GENDER GAP A study of the faculty at U.S. medical schools in 2006 revealed that 32% of the faculty were women and 68% were men. Of the female faculty, 31% were full/associate professors, 47% were assistant professors, and 22% were instructors. Of the male faculty, 51% were full/associate professors, 37% were assistant professors, and 12% were instructors. If a faculty member at a U.S. medical school selected at random holds the rank of full/associate professor, what is the probability that she is female? Source: Association of American Medical Colleges

492

8 ADDITIONAL TOPICS IN PROBABILITY

35. BEVERAGE RESEARCH In a study of the scientific research on soft drinks, juices, and milk, 50 studies were fully sponsored by the food industry, and 30 studies were conducted with no corporate ties. Of those that were fully sponsored by the food industry, 14% of the participants found the products unfavorable, 23% were neutral, and 63% found the products favorable. Of those that had no industry funding, 38% found the products unfavorable, 15% were neutral, and 47% found the products favorable. a. What is the probability that a participant selected at random found the products favorable? b. If a participant selected at random found the product favorable, what is the probability that he or she belongs to a group that participated in a corporate-sponsored study? Source: Children’s Hospital, Boston

36. SELECTION OF SUPREME COURT JUDGES In a past presidential election, it was estimated that the probability that the Republican candidate would be elected was 53, and therefore the probability that the Democratic candidate would be elected was 52 (the two Independent candidates were given no chance of being elected). It was also estimated that if the Republican candidate were elected, the probability that a conservative, moderate, or liberal judge would be appointed to the Supreme Court (one retirement was expected during the presidential term) was 21, 31, and 16, respectively. If the Democratic candidate were elected, the probabilities that a conservative, moderate, or liberal judge would be appointed to the Supreme Court would be 81, 38, and 12, respectively. A conservative judge was appointed to the Supreme Court during the presidential term. What is the probability that the Democratic candidate was elected? 37. PERSONNEL SELECTION Applicants for temporary office work at Carter Temporary Help Agency who have successfully completed a typing test are then placed in suitable positions by Nancy Dwyer and Darla Newberg. Employers who hire temporary help through the agency return a card indicating satisfaction or dissatisfaction with the work performance of those hired. From past experience it is known that 80% of the employees placed by Nancy are rated as satisfactory, and 70% of those placed by Darla are rated as satisfactory. Darla places 55% of the temporary office help at the agency and Nancy the remaining 45%. If a Carter office worker is rated unsatisfactory, what is the probability that he or she was placed by Darla? 38. MEDICAL RESEARCH Based on data obtained from the National Institute of Dental Research, it has been determined that 42% of 12-yr-olds have never had a cavity, 34% of 13-yr-olds have never had a cavity, and 28% of 14-yrolds have never had a cavity. Suppose a child is selected at random from a group of 24 junior high school students that includes six 12-yr-olds, eight 13-yr-olds, and ten 14-yrolds. If this child does not have a cavity, what is the probability that this child is 14 yrs old? Source: National Institute of Dental Research

39. VOTING PATTERNS In a recent senatorial election, 50% of the voters in a certain district were registered as Demo-

crats, 35% were registered as Republicans, and 15% were registered as Independents. The incumbent Democratic senator was reelected over her Republican and Independent opponents. Exit polls indicated that she gained 75% of the Democratic vote, 25% of the Republican vote, and 30% of the Independent vote. Assuming that the exit poll is accurate, what is the probability that a vote for the incumbent was cast by a registered Republican? 40. AUTO-ACCIDENT RATES An insurance company has compiled the accompanying data relating the age of drivers and the accident rate (the probability of being involved in an accident during a 1-yr period) for drivers within that group: Percent of Insured Drivers 16 40 30 14

Age Group Under 25 25–44 45–64 65 and over

Accident Rate, % 5.5 2.5 2 4

What is the probability that an insured driver selected at random a. Will be involved in an accident during a particular 1-yr period? b. Who is involved in an accident is under 25? 41. PERSONAL HABITS There were 80 male guests at a party. The number of men in each of four age categories is given in the following table. The table also gives the probability that a man in the respective age category will keep his paper money in order of denomination. Age 21–34 35–44 45–54 55 and over

Men 25 30 15 10

Keep Paper Money in Order, % 9 61 80 80

A man’s wallet was retrieved and the paper money in it was kept in order of denomination. What is the probability that the wallet belonged to a male guest between the ages of 35 and 44? 42. VOTER TURNOUT BY INCOME Voter turnout drops steadily as income level declines. The following table gives the percent of eligible voters in a certain city, categorized by income, who responded with “did not vote” in the 2000 presidential election. The table also gives the number of eligible voters in the city, categorized by income. Income (percentile) 0–16 17–33 34–67 68–95 96–100

Percent Who “Did Not Vote” 52 31 30 14 12

Eligible Voters 4,000 11,000 17,500 12,500 5,000

493

8.3 BAYES’ THEOREM

If an eligible voter from this city who had voted in the election is selected at random, what is the probability that this person had an income in the 17–33 percentile? Source: The National Election Studies

43. THE SOCIAL LADDER The following table summarizes the results of a poll conducted with 1154 adults.

Annual Household Income, $ Less than 15,000 15,000–29,999 30,000–49,999 50,000–74,999 75,000 and higher

Respondents within That Income Range, % 11.2 18.6 24.5 21.9 23.8

Respondents Who Call Themselves Middle Rich, % Class, % Poor, % 0 24 76 3 60 37 0 86 14 2 90 8 5 91 4

a. What is the probability that a respondent chosen at random calls himself or herself middle class? b. If a randomly chosen respondent calls himself or herself middle class, what is the probability that the annual household income of that individual is between $30,000 and $49,999, inclusive? c. If a randomly chosen respondent calls himself or herself middle class, what is the probability that the individual’s income is either less than or equal to $29,999 or greater than or equal to $50,000? Source: New York Times/CBS News; Wall Street Journal Almanac

44. OBESITY IN CHILDREN Researchers weighed 1976 3-yr-olds from low-income families in 20 U.S. cities. Each child is classified by race (white, black, or Hispanic) and by weight (normal weight, overweight, or obese). The results are tabulated as follows:

Race White Black Hispanic

Children 406 1081 489

Weight, % Normal Weight Overweight 68 18 68 15 56 20

Obese 14 17 24

If a participant in the research is selected at random and is found to be obese, what is the probability that the 3-yr-old is white? Hispanic?

What is the probability that a. A student selected at random from the freshman class is a female? b. A business student selected at random from the freshman class is a male? c. A female student selected at random from the freshman class is majoring in business? 46. VOTER TURNOUT BY PROFESSION The following table gives the percent of eligible voters grouped according to profession who responded with “voted” in the 2000 presidential election. The table also gives the percent of people in a survey categorized by their profession.

Major Business Humanities Education Social science Natural sciences Other

Freshmen Choosing This Major, % 24 8 8 7

Females, % 38 60 66 58

Males, % 62 40 34 42

9 44

52 48

48 52

Percent in Each Profession 12 24 32 10 8 14

If an eligible voter who participated in the survey and voted in the election is selected at random, what is the probability that this person is a housewife? Source: The National Election Studies

47. MEDICAL DIAGNOSES A study was conducted among a certain group of union members whose health insurance policies required second opinions prior to surgery. Of those members whose doctors advised them to have surgery, 20% were informed by a second doctor that no surgery was needed. Of these, 70% took the second doctor’s opinion and did not go through with the surgery. Of the members who were advised to have surgery by both doctors, 95% went through with the surgery. What is the probability that a union member who had surgery was advised to do so by a second doctor? 48. SMOKING AND EDUCATION According to the Centers for Disease Control and Prevention, the percentage of adults 25 yr and older who smoke, by educational level, is as follows:

Source: American Journal of Public Health

45. COLLEGE MAJORS The Office of Admissions and Records of a large western university released the accompanying information concerning the contemplated majors of its freshman class:

Percent Who Voted 84 73 66 57 68 66

Profession Professionals White collar Blue collar Unskilled Farmers Housewives

Educational Level Respondents, %

High No GED school diploma diploma graduate 26

43

25

UnderSome graduate Graduate college level degree 23

10.7

7

In a group of 140 people, there were 8 with no diploma, 14 with GED diplomas, 40 high school graduates, 24 with some college, 42 with an undergraduate degree, and 12 with a graduate degree. (Assume that these categories are mutually exclusive.) If a person selected at random from this group was a smoker, what is the probability that he or she is a person with a graduate degree? Source: Centers for Disease Control and Preventions

494

8 ADDITIONAL TOPICS IN PROBABILITY

8.3 Solutions to Self-Check Exercises 1. Using the probabilities given in the tree diagram and Bayes’ theorem, we have P1B | D2  

P1B2 # P1D | B2

1 14 2 1 13 2



1 12 2 1 12 2



1 14 2 1 14 2



12 19

2. Let R and D, respectively, denote the event that the Republican and the Democratic candidate won the presidential election. Then, P1R2  35 and P1D2  25. Also, let C denote the event that research for the new manned bomber continued. These data may be exhibited as in the accompanying tree diagram:

C

1 5

Cc

3 10

C

7 10

Cc

R

3 5

P1A2 # P1D | A 2  P1B2 # P1D | B2  P1C 2 # P1D | C2 1 12 2 1 12 2

4 5

2 5

D

Using Bayes’ theorem, we find that the probability that the Republican candidate had won the election is given by P1R 0 C c 2  

P1R2 # P1C c 0 R2

P1R2 # P1C c 0 R2  P1D 2 # P1C c 0 D2 1 35 2 1 15 2

1 35 2 1 15 2



1 25 2 1 107 2



3 10

8.4 Distributions of Random Variables Random Variables In many situations, it is desirable to assign numerical values to the outcomes of an experiment. For example, if an experiment consists of rolling a die and observing the face that lands uppermost, then it is natural to assign the numbers 1, 2, 3, 4, 5, and 6, respectively, to the outcomes one, two, three, four, five, and six of the experiment. If we let X denote the outcome of the experiment, then X assumes one of these numbers. Because the values assumed by X depend on the outcomes of a chance experiment, the outcome X is referred to as a random variable.

Random Variable

A random variable is a rule that assigns a number to each outcome of a chance experiment.

More precisely, a random variable is a function with domain given by the set of outcomes of a chance experiment and range contained in the set of real numbers. EXAMPLE 1 A coin is tossed three times. Let the random variable X denote the number of heads that occur in the three tosses. a. List the outcomes of the experiment; that is, find the domain of the function X. b. Find the value assigned to each outcome of the experiment by the random variable X. c. Find the event comprising the outcomes to which a value of 2 has been assigned by X. This event is written (X  2) and is the event consisting of the outcomes in which two heads occur.

8.4 DISTRIBUTIONS OF RANDOM VARIABLES

495

TABLE 3

Solution

Number of Heads in Three Coin Tosses

a. From the results of Example 3, Section 7.5 (page 433), we see that the set of outcomes of the experiment is given by the sample space

Outcome

Value of X

HHH HHT HTH THH HTT THT TTH TTT

3 2 2 2 1 1 1 0

TABLE 4 Number of Coin Tosses before Heads Appear

Outcome

Value of Y

H TH TTH TTTH TTTTH

1 2 3 4 5

o

o

S  {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

b. The outcomes of the experiment are displayed in the first column of Table 3. The corresponding value assigned to each such outcome by the random variable X (the number of heads) appears in the second column. c. With the aid of Table 3, we see that the event (X  2) is given by the set {HHT, HTH, THH}

EXAMPLE 2 A coin is tossed repeatedly until a head occurs. Let the random variable Y denote the number of coin tosses in the experiment. What are the values of Y? Solution

The outcomes of the experiment make up the infinite set S  {H, TH, TTH, TTTH, TTTTH, . . .}

These outcomes of the experiment are displayed in the first column of Table 4. The corresponding values assumed by the random variable Y (the number of tosses) appear in the second column. APPLIED EXAMPLE 3 Product Reliability A disposable flashlight is turned on until its battery runs out. Let the random variable Z denote the length (in hours) of the life of the battery. What values may Z assume? The value of Z may be any nonnegative real number; that is, the possible values of Z comprise the interval 0 Z . Solution

One advantage of working with random variables—rather than working directly with the outcomes of an experiment—is that random variables are functions that may be added, subtracted, and multiplied. Because of this, results developed in the field of algebra and other areas of mathematics may be used freely to help us solve problems in probability and statistics. A random variable is classified into three categories depending on the set of values it assumes. A random variable is called finite discrete if it assumes only finitely many values. For example, the random variable X of Example 1 is finite discrete because it may assume values only from the finite set of numbers {0, 1, 2, 3}. Next, a random variable is said to be infinite discrete if it takes on infinitely many values, which may be arranged in a sequence. For example, the random variable Y of Example 2 is infinite discrete because it assumes values from the set {1, 2, 3, 4, 5, . . .}, which has been arranged in the form of an infinite sequence. Finally, a random variable is called continuous if the values it may assume comprise an interval of real numbers. For example, the random variable Z of Example 3 is continuous because the values it may assume comprise the interval of nonnegative real numbers. For the remainder of this section, unless otherwise noted, all random variables will be assumed to be finite discrete.

Probability Distributions of Random Variables In Section 7.6, we learned how to construct the probability distribution for an experiment. There, the probability distribution took the form of a table that gave the probabilities associated with the outcomes of an experiment. Since the random variable associated with an experiment is related to the outcomes of the experi-

496

8 ADDITIONAL TOPICS IN PROBABILITY

TABLE 5 Probability Distribution for the Random Variable X

x

P(X ⫽ x)

x1 x2 x3

p1 p2 p3

o

xn

o

pn

ment, it is clear that we should be able to construct a probability distribution associated with the random variable rather than one associated with the outcomes of the experiment. Such a distribution is called the probability distribution of a random variable and may be given in the form of a formula or displayed in a table that gives the distinct (numerical) values of the random variable X and the probabilities associated with these values. Thus, if x1, x2, . . . , xn are the values assumed by the random variable X with associated probabilities P(X  x1), P(X  x2), . . . , P(X  xn), respectively, then the required probability distribution of the random variable X may be expressed in the form of the table shown in Table 5, where pi  P(X  xi), i  1, 2, . . . , n. In the next several examples, we illustrate the construction of probability distributions. EXAMPLE 4 Find the probability distribution of the random variable associated with the experiment of Example 1. Solution From the results of Example 1, we see that the values assumed by the random variable X are 0, 1, 2, and 3, corresponding to the events of 0, 1, 2, and 3 heads occurring, respectively. Referring to Table 3 once again, we see that the outcome associated with the event (X  0) is given by the set {TTT}. Consequently, the probability associated with the random variable X when it assumes the value 0 is given by

TABLE 6 Probability Distribution

x

P(X ⫽ x)

0

1 8 3 8 3 8 1 8

1 2 3

P1X  02 

1 8

Note that n(S)  8.

Next, observe that the event (X  1) is given by the set {HTT, THT, TTH}, so P1X  12 

3 8

In a similar manner, we may compute P(X  2) and P(X  3), which gives the probability distribution shown in Table 6. TABLE 7 x

2 3 4 5 6 7 8 9 10 11 12

P(X ⫽ x) 1 36 2 36 3 36 4 36 5 36 6 36 5 36 4 36 3 36 2 36 1 36

EXAMPLE 5 Let X denote the random variable that gives the sum of the faces that fall uppermost when two fair dice are rolled. Find the probability distribution of X. The values assumed by the random variable X are 2, 3, 4, . . . , 12, corresponding to the events E2, E3, E4, . . . , E12 (see Example 4, Section 7.5). The probabilities associated with the random variable X when X assumes the values 2, 3, 4, . . . , 12 are precisely the probabilities P(E2), P(E3), . . . , P(E12), respectively, and may be computed in much the same way as the solution to Example 3, Section 7.6. Thus,

Solution

P1X  22  P1E2 2 

1 36 2 P1X  32  P1E3 2  36

and so on. The required probability distribution of X is given in Table 7. APPLIED EXAMPLE 6 Waiting Lines The following data give the number of cars observed waiting in line at the beginning of 2-minute intervals between 3 p.m. and 5 p.m. on a certain Friday at the drive-in teller of Westwood Savings Bank and the corresponding frequency of occurrence. Find the

8.4 DISTRIBUTIONS OF RANDOM VARIABLES

497

probability distribution of the random variable X, where X denotes the number of cars observed waiting in line.

TABLE 8 Probability Distribution

x

P(X ⫽ x)

0 1 2 3 4 5 6 7 8

.03 .15 .27 .20 .13 .10 .07 .03 .02

Cars

0

1

2

3

4

5

6

7

8

Frequency of Occurrence

2

9

16

12

8

6

4

2

1

Solution Dividing each number in the last row of the given table by 60 (the sum of these numbers) gives the respective probabilities associated with the random variable X when X assumes the values 0, 1, 2, . . . , 8. (Here, we use the relative frequency interpretation of probability.) For example,

P1X  0 2 

2  .03 60 9 P1X  1 2   .15 60

and so on. The resulting probability distribution is shown in Table 8. 4/8

Histograms

3/8

A probability distribution of a random variable may be exhibited graphically by means of a histogram. To construct a histogram of a particular probability distribution, first locate the values of the random variable on a number line. Then, above each such number, erect a rectangle with width 1 and height equal to the probability associated with that value of the random variable. For example, the histogram of the probability distribution appearing in Table 6 is shown in Figure 13. The histograms of the probability distributions of Examples 5 and 6 are constructed in a similar manner and are displayed in Figures 14 and 15, respectively.

2/8 1/8 x 0

1

2

3

FIGURE 13 Histogram showing the probability distribution for the number of heads occurring in three coin tosses

6/36 5/36 4/36 3/36 2/36 FIGURE 14 Histogram showing the probability distribution for the sum of the uppermost faces of two dice

1/36 x 2

3

4

5

6

7

8

9 10 11 12

0.3

0.2

0.1 FIGURE 15 Histogram showing the probability distribution for the number of cars waiting in line

x 0

1

2

3

4

5

6

7

8

498

8 ADDITIONAL TOPICS IN PROBABILITY

Observe that in each histogram, the area of a rectangle associated with a value of a random variable X gives precisely the probability associated with the value of X. This follows because each such rectangle, by construction, has width 1 and height corresponding to the probability associated with the value of the random variable. Another consequence arising from the method of construction of a histogram is that the probability associated with more than one value of the random variable X is given by the sum of the areas of the rectangles associated with those values of X. For example, in the coin-tossing experiment of Example 1, the event of obtaining at least two heads, which corresponds to the event (X  2) or (X  3), is given by P(X  2)  P(X  3)

and may be obtained from the histogram depicted in Figure 13 by adding the areas associated with the values 2 and 3 of the random variable X. We obtain 3 1 1 P1X  22  P1X  32  112 a b  112 a b  8 8 2

This result provides us with a method of computing the probabilities of events directly from the knowledge of a histogram of the probability distribution of the random variable associated with the experiment. EXAMPLE 7 Suppose the probability distribution of a random variable X is represented by the histogram shown in Figure 16. Identify that part of the histogram whose area gives the probability P(10 X 20).

FIGURE 16

x 8

9

10 11 12 13 14 15 16 17 18 19 20 21 22

The event (10 X 20) is the event consisting of outcomes related to the values 10, 11, 12, . . . , 20 of the random variable X. The probability of this event P(10 X 20) is therefore given by the shaded area of the histogram in Figure 17. Solution

FIGURE 17

P(10 X 20)

x 8

9

10 11 12 13 14 15 16 17 18 19 20 21 22

499

8.4 DISTRIBUTIONS OF RANDOM VARIABLES

8.4 Self-Check Exercises 1. Three balls are selected at random without replacement from an urn containing four black balls and five white balls. Let the random variable X denote the number of black balls drawn. a. List the outcomes of the experiment. b. Find the value assigned to each outcome of the experiment by the random variable X. c. Find the event consisting of the outcomes to which a value of 2 has been assigned by X. 2. The following data, extracted from the records of Dover Public Library, give the number of books borrowed by the library’s members over a 1-mo period:

Books Frequency of Occurrence

0

1

2

3

4

5

6

7

8

780

300

412

205

98

54

57

30

6

a. Find the probability distribution of the random variable X, where X denotes the number of books checked out over a 1-mo period by a randomly chosen member. b. Draw the histogram representing this probability distribution. Solutions to Self-Check Exercises 8.4 can be found on page 501.

8.4 Concept Questions 1. What is a random variable? Give an example. 2. Give an example of (a) a finite discrete random variable, (b) an infinite discrete random variable, and (c) a continuous random variable.

3. Suppose you are given the probability distribution for a random variable X. Explain how you would construct a histogram for this probability distribution. What does the area of each rectangle in the histogram represent?

8.4 Exercises 1. Three balls are selected at random without replacement from an urn containing four green balls and six red balls. Let the random variable X denote the number of green balls drawn. a. List the outcomes of the experiment. b. Find the value assigned to each outcome of the experiment by the random variable X. c. Find the event consisting of the outcomes to which a value of 3 has been assigned by X. 2. A coin is tossed four times. Let the random variable X denote the number of tails that occur. a. List the outcomes of the experiment. b. Find the value assigned to each outcome of the experiment by the random variable X. c. Find the event consisting of the outcomes to which a value of 2 has been assigned by X. 3. A die is rolled repeatedly until a 6 falls uppermost. Let the random variable X denote the number of times the die is rolled. What are the values that X may assume? 4. Cards are selected one at a time without replacement from a well-shuffled deck of 52 cards until an ace is drawn. Let X denote the random variable that gives the number of cards drawn. What values may X assume? 5. Let X denote the random variable that gives the sum of the faces that fall uppermost when two fair dice are rolled. Find P(X  7).

6. Two cards are drawn from a well-shuffled deck of 52 playing cards. Let X denote the number of aces drawn. Find P(X  2). In Exercises 7–12, give the range of values that the random variable X may assume and classify the random variable as finite discrete, infinite discrete, or continuous.

7. X  The number of times a die is thrown until a 2 appears 8. X  The number of defective watches in a sample of eight watches 9. X  The distance in miles a commuter travels to work 10. X  The number of hours a child watches television on a given day 11. X  The number of times an accountant takes the CPA examination before passing 12. X  The number of boys in a four-child family 13. The probability distribution of the random variable X is shown in the accompanying table: x P(X  x)

10 .20

Find a. P(X  10) c. P(5 X 5)

5 .15

0 .05

5 .1

b. P(X  5) d. P(X 20)

10 .25

15 .1

20 .15

500

8 ADDITIONAL TOPICS IN PROBABILITY

14. The probability distribution of the random variable X is shown in the accompanying table: 5 .17

x P(X  x)

3 .13

2 .33

Find a. P(X 0) c. P(2 X 2)

0 .16

2 .11

3 .10

b. P(X 3)

15. Suppose that the probability distribution of a random variable X is represented by the accompanying histogram. Shade that part of the histogram whose area gives the probability P(17 X 20).

a. Find the probability distribution of the random variable X, where X denotes the number of persons in a randomly chosen family. b. Draw the histogram corresponding to the probability distribution found in part (a). 19. WAITING LINES The accompanying data were obtained in a study conducted by the manager of SavMore Supermarket. In this study, the number of customers waiting in line at the express checkout at the beginning of each 3-min interval between 9 a.m. and 12 noon on Saturday was observed. Customers Frequency of Occurrence Customers Frequency of Occurrence

x 12 13 14 15 16 17 18 19 20

16. EXAMS An examination consisting of ten true-or-false questions was taken by a class of 100 students. The probability distribution of the random variable X, where X denotes the number of questions answered correctly by a randomly chosen student, is represented by the accompanying histogram. The rectangle with base centered on the number 8 is missing. What should be the height of this rectangle? .25 .20 .15

0

1

2

3

4

1

4

2

7

14

5

6

7

8

9

10

8

10

6

3

4

1

a. Find the probability distribution of the random variable X, where X denotes the number of customers observed waiting in line. b. Draw the histogram representing the probability distribution. 20. MONEY MARKET RATES The interest rates paid by 30 financial institutions on a certain day for money market deposit accounts are shown in the accompanying table: Rate, % Institutions

6 1

Rate, % Institutions

6.58 1

6.25 7 6.60 8

6.55 7

6.56 1

6.65 3

6.85 2

.10

Let the random variable X denote the interest rate paid by a randomly chosen financial institution on its money market deposit accounts and find the probability distribution associated with these data.

.05 x 0

1

2

3

4

5

6

7

8

9

10

17. Two dice are rolled. Let the random variable X denote the number that falls uppermost on the first die, and let Y denote the number that falls uppermost on the second die. a. Find the probability distributions of X and Y. b. Find the probability distribution of X  Y. 18. DISTRIBUTION OF FAMILIES BY SIZE A survey of 1000 families was conducted by the Public Housing Authority in a certain community to determine the distribution of families by size. The results follow: Family Size Frequency of Occurrence

2

3

4

5

6

7

8

350

200

245

125

66

10

4

21. TELEVISION PILOTS After the private screening of a new television pilot, audience members were asked to rate the new show on a scale of 1 to 10 (10 being the highest rating). From a group of 140 people, the following responses were obtained: Rating Frequency of Occurrence

1

2

3

4

5

6

7

8

9

10

1

4

3

11

23

21

28

29

16

4

Let the random variable X denote the rating given to the show by a randomly chosen audience member. Find the probability distribution associated with these data.

8.4 DISTRIBUTIONS OF RANDOM VARIABLES

501

22. U.S. POPULATION BY AGE The following table gives the 2002 age distribution of the U.S. population:

In Exercises 23 and 24, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

Group 1 2 3 4 5 6 Age (in years) Under 5 5–19 20–24 25–44 45–64 65 and over Number (in thousands) 19,527 59,716 18,611 83,009 66,088 33,590

23. Suppose X is a finite discrete random variable assuming the values x1, x2, . . . , xn and associated probabilities p1, p2, . . . , pn. Then p1  p2      pn  1.

Let the random variable X denote a randomly chosen age group within the population. Find the probability distribution associated with these data.

24. The area of a histogram associated with a probability distribution is a number between 0 and 1.

Source: U.S. Census Bureau

8.4 Solutions to Self-Check Exercises 1. a. Using the accompanying tree diagram, we see that the outcomes of the experiment are S  {BBB, BBW, BWB, BWW, WBB, WBW, WWB, WWW}

2. a. We divide each number in the bottom row of the given table by 1942 (the sum of these numbers) to obtain the probabilities associated with the random variable X when X takes on the values 0, 1, 2, 3, 4, 5, 6, 7, and 8. For example,

Outcomes B

780  .402 1942

P1X  12 

300  .154 1942

BBB

B B

P1X  0 2 

W B

BBW BWB

W

BWW

B

WBB

x P(X  x)

0 .402

1 .154

2 .212

3 .106

W B

WBW WWB

x P(X  x)

5 .028

6 .029

7 .015

8 .003

W

WWW

The required probability distribution and histogram follow.

W

B W W

b.

b. Using the results of part (a), we obtain the values assigned to the outcomes of the experiment as follows: Outcome Value

BBB 3

BBW 2

BWB 2

BWW 1

Outcome Value

WBB 2

WBW 1

WWB 1

WWW 0

c. The required event is {BBW, BWB, WBB}.

.4 .3 .2 .1 x 0 1 2 3 4 5 6 7 8

4 .050

502

8 ADDITIONAL TOPICS IN PROBABILITY

USING

TECHNOLOGY

Graphing a Histogram Graphing Utility

A graphing utility can be used to plot the histogram for a given set of data, as illustrated by the following example. APPLIED EXAMPLE 1 A survey of 90,000 households conducted in 1995 revealed the following percentage of women who wear a shoe size within the given ranges. Shoe Size Women, %

5

5–512

6–612

7–712

8–812

9–912

10–1012

1012

1

5

15

27

29

14

7

2

Source: Footwear Market Insights survey

Let X denote the random variable taking on the values 1 through 8, where 1 corresponds to a shoe size less than 5, 2 corresponds to a shoe size of 5–512, and so on. a. Plot a histogram for the given data. b. What percent of women in the survey wear a shoe size within the ranges 7–712 or 8–812? Solution

a. Enter the values of X as x1  1, x2  2, . . . , x8  8 and the corresponding values of Y as y1  1, y2  5, . . . , y8  2. Then using the DRAW function from the Statistics menu, we draw the histogram shown in Figure T1.

FIGURE T1 The histogram for the given data, using the viewing window [0, 9]  [0, 35]

b. The probability that a woman participating in the survey wears a shoe size within the ranges 7–712 or 8–812 is given by P(X  4)  P(X  5)  .27  .29  .56

This tells us that 56% of the women wear a shoe size within the ranges 7–712 or 8–812 shoes. Excel

Excel can be used to plot the histogram for a given set of data, as illustrated by the following example. APPLIED EXAMPLE 2 A survey of 90,000 households conducted in 1995 revealed the following percentage of women who wear a shoe size within the given ranges. Shoe Size Women, %

5

5–512

6–612

7–712

8–812

9–912

10–1012

1012

1

5

15

27

29

14

7

2

Source: Footwear Market Insights survey

8.4 DISTRIBUTIONS OF RANDOM VARIABLES

A 1

B

X

503

Let X denote the random variable taking on the values 1 through 8, where 1 corresponds to a shoe size less than 5, 2 corresponds to a shoe size of 5–512, and so on.

C

Frequency Probability

a. Plot a histogram for the given data. b. What percent of women in the survey wear a shoe size within the ranges 7–712 or 8–812 shoes?

2

1

1

0.01

3

2

5

0.05

4

3

15

0.15

5

4

27

0.27

Solution

6

5

29

0.29

7

6

14

0.14

8

7

7

0.07

9

8

2

0.02

a. Enter the given data in columns A and B onto a spreadsheet, as shown in Figure T2. Highlight the data in column B and select from the toolbar. The sum of the numbers in this column (100) will appear in cell B10. In cell C2, type =B2/100 and then press Enter . To extend the formula to cell C9, move the pointer to the small black box at the lower right corner of cell C2. Drag the black  that appears (at the lower right corner of cell C2) through cell C9 and then release it. The probability distribution shown in cells C2 to C9 will then appear on your spreadsheet. Then highlight the data in the Probability column and select Chart Wizard from the toolbar. Select Column under Chart type: and click Next twice. Under the Titles tab, enter Histogram, X, and Probability in the appropriate boxes. Under the Legend tab, click the Show legend box to delete the check mark. Then click Finish . The histogram shown in Figure T3 will appear.

10

100

FIGURE T2 Completed spreadsheet for Example 2

Histogram 0.35

Probability

0.3 0.25 0.2 0.15 0.1 0.05

FIGURE T3

0

The histogram for the random variable X

1

2

3

4

5

6

7

8

X

b. The probability that a woman participating in the survey wears a shoe size within the ranges 7–712 or 8–812 is given by P(X  4)  P(X  5)  .27  .29  .56

This tells us that 56% of the women wear a shoe size within the ranges 7–712 or 8–812. Note: Boldfaced words/characters enclosed in a box (for example, Enter ) indicate an action (click, select, or press) is required. Words/characters printed blue (for example, Chart sub-type:) indicate words/characters that appear on the screen. Words/characters printed in a typewriter font (for example, =(—2/3)*A2+2) indicates words/characters that need to be typed and entered).

TECHNOLOGY EXERCISES 1. Graph the histogram associated with the data given in Table 3, page 495. Compare your graph with that given in Figure 13, page 497. 2. Graph the histogram associated with the data given in Exercise 18, page 500.

3. Graph the histogram associated with the data given in Exercise 19, page 500. 4. Graph the histogram associated with the data given in Exercise 21, page 500.

504

8 ADDITIONAL TOPICS IN PROBABILITY

8.5 Expected Value Mean The average value of a set of numbers is a familiar notion to most people. For example, to compute the average of the four numbers 12, 16, 23, 37

we simply add these numbers and divide the resulting sum by 4, giving the required average as 88 12  16  23  37   22 4 4 In general, we have the following definition.

Average, or Mean

The average, or mean, of the n numbers x1, x2, . . . , xn

is x (read “x bar”), where x

TABLE 9 Cars

Frequency of Occurrence

0 1 2 3 4 5 6 7 8

2 9 16 12 8 6 4 2 1

x1  x2  p  xn n

APPLIED EXAMPLE 1 Waiting Times Refer to Example 6, Section 8.4. Find the average number of cars waiting in line at the bank’s drive-in teller at the beginning of each 2-minute interval during the period in question. The number of cars, together with its corresponding frequency of occurrence, are reproduced in Table 9. Observe that the number 0 (of cars) occurs twice, the number 1 occurs 9 times, and so on. There are altogether Solution

2  9  16  12  8  6  4  2  1  60

numbers to be averaged. Therefore, the required average is given by

10 # 22  11 # 92  12 # 162  13 # 122  14 # 82  15 # 62  16 # 42  17 # 22  18 # 12 60

 3.1

(10)

or approximately 3.1 cars.

Expected Value Let’s reconsider the expression on the left-hand side of Equation (10), which gives the average of the frequency distribution shown in Table 9. Dividing each term by the denominator, the expression may be rewritten in the form 0# a

2 9 16 12 8 6 b 1# a b 2# a b 3# a b 4# a b 5# a b 60 60 60 60 60 60 4 2 1 6# a b 7# a b 8# a b 60 60 60

8.5 EXPECTED VALUE

505

Observe that each term in the sum is a product of two factors; the first factor is the value assumed by the random variable X, where X denotes the number of cars waiting in line, and the second factor is just the probability associated with that value of the random variable. This observation suggests the following general method for calculating the expected value (that is, the average or mean) of a random variable X that assumes a finite number of values from the knowledge of its probability distribution.

Expected Value of a Random Variable X

Let X denote a random variable that assumes the values x1, x2, . . . , xn with associated probabilities p1, p2, . . . , pn, respectively. Then the expected value of X, denoted by E(X), is given by E(X)  x1p1  x2 p2  . . .  xn pn (11)

Note The numbers x1, x2, . . . , xn may be positive, zero, or negative. For example, such a number might be positive if it represents a profit and negative if it represents a loss. TABLE 10 Probability Distribution

x

P(X ⫽ x)

0 1 2 3 4 5 6 7 8

.03 .15 .27 .20 .13 .10 .07 .03 .02

APPLIED EXAMPLE 2 Waiting Times Re-solve Example 1 by using the probability distribution associated with the experiment, which is reproduced in Table 10. Solution Let X denote the number of cars waiting in line. Then the average number of cars waiting in line is given by the expected value of X—that is, by

E1X2  102 10.32  112 1.152  122 1.272  132 1.202  142 1.132  152 1.102  162 1.072  172 1.032  182 1.022

 3.1 cars

which agrees with the earlier result. The expected value of a random variable X is a measure of the central tendency of the probability distribution associated with X. In repeated trials of an experiment with random variable X, the average of the observed values of X gets closer and closer to the expected value of X as the number of trials gets larger and larger. Geometrically, the expected value of a random variable X has the following simple interpretation: If a laminate is made of the histogram of a probability distribution associated with a random variable X, then the expected value of X corresponds to the point on the base of the laminate at which the laminate will balance perfectly when the point is directly over a fulcrum (Figure 18).

E(X )

x FIGURE 18 Expected value of a random variable X

506

8 ADDITIONAL TOPICS IN PROBABILITY

EXAMPLE 3 Let X denote the random variable that gives the sum of the faces that fall uppermost when two fair dice are rolled. Find the expected value, E(X), of X. Solution The probability distribution of X, reproduced in Table 11, was found in Example 5, Section 8.4. Using this result, we find

E1X2  2 a

1 2 3 4 5 6 b  3a b  4a b  5a b  6a b  7a b 36 36 36 36 36 36 5 4 3 2 1  8 a b  9 a b  10 a b  11 a b  12 a b 36 36 36 36 36 7

TABLE 11 Probability Distribution

x

P(X ⫽ x)

2

1 36 2 36 3 36 4 36 5 36 6 36 5 36 4 36 3 36 2 36 1 36

3 4 5 6 7 8 9 10 11 12

Note that, because of the symmetry of the histogram of the probability distribution with respect to the vertical line x  7, the result could have been obtained by merely inspecting Figure 19. 6/36 5/36 4/36 3/36 2/36 1/36 x 2

3

4

5

6

7

8

9 10 11 12

FIGURE 19 Histogram showing the probability distribution for the sum of the uppermost faces of two dice

The next example shows how we can use the concept of expected value to help us make the best investment decision. APPLIED EXAMPLE 4 Expected Profit A private equity group intends to purchase one of two motels currently being offered for sale in a certain city. The terms of sale of the two motels are similar, although the Regina Inn has 52 rooms and is in a slightly better location than the Merlin Motor Lodge, which has 60 rooms. Records obtained for each motel reveal that the occupancy rates, with corresponding probabilities, during the May–September tourist season are as shown in the following tables. Regina Inn

Occupancy Rate

.80

.85

.90

.95

1.00

Probability

.19

.22

.31

.23

.05

Occupancy Rate

.75

.80

.85

.90

.95

1.00

Probability

.35

.21

.18

.15

.09

.02

Merlin Motor Lodge

The average profit per day for each occupied room at the Regina Inn is $20, whereas the average profit per day for each occupied room at the Merlin Motor Lodge is $18.

8.5 EXPECTED VALUE

507

a. Find the average number of rooms occupied per day at each motel. b. If the investors’ objective is to purchase the motel that generates the higher daily profit, which motel should they purchase? (Compare the expected daily profit of the two motels.) Solution

a. Let X denote the occupancy rate at the Regina Inn. Then the average daily occupancy rate at the Regina Inn is given by the expected value of X—that is, by E1X2  1.802 1.19 2  1.852 1.222  1.902 1.312  1.952 1.232  11.002 1.052  .8865

The average number of rooms occupied per day at the Regina is (.8865)(52)  46.1

or approximately 46.1 rooms. Similarly, letting Y denote the occupancy rate at the Merlin Motor Lodge, we have E1Y2  1.752 1.352  1.802 1.212  1.852 1.182  1.902 1.152  1.952 1.092  11.002 1.022  .8240

The average number of rooms occupied per day at the Merlin is (.8240)(60)  49.4

or approximately 49.4 rooms. b. The expected daily profit at the Regina is given by (46.1)(20)  922

or $922. The expected daily profit at the Merlin is given by (49.4)(18)  889

or $889. From these results we conclude that the private equity group should purchase the Regina Inn, which is expected to yield a higher daily profit. APPLIED EXAMPLE 5 Raffles The Island Club is holding a fundraising raffle. Ten thousand tickets have been sold for $2 each. There will be a first prize of $3000, 3 second prizes of $1000 each, 5 third prizes of $500 each, and 20 consolation prizes of $100 each. Letting X denote the net winnings (that is, winnings less the cost of the ticket) associated with a ticket, find E(X). Interpret your results. The values assumed by X are (0  2), (100  2), (500  2), (1000  2), and (3000  2)—that is, 2, 98, 498, 998, and 2998—which correspond, respectively, to the value of a losing ticket, a consolation prize, a third prize, and so on. The probability distribution of X may be calculated in the usual manner and appears in Table 12. Using the table, we find

Solution

TABLE 12 Probability Distribution for a Raffle

x

P(X ⫽ x)

2 98 498 998 2998

.9971 .0020 .0005 .0003 .0001

E1X2  122 1.99712  981.00202  4981.00052  9981.00032  29981.00012  0.95

This expected value gives the long-run average loss (negative gain) of a holder of one ticket; that is, if one participated in such a raffle by purchasing one ticket each time, in the long run, one may expect to lose, on the average, 95 cents per raffle.

508

8 ADDITIONAL TOPICS IN PROBABILITY

APPLIED EXAMPLE 6 Roulette In the game of roulette as played in Las Vegas casinos, the wheel is divided into 38 compartments numbered 1 through 36, 0, and 00. One-half of the numbers 1 through 36 are red, the other half black, and 0 and 00 are green (Figure 20). Of the many types of bets that may be placed, one type involves betting on the outcome of the color of the winning number. For example, one may place a certain sum of money on red. If the winning number is red, one wins an amount equal to the bet placed and the amount of the bet is returned; otherwise, one loses the amount of the bet. Find the expected value of the winnings on a $1 bet placed on red.

FIGURE 20 Roulette wheel

Let X be a random variable whose values are 1 and 1, which correspond to a win and a loss. The probabilities associated with the values 1 and 1 18 are 38 and 20 38 , respectively. Therefore, the expected value is given by Solution

E1X 2  1 a

18 20 2 b  112 a b   38 38 38  0.053

Thus, if one places a $1 bet on red over and over again, one may expect to lose, on the average, approximately 5 cents per bet in the long run. Examples 5 and 6 illustrate games that are not “fair.” Of course, most participants in such games are aware of this fact and participate in them for other reasons. In a fair game, neither party has an advantage, a condition that translates into the condition that E(X )  0, where X takes on the values of a player’s winnings. APPLIED EXAMPLE 7 Fair Games Mike and Bill play a card game with a standard deck of 52 cards. Mike selects a card from a well-shuffled deck and receives A dollars from Bill if the card selected is a diamond; otherwise, Mike pays Bill a dollar. Determine the value of A if the game is to be fair. Let X denote a random variable whose values are associated with Mike’s winnings. Then X takes on the value A with probability P(X  A)  14 (since there are 13 diamonds in the deck) if Mike wins and takes on the value 1 with probability P(X  1)  34 if Mike loses. Since the game is to be a fair one, the expected value E(X ) of Mike’s winnings must be equal to zero; that is, Solution

1 3 E1X2  A a b  112 a b  0 4 4

Solving this equation for A gives A  3. Thus, the card game will be fair if Bill makes a $3 payoff when a diamond is drawn.

8.5 EXPECTED VALUE

509

Odds In everyday parlance, the probability of the occurrence of an event is often stated in terms of the odds in favor of (or odds against) the occurrence of the event. For example, one often hears statements such as “the odds that the Dodgers will win the World Series this season are 7 to 5” and “the odds that it will not rain tomorrow are 3 to 2.” We will return to these examples later. But first, let us look at a definition that ties together these two concepts.

Odds in Favor Of and Odds Against

If P(E ) is the probability of an event E occurring, then 1. The odds in favor of E occurring are P1E2 1  P1E2



P1E2

P1Ec 2

3P1E2  14

(12a)

3P1E2  04

(12b)

2. The odds against E occurring are 1  P1E2 P1E2



P1Ec 2 P1E2

Notes

1. The odds in favor of the occurrence of an event are given by the ratio of the probability of the event occurring to the probability of the event not occurring. The odds against the occurrence of an event are given by the reciprocal of the odds in favor of the occurrence of the event. 2. Whenever possible, odds are expressed as ratios of whole numbers. If the odds in favor of E are ab, we say the odds in favor of E are a to b. If the odds against E occurring are ba , we say the odds against E are b to a. APPLIED EXAMPLE 8 Roulette Find the odds in favor of winning a bet on red in American roulette. What are the odds against winning a bet on red? Solution The probability of winning a bet here—the probability that the ball lands in a red compartment—is given by P  18 38 . Therefore, using Formula (12a), we see that the odds in favor of winning a bet on red are

P1E2 1  P1E2

 

18 38

1  18 38

E, event of winning a bet on red

18 38 38  18 38

18 # 38 38 20 18 9   20 10 

or 9 to 10. Next, using (12b), we see that the odds against winning a bet on red are 109, or 10 to 9.

510

8 ADDITIONAL TOPICS IN PROBABILITY

PORTFOLIO

Ann-Marie Martz

G

fK ARBOR, LLC is a fullservice, custom marketing research and consulting firm. We develop and apply advanced research methodologies and analyses to a wide array of marketing and marketing research problems. We have provided services to many of the largest corporations in the United States as well as many other countries around the world across a wide array of industries. Statistics play a big part in helping our clients find solutions to their marketing problems. A manufacturer of a brand of juice wanted to know how its brand was performing overall and how various factors in the marketplace were affecting consumers’ perceptions and usage of its brand as well as the juice category overall. This manufacturer was beginning a new advertising campaign, introducing new packaging and flavors, and had reduced the juice content of its product. A year-long tracking study was conducted over the Internet with a sample of juice users. Consumers were asked their opinions, perceptions, and consumption of various brands of juice.

Using statistics, we were able to determine with certainty whether the juice brand’s overall performance had improved or declined over time. Opinion ratings and brand awareness as well as consumption levels from before the new advertising campaign, packaging, flavors, and product formulation occurred were compared to levels after these events. Oftentimes we see movement or change over time, but these changes or differences must be statistically significant for us to say there has in fact been a change. The information obtained from this research gave the juice manufacturer direction for future advertising and the ability to tailor its advertising to include elements that appeal to consumers and motivate them to purchase this particular brand of juice. The manufacturer was able to make informed decisions about whether or not to continue with the new packaging and flavors and whether modifications were needed. We were able to determine that the reduced juice content did not have detrimental effects on consumer opinions or consumption of the brand.

© Victorio Castellani/Alamy

TITLE Senior Project Director INSTITUTION GfK ARBOR

Now, suppose the odds in favor of the occurrence of an event are a to b. Then, (12a) gives P1E2 a  b 1  P1E2 a31  P1E2 4  bP1E2 Cross-multiply. a  aP1E2  bP1E2 a  1a  b2P1E2 a P1E2  ab which leads us to the following result. Probability of an Event (Given the Odds)

If the odds in favor of an event E occurring are a to b, then the probability of E occurring is a P1E2  (13) ab Formula (13) is often used to determine subjective probabilities, as the next example shows.

8.5 EXPECTED VALUE

511

EXAMPLE 9 Consider each of the following statements. a. “The odds that the Dodgers will win the World Series this season are 7 to 5.” b. “The odds that it will not rain tomorrow are 3 to 2.” Express each of these odds as a probability of the event occurring. Solution

a. Using Formula (13) with a  7 and b  5 gives the required probability as 7 7   .5833 75 12

b. Here, the event is that it will not rain tomorrow. Using Formula (13) with a  3 and b  2, we conclude that the probability that it will not rain tomorrow is 3 3   .6 32 5

Explore & Discuss In the movie Casino, the executive of the Tangiers Casino, Sam Rothstein (Robert DeNiro), fired the manager of the slot machines in the casino after three gamblers hit three “million dollar” jackpots in a span of 20 minutes. Rothstein claimed that it was a scam and that somebody had gotten into those machines to set the wheels. He was especially annoyed at the slot machine manager’s assertion that there was no way to determine this. According to Rothstein the odds of hitting a jackpot in a four-wheel machine is 1 in 112 million, and the probability of hitting three jackpots in a row is “in the billions.” “It cannot happen! It will not happen!” To see why Rothstein was so indignant, find the odds of hitting the jackpots in three of the machines in quick succession and comment on the likelihood of this happening.

Median and Mode In addition to the mean, there are two other measures of central tendency of a group of numerical data: the median and the mode of a group of numbers.

Median

The median of a group of numbers arranged in increasing or decreasing order is (a) the middle number if there is an odd number of entries or (b) the mean of the two middle numbers if there is an even number of entries. APPLIED EXAMPLE 10 Commuting Times a. The times, in minutes, Susan took to go to work on nine consecutive working days were 46

42

49

40

52

48

45

43

50

What is the median of her morning commute times? b. The times, in minutes, Susan took to return home from work on eight consecutive working days were 37

36

39

37

34

38

41

What is the median of her evening commute times?

40

512

8 ADDITIONAL TOPICS IN PROBABILITY

Solution

a. Arranging the numbers in increasing order, we have 40

42

43

45

46

48

49

50

52

Here we have an odd number of entries with the middle number equal to 46, and this gives the required median. b. Arranging the numbers in increasing order, we have 34

36

37

37

38

39

40

41

Here the number of entries is even, and the required median is 37  38  37.5 2

Mode

The mode of a group of numbers is the number in the group that occurs most frequently.

Note

A group of numerical data may have no mode, a unique mode, or more than one mode. EXAMPLE 11 Find the mode, if there is one, of the given group of numbers. a. 1, 2, 3, 4, 6

b. 2, 3, 3, 4, 6, 8

c. 2, 3, 3, 3, 4, 4, 4, 8

Solution

a. The set has no mode because there isn’t a number that occurs more frequently than the others. b. The mode is 3 because it occurs more frequently than the others. c. The modes are 3 and 4 because each number occurs three times. Of the three measures of central tendency of a group of numerical data, the mean is by far the most suitable in work that requires mathematical computations.

8.5 Self-Check Exercises 1. Find the expected value of a random variable X having the following probability distribution: x P(X  x)

4 .10

3 .20

1 .25

0 .10

1 .25

2 .10

2. The developer of Shoreline Condominiums has provided the following estimate of the probability that 20, 25, 30, 35, 40, 45, or 50 of the townhouses will be sold within the first month they are offered for sale.

Units Probability

20 .05

25 .10

30 .30

35 .25

40 .15

45 .10

50 .05

How many townhouses can the developer expect to sell within the first month they are put on the market? Solutions to Self-Check Exercises 8.5 can be found on page 516.

8.5 EXPECTED VALUE

513

8.5 Concept Questions 1. What is the expected value of a random variable? Give an example. 2. What is a fair game? Is the game of roulette as played in American casinos a fair game? Why?

3. a. If the probability of an event E occurring is P(E), what are the odds in favor of E occurring? b. If the odds in favor of an event occurring are a to b, what is the probability of E occurring?

8.5 Exercises 1. During the first year at a university that uses a 4-point grading system, a freshman took ten 3-credit courses and received two As, three Bs, four Cs, and one D. a. Compute this student’s grade-point average. b. Let the random variable X denote the number of points corresponding to a given letter grade. Find the probability distribution of the random variable X and compute E(X), the expected value of X. 2. Records kept by the chief dietitian at the university cafeteria over a 30-wk period show the following weekly consumption of milk (in gallons). Milk Weeks

200 3

205 4

210 6

215 5

Milk Weeks

225 3

230 2

235 2

240 1

220 4

3. Find the expected value of a random variable X having the following probability distribution: 5 .12

1 .16

0 .28

1 .22

0 .07

x (in $) P(X  x)

100 .28

5 .12

8 .10

4. Find the expected value of a random variable X having the following probability distribution: x

0

1

2

3

4

5

P(X  x)

1 8

1 4

3 16

1 4

1 16

1 8

5. The daily earnings X of an employee who works on a commission basis are given by the following probability distribution. Find the employee’s expected earnings.

25 .12

50 .17

125 .18

75 .14

150 .04

6. In a four-child family, what is the expected number of boys? (Assume that the probability of a boy being born is the same as the probability of a girl being born.) 7. Based on past experience, the manager of the VideoRama Store has compiled the following table, which gives the probabilities that a customer who enters the VideoRama Store will buy 0, 1, 2, 3, or 4 DVDs. How many DVDs can a customer entering this store be expected to buy? DVDs Probability

a. Find the average number of gallons of milk consumed per week in the cafeteria. b. Let the random variable X denote the number of gallons of milk consumed in a week at the cafeteria. Find the probability distribution of the random variable X and compute E(X ), the expected value of X.

x P(X  x)

x (in $) P(X  x)

0 .42

1 .36

2 .14

3 .05

4 .03

8. If a sample of three batteries is selected from a lot of ten, of which two are defective, what is the expected number of defective batteries? 9. AUTO ACCIDENTS The number of accidents that occur at a certain intersection known as “Five Corners” on a Friday afternoon between the hours of 3 p.m. and 6 p.m., along with the corresponding probabilities, are shown in the following table. Find the expected number of accidents during the period in question. Accidents Probability

0 .935

1 .030

2 .020

3 .010

4 .005

10. EXPECTED DEMAND The owner of a newsstand in a college community estimates the weekly demand for a certain magazine as follows: Quantity Demanded Probability

10 .05

11 .15

12 .25

13 .30

14 .20

15 .05

Find the number of issues of the magazine that the newsstand owner can expect to sell per week.

514

8 ADDITIONAL TOPICS IN PROBABILITY

11. EXPECTED PRODUCT RELIABILITY A bank has two automatic tellers at its main office and two at each of its three branches. The number of machines that break down on a given day, along with the corresponding probabilities, are shown in the following table. Machines That Break Down Probability

0 .43

1 .19

2 .12

3 .09

Machines That Break Down Probability

5 .03

6 .03

7 .02

8 .05

4 .04

12. EXPECTED SALES The management of the Cambridge Company has projected the sales of its products (in millions of dollars) for the upcoming year, with the associated probabilities shown in the following table: 20 .05

22 .10

24 .35

26 .30

28 .15

30 .05

What does the management expect the sales to be next year? 13. INTEREST-RATE PREDICTION A panel of 50 economists was asked to predict the average prime interest rate for the upcoming year. The results of the survey follow: Interest Rate, % Economists

4.9 3

5.0 8

5.1 12

5.2 14

5.3 8

5.4 5

Based on this survey, what does the panel expect the average prime interest rate to be next year? 14. UNEMPLOYMENT RATES A panel of 64 economists was asked to predict the average unemployment rate for the upcoming year. The results of the survey follow: Unemployment Rate, % Economists

4.5 2

4.6 4

4.7 8

4.8 20

4.9 14

5.0 12

18. LIFE INSURANCE POLICIES As a fringe benefit, Dennis Taylor receives a $25,000 life insurance policy from his employer. The probability that Dennis will live another year is .9935. If he purchases the same coverage for himself, what is the minimum amount that he can expect to pay for the policy? 19. EXPECTED PROFIT Max built a spec house at a cost of $450,000. He estimates that he can sell the house for $580,000, $570,000, or $560,000, with probabilities .24, .40, and .36, respectively. What is Max’s expected profit?

Find the expected number of machines that will break down on a given day.

Sales Probability

17. LIFE INSURANCE PREMIUMS A woman purchased a $10,000, 1-yr term-life insurance policy for $130. Assuming that the probability that she will live another year is .992, find the company’s expected gain.

5.1 4

Based on this survey, what does the panel expect the average unemployment rate to be next year? 15. LOTTERIES In a lottery, 5000 tickets are sold for $1 each. One first prize of $2000, 1 second prize of $500, 3 third prizes of $100, and 10 consolation prizes of $25 are to be awarded. What are the expected net earnings of a person who buys one ticket? 16. LIFE INSURANCE PREMIUMS A man wishes to purchase a 5-yr term-life insurance policy that will pay the beneficiary $20,000 in the event that the man’s death occurs during the next 5 yr. Using life insurance tables, he determines that the probability that he will live another 5 yr is .96. What is the minimum amount that he can expect to pay for his premium? Hint: The minimum premium occurs when the insurance company’s expected profit is zero.

20. INVESTMENT ANALYSIS The proprietor of Midland Construction Company has to decide between two projects. He estimates that the first project will yield a profit of $180,000 with a probability of .7 or a profit of $150,000 with a probability of .3; the second project will yield a profit of $220,000 with a probability of .6 or a profit of $80,000 with a probability of .4. Which project should the proprietor choose if he wants to maximize his expected profit? 21. CABLE TELEVISION The management of MultiVision, a cable TV company, intends to submit a bid for the cable television rights in one of two cities, A or B. If the company obtains the rights to city A, the probability of which is .2, the estimated profit over the next 10 yr is $10 million; if the company obtains the rights to city B, the probability of which is .3, the estimated profit over the next 10 yr is $7 million. The cost of submitting a bid for rights in city A is $250,000 and that in city B is $200,000. By comparing the expected profits for each venture, determine whether the company should bid for the rights in city A or city B. 22. EXPECTED AUTO SALES Roger Hunt intends to purchase one of two car dealerships currently for sale in a certain city. Records obtained from each of the two dealers reveal that their weekly volume of sales, with corresponding probabilities, are as follows: Dahl Motors

Cars Sold/Week Probability

5 .05

6 .09

7 .14

8 .24

Cars Sold/Week Probability

9 .18

10 .14

11 .11

12 .05

Farthington Auto Sales

Cars Sold/Week Probability

5 .08

6 .21

7 .31

8 .24

9 .10

10 .06

The average profit/car at Dahl Motors is $362, and the average profit/car at Farthington Auto Sales is $436. a. Find the average number of cars sold each week at each dealership. b. If Roger’s objective is to purchase the dealership that generates the higher weekly profit, which dealership should he purchase? (Compare the expected weekly profit for each dealership.)

8.5 EXPECTED VALUE

23. EXPECTED HOME SALES Sally Leonard, a real estate broker, is relocating in a large metropolitan area where she has received job offers from realty company A and realty company B. The number of houses she expects to sell in a year at each firm and the associated probabilities are shown in the following tables. Company A

Houses Sold Probability

12 .02

13 .03

14 .05

15 .07

16 .07

Houses Sold Probability

17 .16

18 .17

19 .13

20 .11

Houses Sold Probability

21 .09

22 .06

23 .03

24 .01

Company B

Houses Sold Probability

6 .01

7 .04

8 .07

9 .06

10 .11

Houses Sold Probability

11 .12

12 .19

13 .17

14 .13

Houses Sold Probability

15 .04

16 .03

17 .02

18 .01

The average price of a house in the locale of company A is $308,000, whereas the average price of a house in the locale of company B is $474,000. If Sally will receive a 3% commission on sales at both companies, which job offer should she accept to maximize her expected yearly commission? 24. INVESTMENT ANALYSIS Bob, the proprietor of Midway Lumber, bases his projections for the annual revenues of the company on the performance of the housing market. He rates the performance of the market as very strong, strong, normal, weak, or very weak. For the next year, Bob estimates that the probabilities for these outcomes are .18, .27, .42, .10, and .03, respectively. He also thinks that the revenues corresponding to these outcomes are $20, $18.8, $16.2, $14, and $12 million, respectively. What is Bob’s expected revenue for next year? 25. REVENUE PROJECTION Maria sees the growth of her business for the upcoming year as being tied to the gross domestic product (GDP). She believes that her business will grow (or contract) at the rate of 5%, 4.5%, 3%, 0%, or 0.5% per year if the GDP grows (or contracts) at the rate of between 2 and 2.5%, between 1.5 and 2%, between 1 and 1.5%, between 0 and 1%, and between 1 and 0%, respectively. Maria has decided to assign a probability of .12, .24, .40, .20, and .04, respectively, to each outcome. At what rate does Maria expect her business to grow next year? 26. WEATHER PREDICTIONS Suppose the probability that it will rain tomorrow is .3. a. What are the odds that it will rain tomorrow? b. What are the odds that it will not rain tomorrow?

515

27. ROULETTE In American roulette, as described in Example 6, a player may bet on a split (two adjacent numbers). In this case, if the player bets $1 and either number comes up, the player wins $17 and gets his $1 back. If neither comes up, he loses his $1 bet. Find the expected value of the winnings on a $1 bet placed on a split. 28. ROULETTE If a player placed a $1 bet on red and a $1 bet on black in a single play in American roulette, what would be the expected value of his winnings? 29. ROULETTE In European roulette, the wheel is divided into 37 compartments numbered 1 through 36 and 0. (In American roulette there are 38 compartments numbered 1 through 36, 0, and 00.) Find the expected value of the winnings on a $1 bet placed on red in European roulette. 30. The probability of an event E occurring is .8. What are the odds in favor of E occurring? What are the odds against E occurring? 31. The probability of an event E not occurring is .6. What are the odds in favor of E occurring? What are the odds against E occurring? 32. The odds in favor of an event E occurring are 9 to 7. What is the probability of E occurring? 33. The odds against an event E occurring are 2 to 3. What is the probability of E not occurring? 34. ODDS Carmen, a computer sales representative, feels that the odds are 8 to 5 that she will clinch the sale of a minicomputer to a certain company. What is the (subjective) probability that Carmen will make the sale? 35. SPORTS Steffi feels that the odds in favor of her winning her tennis match tomorrow are 7 to 5. What is the (subjective) probability that she will win her match tomorrow? 36. SPORTS If a sports forecaster states that the odds of a certain boxer winning a match are 4 to 3, what is the (subjective) probability that the boxer will win the match? 37. ODDS Bob, the proprietor of Midland Lumber, feels that the odds in favor of a business deal going through are 9 to 5. What is the (subjective) probability that this deal will not materialize? 38. ROULETTE a. Show that, for any number c, E(cX )  cE(X)

b. Use this result to find the expected loss if a gambler bets $300 on red in a single play in American roulette. Hint: Use the results of Example 6.

39. EXAM SCORES In an examination given to a class of 20 students, the following test scores were obtained: 40

45

50

50

55

60

60

75

75

80

80

85

85

85

85

90

90

95

95

100

a. Find the mean (or average) score, the mode, and the median score. b. Which of these three measures of central tendency do you think is the least representative of the set of scores?

516

8 ADDITIONAL TOPICS IN PROBABILITY

40. WAGE RATES The frequency distribution of the hourly wage rates (in dollars) among blue-collar workers in a certain factory is given in the following table. Find the mean (or average) wage rate, the mode, and the median wage rate of these workers. Wage Rate Frequency

10.70 60

10.80 90

10.90 75

11.00 120

11.10 60

11.20 45

41. WAITING TIMES Refer to Example 6, Section 8.4. Find the median of the number of cars waiting in line at the bank’s drive-in teller at the beginning of each 2-min interval during the period in question. Compare you answer to the mean obtained in Example 1, Section 8.5. 42. SAN FRANCISCO WEATHER The normal daily minimum temperature in degrees Fahrenheit for the months of January through December in San Francisco follows: 46.2

48.4

48.6

49.2

50.7

52.5

53.1

54.2

55.8

54.8

51.5

47.2

Find the average and the median daily minimum temperature in San Francisco for these months. Source: San Francisco Convention and Visitors Bureau

43. WEIGHT OF POTATO CHIPS The weights, in ounces, of ten packages of potato chips are 16.1

16

15.8

16

15.9

16.1

15.9

16

16

16.2

Find the average and the median of these weights. 44. BOSTON WEATHER The relative humidity, in percent, in the morning for the months of January through December in Boston follows: 68

67

69

69

71

73

74

76

79

77

74

70

Find the average and the median of these humidity readings. Source: National Weather Service Forecast Office

In Exercises 45 and 46, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

45. A game between two persons is fair if the expected value to both persons is zero. 46. If the odds in favor of an event E occurring are a to b, then the probability of Ec occurring is b/(a  b).

8.5 Solutions to Self-Check Exercises 1. E1X 2  14 2 1.10 2  13 2 1.20 2  11 2 1.25 2  10 2 1.10 2  11 2 1.25 2  122 1.102

given by the expected value of X—that is, by E1X2  201.052  251.10 2  301.30 2  351.252  401.15 2  451.102  501.052

 0.8

2. Let X denote the number of townhouses that will be sold within 1 mo of being put on the market. Then, the number of townhouses the developer expects to sell within 1 mo is

 34.25

or 34 townhouses.

8.6 Variance and Standard Deviation Variance The mean, or expected value, of a random variable enables us to express an important property of the probability distribution associated with the random variable in terms of a single number. But the knowledge of the location, or central tendency, of a probability distribution alone is usually not enough to give a reasonably accurate picture of the probability distribution. Consider, for example, the two probability distributions whose histograms appear in Figure 21. Both distributions have the same expected value, or mean, of ␮  4 (the Greek letter ␮ is read “mu”). Note that the probability distribution with the histogram shown in Figure 21a is closely concentrated about its mean ␮, whereas the one with the histogram shown in Figure 21b is widely dispersed or spread about its mean.

517

8.6 VARIANCE AND STANDARD DEVIATION

␮= 4

␮= 4

x 0 1 (a)

FIGURE 21 The histograms of two probability distributions

2

3

4

5

6

x

7

0 (b)

1

2

3

4

5

6

7

As another example, suppose that Olivia has ten packages of brand A potato chips and ten packages of brand B potato chips. After carefully measuring the weights of each package, she obtains the following results: Weight in Ounces

Brand A

16.1

16

15.8

16

15.9

16.1

15.9

16

16

16.2

Brand B

16.3

15.7

15.8

16.2

15.9

16.1

15.7

16.2

16

16.1

In Example 3, we verify that the mean weights for each of the two brands is 16 ounces. However, a cursory examination of the data now shows that the weights of the brand B packages exhibit much greater dispersion about the mean than those of brand A. One measure of the degree of dispersion, or spread, of a probability distribution about its mean is given by the variance of the random variable associated with the probability distribution. A probability distribution with a small spread about its mean will have a small variance, whereas one with a larger spread will have a larger variance. Thus, the variance of the random variable associated with the probability distribution whose histogram appears in Figure 21a is smaller than the variance of the random variable associated with the probability distribution whose histogram is shown in Figure 21b (see Example 1). Also, as we will see in Example 3, the variance of the random variable associated with the weights of the brand A potato chips is smaller than that of the random variable associated with the weights of the brand B potato chips. We now define the variance of a random variable.

Variance of a Random Variable X

Suppose a random variable has the probability distribution x P(X  x)

x1 p1

x2 p2

x3

...

xn

p3

...

pn

and expected value E(X)  ␮

Then the variance of the random variable X is Var(X)  p1(x1  ␮)2  p2(x2  ␮)2  . . .  pn(xn  ␮)2

(14)

518

8 ADDITIONAL TOPICS IN PROBABILITY

Let’s look a little closer at Equation (14). First, note that the numbers x1  ␮, x2  ␮, . . . , xn  ␮

(15)

measure the deviations of x1, x2, . . . , xn from ␮, respectively. Thus, the numbers (x1  ␮)2, (x2  ␮)2, . . . , (xn  ␮)2

(16)

measure the squares of the deviations of x1, x2, . . . , xn from ␮, respectively. Next, by multiplying each of the numbers in (16) by the probability associated with each value of the random variable X, the numbers are weighted accordingly so that their sum is a measure of the variance of X about its mean. An attempt to define the variance of a random variable about its mean in a similar manner using the deviations in (15), rather than their squares, would not be fruitful since some of the deviations may be positive whereas others may be negative and hence (because of cancellations) the sum will not give a satisfactory measure of the variance of the random variable. EXAMPLE 1 Find the variance of the random variable X and of the random variable Y whose probability distributions are shown in the following table. These are the probability distributions associated with the histograms shown in Figure 21a–b. x

P(X  x)

y

P(Y  y)

1 2 3 4 5 6 7

.05 .075 .2 .375 .15 .1 .05

1 2 3 4 5 6 7

.2 .15 .1 .15 .05 .1 .25

Solution

The mean of the random variable X is given by mX  112 1.052  122 1.0752  132 1.22  142 1.3752  15 2 1.152  162 1.12  172 1.052 4

Therefore, using Equation (14) and the data from the probability distribution of X, we find that the variance of X is given by Var1X2  1.052 11  42 2  1.0752 12  42 2  1.22 13  42 2  1.3752 14  42 2  1.152 15  42 2  1.12 16  42 2  1.052 17  42 2  1.95

Next, we find that the mean of the random variable Y is given by mY  112 1.22  122 1.152  132 1.12  142 1.152  15 2 1.052  162 1.12  172 1.252 4

and so the variance of Y is given by Var1Y2  1.22 11  42 2  1.152 12  42 2  1.12 13  42 2  1.152 14  42 2  1.052 15  42 2  1.12 16  42 2  1.252 17  42 2  5.2

519

8.6 VARIANCE AND STANDARD DEVIATION

Note that Var(X) is smaller than Var(Y ), which confirms our earlier observations about the spread (or dispersion) of the probability distribution of X and Y, respectively.

Standard Deviation Because Equation (14), which gives the variance of the random variable X, involves the squares of the deviations, the unit of measurement of Var(X ) is the square of the unit of measurement of the values of X. For example, if the values assumed by the random variable X are measured in units of a gram, then Var(X) will be measured in units involving the square of a gram. To remedy this situation, one normally works with the square root of Var(X ) rather than Var(X ) itself. The former is called the standard deviation of X.

Standard Deviation of a Random Variable X

The standard deviation of a random variable X denoted ␴ (pronounced “sigma”), is defined by s  1Var1X2

 2p1 1x1  m2 2  p2 1x2  m2 2  p  pn 1xn  m2 2

(17)

where x1, x2, . . . , xn denote the values assumed by the random variable X and p1  P(X  x1), p2  P(X  x2), . . . , pn  P(X  xn). EXAMPLE 2 Find the standard deviations of the random variables X and Y of Example 1. From the results of Example 1, we have Var(X)  1.95 and Var(Y )  5.2. Taking their respective square roots, we have

Solution

sX   sY  

11.95 1.40 15.2 2.28

APPLIED EXAMPLE 3 Packaging Let X and Y denote the random variables whose values are the weights of the brand A and brand B potato chips, respectively (see page 517). Compute the means and standard deviations of X and Y and interpret your results. Solution The probability distributions of X and Y may be computed from the given data as follows:

Brand A

Brand B

x

Relative Frequency of Occurrence

P(X ⫽ x)

y

Relative Frequency of Occurrence

P(Y ⫽ y)

15.8 15.9 16.0 16.1 16.2

1 2 4 2 1

.1 .2 .4 .2 .1

15.7 15.8 15.9 16.0 16.1 16.2 16.3

2 1 1 1 2 2 1

.2 .1 .1 .1 .2 .2 .1

520

8 ADDITIONAL TOPICS IN PROBABILITY

Explore & Discuss

The means of X and Y are given by ␮X  (.1)(15.8)  (.2)(15.9)  (.4)(16.0)  (.2)(16.1)  (.1)(16.2)  16 ␮Y  (.2)(15.7)  (.1)(15.8)  (.1)(15.9)  (.1)(16.0)  (.2)(16.1)  (.2)(16.2)  (.1)(16.3)  16

A useful alternative formula for the variance is ␴ 2  E(X 2)  ␮2 where E(X 2) is the expected value of X 2. 1. Establish the validity of the formula. 2. Use the formula to verify the calculations in Example 3.

Therefore, Var(X)  (.1)(15.8  16)2  (.2)(15.9  16)2  (.4)(16  16)2  (.2)(16.1  16)2  (.1)(16.2  16)2  0.012 Var(Y )  (.2)(15.7  16)2  (.1)(15.8  16)2  (.1)(15.9  16)2  (.1)(16  16)2  (.2)(16.1  16)2  (.2)(16.2  16)2  (.1)(16.3  16)2  0.042

so the standard deviations are sX    sY   

1Var 1X2 10.012 0.11 1Var 1Y2 10.042 0.20

The mean of X and that of Y are both equal to 16. Therefore, the average weight of a package of potato chips of either brand is 16 ounces. However, the standard deviation of Y is greater than that of X. This tells us that the weights of the packages of brand B potato chips are more widely dispersed about the common mean of 16 than are those of brand A.

Explore & Discuss Suppose the mean weight of m packages of brand A potato chips is ␮1 and the standard deviation from the mean of their weight distribution is ␴1. Also suppose the mean weight of n packages of brand B potato chips is ␮2 and the standard deviation from the mean of their weight distribution is ␴2. 1. Show that the mean of the weights of packages of brand A and brand B combined is m

mm1  nm2 mn

2. If ␮1  ␮2, show that the standard deviation from the mean of the combined-weight distribution is sa

ms21  ns22 1/2 b mn

3. Refer to Example 3, page 519. Using the results of parts 1 and 2, find the mean and the standard deviation of the combined-weight distribution.

8.6 VARIANCE AND STANDARD DEVIATION

521

Chebychev’s Inequality The standard deviation of a random variable X may be used in statistical estimations. For example, the following result, derived by the Russian mathematician P. L. Chebychev (1821–1894), gives a bound on the proportion of the values of X lying within k standard deviations of the expected value of X.

Chebychev’s Inequality

Let X be a random variable with expected value ␮ and standard deviation ␴. Then the probability that a randomly chosen outcome of the experiment lies between ␮  k␴ and ␮  k␴ is at least 1  (1/k2); that is, P 1m  ks X m  ks2  1 

1 k2

(18)

To shed some light on this result, let’s take k  2 in Inequality (18) and compute ␮ − 2␴ ␮ − ␴ FIGURE 22

␮

P 1m  2s X m  2s2  1 

␮ + ␴ ␮ + 2␴

At least 75% of the outcomes fall within this interval

1 1  1   .75 22 4

This tells us that at least 75% of the outcomes of the experiment lie within 2 standard deviations of the mean (Figure 22). Taking k  3 in Inequality (18), we have P 1m  3s X m  3s2  1 

1 1 8   .89 2  1  3 9 9

This tells us that at least 89% of the outcomes of the experiment lie within 3 standard deviations of the mean (Figure 23). FIGURE 23 At least 89% of the outcomes fall within this interval

␮ − 3␴ ␮ − 2␴ ␮ − ␴

␮ ␮ + ␴ ␮ + 2␴ ␮ + 3␴

EXAMPLE 4 A probability distribution has a mean of 10 and a standard deviation of 1.5. Use Chebychev’s inequality to find a bound on the probability that an outcome of the experiment lies between 7 and 13. Solution Here, ␮  10 and ␴  1.5. To determine the value of k, note that ␮  k␴  7 and ␮  k␴  13. Substituting the appropriate values for ␮ and ␴, we find k  2. Using Chebychev’s Inequality (18), we see that a bound on the probability that an outcome of the experiment lies between 7 and 13 is given by

P 17 X 132  1  a 

1 b 22

3 4

—that is, at least 75%. The results of Example 4 tell us that at least 75% of the outcomes of the experiment lie between 10  2␴ and 10  2␴—that is, between 7 and 13.

Note

APPLIED EXAMPLE 5 Industrial Accidents Great Northwest Lumber Company employs 400 workers in its mills. It has been estimated that X, the random variable measuring the number of mill workers who have industrial

522

8 ADDITIONAL TOPICS IN PROBABILITY

accidents during a 1-year period, is distributed with a mean of 40 and a standard deviation of 6. Using Chebychev’s Inequality (18), find a bound on the probability that the number of workers who will have an industrial accident over a 1-year period is between 30 and 50, inclusive. Here, ␮  40 and ␴  6. We wish to estimate P(30 X 50). To use Chebychev’s Inequality (18), we first determine the value of k from the equation

Solution

␮  k␴  30 or

␮  k␴  50

Since ␮  40 and ␴  6 in this case, we see that k satisfies 40  6k  30

40  6k  50

and

from which we deduce that k  53. Thus, a bound on the probability that the number of mill workers who will have an industrial accident during a 1-year period is between 30 and 50 is given by P 130 X 502  1 

1 1 53 2 2

16 25



—that is, at least 64%.

8.6 Self-Check Exercises 1. Compute the mean, variance, and standard deviation of the random variable X with probability distribution as follows: x P(X  x)

4 .1

3 .1

1 .2

0 .3

2 .1

5 .2

2. James recorded the following travel times (the length of time in minutes it took him to drive to work) on 10 consecutive days:

55

50

52

48

50

52

46

48

50

51

Calculate the mean and standard deviation of the random variable X associated with these data. Solutions to Self-Check Exercises 8.6 can be found on page 526.

8.6 Concept Questions 1. a. What is the variance of a random variable X? b. What is the standard deviation of a random variable X?

2. What does Chebychev’s inequality measure?

8.6 Exercises In Exercises 1–6, the probability distribution of a random variable X is given. Compute the mean, variance, and standard deviation of X.

1.

2.

x P(X  x) x P(X  x)

1 .4 4 .1

2 .3 2 .2

3 .2 0 .3

4 .1 2 .1

4 .3

3.

4.

5.

x P(X  x)

2 1/16

1 4/16

0 6/16

1 4/16

2 1/16

x

10

11

12

13

14

15

P(X  x)

1/8

2/8

1/8

2/8

1/8

1/8

x P(X  x)

430

480

520

565

580

.1

.2

.4

.2

.1

8.6 VARIANCE AND STANDARD DEVIATION

6.

x

198

195

193

188

185

.15

.30

.10

.25

.20

P(X  x)

7. The following histograms represent the probability distributions of the random variables X and Y. Determine by inspection which probability distribution has the larger variance. (a)

(b) .35 .25

x 2

3

y

4

1

2

3

16

17

18

19

21

1

15

4

28

1

1

a. Describe a random variable X that is associated with these data. b. Find the probability distribution for the random variable X. c. Compute the mean, variance, and standard deviation of X.

Year Birthrate

1991 16.3

1992 15.9

1993 15.5

Year Birthrate

1995 14.8

1996 14.7

1997 14.5

Year Birthrate

1998 14.6

1999 14.5

2000 14.7

1994 15.2

4

8. The following histograms represent the probability distributions of the random variables X and Y. Determine by inspection which probability distribution has the larger variance. (a) .3

15

13. BIRTHRATES The birthrates in the United States for the years 1991–2000 are given in the following table. (The birthrate is the number of live births/1000 population.)

.15

1

Minimum Age Frequency of Occurrence

523

(b) .3

.2

.2

.1

.1

a. Describe a random variable X that is associated with these data. b. Find the probability distribution for the random variable X. c. Compute the mean, variance, and standard deviation of X. Source: National Center for Health Statistics

x 1

2

3

y 1

4

2

3

4

In Exercises 9 and 10, find the variance of the probability distribution for the histogram shown.

9.

Venture A

.3

Earnings 20 40 50

.2 .1 x 1

10.

14. INVESTMENT ANALYSIS Paul Hunt is considering two business ventures. The anticipated returns (in thousands of dollars) of each venture are described by the following probability distributions:

2

3

4

5

.25 .20 .15

Probability .3 .4 .3

Venture B

.10 .05 x 1

2

3

4

5

6

7

8

11. An experiment consists of rolling an eight-sided die (numbered 1 through 8) and observing the number that appears uppermost. Find the mean and variance of this experiment. 12. DRIVING AGE REQUIREMENTS The minimum age requirement for a regular driver’s license differs from state to state. The frequency distribution for this age requirement in the 50 states is given in the following table:

Earnings 15 30 40

Probability .2 .5 .3

a. Compute the mean and variance for each venture. b. Which investment would provide Paul with the higher expected return (the greater mean)? c. In which investment would the element of risk be less (that is, which probability distribution has the smaller variance)? 15. INVESTMENT ANALYSIS Rosa Walters is considering investing $10,000 in two mutual funds. The anticipated returns from

524

8 ADDITIONAL TOPICS IN PROBABILITY

price appreciation and dividends (in hundreds of dollars) are described by the following probability distributions: Mutual Fund A

Returns 4 8 10

Probability .2 .5 .3

Mutual Fund B

Returns 2 6 8

Probability .2 .4 .4

a. Compute the mean and variance associated with the returns for each mutual fund. b. Which investment would provide Rosa with the higher expected return (the greater mean)? c. In which investment would the element of risk be less (that is, which probability distribution has the smaller variance)? 16. The distribution of the number of chocolate chips (x) in a cookie is shown in the following table. Find the mean and the variance of the number of chocolate chips in a cookie. x P(X  x)

0 .01

1 .03

2 .05

x P(X  x)

3 .11

4 .13

5 .24

x P(X  x)

6 .22

7 .16

8 .05

Maximum Price Considered, x

P(X  x)

280

10 500

290

20 500

300

75 500

310

85 500

320

70 500

350

90 500

380

90 500

400

55 500

450

5 500

20. AVERAGE RENT A study of the records of 85,000 apartment units in the greater Boston area revealed the following data: Year Average Rent, $

2002 1352

2003 1336

2004 1317

2005 1308

2006 1355

Find the average of the average rent for the 5 yr in question. What is the standard deviation for these data? Source: Northeast Apartment Advisors Inc.

21. OCCUPANCY RATE A study of the records of 85,000 apartment units in the greater Boston area revealed the following data: Year Occupancy Rate, %

2002

2003

2004

2005

2006

95.6

94.7

95.2

95.1

96.1

Find the average occupancy rate for the 5 yr in question. What is the standard deviation for these data? Source: Northeast Apartment Advisors Inc.

22. EXAM SCORES The following table gives the scores of 30 students in a mathematics examination:

17. Formula (14) can also be expressed in the form Var1X 2  1 p1x 21  p2x 22  p  pnx 2n 2  m2

Find the variance of the distribution of Exercise 1 using this formula. 18. Find the variance of the distribution of Exercise 16 using the formula Var1X 2  1 p1x 21  p2x 22  p  pnx 2n 2  m2

19. HOUSING PRICES A survey was conducted by the market research department of the National Real Estate Company among 500 prospective buyers in a large metropolitan area to determine the maximum price a prospective buyer would be willing to pay for a house. From the data collected, the distribution that follows was obtained. Compute the mean, variance, and standard deviation of the maximum price x (in thousands of dollars) that these buyers were willing to pay for a house.

Scores Students

90–99 4

80–89 8

70–79 12

60–69 4

50–59 2

Find the mean and the standard deviation of the distribution of the given data. Hint: Assume that all scores lying within a group interval take the middle value of that group.

23. BOSTON HOMICIDES The percentage of Boston homicide cases solved each year from 2000 through 2006 is summarized in the following table: Year Percent

2000 49

2001 50

2002 70

2003 64

2004 36

2005 29

2006 38

Find the average percent of Boston homicide cases solved per year for 2000 through 2006. What is the standard deviation for these data? Source: Boston Police Department

8.6 VARIANCE AND STANDARD DEVIATION

24. MARITAL STATUS OF MEN The number of married men (in thousands) between the ages of 20 and 44 in the United States in 1998 is given in the following table:

525

Find the average number of Americans without health insurance in the period from 1995 through 2002. What is the standard deviation for these data? Source: U.S. Census Bureau

Age Men

20–24 1332

25–29 4219

30–34 6345

35–39 7598

40–44 7633

Find the mean and the standard deviation of the given data. Hint: See the hint for Exercise 22. Source: U.S. Census Bureau

25. MAIL DELIVERED The total number of pieces of mail delivered (in billions) each year from 2002 through 2006 is given in the following table: Year Number

2002 203

2003 202

2004 206

2005 212

2006 213

What is the average total number of pieces of mail delivered from 2002 through 2006? What is the standard deviation for these data?

29. ACCESS TO CAPITAL One of the key determinants of economic growth is access to capital. Using 54 variables to create an index of 1–7, with 7 being best possible access to capital, Milken Institute ranked the following as the top ten nations (although technically Hong Kong is not a nation) by the ability of their entrepreneurs to gain access to capital:

Country Index

Hong Kong 5.70

Netherlands 5.59

U.K. 5.57

Singapore 5.56

Switzerland 5.55

Country Index

U.S. 5.55

Australia 5.31

Finland 5.24

Germany 5.23

Denmark 5.22

Find the mean of the indices of the top ten nations. What is the standard deviation for these data? Source: Milken Institute

Source: U.S. Postal Service

26. TVS IN THE HOME In a survey, consumers were asked how many television sets they have in their home. The results are summarized in the following table: TVs Respondents, %

1 13.9

2 26.5

3 28.6

4 14.8

5 16.2

Find the average number of TVs in the home of the respondents. What is the standard deviation for these data?

30. ACCESS TO CAPITAL Refer to Exercise 29. Milken Institute also ranked the following as the ten worst-performing nations by the ability of their entrepreneurs to gain access to capital: Country Index

Peru 3.76

Mexico 3.70

Bulgaria 3.66

Brazil 3.50

Indonesia 3.46

Country Index

Colombia 3.46

Turkey 3.43

Argentina 3.20

Venezuela 2.88

Russia 2.19

Source: RBC Capital Markets

27. HOURS WORKED IN SOME COUNTRIES The number of average hours worked per year per worker in the United States and five European countries in 2002 is given in the following table:

Country

U.S.

Spain

Great Britain

France

West Germany

Norway

Average Hours Worked

1815

1807

1707

1545

1428

1342

Find the average of the average hours worked per worker in 2002 for workers in the six countries. What is the standard deviation for these data? 28. AMERICANS WITHOUT HEALTH INSURANCE The number of Americans without health insurance, in millions, from 1995 through 2002 is summarized in the following table: 1995 40.7

1996 41.8

1997 1998 43.5 44.5

1999 2000 2001 40.2 39.9 41.2

Source: Milken Institute

31. SALES OF VEHICLES The seasonally adjusted annualized sales rate for U.S. cars and light trucks, in millions of units, for May 2003 through April 2004 are given in the following tables: 2003

M 16.5

2002 43.6

J 16.5

J 17.0

A 18.5

F 16.5

M 16.8

A 16.5

S 17.0

O 16.0

N 17.0

D 18.0

2004

J 16.3

Source: Office of Economic Cooperation and Development

Year Number

Find the mean of the indices of the ten worst-performing nations. What is the standard deviation for these data?

What is the average seasonally adjusted annualized sales rate for U.S. motor vehicles for the period in question? What is the standard deviation for these data? Source: Autodata

526

8 ADDITIONAL TOPICS IN PROBABILITY

32. ELECTION TURNOUT The percent of the voting age population who cast ballots in presidential elections from 1932 through 2000 are given in the following table: Election Year Turnout, % Election Year Turnout %

1932

1936

1940

1944

1948

1952

1956

1960

1964

53

57

59

56

51

62

59

59

62

1968

1972

1976

1980

1984

1988

1992

1996

2000

61

55

54

53

53

50

55

49

51

Find the mean and the standard deviation of the given data. Source: Federal Election Commission

37. PRODUCT RELIABILITY The deluxe model hair dryer produced by Roland Electric has a mean expected lifetime of 24 mo with a standard deviation of 3 mo. Find a bound on the probability that one of these hair dryers will last between 20 and 28 mo. 38. PRODUCT RELIABILITY A Christmas tree light has an expected life of 200 hr and a standard deviation of 2 hr. a. Find a bound on the probability that one of these Christmas tree lights will last between 190 hr and 210 hr. b. Suppose 150,000 of these Christmas tree lights are used by a large city as part of its Christmas decorations. Estimate the number of lights that are likely to require replacement between 180 hr and 220 hr of use.

33. A probability distribution has a mean of 42 and a standard deviation of 2. Use Chebychev’s inequality to find a bound on the probability that an outcome of the experiment lies between a. 38 and 46. b. 32 and 52.

39. STARTING SALARIES The mean annual starting salary of a new graduate in a certain profession is $52,000 with a standard deviation of $500. Find a bound on the probability that the starting salary of a new graduate in this profession will be between $50,000 and $54,000?

34. A probability distribution has a mean of 20 and a standard deviation of 3. Use Chebychev’s inequality to find a bound on the probability that an outcome of the experiment lies between a. 15 and 25. b. 10 and 30.

40. QUALITY CONTROL Sugar packaged by a certain machine has a mean weight of 5 lb and a standard deviation of 0.02 lb. For what values of c can the manufacturer of the machinery claim that the sugar packaged by this machine has a weight between 5  c and 5  c lb with probability at least 96%?

35. A probability distribution has a mean of 50 and a standard deviation of 1.4. Use Chebychev’s inequality to find the value of c that guarantees the probability is at least 96% that an outcome of the experiment lies between 50  c and 50  c.

In Exercises 41 and 42, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

36. Suppose X is a random variable with mean ␮ and standard deviation ␴. If a large number of trials is observed, at least what percentage of these values is expected to lie between ␮  2␴ and ␮  2␴?

41. Both the variance and the standard deviation of a random variable measure the spread of a probability distribution. 42. Chebychev’s inequality is useless when k 1.

8.6 Solutions to Self-Check Exercises 1. The mean of the random variable X is ␮  (4)(.1)  (3)(.1)  (1)(.2)

2. We first compute the probability distribution of X from the given data as follows:

 (0)(.3)  (2)(.1)  (5)(.2)  0.3

The variance of X is Var(X )  (.1)(4  0.3)2  (.1)(3  0.3)2  (.2)(1  0.3)2  (.3)(0  0.3)2  (.1)(2  0.3)2  (.2)(5  0.3)2  8.01

The standard deviation of X is s  1Var 1X 2  18.01  2.83

x 46 48 50 51 52 55

Relative Frequency of Occurrence 1 2 3 1 2 1

P(X  x) .1 .2 .3 .1 .2 .1

The mean of X is ␮  (.1)(46)  (.2)(48)  (.3)(50)  (.1)(51)  (.2)(52)  (.1)(55)  50.2

8.6 VARIANCE AND STANDARD DEVIATION

527

from which we deduce the standard deviation

The variance of X is Var(X )  (.1)(46  50.2)2  (.2)(48  50.2)2

s  15.76

 (.3)(50  50.2)2  (.1)(51  50.2)2  (.2)(52  50.2)  (.1)(55  50.2) 2

 2.4

2

 5.76

USING

TECHNOLOGY

Finding the Mean and Standard Deviation We can use a graphing calculator to compute the mean and standard deviation of a random variable. APPLIED EXAMPLE 1 Age Distribution of Company Directors A survey conducted in 1995 of the Fortune 1000 companies revealed the following age distribution of the company directors: Age Directors

Age Directors

20–24

25–29

30–34

35–39

40–44

45–49

50–54

1

6

28

104

277

607

1142

55–59

60–64

65–69

70–74

75–79

80–84

85–89

1413

1424

494

159

62

31

5

Source: Directorship

Let X denote the random variable taking on the values 1 through 14, where 1 corresponds to the age bracket 20–24, 2 corresponds to the age bracket 25–29, and so on. a. Plot a histogram for the given data. b. Find the mean and the standard deviation of these data. Interpret your results. Solution

a. Enter the values of X as x1  1, x2  2, . . . , x14  14 and the corresponding values of Y as y1  1, y2  6, . . . , y14  5. Then using the DRAW function from the Statistics menu of a graphing utility, we obtain the histogram shown in Figure T1.

FIGURE T1 The histogram for the given data, using the viewing window [0, 16]  [0, 1500]

b. Using the appropriate function from the Statistics menu, we find that x  7.9193 and ␴x  1.6378; that is, the mean of X is ␮  7.9 and the standard deviation is ␴  1.6. Interpreting our results, we see that the average age of the directors is in the 55–59-year-old bracket. (continued)

528

8 ADDITIONAL TOPICS IN PROBABILITY

TECHNOLOGY EXERCISES 1. a. Graph the histogram associated with the random variable X in Example 1, page 518. b. Find the mean and the standard deviation for these data.

a. Describe a random variable X that is associated with these data. b. Find the probability distribution for the random variable X. c. Compute the mean and standard deviation of X.

2. a. Graph the histogram associated with the random variable Y in Example 1, page 518. b. Find the mean and the standard deviation for these data.

7. HEIGHTS OF WOMEN The following data, obtained from the records of the Westwood Health Club, give the heights (to the nearest inch) of 200 female members of the club:

3. a. Graph the histogram associated with the data given in Exercise 12, page 523. b. Find the mean and the standard deviation for these data. 4. a. Graph the histogram associated with the data given in Exercise 16, page 524. b. Find the mean and the standard deviation for these data. 5. A sugar refiner uses a machine to pack sugar in 5-lb cartons. To check the machine’s accuracy, cartons are selected at random and weighed. The results follow: 4.98

5.02

4.96

4.97

5.03

4.96

4.98

5.01

5.02

5.06

4.97

5.04

5.04

5.01

4.99

4.98

5.04

5.01

5.03

5.05

4.96

4.97

5.02

5.04

4.97

5.03

5.01

5.00

5.01

4.98

74

92

68

94

66

87

85

70

72

68

73

72

74

88

90

69

66

58

70

98

71

75

68

6212 3

63 4

6312 8

64 11

6412 20

65 32

6512 30

66 18

Height Frequency

6612 18

67 16

6712 8

68 10

6812 5

69 5

6912 4

70 3

7012 2

71 1

8. AGE DISTRIBUTION IN A TOWN The following table gives the distribution of the ages (in years) of the residents (in hundreds) of the town of Monroe who are under the age of 40: Age Residents

0–3 30

4–7 42

8–11 50

12–15 60

16–19 50

Age Residents

20–23 41

24–27 50

28–31 45

32–35 42

36–39 34

Let X denote the random variable taking on the values 1 through 10, where 1 corresponds to the range 0–3, . . . , and 10 corresponds to the range 36–39. a. Plot a histogram for the given data. b. Find the mean and the standard deviation of X.

6. The scores of 25 students in a mathematics examination are as follows: 85

62 2

a. Plot a histogram for the given data. b. Find the mean and the standard deviation of these data.

a. Describe a random variable X that is associated with these data. b. Find the probability distribution for the random variable X. c. Compute the mean and standard deviation of X.

90

Height Frequency

CHAPTER 8 Summary of Principal Formulas and Terms FORMULAS P1A  B2

1. Conditional probability

P(B  A) 

2. Product rule

P(A  B)  P(A)  P(B  A)

3. Test for independence

P(A  B)  P(A)  P(B)

P1A2

CONCEPT REVIEW QUESTIONS

4. Bayes’ Theorem

5. Mean of n numbers

P(Ai  E ) 

P1Ai 2 # P1E Ai 2

P1A1 2 # P1E A1 2  P1A2 2 # P1E A2  . . .  P1An 2 # P1E An 2 x1  x2  . . .  xn x  n

6. Expected value

E(X)  x1p1  x2p2  . . .  xn pn

7. Odds in favor of E occurring

P1E c 2 P1E c 2

8. Odds against E occurring 9. Probability of an event occurring given the odds 10. Variance of a random variable

529

P1E 2

P1E 2

a ab Var(X)  p1(x1  ␮)2  p2(x2  ␮)2  . . .  pn(xn  ␮)2

11. Standard deviation of a random variable

␴  2Var1X 2

12. Chebychev’s inequality

P(␮  k␴ X ␮  k␴)  1 

1 k2

TERMS conditional probability (471) finite stochastic process (475) independent events (478) Bayes’ theorem (486) random variable (494) finite discrete random variable (495)

infinite discrete random variable (495) continuous random variable (495) probability distribution of a random variable (496) histogram (497) average (mean) (504)

expected value (505) median (511) mode (512) variance (517) standard deviation (519)

CHAPTER 8 Concept Review Questions Fill in the blanks.

1. The probability of the event B given that the event A has already occurred is called the ______ probability of B given A. 2. If the outcome of one event does not depend on the other, then the two events are said to be ______. 3. The probability of an event after the outcomes of an experiment have been observed is called a/an ______ ______ ______. 4. A rule that assigns a number to each outcome of a chance experiment is called a/an ______ variable. 5. If a random variable assumes only finitely many values, then it is called ______ discrete; if it takes on infinitely many values that can be arranged in a sequence, then it is

called ______ discrete; if it takes on all real numbers in an interval, then it is said to be ______. 6. The expected value of a random variable X is given by the ______ of the products of the values assumed by the random variable and its associated probabilities. For example, if X assumes the values 2, 3, and 4 with associated probabilities 21, 41, and 14, then its expected value is ______. 7. a. If the probability of an event E occurring is P(E), then the odds in favor of E occurring are ______. b. If the odds in favor of an event E occurring are a to b, then the probability of E occurring is ______. 8. If a random variable X takes on the values x1, x2, . . . , xn with probabilities p1, p2, . . . . , pn and has a mean of ␮, then the variance of X is ______. The standard deviation of X is ______.

530

8 ADDITIONAL TOPICS IN PROBABILITY

CHAPTER 8 Review Exercises The accompanying tree diagram represents an experiment consisting of two trials. In Exercises 1–5, use the diagram to find the given probability. .6

E

.4

Ec

.5

E

.5

Ec

.3

E

.7

Ec

A

.3 .5

B

.2

C

1. P(A  E)

2. P(B  E)

3. P(C  E)

4. P(A  E)

5. P(E) 6. Let E and F be two events and suppose P(E)  .35, P(F)  .55, and P(E  F)  .70. Find P(E  F). 7. An experiment consists of tossing a fair coin three times and observing the outcomes. Let A be the event that at least one head is thrown and B the event that at most two tails are thrown. a. Find P(A). b. Find P(B). c. Are A and B independent events? 8. QUALITY CONTROL In a group of 20 ballpoint pens on a shelf in the stationery department of Metro Department Store, 2 are known to be defective. If a customer selects 3 of these pens, what is the probability that a. At least 1 is defective? b. No more than 1 is defective? 9. Five people are selected at random. What is the probability that none of the people in this group were born on the same day of the week? 10. A pair of fair dice is cast. What is the probability that the sum of the numbers falling uppermost is 8 if it is known that the two numbers are different?

a. List the outcomes of this experiment. b. Find the value assigned to each outcome of this experiment by the random variable X. c. Find the probability distribution of the random variable associated with this experiment. d. Draw the histogram representing this distribution. 16. A man purchased a $25,000, 1-yr term-life insurance policy for $375. Assuming that the probability that he will live for another year is .989, find the company’s expected gain. 17. The probability distribution of a random variable X is shown in the accompanying table: x 0

P(X  x) .1

1 2 3 4 5

.1 .2 .3 .2 .1

a. Compute P(1 X 4). b. Compute the mean and standard deviation of X. 18. FLEX-TIME Of 320 male and 280 female employees at the home office of Gibraltar Insurance Company, 160 of the men and 190 of the women are on flex-time (flexible working hours). Given that an employee selected at random from this group is on flex-time, what is the probability that the employee is a man? 19. QUALITY CONTROL In a manufacturing plant, three machines, A, B, and C, produce 40%, 35%, and 25%, respectively, of the total production. The company’s quality-control department has determined that 1% of the items produced by machine A, 1.5% of the items produced by machine B, and 2% of the items produced by machine C are defective. If an item is selected at random and found to be defective, what is the probability that it was produced by machine B?

14. The second card is black, given that the first card was red.

20. COLLEGE ADMISSIONS Applicants who wish to be admitted to a certain professional school in a large university are required to take a screening test that was devised by an educational testing service. From past results, the testing service has estimated that 70% of all applicants are eligible for admission and that 92% of those who are eligible for admission pass the exam, whereas 12% of those who are ineligible for admission pass the exam. Using these results, what is the probability that an applicant for admission a. Passed the exam? b. Passed the exam but was actually ineligible?

15. Three balls are selected at random without replacement from an urn containing three white balls and four blue balls. Let the random variable X denote the number of blue balls drawn.

21. COMMUTING TIMES Bill commutes to work in the business district of Boston. He takes the train 35 of the time and drives 25 of the time (when he visits clients). If he takes the train, then he gets home by 6:30 p.m. 85% of the time; if

Three cards are drawn at random without replacement from a standard deck of 52 playing cards. In Exercises 11–14, find the probability of each of the given events.

11. All three cards are aces. 12. All three cards are face cards. 13. The second and third cards are red.

BEFORE MOVING ON . . .

he drives, then he gets home by 6:30 p.m. 60% of the time. If Bill gets home by 6:30 p.m., what is the probability that he drove to work? 22. HEIGHTS OF WOMEN The heights of 4000 women who participated in a survey were found to be normally distributed

531

with a mean of 64.5 in. and a standard deviation of 2.5 in. Use Chebychev’s inequality to estimate the probability that the height of a woman who participated in the survey will fall within 2 standard deviations of the mean—that is, that her height will be between 59.5 and 69.5 in.

CHAPTER 8 Before Moving On . . . 1. Suppose A and B are independent events with P(A)  .3 and P(B)  .6. Find P(A  B). 2. The accompanying tree diagram represents a two-stage experiment. Use the diagram to find P(A  D). .2

D

.8

Dc

.3

D

.7

Dc

A .4

.6

x Frequency of Occurrence

3

2

0

1

2

3

4

8

20

24

16

8

4. The probability distribution of the random variable X is shown in the following table. Find (a) P(X 0) and (b) P(4 X 1). x P(X  x)

4 .06

3 .14

1 .32

0 .28

1 .12

3 .08

B

3. The values taken on by a random variable X and the frequency of their occurrence are shown in the following table. Find the probability distribution of X.

5. Find the mean, variance, and standard deviation of a random variable X having the following probability distribution: x P(X  x)

3 .08

1 .24

0 .32

1 .16

3 .12

5 .08

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9

THE DERIVATIVE

I

N THIS CHAPTER, we begin the study of differential calculus. Historically, differential calculus was developed in response to

the problem of finding the tangent line to an arbitrary curve. But

it quickly became apparent that solving this problem provided

problems involving the rate of change of one quantity with respect to another. The basic tool used in differential calculus is the derivative of a function. The concept of the derivative is based, in turn, on a more fundamental notion—that of the limit of a function.

© Spencer Platt/Getty Images

mathematicians with a method of solving many practical

What happens to the sales of a DVD recording of a certain hit movie over a 10-year period after it is first released into the market? In Example 6, page 605, you will see how to find the rate of change of sales for the DVD over the first 10 years after its release.

534

9 THE DERIVATIVE

9.1 Limits Introduction to Calculus Historically, the development of calculus by Isaac Newton (1642–1727) and Gottfried Wilhelm Leibniz (1646–1716) resulted from the investigation of the following problems: 1. Finding the tangent line to a curve at a given point on the curve (Figure 1a) 2. Finding the area of a planar region bounded by an arbitrary curve (Figure 1b)

y

y

T R P

x

(a) What is the slope of the tangent line T at point P?

x

(b) What is the area of the region R?

FIGURE 1

The tangent-line problem might appear to be unrelated to any practical applications of mathematics, but as you will see later, the problem of finding the rate of change of one quantity with respect to another is mathematically equivalent to the geometric problem of finding the slope of the tangent line to a curve at a given point on the curve. It is precisely the discovery of the relationship between these two problems that spurred the development of calculus in the 17th century and made it such an indispensable tool for solving practical problems. The following are a few examples of such problems: ■ ■ ■ ■

Finding the velocity of an object Finding the rate of change of a bacteria population with respect to time Finding the rate of change of a company’s profit with respect to time Finding the rate of change of a travel agency’s revenue with respect to the agency’s expenditure for advertising

The study of the tangent-line problem led to the creation of differential calculus, which relies on the concept of the derivative of a function. The study of the area problem led to the creation of integral calculus, which relies on the concept of the antiderivative, or integral, of a function. (The derivative of a function and the integral of a function are intimately related, as you will see in Section 11.4.) Both the derivative of a function and the integral of a function are defined in terms of a more fundamental concept—the limit—our next topic.

A Real-Life Example From data obtained in a test run conducted on a prototype of a maglev (magnetic levitation train), which moves along a straight monorail track, engineers have determined that the position of the maglev (in feet) from the origin at time t (in seconds) is given by s  f(t)  4t 2

(0 t 30)

(1)

9.1 LIMITS

535

where f is called the position function of the maglev. The position of the maglev at time t  0, 1, 2, 3, . . . , 10, measured from its initial position, is f(0)  0

f(1)  4

f(2)  16

f(3)  36, . . .

f(10)  400

feet (Figure 2).

FIGURE 2 A maglev moving along an elevated monorail track

t=0

t=1

t=2

t=3

t = 10

0

4

16

36

400

s (feet)

Suppose we want to find the velocity of the maglev at t  2. This is just the velocity of the maglev as shown on its speedometer at that precise instant of time. Offhand, calculating this quantity using only Equation (1) appears to be an impossible task; but consider what quantities we can compute using this relationship. Obviously, we can compute the position of the maglev at any time t as we did earlier for some selected values of t. Using these values, we can then compute the average velocity of the maglev over an interval of time. For example, the average velocity of the train over the time interval [2, 4] is given by f 142  f 122 Distance covered  Time elapsed 42 4142 2  4122 2  2 64  16   24 2

or 24 feet/second. Although this is not quite the velocity of the maglev at t  2, it does provide us with an approximation of its velocity at that time. Can we do better? Intuitively, the smaller the time interval we pick (with t  2 as the left endpoint), the better the average velocity over that time interval will approximate the actual velocity of the maglev at t  2.* Now, let’s describe this process in general terms. Let t  2. Then, the average velocity of the maglev over the time interval [2, t] is given by f 1t2  f 122 t2



4t 2  4122 2 t2



41t 2  4 2 t2

(2)

By choosing the values of t closer and closer to 2, we obtain a sequence of numbers that give the average velocities of the maglev over smaller and smaller time intervals. As we observed earlier, this sequence of numbers should approach the instantaneous velocity of the train at t  2. Let’s try some sample calculations. Using Equation (2) and taking the sequence t  2.5, 2.1, 2.01, 2.001, and 2.0001, which approaches 2, we find

*Actually, any interval containing t  2 will do.

536

9 THE DERIVATIVE

The average velocity over [2, 2.5] is The average velocity over [2, 2.1] is

412.52  4 2 2.5  2

412.12  4 2 2.1  2

 18, or 18 feet/second.  16.4, or 16.4 feet/second.

and so forth. These results are summarized in Table 1. TABLE 1 t approaches 2 from the right. t Average Velocity over [2, t ]

2.5 18

2.1

2.01

2.001

2.0001

16.4

16.04

16.004

16.0004

Average velocity approaches 16 from the right.

From Table 1, we see that the average velocity of the maglev seems to approach the number 16 as it is computed over smaller and smaller time intervals. These computations suggest that the instantaneous velocity of the train at t  2 is 16 feet/second. Note Notice that we cannot obtain the instantaneous velocity for the maglev at t  2 by substituting t  2 into Equation (2) because this value of t is not in the domain of the average velocity function.

Intuitive Definition of a Limit Consider the function t defined by t 1t 2 

41t 2  42 t2

which gives the average velocity of the maglev [see Equation (2)]. Suppose we are required to determine the value that t(t) approaches as t approaches the (fixed) number 2. If we take the sequence of values of t approaching 2 from the right-hand side, as we did earlier, we see that t(t) approaches the number 16. Similarly, if we take a sequence of values of t approaching 2 from the left, such as t  1.5, 1.9, 1.99, 1.999, and 1.9999, we obtain the results shown in Table 2. TABLE 2 t approaches 2 from the left. t g(t)

1.5 14

1.9

1.99

1.999

1.9999

15.6

15.96

15.996

15.9996

Average velocity approaches 16 from the left.

Observe that t(t) approaches the number 16 as t approaches 2—this time from the left-hand side. In other words, as t approaches 2 from either side of 2, t(t) approaches 16. In this situation, we say that the limit of t(t) as t approaches 2 is 16, written lim t1t2  lim tS2

tS2

41t 2  42 t2

 16

9.1 LIMITS

537

The graph of the function t, shown in Figure 3, confirms this observation. y y = g(t) =

20 18 16 14 12

4 (t 2 – 4) t–2

8 4 t 1.5

FIGURE 3

1

As t approaches t  2 from either direction, g(t) approaches y  16.

1.9 2.1 2

2.5 3

Observe that the point t  2 is not in the domain of the function t [for this reason, the point (2, 16) is missing from the graph of t]. This, however, is inconsequential because the value, if any, of t(t) at t  2 plays no role in computing the limit. This example leads to the following informal definition.

Limit of a Function

The function f has the limit L as x approaches a, written lim f 1x2  L

xSa

if the value of f(x) can be made as close to the number L as we please by taking x sufficiently close to (but not equal to) a.

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the graph of t 1x2 

41x 2  42 x2

in the viewing window [0, 3]  [0, 20]. 2. Use ZOOM and TRACE to describe what happens to the values of t(x) as x approaches 2, first from the right and then from the left. 3. What happens to the y-value when you try to evaluate t(x) at x  2? Explain. 4. Reconcile your results with those of the preceding example.

Evaluating the Limit of a Function Let’s now consider some examples involving the computation of limits.

538

9 THE DERIVATIVE

EXAMPLE 1 Let f(x)  x 3 and evaluate lim f 1x2 .

y

xS2

Solution The graph of f is shown in Figure 4. You can see that f (x) can be made as close to the number 8 as we please by taking x sufficiently close to 2. Therefore,

y = x3

8 6

lim x3  8

4

xS2

2 x –1

1

2

EXAMPLE 2 Let t 1x2  e

FIGURE 4 f(x) is close to 8 whenever x is close to 2.

Evaluate lim t 1x2 . xS1

The domain of t is the set of all real numbers. From the graph of t shown in Figure 5, we see that t(x) can be made as close to 3 as we please by taking x sufficiently close to 1. Therefore,

5 y = g(x)

lim t 1x2  3

3

xS1

1 x FIGURE 5

lim g(x)  3

xS1

if x  1 if x  1

Solution

y

–1

x2 1

1

3

Observe that t(1)  1, which is not equal to the limit of the function t as x approaches 1. [Once again, the value of t(x) at x  1 has no bearing on the existence or value of the limit of t as x approaches 1.] EXAMPLE 3 Evaluate the limit of the following functions as x approaches the indicated point. f 1x2  e

a.

Solution

1 1

if x 0 ;x0 if x  0

b. t 1x2 

1 ; x0 x2

The graphs of the functions f and t are shown in Figure 6. y

y

5 y = f (x)

1

g(x) = 12 x x

–3

–1

3 x –2 –1

FIGURE 6

(a) lim f(x) does not exist. xS0

1

2

(b) lim g(x) does not exist. xS0

a. Referring to Figure 6a, we see that no matter how close x is to zero, f(x) takes on the values 1 or 1, depending on whether x is positive or negative. Thus, there is no single real number L that f(x) approaches as x approaches zero. We conclude that the limit of f(x) does not exist as x approaches zero. b. Referring to Figure 6b, we see that as x approaches zero (from either side), t(x) increases without bound and thus does not approach any specific real number. We conclude, accordingly, that the limit of t(x) does not exist as x approaches zero.

9.1 LIMITS

539

Explore & Discuss Consider the graph of the function h whose graph is depicted in the following figure. y 1

x

–1

It has the property that as x approaches zero from either the right or the left, the curve oscillates more and more frequently between the lines y  1 and y  1. 1. Explain why lim h1x2 does not exist. xS0

2. Compare this function with those in Example 3. More specifically, discuss the different ways the functions fail to have a limit at x  0.

Until now, we have relied on knowing the actual values of a function or the graph of a function near x  a to help us evaluate the limit of the function f(x) as x approaches a. The following properties of limits, which we list without proof, enable us to evaluate limits of functions algebraically.

THEOREM 1 Properties of Limits Suppose

lim f 1x2  L and lim t 1x2  M

xSa

xSa

Then, 1. lim 3 f 1x2 4 r  3 lim f 1x2 4 r  Lr

r, a real number

2. lim cf 1x2  c lim f 1x2  cL

c, a real number

xSa

xSa

xSa

xSa

3. lim 3 f 1x2 t 1x2 4  lim f 1x2 lim t 1x2  L M xSa

xSa

xSa

4. lim 3 f 1x2t 1x2 4  3 lim f 1x2 4 3 lim t 1x2 4  LM xSa

5. lim xSa

xSa

f 1x2

t 1x2

lim f 1x2



xSa

lim t 1x2



xSa

L M

Provided that M  0

xSa

EXAMPLE 4 Use Theorem 1 to evaluate the following limits. a. lim x3

b. lim 5x3/2

xS2

xS4

d. lim 2x3 2x2  7 xS3

2x2  1 e. lim xS2 x  1

Solution

a. lim x3  3 lim x4 3 xS2

xS2 3

2 8

Property 1 lim x  2

xS2

c. lim 15x4  2 2 xS1

540

9 THE DERIVATIVE

b. lim 5x3/2  53 lim x 3/2 4 xS4

xS4 3/2

 514 2

Property 2

 40

Property 1

c. lim 15x4  22  lim 5x4  lim 2 xS1

xS1

Property 3

xS1

To evaluate lim 2, observe that the constant function t(x)  2 has value 2 for xS1

all values of x. Therefore, t(x) must approach the limit 2 as x approaches x  1 (or any other point for that matter!). Therefore, lim 15x4  22  5112 4  2  3

xS1

d. lim 2x3 2x2  7  2 lim x3 2x2  7 xS3

Property 2

xS3

 2 lim x3 lim 2x2  7 xS3

Property 4

xS3

 2132 3 232  7  21272 116  216

lim 12x 2  12 2x 2  1 xS2 e. lim  lim 1x  12 xS2 x  1

Property 1

Property 5

xS2



2122 2  1 21



9 3 3

Indeterminate Forms Let’s emphasize once again that Property 5 of limits is valid only when the limit of the function that appears in the denominator is not equal to zero at the number in question. If the numerator has a limit different from zero and the denominator has a limit equal to zero, then the limit of the quotient does not exist at the number in question. This is the case with the function t(x)  1/x 2 in Example 3b. Here, as x approaches zero, the numerator approaches 1 but the denominator approaches zero, so the quotient becomes arbitrarily large. Thus, as observed earlier, the limit does not exist. Next, consider lim xS2

41x 2  42 x2

which we evaluated earlier by looking at the values of the function for x near x  2. If we attempt to evaluate this expression by applying Property 5 of limits, we see that both the numerator and denominator of the function 41x 2  42 x2

approach zero as x approaches 2; that is, we obtain an expression of the form 0/0. In this event, we say that the limit of the quotient f (x)/t(x) as x approaches 2 has the indeterminate form 0/0. We need to evaluate limits of this type when we discuss the derivative of a function, a fundamental concept in the study of calculus. As the name suggests, the meaningless expression 0/0 does not provide us with a solution to our problem. One strategy that can be used to solve this type of problem follows.

541

9.1 LIMITS

Strategy for Evaluating Indeterminate Forms

1. Replace the given function with an appropriate one that takes on the same values as the original function everywhere except at x  a. 2. Evaluate the limit of this function as x approaches a. Examples 5 and 6 illustrate this strategy. EXAMPLE 5 Evaluate: lim

41x 2  4 2 x2

xS2

Solution Since both the numerator and the denominator of this expression approach zero as x approaches 2, we have the indeterminate form 0/0. We rewrite

41x 2  42



x2

41x  22 1x  22 1x  22

which, upon canceling the common factors, is equivalent to 4(x  2), provided x  2. Next, we replace 4(x 2  4)/(x  2) with 4(x  2) and find that lim

41x 2  4 2 x2

xS2

 lim 41x  2 2  16 xS2

The graphs of the functions f 1x2 

41x 2  42 x2

and

t1x2  41x  22

are shown in Figure 7. Observe that the graphs are identical except when x  2. The function t is defined for all values of x and, in particular, its value at x  2 is t(2)  4(2  2)  16. Thus, the point (2, 16) is on the graph of t. However, the function f is not defined at x  2. Since f(x)  t(x) for all values of x except x  2, it follows that the graph of f must look exactly like the graph of t, with the exception that the point (2, 16) is missing from the graph of f. This illustrates graphically why we can evaluate the limit of f by evaluating the limit of the “equivalent” function t. y

y

24

24

20

20

16

16

12

12

8

8

4

4 x

x –3

–2

–1

1 –2

FIGURE 7 The graphs of f(x) and g(x) are identical except at the point (2, 16).

(a) f(x) 

Note

4(x 2  4) x2

2

3

4

–3

–2

–1

1

2

3

4

–2 (b) g(x)  4(x  2)

Notice that the limit in Example 5 is the same limit that we evaluated earlier when we discussed the instantaneous velocity of a maglev at a specified time.

542

9 THE DERIVATIVE

Exploring with

TECHNOLOGY 2. Use a graphing utility to plot the graph of t(x)  4(x  2) in the viewing window [0, 3]  [0, 20]. Then use ZOOM and TRACE to find lim 4(x  2).

1. Use a graphing utility to plot the graph of f 1x2 

41x 2  4 2 x2

xS2

What happens to the y-value when you try to evaluate f (x) at x  2? Explain. 3. Can you distinguish between the graphs of f and t? 4. Reconcile your results with those of Example 5.

in the viewing window [0, 3]  [0, 20]. Then use ZOOM and TRACE to find lim xS2

41x 2  4 2 x2

EXAMPLE 6 Evaluate: lim hS0

11  h  1 h

Letting h approach zero, we obtain the indeterminate form 0/0. Next, we rationalize the numerator of the quotient by multiplying both the numerator and the denominator by the expression 1 11  h  12 , obtaining

Solution

1 11  h  12 1 11  h  1 2 11  h  1  * (x ) See page 41. h h1 11  h  12 1h1  1 1a  1b2 1 1a  1b 2  a  b h1 11  h  12 2

h h1 11  h  12 1  11  h  1



Therefore, lim hS0

11  h  1 1 1 1  lim   h hS0 11  h  1 2 11  1

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the graph of 11  x  1 in the viewing window t1x2  x [1, 2]  [0, 1]. Then use ZOOM and TRACE to find 11  x  1 by observing the values of t(x) lim x xS0 as x approaches zero from the left and from the right.

2. Use a graphing utility to plot the graph of f 1x2 

1 in the viewing window 11  x  1

[1, 2]  [0, 1]. Then use ZOOM and TRACE to find 1 lim . What happens to the y-value xS0 11  x  1 when x takes on the value zero? Explain. 3. Can you distinguish between the graphs of f and t? 4. Reconcile your results with those of Example 6.

*The symbol (x2) indicates that an algebraic computation or problem-solving skill used in the example is reviewed on the given page.

9.1 LIMITS

543

Limits at Infinity Up to now we have studied the limit of a function as x approaches a (finite) number a. There are occasions, however, when we want to know whether f(x) approaches a unique number as x increases without bound. Consider, for example, the function P, giving the number of fruit flies (Drosophila) in a container under controlled laboratory conditions, as a function of a time t. The graph of P is shown in Figure 8. You can see from the graph of P that, as t increases without bound (gets larger and larger), P(t) approaches the number 400. This number, called the carrying capacity of the environment, is determined by the amount of living space and food available, as well as other environmental factors.

y

Number of fruit flies

400

y = 400

300 200 100 t 0

FIGURE 8

10

20

The graph of P(t) gives the population of fruit flies in a laboratory experiment.

30 40 Days

50

60

As another example, suppose we are given the function f 1x2 

2x 2 1  x2

and we want to determine what happens to f(x) as x gets larger and larger. Picking the sequence of numbers 1, 2, 5, 10, 100, and 1000 and computing the corresponding values of f(x), we obtain the following table of values: y y=2

2

y=

1

1

–1

1

2

5

10

100

1000

f(x)

1

1.6

1.92

1.98

1.9998

1.999998

2x2 1 + x2 x

–3

x

3

From the table, we see that as x gets larger and larger, f(x) gets closer and closer to 2. The graph of the function f shown in Figure 9 confirms this observation. We call the line y  2 a horizontal asymptote.* In this situation, we say that the limit of the function f(x) as x increases without bound is 2, written

FIGURE 9 The graph of

lim y

2x2 1  x2

has a horizontal asymptote at y  2.

xS

2x 2 2 1  x2

In the general case, the following definition for a limit of a function at infinity is applicable.

*We will discuss asymptotes in greater detail in Section 10.3.

544

9 THE DERIVATIVE

Limit of a Function at Infinity

The function f has the limit L as x increases without bound (or, as x approaches infinity), written lim f 1x2  L

xS

if f(x) can be made arbitrarily close to L by taking x large enough. Similarly, the function f has the limit M as x decreases without bound (or as x approaches negative infinity), written lim f 1x2  M

xS

if f(x) can be made arbitrarily close to M by taking x to be negative and sufficiently large in absolute value. EXAMPLE 7 Let f and t be the functions f 1x2  e

Evaluate:

a. lim f 1x2 and lim f 1x2 xS

1 if x 0 and 1 if x  0

t 1x2 

1 x2

b. lim t 1x2 and lim t 1x2

xS

xS

xS

The graphs of f(x) and t(x) are shown in Figure 10. Referring to the graphs of the respective functions, we see that

Solution

a. lim f 1x2  1 and lim f 1x2  1 xS

b. lim

xS

xS

1 1  0 and lim 2  0 2 xS x x y

y

5 y = f (x)

1

g(x) =

1 x2

x –3

3

–1

x 1

–2 –1 FIGURE 10

(a) lim f(x)  1 and lim f(x)  1 xS

xS

2

(b) lim g(x)  0 and lim g(x)  0 xS

xS

All the properties of limits listed in Theorem 1 are valid when a is replaced by  or . In addition, we have the following property for the limit at infinity.

THEOREM 2 For all n  0, lim xS

provided that

1 is defined. xn

1  0 and xn

lim xS

1 0 xn

9.1 LIMITS

545

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the graphs of y1 

1 x0.5

y2 

1 x

y3 

1 x1.5

1 if xn n  0.5, n  1, and n  1.5? Are these results predicted by Theorem 2?

in the viewing window [0, 200]  [0, 0.5]. What can you say about lim

xS

2. Use a graphing utility to plot the graphs of y1 

1 x

and

y2 

1 x5/3

in the viewing window [50, 0]  [0.5, 0]. What can you say about 1 5 lim n if n  1 and n  ? Are these results predicted by Theorem 2? xS x 3 Hint: To graph y2, write it in the form y2  1/(xˆ(1/3))ˆ5.

We often use the following technique to evaluate the limit at infinity of a rational function: Divide the numerator and denominator of the expression by x n, where n is the highest power present in the denominator of the expression. EXAMPLE 8 Evaluate: lim xS

x2  x  3 2x 3  1

Since the limits of both the numerator and the denominator do not exist as x approaches infinity, the property pertaining to the limit of a quotient (Property 5) is not applicable. Let’s divide the numerator and denominator of the rational expression by x 3, obtaining Solution

1 1 3  2 3 x x x3 x x lim  lim 3 xS xS 1 2x  1 2 3 x 000 0   20 2 2

Use Theorem 2.

0

EXAMPLE 9 Let f 1x2 

Compute lim f 1x 2 if it exists.

3x2  8x  4 2x2  4x  5

xS

Solution Again, we see that Property 5 is not applicable. Dividing the numerator and the denominator by x 2, we obtain

546

9 THE DERIVATIVE

8 x 3x  8x  4  lim lim xS 2x 2  4x  5 xS 4 2 x 1 lim 3  8 lim xS xS x  1 lim 2  4 lim xS xS x 3

2

EXAMPLE 10 Let f 1x2  a. lim f 1x 2 xS

b. lim f 1x 2



300 200



3 2

4 x2 5  2 x 

1 x2 1  5 lim 2 xS x  4 lim xS

Use Theorem 2.

2x 3  3x 2  1 and evaluate: x 2  2x  4

xS

Solution

a. Dividing the numerator and the denominator of the rational expression by x 2, we obtain 1 2x  3x  1 x2 lim 2  lim xS x  2x  4 xS 2 4 1  2 x x 3

2

2x  3 

Since the numerator becomes arbitrarily large whereas the denominator approaches 1 as x approaches infinity, we see that the quotient f (x) gets larger and larger as x approaches infinity. In other words, the limit does not exist. We indicate this by writing lim xS

2x 3  3x 2  1  x 2  2x  4

b. Once again, dividing both the numerator and the denominator by x 2, we obtain 1 2x  3x  1 x2 lim  lim 2 xS x  2x  4 xS 2 4 1  2 x x 3

2

2x  3 

In this case, the numerator becomes arbitrarily large in magnitude but negative in sign, whereas the denominator approaches 1 as x approaches negative infinity. Therefore, the quotient f (x) decreases without bound, and the limit does not exist. We indicate this by writing lim xS

2x 3  3x 2  1   x 2  2x  4

Example 11 gives an application of the concept of the limit of a function at infinity.

9.1 LIMITS

547

APPLIED EXAMPLE 11 Average Cost Functions Custom Office makes a line of executive desks. It is estimated that the total cost of making x Senior Executive Model desks is C(x)  100x  200,000 dollars per year, so the average cost of making x desks is given by C1x2   y ($)

C1x2 x 100x  200,000 200,000  100  x x

dollars per desk. Evaluate lim C1x2 and interpret your results. xS

2000

Solution

200,000 b x xS 200,000  100  lim 100  lim x xS xS

lim C1x2  lim a 100 

xS

1000 C(x) = 100 + 100

2 00,000 x y = 100 x

1000

2000

FIGURE 11 As the level of production increases, the average cost approaches $100 per desk.

A sketch of the graph of the function C (x) appears in Figure 11. The result we obtained is fully expected if we consider its economic implications. Note that as the level of production increases, the fixed cost per desk produced, represented by the term (200,000/x), drops steadily. The average cost should approach a constant unit cost of production—$100 in this case.

Explore & Discuss Consider the graph of the function f depicted in the following figure: y

1 x –1

It has the property that the curve oscillates between y  1 and y  1 indefinitely in either direction. 1. Explain why lim f 1x2 and lim f 1x2 do not exist. xS

xS

2. Compare this function with those of Example 10. More specifically, discuss the different ways each function fails to have a limit at infinity or minus infinity.

9.1 Self-Check Exercises 1. Find the indicated limit if it exists. 2x  7  23x  5 x2 2

a. lim xS3

b. lim xS1

x2  x  2 2x2  x  3

2. The average cost per disc (in dollars) incurred by Herald

Records in pressing x CDs is given by the average cost function C1x2  1.8 

3000 x

Evaluate lim C1x2 and interpret your result. xS

Solutions to Self-Check Exercises 9.1 can be found on page 551.

548

9 THE DERIVATIVE

9.1 Concept Questions 1. Explain what is meant by the statement lim f 1x2  3.

4. What is an indeterminate form? Illustrate with an example.

xS2

2. a. If lim f 1x2  5, what can you say about f(3)? Explain. xS3

b. If f(2)  6, what can you say about lim f 1x2? Explain.

5. Explain in your own words the meaning of lim f 1x2  L xS and lim f 1x2  M. xS

xS2

3. Evaluate and state the property of limits that you use at each step. 2x2  x  5 3/2 ≤ a. lim 1x12x2  1 2 b. lim ¢ xS4 xS1 x4  1

9.1 Exercises In Exercises 1–8, use the graph of the given function f to determine lim f(x) at the indicated value of a, if it exists. xS a

y

1. y = f (x)

y

2.

9. f 1x2  x2  1; lim f 1x2

y = f (x) 3 2 1

3 2 1

xS2

x f(x) x

x –3 –2 –1

1 2 3

–3 –2 –1

1 2 3 a=1

a = –2

y

3. 4 3 2 1

y = f (x)

11. f 1x2  x

–2 –1

x –3 –2 –1

1 2 3 a=1

1 2 3 a=3

y

6.

x f(x)

y = f (x) 3 2

4 3

y = f (x) x

1

1 2 3

x –4 –3 –2 –1

a = –2

y

7. y = f (x)

13. f 1x2 

2

1 –3 –2 –1

1 2 a = –2

3 2

14. f 1x2  y = f (x)

x

x 1 2 a = –2

x f(x)

y

8.

3 2 1

–4 –3 –2 –1

x f(x)

12. f 1x2 

y

5.

–3 –2 –1

1 2 3 a=0

1.99

1.999

2.001

2.01

2.1

0.999

1.001

1.01

1.1

0.001

0.001

0.01

0.1

0.999

1.001

1.01

1.1

0.999

1.001

1.01

1.1

1.999

2.001

2.01

2.1

1.001

1.01

1.1

xS1

y = f (x)

3 2 1

1.9

10. f 1x2  2x2  1; lim f 1x2 x f(x)

y

4.

In Exercises 9–16, complete the table by computing f(x) at the given values of x. Use these results to estimate the indicated limit (if it exists).

x f(x)

15. f 1x2  x f(x)

0.9

0.99

0x0 ; lim f 1x2 x xS0 0.1

0.01

0 x  10 ; lim f 1x2 x  1 xS1 0.9

1

1x  12 2 0.9

0.99

; lim f 1x2 xS1

0.99

1 ; lim f 1x2 x  2 xS2 1.9

1.99

x2  x  2 ; lim f 1x2 x1 xS1 0.9

0.99

0.999

549

9.1 LIMITS

16. f 1x2 

x1 ; lim f 1x2 x  1 xS1

x f(x)

0.9

0.99

xSa

0.999

1.001

1.01

1.1

In Exercises 17–22, sketch the graph of the function f and evaluate lim f(x), if it exists, for the given value of a. xS a

x1 1

18. f 1x2  e

x1 2x  8

if x 0 if x  0

x 19. f 1x2  c 0 x  2 2x  4 20. f 1x2  c 4 x2  1 21. f 1x2  e

0x0 1

22. f 1x2  e

0 x  10 0

1a  0 2

if x 3 if x  3

1a  3 2

if x 1 if x  1 if x  1

1a  1 2

if x 1 if x  1 if x  1

if x  0 if x  0

1a  1 2

xS2

xS3

50. lim

x2  x xS0 x

52. lim

x2  25 xS5 x  5

54. lim

x xS1 x  1

56. lim

xS2

61. lim xS1

sS0

2x  1 xS2 x  2

33. lim

x  x  2x

37. lim 22x  x xS3

2x2  8 xS1 2x  4

39. lim

4  x2 2x2  x3

xS

y f (x) = 2x 2 – 10

64.

y f (x) = x 3 – x 5

10

x –1

x

–5

xS2

x3  1

38. lim xS2

40. lim xS3

65.

y f (x) =

f (x) = 12 x

B x2  1 x2x2  7 2x  22x  3

43. lim 32f 1x2  3t1x2 4

44. lim 3 f 1x2 t 1x2 4

x2 x2 + 1

1

2x3  4

42. lim 2f 1x2 xSa

66.

y

2x3  2

41. lim 3 f 1x2  t1x2 4

xSa

1 2 3

3

32. lim 1x2  12 1x2  42

In Exercises 41–48, find the indicated limit given that lim f(x)  3 and lim g(x)  4. xS a

xS2

xS

xS2

2

Hint: See Exercise 59.

62. lim

2

3 36. lim 25x  2

4

1x  1 . 1x  1

tS3

xS1

xS2

x4 1x  2

xS4

x1 3

60. lim

z S2

26. lim 3x

34. lim

35. lim 1x  2

xSa

1x  1 x1

z3  8 z2

63.

xS1

xSa

x2  x  2

58. lim

In Exercises 63–68, use the graph of the function f to determine lim f(x)and lim f(x), if they exist.

30. lim 14x5  20x2  2x  1 2 31. lim 12s 2  1 2 12s  4 2

x2 xS2 x  2

x2  x  6

57. lim

b1 b3

24. lim 3

29. lim 12x3  3x2  x  2 2 xS0

bS3

55. lim

28. lim 14t 2  2t  1 2

xS1

f 1x2  1t 1x2

2x2  3x xS0 x

53. lim

xS2

27. lim 11  2x2 2

t 1x2  f 1x2

x2  4 xS2 x  2

Hint: Multiply by

xS2

25. lim x

x2  1 xS1 x  1

51. lim

1a  0 2 1a  12

xSa

49. lim

xS1

In Exercises 23–40, find the indicated limit.

xS a

f 1x2t 1x2

48. lim

In Exercises 49–62, find the indicated limit, if it exists.

59. lim

if x  1 if x  1

23. lim 3

3

xSa

2f 1x2  t 1x2

47. lim xSa

17. f 1x2  e

46. lim 25f 1x2  3t 1x2

45. lim 1t1x2

x

x –2

2

67.

–3 –2 –1

y 3

f (x) = 2 – x

x –1

1 2 3

550

9 THE DERIVATIVE

68.

y

f 1x2  c

1 x –2 –1

1

2

if x 0

1x x x1

if x  0

81. TOXIC WASTE A city’s main well was recently found to be contaminated with trichloroethylene, a cancer-causing chemical, as a result of an abandoned chemical dump leaching chemicals into the water. A proposal submitted to city council members indicates that the cost, measured in millions of dollars, of removing x% of the toxic pollutant is given by

3

C1x2  In Exercises 69–72, complete the table by computing f(x) at the given values of x. Use the results to guess at the indicated limits, if they exist.

69. f 1x2 

x2  1

x f(x)

1

x f(x)

1

; lim f 1x2 and lim f 1x2 xS

10

lim xS100

xS

100

10

100

1000

2x ; lim f 1x2 and lim f 1x2 x  1 xS xS 1

x f(x)

5

10

100

10

1000

100

1000

f 1x2  3x3  x2  10; lim f 1x2 and lim f 1x2 xS

x f(x)

1

5

1

x f(x)

10

xS

100

5

1000

10

100

1

10

1

100

10

100

4x2  1 74. lim xS x  2

3x3  x2  1 x3  1

xS

76. lim

2x2  3x  1 x4  x2

xS

x 1 4

79. lim xS

C1x2  2.2 

2500 x

84. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration of a certain drug in a patient’s bloodstream t hr after injection is given by C1t2 

3x  2 73. lim xS x  5

xS

83. AVERAGE COST The average cost/disc in dollars incurred by Herald Records in pressing x DVDs is given by the average cost function

xS

In Exercises 73–80, find the indicated limits, if they exist.

78. lim

10 t 92

Evaluate lim C1x2 and interpret your result.

x f(x)

xS

72 9t

where t is measured in months. a. Find the number of rabbits present in the island initially (at t  0). b. Show that the population of rabbits is increasing without bound. c. Sketch the graph of the function P. (Comment: This phenomenon is referred to as a doomsday situation.)

1000

0x0 72. f 1x2  ; lim f 1x2 and lim f 1x2 x xS xS

77. lim

0.5x 100  x

and interpret your result.

1000

P1t2 

x f(x)

75. lim

a. Find the cost of removing 50%, 60%, 70%, 80%, 90%, and 95% of the pollutant. b. Evaluate

82. A DOOMSDAY SITUATION The population of a certain breed of rabbits introduced into an isolated island is given by

70. f 1x2 

71.

1

10 x 100 2

0.5x 100  x

x3  1 4x4  3x2  1

2x4  x3  x2  x  1 x5  x3  x  1 x  2x  1 6

2

80. lim xS

2x2  1 x  x2  1 3

0.2t t2  1

mg/cm3. Evaluate lim C1t2 and interpret your result. tS

85. BOX-OFFICE RECEIPTS The total worldwide box-office receipts for a long-running blockbuster movie are approximated by the function T1x2 

120x2 x2  4

where T(x) is measured in millions of dollars and x is the number of months since the movie’s release. a. What are the total box-office receipts after the first month? The second month? The third month? b. What will the movie gross in the long run (when x is very large)?

9.1 LIMITS

86. RELIABILITY OF COMPUTER CHIPS The percentage of a certain brand of computer chips that will fail after t yr of use is estimated to be 0.1t

P(t)  100(1  e

)

a. What percentage of this brand of computer chips are expected to be usable after 3 yr? b. Evaluate lim P 1t 2 . Did you expect this result? tS

87. DRIVING COSTS A study of driving costs of 2008 mediumsized sedans found that the average cost (car payments, gas, insurance, upkeep, and depreciation), measured in cents/ mile, is approximated by the function C1x 2 

1735.2  38.6 x1.72

where x denotes the number of miles (in thousands) the car is driven in a year. a. What is the average cost of driving a medium-sized sedan 5000 mi/yr? 10,000 mi/yr? 15,000 mi/yr? 20,000 mi/yr? 25,000 mi/yr? b. Use part (a) to sketch the graph of the function C. c. What happens to the average cost as the number of miles driven increases without bound?

90. If lim f 1x2  4 and lim t1x2  0, then lim f 1x2 t1x 2  0. xS0

xS0

xS0

xS2

xS2

xS2

91. If lim f 1x2  3 and lim t1x2  0, then lim 3 f 1x 2 4 / 3 t1x 2 4 does not exist. 92. If lim f 1x2  0 and lim t1x2  0, then lim 3 f 1x 2 4 / 3t1x 2 4 xS3

xS3

xS3

does not exist. 93. lim a

x x 3 3  b  lim  lim x1 x1 xS2 x  1 xS2 x  1

94. lim a

2x 2 2x 2  b  lim  lim x1 x1 xS1 x  1 xS1 x  1

xS2

xS1

95. SPEED OF A CHEMICAL REACTION Certain proteins, known as enzymes, serve as catalysts for chemical reactions in living things. In 1913 Leonor Michaelis and L. M. Menten discovered the following formula giving the initial speed V (in moles/liter/second) at which the reaction begins in terms of the amount of substrate x (the substance being acted upon, measured in moles/liters) present: V

R1I2 

aI b  I2

where a and b are positive constants. a. Taking a  b  1, compute R(I) for I  0, 1, 2, 3, 4, and 5. b. Evaluate lim R1I 2 . IS

c. Use the results of parts (a) and (b) to sketch the graph of R. Interpret your results. In Exercises 89–94, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.

ax xb

where a and b are positive constants. Evaluate

Source: American Automobile Association

88. PHOTOSYNTHESIS The rate of production R in photosynthesis is related to the light intensity I by the function

lim xS

ax xb

and interpret your result. 96. Show by means of an example that lim 3 f 1x 2  t1x 2 4

may exist even though neither lim f 1x2 nor lim t1x 2 exists. xSa

xSa

xSa

Does this example contradict Theorem 1?

97. Show by means of an example that lim 3 f 1x 2 t1x 2 4 may exist even though neither lim f 1x2 nor lim t1x2 exists. Does this xSa

xSa

xSa

example contradict Theorem 1?

98. Show by means of an example that lim f 1x 2/t1x 2 may

exist even though neither lim f 1x2 nor lim t1x 2 exists. Does xSa

xSa

xSa

this example contradict Theorem 1?

89. If lim f 1x 2 exists, then f is defined at x  a. xSa

9.1 Solutions to Self-Check Exercises 1. a. lim xS3

29  7  23132  5 2x2  7  23x  5  x2 32 216  24 5 6  5



b. Letting x approach 1 leads to the indeterminate form 0/0. Thus, we proceed as follows:

551

lim xS1

1x  12 1x  22 x2  x  2  lim 2x2  x  3 xS1 1x  12 12x  32  lim

xS1

x2 2x  3



1  2 211 2  3



3 5

Cancel the common factors.

552

9 THE DERIVATIVE

2. lim C1x2  lim ¢1.8  xS

xS

 lim 1.8  lim xS

Our computation reveals that, as the production of CDs increases “without bound,” the average cost drops and approaches a unit cost of $1.80/disc.

3000 ≤ x

xS

3000 x

 1.8

USING

TECHNOLOGY

Finding the Limit of a Function A graphing utility can be used to help us find the limit of a function, if it exists, as illustrated in the following examples. EXAMPLE 1 Let f 1x2 

x3  1 . x1

a. Plot the graph of f in the viewing window [2, 2]  [0, 4]. b. Use ZOOM to find lim xS1

x3  1 . x1

c. Verify your result by evaluating the limit algebraically. Solution

a. The graph of f in the viewing window [2, 2]  [0, 4] is shown in Figure T1a.

Plot1 Plot2 Plot3 \Y1 = (X^3 −1)/(X − 1) \Y2 = \Y3 = \Y4 = \Y5 = \Y6 =

FIGURE T1 (a) The graph of

f 1x 2 

x3  1 x1

in the viewing window [2, 2]  [0, 4]; (b) the TI-83/84 equation screen

(a)

(b)

b. Using ZOOM-IN repeatedly, we see that the y-value approaches 3 as the x-value approaches 1. We conclude, accordingly, that lim xS1

x3  1 3 x1

c. We compute lim xS1

1x  12 1x2  x  1 2 x3  1  lim x1 xS1 x1  lim 1x2  x  12  3 xS1

Note If you attempt to find the limit in Example 1 by using the evaluation function of your graphing utility to find the value of f(x) when x  1, you will see that the graphing utility does not display the y-value. This happens because x  1 is not in the domain of f.

9.1 LIMITS

553

EXAMPLE 2 Use ZOOM to find lim 11  x2 1/x. xS0

We first plot the graph of f(x)  (1  x)1/x in a suitable viewing window. Figure T2a shows a plot of f in the window [1, 1]  [0, 4]. Using ZOOM-IN repeatedly, we see that lim 11  x2 1/x  2.71828. Solution

xS0

Plot1 Plot2 Plot3 \Y1 = (1 + X)^(1/X) \Y2 = \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

FIGURE T2

(a) The graph of f( x)  (1  x)1/ x in the viewing window [1, 1]  [0, 4]; (b) the T1-83/84 equation screen

(a)

(b)

The limit of f(x)  (1  x)1/x as x approaches zero, denoted by the letter e, plays a very important role in the study of mathematics and its applications (see Section 3.3). Thus, lim 11  x2 1/x  e

xS0

where, as we have just seen, e  2.71828. APPLIED EXAMPLE 3 Oxygen Content of a Pond When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. Suppose the oxygen content t days after the organic waste has been dumped into the pond is given by f 1t2  100 ¢

t 2  10t  100 ≤ t 2  20t  100

percent of its normal level. a. Plot the graph of f in the viewing window [0, 200]  [70, 100]. b. What can you say about f(t) when t is very large? c. Verify your observation in part (b) by evaluating lim f 1t2 . tS

Solution

a. The graph of f is shown in Figure T3a. b. From the graph of f, it appears that f(t) approaches 100 steadily as t gets larger and larger. This observation tells us that eventually the oxygen content of the pond will be restored to its natural level.

Plot1 Plot2 Plot3 \Y1 = 100(X^2 + 10X + 100)/(X^2 + 20X + 100) \Y2 = \Y3 = \Y4 = \Y5 =

FIGURE T3 (a) The graph of f in the viewing window [0, 200]  [70, 100]; (b) the TI-83/84 equation screen

(a)

(b) (continued)

554

9 THE DERIVATIVE

c. To verify the observation made in part (b), we compute lim f 1t2  lim 100 a

tS

tS

t 2  10t  100 b t 2  20t  100

10 100  2 t t  100 lim § ¥  100 tS 20 100 1  2 t t 1

TECHNOLOGY EXERCISES In Exercises 1–10, find the indicated limit by first plotting the graph of the function in a suitable viewing window and then using the ZOOM-IN feature of the calculator.

2x3  2x2  3x  3 xS1 x1

2. lim

2x3  3x2  x  2 xS2 x2

x3  1 xS1 x  1

4.

1. lim

3. lim

5. lim

xS1

x3  x2  x  1

6. lim

x  3x  2 3

xS1

xS0

1x  1  1 x

8. lim

xS0

xS3

x4  1 x1

2x  1 xS0 x

7. lim 11  2x2 1/x

9. Show that lim

lim

2 does not exist. x3 x  2x  1 does not exist. x2 3

10. Show that lim xS2

11. CITY PLANNING A major developer is building a 5000-acre complex of homes, offices, stores, schools, and churches in the rural community of Marlboro. As a result of this development, the planners have estimated that Marlboro’s population (in thousands) t yr from now will be given by P1t2 

25t 2  125t  200 t 2  5t  40

a. Plot the graph of P in the viewing window [0, 50]  [0, 30]. b. What will be the population of Marlboro in the long run? Hint: Find lim P1t2 . tS

12. AMOUNT OF RAINFALL The total amount of rain (in inches) after t hr during a rainfall is given by T1t2 

0.8t t  4.1

a. Plot the graph of T in the viewing window [0, 30]  [0, 0.8]. b. What is the total amount of rain during this rainfall? Hint: Find lim T1t2 . tS

9.2 One-Sided Limits and Continuity One-Sided Limits y

Consider the function f defined by f 1x2  e

y = f (x) 1 x –1

1 –1

FIGURE 12 The function f does not have a limit as x approaches zero.

x1 x1

if x 0 if x  0

From the graph of f shown in Figure 12, we see that the function f does not have a limit as x approaches zero because, no matter how close x is to zero, f(x) takes on values that are close to 1 if x is positive and values that are close to 1 if x is negative. Therefore, f(x) cannot be close to a single number L—no matter how close x is to zero. Now, if we restrict x to be greater than zero (to the right of zero), then we see that f(x) can be made as close to 1 as we please by taking x sufficiently close to zero. In this situation we say that the right-hand limit of f as x approaches zero (from the right) is 1, written lim f 1x2  1

xS0 

9.2 ONE-SIDED LIMITS AND CONTINUITY

555

Similarly, we see that f (x) can be made as close to 1 as we please by taking x sufficiently close to, but to the left of, zero. In this situation we say that the left-hand limit of f as x approaches zero (from the left) is 1, written lim f 1x2  1

xS0

These limits are called one-sided limits. More generally, we have the following definitions.

One-Sided Limits

The function f has the right-hand limit L as x approaches a from the right, written lim f 1x2  L

xSa

if the values of f (x) can be made as close to L as we please by taking x sufficiently close to (but not equal to) a and to the right of a. Similarly, the function f has the left-hand limit M as x approaches a from the left, written lim f 1x2  M

xSa

if the values of f (x) can be made as close to M as we please by taking x sufficiently close to (but not equal to) a and to the left of a.

The connection between one-sided limits and the two-sided limit defined earlier is given by the following theorem.

THEOREM 3 Let f be a function that is defined for all values of x close to x  a with the possible exception of a itself. Then lim f 1x2  L

if and only if

xSa

lim f 1x2  lim f 1x2  L

xSa

xSa

Thus, the two-sided limit exists if and only if the one-sided limits exist and are equal. EXAMPLE 1 Let f 1x2  e

x 1x

if x 0 1 and t1x2  e if x  0 1

if x 0 if x  0

a. Show that lim f 1x 2 exists by studying the one-sided limits of f as x approaches xS0 x  0. b. Show that lim t 1x 2 does not exist. xS0

Solution

a. For x 0

lim f 1x2  lim 1x2  0

xS0

and for x  0, we find

xS0

lim f 1x2  lim 1x  0

xS0

xS0

556

9 THE DERIVATIVE

Thus,

lim f 1x2  0

xS0

(Figure 13a). b. We have

lim t 1x2  1 and

xS0

lim t1x2  1

xS0

and since these one-sided limits are not equal, we conclude that lim t 1x2 does xS0 not exist (Figure 13b). y

y

2 1

1

x

x –2

–1

1

2 –1

FIGURE 13

(a) lim f(x) exists.

(b) lim g(x) does not exist. xS 0

xS0

Continuous Functions Continuous functions will play an important role throughout most of our study of calculus. Loosely speaking, a function is continuous at a point if the graph of the function at that point is devoid of holes, gaps, jumps, or breaks. Consider, for example, the graph of the function f depicted in Figure 14. y

FIGURE 14 The graph of this function is not continuous at x  a, x  b, x  c, and x  d.

x a

b

c

d

Let’s take a closer look at the behavior of f at or near x  a, x  b, x  c, and x  d. First, note that f is not defined at x  a; that is, x  a is not in the domain of f, thereby resulting in a “hole” in the graph of f. Next, observe that the value of f at b, f(b), is not equal to the limit of f(x) as x approaches b, resulting in a “jump” in the graph of f at x  b. The function f does not have a limit at x  c since the left-hand and right-hand limits of f(x) are not equal, also resulting in a jump in the graph of f at x  c. Finally, the limit of f does not exist at x  d, resulting in a break in the graph of f. The function f is discontinuous at each of these numbers. It is continuous everywhere else. Continuity of a Function at a Number

A function f is continuous at a number x  a if the following conditions are satisfied. 1. f(a) is defined.

2. lim f 1x2 exists. xSa

3. lim f 1x2  f 1a 2 xSa

557

9.2 ONE-SIDED LIMITS AND CONTINUITY

Thus, a function f is continuous at x  a if the limit of f at x  a exists and has the value f(a). Geometrically, f is continuous at x  a if the proximity of x to a implies the proximity of f(x) to f(a). If f is not continuous at x  a, then f is said to be discontinuous at x  a. Also, f is continuous on an interval if f is continuous at every number in the interval. Figure 15 depicts the graph of a continuous function on the interval (a, b). Notice that the graph of the function over the stated interval can be sketched without lifting one’s pencil from the paper.

y

y = f (x)

x

FIGURE 15

a

The graph of f is continuous on the interval (a, b).

b

EXAMPLE 2 Find the values of x for which each function is continuous. b. t 1x2 

a. f(x)  x  2 1 d. F1x2  e 1

x2  4 x2

c. h1x2  e

x2 1

1 e. G1x2  c x 1

if x 0 if x  0

if x  2 if x  2 if x  0 if x 0

The graph of each function is shown in Figure 16. y

y

5

y

5

5

f (x) = x + 2

y = h(x) x2 – 4 g(x) = x–2 x

x 5 (a)

(b)

(c)

y = G(x)

y = F(x) x

x

–1

FIGURE 16

(d)

5

y

y

1

x

5

–1

(e)

558

9 THE DERIVATIVE

Solution

a. The function f is continuous everywhere because the three conditions for continuity are satisfied for all values of x. b. The function g is discontinuous at x  2 because t is not defined at that number. It is continuous everywhere else. c. The function h is discontinuous at x  2 because the third condition for continuity is violated; the limit of h(x) as x approaches 2 exists and has the value 4, but this limit is not equal to h(2)  1. It is continuous for all other values of x. d. The function F is continuous everywhere except at x  0, where the limit of F(x) fails to exist as x approaches zero (see Example 3a, Section 9.1). e. Since the limit of G(x) does not exist as x approaches zero, we conclude that G fails to be continuous at x  0. The function G is continuous everywhere else.

Properties of Continuous Functions The following properties of continuous functions follow directly from the definition of continuity and the corresponding properties of limits. They are stated without proof. Properties of Continuous Functions

1. The constant function f (x)  c is continuous everywhere. 2. The identity function f (x)  x is continuous everywhere. If f and t are continuous at x  a, then 3. [ f(x)]n, where n is a real number, is continuous at x  a whenever it is defined at that number. 4. f t is continuous at x  a. 5. ft is continuous at x  a. 6. f /t is continuous at x  a provided t(a)  0. Using these properties of continuous functions, we can prove the following results. (A proof is sketched in Exercise 100, page 567.) Continuity of Polynomial and Rational Functions

1. A polynomial function y  P(x) is continuous at every value of x. 2. A rational function R(x)  p(x)/q(x) is continuous at every value of x where q(x)  0. EXAMPLE 3 Find the values of x for which each function is continuous. a. f (x)  3x 3  2x 2  x  10 c. h1x 2 

b. t 1x 2 

8x10  4x  1 x2  1

4x 3  3x 2  1 x 2  3x  2

Solution

a. The function f is a polynomial function of degree 3, so f (x) is continuous for all values of x. b. The function t is a rational function. Observe that the denominator of t—namely, x 2  1—is never equal to zero. Therefore, we conclude that t is continuous for all values of x.

9.2 ONE-SIDED LIMITS AND CONTINUITY

559

c. The function h is a rational function. In this case, however, the denominator of h is equal to zero at x  1 and x  2, which can be seen by factoring it. Thus, x 2  3x  2  (x  2)(x  1)

We therefore conclude that h is continuous everywhere except at x  1 and x  2, where it is discontinuous. Up to this point, most of the applications we have discussed involved functions that are continuous everywhere. In Example 4, we consider an application from the field of educational psychology that involves a discontinuous function. APPLIED EXAMPLE 4 Learning Curves Figure 17 depicts the learning curve associated with a certain individual. Beginning with no knowledge of the subject being taught, the individual makes steady progress toward understanding it over the time interval 0 t t1. In this instance, the individual’s progress slows as we approach time t1 because he fails to grasp a particularly difficult concept. All of a sudden, a breakthrough occurs at time t1, propelling his knowledge of the subject to a higher level. The curve is discontinuous at t1.

Knowledge of subject

y (%) 1 00

t (time)

t1

FIGURE 17

A learning curve that is discontinuous at t  t1

Intermediate Value Theorem Let’s look again at our model of the motion of the maglev on a straight stretch of track. We know that the train cannot vanish at any instant of time and it cannot skip portions of the track and reappear someplace else. To put it another way, the train cannot occupy the positions s1 and s2 without at least, at some time, occupying an intermediate position (Figure 18).

s1 FIGURE 18

s

s2

Not possible

s1

s

s2

Possible

The position of the maglev

To state this fact mathematically, recall that the position of the maglev as a function of time is described by f(t)  4t 2

(0 t 10)

560

9 THE DERIVATIVE

Suppose the position of the maglev is s1 at some time t1 and its position is s2 at some time t2 (Figure 19). Then, if s3 is any number between s1 and s2 giving an intermediate position of the maglev, there must be at least one t3 between t1 and t2 giving the time at which the train is at s3—that is, f(t3)  s3. s y = 4t2 s2 s3

FIGURE 19

s1

If s1 s3 s2, then there must be at least one t3 (t1 t3 t2) such that f(t3)  s3.

t1

t3

t

t2

This discussion carries the gist of the intermediate value theorem. The proof of this theorem can be found in most advanced calculus texts.

THEOREM 4 The Intermediate Value Theorem

If f is a continuous function on a closed interval [a, b] and M is any number between f(a) and f(b), then there is at least one number c in [a, b] such that f(c)  M (Figure 20). y

y f(b)

f(b) M

y = f(x)

f(a)

M f(a)

y = f (x) x a

FIGURE 20

(a) f(c)  M

c b

x a c1

c2

c3

b

(b) f(c1)  f(c2)  f(c3)  M

To illustrate the intermediate value theorem, let’s look at the example involving the motion of the maglev again (see Figure 2, page 535). Notice that the initial position of the train is f(0)  0 and the position at the end of its test run is f (10)  400. Furthermore, the function f is continuous on [0, 10]. So, the intermediate value theorem guarantees that if we arbitrarily pick a number between 0 and 400—say, 100—giving the position of the maglev, there must be a t (read “t bar”) between 0 and 10 at which time the train is at the position s  100. To find the value of t, we solve the equation f( t )  s, or 4t 2  100

giving t  5 (t must lie between 0 and 10). It is important to remember when we use Theorem 4 that the function f must be continuous. The conclusion of the intermediate value theorem may not hold if f is not continuous (see Exercise 101, page 567). The next theorem is an immediate consequence of the intermediate value theorem. It not only tells us when a zero of a function f [root of the equation f(x)  0] exists but also provides the basis for a method of approximating it.

9.2 ONE-SIDED LIMITS AND CONTINUITY

561

THEOREM 5 Existence of Zeros of a Continuous Function

If f is a continuous function on a closed interval [a, b], and if f(a) and f(b) have opposite signs, then there is at least one solution of the equation f(x)  0 in the interval (a, b) (Figure 21). y

y f (b)

f (a)

y x

x a

f (b)

c

b

a

c1 c2

b

f (a) f (c1) = f (c2) = 0

f (b) x a

b

FIGURE 21

If f(a) and f(b) have opposite signs, there must be at least one number c (a c b) such that f(c)  0.

f (a) FIGURE 22

f(a) 0 and f(b)  0, but the graph of f does not cross the x-axis between a and b because f is discontinuous.

Geometrically, this property states that if the graph of a continuous function goes from above the x-axis to below the x-axis, or vice versa, it must cross the x-axis. This is not necessarily true if the function is discontinuous (Figure 22). EXAMPLE 5 Let f(x)  x 3  x  1. a. Show that f is continuous for all values of x. b. Compute f(1) and f(1) and use the results to deduce that there must be at least one number x  c, where c lies in the interval (1, 1) and f(c)  0. Solution

a. The function f is a polynomial function of degree 3 and is therefore continuous everywhere. b. f(1)  (1)3  (1)  1  1 and f(1)  13  1  1  3 Since f(1) and f(1) have opposite signs, Theorem 5 tells us that there must be at least one number x  c with 1 c 1 such that f(c)  0. The next example shows how the intermediate value theorem can be used to help us find the zero of a function. EXAMPLE 6 Let f(x)  x 3  x  1. Since f is a polynomial function, it is continuous everywhere. Observe that f(0)  1 and f(1)  1 so that Theorem 5 guarantees the existence of at least one root of the equation f(x)  0 in (0, 1).* We can locate the root more precisely by using Theorem 5 once again as follows: Evaluate f(x) at the midpoint of [0, 1], obtaining f(0.5)  0.375

*It can be shown that f has precisely one zero in (0, 1) (see Exercise 111, Section 10.1).

562

9 THE DERIVATIVE

Because f(0.5) 0 and f (1)  0, Theorem 5 now tells us that the root must lie in (0.5, 1). Repeat the process: Evaluate f (x) at the midpoint of [0.5, 1], which is 0.5  1  0.75 2

TABLE 3 Step Root of f(x)  0 Lies in

1 2 3 4 5 6 7 8 9

(0, 1) (0.5, 1) (0.5, 0.75) (0.625, 0.75) (0.625, 0.6875) (0.65625, 0.6875) (0.671875, 0.6875) (0.6796875, 0.6875) (0.6796875, 0.6835937)

Thus, f(0.75)  0.1719

Because f(0.5) 0 and f(0.75)  0, Theorem 5 tells us that the root is in (0.5, 0.75). This process can be continued. Table 3 summarizes the results of our computations through nine steps. From Table 3 we see that the root is approximately 0.68, accurate to two decimal places. By continuing the process through a sufficient number of steps, we can obtain as accurate an approximation to the root as we please. The process of finding the root of f (x)  0 used in Example 6 is called the method of bisection. It is crude but effective.

Note

9.2 Self-Check Exercises 1. Evaluate lim f 1x 2 and lim  f 1x 2 , where xS1

f 1x 2  e

xS1

1 1  1x  1

if x 1 if x  1

Does lim f 1x 2 exist? xS1

2. Determine the values of x for which the given function is discontinuous. At each number where f is discontinuous, indicate which condition(s) for continuity are violated. Sketch the graph of the function.

a. f 1x 2  e

x 2  1 x1

if x 1 if x  1

x  1

if x 1 if 1 x 1 if x  1

b. t 1x 2  c 2

x  3

Solutions to Self-Check Exercises 9.2 can be found on page 567.

9.2 Concept Questions 1. Explain what is meant by the statement lim f 1x2  2 and xS3 lim f 1x 2  4. xS3

2. Suppose lim f 1x 2  3 and lim f 1x 2  4.

a. What can you say about lim f 1x 2? Explain. xS1

xS1

xS1

b. What can you say about f (1)? Explain. 3. Explain what it means for a function f to be continuous (a) at a number a and (b) on an interval I. 4. Determine whether each function f is continuous or discontinuous. Explain your answer.

a. f(t) gives the altitude of an airplane at time t. b. f(t) measures the total amount of rainfall at time t at the Municipal Airport. c. f(s) measures the fare as a function of the distance s for taking a cab from Kennedy Airport to downtown Manhattan. d. f(t) gives the interest rate charged by a financial institution at time t. 5. Explain the intermediate value theorem in your own words.

563

9.2 ONE-SIDED LIMITS AND CONTINUITY

9.2 Exercises In Exercises 1–8, use the graph of the function f to find lim f(x), lim f(x), and lim f(x) at the indicated value of xSa 

xSa 

xSa

a, if the limit exists.

1.

2.

y 5 4 3 2 1

3 2 1 x

11. lim f 1x2  2

12. lim f 1x2  3

13. lim f 1x2 does not exist.

14. lim f 1x2  3 xS5

y x

2

4

1 2 3 4 5 6 a=3

4.

y

xS2

In Exercises 15–20, refer to the graph of the function f and determine whether each statement is true or false.

y = f (x)

a=2

3.

xS0

xS3

y = f (x)

1

xS3

xS2

y

– 2 –1

10. lim f 1x2  f 102

9. lim  f 1x2  1

y = f(x)

3 2

y

1 3

y = f (x)

2

x

2

1 –3 –2 –1

1

x – 2 –1

2

1

a = –1

2

6.

y

1

2

y = f (x)

5

6

17. lim f 1x2  1

18. lim f 1x2  3

xS0

xS4

19. lim f 1x2 does not exist. 20. lim f 1x2  2 y = f (x)

1 x

x 1

–1

2

1

2

a=0

a=1

8.

y

21. lim 12x  42

22. lim 13x  42

x3 23. lim xS2 x  2

24. lim

x2 x1

xS1

y 2

y = f (x)

1

26. lim

1 x

27. lim

x1 x2  1

28. lim

x1 x2  2x  3

xS0

x –1

1

x

2

–2

–1

1

2

–1 –2 a = 0

a=0

In Exercises 9–14, refer to the graph of the function f and determine whether each statement is true or false. y

30. lim 21x  2

31. lim  12x  12  x 2

32. lim  x11  15  x 2

xS2

xS2

xS5

33. lim

1x 1x

34. lim

35. lim

x2  4 x2

36. lim

xS1

xS0

1

2

3

4

5



xS3

1x  3 x2  1

xS0

f 1x2  e

x

1x 1x

xS1

37. lim f 1x2 and lim f 1x2 , where

y = f(x)

1 –1

xS2

xS0

2

–2

xS0

29. lim 1x

xS2

3

xS1

1 x

y = f (x)

1

xS1

25. lim xS0

2

xS4

In Exercises 21–38, find the indicated one-sided limit, if it exists.

2

2

7.

4

16. lim f 1x2  2

xS4

3

– 2 –1

3

15. lim  f 1x2  2 xS2

4

–3

–1

xS3

a=1

y

–2

–2

1 x

5.

–3

y = f (x)

2x x2

if x 0 if x  0

38. lim f 1x2 and lim f 1x2 , where xS0

xS0

f 1x2  e

x  1 2x  3

if x 0 if x  0

564

9 THE DERIVATIVE

In Exercises 39–44, determine the values of x, if any, at which each function is discontinuous. At each number where f is discontinuous, state the condition(s) for continuity that are violated. 2x  4 if x 0 y 39. f 1x2  e 1 if x  0 5 x 5

In Exercises 45–56, find the values of x for which each function is continuous.

45. f(x)  2x 2  x  1 46. f(x)  x 3  2x 2  x  1 47. f 1x2 

2 x2  1

48. f 1x2 

x 2x2  1

49. f 1x2 

2 2x  1

50. f 1x2 

x1 x1

51. f 1x2 

2x  1 x2  x  2

52. f 1x2 

x1 x2  2x  3

–5 –10

40.

f 1x2  e

y

x2  1 0

if x  0 if x  0

53. f 1x2  e

x 2x  1

54. f 1x2  e

2x  1 x2  1

if x 1 if x  1

10

5

55. f 1x2  | x  1 |

x – 4 – 3 – 2 –1

41.

1 2 3 4

y

f 1x2  e

x5 x 2  5

if x 0 if x  0

5 x –10 – 5 –5

5 10

42.

57. f 1x2 

2x x2  1

58. f 1x2 

1 1x  12 1x  2 2

59. f 1x2 

x2  2x x2  3x  2

60. f 1x2 

x2  3x  2 x2  2x

117 134 f 1x2  d o 321

x 5

43.

x5 f 1x2  c 2 x 2  5

y

5

if x 0 if x  0 if x  0

x –10 – 5 –5

| x  1| x1

In Exercises 57–60, determine all values of x at which the function is discontinuous.

5

–5

56. f 1x2 

61. THE POSTAGE FUNCTION The graph of the “postage function” for 2008,

f 1x2  | x  1 |

y

if x 0 if x  0

if 0 x 1 if 1 x 2 if 12 x 13

where x denotes the weight of a package in ounces and f(x) the postage in cents, is shown in the accompanying figure. Determine the values of x for which f is discontinuous.

y (¢) 300

5 10

200 y

44.

x2  1 f 1x2  c x  1 1

3

x 4

100

if x  1 if x  1

2

4

6

8

10 12

x (oz)

9.2 ONE-SIDED LIMITS AND CONTINUITY

62. INVENTORY CONTROL As part of an optimal inventory policy, the manager of an office supply company orders 500 reams of photocopy paper every 20 days. The accompanying graph shows the actual inventory level of paper in an office supply store during the first 60 business days of 2009. Determine the values of t for which the “inventory function” is discontinuous and give an interpretation of the graph.

565

65. ENERGY CONSUMPTION The following graph shows the amount of home heating oil remaining in a 200-gal tank over a 120-day period (t  0 corresponds to October 1). Explain why the function is discontinuous at t  40, 70, 95, and 110. y

y

Gallons

Reams

800 600 400

200

100

200 20

40 Days

t

60

t 10 20 30 40 50 60 70 80 90 100 110 120 Days

63. LEARNING CURVES The following graph describes the progress Michael made in solving a problem correctly during a mathematics quiz. Here, y denotes the percent of work completed, and x is measured in minutes. Give an interpretation of the graph.

66. PRIME INTEREST RATE The function P, whose graph follows, gives the prime rate (the interest rate banks charge their best corporate customers) for a certain country as a function of time for the first 32 wk in 2009. Determine the values of t for which P is discontinuous and interpret your results. y (percent per year)

y (%) 8

100

7 6 x2 x1 Minutes

x3

t (weeks)

x

4

64. AILING FINANCIAL INSTITUTIONS Franklin Savings and Loan acquired two ailing financial institutions in 2009. One of them was acquired at time t  T1, and the other was acquired at time t  T2 (t  0 corresponds to the beginning of 2009). The following graph shows the total amount of money on deposit with Franklin. Explain the significance of the discontinuities of the function at T1 and T2.

Millions of dollars

y

8

12

16

20

24

28

32

67. ADMINISTRATION OF AN INTRAVENOUS SOLUTION A dextrose solution is being administered to a patient intravenously. The 1-liter (L) bottle holding the solution is removed and replaced by another as soon as the contents drop to approximately 5% of the initial (1-L) amount. The rate of discharge is constant, and it takes 6 hr to discharge 95% of the contents of a full bottle. Draw a graph showing the amount of dextrose solution in a bottle in the IV system over a 24-hr period, assuming that we started with a full bottle. 68. COMMISSIONS The base monthly salary of a salesman working on commission is $22,000. For each $50,000 of sales beyond $100,000, he is paid a $1000 commission. Sketch a graph showing his earnings as a function of the level of his sales x. Determine the values of x for which the function f is discontinuous.

800 600 400 200 t 1

2

3

4

5

6

8 T

T

1

7

Months

2

9

10 11 12

69. PARKING FEES The fee charged per car in a downtown parking lot is $2.00 for the first half hour and $1.00 for each additional half hour or part thereof, subject to a maximum of $10.00. Derive a function f relating the parking fee to the length of time a car is left in the lot. Sketch the graph of f and determine the values of x for which the function f is discontinuous.

566

9 THE DERIVATIVE

70. COMMODITY PRICES The function that gives the cost of a certain commodity is defined by 5x 4x C1x 2  d 3.5x 3.25x

if 0 x 10 if 10 x 30 if 30 x 60 if x  60

where x is the number of pounds of a certain commodity sold and C(x) is measured in dollars. Sketch the graph of the function C and determine the values of x for which the function C is discontinuous. 71. WEISS’S LAW According to Weiss’s law of excitation of tissue, the strength S of an electric current is related to the time t the current takes to excite tissue by the formula a S1t 2   b t

1t  0 2

where a and b are positive constants. a. Evaluate lim S1t 2 and interpret your result. tS0

b. Evaluate lim S1t 2 and interpret your result. tS

(Note: The limit in part (b) is called the threshold strength of the current. Why?) 72. ENERGY EXPENDED BY A FISH Suppose a fish swimming a distance of L ft at a speed of √ ft/sec relative to the water and against a current flowing at the rate of u ft/sec (u √) expends a total energy given by E1√ 2 

aL√ 3 √u

where E is measured in foot-pounds (ft-lb) and a is a constant. a. Evaluate lim E1√ 2 and interpret your result. √Su

b. Evaluate lim E1√ 2 and interpret your result. √ S

73. Let f 1x 2  e

x2 kx 2

77. f(x)  x 2  6x  8; a  1, b  3 78. f(x)  2x 3  3x 2  36x  14; a  0, b  1 79. f(x)  x 3  2x 2  3x  2; a  1, b  1 80. f(x)  2x 5/3  5x 4/3; a  14, b  16 In Exercises 81–82, use the intermediate value theorem to find the value of c such that f(c)  M.

81. f(x)  x 2  4x  6 on [0, 3]; M  4 82. f(x)  x 2  x  1 on [1, 4]; M  7 83. Use the method of bisection (see Example 6) to find the root of the equation x 5  2x  7  0 accurate to two decimal places. 84. Use the method of bisection (see Example 6) to find the root of the equation x 3  x  1  0 accurate to two decimal places. 85. FALLING OBJECT Joan is looking straight out a window of an apartment building at a height of 32 ft from the ground. A boy throws a tennis ball straight up by the side of the building where the window is located. Suppose the height of the ball (measured in feet) from the ground at time t is h(t)  4  64t  16t 2. a. Show that h(0)  4 and h(2)  68. b. Use the intermediate value theorem to conclude that the ball must cross Joan’s line of sight at least once. c. At what time(s) does the ball cross Joan’s line of sight? Interpret your results. 86. OXYGEN CONTENT OF A POND The oxygen content t days after organic waste has been dumped into a pond is given by

if x 1 if x  1

Find the value of k that will make f continuous on (, ). 74. Let x2  4 f 1x 2  c x  2 k

In Exercises 77–80, (a) show that the function f is continuous for all values of x in the interval [a, b] and (b) prove that f must have at least one zero in the interval (a, b) by showing that f(a) and f(b) have opposite signs.

if x  2 if x  2

For what value of k will f be continuous on (, )?

f 1t2  100¢

t 2  10t  100 ≤ t 2  20t  100

percent of its normal level. a. Show that f(0)  100 and f(10)  75. b. Use the intermediate value theorem to conclude that the oxygen content of the pond must have been at a level of 80% at some time. c. At what time(s) is the oxygen content at the 80% level? Hint: Use the quadratic formula.

75. a. Suppose f is continuous at a and t is discontinuous at a. Is the sum f  t discontinuous at a? Explain. b. Suppose f and t are both discontinuous at a. Is the sum f  t necessarily discontinuous at a? Explain.

In Exercises 87–96, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

76. a. Suppose f is continuous at a and t is discontinuous at a. Is the product ft necessarily discontinuous at a? Explain. b. Suppose f and t are both discontinuous at a. Is the product ft necessarily discontinuous at a? Explain.

88. If lim f 1x2  3, then f(0)  3.

87. If f(2)  4, then lim f 1x2  4. xS2

xS0

89. If lim f(x)  3 and f(2)  3 then lim f(x)  3. xS2

xS2

90. If lim f(x) and lim f(x) both exist, then lim f(x) exists. xS3

xS3

xS3

9.2 ONE-SIDED LIMITS AND CONTINUITY

91. If f(5) is not defined, then lim f(x) does not exist. xS5

92. Suppose the function f is defined on the interval [a, b]. If f(a) and f(b) have the same sign, then f has no zero in [a, b]. 93. If lim f 1x2  L and lim f 1x2  L, then f(a)  L. xSa

xSa

xSa

xSa

94. If lim f 1x2  L, then lim f 1x2  lim f 1x2  0. xSa

95. If f is continuous for all x  0 and f(0)  0, then lim f 1x2  0. xS0

96. If lim f 1x2  L and t(a)  M, then lim f 1x2t 1x2  LM. xSa

xSa

97. Suppose f is continuous on [a, b] and f(a) f(b). If M is a number that lies outside the interval [ f(a), f(b)], then there does not exist a number a c b such that f(c)  M. Does this contradict the intermediate value theorem? x2 98. Let f 1x2  2 . x 1 a. Show that f is continuous for all values of x. b. Show that f(x) is nonnegative for all values of x. c. Show that f has a zero at x  0. Does this contradict Theorem 5?

567

99. Let f 1x2  x  21  x2. a. Show that f is continuous for all values of x in the interval [1, 1]. b. Show that f has at least one zero in [1, 1]. c. Find the zeros of f in [1, 1] by solving the equation f(x)  0. 100. a. Prove that a polynomial function y  P(x) is continuous at every number x. Follow these steps: (i) Use Properties 2 and 3 of continuous functions to establish that the function t(x)  x n, where n is a positive integer, is continuous everywhere. (ii) Use Properties 1 and 5 to show that f(x)  cx n, where c is a constant and n is a positive integer, is continuous everywhere. (iii) Use Property 4 to complete the proof of the result. b. Prove that a rational function R(x)  p(x)/q(x) is continuous at every point x, where q(x)  0. Hint: Use the result of part (a) and Property 6.

101. Show that the conclusion of the intermediate value theorem does not necessarily hold if f is discontinuous on [a, b].

9.2 Solutions to Self-Check Exercises 1. For x 1, f(x)  1, and so

b. The graph of t follows:

lim f 1x2  lim  1  1

xS1

y

xS1

For x  1, f 1x2  1  1x  1, and so

4

lim f 1x2  lim  11  1x  12  1

xS1

3

xS1

Since the left-hand and right-hand limits of f exist as x approaches x  1 and both are equal to 1, we conclude that lim f 1x2  1

1 x –3 –2 –1

1

2

3

4

xS1

Since t is not defined at x  1, it is discontinuous there. It is continuous everywhere else.

2. a. The graph of f follows: y 3 2 1 x –3 –2

1

2

3

4

We see that f is continuous everywhere.

568

9 THE DERIVATIVE

USING

Finding the Points of Discontinuity of a Function

TECHNOLOGY

You can very often recognize the points of discontinuity of a function f by examining its graph. For example, Figure T1a shows the graph of f(x)  x/(x 2  1) obtained using a graphing utility. It is evident that f is discontinuous at x  1 and x  1. This observation is also borne out by the fact that both these points are not in the domain of f. Plot1 Plot2 Plot3 \Y1 = X/(X^2 − 1) \Y2 = \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

FIGURE T1 (a) The graph of f 1x2 

x x2  1

in the viewing window [4, 4]  [10, 10]; (b) the TI-83/84 equation screen

(a)

(b)

Consider the function t 1x2 

2x3  x2  7x  6 x2  x  2

Using a graphing utility, we obtain the graph of t shown in Figure T2a. Plot1 Plot2 Plot3 \Y1 = (2X^3 + X^2 − 7X − 6) \ /(X^2 − X − 2) \Y2 = \Y3 = \Y4 = \Y5 = \Y6 =

FIGURE T2 (a) The graph of g 1x2 

2x 3  x 2  7x  6 x2  x  2

in the standard viewing window; (b) the TI-83/84 equation screen.

(a)

An examination of this graph does not reveal any points of discontinuity. However, if we factor both the numerator and the denominator of the rational expression, we see that

y 8 7 6 5 4 3 2 1

t 1x2 

–2

–1 –1 –2

1x  12 1x  22 12x  32

1x  12 1x  22  2x  3

x –3

(b)

1

2

3

provided x  1 and x  2, so that its graph in fact looks like that shown in Figure T3. This example shows the limitation of the graphing utility and reminds us of the importance of studying functions analytically!

FIGURE T3 The graph of g has holes at (1, 1) and (2, 7).

Graphing Functions Defined Piecewise The following example illustrates how to plot the graphs of functions defined in a piecewise manner on a graphing utility. EXAMPLE 1 Plot the graph of x1 f 1x2  c 2 x

if x 1 if x  1

9.2 ONE-SIDED LIMITS AND CONTINUITY

Solution

569

We enter the function y1  (x  1)(x 1)  (2/x)(x  1)

Figure T4 shows the graph of the function in the viewing window [5, 5]  [2, 4]. Plot1 Plot2 Plot3 \Y1 = (X + 1)(X ≤ 1) + (2/X)(X > 1) \Y2 = \Y3 = \Y4 = \Y5 = \Y6 =

FIGURE T4 (a) The graph of f in the viewing window [5, 5]  [2, 4]; (b) the TI-83/84 equation screen.

(a)

(b)

APPLIED EXAMPLE 2 TV Viewing Patterns The percent of U.S. households, P(t), watching television during weekdays between the hours of 4 p.m. and 4 a.m. is given by P1t2  e

0.01354t 4  0.49375t 3  2.58333t 2  3.8t  31.60704 1.35t 2  33.05t  208

if 0 t 8 if 8 t 12

where t is measured in hours, with t  0 corresponding to 4 p.m. Plot the graph of P in the viewing window [0, 12]  [0, 80]. Source: A. C. Nielsen Co.

Solution

We enter the function

y1  (.01354xˆ4  .49375xˆ3  2.58333xˆ2  3.8x  31.60704)(x  0)(x 8)  (1.35xˆ2  33.05x  208)(x  8)(x 12)

Figure T5a shows the graph of P. Plot1 Plot2 Plot3 \Y1 = (.01354X^4 − .49375X^3 + 2.58333 X^2 + 3.8X + 31.60704) (X ≥ 0) (X ≤ 8) + (1.35X^2 − 33.05X + 208) (X > 8) (X ≤ 12) \Y2 =

FIGURE T5 (a) The graph of P in the viewing window [0, 12]  [0, 80]; (b) the TI-83/84 equation screen

(a)

(b)

TECHNOLOGY EXERCISES In Exercises 1–8, plot the graph of f and find the points of discontinuity of f. Then use analytical means to verify your observation and find all numbers where f is discontinuous. 3 2 1. f 1x2  2 2. f 1x2  x x 1x1x  12 6x 3  x 2  2x 3. f 1x2  2x 2  x

5. f 1x2 

2x 4  3x 3  2x 2 2x 2  3x  2

2x 3  x 2  13x  6 4. f 1x2  2x 2  5x  3

6. f 1x2 

6x 4  x 3  5x 2  1 6x 2  x  1

7. f 1x2 

x3  x2  2x x  2x3  x  2 4

Hint: x4  2x3  x  2  (x3  1)(x  2)

8. f 1x2 

x

4/3

x3  x  x  x 1/3  1

Hint: x4/3  x  x 1/3  1  (x 1/3  1)(x  1) Can you explain why part of the graph is missing?

(continued)

570

9 THE DERIVATIVE

In Exercises 9 and 10, plot the graph of f in the indicated viewing window.

9. f 1x2  e 10. f 1x2  e

2 24  x2

if x 0 if x  0; 3 2, 2 4  3 4, 44

x  x  2 2x3  x2  4

11. FLIGHT PATH

2

OF A

if x 1 if x  1; 34, 44  35, 5 4

where both x and f(x) are measured in units of 1000 ft, describes the flight path of a plane taking off from the origin and climbing to an altitude of 15,000 ft. Plot the graph of f to visualize the trajectory of the plane. 12. HOME SHOPPING INDUSTRY According to industry sources, revenue from the home shopping industry for the years since its inception may be approximated by the function R1t2  e

PLANE The function

0 0.00411523x3  0.0679012x 2 f 1x2  d 0.123457x  0.0596708 1.5

if 0 x 1

0.03t 3  0.25t 2  0.12t 0.57t  0.63

if 0 t 3 if 3 t 11

where R(t) measures the revenue in billions of dollars and t is measured in years, with t  0 corresponding to the beginning of 1984. Plot the graph of R.

if 1 x 10 if 10 x 100

Source: Paul Kagan Associates

9.3 The Derivative An Intuitive Example We mentioned in Section 9.1 that the problem of finding the rate of change of one quantity with respect to another is mathematically equivalent to the problem of finding the slope of the tangent line to a curve at a given point on the curve. Before going on to establish this relationship, let’s show its plausibility by looking at it from an intuitive point of view. Consider the motion of the maglev discussed in Section 9.1. Recall that the position of the maglev at any time t is given by s  f(t)  4t 2

(0 t 30)

where s is measured in feet and t in seconds. The graph of the function f is sketched in Figure 23. s ( ft)

60 s = f (t)

40 20

FIGURE 23

1

2

3

4

t (sec)

Graph showing the position s of a maglev at time t

Observe that the graph of f rises slowly at first but more rapidly as t increases, reflecting the fact that the speed of the maglev is increasing with time. This observation suggests a relationship between the speed of the maglev at any time t and the steepness of the curve at the point corresponding to this value of t. Thus, it would appear that we can solve the problem of finding the speed of the maglev at any time if we can find a way to measure the steepness of the curve at any point on the curve. To discover a yardstick that will measure the steepness of a curve, consider the graph of a function f such as the one shown in Figure 24a. Think of the curve as representing a stretch of roller coaster track (Figure 24b). When the car is at the point

9.3 THE DERIVATIVE

571

P on the curve, a passenger sitting erect in the car and looking straight ahead will have a line of sight that is parallel to the line T, the tangent to the curve at P. As Figure 24a suggests, the steepness of the curve—that is, the rate at which y is increasing or decreasing with respect to x—is given by the slope of the tangent line to the graph of f at the point P(x, f(x)). But for now we will show how this relationship can be used to estimate the rate of change of a function from its graph.

y

y T

n

Li

y = f (x) P(x, f (x))

f eo

h sig

t

y = f (x) T

x

x

(a) T is the tangent line to the curve at P.

(b) T is parallel to the line of sight.

FIGURE 24

APPLIED EXAMPLE 1 Social Security Beneficiaries The graph of the function y  N(t), shown in Figure 25, gives the number of Social Security beneficiaries from the beginning of 1990 (t  0) through the year 2045 (t  55). y T2

(Slope ≈1.15)

Millions

80

10 60

FIGURE 25 The number of Social Security beneficiaries from 1990 through 2045. We can use the slope of the tangent line at the indicated points to estimate the rate at which the number of Social Security beneficiaries will be changing.

≈ 11.5

P2

70

(

1

T 1 Slope ≈ 2

50 P1

20

)

≈ 10

40

t 0

5 10 15 20 25 30 35 40 45 50 55 Years

Use the graph of y  N(t) to estimate the rate at which the number of Social Security beneficiaries was growing at the beginning of the year 2000 (t  10). How fast will the number be growing at the beginning of 2025 (t  35)? [Assume that the rate of change of the function N at any value of t is given by the slope of the tangent line at the point P(t, N(t)).] Source: Social Security Administration

From the figure, we see that the slope of the tangent line T1 to the graph of y  N(t) at P1(10, 44.7) is approximately 0.5. This tells us that the quan1 tity y is increasing at the rate of 2 unit per unit increase in t, when t  10. In other words, at the beginning of the year 2000, the number of Social Security beneficiaries was increasing at the rate of approximately 0.5 million, or 500,000, per year. The slope of the tangent line T2 at P2(35, 71.9) is approximately 1.15. This tells us that at the beginning of 2025 the number of Social Security beneficiaries will be growing at the rate of approximately 1.15 million, or 1,150,000, per year.

Solution

572

9 THE DERIVATIVE

Slope of a Tangent Line In Example 1 we answered the questions raised by drawing the graph of the function N and estimating the position of the tangent lines. Ideally, however, we would like to solve a problem analytically whenever possible. To do this we need a precise definition of the slope of a tangent line to a curve. To define the tangent line to a curve C at a point P on the curve, fix P and let Q be any point on C distinct from P (Figure 26). The straight line passing through P and Q is called a secant line. y C

Q

Secant lines

T P(x, f (x))

FIGURE 26

x

As Q approaches P along the curve C, the secant lines approach the tangent line T.

Now, as the point Q is allowed to move toward P along the curve, the secant line through P and Q rotates about the fixed point P and approaches a fixed line through P. This fixed line, which is the limiting position of the secant lines through P and Q as Q approaches P, is the tangent line to the graph of f at the point P. We can describe the process more precisely as follows. Suppose the curve C is the graph of a function f defined by y  f(x). Then the point P is described by P(x, f(x)) and the point Q by Q(x  h, f(x  h)), where h is some appropriate nonzero number (Figure 27a). Observe that we can make Q approach P along the curve C by letting h approach zero (Figure 27b). y

y y = f (x)

y = f (x) Q

Q(x + h, f (x + h))

P(x, f(x))

C

C P

x

x+h

x

x h h h

FIGURE 27

h (b) As h approaches zero, Q approaches P.

(a) The points P(x, f(x)) and Q(x  h, f(x  h))

Next, using the formula for the slope of a line, we can write the slope of the secant line passing through P(x, f(x)) and Q(x  h, f(x  h)) as f 1x  h2  f 1x2 1x  h2  x



f 1x  h2  f 1x2 h

(3)

9.3 THE DERIVATIVE

573

As observed earlier, Q approaches P, and therefore the secant line through P and Q approaches the tangent line T as h approaches zero. Consequently, we might expect that the slope of the secant line would approach the slope of the tangent line T as h approaches zero. This leads to the following definition.

Slope of a Tangent Line

The slope of the tangent line to the graph of f at the point P(x, f(x)) is given by lim

f 1x  h2  f 1x2

(4)

h

hS0

if it exists.

Rates of Change We now show that the problem of finding the slope of the tangent line to the graph of a function f at the point P(x, f(x)) is mathematically equivalent to the problem of finding the rate of change of f at x. To see this, suppose we are given a function f that describes the relationship between the two quantities x and y—that is, y  f(x). The number f(x  h)  f(x) measures the change in y that corresponds to a change h in x (Figure 28). y y = f (x)

f (x + h )

Q(x + h, f (x + h)) f (x + h) – f (x)

f (x)

P(x, f (x)) h

FIGURE 28

f(x  h)  f(x) is the change in y that corresponds to a change h in x.

x

x+h

x

Then, the difference quotient f 1x  h2  f 1x2 h

(5)

measures the average rate of change of y with respect to x over the interval [x, x  h]. For example, if y measures the position of a car at time x, then quotient (5) gives the average velocity of the car over the time interval [x, x  h]. Observe that the difference quotient (5) is the same as (3). We conclude that the difference quotient (5) also measures the slope of the secant line that passes through the two points P(x, f(x)) and Q(x  h, f(x  h)) lying on the graph of y  f(x). Next, by taking the limit of the difference quotient (5) as h goes to zero—that is, by evaluating lim hS0

f 1x  h2  f 1x2 h

(6)

we obtain the rate of change of f at x. For example, if y measures the position of a car at time x, then the limit (6) gives the velocity of the car at time x. For emphasis, the rate of change of a function f at x is often called the instantaneous rate of change

574

9 THE DERIVATIVE

of f at x. This distinguishes it from the average rate of change of f, which is computed over an interval [x, x  h] rather than at a number x. Observe that the limit (6) is the same as (4). Therefore, the limit of the difference quotient also measures the slope of the tangent line to the graph of y  f(x) at the point (x, f(x)). The following summarizes this discussion. Average and Instantaneous Rates of Change

The average rate of change of f over the interval [x, x  h] or slope of the secant line to the graph of f through the points (x, f(x)) and (x  h, f(x  h)) is f 1x  h2  f 1x2

(7)

Explore & Discuss

h

Explain the difference between the average rate of change of a function and the instantaneous rate of change of a function.

The instantaneous rate of change of f at x or slope of the tangent line to the graph of f at (x, f(x)) is lim

f 1x  h2  f 1x2 h

hS0

(8)

The Derivative The limit (4) or (8), which measures both the slope of the tangent line to the graph of y  f(x) at the point P(x, f(x)) and the (instantaneous) rate of change of f at x, is given a special name: the derivative of f at x. Derivative of a Function

The derivative of a function f with respect to x is the function f  (read “f prime”), f ¿1x2  lim

f 1x  h2  f 1x2 h

hS0

(9)

The domain of f  is the set of all x where the limit exists. Thus, the derivative of a function f is a function f  that gives the slope of the tangent line to the graph of f at any point (x, f(x)) and also the rate of change of f at x (Figure 29). y y = f (x ) T f '(x)

P(x, f (x)) 1

FIGURE 29 The slope of the tangent line at P(x, f(x)) is f (x); f changes at the rate of f (x) units per unit change in x at x.

x

x

Other notations for the derivative of f include: Dx f(x) dy dx y

Read “d sub x of f of x” Read “d y d x” Read “y prime”

9.3 THE DERIVATIVE

575

The last two are used when the rule for f is written in the form y  f(x). The calculation of the derivative of f is facilitated using the following four-step process.

Four-Step Process for Finding f(x)

1. Compute f(x  h). 2. Form the difference f(x  h)  f(x). f 1x  h 2  f 1x2 . 3. Form the quotient h f 1x  h 2  f 1x2 . 4. Compute f ¿1x2  lim hS0 h

EXAMPLE 2 Find the slope of the tangent line to the graph of f(x)  3x  5 at any point (x, f(x)). The slope of the tangent line at any point on the graph of f is given by the derivative of f at x. To find the derivative, we use the four-step process:

Solution Step 1 Step 2 Step 3

Step 4

f(x  h)  3(x  h)  5  3x  3h  5 f(x  h)  f(x)  (3x  3h  5)  (3x  5)  3h f 1x  h 2  f 1x2 3h  3 h h f 1x  h 2  f 1x2 f ¿1x2  lim  lim 3  3 hS0 h hS0

We expect this result since the tangent line to any point on a straight line must coincide with the line itself and therefore must have the same slope as the line. In this case, the graph of f is a straight line with slope 3. EXAMPLE 3 Let f(x)  x 2. a. Find f (x). b. Compute f (2) and interpret your result. Solution y

a. To find f (x), we use the four-step process: Step 1 Step 2

y=

x2

4

(2, 4)

Step 3

Step 4 x –2

2

FIGURE 30 The tangent line to the graph of f (x)  x 2 at (2, 4)

f(x  h)  (x  h)2  x 2  2xh  h2 f(x  h)  f(x)  x 2  2xh  h2  x 2  2xh  h2  h(2x  h) f 1x  h2  f 1x2 h12x  h 2   2x  h h h f 1x  h 2  f 1x2 f ¿1x2  lim  lim 12x  h 2  2x hS0 h hS0

b. f (2)  2(2)  4. This result tells us that the slope of the tangent line to the graph of f at the point (2, 4) is 4. It also tells us that the function f is changing at the rate of 4 units per unit change in x at x  2. The graph of f and the tangent line at (2, 4) are shown in Figure 30.

576

9 THE DERIVATIVE

Exploring with

TECHNOLOGY 1. Consider the function f(x)  x 2 of Example 3. Suppose we want to compute f (2), using Equation (9). Thus, f ¿122  lim

f 12  h2  f 122 h

hS0

 lim

hS0

12  h 2 2  22 h

Use a graphing utility to plot the graph of 12  x2 2  4 t 1x2  x

in the viewing window [3, 3]  [2, 6]. 2. Use ZOOM and TRACE to find lim t1x2 . xS0

3. Explain why the limit found in part 2 is f (2).

EXAMPLE 4 Let f(x)  x 2  4x. a. Find f (x). b. Find the point on the graph of f where the tangent line to the curve is horizontal. c. Sketch the graph of f and the tangent line to the curve at the point found in part (b). d. What is the rate of change of f at this point? Solution

a. To find f(x), we use the four-step process: Step 1 y

Step 2

y = x 2 – 4x

Step 3 x –1 –2 –3 T

1 2 3

5

y=–4 (2, – 4)

FIGURE 31 The tangent line to the graph of y  x 2  4x at (2, 4) is y  4.

Explore & Discuss Can the tangent line to the graph of a function intersect the graph at more than one point? Explain your answer using illustrations.

Step 4

f(x  h)  (x  h)2  4(x  h)  x 2  2xh  h2  4x  4h f(x  h)  f(x)  x 2  2xh  h2  4x  4h  (x 2  4x)  2xh  h2  4h  h(2x  h  4) f 1x  h2  f 1x2 h12x  h  42   2x  h  4 h h f 1x  h2  f 1x2 f ¿1x2  lim  lim 12x  h  42  2x  4 hS0 h hS0

b. At a point on the graph of f where the tangent line to the curve is horizontal and hence has slope zero, the derivative f  of f is zero. Accordingly, to find such point(s) we set f (x)  0, which gives 2x  4  0, or x  2. The corresponding value of y is given by y  f(2)  4, and the required point is (2, 4). c. The graph of f and the tangent line are shown in Figure 31. d. The rate of change of f at x  2 is zero. 1 EXAMPLE 5 Let f 1x2  . x a. Find f (x). b. Find the slope of the tangent line T to the graph of f at the point where x  1. c. Find an equation of the tangent line T in part (b).

9.3 THE DERIVATIVE

577

Solution

a. To find f (x), we use the four-step process: Step 1

Step 2

f 1x  h 2 

1 xh

x  1x  h 2 h 1 1    x xh x1x  h 2 x1x  h2 f 1x  h 2  f 1x2 (x ) See page 22. h 1 1 #   h x1x  h 2 h x1x  h 2 f 1x  h2  f 1x2 1 1  2 f ¿1x2  lim  lim  hS0 h hS0 x1x  h 2 x f 1x  h 2  f 1x2 

2

T

y=

Step 3

y 4 3 1 x

1

Step 4 (1, 1) x

–1

1 2 3 4 y = –x + 2

b. The slope of the tangent line T to the graph of f where x  1 is given by f (1)  1. c. When x  1, y  f(1)  1 and T is tangent to the graph of f at the point (1, 1). From part (b), we know that the slope of T is 1. Thus, an equation of T is y  1  1(x  1) y  x  2

FIGURE 32 The tangent line to the graph of f(x)  1/x at (1, 1)

(Figure 32).

Exploring with

TECHNOLOGY 1. Use the results of Example 5 to draw the graph of f(x)  1/x and its tangent line at the point (1, 1) by plotting the graphs of y1  1/x and y2  x  2 in the viewing window [4, 4]  [4, 4]. 2. Some graphing utilities draw the tangent line to the graph of a function at a given point automatically—you need only specify the function and give the x-coordinate of the point of tangency. If your graphing utility has this feature, verify the result of part 1 without finding an equation of the tangent line.

Explore & Discuss Consider the following alternative approach to the definition of the derivative of a function: Let h be a positive number and suppose P(x  h, f(x  h)) and Q(x  h, f(x  h)) are two points on the graph of f. 1. Give a geometric and a physical interpretation of the quotient f 1x  h 2  f 1x  h2 2h Make a sketch to illustrate your answer. 2. Give a geometric and a physical interpretation of the limit lim

f 1x  h2  f 1x  h 2 2h

hS0

Make a sketch to illustrate your answer. 3. Explain why it makes sense to define f ¿1x2  lim

hS0

f 1x  h2  f 1x  h 2 2h

4. Using the definition given in part 3, formulate a four-step process for finding f (x) similar to that given on page 575 and use it to find the derivative of f(x)  x 2. Compare your answer with that obtained in Example 3 on page 575.

578

9 THE DERIVATIVE

APPLIED EXAMPLE 6 Average Velocity of a Car Suppose the distance (in feet) covered by a car moving along a straight road t seconds after starting from rest is given by the function f(t)  2t 2 (0 t 30). a. Calculate the average velocity of the car over the time intervals [22, 23], [22, 22.1], and [22, 22.01]. b. Calculate the (instantaneous) velocity of the car when t  22. c. Compare the results obtained in part (a) with that obtained in part (b). Solution

a. We first compute the average velocity (average rate of change of f ) over the interval [t, t  h] using Formula (7). We find f 1t  h2  f 1t2 h



21t  h2 2  2t 2 h

2t  4th  2h2  2t 2 h  4t  2h 2



Next, using t  22 and h  1, we find that the average velocity of the car over the time interval [22, 23] is 4(22)  2(1)  90

or 90 feet per second. Similarly, using t  22, h  0.1, and h  0.01, we find that its average velocities over the time intervals [22, 22.1] and [22, 22.01] are 88.2 and 88.02 feet per second, respectively. b. Using the limit (8), we see that the instantaneous velocity of the car at any time t is given by lim hS0

f 1t  h2  f 1t2 h

 lim 14t  2h2

Use the results from part (a).

hS0

 4t

In particular, the velocity of the car 22 seconds from rest (t  22) is given by √  4(22)

or 88 feet per second. c. The computations in part (a) show that, as the time intervals over which the average velocity of the car are computed become smaller and smaller, the average velocities over these intervals do approach 88 feet per second, the instantaneous velocity of the car at t  22.

200

APPLIED EXAMPLE 7 Demand for Tires The management of Titan Tire Company has determined that the weekly demand function of their Super Titan tires is given by

p ($)

p  f(x)  144  x 2

where p is measured in dollars and x is measured in units of a thousand (Figure 33).

100

x 5 10 Thousands of units FIGURE 33 The graph of the demand function p  144  x2

15

a. Find the average rate of change in the unit price of a tire if the quantity demanded is between 5000 and 6000 tires, between 5000 and 5100 tires, and between 5000 and 5010 tires. b. What is the instantaneous rate of change of the unit price when the quantity demanded is 5000 units?

9.3 THE DERIVATIVE

579

Solution

a. The average rate of change of the unit price of a tire if the quantity demanded is between x and x  h is f 1x  h2  f 1x 2 h



3144  1x  h2 2 4  1144  x2 2

h 144  x  2xh  h2  144  x 2  h  2x  h 2

To find the average rate of change of the unit price of a tire when the quantity demanded is between 5000 and 6000 tires (that is, over the interval [5, 6]), we take x  5 and h  1, obtaining 2(5)  1  11

or $11 per 1000 tires. (Remember, x is measured in units of a thousand.) Similarly, taking h  0.1 and h  0.01 with x  5, we find that the average rates of change of the unit price when the quantities demanded are between 5000 and 5100 and between 5000 and 5010 are $10.10 and $10.01 per 1000 tires, respectively. b. The instantaneous rate of change of the unit price of a tire when the quantity demanded is x units is given by lim hS0

f 1x  h2  f 1x2 h

 lim 12x  h2

Use the results from part (a).

hS0

 2x

In particular, the instantaneous rate of change of the unit price per tire when the quantity demanded is 5000 is given by 2(5), or $10 per 1000 tires. The derivative of a function provides us with a tool for measuring the rate of change of one quantity with respect to another. Table 4 lists several other applications involving this limit.

TABLE 4 Applications Involving Rate of Change

f(a  h)  f(a) x Stands for

Time

y Stands for

Number of items sold

Concentration of a drug in the bloodstream at time x Revenue at a sales level of x units

Time

Volume of sales at time x

Time

Population of Drosophila (fruit flies) at time x

Temperature in a chemical reaction

Amount of product formed in the chemical reaction when the temperature is x degrees

h Measures

Average rate of change in the concentration of the drug over the time interval [a, a  h] Average rate of change in the revenue when the sales level is between x  a and x  a  h Average rate of change in the volume of sales over the time interval [a, a  h] Average rate of growth of the fruit fly population over the time interval [a, a  h] Average rate of formation of chemical product over the temperature range [a, a  h]

lim hS 0

f (a  h)  f(a) h Measures

Instantaneous rate of change in the concentration of the drug in the bloodstream at time x  a Instantaneous rate of change in the revenue when the sales level is a units Instantaneous rate of change in the volume of sales at time xa Instantaneous rate of change of the fruit fly population at time xa Instantaneous rate of formation of chemical product when the temperature is a degrees

580

9 THE DERIVATIVE

Differentiability and Continuity In practical applications, one encounters continuous functions that fail to be differentiable—that is, do not have a derivative—at certain values in the domain of the function f. It can be shown that a continuous function f fails to be differentiable at x  a when the graph of f makes an abrupt change of direction at (a, f(a)). We call such a point a “corner.” A function also fails to be differentiable at a point where the tangent line is vertical since the slope of a vertical line is undefined. These cases are illustrated in Figure 34. y

y (a, f (a))

(a, f (a))

x

x

a

a

(a) The graph makes an abrupt change of direction at x  a.

FIGURE 34

(b) The slope at x  a is undefined.

The next example illustrates a function that is not differentiable at a point. y

APPLIED EXAMPLE 8 Wages Mary works at the B&O department store, where, on a weekday, she is paid $8 an hour for the first 8 hours and $12 an hour for overtime. The function

130 110

f 1x2  e

Dollars

90 70

(8, 64)

8x 12x  32

if 0 x 8 if 8 x

gives Mary’s earnings on a weekday in which she worked x hours. Sketch the graph of the function f and explain why it is not differentiable at x  8.

50 30 10

x 2

4

6 8 Hours

10 12

FIGURE 35 The function f is not differentiable at (8, 64).

Solution The graph of f is shown in Figure 35. Observe that the graph of f has a corner at x  8 and consequently is not differentiable at x  8.

We close this section by mentioning the connection between the continuity and the differentiability of a function at a given value x  a in the domain of f. By reexamining the function of Example 8, it becomes clear that f is continuous everywhere and, in particular, when x  8. This shows that in general the continuity of a function at x  a does not necessarily imply the differentiability of the function at that number. The converse, however, is true: If a function f is differentiable at x  a, then it is continuous there. Differentiability and Continuity

If a function is differentiable at x  a, then it is continuous at x  a. For a proof of this result, see Exercise 62, page 586.

Explore & Discuss Suppose a function f is differentiable at x  a. Can there be two tangent lines to the graphs of f at the point (a, f(a))? Explain your answer.

Exploring with

TECHNOLOGY 1. Use a graphing utility to plot the graph of f(x)  x1/3 in the viewing window [2, 2]  [2, 2]. 2. Use a graphing utility to draw the tangent line to the graph of f at the point (0, 0). Can you explain why the process breaks down?

9.3 THE DERIVATIVE

581

EXAMPLE 9 Figure 36 depicts a portion of the graph of a function. Explain why the function fails to be differentiable at each of the numbers x  a, b, c, d, e, f, and t. y

FIGURE 36 The graph of this function is not differentiable at the numbers a–g.

a

b

c

d

e

f

x

g

Solution The function fails to be differentiable at x  a, b, and c because it is discontinuous at each of these numbers. The derivative of the function does not exist at x  d, e, and f because it has a kink at each point on the graph corresponding to these numbers. Finally, the function is not differentiable at x  t because the tangent line is vertical at (t, f(t)).

9.3 Self-Check Exercises 1. Let f(x)  x 2  2x  3. a. Find the derivative f  of f, using the definition of the derivative. b. Find the slope of the tangent line to the graph of f at the point (0, 3). c. Find the rate of change of f when x  0. d. Find an equation of the tangent line to the graph of f at the point (0, 3). e. Sketch the graph of f and the tangent line to the curve at the point (0, 3).

2. The losses (in millions of dollars) due to bad loans extended chiefly in agriculture, real estate, shipping, and energy by the Franklin Bank are estimated to be A  f(t)  t 2  10t  30

(0 t 10)

where t is the time in years (t  0 corresponds to the beginning of 2002). How fast were the losses mounting at the beginning of 2005? At the beginning of 2007? At the beginning of 2009? Solutions to Self-Check Exercises 9.3 can be found on page 586.

9.3 Concept Questions For Questions 1 and 2, refer to the following figure.

2. Refer to Question 1. a. Find an expression for the average rate of change of f over the interval [2, 2  h]. b. Find an expression for the instantaneous rate of change of f at 2. c. Compare your answers for part (a) and (b) with those of Question 1.

y y  f(x)

f(2  h)

Q(2  h, f(2  h)) f(2  h)  f(2)

f(2)

P(2, f(2))

f 1x  h 2  f 1x2

h 2

3. a. Give a geometric and a physical interpretation of the expression

2h

x

1. Let P(2, f(2)) and Q(2  h, f(2  h)) be points on the graph of a function f. a. Find an expression for the slope of the secant line passing through P and Q. b. Find an expression for the slope of the tangent line passing through P.

h

b. Give a geometric and a physical interpretation of the expression lim hS0

f 1x  h 2  f 1x2 h

4. Under what conditions does a function fail to have a derivative at a number? Illustrate your answer with sketches.

582

9 THE DERIVATIVE

9.3 Exercises 1. AVERAGE WEIGHT OF AN INFANT The following graph shows the weight measurements of the average infant from the time of birth (t  0) through age 2 (t  24). By computing the slopes of the respective tangent lines, estimate the rate of change of the average infant’s weight when t  3 and when t  18. What is the average rate of change in the average infant’s weight over the first year of life?

y (%) T2

70 60 50 40 30 20 10

2

T1 12.3

42.3

4

t (hr) 2

y

T2

Average weight of infants (in pounds)

30 3.5 T1

6

22.5 20 7.5 5 10 7.5

6

8 10 12 14 16 18 20 22 24

4. CROP YIELD Productivity and yield of cultivated crops are often reduced by insect pests. The following graph shows the relationship between the yield of a certain crop, f(x), as a function of the density of aphids x. (Aphids are small insects that suck plant juices.) Here, f(x) is measured in kilograms/4000 square meters, and x is measured in hundreds of aphids/bean stem. By computing the slopes of the respective tangent lines, estimate the rate of change of the crop yield with respect to the density of aphids when that density is 200 aphids/bean stem and when it is 800 aphids/bean stem. Source: The Random House Encyclopedia

t 2 4 6 8 10 12 14 16 18 20 22 24 Months 3

Source: The Random House Encyclopedia

Crop yield (kg/m 2 )

y

2. FORESTRY The following graph shows the volume of wood produced in a single-species forest. Here f(t) is measured in cubic meters/hectare and t is measured in years. By computing the slopes of the respective tangent lines, estimate the rate at which the wood grown is changing at the beginning of year 10 and at the beginning of year 30.

1000

300 500

500

300 T1

150 T2

x

200 400 600 800 1000 1200 1400 1600 Aphids per bean stem

y Volume of wood produced (cubic meters/hectare)

4

T2

5. The position of car A and car B, starting out side by side and traveling along a straight road, is given by s  f(t) and s  t(t), respectively, where s is measured in feet and t is measured in seconds (see the accompanying figure).

30 25

10

20

y = f(t )

8

15 10 5

4

s

T1

s = g(t) s = f (t)

t 10 12 20

30 Years

40

50

3. TV-VIEWING PATTERNS The following graph shows the percent of U.S. households watching television during a 24-hr period on a weekday (t  0 corresponds to 6 a.m.). By computing the slopes of the respective tangent lines, estimate the rate of change of the percent of households watching television at 4 p.m. and 11 p.m. Source: A. C. Nielsen Company

t1

t2

t3

t

a. Which car is traveling faster at t1? b. What can you say about the speed of the cars at t2? Hint: Compare tangent lines.

c. Which car is traveling faster at t3? d. What can you say about the positions of the cars at t3?

9.3 THE DERIVATIVE

6. The velocity of car A and car B, starting out side by side and traveling along a straight road, is given by √  f(t) and √  t(t), respectively, where √ is measured in feet/second and t is measured in seconds (see the accompanying figure). √

√ = g (t) √ = f (t)

t1

t

t2

a. What can you say about the velocity and acceleration of the two cars at t1? (Acceleration is the rate of change of velocity.) b. What can you say about the velocity and acceleration of the two cars at t2? 7. EFFECT OF A BACTERICIDE ON BACTERIA In the following figure, f(t) gives the population P1 of a certain bacteria culture at time t after a portion of bactericide A was introduced into the population at t  0. The graph of t gives the population P2 of a similar bacteria culture at time t after a portion of bactericide B was introduced into the population at t  0. a. Which population is decreasing faster at t1? b. Which population is decreasing faster at t2?

583

a. The revenue of the established department store is decreasing at the slowest rate. b. The revenue of the established department store is decreasing at the fastest rate. c. The revenue of the discount store first overtakes that of the established store. d. The revenue of the discount store is increasing at the fastest rate. In Exercises 9–16, use the four-step process to find the slope of the tangent line to the graph of the given function at any point.

9. f(x)  13

10. f(x)  6

11. f(x)  2x  7

12. f(x)  8  4x

13. f(x)  3x 2

1 14. f 1x2   x2 2

15. f(x)  x 2  3x

16. f(x)  2x 2  5x

In Exercises 17–22, find the slope of the tangent line to the graph of each function at the given point and determine an equation of the tangent line.

17. f(x)  2x  7 at (2, 11) 18. f(x)  3x  4 at (1, 7) 19. f(x)  3x 2 at (1, 3) 20. f(x)  3x  x 2 at (2, 10)

y

1 1 21. f 1x2   at ¢3,  ≤ x 3 y = g (t)

22. f 1x2 

y = f (t) t1

t

t2

c. Which bactericide is more effective in reducing the population of bacteria in the short run? In the long run? 8. MARKET SHARE The following figure shows the devastating effect the opening of a new discount department store had on an established department store in a small town. The revenue of the discount store at time t (in months) is given by f(t) million dollars, whereas the revenue of the established department store at time t is given by t(t) million dollars. Answer the following questions by giving the value of t at which the specified event took place.

3 3 at ¢1, ≤ 2x 2

23. Let f(x)  2x 2  1. a. Find the derivative f  of f. b. Find an equation of the tangent line to the curve at the point (1, 3). c. Sketch the graph of f. 24. Let f(x)  x 2  6x. a. Find the derivative f  of f. b. Find the point on the graph of f where the tangent line to the curve is horizontal. Hint: Find the value of x for which f (x)  0.

c. Sketch the graph of f and the tangent line to the curve at the point found in part (b).

y y = g (t)

y = f (t)

t1 t2

t3

t

25. Let f(x)  x 2  2x  1. a. Find the derivative f  of f. b. Find the point on the graph of f where the tangent line to the curve is horizontal. c. Sketch the graph of f and the tangent line to the curve at the point found in part (b). d. What is the rate of change of f at this point?

584

9 THE DERIVATIVE

26. Let f 1x 2 

1 . x1 a. Find the derivative f  of f. b. Find an equation of the tangent line to the curve at the point 11, 12 2 . c. Sketch the graph of f and the tangent line to the curve at 11, 12 2 .

33. At a temperature of 20°C, the volume V (in liters) of 1.33 g of O2 is related to its pressure p (in atmospheres) by the formula V  1/p. a. What is the average rate of change of V with respect to p as p increases from p  2 to p  3? b. What is the rate of change of V with respect to p when p  2?

27. Let y  f(x)  x 2  x. a. Find the average rate of change of y with respect to x in the interval from x  2 to x  3, from x  2 to x  2.5, and from x  2 to x  2.1. b. Find the (instantaneous) rate of change of y at x  2. c. Compare the results obtained in part (a) with that of part (b).

34. COST OF PRODUCING SURFBOARDS The total cost C(x) (in dollars) incurred by Aloha Company in manufacturing x surfboards a day is given by

28. Let y  f (x)  x 2  4x. a. Find the average rate of change of y with respect to x in the interval from x  3 to x  4, from x  3 to x  3.5, and from x  3 to x  3.1. b. Find the (instantaneous) rate of change of y at x  3. c. Compare the results obtained in part (a) with that of part (b).

35. EFFECT OF ADVERTISING ON PROFIT The quarterly profit (in thousands of dollars) of Cunningham Realty is given by

29. VELOCITY OF A CAR Suppose the distance s (in feet) covered by a car moving along a straight road after t sec is given by the function s  f (t)  2t 2  48t. a. Calculate the average velocity of the car over the time intervals [20, 21], [20, 20.1], and [20, 20.01]. b. Calculate the (instantaneous) velocity of the car when t  20. c. Compare the results of part (a) with that of part (b). 30. VELOCITY OF A BALL THROWN INTO THE AIR A ball is thrown straight up with an initial velocity of 128 ft/sec, so that its height (in feet) after t sec is given by s(t)  128t  16t 2. a. What is the average velocity of the ball over the time intervals [2, 3], [2, 2.5], and [2, 2.1]? b. What is the instantaneous velocity at time t  2? c. What is the instantaneous velocity at time t  5? Is the ball rising or falling at this time? d. When will the ball hit the ground? 31. During the construction of a high-rise building, a worker accidentally dropped his portable electric screwdriver from a height of 400 ft. After t sec, the screwdriver had fallen a distance of s  16t 2 ft. a. How long did it take the screwdriver to reach the ground? b. What was the average velocity of the screwdriver between the time it was dropped and the time it hit the ground? c. What was the velocity of the screwdriver at the time it hit the ground? 32. A hot-air balloon rises vertically from the ground so that its height after t sec is h  12 t 2  12 t ft 10 t 602 . a. What is the height of the balloon at the end of 40 sec? b. What is the average velocity of the balloon between t  0 and t  40? c. What is the velocity of the balloon at the end of 40 sec?

C(x)  10x 2  300x  130

(0 x 15)

a. Find C(x). b. What is the rate of change of the total cost when the level of production is ten surfboards a day?

1 P1x 2   x 2  7x  30 3

10 x 502

where x (in thousands of dollars) is the amount of money Cunningham spends on advertising per quarter. a. Find P(x). b. What is the rate of change of Cunningham’s quarterly profit if the amount it spends on advertising is $10,000/quarter (x  10) and $30,000/quarter (x  30)? 36. DEMAND FOR TENTS The demand function for Sportsman 5  7 tents is given by p  f(x)  0.1x 2  x  40

where p is measured in dollars and x is measured in units of a thousand. a. Find the average rate of change in the unit price of a tent if the quantity demanded is between 5000 and 5050 tents; between 5000 and 5010 tents. b. What is the rate of change of the unit price if the quantity demanded is 5000? 37. A COUNTRY’S GDP The gross domestic product (GDP) of a certain country is projected to be N(t)  t 2  2t  50

(0 t 5)

billion dollars t yr from now. What will be the rate of change of the country’s GDP 2 yr and 4 yr from now? 38. GROWTH OF BACTERIA Under a set of controlled laboratory conditions, the size of the population of a certain bacteria culture at time t (in minutes) is described by the function P  f(t)  3t 2  2t  1

Find the rate of population growth at t  10 min. 39. AIR TEMPERATURE The air temperature at a height of h ft from the surface of the earth is T  f(h) degrees Fahrenheit. a. Give a physical interpretation of f (h). Give units. b. Generally speaking, what do you expect the sign of f (h) to be? c. If you know that f (1000)  0.05, estimate the change in the air temperature if the altitude changes from 1000 ft to 1001 ft.

9.3 THE DERIVATIVE

40. REVENUE OF A TRAVEL AGENCY Suppose that the total revenue realized by the Odyssey Travel Agency is R  f(x) thousand dollars if x thousand dollars are spent on advertising. a. What does f 1b2  f 1a2

In Exercises 41–46, let x and f(x) represent the given quantities. Fix x  a and let h be a small positive number. Give an interpretation of the quantities and

lim

f(a  h)  f(a) h

hS0

41. x denotes time and f(x) denotes the population of seals at time x. 42. x denotes time and f(x) denotes the prime interest rate at time x. 43. x denotes time and f(x) denotes a country’s industrial production. 44. x denotes the level of production of a certain commodity, and f(x) denotes the total cost incurred in producing x units of the commodity. 45. x denotes altitude and f(x) denotes atmospheric pressure. 46. x denotes the speed of a car (in mph), and f(x) denotes the fuel economy of the car measured in miles per gallon (mpg). In each of Exercises 47–52, the graph of a function is shown. For each function, state whether or not (a) f(x) has a limit at x  a, (b) f(x) is continuous at x  a, and (c) f(x) is differentiable at x  a. Justify your answers.

47.

48.

y

y

x

10 a b2

measure? What are the units? b. What does f (x) measure? Give units. c. Given that f (20)  3, what is the approximate change in the revenue if Odyssey increases its advertising budget from $20,000 to $21,000?

h

52.

a

ba

f(a  h)  f(a)

y

51.

585

y

x

a

53. The distance s (in feet) covered by a motorcycle traveling in a straight line and starting from rest in t sec is given by the function s(t)  0.1t 3  2t 2  24t

Calculate the motorcycle’s average velocity over the time interval [2, 2  h] for h  1, 0.1, 0.01, 0.001, 0.0001, and 0.00001 and use your results to guess at the motorcycle’s instantaneous velocity at t  2. 54. The daily total cost C(x) incurred by Trappee and Sons for producing x cases of TexaPep hot sauce is given by C(x)  0.000002x3  5x  400

Calculate

C1100  h2  C11002 h

for h  1, 0.1, 0.01, 0.001, and 0.0001 and use your results to estimate the rate of change of the total cost function when the level of production is 100 cases/day. In Exercises 55 and 56, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

55. If f is continuous at x  a, then f is differentiable at x  a. 56. If f is continuous at x  a and t is differentiable at x  a, then lim f 1x2t 1x2  f 1a2 t1a 2 . xSa

57. Sketch the graph of the function f(x)   x  1 and show that the function does not have a derivative at x  1. 58. Sketch the graph of the function f(x)  1/(x  1) and show that the function does not have a derivative at x  1.

a

59. Let

x

f 1x2  e x

a

49.

50.

y

x

if x 1 if x  1

Find the values of a and b so that f is continuous and has a derivative at x  1. Sketch the graph of f. y

60. Sketch the graph of the function f(x)  x 2/3. Is the function continuous at x  0? Does f (0) exist? Why or why not?

a a

x2 ax  b

x

61. Prove that the derivative of the function f(x)   x for x  0 is given by f ¿1x2  e

1 1

if x  0 if x 0

Hint: Recall the definition of the absolute value of a number.

586

9 THE DERIVATIVE

62. Show that if a function f is differentiable at x  a, then f must be continuous at that number. Hint: Write f 1x2  f 1a 2  c

f 1x2  f 1a2 xa

Use the product rule for limits and the definition of the derivative to show that lim 3 f 1x2  f 1a 2 4  0

xSa

d 1x  a2

9.3 Solutions to Self-Check Exercises 1. a. f (x)  lim

hS0

 lim

2. The rate of change of the losses at any time t is given by

f 1x  h 2  f 1x2

f (t)

h 31x  h 2 2  21x  h 2  34  1x 2  2x  3 2

h x 2  2xh  h2  2x  2h  3  x 2  2x  3  lim hS0 h h12x  h  2 2  lim hS0 h  lim 12x  h  2 2  2x  2 hS0

hS0

b. From the result of part (a), we see that the slope of the tangent line to the graph of f at any point (x, f(x)) is given by f (x)  2x  2

In particular, the slope of the tangent line to the graph of f at (0, 3) is f (0)  2

c. The rate of change of f when x  0 is given by f (0)  2, or 2 units/unit change in x. d. Using the result from part (b), we see that an equation of the required tangent line is y  3  21x  0 2 y  2x  3

e.

 lim

hS0

 lim

f 1t  h2  f 1t2 h 31t  h2 2  101t  h 2  304  1 t 2  10t  302 h

hS0

t 2  2th  h2  10t  10h  30  t 2  10t  30  lim hS0 h h12t  h  102  lim hS0 h  lim 12t  h  10 2 hS0

 2t  10

Therefore, the rate of change of the losses suffered by the bank at the beginning of 2005 (t  3) was f (3)  2(3)  10  4

In other words, the losses were increasing at the rate of $4 million/year. At the beginning of 2007 (t  5), f (5)  2(5)  10  0

and we see that the growth in losses due to bad loans was zero at this point. At the beginning of 2009 (t  7), f (7)  2(7)  10  4

and we conclude that the losses were decreasing at the rate of $4 million/year.

y

y = – x2 – 2x + 3

x y = –2x + 3

USING

TECHNOLOGY

Graphing a Function and Its Tangent Line We can use a graphing utility to plot the graph of a function f and the tangent line at any point on the graph. EXAMPLE 1 Let f(x)  x 2  4x. a. Find an equation of the tangent line to the graph of f at the point (3, 3). b. Plot both the graph of f and the tangent line found in part (a) on the same set of axes.

9.3 THE DERIVATIVE

587

Solution

a. The slope of the tangent line at any point on the graph of f is given by f (x). But from Example 4 (page 576) we find f (x)  2x  4. Using this result, we see that the slope of the required tangent line is f (3)  2(3)  4  2

Finally, using the point-slope form of the equation of a line, we find that an equation of the tangent line is y  132  21x  32 y  3  2x  6 y  2x  9

b. Figure T1a shows the graph of f in the standard viewing window and the tangent line of interest. Plot1 Plot2 \Y1 = X^2 − 4X \Y2 = 2X − 9 \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

FIGURE T1

(a) The graph of f(x)  x 2  4x and the tangent line y  2x  9 in the standard viewing window; (b) the TI-83/84 equation screen.

(a)

Plot3

(b)

Note

Some graphing utilities will draw both the graph of a function f and the tangent line to the graph of f at a specified point when the function and the specified value of x are entered.

Finding the Derivative of a Function at a Given Point The numerical derivative operation of a graphing utility can be used to give an approximate value of the derivative of a function for a given value of x. EXAMPLE 2 Let f 1x2  1x.

nDeriv(X^.5, X, 4) .250000002

a. Use the numerical derivative operation of a graphing utility to find the derivative of f at (4, 2). b. Find an equation of the tangent line to the graph of f at (4, 2). c. Plot the graph of f and the tangent line on the same set of axes. Solution

a. Using the numerical derivative operation of a graphing utility, we find that f ¿142  FIGURE T2 The TI-83/84 numerical derivative screen.

1 4

(Figure T2). b. An equation of the required tangent line is 1 1x  4 2 4 1 y x1 4

y2

(continued)

588

9 THE DERIVATIVE

c. Figure T3a shows the graph of f and the tangent line in the viewing window [0, 15]  [0, 4]. Plot1 Plot2 \Y1 = X^.5 \Y2 = .25X + 1 \Y3 = \Y4 = \Y5 = \Y6 = \Y7 =

FIGURE T3

(a) The graph of f 1x2  1x and the tangent line y  14 x  1 in the viewing window [0, 15]  [0, 4]; (b) the TI-83/84 equation screen

(a)

Plot3

(b)

TECHNOLOGY EXERCISES In Exercises 1–4, (a) find an equation of the tangent line to the graph of f at the indicated point and (b) plot the graph of f and the tangent line on the same set of axes. Use a suitable viewing window.

1. f(x)  2x 2  x  3; (2, 7) 2. f 1x2  x  ; 11, 2 2 1 x 3. f 1x2  1x; 14, 2 2

Source: Automobile Association of America

1 1 4. f 1x2  ; ¢4, ≤ 2 1x In Exercises 5–8, (a) use the numerical derivative operation to find the derivative of f for the given value of x (to two desired places of accuracy), (b) find an equation of the tangent line to the graph of f at the indicated point, and (c) plot the graph of f and the tangent line on the same set of axes. Use a suitable viewing window.

5. f(x)  x 3  x  1; x  1; (1, 3) 6. f 1x2 

x 2x  1 2

; x  1; ¢1,

12 ≤ 2

9. DRIVING COSTS The average cost of owning and operating a car in the United States from 1991 through 2001 is approximated by the function C(t)  0.06t 2  0.74t  37.3

10. MODELING WITH DATA Annual retail sales in the United States from 1990 through the year 2000 (in billions of dollars) are given in the following table: Year Sales

1990 471.6

1991 485.4

1992 519.2

1993 553.4

1994 595

Year Sales

1996 656.6

1997 685.6

1998 727.2

1999 781.7

2000 877.7

1995 625.5

a. Let t  0 correspond to 1990 and use QuadReg to find a second-degree polynomial regression model based on the given data.

1 1 ; x  1; ¢1, ≤ x1 2

7. f 1x2  x 2x 2  1; x  2; 12, 2152 8. f 1x2 

where C(t) is measured in cents/mile and t is measured in years, with t  0 corresponding to the beginning of 1991. a. Plot the graph of C in the viewing window [0, 10]  [35, 52]. b. What was the average cost of driving a car at the beginning of 1995? c. How fast was the average cost of driving a car changing at the beginning of 1995?

(0 t 11)

b. Plot the graph of the function found in part (a) in the viewing window [0, 10]  [0, 1000]. c. What were the annual retail sales in the United States in 1999 (t  9)? d. Approximately how fast were the retail sales changing in 1999 (t  9)? Source: National Retail Federation

9.4 BASIC RULES OF DIFFERENTIATION

589

9.4 Basic Rules of Differentiation Four Basic Rules The method used in Section 9.3 for computing the derivative of a function is based on a faithful interpretation of the definition of the derivative as the limit of a quotient. To find the rule for the derivative f  of a function f, we first computed the difference quotient f 1x  h2  f 1x2 h

and then evaluated its limit as h approached zero. As you have probably observed, this method is tedious even for relatively simple functions. The main purpose of this chapter is to derive certain rules that will simplify the process of finding the derivative of a function. We will use the notation d 3 f 1x2 4 dx

Read “d, d x of f of x ”

to mean “the derivative of f with respect to x at x.” In stating the rules of differentiation, we assume that the functions f and t are differentiable.

Rule 1: Derivative of a Constant d 1c2  0 dx

(c, a constant)

The derivative of a constant function is equal to zero. y

We can see this from a geometric viewpoint by recalling that the graph of a constant function is a straight line parallel to the x-axis (Figure 37). Since the tangent line to a straight line at any point on the line coincides with the straight line itself, its slope [as given by the derivative of f(x)  c] must be zero. We can also use the definition of the derivative to prove this result by computing

f (x) = c

x

f ¿1x2  lim

f 1x  h 2  f 1x2 h

hS0

FIGURE 37

cc h  lim 0  0

The slope of the tangent line to the graph of f(x)  c, where c is a constant, is zero.

 lim

hS0 hS0

EXAMPLE 1 a. If f(x)  28, then f ¿1x2 

d 128 2  0 dx

f ¿1x2 

d 122  0 dx

b. If f(x)  2, then

590

9 THE DERIVATIVE

Rule 2: The Power Rule

If n is any real number, then

d n 1x 2  nxn1. dx

Let’s verify the power rule for the special case n  2. If f(x)  x 2, then f 1x  h2  f 1x2 d 2 1x 2  lim dx hS0 h 2 2 1x  h2  x  lim hS0 h

f ¿1x2 

x2  2xh  h2  x2 hS0 h 2 h12x  h2 2xh  h  lim  lim hS0 h hS0 h  lim 12x  h2  2x  lim

hS0

as we set out to show. The proof of the power rule for the general case is not easy to prove and will be omitted. However, you will be asked to prove the rule for the special case n  3 in Exercise 79, page 599. EXAMPLE 2 a. If f(x)  x, then f ¿1x2 

d 1x2  1 # x11  x0  1 dx

b. If f(x)  x 8, then f ¿1x2 

d 8 1x 2  8x7 dx

c. If f(x)  x 5/2, then f ¿1x2 

d 5/2 5 1x 2  x3/2 dx 2

To differentiate a function whose rule involves a radical, we first rewrite the rule using fractional powers. The resulting expression can then be differentiated using the power rule. EXAMPLE 3 Find the derivative of the following functions: a. f 1x2  1x

b. t 1x2 

1 3

2x

Solution

a. Rewriting 1x in the form x1/2, we obtain d 1/2 1x 2 dx 1 1 1  x1/2  1/2  2 21x 2x

f ¿1x2 

(x2)

See page 37.

9.4 BASIC RULES OF DIFFERENTIATION

b. Rewriting

1 3

2x

591

in the form x1/3, we obtain t¿1x2 

d 1/3 1x 2 dx

1 1   x4/3   4/3 3 3x

Rule 3: Derivative of a Constant Multiple of a Function d d 3cf 1x2 4  c 3 f 1x 2 4 dx dx

(c, a constant)

The derivative of a constant times a differentiable function is equal to the constant times the derivative of the function. This result follows from the following computations. If t(x)  cf (x), then t ¿1x 2  lim

t 1x  h2  t 1x2

hS0

 c lim

 lim

h f 1x  h2  f 1x2

cf 1x  h2  cf 1x2

hS0

h

h

hS0

 cf ¿1x2

EXAMPLE 4 a. If f (x)  5x 3, then f ¿1x2 

d d 3 15x3 2  5 1x 2 dx dx

 513x2 2  15x2

b. If f 1x 2 

3 , then 1x f ¿1x2 

d 13x 1/2 2 dx

1 3  3¢ x 3/2≤   3/2 2 2x

Rule 4: The Sum Rule d d d 3 f 1x 2 t 1x2 4  3 f 1x 2 4 3t 1x2 4 dx dx dx

The derivative of the sum (difference) of two differentiable functions is equal to the sum (difference) of their derivatives. This result may be extended to the sum and difference of any finite number of differentiable functions. Let’s verify the rule for a sum of two functions.

592

9 THE DERIVATIVE

If s(x)  f(x)  t(x), then s¿1x 2  lim

hS0

 lim

hS0

 lim

hS0

 lim

s1x  h2  s1x 2 h 3 f 1x  h2  t 1x  h2 4  3 f 1x2  t 1x2 4 h 3 f 1x  h2  f 1x2 4  3t 1x  h2  t 1x2 4 f 1x  h2  f 1x 2

h  f ¿1x2  t¿1x2 hS0

h

t 1x  h2  t 1x2

 lim

h

hS0

EXAMPLE 5 Find the derivatives of the following functions: b. t 1t 2 

a. f(x)  4x 5  3x 4  8x 2  x  3

t2 5  3 5 t

Solution

a. f ¿1x 2 

d 14x5  3x4  8x2  x  32 dx d d d d d  14x5 2  13x4 2  18x2 2  1x2  132 dx dx dx dx dx

 20x4  12x3  16x  1

b. Here, the independent variable is t instead of x, so we differentiate with respect to t. Thus, t¿1t 2 

d 1 2 ¢ t  5t3≤ dt 5 2 2 15  t  15t 4  t  4 5 5 t 2t 5  75  5t 4

Rewrite

1 t3

as t3.

Rewrite t4 as

1 . t4

Simplify.

EXAMPLE 6 Find the slope and an equation of the tangent line to the graph of f 1x 2  2x  1/ 1x at the point (1, 3). Solution

The slope of the tangent line at any point on the graph of f is given by f ¿1x 2 

d 1 ¢2x  ≤ dx 1x d  12x  x 1/2 2 dx 1  2  x 3/2 2 1  2  3/2 2x

Rewrite

1 1 as 1/2  x1/2. 1x x

Use the sum rule.

Rewrite

1 3/2 1 x as 3/2 . 2 2x

In particular, the slope of the tangent line to the graph of f at (1, 3) (where x  1) is f ¿112  2 

1 1 3 2  3/2 2 2 211 2

9.4 BASIC RULES OF DIFFERENTIATION

593

Using the point-slope form of the equation of a line with slope 32 and the point (1, 3), we see that an equation of the tangent line is y3

3 1x  1 2 2

y  y 1  m(x  x 1)

(x2)

See page 75.

or, upon simplification, 3 3 y x 2 2

(see Figure 38). y 12 10 8

y  2x 

6

3 3 y x 2 2

4 FIGURE 38 The tangent line to the graph of f 1x2  2x  1/ 1x at (1, 3).

1 x

2 x 1

2

3

4

APPLIED EXAMPLE 7 Conservation of a Species A group of marine biologists at the Neptune Institute of Oceanography recommended that a series of conservation measures be carried out over the next decade to save a certain species of whale from extinction. After implementing the conservation measures, the population of this species is expected to be N(t)  3t 3  2t 2  10t  600

(0 t 10)

where N(t) denotes the population at the end of year t. Find the rate of growth of the whale population when t  2 and t  6. How large will the whale population be 8 years after implementing the conservation measures? Solution

The rate of growth of the whale population at any time t is given by N(t)  9t 2  4t  10

In particular, when t  2 and t  6, we have N¿122  9122 2  4122  10  34 N¿162  9162 2  4162  10  338

Thus, the whale population’s rate of growth will be 34 whales per year after 2 years and 338 per year after 6 years. The whale population at the end of the eighth year will be N182  3182 3  218 2 2  10182  600  2184

The graph of the function N appears in Figure 39. Note the rapid growth of the population in the later years, as the conservation measures begin to pay off, compared with the growth in the early years.

594

9 THE DERIVATIVE y 4000 3000 2000

y = N(t)

1000 FIGURE 39 The whale population after year t is given by N(t).

t (year) 2

4

6

8

10

APPLIED EXAMPLE 8 Altitude of a Rocket The altitude of a rocket (in feet) t seconds into flight is given by s  f(t)  t 3  96t 2  195t  5

(t  0)

a. Find an expression √ for the rocket’s velocity at any time t. b. Compute the rocket’s velocity when t  0, 30, 50, 65, and 70. Interpret your results. c. Using the results from the solution to part (b) and the observation that at the highest point in its trajectory the rocket’s velocity is zero, find the maximum altitude attained by the rocket. Solution

a. The rocket’s velocity at any time t is given by √  f (t)  3t 2  192t  195

b. The rocket’s velocity when t  0, 30, 50, 65, and 70 is given by f ¿102 f ¿1302 f ¿1502 f ¿1652 f ¿1702

s

Feet

150,000 s = f (t) 100,000

50,000 t 20 40 60 80 100 Seconds FIGURE 40 The rocket’s altitude t seconds into flight is given by f(t).

 3102 2  19210 2  195  195  31302 2  192130 2  195  3255  31502 2  192150 2  195  2295  31652 2  192165 2  195  0  31702 2  192170 2  195  1065

or 195, 3255, 2295, 0, and 1065 feet per second (ft/sec). Thus, the rocket has an initial velocity of 195 ft/sec at t  0 and accelerates to a velocity of 3255 ft/sec at t  30. Fifty seconds into the flight, the rocket’s velocity is 2295 ft/sec, which is less than the velocity at t  30. This means that the rocket begins to decelerate after an initial period of acceleration. (Later on we will learn how to determine the rocket’s maximum velocity.) The deceleration continues: The velocity is 0 ft /sec at t  65 and 1065 ft /sec when t  70. This result tells us that 70 seconds into flight the rocket is heading back to Earth with a speed of 1065 ft /sec. c. The results of part (b) show that the rocket’s velocity is zero when t  65. At this instant, the rocket’s maximum altitude is s  f 1652  1652 3  961652 2  1951652  5  143,655

or 143,655 feet. A sketch of the graph of f appears in Figure 40.

595

9.4 BASIC RULES OF DIFFERENTIATION

Exploring with

TECHNOLOGY Refer to Example 8. 1. Use a graphing utility to plot the graph of the velocity function √  f (t)  3t 2  192t  195 using the viewing window [0, 120]  [5000, 5000]. Then, using ZOOM and or the root-finding capability of your graphing utility, verify that f (65)  0. 2. Plot the graph of the position function of the rocket TRACE

s  f (t)  t 3  96t 2  195t  5 using the viewing window [0, 120]  [0, 150,000]. Then, using

ZOOM

and

TRACE repeatedly, verify that the maximum altitude of the rocket is 143,655 feet.

3. Use ZOOM and TRACE or the root-finding capability of your graphing utility to find when the rocket returns to Earth.

9.4 Self-Check Exercises 1. Find the derivative of each function using the rules of differentiation. a. f (x)  1.5x 2  2x 1.5 3 b. t 1x2  21x  1x 2. Let f(x)  2x 3  3x 2  2x  1. a. Compute f (x). b. What is the slope of the tangent line to the graph of f when x  2? c. What is the rate of change of the function f at x  2?

3. A certain country’s gross domestic product (GDP) (in millions of dollars) is described by the function G(t)  2t 3  45t 2  20t  6000

(0 t 11)

where t  0 corresponds to the beginning of 2000. a. At what rate was the GDP changing at the beginning of 2005? At the beginning of 2007? At the beginning of 2010? b. What was the average rate of growth of the GDP over the period 2005–2010? Solutions to Self-Check Exercises 9.4 can be found on page 599.

9.4 Concept Questions 1. State the following rules of differentiation in your own words. a. The rule for differentiating a constant function b. The power rule c. The constant multiple rule d. The sum rule

2. If f (2)  3 and t(2)  2, find a. h(2) if h(x)  2f(x) b. F(2) if F(x)  3f(x)  4t(x) 3. Suppose f and t are differentiable functions and a and b are nonzero numbers. Find F(x) if a. F(x)  af(x)  bt(x) b. F1x2 

f 1x2 a

9.4 Exercises In Exercises 1–34, find the derivative of the function f by using the rules of differentiation.

1. f (x)  3

2. f(x)  365

3. f (x)  x 5

4. f (x)  x 7

5. f (x)  x 2.1

6. f (x)  x 0.8

7. f(x)  3x 2

8. f(x)  2x 3

9. f(r)  pr 2

4 10. f 1r 2  pr 3 3

11. f(x)  9x 1/3

12. f 1x2 

5 4/5 x 4

596

9 THE DERIVATIVE

13. f 1x2  3 1x

14. f 1u 2 

15. f(x)  7x12

16. f(x)  0.3x1.2

17. f(x)  5x 2  3x  7

18. f(x)  x 3  3x 2  1

19. f(x)  x 3  2x 2  6

20. f(x)  x 4  2x 2  5

2 1u

21. f(x)  0.03x 2  0.4x  10 22. f(x)  0.002x 3  0.05x 2  0.1x  20 23. f 1x2 

x3  4x2  3 x

24. f 1x2 

x3  2x2  x  1 x

29. f 1t2 

4 t

4



3 t

3



1 28. f 1x2   1x3  x6 2 3

2 t

1 30. f 1x2  3  2   200 x x x 5

2

31. f 1x2  2x  5 1x

32. f 1t2  2t 2  2t 3

33. f 1x2 

4 1 34. f 1x2  3  1x x

2 x2



3

3

x1/3

35. Let f(x)  2x 3  4x. Find: a. f (2) b. f (0)

c. f (2)

36. Let f(x)  4x 5/4  2x 3/2  x. Find: a. f (0) b. f (16) In Exercises 37–40, find each limit by evaluating the derivative of a suitable function at an appropriate point. Hint: Look at the definition of the derivative.

37. lim hS0

11  h2 3  1 h

x5  1 xS1 x  1

38. lim

Hint: Let h  x  1.

39. lim

312  h 2 2  12  h2  10

40. lim tS0

45. Let f(x)  x 3. a. Find the point on the graph of f where the tangent line is horizontal. b. Sketch the graph of f and draw the horizontal tangent line.

48. Let f 1x2  23 x3  x2  12x  6. Find the values of x for which: a. f (x)  12 b. f (x)  0 c. f (x)  12 49. Let f 1x2  14 x4  13 x3  x2. Find the point(s) on the graph of f where the slope of the tangent line is equal to: a. 2x b. 0 c. 10x 50. A straight line perpendicular to and passing through the point of tangency of the tangent line is called the normal to the curve. Find an equation of the tangent line and the normal to the curve y  x 3  3x  1 at the point (2, 3). 51. GROWTH OF A CANCEROUS TUMOR The volume of a spherical cancerous tumor is given by the function 4 V1r2  pr 3 3

where r is the radius of the tumor in centimeters. Find the rate of change in the volume of the tumor when a. r 

2 cm 3

1  11  t2 2 t 11  t2 2

In Exercises 41–44, find the slope and an equation of the tangent line to the graph of the function f at the specified point.

41. f(x)  2x 2  3x  4; (2, 6) 5 5 42. f 1x2   x2  2x  2; ¢1,  ≤ 3 3

b. r 

5 cm 4

52. VELOCITY OF BLOOD IN AN ARTERY The velocity (in centimeters/second) of blood r cm from the central axis of an artery is given by

h

hS0

1 5 ; ¢4, ≤ 2 1x

47. Let f(x)  x 3  1. a. Find the point(s) on the graph of f where the slope of the tangent line is equal to 12. b. Find the equation(s) of the tangent line(s) of part (a). c. Sketch the graph of f showing the tangent line(s).

2 3/2 x  x2  3x  1 3

27. f(x)  3x1  4x2

44. f 1x2  1x 

46. Let f(x)  x 3  4x 2. Find the point(s) on the graph of f where the tangent line is horizontal.

25. f(x)  4x 4  3x 5/2  2 26. f 1x2  5x4/3 

43. f(x)  x 4  3x 3  2x 2  x  1; (1, 0)

√(r)  k(R 2  r 2)

where k is a constant and R is the radius of the artery (see the accompanying figure). Suppose k  1000 and R  0.2 cm. Find √(0.1) and √(0.1) and interpret your results. R r

Blood vessel

9.4 BASIC RULES OF DIFFERENTIATION

53. SALES OF DIGITAL CAMERAS According to projections made in 2004, the worldwide shipments of digital point-and-shoot cameras are expected to grow in accordance with the rule N(t)  16.3t 0.8766

(1 t 6)

where N(t) is measured in millions and t is measured in years, with t  1 corresponding to 2001. a. How many digital cameras were sold in 2001 (t  1)? b. How fast were sales increasing in 2001? c. What were the projected sales in 2005? d. How fast were the sales projected to grow in 2005? Source: International Data Corp.

54. ONLINE BUYERS As use of the Internet grows, so does the number of consumers who shop online. The number of online buyers, as a percent of net users, is expected to be P(t)  53t 0.12

(1 t 7)

where t is measured in years, with t  1 corresponding to the beginning of 2002. a. How many online buyers, as a percentage of net users, were there at the beginning of 2007? b. How fast was the number of online buyers, as a percentage of net users, changing at the beginning of 2007? Source: Strategy Analytics

55. MARRIED HOUSEHOLDS WITH CHILDREN The percentage of families that were married households with children between 1970 and 2000 is approximately P1t 2 

49.6 t 0.27

11 t 42

where t is measured in decades, with t  1 corresponding to 1970. a. What percentage of families were married households with children in 1970? In 1980? In 1990? In 2000? b. How fast was the percentage of families that were married households with children changing in 1980? In 1990? Source: U.S. Census Bureau

56. EFFECT OF STOPPING ON AVERAGE SPEED According to data from a study, the average speed of your trip A (in mph) is related to the number of stops/mile you make on the trip x by the equation A

26.5 x0.45

Compute dA/dx for x  0.25 and x  2. How is the rate of change of the average speed of your trip affected by the number of stops/mile? Source: General Motors

57. ONLINE VIDEO VIEWERS As broadband Internet grows more popular, video services such as YouTube will continue to expand. The number of online video viewers (in millions) is projected to grow according to the rule N(t)  52t 0.531

(1 t 10)

where t  1 corresponds to 2003.

597

a. What will be the projected number of online video viewers in 2010? b. How fast will the projected number of online video viewers be changing in 2010? Source: eMarketer.com

58. DEMAND FUNCTIONS The demand function for the Luminar desk lamp is given by p  f(x)  0.1x 2  0.4x  35

where x is the quantity demanded in thousands and p is the unit price in dollars. a. Find f (x). b. What is the rate of change of the unit price when the quantity demanded is 10,000 units (x  10)? What is the unit price at that level of demand? 59. STOPPING DISTANCE OF A RACING CAR During a test by the editors of an auto magazine, the stopping distance s (in feet) of the MacPherson X-2 racing car conformed to the rule s  f (t)  120t  15t 2

(t  0)

where t was the time (in seconds) after the brakes were applied. a. Find an expression for the car’s velocity √ at any time t. b. What was the car’s velocity when the brakes were first applied? c. What was the car’s stopping distance for that particular test? Hint: The stopping time is found by setting √  0.

60. INSTANT MESSAGING ACCOUNTS Mobile instant messaging (IM) is a small portion of total IM usage, but it is expected to grow sharply. The function P(t)  0.257t 2  0.57t  3.9

(0 t 4)

gives the projected mobile IM accounts as a percentage of total enterprise IM accounts from 2006 (t  0) through 2010 (t  4). a. What percentage of total enterprise IM accounts are the mobile accounts expected to be in 2008? b. How fast is this percentage expected to change in 2008? Source: The Radical Group

61. CHILD OBESITY The percentage of obese children, ages 12–19, in the United States has grown dramatically in recent years. The percentage of obese children from 1980 through the year 2000 is approximated by the function P(t)  0.0105t 2  0.735t  5

(0 t 20)

where t is measured in years, with t  0 corresponding to the beginning of 1980. a. What percentage of children were obese at the beginning of 1980? At the beginning of 1990? At the beginning of the year 2000? b. How fast was the percentage of obese children changing at the beginning of 1985? At the beginning of 1990? Source: Centers for Disease Control and Prevention

598

9 THE DERIVATIVE

62. SPENDING ON MEDICARE Based on the current eligibility requirement, a study conducted in 2004 showed that federal spending on entitlement programs, particularly Medicare, would grow enormously in the future. The study predicted that spending on Medicare, as a percentage of the gross domestic product (GDP), will be P(t)  0.27t 2  1.4t  2.2

(0 t 5)

percent in year t, where t is measured in decades, with t  0 corresponding to 2000. a. How fast will the spending on Medicare, as a percentage of the GDP, be growing in 2010? In 2020? b. What will the predicted spending on Medicare be in 2010? In 2020? Source: Congressional Budget Office

63. FISHERIES The total groundfish population on Georges Bank in New England between 1989 and 1999 is approximated by the function f(t)  5.303t 2  53.977t  253.8

(0 t 10)

where f(t) is measured in thousands of metric tons and t in years, with t  0 corresponding to the beginning of 1989. a. What was the rate of change of the groundfish population at the beginning of 1994? At the beginning of 1996? b. Fishing restrictions were imposed on Dec. 7, 1994. Were the conservation measures effective? Source: New England Fishery Management Council

64. WORKER EFFICIENCY An efficiency study conducted for Elektra Electronics showed that the number of Space Commander walkie-talkies assembled by the average worker t hr after starting work at 8 a.m. is given by N(t)  t 3  6t 2  15t

a. Find the rate at which the average worker will be assembling walkie-talkies t hr after starting work. b. At what rate will the average worker be assembling walkie-talkies at 10 a.m.? At 11 a.m.? c. How many walkie-talkies will the average worker assemble between 10 a.m. and 11 a.m.? 65. CONSUMER PRICE INDEX An economy’s consumer price index (CPI) is described by the function I(t)  0.2t 3  3t 2  100

(0 t 10)

where t  0 corresponds to 1998. a. At what rate was the CPI changing in 2003? In 2005? In 2008? b. What was the average rate of increase in the CPI over the period from 2003 to 2008? 66. EFFECT OF ADVERTISING ON SALES The relationship between the amount of money x that Cannon Precision Instruments spends on advertising and the company’s total sales S(x) is given by the function S(x)  0.002x 3  0.6x 2  x  500

(0 x 200)

where x is measured in thousands of dollars. Find the rate of change of the sales with respect to the amount of money

spent on advertising. Are Cannon’s total sales increasing at a faster rate when the amount of money spent on advertising is (a) $100,000 or (b) $150,000? 67. SUPPLY FUNCTIONS The supply function for a certain make of satellite radio is given by p  f(x)  0.0001x 5/4  10

where x is the quantity supplied and p is the unit price in dollars. a. Find f (x). b. What is the rate of change of the unit price if the quantity supplied is 10,000 satellite radios? 68. POPULATION GROWTH A study prepared for a Sunbelt town’s chamber of commerce projected that the town’s population in the next 3 yr will grow according to the rule P(t)  50,000  30t 3/2  20t

where P(t) denotes the population t mo from now. How fast will the population be increasing 9 mo and 16 mo from now? 69. AVERAGE SPEED OF A VEHICLE ON A HIGHWAY The average speed of a vehicle on a stretch of Route 134 between 6 a.m. and 10 a.m. on a typical weekday is approximated by the function f 1t2  20t  401t  50

10 t 4 2

where f(t) is measured in mph and t is measured in hours, with t  0 corresponding to 6 a.m. a. Compute f (t). b. What is the average speed of a vehicle on that stretch of Route 134 at 6 a.m.? At 7 a.m.? At 8 a.m.? c. How fast is the average speed of a vehicle on that stretch of Route 134 changing at 6:30 a.m.? At 7 a.m.? At 8 a.m.? 70. CURBING POPULATION GROWTH Five years ago, the government of a Pacific Island state launched an extensive propaganda campaign toward curbing the country’s population growth. According to the Census Department, the population (measured in thousands of people) for the following 4 yr was 1 P1t2   t 3  64t  3000 3

where t is measured in years and t  0 corresponds to the start of the campaign. Find the rate of change of the population at the end of years 1, 2, 3, and 4. Was the plan working? 71. CONSERVATION OF SPECIES A certain species of turtle faces extinction because dealers collect truckloads of turtle eggs to be sold as aphrodisiacs. After severe conservation measures are implemented, it is hoped that the turtle population will grow according to the rule N(t)  2t 3  3t 2  4t  1000

(0 t 10)

where N(t) denotes the population at the end of year t. Find the rate of growth of the turtle population when t  2 and t  8. What will be the population 10 yr after the conservation measures are implemented?

9.4 BASIC RULES OF DIFFERENTIATION

72. FLIGHT OF A ROCKET The altitude (in feet) of a rocket t sec into flight is given by s  f(t)  2t 3  114t 2  480t  1

(t  0)

a. Find an expression √ for the rocket’s velocity at any time t. b. Compute the rocket’s velocity when t  0, 20, 40, and 60. Interpret your results. c. Using the results from the solution to part (b), find the maximum altitude attained by the rocket. Hint: At its highest point, the velocity of the rocket is zero.

73. OBESITY IN AMERICA The body mass index (BMI) measures body weight in relation to height. A BMI of 25 to 29.9 is considered overweight, a BMI of 30 or more is considered obese, and a BMI of 40 or more is morbidly obese. The percentage of the U.S. population that is obese is approximated by the function P(t)  0.0004t 3  0.0036t 2  0.8t  12

(0 t 13)

where t is measured in years, with t  0 corresponding to the beginning of 1991. a. What percentage of the U.S. population was deemed obese at the beginning of 1991? At the beginning of 2004? b. How fast was the percentage of the U.S. population that is deemed obese changing at the beginning of 1991? At the beginning of 2004? (Note: A formula for calculating the BMI of a person is given in Exercise 29, page 834.) Source: Centers for Disease Control and Prevention

74. HEALTH-CARE SPENDING Despite efforts at cost containment, the cost of the Medicare program is increasing. Two major reasons for this increase are an aging population and extensive use by physicians of new technologies. Based on data from the Health Care Financing Administration and the U.S. Census Bureau, health-care spending through the year 2000 may be approximated by the function S(t)  0.02836t 3  0.05167t 2  9.60881t  41.9 (0 t 35)

where S(t) is the spending in billions of dollars and t is measured in years, with t  0 corresponding to the beginning of 1965. a. Find an expression for the rate of change of health-care spending at any time t.

b. How fast was health-care spending changing at the beginning of 1980? At the beginning of 2000? c. What was the amount of health-care spending at the beginning of 1980? At the beginning of 2000? Source: Health Care Financing Administration and U.S. Census Bureau

75. AGING POPULATION The population (in millions) of developed countries from 2005 through 2034 is projected to be f(t)  3.567t  175.2

(5 t 35)

where t is measured in years. On the other hand, the population of underdeveloped/emerging countries over the same period is projected to be t(t)  0.46t 2  0.16t  287.8

(5 t 35)

a. What does the function D  t  f represent? b. Find D and D(10) and interpret your results. Source: U.S. Census Bureau, United Nations

76. SHORTAGE OF NURSES The projected number of nurses (in millions) from the year 2000 through 2015 is given by N1t 2  e

1.9 0.0004t 2  0.038t  1.72

if 0 t 5 if 5 t 15

where t  0 corresponds to 2000. The projected number of nursing jobs (in millions) over the same period is J1t2  e

0.0002t 2  0.032t  2 0.0016t 2  0.12t  1.26

if 0 t 10 if 10 t 15

a. Find the rule for the function G  J  N giving the gap between the supply and the demand of nurses from 2000 through 2015. b. How fast was the gap between the supply and the demand of nurses changing in 2008? In 2012? Source: Department of Health and Human Services

In Exercises 77 and 78, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

77. If f and t are differentiable, then d 3 2f 1x2  5t 1x 2 4  2f ¿1x 2  5t ¿1x 2 dx

78. If f(x)  p x, then f (x)  xp x1. 79. Prove the power rule (Rule 2) for the special case n  3. Hint: Compute lim c hS0

1x  h 2 3  x3 h

d.

9.4 Solutions to Self-Check Exercises 1. a. f ¿ 1x 2 

d d 11.5x2 2  12x1.5 2 dx dx

 11.5 2 12x2  12 2 11.5x0.5 2  3x  31x  31x  1x2

599

b. t ¿1x 2 

d d 12x1/2 2  13x1/2 2 dx dx

1 1  12 2 a x1/2 b  13 2 a x3/2 b 2 2 3 1 2x  3  x1/2  x3/2  x3/2 12x  32  2 2 2x3/2

600

9 THE DERIVATIVE

2. a. f ¿1x2 

d d d d 12x3 2  13x2 2  12x2  11 2 dx dx dx dx

 12 2 13x2 2  132 12x2  2  6x2  6x  2

b. The slope of the tangent line to the graph of f when x  2 is given by f (2)  6(2)2  6(2)  2  14

c. The rate of change of f at x  2 is given by f (2). Using the results of part (b), we see that the required rate of change is 14 units/unit change in x.

(t  10) are given by G(5)  320

G1102  G15 2 10  5

TECHNOLOGY



321102 3  45110 2 2  20110 2  60004 5

32152  4515 2 2  2015 2  60004 3

 

G(t)  6t 2  90t  20

USING

G(10)  320

respectively—that is, by $320 million/year, $356 million/year, and $320 million/year, respectively. b. The average rate of growth of the GDP over the period from the beginning of 2005 (t  5) to the beginning of 2010 (t  10) is given by

3. a. The rate at which the GDP was changing at any time t (0 t 11) is given by

In particular, the rates of change of the GDP at the beginning of the years 2005 (t  5), 2007 (t  7), and 2010

G(7)  356

5

8700  6975 5

or $345 million/year.

Finding the Rate of Change of a Function We can use the numerical derivative operation of a graphing utility to obtain the value of the derivative at a given value of x. Since the derivative of a function f(x) measures the rate of change of the function with respect to x, the numerical derivative operation can be used to answer questions pertaining to the rate of change of one quantity y with respect to another quantity x, where y  f(x), for a specific value of x. EXAMPLE 1 Let y  3t 3  2 1t. a. Use the numerical derivative operation of a graphing utility to find how fast y is changing with respect to t when t  1. b. Verify the result of part (a), using the rules of differentiation of this section.

nDeriv((3X^3+2X^ .5), X, 1) 10.00000313

FIGURE T1 The TI-83/84 numerical derivative screen for computing f ( 1 )

Solution

a. Write f 1t2  3t 3  21t. Using the numerical derivative operation of a graphing utility, we find that the rate of change of y with respect to t when t  1 is given by f (1)  10 (Figure T1). b. Here, f(t)  3t 3  2t 1/2 and 1 1 f ¿1t2  9t 2  2¢ t1/2≤  9t 2  2 1t

Using this result, we see that when t  1, y is changing at the rate of f ¿112  9112 2 

units per unit change in t, as obtained earlier.

1  10 11

9.4 BASIC RULES OF DIFFERENTIATION

601

APPLIED EXAMPLE 2 Fuel Economy of Cars According to data obtained from the U.S. Department of Energy and the Shell Development Company, a typical car’s fuel economy depends on the speed it is driven and is approximated by the function f(x)  0.00000310315x 4  0.000455174x 3  0.00287869x 2  1.25986x (0 x 75)

where x is measured in mph and f(x) is measured in miles per gallon (mpg). a. Use a graphing utility to graph the function f on the interval [0, 75]. b. Find the rate of change of f when x  20 and when x  50. c. Interpret your results. Source: U.S. Department of Energy and the Shell Development Company Solution

FIGURE T2 The graph of the function f on the interval [0, 75]

a. The graph is shown in Figure T2. b. Using the numerical derivative operation of a graphing utility, we see that f (20)  .9280996. The rate of change of f when x  50 is given by f (50)  .3145009995. (See Figure T3a and T3b.) nDeriv(.0000031 0315X^4−.0004551 74X^3+.00287869X ^2+1.25986X, X, 20) .9280996

nDeriv(.0000031 0315X^4−.0004551 74X^3+.00287869X ^2+1.25986X, X, 5 0) −.3145009995

FIGURE T3 The TI-83/84 numerical derivative screen for computing (a) f(20) and (b) f(50)

(a)

(b)

c. The results of part (b) tell us that when a typical car is being driven at 20 mph, its fuel economy increases at the rate of approximately 0.9 mpg per 1 mph increase in its speed. At a speed of 50 mph, its fuel economy decreases at the rate of approximately 0.3 mpg per 1 mph increase in its speed.

TECHNOLOGY EXERCISES In Exercises 1–6, use the numerical derivative operation to find the rate of change of f(x) at the given value of x. Give your answer accurate to four decimal places.

1. f(x)  4x 5  3x 3  2x 2  1; x  0.5 2. f(x)  x 5  4x 2  3; x  0.4 3. f 1x 2  x  21x; x  3 4. f 1x2 

1x  1 ;x2 x

5. f(x)  x 1/2  x 1/3 ; x  1.2 6. f(x)  2x 5/4  x; x  2

7. CARBON MONOXIDE IN THE ATMOSPHERE The projected average global atmospheric concentration of carbon monoxide is approximated by the function f(t)  0.881443t 4  1.45533t 3  0.695876t 2  2.87801t  293 (0 t 4)

where t is measured in 40-yr intervals with t  0 corresponding to the beginning of 1860, and f(t) is measured in parts per million by volume. a. Plot the graph of f in the viewing window [0, 4]  [280, 400]. b. Use a graphing utility to estimate how fast the projected average global atmospheric concentration of carbon monoxide was changing at the beginning of 1900 (t  1) and at the beginning of 2000 (t  3.5). Source: Meadows et al., “Beyond the Limits” (continued)

602

9 THE DERIVATIVE

8. SPREAD OF HIV The estimated number of children newly infected with HIV through mother-to-child contact worldwide is given by

b. Plot the graph of the function found in part (a). c. Use the numerical derivative capability of your graphing utility to find the rate at which the assets of hedge funds were increasing at the beginning of 2000 and the beginning of 2003.

f (t)  0.2083t 3  3.0357t 2  44.0476t  200.2857 (0 t 12)

Sources: Hennessee Group; Institutional Investor

where f (t) is measured in thousands and t is measured in years, with t  0 corresponding to the beginning of 1990. a. Plot the graph of f in the viewing window [0, 12]  [0, 800]. b. How fast was the estimated number of children newly infected with HIV through mother-to-child contact worldwide increasing at the beginning of the year 2000?

10. MODELING WITH DATA The number of people (in millions) enrolled in HMOs from 1994 through 2002 is given in the following table: Year

1994 1995 1996 1997 1998 1999 2000 2001 2002

People 45.4

Source: United Nations

50.6 58.7

67.0 76.4 81.3 80.9 80.0 74.2

Year

1999

2000

2001

2002

2003

2004

a. Use QuartReg to find a fourth-degree polynomial regression model for this data. Let t  0 correspond to 1994. b. Use the model to estimate the number of people enrolled in HMOs in 2000. How does this number compare with the actual number? c. How fast was the number of people receiving their care in an HMO changing at the beginning of 2001?

Assets ($ billions)

472

517

594

650

817

950

Source: Group Health Association of America

9. MODELING WITH DATA A hedge fund is a lightly regulated pool of professionally managed money. The assets (in billions of dollars) of hedge funds from the beginning of 1999 (t  0) through the beginning of 2004 are given in the following table:

a. Use CubicReg to find a third-degree polynomial function for the data, letting t  0 correspond to the beginning of 1999.

9.5 The Product and Quotient Rules; Higher-Order Derivatives In this section we study two more rules of differentiation: the product rule and the quotient rule.

The Product Rule The derivative of the product of two differentiable functions is given by the following rule:

Rule 5: The Product Rule d 3 f 1x2t 1x2 4  f 1x 2t¿1x2  t 1x2 f ¿1x2 dx

The derivative of the product of two functions is the first function times the derivative of the second plus the second function times the derivative of the first. The product rule may be extended to the case involving the product of any finite number of functions (see Exercise 79, p. 614). We prove the product rule at the end of this section.

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

603

The derivative of the product of two functions is not given by the product of the derivatives of the functions; that is, in general d 3 f 1x2t 1x2 4  f ¿1x2t¿1x2 dx

EXAMPLE 1 Find the derivative of the function f(x)  (2x 2  1)(x 3  3) Solution

By the product rule, f ¿1x2  12x2  12

d 3 d 1x  32  1x3  3 2 12x2  12 dx dx  12x2  12 13x2 2  1x3  32 14x2  6x4  3x2  4x4  12x  10x4  3x2  12x Combine like terms. 3  x110x  3x  12 2 Factor out x.

(x2)

See page 10.

EXAMPLE 2 Differentiate (that is, find the derivative of) the function f 1x2  x3 1 1x  12 Solution

First, we express the function in exponential form, obtaining f(x)  x 3(x 1/2  1)

By the product rule, d 1/2 d 1x  1 2  1x1/2  1 2 x3 dx dx 1  x3 a x1/2 b  1x1/2  1 2 13x2 2 2 1  x5/2  3x5/2  3x2 2 7  x5/2  3x2 2

f ¿1x2  x3

Note We can also solve the problem by first expanding the product before differentiating f. Examples for which this is not possible will be considered in Section 9.6, where the true value of the product rule will be appreciated.

The Quotient Rule The derivative of the quotient of two differentiable functions is given by the following rule:

Rule 6: The Quotient Rule t 1x2 f ¿1x2  f 1x2t¿1x2 d f 1x2 c d  dx t 1x2 3t 1x2 4 2

1t 1x2  02

604

9 THE DERIVATIVE

As an aid to remembering this expression, observe that it has the following form: d f 1x2 c d  dx t 1x2

1Denominator2 a

Derivative of Derivative of b  1Numerator2 a b numerator denominator 1Square of denominator2

For a proof of the quotient rule, see Exercise 80, page 614. The derivative of a quotient is not equal to the quotient of the derivatives; that is, f ¿1x2 d f 1x2 c d  dx t 1x2 t¿1x2

For example, if f (x)  x3 and t(x)  x2, then

d f 1x2 d x3 d c d  ¢ ≤  1x2  1 dx t 1x2 dx x2 dx

which is not equal to d 3 1x 2 dx 3x2 3    x t¿1x2 d 2 2x 2 1x 2 dx

f ¿1x2

EXAMPLE 3 Find f (x) if f 1x2  Solution

x . 2x  4

Using the quotient rule, we obtain f ¿1x 2  

12x  42

d d 1x2  x 12x  42 dx dx

12x  42 2 12x  42 112  x122

12x  42 2 2x  4  2x 4   12x  42 2 12x  42 2

EXAMPLE 4 Find f (x) if f 1x 2  Solution

x2  1 . x2  1

By the quotient rule, 1x2  12 f ¿1x2 

d 2 d 1x  12  1x2  12 1x2  12 dx dx

1x2  12 2 1x  12 12x2  1x2  12 12x2 2



1x2  12 2

2x  2x  2x3  2x 1x2  12 2 4x  2 1x  12 2 3



9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

EXAMPLE 5 Find h(x) if h 1x2 

Solution

1x . x2  1

Rewrite h(x) in the form h 1x2  1x2  1 2 h¿1x2  1x  2

 

605

x1/2 . By the quotient rule, we find x2  1

d 1/2 d 1x 2  x1/2 1x2  1 2 dx dx 1x2  12 2  x1/2 12x2

1 2 1 12 x1/2 2

1x2  12 2 1 1/2 2 1x  1  4x2 2 2x

1x  12 1  3x2  21x1x2  1 2 2 2

Factor out 21 x1/2 from the numerator.

2

APPLIED EXAMPLE 6 Rate of Change of DVD Sales The sales (in millions of dollars) of a DVD recording of a hit movie t years from the date of release is given by S1t2 

5t t2  1

a. Find the rate at which the sales are changing at time t. b. How fast are the sales changing at the time the DVDs are released (t  0)? Two years from the date of release? Solution

a. The rate at which the sales are changing at time t is given by S(t). Using the quotient rule, we obtain S ¿1t2 

d d 5t t d 5 d c 2 c 2 dt t  1 dt t  1

5c 5c

1t 2  1 2 112  t 12t2 1t 2  12 2

d

(x2)

See page 22.

511  t 2 2 t 2  1  2t 2 d  1t 2  12 2 1t 2  1 2 2

b. The rate at which the sales are changing at the time the DVDs are released is given by S ¿102 

511  02

10  12 2

5

That is, they are increasing at the rate of $5 million per year. Two years from the date of release, the sales are changing at the rate of S ¿122 

511  42

3    0.6 5 14  12 2

That is, they are decreasing at the rate of $600,000 per year. The graph of the function S is shown in Figure 41.

606

9 THE DERIVATIVE

Millions of dollars

S (t) 3

2

1

FIGURE 41

t

After a spectacular rise, the sales begin to taper off.

2

4

6 Years

8

10

Exploring with

TECHNOLOGY Refer to Example 6. 1. Use a graphing utility to plot the graph of the function S, using the viewing window [0, 10]  [0, 3]. 2. Use TRACE and ZOOM to determine the coordinates of the highest point on the graph of S in the interval [0, 10]. Interpret your results.

Explore & Discuss Suppose the revenue of a company is given by R(x)  xp(x), where x is the number of units of the product sold at a unit price of p(x) dollars. 1. Compute R(x) and explain, in words, the relationship between R(x) and p(x) and/or its derivative. 2. What can you say about R(x) if p(x) is constant? Is this expected?

APPLIED EXAMPLE 7 Oxygen-Restoration Rate in a Pond When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. Suppose the oxygen content t days after organic waste has been dumped into the pond is given by f 1t2  100 c

t 2  10t  100 d t 2  20t  100

10 t  2

percent of its normal level. a. Derive a general expression that gives the rate of change of the pond’s oxygen level at any time t. b. How fast is the pond’s oxygen content changing 1 day, 10 days, and 20 days after the organic waste has been dumped? Solution

a. The rate of change of the pond’s oxygen level at any time t is given by the derivative of the function f. Thus, the required expression is

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

607

d t 2  10t  100 d c dt t 2  20t  100 d d 1t 2  20t  1002 1t 2  10t  1002  1t 2  10t  1002 1t 2  20t  100 2 dt dt  100 £ § 1t 2  20t  1002 2

f ¿1t2  100

1t 2  20t  1002 12t  10 2  1t 2  10t  1002 12t  202

(x ) See page 22. d 1t 2  20t  1002 2 2t 3  10t 2  40t 2  200t  200t  1000  2t 3  20t 2  20t 2  200t  200t  2000  100 c d 1t 2  20t  1002 2 10t 2  1000  100 c 2 d Combine like terms in the numerator. 1t  20t  1002 2

 100 c

2

b. The rate at which the pond’s oxygen content is changing 1 day after the organic waste has been dumped is given by f ¿112  100 c

10  1000 d  6.76 11  20  1002 2

That is, it is dropping at the rate of 6.8% per day. After 10 days, the rate is f ¿1102  100 c

101102 2  1000

1102  201102  1002 2

d 0

That is, it is neither increasing nor decreasing. After 20 days, the rate is f ¿1202  100 c

101202 2  1000

1202  201202  1002 2

d  0.37

That is, the oxygen content is increasing at the rate of 0.37% per day, and the restoration process has indeed begun.

Higher-Order Derivatives The derivative f  of a function f is also a function. As such, the differentiability of f  may be considered. Thus, the function f  has a derivative f  at a point x in the domain of f  if the limit of the quotient f ¿1x  h2  f ¿1x2 h

exists as h approaches zero. In other words, it is the derivative of the first derivative. The function f  obtained in this manner is called the second derivative of the function f, just as the derivative f  of f is often called the first derivative of f. Continuing in this fashion, we are led to considering the third, fourth, and higher-order derivatives of f whenever they exist. Notations for the first, second, third, and, in general, nth derivatives of a function f at a point x are f (x), f (x), f (x), . . . , f (n)(x) or D1f(x), D2f(x), D3f(x), . . . , D nf(x)

If f is written in the form y  f(x), then the notations for its derivatives are y¿,y–,y‡,...,y 1n2 dy d 2y d 3y dny , 2, 3 , . . . , n dx dx dx dx

608

9 THE DERIVATIVE

or D1y, D2y, D3y, . . . , Dny

respectively. EXAMPLE 8 Find the derivatives of all orders of the polynomial function f(x)  x 5  3x 4  4x 3  2x 2  x  8 Solution

We have f ¿1x2  5x4  12x3  12x2  4x  1 d f –1x2  f ¿1x2  20x3  36x2  24x  4 dx d f ‡1x2  f –1x2  60x 2  72x  24 dx d f 142 1x2  f ‡1x2  120x  72 dx d 142 f 152 1x2  f 1x2  120 dx

and, in general, f (n)(x)  0

(for n  5)

EXAMPLE 9 Find the third derivative of the function f defined by y  x 2/3. What is its domain? Solution

We have 2 y¿  x1/3 3 2 1 2 y–  a b a b x4/3   x4/3 3 3 9

y 4

so the required derivative is 2 4 8 7/3 8 y‡  a b a b x7/3  x  9 3 27 27x7/3

2

–4

–2

FIGURE 42

x 2

4

The graph of the function y  x2/3

The common domain of the functions f , f , and f  is the set of all real numbers except x  0. The domain of y  x 2/3 is the set of all real numbers. The graph of the function y  x 2/3 appears in Figure 42. Note Always simplify an expression before differentiating it to obtain the next order derivative.

Just as the derivative of a function f at a point x measures the rate of change of the function f at that point, the second derivative of f (the derivative of f ) measures the rate of change of the derivative f  of the function f. The third derivative of the function f, f , measures the rate of change of f , and so on. In Chapter 10, we will discuss applications involving the geometric interpretation of the second derivative of a function. The following example gives an interpretation of the second derivative in a familiar role.

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

609

APPLIED EXAMPLE 10 Acceleration of a Maglev Refer to the example on pages 534–537. The distance s (in feet) covered by a maglev moving along a straight track t seconds after starting from rest is given by the function s  4t 2 (0 t 10). What is the maglev’s acceleration at any time t? Solution

The velocity of the maglev t seconds from rest is given by √

ds d  14t 2 2  8t dt dt

The acceleration of the maglev t seconds from rest is given by the rate of change of the velocity of t—that is, a

d d ds d 2s d √  a b  2  18t2  8 dt dt dt dt dt

or 8 feet per second per second, normally abbreviated 8 ft/sec2. APPLIED EXAMPLE 11 Acceleration and Velocity of a Falling Object A ball is thrown straight up into the air from the roof of a building. The height of the ball as measured from the ground is given by s  16t 2  24t  120

where s is measured in feet and t in seconds. Find the velocity and acceleration of the ball 3 seconds after it is thrown into the air. Solution

The velocity √ and acceleration a of the ball at any time t are given by √ 

ds d  116t 2  24t  1202  32t  24 dt dt

and a

d 2s d ds d  a b  132t  24 2  32 2 dt dt dt dt

Therefore, the velocity of the ball 3 seconds after it is thrown into the air is √  32(3)  24  72

That is, the ball is falling downward at a speed of 72 ft/sec. The acceleration of the ball is 32 ft/sec2 downward at any time during the motion. Another interpretation of the second derivative of a function—this time from the field of economics—follows. Suppose the consumer price index (CPI) of an economy between the years a and b is described by the function I(t) (a t b) (Figure 43). Then the first derivative of I at t  c, I(c), where a c b, gives the rate of change of I at c. The quantity

I(t)

I ¿1c2 t a

b Years

FIGURE 43 The CPI of a certain economy from year a to year b is given by I(t).

I 1c2

called the relative rate of change of I(t) with respect to t at t  c, measures the inflation rate of the economy at t  c. The second derivative of I at t  c, I (c), gives the rate of change of I at t  c. Now, it is possible for I(t) to be positive and I (t) to be negative at t  c (see Example 12). This tells us that at t  c the economy is experiencing inflation (the CPI is increasing) but the rate at which inflation is growing is in fact decreasing. This is precisely the situation described by an economist or a politician when she claims that “inflation is slowing.” One may not jump to the conclusion from the aforementioned quote that prices of goods and services are about to drop!

610

9 THE DERIVATIVE

APPLIED EXAMPLE 12 Inflation Rate of an Economy The function I(t)  0.2t 3  3t 2  100

(0 t 9)

gives the CPI of an economy, where t  0 corresponds to the beginning of 2002. a. Find the inflation rate at the beginning of 2008 (t  6). b. Show that inflation was moderating at that time. Solution

a. We find I(t)  0.6t 2  6t. Next, we compute I(6)  0.6(6)2  6(6)  14.4

and I(6)  0.2(6)3  3(6)2  100  164.8

from which we see that the inflation rate is I ¿162 I 162

I(t) 200 180



14.4  0.0874 164.8

or approximately 8.7%. b. We find

y = I(t)

160

I –1t2 

140 120

d 10.6t 2  6t2  1.2t  6 dt

Since

100 t 2

4 6 Years

I (6)  1.2(6)  6  1.2

8 9

we see that I is indeed decreasing at t  6 and conclude that inflation was moderating at that time (Figure 44).

FIGURE 44 The CPI of an economy is given by I(t).

Verification of the Product Rule We will now verify the product rule. If p(x)  f(x)t(x), then p ¿1x2  lim

p 1x  h 2  p 1x2 h

hS0

 lim

f 1x  h2t1x  h2  f 1x2t1x2

hS0

h

By adding f(x  h)t(x)  f(x  h)t(x) (which is zero!) to the numerator and factoring, we have p ¿1x2  lim

f 1x  h2 3t1x  h2  t1x2 4  t1x2 3 f 1x  h2  f 1x2 4

hS0

 lim b f 1x  h2 c hS0

 lim f 1x  h2 c

h t1x  h2  t1x2

h t1x  h2  t1x2 h

hS0

 lim f 1x  h2 # lim hS0

f 1x  h2  f 1x2

dr h f 1x  h2  f 1x2 d  lim t1x2 c d hS0 h

By Property 3 of limits

t1x  h2  t1x2

h f 1x  h2  f 1x2

hS0

 lim t1x2 # lim hS0

d  t1x2 c

hS0

 f 1x2t¿1x2  t1x2f ¿1x2

h

By Property 4 of limits

Observe that in the second from the last link in the chain of equalities, we have used the fact that lim f 1x  h2  f 1x2 because f is continuous at x. hS0

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

611

9.5 Self-Check Exercises 1. Find the derivative of f 1x 2 

2x  1 x 1 2

S  f 1t2 

.

2. Find the third derivative of f 1x2  2x  3x  x  6x  10 5

3

2

3. The total sales of Security Products in its first 2 yr of operation are given by

0.3t 3 1  0.4t 2

10 t 22

where S is measured in millions of dollars and t  0 corresponds to the date Security Products began operations. How fast were the sales increasing at the beginning of the company’s second year of operation? Solutions to Self-Check Exercises 9.5 can be found on page 614.

9.5 Concept Questions 1. State the rule of differentiation in your own words. a. Product rule

b. Quotient rule

2. If f (1)  3, t(1)  2, f (1)  1, and t(1)  4, find b. F(1) if F 1x 2 

a. h(1) if h(x)  f(x)t(x)

f 1x 2 t1x2

3. a. What is the second derivative of a function f ? b. How do you find the second derivative of a function f, assuming that it exists? 4. If s  f (t) gives the position of an object moving on the coordinate line, what do f(t) and f (t) measure?

9.5 Exercises 15. f 1x2 

1 x2

16. t 1x2 

3 2x  4

2. f (x)  3x 2(x  1)

17. f 1x2 

x1 2x  1

18. f 1t2 

1  2t 1  3t

3. f (t)  (t  1)(2t  1)

19. f 1x2 

1

20. f 1u 2 

In Exercises 1–30, find the derivative of each function.

1. f (x)  2x(x  1) 2

5. f(x)  (3x  1)(x 2  2)

x 1 s2  4 21. f 1s 2  s1

6. f(x)  (x  1)(2x 2  3x  1)

23. f 1x2 

4. f (x)  (2x  3)(3x  4)

7. f(x)  (x 3  1)(x  1)

25. f 1x2 

8. f(x)  (x 3  12x)(3x 2  2x) 9. f(w)  (w 3  w 2  w  1)(w 2  2) 1 10. f 1x2  x5  1x2  12 1x2  x  12  28 5 11. f 1x 2  15x  12 12 1x  12 2

12. f 1t 2  11  1t2 12t 2  32 2 13. f 1x 2  1x2  5x  22 ¢x  ≤ x 14. f 1x 2  1x3  2x  12 ¢2 

1 x2

26. f 1x2  27. f 1x2 

1x  1 x2  1 x2  2

22. f 1x2 

x2  x  1 x1 2x2  2x  3 1x  12 1x2  1 2 x2

x  23x 3x  1

u u 1 x3  2 2

x2  1 x2  1 24. f 1x 2  1x

1 28. f 1x2  13x2  1 2¢x2  ≤ x x1 x  2 29. f 1x2  2 x 4 x 4 30. f(x) 

≤

2

612

9 THE DERIVATIVE

x

In Exercises 31–34, suppose f and g are functions that are differentiable at x  1 and that f(1)  2, f ⬘(1)  1, g(1)  2, and g⬘(1)  3. Find the value of h⬘(1).

56. Let f(x) 

31. h(x)  f (x) t(x)

32. h(x)  (x 2  1)t(x)

33. h(x) 

34. h(x) 

57. Find the point(s) on the graph of the function f(x)  (x 2  6)(x  5) where the slope of the tangent line is equal to 2. x1 58. Find the point(s) on the graph of the function f(x)  x1 where the slope of the tangent line is equal to  12 .

xf 1x 2

x  t1x2

f 1x 2 t1x 2

f 1x 2  t1x2

In Exercises 35–38, find the derivative of each of the given functions and evaluate f⬘(x) at the given value of x.

35. f (x)  (2x  1)(x 2  3); x  1

59. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration of a certain drug in a patient’s bloodstream t hr after injection is given by

2x  1 36. f(x)  ;x2 2x  1 x

37. f (x) 

; x  1

C(t) 

x  2x  1 38. f (x)  ( 1x  2x)(x 3/2  x); x  4 4

2

In Exercises 39–42, find the slope and an equation of the tangent line to the graph of the function f at the specified point.

41. f(x)  42. f (x) 

x2 4 ; a2, b x1 3 x1 x2  1

; (1, 1)

1  2x1/2 1x

3/2

5 ; a4, b 9

43. f (x)  4x 2  2x  1 45. f (x)  2x 3  3x 2  1 46. t(x)  3x 3  24x 2  6x  64 47. h(t)  t 4  2t 3  6t 2  3t  10 2

In Exercises 49–52, find the third derivative of the given function.

49. f (x)  3x 4  4x 3 50. f (x)  3x 5  6x 4  2x 2  8x  12 51. f(x) 

1 x

52. f (x) 

Find C(80), C(90), C(95), and C(99). What does your result tell you about the cost of removing all of the pollutant?

D(t) 

48. f(x)  x  x  x  x  x  1 3

0.5x 100  x

61. DRUG DOSAGES Thomas Young has suggested the following rule for calculating the dosage of medicine for children 1 to 12 yr old. If a denotes the adult dosage (in milligrams) and if t is the child’s age (in years), then the child’s dosage is given by

44. f (x)  0.2x 2  0.3x  4

4

t 1

a. Find the rate at which the concentration of the drug is changing with respect to time. b. How fast is the concentration changing 12 hr, 1 hr, and 2 hr after the injection?

C(x) 

In Exercises 43–48, find the first and second derivatives of the given function.

5

0.2t 2

60. COST OF REMOVING TOXIC WASTE A city’s main well was recently found to be contaminated with trichloroethylene, a cancer-causing chemical, as a result of an abandoned chemical dump leaching chemicals into the water. A proposal submitted to the city’s council members indicates that the cost, measured in millions of dollars, of removing x% of the toxic pollutant is given by

39. f (x)  (x 3  1)(x 2  2); (2, 18) 40. f (x) 

. Find the point(s) on the graph of f x 1 where the tangent line is horizontal. 2

2 2

x 53. Find an equation of the tangent line to the graph of the function f (x)  (x 3  1)(3x 2  4x  2) at the point (1, 2).

54. Find an equation of the tangent line to the graph of the 3x function f(x)  2 at the point (2, 3). x 2 55. Let f (x)  (x 2  1)(2  x). Find the point(s) on the graph of f where the tangent line is horizontal.

at t  12

Suppose the adult dosage of a substance is 500 mg. Find an expression that gives the rate of change of a child’s dosage with respect to the child’s age. What is the rate of change of a child’s dosage with respect to his or her age for a 6-yrold child? A 10-yr-old child? 62. EFFECT OF BACTERICIDE The number of bacteria N(t) in a certain culture t min after an experimental bactericide is introduced obeys the rule N(t) 

10,000 1  t2

 2000

Find the rate of change of the number of bacteria in the culture 1 min and 2 min after the bactericide is introduced. What is the population of the bacteria in the culture 1 min and 2 min after the bactericide is introduced?

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

63. DEMAND FUNCTIONS The demand function for the Sicard wristwatch is given by d(x) 

50 0.01x  1 2

(0 x 20)

where x (measured in units of a thousand) is the quantity demanded per week and d(x) is the unit price in dollars. a. Find d(x). b. Find d(5), d(10), and d(15) and interpret your results. 64. LEARNING CURVES From experience, Emory Secretarial School knows that the average student taking Advanced Typing will progress according to the rule N(t) 

60t  180 t6

(t  0)

where N(t) measures the number of words/minute the student can type after t wk in the course. a. Find an expression for N(t). b. Compute N(t) for t  1, 3, 4, and 7 and interpret your results. c. Sketch the graph of the function N. Does it confirm the results obtained in part (b)? d. What will be the average student’s typing speed at the end of the 12-wk course? 65. BOX-OFFICE RECEIPTS The total worldwide box-office receipts for a long-running movie are approximated by the function 120x 2 T(x)  2 x 4 where T(x) is measured in millions of dollars and x is the number of years since the movie’s release. How fast are the total receipts changing 1 yr, 3 yr, and 5 yr after its release? 66. FORMALDEHYDE LEVELS A study on formaldehyde levels in 900 homes indicates that emissions of various chemicals can decrease over time. The formaldehyde level (parts per million) in an average home in the study is given by f(t) 

0.055t  0.26 t2

(0 t 12)

where t is the age of the house in years. How fast is the formaldehyde level of the average house dropping when it is new? At the beginning of its fourth year? Source: Bonneville Power Administration

67. POPULATION GROWTH A major corporation is building a 4325-acre complex of homes, offices, stores, schools, and churches in the rural community of Glen Cove. As a result of this development, the planners have estimated that Glen Cove’s population (in thousands) t yr from now will be given by 25t 2  125t  200 P(t)  t 2  5t  40 a. Find the rate at which Glen Cove’s population is changing with respect to time. b. What will be the population after 10 yr? At what rate will the population be increasing when t  10?

613

68. ACCELERATION OF A CAR The distance s (in feet) covered by a car t sec after starting from rest is given by s  t 3  8t 2  20t

(0 t 6)

Find a general expression for the car’s acceleration at any time t(0 t 6). Show that the car is decelerating 223 sec after starting from rest. 69. CRIME RATES The number of major crimes committed in Bronxville between 2000 and 2007 is approximated by the function N(t)  0.1t 3  1.5t 2  100

(0 t 7)

where N(t) denotes the number of crimes committed in year t, with t  0 corresponding to the beginning of 2000. Enraged by the dramatic increase in the crime rate, Bronxville’s citizens, with the help of the local police, organized “Neighborhood Crime Watch” groups in early 2004 to combat this menace. a. Verify that the crime rate was increasing from the beginning of 2000 to the beginning of 2007. Hint: Compute N(0), N(1), . . . , N(7).

b. Show that the Neighborhood Crime Watch program was working by computing N (4), N(5), N (6), and N(7). 70. GDP OF A DEVELOPING COUNTRY A developing country’s gross domestic product (GDP) from 2000 to 2008 is approximated by the function G(t)  0.2t 3  2.4t 2  60

(0 t 8)

where G(t) is measured in billions of dollars, with t  0 corresponding to the beginning of 2000. a. Compute G(0), G(1), . . . , G(8). b. Compute G(0), G (1), . . . , G (8). c. Using the results obtained in parts (a) and (b), show that after a spectacular growth rate in the early years, the growth of the GDP cooled off. 71. DISABILITY BENEFITS The number of persons aged 18–64 receiving disability benefits through Social Security, the Supplemental Security income, or both, from 1990 through 2000 is approximated by the function N(t)  0.00037t 3  0.0242t 2  0.52t  5.3

(0 t 10)

where f(t) is measured in units of a million and t is measured in years, with t  0 corresponding to the beginning of 1990. Compute N(8), N(8), and N(8) and interpret your results. Source: Social Security Administration

72. U.S. CENSUS The number of Americans aged 45 to 54 is approximately N(t)  0.00233t 4  0.00633t 3  0.05417t 2  1.3467t  25 million people in year t, with t  0 corresponding to the beginning of 1990. Compute N(10) and N(10) and interpret your results. Source: U.S. Census Bureau

614

9 THE DERIVATIVE

73. OBESITY IN AMERICA The body mass index (BMI) measures body weight in relation to height. A BMI of 25 to 29.9 is considered overweight, a BMI of 30 or more is considered obese, and a BMI of 40 or more is morbidly obese. The percent of the U.S. population that is obese is approximated by the function P(t)  0.0004t 3  0.0036t 2  0.8t  12

(0 t 13)

where t is measured in years, with t  0 corresponding to the beginning of 1991. Show that the rate of the rate of change of the percent of the U.S. population that is deemed obese was positive from 1991 to 2004. What does this mean? Source: Centers for Disease Control and Prevention

74. AIR PURIFICATION During testing of a certain brand of air purifier, the amount of smoke remaining t min after the start of the test was A(t)  0.00006t 5  0.00468t 4  0.1316t 3  1.915t 2  17.63t  100 percent of the original amount. Compute A(10) and A(10) and interpret your results.

77. If f is differentiable, then f ¿ 1x2 d f 1x2 c 2 d  dx x 2x 78. If the second derivative of f exists at x  a, then f (a)  [ f (a)]2. 79. Extend the product rule for differentiation to the following case involving the product of three differentiable functions: Let h(x)  u(x)√(x)w(x) and show that h(x)  u(x)√(x)w(x)  u(x)√(x)w(x)  u(x)√(x)w(x). Hint: Let f (x)  u(x)√(x), t(x)  w(x), and h(x)  f (x)t(x) and apply the product rule to the function h.

80. Prove the quotient rule for differentiation (Rule 6). Hint: Let k(x)  f (x)/t(x) and verify the following steps: a.

k1x  h 2  k1x 2 h



f 1x  h 2 t1x2  f 1x2 t1x  h 2 ht1x  h 2 t1x2

b. By adding [f (x)t(x)  f (x)t(x)] to the numerator and simplifying, show that k1x  h2  k1x 2

Source: Consumer Reports

h



 ec

In Exercises 75–78, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, given an example to show why it is false.

 c

75. If f and t are differentiable, then d [ f(x)t(x)]  f (x)t(x) dx 76. If f is differentiable, then

1 t1x  h 2 t1x2

c. k(x)  lim

h

t1x  h 2  t1x2 h

d # t1x2

d # f 1x2 f

k1x  h2  k1x 2 h

hS0



f 1x  h 2  f 1x2

t1x 2 f ¿1x 2  f 1x2 t¿ 1x2 3 t1x2 4 2

d [xf (x)]  f(x)  xf (x) dx

9.5 Solutions to Self-Check Exercises 1. We use the quotient rule to obtain f ¿ 1x 2   

1x2  12

d d 12x  1 2  12x  1 2 1x2  1 2 dx dx 1x2  1 2 2

1x2  12 12 2  12x  1 2 12x 2 1x2  1 2 2

2x2  2  4x2  2x 1x2  1 2 2

2x2  2x  2  1x2  1 2 2 

21x2  x  12 1x2  1 2 2

2. f (x)  10x 4  9x 2  2x  6 f (x)  40x 3  18x  2 f (x)  120x 2  18

3. The rate at which the company’s total sales are changing at any time t is given by 11  0.4t 2 2 S ¿1t2  

d d 10.3t 3 2  10.3t 3 2 11  0.4t 2 2 dt dt 11  0.4t 2 2 2

11  0.4t 2 2 10.9t 2 2  10.3t 3 2 10.8t2 11  0.4t 2 2 2

Therefore, at the beginning of the second year of operation, Security Products’ sales were increasing at the rate of S ¿11 2 

11  0.42 10.9 2  10.3 2 10.8 2

or $520,408/year.

11  0.4 2 2

 0.520408

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

USING

TECHNOLOGY

615

The Product and Quotient Rules EXAMPLE 1 Let f 1x2  12 1x  0.5x2 10.3x3  2x  0.3 x 2 . Find f (0.2). Solution

Using the numerical derivative operation of a graphing utility, we find f (0.2)  6.4797499802

See Figure T1. nDeriv((2X^.5+.5 X) (.3X^3+2X−.3/X), X, .2) 6.4797499802

FIGURE T1 The TI-83/84 numerical derivative screen for computing f (0.2)

APPLIED EXAMPLE 2 Importance of Time in Treating Heart Attacks According to the American Heart Association, the treatment benefit for heart attacks depends on the time until treatment and is described by the function f 1t2 

0.44t 4  700 0.1t 4  7

10 t 24 2

where t is measured in hours and f(t) is expressed as a percent. a. Use a graphing utility to graph the function f using the viewing window [0, 24]  [0, 100]. b. Use a graphing utility to find the derivative of f when t  0 and t  2. c. Interpret the results obtained in part (b). Source: American Heart Association

Solution FIGURE T2

a. The graph of f is shown in Figure T2. b. Using the numerical derivative operation of a graphing utility, we find f (0)  0 f (2)  28.95402429

(see Figure T3). nDeriv((.44X^4+7 00)/(.1X^4+7),X, 0) 0

nDeriv((.44X^4+7 00)/(.1X^4+7),X, 2) -28.95402429

FIGURE T3 TI-83/84 numerical derivative screens (a) for computing f(0) and (b) for computing f(2)

(a)

(b)

c. The results of part (b) show that there is no drop in the treatment benefit when the heart attack is treated immediately. But the treatment benefit drops off at the rate of approximately 29% per hour when the time to treatment is 2 hours. Thus, it is extremely urgent that a patient suffering a heart attack receive medical attention as soon as possible. (continued)

616

9 THE DERIVATIVE

Finding the Second Derivative of a Function at a Given Point Some graphing utilities have the capability of numerically computing the second derivative of a function at a point. If your graphing utility has this capability, use it to work through the examples and exercises of this section. EXAMPLE 3 Use the (second) numerical derivative operation of a graphing utility to find the second derivative of f 1x2  1x when x  4. Solution

Using the (second) numerical derivative operation, we find f (4)  der2(xˆ.5, x, 4)  .03125

der2(x^.5, x, 4)

−.03125

FIGURE T4 The TI-86 second derivative screen for computing f ( 4 )

evalF

nDer

der1

der2

Fnlnt

(Figure T4). APPLIED EXAMPLE 4 Prevalence of Alzheimer’s Patients The number of Alzheimer’s patients in the United States is given by f(t)  0.02765t 4  0.3346t 3  1.1261t 2  1.7575t  3.7745 (0 t 5)

where f(t) is measured in millions and t is measured in decades, with t  0 corresponding to the beginning of 1990. a. How fast is the number of Alzheimer’s patients in the United States anticipated to be changing at the beginning of 2030? b. How fast is the rate of change of the number of Alzheimer’s patients in the United States anticipated to be changing at the beginning of 2030? c. Plot the graph of f in the viewing window [0, 5]  [0, 12]. Source: Alzheimer’s Association

Solution

a. Using the numerical derivative operation of a graphing utility, we find that the number of Alzheimer’s patients at the beginning of 2030 can be anticipated to be changing at the rate of f (4)  1.7311

der2(−.02765 x^4+.334 6 x^3−1.1261 x^2+1.75 75 x+3.7745, x, 4) .4694

That is, the number is increasing at the rate of approximately 1.7 million patients per decade. b. Using the (second) numerical derivative operation of a graphing utility, we find that f (4)  0.4694

evalF

nDer

der1

der2

Fnlnt

FIGURE T5 The TI-86 second derivative screen for computing f ( 4 )

(Figure T5); that is, the rate of change of the number of Alzheimer’s patients is increasing at the rate of approximately 0.5 million patients per decade per decade.

617

9.5 THE PRODUCT AND QUOTIENT RULES; HIGHER-ORDER DERIVATIVES

c. Figure T6 shows the graph.

FIGURE T6 The graph of f in the viewing window [0, 5]  [0, 12]

TECHNOLOGY EXERCISES In Exercises 1–6, use the numerical derivative operation to find the rate of change of f(x) at the given value of x. Give your answer accurate to four decimal places.

1. f (x)  (2x 2  1)(x 3  3x  4); x  0.5 2. f 1x 2  1 1x  12 12x2  x  32; x  1.5 3. f 1x 2  4. f 1x2  5. f 1x 2  6. f 1x2 

1x  1 ;x3 1x  1 1x1x2  42 x3  1

x1 x2 12  1x2 1  1x

10. f(x)  2.5x 5  3x 3  1.5x  4; x  2.1 12. f(x)  1.7x 4.2  3.2x 1.3  4.2x  3.2; x  2.2

;x1

;x1

7. NEW CONSTRUCTION JOBS The president of a major housing construction company claims that the number of construction jobs created in the next t mo is given by f 1t2  1.42 ¢

9. f(x)  2x 3  3x 2  1; x  1 11. f(x)  2.1x 3.1  4.2x 1.7  4.2; x  1.4

;x4

1x11  x1 2

In Exercises 9–16, find the value of the second derivative of f at the given value of x. Express your answer correct to four decimal places.

7t 2  140t  700 ≤ 3t 2  80t  550

where f(t) is measured in millions of jobs/year. At what rate will construction jobs be created 1 yr from now, assuming her projection is correct? 8. POPULATION GROWTH A major corporation is building a 4325-acre complex of homes, offices, stores, schools, and churches in the rural community of Glen Cove. As a result of this development, the planners have estimated that Glen Cove’s population (in thousands) t yr from now will be given by 25t 2  125t  200 P 1t2  t 2  5t  40

a. What will be the population 10 yr from now? b. At what rate will the population be increasing 10 yr from now?

13. f 1x 2 

x2  2x  5 ; x  2.1 x3  1

14. f 1x 2 

x3  x  2 ; x  1.2 2x2  5x  4

15. f 1x2 

x1/2  2x3/2  1 ; x  0.5 2x1/2  3

16. f 1x2 

1x  1 ; x  2.3 2x  1x  4

17. RATE OF BANK FAILURES The rate at which banks were failing between 1982 and 1994 is given by f(t)  0.063447t 4  1.953283t 3  14.632576t 2  6.684704t  47.458874

(0 t 12)

where f(t) is measured in the number of banks/year and t is measured in years, with t  0 corresponding to the beginning of 1982. Compute f (6) and interpret your results. Source: Federal Deposit Insurance Corporation

18. MODELING WITH DATA The revenues (in billions of dollars) from cable advertisement for the years 1995 through 2000 follow: Year Revenue

1995 5.1

1996 6.6

1997 8.1

1998 9.4

1999 11.1

2000 13.7

a. Use CubicReg to find a third-degree polynomial regression model for the data. Let t  0 correspond to 1995. b. Plot the graph of the function f found in part (a), using the viewing window [0, 6]  [0, 14]. c. Compute f (5) and interpret your results. Source: National Cable Television Association

618

9 THE DERIVATIVE

9.6 The Chain Rule The population of Americans age 55 years and older as a percentage of the total population is approximated by the function f (t)  10.72(0.9t  10)0.3

(0 t 20)

where t is measured in years with t  0 corresponding to the year 2000 (Figure 45). y

Percent

40 30 20 10 5

10

15

20

t

FIGURE 45 Population of Americans age 55 years and older

Source: U.S. Census Bureau

How fast will the population age 55 years and older be increasing at the beginning of 2012? To answer this question, we have to evaluate f (12), where f  is the derivative of f. But the rules of differentiation that we have developed up to now will not help us find the derivative of f . In this section, we will introduce another rule of differentiation called the chain rule. When used in conjunction with the rules of differentiation developed in the last two sections, the chain rule enables us to greatly enlarge the class of functions that we are able to differentiate. (In Exercise 70, page 626, we will use the chain rule to answer the question posed in the introductory example.)

The Chain Rule Consider the function h(x)  (x 2  x  1)2. If we were to compute h(x) using only the rules of differentiation from the previous sections, then our approach might be to expand h(x). Thus, h1x2  1x2  x  12 2  1x2  x  1 2 1x2  x  12  x4  2x3  3x2  2x  1

from which we find h(x)  4x 3  6x 2  6x  2

But what about the function H(x)  (x 2  x  1)100? The same technique may be used to find the derivative of the function H, but the amount of work involved in this case would be prodigious! Consider, also, the function G 1x2  2x2  1. For each of the two functions H and G, the rules of differentiation of the previous sections cannot be applied directly to compute the derivatives H and G. Observe that both H and G are composite functions; that is, each is composed of, or built up from, simpler functions. For example, the function H is composed of the two simpler functions f(x)  x 2  x  1 and t(x)  x100 as follows: H1x2  t3 f 1x2 4  3 f 1x2 4 100  1x2  x  12 100

9.6 THE CHAIN RULE

619

In a similar manner, we see that the function G is composed of the two simpler functions f(x)  x2  1 and t 1x2  1x. Thus, G 1x2  t3 f 1x2 4  2f 1x2  2x2  1

As a first step toward finding the derivative h of a composite function h  t 폶 f defined by h(x)  t[ f(x)], we write u  f(x) and y  t[ f(x)]  t(u)

The dependency of h on t and f is illustrated in Figure 46. Since u is a function of x, we may compute the derivative of u with respect to x, if f is a differentiable function, obtaining du/dx  f (x). Next, if t is a differentiable function of u, we may compute the derivative of t with respect to u, obtaining dy/du  t(u). Now, since the function h is composed of the function t and the function f, we might suspect that the rule h(x) for the derivative h of h will be given by an expression that involves the rules for the derivatives of f and t. But how do we combine these derivatives to yield h? h = g[ f ] g

f FIGURE 46

The composite function h(x) g[f(x)]

x

y = g(u) = g[ f (x)]

f (x) = u

This question can be answered by interpreting the derivative of each function as the rate of change of that function. For example, suppose u  f(x) changes three times as fast as x—that is, f ¿1x2 

du 3 dx

And suppose y  t(u) changes twice as fast as u—that is, t¿1u 2 

dy 2 du

Then, we would expect y  h(x) to change six times as fast as x—that is, h(x)  t(u)f (x)  (2)(3)  6

or equivalently, dy dy du #  122 132  6  dx du dx

This observation suggests the following result, which we state without proof. Rule 7: The Chain Rule

If h(x)  t[ f(x)], then h ¿1x2 

d t 1 f 1x2 2  t¿1 f 1x2 2 f ¿1x2 dx

(10)

Equivalently, if we write y  h(x)  t(u), where u  f(x), then dy dy du #  dx du dx

(11)

620

9 THE DERIVATIVE

Notes

1. If we label the composite function h in the following manner Inside function 앗

h(x)  t[ f (x)] 앖 Outside function

then h(x) is just the derivative of the “outside function” evaluated at the “inside function” times the derivative of the “inside function.” 2. Equation (11) can be remembered by observing that if we “cancel” the du’s, then dy dy du #  dy  dx du dx dx

The Chain Rule for Powers of Functions Many composite functions have the special form h(x)  t( f (x)), where t is defined by the rule t(x)  x n (n, a real number)—that is, h(x)  [ f (x)]n

In other words, the function h is given by the power of a function f. The functions h(x)  (x 2  x  1)2

H(x)  (x 2  x  1)100

G1x 2  2x 2  1

discussed earlier are examples of this type of composite function. By using the following corollary of the chain rule, the general power rule, we can find the derivative of this type of function much more easily than by using the chain rule directly.

The General Power Rule

If the function f is differentiable and h(x)  [ f (x)]n (n, a real number), then h ¿1x2 

d 3 f 1x2 4 n  n3 f 1x2 4 n1f ¿1x2 dx

(12)

To see this, we observe that h(x)  t( f (x)), where t(x)  x n, so that, by virtue of the chain rule, we have h¿1x2  t¿1 f 1x22 f ¿1x2

 n3 f 1x2 4 n1f ¿1x2

since t(x)  nx n1. EXAMPLE 1 Let F(x)  (3x  1)2. a. Find F(x), using the general power rule. b. Verify your result without the benefit of the general power rule. Solution

a. Using the general power rule, we obtain d 13x  12 dx  213x  12 132  613x  12

F ¿1x2  213x  12 1

9.6 THE CHAIN RULE

621

b. We first expand F(x). Thus, F(x)  (3x  1)2  9x 2  6x  1

Next, differentiating, we have d 19x2  6x  12 dx  18x  6  613x  12

F ¿1x2 

as before. EXAMPLE 2 Differentiate the function G 1x 2  2x2  1. Solution

We rewrite the function G(x) as G(x)  (x 2  1)1/2

and apply the general power rule, obtaining 1 2 d 1x  12 1/2 1x2  12 2 dx 1 2 x  1x  12 1/2 # 2x  2 2x2  1

G ¿1x2 

EXAMPLE 3 Differentiate the function f (x)  x 2(2x  3)5. Solution

Applying the product rule followed by the general power rule, we obtain d d 12x  32 5  12x  32 5 1x2 2 dx dx d  1x2 2512x  32 4 # 12x  32  12x  32 5 12x2 dx

f ¿1x2  x2

 5x2 12x  32 4 122  2x12x  32 5  2x12x  32 4 15x  2x  3 2  2x17x  32 12x  32 4

EXAMPLE 4 Find f (x) if f (x)  (2x 2  3)4(3x  1)5. Solution

Applying the product rule, we have f ¿1x2  12x2  32 4

d d 13x  12 5  13x  12 5 12x2  32 4 dx dx

Next, we apply the general power rule to each term, obtaining f ¿ 1x2  12x2  32 4 # 513x  12 4

d d 13x  12  13x  12 5 # 412x2  32 3 12x2  32 dx dx

 512x2  32 4 13x  12 4 # 3  413x  12 5 12x2  32 3 14x2

Finally, observing that (2x2  3)3(3x  1)4 is common to both terms, we can factor and simplify as follows: f ¿1x 2  12x2  32 3 13x  12 4 31512x2  32  16x13x  12 4  12x2  32 3 13x  12 4 130x2  45  48x2  16x2  12x2  32 3 13x  12 4 178x2  16x  452

622

9 THE DERIVATIVE

EXAMPLE 5 Find f (x) if f 1x2  Solution

1 . 14x  7 2 2 2

Rewriting f(x) and then applying the general power rule, we obtain d d 1 d  14x2  7 2 2 c 2 2 dx 14x  72 dx d  214x2  7 2 3 14x2  7 2 dx

f ¿1x2 

 214x2  7 2 3 18x2  

16x 14x2  72 3

EXAMPLE 6 Find the slope of the tangent line to the graph of the function f 1x2  ¢

at the point 10, 18 2 .

2x  1 3 ≤ 3x  2

The slope of the tangent line to the graph of f at any point is given by f (x). To compute f (x), we use the general power rule followed by the quotient rule, obtaining

Solution

2x  1 2 d 2x  1 ≤ ¢ ≤ 3x  2 dx 3x  2 2x  1 2 13x  22 122  12x  12 132  3¢ ≤ c d 3x  2 13x  22 2

f ¿1x2  3 ¢

 3¢ 

(x2)

See page 22.

2x  1 2 6x  4  6x  3 ≤ c d 3x  2 13x  22 2

312x  12 2 13x  22 4

Combine like terms and simplify.

In particular, the slope of the tangent line to the graph of f at 10, 18 2 is given by f ¿102 

310  12 2 10  22

4



3 16

Exploring with

TECHNOLOGY Refer to Example 6. 1. Use a graphing utility to plot the graph of the function f, using the viewing window [2, 1]  [1, 2]. Then draw the tangent line to the graph of f at the point 10, 18 2 . 2. For a better picture, repeat part 1 using the viewing window [1, 1]  [0.1, 0.3]. 3. Use the numerical differentiation capability of the graphing utility to verify that the slope of the tangent line at 10, 18 2 is 163 . APPLIED EXAMPLE 7 Growth in a Health Club Membership The membership of The Fitness Center, which opened a few years ago, is approximated by the function N(t)  100(64  4t)2/3

(0 t 52)

9.6 THE CHAIN RULE

623

where N(t) gives the number of members at the beginning of week t. a. b. c. d.

Find N(t). How fast was the center’s membership increasing initially (t  0)? How fast was the membership increasing at the beginning of the 40th week? What was the membership when the center first opened? At the beginning of the 40th week?

Solution

a. Using the general power rule, we obtain N ¿1t 2 

d 3100164  4t 2 2/3 4 dt

d 164  4t2 2/3 dt 2 d  100 a b 164  4t2 1/3 164  4t2 3 dt 200  164  4t 2 1/3 142 3  100



800 3164  4t 2 1/3

b. The rate at which the membership was increasing when the center first opened is given by N ¿10 2 

800  66.7 31642 1/3

or approximately 67 people per week. c. The rate at which the membership was increasing at the beginning of the 40th week is given by N ¿1402 

800  43.9 3164  1602 1/3

or approximately 44 people per week. d. The membership when the center first opened is given by N(0)  100(64)2/3  100(16)

or approximately 1600 people. The membership at the beginning of the 40th week is given by N(40)  100(64  160)2/3  3688.3

or approximately 3688 people.

Explore & Discuss The profit P of a one-product software manufacturer depends on the number of units of its products sold. The manufacturer estimates that it will sell x units of its product per week. Suppose P  t(x) and x  f(t), where t and f are differentiable functions. 1. Write an expression giving the rate of change of the profit with respect to the number of units sold. 2. Write an expression giving the rate of change of the number of units sold per week. 3. Write an expression giving the rate of change of the profit per week.

624

9 THE DERIVATIVE

APPLIED EXAMPLE 8 Arteriosclerosis Arteriosclerosis begins during childhood when plaque (soft masses of fatty material) forms in the arterial walls, blocking the flow of blood through the arteries and leading to heart attacks, strokes, and gangrene. Suppose the idealized cross section of the aorta is circular with radius a cm and by year t the thickness of the plaque (assume it is uniform) is h  t(t) cm (Figure 47). Then the area of the opening is given by A  p(a  h)2 square centimeters (cm2). Suppose the radius of an individual’s artery is 1 cm (a  1) and the thickness of the plaque in year t is given by

a A h

FIGURE 47 Cross section of the aorta

h  t(t)  1  0.01(10,000  t 2)1/2 cm

Since the area of the arterial opening is given by A  f(h)  p(1  h)2

the rate at which A is changing with respect to time is given by dA # dh dA   f ¿1h2 # t¿1t2 dt dh dt

By the chain rule

1  2p11  h2 112 c0.01 a b 110,000  t 2 2 1/2 12t2 d 2

Use the chain rule twice.

 2p11  h2 c 

0.01t d 110,000  t 2 2 1/2 0.02p11  h2 t 210,000  t 2

For example, when t  50, h  t(50)  1  0.01(10,000  2500)1/2  0.134

so that 0.02p11  0.134250 dA   0.03 dt 110,000  2500

That is, the area of the arterial opening is decreasing at the rate of 0.03 cm2 per year.

Explore & Discuss Suppose the population P of a certain bacteria culture is given by P  f(T), where T is the temperature of the medium. Further, suppose the temperature T is a function of time t in seconds—that is, T  t(t). Give an interpretation of each of the following quantities: 1.

dP dT

2.

dT dt

3.

dP dt

4. ( f 폶 t)(t)

5. f (t(t))t(t)

9.6 Self-Check Exercises 1. Find the derivative of f 1x2  

1 22x2  1

2. Suppose the life expectancy at birth (in years) of a female in a certain country is described by the function t(t)  50.02(1  1.09t)0.1

(0 t 150)

where t is measured in years, with t  0 corresponding to the beginning of 1900. a. What is the life expectancy at birth of a female born at the beginning of 1980? At the beginning of 2000? b. How fast is the life expectancy at birth of a female born at any time t changing? Solutions to Self-Check Exercises 9.6 can be found on page 628.

9.6 THE CHAIN RULE

625

9.6 Concept Questions 1. In your own words, state the chain rule for differentiating the composite function h(x)  t[ f (x)].

lars) realized from the sale of x units of the company’s products, what does (t 폶 f )(t) describe?

2. In your own words, state the general power rule for differentiating the function h(x)  [ f (x)]n, where n is a real number.

4. Suppose f(x) gives the air temperature in the gondola of a hot-air balloon when it is at an altitude of x ft from the ground and t(t) gives the altitude of the balloon t min after lifting off from the ground. Find a function giving the rate of change of the air temperature in the gondola at time t.

3. If f (t) gives the number of units of a certain product sold by a company after t days, and t(x) gives the revenue (in dol-

9.6 Exercises In Exercises 1–48, find the derivative of each function.

1. f (x)  (2x  1)4

2. f (x)  (1  x)3

3. f (x)  (x 2  2)5

4. f (t)  2(t 3  1)5

5. f (x)  (2x  x 2)3

8. f 1t 2 

9. f (x)  (x 2  4)3/2

1 2 12t  t2 3 2

10. f (t)  (3t 2  2t  1)3/2

11. f 1x2  13x  2

12. f 1t 2  23t 2  t

13. f 1x2  21  x

14. f 1x 2  22x  2x  3

15. f 1x2  17. f 1t2  19. y 

2

2

16. f 1x 2 

1

12x  3 2

3

18. f 1x 2 

1 12t  3

20. f 1t 2 

1

14x  x 2 4

39. f 1x2 

6. f (x)  3(x 3  x)4

7. f (x)  (2x  1)2

3

37. t 1u2 

3/2

2

1x  12 2

4

41. h 1x2 

u1 A 3u  2

38. t 1x2 

x2

40. t 1u2 

1x  1 2 2

4

13x2  1 2 3 1x2  1 2 4

43. f 1x2 

12x  1

45. t 1t2 

2t  1

4 3

22t 2  t

44. f 1t2 

x 1 2

46. f 1x2 

2t 2  1

In Exercises 49–54, find

53. y  1u 

24. f (t)  (2t  1)4  (2t  1)4

28. f (u)  (2u  1)

3/2

 (u  1)

29. f (x)  2x 2(3  4x)4

30. h(t)  t 2(3t  4)3

31. f (x)  (x  1)2(2x  1)4

33. f 1x2  ¢

x3 3 ≤ x2

3/2 t 35. s1t2  ¢ ≤ 2t  1

2x2  1 2x2  1

54. y 

1 and u  x 3  x 1u

1 and u  1x  1 u

56. Suppose h  f 폶 t. Find h(0) given that f(0)  6, f (5)  2, t(0)  5, and t(0)  3. 57. Suppose F(x)  f(x 2  1). Find F(1) if f (2)  3.

32. t(u)  (1  u ) (1  2u ) 2 5

22t 2  2t  1

55. Suppose F(x)  t( f(x)) and f (2)  3, f (2)  3, t(3)  5, and t(3)  4. Find F(2).

3/2

2

4t 2

50. y  1u and u  7x  2x 2 52. y  2u 2  1 and u  x 2  1

27. f 1x2  1x  1  1x  1

13t  22 4

49. y  u4/3 and u  3x 2 1

22. f (t)  (5t 3  2t 2  t  4)3

26. f (√)  (√3  4√2)3

12t  1 2 2

dy du dy , , and . du dx dx

51. y  u2/3 and u  2x 3  x  1

25. f (t)  (t1  t2)3

1u  u2 3

48. t(t)  (2t  3)2(3t 2  1)3

21. f (x)  (3x 2  2x  1)2

23. f (x)  (x 2  1)3  (x 3  1)2

2u2

2

47. f(x)  (3x  1)4(x 2  x  1)3

1 22x2  1

42. t 1t2 

2x  1 A 2x  1

2 8

34. f 1x 2  ¢

58. Let F(x)  f( f(x)). Does it follow that F(x)  [ f (x)]2? x1 5 ≤ x1

1 3/2 36. t 1s2  ¢s2  ≤ s

Hint: Let f (x)  x 2.

59. Suppose h  t 폶 f. Does it follow that h  t 폶 f ? Hint: Let f (x)  x and t(x)  x 2.

60. Suppose h  f 폶 t. Show that h  ( f  폶 t)t.

626

9 THE DERIVATIVE

In Exercises 61–64, find an equation of the tangent line to the graph of the function at the given point.

61. f (x)  (1  x)(x 2  1)2; (2, 9) 62. f 1x2  ¢

x1 2 ≤ ; 13, 42 x1

f(t)  23.7(0.2t  1)1.32

63. f 1x2  x 22x  7; 13, 15 2 2

64. f 1x 2 

8 2x2  6x

65. TELEVISION VIEWING The number of viewers of a television series introduced several years ago is approximated by the function (1 t 26)

where N(t) (measured in millions) denotes the number of weekly viewers of the series in the tth week. Find the rate of increase of the weekly audience at the end of week 2 and at the end of week 12. How many viewers were there in week 2? In week 24? 66. OUTSOURCING OF JOBS According to a study conducted in 2003, the total number of U.S. jobs that are projected to leave the country by year t, where t  0 corresponds to the beginning of 2000, is N(t)  0.0018425(t  5)2.5

(0 t 15)

where N(t) is measured in millions. How fast was the number of U.S. jobs that were outsourced changing at the beginning of 2005? How fast will the number of U.S. jobs that are outsourced be changing at the beginning of 2010 (t  10)? Source: Forrester Research

67. WORKING MOTHERS The percentage of mothers who work outside the home and have children younger than age 6 yr is approximated by the function P(t)  33.55(t  5)0.205

(0 t 21)

where t is measured in years, with t  0 corresponding to the beginning of 1980. Compute P(t). At what rate was the percentage of these mothers changing at the beginning of 2000? What was the percentage of these mothers at the beginning of 2000? Source: U.S. Bureau of Labor Statistics

68. SELLING PRICE OF DVD RECORDERS The rise of digital music and the improvement to the DVD format are some of the reasons why the average selling price of standalone DVD recorders will drop in the coming years. The function A 1t 2 

699 1t  12 0.94

(0 t 11)

where t  0 corresponds to the beginning of 1991. a. Find the rate at which the assets of SRIs were changing at the beginning of 2000. b. What were the assets of SRIs at the beginning of 2000?

; 12, 2 2

N(t)  (60  2t)2/3

69. SOCIALLY RESPONSIBLE FUNDS Since its inception in 1971, socially responsible investments, or SRIs, have yielded returns to investors on par with investments in general. The assets of socially responsible funds (in billions of dollars) from 1991 through 2001 is given by

10 t 52

gives the projected average selling price (in dollars) of stand-alone DVD recorders in year t, where t  0 corresponds to the beginning of 2002. How fast was the average selling price of standalone DVD recorders falling at the beginning of 2002? How fast was it falling at the beginning of 2006? Source: Consumer Electronics Association

Source: Thomson Financial Wiesenberger

70. AGING POPULATION The population of Americans age 55 yr and older as a percentage of the total population is approximated by the function f(t)  10.72(0.9t  10)0.3

(0 t 20)

where t is measured in years, with t  0 corresponding to the year 2000. At what rate was the percentage of Americans age 55 and over changing at the beginning of 2000? At what rate will the percentage of Americans age 55 yr and older be changing in 2010? What will be the percentage of the population of Americans age 55 yr and older in 2010? Source: U.S. Census Bureau

71. CONCENTRATION OF CARBON MONOXIDE (CO) IN THE AIR According to a joint study conducted by Oxnard’s Environmental Management Department and a state government agency, the concentration of CO in the air due to automobile exhaust t yr from now is given by C(t)  0.01(0.2t 2  4t  64)2/3

parts per million. a. Find the rate at which the level of CO is changing with respect to time. b. Find the rate at which the level of CO will be changing 5 yr from now. 72. CONTINUING EDUCATION ENROLLMENT The registrar of Kellogg University estimates that the total student enrollment in the Continuing Education division will be given by N 1t2  

20,000 11  0.2t

 21,000

where N(t) denotes the number of students enrolled in the division t yr from now. Find an expression for N(t). How fast is the student enrollment increasing currently? How fast will it be increasing 5 yr from now? 73. AIR POLLUTION According to the South Coast Air Quality Management District, the level of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in downtown Los Angeles is approximated by A(t)  0.03t 3(t  7)4  60.2

(0 t 7)

where A(t) is measured in pollutant standard index and t is measured in hours, with t  0 corresponding to 7 a.m.

9.6 THE CHAIN RULE

a. Find A(t). b. Find A(1), A(3), and A(4) and interpret your results. Source: Los Angeles Times

74. EFFECT OF LUXURY TAX ON CONSUMPTION Government economists of a developing country determined that the purchase of imported perfume is related to a proposed “luxury tax” by the formula N 1x 2  210,000  40x  0.02x2

10 x 2002

where N(x) measures the percentage of normal consumption of perfume when a “luxury tax” of x% is imposed on it. Find the rate of change of N(x) for taxes of 10%, 100%, and 150%. 75. PULSE RATE OF AN ATHLETE The pulse rate (the number of heartbeats/minute) of a long-distance runner t sec after leaving the starting line is given by P 1t2 

300212 t 2  2t  25 t  25

1t  02

Compute P(t). How fast is the athlete’s pulse rate increasing 10 sec, 60 sec, and 2 min into the run? What is her pulse rate 2 min into the run? 76. THURSTONE LEARNING MODEL Psychologist L. L. Thurstone suggested the following relationship between learning time T and the length of a list n: T  f 1n 2  An 1n  b

where A and b are constants that depend on the person and the task. a. Compute dT/dn and interpret your result. b. For a certain person and a certain task, suppose A  4 and b  4. Compute f (13) and f (29) and interpret your results.

S  t(x)  0.00075x 2  67.5

627

(75 x 350)

where x has the same meaning as before. What was the rate of change of the average speed of traffic flow at the beginning of 1999? What was the average speed of traffic flow at that time? Hint: S  t[ f (t)].

80. HOTEL OCCUPANCY RATES The occupancy rate of the allsuite Wonderland Hotel, located near an amusement park, is given by the function r 1t 2 

10 t 122

10 3 10 2 200 t  t  t  60 81 3 9

where t is measured in months, with t  0 corresponding to the beginning of January. Management has estimated that the monthly revenue (in thousands of dollars/month) is approximated by the function R 1r 2  

9 3 3 r  r2 5000 50

10 r 1002

where r is the occupancy rate. a. Find an expression that gives the rate of change of Wonderland’s occupancy rate with respect to time. b. Find an expression that gives the rate of change of Wonderland’s monthly revenue with respect to the occupancy rate. c. What is the rate of change of Wonderland’s monthly revenue with respect to time at the beginning of January? At the beginning of July? Hint: Use the chain rule to find R(r(0))r(0) and R(r(6))r(6).

81. EFFECT OF HOUSING STARTS ON JOBS The president of a major housing construction firm claims that the number of construction jobs created is given by N(x)  1.42x

77. OIL SPILLS In calm waters, the oil spilling from the ruptured hull of a grounded tanker spreads in all directions. Assuming that the area polluted is a circle and that its radius is increasing at a rate of 2 ft/sec, determine how fast the area is increasing when the radius of the circle is 40 ft.

where x denotes the number of housing starts. Suppose the number of housing starts in the next t mo is expected to be

78. ARTERIOSCLEROSIS Refer to Example 8, page 624. Suppose the radius of an individual’s artery is 1 cm and the thickness of the plaque (in centimeters) t yr from now is given by

million units/year. Find an expression that gives the rate at which the number of construction jobs will be created t mo from now. At what rate will construction jobs be created 1 yr from now?

h  t 1t 2 

0.5t 2 t 2  10

10 t 10 2

How fast will the arterial opening be decreasing 5 yr from now? 79. TRAFFIC FLOW Opened in the late 1950s, the Central Artery in downtown Boston was designed to move 75,000 vehicles a day. The number of vehicles moved per day is approximated by the function x  f (t)  6.25t 2  19.75t  74.75

(0 t 5)

where x is measured in thousands and t in decades, with t  0 corresponding to the beginning of 1959. Suppose the average speed of traffic flow in mph is given by

x 1t2 

7t 2  140t  700 3t 2  80t  550

82. DEMAND FOR PCS The quantity demanded per month, x, of a certain make of personal computer (PC) is related to the average unit price, p (in dollars), of PCs by the equation x  f 1 p2 

100 2810,000  p2 9

It is estimated that t mo from now, the average price of a PC will be given by p1t 2 

400 1  18 1t

 200

10 t 602

dollars. Find the rate at which the quantity demanded per month of the PCs will be changing 16 mo from now.

628

9 THE DERIVATIVE

83. DEMAND FOR WATCHES The demand equation for the Sicard wristwatch is given by 50  p x  f 1 p2  10 B p

86. If f is differentiable and c is a constant, then d 3 f 1cx 2 4  cf ¿1cx 2 dx

10 p 50 2

87. If f is differentiable, then f ¿1x 2 d 2f 1x 2  dx 22f 1x 2

where x (measured in units of a thousand) is the quantity demanded each week and p is the unit price in dollars. Find the rate of change of the quantity demanded of the wristwatches with respect to the unit price when the unit price is $25. 84. CRUISE SHIP BOOKINGS The management of Cruise World, operators of Caribbean luxury cruises, expects that the percentage of young adults booking passage on their cruises in the years ahead will rise dramatically. They have constructed the following model, which gives the percentage of young adult passengers in year t: t 2  2t  4 p  f 1t 2  50¢ 2 ≤ t  4t  8

1 d 1 Bf ¢ ≤R  f ¿ ¢ ≤ x x dx

89. In Section 9.4, we proved that d n 1x 2  nxn1 dx

10 t 5 2

Young adults normally pick shorter cruises and generally spend less on their passage. The following model gives an approximation of the average amount of money R (in dollars) spent per passenger on a cruise when the percentage of young adults is p: R 1 p 2  1000¢

88. If f is differentiable, then

p4 ≤ p2

Find the rate at which the price of the average passage will be changing 2 yr from now. In Exercises 85–88, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

85. If f and t are differentiable and h  f 폶 t, then h(x)  f [t(x)]t(x).

for the special case when n  2. Use the chain rule to show that d 1/n 1 1x 2  x1/n1 n dx

for any nonzero integer n, assuming that f(x)  x1/n is differentiable. Hint: Let f(x)  x1/n so that [ f (x)]n  x. Differentiate both sides with respect to x.

90. With the aid of Exercise 89, prove that d r 1x 2  rx r1 dx

for any rational number r. Hint: Let r  m/n, where m and n are integers, with n  0, and write x r  (x m)1/n.

9.6 Solutions to Self-Check Exercises 1. Rewriting, we have 1/2

f (x)  (2x  1) 2

Using the general power rule, we find f ¿ 1x 2  

d 12x2  1 2 1/2 dx

d 1  ¢ ≤ 12x2  1 2 3/2 12x2  1 2 2 dx 1 2 12x  1 2 3/2 14x 2 2 2x  12x2  1 2 3/2 

2. a. The life expectancy at birth of a female born at the beginning of 1980 is given by t(80)  50.02[1  1.09(80)]0.1  78.29

or approximately 78 yr. Similarly, the life expectancy at birth of a female born at the beginning of the year 2000 is given by t(100)  50.02[1  1.09(100)]0.1  80.04

or approximately 80 yr. b. The rate of change of the life expectancy at birth of a female born at any time t is given by t(t). Using the general power rule, we have t¿ 1t2  50.02

d 11  1.09t2 0.1 dt

 150.02 2 10.12 11  1.09t2 0.9

d 11  1.09t2 dt

 150.02 2 10.12 11.092 11  1.09t2 0.9  5.4521811  1.09t 2 0.9 

5.45218 11  1.09t2 0.9

9.6 THE CHAIN RULE

USING

TECHNOLOGY

629

Finding the Derivative of a Composite Function

EXAMPLE 1 Find the rate of change of f 1x2  1x11  0.02x2 2 3/2 when x  2.1. Solution

Using the numerical derivative operation of a graphing utility, we find f (2.1)  0.5821463392

or approximately 0.58 unit per unit change in x. (See Figure T1.) nDeriv(X^.5(1+.0 2X^2)^1.5, X, 2.1) .5821463392

FIGURE T1 The TI-83/84 numerical derivative screen for computing f (2.1)

APPLIED EXAMPLE 2 Amusement Park Attendance The management of AstroWorld (“The Amusement Park of the Future”) estimates that the total number of visitors (in thousands) to the amusement park t hours after opening time at 9 a.m. is given by

nDeriv((30X)/(2+ X^2)^.5,X,1.5) 6.848066034

N 1t2 

30t 22  t 2

What is the rate at which visitors are admitted to the amusement park at 10:30 a.m.? Solution

Using the numerical derivative operation of a graphing utility, we find N(1.5)  6.8481

FIGURE T2 The TI-83/84 numerical derivative screen for computing N(1.5)

or approximately 6848 visitors per hour. (See Figure T2.)

TECHNOLOGY EXERCISES In Exercises 1–6, use the numerical derivative operation to find the rate of change of f(x) at the given value of x. Give your answer accurate to four decimal places.

1. f 1x2  2x2  x4; x  0.5

2. f 1x2  x  21  x2; x  0.4

Source: Automotive News

3. f 1x2  x21  x2; x  0.2

8. ACCUMULATION YEARS People from their mid-40s to their mid-50s are in the prime investing years. Demographic studies of this type are of particular importance to financial institutions. The function

4. f 1x2  1x  2x2  4 2 3/2; x  1 5. f 1x2  6. f 1x2 

21  x2 x3  2

; x  1

x3

1  11  x 2

2 3/2

N(t)  34.4(1  0.32125t)0.15

;x3

7. WORLDWIDE PRODUCTION OF VEHICLES The worldwide production of vehicles between 1960 and 1990 is given by the function f 1t2  16.5 11  2.2t

where f(t) is measured in units of a million and t is measured in decades, with t  0 corresponding to the beginning of 1960. What was the rate of change of the worldwide production of vehicles at the beginning of 1970? At the beginning of 1980?

10 t 3 2

(0 t 12)

gives the projected number of people in this age group in the United States (in millions) in year t, where t  0 corresponds to the beginning of 1996. a. How large was this segment of the population projected to be at the beginning of 2005? b. How fast was this segment of the population growing at the beginning of 2005? Source: U.S. Census Bureau

630

9 THE DERIVATIVE

9.7 Differentiation of Exponential and Logarithmic Functions The Derivative of the Exponential Function To study the effects of budget deficit-reduction plans at different income levels, it is important to know the income distribution of American families. Based on data from the House Budget Committee, the House Ways and Means Committee, and the U.S. Census Bureau, the graph of f shown in Figure 48 gives the number of American families y (in millions) as a function of their annual income x (in thousands of dollars) in 1990.

FIGURE 48 The graph of f shows the number of families versus their annual income.

Source: House Budget Committee, House Ways and Means Committee, and U.S. Census Bureau

Millions of families

y 2 1.75 1.5 1.25 1 0.75 0.5 0.25

x

0

40 60 80 100 120 140 Thousands of dollars

20

Observe that the graph of f rises very quickly and then tapers off. From the graph of f, you can see that the bulk of American families earned less than $100,000 per year. In fact, 95% of U.S. families earned less than $102,358 per year in 1990. (We will refer to this model again in Using Technology at the end of this section.) To analyze mathematical models involving exponential and logarithmic functions in greater detail, we need to develop rules for computing the derivative of these functions. We begin by looking at the rule for computing the derivative of the exponential function. Rule 8: Derivative of the Exponential Function d x 1e 2  e x dx

Thus, the derivative of the exponential function with base e is equal to the function itself. To demonstrate the validity of this rule, we compute f ¿1x2  lim

f 1x  h2  f 1x2 h

hS0

 lim

hS0

 lim

e

 ex h

xh

e x 1e h  12

hS0

 e x lim hS0

h eh  1 h

Write e xh  e xe h and factor.

Why?

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

631

To evaluate lim hS0

TABLE 5 h

0.1 0.01 0.001 0.1 0.01 0.001

eh  1 h

1.0517 1.0050 1.0005 0.9516 0.9950 0.9995

eh  1 h

let’s refer to Table 5, which is constructed with the aid of a calculator. From the table, we see that lim hS0

eh  1 1 h

(Although a rigorous proof of this fact is possible, it is beyond the scope of this book. Also see Example 1, Using Technology, page 640.) Using this result, we conclude that f (x)  e x  1  e x

as we set out to show. EXAMPLE 1 Find the derivative of each of the following functions: a. f(x)  x 2e x

b. t(t)  (e t  2)3/2

Solution

a. The product rule gives d 2 x d x d 2 1x e 2  x 2 1e 2  e x 1x 2 dx dx dx  x 2e x  e x 12x2  xe x 1x  22

f ¿1x2 

(x2)

See page 16.

b. Using the general power rule, we find t ¿1t2 

3 t d 3 3 1e  2 2 1/2 1e t  22  1e t  2 2 1/2e t  e t 1e t  22 1/2 2 dt 2 2

Exploring with

TECHNOLOGY Consider the exponential function f(x)  b x (b  0, b  1). 1. Use the definition of the derivative of a function to show that f ¿1x2  b x # lim

hS0

bh  1 h

2. Use the result of part 1 to show that d x 2h  1 12 2  2 x # lim dx hS0 h d x 3h  1 13 2  3 x # lim dx hS0 h

3. Use the technique in Using Technology, page 640, to show that (to two decimal places) lim hS0

2h  1  0.69 h

and

lim hS0

3h  1  1.10 h

4. Conclude from the results of parts 2 and 3 that d x 12 2  10.6922 x and dx

d x 13 2  11.1023 x dx (continued)

632

9 THE DERIVATIVE

Thus, d x 1b 2  k # b x dx

where k is an appropriate constant. 5. The results of part 4 suggest that, for convenience, we pick the base b, where 2 b 3, so that k  1. This value of b is e  2.718281828. . . . Thus, d x 1e 2  e x dx

This is why we prefer to work with the exponential function f (x)  e x.

Applying the Chain Rule to Exponential Functions To enlarge the class of exponential functions to be differentiated, we appeal to the chain rule to obtain the following rule for differentiating composite functions of 2 the form h(x)  e f (x). An example of such a function is h(x)  ex 2x. Here, 2 f (x)  x  2x.

Rule 9: Chain Rule for Exponential Functions

If f(x) is a differentiable function, then d f 1x2 1e 2  e f 1x2f ¿1x2 dx

To see this, observe that if h(x)  t[ f(x)], where t(x)  e x, then by virtue of the chain rule, h(x)  t( f (x))f (x)  e f (x)f (x)

since t(x)  e x. As an aid to remembering the chain rule for exponential functions, observe that it has the following form: d f 1x2 1e 2  e f 1x2 # derivative of exponent dx 앖 Same 앖 –

–

EXAMPLE 2 Find the derivative of each of the following functions: b. y  e3x

a. f(x)  e2x

c. t(t)  e2t

2t

Solution

a. f ¿ 1x2  e 2 x b.

d 12x 2  e 2x # 2  2e 2x dx

dy d  e3x 13x 2  3e3x dx dx

c. t ¿1t2  e 2 t t # 2

d 2 12t 2  t 2  14t  12 e 2 t t dt

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

633

EXAMPLE 3 Differentiate the function y  xe2x. Solution

Using the product rule, followed by the chain rule, we find dy d 2x d x e  e2x 1x2 dx dx dx d  xe2x 12x2  e2x dx  2xe2x  e2x  e2x 11  2x2

Use the chain rule on the first term.

EXAMPLE 4 Differentiate the function t 1t2 

et . e t  et Solution Using the quotient rule, followed by the chain rule, we find 1e t  et 2

d t d 1e 2  e t 1e t  et 2 dt dt t ¿1t2  1e t  et 2 2 1e t  et 2et  e t 1et  et 2  1e t  et 2 2 2t e  1  e 2t  1  e0  1 1e t  et 2 2 2  t 1e  et 2 2

(x2)

See page 11.

EXAMPLE 5 In Section 3.3, we discussed some practical applications of the exponential function Q(t)  Q0 e kt where Q0 and k are positive constants and t  [0, ). A quantity Q(t) growing according to this law experiences exponential growth. Show that for a quantity Q(t) experiencing exponential growth, the rate of growth of the quantity Q(t) at any time t is directly proportional to the amount of the quantity present. Solution Using the chain rule for exponential functions, we compute the derivative Q of the function Q. Thus,

Q ¿1t2  Q0 e kt

d 1kt2 dt

 Q0e kt 1k2  kQ0e kt  kQ1t2

Q(t)  Q0 e kt

which is the desired conclusion.

The Derivative of ln x Let’s now turn our attention to the differentiation of logarithmic functions. Rule 10: Derivative of ln x d 1 ln 0 x 0  x dx

1x  02

634

9 THE DERIVATIVE

To derive Rule 10, suppose x  0 and write f (x)  ln x in the equivalent form x  e f (x)

Differentiating both sides of the equation with respect to x, we find, using the chain rule, 1  e f (x)  f (x)

from which we see that f ¿1x 2 

1

e f 1x2

or, since e f (x)  x, f ¿1x2 

1 x

as we set out to show. You are asked to prove the rule for the case x 0 in Exercise 85, page 639. EXAMPLE 6 Find the derivative of each function: ln x a. f(x)  x ln x b. t 1x 2  x Solution

a. Using the product rule, we obtain d d d 1x ln x2  x 1ln x 2  1ln x 2 1x2 dx dx dx 1  x a b  ln x  1  ln x x

f ¿1x2 

b. Using the quotient rule, we obtain x t ¿1x2 

1 d d x a b  ln x 1ln x2  1ln x2 1x2 x dx dx 1  ln x   x2 x2 x2

Explore & Discuss You can derive the formula for the derivative of f (x)  ln x directly from the definition of the derivative, as follows. 1. Show that f ¿1x 2  lim

f 1x  h2  f 1x 2

hS0

h

 lim ln a 1  hS0

h 1/h b x

2. Put m  x/h and note that m 씮  as h 씮 0. Then, f (x) can be written in the form f 1x 2  lim ln a 1  mS

1 m/x b m

3. Finally, use both the fact that the natural logarithmic function is continuous and the definition of the number e to show that f ¿ 1x 2 

1 1 m 1 ln c lim a 1  b d  x m x mS

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

635

The Chain Rule for Logarithmic Functions To enlarge the class of logarithmic functions to be differentiated, we appeal once again to the chain rule to obtain the following rule for differentiating composite functions of the form h(x)  ln f (x), where f(x) is assumed to be a positive differentiable function.

Rule 11: Chain Rule for Logarithmic Functions

If f(x) is a differentiable function, then f ¿1x2 d 3ln f 1x2 4  dx f 1x2

3 f 1x2  04

To see this, observe that h(x)  t[ f (x)], where t(x)  ln x (x  0). Since t(x)  1/x, we have, using the chain rule, h ¿1x2  t ¿1 f 1x2 2 f ¿1x2 f ¿1x2 1 f ¿1x2   f 1x2 f 1x2

Observe that in the special case f(x)  x, h(x)  ln x, so the derivative of h is, by Rule 10, given by h(x)  1/x. EXAMPLE 7 Find the derivative of the function f (x)  ln(x 2  1). Solution

Using Rule 11, we see immediately that d 2 1x  12 dx 2x f ¿1x2   2 2 x 1 x 1

When differentiating functions involving logarithms, the rules of logarithms may be used to advantage, as shown in Examples 8 and 9. EXAMPLE 8 Differentiate the function y  ln[(x 2  1)(x 3  2)6]. Solution

We first rewrite the given function using the properties of logarithms: y  ln[(x 2  1)(x 3  2)6]  ln(x 2  1)  ln(x 3  2)6  ln(x 2  1)  6 ln(x 3  2)

ln mn  ln m  ln n ln m n  n ln m

Differentiating and using Rule 11, we obtain d 2 d 1x  12 6 1x 3  22 dx dx y¿   x2  1 x3  2 

613x 2 2 2x 2x 18x 2    x2  1 x3  2 x2  1 x3  2

636

9 THE DERIVATIVE

Exploring with

TECHNOLOGY Use a graphing utility to plot the graphs of f(x)  ln x; its first derivative function, f (x)  1/x; and its second derivative function f (x)  1/x 2, using the same viewing window [0, 4]  [3, 3]. 1. What can you say about the graph of f ? 2. What can you say about the graph of f ?

EXAMPLE 9 Find the derivative of the function t(t)  ln(t 2et ). 2

Solution Here again, to save a lot of work, we first simplify the given expression using the properties of logarithms. We have

t(t)  ln(t 2et ) 2  ln t 2  ln et  2 ln t  t 2 2

Therefore, t ¿1t 2 

ln mn  ln m  ln n ln mn  n ln m and ln e  1

211  t 2 2 2  2t  t t

Examples 10 and 11 involve finding the rate of change of an exponential function. APPLIED EXAMPLE 10 Asset Depreciation An industrial asset is being depreciated at a rate so that its book value t years from now will be V(t)  50,000e0.4t

dollars. How fast will the book value of the asset be changing 3 years from now? Solution

The rate of change of the book value of the asset t years from now is d 0.4t e dt  50,000(0.4)e0.4t  20,000e0.4t

V(t)  50,000

Therefore, 3 years from now the book value of the asset will be changing at the rate of V(3)  20,000e0.4(3)  20,000e1.2  6023.88 —that is, decreasing at the rate of approximately $6024 per year. APPLIED EXAMPLE 11 Internet Usage According to the Internet Society, Internet connections are proliferating at an ever-increasing rate. The number of host computers (in millions) is estimated to be N(t)  3.45e0.64t

(0 t 6)

in year t (t  0 corresponds to the beginning of 1994). How fast was that number of host computers growing at the beginning of 1996? At the beginning of 1999? Source: Internet Society Solution

The rate of growth of host computers at time t is given by N(t)  (3.45)(0.64)e0.64t  2.208e0.64t

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

637

In particular, the rate of growth of host computers at the beginning of 1996 is given by N(2)  2.208e0.64(2)  7.94138

or approximately 7.94 million computers per year. The rate of growth of host computers at the beginning of 1999 is given by N(5)  2.208e0.64(5)  54.16783

or approximately 54.17 million computers per year.

9.7 Self-Check Exercises 1. Find the first and second derivatives of f (x)  xex.

Solutions to Self-Check Exercises 9.7 can be found on page 640.

2. Find an equation of the tangent line to the graph of f (x)  x ln(2 x  3) at the point (1, 0).

9.7 Concept Questions 1. State the rule for differentiating (a) f (x)  ex and (b) t(x)  e f (x), where f is a differentiable function. 2. Let f (x)  e kx. a. Compute f (x). b. Use the result to deduce the sign of f  for the case k  0 and the case k 0.

3. State the rule for differentiating (a) f (x)  ln앚 x 앚 (x  0), and t(x)  ln f (x) [ f (x)  0], where f is a differentiable function.

9.7 Exercises In Exercises 1–28, find the derivatives of the function.

1. f (x)  e 3x

2. f (x)  3e x

3. t(t)  et

4. f (x)  e2x

5. f (x)  e x  x

6. f (x)  2e x  x 2

7. f (x)  x e

3 x

9. f (x) 

2e x x

11. f(x)  3(e x  ex) 13. f(w) 

ew  1 ew

ex  1 ex  1

28. t(t) 

et 1  t2

In Exercises 29–32, find the second derivative of the function.

2 u

8. f (u)  u e

29. f(x)  e4x  2e 3x

30. f(t)  3e2t  5et

31. f(x)  2xe 3x

32. f(t)  t 2e2t

10. f(x) 

x ex

33. Find an equation of the tangent line to the graph of y  e 2x3 at the point 1 32, 12 .

12. f (x) 

e x  ex 2

34. Find an equation of the tangent line to the graph of y  ex at the point = 11, 1e 2 .

14. f (x) 

ex e 1

In Exercises 35–62, find the derivative of the function.

2

x

15. f(x)  2e 3x1

16. f (t)  4e 3t2

17. h(x)  ex

18. f (x)  e x

2

27. f (x) 

21

19. f (x)  3e1/x

20. f (x)  e1/(2x)

21. f (x)  (e x  1)25

22. f (x)  (4  e3x )3

23. f (x)  e1x

24. f(t)  e12t

25. f(x)  (x  1)e3x2

26. f (s)  (s2  1)es

35. f(x)  5 ln x

36. f(x)  ln 5x

37. f(x)  ln(x  1)

38. t(x)  ln(2x  1)

39. f(x)  ln x 8

40. h(t)  2 ln t 5

41. f(x)  ln 1x

42. f(x)  ln( 1x  1)

43. f(x)  ln 2

1 x2

45. f(x)  ln(4x 2  6x  3)

44. f(x)  ln

1 2x 3

638

9 THE DERIVATIVE

46. f (x)  ln(3x 2  2x  1) 47. f (x)  ln

2x x1

49. f (x)  x 2 ln x 51. f (x) 

48. f (x)  ln

x1 x1

50. f (x)  3x 2 ln 2x

2 ln x x

52. f (x) 

3 ln x x2

53. f (u)  ln(u  2)3

54. f (x)  ln(x 3  3)4

55. f (x)  2ln x

56. f(x)  2ln x  x

57. f (x)  (ln x)3

58. f (x)  2(ln x)3/2

59. f (x)  ln(x 3  1)

60. f(x)  ln 2x 2  4

61. f (x)  e x ln x

62. f (x)  e x ln 2x  3

In Exercises 63–66, find the second derivative of the function.

63. f (x)  ln 2x

64. f(x)  ln(x  5)

65. f (x)  ln(x  2)

66. f(x)  (ln x)2

2

67. Find an equation of the tangent line to the graph of y  x ln x at the point (1, 0). 68. Find an equation of the tangent line to the graph of y  ln x 2 at the point (2, ln 4). 69. PERCENTAGE OF POPULATION RELOCATING Based on data obtained from the Census Bureau, the manager of Plymouth Van Lines estimates that the percentage of the total population relocating in year t (t  0 corresponds to the year 1960) may be approximated by the formula P(t)  20.6e0.009t

(0 t 35)

Compute P(10), P(20), and P(30) and interpret your results. 70. ONLINE BANKING In a study prepared in 2000, the percentage of households using online banking was projected to be f(t)  1.5e 0.78t

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 2000. a. What was the projected percentage of households using online banking at the beginning of 2003? b. How fast was the projected percentage of households using online banking changing at the beginning of 2003? c. How fast was the rate of the projected percentage of households using online banking changing at the beginning of 2003? Hint: We want f (3). Why? Source: Online Banking Report

71. OVER-100 POPULATION Based on data obtained from the Census Bureau, the number of Americans over age 100 is expected to be P(t)  0.07e0.54t

(0 t 4)

where P(t) is measured in millions and t is measured in decades, with t  0 corresponding to the beginning of 2000. a. What was the population of Americans over age 100 at the beginning of 2000? What will it be at the beginning of 2030? b. How fast was the population of Americans over age 100 changing at the beginning of 2000? How fast will it be changing at the beginning of 2030? Source: U.S. Census Bureau

72. WORLD POPULATION GROWTH After its fastest rate of growth ever during the 1980s and 1990s, the rate of growth of world population is expected to slow dramatically in the 21st century. The function G(t)  1.58e0.213t gives the projected annual average percentage of population growth/decade in the tth decade, with t  1 corresponding to 2000. a. What will the projected annual average population growth rate be in 2020 (t  3)? b. How fast will the projected annual average population growth rate be changing in 2020? Source: U.S. Census Bureau

73. DEATH DUE TO STROKES Before 1950 little was known about strokes. By 1960, however, risk factors such as hypertension were identified. In recent years, CAT scans used as a diagnostic tool have helped prevent strokes. As a result, death due to strokes have fallen dramatically. The function N(t)  130.7e0.1155t  50 2

(0 t 6)

gives the number of deaths per 100,000 people from 1950 through 2010, where t is measured in decades, with t  0 corresponding to 1950. a. How many deaths due to strokes per 100,000 people were there in 1950? b. How fast was the number of deaths due to strokes per 100,000 people changing in 1950? In 1960? In 1970? In 1980? c. If the trend continues, how many deaths due to strokes per 100,000 people will there be in 2010? Source: American Heart Association, Centers for Disease Control, and National Institutes of Health.

74. AIR TRAVEL Air travel has been rising dramatically in the past 30 yr. In a study conducted in 2000, the FAA projected further exponential growth for air travel through 2010. The function f(t)  666e 0.0413t

(0 t 11)

gives the number of passengers (in millions) in year t, with t  0 corresponding to 2000. a. How many air passengers were there in 2000? What was the projected number of air passengers for 2005? b. What was the rate of change of the number of air passengers in 2005? Source: Federal Aviation Administration

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

75. BLOOD ALCOHOL LEVEL The percentage of alcohol in a person’s bloodstream t hr after drinking 8 fluid oz of whiskey is given by A(t)  0.23te0.4t

(0 t 12)

a. What is the percentage of alcohol in a person’s bloodstream after 12 hr? After 8 hr? b. How fast is the percentage of alcohol in a person’s bloodstream changing after 12 hr? After 8 hr? Source: Encyclopedia Britannica

76. THERMOMETER READINGS A thermometer is moved from inside a house out to the deck. Its temperature t min after it has been moved is given by T(t)  30  40e0.98t

a. What is the temperature inside the house? b. How fast is the reading on the thermometer changing 1 min after it has been taken out of the house? c. What is the outdoor temperature? Hint: Evaluate lim T (t). tS

77. SALES PROMOTION The Lady Bug, a women’s clothing chain store, found that t days after the end of a sales promotion the volume of sales was given by S(t)  20,000(1  e0.5t )

(0 t 5)

dollars. a. Find the rate of change of The Lady Bug’s sales volume when t  1, t  2, t  3, and t  4. b. After how many days will the sales volume drop below $27,400? 78. ENERGY CONSUMPTION OF APPLIANCES The average energy consumption of the typical refrigerator/freezer manufactured by York Industries is approximately C(t)  1486e0.073t  500

(0 t 20)

kilowatt-hours (kWh) per year, where t is measured in years, with t  0 corresponding to 1972. a. What was the average energy consumption of the York refrigerator/freezer at the beginning of 1972? b. Prove that the average energy consumption of the York refrigerator/freezer is decreasing over the years in question. c. All refrigerator/freezers manufactured as of January 1, 1990, must meet the 950-kWh/year maximum energyconsumption standard set by the National Appliance Conservation Act. Show that the York refrigerator/ freezer satisfies this requirement. 79. PRICE OF PERFUME The monthly demand for a certain brand of perfume is given by the demand equation p  100e0.0002x  150

639

where p denotes the retail unit price (in dollars) and x denotes the quantity (in 1-oz bottles) demanded. a. Find the rate of change of the price per bottle when x  1000 and when x  2000. b. What is the price per bottle when x  1000? When x  2000? 80. POLIO IMMUNIZATION Polio, a once-feared killer, declined markedly in the United States in the 1950s after Jonas Salk developed the inactivated polio vaccine and mass immunization of children took place. The number of polio cases in the United States from the beginning of 1959 to the beginning of 1963 is approximated by the function N(t)  5.3e 0.095t

20.85t

(0 t 4)

where N(t) gives the number of polio cases (in thousands) and t is measured in years with t  0 corresponding to the beginning of 1959. a. Show that the function N is decreasing over the time interval under consideration. b. How fast was the number of polio cases decreasing at the beginning of 1959? At the beginning of 1962? (Comment: Following the introduction of the oral vaccine developed by Dr. Albert B. Sabin in 1963, polio in the United States has, for all practical purposes, been eliminated.) 81. OIL USED TO FUEL PRODUCTIVITY A study on worldwide oil use was prepared for a major oil company. The study predicted that the amount of oil used to fuel productivity in a certain country is given by f(t)  1.5  1.8te1.2t

(0 t 4)

where f(t) denotes the number of barrels per $1000 of economic output and t is measured in decades (t  0 corresponds to 1965). Compute f (0), f (1), f (2), and f (3) and interpret your results. In Exercises 82–84, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

82. If f(x)  3x, then f (x)  x  3x1. 83. If f (x)  e ␲, then f (x)  e␲. 1 84. If f(x)  ln 5, then f (x)  . 5 85. Prove that

d 1 ln  x   (x  0) for the case x 0. dx x

86. Use the definition of the derivative to show that lim

x씮0

ln1x  12 x

1

640

9 THE DERIVATIVE

9.7 Solutions to Self-Check Exercises f (x) 

1. Using the product rule, we obtain f (x)  x

d x d x e  ex dx dx

x

 xex  ex  (1  x)ex

d d x (1  x) e  ex dx dx

 (1  x)(ex)  ex(1) x

 e

x

 xe

x

e

x

 (x  2)e

2. The slope of the tangent line to the graph of f at any point (x, f(x)) lying on the graph of f is given by f (x). Using the product rule, we find

d d (x) ln(2x  3)  ln(2x  3)  dx dx

xa

Using the product rule once again, we obtain f (x)  (1  x)

d [x ln(2x  3)] dx



2 b  ln(2x  3)  1 2x  3

2  ln(2x  3) 2x  3

In particular, the slope of the tangent line to the graph of f at the point (1, 0) is f (1) 

2  ln 1  2 2x  3

Therefore, using the point-slope form of the equation of a line, we see that a required equation is y  0  2(x  1) y  2x  2

USING

TECHNOLOGY

EXAMPLE 1 At the beginning of Section 9.7, we demonstrated via a table of values of (e h  1)/h for selected values of h the plausibility of the result lim hS0

eh  1 1 h

To obtain a visual confirmation of this result, we plot the graph of f 1x2 

ex  1 x

in the viewing window [1, 1]  [0, 2] (Figure T1). From the graph of f, we see that f(x) appears to approach 1 as x approaches 0. The numerical derivative function of a graphing utility will yield the derivative of an exponential or logarithmic function for any value of x, just as it did for algebraic functions.

FIGURE T1 The graph of f in the viewing window [1, 1]  [0, 2]

TECHNOLOGY EXERCISES In Exercises 1–6, use the numerical derivative operation to find the rate of change of f(x) at the given value of x. Give your answer accurate to four decimal places. 3 1/x

1. f (x)  x e

; x  1

2. f 1x 2  1 1x  12 3/2ex; x  0.5 3. f 1x 2  x3 2ln x; x  2

1x ln x ; x  3.2 4. f 1x 2  x1

5. f(x)  ex ln(2x  1); x  0.5 6. f 1x2 

e1x

ln1x 2  1 2

;x1

7. AN EXTINCTION SITUATION The number of saltwater crocodiles in a certain area of northern Australia is given by P 1t 2 

300e0.024t 5e0.024t  1

9.7 DIFFERENTIATION OF EXPONENTIAL AND LOGARITHMIC FUNCTIONS

a. How many crocodiles were in the population initially? b. Show that lim P 1t 2  0. tS

c. Plot the graph of P in the viewing window [0, 200]  [0, 70]. (Comment: This phenomenon is referred to as an extinction situation.) 8. INCOME OF AMERICAN FAMILIES Based on data, it is estimated that the number of American families y (in millions) who earned x thousand dollars in 1990 is related by the equation y  0.1584xe0.0000016x

0.00011x 0.04491x

3

2

(x  0)

a. Plot the graph of the equation in the viewing window [0, 150]  [0, 2]. b. How fast is y changing with respect to x when x  10? When x  50? Interpret your results. Source: House Budget Committee, House Ways and Means Committee, and U.S. Census Bureau

9. WORLD POPULATION GROWTH Based on data obtained in a study, the world population (in billions) is approximated by the function f 1t 2 

12 1  3.74914e1.42804t

10 t 42

where t is measured in half centuries, with t  0 corresponding to the beginning of 1950. a. Plot the graph of f in the viewing window [0, 5]  [0, 14]. b. How fast was the world population expected to increase at the beginning of 2000? Source: United Nations Population Division

10. LOAN AMORTIZATION The Sotos plan to secure a loan of $160,000 to purchase a house. They are considering a conventional 30-yr home mortgage at 9%/year on the unpaid balance. It can be shown that the Sotos will have an outstanding principal of B 1x 2 

160,00011.0075 360  1.0075 x 2 1.0075 360  1

dollars after making x monthly payments of $1287.40. a. Plot the graph of B(x), using the viewing window [0, 360]  [0, 160,000]. b. Compute B(0) and B(0) and interpret your results; compute B(180) and B(180) and interpret your results. 11. INCREASE IN JUVENILE OFFENDERS The number of youths aged 15 to 19 increased by 21% between 1994 and 2005, pushing up the crime rate. According to the National Council on Crime and Delinquency, the number of violent crime arrests of juveniles under age 18 in year t is given by f (t)  0.438t 2  9.002t  107

(0 t 13)

641

where f (t) is measured in thousands and t in years, with t  0 corresponding to 1989. According to the same source, if trends like inner-city drug use and wider availability of guns continues, then the number of violent crime arrests of juveniles under age 18 in year t is given by t 1t2  e

0.438t 2  9.002t  107 99.456e0.07824t

if 0 t 4 if 4 t 13

where t(t) is measured in thousands and t  0 corresponds to 1989. a. Compute f(11) and t(11) and interpret your results. b. Compute f (11) and t(11) and interpret your results. Source: National Council on Crime and Delinquency

12. INCREASING CROP YIELDS If left untreated on bean stems, aphids (small insects that suck plant juices) will multiply at an increasing rate during the summer months and reduce productivity and crop yield of cultivated crops. But if the aphids are treated in mid-June, the numbers decrease sharply to less than 100/bean stem, allowing for steep rises in crop yield. The function F 1t2  e

62e1.152t 349e1.3241t1.52

if 0 t 1.5 if 1.5 t 3

gives the number of aphids on a typical bean stem at time t, where t is measured in months, with t  0 corresponding to the beginning of May. a. How many aphids are there on a typical bean stem at the beginning of June (t  1)? At the beginning of July (t  2)? b. How fast is the population of aphids changing at the beginning of June? At the beginning of July? Source: The Random House Encyclopedia

13. WOMEN IN THE LABOR FORCE Based on data from the U.S. Census Bureau, the chief economist of Manpower, Inc., constructed the following formula giving the percentage of the total female population in the civilian labor force, P(t), at the beginning of the tth decade (t  0 corresponds to the year 1900): P 1t2 

74 0.166t0.04536t 2 0.0066t 3

1  2.6e

10 t 112

Assume that this trend continued for the rest of the 20th century. a. What percentage of the total female population was in the civilian labor force at the beginning of 2000? b. What was the growth rate of the percentage of the total female population in the civilian labor force at the beginning of 2000? Source: U.S. Census Bureau

642

9 THE DERIVATIVE

9.8 Marginal Functions in Economics Marginal analysis is the study of the rate of change of economic quantities. For example, an economist is not merely concerned with the value of an economy’s gross domestic product (GDP) at a given time but is equally concerned with the rate at which it is growing or declining. In the same vein, a manufacturer is not only interested in the total cost corresponding to a certain level of production of a commodity but also is interested in the rate of change of the total cost with respect to the level of production, and so on. Let’s begin with an example to explain the meaning of the adjective marginal, as used by economists.

Cost Functions APPLIED EXAMPLE 1 Rate of Change of Cost Functions Suppose the total cost in dollars incurred each week by Polaraire for manufacturing x refrigerators is given by the total cost function C(x)  8000  200x  0.2x2

(0 x 400)

a. What is the actual cost incurred for manufacturing the 251st refrigerator? b. Find the rate of change of the total cost function with respect to x when x  250. c. Compare the results obtained in parts (a) and (b). Solution

a. The actual cost incurred in producing the 251st refrigerator is the difference between the total cost incurred in producing the first 251 refrigerators and the total cost of producing the first 250 refrigerators: C12512  C12502  38000  20012512  0.212512 2 4  38000  20012502  0.212502 2 4  45,599.8  45,500  99.80

or $99.80. b. The rate of change of the total cost function C with respect to x is given by the derivative of C—that is, C(x)  200  0.4x. Thus, when the level of production is 250 refrigerators, the rate of change of the total cost with respect to x is given by C ¿12502  200  0.412502  100

or $100. c. From the solution to part (a), we know that the actual cost for producing the 251st refrigerator is $99.80. This answer is very closely approximated by the answer to part (b), $100. To see why this is so, observe that the difference C(251)  C(250) may be written in the form C 12512  C 12502 1



C 1250  12  C 12502 1



C 1250  h2  C 12502 h

where h  1. In other words, the difference C(251)  C(250) is precisely the average rate of change of the total cost function C over the interval [250, 251], or, equivalently, the slope of the secant line through the points (250, 45,500)

9.8 MARGINAL FUNCTIONS IN ECONOMICS

643

and (251, 45,599.8). However, the number C(250)  100 is the instantaneous rate of change of the total cost function C at x  250, or, equivalently, the slope of the tangent line to the graph of C at x  250. Now when h is small, the average rate of change of the function C is a good approximation to the instantaneous rate of change of the function C, or, equivalently, the slope of the secant line through the points in question is a good approximation to the slope of the tangent line through the point in question. Thus, we may expect C 12512  C 12502 

C 12512  C 12502

 lim

hS0



C 1250  h2  C 12502

1 C 1250  h2  C 12502 h

(h small)

h  C ¿12502

which is precisely the case in this example. The actual cost incurred in producing an additional unit of a certain commodity given that a plant is already at a certain level of operation is called the marginal cost. Knowing this cost is very important to management. As we saw in Example 1, the marginal cost is approximated by the rate of change of the total cost function evaluated at the appropriate point. For this reason, economists have defined the marginal cost function to be the derivative of the corresponding total cost function. In other words, if C is a total cost function, then the marginal cost function is defined to be its derivative C. Thus, the adjective marginal is synonymous with derivative of. APPLIED EXAMPLE 2 Marginal Cost Functions A subsidiary of Elektra Electronics manufactures a portable DVD player. Management determined that the daily total cost of producing these DVD players (in dollars) is given by C(x)  0.0001x 3  0.08x 2  40x  5000

where x stands for the number of DVD players produced. a. Find the marginal cost function. b. What is the marginal cost when x  200, 300, 400, and 600? c. Interpret your results. Solution

a. The marginal cost function C is given by the derivative of the total cost function C. Thus, C(x)  0.0003x 2  0.16x  40

b. The marginal cost when x  200, 300, 400, and 600 is given by C ¿12002 C ¿13002 C ¿14002 C ¿16002

 0.000312002 2  0.000313002 2  0.000314002 2  0.000316002 2

   

0.1612002 0.1613002 0.1614002 0.1616002

   

40 40 40 40

   

20 19 24 52

or $20/unit, $19/unit, $24/unit, and $52/unit, respectively. c. From the results of part (b), we see that Elektra’s actual cost for producing the 201st DVD player is approximately $20. The actual cost incurred for producing one additional DVD player when the level of production is already 300

644

9 THE DERIVATIVE

players is approximately $19, and so on. Observe that when the level of production is already 600 units, the actual cost of producing one additional unit is approximately $52. The higher cost for producing this additional unit when the level of production is 600 units may be the result of several factors, among them excessive costs incurred because of overtime or higher maintenance, production breakdown caused by greater stress and strain on the equipment, and so on. The graph of the total cost function appears in Figure 49.

y ($)

30,000 20,000

y = C(x)

10,000 x 100

300

500

700

FIGURE 49 The cost of producing x DVD players is given by C(x).

Average Cost Functions Let’s now introduce another marginal concept closely related to the marginal cost. Let C(x) denote the total cost incurred in producing x units of a certain commodity. Then the average cost of producing x units of the commodity is obtained by dividing the total production cost by the number of units produced. This leads to the following definition:

Average Cost Function

Suppose C(x) is a total cost function. Then the average cost function, denoted by C (x) (read “C bar of x”), is C 1x2

(13)

x

The derivative C¿ (x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced. APPLIED EXAMPLE 3 Marginal Average Cost Functions The total cost of producing x units of a certain commodity is given by C(x)  400  20x

dollars. a. Find the average cost function C. b. Find the marginal average cost function C¿ . c. What are the economic implications of your results? Solution

a. The average cost function is given by 400  20x x x 400  20  x

C 1x2 

C1x2



b. The marginal average cost function is C ¿1x2  

400 x2

c. Since the marginal average cost function is negative for all admissible values of x, the rate of change of the average cost function is negative for all x  0;

9.8 MARGINAL FUNCTIONS IN ECONOMICS

that is,  C(x) decreases as x increases. However, the graph of  C always lies above the horizontal line y  20, but it approaches the line since

y ($) 100

60

645

lim C 1x2  lim a20 

400 y = C(x) = 20 + x

xS

y = 20

20

x 20

60

100

FIGURE 50

xS

400 b  20 x

(x) appears in Figure 50. This result is A sketch of the graph of the function C fully expected if we consider the economic implications. Note that as the level of production increases, the fixed cost per unit of production, represented by the term (400/x), drops steadily. The average cost approaches the constant unit of production, which is $20 in this case.

As the level of production increases, the average cost approaches $20.

APPLIED EXAMPLE 4 Marginal Average Cost Functions Once again consider the subsidiary of Elektra Electronics. The daily total cost for producing its portable DVD players is given by C(x)  0.0001x 3  0.08x 2  40x  5000

dollars, where x stands for the number of DVD players produced (see Example 2). a. Find the average cost function C. b. Find the marginal average cost function C¿ . Compute C¿ C (500). c. Sketch the graph of the function C and interpret the results obtained in parts (a) and (b). Solution

a. The average cost function is given by C 1x2 

C 1x2 x

 0.0001x2  0.08x  40 

5000 x

b. The marginal average cost function is given by C ¿1x2  0.0002x  0.08 

5000 x2

Also, C ¿15002  0.000215002  0.08 

y ($) 100 80

y = C(x)

60 40 (500, 35)

20

x 200 400 600 800 1000 FIGURE 51 The average cost reaches a minimum of $35 when 500 DVD players are produced.

5000 0 15002 2

c. To sketch the graph of the function C, observe that if x is a small positive number, then C C(x)  0. Furthermore, C C(x) becomes arbitrarily large as x approaches zero from the right, since the term (5000/x) becomes arbitrarily large as x approaches zero. Next, the result C¿ C (500)  0 obtained in part (b) tells us that the tangent line to the graph of the function C is horizontal at the point (500, 35) on the graph. Finally, plotting the points on the graph corresponding to, say, x  100, 200, 300, . . . , 900, we obtain the sketch in Figure 51. As expected, the average cost drops as the level of production increases. But in this case, as opposed to the case in Example 3, the average cost reaches a minimum value of $35, corresponding to a production level of 500, and increases thereafter. This phenomenon is typical in situations where the marginal cost increases from some point on as production increases, as in Example 2. This situation is in contrast to that of Example 3, in which the marginal cost remains constant at any level of production.

646

9 THE DERIVATIVE

Exploring with

TECHNOLOGY Refer to Example 4. 1. Use a graphing utility to plot the graph of the average cost function C 1x 2  0.0001x2  0.08x  40 

5000 x

using the viewing window [0, 1000]  [0, 100]. Then, using ZOOM and TRACE, show that the lowest point on the graph of C is (500, 35). 2. Draw the tangent line to the graph of C (500, 35). What is its slope? Is this expected? 3. Plot the graph of the marginal average cost function C ¿ 1x 2  0.0002x  0.08 

5000 x2

using the viewing window [0, 2000]  [1, 1]. Then use ZOOM and TRACE to show that the zero of the function C¿ occurs at x  500. Verify this result using the root-finding capability of your graphing utility. Is this result compatible with that obtained in part 2? Explain your answer.

Revenue Functions Recall that a revenue function R(x) gives the revenue realized by a company from the sale of x units of a certain commodity. If the company charges p dollars per unit, then R(x)  px

(14)

However, the price that a company can command for the product depends on the market in which it operates. If the company is one of many—none of which is able to dictate the price of the commodity—then in this competitive market environment the price is determined by market equilibrium (see Section 2.6). On the other hand, if the company is the sole supplier of the product, then under this monopolistic situation it can manipulate the price of the commodity by controlling the supply. The unit selling price p of the commodity is related to the quantity x of the commodity demanded. This relationship between p and x is called a demand equation (see Section 2.6). Solving the demand equation for p in terms of x, we obtain the unit price function f. Thus, p  f (x)

and the revenue function R is given by R(x)  px  xf (x)

The marginal revenue gives the actual revenue realized from the sale of an additional unit of the commodity given that sales are already at a certain level. Following an argument parallel to that applied to the cost function in Example 1, you can convince yourself that the marginal revenue is approximated by R(x). Thus, we define the marginal revenue function to be R(x), where R is the revenue function. The derivative R of the function R measures the rate of change of the revenue function.

9.8 MARGINAL FUNCTIONS IN ECONOMICS

PORTFOLIO

647

Richard Mizak

K

roll Zolfo Cooper is one of the world’s leading restructuring firms and works with companies experiencing critical financial or operational problems. We are retained as interim management or advisors to assist in stabilizing, rehabilitating, and reorganizing the business, whether through performance improvement changes or Chapter 11 (bankruptcy) reorganization. We then make recommendations based on the financial analysis to the company’s senior management team and use the analysis to develop concrete action plans to help get the company back on track. As a Director at Kroll Zolfo Cooper, I use mathematics when I perform financial analysis on companies in financial distress and/or bankruptcy. At a large merchant power company we built a highly complex mathematical model to analyze the financial capabilities of the corporation and to project the company’s financial performance into the future. The model was used by the company to forecast performance and by the

lenders, investors, and other key stakeholders to determine whether or not to lend money, invest, and/or partner with the company. At a major jewelry manufacturer, we determined that the company was losing money on most of its smaller orders. We used our mathematical analysis to work with the company to eliminate a series of costly activities that were unimportant to the smaller customers, determined the true cost of handling smaller orders, revised their computer pricing models, improved the company’s pricing, and created incentives for customers to place larger orders. Almost immediately our financial analysis resulted in higher profitability for the department and higher overall sales results. While these are just a few examples, the bulk of the work performed in the financial world has its basis in the same mathematical principals taught in your college coursework.

© ImageState/Alamy

TITLE Director INSTITUTION Kroll Zolfo Cooper

APPLIED EXAMPLE 5 Marginal Revenue Functions Suppose the relationship between the unit price p in dollars and the quantity demanded x of the Acrosonic model F loudspeaker system is given by the equation p  0.02x  400

(0 x 20,000)

a. Find the revenue function R. b. Find the marginal revenue function R. c. Compute R(2000) and interpret your result. Solution

a. The revenue function R is given by R 1x 2  px  x 10.02x  4002  0.02x2  400x

10 x 20,0002

b. The marginal revenue function R is given by R(x)  0.04x  400 c.

R(2000)  0.04(2000)  400  320

Thus, the actual revenue to be realized from the sale of the 2001st loudspeaker system is approximately $320.

648

9 THE DERIVATIVE

Profit Functions Our final example of a marginal function involves the profit function. The profit function P is given by P(x)  R(x)  C(x)

(15)

where R and C are the revenue and cost functions and x is the number of units of a commodity produced and sold. The marginal profit function P(x) measures the rate of change of the profit function P and provides us with a good approximation of the actual profit or loss realized from the sale of the (x  1)st unit of the commodity (assuming the xth unit has been sold). APPLIED EXAMPLE 6 Marginal Profit Functions Refer to Example 5. Suppose the cost of producing x units of the Acrosonic model F loudspeaker is C(x)  100x  200,000 dollars.

a. b. c. d.

Find the profit function P. Find the marginal profit function P. Compute P(2000) and interpret your result. Sketch the graph of the profit function P.

Solution

a. From the solution to Example 5a, we have R(x)  0.02x 2  400x

Thousands of dollars

y

Thus, the required profit function P is given by P 1x2  R 1x2  C 1x2  10.02x2  400x2  1100x  200,0002  0.02x2  300x  200,000

1000 800 y = P(x)

600 400

b. The marginal profit function P is given by

200

P ¿1x2  0.04x  300

x – 200

2 4 6 8 10 12 14 16 Units of a thousand

FIGURE 52 The total profit made when x loudspeakers are produced is given by P(x).

c.

P ¿120002  0.04120002  300  220

Thus, the actual profit realized from the sale of the 2001st loudspeaker system is approximately $220. d. The graph of the profit function P appears in Figure 52.

9.8 Self-Check Exercises The weekly demand for Pulsar DVD recorders is given by the demand equation p  0.02x  300

(0 x 15,000)

where p denotes the wholesale unit price in dollars and x denotes the quantity demanded. The weekly total cost function associated with manufacturing these recorders is C(x)  0.000003x 3  0.04x 2  200x  70,000

dollars.

1. Find the revenue function R and the profit function P. 2. Find the marginal cost function C, the marginal revenue function R, and the marginal profit function P. 3. Find the marginal average cost function C . 4. Compute C(3000), R(3000), and P(3000) and interpret your results. Solutions to Self-Check Exercises 9.8 can be found on page 651.

9.8 MARGINAL FUNCTIONS IN ECONOMICS

649

9.8 Concept Question 1. Explain each term in your own words: a. Marginal cost function b. Average cost function

c. Marginal average cost function d. Marginal revenue function e. Marginal profit function

9.8 Exercises 1. PRODUCTION COSTS The graph of a typical total cost function C(x) associated with the manufacture of x units of a certain commodity is shown in the following figure. a. Explain why the function C is always increasing. b. As the level of production x increases, the cost/unit drops so that C(x) increases but at a slower pace. However, a level of production is soon reached at which the cost/unit begins to increase dramatically (due to a shortage of raw material, overtime, breakdown of machinery due to excessive stress and strain) so that C(x) continues to increase at a faster pace. Use the graph of C to find the approximate level of production x0 where this occurs.

3. MARGINAL COST The total weekly cost (in dollars) incurred by Lincoln Records in pressing x compact discs is C(x)  2000  2x  0.0001x 2

(0 x 6000)

a. What is the actual cost incurred in producing the 1001st and the 2001st disc? b. What is the marginal cost when x  1000 and 2000? 4. MARGINAL COST A division of Ditton Industries manufactures the Futura model microwave oven. The daily cost (in dollars) of producing these microwave ovens is C(x)  0.0002x 3  0.06x 2  120x  5000

where x stands for the number of units produced. a. What is the actual cost incurred in manufacturing the 101st oven? The 201st oven? The 301st oven? b. What is the marginal cost when x  100, 200, and 300?

y ($) y = C(x)

5. MARGINAL AVERAGE COST Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive model is x (thousands) 1 2 3 4 5 6 7 8

2. PRODUCTION COSTS The graph of a typical average cost function A(x)  C(x)/x, where C(x) is a total cost function associated with the manufacture of x units of a certain commodity is shown in the following figure. a. Explain in economic terms why A(x) is large if x is small and why A(x) is large if x is large. b. What is the significance of the numbers x0 and y0, the x- and y-coordinates of the lowest point on the graph of the function A?

C(x)  100x  200,000

dollars/year. a. Find the average cost function C C. b. Find the marginal average cost function C¿ C. c. What happens to C C(x) when x is very large? Interpret your results. 6. MARGINAL AVERAGE COST The management of ThermoMaster Company, whose Mexican subsidiary manufactures an indoor–outdoor thermometer, has estimated that the total weekly cost (in dollars) for producing x thermometers is C(x)  5000  2x

a. Find the average cost function C C. b. Find the marginal average cost function C¿ C. c. Interpret your results.

y ($) y = A(x)

7. Find the average cost function C and the marginal average cost function C C¿ associated with the total cost function C of Exercise 3.

y0

(x0, y0) x0

x

8. Find the average cost function C and the marginal average cost function C¿ C associated with the total cost function C of Exercise 4.

650

9 THE DERIVATIVE

9. MARGINAL REVENUE Williams Commuter Air Service realizes a monthly revenue of R(x)  8000x  100x 2

dollars when the price charged per passenger is x dollars. a. Find the marginal revenue R. b. Compute R(39), R(40), and R(41). c. Based on the results of part (b), what price should the airline charge in order to maximize their revenue? 10. MARGINAL REVENUE The management of Acrosonic plans to market the ElectroStat, an electrostatic speaker system. The marketing department has determined that the demand for these speakers is p  0.04x  800

(0 x 20,000)

where p denotes the speaker’s unit price (in dollars) and x denotes the quantity demanded. a. Find the revenue function R. b. Find the marginal revenue function R. c. Compute R(5000) and interpret your results. 11. MARGINAL PROFIT Refer to Exercise 10. Acrosonic’s production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker systems in the first year of production will be C(x)  200x  300,000

a. b. c. d.

Find the profit function P. Find the marginal profit function P. Compute P(5000) and P(8000). Sketch the graph of the profit function and interpret your results.

12. MARGINAL PROFIT Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting x apartments is P(x)  10x 2  1760x  50,000

a. What is the actual profit realized from renting the 51st unit, assuming that 50 units have already been rented? b. Compute the marginal profit when x  50 and compare your results with that obtained in part (a). 13. MARGINAL COST, REVENUE, AND PROFIT The weekly demand for the Pulsar 25 color LED television is p  600  0.05x

(0 x 12,000)

where p denotes the wholesale unit price in dollars and x denotes the quantity demanded. The weekly total cost function associated with manufacturing the Pulsar 25 is given by C(x)  0.000002x 3  0.03x 2  400x  80,000

where C(x) denotes the total cost incurred in producing x sets. a. Find the revenue function R and the profit function P. b. Find the marginal cost function C, the marginal revenue function R, and the marginal profit function P.

c. Compute C(2000), R(2000), and P(2000) and interpret your results. d. Sketch the graphs of the functions C, R, and P and interpret parts (b) and (c), using the graphs obtained. 14. MARGINAL COST, REVENUE, AND PROFIT Pulsar also manufactures a series of 20-in. flat-tube digital televisions. The quantity x of these sets demanded each week is related to the wholesale unit price p by the equation p  0.006x  180

The weekly total cost incurred by Pulsar for producing x sets is C(x)  0.000002x 3  0.02x 2  120x  60,000

dollars. Answer the questions in Exercise 13 for these data. 15. MARGINAL AVERAGE COST Find the average cost function C associated with the total cost function C of Exercise 13. a. What is the marginal average cost function C C¿ ? b. Compute C¿ (5000) and C¿ (10,000) and interpret your results. C c. Sketch the graph of C. 16. MARGINAL AVERAGE COST Find the average cost function C associated with the total cost function C of Exercise 14. a. What is the marginal average cost function C¿ ? b. Compute C C¿ (5000) and C C¿ (10,000) and interpret your results. 17. MARGINAL REVENUE The quantity of Sicard wristwatches demanded each month is related to the unit price by the equation p

50 0.01x2  1

10 x 202

where p is measured in dollars and x in units of a thousand. a. Find the revenue function R. b. Find the marginal revenue function R. c. Compute R(2) and interpret your result. 18. MARGINAL PROPENSITY TO CONSUME The consumption function of the U.S. economy from 1929 to 1941 is C(x)  0.712x  95.05

where C(x) is the personal consumption expenditure and x is the personal income, both measured in billions of dollars. Find the rate of change of consumption with respect to income, dC/dx. This quantity is called the marginal propensity to consume. 19. MARGINAL PROPENSITY TO CONSUME Refer to Exercise 18. Suppose a certain economy’s consumption function is C(x)  0.873x1.1  20.34

where C(x) and x are measured in billions of dollars. Find the marginal propensity to consume when x  10.

SUMMARY OF PRINCIPAL FORMULAS AND TERMS

20. MARGINAL PROPENSITY TO SAVE Suppose C(x) measures an economy’s personal consumption expenditure and x the personal income, both in billions of dollars. Then, S(x)  x  C(x)

Income minus consumption

measures the economy’s savings corresponding to an income of x billion dollars. Show that

651

22. Refer to Exercise 20. For the consumption function of Exercise 19, find the marginal propensity to save when x  10. In Exercises 23 and 24, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

23. If C is a differentiable total cost function, then the marginal average cost function is

dC dS 1 dx dx

The quantity dS/dx is called the marginal propensity to save. 21. Refer to Exercise 20. For the consumption function of Exercise 18, find the marginal propensity to save.

C ¿1x2 

xC ¿ 1x 2  C 1x 2 x2

24. If the marginal profit function is positive at x  a, then it makes sense to decrease the level of production.

9.8 Solutions to Self-Check Exercises 1. R 1x 2  px

 x10.02x  300 2

 0.02x2  300x

P 1x 2  R 1x2  C 1x2

Therefore, the marginal average cost function is C ¿1x 2  0.000006x  0.04 

10 x 15,0002

C ¿ 130002  0.000009130002 2  0.0813000 2  200

 10.000003x3  0.04x2  200x  70,000 2

 41

 0.000003x3  0.02x2  100x  70,000

2. C¿ 1x 2  0.000009x2  0.08x  200

That is, when the level of production is already 3000 recorders, the actual cost of producing one additional recorder is approximately $41. Next,

R¿ 1x 2  0.04x  300

P¿ 1x 2  0.000009x2  0.04x  100

R(3000)  0.04(3000)  300  180

3. The average cost function is

That is, the actual revenue to be realized from selling the 3001st recorder is approximately $180. Finally,

C 1x2

P¿ 130002  0.00000913000 2 2  0.04130002  100

x 0.000003x  0.04x  200x  70,000 x 3



x2

4. Using the results from Self-Check Exercise 2, we find

 0.02x2  300x

C 1x 2 

70,000

2

 139

That is, the actual profit realized from selling the 3001st DVD recorder is approximately $139.

70,000  0.000003x  0.04x  200  x 2

CHAPTER 9 Summary of Principal Formulas and Terms FORMULAS 1. Average rate of change of f over [x, x  h] or Slope of the secant line to the graph of f through (x, f (x)) and (x  h, f (x  h)) or Difference quotient

f 1x  h 2  f 1x 2 h

652

9 THE DERIVATIVE

2. Instantaneous rate of change of f at (x, f (x)) or Slope of tangent line to the graph of f at (x, f(x)) at x or Derivative of f

lim

f 1x  h 2  f 1x 2 h

h씮0

3. Derivative of a constant

d (c)  0 dx

4. Power rule

d n (x )  nx n1 dx

5. Constant multiple rule

d [cf (x)]  cf (x) dx

6. Sum rule

d [ f (x) t(x)]  f (x) t(x) dx

7. Product rule

d [ f (x)t(x)]  f(x)t(x)  t(x) f (x) dx

(c, a constant)

8. Quotient rule

t1x 2 f ¿1x2  f 1x 2 t¿ 1x 2 d f 1x2 c d  dx t1x 2 3t1x 2 4 2

9. Chain rule

d t( f (x))  t( f (x))f (x) dx

10. General power rule

d [ f (x)]n  n[ f(x)]n1f (x) dx

11. Derivative of the exponential function

d x (e )  ex dx

12. Chain rule for exponential functions

du d u (e )  eu dx dx

13. Derivative of the logarithmic function

1 d ln  x   x dx

14. Chain rule for logarithmic functions

1 du d (ln u)  u dx dx C1x2

15. Average cost function

 C(x) 

16. Revenue function

R(x)  px

17. Profit function

P(x)  R(x)  C(x)

x

TERMS limit of a function (537) indeterminate form (540) limit of a function at infinity (543) right-hand limit of a function (555) left-hand limit of a function (555) continuity of a function at a number (556)

zero of a function (560) secant line (572) tangent line to the graph of f (572) differentiable function (580) second derivative of f (607) marginal cost (643)

marginal cost function (643) average cost (644) marginal average cost function (644) marginal revenue (646) marginal revenue function (646) marginal profit function (648)

REVIEW EXERCISES

653

CHAPTER 9 Concept Review Questions Fill in the blanks.

1. The statement lim f (x)  L means that there is a number x씮a

_____ such that the values of _____ can be made as close to _____ as we please by taking x sufficiently close to _____. 2. If lim f(x)  L and lim t(x)  M, then x씮a

x씮a

a. lim [ f(x)]r  _____, where r is a real number. x씮a

b. lim [ f(x) t(x)]  _____. x씮a

c. lim [ f(x)t(x)]  _____. x씮a

f 1x 2

d. lim t1x 2  _____ provided that _____. x씮a

3. a. The statement lim f (x)  L means that f (x) can be made x씮 arbitrarily close to _____ by taking _____ large enough. b. The statement lim f (x)  M means that f(x) can be x씮 made arbitrarily close to _____ by taking x to be _____ and sufficiently large in _____ value. 4. a. The statement lim f (x)  L is similar to the statement x씮a lim f(x)  L, but here x is required to lie to the _____ x씮a of a. b. The statement lim f (x)  L is similar to the statement x씮a lim f(x)  L, but here x is required to lie to the _____ x씮a of a. c. lim f(x)  L if and only if both lim f (x)  _____ and x씮a x씮a lim f(x)  _____. x씮a

5. a. If f (a) is defined, lim f (x) exists and lim f(x)  f(a), x씮a x씮a then f is _____ at a. b. If f is not continuous at a, then it is _____ at a. c. f is continuous on an interval I if f is continuous at _____ number in the interval. 6. a. If f and t are continuous at a, then f t and ft are conf tinuous at _____. Also, t is continuous at _____, provided _____  0. b. A polynomial function is continuous _____. c. A rational function R  QP is continuous everywhere except at values of x where _____  0.

7. a. Suppose f is continuous on [a, b] and f(a) M f(b). Then the intermediate value theorem guarantees the existence of at least one number c in _____ such that _____. b. If f is continuous on [a, b] and f(a) f(b) 0, then there must be at least one solution of the equation _____ in the interval _____. 8. a. The tangent line at P(a, f(a)) to the graph of f is the line passing through P and having slope _____. b. If the slope of the tangent line at P(a, f(a)) is m, then an equation of the tangent line at P is _____. 9. a. The slope of the secant line passing through P (a, f(a)) and Q(a  h, f(a  h)) and the average rate of change of f over the interval [a, a  h] are both given by _____. b. The slope of the tangent line at P(a, f(a)) and the instantaneous rate of change of f at a are both given by _____. 10. a. If c is a constant, then dxd (c)  _____. b. The power rule states that if n is any real number, then d n dx (x )  _____. c. The constant multiple rule states that if c is a constant, then dxd [cf (x)]  _____. d. The sum rule states that dxd [ f (x) t(x)]  _____. 11. a. The product rule states that dxd [ f (x)t(x)]  _____. b. The quotient rule states that dxd [ f (x)/t(x)]  _____. 12. a. The chain rule states that if h(x)  t[ f (x)], then h(x)  _____. b. The general power rule states that if h(x)  [ f (x)]n, then h(x)  _____. 13. If C, R, P, and  C denote the total cost function, the total revenue function, the profit function, and the average cost function, respectively, then C denotes the _____ _____ function, R denotes the _____ _____ function, P denotes the _____ _____ function, and C  denotes the _____ _____ _____ function. 14. a. If t(x)  e f (x), where f is a differentiable function, then t(x)  _____. b. If t(x)  ln f (x), where f (x)  0 is differentiable, then t(x)  _____.

CHAPTER 9 Review Exercises In Exercises 1–14, find the indicated limits, if they exist.

1. lim (5x  3) x씮0

2. lim (x  1) 2

8. lim

x씮3

x씮1

3. lim (3x  4)(2x  1) 2

x씮1

4. lim

x씮3

6. lim

x씮2

x3 x4 x 2  2x  3 x  5x  6 2

5. lim

x씮2

x3 x 9

x씮3

2x  1

9. lim x씮1

10. lim

2x  1 x1

11. lim

12. lim

x1 x

13. lim

x씮1

2

7. lim 22x 3  5

4x  3

x씮

x씮

x씮

x1 x1x  1 2 x2 x2  1 3x 2  2x  4 2x 2  3x  1

654

9 THE DERIVATIVE

14. lim

x2 x1

x씮

b. Is f differentiable at x  a? Justify your answers. y

15. Sketch the graph of the function f(x) 

2x  3 if x 2 if x  2

x  3

and evaluate lim f(x), lim f(x), and lim f(x) at a  2, if x씮a

x씮a

x씮a

the limits exist. 16. Sketch the graph of the function f(x) 

4  x if x 2 if x  2

x  2

and evaluate lim f(x), lim f(x), and lim f(x) at a  2, if x씮a

x씮a

x씮a

the limits exist.

18. f(x) 

x  3 if x  2

0

if x  2 3x  4

4x 2  2x  2



1 if x  1 19. f(x)  1x  1 2 2 2 if x  1 20. f(x) 

In Exercises 27–74, find the derivative of the given function.

27. f(x)  3x 5  2x 4  3x 2  2x  1

In Exercises 17–20, determine all values of x for which each function is discontinuous.

17. t(x) 

x

a

2x

28. f(x)  4x 6  2x 4  3x 2  2 29. t(x)  2x3  3x1  2 30. f(t)  2t 2  3t 3  t1/2 31. t(t)  2t1/2  4t3/2  2 2 x

33. f(t)  t 

34. t(s)  2s2 

4 2  s 1s

35. h(x)  x 2 

36. f(x) 

x1 2x  1

37. t(t) 

38. h(t) 

1t 1t  1

39. f(x) 

x

21. Let y  x 2  2. a. Find the average rate of change of y with respect to x in the intervals [1, 2], [1, 1.5], and [1, 1.1]. b. Find the (instantaneous) rate of change of y at x  1.

2 3  2 t t

32. h(x)  x 2 

40. f(t) 

t 2t 2  1

41. f(x) 

2 x 3/2

t2 2t  1 2

1x  1 1x  1

x 2 1x 2  12 x2  1

22. Use the definition of the derivative to find the slope of the tangent line to the graph of the function f(x)  3x  5 at any point P(x, f(x)) on the graph.

42. f(x)  (2x 2  x)3

43. f(x)  (3x 3  2)8

44. h(x)  ( 1x  2)5

45. f(t)  22t 2  1

23. Use the definition of the derivative to find the slope of the tangent line to the graph of the function f(x)  1x at any point P(x, f(x)) on the graph.

3 46. t(t)  2 1  2t 3

47. s(t)  (3t 2  2t  5)2

48. f(x)  (2x 3  3x 2  1)3/2

24. Use the definition of the derivative to find the slope of the tangent line to the graph of the function f (x)  32x  5 at the point (2, 2) and determine an equation of the tangent line. 25. Use the definition of the derivative to find the slope of the tangent line to the graph of the function f (x)  x 2 at the point (2, 4) and determine an equation of the tangent line. 26. The graph of the function f is shown in the accompanying figure. a. Is f continuous at x  a? Why?

49. f(x)  xe2x

50. f(t)  1te t  t

51. t(t)  1te2t

52. t(x)  e x 21  x 2

53. y 

e 2x 1  e2x

55. f(x)  xex

2

54. f(x)  e2x

21

56. t(x)  (1  e2x)3/2

57. f(x)  x 2e x  e x

58. t(t)  t ln t

59. f(x)  ln(e x  1)

60. f(x) 

2

61. f(x) 

ln x x1

x ln x

62. y  (x  1)e x

REVIEW EXERCISES

63. y  ln(e 4x  3) 65. f(x) 

64. f(r) 

1r

93. Find the third derivative of the function 2

f(x) 

x2

ln x 1  ex

67. h(x)  a x 

re r

66. t(x)  1 2 b x

68. h(x) 

e 1  ln x 1x

12x 2  1 2 2

1 2x  1

What is its domain? 94. AVERAGE PRICE OF A COMMODITY The average cost (in dollars) of producing x units of a certain commodity is given by

69. h(t)  (t 2  t)4(2t 2) C(x)  20  

70. f (x)  (2x  1)3(x 2  x)2 71. t(x)  1x (x2  1)3 73. h(x) 

23x  2 4x  3

72. f (x)  74. f (t) 

x 2x  2 3

22t  1 1t  12 3

In Exercises 75–84, find the second derivative of the given function.

75. f (x)  2x 4  3x 3  2x 2  x  4 76. t(x)  1x 

1 1x

77. h(t) 

t t2  4 ex 1  ex

78. f (x)  xe2 x

79. h(x) 

80. f(x)  x ln x

81. y  ln(3x  1)

82. f(x)  (x 3  x  1)2

83. f (x)  22x 2  1

84. f(t)  t(t 2  1)3 1 85. Find h(0) if h(x)  t( f(x)), t(x)  x  , and f(x)  e x. x x1 , and f(x)  ln x. x1

87. Let f(x)  2x 3  3x 2  16x  3. a. Find the points on the graph of f at which the slope of the tangent line is equal to 4. b. Find the equation(s) of the tangent line(s) of part (a). 88. Let f (x)    4x  1. a. Find the points on the graph of f at which the slope of the tangent line is equal to 2. b. Find the equation(s) of the tangent line(s) of part (a). 1 3 3x

400 x

(x) and interpret your results. Evaluate lim C x씮

95. WORLDWIDE NETWORKED PCS The number of worldwide networked PCs (in millions) is given by N(t)  3.136t 2  3.954t  116.468

1 2 2x

89. Find an equation of the tangent line to the graph of y  24  x 2 at the point (1, 23). 90. Find an equation of the tangent line to the graph of y  x(x  1)5 at the point (1, 32). 91. Find an equation of the tangent line to the graph of y  e2x at the point (1, e2). 92. Find an equation of the tangent line to the graph of y  xex at the point (1, e1).

(0 t 9)

where t is measured in years, with t  0 corresponding to the beginning of 1991. a. How many worldwide networked PCs were there at the beginning of 1997? b. How fast was the number of worldwide networked PCs changing at the beginning of 1997? 96. ADULT OBESITY In the United States, the percentage of adults (age 20–74) classified as obese held steady through the 1960s and 1970s at around 14% but began to rise rapidly during the 1980s and 1990s. This rise in adult obesity coincided with the period when an increasing number of Americans began eating more sugar and fats. The function P(t)  0.01484t 2  0.446t  15

86. Find h(1) if h(x)  t( f (x)), t(x) 

655

(0 t 22)

gives the percentage of obese adults from 1978 (t  0) through the year 2000 (t  22). a. What percentage of adults were obese in 1978? In 2000? b. How fast was the percent of obese adults increasing in 1980 (t  2)? In 1998 (t  20)? Source: Journal of the American Medical Association

97. CABLE TV SUBSCRIBERS The number of subscribers to CNC Cable Television in the town of Randolph is approximated by the function N(x)  1000(1  2x)1/2

(1 x 30)

where N(x) denotes the number of subscribers to the service in the xth week. Find the rate of increase in the number of subscribers at the end of the 12th week. 98. COST OF WIRELESS PHONE CALLS As cell phone usage continues to soar, the airtime costs have dropped. The average price per minute of use (in cents) is projected to be f(t)  31.88(1  t)0.45

(0 t 6)

where t is measured in years and t  0 corresponds to the beginning of 1998. Compute f (t). How fast was the aver-

656

9 THE DERIVATIVE

age price/minute of use changing at the beginning of 2000? What was the average price/minute of use at the beginning of 2000?

DVDs is given by the total cost function

Source: Cellular Telecommunications Industry Association

a. What is the marginal cost when x  1000 and 2000? b. Find the average cost function  C and the marginal average cost function C .

99. MALE LIFE EXPECTANCY Suppose the life expectancy of a male at birth in a certain country is described by the function f(t)  46.9(1  1.09t)0.1

(0 t 150)

where t is measured in years, with t  0 corresponding to the beginning of 1900. How long can a male born at the beginning of 2000 in that country expect to live? What is the rate of change of the life expectancy of a male born in that country at the beginning of 2000? 100. DEMAND FOR CORDLESS PHONES The marketing department of Telecon has determined that the demand for their cordless phones obeys the relationship p  0.02x  600

(0 x 30,000)

where p denotes the phone’s unit price (in dollars) and x denotes the quantity demanded. a. Find the revenue function R. b. Find the marginal revenue function R. c. Compute R(10,000) and interpret your result. 101. COST OF PRODUCING DVDS The total weekly cost in dollars incurred by Herald Media Corp. in producing x

C(x)  2500  2.2x

(0 x 8000)

102. DEMAND FOR PHOTOCOPYING MACHINES The weekly demand for the LectroCopy photocopying machine is given by the demand equation p  2000  0.04x

(0 x 50,000)

where p denotes the wholesale unit price in dollars and x denotes the quantity demanded. The weekly total cost function for manufacturing these copiers is given by C(x)  0.000002x 3  0.02x 2  1000x  120,000 where C(x) denotes the total cost incurred in producing x units. a. Find the revenue function R, the profit function P, and the average cost function  C. b. Find the marginal cost function C, the marginal revenue function R, the marginal profit function P, and the marginal average cost function  C. c. Compute C(3000), R(3000), and P(3000). d. Compute C(5000) and C (8000) and interpret your results.

CHAPTER 9 Before Moving On . . . 1. Find lim

x씮1

x 2  4x  3 x 2  3x  2

4. Find the derivative of f(x)  2x3  3x1/3  5x2/3.

.

2. Let f (x) 



x2  1 x3

if 2 x 1 if 1 x 2

Find (a) lim  f(x) and (b) lim  f (x). Is f continuous at x씮1

x씮1

x  1? Explain. 3. Use the definition of the derivative to find the slope of the tangent line to the graph of x 2  3x  1 at the point (1, 1). What is an equation of the tangent line?

5. Differentiate t(x)  x 22x 2  1 . dy 2x  1 6. Find if y  2 . dx x x1 7. Find the first three derivatives of f(x) 

1 2x  1

.

8. Find the slope of the tangent line to the graph of f (x)  e1x. 9. Find the rate at which y  x ln(x2  1) is changing at x  1.

10

APPLICATIONS OF THE DERIVATIVE

T

HIS CHAPTER FURTHER EXPLORES the power of the derivative as a tool to help analyze the properties of

functions. The information obtained can then be used to accurately sketch graphs of functions. We also see how the

problems, including finding what level of production will yield a maximum profit for a company, finding what level of production will result in minimal cost to a company, finding the maximum velocity at which air is expelled when a person coughs, and a host of other problems.

© Lester Lefkowitz/Corbis

derivative is used in solving a large class of optimization

Should the subway fare from a certain suburb to a downtown metropolitan area be raised to generate more revenue for the city’s transit authority? In Example 3, p. 728, we will see how the optimal fare can be determined.

658

10 APPLICATIONS OF THE DERIVATIVE

10.1 Applications of the First Derivative Determining the Intervals Where a Function Is Increasing or Decreasing According to a study by the U.S. Department of Energy and the Shell Development Company, a typical car’s fuel economy as a function of its speed is described by the graph shown in Figure 1. Observe that the fuel economy f(x) in miles per gallon (mpg) improves as x, the vehicle’s speed in miles per hour (mph), increases from 0 to 42, and then drops as the speed increases beyond 42 mph. We use the terms increasing and decreasing to describe the behavior of a function as we move from left to right along its graph.

Miles per gallon

f (x)

FIGURE 1 A typical car’s fuel economy improves as the speed at which it is driven increases from 0 mph to 42 mph and drops at speeds greater than 42 mph.

35 30 25 20 15 10 5 0

0

10

20

30

40 50 Speed, mph

60

70

80

x

Source: U.S. Department of Energy and Shell Development Co.

More precisely, we have the following definitions. Increasing and Decreasing Functions

A function f is increasing on an interval (a, b) if for any two numbers x1 and x2 in (a, b), f(x1) f(x2) whenever x1 x2 (Figure 2a). A function f is decreasing on an interval (a, b) if for any two numbers x1 and x2 in (a, b), f(x1)  f(x2) whenever x1 x2 (Figure 2b). y

y

f (x2)

f (x1) f (x2)

f (x1) x a x1 x2 FIGURE 2

b

(a) f is increasing on (a, b).

x a x1 x2 b (b) f is decreasing on (a, b).

We say that f is increasing at a number c if there exists an interval (a, b) containing c such that f is increasing on (a, b). Similarly, we say that f is decreasing at a number c if there exists an interval (a, b) containing c such that f is decreasing on (a, b). Since the rate of change of a function at x  c is given by the derivative of the function at that number, the derivative lends itself naturally to being a tool for determining the intervals where a differentiable function is increasing or decreasing. Indeed, as we saw in Chapter 9, the derivative of a function at a number measures both

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

659

the slope of the tangent line to the graph of the function at the point on the graph of f corresponding to that number and the rate of change of the function at that number. In fact, at a number where the derivative is positive, the slope of the tangent line to the graph is positive, and the function is increasing. At a number where the derivative is negative, the slope of the tangent line to the graph is negative, and the function is decreasing (Figure 3). y

y

y = f (x) y = f (x)

c FIGURE 3

x

c

f ' (c) > 0

(a) f is increasing at x  c.

x f ' (c) < 0

(b) f is decreasing at x  c.

These observations lead to the following important theorem, which we state without proof.

THEOREM 1 a. If f (x)  0 for each value of x in an interval (a, b), then f is increasing on (a, b). b. If f (x) 0 for each value of x in an interval (a, b), then f is decreasing on (a, b). c. If f (x)  0 for each value of x in an interval (a, b), then f is constant on (a, b). y

EXAMPLE 1 Find the interval where the function f(x)  x 2 is increasing and the interval where it is decreasing. y = x2

4

Solution

The derivative of f(x)  x 2 is f (x)  2x. Since f (x)  2x  0 if x  0

2

and

f (x)  2x 0 if x 0

f is increasing on the interval (0, ) and decreasing on the interval (, 0) (Figure 4). x

–2

2

FIGURE 4 The graph of f falls on (, 0) where f(x) 0 and rises on (0, ) where f(x)  0.

Recall that the graph of a continuous function cannot have any breaks. As a consequence, a continuous function cannot change sign unless it equals zero for some value of x. (See Theorem 5, page 561.) This observation suggests the following procedure for determining the sign of the derivative f  of a function f, and hence the intervals where the function f is increasing and where it is decreasing. Determining the Intervals Where a Function Is Increasing or Decreasing

1. Find all values of x for which f (x)  0 or f  is discontinuous and identify the open intervals determined by these numbers. 2. Select a test number c in each interval found in step 1 and determine the sign of f (c) in that interval. a. If f (c)  0, f is increasing on that interval. b. If f (c) 0, f is decreasing on that interval.

660

10 APPLICATIONS OF THE DERIVATIVE

Explore & Discuss True or false? If f is continuous at c and f is increasing at c, then f (c)  0. Explain your answer.

Hint: Consider f (x)  x 3 and c  0.

EXAMPLE 2 Determine the intervals where the function f(x)  x 3  3x 2  24x  32 is increasing and where it is decreasing. Solution

1. The derivative of f is f (x)  3x 2  6x  24  3(x  2)(x  4)

(x2)

See page 17.

and it is continuous everywhere. The zeros of f (x) are x  2 and x  4, and these numbers divide the real line into the intervals (, 2), (2, 4), and (4, ). 2. To determine the sign of f (x) in the intervals (, 2), (2, 4), and (4, ), compute f (x) at a convenient test point in each interval. The results are shown in the following table. Interval

Test Point c

f (c)

Sign of f (x)

3 0 5

21 24 21

  

(, 2) (2, 4) (4, ) (x2)

See page 55.

Using these results, we obtain the sign diagram shown in Figure 5. We conclude that f is increasing on the intervals (, 2) and (4, ) and is decreasing on the interval (2, 4). Figure 6 shows the graph of f. y

60 y = x 3 – 3x 2 – 24x + 32 40 20 x –5

–3 –1

1

3

5

7

– 20 + + + 0 – – – – – 0 + + + + –2

0

– 40 x

4

FIGURE 5

Sign diagram for f 

FIGURE 6

The graph of f rises on (, 2), falls on (2, 4), and rises again on (4, ).

Note We will learn how to sketch these graphs later. However, if you are familiar with the use of a graphing utility, you may go ahead and verify each graph.

Exploring with

TECHNOLOGY Refer to Example 2. 1. Use a graphing utility to plot the graphs of f(x)  x 3  3x 2  24x  32 and its derivative function f (x)  3x 2  6x  24 using the viewing window [10, 10]  [50, 70].

2. By looking at the graph of f , determine the intervals where f (x)  0 and the intervals where f (x) 0. Next, look at the graph of f and determine the intervals where it is increasing and the intervals where it is decreasing. Describe the relationship. Is it what you expected?

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

661

EXAMPLE 3 Find the interval where the function f(x)  x2/3 is increasing and the interval where it is decreasing. Solution

1. The derivative of f is 2 2 f ¿1x2  x1/3  1/3 3 3x

The function f  is not defined at x  0, so f  is discontinuous there. It is continuous everywhere else. Furthermore, f  is not equal to zero anywhere. The number 0 divides the real line (the domain of f ) into the intervals (, 0) and (0, ). 2. Pick a test point (say, x  1) in the interval (, 0) and compute f ¿112  

2 3

Since f (1) 0, we see that f (x) 0 on (, 0). Next, we pick a test point (say, x  1) in the interval (0, ) and compute 2 3

f ¿112 

Since f (1)  0, we see that f (x)  0 on (0, ). Figure 7 shows these results in the form of a sign diagram. y

4 f ' is not defined at x = 0

2

y = x 2/3

– – – – – – – + + + + + + + x –1

0

1

FIGURE 7

x –4

2

–2

4

FIGURE 8

Sign diagram for f 

f decreases on (, 0) and increases on (0, ).

We conclude that f is decreasing on the interval (, 0) and increasing on the interval (0, ). The graph of f, shown in Figure 8, confirms these results. 1 EXAMPLE 4 Find the intervals where the function f 1x2  x  is increasing x and where it is decreasing. Solution

1. The derivative of f is f ¿1x2  1 

1 x2  1  x2 x2

(x2)

See page 22.

Since f  is not defined at x  0, it is discontinuous there. Furthermore, f (x) is equal to zero when x 2  1  0 or x  1. These values of x partition the domain of f  into the open intervals (, 1), (1, 0), (0, 1), and (1, ), where the sign of f  is different from zero. 2. To determine the sign of f  in each of these intervals, we compute f (x) at the test points x  2, 12, 12, and 2, respectively, obtaining f ¿122  34, f ¿112 2  3,

662

10 APPLICATIONS OF THE DERIVATIVE

f ¿1 12 2  3, and f ¿12 2  34. From the sign diagram for f  (Figure 9), we conclude that f is increasing on (, 1) and (1, ) and decreasing on (1, 0) and (0, 1). y 4 1 y=x+ x

2

x –4

f ' is not defined at x = 0

–2

2

4

–2 + + + + 0 – – –1

– – 0 + + + + 0

x

–4

1

FIGURE 9

FIGURE 10

f  does not change sign as we move across x  0.

The graph of f rises on (, 1), falls on (1, 0) and (0, 1), and rises again on (1, ).

The graph of f appears in Figure 10. Note that f  does not change sign as we move across x  0. (Compare this with Example 3.) Example 4 reminds us that we must not automatically conclude that the derivative f  must change sign when we move across a number where f  is discontinous or a zero of f .

Explore & Discuss Consider the profit function P associated with a certain commodity defined by P(x)  R(x)  C(x)

(x  0)

where R is the revenue function, C is the total cost function, and x is the number of units of the product produced and sold. 1. Find an expression for P(x). 2. Find relationships in terms of the derivatives of R and C so that a. P is increasing at x  a. b. P is decreasing at x  a. c. P is neither increasing nor decreasing at x  a.

Hint: Recall that the derivative of a function at x  a measures the rate of change of the function at that number.

3. Explain the results of part 2 in economic terms.

Exploring with

TECHNOLOGY 1. Use a graphing utility to sketch the graphs of f (x)  x 3  ax for a  2, 1, 0, 1, and 2, using the viewing window [2, 2]  [2, 2]. 2. Use the results of part 1 to guess at the values of a so that f is increasing on (, ). 3. Prove your conjecture analytically.

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

663

Relative Extrema Besides helping us determine where the graph of a function is increasing and decreasing, the first derivative may be used to help us locate certain “high points” and “low points” on the graph of f. Knowing these points is invaluable in sketching the graphs of functions and solving optimization problems. These “high points” and “low points” correspond to the relative (local) maxima and relative minima of a function. They are so called because they are the highest or the lowest points when compared with points nearby. The graph shown in Figure 11 gives the U.S. budget surplus (deficit) from 1996 (t  0) to 2007. The relative maxima and the relative minima of the function f are indicated on the graph. y Relative maximum

Billions of dollars

200 100 0 1

3

4

5

6

7

8

9

10 11

t (years)

– 100 – 200 Relative maximum

– 300 – 400

Relative minimum – 500 FIGURE 11 U.S. budget surplus (deficit) from 1996 to 2007

Source: Office of Management and Budget

More generally, we have the following definition: Relative Maximum

A function f has a relative maximum at x  c if there exists an open interval (a, b) containing c such that f(x) f(c) for all x in (a, b). Geometrically, this means that there is some interval containing x  c such that no point on the graph of f with its x-coordinate in that interval can lie above the point (c, f(c)); that is, f(c) is the largest value of f(x) in some interval around x  c. Figure 12 depicts the graph of a function f that has a relative maximum at x  x1 and another at x  x3. y (x 3 , f (x 3 )) y = f (x)

(x 1 , f (x 1 ))

I1

FIGURE 12

f has a relative maximum at x  x1 and at x  x3.

x1

I3 x2

x3

x4

x

Observe that all the points on the graph of f with x-coordinates in the interval I1 containing x1 (shown in blue) lie on or below the point (x1, f(x1)). This is also true for

664

10 APPLICATIONS OF THE DERIVATIVE

the point (x3, f(x3)) and the interval I3. Thus, even though there are points on the graph of f that are “higher” than the points (x1, f(x1)) and (x3, f(x3)), the latter points are “highest” relative to points in their respective neighborhoods (intervals). Points on the graph of a function f that are “highest” and “lowest” with respect to all points in the domain of f will be studied in Section 10.4. The definition of the relative minimum of a function parallels that of the relative maximum of a function. Relative Minimum

A function f has a relative minimum at x  c if there exists an open interval (a, b) containing c such that f(x)  f(c) for all x in (a, b). The graph of the function f, depicted in Figure 12, has a relative minimum at x  x2 and another at x  x4.

Finding the Relative Extrema We refer to the relative maximum and relative minimum of a function as the relative extrema of that function. As a first step in our quest to find the relative extrema of a function, we consider functions that have derivatives at such points. Suppose that f is a function that is differentiable in some interval (a, b) that contains a number c and that f has a relative maximum at x  c (Figure 13a). y

y f ' (x) > 0

f ' (c) = 0

f ' (x) > 0

f ' (x) < 0

f ' (c) = 0

f ' (x) < 0 x a

c

b

(a) f has a relative maximum at x  c.

FIGURE 13

x a

c

b

(b) f has a relative minimum at x  c.

x

Observe that the slope of the tangent line to the graph of f must change from positive to negative as we move across x  c from left to right. Therefore, the tangent line to the graph of f at the point (c, f(c)) must be horizontal; that is, f (c)  0 (Figure 13a). Using a similar argument, it may be shown that the derivative f  of a differentiable function f must also be equal to zero at x  c, where f has a relative minimum (Figure 13b). This analysis reveals an important characteristic of the relative extrema of a differentiable function f: At any number c where f has a relative extremum, f (c)  0.

f (0)  0, but f does not have a relative extremum at (0, 0).

Before we develop a procedure for finding such numbers, a few words of caution are in order. First, this result tells us that if a differentiable function f has a relative extremum at a number x  c, then f (c)  0. The converse of this statement—if f (c)  0 at x  c, then f must have a relative extremum at that number—is not true. Consider, for example, the function f(x)  x 3. Here, f (x)  3x 2, so f (0)  0. Yet, f has neither a relative maximum nor a relative minimum at x  0 (Figure 14).

y 6

y = x3

4 2 –2

2 –2 –4 –6

FIGURE 14

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

665

Second, our result assumes that the function is differentiable and thus has a derivative at a number that gives rise to a relative extremum. The functions f (x)   x  and t(x)  x 2/3 demonstrate that a relative extremum of a function may exist at a number at which the derivative does not exist. Both these functions fail to be differentiable at x  0, but each has a relative minimum there. Figure 15 shows the graphs of these functions. Note that the slopes of the tangent lines change from negative to positive as we move across x  0, just as in the case of a function that is differentiable at a value of x that gives rise to a relative minimum. y

y

4

4 y = x 

2

2

FIGURE 15 Each of these functions has a relative extremum at (0, 0), but the derivative does not exist there.

y = x 2/3

x –4

2

–2

x

4

–4

(a)

2

–2

4

(b)

We refer to a number in the domain of f that may give rise to a relative extremum as a critical number.

Critical Number of f

A critical number of a function f is any number x in the domain of f such that f (x)  0 or f (x) does not exist. Figure 16 depicts the graph of a function that has critical numbers at x  a, b, c, d, and e. Observe that f (x)  0 at x  a, b, and c. Next, since there is a corner at x  d, f (x) does not exist there. Finally, f (x) does not exist at x  e because the tangent line there is vertical. Also, observe that the critical numbers x  a, b, and d give rise to relative extrema of f, whereas the critical numbers x  c and x  e do not. y Corner

Horizontal tangents

Vertical tangent

FIGURE 16 Critical numbers of f

x a

b

c

d

e

Having defined what a critical number is, we can now state a formal procedure for finding the relative extrema of a continuous function that is differentiable everywhere except at isolated values of x. Incorporated into the procedure is the so-called first derivative test, which helps us determine whether a number gives rise to a relative maximum or a relative minimum of the function f.

666

10 APPLICATIONS OF THE DERIVATIVE

The First Derivative Test

Procedure for Finding Relative Extrema of a Continuous Function f

1. Determine the critical numbers of f. 2. Determine the sign of f (x) to the left and right of each critical number. a. If f (x) changes sign from positive to negative as we move across a critical number c, then f(c) is a relative maximum. b. If f (x) changes sign from negative to positive as we move across a critical number c, then f(c) is a relative minimum. c. If f (x) does not change sign as we move across a critical number c, then f(c) is not a relative extremum. y

EXAMPLE 5 Find the relative maxima and relative minima of the function f(x)  x 2.

y = x2

4

The derivative of f(x)  x 2 is given by f (x)  2x. Setting f (x)  0 yields x  0 as the only critical number of f. Since

Solution 2

f (x) 0 if x 0 x –2

2

FIGURE 17

f has a relative minimum at x  0.

– – – – – – – + + + + + + + 0

x

1

FIGURE 18

Sign diagram for f 

y

4 2

–2

FIGURE 19

The derivative of f is f ¿1x2  23 x1/3. As noted in Example 3, f  is not defined at x  0, is continuous everywhere else, and is not equal to zero in its domain. Thus, x  0 is the only critical number of the function f. The sign diagram obtained in Example 3 is reproduced in Figure 18. We can see that the sign of f (x) changes from negative to positive as we move across x  0 from left to right. Thus, an application of the first derivative test tells us that f(0)  0 is a relative minimum of f (Figure 19).

Solution

y = x 2/3 x

–4

we see that f (x) changes sign from negative to positive as we move across the critical number 0. Thus, we conclude that f (0)  0 is a relative minimum of f (Figure 17). EXAMPLE 6 Find the relative maxima and relative minima of the function f(x)  x 2/3 (see Example 3).

f ' is not defined at x = 0

–1

f (x)  0 if x  0

and

2

4

Explore & Discuss Recall that the average cost function C is defined by

f has a relative minimum at x  0.

C

C 1x2 x

where C(x) is the total cost function and x is the number of units of a commodity manufactured (see Section 9.8). 1. Show that C¿1x2 

C¿1x2  C1x2 x

1x  02

2. Use the result of part 1 to conclude that C is decreasing for values of x at which C(x) C(x). Find similar conditions for which C is increasing and for which C is constant. 3. Explain the results of part 2 in economic terms.

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

667

EXAMPLE 7 Find the relative maxima and relative minima of the function f(x)  x 3  3x 2  24x  32

The derivative of f is

Solution

f (x)  3x 2  6x  24  3(x  2)(x  4)

(x2)

See page 17.

and it is continuous everywhere. The zeros of f (x), x  2 and x  4, are the only critical numbers of the function f. The sign diagram for f  is shown in Figure 20. Examine the two critical numbers x  2 and x  4 for a relative extremum using the first derivative test and the sign diagram for f : 1. The critical number 2: Since the function f (x) changes sign from positive to negative as we move across x  2 from left to right, we conclude that a relative maximum of f occurs at x  2. The value of f(x) when x  2 is f(2)  (2)3  3(2)2  24(2)  32  60

2. The critical number 4: f (x) changes sign from negative to positive as we move across x  4 from left to right, so f(4)  48 is a relative minimum of f. The graph of f appears in Figure 21.

y

Relative maximum 60

y = x 3 – 3x 2 – 24x + 32 40 20 x –5

–3

–1

1

3

5

7

– 20 – 40 + + + 0 – – – – – 0 + + + + –2

Relative minimum

x

4

0

FIGURE 21

f has a relative maximum at x  2 and a relative minimum at x  4.

FIGURE 20

Sign diagram for f 

EXAMPLE 8 Find the relative maxima and the relative minima of the function f 1x2  x  Solution

1 x

The derivative of f is f ¿1x2  1 

1x  12 1x  12 1 x2  1   2 2 x x x2

Since f  is equal to zero at x  1 and x  1, these are critical numbers for the function f. Next, observe that f  is discontinuous at x  0. However, because f is not defined at that number, x  0 does not qualify as a critical number of f. Figure 22 shows the sign diagram for f .

668

10 APPLICATIONS OF THE DERIVATIVE y 4 2 Relative minimum –4

f ' is not defined at x = 0

–2

2

x

4

–2 – – 0 + + + +

+ + + + 0 – – –1

0

Relative maximum

x

–4

1

FIGURE 22

x  0 is not a critical number because f is not defined at x  0.

FIGURE 23 f 1x2  x 

1 x

Since f (x) changes sign from positive to negative as we move across x  1 from left to right, the first derivative test implies that f(1)  2 is a relative maximum of the function f. Next, f (x) changes sign from negative to positive as we move across x  1 from left to right, so f(1)  2 is a relative minimum of the function f. The graph of f appears in Figure 23. Note that this function has a relative maximum that lies below its relative minimum.

Exploring with

TECHNOLOGY Refer to Example 8. 1. Use a graphing utility to plot the graphs of f (x)  x  1/x and its derivative function f (x)  1  1/x 2, using the viewing window [4, 4]  [8, 8]. 2. By studying the graph of f , determine the critical numbers of f. Next, note the sign of f (x) immediately to the left and to the right of each critical number. What can you conclude about each critical number? Are your conclusions borne out by the graph of f ? + + + + + + + + + 0 _ _ _ _ _ _

x 0

1

EXAMPLE 9 Let f(x)  xex and find (a) the interval where f is increasing or decreasing and (b) the relative extrema of f.

FIGURE 24

Sign diagram for f 

y

Solution

1

The derivative f is d d x d (xex)  x (e )  ex (x) dx dx dx  xex(1)  ex  (1  x)ex

f (x) 

0.5 x 1

2

3

4

5

0.5 1 FIGURE 25

The graph of f(x)  xex is increasing on (, 1) and decreasing on (1, ).

Use the product rule.

Observe that f  is continuous everywhere. Next, setting f (x)  0 gives x  1 (remember that ex  0 for all values of x). Therefore, x  1 is the sole critical number of f . The sign diagram of f  is shown in Figure 24. From the sign diagram, we see that f is increasing on (, 1) and decreasing on (1, ). Also, using this diagram and the first derivative test, we see that the critical number x  1 gives rise to a relative maximum of f with value f (1)  e1  1/e. The graph of f shown in Figure 25 confirms our results.

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

APPLIED EXAMPLE 10 Profit Functions The profit function of Acrosonic Company is given by

y Thousands of dollars

669

1000 800

P(x)  0.02x 2  300x  200,000

y = P(x)

600

dollars, where x is the number of Acrosonic model F loudspeaker systems produced. Find where the function P is increasing and where it is decreasing.

400 200 x 16

2 4 6 8 10 12

– 200

Solution

The derivative P of the function P is

Units of a thousand

P(x)  0.04x  300  0.04(x  7500)

FIGURE 26 The profit function is increasing on (0, 7500) and decreasing on (7500, ).

Thus, P(x)  0 when x  7500. Furthermore, P(x)  0 for x in the interval (0, 7500), and P(x) 0 for x in the interval (7500, ). This means that the profit function P is increasing on (0, 7500) and decreasing on (7500, ) (Figure 26). APPLIED EXAMPLE 11 Crime Rates The number of major crimes committed in the city of Bronxville from 2001 to 2008 is approximated by the function

y 150 140 130

N(t)  0.1t 3  1.5t 2  100

y = N(t )

where N(t) denotes the number of crimes committed in year t, with t  0 corresponding to the beginning of 2001. Find where the function N is increasing and where it is decreasing.

120 110 100 t 1

2

3

4 5 Years

6

(0 t 7)

7

FIGURE 27 The number of crimes, N(t), is increasing over the 7-year interval.

Solution

The derivative N of the function N is N(t)  0.3t 2  3t  0.3t(t  10)

Since N(t)  0 for t in the interval (0, 7), the function N is increasing throughout that interval (Figure 27).

10.1 Self-Check Exercises 1. Find the intervals where the function f 1x2  23 x 3  x 2  12x  3 is increasing and the intervals where it is decreasing.

2. Find the relative extrema of f 1x2 

x2 . 1  x2

Solutions to Self-Check Exercises 10.1 can be found on page 675.

10.1 Concept Questions 1. Explain each of the following: a. f is increasing on an interval I. b. f is decreasing on an interval I.

4. a. What is a critical number of a function f ? b. Explain the role of a critical number in determining the relative extrema of a function.

2. Describe a procedure for determining where a function is increasing and where it is decreasing.

5. Describe the first derivative test and describe a procedure for finding the relative extrema of a function.

3. Explain each term: (a) relative maximum and (b) relative minimum.

670

10 APPLICATIONS OF THE DERIVATIVE

10.1 Exercises

1.

2.

y

y

x

x –5

–1

5

3.

1

4.

y

y 2 1

1 –2

x

x

–1

1

–2 –1

2

1 –1

10. AIRCRAFT STRUCTURAL INTEGRITY Among the important factors in determining the structural integrity of an aircraft is its age. Advancing age makes planes more likely to crack. The graph of the function f, shown in the accompanying figure, is referred to as a “bathtub curve” in the airline industry. It gives the fleet damage rate (damage due to corrosion, accident, and metal fatigue) of a typical fleet of commercial aircraft as a function of the number of years of service.

Fleet damage rate

In Exercises 1–8, you are given the graph of a function f. Determine the intervals where f is increasing, constant, or decreasing.

y

t (years in service)

2

2 4 6 8 10 12 14 16 18 20 22 24 Economic life objective

–2

5.

6.

y

y

1

1 x

–1

1

7.

x

2

–1

8.

y

1

y

1

a. Determine the interval where f is decreasing. This corresponds to the time period when the fleet damage rate is dropping as problems are found and corrected during the initial “shakedown” period. b. Determine the interval where f is constant. After the initial shakedown period, planes have few structural problems, and this is reflected by the fact that the function is constant on this interval. c. Determine the interval where f is increasing. Beyond the time period mentioned in part (b), the function is increasing—reflecting an increase in structural defects due mainly to metal fatigue. 11. Refer to the following figure:

x

x –1

1

1

–1

y

–1

–1

6 5

9. THE BOSTON MARATHON The graph of the function f shown in the accompanying figure gives the elevation of that part of the Boston Marathon course that includes the notorious Heartbreak Hill. Determine the intervals (stretches of the course) where the function f is increasing (the runner is laboring), where it is constant (the runner is taking a breather), and where it is decreasing (the runner is coasting). y (ft) Elevation

300 200 100 0

x (miles) 19.6

20.2 20.6 21.1

21.7 21.8

22.7

4 3 2 1 0

x 1

2

3

4

5

6

7

8

What is the sign of the following? a. f (2) b. f (x) in the interval (1, 3) c. f (4) d. f (x) in the interval (3, 6) e. f (7) f. f (x) in the interval (6, 9) g. f (x) in the interval (9, 12)

9 10 11 12

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

12. Refer to the following figure:

43.

44.

y

y

y x

2

6

671

4

1

5

x

4 3

–1 –1

2

–2

1 0

45.

x 1

2

3

4

5

6

7

8

1234

6

– 32

46.

y

y

9 10 11 12 3

a. What are the critical numbers of f. Give reasons for your answers. b. Draw the sign diagram for f . c. Find the relative extrema of f.

2

2

1 1

x 1

2 x –1

In Exercises 13–40, find the interval(s) where the function is increasing and the interval(s) where it is decreasing.

13. f(x)  3x  5

14. f(x)  4  5x

15. f(x)  x  3x

16. f(x)  2x  x  1

17. t(x)  x  x

18. f(x)  x 3  3x 2

2

y

2

3

19. t(x)  x 3  3x 2  1 21. f 1x2 

47.

20. f(x)  x 3  3x  4

2

1 3 x  3x 2  9x  20 3

1 x –3

22. f 1x2 

24. t(x)  x 4  2x 2  4

25. f 1x2 

1 x2

26. h 1x2 

27. h1t2 

t t1

28. t1t2 

29. f(x)  x 3/5

1

2

3

2t t 1

5 4 3 2 1

30. f(x)  x 2/3  5

35. f(x)  x 2ex

36. f(x)  ex / 2

33. f 1x2  216  x 2

(3, 29 ) x

–3

34. t 1x2  x1x  1

–2

(–3, – 29 )

2

ln x x

– 1 –1 –2 –3 –4 –5

1

2

3

38. f(x)  ln x 2

x2  1 x

40. h 1x2 

x2 x1

In Exercises 49–52, match the graph of the function with the graph of its derivative in (a)–(d).

In Exercises 41–48, you are given the graph of a function f. Determine the relative maxima and relative minima, if any.

41.

y

2

32. f(x)  (x  5)2/3

42.

y

50.

y

x

1 x

x 1

49.

y

y

1

–1

–1

48.

1 2x  3

31. f 1x2  1x  1

39. f 1x2 

–2

2 3 x  2x 2  6x  2 3

23. h(x)  x 4  4x 3  10

37. f(x) 

1

–1

1

x

672

10 APPLICATIONS OF THE DERIVATIVE

51.

52.

y

71. f 1x2 

y

x

x

x 1  x2

72. t 1x2 

x x2  1

73. f(x)  xex

74. f(x)  x 2ex

75. f(x)  x  ln x

76. f(x)  x2 ln x

77. A stone is thrown straight up from the roof of an 80-ft building. The distance (in feet) of the stone from the ground at any time t (in seconds) is given by h(t)  16 t 2  64t  80

(a)

(b)

y′

y′

When is the stone rising, and when is it falling? If the stone were to miss the building, when would it hit the ground? Sketch the graph of h. Hint: The stone is on the ground when h(t)  0.

x

(c)

x

(d)

y′

y′

78. PROFIT FUNCTIONS The Mexican subsidiary of ThermoMaster manufactures an indoor–outdoor thermometer. Management estimates that the profit (in dollars) realizable by the company for the manufacture and sale of x units of thermometers each week is P(x)  0.001x 2 8x  5000

Find the intervals where the profit function P is increasing and the intervals where P is decreasing. x

x

In Exercises 53–76, find the relative maxima and relative minima, if any, of each function.

53. f(x)  x 2  4x

54. t(x)  x 2  3x  8

55. h(t)  t 2  6t  6

1 56. f 1x2  x2  2x  4 2

57. f(x)  x 5/3

58. f(x)  x 2/3  2

59. t(x)  x 3  3x 2  4

60. f(x)  x 3  3x  6

1 61. f 1x2  x 4  x 2 2 1 62. h 1x2  x 4  3x 2  4x  8 2

65. t(x)  x 4  4x 3  8 66. f(x)  3x 4  2x 3  4

69. f 1x2  x 

68. h 1x2 

9 2 x

4000 70. t 1x2  2x   10 x 2

(0 x 25)

where x is measured in years, with x  0 corresponding to age 65 yr. Show that P is an increasing function of x on the interval (0, 25). What does your result tell you about the relationship between Alzheimer’s disease and age for the population that is age 65 yr and older? Source: Alzheimer’s Association

80. GROWTH OF MANAGED SERVICES Almost half of companies let other firms manage some of their Web operations—a practice called Web hosting. Managed services—monitoring a customer’s technology services—is the fastest growing part of Web hosting. Managed services sales are expected to grow in accordance with the function (0 t 6)

where f(t) is measured in billions of dollars and t is measured in years, with t  0 corresponding to 1999. a. Find the interval where f is increasing and the interval where f is decreasing. b. What does your result tell you about sales in managed services from 1999 through 2005?

64. F(t)  3t 5  20t 3  20

x1 x

P(x)  0.0726x 2  0.7902x  4.9623

f(t)  0.469t 2  0.758t  0.44

1 63. F 1x2  x 3  x 2  3x  4 3

67. t 1x2 

79. PREVALENCE OF ALZHEIMER’S PATIENTS Based on a study conducted in 1997, the percent of the U.S. population by age afflicted with Alzheimer’s disease is given by the function

x x1

Source: International Data Corp.

81. FLIGHT OF A ROCKET The height (in feet) attained by a rocket t sec into flight is given by the function 1 h 1t2   t 3  16t 2  33t  10 3

1t  0 2

When is the rocket rising, and when is it descending?

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

82. ENVIRONMENT OF FORESTS Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to record an index of environmental quality that measured progress and decline in the environmental quality of its forests. The index for the years 1998 through 2008 is approximated by the function 1 5 I 1t 2  t 3  t 2  80 3 2

10 t 102

where t  0 corresponds to 1998. Find the intervals where the function I is increasing and the intervals where it is decreasing. Interpret your results. 83. AVERAGE SPEED OF A HIGHWAY VEHICLE The average speed of a vehicle on a stretch of Route 134 between 6 a.m. and 10 a.m. on a typical weekday is approximated by the function f (t)  20t  40 1t  50

(0 t 4)

where f(t) is measured in miles per hour and t is measured in hours, with t  0 corresponding to 6 a.m. Find the interval where f is increasing and the interval where f is decreasing and interpret your results. 84. AVERAGE COST The average cost (in dollars) incurred by Lincoln Records each week in pressing x compact discs is given by C 1x 2  0.0001x  2 

2000 x

10 x 60002

Show that  C(x) is always decreasing over the interval (0, 6000). 85. WEB HOSTING Refer to Exercise 80. Sales in the Webhosting industry are projected to grow in accordance with the function f (t)  0.05t 3  0.56t 2  5.47t  7.5

(0 t 6)

where f (t) is measured in billions of dollars and t is measured in years, with t  0 corresponding to 1999. a. Find the interval where f is increasing and the interval where f is decreasing. Hint: Use the quadratic formula.

b. What does your result tell you about sales in the Webhosting industry from 1999 through 2005? Source: International Data Corp.

86. MEDICAL SCHOOL APPLICANTS According to a study from the American Medical Association, the number of medical school applicants from academic year 1997–1998 (t  0) through the academic year 2002–2003 is approximated by the function N(t)  0.0333t 3  0.47t 2  3.8t  47

(0 t 5)

where N(t) measured in thousands. a. Show that the number of medical school applicants had been declining over the period in question. Hint: Use the quadratic formula.

b. What was the largest number of medical school applicants in any one academic year for the period in question? In what academic year did that occur? Source: Journal of the American Medical Association

673

87. SALES OF FUNCTIONAL FOOD PRODUCTS The sales of functional food products—those that promise benefits beyond basic nutrition—have risen sharply in recent years. The sales (in billions of dollars) of foods and beverages with herbal and other additives is approximated by the function S(t)  0.46t 3  2.22t 2  6.21t  17.25

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 1997. Show that S is increasing on the interval [0, 4]. Hint: Use the quadratic formula. Source: Frost & Sullivan

88. PROJECTED RETIREMENT FUNDS Based on data from the Central Provident Fund of a certain country (a government agency similar to the Social Security Administration), the estimated cash in the fund in 2003 is given by A(t)  96.6t 4  403.6t 3  660.9t 2  250

(0 t 5)

where A(t) is measured in billions of dollars and t is measured in decades, with t  0 corresponding to 2003. Find the interval where A is increasing and the interval where A is decreasing and interpret your results. Hint: Use the quadratic formula.

89. SPENDING ON FIBER-OPTIC LINKS U.S. telephone company spending on fiber-optic links to homes and businesses from 2001 to 2006 is projected to be S(t)  2.315t 3  34.325t 2  1.32t  23

(0 t 5)

billion dollars in year t, where t is measured in years with t  0 corresponding to 2001. Show that S(t)  0 for all t in the interval [0, 5]. What conclusion can you draw from this result? Hint: Use the quadratic formula. Source: RHK Inc.

90. AIR POLLUTION According to the South Coast Air Quality Management District, the level of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in downtown Los Angeles is approximated by A(t)  0.03t 3(t  7)4  60.2

(0 t 7)

where A(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. At what time of day is the air pollution increasing, and at what time is it decreasing? 91. DRUG CONCENTRATION IN THE BLOOD The concentration (in milligrams/cubic centimeter) of a certain drug in a patient’s body t hr after injection is given by C 1t2 

t2 2t  1 3

10 t 42

When is the concentration of the drug increasing, and when is it decreasing?

674

10 APPLICATIONS OF THE DERIVATIVE

92. AGE OF DRIVERS IN CRASH FATALITIES The number of crash fatalities per 100,000 vehicle miles of travel (based on 1994 data) is approximated by the model f 1x 2 

15 0.08333x 2  1.91667x  1

10 x 11 2

where x is the age of the driver in years, with x  0 corresponding to age 16. Show that f is decreasing on (0, 11) and interpret your result. Source: National Highway Traffic Safety Administration

93. AIR POLLUTION The amount of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in the city of Long Beach is approximated by 136 A 1t 2   28 1  0.251t  4.5 2 2

10 t 11 2

where A(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. Find the intervals where A is increasing and where A is decreasing and interpret your results. Source: Los Angeles Times

94. PRISON OVERCROWDING The 1980s saw a trend toward oldfashioned punitive deterrence as opposed to the more liberal penal policies and community-based corrections popular in the 1960s and early 1970s. As a result, prisons became more crowded, and the gap between the number of people in prison and the prison capacity widened. The number of prisoners (in thousands) in federal and state prisons is approximated by the function N(t)  3.5t 2  26.7t  436.2

(0 t 10)

where t is measured in years, with t  0 corresponding to 1984. The number of inmates for which prisons were designed is given by C(t)  24.3t  365

(0 t 10)

where C(t) is measured in thousands and t has the same meaning as before. Show that the gap between the number of prisoners and the number for which the prisons were designed has been widening at any time t. Hint: First, write a function G that gives the gap between the number of prisoners and the number for which the prisons were designed at any time t. Then show that G(t)  0 for all values of t in the interval (0, 10). Source: U.S. Department of Justice

95. U.S. NURSING SHORTAGE The demand for nurses between 2000 and 2015 is estimated to be D(t)  0.0007t  0.0265t  2 2

(0 t 15)

where D(t) is measured in millions and t  0 corresponds to the year 2000. The supply of nurses over the same time period is estimated to be S(t)  0.0014t 2  0.0326t  1.9

(0 t 15)

where S(t) is also measured in millions. a. Find an expression G(t) giving the gap between the demand and supply of nurses over the period in question. b. Find the interval where G is decreasing and where it is increasing. Interpret your result. c. Find the relative extrema of G. Interpret your result. Source: U.S. Department of Health and Human Services

In Exercises 96–101, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

96. If f is decreasing on (a, b), then f (x) 0 for each x in (a, b). 97. If f and t are both increasing on (a, b), then f  t is increasing on (a, b). 98. If f and t are both decreasing on (a, b), then f  t is decreasing on (a, b). 99. If f(x) and t(x) are positive on (a, b) and both f and t are increasing on (a, b), then ft is increasing on (a, b). 100. If f (c)  0, then f has a relative maximum or a relative minimum at x  c. 101. If f has a relative minimum at x  c, then f (c)  0. 102. Using Theorem 1, verify that the linear function f (x)  mx  b is (a) increasing everywhere if m  0, (b) decreasing everywhere if m 0, and (c) constant if m  0. 103. Show that the function f(x)  x 3  x  1 has no relative extrema on (, ). 104. Let f(x)  x 2  ax  b. Determine the constants a and b so that f has a relative minimum at x  2 and the relative minimum value is 7. 105. Let f(x)  ax 3  6x 2  bx  4. Determine the constants a and b so that f has a relative minimum at x  1 and a relative maximum at x  2. 106. Let f 1x 2  e

3x 2x  4

if x 0 if x  0

a. Compute f (x) and show that it changes sign from negative to positive as we move across x  0. b. Show that f does not have a relative minimum at x  0. Does this contradict the first derivative test? Explain your answer. 107. Let f 1x 2  e

x 2  3 2

if x  0 if x  0

a. Compute f (x) and show that it changes sign from positive to negative as we move across x  0. b. Show that f does not have a relative maximum at x  0. Does this contradict the first derivative test? Explain your answer.

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

108. Let

675

110. Show that the cubic function 1 f 1x2  • x 2 x2

f(x)  ax 3  bx 2  cx  d

if x  0

has no relative extremum if and only if b 2  3ac 0.

if x 0

a. Compute f (x) and show that it does not change sign as we move across x  0. b. Show that f has a relative minimum at x  0. Does this contradict the first derivative test? Explain your answer.

111. Refer to Example 6, page 561. a. Show that f is increasing on the interval (0, 1). b. Show that f(0)  1 and f(1)  1 and use the result of part (a) together with the intermediate value theorem to conclude that there is exactly one root of f(x)  0 in (0, 1). 112. Show that the function

109. Show that the quadratic function f(x)  ax 2  bx  c

(a  0)

f 1x2 

(a  0)

has a relative extremum when x  b/2a. Also, show that the relative extremum is a relative maximum if a 0 and a relative minimum if a  0.

ax  b cx  d

does not have a relative extremum if ad  bc  0. What can you say about f if ad  bc  0?

10.1 Solutions to Self-Check Exercises 1. The derivative of f is f (x)  2x  2x  12  2(x  2)(x  3) 2

and it is continuous everywhere. The zeros of f (x) are x  2 and x  3. The sign diagram of f  is shown in the accompanying figure. We conclude that f is increasing on the intervals (, 2) and (3, ) and decreasing on the interval (2, 3).

and it is continuous everywhere except at x  1. Since f (x) is equal to zero at x  0, x  0 is a critical number of f. Next, observe that f (x) is discontinuous at x  1, but since these numbers are not in the domain of f, they do not qualify as critical numbers of f. Finally, from the sign diagram of f  shown in the accompanying figure, we conclude that f(0)  0 is a relative minimum of f. f ' is not defined at x = ± 1

+ + + + + 0 – – – – – – – – – – – –0 + + + + x –2

0

– – – – –

– – – 0+ + + + + + + + x

3 –1

0

1

2. The derivative of f is 11  x 2 2 f ¿1x2  

d 2 d 1x 2  x 2 11  x 2 2 dx dx 11  x 2 2 2

11  x 2 2 12x2  x 2 12x2

USING

11  x 2

2 2

TECHNOLOGY



2x 11  x 2 2 2

Using the First Derivative to Analyze a Function A graphing utility is an effective tool for analyzing the properties of functions. This is especially true when we also bring into play the power of calculus, as the following examples show. EXAMPLE 1 Let f(x)  2.4x 4  8.2x 3  2.7x 2  4x  1. a. Use a graphing utility to plot the graph of f. b. Find the intervals where f is increasing and the intervals where f is decreasing. c. Find the relative extrema of f. (continued)

676

10 APPLICATIONS OF THE DERIVATIVE

Solution

a. The graph of f in the viewing window [2, 4]  [10, 10] is shown in Figure T1. b. We compute f (x)  9.6x 3  24.6x 2  5.4x  4

FIGURE T1

and observe that f  is continuous everywhere, so the critical numbers of f occur at values of x where f (x)  0. To solve this last equation, observe that f (x) is a polynomial function of degree 3. The easiest way to solve the polynomial equation

The graph of f in the viewing window [2, 4]  [10, 10]

9.6x3  24.6x 2  5.4x  4  0

is to use the function on a graphing utility for solving polynomial equations. (Not all graphing utilities have this function.) You can also use TRACE and ZOOM, but this will not give the same accuracy without a much greater effort. We find x1  2.22564943249

x2  0.63272944121

x3  0.295878873696

Referring to Figure T1, we conclude that f is decreasing on (, 0.2959) and (0.6327, 2.2256) (correct to four decimal places) and f is increasing on (0.2959, 0.6327) and (2.2256, ). c. Using the evaluation function of a graphing utility, we find the value of f at each of the critical numbers found in part (b). Upon referring to Figure T1 once again, we see that f(x3)  0.2836 and f (x1)  8.2366 are relative minimum values of f and f(x2)  2.9194 is a relative maximum value of f. The equation f (x)  0 in Example 1 is a polynomial equation, and so it is easily solved using the function for solving polynomial equations. We could also solve the equation using the function for finding the roots of equations, but that would require much more work. For equations that are not polynomial equations, however, our only choice is to use the function for finding the roots of equations.

Note

If the derivative of a function is difficult to compute or simplify and we do not require great precision in the solution, we can find the relative extrema of the function using a combination of ZOOM and TRACE. This technique, which does not require the use of the derivative of f, is illustrated in the following example. EXAMPLE 2 Let f (x)  x 1/3(x 2  1)3/23x. a. Use a graphing utility to plot the graph of f. b. Find the relative extrema of f. Solution

a. The graph of f in the viewing window [4, 2]  [2, 1] is shown in Figure T2. b. From the graph of f in Figure T2, we see that f has relative maxima when x  2 and x  0.25 and a relative minimum when x  0.75. To obtain a better approximation of the first relative maximum, we zoom-in with the cursor at approximately

FIGURE T2 The graph of f in the viewing window [4, 2]  [2, 1]

10.1 APPLICATIONS OF THE FIRST DERIVATIVE

677

the point on the graph corresponding to x  2. Then, using TRACE, we see that a relative maximum occurs when x  1.76 with value y  1.01. Similarly, we find the other relative maximum where x  0.20 with value y  0.44. Repeating the procedure, we find the relative minimum at x  0.86 and y  1.07. You can also use the “minimum” and “maximum” functions of a graphing utility to find the relative extrema of the function. See the Web site for the procedure. Finally, we comment that if you have access to a computer and software such as Derive, Maple, or Mathematica, then symbolic differentiation will yield the derivative f (x) of any differentiable function. This software will also solve the equation f (x)  0 with ease. Thus, the use of a computer will simplify even more greatly the analysis of functions.

TECHNOLOGY EXERCISES In Exercises 1–4, find (a) the intervals where f is increasing and the intervals where f is decreasing and (b) the relative extrema of f. Express your answers accurate to four decimal places.

performed in physicians’ offices nationwide has been increasing over the years. The function f (t)  0.00447t 3  0.09864t 2  0.05192t  0.8 (0 t 15)

1. f (x)  3.4x 4  6.2x 3  1.8x 2  3x  2

gives the number of surgeries (in millions) performed in physicians’ offices in year t, with t  0 corresponding to the beginning of 1986. a. Plot the graph of f in the viewing window [0, 15]  [0, 10]. b. Prove that f is increasing on the interval [0, 15].

2. f(x)  1.8x 4  9.1x 3  5x  4 3. f (x)  2x 5  5x 3  8x 2  3x  2 4. f(x)  3x 5  4x 2  3x  1 In Exercises 5–8, use the ZOOM and TRACE features to find (a) the intervals where f is increasing and the intervals where f is decreasing and (b) the relative extrema of f. Express your answers accurate to two decimal places.

5. f (x)  (2x  1)1/3(x 2  1)2/3 6. f 1x 2  3x 2 1x 3  12 4 1/3 

Hint: Show that f  is positive on the interval.

Source: SMG Marketing Group

11. AIR POLLUTION The amount of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in the city of Long Beach, is approximated by

1 x

A1t2 

7. f (x)  ex 2x 2  1  x 3 2

f (t)  0.009417t 3  0.426571t 2  2.74894t  5.54 (0 t 6)

percent where t is measured in years, with t  0 corresponding to the beginning of 1994. a. Plot the graph of f in the viewing window [0, 6]  [0, 11]. b. Determine the interval where f is increasing and the interval where f is decreasing and interpret your result. Source: Federal Reserve

10. SURGERIES IN PHYSICIANS’ OFFICES Driven by technological advances and financial pressures, the number of surgeries

10 t 112

where A(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. When is the PSI increasing and when is it decreasing? At what time is the PSI highest, and what is its value at that time?

xex  x 3/2 8. f(x)  x2  1 9. MANUFACTURING CAPACITY Data show that the annual increase in manufacturing capacity between 1994 and 2000 is given by

136  28 1  0.251t  4.52 2

12. MODELING WITH DATA The following data gives the volume of cargo (in millions of tons) moved in the port of New York/New Jersey from 1991 through 2002. Year

1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002

Volume 13.5 14.1 14.6 15.6 15.1 14.9 15.7 16.9 18.8 20.8 21.9

24

a. Use CubicReg to find a third-degree polynomial regression model for the data. Let t  0 correspond to 1991. b. Plot the graph of V in the viewing window [0, 11]  [0, 25]. c. Where is V increasing? What does this tell us? d. Verify the result of part (c) analytically. Source: Port Authority of New York/New Jersey

678

10 APPLICATIONS OF THE DERIVATIVE

10.2 Applications of the Second Derivative Determining the Intervals of Concavity Consider the graphs shown in Figure 28, which give the estimated population of the world and of the United States through the year 2000. Both graphs are rising, indicating that both the U.S. population and the world population continued to increase through the year 2000. But observe that the graph in Figure 28a opens upward, whereas the graph in Figure 28b opens downward. What is the significance of this? To answer this question, let’s look at the slopes of the tangent lines to various points on each graph (Figure 29). y

y 6

300

5

250

4

200

3

150

2

100 x

1950 FIGURE 28

’60

’70

’80

’90

2000

x 1950

’60

’70

’80

’90

2000

(a) World population in billions (b) U.S. population in millions Source: U.S. Department of Commerce and Worldwatch Institute

In Figure 29a, we see that the slopes of the tangent lines to the graph are increasing as we move from left to right. Since the slope of the tangent line to the graph at a point on the graph measures the rate of change of the function at that point, we conclude that the world population was not only increasing through the year 2000 but was also increasing at an increasing pace. A similar analysis of Figure 29b reveals that the U.S. population was increasing, but at a decreasing pace.

FIGURE 29

(a) Slopes of tangent lines are increasing.

(b) Slopes of tangent lines are decreasing.

The shape of a curve can be described using the notion of concavity. Concavity of a Function f

Let the function f be differentiable on an interval (a, b). Then, 1. f is concave upward on (a, b) if f  is increasing on (a, b). 2. f is concave downward on (a, b) if f  is decreasing on (a, b).

679

10.2 APPLICATIONS OF THE SECOND DERIVATIVE y

y

x a FIGURE 30

x

b

(a) f is concave upward on (a, b).

a

b

(b) f is concave downward on (a, b).

Geometrically, a curve is concave upward if it lies above its tangent lines (Figure 30a). Similarly, a curve is concave downward if it lies below its tangent lines (Figure 30b). We also say that f is concave upward at a number c if there exists an interval (a, b) containing c in which f is concave upward. Similarly, we say that f is concave downward at a number c if there exists an interval (a, b) containing c in which f is concave downward. If a function f has a second derivative f , we can use f  to determine the intervals of concavity of the function. Recall that f (x) measures the rate of change of the slope f (x) of the tangent line to the graph of f at the point (x, f(x)). Thus, if f (x)  0 on an interval (a, b), then the slopes of the tangent lines to the graph of f are increasing on (a, b), and so f is concave upward on (a, b). Similarly, if f (x) 0 on (a, b), then f is concave downward on (a, b). These observations suggest the following theorem.

THEOREM 2 a. If f (x)  0 for each value of x in (a, b), then f is concave upward on (a, b). b. If f (x) 0 for each value of x in (a, b), then f is concave downward on (a, b).

The following procedure, based on the conclusions of Theorem 2, may be used to determine the intervals of concavity of a function.

Determining the Intervals of Concavity of f

1. Determine the values of x for which f  is zero or where f  is not defined, and identify the open intervals determined by these numbers. 2. Determine the sign of f  in each interval found in step 1. To do this, compute f (c), where c is any conveniently chosen test number in the interval. a. If f (c)  0, f is concave upward on that interval. b. If f (c) 0, f is concave downward on that interval.

EXAMPLE 1 Determine where the function f(x)  x 3  3x 2  24x  32 is concave upward and where it is concave downward.

680

10 APPLICATIONS OF THE DERIVATIVE

Solution

Here, f (x)  3x 2  6x  24 f (x)  6x  6  6(x  1)

and f  is defined everywhere. Setting f (x)  0 gives x  1. The sign diagram of f  appears in Figure 31. We conclude that f is concave downward on the interval (, 1) and is concave upward on the interval (1, ). Figure 32 shows the graph of f. y y = x 3 – 3x 2 – 24x + 32

32

x –5

– – – – – – – – –0+ + + + + 0

–3

–1

1

3

5

7

x

1

FIGURE 31

Sign diagram for f 

FIGURE 32 f is concave downward on (, 1) and concave upward on (1, ).

Exploring with

TECHNOLOGY Refer to Example 1.

f " is not defined at x = 0 – – – – – – – + + + + + + + x 0 FIGURE 33

1. Use a graphing utility to plot the graph of f(x)  x 3  3x 2  24x  32 and its second derivative f (x)  6x  6 using the viewing window [10, 10]  [80, 90]. 2. By studying the graph of f , determine the intervals where f (x)  0 and the intervals where f (x) 0. Next, look at the graph of f and determine the intervals where the graph of f is concave upward and the intervals where the graph of f is concave downward. Are these observations what you might have expected?

The sign diagram for f 

1 EXAMPLE 2 Determine the intervals where the function f 1x2  x  is concave x upward and where it is concave downward.

y 4 2

y=x+

1 x

2

4

Solution x

–4

–2 –2 –4

FIGURE 34 f is concave downward on (, 0) and concave upward on (0, ).

We have f ¿1x2  1  f –1x2 

1 x2

2 x3

We deduce from the sign diagram for f  (Figure 33) that the function f is concave downward on the interval (, 0) and concave upward on the interval (0, ). The graph of f is sketched in Figure 34.

681

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

Inflection Points Figure 35 shows the total sales S of a manufacturer of automobile air conditioners versus the amount of money x that the company spends on advertising its product.

Thousands of dollars

y 5000 y = S(x) 3000

(50, 2700)

1000 x

FIGURE 35

20

The graph of S has a point of inflection at (50, 2700).

40 60 80 100 Thousands of dollars

Notice that the graph of the continuous function y  S(x) changes concavity—from upward to downward—at the point (50, 2700). This point is called an inflection point of S. To understand the significance of this inflection point, observe that the total sales increase rather slowly at first, but as more money is spent on advertising, the total sales increase rapidly. This rapid increase reflects the effectiveness of the company’s ads. However, a point is soon reached after which any additional advertising expenditure results in increased sales but at a slower rate of increase. This point, commonly known as the point of diminishing returns, is the point of inflection of the function S. We will return to this example later. Let’s now state formally the definition of an inflection point. Inflection Point

A point on the graph of a continuous function f where the tangent line exists and where the concavity changes is called an inflection point. Observe that the graph of a function crosses its tangent line at a point of inflection (Figure 36). y

y Concave upward

Concave upward Concave downward FIGURE 36 At each point of inflection, the graph of a function crosses its tangent line.

y Concave downward Concave upward

Concave downward x

x

x

The following procedure may be used to find inflection points. Finding Inflection Points

1. Compute f (x). 2. Determine the numbers in the domain of f for which f (x)  0 or f (x) does not exist. 3. Determine the sign of f (x) to the left and right of each number c found in step 2. If there is a change in the sign of f (x) as we move across x  c, then (c, f(c)) is an inflection point of f.

682

10 APPLICATIONS OF THE DERIVATIVE

The numbers determined in step 2 are only candidates for the inflection points of f. For example, you can easily verify that f (0)  0 if f(x)  x 4, but a sketch of the graph of f will show that (0, 0) is not an inflection point of f. EXAMPLE 3 Find the point of inflection of the function f(x)  x 3. Solution

f (x)  3x 2 f (x)  6x

Observe that f  is continuous everywhere and is zero if x  0. The sign diagram of f  is shown in Figure 37. From this diagram, we see that f (x) changes sign as we move across x  0. Thus, the point (0, 0) is an inflection point of the function f (Figure 38). y y = x3 4 2 x –2

2 –2

– – – – – – – 0+ + + + + + +

x

–4

0 FIGURE 37

FIGURE 38

Sign diagram for f 

f has an inflection point at (0, 0).

EXAMPLE 4 Determine the intervals where the function f(x)  (x  1)5/3 is concave upward and where it is concave downward and find the inflection points of f. Solution

The first derivative of f is f ¿1x2 

5 1x  12 2/3 3

and the second derivative of f is f –1x2 

10 10 1x  1 2 1/3  9 91x  1 2 1/3

We see that f  is not defined at x  1. Furthermore, f (x) is not equal to zero anywhere. The sign diagram of f  is shown in Figure 39. From the sign diagram, we see that f is concave downward on (, 1) and concave upward on (1, ). Next, since x  1 does lie in the domain of f, our computations also reveal that the point (1, 0) is an inflection point of f (Figure 40). y 3 2 1 x – 3 – 2 –1

1

2

3

f " not defined here – – – – – – – – –

–2

+ + + + + x

0 FIGURE 39

Sign diagram for f 

–3

1 FIGURE 40

f has an inflection point at (1, 0).

10.2 APPLICATIONS OF THE SECOND DERIVATIVE + + + +0– – – – –0+ + + + 1



EXAMPLE 5 Find the inflection points of the function f(x)  ex . 2

x

1

0

2

683

2

The first derivative of f is

Solution

f (x)  2xex

FIGURE 41

Sign diagram for f 

2

Differentiating f(x) with respect to x yields 2

f (x)  (2x)(2xex )  2ex 2  2ex (2x 2  1)

2

Setting f (x)  0 gives 2

2ex (2x 2  1)  0 y

Since ex never equals zero for any real value of x, we see that x  1/ 22 are the only candidates for inflection points of f. The sign diagram of f , shown in Figure 41, tells us that both x  1/ 22 and x  1/ 22 give rise to inflection points of f. Next, 2

1



 2 , e



1  , e –1/2 2

–2

1

–1

FIGURE 42

1 2

–1/2

2

The graph of y  ex has two inflection points.

f a

x

1 22

b fa

1 22

b  e1/2

and the inflection points of f are (1/ 22, e1/2 ) and (1/ 22, e1/2). The graph of f appears in Figure 42.

Explore & Discuss 1. Suppose (c, f(c)) is an inflection point of f. Can you conclude that f has no relative extremum at x  c? Explain your answer. 2. True or false: A polynomial function of degree 3 has exactly one inflection point. Hint: Study the function f(x)  ax3  bx 2  cx  d (a  0).

The next example uses an interpretation of the first and second derivatives to help us sketch a graph of a function. EXAMPLE 6 Sketch the graph of a function having the following properties: f(1)  4 f(0)  2 f(1)  0 f (1)  0 f (x)  0 f (x) 0 f (x) 0 f (x)  0

f (1)  0 on (, 1)  (1, ) on (1, 1) on (, 0) on (0, )

First, we plot the points (1, 4), (0, 2), and (1, 0) that lie on the graph of f. Since f (1)  0 and f (1)  0, the tangent lines at the points (1, 4) and (1, 0) are horizontal. Since f (x)  0 on (, 1) and f (x) 0 on (1, 1), we see that f has a relative maximum at the point (1, 4). Also, f (x) 0 on (1, 1) and f (x)  0 on (1, ) implies that f has a relative minimum at the point (1, 0) (Figure 43a). Since f (x) 0 on (, 0) and f (x)  0 on (0, ), we see that the point (0, 2) is an inflection point. Finally, we complete the graph making use of the fact

Solution

684

10 APPLICATIONS OF THE DERIVATIVE

that f is increasing on (, 1)  (1, ), where it is given that f (x)  0, and f is decreasing on (1, 1), where f (x) 0. Also, make sure that f is concave downward on (, 0) and concave upward on (0, ) (Figure 43b). y (–1, 4)

–4 –3 –2 –1 FIGURE 43

(a)

y

4 3 2 (0, 2) 1 (1, 0) 1

2

4 3 2 1 x 3

4

x –4 –3 –2 –1

1

2

3

4

(b)

Examples 7 and 8 illustrate familiar interpretations of the significance of the inflection point of a function. APPLIED EXAMPLE 7 Effect of Advertising on Sales The total sales S (in thousands of dollars) of Arctic Air Corporation, a manufacturer of automobile air conditioners, is related to the amount of money x (in thousands of dollars) the company spends on advertising its products by the formula S(x)  0.01x 3  1.5x 2  200

(0 x 100)

Find the inflection point of the function S. Solution Thousands of dollars

y 5000 3000

The first two derivatives of S are given by S(x)  0.03x 2  3x S(x)  0.06x  3

y = S(x)

Setting S(x)  0 gives x  50. So (50, S(50)) is the only candidate for an inflection point of S. Moreover, since

(50, 2700)

S(x)  0 for x 50 S(x) 0 for x  50

1000 x 20 40 60 80 100

and

Thousands of dollars

the point (50, 2700) is an inflection point of the function S. The graph of S appears in Figure 44. Notice that this is the graph of the function we discussed earlier.

FIGURE 44 The graph of S(x) has a point of inflection at (50, 2700).

APPLIED EXAMPLE 8 Consumer Price Index An economy’s consumer price index (CPI) is described by the function I(t)  0.2t 3  3t 2  100

(0 t 10)

where t  0 corresponds to the year 1998. Find the point of inflection of the function I and discuss its significance. Solution

The first two derivatives of I are given by I(t)  0.6t 2  6t I (t)  1.2t  6  1.2(t  5)

Setting I(t)  0 gives t  5. So (5, I(5)) is the only candidate for an inflection point of I. Next, we observe that I(x)  0 for I(x) 0 for

t 5 t5

685

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

so the point (5, 150) is an inflection point of I. The graph of I is sketched in Figure 45. Since the second derivative of I measures the rate of change of the inflation rate, our computations reveal that the rate of inflation had in fact peaked at t  5. Thus, relief actually began at the beginning of 2003. I(t) 200

y = I(t)

180 160 (5, 150)

140 120 100 FIGURE 45

t 1 2 3 4 5 6 7 8 9 10 Years

The graph of I(t) has a point of inflection at (5, 150).

The Second Derivative Test We now show how the second derivative f  of a function f can be used to help us determine whether a critical number of f gives rise to a relative extremum of f. Figure 46a shows the graph of a function that has a relative maximum at x  c. Observe that f is concave downward at that number. Similarly, Figure 46b shows that at a relative minimum of f the graph is concave upward. But from our previous work, we know that f is concave downward at x  c if f (c) 0 and f is concave upward at x  c if f (c)  0. These observations suggest the following alternative procedure for determining whether a critical number of f gives rise to a relative extremum of f. This result is called the second derivative test and is applicable when f  exists. y

y f"(c ) > 0

f"(c) < 0

c FIGURE 46

(a) f has a relative maximum at x  c.

x

c (b) f has a relative minimum at x  c.

The Second Derivative Test

1. Compute f (x) and f (x). 2. Find all the critical numbers of f at which f (x)  0. 3. Compute f (c) for each such critical number c. a. If f (c) 0, then f has a relative maximum at c. b. If f (c)  0, then f has a relative minimum at c. c. If f (c)  0, the test fails; that is, it is inconclusive.

x

686

10 APPLICATIONS OF THE DERIVATIVE

The second derivative test does not yield a conclusion if f (c)  0 or if f (c) does not exist. In other words, x  c may give rise to a relative extremum or an inflection point (see Exercise 118, page 694). In such cases, you should revert to the first derivative test.

Note

EXAMPLE 9 Determine the relative extrema of the function f(x)  x 3  3x 2  24x  32

using the second derivative test. (See Example 7, Section 10.1.) Solution

We have f (x)  3x 2  6x  24  3(x  2)(x  4)

so f (x)  0 gives x  2 and x  4, the critical numbers of f, as in Example 7. Next, we compute f (x)  6x  6  6(x  1)

Since f (2)  6(2  1)  18 0

the second derivative test implies that f (2)  60 is a relative maximum of f. Also, f (4)  6(4  1)  18  0

and the second derivative test implies that f (4)  48 is a relative minimum of f, which confirms the results obtained earlier.

Explore & Discuss Suppose a function f has the following properties: 1. f (x)  0 for all x in an interval (a, b). 2. There is a number c between a and b such that f (c)  0. What special property can you ascribe to the point (c, f(c))? Answer the question if Property 1 is replaced by the property that f (x) 0 for all x in (a, b).

Comparing the First and Second Derivative Tests Notice that both the first derivative test and the second derivative test are used to classify the critical numbers of f. What are the pros and cons of the two tests? Since the second derivative test is applicable only when f  exists, it is less versatile than the first derivative test. For example, it cannot be used to locate the relative minimum f (0)  0 of the function f (x)  x 2/3. Furthermore, the second derivative test is inconclusive when f  is equal to zero at a critical number of f, whereas the first derivative test always yields positive conclusions. The second derivative test is also inconvenient to use when f  is difficult to compute. On the plus side, if f  is computed easily, then we use the second derivative test since it involves just the evaluation of f  at the critical number(s) of f. Also, the conclusions of the second derivative test are important in theoretical work. We close this section by summarizing the different roles played by the first derivative f  and the second derivative f  of a function f in determining the properties of the graph of f. The first derivative f  tells us where f is increasing and where f is decreasing, whereas the second derivative f  tells us where f is concave upward and where f is concave downward. These different properties of f are reflected by the signs

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

687

of f  and f  in the interval of interest. The following table shows the general characteristics of the function f for various possible combinations of the signs of f  and f  in the interval (a, b). Signs of f  and f 

Properties of the Graph of f

f (x)  0 f (x)  0

f increasing f concave upward

f (x)  0 f (x) 0

f increasing f concave downward

f (x) 0 f (x)  0

f decreasing f concave upward

f (x) 0 f (x) 0

f decreasing f concave downward

General Shape of the Graph of f

10.2 Self-Check Exercises 1. Determine where the function f(x)  4x 3  3x 2  6 is concave upward and where it is concave downward.

G(t)  2t 3  45t 2  20t  6000

where t  0 corresponds to the beginning of 1995. Find the inflection point of the function G and discuss its significance.

2. Using the second derivative test, if applicable, find the relative extrema of the function f(x)  2x 3  12x 2  12x  10. 3. A certain country’s gross domestic product (GDP) (in millions of dollars) in year t is described by the function

(0 t 11)

Solutions to Self-Check Exercises 10.2 can be found on page 695.

10.2 Concept Questions 1. Explain what it means for a function f to be (a) concave upward and (b) concave downward on an open interval I. Given that f has a second derivative on I (except at isolated numbers), how do you determine where the graph of f is concave upward and where it is concave downward?

2. What is an inflection point of the graph of a function f ? How do you find the inflection point(s) of the graph of a function f whose rule is given? 3. State the second derivative test. What are the pros and cons of using the first derivative test and the second derivative test?

10.2 Exercises In Exercises 1–8, you are given the graph of a function f. Determine the intervals where f is concave upward and where it is concave downward. Also, find all inflection points of f, if any.

1.

2.

y

3.

y 1 1 2

y

x –1

3 2 1 x

x –2 –1

1 2 3

–1 –2

1

2

1

688

10 APPLICATIONS OF THE DERIVATIVE

4.

b. Explain why the second derivative test cannot be used to show that the critical number 7 does not give rise to a relative extremum of f nor can it be used to show that the critical number 9 gives rise to a relative maximum of f.

y

x – 3 – 2 –1

1 2 3

In Exercises 11–14, determine which graph—(a), (b), or (c)—is the graph of the function f with the specified properties.

–1

5.

6.

y

4 3 2 1

x 1

–1

11. f(2)  1, f (2)  0, and f (2) 0 (a) y

y

2

2

1 x

–1

x

1 2 3 4 5 6

1

2

1

2

1

2

–2

7.

y

(b)

y

3 2

2

1

1 x – 2 –1

1

8.

x

2

y y

(c) 2 2

1

1

x 1

2

x

9. Refer to the graph of f shown in the following figure: y

12. f(1)  2, f (x)  0 on (, 1)  (1, ), and f (1)  0 y (a)

6 5 4 2

3 2

1

1 0

x

x 1

2

3

4

5

6

7

8

9 10 11 12

a. Find the intervals where f is concave upward and the intervals where f is concave downward. b. Find the inflection points of f. 10. Refer to the figure for Exercise 9. a. Explain how the second derivative test can be used to show that the critical number 3 gives rise to a relative maximum of f and the critical number 5 gives rise to a relative minimum of f.

(b)

1

2

1

2

y

2

1 x

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

(c)

689

14. f is decreasing on (, 2) and increasing on (2, ), f is concave upward on (1, ), and f has inflection points at x  0 and x  1. y (a)

y

2

1 x 1

1

2

x

13. f (0) is undefined, f is decreasing on (, 0), f is concave downward on (0, 3), and f has an inflection point at x  3. (a)

y

(b)

1

2

1

2

y

1 x

x 1

2

3

(c) (b)

y

y 1 x 1

2

x 1

(c)

2

15. EFFECT OF ADVERTISING ON BANK DEPOSITS The following graphs were used by the CEO of the Madison Savings Bank to illustrate what effect a projected promotional campaign would have on its deposits over the next year. The functions D1 and D2 give the projected amount of money on deposit with the bank over the next 12 mo with and without the proposed promotional campaign, respectively. a. Determine the signs of D1(t), D2(t), D1(t), and D2(t) on the interval (0, 12). b. What can you conclude about the rate of change of the growth rate of the money on deposit with the bank with and without the proposed promotional campaign?

3

y

x 1

2

3

y ($) y = D1(t) y = D2(t)

t (months) 12

690

10 APPLICATIONS OF THE DERIVATIVE

16. ASSEMBLY TIME OF A WORKER In the following graph, N(t) gives the number of personal radios assembled by the average worker by the tth hr, where t  0 corresponds to 8 a.m. and 0 t 4. The point P is an inflection point of N. a. What can you say about the rate of change of the rate of the number of personal radios assembled by the average worker between 8 a.m. and 10 a.m.? Between 10 a.m. and 12 a.m.? b. At what time is the rate at which the personal radios are being assembled by the average worker greatest?

In Exercises 19–24, show that the function is concave upward wherever it is defined.

19. f(x)  4x 2  12x  7 1 20. t(x)  x 4  x 2  6x  10 2 21. f 1x2 

1 x4

22. h(x) 

23. t 1x2  24  x 2

1 x2

24. h(x)  2x 2  4

In Exercises 25–46, determine where the function is concave upward and where it is concave downward.

y y = N(t) P

25. f(x)  2x 2  3x  4

26. t(x)  x 2  3x  4

27. f(x)  x 3  1

28. t(x)  x 3  x

29. f(x)  x 4  6x 3  2x  8 t (hr) 1

2

3

4

30. f(x)  3x 4  6x 3  x  8 31. f(x)  x 4/7

17. WATER POLLUTION When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. In the following graph, P(t) gives the oxygen content (as a percent of its normal level) t days after organic waste has been dumped into the pond. Explain the significance of the inflection point Q.

33. f 1x2  14  x

34. t 1x2  1x  2

35. f 1x2 

1 x2

36. t 1x2 

x x1

37. f 1x2 

1 2  x2

38. t 1x2 

x 1  x2

39. h 1t2 

t2 t1

40. f 1x2 

x1 x1

y (%)

41. t 1x2  x 

100 y = P(t)

1 x2

43. t(t)  (2t  4)1/3

Q

t (days)

18. SPREAD OF A RUMOR Initially, a handful of students heard a rumor on campus. The rumor spread and, after t hr, the number had grown to N(t). The graph of the function N is shown in the following figure:

45. f(x) 

e x  ex 2

47. f(x)  x 2  ln x 2

42. h 1r2  

1 1r  22 2

44. f(x)  (x  2)2/3 46. f(x)  xex 48. f(x) 

ln x x

In Exercises 49–62, find the inflection point(s), if any, of each function.

49. f(x)  x 3  2

y

3 32. f 1x2  2 x

50. t(x)  x 3  6x

51. f(x)  6x 3  18x 2  12x  15 y  N(t)

52. t(x)  2x 3  3x 2  18x  8 53. f(x)  3x 4  4x 3  1

P

54. f(x)  x 4  2x 3  6 t (hr)

Describe the spread of the rumor in terms of the speed it was spread. In particular, explain the significance of the inflection point P of the graph of N.

3 55. t 1t2  2t

5 56. f 1x2  2x

57. f(x)  (x  1)3  2

58. f(x)  (x  2)4/3

59. f(x)  2ex

60. f(x)  xe2x

61. f(x)  x2 ln x

62. f(x)  ln(x2  1)

2

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

In Exercises 63–80, find the relative extrema, if any, of each function. Use the second derivative test, if applicable.

63. f(x)  x 2  2x  4

64. t(x)  2x 2  3x  7

65. f(x)  2x 3  1

66. t(x)  x 3  6x

67. f 1x2 

1 3 x  2x2  5x  10 3

68. f(x)  2x 3  3x 2  12x  4 69. t 1t2  t  71. f 1x2 

72. f 1x2 

x 1x

73. f 1t2  t 2  75. t 1s2 

70. f 1t2  2t 

9 t

76. t 1x2 

s 1  s2

77. t(t)  et

2x x2  1

74. t 1x2  x 2 

16 t

22t

3 t

88. EFFECT OF BUDGET CUTS ON DRUG-RELATED CRIMES The graphs below were used by a police commissioner to illustrate what effect a budget cut would have on crime in the city. The number N1(t) gives the projected number of drugrelated crimes in the next 12 mo. The number N2(t) gives the projected number of drug-related crimes in the same time frame if next year’s budget is cut. a. Explain why N1(t) and N2(t) are both positive on the interval (0, 12). b. What are the signs of N 1(t) and N2(t) on the interval (0, 12)? c. Interpret the results of part (b). y

y = N2(t)

2 x y = N1(t)

1 1  x2

78. f(x)  x 2ex

79. f(x)  ln(x  1)

80. t(x)  x  ln x

2

691

In Exercises 81–86, sketch the graph of a function having the given properties.

81. f(2)  4, f (2)  0, f (x) 0 on (, ) 82. f(2)  2, f (2)  0, f (x)  0 on (, 2), f (x)  0 on (2, ), f (x) 0 on (, 2), f (x)  0 on (2, )

t (months)

12

89. In the following figure, water is poured into the vase at a constant rate (in appropriate units), and the water level rises to a height of f(t) units at time t as measured from the base of the vase. The graph of f follows. Explain the shape of the curve in terms of its concavity. What is the significance of the inflection point? y

83. f(2)  4, f(3)  2, f (2)  0, f (3)  0, f (x)  0 on (, 2)  (3, ), f (x) 0 on (2, 3), inflection point at (1, 1) 84. f(0)  0, f (0) does not exist, f (x) 0 if x  0 85. f(0)  1, f (0)  0, f (x)  0 on (, ), f (x) 0 on (12/2, 12/2), f (x)  0 on (, 12/2)  ( 12/2, ) 86. f has domain [1, 1], f(1)  1, f (12Ô  2, f (12Ô  0, f (x)  0 on (1, 1) 87. DEMAND FOR RNS The following graph gives the total number of help-wanted ads for RNs (registered nurses) in 22 cities over the last 12 mo as a function of time t (t measured in months). a. Explain why N (t) is positive on the interval (0, 12). b. Determine the signs of N(t) on the interval (0, 6) and the interval (6, 12). c. Interpret the results of part (b).

Concave downward

f (t)

Concave upward

Inflection point

t

90. In the following figure, water is poured into an urn at a constant rate (in appropriate units), and the water level rises to a height of f(t) units at time t as measured from the base of the urn. Sketch the graph of f and explain its shape, indicating where it is concave upward and concave downward. Indicate the inflection point on the graph and explain its significance. Hint: Study Exercise 89.

y f (t) y = N(t)

91. STATE CIGARETTE TAXES The average state cigarette tax per pack (in dollars) from 2001 through 2007 is approximated by the function t (months) 6

12

T(t)  0.43t 0.43

(1 t 7)

692

10 APPLICATIONS OF THE DERIVATIVE

where t is measured in years, with t  1 corresponding to the beginning of 2001. a. Show that the average state cigarette tax per pack was increasing throughout the period in question. b. What can you say about the rate at which the average state cigarette tax per pack was increasing over the period in question? Source: Campaign for Tobacco-Free Kids

92. GLOBAL WARMING The increase in carbon dioxide (CO2) in the atmosphere is a major cause of global warming. Using data obtained by Charles David Keeling, professor at Scripps Institution of Oceanography, the average amount of CO2 in the atmosphere from 1958 through 2007 is approximated by A(t)  0.010716t 2  0.8212t  313.4

(1 t 50)

where A(t) is measured in parts per million volume (ppmv) and t in years, with t  1 corresponding to the beginning of 1958. a. What can you say about the rate of change of the average amount of atmospheric CO2 from the beginning of 1958 through 2007? b. What can you say about the rate of the rate of change of the average amount of atmospheric CO2 from the beginning of 1958 through 2007? Source: Scripps Institution of Oceanography

93. EFFECT OF SMOKING BANS The sales (in billions of dollars) in restaurants and bars in California from the beginning of 1993 (t  0) through 2000 (t  7) are approximated by the function S(t)  0.195t 2  0.32t  23.7

(0 t 7)

a. Show that the sales in restaurants and bars continued to rise after smoking bans were implemented in restaurants in 1995 and in bars in 1998. Hint: Show that S is increasing in the interval (2, 7).

b. What can you say about the rate at which the sales were rising after smoking bans were implemented? Source: California Board of Equalization

94. DIGITAL TELEVISION SALES Since their introduction into the market in the late 1990s, the sales of digital televisions, including high-definition television sets, have slowly gathered momentum. The model S(t)  0.164t  0.85t  0.3 2

(0 t 4)

describes the sales of digital television sets (in billions of dollars) between the beginning of 1999 (t  0) and the beginning of 2003 (t  4). a. Find S(t) and S(t). b. Use the results of part (a) to conclude that the sales of digital TVs were increasing between 1999 and 2003 and that the sales were increasing at an increasing rate over that time interval. Source: Consumer Electronics Association

95. WORKER EFFICIENCY An efficiency study conducted for Elektra Electronics showed that the number of Space Com-

mander walkie-talkies assembled by the average worker t hr after starting work at 8 a.m. is given by N(t)  t 3  6t 2  15t

(0 t 4)

At what time during the morning shift is the average worker performing at peak efficiency? 96. FLIGHT OF A ROCKET The altitude (in feet) of a rocket t sec into flight is given by s  f (t)  t 3  54t 2  480t  6

(t  0)

Find the point of inflection of the function f and interpret your result. What is the maximum velocity attained by the rocket? 97. BUSINESS SPENDING ON TECHNOLOGY In a study conducted in 2003, business spending on technology (in billions of dollars) from the beginning of 2000 through 2005 was projected to be S(t)  1.88t 3  30.33t 2  76.14t  474

(0 t 5)

where t is measured in years, with t  0 corresponding to 2000. Show that the graph of S is concave upward on the interval (0, 5). What does this result tell you about the rate of business spending on technology over the period in question? Source: Quantit Economic Group

98. ALTERNATIVE MINIMUM TAX Congress created the alternative minimum tax (AMT) in the late 1970s to ensure that wealthy people paid their fair share of taxes. But because of quirks in the law, even middle-income taxpayers have started to get hit with the tax. The AMT (in billions of dollars) projected to be collected by the IRS from the beginning of 2001 through 2010 is f(t)  0.0117t 3  0.0037t 2  0.7563t  4.1

(0 t 9)

where t is measured in years, with t  0 corresponding to 2001. a. Show that f is increasing on the interval (0, 9). What does this result tell you about the projected amount of AMT paid over the years in question? b. Show that f  is increasing on the interval (0, 9). What conclusion can you draw from this result concerning the rate of growth at which the AMT is paid over the years in question? Source: U.S. Congress Joint Economic Committee

99. EFFECT OF ADVERTISING ON HOTEL REVENUE The total annual revenue R of the Miramar Resorts Hotel is related to the amount of money x the hotel spends on advertising its services by the function R(x)  0.003x 3  1.35x 2  2x  8000

(0 x 400)

where both R and x are measured in thousands of dollars. a. Find the interval where the graph of R is concave upward and the interval where the graph of R is concave downward. What is the inflection point of R? b. Would it be more beneficial for the hotel to increase its advertising budget slightly when the budget is $140,000 or when it is $160,000?

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

100. FORECASTING PROFIT As a result of increasing energy costs, the growth rate of the profit of the 4-yr old Venice Glassblowing Company has begun to decline. Venice’s management, after consulting with energy experts, decides to implement certain energy-conservation measures aimed at cutting energy bills. The general manager reports that, according to his calculations, the growth rate of Venice’s profit should be on the increase again within 4 yr. If Venice’s profit (in hundreds of dollars) t yr from now is given by the function P(t)  t 3  9t 2  40t  50

(0 t 8)

determine whether the general manager’s forecast will be accurate. Hint: Find the inflection point of the function P and study the concavity of P.

101. OUTSOURCING The amount (in billions of dollars) spent by the top 15 U.S. financial institutions on IT (information technology) offshore outsourcing is projected to be A(t)  0.92(t  1)

0.61

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 2004. a. Show that A is increasing on (0, 4) and interpret your result. b. Show that A is concave downward on (0, 4). Interpret your result. Source: Tower Group

102. SALES OF MOBILE PROCESSORS The rising popularity of notebook computers is fueling the sales of mobile PC processors. In a study conducted in 2003, the sales of these chips (in billions of dollars) was projected to be S(t)  6.8(t  1.03)0.49

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 2003. a. Show that S is increasing on the interval (0, 4) and interpret your result. b. Show that the graph of S is concave downward on the interval (0, 4). Interpret your result. Source: International Data Corp.

103. DRUG SPENDING Medicaid spending on drugs in Massachusetts started slowing down in part after the state demanded that patients use more generic drugs and limited the range of drugs available to the program. The annual pharmacy spending (in millions of dollars) from 1999 through 2004 is given by S(t)  1.806t 3  10.238t 2  93.35t  583

(0 t 5)

where t is measured in years with t  0 corresponding to the beginning of 1999. Find the inflection point of S and interpret your result. Source: MassHealth

104. SURVEILLANCE CAMERAS Research reports indicate that surveillance cameras at major intersections dramatically reduce the number of drivers who barrel through red

693

lights. The cameras automatically photograph vehicles that drive into intersections after the light turns red. Vehicle owners are then mailed citations instructing them to pay a fine or sign an affidavit that they weren’t driving at the time. The function N(t)  6.08t 3  26.79t 2  53.06t  69.5

(0 t 4)

gives the number, N(t), of U.S. communities using surveillance cameras at intersections in year t, with t  0 corresponding to the beginning of 2003. a. Show that N is increasing on [0, 4]. b. When was the number of communities using surveillance cameras at intersections increasing least rapidly? What is the rate of increase? Source: Insurance Institute for Highway Safety

105. GOOGLE’S REVENUE The revenue for Google from the beginning of 1999 (t  0) through 2003 (t  4) is approximated by the function R(t)  24.975t 3  49.81t 2  41.25t  0.2

(0 t 4)

where R(t) is measured in millions of dollars. a. Find R(t) and R(t). b. Show that R(t)  0 for all t in the interval (0, 4) and interpret your result. Hint: Use the quadratic formula.

c. Find the inflection point of R and interpret your result. Source: Company Report

106. POPULATION GROWTH IN CLARK COUNTY Clark County in Nevada—dominated by greater Las Vegas—is one of the fastest-growing metropolitan areas in the United States. The population of the county from 1970 through 2000 is approximated by the function P(t)  44560t 3  89394t 2  234633t  273288 (0 t 4)

where t is measured in decades, with t  0 corresponding to the beginning of 1970. a. Show that the population of Clark County was always increasing over the time period in question. Hint: Show that P(t)  0 for all t in the interval (0, 4).

b. Show that the population of Clark County was increasing at the slowest pace some time toward the middle of August 1976. Hint: Find the inflection point of P in the interval (0, 4). Source: U.S. Census Bureau

107. MEASLES DEATHS Measles is still a leading cause of vaccine-preventable death among children, but due to improvements in immunizations, measles deaths have dropped globally. The function N(t)  2.42t 3  24.5t 2  123.3t  506

(0 t 6)

gives the number of measles deaths (in thousands) in subSaharan Africa in year t, with t  0 corresponding to 1999. a. How many measles deaths were there in 1999? In 2005? b. Show that N(t) 0 on (0, 6). What does this say about the number of measles deaths from 1999 through 2005?

694

10 APPLICATIONS OF THE DERIVATIVE

c. When was the number of measles deaths decreasing most rapidly? What was the rate of measles death at that instant of time? Source: Centers for Disease Control and World Health Organization

108. HIRING LOBBYISTS Many public entities like cities, counties, states, utilities, and Indian tribes are hiring firms to lobby Congress. One goal of such lobbying is to place earmarks—money directed at a specific project—into appropriation bills. The amount (in millions of dollars) spent by public entities on lobbying from 1998 through 2004 is given by f (t)  0.425t 3  3.6571t 2  4.018t  43.7 (0 t 6)

where t is measured in years, with t  0 corresponding to the beginning of 1998. a. Show that f is increasing on (0, 6). What does this say about the spending by public entities on lobbying over the years in question? b. Find the inflection point of f. What does your result tell you about the growth of spending by the public entities on lobbying? Source: Center for Public Integrity

109. AIR POLLUTION The level of ozone, an invisible gas that irritates and impairs breathing, present in the atmosphere on a certain May day in the city of Riverside was approximated by A(t)  1.0974t 3  0.0915t 4

(0 t 11)

where A(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. Use the second derivative test to show that the function A has a relative maximum at approximately t  9. Interpret your results. 110. CASH RESERVES AT BLUE CROSS AND BLUE SHIELD Based on company financial reports, the cash reserves of Blue Cross and Blue Shield as of the beginning of year t is approximated by the function R(t)  1.5t 4  14t 3  25.4t 2  64t  290 (0 t 6)

where R(t) is measured in millions of dollars and t is measured in years, with t  0 corresponding to the beginning of 1998. a. Find the inflection points of R. Hint: Use the quadratic formula.

b. Use the result of part (a) to show that the cash reserves of the company was growing at the greatest rate at the beginning of 2002. Source: Blue Cross and Blue Shield

111. WOMEN’S SOCCER Starting with the youth movement that took hold in the 1970s and buoyed by the success of the U.S. national women’s team in international competition in recent years, girls and women have taken to soccer in ever-growing numbers. The function N(t)  0.9307t 3  74.04t 2  46.8667t  3967 (0 t 16)

gives the number of participants in women’s soccer in year t, with t  0 corresponding to the beginning of 1985. a. Verify that the number of participants in women’s soccer had been increasing from 1985 through 2000. Hint: Use the quadratic formula.

b. Show that the number of participants in women’s soccer had been increasing at an increasing rate from 1985 through 2000. Hint: Show that the sign of N  is positive on the interval in question. Source: NCCA News

112. DEPENDENCY RATIO The share of the world population that is over 60 years of age compared to the rest of the working population in the world is of concern to economists. An increasing dependency ratio means that there will be fewer workers to support an aging population. The dependency ratio over the next century is forecast to be R(t)  0.00731t 4  0.174t 3  1.528t 2  0.48t  19.3 (0 t 10)

in year t, where t is measured in decades with t  0 corresponding to 2000. a. Show that the dependency ratio will be increasing at the fastest pace around 2052. Hint: Use the quadratic formula.

b. What will the dependency ratio be at that time? Source: International Institute for Applied Systems Analysis

In Exercises 113–116, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

113. If the graph of f is concave upward on (a, b), then the graph of f is concave downward on (a, b). 114. If the graph of f is concave upward on (a, c) and concave downward on (c, b), where a c b, then f has an inflection point at (c, f (c)). 115. If c is a critical number of f where a c b and f (x) 0 on (a, b), then f has a relative maximum at x  c. 116. A polynomial function of degree n (n  3) can have at most (n  2) inflection points. 117. Show that the quadratic function f(x)  ax 2  bx  c

(a  0)

is concave upward if a  0 and concave downward if a 0. Thus, by examining the sign of the coefficient of x 2, one can tell immediately whether the parabola opens upward or downward. 118. Consider the functions f (x)  x 3, t(x)  x 4, and h(x)  x 4. a. Show that x  0 is a critical number of each of the functions f, t, and h. b. Show that the second derivative of each of the functions f, t, and h equals zero at x  0. c. Show that f has neither a relative maximum nor a relative minimum at x  0, that t has a relative minimum at x  0, and that h has a relative maximum at x  0.

10.2 APPLICATIONS OF THE SECOND DERIVATIVE

695

10.2 Solutions to Self-Check Exercises Since

1. We first compute f (x)  12x 2  6x

4 4 f – a  b  12 a  b  1  17 0 3 3

f (x)  24x  6  6(4x  1)

Observe that f  is continuous everywhere and has a zero at x  14 . The sign diagram of f  is shown in the accompanying figure. – – – – – –0+ + + + + + 0

x

1 4

2. First, we find the critical numbers of f by solving the equation f (x)  6x 2  x  12  0

That is, (3x  4)(2x  3)  0

giving x 

3 3 f – a b  12 a b  1  17  0 2 2

and we see that f 1 32 2   179 8 is a relative minimum. 3. We compute the second derivative of G. Thus,

From the sign diagram for f , we see that f is concave upward on Ó41, Ô and concave downward on Ó, 41Ô.

 43

the second derivative test implies that f 143 2  10 27 is a relative maximum of f. Also,

and x  32. Next, we compute

G(t)  6t 2  90t  20 G(t)  12t  90

Now, G is continuous everywhere, and G(t)  0, when t  152, giving t  152 as the only candidate for an inflection point of G. Since G(t)  0 for t 152 and G(t) 0 for t  152, we see that Ó152, 15,675 2 Ô is an inflection point of G. The results of our computations tell us that the country’s GDP was increasing most rapidly at the beginning of July 2002.

f (x)  12x  1

USING

TECHNOLOGY

Finding the Inflection Points of a Function A graphing utility can be used to find the inflection points of a function and hence the intervals where the graph of the function is concave upward and the intervals where it is concave downward. Some graphing utilities have an operation for finding inflection points directly. For example, both the TI-85 and TI-86 graphing calculators have this capability. If your graphing utility has this capability, use it to work through the example and exercises in this section. EXAMPLE 1 Let f(x)  2.5x 5  12.4x 3  4.2x 2  5.2x  4. a. Use a graphing utility to plot the graph of f. b. Find the inflection points of f. c. Find the intervals where f is concave upward and where it is concave downward. Solution

FIGURE T1 The graph of f in the viewing window [3, 3]  [25, 60]

a. The graph of f, using the viewing window [3, 3]  [25, 60], is shown in Figure T1. b. We describe here the procedure using the TI-85. See the Web site for instructions for using the TI-86. From Figure T1 we see that f has three inflection points— one occurring at the point where the x-coordinate is approximately 1, another at the point where x  0, and the third at the point where x  1. To find the first inflection point, we use the inflection operation, moving the cursor to the point on the graph of f where x  1. We obtain the point (1.2728, 34.6395) (accurate to four decimal places). Next, setting the cursor near x  0 yields the inflection point (0.1139, 3.4440). Finally, with the cursor set at x  1, we obtain the third inflection point (1.1589, 10.4594). (See Figure T2a–c.) (continued)

696

10 APPLICATIONS OF THE DERIVATIVE

c. From the results of part (b), we see that f is concave upward on the intervals (1.2728, 0.1139) and (1.1589, ) and concave downward on (, 1.2728) and (0.1139, 1.1589).

INFLC x = −1.272789664 y = 34.639469452

INFLC x = .11389616904

(a)

y = 3.4439506602

(b)

INFLC x = 1.1588934952

y = −10.45942011

(c)

FIGURE T2 The TI-85 inflection point screens showing the points (a) (1.2728, 34.6395), (b) (0.1139, 3.4440), and (c) (1.1589, 10.4594)

TECHNOLOGY EXERCISES In Exercises 1–8, find (a) the intervals where f is concave upward and the intervals where f is concave downward and (b) the inflection points of f. Express your answers accurate to four decimal places.

1. f(x)  1.8x 4  4.2x 3  2.1x  2

f(t)  0.00447t 3  0.09864t 2  0.05192t  0.8

2. f(x)  2.1x  3.1x  2x  x  1.2 4

3

2

(0 t 15)

3. f(x)  1.2x 5  2x 4  3.2x 3  4x  2 4. f(x)  2.1x 5  3.2x 3  2.2x 2  4.2x  4 5. f(x)  x 3(x 2  1)1/3

6. f(x)  x 2(x 3  1)3

7. f 1x2 

8. f 1x2  xex 

ex  x3 x

11. SURGERIES IN PHYSICIANS’ OFFICES Driven by technological advances and financial pressures, the number of surgeries performed in physicians’ offices nationwide has been increasing over the years. The function

1 x

9. TIME ON THE MARKET The average number of days a singlefamily home remains for sale from listing to accepted offer (in the greater Boston area) is approximated by the function f(t)  0.0171911t  0.662121t  6.18083t 4

 8.97086t  53.3357

3

2

(0 t 10)

where t is measured in years, with t  0 corresponding to the beginning of 1984. a. Plot the graph of f in the viewing window [0, 12]  [0, 120]. b. Find the points of inflection and interpret your result. Source: Greater Boston Real Estate Board—Multiple Listing Service

10. MULTIMEDIA SALES Sales in the multimedia market (hardware and software) are approximated by the function S(t)  0.0094t 4  0.1204t 3  0.0868t 2  0.0195t  3.3325

(0 t 10)

where S(t) is measured in billions of dollars and t is measured in years, with t  0 corresponding to 1990. a. Plot the graph of S in the viewing window [0, 12]  [0, 25]. b. Find the inflection point of S and interpret your result. Source: Electronic Industries Association

gives the number of surgeries (in millions) performed in physicians’ offices in year t, with t  0 corresponding to the beginning of 1986. a. Plot the graph of f in the viewing window [0, 15]  [0, 10]. b. At what time in the period under consideration is the number of surgeries performed in physicians’ offices increasing at the fastest rate? Source: SMG Marketing Group

12. MODELING WITH DATA The following data gives the number of computer-security incidents (in thousands), including computer viruses and intrusions, in which the same tool is used by an intruder, from 1999 through 2003. Year Number of incidents

1999 10

2000 21

2001 53

2002 83

2003 137

a. Use QuartReg to find a fourth-degree polynomial regression model for the data. Let t  0 correspond to 1999. b. Show that the number N(t) of computer-security incidents was always increasing between 2000 and 2003. Hint: Plot the graph of N and show that it always lies above the t-axis for 1 t 4.

c. Show that between 2000 and 2001, the number of computer-security incidents was increasing at the fastest rate in the middle of 2000 and that between 2001 and 2003 the number of incidents was increasing at the slowest rate in the middle of 2001. Hint: Study the nature of the inflection points of N. Source: CERT Coordination Center

10.3 CURVE SKETCHING

697

10.3 Curve Sketching A Real-Life Example As we have seen on numerous occasions, the graph of a function is a useful aid for visualizing the function’s properties. From a practical point of view, the graph of a function also gives, at one glance, a complete summary of all the information captured by the function. Consider, for example, the graph of the function giving the Dow-Jones Industrial Average (DJIA) on Black Monday, October 19, 1987 (Figure 47). Here, t  0 corresponds to 9:30 a.m., when the market was open for business, and t  6.5 corresponds to 4 p.m., the closing time. The following information may be gleaned from studying the graph. y 2200 2164

(2, 2150)

DJIA

2100 (1, 2047)

2000

(4, 2006) 1900 1800 1700

0 FIGURE 47 The Dow-Jones Industrial Average on Black Monday.

1

2

3

4 Hours

5

6

7

t

Source: Wall Street Journal

The graph is decreasing rapidly from t  0 to t  1, reflecting the sharp drop in the index in the first hour of trading. The point (1, 2047) is a relative minimum point of the function, and this turning point coincides with the start of an aborted recovery. The short-lived rally, represented by the portion of the graph that is increasing on the interval (1, 2), quickly fizzled out at t  2 (11:30 a.m.). The relative maximum point (2, 2150) marks the highest point of the recovery. The function is decreasing in the rest of the interval. The point (4, 2006) is an inflection point of the function; it shows that there was a temporary respite at t  4 (1:30 p.m.). However, selling pressure continued unabated, and the DJIA continued to fall until the closing bell. Finally, the graph also shows that the index opened at the high of the day [ f (0)  2164 is the absolute maximum of the function] and closed at the low of the day [ f Ó132Ô  1739 is the absolute minimum of the function], a drop of 508 points from the previous close!* Before we turn our attention to the actual task of sketching the graph of a function, let’s look at some properties of graphs that will be helpful in this connection.

Vertical Asymptotes Before going on, you might want to review the material on one-sided limits and the limit at infinity of a function (Sections 9.1 and 9.2). *Absolute maxima and absolute minima of functions are covered in Section 10.4.

698

10 APPLICATIONS OF THE DERIVATIVE

Consider the graph of the function

y

4 y=

f 1x2 

x+1 x–1

2 y=1

shown in Figure 48. Observe that f(x) increases without bound (tends to infinity) as x approaches x  1 from the right; that is,

x –2

2 –2

lim

4

x=1

FIGURE 48 The graph of f has a vertical asymptote at x  1.

x1 x1

xS1

x1  x1

You can verify this by taking a sequence of values of x approaching x  1 from the right and looking at the corresponding values of f (x). Here is another way of looking at the situation: Observe that if x is a number that is a little larger than 1, then both (x  1) and (x  1) are positive, so (x  1)/(x  1) is also positive. As x approaches x  1, the numerator (x  1) approaches the number 2, but the denominator (x  1) approaches zero, so the quotient (x  1)/(x  1) approaches infinity, as observed earlier. The line x  1 is called a vertical asymptote of the graph of f. For the function f(x)  (x  1)/(x  1), you can show that lim

xS1

x1   x1

and this tells us how f (x) approaches the asymptote x  1 from the left. More generally, we have the following definition:

Vertical Asymptote

The line x  a is a vertical asymptote of the graph of a function f if either lim f 1x2  

or 

lim f 1x2  

or 

xSa 

or xSa

Note Although a vertical asymptote of a graph is not part of the graph, it serves as a useful aid for sketching the graph.

For rational functions f 1x2 

P1x2 Q1x2

there is a simple criterion for determining whether the graph of f has any vertical asymptotes.

Finding Vertical Asymptotes of Rational Functions

Suppose f is a rational function f 1x2 

P1x2 Q1x2

where P and Q are polynomial functions. Then, the line x  a is a vertical asymptote of the graph of f if Q(a)  0 but P(a)  0.

10.3 CURVE SKETCHING

699

For the function f 1x2 

x1 x1

considered earlier, P(x)  x  1 and Q(x)  x  1. Observe that Q(1)  0 but P(1)  2  0, so x  1 is a vertical asymptote of the graph of f. EXAMPLE 1 Find the vertical asymptotes of the graph of the function f 1x2 

x2 4  x2

y x = –2

The function f is a rational function with P(x)  x 2 and Q(x)  4  x 2. The zeros of Q are found by solving

Solution

x=2

4  x2  0 x

—that is, (2  x)(2  x)  0

y = –1

FIGURE 49

x  2 and x  2 are vertical asymptotes of the graph of f.

giving x  2 and x  2. These are candidates for the vertical asymptotes of the graph of f. Examining x  2, we compute P(2)  (2)2  4  0, and we see that x  2 is indeed a vertical asymptote of the graph of f. Similarly, we find P(2)  22  4  0, and so x  2 is also a vertical asymptote of the graph of f. The graph of f sketched in Figure 49 confirms these results. Recall that in order for the line x  a to be a vertical asymptote of the graph of a rational function f, only the denominator of f(x) must be equal to zero at x  a. If both P(a) and Q(a) are equal to zero, then x  a need not be a vertical asymptote. For example, look at the function f 1x2 

41x 2  4 2 x2

whose graph appears in Figure 7a, page 541.

Horizontal Asymptotes Let’s return to the function f defined by f 1x2 

x 1 x1

(Figure 50). y

4 y=

x+1 x–1

2 y=1 x –2 FIGURE 50 The graph of f has a horizontal asymptote at y  1.

2

4

–2 x=1

Observe that f(x) approaches the horizontal line y  1 as x approaches infinity, and, in this case, f(x) approaches y  1 as x approaches minus infinity as well. The

700

10 APPLICATIONS OF THE DERIVATIVE

line y  1 is called a horizontal asymptote of the graph of f. More generally, we have the following definition: Horizontal Asymptote

The line y  b is a horizontal asymptote of the graph of a function f if either lim f 1x2  b

lim f 1x2  b

or

xS

xS

For the function f 1x2 

x 1 x1

we see that x1 lim  lim xS x  1 xS

1

1 x

1

1 x

Divide numerator and denominator by x .

1

Also,

lim xS

x1  lim x  1 xS

1

1 x

1

1 x

1

In either case, we conclude that y  1 is a horizontal asymptote of the graph of f, as observed earlier. EXAMPLE 2 Find the horizontal asymptotes of the graph of the function f 1x2  Solution

x2 4  x2

We compute lim xS

x2 1 2  lim xS 4 4x 1 x2  1

Divide numerator and denominator by x 2.

and so y  1 is a horizontal asymptote, as before. (Similarly, lim f 1x2  1, as xS well.) The graph of f sketched in Figure 51 confirms this result. y x = –2

x=2

x y = –1

FIGURE 51 The graph of f has a horizontal asymptote at y  1.

10.3 CURVE SKETCHING

701

We next state an important property of polynomial functions. A polynomial function has no vertical or horizontal asymptotes. To see this, note that a polynomial function P(x) can be written as a rational function with denominator equal to 1. Thus, P 1x2 

P1x2 1

Since the denominator is never equal to zero, P has no vertical asymptotes. Next, if P is a polynomial of degree greater than or equal to 1, then lim P1x2 xS

and

lim P1x 2

xS

are either infinity or minus infinity; that is, they do not exist. Therefore, P has no horizontal asymptotes. In the last two sections, we saw how the first and second derivatives of a function are used to reveal various properties of the graph of a function f. We now show how this information can be used to help us sketch the graph of f. We begin by giving a general procedure for curve sketching.

A Guide to Curve Sketching

1. 2. 3. 4. 5. 6. 7. 8. 9.

Determine the domain of f. Find the x- and y-intercepts of f.* Determine the behavior of f for large absolute values of x. Find all horizontal and vertical asymptotes of f. Determine the intervals where f is increasing and where f is decreasing. Find the relative extrema of f. Determine the concavity of f. Find the inflection points of f. Plot a few additional points to help further identify the shape of the graph of f and sketch the graph.

*The equation f (x)  0 may be difficult to solve, in which case one may decide against finding the x-intercepts or to use technology, if available, for assistance.

We now illustrate the techniques of curve sketching in the next two examples.

Two Step-by-Step Examples EXAMPLE 3 Sketch the graph of the function y  f (x)  x 3  6x 2  9x  2 Solution

Obtain the following information on the graph of f.

1. The domain of f is the interval (, ). 2. By setting x  0, we find that the y-intercept is 2. The x-intercept is found by setting y  0, which in this case leads to a cubic equation. Since the solution is not readily found, we will not use this information.

702

10 APPLICATIONS OF THE DERIVATIVE

3. Since lim f 1x2  lim 1x 3  6x 2  9x  2 2  

xS

xS

lim f 1x2  lim 1x 3  6x 2  9x  22  

xS

xS

we see that f decreases without bound as x decreases without bound and that f increases without bound as x increases without bound. 4. Since f is a polynomial function, there are no asymptotes. f (x)  3x 2  12x  9  3(x 2  4x  3)

5. + + + + + +0 – – – 0+ + + + 0

1

2

 3(x  3)(x  1) x

3

FIGURE 52

Sign diagram for f 

– – – – – – – – –0+ + + + 0

1

Setting f(x)  0 gives x  1 or x  3. The sign diagram for f  shows that f is increasing on the intervals (, 1) and (3, ) and decreasing on the interval (1, 3) (Figure 52). 6. From the results of step 5, we see that x  1 and x  3 are critical numbers of f. Furthermore, f  changes sign from positive to negative as we move across x  1, so a relative maximum of f occurs at x  1. Similarly, we see that a relative minimum of f occurs at x  3. Now, f(1)  1  6  9  2  6

x

2

f(3)  33  6(3)2  9(3)  2  2

FIGURE 53

Sign diagram for f 

so f(1)  6 is a relative maximum of f and f(3)  2 is a relative minimum of f.

7

f (x)  6x  12  6(x  2)

7.

y (1, 6)

which is equal to zero when x  2. The sign diagram of f  shows that f is concave downward on the interval (, 2) and concave upward on the interval (2, ) (Figure 53). 8. From the results of step 7, we see that f  changes sign as we move across x  2. Next,

Relative maximum

6

Point of inflection

5 4 3

Intercept

2

(3, 2)

1

f(2)  23  6(2)2  9(2)  2  4

Relative minimum

and so the required inflection point of f is (2, 4). x

1

2

3

4

5

6

Summarizing, we have the following:

FIGURE 54 We first plot the intercept, the relative extrema, and the inflection point.

Domain: (, ) Intercept: (0, 2) lim f 1x2; lim f 1x2 : ; 

y

xS

7 6

xS

Asymptotes: None Intervals where f is Q or R: Q on (, 1)  (3, ); R on (1, 3) Relative extrema: Relative maximum at (1, 6); relative minimum at (3, 2) Concavity: Downward on (, 2); upward on (2, ) Point of inflection: (2, 4)

(1, 6)

5 4 3 2 (3, 2)

1

x 1 FIGURE 55

2

3

4

5

6

The graph of y  x 3  6x 2  9x  2

In general, it is a good idea to start graphing by plotting the intercept(s), relative extrema, and inflection point(s) (Figure 54). Then, using the rest of the information, we complete the graph of f, as sketched in Figure 55.

10.3 CURVE SKETCHING

703

Explore & Discuss The average price of gasoline at the pump over a 3-month period, during which there was a temporary shortage of oil, is described by the function f defined on the interval [0, 3]. During the first month, the price was increasing at an increasing rate. Starting with the second month, the good news was that the rate of increase was slowing down, although the price of gas was still increasing. This pattern continued until the end of the second month. The price of gas peaked at the end of t  2 and began to fall at an increasing rate until t  3. 1. Describe the signs of f (t) and f (t) over each of the intervals (0, 1), (1, 2), and (2, 3). 2. Make a sketch showing a plausible graph of f over [0, 3].

EXAMPLE 4 Sketch the graph of the function y  f 1x2  Solution

x1 x1

Obtain the following information:

1. f is undefined when x  1, so the domain of f is the set of all real numbers other than x  1. 2. Setting y  0 gives 1, the x-intercept of f. Next, setting x  0 gives 1 as the y-intercept of f. 3. Earlier we found that x1 1 xS x  1 lim

and

x1 1 xS x  1 lim

(see pages 698–700). Consequently, we see that f(x) approaches the line y  1 as 0 x 0 becomes arbitrarily large. For x  1, f(x)  1 and f(x) approaches the line y  1 from above. For x 1, f(x) 1, so f(x) approaches the line y  1 from below. 4. The straight line x  1 is a vertical asymptote of the graph of f. Also, from the results of step 3, we conclude that y  1 is a horizontal asymptote of the graph of f. 5. f ' is not defined here – – – – – – – – – – – – – – x 0

1

FIGURE 56

f ¿1x2 

7.

– – – – – – – – – + + + + + x 0 FIGURE 57

The sign diagram for f 

1

1x  12

2



2 1x  12 2

and is discontinuous at x  1. The sign diagram of f  shows that f (x) 0 whenever it is defined. Thus, f is decreasing on the intervals (, 1) and (1, ) (Figure 56). 6. From the results of step 5, we see that there are no critical numbers of f since f (x) is never equal to zero for any value of x in the domain of f.

The sign diagram for f 

f '' is not defined here

1x  12 112  1x  12 112

f –1x2 

d 4 321x  12 2 4  41x  12 3  dx 1x  12 3

The sign diagram of f  shows immediately that f is concave downward on the interval (, 1) and concave upward on the interval (1, ) (Figure 57). 8. From the results of step 7, we see that there are no candidates for inflection points of f since f (x) is never equal to zero for any value of x in the domain of f. Hence, f has no inflection points.

704

10 APPLICATIONS OF THE DERIVATIVE

Summarizing, we have the following: y

4 y=

Domain: (, 1)  (1, ) Intercepts: (0, 1); (1, 0) lim f 1x2 ; lim f 1x2: 1; 1

x+1 x–1

xS

2 y=1 x –2

2

xS

Asymptotes: x  1 is a vertical asymptote y  1 is a horizontal asymptote Intervals where f is Q or R: R on (, 1)  (1, ) Relative extrema: None Concavity: Downward on (, 1); upward on (1, ) Points of inflection: None

4

–2 x=1 FIGURE 58 The graph of f has a horizontal asymptote at y  1 and a vertical asymptote at x  1.

The graph of f is sketched in Figure 58.

10.3 Self-Check Exercises 1. Find the horizontal and vertical asymptotes of the graph of the function 2x 2 f 1x2  2 x 1

2. Sketch the graph of the function 2 f 1x2  x 3  2x 2  6x  4 3

Solutions to Self-Check Exercises 10.3 can be found on page 708.

10.3 Concept Questions 1. Explain the following terms in your own words: a. Vertical asymptote b. Horizontal asymptote

3. How do you find the vertical asymptotes of a rational function?

2. a. How many vertical asymptotes can the graph of a function f have? Explain using graphs. b. How many horizontal asymptotes can the graph of a function f have? Explain using graphs.

4. Give a procedure for sketching the graph of a function.

10.3 Exercises In Exercises 1–10, find the horizontal and vertical asymptotes of the graph.

1.

2.

y

y y= 1

2 y=

2 1 + 0.5 x

1 (x + 1) 2 x

–1 x

10.3 CURVE SKETCHING

3.

8.

y y=

705

y

1 x3

y=

1

1 (x + 2) 2

x –1

1 1

–1

x –1

4.

9.

y 1

y 1

1 x2 + 1

y=

y  ex

2

x 2

x

1

1 y

10.

5.

2

y y=

1

x x2 – 1

1

x –1

y  ln | x2  1|

1

6.

x

0

In Exercises 11–28, find the horizontal and vertical asymptotes of the graph of the function. (You need not sketch the graph.)

y

11. f 1x2 

x

y=

x2 + 1

1 x2

2 x2

14. t 1x2 

1 1  2x 2

x1 x1

16. t 1t2 

t1 2t  1

13. f 1x2  

1 2

x –1

12. f 1x2 

1 x

1 1 2

15. f 1x2 

17. h(x)  x 3  3x 2  x  1 18. t(x)  2x 3  x 2  1

7.

y y=3–

1 x2

3

x –3 –2 –1

1

2

19. f 1t2 

t2 t 9

20. t 1x2 

x3 x 4

21. f 1x2 

3x x x6

22. t 1x2 

2x x x2

2

2

23. t 1t2  2 

3

25. f 1x2 

5 1t  22 2

x2  2 x2  4

2

2

24. f 1x2  1  26. h1x2 

2 x3

2  x2 x2  x

706

4 APPLICATIONS OF THE DERIVATIVE

27. t 1x2 

x3  x x1x  1 2

28. f 1x2 

x4  x 2 x1x  12 1x  22

In Exercises 33–36, use the information summarized in the table to sketch the graph of f.

33. f(x)  x 3  3x 2  1 In Exercises 29 and 30, you are given the graphs of two functions f and g. One function is the derivative function of the other. Identify each of them.

29.

y 10

t

7.5 5 2.5 x –3

–2

–1

1

–2.5

2

3

–5 –10

30.

y f

10 8 6 2 x

–1 t

–2

1 9

35. f 1x2 

4

–2

34. f 1x2  1x 4  4x 3 2 Domain: (, ) Intercepts: x-intercepts: 0, 4; y-intercept: 0 Asymptotes: None Intervals where f is Q and R: Q on (3, ); R on (, 0)  (0, 3) Relative extrema: Rel. min. at (3, 3) Concavity: Downward on (0, 2); upward on (, 0)  (2, ) Points of inflection: (0, 0) and Ó2, 169 )

–7.5 f

Domain: (, ) Intercept: y-intercept: 1 Asymptotes: None Intervals where f is Q and R: Q on (, 0)  (2, ); R on (0, 2) Relative extrema: Rel. max. at (0, 1); rel. min. at (2, 3) Concavity: Downward on (, 1); upward on (1, ) Point of inflection: (1, 1)

1

2

3

4

–4 –6

31. TERMINAL VELOCITY A skydiver leaps from the gondola of a hot-air balloon. As she free-falls, air resistance, which is proportional to her velocity, builds up to a point where it balances the force due to gravity. The resulting motion may be described in terms of her velocity as follows: Starting at rest (zero velocity), her velocity increases and approaches a constant velocity, called the terminal velocity. Sketch a graph of her velocity √ versus time t. 32. SPREAD OF A FLU EPIDEMIC Initially, 10 students at a junior high school contracted influenza. The flu spread over time, and the total number of students who eventually contracted the flu approached but never exceeded 200. Let P(t) denote the number of students who had contracted the flu after t days, where P is an appropriate function. a. Make a sketch of the graph of P. (Your answer will not be unique.) b. Where is the function increasing? c. Does P have a horizontal asymptote? If so, what is it? d. Discuss the concavity of P. Explain its significance. e. Is there an inflection point on the graph of P? If so, explain its significance.

4x  4 x2

Domain: (, 0)  (0, ) Intercept: x-intercept: 1 Asymptotes: x-axis and y-axis Intervals where f is Q and R: Q on (0, 2); R on (, 0)  (2, ) Relative extrema: Rel. max. at (2, 1) Concavity: Downward on (, 0)  (0, 3); upward on (3, ) Point of inflection: Ó3, 89 Ô 36. f(x)  x  3x 1/3 Domain: (, ) Intercepts: x-intercepts: 3 13, 0 Asymptotes: None Intervals where f is Q and R: Q on (, 1)  (1, ); R on (1, 1) Relative extrema: Rel. max. at (1, 2); rel. min. at (1, 2) Concavity: Downward on (, 0); upward on (0, ) Point of inflection: (0, 0) In Exercises 37–60, sketch the graph of the function, using the curve-sketching guide of this section.

37. t(x)  4  3x  2x 3

38. f(x)  x 2  2x  3

39. h(x)  x 3  3x  1

40. f(x)  2x 3  1

41. f(x)  2x 3  3x 2  12x  2 42. f(t)  2t 3  15t 2  36t  20

10.3 CURVE SKETCHING

43. h1x 2 

3 4 x  2x3  6x 2  8 2

44. f (t)  3t 4  4t 3 45. f 1t 2  2t 2  4

46. f 1x 2  2x 2  5

47. t 1x2 

1 x  1x 2

3 48. f 1x 2  2x 2

49. t 1x 2 

2 x1

50. f 1x 2 

1 x1

51. h1x 2 

x2 x2

52. t 1x2 

x x1

53. f 1t2 

2

54. t 1x 2 

x x2  4

55. f (t)  e t  t

56. h 1x2 

e x  ex 2

57. f (x)  2  ex

58. f 1x 2 

3 1  ex

59. f (x)  ln(x  1)

60. f (x)  2x  ln x

t 1  t2

61. COST OF REMOVING TOXIC POLLUTANTS A city’s main well was recently found to be contaminated with trichloroethylene (a cancer-causing chemical) as a result of an abandoned chemical dump that leached chemicals into the water. A proposal submitted to the city council indicated that the cost, measured in millions of dollars, of removing x% of the toxic pollutants is given by C 1x2 

0.5x 100  x

a. Find the vertical asymptote of C(x). b. Is it possible to remove 100% of the toxic pollutant from the water? 62. AVERAGE COST OF PRODUCING DVDS The average cost per disc (in dollars) incurred by Herald Media Corporation in pressing x DVDs is given by the average cost function C 1x2  2.2 

2500 x

a. Find the horizontal asymptote of C (x). b. What is the limiting value of the average cost? 63. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration (in milligrams/cubic centimeter) of a certain drug in a patient’s bloodstream t hr after injection is given by C 1t 2 

0.2t t2  1

a. Find the horizontal asymptote of C(t). b. Interpret your result. 64. EFFECT OF ENZYMES ON CHEMICAL REACTIONS Certain proteins, known as enzymes, serve as catalysts for chemical reactions in living things. In 1913 Leonor Michaelis and

707

L. M. Menten discovered the following formula giving the initial speed V (in moles/liter/second) at which the reaction begins in terms of the amount of substrate x (the substance that is being acted upon, measured in moles/liter): V

ax xb

where a and b are positive constants. a. Find the horizontal asymptote of V. b. What does the result of part (a) tell you about the initial speed at which the reaction begins, if the amount of substrate is very large? 65. GDP OF A DEVELOPING COUNTRY A developing country’s gross domestic product (GDP) from 2000 to 2008 is approximated by the function G(t)  0.2t 3  2.4t 2  60

(0 t 8)

where G(t) is measured in billions of dollars, with t  0 corresponding to 2000. Sketch the graph of the function G and interpret your results. 66. CRIME RATE The number of major crimes per 100,000 committed in a city between 2000 and 2007 is approximated by the function N(t)  0.1t 3  1.5t 2  80

(0 t 7)

where N(t) denotes the number of crimes per 100,000 committed in year t, with t  0 corresponding to 2000. Enraged by the dramatic increase in the crime rate, the citizens, with the help of the local police, organized Neighborhood Crime Watch groups in early 2004 to combat this menace. Sketch the graph of the function N and interpret your results. Is the Neighborhood Crime Watch program working? 67. WORKER EFFICIENCY An efficiency study showed that the total number of cordless telephones assembled by an average worker at Delphi Electronics t hr after starting work at 8 a.m. is given by 1 N1t2   t 3  3t 2  10t 2

10 t 42

Sketch the graph of the function N and interpret your results. 68. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration (in millimeters/cubic centimeter) of a certain drug in a patient’s bloodstream t hr after injection is given by C 1t2 

0.2t t2  1

Sketch the graph of the function C and interpret your results. 69. BOX-OFFICE RECEIPTS The total worldwide box-office receipts for a long-running movie are approximated by the function T 1x2 

120x 2 x2  4

708

10 APPLICATIONS OF THE DERIVATIVE

where T(x) is measured in millions of dollars and x is the number of years since the movie’s release. Sketch the graph of the function T and interpret your results.

10 a.m. on a typical workday is approximated by the function

70. OXYGEN CONTENT OF A POND When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. Suppose the oxygen content t days after organic waste has been dumped into the pond is given by

where t is measured in hours, with t  0 corresponding to 6 a.m. Sketch the graph of f and interpret your results.

f 1t2  100 a

t 2  4t  4 b t2  4

71. COST OF REMOVING TOXIC POLLUTANTS Refer to Exercise 61. The cost, measured in millions of dollars, of removing x% of a toxic pollutant is given by 0.5x 100  x

Sketch the graph of the function C and interpret your results. 72. TRAFFIC FLOW ANALYSIS The speed of traffic flow in miles per hour on a stretch of Route 123 between 6 a.m. and

10 t 42

73. SPREAD OF AN EPIDEMIC During a flu epidemic, the total number of students on a state university campus who had contracted influenza by the xth day was given by

10 t  2

percent of its normal level. Sketch the graph of the function f and interpret your results.

C 1x2 

f 1t2  20t  401t  52

N(x) 

3000 1  99ex

(x  0)

a. How many students had influenza initially? b. Derive an expression for the rate at which the disease was being spread and prove that the function N is increasing on the interval (0, ). c. Sketch the graph of N. What was the total number of students who contracted influenza during that particular epidemic? 74. ABSORPTION OF DRUGS A liquid carries a drug into an organ of volume V cm3 at the rate of a cm3/sec and leaves at the same rate. The concentration of the drug in the entering liquid is c g/cm3. Letting x(t) denote the concentration of the drug in the organ at any time t, we have x(t)  c(1  eat/V ). a. Show that x is an increasing function on (0, ). b. Sketch the graph of x.

10.3 Solutions to Self-Check Exercises 1. Since lim xS

2x 2  lim xS x 1 2

2 1

1 x2

Divide the numerator and denominator by x 2.

2

we see that y  2 is a horizontal asymptote. Next, since x 2  1  (x  1)(x  1)  0

(4) Since f is a polynomial function, there are no asymptotes. (5)

f (x)  2x 2  4x  6  2(x 2  2x  3)  2(x  1)(x  3)

Setting f (x)  0 gives x  1 or x  3. The accompanying sign diagram for f  shows that f is increasing on the intervals (, 1) and (3, ) and decreasing on (1, 3).

implies x  1 or x  1, these are candidates for the vertical asymptotes of f. Since the numerator of f is not equal to zero for x  1 or x  1, we conclude that x  1 and x  1 are vertical asymptotes of the graph of f. 2. We obtain the following information on the graph of f. (1) The domain of f is the interval (, ). (2) By setting x  0, we find the y-intercept is 4. (3) Since 2 lim f 1x2  lim a x 3  2x 2  6x  4 b   xS 3

xS

2 lim f 1x2  lim a x 3  2x 2  6x  4 b   xS 3

xS

we see that f(x) decreases without bound as x decreases without bound and that f(x) increases without bound as x increases without bound.

++++0––––––0++++ x –1 0 3 Sign diagram for f '

(6) From the results of step 5, we see that x  1 and x  3 are critical numbers of f. Furthermore, the sign diagram of f  tells us that x  1 gives rise to a relative maximum of f and x  3 gives rise to a relative minimum of f. Now, f 112 

22 2 112 3  211 2 2  611 2  4  3 3

f 13 2 

2 3 132  213 2 2  613 2  4  14 3

so f 112  223 is a relative maximum of f and f(3)  14 is a relative minimum of f.

10.3 CURVE SKETCHING

(7) f (x)  4x  4  4(x  1) which is equal to zero when x  1. The accompanying sign diagram of f  shows that f is concave downward on the interval (, 1) and concave upward on the interval (1, ).

(9) Summarizing this information, we have the following: Domain: (, ) Intercept: (0, 4) lim f 1x2; lim f 1x2: ;  xS

– – – – – – – –0+ + + +

xS

Asymptotes: None Intervals where f is Q or R: Q on (, 1)  (3, ); R on (1, 3) Relative extrema: Rel. max. at 11, 223 2 ; rel. min. at (3, 14) Concavity: Downward on (, 1); upward on (1, ) Point of inflection: 11, 103 2

x 0 1 Sign diagram for f "

(8) From the results of step 7, we see that x  1 is the only candidate for an inflection point of f. Since f (x) changes sign as we move across the point x  1 and f 112 

709

2 10 11 2 3  211 2 2  611 2  4   3 3

The graph of f is sketched in the accompanying figure.

we see that the required inflection point is 11, 103 2 .

y y = 32 x 3 – 2 x 2 – 6x + 4

x –1

1

2

3

4

5

–10

USING

TECHNOLOGY

Analyzing the Properties of a Function One of the main purposes of studying Section 10.3 is to see how the many concepts of calculus come together to paint a picture of a function. The techniques of graphing also play a very practical role. For example, using the techniques of graphing developed in Section 10.3, you can tell if the graph of a function generated by a graphing utility is reasonably complete. Furthermore, these techniques can often reveal details that are missing from a graph. EXAMPLE 1 Consider the function f(x)  2x 3  3.5x 2  x  10. A plot of the graph of f in the standard viewing window is shown in Figure T1. Since the domain of f is the interval (, ), we see that Figure T1 does not reveal the part of the graph to the left of the y-axis. This suggests that we enlarge the viewing window accordingly. Figure T2 shows the graph of f in the viewing window [10, 10]  [20, 10]. The behavior of f for large values of f

FIGURE T1 The graph of f in the standard viewing window

lim f 1x2  

xS

and

lim f 1x2  

xS

suggests that this viewing window has captured a sufficiently complete picture of f. Next, an analysis of the first derivative of x, f (x)  6x 2  7x  1  (6x  1)(x  1)

FIGURE T2 The graph of f in the viewing window [10, 10]  [20, 10]

reveals that f has critical values at x  16 and x  1. In fact, a sign diagram of f  shows that f has a relative maximum at x  16 and a relative minimum at x  1, details that are not revealed in the graph of f shown in Figure T2. To examine this portion of the graph of f, we use, say, the viewing window [1, 2]  [11, 9]. The resulting graph of f is shown in Figure T3, which certainly reveals the hitherto missing details! Thus, through an interaction of calculus and a graphing utility, we are able to obtain a good picture of the properties of f. (continued)

710

10 APPLICATIONS OF THE DERIVATIVE

Finding x-Intercepts

As noted in Section 10.3, it is not always easy to find the x-intercepts of the graph of a function. But this information is very important in applications. By using the function for solving polynomial equations or the function for finding the roots of an equation, we can solve the equation f(x)  0 quite easily and hence yield the x-intercepts of the graph of a function. FIGURE T3 The graph of f in the viewing window [1, 2]  [11, 9]

EXAMPLE 2 Let f(x)  x 3  3x 2  x  1.5. a. Use the function for solving polynomial equations on a graphing utility to find the x-intercepts of the graph of f. b. Use the function for finding the roots of an equation on a graphing utility to find the x-intercepts of the graph of f. Solution

a. Observe that f is a polynomial function of degree 3, and so we may use the function for solving polynomial equations to solve the equation x 3  3x 2  x  1.5  0 [ f(x)  0]. We find that the solutions (x-intercepts) are x1  0.525687120865

FIGURE T4

The graph of f(x)  x 3  3x 2  x  1.5

x2  1.2586520225

x3  2.26703509836

b. Using the graph of f (Figure T4), we see that x1  0.5, x2  1, and x3  2. Using the function for finding the roots of an equation on a graphing utility, and these values of x as initial guesses, we find x1  0.5256871209

x2  1.2586520225

x3  2.2670350984

Note The function for solving polynomial equations on a graphing utility will solve a polynomial equation f(x)  0, where f is a polynomial function. The function for finding the roots of a polynomial, however, will solve equations f(x)  0 even if f is not a polynomial.

APPLIED EXAMPLE 3 TV Mobile Phones The number of people watching TV on mobile phones (in millions) is expected to be N1t2  11.911  0.91t

10 t 42

where t is measured in years, with t  0 corresponding to the beginning of 2007. a. Use a graphing calculator to plot the graph of N. b. Based on this model, when will the number of people watching TV on mobile phones first exceed 20 million? Solution

a. The graph of N in the window [0, 4]  [0, 30] is shown in Figure T5a. b. Using the function for finding the intersection of the graphs of y1  N(t) and y2  20, we find t  2.005 (see Figure T5b). So the number of people watching TV on mobile phones will first exceed 20 million at the beginning of January 2009.

Intersection X=2.0051201 Y=20 FIGURE T5

(a) The graph of N in the viewing window [0, 4]  [0, 30]

(b) The graph showing the intersection of y1  N(t) and y2  20 on the TI 83/84.

10.4 OPTIMIZATION I

711

TECHNOLOGY EXERCISES In Exercises 1–4, use the method of Example 1 to analyze the function. (Note: Your answers will not be unique.)

1. f (x)  4x 3  4x 2  x  10 2. f (x)  x 3  2x 2  x  12

11. AIR POLLUTION The level of ozone, an invisible gas that irritates and impairs breathing, present in the atmosphere on a certain day in June in the city of Riverside is approximated by S(t)  1.0974t 3  0.0915t 4

1 1 3. f 1x2  x 4  x 3  x 2  10 2 2

where S(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. Sketch the graph of S and interpret your results.

4. f (x)  2.25x 4  4x 3  2x 2  2 In Exercises 5–8, find the x-intercepts of the graph of f. Give your answers accurate to four decimal places.

Source: Los Angeles Times

12. FLIGHT PATH

5. f (x)  0.2x  1.2x  0.8x  2.1 3

(0 t 11)

OF A

PLANE The function

2

0 0.0411523x 3  0.679012x 2 f 1x2  μ 1.23457x  0.596708 15

6. f (x)  0.2x  0.8x  2.1x  1.2 4

3

7. f 1x2  2x 2  1x  1  3 8. f 1x2  x  21  x 2

if 0 x 1 if 1 x 10 if 10 x 11

where both x and f (x) are measured in units of 1000 ft, describes the flight path of a plane taking off from the origin and climbing to an altitude of 15,000 ft. Sketch the graph of f to visualize the trajectory of the plane.

9. f (x)  ex 2x  2 10. f (x)  ln(1  x 2)  2x  3

10.4 Optimization I Absolute Extrema The graph of the function f in Figure 59 shows the average age of cars in use in the United States from the beginning of 1946 (t  0) to the beginning of 2002 (t  56). Observe that the highest average age of cars in use during this period is 9 years, whereas the lowest average age of cars in use during the same period is 512 years. The number 9, the largest value of f(t) for all values of t in the interval [0, 56] (the domain

Average age of cars in use

y (years) Absolute maximum

9 8

Absolute minimum

y = f (t)

7 6 5 t (years)

FIGURE 59 f(t) gives the average age of cars in use in year t, t in [0, 56].

0

12

Source: American Automobile Association

23

56

712

10 APPLICATIONS OF THE DERIVATIVE

of f ), is called the absolute maximum value of f on that interval. The number 512, the smallest value of f(t) for all values of t in [0, 56], is called the absolute minimum value of f on that interval. Notice, too, that the absolute maximum value of f is attained at the endpoint t  0 of the interval, whereas the absolute minimum value of f is attained at the points t  12 (corresponding to 1958) and t  23 (corresponding to 1969) that lie within the interval (0, 56). (Incidentally, it is interesting to note that 1946 marked the first year of peace following World War II, and the two years, 1958 and 1969, marked the end of two periods of prosperity in recent U.S. history!) A precise definition of the absolute extrema (absolute maximum or absolute minimum) of a function follows.

The Absolute Extrema of a Function f

If f(x) f(c) for all x in the domain of f, then f(c) is called the absolute maximum value of f. If f(x)  f(c) for all x in the domain of f, then f(c) is called the absolute minimum value of f.

Figure 60 shows the graphs of several functions and gives the absolute maximum and absolute minimum of each function, if they exist. y

y

y = x2

4

4

3

3

2

2

y = 4 – x2

1

1 x – 2 –1

1

2

(a) f(0)  0 is the absolute minimum of f; f has no absolute maximum.

x –1

–2

1

(b) f(0)  4 is the absolute maximum of f; f has no absolute minimum.

y

y

1 2

2

y = x3

2

y = x 1 – x2

1 x

–1

1 2

1

x –2

–1

1

2

–2

FIGURE 60

(c) f 1 12/22  1/2 is the absolute maximum of f; f 112/22  1/2 is the absolute minimum of f.

(d) f has no absolute extrema.

10.4 OPTIMIZATION I

713

Absolute Extrema on a Closed Interval As the preceding examples show, a continuous function defined on an arbitrary interval does not always have an absolute maximum or an absolute minimum. But an important case arises often in practical applications in which both the absolute maximum and the absolute minimum of a function are guaranteed to exist. This occurs when a continuous function is defined on a closed interval. Let’s state this important result in the form of a theorem, whose proof we will omit.

THEOREM 3 If a function f is continuous on a closed interval [a, b], then f has both an absolute maximum value and an absolute minimum value on [a, b]. Observe that if an absolute extremum of a continuous function f occurs at a point in an open interval (a, b), then it must be a relative extremum of f and hence its x-coordinate must be a critical number of f. Otherwise, the absolute extremum of f must occur at one or both of the endpoints of the interval [a, b]. A typical situation is illustrated in Figure 61. y Absolute maximum Relative maximum

Relative minimum

FIGURE 61 The relative minimum of f at x3 is the absolute minimum of f. The right endpoint b of the interval [a, b] gives rise to the absolute maximum value f(b) of f.

y = f (x)

a

x1

Absolute minimum x2

x3

b

x

Here x1, x2, and x3 are critical numbers of f. The absolute minimum of f occurs at x3, which lies in the open interval (a, b) and is a critical number of f. The absolute maximum of f occurs at b, an endpoint. This observation suggests the following procedure for finding the absolute extrema of a continuous function on a closed interval.

Finding the Absolute Extrema of f on a Closed Interval

1. Find the critical numbers of f that lie in (a, b). 2. Compute the value of f at each critical number found in step 1 and compute f(a) and f(b). 3. The absolute maximum value and absolute minimum value of f will correspond to the largest and smallest numbers, respectively, found in step 2. EXAMPLE 1 Find the absolute extrema of the function F(x)  x 2 defined on the interval [1, 2]. The function F is continuous on the closed interval [1, 2] and differentiable on the open interval (1, 2). The derivative of F is Solution

F(x)  2x

714

10 APPLICATIONS OF THE DERIVATIVE

so 0 is the only critical number of F. Next, evaluate F(x) at x  1, x  0, and x  2. Thus, F(1)  1 F(0)  0 F(2)  4

y

3

It follows that 0 is the absolute minimum value of F and 4 is the absolute maximum value of F. The graph of F, in Figure 62, confirms our results.

y = x2 1 x – 3 – 2 –1

1

2

3

EXAMPLE 2 Find the absolute extrema of the function f(x)  x 3  2x 2  4x  4

FIGURE 62 F has an absolute minimum value of 0 and an absolute maximum value of 4.

defined on the interval [0, 3]. Solution The function f is continuous on the closed interval [0, 3] and differentiable on the open interval (0, 3). The derivative of f is

y

f (x)  3x 2  4x  4  (3x  2)(x  2)

Absolute maximum

4 y = x3 – 2x2 –4x + 4 2

–2

2

x

4

f(0)  4

f(2)  4

f(3)  1

From these results, we conclude that 4 is the absolute minimum value of f and 4 is the absolute maximum value of f. The graph of f, which appears in Figure 63, confirms our results. Observe that the absolute maximum of f occurs at the endpoint x  0 of the interval [0, 3], while the absolute minimum of f occurs at x  2, which lies in the interval (0, 3).

–2 –4

and it is equal to zero when x  23 and x  2. Since x  23 lies outside the interval [0, 3], it is dropped from further consideration, and x  2 is seen to be the sole critical number of f. Next, we evaluate f(x) at the critical number of f as well as the endpoints of f, obtaining

Absolute minimum

FIGURE 63 f has an absolute maximum value of 4 and an absolute minimum value of 4.

Exploring with

TECHNOLOGY Let f(x)  x 3  2x 2  4x  4. (This is the function of Example 2.) 1. Use a graphing utility to plot the graph of f, using the viewing window [0, 3]  [5, 5]. Use TRACE to find the absolute extrema of f on the interval [0, 3] and thus verify the results obtained analytically in Example 2. 2. Plot the graph of f, using the viewing window [2, 1]  [5, 6]. Use ZOOM and TRACE to find the absolute extrema of f on the interval [2, 1]. Verify your results analytically. EXAMPLE 3 Find the absolute maximum and absolute minimum values of the function f(x)  x 2/3 on the interval [1, 8]. y

Solution

Absolute maximum

4 3 2

y=

x 2/3

x –1

2 4 6 Absolute minimum

8

FIGURE 64 f has an absolute minimum value of f(0)  0 and an absolute maximum value of f(8)  4.

The derivative of f is f ¿1x2 

2 1/3 2 x  1/3 3 3x

Note that f  is not defined at x  0, is continuous everywhere else, and does not equal zero for all x. Therefore, 0 is the only critical number of f. Evaluating f(x) at x  1, 0, and 8, we obtain f(1)  1

f(0)  0

f(8)  4

We conclude that the absolute minimum value of f is 0, attained at x  0, and the absolute maximum value of f is 4, attained at x  8 (Figure 64).

10.4 OPTIMIZATION I

715

Many real-world applications call for finding the absolute maximum value or the absolute minimum value of a given function. For example, management is interested in finding what level of production will yield the maximum profit for a company; a farmer is interested in finding the right amount of fertilizer to maximize crop yield; a doctor is interested in finding the maximum concentration of a drug in a patient’s body and the time at which it occurs; and an engineer is interested in finding the dimension of a container with a specified shape and volume that can be constructed at a minimum cost. APPLIED EXAMPLE 4 Maximizing Profit Acrosonic’s total profit (in dollars) from manufacturing and selling x units of their model F loudspeaker systems is given by P(x)  0.02x 2  300x  200,000

(0 x 20,000)

How many units of the loudspeaker system must Acrosonic produce to maximize its profits? To find the absolute maximum of P on [0, 20,000], first find the critical points of P on the interval (0, 20,000). To do this, compute Solution

Thousands of dollars

y

P(x)  0.04x  300

Absolute maximum

1000

Solving the equation P(x)  0 gives x  7500. Next, evaluate P(x) at x  7500 as well as the endpoints x  0 and x  20,000 of the interval [0, 20,000], obtaining

800 600

y = P(x)

P(0)  200,000

400 200

P(7500)  925,000

x – 200

2 4 6 8 10 12 Units of a thousand

FIGURE 65 P has an absolute maximum at (7500, 925,000).

P(20,000)  2,200,000

16

From these computations we see that the absolute maximum value of the function P is 925,000. Thus, by producing 7500 units, Acrosonic will realize a maximum profit of $925,000. The graph of P is sketched in Figure 65.

Explore & Discuss Recall that the total profit function P is defined as P(x)  R(x)  C(x), where R is the total revenue function, C is the total cost function, and x is the number of units of a product produced and sold. (Assume all derivatives exist.) 1. Show that at the level of production x0 that yields the maximum profit for the company, the following two conditions are satisfied: R(x0)  C(x0) and R(x0) C(x0) 2. Interpret the two conditions in part 1 in economic terms and explain why they make sense.

APPLIED EXAMPLE 5 Trachea Contraction during a Cough When a person coughs, the trachea (windpipe) contracts, allowing air to be expelled at a maximum velocity. It can be shown that during a cough the velocity √ of airflow is given by the function √  f(r)  kr 2(R  r)

where r is the trachea’s radius (in centimeters) during a cough, R is the trachea’s normal radius (in centimeters), and k is a positive constant that depends on the length of the trachea. Find the radius r for which the velocity of airflow is greatest.

716

10 APPLICATIONS OF THE DERIVATIVE

Solution To find the absolute maximum of f on [0, R], first find the critical numbers of f on the interval (0, R). We compute

f (r)  2kr (R  r)  kr 2

Use the product rule.

 3kr 2  2kRr  kr (3r  2R) √

Absolute maximum

Setting f (r)  0 gives r  0 or r  23 R, and so 23 R is the sole critical number of f (r  0 is an endpoint). Evaluating f(r) at r  23 R, as well as at the endpoints r  0 and r  R, we obtain

√ = f (r)

f 102  0 2 4k f a R b  R3 3 27 f 1R2  0

r 2 3

R

R

FIGURE 66 The velocity of airflow is greatest when the radius of the contracted trachea is 23 R.

from which we deduce that the velocity of airflow is greatest when the radius of the contracted trachea is 23 R—that is, when the radius is contracted by approximately 33%. The graph of the function f is shown in Figure 66.

Explore & Discuss Prove that if a cost function C(x) is concave upward [C (x)  0], then the level of production that will result in the smallest average production cost occurs when C1x2  C ¿1x2 —that is, when the average cost C1x2 is equal to the marginal cost C(x). Hints:

1. Show that C ¿1x2 

xC ¿1x2  C1x2 x2

so that the critical number of the function C occurs when xC(x)  C(x)  0 2. Show that at a critical number of C C –1x2 

C –1x2 x

Use the second derivative test to reach the desired conclusion.

APPLIED EXAMPLE 6 Minimizing Average Cost The daily average cost function (in dollars per unit) of Elektra Electronics is given by C1x2  0.0001x 2  0.08x  40 

5000 x

1x  02

where x stands for the number of graphing calculators that Elektra produces. Show that a production level of 500 units per day results in a minimum average cost for the company. The domain of the function C is the interval (0, ), which is not closed. To solve the problem, we resort to the graphical method. Using the

Solution

10.4 OPTIMIZATION I y ($) 100

717

techniques of graphing from the last section, we sketch the graph of C (Figure 67). Now,

y = C(x)

80 Absolute minimum

60

C¿1x2  0.0002x  0.08 

40

Substituting the given value of x, 500, into C¿1x2 gives C¿1500 2  0, so 500 is a critical number of C. Next,

(500, 35)

20

5000 x2

x 200 400 600 800 1000

C –1x2  0.0002 

FIGURE 67 The minimum average cost is $35 per unit.

10,000 x3

Thus, C –15002  0.0002 

10,000 0 15002 3

and by the second derivative test, a relative minimum of the function C occurs at 500. Furthermore, C (x)  0 for x  0, which implies that the graph of C is concave upward everywhere, so the relative minimum of C must be the absolute minimum of C. The minimum average cost is given by C 15002  0.000115002 2  0.0815002  40 

5000 500

 35

or $35 per unit.

Exploring with

TECHNOLOGY Refer to the preceding Explore & Discuss and Example 6. 1. Using a graphing utility, plot the graphs of C 1x2  0.0001x 2  0.08x  40 

5000 x 2 C¿ 1x2  0.0003x  0.16x  40

using the viewing window [0, 1000]  [0, 150]. Note: C(x)  0.0001x 3  0.08x 2  40x  5000 (Why?) 2. Find the point of intersection of the graphs of C and C and thus verify the assertion in the Explore & Discuss for the special case studied in Example 6.

Our final example involves finding the absolute maximum of an exponential function. APPLIED EXAMPLE 7 Optimal Market Price The present value of the market price of the Blakely Office Building is given by P1t2  300,000e 0.09t1t/2

10 t 102

Find the optimal present value of the building’s market price.

718

10 APPLICATIONS OF THE DERIVATIVE

Solution

To find the maximum value of P over [0, 10], we compute d 1 a 0.09t  t 1/2 b dt 2 1  300,000e 0.09t 1t/2 a 0.09  t 1/2 b 4

P ¿1t2  300,000e0.09t 1t/2

Setting P(t)  0 gives 0.09 

1 0 4t 1/2

since e0.09t1t/2 is never zero for any value of t. Solving this equation, we find 1  0.09 4t 1/2 1 t 1/2  410.092 1 0.36 1 2 t a b  7.72 0.36 

the sole critical number of the function P. Finally, evaluating P(t) at the critical number as well as at the endpoints of [0, 10], we have t P(t)

0

7.72

10

300,000

600,779

592,838

We conclude, accordingly, that the optimal present value of the property’s market price is $600,779 and that this will occur 7.72 years from now.

10.4 Self-Check Exercises 1. Let f 1x2  x  21x a. Find the absolute extrema of f on the interval [0, 9]. b. Find the absolute extrema of f. 2. Find the absolute extrema of f (x)  3x 4  4x 3  1 on [2, 1]. 3. The operating rate (expressed as a percent) of factories, mines, and utilities in a certain region of the country on the tth day of 2008 is given by the function

f 1t2  80 

1200t t 2  40,000

10 t 250 2

On which of the first 250 days of 2008 was the manufacturing capacity operating rate highest? Solutions to Self-Check Exercises 10.4 can be found on page 724.

10.4 Concept Questions 1. Explain the following terms: (a) absolute maximum and (b) absolute minimum.

2. Describe the procedure for finding the absolute extrema of a continuous function on a closed interval.

10.4 OPTIMIZATION I

719

10.4 Exercises In Exercises 1–8, you are given the graph of a function f defined on the indicated interval. Find the absolute maximum and the absolute minimum of f, if they exist.

1.

6.

y

1

y 4

x –1

1

2

1

f defined on (–1,  ) x

–2 –1

1

2

7.

y

f defined on (–, )

2.

3

y

2 1 x

1 2

–1

( 23 , – 1627 )

–2

x 1 2 3 4 5 1 2

2

–1

–4 –3 –2 –1

3.

1

f defined on [–1, 2]

8.

f defined on (–, )

y

y

1 x –2

–1

1

2

3

–1

2 –2 x –1

–3

1

f defined on [–1, 3]

f defined on (–, ) y

4.

In Exercises 9–40, find the absolute maximum value and the absolute minimum value, if any, of each function.

9. f(x)  2x 2  3x  4

x

11. h(x)  x 1/3

12. f(x)  x 2/3

13. f 1x2 

14. f 1x2 

1 1  x2

16. t(x)  x 2  2x  3 on [0, 4]

y

17. f(x)  x 2  4x  6 on [0, 5]

3

18. f(x)  x 2  4x  6 on [3, 6]

2

19. f(x)  x 3  3x 2  1 on [3, 2]

1 x –1

x 1  x2

15. f(x)  x 2  2x  3 on [2, 3]

f defined on [ 0, )

5.

10. t(x)  x 2  4x  3

1

2

–2 f defined on [0, 2]

20. t(x)  x 3  3x 2  1 on [3, 1] 21. t(x)  3x 4  4x 3 on [2, 1] 2 1 22. f 1x2  x4  x 3  2x 2  3 on 32, 3 4 2 3

720

10 APPLICATIONS OF THE DERIVATIVE

23. f 1x 2 

x1 on 32, 4 4 x1

25. f 1x 2  4x 

24. t 1t 2 

t on 32, 4 4 t1

1 1 on 31, 3 4 26. f 1x 2  9x  on 3 1, 34 x x

27. f 1x 2 

1 2 x  2 1x on 3 0, 34 2

28. t 1x2 

1 2 x  4 1x on 3 0, 94 8

1 29. f 1x 2  on 10,  2 x

2

35. f (x)  ex on [1, 1] on [2, 2]

37. t(x)  (2x  1)ex on [0, 4]

40. t(x) 

39. f(x)  x  ln x on 3 12, 34

x on [2, 5] ln x

41. A stone is thrown straight up from the roof of an 80-ft building. The height (in feet) of the stone at any time t (in seconds), measured from the ground, is given by h(t)  16t 2  64t  80

What is the maximum height the stone reaches? 42. MAXIMIZING PROFIT Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting out x apartments is given by P(x)  10x 2  1760x  50,000

To maximize the monthly rental profit, how many units should be rented out? What is the maximum monthly profit realizable? 43. SENIORS IN THE WORKFORCE The percentage of men, age 65 yr and older, in the workforce from 1950 (t  0) through 2000 (t  50) is approximately P(t)  0.0135t 2  1.126t  41.2

(0 t 50)

Show that the percentage of men, age 65 yr and older, in the workforce in the period of time under consideration was smallest around mid-September 1991. What is that percent? Source: U.S. Census Bureau

44. FLIGHT OF A ROCKET The altitude (in feet) attained by a model rocket t sec into flight is given by the function 1 h 1t2   t 3  4t 2  20t  2 3

10 t 4 2

where f(t) is measured in miles per hour and t is measured in hours, with t  0 corresponding to 6 a.m. At what time of the morning commute is the traffic moving at the slowest rate? What is the average speed of a vehicle at that time?

34. f (x)  x 2/3(x 2  4) on [1, 3]

2

46. AVERAGE SPEED OF A VEHICLE The average speed of a vehicle on a stretch of Route 134 between 6 a.m. and 10 a.m. on a typical weekday is approximated by the function f 1t2  20t  40 1t  50

33. f (x)  x 2/3(x 2  4) on [1, 2]

38. f (x)  xex on [0, 2]

10 t 6 2

Source: U.S. Department of Labor

1 30. t 1x 2  on 10, 2 x1

32. t(x)  x 2  2x 2/3 on [2, 2]

24

N 1t2  0.81t  1.14 1t  1.53

where N(t) is measured in millions and t is measured in 5-yr intervals, with t  0 corresponding to the beginning of 1963. Determine the absolute extrema of the function N on the interval [0, 6]. Interpret your results.

31. f (x)  3x 2/3  2x on [0, 3]

36. h(x)  ex

45. FEMALE SELF-EMPLOYED WORKFORCE Data show that the number of nonfarm, full-time, self-employed women can be approximated by

1t  02

Find the maximum altitude attained by the rocket.

47. MAXIMIZING PROFIT The management of Trappee and Sons, producers of the famous TexaPep hot sauce, estimate that their profit (in dollars) from the daily production and sale of x cases (each case consisting of 24 bottles) of the hot sauce is given by P(x)  0.000002x 3  6x  400

What is the largest possible profit Trappee can make in 1 day? 48. MAXIMIZING PROFIT The quantity demanded each month of the Walter Serkin recording of Beethoven’s Moonlight Sonata, manufactured by Phonola Record Industries, is related to the price/compact disc. The equation p  0.00042x  6

(0 x 12,000)

where p denotes the unit price in dollars and x is the number of discs demanded, relates the demand to the price. The total monthly cost (in dollars) for pressing and packaging x copies of this classical recording is given by C(x)  600  2x  0.00002x 2

(0 x 20,000)

To maximize its profits, how many copies should Phonola produce each month? Hint: The revenue is R(x)  px, and the profit is P(x)  R(x)  C(x).

49. MAXIMIZING PROFIT A manufacturer of tennis rackets finds that the total cost C(x) (in dollars) of manufacturing x rackets/day is given by C(x)  400  4x  0.0001x 2. Each racket can be sold at a price of p dollars, where p is related to x by the demand equation p  10  0.0004x. If all rackets that are manufactured can be sold, find the daily level of production that will yield a maximum profit for the manufacturer.

10.4 OPTIMIZATION I

50. MAXIMIZING PROFIT The weekly demand for the Pulsar 25-in. color console television is given by the demand equation p  0.05x  600

(0 x 12,000)

where p denotes the wholesale unit price in dollars and x denotes the quantity demanded. The weekly total cost function associated with manufacturing these sets is given by C(x)  0.000002x 3  0.03x 2  400x  80,000

where C(x) denotes the total cost incurred in producing x sets. Find the level of production that will yield a maximum profit for the manufacturer. Hint: Use the quadratic formula.

51. MAXIMIZING PROFIT A division of Chapman Corporation manufactures a pager. The weekly fixed cost for the division is $20,000, and the variable cost for producing x pagers/week is V(x)  0.000001x 3  0.01x 2  50x

dollars. The company realizes a revenue of R(x)  0.02x 2  150x

(0 x 7500)

dollars from the sale of x pagers/week. Find the level of production that will yield a maximum profit for the manufacturer. Hint: Use the quadratic formula.

52. MINIMIZING AVERAGE COST Suppose the total cost function for manufacturing a certain product is C(x)  0.2(0.01x 2  120) dollars, where x represents the number of units produced. Find the level of production that will minimize the average cost. 53. MINIMIZING PRODUCTION COSTS The total monthly cost (in dollars) incurred by Cannon Precision Instruments for manufacturing x units of the model M1 camera is given by the function C(x)  0.0025x 2  80x  10,000

a. Find the average cost function C. b. Find the level of production that results in the smallest average production cost. c. Find the level of production for which the average cost is equal to the marginal cost. d. Compare the result of part (c) with that of part (b). 54. MINIMIZING PRODUCTION COSTS The daily total cost (in dollars) incurred by Trappee and Sons for producing x cases of TexaPep hot sauce is given by the function C(x)  0.000002x 3  5x  400

Using this function, answer the questions posed in Exercise 53. 55. MAXIMIZING REVENUE Suppose the quantity demanded per week of a certain dress is related to the unit price p by the demand equation p  1800  x, where p is in dollars and x is the number of dresses made. To maximize the revenue, how many dresses should be made and sold each week? Hint: R(x)  px.

721

56. MAXIMIZING REVENUE The quantity demanded each month of the Sicard wristwatch is related to the unit price by the equation p

50 0.01x 2  1

10 x 202

where p is measured in dollars and x is measured in units of a thousand. To yield a maximum revenue, how many watches must be sold? 57. OPTIMAL SELLING TIME The present value of a piece of waterfront property purchased by an investor is given by the function P(t)  80,000e1t/20.09t

(0 t 8)

where P(t) is measured in dollars and t is the time in years from the present. Determine the optimal time (based on present value) for the investor to sell the property. What is the property’s optimal present value? 58. MAXIMUM OIL PRODUCTION It has been estimated that the total production of oil from a certain oil well is given by T(t)  1000(t  10)e0.1t  10,000 thousand barrels t yr after production has begun. Determine the year when the oil well will be producing at maximum capacity. 59. OXYGEN CONTENT OF A POND When organic waste is dumped into a pond, the oxidation process that takes place reduces the pond’s oxygen content. However, given time, nature will restore the oxygen content to its natural level. Suppose the oxygen content t days after organic waste has been dumped into the pond is given by f 1t2  100 c

t 2  4t  4 d t2  4

10 t  2

percent of its normal level. a. When is the level of oxygen content lowest? b. When is the rate of oxygen regeneration greatest? 60. AIR POLLUTION The amount of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in the city of Long Beach is approximated by A1t2 

136  28 1  0.251t  4.52 2

10 t 112

where A(t) is measured in pollutant standard index (PSI) and t is measured in hours, with t  0 corresponding to 7 a.m. Determine the time of day when the pollution is at its highest level. 61. MAXIMIZING REVENUE The average revenue is defined as the function R1x 2 

R1x 2 x

1x  02

Prove that if a revenue function R(x) is concave downward [R (x) 0], then the level of sales that will result in the largest average revenue occurs when R1x2  R¿1x 2 .

722

10 APPLICATIONS OF THE DERIVATIVE

62. VELOCITY OF BLOOD According to a law discovered by the 19th-century physician Jean Louis Marie Poiseuille, the velocity (in centimeters/second) of blood r cm from the central axis of an artery is given by

67. BRAIN GROWTH AND IQS Refer to Exercise 66. The researchers at the Institute also measured the thickness (also in millimeters) of the cortex of children of age t yr who were of average intelligence. These data lead to the model

√ (r)  k(R 2  r 2)

A(t)  0.00005t 3  0.000826t 2  0.0153t  4.55 (5 t 19)

where k is a constant and R is the radius of the artery. Show that the velocity of blood is greatest along the central axis. 63. GDP OF A DEVELOPING COUNTRY A developing country’s gross domestic product (GDP) from 2000 to 2008 is approximated by the function G(t)  0.2t 3  2.4t 2  60

(0 t 8)

where G(t) is measured in billions of dollars and t  0 corresponds to 2000. Show that the growth rate of the country’s GDP was maximal in 2004. 64. CRIME RATES The number of major crimes committed in the city of Bronxville between 2000 and 2007 is approximated by the function N(t)  0.1t 3  1.5t 2  100

(0 t 7)

where N(t) denotes the number of crimes committed in year t (t  0 corresponds to 2000). Enraged by the dramatic increase in the crime rate, the citizens of Bronxville, with the help of the local police, organized “Neighborhood Crime Watch” groups in early 2004 to combat this menace. Show that the growth in the crime rate was maximal in 2005, giving credence to the claim that the Neighborhood Crime Watch program was working. 65. FOREIGN-BORN MEDICAL RESIDENTS The percentage of foreign-born residents in the United States from 1910 through 2000 is approximated by the function P(t)  0.04363t 3  0.267t 2  1.59t  14.7

(0 t 9)

where t is measured in decades, with t  0 corresponding to 1910. Show that the percentage of foreign-born residents was lowest in early 1970. Hint: Use the quadratic formula. Source: Journal of American Medical Association

66. BRAIN GROWTH AND IQS In a study conducted at the National Institute of Mental Health, researchers followed the development of the cortex, the thinking part of the brain, in 307 children. Using repeated magnetic resonance imaging scans from childhood to the latter teens, they measured the thickness (in millimeters) of the cortex of children of age t yr with the highest IQs—121 to 149. These data lead to the model S(t)  0.000989t 3  0.0486t 2  0.7116t  1.46 (5 t 19)

Show that the cortex of children with superior intelligence reaches maximum thickness around age 11. Hint: Use the quadratic formula. Source: Nature

Show that the cortex of children with average intelligence reaches maximum thickness at age 6 yr. Source: Nature

68. AVERAGE PRICES OF HOMES The average annual price of single-family homes in Massachusetts between 1990 and 2002 is approximated by the function P(t)  0.183t 3  4.65t 2  17.3t  200

(0 t 12)

where P(t) is measured in thousands of dollars and t is measured in years, with t  0 corresponding to 1990. In what year was the average annual price of single-family homes in Massachusetts lowest? What was the approximate lowest average annual price? Hint: Use the quadratic formula. Source: Massachusetts Association of Realtors

69. OFFICE RENTS After the economy softened, the sky-high office space rents of the late 1990s started to come down to earth. The function R gives the approximate price per square foot in dollars, R(t), of prime space in Boston’s Back Bay and Financial District from 1997 (t  0) through 2002, where R(t)  0.711t 3  3.76t 2  0.2t  36.5

(0 t 5)

Show that the office space rents peaked at about the middle of 2000. What was the highest office space rent during the period in question? Hint: Use the quadratic formula. Source: Meredith & Grew Inc./Oncor

70. WORLD POPULATION The total world population is forecast to be P(t)  0.00074t 3  0.0704t 2  0.89t  6.04

(0 t 10)

in year t, where t is measured in decades with t  0 corresponding to 2000 and P(t) is measured in billions. a. Show that the world population is forecast to peak around 2071. Hint: Use the quadratic formula.

b. What will the population peak at? Source: International Institute for Applied Systems Analysis

71. VENTURE-CAPITAL INVESTMENT Venture-capital investment increased dramatically in the late 1990s but came to a screeching halt after the dot-com bust. The venture-capital investment (in billions of dollars) from 1995 (t  0) through 2003 (t  8) is approximated by the function 0.6t 2  2.4t  7.6 3t 2  18.8t  63.2 C1t2  μ 3.3167t3  80.1t2  642.583t  1730.8025

if 0 t 3 if 3 t 5 if 5 t 8

10.4 OPTIMIZATION I

a. In what year did venture-capital investment peak over the period under consideration? What was the amount of that investment? b. In what year was√ the venture-capital investment lowest over this period? What was the amount of that investment? Hint: Find the absolute extrema of C on each of the closed intervals [0, 3], [3, 5], and [5, 8]. Sources: Venture One; Ernst & Young

72. ENERGY EXPENDED BY A FISH It has been conjectured that a fish swimming a distance of L ft at a speed of √ ft/sec relative to the water and against a current flowing at the rate of u ft/sec (u √) expends a total energy given by E1√2 

723

where k is a constant. Show that the rate of the chemical reaction is greatest at the point when exactly half of the original substrate has been transformed. 78. A MIXTURE PROBLEM A tank initially contains 10 gal of brine with 2 lb of salt. Brine with 1.5 lb of salt per gallon enters the tank at the rate of 3 gal/min, and the well-stirred mixture leaves the tank at the rate of 4 gal/min. It can be shown that the amount of salt in the tank after t min is x lb where x  f(t)  1.5(10  t)  0.0013(10  t)4

(0 t 10)

What is the maximum amount of salt present in the tank at any time?

aL√ 3 √u

where E is measured in foot-pounds (ft-lb) and a is a constant. Find the speed √ at which the fish must swim in order to minimize the total energy expended. (Note: This result has been verified by biologists.) 73. REACTION TO A DRUG The strength of a human body’s reaction R to a dosage D of a certain drug is given by R  D2 a

k D  b 2 3

where k is a positive constant. Show that the maximum reaction is achieved if the dosage is k units. 74. Refer to Exercise 73. Show that the rate of change in the reaction R with respect to the dosage D is maximal if D  k/2. 75. MAXIMUM POWER OUTPUT Suppose the source of current in an electric circuit is a battery. Then the power output P (in watts) obtained if the circuit has a resistance of R ohms is given by E 2R P 1R  r 2 2

where E is the electromotive force in volts and r is the internal resistance of the battery in ohms. If E and r are constant, find the value of R that will result in the greatest power output. What is the maximum power output? 76. VELOCITY OF A WAVE In deep water, a wave of length L travels with a velocity L C √k  AC L

where k and C are positive constants. Find the length of the wave that has a minimum velocity. 77. CHEMICAL REACTION In an autocatalytic chemical reaction, the product formed acts as a catalyst for the reaction. If Q is the amount of the original substrate present initially and x is the amount of catalyst formed, then the rate of change of the chemical reaction with respect to the amount of catalyst present in the reaction is R(x)  kx(Q  x)

(0 x Q)

In Exercises 79–82, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

79. If f is defined on a closed interval [a, b], then f has an absolute maximum value. 80. If f is continuous on an open interval (a, b), then f does not have an absolute minimum value. 81. If f is not continuous on the closed interval [a, b], then f cannot have an absolute maximum value. 82. If f (x) 0 on (a, b) and f (c)  0 where a c b, then f(c) is the absolute maximum value of f on [a, b]. 83. Let f be a constant function—that is, let f(x)  c, where c is some real number. Show that every number a gives rise to an absolute maximum and, at the same time, an absolute minimum of f. 84. Show that a polynomial function defined on the interval (, ) cannot have both an absolute maximum and an absolute minimum unless it is a constant function. 85. One condition that must be satisfied before Theorem 3 (page 713) is applicable is that the function f must be continuous on the closed interval [a, b]. Define a function f on the closed interval [1, 1] by 1 if x  31, 14 f 1x 2  • x 0 if x  0

1x  0 2

a. Show that f is not continuous at x  0. b. Show that f(x) does not attain an absolute maximum or an absolute minimum on the interval [1, 1]. c. Confirm your results by sketching the function f.

724

10 APPLICATIONS OF THE DERIVATIVE

86. One condition that must be satisfied before Theorem 3 (page 713) is applicable is that the interval on which f is defined must be a closed interval [a, b]. Define a function f on the open interval (1, 1) by f(x)  x. Show that f does

not attain an absolute maximum or an absolute minimum on the interval (1, 1). Hint: What happens to f(x) if x is close to but not equal to x  1? If x is close to but not equal to x  1?

10.4 Solutions to Self-Check Exercises 1. a. The function f is continuous in its domain and differentiable in the interval (0, 9). The derivative of f is f ¿1x2  1  x 1/2 

x 1/2  1 x 1/2

f (x)  12x 3  12x 2  12x 2(x  1)

and it is equal to zero when x  1. Evaluating f(x) at the endpoints x  0 and x  9 and at the critical number 1 of f, we have f(0)  0

f(1)  1

2. The function f is continuous on the interval [2, 1]. It is also differentiable on the open interval (2, 1). The derivative of f is

f(9)  3

From these results, we see that 1 is the absolute minimum value of f and 3 is the absolute maximum value of f. b. In this case, the domain of f is the interval [0, ), which is not closed. Therefore, we resort to the graphical method. Using the techniques of graphing, we sketch the graph of f in the accompanying figure.

and it is continuous on (2, 1). Setting f (x)  0 gives 1 and 0 as critical numbers of f. Evaluating f(x) at these critical numbers of f as well as at the endpoints of the interval [2, 1], we obtain f(2)  17



3

x

–2

(1, –1)

USING

TECHNOLOGY

1t 2  40,0002 11200 2  1200t12t2 1t 2  40,0002 2

12001t 2  40,0002 1t 2  40,0002 2

Upon setting f (t)  0 and solving the resulting equation, we obtain t  200 or 200. Since 200 lies outside the interval [0, 250], we are interested only in the critical number 200 of f. Evaluating f(t) at t  0, t  200, and t  250, we find f(0)  80

The graph of f shows that 1 is the absolute minimum value of f, but f has no absolute maximum since f(x) increases without bound as x increases without bound.

f(1)  8

3. The problem is solved by finding the absolute maximum of the function f on [0, 250]. Differentiating f(t), we obtain

y

8

f(0)  1

From these results, we see that 0 is the absolute minimum value of f and 17 is the absolute maximum value of f.

f ¿1t2 

Absolute minimum

f(1)  0

f(200)  83

f(250)  82.93

We conclude that the manufacturing capacity operating rate was the highest on the 200th day of 2008—that is, a little past the middle of July 2008.

Finding the Absolute Extrema of a Function Some graphing utilities have a function for finding the absolute maximum and the absolute minimum values of a continuous function on a closed interval. If your graphing utility has this capability, use it to work through the example and exercises of this section. EXAMPLE 1 Let f 1x2 

2x  4 . 1x 2  12 3/2

a. Use a graphing utility to plot the graph of f in the viewing window [3, 3]  [1, 5]. b. Find the absolute maximum and absolute minimum values of f on the interval [3, 3]. Express your answers accurate to four decimal places.

10.4 OPTIMIZATION I

725

Solution

a. The graph of f is shown in Figure T1. b. Using the function on a graphing utility for finding the absolute minimum value of a continuous function on a closed interval, we find the absolute minimum value of f to be 0.0632. Similarly, using the function for finding the absolute maximum value, we find the absolute maximum value to be 4.1593. fMax((2X+4)/(X^2 +1)^1.5,X,-3,3) .1583117413 (2*.1583+4)/(.15 83^2+1)^1.5 4.15928406

FIGURE T1

FIGURE T2

The graph of f in the viewing window [3, 3]  [1, 5]

The TI-83/84 screen for Example 1

Note Some graphing utilities will enable you to find the absolute minimum and absolute maximum values of a continuous function on a closed interval without having to graph the function. For example, using fMax on the TI-83/84 will yield the x-coordinate of the absolute maximum of f. The absolute maximum value can then be found by evaluating f at that value of x. Figure T2 shows the work involved in finding the absolute maximum of the function of Example 1.

TECHNOLOGY EXERCISES In Exercises 1–6, find the absolute maximum and the absolute minimum values of f in the given interval using the method of Example 1. Express your answers accurate to four decimal places.

1. f(x)  3x 4  4.2x 3  6.1x  2; [2, 3] 2. f(x)  2.1x 4  3.2x 3  4.1x 2  3x  4; [1, 2] 3. f 1x2 

2x 3  3x 2  1 ; 33, 14 x 2  2x  8

4. f 1x2  1x1x 3  4 2 2; 30.5, 14 5. f(x)  ex ln(x 2  1); [2, 2] 6. f(x)  x 2e2x; [1, 1] 7. f 1x2 

x3  1 ; 31, 3 4 x2

8. f 1x2 

x3  x2  1 ; 31, 3 4 x2

9. USE OF DIESEL ENGINES Diesel engines are popular in cars in Europe. The percentage of new vehicles in Western Europe equipped with diesel engines is approximated by the function

f(t)  0.3t 4  2.58t 3  8.11t 2  7.71t  23.75

(0 t 4)

where t is measured in years, with t  0 corresponding to the beginning of 1996. a. Use a graphing utility to sketch the graph of f on [0, 4]  [0, 40]. b. What was the lowest percentage of new vehicles equipped with diesel engines for the period in question? Source: German Automobile Industry Association

10. DEMAND FOR ELECTRICITY The demand for electricity from 1 a.m. through 7 p.m. on August 1, 2006, in Boston is described by the function D(t)  11.3975t 3  285.991t 2  1467.73t  23,755 (0 t 18)

where D(t) is measured in megawatts (MW), with t  0 corresponding to 1 a.m. Driven overwhelmingly by airconditioning and refrigeration systems, the demand for electricity reached a new record high that day. Show that the demand for electricity did not exceed the system capacity of 31,000 MW, thus negating the necessity for imposing rolling blackouts if electricity demand were to exceed supply. Source: ISO New England (continued)

726

10 APPLICATIONS OF THE DERIVATIVE

11. SICKOUTS In a sickout by pilots of American Airlines in February 1999, the number of canceled flights from February 6 (t  0) through February 14 (t  8) is approximated by the function N(t)  1.2576t 4  26.357t 3  127.98t 2  82.3t  43 (0 t 8)

12. MODELING WITH DATA The following data gives the average account balance (in thousands of dollars) of a 401(k) investor from 1996 through 2002. Year Account Balance

where t is measured in days. The sickout ended after the union was threatened with millions of dollars of fines. a. Show that the number of canceled flights was increasing at the fastest rate on February 8. b. Estimate the maximum number of canceled flights in a day during the sickout. Source: Associated Press

1996 37.5

1997 40.8

1998 47.3

1999 55.5

2000 49.4

2001 43

2002 40

a. Use QuartReg to find a fourth-degree polynomial regression model for the data. Let t  0 correspond to 1996. b. Plot the graph of A, using the viewing window [0, 6]  [0, 60]. c. When was the average account balance lowest in the period under consideration? When was it highest? d. What were the lowest average account balance and the highest average account balance during the period under consideration? Source: Investment Company Institute

10.5 Optimization II Section 10.4 outlined how to find the solution to certain optimization problems in which the objective function is given. In this section, we consider problems in which we are required to first find the appropriate function to be optimized. The following guidelines will be useful for solving these problems. Guidelines for Solving Optimization Problems

1. Assign a letter to each variable mentioned in the problem. If appropriate, draw and label a figure. 2. Find an expression for the quantity to be optimized. 3. Use the conditions given in the problem to write the quantity to be optimized as a function f of one variable. Note any restrictions to be placed on the domain of f from physical considerations of the problem. 4. Optimize the function f over its domain using the methods of Section 10.4. In carrying out step 4, remember that if the function f to be optimized is continuous on a closed interval, then the absolute maximum and absolute minimum of f are, respectively, the largest and smallest values of f (x) on the set composed of the critical numbers of f and the endpoints of the interval. If the domain of f is not a closed interval, then we resort to the graphical method.

Note

Maximization Problems APPLIED EXAMPLE 1 Fencing a Garden A man wishes to have a rectangular-shaped garden in his backyard. He has 50 feet of fencing with which to enclose his garden. Find the dimensions for the largest garden he can have if he uses all of the fencing.

10.5 OPTIMIZATION II

727

Solution Step 1

Let x and y denote the dimensions (in feet) of two adjacent sides of the (x ) See page 139. garden (Figure 68) and let A denote its area. The area of the garden A  xy (1) 2

x Step 2

y FIGURE 68

Step 3

What is the maximum rectangular area that can be enclosed with 50 feet of fencing?

is the quantity to be maximized. The perimeter of the rectangle, (2x  2y) feet, must equal 50 feet. Therefore, we have the equation 2x  2y  50

Next, solving this equation for y in terms of x yields y  25  x

(2)

which, when substituted into Equation (1), gives A  x(25  x)  x 2  25x

Step 4

(Remember, the function to be optimized must involve just one variable.) Since the sides of the rectangle must be nonnegative, we must have x  0 and y  25  x  0; that is, we must have 0 x 25. Thus, the problem is reduced to that of finding the absolute maximum of A  f(x)  x 2  25x on the closed interval [0, 25]. Observe that f is continuous on [0, 25], so the absolute maximum value of f must occur at the endpoint(s) of the interval or at the critical number(s) of f. The derivative of the function A is given by A  f (x)  2x  25

Setting A  0 gives 2x  25  0

or 12.5, as the critical number of A. Next, we evaluate the function A  f(x) at x  12.5 and at the endpoints x  0 and x  25 of the interval [0, 25], obtaining f(0)  0

f(12.5)  156.25

f(25)  0

We see that the absolute maximum value of the function f is 156.25. From Equation (2) we see that y  12.5 when x  12.5. Thus, the garden of maximum area (156.25 square feet) is a square with sides of length 12.5 feet.

APPLIED EXAMPLE 2 Packaging By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, the cardboard may be turned into an open box. If the cardboard is 16 inches long and 10 inches wide, find the dimensions of the box that will yield the maximum volume. Solution Step 1

Let x denote the length (in inches) of one side of each of the identical squares to be cut out of the cardboard (Figure 69) and let V denote the volume of the resulting box.

728

10 APPLICATIONS OF THE DERIVATIVE x

x

x

x

10 10 – 2x

x

x

x x

16 – 2x

– 16

2x

The dimensions of the open box are (16  2x) inches by (10  2x) inches by x inches.

x

– 10

FIGURE 69

2x

16

Step 2

The dimensions of the box are (16  2x) inches by (10  2x) inches by x inches. Therefore, its volume (in cubic inches), V  (16  2x)(10  2x)x  4(x 3  13x 2  40x)

Step 3

Expand the expression.

is the quantity to be maximized. Since each side of the box must be nonnegative, x must satisfy the inequalities x  0, 16  2x  0, and 10  2x  0. This set of inequalities is satisfied if 0 x 5. Thus, the problem at hand is equivalent to that of finding the absolute maximum of V  f(x)  4(x 3  13x 2  40x)

Step 4

on the closed interval [0, 5]. Observe that f is continuous on [0, 5], so the absolute maximum value of f must be attained at the endpoint(s) or at the critical number(s) of f. Differentiating f(x), we obtain f (x)  4(3x 2  26x  40)  4(3x  20)(x  2)

Upon setting f (x)  0 and solving the resulting equation for x, we obtain x  203 or x  2. Since 203 lies outside the interval [0, 5], it is no longer considered, and we are interested only in the critical number 2 of f. Next, evaluating f(x) at x  0, x  5 (the endpoints of the interval [0, 5]), and x  2, we obtain f(0)  0

f(2)  144

f(5)  0

Thus, the volume of the box is maximized by taking x  2. The dimensions of the box are 12  6  2, and the volume is 144 cubic inches.

Exploring with

TECHNOLOGY Refer to Example 2. 1. Use a graphing utility to plot the graph of f(x)  4(x 3  13x 2  40x)

using the viewing window [0, 5]  [0, 150]. Explain what happens to f(x) as x increases from x  0 to x  5 and give a physical interpretation. 2. Using ZOOM and TRACE, find the absolute maximum of f on the interval [0, 5] and thus verify the solution for Example 2 obtained analytically.

10.5 OPTIMIZATION II

729

APPLIED EXAMPLE 3 Optimal Subway Fare A city’s Metropolitan Transit Authority (MTA) operates a subway line for commuters from a certain suburb to the downtown metropolitan area. Currently, an average of 6000 passengers a day take the trains, paying a fare of $3.00 per ride. The board of the MTA, contemplating raising the fare to $3.50 per ride in order to generate a larger revenue, engages the services of a consulting firm. The firm’s study reveals that for each $.50 increase in fare, the ridership will be reduced by an average of 1000 passengers a day. Thus, the consulting firm recommends that MTA stick to the current fare of $3.00 per ride, which already yields a maximum revenue. Show that the consultants are correct. Solution Step 1

Let x denote the number of passengers per day, p denote the fare per ride, (x ) See page 140. and R be MTA’s revenue. 2

Step 2

To find a relationship between x and p, observe that the given data imply that when x  6000, p  3, and when x  5000, p  3.50. Therefore, the points (6000, 3) and (5000, 3.50) lie on a straight line. (Why?) To find the linear relationship between p and x, use the point-slope form of the equation of a straight line. Now, the slope of the line is m

3.50  3  0.0005 5000  6000

Therefore, the required equation is p  3  0.0005(x  6000)  0.0005x  3 p  0.0005x  6

Therefore, the revenue R  f(x)  xp  0.0005x 2  6x

Number of riders  unit fare

is the quantity to be maximized. Step 3

Since both p and x must be nonnegative, we see that 0 x 12,000, and the problem is that of finding the absolute maximum of the function f on the closed interval [0, 12,000].

Step 4

Observe that f is continuous on [0, 12,000]. To find the critical number of R, we compute f (x)  0.001x  6

and set it equal to zero, giving x  6000. Evaluating the function f at x  6000, as well as at the endpoints x  0 and x  12,000, yields

y ($) Absolute maximum

20,000 16,000

f(0)  0

y = R(x)

12,000

f(6000)  18,000

8,000

f(12,000)  0

4,000 x 6,000

12,000

FIGURE 70 f has an absolute maximum of 18,000 when x  6000.

We conclude that a maximum revenue of $18,000 per day is realized when the ridership is 6000 per day. The optimum price of the fare per ride is therefore $3.00, as recommended by the consultants. The graph of the revenue function R is shown in Figure 70.

730

10 APPLICATIONS OF THE DERIVATIVE

Minimization Problems APPLIED EXAMPLE 4 Packaging Betty Moore Company requires that its corned beef hash containers have a capacity of 54 cubic inches, have the shape of right circular cylinders, and be made of aluminum. Determine the radius and height of the container that requires the least amount of metal. Solution Step 1

r

Step 2

h

FIGURE 71 We want to minimize the amount of material used to construct the container.

Step 3

Let the radius and height of the container be r and h inches, respectively, and let S denote the surface area of the container (Figure 71). The amount of aluminum used to construct the container is given by the total surface area of the cylinder. Now, the area of the base and the top of the cylinder are each pr 2 square inches and the area of the side is 2prh square inches. Therefore, S  2pr 2  2prh

(3)

is the quantity to be minimized. The requirement that the volume of a container be 54 cubic inches implies that pr 2h  54

(4)

Solving Equation (4) for h, we obtain h

54 pr 2

(5)

which, when substituted into (3), yields S  2pr 2  2pr a  2pr 2 

54 b pr 2

108 r

Clearly, the radius r of the container must satisfy the inequality r  0. The problem now is reduced to finding the absolute minimum of the function S  f(r) on the interval (0, ). y

Step 4

Square inches

200

Using the curve-sketching techniques of Section 10.3, we obtain the graph of f in Figure 72. To find the critical number of f, we compute

150

S ¿  4pr 

100

108 r2

and solve the equation S  0 for r:

50 r 1

2

3 4 Inches

FIGURE 72 The total surface area of the right cylindrical container is graphed as a function of r.

5

4pr 

108 0 r2

4pr 3  108  0 r3  r

27 p 3 3 2 p

2

Next, let’s show that this value of r gives rise to the absolute minimum of f. To show this, we first compute S–  4p 

216 r3

(6)

10.5 OPTIMIZATION II

PORTFOLIO

731

Gary Li

A

s one of the leading financial institutions in the world, JPMorgan Chase & Co. depends on a wide range of mathematical disciplines from statistics to linear programming to calculus. Whether assessing the credit worthiness of a borrower, recommending portfolio investments, or pricing an exotic derivative, quantitative understanding is a critical tool in serving the financial needs of clients. I work in the Fixed-Income Derivatives Strategy group. A derivative in finance is an instrument whose value depends on the price of some other underlying instrument. A simple type of derivative is the forward contract where two parties agree to a future trade at a specified price. In agriculture, for instance, farmers will often pledge their crops for sale to buyers at an agreed price before even planting the harvest. Depending on the weather, demand, and other factors, the actual price may turn out higher or lower. Either the buyer or seller of the forward contract benefits accordingly. The value of the contract changes one-for-one with the actual price. In derivatives lingo, we borrow from calculus and say forward contracts have a delta of 1. Nowadays, the bulk of derivatives deal with interest rate rather than agricultural risk. The value of any asset with fixed payments over time varies with interest rates. With trillions of dollars in this form, especially government bonds and mortgages, fixed-income derivatives are vital to the

economy. As a strategy group, our job is to track and anticipate key drivers and developments in the market using, in significant part, quantitative analysis. Some of the derivatives that we look at are the forward kind such as interest-rate swaps, where over time you receive fixed-rate payments in exchange for paying a floating rate or vice versa. A whole other class of derivatives where statistics and calculus are especially relevant are options. Whereas forward contracts bind both parties to a future trade, options give the holder the right but not the obligation to trade at a specified time and price. Similar to an insurance policy, the holder of the option pays an upfront premium in exchange for potential gain. Solving this pricing problem requires statistics, stochastic calculus, and enough insight to win a Nobel Prize. Fortunately for us, this was taken care of by Fischer Black, Myron Scholes, and Robert Merton in the early 1970s (including the 1997 Nobel Prize in Economics for Scholes and Merton). The Black–Scholes differential equation was the first accurate options pricing model, making possible the rapid growth of the derivatives market. Black–Scholes and the many derivatives of it continue to be used to this day.

© AA World Travel Library/Alamy

TITLE Associate INSTITUTION JPMorgan Chase

3

Since S   0 for r  3/ 2p, the second derivative test implies that the value of r in Equation (6) gives rise to a relative minimum of f. Finally, this relative minimum of f is also the absolute minimum of f since f is always concave upward (S   0 for all r  0). To find the height of the given container, we substitute the value of r given in (6) into (5). Thus, h

54  pr 2

54 3 2 p a 1/3 b p



54p 2/3 1p29



6 6  3 p1/3 2p

 2r

We conclude that the required container has a radius of approximately 2 inches and a height of approximately 4 inches, or twice the size of the radius.

732

10 APPLICATIONS OF THE DERIVATIVE

An Inventory Problem One problem faced by many companies is that of controlling the inventory of goods carried. Ideally, the manager must ensure that the company has sufficient stock to meet customer demand at all times. At the same time, she must make sure that this is accomplished without overstocking (incurring unnecessary storage costs) and also without having to place orders too frequently (incurring reordering costs). APPLIED EXAMPLE 5 Inventory Control and Planning Dixie Import-Export is the sole agent for the Excalibur 250-cc motorcycle. Management estimates that the demand for these motorcycles is 10,000 per year and that they will sell at a uniform rate throughout the year. The cost incurred in ordering each shipment of motorcycles is $10,000, and the cost per year of storing each motorcycle is $200. Dixie’s management faces the following problem: Ordering too many motorcycles at one time ties up valuable storage space and increases the storage cost. On the other hand, placing orders too frequently increases the ordering costs. How large should each order be, and how often should orders be placed, to minimize ordering and storage costs? Inventory level x x 2

Average inventory Time

FIGURE 73

Solution Let x denote the number of motorcycles in each order (the lot size). Then, assuming that each shipment arrives just as the previous shipment has been sold, the average number of motorcycles in storage during the year is x/2. You can see that this is the case by examining Figure 73. Thus, Dixie’s storage cost for the year is given by 200(x/2), or 100x dollars. Next, since the company requires 10,000 motorcycles for the year and since each order is for x motorcycles, the number of orders required is

As each lot is depleted, the new lot arrives. The average inventory level is x/2 if x is the lot size.

10,000 x

This gives an ordering cost of 10,000 a

100,000,000 10,000 b  x x

dollars for the year. Thus, the total yearly cost incurred by Dixie, which includes the ordering and storage costs attributed to the sale of these motorcycles, is given by C1x2  100x 

100,000,000 x

The problem is reduced to finding the absolute minimum of the function C in the interval (0, 10,000]. To accomplish this, we compute C¿1x2  100 

100,000,000 x2

Setting C(x)  0 and solving the resulting equation, we obtain x  1000. Since the number 1000 is outside the domain of the function C, it is rejected, leaving 1000 as the only critical number of C. Next, we find

C

C–1x2  200,000

C(x) = 100x +

100,000,000 x

1,000 2,000 3,000

FIGURE 74 C has an absolute minimum at (1000, 200,000).

x

200,000,000 x3

Since C(1000)  0, the second derivative test implies that the critical number 1000 is a relative minimum of the function C (Figure 74). Also, since C (x)  0 for all x in (0, 10,000], the function C is concave upward everywhere so that x  1000 also gives the absolute minimum of C. Thus, to minimize the ordering and storage costs, Dixie should place 10,000/1000, or 10, orders a year, each for a shipment of 1000 motorcycles.

10.5 OPTIMIZATION II

733

10.5 Self-Check Exercises 1. A man wishes to have an enclosed vegetable garden in his backyard. If the garden is to be a rectangular area of 300 ft2, find the dimensions of the garden that will minimize the amount of fencing needed. 2. The demand for the Super Titan tires is 1,000,000/year. The setup cost for each production run is $4000, and the manufacturing cost is $20/tire. The cost of storing each tire

over the year is $2. Assuming uniformity of demand throughout the year and instantaneous production, determine how many tires should be manufactured per production run in order to keep the production cost to a minimum. Solutions to Self-Check Exercises 10.5 can be found on page 737.

10.5 Concept Questions 1. If the domain of a function f is not a closed interval, how would you find the absolute extrema of f, if they exist?

2. Refer to Example 4 (page 730). In the solution given in the example, we solved for h in terms of r, resulting in a function of r, which we then optimized with respect to r. Write S in terms of h and re-solve the problem. Which choice is better?

10.5 Exercises 1. Find the dimensions of a rectangle with a perimeter of 100 ft that has the largest possible area. 2. Find the dimensions of a rectangle of area 144 sq ft that has the smallest possible perimeter. 3. ENCLOSING THE LARGEST AREA The owner of the Rancho Los Feliz has 3000 yd of fencing with which to enclose a rectangular piece of grazing land along the straight portion of a river. If fencing is not required along the river, what are the dimensions of the largest area that he can enclose? What is this area? 4. ENCLOSING THE LARGEST AREA Refer to Exercise 3. As an alternative plan, the owner of the Rancho Los Feliz might use the 3000 yd of fencing to enclose the rectangular piece of grazing land along the straight portion of the river and then subdivide it by means of a fence running parallel to the sides. Again, no fencing is required along the river. What are the dimensions of the largest area that can be enclosed? What is this area? (See the accompanying figure.)

flowers. One side will be formed by the external wall of the store, two sides will be constructed of pine boards, and the fourth side will be made of galvanized steel fencing. If the pine board fencing costs $6/running foot and the steel fencing costs $3/running foot, determine the dimensions of the enclosure that can be erected at minimum cost.

Wood

Wood

Steel

6. PACKAGING By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. If the cardboard is 15 in. long and 8 in. wide, find the dimensions of the box that will yield the maximum volume.

x

y

x

5. MINIMIZING CONSTRUCTION COSTS The management of the UNICO department store has decided to enclose an 800-ft2 area outside the building for displaying potted plants and

7. METAL FABRICATION If an open box is made from a tin sheet 8 in. square by cutting out identical squares from each corner and bending up the resulting flaps, determine the dimensions of the largest box that can be made. 8. MINIMIZING PACKAGING COSTS If an open box has a square base and a volume of 108 in.3 and is constructed from a tin sheet, find the dimensions of the box, assuming a minimum amount of material is used in its construction.

734

10 APPLICATIONS OF THE DERIVATIVE

9. MINIMIZING PACKAGING COSTS What are the dimensions of a closed rectangular box that has a square cross section, a capacity of 128 in.3, and is constructed using the least amount of material?

13. PARCEL POST REGULATIONS Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 108 in. Find the dimensions of the cylindrical package of greatest volume that may be sent via priority mail. What is the volume of such a package? Compare with Exercise 11. Hint: The length plus the girth is 2pr  l.

y

x r

x

10. MINIMIZING PACKAGING COSTS A rectangular box is to have a square base and a volume of 20 ft 3. If the material for the base costs 30¢/square foot, the material for the sides costs 10¢/square foot, and the material for the top costs 20¢/square foot, determine the dimensions of the box that can be constructed at minimum cost. (Refer to the figure for Exercise 9.) 11. PARCEL POST REGULATIONS Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 108 in. Find the dimensions of a rectangular package that has a square cross section and the largest volume that may be sent via priority mail. What is the volume of such a package? Hint: The length plus the girth is 4x  h (see the accompanying figure).

14. MINIMIZING COSTS For its beef stew, Betty Moore Company uses aluminum containers that have the form of right circular cylinders. Find the radius and height of a container if it has a capacity of 36 in.3 and is constructed using the least amount of metal. 15. PRODUCT DESIGN The cabinet that will enclose the Acrosonic model D loudspeaker system will be rectangular and will have an internal volume of 2.4 ft 3. For aesthetic reasons, it has been decided that the height of the cabinet is to be 1.5 times its width. If the top, bottom, and sides of the cabinet are constructed of veneer costing 40¢/square foot and the front (ignore the cutouts in the baffle) and rear are constructed of particle board costing 20¢/square foot, what are the dimensions of the enclosure that can be constructed at a minimum cost? 16. DESIGNING A NORMAN WINDOW A Norman window has the shape of a rectangle surmounted by a semicircle (see the accompanying figure). If a Norman window is to have a perimeter of 28 ft, what should its dimensions be in order to allow the maximum amount of light through the window?

x h

x

12. BOOK DESIGN A book designer has decided that the pages of a book should have 1-in. margins at the top and bottom and 12-in. margins on the sides. She further stipulated that each page should have an area of 50 in.2 (see the accompanying figure). Determine the page dimensions that will result in the maximum printed area on the page. x

1 2

l

y

in.

1 in.

x y

17. OPTIMAL CHARTER-FLIGHT FARE If exactly 200 people sign up for a charter flight, Leisure World Travel Agency charges $300/person. However, if more than 200 people sign up for the flight (assume this is the case), then each fare is reduced by $1 for each additional person. Determine how many passengers will result in a maximum revenue for the travel agency. What is the maximum revenue? What would be the fare per passenger in this case? Hint: Let x denote the number of passengers above 200. Show that the revenue function R is given by R(x)  (200  x)(300  x).

10.5 OPTIMIZATION II

18. MAXIMIZING YIELD An apple orchard has an average yield of 36 bushels of apples/tree if tree density is 22 trees/acre. For each unit increase in tree density, the yield decreases by 2 bushels/tree. How many trees should be planted in order to maximize the yield? 19. CHARTER REVENUE The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $600/person/ day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then each fare is reduced by $4 for each additional passenger. Assuming at least 20 people sign up for the cruise, determine how many passengers will result in the maximum revenue for the owner of the yacht. What is the maximum revenue? What would be the fare/passenger in this case? 20. PROFIT OF A VINEYARD Phillip, the proprietor of a vineyard, estimates that the first 10,000 bottles of wine produced this season will fetch a profit of $5/bottle. But if more than 10,000 bottles were produced, then the profit/bottle for the entire lot would drop by $0.0002 for each additional bottle sold. Assuming at least 10,000 bottles of wine are produced and sold, what is the maximum profit? 21. OPTIMAL SPEED OF A TRUCK A truck gets 600/x mpg when driven at a constant speed of x mph (between 50 and 70 mph). If the price of fuel is $3/gallon and the driver is paid $18/hour, at what speed between 50 and 70 mph is it most economical to drive? 22. MINIMIZING COSTS Suppose the cost incurred in operating a cruise ship for one hour is a  b√ 3 dollars, where a and b are positive constants and √ is the ship’s speed in miles per hour. At what speed should the ship be operated between two ports, to minimize the cost? 23. STRENGTH OF A BEAM A wooden beam has a rectangular cross section of height h in. and width w in. (see the accompanying figure). The strength S of the beam is directly proportional to its width and the square of its height. What are the dimensions of the cross section of the strongest beam that can be cut from a round log of diameter 24 in.?

735

r

h

25. MINIMIZING COST OF LAYING CABLE In the following diagram, S represents the position of a power relay station located on a straight coast, and E shows the location of a marine biology experimental station on an island. A cable is to be laid connecting the relay station with the experimental station. If the cost of running the cable on land is $1.50/running foot and the cost of running the cable under water is $2.50/running foot, locate the point P that will result in a minimum cost (solve for x).

Island

E 3000' P Land

x

S

10,000 – x 10,000'

26. STORING RADIOACTIVE WASTE A cylindrical container for storing radioactive waste is to be constructed from lead and have a thickness of 6 in. (see the accompanying figure). If the volume of the outside cylinder is to be 16p ft3, find the radius and the height of the inside cylinder that will result in a container of maximum storage capacity. r

Hint: S  kh2 w, where k is a constant of proportionality.

6 in.

h

24 in.

h w

24. DESIGNING A GRAIN SILO A grain silo has the shape of a right circular cylinder surmounted by a hemisphere (see the accompanying figure). If the silo is to have a capacity of 504p ft3, find the radius and height of the silo that requires the least amount of material to construct. Hint: The volume of the silo is p r 2h  23pr 3, and the surface area (including the floor) is p (3r 2  2rh).

6 in.

Hint: Show that the storage capacity (inside volume) is given by V 1r2  pr 2 c

16

1r  12 2 2

 1d

10 r 72 2

736

10 APPLICATIONS OF THE DERIVATIVE

27. FLIGHTS OF BIRDS During daylight hours, some birds fly more slowly over water than over land because some of their energy is expended in overcoming the downdrafts of air over open bodies of water. Suppose a bird that flies at a constant speed of 4 mph over water and 6 mph over land starts its journey at the point E on an island and ends at its nest N on the shore of the mainland, as shown in the accompanying figure. Find the location of the point P that allows the bird to complete its journey in the minimum time (solve for x).

Island

E 3 mi P Land

N

x

12 – x 12 mi

28. MINIMIZING TRAVEL TIME A woman is on a lake in a row boat located 1 mi from the closest point P of a straight shoreline (see the accompanying figure). She wishes to get to point Q, 10 mi along the shore from P, by rowing to a point R between P and Q and then walking the rest of the distance. If she can row at a speed of 2 mph and walk at a speed of 3 mph, how should she pick the point R in order to get to Q as quickly as possible? How much time does she require?

31. INVENTORY CONTROL AND PLANNING McDuff Preserves expects to bottle and sell 2,000,000 32-oz jars of jam at a uniform rate throughout the year. The company orders its containers from Consolidated Bottle Company. The cost of ordering a shipment of bottles is $200, and the cost of storing each empty bottle for a year is $.40. How many orders should McDuff place per year and how many bottles should be in each shipment if the ordering and storage costs are to be minimized? (Assume that each shipment of bottles is used up before the next shipment arrives.) 32. INVENTORY CONTROL AND PLANNING Neilsen Cookie Company sells its assorted butter cookies in containers that have a net content of 1 lb. The estimated demand for the cookies is 1,000,000 1-lb containers. The setup cost for each production run is $500, and the manufacturing cost is $.50 for each container of cookies. The cost of storing each container of cookies over the year is $.40. Assuming uniformity of demand throughout the year and instantaneous production, how many containers of cookies should Neilsen produce per production run in order to minimize the production cost? Hint: Following the method of Example 5, show that the total production cost is given by the function

10 mi P

30. INVENTORY CONTROL AND PLANNING The demand for motorcycle tires imported by Dixie Import-Export is 40,000/year and may be assumed to be uniform throughout the year. The cost of ordering a shipment of tires is $400, and the cost of storing each tire for a year is $2. Determine how many tires should be in each shipment if the ordering and storage costs are to be minimized. (Assume that each shipment arrives just as the previous one has been sold.)

R

Q

C1x2 

1 mi

500,000,000 x

 0.2x  500,000

Then minimize the function C on the interval (0, 1,000,000).

29. RACETRACK DESIGN The accompanying figure depicts a racetrack with ends that are semicircular in shape. The length of the track is 1760 ft Ó13 miÔ. Find l and r so that the area enclosed by the rectangular region of the racetrack is as large as possible. What is the area enclosed by the track in this case?

33. INVENTORY CONTROL AND PLANNING A company expects to sell D units of a certain product per year. Sales are assumed to be at a steady rate with no shortages allowed. Each time an order for the product is placed, an ordering cost of K dollars is incurred. Each item costs p dollars, and the holding cost is h dollars per item per year. a. Show that the inventory cost (the combined ordering cost, purchasing cost, and holding cost) is C1x2 

r

KD hx  pD  x 2

1x  02

where x is the order quantity (the number of items in each order). b. Use the result of part (a) to show that the inventory cost is minimized if x

2KD B h

This quantity is called the economic order quantity (EOQ). l

10.5 OPTIMIZATION II

34. INVENTORY CONTROL AND PLANNING Refer to Exercise 33. The Camera Store sells 960 Yamaha A35 digital cameras per year. Each time an order for cameras is placed with the manufacturer, an ordering cost of $10 is incurred. The store pays $80 for each camera, and the cost for holding a camera (mainly due to the opportunity cost incurred in tying up

737

capital in inventory) is $12/year. Assume that the cameras sell at a uniform rate and no shortages are allowed. a. What is the EOQ? b. How many orders will be placed each year? c. What is the interval between orders?

10.5 Solutions to Self-Check Exercises 1. Let x and y (measured in feet) denote the length and width of the rectangular garden.

y

x

Since the area is to be 300 ft2, we have xy  300

Next, the amount of fencing to be used is given by the perimeter, and this quantity is to be minimized. Thus, we want to minimize 2x  2y

or, since y  300/x (obtained by solving for y in the first equation), we see that the expression to be minimized is 300 b f 1x2  2x  2 a x 600  2x  x

600 x2

Setting f (x)  0 yields x  1300 or x  1300. We consider only the critical number 1300 since 1300 lies outside the interval (0, ). We then compute f –1x2 

2. Let x denote the number of tires in each production run. Then, the average number of tires in storage is x/2, so the storage cost incurred by the company is 2(x/2), or x dollars. Next, since the company needs to manufacture 1,000,000 tires for the year in order to meet the demand, the number of production runs is 1,000,000/x. This gives setup costs amounting to 4000 a

1,000,000 4,000,000,000 b  x x

dollars for the year. The total manufacturing cost is $20,000,000. Thus, the total yearly cost incurred by the company is given by C 1x2  x 

4,000,000,000  20,000,000 x

Differentiating C(x), we find C ¿1x2  1 

for positive values of x. Now f ¿1x2  2 

the second derivative test implies that a relative minimum of f occurs at x  1300. In fact, since f (x)  0 for all x in (0, ), we conclude that x  1300 gives rise to the absolute minimum of f. The corresponding value of y, obtained by substituting this value of x into the equation xy  300, is y  1300. Therefore, the required dimensions of the vegetable garden are approximately 17.3 ft  17.3 ft.

1200 x3

Since f (300)  0

4,000,000,000 x2

Setting C(x)  0 gives 63,246 as the critical number in the interval (0, 1,000,000). Next, we find C–1x2 

8,000,000,000 x3

Since C (x)  0 for all x  0, we see that C is concave upward for all x  0. Furthermore, C (63,246)  0 implies that x  63,246 gives rise to a relative minimum of C (by the second derivative test). Since C is always concave upward for x  0, x  63,246 gives the absolute minimum of C. Therefore, the company should manufacture 63,246 tires in each production run.

738

10 APPLICATIONS OF THE DERIVATIVE

CHAPTER 10 Summary of Principal Terms TERMS increasing function (658) decreasing function (658) relative maximum (663) relative minimum (664) relative extrema (664) critical number (665)

first derivative test (665) concave upward (678) concave downward (678) inflection point (681) second derivative test (685)

vertical asymptote (698) horizontal asymptote (700) absolute extrema (712) absolute maximum value (712) absolute minimum value (712)

CHAPTER 10 Concept Review Questions Fill in the blanks.

1. a. A function f is increasing on an interval I, if for any two numbers x1 and x2 in I, x1 x2 implies that _____. b. A function f is decreasing on an interval I, if for any two numbers x1 and x2 in I, x1 x2 implies that _____. 2. a. If f is differentiable on an open interval (a, b) and f (x)  0 on (a, b), then f is _____ on (a, b). b. If f is differentiable on an open interval (a, b) and _____ on (a, b), then f is decreasing on (a, b). c. If f (x)  0 for each value of x in the interval (a, b), then f is _____ on (a, b). 3. a. A function f has a relative maximum at c if there exists an open interval (a, b) containing c such that _____ for all x in (a, b). b. A function f has a relative minimum at c if there exists an open interval (a, b) containing c such that _____ for all x in (a, b). 4. a. A critical number of a function f is any number in the _____ of f at which f (c) _____ or f (c) does not _____. b. If f has a relative extremum at c, then c must be a/an _____ _____ of f. c. If c is a critical number of f, then f may or may not have a/an _____ _____ at c. 5. a. A differentiable function f is concave upward on an interval I if _____ is increasing on I. b. If f has a second derivative on an open interval I and f (x) _____ on I, then the graph of f is concave upward on I.

c. If the graph of a continuous function f has a tangent line at P(c, f (c)) and the graph of f changes _____ at P, then P is called an inflection point of the graph of f. d. Suppose f has a continuous second derivative on an interval (a, b), containing a critical number c of f. If f (c) 0, then f has a/an _____ _____ at c. If f (c)  0, then f may or may not have a/an _____ _____ at c. 6. The line x  a is a vertical asymptote of the graph f if at least one of the following is true: lim f 1x2  _____ or xSa lim f 1x2  _____. xSa

7. For a rational function f 1x2 

P1x2

, the line x  a is a Q1x2 vertical asymptote of the graph of f if Q(a)  _____ but P(a)  _____.

8. The line y  b is a horizontal asymptote of the graph of a function f if either lim f 1x2  _____ or lim f 1x 2  xS xS _____. 9. a. A function f has an absolute maximum at c if _____ for all x in the domain D of f. The number f (c) is called the _____ _____ _____ of f on D. b. A function f has a relative minimum at c if _____ for all values of x in some _____ _____ containing c. 10. The extreme value theorem states that if f is _____ on the closed interval [a, b], then f has both a/an _____ maximum value and a/an _____ minimum value on [a, b].

CHAPTER 10 Review Exercises In Exercises 1–12, (a) find the intervals where the given function f is increasing and where it is decreasing, (b) find the relative extrema of f, (c) find the intervals where f is concave upward and where it is concave downward, and (d) find the inflection points, if any, of f.

1 1. f (x)  x 3  x 2  x  6 3 2. f(x)  (x  2)

3

4. f(x)  x 

3. f (x)  x  2x

2

5. f(x) 

x2 x1

6. f(x)  2x  1

7. f (x)  (1  x)1/3

8. f(x)  x 2x  1

9. f(x) 

10. f(x)  4

4 x

1 1  x2

12. f(x)  x 2 ln x

2x x1

11. f (x)  (4  x)e x

REVIEW EXERCISES

In Exercises 13–22, obtain as much information as possible on each of the given functions. Then use this information to sketch the graph of the function.

13. f (x)  x 2  5x  5 14. f(x)  2x 2  x  1 15. t(x)  2x 3  6x 2  6x  1

17. h(x)  x 2x  2 19. f (x) 

x2 x2

18. h(x) 

2x 1  x2

20. f (x)  x 

21. f (x)  xe2x

1 x

22. f (x)  x2  ln x

In Exercises 23–26, find the horizontal and vertical asymptotes of the graphs of the given functions. Do not sketch the graphs.

23. f (x) 

1 2x  3

24. f(x) 

2x x1

25. f (x) 

5x x  2x  8

26. f(x) 

x2  x x1x  12

2

In Exercises 27–38, find the absolute maximum value and the absolute minimum value, if any, of the given function.

27. f (x)  2x 2  3x  2

28. t(x)  x 2/3

29. t(t)  225  t 2 1 30. f(x)  x 3  x 2  x  1 on [0, 2] 3 31. h(t)  t 3  6t 2 on [2, 5] 32. t(x) 

x on [0, 5] 2 x 1

33. f (x)  x 

1 on [1, 3] x

34. h(t)  8t 

1 on [1, 3] t2

To maximize its monthly profits, what should be Odyssey’s monthly advertising budget? 40. ONLINE HOTEL RESERVATIONS The online lodging industry is expected to grow dramatically. In a study conducted in 1999, analysts projected the U.S. online travel spending for lodging to be approximately f(t)  0.157t 2  1.175t  2.03

1 16. t(x)  x 3  x 2  x  3 3

35. f (x)  tet on [2, 2] ln t 36. t(t)  on [1, 2] t 37. f(s)  s 21  s 2 on [1, 1] x2 38. f(x)  on [1, 3] x1 39. MAXIMIZING PROFIT Odyssey Travel Agency’s monthly profit (in thousands of dollars) depends on the amount of money x (in thousands of dollars) spent on advertising each month according to the rule P(x)  x 2  8x  20

739

(0 t 6)

billion dollars, where t is measured in years, with t  0 corresponding to 1999. a. Show that f is increasing on the interval (0, 6). b. Show that the graph of f is concave upward on (0, 6). c. What do your results from parts (a) and (b) tell you about the growth of online travel spending over the years in question? Source: International Data Corp.

41. SALES OF CAMERA PHONES Camera phones, virtually nonexistent a few years ago, are quickly gaining in popularity. The function N(t)  8.125t 2  24.625t  18.375

(0 t 3)

gives the projected worldwide shipments of camera phones (in millions of units) in year t, with t  0 corresponding to 2002. a. Find N (t). What does this say about the sales of camera phones between 2002 and 2005? b. Find N (t). What does this say about the rate of the rate of sales of camera phones between 2002 and 2005? Source: In-Stat/MDR

42. INDEX OF ENVIRONMENTAL QUALITY The Department of the Interior of an African country began to record an index of environmental quality to measure progress or decline in the environmental quality of its wildlife. The index for the years 1998 through 2008 is approximated by the function I1t2 

50t 2  600 t 2  10

10 t 10 2

a. Compute I(t) and show that I(t) is decreasing on the interval (0, 10). b. Compute I (t). Study the concavity of the graph of I. c. Sketch the graph of I. d. Interpret your results. 43. MAXIMIZING PROFIT The weekly demand for DVDs manufactured by Herald Media Corporation is given by p  0.0005x 2  60

where p denotes the unit price in dollars and x denotes the quantity demanded. The weekly total cost function associated with producing these discs is given by C(x)  0.001x 2  18x  4000

where C(x) denotes the total cost (in dollars) incurred in pressing x discs. Find the production level that will yield a maximum profit for the manufacturer. Hint: Use the quadratic formula.

740

10 APPLICATIONS OF THE DERIVATIVE

44. MAXIMIZING PROFIT The estimated monthly profit (in dollars) realizable by Cannon Precision Instruments for manufacturing and selling x units of its model M1 digital camera is P(x)  0.04x 2  240x  10,000

To maximize its profits, how many cameras should Cannon produce each month? 45. MINIMIZING AVERAGE COST The total monthly cost (in dollars) incurred by Carlota Music in manufacturing x units of its Professional Series guitars is given by the function C(x)  0.001x 2  100x  4000

a. Find the average cost function  C. b. Determine the production level that will result in the smallest average production cost. 46. WORKER EFFICIENCY The average worker at Wakefield Avionics can assemble N(t)  2t 3  12t 2  2t

(0 t 4)

ready-to-fly radio-controlled model airplanes t hr into the 8 a.m. to 12 noon morning shift. At what time during this shift is the average worker performing at peak efficiency? 47. SENIOR WORKFORCE The percentage of women 65 yr and older in the workforce from 1970 through the year 2000 is approximated by the function P(t)  0.0002t 3  0.018t 2  0.36t  10

(0 t 30)

where t is measured in years, with t  0 corresponding to the beginning of 1970. a. Find the interval where P is decreasing and the interval where P is increasing. b. Find the absolute minimum of P. c. Interpret the results of parts (a) and (b). Source: U.S. Census Bureau

48. SPREAD OF A CONTAGIOUS DISEASE The incidence (number of new cases/day) of a contagious disease spreading in a population of M people is given by R(x)  kx (M  x)

where k is a positive constant and x denotes the number of people already infected. Show that the incidence R is greatest when half the population is infected.

49. MAXIMIZING THE VOLUME OF A BOX A box with an open top is to be constructed from a square piece of cardboard, 10 in. wide, by cutting out a square from each of the four corners and bending up the sides. What is the maximum volume of such a box? 50. MINIMIZING CONSTRUCTION COSTS A man wishes to construct a cylindrical barrel with a capacity of 32p ft 3. The cost/square foot of the material for the side of the barrel is half that of the cost/square foot for the top and bottom. Help him find the dimensions of the barrel that can be constructed at a minimum cost in terms of material used. 51. PACKAGING You wish to construct a closed rectangular box that has a volume of 4 ft 3. The length of the base of the box will be twice as long as its width. The material for the top and bottom of the box costs 30¢/square foot. The material for the sides of the box costs 20¢/square foot. Find the dimensions of the least expensive box that can be constructed. 52. INVENTORY CONTROL AND PLANNING Lehen Vinters imports a certain brand of beer. The demand, which may be assumed to be uniform, is 800,000 cases/year. The cost of ordering a shipment of beer is $500, and the cost of storing each case of beer for a year is $2. Determine how many cases of beer should be in each shipment if the ordering and storage costs are to be kept at a minimum. (Assume that each shipment of beer arrives just as the previous one has been sold.) 53. Let f (x)  x 2  ax  b. Determine the constants a and b so that f has a relative minimum at x  2 and the relative minimum value is 7. 54. Find the values of c so that the graph of f (x)  x 4  2x 3  cx2  2x  2 is concave upward everywhere. 55. Suppose that the point (a, f(a)) is an inflection point of the graph of y  f (x). Show that the number a gives rise to a relative extremum of the function f . 56. Let f 1x 2  e

x3  1 2

if x  0 if x  0

a. Compute f (x) and show that it does not change sign as we move across x  0. b. Show that f has a relative maximum at x  0. Does this contradict the first derivative test? Explain your answer.

CHAPTER 10 Before Moving On . . . x2 1. Find the interval(s) where f 1x 2  is increasing and 1x where it is decreasing. 2. Find the relative maxima and inflection point of the graph of f (x)  xex.

3. Find the intervals where f 1x 2  13 x 3  14 x 2  12 x  1 is concave upward, the intervals where f is concave downward, and the inflection point(s) of f.

4. Sketch the graph of f(x)  2x 3  9x 2  12x  1. 5. Find the absolute maximum and absolute minimum values of f(x)  2x 3  3x 2  1 on the interval [2, 3]. 6. An open bucket in the form of a right circular cylinder is to be constructed with a capacity of 1 ft3. Find the radius and height of the cylinder if the amount of material used is minimal.

11

INTEGRATION

D

IFFERENTIAL CALCULUS IS concerned with the problem

of finding the rate of change of one quantity with respect

to another. In this chapter, we begin the study of the other branch of calculus, known as integral calculus. Here we are interested in precisely the opposite problem: If we know the rate

the relationship between the two quantities? The principal tool used in the study of integral calculus is the antiderivative of a function, and we develop rules for antidifferentiation, or integration, as the process of finding the antiderivative is called. We also show that a link is established between differential and integral calculus—via the fundamental theorem of calculus.

© Anthony Dunn/Alamy

of change of one quantity with respect to another, can we find

How much electricity should be produced over the next 3 years to meet the projected demand? In Example 9, page 780, you will see how the current rate of consumption can be used to answer this question.

742

11 INTEGRATION

11.1 Antiderivatives and the Rules of Integration Antiderivatives Let’s return, once again, to the example involving the motion of the maglev (Figure 1).

s (ft)

FIGURE 1

0

A maglev moving along an elevated monorail track

16

4

36

3600

In Chapter 9, we discussed the following problem: If we know the position of the maglev at any time t, can we find its velocity at time t? As it turns out, if the position of the maglev is described by the position function f, then its velocity at any time t is given by f (t). Here f —the velocity function of the maglev—is just the derivative of f. Now, in this chapter, we will consider precisely the opposite problem: If we know the velocity of the maglev at any time t, can we find its position at time t? Stated another way, if we know the velocity function f  of the maglev, can we find its position function f ? To solve this problem, we need the concept of an antiderivative of a function.

Antiderivative

A function F is an antiderivative of f on an interval I if F(x)  f(x) for all x in I.

Thus, an antiderivative of a function f is a function F whose derivative is f. For example, F(x)  x 2 is an antiderivative of f(x)  2x because F¿1x2 

d 2 1x 2  2x  f 1x2 dx

and F(x)  x 3  2x  1 is an antiderivative of f(x)  3x 2  2 because F¿1x2 

d 3 1x  2x  12  3x 2  2  f 1x2 dx

EXAMPLE 1 Let F1x2  13 x 3  2x 2  x  1. Show that F is an antiderivative of f(x)  x 2  4x  1. Solution

Differentiating the function F, we obtain F¿1x2  x 2  4x  1  f 1x2

and the desired result follows. EXAMPLE 2 Let F(x)  x, G(x)  x  2, and H(x)  x  C, where C is a constant. Show that F, G, and H are all antiderivatives of the function f defined by f(x)  1.

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

Solution

743

Since d 1x2  1  f 1x2 dx d G¿1x2  1x  22  1  f 1x2 dx d H¿1x2  1x  C2  1  f 1x2 dx F¿1x2 

we see that F, G, and H are indeed antiderivatives of f. Example 2 shows that once an antiderivative G of a function f is known, then another antiderivative of f may be found by adding an arbitrary constant to the function G. The following theorem states that no function other than one obtained in this manner can be an antiderivative of f. (We omit the proof.)

y

F(x) = x + 3 (C = 3) F(x) = x + 2 (C = 2) F(x) = x + 1 (C = 1) F(x) = x (C = 0) F(x) = x – 1 (C = –1)

4 2 –4

x

2

FIGURE 2 The graphs of some antiderivatives of f (x)  1

y

2

F(x) = x 2

(C = 0)

F(x) = x 2 – 21

(

C = – 21

x –2

Returning to Example 2, we see that there are infinitely many antiderivatives of the function f(x)  1. We obtain each one by specifying the constant C in the function F(x)  x  C. Figure 2 shows the graphs of some of these antiderivatives for selected values of C. These graphs constitute part of a family of infinitely many parallel straight lines, each having a slope equal to 1. This result is expected since there are infinitely many curves (straight lines) with a given slope equal to 1. The antiderivatives F(x)  x  C (C, a constant) are precisely the functions representing this family of straight lines. EXAMPLE 3 Prove that the function G(x)  x 2 is an antiderivative of the function f(x)  2x. Write a general expression for the antiderivatives of f.

F(x) = x 2 + 1 (C = 1)

4

THEOREM 1 Let G be an antiderivative of a function f. Then, every antiderivative F of f must be of the form F(x)  G(x)  C, where C is a constant.

Since G(x)  2x  f(x), we have shown that G(x)  x 2 is an antiderivative of f(x)  2x. By Theorem 1, every antiderivative of the function f(x)  2x has the form F(x)  x 2  C, where C is some constant. The graphs of a few of the antiderivatives of f are shown in Figure 3.

Solution

)

2

FIGURE 3 The graphs of some antiderivatives of f (x)  2x

Exploring with

TECHNOLOGY Let f(x)  x 2  1. 1. Show that F1x2  13 x3  x  C, where C is an arbitrary constant, is an antiderivative of f. 2. Use a graphing utility to plot the graphs of the antiderivatives of f corresponding to C  2, C  1, C  0, C  1, and C  2 on the same set of axes, using the viewing window [4, 4]  [4, 4]. 3. If your graphing utility has the capability, draw the tangent line to each of the graphs in part 2 at the point whose x-coordinate is 2. What can you say about this family of tangent lines? 4. What is the slope of a tangent line in this family? Explain how you obtained your answer.

744

11 INTEGRATION

The Indefinite Integral The process of finding all antiderivatives of a function is called antidifferentiation, or integration. We use the symbol , called an integral sign, to indicate that the operation of integration is to be performed on some function f. Thus,

 f 1x2 dx  F1x2  C [read “the indefinite integral of f (x) with respect to x equals F(x) plus C ”] tells us that the indefinite integral of f is the family of functions given by F(x)  C, where F(x)  f (x). The function f to be integrated is called the integrand, and the constant C is called a constant of integration. The expression dx following the integrand f (x) reminds us that the operation is performed with respect to x. If the independent variable is t, we write  f (t) dt instead. In this sense both t and x are “dummy variables.” Using this notation, we can write the results of Examples 2 and 3 as

 1 dx  x  C

and

 2x dx  x 2  K

where C and K are arbitrary constants.

Basic Integration Rules Our next task is to develop some rules for finding the indefinite integral of a given function f. Because integration and differentiation are reverse operations, we discover many of the rules of integration by first making an “educated guess” at the antiderivative F of the function f to be integrated. Then this result is verified by demonstrating that F  f. Rule 1: The Indefinite Integral of a Constant

 k dx  kx  C

1k, a constant2

To prove this result, observe that F¿1x2 

d 1kx  C2  k dx

EXAMPLE 4 Find each of the following indefinite integrals: a.

 2 dx

b.

 p2 dx

Each of the integrands has the form f (x)  k, where k is a constant. Applying Rule 1 in each case yields

Solution

a.

 2 dx  2x  C

b.

 p2 dx  p 2x  C

Next, from the rule of differentiation, d n x  nx n1 dx

we obtain the following rule of integration.

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

745

Rule 2: The Power Rule 1n  12

1

 x n dx  n  1 x n1  C

An antiderivative of a power function is another power function obtained from the integrand by increasing its power by 1 and dividing the resulting expression by the new power. To prove this result, observe that d 1 a x n1  C b dx n  1 n1 n  x n1  xn  f 1x2

F¿1x2 

EXAMPLE 5 Find each of the following indefinite integrals: 1 a.  x 3 dx b.  x 3/2 dx c.  3/2 dx x Solution Each integrand is a power function with exponent n  1. Applying Rule 2 in each case yields the following results:

1

a.

 x 3 dx  4 x4  C

b.

 x 3/2 dx 

c.

 x 3/2 dx   x3/2 dx  1 x1/2  C  2x1/2  C   x1/2  C

1

1 5 2

2 5/2 x C 5

x 5/2  C  1

2

2

These results may be verified by differentiating each of the antiderivatives and showing that the result is equal to the corresponding integrand. The next rule tells us that a constant factor may be moved through an integral sign. Rule 3: The Indefinite Integral of a Constant Multiple of a Function

 cf 1x2 dx  c  f 1x2 dx

1c, a constant2

The indefinite integral of a constant multiple of a function is equal to the constant multiple of the indefinite integral of the function. This result follows from the corresponding rule of differentiation (see Rule 3, Section 9.4). Only a constant can be “moved out” of an integral sign. For example, it would be incorrect to write

 x 2 dx  x 2  1 dx In fact,  x 2 dx  13 x 3  C, whereas x 2  1 dx  x 2(x  C )  x 3  Cx 2.

746

11 INTEGRATION

EXAMPLE 6 Find each of the following indefinite integrals: a.

 2t 3 dt

b.

 3x2 dx

Solution Each integrand has the form cf (x), where c is a constant. Applying Rule 3, we obtain:

a.

 2t 3 dt  2  t 3 dt  2 a 4 t 4  K b 1



1 4 1 t  2K  t 4  C 2 2

where C  2K. From now on, we will write the constant of integration as C, since any nonzero multiple of an arbitrary constant is an arbitrary constant. b.

 3x 2 dx  3  x 2 dx  13 2 112x 1  C  x  C 3

Rule 4: The Sum Rule

 3 f 1x2  t1x2 4 dx   f 1x2 dx   t1x2 dx  3 f 1x2  t1x2 4 dx   f 1x2 dx   t1x2 dx The indefinite integral of a sum (difference) of two integrable functions is equal to the sum (difference) of their indefinite integrals. This result is easily extended to the case involving the sum and difference of any finite number of functions. As in Rule 3, the proof of Rule 4 follows from the corresponding rule of differentiation (see Rule 4, Section 9.4). EXAMPLE 7 Find the indefinite integral

 13x 5  4x 3/2  2x 1/2 2 dx Solution

Applying the extended version of Rule 4, we find that

 13x 5  4x 3/2  2x 1/2 2 dx   3x 5 dx   4x 3/2 dx   2x 1/2 dx  3  x 5 dx  4  x 3/2 dx  2  x 1/2 dx 1 2  132 a b x 6  142 a b x 5/2  122 122x 1/2  C 6 5 1 8  x 6  x 5/2  4x 1/2  C 2 5

Rule 3 Rule 2

Observe that we have combined the three constants of integration, which arise from evaluating the three indefinite integrals, to obtain one constant C. After all, the sum of three arbitrary constants is also an arbitrary constant. Rule 5: The Indefinite Integral of the Exponential Function

 e x dx  e x  C The indefinite integral of the exponential function with base e is equal to the function itself (except, of course, for the constant of integration).

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

747

EXAMPLE 8 Find the indefinite integral

 12e x  x 3 2 dx Solution

We have

 12e x  x 3 2 dx   2e x dx   x 3 dx  2  e x dx   x 3 dx 1  2e x  x 4  C 4

The last rule of integration in this section covers the integration of the function f(x)  x1. Remember that this function constituted the only exceptional case in the integration of the power function f(x)  x n (see Rule 2).

Rule 6: The Indefinite Integral of the Function f(x)  x 1

 x 1 dx   x dx  ln 0 x 0 1

C

1x  02

To prove Rule 6, observe that d 1 ln 0 x 0  x dx

See Rule 10, Section 9.7.

EXAMPLE 9 Find the indefinite integral

 a 2x  x  x 2 b dx 3

4

Solution

 a 2x  x  x 2 b dx   2x dx   x dx   x 2 dx 3

4

3

 2  x dx  3 

4

1 dx  4  x 2 dx x

1  2 a b x 2  3 ln 0 x 0  4112x1  C 2 4  x2  3 ln 0 x 0   C x

Differential Equations Let’s return to the problem posed at the beginning of the section: Given the derivative of a function, f , can we find the function f? As an example, suppose we are given the function f (x)  2x  1

(1)

and we wish to find f (x). From what we now know, we can find f by integrating Equation (1). Thus, f 1x 2   f ¿1x2 dx   12x  12 dx  x 2  x  C

(2)

748

11 INTEGRATION C=3 C=2

y

C=1

(1, 3) 3

C=0

2

C = –1

1 x –1

2

3

FIGURE 4 The graphs of some of the functions having the derivative f(x)  2x  1. Observe that the slopes of the tangent lines to the graphs are the same for a fixed value of x.

where C is an arbitrary constant. Thus, infinitely many functions have the derivative f , each differing from the other by a constant. Equation (1) is called a differential equation. In general, a differential equation is an equation that involves the derivative or differential of an unknown function. [In the case of Equation (1), the unknown function is f.] A solution of a differential equation is any function that satisfies the differential equation. Thus, Equation (2) gives all the solutions of the differential Equation (1), and it is, accordingly, called the general solution of the differential equation f (x)  2x  1. The graphs of f(x)  x 2  x  C for selected values of C are shown in Figure 4. These graphs have one property in common: For any fixed value of x, the tangent lines to these graphs have the same slope. This follows because any member of the family f(x)  x 2  x  C must have the same slope at x—namely, 2x  1! Although there are infinitely many solutions to the differential equation f (x)  2x  1, we can obtain a particular solution by specifying the value the function must assume at a certain value of x. For example, suppose we stipulate that the function f under consideration must satisfy the condition f(1)  3 or, equivalently, the graph of f must pass through the point (1, 3). Then, using the condition on the general solution f(x)  x 2  x  C, we find that f(1)  1  1  C  3

and C  3. Thus, the particular solution is f(x)  x 2  x  3 (see Figure 4). The condition f(1)  3 is an example of an initial condition. More generally, an initial condition is a condition imposed on the value of f at x  a.

Initial Value Problems An initial value problem is one in which we are required to find a function satisfying (1) a differential equation and (2) one or more initial conditions. The following are examples of initial value problems. EXAMPLE 10 Find the function f if it is known that f (x)  3x 2  4x  8 and Solution

f(1)  9

We are required to solve the initial value problem f ¿1x2  3x2  4x  8 f f 112  9

Integrating the function f , we find f 1x2   f ¿1x2 dx

  13x 2  4x  82 dx  x 3  2x 2  8x  C

Using the condition f(1)  9, we have

9  f 11 2  13  2112 2  811 2  C  7  C or

C2

Therefore, the required function f is given by f(x)  x 3  2x 2  8x  2. APPLIED EXAMPLE 11 Velocity of a Maglev In a test run of a maglev along a straight elevated monorail track, data obtained from reading its speedometer indicate that the velocity of the maglev at time t can be described by the velocity function √(t)  8t

(0 t 30)

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

749

Find the position function of the maglev. Assume that initially the maglev is located at the origin of a coordinate line. Let s(t) denote the position of the maglev at any time t (0 t 30). Then, s(t)  √ (t). So, we have the initial value problem

Solution

s¿1t2  8t f s102  0

Integrating both sides of the differential equation s(t)  8t, we obtain s1t2   s¿1t2 dt   8t dt  4t 2  C

where C is an arbitrary constant. To evaluate C, we use the initial condition s(0)  0 to write s(0)  4(0)  C  0

or

C0

Therefore, the required position function is s(t)  4t 2 (0 t 30). APPLIED EXAMPLE 12 Magazine Circulation The current circulation of the Investor’s Digest is 3000 copies per week. The managing editor of the weekly projects a growth rate of 4  5t 2/3

copies per week, t weeks from now, for the next 3 years. Based on her projection, what will be the circulation of the digest 125 weeks from now? Let S(t) denote the circulation of the digest t weeks from now. Then S(t) is the rate of change in the circulation in the t th week and is given by

Solution

S(t)  4  5t 2/3

Furthermore, the current circulation of 3000 copies per week translates into the initial condition S(0)  3000. Integrating the differential equation with respect to t gives S1t2   S¿1t 2 dt   14  5t 2/3 2 dt  4t  5 a

t 5/3 5 3

b  C  4t  3t 5/3  C

To determine the value of C, we use the condition S(0)  3000 to write S(0)  4(0)  3(0)  C  3000

which gives C  3000. Therefore, the circulation of the digest t weeks from now will be S(t)  4t  3t 5/3  3000

In particular, the circulation 125 weeks from now will be S(125)  4(125)  3(125)5/3  3000  12,875

copies per week.

750

11 INTEGRATION

11.1 Self-Check Exercises 1. Evaluate  a

1 2   3ex b dx. x 1x

certain country is changing at the rate of f(t)  0.01875t 2  0.15t  1.2

2. Find the rule for the function f given that (1) the slope of the tangent line to the graph of f at any point P(x, f (x)) is given by the expression 3x 2  6x  3 and (2) the graph of f passes through the point (2, 9). 3. Suppose United Motors’ share of the new cars sold in a

(0 t 12)

percent/year at year t (t  0 corresponds to the beginning of 1996). The company’s market share at the beginning of 1996 was 48.4%. What was United Motors’ market share at the beginning of 2008? Solutions to Self-Check Exercises 11.1 can be found on page 755.

11.1 Concept Questions 1. What is an antiderivative? Give an example. 2. If f (x)  t(x) for all x in an interval I, what is the relationship between f and t?

3. What is the difference between an antiderivative of f and the indefinite integral of f ? 1 4. Can the power rule be used to integrate  dx? Explain x your answer.

11.1 Exercises In Exercises 1–4, verify directly that F is an antiderivative of f.

2

1

19.

 x 2 dx

20.

 3x 5 dx

21.

 p1t dt

22.

 1t dt

2. F(x)  xe x  p ; f(x)  e x(1  x)

23.

 13  2x 2 dx

24.

 11  u  u 2 2 du

3. F 1x2  22x2  1; f 1x 2 

25.

 1x 2  x  x 3 2 dx

26.

 10.3t 2  0.02t  22 dt

27.

 4e x dx

28.

 11  e x 2 dx

29.

 11  x  e x 2 dx

30.

 12  x  2x 2  e x 2 dx

31.

 a 4x 3  x 2  1 b dx

32.

 a 6x 3  x 2  x b dx

1. F 1x2 

1 3 x  2x 2  x  2; f 1x 2  x 2  4x  1 3

2x 22x2  1

4. F(x)  x ln x  x; f (x)  ln x In Exercises 5–8, (a) verify that G is an antiderivative of f, (b) find all antiderivatives of f, and (c) sketch the graphs of a few of the family of antiderivatives found in part (b).

2

3

3

5. G(x)  2x; f (x)  2

6. G(x)  2x 2; f (x)  4x

33.

 1x 5/2  2x 3/2  x 2 dx

34.

 1t 3/2  2t1/2  4t1/2 2 dt

7. G1x 2 

8. G(x)  e x; f(x)  ex

35.

 a 1x 

36.

 a 23 x 2  x 2 b dx

37.

a

1 3 x ; f 1x 2  x 2 3

In Exercises 9–50, find the indefinite integral.

9.

 6 dx

10.

 12 dx

11.

 x 3 dx

12.

 2x 5 dx

13.

x

dx

14.

 3t

15.

 x 2/3 dx

16.

 2u3/4 du

17.

 x 5/4 dx

18.

 3x 2/3 dx

4

7

dt



u3  2u2  u 1 2 1  u2  u  3u 3 3 3

x4  1 dx x2

Hint:

39.

1

u 3  2u 2  u b du 3u

Hint:

38.

3 b dx 1x

x4  1 x2

 x 2  x 2

 12t  1 2 1t  22 dt

40.

 u2 11  u2  u4 2 du

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

 x 2 1x 4  2x 2  1 2 dx

43. 45.

47.

42.

 1t 1t 2  t  1 2 dt

 1s  1 2 2

44.

 a 1x  x  2e x b dx

 1e t  t e 2 dt

46.

 a x2 

1

ds



3

1

1 3

2x

2



1 2x

b dx

x3  x2  x  1 a b dx x2

Hint: Simplify the integrand first.

48.

3 t3  2 t  t 2 dt

posited into branch A and branch B in the first 180 business days is given by the graphs of f and t, respectively (see the figure). Which branch has a larger amount on deposit at the end of 180 business days? Justify your answer. Rate of deposit (in thousands of dollars per day)

41.

751

y

f y=

(t)

y = g(t) 180

t (days)

Hint: Simplify the integrand first.

49.



1 1x  1 2 2 x

2

64. VELOCITY OF A CAR Two cars, side by side, start from rest and travel along a straight road. The velocity of car A is given by √  f(t), and the velocity of car B is given by √  t(t). The graphs of f and t are shown in the figure below. Are the cars still side by side after T sec? If not, which car is ahead of the other? Justify your answer.

dx

Hint: Simplify the integrand first.

50.

 1x  12 2 a 1  x b dx 1

Hint: Simplify the integrand first.

√ (ft/sec)

In Exercises 51–58, find f(x) by solving the initial value problem.

y = f (t)

51. f (x)  2x  1; f(1)  3 52. f (x)  3x 2  6x; f(2)  4 53. f (x)  3x 2  4x  1; f(2)  9 54. f ¿1x2 

y = g (t)

1 ; f 142  2 1x

55. f ¿1x2  1 

t (sec) T

1 ; f 11 2  2 x2

65. VELOCITY OF A CAR The velocity of a car (in feet/second) t sec after starting from rest is given by the function

56. f (x)  e x  2x; f(0)  2 57. f ¿1x2 

f 1t2  2 1t

x1 ; f 112  1 x

Find the car’s position, s(t), at any time t. Assume s(0)  0.

1 58. f ¿1x2  1  ex  ; f 112  3  e x

66. VELOCITY OF maglev is

In Exercises 59–62, find the function f given that the slope of the tangent line to the graph of f at any point (x, f(x)) is f(x) and that the graph of f passes through the given point.

59. f ¿1x2 

1 1/2 x ; 12, 122 2

62. f ¿1x2 

A

MAGLEV The velocity (in feet/second) of a

√(t)  0.2t  3

(0 t 120)

At t  0, it is at the station. Find the function giving the position of the maglev at time t, assuming that the motion takes place along a straight stretch of track. 67. COST OF PRODUCING CLOCKS Lorimar Watch Company manufactures travel clocks. The daily marginal cost function associated with producing these clocks is

60. f (t)  t 2  2t  3; (1, 2) 61. f (x)  e x  x; (0, 3)

10 t 30 2

2  1; 11, 2 2 x

63. BANK DEPOSITS Madison Finance opened two branches on September 1 (t  0). Branch A is located in an established industrial park, and branch B is located in a fast-growing new development. The net rate at which money was de-

C(x)  0.000009x 2  0.009x  8

where C(x) is measured in dollars/unit and x denotes the number of units produced. Management has determined that the daily fixed cost incurred in producing these clocks is $120. Find the total cost incurred by Lorimar in producing the first 500 travel clocks/day.

752

11 INTEGRATION

68. REVENUE FUNCTIONS The management of Lorimar Watch Company has determined that the daily marginal revenue function associated with producing and selling their travel clocks is given by R(x)  0.009x  12

where x denotes the number of units produced and sold and R(x) is measured in dollars/unit. a. Determine the revenue function R(x) associated with producing and selling these clocks. b. What is the demand equation that relates the wholesale unit price with the quantity of travel clocks demanded? 69. PROFIT FUNCTIONS Cannon Precision Instruments makes an automatic electronic flash with Thyrister circuitry. The estimated marginal profit associated with producing and selling these electronic flashes is P(x)  0.004x  20

dollars/unit/month when the production level is x units per month. Cannon’s fixed cost for producing and selling these electronic flashes is $16,000/month. At what level of production does Cannon realize a maximum profit? What is the maximum monthly profit? 70. COST OF PRODUCING GUITARS Carlota Music Company estimates that the marginal cost of manufacturing its Professional Series guitars is C(x)  0.002x  100

dollars/month when the level of production is x guitars/ month. The fixed costs incurred by Carlota are $4000/ month. Find the total monthly cost incurred by Carlota in manufacturing x guitars/month. 71. HEALTH COSTS The national health expenditures are projected to grow at the rate of r(t)  0.0058t  0.159

(0 t 13)

b. How many sets does the average inspector check during a morning shift? 73. SATELLITE RADIO SUBSCRIPTIONS Based on data obtained by polling automobile buyers, the number of subscribers of satellite radios is expected to grow at the rate of r (t)  0.375t 2  2.1t  2.45

(0 t 5)

million subscribers/year between 2003 (t  0) and 2008 (t  5). The number of satellite radio subscribers at the beginning of 2003 was 1.5 million. a. Find an expression giving the number of satellite radio subscribers in year t (0 t 5). b. Based on this model, what was the number of satellite radio subscribers in 2008? Source: Carmel Group

74. RISK OF DOWN SYNDROME The rate at which the risk of Down syndrome is changing is approximated by the function r (x)  0.004641x 2  0.3012x  4.9

(20 x 45)

where r (x) is measured in percentage of all births/year and x is the maternal age at delivery. a. Find a function f giving the risk as a percentage of all births when the maternal age at delivery is x years, given that the risk of down syndrome at age 30 is 0.14% of all births. b. Based on this model, what is the risk of Down syndrome when the maternal age at delivery is 40 years? 45 years? Source: New England Journal of Medicine

75. CREDIT CARD DEBT The average credit card debt per U.S. household between 1990 (t  0) and 2003 (t  13) was growing at the rate of approximately D(t)  4.479t 2  69.8t  279.5

(0 t 13)

trillion dollars/year from 2002 through 2015. Here, t  0 corresponds to 2002. The expenditure in 2002 was $1.60 trillion. a. Find a function f giving the projected national health expenditures in year t. b. What does your model project the national health expenditure to be in 2015?

dollars/year. The average credit card debt per U.S. household stood at $2917 in 1990. a. Find an expression giving the approximate average credit card debt per U.S. household in year t (0 t 13). b. Use the result of part (a) to estimate the average credit card debt per U.S. household in 2003.

Source: National Health Expenditures

Source: Encore Capital Group

72. QUALITY CONTROL As part of a quality-control program, the chess sets manufactured by Jones Brothers are subjected to a final inspection before packing. The rate of increase in the number of sets checked per hour by an inspector t hr into the 8 a.m. to 12 noon morning shift is approximately N (t)  3t  12t  45 2

(0 t 4)

a. Find an expression N(t) that approximates the number of sets inspected at the end of t hours. Hint: N(0)  0.

76. GENETICALLY MODIFIED CROPS The total number of acres of genetically modified crops grown worldwide from 1997 through 2003 was changing at the rate of R(t)  2.718t 2  19.86t  50.18

(0 t 6)

million acres/year. The total number of acres of such crops grown in 1997 (t  0) was 27.2 million acres. How many acres of genetically modified crops were grown worldwide in 2003? Source: International Services for the Acquisition of Agri-biotech Applications

11.1 ANTIDERIVATIVES AND THE RULES OF INTEGRATION

753

77. GASTRIC BYPASS SURGERIES One method of weight loss gaining in popularity is stomach-reducing surgery. It is generally reserved for people at least 100 lb overweight because the procedure carries a serious risk of death or complications. According to the American Society of Bariatric Surgery, the number of morbidly obese patients undergoing the procedure was increasing at the rate of R(t)  9.399t 2  13.4t  14.07

(0 t 3)

thousands/year, with t  0 corresponding to 2000. The number of gastric bypass surgeries performed in 2000 was 36.7 thousand. a. Find an expression giving the number of gastric bypass surgeries performed in year t (0 t 3). b. Use the result of part (a) to find the number of gastric bypass surgeries performed in 2003. Source: American Society for Bariatric Surgery

78. ONLINE AD SALES According to a study conducted in 2004, the share of online advertisement, worldwide, as a percentage of the total ad market, is expected to grow at the rate of R(t)  0.033t 2  0.3428t  0.07

(0 t 6)

percent/year at time t (in years), with t  0 corresponding to the beginning of 2000. The online ad market at the beginning of 2000 was 2.9% of the total ad market. a. What is the projected online ad market share at any time t? b. What was the projected online ad market share at the beginning of 2005? Source: Jupiter Media Metrix, Inc.

79. HEALTH-CARE COSTS The average out-of-pocket costs for beneficiaries in traditional Medicare (including premiums, cost sharing, and prescription drugs not covered by Medicare) is projected to grow at the rate of C(t)  12.288t 2  150.5594t  695.23

dollars/year, where t is measured in 5-yr intervals, with t  0 corresponding to 2000. The out-of-pocket costs for beneficiaries in 2000 were $3142. a. Find an expression giving the average out-of-pocket costs for beneficiaries in year t. b. What is the projected average out-of-pocket costs for beneficiaries in 2010? Source: The Urban Institute

80. BALLAST DROPPED FROM A BALLOON A ballast is dropped from a stationary hot-air balloon that is hovering at an altitude of 400 ft. Its velocity after t sec is 32t ft/sec. a. Find the height h(t) of the ballast from the ground at time t. Hint: h(t)  32t and h(0)  400.

b. When will the ballast strike the ground? c. Find the velocity of the ballast when it hits the ground.

Ballast

81. CABLE TV SUBSCRIBERS A study conducted by TeleCable estimates that the number of cable TV subscribers will grow at the rate of 100  210t 3/4

new subscribers/month, t mo from the start date of the service. If 5000 subscribers signed up for the service before the starting date, how many subscribers will there be 16 mo from that date? 82. OZONE POLLUTION The rate of change of the level of ozone, an invisible gas that is an irritant and impairs breathing, present in the atmosphere on a certain May day in the city of Riverside is given by R(t)  3.2922t 2  0.366t 3

(0 t 11)

(measured in pollutant standard index/hour). Here, t is measured in hours, with t  0 corresponding to 7 a.m. Find the ozone level A(t) at any time t, assuming that at 7 a.m. it is zero. Hint: A(t)  R(t) and A(0)  0. Source: Los Angeles Times

83. FLIGHT OF A ROCKET The velocity, in feet/second, of a rocket t sec into vertical flight is given by √(t)  3t 2  192t  120

Find an expression h(t) that gives the rocket’s altitude, in feet, t sec after liftoff. What is the altitude of the rocket 30 sec after liftoff? Hint: h(t)  √(t); h(0)  0.

84. POPULATION GROWTH The development of AstroWorld (“The Amusement Park of the Future”) on the outskirts of a city will increase the city’s population at the rate of 45001t  1000

people/year, t yr from the start of construction. The population before construction is 30,000. Determine the projected population 9 yr after construction of the park has begun.

754

11 INTEGRATION

85. U.S. SALES OF ORGANIC MILK The sales of organic milk from 1999 through 2004 grew at the rate of approximately R(t)  3t 3  17.9445t 2  28.7222t  26.632

where k is a constant. If the radius of an artery is R cm, find an expression for the velocity of blood as a function of r (see the accompanying figure). Hint: √(r)  a(r) and √(R)  0. (Why?)

(0 t 5)

million dollars/year, where t is measured in years, with t  0 corresponding to 1999. Sales of organic milk in 1999 totaled $108 million. a. Find an expression giving the total sales of organic milk by year t (0 t 5). b. According to this model, what were the total sales of organic milk in 2004? Source: Resource, Inc.

86. SURFACE AREA OF A HUMAN Empirical data suggest that the surface area of a 180-cm-tall human body changes at the rate of S(W)  0.131773W 0.575

square meters/kilogram, where W is the weight of the body in kilograms. If the surface area of a 180-cm-tall human body weighing 70 kg is 1.886277 m2, what is the surface area of a human body of the same height weighing 75 kg? 87. OUTPATIENT SERVICE COMPANIES The number of Medicarecertified home-health-care agencies (70% are freestanding, and 30% are owned by a hospital or other large facility) has been declining at the rate of 0.186e0.02t

(0 t 14)

thousand agencies/year between 1988 (t  0) and 2002 (t  14). The number of such agencies stood at 9.3 thousand units in 1988. a. Find an expression giving the number of health-care agencies in year t. b. What was the number of health-care agencies in 2002? c. If this model held true through 2005, how many care agencies were there in 2005? Source: Centers for Medicare and Medicaid Services

R r

Blood vessel

90. ACCELERATION OF A CAR A car traveling along a straight road at 66 ft/sec accelerated to a speed of 88 ft/sec over a distance of 440 ft. What was the acceleration of the car, assuming it was constant? 91. DECELERATION OF A CAR What constant deceleration would a car moving along a straight road have to be subjected to if it were brought to rest from a speed of 88 ft/sec in 9 sec? What would be the stopping distance? 92. CARRIER LANDING A pilot lands a fighter aircraft on an aircraft carrier. At the moment of touchdown, the speed of the aircraft is 160 mph. If the aircraft is brought to a complete stop in 1 sec and the deceleration is assumed to be constant, find the number of g’s the pilot is subjected to during landing (1 g  32 ft/sec2). 93. CROSSING THE FINISH LINE After rounding the final turn in the bell lap, two runners emerged ahead of the pack. When runner A is 200 ft from the finish line, his speed is 22 ft/sec, a speed that he maintains until he crosses the line. At that instant of time, runner B, who is 20 ft behind runner A and running at a speed of 20 ft/sec, begins to sprint. Assuming that runner B sprints with a constant acceleration, what minimum acceleration will enable him to cross the finish line ahead of runner A? 94. DRAINING A TANK A tank has a constant cross-sectional area of 50 ft2 and an orifice of constant cross-sectional area of 12 ft2 located at the bottom of the tank (see the accompanying figure).

88. HEIGHTS OF CHILDREN According to the Jenss model for predicting the height of preschool children, the rate of growth of a typical preschool child is R1t2  25.8931e0.993t  6.39

1 14 t 6 2

centimeters/year, where t is measured in years. The height of a typical 3-mo-old preschool child is 60.2952 cm. a. Find a model for predicting the height of a typical preschool child at age t. b. Use the result of part (a) to estimate the height of a typical 1-yr-old child. 89. BLOOD FLOW IN AN ARTERY Nineteenth-century physician Jean Louis Marie Poiseuille discovered that the rate of change of the velocity of blood r cm from the central axis of an artery (in centimeters/second/centimeter) is given by a(r)  kr

h

If the tank is filled with water to a height of h ft and allowed to drain, then the height of the water decreases at a rate that is described by the equation dh 1 t   a 120  b dt 25 50

10 t 501202

Find an expression for the height of the water at any time t if its height initially is 20 ft.

11.2 INTEGRATION BY SUBSTITUTION

95. AMOUNT OF RAINFALL During a thunderstorm, rain was falling at the rate of 8 1t  42 2

10 t 22

755

In Exercises 97–100, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

97. If F and G are antiderivatives of f on an interval I, then F(x)  G(x)  C on I.

inches/hour. a. Find an expression giving the total amount of rainfall after t hr. Hint: The total amount of rainfall at t  0 is zero.

b. How much rain had fallen after 1 hr? After 2 hr? 96. LAUNCHING A FIGHTER AIRCRAFT A fighter aircraft is launched from the deck of a Nimitz-class aircraft carrier with the help of a steam catapult. If the aircraft is to attain a takeoff speed of at least 240 ft/sec after traveling 800 ft along the flight deck, find the minimum acceleration it must be subjected to, assuming it is constant.

98. If F is an antiderivative of f on an interval I, then  f(x) dx  F(x). 99. If f and t are integrable, then  [2 f(x)  3t(x)] dx  2  f(x) dx  3  t(x) dx. 100. If f and t are integrable, then  f(x)t(x) dx  [  f(x) dx][  t(x) dx].

11.1 Solutions to Self-Check Exercises 1.

 a 1x  x  3e x b dx   a x1/2  x  3e x b dx 1

2

2

  x1/2 dx  2 

1 dx  3  e x dx x

 2x1/2  2 ln 0 x 0  3e x  C

 21x  2 ln 0 x 0  3e x  C

2. The slope of the tangent line to the graph of the function f at any point P(x, f(x)) is given by the derivative f  of f. Thus, the first condition implies that f (x)  3x 2  6x  3

which, upon integration, yields f 1x 2   13x 2  6x  3 2 dx  x 3  3x 2  3x  k

or k  7. Hence, the required rule of definition of the function f is f(x)  x 3  3x 2  3x  7

3. Let M(t) denote United Motors’ market share at year t. Then, M1t2   f 1t2 dt

  10.01875t 2  0.15t  1.2 2 dt

 0.00625t 3  0.075t 2  1.2t  C

To determine the value of C, we use the initial condition M(0)  48.4, obtaining C  48.4. Therefore, M(t)  0.00625t 3  0.075t 2  1.2t  48.4

In particular, United Motors’ market share of new cars at the beginning of 2008 is given by

where k is the constant of integration. To evaluate k, we use the initial condition (2), which implies that f (2)  9, or 9  f(2)  23  3(2)2  3(2)  k

M1122  0.006251122 3  0.0751122 2  1.21122  48.4  34

or 34%.

11.2 Integration by Substitution In Section 11.1, we developed certain rules of integration that are closely related to the corresponding rules of differentiation in Chapter 9. In this section, we introduce a method of integration called the method of substitution, which is related to the chain rule for differentiating functions. When used in conjunction with the rules of integration developed earlier, the method of substitution is a powerful tool for integrating a large class of functions.

756

11 INTEGRATION

How the Method of Substitution Works Consider the indefinite integral

 212x  42 5 dx

(3)

One way of evaluating this integral is to expand the expression (2x  4) and then integrate the resulting integrand term by term. As an alternative approach, let’s see if we can simplify the integral by making a change of variable. Write 5

u  2x  4

with differential* du  2 dx

If we formally substitute these quantities into Equation (3), we obtain

 212x  42 5 dx   12x  42 5 12 dx 2   u5 du 앖 앖 udu2x2 dx 4 Rewrite Now, the last integral involves a power function and is easily evaluated using Rule 2 of Section 11.1. Thus, 1  u5 du  6 u6  C Therefore, using this result and replacing u by u  2x  4, we obtain

 212x  42 5 dx  6 12x  42 6  C 1

We can verify that the foregoing result is indeed correct by computing d 1 1 c 12x  42 6  C d  # 612x  42 5 122 dx 6 6

Use the chain rule.

 212x  42 5

and observing that the last expression is just the integrand of (3).

The Method of Integration by Substitution To see why the approach used in evaluating the integral in (3) is successful, write f(x)  x 5

and

t(x)  2x  4

Then, t(x)  2. Furthermore, the integrand of (3) is just the composition of f and t. Thus, 1 f ⴰ t2 1x2  f 1t1x2 2  3t1x2 4 5  12x  42 5 Therefore, (3) can be written as

 f 1 t1x2 2 t¿1x2 dx

(4)

Next, let’s show that an integral having the form (4) can always be written as

 f 1u2 du Suppose F is an antiderivative of f. By the chain rule, we have d 3F1 t1x2 2 4  F¿1 t1x2 2 t¿1x2 dx *If u  f (x), the differential of u, written du, is du  f (x)dx.

(5)

11.2 INTEGRATION BY SUBSTITUTION

757

Therefore,

 F¿1t1x2 2 t¿1x2 dx  F1t1x 2 2  C Letting F  f and making the substitution u  t(x), we have

 f 1t1x2 2 t¿1x2 dx  F1u2  C   F¿1u2 du   f 1u2 du as we wished to show. Thus, if the transformed integral is readily evaluated, as is the case with the integral (3), then the method of substitution will prove successful. Before we look at more examples, let’s summarize the steps involved in integration by substitution.

Integration by Substitution Step 1 Step 2 Step 3 Step 4 Step 5

Let u  t(x), where t(x) is part of the integrand, usually the “inside function” of the composite function f (t(x)). Find du  t(x) dx. Use the substitution u  t(x) and du  t(x) dx to convert the entire integral into one involving only u. Evaluate the resulting integral. Replace u by t(x) to obtain the final solution as a function of x.

Sometimes we need to consider different choices of t for the substitution u  t(x) in order to carry out Step 3 and/or Step 4.

Note

EXAMPLE 1 Find  2x(x 2  3)4 dx. Solution Step 1 Step 2 Step 3

Observe that the integrand involves the composite function (x 2  3)4 with “inside function” t(x)  x 2  3. So, we choose u  x 2  3. Find du  2x dx. Making the substitution u  x 2  3 and du  2x dx, we obtain

 2x1x 2  32 4 dx   1x 2  32 4 12x dx2   u4 du 앖 Rewrite

an integral involving only the variable u. Step 4

Evaluate 1

 u4 du  5 u5  C Step 5

Replacing u by x 2  3, we obtain

 2x1x 2  32 4 dx  5 1x 2  32 5  C 1

EXAMPLE 2 Find  3 13x  1 dx. Solution Step 1 Step 2

The integrand involves the composite function 13x  1 with “inside function” t(x)  3x  1. So, let u  3x  1. Find du  3 dx.

758

11 INTEGRATION Step 3

Making the substitution u  3x  1 and du  3 dx, we obtain

 313x  1 dx   13x  113 dx2   1u du Step 4

an integral involving only the variable u. Evaluate 2

 1u du   u1/2 du  3 u3/2  C Step 5

Replacing u by 3x  1, we obtain

 313x  1 dx  3 13x  12 3/2  C 2

EXAMPLE 3 Find  x 2 1x 3  12 3/2 dx. Solution Step 1 Step 2 Step 3

The integrand contains the composite function (x 3  1)3/2 with “inside function” t(x)  x 3  1. So, let u  x 3  1. Find du  3x 2 dx. Making the substitution u  x 3  1 and du  3x 2 dx, or x 2 dx  13 du, we obtain

 x 2 1x 3  12 3/2 dx   1x 3  12 3/2 1x 2 dx2 1 1   u 3/2 a du b   u 3/2 du 3 3 Step 4

an integral involving only the variable u. We evaluate 1 3/2 1 2 2 5/2 u du  # u5/2  C  u C  3 3 5 15

Step 5

Replacing u by x 3  1, we obtain

 x 2 1x 3  12 3/2 dx  15 1x 3  12 5/2  C 2

Explore & Discuss Let f (x)  x 2(x 3  1)3/2. Using the result of Example 3, we see that an antiderivative of f is F1x 2  152 1x 3  12 5/2. However, in terms of u (where u  x 3  1), an antiderivative of f is G1u 2  152 u5/2. Compute F(2). Next, suppose we want to compute F(2) using the function G instead. At what value of u should you evaluate G(u) in order to obtain the desired result? Explain your answer.

In the remaining examples, we drop the practice of labeling the steps involved in evaluating each integral. EXAMPLE 4 Find  e3x dx. Solution

Let u  3x so that du  3 dx, or dx  13 du. Then,

 e 3x dx   e u a 3 du b 1



1 u  e du 3

1 1   e u  C   e 3x  C 3 3

11.2 INTEGRATION BY SUBSTITUTION

EXAMPLE 5 Find 

759

x dx. 3x  1 2

Let u  3x 2  1. Then, du  6x dx, or x dx  16 du. Making the appropriate substitutions, we have

Solution

1

x

 3x 2  1 dx   u6 du 1 1  du 6 u 1  ln 0 u 0  C 6 1  ln13x 2  12  C 6 

EXAMPLE 6 Find  Solution

1ln x2 2 2x

Since 3x 2  1  0

dx.

Let u  ln x. Then, du 



1ln x2 2 2x

d 1 1ln x2 dx  dx x dx

2 1 1ln x2  x dx 2 1   u 2 du 2 1  u3  C 6 1  1ln x2 3  C 6

dx 

Explore & Discuss

Suppose  f 1u2 du  F1u2  C. 1. Show that  f 1ax  b 2 dx 

1 F1ax  b2  C. a

2. How can you use this result to facilitate the evaluation of integrals such as  (2x  3)5 dx and  e 3x2 dx? Explain your answer.

Examples 7 and 8 show how the method of substitution can be used in practical situations. APPLIED EXAMPLE 7 Cost of Producing Solar Cell Panels In 1990 the head of the research and development department of Soloron Corporation claimed that the cost of producing solar cell panels would drop at the rate of 58 13t  22 2

10 t 102

760

11 INTEGRATION

dollars per peak watt for the next t years, with t  0 corresponding to the beginning of 1990. (A peak watt is the power produced at noon on a sunny day.) In 1990 the panels, which are used for photovoltaic power systems, cost $10 per peak watt. Find an expression giving the cost per peak watt of producing solar cell panels at the beginning of year t. What was the cost at the beginning of 2000? Solution Let C(t) denote the cost per peak watt for producing solar cell panels at the beginning of year t. Then,

C¿1t2  

58 13t  22 2

Integrating, we find that C1t2  

58 dt 13t  22 2

 58  13t  22 2 dt

Let u  3t  2 so that du  3 dt or dt 

1 du 3

Then, 1 C1t 2  58 a b  u2 du 3 58   112u1  k 3 58  k 313t  22

where k is an arbitrary constant. To determine the value of k, note that the cost per peak watt of producing solar cell panels at the beginning of 1990 (t  0) was 10, or C(0)  10. This gives C10 2 

58  k  10 3122

or k  13. Therefore, the required expression is given by C1t 2  

58 1  313t  22 3 58  13t  22

313t  22 t  20  3t  2



3t  60 313t  22

The cost per peak watt for producing solar cell panels at the beginning of 2000 is given by C1102 

10  20  0.94 31102  2

or approximately $0.94 per peak watt.

11.2 INTEGRATION BY SUBSTITUTION

761

Exploring with

TECHNOLOGY Refer to Example 7. 1. Use a graphing utility to plot the graph of C1t 2 

t  20 3t  2

using the viewing window [0, 10]  [0, 5]. Then, use the numerical differentiation capability of the graphing utility to compute C(10). 2. Plot the graph of C¿1t 2  

58 13t  2 2 2

using the viewing window [0, 10]  [10, 0]. Then, use the evaluation capability of the graphing utility to find C(10). Is this value of C(10) the same as that obtained in part 1? Explain your answer.

APPLIED EXAMPLE 8 Computer Sales Projections A study prepared by the marketing department of Universal Instruments forecasts that, after its new line of Galaxy Home Computers is introduced into the market, sales will grow at the rate of 2000  1500e0.05t

(0 t 60)

units per month. Find an expression that gives the total number of computers that will sell t months after they become available on the market. How many computers will Universal sell in the first year they are on the market? Solution Let N(t) denote the total number of computers that may be expected to be sold t months after their introduction in the market. Then, the rate of growth of sales is given by N(t) units per month. Thus,

N(t)  2000  1500e0.05t

so that N1t 2   12000  1500e 0.05t 2 dt   2000 dt  1500  e 0.05t dt

Upon integrating the second integral by the method of substitution, we obtain N1t 2  2000t 

1500 0.05t e C 0.05

 2000t  30,000e 0.05t  C

Let u  0.05t; then du  0.05 dt.

To determine the value of C, note that the number of computers sold at the end of month 0 is nil, so N(0)  0. This gives N(0)  30,000  C  0

Since e 0  1

or C  30,000. Therefore, the required expression is given by N1t2  2000t  30,000e 0.05t  30,000  2000t  30,0001e 0.05t  12

762

11 INTEGRATION

The number of computers that Universal can expect to sell in the first year is given by N1122  20001122  30,0001e 0.051122  12  10,464

11.2 Self-Check Exercises 1. Evaluate  12x  5 dx. 2. Evaluate 

x2

12x  1 2 3/2 3

air due to automobile exhaust is increasing at the rate given by f 1t 2 

dx.

3. Evaluate  xe2x 1 dx. 2

4. According to a joint study conducted by Oxnard’s Environmental Management Department and a state government agency, the concentration of carbon monoxide (CO) in the

810.1t  12

30010.2t 2  4t  64 2 1/3

parts per million (ppm) per year t. Currently, the CO concentration due to automobile exhaust is 0.16 ppm. Find an expression giving the CO concentration t yr from now. Solutions to Self-Check Exercises 11.2 can be found on page 764.

11.2 Concept Questions 1. Explain how the method of substitution works by showing the steps used to find  f 1 t1x 2 2 t¿ 1x 2 dx.

2. Explain why the method of substitution works for the inte2 2 gral  xex dx, but not for the integral  ex dx.

11.2 Exercises In Exercises 1–50, find the indefinite integral.

1. 3. 4. 5. 7. 9. 11.

 414x  32 4 dx

2.

 4x12x 2  12 7 dx

 1x 3  2x2 2 13x 2  22 dx  13x2  2x  1 2 1x3  x2  x2 4 dx 4x

 12x2  3 2 3 dx  3t 2 2t 3  2 dt  1x 2  1 2 9x dx x

6.

 1  x5 dx

12.



x2 2x 3  1

dx

 e2x dx  xex dx  1ex  ex 2 dx 2

e

 1  e x dx

29.

 1x dx

31. 33.



 1e3x  x 3 2 3 dx

32.

 1e x  ex 2 3/2 dx

 e2x 1e2x  12 3 dx

34.

 ex 11  ex 2

e3x  x 2

ln 5x dx x



0.3x  0.2 dx 15.  0.3x 2  0.4x  2

2x 2  1 dx 16.  0.2x 3  0.3x

37.

 x ln x dx

39.



41.

 a xe x

x

19.

e

2x

dx

x 1

18.

 x 3  3x  1 dx

20.

e

0.02x

dx

e2x

30.

e1x

35.

 3x 2  1 dx

26.

3

 1  e2x dx

x2 dx 14.  3 x 3

17.

24.

 e2t3 dt  x 2e x 1 dx  1e2x  e3x 2 dx

28.

2 dx 13.  x2

2

22.

x

27.

3x 2  2

 1x 3  2x2 2 dx

10.

4

23. 25.

 3t 2 1t 3  22 3/2 dt  x 2 12x3  32 4 dx

8.

21.

1

2ln x dx x 2



x b dx x 2 2

e1/x dx x2 e x  ex

1ln u2

dx

3

36.



38.

 x1ln x2 2 dx

40.



42.

 a xex

du

u 1

1ln x2 7/2 x 2

dx



ex b dx e 3 x

11.2 INTEGRATION BY SUBSTITUTION

43.

x1

 1x  1 dx

44.

Hint: Let √  eu  u.

Hint: Let u  1x  1 .

45.

eu  1

 eu  u du

 x1x  1 2 5 dx t

 t  1 dt Hint:

48.

47.

t 1 1 . t1 t1

1  1x

 1  1x dx

Hint: Let u  1  1x .

50.

 x3 1x2  12 3/2

1  1x

 1  1x dx Hint: Let u  1  1x.

49.

students/year, t yr from now. If the current student enrollment is 1000, find an expression giving the total student enrollment t yr from now. What will be the student enrollment 5 yr from now? 58. TV ON MOBILE PHONES The number of people watching TV on mobile phones is expected to grow at the rate of

Hint: u  x  1 implies x  u  1.

46.

763

 √ 2(1  √) 6 d√ Hint: Let u  1  √.

dx

N ¿1t2 

5.4145 11  0.91t

10 t 42

million/year. The number of people watching TV on mobile phones at the beginning of 2007 (t  0) was 11.9 million. a. Find an expression giving the number of people watching TV on mobile phones in year t. b. According to this projection, how many people will be watching TV on mobile phones at the beginning of 2011? Source: International Data Corporation, U.S. forecast

Hint: Let u  x  1. 2

In Exercises 51–54, find the function f given that the slope of the tangent line to the graph of f at any point (x, f(x)) is f(x) and that the graph of f passes through the given point.

3x 2 2 2x3  1

53. f (x)  2xex 54. f ¿1x 2  1 

p¿1x2 

; 11, 1 2

60. POPULATION GROWTH The population of a certain city is projected to grow at the rate of

21

; (1, 0)

2x ; 10, 2 2 x2  1

r1t2  400 a 1 

55. CABLE TELEPHONE SUBSCRIBERS The number of cable telephone subscribers stood at 3.2 million at the beginning of 2004 (t  0). For the next 5 yr, the number was projected to grow at the rate of R(t)  3.36(t  1)

0.05

(0 t 5)

Source: Sanford C. Bernstein

56. TV VIEWERS: NEWSMAGAZINE SHOWS The number of viewers of a weekly TV newsmagazine show, introduced in the 2003 season, has been increasing at the rate of 1 1/3 tb 2

11 t 62

million viewers/year in its t th year on the air. The number of viewers of the program during its first year on the air is given by 9(5/2)2/3 million. Find how many viewers were expected in the 2008 season. 57. STUDENT ENROLLMENT The registrar of Kellogg University estimates that the total student enrollment in the Continuing Education division will grow at the rate of N(t)  2000(1  0.2t)3/2

2t b 24  t 2

10 t 52

people/year, t years from now. The current population is 60,000. What will be the population 5 yr from now? 61. OIL SPILL In calm waters, the oil spilling from the ruptured hull of a grounded tanker forms an oil slick that is circular in shape. If the radius r of the circle is increasing at the rate of

million subscribers/year. If the projection held true, how many cable telephone subscribers were there at the beginning of 2008 (t  4)?

3a2 

250 x 116  x 2 2 3/2

where x is the quantity demanded daily in units of a hundred. Find the demand function for these boots if the quantity demanded daily is 300 pairs (x  3) when the unit price is $50/pair.

51. f (x)  5(2x  1)4; (1, 3) 52. f ¿1x 2 

59. DEMAND: WOMEN’S BOOTS The rate of change of the unit price p (in dollars) of Apex women’s boots is given by

r¿1t2 

30 12t  4

feet/minute t min after the rupture occurs, find an expression for the radius at any time t. How large is the polluted area 16 min after the rupture occurred? Hint: r(0)  0.

62. LIFE EXPECTANCY OF A FEMALE Suppose in a certain country the life expectancy at birth of a female is changing at the rate of t¿ 1t2 

5.45218 11  1.09t2 0.9

years/year. Here, t is measured in years, with t  0 corresponding to the beginning of 1900. Find an expression t(t) giving the life expectancy at birth (in years) of a female in that country if the life expectancy at the beginning of 1900 is 50.02 yr. What is the life expectancy at birth of a female born in 2000 in that country?

764

11 INTEGRATION

63. AVERAGE BIRTH HEIGHT OF BOYS Using data collected at Kaiser Hospital, pediatricians estimate that the average height of male children changes at the rate of h¿ 1t 2 

52.8706e 0.3277t 11  2.449e 0.3277t 2 2

inches/year, where the child’s height h(t) is measured in inches and t, the child’s age, is measured in years, with t  0 corresponding to the age at birth. Find an expression h(t) for the average height of a boy at age t if the height at birth of an average child is 19.4 in. What is the height of an average 8-yr-old boy?

mg/min, where a is a positive constant associated with the rate at which excess glucose is eliminated from the bloodstream and is dependent on the patient’s metabolism rate. Derive an expression for the amount of glucose in the bloodstream at time t. Hint: A(0)  0.

66. CONCENTRATION OF A DRUG IN AN ORGAN A drug is carried into an organ of volume V cm3 by a liquid that enters the organ at the rate of a cm3/sec and leaves it at the rate of b cm3/sec. The concentration of the drug in the liquid entering the organ is c g/cm3. If the concentration of the drug in the organ at time t is increasing at the rate of

64. LEARNING CURVES The average student enrolled in the 20-wk Court Reporting I course at the American Institute of Court Reporting progresses according to the rule N(t)  6e0.05t

(0 t 20)

where N(t) measures the rate of change in the number of words/minute of dictation the student takes in machine shorthand after t wk in the course. Assuming that the average student enrolled in this course begins with a dictation speed of 60 words/minute, find an expression N(t) that gives the dictation speed of the student after t wk in the course. 65. AMOUNT OF GLUCOSE IN THE BLOODSTREAM Suppose a patient is given a continuous intravenous infusion of glucose at a constant rate of r mg/min. Then, the rate at which the amount of glucose in the bloodstream is changing at time t due to this infusion is given by A(t)  reat

x¿1t2 

1 1ac  bx0 2e bt/V V

g/cm3/sec, and the concentration of the drug in the organ initially is x0 g/cm3, show that the concentration of the drug in the organ at time t is given by x1t2 

ac ac  a x0  b e bt/V b b

In Exercises 67 and 68, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

67. If f is continuous, then  xf 1x 2 2 dx 

1  f 1x2 dx. 2

68. If f is continuous, then  f 1ax  b2 dx  a  f 1x2 dx.

11.2 Solutions to Self-Check Exercises 1. Let u  2x  5. Then, du  2 dx, or dx  12 du. Making the appropriate substitutions, we have

3. Let u  2x 2  1, so that du  4x dx, or x dx  14 du. Then, 1

 xe 2x 1 dx  4  e u du 2

 22x  5

dx  

1 1 1u a du b   u1/2 du 2 2

1 2  a b u3/2  C 2 3 1  12x  5 2 3/2  C 3

2. Let u  2x 3  1, so that du  6x 2 dx, or x 2 dx  16 du. Making the appropriate substitutions, we have



1 16 2 du x2 1 dx   3/2   u3/2 du 3 3/2 6 12x  1 2 u 1  a b 12 2 u1/2  C 6 1   12x 3  1 2 1/2  C 3 

1 3 22x 3  1

C



1 u e C 4



1 2x 21 e C 4

4. Let C(t) denote the CO concentration in the air due to automobile exhaust t yr from now. Then, C¿ 1t2  f 1t2  

810.1t  12 30010.2t 2  4t  642 1/3 8 10.1t  12 10.2t 2  4t  64 2 1/3 300

Integrating, we find C1t2   

8 10.1t  12 10.2t 2  4t  642 1/3 dt 300

8 300

 10.1t  1 2 10.2t 2  4t  642 1/3 dt

765

11.3 AREA AND THE DEFINITE INTEGRAL

Let u  0.2t 2  4t  64, so that du  (0.4t  4) dt  4(0.1t  1) dt, or 10.1t  1 2 dt 

where k is an arbitrary constant. To determine the value of k, we use the condition C(0)  0.16, obtaining C10 2  0.16  0.01164 2 2/3  k

1 du 4

0.16  0.16  k k0

Then, C1t2 

8 1 a b  u1/3 du 300 4

Therefore, C(t)  0.01(0.2t 2  4t  64)2/3

1 3  a u2/3 b  k 150 2

 0.0110.2t 2  4t  64 2 2/3  k

11.3 Area and the Definite Integral An Intuitive Look Suppose a certain state’s annual rate of petroleum consumption over a 4-year period is constant and is given by the function f(t)  1.2

(0 t 4)

where t is measured in years and f(t) in millions of barrels per year. Then, the state’s total petroleum consumption over the period of time in question is (1.2)(4  0)

Rate of consumption  Time elapsed

or 4.8 million barrels. If you examine the graph of f shown in Figure 5, you will see that this total is just the area of the rectangular region bounded above by the graph of f, below by the t-axis, and to the left and right by the vertical lines t  0 (the y-axis) and t  4, respectively.

y t=4 y = f (t) = 1.2

1.2

1

2 3 Years

4

Million barrels per year

Million barrels per year

y 0.6 0.5 0.4 0.3 0.2 0.1 t

t 1

2 3 Years

4

FIGURE 5

FIGURE 6

The total petroleum consumption is given by the area of the rectangular region.

The daily petroleum consumption is given by the “area” of the shaded region.

Figure 6 shows the actual petroleum consumption of a certain New England state over a 4-year period from 1990 (t  0) to 1994 (t  4). Observe that the rate of consumption is not constant; that is, the function f is not a constant function. What is the state’s total petroleum consumption over this 4-year period? It seems reasonable to conjecture that it is given by the “area” of the region bounded above by the graph of f, below by the t-axis, and to the left and right by the vertical lines t  0 and t  4, respectively.

766

11 INTEGRATION

This example raises two questions: 1. What is the “area” of the region shown in Figure 6? 2. How do we compute this area? y

The Area Problem x=a

x=b

y = f (x )

x a

b

The preceding example touches on the second fundamental problem in calculus: Calculate the area of the region bounded by the graph of a nonnegative function f, the x-axis, and the vertical lines x  a and x  b (Figure 7). This area is called the area under the graph of f on the interval [a, b], or from a to b.

Defining Area—Two Examples Just as we used the slopes of secant lines (quantities that we could compute) to help us define the slope of the tangent line to a point on the graph of a function, we now adopt a parallel approach and use the areas of rectangles (quantities that we can compute) to help us define the area under the graph of a function. We begin by looking at a specific example.

FIGURE 7 The area under the graph of f on [a, b]

EXAMPLE 1 Let f(x)  x 2 and consider the region R under the graph of f on the interval [0, 1] (Figure 8a). To obtain an approximation of the area of R, let’s construct four nonoverlapping rectangles as follows: Divide the interval [0, 1] into four subintervals 1 c 0, d , 4

y y = x2

1

1 1 c , d, 4 2

1 f a b, 8

x 1

y y = x2

( 58 )

5 , 8

7 8

3 f a b, 8

5 f a b, 8

7 fa b 8

respectively (Figure 8b). If we approximate the area A of R by the sum of the areas of the four rectangles, we obtain

(a)

f

3 , 8

of each subinterval. Then, each of these rectangles has width 14 and height

R

( 78 )

3 c , 1d 4

of equal length 14. Next, construct four rectangles with these subintervals as bases and with heights given by the values of the function at the midpoints 1 , 8

f

1 3 c , d, 2 4

f ( 38 ) f ( 18 )

x 1 8

1 4

3 8

1 2

5 8

3 4

7 8

1 4 1  4 1  4 1  4

A

1

1 1 3 1 5 1 7 fa b  fa b  fa b  fa b 8 4 8 4 8 4 8 1 3 5 7 cf a b  f a b  f a b  f a b d 8 8 8 8 1 2 3 2 5 2 7 2 Recall that f (x )  x 2. ca b  a b  a b  a b d 8 8 8 8 1 9 25 49 21 a    b  64 64 64 64 64

or approximately 0.328125 square unit.

(b) FIGURE 8 The area of the region under the graph of f on [0, 1] in (a) is approximated by the sum of the areas of the four rectangles in (b).

Following the procedure of Example 1, we can obtain approximations of the area of the region R using any number n of rectangles (n  4 in Example 1). Figure 9a shows the approximation of the area A of R using 8 rectangles (n  8), and Figure 9b shows the approximation of the area A of R using 16 rectangles.

767

11.3 AREA AND THE DEFINITE INTEGRAL y

y y = x2

1

FIGURE 9

y = x2

1

x

x

As n increases, the number of rectangles increases, and the approximation improves.

1

1 (a) n  8

(b) n  16

These figures suggest that the approximations seem to get better as n increases. This is borne out by the results given in Table 1, which were obtained using a computer. TABLE 1

4

8

16

32

64

100

200

0.328125

0.332031

0.333008

0.333252

0.333313

0.333325

0.333331

Number of Rectangles, n Approximation of A

Our computations seem to suggest that the approximations approach the number 31 as n gets larger and larger. This result suggests that we define the area of the region under the graph of f(x)  x 2 on the interval [0, 1] to be 13 square unit. In Example 1, we chose the midpoint of each subinterval as the point at which to evaluate f(x) to obtain the height of the approximating rectangle. Let’s consider another example, this time choosing the left endpoint of each subinterval. EXAMPLE 2 Let R be the region under the graph of f(x)  16  x 2 on the interval [1, 3]. Find an approximation of the area A of R using four subintervals of [1, 3] of equal length and picking the left endpoint of each subinterval to evaluate f(x) to obtain the height of the approximating rectangle. Solution The graph of f is sketched in Figure 10a. Since the length of [1, 3] is 2, we see that the length of each subinterval is 42 , or 12 . Therefore, the four subintervals are

3 c 1, d , 2

3 c , 2d, 2

5 c 2, d , 2

y

y f (1)

16

f ( 32 )

12

f (2) f ( 25 )

8 R 4 FIGURE 10 The area of R in (a) is approximated by the sum of the areas of the four rectangles in (b).

5 c , 3d 2

8 4

x 1 (a)

2

3

x

4

1 (b)

3 2

2

5 2

3

4

768

11 INTEGRATION

The left endpoints of these subintervals are 1, 32, 2, and 52, respectively, so the heights of the approximating rectangles are f(1), f 1 32 2 , f(2), and f 1 52 2 , respectively (Figure 10b). Therefore, the required approximation is 1 1 3 1 1 5 f 112  f a b  f 122  f a b 2 2 2 2 2 2 1 3 5  c f 112  f a b  f 122  f a b d 2 2 2 2 1 3  e 316  112 2 4  c 16  a b d 2 2 5 2   316  122 2 4  c 16  a b d f Recall that f (x)  16  x 2. 2 1 55 39 101  a 15   12  b  2 4 4 4

A

or approximately 25.25 square units. Table 2 shows the approximations of the area A of the region R of Example 2 when n rectangles are used for the approximation and the heights of the approximating rectangles are found by evaluating f(x) at the left endpoints. TABLE 2 Number of Rectangles, n Approximation of A

4

10

100

1,000

10,000

50,000

100,000

25.2500

24.1200

23.4132

23.3413

23.3341

23.3335

23.3334

Once again, we see that the approximations seem to approach a unique number as n gets larger and larger—this time the number is 2313. This result suggests that we define the area of the region under the graph of f(x)  16  x 2 on the interval [1, 3] to be 2313 square units.

Defining Area—The General Case Examples 1 and 2 point the way to defining the area A under the graph of an arbitrary but continuous and nonnegative function f on an interval [a, b] (Figure 11a). y

y y = f (x)

y = f (x)

R FIGURE 11 The area of the region under the graph of f on [a, b] in (a) is approximated by the sum of the areas of the n rectangles shown in (b).

x

x a (a)

a x1

b

x2

x3

x4

...

xn b

(b)

Divide the interval [a, b] into n subintervals of equal length x  (b  a)/n. Next, pick n arbitrary points x1, x2, . . . , xn, called representative points, from the first, second, . . . , and nth subintervals, respectively (Figure 11b). Then, approximating the

11.3 AREA AND THE DEFINITE INTEGRAL

769

area A of the region R by the n rectangles of width x and heights f (x1), f(x2), . . . , f(xn), so that the areas of the rectangles are f(x1) x, f (x2) x, . . . , f (xn)x, we have A  f (x1)x  f (x2)x  . . .  f (xn)x The sum on the right-hand side of this expression is called a Riemann sum in honor of the German mathematician Bernhard Riemann (1826–1866). Now, as the earlier examples seem to suggest, the Riemann sum will approach a unique number as n becomes arbitrarily large.* We define this number to be the area A of the region R. The Area under the Graph of a Function

Let f be a nonnegative continuous function on [a, b]. Then, the area of the region under the graph of f is A  lim 3 f 1x1 2  f 1x2 2  . . .  f 1xn 2 4 ¢x

(6) nS where x1, x2, . . . , xn are arbitrary points in the n subintervals of [a, b] of equal width  x  (b  a)/n.

The Definite Integral As we have just seen, the area under the graph of a continuous nonnegative function f on an interval [a, b] is defined by the limit of the Riemann sum lim 3 f 1x1 2 ¢ x  f 1x2 2 ¢ x  . . .  f 1xn 2 ¢ x 4 nS

We now turn our attention to the study of limits of Riemann sums involving functions that are not necessarily nonnegative. Such limits arise in many applications of calculus. For example, the calculation of the distance covered by a body traveling along a straight line involves evaluating a limit of this form. The computation of the total revenue realized by a company over a certain time period, the calculation of the total amount of electricity consumed in a typical home over a 24-hour period, the average concentration of a drug in a body over a certain interval of time, and the volume of a solid—all involve limits of this type. We begin with the following definition. The Definite Integral

Let f be a continuous function defined on [a, b]. If lim 3 f 1x1 2 ¢ x  f 1x2 2 ¢ x  . . .  f 1xn 2 ¢ x4

nS

exists for all choices of representative points x1, x2, . . . , xn in the n subintervals of [a, b] of equal width  x  (b  a)/n, then this limit is called the definite integral of f from a to b and is denoted byab f 1x 2 dx. Thus, b

 f 1x2 dx  lim 3 f 1x 2 ¢ x  f 1x 2 ¢ x  . . .  f 1x 2 ¢ x4 a

nS

1

2

n

(7)

The number a is the lower limit of integration, and the number b is the upper limit of integration.

*Even though we chose the representative points to be the midpoints of the subintervals in Example 1 and the left endpoints in Example 2, it can be shown that each of the respective sums will always approach a unique number as n approaches infinity.

770

11 INTEGRATION

Notes

1. If f is nonnegative, then the limit in (7) is the same as the limit in (6); therefore, the definite integral gives the area under the graph of f on [a, b]. 2. The limit in (7) is denoted by the integral sign  because, as we will see later, the definite integral and the antiderivative of a function f are related. 3. It is important to realize that the definite integral ab f 1x2 dx is a number, whereas the indefinite integral  f 1x2 dx represents a family of functions (the antiderivatives of f ). 4. If the limit in (7) exists, we say that f is integrable on the interval [a, b].

When Is a Function Integrable? The following theorem, which we state without proof, guarantees that a continuous function is integrable. Integrability of a Function

Let f be continuous on [a, b]. Then, f is integrable on [a, b]; that is, the definite integral ab f 1x2 dx exists.

Geometric Interpretation of the Definite Integral If f is nonnegative and integrable on [a, b], then we have the following geometric interpretation of the definite integral ab f 1x2 dx . b

Geometric Interpretation of a f(x) dx for f(x)  0 on [a, b]

If f is nonnegative and continuous on [a, b], then



b

f 1x2 dx

(8)

a

is equal to the area of the region under the graph of f on [a, b] (Figure 12). y y = f (x) FIGURE 12 If f(x)  0 on [a, b], then

ab f( x) dx  area under the graph of f on [a, b].

Explore & Discuss Suppose f is nonpositive [that is, f(x) 0] and continuous on [a, b]. Explain why the area of the region below the x-axis and above the graph of f is given by ab f(x) dx.

A=

b a

f(x) dx

x a

b

Next, let’s extend our geometric interpretation of the definite integral to include the case where f assumes both positive as well as negative values on [a, b]. Consider a typical Riemann sum of the function f, f(x1)x  f(x2)x  . . .  f(xn)x corresponding to a partition of [a, b] into n subintervals of equal width (b  a)/n, where x1, x2, . . . , xn are representative points in the subintervals. The sum consists of n terms in which a positive term corresponds to the area of a rectangle of height f(xk) (for some positive integer k) lying above the x-axis and a negative term corresponds

11.3 AREA AND THE DEFINITE INTEGRAL

771

to the area of a rectangle of height f(xk) lying below the x-axis. (See Figure 13, which depicts a situation with n  6.) y

y = f (x) FIGURE 13 The positive terms in the Riemann sum are associated with the areas of the rectangles that lie above the x-axis, and the negative terms are associated with the areas of those that lie below the x-axis.

x4 a x1

x2

x3

x x5

x6 b

As n gets larger and larger, the sums of the areas of the rectangles lying above the x-axis seem to give a better and better approximation of the area of the region lying above the x-axis (Figure 14). Similarly, the sums of the areas of those rectangles lying below the x-axis seem to give a better and better approximation of the area of the region lying below the x-axis. y

y = f (x)

FIGURE 14 As n gets larger, the approximations get better. Here, n  12 and we are approximating with twice as many rectangles as in Figure 13.

x a

b

These observations suggest the following geometric interpretation of the definite integral for an arbitrary continuous function on an interval [a, b].

b

Geometric Interpretation of a f(x) dx on [a, b]

If f is continuous on [a, b], then



b

f 1x2 dx

a

is equal to the area of the region above [a, b] minus the area of the region below [a, b] (Figure 15). y

y = f (x) R1

R3

FIGURE 15 ab f(x) dx  Area of R 1  Area of R 2  Area of R 3

x a

R2

b

772

11 INTEGRATION

11.3 Self-Check Exercise Find an approximation of the area of the region R under the graph of f(x)  2x 2  1 on the interval [0, 3], using four subintervals of [0, 3] of equal length and picking the midpoint of each subinterval as a representative point.

The solution to Self-Check Exercise 11.3 can be found on page 774.

11.3 Concept Questions 1. Explain how you would define the area of the region under the graph of a nonnegative continuous function f on the interval [a, b].

for the case where (a) f is nonnegative on [a, b] and (b) f assumes both positive as well as negative values on [a, b]. Illustrate your answers graphically.

2. Define the definite integral of a continuous function on the interval [a, b]. Give a geometric interpretation of ab f 1x2 dx

11.3 Exercises In Exercises 1 and 2, find an approximation of the area of the region R under the graph of f by computing the Riemann sum of f corresponding to the partition of the interval into the subintervals shown in the accompanying figures. In each case, use the midpoints of the subintervals as the representative points.

1.

2.7

y

2.4 1.9

2.5

1.8 1.5

y = f(x)

4. Repeat Exercise 3, choosing the representative points to be the right endpoints of the subintervals.

x 1

2.

2

3

y 8.0 8.5 6.0 4.0

4.5

3.0

2.5 2.0 y = f(x) x

1

2

3. Let f(x)  3x. a. Sketch the region R under the graph of f on the interval [0, 2] and find its exact area using geometry. b. Use a Riemann sum with four subintervals of equal length (n  4) to approximate the area of R. Choose the representative points to be the left endpoints of the subintervals. c. Repeat part (b) with eight subintervals of equal length (n  8). d. Compare the approximations obtained in parts (b) and (c) with the exact area found in part (a). Do the approximations improve with larger n?

5. Let f(x)  4  2x. a. Sketch the region R under the graph of f on the interval [0, 2] and find its exact area using geometry. b. Use a Riemann sum with five subintervals of equal length (n  5) to approximate the area of R. Choose the representative points to be the left endpoints of the subintervals. c. Repeat part (b) with ten subintervals of equal length (n  10). d. Compare the approximations obtained in parts (b) and (c) with the exact area found in part (a). Do the approximations improve with larger n? 6. Repeat Exercise 5, choosing the representative points to be the right endpoints of the subintervals.

11.3 AREA AND THE DEFINITE INTEGRAL

7. Let f(x)  x 2 and compute the Riemann sum of f over the interval [2, 4], using a. Two subintervals of equal length (n  2). b. Five subintervals of equal length (n  5). c. Ten subintervals of equal length (n  10). In each case, choose the representative points to be the midpoints of the subintervals. d. Can you guess at the area of the region under the graph of f on the interval [2, 4]?

to the upper boundary of the property. These measurements give the values of f (x) at x  10, 30, 50, 70, and 90. What is the approximate area of the lot?

8. Repeat Exercise 7, choosing the representative points to be the left endpoints of the subintervals. 9. Repeat Exercise 7, choosing the representative points to be the right endpoints of the subintervals.

773

Road (a) y (ft)

10. Let f(x)  x 3 and compute the Riemann sum of f over the interval [0, 1], using a. Two subintervals of equal length (n  2). b. Five subintervals of equal length (n  5). c. Ten subintervals of equal length (n  10). In each case, choose the representative points to be the midpoints of the subintervals. d. Can you guess at the area of the region under the graph of f on the interval [0, 1]?

80

100

110

100

80

x (ft) 10 20 30 40 50 60 70 80 90 100 (b)

11. Repeat Exercise 10, choosing the representative points to be the left endpoints of the subintervals. 12. Repeat Exercise 10, choosing the representative points to be the right endpoints of the subintervals.

18. REAL ESTATE Use the technique of Exercise 17 to obtain an estimate of the area of the vacant lot shown in the accompanying figures.

Road

In Exercises 13–16, find an approximation of the area of the region R under the graph of the function f on the interval [a, b]. In each case, use n subintervals and choose the representative points as indicated.

13. f(x)  x 2  1; [0, 2]; n 5; midpoints 14. f(x)  4  x 2; [1, 2]; n  6; left endpoints 1 15. f 1x2  ; 3 1, 34; n  4; right endpoints x

Road (a)

16. f(x)  e x; [0, 3]; n  5; midpoints 17. REAL ESTATE Figure (a) shows a vacant lot with a 100-ft frontage in a development. To estimate its area, we introduce a coordinate system so that the x-axis coincides with the edge of the straight road forming the lower boundary of the property, as shown in Figure (b). Then, thinking of the upper boundary of the property as the graph of a continuous function f over the interval [0, 100], we see that the problem is mathematically equivalent to that of finding the area under the graph of f on [0, 100]. To estimate the area of the lot using a Riemann sum, we divide the interval [0, 100] into five equal subintervals of length 20 ft. Then, using surveyor’s equipment, we measure the distance from the midpoint of each of these subintervals

y (ft)

100

75

80

82.5

10 20 30 40 50 60 70 80 (b)

x (ft)

774

11 INTEGRATION

11.3 Solution to Self-Check Exercise The length of each subinterval is 34. Therefore, the four subintervals are 3 c 0, d , 4

3 3 c , d, 4 2

3 9 c , d, 2 4

3 3 3 9 3 15 3 21 fa b  fa b  fa b  fa b 4 8 4 8 4 8 4 8 3 3 9 15 21  cf a b  f a b  f a b  f a b d 4 8 8 8 8 3 9 2 15 2 3 2  e c2a b  1d  c2a b  1d  c2a b  1d 4 8 8 8 21 2   c2a b  1d f 8 113 257 473 663 3 41  a    b  4 32 32 32 32 32

A

9 c , 3d 4

The representative points are 38, 98, 158, and 218, respectively. Therefore, the required approximation is

or approximately 20.72 square units.

11.4 The Fundamental Theorem of Calculus The Fundamental Theorem of Calculus In Section 11.3, we defined the definite integral of an arbitrary continuous function on an interval [a, b] as a limit of Riemann sums. Calculating the value of a definite integral by actually taking the limit of such sums is tedious and in most cases impractical. It is important to realize that the numerical results we obtained in Examples 1 and 2 of Section 11.3 were approximations of the respective areas of the regions in question, even though these results enabled us to conjecture what the actual areas might be. Fortunately, there is a much better way of finding the exact value of a definite integral. The following theorem shows how to evaluate the definite integral of a continuous function provided we can find an antiderivative of that function. Because of its importance in establishing the relationship between differentiation and integration, this theorem—discovered independently by Sir Isaac Newton (1642–1727) in England and Gottfied Wilhelm Leibniz (1646–1716) in Germany—is called the fundamental theorem of calculus.

THEOREM 2 The Fundamental Theorem of Calculus

Let f be continuous on [a, b]. Then, b

 f 1x2 dx  F1b2  F1a2

(9)

a

where F is any antiderivative of f ; that is, F(x)  f (x). We will explain why this theorem is true at the end of this section. When applying the fundamental theorem of calculus, it is convenient to use the notation F1x2 `  F1b2  F1a2 b a

For example, using this notation, Equation (9) is written



a

b

f 1x2 dx  F1x2 `  F1b2  F1a 2 b a

11.4 THE FUNDAMENTAL THEOREM OF CALCULUS

775

EXAMPLE 1 Let R be the region under the graph of f(x)  x on the interval [1, 3]. Use the fundamental theorem of calculus to find the area A of R and verify your result by elementary means. Solution The region R is shown in Figure 16a. Since f is nonnegative on [1, 3], the area of R is given by the definite integral of f from 1 to 3; that is, 3

A

 x dx 1

y

y 4

4

y = f (x) = x

y = f (x) = x

3

3

2

2

2 R2

x=3 1

1

R

R1 x 1

FIGURE 16 The area of R can be computed in two different ways.

2

3

x 1

4

2

3

4

x=1 (a)

(b)

To evaluate the definite integral, observe that an antiderivative of f(x)  x is F1x2  12 x 2  C, where C is an arbitrary constant. Therefore, by the fundamental theorem of calculus, we have



3

3 1 2 x C` 2 1 1 9 1  a  C b  a  C b  4 square units 2 2

A

x dx 

To verify this result by elementary means, observe that the area A is the area of the rectangle R1 (width  height) plus the area of the triangle R2 Ó12 base  heightÔ (see Figure 16b); that is, 211 2 

1 122 122  2  2  4 2

which agrees with the result obtained earlier. Observe that in evaluating the definite integral in Example 1, the constant of integration “dropped out.” This is true in general, for if F(x)  C denotes an antiderivative of some function f, then F1x2  C `  3F1b2  C4  3F1a2  C4 b a

 F1b2  C  F1a2  C  F1b2  F1a2

With this fact in mind, we may, in all future computations involving the evaluation of a definite integral, drop the constant of integration from our calculations.

Finding the Area under a Curve Having seen how effective the fundamental theorem of calculus is in helping us find the area of simple regions, we now use it to find the area of more complicated regions.

776

11 INTEGRATION

y

EXAMPLE 2 In Section 11.3, we conjectured that the area of the region R under the graph of f(x)  x 2 on the interval [0, 1] was 13 square unit. Use the fundamental theorem of calculus to verify this conjecture.

1

Solution The region R is reproduced in Figure 17. Observe that f is nonnegative on [0, 1], so the area of R is given by A  01 x 2 dx. Since an antiderivative of f(x)  x 2 is F1x2  13 x3, we see, using the fundamental theorem of calculus, that

y = x2

R

A



1

x2 dx 

0

x 1 FIGURE 17

1 3 1 1 1 1 x `  112  10 2  square unit 3 3 3 3 0

as we wished to show. It is important to realize that the value, 13, is by definition the exact value of the area of R. Note

The area of R is  1 x 2 dx  13 . 0

EXAMPLE 3 Find the area of the region R under the graph of y  x 2  1 from x  1 to x  2.

y y = f (x) = x 2 + 1

Solution The region R under consideration is shown in Figure 18. Using the fundamental theorem of calculus, we find that the required area is

6



2

2 1 1x 2  12 dx  a x 3  x b ` 3 1 1 1 1  c 182  2 d  c 112 3  112 d  6 3 3

4

2 R

x = –1

or 6 square units.

x=2 x

–2

2

FIGURE 18 The area of R is  2 (x 2  1) dx. 1

Evaluating Definite Integrals In Examples 4 and 5, we use the rules of integration of Section 11.1 to help us evaluate the definite integrals. EXAMPLE 4 Evaluate



3

13x 2  e x 2 dx.

1

Solution



3

13x 2  e x 2 dx  x 3  e x `

3 1

1

 127  e 2  11  e2  26  e 3  e 3

2

EXAMPLE 5 Evaluate

 ax  x 1

1 2

b dx.

1

Solution



1

2

a

1 1  2 b dx  x x

2

 ax  x 1

2

b dx

1

 ln 0 x 0 

1 2 ` x 1

 a ln 2 

1 b  1ln 1  12 2

 ln 2 

1 2

Recall, ln 1  0.

11.4 THE FUNDAMENTAL THEOREM OF CALCULUS

777

Explore & Discuss Consider the definite integral



1

1 dx. 2 x 1

1. Show that a formal application of Equation (9) leads to



1

1

1 1 1 `  1  1  2 dx   x 1 x2

2. Observe that f (x)  1/x 2 is positive at each value of x in [1, 1] where it is defined. So, one might expect that the definite integral with integrand f has a positive value, if it exists. 3. Explain this apparent contradiction in the result (1) and the observation (2).

The Definite Integral as a Measure of Net Change In real-world applications, we are often interested in the net change of a quantity over a period of time. For example, suppose P is a function giving the population, P(t), of a city at time t. Then the net change in the population over the period from t  a to t  b is given by P(b)  P(a)

Population at t  b minus population at t  a

If P has a continuous derivative P in [a, b], then we can invoke the fundamental theorem of calculus to write b

P1b2  P1a2 

 P¿1t 2 dt

P is an antiderivative of P.

a

Thus, if we know the rate of change of the population at any time t, then we can calculate the net change in the population from t  a to t  b by evaluating an appropriate definite integral. APPLIED EXAMPLE 6 Population Growth in Clark County Clark County in Nevada—dominated by Las Vegas—is the fastest-growing metropolitan area in the United States. From 1970 through 2000, the population was growing at the rate of R(t)  133,680t 2  178,788t  234,633

(0 t 3)

people per decade, where t  0 corresponds to the beginning of 1970. What was the net change in the population over the decade from 1980 to 1990? Source: U.S. Census Bureau

The net change in the population over the decade from 1980 (t  1) to 1990 (t  2) is given by P(2)  P(1), where P denotes the population in the county at time t. But P  R, and so

Solution

P122  P112 



2



2

P¿1t 2 dt 

1



2

 R1t 2 dt 1

1133,680t 2  178,788t  234,6332 dt

1

 44,560t 3  89,394t 2  234,633t `

2

 344,560122 3  89,394122 2  234,633122 4   344,560  89,394  234,6334  278,371 1

and so the net change is 278,371.

778

11 INTEGRATION

More generally, we have the following result. We assume that f has a continuous derivative, even though the integrability of f  is sufficient.

Net Change Formula

The net change in a function f over an interval [a, b] is given by f 1b2  f 1a2 

b

 f ¿1x2 dx

(10)

a

provided f  is continuous on [a, b].

As another example of the net change of a function, let’s consider the following example.

APPLIED EXAMPLE 7 Production Costs The management of Staedtler Office Equipment has determined that the daily marginal cost function associated with producing battery-operated pencil sharpeners is given by C(x)  0.000006x 2  0.006x  4

where C(x) is measured in dollars per unit and x denotes the number of units produced. Management has also determined that the daily fixed cost incurred in producing these pencil sharpeners is $100. Find Staedtler’s daily total cost for producing (a) the first 500 units and (b) the 201st through 400th units. Solution

a. Since C(x) is the marginal cost function, its antiderivative C(x) is the total cost function. The daily fixed cost incurred in producing the pencil sharpeners is C(0) dollars. Since the daily fixed cost is given as $100, we have C(0)  100. We are required to find C(500). Let’s compute C(500)  C(0), the net change in the total cost function C(x) over the interval [0, 500]. Using the fundamental theorem of calculus, we find C15002  C102 



500



500

C¿1x2 dx

0



10.000006x 2  0.006x  42 dx

0

 0.000002x 3  0.003x 2  4x `

500 0

 30.00000215002  0.00315002 2  415002 4 3

  30.000002102 3  0.003102 2  4102 4  1500

Therefore, C(500)  1500  C(0)  1500  100  1600, so the total cost incurred daily by Staedtler in producing 500 pencil sharpeners is $1600. b. The daily total cost incurred by Staedtler in producing the 201st through 400th units of battery-operated pencil sharpeners is given by

11.4 THE FUNDAMENTAL THEOREM OF CALCULUS

C14002  C12002 



400

C¿1x2 dx

200 400



779



10.000006x 2  0.006x  42 dx

200

 0.000002x 3  0.003x 2  4x `

400 200 2

 30.00000214002  0.00314002  41400 2 4 3

  30.00000212002 3  0.00312002 2  412002 4  552

or $552. Since C(x) is nonnegative for x in the interval (0, ), we have the following geometric interpretation of the two definite integrals in Example 7: 0500 C¿1x2 dx is the area of the region under the graph of the function C from x  0 to x  500, shown 400 C¿1x2 dx is the area of the region from x  200 to x  400, in Figure 19a, and 200 shown in Figure 19b. y

y

y = C'(x)

4 3

3

2 1

y = C'(x)

4

2 R1

R2

1

x

x 500 FIGURE 19

1000

1000 200 400 400 (b) Area of R2  200 C(x) dx

(a) Area of R1  0500 C(x) dx

APPLIED EXAMPLE 8 Assembly Time of Workers An efficiency study conducted for Elektra Electronics showed that the rate at which Space Commander walkie-talkies are assembled by the average worker t hours after starting work at 8 a.m. is given by the function f(t)  3t 2  12t  15

(0 t 4)

Determine how many walkie-talkies can be assembled by the average worker in the first hour of the morning shift. Let N(t) denote the number of walkie-talkies assembled by the average worker t hours after starting work in the morning shift. Then, we have

Solution

N(t)  f(t)  3t 2  12t  15

Therefore, the number of units assembled by the average worker in the first hour of the morning shift is N112  N102 



1

N ¿1t2 dt 

0



1

13t 2  12t  152 dt

0

 t  6t  15t `  1  6  15 1

3

2

0

 20

or 20 units.

780

11 INTEGRATION

Exploring with

TECHNOLOGY You can demonstrate graphically that 0x t dt  12 x 2 as follows:

1. Plot the graphs of y1  fnInt 1t, t, 0, x2  0x t dt and y2  12 x 2 on the same set of axes, using the viewing window [5, 5]  [0, 10]. 2. Compare the graphs of y1 and y2 and draw the desired conclusion.

APPLIED EXAMPLE 9 Projected Demand for Electricity A certain city’s rate of electricity consumption is expected to grow exponentially with a growth constant of k  0.04. If the present rate of consumption is 40 million kilowatt-hours (kWh) per year, what should be the total production of electricity over the next 3 years in order to meet the projected demand?

Explore & Discuss The definite integral 3 29  x2 dx cannot be 3 evaluated here using the fundamental theorem of calculus because the method of this section does not enable us to find an antiderivative of the integrand. But the integral can be evaluated by interpreting it as the area of a certain plane region. What is the region? And what is the value of the integral?

If R(t) denotes the expected rate of consumption of electricity t years from now, then

Solution

R(t)  40e0.04t

million kWh per year. Next, if C(t) denotes the expected total consumption of electricity over a period of t years, then C(t)  R(t)

Therefore, the total consumption of electricity expected over the next 3 years is given by 3

3

 C¿1t2 dt   40e

y

0

0.04t

dt

0

40 0.04t 3 e ` 0.04 0 0.12  10001e  12  127.5 

y = f (x)

A(t) x=t

x=b x

a

t

b

FIGURE 20

or 127.5 million kWh, the amount that must be produced over the next 3 years in order to meet the demand.

Validity of the Fundamental Theorem of Calculus

A(t)  area under the graph of f from x  a to x  t

To demonstrate the plausibility of the fundamental theorem of calculus for the case where f is nonnegative on an interval [a, b], let’s define an “area function” A as follows. Let A(t) denote the area of the region R under the graph of y  f(x) from x  a to x  t, where a t b (Figure 20). If h is a small positive number, then A(t  h) is the area of the region under the graph of y  f(x) from x  a to x  t  h. Therefore, the difference

y

y = f (x)

A(t  h)  A(t) x=b x a

t

b t+h

FIGURE 21

A(t  h)  A(t)  area under the graph of f from x  t to x  t  h

is the area under the graph of y  f(x) from x  t to x  t  h (Figure 21). Now, the area of this last region can be approximated by the area of the rectangle of width h and height f(t)—that is, by the expression h  f(t) (Figure 22). Thus, A(t  h)  A(t)  h  f(t)

where the approximations improve as h is taken to be smaller and smaller.

11.4 THE FUNDAMENTAL THEOREM OF CALCULUS y

781

Dividing both sides of the foregoing relationship by h, we obtain A1t  h2  A1t2 y = f (x)

h

 f 1t2

Taking the limit as h approaches zero, we find, by the definition of the derivative, that the left-hand side is

f (t) x a t

The area of the rectangle is h

h

hS0

t+h

FIGURE 22

A1t  h2  A1t2

lim

b

h

 A¿1t2

The right-hand side, which is independent of h, remains constant throughout the limiting process. Because the approximation becomes exact as h approaches zero, we find that

 f( t).

A(t)  f(t)

Since the foregoing equation holds for all values of t in the interval [a, b], we have shown that the area function A is an antiderivative of the function f(x). By Theorem 1 of Section 11.1, we conclude that A(x) must have the form

y

x=a

y = f (x)

R

A(x)  F(x)  C

where F is any antiderivative of f and C is a constant. To determine the value of C, observe that A(a)  0. This condition implies that

x=b

A(a)  F(a)  C  0

x a

b

FIGURE 23 The area of R is given by A(b).

or C  F(a). Next, since the area of the region R is A(b) (Figure 23), we see that the required area is A1b2  F 1b2  C  F 1b 2  F 1a2

Since the area of the region R is b

 f 1x2 dx a

we have b

 f 1x2 dx  F 1b2  F 1a2 a

as we set out to show.

11.4 Self-Check Exercises 1. Evaluate



2

1x  e x 2 dx.

0

2. The daily marginal profit function associated with producing and selling TexaPep hot sauce is P(x)  0.000006x 2  6

where x denotes the number of cases (each case contains 24 bottles) produced and sold daily and P(x) is measured in dollars/unit. The fixed cost is $400.

a. What is the total profit realizable from producing and selling 1000 cases of TexaPep per day? b. What is the additional profit realizable if the production and sale of TexaPep is increased from 1000 to 1200 cases/day? Solutions to Self-Check Exercises 11.4 can be found on page 784.

782

11 INTEGRATION

11.4 Concept Questions 1. State the fundamental theorem of calculus.

b. If a private jet airplane consumes fuel at the rate of R gal/min, write an integral giving the net fuel consumption by the airplane between times t  a and t  b (a b), where t is measured in minutes.

2. State the net change formula and use it to answer the following questions: a. If a company generates income at the rate of R dollars/ day, explain what ab R1t 2 dt measures, where a and b are measured in days with a b.

11.4 Exercises In Exercises 1–4, find the area of the region under the graph of the function f on the interval [a, b], using the fundamental theorem of calculus. Then verify your result using geometry.

1. f (x)  2; [1, 4]

2. f(x)  4; [1, 2]

3. f (x)  2x; [1, 3]

1 4. f 1x 2   x  1; 31, 4 4 4

In Exercises 5–16, find the area of the region under the graph of the function f on the interval [a, b].

5. f (x)  2x  3; [1, 2]

6. f (x)  4x  1; [2, 4]

7. f (x)  x 2  4; [1, 2]

8. f (x)  4x  x 2; [0, 4]

1 9. f 1x 2  ; 3 1, 24 x

1 10. f 1x2  2 ; 32, 4 4 x

11. f 1x2  1x; 3 1, 9 4

12. f (x)  x 3; [1, 3]

3 13. f 1x 2  1  2x; 38, 1 4

1 ; 31, 94 14. f 1x 2  1x

15. f(x)  e x; [0, 2]

16. f (x)  e x  x; [1, 2]

In Exercises 17–40, evaluate the definite integral.

17.



4



3



3

18.

3 dx 12x  3 2 dx

20.

2x2 dx

1 2

23.



22.

1x2  12 dx

24.

1/3

dx

26.

1

27.

 

4

2

3



4



4



2



3

1u du

1x3  2x 2  12 dx

2x3/2 dx

1

28.

0

29.

 8x dx 1

 4x 1

14  x 2 dx

0

2 8

25.



1 2

1

21.

2 dx

1 0

2

19.



2

1t 5  t 3  12 dt

1

1 dx x

30.

1

2 dx x

31.



4



3



1

x1x 2  1 2 dx

32.

0

33.

1t 2  t2 2 dt

3 4

37.

34.

 

1

1

1 2

1 dx x2

36.

4



1

1 a 1x  b dx 1x

1

39.



1x  42 1x  12 dx

0

1

35.



2

2 dx x3

1

38.

 12x1 1x  122 dx 0

3

3x  2x 2  4 dx x2

1x 2  1 2 2 dx

2

40.

 a1  u  u 1

1 2

b du

1

41. MARGINAL COST A division of Ditton Industries manufactures a deluxe toaster oven. Management has determined that the daily marginal cost function associated with producing these toaster ovens is given by C(x)  0.0003x 2  0.12x  20

where C(x) is measured in dollars/unit and x denotes the number of units produced. Management has also determined that the daily fixed cost incurred in the production is $800. a. Find the total cost incurred by Ditton in producing the first 300 units of these toaster ovens per day. b. What is the total cost incurred by Ditton in producing the 201st through 300th units/day? 42. MARGINAL REVENUE The management of Ditton Industries has determined that the daily marginal revenue function associated with selling x units of their deluxe toaster ovens is given by R(x)  0.1x  40

where R(x) is measured in dollars/unit. a. Find the daily total revenue realized from the sale of 200 units of the toaster oven. b. Find the additional revenue realized when the production (and sales) level is increased from 200 to 300 units. 43. MARGINAL PROFIT Refer to Exercise 41. The daily marginal profit function associated with the production and sales of the deluxe toaster ovens is known to be P(x)  0.0003x 2  0.02x  20

11.4 THE FUNDAMENTAL THEOREM OF CALCULUS

where x denotes the number of units manufactured and sold daily and P(x) is measured in dollars/unit. a. Find the total profit realizable from the manufacture and sale of 200 units of the toaster ovens per day. Hint: P(200)  P(0)  0200 P(x) dx, P(0)   800.

b. What is the additional daily profit realizable if the production and sale of the toaster ovens are increased from 200 to 220 units/day? 44. INTERNET ADVERTISING U.S. Internet advertising revenue grew at the rate of R(t)  0.82t  1.14

(0 t 4)

billion dollars/year between 2002 (t  0) and 2006 (t  4). The advertising revenue in 2002 was $5.9 billion. a. Find an expression giving the advertising revenue in year t. b. If the trend continued, what was the Internet advertising revenue in 2007? Source: Interactive Advertising Bureau

45. MOBILE-PHONE AD SPENDING Mobile-phone ad spending is expected to grow at the rate of R(t)  0.8256t0.04

(1 t 5)

billion dollars/year between 2007 (t  1) and 2011 (t  5). The mobile-phone ad spending in 2007 was $0.9 billion. a. Find an expression giving the mobile-phone ad spending in year t. b. If the trend continued, what will be the mobile-phone ad spending in 2012? Source: Interactive Advertising Bureau

46. EFFICIENCY STUDIES Tempco Electronics, a division of Tempco Toys, manufactures an electronic football game. An efficiency study showed that the rate at which the games are assembled by the average worker t hr after starting work at 8 a.m. is 3  t 2  6t  20 2

10 t 4 2

783

where t is measured in years, with t  0 corresponding to 1997. How many pocket computers were sold over the 6-yr period between the beginning of 1997 and the end of 2002? Source: Dataquest, Inc.

49. SINGLE FEMALE-HEADED HOUSEHOLDS WITH CHILDREN The percentage of families with children that are headed by single females grew at the rate of R(t)  0.8499t 2  3.872t  5

(0 t 3)

households/decade between 1970 (t  0) and 2000 (t  3). The number of such households stood at 5.6% of all families in 1970. a. Find an expression giving the percentage of these households in the tth decade. b. If the trend continued, estimate the percentage of these households in 2010. c. What was the net increase in the percentage of these households from 1970 to 2000? Source: U.S. Census Bureau

50. AIR PURIFICATION To test air purifiers, engineers ran a purifier in a smoke-filled 10-ft  20-ft room. While conducting a test for a certain brand of air purifier, it was determined that the amount of smoke in the room was decreasing at the rate of R(t)  0.00032t 4  0.01872t 3  0.3948t 2  3.83t  17.63 (0 t 20)

percent of the (original) amount of the smoke per minute, t min after the start of the test. How much smoke was left in the room 5 min after the start of the test? Ten min after the start of the test? Source: Consumer Reports

51. TV SET-TOP BOXES The number of television set-top boxes shipped worldwide from the beginning of 2003 until the beginning of 2009 is projected to be f(t)  0.05556t 3  0.262t 2  17.46t  63.4 (0 t 6)

units/hour. a. Find the total number of games the average worker can be expected to assemble in the 4-hr morning shift. b. How many units can the average worker be expected to assemble in the first hour of the morning shift? In the second hour of the morning shift?

million units/year, where t is measured in years, with t  0 corresponding to 2003. If the projection held true, how many set-top boxes were expected to be shipped from the beginning of 2003 until the beginning of 2009?

47. SPEEDBOAT RACING In a recent pretrial run for the world water speed record, the velocity of the Sea Falcon II t sec after firing the booster rocket was given by

52. CANADIAN OIL-SANDS PRODUCTION The production of oil (in millions of barrels per day) extracted from oil sands in Canada is projected to grow according to the function

√(t)  t 2  20t  440

(0 t 20)

feet/second. Find the distance covered by the boat over the 20-sec period after the booster rocket was activated. Hint: The distance is given by 020 √ (t) dt.

48. POCKET COMPUTERS Annual sales (in millions of units) of pocket computers are expected to grow in accordance with the function f (t)  0.18t 2  0.16t  2.64

(0 t 6)

Source: In-Stat.

P(t) 

4.76 1  4.11e0.22t

(0 t 15)

where t is measured in years, with t  0 corresponding to 2005. What is the total production of oil from oil sands over the years from 2005 until 2020 (t  15)? Hint: Multiply the integrand by

e0.22t . e0.22t

Source: Canadian Association of Petroleum Producers.

784

11 INTEGRATION

53. SENIOR CITIZENS The population aged 65 yr old and older (in millions) from 2000 to 2050 is projected to be f 1t 2 

10 t 52

85 1  1.859e0.66t

where t is measured in decades, with t  0 corresponding to 2000. By how much will the population aged 65 yr and older increase from the beginning of 2000 until the beginning of 2030? Hint: Multiply the integrand by e0.66t/e0.66t.

56. Find the area of the region bounded by the graph of the function f 1x2  1x  12 / 1x, the x-axis, and the lines x  a and x  b where a and b are, respectively, the x-coordinates of the relative minimum point and the inflection point of f. In Exercises 57–60, determine whether the statement is true or false. Give a reason for your answer.

57.



V

0

R

k x1R2  x 2 2 dx L



1

1

Source: U.S. Census Bureau

54. BLOOD FLOW Consider an artery of length L cm and radius R cm. Using Poiseuille’s law (page 131), it can be shown that the rate at which blood flows through the artery (measured in cubic centimeters/second) is given by



1

58.

1 x

3

Hint: Use the substitution u  R  x .

1 2x

2

`

1 1

1 1    a b  0 2 2

1 1 dx  ln 0 x 0 `  ln 0 1 0  ln 0 1 0  ln 1  ln 1  0 x 1 1

59. 02 11  x2 dx gives the area of the region under the graph of f(x)  1  x on the interval [0, 2]. 60. The total revenue realized in selling the first 500 units of a product is given by



where k is a constant. Find an expression for V that does not involve an integral. 2

dx  

500

R¿1x 2 dx  R15002  R102

0

2

where R(x) is the total revenue.

55. Find the area of the region bounded by the graph of the function f(x)  x4  2x 2  2, the x-axis, and the lines x  a and x  b, where a b and a and b are the x-coordinates of the relative maximum point and a relative minimum point of f, respectively.

11.4 Solutions to Self-Check Exercises 1.



2

1x  e x 2 dx 

0

2 1 2 x  ex ` 2 0

1 1  c 12 2 2  e 2 d  c 10 2  e 0 d 2 2  2  e2  1

So, P(1000)  4000  P(0)  4000  400, or $3600/day [P(0)  C(0)]. b. The additional profit realizable is given by



1200

1000

 e2  1



1000

P¿1x2 dx 

0

1200 1000

 30.000002112002 3  611200 2 4

  30.000002110002 3  611000 2 4

2. a. We want P(1000), but P11000 2  P10 2 

P¿1x 2 dx  0.000002x 3  6x `



1000

 3744  4000

10.000006x 2  62 dx

 256

0

 0.000002x 3  6x `

1000 0

 0.00000211000 2 3  611000 2

That is, the company sustains a loss of $256/day if production is increased from 1000 to 1200 cases/day.

 4000

USING

TECHNOLOGY

Evaluating Definite Integrals Some graphing utilities have an operation for finding the definite integral of a function. If your graphing utility has this capability, use it to work through the example and exercises of this section.

11.5 EVALUATING DEFINITE INTEGRALS

785

EXAMPLE 1 Use the numerical integral operation of a graphing utility to evaluate



2

1

Using the numerical integral operation of a graphing utility, we find

Solution



2

1

2x  4 dx 1x 2  12 3/2

2x  4 dx  fnInt112x  42/1x^2  12^1.5, x, 1, 22  6.92592226 1x 2  12 3/2

TECHNOLOGY EXERCISES In Exercises 1–4, find the area of the region under the graph of f on the interval [a, b]. Express your answer to four decimal places.

1. f(x)  0.002x 5  0.032x 4  0.2x 2  2; [1.1, 2.2] 2. f 1x 2  x2x3  1; 31, 2 4

ln x 21  x 2

; 31, 2 4



2.3

10.2x4  0.32x 3  1.2x  1 2 dx

1.2

 x1x

 12 3.2 dx

4

1

7.



2



2

0

9.

0

3x  2x  1 dx 2x 2  3 3

e

2

8.

2x 2  1



2



3

1

x

dx

10 t 92

14. MARIJUANA ARRESTS The number of arrests for marijuana sales and possession in New York City grew at the rate of approximately f 1t2  0.0125t 4  0.01389t 3  0.55417t 2  0.53294t  4.95238

3

6.

 8833.379t  20,000

Source: Centers for Disease Control

In Exercises 5–10, evaluate the definite integral.

5.

f 1t 2  53.254t 4  673.7t 3  2801.07t 2

with t  0 corresponding to the beginning of 1988. Find the total number of AIDS-related deaths in the United States between the beginning of 1988 and the end of 1996.

3. f 1x 2  1xex; 30, 3 4 4. f 1x 2 

13. THE GLOBAL EPIDEMIC The number of AIDS-related deaths/year in the United States is given by the function

10.

1x  1 dx 2x 2  1 ex ln1x 2  12 dx

1

11. Rework Exercise 50, Exercises 11.4. 12. Rework Exercise 53, Exercises 11.4.

10 t 52

thousand/year, where t is measured in years, with t  0 corresponding to the beginning of 1992. Find the approximate number of marijuana arrests in the city from the beginning of 1992 to the end of 1997. Source: State Division of Criminal Justice Services

15. POPULATION GROWTH The population of a certain city is projected to grow at the rate of 18 1t  1 ln 1t  1 thousand people/year t yr from now. If the current population is 800,000, what will be the population 45 yr from now?

11.5 Evaluating Definite Integrals This section continues our discussion of the applications of the fundamental theorem of calculus.

Properties of the Definite Integral Before going on, we list the following useful properties of the definite integral, some of which parallel the rules of integration of Section 11.1.

786

11 INTEGRATION

Properties of the Definite Integral

Let f and t be integrable functions; then, 1.



a

f 1x2 dx  0



b

f 1x2 dx  

a

2.

a

a

 f 1x2 dx b

b

3.

b

 cf 1x2 dx  c  f 1x2 dx a

4.



b

b

b

 f 1x2 dx  t1x2 dx

3 f 1x2 t1x2 4 dx 

a

a

b

5.

1c, a constant 2

a

a

c

b

 f 1x2 dx   f 1x2 dx   f 1x2 dx a

a

1a c b 2

c

Property 5 states that if c is a number lying between a and b so that the interval [a, b] is divided into the intervals [a, c] and [c, b], then the integral of f over the interval [a, b] may be expressed as the sum of the integral of f over the interval [a, c] and the integral of f over the interval [c, b]. Property 5 has the following geometric interpretation when f is nonnegative. By definition

y

y = f (x)

b

 f 1x2 dx

x a

c

a

b

FIGURE 24 ab f(x) dx  ac f(x) dx  cb f( x) dx

is the area of the region under the graph of y  f(x) from x  a to x  b (Figure 24). Similarly, we interpret the definite integrals



c

f 1x2 dx and

a

b

 f 1x2 dx c

as the areas of the regions under the graph of y  f(x) from x  a to x  c and from x  c to x  b, respectively. Since the two regions do not overlap, we see that



b

f 1x2 dx 

a



c

f 1x2 dx 

a

b

 f 1x2 dx c

The Method of Substitution for Definite Integrals Our first example shows two approaches generally used when evaluating a definite integral using the method of substitution. 4

EXAMPLE 1 Evaluate

 x29  x

2

dx.

0

Solution Method 1

We first find the corresponding indefinite integral: I   x29  x 2 dx

11.5 EVALUATING DEFINITE INTEGRALS

787

Make the substitution u  9  x 2 so that d 19  x 2 2 dx dx  2x dx 1 x dx  du Divide both sides by 2. 2 du 

Then, 1 1 1u du   u1/2 du 2 2 1 1  u3/2  C  19  x 2 2 3/2  C 3 3

I

Substitute 9  x 2 for u.

Using this result, we now evaluate the given definite integral: 4

 x29  x 0

Method 2

2

4 1 19  x 2 2 3/2 ` 3 0 1  3 19  162 3/2  93/2 4 3 1 98  1125  272   32 23 3 3

dx 

Changing the Limits of Integration. As before, we make the substitution u  9  x2

(11)

so that du  2x dx 1 x dx  du 2

Next, observe that the given definite integral is evaluated with respect to x with the range of integration given by the interval [0, 4]. If we perform the integration with respect to u via the substitution (11), then we must adjust the range of integration to reflect the fact that the integration is being performed with respect to the new variable u. To determine the proper range of integration, note that when x  0, Equation (11) implies that u  9  02  9

which gives the required lower limit of integration with respect to u. Similarly, when x  4, u  9  16  25

is the required upper limit of integration with respect to u. Thus, the range of integration when the integration is performed with respect to u is given by the interval [9, 25]. Therefore, we have



0

4



25



25

1 1 1u du  u1/2 du 2 2 9 9 1 3/2 25 1 3/2  u `  125  93/2 2 3 3 9 1 98  1125  272   32 23 3 3

x29  x 2 dx 

which agrees with the result obtained using Method 1.

788

11 INTEGRATION

When you use the method of substitution, make sure you adjust the limits of integration to reflect integrating with respect to the new variable u.

Exploring with

TECHNOLOGY Refer to Example 1. You can confirm the results obtained there by using a graphing utility as follows: 1. Use the numerical integration operation of the graphing utility to evaluate 4

 x29  x

2

dx

0

2. Evaluate

1 2



25

1u du.

9



3. Conclude that

4



1 2

x 29  x 2 dx 

0

25

1u du.

9

2

EXAMPLE 2 Evaluate

 xe

2x2

dx.

0

Let u  2x 2 so that du  4x dx, or x dx  14 du. When x  0, u  0, and when x  2, u  8. This gives the lower and upper limits of integration with respect to u. Making the indicated substitutions, we find

Solution



2 2

xe 2x dx 

0



0



EXAMPLE 3 Evaluate

0

1

8

8 1 u 1 1 e du  e u `  1e 8  12 4 4 4 0

x2 dx. x3  1

Let u  x 3  1 so that du  3x 2 dx, or x 2 dx  13 du. When x  0, u  1, and when x  1, u  2. This gives the lower and upper limits of integration with respect to u. Making the indicated substitutions, we find

Solution



0

1



2

2 1 1 x2 du dx   ln 0 u 0 ` x3  1 3 1 u 3 1 1 1  1ln 2  ln 1 2  ln 2 3 3

Finding the Area under a Curve EXAMPLE 4 Find the area of the region R under the graph of f (x)  e(1/2)x from x  1 to x  1. Solution

The region R is shown in Figure 25. Its area is given by A



1

e11/22x dx

1

To evaluate this integral, we make the substitution u

1 x 2

11.5 EVALUATING DEFINITE INTEGRALS y

so that y = e(1/2)x

x = –1

1 dx 2 dx  2 du

du 

x=1 2 1 R x

–2

–1

FIGURE 25 Area of R 

789

1

2

When x  1, u  12, and when x  1, u  12. Making the indicated substitutions, we obtain

3

A



1

e11/22x dx  2

1

1 1 e(1/2)x dx

 2e u `



1/2

eu du

1/2

1/2 1/2

 21e 1/2  e 1/2 2

or approximately 2.08 square units.

Explore & Discuss Let f be a function defined piecewise by the rule 1x f 1x2  • 1

if 0 x 1 if 1 x 2

x

How would you use Property 5 of definite integrals to find the area of the region under the graph of f on [0, 2]? What is the area?

Average Value of a Function The average value of a function over an interval provides us with an application of the definite integral. Recall that the average value of a set of n numbers is the number y1  y2  p  yn n

Now, suppose f is a continuous function defined on [a, b]. Let’s divide the interval [a, b] into n subintervals of equal length (b  a)/n. Choose points x1, x2, . . . , xn in the first, second, . . . , and nth subintervals, respectively. Then, the average value of the numbers f(x1), f(x2), . . . , f(xn), given by f 1x1 2  f 1x2 2  p  f 1xn 2 n

is an approximation of the average of all the values of f(x) on the interval [a, b]. This expression can be written in the form 1b  a2

1b  a2

c f 1x1 2

# 1  f 1x2 2 # 1  p  f 1xn 2 # 1 d n

n

n

1 ba ba p ba  c f 1x1 2 #  f 1x2 2 #   f 1xn 2 # d n n n ba 1  3 f 1x1 2 ¢x  f 1x2 2 ¢x  p  f 1xn 2 ¢x4 ba

(12)

790

11 INTEGRATION

As n gets larger and larger, the expression (12) approximates the average value of f(x) over [a, b] with increasing accuracy. But the sum inside the brackets in (12) is a Riemann sum of the function f over [a, b]. In view of this, we have f 1x1 2  f 1x2 2  p  f 1xn 2 lim c d nS n 1  lim 3 f 1x1 2 ¢x  f 1x2 2 ¢x  p  f 1xn 2 ¢x4 b  a nS 

b

 f 1x2 dx

1 ba

a

This discussion motivates the following definition. The Average Value of a Function

Suppose f is integrable on [a, b]. Then the average value of f over [a, b] is 1 ba

b

 f 1x2 dx a

EXAMPLE 5 Find the average value of the function f 1x 2  1x over the interval [0, 4]. Solution

The required average value is given by 1 40



4

1x dx 

0

1 4



4

x 1/2 dx

0



1 3/2 4 1 3/2 x `  14 2 6 6 0



4 3

APPLIED EXAMPLE 6 Automobile Financing The interest rates charged by Madison Finance on auto loans for used cars over a certain 6-month period in 2008 are approximated by the function r1t2  

1 3 7 2 t  t  3t  12 12 8

10 t 62

where t is measured in months and r(t) is the annual percentage rate. What is the average rate on auto loans extended by Madison over the 6-month period? Solution

The average rate over the 6-month period in question is given by 1 60

6

 a12 t



0

1

3



7 2 t  3t  12 b dt 8

6 1 1 7 3 3 2 a t 4  t  t  12t b ` 6 48 24 2 0

1 1 7 3 3 c  164 2  16 2  162 2  12162 d 6 48 24 2 9 

or 9% per year.

11.5 EVALUATING DEFINITE INTEGRALS

791

APPLIED EXAMPLE 7 Drug Concentration in a Body The amount of a certain drug in a patient’s body t days after it has been administered is C(t)  5e0.2t

units. Determine the average amount of the drug present in the patient’s body for the first 4 days after the drug has been administered. Solution The average amount of the drug present in the patient’s body for the first 4 days after it has been administered is given by

1 40



4

5e0.2t dt 

0

5 4



4

e0.2t dt

0

4 5 1  c a b e 0.2t ` d 4 0.2 0 5  15e 0.8  52 4  3.44

or approximately 3.44 units. We now give a geometric interpretation of the average value of a function f over an interval [a, b]. Suppose f(x) is nonnegative so that the definite integral

y

b

y = f (x)

 f 1x2 dx

y = g(x) = k

k

a

x a

b

FIGURE 26 The average value of f over [a, b] is k.

gives the area under the graph of f from x  a to x  b (Figure 26). Observe that, in general, the “height” f(x) varies from point to point. Can we replace f(x) by a constant function t(x)  k (which has constant height) such that the areas under each of the two functions f and t are the same? If so, since the area under the graph of t from x  a to x  b is k(b  a), we have k 1b  a2 

b

 f 1x2 dx a

k

1 ba



b

f 1x2 dx

a

so that k is the average value of f over [a, b]. Thus, the average value of a function f over an interval [a, b] is the height of a rectangle with base of length (b  a) that has the same area as that of the region under the graph of f from x  a to x  b.

11.5 Self-Check Exercises 1. Evaluate



2

12x  5 dx.

f(t)  t 3  7t 2  17t  280

(0 t 5)

0

2. Find the average value of the function f(x)  1  x 2 over the interval [1, 2]. 3. The median price of a house in a southwestern state between January 1, 2003, and January 1, 2008, is approximated by the function

where f(t) is measured in thousands of dollars and t is expressed in years, with t  0 corresponding to the beginning of 2003. Determine the average median price of a house over that time interval. Solutions to Self-Check Exercises 11.5 can be found on page 795.

792

11 INTEGRATION

11.5 Concept Questions 1. Describe two approaches used to evaluate a definite integral using the method of substitution. Illustrate with the integral 01 x 2 1x3  12 2 dx.

2. Define the average value of a function f over an interval [a, b]. Give a geometric interpretation.

11.5 Exercises In Exercises 1–28, evaluate the definite integral. 2

1.

1

 x1x

 12 3 dx

2

2.

0

 x 25x

2

2

 4 dx

4.

 x 1x 2

3



1

 12

3/2

dx

9.



2

 2 dx

6.



5



2

12x  1 2

8.

x 2x  5 2

0

dx

dx

12x  1 2 4 dx

1

 12x  42 1x

2

 4x  82 3 dx



1



2



5

x 1x  1 2 dx 2

3

4

1

12.

a x3 

1

13.

4

x 1x  1 dx

14.

 x 1x  1 dx 1

Hint: Let u  x  1. 2

 xe

1

x2

16.

dx

0

17.



1



1



6



2



2



2

1e2x  x2  1 2 dx

18.

xe x 1 dx 2

3

23.

20.

1

27.

1



2



4



1



1

0

2 dx x2

22.

0

x  2x dx x  3x2  1 2

3

1

25.

x

dx

1e t  et 2 dt

0

1

21.

e 0

0

19.

33. f(x)  ex/2; [1, 2]

a 4e2u 

1 b du u

a 2e4x 

1 b dx x2

24.

0 2

26.

e1x dx 1x

34. f(x) 

ln x ; [1, 2] 4x

35. f(x)  2x  3; [0, 2]

36. f(x)  8  x; [1, 4]

37. f(x)  2x  3; [1, 3]

38. f(x)  4  x 2; [2, 3]

40. f(x)  x 3; [1, 1]

41. f 1x2  12x  1; 30, 44

42. f(x)  ex; [0, 4]

43. f(x)  xe x ; [0, 2]

e dx 1  ex

 a 1  x  e b dx 

1

2

ln x dx x

1 ; 3 0, 24 x1

45. WORLD PRODUCTION OF COAL A study proposed in 1980 by researchers from the major producers and consumers of the world’s coal concluded that coal could and must play an important role in fueling global economic growth over the next 20 yr. The world production of coal in 1980 was 3.5 billion metric tons. If output increased at the rate of 3.5e0.05t billion metric tons/year in year t (t  0 corresponding to 1980), determine how much coal was produced worldwide between 1980 and the end of the 20th century.

18e0.6t

x

1

2

46. NEWTON’S LAW OF COOLING A bottle of white wine at room temperature (68°F) is placed in a refrigerator at 4 p.m. Its temperature after t hr is changing at the rate of

x dx 1  2x2

1

28.

1 ; [1, 2] x2

In Exercises 35–44, find the average value of the function f over the indicated interval [a, b].

44. f 1x2 

3 b 1x4  3x2 2 dx 4

1

15.

31. f(x) 

39. f(x)  x 2  2x  3; [1, 2]

1

11.

30. f(x)  x 3  x; [0, 1]

2

2

10.

29. f(x)  x 2  2x  2; [1, 2]

32. f(x)  2  1x  1; [0, 3] 5/2

1

1 dx 12x  1

0

 x 23x

2

1

0

7.

 1 2 4 dx

3

3

0

5.

2

0

1

3.

 x 12x

In Exercises 29–34, find the area of the region under the graph of f on [a, b].

x

°F/hour. By how many degrees will the temperature of the wine have dropped by 7 p.m.? What will the temperature of the wine be at 7 p.m.? 47. NET INVESTMENT FLOW The net investment flow (rate of capital formation) of the giant conglomerate LTF incorporated is projected to be t

1 2 t 1 B2

11.5 EVALUATING DEFINITE INTEGRALS

million dollars/year in year t. Find the accruement on the company’s capital stock in the second year. Hint: The amount is given by 2

 t B2 t 1

2

 1 dt

1

48. OIL PRODUCTION Based on a preliminary report by a geological survey team, it is estimated that a newly discovered oil field can be expected to produce oil at the rate of 600t 2 5 R 1t2  3 t  32

10 t 202

thousand barrels/year, t yr after production begins. Find the amount of oil that the field can be expected to yield during the first 5 yr of production, assuming that the projection holds true. 49. DEPRECIATION: DOUBLE DECLINING-BALANCE METHOD Suppose a tractor purchased at a price of $60,000 is to be depreciated by the double declining-balance method over a 10-yr period. It can be shown that the rate at which the book value will be decreasing is given by 0.22314t

R(t)  13388.61e

(0 t 10)

dollars/year at year t. Find the amount by which the book value of the tractor will depreciate over the first 5 yr of its life. 50. VELOCITY OF A CAR A car moves along a straight road in such a way that its velocity (in feet/second) at any time t (in seconds) is given by √ 1t 2  3t 216  t 2

10 t 42

Find the distance traveled by the car in the 4 sec from t  0 to t  4. 51. MOBILE-PHONE AD SPENDING Mobile-phone ad spending between 2005 (t  1) and 2011 (t  7) is projected to be S(t)  0.86t 0.96

(1 t 7)

where S(t) is measured in billions of dollars and t is measured in years. What is the projected average spending per year on mobile-phone spending between 2005 and 2011? Source: Interactive Advertising Bureau

52. GLOBAL WARMING The increase in carbon dioxide (CO2) in the atmosphere is a major cause of global warming. Using data obtained by Charles David Keeling, professor at Scripps Institution of Oceanography, the average amount of CO2 in the atmosphere from 1958 through 2007 is approximated by A(t)  0.010716t 2  0.8212t  313.4

(1 t 50)

where A(t) is measured in parts per million volume (ppmv) and t in years, with t  1 corresponding to 1958. Find the average rate of increase of the average amount of CO2 in the atmosphere from 1958 through 2007. Source: Scripps Institution of Oceanography

793

53. PROJECTED U.S. GASOLINE USAGE The White House wants to cut the gasoline usage from 140 billion gallons per year in 2007 to 128 billion gallons per year in 2017. But estimates by the Department of Energy’s Energy Information Agency suggest that won’t happen. In fact, the agency’s projection of gasoline usage from the beginning of 2007 until the beginning of 2017 is given by A(t)  0.014t 2  1.93t  140

(0 t 10)

where A(t) is measured in billions of gallons/year and t is in years, with t  0 corresponding to 2007. a. According to the agency’s projection, what will be gasoline consumption at the beginning of 2017? b. What will be the average consumption/year over the period from the beginning of 2007 until the beginning of 2017? Source: U.S. Department of Energy, Energy Information Agency

54. U.S. CITIZENS 65 YEARS AND OLDER The number of U.S. citizens aged 65 yr and older from 1900 through 2050 is estimated to be growing at the rate of R(t)  0.063t 2  0.48t  3.87

(0 t 15)

million people/decade, where t is measured in decades, with t  0 corresponding to 1900. Show that the average rate of growth of U.S. citizens aged 65 yr and older between 2000 and 2050 will be growing at twice the rate of that between 1950 and 2000. Source: American Heart Association

55. OFFICE VACANCY RATE The total vacancy rate (in percent) of offices in Manhattan from 2000 through 2006 is approximated by the function R(t)  0.032t 4  0.26t 3  0.478t 2  5.82t  3.8 (0 t 6)

where t is measured in years, with t  0 corresponding to 2000. What was the average vacancy rate of offices in Manhattan over the period from 2000 through 2006? Source: Cushman and Wakefield

56. AVERAGE YEARLY SALES The sales of Universal Instruments in the first t yr of its operation are approximated by the function S 1t2  t20.2t 2  4

where S(t) is measured in millions of dollars. What were Universal’s average yearly sales over its first 5 yr of operation? 57. CABLE TV SUBSCRIBERS The manager of TeleStar Cable Service estimates that the total number of subscribers to the service in a certain city t yr from now will be N 1t2  

40,000 11  0.2t

 50,000

Find the average number of cable television subscribers over the next 5 yr if this prediction holds true.

794

11 INTEGRATION

58. CONCENTRATION OF A DRUG IN THE BLOODSTREAM The concentration of a certain drug in a patient’s bloodstream t hr after injection is C 1t2 

0.2t t2  1

63. Prove Property 1 of the definite integral.

3

mg/cm . Determine the average concentration of the drug in the patient’s bloodstream over the first 4 hr after the drug is injected. 59. AVERAGE PRICE OF A COMMODITY The price of a certain commodity in dollars/unit at time t (measured in weeks) is given by 2t

p  18  3e

Hint: Let F be an antiderivative of f and use the definition of the definite integral.

64. Prove Property 2 of the definite integral. Hint: See Exercise 63.

65. Verify by direct computation that 3

2

 6e

60. FLOW OF BLOOD IN AN ARTERY According to a law discovered by 19th-century physician Jean Louis Marie Poiseuille, the velocity of blood (in centimeters/second) r cm from the central axis of an artery is given by √(r)  k(R  r ) 2

2

where k is a constant and R is the radius of the artery. Find the average velocity of blood along a radius of the artery (see the accompanying figure). 1 R  √ 1r2 dr. R 0

1

 x dx    x dx

t/3

What is the average price of the commodity over the 5-wk period from t  0 to t  5?

Hint: Evaluate

h ft. The velocity of the hammer after falling a distance of x ft is √  12tx ft/sec 10 x h2 . Show that the average velocity of the hammer over this path is √  23 12th ft/sec.

2

1

3

66. Prove Property 3 of the definite integral. Hint: See Exercise 63.

67. Verify by direct computation that



9

9

21x dx  2

1

 1x dx 1

68. Verify by direct computation that



1

11  x  e x 2 dx 

0

1

1

1

 dx   x dx   e dx x

0

0

0

What properties of the definite integral are demonstrated in this exercise? 69. Verify by direct computation that



R

3



11  x 3 2 dx 

0

r

1

11  x 3 2 dx 

0



3

11  x 3 2 dx

1

What property of the definite integral is demonstrated here? Blood vessel

70. Verify by direct computation that 61. WASTE DISPOSAL When organic waste is dumped into a pond, the oxidization process that takes place reduces the pond’s oxygen content. However, in time, nature will restore the oxygen content to its natural level. Suppose that the oxygen content t days after organic waste has been dumped into a pond is given by f 1t2  100 a

t 2  10t  100 b t 2  20t  100

percent of its normal level. Find the average content of oxygen in the pond over the first 10 days after organic waste has been dumped into it. Hint: Show that t 2  10t  100 100 10  1 t  10 t 2  20t  100 1t  10 2 2

62. VELOCITY OF A FALLING HAMMER During the construction of a high-rise apartment building, a construction worker accidently drops a hammer that falls vertically a distance of



3

11  x 3 2 dx

0





1

11  x 3 2 dx 

0



2

11  x 3 2 dx 

1



3

11  x 3 2 dx

2

hence showing that Property 5 may be extended. 71. Evaluate 3 11  1x2ex dx. 3

72. Evaluate 3 f 1x2 dx, given that 0 f 1x2 dx  4. 0

3

2 73. Given that 1 f 1x2 dx  2 and 1 t 1x2 dx  3, evaluate 2

a. 1 3 2f 1x2  t 1x2 4 dx 2

b. 1 3 t 1x2  f 1x2 4 dx 2

c. 1 3 2f 1x2  3t 1x2 4 dx 2

74. Given that 1 f 1x2 dx  2 and 0 f 1x2 dx  3, evaluate 2

a. 1 f 1x2 dx 0

2

b. 0 f 1x2 dx  1 f 1x2 dx 2

0

11.5 EVALUATING DEFINITE INTEGRALS

In Exercises 75–80, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.

75.



2



3

2

76.

1

x

e dx  0 11  x dx  x2



3

1

79. If f and t are continuous on [a, b] and k is a constant, then b

3kf 1x2  t 1x 2 4 dx  k

a



b

f 1x 2 dx 

a

b

 t 1x 2 dx a

80. If f is continuous on [a, b] and a c b, then

1

77.

78. If f  is continuous on [0, 2], then 02 f ¿(x) dx  f (2)  f (0).



dx x2

795

 x 1x  1 dx  1x  1  0

1

0



1 1 12 x dx  x2 1x  1 `  2 2 0

c

f 1x 2 dx 

b



a

c

f 1x2 dx 

b

 f 1x2 dx a

11.5 Solutions to Self-Check Exercises 1. Let u  2x  5. Then, du  2 dx, or dx  12 du. Also, when x  0, u  5, and when x  2, u  9. Therefore,



2

12x  5 dx 

0



2

12x  5 2 1/2 dx

0

1  2



3. The average median price of a house over the stated time interval is given by

9 1/2

u

du

5

1 3/2 3 9  53/2 4 3

1  127  5 152 3

5

1t 3  7t 2  17t  2802 dt

0

5 1 1 7 17 2  a t4  t3  t  280t b ` 5 4 3 2 0

9 1 2  a b a u3/2 b ` 2 3 5





1 50



1 1 7 17 c 152 4  152 3  152 2  280152 d 5 4 3 2

 295.417

or $295,417.

2. The required average value is given by 1 2  112



2

11  x 2 2 dx 

1

USING

1 3



2

11  x 2 2 dx

1



2 1 1 ax  x 3 b ` 3 3 1



8 1 1 c a2  b  a1  b d  0 3 3 3

TECHNOLOGY

Evaluating Definite Integrals for Piecewise-Defined Functions We continue using graphing utilities to find the definite integral of a function. But here we will make use of Property 5 of the properties of the definite integral (page 786). EXAMPLE 1 Use the numerical integral operation of a graphing utility to evaluate



2

f 1x2 dx

1

(continued)

796

11 INTEGRATION

where f 1x2  e Solution

x2 1x

if x 0 if x  0

Using Property 5 of the definite integral, we can write



2

f 1x2 dx 

1



0

2

x2 dx 

1

x

1/2

dx

0

Using a graphing utility, we find



2

f 1x2 dx  fnInt1x^2, x, 1, 02  fnInt1x^0.5, x, 0, 22

1

 0.333333  1.885618  1.552285

TECHNOLOGY EXERCISES In Exercises 1–4, use Property 5 of the properties of the definite integral (page 786) to evaluate the definite integral accurate to six decimal places. 2 1. 1 f 1x2 dx, where

f 1x 2  e

2.3x3  3.1x2  2.7x  3 1.7x2  2.3x  4.3

1x 2. 03 f 1x2 dx, where f 1x 2  • 1  x2 2 0.5e0.1x 3. 2 f 1x2 dx, where f 1x 2  e 2

if x 1 if x  1

if 0 x 1 if x  1

x  2x  4 2 ln 1x  e 2 2 4

2

if x 0 if x  0

6 4. 2 f 1x2 dx, where

2x3  3x2  x  2 f 1x 2  • 13x  4  5 x2  3x  5

if x 1 if 1 x 4 if x  4

5. AIDS IN MASSACHUSETTS The rate of growth (and decline) of the number of AIDS cases diagnosed in Massachusetts from the beginning of 1989 (t  0) through the end of 1997 (t  8) is approximated by the function 69.83333t 2  30.16667t  1000 1719 f 1t2  μ 28.79167t 3  491.37500t 2 2985.083333t  7640

if 0 t 3 if 3 t 4 if 4 t 8

where f(t) is measured in the number of cases/year. Estimate the total number of AIDS cases diagnosed in Massachusetts from the beginning of 1989 through the end of 1997. Source: Massachusetts Department of Health

6. CROP YIELD If left untreated on bean stems, aphids (small insects that suck plant juices) will multiply at an increasing rate during the summer months and reduce productivity and crop yield of cultivated crops. But if the aphids are treated in mid-June, the numbers decrease sharply to less than 100/bean stem, allowing for steep rises in crop yield. The function F 1t2  e

62e 1.152t 349e 1.3241t1.52

if 0 t 1.5 if 1.5 t 3

gives the number of aphids on a typical bean stem at time t, where t is measured in months, t  0 corresponding to the beginning of May. Find the average number of aphids on a typical bean stem over the period from the beginning of May to the beginning of August. 7. ABSORPTION OF DRUGS Jane took 100 mg of a drug in the morning and another 100 mg of the same drug at the same time the following morning. The amount of the drug in her body t days after the first dosage was taken is given by A1t 2  e

100e1.4t 10011  e1.4 2e1.4t

if 0 t 1 if t  1

Find the average amount of the drug in Jane’s body over the first 2 days. 8. ABSORPTION OF DRUGS The concentration of a drug in an organ at any time t (in seconds) is given by C 1t2  e

0.3t  1811  e t/60 2 18e t/60  12e 1t202/60

if 0 t 20 if t  20

where C(t) is measured in grams/cubic centimeter (g/cm3). Find the average concentration of the drug in the organ over the first 30 sec after it is administered.

797

11.6 AREA BETWEEN TWO CURVES

11.6 Area between Two Curves Suppose a certain country’s petroleum consumption is expected to grow at the rate of f(t) million barrels per year, t years from now, for the next 5 years. Then, the country’s total petroleum consumption over the period of time in question is given by the area under the graph of f on the interval [0, 5] (Figure 27). Next, suppose that because of the implementation of certain energy-conservation measures, the rate of growth of petroleum consumption is expected to be t(t) million barrels per year instead. Then, the country’s projected total petroleum consumption over the 5-year period is given by the area under the graph of t on the interval [0, 5] (Figure 28). Therefore, the area of the shaded region S lying between the graphs of f and t on the interval [0, 5] (Figure 29) gives the amount of petroleum that would be saved over the 5-year period because of the conservation measures.

y

y

y = g(t)

t

t

y = f (t)

Million barrels per year

Million barrels per year

y = f (t)

Million barrels per year

y

y = g(t) S

t

5

5

5

Years

Years

Years

FIGURE 27

FIGURE 28

FIGURE 29

At a rate of consumption of f( t) million barrels per year, the total petroleum consumption is given by the area of the region under the graph of f.

At a rate of consumption of g(t) million barrels per year, the total petroleum consumption is given by the area of the region under the graph of g.

The area of S gives the amount of petroleum that would be saved over the 5-year period.

But the area of S is given by Area under the graph of f on [a, b]  Area under the graph of t on [a, b]

  

5



0

f 1t2 dt 

5

 t1t2 dt 0

5

3 f 1t2  t1t2 4 dt

By Property 4, Section 11.5

0

This example shows that some practical problems can be solved by finding the area of a region between two curves, which in turn can be found by evaluating an appropriate definite integral.

y y = f (x)

y = g(x)

R

x a

b

FIGURE 30 Area of R   b[ f(x)  g(x)] dx a

Finding the Area between Two Curves We now turn our attention to the general problem of finding the area of a plane region bounded both above and below by the graphs of functions. First, consider the situation in which the graph of one function lies above that of another. More specifically, let R be the region in the xy-plane (Figure 30) that is bounded above by the graph of a continuous function f, below by a continuous function t where

798

11 INTEGRATION

f(x)  t(x) on [a, b], and to the left and right by the vertical lines x  a and x  b, respectively. From the figure, we see that Area of R  Area under f 1x2  Area under t1x2 



b



b

f 1x2 dx 

a



b

 t1x2 dx a

3 f 1x2  t1x2 4 dx

a

upon using Property 4 of the definite integral.

The Area between Two Curves

Let f and t be continuous functions such that f (x)  t(x) on the interval [a, b]. Then, the area of the region bounded above by y  f (x) and below by y  t(x) on [a, b] is given by



b

3 f 1x2  t1x2 4 dx

(13)

a

Even though we assumed that both f and t were nonnegative in the derivation of (13), it may be shown that this equation is valid if f and t are not nonnegative (see Exercise 57). Also, observe that if t(x) is 0 for all x—that is, when the lower boundary of the region R is the x-axis—Equation (13) gives the area of the region under the curve y  f(x) from x  a to x  b, as we would expect. EXAMPLE 1 Find the area of the region bounded by the x-axis, the graph of y  x 2  4x  8, and the lines x  1 and x  4. y x –2

2 R –4

x=4

x = –1

Solution The region R under consideration is shown in Figure 31. We can view R as the region bounded above by the graph of f(x)  0 (the x-axis) and below by the graph of t(x)  x 2  4x  8 on [1, 4]. Therefore, the area of R is given by



b

3 f 1x2  t1x2 4 dx 



4

1 4

a



30  1x 2  4x  82 4 dx 1x 2  4x  82 dx

–8



–12

4 1  x 3  2x 2  8x ` 3 1 1 1  c 164 2  21162  8142 d  c 112  2112  811 2 d 3 3

1

y = – x 2 + 4x – 8 FIGURE 31 Area of R    4 g(x) dx 1

 3123

or 3123 square units. EXAMPLE 2 Find the area of the region R bounded by the graphs of f(x)  2x  1 and

and the vertical lines x  1 and x  2.

t(x)  x 2  4

11.6 AREA BETWEEN TWO CURVES

We first sketch the graphs of the functions f(x)  2x  1 and t(x)  x  4 and the vertical lines x  1 and x  2, and then we identify the region R whose area is to be calculated (Figure 32). Since the graph of f always lies above that of t for x in the interval [1, 2], we see by Equation (13) that the required area is given by

y

Solution

x=2

x=1

2

4 y = x2 – 4 2 R –4

x

–2

799

4



2

  

3 f 1x2  t 1x2 4 dx 

1

2

3 12x  12  1x 2  4 2 4 dx

2

1x 2  2x  3 2 dx

1

y = 2x – 1 –4

1

2 1   x 3  x 2  3x ` 3 1 8 1 11  a  4  6 b  a  1  3 b  3 3 3

FIGURE 32 Area of R  12 [ f(x)  g(x)] dx

or 113 square units. EXAMPLE 3 Find the area of the region R that is completely enclosed by the graphs of the functions f(x)  2x  1 and

t(x)  x 2  4

Solution The region R is shown in Figure 33. First, we find the points of intersection of the two curves. To do this, we solve the system that consists of the two equations y  2x  1 and y  x 2  4. Equating the two values of y gives

y (3, 5) 4

x 2  4  2x  1 x  2x  3  0 1x  12 1x  32  0

y = x2 – 4

2

R

–4

x 4

(–1, –3) y = 2x – 1

–4

FIGURE 33 3 Area of R  1 [ f(x)  g(x)] dx

so x  1 or x  3. That is, the two curves intersect when x  1 and x  3. Observe that we could also view the region R as the region bounded above by the graph of the function f (x)  2x  1, below by the graph of the function t(x)  x 2  4, and to the left and right by the vertical lines x  1 and x  3, respectively. Next, since the graph of the function f always lies above that of the function t on [1, 3], we can use (13) to compute the desired area:



b

3 f 1x2  t1x2 4 dx 



3

1 3

a





3 12x  12  1x 2  42 4 dx 1x 2  2x  32 dx

1

3 1   x 3  x 2  3x ` 3 1 1 32  19  9  92  a  1  3 b  3 3 2  10 3

or 10 23 square units. EXAMPLE 4 Find the area of the region R bounded by the graphs of the functions f(x)  x 2  2x  1 and

and the vertical lines x  1 and x  1.

t(x)  e x  1

800

11 INTEGRATION y

y = x2 – 2x – 1

Solution The region R is shown in Figure 34. Since the graph of the function f always lies above that of the function t, the area of the region R is given by



b



x 3

R



3 1x 2  2x  12  1e x  1 2 4 dx 1x 2  2x  e x 2 dx

1

1 1  x3  x2  ex ` 3 1 1 1  a  1  e b  a  1  e 1 b 3 3 2 1   e  , or approximately 3.02 square units e 3

y = – e x –1 x=1

–3

1

1 1

a

x = –1 –3



3 f 1x2  t1x2 4 dx 

FIGURE 34 1 Area of R  1 [ f (x)  g(x)] dx

Equation (13), which gives the area of the region between the curves y  f(x) and y  t(x) for a x b, is valid when the graph of the function f lies above that of the function t over the interval [a, b]. Example 5 shows how to use (13) to find the area of a region when the latter condition does not hold. EXAMPLE 5 Find the area of the region bounded by the graph of the function f(x)  x 3, the x-axis, and the lines x  1 and x  1. y

Solution The region R under consideration can be thought of as composed of the two subregions R1 and R2, as shown in Figure 35. Recall that the x-axis is represented by the function t(x)  0. Since t(x)  f(x) on [1, 0], we see that the area of R1 is given by

y = x3 1 x=1 R2 x = –1

R1



x

b

3t1x2  f 1x2 4 dx 



0

10  x3 2 dx  

1

a



0

x3 dx

1

0 1 1 1   x 4 `  0  a b  4 4 4 1

–1

To find the area of R2, we observe that f(x)  t(x) on [0, 1], so it is given by



FIGURE 35

Area of R1  Area of R2

b

3 f 1x2  t1x2 4 dx 

a



1

1x 3  0 2 dx 

0

1

 x dx 3

0

1 1 1 1  x4 `  a b  0  4 4 4 0

Therefore, the area of R is 14  14, or 12, square units. By making use of symmetry, we could have obtained the same result by computing 2



0

x 3 dx or

1

2



1

x 3 dx

0

as you may verify.

Explore & Discuss A function is even if it satisfies the condition f(x)  f(x), and it is odd if it satisfies the condition f(x)  f(x). Show that the graph of an even function is symmetric with respect to the y-axis while the graph of an odd function is symmetric with respect to the origin. Explain why a a a f 1x2 dx  2 0 f 1x2 dx if f is even

and

a a f 1x2 dx  0

if f is odd

11.6 AREA BETWEEN TWO CURVES y

y=x+3

y = x 3 – 3x + 3 5

f(x)  x 3  3x  3 and

R2 1 x –3

t(x)  x  3

First, sketch the graphs of y  x 3  3x  3 and y  x  3 and then identify the required region R. We can view the region R as being composed of the two subregions R1 and R2, as shown in Figure 36. By solving the equations y  x  3 and y  x 3 3x  3 simultaneously, we find the points of intersection of the two curves. Equating the two values of y, we have Solution

3 (– 2, 1)

EXAMPLE 6 Find the area of the region completely enclosed by the graphs of the functions

(2, 5)

R1

801

–1

1

3

x 3  3x  3  x  3 x 3  4x  0 x1x 2  42  0 x1x  22 1x  22  0 x  0, 2, 2

FIGURE 36

Area of R1  Area of R2 0  2 [ f (x)  g(x)] dx   02 [ g(x)  f(x)] dx

Hence, the points of intersection of the two curves are (2, 1), (0, 3), and (2, 5). For 2 x 0, we see that the graph of the function f lies above that of the function t, so the area of the region R1 is, by virtue of (13),



0

3 1x 3  3x  32  1x  3 2 4 dx 

2



0

1x 3  4x2 dx

2

0 1  x 4  2x 2 ` 4 2  14  82 4

or 4 square units. For 0 x 2, the graph of the function t lies above that of the function f, and the area of R2 is given by



2

3 1x  32  1x 3  3x  32 4 dx 

0



2

1x 3  4x2 dx

0

2 1   x 4  2x 2 ` 4 0  4  8 4

or 4 square units. Therefore, the required area is the sum of the area of the two regions R1  R2—that is, 4  4, or 8 square units. APPLIED EXAMPLE 7 Conservation of Oil In a 2002 study for a developing country’s Economic Development Board, government economists and energy experts concluded that if the Energy Conservation Bill were implemented in 2003, the country’s oil consumption for the next 5 years would be expected to grow in accordance with the model R(t)  20e0.05t

where t is measured in years (t  0 corresponding to the year 2003) and R(t) in millions of barrels per year. Without the government-imposed conservation measures, however, the expected rate of growth of oil consumption would be given by R1(t)  20e0.08t

millions of barrels per year. Using these models, determine how much oil would have been saved from 2003 through 2008 if the bill had been implemented.

802

11 INTEGRATION

Solution Under the Energy Conservation Bill, the total amount of oil that would have been consumed between 2003 and 2008 is given by



5

R 1t2 dt 

0

y = R1(t) = 20e0.08t 30



S

y = R(t) = 20e0.05t t 2

3

4

0.05t

dt

(14)

0

5

R1 1t2 dt 

0

25

1

 20e

Without the bill, the total amount of oil that would have been consumed between 2003 and 2008 is given by

y

20

5

5

FIGURE 37 Area of S  05 [R1(t)  R(t)] dt

5

 20e

0.08t

dt

(15)

0

Equation (14) may be interpreted as the area of the region under the curve y  R(t) from t  0 to t  5. Similarly, we interpret (15) as the area of the region under the curve y  R1(t) from t  0 to t  5. Furthermore, note that the graph of y  R1(t)  20e0.08t always lies on or above the graph of y  R(t)  20e0.05t (t  0). Thus, the area of the shaded region S in Figure 37 shows the amount of oil that would have been saved from 2003 to 2008 if the Energy Conservation Bill had been implemented. But the area of the region S is given by



5

3R1 1t2  R 1t2 4 dt 

0



5

320e 0.08t  20e 0.05t 4 dt

0 5

 20

 1e

0.08t

 e 0.05t 2 dt

0

 20 a

e 0.08t e 0.05t 5  b ` 0.08 0.05 0 e 0.4 e 0.25 1 1  20 c a  b  a  bd 0.08 0.05 0.08 0.05  9.3

or approximately 9.3 square units. Thus, the amount of oil that would have been saved is 9.3 million barrels.

Exploring with

TECHNOLOGY Refer to Example 7. Suppose we want to construct a mathematical model giving the amount of oil saved from 2003 through the year (2003  x) where x  0. In Example 7, for instance, we take x  5. 1. Show that this model is given by F 1x2 



x

3R1 1t2  R 1t2 4 dt

0

 250e0.08x  400e0.05x  150 Hint: You may find it helpful to use some of the results of Example 7.

2. Use a graphing utility to plot the graph of F, using the viewing window [0, 10]  [0, 50]. 3. Find F(5) and thus confirm the result of Example 7. 4. What is the main advantage of this model?

11.6 AREA BETWEEN TWO CURVES

803

11.6 Self-Check Exercises 1. Find the area of the region bounded by the graphs of f(x)  x 2  2 and t(x)  1  x and the vertical lines x  0 and x  1.

renovations and improvements of existing hotels and proposed acquisitions of new hotels, Kane’s profits are expected to grow at the rate of t  2 1t  4 million dollars/year in the next decade. What additional profits are expected over the next 10 yr if the group implements the proposed plans?

2. Find the area of the region completely enclosed by the graphs of f(x)  x 2  6x  5 and t(x)  x 2  5. 3. The management of Kane Corporation, which operates a chain of hotels, expects its profits to grow at the rate of 1  t 2/3 million dollars/year t yr from now. However, with

Solutions to Self-Check Exercises 11.6 can be found on page 807.

11.6 Concept Questions 1. Suppose f and t are continuous functions such that f (x)  t(x) on the interval [a, b]. Write an integral giving the area of the region bounded above by the graph of f, below by the graph of t, and on the left and right by the lines x  a and x  b.

y y  f (x) y  g(x)

a

2. Write an expression in terms of definite integrals giving the area of the shaded region in the following figure:

b

c

x

d

11.6 Exercises In Exercises 1–8, find the area of the shaded region.

1.

3.

y

y

y=

x3

–

y = x œ1 – x2

1 2

6x 2

y=0

y=0

x –1

1

x

y=0

6

1 2

4. 2.

y

y 2 1

y=

1 2

y = x 4 – 2x 3 y=0

x 1 x

–1

1 2

2 –1

2x x2+ 4

x = –2

x=2

804

11 INTEGRATION

5.

14. f 1x2 

y

1 x  1x; a  0, b  4 2

15. f(x)  e(1/2)x; a  2, b  4 y = x – 2œx

16. f(x)  xex ; a  0, b  1 2

x

In Exercises 17–26, sketch the graphs of the functions f and g and find the area of the region enclosed by these graphs and the vertical lines x  a and x  b.

4

–1

17. f(x)  x 2  3, t(x)  1; a  1, b  3 6.

y

18. f(x)  x  2, t(x)  x 2  4; a  1, b  2

y=x–2

19. f(x)  x 2  2x  3, t(x)  x  3; a  0, b  2

2

y = œx

20. f(x)  9  x 2, t(x)  2x  3; a  1, b  1

1 x 2

3

21. f 1x2  x 2  1, t 1x2 

4

–1 –2

1 3 x ; a  1, b  2 3

1 22. f 1x2  1x, t 1x2   x  1; a  1, b  4 2

7.

y

1 23. f 1x2  , t 1x2  2x  1; a  1, b  4 x

y = x2

24. f 1x2  x 2, t 1x2 

y = x 1/3

1

x

1 25. f 1x2  e x, t 1x2  ; a  1, b  2 x

–1 x = –1

26. f(x)  x, t(x)  e 2x; a  1, b  3

x =1

8.

y

y = x3

1 ; a  1, b  3 x2

In Exercises 27–34, sketch the graph and find the area of the region bounded by the graph of the function f and the lines y  0, x  a, and x  b.

y=x+6

8

27. f(x)  x; a  1, b  2 28. f(x)  x 2  2x; a  1, b  1 29. f(x)  x 2  4x  3; a  1, b  2 x

–6 –5 –4 –3 –2

1

4 1 2

y =– x

30. f(x)  x 3  x 2; a  1, b  1 31. f(x)  x 3  4x 2  3x; a  0, b  2 32. f(x)  4x 1/3  x 4/3; a  1, b  8

In Exercises 9–16, sketch the graph and find the area of the region bounded below by the graph of each function and above by the x-axis from x  a to x  b.

9. f(x)  x 2; a  1, b  2

33. f(x)  e x  1; a  1, b  3 34. f(x)  xe x ; a  0, b  2 2

11. f(x)  x 2  5x  4; a  1, b  3

In Exercises 35–42, sketch the graph and find the area of the region completely enclosed by the graphs of the given functions f and g.

12. f(x)  x 3; a  1, b  0

35. f(x)  x  2 and t(x)  x 2  4

13. f 1x2  1  1x; a  0, b  9

36. f(x)  x 2  4x and t(x)  2x  3

10. f(x)  x 2  4; a  2, b  2

11.6 AREA BETWEEN TWO CURVES

37. f(x)  x 2 and t(x)  x 3

y (billions of barrels)

38. f(x)  x 3  2x 2  3x and t(x)  0

60

39. f(x)  x 3  6x 2  9x and t(x)  x 2  3x 40. f 1x 2  1x and t 1x2  x2

50 y = f(t)

41. f 1x2  x29  x and t 1x2  0

y = f(t)

40

2

42. f 1x2  2x and t 1x2  x1x  1

30

43. EFFECT OF ADVERTISING ON REVENUE In the accompanying figure, the function f gives the rate of change of Odyssey Travel’s revenue with respect to the amount x it spends on advertising with their current advertising agency. By engaging the services of a different advertising agency, it is expected that Odyssey’s revenue will grow at the rate given by the function t. Give an interpretation of the area A of the region S and find an expression for A in terms of a definite integral involving f and t. R

R = g(x)

Dollars/dollar

805

S R = f(x)

20

y = g(t)

10 t (year) 1990 2000 2010 2020 2030 2040 2050

46. AIR PURIFICATION To study the effectiveness of air purifiers in removing smoke, engineers ran each purifier in a smokefilled 10-ft  20-ft room. In the accompanying figure, the function f gives the rate of change of the smoke level/ minute, t min after the start of the test, when a brand A purifier is used. The function t gives the rate of change of the smoke level/minute when a brand B purifier is used. a. Give an interpretation of the area of the region S. b. Find an expression for the area of S in terms of a definite integral involving f and t.

x 0

b

Dollars

y (%/min)

44. PULSE RATE DURING EXERCISE In the accompanying figure, the function f gives the rate of increase of an individual’s pulse rate when he walked a prescribed course on a treadmill 6 mo ago. The function t gives the rate of increase of his pulse rate when he recently walked the same prescribed course. Give an interpretation of the area A of the region S and find an expression for A in terms of a definite integral involving f and t. y Beats per second

y = f(t)

y = g(t)

S

Seconds

y = f (t) y = g(t)

S

t (min)

47. Two cars start out side by side and travel along a straight road. The velocity of car 1 is f(t) ft/sec, the velocity of car 2 is t(t) ft/sec over the interval [0, T], and 0 T1 T. Furthermore, suppose the graphs of f and t are as depicted in the accompanying figure. Let A1 and A2 denote the areas of the regions (shown shaded). y (ft/sec)

t 0

b

a

b

45. OIL PRODUCTION SHORTFALL Energy experts disagree about when global oil production will begin to decline. In the following figure, the function f gives the annual world oil production in billions of barrels from 1980 to 2050, according to the Department of Energy projection. The function t gives the world oil production in billions of barrels per year over the same period, according to longtime petroleum geologist Colin Campbell. Find an expression in terms of the definite integrals involving f and t, giving the shortfall in the total oil production over the period in question heeding Campbell’s dire warnings. Source: U.S. Department of Energy; Colin Campbell

y = g(t)

y = f (t) A2 A1 T1

T

t (sec)

a. Write the number



T

T1

3t 1t2  f 1t2 4 dt 



T1

3 f 1t2  t 1t2 4 dt

0

in terms of A1 and A2. b. What does the number obtained in part (a) represent?

806

11 INTEGRATION

48. The rate of change of the revenue of company A over the (time) interval [0, T ] is f(t) dollars/week, whereas the rate of change of the revenue of company B over the same period is t(t) dollars/week. The graphs of f and t are depicted in the accompanying figure. Find an expression in terms of definite integrals involving f and t giving the additional revenue that company B will have over company A in the period [0, T].

52. POPULATION GROWTH In an endeavor to curb population growth in a Southeast Asian island state, the government has decided to launch an extensive propaganda campaign. Without curbs, the government expects the rate of population growth to have been 60e0.02t

thousand people/year, t yr from now, over the next 5 yr. However, successful implementation of the proposed campaign is expected to result in a population growth rate of

y ($/wk) y = g(t )

t 2  60

y = f (t )

T

T1

t (wk)

49. TURBO-CHARGED ENGINE VS. STANDARD ENGINE In tests conducted by Auto Test Magazine on two identical models of the Phoenix Elite—one equipped with a standard engine and the other with a turbo-charger—it was found that the acceleration of the former is given by a  f(t)  4  0.8t

(0 t 12)

ft/sec/sec, t sec after starting from rest at full throttle, whereas the acceleration of the latter is given by a  t(t)  4  1.2t  0.03t 2

(0 t 12)

ft/sec/sec. How much faster is the turbo-charged model moving than the model with the standard engine at the end of a 10-sec test run at full throttle?

thousand people/year, t yr from now, over the next 5 yr. Assuming that the campaign is mounted, how many fewer people will there be in that country 5 yr from now than there would have been if no curbs had been imposed? In Exercises 53–56, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

53. If f and t are continuous on [a, b] and either f(x)  t(x) for all x in [a, b] or f(x) t(x) for all x in [a, b], then the area of the region bounded by the graphs of f and t and the vertical lines x  a and x  b is given by ab | f 1x2  t 1x2| dx. 54. The area of the region bounded by the graphs of f(x)  2  x and t(x)  4  x 2 and the vertical lines x  0 and x  2 is given by 02 3 f 1x2  t 1x2 4 dx. 55. If A denotes the area bounded by the graphs of f and t on [a, b], then



A2 

b

3 f 1x2  t 1x2 4 2 dx.

a

50. ALTERNATIVE ENERGY SOURCES Because of the increasingly important role played by coal as a viable alternative energy source, the production of coal has been growing at the rate of 3.5e0.05t

billion metric tons/year, t yr from 1980 (which corresponds to t  0). Had it not been for the energy crisis, the rate of production of coal since 1980 might have been only

56. If f and t are continuous on [a, b] and ab [ f(t)  t(t)] dt  0, then f(t)  t(t) for all t in [a, b]. 57. Show that the area of a region R bounded above by the graph of a function f and below by the graph of a function t from x  a to x  b is given by



b

3 f 1x2  t 1x2 4 dx

a

3.5e0.01t

billion metric tons/year, t yr from 1980. Determine how much additional coal was produced between 1980 and the end of the century as an alternate energy source. 51. EFFECT OF TV ADVERTISING ON CAR SALES Carl Williams, the proprietor of Carl Williams Auto Sales, estimates that with extensive television advertising, car sales over the next several years could be increasing at the rate of 5e0.3t

Hint: The validity of the formula was verified earlier for the case when both f and t were nonnegative. Now, let f and t be two functions such that f(x)  t(x) for a x b. Then, there exists some nonnegative constant c such that the curves y  f(x)  c and y  t(x)  c are translated in the y-direction in such a way that the region R has the same area as the region R (see the accompanying figures). Show that the area of R is given by



b

5 3 f 1x 2  c4  3 t 1x2  c4 6 dx 

a



b

3 f 1x2  t 1x2 4 dx

a

y

y

thousand cars/year, t yr from now, instead of at the current rate of

y = f (x) + c

(5  0.5t 3/2)

thousand cars/year, t yr from now. Find how many more cars Carl expects to sell over the next 5 yr by implementing his advertising plans.

R'

y = f (x) a

R

b y = g(x)

x

a

b y = g(x) + c

x

11.6 AREA BETWEEN TWO CURVES

807

11.6 Solutions to Self-Check Exercises y

1. The region in question is shown in the accompanying figure. Since the graph of the function f lies above that of the function t for 0 x 1, we see that the required area is given by



1

3 1x 2  22  11  x2 4 dx 

0



1

14

y = –x2 + 6x + 5

10

1x 2  x  1 2 dx

y = x2 + 5

0

1 1 1  x3  x2  x ` 3 2 0



1 1  1 3 2



11 6

x –1 –2

1

5

Since the graph of f always lies above that of t for 0 x 3, we see that the required area is given by

or 116 square units.



3

3 1x 2  6x  52  1x 2  52 4 dx 

0

y



3

12x 2  6x2 dx

0

3 2   x 3  3x 2 ` 3 0

y = x2 + 2

 18  27 9

or 9 square units. y=1–x

3. The additional profits realizable over the next 10 yr are given by

x – 2 –1

1

2



10

3 1t  21t  42  11  t 2/3 2 4 dt

0

2. The region in question is shown in the accompanying figure. To find the points of intersection of the two curves, we solve the equations x  6x  5  x  5 2

2

2x 2  6x  0 2x1x  32  0

giving x  0 or x  3. Therefore, the points of intersection are (0, 5) and (3, 14).

USING

TECHNOLOGY





10

1t  2t 1/2  3  t 2/3 2 dt

0



10 1 2 4 3/2 3 t  t  3t  t 5/3 ` 2 3 5 0



1 4 3 1102 2  1102 3/2  3110 2  1102 5/3 2 3 5

 9.99

or approximately $10 million.

Finding the Area between Two Curves The numerical integral operation can also be used to find the area between two curves. We do this by using the numerical integral operation to evaluate an appropriate definite integral or the sum (difference) of appropriate definite integrals. In the following example, the intersection operation is also used to advantage to help us find the limits of integration. EXAMPLE 1 Use a graphing utility to find the area of the smaller region R that is completely enclosed by the graphs of the functions f(x)  2x 3  8x2  4x  3 and

t(x)  3x 2  10x  11 (continued)

808

11 INTEGRATION

The graphs of f and t in the viewing window [3, 4]  [20, 5] are shown in Figure T1. Using the intersection operation of a graphing utility, we find the x-coordinates of the points of intersection of the two graphs to be approximately 1.04 and 0.65, respectively. Since the graph of f lies above that of t on the interval [1.04, 0.65], we see that the area of R is given by

Solution

A

FIGURE T1



0.65

1.04 0.65

The region R is completely enclosed by the graphs of f and g.





3 12x 3  8x 2  4x  32  13x 2  10x  112 4 dx 12x 3  11x 2  6x  82 dx

1.04

Using the numerical integral function of a graphing utility, we find A  9.87, and so the area of R is approximately 9.87 square units.

TECHNOLOGY EXERCISES In Exercises 1–6, (a) plot the graphs of the functions f and g and (b) find the area of the region enclosed by these graphs and the vertical lines x  a and x  b. Express your answers accurate to four decimal places.

1. f(x)  x (x  5) , t(x)  0; a  1, b  3 3

7. f (x)  2x 3  8x 2  4x  3 and t(x)  3x 2  10x  10

4

1 1 2. f 1x2  x  21  x 2, t 1x2  0; a   , b  2 2 3. f(x)  x1/3(x  1)1/2, t(x)  x1; a  1.2, b  2 4. f(x)  2, t(x)  ln(1  x 2); a  1, b  1 x2  3 5. f 1x2  1x, t 1x2  2 ; a  0, b  3 x 1 6. f 1x2 

In Exercises 7–12, (a) plot the graphs of the functions f and g and (b) find the area of the region totally enclosed by the graphs of these functions.

4 , t 1x2  x 4; a  1, b  1 x2  1

8. f(x)  x 4  2x 2  2 and t(x)  4  2x 2 9. f(x)  2x 3  3x 2  x  5 and t(x)  e 2x  3 10. f 1x2 

1 2 x  3 and t 1x2  ln x 2

11. f 1x2  xex and t 1x2  x  21x 12. f(x)  ex and t(x)  x 4 2

13. Refer to Example 1. Find the area of the larger region that is completely enclosed by the graphs of the functions f and t.

11.7 Applications of the Definite Integral to Business and Economics In this section, we consider several applications of the definite integral in the fields of business and economics.

Consumers’ and Producers’ Surplus p

p = D(x) p x x FIGURE 38 D(x) is a demand function.

We begin by deriving a formula for computing the consumers’ surplus. Suppose p  D(x) is the demand function that relates the unit price p of a commodity to the quantity x demanded of it. Furthermore, suppose a fixed unit market price p has been established for the commodity and corresponding to this unit price the quantity demanded is x units (Figure 38). Then, those consumers who would be willing to pay a unit price higher than p for the commodity would in effect experience a savings. This difference between what the consumers would be willing to pay for x units of the commodity and what they actually pay for them is called the consumers’ surplus.

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS

809

To derive a formula for computing the consumers’ surplus, divide the interval [0, x] into n subintervals, each of length x  x/n, and denote the right endpoints of these subintervals by x1, x2, . . . , xn  x (Figure 39). We observe in Figure 39 that there are consumers who would pay a unit price of at least D(x1) dollars for the first  x units of the commodity instead of the market price of p dollars per unit. The savings to these consumers is approximated by D(x1)x  px  [D(x 1)  p]x p

D(x1) D(x 2 ) r1 r2

rn

p

FIGURE 39 Approximating consumers’ surplus by the sum of the areas of the rectangles r1, r2, . . . , rn

x1 x 2

...

p=p

x xn = x xn – 1

which is the area of the rectangle r1. Pursuing the same line of reasoning, we find that the savings to the consumers who would be willing to pay a unit price of at least D(x 2) dollars for the next  x units (from x1 through x 2) of the commodity, instead of the market price of p dollars per unit, is approximated by D(x 2)x  px  [D(x 2)  p]x

Continuing, we approximate the total savings to the consumers in purchasing x units of the commodity by the sum 3D1x1 2  p4 ¢x  3D1x2 2  p4 ¢x  p  3D1xn 2  p4 ¢x  3D1x1 2  D1x2 2  p  D1xn 2 4 ¢x  3p¢x  p¢x  p  p¢x4  n terms

 3D1x1 2  D1x2 2  p  D1xn 2 4 ¢x  np¢x  3D1x1 2  D1x2 2  p  D1xn 2 4 ¢x  p x

Now, the first term in the last expression is the Riemann sum of the demand function p  D(x) over the interval [0, x] with representative points x1, x2, . . . , xn. Letting n approach infinity, we obtain the following formula for the consumers’ surplus CS.

Consumers’ Surplus

The consumers’ surplus is given by x

CS 

 D1x2 dx  p x

(16)

0

where D is the demand function, p is the unit market price, and x is the quantity sold.

810

11 INTEGRATION p

The consumer’s surplus is given by the area of the region bounded above by the demand curve p  D(x) and below by the straight line p  p from x  0 to x  x (Figure 40). We can also see this if we rewrite Equation (16) in the form p = D(x)



p x Consumers’ surplus

p p = S(x ) p

x x

3D1x2  p4 dx

0

x FIGURE 40

x

and interpret the result geometrically. Analogously, we can derive a formula for computing the producers’ surplus. Suppose p  S(x) is the supply equation that relates the unit price p of a certain commodity to the quantity x that the supplier will make available in the market at that price. Again, suppose a fixed market price p has been established for the commodity and, corresponding to this unit price, a quantity of x units will be made available in the market by the supplier (Figure 41). Then, the suppliers who would be willing to make the commodity available at a lower price stand to gain from the fact that the market price is set as such. The difference between what the suppliers actually receive and what they would be willing to receive is called the producers’ surplus. Proceeding in a manner similar to the derivation of the equation for computing the consumers’ surplus, we find that the producers’ surplus PS is defined as follows:

FIGURE 41 S(x) is a supply function.

Producers’ Surplus

The producers’ surplus is given by

 S 1x2 dx x

PS  p x 

(17)

0

where S(x) is the supply function, p is the unit market price, and x is the quantity supplied.

Geometrically, the producers’ surplus is given by the area of the region bounded above by the straight line p  p and below by the supply curve p  S(x) from x  0 to x  x (Figure 42). We can also show that the last statement is true by converting Equation (17) to the form



x

3 p  S 1x2 4 dx

0

and interpreting the definite integral geometrically. EXAMPLE 1 The demand function for a certain make of 10-speed bicycle is given by p

p  D(x)  0.001x 2  250 p = S(x )

where p is the unit price in dollars and x is the quantity demanded in units of a thousand. The supply function for these bicycles is given by

p

p  S(x)  0.0006x 2  0.02x  100 x x FIGURE 42 Producers’ surplus

where p stands for the unit price in dollars and x stands for the number of bicycles that the supplier will put on the market, in units of a thousand. Determine the consumers’ surplus and the producers’ surplus if the market price of a bicycle is set at the equilibrium price.

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS p 250 200 150

CS p = p = 160

811

Solution Recall that the equilibrium price is the unit price of the commodity when market equilibrium occurs. We determine the equilibrium price by solving for the point of intersection of the demand curve and the supply curve (Figure 43). To solve the system of equations

PS

p  0.001x 2  250 p  0.0006x 2  0.02x  100

100 50 x 100 200 300 400 500

we simply substitute the first equation into the second, obtaining 0.0006x 2  0.02x  100  0.001x 2  250 0.0016x 2  0.02x  150  0 16x 2  200x  1,500,000  0 2x 2  25x  187,500  0

FIGURE 43 Consumers’ surplus and producers’ surplus when market price  equilibrium price

Factoring this last equation, we obtain (2x  625)(x  300)  0

Thus, x  625/2 or x  300. The first number lies outside the interval of interest, so we are left with the solution x  300, with a corresponding value of p  0.001(300)2  250  160

Thus, the equilibrium point is (300, 160); that is, the equilibrium quantity is 300,000, and the equilibrium price is $160. Setting the market price at $160 per unit and using Formula (16) with p  160 and x  300, we find that the consumers’ surplus is given by CS 



300

10.001x 2  2502 dx  11602 1300 2

0

 a

300 1 x 3  250x b `  48,000 3000 0 3003   12502 13002  48,000 3000  18,000

or $18,000,000. (Recall that x is measured in units of a thousand.) Next, using (17), we find that the producers’ surplus is given by PS  11602 13002 



300

10.0006x 2  0.02x  1002 dx

0

 48,000  10.0002x 3  0.01x 2  100x2 `

300 0

 48,000  3 10.00022 13002 3  10.012 13002 2  10013002 4  11,700

or $11,700,000.

The Future and Present Value of an Income Stream Suppose a firm generates a stream of income over a period of time—for example, the revenue generated by a large chain of retail stores over a 5-year period. As the income is realized, it is reinvested and earns interest at a fixed rate. The accumulated future income stream over the 5-year period is the amount of money the firm ends up with at the end of that period.

812

11 INTEGRATION

The definite integral can be used to determine this accumulated, or total, future income stream over a period of time. The total future value of an income stream gives us a way to measure the value of such a stream. To find the total future value of an income stream, suppose R(t)  Rate of income generation at any time t r  Interest rate compounded continuously T  Term 0

t1

t2

t 3 . . . tn – 1

tn = T

FIGURE 44 The time interval [0, T ] is partitioned into n subintervals.

Dollars per year

In years

Let’s divide the time interval [0, T] into n subintervals of equal length t  T/n and denote the right endpoints of these intervals by t1, t2, . . . , tn  T, as shown in Figure 44. If R is a continuous function on [0, T ], then R(t) will not differ by much from R(t1) in the subinterval [0, t1] provided that the subinterval is small (which is true if n is large). Therefore, the income generated over the time interval [0, t1] is approximately R(t1)t

Constant rate of income  Length of time

dollars. The future value of this amount, T years from now, calculated as if it were earned at time t1, is [R(t1)t]er (Tt1)

Equation (5), Section 4.1

dollars. Similarly, the income generated over the time interval [t1, t2] is approximately R(t2)t dollars and has a future value, T years from now, of approximately [R(t2)t]er (Tt2)

dollars. Therefore, the sum of the future values of the income stream generated over the time interval [0, T ] is approximately R(t1)er(Tt1)t  R(t2)er(Tt2)t  p  R(tn)er(Ttn)t  erT[R(t1)er t1t  R(t2)ert2t  p  R(tn)er tnt] dollars. But this sum is just the Riemann sum of the function erTR(t)ert over the interval [0, T ] with representative points t1, t2, . . . , tn. Letting n approach infinity, we obtain the following result.

Accumulated or Total Future Value of an Income Stream

The accumulated, or total, future value after T years of an income stream of R(t) dollars per year, earning interest at the rate of r per year compounded continuously, is given by A  e rT



T

R 1t2ert dt

(18)

0

APPLIED EXAMPLE 2 Income Stream Crystal Car Wash recently bought an automatic car-washing machine that is expected to generate $40,000 in revenue per year, t years from now, for the next 5 years. If the income is reinvested in a business earning interest at the rate of 12% per year compounded continuously, find the total accumulated value of this income stream at the end of 5 years. Solution We are required to find the total future value of the given income stream after 5 years. Using Equation (18) with R(t)  40,000, r  0.12, and T  5, we see that the required value is given by

813

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS 5

e 0.12152

 40,000e

0.12t

dt

0

 e 0.6 c

40,000 0.12t 5 Integrate using the e d ` substitution u  0.12t. 0.12 0 40,000e 0.6 0.6  1e  12  274,039.60 0.12

or approximately $274,040. Another way of measuring the value of an income stream is by considering its present value. The present value of an income stream of R(t) dollars per year over a term of T years, earning interest at the rate of r per year compounded continuously, is the principal P that will yield the same accumulated value as the income stream itself when P is invested today for a period of T years at the same rate of interest. In other words, Pe rT  e rT



T

R 1t2e rt dt

0

Dividing both sides of the equation by erT gives the following result. Present Value of an Income Stream

The present value of an income stream of R(t) dollars per year, earning interest at the rate of r per year compounded continuously, is given by PV 



T

R 1t 2e rt dt

(19)

0

APPLIED EXAMPLE 3 Investment Analysis The owner of a local cinema is considering two alternative plans for renovating and improving the theater. Plan A calls for an immediate cash outlay of $250,000, whereas plan B requires an immediate cash outlay of $180,000. It has been estimated that adopting plan A would result in a net income stream generated at the rate of f(t)  630,000

dollars per year, whereas adopting plan B would result in a net income stream generated at the rate of t(t)  580,000

dollars per year for the next 3 years. If the prevailing interest rate for the next 5 years is 10% per year, which plan will generate a higher net income by the end of 3 years? Solution Since the initial outlay is $250,000, we find—using Equation (19) with R(t)  630,000, r  0.1, and T  3—that the present value of the net income under plan A is given by 3

 630,000e

0.1t

dt  250,000

0

630,000 0.1t 3 Integrate using the e `  250,000 substitution u  0.1t. 0.1 0  6,300,000e 0.3  6,300,000  250,000  1,382,845 

or approximately $1,382,845.

814

11 INTEGRATION

To find the present value of the net income under plan B, we use (19) with R(t)  580,000, r  0.1, and T  3, obtaining 3

 580,000e

0.1t

dt  180,000

0

dollars. Proceeding as in the previous computation, we see that the required value is $1,323,254 (see Exercise 8, page 818). Comparing the present value of each plan, we conclude that plan A would generate a higher net income by the end of 3 years. The function R in Example 3 is a constant function. If R is not a constant function, then we may need more sophisticated techniques of integration to evaluate the integral in (19).

Note

The Amount and Present Value of an Annuity An annuity is a sequence of payments made at regular time intervals. The time period in which these payments are made is called the term of the annuity. Although the payments need not be equal in size, they are equal in many important applications, and we will assume that they are equal in our discussion. Examples of annuities are regular deposits to a savings account, monthly home mortgage payments, and monthly insurance payments. The amount of an annuity is the sum of the payments plus the interest earned. A formula for computing the amount of an annuity A can be derived with the help of (18). Let P  Size of each payment in the annuity r  Interest rate compounded continuously T  Term of the annuity (in years) m  Number of payments per year

The payments into the annuity constitute a constant income stream of R(t)  mP dollars per year. With this value of R(t), (18) yields A  erT



T

R 1t 2ert dt  erT

0



T

mPert dt

0

e rt T e rT 1  mPe rT c d `  mPe rT c  d r r r 0 

mP rT 1e  12 r

Since e rT  erT  1

This leads us to the following formula. Amount of an Annuity

The amount of an annuity is A

mP rT 1e  12 r

(20)

where P, r, T, and m are as defined earlier. APPLIED EXAMPLE 4 IRAs On January 1, 1992, Marcus Chapman deposited $2000 into an Individual Retirement Account (IRA) paying interest at the rate of 5% per year compounded continuously. Assuming that he

815

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS

deposited $2000 annually into the account, how much did he have in his IRA at the beginning of 2008? Solution

We use (20), with P  2000, r  0.05, T  16, and m  1, obtaining 2000 0.8 1e  12 0.05  49,021.64

A

Thus, Marcus had approximately $49.022 in his account at the beginning of 2008.

Exploring with

TECHNOLOGY Refer to Example 4. Suppose Marcus wished to know how much he would have in his IRA at any time in the future, not just at the beginning of 2008, as you were asked to compute in the example. 1. Using Formula (18) and the relevant data from Example 4, show that the required amount at any time x (x measured in years, x  0) is given by A  f (x)  20,000(e0.05x  1)

2. Use a graphing utility to plot the graph of f, using the viewing window [0, 30]  [2000, 400,000]. 3. Using ZOOM and TRACE , or using the function evaluation capability of your graphing utility, use the result of part 2 to verify the result obtained in Example 4. Comment on the advantage of the mathematical model found in part 1. Using (19), we can derive the following formula for the present value of an annuity.

Present Value of an Annuity

The present value of an annuity is given by PV 

mP 11  e rT 2 r

(21)

where P, r, T, and m are as defined earlier. APPLIED EXAMPLE 5 Sinking Funds Tomas Perez, the proprietor of a hardware store, wants to establish a fund from which he will withdraw $1000 per month for the next 10 years. If the fund earns interest at the rate of 6% per year compounded continuously, how much money does he need to establish the fund? We want to find the present value of an annuity with P  1000, r  0.06, T  10, and m  12. Using Equation (21), we find

Solution

12,000 11  e10.062 1102 2 0.06  90,237.70

PV 

Thus, Tomas needs approximately $90,238 to establish the fund.

816

11 INTEGRATION

Lorentz Curves and Income Distributions One method used by economists to study the distribution of income in a society is based on the Lorentz curve, named after American statistician M.D. Lorentz. To describe the Lorentz curve, let f(x) denote the proportion of the total income received by the poorest 100x% of the population for 0 x 1. Using this terminology, f(0.3)  0.1 simply states that the lowest 30% of the income recipients receive 10% of the total income. The function f has the following properties: y

1. 2. 3. 4. 5.

1

y = f (x )

x 1 FIGURE 45 A Lorentz curve

The domain of f is [0, 1]. The range of f is [0, 1]. f(0)  0 and f(1)  1. f(x) x for every x in [0, 1]. f is increasing on [0, 1].

The first two properties follow from the fact that both x and f(x) are fractions of a whole. Property 3 is a statement that 0% of the income recipients receive 0% of the total income and 100% of the income recipients receive 100% of the total income. Property 4 follows from the fact that the lowest 100x% of the income recipients cannot receive more than 100x% of the total income. A typical Lorentz curve is shown in Figure 45. APPLIED EXAMPLE 6 Lorentz Curves A developing country’s income distribution is described by the function f 1x2 

19 2 1 x  x 20 20

a. Sketch the Lorentz curve for the given function. b. Compute f(0.2) and f(0.8) and interpret your results.

y 1

Solution

a. The Lorentz curve is shown in Figure 46. y = f (x)

0.5

b.

f 10.2 2 

19 1 10.22 2  10.22  0.048 20 20

Thus, the lowest 20% of the people receive 4.8% of the total income. x 0.5 FIGURE 46 The Lorentz curve f (x) 

1 1 19 2 x  x 20 20

1

y=x

x FIGURE 47 The closer the Lorentz curve is to the line, the more equitable the income distribution.

19 1 10.82 2  10.82  0.648 20 20

Thus, the lowest 80% of the people receive 64.8% of the total income.

y

1

f 10.8 2 

Next, let’s consider the Lorentz curve described by the function y  f(x)  x. Since exactly 100x% of the total income is received by the lowest 100x% of income recipients, the line y  x is called the line of complete equality. For example, 10% of the total income is received by the lowest 10% of income recipients, 20% of the total income is received by the lowest 20% of income recipients, and so on. Now, it is evident that the closer a Lorentz curve is to this line, the more equitable the income distribution is among the income recipients. But the proximity of a Lorentz curve to the line of complete equality is reflected by the area between the Lorentz curve and the line y  x (Figure 47). The closer the curve is to the line, the smaller the enclosed area. This observation suggests that we may define a number, called the coefficient of inequality of a Lorentz curve, as the ratio of the area between the line of complete equality and the Lorentz curve to the area under the line of complete equality. Since

817

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS

the area under the line of complete equality is 12, we see that the coefficient of inequality is given by the following formula.

Coefficient of Inequality of a Lorentz Curve

The coefficient of inequality, or Gini index, of a Lorentz curve is L2



1

3x  f 1x2 4 dx

(22)

0

The coefficient of inequality is a number between 0 and 1. For example, a coefficient of zero implies that the income distribution is perfectly uniform. APPLIED EXAMPLE 7 Income Distributions In a study conducted by a certain country’s Economic Development Board with regard to the income distribution of certain segments of the country’s workforce, it was found that the Lorentz curves for the distribution of income of medical doctors and of movie actors are described by the functions f 1x 2 

14 2 1 x  x and 15 15

t1x2 

5 4 3 x  x 8 8

respectively. Compute the coefficient of inequality for each Lorentz curve. Which profession has a more equitable income distribution? Solution

The required coefficients of inequality are, respectively,

L1  2



1

cx  a

0



14 2 1 x  x b d dx  2 15 15

1

 a 15 x  15 x b dx 14

14

2

0

1

28 28 1 2 1 3 1  1x  x 2 2 dx  a x  x b` 15 0 15 2 3 0 14   0.311 45 L2  2



1

0

5  4



0

5 3 c x  a x 4  x b d dx  2 8 8 1

1

 a 8 x  8 x b dx 5

5

4

0

1 5 1 1 1x  x 4 2 dx  a x 2  x 5 b ` 4 2 5 0

15   0.375 40

We conclude that in this country the incomes of medical doctors are more evenly distributed than the incomes of movie actors.

11.7 Self-Check Exercises The demand function for a certain make of exercise bicycle that is sold exclusively through cable television is p  d 1x 2  19  0.02x

where p is the unit price in hundreds of dollars and x is the quantity demanded/week. The corresponding supply function is given by

p  s 1x 2  11  0.02x

where p has the same meaning as before and x is the number of exercise bicycles the supplier will make available at price p. Determine the consumers’ surplus and the producers’ surplus if the unit price is set at the equilibrium price. The solution to Self-Check Exercise 11.7 can be found on page 820.

818

11 INTEGRATION

11.7 Concept Questions 1. a. Define consumers’ surplus. Give a formula for computing it. b. Define producers’ surplus. Give a formula for computing it.

3. Define the amount of an annuity. Give a formula for computing it. 4. Explain the following terms: (a) Lorentz curve (b) Coefficient of inequality of a Lorentz curve.

2. a. Define the accumulated (future) value of an income stream. Give a formula for computing it. b. Define the present value of an income stream. Give a formula for computing it.

11.7 Exercises 1. CONSUMERS’ SURPLUS The demand function for a certain make of replacement cartridges for a water purifier is given by p  0.01x 2  0.1x  6

where p is the unit price in dollars and x is the quantity demanded each week, measured in units of a thousand. Determine the consumers’ surplus if the market price is set at $4/cartridge. 2. CONSUMERS’ SURPLUS The demand function for a certain brand of CD is given by p  0.01x 2  0.2x  8

where p is the wholesale unit price in dollars and x is the quantity demanded each week, measured in units of a thousand. Determine the consumers’ surplus if the wholesale market price is set at $5/disc. 3. CONSUMERS’ SURPLUS It is known that the quantity demanded of a certain make of portable hair dryer is x hundred units/week and the corresponding wholesale unit price is p  1225  5x

dollars. Determine the consumers’ surplus if the wholesale market price is set at $10/unit. 4. PRODUCERS’ SURPLUS The supplier of the portable hair dryers in Exercise 3 will make x hundred units of hair dryers available in the market when the wholesale unit price is p  136  1.8x

dollars. Determine the producers’ surplus if the wholesale market price is set at $9/unit. 5. PRODUCERS’ SURPLUS The supply function for the CDs of Exercise 2 is given by p  0.01x 2  0.1x  3

where p is the unit wholesale price in dollars and x stands for the quantity that will be made available in the market

by the supplier, measured in units of a thousand. Determine the producers’ surplus if the wholesale market price is set at the equilibrium price. 6. CONSUMERS’ AND PRODUCERS’ SURPLUS The management of the Titan Tire Company has determined that the quantity demanded x of their Super Titan tires/week is related to the unit price p by the relation p  144  x 2

where p is measured in dollars and x is measured in units of a thousand. Titan will make x units of the tires available in the market if the unit price is p  48 

1 2 x 2

dollars. Determine the consumers’ surplus and the producers’ surplus when the market unit price is set at the equilibrium price. 7. CONSUMERS’ AND PRODUCERS’ SURPLUS The quantity demanded x (in units of a hundred) of the Mikado miniature cameras/week is related to the unit price p (in dollars) by p  0.2x 2  80

and the quantity x (in units of a hundred) that the supplier is willing to make available in the market is related to the unit price p (in dollars) by p  0.1x 2  x  40

If the market price is set at the equilibrium price, find the consumers’ surplus and the producers’ surplus. 8. Refer to Example 3, page 813. Verify that 3

 580,000e

0.1t

dt  180,000  1,323,254

0

9. PRESENT VALUE OF AN INVESTMENT Suppose an investment is expected to generate income at the rate of R(t)  200,000

11.7 APPLICATIONS OF THE DEFINITE INTEGRAL TO BUSINESS AND ECONOMICS

819

dollars/year for the next 5 yr. Find the present value of this investment if the prevailing interest rate is 8%/year compounded continuously.

(RAM) on his home to meet this need. Estimate the amount of the mortgage he will require if the prevailing interest rate is 8%/year compounded continuously.

10. FRANCHISES Camille purchased a 15-yr franchise for a computer outlet store that is expected to generate income at the rate of

20. REVERSE ANNUITY MORTGAGE Refer to Exercise 19. Leah wishes to supplement her retirement income by $400/month for the next 15 yr by obtaining a RAM. Estimate the amount of the mortgage she will require if the prevailing interest rate is 6%/year compounded continuously.

R(t)  400,000

dollars/year. If the prevailing interest rate is 10%/year compounded continuously, find the present value of the franchise. 11. THE AMOUNT OF AN ANNUITY Find the amount of an annuity if $250/month is paid into it for a period of 20 yr, earning interest at the rate of 8%/year compounded continuously. 12. THE AMOUNT OF AN ANNUITY Find the amount of an annuity if $400/month is paid into it for a period of 20 yr, earning interest at the rate of 6%/year compounded continuously. 13. THE AMOUNT OF AN ANNUITY Aiso deposits $150/month in a savings account paying 6%/year compounded continuously. Estimate the amount that will be in his account after 15 yr. 14. CUSTODIAL ACCOUNTS The Armstrongs wish to establish a custodial account to finance their children’s education. If they deposit $200 monthly for 10 yr in a savings account paying 6%/year compounded continuously, how much will their savings account be worth at the end of this period? 15. IRA ACCOUNTS Refer to Example 4, page 814. Suppose Marcus made his IRA payment on April 1, 1992, and annually thereafter. If interest is paid at the same initial rate, approximately how much did Marcus have in his account at the beginning of 2008? 16. PRESENT VALUE OF AN ANNUITY Estimate the present value of an annuity if payments are $800 monthly for 12 yr and the account earns interest at the rate of 5%/year compounded continuously. 17. PRESENT VALUE OF AN ANNUITY Estimate the present value of an annuity if payments are $1200 monthly for 15 yr and the account earns interest at the rate of 6%/year compounded continuously. 18. LOTTERY PAYMENTS A state lottery commission pays the winner of the “Million Dollar” lottery 20 annual installments of $50,000 each. If the prevailing interest rate is 6%/year compounded continuously, find the present value of the winning ticket. 19. REVERSE ANNUITY MORTGAGES Sinclair wishes to supplement his retirement income by $300/month for the next 10 yr. He plans to obtain a reverse annuity mortgage

21. LORENTZ CURVES A certain country’s income distribution is described by the function f 1x2 

1 15 2 x  x 16 16

a. Sketch the Lorentz curve for this function. b. Compute f(0.4) and f(0.9) and interpret your results. 22. LORENTZ CURVES In a study conducted by a certain country’s Economic Development Board, it was found that the Lorentz curve for the distribution of income of college teachers was described by the function f 1x 2 

1 13 2 x  x 14 14

and that of lawyers by the function t 1x 2 

9 4 2 x  x 11 11

a. Compute the coefficient of inequality for each Lorentz curve. b. Which profession has a more equitable income distribution? 23. LORENTZ CURVES A certain country’s income distribution is described by the function f 1x2 

14 2 1 x  x 15 15

a. Sketch the Lorentz curve for this function. b. Compute f(0.3) and f(0.7). 24. LORENTZ CURVES In a study conducted by a certain country’s Economic Development Board, it was found that the Lorentz curve for the distribution of income of stockbrokers was described by the function f 1x 2 

11 2 1 x  x 12 12

and that of high school teachers by the function t 1x2 

5 2 1 x  x 6 6

a. Compute the coefficient of inequality for each Lorentz curve. b. Which profession has a more equitable income distribution?

820

11 INTEGRATION

11.7 Solutions to Self-Check Exercises We find the equilibrium price and equilibrium quantity by solving the system of equations

CS 

200

29  0.02x dx  12.24 2 1200 2



200

19  0.02x2 1/2 dx  448

0



p  29  0.02x



0

p  21  0.02x

simultaneously. Substituting the first equation into the second, we have 29  0.02x  21  0.02x

Squaring both sides of the equation then leads to 9  0.02x  1  0.02x x  200



200 2 1 a b 19  0.02x 2 3/2 `  448 0.02 3 0



1 153/2  93/2 2  448 0.03

 79.32

or approximately $7932. Next, the producers’ surplus is given by PS  12.242 12002 

Therefore,

Integrate by substitution.



200

21  0.02x dx

0

p  29  0.021200 2

 448 



200

11  0.02x 2 1/2 dx

0

 25  2.24

The equilibrium price is $224, and the equilibrium quantity is 200. The consumers’ surplus is given by

 448 

200 2 1 a b 11  0.02x 2 3/2 ` 0.02 3 0

 448 

1 153/2  12 0.03

 108.66

or approximately $10,866.

USING

TECHNOLOGY

Business and Economic Applications/Technology Exercises 1. Re-solve Example 1, Section 11.7, using a graphing utility. Hint: Use the intersection operation to find the equilibrium quantity and the equilibrium price. Use the numerical integral operation to evaluate the definite integral.

2. Re-solve Exercise 7, Section 11.7, using a graphing utility. Hint: See Exercise 1.

3. The demand function for a certain brand of travel alarm clocks is given by p  0.01x 2  0.3x  10

where p is the wholesale unit price in dollars and x is the quantity demanded each month, measured in units of a thousand. The supply function for this brand of clocks is given by p  0.01x 2  0.2x  4

where p has the same meaning as before and x is the quantity, in thousands, the supplier will make available in the marketplace per month. Determine the consumers’ surplus and the producers’ surplus when the market unit price is set at the equilibrium price. 4. The quantity demanded of a certain make of compact disc organizer is x thousand units per week, and the corresponding wholesale unit price is p  1400  8x

SUMMARY OF PRINCIPAL FORMULAS AND TERMS

821

dollars. The supplier of the organizers will make x thousand units available in the market when the unit wholesale price is p  0.02x 2  0.04x  5

dollars. Determine the consumers’ surplus and the producers’ surplus when the market unit price is set at the equilibrium price. 5. Investment A is expected to generate income at the rate of R1 1t2  50,000  10,0001t

dollars/year for the next 5 years and investment B is expected to generate income at the rate of R2(t)  50,000  6000t

dollars/year over the same period of time. If the prevailing interest rate for the next 5 years is 10%/year, which investment will generate a higher net income by the end of 5 years? 6. Investment A is expected to generate income at the rate of R1(t)  40,000  5000t  100t 2

dollars/year for the next 10 years and investment B is expected to generate income at the rate of R2(t)  60,000  2000t

dollars/year over the same period of time. If the prevailing interest rate for the next 10 years is 8%/year, which investment will generate a higher net income by the end of 10 years?

CHAPTER 11 Summary of Principal Formulas and Terms FORMULAS 1. Indefinite integral of a constant

 k du  ku  C

2. Power rule

 u n du  n  1  C

3. Constant multiple rule

 k f 1u 2 du  k  f 1u2 du

u n1

1n  12

(k, a constant)

 3 f 1u 2 t 1u2 4 du   f 1u2 du  t 1u 2 du

4. Sum rule

5. Indefinite integral of the exponential

function 6. Indefinite integral of f 1u 2  7. Method of substitution

1 u

 e u du  e u  C 

du  ln 0 u 0  C u

 f ¿ 1t 1x2 2 t¿ 1x2 dx   f ¿ 1u 2 du

822

11 INTEGRATION b

8. Definite integral as the limit of a sum

 f 1x 2 dx  lim S , nS

a

n

where Sn is a Riemann sum b

9. Fundamental theorem of calculus

 f 1x 2 dx  F1b 2  F1a2, F¿ 1x2  f 1x2 a

10. Average value of f over [a, b]

11. Area between two curves

1 ba



b



b

f 1x2 dx

a

3 f 1x2  t 1x2 4 dx, f 1x2  t 1x2

a x

12. Consumers’ surplus

CS 

 D1x2 dx  p x 0

x

13. Producers’ surplus

PS  p x 

 S1x2 dx 0

14. Accumulated (future) value of an income stream 15. Present value of an income stream



A  erT

T

R1t2 ert dt

0

PV 



T

R1t2 ert dt

0

16. Amount of an annuity 17. Present value of an annuity 18. Coefficient of inequality of a Lorentz curve

mP rT A 1e  1 2 r mP PV  11  erT 2 r L2



1

3 x  f 1x2 4 dx

0

TERMS antiderivative (742) antidifferentiation (744) integration (744) indefinite integral (744) integrand (744)

constant of integration (744) differential equation (748) initial value problem (748) Riemann sum (769) definite integral (769)

lower limit of integration (769) upper limit of integration (769) Lorentz curve (816) line of complete equality (816)

CHAPTER 11 Concept Review Questions Fill in the blanks.

1. a. A function F is an antiderivative of f on an interval, if _____ for all x in I. b. If F is an antiderivative of f on an interval I, then every antiderivative of f on I has the form _____. 2. a.  cf 1x 2 dx  _____ b.  3 f 1x 2 t 1x 2 4 dx  _____

3. a. A differential equation is an equation that involves the derivative or differential of a/an _____ function. b. A solution of a differential equation on an interval I is any _____ that satisfies the differential equation.

4. If we let u  t(x), then du  _____, and the substitution transforms the integral  f 1 t 1x2 2t¿ 1x2 dx into the integral _____ involving only u. 5. a. If f is continuous and nonnegative on an interval [a, b], then the area of the region under the graph of f on [a, b] is given by _____. b. If f is continuous on an interval [a, b], then ab f 1x 2 dx is equal to the area(s) of the regions lying above the x-axis and bounded by the graph of f on [a, b] _____ the area(s) of the regions lying below the x-axis and bounded by the graph of f on [a, b].

REVIEW EXERCISES

6. a. The fundamental theorem of calculus states that if f is continuous on [a, b], then ab f 1x 2 dx  _____, where F is a/an _____ of f. b. The net change in a function f over an interval [a, b] is given by f (b)  f (a)  _____, provided f  is continuous on [a, b]. 7. a. If f is continuous on [a, b], then the average value of f over [a, b] is the number _____. b. If f is a continuous and nonnegative function on [a, b], then the average value of f over [a, b] may be thought of as the _____ of the rectangle with base lying on the interval [a, b] and having the same _____ as the region under the graph of f on [a, b].

823

9. a. The consumers’ surplus is given by CS  _____. b. The producers’ surplus is given by PS  _____. 10. a. The accumulated value after T years of an income stream of R(t) dollars/year, earning interest of r/year compounded continuously, is given by A  _____. b. The present value of an income stream is given by PV  _____. 11. The amount of an annuity is A  _____. 12. The coefficient of inequality of a Lorentz curve is L  _____.

8. If f and t are continuous on [a, b] and f (x)  t(x) for all x in [a, b], then the area of the region between the graphs of f and t and the vertical lines x  a and x  b is A  _____.

CHAPTER 11 Review Exercises In Exercises 1–20, find each indefinite integral.

1. 3. 5.

 1x 3  2x 2  x2 dx

2.

 a x 4  2x 3  x 2 b dx

4.

1

 x12x 2  x1/2 2 dx

6.

2 a x 2  x   5 b dx 8. x

 a 3 x 3  2x 2  8 b dx  1x1/3  1x  4 2 dx  1x 2  12 1 1x  12 dx



9.

 13x  12 13x 2  2x  12 1/3 dx 1x  2 2 dx

10.

x

12.

 2e

14.

 1ex  x2 2 dx

3

2x

10

dx

ex  1

ln x 2 dx 16.  x 18. 20.

 x 1x  1 dx

 12x  1 dx

1 2 a x  b ex x1 dx 2

13.



15.



17.

x

19.



1ln x 2 5 x 3

dx

1x  12 dx 2

10

x dx 1x  2



1

12x 3  3x 2  12 dx



2

14x 3  9x 2  2x  12 dx

0

22.



0



7



1



2



e

1 1x  x3/2 2 dx

0

1

24.

 20x12x

2

 1 2 4 dx

0

121x 2  2x2 1x 3  3x 2  1 2 3 dx

1

26.

x1x  3 dx

27.

4

28.

0

29.

1



2

xe 11/22x dx

31.

2



0

x dx x 1 2

4x 21  2x 2

0

1

0

32.



2

0

dx 15  2x2 2

dx

ex dx 11  ex 2 2

ln x dx x

In Exercises 33–36, find the function f given that the slope of the tangent line to the graph at any point (x, f(x)) is f (x) and that the graph of f passes through the given point.

33. f (x)  3x 2  4x  1; (1, 1) 34. f ¿1x2 

x 2x  1 2

; 10, 1 2

35. f (x)  1  ex ; (0, 2)

3x

 1x  1 dx

In Exercises 21–32, evaluate each definite integral.

21.

25.

30.

x1 dx 11.  2 x  2x  5



4

1

1

7.

2

23.

36. f ¿1x2 

ln x ; 11, 22 x

37. Let f(x)  2x 2  1 and compute the Riemann sum of f over the interval [1, 2] by partitioning the interval into five subintervals of the same length (n  5), where the points pi (1 i 5) are taken to be the right endpoints of the respective subintervals.

824

11 INTEGRATION

38. MARGINAL COST FUNCTIONS The management of National Electric has determined that the daily marginal cost function associated with producing their automatic drip coffeemakers is given by C(x)  0.00003x 2  0.03x  20

where C(x) is measured in dollars/unit and x denotes the number of units produced. Management has also determined that the daily fixed cost incurred in producing these coffeemakers is $500. What is the total cost incurred by National in producing the first 400 coffeemakers/day? 39. MARGINAL REVENUE FUNCTIONS Refer to Exercise 38. Management has also determined that the daily marginal revenue function associated with producing and selling their coffeemakers is given by R(x)  0.03x  60

where x denotes the number of units produced and sold and R(x) is measured in dollars/unit. a. Determine the revenue function R(x) associated with producing and selling these coffeemakers. b. What is the demand equation relating the wholesale unit price to the quantity of coffeemakers demanded? 40. COMPUTER RESALE VALUE Franklin National Life Insurance Company purchased new computers for $200,000. If the rate at which the computers’ resale value changes is given by the function

43. AIR POLLUTION On an average summer day, the level of carbon monoxide (CO) in a city’s air is 2 parts per million (ppm). An environmental protection agency’s study predicts that, unless more stringent measures are taken to protect the city’s atmosphere, the CO concentration present in the air will increase at the rate of 0.003t 2  0.06t  0.1

ppm/year, t yr from now. If no further pollution-control efforts are made, what will be the CO concentration on an average summer day 5 yr from now? 44. PROJECTION TV SALES The marketing department of Vista Vision forecasts that sales of their new line of projection television systems will grow at the rate of 3000  2000e0.04t

units/month once they are introduced into the market. Find an expression giving the total number of the projection television systems that Vista may expect to sell t mo from the time they are put on the market. How many units of the television systems can Vista expect to sell during the first year? 45. COMMUTER TRENDS Due to the increasing cost of fuel, the manager of the City Transit Authority estimates that the number of commuters using the city subway system will increase at the rate of 3000(1  0.4t)1/2

V(t)  3800(t  10)

(0 t 24)

(0 t 36)

where t is the length of time since the purchase date and V (t) is measured in dollars/year, find an expression V(t) that gives the resale value of the computers after t yr. How much would the computers cost after 6 yr?

per month, t mo from now. If 100,000 commuters are currently using the system, find an expression giving the total number of commuters who will be using the subway t mo from now. How many commuters will be using the subway 6 mo from now?

41. MEASURING TEMPERATURE The temperature on a certain day as measured at the airport of a city is changing at the rate of

46. SALES: LOUDSPEAKERS Sales of the Acrosonic model F loudspeaker systems have been growing at the rate of

T(t)  0.15t 2  3.6t  14.4

(0 t 4)

°F/hour, where t is measured in hours, with t  0 corresponding to 6 a.m. The temperature at 6 a.m. was 24°F. a. Find an expression giving the temperature T at the airport at any time between 6 a.m. and 10 a.m. b. What was the temperature at 10 a.m.? 42. DVD SALES The total number of DVDs sold to U.S. dealers for rental and sale from 1999 through 2003 grew at the rate of approximately R(t)  0.03t 2  0.218t  0.032

(0 t 4)

billion units/year, where t is measured in years, with t  0 corresponding to 1999. The total number of DVDs sold as of 1999 was 0.1 billion units. a. Find an expression giving the total number of DVDs sold by year t (0 t 4). b. How many DVDs were sold in 2003? Source: Adams Media

f (t)  2000(3  2et )

units/year, where t denotes the number of years these loudspeaker systems have been on the market. Determine the number of loudspeaker systems that were sold in the first 5 yr after they appeared on the market. 47. SUPPLY: WOMEN’S BOOTS The rate of change of the unit price p (in dollars) of Apex women’s boots is given by p¿1x2 

240 15  x 2 2

where x is the number of pairs in units of a hundred that the supplier will make available in the market daily when the unit price is $p/pair. Find the supply equation for these boots if the quantity the supplier is willing to make available is 200 pairs daily (x  2) when the unit price is $50/pair.

REVIEW EXERCISES

48. MARGINAL COST FUNCTIONS The management of a division of Ditton Industries has determined that the daily marginal cost function associated with producing their hot-air corn poppers is given by C (x)  0.00003x 2  0.03x  10

where C(x) is measured in dollars/unit and x denotes the number of units manufactured. Management has also determined that the daily fixed cost incurred in producing these corn poppers is $600. Find the total cost incurred by Ditton in producing the first 500 corn poppers. 49. U.S. CENSUS The number of Americans aged 45–54 yr (which stood at 25 million at the beginning of 1990) grew at the rate of

58. OIL PRODUCTION Based on current production techniques, the rate of oil production from a certain oil well t yr from now is estimated to be R1(t)  100e0.05t

thousand barrels/year. Based on a new production technique, however, it is estimated that the rate of oil production from that oil well t yr from now will be R2(t)  100e0.08t

thousand barrels/year. Determine how much additional oil will be produced over the next 10 yr if the new technique is adopted. 59. Find the average value of the function f 1x 2 

R(t)  0.00933t 3  0.019t 2  0.10833t  1.3467

million people/year, t yr from the beginning of 1990. How many Americans aged 45 to 54 were added to the population between 1990 and the year 2000? Source: U.S. Census Bureau

50. ONLINE RETAIL SALES Since the inception of the Web, online commerce has enjoyed phenomenal growth. But growth, led by such major sectors as books, tickets, and office supplies, is expected to slow in the coming years. The projected growth of online retail sales is given by R(t)  15.82e0.176t

(0 t 4)

where t is measured in years with t  0 corresponding to 2007 and R(t) is measured in billions of dollars per year. Online retail sales in 2007 were $116 billion. a. Find an expression for online retail sales in year t. b. If the projection holds true, what will be online retail sales in 2011? Source: Jupiter Research

51. Find the area of the region under the curve y  3x  2x  1 from x  1 to x  2. 2

52. Find the area of the region under the curve y  e 2x from x  0 to x  2. 53. Find the area of the region bounded by the graph of the function y  1/x 2, the x-axis, and the lines x  1 and x  3. 54. Find the area of the region bounded by the curve y  x 2  x  2 and the x-axis. 55. Find the area of the region bounded by the graphs of the functions f(x)  e x and t(x)  x and the vertical lines x  0 and x  2. 56. Find the area of the region that is completely enclosed by the graphs of f (x)  x 4 and t(x)  x. 57. Find the area of the region between the curve y  x(x  1)(x  2) and the x-axis.

825

x 2x  16 2

over the interval [0, 3]. 60. AVERAGE TEMPERATURE The temperature (in °F) in Boston over a 12-hr period on a certain December day was given by T  0.05t 3  0.4t 2  3.8t  5.6

(0 t 12)

where t is measured in hours, with t  0 corresponding to 6 a.m. Determine the average temperature on that day over the 12-hr period from 6 a.m. to 6 p.m. 61. AVERAGE VELOCITY OF A TRUCK A truck traveling along a straight road has a velocity (in feet/second) at time t (in seconds) given by √ 1t2 

1 2 t  2t  44 12

10 t 52

What is the average velocity of the truck over the time interval from t  0 to t  5? 62. MEMBERSHIP IN CREDIT UNIONS Credit unions in Massachusetts have grown remarkably in recent years. Their taxexempt status allows them to offer deposit and loan rates that are often more favorable than those offered by banks. The membership in Massachusetts credit unions grew at the rate of R(t)  0.0039t 2  0.0374t  0.0046

(0 t 9)

million members/year between 1994 (t  0) and 2003 (t  9). Find the average rate of growth of membership in Massachusetts credit unions over the period in question. Source: Massachusetts Credit Union League

63. DEMAND FOR DIGITAL CAMCORDER TAPES The demand function for a brand of blank digital camcorder tapes is given by p  0.01x 2  0.2x  23

where p is the wholesale unit price in dollars and x is the quantity demanded each week, measured in units of a thousand. Determine the consumers’ surplus if the wholesale unit price is $8/tape.

826

11 INTEGRATION

64. CONSUMERS’ AND PRODUCERS’ SURPLUS The quantity demanded x (in units of a hundred) of the Sportsman 5  7 tents, per week, is related to the unit price p (in dollars) by the relation p  0.1x 2  x  40

The quantity x (in units of a hundred) that the supplier is willing to make available in the market is related to the unit price by the relation p  0.1x 2  2x  20

67. PRESENT VALUE OF A FRANCHISE Alicia purchased a 10-yr franchise for a health spa that is expected to generate income at the rate of P(t)  80,000

dollars/year. If the prevailing interest rate is 10%/year compounded continuously, find the present value of the franchise. 68. INCOME DISTRIBUTION OF A COUNTRY A certain country’s income distribution is described by the function f 1x 2 

If the market price is set at the equilibrium price, find the consumers’ surplus and the producers’ surplus.

17 2 1 x  x 18 18

65. RETIREMENT ACCOUNT SAVINGS Chi-Tai plans to deposit $4000/year in his Keogh Retirement Account. If interest is compounded continuously at the rate of 8%/year, how much will he have in his retirement account after 20 yr?

a. Sketch the Lorentz curve for this function. b. Compute f(0.3) and f(0.6) and interpret your results. c. Compute the coefficient of inequality for this Lorentz curve.

66. INSTALLMENT CONTRACTS Glenda sold her house under an installment contract whereby the buyer gave her a down payment of $20,000 and agreed to make monthly payments of $925/month for 30 yr. If the prevailing interest rate is 6%/year compounded continuously, find the present value of the purchase price of the house.

69. POPULATION GROWTH The population of a certain Sunbelt city, currently 80,000, is expected to grow exponentially in the next 5 yr with a growth constant of 0.05. If the prediction comes true, what will be the average population of the city over the next 5 yr?

CHAPTER 11 Before Moving On . . . 1. Find  a 2x 3  1x 

2 2  b dx. x 1x

2. Find f if f (x)  e x  x and f (0)  2. 3. Find 

x 2x 2  1

dx.

1

4. Evaluate

 x 22  x

2

dx

0

5. Find the area of the region completely enclosed by the graphs of y  x 2  1 and y  1  x.

12

CALCULUS OF SEVERAL VARIABLES

U

P TO NOW, we have dealt with functions involving one variable. However, many situations involve functions of

two or more variables. For example, the Consumer Price Index (CPI) compiled by the Bureau of Labor Statistics depends on the price of more than 95,000 consumer items. To study such

variables, the first topic in this chapter. Next, generalizing the concept of the derivative of a function of one variable, we study the partial derivatives of a function of two or more variables. Using partial derivatives, we study the rate of change of a function with respect to one variable while holding all other variables constant. We then learn how to find the extremum values of a function of several variables. For example, we will learn how a manufacturer can maximize her profits by producing the optimal quantity of her products.

© Judith Collins/Alamy

relationships, we need the notion of a function of several

How many loudspeaker systems should the Aerosonic company produce to maximize its profit? In Example 4, page 855, you will see how the techniques of calculus can be used to help answer this question.

828

12 CALCULUS OF SEVERAL VARIABLES

12.1 Functions of Several Variables Up to now, our study of calculus has been restricted to functions of one variable. In many practical situations, however, the formulation of a problem results in a mathematical model that involves a function of two or more variables. For example, suppose Ace Novelty determines that the profits are $6, $5, and $4 for three types of souvenirs it produces. Let x, y, and z denote the number of type-A, type-B, and type-C souvenirs to be made; then the company’s profit is given by P  6x  5y  4z

and P is a function of the three variables, x, y, and z.

Functions of Two Variables Although this chapter deals with real-valued functions of several variables, most of our definitions and results are stated in terms of a function of two variables. One reason for adopting this approach, as you will soon see, is that there is a geometric interpretation for this special case, which serves as an important visual aid. We can then draw upon the experience gained from studying the two-variable case to help us understand the concepts and results connected with the more general case, which, by and large, is just a simple extension of the lower-dimensional case. A Function of Two Variables

A real-valued function of two variables f consists of 1. A set A of ordered pairs of real numbers (x, y) called the domain of the function. 2. A rule that associates with each ordered pair in the domain of f one and only one real number, denoted by z  f (x, y). The variables x and y are called independent variables, and the variable z, which is dependent on the values of x and y, is referred to as a dependent variable. As in the case of a real-valued function of one real variable, the number z  f(x, y) is called the value of f at the point (x, y). And, unless specified, the domain of the function f will be taken to be the largest possible set for which the rule defining f is meaningful. EXAMPLE 1 Let f be the function defined by f(x, y)  x  xy  y 2  2

Compute f(0, 0), f (1, 2), and f (2, 1). Solution

We have f(0, 0)  0  (0)(0)  02  2  2 f(1, 2)  1  (1)(2)  22  2  9 f(2, 1)  2  (2)(1)  12  2  7

The domain of a function of two variables f(x, y) is a set of ordered pairs of real numbers and may therefore be viewed as a subset of the xy-plane. EXAMPLE 2 Find the domain of each of the following functions. a. f(x, y)  x 2  y 2

b. t1x, y 2 

2 xy

c. h 1x, y 2  21  x 2  y 2

12.1 FUNCTIONS OF SEVERAL VARIABLES y

Solution

x

a. f(x, y) is defined for all real values of x and y, so the domain of the function f is the set of all points (x, y) in the xy-plane. b. t(x, y) is defined for all x  y, so the domain of the function t is the set of all points in the xy-plane except those lying on the line y  x (Figure 1a). c. We require that 1  x 2  y 2  0 or x 2  y 2 1, which is just the set of all points (x, y) lying on and inside the circle of radius 1 with center at the origin (Figure 1b). APPLIED EXAMPLE 3 Revenue Functions Acrosonic manufactures a bookshelf loudspeaker system that may be bought fully assembled or in a kit. The demand equations that relate the unit prices, p and q, to the quantities demanded weekly, x and y, of the assembled and kit versions of the loudspeaker systems are given by

(a) Domain of g y

1

p  300  x

–1

829

1

1 1 x  y and 4 8

q  240 

1 3 x y 8 8

a. What is the weekly total revenue function R(x, y)? b. What is the domain of the function R?

–1

Solution (b) Domain of h FIGURE 1

a. The weekly revenue realizable from the sale of x units of the assembled speaker systems at p dollars per unit is given by xp dollars. Similarly, the weekly revenue realizable from the sale of y units of the kits at q dollars per unit is given by yq dollars. Therefore, the weekly total revenue function R is given by R 1x, y2  xp  yq  x a 300 

1 1 1 3 x  y b  y a 240  x  y b 4 8 8 8 3 1 1   x 2  y 2  xy  300x  240y 4 8 4

y

1 4

1 x 4 1 240  x  8 300 

1000

1 3 240 – 8 x – 8 y = 0

D

x 1000

2000

FIGURE 2 The domain of R(x, y)

See page 10.

b. To find the domain of the function R, let’s observe that the quantities x, y, p, and q must be nonnegative. This observation leads to the following system of linear inequalities:

1 8

300 – x – y = 0

2000

(x2)

1 y0 8 3 y0 8 x0 y0

The domain of the function R is sketched in Figure 2.

Explore & Discuss Suppose the total profit of a two-product company is given by P(x, y), where x denotes the number of units of the first product produced and sold and y denotes the number of units of the second product produced and sold. Fix x  a, where a is a positive number so that (a, y) is in the domain of P. Describe and give an economic interpretation of the function f(y)  P(a, y). Next, fix y  b, where b is a positive number so that (x, b) is in the domain of P. Describe and give an economic interpretation of the function t(x)  P(x, b).

830

12 CALCULUS OF SEVERAL VARIABLES

APPLIED EXAMPLE 4 Home Mortgage Payments The monthly payment that amortizes a loan of A dollars in t years when the interest rate is r per year is given by P  f 1A, r, t2 

Ar 1231  11  12r 2 12t 4

Find the monthly payment for a home mortgage of $270,000 to be amortized over 30 years when the interest rate is 8% per year, compounded monthly. Letting A  270,000, r  0.08, and t  30, we find the required monthly payment to be Solution

P  f 1270,000, 0.08, 302 

270,00010.08 2

360 1231  11  0.08 4 12 2

 1981.16

or approximately $1981.16. z

Graphs of Functions of Two Variables 2

–2 O

–2

y 2

2 –2 x FIGURE 3 The three-dimensional Cartesian coordinate system

To graph a function of two variables, we need a three-dimensional coordinate system. This is readily constructed by adding a third axis to the plane Cartesian coordinate system in such a way that the three resulting axes are mutually perpendicular and intersect at O. Observe that, by construction, the zeros of the three number scales coincide at the origin of the three-dimensional Cartesian coordinate system (Figure 3). A point in three-dimensional space can now be represented uniquely in this coordinate system by an ordered triple of numbers (x, y, z), and, conversely, every ordered triple of real numbers (x, y, z) represents a point in three-dimensional space (Figure 4a). For example, the points A(2, 3, 4), B(1, 2, 2), C(2, 4, 0), and D(0, 0, 4) are shown in Figure 4b. z

z D(0, 0, 4)

A(2, 3, 4)

P(x, y, z) y

y C(2, 4, 0) (x, y) x (a) A point in three-dimensional space

z (x, y, z)

z = f (x, y )

y (x, y) x FIGURE 5 The graph of a function in threedimensional space

x

B(1, – 2, – 2)

(b) Some sample points in threedimensional space

FIGURE 4

Now, if f(x, y) is a function of two variables x and y, the domain of f is a subset of the xy-plane. Let z  f(x, y) so that there is one and only one point (x, y, z)  (x, y, f(x, y)) associated with each point (x, y) in the domain of f. The totality of all such points makes up the graph of the function f and is, except for certain degenerate cases, a surface in three-dimensional space (Figure 5). In interpreting the graph of a function f(x, y), one often thinks of the value z  f(x, y) of the function at the point (x, y) as the “height” of the point (x, y, z) on the graph of f. If f(x, y)  0, then the point (x, y, z) is f(x, y) units above the xy-plane; if f(x, y) 0, then the point (x, y, z) is  f(x, y) units below the xy-plane.

12.1 FUNCTIONS OF SEVERAL VARIABLES

831

In general, it is quite difficult to draw the graph of a function of two variables. But techniques have been developed that enable us to generate such graphs with minimum effort, using a computer. Figure 6 shows the computer-generated graphs of two functions.

FIGURE 6 Two computer-generated graphs of functions of two variables

(a) f(x, y)  x 3  3y 2x

(b) f(x, y)  ln(x 2  2y 2  1)

Level Curves As mentioned earlier, the graph of a function of two variables is often difficult to sketch, and we will not develop a systematic procedure for sketching it. Instead, we describe a method that is used in constructing topographic maps. This method is relatively easy to apply and conveys sufficient information to enable one to obtain a feel for the graph of the function. Suppose that f(x, y) is a function of two variables x and y, with a graph as shown in Figure 7. If c is some value of the function f, then the equation f(x, y)  c describes a curve lying on the plane z  c called the trace of the graph of f in the plane z  c. If this trace is projected onto the xy-plane, the resulting curve in the xy-plane is called a level curve. By drawing the level curves corresponding to several admissible values of c, we obtain a contour map. Observe that, by construction, every point on a particular level curve corresponds to a point on the surface z  f(x, y) that is a certain fixed distance from the xy-plane. Thus, by elevating or depressing the level curves that make up the contour map in one’s mind, it is possible to obtain a feel for the general shape z

z = f (x, y)

z=c

y f (x, y) = c (level curve) FIGURE 7

The graph of the function z  f(x, y) and its intersection with the plane z  c

x

832

12 CALCULUS OF SEVERAL VARIABLES

of the surface represented by the function f. Figure 8a shows a part of a mountain range with one peak; Figure 8b is the associated contour map.

2000 1600 1600

1200

1200 2000 800

800 400

FIGURE 8

400

(a) A peak on a mountain range

(b) A contour map for the mountain peak

EXAMPLE 5 Sketch a contour map for the function f(x, y)  x 2  y 2. The level curves are the graphs of the equation x 2  y 2  c for nonnegative numbers c. Taking c  0, 1, 4, 9, and 16, for example, we obtain Solution

c  0: x 2  y 2  0 c  1: x 2  y 2  1 c  4: x 2  y 2  4  22 c  9: x 2  y 2  9  32 c  16: x 2  y 2  16  42

The five level curves are concentric circles with center at the origin and radius given by r  0, 1, 2, 3, and 4, respectively (Figure 9a). A sketch of the graph of f(x, y)  x 2  y 2 is included for your reference in Figure 9b. z

y

c=1 c=4

f (x, y) = x 2 + y 2

c=9 c = 16

x 2 + y 2 = 16 1

2

3

x

4

x2 + y2 = 9 x2 + y2 = 4 x2 + y2 = 1

y

x2 + y2 = 0

c=0 x FIGURE 9

(a) Level curves of f(x, y)  x  y 2

2

(b) The graph of f(x, y)  x 2  y 2

EXAMPLE 6 Sketch the level curves for the function f(x, y)  2x 2  y corresponding to z  2, 1, 0, 1, and 2. The level curves are the graphs of the equation 2x 2  y  k or y  2x  k for k  2, 1, 0, 1, and 2. The required level curves are shown in Figure 10.

Solution 2

12.1 FUNCTIONS OF SEVERAL VARIABLES k = –2 k = –1 k=0

y 4

k=2 k=1 x 2

–2

–2

833

Level curves of functions of two variables are found in many practical applications. For example, if f(x, y) denotes the temperature at a location within the continental United States with longitude x and latitude y at a certain time of day, then the temperature at the point (x, y) is given by the “height” of the surface, represented by z  f(x, y). In this situation the level curve f(x, y)  k is a curve superimposed on a map of the United States, connecting points having the same temperature at a given time (Figure 11). These level curves are called isotherms. Similarly, if f(x, y) gives the barometric pressure at the location (x, y), then the level curves of the function f are called isobars, lines connecting points having the same barometric pressure at a given time. As a final example, suppose P(x, y, z) is a function of three variables x, y, and z giving the profit realized when x, y, and z units of three products, A, B, and C, respectively, are produced and sold. Then, the equation P(x, y, z)  k, where k is a constant, represents a surface in three-dimensional space called a level surface of P. In this situation, the level surface represented by P(x, y, z)  k represents the product mix that results in a profit of exactly k dollars. Such a level surface is called an isoprofit surface.

FIGURE 10

Level curves for f(x, y)  2x 2  y

50

40

30 30

60

40

70

50 60

80

70 80 FIGURE 11

70

Isotherms: curves connecting points that have the same temperature

80

80

12.1 Self-Check Exercises 1. Let f 1x, y2  x 2  3xy  1x  y. Compute f(1, 3) and f(1, 1). Is the point (1, 0) in the domain of f ? 2. Find the domain of f 1x, y2 

1 1   e xy. x xy

3. Odyssey Travel Agency has a monthly advertising budget of $20,000. Odyssey’s management estimates that if they spend x dollars on newspaper advertising and y dollars on

television advertising, then the monthly revenue will be f(x, y)  30x 1/4y 3/4

dollars. What will be the monthly revenue if Odyssey spends $5000/month on newspaper ads and $15,000/month on television ads? If Odyssey spends $4000/month on newspaper ads and $16,000/month on television ads? Solutions to Self-Check Exercises 12.1 can be found on page 836.

12.1 Concept Questions 1. What is a function of two variables? Give an example of a function of two variables and state its rule of definition and domain. 2. If f is a function of two variables, what can you say about

the relationship between f (a, b) and f (c, d), if (a, b) is in the domain of f and c  a and d  b? 3. Define (a) the graph of f (x, y) and (b) a level curve of f.

834

12 CALCULUS OF SEVERAL VARIABLES

12.1 Exercises 1. Let f(x, y)  2x  3y  4. Compute f (0, 0), f (1, 0), f (0, 1), f (1, 2), and f(2, 1).

27. The volume of a cylindrical tank of radius r and height h is given by

2. Let t(x, y)  2x 2  y 2. Compute t(1, 2), t(2, 1), t(1, 1), t(1, 1), and t(2, 1).

V  f(r, h)  pr 2h

3. Let f (x, y)  x 2  2xy  x  3. Compute f(1, 2), f(2, 1), f (1, 2), and f (2, 1). 4. Let h(x, y)  (x  y)/(x  y). Compute h(0, 1), h(1, 1), h(2, 1), and h(p, p). 5. Let t 1s, t 2  3s1t  t 1s  2. Compute t(1, 2), t(2, 1), t(0, 4), and t(4, 9). 6. Let f (x, y)  xye x f (1, 1).

2y 2

. Compute f (0, 0), f (0, 1), f (1, 1), and

7. Let h(s, t)  s ln t  t ln s. Compute h(1, e), h(e, 1), and h(e, e). 8. Let f(u, √)  (u 2  √ 2)eu√ . Compute f (0, 1), f(1, 1), f (a, b), and f (b, a).

Find the volume of a cylindrical tank of radius 1.5 ft and height 4 ft. 28. IQS The IQ (intelligence quotient) of a person whose mental age is m yr and whose chronological age is c yr is defined as f 1m, c 2 

100m c

What is the IQ of a 9-yr-old child who has a mental age of 13.5 yr? 29. BODY MASS The body mass index (BMI) is used to identify, evaluate, and treat overweight and obese adults. The BMI value for an adult of weight w (in kilograms) and height h (in meters) is defined to be

2

9. Let t(r, s, t)  re s/t. Compute t(1, 1, 1), t(1, 0, 1), and t(1, 1, 1). 10. Let t(u, √, w)  (ue √w  √e uw  we u√)/(u 2  √ 2  w 2). Compute t(1, 2, 3) and t(3, 2, 1). In Exercises 11–18, find the domain of the function.

11. f (x, y)  2x  3y

12. t(x, y, z)  x 2  y 2  z 2

u√ 13. h 1u, √2  u√

14. f 1s, t 2  2s  t

15. t 1r, s 2  1rs

16. f (x, y)  exy

2

2

17. h(x, y)  ln(x  y  5) 18. h 1u, √ 2  24  u 2  √ 2 In Exercises 19–24, sketch the level curves of the function corresponding to each value of z.

19. f (x, y)  2x  3y; z  2, 1, 0, 1, 2 20. f (x, y)  x 2  y; z  2, 1, 0, 1, 2 21. f (x, y)  2x 2  y; z  2, 1, 0, 1, 2 22. f (x, y)  xy; z  4, 2, 2, 4 23. f 1x, y 2  216  x 2  y 2; z  0, 1, 2, 3, 4 24. f (x, y)  e x  y; z  2, 1, 0, 1, 2

M  f 1w, h2 

w h2

According to federal guidelines, an adult is overweight if he or she has a BMI value between 25 and 29.9 and is “obese” if the value is greater than or equal to 30. a. What is the BMI of an adult who weighs in at 80 kg and stands 1.8 m tall? b. What is the maximum weight for an adult of height 1.8 m, who is not classified as overweight or obese? 30. POISEUILLE’S LAW Poiseuille’s law states that the resistance R, measured in dynes, of blood flowing in a blood vessel of length l and radius r (both in centimeters) is given by R  f 1l, r 2 

kl r4

where k is the viscosity of blood (in dyne-sec/cm2). What is the resistance, in terms of k, of blood flowing through an arteriole 4 cm long and of radius 0.1 cm? 31. REVENUE FUNCTIONS Country Workshop manufactures both finished and unfinished furniture for the home. The estimated quantities demanded each week of its rolltop desks in the finished and unfinished versions are x and y units when the corresponding unit prices are p  200 

1 1 x y 5 10

q  160 

1 1 x y 10 4

25. Find an equation of the level curve of f (x, y)  2x 2  y 2 that contains the point (3, 4).

dollars, respectively. a. What is the weekly total revenue function R(x, y)? b. Find the domain of the function R.

26. Find an equation of the level surface of f (x, y, z)  2x 2  3y 2  z that contains the point (1, 2, 3).

32. For the total revenue function R(x, y) of Exercise 31, compute R(100, 60) and R(60, 100). Interpret your results.

12.1 FUNCTIONS OF SEVERAL VARIABLES

33. REVENUE FUNCTIONS Weston Publishing publishes a deluxe edition and a standard edition of its English language dictionary. Weston’s management estimates that the number of deluxe editions demanded is x copies/day and the number of standard editions demanded is y copies/day when the unit prices are p  20  0.005x  0.001y q  15  0.001x  0.003y

dollars, respectively. a. Find the daily total revenue function R(x, y). b. Find the domain of the function R. 34. For the total revenue function R(x, y) of Exercise 33, compute R(300, 200) and R(200, 300). Interpret your results. 35. VOLUME OF A GAS The volume of a certain mass of gas is related to its pressure and temperature by the formula V

30.9T P

where the volume V is measured in liters, the temperature T is measured in degrees Kelvin (obtained by adding 273° to the Celsius temperature), and the pressure P is measured in millimeters of mercury pressure. a. Find the domain of the function V. b. Calculate the volume of the gas at standard temperature and pressure—that is, when T  273 K and P  760 mm of mercury. 36. SURFACE AREA OF A HUMAN BODY An empirical formula by E. F. Dubois relates the surface area S of a human body (in square meters) to its weight W (in kilograms) and its height H (in centimeters). The formula, given by S  0.007184W 0.425H 0.725

is used by physiologists in metabolism studies. a. Find the domain of the function S. b. What is the surface area of a human body that weighs 70 kg and has a height of 178 cm? 37. PRODUCTION FUNCTION Suppose the output of a certain country is given by f(x, y)  100x 3/5y 2/5

billion dollars if x billion dollars are spent for labor and y billion dollars are spent on capital. Find the output if the country spent $32 billion on labor and $243 billion on capital. 38. PRODUCTION FUNCTION Economists have found that the output of a finished product, f(x, y), is sometimes described by the function f(x, y)  ax by1b

where x stands for the amount of money expended for labor, y stands for the amount expended on capital, and a and b are positive constants with 0 b 1. a. If p is a positive number, show that f ( px, py)  pf( x, y). b. Use the result of part (a) to show that if the amount of money expended for labor and capital are both increased by r%, then the output is also increased by r%.

835

39. ARSON FOR PROFIT A study of arson for profit was conducted by a team of paid civilian experts and police detectives appointed by the mayor of a large city. It was found that the number of suspicious fires in that city in 2006 was very closely related to the concentration of tenants in the city’s public housing and to the level of reinvestment in the area in conventional mortgages by the ten largest banks. In fact, the number of fires was closely approximated by the formula N 1x, y 2 

10011000  0.03x 2y 2 1/2 15  0.2y 2 2

(0 x 150; 5 y 35)

where x denotes the number of persons/census tract and y denotes the level of reinvestment in the area in cents/dollar deposited. Using this formula, estimate the total number of suspicious fires in the districts of the city where the concentration of public housing tenants was 100/census tract and the level of reinvestment was 20 cents/dollar deposited. 40. CONTINUOUSLY COMPOUNDED INTEREST If a principal of P dollars is deposited in an account earning interest at the rate of r/year compounded continuously, then the accumulated amount at the end of t yr is given by A  f(P, r, t)  Pe rt

dollars. Find the accumulated amount at the end of 3 yr if a sum of $10,000 is deposited in an account earning interest at the rate of 6%/year. 41. HOME MORTGAGES The monthly payment that amortizes a loan of A dollars in t yr when the interest rate is r per year, compounded monthly, is given by P  f 1A, r, t2 

Ar 123 1  11  12r 2 12t 4

a. What is the monthly payment for a home mortgage of $300,000 that will be amortized over 30 yr with an interest rate of 6%/year? An interest rate of 8%/year? b. Find the monthly payment for a home mortgage of $300,000 that will be amortized over 20 yr with an interest rate of 8%/year. 42. HOME MORTGAGES Suppose a home buyer secures a bank loan of A dollars to purchase a house. If the interest rate charged is r/year and the loan is to be amortized in t yr, then the principal repayment at the end of i mo is given by B  f 1A, r, t, i2  Ac

11  12r 2 i  1

11  12r 2 12t  1

d

10 i 12t2

Suppose the Blakelys borrow a sum of $280,000 from a bank to help finance the purchase of a house and the bank charges interest at a rate of 6%/year. If the Blakelys agree to repay the loan in equal installments over 30 yr, how much will they owe the bank after the 60th payment (5 yr)? The 240th payment (20 yr)?

836

12 CALCULUS OF SEVERAL VARIABLES

43. FORCE GENERATED BY A CENTRIFUGE A centrifuge is a machine designed for the specific purpose of subjecting materials to a sustained centrifugal force. The actual amount of centrifugal force, F, expressed in dynes (1 gram of force  980 dynes) is given by F  f 1M, S, R2 

p S MR 900 2 2

where S is in revolutions per minute (rpm), M is in grams, and R is in centimeters. Show that an object revolving at the rate of 600 rpm in a circle with radius of 10 cm generates a centrifugal force that is approximately 40 times gravity. 44. WILSON LOT-SIZE FORMULA The Wilson lot-size formula in economics states that the optimal quantity Q of goods for a store to order is given by Q  f 1C, N, h2 

2 CN B h

where C is the cost of placing an order, N is the number of items the store sells per week, and h is the weekly holding cost for each item. Find the most economical quantity of 10-speed bicycles to order if it costs the store $20 to place an order, $5 to hold a bicycle for a week, and the store expects to sell 40 bicycles a week. 45. IDEAL GAS LAW According to the ideal gas law, the volume V of an ideal gas is related to its pressure P and temperature T by the formula V

kT P

where k is a positive constant. Describe the level curves of V and give a physical interpretation of your result. 46. INTERNATIONAL AMERICA’S CUP CLASS Drafted by an international committee in 1989, the rules for the new International America’s Cup Class (IACC) include a formula that governs the basic yacht dimensions. The formula

where f 1L, S, D 2 

L  1.25S 1/2  9.80D1/3 0.388

balances the rated length L (in meters), the rated sail area S (in square meters), and the displacement D (in cubic meters). All changes in the basic dimensions are trade-offs. For example, if you want to pick up speed by increasing the sail area, you must pay for it by decreasing the length or increasing the displacement, both of which slow down the boat. Show that yacht A of rated length 20.95 m, rated sail area 277.3 m2, and displacement 17.56 m3 and the longer and heavier yacht B with L  21.87, S  311.78, and D  22.48 both satisfy the formula. In Exercises 47–52, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

47. If h is a function of x and y, then there are functions f and t of one variable such that h(x, y)  f(x)  t(y)

48. If f is a function of x and y and a is a real number, then f(ax, ay)  af(x, y)

49. The domain of f(x, y)  1/(x 2  y 2) is {(x, y)y  x}. 50. Every point on the level curve f(x, y)  c corresponds to a point on the graph of f that is c units above the xy-plane if c  0 and  c units below the xy-plane if c 0. 51. f is a function of x and y if and only if for any two points P1(x1, y1) and P2(x2, y2) in the domain of f, f(x1, y1)  f(x2, y2) implies that P1(x1, y1)  P2(x2, y2). 52. The level curves of a function f of two variables, f(x, y)  k, exist for all values of k.

f(L, S, D) 42

12.1 Solutions to Self-Check Exercises 1. f 11, 3 2  12  3112 13 2  11  3  6 f 11, 1 2  112 2  3112 11 2  11  1  4 The point (1, 0) is not in the domain of f because the term 1x  y is not defined when x  1 and y  0. In fact, the domain of f consists of all real values of x and y that satisfy the inequality x  y  0, the shaded half-plane shown in the accompanying figure.

y 10 5

–10

–5

5 –5 –10

10

x

12.2 PARTIAL DERIVATIVES

2. Since division by zero is not permitted, we see that x  0 and x  y  0. Therefore, the domain of f is the set of all points in the xy-plane not containing the y-axis (x  0) and the straight line x  y.

or approximately $341,926. If the agency spends $4000/month on newspaper ads and $16,000/month on television ads, then its monthly revenue will be given by f(4000, 16,000)  30(4000)1/4(16,000)3/4

3. If Odyssey spends $5000/month on newspaper ads (x  5000) and $15,000/month on television ads ( y  15,000), then its monthly revenue will be given by f(5000, 15,000)  30(5000) (15,000) 1/4

837

 339,411.26

or approximately $339,411.

3/4

 341,926.06

12.2 Partial Derivatives Partial Derivatives z

For a function f(x) of one variable x, there is no ambiguity when we speak about the rate of change of f(x) with respect to x since x must be constrained to move along the x-axis. The situation becomes more complicated, however, when we study the rate of change of a function of two or more variables. For example, the domain D of a function of two variables f(x, y) is a subset of the plane (Figure 12), so if P(a, b) is any point in the domain of f, there are infinitely many directions from which one can approach the point P. We may therefore ask for the rate of change of f at P along any of these directions. However, we will not deal with this general problem. Instead, we will restrict ourselves to studying the rate of change of the function f(x, y) at a point P(a, b) in each of two preferred directions—namely, the direction parallel to the x-axis and the direction parallel to the y-axis. Let y  b, where b is a constant, so that f(x, b) is a function of the one variable x. Since the equation z  f(x, y) is the equation of a surface, the equation z  f(x, b) is the equation of the curve C on the surface formed by the intersection of the surface and the plane y  b (Figure 13). Because f(x, b) is a function of one variable x, we may compute the derivative of f with respect to x at x  a. This derivative, obtained by keeping the variable y fixed and differentiating the resulting function f(x, b) with respect to x, is called the first partial derivative of f with respect to x at (a, b), written

(a, b, f (a, b)) y

P(a, b)

x FIGURE 12

We can approach a point in the plane from infinitely many directions.

z y =b

T

0z 1a, b2 0x

C P(a, b, f (a, b)) y (a, b)

Thus,

or

0f 1a, b2 0x

or fx 1a, b2

f 1a  h, b2  f 1a, b2 0f 0z 1a, b2  1a, b2  fx 1a, b2  lim 0x 0x hS0 h

x FIGURE 13 The curve C is formed by the intersection of the plane y  b with the surface z  f(x, y).

provided that the limit exists. The first partial derivative of f with respect to x at (a, b) measures both the slope of the tangent line T to the curve C and the rate of change of the function f in the x-direction when x  a and y  b. We also write 0f `  fx 1a, b2 0x 1a, b2 Similarly, we define the first partial derivative of f with respect to y at (a, b), written 0z 1a, b2 0y

or

0f 1a, b2 0y

or fy 1a, b2

838

12 CALCULUS OF SEVERAL VARIABLES z

as the derivative obtained by keeping the variable x fixed and differentiating the resulting function f(a, y) with respect to y. That is,

x=a T

0f 0z 1a, b2  1a, b2  fy 1a, b2 0y 0y f 1a, b  k2  f 1a, b2  lim kS0 k

P(a, b, f (a, b))

C

x FIGURE 14

y

(a, b)

The first partial derivative of f with respect to y at (a, b) measures the slope of the tangent line T to the curve C with x held constant.

if the limit exists. The first partial derivative of f with respect to y at (a, b) measures both the slope of the tangent line T to the curve C, obtained by holding x constant (Figure 14), and the rate of change of the function f in the y-direction when x  a and y  b. We write 0f `  fy 1a, b2 0y 1a, b2 Before looking at some examples, let’s summarize these definitions.

First Partial Derivatives of f(x, y)

Suppose f(x, y) is a function of the two variables x and y. Then, the first partial derivative of f with respect to x at the point (x, y) is f 1x  h, y2  f 1x, y2 0f  lim 0x hS0 h

provided the limit exists. The first partial derivative of f with respect to y at the point (x, y) is f 1x, y  k2  f 1x, y2 0f  lim 0y kS0 k provided the limit exists. EXAMPLE 1 Find the partial derivatives

0f 0f and of the function 0x 0y

f(x, y)  x 2  xy 2  y 3

What is the rate of change of the function f in the x-direction at the point (1, 2)? What is the rate of change of the function f in the y-direction at the point (1, 2)? 0f To compute , think of the variable y as a constant and differentiate 0x the resulting function of x with respect to x. Let’s write Solution

f(x, y)  x 2  xy 2  y 3

where the variable y to be treated as a constant is shown in color. Then, 0f  2x  y 2 0x

0f To compute , think of the variable x as being fixed—that is, as a constant—and 0y differentiate the resulting function of y with respect to y. In this case, f(x, y)  x 2  xy 2  y 3

so that 0f  2xy  3y 2 0y

12.2 PARTIAL DERIVATIVES

839

The rate of change of the function f in the x-direction at the point (1, 2) is given by fx 11, 22 

0f `  2112  2 2  2 0x 11, 22

That is, f decreases 2 units for each unit increase in the x-direction, y being kept constant ( y  2). The rate of change of the function f in the y-direction at the point (1, 2) is given by 0f fy 11, 22  `  2112 122  3122 2  8 0y 11, 22 That is, f increases 8 units for each unit increase in the y-direction, x being kept constant (x  1).

Explore & Discuss Refer to the Explore & Discuss on page 829. Suppose management has decided that the projected sales of the first product is a units. Describe how you might help management decide how many units of the second product the company should produce and sell in order to maximize the company’s total profit. Justify your method to management. Suppose, however, management feels that b units of the second product can be manufactured and sold. How would you help management decide how many units of the first product to manufacture in order to maximize the company’s total profit?

EXAMPLE 2 Compute the first partial derivatives of each function. a. f 1x, y2 

xy x  y2 2 2 c. h(u, √)  eu √

b. t(s, t)  (s 2  st  t 2)5

2

d. f (x, y)  ln(x 2  2y 2)

Solution

0f , think of the variable y as a constant. Thus, 0x xy f 1x, y2  2 x  y2 so that, upon using the quotient rule, we have

a. To compute

1x 2  y 2 2y  xy12x2 0f x 2y  y 3  2x 2y   2 2 2 0x 1x  y 2 1x 2  y 2 2 2 y 1 y2  x22  2 1x  y 2 2 2

0f upon simplification and factorization. To compute , think of the variable x 0y as a constant. Thus, xy f 1x, y2  2 x  y2 so that, upon using the quotient rule once again, we obtain 1x 2  y 2 2x  xy12y2 0f x 3  xy 2  2xy 2   2 2 2 0y 1x  y 2 1x 2  y 2 2 2 

x1x 2  y 2 2

1x 2  y 2 2 2

840

12 CALCULUS OF SEVERAL VARIABLES

b. To compute

0t 0s

, we treat the variable t as if it were a constant. Thus, t(s, t)  (s 2  st  t 2)5

Using the general power rule, we find 0t 0s

To compute

c. To compute

0t 0t

 5(s 2  st  t 2)4 # (2s  t)  5(2s  t)(s 2  st  t 2)4

, we treat the variable s as if it were a constant. Thus, t1s, t2  1s 2  st  t 2 2 5 0t  51s 2  st  t 2 2 4 1s  2t 2 0t  512t  s2 1s 2  st  t 2 2 4

0h , think of the variable √ as a constant. Thus, 0u 2 2 h(u, √)  e u √

Using the chain rule for exponential functions, we have 0h 2 2 2 2  e u √ # 2u  2ue u √ 0u

Next, we treat the variable u as if it were a constant, h(u, √)  eu

2√ 2

and we obtain 0h 2 2 2 2  e u √ # 12√2  2√eu √ 0√

d. To compute

0f , think of the variable y as a constant. Thus, 0x f(x, y)  ln(x 2  2y 2)

so that the chain rule for logarithmic functions gives 0f 2x  2 0x x  2y 2

Next, treating the variable x as if it were a constant, we find f 1x, y 2  ln 1x 2  2y 2 2 0f 4y  2 0y x  2y 2

To compute the partial derivative of a function of several variables with respect to one variable—say, x—we think of the other variables as if they were constants and differentiate the resulting function with respect to x.

Explore & Discuss 1. Let (a, b) be a point in the domain of f (x, y). Put t(x)  f (x, b) and suppose t is differentiable at x  a. Explain why you can find fx (a, b) by computing t(a). How would you go about calculating fy (a, b) using a similar technique? Give a geometric interpretation of these processes. 2. Let f (x, y)  x 2 y 3  3x 2 y  2. Use the method of Problem 1 to find fx (1, 2) and fy (1, 2).

12.2 PARTIAL DERIVATIVES

841

EXAMPLE 3 Compute the first partial derivatives of the function w  f (x, y, z)  xyz  xe yz  x ln y

Here we have a function of three variables, x, y, and z, and we are required to compute

Solution

0f , 0x

0f , 0y

0f 0z

To compute fx , we think of the other two variables, y and z, as fixed, and we differentiate the resulting function of x with respect to x, thereby obtaining fx  yz  e yz  ln y

To compute fy , we think of the other two variables, x and z, as constants, and we differentiate the resulting function of y with respect to y. We then obtain fy  xz  xze yz 

x y

Finally, to compute fz , we treat the variables x and y as constants and differentiate the function f with respect to z, obtaining fz  xy  xye yz

Exploring with

TECHNOLOGY Refer to the Explore & Discuss on page 840. Let f 1x, y2 

e 1xy 11  xy 2 2 3/2

1. Compute t(x)  f (x, 1) and use a graphing utility to plot the graph of t in the viewing window [0, 2]  [0, 2]. 2. Use the differentiation operation of your graphing utility to find t(1) and hence fx (1, 1). 3. Compute h(y)  f (1, y) and use a graphing utility to plot the graph of h in the viewing window [0, 2]  [0, 2]. 4. Use the differentiation operation of your graphing utility to find h(1) and hence fy (1, 1).

The Cobb–Douglas Production Function For an economic interpretation of the first partial derivatives of a function of two variables, let’s turn our attention to the function f(x, y)  ax by 1b

(1)

where a and b are positive constants with 0 b 1. This function is called the Cobb–Douglas production function. Here, x stands for the amount of money expended for labor, y stands for the cost of capital equipment (buildings, machinery, and other tools of production), and the function f measures the output of the finished product (in suitable units) and is called, accordingly, the production function. The partial derivative fx is called the marginal productivity of labor. It measures the rate of change of production with respect to the amount of money expended for labor, with the level of capital expenditure held constant. Similarly, the partial derivative fy , called the marginal productivity of capital, measures the rate of change of

842

12 CALCULUS OF SEVERAL VARIABLES

production with respect to the amount expended on capital, with the level of labor expenditure held fixed. APPLIED EXAMPLE 4 Marginal Productivity A certain country’s production in the early years following World War II is described by the function f(x, y)  30x 2/3 y 1/3 units, when x units of labor and y units of capital were used. a. Compute fx and fy. b. What is the marginal productivity of labor and the marginal productivity of capital when the amounts expended on labor and capital are 125 units and 27 units, respectively? c. Should the government have encouraged capital investment rather than increasing expenditure on labor to increase the country’s productivity? Solution

a. fx  30 #

y 1/3 2 1/3 1/3 x y  20 a b x 3 1 x 2/3 fy  30x 2/3 # y 2/3  10 a b y 3 b. The required marginal productivity of labor is given by fx 1125, 272  20 a

27 1/3 3 b  20 a b 125 5

or 12 units per unit increase in labor expenditure (capital expenditure is held constant at 27 units). The required marginal productivity of capital is given by fy 1125, 272  10 a

125 2/3 25 b  10 a b 27 9

or 2779 units per unit increase in capital expenditure (labor outlay is held constant at 125 units). c. From the results of part (b), we see that a unit increase in capital expenditure resulted in a much faster increase in productivity than a unit increase in labor expenditure would have. Therefore, the government should have encouraged increased spending on capital rather than on labor during the early years of reconstruction.

Substitute and Complementary Commodities For another application of the first partial derivatives of a function of two variables in the field of economics, let’s consider the relative demands of two commodities. We say that the two commodities are substitute (competitive) commodities if a decrease in the demand for one results in an increase in the demand for the other. Examples of substitute commodities are coffee and tea. Conversely, two commodities are referred to as complementary commodities if a decrease in the demand for one results in a decrease in the demand for the other as well. Examples of complementary commodities are automobiles and tires. We now derive a criterion for determining whether two commodities A and B are substitute or complementary. Suppose the demand equations that relate the quantities demanded, x and y, to the unit prices, p and q, of the two commodities are given by x  f ( p, q) and

y  t( p, q)

12.2 PARTIAL DERIVATIVES

843

Let’s consider the partial derivative f/p. Since f is the demand function for commodity A, we see that, for fixed q, f is typically a decreasing function of p—that is, f/p 0. Now, if the two commodities were substitute commodities, then the quantity demanded of commodity B would increase with respect to p—that is, t /p  0. A similar argument with p fixed shows that if A and B are substitute commodities, then f/q  0. Thus, the two commodities A and B are substitute commodities if 0f  0 and 0q

0t 0p

0

Similarly, A and B are complementary commodities if 0f 0 and 0q

0t 0p

0

Substitute and Complementary Commodities

Two commodities A and B are substitute commodities if 0f 0 0q

and

0t 0p

0

(2)

Two commodities A and B are complementary commodities if 0f 0 0q

and

0t 0p

0

(3)

APPLIED EXAMPLE 5 Substitute and Complementary Commodities Suppose that the daily demand for butter is given by x  f 1 p, q2 

3q 1  p2

and the daily demand for margarine is given by y  t1 p, q2 

1 p  0, q  02

2p 1  1q

where p and q denote the prices per pound (in dollars) of butter and margarine, respectively, and x and y are measured in millions of pounds. Determine whether these two commodities are substitute, complementary, or neither. Solution

We compute 0f 3  0q 1  p2

0t

and

0p

0f  0 and 0q

0t



2 1  1q

Since 0p

0

for all values of p  0 and q  0, we conclude that butter and margarine are substitute commodities.

Second-Order Partial Derivatives The first partial derivatives fx (x, y) and fy (x, y) of a function f (x, y) of the two variables x and y are also functions of x and y. As such, we may differentiate each of the

844

12 CALCULUS OF SEVERAL VARIABLES

functions fx and fy to obtain the second-order partial derivatives of f (Figure 15). Thus, differentiating the function fx with respect to x leads to the second partial derivative fxx 

∂ ∂x

∂ ∂x

∂f ∂x

∂ ∂y

f ∂ ∂y

FIGURE 15

0 2f 0 1f 2 2  0x 0x x ∂ ∂f ∂ 2f = 2 ∂x ∂x ∂x ∂ ∂f ∂ 2f = ∂y ∂x ∂y∂x ∂ ∂x

∂f ∂y ∂ ∂y

A schematic showing the four secondorder partial derivatives of f

) ) ) )

∂ 2f ∂ ∂f = ∂x ∂y ∂x∂y ∂ ∂f ∂ 2f = 2 ∂y ∂y ∂y

However, differentiation of fx with respect to y leads to the second partial derivative fxy 

0 2f 0  1f 2 0y0x 0y x

Similarly, differentiation of the function fy with respect to x and with respect to y leads to fyx 

0 2f 0  1f 2 0x0y 0x y

fyy 

0 2f 0  1f 2 0y 2 0y y

respectively. Note that, in general, it is not true that fxy  fyx , but they are equal if both fxy and fyx are continuous. We might add that this is the case in most practical applications. EXAMPLE 6 Find the second-order partial derivatives of the function f(x, y)  x 3  3x 2y  3xy 2  y 2 Solution

The first partial derivatives of f are 0 3 1x  3x 2y  3xy 2  y 2 2 0x  3x 2  6xy  3y 2 0 3 fy  1x  3x 2y  3xy 2  y 2 2 0y  3x 2  6xy  2y fx 

Therefore, 0 0 1f 2  13x 2  6xy  3y 2 2 0x x 0x  6x  6y  6 1x  y2 0 0 1f 2  13x 2  6xy  3y 2 2 fxy  0y x 0y

fxx 

 6x  6y  6 1 y  x2

12.2 PARTIAL DERIVATIVES

845

0 0 1 fy 2  13x 2  6xy  2y2 0x 0x  6x  6y  6 1 y  x2 0 0 fyy  1 fy 2  13x 2  6xy  2y2 0y 0y  6x  2

fyx 

EXAMPLE 7 Find the second-order partial derivatives of the function f(x, y)  e xy Solution

2

We have 0 xy 2 1e 2 0x 2  y 2e xy 0 xy 2 fy  1e 2 0y 2  2xye xy fx 

so the required second-order partial derivatives of f are 0 0 2 1 fx 2  1 y 2e xy 2 0x 0x 4 xy 2 y e 0 0 2 fxy  1 fx 2  1 y 2e xy 2 0y 0y 2 xy 2  2ye  2xy 3e xy 2  2ye xy 11  xy 2 2 0 0 2 fyx  1 fy 2  12xye xy 2 0x 0x 2 2  2ye xy  2xy 3e xy 2  2ye xy 11  xy 2 2 0 0 2 fyy  1 fy 2  12xye xy 2 0y 0y 2 2  2xe xy  12xy 2 12xy 2e xy 2  2xe xy 11  2xy 2 2 fxx 

12.2 Self-Check Exercises 1. Compute the first partial derivatives of f (x, y)  x 3  2xy 2  y 2  8. 2. Find the first partial derivatives of f (x, y)  x ln y  ye x  x 2 at (0, 1) and interpret your results. 3. Find the second-order partial derivatives of the function of Self-Check Exercise 1. 4. A certain country’s production is described by the function f (x, y)  60x 1/3y 2/3

when x units of labor and y units of capital are used. a. What is the marginal productivity of labor and the marginal productivity of capital when the amounts expended on labor and capital are 125 units and 8 units, respectively? b. Should the government encourage capital investment rather than increased expenditure on labor at this time in order to increase the country’s productivity? Solutions to Self-Check Exercises 12.2 can be found on page 848.

846

12 CALCULUS OF SEVERAL VARIABLES

12.2 Concept Questions 1. a. What is the partial derivative of f (x, y) with respect to x at (a, b)? b. Give a geometric interpretation of fx(a, b) and a physical interpretation of fx(a, b). 2. a. What are substitute commodities and complementary commodities? Give an example of each.

b. Suppose x  f ( p, q) and y  t(p, q) are demand functions for two commodities A and B, respectively. Give conditions for determining whether A and B are substitute or complementary commodities. 3. List all second-order partial derivatives of f.

12.2 Exercises 1. Let f(x, y)  x 2  2y 2. a. Find f x (2, 1) and f y (2, 1). b. Interpret the numbers in part (a) as slopes. c. Interpret the numbers in part (a) as rates of change. 2. Let f (x, y)  9  x 2  xy  2y 2. a. Find f x (1, 2) and f y (1, 2). b. Interpret the numbers in part (a) as slopes. c. Interpret the numbers in part (a) as rates of change. In Exercises 3–24, find the first partial derivatives of the function.

3. f (x, y)  2x  3y  5

4. f (x, y)  2xy

5. t(x, y)  2x 2  4y  1

6. f (x, y)  1  x 2  y 2

2y 7. f 1x, y 2  2 x

x 8. f 1x, y2  1y

9. t 1u, √ 2 

u√ u√

10. f 1x, y2 

13. f (x, y)  (x 2  y 2)2/3

14. f 1x, y2  x 21  y 2

15. f(x, y)  e

16. f (x, y)  (e  e )

17. f (x, y)  x ln y  y ln x 18. f 1x, y 2  x 2e y 19. t(u, √)  eu ln √

20. f 1x, y2 

y 5

2

e xy xy

21. f (x, y, z)  xyz  xy 2  yz 2  zx 2 2u√w 22. t 1u, √, w2  2 u  √2  w2 23. h(r, s, t)  erst

24. f (x, y, z)  xe y/z

In Exercises 25–34, evaluate the first partial derivatives of the function at the given point.

25. f (x, y)  x 2 y  xy 2; (1, 2) 26. f(x, y)  x 2  xy  y 2  2x  y; (1, 2) 27. f 1x, y 2  x 1y  y 2; 12, 12

28. t 1x, y 2  2x 2  y 2; 13, 4 2

xy ; 11, 22 xy

31. f(x, y)  e xy; (1, 1) 32. f(x, y)  e x ln y; (0, e) 33. f(x, y, z)  x 2 yz 3; (1, 0, 2) 34. f(x, y, z)  x 2 y 2  z 2; (1, 1, 2) In Exercises 35–42, find the second-order partial derivatives of the function. In each case, show that the mixed partial derivatives fxy and fyx are equal.

36. f(x, y)  x 3  x 2 y  x  4

x2  y2 x2  y2

x

30. f 1x, y2 

35. f(x, y)  x 2 y  xy 3

11. f (s, t)  (s 2  st  t 2)3 12. t(s, t)  s 2t  st 3

xy1

x 29. f 1x, y2  ; 11, 22 y

37. f(x, y)  x 2  2xy  2y 2  x  2y 38. f(x, y)  x 3  x 2 y 2  y 3  x  y

39. f 1x, y2  2x 2  y 2

40. f 1x, y2  x1y  y1x 41. f(x, y)  ex/y 42. f(x, y)  ln(1  x 2 y 2) 43. PRODUCTIVITY OF A COUNTRY The productivity of a South American country is given by the function f(x, y)  20x 3/4 y 1/4 when x units of labor and y units of capital are used. a. What is the marginal productivity of labor and the marginal productivity of capital when the amounts expended on labor and capital are 256 units and 16 units, respectively? b. Should the government encourage capital investment rather than increased expenditure on labor at this time in order to increase the country’s productivity? 44. PRODUCTIVITY OF A COUNTRY The productivity of a country in Western Europe is given by the function f(x, y)  40x 4/5y 1/5 when x units of labor and y units of capital are used.

12.2 PARTIAL DERIVATIVES

a. What is the marginal productivity of labor and the marginal productivity of capital when the amounts expended on labor and capital are 32 units and 243 units, respectively? b. Should the government encourage capital investment rather than increased expenditure on labor at this time in order to increase the country’s productivity? 45. LAND PRICES The rectangular region R shown in the following figure represents a city’s financial district. The price of land within the district is approximated by the function 1 2 p 1x, y2  200  10 a x  b  151 y  12 2 2

where p(x, y) is the price of land at the point (x, y) in dollars per square foot and x and y are measured in miles. Compute 0p 10, 1 2 0x

and

0p 10, 1 2 0y

y  t( p, q)  50,000  4000q  10p where p and q denote the unit prices, respectively, and x and y denote the number of VCRs and the number of blank VCR tapes demanded each week. Determine whether these two products are substitute, complementary, or neither. 48. COMPLEMENTARY AND SUBSTITUTE COMMODITIES Refer to Exercise 31, Exercises 12.1. Show that the finished and unfinished home furniture manufactured by Country Workshop are substitute commodities. Hint: Solve the system of equations for x and y in terms of p and q.

49. REVENUE FUNCTIONS The total weekly revenue (in dollars) of Country Workshop associated with manufacturing and selling their rolltop desks is given by the function R(x, y)  0.2x 2  0.25y 2  0.2xy  200x  160y where x denotes the number of finished units and y denotes the number of unfinished units manufactured and sold each week. Compute R/x and R/y when x  300 and y  250. Interpret your results.

and interpret your results. y (miles)

50. PROFIT FUNCTIONS The monthly profit (in dollars) of Bond and Barker Department Store depends on the level of inventory x (in thousands of dollars) and the floor space y (in thousands of square feet) available for display of the merchandise, as given by the equation

2

1

847

P(x, y)  0.02x 2  15y 2  xy  39x  25y  20,000

R

Compute P/x and P/y when x  4000 and y  150. Interpret your results. Repeat with x  5000 and y  150.

x (miles) 1

2

46. COMPLEMENTARY AND SUBSTITUTE COMMODITIES In a survey conducted by Home Entertainment magazine, it was determined that the demand equation for VCRs is given by x  f( p, q)  10,000  10p  0.2q 2 and the demand equation for DVD players is given by y  t( p, q)  5000  0.8p 2  20q where p and q denote the unit prices (in dollars) for the VCRs and DVD players, respectively, and x and y denote the number of VCRs and DVD players demanded per week. Determine whether these two products are substitute, complementary, or neither. 47. COMPLEMENTARY AND SUBSTITUTE COMMODITIES In a survey it was determined that the demand equation for VCRs is given by x  f( p, q)  10,000  10p  e

0.5q

The demand equation for blank VCR tapes is given by

51. WIND CHILL FACTOR A formula used by meteorologists to calculate the wind chill temperature (the temperature that you feel in still air that is the same as the actual temperature when the presence of wind is taken into consideration) is T  f(t, s)  35.74  0.6215t  35.75s 0.16  0.4275ts0.16 (s  1) where t is the actual air temperature in degrees Fahrenheit and s is the wind speed in mph. a. What is the wind chill temperature when the actual air temperature is 32°F and the wind speed is 20 mph? b. If the temperature is 32°F, by how much approximately will the wind chill temperature change if the wind speed increases from 20 mph to 21 mph? 52. ENGINE EFFICIENCY The efficiency of an internal combustion engine is given by E  a1 

√ 0.4 b V

where V and √ are the respective maximum and minimum volumes of air in each cylinder. a. Show that E/V  0 and interpret your result. b. Show that E/√ 0 and interpret your result.

848

12 CALCULUS OF SEVERAL VARIABLES

53. VOLUME OF A GAS The volume V (in liters) of a certain mass of gas is related to its pressure P (in millimeters of mercury) and its temperature T (in degrees Kelvin) by the law V

30.9T P

where k is a constant. Show that 0V # 0T # 0P  1 0T 0P 0V

56. KINETIC ENERGY OF A BODY The kinetic energy K of a body of mass m and velocity √ is given by

Compute V/T and V/P when T  300 and P  800. Interpret your results. 54. SURFACE AREA

OF A

HUMAN BODY The formula

S  0.007184W 0.425H 0.725 gives the surface area S of a human body (in square meters) in terms of its weight W (in kilograms) and its height H (in centimeters). Compute S/W and S/H when W  70 kg and H  180 cm. Interpret your results. 55. According to the ideal gas law, the volume V (in liters) of an ideal gas is related to its pressure P (in pascals) and temperature T (in degrees Kelvin) by the formula kT V P

K

Show that

1 m√ 2 2

0K 0 2K #  K. 0m 0√ 2

In Exercises 57–60, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

57. If fx (x, y) is defined at (a, b), then fy (x, y) must also be defined at (a, b). 58. If fx (a, b) 0, then f is decreasing with respect to x near (a, b). 59. If fxy (x, y) and fyx (x, y) are both continuous for all values of x and y, then fxy  fyx for all values of x and y. 60. If both f xy and fyx are defined at (a, b), then fxx and fyy must be defined at (a, b).

12.2 Solutions to Self-Check Exercises 0f  3x 2  2y 2 0x 0f  2x 12y 2  2y fy  0y  2y 11  2x2

1. fx 

x 2. fx  ln y  ye x  2x; fy   e x y In particular, fx 10, 1 2  ln 1  1e 0  210 2  1 0 fy 10, 1 2   e 0  1 1

The results tell us that at the point (0, 1), f(x, y) increases 1 unit for each unit increase in the x-direction, y being kept constant; f(x, y) also increases 1 unit for each unit increase in the y-direction, x being kept constant. 3. From the results of Self-Check Exercise 1, fx  3x 2  2y 2 Therefore, fxx 

0 13x 2  2y 2 2  6x 0x

0 fxy  13x 2  2y 2 2  4y 0y

Also, from the results of Self-Check Exercise 1, fy  2y(1  2x) Thus, fyx 

0 32y11  2x 2 4  4y 0x

fyy 

0 32y11  2x 2 4  211  2x 2 0y

4. a. The marginal productivity of labor when the amounts expended on labor and capital are x and y units, respectively, is given by y 2/3 1 fx 1x, y2  60 a x 2/3 b y 2/3  20 a b x 3

In particular, the required marginal productivity of labor is given by fx 1125, 8 2  20 a

8 2/3 4 b  20 a b 125 25

or 3.2 units/unit increase in labor expenditure, capital expenditure being held constant at 8 units. Next, we compute 2 x 1/3 fy 1x, y2  60x 1/3 a y 1/3 b  40 a b y 3

12.2 PARTIAL DERIVATIVES

and deduce that the required marginal productivity of capital is given by fy 1125, 82  40 a

125 1/3 5 b  40 a b 8 2

USING

849

or 100 units/unit increase in capital expenditure, labor expenditure being held constant at 125 units. b. The results of part (a) tell us that the government should encourage increased spending on capital rather than on labor.

Finding Partial Derivatives at a Given Point

TECHNOLOGY

Suppose f(x, y) is a function of two variables and we wish to compute fx 1a, b2 

0f ` 0x 1a, b2

Recall that in computing f /x, we think of y as being fixed. But in this situation, we are evaluating f /x at (a, b). Therefore, we set y equal to b. Doing this leads to the function t of one variable, x, defined by t(x)  f(x, b)

It follows from the definition of the partial derivative that fx (a, b)  t(a)

Thus, the value of the partial derivative f /x at a given point (a, b) can be found by evaluating the derivative of a function of one variable. In particular, the latter can be found by using the numerical derivative operation of a graphing utility. We find fy (a, b) in a similar manner. EXAMPLE 1 Let f (x, y)  (1  xy 2)3/2e x y. Find (a) fx (1, 2) and (b) fy (1, 2). 2

Solution

a. Define t(x)  f (x, 2)  (1  4x)3/2e2x . Using the numerical derivative operation to find t(1), we obtain 2

fx (1, 2)  t(1)  429.585835

b. Define h( y)  f (1, y)  (1  y 2)3/2e y. Using the numerical derivative operation to find h(2), we obtain fy (1, 2)  h(2)  181.7468642

TECHNOLOGY EXERCISES Compute the following at the given point: f x

and

f y

1. f 1x, y 2  1x12  xy 2 2 1/3; 11, 22

2. f 1x, y 2  1xy11  2xy 2 2/3; 11, 4 2 3. f 1x, y 2 

x  y2 ; 11, 2 2 1  x 2y

4. f 1x, y2 

xy 2

1 1x  1y2 2

; 14, 12

5. f(x, y)  exy (x  y)1/3; (1, 1) 2

6. f 1x, y2 

ln 1 1x  y 2 2 x2  y2

; 14, 12

850

12 CALCULUS OF SEVERAL VARIABLES

12.3 Maxima and Minima of Functions of Several Variables Maxima and Minima In Chapter 10, we saw that the solution of a problem often reduces to finding the extreme values of a function of one variable. In practice, however, situations also arise in which a problem is solved by finding the absolute maximum or absolute minimum value of a function of two or more variables. For example, suppose Scandi Company manufactures computer desks in both assembled and unassembled versions. Its profit P is therefore a function of the number of assembled units, x, and the number of unassembled units, y, manufactured and sold per week; that is, P  f(x, y). A question of paramount importance to the manufacturer is, How many assembled and unassembled desks should the company manufacture per week in order to maximize its weekly profit? Mathematically, the problem is solved by finding the values of x and y that will make f(x, y) a maximum. In this section we will focus our attention on finding the extrema of a function of two variables. As in the case of a function of one variable, we distinguish between the relative (or local) extrema and the absolute extrema of a function of two variables. Relative Extrema of a Function of Two Variables

Let f be a function defined on a region R containing the point (a, b). Then, f has a relative maximum at (a, b) if f (x, y) f(a, b) for all points (x, y) that are sufficiently close to (a, b). The number f(a, b) is called a relative maximum value. Similarly, f has a relative minimum at (a, b), with relative minimum value f(a, b) if f(x, y)  f(a, b) for all points (x, y) that are sufficiently close to (a, b). Loosely speaking, f has a relative maximum at (a, b) if the point (a, b, f(a, b)) is the highest point on the graph of f when compared with all nearby points. A similar interpretation holds for a relative minimum. If the inequalities in this last definition hold for all points (x, y) in the domain of f, then f has an absolute maximum (or absolute minimum) at (a, b) with absolute maximum value (or absolute minimum value) f(a, b). Figure 16 shows the graph of a function with relative maxima at (a, b) and (e, f ) and a relative minimum at (c, d). The absolute maximum of f occurs at (e, f ) and the absolute minimum of f occurs at (t, h). Observe that in the case of a function of one variable, a relative extremum (relative maximum or relative minimum) may or may not be an absolute extremum. z Absolute maximum (also a relative maximum) Relative maximum

y Relative minimum

(e, f)

(a, b) Absolute minimum FIGURE 16

x

D

(c, d)

(g, h)

Now let’s turn our attention to the study of relative extrema of a function. Suppose that a differentiable function f(x, y) of two variables has a relative maximum

12.3 MAXIMA AND MINIMA OF FUNCTIONS OF SEVERAL VARIABLES

851

(relative minimum) at a point (a, b) in the domain of f. From Figure 17 it is clear that at the point (a, b) the slope of the “tangent lines” to the surface in any direction must be zero. In particular, this implies that both 0f 1a, b2 0x

and

0f 1a, b2 0y

must be zero. z

z

(a, b, f (a, b)) ∂f ∂f (a, b) = 0 (a, b) = 0 ∂x ∂y

∂f (a, b) = 0 ∂y

y ∂f (a, b) = 0 ∂x

(a, b)

FIGURE 17

x x (a) f has a relative maximum at (a, b).

y (a, b, f (a, b)) (a, b)

(b) f has a relative minimum at (a, b).

Lest we are tempted to jump to the conclusion that a differentiable function f satisfying both the conditions 0f 1a, b2  0 0x

and

0f 1a, b2  0 0y

at a point (a, b) must have a relative extremum at the point (a, b), let’s examine the graph of the function f depicted in Figure 18. Here both 0f 1a, b2  0 0x

and

0f 1a, b2  0 0y

but f has neither a relative maximum nor a relative minimum at the point (a, b) because some nearby points are higher and some are lower than the point (a, b, f(a, b)). The point (a, b, f(a, b)) is called a saddle point. z

∂f (a, b) = 0 ∂y

(a, b, f (a, b))

y FIGURE 18 The point (a, b, f(a, b)) is called a saddle point.

x

∂f (a, b) = 0 ∂x (a, b)

852

12 CALCULUS OF SEVERAL VARIABLES

PORTFOLIO

Kirk Hoiberg

C

BRE is the world’s largest commercial real estate services firm. Large companies often have considerable real estate holdings and inevitably have to deal with everyday real estate activities as well as complex, high-stakes real estate decisions. However, most companies wish they could focus on their core business instead. That’s where we come in. The Global Corporate Services provides customized corporate real estate strategies and comprehensive corporate real estate outsourcing solutions to leading organizations worldwide. With over 40% of the Fortune 500 as clients, we deal with sophisticated businesses that demand rigorous analysis to support our recommendations and actions on their behalf. Doing this without regular use of quantitative and mathematical skills would be impossible.

For example, when a client needs to locate or acquire new facilities somewhere in the world, we use linear algebraic models to simultaneously optimize multivariable functions against a broad array of inputs and constraints drawn from labor markets, property markets, macroeconomics, the client’s supply chain, and many other areas. At the local level, we regularly model the real estate cycle in different cities. As you can see, the realm of real estate offers many opportunities for the use of applied mathematics. While it is not always readily apparent in college, these skills play a crucial role in the development of a successful business. In the future, the ability to understand and interpret the information generated by these techniques can be crucial to your own success.

© FAN travelstock/Alamy

TITLE Senior Managing Director, Global Corporate Services INSTITUTION CB Richard Ellis (CBRE)

Finally, an examination of the graph of the function f depicted in Figure 19 should convince you that f has a relative maximum at the point (a, b). But both f/x and f/y fail to be defined at (a, b). z

(a, b, f (a, b)) y FIGURE 19 f has a relative maximum at (a, b), but neither f/x nor f/y exist at (a, b).

(a, b) x

To summarize, a function f of two variables can only have a relative extremum at a point (a, b) in its domain where f/x and f/y both exist and are equal to zero at (a, b) or at least one of the partial derivatives does not exist. As in the case of one variable, we refer to a point in the domain of f that may give rise to a relative extremum as a critical point. The precise definition follows.

Critical Point of f

A critical point of f is a point (a, b) in the domain of f such that both 0f 1a, b2  0 0x

and

0f 1a, b2  0 0y

or at least one of the partial derivatives does not exist.

12.3 MAXIMA AND MINIMA OF FUNCTIONS OF SEVERAL VARIABLES

853

To determine the nature of a critical point of a function f(x, y) of two variables, we use the second partial derivatives of f. The resulting test, which helps us classify these points, is called the second derivative test and is incorporated in the following procedure for finding and classifying the relative extrema of f.

Determining Relative Extrema

1. Find the critical points of f(x, y) by solving the system of simultaneous equations fx  0 fy  0

2. The second derivative test: Let D(x, y)  fxx fyy  f 2xy

Then, a. D(a, b)  0 and fxx (a, b) 0 implies that f(x, y) has a relative maximum at the point (a, b). b. D(a, b)  0 and fxx (a, b)  0 implies that f(x, y) has a relative minimum at the point (a, b). c. D(a, b) 0 implies that f(x, y) has neither a relative maximum nor a relative minimum at the point (a, b). d. D(a, b)  0 implies that the test is inconclusive, so some other technique must be used to solve the problem.

EXAMPLE 1 Find the relative extrema of the function f(x, y)  x 2  y 2 Solution

We have fx  2x fy  2y

To find the critical point(s) of f, we set fx  0 and fy  0 and solve the resulting system of simultaneous equations

z

2x  0 2y  0

obtaining x  0, y  0, or (0, 0), as the sole critical point of f. Next, we apply the second derivative test to determine the nature of the critical point (0, 0). We compute fxx  2 y

fxy  0

fyy  2

and 2 D(x, y)  fxx fyy  f xy  (2)(2)  0  4

x FIGURE 20

The graph of f(x, y)  x 2  y 2

In particular, D(0, 0)  4. Since D(0, 0)  0 and fxx(0, 0)  2  0, we conclude that f (x, y) has a relative minimum at the point (0, 0). The relative minimum value, 0, also happens to be the absolute minimum of f. The graph of the function f, shown in Figure 20, confirms these results.

854

12 CALCULUS OF SEVERAL VARIABLES

EXAMPLE 2 Find the relative extrema of the function f(x, y)  3x 2  4xy  4y 2  4x  8y  4 Solution

We have fx  6x  4y  4 fy  4x  8y  8

To find the critical points of f, we set fx  0 and fy  0 and solve the resulting system of simultaneous equations 6x  4y  4 4x  8y  8

Multiplying the first equation by 2 and the second equation by 3, we obtain the equivalent system 12x  8y  08 12x  24y  24

Explore & Discuss Suppose f(x, y) has a relative extremum (relative maximum or relative minimum) at a point (a, b). Let t(x)  f(x, b) and h(y)  f(a, y). Assuming that f and t are differentiable, explain why t(a)  0 and h(b)  0. Explain why these results are equivalent to the conditions fx (a, b)  0 and fy (a, b)  0.

Adding the two equations gives 16y  16, or y  1. We substitute this value for y into either equation in the system to get x  0. Thus, the only critical point of f is the point (0, 1). Next, we apply the second derivative test to determine whether the point (0, 1) gives rise to a relative extremum of f. We compute fxx  6

fxy  4

fyy  8

and D(x, y)  fxx fyy  f 2xy  (6)(8)  (4)2  32

Since D(0, 1)  32  0 and fxx (0, 1)  6  0, we conclude that f (x, y) has a relative minimum at the point (0, 1). The value of f (x, y) at the point (0, 1) is given by f(0, 1)  3(0)2  4(0)(1)  4(1)2  4(0)  8(1)  4  0

EXAMPLE 3 Find the relative extrema of the function f(x, y)  4y 3  x 2  12y 2  36y  2 Solution

To find the critical points of f, we set fx  0 and fy  0 simultaneously,

obtaining fx  2x  0 fy  12y 2  24y  36  0

The first equation implies that x  0. The second equation implies that y 2  2y  3  0 ( y  1)(y  3)  0

—that is, y  1 or 3. Therefore, there are two critical points of the function f— namely, (0, 1) and (0, 3). Next, we apply the second derivative test to determine the nature of each of the two critical points. We compute fxx  2

fxy  0

fyy  24y  24  24(y  1)

Therefore, D(x, y)  fxx fyy  f 2xy  48( y  1)

For the point (0, 1), D(0, 1)  48(1  1)  96 0

12.3 MAXIMA AND MINIMA OF FUNCTIONS OF SEVERAL VARIABLES

Explore & Discuss 1. Refer to the second derivative test. Can the condition fxx (a, b) 0 in part 2a be replaced by the condition fyy (a, b) 0? Explain your answer. How about the condition fxx (a, b)  0 in part 2b? 2. Let f (x, y)  x 4  y 4. a. Show that (0, 0) is a critical point of f and that D(0, 0)  0. b. Explain why f has a relative (in fact, an absolute) minimum at (0, 0). Does this contradict the second derivative test? Explain your answer.

855

Since D(0, 1) 0, we conclude that the point (0, 1) gives a saddle point of f. For the point (0, 3), D(0, 3)  48(3  1)  96  0

Since D(0, 3)  0 and fxx (0, 3)  0, we conclude that the function f has a relative minimum at the point (0, 3). Furthermore, since f(0, 3)  4(3)3  (0)2  12(3)2  36(3)  2  106

we see that the relative minimum value of f is 106. As in the case of a practical optimization problem involving a function of one variable, the solution to an optimization problem involving a function of several variables calls for finding the absolute extremum of the function. Determining the absolute extremum of a function of several variables is more difficult than merely finding the relative extrema of the function. However, in many situations, the absolute extremum of a function actually coincides with the largest relative extremum of the function that occurs in the interior of its domain. We assume that the problems considered here belong to this category. Furthermore, the existence of the absolute extremum (solution) of a practical problem is often deduced from the geometric or physical nature of the problem. APPLIED EXAMPLE 4 Maximizing Profit The total weekly revenue (in dollars) that Acrosonic realizes in producing and selling its bookshelf loudspeaker systems is given by 3 1 1 R 1x, y2   x 2  y 2  xy  300x  240y 4 8 4

where x denotes the number of fully assembled units and y denotes the number of kits produced and sold each week. The total weekly cost attributable to the production of these loudspeakers is C(x, y)  180x  140y  5000

dollars, where x and y have the same meaning as before. Determine how many assembled units and how many kits Acrosonic should produce per week to maximize its profit. Solution The contribution to Acrosonic’s weekly profit stemming from the production and sale of the bookshelf loudspeaker systems is given by

P 1x, y 2  R 1x, y2  C 1x, y2 1 3 1  a  x 2  y 2  xy  300x  240y b  1180x  140y  50002 4 8 4 1 2 3 2 1   x  y  xy  120x  100y  5000 4 8 4

To find the relative maximum of the profit function P(x, y), we first locate the critical point(s) of P. Setting Px (x, y) and Py (x, y) equal to zero, we obtain 1 1 Px   x  y  120  0 2 4 3 1 Py   y  x  100  0 4 4

Solving the first of these equations for y yields y  2x  480

856

12 CALCULUS OF SEVERAL VARIABLES

which, upon substitution into the second equation, yields 3 1  12x  4802  x  100  0 4 4 6x  1440  x  400  0 x  208

We substitute this value of x into the equation y  2x  480 to get y  64

Therefore, the function P has the sole critical point (208, 64). To show that the point (208, 64) is a solution to our problem, we use the second derivative test. We compute Pxx  

1 2

Pxy  

1 4

Pyy  

3 4

So, 1 3 1 2 3 1 5 D 1x, y2  a  b a  b  a  b    2 4 4 8 16 16

In particular, D(208, 64)  5/16  0. Since D(208, 64)  0 and Pxx (208, 64) 0, the point (208, 64) yields a relative maximum of P. This relative maximum is also the absolute maximum of P. We conclude that Acrosonic can maximize its weekly profit by manufacturing 208 assembled units and 64 kits of their bookshelf loudspeaker systems. The maximum weekly profit realizable from the production and sale of these loudspeaker systems is given by 1 3 1 P 1208, 64 2   12082 2  1642 2  12082 1642 4 8 4  120 12082  100 1642  5000  10,680

or $10,680. APPLIED EXAMPLE 5 Locating a Television Relay Station Site A television relay station will serve towns A, B, and C, whose relative locations are shown in Figure 21. Determine a site for the location of the station if the sum of the squares of the distances from each town to the site is minimized.

y (miles) 40

A (30, 20)

20 B (– 20, 10) P(x, y)

x (miles) – 20

20 C(10, –10) –20

FIGURE 21 Locating a site for a television relay station

Solution Suppose the required site is located at the point P(x, y). With the aid of the distance formula, we find that the square of the distance from town A to the site is

(x  30)2  (y  20)2

d 2  (x 2  x 1)2  ( y 2  y 1)2

The respective distances from towns B and C to the site are found in a similar manner, so the sum of the squares of the distances from each town to the site is given by f(x, y)  (x  30)2  (y  20)2  (x  20)2  (y  10)2  (x  10)2  (y  10)2

To find the relative minimum of f(x, y), we first find the critical point(s) of f. Using the chain rule to find fx (x, y) and fy (x, y) and setting each equal to zero, we obtain fx  2(x  30)  2(x  20)  2(x  10)  6x  40  0 fy  2(y  20)  2(y  10)  2(y  10)  6y  40  0

12.3 MAXIMA AND MINIMA OF FUNCTIONS OF SEVERAL VARIABLES

857

from which we deduce that 1 203 , 203 2 is the sole critical point of f. Since fxx  6

fxy  0

fyy  6

we have D1x, y2  fxx fyy  f 2xy  162 162  0  36

Since D 1 203, 203 2  0 and fxx 1 203, 203 2  0, we conclude that the point 1 203, 203 2 yields a relative minimum of f. Thus, the required site has coordinates x  203 and y  203.

12.3 Self-Check Exercises 1. Let f(x, y)  2x 2  3y 2  4xy  4x  2y  3. a. Find the critical point of f. b. Use the second derivative test to classify the nature of the critical point. c. Find the relative extremum of f, if it exists. 2. Robertson Controls manufactures two basic models of setback thermostats: a standard mechanical thermostat and a deluxe electronic thermostat. Robertson’s monthly revenue (in hundreds of dollars) is 1 1 1 R 1x, y 2   x 2  y 2  xy  20x  60y 8 2 4

where x (in units of a hundred) denotes the number of mechanical thermostats manufactured and y (in units of a hundred) denotes the number of electronic thermostats manufactured each month. The total monthly cost incurred in producing these thermostats is C(x, y)  7x  20y  280 hundred dollars. Find how many thermostats of each model Robertson should manufacture each month in order to maximize its profits. What is the maximum profit? Solutions to Self-Check Exercises 12.3 can be found on page 859.

12.3 Concept Questions 1. Explain the terms (a) relative maximum of a function f(x, y) and (b) absolute maximum of a function f(x, y).

3. Explain how the second derivative test is used to determine the relative extrema of a function of two variables.

2. a. What is a critical point of a function f(x, y)? b. Explain the role of a critical point in determining the relative extrema of a function of two variables.

12.3 Exercises In Exercises 1–20, find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function.

1. f (x, y)  1  2x 2  3y 2 2. f (x, y)  x 2  xy  y 2  1 3. f (x, y)  x 2  y 2  2x  4y  1 4. f(x, y)  2x 2  y 2  4x  6y  3 5. f (x, y)  x 2  2xy  2y 2  4x  8y  1 6. f (x, y)  x 2  4xy  2y 2  4x  8y  1

9. f(x, y)  x 3  y2  2xy  7x  8y  4 10. f(x, y)  2y 3  3y2  12y  2x 2  6x  2 11. f(x, y)  x3  3xy  y3  2 12. f(x, y)  x3  2xy  y 2  5 13. f 1x, y2  xy 

4 2  x y

15. f(x, y)  x 2  e y 17. f(x, y)  e x

2

2y 2

7. f (x, y)  2x 3  y 2  9x 2  4y  12x  2

19. f(x, y)  ln(1  x 2  y 2)

8. f (x, y)  2x 3  y 2  6x 2  4y  12x  2

20. f(x, y)  xy  ln x  2y 2

14. f 1x, y2 

x  xy y2

16. f(x, y)  e x

2y 2

18. f(x, y)  e xy

858

12 CALCULUS OF SEVERAL VARIABLES

21. MAXIMIZING PROFIT The total weekly revenue (in dollars) of the Country Workshop realized in manufacturing and selling its rolltop desks is given by R(x, y)  0.2x 2  0.25y 2  0.2xy  200x  160y

where x denotes the number of finished units and y denotes the number of unfinished units manufactured and sold each week. The total weekly cost attributable to the manufacture of these desks is given by C(x, y)  100x  70y  4000 dollars. Determine how many finished units and how many unfinished units the company should manufacture each week in order to maximize its profit. What is the maximum profit realizable? 22. MAXIMIZING PROFIT The total daily revenue (in dollars) that Weston Publishing realizes in publishing and selling its English-language dictionaries is given by R(x, y)  0.005x 2  0.003y 2  0.002xy  20x  15y where x denotes the number of deluxe copies and y denotes the number of standard copies published and sold daily. The total daily cost of publishing these dictionaries is given by

where p(x, y) is the price of land at the point (x, y) in dollars/square foot and x and y are measured in miles. At what point within the financial district is the price of land highest? 24. MAXIMIZING PROFIT C&G Imports imports two brands of white wine, one from Germany and the other from Italy. The German wine costs $4/bottle, and the Italian wine costs $3/bottle. It has been estimated that if the German wine retails at p dollars/bottle and the Italian wine is sold for q dollars/bottle, then 2000  150p  100q bottles of the German wine and 1000  80p  120q bottles of the Italian wine will be sold each week. Determine the unit price for each brand that will allow C&G to realize the largest possible weekly profit. 25. DETERMINING THE OPTIMAL SITE An auxiliary electric power station will serve three communities, A, B, and C, whose relative locations are shown in the accompanying figure. Determine where the power station should be located if the sum of the squares of the distances from each community to the site is minimized.

C(x, y)  6x  3y  200

y (miles)

dollars. Determine how many deluxe copies and how many standard copies Weston should publish each day to maximize its profits. What is the maximum profit realizable?

B (– 4, 4)

A (5, 2)

23. MAXIMUM PRICE The rectangular region R shown in the accompanying figure represents the financial district of a city. The price of land within the district is approximated by the function p 1x, y2  200  10 a x 

1 2 b  151 y  1 2 2 2

y (miles)

x (miles)

C(–1, – 3)

26. PACKAGING An open rectangular box having a volume of 108 in.3 is to be constructed from a tin sheet. Find the dimensions of such a box if the amount of material used in its construction is to be minimal.

2

Hint: Let the dimensions of the box be x  by y  by z . Then, xyz  108 and the amount of material used is given by S  xy  2yz  2xz. Show that 1

R

S  f 1x, y2  xy 

216 216  x y

Minimize f (x, y).

1

2

x (miles)

27. PACKAGING An open rectangular box having a surface area of 300 in.2 is to be constructed from a tin sheet. Find the dimensions of the box if the volume of the box is to be as large as possible. What is the maximum volume?

12.3 MAXIMA AND MINIMA OF FUNCTIONS OF SEVERAL VARIABLES Hint: Let the dimensions of the box be x  y  z (see the figure that follows). Then the surface area is xy  2xz  2yz, and its volume is xyz.

z

859

30. PACKAGING An open box having a volume of 48 in.3 is to be constructed. If the box is to include a partition that is parallel to a side of the box, as shown in the figure, and the amount of material used is to be minimal, what should be the dimensions of the box? z

y x

28. PACKAGING Postal regulations specify that the combined length and girth of a parcel sent by parcel post may not exceed 130 in. Find the dimensions of the rectangular package that would have the greatest possible volume under these regulations. Hint: Let the dimensions of the box be x  by y  by z (see the figure below). Then, 2x  2z  y  130, and the volume V  xyz. Show that V  f (x, z)  130xz  2x 2z  2xz 2 Maximize f(x, z).

y

x

In Exercises 31–36, determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false.

31. If fx (a, b)  0 and fy (a, b)  0, then f must have a relative extremum at (a, b). 32. If (a, b) is a critical point of f and both the conditions fxx (a, b) 0 and fyy (a, b) 0 hold, then f has a relative maximum at (a, b).

z

33. If f(x, y) has a relative maximum at (a, b), then fx (a, b)  0 and fy (a, b)  0.

y x

29. MINIMIZING HEATING AND COOLING COSTS A building in the shape of a rectangular box is to have a volume of 12,000 ft3 (see the figure). It is estimated that the annual heating and cooling costs will be $2/square foot for the top, $4/square foot for the front and back, and $3/square foot for the sides. Find the dimensions of the building that will result in a minimal annual heating and cooling cost. What is the minimal annual heating and cooling cost? z

34. Let h(x, y)  f(x)  t(y). If f(x)  0 and t(y) 0, then h cannot have a relative maximum or a relative minimum at any point. 35. If f(x, y) satisfies fxx (a, b)  0, fxy(a, b)  0, fyy(a, b)  0, and fxx (a, b)  fyy(a, b)  0 at the critical point (a, b) of f, then f cannot have a relative extremum at (a, b). 36. Suppose h(x, y)  f(x)  t(y), where f and t have continuous second derivatives near a and b, respectively. If a is a critical number of f, b is a critical number of t, and f (a)t(b)  0, then h has a relative extremum at (a, b).

y x

12.3 Solutions to Self-Check Exercises 1. a. To find the critical point(s) of f, we solve the system of equations fx  4x  4y  4  0 fy  4x  6y  2  0 obtaining x  2 and y  1. Thus, the only critical point of f is the point (2, 1). b. We have fxx  4, fxy  4, and fyy  6, so

D(x, y)  fxx fyy  f 2xy  (4)(6)  (4)2  8 Since D(2, 1)  0 and fxx (2, 1)  0, we conclude that f has a relative minimum at the point (2, 1). c. The relative minimum value of f(x, y) at the point (2, 1) is f(2, 1)  2(2)2  3(1)2  4(2)(1)  4(2)  2(1)  3 0

860

12 CALCULUS OF SEVERAL VARIABLES

2. Robertson’s monthly profit is

and

P1x, y2  R1x, y 2  C1x, y 2

D 1x, y 2  Pxx Pyy  P 2xy

1 1 1  a x 2  y 2  xy  20x  60y b  17x  20y  2802 8 2 4 1 1 1   x 2  y 2  xy  13x  40y  280 8 2 4

The critical point of P is found by solving the system 1 1 Px   x  y  13  0 4 4

  13 1162  40 1362  280

giving x  16 and y  36. Thus, (16, 36) is the critical point of P. Next, 1 Pxy   4

Since D(16, 36)  0 and Pxx (16, 36) 0, the point (16, 36) yields a relative maximum of P. We conclude that the monthly profit is maximized by manufacturing 1600 mechanical and 3600 electronic setback thermostats each month. The maximum monthly profit realizable is 1 1 1 P 116, 362   1162 2  1362 2  1162 1362 8 2 4

1 Py   x  y  40  0 4

1 Pxx   4

3 1 2 1  a b 112  a b  4 4 16

 544

or $54,400.

Pyy  1

CHAPTER 12 Summary of Principal Terms TERMS function of two variables (828) domain (828) three-dimensional Cartesian coordinate system (830) level curve (831) first partial derivatives of f (838) Cobb–Douglas production function (841) marginal productivity of labor (841)

marginal productivity of capital (841) substitute commodity (842) complementary commodity (842) second-order partial derivative of f (844) relative maximum (850) relative maximum value (850) relative minimum (850) relative minimum value (850)

absolute maximum (850) absolute minimum (850) absolute maximum value (850) absolute minimum value (850) saddle point (851) critical point (852) second derivative test (853)

CHAPTER 12 Concept Review Questions Fill in the blanks.

1. The domain of a function f of two variables is a subset of the _____ -plane. The rule of f associates with each _____ _____ in the domain of f one and only one _____ _____ , denoted by z  _____ . 2. If the function f has rule z  f (x, y), then x and y are called _____ variables, and z is a/an _____ variable. The number z is also called the _____ of f. 3. The graph of a function f of two variables is the set of all points (x, y, z), where _____ , and (x, y) is the domain of _____ . The graph of a function of two variables is a/an _____ in three-dimensional space.

4. The trace of the graph of f(x, y) in the plane z  c is the curve with equation _____ lying in the plane z  c. The projection of the trace of f in the plane z  c onto the xy-plane is called the _____ _____ of f. The contour map associated with f is obtained by drawing the _____ _____ of f corresponding to several admissible values of _____ . 5. The partial derivative 0f/0x of f at (x, y) can be found by thinking of y as a/an _____ _____ in the expression for f, and differentiating this expression with respect to _____ as if it were a function of x alone. 6. The number fx(a, b) measures the _____ of the tangent line to the curve C obtained by the intersection of the graph of f and the plane y  b at the point _____ . It also measures the rate of change of f with respect to _____ at the point (a, b) with y held fixed with value _____ .

REVIEW EXERCISES

7. A function f (x, y) has a relative maximum at (a, b) if f(x, y) _____ f(a, b) for all points (x, y) that are sufficiently close to _____ . The absolute maximum value of f (x, y) is the number f (a, b) such that f (x, y) _____ f (a, b) for all (x, y) in the _____ of f.

861

8. A critical point of f (x, y) is a point (a, b) in the _____ of f such that _____ _____ _____ or at least one of the partial derivatives of f does not _____ . A critical point of f is a/an _____ for a relative extremum of f.

CHAPTER 12 Review Exercises 1. Let f 1x, y 2 

xy . Compute f(0, 1), f(1, 0), and f(1, 1). x2  y2 Does f(0, 0) exist?

2. Let f 1x, y 2 

xe y . Compute f (1, 1), f(1, 2), and 1  ln xy f(2, 1). Does f (1, 0) exist?

x 3. Let h 1x, y, z 2  xye z  . Compute h(1, 1, 0), h(1, 1, 1), y and h(1, 1, 1). 4. Find the domain of the function f 1u, √2 

1u . u√

5. Find the domain of the function f 1x, y2 

xy . xy

In Exercises 22–27, compute the second-order partial derivatives of the function.

22. f(x, y)  x 3  2x 2 y  y 2  x  2y 23. f(x, y)  x 4  2x 2 y 2  y 4 24. f(x, y)  (2x 2  3y 2)3 26. t(x, y)  e x

2y 2

25. t 1x, y2 

x x  y2 s 27. h 1s, t2  ln a b t

28. Let f(x, y, z)  x 3y 2z  xy 2z  3xy  4z. Compute fx (1, 1, 0), fy (1, 1, 0), and fz (1, 1, 0) and interpret your results.

6. Find the domain of the function f(x, y)  x 1y  y 11  x .

In Exercises 29–34, find the critical point(s) of the functions. Then use the second derivative test to classify the nature of each of these points, if possible. Finally, determine the relative extrema of each function.

7. Find the domain of the function

29. f(x, y)  2x 2  y 2  8x  6y  4

f 1x, y, z 2 

xy 1z 11  x2 11  y 2 11  z 2

In Exercises 8–11, sketch the level curves of the function corresponding to each value of z.

8. z  f (x, y)  2x  3y; z  2, 1, 0, 1, 2 9. z  f (x, y)  y  x 2; z  2, 1, 0, 1, 2

10. z  f 1x, y2  2x 2  y 2; z  0, 1, 2, 3, 4 11. z  f (x, y)  e xy; z  1, 2, 3 In Exercises 12–21, compute the first partial derivatives of the function.

12. f 1x, y 2  x 2y 3  3xy 2 

x y

13. f 1x, y 2  x 1y  y1x

14. f 1u, √ 2  2u√ 2  2u

15. f 1x, y 2 

xy y  2x

16. t 1x, y 2 

17. h(x, y)  (2xy  3y 2)5 19. f (x, y)  (x 2  y 2)e x

18. f (x, y)  (xe y  1)1/2

2y 2

20. f (x, y)  ln(1  2x 2  4y 4) x2 21. f 1x, y 2  ln a1  2 b y

xy x  y2 2

30. f(x, y)  x 2  3xy  y 2  10x  20y  12 31. f(x, y)  x 3  3xy  y 2 32. f(x, y)  x 3  y 2  4xy  17x  10y  8 33. f(x, y)  e2x

2y 2

34. f(x, y)  ln(x 2  y 2  2x  2y  4) 35. IQS The IQ (intelligence quotient) of a person whose chronological age is c and whose mental age is m is defined as I(c, m) 

100m c

Describe the level curves of I. Sketch the level curves corresponding to I  90, 100, 120, 180. Interpret your results. 36. REVENUE FUNCTIONS A division of Ditton Industries makes a 16-speed and a 10-speed electric blender. The company’s management estimates that x units of the 16-speed model and y units of the 10-speed model are demanded daily when the unit prices are p  80  0.02x  0.1y q  60  0.1x  0.05y dollars, respectively. a. Find the daily total revenue function R(x, y). b. Find the domain of the function R. c. Compute R(100, 300) and interpret your result.

862

12 CALCULUS OF SEVERAL VARIABLES

37. DEMAND FOR CD PLAYERS In a survey conducted by Home Entertainment magazine, it was determined that the demand equation for CD players is given by x  f ( p, q)  900  9p  e0.4q

whereas the demand equation for audio CDs is given by y  t( p, q)  20,000  3000q  4p

where p and q denote the unit prices (in dollars) for the CD players and audio CDs, respectively, and x and y denote the number of CD players and audio CDs demanded per week. Determine whether these two products are substitute, complementary, or neither. 38. MAXIMIZING REVENUE Odyssey Travel Agency’s monthly revenue depends on the amount of money x (in thousands of dollars) spent on advertising per month and the number of agents y in its employ in accordance with the rule

Determine the amount of money the agency should spend per month and the number of agents it should employ in order to maximize its monthly revenue. 39. MINIMIZING FENCING COSTS The owner of the Rancho Grande wants to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it using a fence running parallel to the sides. No fencing is required along the river. If the material for the sides costs $3/running yard and the material for the divider costs $2/running yard, what will be the dimensions of a 303,750 sq yd pasture if the cost of fencing is kept to a minimum? 40. COBB–DOUGLAS PRODUCTION FUNCTION Show that the Cobb–Douglas production function P  kxa y1a, where 0 a 1, satisfies the equation x

0P 0P y P 0x 0y

R(x, y)  x 2  0.5y 2  xy  8x  3y  20

CHAPTER 12 Before Moving On . . . 1. Find the domain of f 1x, y2 

1x  1y 11  x2 12  y 2

2. Sketch the level curves of the function f ( x, y)  x  2y 2 corresponding to z  3, 2, 1, 0, 1, 2, 3.

3. Find fx( 1, 2) and fy( 1, 2) if f( x, y)  x 3y 2x 2y2  3xy3 and interpret your results. 4. Find the first- and second-order partial derivatives of f(x, y)  x2y  e xy. 5. Find the relative extrema, if any, of f(x, y)  2x3  2y3  6xy  5.

863

ANSWERS TO CHAPTER 1 ODD -NUMBERED EXERCISES

Answers to Odd-Numbered Exercises

CHAPTER

1

Exercises 1.1, page 6 1. Integer, rational, and real 5. Irrational and real

3. Rational and real

11. False

41. u2(√ 2  2)(√ 4  2√ 2  4)

43. (2x  1)(x 2  3)

13. True

23. Associative law of addition

21. Distributive law

25. Property 1 of negatives

27. Property 1 of zero properties

33. Properties 2 and 5 of quotients

1.

21.

11. 243y

13. 6x  3

5

17. 4y  y  8

31. 6x 2  5xy  6y 2

35. 0.06x 2  0.06xy  2.52y 2 39. 4x  12xy  9y 43. 2x  x  2

45. 4x 2  6xy  9y 2  2y  x  2

2

41. 4u  √ 2

47. 2t 4  4t 3  9t 2  2t  4 53. x 2  10x  50

49. 2x  1

51. x  1

61. False

63. False

3. 3ab(3b  2a)

25.

65. m

5. 5mn(2m  3n  4)

9. (2c  d)(3a  b  4ac  2ad) 13. (x  3y)(x  2y)

17. (2a  b)(2a  b)

19. (u√  w)(u√  w)

25. (x  4)(x  1)

29. (7r  4)(5r  3) 33. (x 2  4y)(x 2  4y)

15. Prime 21. Prime

27. 2y(3x  2)(2x  3)

31. xy(3x  y)(3x  y) 35. 8ab

xy

43.

xy  1

37. yx

bx  ay

ab1x  y 2 45. 

x 2y 2

5. 16

1 49

3.

13. 1

43.

11. (2m  1)(m  6)

23. Prime

1. 8

1 32

15.

1

27.

a

6

35. 864x 4

Exercises 1.3, page 19

7. (3x  5)(2x  1)

1x  2 2 1x  2 2

1 2x1x  h 2

7.

7 12

9. 0.0004

11. 1

2

57. 0.000002x 3  0.02x 2  1000x  120,000

1. 2m(3m  1)

12m  2m  1 2 12m2  3m  3 2 2

21x 2  x  2 2

33.

x1 x1

41.

4m3  3

29.

39.

55. 22x 3  20x 2  6x

59. 3.5t 2  2.4t  71.2

x2  x  3 1x  1 2 1x  1 2

10x  7 12x  3 2 12x  1 2

25.

5x  9 1x  3 2 1x  2 2 1x  1 2

4 3

19.

Exercises 1.5, page 29

37. 6x3  3x 2y  4xy  2y2

2

2

k1 k2

x 3  2x 2  3x  24 1x  3 2 1x  2 2 1x  2 2 1x  1 2

25. 7m2  9m

33. 12r 2  rs  6s 2

23.

x2 2x  3

9.

5x 2

17.

35.

2

29. 6x 2  5x  6

k D  b 2 3

x1 x1

7.

15. 25 x 2

13. 12 x

2

31. 

15. 9x  3x  1 3

2x  1 2x

5.

313r  2 2

9. 256

2

23. 2x 3  4x

27. 14a  7b

54

7. 125

19. 1.2x  4.2x  2.5x  8.2

2

21. 6x 5

27.

5. 64

3. 27

4 3

3.

41. False

8

1. 81

4 x

11. x  y

37. False

Exercises 1.2, page 13

57. D 2 a

55. P(1  rt)

Exercises 1.4, page 24

29. Property 2 of zero properties

35. Property 6 of quotients and distributive law

51. (x3  2)(x  3)

15. False 53. (au  c)(u  1)

19. Commutative law of multiplication

39. False

47. (u  √)(u  √)(u2  √ 2)

49. (x  y)(2x  3y)(2x  3y)

17. Commutative law of addition

31. Property 2 of quotients

39. (2r  3s)(4r 2  6rs  9s 2)

45. (3a  b)(x  2y)

7. Irrational and real

9. Rational and real

37. (2m  1)(4m 2  2m  1)

51.

17. 1

8y 6

a10

1 4x

39.

8

45. 9a2b8

12

b

1 u√

53.

8 xy

29.

x6 37.

19.

47.

ba ba

21. 12 x5

1 27

23.

31. 2x 2y5 4u4

41.

9√ 5 u8 16

3 2u√ 2

1 1728x 2y 3z 2

1x 1x

49.

55. False

33.

3 2x

57. False

Exercises 1.6, page 34 1. x  4

3. y  403

9. p  15

11. p  0

19. x 

1 2

27. q  1

21. x 

1 2

5. x  32 13. k  23 23. y 

29. k  2

3 2

7. y  5 15. x  2 25. x 

31. No solution

17. x  8

17 8

33. x  1

864

ANSWERS TO CHAPTER 1 ODD -NUMBERED EXERCISES

35. k  52

37. k  13

Vb 43. x  aV 47. t 

45. m 

I 3 ; yr Pr 2

51. a. t 

39. r 

rB1n  1 2

71. 9.2 sec

73. 1.41 sec after passing the tree

77. 40,000

79. 3.82 or 26.18 days

81. 12 in.  6 in.  2 in.

2I b. $115,000

1. False

b. 5 yr

0

5. 3

9. 5

7. 4

7.

11. 4

25.

2 3

9 4

15.

3 4

17.

29. x1/5

27. 64

37. x12/5  2 x17/5 45. 4xy 1y

55.

57.

3 2 18 3

65.

73.

xy

81.

xy

85. True

2x x

59.

3

2

y

x3

3 43. 3 2 2

53.

3

67.

3 2 18y 2

y 2xz 2

2 23 3

2a11  a 2 a 3x

1/3

83.

21x  12

6x1/2 11  x1/3 2 2

) 6

x

) 0

x

4

(

x 13. (, 5]

11. (, 2)

17. (, 3)  (3, )

15. (4, 6)

19. (2, 3)

21. [3, 5]

23. (, 1]  [ 32 , Ô

25. (, 3]  (2, )

27. (, 0]  (1, )

29. 4

39. False

41. False

45. a  b x a  b 53. $50.70

31. 2

33. 5œ3

35. ␲  1

43. True

47. False

55. [362, 488.7]

49. True

51. False

57. $32,000

59. Between 1000 and 4000 units 61. Between 98.04% and 98.36% of the toxic pollutants 63. After 2 min

67. x  0.5 0.01

65. 4 sec

Chapter 1 Concept Review Questions, page 63

87. True 1. a. Rational; repeating; terminating b. Irrational; terminates; repeats

Exercises 1.8, page 49 1. x  3, 2

3. x  2, 2

7. t  1, 21

9. x  2

15. z  2, 32 21. m 

91. False

0

37. 2 4 23 69. 3

xz

77.

3

2x  113x  22

9. 5/2

61. œ3  1

q1 75.

35.

6 51. 2 x

q1 2q  1 2

26 2x

9 x6

41. 4 22

3

1 16

23.

33.

3 49. 2 3

223y

63. (1  22)

79.

31. x

47. m2np4

32x 2x

21. 9

39. 4p2  2p

2

71.

19. 23

1 4

( 3

[ –1

13.

89. False

3. False

5. 3. 4

87. 1.83 ft

Exercises 1.9, page 60

Exercises 1.7, page 42 1. 9

75. 10,000

83. 30 ft and 90 ft

85. 1500 yd  750 yd

NV  St Nt

49. a. C 

24c  a a

p 1 41. q    3 3

I Pt

12



5. x  4, 3

11. m  2, 32

17. x  4, 2 1 2

213,

12



1 2

19. x  1 

39. y  22, 23 45. x  2, 32 51. x  8, 2

47. x  52 , 1 53. x  163

57. u  3 or 2

37. x  22, 23

35. x  0.93, 3.17 41. x 

59. r  3

213 2

31. x  12 14 210

27 ,

3. a. a; (ab)  a(b); ab

b. 0; 0

4. a. Polynomial; x; degree; term; polynomial; coefficient

b. Like

5. Product; prime; x(x  2)(x  1) 25. x 

29. m  2 23

33. x  1 12 210

26 26 ,1 2 2

213

3 241 3 241 23. x    ,  4 4 4 4 27. x  32 , 2

13. x  32 , 23

2. a. b  a; (a  b)  c; a; 0 b. ba; (ab)c; 1 ⭈ a; 1 c. ab  ac

53

43. w  49 , 49

49. y  23 , 4 55. t  1 12 26 61. s  6

6. a. Polynomials b. Numerator; denominator; factors; 1; 1 c. Denominator; fractions 1 x 7. Compound; 1 1 y 1

8. a. a ⭈ a ⭈ a ⭈    ⭈ a; base; exponent; power  n factors 1 c. n a 9. a. Equation

63. Two real solutions

65. No real solutions

67. One real solution

69. Two real solutions

10. a. an  b

b. Number b. Pairs

11. a. Radical; b1/n

c. No

b. Radical

b. 1; not defined

c. ax  b  0; 1 d. Real root

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

12. a. ax2  bx  c  0 b 2b2  4ac b. Factoring; completing the square; x  2a

2. Irrational and real

3. Irrational and real

8. 25

9.

3 14. 32 3

6. Irrational and real 10. 32

1 144

11.

15. 4(x2  y)2

20. 29 a5b8

19. 6xy7

83. $100

4. Whole, integer, rational, and real

5. Rational and real

64 27

17.

b11

21. 9x 2y4

22.

27 8

7.

12.

a15

16.

1 4

3 5

13.

2x 3z

18. x1/2

26. 3a  b

27.

29.

180

1t  62

28.

2

3

312x  12 13x  1 2

30.

31. 2␲r2(␲r  50)

46.

1x  22 1x  12

51. y  12 , 1 54. x 

55. x  14 59. k  2

rB1n  1 2 2m

69. ␲  6

73. (2, 32 )

2 3. (2, 2); Quadrant IV 7. A

9. E, F, and G

y

x

(

17. 8, – 27

43. 2

5 213 2

53. x  0, 3, 1

56. p  2

63. [2, )

57. x  35 , 0

61. x 

66. (, 5)  (5, )

75.

100C 20  C

21.

1 2

29.

db ca

23. Not defined

67. 4

71. [2, 12 ]

[32, 2]

(a  c)

35. a  5

25. 5

76. 23 ; 32

72. [4, 3]

27.

5 6

b. 8

31. a. 4

33. Parallel

37. Yes

Exercises 2.2, page 80 3. (a)

11. y  2x  10

23. y 

m

7. Perpendicular

13. y  2

17. y  x  1 1 2 x;

5. (f)

b0

21. y  5

25. y 

31. y  43 x  34

33. y  6

37. y  23 x  23

39. k  8

9. y  3

15. y  3x  2

19. y  3x  4 1 2;

27. y  12 x  72 ; m  12 ; b  72

64. [1, 2]

70. 8  3 23

)

19. (4.5, – 4.5)

50. x 

60. x  1

74. (1, 4)

b. 12 (3  217) or 12 (3  217)

13–19. See the following figure.

1. (e)

22 2

65. (, 4)  (5, ) 68. 1

3 241 4

52. m  1.2871, 8.2871

58. q  176 62. I 

1t 2  4 2 2

47. x  34 , 21

1x  1 2 2

49. x 

41t 2  4 2

42.

2s 2 1  2s

15. (3, –1)

x 1x  22 1x  3 2

x21  3x 2 13x 2  5x  1 2

48. x  2, 13

5.

39. 3a2b2(2a2b2c  ac  3)

x2 x3

45.

3

1 2xy

13. (– 2, 5)

37. (3a  5b)(3a  5b)

2

22 2

10. [2, 1]

33. (4  x)(4  x)

36. 4(3x  5)(x  6)

3x12x 3  2x  1 2

4.

7. a. 4 or 32

9. [23 , 32 ]

11. F

35. 2(x  3)(x  1)

44.

5x 2  1 13x  1 2 1x  2 2 1x  1 2

5. (4, 6); Quadrant III

x1

32. 2√w(√ 2  w 2  u2)

41.

1  4x

b. a(a  1)(a  2b  a2)

1. (3, 3); Quadrant I

34. 6t(2t  3)(t  1)

40. (2x  y)(3x  y)

311  22x2

Exercises 2.1, page 73

2 2x  11x  22

38. u3(2u√  3)(4u2√2  6u√  9)

3.

CHAPTER

413x 2  2 2 1x  22

2

80.

2

15x 2  24x  2

78x 2  8x  27

82. x  2

2. a. x2(x  3)(x  2)

8. 21

25. 2x2  9y2  12xy  7x  3

2

x  2x 2x

79.

Chapter 1 Before Moving On, page 65

6. 7  4 23

24. 9x  18x  17x  12

3

x 3 z2 xy

84. $400

1/2

23. 5x  20x  12x  14x  3 4

78.

1. 3(5x2  9x  4)

x y

1 2x  1

81. x  1 26

Chapter 1 Review Exercises, page 63 1. Rational and real

77.

2 3x

 3; m  32 ; b  3

29. y  12 x  3 35. y  b

865

866

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

41.

43.

63. a and b. y

y

y

Dollars

4

4

x 2

x

(100, 250)

250 240 230 220 210 200

x

2

45.

20 40 60 80 100 Units c. y  12 x  200

y

65. a and b. y

x

Millions of dollars

3

–5

49. y  2x  4 55. a.

d. $227

51. y  18 x  12

53. Yes

L

9 8 7 6 5 x 1

y (% of total capacity)

100

2

3 4 Years

c. y  0.8x  5

80

67. False

60

69. True

5

d. $12.2 million 71. True

Using Technology Exercises 2.2, page 87

40

Graphing Utility

20

1.

t 5

10 Years

15

20

b. 1.9467; 70.082 c. The capacity utilization has been increasing by 1.9467% each year since 1990 when it stood at 70.082%. d. In the first half of 2005 57. a. y  0.55x

b. 2000

3.

59. 84.8%

61. a and b. y (billion dollars) 20 5. a.

15 10 5 x 1

2

c. y  1.82x  7.9

3 4 Years

5

6

d. $17 billion; same

b.

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

7. a.

7.

867

20x + 16y = 300 40 30 y

20 10

b. −20

0

−10

−10

0

10

20

30

x 9.

20x + 30y = 600 30

9. y

20 10 −20

0

−10

0

10

20

30

40

50

−10 11.

x 22.4x + 16.1y − 352 = 0

11.

40 30 y

20 10

Excel −20

3.2x + 2.1y − 6.72 = 0

1.

−10

20

y −15

−10

−5

0

5

10

15

5. 2a  2h  5, 2a  5, 2a2  5, 2a  4h  5, 4a  2h  5

x

7.

y

1.6x + 5.1y = 8.16

−10

−5

6 5 4 3 2 1 0 −1 0 −2 x

y −15

−10

−5

50 40 30 20 10 0 0 −10 −20 −30 x

212  a2 21t  1 2 8 2a , 0, 2 , 2 , 15 a  1 a  4a  3 t 1t  2 2

9. 8,

5

10

15

21x  1 2 2 21x  1 2 2 2a 2 , , 1a  1 1x 1x  2

11. 5, 1, 1

13. 52 , 3, 3, 9

15. a. 2 c. [0, 6]

b. (i) x  2; (ii) x  1 d. [2, 6]

17. Yes

19. Yes

23. 1, 2

12.1x + 4.1y − 49.61 = 0

5.

1. 21, 9, 5a  6, 5a  6, 5a  21 3. 3, 6, 3a 2  6a  3, 3a 2  6a  3, 3x 2  6

−20

−15

20

Exercises 2.3, page 95

−10

3.

10

−10 x

10 0

0

27. (, )

21. 7

25. 1, 0 2  10,  2 29. 1, 5 4

31. 1, 1 2  11, 1 2  11,  2 33. 3 3,  2 5

10

15

35. 1, 2 2  12, 1 4

30

868

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

37. a. (, ) b. 6, 0, 4, 6, 254 , 6, 4, 0 c. y

y

47. 5

5

x 5

x 5

(, );

–5

(, 0)  [1, ) y

49. y

39. 30 25 20 15 10 5

5

x 2 (, );

4

[1, )

y

41.

x –1

(, );

[0, )

51. Yes

53. No

59. 10p in.

2 x [0, );

8

[2, )

4

55. Yes

57. Yes

61. 8

63. a. f 1t2  e

4

1

–4

0.0185t  0.58 if 0 t 20 0.015t  0.65 if 20 t 30

b. 0.0185/yr from 1960 through 1980; 0.015/yr from 1980 through 1990 c. 1983 65. 20; 26

67. $5.6 billion; $7.8 billion

y

43.

69. a. $0.6 trillion; $0.6 trillion

x 1 (, 1];

[0, ) y

45.

b. $0.96 trillion; $1.2 trillion

71. a. 130 tons/day; 100 tons/day; 40 tons/day y b. 140 120 100 80 60 40 20 t 0 73. False

x –1

1 –1

(, );

[1, )

2

4

6

8

10

75. False

Using Technology Exercises 2.3, page 102 1. a.

b.

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

3. a.

b.

23. f 1x2  t1x2  f 1x2  t1x 2  f 1x2 t1x2 

5.

7.

21x 2  22

1x  1 2 1x  2 2

869

;

2x ; 1x  1 2 1x  2 2

1x  1 2 1x  2 2 f 1x2 1x  12 1x  22 ;  1x  1 2 1x  2 2 t1x2 1x  1 2 1x  22

25. f ( t(x))  x 4  x 2  1; t( f (x))  (x 2  x  1)2

`

27. f 1t1x2 2  2x 2  1  1; t1 f 1x 2 2  x  21x 29. f 1t1x2 2 

9. 18.5505

33.

11. 4.1616

15 5

x x 1 2

; t1 f 1x2 2 

x2  1 x

31. 49

35. f (x)  2x 3  x 2  1 and t(x)  x 5

37. f 1x 2  x 2  1 and t1x2  1x

13. a.

39. f 1x2  x 2  1 and t1x2 

1 x

41. f 1x 2  3x 2  2 and t1x2  b. $62.96 million; $107.66 million 47. 2a  h

15. a.

1 x3/2

43. 3h

49. 3a 2  3ah  h 2  1

45. h(2a  h)

51. 

1 a1a  h2

53. The total revenue in dollars from both restaurants at time t 55. The value in dollars of Nancy’s shares of IBM at time t 57. The carbon monoxide pollution in parts per million at time t b. 44.7; 52.7; 129.2

59. C(x)  0.6x  12,100

Exercises 2.4, page 108 1. f(x)  t(x)  x  x  3 3

5.

f 1x2 t1x2



x3  5

7.

x 2 2

3. f (x)t(x)  x  2x  5x  10

2

f 1x 2t1x 2 h1x 2

5



x5  2x 3  5x 2  10 2x  4

9. f 1x2  t1x2  x  1  1x  1 11. f 1x2t1x2  1x  1 2 1x  1 13.

17.

t1x2 h1x2



1x  1 2x  1

f 1x2  h1x2 t1x2

15.

3



f 1x 2 t1x 2 h1x 2

1x  12 1x  1



2x 3  1

f 1x2  t1x2 

63. a. 23; In 2002, 23% of reported serious crimes ended in the arrests or in the identification of the suspects. b. 18; In 2007, 18% of reported serious crimes ended in the arrests or in the identification of the suspects. 65. a. P(x)  0.000003x 3  0.07x 2  300x  100,000 b. $182,375 67. a. 3.5t 2  2.4t  71.2

73. True

b. 71,200; 109,900

b. $444,700; $1,167,600

75. False

Exercises 2.5, page 117

2

21. f 1x2  t1x2 

61. a. f (t)  267; t(t)  2t 2  46t  733 b. f (t)  t(t)  2t 2  46t  1000 c. 1936 tons

71. a. s(x)  f(x)  t(x)  h(x)

19. f 1x2  t1x2  x 2  1x  3;

f 1x2 t1x2  1x 2  5 2 1 1x  2 2;

2

69. a. 55%; 98.2%

x  2x 3 1x  1

f 1x2  t1x2  x  1x  7;

3

f 1x 2

t1x 2



1x  12 1x  3  1 x1

;

x1

;

1x  12 1x  3  1

x 5 1x  2 2

1x  3 f 1x 2 ;  1x  1 2 1x  3 f 1x2t1x2  x  1 t1x 2

1. Yes; y  32 x  2 5. Yes; y  12 x  94

3. Yes; y  12 x  2 7. No

9. No

11. a. C(x)  8x  40,000 b. R(x)  12x c. P(x)  4x  40,000 d. Loss of $8000; profit of $8000 13. m  1; b  2 21. 1000 units; $15,000

15. (2, 10)

17. Ó4, 23 Ô

23. 600 units; $240

19. (4, 6)

870

25. $900,000; $800,000 27. a. y  1.053x

b.

b. $1074.06

29. C(x)  0.6x  12,100; R(x)  1.15x; P(x)  0.55x  12,100 b. V  60,000  12,000t

Sales in thousands of dollars

31. a. $12,000/yr c. V

Thousands of dollars

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

y 30

C1 (x)

15

R(x)

C2 (x)

x 1 2 3 4 5 6 7 In units of a hundred

60 50

c. Machine II; machine II; machine I d. ($1500); $1500; $4750

40 30

47. Middle of 2003

20 49. a.

10

y 60

t 1

2 3 Years

50

4

40 30

d. $24,000

20

33. $900,000; $800,000

10 35. a. m  a/1.7; b  0

b. 117.65 mg

37. a. f (t)  6.5t  20 (0 t 8)

41. a.

Thousands of dollars

39. a. F  95 C  32

b. 68°F

t

b. 72 million c. 21.1°C b. 8000 units; $112,000

y C(x)

6

3. 2.880952381

5. 7.2851648352

Exercises 2.6, page 129

20

x 2 10 In units of a thousand d. (8000, 0)

P 50 P(x)

x

1. Vertex: 112 , 254 2 ; x-intercepts: 3, 2 y 20 15 10 5 x 6 4 25 2 4 6 10

8

– 50

10

51. True

7. 2.4680851064

In units of a thousand

8

b. Feb. 2005

1. 2.2875 R(x)

Thousands of dollars

4

Using Technology Exercises 2.5, page 123

100

c.

2

3. Vertex: (2, 0); x-intercept: 2 y 100 80

43. 9259 units; $83,331

60

45. a. C1(x)  18,000  15x C2(x)  15,000  20x

40 20 x 5

5

10

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

5. Vertex: 1 52 , 14 2 ; x-intercepts: 2, 3

17.

y

Vertex: 1 43 , 103 2 ; x-intercepts: 13 , 3 y

x 2 4 6 8

1

2

3

4

30

5

20 10 x

6 4 2

7. Vertex: 1 56 , 13 12 2 ; x-intercepts: 0.2324, 1.4343 y

2

4

21. (2, 2); (3, 3)

19. (2, 0); (1, 3)

20

23. (1.1205, 0.1133), (2.3205, 8.8332)

15

25. a.

10 5 x

2 1

1

2

b. 5000

p 35 30 25 20 15 10 5

3

9. Vertex: 1 34 , 158 2 ; no x-intercepts

x

y

1 2 3 4 5 6

15 12.5 10 7.5 5 2.5

27. a.

b. $26

p ($)

30

x x 3

11. Vertex: (0, 4); x-intercepts: 2

Units of a thousand

y 20

29. 2500; $67.50

15

33. a. 3.6 million; 9.5 million

10

35. a.

31. 11,000; $3 b. 11.2 million b. t  2; 144 ft

y

5

140 x 2

4

Feet

4 2

13. Vertex: (0, 16); x-intercepts: 4

120 100 80

y

t 1

15 5

37. 3000 4

6

20 Vertex: 1 83 , 23 2 ; x-intercepts: 43 , 4

39. a.

b. $30

R Hundred dollars

2

15

400 300 200 100 p

y

10 20 30 40 50 60 Dollars

15 12.5 10 7.5 5 2.5 4 2

4

x

10

15.

3

Seconds

10

6 4 2 5

2

41. 123,780,000 kWh; 175,820,000 kWh 43. a. $3.25 billion x 2 4 6 8

45. 500; $32.50

b. $3.88 billion; $4.39 billion; $4.78 billion

871

872

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

√ (r)

47. a.

21. a.

y ($/kilo)

40

250

30

200

20

150

10 100

r 0.05 0.1 0.15 0.2

50

b. 0, 0.2. The velocity of blood is greatest along the central artery (r  0) and smallest along the wall of the artery (r  0.2). The maximum velocity is √(0)  40 cm/sec, and the minimum velocity is √(0.2)  0 cm/sec. 49.

t (year) 5

51. True

15

20

25

30

b. $7.44/kilo; $108.48/kilo 23. a.

28 28 ft by ft p4 p4

10

53. True

y% 30 25

55. True

20

Using Technology Exercises 2.6, page 133

15

1. (3.0414, 0.1503); (3.0414, 7.4497)

10 5

3. (2.3371, 2.4117); (6.0514, 2.5015)

t (year)

5. (1.1055, 6.5214); (1.1055, 1.8783)

5

10

15

20

25

b. 13.43%; 1823 %

7. a.

25. b. Early 2002 27. f 1x2  2x 

500 ;x0 x

29. f 1x2  0.5x 2 

8 x

31. f(x)  (22  x)(36  2x) bushels/acre b. 438 wall clocks; $40.92

33. a. P(x)  (10,000  x)(5  0.0002x)

Exercises 2.7, page 140

35. False

1. Polynomial function; degree 6

1. a. y  0.1375t 2  0.675t  3.1 b.

5. Some other function 100x 40  x

37. False

Using Technology Exercises 2.7, page 145

3. Polynomial function; degree 6

7. a. R(x) 

b. $60,800

b. 60%

9. $751.50/yr; $1772.38/yr 11. a. 320,000

b. 3,923,200

c. 3.1; 3.9; 5; 6.4; 8; 9.9

N(t) (million)

13. a.

3. a. f(t)  1.85t  16.9 b.

200 175 150 125 100 75 50 25 t (year) 2

4

6

8

10

b. 157,000,000 15. 582,650; 1,605,590 19.

t y

1 18.8

d. 31.7 gallons 17. $699; $130

2 1  26 a t 2  1b  52; $32, $6.71, $3; the gap was closing. 4 1

110 1 2t

c.

2 20.6

3 22.5

4 24.3

5 26.2

6 28.0

ANSWERS TO CHAPTER 2 ODD -NUMBERED EXERCISES

5. a. f(t)  0.221t 2  4.14t  64.8 b.

c. 77.8 million

4. m1  m2; m1  

873

1 m2

5. a. y  y1  m(x  x1); point-slope form b. y  mx  b; slope-intercept 6. a. Ax  By  C  0 (A, B, not both zero) 7. Domain; range; B 7. a.

b. 

a b

8. Domain, f(x); vertical, point

9. f (x) t(x); f (x)t(x);

f 1x2

t 1x 2

; A  B; A  B; 0

10. t[ f (x)]; f ; f (x); t 11. ax2  bx  c; parabola; upward; downward; vertex; b. f(t)  2.94t 2  38.75t  188.5

c. $604 billion

9. a. f(t)  0.00081t 3  0.0206t 2  0.125t  1.69 b.

b b ;x 2a 2a

12. a. P(x)  an x n  an1 x n1      a1x  a0 (an  0; n, a positive integer) b. Linear; quadratic c. Quotient; polynomials d. x r (r, a real number)

Chapter 2 Review Exercises, page 149 1. x  2

c. $1.8 trillion; $4.2 trillion 11. a. f(t)  0.425t 3  3.6571t 2  4.018t  43.7 b.

2. y  4

3. y  101 x  195

4. y  54 x  125

5. y  25 x  9

7. y  21 x  3

8. 53 ; 65

10. y  53 x  125 12.

6. y  43 x  112

9. y  43 x  92

11. y  32 x  7

y

x 8 c. $43.7 million; $77.2 million; $107.7 million 6

13. a. f(t)  2.4167t 3  24.5t2  123.33t  506 b. 13.

y

3 c. 506,000; 338,000; 126,000 15. a. f(t)  0.000133t 4  0.00353t3  0.04487t2  0.143t  1.71 b.

10

6

x 1 15. (, 1)  Ó1, 32 Ô  Ó 32 , Ô

14. (, 9]

16. a. 0 b. 3a2  17a  20 c. 12a2  10a  2 d. 3a2  3h2  6ah  5a  5h  2 c. 1.71 mg; 1.81 mg; 1.85 mg; 1.84 mg; 1.82 mg; 1.83 mg d. 1.9 mg/cigarette

Chapter 2 Concept Review Questions, page 149

17. a. From 1985 to 1990 b. From 1990 on c. 1990; $3.5 billion 18. a.

b. No

y

1. Ordered; abscissa (x-coordinate); ordinate (y-coordinate) 2. a. x-; y-; 3. a.

y2  y1 x2  x1

b. Third b. Undefined

c. 0

d. Positive

x

c. Yes

874

ANSWERS TO CHAPTER 3 ODD -NUMBERED EXERCISES

19.

34. p  361 x  400 9

y

35. 117 mg

36. a. y  0.25x 2

39.

c.

2x  3 x

b.

1 2x  3

d.

1 x12x  3 2

n

2 3 x

4

8 10 12

3 13V 2 / 14p 2 41. a. r  f(V)  2 d. 3 ft

250 200 150 100 50

3 t c. h(t)  23 2

b. t(t)  92 ␲t

Chapter 2 Before Moving On, page 151 1. y  75 x  35 4. a.

x

6 4 2

2 4 6 8

2

4

120 24. 16,

x2  1 x1

c.

b. 2

1

d.

x2  2

c. 1

17 4

1x  1 2 2

1

3

25. 12,

1 32

b. 27

3. a. 3

5. a. 3

b. 8

7. a. 4x 3

13. 2 26. (2500, 50,000)

b. 15

1. a. 16

2 a2

b. 31 b 2 15. 3

b. 5xy 2 1x

11. a. 8x 9y 6

17. 3

19.

y

23.

28. L 2

5 4

b. 16x 4y 4z 6 21. 1 or 2 y

25. y = 2x

30. a. f(x)  x  2.4

31. a. 6x  30,000 b. 10x d. ($6,000); $2000; $18,000 32. a. $200,000/yr

b.

3. a. 3

Exercises 3.1, page 158

6

9. a. 21 2 2

1  x2  1 x1

CHAPTER

x

4 220 40 60 80 100

2. y  13 x  43

5. 108x2  4x3

22. Vertex: 1 12 , 42 ; x-intercepts: 12 , 32 y

29. 60,000

6

As the length of the list increases, the time taken to learn the list increases by a very large amount.

y

27. L 2

38. 400; 800

40. 5000; $20

T

2

2 5 361 21. Vertex: 1 11 12 ,  24 2 ; x-intercepts: 3 , 2

23. (2, 3)

37. $45,000

140 120 100 80 60 40 20

x 2

20. a.

b. 1600

b. $5.4 million y = 2–x

c. 4x  30,000

x

x

b. $4,000,000

– 3 – 2 –1

1 2 3

1 2

33. p  0.05x  200 p

27.

y

y

29.

200 30

y = 4 0.5x

150

20

100

10

50 x

–1000 –50

1000 2000 3000 4000 5000 6000

y = e 0.5x

x

x –1

1 2 3

ANSWERS TO CHAPTER 3 ODD -NUMBERED EXERCISES

y

31.

9.

y = 0.5e –x 11. a.

x 33. f(x)  100 1 65 2 x

35. 54.56

37. a. 26.3%; 24.67%; 21.71%; 19.72% b. R(t) b. 0.08 g/cm3

25

c. 0.12 g/cm3

13. a.

20 15 10 5 t 5

10

15 b. 20 sec

39. a. Year Web Addresses (billions)

0

1

2

3

4

5

0.45

0.80

1.41

2.49

4.39

7.76

Exercises 3.2, page 168 1. log 2 64  6 7. log32 8  35

N(t) (billions)

b.

c. 35.1 sec

6

13. 1.2042

3. log3 19  2 9. log10 0.001  3

15. 1.6813

17. ln a2b3

4 21. log x  4 log(x  1)

2 1

2

3

4

5

t (yr)

41. 34,210,000 43. a. 0.08 g/cm3 45. False

b. 0.12 g/cm3

25. ln x  x 2

23.

1 2

33. x  10

39. x  113

41. x  3

35. x  32

y

Using Technology Exercises 3.1, page 161 1.

y = log 3 x

2

3.

1 x 1

5

–1 y

45. 5.

7.

4 3

y = ln 2x

2 1 x 5 –1

11. 1.0792 19. ln

31xy 3 1 z

log1x  1 2  log1x 2  12

27. 32 ln x  12 ln11  x 2 2

31. x  3

43.

47. True

5. log1/3 31  1

29. x  8 37. x  167

875

876

ANSWERS TO CHAPTER 3 ODD -NUMBERED EXERCISES

47.

y

Using Technology Exercises 3.3, page 180 y = 2x

5

1. a.

y = log 2 x

x 5

51. 0.0912

49. 5.1986 57. 2 ln a

3. a.

A b B

53. 8.0472

59. 2  2.8854 ln x

55. 4.9041

61. 105.7 mm b. 666 million, 926.8 million

63. a. 103I0 b. 100,000 times greater c. 10,000,000 times greater 65. 27.40 yr

67. 6.44 yr

71. False

5. a.

69. a. 9.12 sec

b. 20.27 sec

73. a. ln 2

Exercises 3.3, page 177 1. a. 0.05 c. t Q

b. 325 million

b. 400

7. a. 0 400

10 660

3. a. Q(t)  100e 0.035t 5. a. 54.93 yr

20 1087

100 59,365

c. Q(t)  1000e 0.035t

b. 266 min

b. 14.25 billion

9. Q(t)  100e0.049t; 70.7 g

1000 2.07  1024

7. 8.7 lb/in.2

Q(t)

13.

b. 0 c. 0.237 g/cm3 d. 0.760 g/cm3

11. 13,412 yr ago

9. a. f 1t 2  b.

100

10

20

a. 60 words/min

t

b. 107 words/min

c. 136 words/min

Chapter 3 Concept Review, page 182 1. Power; 0; 1; exponential

15. $5.806 trillion; $8.575 trillion

2. a. 1,  2 ; 10,  2

D(t)

17.

544.65 1  1.65e0.1846t

3. a. 10, 2; 1,  2; 11, 0 2

2000

4. a. x 1000

50 a. 573 computers; 1177 computers; 1548 computers; 1925 computers b. 2000 computers

23. 76.4 million

21. 86.1% 25. 1080

b. Falls; rises

b. x

5. a. Initially; growth t

19. 122.3 cm

b. 10, 1 2 ; left; right

b. Decay

c. Time; one half

6. a. Learning curve; C b. Logistic growth model; A, carrying capacity

Chapter 3 Review Exercises, page 182 1.

2.

y 120 100 80 60 40 20 1

y 120 100 80 60 40 20

x 1

2

3

3 2 1

x 1

ANSWERS TO CHAPTER 4 ODD -NUMBERED EXERCISES

3.

4.

y

y

1 x 2

1

4

6

8

CHAPTER

2 1 x

10

2

1

2

4

Exercises 4.1, page 197 4

6

8

1. $80; $580

3. $836

9. 10%/yr

11. $1718.19

15. $27,566.93 5. log3 81  4

6. log9 3 

8. log16 0.125  34

16. x  3

17. x  2, 1

20. x  152

21. x  2

24. x  2.5025 27. x  1.8195

7.

9. 3.4011

13. x  y  z

12. 4.3174

1 2

14. x  2y  z 18. x  5

11. 1.2809 15. y  2z

23. x  0.9464

26. x  2.8332

31. x  2.5903

23. 8.3%/yr

27. $30,255.95 33. 7.7 yr

32. x  9.1629

35. 6.08%/yr

41. $123,600

43. 5%/yr

55. a. $34,626.88

b. $33,886.16

47. $255,256

53. $26,267.49 c. $33,506.76

59. $23,329.48

61. $5994.86

65. Investment A

75. 5.83%

7. 10.20%/yr

69. 80,000e1t/20.09t; $151,718 77. True

79. True

7. $137,209.97 y = log3 (x + 1)

1 x 4

6

8

3. $475.49

5. 8.95%/yr

9. $29,743.30

11. $53,303.25

Exercises 4.2, page 211 1. $15,937.42

2

39. 24%/yr

45. $852.21

51. $22,163.75

1. $5872.78

x

1

37. 2.06 yr

Using Technology Exercises 4.1, page 204 y = log2 (x + 3)

2

31. 2.2 yr

49. $2.58 million

73. 4.2%

2

y

25. $29,277.61

67. $33,885.14; $33,565.38

35. x  9.1629

19. $214,986.69

29. $6885.64

63. $115.3 billion

y

37.

7. 146 days

13. $4974.47

17. $261,751.04

10 14 %/yr

57. Acme Mutual Fund

29. x  33.8672

34. x  3.4657

36.

21.

19. x  2, 3

22. x  1.1610

28. x  0.2409

33. x  8.9588

 3

10. 2.1972

25. x  1.2528

30. x  1.8934

log2/3 278

5. $1000

10

10

3. $54,759.35

5. $37,965.57

9. $28,733.19

11. $15,558.61

13. $15,011.29

15. $109,658.91

17. $455.70

19. $44,526.45

21. Karen

23. $9850.12

25. $608.54

27. Between $383,242 and $469,053

2

29. Between $307,014 and $373,768

31. $17,887.62

33. False 38. a. Q(t)  2000e0.01831t 40.

b. 161,992

39. k  0.0004

a. 1175; 2540; 3289

D(t)

Using Technology Exercises 4.2, page 215 b. 4000

4000

1. $59,622.15

3. $8453.59

7. $13,828.60

9. a.

5. $35,607.23

2000

t 50 b. $35,038.78/yr 41.  970 students 42. a. 12.5/1000 live births b. 9.3/1000 live births c. 6.9/1000 live births 43. a. 0 g/cm3 b. 0.0361 g/cm3

Exercises 4.3, page 222 1. $14,902.95

Chapter 3 Before Moving On, page 183 1.

12 x6

2. x  ln 3

3. x  0 or 8

4. 0.9589

5. 8.7 min

3. $444.24

7. $731.79

9. $1491.19

13. $172.95

15. $1957.36

19. $16,274.54

5. $622.13 11. $516.76

21. a. $212.27

17. $3450.87

23. a. $387.21; $304.35

b. $1316.36; $438.79

b. $1939.56; $2608.80

25. $1761.03; $41,833; $59,461; $124,853

27. $60,982.31

877

878

ANSWERS TO CHAPTER 5 ODD -NUMBERED EXERCISES

29. $3135.48

31. $242.23

35. $2090.41; $4280.21 41. $212.77

33. $199.07

37. $24,639.53

43. $167,341.33

47. a. $1681.71

45. $1957.80; $257,135.23

b. $194,282.67

49. $1000.92

39. $33,835.20

c. $1260.11

d. $421.60

51. $71,799

3. $1685.47

7. $894.12

9. $18,288.92

3. 29

9. 795

5. $1960.96

b. 280

19. $15.80

21. b. $800

27. GP; 1/3; 364 13 33. $56,284

7. x  6y

31. 293,866

b. $87,537.38

39. $25,165.82

b. Interest; P(1  i )n; A(1  i )n

2. Simple; one; nominal; m; a 1 

Pi 1  11  i2 n

b. R c

1  11  i 2 n i

;

1r

b. $7387.28

2. a. $19,859.95 d. $20,156.03 3. a. 12% 4. a. 11.5%

5

Exercises 5.1, page 247 3. No solution

b. 12.36%

d. 12.6825%

c. 12.0055%

5. $30,000.29

6. $39,999.95

8. $23,221.71

9. $7861.70

13. k  2

11. No solution

19.

17. 5x  y  100 5x  6y  560

x y  1000 0.5x  1.5y  1300

Exercises 5.2, page 260

c. $20,100.14

c. 12.5509%

b. 11.8306%

7. Infinitely many solutions; 1t, 25 t  2 2 ; t, a parameter

29. True

c. $7422.53

b. $20,018.07

d. 12.1259%

7. $5557.68 10. $173,804.43

11. $694.49

12. $318.93

13. $332.73

15. 7.442%

16. 10.034%

17. $80,000

1. c

2 3

0 3. £ 2 0

3 7 ` d 1 4 1 2 3

2 6 8 † 7 § 4 0

5. 3x  2y  4 x y 5

14. $208.44

18. $2,592,702; $8,612,002

19. $5,491,922

21. $15,000

23. 7.6%

22. $5000

b. 127.5

27. 10x  6y  8z  100 10x  12y  6z  100 5x  4y  12z  100

a11  rn 2

Chapter 4 Review Exercises, page 238 1. a. $7320.50 d. $7446.77

CHAPTER

4. $1213.28

25. 12,000x  18,000y  24,000z  1,500,000 x  2y x y z  100

n 7. Constant d; a  1n  12d; 3 2a  1n  12 d4 2 8. Constant r; ar

6. a. 210

3. $569,565.47

23. 18x  20y  24z  26,400 4x  4y  3z  4,900 5x  4y  6z  6,200

d

iS 11  i 2 n  1

6. Future;

n1

32. $205.09; 20.27%/yr

21. 0.06x  0.08y  0.12z  21,600 z  2x 0.12z  0.08y

r m b 1 m

3. Annuity; ordinary annuity; simple annuity.

5.

2. 6.18%/yr

15. 42x  30y  18,500 42x  30y  18,600

43. True

1. a. Original; P(1  rt)

i

31. $4727.67

9. Unique solution; (1, 2)

Chapter 4 Concept Review Questions, page 237

d

30. $19,573.56

c. $91,367

5. Unique solution; (3, 2) 25. Not a GP

35. Annual raise of 8%/yr

11  i2 n  1

b. $99,081.60

1. Unique solution; (2, 1)

23. GP; 256; 508

41. $39,321.60; $110,678.40

4. a. R c

c. $42,684

17. At the beginning of the 37th wk

29. 3; 0

37. a. $20,113.57

29. a. $1217.12

5. $35.13

13. 550

15. a. 275

b. $227,598

1. $2540.47

5. 3, 8, 19, 30, 41

11. 792

28. a. $965.55

27. $2000

Chapter 4 Before Moving On, page 239

Exercises 4.4, page 234 1. 30

26. $13,026.89

33. $2203.83

Using Technology Exercises 4.3, page 227 1. $628.02

25. $73,178.41

9. Yes 20. $2982.73

24. $218.64

19. c

1 0

11. No 4 2 d ` 5 10

7.

x  3y  2z  4 2x 5 3x  3y  2z  6

13. Yes 21. c

1 0

15. No 2 3 d ` 16 20

17. No

ANSWERS TO CHAPTER 5 ODD -NUMBERED EXERCISES

1 23. £ 0 0

2 1 7

6 25. £ 2 1 3 27. c 2

R  2R

1 0

1. x1  3; x2  1; x3  1; x4  2 3. x1  5; x2  4; x3  3; x4  4

0 5 1 † 3§ 0 10

9 6 13 R1 1 ` d —씮 c 1 4 2

2 1 —— —씮 c

c

Using Technology Exercises 5.2, page 265

3 6 5 † 7 § 7 14

11 4 2

1 0

879

5. x1  1; x2  1; x3  2; x4  0; x5  3

Exercises 5.3, page 271

3 2 ` d 1 4

3 2 ` d 5 0

3 2 R1  3R2 1 ` d —— —씮 c 1 0 0

0 2 ` d 1 0

1. a. One solution

b. (3, 1, 2)

3. a. One solution

b. (2, 4)

5. a. Infinitely many solutions b. (4  t, 2, t); t, a parameter 7. a. No solution

1 29. £ 3 2

3 8 3

1 3 R2  3R1 —씮 3† 7 § —— R3  2R1 1 10

1 £0 0

3 1 9

1 3 R2 0 † 2 § ——씮 1 16

1 £0 0

3 1 9

1 3 R1  3R2 —씮 0† 2 § —— R3  9R2 1 16

1 £0 0

0 1 0

1 3 R1  R3 —씮 0 † 2 § —— R3 1 2

1 £0 0

0 1 0

0 1 0 † 2§ 1 2

9. a. Infinitely many solutions b. (2, 1, 2  t, t ); t, a parameter 11. a. Infinitely many solutions b. (2  3s, 1  s, s, t); s, t, parameters 13. (2, 1)

15. No solution

17. (1, 1)

19. (2  2t, t); t, a parameter 21. 1 43  23 t, t 2 ; t, a parameter 23. 12  12 s  12 t, s, t 2 ; s, t, parameters 25. 11, 177 , 237 2 27. 11  14 s  14 t, s, t 2 ; s, t, parameters 29. No solution

31. (2, 0)

33. (1, 2, 2)

35. (4, 2)

37. (1, 2)

39. 1 79 , 19 , 23 2

41. (19, 7, 15)

43. (3, 0, 2)

45. (1, 2, 1)

47. (20, 28, 13)

49. (4, 1, 3)

51. 300 acres of corn, 200 acres of wheat 53. In 100 lb of blended coffee, use 40 lb of the $5/lb coffee and 60 lb of the $6/lb coffee. 55. 200 children and 800 adults 57. $40,000 in a savings account, $120,000 in mutual funds, $80,000 in bonds

31. (2, 1, 4)

33. x  20  z, y  40  2z; 25 compact cars, 30 mid-sized cars, and 5 full-sized cars; 30 compact cars, 20 mid-sized cars, and 10 fullsized cars 37. $10,000 in money-market account, $60,000 in stocks, and $30,000 in bonds; $20,000 in money-market account, $70,000 in stocks, and $10,000 in bonds 39. a. x1  x6  1700 x1  x2  x7  700 x2  x3  300  x3  x4  400  x4  x5  x7  700 x5  x6  1800 b. (1700  s, 1000  s  t, 700  s  t, 1100  s  t, 1800  s, s, t); (900, 1000, 700, 1100, 1000, 800, 800); (1000, 1100, 800, 1200, 1100, 700, 800) c. x6 must have at least 300 cars/hr.

59. 400 bags of grade-A fertilizer; 600 bags of grade-B fertilizer; 300 bags of grade-C fertilizer

41. k  36; 14  23 y  43 z, y, z 2

61. 60 compact, 30 intermediate-size, and 10 full-size cars

Using Technology Exercises 5.3, page 275

63. 4 oz of food I, 2 oz of food II, 6 oz of food III 65. 240 front orchestra seats, 560 rear orchestra seats, 200 front balcony seats 67. 7 days in London, 4 days in Paris, and 3 days in Rome 69. False

43. False

1. (1  t, 2  t, t); t, a parameter 3. 1177  67 t, 3  t, 187  17 t, t 2 ; t, a parameter 5. No solution

Exercises 5.4, page 281 1. 4  4; 4  3; 1  5; 4  1

3. 2; 3; 8

880

ANSWERS TO CHAPTER 5 ODD -NUMBERED EXERCISES

5. D; D T  [1 3 1 9. £ 6 2 13. c

3 4

6 1 § 2

7 2 £ 196 29 3

7. 3  2; 3  2; 3  3; 3  3

0]

1 11. £ 1 6 9 d 13

5 10

1.9 17. c 6.0

19.

2

15. c

1 172 1

2 3 17 6

4 4

3 17

1. 2  5; not defined

16 d 16

10 3 23 3 §

21. u  3, x  25 , y  7, and z  2

1 d 3

9. c

4 9

2 d 13

9 d 10

11. c

9 d 16

2 5

6 17. £ 2 4

3 1 4

3 2 ¥ 31. ≥ 1 5

4 21. £ 4 12

20 12 32

27. AB  c

10 22

220 35. £ 220 215

215 210 205

210 200 195

0 1§ 0 350.2 37. B  £ 422.3 638.6

205 195 § 190

2960 39. a. D  £ 1100 1230

1510 550 590

1150 490 § 470

3256 b. E  £ 1210 1353

1661 605 649

1265 539 § 517

2000 2001 41. MA 6.88 7.05 c U.S. 4.13 4.09

45. True

3. £

5 1 0.5

16.44 5. £ 12.77 5.09

6.3 0.5 4.2

67.5 52.5 65

6.8 5.4 3.5

3.65 10.64 0.28

19. c

4 0§ 20

23. c

5 1

1 d 2

3 1

4 7

7 5 d ; BA  c 15 13

2 3

2 d 5

8 d 20

33. a. AT  c

35. AX  B, where A  c

3 d 3

1 7

2 4

5 d 6

3 x d, X  c d, 4 y

7 and B  c d 8 3 2 1

4 x 3 § , X  £ y § , 2 z

1 1 2

x1 1 1 § , X  £ x2 § , 4 x3

0 and B  £ 2 § 4

33.75 38.75 § 105

3.9 4.8 § 5.6

3.66 2.58 10.84

2 5

1.93 d 1.76

0 8 § 9

1 39. AX  B, where A  £ 2 3

Men 76 69.9 § 75.9

47. False

38.75 40 35

31. A  c

0.57 0.64

6 and B  £ 7 § 4

Using Technology Exercises 5.4, page 287 15 1. £ 51.25 21.25

391.4 453.2 § 721

15. c

2 37. AX  B, where A  £ 0 1

2002 7.18 d 4.06

White Black Hispanic 43. Women 81 76.1 82.2 c d Men 76 69.9 75.9 Women White 81 Black £ 76.1 Hispanic 82.2

370.8 442.9 679.8

3. 1  1; 7  7

7. c

23. x  2, y  2, z  73, and u  15 3 4 2

4.5 4.2 § 33.6

5. n  s; m  t

13. c

2

1 33. £ 1 2

12 9 20.7

Exercises 5.5, page 294

0.6 d 1.2

3.0 9.6 3

4 1§ 1

1 8 3

0.3 17.7 4.2

22.2 7. £ 21.6 8.7

0.63 0.05 § 17.64

51,400 d 54,200 b. The first entry shows that William’s total stockholdings are $51,400; the second shows that Michael’s stockholdings are $54,200.

41. a. AB  c

43. a.

N S D krones krones krones A

Kaitlin Emma

c

0.1651 0.1462 b. B  ≥ ¥ 0.1811 0.0387

82 64 N S D R

68 74

62 44

R rubles 1200 d 1600

c. Kaitlin: $81.15; Emma: $91.27

ANSWERS TO CHAPTER 5 ODD -NUMBERED EXERCISES

0.78 45. B  £ 0.88 § ; 2006: $71.412 million, 2007: $74.536 million, 0.80 2008: $80.096 million

3 2 15. ≥ 4 4

47.

17. a. A  c

Dem BA  [41,000

Rep 35,000

1575 49. AB  £ 410 215

Ind 14,000]

1590 405 205

1560 415 225

55. False

8800 b. £ 3380 § 1020

17,600 c. £ 6,760 § 2,040

Using Technology Exercises 5.5, page 300 18.66 1. £ 24.48 15.39

15.2 41.88 7.16

12 89.82 § 1.25

20.09 3. £ 44.42 20.97

20.61 71.6 7.17

1.3 64.89 § 60.65 57.17 256.92 § 181.64

128.59 7. £ 246.73 125.06

123.08 403.12 47.01

32.50 481.52 § 264.81

87 119 9. ≥ 51 28

68 176 128 174

110 221 142 174

113 72 E 81 133 154

117 85 69 157 157

72 36 76 56 94

2 9. £ 1 0 13 10

13.

£ 52 107

5 d 2 11 6 1 7 5 15 3 5

0§ 1 2

1 x 3 2 § ; X  £ y § ; B  £ 1 § 3 z 7

4 3 2

101 72 87 121 127

1 2 23. a. A  ≥ 2 2

1 1 0 1

1 1 1 1

1 x1 6 0 4 x2 ¥; X  ≥ ¥; B  ≥ ¥ 1 x3 7 3 x4 9

31. b. (i) x1  1; x2  4; x3  5; x4  1 (ii) x1  12; x2  24; x3  21; x4  7 33. a. A1  c

52 2

35. a. ABC  c B1  c

90 76 30U 146 122 106.3 164 125.5 274.3

(ii) x  25 ; y  95

(ii) x  1; y  0; z  5

37. c

5 7 37

4 2

1 1

32 d 1 10 3 d ; A1  c 3 1 1 3 d ; C1  c 81 4 4

11. Does not exist

5 d; 2 38

1d 4

3 7 8d 7

39. a. 3214; 3929 341.3 506.4 ¥ 312.9 354.2

7. Does not exist

1 2

1 21. a. A  £ 2 1

60 29. b. (i) x  172 ; y  10 17 ; z  17

82 143 ¥ 94 112

133.1 324.1 231.5 291

3 2 § 0

b. x  1; y  2; z  3

27. b. (i) x  1; y  3; z  2 (ii) x  1; y  8; z  12

Exercises 5.6, page 309 3 1

4 x 4 1 § ; X  £ y § ; B  £ 3 § 1 z 8

25. b. (i) x  245 ; y  235

13.63 8.37 14.29

5. c

3 0 2

2 19. a. A  £ 0 1

b. x1  1; x2  2; x3  0; x4  3

32.89 5. £ 12.85 13.48

18.1 226.5 157.7 245.2

5 x 3 d; X  c d; B  c d 3 y 2

2 1

b. x  1; y  1; z  2

57. True

170 349 11. ≥ 245.2 310

1 1 ¥ 1 1

b. x  1; y  1

975 270 § 155

51. [277.60]; it represents Cindy’s long-distance bill for phone calls to London, Tokyo, and Hong Kong. 8800 53. a. £ 3380 § 1020

6 5 7 8

4 3 4 5

b. 4286; 3571

c. 3929; 5357

41. a. 400 acres of soybeans; 300 acres of corn; 300 acres of wheat b. 500 acres of soybeans; 400 acres of corn; 300 acres of wheat 43. a. $80,000 in high-risk stocks; $20,000 in medium-risk stocks; $100,000 in low-risk stocks b. $88,000 in high-risk stocks; $22,000 in medium-risk stocks; $110,000 in low-risk stocks c. $56,000 in high-risk stocks; $64,000 in medium-risk stocks; $120,000 in low-risk stocks 45. All values of k except k  32 ; 47. True

49. True

3 1 c 3  2k k

2 d 1

881

882

ANSWERS TO CHAPTER 5 ODD -NUMBERED EXERCISES

Using Technology Exercises 5.6, page 315 0.36 0.20 § 0.09

0.36 1. £ 0.06 0.19

0.04 0.05 0.10

0.01 0.25 3. ≥ 0.86 0.27

0.09 0.58 0.42 0.01

0.30 0.21 5. E 0.03 0.14 0.10

19. x  1; y  2; z  3 20. (2, 2t  5, t); t, a parameter 22. x  1; y  1; z  2; w  2 23. x  1; y  0; z  1

0.11 0.02 ¥ 0.37 0.31

0.31 0.15 0.07 0.05 0.10 0.01 0.12 0.13 0.10

0.85 0.10 0.16 0.46 0.05

0.77 0.26 0.01 0.71 0.03

0.11 0.21 0.03U 0.05 0.11

2 5 15

15

26. c

27. c

1 1

2 d 32

28. c 41

Chapter 5 Concept Review Questions, page 316 b. One; many; no

2. Equations

3. Ri 씯씮 Rj; cRi; Ri  aRj; solution 4. a. Unique 5. Size; entries

8. cA; c

9. a. Columns; rows

b. m  p

2

38. A1  c

12. A B

Chapter 5 Review Exercises, page 317 2 1. £ 1 3

2 4§ 3

2. c

2 2

0 d 6

3 7 d; 27

37. A1  c 71

1

11. A A; AA ; singular

36. c

2]

3. [6

4. c

17 d 13

2 5

15

25 1

0  £ 1 12

1 7 47 12

1

40. A

3 5

3 8

15 1

2 5

1§

1 5

3 5

78

11 24

1d 4

121 37

4 7 37

4d 7

x  1; y  2

3 10 1 d; 10

1 39. A1  £ 1 12

14 58 §

1 2 34 1 4

0 32. £ 2 1

34. c

1d 5

£ 78 18

30.

1 3§ 16

35

5

b. n  r

1

1 d 1

1 2 d 14

14

0

1 15

7

7. m  n; n  m; aji

1

3 2

72 2

6. Size; corresponding

10. a. A(BC ); AB  AC

33. c

2 5

13

1d 4

8

74 3 4§ 5 4

2 3 1  30

12

3 4 18 1

1 4 14 1 4

15

35. c 51

b. No; infinitely many; unique

3d 5

5 4 £ 14 34

31. £

9. x1  2.50; x2  0.88; x3  0.70; x4  0.51

24. x  2; y  1; z  3

25. c

29.

7. x  1.2; y  3.6; z  2.7

1. a. One; many; no

21. No solution

x  2; y  1 4 5

1 § ; x  1; y  2; z  4 107 2 7 6 7§; 1 2

x  3; y  1; z  2

41. $9,274, $8,628, and $11,366 5. x  2; y  3; z  1; w  3

6. x  2; y  2

42. $2,300,000; $2,450,000; an increase of $150,000

7. a  3; b  4; c  2; d  2; e  3 8. x  1; y  2; z  1 8 9. £ 10 11

9 1 12

6 11. £ 12 24

18 6 0

11 13. £ 4 6

16 2 14

3 15. £ 2 74

17 56 78

1 10. £ 2 10

11 3§ 10 6 18 § 12 15 10 § 2

8 27 § 116

17. x  1; y  1

12. £

10 4 16

10 14 32

5 14. £ 2 26

16.

3 2 £ 112 7 2

3 11 § 2

7 5 8

2 1 3

18. x  1; y  3

18 26 § 4

20 20 10 5 11 § 0

19 8§ 30

800 43. a. A  c 600

1200 1400

400 600

50.26 31.00 ¥ b. B  ≥ 103.07 38.67

1500 d 2000

b. William: $176,641; Michael: $212,738 IBM Google Boeing 800 500 1200 44. a. A  c 500 600 2000

GM 1500 d 800

IBM Google Boeing 900 600 1000 B c 700 500 2100

GM 1200 d 900

IBM Google 100 100 b. C  c 200 100

Boeing 200 100

;

GM 300 Olivia d 100 Max

45. 30 of each type 46. Houston: 100,000 gallons; Tulsa: 600,000 gallons

ANSWERS TO CHAPTER 6 ODD -NUMBERED EXERCISES

21.

Chapter 5 Before Moving On, page 319

y

1. 1 23 ,23 , 53 2 2. a. (2, 3, 1) d. (0, 0, 0, 0)

b. No solution c. (2, 1  3t, t), t, a parameter e. (2  t, 3  2t, t), t, a parameter

3. a. (1, 2)

b. 1 47 , 57  2t, t2 , t, a parameter

4. a. c

4 d 6

3 5

3 5. £ 3 1

1 2 2 2 1

CHAPTER

b. c

14 14

3 5

7 d 1

c. c

x 5 0 4

5 1

3 d 11 Unbounded

5 6§ 2

6. (1, 1, 2)

23.

y

6

x –1

Exercises 6.1, page 327 1.

3.

y

3

y Bounded

No solution

25.

y x=3

x

6 4 2

5

x 2 –5

x 2 5.

7.

y

4

6

Bounded

y

x = –3 27.

4

y

x 2

x

2 x –4

4

–2

Unbounded 9.

y 29.

8

y

3x – 7y = – 24

x –6 x x + 3y = 8

Unbounded

11. x  1; x 5; y  2; y 4 13. 2x  y  2; 5x  7y  35; x 4

31.

y

15. x  y  10; 7x  4y 140; x  3y  30 17. x  y  7; x  2; y  3; y 7 19.

x

y

3 –4

4

Bounded x

–7 Unbounded

8

883

884

ANSWERS TO CHAPTER 6 ODD -NUMBERED EXERCISES

33.

15. Minimize C  2x  5y subject to 30x  25y  400 x  0.5y  10 2x  5y  40 x  0, y  0

y

x+y=4

17. Minimize C  1000x  800y subject to 70,000x  10,000y  2,000,000 40,000x  20,000y  1,400,000 20,000x  40,000y  1,000,000 x  0, y  0

6x + 5y = 30 x

Bounded 3x + y = 6 35.

y x – y = –6

x – 2y = –2

3 –6

x 6

Unbounded 37. False

39. True

Exercises 6.2, page 334 1. Maximize P  3x  4y subject to 6x  9y 300 5x  4y 180 x  0, y  0 3. Maximize P  2x  1.5y subject to 3x  4y 1000 6x  3y 1200 x  0, y  0 5. Maximize P  45x  20y subject to 40x  16y 3200 3x  4y 520 x  0, y  0 7. Maximize P  0.1x  0.12y subject to x  y 20 x  4y  0 x  0, y  0 9. Maximize P  50x  40y 1 1 subject to 200 x  200 y 1 1 1 x  100 300 y 1 x  0, y  0 11. Minimize C  14,000x  16,000y subject to 50x  75y  650 3000x  1000y  18,000 x  0, y  0 13. Minimize C  300x  500y subject to x  y  10 x 5 y 10 y 6 x0

19. Maximize P  0.1x  0.15y  0.2z subject to x  y  z 2,000,000 2 x  2y  8z 0 6 x  4y  4z 0 10x  6y  6z 0 x  0, y  0, z  0 21. Maximize P  18x  12y  15z subject to 2x  y  2z 900 3x  y  2z 1080 2x  2y  z 840 x  0, y  0, z  0 23. Maximize P  26x  28y  24z subject to 54 x  32 y  32 z 310 x  y  34 z 205 x  y  12 z 190 x  0, y  0, z  0 25. Minimize C  60x1  60x2  80x3  80x4  70x5  50x6 subject to x1  x2  x3 300 x4  x5  x6 250 x1  x4  200 x2  x5  150 x3  x6  200 x1  0, x2  0, . . . , x6  0 27. Maximize P  x  0.8y  0.9z subject to 8x  4z 16,000 8x  12y  8z 24,000 4y  4z 5000 z

800 x  0, y  0, z  0 29. False

Exercises 6.3, page 345 1. Max: 35; Min: 5

3. No max. value; Min: 27

5. Max: 44; Min: 15

7. x  0; y  6; P  18

9. Any point (x, y) lying on the line segment joining 1 52 , 0 2 and (1, 3); P5 11. x  0; y  8; P  64 13. x  0; y  4; P  12 15. x  2; y  1; C  10 17. Any point (x, y) lying on the line segment joining (20, 10) and (40, 0); C  120 19. x  14; y  3; C  58 21. x  3; y  3; C  75 23. x  15; y  17.5; P  115

ANSWERS TO CHAPTER 6 ODD -NUMBERED EXERCISES

25. x  10; y  38; P  134

17. x  0, y  4, z  4, u  0, √  0; P  36

27. Max: x  6; y 

19. x  0, y  3, z  0, u  90, √  0, w  75; P  12

33 2;

P  258; Min: x  15; y  3; P  186

29. 20 product A, 20 product B; $140

21. x  15, y  3, z  0, u  2, √  0, w  0; P  78

31. 120 model A, 160 model B; $480

23. x  54 , y  152 , z  0, u  0, √  154 , w  0; P  90

33. 40 tables; 100 chairs; $3800

25. x  2, y  1, z  1, u  0, √  0, w  0; P  87

35. $16 million in homeowner loans, $4 million in auto loans; $2.08 million 37. 50 fully assembled units, 150 kits; $8500 39. Saddle Mine: 4 days; Horseshoe Mine: 6 days; $152,000

885

29. No model A, 2500 model B; $100,000 31. 65 acres of crop A, 80 acres of crop B; $25,750; no 33. $62,500 in the money market fund, $125,000 in the international equity fund, $62,500 in the growth-and-income fund; $25,625

41. Reservoir: 4 million gallons; pipeline: 6 million gallons; $4200

35. 180 units of product A, 140 units of product B, and 200 units of product C; $7920; no

43. Infinitely many solutions; 10 oz of food A and 4 oz of food B or 20 oz of food A and 0 oz of food B, etc., with a minimum value of 40 mg of cholesterol

37. 22 min of morning advertising time, 3 min of evening advertising time

45. 30 in newspaper I, 10 in newspaper II; $38,000

39. 80 units of model A, 80 units of model B, and 60 units of model C; maximum profit: $5760; no

47. 80 from I to A, 20 from I to B, 0 from II to A, 50 from II to B 49. $22,500 in growth stocks and $7500 in speculative stocks; maximum return; $5250 51. 750 urban, 750 suburban; $10,950 53. False 59. a.

55. a. True

41. 9000 bottles of formula I, 7833 bottles of formula II, 6000 bottles of formula III; maximum profit: $4986.60; Yes, ingredients for 4167 bottles of formula II 43. Project A: $800,000, project B: $800,000, and project C: $400,000; $280,000

b. True

45. False

y

47. True

Using Technology Exercises 6.4, page 376 1. x  1.2, y  0, z  1.6, w  0; P  8.8 3. x  1.6, y  0, z  0, w  3.6; P  12.4

Exercises 6.5, page 384 1. x  4, y  0; C  8 3. x  4, y  3; C  18 x

5. x  0, y  13, z  18, w  14; C  111 7. x  54 , y  14 , u  2, √  3; C  P  13

b. No solution

Exercises 6.4, page 367 1. In final form; x  307 , y  207 , u  0, √  0; P  220 7 3. Not in final form; pivot element is 12, lying in the first row, second column. 5. In final form; x  13 , y  0, z  133 , u  0, √  6, w  0; P  17 7. Not in final form; pivot element is 1, lying in the third row, second column. 9. In final form; x  30, y  10, z  0, u  0, √  0; P  60; x  30, y  0, z  0, u  10, √  0; P  60; among others 11. x  0, y  4, u  0, √  1; P  16 13. x  6, y  3, u  0, √  0; P  96 15. x  6, y  6, u  0, √  0, w  0; P  60

9. x  5, y  10, z  0, u  1, √  2; C  P  80 11. Maximize P  4u  6√ subject to u  3√ 2 2u  2√ 5; u  0, √  0

x  4, y  0; C  8

13. Maximize P  60u  40√  30w subject to 6u  2√  w 6 u  √  w 4; x  10, y  20; C  140 u  0, √  0, w  0 15. Maximize P  10u  20√ subject to 20u  √ 200 10u  √ 150; u  2√ 120 u  0, √  0

x  0, y  0, z  10; C  1200

17. Maximize P  10u  24√  16w subject to u  2√  w 6 2u  √  w 8; x  8, y  0, z  8; C  80 2u  √  w 4 u  0, √  0, w  0

886

ANSWERS TO CHAPTER 7 ODD -NUMBERED EXERCISES

19. Maximize P  6u  2√  4w subject to 2u  6√

30 4u  6w 12; 3u  √  2w 20 u  0, √  0, w  0

20. x  0, y  2, z  0, u  1, √  0, w  0, and C  4 4

x  13 , y  3 , z  0; C  26

21. $40,000 in each company; P  $13,600 22. 60 model A clock radios; 60 model B clock radios; P  $1320

21. 2 type-A vessels; 3 type-B vessels; $250,000

23. 93 model A, 180 model B; P  $456

23. 30 in newspaper I; 10 in newspaper II; $38,000

24. Saddle Mine: 4 days; Horseshoe Mine: 6 days; $152,000

25. 8 oz of orange juice; 6 oz of pink grapefruit juice; 178 calories 27. True

25. $70,000 in blue-chip stocks; $0 in growth stocks; $30,000 in speculative stocks; maximum return: $13,000

Using Technology Exercises 6.5, page 390

26. 0 unit product A, 30 units product B, 0 unit product C; P  $180

Chapter 6 Before Moving On, page 393

1. x  1.333333, y  3.333333, z  0; and C  4.66667 3. x  0.9524, y  4.2857, z  0; C  6.0952

1. Min: x  3, y  16; C  7; Max: x  28, y  8; P  76

Chapter 6 Concept Review Questions, page 390 b. ax  by c; ax  by  c

1. a. Half plane; line 2. a. Points; each

2. Max: x  0, y  247 ; P  727 3.

x

y

z

u

v

w

P

2 1 3

1 2 2

1 3 4

1 0 0

0 1 0

0 0 1

0 0 0

1

2

3

0

0

0

1

b. Bounded; enclosed

3. Objective function; maximized; minimized; linear; inequalities 4. a. Corner point

b. Line

6. Equations; slack variables; c1x1  c2x2      cn xn  P  0; below; augmented

0

5. Max: x  6, y  2; P  34

CHAPTER

7. Minimized; nonnegative; greater than; equal to

7

Exercises 7.1, page 402

8. Dual; objective; optimal value

1. {x 0 x is a gold medalist in the 2010 Winter Olympic Games}

Chapter 6 Review Exercises, page 391

3. {x 0 x is an integer greater than 2 and less than 8}

1. Max: 18—any point (x, y) lying on the line segment joining (0, 6) to (3, 4); Min: 0

5. {2, 3, 4, 5, 6} 9. a. True

3. x  0; y  4; P  20

13. True

4. x  0; y  12; P  36 5. x  3; y  4; C  26

3 1 17

4. x  2; y  0; z  11; u  2; v  0; w  0; P  28

5. Maximized; nonnegative; less than; equal to

2. Max: 27; Min: 7



Constant

7. {2}

b. False 15. a. True

11. a. False

b. False

b. False

17. a. and b. 6. x  1.25; y  1.5; C  9.75 63. a. 0.9 thousand metric tons/yr; 20.3 thousand metric tons/yr b. Yes

7. x  3; y  10; P  29

8. x  8; y  0; P  48

9. x  20; y  0; C  40

10. x  2; y  6; and C  14

11. Max: x  22; y  0; Q  22; Min: x  3; y 

5 ; 2

Q

11 2

12. Max: x  12; y  6; Q  54; Min: x  4; y  0; Q  8 13. x  3, y  4, u  0, √  0, and P  25 14. x  3, y  6, u  4, √  0, w  0, and P  36

19. a. , {1}, {2}, {1, 2} b. , {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3} c. , {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4} 21. {1, 2, 3, 4, 6, 8, 10} 23. {Jill, John, Jack, Susan, Sharon} 25. a.

U

15. x  565 , y  25 , z  0, u  0, √  0, and P  2335 16. x  0, y  113 , z  256 , u  376 , √  0, w  0, and P  119 6 17. x  23 , y  1, u  14 , √  54 , and C  132 36 2 104 18. x  32 11 , y  11 , u  11 , √  0, and C  11

19. x  34 , y  0, z  74 , u  6, √  6, and C  60

A B C

ANSWERS TO CHAPTER 7 ODD -NUMBERED EXERCISES

b.

b.

U

U A

A

887

B

B C

c.

U

33. a. {2, 4, 6, 8, 10} b. {1, 2, 4, 5, 6, 8, 9, 10} c. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} 35. a. C  {1, 2, 4, 5, 8, 9} b.  c. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

A, B, C

37. a. Not disjoint

27. a.

U A

U A

39. a. The set of all employees at Universal Life Insurance who do not drink tea b. The set of all employees at Universal Life Insurance who do not drink coffee 41. a. The set of all employees at Universal Life Insurance who drink tea but not coffee b. The set of all employees at Universal Life Insurance who drink coffee but not tea

B

b.

43. a. The set of all employees in a hospital who are not doctors b. The set of all employees in a hospital who are not nurses 45. a. The set of all employees in a hospital who are female doctors b. The set of all employees in a hospital who are both doctors and administrators

B

47. a. D  F 49. a. B c 29. a.

U A

b. Disjoint

B

C

b. R  Fc  Lc b. A  B

c. A  B  Cc

51. a. A  B  C; the set of tourists who have taken the underground, a cab, and a bus over a 1-wk period in London b. A  C; the set of tourists who have taken the underground and a bus over a 1-wk period in London c. Bc; the set of tourists who have not taken a cab over a 1-wk period in London 53.

b.

U A

B

U A

B

C U 31. a.

U A

B

C

A

B

888

ANSWERS TO CHAPTER 7 ODD -NUMBERED EXERCISES

55.

19. a. 17,576,000

U A

b. 17,576,000

21. 1024; 59,049

B

25. 217

23. 2730

27. True

Exercises 7.4, page 426

C

1. 360 U A

B

7. 20

9. n

13. 35

15. 1

19.

U A

B

5. 120 11. 1

n1n  1 2

C

57.

3. 10

17. 84 n! 2

21.

2

23. Permutation

25. Combination

27. Permutation

29. Combination

31. P(4, 4)  24

33. P(4, 4)  24

35. P(9, 9)  362,880 39. 151,200

C

43. 20

37. C(12, 3)  220

41. 2520

45. C(12, 3)  220

47. C(100, 3)  161,700 51. P(12, 6)  665,280

U A

B

53. a. P(10, 10)  3,628,800 b. P(3, 3)P(4, 4)P(3, 3)P(3, 3)  5184 55. a. P(20, 20)  20! b. P(5, 5)P[(4, 4)]5  5!(4!)5  955,514,880

C

61. a. x, y, √, r, w, u 63. a. s, t, y 67. False

57. a. P(12, 9)  79,833,600 b. C(12, 9)  220 c. C(12, 9) ⭈ C(3, 2)  660

b. √, r 65. A  C

b. t, z, w, x, s 69. True

59. 2{C(2, 2)  [C(3, 2)  C(2, 2)]}  6

71. True

61. C(3,3)[C(8, 6)  C(8, 7)  C(8, 8)]  37 63. a. C(12, 3)  220 b. C(11, 2)  55 c. C(5, 1)C(7, 2)  C(5, 2)C(7, 1) C(5, 3)  185

Exercises 7.2, page 408 3. a. 4

b. 5

c. 7

d. 2

65. P(7, 3)  C(7, 2)P(3, 2)  336

7. 20 9. a. 140 11. 13

67. C(5, 1)C(3, 1)C(6, 2)[C(4, 1)  C(3, 1)]  1575 b. 100 13. 0

c. 60

15. 13

19. a. 106

b. 64

21. a. 182

b. 118

69. 10C(4, 1)  40 17. 61

c. 38 c. 56

25. a. 64

b. 10

27. a. 36

31. a. 62

b. 33

c. 25

33. a. 108

b. 15

c. 45

35. a. 22

b. 80

37. True

39. True

71. C(4, 1)C(13, 5)  40  5108

d. 14

73. 13C(4, 3) ⭈ 12C(4, 2)  3744

d. 18

23. 30

b. 36 d. 38

7. 24 15. 400

29. 5

75. C(6, 2)  15 77. C(12, 6)  C(12, 7)  C(12, 8)  C(12, 9)  C(12, 10)  C(12, 11)  C(12, 12)  2510 79. 4!  24

d. 12

83. True

85. True

Using Technology Exercises 7.4, page 431 1. 1.307674368  1012

Exercises 7.3, page 415 1. 12

49. P(6, 6)  720

3. 64

5. 674,274,182,400

9. 60

5. 24

17. 9990

11. 1 billion

9. 4,656,960 13. 5

50

11. 658,337,004,000

3. 2.56094948229  1016 7. 133,784,560

ANSWERS TO CHAPTER 7 ODD -NUMBERED EXERCISES

Exercises 7.5, page 436

b.

1. {a, b, d, f }; {a}

3. {b, c, e}; {a}

9. 

13. Yes

11. Yes

5. No

15. E  F

Cars, x 0 x 200 200 x 400 400 x 600 600 x 800 800 x 1000 x  1000

7. S 17. G c

19. (E  F  G)c 21. a. {(2, 1), (3, 1), (4, 1), (5, 1), (6, 1), (3, 2), (4, 2), (5, 2), (6, 2), (4, 3), (5, 3), (6, 3), (5, 4), (6, 4), (6, 5)} b. {(1, 2), (2, 4), (3, 6)}

19. .469

23. , {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, S

25. a.

25. a. S  {B, R}

29. a. .633

b. , {B}, {R}, S

29. a. No

35. a. E c b. E c  F c c. E  F d. (E  F c)  (E c  F)

41. a. S  {0, 1, 2, . . . , 20} b. E  {0, 1, 2, . . . , 9}

b. .255

1 6

45. a.

1.

1 2

9.

3 13

3.

1 36

11.

19

5. 12 13

c. 1

47. True

7.

1 52

13. .002; .998

c. F  {20}

21. E C  F C  {e}   23. P[(G  C c)]  1  P(G)  P(C); he has not considered the case in which a customer buys both glasses and contact lenses. 25. a. 0 1 3 2, 8

b. .7

31. a. .24

b. .46

35. a. .41

b. .518

7. {(A, Rh)}, {(A, Rh)}, {(B, Rh)}, {(B, Rh)}, {(AB, Rh)}, {(AB, Rh)}, {(O, Rh)}, {(O, Rh)} A .10

B .25

Falling behind .40

Staying even .44

Favor .47

C .45

39. a. .439

D .15

F .05

Increasing faster .12 Oppose .46

Don’t know .04 Don’t know .07

b.

c. .8

1 5 2, 8

5. {(1, i)}, {(1, d )}, {(1, s)}, {(2, i)}, {(2, d )}, {(2, s)}, . . . , {(5, i)}, {(5, d)}, {(5, s)}

Opinion Probability

5 6

Exercises 7.7, page 454

27. a.

13.

39. .783

b.

3. {(D, m)}, {(D, f )}, {(R, m)}, {(R, f )}, {(I, m)}, {(I, f )}

Answer Probability

b. .23

19. The two events are not mutually exclusive; hence, the probability of the given event is 16  16  361  11 36 .

1. {(H, H)}, {(H, T)}, {(T, H)}, {(T, T)}

11.

b. .33

17. Since the five events are not mutually exclusive, Property (3) cannot be used; that is, he could win more than one purse.

b. E  {0, 1, 2, 3}

Exercises 7.6, page 444

Grade Probability

27.

15. P(a)  P(b)  P(c)  1

c. 5t 0 t  26

47. False

9.

23. .46

3 8

31. a. .35

35. a. .4

43. No

33. a. {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} b. 6 c. 3 d. 6

39. a. S  {0, 1, 2, 3, . . . , 10} c. F  {5, 6, 7, 8, 9, 10}

c.

b. .144

1 13

41. There are six ways of obtaining a sum of 7.

31. S  {ddd, ddn, dnd, ndd, dnn, ndn, nnd , nnn}

b. 5t 0 0 t 26

1 2

b. .276

37. a. .448

b. No

37. a. 5t 0 t  06

b.

33. .530

27. a. S  {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)} b. {(H, 2), (H, 4), (H, 6)}

Probability .075 .1 .175 .35 .225 .075

21. a. .856

1 4

889

c.

d. .3 1 8

3 4

d.

33. a. .16

b. .385

29. .332 b. .38

37. a. .52

b. .34

41. b. .52

43. a. .90

b. .40

c. .40

45. a. .6

b. .332

c. .232

49. True

51. False

c. .22

c. .859

d. .6

Chapter 7 Concept Review Questions, page 460 1. Set; elements; set

2. Equal

4. a. No

5. a. Union

b. All

6. Complement

3. Subset b. Intersection

7. AC  B C  C C

8. Permutation; combination 15. Event Probability

A .026

B .199

C .570

17. a. S  {(0 x 200), (200 x 400), (400 x 600), (600 x 800), (800 x 1000), (x  1000)}

D .193

E .012

9. Experiment; sample; space; event

10. 

11. Uniform;

Chapter 7 Review Exercises, page 460 1. {3} 4. {4}

2. {A, E, H, L, S, T } 5. Yes

6. Yes

3. {4, 6, 8, 10} 7. Yes

8. No

1 n

890

ANSWERS TO CHAPTER 8 ODD -NUMBERED EXERCISES

9.

43. 720

U A

44. 1050

46. a. 487,635

B

45. a. 5040

b. 550

47. a. C(15, 4)  1365 C

48. a. .019

(B

A

U

2. 360

B

b. {b, c, d, e, f, g}

3. 200

CHAPTER

C B

b. C(15, 4)  C(10, 4)  1155

b. .981

1. a. {d, f, g}

10.

(A

c. 341,055

Chapter 7 Before Moving On, page 462

C)

A

b. 3600

4.

5 12

c. {b, c, e} 4 13

5.

6. a. .9

b. .3

8

Exercises 8.1, page 468 1.

C )C

1 32

3.

31 32

5. P(E)  13C(4, 2)/C(52, 2)  .059

11.

U A

7. C(26, 2)/C(52, 2)  .245

B

9. [C(3, 2)C(5, 2)]/C(8, 4)  3/7 11. [C(5, 3)C(3, 1)]/C(8, 4)  3/7

C

17. C(10, 6)/210  .205

15. 1/8 AC

BC

CC

12.

19. a. C(4, 2)/C(24, 2)  .022 b. 1  C(20, 2)/C(24, 2)  .312

U A

21. a. C(6, 2)/C(80, 2)  .005 b. 1  C(74, 2)/C(80, 2)  .145

B

23. a. .12; C(98, 10)/C(100, 12)  .013 b. .15; .015

C AC

(B C

25. [C(12, 8)C(8, 2)  C(12, 9)C(8, 1)  C(12, 10)]/C(20, 10)  .085

CC )

27. a. 17. The set of all participants in a consumer-behavior survey who both avoided buying a product because it is not recyclable and boycotted a company’s products because of its record on the environment. 18. The set of all participants in a consumer-behavior survey who avoided buying a product because it is not recyclable and/or voluntarily recycled their garbage. 19. The set of all participants in a consumer-behavior survey who both did not use cloth diapers rather than disposable diapers and voluntarily recycled their garbage.

29.

b. C(3, 1)/C(5, 3)  .3

3 5

1 729

31. .0001

37. [4C(13, 5)  40]/C(52, 5)  .00197 39. [13C(4, 3) ⭈ 12C(4, 2)]/C(52, 5)  .00144 41. a. .618

b. .059

43. .030

Exercises 8.2, page 481 1. a. .4

b. .33

3. .3

11. a. .5

b. .4

c. .2

21. 150

22. 230

13. a. .4

b. .3

c. .12

27. 190

28. 181,440

29. 120

31. a. 0

b. .6

d. .4

23. 270

24. 30

b. .65

c. .05

33. a. .49

b. .39

c. .48

34.

9. a. .24

b. .76 d. .35

b. 377

39. a. 50,400

e. No

d. .30

30. 8400

f. No

e. Yes .3

f. Yes C

A .4

.7

.6

.3

D C

B

35. None

36. a. 446

41. 80

26. 200

7. Independent

5. Independent

e. 1

32. a. .35

2 7

25. 70

c. 1  C(3, 3)/C(5, 3)  .9 35. 40/C(52, 5)  .0000154

33. .1

20. The set of all participants in a consumer-behavior survey who did not boycott a company’s products because of the company’s record on the environment and/or who do not voluntarily recycle their garbage.

c. .6

13. C(3, 2)/8  3/8

c. 34

b. 5040

42. a. 1287

37. 720

40. a. 60 b. 288

.7

38. 20 b. 125

15. a. 17.

4 11

1 12

b.

1 36

c.

1 6

19. Independent

d.

1 6

D

e. No

21. Not independent

23. .1875

891

ANSWERS TO CHAPTER 8 ODD -NUMBERED EXERCISES

25. a.

4 9

4 9

b.

27. a.

1 21

1 3

b.

29. .25

31.

1 7

33. a. R

.24

.16

P

.64

r N

.58

P  Professional A  Amateur R  Recovered within 48 hr r  Recovered after 48 hr N  Never recovered

r

.04

N b. .24

c. .3984

35. a. .16

b. .424

37. a. .092

c. .1696

39. a. .28; .39; .18; .643; .292

47. 3

51. 1

45. a. .4906

b. .62

c. .186

47. .927

1. a. See part (b) b. Outcome Value

GGG 3

GGR 2

GRG 2

RGG 2

Outcome Value

GRR 1

RGR 1

RRG 1

RRR 0

c. {GGG} 3. Any positive integer

5.

1 6

7. Any positive integer; infinite discrete 9. x  0; continuous

b. .008

41. Not independent

c. .724

R

.38

A

b. .276

Exercises 8.4, page 499

.60

.36

43. a. .763

11. Any positive integer; infinite discrete

b. Not independent

43. .0000068 55. False

45. a.

7 10

b.

1 5

13. a. .20

b. .60

c. .30

d. 1

15.

57. True

Exercises 8.3, page 489 1.

.57

D

.43

Dc

.71

D

.29

Dc

.33

D

A ) P(A

35 =.

P(B) = .35 P(C )=

x 12 13 14 15 16 17 18 19 20 17. a.

B

.30

C .67

3. a. .45

b. .2222

7. a. .08

b. .15

9. a. 11.

1 12

4 17

1 4

b. 13.

5. a. .48

Dc

c.

d.

3 14

4 51

15.

4 9

2 5

3 5

W

B

1 3

W

2 3

B

2

3

4

5

6

P(X  x)

1 6

1 6

1 6

1 6

1 6

1 6

y

1

2

3

4

5

6

P(Y  y)

1 6

1 6

1 6

1 6

1 6

1 6

xy

2

3

4

5

6

7

P(X  Y  x  y)

1 36

2 36

3 36

4 36

5 36

6 36

xy

8

9

10

11

12

P(X  Y  x  y)

5 36

4 36

3 36

2 36

1 36

19. a.

W 5 9

1

b.

b. .33

c. .348 1 18

x

B

x P(X  x)

0 .017

1 .067

2 .033

3 .117

4 .233

x P(X  x)

5 .133

6 .167

7 .100

8 .050

9 .067

b. .2

17.

9 17

19. .422

21. a.

43

b.

27. a. .543

b. .545

c. .455

31. a. .297

b. .10

33. .856

39. .172

41. .301

37. .647

2 9

23. .125

25. .407 .1

29. .377 35. a. .57

b. .691

x 0 1 2 3 4 5 6 7 8 9 10

10 .017

892

ANSWERS TO CHAPTER 8 ODD -NUMBERED EXERCISES

21. x P(X  x)

1 .007

2 .029

3 .021

4 .079

5 .164

x P(X  x)

6 .15

7 .20

8 .207

9 .114

10 .029

21. City B

23. Company B

27. 5.3¢

29. 2.7¢

33. .4

35.

7 12

37.

25. 2.86%

31. 2 to 3; 3 to 2 5 14

39. a. Mean: 74; mode: 85; median: 80 41. 3; close

23. True

43. 16; 16; 16

b. Mode

45. True

Exercises 8.6, page 522

Using Technology Exercises 8.4, page 503

1. ␮  2, Var(X)  1, ␴  1

Graphing Utility

3. ␮  0, Var(X)  1, ␴  1

1.

5. ␮  518, Var(X)  1891, ␴  43.5 7. Figure (a)

9. 1.56

11. ␮  4.5, Var(X)  5.25 13. a. Let X  the annual birthrate during the years 1991–2000 b.

3.

x P(X  x)

14.5 .2

14.6 .1

14.7 .2

14.8 .1

15.2 .1

15.5 .1

15.9 .1

16.3 .1

c. ␮  15.07, Var(X)  0.3621, ␴  0.6017 15. a. Mutual fund A: ␮  $620, Var(X)  267,600; Mutual fund B: ␮  $520, Var(X)  137,600 b. Mutual fund A c. Mutual fund B

Excel 1.

Probability

Histogram 0.4

17. 1

0.3

19. ␮  $339,600; Var(X)  1,443,840,000; ␴  $37,998

0.2 21. 95.3%; 0.5%

25. 207.2 billion; 4.5 billion

27. ␮  1607; ␴  182

0 1

2

3

4

29. ␮  5.452; ␴  0.1713

X

31. 16.88 million; 0.68 million

3. Histogram

33. a. At least .75 b. At least .96

0.25 0.2 Probability

23. 48%; 13.9%

0.1

35. 7

37. At least 167

0.15 39. At least 15 16

0.1

41. True

Using Technology Exercises 8.6, page 528

0.05 0 1

2

3

4

5

6 X

7

8

9

10

4 .2

; 2.6

11

1. a.

b. ␮  4, ␴  1.40

3. a.

b. ␮  17.34, ␴  1.11

Exercises 8.5, page 513 1. a. 2.6 b. x P(X  x) 3. 0.86 9. 0.12 15. 39¢

5. $78.50 11. 1.73 17. $50

0 0

1 .1

2 .4

7. 0.91 13. 5.16% 19. $118,800

3 .3

893

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

5. a. Let X denote the random variable that gives the weight of a carton of sugar. b. x 4.96 4.97 4.98 4.99 5.00 5.01 P(X  x) x

3 30

4 30

4 30

1 30

1 30

5.02

5.03

5.04

5.05

5.06

3 30

3 30

4 30

1 30

1 30

P(X  x)

5 30

Chapter 8 Before Moving On, page 531 1. .72

2. .3077

3.

4. a. .8

c. ␮  5.00; ␴  0.03

b. .92

CHAPTER

7. a.

3 .05

x P(X  x)

2 .1

0 .25

1 .3

2 .2

3 .1

5. 0.44; 4.0064; 2

9

Exercises 9.1, page 548

b. 65.875; 1.73

1. lim f 1x2  3

3. lim f 1x2  3

xS2

5. lim f 1x2  3

xS3

xS2

7. The limit does not exist. 9.

Chapter 8 Concept Review Questions, page 529 1. Conditional

2. Independent

4. Random

5. Finite; infinite; continuous

P1E2

6. Sum; .75

a b. ab

P1E c 2

7. a.

3. A posteriori probability

7. a.

2. .25 b.

9. .150

11.

13. .2451

3. .06

1.999 4.9960

x f(x)

2.001 5.004

2.01 5.0401

2.1 5.41

x f(x)

0.1 1

0.01 1

0.001 1

x f(x)

0.001 1

0.01 1

0.1 1

4. .367

5. .49

6. .364

The limit does not exist.

7 8

10.

1.99 4.9601

lim 1x 2  1 2  5

Chapter 8 Review Exercises, page 530

7 8

1.9 4.61

xS2

8. p1(x1  ␮)2  p2(x2  ␮)2      pn(xn  ␮)2; 2Var1X2

1. .18

x f(x)

c. No 2 15

8. a. .284

11. .00018

b. .984 13.

12. .00995

x f(x)

0.9 100

0.99 10,000

0.999 1,000,000

x f(x)

1.001 1,000,000

1.01 10,000

1.1 100

14. .510

15. a. {WWW, BWW, WBW, WWB, BBW, BWB, WBB, BBB} b. Outcome WWW BWW WBW WWB Value of X 0 1 1 1 Outcome Value of X

BBW 2

BWB 2

WBB 2

The limit does not exist. 15.

BBB 3

x f(x) lim xS1

c.

d.

x

0

1

2

3

P(X  x)

1 35

12 35

18 35

4 35

0.9 2.9

0.99 2.99

0.999 2.999

x2  x  2 3 x1 y

17.

x

20 35 16 35 12 35 8 35 4 35

lim f (x) = –1 x→0

0

1

16. $100

17. a. .8

18. .457

19. .368

22. At least .75

2

y

19.

x 3

1

b. ␮  2.7; ␴  1.42 20. a. .68

b. .053

x

21. .32

1 lim f(x) = 1 x→1

1.001 3.001

1.01 3.01

1.1 3.1

894

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

y

21.

89. False

91. True

93. True

95. a moles/liter/second

97. No

Using Technology Exercises 9.1, page 554

2

1. 5

x

3. 3

5.

1

2 3

7. e 2

11. a.

lim f(x) = 0 x→0

27. 1

23. 3

25. 3

35. 2

37. 1171  3119

45. 2

47.

1 6

39.

55. The limit does not exist.

57.

5 4

43. 6

53. 10

5 3

63. lim f 1x2  ; lim f 1x2  

33.

41. 1

3 2

51. 1

49. 2

xS

31. 4

29. 2

1 2

59.

61.

Exercises 9.2, page 563 65. 0; 0

xS

1. 3; 2; the limit does not exist.

67. lim f 1x2  ; lim f 1x2   xS

69.

x f(x)

1 0.5

10 0.009901

100 0.0001

1000 0.000001

x f(x)

1 0.5

10 0.009901

100 0.0001

1000 0.000001

lim f 1x2  0 and lim f 1x2  0

71.

3. The limit does not exist; 2; the limit does not exist.

xS

xS

xS

x f(x)

1 12

5 360

x f(x)

1000 2.999  109

x f(x)

10 3090

10 2910 1 6

100 2.99  106

100 3.01  106

73. 3

1000 3.0  109

77. lim f 1x2  

7. 2; 2; the limit does not exist. 13. False

79. 0

xS

81. a. $0.5 million; $0.75 million; $1,166,667; $2 million; $4.5 million; $9.5 million b. The limit does not exist; as the percent of pollutant to be removed approaches 100, the cost becomes astronomical.

Cents

19. True

21. 6

27. 1

29. 0

31. 4

33. The limit does not exist.

35. 4

37. 0; 0

39. x  0; conditions 2 and 3

1 22



1 12 ,

53. (, )

41. Continuous everywhere

45. 1, 2

2

47. (, )

51. 1, 2 2  12, 12  11,  2

55. (, )

57. 1 and 1

59. 1 and 2

61. f is discontinuous at x  1, 2, . . . , 12. 63. Michael makes progress toward solving the problem until x  x1. Between x  x1 and x  x2, he makes no further progress. But at x  x2 he suddenly achieves a breakthrough, and at x  x3 he proceeds to complete the problem. 65. Conditions 2 and 3 are not satisfied at each of these points.

y

67.

100 80

b. $120 million

87. a. 147.5¢/mi; 71.7¢/mi; 55.1¢/mi; 48.6¢/mi; 45.4¢/mi b. C(x) 160 140 120 100 80 60 40 20 x 5 10 15 20 c. It approaches 38.6¢/mi.

17. False

11. True

25. The limit does not exist.

23.

83. $2.20; the average cost of producing x DVDs will approach $2.20/disc in the long run. 85. a. $24 million; $60 million; $83.1 million

15. True

9. True

14

49. 1,

xS

75. 3

5. 0; 2; the limit does not exist.

43. x  0; condition 3

5 390

lim f 1x2   and lim f 1x2  

xS

b. 25,000

1 3

60 40 20 x 5

10

15

20

y

69. 10 8 6 4 2

x 1

2

3

4

5

6

f is discontinuous at x  12 , 1, 112 , p , 4.

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

71. a. ; As the time taken to excite the tissue is made smaller and smaller, the strength of the electric current gets stronger and stronger. b. b; As the time taken to excite the tissue is made larger and larger, the strength of the electric current gets smaller and smaller and approaches b. 73. 3

75. a. Yes

b. No

77. a. f is a polynomial of degree 2.

b. f(1)  3 and f(3)  1

79. a. f is a polynomial of degree 3.

b. f(1)  4 and f(1)  4

81. x  0.59 85. c.

1 7 2; 2;

Joan sees the ball on its way up 12 sec after it was thrown and again 312 sec later.

87. False 97. No

89. False 99. c.

91. False

93. False

95. False

12 2

Using Technology Exercises 9.2, page 569 1. x  0, 1

27. a. 6; 5.5; 5.1 b. 5 c. The computations in part (a) show that as h approaches zero, the average velocity approaches the instantaneous velocity. 29. a. 130 ft/sec; 128.2 ft/sec; 128.02 ft/sec b. 128 ft/sec c. The computations in part (a) show that as the time intervals over which the average velocity are computed become smaller and smaller, the average velocity approaches the instantaneous velocity of the car at t  20. 31. a. 5 sec

b. 80 ft/sec

c. 160 ft/sec b. 14 liter/atmosphere

33. a. 16 liter/atmosphere

83. 1.34

3. x  0, 12

5. x  12 , 2

9.

7. x  2, 1

11.

35. a. 23 x  7

b. $333/quarter; $13,000/quarter

37. $6 billion/yr; $10 billion/yr 39. a. f(h) gives the instantaneous rate of change of the temperature at a given height h. b. Negative c. 0.05°F 41. Average rate of change of the seal population over [a, a  h]; instantaneous rate of change of the seal population at x  a 43. Average rate of change of the country’s industrial production over [a, a  h]; instantaneous rate of change of the country’s industrial production at x  a 45. Average rate of change of atmospheric pressure over [a, a  h]; instantaneous rate of change of atmospheric pressure at x  a

Exercises 9.3, page 582 3. 3.1%/hr; 21.2%/hr

1. 1.5 lb/mo; 0.58 lb/mo; 1.25 lb/mo 5. a. Car A c. Car B

b. They are traveling at the same speed. d. Both cars covered the same distance.

47. a. Yes

b. No

c. No

49. a. Yes

b. Yes

c. No

51. a. No

b. No

c. No

53. 32.1, 30.939, 30.814, 30.8014, 30.8001, 30.8000; 30.8 ft/sec 55. False y

57. 7. a. P2 9. 0

b. P1 11. 2

c. Bactericide B; bactericide A 15. 2x  3

13. 6x

19. 6; y  6x  3

17. 2; y  2x  7

21. 19 ; y  19 x  23

b. y  4x  1 y

23. a. 4x c.

1 x

−1 59. a  2, b  1 y 40

x

30 25. a. 2x  2 c.

b. (1, 0)

20

y

10

10 −5

5

x 1 d. 0

2

3

4

895

x 5

10

896

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

Using Technology Exercises 9.3, page 588 1. a. y  9x  11 b.

y

c.

3. a. y  14 x  1 b. (2, 9) x (– 2, – 7)

5. a. 4 b. y  4x  1 c.

3 –10

49. a. 10, 0 2; 11, 13 b. 10, 0 2 ; 12, 83 2 ; 11, 125 2 12 2 c. 10, 02; 14, 803 2; 13, 814 2

7. a. 4.02 b. y  4.02x  3.57 c.

51. a.

16p cm 3/cm 9

b.

25p cm 3/cm 4

53. a. 16.3 million b. 14.3 million/yr d. 11.7 million/yr 55. a. 49.6%; 41.13%; 36.87%; 34.11% b. 5.55%/yr; 3.32%/yr

9. a.

57. a. 157 million 59. a. 120  30t

b. 10.4 million/yr b. 120 ft/sec

61. a. 5%; 11.3%; 15.5% b. 41.22¢/mi

1. 0

3. 5x

3 2 1x

4

5. 2.1x

15. 84x13

21. 0.06x  0.4 27.  33.  37. 3

3 x2 4 x3

 

7. 6x

8

29. 

16 t5

9. 2pr

17. 10x  3

23. 2x  4 

x3



9 t4

3 x2



2 t2

11.

3 x 2/3

19. 3x 2  4x

25. 16x 3  7.5x 3/2 31. 2 

5 2 1x

67. a.

10.0001 2 1 54 2 x 1/4

35. a. 20

x 4/3

b. 4

41. m  5; y  5x  4

39. 11

c. 20

b. 10 pts/yr

b. $0.00125/radio

69. a. 20 a 1 

1 b b. 50 mph; 30 mph; 33.43 mph 1t c. 8.28; 0; 5.86; at 6:30 a.m., the average velocity is decreasing at the rate of 8.28 mph/hr; at 7 a.m., it is unchanged; and at 8 a.m., it is increasing at the rate of 5.86 mph.

71. 32 turtles/yr; 428 turtles/yr; 3260 turtles 73. a. 12%; 23.9%

1

b. 0.63%/yr; 0.525%/yr

65. a. 15 pts/yr; 12.6 pts/yr; 0 pts/yr

1.1

c. 240 ft

63. a. 0.9 thousand metric tons/yr; 20.3 thousand metric tons/yr b. Yes

c. 1.22¢/mi/yr

Exercises 9.4, page 595

13.

c. 66.8 million

b. 0.8%/yr; 1.1%/yr

75. a. The total population, including the population of the developed countries and that of the underdeveloped/emerging countries b. 0.92t  3.727; 13 million people/yr

43. m  2; y  2x  2

77. True

45. a. (0, 0) b.

Using Technology Exercises 9.4, page 601 y 1. 1

3. 0.4226

5. 0.1613

7. a. 4 x 2

b. 3.4295 ppm/40 yr; 105.4332 ppm/40 yr 47. a. (2, 7), (2, 9) b. y  12x  17 and y  12x  15

9. a. f(t)  0.611t 3  9.702t 2  32.544t  473.5 b.

897

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

c. At the beginning of 2000, the assets of the hedge funds were increasing at the rate of $53.781 billion/yr, and at the beginning of 2003, they were increasing at the rate of $139.488 billion/yr.

0.211  t 2 2 1t 2  12 2

59. a.

b. 0.096%/hr; 0%/hr; 0.024%/hr

Exercises 9.5, page 611 61.

1. 2x(2x)  (x 2  1)(2), or 6x 2  2 3. (t  1)(2)  (2t  1)(1), or 4t  1

63. a. 

5. (3x  1)(2x)  (x  2)(3), or 9x  2x  6 2

6000

1t  12 2 2

2

; 18.5 mg/yr; 12.4 mg/yr x

b. 3.2; 2.5; 1.4

10.01x 2  12 2

7. (x 3  1)(1)  (x  1)(3x 2), or 4x 3  3x 2  1

65. $38.4 million/yr; $17.04 million/yr; $5.71 million/yr

9. (w 3  w 2  w  1)(2w)  (w 2  2)(3w 2  2w  1), or 5w 4  4w 3  9w 2  6w  2

67. a.

11. (5x 2  1)(x1/2)  (2x 1/2  1)(10x), or 1x  5x  2 2 1x  2 2 2

13.

1

15. 

1x  22 2

19. 

1x 2  12 2

23.

25.

27.

17.

2x

2



x

2x  1  1x  12 12 2 12x  1 2 2

3x  10x  4 4

, or

, or

3

12x  1 2 2

s 2  2s  4 1s  1 2 2

21.

1 12 x1/2 2 3 1x2  1 2  4x2 4  2x 1x2  1 2 2

, or

1  3x  4x

2 2x1x 2  1 2 2

1x 2  x  12 2

, or

x 2  2x  2

1x 2  x  1 2 2

1x  22 13x 2  2x  12  1x 3  x 2  x  12 1x  22 2

1x 2  4 2 2 1x 2  4 2 2

2x  24x  16x  32x  128 4

33. 9

4 7.2 0.6

5 7.5 0

6 7.2 0.6

7 6.3 1.2

71. 8.1 million; 0.204 million/yr; 0.03 million/yr2. At the beginning of 1998, there were 8.1 million people receiving disability benefits; the number was increasing at the rate of 0.2 million/yr; the rate of the rate of change of the number of people was decreasing at the rate of 0.03 million people/yr2. 77. False

Using Technology Exercises 9.5, page 617 1. 0.8750

5. 0.5000

3. 0.0774 9. 18

7. 87,322/yr

11. 15.2762

15. 0.1973

1. 8(2x  1)3

3. 10x(x 2  2)4

, or 5. 3(2x  x 2)2(2  2x), or 6x 2(1  x)(2  x)2 9. 3x2x 2  4

35. 2(3x 2  x  3); 10

3x4  2x 2  1

15. 

1 37. 4 ; 2 1x  2x 2  1 2 2 39. 60; y  60x  102

41.  21 ; y   21 x  23

45. 6x 2  6x; 6(2x  1)

47. 4t 3  6t 2  12t  3; 12(t 2  t  1)

53. y  7x  5

3 6.3

7. 

3

1x 2  4 2 2 1x 2  4 2 2

49. 72x  24

2 4.8

Exercises 9.6, page 625

1x 2  42 1x 2  4 2 12x  8 2  1x 2  8x  42 14x 3 2

43. 8x  2; 8

1 2.7

17. 68.46214; at the beginning of 1988, the rate of the rate of the rate at which banks were failing was 68 banks/yr/yr/yr.

1x  2 2 2

31. 8

0 0

13. 0.6255 , or

2

5

b. 20,790; 554

3/2

2x  5x  4x  3

29.

t N(t) N (t)

75. False 2

2x 3  2x 2  2x  2x 3  x 2  4x  2

3

3

x2

;

69. a. and b.

2x

1x  2 2 12x  5 2

2

x2

25x 2  10x 2x  1

80012t  5 2

1t 2  5t  40 2 2

51. 

6 x4

55. 1 13 , 50 27 2 ; (1, 2)

57. 1 43 ,  770 27 2 ; (2, 30)

6

12x  3 2

4

11.

3 2 13x  2

17. 

1

12t  3 2

3/2

13. 

4

12x  1 2 3

2x

311  x 2 2 2/3

19. 

3116x 3  1 2

214x 4  x 2 5/2

21. 2(3x 2  2x  1)3(6x  2)  4(3x  1)(3x 2  2x  1)3 23. 3(x 2  1)2(2x)  2(x 3  1)(3x 2), or 6x(2x 2  x  1) 25. 3(t 1 t 2)2(t 2  2t 3) 27.

1 1  2 1x  1 2 1x  1

29. 2x 2(4)(3  4x)3(4)  (3  4x)4(4x), or (12x)(4x  1)(3  4x)3 31. 8(x  1)2(2x  1)3  2(x  1)(2x  1)4, or 6(x  1)(2x  1)(2x  1)3

898

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

151x  32 2 x  3 2 1x  22 11 2  1x  32 112 b c d , or  x2 1x  2 2 2 1x  22 4

33. 3 a

35.

3 t a b 2 2t  1

1/2

c

12t  12 11 2  t122 12t  1 2 2

d , or

3t

81.

212t  12 5/2

39.

41.

43.

45.

4

2

3

12x 2 13x  1 2 2

, or

1x 2  1 2 8

Exercises 9.7, page 637

1x 2  12 5

1x  12

2

, or

9.

3x 2  2x  1

12x  11x 2  1 2 2

t 1 2

t 2  2t  1 2 1t  11t 2  12 3/2

3u5/3

; 6x  1;  2

27.

2e x

1e x  12 2

312x 3  x  12 5/3

u1/2  12 u3/2; 3x 2  1;

55. 12

57. 6

51.

13x  1 2 1x  x  12

45.

21x  x 2

3/2

57.

35.

61. y  33x  57

1

x2

e2x

5 x

25. e 3x2(3x  2)

37.

214x  3 2

53.

3x

47.

55.

39.

8 x

1 x1x  12

41.

1 2x

49. x(1  2 ln x)

1 2x2ln x

2

212  x 2 2

31. 6e 3x(3x  2)

1 x1

3 u2

x3  1

1 ew

3e1/x

19.

4x 2  6x  3

59.

x

13. 

29. 2(8e4x  9e 3x)

x2 31ln x2 2

7. x 2e x(x  3)

22x

211  ln x2

3

3

59. No

2 x

2

23.

33. y  2x  2 43. 

216x 2  1 2

2

1 2

17. 2xex

21. 25e x(e x  1)24

, or

5. e x  1

11. 3(e x  ex)

x2

u1/3; 6x; 8x13x 2  12 1/3

51. 

53.

2e x 1x  1 2

15. 6e 3x1

1t 2  1 2 1/2 1 12 2 1t  1 2 1/2 112  1t  1 2 1/2 1 12 2 1t 2  1 2 1/2 12t 2

2

3. et

1. 3e 3x

2

5. 4.9498

3. 0.9390

7. 10,146,200/decade; 7,810,520/decade

, or

2x13x 2  132 13x 2  1 2 2

12x  12 1/2 3 1x 2  12  12x  1 2 12x2 4

4 3

; 31,312 jobs/yr

87. True

1. 0.5774

47. 4(3x  1)3(3)(x 2  x  1)3  (3x  1)4(3)(x 2  x  1)2(2x  1), or 3(3x  1)3(x 2  x  1)2(10x 2  5x  3) 49.

13t 2  80t  550 2 2

d,

Using Technology Exercises 9.6, page 629

1x 2  1 2 5

2x1x 2  12 3 13x 2  1 2 2 391x 2  1 2  413x 2  1 2 4



1.421140t 2  3500t  21,000 2

85. True

2

1x 2  1 2 8



13t 2  80t  5502 2

83. 400 wristwatches/(dollar price increase)

1

1x  12 12x2  x 142 1x  1 2 12x2



or

2 1u  1 13u  2 2 3/2 2

13t 2  80t  550 2 114t  140 2  17t 2  140t  700 2 16t  802

11.42 2 c

1/2

1 u  1 1/2 13u  2 2 11 2  1u  12 132 37. a b c d , or 2 3u  2 13u  22 2 

79. 27 mph/decade; 19 mph

77. 160p ft2/sec

61.

1x ln x  1 2 e x x

63. y  435 x  545

63. 

65. 0.333 million/wk; 0.305 million/wk; 16 million; 22.7 million

69. 0.1694, 0.1549, 0.1415; the percentage of the total population relocating was decreasing at the rate of 0.17%/yr in 1970, 0.15%/yr in 1980, and 0.14%/yr in 1990.

6.87775

15  t2 0.795

67.

; 0.53%/yr; 64.9%

69. a. $8.7 billion/yr

b. 0.0091 ppm/yr

73. a. 0.03[3t 2(t  7)4  t 3(4)(t  7)3], or 0.21t 2(t  3)(t  7)3 b. 90.72; 0; 90.72; at 8 a.m. the level of nitrogen dioxide is increasing; at 10 a.m. the level stops increasing; at 11 a.m. the level is decreasing. 75. 300 c

1t  252 12 1 12 t 2  2t  25 2 1/2 1t  2 2  1 12 t 2  2t  252 1/2 112

or

1t  25 2 2

3450t 1t  252 2312 t 2  2t  25

65.

1x 2  22 2

71. a. 70,000; 353,700

b. $92.3 billion

71. a. 0.027(0.2t 2  4t  64)1/3(0.1t  1)

x

2

;

2.9 beats/min2, 0.7 beats/min2, 0.2 beats/min2, 179 beats/min

d,

67. y  x  1

b. 37,800/decade; 191,000/decade

73. a. 181/100,000 b. 0/100,000 people; 27/100,000 people; 38/100,000 people; 32/100,000 people c. 52/100,000 75. a. 0.094; 0.075 b. 0.151/hr; 0.021/hr 77. a. $6065/day; $3679/day; $2231/day; $1353/day b. 2 days 79. a. 1.63¢/bottle; 1.34¢/bottle b. $231.87/bottle; $217.03/bottle

81. 1.8/$1000 output/decade; 0.11/$1000 output/decade; 0.23/$1000 output/decade; 0.13/$1000 output/decade

d.

83. False

Using Technology Exercises 9.7, page 640 1. 5.4366

3. 12.3929

7. a. 50

5. 0.1861

Hundreds of thousands of dollars

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

899

C 30 20 10 x 1 3 5 7 Units of a thousand

c.

Hundreds of thousands of dollars

9. a.

Tens of thousands of dollars

R 30

30

20 10 x 4 8 12 Units of a thousand

b. 4.2720 billion/half century

P

11. a. 153,024; 235,181 b. 634; 18,401 13. a. 69.63%

b. 5.094%/decade

Exercises 9.8, page 649

20 10

1. a. C(x) is always increasing because as the number of units x produced increases, the amount of money that must be spent on production also increases. b. 4000 3. a. $1.80; $1.60

200,000 200,000 b.  x x2 c. C (x) approaches $100 if the production level is very high. 2000 2000  2  0.0001x;  2  0.0001 x x

9. a. 8000  200x

a. 0.000004x  0.03 

x2 b. 0.0132; 0.0092; the marginal average cost is negative (average cost is decreasing) when 5000 units are produced and positive (average cost is increasing) when 10,000 units are produced. c. y ($) 180

b. 200, 0, 200

c. $40 140

11. a. 0.04x 2  600x  300,000 b. 0.08x  600 c. 200; 40 d. The profit increases as production increases, peaking at 7500 units; beyond this level, profit falls.

100 x 5 10 Units of a thousand

P(x) 2 (millions of dollars)

80,000 x 80,000

15. 0.000002x 2  0.03x  400 

b. $1.80; $1.60

5. a. 100 

7.

x 1 3 5 7 Units of a thousand

50x

50  0.5x 2

0.01x  1 10.01x 2  12 2 c. $44,380; when the level of production is 2000 units, the revenue increases at the rate of $44,380 per additional 1000 units produced.

17. a.

1.5 1 .5 x (thousands) 2.5

5

7.5

10

12.5

15

–.5

2

b.

19. $1.21 billion/billion dollars

21. $0.288 billion/billion dollars

23. True

Chapter 9 Concept Review Questions, page 653 13. a. 600x  0.05x ; 0.000002x  0.02x  200x  80,000 b. 0.000006x 2  0.06x  400; 600  0.1x; 0.000006x 2  0.04x  200 c. 304; 400; 96 2

3

2

1. L; f (x); L; a r

2. a. L

b. L M

c. LM

d.

L ;M0 M

900

ANSWERS TO CHAPTER 9 ODD -NUMBERED EXERCISES

3. a. L; x

b. M; negative; absolute

4. a. Right

b. Left

5. a. Continuous 6. a. a; a; t(a)

9. a.

b. Everywhere

c. Every 29.

c. Q(x)

b. lim

h

f 1a  h2  f 1a2

c. cf (x)

b. nx n1

11. a. f (x)t(x)  t(x) f (x)

b.

35. 2x 

h

h씮0

12. a. t[ f (x)] f (x)

d. f (x) t(x) 37.

t1x2 f ¿1x2  f 1x2 t¿1x2 3 t1x2 4 2

38.

b. n[ f (x)]n1f (x)

13. Marginal cost; marginal revenue; marginal profit; marginal average cost 14. a. e f (x)f (x)

b.

f ¿1x2 f 1x2

2. 2

3. 21

12. 1

13.

3 2

41.

3

7. 7

8.

9 2

9. 1

10.

14. The limit does not exist.

1 2

2

33. 1 

x2 3



6

34. 4s 

t3

4 s2

12t 2  1 2 2

, or

, or

3

12x  1 2 2

1

1x 1/2  12 2

, or

1

2x 1 2x  1 2 2

1  2t 2

12t 2  12 2

, or

1x 2  1 2 14x 3  2x2  1x 4  x 2 2 12x2 1x  12

, or 

2 2t 1 2t  1 2 2

1x 1/2  12 1 12 x1/2 2  1x 1/2  1 2 1 12 x1/2 2

2

1 s 3/2

2t

1t 1/2  1 2 2

12t 2  1 2 2



t 5/2

12t 2  1 2 2

1t 1/2  1 2 12 t 1/2  t 1/2 1 12 t 1/2 2

12t 2  1 2 11 2  t14t2

6



t 3/2

12x  1 2 2

12t 2  1 2 12t2  t 2 14t2

44. 5(x 1/2  2)4 

1

31. 

12x  1 2 11 2  1x  12 12 2

36.

x 5/2

2 t2

2

42. 3(4x  1)(2x 2  x)2

45. x

5

30. 4t  9t 2  21 t3/2

x2

y

15.

b. No

28. 24x  8x 3  6x

3

5. 1

4. 0

6. The limit does not exist. 11. 1

39.

40.

Chapter 9 Review Exercises, page 653 1. 3



32. 2x 

b. y  f (a)  m(x  a)

10. a. 0

6 x4

b. f (x)  0; (a, b)

f 1a  h2  f 1a2

26. a. Yes

27. 15x  8x  6x  2 4

b. Discontinuous

7. a. [a, b]; f (c)  M 8. a. f (a)

25. 4; y  4x  4

c. L; L

, or

2x1x 4  2x 2  1 2 1x 2  1 2 2

43. 8(3x 3  2)7(9x 2), or 72x 2(3x 3  2)7

51 2x  22 4 1 1/2 x , or 2 2 2x

1 2t (2t 2  1)1/2(4t), or 2 22t 2  1

46. 13 (1  2t 3)2/3(6t 2), or 2t 2(1  2t 3)2/3

5 −2

47. 4(3t 2  2t  5)3(3t  1), or 

413t  1 2

13t 2  2t  52 3

48. 32 (2x 3  3x 2  1)5/2(6x 2  6x), or 9x(x  1)(2x 3  3x 2  1)5/2 1; 1; 1

49. (2x  1)e 2x

2 2t

y

16.

52.

e x 1x 2  x  1 2

58. ln t  1

2

59.

x 2 61. 4; 2; the limit does not exist. 17. x  2

18. x  12 , 1

21. a. 3; 2.5; 2.1 1 x2

b. 2

24. 32 ; y  32 x  5

19. x  1

20. x  0

64.

22. 3 66.

 2te t  1

21e 2x  2 2

51.

2

60.

2

e 1

x  x ln x  1 x1x  1 2 2

x

62. (x  2)e x

1r 3  r 2  r  1 2 e r 11  r 2 2 2

12x 2  2x 2 # ln x  1 2e x x11  ln x 2 2

65. 2

2 2te 2t 2

56. 3e 2x(1  e 2x)1/2 2xe x

1  4t

54. 4xe 2x 1

11  e2x 2 2

53.

21  x 2

55. (1  2x 2)ex

23.

et

50.

57. (x  1)2e x

ln x  1 1ln x2 2 63.

4e 4x e 4x  3

1  e x 11  x ln x2 x11  e x 2 2

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

67. 2 a x 

21x 2  1 2 1x 2  1 2 1 1 b a 1  2 b , or x x x3

12x  12 11 2  11  x 2212x  1 2 14x 2 2

68.

2

12x  1 2

69. (t  t) (4t)  2t 4

2

 4(t

2

4

6x 2  8x  1

, or 

12x  12 2

98. 14.346(1  t)1.45; 2.92¢/min; 19.45¢/min

3

99.  75 yr; 0.07 yr/yr

 t) (2t  1), or 4t (5t  3)(t 2  t)3 3

2

100. a. 0.02x 2  600x b. 0.04x  600 c. 200; the sale of the 10,001st phone will bring a revenue of $200.

70. (2x  1)  2(x  x)(2x  1)  (x  x) 3(2x  1) (2), or 2(2x  1)2(x 2  x)(7x 2  7x  1) 3

71. x

1/2

 3(x

2

2

2

 1) (2x)  (x  1) 2

2

3



2

2

101. a. $2.20; $2.20

1 1/2 x , or 2

c. lim a

113x 2  12 1x 3  1 2 2

x씮

22x 1x  22 11 2  x # 1x  2 2 3

72.

73.

3

# 3x

x 2

b.

2500 2500  2.2;  2 x x

2500  2.2 b  2.2 x

102. a. 2000x  0.04x 2; 0.000002x 3  0.02x 2  1000x  120,000; 2

4  x3

0.000002x 2  0.02x  1000 

21x 3  2 2 3/2

, or

14x  32 12 13x  2 2 1/2 132  13x  2 2 1/2 142 14x  3 2 2

120,000 x

b. 0.000006x 2  0.04x  1000; 2000  0.08x; 0.000006x 2  , or

0.04x  1000; 0.000004x  0.02 

12x  25

223x  214x  3 2 2

1t  12 3 12 12t  12 1/2 122  12t  1 2 1/2 # 31t  12 2 112 1t  1 2 6



x2

, or

Chapter 9 Before Moving On, page 656

22t  11t  1 2

4

1. 2 76. 

1 4x 3/2



3

1t  4 2 2

79.

4

e x 11  e x 2 11  e 2

x 3

80.

2. a. 0

b. 1; no

3. 1; y  x

4x 5/2

1t 2  42 2 12t 2  14  t 2 2 122 1t 2  4 2 12t 2

78. 4e2x(x  1)

120,000

c. 934; 1760; 826 d. 0.0048; 0.010125; at a production level of 5000, the average cost is decreasing by 0.48¢/unit; at a production level of 8000, the average cost is increasing by 1.0125¢/unit.

5t  2

75. 2(12x2  9x  2)

77.

1/2

3



74.

1 2

1/2

b. 0.51%/yr; 1.04%/yr

97. 200 subscribers/wk

2

2

2

96. a. 15%; 31.99%

901

, or

2t1t 2  122

1 x

1t 2  4 2 3

81. 

6.  9

13x  1 2

2

8.

4. 6x 2 

2x 2  2x  1

1x 2  x  1 2 2

e2x 22x

1 x

7. 

2/3



10 3x

5/3

5.

4x 2  1 22x 2  1

1 3 15 ; ; 21x  1 2 3/2 41x  1 2 5/2 81x  1 2 7/2

9. 1  ln 2

82. 2(15x4  12x2  6x  1) 1 2 83. 2(2x2  1)1/2  2x a b (2x2  1)3/2(4x), or 2 12x 2  12 3/2 84. (t 2  1)(14t)  (7t 2  1)(2)(t 2  1)(2t ), or 6 t(t 2  1)(7t 2  3) 85. 0

7. Decreasing on (, 1)  (1, ) and increasing on (1, 1) 9. Increasing on (20.2, 20.6)  (21.7, 21.8), constant on (19.6, 20.2)  (20.6, 21.1), and decreasing on (21.1, 21.7)  (21.8, 22.7)

88. a. Ó2, 253 Ô and Ó1,  136 Ô b. y  2x  133 ; y  2x  16 23 4 x  23 89. y   3 3

90. y  112x  80

95. a. 253.1 million

11. a. Positive e. Negative

b. Positive f. Negative

c. Zero d. Zero g. Positive

13. Increasing on (, ) 15. Decreasing on 1, 32 2 and increasing on 1 32 ,  2

1 92. y  e

1 1 ; a; b  a ,  b 2 2 12x  12 4 48

1. Decreasing on (, 0) and increasing on (0, )

5. Decreasing on (, 0)  (2, ) and increasing on (0, 2)

87. a. (2, 25) and (1, 14) b. y  4x  17; y  4x  10

93. 

10

Exercises 10.1, page 670

3. Increasing on (, 1)  (1, ) and decreasing on (1, 1)

86. 2

91. y  (2x  3)e2

CHAPTER

94. 20

b. 41.6 million units/yr

17. Decreasing on 1,  13/32  1 13/3, 2 and increasing on 1 13/3, 13/32 19. Increasing on 1, 2 2  10,  2 and decreasing on (2, 0)

902

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

21. Increasing on (, 3)  (3, ) 23. Decreasing on (, 0)  (0, 3) and increasing on (3, ) 25. Decreasing on (, 2)  (2, ) 27. Decreasing on (, 1)  (1, ) 29. Increasing on (, 0)  (0, )

31. Increasing on (1, )

33. Increasing on (4, 0); decreasing on (0, 4) 35. Increasing on (0, 2); decreasing on (, 0)  (2, )

93. Increasing on (0, 4.5) and decreasing on (4.5, 11); the pollution is increasing from 7 a.m. to 11:30 a.m. and decreasing from 11:30 a.m. to 6 p.m. 95. a. 0.0021t 2  0.0061t  0.1 b. Decreasing on (0, 1.5) and increasing on (1.5, 15). The gap (shortage of nurses) was decreasing from 2000 to mid-2001 and is expected to be increasing from mid-2001 to 2015. c. (1.5, 0.096). The gap was smallest ( 96,000) in mid-2001. 97. True

99. True

101. False

105. a  4; b  24

37. Increasing on (0, e); decreasing on (e, )

107. a. 2x if x  0

39. Increasing on (, 0)  (0, )

Using Technology Exercises 10.1, page 677

41. Relative maximum: f(0)  1; relative minima: f(1)  0 and f(1)  0 43. Relative maximum: f(1)  2; relative minimum: f(1)  2 45. Relative maximum: f(1)  3; relative minimum: f(2)  2 47. Relative minimum: f(0)  2

49. a

51. d

53. Relative minimum: f(2)  4 55. Relative maximum: f(3)  15

57. None

59. Relative maximum: t(0)  4; relative minimum: t(2)  0 61. Relative maximum: f(0)  0; relative minima: f 11 2  12 and f 11 2  12 63. Relative minimum: F(3)  5; relative maximum: F11 2  173 65. Relative minimum: t(3)  19

67. None

b. No

1. a. f is decreasing on (, 0.2934) and increasing on (0.2934, ). b. Relative minimum: f(0.2934)  2.5435 3. a. f is increasing on (, 1.6144)  (0.2390, ) and decreasing on (1.6144, 0.2390). b. Relative maximum: f(1.6144)  26.7991; relative minimum: f(0.2390)  1.6733 5. a. f is decreasing on (, 1)  (0.33, ) and increasing on (1, 0.33). b. Relative maximum: f(0.33)  1.11; relative minimum: f(1)  0.63 7. a. f is decreasing on (, 0.40) and increasing on (0.40, ). b. Relative minimum: f(0.40)  0.79 9. a.

69. Relative maximum: f(3)  4; relative minimum: f(3)  8 71. Relative maximum: f 11 2  12 ; relative minimum: f 112  12 73. Relative maximum: f(1)  e1 75. Relative minimum: f(1)  1

b. Increasing on (0, 3.6676) and decreasing on (3.6676, 6)

y

77.

11. Increasing on (0, 4.5) and decreasing on (4.5, 11); 11:30 a.m.; 164 PSI

Exercises 10.2, page 687 100

1. Concave downward on (, 0) and concave upward on (0, ); inflection point: (0, 0) 3. Concave downward on (, 0)  (0, ) t 2

Rising in the time interval (0, 2); falling in the time interval (2, 5); when t  5 sec 79. The percentage of the U.S. population age 65 and over afflicted by the disease increases with age. 81. Rising on (0, 33) and descending on (33, T) for some positive number T. 83. f is decreasing on (0, 1) and increasing on (1, 4). The average speed decreases from 6 a.m. to 7 a.m. and then picks up from 7 a.m. to 10 a.m. 85. a. Increasing on (0, 6)

b. Sales will be increasing.

89. Spending was increasing from 2001 to 2006. 91. Increasing on (0, 1) and decreasing on (1, 4)

5. Concave upward on (, 0)  (1, ) and concave downward on (0, 1); inflection points: (0, 0) and (1, 1) 7. Concave downward on (, 2)  (2, 2)  (2, ) 9. a. Concave upward on (0, 2)  (4, 6)  (7, 9)  (9, 12) and concave downward on (2, 4)  (6, 7) b. 12, 52 2 , (4, 2), (6, 2), and (7, 3) 11. (a)

13. (b)

15. a. D¿1 1t2  0, D¿2 1t2  0, D–1 1t2  0, and D–2 1t2 0 on 10, 122 b. With or without the proposed promotional campaign, the deposits will increase; with the promotion, the deposits will increase at an increasing rate; without the promotion, the deposits will increase at a decreasing rate. 17. At the time t 0, corresponding to its t-coordinate, the restoration process is working at its peak. 25. Concave upward on (, )

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

27. Concave downward on (, 0); concave upward on (0, )

85.

903

y

29. Concave upward on (, 0)  (3, ); concave downward on (0, 3) 1

31. Concave downward on (, 0)  (0, ) 33. Concave downward on (, 4) 35. Concave downward on (, 2); concave upward on (2, )

x  2 2

37. Concave upward on 1, 16/3 2  1 16/3, 2; concave downward on 116/3, 16/3 2 39. Concave downward on (, 1); concave upward on (1, )

87. a. N is increasing on (0, 12). b. N (t) 0 on (0, 6) and N (t)  0 on (6, 12) c. The rate of growth of the number of help-wanted advertisements was decreasing over the first 6 mo of the year and increasing over the last 6 mo.

41. Concave upward on (, 0)  (0, ) 43. Concave upward on (, 2); concave downward on (2, ) 45. Concave upward on (0, ); concave downward on (, 0) 47. Concave upward on (, 1)  (1, ); concave downward on (1, 0)  (0, 1) 49. (0, 2)

51. (1, 15)

53. 10, 12 and

1 23 , 11 27 2

57. (1, 2)

59. 1

61. 1e3/2, 32 e3 2

2e1/2 2; 1

22 2 ,

2e1/2 2

93. b. The rate was increasing.

63. Relative maximum: f(1)  5

65. None

67. Relative maximum: f 112  223 , relative minimum: f 15 2  130 3 69. Relative maximum: t(3)  6; relative minimum: t(3)  6 73. Relative minimum: f(2)  12

71. None

75. Relative maximum: t 11 2 

1 2;

89. f(t) increases at an increasing rate until the water level reaches the middle of the vase at which time (corresponding to the inflection point) f(t) is increasing at the fastest rate. After that, f(t) increases at a decreasing rate until the vase is filled. 91. b. The rate of increase of the average state cigarette tax was decreasing from 2001 to 2008.

55. (0, 0) 22 2 ,

2 2

relative minimum: t 112 

12

95. 10 a.m.

97. The rate of business spending on technology was increasing from 2000 through 2005. 99. a. Concave upward on (0, 150); concave downward on (150, 400); (150, 28,550) b. $140,000 103. (1.9, 784.9); the rate of annual pharmacy spending slowed down near the end of 2000. 105. a. 74.925t 2  99.62t  41.25; 149.85t  99.62 c. (0.66, 12.91); the rate was increasing least rapidly around August 1999.

77. Relative minimum: f 112  1e 79. Relative minimum: f(0)  0

3

107. a. 506,000; 125,480 b. The number of measles deaths was dropping from 1999 through 2005. c. April 2002; approximately 41 deaths/yr

2

113. True

81.

y 4

1

Using Technology Exercises 10.2, page 696

x 1

2

3

83.

115. True

4

1. a. f is concave upward on (, 0)  (1.1667, ) and concave downward on (0, 1.1667). b. (1.1667, 1.1153); (0, 2)

y 3. a. f is concave downward on (, 0) and concave upward on (0, ). b. (0, 2)

4

5. a. f is concave downward on (, 0) and concave upward on (0, ). b. (0, 0) x –4

4

7. a. f is concave downward on (, 0) and concave upward on (0, ). b. None 9. a.

b. (3.9024, 77.0919)

904

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

11. a.

y

37. 60 40 20

x –3

–2

–1 –20 –40 –60

b. April 1993 (t  7.36)

Exercises 10.3, page 704 1. Horizontal asymptote: y  0

1

2

3

y

39.

3. Horizontal asymptote: y  0; vertical asymptote: x  0

20

5. Horizontal asymptote: y  0; vertical asymptotes: x  1 and x  1

10

7. Horizontal asymptote: y  3; vertical asymptote: x  0 9. Horizontal asymptote: y  0

x –4

11. Horizontal asymptote: y  0; vertical asymptote: x  0

–2

2

4

–10

13. Horizontal asymptote: y  0; vertical asymptote: x  0 15. Horizontal asymptote: y  1; vertical asymptote: x  1 17. None

y

41.

19. Horizontal asymptote: y  1; vertical asymptotes: t  3 and t  3

60

21. Horizontal asymptote: y  0; vertical asymptotes: x  2 and x  3

40

23. Horizontal asymptote: y  2; vertical asymptote: t  2

20

25. Horizontal asymptote: y  1; vertical asymptotes: x  2 and x  2 27. None

x –4

29. f is the derivative function of the function t.

–2

2 –20

v

31.

4

–40

Terminal velocity y

43. 30 20 t

10 x

y

33.

–3

20 15 10 5 −2

–2

1

2

y

45. x 2

−5

6

4

−10 −15 −20

t –4

2 −2

4

y

47.

y

35.

−4

–1

2 x

−2 −4 −6 −8 −10

2

4 x 8

3

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

y

49.

y

65.

110

20

100

10

90

x –4

905

–2

2

4

6

80

8

–10

70 60

–20

t 2

y

51.

6

8

y

67.

10

4

5 x

–10

–5

5

10

30

–5 –10

t 2

4

y

53.

T

69. 0.8

100

0.6

80 60 40 20

0.4 0.2 t –6

–4

–2

2

4

y

55.

x

6

1

2

3

4

5

y

71.

80 60 4

40 20 x

t

20

2

2 20

c.

x 1 2 3 4

40 60 80 y

100

297,000ex

11  99ex 2 2 ; 3000

5

10

15

20

25

x

Using Technology Exercises 10.3, page 711

2 1 x –1

80

y

3000 2500 2000 1500 1000 500 0

59.

60

b. N t 1x2 

73. a. 30

y

57.

40

2

4

6

1.

3.

8

–3 61. a. x  100

b. No

63. a. y  0 b. As time passes, the concentration of the drug decreases and approaches zero.

5. 0.9733; 2.3165, 4.6569

7. 1.5142

9. 0.7680, 1.6783

906

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

11.

y

85. c. 40 20

x –1

Exercises 10.4, page 719 1. None

–20 – 40

3. Absolute minimum value: 0

5. Absolute maximum value: 3; absolute minimum value: 2 7. Absolute maximum value: 3; absolute minimum value: 27 16 9. Absolute minimum value: 418 11. No absolute extrema

1

13. Absolute maximum value: 1

Using Technology Exercises 10.4, page 725 1. Absolute maximum value: 145.8985; absolute minimum value: 4.3834 3. Absolute maximum value: 16; absolute minimum value: 0.1257

15. Absolute maximum value: 5; absolute minimum value: 4

5. Absolute maximum value: 11.8922; absolute minimum value: 0

17. Absolute maximum value: 10; absolute minimum value: 1

7. Absolute maximum value: 2.8889; absolute minimum value: 0

19. Absolute maximum value: 19; absolute minimum value: 1

9. a.

21. Absolute maximum value: 16; absolute minimum value: 1 23. Absolute maximum value: 3; absolute minimum value: 53 25. Absolute maximum value: 373 ; absolute minimum value: 5 b. 21.51%

27. Absolute maximum value  1.04; absolute minimum value: 1.5

11. b. 1145 29. No absolute extrema 31. Absolute maximum value: 1; absolute minimum value: 0 33. Absolute maximum value: 0; absolute minimum value: 3 35. Absolute maximum value: 1; absolute minimum value: 1e 37. Absolute maximum value: 2e3/2; absolute minimum value: 1

Exercises 10.5, page 732 1. 25 ft  25 ft 3. 750 yd  1500 yd; 1,125,000 yd2 5. 1012 ft  40 12 ft 7.

39. Absolute maximum value: 3  ln 3; absolute minimum value: 1 41. 144 ft

43. 17.72%

45. f(6)  3.60, f(0.5)  1.13; the number of nonfarm, full-time, selfemployed women over the time interval from 1963 to 1993 reached its highest level, 3.6 million, in 1993. 47. $3600

49. 6000

53. a. 0.0025x  80  c. 2000 55. 533

51. 3333

10,000 x

in. 

4 3

in.

11. 18 in.  18 in.  36 in.; 11,664 in.3 13. r  2 3

46,656 3 36 in.; l  36 in.; in. p p

3 3 1 9 ft  1 9 ft 

2 5

3 1 9 ft

17. 250; $62,500; $250 21. 60 miles/hr

23. w  13.86 in.; h  19.60 in.

57. 7.72 yr; $160,208

69. $52.79/sq ft

25. x  2250 ft

27. x  2.68

29. 440 ft; 140 ft; 184,874 sq ft

31. 45, 44,445

Chapter 10 Concept Review, page 738

71. a. 2000; $105.8 billion

b. 1995; $7.6 billion

2

E watts 4r

16 3

19. 85; $28,900; $340

d. Same

59. a. 2 days after the organic waste was dumped into the pond b. 3.5 days after the organic waste was dumped into the pond

75. R  r;

in. 

9. 5.04 in.  5.04 in.  5.04 in.

15.

b. 2000

16 3

79. False

81. False

1. a. f(x1) f(x2)

b. f(x1)  f(x2)

2. a. Increasing

b. f (x) 0

3. a. f(x) f(c)

b. f(x)  f(c)

c. Constant

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

4. a. Domain;  0; exist c. Relative extremum

b. Critical number

5. a. f (x) b.  0 c. Concavity d. Relative maximum; relative extremum 6. ; 

7. 0; 0

8. b; b

9. a. f(x) f(c); absolute maximum value b. f(x)  f(c); open interval 10. Continuous; absolute; absolute

Chapter 10 Review Exercises, page 738 1. a. b. c. d.

f is increasing on (, 1)  (1, ) No relative extrema Concave down on (, 1); concave up on (1, ) 11, 173 2

2. a. b. c. d.

f is increasing on (, 2)  (2, ) No relative extrema Concave down on (, 2); concave up on (2, ) (2, 0)

10. a. f is decreasing on (, 0) and increasing on (0, ) b. Relative minimum value: 1 1 1 c. Concave down on a,  b  a ,  b ; concave up on 23 23 1 1 a , b 23 23 1 3 1 3 d. a ,  b; a , b 4 4 23 23 11. a. b. c. d.

f is increasing on (, 3) and decreasing on (3, ) Relative maximum value: e3 Concave up on (, 2); concave down on (2, ) (2, 2e2)

12. a. b. c. d.

f is decreasing on (0, e1/2) and increasing on (e1/2, ) Relative minimum value: 12 e1 Concave down on (0, e3/2); concave up on (e3/2, ) (e3/2, 32 e3) y

13.

3

3. a. f is increasing on (1, 0)  (1, ) and decreasing on (, 1)  (0, 1) b. Relative maximum value: 0; relative minimum value: 1 c. Concave up on a,  a d. a

x 1

23 23 b  a ,  b ; concave down on 3 3

23 23 , b 3 3

( 52, – 54 ) 14.

23 5 23 5 ,  b; a , b 3 9 3 9

y

6. a. b. c. d. 7. a. b. c. d.

8. a. f is increasing on (1, ) b. No relative extrema c. Concave down on 11, 43 2 ; concave up on 1 43 , 2 4 423 d. a , b 3 9 9. a. b. c. d.

f is increasing on (, 1)  (1, ) No relative extrema Concave down on (1, ); concave up on (, 1) None

2.5

5

7.5

−40 −60 −80 −100 −120 15.

y

4

f is increasing on (1, ) No relative extrema Concave down on (1, ) None f is decreasing on (, 1)  (1, ) No relative extrema Concave down on (, 1); concave up on (1, ) (1, 0)

x

−7.5 −5 −2.5 −20

4. a. f is increasing on (, 2)  (2, ) and decreasing on (2, 0)  (0, 2) b. Relative maximum value: 4; relative minimum value: 4 c. Concave down on (, 0); concave up on (0, ) d. None 5. a. f is increasing on (, 0)  (2, ); decreasing on (0, 1)  (1, 2) b. Relative maximum value: 0; relative minimum value: 4 c. Concave up on (1, ); concave down on (, 1) d. None

907

x 1 16.

y 150 100 50 −10

−5

−50 −100 −150

x 5

10

908

ANSWERS TO CHAPTER 10 ODD -NUMBERED EXERCISES

17.

y

23. Vertical asymptote: x   32 ; horizontal asymptote: y  0 24. Horizontal asymptote: y  2; vertical asymptote: x  1

4

25. Vertical asymptotes: x  2, x  4, horizontal asymptote: y  0 26. Horizontal asymptote: y  1; vertical asymptote: x  1 27. Absolute minimum value:  258

x 2

28. Absolute minimum value: 0

18.

29. Absolute maximum value: 5; absolute minimum value: 0

y

30. Absolute maximum value: 53 ; absolute minimum value: 1

1 0.5

31. Absolute maximum value: 16; absolute minimum value: 32 x

−7.5 −5 −2.5 −0.5

2.5

5

32. Absolute maximum value: 12 ; absolute minimum value: 0

7.5

33. Absolute maximum value: 83 ; absolute minimum value: 0

−1

34. Absolute maximum value: 215 9 ; absolute minimum value: 7 19.

35. Absolute maximum value: 1/e; absolute minimum value: 2e2

y

36. Absolute maximum value: (ln 2)/2; absolute minimum value: 0 37. Absolute maximum value: 21 ; absolute minimum value:  21

3

38. No absolute extrema x 2

39. $4000 40. c. Online travel spending is expected to increase at an increasing rate over that period of time.

20.

41. a. 16.25t  24.625; sales were increasing. b. 16.25; the rate of sales was increasing from 2002 to 2005.

y 20 10 −2

−1

x 1

−10

42. a. I¿1t2  

2 b. I–1t2 

−20

c. 21.

y

200t

1t 2  102 2

200110  3t 2 2 1t 2  102 3

; concave up on 1 110/3,  2 ;

concave down on 10, 110/3 2 y 60 58

0.5

56 54 x 1

2

3

52 51 t 2

22.

y

4

6

8

10

d. The rate of decline in the environmental quality of the wildlife was increasing the first 1.8 yr. After that time the rate of decline decreased.

10

43. 168

44. 3000

45. a. 0.001x  100  x 3

46. 10 a.m.

4000 x

b. 2000

ANSWERS TO CHAPTER 11 ODD -NUMBERED EXERCISES

47. a. Decreasing on (0, 12.7); increasing on (12.7, 30) b. (12.7, 7.9) c. The percent of women 65 years and older in the workforce was decreasing from 1970 to Sept. 1982 and increasing from Sept. 1982 to 2000. It reached a minimum value of 7.9% in Sept. 1982. 49. 74.07 in.3

50. Radius: 2 ft; height: 8 ft

51. 1 ft  2 ft  2 ft

52. 20,000 cases

53. a  4; b  11

54. c  32

56. a. f (x)  3x 2 if x  0

9. 6x  C

1 4

11.

x4  C

17. 

4

15.

3 5

x 5/3  C

21.

2 3

pt

25.

1 3 1 2 1 x  x  2C 3 2 2x

3/2

C

x

1/4

Chapter 10 Before Moving On, page 740 1. Decreasing on (, 0)  (2, ); increasing on (0, 1)  (1, 2) 2. Relative maximum value: (1, e1); inflection point: (2, 2e2) 3. Concave downward on 1, 14 2; concave upward on 1 14 ,  2 ; 1 14 , 83 96 2

C

2 19.   C x

C

2 7

x7/2  45 x5/2  12 x 2  C

37.

1 9

u 3  13 u 2  13 u  C

41.

1 3

x 3  2x 

35.

43.

47.

1 3

2 xC x 2 3

2 3 3t

39.

1 C x

t e1 C e1

27. 4e x  C

31. x 4 

33.

45. e t 

1 3x 3

23. 3x  x 2  C

29. x  12 x 2  e x  C

b. No

13. 

x3/2  6 1x  C  32 t 2  2t  C

s3  s2  s  C

1 2 1 x  x  ln 0 x 0   C 2 x

y

4.

49. ln 0 x 0 

10

4 1  C x 1x

8 6

53. x 3  2x 2  x  5

51. x 2  x  1

55. x 

4 59. 1x

2 –4

–2

2

4

6

x

–2

61. e x  12 x 2  2

65. s1t 2  43 t 3/2

63. Branch A

67. $3370

71. a. 0.0029t 2  0.159t  1.6

–4

57. x  ln 0 x 0

1 2 x

69. 5000 units; $34,000 b. $4.16 trillion

73. a. 0.125t 3  1.05t 2  2.45t  1.5 5. Absolute minimum value: 5; absolute maximum value: 80 6. r  h 

1ft2

1 3 1 p

CHAPTER

b. 24.375 million

75. a. 1.493t 3  34.9t 2  279.5t  2917 77. a. 3.133t 3  6.7t 2  14.07t  36.7

b. $9168 b. 103,201

79. a. y  4.096t 3  75.2797t 2  695.23t  3142

11

83. t 3  96t 2  120t; 63,000 ft

81. 21,960

Exercises 11.1, page 750

b. $4264.11

85. a. 0.75t 4  5.9815t 3  14.3611t 2  26.632t  108 b. $321.25 million

5. b. y  2x  C y

87. a. 9.3e0.02t 5

89.

k1R 2  r 2 2

95. a.

x –5

1 2

b. 7030

5

2t t4

c. 6619

91. 9 79 ft/sec2; 396 ft b.

2 5

in.; 23 in.

93. 0.924 ft/sec2

97. True

99. True

Exercises 11.2, page 762 –5

1. 15 14x  3 2 5  C 5. 

7. b. y  x  C 1 3

3

y 30 20 10

C=5 C = 10

C=0 C = –5

–10 – 20

2

4

1 2 20 1x

1 6

 1 2 10  C

11. 15 ln 0 1  x 5 0  C 15.

ln 0 3x 2  1 0  C

23. 12 e x  C 2

7. 23 1t 3  2 2 3/2  C

C

13. ln1x  2 2 2  C 17.

x –4

9.

1 212x 2  32 2

3. 13 1x 3  2x2 3  C

1 2

ln10.3x 2  0.4x  2 2  C

19. 12 e 2x  C

25. e x  ex  C

21. e 2x  C

27. ln(1  e x )  C

909

910

ANSWERS TO CHAPTER 11 ODD -NUMBERED EXERCISES

29. 2e 1x  C

31. 

1

33. 18 1e 2x  1 2 4  C

C

61e 3x  x 3 2 2

1 2

1ln 5x 2 2  C

1 2

e x  12 ln1x 2  2 2  C

51. 695.5 million

41. 43.

2 3

1 1x  1 2 3  31 1x  1 2 2  81 1x  1 2  4 ln 0 1x  1 0  C

57. False

39.

2 3

1ln x 2 3/2  C

2

16x  12 1x  12 6 42

C

1 49. 252 11  √2 7 128√ 2  7√  12  C

51. 12 3 12x  12 5  54

53. e x

20,000 11  0.2t

2

1

63.

1  2.449e0.3277t

53. 149.1 million

1

55. 17,341,000 250

216  x 2

9. 3.9973

11. 46%; 24%

32 15

19 15

3.

r 65. 11  eat 2 a

67. True

23.

1 3

1 2

37.

17 3

17. 12 e 2  56

1ln 19  ln 32

1e4  e8  1 2

27.

1e4  1 2

39. 1

13 6

19. 0

25. 2e 4  2e 2  ln 2

29. 6 41.

9. 2415

35. 5

1e 4  1 2

1 4

43.

33. 21 1e  1e 2

1 2

31.

45. 120.3 billion metric tons

y

55. 9.8%

5 4 3 2 1

75. True

59. $14.78

61. 80.7%

73. a. 1

b. 5

c. 13

79. True

Using Technology Exercises 11.5, page 796

x 1.5

71. 0

77. False

51. $3.24 billion/yr

b. 150.1 billion gal/yr/yr

57. 16,863

69. Property 5

1

49. $40,339.50

53. a. 160.7 billion gal/yr

y = 3x

6

2

1. 7.71667

3. 17.56487

5. 10,140

7. 60.45 mg/day

d. Yes

Exercises 11.6, page 803

y

5. a. 4

15. 903,213

7. 13  1 1 2

15.

47. $2.24 million

c. 5.25

7. 2.7044

13. 333,209

5. 32154

13. 18152

21. 2 ln 4

2

 0.3; 56.22 in.

0.5

5. 0.5888

3. 0.7873

11.

1. 4.27

b. 4.5

23 15

55.

59. False

1. 6.1787

1. 10

Exercises 11.3, page 772

3. a. 6

c. 5.2%

Exercises 11.5, page 792

59.

; 6858

61. 301 12t  4  2 2; 14,400 p ft 65.8794

b. 12.8%

Using Technology Exercises 11.4, page 785

47. 5  41x  x  4 ln11  1x2  C

57. 21,000 

47. 10,13313 ft

b. $4.84 billion

49. a. 0.2833t 3  1.936t 2  5t  5.6

35.

45.

37. ln 0 ln x 0  C

45. a. 0.86t0.96  0.04

4

1. 108

y = 4 – 2x

3

13. 27

2

3.

2 3

15. 2(e2  e1)

23. 12  ln 4

1

5. 223

33. e 3  4  1e

7. 112 17. 1223

25. e 2  e  ln 2 35. 20 56

11. 313

9. 3 19. 313 27. 212

1 12

37.

39.

21. 434 29. 713

71 6

31.

3 2

41. 18

x 0.5 b. 4.8

c. 4.4

7. a. 18.5

1

13. 4.64

15. 0.95

47. a. A2  A1

d. 19.9

c. 19.88

b. 0.16

2050 45. Shortfall  2010 3 f 1t2  t1t2 4 dt

d. 18.7

c. 18.66

b. 21.12

11. a. 0.0625

43. S is the additional revenue that Odyssey Travel could realize by switching to the new agency; S  0b 3t1x2  f 1x2 4 dx

2

d. Yes

b. 18.64

9. a. 25

1.5

49. 30 ft/sec faster

d. 0.2

c. 0.2025

3. 8

15. e 2  1 27.

7 12

39. 1912

5. 12

1. a.

17. 6

29. ln 2

7. 9 19. 14

31. 56

41. a. $4100

11. 1713

9. ln 2 21. 1823 33.

b. $900

256 15

51. 21,850

53. True

55. False

Using Technology Exercises 11.6, page 808

17. 9400 sq ft

Exercises 11.4, page 782 1. 6

b. The distance car 2 is ahead of car 1 after t sec

23. 35.

2 3

4 3

3. a.

13. 1814 25. 45

37. 223

43. a. $2800

b. $219.20

b. 1074.2857

b. 0.9961

ANSWERS TO CHAPTER 11 ODD -NUMBERED EXERCISES

5. a.

7. a.

b

 f 1x2 dx

1 ba

7. a.

x

x

b. 0 R1t 2 ert dt

T

b. 25.8549

9. a.

b. 3.5799

13. 207.43

3. $6667

15. $47,916

5. $11,667

11. $148,239 17. $142,423

19. $24,780

1 4

x 4  23 x 3  12 x 2  C

3.

1 5

x 5  12 x 4 

5.

1 2

x 4  25 x 5/2  C

7.

1 3

x 3  12 x 2  2 ln 0 x 0  5x  C

2 7

6.

ln1x 2  2x  5 2  C

13.

1 2

ex

2

x1

C

18.

2 15

17.

y

30. 1 

1

1 e2

37. 4.28

33

C

15.

264 19. 21.

1 6

1ln x2 6  C

C

1x  4 2 1x  2  C

2 3

22. 6

1 2

26.

132 5

31.

e1 211  e 2

27.

1 2

23. 523

ln 5 32.

28.

1 15

1 2

34. f 1x2  2x 2  1

36. f 1x2  12 1ln x2 2  2

38. $6740

39. a. 0.015x 2  60x; x

1x 3  2 2 11

12. e2x  C

33. f(x)  x 3  2x 2  x  1 35. f(x)  x  ex  1

y = f (x)

8. 13 12x  1 2 3/2  C

111x 2  12 1x 2  12 11

25. 80

29. 4

b. 0.104; 0.504

b. p  0.015x  60

40. V(t)  1900(t  10)2  10,000; $40,400

1

Using Technology Exercises 11.7, page 820 1. Consumers’ surplus: $18,000,000; producers’ surplus: $11,700,000

41. a. 0.05t 3  1.8t 2  14.4t  24

b. 56°F

42. a. 0.01t 3  0.109t 2  0.032t  0.1

b. 1.076 billion

44. 3000t  50,000(1  e0.04t ); 16,939

43. 3.375 ppm 3. Consumers’ surplus: $33,120; producers’ surplus: $2880

45. N1t2  15,000 11  0.4t  85,000; 112,659

5. Investment A

Chapter 11 Concept Review, page 822 1. a. F(x)  f(x)

x 7/2  13 x 3  23 x 3/2  x  C

13x  2 2 1x  12 3/2  C

24. 242 x

x 4/3  23 x 3/2  4x  C

10.

20. 21x  2 2 1x  1  C

1

3 4

x 4  23 x 3  8x  C

1 C e x  x

14.

16. (ln x)2  C

y = f (x)

b. F(x)  C

2. a. c  f 1x2 dx

b.  f 1x2 dx  t 1x 2 dx

3. a. Unknown

b. Function

5. a.  f 1x2 dx

b. Minus

b a

4.

1 2

1 12

2.

1 C x

11.

b. 0.175; 0.816

1

23. a.

1

13. $43,788

y

21. a.

12. L  2 0 3x  f 1x2 4 dx

1.

7. Consumers’ surplus: $13,333; producers’ surplus: $11,667 9. $824,200

mP rT 1e  1 2 r

9. 38 13x 2  2x  12 4/3  C

Exercises 11.7, page 818 1. $11,667

T

Chapter 11 Review Exercises, page 823

11. a.

b. 10.5144

11. A 

b

b. p x  0 S1x2 dx

10. a. erT 0 R1t2ert dt b. 5.4603

8. a 3 f 1x2  t1x2 4 dx

b. Area; area

a

9. a. 0 D1x2 dx  p x

6. a. F(b)  F(a); antiderivative

4. t(x) dx;  f(u) du

47.

48. $3100

49. 37.7 million

50. a. S(t)  205.89  89.89e 0.176t 51. 15 53.

b a

b.  f ¿1x2 dx

240  30 5x

46. 26,027

2 3

52. 54.

9 2

1 4 2 1e

 12

911

b. $161.43 billion

912

ANSWERS TO CHAPTER 12 ODD -NUMBERED EXERCISES

55. e 2  3

3 10

56.

58. 234,500 barrels 61. 49.7 ft/sec

57. 59.

1 3

y

23.

1 2

60. 26°F

62. 67,600/yr

2

63. $270,000

x 64. Consumers’ surplus: $2083; producers’ surplus: $3333 65. $197,652

66. $174,420

3

67. $505,696

y

68. a.

25. 2x 2  y 2  5

1.0 0.8 0.6 0.4 0.2

15

x b. 0.1017; 0.3733

c. 0.315

3. 2x 2  1  C

4. 31 12 12  1 2

2. e x  12 x 2  1 5.

37. $7200 billion

9 2

39. 103

41. a. $1798.65; $2201.29

CHAPTER

b. 81 kg

1 5

35. a. The set of all ordered pairs (P, T ), where P and T are positive numbers b. 11.10 L

Chapter 11 Before Moving On, page 826 x 4  23 x 3/2  2 ln 0 x 0  41x  C

1 4

33. a. 0.005x 2  0.003y 2  0.002xy  20x  15y b. The set of all ordered pairs (x, y) for which 20  0.005x  0.001y  0 15  0.001x  0.003y  0, x  0, y  0

69. 90,888

1 2

29. a. 24.69

31. a. x 2  y 2  xy  200x  160y b. The set of all points (x, y) satisfying 200  15 x  101 y  0, 160  101 x  14 y  0, x  0, y  0 0.2 0.4 0.6 0.8 1.0

1.

27. 9p ft 3

12

43. 40.28 times gravity

Exercises 12.1, page 834

kT  C (C, a positive constant). P C The level curves are a family of straight lines T  a b P lying in k the first quadrant since k, T, and P are positive. Every point on the level curve V  C gives the same volume C.

45. The level curves of V have equation

1. f(0, 0)  4; f(1, 0)  2; f(0, 1)  1; f(1, 2)  4; f(2, 1)  3 3. f(1, 2)  7; f(2, 1)  9; f(1, 2)  1; f(2, 1)  1 5. t 11, 22  4  312; t 12, 12  8  12; t 10, 4 2  2; t 14, 9 2  56

47. False

7. h(1, e)  1; h(e, 1)  1; h(e, e)  0

11. All real values of x and y 13. All real values of u and √ except those satisfying the equation u  √ 15. All real values of r and s satisfying rs  0 17. All real values of x and y satisfying x  y  5 y

y

21. 2

x x –2 –1

49. False

51. False

Exercises 12.2, page 846

9. t(1, 1, 1)  e; t(1, 0, 1)  1; t(1, 1, 1)  e

19.

b. $2509.32

1. a. 4; 4 b. f x(2, 1)  4 says that the slope of the tangent line to the curve of intersection of the surface z  x2  2y2 and the plane y  1 at the point (2, 1, 6) is 4. f y(2, 1)  4 says that the slope of the tangent line to the curve of intersection of the surface z  x2  2y2 and the plane x  2 at the point (2, 1, 6) is 4. c. f x(2, 1)  4 says that the rate of change of f(x, y) with respect to x with y held fixed with a value of 1 is 4 units/unit change in x. f y(2, 1)  4 says that the rate of change of f(x, y) with respect to y with x held fixed with a value of 2 is 4 units/unit change in y. 3. 2; 3

5. 4x; 4

7. 

4y 2 ; x3 x2

9.

2√

1u  √2 2

z=2 z=1

11. 3(2s  t)(s 2  st  t 2)2; 3(2t  s)(s 2  st  t 2)2

z=0 z = –1

13.

z = –2

4y 4x ; 31x 2  y 2 2 1/3 31x 2  y 2 2 1/3

y x 17. ln y  ;  ln x x y

;

15. ye xy1; xe xy1

19. e u ln √;

eu √

21. yz  y 2  2xz; xz  2xy  z 2; xy  2yz  x 2

2u

1u  √2 2

ANSWERS TO CHAPTER 12 ODD -NUMBERED EXERCISES

25. fx(1, 2)  8; fy(1, 2)  5

23. ste rst; rte rst; rse rst

27. fx(2, 1)  1; fy (2, 1)  3

29. fx(1, 2)  21 ; fy(1, 2)  14

15. (0, 0); saddle point: f(0, 0)  1 17. (0, 0); relative minimum value: f(0, 0)  1 19. (0, 0); relative minimum value: f(0, 0)  0

31. fx (1, 1)  e; fy (1, 1)  e

21. 200 finished units and 100 unfinished units; $10,500

33. fx(1, 0, 2)  0; fy (1, 0, 2)  8; fz (1, 0, 2)  0

23. Price of land ($200/ft2) is highest at 1 12 , 1 2

35. fxx  2y; fxy  2x  3y 2  fyx; fyy  6xy

25. (0, 1) gives desired location.

37. fxx  2; fxy  fyx  2; fyy  4

29. 30  40  10; $7200

39. fxx  fyy  41. fxx 

y2

1x  y 2 2

2 3/2

913

; fxy  fyx  

xy

1x  y 2 2

2 3/2

;

27. 10  10  5; 500 in.3 31. False

33. False

35. True

Chapter 12 Concept Review, page 860 1. xy; ordered pair; real number; f(x, y)

x2

1x 2  y 2 2 3/2 1 y

2

e x/y; fxy 

2. Independent; dependent; value yx y

3

3. z  f(x, y); f; surface

e x/y  fyx;

4. f(x, y)  c; level curve; level curves; c

x fyy  3 a  2 b e x/y y y x

43. a. fx  7.5; fy  40

5. Fixed number; x 7. ; (a, b); ; domain

b. Yes

45. px  10—at (0, 1), the price of land is changing at the rate of $10/ft2/mile change to the right; py  0—at (0, 1), the price of land is constant/mile change upward.

49. $30/unit change in finished desks; $25/unit change in unfinished desks. The weekly revenue increases by $30/unit for each additional finished desk produced (beyond 300) when the level of production of unfinished desks remains fixed at 250; the revenue decreases by $25/unit when each additional unfinished desk (beyond 250) is produced and the level of production of finished desks remains fixed at 300. b.  0.3°F

53. 0.039 L/degree; 0.015 L/mm of mercury. The volume increases by 0.039 L when the temperature increases by 1 degree (beyond 300 K) and the pressure is fixed at 800 mm of mercury. The volume decreases by 0.015 L when the pressure increases by 1 mm of mercury (beyond 800 mm) and the temperature is fixed at 300 K. 57. False

8. Domain; fx(a, b)  0 and f y(a, b)  0; exist; candidate

Chapter 12 Review Exercises, page 861 1. 0, 0, 12 ; no

47. Complementary commodities

51. a. 20°F

6. Slope; (a, b, f(a, b)); x; b

2. e,

e2 2e , ; no 1  ln 2 1  ln 2

3. 2, (e  1), (e  1) 4. The set of all ordered pairs (u, √) such that u  √ 5. The set of all ordered pairs (x, y) such that y  x 6. The set of all ordered pairs (x, y) such that x 1 and y  0 7. The set of all triplets (x, y, z) such that z  0 and x  1, y  1, and z1 8. 2x  3y  z

y

2

59. True x

Using Technology Exercises 12.2, page 849 1. 1.3124; 0.4038

3. 1.8889; 0.7778

−2

5. 0.3863; 0.8497

Exercises 12.3, page 857 1. (0, 0); relative maximum value: f(0, 0)  1 3. (1, 2); saddle point: f(1, 2)  4 5. (8, 6); relative minimum value: f(8, 6)  41

9. z  y  x 2

y 4

7. (1, 2) and (2, 2); saddle point: f(1, 2)  1; relative minimum value: f(2, 2)  2 9. 113 , 113 2 and (1, 5); saddle point: f 113 , 113 2  319 27 ; relative minimum value: f(1, 5)  13 11. (0, 0) and (1, 1); saddle point: f(0, 0)  2; relative minimum value: f(1, 1)  3 13. (2, 1); relative minimum value: f(2, 1)  6

2

x

914

ANSWERS TO CHAPTER 12 ODD -NUMBERED EXERCISES

10. z  2x 2  y 2

1 1 27. hss   2 ; hst  hts  0; htt  2 s t

y 4 3 2 1

28. fx(1, 1, 0)  3; fy(1, 1, 0)  3; fz(1, 1, 0)  2 29. (2, 3); relative minimum value: f(2, 3)  13 x 1

11. z  e xy

2

3

4

30. (8, 2); saddle point at f(8, 2)  8 31. (0, 0) and 1 32 , 94 2 ; saddle point at f(0, 0)  0; relative minimum value: f 1 32 , 94 2  27 16 32. 113 , 133 2 , (3, 11); saddle point at f 113 , 133 2  445 27 ; relative minimum value: f 13, 11 2  35

y

33. (0, 0); relative minimum value: f(0, 0)  1 z=3 z=1

34. (1, 1); relative minimum value: f(1, 1)  ln 2 x

35. k 

100 m c I  180 I  120 I  100 I  90

m 10 8 6 4 2

1 x 12. f x  2xy  3y  ; fy  3x 2y 2  6xy  2 y y 3

2

y

13. f x  1y  14. fu 

21x

√2  2 22u√ 2  2u 3y

15. f x 

1 y  2x2 2 1x  y 2 2

; f√ 

; fy  

y1 y 2  x 2 2

16. tx 

x  1x 2 1y

; fy 

2 2

; ty 

2

u√

ey 21xe y  12 1/2

3x

1 y  2x2 2

x1x 2  y 2 2

xe y

39. 337.5 yd  900 yd

19. f x  2x11  x 2  y 2 2e x y ; f y  2y11  x 2  y 2 2e x y 20. f x  21. fx 

4x 1  2x 2  4y 4 2x x y 2

2

2

; fy 

; fy  

2

16y 3

Chapter 12 Before Moving On, page 862

2

1. All real values of x and y satisfying x  0, x  1, y  0, y  2 y

2.

1  2x 2  4y 4

2

2x 2

y1x  y 2 2

2

22. fxx  6x  4y; fxy  4x  fyx; fyy  2

–3

23. fxx  12x  4y ; fxy  8xy  fyx ; fyy  4x  12y 2

2

2

24. fxx  12(2x 2  3y 2)(10x 2  3y 2); fxy  144xy(2x 2  3y 2)  fyx; fyy  18(2x 2  3y 2)(2x 2  15y 2) 25. txx  tyy 

2y 2

1x  y 2

2 3

; txy 

2y1x  y 2 2

 tyx ;

1x  y 2 2 3

1x  y2 2 3

26. txx  2(1  2x 2)e x y ; txy  4xye x y  tyx; 2 2 tyy  2(1  2y 2)e x y 2

2

3

z = –3 z = –2

x

−2

2x13y 2  x2

2

x

38. The company should spend $11,000 on advertising and employ 14 agents in order to maximize its revenue.

21xe y  1 2 1/2

2

8 10

37. Complementary

1x 2  y 2 2 2

; fy 

6

36. a. R(x, y)  0.02x 2  0.2xy  0.05y 2  80x  60y b. The set of all points satisfying 0.02x  0.1y 80, 0.1x  0.05y 60, x  0, y  0 c. 15,300; the revenue realized from the sale of 100 16-speed and 300 10-speed electric blenders is $15,300.

2u√ 2  2u

17. hx  10y(2xy  3y 2)4; hy  10(x  3y)(2xy  3y 2)4 18. f x 

4

2

2

3. 14; 29; at the point (1, 2), f (x, y) increases at the rate of 14 units for each unit increase in x with y held constant at a value of 2; f (x, y) increases at the rate of 29 units per unit increase in y with x held fixed at 2. 4. fx  2xy  ye xy; fxx  2y  y 2e xy; fxy  2x  (xy  1)e xy  fyx; fy  x 2  xe xy; fyy  x 2e xy 5. Relative minimum value: (1, 1, 7)

INDEX Abscissa, 68 Absolute extrema, 712, 850 Absolute value, 58–59 Amortization, 215–219 formula, 215 schedule, 216 Annuity, 204–207 amount of, 814 certain, 204 compound amount factor, 205 future value, 206 ordinary, 204 present value, 207, 815 simple, 204 term, 204 Antiderivative, 742 Antidifferentiation, 744 Area between curves, 797–802 under a curve, 775–776, 788 Arithmetic progression, 228–230 common difference, 228 nth term, 228 sum, 229 Asymptotes, 697–701 horizontal, 700 vertical, 698 Augmented matrix, 252 Average cost function, 644 Average rate of change, 574 Average value, 789–791 Average, 504 Axes, 69 Base, 7, 154 Basic solution, 354 Basic variables, 353 Bayes’ theorem, 486 Birthday problem, 466–467 Book value, 69, 111, 232, 636 Break-even analysis, 114–116 Break-even point, 114 Carbon-14 dating, 173 Cartesian coordinate system, 68 coordinate, 68 ordered pair, 68 origin, 68 quadrants, 69 three-dimensional, 830

Chain Rule, 618–623 for exponential functions, 632 for logarithmic functions, 635 for powers of functions, 620–624 Change of variable, 756 Chebychev’s inequality, 521 Closed interval, 53 Cobb–Douglas production function, 841 Coefficient matrix, 252 Coefficient of inequality, 816 Column matrix, 276 Column vector, 276 Combinations, 422–426 Combinatorics, 405 Common factors, 15–16 Common logarithm, 162 Complement of a set, 399 Complementary commodities, 842 Completing the square, 45–46 Composition of functions, 105–107 Compound fraction, 23 Compound interest, 187–190. See also Interest Concavity, 678–680 intervals, 679 test for, 679 Conditional probability, 471–473 Conjugates, 41 Constant of integration, 744 Consumers’ surplus, 808–809 Continuity, 556–559 on an interval, 557 at a number, 556 of polynomial and rational functions, 558 Continuous compound interest, 190–191 Continuous function, 556 Continuous random variable, 495 Contour map, 831 Conversion period, 187 Coordinates, 68 Cost function, 104, 112, 642–643 Counting problem, 405 Critical number, 665 Critical point, 852 Cube root, 36 Curve sketching, 697–704 Decay constant, 172 Decimal representation, 3

Decreasing function, 658 Definite integral, 769 as area, 766–769 evaluation of, 776–780 geometric interpretation, 770–771 as a limit of a sum, 769 limits of integration, 769 method of substitution, 786–788 properties of, 786 Degree of a polynomial, 9 Demand function, 126 De Morgan’s laws, 400 Dependent variable, 89, 828 Depreciation book value, 69, 232 double-declining balance, 232–233 linear, 111–112 straight line, 69, 111 sum-of-the-years’-digits, 235 Derivative definition, 574 four step process, 575 higher-order, 607–609 instantaneous rate of change, 574 notation, 574 partial, 837–841 as a rate of change, 573 second, 853 second-order partial, 844 Derivative rules, 589–591, 602–603 chain, 619 constant, 589 constant multiple of a function, 591 for exponential functions, 630, 632 for logarithmic functions, 633, 635 Power Rule, 590, 620 Product Rule, 602 Quotient Rule, 603 Sum Rule, 591 Difference quotient, 573 Differential equations, 747–748 Differentialable function, 580 Discontinuous function, 557 Discriminant, 49 Disjoint sets, 405 Domain of a function of one variable, 87 of a function of two variables, 828 Dual problem, 378

916

INDEX

e, 157 Effective rate of interest, 191 Empty set, 397 Equality properties, 30 Equations of straight lines, 79 Equilibrium price, 128 quantity, 128 Events, 431–433 complement of, 432 independent, 478–480 intersection of, 432 mutually exclusive, 433, 440 probability of, 439–440 simple, 440 union of, 432 Expected value, 505 Experiment, 431 event, 431 outcome, 431 sample point, 431 sample space, 431 Exponent, 7, 26–28, 155 Exponential decay, 172 Exponential function, 154 applications of, 171–176 base e, 157 derivative of, 630 graph of, 157 indefinite integral of, 746 properties of, 156 Exponential growth, 171 Exponential notation, 7 Extraneous solution, 32 Factorial, 419 Factoring by regrouping, 17–18 Factoring polynomials, 14–18 Fair game, 508 Feasible set, 338 Feasible solution, 338 Finite interval, 53 Finite sample space, 431 First derivative test, 665 Fixed costs, 104 Function, 87, 90 average cost, 644 average value of, 790 composite, 105–107 continuous, 556 cost, 104, 112 decreasing, 658 demand, 126 dependent variable, 89 differentiable, 580

domain, 87 exponential, 154 graph of, 90 increasing, 659 independent variable, 89 linear, 111 logarithmic, 165 marginal average cost, 644 marginal cost, 644 marginal profit, 648 marginal revenue, 646 objective, 330 piecewise defined, 92 polynomial, 9, 135 power, 138 probability, 440 product of, 104 profit, 105, 112 quadratic, 123 range, 88 rational, 137 revenue, 112 zero of, 560 Functions of several variables, 828–831 critical points, 852 dependent variable, 828 domain, 828 independent variable, 828 maxima and minima, 850–857 partial derivative of, 837–839 saddle point, 851 Second derivative test, 853 Fundamental Theorem of Calculus, 774–781 Fundamental Theorem of Duality, 378 Future value, 193 Gauss–Jordan elimination method, 249–259 row operations, 254 steps in, 256 Generalized multiplication principle, 413 Geometric progression, 230–232 common ratio, 230 nth term, 230 sum, 232 Graph of an equation, 93 of a function, 91, 830–831 of linear inequalities, 322–327 Growth constant, 171 Half-life, 172 Half-open interval, 53 Half-planes, 322

Higher-order derivative, 607–608 Histogram, 497 Horizontal asymptote, 700 Identity matrix, 291 Income stream, 811–814 Increasing function, 658 Indefinite integral, 744 of a constant, 744 of a constant multiple of a function, 745 of an exponential function, 746 Power Rule, 745 Sum Rule, 746 Independent events, 478–480 Independent variable, 89, 828 Indeterminate forms, 540 Index, 37 Inequalities, 54–57 Infinite interval, 53 Inflection point, 681 Initial value problem, 748 Instantaneous rate of change, 574 Integer, 2 Integer exponents, 26–28 Integral change of variable, 756 of a constant, 744 of a constant multiple of a function, 745 definite, 769 of an exponential function, 746 indefinite, 744 notation, 744 Power Rule for, 745 properties of, 786 sign, 744 Sum Rule for, 746 Integrand, 744 Integration. See also Integral constant of, 744 limits of, 769 rules, 744–747 by substitution, 755–759, 786–788 Intercepts, 80 Interest compound, 187–190 accumulated amount, 188 formula, 188 future value, 188 present value, 193 principal, 188 continuous compound, 190–191, 194 accumulated amount, 190 present value, 194 conversion period, 187 effective rate of, 191–193

INDEX

simple, 186 accumulated value, 186 formula, 186 Intermediate value theorem, 560 Intersection of lines, 113–114 Intersection of sets, 399 Interval(s), 53–54 closed, 53 finite, 53 half-open, 53 infinite, 53 open, 53 Inventory control, 730–731 Inverse of a matrix, 302 Irrational number, 2 Isoprofit line, 339 Isotherms, 833 Laws of exponents, 27, 155 Laws of logarithms, 163 Learning curves, 174–175 Level curves, 831 Limits, 534–547 of a function, 537 at infinity, 543 of integration, 787 left-hand, 555 properties of, 539 right-hand, 555 Linear depreciation, 111 Linear equations, 30–34 forms of, 79 general form, 79, 246 intercepts, 77 point-slope form, 79 slope-intercept form, 79 vertical lines, 79 Linear function(s), 111–113 break-even analysis, 114 simple depreciation, 111 Linear inequality, 322–325 Linear programming feasible set, 338 feasible solution, 338 graphical solution, 338–344 maximization problems, 351–353, 366 method of corners, 340 minimization problems, 376–384 objective function, 330 optimal solution, 338 problem, 330, 377 basic solution, 354 dual, 378 existence of a solution, 340 primal, 378

standard, 351, 376 simplex method, 351–366, 376–384 basic variables, 353 initial simplex tableau, 356 nonbasic variables, 353 optimal solution(s), 338 pivot column, 355 pivot element, 355 pivot row, 355 simplex tableau, 356 slack variables, 352 steps in, 357 Line of complete equality, 816 Lines. See Linear equations Logarithmic functions, 165–168 derivative of, 633–635 graph of, 166 properties of, 166 Logarithms, 162–165 common, 162 laws of, 163 natural, 162 Logistic curve, 175 Logistic growth function, 175–176 Lorentz curves, 816–817 Marginal analysis, 642–648 average cost function, 644 cost function, 643 productivity, 841 profit function, 648 revenue, 646 Market equilibrium, 128–129 Mathematical models, 134–140 Matrix, 252, 276 addition, 278–279 augmented, 252 coefficient, 252 column, 276 definition, 276 dimension, 276 elements, 276 entries, 276 equality, 277 identity, 291 ijth entry (aij), 276 inverse, 302 inverse of a 2  2 matrix, 305 multiplication, 287–293 nonsingular, 302 pivot element, 255 product, 288 production, 292 representation, 293

row, 276 row operations, 254 row-reduced form, 253 scalar product, 280 singular, 302 size, 276 square, 276 subtraction, 278 transpose, 280 zero, 279 Maxima and minima absolute, 712, 850 relative, 663–664, 850 Mean, 504 Median, 511 Method of corners, 340 Method of integration by substitution, 755–759, 786–788 Minima. See Maxima and minima Mode, 512 Modeling, 134–140 Multiplication principle, 411–415 Mutually exclusive events, 433, 440 Natural logarithm, 162 Natural number, 2 Nominal rate, 187 Nonbasic variables, 353 nth roots, 36 Number line, 3–4 Objective function, 330 Odds, 509–511 Open interval, 53 Operations, 4 Optimal solution, 338 Optimization, 711–718, 726–732 Ordered pair, 68 Ordered triple, 830 Order of operations, 12 Ordinary annuity, 204 Ordinate, 68 Origin, 68 Outcome, 431 Parabola, 123 Parallel lines, 72 Parameter, 243 Partial derivative first-order, 838 second-order, 844 Partition, 485 Permutations, 417–422 n distinct objects, 420 n objects, 421

917

918

INDEX

Perpendicular lines, 76 Piecewise defined function, 92 Pivot column, 355 Pivot element, 255, 355 Pivoting, 255, 357–358 Pivot row, 355 Polynomial(s), 7–12 addition, 10 factoring, 14–18 multiplication, 10–12 in one variable, 9 subtraction, 10 Power Rule for differentiation, 590, 620 for integration, 745 Present value, 193 Primal problem, 378 Probability addition principle, 442, 450 a posteriori, 485 a priori, 485 Bayes’ theorem, 486 conditional, 471–475 counting techniques, 464–466 distribution, 440 elementary event, 440 empirical, 440 of an event, 440 expected value, 505 experiment, 431 function, 440 independent event, 478 mutually exclusive events, 433, 440 Product Rule, 474 properties, 449–452 relative frequency, 440 rule of complements, 452 sample point, 431 sample space, 431 event, 431 finite, 431 infinite, 435 reduced, 471 uniform, 441 simple event, 440 tree diagram, 412, 475–477 Producers’ surplus, 810 Production function, 841–842 Product Rule, 474, 602 Profit function, 112, 648 Quadrant, 69 Quadratic equations, 44–49 Quadratic formula, 46

Quadratic function, 123–129 Quotient Rule, 603 Radical(s), 37 index, 37 sign, 37 simplification of, 39–42 Radicand, 37 Radioactive decay, 172–173 Random variable, 494 continuous, 495 expected value, 504–505 finite discrete, 495 infinite discrete, 495 probability distribution of, 496 standard deviation of, 519 variance, 517 Range, 88 Rate of change, 573–574 average, 573 instantaneous, 573 Rational expression(s), 20–24 addition, 22–23 multiplication, 21–22 simplification, 20 subtraction, 22–23 Rationalization, 41–42 Rational number, 2 Real number(s), 2–6 decimal representation, 3 line, 3 operations, 4–6 order of operations, 12 properties, 4–5 Real number system, 2–6 integers, 2 irrational numbers, 2 natural numbers, 2 rational numbers, 2 whole numbers, 2 Relative extrema, 664, 850, 853 Relative frequency, 440 Relative maximum, 663 test for, 666, 853 Relative minimum, 664 test for, 666, 853 Repeating decimal, 3 Revenue function, 112, 646–647 Riemann sum, 769 Roulette, 508 Row matrix, 276 Row operations, 254 Row reduced form, 253 Rule of complements, 452

Saddle point, 851 Sample space, 431 finite, 431 infinite, 435 reduced, 471 uniform, 441 Scalar, 280 Secant line, 572 Second derivative test, 685, 853 Second-order partial derivative, 844 Set(s), 396–401 complement, 399 De Morgan’s laws, 400 definition, 396 disjoint, 399 elements, 396 empty, 397 equal, 396 intersection, 399 members, 396 notation roster, 396 set-builder, 396 number of elements in, 405–408 operations, 400 proper subset, 397 subset, 397 union, 399 universal, 398 Venn diagrams, 398 Simple depreciation, 111 Simple interest, 186 Simplex method. See Linear programming Simplex tableau, 357 Singular matrix, 302 Sinking fund, 219, 815 Slack variables, 352 Slope, 70 of a tangent line, 572 Solution of an equation, 30 Solution set bounded, 326 unbounded, 326 Square matrix, 276 Square root, 36 Standard deviation, 519 Standard linear programming problem, 351, 376 Stochastic process, 475 Straight line depreciation, 69, 111 Subset, 397 Substitute commodities, 842 Supply function, 127

INDEX

Systems of linear equations, 242–245 dependent, 244 equivalent, 250 Gauss–Jordan elimination method, 250–259 inconsistent, 244 solution by inverses, 306–308 solution by substitution, 242–245 Systems of linear inequalities, 322–325 half-planes, 322 procedure for graphing, 324 Tangent line, 572 Terminating decimal, 3 Test for independent events, 478–479 Total cost function, 112 Trace, 831

Transportation problem, 332–334 Transpose of a matrix, 279 Tree diagram, 412, 475–477 Triangle inequality, 58 Uniform sample space, 441, 464 Union of sets, 399 Unit column, 254 Universal set, 398 Variable(s) basic, 353 dependent, 89, 828 independent, 89, 820 nonbasic, 353 random, 494 slack, 352

Variable costs, 104 Variance, 517 Velocity average, 535–536, 573, 578 instantaneous, 535–536, 578 Venn diagrams, 398 Vertical asymptotes, 698 Vertical-line test, 93 Warehouse problem, 333–334 Whole number, 2 Zero exponent, 26 Zero matrix, 279 Zero-product property, 44

919

How-To Technology Index 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39.

Graph a straight line Graph a function Evaluate a function Find the point(s) of intersection of two graphs Construct mathematical models Find the accumulated amount of an investment Find the effective rate of interest Find the present value of an investment Find the future value of an annuity Find the present value of an annuity Find the payment needed to amortize a loan Find the payment needed for a sinking fund Solve a system of linear equations using the Gauss–Jordan method Perform matrix operations Perform matrix multiplication Find the inverse of a square matrix Use the simplex method to solve a maximization linear programming problem Use the simplex method to solve a minimization linear programming problem Evaluate n!, P(n, r), and C(n, r) Simulate an experiment Graph a histogram for a given set of data Find the mean and standard deviation of a random variable Find the limit of a function Find the points of discontinuity of a function Graph a piecewise-defined function Graph a function and its tangent line Find the derivative of a function at a given point Find the rate of change of a function at a given value Find the second derivative of a function at a given point Find the derivative of a composite function Use the first derivative to analyze a function Find the inflection points of a function Analyze the properties of a function Find the x-intercepts on the graph of a function Find the absolute extrema of a function Evaluate a definite integral Evaluate a definite integral for a piecewise-defined function Find the area between two curves Find the partial derivative of a function at a given point

Page 84 100 101 132 144, 180 201 201 201 212 212 225 226 263, 274 284 299 313 372 387 430 441 502 527 552 568 568 586 586 600 616 629 675 695 709 710 724 784 795 807 849

Formulas Equation of a Straight Line

a. point-slope form: y  y1  m(x  x1) b. slope-intercept form: y  mx  b c. general form: Ax  By  C  0 (i  r/m, n  mt)

A  P(1  i)n

Compound Interest

where A is the accumulated amount at the end of n conversion periods, P is the principal, r is the interest rate per year, m is the number of conversion periods per year, and t is the number of years. reff  a1 

Effective Rate of Interest

r m b 1 m

where reff is the effective rate of interest, r is the nominal interest rate per year, and m is the number of conversion periods per year. SRc

Future Value of an Annuity

PRc

Present Value of an Annuity

11  i 2 n  1 i

1  11  i 2 n i

Amortization Formula

R

Pi 1  11  i 2 n

Sinking Fund Payment

R

iS 11  i2 n  1

The Number of Permutations of n Distinct Objects Taken r at a Time

P(n, r) 

The Number of Permutations of n Objects, Not All Distinct

C(n, r) 

n! 1n  r2!

n! r!1n  r 2!

P(A  B)  P(A)  P(B  A)

The Product Rule for Probability

Expected Value of a Random Variable

d

n! , where n1  n2  . . .  nm  n n1!n2! . . . nm!

The Number of Combinations of n Distinct Objects Taken r at a Time

Bayes’ Formula

d

P(Ai  E) 

P1Ai 2 # P1E Ai 2

P1A1 2 # P1E A1 2  P1A2 2 # P1E A2 2  . . .  P1An 2 # P1E An 2 E(X)  x1 p1  x2 p2  . . .  xn pn

Basic Rules of Differentiation 1.

d 1c2  0, dx

2.

d n du 1u 2  nu n1 dx dx

3.

d du d√ 1u √2 

dx dx dx

4.

d du 1cu 2  c , c, a constant dx dx

5.

d d√ du 1u√2  u  √ dx dx dx

c, a constant

d√ du u d u dx dx 6. a b  dx √ √2 √

7.

d u du 1e 2  e u dx dx

8.

d 1 du 1ln u2  # u dx dx

Basic Rules of Integration 1.

 du  u  C

2.

 kf 1u2 du  k  f 1u2 du,

3.

 3 f 1u2 t1u2 4 du   f 1u2 du  t1u2 du

4.

 u n du  n  1  C,

5.

 e u du  e u  C

6.



u n1

du  ln 0 u 0  C u

k, a constant

n  1

List of Applications BUSINESS AND ECONOMICS 401(k) investors, 456, 726 401(k) retirement plans, 296 Access to capital, 525 Accumulated value of an income stream, 812 Accumulation years of baby boomers, 629 Adjustable-rate mortgage, 219, 224 Advertising, 334, 336, 348, 370, 386, 833 Age distribution of company directors, 527 Agriculture, 247, 261, 311, 335 Ailing financial institutions, 565, 581 Aircraft structural integrity, 670 Airline safety, 447 Air travel, 180, 638 Allocation of funds, 335, 347 Alternative energy sources, 456, 806 Alternative minimum tax, 159, 692 Amusement park attendance, 629 Annual retail sales, 119, 145, 588 Annuities, 209, 215, 217, 220, 222, 238, 814, 819 Assembly-time studies, 438, 457, 690, 779 Asset allocation, 335, 336, 347, 369, 370 Asset appreciation, 636 ATM cards, 416 Auditing tax returns, 482 Automatic tellers, 438 Automobile financing, 211, 223, 790 Automobile leasing, 211, 238 Automobile options, 401 Auto replacement parts market, 142 Average age of cars in U.S., 711 Average price of a commodity, 794 Average prices of homes, 722 Average single-family property tax, 131 Balloon payment mortgage, 224 Banking, 93, 283, 751 Beverage research, 492 Bidding for contracts, 428 BlackBerry subscribers, 141 Black Monday, 697 Book design, 48, 143, 734 Bookstore inventories, 283 Box office receipts, 243, 262, 296, 550, 613, 707 Brand selection, 469 Break-even analysis, 114, 119 Bridge loans, 198 Broadband Internet households, 118 Broadband versus dial-up, 120 Budget deficit and surplus, 103 Business spending on technology, 692 Business travel expenses, 262 Cable television, 514 Cable TV ads, 617 Cable TV subscription, 655, 753, 763, 793 Canadian oil-sands production, 783 Capital expenditures, 307 Cargo volume, 677 Cash reserves at Blue Cross and Blue Shield, 694 CDs, 238 Charter revenue, 140, 143, 735 Chip sales, 141 City planning, 554 Coal production, 792, 806 Cobb–Douglas production function, 842, 846, 862 COLAs, 235 Cold formula production, 337, 370 Commissions, 565 Commodity prices, 566, 655, 794 Common stock transactions, 200, 294, 318, 438 Company sales, 230, 232, 238 Complementary commodities, 843, 847 Computer game sales, 180 Computer resale value, 824 Computer sales projections, 761 Computer security, 696 Computing phone bills, 297 Consolidation of business loans, 199 Construction jobs, 110, 617, 627 Consumer decisions, 198, 235 Consumer demand, 578, 597, 613 Consumer price index, 598, 684 Consumer surveys, 406, 408, 409, 456 Consumers’ surplus, 810, 817, 818, 826 Consumption of boiled water, 146 Consumption of electricity, 198, 780 Contract bidding, 428

Corporate bonds, 198 Cost of a commodity, 83 Cost of drilling, 235 Cost of producing DVDs, 656, 707 Cost of producing guitars, 752 Cost of producing loudspeakers, 298 Cost of producing PDAs, 109 Cost of producing solar cell panels, 759 Cost of producing surfboards, 584 Cost of removing toxic waste, 612, 707, 708 Cost of wireless phone calls, 655 Creation of new jobs, 110, 617, 627 Credit card debt, 142, 239, 752 Credit cards, 142, 239, 461, 752 Cruise ship bookings, 628 Customer service, 438 Decision analysis, 115, 116, 119, 803 Demand for Bluetooth headsets, 127 Demand for CD players, 862 Demand for computers, 178 Demand for digital camcorder tapes, 825 Demand for DVD players, 183 Demand for electricity, 725, 780 Demand for RNs, 691 Demand for wristwatches, 628 Depreciation, 233, 793 Designing a metal container, 52 Dialup Internet households, 118 Digital TV sales, 692 Digital TV services, 83 Digital TV shipments, 146 Digital versus film cameras, 119 Disability benefits, 613 Disability rates, 159 Double-declining balance depreciation, 234, 236 Dow-Jones Industrial average, 697 Downloading music, 457 Driving costs, 138, 551, 558 Drug spending, 693 Durable goods orders, 444 DVD sales, 824 Economic surveys, 410 Effect of advertising on bank deposits, 689 Effect of advertising on hotel revenue, 692 Effect of advertising on profit, 126, 130, 584 Effect of advertising on revenue, 109, 805 Effect of advertising on sales, 178, 598, 684 Effect of budget cuts on drug-related crimes, 691 Effect of housing starts on jobs, 627 Effect of inflation on salaries, 199 Effect of luxury tax on consumption, 627 Effect of mortgage rates on housing starts, 110 Effect of TV advertising on car sales, 806 Efficiency studies, 783 Electricity consumption, 198 Electricity generation, 457 Employee education and income, 483 Energy conservation, 693, 797 Energy consumption, 565 Energy efficiency of appliances, 639 Expected auto sales, 514, 515 Expected demand, 513 Expected home sales, 515 Expected product reliability, 514 Expected profit, 506, 514 Expected sales, 514 Federal budget deficit, 103 Federal debt, 178, 181 Female self-employed workforce, 720 Fighting inflation, 445 Financial analysis, 222, 392 Financial planning, 212, 223, 239 Financing a car, 208, 222, 223 Financing a college education, 199, 223 Financing a home, 222, 223, 224, 225 Flex-time, 530 Forecasting profits, 693 Foreign exchange, 296 Franchise, 819 Fuel economy of cars, 601, 658 Gasoline sales, 281, 285, 286, 318 Gift cards, 141 Global supply of plutonium, 109 Google’s revenue, 693 Green companies, 447 Gross domestic product, 57, 584, 595, 613, 687, 707, 722 Growth in a health club membership, 623 Growth of HMOs, 602 Growth of managed services, 672 Growth of Web sites, 159

Health-care costs, 752, 753 Health-care plan options, 416 Health-care spending, 14, 599 Health club membership, 151, 622 Hedge funds, 98, 602 Hiring lobbyists, 102, 147, 694 Home affordability, 218 Home equity, 217 Home financing, 239 Home mortgages, 216, 221, 222, 830, 835 Home refinancing, 224 Home sales, 283 Home-shopping industry, 570 Hospital costs,198 Hotel occupancy rate, 110, 627 Hotel rates, 98 Hours worked in some countries, 525 Housing appreciation, 198, 200, 448 Housing loans, 482 Housing prices, 524, 791 Housing starts, 110 Illegal ivory trade, 142 Income distributions, 487, 817, 826 Income stream, 812 Incomes of American families, 630, 641 Increasing crop yields, 641 Indian gaming industry, 144 Industrial accidents, 521 Inflation, 610 Installment contract sales, 826 Instant messaging accounts, 130, 597 Insurance claims, 283 Insurance probabilities, 514, 530 Interest rate prediction, 514 Internet advertising, 783 Internet gaming sales, 180 Internet usage, 636 Internet users in China, 159, 161 Inventory control and planning, 565, 732, 736, 737, 740 Investment analysis, 209, 211, 212, 224, 248, 261, 295, 349, 392, 409, 514, 515, 523, 813 Investment clubs, 248, 261, 262, 311 Investment options, 196, 199, 414, 425 Investment planning, 199, 248, 261 Investment portfolios, 283, 318 Investments, 199, 318, 410, 455, 461 IRAs, 196, 209, 210, 211, 223, 814, 819 Keogh accounts, 211 Kinetic energy of a body, 848 Land prices, 847 Launching a fighter aircraft, 755 LCDs versus CRTs, 119 Leasing, 119 Life insurance premiums, 514 Linear depreciation, 35, 111, 117, 118, 150 Loan amortization, 222, 225, 226, 641 Locating a power station, 858 Locating a TV relay station, 856 Lorentz curves, 816, 817, 819, 826 Machine scheduling, 318 Magazine circulation, 749 Management decisions, 248, 262, 272, 422, 427, 428 Manufacturing capacity, 677 Manufacturing capacity operating rate, 718 Marginal average cost functions, 644, 645, 649, 650 Marginal cost functions, 642, 643, 649, 782, 824, 825 Marginal productivity of labor and capital, 842, 845 Marginal profit, 648, 650, 782 Marginal propensity to consume, 650 Marginal propensity to save, 651 Marginal revenue functions, 647, 650, 782, 824 Market equilibrium, 128, 133, 151 Market for cholesterol reducing drugs, 121, 122 Marketing surveys, 407 Market research, 349 Market share, 284, 583, 750 Maximizing crop yield, 735 Maximizing profit, 130, 341, 367, 392, 715 Maximizing revenue, 130, 721, 862 Maximum capacity of an oil well, 721 Maximum power output, 723 Meeting profit goals, 61 Meeting sales targets, 61 Membership in credit unions, 825 Metal fabrication, 733 Minimizing average costs, 716, 721, 740 Minimizing construction costs, 733, 740 Minimizing container costs, 730, 734 Minimizing costs of laying cable, 735 Minimizing fencing costs, 862

(continued)

List of Applications (continued) Minimizing heating and cooling costs, 859 Minimizing mining costs, 335, 348, 392 Minimizing packaging costs, 734, 740 Minimizing production costs, 721 Minimizing shipping costs, 332, 333, 336, 337, 348, 386 Minimizing travel time, 736 Mining production, 335 Mobile-phone ad spending, 783, 793 Mobile enterprise IM accounts, 147 Money market mutual funds, 200 Money market rates, 500 Movie attendance, 434, 444 Multimedia sales, 696 Municipal bonds, 198 Music venues, 447 Mutual funds, 198, 238 Net investment flow, 792 New construction jobs, 617 Newsmagazine shows, 763 Newspaper advertisements, 428 Newspaper subscriptions, 411 Nielsen television polls, 569, 582 Nuclear plant utilization, 82 Occupancy rate, 524 Office rents, 722 Office vacancy rate, 148, 793 Oil production, 793, 825 Oil production shortfall, 805 Oil spills, 144, 763 Online ad sales, 753 Online banking, 180, 638 Online buyers, 597 Online hotel reservations, 739 Online retail sales, 199, 825 Online video viewers, 141, 597 Optimal charter flight fare, 734 Optimal market price, 717 Optimal selling price, 721 Optimal speed of a truck, 735 Optimal subway fare, 729 Optimizing production schedules, 272 Organizing business data, 276, 278, 280 Organizing production data, 276, 278 Organizing sales data, 283 Outsourcing of jobs, 141, 626, 693 Packaging, 89, 143, 519, 727, 730, 733, 740, 858, 859 PC shipments, 181 Pension funds, 198, 199 Personal consumption expenditure, 650 Personal loans, 224 Personnel selection, 428, 469, 492 Petroleum production, 318 Plans to keep cars, 457 Pocket computers, 783 Predicting sales figures, 78 Prefab housing, 337, 370 Present value of a franchise, 826 Present value of an income stream, 813 Price of ivory, 142 Price of perfume, 639 Pricing, 310 Prime interest rate, 565 Producers’ surplus, 810, 817, 818, 826 Product design, 734 Product reliability, 482, 484, 491, 495, 514 Product safety surveys, 445 Production costs, 108, 649, 778 Production planning, 280, 292, 297, 298, 330, 337, 348, 349, 364, 369, 370, 386 Production scheduling, 244, 258, 259, 262, 272, 334, 336, 337, 347, 392 Productivity fueled by oil, 639 Productivity of a country, 846 Profit from sales of loudspeaker systems, 647 Profit from sales of pagers, 109 Profit from sales of PDAs, 109 Profit of a vineyard, 51, 144, 735 Projected Provident funds, 673 Projected retirement funds, 673 Projected U.S. gasoline usage, 793 Projection TV sales, 824 Promissory notes, 199 Purchasing a home, 212 Purchasing power, 199 Quality control, 61, 427, 437, 438, 444, 446, 451, 462, 465, 469, 477, 480, 482, 483, 484, 486, 490, 491, 530, 752 Racetrack design, 736 Rate comparisons, 199 Rate of bank failures, 617 Rate of change of DVD sales, 605 Real estate, 195, 199, 248, 261, 296, 454, 512, 773 Recycling, 460

Refinancing a home, 224, 225 Reliability of a home theater system, 484 Reliability of computer chips, 178, 551 Reliability of security systems, 483 Resale value, 177 Restaurant revenue, 108 Retirement planning, 198, 211, 221, 223, 238, 447, 490, 826 Revenue growth of a home theater business, 199 Revenue of a charter yacht, 735 Revenue of a travel agency, 585 Revenue of Polo Ralph Lauren, 131 Revenue projection, 515 Reverse annuity mortgage, 819 Ridership, 248, 261 Rising water rates, 141 Risk of an airplane crash, 447 Royalty income, 210 Salary comparisons, 235 Sales forecasts, 78 Sales growth and decay, 235 Sales of camera phones, 739 Sales of digital cameras, 597 Sales of digital signal processors, 145 Sales of digital TV’s, 692 Sales of DSPs, 145 Sales of DVD players vs. VCRs, 143 Sales of functional food products, 673 Sales of GPS equipment, 82 Sales of mobile processors, 693 Sales of MP3 players, 150 Sales of prerecorded music, 150 Sales promotions, 639 Satellite radio subscriptions, 752 Satellite TV subscribers, 80 Self-serve gas sales, 94 Selling price of DVD recorders, 141, 626 Shipping costs, 336, 337, 348, 386 Shoplifting, 446 Shortage of nurses, 599 Shuttle bus usage, 438 Sickouts, 726 Sinking funds, 220, 223, 226, 227, 239, 815 Socially responsible funds, 626 Social Security beneficiaries, 571 Social Security benefits, 118 Social Security contributions, 82 Solvency of the Social Security system, 136, 148 Spam messages, 109 Spending on fiber-optic links, 673 Spending on Medicare, 598 Staffing, 417 Starting salaries, 526 Stock transactions, 57, 288 Substitute commodities, 843, 847 Sum-of-the-years’-digits method of depreciation, 235 Supply and demand, 51, 127, 150 Switching Internet service providers, 483 Switching jobs, 456 Tax planning, 209 Tax preparation, 456 Telecommunications industry revenue, 147 Television pilots, 500 Television programming, 427 Testing new products, 435, 442, 443 Time on the market, 696 TIVO owners, 147 Tour revenue, 309 Tracking with GPS, 158 Transportation, 335, 348 Transportation problem, 332 Trust funds, 187, 198, 223, 236 TV households, 454 TV mobile phones, 710, 763 TV-viewing patterns, 569, 582, 763 Unemployment rates, 514 Union bargaining issues, 416 U.S. financial transactions, 119 U.S. health-care information technology spending, 98 U.S. sales of organic milk, 754 U.S. set-top boxes, 783 Use of brokers, 409 Use of diesel engines, 725 Value of an investment, 108 Venture-capital investments, 722 Wages, 516, 580 Waiting lines, 496, 500, 504, 505, 516 Warehouse problem, 333, 381 Warranties, 417, 452 Waste disposal, 794 Web conferencing, 146 Web hosting, 673 Wilson lot size formula, 836

Worker efficiency, 98, 598, 692, 707, 740 World production of coal, 792 Worldwide networked PCs, 655 Worldwide PC shipments, 181 Worldwide production of vehicles, 629 Yield of an apple orchard, 143 Zero coupon bonds, 199, 200

SOCIAL SCIENCES Accident prevention, 444 Age distribution in a town, 528 Age distribution of renters, 491 Age of drivers in crash fatalities, 674 Aging drivers, 140 Aging population, 599 Air pollution, 61, 626, 673, 674, 677, 694, 711, 721, 824 Americans without health insurance, 525 Arrival times, 446 Arson for profit, 835 Assembly time, 174 Auto-accident rates, 492, 513 Automobile pollution, 106 Average life span, 169 Birthrates, 523 Boston homicides, 524 Bursts of knowledge, 559 Car pools, 427 Car theft, 482 Closing the gender gap in education, 97 College admissions, 82, 151, 297, 483, 530 College majors, 493 College savings program, 238 Committee selection, 423 Commuter options, 416 Commuting times, 511, 530 Commuter trends, 409, 824 Compliance with seat belt laws, 490 Conservation of oil, 801 Consumer decisions, 198 Consumer surveys, 409, 410, 445, 456 Continuing education enrollment, 626 Correctional supervision, 446 Cost of removing toxic waste, 61, 550, 612 Course enrollments, 456 Course selection, 428 Court judgment, 198 Crime, 491, 613, 669, 707, 722 Cube rule, 98 Curbing population growth, 598 Demographics, 179 Dependency ratio, 694 Disposition of criminal cases, 446 Dissemination of information, 179 Distracted driving, 457 Distribution of families by size, 500 Distribution of incomes, 61, 487, 630, 816, 817 Drivers’ tests, 428, 469 Driving age requirements, 523 Education and income, 483 Educational level of voters, 482 Effect of budget cuts on crime rate, 691 Effect of smoking bans, 692 Efforts to stop shoplifting, 446 Elderly workforce, 720 Elections, 462, 488 Election turnout, 526 Exams, 417, 428, 500, 515, 524 Family composition, 435 Female life expectancy, 763 Financing a college education, 199, 208 Foreign-born medical residents, 722 Gender gap, 98, 491 Global epidemic, 692 Grade distributions, 445 Growth of HMOs, 602 Gun-control laws, 457 Health-care spending, 107, 146 Immigration, 141, 176 Increase in juvenile offenders, 641 Index of environmental quality, 739 Jury selection, 428 Lay teachers at Roman Catholic schools, 178 Learning curves, 178, 559, 565, 613, 764 Library usage, 499 Life expectancy, 284 Logistic curves, 175 Male life expectancy, 656 Marijuana arrests, 785 Marital status of men, 525

Married households, 159 Married households with children, 597 Mass transit, 729 Medical school applicants, 673 Mortality rates, 284 Motorcycle deaths, 109 Narrowing gender gap, 82 Oil spills, 52, 627 Opinion polls, 444, 490, 491 Organizing educational data, 297, 410 Organizing sociological data, 500, 525 Over-100 population, 638 Overcrowding of prisons, 109, 674 Parental influence, 446 Percentage of females in the labor force, 641 Percentage of population relocating, 638 Political polls, 416, 438, 446 Politics, 98, 438, 490 Population growth, 235, 598, 613, 617, 753, 763, 777, 785, 806, 826 Population growth in Clark county, 147, 693 Population growth in the 21st century, 179, 180 Prison population, 109, 409, 674 Psychology experiments, 416 Public housing, 469 Research funding, 311 Rising median age, 98 Rollover deaths, 456 Safe drivers, 102 Same-sex marriage, 445 SAT scores, 410, 449 Security breaches, 447 Selection of Senate committees, 423, 428 Selection of Supreme Court judges, 492 Senior citizens’ health care, 142, 753 Seniors in the workplace, 720, 740 Single female-headed households with children, 783 Smoking and education, 493 Social ladder, 493 Social programs planning 336, 348 Socially responsible funds, 626 Spread of rumor, 690 Student dropout rate, 410 Student enrollment, 482, 763 Student financial aid, 483 Student loans, 223 Student population, 146 Student reading habits, 410 Student surveys, 410, 461 Study groups, 427 Surveillance cameras, 102 Switching jobs, 456 Teacher attitudes, 455 Teaching assistantships, 428 Television-viewing polls, 416 Thurston learning models, 151, 627 Traffic deaths, 445 Traffic-flow analysis, 269, 272, 627, 708 Traffic surveys, 445, 446 TV viewing patterns, 569, 582 U.N. Security Council voting, 425, 428 U.S. birthrate, 523 U.S. census, 613, 825 U.S. citizens 65 and older, 793 U.S. nursing shortage, 674 U.S. population by age, 501 Voter affiliation, 296 Voter turnout by income, 492 Voter turnout by profession, 493 Voting patterns, 492 Voting quorum, 429 Water supply, 335, 348 Women in the labor force, 641 Working-age population, 142 Working mothers, 626 World population growth, 177, 638, 641, 722

LIFE SCIENCES Absorption of drugs, 159, 161, 170, 181, 183, 708, 796 Administration of an IV solution, 565 Adult obesity, 655 Agriculture, 248, 261, 311 AIDS in Massachusetts, 796 Air purification, 614, 783, 805 Amount of glucose in the bloodstream, 764 Animal nutrition, 349 Anticipated rise in Alzheimer’s patients, 101 Arteriosclerosis, 624, 627 Average weights and heights of infants, 582, 764

Bacteria growth, 236 Birthrate of endangered species, 108 Birthrates, 523 Blood alcohol level, 639 Blood flow in an artery, 754 Blood pressure, 169 Blood types, 437, 444, 445 Body mass, 834 Brain growth and IQs, 722 Cancer survivors, 130 Carbon-14 dating, 173, 177 Carbon monoxide in the air, 108, 601, 762 Child obesity, 597 Cholesterol levels, 282 Clark’s rule, 151 Color blindness, 473 Concentration of a drug in an organ, 673, 764 Concentration of a drug in the bloodstream, 61, 550, 612, 707, 791, 793 Conservation of species, 593, 598 Contraction of the trachea during a cough, 715 Corrective lens use, 446 Cowling’s rule, 35 Cricket chirping and temperature, 119 Crop planning, 247, 259, 261, 311, 335, 348 Crop yield, 582, 641, 796 Death due to strokes, 638 Dietary planning, 248, 262, 298, 386 Diet-mix problems, 272, 310, 336, 348 Disability rates, 159 Doomsday situation, 550 Drug dosages, 118, 612 Effect of bactericide, 61, 583, 612 Effect of enzymes on chemical reactions, 707 Energy expended by a fish, 566, 723 Environment of forests, 673 Eradication of polio, 639 Extinction situation, 640 Fertilizer mixtures, 248, 261, 311 Fisheries, 598 Flights of birds, 736 Flow of blood in an artery, 794 Forensic science, 170 Forestry, 582 Formaldehyde levels, 613 Flu epidemic, 183 Gastric bypass surgeries, 752 Genetically modified crops, 752 Global epidemic, 785 Global warming, 135, 793 Growth of a cancerous tumor, 97, 596 Growth of bacteria, 171, 177, 182, 584 Growth of fruit fly population, 178 Harbor cleanup, 98 Heights of children, 754 Heights of trees, 169 Heights of women, 528, 531 Ideal heights and weights for women, 83 Importance of time in treating heart attacks, 615 Increasing crop yields, 641 Infant mortality rates in MA, 141 Lengths of fish, 170, 178 Life expectancy after age 65, 97 Life expectancy of a female, 624, 763 Living with HIV, 178 Logistic growth function, 179 Lorentz curves, 816, 817, 819, 826 Male life expectancy, 656 Measles deaths, 147, 693 Medical diagnoses, 493 Medical research, 483, 492 Medical surveys, 479 Meteorology, 444 Nicotine content of cigarettes, 148 Nuclear fallout, 177 Nutrition, 272, 310, 331, 336, 342, 348 Obese children in the U.S., 142, 493 Obesity in America, 599, 614 Organizing medical data, 282 Outpatient service company, 754 Oxygen content of a pond, 51, 553, 566, 606, 708, 721 Ozone pollution, 753 Photosynthesis, 551 Poiseuille’s law, 131, 722, 754, 784, 794, 834 Polio immunization, 639 Preservation of species, 598 Prevalence of Alzheimer’s patients, 101, 130, 616, 672 Probability of transplant rejection, 484 Pulse rates, 627, 805 Quality of environment, 739 Radioactive decay, 172, 173, 177, 179, 183 Rate of growth of a tumor, 181

Reaction of a frog to a drug, 140 Reaction to a drug, 19, 723 Reliability of medical tests, 491 Risk of Down syndrome, 752 Smoking and emphysema, 479 Speed of a chemical reaction, 551 Spread of flu epidemic, 19, 175, 178, 708 Spread of HIV, 602 Storing radioactive waste, 735 Surface area of the human body, 754, 835, 848 Surgeries in physicians offices, 677, 696 Toxic pollutants, 550 U.S. infant mortality rate, 183 Velocity of blood, 596, 722 Veterinary science, 349 Walking vs running, 142 Water pollution, 690 Weight of whales, 82 Weiss’s law, 566 Whale population, 593 Yield of an apple orchard, 143, 735

GENERAL INTEREST Acceleration of a car, 613, 754 Amount of rainfall, 755 Atmospheric pressure, 177 Automobile options, 401 Average highway speed of a vehicle, 598, 673, 720 Average velocity of a truck, 825 Ballast dropped from a balloon, 753 Birthday problem, 466, 470 Blackjack, 416, 469 Boston Marathon, 670 Bus routing, 429 Carrier landing, 754 Celsius and Fahrenheit temperature, 60, 118 Code words, 416 Computer dating, 416 Designing a grain silo, 735 Designing a Norman window, 131, 734 Draining a tank, 754 Driving range of a car, 60 Effect of stopping on average speed, 597 Engine efficiency, 847 Exercise program, 235 Family food expenditure, 198 Fencing a garden, 726 Flight of a rocket, 594, 599, 672, 692, 720 Flight path of a plane, 570, 711, 753 Force generated by a centrifuge, 836 Game shows, 437 Golden ratio, 51 Inflating a balloon, 151 International Americas’ cup class, 836 IQs, 834, 861 Keeping with the traffic flow, 102 Launching a fighter aircraft, 755 License plate numbers, 416, 417 Lightning deaths, 446 Lotteries, 211, 417, 514 Magnitude of earthquakes, 169 Manned bomber research, 488 Measuring temperature, 824 Menu selection, 413 Motion of a maglev, 609, 748, 751 Newton’s law of cooling, 169, 180, 792 Poker, 424, 461 Postal regulations, 564, 734 Raffles, 507 Roulette, 446, 469, 508, 509, 515 Scheduling performances, 425 Slot machines, 417, 469 Sound intensity, 169 Speedboat racing, 783 Sports, 428, 429, 438, 515 Stopping distance of a racing car, 597 Strength of a beam, 735 Sweepstakes, 446 Team selection, 462 Terminal velocity, 706 Travel options, 415 Turbo-charged engine performance, 806 Vacation costs, 262 Velocity of a car, 578, 584, 793 Wardrobe selection, 416 Weather, 516 Wind chill factor, 847 Women’s soccer, 694 Zodiac signs, 470